ABCF->ab-angle angle

Percentage Accurate: 53.3% → 80.9%
Time: 5.1s
Alternatives: 14
Speedup: 1.5×

Specification

?
\[\begin{array}{l} \\ 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (*
  180.0
  (/
   (atan (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
   PI)))
double code(double A, double B, double C) {
	return 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / ((double) M_PI));
}
public static double code(double A, double B, double C) {
	return 180.0 * (Math.atan(((1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / Math.PI);
}
def code(A, B, C):
	return 180.0 * (math.atan(((1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / math.pi)
function code(A, B, C)
	return Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))) / pi))
end
function tmp = code(A, B, C)
	tmp = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / pi);
end
code[A_, B_, C_] := N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}
\end{array}

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 14 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 53.3% accurate, 1.0× speedup?

\[\begin{array}{l} \\ 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (*
  180.0
  (/
   (atan (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
   PI)))
double code(double A, double B, double C) {
	return 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / ((double) M_PI));
}
public static double code(double A, double B, double C) {
	return 180.0 * (Math.atan(((1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / Math.PI);
}
def code(A, B, C):
	return 180.0 * (math.atan(((1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / math.pi)
function code(A, B, C)
	return Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))) / pi))
end
function tmp = code(A, B, C)
	tmp = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / pi);
end
code[A_, B_, C_] := N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}
\end{array}

Alternative 1: 80.9% accurate, 1.4× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;A \leq -1.14 \cdot 10^{+136}:\\ \;\;\;\;\frac{\tan^{-1} \left(\frac{0.5 \cdot \mathsf{fma}\left(\frac{C}{A}, B, B\right)}{A}\right)}{\pi} \cdot 180\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \mathsf{hypot}\left(A - C, B\right)\right)\right)}{\pi}\\ \end{array} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (if (<= A -1.14e+136)
   (* (/ (atan (/ (* 0.5 (fma (/ C A) B B)) A)) PI) 180.0)
   (* 180.0 (/ (atan (* (/ 1.0 B) (- (- C A) (hypot (- A C) B)))) PI))))
double code(double A, double B, double C) {
	double tmp;
	if (A <= -1.14e+136) {
		tmp = (atan(((0.5 * fma((C / A), B, B)) / A)) / ((double) M_PI)) * 180.0;
	} else {
		tmp = 180.0 * (atan(((1.0 / B) * ((C - A) - hypot((A - C), B)))) / ((double) M_PI));
	}
	return tmp;
}
function code(A, B, C)
	tmp = 0.0
	if (A <= -1.14e+136)
		tmp = Float64(Float64(atan(Float64(Float64(0.5 * fma(Float64(C / A), B, B)) / A)) / pi) * 180.0);
	else
		tmp = Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(Float64(C - A) - hypot(Float64(A - C), B)))) / pi));
	end
	return tmp
end
code[A_, B_, C_] := If[LessEqual[A, -1.14e+136], N[(N[(N[ArcTan[N[(N[(0.5 * N[(N[(C / A), $MachinePrecision] * B + B), $MachinePrecision]), $MachinePrecision] / A), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision] * 180.0), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;A \leq -1.14 \cdot 10^{+136}:\\
\;\;\;\;\frac{\tan^{-1} \left(\frac{0.5 \cdot \mathsf{fma}\left(\frac{C}{A}, B, B\right)}{A}\right)}{\pi} \cdot 180\\

\mathbf{else}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \mathsf{hypot}\left(A - C, B\right)\right)\right)}{\pi}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if A < -1.14e136

    1. Initial program 14.2%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Taylor expanded in A around -inf

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{\frac{-1}{2} \cdot B + \frac{-1}{2} \cdot \frac{B \cdot C}{A}}{A}\right)}}{\pi} \]
    3. Step-by-step derivation
      1. mul-1-negN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\mathsf{neg}\left(\frac{\frac{-1}{2} \cdot B + \frac{-1}{2} \cdot \frac{B \cdot C}{A}}{A}\right)\right)}{\pi} \]
      2. lower-neg.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{\frac{-1}{2} \cdot B + \frac{-1}{2} \cdot \frac{B \cdot C}{A}}{A}\right)}{\pi} \]
      3. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{\frac{-1}{2} \cdot B + \frac{-1}{2} \cdot \frac{B \cdot C}{A}}{A}\right)}{\pi} \]
      4. distribute-lft-outN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{\frac{-1}{2} \cdot \left(B + \frac{B \cdot C}{A}\right)}{A}\right)}{\pi} \]
      5. lower-*.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{\frac{-1}{2} \cdot \left(B + \frac{B \cdot C}{A}\right)}{A}\right)}{\pi} \]
      6. lower-+.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{\frac{-1}{2} \cdot \left(B + \frac{B \cdot C}{A}\right)}{A}\right)}{\pi} \]
      7. associate-/l*N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{\frac{-1}{2} \cdot \left(B + B \cdot \frac{C}{A}\right)}{A}\right)}{\pi} \]
      8. lower-*.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{\frac{-1}{2} \cdot \left(B + B \cdot \frac{C}{A}\right)}{A}\right)}{\pi} \]
      9. lower-/.f6476.5

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{-0.5 \cdot \left(B + B \cdot \frac{C}{A}\right)}{A}\right)}{\pi} \]
    4. Applied rewrites76.5%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-\frac{-0.5 \cdot \left(B + B \cdot \frac{C}{A}\right)}{A}\right)}}{\pi} \]
    5. Applied rewrites76.5%

      \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{0.5 \cdot \mathsf{fma}\left(\frac{C}{A}, B, B\right)}{A}\right)}{\pi} \cdot 180} \]

    if -1.14e136 < A

    1. Initial program 59.7%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\pi} \]
      2. lift-+.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\pi} \]
      3. lift--.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\color{blue}{\left(A - C\right)}}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      4. lift-pow.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2}} + {B}^{2}}\right)\right)}{\pi} \]
      5. unpow2N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{\left(A - C\right) \cdot \left(A - C\right)} + {B}^{2}}\right)\right)}{\pi} \]
      6. lift-pow.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\left(A - C\right) \cdot \left(A - C\right) + \color{blue}{{B}^{2}}}\right)\right)}{\pi} \]
      7. unpow2N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\left(A - C\right) \cdot \left(A - C\right) + \color{blue}{B \cdot B}}\right)\right)}{\pi} \]
      8. lower-hypot.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\mathsf{hypot}\left(A - C, B\right)}\right)\right)}{\pi} \]
      9. lift--.f6481.6

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \mathsf{hypot}\left(\color{blue}{A - C}, B\right)\right)\right)}{\pi} \]
    3. Applied rewrites81.6%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\mathsf{hypot}\left(A - C, B\right)}\right)\right)}{\pi} \]
  3. Recombined 2 regimes into one program.
  4. Add Preprocessing

Alternative 2: 79.3% accurate, 1.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;A \leq -4.8 \cdot 10^{+47}:\\ \;\;\;\;\frac{\tan^{-1} \left(\frac{0.5 \cdot \mathsf{fma}\left(\frac{C}{A}, B, B\right)}{A}\right)}{\pi} \cdot 180\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(C - \mathsf{hypot}\left(A - C, B\right)\right)\right)}{\pi}\\ \end{array} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (if (<= A -4.8e+47)
   (* (/ (atan (/ (* 0.5 (fma (/ C A) B B)) A)) PI) 180.0)
   (* 180.0 (/ (atan (* (/ 1.0 B) (- C (hypot (- A C) B)))) PI))))
double code(double A, double B, double C) {
	double tmp;
	if (A <= -4.8e+47) {
		tmp = (atan(((0.5 * fma((C / A), B, B)) / A)) / ((double) M_PI)) * 180.0;
	} else {
		tmp = 180.0 * (atan(((1.0 / B) * (C - hypot((A - C), B)))) / ((double) M_PI));
	}
	return tmp;
}
function code(A, B, C)
	tmp = 0.0
	if (A <= -4.8e+47)
		tmp = Float64(Float64(atan(Float64(Float64(0.5 * fma(Float64(C / A), B, B)) / A)) / pi) * 180.0);
	else
		tmp = Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(C - hypot(Float64(A - C), B)))) / pi));
	end
	return tmp
end
code[A_, B_, C_] := If[LessEqual[A, -4.8e+47], N[(N[(N[ArcTan[N[(N[(0.5 * N[(N[(C / A), $MachinePrecision] * B + B), $MachinePrecision]), $MachinePrecision] / A), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision] * 180.0), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(C - N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;A \leq -4.8 \cdot 10^{+47}:\\
\;\;\;\;\frac{\tan^{-1} \left(\frac{0.5 \cdot \mathsf{fma}\left(\frac{C}{A}, B, B\right)}{A}\right)}{\pi} \cdot 180\\

\mathbf{else}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(C - \mathsf{hypot}\left(A - C, B\right)\right)\right)}{\pi}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if A < -4.80000000000000037e47

    1. Initial program 21.5%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Taylor expanded in A around -inf

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{\frac{-1}{2} \cdot B + \frac{-1}{2} \cdot \frac{B \cdot C}{A}}{A}\right)}}{\pi} \]
    3. Step-by-step derivation
      1. mul-1-negN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\mathsf{neg}\left(\frac{\frac{-1}{2} \cdot B + \frac{-1}{2} \cdot \frac{B \cdot C}{A}}{A}\right)\right)}{\pi} \]
      2. lower-neg.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{\frac{-1}{2} \cdot B + \frac{-1}{2} \cdot \frac{B \cdot C}{A}}{A}\right)}{\pi} \]
      3. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{\frac{-1}{2} \cdot B + \frac{-1}{2} \cdot \frac{B \cdot C}{A}}{A}\right)}{\pi} \]
      4. distribute-lft-outN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{\frac{-1}{2} \cdot \left(B + \frac{B \cdot C}{A}\right)}{A}\right)}{\pi} \]
      5. lower-*.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{\frac{-1}{2} \cdot \left(B + \frac{B \cdot C}{A}\right)}{A}\right)}{\pi} \]
      6. lower-+.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{\frac{-1}{2} \cdot \left(B + \frac{B \cdot C}{A}\right)}{A}\right)}{\pi} \]
      7. associate-/l*N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{\frac{-1}{2} \cdot \left(B + B \cdot \frac{C}{A}\right)}{A}\right)}{\pi} \]
      8. lower-*.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{\frac{-1}{2} \cdot \left(B + B \cdot \frac{C}{A}\right)}{A}\right)}{\pi} \]
      9. lower-/.f6467.4

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{-0.5 \cdot \left(B + B \cdot \frac{C}{A}\right)}{A}\right)}{\pi} \]
    4. Applied rewrites67.4%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-\frac{-0.5 \cdot \left(B + B \cdot \frac{C}{A}\right)}{A}\right)}}{\pi} \]
    5. Applied rewrites67.4%

