Jmat.Real.erfi, branch x greater than or equal to 5

Percentage Accurate: 100.0% → 100.0%
Time: 4.5s
Alternatives: 8
Speedup: 2.4×

Specification

?
\[x \geq 0.5\]
\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{\left|x\right|}\\ t_1 := \left(t\_0 \cdot t\_0\right) \cdot t\_0\\ t_2 := \left(t\_1 \cdot t\_0\right) \cdot t\_0\\ \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(t\_0 + \frac{1}{2} \cdot t\_1\right) + \frac{3}{4} \cdot t\_2\right) + \frac{15}{8} \cdot \left(\left(t\_2 \cdot t\_0\right) \cdot t\_0\right)\right) \end{array} \end{array} \]
(FPCore (x)
 :precision binary64
 (let* ((t_0 (/ 1.0 (fabs x)))
        (t_1 (* (* t_0 t_0) t_0))
        (t_2 (* (* t_1 t_0) t_0)))
   (*
    (* (/ 1.0 (sqrt PI)) (exp (* (fabs x) (fabs x))))
    (+
     (+ (+ t_0 (* (/ 1.0 2.0) t_1)) (* (/ 3.0 4.0) t_2))
     (* (/ 15.0 8.0) (* (* t_2 t_0) t_0))))))
double code(double x) {
	double t_0 = 1.0 / fabs(x);
	double t_1 = (t_0 * t_0) * t_0;
	double t_2 = (t_1 * t_0) * t_0;
	return ((1.0 / sqrt(((double) M_PI))) * exp((fabs(x) * fabs(x)))) * (((t_0 + ((1.0 / 2.0) * t_1)) + ((3.0 / 4.0) * t_2)) + ((15.0 / 8.0) * ((t_2 * t_0) * t_0)));
}
public static double code(double x) {
	double t_0 = 1.0 / Math.abs(x);
	double t_1 = (t_0 * t_0) * t_0;
	double t_2 = (t_1 * t_0) * t_0;
	return ((1.0 / Math.sqrt(Math.PI)) * Math.exp((Math.abs(x) * Math.abs(x)))) * (((t_0 + ((1.0 / 2.0) * t_1)) + ((3.0 / 4.0) * t_2)) + ((15.0 / 8.0) * ((t_2 * t_0) * t_0)));
}
def code(x):
	t_0 = 1.0 / math.fabs(x)
	t_1 = (t_0 * t_0) * t_0
	t_2 = (t_1 * t_0) * t_0
	return ((1.0 / math.sqrt(math.pi)) * math.exp((math.fabs(x) * math.fabs(x)))) * (((t_0 + ((1.0 / 2.0) * t_1)) + ((3.0 / 4.0) * t_2)) + ((15.0 / 8.0) * ((t_2 * t_0) * t_0)))
function code(x)
	t_0 = Float64(1.0 / abs(x))
	t_1 = Float64(Float64(t_0 * t_0) * t_0)
	t_2 = Float64(Float64(t_1 * t_0) * t_0)
	return Float64(Float64(Float64(1.0 / sqrt(pi)) * exp(Float64(abs(x) * abs(x)))) * Float64(Float64(Float64(t_0 + Float64(Float64(1.0 / 2.0) * t_1)) + Float64(Float64(3.0 / 4.0) * t_2)) + Float64(Float64(15.0 / 8.0) * Float64(Float64(t_2 * t_0) * t_0))))
end
function tmp = code(x)
	t_0 = 1.0 / abs(x);
	t_1 = (t_0 * t_0) * t_0;
	t_2 = (t_1 * t_0) * t_0;
	tmp = ((1.0 / sqrt(pi)) * exp((abs(x) * abs(x)))) * (((t_0 + ((1.0 / 2.0) * t_1)) + ((3.0 / 4.0) * t_2)) + ((15.0 / 8.0) * ((t_2 * t_0) * t_0)));
end
code[x_] := Block[{t$95$0 = N[(1.0 / N[Abs[x], $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(t$95$0 * t$95$0), $MachinePrecision] * t$95$0), $MachinePrecision]}, Block[{t$95$2 = N[(N[(t$95$1 * t$95$0), $MachinePrecision] * t$95$0), $MachinePrecision]}, N[(N[(N[(1.0 / N[Sqrt[Pi], $MachinePrecision]), $MachinePrecision] * N[Exp[N[(N[Abs[x], $MachinePrecision] * N[Abs[x], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[(N[(N[(t$95$0 + N[(N[(1.0 / 2.0), $MachinePrecision] * t$95$1), $MachinePrecision]), $MachinePrecision] + N[(N[(3.0 / 4.0), $MachinePrecision] * t$95$2), $MachinePrecision]), $MachinePrecision] + N[(N[(15.0 / 8.0), $MachinePrecision] * N[(N[(t$95$2 * t$95$0), $MachinePrecision] * t$95$0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{1}{\left|x\right|}\\
t_1 := \left(t\_0 \cdot t\_0\right) \cdot t\_0\\
t_2 := \left(t\_1 \cdot t\_0\right) \cdot t\_0\\
\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(t\_0 + \frac{1}{2} \cdot t\_1\right) + \frac{3}{4} \cdot t\_2\right) + \frac{15}{8} \cdot \left(\left(t\_2 \cdot t\_0\right) \cdot t\_0\right)\right)
\end{array}
\end{array}

