2-ancestry mixing, positive discriminant

Percentage Accurate: 44.7% → 95.8%
Time: 9.3s
Alternatives: 3
Speedup: 3.8×

Specification

?
\[\begin{array}{l} t_0 := \frac{1}{2 \cdot a}\\ t_1 := \sqrt{g \cdot g - h \cdot h}\\ \sqrt[3]{t\_0 \cdot \left(\left(-g\right) + t\_1\right)} + \sqrt[3]{t\_0 \cdot \left(\left(-g\right) - t\_1\right)} \end{array} \]
(FPCore (g h a)
  :precision binary64
  (let* ((t_0 (/ 1.0 (* 2.0 a))) (t_1 (sqrt (- (* g g) (* h h)))))
  (+ (cbrt (* t_0 (+ (- g) t_1))) (cbrt (* t_0 (- (- g) t_1))))))
double code(double g, double h, double a) {
	double t_0 = 1.0 / (2.0 * a);
	double t_1 = sqrt(((g * g) - (h * h)));
	return cbrt((t_0 * (-g + t_1))) + cbrt((t_0 * (-g - t_1)));
}
public static double code(double g, double h, double a) {
	double t_0 = 1.0 / (2.0 * a);
	double t_1 = Math.sqrt(((g * g) - (h * h)));
	return Math.cbrt((t_0 * (-g + t_1))) + Math.cbrt((t_0 * (-g - t_1)));
}
function code(g, h, a)
	t_0 = Float64(1.0 / Float64(2.0 * a))
	t_1 = sqrt(Float64(Float64(g * g) - Float64(h * h)))
	return Float64(cbrt(Float64(t_0 * Float64(Float64(-g) + t_1))) + cbrt(Float64(t_0 * Float64(Float64(-g) - t_1))))
end
code[g_, h_, a_] := Block[{t$95$0 = N[(1.0 / N[(2.0 * a), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[Sqrt[N[(N[(g * g), $MachinePrecision] - N[(h * h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, N[(N[Power[N[(t$95$0 * N[((-g) + t$95$1), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(t$95$0 * N[((-g) - t$95$1), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}
t_0 := \frac{1}{2 \cdot a}\\
t_1 := \sqrt{g \cdot g - h \cdot h}\\
\sqrt[3]{t\_0 \cdot \left(\left(-g\right) + t\_1\right)} + \sqrt[3]{t\_0 \cdot \left(\left(-g\right) - t\_1\right)}
\end{array}

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 3 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 44.7% accurate, 1.0× speedup?

\[\begin{array}{l} t_0 := \frac{1}{2 \cdot a}\\ t_1 := \sqrt{g \cdot g - h \cdot h}\\ \sqrt[3]{t\_0 \cdot \left(\left(-g\right) + t\_1\right)} + \sqrt[3]{t\_0 \cdot \left(\left(-g\right) - t\_1\right)} \end{array} \]
(FPCore (g h a)
  :precision binary64
  (let* ((t_0 (/ 1.0 (* 2.0 a))) (t_1 (sqrt (- (* g g) (* h h)))))
  (+ (cbrt (* t_0 (+ (- g) t_1))) (cbrt (* t_0 (- (- g) t_1))))))
double code(double g, double h, double a) {
	double t_0 = 1.0 / (2.0 * a);
	double t_1 = sqrt(((g * g) - (h * h)));
	return cbrt((t_0 * (-g + t_1))) + cbrt((t_0 * (-g - t_1)));
}
public static double code(double g, double h, double a) {
	double t_0 = 1.0 / (2.0 * a);
	double t_1 = Math.sqrt(((g * g) - (h * h)));
	return Math.cbrt((t_0 * (-g + t_1))) + Math.cbrt((t_0 * (-g - t_1)));
}
function code(g, h, a)
	t_0 = Float64(1.0 / Float64(2.0 * a))
	t_1 = sqrt(Float64(Float64(g * g) - Float64(h * h)))
	return Float64(cbrt(Float64(t_0 * Float64(Float64(-g) + t_1))) + cbrt(Float64(t_0 * Float64(Float64(-g) - t_1))))
end
code[g_, h_, a_] := Block[{t$95$0 = N[(1.0 / N[(2.0 * a), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[Sqrt[N[(N[(g * g), $MachinePrecision] - N[(h * h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, N[(N[Power[N[(t$95$0 * N[((-g) + t$95$1), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(t$95$0 * N[((-g) - t$95$1), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}
t_0 := \frac{1}{2 \cdot a}\\
t_1 := \sqrt{g \cdot g - h \cdot h}\\
\sqrt[3]{t\_0 \cdot \left(\left(-g\right) + t\_1\right)} + \sqrt[3]{t\_0 \cdot \left(\left(-g\right) - t\_1\right)}
\end{array}

