ABCF->ab-angle b

Percentage Accurate: 19.1% → 45.3%
Time: 8.4s
Alternatives: 10
Speedup: 6.5×

Specification

?
\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (- (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
module fmin_fmax_functions
    implicit none
    private
    public fmax
    public fmin

    interface fmax
        module procedure fmax88
        module procedure fmax44
        module procedure fmax84
        module procedure fmax48
    end interface
    interface fmin
        module procedure fmin88
        module procedure fmin44
        module procedure fmin84
        module procedure fmin48
    end interface
contains
    real(8) function fmax88(x, y) result (res)
        real(8), intent (in) :: x
        real(8), intent (in) :: y
        res = merge(y, merge(x, max(x, y), y /= y), x /= x)
    end function
    real(4) function fmax44(x, y) result (res)
        real(4), intent (in) :: x
        real(4), intent (in) :: y
        res = merge(y, merge(x, max(x, y), y /= y), x /= x)
    end function
    real(8) function fmax84(x, y) result(res)
        real(8), intent (in) :: x
        real(4), intent (in) :: y
        res = merge(dble(y), merge(x, max(x, dble(y)), y /= y), x /= x)
    end function
    real(8) function fmax48(x, y) result(res)
        real(4), intent (in) :: x
        real(8), intent (in) :: y
        res = merge(y, merge(dble(x), max(dble(x), y), y /= y), x /= x)
    end function
    real(8) function fmin88(x, y) result (res)
        real(8), intent (in) :: x
        real(8), intent (in) :: y
        res = merge(y, merge(x, min(x, y), y /= y), x /= x)
    end function
    real(4) function fmin44(x, y) result (res)
        real(4), intent (in) :: x
        real(4), intent (in) :: y
        res = merge(y, merge(x, min(x, y), y /= y), x /= x)
    end function
    real(8) function fmin84(x, y) result(res)
        real(8), intent (in) :: x
        real(4), intent (in) :: y
        res = merge(dble(y), merge(x, min(x, dble(y)), y /= y), x /= x)
    end function
    real(8) function fmin48(x, y) result(res)
        real(4), intent (in) :: x
        real(8), intent (in) :: y
        res = merge(y, merge(dble(x), min(dble(x), y), y /= y), x /= x)
    end function
end module

real(8) function code(a, b, c, f)
use fmin_fmax_functions
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) - sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 10 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 19.1% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (- (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
module fmin_fmax_functions
    implicit none
    private
    public fmax
    public fmin

    interface fmax
        module procedure fmax88
        module procedure fmax44
        module procedure fmax84
        module procedure fmax48
    end interface
    interface fmin
        module procedure fmin88
        module procedure fmin44
        module procedure fmin84
        module procedure fmin48
    end interface
contains
    real(8) function fmax88(x, y) result (res)
        real(8), intent (in) :: x
        real(8), intent (in) :: y
        res = merge(y, merge(x, max(x, y), y /= y), x /= x)
    end function
    real(4) function fmax44(x, y) result (res)
        real(4), intent (in) :: x
        real(4), intent (in) :: y
        res = merge(y, merge(x, max(x, y), y /= y), x /= x)
    end function
    real(8) function fmax84(x, y) result(res)
        real(8), intent (in) :: x
        real(4), intent (in) :: y
        res = merge(dble(y), merge(x, max(x, dble(y)), y /= y), x /= x)
    end function
    real(8) function fmax48(x, y) result(res)
        real(4), intent (in) :: x
        real(8), intent (in) :: y
        res = merge(y, merge(dble(x), max(dble(x), y), y /= y), x /= x)
    end function
    real(8) function fmin88(x, y) result (res)
        real(8), intent (in) :: x
        real(8), intent (in) :: y
        res = merge(y, merge(x, min(x, y), y /= y), x /= x)
    end function
    real(4) function fmin44(x, y) result (res)
        real(4), intent (in) :: x
        real(4), intent (in) :: y
        res = merge(y, merge(x, min(x, y), y /= y), x /= x)
    end function
    real(8) function fmin84(x, y) result(res)
        real(8), intent (in) :: x
        real(4), intent (in) :: y
        res = merge(dble(y), merge(x, min(x, dble(y)), y /= y), x /= x)
    end function
    real(8) function fmin48(x, y) result(res)
        real(4), intent (in) :: x
        real(8), intent (in) :: y
        res = merge(y, merge(dble(x), min(dble(x), y), y /= y), x /= x)
    end function
end module

real(8) function code(a, b, c, f)
use fmin_fmax_functions
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) - sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Alternative 1: 45.3% accurate, 1.2× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, A \cdot C, {B\_m}^{2}\right)\\ \mathbf{if}\;B\_m \leq 246000000:\\ \;\;\;\;\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(2 \cdot A\right)}}{t\_0}\\ \mathbf{elif}\;B\_m \leq 1.3 \cdot 10^{+118}:\\ \;\;\;\;\frac{-\left(B\_m \cdot \sqrt{2}\right) \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B\_m}^{2}}\right)}}{{B\_m}^{2} - \left(4 \cdot A\right) \cdot C}\\ \mathbf{else}:\\ \;\;\;\;-1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B\_m}} \cdot \sqrt{2}\right)\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (let* ((t_0 (fma -4.0 (* A C) (pow B_m 2.0))))
   (if (<= B_m 246000000.0)
     (/ (- (sqrt (* (* 2.0 (* t_0 F)) (* 2.0 A)))) t_0)
     (if (<= B_m 1.3e+118)
       (/
        (-
         (*
          (* B_m (sqrt 2.0))
          (sqrt (* F (- A (sqrt (+ (pow A 2.0) (pow B_m 2.0))))))))
        (- (pow B_m 2.0) (* (* 4.0 A) C)))
       (* -1.0 (* (sqrt (* -1.0 (/ F B_m))) (sqrt 2.0)))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double t_0 = fma(-4.0, (A * C), pow(B_m, 2.0));
	double tmp;
	if (B_m <= 246000000.0) {
		tmp = -sqrt(((2.0 * (t_0 * F)) * (2.0 * A))) / t_0;
	} else if (B_m <= 1.3e+118) {
		tmp = -((B_m * sqrt(2.0)) * sqrt((F * (A - sqrt((pow(A, 2.0) + pow(B_m, 2.0))))))) / (pow(B_m, 2.0) - ((4.0 * A) * C));
	} else {
		tmp = -1.0 * (sqrt((-1.0 * (F / B_m))) * sqrt(2.0));
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	t_0 = fma(-4.0, Float64(A * C), (B_m ^ 2.0))
	tmp = 0.0
	if (B_m <= 246000000.0)
		tmp = Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(2.0 * A)))) / t_0);
	elseif (B_m <= 1.3e+118)
		tmp = Float64(Float64(-Float64(Float64(B_m * sqrt(2.0)) * sqrt(Float64(F * Float64(A - sqrt(Float64((A ^ 2.0) + (B_m ^ 2.0)))))))) / Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C)));
	else
		tmp = Float64(-1.0 * Float64(sqrt(Float64(-1.0 * Float64(F / B_m))) * sqrt(2.0)));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(A * C), $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]}, If[LessEqual[B$95$m, 246000000.0], N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(2.0 * A), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision], If[LessEqual[B$95$m, 1.3e+118], N[((-N[(N[(B$95$m * N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision] * N[Sqrt[N[(F * N[(A - N[Sqrt[N[(N[Power[A, 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]) / N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(-1.0 * N[(N[Sqrt[N[(-1.0 * N[(F / B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
t_0 := \mathsf{fma}\left(-4, A \cdot C, {B\_m}^{2}\right)\\
\mathbf{if}\;B\_m \leq 246000000:\\
\;\;\;\;\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(2 \cdot A\right)}}{t\_0}\\

\mathbf{elif}\;B\_m \leq 1.3 \cdot 10^{+118}:\\
\;\;\;\;\frac{-\left(B\_m \cdot \sqrt{2}\right) \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B\_m}^{2}}\right)}}{{B\_m}^{2} - \left(4 \cdot A\right) \cdot C}\\

\mathbf{else}:\\
\;\;\;\;-1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B\_m}} \cdot \sqrt{2}\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if B < 2.46e8

    1. Initial program 23.7%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Taylor expanded in C around inf

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    3. Step-by-step derivation
      1. lower--.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - \color{blue}{-1 \cdot A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lower-+.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - \color{blue}{-1} \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. lower-/.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. lift-pow.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. lower-*.f6443.9

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot \color{blue}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Applied rewrites43.9%

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    5. Taylor expanded in A around 0

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\color{blue}{\left(-4 \cdot \left(A \cdot C\right) + {B}^{2}\right)} \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    6. Step-by-step derivation
      1. lower-fma.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, \color{blue}{A \cdot C}, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot \color{blue}{C}, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. lift-pow.f6443.9

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    7. Applied rewrites43.9%

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\color{blue}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    8. Taylor expanded in A around 0

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\color{blue}{-4 \cdot \left(A \cdot C\right) + {B}^{2}}} \]
    9. Step-by-step derivation
      1. lower-fma.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\mathsf{fma}\left(-4, \color{blue}{A \cdot C}, {B}^{2}\right)} \]
      2. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot \color{blue}{C}, {B}^{2}\right)} \]
      3. lift-pow.f6443.9

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
    10. Applied rewrites43.9%

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\color{blue}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)}} \]
    11. Taylor expanded in A around -inf

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot A\right)}}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
    12. Step-by-step derivation
      1. lower-*.f6444.5

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(2 \cdot \color{blue}{A}\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
    13. Applied rewrites44.5%

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot A\right)}}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]

    if 2.46e8 < B < 1.30000000000000008e118

    1. Initial program 33.2%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Taylor expanded in C around 0

      \[\leadsto \frac{-\color{blue}{\left(B \cdot \sqrt{2}\right) \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    3. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto \frac{-\left(B \cdot \sqrt{2}\right) \cdot \color{blue}{\sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lower-*.f64N/A

        \[\leadsto \frac{-\left(B \cdot \sqrt{2}\right) \cdot \sqrt{\color{blue}{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. lower-sqrt.f64N/A

        \[\leadsto \frac{-\left(B \cdot \sqrt{2}\right) \cdot \sqrt{F \cdot \color{blue}{\left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. lower-sqrt.f64N/A

        \[\leadsto \frac{-\left(B \cdot \sqrt{2}\right) \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. lower-*.f64N/A

        \[\leadsto \frac{-\left(B \cdot \sqrt{2}\right) \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. lower--.f64N/A

        \[\leadsto \frac{-\left(B \cdot \sqrt{2}\right) \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      7. lower-sqrt.f64N/A

        \[\leadsto \frac{-\left(B \cdot \sqrt{2}\right) \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      8. lower-+.f64N/A

        \[\leadsto \frac{-\left(B \cdot \sqrt{2}\right) \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      9. lower-pow.f64N/A

        \[\leadsto \frac{-\left(B \cdot \sqrt{2}\right) \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      10. lift-pow.f6441.2

        \[\leadsto \frac{-\left(B \cdot \sqrt{2}\right) \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Applied rewrites41.2%

      \[\leadsto \frac{-\color{blue}{\left(B \cdot \sqrt{2}\right) \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

    if 1.30000000000000008e118 < B

    1. Initial program 3.7%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Taylor expanded in F around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    3. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \color{blue}{\left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
      2. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \color{blue}{\sqrt{2}}\right) \]
    4. Applied rewrites6.7%

