Migdal et al, Equation (51)

Percentage Accurate: 99.4% → 99.5%
Time: 6.2s
Alternatives: 11
Speedup: 1.1×

Specification

?
\[\begin{array}{l} \\ \frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \end{array} \]
(FPCore (k n)
 :precision binary64
 (* (/ 1.0 (sqrt k)) (pow (* (* 2.0 PI) n) (/ (- 1.0 k) 2.0))))
double code(double k, double n) {
	return (1.0 / sqrt(k)) * pow(((2.0 * ((double) M_PI)) * n), ((1.0 - k) / 2.0));
}
public static double code(double k, double n) {
	return (1.0 / Math.sqrt(k)) * Math.pow(((2.0 * Math.PI) * n), ((1.0 - k) / 2.0));
}
def code(k, n):
	return (1.0 / math.sqrt(k)) * math.pow(((2.0 * math.pi) * n), ((1.0 - k) / 2.0))
function code(k, n)
	return Float64(Float64(1.0 / sqrt(k)) * (Float64(Float64(2.0 * pi) * n) ^ Float64(Float64(1.0 - k) / 2.0)))
end
function tmp = code(k, n)
	tmp = (1.0 / sqrt(k)) * (((2.0 * pi) * n) ^ ((1.0 - k) / 2.0));
end
code[k_, n_] := N[(N[(1.0 / N[Sqrt[k], $MachinePrecision]), $MachinePrecision] * N[Power[N[(N[(2.0 * Pi), $MachinePrecision] * n), $MachinePrecision], N[(N[(1.0 - k), $MachinePrecision] / 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}
\end{array}

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 11 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 99.4% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \end{array} \]
(FPCore (k n)
 :precision binary64
 (* (/ 1.0 (sqrt k)) (pow (* (* 2.0 PI) n) (/ (- 1.0 k) 2.0))))
double code(double k, double n) {
	return (1.0 / sqrt(k)) * pow(((2.0 * ((double) M_PI)) * n), ((1.0 - k) / 2.0));
}
public static double code(double k, double n) {
	return (1.0 / Math.sqrt(k)) * Math.pow(((2.0 * Math.PI) * n), ((1.0 - k) / 2.0));
}
def code(k, n):
	return (1.0 / math.sqrt(k)) * math.pow(((2.0 * math.pi) * n), ((1.0 - k) / 2.0))
function code(k, n)
	return Float64(Float64(1.0 / sqrt(k)) * (Float64(Float64(2.0 * pi) * n) ^ Float64(Float64(1.0 - k) / 2.0)))
end
function tmp = code(k, n)
	tmp = (1.0 / sqrt(k)) * (((2.0 * pi) * n) ^ ((1.0 - k) / 2.0));
end
code[k_, n_] := N[(N[(1.0 / N[Sqrt[k], $MachinePrecision]), $MachinePrecision] * N[Power[N[(N[(2.0 * Pi), $MachinePrecision] * n), $MachinePrecision], N[(N[(1.0 - k), $MachinePrecision] / 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}
\end{array}

Alternative 1: 99.5% accurate, 0.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := n \cdot \left(\pi + \pi\right)\\ \frac{1}{\sqrt{k}} \cdot \left({t\_0}^{\left(k \cdot -0.5\right)} \cdot {t\_0}^{0.5}\right) \end{array} \end{array} \]
(FPCore (k n)
 :precision binary64
 (let* ((t_0 (* n (+ PI PI))))
   (* (/ 1.0 (sqrt k)) (* (pow t_0 (* k -0.5)) (pow t_0 0.5)))))
double code(double k, double n) {
	double t_0 = n * (((double) M_PI) + ((double) M_PI));
	return (1.0 / sqrt(k)) * (pow(t_0, (k * -0.5)) * pow(t_0, 0.5));
}
public static double code(double k, double n) {
	double t_0 = n * (Math.PI + Math.PI);
	return (1.0 / Math.sqrt(k)) * (Math.pow(t_0, (k * -0.5)) * Math.pow(t_0, 0.5));
}
def code(k, n):
	t_0 = n * (math.pi + math.pi)
	return (1.0 / math.sqrt(k)) * (math.pow(t_0, (k * -0.5)) * math.pow(t_0, 0.5))
function code(k, n)
	t_0 = Float64(n * Float64(pi + pi))
	return Float64(Float64(1.0 / sqrt(k)) * Float64((t_0 ^ Float64(k * -0.5)) * (t_0 ^ 0.5)))
end
function tmp = code(k, n)
	t_0 = n * (pi + pi);
	tmp = (1.0 / sqrt(k)) * ((t_0 ^ (k * -0.5)) * (t_0 ^ 0.5));
end
code[k_, n_] := Block[{t$95$0 = N[(n * N[(Pi + Pi), $MachinePrecision]), $MachinePrecision]}, N[(N[(1.0 / N[Sqrt[k], $MachinePrecision]), $MachinePrecision] * N[(N[Power[t$95$0, N[(k * -0.5), $MachinePrecision]], $MachinePrecision] * N[Power[t$95$0, 0.5], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := n \cdot \left(\pi + \pi\right)\\
\frac{1}{\sqrt{k}} \cdot \left({t\_0}^{\left(k \cdot -0.5\right)} \cdot {t\_0}^{0.5}\right)
\end{array}
\end{array}
Derivation
  1. Initial program 99.4%

    \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
  2. Step-by-step derivation
    1. lift-pow.f64N/A

      \[\leadsto \frac{1}{\sqrt{k}} \cdot \color{blue}{{\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}} \]
    2. lift-/.f64N/A

      \[\leadsto \frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\color{blue}{\left(\frac{1 - k}{2}\right)}} \]
    3. lift--.f64N/A

      \[\leadsto \frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{\color{blue}{1 - k}}{2}\right)} \]
    4. sub-flipN/A

      \[\leadsto \frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{\color{blue}{1 + \left(\mathsf{neg}\left(k\right)\right)}}{2}\right)} \]
    5. +-commutativeN/A

      \[\leadsto \frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{\color{blue}{\left(\mathsf{neg}\left(k\right)\right) + 1}}{2}\right)} \]
    6. div-addN/A

      \[\leadsto \frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\color{blue}{\left(\frac{\mathsf{neg}\left(k\right)}{2} + \frac{1}{2}\right)}} \]
    7. metadata-evalN/A

      \[\leadsto \frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{\mathsf{neg}\left(k\right)}{2} + \color{blue}{\frac{1}{2}}\right)} \]
    8. pow-addN/A

      \[\leadsto \frac{1}{\sqrt{k}} \cdot \color{blue}{\left({\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{\mathsf{neg}\left(k\right)}{2}\right)} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\frac{1}{2}}\right)} \]
    9. lower-unsound-*.f64N/A

      \[\leadsto \frac{1}{\sqrt{k}} \cdot \color{blue}{\left({\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{\mathsf{neg}\left(k\right)}{2}\right)} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\frac{1}{2}}\right)} \]
  3. Applied rewrites99.5%

    \[\leadsto \frac{1}{\sqrt{k}} \cdot \color{blue}{\left({\left(n \cdot \left(\pi + \pi\right)\right)}^{\left(k \cdot -0.5\right)} \cdot {\left(n \cdot \left(\pi + \pi\right)\right)}^{0.5}\right)} \]
  4. Add Preprocessing