Alternative 1: 95.8% accurate, 0.8× speedup?

\[\begin{array}{l} t_0 := g \cdot \left(1 + 0.5 \cdot \frac{h + -1 \cdot h}{g}\right)\\ \mathsf{fma}\left(\sqrt[3]{\frac{1}{a}}, \sqrt[3]{\frac{t\_0 + g}{-2}}, \sqrt[3]{\frac{t\_0 - g}{a + a}}\right) \end{array} \]
(FPCore (g h a)
  :precision binary64
  (let* ((t_0 (* g (+ 1.0 (* 0.5 (/ (+ h (* -1.0 h)) g))))))
  (fma
   (cbrt (/ 1.0 a))
   (cbrt (/ (+ t_0 g) -2.0))
   (cbrt (/ (- t_0 g) (+ a a))))))
double code(double g, double h, double a) {
	double t_0 = g * (1.0 + (0.5 * ((h + (-1.0 * h)) / g)));
	return fma(cbrt((1.0 / a)), cbrt(((t_0 + g) / -2.0)), cbrt(((t_0 - g) / (a + a))));
}
function code(g, h, a)
	t_0 = Float64(g * Float64(1.0 + Float64(0.5 * Float64(Float64(h + Float64(-1.0 * h)) / g))))
	return fma(cbrt(Float64(1.0 / a)), cbrt(Float64(Float64(t_0 + g) / -2.0)), cbrt(Float64(Float64(t_0 - g) / Float64(a + a))))
end
code[g_, h_, a_] := Block[{t$95$0 = N[(g * N[(1.0 + N[(0.5 * N[(N[(h + N[(-1.0 * h), $MachinePrecision]), $MachinePrecision] / g), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, N[(N[Power[N[(1.0 / a), $MachinePrecision], 1/3], $MachinePrecision] * N[Power[N[(N[(t$95$0 + g), $MachinePrecision] / -2.0), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(N[(t$95$0 - g), $MachinePrecision] / N[(a + a), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}
t_0 := g \cdot \left(1 + 0.5 \cdot \frac{h + -1 \cdot h}{g}\right)\\
\mathsf{fma}\left(\sqrt[3]{\frac{1}{a}}, \sqrt[3]{\frac{t\_0 + g}{-2}}, \sqrt[3]{\frac{t\_0 - g}{a + a}}\right)
\end{array}
Derivation
  1. Initial program 44.7%

    \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
  2. Applied rewrites47.5%

    \[\leadsto \color{blue}{\mathsf{fma}\left(\sqrt[3]{\frac{1}{a}}, \sqrt[3]{\frac{\sqrt{\left(g - h\right) \cdot \left(h + g\right)} + g}{-2}}, \sqrt[3]{\frac{\sqrt{\left(g - h\right) \cdot \left(h + g\right)} - g}{a + a}}\right)} \]
  3. Taylor expanded in g around inf

    \[\leadsto \mathsf{fma}\left(\sqrt[3]{\frac{1}{a}}, \sqrt[3]{\frac{\color{blue}{g \cdot \left(1 + \frac{1}{2} \cdot \frac{h + -1 \cdot h}{g}\right)} + g}{-2}}, \sqrt[3]{\frac{\sqrt{\left(g - h\right) \cdot \left(h + g\right)} - g}{a + a}}\right) \]
  4. Step-by-step derivation
    1. lower-*.f64N/A

      \[\leadsto \mathsf{fma}\left(\sqrt[3]{\frac{1}{a}}, \sqrt[3]{\frac{g \cdot \color{blue}{\left(1 + \frac{1}{2} \cdot \frac{h + -1 \cdot h}{g}\right)} + g}{-2}}, \sqrt[3]{\frac{\sqrt{\left(g - h\right) \cdot \left(h + g\right)} - g}{a + a}}\right) \]
    2. lower-+.f64N/A

