ABCF->ab-angle angle

Percentage Accurate: 53.5% → 88.4%
Time: 5.8s
Alternatives: 18
Speedup: 2.3×

Specification

?
\[\begin{array}{l} \\ 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (*
  180.0
  (/
   (atan (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
   PI)))
double code(double A, double B, double C) {
	return 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / ((double) M_PI));
}
public static double code(double A, double B, double C) {
	return 180.0 * (Math.atan(((1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / Math.PI);
}
def code(A, B, C):
	return 180.0 * (math.atan(((1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / math.pi)
function code(A, B, C)
	return Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))) / pi))
end
function tmp = code(A, B, C)
	tmp = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / pi);
end
code[A_, B_, C_] := N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}
\end{array}

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 18 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 53.5% accurate, 1.0× speedup?

\[\begin{array}{l} \\ 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (*
  180.0
  (/
   (atan (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
   PI)))
double code(double A, double B, double C) {
	return 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / ((double) M_PI));
}
public static double code(double A, double B, double C) {
	return 180.0 * (Math.atan(((1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / Math.PI);
}
def code(A, B, C):
	return 180.0 * (math.atan(((1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / math.pi)
function code(A, B, C)
	return Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))) / pi))
end
function tmp = code(A, B, C)
	tmp = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / pi);
end
code[A_, B_, C_] := N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}
\end{array}

Alternative 1: 88.4% accurate, 0.4× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\ t_1 := \left(-A\right) + C\\ t_2 := 180 \cdot \frac{\tan^{-1} \left(\frac{t\_1 - \mathsf{hypot}\left(t\_1, B\right)}{B}\right)}{\pi}\\ \mathbf{if}\;t\_0 \leq -0.5:\\ \;\;\;\;t\_2\\ \mathbf{elif}\;t\_0 \leq 0:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;t\_2\\ \end{array} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (let* ((t_0
         (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
        (t_1 (+ (- A) C))
        (t_2 (* 180.0 (/ (atan (/ (- t_1 (hypot t_1 B)) B)) PI))))
   (if (<= t_0 -0.5)
     t_2
     (if (<= t_0 0.0) (* 180.0 (/ (atan (* (/ B (- C A)) -0.5)) PI)) t_2))))
double code(double A, double B, double C) {
	double t_0 = (1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0))));
	double t_1 = -A + C;
	double t_2 = 180.0 * (atan(((t_1 - hypot(t_1, B)) / B)) / ((double) M_PI));
	double tmp;
	if (t_0 <= -0.5) {
		tmp = t_2;
	} else if (t_0 <= 0.0) {
		tmp = 180.0 * (atan(((B / (C - A)) * -0.5)) / ((double) M_PI));
	} else {
		tmp = t_2;
	}
	return tmp;
}
public static double code(double A, double B, double C) {
	double t_0 = (1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0))));
	double t_1 = -A + C;
	double t_2 = 180.0 * (Math.atan(((t_1 - Math.hypot(t_1, B)) / B)) / Math.PI);
	double tmp;
	if (t_0 <= -0.5) {
		tmp = t_2;
	} else if (t_0 <= 0.0) {
		tmp = 180.0 * (Math.atan(((B / (C - A)) * -0.5)) / Math.PI);
	} else {
		tmp = t_2;
	}
	return tmp;
}
def code(A, B, C):
	t_0 = (1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0))))
	t_1 = -A + C
	t_2 = 180.0 * (math.atan(((t_1 - math.hypot(t_1, B)) / B)) / math.pi)
	tmp = 0
	if t_0 <= -0.5:
		tmp = t_2
	elif t_0 <= 0.0:
		tmp = 180.0 * (math.atan(((B / (C - A)) * -0.5)) / math.pi)
	else:
		tmp = t_2
	return tmp
function code(A, B, C)
	t_0 = Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))
	t_1 = Float64(Float64(-A) + C)
	t_2 = Float64(180.0 * Float64(atan(Float64(Float64(t_1 - hypot(t_1, B)) / B)) / pi))
	tmp = 0.0
	if (t_0 <= -0.5)
		tmp = t_2;
	elseif (t_0 <= 0.0)
		tmp = Float64(180.0 * Float64(atan(Float64(Float64(B / Float64(C - A)) * -0.5)) / pi));
	else
		tmp = t_2;
	end
	return tmp
end
function tmp_2 = code(A, B, C)
	t_0 = (1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0))));
	t_1 = -A + C;
	t_2 = 180.0 * (atan(((t_1 - hypot(t_1, B)) / B)) / pi);
	tmp = 0.0;
	if (t_0 <= -0.5)
		tmp = t_2;
	elseif (t_0 <= 0.0)
		tmp = 180.0 * (atan(((B / (C - A)) * -0.5)) / pi);
	else
		tmp = t_2;
	end
	tmp_2 = tmp;
end
code[A_, B_, C_] := Block[{t$95$0 = N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[((-A) + C), $MachinePrecision]}, Block[{t$95$2 = N[(180.0 * N[(N[ArcTan[N[(N[(t$95$1 - N[Sqrt[t$95$1 ^ 2 + B ^ 2], $MachinePrecision]), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, -0.5], t$95$2, If[LessEqual[t$95$0, 0.0], N[(180.0 * N[(N[ArcTan[N[(N[(B / N[(C - A), $MachinePrecision]), $MachinePrecision] * -0.5), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], t$95$2]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\
t_1 := \left(-A\right) + C\\
t_2 := 180 \cdot \frac{\tan^{-1} \left(\frac{t\_1 - \mathsf{hypot}\left(t\_1, B\right)}{B}\right)}{\pi}\\
\mathbf{if}\;t\_0 \leq -0.5:\\
\;\;\;\;t\_2\\

\mathbf{elif}\;t\_0 \leq 0:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi}\\

\mathbf{else}:\\
\;\;\;\;t\_2\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -0.5 or -0.0 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))

    1. Initial program 59.2%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Taylor expanded in A around -inf

      \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}}{\pi} \]
    3. Step-by-step derivation
      1. lower-atan.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
      2. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
    4. Applied rewrites87.0%

      \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]

    if -0.5 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -0.0

    1. Initial program 18.0%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Taylor expanded in A around -inf

      \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}}{\pi} \]
    3. Step-by-step derivation
      1. lower-atan.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
      2. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
    4. Applied rewrites19.5%

      \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
    5. Taylor expanded in B around 0

      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}{\pi} \]
    6. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
      2. lower-*.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
      3. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
      4. lift--.f6497.3

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi} \]
    7. Applied rewrites97.3%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi} \]
  3. Recombined 2 regimes into one program.
  4. Add Preprocessing

Alternative 2: 80.8% accurate, 1.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;C \leq 4.5 \cdot 10^{+37}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(-A, B\right)}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi}\\ \end{array} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (if (<= C 4.5e+37)
   (* 180.0 (/ (atan (/ (- (- C A) (hypot (- A) B)) B)) PI))
   (/ (* 180.0 (atan (* (/ B (- C A)) -0.5))) PI)))
double code(double A, double B, double C) {
	double tmp;
	if (C <= 4.5e+37) {
		tmp = 180.0 * (atan((((C - A) - hypot(-A, B)) / B)) / ((double) M_PI));
	} else {
		tmp = (180.0 * atan(((B / (C - A)) * -0.5))) / ((double) M_PI);
	}
	return tmp;
}
public static double code(double A, double B, double C) {
	double tmp;
	if (C <= 4.5e+37) {
		tmp = 180.0 * (Math.atan((((C - A) - Math.hypot(-A, B)) / B)) / Math.PI);
	} else {
		tmp = (180.0 * Math.atan(((B / (C - A)) * -0.5))) / Math.PI;
	}
	return tmp;
}
def code(A, B, C):
	tmp = 0
	if C <= 4.5e+37:
		tmp = 180.0 * (math.atan((((C - A) - math.hypot(-A, B)) / B)) / math.pi)
	else:
		tmp = (180.0 * math.atan(((B / (C - A)) * -0.5))) / math.pi
	return tmp
function code(A, B, C)
	tmp = 0.0
	if (C <= 4.5e+37)
		tmp = Float64(180.0 * Float64(atan(Float64(Float64(Float64(C - A) - hypot(Float64(-A), B)) / B)) / pi));
	else
		tmp = Float64(Float64(180.0 * atan(Float64(Float64(B / Float64(C - A)) * -0.5))) / pi);
	end
	return tmp
end
function tmp_2 = code(A, B, C)
	tmp = 0.0;
	if (C <= 4.5e+37)
		tmp = 180.0 * (atan((((C - A) - hypot(-A, B)) / B)) / pi);
	else
		tmp = (180.0 * atan(((B / (C - A)) * -0.5))) / pi;
	end
	tmp_2 = tmp;
end
code[A_, B_, C_] := If[LessEqual[C, 4.5e+37], N[(180.0 * N[(N[ArcTan[N[(N[(N[(C - A), $MachinePrecision] - N[Sqrt[(-A) ^ 2 + B ^ 2], $MachinePrecision]), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(N[(180.0 * N[ArcTan[N[(N[(B / N[(C - A), $MachinePrecision]), $MachinePrecision] * -0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;C \leq 4.5 \cdot 10^{+37}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(-A, B\right)}{B}\right)}{\pi}\\

\mathbf{else}:\\
\;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if C < 4.49999999999999962e37

    1. Initial program 62.1%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Taylor expanded in A around -inf

      \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}}{\pi} \]
    3. Step-by-step derivation
      1. lower-atan.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
      2. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
    4. Applied rewrites83.5%

      \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
    5. Taylor expanded in A around inf

      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(-1 \cdot A, B\right)}{B}\right)}{\pi} \]
    6. Step-by-step derivation
      1. mul-1-negN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\mathsf{neg}\left(A\right), B\right)}{B}\right)}{\pi} \]
      2. lift-neg.f6482.6

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(-A, B\right)}{B}\right)}{\pi} \]
    7. Applied rewrites82.6%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(-A, B\right)}{B}\right)}{\pi} \]
    8. Taylor expanded in C around 0

      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(-A, B\right)}{B}\right)}{\pi} \]
    9. Step-by-step derivation
      1. lift--.f6482.6

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(-A, B\right)}{B}\right)}{\pi} \]
    10. Applied rewrites82.6%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(-A, B\right)}{B}\right)}{\pi} \]

    if 4.49999999999999962e37 < C

    1. Initial program 23.4%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Taylor expanded in A around -inf

      \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}}{\pi} \]
    3. Step-by-step derivation
      1. lower-atan.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
      2. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
    4. Applied rewrites57.2%

      \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
    5. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
      2. lift-/.f64N/A

        \[\leadsto 180 \cdot \color{blue}{\frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
      3. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
      4. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
      5. lower-*.f6457.2

        \[\leadsto \frac{\color{blue}{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
    6. Applied rewrites57.2%

      \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
    7. Taylor expanded in B around 0

      \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}{\pi} \]
    8. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
      2. lower-*.f64N/A

        \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
      3. lower-/.f64N/A

        \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
      4. lift--.f6474.4

        \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi} \]
    9. Applied rewrites74.4%

      \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi} \]
  3. Recombined 2 regimes into one program.
  4. Add Preprocessing