Alternative 2: 99.5% accurate, 0.9× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(\pi + \pi\right) \cdot n\\ \frac{{t\_0}^{\left(-0.5 \cdot k\right)}}{\sqrt{k}} \cdot \sqrt{t\_0} \end{array} \end{array} \]
(FPCore (k n)
 :precision binary64
 (let* ((t_0 (* (+ PI PI) n)))
   (* (/ (pow t_0 (* -0.5 k)) (sqrt k)) (sqrt t_0))))
double code(double k, double n) {
	double t_0 = (((double) M_PI) + ((double) M_PI)) * n;
	return (pow(t_0, (-0.5 * k)) / sqrt(k)) * sqrt(t_0);
}
public static double code(double k, double n) {
	double t_0 = (Math.PI + Math.PI) * n;
	return (Math.pow(t_0, (-0.5 * k)) / Math.sqrt(k)) * Math.sqrt(t_0);
}
def code(k, n):
	t_0 = (math.pi + math.pi) * n
	return (math.pow(t_0, (-0.5 * k)) / math.sqrt(k)) * math.sqrt(t_0)
function code(k, n)
	t_0 = Float64(Float64(pi + pi) * n)
	return Float64(Float64((t_0 ^ Float64(-0.5 * k)) / sqrt(k)) * sqrt(t_0))
end
function tmp = code(k, n)
	t_0 = (pi + pi) * n;
	tmp = ((t_0 ^ (-0.5 * k)) / sqrt(k)) * sqrt(t_0);
end
code[k_, n_] := Block[{t$95$0 = N[(N[(Pi + Pi), $MachinePrecision] * n), $MachinePrecision]}, N[(N[(N[Power[t$95$0, N[(-0.5 * k), $MachinePrecision]], $MachinePrecision] / N[Sqrt[k], $MachinePrecision]), $MachinePrecision] * N[Sqrt[t$95$0], $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \left(\pi + \pi\right) \cdot n\\
\frac{{t\_0}^{\left(-0.5 \cdot k\right)}}{\sqrt{k}} \cdot \sqrt{t\_0}
\end{array}
\end{array}
Derivation
  1. Initial program 99.4%

    \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
  2. Step-by-step derivation
    1. lift-pow.f64N/A

      \[\leadsto \frac{1}{\sqrt{k}} \cdot \color{blue}{{\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}} \]
    2. lift-/.f64N/A

      \[\leadsto \frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\color{blue}{\left(\frac{1 - k}{2}\right)}} \]
    3. lift--.f64N/A

      \[\leadsto \frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{\color{blue}{1 - k}}{2}\right)} \]
    4. sub-flipN/A

      \[\leadsto \frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{\color{blue}{1 + \left(\mathsf{neg}\left(k\right)\right)}}{2}\right)} \]
    5. +-commutativeN/A

      \[\leadsto \frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{\color{blue}{\left(\mathsf{neg}\left(k\right)\right) + 1}}{2}\right)} \]
    6. div-addN/A

      \[\leadsto \frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\color{blue}{\left(\frac{\mathsf{neg}\left(k\right)}{2} + \frac{1}{2}\right)}} \]
    7. metadata-evalN/A

      \[\leadsto \frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{\mathsf{neg}\left(k\right)}{2} + \color{blue}{\frac{1}{2}}\right)} \]
    8. pow-addN/A

      \[\leadsto \frac{1}{\sqrt{k}} \cdot \color{blue}{\left({\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{\mathsf{neg}\left(k\right)}{2}\right)} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\frac{1}{2}}\right)} \]
    9. lower-unsound-*.f64N/A

      \[\leadsto \frac{1}{\sqrt{k}} \cdot \color{blue}{\left({\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{\mathsf{neg}\left(k\right)}{2}\right)} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\frac{1}{2}}\right)} \]
  3. Applied rewrites99.5%

    \[\leadsto \frac{1}{\sqrt{k}} \cdot \color{blue}{\left({\left(n \cdot \left(\pi + \pi\right)\right)}^{\left(k \cdot -0.5\right)} \cdot {\left(n \cdot \left(\pi + \pi\right)\right)}^{0.5}\right)} \]
  4. Applied rewrites99.5%

    \[\leadsto \color{blue}{\frac{{\left(\left(\pi + \pi\right) \cdot n\right)}^{\left(-0.5 \cdot k\right)}}{\sqrt{k}} \cdot \sqrt{\left(\pi + \pi\right) \cdot n}} \]
  5. Add Preprocessing

Alternative 3: 99.5% accurate, 1.1× speedup?

\[\begin{array}{l} \\ \frac{{\left(n \cdot \left(\pi + \pi\right)\right)}^{\left(\mathsf{fma}\left(k, -0.5, 0.5\right)\right)}}{\sqrt{k}} \end{array} \]
(FPCore (k n)
 :precision binary64
 (/ (pow (* n (+ PI PI)) (fma k -0.5 0.5)) (sqrt k)))
double code(double k, double n) {
	return pow((n * (((double) M_PI) + ((double) M_PI))), fma(k, -0.5, 0.5)) / sqrt(k);
}
function code(k, n)
	return Float64((Float64(n * Float64(pi + pi)) ^ fma(k, -0.5, 0.5)) / sqrt(k))
end
code[k_, n_] := N[(N[Power[N[(n * N[(Pi + Pi), $MachinePrecision]), $MachinePrecision], N[(k * -0.5 + 0.5), $MachinePrecision]], $MachinePrecision] / N[Sqrt[k], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{{\left(n \cdot \left(\pi + \pi\right)\right)}^{\left(\mathsf{fma}\left(k, -0.5, 0.5\right)\right)}}{\sqrt{k}}
\end{array}
Derivation
  1. Initial program 99.4%

    \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
  2. Step-by-step derivation
    1. lift-*.f64N/A

      \[\leadsto \color{blue}{\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}} \]
    2. *-commutativeN/A

      \[\leadsto \color{blue}{{\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \cdot \frac{1}{\sqrt{k}}} \]
    3. lift-/.f64N/A

      \[\leadsto {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \cdot \color{blue}{\frac{1}{\sqrt{k}}} \]
    4. mult-flip-revN/A

      \[\leadsto \color{blue}{\frac{{\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}}{\sqrt{k}}} \]
    5. lower-/.f6499.5

      \[\leadsto \color{blue}{\frac{{\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}}{\sqrt{k}}} \]
  3. Applied rewrites99.5%

    \[\leadsto \color{blue}{\frac{{\left(n \cdot \left(\pi + \pi\right)\right)}^{\left(\mathsf{fma}\left(k, -0.5, 0.5\right)\right)}}{\sqrt{k}}} \]
  4. Add Preprocessing