      \[\leadsto \mathsf{fma}\left(\sqrt[3]{\frac{1}{a}}, \sqrt[3]{\frac{g \cdot \left(1 + \color{blue}{\frac{1}{2} \cdot \frac{h + -1 \cdot h}{g}}\right) + g}{-2}}, \sqrt[3]{\frac{\sqrt{\left(g - h\right) \cdot \left(h + g\right)} - g}{a + a}}\right) \]
    3. lower-*.f64N/A

      \[\leadsto \mathsf{fma}\left(\sqrt[3]{\frac{1}{a}}, \sqrt[3]{\frac{g \cdot \left(1 + \frac{1}{2} \cdot \color{blue}{\frac{h + -1 \cdot h}{g}}\right) + g}{-2}}, \sqrt[3]{\frac{\sqrt{\left(g - h\right) \cdot \left(h + g\right)} - g}{a + a}}\right) \]
    4. lower-/.f64N/A

      \[\leadsto \mathsf{fma}\left(\sqrt[3]{\frac{1}{a}}, \sqrt[3]{\frac{g \cdot \left(1 + \frac{1}{2} \cdot \frac{h + -1 \cdot h}{\color{blue}{g}}\right) + g}{-2}}, \sqrt[3]{\frac{\sqrt{\left(g - h\right) \cdot \left(h + g\right)} - g}{a + a}}\right) \]
    5. lower-+.f64N/A

      \[\leadsto \mathsf{fma}\left(\sqrt[3]{\frac{1}{a}}, \sqrt[3]{\frac{g \cdot \left(1 + \frac{1}{2} \cdot \frac{h + -1 \cdot h}{g}\right) + g}{-2}}, \sqrt[3]{\frac{\sqrt{\left(g - h\right) \cdot \left(h + g\right)} - g}{a + a}}\right) \]
    6. lower-*.f6432.8%

      \[\leadsto \mathsf{fma}\left(\sqrt[3]{\frac{1}{a}}, \sqrt[3]{\frac{g \cdot \left(1 + 0.5 \cdot \frac{h + -1 \cdot h}{g}\right) + g}{-2}}, \sqrt[3]{\frac{\sqrt{\left(g - h\right) \cdot \left(h + g\right)} - g}{a + a}}\right) \]
  5. Applied rewrites32.8%

    \[\leadsto \mathsf{fma}\left(\sqrt[3]{\frac{1}{a}}, \sqrt[3]{\frac{\color{blue}{g \cdot \left(1 + 0.5 \cdot \frac{h + -1 \cdot h}{g}\right)} + g}{-2}}, \sqrt[3]{\frac{\sqrt{\left(g - h\right) \cdot \left(h + g\right)} - g}{a + a}}\right) \]
  6. Taylor expanded in g around inf

    \[\leadsto \mathsf{fma}\left(\sqrt[3]{\frac{1}{a}}, \sqrt[3]{\frac{g \cdot \left(1 + 0.5 \cdot \frac{h + -1 \cdot h}{g}\right) + g}{-2}}, \sqrt[3]{\frac{\color{blue}{g \cdot \left(1 + \frac{1}{2} \cdot \frac{h + -1 \cdot h}{g}\right)} - g}{a + a}}\right) \]
  7. Step-by-step derivation
    1. lower-*.f64N/A

      \[\leadsto \mathsf{fma}\left(\sqrt[3]{\frac{1}{a}}, \sqrt[3]{\frac{g \cdot \left(1 + \frac{1}{2} \cdot \frac{h + -1 \cdot h}{g}\right) + g}{-2}}, \sqrt[3]{\frac{g \cdot \color{blue}{\left(1 + \frac{1}{2} \cdot \frac{h + -1 \cdot h}{g}\right)} - g}{a + a}}\right) \]
    2. lower-+.f64N/A

      \[\leadsto \mathsf{fma}\left(\sqrt[3]{\frac{1}{a}}, \sqrt[3]{\frac{g \cdot \left(1 + \frac{1}{2} \cdot \frac{h + -1 \cdot h}{g}\right) + g}{-2}}, \sqrt[3]{\frac{g \cdot \left(1 + \color{blue}{\frac{1}{2} \cdot \frac{h + -1 \cdot h}{g}}\right) - g}{a + a}}\right) \]
    3. lower-*.f64N/A

      \[\leadsto \mathsf{fma}\left(\sqrt[3]{\frac{1}{a}}, \sqrt[3]{\frac{g \cdot \left(1 + \frac{1}{2} \cdot \frac{h + -1 \cdot h}{g}\right) + g}{-2}}, \sqrt[3]{\frac{g \cdot \left(1 + \frac{1}{2} \cdot \color{blue}{\frac{h + -1 \cdot h}{g}}\right) - g}{a + a}}\right) \]
    4. lower-/.f64N/A

