ABCF->ab-angle b

Percentage Accurate: 18.7% → 46.8%
Time: 12.5s
Alternatives: 11
Speedup: N/A×

Specification

?
\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (- (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
module fmin_fmax_functions
    implicit none
    private
    public fmax
    public fmin

    interface fmax
        module procedure fmax88
        module procedure fmax44
        module procedure fmax84
        module procedure fmax48
    end interface
    interface fmin
        module procedure fmin88
        module procedure fmin44
        module procedure fmin84
        module procedure fmin48
    end interface
contains
    real(8) function fmax88(x, y) result (res)
        real(8), intent (in) :: x
        real(8), intent (in) :: y
        res = merge(y, merge(x, max(x, y), y /= y), x /= x)
    end function
    real(4) function fmax44(x, y) result (res)
        real(4), intent (in) :: x
        real(4), intent (in) :: y
        res = merge(y, merge(x, max(x, y), y /= y), x /= x)
    end function
    real(8) function fmax84(x, y) result(res)
        real(8), intent (in) :: x
        real(4), intent (in) :: y
        res = merge(dble(y), merge(x, max(x, dble(y)), y /= y), x /= x)
    end function
    real(8) function fmax48(x, y) result(res)
        real(4), intent (in) :: x
        real(8), intent (in) :: y
        res = merge(y, merge(dble(x), max(dble(x), y), y /= y), x /= x)
    end function
    real(8) function fmin88(x, y) result (res)
        real(8), intent (in) :: x
        real(8), intent (in) :: y
        res = merge(y, merge(x, min(x, y), y /= y), x /= x)
    end function
    real(4) function fmin44(x, y) result (res)
        real(4), intent (in) :: x
        real(4), intent (in) :: y
        res = merge(y, merge(x, min(x, y), y /= y), x /= x)
    end function
    real(8) function fmin84(x, y) result(res)
        real(8), intent (in) :: x
        real(4), intent (in) :: y
        res = merge(dble(y), merge(x, min(x, dble(y)), y /= y), x /= x)
    end function
    real(8) function fmin48(x, y) result(res)
        real(4), intent (in) :: x
        real(8), intent (in) :: y
        res = merge(y, merge(dble(x), min(dble(x), y), y /= y), x /= x)
    end function
end module

real(8) function code(a, b, c, f)
use fmin_fmax_functions
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) - sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 11 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 18.7% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (- (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
module fmin_fmax_functions
    implicit none
    private
    public fmax
    public fmin

    interface fmax
        module procedure fmax88
        module procedure fmax44
        module procedure fmax84
        module procedure fmax48
    end interface
    interface fmin
        module procedure fmin88
        module procedure fmin44
        module procedure fmin84
        module procedure fmin48
    end interface
contains
    real(8) function fmax88(x, y) result (res)
        real(8), intent (in) :: x
        real(8), intent (in) :: y
        res = merge(y, merge(x, max(x, y), y /= y), x /= x)
    end function
    real(4) function fmax44(x, y) result (res)
        real(4), intent (in) :: x
        real(4), intent (in) :: y
        res = merge(y, merge(x, max(x, y), y /= y), x /= x)
    end function
    real(8) function fmax84(x, y) result(res)
        real(8), intent (in) :: x
        real(4), intent (in) :: y
        res = merge(dble(y), merge(x, max(x, dble(y)), y /= y), x /= x)
    end function
    real(8) function fmax48(x, y) result(res)
        real(4), intent (in) :: x
        real(8), intent (in) :: y
        res = merge(y, merge(dble(x), max(dble(x), y), y /= y), x /= x)
    end function
    real(8) function fmin88(x, y) result (res)
        real(8), intent (in) :: x
        real(8), intent (in) :: y
        res = merge(y, merge(x, min(x, y), y /= y), x /= x)
    end function
    real(4) function fmin44(x, y) result (res)
        real(4), intent (in) :: x
        real(4), intent (in) :: y
        res = merge(y, merge(x, min(x, y), y /= y), x /= x)
    end function
    real(8) function fmin84(x, y) result(res)
        real(8), intent (in) :: x
        real(4), intent (in) :: y
        res = merge(dble(y), merge(x, min(x, dble(y)), y /= y), x /= x)
    end function
    real(8) function fmin48(x, y) result(res)
        real(4), intent (in) :: x
        real(8), intent (in) :: y
        res = merge(y, merge(dble(x), min(dble(x), y), y /= y), x /= x)
    end function
end module

real(8) function code(a, b, c, f)
use fmin_fmax_functions
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) - sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Alternative 1: 46.8% accurate, N/A× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;B\_m \leq 1400000000:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(A - -1 \cdot A\right)}}{-1 \cdot {B\_m}^{2} - \left(\left(-1 \cdot 4\right) \cdot A\right) \cdot C}\\ \mathbf{else}:\\ \;\;\;\;\left(-1 \cdot \frac{{2}^{0.5}}{B\_m}\right) \cdot {\left(F \cdot \left(-1 \cdot \left(-1 \cdot A + \mathsf{hypot}\left(-1 \cdot A, -1 \cdot B\_m\right)\right)\right)\right)}^{0.5}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (if (<= B_m 1400000000.0)
   (/
    (sqrt (* (* 2.0 (* (- (pow B_m 2.0) (* (* 4.0 A) C)) F)) (- A (* -1.0 A))))
    (- (* -1.0 (pow B_m 2.0)) (* (* (* -1.0 4.0) A) C)))
   (*
    (* -1.0 (/ (pow 2.0 0.5) B_m))
    (pow (* F (* -1.0 (+ (* -1.0 A) (hypot (* -1.0 A) (* -1.0 B_m))))) 0.5))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double tmp;
	if (B_m <= 1400000000.0) {
		tmp = sqrt(((2.0 * ((pow(B_m, 2.0) - ((4.0 * A) * C)) * F)) * (A - (-1.0 * A)))) / ((-1.0 * pow(B_m, 2.0)) - (((-1.0 * 4.0) * A) * C));
	} else {
		tmp = (-1.0 * (pow(2.0, 0.5) / B_m)) * pow((F * (-1.0 * ((-1.0 * A) + hypot((-1.0 * A), (-1.0 * B_m))))), 0.5);
	}
	return tmp;
}
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	double tmp;
	if (B_m <= 1400000000.0) {
		tmp = Math.sqrt(((2.0 * ((Math.pow(B_m, 2.0) - ((4.0 * A) * C)) * F)) * (A - (-1.0 * A)))) / ((-1.0 * Math.pow(B_m, 2.0)) - (((-1.0 * 4.0) * A) * C));
	} else {
		tmp = (-1.0 * (Math.pow(2.0, 0.5) / B_m)) * Math.pow((F * (-1.0 * ((-1.0 * A) + Math.hypot((-1.0 * A), (-1.0 * B_m))))), 0.5);
	}
	return tmp;
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	tmp = 0
	if B_m <= 1400000000.0:
		tmp = math.sqrt(((2.0 * ((math.pow(B_m, 2.0) - ((4.0 * A) * C)) * F)) * (A - (-1.0 * A)))) / ((-1.0 * math.pow(B_m, 2.0)) - (((-1.0 * 4.0) * A) * C))
	else:
		tmp = (-1.0 * (math.pow(2.0, 0.5) / B_m)) * math.pow((F * (-1.0 * ((-1.0 * A) + math.hypot((-1.0 * A), (-1.0 * B_m))))), 0.5)
	return tmp
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	tmp = 0.0
	if (B_m <= 1400000000.0)
		tmp = Float64(sqrt(Float64(Float64(2.0 * Float64(Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C)) * F)) * Float64(A - Float64(-1.0 * A)))) / Float64(Float64(-1.0 * (B_m ^ 2.0)) - Float64(Float64(Float64(-1.0 * 4.0) * A) * C)));
	else
		tmp = Float64(Float64(-1.0 * Float64((2.0 ^ 0.5) / B_m)) * (Float64(F * Float64(-1.0 * Float64(Float64(-1.0 * A) + hypot(Float64(-1.0 * A), Float64(-1.0 * B_m))))) ^ 0.5));
	end
	return tmp
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp_2 = code(A, B_m, C, F)
	tmp = 0.0;
	if (B_m <= 1400000000.0)
		tmp = sqrt(((2.0 * (((B_m ^ 2.0) - ((4.0 * A) * C)) * F)) * (A - (-1.0 * A)))) / ((-1.0 * (B_m ^ 2.0)) - (((-1.0 * 4.0) * A) * C));
	else
		tmp = (-1.0 * ((2.0 ^ 0.5) / B_m)) * ((F * (-1.0 * ((-1.0 * A) + hypot((-1.0 * A), (-1.0 * B_m))))) ^ 0.5);
	end
	tmp_2 = tmp;
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := If[LessEqual[B$95$m, 1400000000.0], N[(N[Sqrt[N[(N[(2.0 * N[(N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision] * F), $MachinePrecision]), $MachinePrecision] * N[(A - N[(-1.0 * A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[(N[(-1.0 * N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision] - N[(N[(N[(-1.0 * 4.0), $MachinePrecision] * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(-1.0 * N[(N[Power[2.0, 0.5], $MachinePrecision] / B$95$m), $MachinePrecision]), $MachinePrecision] * N[Power[N[(F * N[(-1.0 * N[(N[(-1.0 * A), $MachinePrecision] + N[Sqrt[N[(-1.0 * A), $MachinePrecision] ^ 2 + N[(-1.0 * B$95$m), $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 0.5], $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
\mathbf{if}\;B\_m \leq 1400000000:\\
\;\;\;\;\frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(A - -1 \cdot A\right)}}{-1 \cdot {B\_m}^{2} - \left(\left(-1 \cdot 4\right) \cdot A\right) \cdot C}\\

\mathbf{else}:\\
\;\;\;\;\left(-1 \cdot \frac{{2}^{0.5}}{B\_m}\right) \cdot {\left(F \cdot \left(-1 \cdot \left(-1 \cdot A + \mathsf{hypot}\left(-1 \cdot A, -1 \cdot B\_m\right)\right)\right)\right)}^{0.5}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if B < 1.4e9

    1. Initial program 18.3%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around inf

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(A - -1 \cdot A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Step-by-step derivation
      1. lower--.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(A - \color{blue}{-1 \cdot A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lower-*.f6420.3

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(A - -1 \cdot \color{blue}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    5. Applied rewrites20.3%

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(A - -1 \cdot A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

    if 1.4e9 < B

    1. Initial program 8.7%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \color{blue}{\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
      2. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \color{blue}{\sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      3. lower-/.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      4. pow1/2N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot \sqrt{\color{blue}{F} \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      5. lower-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot \sqrt{\color{blue}{F} \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      6. pow1/2N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)}^{\color{blue}{\frac{1}{2}}}\right) \]
      7. lower-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)}^{\color{blue}{\frac{1}{2}}}\right) \]
    5. Applied rewrites12.4%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{{2}^{0.5}}{B} \cdot {\left(F \cdot \left(A - {\left(\mathsf{fma}\left(A, A, B \cdot B\right)\right)}^{0.5}\right)\right)}^{0.5}\right)} \]
    6. Step-by-step derivation
      1. lift-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - {\left(\mathsf{fma}\left(A, A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)\right)}^{\frac{1}{2}}\right) \]
      2. lift-fma.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - {\left(A \cdot A + B \cdot B\right)}^{\frac{1}{2}}\right)\right)}^{\frac{1}{2}}\right) \]
      3. lift-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - {\left(A \cdot A + B \cdot B\right)}^{\frac{1}{2}}\right)\right)}^{\frac{1}{2}}\right) \]
      4. unpow1/2N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{A \cdot A + B \cdot B}\right)\right)}^{\frac{1}{2}}\right) \]
      5. sqr-neg-revN/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{\left(\mathsf{neg}\left(A\right)\right) \cdot \left(\mathsf{neg}\left(A\right)\right) + B \cdot B}\right)\right)}^{\frac{1}{2}}\right) \]
      6. sqr-neg-revN/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{\left(\mathsf{neg}\left(A\right)\right) \cdot \left(\mathsf{neg}\left(A\right)\right) + \left(\mathsf{neg}\left(B\right)\right) \cdot \left(\mathsf{neg}\left(B\right)\right)}\right)\right)}^{\frac{1}{2}}\right) \]
      7. lower-hypot.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \mathsf{hypot}\left(\mathsf{neg}\left(A\right), \mathsf{neg}\left(B\right)\right)\right)\right)}^{\frac{1}{2}}\right) \]
      8. lower-neg.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \mathsf{hypot}\left(-A, \mathsf{neg}\left(B\right)\right)\right)\right)}^{\frac{1}{2}}\right) \]
      9. lower-neg.f6440.5

        \[\leadsto -1 \cdot \left(\frac{{2}^{0.5}}{B} \cdot {\left(F \cdot \left(A - \mathsf{hypot}\left(-A, -B\right)\right)\right)}^{0.5}\right) \]
    7. Applied rewrites40.5%

      \[\leadsto -1 \cdot \left(\frac{{2}^{0.5}}{B} \cdot {\left(F \cdot \left(A - \mathsf{hypot}\left(-A, -B\right)\right)\right)}^{0.5}\right) \]
  3. Recombined 2 regimes into one program.
  4. Final simplification24.2%

    \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 1400000000:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(A - -1 \cdot A\right)}}{-1 \cdot {B}^{2} - \left(\left(-1 \cdot 4\right) \cdot A\right) \cdot C}\\ \mathbf{else}:\\ \;\;\;\;\left(-1 \cdot \frac{{2}^{0.5}}{B}\right) \cdot {\left(F \cdot \left(-1 \cdot \left(-1 \cdot A + \mathsf{hypot}\left(-1 \cdot A, -1 \cdot B\right)\right)\right)\right)}^{0.5}\\ \end{array} \]
  5. Add Preprocessing

