R \cdot \sqrt{\left(\left(\lambda_1 - \lambda_2\right) \cdot \cos \left(\frac{\phi_1 + \phi_2}{2}\right)\right) \cdot \left(\left(\lambda_1 - \lambda_2\right) \cdot \cos \left(\frac{\phi_1 + \phi_2}{2}\right)\right) + \left(\phi_1 - \phi_2\right) \cdot \left(\phi_1 - \phi_2\right)}\begin{array}{l}
\mathbf{if}\;\phi_2 \le 1.040568751298684604162040128554892939397 \cdot 10^{54}:\\
\;\;\;\;R \cdot \sqrt{\left(\lambda_1 - \lambda_2\right) \cdot \left(\cos \left(\frac{\phi_1 + \phi_2}{2}\right) \cdot \left(\left(\lambda_1 - \lambda_2\right) \cdot \cos \left(\frac{\phi_1 + \phi_2}{2}\right)\right)\right) + \left(\phi_1 - \phi_2\right) \cdot \left(\phi_1 - \phi_2\right)}\\
\mathbf{else}:\\
\;\;\;\;R \cdot \left(\phi_2 - \phi_1\right)\\
\end{array}double f(double R, double lambda1, double lambda2, double phi1, double phi2) {
double r94141 = R;
double r94142 = lambda1;
double r94143 = lambda2;
double r94144 = r94142 - r94143;
double r94145 = phi1;
double r94146 = phi2;
double r94147 = r94145 + r94146;
double r94148 = 2.0;
double r94149 = r94147 / r94148;
double r94150 = cos(r94149);
double r94151 = r94144 * r94150;
double r94152 = r94151 * r94151;
double r94153 = r94145 - r94146;
double r94154 = r94153 * r94153;
double r94155 = r94152 + r94154;
double r94156 = sqrt(r94155);
double r94157 = r94141 * r94156;
return r94157;
}
double f(double R, double lambda1, double lambda2, double phi1, double phi2) {
double r94158 = phi2;
double r94159 = 1.0405687512986846e+54;
bool r94160 = r94158 <= r94159;
double r94161 = R;
double r94162 = lambda1;
double r94163 = lambda2;
double r94164 = r94162 - r94163;
double r94165 = phi1;
double r94166 = r94165 + r94158;
double r94167 = 2.0;
double r94168 = r94166 / r94167;
double r94169 = cos(r94168);
double r94170 = r94164 * r94169;
double r94171 = r94169 * r94170;
double r94172 = r94164 * r94171;
double r94173 = r94165 - r94158;
double r94174 = r94173 * r94173;
double r94175 = r94172 + r94174;
double r94176 = sqrt(r94175);
double r94177 = r94161 * r94176;
double r94178 = r94158 - r94165;
double r94179 = r94161 * r94178;
double r94180 = r94160 ? r94177 : r94179;
return r94180;
}



Bits error versus R



Bits error versus lambda1



Bits error versus lambda2



Bits error versus phi1



Bits error versus phi2
Results
if phi2 < 1.0405687512986846e+54Initial program 36.0
rmApplied associate-*l*36.0
if 1.0405687512986846e+54 < phi2 Initial program 49.9
Taylor expanded around 0 22.3
Final simplification33.4
herbie shell --seed 2019356
(FPCore (R lambda1 lambda2 phi1 phi2)
:name "Equirectangular approximation to distance on a great circle"
:precision binary64
(* R (sqrt (+ (* (* (- lambda1 lambda2) (cos (/ (+ phi1 phi2) 2))) (* (- lambda1 lambda2) (cos (/ (+ phi1 phi2) 2)))) (* (- phi1 phi2) (- phi1 phi2))))))