      \[\leadsto \mathsf{fma}\left(\sqrt[3]{\frac{1}{a}}, \sqrt[3]{\frac{g \cdot \left(1 + \frac{1}{2} \cdot \frac{h + -1 \cdot h}{g}\right) + g}{-2}}, \sqrt[3]{\frac{g \cdot \left(1 + \frac{1}{2} \cdot \frac{h + -1 \cdot h}{\color{blue}{g}}\right) - g}{a + a}}\right) \]
    5. lower-+.f64N/A

      \[\leadsto \mathsf{fma}\left(\sqrt[3]{\frac{1}{a}}, \sqrt[3]{\frac{g \cdot \left(1 + \frac{1}{2} \cdot \frac{h + -1 \cdot h}{g}\right) + g}{-2}}, \sqrt[3]{\frac{g \cdot \left(1 + \frac{1}{2} \cdot \frac{h + -1 \cdot h}{g}\right) - g}{a + a}}\right) \]
    6. lower-*.f6495.6%

      \[\leadsto \mathsf{fma}\left(\sqrt[3]{\frac{1}{a}}, \sqrt[3]{\frac{g \cdot \left(1 + 0.5 \cdot \frac{h + -1 \cdot h}{g}\right) + g}{-2}}, \sqrt[3]{\frac{g \cdot \left(1 + 0.5 \cdot \frac{h + -1 \cdot h}{g}\right) - g}{a + a}}\right) \]
  8. Applied rewrites95.6%

    \[\leadsto \mathsf{fma}\left(\sqrt[3]{\frac{1}{a}}, \sqrt[3]{\frac{g \cdot \left(1 + 0.5 \cdot \frac{h + -1 \cdot h}{g}\right) + g}{-2}}, \sqrt[3]{\frac{\color{blue}{g \cdot \left(1 + 0.5 \cdot \frac{h + -1 \cdot h}{g}\right)} - g}{a + a}}\right) \]
  9. Add Preprocessing

Alternative 2: 95.6% accurate, 2.2× speedup?

\[\frac{-\sqrt[3]{g}}{\sqrt[3]{a}} \]
(FPCore (g h a)
  :precision binary64
  (/ (- (cbrt g)) (cbrt a)))
double code(double g, double h, double a) {
	return -cbrt(g) / cbrt(a);
}
public static double code(double g, double h, double a) {
	return -Math.cbrt(g) / Math.cbrt(a);
}
function code(g, h, a)
	return Float64(Float64(-cbrt(g)) / cbrt(a))
end
code[g_, h_, a_] := N[((-N[Power[g, 1/3], $MachinePrecision]) / N[Power[a, 1/3], $MachinePrecision]), $MachinePrecision]
\frac{-\sqrt[3]{g}}{\sqrt[3]{a}}
Derivation
  1. Initial program 44.7%

    \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
  2. Step-by-step derivation
    1. lift-+.f64N/A

      \[\leadsto \color{blue}{\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)}} \]
    2. +-commutativeN/A

      \[\leadsto \color{blue}{\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)}} \]
    3. lift-cbrt.f64N/A

      \[\leadsto \color{blue}{\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)}} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} \]
    4. lift-*.f64N/A

      \[\leadsto \sqrt[3]{\color{blue}{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)}} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} \]
    5. cbrt-prodN/A

      \[\leadsto \color{blue}{\sqrt[3]{\frac{1}{2 \cdot a}} \cdot \sqrt[3]{\left(-g\right) - \sqrt{g \cdot g - h \cdot h}}} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} \]
    6. lift-cbrt.f64N/A

      \[\leadsto \sqrt[3]{\frac{1}{2 \cdot a}} \cdot \sqrt[3]{\left(-g\right) - \sqrt{g \cdot g - h \cdot h}} + \color{blue}{\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)}} \]
    7. lift-*.f64N/A

      \[\leadsto \sqrt[3]{\frac{1}{2 \cdot a}} \cdot \sqrt[3]{\left(-g\right) - \sqrt{g \cdot g - h \cdot h}} + \sqrt[3]{\color{blue}{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)}} \]
    8. cbrt-prodN/A