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 8 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{\left|x\right|}\\ t_1 := \left(t\_0 \cdot t\_0\right) \cdot t\_0\\ t_2 := \left(t\_1 \cdot t\_0\right) \cdot t\_0\\ \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(t\_0 + \frac{1}{2} \cdot t\_1\right) + \frac{3}{4} \cdot t\_2\right) + \frac{15}{8} \cdot \left(\left(t\_2 \cdot t\_0\right) \cdot t\_0\right)\right) \end{array} \end{array} \]
(FPCore (x)
 :precision binary64
 (let* ((t_0 (/ 1.0 (fabs x)))
        (t_1 (* (* t_0 t_0) t_0))
        (t_2 (* (* t_1 t_0) t_0)))
   (*
    (* (/ 1.0 (sqrt PI)) (exp (* (fabs x) (fabs x))))
    (+
     (+ (+ t_0 (* (/ 1.0 2.0) t_1)) (* (/ 3.0 4.0) t_2))
     (* (/ 15.0 8.0) (* (* t_2 t_0) t_0))))))
double code(double x) {
	double t_0 = 1.0 / fabs(x);
	double t_1 = (t_0 * t_0) * t_0;
	double t_2 = (t_1 * t_0) * t_0;
	return ((1.0 / sqrt(((double) M_PI))) * exp((fabs(x) * fabs(x)))) * (((t_0 + ((1.0 / 2.0) * t_1)) + ((3.0 / 4.0) * t_2)) + ((15.0 / 8.0) * ((t_2 * t_0) * t_0)));
}
public static double code(double x) {
	double t_0 = 1.0 / Math.abs(x);
	double t_1 = (t_0 * t_0) * t_0;
	double t_2 = (t_1 * t_0) * t_0;
	return ((1.0 / Math.sqrt(Math.PI)) * Math.exp((Math.abs(x) * Math.abs(x)))) * (((t_0 + ((1.0 / 2.0) * t_1)) + ((3.0 / 4.0) * t_2)) + ((15.0 / 8.0) * ((t_2 * t_0) * t_0)));
}
def code(x):
	t_0 = 1.0 / math.fabs(x)
	t_1 = (t_0 * t_0) * t_0
	t_2 = (t_1 * t_0) * t_0
	return ((1.0 / math.sqrt(math.pi)) * math.exp((math.fabs(x) * math.fabs(x)))) * (((t_0 + ((1.0 / 2.0) * t_1)) + ((3.0 / 4.0) * t_2)) + ((15.0 / 8.0) * ((t_2 * t_0) * t_0)))
function code(x)
	t_0 = Float64(1.0 / abs(x))
	t_1 = Float64(Float64(t_0 * t_0) * t_0)
	t_2 = Float64(Float64(t_1 * t_0) * t_0)
	return Float64(Float64(Float64(1.0 / sqrt(pi)) * exp(Float64(abs(x) * abs(x)))) * Float64(Float64(Float64(t_0 + Float64(Float64(1.0 / 2.0) * t_1)) + Float64(Float64(3.0 / 4.0) * t_2)) + Float64(Float64(15.0 / 8.0) * Float64(Float64(t_2 * t_0) * t_0))))
end
function tmp = code(x)
	t_0 = 1.0 / abs(x);
	t_1 = (t_0 * t_0) * t_0;
	t_2 = (t_1 * t_0) * t_0;
	tmp = ((1.0 / sqrt(pi)) * exp((abs(x) * abs(x)))) * (((t_0 + ((1.0 / 2.0) * t_1)) + ((3.0 / 4.0) * t_2)) + ((15.0 / 8.0) * ((t_2 * t_0) * t_0)));
end
code[x_] := Block[{t$95$0 = N[(1.0 / N[Abs[x], $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(t$95$0 * t$95$0), $MachinePrecision] * t$95$0), $MachinePrecision]}, Block[{t$95$2 = N[(N[(t$95$1 * t$95$0), $MachinePrecision] * t$95$0), $MachinePrecision]}, N[(N[(N[(1.0 / N[Sqrt[Pi], $MachinePrecision]), $MachinePrecision] * N[Exp[N[(N[Abs[x], $MachinePrecision] * N[Abs[x], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[(N[(N[(t$95$0 + N[(N[(1.0 / 2.0), $MachinePrecision] * t$95$1), $MachinePrecision]), $MachinePrecision] + N[(N[(3.0 / 4.0), $MachinePrecision] * t$95$2), $MachinePrecision]), $MachinePrecision] + N[(N[(15.0 / 8.0), $MachinePrecision] * N[(N[(t$95$2 * t$95$0), $MachinePrecision] * t$95$0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{1}{\left|x\right|}\\
t_1 := \left(t\_0 \cdot t\_0\right) \cdot t\_0\\
t_2 := \left(t\_1 \cdot t\_0\right) \cdot t\_0\\
\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(t\_0 + \frac{1}{2} \cdot t\_1\right) + \frac{3}{4} \cdot t\_2\right) + \frac{15}{8} \cdot \left(\left(t\_2 \cdot t\_0\right) \cdot t\_0\right)\right)
\end{array}
\end{array}

Alternative 1: 100.0% accurate, 2.4× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(x \cdot x\right) \cdot x\\ \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(-\left(\frac{\frac{\frac{1.875}{x \cdot x} + 0.75}{-t\_0 \cdot x} - 1}{x} - \frac{0.5}{t\_0}\right)\right) \end{array} \end{array} \]
(FPCore (x)
 :precision binary64
 (let* ((t_0 (* (* x x) x)))
   (*
    (* (/ 1.0 (sqrt PI)) (exp (* (fabs x) (fabs x))))
    (-
     (-
      (/ (- (/ (+ (/ 1.875 (* x x)) 0.75) (- (* t_0 x))) 1.0) x)
      (/ 0.5 t_0))))))
double code(double x) {
	double t_0 = (x * x) * x;
	return ((1.0 / sqrt(((double) M_PI))) * exp((fabs(x) * fabs(x)))) * -((((((1.875 / (x * x)) + 0.75) / -(t_0 * x)) - 1.0) / x) - (0.5 / t_0));
}
public static double code(double x) {
	double t_0 = (x * x) * x;
	return ((1.0 / Math.sqrt(Math.PI)) * Math.exp((Math.abs(x) * Math.abs(x)))) * -((((((1.875 / (x * x)) + 0.75) / -(t_0 * x)) - 1.0) / x) - (0.5 / t_0));
}
def code(x):
	t_0 = (x * x) * x
	return ((1.0 / math.sqrt(math.pi)) * math.exp((math.fabs(x) * math.fabs(x)))) * -((((((1.875 / (x * x)) + 0.75) / -(t_0 * x)) - 1.0) / x) - (0.5 / t_0))
function code(x)
	t_0 = Float64(Float64(x * x) * x)
	return Float64(Float64(Float64(1.0 / sqrt(pi)) * exp(Float64(abs(x) * abs(x)))) * Float64(-Float64(Float64(Float64(Float64(Float64(Float64(1.875 / Float64(x * x)) + 0.75) / Float64(-Float64(t_0 * x))) - 1.0) / x) - Float64(0.5 / t_0))))
end
function tmp = code(x)
	t_0 = (x * x) * x;
	tmp = ((1.0 / sqrt(pi)) * exp((abs(x) * abs(x)))) * -((((((1.875 / (x * x)) + 0.75) / -(t_0 * x)) - 1.0) / x) - (0.5 / t_0));
end
code[x_] := Block[{t$95$0 = N[(N[(x * x), $MachinePrecision] * x), $MachinePrecision]}, N[(N[(N[(1.0 / N[Sqrt[Pi], $MachinePrecision]), $MachinePrecision] * N[Exp[N[(N[Abs[x], $MachinePrecision] * N[Abs[x], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * (-N[(N[(N[(N[(N[(N[(1.875 / N[(x * x), $MachinePrecision]), $MachinePrecision] + 0.75), $MachinePrecision] / (-N[(t$95$0 * x), $MachinePrecision])), $MachinePrecision] - 1.0), $MachinePrecision] / x), $MachinePrecision] - N[(0.5 / t$95$0), $MachinePrecision]), $MachinePrecision])), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \left(x \cdot x\right) \cdot x\\
\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(-\left(\frac{\frac{\frac{1.875}{x \cdot x} + 0.75}{-t\_0 \cdot x} - 1}{x} - \frac{0.5}{t\_0}\right)\right)
\end{array}
\end{array}
Derivation
  1. Initial program 100.0%