Alternative 2: 46.7% accurate, N/A× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := {\left(A - C\right)}^{2}\\ t_1 := -1 \cdot {B\_m}^{2} - \left(\left(-1 \cdot 4\right) \cdot A\right) \cdot C\\ t_2 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{t\_0 + {B\_m}^{2}}\right)}}{t\_1}\\ \mathbf{if}\;t\_2 \leq -\infty:\\ \;\;\;\;{\left(-0.5 \cdot \frac{F}{C}\right)}^{0.5} \cdot \left(-1 \cdot {2}^{0.5}\right)\\ \mathbf{elif}\;t\_2 \leq -1 \cdot 10^{-193}:\\ \;\;\;\;\frac{\sqrt{F \cdot \left(\left(\left(A + C\right) - \sqrt{{B\_m}^{2} + t\_0}\right) \cdot \left({B\_m}^{2} - 4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{2}}{t\_1}\\ \mathbf{elif}\;t\_2 \leq \infty:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-8, A \cdot \left(C \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right), 2 \cdot \left(\left(B\_m \cdot B\_m\right) \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) + A\right)\right)\right)\right)}}{t\_1}\\ \mathbf{else}:\\ \;\;\;\;\left(-1 \cdot \frac{{2}^{0.5}}{B\_m}\right) \cdot {\left(F \cdot \left(-1 \cdot \left(-1 \cdot A + \mathsf{hypot}\left(-1 \cdot A, -1 \cdot B\_m\right)\right)\right)\right)}^{0.5}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (let* ((t_0 (pow (- A C) 2.0))
        (t_1 (- (* -1.0 (pow B_m 2.0)) (* (* (* -1.0 4.0) A) C)))
        (t_2
         (/
          (sqrt
           (*
            (* 2.0 (* (- (pow B_m 2.0) (* (* 4.0 A) C)) F))
            (- (+ A C) (sqrt (+ t_0 (pow B_m 2.0))))))
          t_1)))
   (if (<= t_2 (- INFINITY))
     (* (pow (* -0.5 (/ F C)) 0.5) (* -1.0 (pow 2.0 0.5)))
     (if (<= t_2 -1e-193)
       (/
        (*
         (sqrt
          (*
           F
           (*
            (- (+ A C) (sqrt (+ (pow B_m 2.0) t_0)))
            (- (pow B_m 2.0) (* 4.0 (* A C))))))
         (sqrt 2.0))
        t_1)
       (if (<= t_2 INFINITY)
         (/
          (sqrt
           (fma
            -8.0
            (* A (* C (* F (- A (* -1.0 A)))))
            (* 2.0 (* (* B_m B_m) (* F (+ (+ A (* 2.0 A)) A))))))
          t_1)
         (*
          (* -1.0 (/ (pow 2.0 0.5) B_m))
          (pow
           (* F (* -1.0 (+ (* -1.0 A) (hypot (* -1.0 A) (* -1.0 B_m)))))
           0.5)))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double t_0 = pow((A - C), 2.0);
	double t_1 = (-1.0 * pow(B_m, 2.0)) - (((-1.0 * 4.0) * A) * C);
	double t_2 = sqrt(((2.0 * ((pow(B_m, 2.0) - ((4.0 * A) * C)) * F)) * ((A + C) - sqrt((t_0 + pow(B_m, 2.0)))))) / t_1;
	double tmp;
	if (t_2 <= -((double) INFINITY)) {
		tmp = pow((-0.5 * (F / C)), 0.5) * (-1.0 * pow(2.0, 0.5));
	} else if (t_2 <= -1e-193) {
		tmp = (sqrt((F * (((A + C) - sqrt((pow(B_m, 2.0) + t_0))) * (pow(B_m, 2.0) - (4.0 * (A * C)))))) * sqrt(2.0)) / t_1;
	} else if (t_2 <= ((double) INFINITY)) {
		tmp = sqrt(fma(-8.0, (A * (C * (F * (A - (-1.0 * A))))), (2.0 * ((B_m * B_m) * (F * ((A + (2.0 * A)) + A)))))) / t_1;
	} else {
		tmp = (-1.0 * (pow(2.0, 0.5) / B_m)) * pow((F * (-1.0 * ((-1.0 * A) + hypot((-1.0 * A), (-1.0 * B_m))))), 0.5);
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	t_0 = Float64(A - C) ^ 2.0
	t_1 = Float64(Float64(-1.0 * (B_m ^ 2.0)) - Float64(Float64(Float64(-1.0 * 4.0) * A) * C))
	t_2 = Float64(sqrt(Float64(Float64(2.0 * Float64(Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C)) * F)) * Float64(Float64(A + C) - sqrt(Float64(t_0 + (B_m ^ 2.0)))))) / t_1)
	tmp = 0.0
	if (t_2 <= Float64(-Inf))
		tmp = Float64((Float64(-0.5 * Float64(F / C)) ^ 0.5) * Float64(-1.0 * (2.0 ^ 0.5)));
	elseif (t_2 <= -1e-193)
		tmp = Float64(Float64(sqrt(Float64(F * Float64(Float64(Float64(A + C) - sqrt(Float64((B_m ^ 2.0) + t_0))) * Float64((B_m ^ 2.0) - Float64(4.0 * Float64(A * C)))))) * sqrt(2.0)) / t_1);
	elseif (t_2 <= Inf)
		tmp = Float64(sqrt(fma(-8.0, Float64(A * Float64(C * Float64(F * Float64(A - Float64(-1.0 * A))))), Float64(2.0 * Float64(Float64(B_m * B_m) * Float64(F * Float64(Float64(A + Float64(2.0 * A)) + A)))))) / t_1);
	else
		tmp = Float64(Float64(-1.0 * Float64((2.0 ^ 0.5) / B_m)) * (Float64(F * Float64(-1.0 * Float64(Float64(-1.0 * A) + hypot(Float64(-1.0 * A), Float64(-1.0 * B_m))))) ^ 0.5));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision]}, Block[{t$95$1 = N[(N[(-1.0 * N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision] - N[(N[(N[(-1.0 * 4.0), $MachinePrecision] * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(N[Sqrt[N[(N[(2.0 * N[(N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision] * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] - N[Sqrt[N[(t$95$0 + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / t$95$1), $MachinePrecision]}, If[LessEqual[t$95$2, (-Infinity)], N[(N[Power[N[(-0.5 * N[(F / C), $MachinePrecision]), $MachinePrecision], 0.5], $MachinePrecision] * N[(-1.0 * N[Power[2.0, 0.5], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$2, -1e-193], N[(N[(N[Sqrt[N[(F * N[(N[(N[(A + C), $MachinePrecision] - N[Sqrt[N[(N[Power[B$95$m, 2.0], $MachinePrecision] + t$95$0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(4.0 * N[(A * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision] / t$95$1), $MachinePrecision], If[LessEqual[t$95$2, Infinity], N[(N[Sqrt[N[(-8.0 * N[(A * N[(C * N[(F * N[(A - N[(-1.0 * A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(2.0 * N[(N[(B$95$m * B$95$m), $MachinePrecision] * N[(F * N[(N[(A + N[(2.0 * A), $MachinePrecision]), $MachinePrecision] + A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / t$95$1), $MachinePrecision], N[(N[(-1.0 * N[(N[Power[2.0, 0.5], $MachinePrecision] / B$95$m), $MachinePrecision]), $MachinePrecision] * N[Power[N[(F * N[(-1.0 * N[(N[(-1.0 * A), $MachinePrecision] + N[Sqrt[N[(-1.0 * A), $MachinePrecision] ^ 2 + N[(-1.0 * B$95$m), $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 0.5], $MachinePrecision]), $MachinePrecision]]]]]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
t_0 := {\left(A - C\right)}^{2}\\
t_1 := -1 \cdot {B\_m}^{2} - \left(\left(-1 \cdot 4\right) \cdot A\right) \cdot C\\
t_2 := \frac{\sqrt{\left(2 \cdot \left(\left({B\_m}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{t\_0 + {B\_m}^{2}}\right)}}{t\_1}\\
\mathbf{if}\;t\_2 \leq -\infty:\\
\;\;\;\;{\left(-0.5 \cdot \frac{F}{C}\right)}^{0.5} \cdot \left(-1 \cdot {2}^{0.5}\right)\\

\mathbf{elif}\;t\_2 \leq -1 \cdot 10^{-193}:\\
\;\;\;\;\frac{\sqrt{F \cdot \left(\left(\left(A + C\right) - \sqrt{{B\_m}^{2} + t\_0}\right) \cdot \left({B\_m}^{2} - 4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{2}}{t\_1}\\

\mathbf{elif}\;t\_2 \leq \infty:\\
\;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-8, A \cdot \left(C \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right), 2 \cdot \left(\left(B\_m \cdot B\_m\right) \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) + A\right)\right)\right)\right)}}{t\_1}\\

\mathbf{else}:\\
\;\;\;\;\left(-1 \cdot \frac{{2}^{0.5}}{B\_m}\right) \cdot {\left(F \cdot \left(-1 \cdot \left(-1 \cdot A + \mathsf{hypot}\left(-1 \cdot A, -1 \cdot B\_m\right)\right)\right)\right)}^{0.5}\\


\end{array}
\end{array}
Derivation
  1. Split input into 4 regimes
  2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (-.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -inf.0

    1. Initial program 3.5%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    4. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \color{blue}{\left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
      2. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \color{blue}{\sqrt{2}}\right) \]
    5. Applied rewrites14.3%

      \[\leadsto \color{blue}{-1 \cdot \left({\left(\frac{F \cdot \left(\left(A + C\right) - {\left(\mathsf{fma}\left(B, B, {\left(A - C\right)}^{2}\right)\right)}^{0.5}\right)}{B \cdot B - 4 \cdot \left(A \cdot C\right)}\right)}^{0.5} \cdot {2}^{0.5}\right)} \]
    6. Taylor expanded in A around -inf

      \[\leadsto -1 \cdot \left({\left(\frac{-1}{2} \cdot \frac{F}{C}\right)}^{\frac{1}{2}} \cdot {2}^{\frac{1}{2}}\right) \]
    7. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \left({\left(\frac{-1}{2} \cdot \frac{F}{C}\right)}^{\frac{1}{2}} \cdot {2}^{\frac{1}{2}}\right) \]
      2. lower-/.f6425.0

        \[\leadsto -1 \cdot \left({\left(-0.5 \cdot \frac{F}{C}\right)}^{0.5} \cdot {2}^{0.5}\right) \]
    8. Applied rewrites25.0%

      \[\leadsto -1 \cdot \left({\left(-0.5 \cdot \frac{F}{C}\right)}^{0.5} \cdot {2}^{0.5}\right) \]

    if -inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (-.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -1e-193

    1. Initial program 99.2%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around 0

      \[\leadsto \frac{-\color{blue}{\sqrt{F \cdot \left(\left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right) \cdot \left({B}^{2} - 4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{F \cdot \left(\left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right) \cdot \left({B}^{2} - 4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \color{blue}{\sqrt{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    5. Applied rewrites0.0%

      \[\leadsto \frac{-\color{blue}{\left(\sqrt{F} \cdot \sqrt{\left(\left(A + C\right) - {\left(\mathsf{fma}\left(B, B, {\left(A - C\right)}^{2}\right)\right)}^{0.5}\right) \cdot \left(B \cdot B - 4 \cdot \left(A \cdot C\right)\right)}\right) \cdot {2}^{0.5}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    6. Taylor expanded in F around 0

      \[\leadsto \frac{-\color{blue}{\sqrt{F \cdot \left(\left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right) \cdot \left({B}^{2} - 4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    7. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{F \cdot \left(\left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right) \cdot \left({B}^{2} - 4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \color{blue}{\sqrt{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    8. Applied rewrites90.0%

      \[\leadsto \frac{-\color{blue}{\sqrt{F \cdot \left(\left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right) \cdot \left({B}^{2} - 4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

    if -1e-193 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (-.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

    1. Initial program 14.0%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around inf

      \[\leadsto \frac{-\sqrt{\color{blue}{C \cdot \left(-8 \cdot \left(A \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right) + 2 \cdot \frac{F \cdot \left(2 \cdot \left(A \cdot {B}^{2}\right) + {B}^{2} \cdot \left(A - -1 \cdot A\right)\right)}{C}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{C \cdot \color{blue}{\left(-8 \cdot \left(A \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right) + 2 \cdot \frac{F \cdot \left(2 \cdot \left(A \cdot {B}^{2}\right) + {B}^{2} \cdot \left(A - -1 \cdot A\right)\right)}{C}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lower-fma.f64N/A

        \[\leadsto \frac{-\sqrt{C \cdot \mathsf{fma}\left(-8, \color{blue}{A \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)}, 2 \cdot \frac{F \cdot \left(2 \cdot \left(A \cdot {B}^{2}\right) + {B}^{2} \cdot \left(A - -1 \cdot A\right)\right)}{C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{C \cdot \mathsf{fma}\left(-8, A \cdot \color{blue}{\left(F \cdot \left(A - -1 \cdot A\right)\right)}, 2 \cdot \frac{F \cdot \left(2 \cdot \left(A \cdot {B}^{2}\right) + {B}^{2} \cdot \left(A - -1 \cdot A\right)\right)}{C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{C \cdot \mathsf{fma}\left(-8, A \cdot \left(F \cdot \color{blue}{\left(A - -1 \cdot A\right)}\right), 2 \cdot \frac{F \cdot \left(2 \cdot \left(A \cdot {B}^{2}\right) + {B}^{2} \cdot \left(A - -1 \cdot A\right)\right)}{C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. lower--.f64N/A

        \[\leadsto \frac{-\sqrt{C \cdot \mathsf{fma}\left(-8, A \cdot \left(F \cdot \left(A - \color{blue}{-1 \cdot A}\right)\right), 2 \cdot \frac{F \cdot \left(2 \cdot \left(A \cdot {B}^{2}\right) + {B}^{2} \cdot \left(A - -1 \cdot A\right)\right)}{C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{C \cdot \mathsf{fma}\left(-8, A \cdot \left(F \cdot \left(A - -1 \cdot \color{blue}{A}\right)\right), 2 \cdot \frac{F \cdot \left(2 \cdot \left(A \cdot {B}^{2}\right) + {B}^{2} \cdot \left(A - -1 \cdot A\right)\right)}{C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      7. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{C \cdot \mathsf{fma}\left(-8, A \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right), 2 \cdot \frac{F \cdot \left(2 \cdot \left(A \cdot {B}^{2}\right) + {B}^{2} \cdot \left(A - -1 \cdot A\right)\right)}{C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    5. Applied rewrites28.5%

      \[\leadsto \frac{-\sqrt{\color{blue}{C \cdot \mathsf{fma}\left(-8, A \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right), 2 \cdot \frac{F \cdot \mathsf{fma}\left(2, A \cdot \left(B \cdot B\right), \left(B \cdot B\right) \cdot \left(A - -1 \cdot A\right)\right)}{C}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    6. Taylor expanded in B around 0

      \[\leadsto \frac{-\sqrt{-8 \cdot \left(A \cdot \left(C \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right)\right) + \color{blue}{2 \cdot \left({B}^{2} \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) - -1 \cdot A\right)\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    7. Step-by-step derivation
      1. lower-fma.f64N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-8, A \cdot \color{blue}{\left(C \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right)}, 2 \cdot \left({B}^{2} \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) - -1 \cdot A\right)\right)\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-8, A \cdot \left(C \cdot \color{blue}{\left(F \cdot \left(A - -1 \cdot A\right)\right)}\right), 2 \cdot \left({B}^{2} \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) - -1 \cdot A\right)\right)\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-8, A \cdot \left(C \cdot \left(F \cdot \color{blue}{\left(A - -1 \cdot A\right)}\right)\right), 2 \cdot \left({B}^{2} \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) - -1 \cdot A\right)\right)\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-8, A \cdot \left(C \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right), 2 \cdot \left({B}^{2} \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) - -1 \cdot A\right)\right)\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. lift--.f64N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-8, A \cdot \left(C \cdot \left(F \cdot \left(A - -1 \cdot \color{blue}{A}\right)\right)\right), 2 \cdot \left({B}^{2} \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) - -1 \cdot A\right)\right)\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-8, A \cdot \left(C \cdot \left(F \cdot \left(A - \color{blue}{-1 \cdot A}\right)\right)\right), 2 \cdot \left({B}^{2} \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) - -1 \cdot A\right)\right)\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      7. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-8, A \cdot \left(C \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right), 2 \cdot \left({B}^{2} \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) - -1 \cdot A\right)\right)\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      8. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-8, A \cdot \left(C \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right), 2 \cdot \left({B}^{2} \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) - -1 \cdot A\right)\right)\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      9. pow2N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-8, A \cdot \left(C \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right), 2 \cdot \left(\left(B \cdot B\right) \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) - -1 \cdot A\right)\right)\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      10. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-8, A \cdot \left(C \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right), 2 \cdot \left(\left(B \cdot B\right) \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) - -1 \cdot A\right)\right)\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      11. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-8, A \cdot \left(C \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right), 2 \cdot \left(\left(B \cdot B\right) \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) - -1 \cdot A\right)\right)\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    8. Applied rewrites33.2%

      \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-8, \color{blue}{A \cdot \left(C \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right)}, 2 \cdot \left(\left(B \cdot B\right) \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) - -1 \cdot A\right)\right)\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

    if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (-.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

    1. Initial program 0.0%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \color{blue}{\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
      2. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \color{blue}{\sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      3. lower-/.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      4. pow1/2N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot \sqrt{\color{blue}{F} \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      5. lower-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot \sqrt{\color{blue}{F} \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      6. pow1/2N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)}^{\color{blue}{\frac{1}{2}}}\right) \]
      7. lower-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)}^{\color{blue}{\frac{1}{2}}}\right) \]
    5. Applied rewrites1.8%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{{2}^{0.5}}{B} \cdot {\left(F \cdot \left(A - {\left(\mathsf{fma}\left(A, A, B \cdot B\right)\right)}^{0.5}\right)\right)}^{0.5}\right)} \]
    6. Step-by-step derivation
      1. lift-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - {\left(\mathsf{fma}\left(A, A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)\right)}^{\frac{1}{2}}\right) \]
      2. lift-fma.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - {\left(A \cdot A + B \cdot B\right)}^{\frac{1}{2}}\right)\right)}^{\frac{1}{2}}\right) \]
      3. lift-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - {\left(A \cdot A + B \cdot B\right)}^{\frac{1}{2}}\right)\right)}^{\frac{1}{2}}\right) \]
      4. unpow1/2N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{A \cdot A + B \cdot B}\right)\right)}^{\frac{1}{2}}\right) \]
      5. sqr-neg-revN/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{\left(\mathsf{neg}\left(A\right)\right) \cdot \left(\mathsf{neg}\left(A\right)\right) + B \cdot B}\right)\right)}^{\frac{1}{2}}\right) \]
      6. sqr-neg-revN/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{\left(\mathsf{neg}\left(A\right)\right) \cdot \left(\mathsf{neg}\left(A\right)\right) + \left(\mathsf{neg}\left(B\right)\right) \cdot \left(\mathsf{neg}\left(B\right)\right)}\right)\right)}^{\frac{1}{2}}\right) \]
      7. lower-hypot.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \mathsf{hypot}\left(\mathsf{neg}\left(A\right), \mathsf{neg}\left(B\right)\right)\right)\right)}^{\frac{1}{2}}\right) \]
      8. lower-neg.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \mathsf{hypot}\left(-A, \mathsf{neg}\left(B\right)\right)\right)\right)}^{\frac{1}{2}}\right) \]
      9. lower-neg.f6414.0

        \[\leadsto -1 \cdot \left(\frac{{2}^{0.5}}{B} \cdot {\left(F \cdot \left(A - \mathsf{hypot}\left(-A, -B\right)\right)\right)}^{0.5}\right) \]
    7. Applied rewrites14.0%

      \[\leadsto -1 \cdot \left(\frac{{2}^{0.5}}{B} \cdot {\left(F \cdot \left(A - \mathsf{hypot}\left(-A, -B\right)\right)\right)}^{0.5}\right) \]
  3. Recombined 4 regimes into one program.
  4. Final simplification30.1%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-1 \cdot {B}^{2} - \left(\left(-1 \cdot 4\right) \cdot A\right) \cdot C} \leq -\infty:\\ \;\;\;\;{\left(-0.5 \cdot \frac{F}{C}\right)}^{0.5} \cdot \left(-1 \cdot {2}^{0.5}\right)\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-1 \cdot {B}^{2} - \left(\left(-1 \cdot 4\right) \cdot A\right) \cdot C} \leq -1 \cdot 10^{-193}:\\ \;\;\;\;\frac{\sqrt{F \cdot \left(\left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right) \cdot \left({B}^{2} - 4 \cdot \left(A \cdot C\right)\right)\right)} \cdot \sqrt{2}}{-1 \cdot {B}^{2} - \left(\left(-1 \cdot 4\right) \cdot A\right) \cdot C}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-1 \cdot {B}^{2} - \left(\left(-1 \cdot 4\right) \cdot A\right) \cdot C} \leq \infty:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-8, A \cdot \left(C \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right), 2 \cdot \left(\left(B \cdot B\right) \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) + A\right)\right)\right)\right)}}{-1 \cdot {B}^{2} - \left(\left(-1 \cdot 4\right) \cdot A\right) \cdot C}\\ \mathbf{else}:\\ \;\;\;\;\left(-1 \cdot \frac{{2}^{0.5}}{B}\right) \cdot {\left(F \cdot \left(-1 \cdot \left(-1 \cdot A + \mathsf{hypot}\left(-1 \cdot A, -1 \cdot B\right)\right)\right)\right)}^{0.5}\\ \end{array} \]
  5. Add Preprocessing