      \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{0.5 \cdot \mathsf{fma}\left(\frac{C}{A}, B, B\right)}{A}\right)}{\pi} \cdot 180} \]

    if -4.80000000000000037e47 < A

    1. Initial program 61.9%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\pi} \]
      2. lift-+.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\pi} \]
      3. lift--.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\color{blue}{\left(A - C\right)}}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      4. lift-pow.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2}} + {B}^{2}}\right)\right)}{\pi} \]
      5. unpow2N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{\left(A - C\right) \cdot \left(A - C\right)} + {B}^{2}}\right)\right)}{\pi} \]
      6. lift-pow.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\left(A - C\right) \cdot \left(A - C\right) + \color{blue}{{B}^{2}}}\right)\right)}{\pi} \]
      7. unpow2N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\left(A - C\right) \cdot \left(A - C\right) + \color{blue}{B \cdot B}}\right)\right)}{\pi} \]
      8. lower-hypot.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\mathsf{hypot}\left(A - C, B\right)}\right)\right)}{\pi} \]
      9. lift--.f6483.4

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \mathsf{hypot}\left(\color{blue}{A - C}, B\right)\right)\right)}{\pi} \]
    3. Applied rewrites83.4%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\mathsf{hypot}\left(A - C, B\right)}\right)\right)}{\pi} \]
    4. Taylor expanded in A around 0

      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\color{blue}{C} - \mathsf{hypot}\left(A - C, B\right)\right)\right)}{\pi} \]
    5. Step-by-step derivation
      1. Applied rewrites82.6%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\color{blue}{C} - \mathsf{hypot}\left(A - C, B\right)\right)\right)}{\pi} \]
    6. Recombined 2 regimes into one program.
    7. Add Preprocessing

    Alternative 3: 76.3% accurate, 1.4× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;A \leq -4.8 \cdot 10^{+47}:\\ \;\;\;\;\frac{\tan^{-1} \left(\frac{0.5 \cdot \mathsf{fma}\left(\frac{C}{A}, B, B\right)}{A}\right)}{\pi} \cdot 180\\ \mathbf{elif}\;A \leq 4.8 \cdot 10^{+91}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(C - \mathsf{hypot}\left(-C, B\right)\right)\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(-A\right) - \mathsf{hypot}\left(A, B\right)\right)\right)}{\pi}\\ \end{array} \end{array} \]
    (FPCore (A B C)
     :precision binary64
     (if (<= A -4.8e+47)
       (* (/ (atan (/ (* 0.5 (fma (/ C A) B B)) A)) PI) 180.0)
       (if (<= A 4.8e+91)
         (* 180.0 (/ (atan (* (/ 1.0 B) (- C (hypot (- C) B)))) PI))
         (* 180.0 (/ (atan (* (/ 1.0 B) (- (- A) (hypot A B)))) PI)))))
    double code(double A, double B, double C) {
    	double tmp;
    	if (A <= -4.8e+47) {
    		tmp = (atan(((0.5 * fma((C / A), B, B)) / A)) / ((double) M_PI)) * 180.0;
    	} else if (A <= 4.8e+91) {
    		tmp = 180.0 * (atan(((1.0 / B) * (C - hypot(-C, B)))) / ((double) M_PI));
    	} else {
    		tmp = 180.0 * (atan(((1.0 / B) * (-A - hypot(A, B)))) / ((double) M_PI));
    	}
    	return tmp;
    }
    
    function code(A, B, C)
    	tmp = 0.0
    	if (A <= -4.8e+47)
    		tmp = Float64(Float64(atan(Float64(Float64(0.5 * fma(Float64(C / A), B, B)) / A)) / pi) * 180.0);
    	elseif (A <= 4.8e+91)
    		tmp = Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(C - hypot(Float64(-C), B)))) / pi));
    	else
    		tmp = Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(Float64(-A) - hypot(A, B)))) / pi));
    	end
    	return tmp
    end
    
    code[A_, B_, C_] := If[LessEqual[A, -4.8e+47], N[(N[(N[ArcTan[N[(N[(0.5 * N[(N[(C / A), $MachinePrecision] * B + B), $MachinePrecision]), $MachinePrecision] / A), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision] * 180.0), $MachinePrecision], If[LessEqual[A, 4.8e+91], N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(C - N[Sqrt[(-C) ^ 2 + B ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[((-A) - N[Sqrt[A ^ 2 + B ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;A \leq -4.8 \cdot 10^{+47}:\\
    \;\;\;\;\frac{\tan^{-1} \left(\frac{0.5 \cdot \mathsf{fma}\left(\frac{C}{A}, B, B\right)}{A}\right)}{\pi} \cdot 180\\
    
    \mathbf{elif}\;A \leq 4.8 \cdot 10^{+91}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(C - \mathsf{hypot}\left(-C, B\right)\right)\right)}{\pi}\\
    
    \mathbf{else}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(-A\right) - \mathsf{hypot}\left(A, B\right)\right)\right)}{\pi}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 3 regimes
    2. if A < -4.80000000000000037e47

      1. Initial program 21.5%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Taylor expanded in A around -inf

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{\frac{-1}{2} \cdot B + \frac{-1}{2} \cdot \frac{B \cdot C}{A}}{A}\right)}}{\pi} \]
      3. Step-by-step derivation
        1. mul-1-negN/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\mathsf{neg}\left(\frac{\frac{-1}{2} \cdot B + \frac{-1}{2} \cdot \frac{B \cdot C}{A}}{A}\right)\right)}{\pi} \]
        2. lower-neg.f64N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{\frac{-1}{2} \cdot B + \frac{-1}{2} \cdot \frac{B \cdot C}{A}}{A}\right)}{\pi} \]
        3. lower-/.f64N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{\frac{-1}{2} \cdot B + \frac{-1}{2} \cdot \frac{B \cdot C}{A}}{A}\right)}{\pi} \]
        4. distribute-lft-outN/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{\frac{-1}{2} \cdot \left(B + \frac{B \cdot C}{A}\right)}{A}\right)}{\pi} \]
        5. lower-*.f64N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{\frac{-1}{2} \cdot \left(B + \frac{B \cdot C}{A}\right)}{A}\right)}{\pi} \]
        6. lower-+.f64N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{\frac{-1}{2} \cdot \left(B + \frac{B \cdot C}{A}\right)}{A}\right)}{\pi} \]
        7. associate-/l*N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{\frac{-1}{2} \cdot \left(B + B \cdot \frac{C}{A}\right)}{A}\right)}{\pi} \]
        8. lower-*.f64N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{\frac{-1}{2} \cdot \left(B + B \cdot \frac{C}{A}\right)}{A}\right)}{\pi} \]
        9. lower-/.f6467.4

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{-0.5 \cdot \left(B + B \cdot \frac{C}{A}\right)}{A}\right)}{\pi} \]
      4. Applied rewrites67.4%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-\frac{-0.5 \cdot \left(B + B \cdot \frac{C}{A}\right)}{A}\right)}}{\pi} \]
      5. Applied rewrites67.4%

        \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{0.5 \cdot \mathsf{fma}\left(\frac{C}{A}, B, B\right)}{A}\right)}{\pi} \cdot 180} \]

      if -4.80000000000000037e47 < A < 4.79999999999999966e91

      1. Initial program 56.6%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Step-by-step derivation
        1. lift-sqrt.f64N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\pi} \]
        2. lift-+.f64N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\pi} \]
        3. lift--.f64N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\color{blue}{\left(A - C\right)}}^{2} + {B}^{2}}\right)\right)}{\pi} \]
        4. lift-pow.f64N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2}} + {B}^{2}}\right)\right)}{\pi} \]
        5. unpow2N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{\left(A - C\right) \cdot \left(A - C\right)} + {B}^{2}}\right)\right)}{\pi} \]
        6. lift-pow.f64N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\left(A - C\right) \cdot \left(A - C\right) + \color{blue}{{B}^{2}}}\right)\right)}{\pi} \]
        7. unpow2N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\left(A - C\right) \cdot \left(A - C\right) + \color{blue}{B \cdot B}}\right)\right)}{\pi} \]
        8. lower-hypot.f64N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\mathsf{hypot}\left(A - C, B\right)}\right)\right)}{\pi} \]
        9. lift--.f6480.0

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \mathsf{hypot}\left(\color{blue}{A - C}, B\right)\right)\right)}{\pi} \]
      3. Applied rewrites80.0%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\mathsf{hypot}\left(A - C, B\right)}\right)\right)}{\pi} \]
      4. Taylor expanded in A around 0

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\color{blue}{C} - \mathsf{hypot}\left(A - C, B\right)\right)\right)}{\pi} \]
      5. Step-by-step derivation
        1. Applied rewrites79.5%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\color{blue}{C} - \mathsf{hypot}\left(A - C, B\right)\right)\right)}{\pi} \]
        2. Taylor expanded in A around 0

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(C - \mathsf{hypot}\left(\color{blue}{-1 \cdot C}, B\right)\right)\right)}{\pi} \]
        3. Step-by-step derivation
          1. mul-1-negN/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(C - \mathsf{hypot}\left(\mathsf{neg}\left(C\right), B\right)\right)\right)}{\pi} \]
          2. lower-neg.f6475.1

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(C - \mathsf{hypot}\left(-C, B\right)\right)\right)}{\pi} \]
        4. Applied rewrites75.1%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(C - \mathsf{hypot}\left(\color{blue}{-C}, B\right)\right)\right)}{\pi} \]

        if 4.79999999999999966e91 < A

        1. Initial program 80.9%

          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
        2. Step-by-step derivation
          1. lift-sqrt.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\pi} \]
          2. lift-+.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\pi} \]
          3. lift--.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\color{blue}{\left(A - C\right)}}^{2} + {B}^{2}}\right)\right)}{\pi} \]
          4. lift-pow.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2}} + {B}^{2}}\right)\right)}{\pi} \]
          5. unpow2N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{\left(A - C\right) \cdot \left(A - C\right)} + {B}^{2}}\right)\right)}{\pi} \]
          6. lift-pow.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\left(A - C\right) \cdot \left(A - C\right) + \color{blue}{{B}^{2}}}\right)\right)}{\pi} \]
          7. unpow2N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\left(A - C\right) \cdot \left(A - C\right) + \color{blue}{B \cdot B}}\right)\right)}{\pi} \]
          8. lower-hypot.f64N/A

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\mathsf{hypot}\left(A - C, B\right)}\right)\right)}{\pi} \]
          9. lift--.f6495.5

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \mathsf{hypot}\left(\color{blue}{A - C}, B\right)\right)\right)}{\pi} \]
        3. Applied rewrites95.5%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\mathsf{hypot}\left(A - C, B\right)}\right)\right)}{\pi} \]
        4. Taylor expanded in A around inf

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \mathsf{hypot}\left(\color{blue}{A}, B\right)\right)\right)}{\pi} \]
        5. Step-by-step derivation
          1. Applied rewrites92.2%

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \mathsf{hypot}\left(\color{blue}{A}, B\right)\right)\right)}{\pi} \]
          2. Taylor expanded in A around inf

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\color{blue}{-1 \cdot A} - \mathsf{hypot}\left(A, B\right)\right)\right)}{\pi} \]
          3. Step-by-step derivation
            1. mul-1-negN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(\mathsf{neg}\left(A\right)\right) - \mathsf{hypot}\left(A, B\right)\right)\right)}{\pi} \]
            2. lower-neg.f6491.5

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(-A\right) - \mathsf{hypot}\left(A, B\right)\right)\right)}{\pi} \]
          4. Applied rewrites91.5%

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\color{blue}{\left(-A\right)} - \mathsf{hypot}\left(A, B\right)\right)\right)}{\pi} \]
        6. Recombined 3 regimes into one program.
        7. Add Preprocessing

        Alternative 4: 75.1% accurate, 1.4× speedup?