    \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
  2. Taylor expanded in x around 0

    \[\leadsto \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \color{blue}{\left(\frac{3}{4} \cdot \frac{1}{{\left(\left|x\right|\right)}^{5}} + \left(\frac{15}{8} \cdot \frac{1}{{\left(\left|x\right|\right)}^{7}} + \left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \frac{1}{{\left(\left|x\right|\right)}^{3}}\right)\right)\right)} \]
  3. Applied rewrites100.0%

    \[\leadsto \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{0.5}{x \cdot x} + 1, \frac{1}{\left|x\right|}, \mathsf{fma}\left({\left(\left|x\right|\right)}^{-7}, 1.875, {\left(\left|x\right|\right)}^{-5} \cdot 0.75\right)\right)} \]
  4. Taylor expanded in x around 0

    \[\leadsto \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \color{blue}{\left(\frac{3}{4} \cdot \frac{1}{{\left(\left|x\right|\right)}^{5}} + \left(\frac{15}{8} \cdot \frac{1}{{\left(\left|x\right|\right)}^{7}} + \left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \frac{1}{{\left(\left|x\right|\right)}^{3}}\right)\right)\right)} \]
  5. Applied rewrites100.0%

    \[\leadsto \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \color{blue}{\mathsf{fma}\left({x}^{-5}, 0.75, \mathsf{fma}\left({x}^{-7}, 1.875, \frac{\frac{0.5}{x \cdot x} + 1}{x}\right)\right)} \]
  6. Taylor expanded in x around -inf

    \[\leadsto \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(-1 \cdot \color{blue}{\frac{-1 \cdot \frac{\frac{3}{4} + \frac{15}{8} \cdot \frac{1}{{x}^{2}}}{{x}^{4}} - \left(1 + \frac{1}{2} \cdot \frac{1}{{x}^{2}}\right)}{x}}\right) \]
  7. Applied rewrites100.0%

    \[\leadsto \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(-\frac{\left(\left(-\frac{\frac{1.875}{x \cdot x} + 0.75}{\left(x \cdot x\right) \cdot \left(x \cdot x\right)}\right) - 1\right) - \frac{0.5}{x \cdot x}}{x}\right) \]
  8. Applied rewrites100.0%

    \[\leadsto \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(-\left(\frac{\frac{\frac{1.875}{x \cdot x} + 0.75}{-\left(\left(x \cdot x\right) \cdot x\right) \cdot x} - 1}{x} - \frac{0.5}{\left(x \cdot x\right) \cdot x}\right)\right) \]
  9. Add Preprocessing

Alternative 2: 100.0% accurate, 2.6× speedup?

\[\begin{array}{l} \\ \frac{1}{\sqrt{\pi}} \cdot \left(e^{x \cdot x} \cdot \frac{\frac{\frac{1.875}{x \cdot x} + 0.75}{-\left(\left(x \cdot x\right) \cdot x\right) \cdot x} - \left(1 - \frac{-0.5}{x \cdot x}\right)}{-x}\right) \end{array} \]
(FPCore (x)
 :precision binary64
 (*
  (/ 1.0 (sqrt PI))
  (*
   (exp (* x x))
   (/
    (-
     (/ (+ (/ 1.875 (* x x)) 0.75) (- (* (* (* x x) x) x)))
     (- 1.0 (/ -0.5 (* x x))))
    (- x)))))
double code(double x) {
	return (1.0 / sqrt(((double) M_PI))) * (exp((x * x)) * (((((1.875 / (x * x)) + 0.75) / -(((x * x) * x) * x)) - (1.0 - (-0.5 / (x * x)))) / -x));
}
public static double code(double x) {
	return (1.0 / Math.sqrt(Math.PI)) * (Math.exp((x * x)) * (((((1.875 / (x * x)) + 0.75) / -(((x * x) * x) * x)) - (1.0 - (-0.5 / (x * x)))) / -x));
}
def code(x):
	return (1.0 / math.sqrt(math.pi)) * (math.exp((x * x)) * (((((1.875 / (x * x)) + 0.75) / -(((x * x) * x) * x)) - (1.0 - (-0.5 / (x * x)))) / -x))
function code(x)
	return Float64(Float64(1.0 / sqrt(pi)) * Float64(exp(Float64(x * x)) * Float64(Float64(Float64(Float64(Float64(1.875 / Float64(x * x)) + 0.75) / Float64(-Float64(Float64(Float64(x * x) * x) * x))) - Float64(1.0 - Float64(-0.5 / Float64(x * x)))) / Float64(-x))))
end
function tmp = code(x)
	tmp = (1.0 / sqrt(pi)) * (exp((x * x)) * (((((1.875 / (x * x)) + 0.75) / -(((x * x) * x) * x)) - (1.0 - (-0.5 / (x * x)))) / -x));
end
code[x_] := N[(N[(1.0 / N[Sqrt[Pi], $MachinePrecision]), $MachinePrecision] * N[(N[Exp[N[(x * x), $MachinePrecision]], $MachinePrecision] * N[(N[(N[(N[(N[(1.875 / N[(x * x), $MachinePrecision]), $MachinePrecision] + 0.75), $MachinePrecision] / (-N[(N[(N[(x * x), $MachinePrecision] * x), $MachinePrecision] * x), $MachinePrecision])), $MachinePrecision] - N[(1.0 - N[(-0.5 / N[(x * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / (-x)), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{1}{\sqrt{\pi}} \cdot \left(e^{x \cdot x} \cdot \frac{\frac{\frac{1.875}{x \cdot x} + 0.75}{-\left(\left(x \cdot x\right) \cdot x\right) \cdot x} - \left(1 - \frac{-0.5}{x \cdot x}\right)}{-x}\right)
\end{array}
Derivation
  1. Initial program 100.0%