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    5. Taylor expanded in B around inf

      \[\leadsto -1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B}} \cdot \sqrt{2}\right) \]
    6. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B}} \cdot \sqrt{2}\right) \]
      2. lower-/.f6449.0

        \[\leadsto -1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B}} \cdot \sqrt{2}\right) \]
    7. Applied rewrites49.0%

      \[\leadsto -1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B}} \cdot \sqrt{2}\right) \]
  3. Recombined 3 regimes into one program.
  4. Add Preprocessing

Alternative 2: 45.3% accurate, 1.1× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, A \cdot C, {B\_m}^{2}\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 2 \cdot 10^{+16}:\\ \;\;\;\;\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(2 \cdot A\right)}}{t\_0}\\ \mathbf{elif}\;{B\_m}^{2} \leq 10^{+235}:\\ \;\;\;\;-1 \cdot \left(\frac{\sqrt{2}}{B\_m} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B\_m}^{2}}\right)}\right)\\ \mathbf{else}:\\ \;\;\;\;-1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B\_m}} \cdot \sqrt{2}\right)\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (let* ((t_0 (fma -4.0 (* A C) (pow B_m 2.0))))
   (if (<= (pow B_m 2.0) 2e+16)
     (/ (- (sqrt (* (* 2.0 (* t_0 F)) (* 2.0 A)))) t_0)
     (if (<= (pow B_m 2.0) 1e+235)
       (*
        -1.0
        (*
         (/ (sqrt 2.0) B_m)
         (sqrt (* F (- A (sqrt (+ (pow A 2.0) (pow B_m 2.0))))))))
       (* -1.0 (* (sqrt (* -1.0 (/ F B_m))) (sqrt 2.0)))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double t_0 = fma(-4.0, (A * C), pow(B_m, 2.0));
	double tmp;
	if (pow(B_m, 2.0) <= 2e+16) {
		tmp = -sqrt(((2.0 * (t_0 * F)) * (2.0 * A))) / t_0;
	} else if (pow(B_m, 2.0) <= 1e+235) {
		tmp = -1.0 * ((sqrt(2.0) / B_m) * sqrt((F * (A - sqrt((pow(A, 2.0) + pow(B_m, 2.0)))))));
	} else {
		tmp = -1.0 * (sqrt((-1.0 * (F / B_m))) * sqrt(2.0));
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	t_0 = fma(-4.0, Float64(A * C), (B_m ^ 2.0))
	tmp = 0.0
	if ((B_m ^ 2.0) <= 2e+16)
		tmp = Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(2.0 * A)))) / t_0);
	elseif ((B_m ^ 2.0) <= 1e+235)
		tmp = Float64(-1.0 * Float64(Float64(sqrt(2.0) / B_m) * sqrt(Float64(F * Float64(A - sqrt(Float64((A ^ 2.0) + (B_m ^ 2.0))))))));
	else
		tmp = Float64(-1.0 * Float64(sqrt(Float64(-1.0 * Float64(F / B_m))) * sqrt(2.0)));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(A * C), $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 2e+16], N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(2.0 * A), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision], If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e+235], N[(-1.0 * N[(N[(N[Sqrt[2.0], $MachinePrecision] / B$95$m), $MachinePrecision] * N[Sqrt[N[(F * N[(A - N[Sqrt[N[(N[Power[A, 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(-1.0 * N[(N[Sqrt[N[(-1.0 * N[(F / B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
t_0 := \mathsf{fma}\left(-4, A \cdot C, {B\_m}^{2}\right)\\
\mathbf{if}\;{B\_m}^{2} \leq 2 \cdot 10^{+16}:\\
\;\;\;\;\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(2 \cdot A\right)}}{t\_0}\\

\mathbf{elif}\;{B\_m}^{2} \leq 10^{+235}:\\
\;\;\;\;-1 \cdot \left(\frac{\sqrt{2}}{B\_m} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B\_m}^{2}}\right)}\right)\\

\mathbf{else}:\\
\;\;\;\;-1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B\_m}} \cdot \sqrt{2}\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (pow.f64 B #s(literal 2 binary64)) < 2e16

    1. Initial program 23.7%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Taylor expanded in C around inf

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    3. Step-by-step derivation
      1. lower--.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - \color{blue}{-1 \cdot A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lower-+.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - \color{blue}{-1} \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. lower-/.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. lift-pow.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. lower-*.f6443.9

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot \color{blue}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Applied rewrites43.9%

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    5. Taylor expanded in A around 0

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\color{blue}{\left(-4 \cdot \left(A \cdot C\right) + {B}^{2}\right)} \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    6. Step-by-step derivation
      1. lower-fma.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, \color{blue}{A \cdot C}, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot \color{blue}{C}, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. lift-pow.f6443.9

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    7. Applied rewrites43.9%

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\color{blue}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    8. Taylor expanded in A around 0

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\color{blue}{-4 \cdot \left(A \cdot C\right) + {B}^{2}}} \]
    9. Step-by-step derivation
      1. lower-fma.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\mathsf{fma}\left(-4, \color{blue}{A \cdot C}, {B}^{2}\right)} \]
      2. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot \color{blue}{C}, {B}^{2}\right)} \]
      3. lift-pow.f6443.9

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
    10. Applied rewrites43.9%

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\color{blue}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)}} \]
    11. Taylor expanded in A around -inf

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot A\right)}}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
    12. Step-by-step derivation
      1. lower-*.f6444.5

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(2 \cdot \color{blue}{A}\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
    13. Applied rewrites44.5%

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot A\right)}}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]

    if 2e16 < (pow.f64 B #s(literal 2 binary64)) < 1.0000000000000001e235

    1. Initial program 33.1%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Taylor expanded in C around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    3. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \color{blue}{\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
      2. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \color{blue}{\sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      3. lower-/.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      4. lower-sqrt.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F} \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      5. lower-sqrt.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      6. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      7. lower--.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      8. lower-sqrt.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      9. lower-+.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      10. lower-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      11. lift-pow.f6441.2

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
    4. Applied rewrites41.2%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]

    if 1.0000000000000001e235 < (pow.f64 B #s(literal 2 binary64))

    1. Initial program 3.8%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Taylor expanded in F around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    3. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \color{blue}{\left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
      2. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \color{blue}{\sqrt{2}}\right) \]
    4. Applied rewrites6.7%

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    5. Taylor expanded in B around inf

      \[\leadsto -1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B}} \cdot \sqrt{2}\right) \]
    6. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B}} \cdot \sqrt{2}\right) \]
      2. lower-/.f6448.9

        \[\leadsto -1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B}} \cdot \sqrt{2}\right) \]
    7. Applied rewrites48.9%

      \[\leadsto -1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B}} \cdot \sqrt{2}\right) \]
  3. Recombined 3 regimes into one program.
  4. Add Preprocessing

Alternative 3: 44.0% accurate, 1.2× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, A \cdot C, {B\_m}^{2}\right)\\ \mathbf{if}\;B\_m \leq 3.2 \cdot 10^{+33}:\\ \;\;\;\;\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \mathsf{fma}\left(-0.5, \frac{{B\_m}^{2}}{C}, 2 \cdot A\right)}}{t\_0}\\ \mathbf{else}:\\ \;\;\;\;-1 \cdot \left(\left(\frac{1}{B\_m} \cdot \sqrt{F \cdot \left(A - B\_m\right)}\right) \cdot \sqrt{2}\right)\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (let* ((t_0 (fma -4.0 (* A C) (pow B_m 2.0))))
   (if (<= B_m 3.2e+33)
     (/
      (- (sqrt (* (* 2.0 (* t_0 F)) (fma -0.5 (/ (pow B_m 2.0) C) (* 2.0 A)))))
      t_0)
     (* -1.0 (* (* (/ 1.0 B_m) (sqrt (* F (- A B_m)))) (sqrt 2.0))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double t_0 = fma(-4.0, (A * C), pow(B_m, 2.0));
	double tmp;
	if (B_m <= 3.2e+33) {
		tmp = -sqrt(((2.0 * (t_0 * F)) * fma(-0.5, (pow(B_m, 2.0) / C), (2.0 * A)))) / t_0;
	} else {
		tmp = -1.0 * (((1.0 / B_m) * sqrt((F * (A - B_m)))) * sqrt(2.0));
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	t_0 = fma(-4.0, Float64(A * C), (B_m ^ 2.0))
	tmp = 0.0
	if (B_m <= 3.2e+33)
		tmp = Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * fma(-0.5, Float64((B_m ^ 2.0) / C), Float64(2.0 * A))))) / t_0);
	else
		tmp = Float64(-1.0 * Float64(Float64(Float64(1.0 / B_m) * sqrt(Float64(F * Float64(A - B_m)))) * sqrt(2.0)));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(A * C), $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]}, If[LessEqual[B$95$m, 3.2e+33], N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(-0.5 * N[(N[Power[B$95$m, 2.0], $MachinePrecision] / C), $MachinePrecision] + N[(2.0 * A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision], N[(-1.0 * N[(N[(N[(1.0 / B$95$m), $MachinePrecision] * N[Sqrt[N[(F * N[(A - B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
t_0 := \mathsf{fma}\left(-4, A \cdot C, {B\_m}^{2}\right)\\
\mathbf{if}\;B\_m \leq 3.2 \cdot 10^{+33}:\\
\;\;\;\;\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \mathsf{fma}\left(-0.5, \frac{{B\_m}^{2}}{C}, 2 \cdot A\right)}}{t\_0}\\

\mathbf{else}:\\
\;\;\;\;-1 \cdot \left(\left(\frac{1}{B\_m} \cdot \sqrt{F \cdot \left(A - B\_m\right)}\right) \cdot \sqrt{2}\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if B < 3.20000000000000017e33

    1. Initial program 24.8%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Taylor expanded in C around inf

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    3. Step-by-step derivation
      1. lower--.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - \color{blue}{-1 \cdot A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lower-+.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - \color{blue}{-1} \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. lower-/.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. lift-pow.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. lower-*.f6443.1

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot \color{blue}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Applied rewrites43.1%

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    5. Taylor expanded in A around 0