Alternative 3: 78.8% accurate, 0.4× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}\\ \mathbf{if}\;t\_0 \leq -40:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - B}{B}\right)}{\pi}\\ \mathbf{elif}\;t\_0 \leq 0:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\ \end{array} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (let* ((t_0
         (*
          180.0
          (/
           (atan
            (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
           PI))))
   (if (<= t_0 -40.0)
     (* 180.0 (/ (atan (/ (- (+ (- A) C) B) B)) PI))
     (if (<= t_0 0.0)
       (* 180.0 (/ (atan (* (/ B (- C A)) -0.5)) PI))
       (* 180.0 (/ (atan (+ 1.0 (/ (- C A) B))) PI))))))
double code(double A, double B, double C) {
	double t_0 = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / ((double) M_PI));
	double tmp;
	if (t_0 <= -40.0) {
		tmp = 180.0 * (atan((((-A + C) - B) / B)) / ((double) M_PI));
	} else if (t_0 <= 0.0) {
		tmp = 180.0 * (atan(((B / (C - A)) * -0.5)) / ((double) M_PI));
	} else {
		tmp = 180.0 * (atan((1.0 + ((C - A) / B))) / ((double) M_PI));
	}
	return tmp;
}
public static double code(double A, double B, double C) {
	double t_0 = 180.0 * (Math.atan(((1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / Math.PI);
	double tmp;
	if (t_0 <= -40.0) {
		tmp = 180.0 * (Math.atan((((-A + C) - B) / B)) / Math.PI);
	} else if (t_0 <= 0.0) {
		tmp = 180.0 * (Math.atan(((B / (C - A)) * -0.5)) / Math.PI);
	} else {
		tmp = 180.0 * (Math.atan((1.0 + ((C - A) / B))) / Math.PI);
	}
	return tmp;
}
def code(A, B, C):
	t_0 = 180.0 * (math.atan(((1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / math.pi)
	tmp = 0
	if t_0 <= -40.0:
		tmp = 180.0 * (math.atan((((-A + C) - B) / B)) / math.pi)
	elif t_0 <= 0.0:
		tmp = 180.0 * (math.atan(((B / (C - A)) * -0.5)) / math.pi)
	else:
		tmp = 180.0 * (math.atan((1.0 + ((C - A) / B))) / math.pi)
	return tmp
function code(A, B, C)
	t_0 = Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))) / pi))
	tmp = 0.0
	if (t_0 <= -40.0)
		tmp = Float64(180.0 * Float64(atan(Float64(Float64(Float64(Float64(-A) + C) - B) / B)) / pi));
	elseif (t_0 <= 0.0)
		tmp = Float64(180.0 * Float64(atan(Float64(Float64(B / Float64(C - A)) * -0.5)) / pi));
	else
		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + Float64(Float64(C - A) / B))) / pi));
	end
	return tmp
end
function tmp_2 = code(A, B, C)
	t_0 = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / pi);
	tmp = 0.0;
	if (t_0 <= -40.0)
		tmp = 180.0 * (atan((((-A + C) - B) / B)) / pi);
	elseif (t_0 <= 0.0)
		tmp = 180.0 * (atan(((B / (C - A)) * -0.5)) / pi);
	else
		tmp = 180.0 * (atan((1.0 + ((C - A) / B))) / pi);
	end
	tmp_2 = tmp;
end
code[A_, B_, C_] := Block[{t$95$0 = N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, -40.0], N[(180.0 * N[(N[ArcTan[N[(N[(N[((-A) + C), $MachinePrecision] - B), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$0, 0.0], N[(180.0 * N[(N[ArcTan[N[(N[(B / N[(C - A), $MachinePrecision]), $MachinePrecision] * -0.5), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(1.0 + N[(N[(C - A), $MachinePrecision] / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}\\
\mathbf{if}\;t\_0 \leq -40:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - B}{B}\right)}{\pi}\\

\mathbf{elif}\;t\_0 \leq 0:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi}\\

\mathbf{else}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (*.f64 #s(literal 180 binary64) (/.f64 (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))) (PI.f64))) < -40

    1. Initial program 59.5%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Taylor expanded in A around -inf

      \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}}{\pi} \]
    3. Step-by-step derivation
      1. lower-atan.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
      2. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
    4. Applied rewrites86.8%

      \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
    5. Taylor expanded in B around inf

      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - B}{B}\right)}{\pi} \]
    6. Step-by-step derivation
      1. Applied rewrites76.1%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - B}{B}\right)}{\pi} \]

      if -40 < (*.f64 #s(literal 180 binary64) (/.f64 (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))) (PI.f64))) < -0.0

      1. Initial program 18.0%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Taylor expanded in A around -inf

        \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}}{\pi} \]
      3. Step-by-step derivation
        1. lower-atan.f64N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
        2. lower-/.f64N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
      4. Applied rewrites19.6%

        \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
      5. Taylor expanded in B around 0

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}{\pi} \]
      6. Step-by-step derivation
        1. *-commutativeN/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
        2. lower-*.f64N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
        3. lower-/.f64N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
        4. lift--.f6497.2

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi} \]
      7. Applied rewrites97.2%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi} \]

      if -0.0 < (*.f64 #s(literal 180 binary64) (/.f64 (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))) (PI.f64)))

      1. Initial program 58.8%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Taylor expanded in B around -inf

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
      3. Step-by-step derivation
        1. associate--l+N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
        2. div-subN/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
        3. lower-+.f64N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
        4. lower-/.f64N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
        5. lift--.f6475.4

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
      4. Applied rewrites75.4%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
    7. Recombined 3 regimes into one program.
    8. Add Preprocessing

    Alternative 4: 78.8% accurate, 0.4× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} t_0 := 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}\\ \mathbf{if}\;t\_0 \leq -40:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - B}{B}\right)}{\pi}\\ \mathbf{elif}\;t\_0 \leq 0:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\ \end{array} \end{array} \]
    (FPCore (A B C)
     :precision binary64
     (let* ((t_0
             (*
              180.0
              (/
               (atan
                (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
               PI))))
       (if (<= t_0 -40.0)
         (/ (* 180.0 (atan (/ (- (+ (- A) C) B) B))) PI)
         (if (<= t_0 0.0)
           (* 180.0 (/ (atan (* (/ B (- C A)) -0.5)) PI))
           (* 180.0 (/ (atan (+ 1.0 (/ (- C A) B))) PI))))))
    double code(double A, double B, double C) {
    	double t_0 = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / ((double) M_PI));
    	double tmp;
    	if (t_0 <= -40.0) {
    		tmp = (180.0 * atan((((-A + C) - B) / B))) / ((double) M_PI);
    	} else if (t_0 <= 0.0) {
    		tmp = 180.0 * (atan(((B / (C - A)) * -0.5)) / ((double) M_PI));
    	} else {
    		tmp = 180.0 * (atan((1.0 + ((C - A) / B))) / ((double) M_PI));
    	}
    	return tmp;
    }
    
    public static double code(double A, double B, double C) {
    	double t_0 = 180.0 * (Math.atan(((1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / Math.PI);
    	double tmp;
    	if (t_0 <= -40.0) {
    		tmp = (180.0 * Math.atan((((-A + C) - B) / B))) / Math.PI;
    	} else if (t_0 <= 0.0) {
    		tmp = 180.0 * (Math.atan(((B / (C - A)) * -0.5)) / Math.PI);
    	} else {
    		tmp = 180.0 * (Math.atan((1.0 + ((C - A) / B))) / Math.PI);
    	}
    	return tmp;
    }
    
    def code(A, B, C):
    	t_0 = 180.0 * (math.atan(((1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / math.pi)
    	tmp = 0
    	if t_0 <= -40.0:
    		tmp = (180.0 * math.atan((((-A + C) - B) / B))) / math.pi
    	elif t_0 <= 0.0:
    		tmp = 180.0 * (math.atan(((B / (C - A)) * -0.5)) / math.pi)
    	else:
    		tmp = 180.0 * (math.atan((1.0 + ((C - A) / B))) / math.pi)
    	return tmp
    
    function code(A, B, C)
    	t_0 = Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))) / pi))
    	tmp = 0.0
    	if (t_0 <= -40.0)
    		tmp = Float64(Float64(180.0 * atan(Float64(Float64(Float64(Float64(-A) + C) - B) / B))) / pi);
    	elseif (t_0 <= 0.0)
    		tmp = Float64(180.0 * Float64(atan(Float64(Float64(B / Float64(C - A)) * -0.5)) / pi));
    	else
    		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + Float64(Float64(C - A) / B))) / pi));
    	end
    	return tmp
    end
    
    function tmp_2 = code(A, B, C)
    	t_0 = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / pi);
    	tmp = 0.0;
    	if (t_0 <= -40.0)
    		tmp = (180.0 * atan((((-A + C) - B) / B))) / pi;
    	elseif (t_0 <= 0.0)
    		tmp = 180.0 * (atan(((B / (C - A)) * -0.5)) / pi);
    	else
    		tmp = 180.0 * (atan((1.0 + ((C - A) / B))) / pi);
    	end
    	tmp_2 = tmp;
    end
    
    code[A_, B_, C_] := Block[{t$95$0 = N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, -40.0], N[(N[(180.0 * N[ArcTan[N[(N[(N[((-A) + C), $MachinePrecision] - B), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision], If[LessEqual[t$95$0, 0.0], N[(180.0 * N[(N[ArcTan[N[(N[(B / N[(C - A), $MachinePrecision]), $MachinePrecision] * -0.5), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(1.0 + N[(N[(C - A), $MachinePrecision] / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    t_0 := 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}\\
    \mathbf{if}\;t\_0 \leq -40:\\
    \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - B}{B}\right)}{\pi}\\
    
    \mathbf{elif}\;t\_0 \leq 0:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi}\\
    
    \mathbf{else}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 3 regimes
    2. if (*.f64 #s(literal 180 binary64) (/.f64 (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))) (PI.f64))) < -40

      1. Initial program 59.5%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Taylor expanded in A around -inf

        \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}}{\pi} \]
      3. Step-by-step derivation
        1. lower-atan.f64N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
        2. lower-/.f64N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
      4. Applied rewrites86.8%

        \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
      5. Step-by-step derivation
        1. lift-*.f64N/A

          \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
        2. lift-/.f64N/A

          \[\leadsto 180 \cdot \color{blue}{\frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
        3. associate-*r/N/A

          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
        4. lower-/.f64N/A

          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
        5. lower-*.f6486.8

          \[\leadsto \frac{\color{blue}{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
      6. Applied rewrites86.8%

        \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
      7. Taylor expanded in B around inf

        \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - B}{B}\right)}{\pi} \]
      8. Step-by-step derivation
        1. Applied rewrites76.1%

          \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - B}{B}\right)}{\pi} \]

        if -40 < (*.f64 #s(literal 180 binary64) (/.f64 (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))) (PI.f64))) < -0.0

        1. Initial program 18.0%

          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
        2. Taylor expanded in A around -inf

          \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}}{\pi} \]
        3. Step-by-step derivation
          1. lower-atan.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
          2. lower-/.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
        4. Applied rewrites19.6%

          \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
        5. Taylor expanded in B around 0

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}{\pi} \]
        6. Step-by-step derivation
          1. *-commutativeN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
          2. lower-*.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
          3. lower-/.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
          4. lift--.f6497.2

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi} \]
        7. Applied rewrites97.2%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi} \]

        if -0.0 < (*.f64 #s(literal 180 binary64) (/.f64 (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))) (PI.f64)))

        1. Initial program 58.8%

          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
        2. Taylor expanded in B around -inf

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
        3. Step-by-step derivation
          1. associate--l+N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
          2. div-subN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
          3. lower-+.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
          4. lower-/.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
          5. lift--.f6475.4

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
        4. Applied rewrites75.4%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
      9. Recombined 3 regimes into one program.
      10. Add Preprocessing

      Alternative 5: 69.8% accurate, 0.3× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{C - A}{B}\\ t_1 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\ t_2 := \tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)\\ \mathbf{if}\;t\_1 \leq -\infty:\\ \;\;\;\;\frac{180 \cdot t\_2}{\pi}\\ \mathbf{elif}\;t\_1 \leq -1000000:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(t\_0 + 1\right)}{\pi}\\ \mathbf{elif}\;t\_1 \leq -0.5:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \mathbf{elif}\;t\_1 \leq 0:\\ \;\;\;\;180 \cdot \frac{t\_2}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + t\_0\right)}{\pi}\\ \end{array} \end{array} \]
      (FPCore (A B C)
       :precision binary64
       (let* ((t_0 (/ (- C A) B))
              (t_1
               (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
              (t_2 (atan (* (/ B (- C A)) -0.5))))
         (if (<= t_1 (- INFINITY))
           (/ (* 180.0 t_2) PI)
           (if (<= t_1 -1000000.0)
             (/ (* 180.0 (atan (+ t_0 1.0))) PI)
             (if (<= t_1 -0.5)
               (* 180.0 (/ (atan -1.0) PI))
               (if (<= t_1 0.0)
                 (* 180.0 (/ t_2 PI))
                 (* 180.0 (/ (atan (+ 1.0 t_0)) PI))))))))
      double code(double A, double B, double C) {
      	double t_0 = (C - A) / B;
      	double t_1 = (1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0))));
      	double t_2 = atan(((B / (C - A)) * -0.5));
      	double tmp;
      	if (t_1 <= -((double) INFINITY)) {
      		tmp = (180.0 * t_2) / ((double) M_PI);
      	} else if (t_1 <= -1000000.0) {
      		tmp = (180.0 * atan((t_0 + 1.0))) / ((double) M_PI);
      	} else if (t_1 <= -0.5) {
      		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
      	} else if (t_1 <= 0.0) {
      		tmp = 180.0 * (t_2 / ((double) M_PI));
      	} else {
      		tmp = 180.0 * (atan((1.0 + t_0)) / ((double) M_PI));
      	}
      	return tmp;
      }
      