    \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
  2. Taylor expanded in x around 0

    \[\leadsto \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \color{blue}{\left(\frac{3}{4} \cdot \frac{1}{{\left(\left|x\right|\right)}^{5}} + \left(\frac{15}{8} \cdot \frac{1}{{\left(\left|x\right|\right)}^{7}} + \left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \frac{1}{{\left(\left|x\right|\right)}^{3}}\right)\right)\right)} \]
  3. Applied rewrites100.0%

    \[\leadsto \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{0.5}{x \cdot x} + 1, \frac{1}{\left|x\right|}, \mathsf{fma}\left({\left(\left|x\right|\right)}^{-7}, 1.875, {\left(\left|x\right|\right)}^{-5} \cdot 0.75\right)\right)} \]
  4. Taylor expanded in x around 0

    \[\leadsto \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \color{blue}{\left(\frac{3}{4} \cdot \frac{1}{{\left(\left|x\right|\right)}^{5}} + \left(\frac{15}{8} \cdot \frac{1}{{\left(\left|x\right|\right)}^{7}} + \left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \frac{1}{{\left(\left|x\right|\right)}^{3}}\right)\right)\right)} \]
  5. Applied rewrites100.0%

    \[\leadsto \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \color{blue}{\mathsf{fma}\left({x}^{-5}, 0.75, \mathsf{fma}\left({x}^{-7}, 1.875, \frac{\frac{0.5}{x \cdot x} + 1}{x}\right)\right)} \]
  6. Taylor expanded in x around -inf

    \[\leadsto \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(-1 \cdot \color{blue}{\frac{-1 \cdot \frac{\frac{3}{4} + \frac{15}{8} \cdot \frac{1}{{x}^{2}}}{{x}^{4}} - \left(1 + \frac{1}{2} \cdot \frac{1}{{x}^{2}}\right)}{x}}\right) \]
  7. Applied rewrites100.0%

    \[\leadsto \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(-\frac{\left(\left(-\frac{\frac{1.875}{x \cdot x} + 0.75}{\left(x \cdot x\right) \cdot \left(x \cdot x\right)}\right) - 1\right) - \frac{0.5}{x \cdot x}}{x}\right) \]
  8. Applied rewrites100.0%

    \[\leadsto \color{blue}{\frac{1}{\sqrt{\pi}} \cdot \left(e^{x \cdot x} \cdot \frac{\frac{\frac{1.875}{x \cdot x} + 0.75}{-\left(\left(x \cdot x\right) \cdot x\right) \cdot x} - \left(1 - \frac{-0.5}{x \cdot x}\right)}{-x}\right)} \]
  9. Add Preprocessing

Alternative 3: 100.0% accurate, 2.7× speedup?

\[\begin{array}{l} \\ \left(-\frac{\left(\left(-\frac{\frac{1.875}{x \cdot x} + 0.75}{\left(x \cdot x\right) \cdot \left(x \cdot x\right)}\right) - 1\right) - \frac{0.5}{x \cdot x}}{x}\right) \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \end{array} \]
(FPCore (x)
 :precision binary64
 (*
  (-
   (/
    (-
     (- (- (/ (+ (/ 1.875 (* x x)) 0.75) (* (* x x) (* x x)))) 1.0)
     (/ 0.5 (* x x)))
    x))
  (/ (exp (* x x)) (sqrt PI))))
double code(double x) {
	return -(((-(((1.875 / (x * x)) + 0.75) / ((x * x) * (x * x))) - 1.0) - (0.5 / (x * x))) / x) * (exp((x * x)) / sqrt(((double) M_PI)));
}
public static double code(double x) {
	return -(((-(((1.875 / (x * x)) + 0.75) / ((x * x) * (x * x))) - 1.0) - (0.5 / (x * x))) / x) * (Math.exp((x * x)) / Math.sqrt(Math.PI));
}
def code(x):
	return -(((-(((1.875 / (x * x)) + 0.75) / ((x * x) * (x * x))) - 1.0) - (0.5 / (x * x))) / x) * (math.exp((x * x)) / math.sqrt(math.pi))
function code(x)
	return Float64(Float64(-Float64(Float64(Float64(Float64(-Float64(Float64(Float64(1.875 / Float64(x * x)) + 0.75) / Float64(Float64(x * x) * Float64(x * x)))) - 1.0) - Float64(0.5 / Float64(x * x))) / x)) * Float64(exp(Float64(x * x)) / sqrt(pi)))
end
function tmp = code(x)
	tmp = -(((-(((1.875 / (x * x)) + 0.75) / ((x * x) * (x * x))) - 1.0) - (0.5 / (x * x))) / x) * (exp((x * x)) / sqrt(pi));
end
code[x_] := N[((-N[(N[(N[((-N[(N[(N[(1.875 / N[(x * x), $MachinePrecision]), $MachinePrecision] + 0.75), $MachinePrecision] / N[(N[(x * x), $MachinePrecision] * N[(x * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]) - 1.0), $MachinePrecision] - N[(0.5 / N[(x * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / x), $MachinePrecision]) * N[(N[Exp[N[(x * x), $MachinePrecision]], $MachinePrecision] / N[Sqrt[Pi], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\left(-\frac{\left(\left(-\frac{\frac{1.875}{x \cdot x} + 0.75}{\left(x \cdot x\right) \cdot \left(x \cdot x\right)}\right) - 1\right) - \frac{0.5}{x \cdot x}}{x}\right) \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}}
\end{array}
Derivation
  1. Initial program 100.0%

    \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
  2. Taylor expanded in x around 0

    \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \left(e^{{\left(\left|x\right|\right)}^{2}} \cdot \left(\frac{3}{4} \cdot \frac{1}{{\left(\left|x\right|\right)}^{5}} + \left(\frac{15}{8} \cdot \frac{1}{{\left(\left|x\right|\right)}^{7}} + \left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \frac{1}{{\left(\left|x\right|\right)}^{3}}\right)\right)\right)\right)} \]
  3. Applied rewrites100.0%

    \[\leadsto \color{blue}{\mathsf{fma}\left(\frac{0.5}{x \cdot x} + 1, \frac{1}{\left|x\right|}, \mathsf{fma}\left({\left(\left|x\right|\right)}^{-7}, 1.875, {\left(\left|x\right|\right)}^{-5} \cdot 0.75\right)\right) \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}}} \]
  4. Taylor expanded in x around inf

    \[\leadsto \left(\frac{3}{4} \cdot \frac{1}{{\left(\left|x\right|\right)}^{5}} + \left(\frac{15}{8} \cdot \frac{1}{{\left(\left|x\right|\right)}^{7}} + \left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \frac{1}{{x}^{2} \cdot \left|x\right|}\right)\right)\right) \cdot \frac{\color{blue}{e^{x \cdot x}}}{\sqrt{\pi}} \]
  5. Applied rewrites100.0%

    \[\leadsto \mathsf{fma}\left({x}^{-5}, 0.75, \mathsf{fma}\left({x}^{-7}, 1.875, \frac{\frac{0.5}{x \cdot x} + 1}{x}\right)\right) \cdot \frac{\color{blue}{e^{x \cdot x}}}{\sqrt{\pi}} \]
  6. Taylor expanded in x around -inf

    \[\leadsto \left(-1 \cdot \frac{-1 \cdot \frac{\frac{3}{4} + \frac{15}{8} \cdot \frac{1}{{x}^{2}}}{{x}^{4}} - \left(1 + \frac{1}{2} \cdot \frac{1}{{x}^{2}}\right)}{x}\right) \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
  7. Applied rewrites100.0%

    \[\leadsto \left(-\frac{\left(\left(-\frac{\frac{1.875}{x \cdot x} + 0.75}{\left(x \cdot x\right) \cdot \left(x \cdot x\right)}\right) - 1\right) - \frac{0.5}{x \cdot x}}{x}\right) \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
  8. Add Preprocessing