Alternative 4: 98.4% accurate, 1.1× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(\pi + \pi\right) \cdot n\\ \mathbf{if}\;k \leq 1:\\ \;\;\;\;\frac{\sqrt{t\_0}}{\sqrt{k}}\\ \mathbf{else}:\\ \;\;\;\;\frac{{t\_0}^{\left(-0.5 \cdot k\right)}}{\sqrt{k}}\\ \end{array} \end{array} \]
(FPCore (k n)
 :precision binary64
 (let* ((t_0 (* (+ PI PI) n)))
   (if (<= k 1.0) (/ (sqrt t_0) (sqrt k)) (/ (pow t_0 (* -0.5 k)) (sqrt k)))))
double code(double k, double n) {
	double t_0 = (((double) M_PI) + ((double) M_PI)) * n;
	double tmp;
	if (k <= 1.0) {
		tmp = sqrt(t_0) / sqrt(k);
	} else {
		tmp = pow(t_0, (-0.5 * k)) / sqrt(k);
	}
	return tmp;
}
public static double code(double k, double n) {
	double t_0 = (Math.PI + Math.PI) * n;
	double tmp;
	if (k <= 1.0) {
		tmp = Math.sqrt(t_0) / Math.sqrt(k);
	} else {
		tmp = Math.pow(t_0, (-0.5 * k)) / Math.sqrt(k);
	}
	return tmp;
}
def code(k, n):
	t_0 = (math.pi + math.pi) * n
	tmp = 0
	if k <= 1.0:
		tmp = math.sqrt(t_0) / math.sqrt(k)
	else:
		tmp = math.pow(t_0, (-0.5 * k)) / math.sqrt(k)
	return tmp
function code(k, n)
	t_0 = Float64(Float64(pi + pi) * n)
	tmp = 0.0
	if (k <= 1.0)
		tmp = Float64(sqrt(t_0) / sqrt(k));
	else
		tmp = Float64((t_0 ^ Float64(-0.5 * k)) / sqrt(k));
	end
	return tmp
end
function tmp_2 = code(k, n)
	t_0 = (pi + pi) * n;
	tmp = 0.0;
	if (k <= 1.0)
		tmp = sqrt(t_0) / sqrt(k);
	else
		tmp = (t_0 ^ (-0.5 * k)) / sqrt(k);
	end
	tmp_2 = tmp;
end
code[k_, n_] := Block[{t$95$0 = N[(N[(Pi + Pi), $MachinePrecision] * n), $MachinePrecision]}, If[LessEqual[k, 1.0], N[(N[Sqrt[t$95$0], $MachinePrecision] / N[Sqrt[k], $MachinePrecision]), $MachinePrecision], N[(N[Power[t$95$0, N[(-0.5 * k), $MachinePrecision]], $MachinePrecision] / N[Sqrt[k], $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \left(\pi + \pi\right) \cdot n\\
\mathbf{if}\;k \leq 1:\\
\;\;\;\;\frac{\sqrt{t\_0}}{\sqrt{k}}\\

\mathbf{else}:\\
\;\;\;\;\frac{{t\_0}^{\left(-0.5 \cdot k\right)}}{\sqrt{k}}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if k < 1

    1. Initial program 99.4%

      \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
    2. Taylor expanded in k around 0

      \[\leadsto \color{blue}{\frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}}} \]
    3. Step-by-step derivation
      1. lower-/.f64N/A

        \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\color{blue}{\sqrt{k}}} \]
      2. lower-pow.f64N/A

        \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{\color{blue}{k}}} \]
      3. lower-*.f64N/A

        \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
      4. lower-*.f64N/A

        \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
      5. lower-PI.f64N/A

        \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
      6. lower-sqrt.f6450.3

        \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{0.5}}{\sqrt{k}} \]
    4. Applied rewrites50.3%

      \[\leadsto \color{blue}{\frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{0.5}}{\sqrt{k}}} \]
    5. Step-by-step derivation
      1. Applied rewrites50.3%

        \[\leadsto \frac{\sqrt{\left(\pi + \pi\right) \cdot n}}{\color{blue}{\sqrt{k}}} \]

      if 1 < k

      1. Initial program 99.4%

        \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
      2. Step-by-step derivation
        1. lift-pow.f64N/A

          \[\leadsto \frac{1}{\sqrt{k}} \cdot \color{blue}{{\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}} \]
        2. lift-/.f64N/A

          \[\leadsto \frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\color{blue}{\left(\frac{1 - k}{2}\right)}} \]
        3. lift--.f64N/A

          \[\leadsto \frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{\color{blue}{1 - k}}{2}\right)} \]
        4. sub-flipN/A

          \[\leadsto \frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{\color{blue}{1 + \left(\mathsf{neg}\left(k\right)\right)}}{2}\right)} \]
        5. +-commutativeN/A

          \[\leadsto \frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{\color{blue}{\left(\mathsf{neg}\left(k\right)\right) + 1}}{2}\right)} \]
        6. div-addN/A

          \[\leadsto \frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\color{blue}{\left(\frac{\mathsf{neg}\left(k\right)}{2} + \frac{1}{2}\right)}} \]
        7. metadata-evalN/A

          \[\leadsto \frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{\mathsf{neg}\left(k\right)}{2} + \color{blue}{\frac{1}{2}}\right)} \]
        8. pow-addN/A

          \[\leadsto \frac{1}{\sqrt{k}} \cdot \color{blue}{\left({\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{\mathsf{neg}\left(k\right)}{2}\right)} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\frac{1}{2}}\right)} \]
        9. lower-unsound-*.f64N/A

          \[\leadsto \frac{1}{\sqrt{k}} \cdot \color{blue}{\left({\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{\mathsf{neg}\left(k\right)}{2}\right)} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\frac{1}{2}}\right)} \]
      3. Applied rewrites99.5%

        \[\leadsto \frac{1}{\sqrt{k}} \cdot \color{blue}{\left({\left(n \cdot \left(\pi + \pi\right)\right)}^{\left(k \cdot -0.5\right)} \cdot {\left(n \cdot \left(\pi + \pi\right)\right)}^{0.5}\right)} \]
      4. Step-by-step derivation
        1. lift-*.f64N/A

          \[\leadsto \color{blue}{\frac{1}{\sqrt{k}} \cdot \left({\left(n \cdot \left(\pi + \pi\right)\right)}^{\left(k \cdot \frac{-1}{2}\right)} \cdot {\left(n \cdot \left(\pi + \pi\right)\right)}^{\frac{1}{2}}\right)} \]
        2. lift-/.f64N/A

          \[\leadsto \color{blue}{\frac{1}{\sqrt{k}}} \cdot \left({\left(n \cdot \left(\pi + \pi\right)\right)}^{\left(k \cdot \frac{-1}{2}\right)} \cdot {\left(n \cdot \left(\pi + \pi\right)\right)}^{\frac{1}{2}}\right) \]
        3. associate-/r/N/A

          \[\leadsto \color{blue}{\frac{1}{\frac{\sqrt{k}}{{\left(n \cdot \left(\pi + \pi\right)\right)}^{\left(k \cdot \frac{-1}{2}\right)} \cdot {\left(n \cdot \left(\pi + \pi\right)\right)}^{\frac{1}{2}}}}} \]
        4. div-flip-revN/A

          \[\leadsto \color{blue}{\frac{{\left(n \cdot \left(\pi + \pi\right)\right)}^{\left(k \cdot \frac{-1}{2}\right)} \cdot {\left(n \cdot \left(\pi + \pi\right)\right)}^{\frac{1}{2}}}{\sqrt{k}}} \]
        5. lower-/.f6499.6

          \[\leadsto \color{blue}{\frac{{\left(n \cdot \left(\pi + \pi\right)\right)}^{\left(k \cdot -0.5\right)} \cdot {\left(n \cdot \left(\pi + \pi\right)\right)}^{0.5}}{\sqrt{k}}} \]
      5. Applied rewrites99.5%

        \[\leadsto \color{blue}{\frac{{\left(\left(\pi + \pi\right) \cdot n\right)}^{\left(\mathsf{fma}\left(-0.5, k, 0.5\right)\right)}}{\sqrt{k}}} \]
      6. Taylor expanded in k around inf

        \[\leadsto \frac{{\left(\left(\pi + \pi\right) \cdot n\right)}^{\color{blue}{\left(\frac{-1}{2} \cdot k\right)}}}{\sqrt{k}} \]
      7. Step-by-step derivation
        1. lower-*.f6452.9

          \[\leadsto \frac{{\left(\left(\pi + \pi\right) \cdot n\right)}^{\left(-0.5 \cdot \color{blue}{k}\right)}}{\sqrt{k}} \]
      8. Applied rewrites52.9%

        \[\leadsto \frac{{\left(\left(\pi + \pi\right) \cdot n\right)}^{\color{blue}{\left(-0.5 \cdot k\right)}}}{\sqrt{k}} \]
    6. Recombined 2 regimes into one program.
    7. Add Preprocessing