      \[\leadsto \sqrt[3]{\frac{1}{2 \cdot a}} \cdot \sqrt[3]{\left(-g\right) - \sqrt{g \cdot g - h \cdot h}} + \color{blue}{\sqrt[3]{\frac{1}{2 \cdot a}} \cdot \sqrt[3]{\left(-g\right) + \sqrt{g \cdot g - h \cdot h}}} \]
  3. Applied rewrites23.9%

    \[\leadsto \color{blue}{{\left(a + a\right)}^{-0.3333333333333333} \cdot \left(\sqrt[3]{\sqrt{\left(g - h\right) \cdot \left(h + g\right)} - g} - \sqrt[3]{\sqrt{\left(g - h\right) \cdot \left(h + g\right)} + g}\right)} \]
  4. Taylor expanded in g around inf

    \[\leadsto \color{blue}{-1 \cdot \frac{\sqrt[3]{g}}{\sqrt[3]{a}}} \]
  5. Step-by-step derivation
    1. lower-*.f64N/A

      \[\leadsto -1 \cdot \color{blue}{\frac{\sqrt[3]{g}}{\sqrt[3]{a}}} \]
    2. lower-/.f64N/A

      \[\leadsto -1 \cdot \frac{\sqrt[3]{g}}{\color{blue}{\sqrt[3]{a}}} \]
    3. lower-cbrt.f64N/A

      \[\leadsto -1 \cdot \frac{\sqrt[3]{g}}{\sqrt[3]{\color{blue}{a}}} \]
    4. lower-cbrt.f6495.8%

      \[\leadsto -1 \cdot \frac{\sqrt[3]{g}}{\sqrt[3]{a}} \]
  6. Applied rewrites95.8%

    \[\leadsto \color{blue}{-1 \cdot \frac{\sqrt[3]{g}}{\sqrt[3]{a}}} \]
  7. Step-by-step derivation
    1. lift-*.f64N/A

      \[\leadsto -1 \cdot \color{blue}{\frac{\sqrt[3]{g}}{\sqrt[3]{a}}} \]
    2. mul-1-negN/A

      \[\leadsto \mathsf{neg}\left(\frac{\sqrt[3]{g}}{\sqrt[3]{a}}\right) \]
    3. lift-/.f64N/A

      \[\leadsto \mathsf{neg}\left(\frac{\sqrt[3]{g}}{\sqrt[3]{a}}\right) \]
    4. distribute-neg-fracN/A

      \[\leadsto \frac{\mathsf{neg}\left(\sqrt[3]{g}\right)}{\color{blue}{\sqrt[3]{a}}} \]
    5. lower-/.f64N/A

      \[\leadsto \frac{\mathsf{neg}\left(\sqrt[3]{g}\right)}{\color{blue}{\sqrt[3]{a}}} \]
    6. lower-neg.f6495.8%

      \[\leadsto \frac{-\sqrt[3]{g}}{\sqrt[3]{\color{blue}{a}}} \]
  8. Applied rewrites95.8%

    \[\leadsto \frac{-\sqrt[3]{g}}{\color{blue}{\sqrt[3]{a}}} \]
  9. Add Preprocessing

Alternative 3: 73.7% accurate, 3.8× speedup?

\[-\sqrt[3]{\frac{g}{a}} \]
(FPCore (g h a)
  :precision binary64
  (- (cbrt (/ g a))))
double code(double g, double h, double a) {
	return -cbrt((g / a));
}
public static double code(double g, double h, double a) {
	return -Math.cbrt((g / a));
}
function code(g, h, a)
	return Float64(-cbrt(Float64(g / a)))
end
code[g_, h_, a_] := (-N[Power[N[(g / a), $MachinePrecision], 1/3], $MachinePrecision])
-\sqrt[3]{\frac{g}{a}}
Derivation
  1. Initial program 44.7%