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\color{blue}{\left(-4 \cdot \left(A \cdot C\right) + {B}^{2}\right)} \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    6. Step-by-step derivation
      1. lower-fma.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, \color{blue}{A \cdot C}, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot \color{blue}{C}, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. lift-pow.f6443.0

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    7. Applied rewrites43.0%

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\color{blue}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    8. Taylor expanded in A around 0

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\color{blue}{-4 \cdot \left(A \cdot C\right) + {B}^{2}}} \]
    9. Step-by-step derivation
      1. lower-fma.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\mathsf{fma}\left(-4, \color{blue}{A \cdot C}, {B}^{2}\right)} \]
      2. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot \color{blue}{C}, {B}^{2}\right)} \]
      3. lift-pow.f6443.0

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
    10. Applied rewrites43.0%

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\color{blue}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)}} \]
    11. Taylor expanded in A around 0

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\frac{-1}{2} \cdot \frac{{B}^{2}}{C} + \color{blue}{2 \cdot A}\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
    12. Step-by-step derivation
      1. lower-fma.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{\color{blue}{C}}, 2 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
      2. lift-pow.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{C}, 2 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
      3. lift-/.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{C}, 2 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
      4. lower-*.f6443.1

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(-0.5, \frac{{B}^{2}}{C}, 2 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
    13. Applied rewrites43.1%

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(-0.5, \color{blue}{\frac{{B}^{2}}{C}}, 2 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]

    if 3.20000000000000017e33 < B

    1. Initial program 12.1%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Taylor expanded in F around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    3. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \color{blue}{\left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
      2. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \color{blue}{\sqrt{2}}\right) \]
    4. Applied rewrites15.8%

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    5. Taylor expanded in C around 0

      \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{\color{blue}{2}}\right) \]
    6. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
      2. lower-/.f64N/A

        \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
      3. lower-sqrt.f64N/A

        \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
      4. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
      5. lower--.f64N/A

        \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
      6. lower-sqrt.f64N/A

        \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
      7. lower-+.f64N/A

        \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
      8. lower-pow.f64N/A

        \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
      9. lift-pow.f6420.1

        \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
    7. Applied rewrites20.1%

      \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{\color{blue}{2}}\right) \]
    8. Taylor expanded in A around 0

      \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - B\right)}\right) \cdot \sqrt{2}\right) \]
    9. Step-by-step derivation
      1. Applied rewrites45.1%

        \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - B\right)}\right) \cdot \sqrt{2}\right) \]
    10. Recombined 2 regimes into one program.
    11. Add Preprocessing

    Alternative 4: 43.9% accurate, 1.1× speedup?

    \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := -4 \cdot \left(A \cdot C\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 10^{-10}:\\ \;\;\;\;\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \mathsf{fma}\left(-0.5, \frac{{B\_m}^{2}}{C}, 2 \cdot A\right)}}{t\_0}\\ \mathbf{elif}\;{B\_m}^{2} \leq 10^{+235}:\\ \;\;\;\;-1 \cdot \left(\frac{\sqrt{2}}{B\_m} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B\_m}^{2}}\right)}\right)\\ \mathbf{else}:\\ \;\;\;\;-1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B\_m}} \cdot \sqrt{2}\right)\\ \end{array} \end{array} \]
    B_m = (fabs.f64 B)
    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
    (FPCore (A B_m C F)
     :precision binary64
     (let* ((t_0 (* -4.0 (* A C))))
       (if (<= (pow B_m 2.0) 1e-10)
         (/
          (- (sqrt (* (* 2.0 (* t_0 F)) (fma -0.5 (/ (pow B_m 2.0) C) (* 2.0 A)))))
          t_0)
         (if (<= (pow B_m 2.0) 1e+235)
           (*
            -1.0
            (*
             (/ (sqrt 2.0) B_m)
             (sqrt (* F (- A (sqrt (+ (pow A 2.0) (pow B_m 2.0))))))))
           (* -1.0 (* (sqrt (* -1.0 (/ F B_m))) (sqrt 2.0)))))))
    B_m = fabs(B);
    assert(A < B_m && B_m < C && C < F);
    double code(double A, double B_m, double C, double F) {
    	double t_0 = -4.0 * (A * C);
    	double tmp;
    	if (pow(B_m, 2.0) <= 1e-10) {
    		tmp = -sqrt(((2.0 * (t_0 * F)) * fma(-0.5, (pow(B_m, 2.0) / C), (2.0 * A)))) / t_0;
    	} else if (pow(B_m, 2.0) <= 1e+235) {
    		tmp = -1.0 * ((sqrt(2.0) / B_m) * sqrt((F * (A - sqrt((pow(A, 2.0) + pow(B_m, 2.0)))))));
    	} else {
    		tmp = -1.0 * (sqrt((-1.0 * (F / B_m))) * sqrt(2.0));
    	}
    	return tmp;
    }
    
    B_m = abs(B)
    A, B_m, C, F = sort([A, B_m, C, F])
    function code(A, B_m, C, F)
    	t_0 = Float64(-4.0 * Float64(A * C))
    	tmp = 0.0
    	if ((B_m ^ 2.0) <= 1e-10)
    		tmp = Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * fma(-0.5, Float64((B_m ^ 2.0) / C), Float64(2.0 * A))))) / t_0);
    	elseif ((B_m ^ 2.0) <= 1e+235)
    		tmp = Float64(-1.0 * Float64(Float64(sqrt(2.0) / B_m) * sqrt(Float64(F * Float64(A - sqrt(Float64((A ^ 2.0) + (B_m ^ 2.0))))))));
    	else
    		tmp = Float64(-1.0 * Float64(sqrt(Float64(-1.0 * Float64(F / B_m))) * sqrt(2.0)));
    	end
    	return tmp
    end
    
    B_m = N[Abs[B], $MachinePrecision]
    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
    code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(A * C), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e-10], N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(-0.5 * N[(N[Power[B$95$m, 2.0], $MachinePrecision] / C), $MachinePrecision] + N[(2.0 * A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision], If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e+235], N[(-1.0 * N[(N[(N[Sqrt[2.0], $MachinePrecision] / B$95$m), $MachinePrecision] * N[Sqrt[N[(F * N[(A - N[Sqrt[N[(N[Power[A, 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(-1.0 * N[(N[Sqrt[N[(-1.0 * N[(F / B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]]
    
    \begin{array}{l}
    B_m = \left|B\right|
    \\
    [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
    \\
    \begin{array}{l}
    t_0 := -4 \cdot \left(A \cdot C\right)\\
    \mathbf{if}\;{B\_m}^{2} \leq 10^{-10}:\\
    \;\;\;\;\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \mathsf{fma}\left(-0.5, \frac{{B\_m}^{2}}{C}, 2 \cdot A\right)}}{t\_0}\\
    
    \mathbf{elif}\;{B\_m}^{2} \leq 10^{+235}:\\
    \;\;\;\;-1 \cdot \left(\frac{\sqrt{2}}{B\_m} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B\_m}^{2}}\right)}\right)\\
    
    \mathbf{else}:\\
    \;\;\;\;-1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B\_m}} \cdot \sqrt{2}\right)\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 3 regimes
    2. if (pow.f64 B #s(literal 2 binary64)) < 1.00000000000000004e-10

      1. Initial program 22.8%

        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. Taylor expanded in C around inf

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. Step-by-step derivation
        1. lower--.f64N/A

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - \color{blue}{-1 \cdot A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. lower-+.f64N/A

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - \color{blue}{-1} \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        3. lower-*.f64N/A

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        4. lower-/.f64N/A

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        5. lift-pow.f64N/A

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        6. lower-*.f6444.4

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot \color{blue}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. Applied rewrites44.4%

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. Taylor expanded in A around 0

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\color{blue}{\left(-4 \cdot \left(A \cdot C\right) + {B}^{2}\right)} \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. Step-by-step derivation
        1. lower-fma.f64N/A

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, \color{blue}{A \cdot C}, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. lift-*.f64N/A

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot \color{blue}{C}, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        3. lift-pow.f6444.4

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      7. Applied rewrites44.4%

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\color{blue}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      8. Taylor expanded in A around 0

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\color{blue}{-4 \cdot \left(A \cdot C\right) + {B}^{2}}} \]
      9. Step-by-step derivation
        1. lower-fma.f64N/A

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\mathsf{fma}\left(-4, \color{blue}{A \cdot C}, {B}^{2}\right)} \]
        2. lift-*.f64N/A

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot \color{blue}{C}, {B}^{2}\right)} \]
        3. lift-pow.f6444.4

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
      10. Applied rewrites44.4%

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\color{blue}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)}} \]
      11. Taylor expanded in A around 0

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\frac{-1}{2} \cdot \frac{{B}^{2}}{C} + \color{blue}{2 \cdot A}\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
      12. Step-by-step derivation
        1. lower-fma.f64N/A

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{\color{blue}{C}}, 2 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
        2. lift-pow.f64N/A

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{C}, 2 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
        3. lift-/.f64N/A

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{C}, 2 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
        4. lower-*.f6444.4

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(-0.5, \frac{{B}^{2}}{C}, 2 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
      13. Applied rewrites44.4%

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(-0.5, \color{blue}{\frac{{B}^{2}}{C}}, 2 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
      14. Taylor expanded in A around inf

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left(-4 \cdot \color{blue}{\left(A \cdot C\right)}\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{C}, 2 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
      15. Step-by-step derivation
        1. lower-*.f64N/A

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left(-4 \cdot \left(A \cdot \color{blue}{C}\right)\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{C}, 2 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
        2. lift-*.f6444.2

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left(-4 \cdot \left(A \cdot C\right)\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(-0.5, \frac{{B}^{2}}{C}, 2 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
      16. Applied rewrites44.2%

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left(-4 \cdot \color{blue}{\left(A \cdot C\right)}\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(-0.5, \frac{{B}^{2}}{C}, 2 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
      17. Taylor expanded in A around inf

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left(-4 \cdot \left(A \cdot C\right)\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{C}, 2 \cdot A\right)}}{-4 \cdot \color{blue}{\left(A \cdot C\right)}} \]
      18. Step-by-step derivation
        1. lower-*.f64N/A

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left(-4 \cdot \left(A \cdot C\right)\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{C}, 2 \cdot A\right)}}{-4 \cdot \left(A \cdot \color{blue}{C}\right)} \]
        2. lift-*.f6441.9

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left(-4 \cdot \left(A \cdot C\right)\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(-0.5, \frac{{B}^{2}}{C}, 2 \cdot A\right)}}{-4 \cdot \left(A \cdot C\right)} \]
      19. Applied rewrites41.9%

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left(-4 \cdot \left(A \cdot C\right)\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(-0.5, \frac{{B}^{2}}{C}, 2 \cdot A\right)}}{-4 \cdot \color{blue}{\left(A \cdot C\right)}} \]

      if 1.00000000000000004e-10 < (pow.f64 B #s(literal 2 binary64)) < 1.0000000000000001e235