Alternative 4: 99.7% accurate, 3.7× speedup?

\[\begin{array}{l} \\ \frac{\frac{\frac{0.75}{x \cdot x} + 0.5}{x \cdot x} + 1}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \end{array} \]
(FPCore (x)
 :precision binary64
 (*
  (/ (+ (/ (+ (/ 0.75 (* x x)) 0.5) (* x x)) 1.0) x)
  (/ (exp (* x x)) (sqrt PI))))
double code(double x) {
	return (((((0.75 / (x * x)) + 0.5) / (x * x)) + 1.0) / x) * (exp((x * x)) / sqrt(((double) M_PI)));
}
public static double code(double x) {
	return (((((0.75 / (x * x)) + 0.5) / (x * x)) + 1.0) / x) * (Math.exp((x * x)) / Math.sqrt(Math.PI));
}
def code(x):
	return (((((0.75 / (x * x)) + 0.5) / (x * x)) + 1.0) / x) * (math.exp((x * x)) / math.sqrt(math.pi))
function code(x)
	return Float64(Float64(Float64(Float64(Float64(Float64(0.75 / Float64(x * x)) + 0.5) / Float64(x * x)) + 1.0) / x) * Float64(exp(Float64(x * x)) / sqrt(pi)))
end
function tmp = code(x)
	tmp = (((((0.75 / (x * x)) + 0.5) / (x * x)) + 1.0) / x) * (exp((x * x)) / sqrt(pi));
end
code[x_] := N[(N[(N[(N[(N[(N[(0.75 / N[(x * x), $MachinePrecision]), $MachinePrecision] + 0.5), $MachinePrecision] / N[(x * x), $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision] / x), $MachinePrecision] * N[(N[Exp[N[(x * x), $MachinePrecision]], $MachinePrecision] / N[Sqrt[Pi], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{\frac{\frac{0.75}{x \cdot x} + 0.5}{x \cdot x} + 1}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}}
\end{array}
Derivation
  1. Initial program 100.0%

    \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
  2. Taylor expanded in x around 0

    \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \left(e^{{\left(\left|x\right|\right)}^{2}} \cdot \left(\frac{3}{4} \cdot \frac{1}{{\left(\left|x\right|\right)}^{5}} + \left(\frac{15}{8} \cdot \frac{1}{{\left(\left|x\right|\right)}^{7}} + \left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \frac{1}{{\left(\left|x\right|\right)}^{3}}\right)\right)\right)\right)} \]
  3. Applied rewrites100.0%

    \[\leadsto \color{blue}{\mathsf{fma}\left(\frac{0.5}{x \cdot x} + 1, \frac{1}{\left|x\right|}, \mathsf{fma}\left({\left(\left|x\right|\right)}^{-7}, 1.875, {\left(\left|x\right|\right)}^{-5} \cdot 0.75\right)\right) \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}}} \]
  4. Taylor expanded in x around inf

    \[\leadsto \left(\frac{3}{4} \cdot \frac{1}{{\left(\left|x\right|\right)}^{5}} + \left(\frac{15}{8} \cdot \frac{1}{{\left(\left|x\right|\right)}^{7}} + \left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \frac{1}{{x}^{2} \cdot \left|x\right|}\right)\right)\right) \cdot \frac{\color{blue}{e^{x \cdot x}}}{\sqrt{\pi}} \]
  5. Applied rewrites100.0%

    \[\leadsto \mathsf{fma}\left({x}^{-5}, 0.75, \mathsf{fma}\left({x}^{-7}, 1.875, \frac{\frac{0.5}{x \cdot x} + 1}{x}\right)\right) \cdot \frac{\color{blue}{e^{x \cdot x}}}{\sqrt{\pi}} \]
  6. Taylor expanded in x around -inf

    \[\leadsto \left(-1 \cdot \frac{-1 \cdot \frac{\frac{1}{2} + \frac{3}{4} \cdot \frac{1}{{x}^{2}}}{{x}^{2}} - 1}{x}\right) \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
  7. Step-by-step derivation
    1. metadata-evalN/A

      \[\leadsto \left(-1 \cdot \frac{-1 \cdot \frac{\frac{1}{2} + \frac{3}{4} \cdot \frac{1}{{x}^{2}}}{{x}^{2}} - 1}{x}\right) \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
    2. metadata-evalN/A

      \[\leadsto \left(-1 \cdot \frac{-1 \cdot \frac{\frac{1}{2} + \frac{3}{4} \cdot \frac{1}{{x}^{2}}}{{x}^{2}} - 1}{x}\right) \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
    3. mul-1-negN/A

      \[\leadsto \left(\mathsf{neg}\left(\frac{-1 \cdot \frac{\frac{1}{2} + \frac{3}{4} \cdot \frac{1}{{x}^{2}}}{{x}^{2}} - 1}{x}\right)\right) \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
    4. lower-neg.f64N/A

      \[\leadsto \left(-\frac{-1 \cdot \frac{\frac{1}{2} + \frac{3}{4} \cdot \frac{1}{{x}^{2}}}{{x}^{2}} - 1}{x}\right) \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
    5. lower-/.f64N/A

      \[\leadsto \left(-\frac{-1 \cdot \frac{\frac{1}{2} + \frac{3}{4} \cdot \frac{1}{{x}^{2}}}{{x}^{2}} - 1}{x}\right) \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
  8. Applied rewrites99.7%

    \[\leadsto \left(-\frac{\left(-\frac{\frac{0.75}{x \cdot x} + 0.5}{x \cdot x}\right) - 1}{x}\right) \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
  9. Taylor expanded in x around inf

    \[\leadsto \frac{1 + \left(\frac{\frac{3}{4}}{{x}^{4}} + \frac{1}{2} \cdot \frac{1}{{x}^{2}}\right)}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
  10. Applied rewrites99.7%

    \[\leadsto \frac{\frac{\frac{0.75}{x \cdot x} + 0.5}{x \cdot x} + 1}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
  11. Add Preprocessing

Alternative 5: 99.7% accurate, 4.7× speedup?