    Alternative 5: 74.8% accurate, 1.7× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;n \leq 2 \cdot 10^{-20}:\\ \;\;\;\;\frac{n \cdot \sqrt{2 \cdot \frac{k \cdot \pi}{n}}}{k}\\ \mathbf{else}:\\ \;\;\;\;n \cdot \sqrt{2 \cdot \frac{\pi}{k \cdot n}}\\ \end{array} \end{array} \]
    (FPCore (k n)
     :precision binary64
     (if (<= n 2e-20)
       (/ (* n (sqrt (* 2.0 (/ (* k PI) n)))) k)
       (* n (sqrt (* 2.0 (/ PI (* k n)))))))
    double code(double k, double n) {
    	double tmp;
    	if (n <= 2e-20) {
    		tmp = (n * sqrt((2.0 * ((k * ((double) M_PI)) / n)))) / k;
    	} else {
    		tmp = n * sqrt((2.0 * (((double) M_PI) / (k * n))));
    	}
    	return tmp;
    }
    
    public static double code(double k, double n) {
    	double tmp;
    	if (n <= 2e-20) {
    		tmp = (n * Math.sqrt((2.0 * ((k * Math.PI) / n)))) / k;
    	} else {
    		tmp = n * Math.sqrt((2.0 * (Math.PI / (k * n))));
    	}
    	return tmp;
    }
    
    def code(k, n):
    	tmp = 0
    	if n <= 2e-20:
    		tmp = (n * math.sqrt((2.0 * ((k * math.pi) / n)))) / k
    	else:
    		tmp = n * math.sqrt((2.0 * (math.pi / (k * n))))
    	return tmp
    
    function code(k, n)
    	tmp = 0.0
    	if (n <= 2e-20)
    		tmp = Float64(Float64(n * sqrt(Float64(2.0 * Float64(Float64(k * pi) / n)))) / k);
    	else
    		tmp = Float64(n * sqrt(Float64(2.0 * Float64(pi / Float64(k * n)))));
    	end
    	return tmp
    end
    
    function tmp_2 = code(k, n)
    	tmp = 0.0;
    	if (n <= 2e-20)
    		tmp = (n * sqrt((2.0 * ((k * pi) / n)))) / k;
    	else
    		tmp = n * sqrt((2.0 * (pi / (k * n))));
    	end
    	tmp_2 = tmp;
    end
    
    code[k_, n_] := If[LessEqual[n, 2e-20], N[(N[(n * N[Sqrt[N[(2.0 * N[(N[(k * Pi), $MachinePrecision] / n), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / k), $MachinePrecision], N[(n * N[Sqrt[N[(2.0 * N[(Pi / N[(k * n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;n \leq 2 \cdot 10^{-20}:\\
    \;\;\;\;\frac{n \cdot \sqrt{2 \cdot \frac{k \cdot \pi}{n}}}{k}\\
    
    \mathbf{else}:\\
    \;\;\;\;n \cdot \sqrt{2 \cdot \frac{\pi}{k \cdot n}}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 2 regimes
    2. if n < 1.99999999999999989e-20

      1. Initial program 99.4%

        \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
      2. Taylor expanded in k around 0

        \[\leadsto \color{blue}{\frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}}} \]
      3. Step-by-step derivation
        1. lower-/.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\color{blue}{\sqrt{k}}} \]
        2. lower-pow.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{\color{blue}{k}}} \]
        3. lower-*.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
        4. lower-*.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
        5. lower-PI.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
        6. lower-sqrt.f6450.3

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{0.5}}{\sqrt{k}} \]
      4. Applied rewrites50.3%

        \[\leadsto \color{blue}{\frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{0.5}}{\sqrt{k}}} \]
      5. Step-by-step derivation
        1. lift-/.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{\frac{1}{2}}}{\color{blue}{\sqrt{k}}} \]
      6. Applied rewrites38.5%

        \[\leadsto \color{blue}{\sqrt{\frac{\left(\pi + \pi\right) \cdot n}{k}}} \]
      7. Taylor expanded in k around 0

        \[\leadsto \frac{\sqrt{2 \cdot \left(k \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}}{\color{blue}{k}} \]
      8. Step-by-step derivation
        1. lower-/.f64N/A

          \[\leadsto \frac{\sqrt{2 \cdot \left(k \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}}{k} \]
        2. lower-sqrt.f64N/A

          \[\leadsto \frac{\sqrt{2 \cdot \left(k \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}}{k} \]
        3. lower-*.f64N/A

          \[\leadsto \frac{\sqrt{2 \cdot \left(k \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}}{k} \]
        4. lower-*.f64N/A

          \[\leadsto \frac{\sqrt{2 \cdot \left(k \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}}{k} \]
        5. lower-*.f64N/A

          \[\leadsto \frac{\sqrt{2 \cdot \left(k \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}}{k} \]
        6. lower-PI.f6438.4

          \[\leadsto \frac{\sqrt{2 \cdot \left(k \cdot \left(n \cdot \pi\right)\right)}}{k} \]
      9. Applied rewrites38.4%

        \[\leadsto \frac{\sqrt{2 \cdot \left(k \cdot \left(n \cdot \pi\right)\right)}}{\color{blue}{k}} \]
      10. Taylor expanded in n around inf

        \[\leadsto \frac{n \cdot \sqrt{2 \cdot \frac{k \cdot \mathsf{PI}\left(\right)}{n}}}{k} \]
      11. Step-by-step derivation
        1. lower-*.f64N/A

          \[\leadsto \frac{n \cdot \sqrt{2 \cdot \frac{k \cdot \mathsf{PI}\left(\right)}{n}}}{k} \]
        2. lower-sqrt.f64N/A

          \[\leadsto \frac{n \cdot \sqrt{2 \cdot \frac{k \cdot \mathsf{PI}\left(\right)}{n}}}{k} \]
        3. lower-*.f64N/A

          \[\leadsto \frac{n \cdot \sqrt{2 \cdot \frac{k \cdot \mathsf{PI}\left(\right)}{n}}}{k} \]
        4. lower-/.f64N/A

          \[\leadsto \frac{n \cdot \sqrt{2 \cdot \frac{k \cdot \mathsf{PI}\left(\right)}{n}}}{k} \]
        5. lower-*.f64N/A

          \[\leadsto \frac{n \cdot \sqrt{2 \cdot \frac{k \cdot \mathsf{PI}\left(\right)}{n}}}{k} \]
        6. lower-PI.f6450.9

          \[\leadsto \frac{n \cdot \sqrt{2 \cdot \frac{k \cdot \pi}{n}}}{k} \]
      12. Applied rewrites50.9%

        \[\leadsto \frac{n \cdot \sqrt{2 \cdot \frac{k \cdot \pi}{n}}}{k} \]

      if 1.99999999999999989e-20 < n

      1. Initial program 99.4%

        \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
      2. Taylor expanded in k around 0

        \[\leadsto \color{blue}{\frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}}} \]
      3. Step-by-step derivation
        1. lower-/.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\color{blue}{\sqrt{k}}} \]
        2. lower-pow.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{\color{blue}{k}}} \]
        3. lower-*.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
        4. lower-*.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
        5. lower-PI.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
        6. lower-sqrt.f6450.3