      public static double code(double A, double B, double C) {
      	double t_0 = (C - A) / B;
      	double t_1 = (1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0))));
      	double t_2 = Math.atan(((B / (C - A)) * -0.5));
      	double tmp;
      	if (t_1 <= -Double.POSITIVE_INFINITY) {
      		tmp = (180.0 * t_2) / Math.PI;
      	} else if (t_1 <= -1000000.0) {
      		tmp = (180.0 * Math.atan((t_0 + 1.0))) / Math.PI;
      	} else if (t_1 <= -0.5) {
      		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
      	} else if (t_1 <= 0.0) {
      		tmp = 180.0 * (t_2 / Math.PI);
      	} else {
      		tmp = 180.0 * (Math.atan((1.0 + t_0)) / Math.PI);
      	}
      	return tmp;
      }
      
      def code(A, B, C):
      	t_0 = (C - A) / B
      	t_1 = (1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0))))
      	t_2 = math.atan(((B / (C - A)) * -0.5))
      	tmp = 0
      	if t_1 <= -math.inf:
      		tmp = (180.0 * t_2) / math.pi
      	elif t_1 <= -1000000.0:
      		tmp = (180.0 * math.atan((t_0 + 1.0))) / math.pi
      	elif t_1 <= -0.5:
      		tmp = 180.0 * (math.atan(-1.0) / math.pi)
      	elif t_1 <= 0.0:
      		tmp = 180.0 * (t_2 / math.pi)
      	else:
      		tmp = 180.0 * (math.atan((1.0 + t_0)) / math.pi)
      	return tmp
      
      function code(A, B, C)
      	t_0 = Float64(Float64(C - A) / B)
      	t_1 = Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))
      	t_2 = atan(Float64(Float64(B / Float64(C - A)) * -0.5))
      	tmp = 0.0
      	if (t_1 <= Float64(-Inf))
      		tmp = Float64(Float64(180.0 * t_2) / pi);
      	elseif (t_1 <= -1000000.0)
      		tmp = Float64(Float64(180.0 * atan(Float64(t_0 + 1.0))) / pi);
      	elseif (t_1 <= -0.5)
      		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
      	elseif (t_1 <= 0.0)
      		tmp = Float64(180.0 * Float64(t_2 / pi));
      	else
      		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + t_0)) / pi));
      	end
      	return tmp
      end
      
      function tmp_2 = code(A, B, C)
      	t_0 = (C - A) / B;
      	t_1 = (1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0))));
      	t_2 = atan(((B / (C - A)) * -0.5));
      	tmp = 0.0;
      	if (t_1 <= -Inf)
      		tmp = (180.0 * t_2) / pi;
      	elseif (t_1 <= -1000000.0)
      		tmp = (180.0 * atan((t_0 + 1.0))) / pi;
      	elseif (t_1 <= -0.5)
      		tmp = 180.0 * (atan(-1.0) / pi);
      	elseif (t_1 <= 0.0)
      		tmp = 180.0 * (t_2 / pi);
      	else
      		tmp = 180.0 * (atan((1.0 + t_0)) / pi);
      	end
      	tmp_2 = tmp;
      end
      
      code[A_, B_, C_] := Block[{t$95$0 = N[(N[(C - A), $MachinePrecision] / B), $MachinePrecision]}, Block[{t$95$1 = N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[ArcTan[N[(N[(B / N[(C - A), $MachinePrecision]), $MachinePrecision] * -0.5), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[t$95$1, (-Infinity)], N[(N[(180.0 * t$95$2), $MachinePrecision] / Pi), $MachinePrecision], If[LessEqual[t$95$1, -1000000.0], N[(N[(180.0 * N[ArcTan[N[(t$95$0 + 1.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision], If[LessEqual[t$95$1, -0.5], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$1, 0.0], N[(180.0 * N[(t$95$2 / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(1.0 + t$95$0), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]]]]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      t_0 := \frac{C - A}{B}\\
      t_1 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\
      t_2 := \tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)\\
      \mathbf{if}\;t\_1 \leq -\infty:\\
      \;\;\;\;\frac{180 \cdot t\_2}{\pi}\\
      
      \mathbf{elif}\;t\_1 \leq -1000000:\\
      \;\;\;\;\frac{180 \cdot \tan^{-1} \left(t\_0 + 1\right)}{\pi}\\
      
      \mathbf{elif}\;t\_1 \leq -0.5:\\
      \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
      
      \mathbf{elif}\;t\_1 \leq 0:\\
      \;\;\;\;180 \cdot \frac{t\_2}{\pi}\\
      
      \mathbf{else}:\\
      \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + t\_0\right)}{\pi}\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 5 regimes
      2. if (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -inf.0

        1. Initial program 42.0%

          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
        2. Taylor expanded in A around -inf

          \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}}{\pi} \]
        3. Step-by-step derivation
          1. lower-atan.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
          2. lower-/.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
        4. Applied rewrites81.6%

          \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
        5. Step-by-step derivation
          1. lift-*.f64N/A

            \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
          2. lift-/.f64N/A

            \[\leadsto 180 \cdot \color{blue}{\frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
          3. associate-*r/N/A

            \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
          4. lower-/.f64N/A

            \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
          5. lower-*.f6481.6

            \[\leadsto \frac{\color{blue}{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
        6. Applied rewrites81.6%

          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
        7. Taylor expanded in B around 0

          \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}{\pi} \]
        8. Step-by-step derivation
          1. *-commutativeN/A

            \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
          2. lower-*.f64N/A

            \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
          3. lower-/.f64N/A

            \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
          4. lift--.f6437.2

            \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi} \]
        9. Applied rewrites37.2%

          \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi} \]

        if -inf.0 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -1e6

        1. Initial program 96.6%

          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
        2. Taylor expanded in B around -inf

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
        3. Step-by-step derivation
          1. associate--l+N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
          2. div-subN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
          3. lower-+.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
          4. lower-/.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
          5. lift--.f6495.7

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
        4. Applied rewrites95.7%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
        5. Step-by-step derivation
          1. lift-*.f64N/A

            \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}} \]
          2. lift-/.f64N/A

            \[\leadsto 180 \cdot \color{blue}{\frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}} \]
          3. associate-*r/N/A

            \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}} \]
          4. lower-/.f64N/A

            \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}} \]
        6. Applied rewrites95.7%

          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{C - A}{B} + 1\right)}{\pi}} \]

        if -1e6 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -0.5

        1. Initial program 99.5%

          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
        2. Taylor expanded in B around inf

          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
        3. Step-by-step derivation
          1. Applied rewrites95.3%

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]

          if -0.5 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -0.0

          1. Initial program 18.0%

            \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
          2. Taylor expanded in A around -inf

            \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}}{\pi} \]
          3. Step-by-step derivation
            1. lower-atan.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
            2. lower-/.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
          4. Applied rewrites19.5%

            \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
          5. Taylor expanded in B around 0

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}{\pi} \]
          6. Step-by-step derivation
            1. *-commutativeN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
            2. lower-*.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
            3. lower-/.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
            4. lift--.f6497.3

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi} \]
          7. Applied rewrites97.3%

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi} \]

          if -0.0 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))

          1. Initial program 58.8%

            \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
          2. Taylor expanded in B around -inf

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
          3. Step-by-step derivation
            1. associate--l+N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
            2. div-subN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
            3. lower-+.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
            4. lower-/.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
            5. lift--.f6475.4

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
          4. Applied rewrites75.4%

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
        4. Recombined 5 regimes into one program.
        5. Add Preprocessing

        Alternative 6: 69.8% accurate, 0.3× speedup?

        \[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{C - A}{B}\\ t_1 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\ t_2 := \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi}\\ \mathbf{if}\;t\_1 \leq -\infty:\\ \;\;\;\;t\_2\\ \mathbf{elif}\;t\_1 \leq -1000000:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(t\_0 + 1\right)}{\pi}\\ \mathbf{elif}\;t\_1 \leq -0.5:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \mathbf{elif}\;t\_1 \leq 0:\\ \;\;\;\;t\_2\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + t\_0\right)}{\pi}\\ \end{array} \end{array} \]
        (FPCore (A B C)
         :precision binary64
         (let* ((t_0 (/ (- C A) B))
                (t_1
                 (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
                (t_2 (/ (* 180.0 (atan (* (/ B (- C A)) -0.5))) PI)))
           (if (<= t_1 (- INFINITY))
             t_2
             (if (<= t_1 -1000000.0)
               (/ (* 180.0 (atan (+ t_0 1.0))) PI)
               (if (<= t_1 -0.5)
                 (* 180.0 (/ (atan -1.0) PI))
                 (if (<= t_1 0.0) t_2 (* 180.0 (/ (atan (+ 1.0 t_0)) PI))))))))
        double code(double A, double B, double C) {
        	double t_0 = (C - A) / B;
        	double t_1 = (1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0))));
        	double t_2 = (180.0 * atan(((B / (C - A)) * -0.5))) / ((double) M_PI);
        	double tmp;
        	if (t_1 <= -((double) INFINITY)) {
        		tmp = t_2;
        	} else if (t_1 <= -1000000.0) {
        		tmp = (180.0 * atan((t_0 + 1.0))) / ((double) M_PI);
        	} else if (t_1 <= -0.5) {
        		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
        	} else if (t_1 <= 0.0) {
        		tmp = t_2;
        	} else {
        		tmp = 180.0 * (atan((1.0 + t_0)) / ((double) M_PI));
        	}
        	return tmp;
        }
        
        public static double code(double A, double B, double C) {
        	double t_0 = (C - A) / B;
        	double t_1 = (1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0))));
        	double t_2 = (180.0 * Math.atan(((B / (C - A)) * -0.5))) / Math.PI;
        	double tmp;
        	if (t_1 <= -Double.POSITIVE_INFINITY) {
        		tmp = t_2;
        	} else if (t_1 <= -1000000.0) {
        		tmp = (180.0 * Math.atan((t_0 + 1.0))) / Math.PI;
        	} else if (t_1 <= -0.5) {
        		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
        	} else if (t_1 <= 0.0) {
        		tmp = t_2;
        	} else {
        		tmp = 180.0 * (Math.atan((1.0 + t_0)) / Math.PI);
        	}
        	return tmp;
        }
        
        def code(A, B, C):
        	t_0 = (C - A) / B
        	t_1 = (1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0))))
        	t_2 = (180.0 * math.atan(((B / (C - A)) * -0.5))) / math.pi
        	tmp = 0
        	if t_1 <= -math.inf:
        		tmp = t_2
        	elif t_1 <= -1000000.0:
        		tmp = (180.0 * math.atan((t_0 + 1.0))) / math.pi
        	elif t_1 <= -0.5:
        		tmp = 180.0 * (math.atan(-1.0) / math.pi)
        	elif t_1 <= 0.0:
        		tmp = t_2
        	else:
        		tmp = 180.0 * (math.atan((1.0 + t_0)) / math.pi)
        	return tmp
        
        function code(A, B, C)
        	t_0 = Float64(Float64(C - A) / B)
        	t_1 = Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))
        	t_2 = Float64(Float64(180.0 * atan(Float64(Float64(B / Float64(C - A)) * -0.5))) / pi)
        	tmp = 0.0
        	if (t_1 <= Float64(-Inf))
        		tmp = t_2;
        	elseif (t_1 <= -1000000.0)
        		tmp = Float64(Float64(180.0 * atan(Float64(t_0 + 1.0))) / pi);
        	elseif (t_1 <= -0.5)
        		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
        	elseif (t_1 <= 0.0)
        		tmp = t_2;
        	else
        		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + t_0)) / pi));
        	end
        	return tmp
        end
        
        function tmp_2 = code(A, B, C)
        	t_0 = (C - A) / B;
        	t_1 = (1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0))));
        	t_2 = (180.0 * atan(((B / (C - A)) * -0.5))) / pi;
        	tmp = 0.0;
        	if (t_1 <= -Inf)
        		tmp = t_2;
        	elseif (t_1 <= -1000000.0)
        		tmp = (180.0 * atan((t_0 + 1.0))) / pi;
        	elseif (t_1 <= -0.5)
        		tmp = 180.0 * (atan(-1.0) / pi);
        	elseif (t_1 <= 0.0)
        		tmp = t_2;
        	else
        		tmp = 180.0 * (atan((1.0 + t_0)) / pi);
        	end
        	tmp_2 = tmp;
        end
        
        code[A_, B_, C_] := Block[{t$95$0 = N[(N[(C - A), $MachinePrecision] / B), $MachinePrecision]}, Block[{t$95$1 = N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(N[(180.0 * N[ArcTan[N[(N[(B / N[(C - A), $MachinePrecision]), $MachinePrecision] * -0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision]}, If[LessEqual[t$95$1, (-Infinity)], t$95$2, If[LessEqual[t$95$1, -1000000.0], N[(N[(180.0 * N[ArcTan[N[(t$95$0 + 1.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision], If[LessEqual[t$95$1, -0.5], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$1, 0.0], t$95$2, N[(180.0 * N[(N[ArcTan[N[(1.0 + t$95$0), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]]]]]
        
        \begin{array}{l}
        
        \\
        \begin{array}{l}
        t_0 := \frac{C - A}{B}\\
        t_1 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\
        t_2 := \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi}\\
        \mathbf{if}\;t\_1 \leq -\infty:\\
        \;\;\;\;t\_2\\
        