Alternative 3: 43.7% accurate, N/A× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;{B\_m}^{2} \leq 10^{-117}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot \mathsf{fma}\left(-4, A \cdot \left(C \cdot F\right), \left(B\_m \cdot B\_m\right) \cdot F\right)\right) \cdot \left(A - -1 \cdot A\right)}}{-1 \cdot {B\_m}^{2} - \left(\left(-1 \cdot 4\right) \cdot A\right) \cdot C}\\ \mathbf{elif}\;{B\_m}^{2} \leq 4 \cdot 10^{-21}:\\ \;\;\;\;{\left(-0.5 \cdot \frac{F}{C}\right)}^{0.5} \cdot \left(-1 \cdot {2}^{0.5}\right)\\ \mathbf{else}:\\ \;\;\;\;\left(-1 \cdot \frac{{2}^{0.5}}{B\_m}\right) \cdot {\left(F \cdot \left(-1 \cdot \left(-1 \cdot A + \mathsf{hypot}\left(-1 \cdot A, -1 \cdot B\_m\right)\right)\right)\right)}^{0.5}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (if (<= (pow B_m 2.0) 1e-117)
   (/
    (sqrt
     (* (* 2.0 (fma -4.0 (* A (* C F)) (* (* B_m B_m) F))) (- A (* -1.0 A))))
    (- (* -1.0 (pow B_m 2.0)) (* (* (* -1.0 4.0) A) C)))
   (if (<= (pow B_m 2.0) 4e-21)
     (* (pow (* -0.5 (/ F C)) 0.5) (* -1.0 (pow 2.0 0.5)))
     (*
      (* -1.0 (/ (pow 2.0 0.5) B_m))
      (pow
       (* F (* -1.0 (+ (* -1.0 A) (hypot (* -1.0 A) (* -1.0 B_m)))))
       0.5)))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double tmp;
	if (pow(B_m, 2.0) <= 1e-117) {
		tmp = sqrt(((2.0 * fma(-4.0, (A * (C * F)), ((B_m * B_m) * F))) * (A - (-1.0 * A)))) / ((-1.0 * pow(B_m, 2.0)) - (((-1.0 * 4.0) * A) * C));
	} else if (pow(B_m, 2.0) <= 4e-21) {
		tmp = pow((-0.5 * (F / C)), 0.5) * (-1.0 * pow(2.0, 0.5));
	} else {
		tmp = (-1.0 * (pow(2.0, 0.5) / B_m)) * pow((F * (-1.0 * ((-1.0 * A) + hypot((-1.0 * A), (-1.0 * B_m))))), 0.5);
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	tmp = 0.0
	if ((B_m ^ 2.0) <= 1e-117)
		tmp = Float64(sqrt(Float64(Float64(2.0 * fma(-4.0, Float64(A * Float64(C * F)), Float64(Float64(B_m * B_m) * F))) * Float64(A - Float64(-1.0 * A)))) / Float64(Float64(-1.0 * (B_m ^ 2.0)) - Float64(Float64(Float64(-1.0 * 4.0) * A) * C)));
	elseif ((B_m ^ 2.0) <= 4e-21)
		tmp = Float64((Float64(-0.5 * Float64(F / C)) ^ 0.5) * Float64(-1.0 * (2.0 ^ 0.5)));
	else
		tmp = Float64(Float64(-1.0 * Float64((2.0 ^ 0.5) / B_m)) * (Float64(F * Float64(-1.0 * Float64(Float64(-1.0 * A) + hypot(Float64(-1.0 * A), Float64(-1.0 * B_m))))) ^ 0.5));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e-117], N[(N[Sqrt[N[(N[(2.0 * N[(-4.0 * N[(A * N[(C * F), $MachinePrecision]), $MachinePrecision] + N[(N[(B$95$m * B$95$m), $MachinePrecision] * F), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[(A - N[(-1.0 * A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[(N[(-1.0 * N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision] - N[(N[(N[(-1.0 * 4.0), $MachinePrecision] * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 4e-21], N[(N[Power[N[(-0.5 * N[(F / C), $MachinePrecision]), $MachinePrecision], 0.5], $MachinePrecision] * N[(-1.0 * N[Power[2.0, 0.5], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(-1.0 * N[(N[Power[2.0, 0.5], $MachinePrecision] / B$95$m), $MachinePrecision]), $MachinePrecision] * N[Power[N[(F * N[(-1.0 * N[(N[(-1.0 * A), $MachinePrecision] + N[Sqrt[N[(-1.0 * A), $MachinePrecision] ^ 2 + N[(-1.0 * B$95$m), $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 0.5], $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
\mathbf{if}\;{B\_m}^{2} \leq 10^{-117}:\\
\;\;\;\;\frac{\sqrt{\left(2 \cdot \mathsf{fma}\left(-4, A \cdot \left(C \cdot F\right), \left(B\_m \cdot B\_m\right) \cdot F\right)\right) \cdot \left(A - -1 \cdot A\right)}}{-1 \cdot {B\_m}^{2} - \left(\left(-1 \cdot 4\right) \cdot A\right) \cdot C}\\

\mathbf{elif}\;{B\_m}^{2} \leq 4 \cdot 10^{-21}:\\
\;\;\;\;{\left(-0.5 \cdot \frac{F}{C}\right)}^{0.5} \cdot \left(-1 \cdot {2}^{0.5}\right)\\

\mathbf{else}:\\
\;\;\;\;\left(-1 \cdot \frac{{2}^{0.5}}{B\_m}\right) \cdot {\left(F \cdot \left(-1 \cdot \left(-1 \cdot A + \mathsf{hypot}\left(-1 \cdot A, -1 \cdot B\_m\right)\right)\right)\right)}^{0.5}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (pow.f64 B #s(literal 2 binary64)) < 1.00000000000000003e-117

    1. Initial program 19.9%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around inf

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(A - -1 \cdot A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Step-by-step derivation
      1. lower--.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(A - \color{blue}{-1 \cdot A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lower-*.f6426.7

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(A - -1 \cdot \color{blue}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    5. Applied rewrites26.7%

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(A - -1 \cdot A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    6. Taylor expanded in A around 0

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \color{blue}{\left(-4 \cdot \left(A \cdot \left(C \cdot F\right)\right) + {B}^{2} \cdot F\right)}\right) \cdot \left(A - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    7. Step-by-step derivation
      1. lower-fma.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \mathsf{fma}\left(-4, \color{blue}{A \cdot \left(C \cdot F\right)}, {B}^{2} \cdot F\right)\right) \cdot \left(A - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \mathsf{fma}\left(-4, A \cdot \color{blue}{\left(C \cdot F\right)}, {B}^{2} \cdot F\right)\right) \cdot \left(A - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \mathsf{fma}\left(-4, A \cdot \left(C \cdot \color{blue}{F}\right), {B}^{2} \cdot F\right)\right) \cdot \left(A - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \mathsf{fma}\left(-4, A \cdot \left(C \cdot F\right), {B}^{2} \cdot F\right)\right) \cdot \left(A - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. pow2N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \mathsf{fma}\left(-4, A \cdot \left(C \cdot F\right), \left(B \cdot B\right) \cdot F\right)\right) \cdot \left(A - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. lift-*.f6422.6

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \mathsf{fma}\left(-4, A \cdot \left(C \cdot F\right), \left(B \cdot B\right) \cdot F\right)\right) \cdot \left(A - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    8. Applied rewrites22.6%

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \color{blue}{\mathsf{fma}\left(-4, A \cdot \left(C \cdot F\right), \left(B \cdot B\right) \cdot F\right)}\right) \cdot \left(A - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

    if 1.00000000000000003e-117 < (pow.f64 B #s(literal 2 binary64)) < 3.99999999999999963e-21

    1. Initial program 22.2%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    4. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \color{blue}{\left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
      2. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \color{blue}{\sqrt{2}}\right) \]
    5. Applied rewrites22.3%

      \[\leadsto \color{blue}{-1 \cdot \left({\left(\frac{F \cdot \left(\left(A + C\right) - {\left(\mathsf{fma}\left(B, B, {\left(A - C\right)}^{2}\right)\right)}^{0.5}\right)}{B \cdot B - 4 \cdot \left(A \cdot C\right)}\right)}^{0.5} \cdot {2}^{0.5}\right)} \]
    6. Taylor expanded in A around -inf

      \[\leadsto -1 \cdot \left({\left(\frac{-1}{2} \cdot \frac{F}{C}\right)}^{\frac{1}{2}} \cdot {2}^{\frac{1}{2}}\right) \]
    7. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \left({\left(\frac{-1}{2} \cdot \frac{F}{C}\right)}^{\frac{1}{2}} \cdot {2}^{\frac{1}{2}}\right) \]
      2. lower-/.f6434.9

        \[\leadsto -1 \cdot \left({\left(-0.5 \cdot \frac{F}{C}\right)}^{0.5} \cdot {2}^{0.5}\right) \]
    8. Applied rewrites34.9%

      \[\leadsto -1 \cdot \left({\left(-0.5 \cdot \frac{F}{C}\right)}^{0.5} \cdot {2}^{0.5}\right) \]

    if 3.99999999999999963e-21 < (pow.f64 B #s(literal 2 binary64))

    1. Initial program 11.9%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \color{blue}{\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
      2. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \color{blue}{\sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      3. lower-/.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      4. pow1/2N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot \sqrt{\color{blue}{F} \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      5. lower-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot \sqrt{\color{blue}{F} \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      6. pow1/2N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)}^{\color{blue}{\frac{1}{2}}}\right) \]
      7. lower-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)}^{\color{blue}{\frac{1}{2}}}\right) \]
    5. Applied rewrites6.9%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{{2}^{0.5}}{B} \cdot {\left(F \cdot \left(A - {\left(\mathsf{fma}\left(A, A, B \cdot B\right)\right)}^{0.5}\right)\right)}^{0.5}\right)} \]
    6. Step-by-step derivation
      1. lift-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - {\left(\mathsf{fma}\left(A, A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)\right)}^{\frac{1}{2}}\right) \]
      2. lift-fma.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - {\left(A \cdot A + B \cdot B\right)}^{\frac{1}{2}}\right)\right)}^{\frac{1}{2}}\right) \]
      3. lift-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - {\left(A \cdot A + B \cdot B\right)}^{\frac{1}{2}}\right)\right)}^{\frac{1}{2}}\right) \]
      4. unpow1/2N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{A \cdot A + B \cdot B}\right)\right)}^{\frac{1}{2}}\right) \]
      5. sqr-neg-revN/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{\left(\mathsf{neg}\left(A\right)\right) \cdot \left(\mathsf{neg}\left(A\right)\right) + B \cdot B}\right)\right)}^{\frac{1}{2}}\right) \]
      6. sqr-neg-revN/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{\left(\mathsf{neg}\left(A\right)\right) \cdot \left(\mathsf{neg}\left(A\right)\right) + \left(\mathsf{neg}\left(B\right)\right) \cdot \left(\mathsf{neg}\left(B\right)\right)}\right)\right)}^{\frac{1}{2}}\right) \]
      7. lower-hypot.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \mathsf{hypot}\left(\mathsf{neg}\left(A\right), \mathsf{neg}\left(B\right)\right)\right)\right)}^{\frac{1}{2}}\right) \]
      8. lower-neg.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \mathsf{hypot}\left(-A, \mathsf{neg}\left(B\right)\right)\right)\right)}^{\frac{1}{2}}\right) \]
      9. lower-neg.f6419.6

        \[\leadsto -1 \cdot \left(\frac{{2}^{0.5}}{B} \cdot {\left(F \cdot \left(A - \mathsf{hypot}\left(-A, -B\right)\right)\right)}^{0.5}\right) \]
    7. Applied rewrites19.6%

      \[\leadsto -1 \cdot \left(\frac{{2}^{0.5}}{B} \cdot {\left(F \cdot \left(A - \mathsf{hypot}\left(-A, -B\right)\right)\right)}^{0.5}\right) \]
  3. Recombined 3 regimes into one program.
  4. Final simplification22.4%

    \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 10^{-117}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot \mathsf{fma}\left(-4, A \cdot \left(C \cdot F\right), \left(B \cdot B\right) \cdot F\right)\right) \cdot \left(A - -1 \cdot A\right)}}{-1 \cdot {B}^{2} - \left(\left(-1 \cdot 4\right) \cdot A\right) \cdot C}\\ \mathbf{elif}\;{B}^{2} \leq 4 \cdot 10^{-21}:\\ \;\;\;\;{\left(-0.5 \cdot \frac{F}{C}\right)}^{0.5} \cdot \left(-1 \cdot {2}^{0.5}\right)\\ \mathbf{else}:\\ \;\;\;\;\left(-1 \cdot \frac{{2}^{0.5}}{B}\right) \cdot {\left(F \cdot \left(-1 \cdot \left(-1 \cdot A + \mathsf{hypot}\left(-1 \cdot A, -1 \cdot B\right)\right)\right)\right)}^{0.5}\\ \end{array} \]
  5. Add Preprocessing