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{0.5}}{\sqrt{k}} \]
      4. Applied rewrites50.3%

        \[\leadsto \color{blue}{\frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{0.5}}{\sqrt{k}}} \]
      5. Step-by-step derivation
        1. lift-/.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{\frac{1}{2}}}{\color{blue}{\sqrt{k}}} \]
      6. Applied rewrites38.5%

        \[\leadsto \color{blue}{\sqrt{\frac{\left(\pi + \pi\right) \cdot n}{k}}} \]
      7. Taylor expanded in n around inf

        \[\leadsto n \cdot \color{blue}{\sqrt{2 \cdot \frac{\mathsf{PI}\left(\right)}{k \cdot n}}} \]
      8. Step-by-step derivation
        1. lower-*.f64N/A

          \[\leadsto n \cdot \sqrt{2 \cdot \frac{\mathsf{PI}\left(\right)}{k \cdot n}} \]
        2. lower-sqrt.f64N/A

          \[\leadsto n \cdot \sqrt{2 \cdot \frac{\mathsf{PI}\left(\right)}{k \cdot n}} \]
        3. lower-*.f64N/A

          \[\leadsto n \cdot \sqrt{2 \cdot \frac{\mathsf{PI}\left(\right)}{k \cdot n}} \]
        4. lower-/.f64N/A

          \[\leadsto n \cdot \sqrt{2 \cdot \frac{\mathsf{PI}\left(\right)}{k \cdot n}} \]
        5. lower-PI.f64N/A

          \[\leadsto n \cdot \sqrt{2 \cdot \frac{\pi}{k \cdot n}} \]
        6. lower-*.f6450.3

          \[\leadsto n \cdot \sqrt{2 \cdot \frac{\pi}{k \cdot n}} \]
      9. Applied rewrites50.3%

        \[\leadsto n \cdot \color{blue}{\sqrt{2 \cdot \frac{\pi}{k \cdot n}}} \]
    3. Recombined 2 regimes into one program.
    4. Add Preprocessing

    Alternative 6: 62.8% accurate, 2.0× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;n \leq 2 \cdot 10^{-9}:\\ \;\;\;\;\sqrt{\left(n \cdot \pi\right) \cdot \frac{2}{k}}\\ \mathbf{else}:\\ \;\;\;\;n \cdot \sqrt{2 \cdot \frac{\pi}{k \cdot n}}\\ \end{array} \end{array} \]
    (FPCore (k n)
     :precision binary64
     (if (<= n 2e-9)
       (sqrt (* (* n PI) (/ 2.0 k)))
       (* n (sqrt (* 2.0 (/ PI (* k n)))))))
    double code(double k, double n) {
    	double tmp;
    	if (n <= 2e-9) {
    		tmp = sqrt(((n * ((double) M_PI)) * (2.0 / k)));
    	} else {
    		tmp = n * sqrt((2.0 * (((double) M_PI) / (k * n))));
    	}
    	return tmp;
    }
    
    public static double code(double k, double n) {
    	double tmp;
    	if (n <= 2e-9) {
    		tmp = Math.sqrt(((n * Math.PI) * (2.0 / k)));
    	} else {
    		tmp = n * Math.sqrt((2.0 * (Math.PI / (k * n))));
    	}
    	return tmp;
    }
    
    def code(k, n):
    	tmp = 0
    	if n <= 2e-9:
    		tmp = math.sqrt(((n * math.pi) * (2.0 / k)))
    	else:
    		tmp = n * math.sqrt((2.0 * (math.pi / (k * n))))
    	return tmp
    
    function code(k, n)
    	tmp = 0.0
    	if (n <= 2e-9)
    		tmp = sqrt(Float64(Float64(n * pi) * Float64(2.0 / k)));
    	else
    		tmp = Float64(n * sqrt(Float64(2.0 * Float64(pi / Float64(k * n)))));
    	end
    	return tmp
    end
    
    function tmp_2 = code(k, n)
    	tmp = 0.0;
    	if (n <= 2e-9)
    		tmp = sqrt(((n * pi) * (2.0 / k)));
    	else
    		tmp = n * sqrt((2.0 * (pi / (k * n))));
    	end
    	tmp_2 = tmp;
    end
    
    code[k_, n_] := If[LessEqual[n, 2e-9], N[Sqrt[N[(N[(n * Pi), $MachinePrecision] * N[(2.0 / k), $MachinePrecision]), $MachinePrecision]], $MachinePrecision], N[(n * N[Sqrt[N[(2.0 * N[(Pi / N[(k * n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;n \leq 2 \cdot 10^{-9}:\\
    \;\;\;\;\sqrt{\left(n \cdot \pi\right) \cdot \frac{2}{k}}\\
    
    \mathbf{else}:\\
    \;\;\;\;n \cdot \sqrt{2 \cdot \frac{\pi}{k \cdot n}}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 2 regimes
    2. if n < 2.00000000000000012e-9

      1. Initial program 99.4%

        \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
      2. Taylor expanded in k around 0

        \[\leadsto \color{blue}{\frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}}} \]
      3. Step-by-step derivation
        1. lower-/.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\color{blue}{\sqrt{k}}} \]
        2. lower-pow.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{\color{blue}{k}}} \]
        3. lower-*.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
        4. lower-*.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
        5. lower-PI.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
        6. lower-sqrt.f6450.3

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{0.5}}{\sqrt{k}} \]
      4. Applied rewrites50.3%

        \[\leadsto \color{blue}{\frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{0.5}}{\sqrt{k}}} \]
      5. Step-by-step derivation
        1. lift-/.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{\frac{1}{2}}}{\color{blue}{\sqrt{k}}} \]
      6. Applied rewrites38.5%

        \[\leadsto \color{blue}{\sqrt{\frac{\left(\pi + \pi\right) \cdot n}{k}}} \]
      7. Step-by-step derivation
        1. lift-/.f64N/A

          \[\leadsto \sqrt{\frac{\left(\pi + \pi\right) \cdot n}{k}} \]
        2. mult-flipN/A

          \[\leadsto \sqrt{\left(\left(\pi + \pi\right) \cdot n\right) \cdot \frac{1}{k}} \]
        3. lift-*.f64N/A

          \[\leadsto \sqrt{\left(\left(\pi + \pi\right) \cdot n\right) \cdot \frac{1}{k}} \]
        4. lift-+.f64N/A

          \[\leadsto \sqrt{\left(\left(\pi + \pi\right) \cdot n\right) \cdot \frac{1}{k}} \]
        5. count-2-revN/A

          \[\leadsto \sqrt{\left(\left(2 \cdot \pi\right) \cdot n\right) \cdot \frac{1}{k}} \]
        6. associate-*l*N/A

          \[\leadsto \sqrt{\left(2 \cdot \left(\pi \cdot n\right)\right) \cdot \frac{1}{k}} \]
        7. *-commutativeN/A

          \[\leadsto \sqrt{\left(2 \cdot \left(n \cdot \pi\right)\right) \cdot \frac{1}{k}} \]
        8. lift-PI.f64N/A