        \mathbf{elif}\;t\_1 \leq -1000000:\\
        \;\;\;\;\frac{180 \cdot \tan^{-1} \left(t\_0 + 1\right)}{\pi}\\
        
        \mathbf{elif}\;t\_1 \leq -0.5:\\
        \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
        
        \mathbf{elif}\;t\_1 \leq 0:\\
        \;\;\;\;t\_2\\
        
        \mathbf{else}:\\
        \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + t\_0\right)}{\pi}\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 4 regimes
        2. if (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -inf.0 or -0.5 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -0.0

          1. Initial program 34.4%

            \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
          2. Taylor expanded in A around -inf

            \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}}{\pi} \]
          3. Step-by-step derivation
            1. lower-atan.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
            2. lower-/.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
          4. Applied rewrites61.9%

            \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
          5. Step-by-step derivation
            1. lift-*.f64N/A

              \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
            2. lift-/.f64N/A

              \[\leadsto 180 \cdot \color{blue}{\frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
            3. associate-*r/N/A

              \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
            4. lower-/.f64N/A

              \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
            5. lower-*.f6461.9

              \[\leadsto \frac{\color{blue}{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
          6. Applied rewrites61.9%

            \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
          7. Taylor expanded in B around 0

            \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}{\pi} \]
          8. Step-by-step derivation
            1. *-commutativeN/A

              \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
            2. lower-*.f64N/A

              \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
            3. lower-/.f64N/A

              \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
            4. lift--.f6456.3

              \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi} \]
          9. Applied rewrites56.3%

            \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi} \]

          if -inf.0 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -1e6

          1. Initial program 96.6%

            \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
          2. Taylor expanded in B around -inf

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
          3. Step-by-step derivation
            1. associate--l+N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
            2. div-subN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
            3. lower-+.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
            4. lower-/.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
            5. lift--.f6495.7

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
          4. Applied rewrites95.7%

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
          5. Step-by-step derivation
            1. lift-*.f64N/A

              \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}} \]
            2. lift-/.f64N/A

              \[\leadsto 180 \cdot \color{blue}{\frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}} \]
            3. associate-*r/N/A

              \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}} \]
            4. lower-/.f64N/A

              \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}} \]
          6. Applied rewrites95.7%

            \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{C - A}{B} + 1\right)}{\pi}} \]

          if -1e6 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -0.5

          1. Initial program 99.5%

            \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
          2. Taylor expanded in B around inf

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
          3. Step-by-step derivation
            1. Applied rewrites95.3%

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]

            if -0.0 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))

            1. Initial program 58.8%

              \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
            2. Taylor expanded in B around -inf

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
            3. Step-by-step derivation
              1. associate--l+N/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
              2. div-subN/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
              3. lower-+.f64N/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
              4. lower-/.f64N/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
              5. lift--.f6475.4

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
            4. Applied rewrites75.4%

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
          4. Recombined 4 regimes into one program.
          5. Add Preprocessing

          Alternative 7: 60.8% accurate, 2.3× speedup?

          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;C \leq 6.1 \cdot 10^{+29}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B}{C} \cdot -0.5\right)}{\pi}\\ \end{array} \end{array} \]
          (FPCore (A B C)
           :precision binary64
           (if (<= C 6.1e+29)
             (* 180.0 (/ (atan (+ 1.0 (/ (- C A) B))) PI))
             (/ (* 180.0 (atan (* (/ B C) -0.5))) PI)))
          double code(double A, double B, double C) {
          	double tmp;
          	if (C <= 6.1e+29) {
          		tmp = 180.0 * (atan((1.0 + ((C - A) / B))) / ((double) M_PI));
          	} else {
          		tmp = (180.0 * atan(((B / C) * -0.5))) / ((double) M_PI);
          	}
          	return tmp;
          }
          
          public static double code(double A, double B, double C) {
          	double tmp;
          	if (C <= 6.1e+29) {
          		tmp = 180.0 * (Math.atan((1.0 + ((C - A) / B))) / Math.PI);
          	} else {
          		tmp = (180.0 * Math.atan(((B / C) * -0.5))) / Math.PI;
          	}
          	return tmp;
          }
          
          def code(A, B, C):
          	tmp = 0
          	if C <= 6.1e+29:
          		tmp = 180.0 * (math.atan((1.0 + ((C - A) / B))) / math.pi)
          	else:
          		tmp = (180.0 * math.atan(((B / C) * -0.5))) / math.pi
          	return tmp
          
          function code(A, B, C)
          	tmp = 0.0
          	if (C <= 6.1e+29)
          		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + Float64(Float64(C - A) / B))) / pi));
          	else
          		tmp = Float64(Float64(180.0 * atan(Float64(Float64(B / C) * -0.5))) / pi);
          	end
          	return tmp
          end
          
          function tmp_2 = code(A, B, C)
          	tmp = 0.0;
          	if (C <= 6.1e+29)
          		tmp = 180.0 * (atan((1.0 + ((C - A) / B))) / pi);
          	else
          		tmp = (180.0 * atan(((B / C) * -0.5))) / pi;
          	end
          	tmp_2 = tmp;
          end
          
          code[A_, B_, C_] := If[LessEqual[C, 6.1e+29], N[(180.0 * N[(N[ArcTan[N[(1.0 + N[(N[(C - A), $MachinePrecision] / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(N[(180.0 * N[ArcTan[N[(N[(B / C), $MachinePrecision] * -0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision]]
          
          \begin{array}{l}
          
          \\
          \begin{array}{l}
          \mathbf{if}\;C \leq 6.1 \cdot 10^{+29}:\\
          \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\
          
          \mathbf{else}:\\
          \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B}{C} \cdot -0.5\right)}{\pi}\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if C < 6.0999999999999998e29

            1. Initial program 62.4%

              \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
            2. Taylor expanded in B around -inf

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
            3. Step-by-step derivation
              1. associate--l+N/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
              2. div-subN/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
              3. lower-+.f64N/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
              4. lower-/.f64N/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
              5. lift--.f6458.4

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
            4. Applied rewrites58.4%

              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]

            if 6.0999999999999998e29 < C

            1. Initial program 23.7%

              \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
            2. Taylor expanded in A around -inf

              \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}}{\pi} \]
            3. Step-by-step derivation
              1. lower-atan.f64N/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
              2. lower-/.f64N/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
            4. Applied rewrites57.2%

              \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
            5. Step-by-step derivation
              1. lift-*.f64N/A

                \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
              2. lift-/.f64N/A

                \[\leadsto 180 \cdot \color{blue}{\frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
              3. associate-*r/N/A

                \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
              4. lower-/.f64N/A

                \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
              5. lower-*.f6457.2

                \[\leadsto \frac{\color{blue}{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
            6. Applied rewrites57.2%

              \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
            7. Taylor expanded in B around 0

              \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}{\pi} \]
            8. Step-by-step derivation
              1. *-commutativeN/A

                \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
              2. lower-*.f64N/A

                \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
              3. lower-/.f64N/A

                \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
              4. lift--.f6474.0

                \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi} \]
            9. Applied rewrites74.0%

              \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi} \]
            10. Taylor expanded in A around 0

              \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C} \cdot \frac{-1}{2}\right)}{\pi} \]
            11. Step-by-step derivation
              1. Applied rewrites69.1%

                \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C} \cdot -0.5\right)}{\pi} \]
            12. Recombined 2 regimes into one program.
            13. Add Preprocessing

            Alternative 8: 60.8% accurate, 2.3× speedup?

            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;C \leq 6.1 \cdot 10^{+29}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{C - A}{B} + 1\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B}{C} \cdot -0.5\right)}{\pi}\\ \end{array} \end{array} \]
            (FPCore (A B C)
             :precision binary64
             (if (<= C 6.1e+29)
               (/ (* 180.0 (atan (+ (/ (- C A) B) 1.0))) PI)
               (/ (* 180.0 (atan (* (/ B C) -0.5))) PI)))
            double code(double A, double B, double C) {
            	double tmp;
            	if (C <= 6.1e+29) {
            		tmp = (180.0 * atan((((C - A) / B) + 1.0))) / ((double) M_PI);
            	} else {
            		tmp = (180.0 * atan(((B / C) * -0.5))) / ((double) M_PI);
            	}
            	return tmp;
            }
            
            public static double code(double A, double B, double C) {
            	double tmp;
            	if (C <= 6.1e+29) {
            		tmp = (180.0 * Math.atan((((C - A) / B) + 1.0))) / Math.PI;
            	} else {
            		tmp = (180.0 * Math.atan(((B / C) * -0.5))) / Math.PI;
            	}
            	return tmp;
            }
            
            def code(A, B, C):
            	tmp = 0
            	if C <= 6.1e+29:
            		tmp = (180.0 * math.atan((((C - A) / B) + 1.0))) / math.pi
            	else:
            		tmp = (180.0 * math.atan(((B / C) * -0.5))) / math.pi
            	return tmp
            
            function code(A, B, C)
            	tmp = 0.0
            	if (C <= 6.1e+29)
            		tmp = Float64(Float64(180.0 * atan(Float64(Float64(Float64(C - A) / B) + 1.0))) / pi);
            	else
            		tmp = Float64(Float64(180.0 * atan(Float64(Float64(B / C) * -0.5))) / pi);
            	end
            	return tmp
            end
            
            function tmp_2 = code(A, B, C)
            	tmp = 0.0;
            	if (C <= 6.1e+29)
            		tmp = (180.0 * atan((((C - A) / B) + 1.0))) / pi;
            	else
            		tmp = (180.0 * atan(((B / C) * -0.5))) / pi;
            	end
            	tmp_2 = tmp;
            end
            
            code[A_, B_, C_] := If[LessEqual[C, 6.1e+29], N[(N[(180.0 * N[ArcTan[N[(N[(N[(C - A), $MachinePrecision] / B), $MachinePrecision] + 1.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision], N[(N[(180.0 * N[ArcTan[N[(N[(B / C), $MachinePrecision] * -0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision]]
            
            \begin{array}{l}
            
            \\
            \begin{array}{l}
            \mathbf{if}\;C \leq 6.1 \cdot 10^{+29}:\\
            \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{C - A}{B} + 1\right)}{\pi}\\
            
            \mathbf{else}:\\
            \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B}{C} \cdot -0.5\right)}{\pi}\\
            
            
            \end{array}
            \end{array}
            
            Derivation
            1. Split input into 2 regimes
            2. if C < 6.0999999999999998e29

              1. Initial program 62.4%

                \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
              2. Taylor expanded in B around -inf

                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
              3. Step-by-step derivation
                1. associate--l+N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
                2. div-subN/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                3. lower-+.f64N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
                4. lower-/.f64N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                5. lift--.f6458.4

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
              4. Applied rewrites58.4%

                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
              5. Step-by-step derivation
                1. lift-*.f64N/A

                  \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}} \]
                2. lift-/.f64N/A

                  \[\leadsto 180 \cdot \color{blue}{\frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}} \]
                3. associate-*r/N/A

                  \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}} \]
                4. lower-/.f64N/A

                  \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}} \]
              6. Applied rewrites58.4%

                \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{C - A}{B} + 1\right)}{\pi}} \]

              if 6.0999999999999998e29 < C

              1. Initial program 23.7%

                \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
              2. Taylor expanded in A around -inf

                \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}}{\pi} \]
              3. Step-by-step derivation
                1. lower-atan.f64N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
                2. lower-/.f64N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
              4. Applied rewrites57.2%

                \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
              5. Step-by-step derivation
                1. lift-*.f64N/A

                  \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
                2. lift-/.f64N/A

                  \[\leadsto 180 \cdot \color{blue}{\frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
                3. associate-*r/N/A

                  \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
                4. lower-/.f64N/A

                  \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
                5. lower-*.f6457.2

                  \[\leadsto \frac{\color{blue}{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
              6. Applied rewrites57.2%

                \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
              7. Taylor expanded in B around 0

                \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}{\pi} \]
              8. Step-by-step derivation
                1. *-commutativeN/A

                  \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
                2. lower-*.f64N/A

                  \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
                3. lower-/.f64N/A

                  \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
                4. lift--.f6474.0

                  \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi} \]
              9. Applied rewrites74.0%

                \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi} \]
              10. Taylor expanded in A around 0

                \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C} \cdot \frac{-1}{2}\right)}{\pi} \]
              11. Step-by-step derivation
                1. Applied rewrites69.1%

                  \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C} \cdot -0.5\right)}{\pi} \]
              12. Recombined 2 regimes into one program.
              13. Add Preprocessing

              Alternative 9: 59.3% accurate, 2.1× speedup?