Alternative 4: 43.3% accurate, N/A× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;{B\_m}^{2} \leq 4 \cdot 10^{-21}:\\ \;\;\;\;{\left(-0.5 \cdot \frac{F}{C}\right)}^{0.5} \cdot \left(-1 \cdot {2}^{0.5}\right)\\ \mathbf{else}:\\ \;\;\;\;\left(-1 \cdot \frac{{2}^{0.5}}{B\_m}\right) \cdot {\left(F \cdot \left(-1 \cdot \left(-1 \cdot A + \mathsf{hypot}\left(-1 \cdot A, -1 \cdot B\_m\right)\right)\right)\right)}^{0.5}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (if (<= (pow B_m 2.0) 4e-21)
   (* (pow (* -0.5 (/ F C)) 0.5) (* -1.0 (pow 2.0 0.5)))
   (*
    (* -1.0 (/ (pow 2.0 0.5) B_m))
    (pow (* F (* -1.0 (+ (* -1.0 A) (hypot (* -1.0 A) (* -1.0 B_m))))) 0.5))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double tmp;
	if (pow(B_m, 2.0) <= 4e-21) {
		tmp = pow((-0.5 * (F / C)), 0.5) * (-1.0 * pow(2.0, 0.5));
	} else {
		tmp = (-1.0 * (pow(2.0, 0.5) / B_m)) * pow((F * (-1.0 * ((-1.0 * A) + hypot((-1.0 * A), (-1.0 * B_m))))), 0.5);
	}
	return tmp;
}
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	double tmp;
	if (Math.pow(B_m, 2.0) <= 4e-21) {
		tmp = Math.pow((-0.5 * (F / C)), 0.5) * (-1.0 * Math.pow(2.0, 0.5));
	} else {
		tmp = (-1.0 * (Math.pow(2.0, 0.5) / B_m)) * Math.pow((F * (-1.0 * ((-1.0 * A) + Math.hypot((-1.0 * A), (-1.0 * B_m))))), 0.5);
	}
	return tmp;
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	tmp = 0
	if math.pow(B_m, 2.0) <= 4e-21:
		tmp = math.pow((-0.5 * (F / C)), 0.5) * (-1.0 * math.pow(2.0, 0.5))
	else:
		tmp = (-1.0 * (math.pow(2.0, 0.5) / B_m)) * math.pow((F * (-1.0 * ((-1.0 * A) + math.hypot((-1.0 * A), (-1.0 * B_m))))), 0.5)
	return tmp
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	tmp = 0.0
	if ((B_m ^ 2.0) <= 4e-21)
		tmp = Float64((Float64(-0.5 * Float64(F / C)) ^ 0.5) * Float64(-1.0 * (2.0 ^ 0.5)));
	else
		tmp = Float64(Float64(-1.0 * Float64((2.0 ^ 0.5) / B_m)) * (Float64(F * Float64(-1.0 * Float64(Float64(-1.0 * A) + hypot(Float64(-1.0 * A), Float64(-1.0 * B_m))))) ^ 0.5));
	end
	return tmp
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp_2 = code(A, B_m, C, F)
	tmp = 0.0;
	if ((B_m ^ 2.0) <= 4e-21)
		tmp = ((-0.5 * (F / C)) ^ 0.5) * (-1.0 * (2.0 ^ 0.5));
	else
		tmp = (-1.0 * ((2.0 ^ 0.5) / B_m)) * ((F * (-1.0 * ((-1.0 * A) + hypot((-1.0 * A), (-1.0 * B_m))))) ^ 0.5);
	end
	tmp_2 = tmp;
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 4e-21], N[(N[Power[N[(-0.5 * N[(F / C), $MachinePrecision]), $MachinePrecision], 0.5], $MachinePrecision] * N[(-1.0 * N[Power[2.0, 0.5], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(-1.0 * N[(N[Power[2.0, 0.5], $MachinePrecision] / B$95$m), $MachinePrecision]), $MachinePrecision] * N[Power[N[(F * N[(-1.0 * N[(N[(-1.0 * A), $MachinePrecision] + N[Sqrt[N[(-1.0 * A), $MachinePrecision] ^ 2 + N[(-1.0 * B$95$m), $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 0.5], $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
\mathbf{if}\;{B\_m}^{2} \leq 4 \cdot 10^{-21}:\\
\;\;\;\;{\left(-0.5 \cdot \frac{F}{C}\right)}^{0.5} \cdot \left(-1 \cdot {2}^{0.5}\right)\\

\mathbf{else}:\\
\;\;\;\;\left(-1 \cdot \frac{{2}^{0.5}}{B\_m}\right) \cdot {\left(F \cdot \left(-1 \cdot \left(-1 \cdot A + \mathsf{hypot}\left(-1 \cdot A, -1 \cdot B\_m\right)\right)\right)\right)}^{0.5}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (pow.f64 B #s(literal 2 binary64)) < 3.99999999999999963e-21

    1. Initial program 20.3%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    4. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \color{blue}{\left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
      2. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \color{blue}{\sqrt{2}}\right) \]
    5. Applied rewrites18.1%

      \[\leadsto \color{blue}{-1 \cdot \left({\left(\frac{F \cdot \left(\left(A + C\right) - {\left(\mathsf{fma}\left(B, B, {\left(A - C\right)}^{2}\right)\right)}^{0.5}\right)}{B \cdot B - 4 \cdot \left(A \cdot C\right)}\right)}^{0.5} \cdot {2}^{0.5}\right)} \]
    6. Taylor expanded in A around -inf

      \[\leadsto -1 \cdot \left({\left(\frac{-1}{2} \cdot \frac{F}{C}\right)}^{\frac{1}{2}} \cdot {2}^{\frac{1}{2}}\right) \]
    7. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \left({\left(\frac{-1}{2} \cdot \frac{F}{C}\right)}^{\frac{1}{2}} \cdot {2}^{\frac{1}{2}}\right) \]
      2. lower-/.f6420.2

        \[\leadsto -1 \cdot \left({\left(-0.5 \cdot \frac{F}{C}\right)}^{0.5} \cdot {2}^{0.5}\right) \]
    8. Applied rewrites20.2%

      \[\leadsto -1 \cdot \left({\left(-0.5 \cdot \frac{F}{C}\right)}^{0.5} \cdot {2}^{0.5}\right) \]

    if 3.99999999999999963e-21 < (pow.f64 B #s(literal 2 binary64))

    1. Initial program 11.9%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \color{blue}{\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
      2. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \color{blue}{\sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      3. lower-/.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      4. pow1/2N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot \sqrt{\color{blue}{F} \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      5. lower-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot \sqrt{\color{blue}{F} \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      6. pow1/2N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)}^{\color{blue}{\frac{1}{2}}}\right) \]
      7. lower-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)}^{\color{blue}{\frac{1}{2}}}\right) \]
    5. Applied rewrites6.9%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{{2}^{0.5}}{B} \cdot {\left(F \cdot \left(A - {\left(\mathsf{fma}\left(A, A, B \cdot B\right)\right)}^{0.5}\right)\right)}^{0.5}\right)} \]
    6. Step-by-step derivation
      1. lift-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - {\left(\mathsf{fma}\left(A, A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)\right)}^{\frac{1}{2}}\right) \]
      2. lift-fma.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - {\left(A \cdot A + B \cdot B\right)}^{\frac{1}{2}}\right)\right)}^{\frac{1}{2}}\right) \]
      3. lift-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - {\left(A \cdot A + B \cdot B\right)}^{\frac{1}{2}}\right)\right)}^{\frac{1}{2}}\right) \]
      4. unpow1/2N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{A \cdot A + B \cdot B}\right)\right)}^{\frac{1}{2}}\right) \]
      5. sqr-neg-revN/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{\left(\mathsf{neg}\left(A\right)\right) \cdot \left(\mathsf{neg}\left(A\right)\right) + B \cdot B}\right)\right)}^{\frac{1}{2}}\right) \]
      6. sqr-neg-revN/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{\left(\mathsf{neg}\left(A\right)\right) \cdot \left(\mathsf{neg}\left(A\right)\right) + \left(\mathsf{neg}\left(B\right)\right) \cdot \left(\mathsf{neg}\left(B\right)\right)}\right)\right)}^{\frac{1}{2}}\right) \]
      7. lower-hypot.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \mathsf{hypot}\left(\mathsf{neg}\left(A\right), \mathsf{neg}\left(B\right)\right)\right)\right)}^{\frac{1}{2}}\right) \]
      8. lower-neg.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \mathsf{hypot}\left(-A, \mathsf{neg}\left(B\right)\right)\right)\right)}^{\frac{1}{2}}\right) \]
      9. lower-neg.f6419.6

        \[\leadsto -1 \cdot \left(\frac{{2}^{0.5}}{B} \cdot {\left(F \cdot \left(A - \mathsf{hypot}\left(-A, -B\right)\right)\right)}^{0.5}\right) \]
    7. Applied rewrites19.6%

      \[\leadsto -1 \cdot \left(\frac{{2}^{0.5}}{B} \cdot {\left(F \cdot \left(A - \mathsf{hypot}\left(-A, -B\right)\right)\right)}^{0.5}\right) \]
  3. Recombined 2 regimes into one program.
  4. Final simplification19.9%

    \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 4 \cdot 10^{-21}:\\ \;\;\;\;{\left(-0.5 \cdot \frac{F}{C}\right)}^{0.5} \cdot \left(-1 \cdot {2}^{0.5}\right)\\ \mathbf{else}:\\ \;\;\;\;\left(-1 \cdot \frac{{2}^{0.5}}{B}\right) \cdot {\left(F \cdot \left(-1 \cdot \left(-1 \cdot A + \mathsf{hypot}\left(-1 \cdot A, -1 \cdot B\right)\right)\right)\right)}^{0.5}\\ \end{array} \]
  5. Add Preprocessing

Alternative 5: 37.4% accurate, N/A× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;F \leq -5.2 \cdot 10^{+25}:\\ \;\;\;\;{\left(-1 \cdot \frac{F}{B\_m}\right)}^{0.5} \cdot \left(-1 \cdot e^{\log 2 \cdot 0.5}\right)\\ \mathbf{else}:\\ \;\;\;\;\left(-1 \cdot \frac{{2}^{0.5}}{B\_m}\right) \cdot {\left(F \cdot \left(-1 \cdot \left(-1 \cdot A + \mathsf{hypot}\left(-1 \cdot A, -1 \cdot B\_m\right)\right)\right)\right)}^{0.5}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (if (<= F -5.2e+25)
   (* (pow (* -1.0 (/ F B_m)) 0.5) (* -1.0 (exp (* (log 2.0) 0.5))))
   (*
    (* -1.0 (/ (pow 2.0 0.5) B_m))
    (pow (* F (* -1.0 (+ (* -1.0 A) (hypot (* -1.0 A) (* -1.0 B_m))))) 0.5))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double tmp;
	if (F <= -5.2e+25) {
		tmp = pow((-1.0 * (F / B_m)), 0.5) * (-1.0 * exp((log(2.0) * 0.5)));
	} else {
		tmp = (-1.0 * (pow(2.0, 0.5) / B_m)) * pow((F * (-1.0 * ((-1.0 * A) + hypot((-1.0 * A), (-1.0 * B_m))))), 0.5);
	}
	return tmp;
}
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	double tmp;
	if (F <= -5.2e+25) {
		tmp = Math.pow((-1.0 * (F / B_m)), 0.5) * (-1.0 * Math.exp((Math.log(2.0) * 0.5)));
	} else {
		tmp = (-1.0 * (Math.pow(2.0, 0.5) / B_m)) * Math.pow((F * (-1.0 * ((-1.0 * A) + Math.hypot((-1.0 * A), (-1.0 * B_m))))), 0.5);
	}
	return tmp;
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	tmp = 0
	if F <= -5.2e+25:
		tmp = math.pow((-1.0 * (F / B_m)), 0.5) * (-1.0 * math.exp((math.log(2.0) * 0.5)))
	else:
		tmp = (-1.0 * (math.pow(2.0, 0.5) / B_m)) * math.pow((F * (-1.0 * ((-1.0 * A) + math.hypot((-1.0 * A), (-1.0 * B_m))))), 0.5)
	return tmp
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	tmp = 0.0
	if (F <= -5.2e+25)
		tmp = Float64((Float64(-1.0 * Float64(F / B_m)) ^ 0.5) * Float64(-1.0 * exp(Float64(log(2.0) * 0.5))));
	else
		tmp = Float64(Float64(-1.0 * Float64((2.0 ^ 0.5) / B_m)) * (Float64(F * Float64(-1.0 * Float64(Float64(-1.0 * A) + hypot(Float64(-1.0 * A), Float64(-1.0 * B_m))))) ^ 0.5));
	end
	return tmp
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp_2 = code(A, B_m, C, F)
	tmp = 0.0;
	if (F <= -5.2e+25)
		tmp = ((-1.0 * (F / B_m)) ^ 0.5) * (-1.0 * exp((log(2.0) * 0.5)));
	else
		tmp = (-1.0 * ((2.0 ^ 0.5) / B_m)) * ((F * (-1.0 * ((-1.0 * A) + hypot((-1.0 * A), (-1.0 * B_m))))) ^ 0.5);
	end
	tmp_2 = tmp;
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := If[LessEqual[F, -5.2e+25], N[(N[Power[N[(-1.0 * N[(F / B$95$m), $MachinePrecision]), $MachinePrecision], 0.5], $MachinePrecision] * N[(-1.0 * N[Exp[N[(N[Log[2.0], $MachinePrecision] * 0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(-1.0 * N[(N[Power[2.0, 0.5], $MachinePrecision] / B$95$m), $MachinePrecision]), $MachinePrecision] * N[Power[N[(F * N[(-1.0 * N[(N[(-1.0 * A), $MachinePrecision] + N[Sqrt[N[(-1.0 * A), $MachinePrecision] ^ 2 + N[(-1.0 * B$95$m), $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 0.5], $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
\mathbf{if}\;F \leq -5.2 \cdot 10^{+25}:\\
\;\;\;\;{\left(-1 \cdot \frac{F}{B\_m}\right)}^{0.5} \cdot \left(-1 \cdot e^{\log 2 \cdot 0.5}\right)\\

\mathbf{else}:\\
\;\;\;\;\left(-1 \cdot \frac{{2}^{0.5}}{B\_m}\right) \cdot {\left(F \cdot \left(-1 \cdot \left(-1 \cdot A + \mathsf{hypot}\left(-1 \cdot A, -1 \cdot B\_m\right)\right)\right)\right)}^{0.5}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if F < -5.1999999999999997e25

    1. Initial program 11.9%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    4. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \color{blue}{\left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
      2. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \color{blue}{\sqrt{2}}\right) \]
    5. Applied rewrites14.0%

      \[\leadsto \color{blue}{-1 \cdot \left({\left(\frac{F \cdot \left(\left(A + C\right) - {\left(\mathsf{fma}\left(B, B, {\left(A - C\right)}^{2}\right)\right)}^{0.5}\right)}{B \cdot B - 4 \cdot \left(A \cdot C\right)}\right)}^{0.5} \cdot {2}^{0.5}\right)} \]
    6. Taylor expanded in B around inf

      \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{\frac{1}{2}} \cdot {2}^{\frac{1}{2}}\right) \]
    7. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{\frac{1}{2}} \cdot {2}^{\frac{1}{2}}\right) \]
      2. lower-/.f6412.8

        \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{0.5} \cdot {2}^{0.5}\right) \]
    8. Applied rewrites12.8%

      \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{0.5} \cdot {2}^{0.5}\right) \]
    9. Step-by-step derivation
      1. lift-pow.f64N/A

        \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{\frac{1}{2}} \cdot {2}^{\color{blue}{\frac{1}{2}}}\right) \]
      2. pow-to-expN/A

        \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{\frac{1}{2}} \cdot e^{\log 2 \cdot \frac{1}{2}}\right) \]
      3. lower-exp.f64N/A

        \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{\frac{1}{2}} \cdot e^{\log 2 \cdot \frac{1}{2}}\right) \]
      4. lower-*.f64N/A

        \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{\frac{1}{2}} \cdot e^{\log 2 \cdot \frac{1}{2}}\right) \]
      5. lower-log.f6412.8

        \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{0.5} \cdot e^{\log 2 \cdot 0.5}\right) \]
    10. Applied rewrites12.8%

      \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{0.5} \cdot e^{\log 2 \cdot 0.5}\right) \]

    if -5.1999999999999997e25 < F

    1. Initial program 19.6%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \color{blue}{\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
      2. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \color{blue}{\sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      3. lower-/.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      4. pow1/2N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot \sqrt{\color{blue}{F} \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      5. lower-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot \sqrt{\color{blue}{F} \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      6. pow1/2N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)}^{\color{blue}{\frac{1}{2}}}\right) \]
      7. lower-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)}^{\color{blue}{\frac{1}{2}}}\right) \]
    5. Applied rewrites7.2%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{{2}^{0.5}}{B} \cdot {\left(F \cdot \left(A - {\left(\mathsf{fma}\left(A, A, B \cdot B\right)\right)}^{0.5}\right)\right)}^{0.5}\right)} \]
    6. Step-by-step derivation
      1. lift-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - {\left(\mathsf{fma}\left(A, A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)\right)}^{\frac{1}{2}}\right) \]
      2. lift-fma.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - {\left(A \cdot A + B \cdot B\right)}^{\frac{1}{2}}\right)\right)}^{\frac{1}{2}}\right) \]
      3. lift-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - {\left(A \cdot A + B \cdot B\right)}^{\frac{1}{2}}\right)\right)}^{\frac{1}{2}}\right) \]
      4. unpow1/2N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{A \cdot A + B \cdot B}\right)\right)}^{\frac{1}{2}}\right) \]
      5. sqr-neg-revN/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{\left(\mathsf{neg}\left(A\right)\right) \cdot \left(\mathsf{neg}\left(A\right)\right) + B \cdot B}\right)\right)}^{\frac{1}{2}}\right) \]
      6. sqr-neg-revN/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{\left(\mathsf{neg}\left(A\right)\right) \cdot \left(\mathsf{neg}\left(A\right)\right) + \left(\mathsf{neg}\left(B\right)\right) \cdot \left(\mathsf{neg}\left(B\right)\right)}\right)\right)}^{\frac{1}{2}}\right) \]
      7. lower-hypot.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \mathsf{hypot}\left(\mathsf{neg}\left(A\right), \mathsf{neg}\left(B\right)\right)\right)\right)}^{\frac{1}{2}}\right) \]
      8. lower-neg.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \mathsf{hypot}\left(-A, \mathsf{neg}\left(B\right)\right)\right)\right)}^{\frac{1}{2}}\right) \]
      9. lower-neg.f6416.2

        \[\leadsto -1 \cdot \left(\frac{{2}^{0.5}}{B} \cdot {\left(F \cdot \left(A - \mathsf{hypot}\left(-A, -B\right)\right)\right)}^{0.5}\right) \]
    7. Applied rewrites16.2%

      \[\leadsto -1 \cdot \left(\frac{{2}^{0.5}}{B} \cdot {\left(F \cdot \left(A - \mathsf{hypot}\left(-A, -B\right)\right)\right)}^{0.5}\right) \]
  3. Recombined 2 regimes into one program.
  4. Final simplification14.8%

    \[\leadsto \begin{array}{l} \mathbf{if}\;F \leq -5.2 \cdot 10^{+25}:\\ \;\;\;\;{\left(-1 \cdot \frac{F}{B}\right)}^{0.5} \cdot \left(-1 \cdot e^{\log 2 \cdot 0.5}\right)\\ \mathbf{else}:\\ \;\;\;\;\left(-1 \cdot \frac{{2}^{0.5}}{B}\right) \cdot {\left(F \cdot \left(-1 \cdot \left(-1 \cdot A + \mathsf{hypot}\left(-1 \cdot A, -1 \cdot B\right)\right)\right)\right)}^{0.5}\\ \end{array} \]
  5. Add Preprocessing