\[\begin{array}{l} \\ \frac{1 - \frac{-0.5}{x \cdot x}}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \end{array} \]
(FPCore (x)
 :precision binary64
 (* (/ (- 1.0 (/ -0.5 (* x x))) x) (/ (exp (* x x)) (sqrt PI))))
double code(double x) {
	return ((1.0 - (-0.5 / (x * x))) / x) * (exp((x * x)) / sqrt(((double) M_PI)));
}
public static double code(double x) {
	return ((1.0 - (-0.5 / (x * x))) / x) * (Math.exp((x * x)) / Math.sqrt(Math.PI));
}
def code(x):
	return ((1.0 - (-0.5 / (x * x))) / x) * (math.exp((x * x)) / math.sqrt(math.pi))
function code(x)
	return Float64(Float64(Float64(1.0 - Float64(-0.5 / Float64(x * x))) / x) * Float64(exp(Float64(x * x)) / sqrt(pi)))
end
function tmp = code(x)
	tmp = ((1.0 - (-0.5 / (x * x))) / x) * (exp((x * x)) / sqrt(pi));
end
code[x_] := N[(N[(N[(1.0 - N[(-0.5 / N[(x * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / x), $MachinePrecision] * N[(N[Exp[N[(x * x), $MachinePrecision]], $MachinePrecision] / N[Sqrt[Pi], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{1 - \frac{-0.5}{x \cdot x}}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}}
\end{array}
Derivation
  1. Initial program 100.0%

    \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
  2. Taylor expanded in x around 0

    \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \left(e^{{\left(\left|x\right|\right)}^{2}} \cdot \left(\frac{3}{4} \cdot \frac{1}{{\left(\left|x\right|\right)}^{5}} + \left(\frac{15}{8} \cdot \frac{1}{{\left(\left|x\right|\right)}^{7}} + \left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \frac{1}{{\left(\left|x\right|\right)}^{3}}\right)\right)\right)\right)} \]
  3. Applied rewrites100.0%

    \[\leadsto \color{blue}{\mathsf{fma}\left(\frac{0.5}{x \cdot x} + 1, \frac{1}{\left|x\right|}, \mathsf{fma}\left({\left(\left|x\right|\right)}^{-7}, 1.875, {\left(\left|x\right|\right)}^{-5} \cdot 0.75\right)\right) \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}}} \]
  4. Taylor expanded in x around inf

    \[\leadsto \left(\frac{3}{4} \cdot \frac{1}{{\left(\left|x\right|\right)}^{5}} + \left(\frac{15}{8} \cdot \frac{1}{{\left(\left|x\right|\right)}^{7}} + \left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \frac{1}{{x}^{2} \cdot \left|x\right|}\right)\right)\right) \cdot \frac{\color{blue}{e^{x \cdot x}}}{\sqrt{\pi}} \]
  5. Applied rewrites100.0%

    \[\leadsto \mathsf{fma}\left({x}^{-5}, 0.75, \mathsf{fma}\left({x}^{-7}, 1.875, \frac{\frac{0.5}{x \cdot x} + 1}{x}\right)\right) \cdot \frac{\color{blue}{e^{x \cdot x}}}{\sqrt{\pi}} \]
  6. Taylor expanded in x around -inf

    \[\leadsto \left(-1 \cdot \frac{-1 \cdot \frac{\frac{1}{2} + \frac{3}{4} \cdot \frac{1}{{x}^{2}}}{{x}^{2}} - 1}{x}\right) \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
  7. Step-by-step derivation
    1. metadata-evalN/A

      \[\leadsto \left(-1 \cdot \frac{-1 \cdot \frac{\frac{1}{2} + \frac{3}{4} \cdot \frac{1}{{x}^{2}}}{{x}^{2}} - 1}{x}\right) \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
    2. metadata-evalN/A

      \[\leadsto \left(-1 \cdot \frac{-1 \cdot \frac{\frac{1}{2} + \frac{3}{4} \cdot \frac{1}{{x}^{2}}}{{x}^{2}} - 1}{x}\right) \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
    3. mul-1-negN/A

      \[\leadsto \left(\mathsf{neg}\left(\frac{-1 \cdot \frac{\frac{1}{2} + \frac{3}{4} \cdot \frac{1}{{x}^{2}}}{{x}^{2}} - 1}{x}\right)\right) \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
    4. lower-neg.f64N/A

      \[\leadsto \left(-\frac{-1 \cdot \frac{\frac{1}{2} + \frac{3}{4} \cdot \frac{1}{{x}^{2}}}{{x}^{2}} - 1}{x}\right) \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
    5. lower-/.f64N/A

      \[\leadsto \left(-\frac{-1 \cdot \frac{\frac{1}{2} + \frac{3}{4} \cdot \frac{1}{{x}^{2}}}{{x}^{2}} - 1}{x}\right) \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
  8. Applied rewrites99.7%

    \[\leadsto \left(-\frac{\left(-\frac{\frac{0.75}{x \cdot x} + 0.5}{x \cdot x}\right) - 1}{x}\right) \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
  9. Taylor expanded in x around inf

    \[\leadsto \frac{1 + \frac{1}{2} \cdot \frac{1}{{x}^{2}}}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
  10. Step-by-step derivation
    1. metadata-evalN/A

      \[\leadsto \frac{1 + \frac{1}{2} \cdot \frac{1}{{x}^{2}}}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
    2. lower-/.f64N/A

      \[\leadsto \frac{1 + \frac{1}{2} \cdot \frac{1}{{x}^{2}}}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
    3. fp-cancel-sign-sub-invN/A

      \[\leadsto \frac{1 - \left(\mathsf{neg}\left(\frac{1}{2}\right)\right) \cdot \frac{1}{{x}^{2}}}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
    4. metadata-evalN/A

      \[\leadsto \frac{1 - \left(\mathsf{neg}\left(\frac{1}{2}\right)\right) \cdot \frac{1}{{x}^{2}}}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
    5. metadata-evalN/A

      \[\leadsto \frac{1 - \frac{-1}{2} \cdot \frac{1}{{x}^{2}}}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
    6. metadata-evalN/A

      \[\leadsto \frac{1 - \frac{\frac{1}{2}}{-1} \cdot \frac{1}{{x}^{2}}}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
    7. metadata-evalN/A

      \[\leadsto \frac{1 - \frac{\frac{1}{2}}{-1} \cdot \frac{1}{{x}^{2}}}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
    8. times-fracN/A

      \[\leadsto \frac{1 - \frac{\frac{1}{2} \cdot 1}{-1 \cdot {x}^{2}}}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
    9. metadata-evalN/A

      \[\leadsto \frac{1 - \frac{\frac{1}{2} \cdot 1}{-1 \cdot {x}^{2}}}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
    10. metadata-evalN/A