              \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;C \leq -5 \cdot 10^{-127}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi}\\ \mathbf{elif}\;C \leq 6.1 \cdot 10^{+29}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{-A}{B} + 1\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B}{C} \cdot -0.5\right)}{\pi}\\ \end{array} \end{array} \]
              (FPCore (A B C)
               :precision binary64
               (if (<= C -5e-127)
                 (* 180.0 (/ (atan (+ 1.0 (/ C B))) PI))
                 (if (<= C 6.1e+29)
                   (/ (* 180.0 (atan (+ (/ (- A) B) 1.0))) PI)
                   (/ (* 180.0 (atan (* (/ B C) -0.5))) PI))))
              double code(double A, double B, double C) {
              	double tmp;
              	if (C <= -5e-127) {
              		tmp = 180.0 * (atan((1.0 + (C / B))) / ((double) M_PI));
              	} else if (C <= 6.1e+29) {
              		tmp = (180.0 * atan(((-A / B) + 1.0))) / ((double) M_PI);
              	} else {
              		tmp = (180.0 * atan(((B / C) * -0.5))) / ((double) M_PI);
              	}
              	return tmp;
              }
              
              public static double code(double A, double B, double C) {
              	double tmp;
              	if (C <= -5e-127) {
              		tmp = 180.0 * (Math.atan((1.0 + (C / B))) / Math.PI);
              	} else if (C <= 6.1e+29) {
              		tmp = (180.0 * Math.atan(((-A / B) + 1.0))) / Math.PI;
              	} else {
              		tmp = (180.0 * Math.atan(((B / C) * -0.5))) / Math.PI;
              	}
              	return tmp;
              }
              
              def code(A, B, C):
              	tmp = 0
              	if C <= -5e-127:
              		tmp = 180.0 * (math.atan((1.0 + (C / B))) / math.pi)
              	elif C <= 6.1e+29:
              		tmp = (180.0 * math.atan(((-A / B) + 1.0))) / math.pi
              	else:
              		tmp = (180.0 * math.atan(((B / C) * -0.5))) / math.pi
              	return tmp
              
              function code(A, B, C)
              	tmp = 0.0
              	if (C <= -5e-127)
              		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + Float64(C / B))) / pi));
              	elseif (C <= 6.1e+29)
              		tmp = Float64(Float64(180.0 * atan(Float64(Float64(Float64(-A) / B) + 1.0))) / pi);
              	else
              		tmp = Float64(Float64(180.0 * atan(Float64(Float64(B / C) * -0.5))) / pi);
              	end
              	return tmp
              end
              
              function tmp_2 = code(A, B, C)
              	tmp = 0.0;
              	if (C <= -5e-127)
              		tmp = 180.0 * (atan((1.0 + (C / B))) / pi);
              	elseif (C <= 6.1e+29)
              		tmp = (180.0 * atan(((-A / B) + 1.0))) / pi;
              	else
              		tmp = (180.0 * atan(((B / C) * -0.5))) / pi;
              	end
              	tmp_2 = tmp;
              end
              
              code[A_, B_, C_] := If[LessEqual[C, -5e-127], N[(180.0 * N[(N[ArcTan[N[(1.0 + N[(C / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[C, 6.1e+29], N[(N[(180.0 * N[ArcTan[N[(N[((-A) / B), $MachinePrecision] + 1.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision], N[(N[(180.0 * N[ArcTan[N[(N[(B / C), $MachinePrecision] * -0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision]]]
              
              \begin{array}{l}
              
              \\
              \begin{array}{l}
              \mathbf{if}\;C \leq -5 \cdot 10^{-127}:\\
              \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi}\\
              
              \mathbf{elif}\;C \leq 6.1 \cdot 10^{+29}:\\
              \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{-A}{B} + 1\right)}{\pi}\\
              
              \mathbf{else}:\\
              \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B}{C} \cdot -0.5\right)}{\pi}\\
              
              
              \end{array}
              \end{array}
              
              Derivation
              1. Split input into 3 regimes
              2. if C < -4.9999999999999997e-127

                1. Initial program 71.6%

                  \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                2. Taylor expanded in B around -inf

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
                3. Step-by-step derivation
                  1. associate--l+N/A

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
                  2. div-subN/A

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                  3. lower-+.f64N/A

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
                  4. lower-/.f64N/A

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                  5. lift--.f6471.7

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
                4. Applied rewrites71.7%

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
                5. Taylor expanded in A around 0

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi} \]
                6. Step-by-step derivation
                  1. Applied rewrites68.1%

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi} \]

                  if -4.9999999999999997e-127 < C < 6.0999999999999998e29

                  1. Initial program 54.8%

                    \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                  2. Taylor expanded in B around -inf

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
                  3. Step-by-step derivation
                    1. associate--l+N/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
                    2. div-subN/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                    3. lower-+.f64N/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
                    4. lower-/.f64N/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                    5. lift--.f6447.3

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
                  4. Applied rewrites47.3%

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
                  5. Step-by-step derivation
                    1. lift-*.f64N/A

                      \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}} \]
                    2. lift-/.f64N/A

                      \[\leadsto 180 \cdot \color{blue}{\frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}} \]
                    3. associate-*r/N/A

                      \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}} \]
                    4. lower-/.f64N/A

                      \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}} \]
                  6. Applied rewrites47.3%

                    \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{C - A}{B} + 1\right)}{\pi}} \]
                  7. Taylor expanded in A around inf

                    \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{-1 \cdot A}{B} + 1\right)}{\pi} \]
                  8. Step-by-step derivation
                    1. mul-1-negN/A

                      \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{\mathsf{neg}\left(A\right)}{B} + 1\right)}{\pi} \]
                    2. lift-neg.f6446.7

                      \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{-A}{B} + 1\right)}{\pi} \]
                  9. Applied rewrites46.7%

                    \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{-A}{B} + 1\right)}{\pi} \]

                  if 6.0999999999999998e29 < C

                  1. Initial program 23.7%

                    \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                  2. Taylor expanded in A around -inf

                    \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}}{\pi} \]
                  3. Step-by-step derivation
                    1. lower-atan.f64N/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
                    2. lower-/.f64N/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
                  4. Applied rewrites57.2%

                    \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
                  5. Step-by-step derivation
                    1. lift-*.f64N/A

                      \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
                    2. lift-/.f64N/A

                      \[\leadsto 180 \cdot \color{blue}{\frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
                    3. associate-*r/N/A

                      \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
                    4. lower-/.f64N/A

                      \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
                    5. lower-*.f6457.2

                      \[\leadsto \frac{\color{blue}{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
                  6. Applied rewrites57.2%

                    \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
                  7. Taylor expanded in B around 0

                    \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}{\pi} \]
                  8. Step-by-step derivation
                    1. *-commutativeN/A

                      \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
                    2. lower-*.f64N/A

                      \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
                    3. lower-/.f64N/A

                      \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
                    4. lift--.f6474.0

                      \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi} \]
                  9. Applied rewrites74.0%

                    \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi} \]
                  10. Taylor expanded in A around 0

                    \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C} \cdot \frac{-1}{2}\right)}{\pi} \]
                  11. Step-by-step derivation
                    1. Applied rewrites69.1%

                      \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C} \cdot -0.5\right)}{\pi} \]
                  12. Recombined 3 regimes into one program.
                  13. Add Preprocessing

                  Alternative 10: 59.3% accurate, 2.2× speedup?

                  \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;C \leq -5 \cdot 10^{-127}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi}\\ \mathbf{elif}\;C \leq 6.1 \cdot 10^{+29}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B}{C} \cdot -0.5\right)}{\pi}\\ \end{array} \end{array} \]
                  (FPCore (A B C)
                   :precision binary64
                   (if (<= C -5e-127)
                     (* 180.0 (/ (atan (+ 1.0 (/ C B))) PI))
                     (if (<= C 6.1e+29)
                       (* 180.0 (/ (atan (- 1.0 (/ A B))) PI))
                       (/ (* 180.0 (atan (* (/ B C) -0.5))) PI))))
                  double code(double A, double B, double C) {
                  	double tmp;
                  	if (C <= -5e-127) {
                  		tmp = 180.0 * (atan((1.0 + (C / B))) / ((double) M_PI));
                  	} else if (C <= 6.1e+29) {
                  		tmp = 180.0 * (atan((1.0 - (A / B))) / ((double) M_PI));
                  	} else {
                  		tmp = (180.0 * atan(((B / C) * -0.5))) / ((double) M_PI);
                  	}
                  	return tmp;
                  }
                  
                  public static double code(double A, double B, double C) {
                  	double tmp;
                  	if (C <= -5e-127) {
                  		tmp = 180.0 * (Math.atan((1.0 + (C / B))) / Math.PI);
                  	} else if (C <= 6.1e+29) {
                  		tmp = 180.0 * (Math.atan((1.0 - (A / B))) / Math.PI);
                  	} else {
                  		tmp = (180.0 * Math.atan(((B / C) * -0.5))) / Math.PI;
                  	}
                  	return tmp;
                  }
                  
                  def code(A, B, C):
                  	tmp = 0
                  	if C <= -5e-127:
                  		tmp = 180.0 * (math.atan((1.0 + (C / B))) / math.pi)
                  	elif C <= 6.1e+29:
                  		tmp = 180.0 * (math.atan((1.0 - (A / B))) / math.pi)
                  	else:
                  		tmp = (180.0 * math.atan(((B / C) * -0.5))) / math.pi
                  	return tmp
                  
                  function code(A, B, C)
                  	tmp = 0.0
                  	if (C <= -5e-127)
                  		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + Float64(C / B))) / pi));
                  	elseif (C <= 6.1e+29)
                  		tmp = Float64(180.0 * Float64(atan(Float64(1.0 - Float64(A / B))) / pi));
                  	else
                  		tmp = Float64(Float64(180.0 * atan(Float64(Float64(B / C) * -0.5))) / pi);
                  	end
                  	return tmp
                  end
                  
                  function tmp_2 = code(A, B, C)
                  	tmp = 0.0;
                  	if (C <= -5e-127)
                  		tmp = 180.0 * (atan((1.0 + (C / B))) / pi);
                  	elseif (C <= 6.1e+29)
                  		tmp = 180.0 * (atan((1.0 - (A / B))) / pi);
                  	else
                  		tmp = (180.0 * atan(((B / C) * -0.5))) / pi;
                  	end
                  	tmp_2 = tmp;
                  end
                  
                  code[A_, B_, C_] := If[LessEqual[C, -5e-127], N[(180.0 * N[(N[ArcTan[N[(1.0 + N[(C / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[C, 6.1e+29], N[(180.0 * N[(N[ArcTan[N[(1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(N[(180.0 * N[ArcTan[N[(N[(B / C), $MachinePrecision] * -0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision]]]
                  
                  \begin{array}{l}
                  
                  \\
                  \begin{array}{l}
                  \mathbf{if}\;C \leq -5 \cdot 10^{-127}:\\
                  \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi}\\
                  
                  \mathbf{elif}\;C \leq 6.1 \cdot 10^{+29}:\\
                  \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\
                  
                  \mathbf{else}:\\
                  \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B}{C} \cdot -0.5\right)}{\pi}\\
                  
                  
                  \end{array}
                  \end{array}
                  
                  Derivation
                  1. Split input into 3 regimes
                  2. if C < -4.9999999999999997e-127