Alternative 6: 36.8% accurate, N/A× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;F \leq -3.4 \cdot 10^{+96}:\\ \;\;\;\;e^{\log \left(-1 \cdot \frac{F}{B\_m}\right) \cdot 0.5} \cdot \left(-1 \cdot {2}^{0.5}\right)\\ \mathbf{else}:\\ \;\;\;\;\left(-1 \cdot \frac{{2}^{0.5}}{B\_m}\right) \cdot {\left(F \cdot \left(-1 \cdot \left(-1 \cdot A + \mathsf{hypot}\left(-1 \cdot A, -1 \cdot B\_m\right)\right)\right)\right)}^{0.5}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (if (<= F -3.4e+96)
   (* (exp (* (log (* -1.0 (/ F B_m))) 0.5)) (* -1.0 (pow 2.0 0.5)))
   (*
    (* -1.0 (/ (pow 2.0 0.5) B_m))
    (pow (* F (* -1.0 (+ (* -1.0 A) (hypot (* -1.0 A) (* -1.0 B_m))))) 0.5))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double tmp;
	if (F <= -3.4e+96) {
		tmp = exp((log((-1.0 * (F / B_m))) * 0.5)) * (-1.0 * pow(2.0, 0.5));
	} else {
		tmp = (-1.0 * (pow(2.0, 0.5) / B_m)) * pow((F * (-1.0 * ((-1.0 * A) + hypot((-1.0 * A), (-1.0 * B_m))))), 0.5);
	}
	return tmp;
}
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	double tmp;
	if (F <= -3.4e+96) {
		tmp = Math.exp((Math.log((-1.0 * (F / B_m))) * 0.5)) * (-1.0 * Math.pow(2.0, 0.5));
	} else {
		tmp = (-1.0 * (Math.pow(2.0, 0.5) / B_m)) * Math.pow((F * (-1.0 * ((-1.0 * A) + Math.hypot((-1.0 * A), (-1.0 * B_m))))), 0.5);
	}
	return tmp;
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	tmp = 0
	if F <= -3.4e+96:
		tmp = math.exp((math.log((-1.0 * (F / B_m))) * 0.5)) * (-1.0 * math.pow(2.0, 0.5))
	else:
		tmp = (-1.0 * (math.pow(2.0, 0.5) / B_m)) * math.pow((F * (-1.0 * ((-1.0 * A) + math.hypot((-1.0 * A), (-1.0 * B_m))))), 0.5)
	return tmp
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	tmp = 0.0
	if (F <= -3.4e+96)
		tmp = Float64(exp(Float64(log(Float64(-1.0 * Float64(F / B_m))) * 0.5)) * Float64(-1.0 * (2.0 ^ 0.5)));
	else
		tmp = Float64(Float64(-1.0 * Float64((2.0 ^ 0.5) / B_m)) * (Float64(F * Float64(-1.0 * Float64(Float64(-1.0 * A) + hypot(Float64(-1.0 * A), Float64(-1.0 * B_m))))) ^ 0.5));
	end
	return tmp
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp_2 = code(A, B_m, C, F)
	tmp = 0.0;
	if (F <= -3.4e+96)
		tmp = exp((log((-1.0 * (F / B_m))) * 0.5)) * (-1.0 * (2.0 ^ 0.5));
	else
		tmp = (-1.0 * ((2.0 ^ 0.5) / B_m)) * ((F * (-1.0 * ((-1.0 * A) + hypot((-1.0 * A), (-1.0 * B_m))))) ^ 0.5);
	end
	tmp_2 = tmp;
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := If[LessEqual[F, -3.4e+96], N[(N[Exp[N[(N[Log[N[(-1.0 * N[(F / B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * 0.5), $MachinePrecision]], $MachinePrecision] * N[(-1.0 * N[Power[2.0, 0.5], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(-1.0 * N[(N[Power[2.0, 0.5], $MachinePrecision] / B$95$m), $MachinePrecision]), $MachinePrecision] * N[Power[N[(F * N[(-1.0 * N[(N[(-1.0 * A), $MachinePrecision] + N[Sqrt[N[(-1.0 * A), $MachinePrecision] ^ 2 + N[(-1.0 * B$95$m), $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 0.5], $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
\mathbf{if}\;F \leq -3.4 \cdot 10^{+96}:\\
\;\;\;\;e^{\log \left(-1 \cdot \frac{F}{B\_m}\right) \cdot 0.5} \cdot \left(-1 \cdot {2}^{0.5}\right)\\

\mathbf{else}:\\
\;\;\;\;\left(-1 \cdot \frac{{2}^{0.5}}{B\_m}\right) \cdot {\left(F \cdot \left(-1 \cdot \left(-1 \cdot A + \mathsf{hypot}\left(-1 \cdot A, -1 \cdot B\_m\right)\right)\right)\right)}^{0.5}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if F < -3.4000000000000001e96

    1. Initial program 13.3%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    4. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \color{blue}{\left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
      2. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \color{blue}{\sqrt{2}}\right) \]
    5. Applied rewrites14.7%

      \[\leadsto \color{blue}{-1 \cdot \left({\left(\frac{F \cdot \left(\left(A + C\right) - {\left(\mathsf{fma}\left(B, B, {\left(A - C\right)}^{2}\right)\right)}^{0.5}\right)}{B \cdot B - 4 \cdot \left(A \cdot C\right)}\right)}^{0.5} \cdot {2}^{0.5}\right)} \]
    6. Taylor expanded in B around inf

      \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{\frac{1}{2}} \cdot {2}^{\frac{1}{2}}\right) \]
    7. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{\frac{1}{2}} \cdot {2}^{\frac{1}{2}}\right) \]
      2. lower-/.f6414.3

        \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{0.5} \cdot {2}^{0.5}\right) \]
    8. Applied rewrites14.3%

      \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{0.5} \cdot {2}^{0.5}\right) \]
    9. Step-by-step derivation
      1. lift-pow.f64N/A

        \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{\frac{1}{2}} \cdot {\color{blue}{2}}^{\frac{1}{2}}\right) \]
      2. pow-to-expN/A

        \[\leadsto -1 \cdot \left(e^{\log \left(-1 \cdot \frac{F}{B}\right) \cdot \frac{1}{2}} \cdot {\color{blue}{2}}^{\frac{1}{2}}\right) \]
      3. lower-exp.f64N/A

        \[\leadsto -1 \cdot \left(e^{\log \left(-1 \cdot \frac{F}{B}\right) \cdot \frac{1}{2}} \cdot {\color{blue}{2}}^{\frac{1}{2}}\right) \]
      4. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(e^{\log \left(-1 \cdot \frac{F}{B}\right) \cdot \frac{1}{2}} \cdot {2}^{\frac{1}{2}}\right) \]
      5. lower-log.f6413.0

        \[\leadsto -1 \cdot \left(e^{\log \left(-1 \cdot \frac{F}{B}\right) \cdot 0.5} \cdot {2}^{0.5}\right) \]
    10. Applied rewrites13.0%

      \[\leadsto -1 \cdot \left(e^{\log \left(-1 \cdot \frac{F}{B}\right) \cdot 0.5} \cdot {\color{blue}{2}}^{0.5}\right) \]

    if -3.4000000000000001e96 < F

    1. Initial program 18.0%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \color{blue}{\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
      2. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \color{blue}{\sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      3. lower-/.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      4. pow1/2N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot \sqrt{\color{blue}{F} \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      5. lower-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot \sqrt{\color{blue}{F} \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      6. pow1/2N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)}^{\color{blue}{\frac{1}{2}}}\right) \]
      7. lower-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)}^{\color{blue}{\frac{1}{2}}}\right) \]
    5. Applied rewrites7.2%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{{2}^{0.5}}{B} \cdot {\left(F \cdot \left(A - {\left(\mathsf{fma}\left(A, A, B \cdot B\right)\right)}^{0.5}\right)\right)}^{0.5}\right)} \]
    6. Step-by-step derivation
      1. lift-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - {\left(\mathsf{fma}\left(A, A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)\right)}^{\frac{1}{2}}\right) \]
      2. lift-fma.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - {\left(A \cdot A + B \cdot B\right)}^{\frac{1}{2}}\right)\right)}^{\frac{1}{2}}\right) \]
      3. lift-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - {\left(A \cdot A + B \cdot B\right)}^{\frac{1}{2}}\right)\right)}^{\frac{1}{2}}\right) \]
      4. unpow1/2N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{A \cdot A + B \cdot B}\right)\right)}^{\frac{1}{2}}\right) \]
      5. sqr-neg-revN/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{\left(\mathsf{neg}\left(A\right)\right) \cdot \left(\mathsf{neg}\left(A\right)\right) + B \cdot B}\right)\right)}^{\frac{1}{2}}\right) \]
      6. sqr-neg-revN/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{\left(\mathsf{neg}\left(A\right)\right) \cdot \left(\mathsf{neg}\left(A\right)\right) + \left(\mathsf{neg}\left(B\right)\right) \cdot \left(\mathsf{neg}\left(B\right)\right)}\right)\right)}^{\frac{1}{2}}\right) \]
      7. lower-hypot.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \mathsf{hypot}\left(\mathsf{neg}\left(A\right), \mathsf{neg}\left(B\right)\right)\right)\right)}^{\frac{1}{2}}\right) \]
      8. lower-neg.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \mathsf{hypot}\left(-A, \mathsf{neg}\left(B\right)\right)\right)\right)}^{\frac{1}{2}}\right) \]
      9. lower-neg.f6415.7

        \[\leadsto -1 \cdot \left(\frac{{2}^{0.5}}{B} \cdot {\left(F \cdot \left(A - \mathsf{hypot}\left(-A, -B\right)\right)\right)}^{0.5}\right) \]
    7. Applied rewrites15.7%

      \[\leadsto -1 \cdot \left(\frac{{2}^{0.5}}{B} \cdot {\left(F \cdot \left(A - \mathsf{hypot}\left(-A, -B\right)\right)\right)}^{0.5}\right) \]
  3. Recombined 2 regimes into one program.
  4. Final simplification14.8%

    \[\leadsto \begin{array}{l} \mathbf{if}\;F \leq -3.4 \cdot 10^{+96}:\\ \;\;\;\;e^{\log \left(-1 \cdot \frac{F}{B}\right) \cdot 0.5} \cdot \left(-1 \cdot {2}^{0.5}\right)\\ \mathbf{else}:\\ \;\;\;\;\left(-1 \cdot \frac{{2}^{0.5}}{B}\right) \cdot {\left(F \cdot \left(-1 \cdot \left(-1 \cdot A + \mathsf{hypot}\left(-1 \cdot A, -1 \cdot B\right)\right)\right)\right)}^{0.5}\\ \end{array} \]
  5. Add Preprocessing

Alternative 7: 35.5% accurate, N/A× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;F \leq -5.2 \cdot 10^{+25}:\\ \;\;\;\;e^{\log \left(-1 \cdot \frac{F}{B\_m}\right) \cdot 0.5} \cdot \left(-1 \cdot {2}^{0.5}\right)\\ \mathbf{else}:\\ \;\;\;\;\left(-1 \cdot \frac{{2}^{0.5}}{B\_m}\right) \cdot e^{\log \left(F \cdot \left(A - \mathsf{hypot}\left(A, B\_m\right)\right)\right) \cdot 0.5}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (if (<= F -5.2e+25)
   (* (exp (* (log (* -1.0 (/ F B_m))) 0.5)) (* -1.0 (pow 2.0 0.5)))
   (*
    (* -1.0 (/ (pow 2.0 0.5) B_m))
    (exp (* (log (* F (- A (hypot A B_m)))) 0.5)))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double tmp;
	if (F <= -5.2e+25) {
		tmp = exp((log((-1.0 * (F / B_m))) * 0.5)) * (-1.0 * pow(2.0, 0.5));
	} else {
		tmp = (-1.0 * (pow(2.0, 0.5) / B_m)) * exp((log((F * (A - hypot(A, B_m)))) * 0.5));
	}
	return tmp;
}
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	double tmp;
	if (F <= -5.2e+25) {
		tmp = Math.exp((Math.log((-1.0 * (F / B_m))) * 0.5)) * (-1.0 * Math.pow(2.0, 0.5));
	} else {
		tmp = (-1.0 * (Math.pow(2.0, 0.5) / B_m)) * Math.exp((Math.log((F * (A - Math.hypot(A, B_m)))) * 0.5));
	}
	return tmp;
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	tmp = 0
	if F <= -5.2e+25:
		tmp = math.exp((math.log((-1.0 * (F / B_m))) * 0.5)) * (-1.0 * math.pow(2.0, 0.5))
	else:
		tmp = (-1.0 * (math.pow(2.0, 0.5) / B_m)) * math.exp((math.log((F * (A - math.hypot(A, B_m)))) * 0.5))
	return tmp
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	tmp = 0.0
	if (F <= -5.2e+25)
		tmp = Float64(exp(Float64(log(Float64(-1.0 * Float64(F / B_m))) * 0.5)) * Float64(-1.0 * (2.0 ^ 0.5)));
	else
		tmp = Float64(Float64(-1.0 * Float64((2.0 ^ 0.5) / B_m)) * exp(Float64(log(Float64(F * Float64(A - hypot(A, B_m)))) * 0.5)));
	end
	return tmp
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp_2 = code(A, B_m, C, F)
	tmp = 0.0;
	if (F <= -5.2e+25)
		tmp = exp((log((-1.0 * (F / B_m))) * 0.5)) * (-1.0 * (2.0 ^ 0.5));
	else
		tmp = (-1.0 * ((2.0 ^ 0.5) / B_m)) * exp((log((F * (A - hypot(A, B_m)))) * 0.5));
	end
	tmp_2 = tmp;
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := If[LessEqual[F, -5.2e+25], N[(N[Exp[N[(N[Log[N[(-1.0 * N[(F / B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * 0.5), $MachinePrecision]], $MachinePrecision] * N[(-1.0 * N[Power[2.0, 0.5], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(-1.0 * N[(N[Power[2.0, 0.5], $MachinePrecision] / B$95$m), $MachinePrecision]), $MachinePrecision] * N[Exp[N[(N[Log[N[(F * N[(A - N[Sqrt[A ^ 2 + B$95$m ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * 0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
\mathbf{if}\;F \leq -5.2 \cdot 10^{+25}:\\
\;\;\;\;e^{\log \left(-1 \cdot \frac{F}{B\_m}\right) \cdot 0.5} \cdot \left(-1 \cdot {2}^{0.5}\right)\\

\mathbf{else}:\\
\;\;\;\;\left(-1 \cdot \frac{{2}^{0.5}}{B\_m}\right) \cdot e^{\log \left(F \cdot \left(A - \mathsf{hypot}\left(A, B\_m\right)\right)\right) \cdot 0.5}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if F < -5.1999999999999997e25

    1. Initial program 11.9%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    4. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \color{blue}{\left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
      2. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \color{blue}{\sqrt{2}}\right) \]
    5. Applied rewrites14.0%

      \[\leadsto \color{blue}{-1 \cdot \left({\left(\frac{F \cdot \left(\left(A + C\right) - {\left(\mathsf{fma}\left(B, B, {\left(A - C\right)}^{2}\right)\right)}^{0.5}\right)}{B \cdot B - 4 \cdot \left(A \cdot C\right)}\right)}^{0.5} \cdot {2}^{0.5}\right)} \]
    6. Taylor expanded in B around inf

      \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{\frac{1}{2}} \cdot {2}^{\frac{1}{2}}\right) \]
    7. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{\frac{1}{2}} \cdot {2}^{\frac{1}{2}}\right) \]
      2. lower-/.f6412.8

        \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{0.5} \cdot {2}^{0.5}\right) \]
    8. Applied rewrites12.8%