      1. Initial program 34.2%

        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. Taylor expanded in C around 0

        \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
      3. Step-by-step derivation
        1. lower-*.f64N/A

          \[\leadsto -1 \cdot \color{blue}{\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
        2. lower-*.f64N/A

          \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \color{blue}{\sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
        3. lower-/.f64N/A

          \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
        4. lower-sqrt.f64N/A

          \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F} \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
        5. lower-sqrt.f64N/A

          \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
        6. lower-*.f64N/A

          \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
        7. lower--.f64N/A

          \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
        8. lower-sqrt.f64N/A

          \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
        9. lower-+.f64N/A

          \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
        10. lower-pow.f64N/A

          \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
        11. lift-pow.f6440.7

          \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      4. Applied rewrites40.7%

        \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]

      if 1.0000000000000001e235 < (pow.f64 B #s(literal 2 binary64))

      1. Initial program 3.8%

        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. Taylor expanded in F around 0

        \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
      3. Step-by-step derivation
        1. lower-*.f64N/A

          \[\leadsto -1 \cdot \color{blue}{\left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
        2. lower-*.f64N/A

          \[\leadsto -1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \color{blue}{\sqrt{2}}\right) \]
      4. Applied rewrites6.7%

        \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
      5. Taylor expanded in B around inf

        \[\leadsto -1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B}} \cdot \sqrt{2}\right) \]
      6. Step-by-step derivation
        1. lower-*.f64N/A

          \[\leadsto -1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B}} \cdot \sqrt{2}\right) \]
        2. lower-/.f6448.9

          \[\leadsto -1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B}} \cdot \sqrt{2}\right) \]
      7. Applied rewrites48.9%

        \[\leadsto -1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B}} \cdot \sqrt{2}\right) \]
    3. Recombined 3 regimes into one program.
    4. Add Preprocessing

    Alternative 5: 42.7% accurate, 1.5× speedup?

    \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := -4 \cdot \left(A \cdot C\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 2 \cdot 10^{-15}:\\ \;\;\;\;\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \mathsf{fma}\left(-0.5, \frac{{B\_m}^{2}}{C}, 2 \cdot A\right)}}{t\_0}\\ \mathbf{elif}\;{B\_m}^{2} \leq 5 \cdot 10^{+85}:\\ \;\;\;\;-1 \cdot \left(\sqrt{-0.5 \cdot \frac{F}{C}} \cdot \sqrt{2}\right)\\ \mathbf{else}:\\ \;\;\;\;-1 \cdot \left(\left(\frac{1}{B\_m} \cdot \sqrt{F \cdot \left(A - B\_m\right)}\right) \cdot \sqrt{2}\right)\\ \end{array} \end{array} \]
    B_m = (fabs.f64 B)
    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
    (FPCore (A B_m C F)
     :precision binary64
     (let* ((t_0 (* -4.0 (* A C))))
       (if (<= (pow B_m 2.0) 2e-15)
         (/
          (- (sqrt (* (* 2.0 (* t_0 F)) (fma -0.5 (/ (pow B_m 2.0) C) (* 2.0 A)))))
          t_0)
         (if (<= (pow B_m 2.0) 5e+85)
           (* -1.0 (* (sqrt (* -0.5 (/ F C))) (sqrt 2.0)))
           (* -1.0 (* (* (/ 1.0 B_m) (sqrt (* F (- A B_m)))) (sqrt 2.0)))))))
    B_m = fabs(B);
    assert(A < B_m && B_m < C && C < F);
    double code(double A, double B_m, double C, double F) {
    	double t_0 = -4.0 * (A * C);
    	double tmp;
    	if (pow(B_m, 2.0) <= 2e-15) {
    		tmp = -sqrt(((2.0 * (t_0 * F)) * fma(-0.5, (pow(B_m, 2.0) / C), (2.0 * A)))) / t_0;
    	} else if (pow(B_m, 2.0) <= 5e+85) {
    		tmp = -1.0 * (sqrt((-0.5 * (F / C))) * sqrt(2.0));
    	} else {
    		tmp = -1.0 * (((1.0 / B_m) * sqrt((F * (A - B_m)))) * sqrt(2.0));
    	}
    	return tmp;
    }
    
    B_m = abs(B)
    A, B_m, C, F = sort([A, B_m, C, F])
    function code(A, B_m, C, F)
    	t_0 = Float64(-4.0 * Float64(A * C))
    	tmp = 0.0
    	if ((B_m ^ 2.0) <= 2e-15)
    		tmp = Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * fma(-0.5, Float64((B_m ^ 2.0) / C), Float64(2.0 * A))))) / t_0);
    	elseif ((B_m ^ 2.0) <= 5e+85)
    		tmp = Float64(-1.0 * Float64(sqrt(Float64(-0.5 * Float64(F / C))) * sqrt(2.0)));
    	else
    		tmp = Float64(-1.0 * Float64(Float64(Float64(1.0 / B_m) * sqrt(Float64(F * Float64(A - B_m)))) * sqrt(2.0)));
    	end
    	return tmp
    end
    
    B_m = N[Abs[B], $MachinePrecision]
    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
    code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(A * C), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 2e-15], N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(-0.5 * N[(N[Power[B$95$m, 2.0], $MachinePrecision] / C), $MachinePrecision] + N[(2.0 * A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision], If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 5e+85], N[(-1.0 * N[(N[Sqrt[N[(-0.5 * N[(F / C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(-1.0 * N[(N[(N[(1.0 / B$95$m), $MachinePrecision] * N[Sqrt[N[(F * N[(A - B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]]
    
    \begin{array}{l}
    B_m = \left|B\right|
    \\
    [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
    \\
    \begin{array}{l}
    t_0 := -4 \cdot \left(A \cdot C\right)\\
    \mathbf{if}\;{B\_m}^{2} \leq 2 \cdot 10^{-15}:\\
    \;\;\;\;\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \mathsf{fma}\left(-0.5, \frac{{B\_m}^{2}}{C}, 2 \cdot A\right)}}{t\_0}\\
    
    \mathbf{elif}\;{B\_m}^{2} \leq 5 \cdot 10^{+85}:\\
    \;\;\;\;-1 \cdot \left(\sqrt{-0.5 \cdot \frac{F}{C}} \cdot \sqrt{2}\right)\\
    
    \mathbf{else}:\\
    \;\;\;\;-1 \cdot \left(\left(\frac{1}{B\_m} \cdot \sqrt{F \cdot \left(A - B\_m\right)}\right) \cdot \sqrt{2}\right)\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 3 regimes
    2. if (pow.f64 B #s(literal 2 binary64)) < 2.0000000000000002e-15

      1. Initial program 22.7%

        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. Taylor expanded in C around inf

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. Step-by-step derivation
        1. lower--.f64N/A

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - \color{blue}{-1 \cdot A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. lower-+.f64N/A

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - \color{blue}{-1} \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        3. lower-*.f64N/A

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        4. lower-/.f64N/A

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        5. lift-pow.f64N/A

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        6. lower-*.f6444.4

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot \color{blue}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. Applied rewrites44.4%

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. Taylor expanded in A around 0

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\color{blue}{\left(-4 \cdot \left(A \cdot C\right) + {B}^{2}\right)} \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. Step-by-step derivation
        1. lower-fma.f64N/A

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, \color{blue}{A \cdot C}, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. lift-*.f64N/A

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot \color{blue}{C}, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        3. lift-pow.f6444.4

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      7. Applied rewrites44.4%

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\color{blue}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      8. Taylor expanded in A around 0

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\color{blue}{-4 \cdot \left(A \cdot C\right) + {B}^{2}}} \]
      9. Step-by-step derivation
        1. lower-fma.f64N/A

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\mathsf{fma}\left(-4, \color{blue}{A \cdot C}, {B}^{2}\right)} \]
        2. lift-*.f64N/A

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot \color{blue}{C}, {B}^{2}\right)} \]
        3. lift-pow.f6444.4

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
      10. Applied rewrites44.4%

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\color{blue}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)}} \]
      11. Taylor expanded in A around 0

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\frac{-1}{2} \cdot \frac{{B}^{2}}{C} + \color{blue}{2 \cdot A}\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
      12. Step-by-step derivation
        1. lower-fma.f64N/A

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{\color{blue}{C}}, 2 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
        2. lift-pow.f64N/A

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{C}, 2 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
        3. lift-/.f64N/A

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{C}, 2 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
        4. lower-*.f6444.4

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(-0.5, \frac{{B}^{2}}{C}, 2 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
      13. Applied rewrites44.4%

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(-0.5, \color{blue}{\frac{{B}^{2}}{C}}, 2 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
      14. Taylor expanded in A around inf

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left(-4 \cdot \color{blue}{\left(A \cdot C\right)}\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{C}, 2 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
      15. Step-by-step derivation
        1. lower-*.f64N/A

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left(-4 \cdot \left(A \cdot \color{blue}{C}\right)\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{C}, 2 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
        2. lift-*.f6444.2

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left(-4 \cdot \left(A \cdot C\right)\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(-0.5, \frac{{B}^{2}}{C}, 2 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
      16. Applied rewrites44.2%

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left(-4 \cdot \color{blue}{\left(A \cdot C\right)}\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(-0.5, \frac{{B}^{2}}{C}, 2 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
      17. Taylor expanded in A around inf

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left(-4 \cdot \left(A \cdot C\right)\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{C}, 2 \cdot A\right)}}{-4 \cdot \color{blue}{\left(A \cdot C\right)}} \]
      18. Step-by-step derivation
        1. lower-*.f64N/A

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left(-4 \cdot \left(A \cdot C\right)\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{C}, 2 \cdot A\right)}}{-4 \cdot \left(A \cdot \color{blue}{C}\right)} \]
        2. lift-*.f6442.0

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left(-4 \cdot \left(A \cdot C\right)\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(-0.5, \frac{{B}^{2}}{C}, 2 \cdot A\right)}}{-4 \cdot \left(A \cdot C\right)} \]
      19. Applied rewrites42.0%

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left(-4 \cdot \left(A \cdot C\right)\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(-0.5, \frac{{B}^{2}}{C}, 2 \cdot A\right)}}{-4 \cdot \color{blue}{\left(A \cdot C\right)}} \]

      if 2.0000000000000002e-15 < (pow.f64 B #s(literal 2 binary64)) < 5.0000000000000001e85

      1. Initial program 39.2%

        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. Taylor expanded in F around 0

        \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
      3. Step-by-step derivation
        1. lower-*.f64N/A

          \[\leadsto -1 \cdot \color{blue}{\left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
        2. lower-*.f64N/A

          \[\leadsto -1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \color{blue}{\sqrt{2}}\right) \]
      4. Applied rewrites39.6%