                    1. Initial program 71.6%

                      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                    2. Taylor expanded in B around -inf

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
                    3. Step-by-step derivation
                      1. associate--l+N/A

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
                      2. div-subN/A

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                      3. lower-+.f64N/A

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
                      4. lower-/.f64N/A

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                      5. lift--.f6471.7

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
                    4. Applied rewrites71.7%

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
                    5. Taylor expanded in A around 0

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi} \]
                    6. Step-by-step derivation
                      1. Applied rewrites68.1%

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi} \]

                      if -4.9999999999999997e-127 < C < 6.0999999999999998e29

                      1. Initial program 54.8%

                        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                      2. Taylor expanded in B around -inf

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
                      3. Step-by-step derivation
                        1. associate--l+N/A

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
                        2. div-subN/A

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                        3. lower-+.f64N/A

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
                        4. lower-/.f64N/A

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                        5. lift--.f6447.3

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
                      4. Applied rewrites47.3%

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
                      5. Taylor expanded in C around 0

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]
                      6. Step-by-step derivation
                        1. lower--.f64N/A

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{\color{blue}{B}}\right)}{\pi} \]
                        2. lift-/.f6446.7

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi} \]
                      7. Applied rewrites46.7%

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]

                      if 6.0999999999999998e29 < C

                      1. Initial program 23.7%

                        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                      2. Taylor expanded in A around -inf

                        \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}}{\pi} \]
                      3. Step-by-step derivation
                        1. lower-atan.f64N/A

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
                        2. lower-/.f64N/A

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
                      4. Applied rewrites57.2%

                        \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
                      5. Step-by-step derivation
                        1. lift-*.f64N/A

                          \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
                        2. lift-/.f64N/A

                          \[\leadsto 180 \cdot \color{blue}{\frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
                        3. associate-*r/N/A

                          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
                        4. lower-/.f64N/A

                          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
                        5. lower-*.f6457.2

                          \[\leadsto \frac{\color{blue}{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
                      6. Applied rewrites57.2%

                        \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
                      7. Taylor expanded in B around 0

                        \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}{\pi} \]
                      8. Step-by-step derivation
                        1. *-commutativeN/A

                          \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
                        2. lower-*.f64N/A

                          \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
                        3. lower-/.f64N/A

                          \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
                        4. lift--.f6474.0

                          \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi} \]
                      9. Applied rewrites74.0%

                        \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi} \]
                      10. Taylor expanded in A around 0

                        \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C} \cdot \frac{-1}{2}\right)}{\pi} \]
                      11. Step-by-step derivation
                        1. Applied rewrites69.1%

                          \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{C} \cdot -0.5\right)}{\pi} \]
                      12. Recombined 3 regimes into one program.
                      13. Add Preprocessing

                      Alternative 11: 59.0% accurate, 2.2× speedup?

                      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;A \leq -1.3 \cdot 10^{+55}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi}\\ \mathbf{elif}\;A \leq 7.4 \cdot 10^{-104}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \end{array} \end{array} \]
                      (FPCore (A B C)
                       :precision binary64
                       (if (<= A -1.3e+55)
                         (/ (* 180.0 (atan (* (/ B A) 0.5))) PI)
                         (if (<= A 7.4e-104)
                           (* 180.0 (/ (atan (+ 1.0 (/ C B))) PI))
                           (* 180.0 (/ (atan (- 1.0 (/ A B))) PI)))))
                      double code(double A, double B, double C) {
                      	double tmp;
                      	if (A <= -1.3e+55) {
                      		tmp = (180.0 * atan(((B / A) * 0.5))) / ((double) M_PI);
                      	} else if (A <= 7.4e-104) {
                      		tmp = 180.0 * (atan((1.0 + (C / B))) / ((double) M_PI));
                      	} else {
                      		tmp = 180.0 * (atan((1.0 - (A / B))) / ((double) M_PI));
                      	}
                      	return tmp;
                      }
                      
                      public static double code(double A, double B, double C) {
                      	double tmp;
                      	if (A <= -1.3e+55) {
                      		tmp = (180.0 * Math.atan(((B / A) * 0.5))) / Math.PI;
                      	} else if (A <= 7.4e-104) {
                      		tmp = 180.0 * (Math.atan((1.0 + (C / B))) / Math.PI);
                      	} else {
                      		tmp = 180.0 * (Math.atan((1.0 - (A / B))) / Math.PI);
                      	}
                      	return tmp;
                      }
                      
                      def code(A, B, C):
                      	tmp = 0
                      	if A <= -1.3e+55:
                      		tmp = (180.0 * math.atan(((B / A) * 0.5))) / math.pi
                      	elif A <= 7.4e-104:
                      		tmp = 180.0 * (math.atan((1.0 + (C / B))) / math.pi)
                      	else:
                      		tmp = 180.0 * (math.atan((1.0 - (A / B))) / math.pi)
                      	return tmp
                      
                      function code(A, B, C)
                      	tmp = 0.0
                      	if (A <= -1.3e+55)
                      		tmp = Float64(Float64(180.0 * atan(Float64(Float64(B / A) * 0.5))) / pi);
                      	elseif (A <= 7.4e-104)
                      		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + Float64(C / B))) / pi));
                      	else
                      		tmp = Float64(180.0 * Float64(atan(Float64(1.0 - Float64(A / B))) / pi));
                      	end
                      	return tmp
                      end
                      
                      function tmp_2 = code(A, B, C)
                      	tmp = 0.0;
                      	if (A <= -1.3e+55)
                      		tmp = (180.0 * atan(((B / A) * 0.5))) / pi;
                      	elseif (A <= 7.4e-104)
                      		tmp = 180.0 * (atan((1.0 + (C / B))) / pi);
                      	else
                      		tmp = 180.0 * (atan((1.0 - (A / B))) / pi);
                      	end
                      	tmp_2 = tmp;
                      end
                      
                      code[A_, B_, C_] := If[LessEqual[A, -1.3e+55], N[(N[(180.0 * N[ArcTan[N[(N[(B / A), $MachinePrecision] * 0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision], If[LessEqual[A, 7.4e-104], N[(180.0 * N[(N[ArcTan[N[(1.0 + N[(C / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]
                      
                      \begin{array}{l}
                      
                      \\
                      \begin{array}{l}
                      \mathbf{if}\;A \leq -1.3 \cdot 10^{+55}:\\
                      \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi}\\
                      
                      \mathbf{elif}\;A \leq 7.4 \cdot 10^{-104}:\\
                      \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi}\\
                      
                      \mathbf{else}:\\
                      \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\
                      
                      
                      \end{array}
                      \end{array}
                      
                      Derivation
                      1. Split input into 3 regimes
                      2. if A < -1.3e55

                        1. Initial program 21.7%

                          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                        2. Taylor expanded in A around -inf

                          \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}}{\pi} \]
                        3. Step-by-step derivation
                          1. lower-atan.f64N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
                          2. lower-/.f64N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
                        4. Applied rewrites57.2%

                          \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
                        5. Step-by-step derivation
                          1. lift-*.f64N/A

                            \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
                          2. lift-/.f64N/A

                            \[\leadsto 180 \cdot \color{blue}{\frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
                          3. associate-*r/N/A

                            \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
                          4. lower-/.f64N/A

                            \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
                          5. lower-*.f6457.2

                            \[\leadsto \frac{\color{blue}{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
                        6. Applied rewrites57.2%

                          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}{\pi}} \]
                        7. Taylor expanded in A around -inf

                          \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{1}{2} \cdot \frac{B}{A}\right)}{\pi} \]
                        8. Step-by-step derivation
                          1. *-commutativeN/A

                            \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi} \]
                          2. lower-*.f64N/A

                            \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi} \]
                          3. lower-/.f6472.1

                            \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \]
                        9. Applied rewrites72.1%

                          \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \]

                        if -1.3e55 < A < 7.3999999999999999e-104

                        1. Initial program 53.2%

                          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                        2. Taylor expanded in B around -inf

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
                        3. Step-by-step derivation
                          1. associate--l+N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
                          2. div-subN/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                          3. lower-+.f64N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
                          4. lower-/.f64N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                          5. lift--.f6445.7

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
                        4. Applied rewrites45.7%

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
                        5. Taylor expanded in A around 0

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi} \]
                        6. Step-by-step derivation
                          1. Applied rewrites44.8%

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi} \]

                          if 7.3999999999999999e-104 < A

                          1. Initial program 73.0%

                            \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                          2. Taylor expanded in B around -inf

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
                          3. Step-by-step derivation
                            1. associate--l+N/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
                            2. div-subN/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                            3. lower-+.f64N/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
                            4. lower-/.f64N/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                            5. lift--.f6474.0

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
                          4. Applied rewrites74.0%

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
                          5. Taylor expanded in C around 0

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]
                          6. Step-by-step derivation
                            1. lower--.f64N/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{\color{blue}{B}}\right)}{\pi} \]
                            2. lift-/.f6470.7

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi} \]
                          7. Applied rewrites70.7%

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]
                        7. Recombined 3 regimes into one program.
                        8. Add Preprocessing

                        Alternative 12: 50.8% accurate, 2.5× speedup?

                        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq 5.8 \cdot 10^{-108}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
                        (FPCore (A B C)
                         :precision binary64
                         (if (<= B 5.8e-108)
                           (* 180.0 (/ (atan (+ 1.0 (/ C B))) PI))
                           (* 180.0 (/ (atan -1.0) PI))))
                        double code(double A, double B, double C) {
                        	double tmp;
                        	if (B <= 5.8e-108) {
                        		tmp = 180.0 * (atan((1.0 + (C / B))) / ((double) M_PI));
                        	} else {
                        		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
                        	}
                        	return tmp;
                        }
                        
                        public static double code(double A, double B, double C) {
                        	double tmp;
                        	if (B <= 5.8e-108) {
                        		tmp = 180.0 * (Math.atan((1.0 + (C / B))) / Math.PI);
                        	} else {
                        		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
                        	}
                        	return tmp;
                        }
                        
                        def code(A, B, C):
                        	tmp = 0
                        	if B <= 5.8e-108:
                        		tmp = 180.0 * (math.atan((1.0 + (C / B))) / math.pi)
                        	else:
                        		tmp = 180.0 * (math.atan(-1.0) / math.pi)
                        	return tmp
                        
                        function code(A, B, C)
                        	tmp = 0.0
                        	if (B <= 5.8e-108)
                        		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + Float64(C / B))) / pi));
                        	else
                        		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
                        	end
                        	return tmp
                        end
                        
                        function tmp_2 = code(A, B, C)
                        	tmp = 0.0;
                        	if (B <= 5.8e-108)
                        		tmp = 180.0 * (atan((1.0 + (C / B))) / pi);
                        	else
                        		tmp = 180.0 * (atan(-1.0) / pi);
                        	end
                        	tmp_2 = tmp;
                        end
                        
                        code[A_, B_, C_] := If[LessEqual[B, 5.8e-108], N[(180.0 * N[(N[ArcTan[N[(1.0 + N[(C / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]
                        
                        \begin{array}{l}
                        
                        \\
                        \begin{array}{l}
                        \mathbf{if}\;B \leq 5.8 \cdot 10^{-108}:\\
                        \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi}\\
                        
                        \mathbf{else}:\\
                        \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
                        
                        
                        \end{array}
                        \end{array}
                        
                        Derivation
                        1. Split input into 2 regimes
                        2. if B < 5.8000000000000002e-108

                          1. Initial program 54.1%

                            \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                          2. Taylor expanded in B around -inf

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
                          3. Step-by-step derivation
                            1. associate--l+N/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
                            2. div-subN/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                            3. lower-+.f64N/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
                            4. lower-/.f64N/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                            5. lift--.f6461.5

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
                          4. Applied rewrites61.5%

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
                          5. Taylor expanded in A around 0

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi} \]
                          6. Step-by-step derivation
                            1. Applied rewrites49.3%

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi} \]

                            if 5.8000000000000002e-108 < B

                            1. Initial program 52.2%

                              \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                            2. Taylor expanded in B around inf

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                            3. Step-by-step derivation
                              1. Applied rewrites52.8%

                                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                            4. Recombined 2 regimes into one program.
                            5. Add Preprocessing

                            Alternative 13: 50.8% accurate, 2.5× speedup?