      \[\leadsto \frac{1 - \frac{\frac{1}{2}}{-1 \cdot {x}^{2}}}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
    11. metadata-evalN/A

      \[\leadsto \frac{1 - \frac{\mathsf{neg}\left(\frac{-1}{2}\right)}{-1 \cdot {x}^{2}}}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
    12. mul-1-negN/A

      \[\leadsto \frac{1 - \frac{\mathsf{neg}\left(\frac{-1}{2}\right)}{\mathsf{neg}\left({x}^{2}\right)}}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
    13. frac-2negN/A

      \[\leadsto \frac{1 - \frac{\frac{-1}{2}}{{x}^{2}}}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
    14. lower--.f64N/A

      \[\leadsto \frac{1 - \frac{\frac{-1}{2}}{{x}^{2}}}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
    15. lower-/.f64N/A

      \[\leadsto \frac{1 - \frac{\frac{-1}{2}}{{x}^{2}}}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
    16. pow2N/A

      \[\leadsto \frac{1 - \frac{\frac{-1}{2}}{x \cdot x}}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
    17. lift-*.f6499.7

      \[\leadsto \frac{1 - \frac{-0.5}{x \cdot x}}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
  11. Applied rewrites99.7%

    \[\leadsto \frac{1 - \frac{-0.5}{x \cdot x}}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
  12. Add Preprocessing

Alternative 6: 99.7% accurate, 6.4× speedup?

\[\begin{array}{l} \\ \frac{e^{x \cdot x}}{\sqrt{\pi}} \cdot \frac{1}{x} \end{array} \]
(FPCore (x) :precision binary64 (* (/ (exp (* x x)) (sqrt PI)) (/ 1.0 x)))
double code(double x) {
	return (exp((x * x)) / sqrt(((double) M_PI))) * (1.0 / x);
}
public static double code(double x) {
	return (Math.exp((x * x)) / Math.sqrt(Math.PI)) * (1.0 / x);
}
def code(x):
	return (math.exp((x * x)) / math.sqrt(math.pi)) * (1.0 / x)
function code(x)
	return Float64(Float64(exp(Float64(x * x)) / sqrt(pi)) * Float64(1.0 / x))
end
function tmp = code(x)
	tmp = (exp((x * x)) / sqrt(pi)) * (1.0 / x);
end
code[x_] := N[(N[(N[Exp[N[(x * x), $MachinePrecision]], $MachinePrecision] / N[Sqrt[Pi], $MachinePrecision]), $MachinePrecision] * N[(1.0 / x), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{e^{x \cdot x}}{\sqrt{\pi}} \cdot \frac{1}{x}
\end{array}
Derivation
  1. Initial program 100.0%

    \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
  2. Taylor expanded in x around 0

    \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \left(e^{{\left(\left|x\right|\right)}^{2}} \cdot \left(\frac{3}{4} \cdot \frac{1}{{\left(\left|x\right|\right)}^{5}} + \left(\frac{15}{8} \cdot \frac{1}{{\left(\left|x\right|\right)}^{7}} + \left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \frac{1}{{\left(\left|x\right|\right)}^{3}}\right)\right)\right)\right)} \]
  3. Applied rewrites100.0%

    \[\leadsto \color{blue}{\mathsf{fma}\left(\frac{0.5}{x \cdot x} + 1, \frac{1}{\left|x\right|}, \mathsf{fma}\left({\left(\left|x\right|\right)}^{-7}, 1.875, {\left(\left|x\right|\right)}^{-5} \cdot 0.75\right)\right) \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}}} \]
  4. Taylor expanded in x around inf

    \[\leadsto \left(\frac{3}{4} \cdot \frac{1}{{\left(\left|x\right|\right)}^{5}} + \left(\frac{15}{8} \cdot \frac{1}{{\left(\left|x\right|\right)}^{7}} + \left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \frac{1}{{x}^{2} \cdot \left|x\right|}\right)\right)\right) \cdot \frac{\color{blue}{e^{x \cdot x}}}{\sqrt{\pi}} \]
  5. Applied rewrites100.0%

    \[\leadsto \mathsf{fma}\left({x}^{-5}, 0.75, \mathsf{fma}\left({x}^{-7}, 1.875, \frac{\frac{0.5}{x \cdot x} + 1}{x}\right)\right) \cdot \frac{\color{blue}{e^{x \cdot x}}}{\sqrt{\pi}} \]
  6. Taylor expanded in x around inf

    \[\leadsto \frac{1}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
  7. Step-by-step derivation
    1. lift-/.f6499.7

      \[\leadsto \frac{1}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
  8. Applied rewrites99.7%

    \[\leadsto \frac{1}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
  9. Applied rewrites99.7%

    \[\leadsto \color{blue}{\frac{e^{x \cdot x}}{\sqrt{\pi}} \cdot \frac{1}{x}} \]
  10. Add Preprocessing

Alternative 7: 52.6% accurate, 9.4× speedup?

\[\begin{array}{l} \\ \frac{1}{x} \cdot \frac{\mathsf{fma}\left(x, x, 1\right)}{\sqrt{\pi}} \end{array} \]
(FPCore (x) :precision binary64 (* (/ 1.0 x) (/ (fma x x 1.0) (sqrt PI))))
double code(double x) {
	return (1.0 / x) * (fma(x, x, 1.0) / sqrt(((double) M_PI)));
}
function code(x)
	return Float64(Float64(1.0 / x) * Float64(fma(x, x, 1.0) / sqrt(pi)))
end
code[x_] := N[(N[(1.0 / x), $MachinePrecision] * N[(N[(x * x + 1.0), $MachinePrecision] / N[Sqrt[Pi], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{1}{x} \cdot \frac{\mathsf{fma}\left(x, x, 1\right)}{\sqrt{\pi}}
\end{array}
Derivation
  1. Initial program 100.0%

    \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
  2. Taylor expanded in x around 0