        \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
      5. Taylor expanded in A around -inf

        \[\leadsto -1 \cdot \left(\sqrt{\frac{-1}{2} \cdot \frac{F}{C}} \cdot \sqrt{2}\right) \]
      6. Step-by-step derivation
        1. lower-*.f64N/A

          \[\leadsto -1 \cdot \left(\sqrt{\frac{-1}{2} \cdot \frac{F}{C}} \cdot \sqrt{2}\right) \]
        2. lift-/.f6431.3

          \[\leadsto -1 \cdot \left(\sqrt{-0.5 \cdot \frac{F}{C}} \cdot \sqrt{2}\right) \]
      7. Applied rewrites31.3%

        \[\leadsto -1 \cdot \left(\sqrt{-0.5 \cdot \frac{F}{C}} \cdot \sqrt{2}\right) \]

      if 5.0000000000000001e85 < (pow.f64 B #s(literal 2 binary64))

      1. Initial program 11.2%

        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. Taylor expanded in F around 0

        \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
      3. Step-by-step derivation
        1. lower-*.f64N/A

          \[\leadsto -1 \cdot \color{blue}{\left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
        2. lower-*.f64N/A

          \[\leadsto -1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \color{blue}{\sqrt{2}}\right) \]
      4. Applied rewrites15.0%

        \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
      5. Taylor expanded in C around 0

        \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{\color{blue}{2}}\right) \]
      6. Step-by-step derivation
        1. lower-*.f64N/A

          \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
        2. lower-/.f64N/A

          \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
        3. lower-sqrt.f64N/A

          \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
        4. lower-*.f64N/A

          \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
        5. lower--.f64N/A

          \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
        6. lower-sqrt.f64N/A

          \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
        7. lower-+.f64N/A

          \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
        8. lower-pow.f64N/A

          \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
        9. lift-pow.f6419.4

          \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
      7. Applied rewrites19.4%

        \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{\color{blue}{2}}\right) \]
      8. Taylor expanded in A around 0

        \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - B\right)}\right) \cdot \sqrt{2}\right) \]
      9. Step-by-step derivation
        1. Applied rewrites45.6%

          \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - B\right)}\right) \cdot \sqrt{2}\right) \]
      10. Recombined 3 regimes into one program.
      11. Add Preprocessing

      Alternative 6: 41.9% accurate, 2.1× speedup?

      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;B\_m \leq 5.8 \cdot 10^{-8}:\\ \;\;\;\;\frac{-\sqrt{-8 \cdot \left(A \cdot \left(C \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right)\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B\_m}^{2}\right)}\\ \mathbf{elif}\;B\_m \leq 8.2 \cdot 10^{+42}:\\ \;\;\;\;-1 \cdot \left(\sqrt{-0.5 \cdot \frac{F}{C}} \cdot \sqrt{2}\right)\\ \mathbf{else}:\\ \;\;\;\;-1 \cdot \left(\left(\frac{1}{B\_m} \cdot \sqrt{F \cdot \left(A - B\_m\right)}\right) \cdot \sqrt{2}\right)\\ \end{array} \end{array} \]
      B_m = (fabs.f64 B)
      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
      (FPCore (A B_m C F)
       :precision binary64
       (if (<= B_m 5.8e-8)
         (/
          (- (sqrt (* -8.0 (* A (* C (* F (- A (* -1.0 A))))))))
          (fma -4.0 (* A C) (pow B_m 2.0)))
         (if (<= B_m 8.2e+42)
           (* -1.0 (* (sqrt (* -0.5 (/ F C))) (sqrt 2.0)))
           (* -1.0 (* (* (/ 1.0 B_m) (sqrt (* F (- A B_m)))) (sqrt 2.0))))))
      B_m = fabs(B);
      assert(A < B_m && B_m < C && C < F);
      double code(double A, double B_m, double C, double F) {
      	double tmp;
      	if (B_m <= 5.8e-8) {
      		tmp = -sqrt((-8.0 * (A * (C * (F * (A - (-1.0 * A))))))) / fma(-4.0, (A * C), pow(B_m, 2.0));
      	} else if (B_m <= 8.2e+42) {
      		tmp = -1.0 * (sqrt((-0.5 * (F / C))) * sqrt(2.0));
      	} else {
      		tmp = -1.0 * (((1.0 / B_m) * sqrt((F * (A - B_m)))) * sqrt(2.0));
      	}
      	return tmp;
      }
      
      B_m = abs(B)
      A, B_m, C, F = sort([A, B_m, C, F])
      function code(A, B_m, C, F)
      	tmp = 0.0
      	if (B_m <= 5.8e-8)
      		tmp = Float64(Float64(-sqrt(Float64(-8.0 * Float64(A * Float64(C * Float64(F * Float64(A - Float64(-1.0 * A)))))))) / fma(-4.0, Float64(A * C), (B_m ^ 2.0)));
      	elseif (B_m <= 8.2e+42)
      		tmp = Float64(-1.0 * Float64(sqrt(Float64(-0.5 * Float64(F / C))) * sqrt(2.0)));
      	else
      		tmp = Float64(-1.0 * Float64(Float64(Float64(1.0 / B_m) * sqrt(Float64(F * Float64(A - B_m)))) * sqrt(2.0)));
      	end
      	return tmp
      end
      
      B_m = N[Abs[B], $MachinePrecision]
      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
      code[A_, B$95$m_, C_, F_] := If[LessEqual[B$95$m, 5.8e-8], N[((-N[Sqrt[N[(-8.0 * N[(A * N[(C * N[(F * N[(A - N[(-1.0 * A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / N[(-4.0 * N[(A * C), $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[B$95$m, 8.2e+42], N[(-1.0 * N[(N[Sqrt[N[(-0.5 * N[(F / C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(-1.0 * N[(N[(N[(1.0 / B$95$m), $MachinePrecision] * N[Sqrt[N[(F * N[(A - B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]
      
      \begin{array}{l}
      B_m = \left|B\right|
      \\
      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
      \\
      \begin{array}{l}
      \mathbf{if}\;B\_m \leq 5.8 \cdot 10^{-8}:\\
      \;\;\;\;\frac{-\sqrt{-8 \cdot \left(A \cdot \left(C \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right)\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B\_m}^{2}\right)}\\
      
      \mathbf{elif}\;B\_m \leq 8.2 \cdot 10^{+42}:\\
      \;\;\;\;-1 \cdot \left(\sqrt{-0.5 \cdot \frac{F}{C}} \cdot \sqrt{2}\right)\\
      
      \mathbf{else}:\\
      \;\;\;\;-1 \cdot \left(\left(\frac{1}{B\_m} \cdot \sqrt{F \cdot \left(A - B\_m\right)}\right) \cdot \sqrt{2}\right)\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 3 regimes
      2. if B < 5.8000000000000003e-8

        1. Initial program 22.7%

          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. Taylor expanded in C around inf

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        3. Step-by-step derivation
          1. lower--.f64N/A

            \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - \color{blue}{-1 \cdot A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. lower-+.f64N/A

            \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - \color{blue}{-1} \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          3. lower-*.f64N/A

            \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          4. lower-/.f64N/A

            \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          5. lift-pow.f64N/A

            \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          6. lower-*.f6444.4

            \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot \color{blue}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        4. Applied rewrites44.4%

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        5. Taylor expanded in A around 0

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\color{blue}{\left(-4 \cdot \left(A \cdot C\right) + {B}^{2}\right)} \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        6. Step-by-step derivation
          1. lower-fma.f64N/A

            \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, \color{blue}{A \cdot C}, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. lift-*.f64N/A

            \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot \color{blue}{C}, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          3. lift-pow.f6444.4

            \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        7. Applied rewrites44.4%

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\color{blue}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        8. Taylor expanded in A around 0

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\color{blue}{-4 \cdot \left(A \cdot C\right) + {B}^{2}}} \]
        9. Step-by-step derivation
          1. lower-fma.f64N/A

            \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\mathsf{fma}\left(-4, \color{blue}{A \cdot C}, {B}^{2}\right)} \]
          2. lift-*.f64N/A

            \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot \color{blue}{C}, {B}^{2}\right)} \]
          3. lift-pow.f6444.4

            \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
        10. Applied rewrites44.4%

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right) \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{\color{blue}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)}} \]
        11. Taylor expanded in C around inf

          \[\leadsto \frac{-\sqrt{\color{blue}{-8 \cdot \left(A \cdot \left(C \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right)\right)}}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
        12. Step-by-step derivation
          1. lower-*.f64N/A

            \[\leadsto \frac{-\sqrt{-8 \cdot \color{blue}{\left(A \cdot \left(C \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right)\right)}}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
          2. lower-*.f64N/A

            \[\leadsto \frac{-\sqrt{-8 \cdot \left(A \cdot \color{blue}{\left(C \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right)}\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
          3. lower-*.f64N/A

            \[\leadsto \frac{-\sqrt{-8 \cdot \left(A \cdot \left(C \cdot \color{blue}{\left(F \cdot \left(A - -1 \cdot A\right)\right)}\right)\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
          4. lower-*.f64N/A

            \[\leadsto \frac{-\sqrt{-8 \cdot \left(A \cdot \left(C \cdot \left(F \cdot \color{blue}{\left(A - -1 \cdot A\right)}\right)\right)\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
          5. lower--.f64N/A

            \[\leadsto \frac{-\sqrt{-8 \cdot \left(A \cdot \left(C \cdot \left(F \cdot \left(A - \color{blue}{-1 \cdot A}\right)\right)\right)\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
          6. lift-*.f6440.5

            \[\leadsto \frac{-\sqrt{-8 \cdot \left(A \cdot \left(C \cdot \left(F \cdot \left(A - -1 \cdot \color{blue}{A}\right)\right)\right)\right)}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]
        13. Applied rewrites40.5%

          \[\leadsto \frac{-\sqrt{\color{blue}{-8 \cdot \left(A \cdot \left(C \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right)\right)}}}{\mathsf{fma}\left(-4, A \cdot C, {B}^{2}\right)} \]

        if 5.8000000000000003e-8 < B < 8.2000000000000001e42

        1. Initial program 39.1%

          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. Taylor expanded in F around 0

          \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
        3. Step-by-step derivation
          1. lower-*.f64N/A

            \[\leadsto -1 \cdot \color{blue}{\left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
          2. lower-*.f64N/A

            \[\leadsto -1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \color{blue}{\sqrt{2}}\right) \]
        4. Applied rewrites39.6%