                            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq 5.8 \cdot 10^{-108}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{C}{B} + 1\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
                            (FPCore (A B C)
                             :precision binary64
                             (if (<= B 5.8e-108)
                               (/ (* 180.0 (atan (+ (/ C B) 1.0))) PI)
                               (* 180.0 (/ (atan -1.0) PI))))
                            double code(double A, double B, double C) {
                            	double tmp;
                            	if (B <= 5.8e-108) {
                            		tmp = (180.0 * atan(((C / B) + 1.0))) / ((double) M_PI);
                            	} else {
                            		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
                            	}
                            	return tmp;
                            }
                            
                            public static double code(double A, double B, double C) {
                            	double tmp;
                            	if (B <= 5.8e-108) {
                            		tmp = (180.0 * Math.atan(((C / B) + 1.0))) / Math.PI;
                            	} else {
                            		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
                            	}
                            	return tmp;
                            }
                            
                            def code(A, B, C):
                            	tmp = 0
                            	if B <= 5.8e-108:
                            		tmp = (180.0 * math.atan(((C / B) + 1.0))) / math.pi
                            	else:
                            		tmp = 180.0 * (math.atan(-1.0) / math.pi)
                            	return tmp
                            
                            function code(A, B, C)
                            	tmp = 0.0
                            	if (B <= 5.8e-108)
                            		tmp = Float64(Float64(180.0 * atan(Float64(Float64(C / B) + 1.0))) / pi);
                            	else
                            		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
                            	end
                            	return tmp
                            end
                            
                            function tmp_2 = code(A, B, C)
                            	tmp = 0.0;
                            	if (B <= 5.8e-108)
                            		tmp = (180.0 * atan(((C / B) + 1.0))) / pi;
                            	else
                            		tmp = 180.0 * (atan(-1.0) / pi);
                            	end
                            	tmp_2 = tmp;
                            end
                            
                            code[A_, B_, C_] := If[LessEqual[B, 5.8e-108], N[(N[(180.0 * N[ArcTan[N[(N[(C / B), $MachinePrecision] + 1.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]
                            
                            \begin{array}{l}
                            
                            \\
                            \begin{array}{l}
                            \mathbf{if}\;B \leq 5.8 \cdot 10^{-108}:\\
                            \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{C}{B} + 1\right)}{\pi}\\
                            
                            \mathbf{else}:\\
                            \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
                            
                            
                            \end{array}
                            \end{array}
                            
                            Derivation
                            1. Split input into 2 regimes
                            2. if B < 5.8000000000000002e-108

                              1. Initial program 54.1%

                                \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                              2. Taylor expanded in B around -inf

                                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
                              3. Step-by-step derivation
                                1. associate--l+N/A

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
                                2. div-subN/A

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                                3. lower-+.f64N/A

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
                                4. lower-/.f64N/A

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                                5. lift--.f6461.5

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
                              4. Applied rewrites61.5%

                                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
                              5. Step-by-step derivation
                                1. lift-*.f64N/A

                                  \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}} \]
                                2. lift-/.f64N/A

                                  \[\leadsto 180 \cdot \color{blue}{\frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}} \]
                                3. associate-*r/N/A

                                  \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}} \]
                                4. lower-/.f64N/A

                                  \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}} \]
                              6. Applied rewrites61.5%

                                \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{C - A}{B} + 1\right)}{\pi}} \]
                              7. Taylor expanded in A around 0

                                \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{C}{B} + 1\right)}{\pi} \]
                              8. Step-by-step derivation
                                1. Applied rewrites49.3%

                                  \[\leadsto \frac{180 \cdot \tan^{-1} \left(\frac{C}{B} + 1\right)}{\pi} \]

                                if 5.8000000000000002e-108 < B

                                1. Initial program 52.2%

                                  \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                2. Taylor expanded in B around inf

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                3. Step-by-step derivation
                                  1. Applied rewrites52.8%

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                4. Recombined 2 regimes into one program.
                                5. Add Preprocessing

                                Alternative 14: 50.5% accurate, 2.2× speedup?

                                \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq -1.75 \cdot 10^{-245}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \mathbf{elif}\;B \leq 5.8 \cdot 10^{-108}:\\ \;\;\;\;\frac{\tan^{-1} \left(\frac{C + C}{B}\right)}{\pi} \cdot 180\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
                                (FPCore (A B C)
                                 :precision binary64
                                 (if (<= B -1.75e-245)
                                   (* 180.0 (/ (atan (- 1.0 (/ A B))) PI))
                                   (if (<= B 5.8e-108)
                                     (* (/ (atan (/ (+ C C) B)) PI) 180.0)
                                     (* 180.0 (/ (atan -1.0) PI)))))
                                double code(double A, double B, double C) {
                                	double tmp;
                                	if (B <= -1.75e-245) {
                                		tmp = 180.0 * (atan((1.0 - (A / B))) / ((double) M_PI));
                                	} else if (B <= 5.8e-108) {
                                		tmp = (atan(((C + C) / B)) / ((double) M_PI)) * 180.0;
                                	} else {
                                		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
                                	}
                                	return tmp;
                                }
                                
                                public static double code(double A, double B, double C) {
                                	double tmp;
                                	if (B <= -1.75e-245) {
                                		tmp = 180.0 * (Math.atan((1.0 - (A / B))) / Math.PI);
                                	} else if (B <= 5.8e-108) {
                                		tmp = (Math.atan(((C + C) / B)) / Math.PI) * 180.0;
                                	} else {
                                		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
                                	}
                                	return tmp;
                                }
                                
                                def code(A, B, C):
                                	tmp = 0
                                	if B <= -1.75e-245:
                                		tmp = 180.0 * (math.atan((1.0 - (A / B))) / math.pi)
                                	elif B <= 5.8e-108:
                                		tmp = (math.atan(((C + C) / B)) / math.pi) * 180.0
                                	else:
                                		tmp = 180.0 * (math.atan(-1.0) / math.pi)
                                	return tmp
                                
                                function code(A, B, C)
                                	tmp = 0.0
                                	if (B <= -1.75e-245)
                                		tmp = Float64(180.0 * Float64(atan(Float64(1.0 - Float64(A / B))) / pi));
                                	elseif (B <= 5.8e-108)
                                		tmp = Float64(Float64(atan(Float64(Float64(C + C) / B)) / pi) * 180.0);
                                	else
                                		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
                                	end
                                	return tmp
                                end
                                
                                function tmp_2 = code(A, B, C)
                                	tmp = 0.0;
                                	if (B <= -1.75e-245)
                                		tmp = 180.0 * (atan((1.0 - (A / B))) / pi);
                                	elseif (B <= 5.8e-108)
                                		tmp = (atan(((C + C) / B)) / pi) * 180.0;
                                	else
                                		tmp = 180.0 * (atan(-1.0) / pi);
                                	end
                                	tmp_2 = tmp;
                                end
                                
                                code[A_, B_, C_] := If[LessEqual[B, -1.75e-245], N[(180.0 * N[(N[ArcTan[N[(1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[B, 5.8e-108], N[(N[(N[ArcTan[N[(N[(C + C), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision] * 180.0), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]
                                
                                \begin{array}{l}
                                
                                \\
                                \begin{array}{l}
                                \mathbf{if}\;B \leq -1.75 \cdot 10^{-245}:\\
                                \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\
                                
                                \mathbf{elif}\;B \leq 5.8 \cdot 10^{-108}:\\
                                \;\;\;\;\frac{\tan^{-1} \left(\frac{C + C}{B}\right)}{\pi} \cdot 180\\
                                
                                \mathbf{else}:\\
                                \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
                                
                                
                                \end{array}
                                \end{array}
                                
                                Derivation
                                1. Split input into 3 regimes
                                2. if B < -1.75000000000000008e-245

                                  1. Initial program 51.6%

                                    \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                  2. Taylor expanded in B around -inf

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
                                  3. Step-by-step derivation
                                    1. associate--l+N/A

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
                                    2. div-subN/A

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                                    3. lower-+.f64N/A

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
                                    4. lower-/.f64N/A

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                                    5. lift--.f6466.5

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
                                  4. Applied rewrites66.5%

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
                                  5. Taylor expanded in C around 0

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]
                                  6. Step-by-step derivation
                                    1. lower--.f64N/A

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{\color{blue}{B}}\right)}{\pi} \]
                                    2. lift-/.f6456.8

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi} \]
                                  7. Applied rewrites56.8%

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]

                                  if -1.75000000000000008e-245 < B < 5.8000000000000002e-108

                                  1. Initial program 59.5%

                                    \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                  2. Taylor expanded in C around -inf

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(2 \cdot \frac{C}{B}\right)}}{\pi} \]
                                  3. Step-by-step derivation
                                    1. associate-*r/N/A

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{2 \cdot C}{\color{blue}{B}}\right)}{\pi} \]
                                    2. lower-/.f64N/A

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{2 \cdot C}{\color{blue}{B}}\right)}{\pi} \]
                                    3. count-2-revN/A

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C + C}{B}\right)}{\pi} \]
                                    4. lower-+.f6434.8

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C + C}{B}\right)}{\pi} \]
                                  4. Applied rewrites34.8%

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C + C}{B}\right)}}{\pi} \]
                                  5. Step-by-step derivation
                                    1. lift-*.f64N/A

                                      \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{C + C}{B}\right)}{\pi}} \]
                                    2. *-commutativeN/A

                                      \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{C + C}{B}\right)}{\pi} \cdot 180} \]
                                    3. lower-*.f6434.8

                                      \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{C + C}{B}\right)}{\pi} \cdot 180} \]
                                    4. *-commutative34.8

                                      \[\leadsto \frac{\tan^{-1} \left(\frac{\color{blue}{C + C}}{B}\right)}{\pi} \cdot 180 \]
                                  6. Applied rewrites34.8%

                                    \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{C + C}{B}\right)}{\pi} \cdot 180} \]

                                  if 5.8000000000000002e-108 < B

                                  1. Initial program 52.2%

                                    \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                  2. Taylor expanded in B around inf

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                  3. Step-by-step derivation
                                    1. Applied rewrites52.8%

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                  4. Recombined 3 regimes into one program.
                                  5. Add Preprocessing

                                  Alternative 15: 50.5% accurate, 2.4× speedup?

                                  \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq -1.75 \cdot 10^{-245}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \mathbf{elif}\;B \leq 5.8 \cdot 10^{-108}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
                                  (FPCore (A B C)
                                   :precision binary64
                                   (if (<= B -1.75e-245)
                                     (* 180.0 (/ (atan (- 1.0 (/ A B))) PI))
                                     (if (<= B 5.8e-108)
                                       (* 180.0 (/ (atan (/ C B)) PI))
                                       (* 180.0 (/ (atan -1.0) PI)))))
                                  double code(double A, double B, double C) {
                                  	double tmp;
                                  	if (B <= -1.75e-245) {
                                  		tmp = 180.0 * (atan((1.0 - (A / B))) / ((double) M_PI));
                                  	} else if (B <= 5.8e-108) {
                                  		tmp = 180.0 * (atan((C / B)) / ((double) M_PI));
                                  	} else {
                                  		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
                                  	}
                                  	return tmp;
                                  }
                                  
                                  public static double code(double A, double B, double C) {
                                  	double tmp;
                                  	if (B <= -1.75e-245) {
                                  		tmp = 180.0 * (Math.atan((1.0 - (A / B))) / Math.PI);
                                  	} else if (B <= 5.8e-108) {
                                  		tmp = 180.0 * (Math.atan((C / B)) / Math.PI);
                                  	} else {
                                  		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
                                  	}
                                  	return tmp;
                                  }
                                  
                                  def code(A, B, C):
                                  	tmp = 0
                                  	if B <= -1.75e-245:
                                  		tmp = 180.0 * (math.atan((1.0 - (A / B))) / math.pi)
                                  	elif B <= 5.8e-108:
                                  		tmp = 180.0 * (math.atan((C / B)) / math.pi)
                                  	else:
                                  		tmp = 180.0 * (math.atan(-1.0) / math.pi)
                                  	return tmp
                                  
                                  function code(A, B, C)
                                  	tmp = 0.0
                                  	if (B <= -1.75e-245)
                                  		tmp = Float64(180.0 * Float64(atan(Float64(1.0 - Float64(A / B))) / pi));
                                  	elseif (B <= 5.8e-108)
                                  		tmp = Float64(180.0 * Float64(atan(Float64(C / B)) / pi));
                                  	else
                                  		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
                                  	end
                                  	return tmp
                                  end
                                  