    \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \left(e^{{\left(\left|x\right|\right)}^{2}} \cdot \left(\frac{3}{4} \cdot \frac{1}{{\left(\left|x\right|\right)}^{5}} + \left(\frac{15}{8} \cdot \frac{1}{{\left(\left|x\right|\right)}^{7}} + \left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \frac{1}{{\left(\left|x\right|\right)}^{3}}\right)\right)\right)\right)} \]
  3. Applied rewrites100.0%

    \[\leadsto \color{blue}{\mathsf{fma}\left(\frac{0.5}{x \cdot x} + 1, \frac{1}{\left|x\right|}, \mathsf{fma}\left({\left(\left|x\right|\right)}^{-7}, 1.875, {\left(\left|x\right|\right)}^{-5} \cdot 0.75\right)\right) \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}}} \]
  4. Taylor expanded in x around inf

    \[\leadsto \left(\frac{3}{4} \cdot \frac{1}{{\left(\left|x\right|\right)}^{5}} + \left(\frac{15}{8} \cdot \frac{1}{{\left(\left|x\right|\right)}^{7}} + \left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \frac{1}{{x}^{2} \cdot \left|x\right|}\right)\right)\right) \cdot \frac{\color{blue}{e^{x \cdot x}}}{\sqrt{\pi}} \]
  5. Applied rewrites100.0%

    \[\leadsto \mathsf{fma}\left({x}^{-5}, 0.75, \mathsf{fma}\left({x}^{-7}, 1.875, \frac{\frac{0.5}{x \cdot x} + 1}{x}\right)\right) \cdot \frac{\color{blue}{e^{x \cdot x}}}{\sqrt{\pi}} \]
  6. Taylor expanded in x around inf

    \[\leadsto \frac{1}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
  7. Step-by-step derivation
    1. lift-/.f6499.7

      \[\leadsto \frac{1}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
  8. Applied rewrites99.7%

    \[\leadsto \frac{1}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
  9. Taylor expanded in x around 0

    \[\leadsto \frac{1}{x} \cdot \frac{1 + {x}^{2}}{\sqrt{\color{blue}{\pi}}} \]
  10. Step-by-step derivation
    1. +-commutativeN/A

      \[\leadsto \frac{1}{x} \cdot \frac{{x}^{2} + 1}{\sqrt{\pi}} \]
    2. pow2N/A

      \[\leadsto \frac{1}{x} \cdot \frac{x \cdot x + 1}{\sqrt{\pi}} \]
    3. lower-fma.f6452.6

      \[\leadsto \frac{1}{x} \cdot \frac{\mathsf{fma}\left(x, x, 1\right)}{\sqrt{\pi}} \]
  11. Applied rewrites52.6%

    \[\leadsto \frac{1}{x} \cdot \frac{\mathsf{fma}\left(x, x, 1\right)}{\sqrt{\color{blue}{\pi}}} \]
  12. Add Preprocessing

Alternative 8: 2.3% accurate, 13.1× speedup?

\[\begin{array}{l} \\ \frac{1}{x} \cdot \frac{1}{\sqrt{\pi}} \end{array} \]
(FPCore (x) :precision binary64 (* (/ 1.0 x) (/ 1.0 (sqrt PI))))
double code(double x) {
	return (1.0 / x) * (1.0 / sqrt(((double) M_PI)));
}
public static double code(double x) {
	return (1.0 / x) * (1.0 / Math.sqrt(Math.PI));
}
def code(x):
	return (1.0 / x) * (1.0 / math.sqrt(math.pi))
function code(x)
	return Float64(Float64(1.0 / x) * Float64(1.0 / sqrt(pi)))
end
function tmp = code(x)
	tmp = (1.0 / x) * (1.0 / sqrt(pi));
end
code[x_] := N[(N[(1.0 / x), $MachinePrecision] * N[(1.0 / N[Sqrt[Pi], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{1}{x} \cdot \frac{1}{\sqrt{\pi}}
\end{array}
Derivation
  1. Initial program 100.0%

    \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
  2. Taylor expanded in x around 0

    \[\leadsto \color{blue}{\sqrt{\frac{1}{\mathsf{PI}\left(\right)}} \cdot \left(e^{{\left(\left|x\right|\right)}^{2}} \cdot \left(\frac{3}{4} \cdot \frac{1}{{\left(\left|x\right|\right)}^{5}} + \left(\frac{15}{8} \cdot \frac{1}{{\left(\left|x\right|\right)}^{7}} + \left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \frac{1}{{\left(\left|x\right|\right)}^{3}}\right)\right)\right)\right)} \]
  3. Applied rewrites100.0%

    \[\leadsto \color{blue}{\mathsf{fma}\left(\frac{0.5}{x \cdot x} + 1, \frac{1}{\left|x\right|}, \mathsf{fma}\left({\left(\left|x\right|\right)}^{-7}, 1.875, {\left(\left|x\right|\right)}^{-5} \cdot 0.75\right)\right) \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}}} \]
  4. Taylor expanded in x around inf

    \[\leadsto \left(\frac{3}{4} \cdot \frac{1}{{\left(\left|x\right|\right)}^{5}} + \left(\frac{15}{8} \cdot \frac{1}{{\left(\left|x\right|\right)}^{7}} + \left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \frac{1}{{x}^{2} \cdot \left|x\right|}\right)\right)\right) \cdot \frac{\color{blue}{e^{x \cdot x}}}{\sqrt{\pi}} \]
  5. Applied rewrites100.0%

    \[\leadsto \mathsf{fma}\left({x}^{-5}, 0.75, \mathsf{fma}\left({x}^{-7}, 1.875, \frac{\frac{0.5}{x \cdot x} + 1}{x}\right)\right) \cdot \frac{\color{blue}{e^{x \cdot x}}}{\sqrt{\pi}} \]
  6. Taylor expanded in x around inf

    \[\leadsto \frac{1}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
  7. Step-by-step derivation
    1. lift-/.f6499.7

      \[\leadsto \frac{1}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
  8. Applied rewrites99.7%

    \[\leadsto \frac{1}{x} \cdot \frac{e^{x \cdot x}}{\sqrt{\pi}} \]
  9. Taylor expanded in x around 0

    \[\leadsto \frac{1}{x} \cdot \frac{1}{\sqrt{\color{blue}{\pi}}} \]
  10. Step-by-step derivation
    1. Applied rewrites2.3%

      \[\leadsto \frac{1}{x} \cdot \frac{1}{\sqrt{\color{blue}{\pi}}} \]
    2. Add Preprocessing

    Reproduce

    ?
    herbie shell --seed 2025117 
    (FPCore (x)
      :name "Jmat.Real.erfi, branch x greater than or equal to 5"
      :precision binary64
      :pre (>= x 0.5)
      (* (* (/ 1.0 (sqrt PI)) (exp (* (fabs x) (fabs x)))) (+ (+ (+ (/ 1.0 (fabs x)) (* (/ 1.0 2.0) (* (* (/ 1.0 (fabs x)) (/ 1.0 (fabs x))) (/ 1.0 (fabs x))))) (* (/ 3.0 4.0) (* (* (* (* (/ 1.0 (fabs x)) (/ 1.0 (fabs x))) (/ 1.0 (fabs x))) (/ 1.0 (fabs x))) (/ 1.0 (fabs x))))) (* (/ 15.0 8.0) (* (* (* (* (* (* (/ 1.0 (fabs x)) (/ 1.0 (fabs x))) (/ 1.0 (fabs x))) (/ 1.0 (fabs x))) (/ 1.0 (fabs x))) (/ 1.0 (fabs x))) (/ 1.0 (fabs x)))))))