        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;A \leq -4.8 \cdot 10^{+47}:\\ \;\;\;\;\frac{\tan^{-1} \left(\frac{0.5 \cdot \mathsf{fma}\left(\frac{C}{A}, B, B\right)}{A}\right)}{\pi} \cdot 180\\ \mathbf{elif}\;A \leq 3.5 \cdot 10^{+58}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(C - \mathsf{hypot}\left(-C, B\right)\right)\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\left(\left(C - A\right) - B\right) \cdot \frac{1}{B}\right)}{\pi}\\ \end{array} \end{array} \]
        (FPCore (A B C)
         :precision binary64
         (if (<= A -4.8e+47)
           (* (/ (atan (/ (* 0.5 (fma (/ C A) B B)) A)) PI) 180.0)
           (if (<= A 3.5e+58)
             (* 180.0 (/ (atan (* (/ 1.0 B) (- C (hypot (- C) B)))) PI))
             (/ (* 180.0 (atan (* (- (- C A) B) (/ 1.0 B)))) PI))))
        double code(double A, double B, double C) {
        	double tmp;
        	if (A <= -4.8e+47) {
        		tmp = (atan(((0.5 * fma((C / A), B, B)) / A)) / ((double) M_PI)) * 180.0;
        	} else if (A <= 3.5e+58) {
        		tmp = 180.0 * (atan(((1.0 / B) * (C - hypot(-C, B)))) / ((double) M_PI));
        	} else {
        		tmp = (180.0 * atan((((C - A) - B) * (1.0 / B)))) / ((double) M_PI);
        	}
        	return tmp;
        }
        
        function code(A, B, C)
        	tmp = 0.0
        	if (A <= -4.8e+47)
        		tmp = Float64(Float64(atan(Float64(Float64(0.5 * fma(Float64(C / A), B, B)) / A)) / pi) * 180.0);
        	elseif (A <= 3.5e+58)
        		tmp = Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(C - hypot(Float64(-C), B)))) / pi));
        	else
        		tmp = Float64(Float64(180.0 * atan(Float64(Float64(Float64(C - A) - B) * Float64(1.0 / B)))) / pi);
        	end
        	return tmp
        end
        
        code[A_, B_, C_] := If[LessEqual[A, -4.8e+47], N[(N[(N[ArcTan[N[(N[(0.5 * N[(N[(C / A), $MachinePrecision] * B + B), $MachinePrecision]), $MachinePrecision] / A), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision] * 180.0), $MachinePrecision], If[LessEqual[A, 3.5e+58], N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(C - N[Sqrt[(-C) ^ 2 + B ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(N[(180.0 * N[ArcTan[N[(N[(N[(C - A), $MachinePrecision] - B), $MachinePrecision] * N[(1.0 / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision]]]
        
        \begin{array}{l}
        
        \\
        \begin{array}{l}
        \mathbf{if}\;A \leq -4.8 \cdot 10^{+47}:\\
        \;\;\;\;\frac{\tan^{-1} \left(\frac{0.5 \cdot \mathsf{fma}\left(\frac{C}{A}, B, B\right)}{A}\right)}{\pi} \cdot 180\\
        
        \mathbf{elif}\;A \leq 3.5 \cdot 10^{+58}:\\
        \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(C - \mathsf{hypot}\left(-C, B\right)\right)\right)}{\pi}\\
        
        \mathbf{else}:\\
        \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\left(\left(C - A\right) - B\right) \cdot \frac{1}{B}\right)}{\pi}\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 3 regimes
        2. if A < -4.80000000000000037e47

          1. Initial program 21.5%

            \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
          2. Taylor expanded in A around -inf

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{\frac{-1}{2} \cdot B + \frac{-1}{2} \cdot \frac{B \cdot C}{A}}{A}\right)}}{\pi} \]
          3. Step-by-step derivation
            1. mul-1-negN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\mathsf{neg}\left(\frac{\frac{-1}{2} \cdot B + \frac{-1}{2} \cdot \frac{B \cdot C}{A}}{A}\right)\right)}{\pi} \]
            2. lower-neg.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{\frac{-1}{2} \cdot B + \frac{-1}{2} \cdot \frac{B \cdot C}{A}}{A}\right)}{\pi} \]
            3. lower-/.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{\frac{-1}{2} \cdot B + \frac{-1}{2} \cdot \frac{B \cdot C}{A}}{A}\right)}{\pi} \]
            4. distribute-lft-outN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{\frac{-1}{2} \cdot \left(B + \frac{B \cdot C}{A}\right)}{A}\right)}{\pi} \]
            5. lower-*.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{\frac{-1}{2} \cdot \left(B + \frac{B \cdot C}{A}\right)}{A}\right)}{\pi} \]
            6. lower-+.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{\frac{-1}{2} \cdot \left(B + \frac{B \cdot C}{A}\right)}{A}\right)}{\pi} \]
            7. associate-/l*N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{\frac{-1}{2} \cdot \left(B + B \cdot \frac{C}{A}\right)}{A}\right)}{\pi} \]
            8. lower-*.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{\frac{-1}{2} \cdot \left(B + B \cdot \frac{C}{A}\right)}{A}\right)}{\pi} \]
            9. lower-/.f6467.4

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(-\frac{-0.5 \cdot \left(B + B \cdot \frac{C}{A}\right)}{A}\right)}{\pi} \]
          4. Applied rewrites67.4%

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-\frac{-0.5 \cdot \left(B + B \cdot \frac{C}{A}\right)}{A}\right)}}{\pi} \]
          5. Applied rewrites67.4%

            \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{0.5 \cdot \mathsf{fma}\left(\frac{C}{A}, B, B\right)}{A}\right)}{\pi} \cdot 180} \]

          if -4.80000000000000037e47 < A < 3.4999999999999997e58

          1. Initial program 56.0%

            \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
          2. Step-by-step derivation
            1. lift-sqrt.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\pi} \]
            2. lift-+.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2} + {B}^{2}}}\right)\right)}{\pi} \]
            3. lift--.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\color{blue}{\left(A - C\right)}}^{2} + {B}^{2}}\right)\right)}{\pi} \]
            4. lift-pow.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{{\left(A - C\right)}^{2}} + {B}^{2}}\right)\right)}{\pi} \]
            5. unpow2N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\color{blue}{\left(A - C\right) \cdot \left(A - C\right)} + {B}^{2}}\right)\right)}{\pi} \]
            6. lift-pow.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\left(A - C\right) \cdot \left(A - C\right) + \color{blue}{{B}^{2}}}\right)\right)}{\pi} \]
            7. unpow2N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{\left(A - C\right) \cdot \left(A - C\right) + \color{blue}{B \cdot B}}\right)\right)}{\pi} \]
            8. lower-hypot.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\mathsf{hypot}\left(A - C, B\right)}\right)\right)}{\pi} \]
            9. lift--.f6479.6

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \mathsf{hypot}\left(\color{blue}{A - C}, B\right)\right)\right)}{\pi} \]
          3. Applied rewrites79.6%

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{\mathsf{hypot}\left(A - C, B\right)}\right)\right)}{\pi} \]
          4. Taylor expanded in A around 0

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\color{blue}{C} - \mathsf{hypot}\left(A - C, B\right)\right)\right)}{\pi} \]
          5. Step-by-step derivation
            1. Applied rewrites79.0%

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\color{blue}{C} - \mathsf{hypot}\left(A - C, B\right)\right)\right)}{\pi} \]
            2. Taylor expanded in A around 0

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(C - \mathsf{hypot}\left(\color{blue}{-1 \cdot C}, B\right)\right)\right)}{\pi} \]
            3. Step-by-step derivation
              1. mul-1-negN/A

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(C - \mathsf{hypot}\left(\mathsf{neg}\left(C\right), B\right)\right)\right)}{\pi} \]
              2. lower-neg.f6475.5

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(C - \mathsf{hypot}\left(-C, B\right)\right)\right)}{\pi} \]
            4. Applied rewrites75.5%

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(C - \mathsf{hypot}\left(\color{blue}{-C}, B\right)\right)\right)}{\pi} \]

            if 3.4999999999999997e58 < A

            1. Initial program 79.5%

              \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
            2. Taylor expanded in B around inf

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{B}\right)\right)}{\pi} \]
            3. Step-by-step derivation
              1. Applied rewrites82.3%

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{B}\right)\right)}{\pi} \]
              2. Step-by-step derivation
                1. lift-*.f64N/A

                  \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - B\right)\right)}{\pi}} \]
                2. lift-/.f64N/A

                  \[\leadsto 180 \cdot \color{blue}{\frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - B\right)\right)}{\pi}} \]
                3. associate-*r/N/A

                  \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - B\right)\right)}{\pi}} \]
                4. lower-/.f64N/A

                  \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - B\right)\right)}{\pi}} \]
              3. Applied rewrites82.3%

                \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\left(\left(C - A\right) - B\right) \cdot \frac{1}{B}\right)}{\pi}} \]
            4. Recombined 3 regimes into one program.
            5. Add Preprocessing

            Alternative 5: 72.3% accurate, 0.4× speedup?

            \[\begin{array}{l} \\ \begin{array}{l} t_0 := 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}\\ \mathbf{if}\;t\_0 \leq -40:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\left(\left(C - A\right) - B\right) \cdot \frac{1}{B}\right)}{\pi}\\ \mathbf{elif}\;t\_0 \leq 0.0005:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\ \end{array} \end{array} \]
            (FPCore (A B C)
             :precision binary64
             (let* ((t_0
                     (*
                      180.0
                      (/
                       (atan
                        (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
                       PI))))
               (if (<= t_0 -40.0)
                 (/ (* 180.0 (atan (* (- (- C A) B) (/ 1.0 B)))) PI)
                 (if (<= t_0 0.0005)
                   (/ (* 180.0 (atan (* (/ B A) 0.5))) PI)
                   (* 180.0 (/ (atan (+ 1.0 (/ (- C A) B))) PI))))))
            double code(double A, double B, double C) {
            	double t_0 = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / ((double) M_PI));
            	double tmp;
            	if (t_0 <= -40.0) {
            		tmp = (180.0 * atan((((C - A) - B) * (1.0 / B)))) / ((double) M_PI);
            	} else if (t_0 <= 0.0005) {
            		tmp = (180.0 * atan(((B / A) * 0.5))) / ((double) M_PI);
            	} else {
            		tmp = 180.0 * (atan((1.0 + ((C - A) / B))) / ((double) M_PI));
            	}
            	return tmp;
            }
            
            public static double code(double A, double B, double C) {
            	double t_0 = 180.0 * (Math.atan(((1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / Math.PI);
            	double tmp;
            	if (t_0 <= -40.0) {
            		tmp = (180.0 * Math.atan((((C - A) - B) * (1.0 / B)))) / Math.PI;
            	} else if (t_0 <= 0.0005) {
            		tmp = (180.0 * Math.atan(((B / A) * 0.5))) / Math.PI;
            	} else {
            		tmp = 180.0 * (Math.atan((1.0 + ((C - A) / B))) / Math.PI);
            	}
            	return tmp;
            }
            