      \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{0.5} \cdot {2}^{0.5}\right) \]
    9. Step-by-step derivation
      1. lift-pow.f64N/A

        \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{\frac{1}{2}} \cdot {\color{blue}{2}}^{\frac{1}{2}}\right) \]
      2. pow-to-expN/A

        \[\leadsto -1 \cdot \left(e^{\log \left(-1 \cdot \frac{F}{B}\right) \cdot \frac{1}{2}} \cdot {\color{blue}{2}}^{\frac{1}{2}}\right) \]
      3. lower-exp.f64N/A

        \[\leadsto -1 \cdot \left(e^{\log \left(-1 \cdot \frac{F}{B}\right) \cdot \frac{1}{2}} \cdot {\color{blue}{2}}^{\frac{1}{2}}\right) \]
      4. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(e^{\log \left(-1 \cdot \frac{F}{B}\right) \cdot \frac{1}{2}} \cdot {2}^{\frac{1}{2}}\right) \]
      5. lower-log.f6411.8

        \[\leadsto -1 \cdot \left(e^{\log \left(-1 \cdot \frac{F}{B}\right) \cdot 0.5} \cdot {2}^{0.5}\right) \]
    10. Applied rewrites11.8%

      \[\leadsto -1 \cdot \left(e^{\log \left(-1 \cdot \frac{F}{B}\right) \cdot 0.5} \cdot {\color{blue}{2}}^{0.5}\right) \]

    if -5.1999999999999997e25 < F

    1. Initial program 19.6%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \color{blue}{\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
      2. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \color{blue}{\sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      3. lower-/.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      4. pow1/2N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot \sqrt{\color{blue}{F} \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      5. lower-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot \sqrt{\color{blue}{F} \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      6. pow1/2N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)}^{\color{blue}{\frac{1}{2}}}\right) \]
      7. lower-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)}^{\color{blue}{\frac{1}{2}}}\right) \]
    5. Applied rewrites7.2%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{{2}^{0.5}}{B} \cdot {\left(F \cdot \left(A - {\left(\mathsf{fma}\left(A, A, B \cdot B\right)\right)}^{0.5}\right)\right)}^{0.5}\right)} \]
    6. Step-by-step derivation
      1. lift-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - {\left(\mathsf{fma}\left(A, A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)\right)}^{\color{blue}{\frac{1}{2}}}\right) \]
      2. lift-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - {\left(\mathsf{fma}\left(A, A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)\right)}^{\frac{1}{2}}\right) \]
      3. lift--.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - {\left(\mathsf{fma}\left(A, A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)\right)}^{\frac{1}{2}}\right) \]
      4. lift-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - {\left(\mathsf{fma}\left(A, A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)\right)}^{\frac{1}{2}}\right) \]
      5. lift-fma.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - {\left(A \cdot A + B \cdot B\right)}^{\frac{1}{2}}\right)\right)}^{\frac{1}{2}}\right) \]
      6. lift-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - {\left(A \cdot A + B \cdot B\right)}^{\frac{1}{2}}\right)\right)}^{\frac{1}{2}}\right) \]
      7. pow-to-expN/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot e^{\log \left(F \cdot \left(A - {\left(A \cdot A + B \cdot B\right)}^{\frac{1}{2}}\right)\right) \cdot \frac{1}{2}}\right) \]
      8. lower-exp.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot e^{\log \left(F \cdot \left(A - {\left(A \cdot A + B \cdot B\right)}^{\frac{1}{2}}\right)\right) \cdot \frac{1}{2}}\right) \]
      9. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot e^{\log \left(F \cdot \left(A - {\left(A \cdot A + B \cdot B\right)}^{\frac{1}{2}}\right)\right) \cdot \frac{1}{2}}\right) \]
    7. Applied rewrites15.3%

      \[\leadsto -1 \cdot \left(\frac{{2}^{0.5}}{B} \cdot e^{\log \left(F \cdot \left(A - \mathsf{hypot}\left(A, B\right)\right)\right) \cdot 0.5}\right) \]
  3. Recombined 2 regimes into one program.
  4. Final simplification13.9%

    \[\leadsto \begin{array}{l} \mathbf{if}\;F \leq -5.2 \cdot 10^{+25}:\\ \;\;\;\;e^{\log \left(-1 \cdot \frac{F}{B}\right) \cdot 0.5} \cdot \left(-1 \cdot {2}^{0.5}\right)\\ \mathbf{else}:\\ \;\;\;\;\left(-1 \cdot \frac{{2}^{0.5}}{B}\right) \cdot e^{\log \left(F \cdot \left(A - \mathsf{hypot}\left(A, B\right)\right)\right) \cdot 0.5}\\ \end{array} \]
  5. Add Preprocessing

Alternative 8: 27.6% accurate, N/A× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;{B\_m}^{2} \leq 10^{+226}:\\ \;\;\;\;\frac{e^{\log 2 \cdot 0.5}}{-1 \cdot B\_m} \cdot {\left(F \cdot \left(A - {\left(\mathsf{fma}\left(A, A, B\_m \cdot B\_m\right)\right)}^{0.5}\right)\right)}^{0.5}\\ \mathbf{else}:\\ \;\;\;\;e^{\log \left(-1 \cdot \frac{F}{B\_m}\right) \cdot 0.5} \cdot \left(-1 \cdot {2}^{0.5}\right)\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (if (<= (pow B_m 2.0) 1e+226)
   (*
    (/ (exp (* (log 2.0) 0.5)) (* -1.0 B_m))
    (pow (* F (- A (pow (fma A A (* B_m B_m)) 0.5))) 0.5))
   (* (exp (* (log (* -1.0 (/ F B_m))) 0.5)) (* -1.0 (pow 2.0 0.5)))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double tmp;
	if (pow(B_m, 2.0) <= 1e+226) {
		tmp = (exp((log(2.0) * 0.5)) / (-1.0 * B_m)) * pow((F * (A - pow(fma(A, A, (B_m * B_m)), 0.5))), 0.5);
	} else {
		tmp = exp((log((-1.0 * (F / B_m))) * 0.5)) * (-1.0 * pow(2.0, 0.5));
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	tmp = 0.0
	if ((B_m ^ 2.0) <= 1e+226)
		tmp = Float64(Float64(exp(Float64(log(2.0) * 0.5)) / Float64(-1.0 * B_m)) * (Float64(F * Float64(A - (fma(A, A, Float64(B_m * B_m)) ^ 0.5))) ^ 0.5));
	else
		tmp = Float64(exp(Float64(log(Float64(-1.0 * Float64(F / B_m))) * 0.5)) * Float64(-1.0 * (2.0 ^ 0.5)));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e+226], N[(N[(N[Exp[N[(N[Log[2.0], $MachinePrecision] * 0.5), $MachinePrecision]], $MachinePrecision] / N[(-1.0 * B$95$m), $MachinePrecision]), $MachinePrecision] * N[Power[N[(F * N[(A - N[Power[N[(A * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision], 0.5], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 0.5], $MachinePrecision]), $MachinePrecision], N[(N[Exp[N[(N[Log[N[(-1.0 * N[(F / B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * 0.5), $MachinePrecision]], $MachinePrecision] * N[(-1.0 * N[Power[2.0, 0.5], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
\mathbf{if}\;{B\_m}^{2} \leq 10^{+226}:\\
\;\;\;\;\frac{e^{\log 2 \cdot 0.5}}{-1 \cdot B\_m} \cdot {\left(F \cdot \left(A - {\left(\mathsf{fma}\left(A, A, B\_m \cdot B\_m\right)\right)}^{0.5}\right)\right)}^{0.5}\\

\mathbf{else}:\\
\;\;\;\;e^{\log \left(-1 \cdot \frac{F}{B\_m}\right) \cdot 0.5} \cdot \left(-1 \cdot {2}^{0.5}\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (pow.f64 B #s(literal 2 binary64)) < 9.99999999999999961e225

    1. Initial program 22.8%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \color{blue}{\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
      2. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \color{blue}{\sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      3. lower-/.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      4. pow1/2N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot \sqrt{\color{blue}{F} \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      5. lower-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot \sqrt{\color{blue}{F} \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      6. pow1/2N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)}^{\color{blue}{\frac{1}{2}}}\right) \]
      7. lower-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)}^{\color{blue}{\frac{1}{2}}}\right) \]
    5. Applied rewrites8.1%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{{2}^{0.5}}{B} \cdot {\left(F \cdot \left(A - {\left(\mathsf{fma}\left(A, A, B \cdot B\right)\right)}^{0.5}\right)\right)}^{0.5}\right)} \]
    6. Step-by-step derivation
      1. lift-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(\color{blue}{F} \cdot \left(A - {\left(\mathsf{fma}\left(A, A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)\right)}^{\frac{1}{2}}\right) \]
      2. pow-to-expN/A

        \[\leadsto -1 \cdot \left(\frac{e^{\log 2 \cdot \frac{1}{2}}}{B} \cdot {\left(\color{blue}{F} \cdot \left(A - {\left(\mathsf{fma}\left(A, A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)\right)}^{\frac{1}{2}}\right) \]
      3. lower-exp.f64N/A

        \[\leadsto -1 \cdot \left(\frac{e^{\log 2 \cdot \frac{1}{2}}}{B} \cdot {\left(\color{blue}{F} \cdot \left(A - {\left(\mathsf{fma}\left(A, A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)\right)}^{\frac{1}{2}}\right) \]
      4. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{e^{\log 2 \cdot \frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - {\left(\mathsf{fma}\left(A, A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)\right)}^{\frac{1}{2}}\right) \]
      5. lower-log.f648.1

        \[\leadsto -1 \cdot \left(\frac{e^{\log 2 \cdot 0.5}}{B} \cdot {\left(F \cdot \left(A - {\left(\mathsf{fma}\left(A, A, B \cdot B\right)\right)}^{0.5}\right)\right)}^{0.5}\right) \]
    7. Applied rewrites8.1%

      \[\leadsto -1 \cdot \left(\frac{e^{\log 2 \cdot 0.5}}{B} \cdot {\left(\color{blue}{F} \cdot \left(A - {\left(\mathsf{fma}\left(A, A, B \cdot B\right)\right)}^{0.5}\right)\right)}^{0.5}\right) \]

    if 9.99999999999999961e225 < (pow.f64 B #s(literal 2 binary64))

    1. Initial program 1.7%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    4. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \color{blue}{\left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
      2. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \color{blue}{\sqrt{2}}\right) \]
    5. Applied rewrites1.7%

      \[\leadsto \color{blue}{-1 \cdot \left({\left(\frac{F \cdot \left(\left(A + C\right) - {\left(\mathsf{fma}\left(B, B, {\left(A - C\right)}^{2}\right)\right)}^{0.5}\right)}{B \cdot B - 4 \cdot \left(A \cdot C\right)}\right)}^{0.5} \cdot {2}^{0.5}\right)} \]
    6. Taylor expanded in B around inf

      \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{\frac{1}{2}} \cdot {2}^{\frac{1}{2}}\right) \]
    7. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{\frac{1}{2}} \cdot {2}^{\frac{1}{2}}\right) \]
      2. lower-/.f6417.3

        \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{0.5} \cdot {2}^{0.5}\right) \]
    8. Applied rewrites17.3%

      \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{0.5} \cdot {2}^{0.5}\right) \]
    9. Step-by-step derivation
      1. lift-pow.f64N/A

        \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{\frac{1}{2}} \cdot {\color{blue}{2}}^{\frac{1}{2}}\right) \]
      2. pow-to-expN/A

        \[\leadsto -1 \cdot \left(e^{\log \left(-1 \cdot \frac{F}{B}\right) \cdot \frac{1}{2}} \cdot {\color{blue}{2}}^{\frac{1}{2}}\right) \]
      3. lower-exp.f64N/A

        \[\leadsto -1 \cdot \left(e^{\log \left(-1 \cdot \frac{F}{B}\right) \cdot \frac{1}{2}} \cdot {\color{blue}{2}}^{\frac{1}{2}}\right) \]
      4. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(e^{\log \left(-1 \cdot \frac{F}{B}\right) \cdot \frac{1}{2}} \cdot {2}^{\frac{1}{2}}\right) \]
      5. lower-log.f6416.5

        \[\leadsto -1 \cdot \left(e^{\log \left(-1 \cdot \frac{F}{B}\right) \cdot 0.5} \cdot {2}^{0.5}\right) \]
    10. Applied rewrites16.5%

      \[\leadsto -1 \cdot \left(e^{\log \left(-1 \cdot \frac{F}{B}\right) \cdot 0.5} \cdot {\color{blue}{2}}^{0.5}\right) \]
  3. Recombined 2 regimes into one program.
  4. Final simplification10.6%

    \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 10^{+226}:\\ \;\;\;\;\frac{e^{\log 2 \cdot 0.5}}{-1 \cdot B} \cdot {\left(F \cdot \left(A - {\left(\mathsf{fma}\left(A, A, B \cdot B\right)\right)}^{0.5}\right)\right)}^{0.5}\\ \mathbf{else}:\\ \;\;\;\;e^{\log \left(-1 \cdot \frac{F}{B}\right) \cdot 0.5} \cdot \left(-1 \cdot {2}^{0.5}\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 9: 26.0% accurate, N/A× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;A \leq -6 \cdot 10^{+199}:\\ \;\;\;\;-1 \cdot \left(\left(-1 \cdot {\left(A \cdot F\right)}^{0.5}\right) \cdot \frac{-2}{B\_m}\right)\\ \mathbf{else}:\\ \;\;\;\;e^{\log \left(-1 \cdot \frac{F}{B\_m}\right) \cdot 0.5} \cdot \left(-1 \cdot {2}^{0.5}\right)\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (if (<= A -6e+199)
   (* -1.0 (* (* -1.0 (pow (* A F) 0.5)) (/ -2.0 B_m)))
   (* (exp (* (log (* -1.0 (/ F B_m))) 0.5)) (* -1.0 (pow 2.0 0.5)))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double tmp;
	if (A <= -6e+199) {
		tmp = -1.0 * ((-1.0 * pow((A * F), 0.5)) * (-2.0 / B_m));
	} else {
		tmp = exp((log((-1.0 * (F / B_m))) * 0.5)) * (-1.0 * pow(2.0, 0.5));
	}
	return tmp;
}
B_m =     private
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
module fmin_fmax_functions
    implicit none
    private
    public fmax
    public fmin

    interface fmax
        module procedure fmax88
        module procedure fmax44
        module procedure fmax84
        module procedure fmax48
    end interface
    interface fmin
        module procedure fmin88
        module procedure fmin44
        module procedure fmin84
        module procedure fmin48
    end interface
contains
    real(8) function fmax88(x, y) result (res)
        real(8), intent (in) :: x
        real(8), intent (in) :: y
        res = merge(y, merge(x, max(x, y), y /= y), x /= x)
    end function
    real(4) function fmax44(x, y) result (res)
        real(4), intent (in) :: x
        real(4), intent (in) :: y
        res = merge(y, merge(x, max(x, y), y /= y), x /= x)
    end function
    real(8) function fmax84(x, y) result(res)
        real(8), intent (in) :: x
        real(4), intent (in) :: y
        res = merge(dble(y), merge(x, max(x, dble(y)), y /= y), x /= x)
    end function
    real(8) function fmax48(x, y) result(res)
        real(4), intent (in) :: x
        real(8), intent (in) :: y
        res = merge(y, merge(dble(x), max(dble(x), y), y /= y), x /= x)
    end function
    real(8) function fmin88(x, y) result (res)
        real(8), intent (in) :: x
        real(8), intent (in) :: y
        res = merge(y, merge(x, min(x, y), y /= y), x /= x)
    end function
    real(4) function fmin44(x, y) result (res)
        real(4), intent (in) :: x
        real(4), intent (in) :: y
        res = merge(y, merge(x, min(x, y), y /= y), x /= x)
    end function
    real(8) function fmin84(x, y) result(res)
        real(8), intent (in) :: x
        real(4), intent (in) :: y
        res = merge(dble(y), merge(x, min(x, dble(y)), y /= y), x /= x)
    end function
    real(8) function fmin48(x, y) result(res)
        real(4), intent (in) :: x
        real(8), intent (in) :: y
        res = merge(y, merge(dble(x), min(dble(x), y), y /= y), x /= x)
    end function
end module

real(8) function code(a, b_m, c, f)
use fmin_fmax_functions
    real(8), intent (in) :: a
    real(8), intent (in) :: b_m
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: tmp
    if (a <= (-6d+199)) then
        tmp = (-1.0d0) * (((-1.0d0) * ((a * f) ** 0.5d0)) * ((-2.0d0) / b_m))
    else
        tmp = exp((log(((-1.0d0) * (f / b_m))) * 0.5d0)) * ((-1.0d0) * (2.0d0 ** 0.5d0))
    end if
    code = tmp
end function
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	double tmp;
	if (A <= -6e+199) {
		tmp = -1.0 * ((-1.0 * Math.pow((A * F), 0.5)) * (-2.0 / B_m));
	} else {
		tmp = Math.exp((Math.log((-1.0 * (F / B_m))) * 0.5)) * (-1.0 * Math.pow(2.0, 0.5));
	}
	return tmp;
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	tmp = 0
	if A <= -6e+199:
		tmp = -1.0 * ((-1.0 * math.pow((A * F), 0.5)) * (-2.0 / B_m))
	else:
		tmp = math.exp((math.log((-1.0 * (F / B_m))) * 0.5)) * (-1.0 * math.pow(2.0, 0.5))
	return tmp
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	tmp = 0.0
	if (A <= -6e+199)
		tmp = Float64(-1.0 * Float64(Float64(-1.0 * (Float64(A * F) ^ 0.5)) * Float64(-2.0 / B_m)));
	else
		tmp = Float64(exp(Float64(log(Float64(-1.0 * Float64(F / B_m))) * 0.5)) * Float64(-1.0 * (2.0 ^ 0.5)));
	end
	return tmp
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp_2 = code(A, B_m, C, F)
	tmp = 0.0;
	if (A <= -6e+199)
		tmp = -1.0 * ((-1.0 * ((A * F) ^ 0.5)) * (-2.0 / B_m));
	else
		tmp = exp((log((-1.0 * (F / B_m))) * 0.5)) * (-1.0 * (2.0 ^ 0.5));
	end
	tmp_2 = tmp;
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := If[LessEqual[A, -6e+199], N[(-1.0 * N[(N[(-1.0 * N[Power[N[(A * F), $MachinePrecision], 0.5], $MachinePrecision]), $MachinePrecision] * N[(-2.0 / B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[Exp[N[(N[Log[N[(-1.0 * N[(F / B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * 0.5), $MachinePrecision]], $MachinePrecision] * N[(-1.0 * N[Power[2.0, 0.5], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
\mathbf{if}\;A \leq -6 \cdot 10^{+199}:\\
\;\;\;\;-1 \cdot \left(\left(-1 \cdot {\left(A \cdot F\right)}^{0.5}\right) \cdot \frac{-2}{B\_m}\right)\\