                                  function tmp_2 = code(A, B, C)
                                  	tmp = 0.0;
                                  	if (B <= -1.75e-245)
                                  		tmp = 180.0 * (atan((1.0 - (A / B))) / pi);
                                  	elseif (B <= 5.8e-108)
                                  		tmp = 180.0 * (atan((C / B)) / pi);
                                  	else
                                  		tmp = 180.0 * (atan(-1.0) / pi);
                                  	end
                                  	tmp_2 = tmp;
                                  end
                                  
                                  code[A_, B_, C_] := If[LessEqual[B, -1.75e-245], N[(180.0 * N[(N[ArcTan[N[(1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[B, 5.8e-108], N[(180.0 * N[(N[ArcTan[N[(C / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]
                                  
                                  \begin{array}{l}
                                  
                                  \\
                                  \begin{array}{l}
                                  \mathbf{if}\;B \leq -1.75 \cdot 10^{-245}:\\
                                  \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\
                                  
                                  \mathbf{elif}\;B \leq 5.8 \cdot 10^{-108}:\\
                                  \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C}{B}\right)}{\pi}\\
                                  
                                  \mathbf{else}:\\
                                  \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
                                  
                                  
                                  \end{array}
                                  \end{array}
                                  
                                  Derivation
                                  1. Split input into 3 regimes
                                  2. if B < -1.75000000000000008e-245

                                    1. Initial program 51.6%

                                      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                    2. Taylor expanded in B around -inf

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
                                    3. Step-by-step derivation
                                      1. associate--l+N/A

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
                                      2. div-subN/A

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                                      3. lower-+.f64N/A

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
                                      4. lower-/.f64N/A

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                                      5. lift--.f6466.5

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
                                    4. Applied rewrites66.5%

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
                                    5. Taylor expanded in C around 0

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]
                                    6. Step-by-step derivation
                                      1. lower--.f64N/A

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{\color{blue}{B}}\right)}{\pi} \]
                                      2. lift-/.f6456.8

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi} \]
                                    7. Applied rewrites56.8%

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]

                                    if -1.75000000000000008e-245 < B < 5.8000000000000002e-108

                                    1. Initial program 59.5%

                                      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                    2. Taylor expanded in B around -inf

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
                                    3. Step-by-step derivation
                                      1. associate--l+N/A

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
                                      2. div-subN/A

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                                      3. lower-+.f64N/A

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
                                      4. lower-/.f64N/A

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                                      5. lift--.f6451.0

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
                                    4. Applied rewrites51.0%

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
                                    5. Taylor expanded in C around inf

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C}{\color{blue}{B}}\right)}{\pi} \]
                                    6. Step-by-step derivation
                                      1. lower-/.f6434.8

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C}{B}\right)}{\pi} \]
                                    7. Applied rewrites34.8%

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C}{\color{blue}{B}}\right)}{\pi} \]

                                    if 5.8000000000000002e-108 < B

                                    1. Initial program 52.2%

                                      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                    2. Taylor expanded in B around inf

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                    3. Step-by-step derivation
                                      1. Applied rewrites52.8%

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                    4. Recombined 3 regimes into one program.
                                    5. Add Preprocessing

                                    Alternative 16: 45.7% accurate, 2.4× speedup?

                                    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq -3.8 \cdot 10^{-158}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\ \mathbf{elif}\;B \leq 5.8 \cdot 10^{-108}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
                                    (FPCore (A B C)
                                     :precision binary64
                                     (if (<= B -3.8e-158)
                                       (* 180.0 (/ (atan 1.0) PI))
                                       (if (<= B 5.8e-108)
                                         (* 180.0 (/ (atan (/ C B)) PI))
                                         (* 180.0 (/ (atan -1.0) PI)))))
                                    double code(double A, double B, double C) {
                                    	double tmp;
                                    	if (B <= -3.8e-158) {
                                    		tmp = 180.0 * (atan(1.0) / ((double) M_PI));
                                    	} else if (B <= 5.8e-108) {
                                    		tmp = 180.0 * (atan((C / B)) / ((double) M_PI));
                                    	} else {
                                    		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
                                    	}
                                    	return tmp;
                                    }
                                    
                                    public static double code(double A, double B, double C) {
                                    	double tmp;
                                    	if (B <= -3.8e-158) {
                                    		tmp = 180.0 * (Math.atan(1.0) / Math.PI);
                                    	} else if (B <= 5.8e-108) {
                                    		tmp = 180.0 * (Math.atan((C / B)) / Math.PI);
                                    	} else {
                                    		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
                                    	}
                                    	return tmp;
                                    }
                                    
                                    def code(A, B, C):
                                    	tmp = 0
                                    	if B <= -3.8e-158:
                                    		tmp = 180.0 * (math.atan(1.0) / math.pi)
                                    	elif B <= 5.8e-108:
                                    		tmp = 180.0 * (math.atan((C / B)) / math.pi)
                                    	else:
                                    		tmp = 180.0 * (math.atan(-1.0) / math.pi)
                                    	return tmp
                                    
                                    function code(A, B, C)
                                    	tmp = 0.0
                                    	if (B <= -3.8e-158)
                                    		tmp = Float64(180.0 * Float64(atan(1.0) / pi));
                                    	elseif (B <= 5.8e-108)
                                    		tmp = Float64(180.0 * Float64(atan(Float64(C / B)) / pi));
                                    	else
                                    		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
                                    	end
                                    	return tmp
                                    end
                                    
                                    function tmp_2 = code(A, B, C)
                                    	tmp = 0.0;
                                    	if (B <= -3.8e-158)
                                    		tmp = 180.0 * (atan(1.0) / pi);
                                    	elseif (B <= 5.8e-108)
                                    		tmp = 180.0 * (atan((C / B)) / pi);
                                    	else
                                    		tmp = 180.0 * (atan(-1.0) / pi);
                                    	end
                                    	tmp_2 = tmp;
                                    end
                                    
                                    code[A_, B_, C_] := If[LessEqual[B, -3.8e-158], N[(180.0 * N[(N[ArcTan[1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[B, 5.8e-108], N[(180.0 * N[(N[ArcTan[N[(C / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]
                                    
                                    \begin{array}{l}
                                    
                                    \\
                                    \begin{array}{l}
                                    \mathbf{if}\;B \leq -3.8 \cdot 10^{-158}:\\
                                    \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\
                                    
                                    \mathbf{elif}\;B \leq 5.8 \cdot 10^{-108}:\\
                                    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C}{B}\right)}{\pi}\\
                                    
                                    \mathbf{else}:\\
                                    \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
                                    
                                    
                                    \end{array}
                                    \end{array}
                                    
                                    Derivation
                                    1. Split input into 3 regimes
                                    2. if B < -3.7999999999999999e-158

                                      1. Initial program 51.6%

                                        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                      2. Taylor expanded in B around -inf

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\pi} \]
                                      3. Step-by-step derivation
                                        1. Applied rewrites48.4%

                                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\pi} \]

                                        if -3.7999999999999999e-158 < B < 5.8000000000000002e-108

                                        1. Initial program 57.4%

                                          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                        2. Taylor expanded in B around -inf

                                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
                                        3. Step-by-step derivation
                                          1. associate--l+N/A

                                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
                                          2. div-subN/A

                                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                                          3. lower-+.f64N/A

                                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
                                          4. lower-/.f64N/A

                                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                                          5. lift--.f6450.4

                                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
                                        4. Applied rewrites50.4%

                                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
                                        5. Taylor expanded in C around inf

                                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C}{\color{blue}{B}}\right)}{\pi} \]
                                        6. Step-by-step derivation
                                          1. lower-/.f6433.8

                                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C}{B}\right)}{\pi} \]
                                        7. Applied rewrites33.8%

                                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C}{\color{blue}{B}}\right)}{\pi} \]

                                        if 5.8000000000000002e-108 < B

                                        1. Initial program 52.2%

                                          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                        2. Taylor expanded in B around inf

                                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                        3. Step-by-step derivation
                                          1. Applied rewrites52.8%

                                            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                        4. Recombined 3 regimes into one program.
                                        5. Add Preprocessing

                                        Alternative 17: 39.9% accurate, 3.3× speedup?

                                        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq -1 \cdot 10^{-309}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
                                        (FPCore (A B C)
                                         :precision binary64
                                         (if (<= B -1e-309) (* 180.0 (/ (atan 1.0) PI)) (* 180.0 (/ (atan -1.0) PI))))
                                        double code(double A, double B, double C) {
                                        	double tmp;
                                        	if (B <= -1e-309) {
                                        		tmp = 180.0 * (atan(1.0) / ((double) M_PI));
                                        	} else {
                                        		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
                                        	}
                                        	return tmp;
                                        }
                                        
                                        public static double code(double A, double B, double C) {
                                        	double tmp;
                                        	if (B <= -1e-309) {
                                        		tmp = 180.0 * (Math.atan(1.0) / Math.PI);
                                        	} else {
                                        		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
                                        	}
                                        	return tmp;
                                        }
                                        
                                        def code(A, B, C):
                                        	tmp = 0
                                        	if B <= -1e-309:
                                        		tmp = 180.0 * (math.atan(1.0) / math.pi)
                                        	else:
                                        		tmp = 180.0 * (math.atan(-1.0) / math.pi)
                                        	return tmp
                                        
                                        function code(A, B, C)
                                        	tmp = 0.0
                                        	if (B <= -1e-309)
                                        		tmp = Float64(180.0 * Float64(atan(1.0) / pi));
                                        	else
                                        		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
                                        	end
                                        	return tmp
                                        end
                                        
                                        function tmp_2 = code(A, B, C)
                                        	tmp = 0.0;
                                        	if (B <= -1e-309)
                                        		tmp = 180.0 * (atan(1.0) / pi);
                                        	else
                                        		tmp = 180.0 * (atan(-1.0) / pi);
                                        	end
                                        	tmp_2 = tmp;
                                        end
                                        
                                        code[A_, B_, C_] := If[LessEqual[B, -1e-309], N[(180.0 * N[(N[ArcTan[1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]
                                        
                                        \begin{array}{l}
                                        
                                        \\
                                        \begin{array}{l}
                                        \mathbf{if}\;B \leq -1 \cdot 10^{-309}:\\
                                        \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\
                                        
                                        \mathbf{else}:\\
                                        \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
                                        
                                        
                                        \end{array}
                                        \end{array}
                                        
                                        Derivation
                                        1. Split input into 2 regimes
                                        2. if B < -1.000000000000002e-309

                                          1. Initial program 52.6%

                                            \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                          2. Taylor expanded in B around -inf

                                            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\pi} \]
                                          3. Step-by-step derivation
                                            1. Applied rewrites39.4%

                                              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\pi} \]

                                            if -1.000000000000002e-309 < B

                                            1. Initial program 54.3%

                                              \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                            2. Taylor expanded in B around inf

                                              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                            3. Step-by-step derivation
                                              1. Applied rewrites40.3%

                                                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                            4. Recombined 2 regimes into one program.
                                            5. Add Preprocessing

                                            Alternative 18: 21.1% accurate, 4.1× speedup?

                                            \[\begin{array}{l} \\ 180 \cdot \frac{\tan^{-1} -1}{\pi} \end{array} \]
                                            (FPCore (A B C) :precision binary64 (* 180.0 (/ (atan -1.0) PI)))
                                            double code(double A, double B, double C) {
                                            	return 180.0 * (atan(-1.0) / ((double) M_PI));
                                            }
                                            
                                            public static double code(double A, double B, double C) {
                                            	return 180.0 * (Math.atan(-1.0) / Math.PI);
                                            }
                                            
                                            def code(A, B, C):
                                            	return 180.0 * (math.atan(-1.0) / math.pi)
                                            
                                            function code(A, B, C)
                                            	return Float64(180.0 * Float64(atan(-1.0) / pi))
                                            end
                                            
                                            function tmp = code(A, B, C)
                                            	tmp = 180.0 * (atan(-1.0) / pi);
                                            end
                                            
                                            code[A_, B_, C_] := N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]
                                            
                                            \begin{array}{l}
                                            
                                            \\
                                            180 \cdot \frac{\tan^{-1} -1}{\pi}
                                            \end{array}
                                            
                                            Derivation
                                            1. Initial program 53.5%

                                              \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                            2. Taylor expanded in B around inf

                                              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                            3. Step-by-step derivation
                                              1. Applied rewrites21.1%

                                                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                              2. Add Preprocessing

                                              Reproduce

                                              ?
                                              herbie shell --seed 2025112 
                                              (FPCore (A B C)
                                                :name "ABCF->ab-angle angle"
                                                :precision binary64
                                                (* 180.0 (/ (atan (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))) PI)))