          \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
        5. Taylor expanded in A around -inf

          \[\leadsto -1 \cdot \left(\sqrt{\frac{-1}{2} \cdot \frac{F}{C}} \cdot \sqrt{2}\right) \]
        6. Step-by-step derivation
          1. lower-*.f64N/A

            \[\leadsto -1 \cdot \left(\sqrt{\frac{-1}{2} \cdot \frac{F}{C}} \cdot \sqrt{2}\right) \]
          2. lift-/.f6431.1

            \[\leadsto -1 \cdot \left(\sqrt{-0.5 \cdot \frac{F}{C}} \cdot \sqrt{2}\right) \]
        7. Applied rewrites31.1%

          \[\leadsto -1 \cdot \left(\sqrt{-0.5 \cdot \frac{F}{C}} \cdot \sqrt{2}\right) \]

        if 8.2000000000000001e42 < B

        1. Initial program 11.2%

          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. Taylor expanded in F around 0

          \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
        3. Step-by-step derivation
          1. lower-*.f64N/A

            \[\leadsto -1 \cdot \color{blue}{\left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
          2. lower-*.f64N/A

            \[\leadsto -1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \color{blue}{\sqrt{2}}\right) \]
        4. Applied rewrites15.0%

          \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
        5. Taylor expanded in C around 0

          \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{\color{blue}{2}}\right) \]
        6. Step-by-step derivation
          1. lower-*.f64N/A

            \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
          2. lower-/.f64N/A

            \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
          3. lower-sqrt.f64N/A

            \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
          4. lower-*.f64N/A

            \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
          5. lower--.f64N/A

            \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
          6. lower-sqrt.f64N/A

            \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
          7. lower-+.f64N/A

            \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
          8. lower-pow.f64N/A

            \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
          9. lift-pow.f6419.4

            \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
        7. Applied rewrites19.4%

          \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{\color{blue}{2}}\right) \]
        8. Taylor expanded in A around 0

          \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - B\right)}\right) \cdot \sqrt{2}\right) \]
        9. Step-by-step derivation
          1. Applied rewrites45.6%

            \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - B\right)}\right) \cdot \sqrt{2}\right) \]
        10. Recombined 3 regimes into one program.
        11. Add Preprocessing

        Alternative 7: 40.8% accurate, 2.6× speedup?

        \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;{B\_m}^{2} \leq 5 \cdot 10^{+85}:\\ \;\;\;\;-1 \cdot \left(\sqrt{-0.5 \cdot \frac{F}{C}} \cdot \sqrt{2}\right)\\ \mathbf{else}:\\ \;\;\;\;-1 \cdot \left(\left(\frac{1}{B\_m} \cdot \sqrt{F \cdot \left(A - B\_m\right)}\right) \cdot \sqrt{2}\right)\\ \end{array} \end{array} \]
        B_m = (fabs.f64 B)
        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
        (FPCore (A B_m C F)
         :precision binary64
         (if (<= (pow B_m 2.0) 5e+85)
           (* -1.0 (* (sqrt (* -0.5 (/ F C))) (sqrt 2.0)))
           (* -1.0 (* (* (/ 1.0 B_m) (sqrt (* F (- A B_m)))) (sqrt 2.0)))))
        B_m = fabs(B);
        assert(A < B_m && B_m < C && C < F);
        double code(double A, double B_m, double C, double F) {
        	double tmp;
        	if (pow(B_m, 2.0) <= 5e+85) {
        		tmp = -1.0 * (sqrt((-0.5 * (F / C))) * sqrt(2.0));
        	} else {
        		tmp = -1.0 * (((1.0 / B_m) * sqrt((F * (A - B_m)))) * sqrt(2.0));
        	}
        	return tmp;
        }
        
        B_m =     private
        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
        module fmin_fmax_functions
            implicit none
            private
            public fmax
            public fmin
        
            interface fmax
                module procedure fmax88
                module procedure fmax44
                module procedure fmax84
                module procedure fmax48
            end interface
            interface fmin
                module procedure fmin88
                module procedure fmin44
                module procedure fmin84
                module procedure fmin48
            end interface
        contains
            real(8) function fmax88(x, y) result (res)
                real(8), intent (in) :: x
                real(8), intent (in) :: y
                res = merge(y, merge(x, max(x, y), y /= y), x /= x)
            end function
            real(4) function fmax44(x, y) result (res)
                real(4), intent (in) :: x
                real(4), intent (in) :: y
                res = merge(y, merge(x, max(x, y), y /= y), x /= x)
            end function
            real(8) function fmax84(x, y) result(res)
                real(8), intent (in) :: x
                real(4), intent (in) :: y
                res = merge(dble(y), merge(x, max(x, dble(y)), y /= y), x /= x)
            end function
            real(8) function fmax48(x, y) result(res)
                real(4), intent (in) :: x
                real(8), intent (in) :: y
                res = merge(y, merge(dble(x), max(dble(x), y), y /= y), x /= x)
            end function
            real(8) function fmin88(x, y) result (res)
                real(8), intent (in) :: x
                real(8), intent (in) :: y
                res = merge(y, merge(x, min(x, y), y /= y), x /= x)
            end function
            real(4) function fmin44(x, y) result (res)
                real(4), intent (in) :: x
                real(4), intent (in) :: y
                res = merge(y, merge(x, min(x, y), y /= y), x /= x)
            end function
            real(8) function fmin84(x, y) result(res)
                real(8), intent (in) :: x
                real(4), intent (in) :: y
                res = merge(dble(y), merge(x, min(x, dble(y)), y /= y), x /= x)
            end function
            real(8) function fmin48(x, y) result(res)
                real(4), intent (in) :: x
                real(8), intent (in) :: y
                res = merge(y, merge(dble(x), min(dble(x), y), y /= y), x /= x)
            end function
        end module
        
        real(8) function code(a, b_m, c, f)
        use fmin_fmax_functions
            real(8), intent (in) :: a
            real(8), intent (in) :: b_m
            real(8), intent (in) :: c
            real(8), intent (in) :: f
            real(8) :: tmp
            if ((b_m ** 2.0d0) <= 5d+85) then
                tmp = (-1.0d0) * (sqrt(((-0.5d0) * (f / c))) * sqrt(2.0d0))
            else
                tmp = (-1.0d0) * (((1.0d0 / b_m) * sqrt((f * (a - b_m)))) * sqrt(2.0d0))
            end if
            code = tmp
        end function
        
        B_m = Math.abs(B);
        assert A < B_m && B_m < C && C < F;
        public static double code(double A, double B_m, double C, double F) {
        	double tmp;
        	if (Math.pow(B_m, 2.0) <= 5e+85) {
        		tmp = -1.0 * (Math.sqrt((-0.5 * (F / C))) * Math.sqrt(2.0));
        	} else {
        		tmp = -1.0 * (((1.0 / B_m) * Math.sqrt((F * (A - B_m)))) * Math.sqrt(2.0));
        	}
        	return tmp;
        }
        
        B_m = math.fabs(B)
        [A, B_m, C, F] = sort([A, B_m, C, F])
        def code(A, B_m, C, F):
        	tmp = 0
        	if math.pow(B_m, 2.0) <= 5e+85:
        		tmp = -1.0 * (math.sqrt((-0.5 * (F / C))) * math.sqrt(2.0))
        	else:
        		tmp = -1.0 * (((1.0 / B_m) * math.sqrt((F * (A - B_m)))) * math.sqrt(2.0))
        	return tmp
        
        B_m = abs(B)
        A, B_m, C, F = sort([A, B_m, C, F])
        function code(A, B_m, C, F)
        	tmp = 0.0
        	if ((B_m ^ 2.0) <= 5e+85)
        		tmp = Float64(-1.0 * Float64(sqrt(Float64(-0.5 * Float64(F / C))) * sqrt(2.0)));
        	else
        		tmp = Float64(-1.0 * Float64(Float64(Float64(1.0 / B_m) * sqrt(Float64(F * Float64(A - B_m)))) * sqrt(2.0)));
        	end
        	return tmp
        end
        
        B_m = abs(B);
        A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
        function tmp_2 = code(A, B_m, C, F)
        	tmp = 0.0;
        	if ((B_m ^ 2.0) <= 5e+85)
        		tmp = -1.0 * (sqrt((-0.5 * (F / C))) * sqrt(2.0));
        	else
        		tmp = -1.0 * (((1.0 / B_m) * sqrt((F * (A - B_m)))) * sqrt(2.0));
        	end
        	tmp_2 = tmp;
        end
        
        B_m = N[Abs[B], $MachinePrecision]
        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
        code[A_, B$95$m_, C_, F_] := If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 5e+85], N[(-1.0 * N[(N[Sqrt[N[(-0.5 * N[(F / C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(-1.0 * N[(N[(N[(1.0 / B$95$m), $MachinePrecision] * N[Sqrt[N[(F * N[(A - B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
        
        \begin{array}{l}
        B_m = \left|B\right|
        \\
        [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
        \\
        \begin{array}{l}
        \mathbf{if}\;{B\_m}^{2} \leq 5 \cdot 10^{+85}:\\
        \;\;\;\;-1 \cdot \left(\sqrt{-0.5 \cdot \frac{F}{C}} \cdot \sqrt{2}\right)\\
        
        \mathbf{else}:\\
        \;\;\;\;-1 \cdot \left(\left(\frac{1}{B\_m} \cdot \sqrt{F \cdot \left(A - B\_m\right)}\right) \cdot \sqrt{2}\right)\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 2 regimes
        2. if (pow.f64 B #s(literal 2 binary64)) < 5.0000000000000001e85

          1. Initial program 25.1%

            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. Taylor expanded in F around 0

            \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
          3. Step-by-step derivation
            1. lower-*.f64N/A

              \[\leadsto -1 \cdot \color{blue}{\left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
            2. lower-*.f64N/A

              \[\leadsto -1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \color{blue}{\sqrt{2}}\right) \]
          4. Applied rewrites20.1%

            \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
          5. Taylor expanded in A around -inf

            \[\leadsto -1 \cdot \left(\sqrt{\frac{-1}{2} \cdot \frac{F}{C}} \cdot \sqrt{2}\right) \]
          6. Step-by-step derivation
            1. lower-*.f64N/A

              \[\leadsto -1 \cdot \left(\sqrt{\frac{-1}{2} \cdot \frac{F}{C}} \cdot \sqrt{2}\right) \]
            2. lift-/.f6436.8

              \[\leadsto -1 \cdot \left(\sqrt{-0.5 \cdot \frac{F}{C}} \cdot \sqrt{2}\right) \]
          7. Applied rewrites36.8%

            \[\leadsto -1 \cdot \left(\sqrt{-0.5 \cdot \frac{F}{C}} \cdot \sqrt{2}\right) \]

          if 5.0000000000000001e85 < (pow.f64 B #s(literal 2 binary64))

          1. Initial program 11.2%

            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. Taylor expanded in F around 0

            \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
          3. Step-by-step derivation
            1. lower-*.f64N/A

              \[\leadsto -1 \cdot \color{blue}{\left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
            2. lower-*.f64N/A

              \[\leadsto -1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \color{blue}{\sqrt{2}}\right) \]
          4. Applied rewrites15.0%

            \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
          5. Taylor expanded in C around 0

            \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{\color{blue}{2}}\right) \]
          6. Step-by-step derivation
            1. lower-*.f64N/A

              \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
            2. lower-/.f64N/A

              \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
            3. lower-sqrt.f64N/A

              \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
            4. lower-*.f64N/A

              \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
            5. lower--.f64N/A

              \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
            6. lower-sqrt.f64N/A

              \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
            7. lower-+.f64N/A

              \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
            8. lower-pow.f64N/A

              \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
            9. lift-pow.f6419.4

              \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{2}\right) \]
          7. Applied rewrites19.4%

            \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \cdot \sqrt{\color{blue}{2}}\right) \]
          8. Taylor expanded in A around 0

            \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - B\right)}\right) \cdot \sqrt{2}\right) \]
          9. Step-by-step derivation
            1. Applied rewrites45.6%

              \[\leadsto -1 \cdot \left(\left(\frac{1}{B} \cdot \sqrt{F \cdot \left(A - B\right)}\right) \cdot \sqrt{2}\right) \]
          10. Recombined 2 regimes into one program.
          11. Add Preprocessing

          Alternative 8: 40.6% accurate, 3.0× speedup?