\mathbf{else}:\\
\;\;\;\;e^{\log \left(-1 \cdot \frac{F}{B\_m}\right) \cdot 0.5} \cdot \left(-1 \cdot {2}^{0.5}\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if A < -6.0000000000000002e199

    1. Initial program 1.9%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \color{blue}{\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
      2. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \color{blue}{\sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      3. lower-/.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      4. pow1/2N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot \sqrt{\color{blue}{F} \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      5. lower-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot \sqrt{\color{blue}{F} \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      6. pow1/2N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)}^{\color{blue}{\frac{1}{2}}}\right) \]
      7. lower-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)}^{\color{blue}{\frac{1}{2}}}\right) \]
    5. Applied rewrites1.7%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{{2}^{0.5}}{B} \cdot {\left(F \cdot \left(A - {\left(\mathsf{fma}\left(A, A, B \cdot B\right)\right)}^{0.5}\right)\right)}^{0.5}\right)} \]
    6. Taylor expanded in A around -inf

      \[\leadsto -1 \cdot \left(-1 \cdot \color{blue}{\left(\sqrt{A \cdot F} \cdot \frac{{\left(\sqrt{-1}\right)}^{2} \cdot {\left(\sqrt{2}\right)}^{2}}{B}\right)}\right) \]
    7. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(-1 \cdot \left(\sqrt{A \cdot F} \cdot \color{blue}{\frac{{\left(\sqrt{-1}\right)}^{2} \cdot {\left(\sqrt{2}\right)}^{2}}{B}}\right)\right) \]
      2. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(-1 \cdot \left(\sqrt{A \cdot F} \cdot \frac{{\left(\sqrt{-1}\right)}^{2} \cdot {\left(\sqrt{2}\right)}^{2}}{\color{blue}{B}}\right)\right) \]
      3. pow1/2N/A

        \[\leadsto -1 \cdot \left(-1 \cdot \left({\left(A \cdot F\right)}^{\frac{1}{2}} \cdot \frac{{\left(\sqrt{-1}\right)}^{2} \cdot {\left(\sqrt{2}\right)}^{2}}{B}\right)\right) \]
      4. lower-pow.f64N/A

        \[\leadsto -1 \cdot \left(-1 \cdot \left({\left(A \cdot F\right)}^{\frac{1}{2}} \cdot \frac{{\left(\sqrt{-1}\right)}^{2} \cdot {\left(\sqrt{2}\right)}^{2}}{B}\right)\right) \]
      5. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(-1 \cdot \left({\left(A \cdot F\right)}^{\frac{1}{2}} \cdot \frac{{\left(\sqrt{-1}\right)}^{2} \cdot {\left(\sqrt{2}\right)}^{2}}{B}\right)\right) \]
      6. pow-prod-downN/A

        \[\leadsto -1 \cdot \left(-1 \cdot \left({\left(A \cdot F\right)}^{\frac{1}{2}} \cdot \frac{{\left(\sqrt{-1} \cdot \sqrt{2}\right)}^{2}}{B}\right)\right) \]
      7. sqrt-unprodN/A

        \[\leadsto -1 \cdot \left(-1 \cdot \left({\left(A \cdot F\right)}^{\frac{1}{2}} \cdot \frac{{\left(\sqrt{-1 \cdot 2}\right)}^{2}}{B}\right)\right) \]
      8. metadata-evalN/A

        \[\leadsto -1 \cdot \left(-1 \cdot \left({\left(A \cdot F\right)}^{\frac{1}{2}} \cdot \frac{{\left(\sqrt{-2}\right)}^{2}}{B}\right)\right) \]
      9. sqrt-pow2N/A

        \[\leadsto -1 \cdot \left(-1 \cdot \left({\left(A \cdot F\right)}^{\frac{1}{2}} \cdot \frac{{-2}^{\left(\frac{2}{2}\right)}}{B}\right)\right) \]
      10. metadata-evalN/A

        \[\leadsto -1 \cdot \left(-1 \cdot \left({\left(A \cdot F\right)}^{\frac{1}{2}} \cdot \frac{{-2}^{1}}{B}\right)\right) \]
      11. metadata-evalN/A

        \[\leadsto -1 \cdot \left(-1 \cdot \left({\left(A \cdot F\right)}^{\frac{1}{2}} \cdot \frac{-2}{B}\right)\right) \]
      12. lower-/.f647.9

        \[\leadsto -1 \cdot \left(-1 \cdot \left({\left(A \cdot F\right)}^{0.5} \cdot \frac{-2}{B}\right)\right) \]
    8. Applied rewrites7.9%

      \[\leadsto -1 \cdot \left(-1 \cdot \color{blue}{\left({\left(A \cdot F\right)}^{0.5} \cdot \frac{-2}{B}\right)}\right) \]

    if -6.0000000000000002e199 < A

    1. Initial program 18.4%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    4. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \color{blue}{\left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
      2. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \color{blue}{\sqrt{2}}\right) \]
    5. Applied rewrites17.8%

      \[\leadsto \color{blue}{-1 \cdot \left({\left(\frac{F \cdot \left(\left(A + C\right) - {\left(\mathsf{fma}\left(B, B, {\left(A - C\right)}^{2}\right)\right)}^{0.5}\right)}{B \cdot B - 4 \cdot \left(A \cdot C\right)}\right)}^{0.5} \cdot {2}^{0.5}\right)} \]
    6. Taylor expanded in B around inf

      \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{\frac{1}{2}} \cdot {2}^{\frac{1}{2}}\right) \]
    7. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{\frac{1}{2}} \cdot {2}^{\frac{1}{2}}\right) \]
      2. lower-/.f6410.7

        \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{0.5} \cdot {2}^{0.5}\right) \]
    8. Applied rewrites10.7%

      \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{0.5} \cdot {2}^{0.5}\right) \]
    9. Step-by-step derivation
      1. lift-pow.f64N/A

        \[\leadsto -1 \cdot \left({\left(-1 \cdot \frac{F}{B}\right)}^{\frac{1}{2}} \cdot {\color{blue}{2}}^{\frac{1}{2}}\right) \]
      2. pow-to-expN/A

        \[\leadsto -1 \cdot \left(e^{\log \left(-1 \cdot \frac{F}{B}\right) \cdot \frac{1}{2}} \cdot {\color{blue}{2}}^{\frac{1}{2}}\right) \]
      3. lower-exp.f64N/A

        \[\leadsto -1 \cdot \left(e^{\log \left(-1 \cdot \frac{F}{B}\right) \cdot \frac{1}{2}} \cdot {\color{blue}{2}}^{\frac{1}{2}}\right) \]
      4. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(e^{\log \left(-1 \cdot \frac{F}{B}\right) \cdot \frac{1}{2}} \cdot {2}^{\frac{1}{2}}\right) \]
      5. lower-log.f6410.0

        \[\leadsto -1 \cdot \left(e^{\log \left(-1 \cdot \frac{F}{B}\right) \cdot 0.5} \cdot {2}^{0.5}\right) \]
    10. Applied rewrites10.0%

      \[\leadsto -1 \cdot \left(e^{\log \left(-1 \cdot \frac{F}{B}\right) \cdot 0.5} \cdot {\color{blue}{2}}^{0.5}\right) \]
  3. Recombined 2 regimes into one program.
  4. Final simplification9.8%

    \[\leadsto \begin{array}{l} \mathbf{if}\;A \leq -6 \cdot 10^{+199}:\\ \;\;\;\;-1 \cdot \left(\left(-1 \cdot {\left(A \cdot F\right)}^{0.5}\right) \cdot \frac{-2}{B}\right)\\ \mathbf{else}:\\ \;\;\;\;e^{\log \left(-1 \cdot \frac{F}{B}\right) \cdot 0.5} \cdot \left(-1 \cdot {2}^{0.5}\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 10: 10.5% accurate, N/A× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(B\_m, B\_m, C \cdot C\right)\\ t_1 := F \cdot \left(C - {t\_0}^{0.5}\right)\\ \mathbf{if}\;C \leq 9.5 \cdot 10^{-185}:\\ \;\;\;\;-1 \cdot \left(\left(-1 \cdot {\left(A \cdot F\right)}^{0.5}\right) \cdot \frac{-2}{B\_m}\right)\\ \mathbf{else}:\\ \;\;\;\;A \cdot \mathsf{fma}\left(-1, \frac{{2}^{0.5}}{A \cdot B\_m} \cdot {t\_1}^{0.5}, -0.5 \cdot \left(\left(B\_m \cdot \left({2}^{0.5} \cdot \left(\frac{F \cdot \left(1 - -1 \cdot \left(C \cdot {\left({t\_0}^{-1}\right)}^{0.5}\right)\right)}{B\_m \cdot B\_m} - -4 \cdot \frac{C \cdot t\_1}{{B\_m}^{4}}\right)\right)\right) \cdot {\left({t\_1}^{-1}\right)}^{0.5}\right)\right)\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (let* ((t_0 (fma B_m B_m (* C C))) (t_1 (* F (- C (pow t_0 0.5)))))
   (if (<= C 9.5e-185)
     (* -1.0 (* (* -1.0 (pow (* A F) 0.5)) (/ -2.0 B_m)))
     (*
      A
      (fma
       -1.0
       (* (/ (pow 2.0 0.5) (* A B_m)) (pow t_1 0.5))
       (*
        -0.5
        (*
         (*
          B_m
          (*
           (pow 2.0 0.5)
           (-
            (/
             (* F (- 1.0 (* -1.0 (* C (pow (pow t_0 -1.0) 0.5)))))
             (* B_m B_m))
            (* -4.0 (/ (* C t_1) (pow B_m 4.0))))))
         (pow (pow t_1 -1.0) 0.5))))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double t_0 = fma(B_m, B_m, (C * C));
	double t_1 = F * (C - pow(t_0, 0.5));
	double tmp;
	if (C <= 9.5e-185) {
		tmp = -1.0 * ((-1.0 * pow((A * F), 0.5)) * (-2.0 / B_m));
	} else {
		tmp = A * fma(-1.0, ((pow(2.0, 0.5) / (A * B_m)) * pow(t_1, 0.5)), (-0.5 * ((B_m * (pow(2.0, 0.5) * (((F * (1.0 - (-1.0 * (C * pow(pow(t_0, -1.0), 0.5))))) / (B_m * B_m)) - (-4.0 * ((C * t_1) / pow(B_m, 4.0)))))) * pow(pow(t_1, -1.0), 0.5))));
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	t_0 = fma(B_m, B_m, Float64(C * C))
	t_1 = Float64(F * Float64(C - (t_0 ^ 0.5)))
	tmp = 0.0
	if (C <= 9.5e-185)
		tmp = Float64(-1.0 * Float64(Float64(-1.0 * (Float64(A * F) ^ 0.5)) * Float64(-2.0 / B_m)));
	else
		tmp = Float64(A * fma(-1.0, Float64(Float64((2.0 ^ 0.5) / Float64(A * B_m)) * (t_1 ^ 0.5)), Float64(-0.5 * Float64(Float64(B_m * Float64((2.0 ^ 0.5) * Float64(Float64(Float64(F * Float64(1.0 - Float64(-1.0 * Float64(C * ((t_0 ^ -1.0) ^ 0.5))))) / Float64(B_m * B_m)) - Float64(-4.0 * Float64(Float64(C * t_1) / (B_m ^ 4.0)))))) * ((t_1 ^ -1.0) ^ 0.5)))));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(B$95$m * B$95$m + N[(C * C), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(F * N[(C - N[Power[t$95$0, 0.5], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[C, 9.5e-185], N[(-1.0 * N[(N[(-1.0 * N[Power[N[(A * F), $MachinePrecision], 0.5], $MachinePrecision]), $MachinePrecision] * N[(-2.0 / B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(A * N[(-1.0 * N[(N[(N[Power[2.0, 0.5], $MachinePrecision] / N[(A * B$95$m), $MachinePrecision]), $MachinePrecision] * N[Power[t$95$1, 0.5], $MachinePrecision]), $MachinePrecision] + N[(-0.5 * N[(N[(B$95$m * N[(N[Power[2.0, 0.5], $MachinePrecision] * N[(N[(N[(F * N[(1.0 - N[(-1.0 * N[(C * N[Power[N[Power[t$95$0, -1.0], $MachinePrecision], 0.5], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision] - N[(-4.0 * N[(N[(C * t$95$1), $MachinePrecision] / N[Power[B$95$m, 4.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[Power[N[Power[t$95$1, -1.0], $MachinePrecision], 0.5], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
t_0 := \mathsf{fma}\left(B\_m, B\_m, C \cdot C\right)\\
t_1 := F \cdot \left(C - {t\_0}^{0.5}\right)\\
\mathbf{if}\;C \leq 9.5 \cdot 10^{-185}:\\
\;\;\;\;-1 \cdot \left(\left(-1 \cdot {\left(A \cdot F\right)}^{0.5}\right) \cdot \frac{-2}{B\_m}\right)\\

\mathbf{else}:\\
\;\;\;\;A \cdot \mathsf{fma}\left(-1, \frac{{2}^{0.5}}{A \cdot B\_m} \cdot {t\_1}^{0.5}, -0.5 \cdot \left(\left(B\_m \cdot \left({2}^{0.5} \cdot \left(\frac{F \cdot \left(1 - -1 \cdot \left(C \cdot {\left({t\_0}^{-1}\right)}^{0.5}\right)\right)}{B\_m \cdot B\_m} - -4 \cdot \frac{C \cdot t\_1}{{B\_m}^{4}}\right)\right)\right) \cdot {\left({t\_1}^{-1}\right)}^{0.5}\right)\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if C < 9.50000000000000042e-185