    \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
  2. Step-by-step derivation
    1. lift-+.f64N/A

      \[\leadsto \color{blue}{\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)}} \]
    2. +-commutativeN/A

      \[\leadsto \color{blue}{\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)}} \]
    3. lift-cbrt.f64N/A

      \[\leadsto \color{blue}{\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)}} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} \]
    4. lift-*.f64N/A

      \[\leadsto \sqrt[3]{\color{blue}{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)}} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} \]
    5. cbrt-prodN/A

      \[\leadsto \color{blue}{\sqrt[3]{\frac{1}{2 \cdot a}} \cdot \sqrt[3]{\left(-g\right) - \sqrt{g \cdot g - h \cdot h}}} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} \]
    6. lift-cbrt.f64N/A

      \[\leadsto \sqrt[3]{\frac{1}{2 \cdot a}} \cdot \sqrt[3]{\left(-g\right) - \sqrt{g \cdot g - h \cdot h}} + \color{blue}{\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)}} \]
    7. lift-*.f64N/A

      \[\leadsto \sqrt[3]{\frac{1}{2 \cdot a}} \cdot \sqrt[3]{\left(-g\right) - \sqrt{g \cdot g - h \cdot h}} + \sqrt[3]{\color{blue}{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)}} \]
    8. cbrt-prodN/A

      \[\leadsto \sqrt[3]{\frac{1}{2 \cdot a}} \cdot \sqrt[3]{\left(-g\right) - \sqrt{g \cdot g - h \cdot h}} + \color{blue}{\sqrt[3]{\frac{1}{2 \cdot a}} \cdot \sqrt[3]{\left(-g\right) + \sqrt{g \cdot g - h \cdot h}}} \]
  3. Applied rewrites23.9%

    \[\leadsto \color{blue}{{\left(a + a\right)}^{-0.3333333333333333} \cdot \left(\sqrt[3]{\sqrt{\left(g - h\right) \cdot \left(h + g\right)} - g} - \sqrt[3]{\sqrt{\left(g - h\right) \cdot \left(h + g\right)} + g}\right)} \]
  4. Taylor expanded in g around inf

    \[\leadsto \color{blue}{-1 \cdot \frac{\sqrt[3]{g}}{\sqrt[3]{a}}} \]
  5. Step-by-step derivation
    1. lower-*.f64N/A

      \[\leadsto -1 \cdot \color{blue}{\frac{\sqrt[3]{g}}{\sqrt[3]{a}}} \]
    2. lower-/.f64N/A

      \[\leadsto -1 \cdot \frac{\sqrt[3]{g}}{\color{blue}{\sqrt[3]{a}}} \]
    3. lower-cbrt.f64N/A

      \[\leadsto -1 \cdot \frac{\sqrt[3]{g}}{\sqrt[3]{\color{blue}{a}}} \]
    4. lower-cbrt.f6495.8%

      \[\leadsto -1 \cdot \frac{\sqrt[3]{g}}{\sqrt[3]{a}} \]
  6. Applied rewrites95.8%

    \[\leadsto \color{blue}{-1 \cdot \frac{\sqrt[3]{g}}{\sqrt[3]{a}}} \]
  7. Step-by-step derivation
    1. lift-*.f64N/A

      \[\leadsto -1 \cdot \color{blue}{\frac{\sqrt[3]{g}}{\sqrt[3]{a}}} \]
    2. mul-1-negN/A

      \[\leadsto \mathsf{neg}\left(\frac{\sqrt[3]{g}}{\sqrt[3]{a}}\right) \]
    3. lower-neg.f6495.8%

      \[\leadsto -\frac{\sqrt[3]{g}}{\sqrt[3]{a}} \]
    4. lift-/.f64N/A

      \[\leadsto -\frac{\sqrt[3]{g}}{\sqrt[3]{a}} \]
    5. lift-cbrt.f64N/A

      \[\leadsto -\frac{\sqrt[3]{g}}{\sqrt[3]{a}} \]
    6. lift-cbrt.f64N/A

      \[\leadsto -\frac{\sqrt[3]{g}}{\sqrt[3]{a}} \]
    7. cbrt-undivN/A

      \[\leadsto -\sqrt[3]{\frac{g}{a}} \]
    8. lift-/.f64N/A

      \[\leadsto -\sqrt[3]{\frac{g}{a}} \]
    9. lower-cbrt.f6473.7%

      \[\leadsto -\sqrt[3]{\frac{g}{a}} \]
  8. Applied rewrites73.7%

    \[\leadsto -\sqrt[3]{\frac{g}{a}} \]
  9. Add Preprocessing

Reproduce

?
herbie shell --seed 2025213 
(FPCore (g h a)
  :name "2-ancestry mixing, positive discriminant"
  :precision binary64
  (+ (cbrt (* (/ 1.0 (* 2.0 a)) (+ (- g) (sqrt (- (* g g) (* h h)))))) (cbrt (* (/ 1.0 (* 2.0 a)) (- (- g) (sqrt (- (* g g) (* h h))))))))