            def code(A, B, C):
            	t_0 = 180.0 * (math.atan(((1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / math.pi)
            	tmp = 0
            	if t_0 <= -40.0:
            		tmp = (180.0 * math.atan((((C - A) - B) * (1.0 / B)))) / math.pi
            	elif t_0 <= 0.0005:
            		tmp = (180.0 * math.atan(((B / A) * 0.5))) / math.pi
            	else:
            		tmp = 180.0 * (math.atan((1.0 + ((C - A) / B))) / math.pi)
            	return tmp
            
            function code(A, B, C)
            	t_0 = Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))) / pi))
            	tmp = 0.0
            	if (t_0 <= -40.0)
            		tmp = Float64(Float64(180.0 * atan(Float64(Float64(Float64(C - A) - B) * Float64(1.0 / B)))) / pi);
            	elseif (t_0 <= 0.0005)
            		tmp = Float64(Float64(180.0 * atan(Float64(Float64(B / A) * 0.5))) / pi);
            	else
            		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + Float64(Float64(C - A) / B))) / pi));
            	end
            	return tmp
            end
            
            function tmp_2 = code(A, B, C)
            	t_0 = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / pi);
            	tmp = 0.0;
            	if (t_0 <= -40.0)
            		tmp = (180.0 * atan((((C - A) - B) * (1.0 / B)))) / pi;
            	elseif (t_0 <= 0.0005)
            		tmp = (180.0 * atan(((B / A) * 0.5))) / pi;
            	else
            		tmp = 180.0 * (atan((1.0 + ((C - A) / B))) / pi);
            	end
            	tmp_2 = tmp;
            end
            
            code[A_, B_, C_] := Block[{t$95$0 = N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, -40.0], N[(N[(180.0 * N[ArcTan[N[(N[(N[(C - A), $MachinePrecision] - B), $MachinePrecision] * N[(1.0 / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision], If[LessEqual[t$95$0, 0.0005], N[(N[(180.0 * N[ArcTan[N[(N[(B / A), $MachinePrecision] * 0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(1.0 + N[(N[(C - A), $MachinePrecision] / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]
            
            \begin{array}{l}
            
            \\
            \begin{array}{l}
            t_0 := 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}\\
            \mathbf{if}\;t\_0 \leq -40:\\
            \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\left(\left(C - A\right) - B\right) \cdot \frac{1}{B}\right)}{\pi}\\
            
            \mathbf{elif}\;t\_0 \leq 0.0005:\\
            \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi}\\
            
            \mathbf{else}:\\
            \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\
            
            
            \end{array}
            \end{array}
            
            Derivation
            1. Split input into 3 regimes
            2. if (*.f64 #s(literal 180 binary64) (/.f64 (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))) (PI.f64))) < -40

              1. Initial program 58.9%

                \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
              2. Taylor expanded in B around inf

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{B}\right)\right)}{\pi} \]
              3. Step-by-step derivation
                1. Applied rewrites76.2%

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{B}\right)\right)}{\pi} \]
                2. Step-by-step derivation
                  1. lift-*.f64N/A

                    \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - B\right)\right)}{\pi}} \]
                  2. lift-/.f64N/A

                    \[\leadsto 180 \cdot \color{blue}{\frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - B\right)\right)}{\pi}} \]
                  3. associate-*r/N/A

                    \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - B\right)\right)}{\pi}} \]
                  4. lower-/.f64N/A

                    \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - B\right)\right)}{\pi}} \]
                3. Applied rewrites76.2%

                  \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\left(\left(C - A\right) - B\right) \cdot \frac{1}{B}\right)}{\pi}} \]

                if -40 < (*.f64 #s(literal 180 binary64) (/.f64 (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))) (PI.f64))) < 5.0000000000000001e-4

                1. Initial program 16.9%

                  \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                2. Taylor expanded in A around -inf

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1}{2} \cdot \frac{B}{A}\right)}}{\pi} \]
                3. Step-by-step derivation
                  1. *-commutativeN/A

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \color{blue}{\frac{1}{2}}\right)}{\pi} \]
                  2. lower-*.f64N/A

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \color{blue}{\frac{1}{2}}\right)}{\pi} \]
                  3. lower-/.f6447.7

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \]
                4. Applied rewrites47.7%

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{B}{A} \cdot 0.5\right)}}{\pi} \]
                5. Step-by-step derivation
                  1. lift-*.f64N/A

                    \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                  2. lift-/.f64N/A

                    \[\leadsto 180 \cdot \color{blue}{\frac{\tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                  3. associate-*r/N/A

                    \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                  4. lower-/.f64N/A

                    \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                6. Applied rewrites47.7%

                  \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi}} \]

                if 5.0000000000000001e-4 < (*.f64 #s(literal 180 binary64) (/.f64 (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))) (PI.f64)))

                1. Initial program 59.2%

                  \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                2. Taylor expanded in B around -inf

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
                3. Step-by-step derivation
                  1. associate--l+N/A

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
                  2. div-subN/A

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                  3. lower-+.f64N/A

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
                  4. lower-/.f64N/A

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                  5. lift--.f6476.1

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
                4. Applied rewrites76.1%

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
              4. Recombined 3 regimes into one program.
              5. Add Preprocessing

              Alternative 6: 66.8% accurate, 0.5× speedup?

              \[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\ \mathbf{if}\;t\_0 \leq -0.02:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(-A\right) - B\right)\right)}{\pi}\\ \mathbf{elif}\;t\_0 \leq 10^{-5}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\ \end{array} \end{array} \]
              (FPCore (A B C)
               :precision binary64
               (let* ((t_0
                       (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
                 (if (<= t_0 -0.02)
                   (* 180.0 (/ (atan (* (/ 1.0 B) (- (- A) B))) PI))
                   (if (<= t_0 1e-5)
                     (/ (* 180.0 (atan (* (/ B A) 0.5))) PI)
                     (* 180.0 (/ (atan (+ 1.0 (/ (- C A) B))) PI))))))
              double code(double A, double B, double C) {
              	double t_0 = (1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0))));
              	double tmp;
              	if (t_0 <= -0.02) {
              		tmp = 180.0 * (atan(((1.0 / B) * (-A - B))) / ((double) M_PI));
              	} else if (t_0 <= 1e-5) {
              		tmp = (180.0 * atan(((B / A) * 0.5))) / ((double) M_PI);
              	} else {
              		tmp = 180.0 * (atan((1.0 + ((C - A) / B))) / ((double) M_PI));
              	}
              	return tmp;
              }
              
              public static double code(double A, double B, double C) {
              	double t_0 = (1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0))));
              	double tmp;
              	if (t_0 <= -0.02) {
              		tmp = 180.0 * (Math.atan(((1.0 / B) * (-A - B))) / Math.PI);
              	} else if (t_0 <= 1e-5) {
              		tmp = (180.0 * Math.atan(((B / A) * 0.5))) / Math.PI;
              	} else {
              		tmp = 180.0 * (Math.atan((1.0 + ((C - A) / B))) / Math.PI);
              	}
              	return tmp;
              }
              
              def code(A, B, C):
              	t_0 = (1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0))))
              	tmp = 0
              	if t_0 <= -0.02:
              		tmp = 180.0 * (math.atan(((1.0 / B) * (-A - B))) / math.pi)
              	elif t_0 <= 1e-5:
              		tmp = (180.0 * math.atan(((B / A) * 0.5))) / math.pi
              	else:
              		tmp = 180.0 * (math.atan((1.0 + ((C - A) / B))) / math.pi)
              	return tmp
              
              function code(A, B, C)
              	t_0 = Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))
              	tmp = 0.0
              	if (t_0 <= -0.02)
              		tmp = Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(Float64(-A) - B))) / pi));
              	elseif (t_0 <= 1e-5)
              		tmp = Float64(Float64(180.0 * atan(Float64(Float64(B / A) * 0.5))) / pi);
              	else
              		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + Float64(Float64(C - A) / B))) / pi));
              	end
              	return tmp
              end
              
              function tmp_2 = code(A, B, C)
              	t_0 = (1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0))));
              	tmp = 0.0;
              	if (t_0 <= -0.02)
              		tmp = 180.0 * (atan(((1.0 / B) * (-A - B))) / pi);
              	elseif (t_0 <= 1e-5)
              		tmp = (180.0 * atan(((B / A) * 0.5))) / pi;
              	else
              		tmp = 180.0 * (atan((1.0 + ((C - A) / B))) / pi);
              	end
              	tmp_2 = tmp;
              end
              
              code[A_, B_, C_] := Block[{t$95$0 = N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, -0.02], N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[((-A) - B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$0, 1e-5], N[(N[(180.0 * N[ArcTan[N[(N[(B / A), $MachinePrecision] * 0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(1.0 + N[(N[(C - A), $MachinePrecision] / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]
              
              \begin{array}{l}
              
              \\
              \begin{array}{l}
              t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\
              \mathbf{if}\;t\_0 \leq -0.02:\\
              \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(-A\right) - B\right)\right)}{\pi}\\
              
              \mathbf{elif}\;t\_0 \leq 10^{-5}:\\
              \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi}\\
              
              \mathbf{else}:\\
              \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\
              
              
              \end{array}
              \end{array}
              
              Derivation
              1. Split input into 3 regimes
              2. if (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -0.0200000000000000004

                1. Initial program 58.8%

                  \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                2. Taylor expanded in B around inf

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{B}\right)\right)}{\pi} \]
                3. Step-by-step derivation
                  1. Applied rewrites76.1%

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{B}\right)\right)}{\pi} \]
                  2. Taylor expanded in A around inf

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\color{blue}{-1 \cdot A} - B\right)\right)}{\pi} \]
                  3. Step-by-step derivation
                    1. mul-1-negN/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(\mathsf{neg}\left(A\right)\right) - B\right)\right)}{\pi} \]
                    2. lower-neg.f6463.2

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(-A\right) - B\right)\right)}{\pi} \]
                  4. Applied rewrites63.2%

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\color{blue}{\left(-A\right)} - B\right)\right)}{\pi} \]

                  if -0.0200000000000000004 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < 1.00000000000000008e-5

                  1. Initial program 16.7%

                    \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                  2. Taylor expanded in A around -inf

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1}{2} \cdot \frac{B}{A}\right)}}{\pi} \]
                  3. Step-by-step derivation
                    1. *-commutativeN/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \color{blue}{\frac{1}{2}}\right)}{\pi} \]
                    2. lower-*.f64N/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \color{blue}{\frac{1}{2}}\right)}{\pi} \]
                    3. lower-/.f6447.9

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \]
                  4. Applied rewrites47.9%

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{B}{A} \cdot 0.5\right)}}{\pi} \]
                  5. Step-by-step derivation
                    1. lift-*.f64N/A

                      \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                    2. lift-/.f64N/A

                      \[\leadsto 180 \cdot \color{blue}{\frac{\tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                    3. associate-*r/N/A

                      \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                    4. lower-/.f64N/A

                      \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                  6. Applied rewrites47.9%

                    \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi}} \]

                  if 1.00000000000000008e-5 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))

                  1. Initial program 59.2%

                    \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                  2. Taylor expanded in B around -inf