          \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;{B\_m}^{2} \leq 5 \cdot 10^{+85}:\\ \;\;\;\;-1 \cdot \left(\sqrt{-0.5 \cdot \frac{F}{C}} \cdot \sqrt{2}\right)\\ \mathbf{else}:\\ \;\;\;\;-1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B\_m}} \cdot \sqrt{2}\right)\\ \end{array} \end{array} \]
          B_m = (fabs.f64 B)
          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
          (FPCore (A B_m C F)
           :precision binary64
           (if (<= (pow B_m 2.0) 5e+85)
             (* -1.0 (* (sqrt (* -0.5 (/ F C))) (sqrt 2.0)))
             (* -1.0 (* (sqrt (* -1.0 (/ F B_m))) (sqrt 2.0)))))
          B_m = fabs(B);
          assert(A < B_m && B_m < C && C < F);
          double code(double A, double B_m, double C, double F) {
          	double tmp;
          	if (pow(B_m, 2.0) <= 5e+85) {
          		tmp = -1.0 * (sqrt((-0.5 * (F / C))) * sqrt(2.0));
          	} else {
          		tmp = -1.0 * (sqrt((-1.0 * (F / B_m))) * sqrt(2.0));
          	}
          	return tmp;
          }
          
          B_m =     private
          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
          module fmin_fmax_functions
              implicit none
              private
              public fmax
              public fmin
          
              interface fmax
                  module procedure fmax88
                  module procedure fmax44
                  module procedure fmax84
                  module procedure fmax48
              end interface
              interface fmin
                  module procedure fmin88
                  module procedure fmin44
                  module procedure fmin84
                  module procedure fmin48
              end interface
          contains
              real(8) function fmax88(x, y) result (res)
                  real(8), intent (in) :: x
                  real(8), intent (in) :: y
                  res = merge(y, merge(x, max(x, y), y /= y), x /= x)
              end function
              real(4) function fmax44(x, y) result (res)
                  real(4), intent (in) :: x
                  real(4), intent (in) :: y
                  res = merge(y, merge(x, max(x, y), y /= y), x /= x)
              end function
              real(8) function fmax84(x, y) result(res)
                  real(8), intent (in) :: x
                  real(4), intent (in) :: y
                  res = merge(dble(y), merge(x, max(x, dble(y)), y /= y), x /= x)
              end function
              real(8) function fmax48(x, y) result(res)
                  real(4), intent (in) :: x
                  real(8), intent (in) :: y
                  res = merge(y, merge(dble(x), max(dble(x), y), y /= y), x /= x)
              end function
              real(8) function fmin88(x, y) result (res)
                  real(8), intent (in) :: x
                  real(8), intent (in) :: y
                  res = merge(y, merge(x, min(x, y), y /= y), x /= x)
              end function
              real(4) function fmin44(x, y) result (res)
                  real(4), intent (in) :: x
                  real(4), intent (in) :: y
                  res = merge(y, merge(x, min(x, y), y /= y), x /= x)
              end function
              real(8) function fmin84(x, y) result(res)
                  real(8), intent (in) :: x
                  real(4), intent (in) :: y
                  res = merge(dble(y), merge(x, min(x, dble(y)), y /= y), x /= x)
              end function
              real(8) function fmin48(x, y) result(res)
                  real(4), intent (in) :: x
                  real(8), intent (in) :: y
                  res = merge(y, merge(dble(x), min(dble(x), y), y /= y), x /= x)
              end function
          end module
          
          real(8) function code(a, b_m, c, f)
          use fmin_fmax_functions
              real(8), intent (in) :: a
              real(8), intent (in) :: b_m
              real(8), intent (in) :: c
              real(8), intent (in) :: f
              real(8) :: tmp
              if ((b_m ** 2.0d0) <= 5d+85) then
                  tmp = (-1.0d0) * (sqrt(((-0.5d0) * (f / c))) * sqrt(2.0d0))
              else
                  tmp = (-1.0d0) * (sqrt(((-1.0d0) * (f / b_m))) * sqrt(2.0d0))
              end if
              code = tmp
          end function
          
          B_m = Math.abs(B);
          assert A < B_m && B_m < C && C < F;
          public static double code(double A, double B_m, double C, double F) {
          	double tmp;
          	if (Math.pow(B_m, 2.0) <= 5e+85) {
          		tmp = -1.0 * (Math.sqrt((-0.5 * (F / C))) * Math.sqrt(2.0));
          	} else {
          		tmp = -1.0 * (Math.sqrt((-1.0 * (F / B_m))) * Math.sqrt(2.0));
          	}
          	return tmp;
          }
          
          B_m = math.fabs(B)
          [A, B_m, C, F] = sort([A, B_m, C, F])
          def code(A, B_m, C, F):
          	tmp = 0
          	if math.pow(B_m, 2.0) <= 5e+85:
          		tmp = -1.0 * (math.sqrt((-0.5 * (F / C))) * math.sqrt(2.0))
          	else:
          		tmp = -1.0 * (math.sqrt((-1.0 * (F / B_m))) * math.sqrt(2.0))
          	return tmp
          
          B_m = abs(B)
          A, B_m, C, F = sort([A, B_m, C, F])
          function code(A, B_m, C, F)
          	tmp = 0.0
          	if ((B_m ^ 2.0) <= 5e+85)
          		tmp = Float64(-1.0 * Float64(sqrt(Float64(-0.5 * Float64(F / C))) * sqrt(2.0)));
          	else
          		tmp = Float64(-1.0 * Float64(sqrt(Float64(-1.0 * Float64(F / B_m))) * sqrt(2.0)));
          	end
          	return tmp
          end
          
          B_m = abs(B);
          A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
          function tmp_2 = code(A, B_m, C, F)
          	tmp = 0.0;
          	if ((B_m ^ 2.0) <= 5e+85)
          		tmp = -1.0 * (sqrt((-0.5 * (F / C))) * sqrt(2.0));
          	else
          		tmp = -1.0 * (sqrt((-1.0 * (F / B_m))) * sqrt(2.0));
          	end
          	tmp_2 = tmp;
          end
          
          B_m = N[Abs[B], $MachinePrecision]
          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
          code[A_, B$95$m_, C_, F_] := If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 5e+85], N[(-1.0 * N[(N[Sqrt[N[(-0.5 * N[(F / C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(-1.0 * N[(N[Sqrt[N[(-1.0 * N[(F / B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
          
          \begin{array}{l}
          B_m = \left|B\right|
          \\
          [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
          \\
          \begin{array}{l}
          \mathbf{if}\;{B\_m}^{2} \leq 5 \cdot 10^{+85}:\\
          \;\;\;\;-1 \cdot \left(\sqrt{-0.5 \cdot \frac{F}{C}} \cdot \sqrt{2}\right)\\
          
          \mathbf{else}:\\
          \;\;\;\;-1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B\_m}} \cdot \sqrt{2}\right)\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if (pow.f64 B #s(literal 2 binary64)) < 5.0000000000000001e85

            1. Initial program 25.1%

              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            2. Taylor expanded in F around 0

              \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
            3. Step-by-step derivation
              1. lower-*.f64N/A

                \[\leadsto -1 \cdot \color{blue}{\left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
              2. lower-*.f64N/A

                \[\leadsto -1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \color{blue}{\sqrt{2}}\right) \]
            4. Applied rewrites20.1%

              \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
            5. Taylor expanded in A around -inf

              \[\leadsto -1 \cdot \left(\sqrt{\frac{-1}{2} \cdot \frac{F}{C}} \cdot \sqrt{2}\right) \]
            6. Step-by-step derivation
              1. lower-*.f64N/A

                \[\leadsto -1 \cdot \left(\sqrt{\frac{-1}{2} \cdot \frac{F}{C}} \cdot \sqrt{2}\right) \]
              2. lift-/.f6436.8

                \[\leadsto -1 \cdot \left(\sqrt{-0.5 \cdot \frac{F}{C}} \cdot \sqrt{2}\right) \]
            7. Applied rewrites36.8%

              \[\leadsto -1 \cdot \left(\sqrt{-0.5 \cdot \frac{F}{C}} \cdot \sqrt{2}\right) \]

            if 5.0000000000000001e85 < (pow.f64 B #s(literal 2 binary64))

            1. Initial program 11.2%

              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            2. Taylor expanded in F around 0

              \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
            3. Step-by-step derivation
              1. lower-*.f64N/A

                \[\leadsto -1 \cdot \color{blue}{\left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
              2. lower-*.f64N/A

                \[\leadsto -1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \color{blue}{\sqrt{2}}\right) \]
            4. Applied rewrites15.0%

              \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
            5. Taylor expanded in B around inf

              \[\leadsto -1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B}} \cdot \sqrt{2}\right) \]
            6. Step-by-step derivation
              1. lower-*.f64N/A

                \[\leadsto -1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B}} \cdot \sqrt{2}\right) \]
              2. lower-/.f6446.2

                \[\leadsto -1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B}} \cdot \sqrt{2}\right) \]
            7. Applied rewrites46.2%

              \[\leadsto -1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B}} \cdot \sqrt{2}\right) \]
          3. Recombined 2 regimes into one program.
          4. Add Preprocessing

          Alternative 9: 27.0% accurate, 6.5× speedup?