          \[\leadsto \sqrt{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right) \cdot \frac{1}{k}} \]
        9. *-commutativeN/A

          \[\leadsto \sqrt{\left(\left(n \cdot \mathsf{PI}\left(\right)\right) \cdot 2\right) \cdot \frac{1}{k}} \]
        10. associate-*l*N/A

          \[\leadsto \sqrt{\left(n \cdot \mathsf{PI}\left(\right)\right) \cdot \left(2 \cdot \frac{1}{k}\right)} \]
        11. lower-*.f64N/A

          \[\leadsto \sqrt{\left(n \cdot \mathsf{PI}\left(\right)\right) \cdot \left(2 \cdot \frac{1}{k}\right)} \]
        12. lift-PI.f64N/A

          \[\leadsto \sqrt{\left(n \cdot \pi\right) \cdot \left(2 \cdot \frac{1}{k}\right)} \]
        13. lower-*.f64N/A

          \[\leadsto \sqrt{\left(n \cdot \pi\right) \cdot \left(2 \cdot \frac{1}{k}\right)} \]
        14. mult-flip-revN/A

          \[\leadsto \sqrt{\left(n \cdot \pi\right) \cdot \frac{2}{k}} \]
        15. lower-/.f6438.5

          \[\leadsto \sqrt{\left(n \cdot \pi\right) \cdot \frac{2}{k}} \]
      8. Applied rewrites38.5%

        \[\leadsto \sqrt{\left(n \cdot \pi\right) \cdot \frac{2}{k}} \]

      if 2.00000000000000012e-9 < n

      1. Initial program 99.4%

        \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
      2. Taylor expanded in k around 0

        \[\leadsto \color{blue}{\frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}}} \]
      3. Step-by-step derivation
        1. lower-/.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\color{blue}{\sqrt{k}}} \]
        2. lower-pow.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{\color{blue}{k}}} \]
        3. lower-*.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
        4. lower-*.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
        5. lower-PI.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
        6. lower-sqrt.f6450.3

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{0.5}}{\sqrt{k}} \]
      4. Applied rewrites50.3%

        \[\leadsto \color{blue}{\frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{0.5}}{\sqrt{k}}} \]
      5. Step-by-step derivation
        1. lift-/.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{\frac{1}{2}}}{\color{blue}{\sqrt{k}}} \]
      6. Applied rewrites38.5%

        \[\leadsto \color{blue}{\sqrt{\frac{\left(\pi + \pi\right) \cdot n}{k}}} \]
      7. Taylor expanded in n around inf

        \[\leadsto n \cdot \color{blue}{\sqrt{2 \cdot \frac{\mathsf{PI}\left(\right)}{k \cdot n}}} \]
      8. Step-by-step derivation
        1. lower-*.f64N/A

          \[\leadsto n \cdot \sqrt{2 \cdot \frac{\mathsf{PI}\left(\right)}{k \cdot n}} \]
        2. lower-sqrt.f64N/A

          \[\leadsto n \cdot \sqrt{2 \cdot \frac{\mathsf{PI}\left(\right)}{k \cdot n}} \]
        3. lower-*.f64N/A

          \[\leadsto n \cdot \sqrt{2 \cdot \frac{\mathsf{PI}\left(\right)}{k \cdot n}} \]
        4. lower-/.f64N/A

          \[\leadsto n \cdot \sqrt{2 \cdot \frac{\mathsf{PI}\left(\right)}{k \cdot n}} \]
        5. lower-PI.f64N/A

          \[\leadsto n \cdot \sqrt{2 \cdot \frac{\pi}{k \cdot n}} \]
        6. lower-*.f6450.3

          \[\leadsto n \cdot \sqrt{2 \cdot \frac{\pi}{k \cdot n}} \]
      9. Applied rewrites50.3%

        \[\leadsto n \cdot \color{blue}{\sqrt{2 \cdot \frac{\pi}{k \cdot n}}} \]
    3. Recombined 2 regimes into one program.
    4. Add Preprocessing

    Alternative 7: 50.3% accurate, 2.7× speedup?

    \[\begin{array}{l} \\ \frac{\sqrt{\left(\pi + \pi\right) \cdot n}}{\sqrt{k}} \end{array} \]
    (FPCore (k n) :precision binary64 (/ (sqrt (* (+ PI PI) n)) (sqrt k)))
    double code(double k, double n) {
    	return sqrt(((((double) M_PI) + ((double) M_PI)) * n)) / sqrt(k);
    }
    
    public static double code(double k, double n) {
    	return Math.sqrt(((Math.PI + Math.PI) * n)) / Math.sqrt(k);
    }
    
    def code(k, n):
    	return math.sqrt(((math.pi + math.pi) * n)) / math.sqrt(k)
    
    function code(k, n)
    	return Float64(sqrt(Float64(Float64(pi + pi) * n)) / sqrt(k))
    end
    
    function tmp = code(k, n)
    	tmp = sqrt(((pi + pi) * n)) / sqrt(k);
    end
    
    code[k_, n_] := N[(N[Sqrt[N[(N[(Pi + Pi), $MachinePrecision] * n), $MachinePrecision]], $MachinePrecision] / N[Sqrt[k], $MachinePrecision]), $MachinePrecision]
    
    \begin{array}{l}
    
    \\
    \frac{\sqrt{\left(\pi + \pi\right) \cdot n}}{\sqrt{k}}
    \end{array}
    
    Derivation
    1. Initial program 99.4%

      \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
    2. Taylor expanded in k around 0

      \[\leadsto \color{blue}{\frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}}} \]
    3. Step-by-step derivation
      1. lower-/.f64N/A

        \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\color{blue}{\sqrt{k}}} \]
      2. lower-pow.f64N/A

        \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{\color{blue}{k}}} \]
      3. lower-*.f64N/A

        \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
      4. lower-*.f64N/A

        \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
      5. lower-PI.f64N/A

        \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
      6. lower-sqrt.f6450.3

        \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{0.5}}{\sqrt{k}} \]
    4. Applied rewrites50.3%

      \[\leadsto \color{blue}{\frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{0.5}}{\sqrt{k}}} \]
    5. Step-by-step derivation
      1. Applied rewrites50.3%

        \[\leadsto \frac{\sqrt{\left(\pi + \pi\right) \cdot n}}{\color{blue}{\sqrt{k}}} \]
      2. Add Preprocessing

      Alternative 8: 50.3% accurate, 2.7× speedup?

      \[\begin{array}{l} \\ \sqrt{n} \cdot \sqrt{\frac{\pi + \pi}{k}} \end{array} \]
      (FPCore (k n) :precision binary64 (* (sqrt n) (sqrt (/ (+ PI PI) k))))
      double code(double k, double n) {
      	return sqrt(n) * sqrt(((((double) M_PI) + ((double) M_PI)) / k));
      }
      
      public static double code(double k, double n) {
      	return Math.sqrt(n) * Math.sqrt(((Math.PI + Math.PI) / k));
      }
      
      def code(k, n):
      	return math.sqrt(n) * math.sqrt(((math.pi + math.pi) / k))
      
      function code(k, n)
      	return Float64(sqrt(n) * sqrt(Float64(Float64(pi + pi) / k)))
      end
      
      function tmp = code(k, n)
      	tmp = sqrt(n) * sqrt(((pi + pi) / k));
      end
      
      code[k_, n_] := N[(N[Sqrt[n], $MachinePrecision] * N[Sqrt[N[(N[(Pi + Pi), $MachinePrecision] / k), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
      
      \begin{array}{l}
      
      \\
      \sqrt{n} \cdot \sqrt{\frac{\pi + \pi}{k}}
      \end{array}
      
      Derivation
      1. Initial program 99.4%

        \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
      2. Taylor expanded in k around 0

        \[\leadsto \color{blue}{\frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}}} \]
      3. Step-by-step derivation
        1. lower-/.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\color{blue}{\sqrt{k}}} \]
        2. lower-pow.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{\color{blue}{k}}} \]
        3. lower-*.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
        4. lower-*.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
        5. lower-PI.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
        6. lower-sqrt.f6450.3