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
                  3. Step-by-step derivation
                    1. associate--l+N/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
                    2. div-subN/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                    3. lower-+.f64N/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
                    4. lower-/.f64N/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                    5. lift--.f6476.1

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
                  4. Applied rewrites76.1%

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
                4. Recombined 3 regimes into one program.
                5. Add Preprocessing

                Alternative 7: 66.7% accurate, 0.5× speedup?

                \[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\ \mathbf{if}\;t\_0 \leq -0.5:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(C - B\right)\right)}{\pi}\\ \mathbf{elif}\;t\_0 \leq 10^{-5}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\ \end{array} \end{array} \]
                (FPCore (A B C)
                 :precision binary64
                 (let* ((t_0
                         (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
                   (if (<= t_0 -0.5)
                     (* 180.0 (/ (atan (* (/ 1.0 B) (- C B))) PI))
                     (if (<= t_0 1e-5)
                       (/ (* 180.0 (atan (* (/ B A) 0.5))) PI)
                       (* 180.0 (/ (atan (+ 1.0 (/ (- C A) B))) PI))))))
                double code(double A, double B, double C) {
                	double t_0 = (1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0))));
                	double tmp;
                	if (t_0 <= -0.5) {
                		tmp = 180.0 * (atan(((1.0 / B) * (C - B))) / ((double) M_PI));
                	} else if (t_0 <= 1e-5) {
                		tmp = (180.0 * atan(((B / A) * 0.5))) / ((double) M_PI);
                	} else {
                		tmp = 180.0 * (atan((1.0 + ((C - A) / B))) / ((double) M_PI));
                	}
                	return tmp;
                }
                
                public static double code(double A, double B, double C) {
                	double t_0 = (1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0))));
                	double tmp;
                	if (t_0 <= -0.5) {
                		tmp = 180.0 * (Math.atan(((1.0 / B) * (C - B))) / Math.PI);
                	} else if (t_0 <= 1e-5) {
                		tmp = (180.0 * Math.atan(((B / A) * 0.5))) / Math.PI;
                	} else {
                		tmp = 180.0 * (Math.atan((1.0 + ((C - A) / B))) / Math.PI);
                	}
                	return tmp;
                }
                
                def code(A, B, C):
                	t_0 = (1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0))))
                	tmp = 0
                	if t_0 <= -0.5:
                		tmp = 180.0 * (math.atan(((1.0 / B) * (C - B))) / math.pi)
                	elif t_0 <= 1e-5:
                		tmp = (180.0 * math.atan(((B / A) * 0.5))) / math.pi
                	else:
                		tmp = 180.0 * (math.atan((1.0 + ((C - A) / B))) / math.pi)
                	return tmp
                
                function code(A, B, C)
                	t_0 = Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))
                	tmp = 0.0
                	if (t_0 <= -0.5)
                		tmp = Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(C - B))) / pi));
                	elseif (t_0 <= 1e-5)
                		tmp = Float64(Float64(180.0 * atan(Float64(Float64(B / A) * 0.5))) / pi);
                	else
                		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + Float64(Float64(C - A) / B))) / pi));
                	end
                	return tmp
                end
                
                function tmp_2 = code(A, B, C)
                	t_0 = (1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0))));
                	tmp = 0.0;
                	if (t_0 <= -0.5)
                		tmp = 180.0 * (atan(((1.0 / B) * (C - B))) / pi);
                	elseif (t_0 <= 1e-5)
                		tmp = (180.0 * atan(((B / A) * 0.5))) / pi;
                	else
                		tmp = 180.0 * (atan((1.0 + ((C - A) / B))) / pi);
                	end
                	tmp_2 = tmp;
                end
                
                code[A_, B_, C_] := Block[{t$95$0 = N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, -0.5], N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(C - B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$0, 1e-5], N[(N[(180.0 * N[ArcTan[N[(N[(B / A), $MachinePrecision] * 0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(1.0 + N[(N[(C - A), $MachinePrecision] / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]
                
                \begin{array}{l}
                
                \\
                \begin{array}{l}
                t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\
                \mathbf{if}\;t\_0 \leq -0.5:\\
                \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(C - B\right)\right)}{\pi}\\
                
                \mathbf{elif}\;t\_0 \leq 10^{-5}:\\
                \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi}\\
                
                \mathbf{else}:\\
                \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\
                
                
                \end{array}
                \end{array}
                
                Derivation
                1. Split input into 3 regimes
                2. if (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -0.5

                  1. Initial program 58.9%

                    \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                  2. Taylor expanded in B around inf

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{B}\right)\right)}{\pi} \]
                  3. Step-by-step derivation
                    1. Applied rewrites76.2%

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \color{blue}{B}\right)\right)}{\pi} \]
                    2. Taylor expanded in A around 0

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\color{blue}{C} - B\right)\right)}{\pi} \]
                    3. Step-by-step derivation
                      1. Applied rewrites63.5%

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\color{blue}{C} - B\right)\right)}{\pi} \]

                      if -0.5 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < 1.00000000000000008e-5

                      1. Initial program 16.8%

                        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                      2. Taylor expanded in A around -inf

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1}{2} \cdot \frac{B}{A}\right)}}{\pi} \]
                      3. Step-by-step derivation
                        1. *-commutativeN/A

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \color{blue}{\frac{1}{2}}\right)}{\pi} \]
                        2. lower-*.f64N/A

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \color{blue}{\frac{1}{2}}\right)}{\pi} \]
                        3. lower-/.f6447.7

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \]
                      4. Applied rewrites47.7%

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{B}{A} \cdot 0.5\right)}}{\pi} \]
                      5. Step-by-step derivation
                        1. lift-*.f64N/A

                          \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                        2. lift-/.f64N/A

                          \[\leadsto 180 \cdot \color{blue}{\frac{\tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                        3. associate-*r/N/A

                          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                        4. lower-/.f64N/A

                          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                      6. Applied rewrites47.7%

                        \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi}} \]

                      if 1.00000000000000008e-5 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))

                      1. Initial program 59.2%

                        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                      2. Taylor expanded in B around -inf

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
                      3. Step-by-step derivation
                        1. associate--l+N/A

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
                        2. div-subN/A

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                        3. lower-+.f64N/A

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
                        4. lower-/.f64N/A

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                        5. lift--.f6476.1

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
                      4. Applied rewrites76.1%

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
                    4. Recombined 3 regimes into one program.
                    5. Add Preprocessing

                    Alternative 8: 62.7% accurate, 0.4× speedup?

                    \[\begin{array}{l} \\ \begin{array}{l} t_0 := 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\ t_1 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\ \mathbf{if}\;t\_1 \leq -50:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;t\_1 \leq -0.02:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \mathbf{elif}\;t\_1 \leq 10^{-5}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;t\_0\\ \end{array} \end{array} \]
                    (FPCore (A B C)
                     :precision binary64
                     (let* ((t_0 (* 180.0 (/ (atan (+ 1.0 (/ (- C A) B))) PI)))
                            (t_1
                             (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
                       (if (<= t_1 -50.0)
                         t_0
                         (if (<= t_1 -0.02)
                           (* 180.0 (/ (atan -1.0) PI))
                           (if (<= t_1 1e-5) (/ (* 180.0 (atan (* (/ B A) 0.5))) PI) t_0)))))
                    double code(double A, double B, double C) {
                    	double t_0 = 180.0 * (atan((1.0 + ((C - A) / B))) / ((double) M_PI));
                    	double t_1 = (1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0))));
                    	double tmp;
                    	if (t_1 <= -50.0) {
                    		tmp = t_0;
                    	} else if (t_1 <= -0.02) {
                    		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
                    	} else if (t_1 <= 1e-5) {
                    		tmp = (180.0 * atan(((B / A) * 0.5))) / ((double) M_PI);
                    	} else {
                    		tmp = t_0;
                    	}
                    	return tmp;
                    }
                    
                    public static double code(double A, double B, double C) {
                    	double t_0 = 180.0 * (Math.atan((1.0 + ((C - A) / B))) / Math.PI);
                    	double t_1 = (1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0))));
                    	double tmp;
                    	if (t_1 <= -50.0) {
                    		tmp = t_0;
                    	} else if (t_1 <= -0.02) {
                    		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
                    	} else if (t_1 <= 1e-5) {
                    		tmp = (180.0 * Math.atan(((B / A) * 0.5))) / Math.PI;
                    	} else {
                    		tmp = t_0;
                    	}
                    	return tmp;
                    }
                    
                    def code(A, B, C):
                    	t_0 = 180.0 * (math.atan((1.0 + ((C - A) / B))) / math.pi)
                    	t_1 = (1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0))))
                    	tmp = 0
                    	if t_1 <= -50.0:
                    		tmp = t_0
                    	elif t_1 <= -0.02:
                    		tmp = 180.0 * (math.atan(-1.0) / math.pi)
                    	elif t_1 <= 1e-5:
                    		tmp = (180.0 * math.atan(((B / A) * 0.5))) / math.pi
                    	else:
                    		tmp = t_0
                    	return tmp
                    
                    function code(A, B, C)
                    	t_0 = Float64(180.0 * Float64(atan(Float64(1.0 + Float64(Float64(C - A) / B))) / pi))
                    	t_1 = Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))
                    	tmp = 0.0
                    	if (t_1 <= -50.0)
                    		tmp = t_0;
                    	elseif (t_1 <= -0.02)
                    		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
                    	elseif (t_1 <= 1e-5)
                    		tmp = Float64(Float64(180.0 * atan(Float64(Float64(B / A) * 0.5))) / pi);
                    	else
                    		tmp = t_0;
                    	end
                    	return tmp
                    end
                    
                    function tmp_2 = code(A, B, C)
                    	t_0 = 180.0 * (atan((1.0 + ((C - A) / B))) / pi);
                    	t_1 = (1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0))));
                    	tmp = 0.0;
                    	if (t_1 <= -50.0)
                    		tmp = t_0;
                    	elseif (t_1 <= -0.02)
                    		tmp = 180.0 * (atan(-1.0) / pi);
                    	elseif (t_1 <= 1e-5)
                    		tmp = (180.0 * atan(((B / A) * 0.5))) / pi;
                    	else
                    		tmp = t_0;
                    	end
                    	tmp_2 = tmp;
                    end
                    
                    code[A_, B_, C_] := Block[{t$95$0 = N[(180.0 * N[(N[ArcTan[N[(1.0 + N[(N[(C - A), $MachinePrecision] / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$1, -50.0], t$95$0, If[LessEqual[t$95$1, -0.02], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$1, 1e-5], N[(N[(180.0 * N[ArcTan[N[(N[(B / A), $MachinePrecision] * 0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision], t$95$0]]]]]
                    
                    \begin{array}{l}
                    
                    \\
                    \begin{array}{l}
                    t_0 := 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\
                    t_1 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\
                    \mathbf{if}\;t\_1 \leq -50:\\
                    \;\;\;\;t\_0\\
                    
                    \mathbf{elif}\;t\_1 \leq -0.02:\\
                    \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
                    
                    \mathbf{elif}\;t\_1 \leq 10^{-5}:\\
                    \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi}\\
                    
                    \mathbf{else}:\\
                    \;\;\;\;t\_0\\
                    
                    
                    \end{array}
                    \end{array}
                    
                    Derivation
                    1. Split input into 3 regimes
                    2. if (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -50 or 1.00000000000000008e-5 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))