          \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ -1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B\_m}} \cdot \sqrt{2}\right) \end{array} \]
          B_m = (fabs.f64 B)
          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
          (FPCore (A B_m C F)
           :precision binary64
           (* -1.0 (* (sqrt (* -1.0 (/ F B_m))) (sqrt 2.0))))
          B_m = fabs(B);
          assert(A < B_m && B_m < C && C < F);
          double code(double A, double B_m, double C, double F) {
          	return -1.0 * (sqrt((-1.0 * (F / B_m))) * sqrt(2.0));
          }
          
          B_m =     private
          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
          module fmin_fmax_functions
              implicit none
              private
              public fmax
              public fmin
          
              interface fmax
                  module procedure fmax88
                  module procedure fmax44
                  module procedure fmax84
                  module procedure fmax48
              end interface
              interface fmin
                  module procedure fmin88
                  module procedure fmin44
                  module procedure fmin84
                  module procedure fmin48
              end interface
          contains
              real(8) function fmax88(x, y) result (res)
                  real(8), intent (in) :: x
                  real(8), intent (in) :: y
                  res = merge(y, merge(x, max(x, y), y /= y), x /= x)
              end function
              real(4) function fmax44(x, y) result (res)
                  real(4), intent (in) :: x
                  real(4), intent (in) :: y
                  res = merge(y, merge(x, max(x, y), y /= y), x /= x)
              end function
              real(8) function fmax84(x, y) result(res)
                  real(8), intent (in) :: x
                  real(4), intent (in) :: y
                  res = merge(dble(y), merge(x, max(x, dble(y)), y /= y), x /= x)
              end function
              real(8) function fmax48(x, y) result(res)
                  real(4), intent (in) :: x
                  real(8), intent (in) :: y
                  res = merge(y, merge(dble(x), max(dble(x), y), y /= y), x /= x)
              end function
              real(8) function fmin88(x, y) result (res)
                  real(8), intent (in) :: x
                  real(8), intent (in) :: y
                  res = merge(y, merge(x, min(x, y), y /= y), x /= x)
              end function
              real(4) function fmin44(x, y) result (res)
                  real(4), intent (in) :: x
                  real(4), intent (in) :: y
                  res = merge(y, merge(x, min(x, y), y /= y), x /= x)
              end function
              real(8) function fmin84(x, y) result(res)
                  real(8), intent (in) :: x
                  real(4), intent (in) :: y
                  res = merge(dble(y), merge(x, min(x, dble(y)), y /= y), x /= x)
              end function
              real(8) function fmin48(x, y) result(res)
                  real(4), intent (in) :: x
                  real(8), intent (in) :: y
                  res = merge(y, merge(dble(x), min(dble(x), y), y /= y), x /= x)
              end function
          end module
          
          real(8) function code(a, b_m, c, f)
          use fmin_fmax_functions
              real(8), intent (in) :: a
              real(8), intent (in) :: b_m
              real(8), intent (in) :: c
              real(8), intent (in) :: f
              code = (-1.0d0) * (sqrt(((-1.0d0) * (f / b_m))) * sqrt(2.0d0))
          end function
          
          B_m = Math.abs(B);
          assert A < B_m && B_m < C && C < F;
          public static double code(double A, double B_m, double C, double F) {
          	return -1.0 * (Math.sqrt((-1.0 * (F / B_m))) * Math.sqrt(2.0));
          }
          
          B_m = math.fabs(B)
          [A, B_m, C, F] = sort([A, B_m, C, F])
          def code(A, B_m, C, F):
          	return -1.0 * (math.sqrt((-1.0 * (F / B_m))) * math.sqrt(2.0))
          
          B_m = abs(B)
          A, B_m, C, F = sort([A, B_m, C, F])
          function code(A, B_m, C, F)
          	return Float64(-1.0 * Float64(sqrt(Float64(-1.0 * Float64(F / B_m))) * sqrt(2.0)))
          end
          
          B_m = abs(B);
          A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
          function tmp = code(A, B_m, C, F)
          	tmp = -1.0 * (sqrt((-1.0 * (F / B_m))) * sqrt(2.0));
          end
          
          B_m = N[Abs[B], $MachinePrecision]
          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
          code[A_, B$95$m_, C_, F_] := N[(-1.0 * N[(N[Sqrt[N[(-1.0 * N[(F / B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
          
          \begin{array}{l}
          B_m = \left|B\right|
          \\
          [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
          \\
          -1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B\_m}} \cdot \sqrt{2}\right)
          \end{array}
          
          Derivation
          1. Initial program 19.1%

            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. Taylor expanded in F around 0

            \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
          3. Step-by-step derivation
            1. lower-*.f64N/A

              \[\leadsto -1 \cdot \color{blue}{\left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
            2. lower-*.f64N/A

              \[\leadsto -1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \color{blue}{\sqrt{2}}\right) \]
          4. Applied rewrites17.9%

            \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
          5. Taylor expanded in B around inf

            \[\leadsto -1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B}} \cdot \sqrt{2}\right) \]
          6. Step-by-step derivation
            1. lower-*.f64N/A

              \[\leadsto -1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B}} \cdot \sqrt{2}\right) \]
            2. lower-/.f6427.0

              \[\leadsto -1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B}} \cdot \sqrt{2}\right) \]
          7. Applied rewrites27.0%

            \[\leadsto -1 \cdot \left(\sqrt{-1 \cdot \frac{F}{B}} \cdot \sqrt{2}\right) \]
          8. Add Preprocessing

          Alternative 10: 0.8% accurate, 7.9× speedup?

          \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ -1 \cdot \left(\sqrt{\frac{F}{B\_m}} \cdot \sqrt{2}\right) \end{array} \]
          B_m = (fabs.f64 B)
          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
          (FPCore (A B_m C F)
           :precision binary64
           (* -1.0 (* (sqrt (/ F B_m)) (sqrt 2.0))))
          B_m = fabs(B);
          assert(A < B_m && B_m < C && C < F);
          double code(double A, double B_m, double C, double F) {
          	return -1.0 * (sqrt((F / B_m)) * sqrt(2.0));
          }
          
          B_m =     private
          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
          module fmin_fmax_functions
              implicit none
              private
              public fmax
              public fmin
          
              interface fmax
                  module procedure fmax88
                  module procedure fmax44
                  module procedure fmax84
                  module procedure fmax48
              end interface
              interface fmin
                  module procedure fmin88
                  module procedure fmin44
                  module procedure fmin84
                  module procedure fmin48
              end interface
          contains
              real(8) function fmax88(x, y) result (res)
                  real(8), intent (in) :: x
                  real(8), intent (in) :: y
                  res = merge(y, merge(x, max(x, y), y /= y), x /= x)
              end function
              real(4) function fmax44(x, y) result (res)
                  real(4), intent (in) :: x
                  real(4), intent (in) :: y
                  res = merge(y, merge(x, max(x, y), y /= y), x /= x)
              end function
              real(8) function fmax84(x, y) result(res)
                  real(8), intent (in) :: x
                  real(4), intent (in) :: y
                  res = merge(dble(y), merge(x, max(x, dble(y)), y /= y), x /= x)
              end function
              real(8) function fmax48(x, y) result(res)
                  real(4), intent (in) :: x
                  real(8), intent (in) :: y
                  res = merge(y, merge(dble(x), max(dble(x), y), y /= y), x /= x)
              end function
              real(8) function fmin88(x, y) result (res)
                  real(8), intent (in) :: x
                  real(8), intent (in) :: y
                  res = merge(y, merge(x, min(x, y), y /= y), x /= x)
              end function
              real(4) function fmin44(x, y) result (res)
                  real(4), intent (in) :: x
                  real(4), intent (in) :: y
                  res = merge(y, merge(x, min(x, y), y /= y), x /= x)
              end function
              real(8) function fmin84(x, y) result(res)
                  real(8), intent (in) :: x
                  real(4), intent (in) :: y
                  res = merge(dble(y), merge(x, min(x, dble(y)), y /= y), x /= x)
              end function
              real(8) function fmin48(x, y) result(res)
                  real(4), intent (in) :: x
                  real(8), intent (in) :: y
                  res = merge(y, merge(dble(x), min(dble(x), y), y /= y), x /= x)
              end function
          end module
          
          real(8) function code(a, b_m, c, f)
          use fmin_fmax_functions
              real(8), intent (in) :: a
              real(8), intent (in) :: b_m
              real(8), intent (in) :: c
              real(8), intent (in) :: f
              code = (-1.0d0) * (sqrt((f / b_m)) * sqrt(2.0d0))
          end function
          
          B_m = Math.abs(B);
          assert A < B_m && B_m < C && C < F;
          public static double code(double A, double B_m, double C, double F) {
          	return -1.0 * (Math.sqrt((F / B_m)) * Math.sqrt(2.0));
          }
          
          B_m = math.fabs(B)
          [A, B_m, C, F] = sort([A, B_m, C, F])
          def code(A, B_m, C, F):
          	return -1.0 * (math.sqrt((F / B_m)) * math.sqrt(2.0))
          
          B_m = abs(B)
          A, B_m, C, F = sort([A, B_m, C, F])
          function code(A, B_m, C, F)
          	return Float64(-1.0 * Float64(sqrt(Float64(F / B_m)) * sqrt(2.0)))
          end
          
          B_m = abs(B);
          A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
          function tmp = code(A, B_m, C, F)
          	tmp = -1.0 * (sqrt((F / B_m)) * sqrt(2.0));
          end
          
          B_m = N[Abs[B], $MachinePrecision]
          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
          code[A_, B$95$m_, C_, F_] := N[(-1.0 * N[(N[Sqrt[N[(F / B$95$m), $MachinePrecision]], $MachinePrecision] * N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
          
          \begin{array}{l}
          B_m = \left|B\right|
          \\
          [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
          \\
          -1 \cdot \left(\sqrt{\frac{F}{B\_m}} \cdot \sqrt{2}\right)
          \end{array}
          
          Derivation
          1. Initial program 19.1%

            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. Taylor expanded in F around 0

            \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
          3. Step-by-step derivation
            1. lower-*.f64N/A

              \[\leadsto -1 \cdot \color{blue}{\left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
            2. lower-*.f64N/A

              \[\leadsto -1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \color{blue}{\sqrt{2}}\right) \]
          4. Applied rewrites17.9%

            \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
          5. Taylor expanded in B around -inf

            \[\leadsto -1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right) \]
          6. Step-by-step derivation
            1. lower-/.f640.8

              \[\leadsto -1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right) \]
          7. Applied rewrites0.8%

            \[\leadsto -1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right) \]
          8. Add Preprocessing

          Reproduce

          ?
          herbie shell --seed 2025128 
          (FPCore (A B C F)
            :name "ABCF->ab-angle b"
            :precision binary64
            (/ (- (sqrt (* (* 2.0 (* (- (pow B 2.0) (* (* 4.0 A) C)) F)) (- (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))) (- (pow B 2.0) (* (* 4.0 A) C))))