    1. Initial program 19.5%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \color{blue}{\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
      2. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \color{blue}{\sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      3. lower-/.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      4. pow1/2N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot \sqrt{\color{blue}{F} \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      5. lower-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot \sqrt{\color{blue}{F} \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      6. pow1/2N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)}^{\color{blue}{\frac{1}{2}}}\right) \]
      7. lower-pow.f64N/A

        \[\leadsto -1 \cdot \left(\frac{{2}^{\frac{1}{2}}}{B} \cdot {\left(F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)\right)}^{\color{blue}{\frac{1}{2}}}\right) \]
    5. Applied rewrites5.9%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{{2}^{0.5}}{B} \cdot {\left(F \cdot \left(A - {\left(\mathsf{fma}\left(A, A, B \cdot B\right)\right)}^{0.5}\right)\right)}^{0.5}\right)} \]
    6. Taylor expanded in A around -inf

      \[\leadsto -1 \cdot \left(-1 \cdot \color{blue}{\left(\sqrt{A \cdot F} \cdot \frac{{\left(\sqrt{-1}\right)}^{2} \cdot {\left(\sqrt{2}\right)}^{2}}{B}\right)}\right) \]
    7. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(-1 \cdot \left(\sqrt{A \cdot F} \cdot \color{blue}{\frac{{\left(\sqrt{-1}\right)}^{2} \cdot {\left(\sqrt{2}\right)}^{2}}{B}}\right)\right) \]
      2. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(-1 \cdot \left(\sqrt{A \cdot F} \cdot \frac{{\left(\sqrt{-1}\right)}^{2} \cdot {\left(\sqrt{2}\right)}^{2}}{\color{blue}{B}}\right)\right) \]
      3. pow1/2N/A

        \[\leadsto -1 \cdot \left(-1 \cdot \left({\left(A \cdot F\right)}^{\frac{1}{2}} \cdot \frac{{\left(\sqrt{-1}\right)}^{2} \cdot {\left(\sqrt{2}\right)}^{2}}{B}\right)\right) \]
      4. lower-pow.f64N/A

        \[\leadsto -1 \cdot \left(-1 \cdot \left({\left(A \cdot F\right)}^{\frac{1}{2}} \cdot \frac{{\left(\sqrt{-1}\right)}^{2} \cdot {\left(\sqrt{2}\right)}^{2}}{B}\right)\right) \]
      5. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(-1 \cdot \left({\left(A \cdot F\right)}^{\frac{1}{2}} \cdot \frac{{\left(\sqrt{-1}\right)}^{2} \cdot {\left(\sqrt{2}\right)}^{2}}{B}\right)\right) \]
      6. pow-prod-downN/A

        \[\leadsto -1 \cdot \left(-1 \cdot \left({\left(A \cdot F\right)}^{\frac{1}{2}} \cdot \frac{{\left(\sqrt{-1} \cdot \sqrt{2}\right)}^{2}}{B}\right)\right) \]
      7. sqrt-unprodN/A

        \[\leadsto -1 \cdot \left(-1 \cdot \left({\left(A \cdot F\right)}^{\frac{1}{2}} \cdot \frac{{\left(\sqrt{-1 \cdot 2}\right)}^{2}}{B}\right)\right) \]
      8. metadata-evalN/A

        \[\leadsto -1 \cdot \left(-1 \cdot \left({\left(A \cdot F\right)}^{\frac{1}{2}} \cdot \frac{{\left(\sqrt{-2}\right)}^{2}}{B}\right)\right) \]
      9. sqrt-pow2N/A

        \[\leadsto -1 \cdot \left(-1 \cdot \left({\left(A \cdot F\right)}^{\frac{1}{2}} \cdot \frac{{-2}^{\left(\frac{2}{2}\right)}}{B}\right)\right) \]
      10. metadata-evalN/A

        \[\leadsto -1 \cdot \left(-1 \cdot \left({\left(A \cdot F\right)}^{\frac{1}{2}} \cdot \frac{{-2}^{1}}{B}\right)\right) \]
      11. metadata-evalN/A

        \[\leadsto -1 \cdot \left(-1 \cdot \left({\left(A \cdot F\right)}^{\frac{1}{2}} \cdot \frac{-2}{B}\right)\right) \]
      12. lower-/.f644.8

        \[\leadsto -1 \cdot \left(-1 \cdot \left({\left(A \cdot F\right)}^{0.5} \cdot \frac{-2}{B}\right)\right) \]
    8. Applied rewrites4.8%

      \[\leadsto -1 \cdot \left(-1 \cdot \color{blue}{\left({\left(A \cdot F\right)}^{0.5} \cdot \frac{-2}{B}\right)}\right) \]

    if 9.50000000000000042e-185 < C

    1. Initial program 12.0%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in A around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)}\right) + \frac{-1}{2} \cdot \left(\left(A \cdot \left(B \cdot \left(\sqrt{2} \cdot \left(\frac{F \cdot \left(1 - -1 \cdot \left(C \cdot \sqrt{\frac{1}{{B}^{2} + {C}^{2}}}\right)\right)}{{B}^{2}} - -4 \cdot \frac{C \cdot \left(F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)\right)}{{B}^{4}}\right)\right)\right)\right) \cdot \sqrt{\frac{1}{F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)}}\right)} \]
    4. Applied rewrites4.5%

      \[\leadsto \color{blue}{\mathsf{fma}\left(-1, \frac{{2}^{0.5}}{B} \cdot {\left(F \cdot \left(C - {\left(\mathsf{fma}\left(B, B, C \cdot C\right)\right)}^{0.5}\right)\right)}^{0.5}, -0.5 \cdot \left(\left(A \cdot \left(B \cdot \left({2}^{0.5} \cdot \left(\frac{F \cdot \left(1 - -1 \cdot \left(C \cdot {\left({\left(\mathsf{fma}\left(B, B, C \cdot C\right)\right)}^{-1}\right)}^{0.5}\right)\right)}{B \cdot B} - -4 \cdot \frac{C \cdot \left(F \cdot \left(C - {\left(\mathsf{fma}\left(B, B, C \cdot C\right)\right)}^{0.5}\right)\right)}{{B}^{4}}\right)\right)\right)\right) \cdot {\left({\left(F \cdot \left(C - {\left(\mathsf{fma}\left(B, B, C \cdot C\right)\right)}^{0.5}\right)\right)}^{-1}\right)}^{0.5}\right)\right)} \]
    5. Taylor expanded in A around inf

      \[\leadsto A \cdot \color{blue}{\left(-1 \cdot \left(\frac{\sqrt{2}}{A \cdot B} \cdot \sqrt{F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)}\right) + \frac{-1}{2} \cdot \left(\left(B \cdot \left(\sqrt{2} \cdot \left(\frac{F \cdot \left(1 - -1 \cdot \left(C \cdot \sqrt{\frac{1}{{B}^{2} + {C}^{2}}}\right)\right)}{{B}^{2}} - -4 \cdot \frac{C \cdot \left(F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)\right)}{{B}^{4}}\right)\right)\right) \cdot \sqrt{\frac{1}{F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)}}\right)\right)} \]
    6. Applied rewrites4.4%

      \[\leadsto A \cdot \color{blue}{\mathsf{fma}\left(-1, \frac{{2}^{0.5}}{A \cdot B} \cdot {\left(F \cdot \left(C - {\left(\mathsf{fma}\left(B, B, C \cdot C\right)\right)}^{0.5}\right)\right)}^{0.5}, -0.5 \cdot \left(\left(B \cdot \left({2}^{0.5} \cdot \left(\frac{F \cdot \left(1 - -1 \cdot \left(C \cdot {\left({\left(\mathsf{fma}\left(B, B, C \cdot C\right)\right)}^{-1}\right)}^{0.5}\right)\right)}{B \cdot B} - -4 \cdot \frac{C \cdot \left(F \cdot \left(C - {\left(\mathsf{fma}\left(B, B, C \cdot C\right)\right)}^{0.5}\right)\right)}{{B}^{4}}\right)\right)\right) \cdot {\left({\left(F \cdot \left(C - {\left(\mathsf{fma}\left(B, B, C \cdot C\right)\right)}^{0.5}\right)\right)}^{-1}\right)}^{0.5}\right)\right)} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification4.7%

    \[\leadsto \begin{array}{l} \mathbf{if}\;C \leq 9.5 \cdot 10^{-185}:\\ \;\;\;\;-1 \cdot \left(\left(-1 \cdot {\left(A \cdot F\right)}^{0.5}\right) \cdot \frac{-2}{B}\right)\\ \mathbf{else}:\\ \;\;\;\;A \cdot \mathsf{fma}\left(-1, \frac{{2}^{0.5}}{A \cdot B} \cdot {\left(F \cdot \left(C - {\left(\mathsf{fma}\left(B, B, C \cdot C\right)\right)}^{0.5}\right)\right)}^{0.5}, -0.5 \cdot \left(\left(B \cdot \left({2}^{0.5} \cdot \left(\frac{F \cdot \left(1 - -1 \cdot \left(C \cdot {\left({\left(\mathsf{fma}\left(B, B, C \cdot C\right)\right)}^{-1}\right)}^{0.5}\right)\right)}{B \cdot B} - -4 \cdot \frac{C \cdot \left(F \cdot \left(C - {\left(\mathsf{fma}\left(B, B, C \cdot C\right)\right)}^{0.5}\right)\right)}{{B}^{4}}\right)\right)\right) \cdot {\left({\left(F \cdot \left(C - {\left(\mathsf{fma}\left(B, B, C \cdot C\right)\right)}^{0.5}\right)\right)}^{-1}\right)}^{0.5}\right)\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 11: 9.8% accurate, N/A× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(B\_m, B\_m, C \cdot C\right)\\ t_1 := F \cdot \left(C - {t\_0}^{0.5}\right)\\ A \cdot \mathsf{fma}\left(-1, \frac{{2}^{0.5}}{A \cdot B\_m} \cdot {t\_1}^{0.5}, -0.5 \cdot \left(\left(B\_m \cdot \left({2}^{0.5} \cdot \left(\frac{F \cdot \left(1 - -1 \cdot \left(C \cdot {\left({t\_0}^{-1}\right)}^{0.5}\right)\right)}{B\_m \cdot B\_m} - -4 \cdot \frac{C \cdot t\_1}{{B\_m}^{4}}\right)\right)\right) \cdot {\left({t\_1}^{-1}\right)}^{0.5}\right)\right) \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (let* ((t_0 (fma B_m B_m (* C C))) (t_1 (* F (- C (pow t_0 0.5)))))
   (*
    A
    (fma
     -1.0
     (* (/ (pow 2.0 0.5) (* A B_m)) (pow t_1 0.5))
     (*
      -0.5
      (*
       (*
        B_m
        (*
         (pow 2.0 0.5)
         (-
          (/ (* F (- 1.0 (* -1.0 (* C (pow (pow t_0 -1.0) 0.5))))) (* B_m B_m))
          (* -4.0 (/ (* C t_1) (pow B_m 4.0))))))
       (pow (pow t_1 -1.0) 0.5)))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double t_0 = fma(B_m, B_m, (C * C));
	double t_1 = F * (C - pow(t_0, 0.5));
	return A * fma(-1.0, ((pow(2.0, 0.5) / (A * B_m)) * pow(t_1, 0.5)), (-0.5 * ((B_m * (pow(2.0, 0.5) * (((F * (1.0 - (-1.0 * (C * pow(pow(t_0, -1.0), 0.5))))) / (B_m * B_m)) - (-4.0 * ((C * t_1) / pow(B_m, 4.0)))))) * pow(pow(t_1, -1.0), 0.5))));
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	t_0 = fma(B_m, B_m, Float64(C * C))
	t_1 = Float64(F * Float64(C - (t_0 ^ 0.5)))
	return Float64(A * fma(-1.0, Float64(Float64((2.0 ^ 0.5) / Float64(A * B_m)) * (t_1 ^ 0.5)), Float64(-0.5 * Float64(Float64(B_m * Float64((2.0 ^ 0.5) * Float64(Float64(Float64(F * Float64(1.0 - Float64(-1.0 * Float64(C * ((t_0 ^ -1.0) ^ 0.5))))) / Float64(B_m * B_m)) - Float64(-4.0 * Float64(Float64(C * t_1) / (B_m ^ 4.0)))))) * ((t_1 ^ -1.0) ^ 0.5)))))
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(B$95$m * B$95$m + N[(C * C), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(F * N[(C - N[Power[t$95$0, 0.5], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, N[(A * N[(-1.0 * N[(N[(N[Power[2.0, 0.5], $MachinePrecision] / N[(A * B$95$m), $MachinePrecision]), $MachinePrecision] * N[Power[t$95$1, 0.5], $MachinePrecision]), $MachinePrecision] + N[(-0.5 * N[(N[(B$95$m * N[(N[Power[2.0, 0.5], $MachinePrecision] * N[(N[(N[(F * N[(1.0 - N[(-1.0 * N[(C * N[Power[N[Power[t$95$0, -1.0], $MachinePrecision], 0.5], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision] - N[(-4.0 * N[(N[(C * t$95$1), $MachinePrecision] / N[Power[B$95$m, 4.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[Power[N[Power[t$95$1, -1.0], $MachinePrecision], 0.5], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
t_0 := \mathsf{fma}\left(B\_m, B\_m, C \cdot C\right)\\
t_1 := F \cdot \left(C - {t\_0}^{0.5}\right)\\
A \cdot \mathsf{fma}\left(-1, \frac{{2}^{0.5}}{A \cdot B\_m} \cdot {t\_1}^{0.5}, -0.5 \cdot \left(\left(B\_m \cdot \left({2}^{0.5} \cdot \left(\frac{F \cdot \left(1 - -1 \cdot \left(C \cdot {\left({t\_0}^{-1}\right)}^{0.5}\right)\right)}{B\_m \cdot B\_m} - -4 \cdot \frac{C \cdot t\_1}{{B\_m}^{4}}\right)\right)\right) \cdot {\left({t\_1}^{-1}\right)}^{0.5}\right)\right)
\end{array}
\end{array}
Derivation
  1. Initial program 16.5%

    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
  2. Add Preprocessing
  3. Taylor expanded in A around 0

    \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)}\right) + \frac{-1}{2} \cdot \left(\left(A \cdot \left(B \cdot \left(\sqrt{2} \cdot \left(\frac{F \cdot \left(1 - -1 \cdot \left(C \cdot \sqrt{\frac{1}{{B}^{2} + {C}^{2}}}\right)\right)}{{B}^{2}} - -4 \cdot \frac{C \cdot \left(F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)\right)}{{B}^{4}}\right)\right)\right)\right) \cdot \sqrt{\frac{1}{F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)}}\right)} \]
  4. Applied rewrites3.2%

    \[\leadsto \color{blue}{\mathsf{fma}\left(-1, \frac{{2}^{0.5}}{B} \cdot {\left(F \cdot \left(C - {\left(\mathsf{fma}\left(B, B, C \cdot C\right)\right)}^{0.5}\right)\right)}^{0.5}, -0.5 \cdot \left(\left(A \cdot \left(B \cdot \left({2}^{0.5} \cdot \left(\frac{F \cdot \left(1 - -1 \cdot \left(C \cdot {\left({\left(\mathsf{fma}\left(B, B, C \cdot C\right)\right)}^{-1}\right)}^{0.5}\right)\right)}{B \cdot B} - -4 \cdot \frac{C \cdot \left(F \cdot \left(C - {\left(\mathsf{fma}\left(B, B, C \cdot C\right)\right)}^{0.5}\right)\right)}{{B}^{4}}\right)\right)\right)\right) \cdot {\left({\left(F \cdot \left(C - {\left(\mathsf{fma}\left(B, B, C \cdot C\right)\right)}^{0.5}\right)\right)}^{-1}\right)}^{0.5}\right)\right)} \]
  5. Taylor expanded in A around inf

    \[\leadsto A \cdot \color{blue}{\left(-1 \cdot \left(\frac{\sqrt{2}}{A \cdot B} \cdot \sqrt{F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)}\right) + \frac{-1}{2} \cdot \left(\left(B \cdot \left(\sqrt{2} \cdot \left(\frac{F \cdot \left(1 - -1 \cdot \left(C \cdot \sqrt{\frac{1}{{B}^{2} + {C}^{2}}}\right)\right)}{{B}^{2}} - -4 \cdot \frac{C \cdot \left(F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)\right)}{{B}^{4}}\right)\right)\right) \cdot \sqrt{\frac{1}{F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)}}\right)\right)} \]
  6. Applied rewrites3.2%

    \[\leadsto A \cdot \color{blue}{\mathsf{fma}\left(-1, \frac{{2}^{0.5}}{A \cdot B} \cdot {\left(F \cdot \left(C - {\left(\mathsf{fma}\left(B, B, C \cdot C\right)\right)}^{0.5}\right)\right)}^{0.5}, -0.5 \cdot \left(\left(B \cdot \left({2}^{0.5} \cdot \left(\frac{F \cdot \left(1 - -1 \cdot \left(C \cdot {\left({\left(\mathsf{fma}\left(B, B, C \cdot C\right)\right)}^{-1}\right)}^{0.5}\right)\right)}{B \cdot B} - -4 \cdot \frac{C \cdot \left(F \cdot \left(C - {\left(\mathsf{fma}\left(B, B, C \cdot C\right)\right)}^{0.5}\right)\right)}{{B}^{4}}\right)\right)\right) \cdot {\left({\left(F \cdot \left(C - {\left(\mathsf{fma}\left(B, B, C \cdot C\right)\right)}^{0.5}\right)\right)}^{-1}\right)}^{0.5}\right)\right)} \]
  7. Add Preprocessing

Reproduce

?
herbie shell --seed 2025065 
(FPCore (A B C F)
  :name "ABCF->ab-angle b"
  :precision binary64
  (/ (- (sqrt (* (* 2.0 (* (- (pow B 2.0) (* (* 4.0 A) C)) F)) (- (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))) (- (pow B 2.0) (* (* 4.0 A) C))))