                      1. Initial program 55.8%

                        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                      2. Taylor expanded in B around -inf

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
                      3. Step-by-step derivation
                        1. associate--l+N/A

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
                        2. div-subN/A

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                        3. lower-+.f64N/A

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
                        4. lower-/.f64N/A

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                        5. lift--.f6462.5

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
                      4. Applied rewrites62.5%

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]

                      if -50 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < -0.0200000000000000004

                      1. Initial program 99.1%

                        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                      2. Taylor expanded in B around inf

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                      3. Step-by-step derivation
                        1. Applied rewrites95.6%

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]

                        if -0.0200000000000000004 < (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))) < 1.00000000000000008e-5

                        1. Initial program 16.7%

                          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                        2. Taylor expanded in A around -inf

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1}{2} \cdot \frac{B}{A}\right)}}{\pi} \]
                        3. Step-by-step derivation
                          1. *-commutativeN/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \color{blue}{\frac{1}{2}}\right)}{\pi} \]
                          2. lower-*.f64N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \color{blue}{\frac{1}{2}}\right)}{\pi} \]
                          3. lower-/.f6447.9

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \]
                        4. Applied rewrites47.9%

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{B}{A} \cdot 0.5\right)}}{\pi} \]
                        5. Step-by-step derivation
                          1. lift-*.f64N/A

                            \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                          2. lift-/.f64N/A

                            \[\leadsto 180 \cdot \color{blue}{\frac{\tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                          3. associate-*r/N/A

                            \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                          4. lower-/.f64N/A

                            \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                        6. Applied rewrites47.9%

                          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi}} \]
                      4. Recombined 3 regimes into one program.
                      5. Add Preprocessing

                      Alternative 9: 46.0% accurate, 2.2× speedup?

                      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;A \leq -3.3 \cdot 10^{-274}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi}\\ \mathbf{elif}\;A \leq 1.05 \cdot 10^{+91}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{C + C}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;\frac{\tan^{-1} \left(\frac{A}{B} \cdot -2\right)}{\pi} \cdot 180\\ \end{array} \end{array} \]
                      (FPCore (A B C)
                       :precision binary64
                       (if (<= A -3.3e-274)
                         (/ (* 180.0 (atan (* (/ B A) 0.5))) PI)
                         (if (<= A 1.05e+91)
                           (/ (* 180.0 (atan (/ (+ C C) B))) PI)
                           (* (/ (atan (* (/ A B) -2.0)) PI) 180.0))))
                      double code(double A, double B, double C) {
                      	double tmp;
                      	if (A <= -3.3e-274) {
                      		tmp = (180.0 * atan(((B / A) * 0.5))) / ((double) M_PI);
                      	} else if (A <= 1.05e+91) {
                      		tmp = (180.0 * atan(((C + C) / B))) / ((double) M_PI);
                      	} else {
                      		tmp = (atan(((A / B) * -2.0)) / ((double) M_PI)) * 180.0;
                      	}
                      	return tmp;
                      }
                      
                      public static double code(double A, double B, double C) {
                      	double tmp;
                      	if (A <= -3.3e-274) {
                      		tmp = (180.0 * Math.atan(((B / A) * 0.5))) / Math.PI;
                      	} else if (A <= 1.05e+91) {
                      		tmp = (180.0 * Math.atan(((C + C) / B))) / Math.PI;
                      	} else {
                      		tmp = (Math.atan(((A / B) * -2.0)) / Math.PI) * 180.0;
                      	}
                      	return tmp;
                      }
                      
                      def code(A, B, C):
                      	tmp = 0
                      	if A <= -3.3e-274:
                      		tmp = (180.0 * math.atan(((B / A) * 0.5))) / math.pi
                      	elif A <= 1.05e+91:
                      		tmp = (180.0 * math.atan(((C + C) / B))) / math.pi
                      	else:
                      		tmp = (math.atan(((A / B) * -2.0)) / math.pi) * 180.0
                      	return tmp
                      
                      function code(A, B, C)
                      	tmp = 0.0
                      	if (A <= -3.3e-274)
                      		tmp = Float64(Float64(180.0 * atan(Float64(Float64(B / A) * 0.5))) / pi);
                      	elseif (A <= 1.05e+91)
                      		tmp = Float64(Float64(180.0 * atan(Float64(Float64(C + C) / B))) / pi);
                      	else
                      		tmp = Float64(Float64(atan(Float64(Float64(A / B) * -2.0)) / pi) * 180.0);
                      	end
                      	return tmp
                      end
                      
                      function tmp_2 = code(A, B, C)
                      	tmp = 0.0;
                      	if (A <= -3.3e-274)
                      		tmp = (180.0 * atan(((B / A) * 0.5))) / pi;
                      	elseif (A <= 1.05e+91)
                      		tmp = (180.0 * atan(((C + C) / B))) / pi;
                      	else
                      		tmp = (atan(((A / B) * -2.0)) / pi) * 180.0;
                      	end
                      	tmp_2 = tmp;
                      end
                      
                      code[A_, B_, C_] := If[LessEqual[A, -3.3e-274], N[(N[(180.0 * N[ArcTan[N[(N[(B / A), $MachinePrecision] * 0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision], If[LessEqual[A, 1.05e+91], N[(N[(180.0 * N[ArcTan[N[(N[(C + C), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision], N[(N[(N[ArcTan[N[(N[(A / B), $MachinePrecision] * -2.0), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision] * 180.0), $MachinePrecision]]]
                      
                      \begin{array}{l}
                      
                      \\
                      \begin{array}{l}
                      \mathbf{if}\;A \leq -3.3 \cdot 10^{-274}:\\
                      \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi}\\
                      
                      \mathbf{elif}\;A \leq 1.05 \cdot 10^{+91}:\\
                      \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{C + C}{B}\right)}{\pi}\\
                      
                      \mathbf{else}:\\
                      \;\;\;\;\frac{\tan^{-1} \left(\frac{A}{B} \cdot -2\right)}{\pi} \cdot 180\\
                      
                      
                      \end{array}
                      \end{array}
                      
                      Derivation
                      1. Split input into 3 regimes
                      2. if A < -3.2999999999999998e-274

                        1. Initial program 37.8%

                          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                        2. Taylor expanded in A around -inf

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1}{2} \cdot \frac{B}{A}\right)}}{\pi} \]
                        3. Step-by-step derivation
                          1. *-commutativeN/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \color{blue}{\frac{1}{2}}\right)}{\pi} \]
                          2. lower-*.f64N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \color{blue}{\frac{1}{2}}\right)}{\pi} \]
                          3. lower-/.f6448.4

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \]
                        4. Applied rewrites48.4%

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{B}{A} \cdot 0.5\right)}}{\pi} \]
                        5. Step-by-step derivation
                          1. lift-*.f64N/A

                            \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                          2. lift-/.f64N/A

                            \[\leadsto 180 \cdot \color{blue}{\frac{\tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                          3. associate-*r/N/A

                            \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                          4. lower-/.f64N/A

                            \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                        6. Applied rewrites48.4%

                          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi}} \]

                        if -3.2999999999999998e-274 < A < 1.05000000000000004e91

                        1. Initial program 60.7%

                          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                        2. Taylor expanded in C around -inf

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(2 \cdot \frac{C}{B}\right)}}{\pi} \]
                        3. Step-by-step derivation
                          1. associate-*r/N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{2 \cdot C}{\color{blue}{B}}\right)}{\pi} \]
                          2. lower-/.f64N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{2 \cdot C}{\color{blue}{B}}\right)}{\pi} \]
                          3. count-2-revN/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C + C}{B}\right)}{\pi} \]
                          4. lower-+.f6427.3

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C + C}{B}\right)}{\pi} \]
                        4. Applied rewrites27.3%

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C + C}{B}\right)}}{\pi} \]
                        5. Step-by-step derivation
                          1. lift-*.f64N/A

                            \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{C + C}{B}\right)}{\pi}} \]
                          2. lift-PI.f64N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C + C}{B}\right)}{\color{blue}{\mathsf{PI}\left(\right)}} \]
                          3. lift-/.f64N/A

                            \[\leadsto 180 \cdot \color{blue}{\frac{\tan^{-1} \left(\frac{C + C}{B}\right)}{\mathsf{PI}\left(\right)}} \]
                          4. associate-*r/N/A

                            \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{C + C}{B}\right)}{\mathsf{PI}\left(\right)}} \]
                          5. lower-/.f64N/A

                            \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{C + C}{B}\right)}{\mathsf{PI}\left(\right)}} \]
                        6. Applied rewrites27.3%

                          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{C + C}{B}\right)}{\pi}} \]

                        if 1.05000000000000004e91 < A

                        1. Initial program 80.9%

                          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                        2. Taylor expanded in A around inf

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-2 \cdot \frac{A}{B}\right)}}{\pi} \]
                        3. Step-by-step derivation
                          1. *-commutativeN/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A}{B} \cdot \color{blue}{-2}\right)}{\pi} \]
                          2. lower-*.f64N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A}{B} \cdot \color{blue}{-2}\right)}{\pi} \]
                          3. lower-/.f6477.3

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A}{B} \cdot -2\right)}{\pi} \]
                        4. Applied rewrites77.3%

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{A}{B} \cdot -2\right)}}{\pi} \]
                        5. Step-by-step derivation
                          1. lift-*.f64N/A

                            \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{A}{B} \cdot -2\right)}{\pi}} \]
                          2. *-commutativeN/A

                            \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{A}{B} \cdot -2\right)}{\pi} \cdot 180} \]
                          3. lower-*.f6477.3

                            \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{A}{B} \cdot -2\right)}{\pi} \cdot 180} \]
                        6. Applied rewrites77.3%

                          \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{A}{B} \cdot -2\right)}{\pi} \cdot 180} \]
                      3. Recombined 3 regimes into one program.
                      4. Add Preprocessing

                      Alternative 10: 46.0% accurate, 2.2× speedup?