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{0.5}}{\sqrt{k}} \]
      4. Applied rewrites50.3%

        \[\leadsto \color{blue}{\frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{0.5}}{\sqrt{k}}} \]
      5. Step-by-step derivation
        1. lift-/.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{\frac{1}{2}}}{\color{blue}{\sqrt{k}}} \]
      6. Applied rewrites38.5%

        \[\leadsto \color{blue}{\sqrt{\frac{\left(\pi + \pi\right) \cdot n}{k}}} \]
      7. Step-by-step derivation
        1. lift-sqrt.f64N/A

          \[\leadsto \sqrt{\frac{\left(\pi + \pi\right) \cdot n}{k}} \]
        2. lift-/.f64N/A

          \[\leadsto \sqrt{\frac{\left(\pi + \pi\right) \cdot n}{k}} \]
        3. mult-flipN/A

          \[\leadsto \sqrt{\left(\left(\pi + \pi\right) \cdot n\right) \cdot \frac{1}{k}} \]
        4. lift-*.f64N/A

          \[\leadsto \sqrt{\left(\left(\pi + \pi\right) \cdot n\right) \cdot \frac{1}{k}} \]
        5. *-commutativeN/A

          \[\leadsto \sqrt{\left(n \cdot \left(\pi + \pi\right)\right) \cdot \frac{1}{k}} \]
        6. associate-*l*N/A

          \[\leadsto \sqrt{n \cdot \left(\left(\pi + \pi\right) \cdot \frac{1}{k}\right)} \]
        7. sqrt-prodN/A

          \[\leadsto \sqrt{n} \cdot \color{blue}{\sqrt{\left(\pi + \pi\right) \cdot \frac{1}{k}}} \]
        8. lower-unsound-*.f64N/A

          \[\leadsto \sqrt{n} \cdot \color{blue}{\sqrt{\left(\pi + \pi\right) \cdot \frac{1}{k}}} \]
        9. lower-unsound-sqrt.f64N/A

          \[\leadsto \sqrt{n} \cdot \sqrt{\color{blue}{\left(\pi + \pi\right) \cdot \frac{1}{k}}} \]
        10. lower-unsound-sqrt.f64N/A

          \[\leadsto \sqrt{n} \cdot \sqrt{\left(\pi + \pi\right) \cdot \frac{1}{k}} \]
        11. mult-flip-revN/A

          \[\leadsto \sqrt{n} \cdot \sqrt{\frac{\pi + \pi}{k}} \]
        12. lower-/.f6450.3

          \[\leadsto \sqrt{n} \cdot \sqrt{\frac{\pi + \pi}{k}} \]
      8. Applied rewrites50.3%

        \[\leadsto \sqrt{n} \cdot \color{blue}{\sqrt{\frac{\pi + \pi}{k}}} \]
      9. Add Preprocessing

      Alternative 9: 38.5% accurate, 3.1× speedup?

      \[\begin{array}{l} \\ \sqrt{\left(n \cdot \pi\right) \cdot \frac{2}{k}} \end{array} \]
      (FPCore (k n) :precision binary64 (sqrt (* (* n PI) (/ 2.0 k))))
      double code(double k, double n) {
      	return sqrt(((n * ((double) M_PI)) * (2.0 / k)));
      }
      
      public static double code(double k, double n) {
      	return Math.sqrt(((n * Math.PI) * (2.0 / k)));
      }
      
      def code(k, n):
      	return math.sqrt(((n * math.pi) * (2.0 / k)))
      
      function code(k, n)
      	return sqrt(Float64(Float64(n * pi) * Float64(2.0 / k)))
      end
      
      function tmp = code(k, n)
      	tmp = sqrt(((n * pi) * (2.0 / k)));
      end
      
      code[k_, n_] := N[Sqrt[N[(N[(n * Pi), $MachinePrecision] * N[(2.0 / k), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
      
      \begin{array}{l}
      
      \\
      \sqrt{\left(n \cdot \pi\right) \cdot \frac{2}{k}}
      \end{array}
      
      Derivation
      1. Initial program 99.4%

        \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
      2. Taylor expanded in k around 0

        \[\leadsto \color{blue}{\frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}}} \]
      3. Step-by-step derivation
        1. lower-/.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\color{blue}{\sqrt{k}}} \]
        2. lower-pow.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{\color{blue}{k}}} \]
        3. lower-*.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
        4. lower-*.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
        5. lower-PI.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
        6. lower-sqrt.f6450.3

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{0.5}}{\sqrt{k}} \]
      4. Applied rewrites50.3%

        \[\leadsto \color{blue}{\frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{0.5}}{\sqrt{k}}} \]
      5. Step-by-step derivation
        1. lift-/.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{\frac{1}{2}}}{\color{blue}{\sqrt{k}}} \]
      6. Applied rewrites38.5%

        \[\leadsto \color{blue}{\sqrt{\frac{\left(\pi + \pi\right) \cdot n}{k}}} \]
      7. Step-by-step derivation
        1. lift-/.f64N/A

          \[\leadsto \sqrt{\frac{\left(\pi + \pi\right) \cdot n}{k}} \]
        2. mult-flipN/A

          \[\leadsto \sqrt{\left(\left(\pi + \pi\right) \cdot n\right) \cdot \frac{1}{k}} \]
        3. lift-*.f64N/A

          \[\leadsto \sqrt{\left(\left(\pi + \pi\right) \cdot n\right) \cdot \frac{1}{k}} \]
        4. lift-+.f64N/A

          \[\leadsto \sqrt{\left(\left(\pi + \pi\right) \cdot n\right) \cdot \frac{1}{k}} \]
        5. count-2-revN/A

          \[\leadsto \sqrt{\left(\left(2 \cdot \pi\right) \cdot n\right) \cdot \frac{1}{k}} \]
        6. associate-*l*N/A

          \[\leadsto \sqrt{\left(2 \cdot \left(\pi \cdot n\right)\right) \cdot \frac{1}{k}} \]
        7. *-commutativeN/A

          \[\leadsto \sqrt{\left(2 \cdot \left(n \cdot \pi\right)\right) \cdot \frac{1}{k}} \]
        8. lift-PI.f64N/A

          \[\leadsto \sqrt{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right) \cdot \frac{1}{k}} \]
        9. *-commutativeN/A

          \[\leadsto \sqrt{\left(\left(n \cdot \mathsf{PI}\left(\right)\right) \cdot 2\right) \cdot \frac{1}{k}} \]
        10. associate-*l*N/A

          \[\leadsto \sqrt{\left(n \cdot \mathsf{PI}\left(\right)\right) \cdot \left(2 \cdot \frac{1}{k}\right)} \]
        11. lower-*.f64N/A

          \[\leadsto \sqrt{\left(n \cdot \mathsf{PI}\left(\right)\right) \cdot \left(2 \cdot \frac{1}{k}\right)} \]
        12. lift-PI.f64N/A

          \[\leadsto \sqrt{\left(n \cdot \pi\right) \cdot \left(2 \cdot \frac{1}{k}\right)} \]
        13. lower-*.f64N/A

          \[\leadsto \sqrt{\left(n \cdot \pi\right) \cdot \left(2 \cdot \frac{1}{k}\right)} \]
        14. mult-flip-revN/A

          \[\leadsto \sqrt{\left(n \cdot \pi\right) \cdot \frac{2}{k}} \]
        15. lower-/.f6438.5

          \[\leadsto \sqrt{\left(n \cdot \pi\right) \cdot \frac{2}{k}} \]
      8. Applied rewrites38.5%

        \[\leadsto \sqrt{\left(n \cdot \pi\right) \cdot \frac{2}{k}} \]
      9. Add Preprocessing