                      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;A \leq -3.3 \cdot 10^{-274}:\\ \;\;\;\;\frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \cdot 180\\ \mathbf{elif}\;A \leq 1.05 \cdot 10^{+91}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{C + C}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;\frac{\tan^{-1} \left(\frac{A}{B} \cdot -2\right)}{\pi} \cdot 180\\ \end{array} \end{array} \]
                      (FPCore (A B C)
                       :precision binary64
                       (if (<= A -3.3e-274)
                         (* (/ (atan (* (/ B A) 0.5)) PI) 180.0)
                         (if (<= A 1.05e+91)
                           (/ (* 180.0 (atan (/ (+ C C) B))) PI)
                           (* (/ (atan (* (/ A B) -2.0)) PI) 180.0))))
                      double code(double A, double B, double C) {
                      	double tmp;
                      	if (A <= -3.3e-274) {
                      		tmp = (atan(((B / A) * 0.5)) / ((double) M_PI)) * 180.0;
                      	} else if (A <= 1.05e+91) {
                      		tmp = (180.0 * atan(((C + C) / B))) / ((double) M_PI);
                      	} else {
                      		tmp = (atan(((A / B) * -2.0)) / ((double) M_PI)) * 180.0;
                      	}
                      	return tmp;
                      }
                      
                      public static double code(double A, double B, double C) {
                      	double tmp;
                      	if (A <= -3.3e-274) {
                      		tmp = (Math.atan(((B / A) * 0.5)) / Math.PI) * 180.0;
                      	} else if (A <= 1.05e+91) {
                      		tmp = (180.0 * Math.atan(((C + C) / B))) / Math.PI;
                      	} else {
                      		tmp = (Math.atan(((A / B) * -2.0)) / Math.PI) * 180.0;
                      	}
                      	return tmp;
                      }
                      
                      def code(A, B, C):
                      	tmp = 0
                      	if A <= -3.3e-274:
                      		tmp = (math.atan(((B / A) * 0.5)) / math.pi) * 180.0
                      	elif A <= 1.05e+91:
                      		tmp = (180.0 * math.atan(((C + C) / B))) / math.pi
                      	else:
                      		tmp = (math.atan(((A / B) * -2.0)) / math.pi) * 180.0
                      	return tmp
                      
                      function code(A, B, C)
                      	tmp = 0.0
                      	if (A <= -3.3e-274)
                      		tmp = Float64(Float64(atan(Float64(Float64(B / A) * 0.5)) / pi) * 180.0);
                      	elseif (A <= 1.05e+91)
                      		tmp = Float64(Float64(180.0 * atan(Float64(Float64(C + C) / B))) / pi);
                      	else
                      		tmp = Float64(Float64(atan(Float64(Float64(A / B) * -2.0)) / pi) * 180.0);
                      	end
                      	return tmp
                      end
                      
                      function tmp_2 = code(A, B, C)
                      	tmp = 0.0;
                      	if (A <= -3.3e-274)
                      		tmp = (atan(((B / A) * 0.5)) / pi) * 180.0;
                      	elseif (A <= 1.05e+91)
                      		tmp = (180.0 * atan(((C + C) / B))) / pi;
                      	else
                      		tmp = (atan(((A / B) * -2.0)) / pi) * 180.0;
                      	end
                      	tmp_2 = tmp;
                      end
                      
                      code[A_, B_, C_] := If[LessEqual[A, -3.3e-274], N[(N[(N[ArcTan[N[(N[(B / A), $MachinePrecision] * 0.5), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision] * 180.0), $MachinePrecision], If[LessEqual[A, 1.05e+91], N[(N[(180.0 * N[ArcTan[N[(N[(C + C), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision], N[(N[(N[ArcTan[N[(N[(A / B), $MachinePrecision] * -2.0), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision] * 180.0), $MachinePrecision]]]
                      
                      \begin{array}{l}
                      
                      \\
                      \begin{array}{l}
                      \mathbf{if}\;A \leq -3.3 \cdot 10^{-274}:\\
                      \;\;\;\;\frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \cdot 180\\
                      
                      \mathbf{elif}\;A \leq 1.05 \cdot 10^{+91}:\\
                      \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{C + C}{B}\right)}{\pi}\\
                      
                      \mathbf{else}:\\
                      \;\;\;\;\frac{\tan^{-1} \left(\frac{A}{B} \cdot -2\right)}{\pi} \cdot 180\\
                      
                      
                      \end{array}
                      \end{array}
                      
                      Derivation
                      1. Split input into 3 regimes
                      2. if A < -3.2999999999999998e-274

                        1. Initial program 37.8%

                          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                        2. Taylor expanded in A around -inf

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1}{2} \cdot \frac{B}{A}\right)}}{\pi} \]
                        3. Step-by-step derivation
                          1. *-commutativeN/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \color{blue}{\frac{1}{2}}\right)}{\pi} \]
                          2. lower-*.f64N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \color{blue}{\frac{1}{2}}\right)}{\pi} \]
                          3. lower-/.f6448.4

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \]
                        4. Applied rewrites48.4%

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{B}{A} \cdot 0.5\right)}}{\pi} \]
                        5. Step-by-step derivation
                          1. lift-*.f64N/A

                            \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                          2. *-commutativeN/A

                            \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi} \cdot 180} \]
                          3. lower-*.f6448.4

                            \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \cdot 180} \]
                          4. pow248.4

                            \[\leadsto \frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \cdot 180 \]
                          5. pow248.4

                            \[\leadsto \frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \cdot 180 \]
                        6. Applied rewrites48.4%

                          \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \cdot 180} \]

                        if -3.2999999999999998e-274 < A < 1.05000000000000004e91

                        1. Initial program 60.7%

                          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                        2. Taylor expanded in C around -inf

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(2 \cdot \frac{C}{B}\right)}}{\pi} \]
                        3. Step-by-step derivation
                          1. associate-*r/N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{2 \cdot C}{\color{blue}{B}}\right)}{\pi} \]
                          2. lower-/.f64N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{2 \cdot C}{\color{blue}{B}}\right)}{\pi} \]
                          3. count-2-revN/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C + C}{B}\right)}{\pi} \]
                          4. lower-+.f6427.3

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C + C}{B}\right)}{\pi} \]
                        4. Applied rewrites27.3%

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C + C}{B}\right)}}{\pi} \]
                        5. Step-by-step derivation
                          1. lift-*.f64N/A

                            \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{C + C}{B}\right)}{\pi}} \]
                          2. lift-PI.f64N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C + C}{B}\right)}{\color{blue}{\mathsf{PI}\left(\right)}} \]
                          3. lift-/.f64N/A

                            \[\leadsto 180 \cdot \color{blue}{\frac{\tan^{-1} \left(\frac{C + C}{B}\right)}{\mathsf{PI}\left(\right)}} \]
                          4. associate-*r/N/A

                            \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{C + C}{B}\right)}{\mathsf{PI}\left(\right)}} \]
                          5. lower-/.f64N/A

                            \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{C + C}{B}\right)}{\mathsf{PI}\left(\right)}} \]
                        6. Applied rewrites27.3%

                          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{C + C}{B}\right)}{\pi}} \]

                        if 1.05000000000000004e91 < A

                        1. Initial program 80.9%

                          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                        2. Taylor expanded in A around inf

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-2 \cdot \frac{A}{B}\right)}}{\pi} \]
                        3. Step-by-step derivation
                          1. *-commutativeN/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A}{B} \cdot \color{blue}{-2}\right)}{\pi} \]
                          2. lower-*.f64N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A}{B} \cdot \color{blue}{-2}\right)}{\pi} \]
                          3. lower-/.f6477.3

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{A}{B} \cdot -2\right)}{\pi} \]
                        4. Applied rewrites77.3%

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{A}{B} \cdot -2\right)}}{\pi} \]
                        5. Step-by-step derivation
                          1. lift-*.f64N/A

                            \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{A}{B} \cdot -2\right)}{\pi}} \]
                          2. *-commutativeN/A

                            \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{A}{B} \cdot -2\right)}{\pi} \cdot 180} \]
                          3. lower-*.f6477.3

                            \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{A}{B} \cdot -2\right)}{\pi} \cdot 180} \]
                        6. Applied rewrites77.3%

                          \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{A}{B} \cdot -2\right)}{\pi} \cdot 180} \]
                      3. Recombined 3 regimes into one program.
                      4. Add Preprocessing

                      Alternative 11: 45.9% accurate, 2.2× speedup?

                      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq -2.3 \cdot 10^{+64}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\ \mathbf{elif}\;B \leq 5.4 \cdot 10^{-26}:\\ \;\;\;\;\frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \cdot 180\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
                      (FPCore (A B C)
                       :precision binary64
                       (if (<= B -2.3e+64)
                         (* 180.0 (/ (atan 1.0) PI))
                         (if (<= B 5.4e-26)
                           (* (/ (atan (* (/ B A) 0.5)) PI) 180.0)
                           (* 180.0 (/ (atan -1.0) PI)))))
                      double code(double A, double B, double C) {
                      	double tmp;
                      	if (B <= -2.3e+64) {
                      		tmp = 180.0 * (atan(1.0) / ((double) M_PI));
                      	} else if (B <= 5.4e-26) {
                      		tmp = (atan(((B / A) * 0.5)) / ((double) M_PI)) * 180.0;
                      	} else {
                      		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
                      	}
                      	return tmp;
                      }
                      
                      public static double code(double A, double B, double C) {
                      	double tmp;
                      	if (B <= -2.3e+64) {
                      		tmp = 180.0 * (Math.atan(1.0) / Math.PI);
                      	} else if (B <= 5.4e-26) {
                      		tmp = (Math.atan(((B / A) * 0.5)) / Math.PI) * 180.0;
                      	} else {
                      		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
                      	}
                      	return tmp;
                      }
                      
                      def code(A, B, C):
                      	tmp = 0
                      	if B <= -2.3e+64:
                      		tmp = 180.0 * (math.atan(1.0) / math.pi)
                      	elif B <= 5.4e-26:
                      		tmp = (math.atan(((B / A) * 0.5)) / math.pi) * 180.0
                      	else:
                      		tmp = 180.0 * (math.atan(-1.0) / math.pi)
                      	return tmp
                      
                      function code(A, B, C)
                      	tmp = 0.0
                      	if (B <= -2.3e+64)
                      		tmp = Float64(180.0 * Float64(atan(1.0) / pi));
                      	elseif (B <= 5.4e-26)
                      		tmp = Float64(Float64(atan(Float64(Float64(B / A) * 0.5)) / pi) * 180.0);
                      	else
                      		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
                      	end
                      	return tmp
                      end
                      
                      function tmp_2 = code(A, B, C)
                      	tmp = 0.0;
                      	if (B <= -2.3e+64)
                      		tmp = 180.0 * (atan(1.0) / pi);
                      	elseif (B <= 5.4e-26)
                      		tmp = (atan(((B / A) * 0.5)) / pi) * 180.0;
                      	else
                      		tmp = 180.0 * (atan(-1.0) / pi);
                      	end
                      	tmp_2 = tmp;
                      end
                      
                      code[A_, B_, C_] := If[LessEqual[B, -2.3e+64], N[(180.0 * N[(N[ArcTan[1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[B, 5.4e-26], N[(N[(N[ArcTan[N[(N[(B / A), $MachinePrecision] * 0.5), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision] * 180.0), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]
                      
                      \begin{array}{l}
                      
                      \\
                      \begin{array}{l}
                      \mathbf{if}\;B \leq -2.3 \cdot 10^{+64}:\\
                      \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\
                      
                      \mathbf{elif}\;B \leq 5.4 \cdot 10^{-26}:\\
                      \;\;\;\;\frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \cdot 180\\
                      
                      \mathbf{else}:\\
                      \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
                      
                      
                      \end{array}
                      \end{array}
                      
                      Derivation
                      1. Split input into 3 regimes
                      2. if B < -2.3e64

                        1. Initial program 43.8%

                          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                        2. Taylor expanded in B around -inf

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\pi} \]
                        3. Step-by-step derivation
                          1. Applied rewrites68.5%

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\pi} \]

                          if -2.3e64 < B < 5.39999999999999963e-26

                          1. Initial program 58.8%

                            \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                          2. Taylor expanded in A around -inf

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1}{2} \cdot \frac{B}{A}\right)}}{\pi} \]
                          3. Step-by-step derivation
                            1. *-commutativeN/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \color{blue}{\frac{1}{2}}\right)}{\pi} \]
                            2. lower-*.f64N/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \color{blue}{\frac{1}{2}}\right)}{\pi} \]
                            3. lower-/.f6430.2

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \]
                          4. Applied rewrites30.2%

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{B}{A} \cdot 0.5\right)}}{\pi} \]
                          5. Step-by-step derivation
                            1. lift-*.f64N/A

                              \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                            2. *-commutativeN/A

                              \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi} \cdot 180} \]
                            3. lower-*.f6430.2

                              \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \cdot 180} \]
                            4. pow230.2

                              \[\leadsto \frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \cdot 180 \]
                            5. pow230.2

                              \[\leadsto \frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \cdot 180 \]
                          6. Applied rewrites30.2%

                            \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \cdot 180} \]

                          if 5.39999999999999963e-26 < B

                          1. Initial program 49.5%

                            \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                          2. Taylor expanded in B around inf

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                          3. Step-by-step derivation
                            1. Applied rewrites59.5%

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                          4. Recombined 3 regimes into one program.
                          5. Add Preprocessing

                          Alternative 12: 45.1% accurate, 2.2× speedup?

                          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq -9.2 \cdot 10^{+123}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\ \mathbf{elif}\;B \leq 6.4 \cdot 10^{-66}:\\ \;\;\;\;\frac{\tan^{-1} \left(\frac{C + C}{B}\right)}{\pi} \cdot 180\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
                          (FPCore (A B C)
                           :precision binary64
                           (if (<= B -9.2e+123)
                             (* 180.0 (/ (atan 1.0) PI))
                             (if (<= B 6.4e-66)
                               (* (/ (atan (/ (+ C C) B)) PI) 180.0)
                               (* 180.0 (/ (atan -1.0) PI)))))
                          double code(double A, double B, double C) {
                          	double tmp;
                          	if (B <= -9.2e+123) {
                          		tmp = 180.0 * (atan(1.0) / ((double) M_PI));
                          	} else if (B <= 6.4e-66) {
                          		tmp = (atan(((C + C) / B)) / ((double) M_PI)) * 180.0;
                          	} else {
                          		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
                          	}
                          	return tmp;
                          }
                          
                          public static double code(double A, double B, double C) {
                          	double tmp;
                          	if (B <= -9.2e+123) {
                          		tmp = 180.0 * (Math.atan(1.0) / Math.PI);
                          	} else if (B <= 6.4e-66) {
                          		tmp = (Math.atan(((C + C) / B)) / Math.PI) * 180.0;
                          	} else {
                          		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
                          	}
                          	return tmp;
                          }
                          
                          def code(A, B, C):
                          	tmp = 0
                          	if B <= -9.2e+123:
                          		tmp = 180.0 * (math.atan(1.0) / math.pi)
                          	elif B <= 6.4e-66:
                          		tmp = (math.atan(((C + C) / B)) / math.pi) * 180.0
                          	else:
                          		tmp = 180.0 * (math.atan(-1.0) / math.pi)
                          	return tmp
                          
                          function code(A, B, C)
                          	tmp = 0.0
                          	if (B <= -9.2e+123)
                          		tmp = Float64(180.0 * Float64(atan(1.0) / pi));
                          	elseif (B <= 6.4e-66)
                          		tmp = Float64(Float64(atan(Float64(Float64(C + C) / B)) / pi) * 180.0);
                          	else
                          		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
                          	end
                          	return tmp
                          end
                          
                          function tmp_2 = code(A, B, C)
                          	tmp = 0.0;
                          	if (B <= -9.2e+123)
                          		tmp = 180.0 * (atan(1.0) / pi);
                          	elseif (B <= 6.4e-66)
                          		tmp = (atan(((C + C) / B)) / pi) * 180.0;
                          	else
                          		tmp = 180.0 * (atan(-1.0) / pi);
                          	end
                          	tmp_2 = tmp;
                          end
                          
                          code[A_, B_, C_] := If[LessEqual[B, -9.2e+123], N[(180.0 * N[(N[ArcTan[1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[B, 6.4e-66], N[(N[(N[ArcTan[N[(N[(C + C), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision] * 180.0), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]
                          
                          \begin{array}{l}
                          
                          \\
                          \begin{array}{l}
                          \mathbf{if}\;B \leq -9.2 \cdot 10^{+123}:\\
                          \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\
                          
                          \mathbf{elif}\;B \leq 6.4 \cdot 10^{-66}:\\
                          \;\;\;\;\frac{\tan^{-1} \left(\frac{C + C}{B}\right)}{\pi} \cdot 180\\
                          
                          \mathbf{else}:\\
                          \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
                          
                          
                          \end{array}
                          \end{array}
                          
                          Derivation
                          1. Split input into 3 regimes
                          2. if B < -9.19999999999999962e123

                            1. Initial program 34.9%

                              \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                            2. Taylor expanded in B around -inf

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\pi} \]
                            3. Step-by-step derivation
                              1. Applied rewrites75.2%

                                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\pi} \]

                              if -9.19999999999999962e123 < B < 6.39999999999999963e-66

                              1. Initial program 59.9%

                                \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                              2. Taylor expanded in C around -inf

                                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(2 \cdot \frac{C}{B}\right)}}{\pi} \]
                              3. Step-by-step derivation
                                1. associate-*r/N/A

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{2 \cdot C}{\color{blue}{B}}\right)}{\pi} \]
                                2. lower-/.f64N/A

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{2 \cdot C}{\color{blue}{B}}\right)}{\pi} \]
                                3. count-2-revN/A

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C + C}{B}\right)}{\pi} \]
                                4. lower-+.f6430.8

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C + C}{B}\right)}{\pi} \]
                              4. Applied rewrites30.8%

                                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{C + C}{B}\right)}}{\pi} \]
                              5. Step-by-step derivation
                                1. lift-*.f64N/A

                                  \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{C + C}{B}\right)}{\pi}} \]
                                2. *-commutativeN/A

                                  \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{C + C}{B}\right)}{\pi} \cdot 180} \]
                                3. lower-*.f6430.8

                                  \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{C + C}{B}\right)}{\pi} \cdot 180} \]
                                4. pow230.8

                                  \[\leadsto \frac{\tan^{-1} \left(\frac{C + C}{B}\right)}{\pi} \cdot 180 \]
                                5. pow230.8

                                  \[\leadsto \frac{\tan^{-1} \left(\frac{C + C}{B}\right)}{\pi} \cdot 180 \]
                              6. Applied rewrites30.8%

                                \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{C + C}{B}\right)}{\pi} \cdot 180} \]

                              if 6.39999999999999963e-66 < B

                              1. Initial program 50.4%

                                \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                              2. Taylor expanded in B around inf

                                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                              3. Step-by-step derivation
                                1. Applied rewrites56.0%

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                              4. Recombined 3 regimes into one program.
                              5. Add Preprocessing

                              Alternative 13: 40.1% accurate, 3.3× speedup?

                              \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq -5 \cdot 10^{-310}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
                              (FPCore (A B C)
                               :precision binary64
                               (if (<= B -5e-310) (* 180.0 (/ (atan 1.0) PI)) (* 180.0 (/ (atan -1.0) PI))))
                              double code(double A, double B, double C) {
                              	double tmp;
                              	if (B <= -5e-310) {
                              		tmp = 180.0 * (atan(1.0) / ((double) M_PI));
                              	} else {
                              		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
                              	}
                              	return tmp;
                              }
                              
                              public static double code(double A, double B, double C) {
                              	double tmp;
                              	if (B <= -5e-310) {
                              		tmp = 180.0 * (Math.atan(1.0) / Math.PI);
                              	} else {
                              		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
                              	}
                              	return tmp;
                              }
                              
                              def code(A, B, C):
                              	tmp = 0
                              	if B <= -5e-310:
                              		tmp = 180.0 * (math.atan(1.0) / math.pi)
                              	else:
                              		tmp = 180.0 * (math.atan(-1.0) / math.pi)
                              	return tmp
                              
                              function code(A, B, C)
                              	tmp = 0.0
                              	if (B <= -5e-310)
                              		tmp = Float64(180.0 * Float64(atan(1.0) / pi));
                              	else
                              		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
                              	end
                              	return tmp
                              end
                              
                              function tmp_2 = code(A, B, C)
                              	tmp = 0.0;
                              	if (B <= -5e-310)
                              		tmp = 180.0 * (atan(1.0) / pi);
                              	else
                              		tmp = 180.0 * (atan(-1.0) / pi);
                              	end
                              	tmp_2 = tmp;
                              end
                              
                              code[A_, B_, C_] := If[LessEqual[B, -5e-310], N[(180.0 * N[(N[ArcTan[1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]
                              
                              \begin{array}{l}
                              
                              \\
                              \begin{array}{l}
                              \mathbf{if}\;B \leq -5 \cdot 10^{-310}:\\
                              \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\
                              
                              \mathbf{else}:\\
                              \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
                              
                              
                              \end{array}
                              \end{array}
                              
                              Derivation
                              1. Split input into 2 regimes
                              2. if B < -4.999999999999985e-310

                                1. Initial program 53.4%

                                  \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                2. Taylor expanded in B around -inf

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\pi} \]
                                3. Step-by-step derivation
                                  1. Applied rewrites40.2%

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\pi} \]

                                  if -4.999999999999985e-310 < B

                                  1. Initial program 53.1%

                                    \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                  2. Taylor expanded in B around inf

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                  3. Step-by-step derivation
                                    1. Applied rewrites40.1%

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                  4. Recombined 2 regimes into one program.
                                  5. Add Preprocessing

                                  Alternative 14: 20.8% accurate, 4.1× speedup?

                                  \[\begin{array}{l} \\ 180 \cdot \frac{\tan^{-1} -1}{\pi} \end{array} \]
                                  (FPCore (A B C) :precision binary64 (* 180.0 (/ (atan -1.0) PI)))
                                  double code(double A, double B, double C) {
                                  	return 180.0 * (atan(-1.0) / ((double) M_PI));
                                  }
                                  
                                  public static double code(double A, double B, double C) {
                                  	return 180.0 * (Math.atan(-1.0) / Math.PI);
                                  }
                                  
                                  def code(A, B, C):
                                  	return 180.0 * (math.atan(-1.0) / math.pi)
                                  
                                  function code(A, B, C)
                                  	return Float64(180.0 * Float64(atan(-1.0) / pi))
                                  end
                                  
                                  function tmp = code(A, B, C)
                                  	tmp = 180.0 * (atan(-1.0) / pi);
                                  end
                                  
                                  code[A_, B_, C_] := N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]
                                  
                                  \begin{array}{l}
                                  
                                  \\
                                  180 \cdot \frac{\tan^{-1} -1}{\pi}
                                  \end{array}
                                  
                                  Derivation
                                  1. Initial program 53.3%

                                    \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                  2. Taylor expanded in B around inf

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                  3. Step-by-step derivation
                                    1. Applied rewrites20.8%

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                    2. Add Preprocessing

                                    Reproduce

                                    ?
                                    herbie shell --seed 2025110 
                                    (FPCore (A B C)
                                      :name "ABCF->ab-angle angle"
                                      :precision binary64
                                      (* 180.0 (/ (atan (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))) PI)))