      Alternative 10: 38.5% accurate, 3.1× speedup?

      \[\begin{array}{l} \\ \sqrt{\frac{\left(\pi + \pi\right) \cdot n}{k}} \end{array} \]
      (FPCore (k n) :precision binary64 (sqrt (/ (* (+ PI PI) n) k)))
      double code(double k, double n) {
      	return sqrt((((((double) M_PI) + ((double) M_PI)) * n) / k));
      }
      
      public static double code(double k, double n) {
      	return Math.sqrt((((Math.PI + Math.PI) * n) / k));
      }
      
      def code(k, n):
      	return math.sqrt((((math.pi + math.pi) * n) / k))
      
      function code(k, n)
      	return sqrt(Float64(Float64(Float64(pi + pi) * n) / k))
      end
      
      function tmp = code(k, n)
      	tmp = sqrt((((pi + pi) * n) / k));
      end
      
      code[k_, n_] := N[Sqrt[N[(N[(N[(Pi + Pi), $MachinePrecision] * n), $MachinePrecision] / k), $MachinePrecision]], $MachinePrecision]
      
      \begin{array}{l}
      
      \\
      \sqrt{\frac{\left(\pi + \pi\right) \cdot n}{k}}
      \end{array}
      
      Derivation
      1. Initial program 99.4%

        \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
      2. Taylor expanded in k around 0

        \[\leadsto \color{blue}{\frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}}} \]
      3. Step-by-step derivation
        1. lower-/.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\color{blue}{\sqrt{k}}} \]
        2. lower-pow.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{\color{blue}{k}}} \]
        3. lower-*.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
        4. lower-*.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
        5. lower-PI.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
        6. lower-sqrt.f6450.3

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{0.5}}{\sqrt{k}} \]
      4. Applied rewrites50.3%

        \[\leadsto \color{blue}{\frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{0.5}}{\sqrt{k}}} \]
      5. Step-by-step derivation
        1. lift-/.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{\frac{1}{2}}}{\color{blue}{\sqrt{k}}} \]
      6. Applied rewrites38.5%

        \[\leadsto \color{blue}{\sqrt{\frac{\left(\pi + \pi\right) \cdot n}{k}}} \]
      7. Add Preprocessing

      Alternative 11: 38.5% accurate, 3.1× speedup?

      \[\begin{array}{l} \\ \sqrt{\left(n + n\right) \cdot \frac{\pi}{k}} \end{array} \]
      (FPCore (k n) :precision binary64 (sqrt (* (+ n n) (/ PI k))))
      double code(double k, double n) {
      	return sqrt(((n + n) * (((double) M_PI) / k)));
      }
      
      public static double code(double k, double n) {
      	return Math.sqrt(((n + n) * (Math.PI / k)));
      }
      
      def code(k, n):
      	return math.sqrt(((n + n) * (math.pi / k)))
      
      function code(k, n)
      	return sqrt(Float64(Float64(n + n) * Float64(pi / k)))
      end
      
      function tmp = code(k, n)
      	tmp = sqrt(((n + n) * (pi / k)));
      end
      
      code[k_, n_] := N[Sqrt[N[(N[(n + n), $MachinePrecision] * N[(Pi / k), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
      
      \begin{array}{l}
      
      \\
      \sqrt{\left(n + n\right) \cdot \frac{\pi}{k}}
      \end{array}
      
      Derivation
      1. Initial program 99.4%

        \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
      2. Taylor expanded in k around 0

        \[\leadsto \color{blue}{\frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}}} \]
      3. Step-by-step derivation
        1. lower-/.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\color{blue}{\sqrt{k}}} \]
        2. lower-pow.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{\color{blue}{k}}} \]
        3. lower-*.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
        4. lower-*.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \mathsf{PI}\left(\right)\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
        5. lower-PI.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{\frac{1}{2}}}{\sqrt{k}} \]
        6. lower-sqrt.f6450.3

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{0.5}}{\sqrt{k}} \]
      4. Applied rewrites50.3%

        \[\leadsto \color{blue}{\frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{0.5}}{\sqrt{k}}} \]
      5. Step-by-step derivation
        1. lift-/.f64N/A

          \[\leadsto \frac{{\left(2 \cdot \left(n \cdot \pi\right)\right)}^{\frac{1}{2}}}{\color{blue}{\sqrt{k}}} \]
      6. Applied rewrites38.5%

        \[\leadsto \color{blue}{\sqrt{\frac{\left(\pi + \pi\right) \cdot n}{k}}} \]
      7. Step-by-step derivation
        1. lift-/.f64N/A

          \[\leadsto \sqrt{\frac{\left(\pi + \pi\right) \cdot n}{k}} \]
        2. lift-*.f64N/A

          \[\leadsto \sqrt{\frac{\left(\pi + \pi\right) \cdot n}{k}} \]
        3. lift-+.f64N/A

          \[\leadsto \sqrt{\frac{\left(\pi + \pi\right) \cdot n}{k}} \]
        4. count-2-revN/A

          \[\leadsto \sqrt{\frac{\left(2 \cdot \pi\right) \cdot n}{k}} \]
        5. associate-*l*N/A

          \[\leadsto \sqrt{\frac{2 \cdot \left(\pi \cdot n\right)}{k}} \]
        6. *-commutativeN/A

          \[\leadsto \sqrt{\frac{2 \cdot \left(n \cdot \pi\right)}{k}} \]
        7. associate-*r*N/A

          \[\leadsto \sqrt{\frac{\left(2 \cdot n\right) \cdot \pi}{k}} \]
        8. associate-/l*N/A

          \[\leadsto \sqrt{\left(2 \cdot n\right) \cdot \frac{\pi}{k}} \]
        9. lower-*.f64N/A

          \[\leadsto \sqrt{\left(2 \cdot n\right) \cdot \frac{\pi}{k}} \]
        10. count-2-revN/A

          \[\leadsto \sqrt{\left(n + n\right) \cdot \frac{\pi}{k}} \]
        11. lower-+.f64N/A

          \[\leadsto \sqrt{\left(n + n\right) \cdot \frac{\pi}{k}} \]
        12. lower-/.f6438.5

          \[\leadsto \sqrt{\left(n + n\right) \cdot \frac{\pi}{k}} \]
      8. Applied rewrites38.5%

        \[\leadsto \sqrt{\left(n + n\right) \cdot \frac{\pi}{k}} \]
      9. Add Preprocessing

      Reproduce

      ?
      herbie shell --seed 2025157 
      (FPCore (k n)
        :name "Migdal et al, Equation (51)"
        :precision binary64
        (* (/ 1.0 (sqrt k)) (pow (* (* 2.0 PI) n) (/ (- 1.0 k) 2.0))))