ABCF->ab-angle angle

Percentage Accurate: 53.6% → 89.2%
Time: 7.3s
Alternatives: 15
Speedup: 2.3×

Specification

?
\[\begin{array}{l} \\ 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (*
  180.0
  (/
   (atan (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
   PI)))
double code(double A, double B, double C) {
	return 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / ((double) M_PI));
}
public static double code(double A, double B, double C) {
	return 180.0 * (Math.atan(((1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / Math.PI);
}
def code(A, B, C):
	return 180.0 * (math.atan(((1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / math.pi)
function code(A, B, C)
	return Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))) / pi))
end
function tmp = code(A, B, C)
	tmp = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / pi);
end
code[A_, B_, C_] := N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 15 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 53.6% accurate, 1.0× speedup?

\[\begin{array}{l} \\ 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (*
  180.0
  (/
   (atan (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
   PI)))
double code(double A, double B, double C) {
	return 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / ((double) M_PI));
}
public static double code(double A, double B, double C) {
	return 180.0 * (Math.atan(((1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / Math.PI);
}
def code(A, B, C):
	return 180.0 * (math.atan(((1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / math.pi)
function code(A, B, C)
	return Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))) / pi))
end
function tmp = code(A, B, C)
	tmp = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / pi);
end
code[A_, B_, C_] := N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}
\end{array}

Alternative 1: 89.2% accurate, 0.4× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}\\ t_1 := \left(-A\right) + C\\ t_2 := 180 \cdot \frac{\tan^{-1} \left(\frac{t\_1 - \mathsf{hypot}\left(t\_1, B\right)}{B}\right)}{\pi}\\ \mathbf{if}\;t\_0 \leq -5 \cdot 10^{-75}:\\ \;\;\;\;t\_2\\ \mathbf{elif}\;t\_0 \leq 0:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;t\_2\\ \end{array} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (let* ((t_0
         (*
          180.0
          (/
           (atan
            (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
           PI)))
        (t_1 (+ (- A) C))
        (t_2 (* 180.0 (/ (atan (/ (- t_1 (hypot t_1 B)) B)) PI))))
   (if (<= t_0 -5e-75)
     t_2
     (if (<= t_0 0.0) (* 180.0 (/ (atan (* (/ B (- C A)) -0.5)) PI)) t_2))))
double code(double A, double B, double C) {
	double t_0 = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / ((double) M_PI));
	double t_1 = -A + C;
	double t_2 = 180.0 * (atan(((t_1 - hypot(t_1, B)) / B)) / ((double) M_PI));
	double tmp;
	if (t_0 <= -5e-75) {
		tmp = t_2;
	} else if (t_0 <= 0.0) {
		tmp = 180.0 * (atan(((B / (C - A)) * -0.5)) / ((double) M_PI));
	} else {
		tmp = t_2;
	}
	return tmp;
}
public static double code(double A, double B, double C) {
	double t_0 = 180.0 * (Math.atan(((1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / Math.PI);
	double t_1 = -A + C;
	double t_2 = 180.0 * (Math.atan(((t_1 - Math.hypot(t_1, B)) / B)) / Math.PI);
	double tmp;
	if (t_0 <= -5e-75) {
		tmp = t_2;
	} else if (t_0 <= 0.0) {
		tmp = 180.0 * (Math.atan(((B / (C - A)) * -0.5)) / Math.PI);
	} else {
		tmp = t_2;
	}
	return tmp;
}
def code(A, B, C):
	t_0 = 180.0 * (math.atan(((1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / math.pi)
	t_1 = -A + C
	t_2 = 180.0 * (math.atan(((t_1 - math.hypot(t_1, B)) / B)) / math.pi)
	tmp = 0
	if t_0 <= -5e-75:
		tmp = t_2
	elif t_0 <= 0.0:
		tmp = 180.0 * (math.atan(((B / (C - A)) * -0.5)) / math.pi)
	else:
		tmp = t_2
	return tmp
function code(A, B, C)
	t_0 = Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))) / pi))
	t_1 = Float64(Float64(-A) + C)
	t_2 = Float64(180.0 * Float64(atan(Float64(Float64(t_1 - hypot(t_1, B)) / B)) / pi))
	tmp = 0.0
	if (t_0 <= -5e-75)
		tmp = t_2;
	elseif (t_0 <= 0.0)
		tmp = Float64(180.0 * Float64(atan(Float64(Float64(B / Float64(C - A)) * -0.5)) / pi));
	else
		tmp = t_2;
	end
	return tmp
end
function tmp_2 = code(A, B, C)
	t_0 = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / pi);
	t_1 = -A + C;
	t_2 = 180.0 * (atan(((t_1 - hypot(t_1, B)) / B)) / pi);
	tmp = 0.0;
	if (t_0 <= -5e-75)
		tmp = t_2;
	elseif (t_0 <= 0.0)
		tmp = 180.0 * (atan(((B / (C - A)) * -0.5)) / pi);
	else
		tmp = t_2;
	end
	tmp_2 = tmp;
end
code[A_, B_, C_] := Block[{t$95$0 = N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[((-A) + C), $MachinePrecision]}, Block[{t$95$2 = N[(180.0 * N[(N[ArcTan[N[(N[(t$95$1 - N[Sqrt[t$95$1 ^ 2 + B ^ 2], $MachinePrecision]), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, -5e-75], t$95$2, If[LessEqual[t$95$0, 0.0], N[(180.0 * N[(N[ArcTan[N[(N[(B / N[(C - A), $MachinePrecision]), $MachinePrecision] * -0.5), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], t$95$2]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}\\
t_1 := \left(-A\right) + C\\
t_2 := 180 \cdot \frac{\tan^{-1} \left(\frac{t\_1 - \mathsf{hypot}\left(t\_1, B\right)}{B}\right)}{\pi}\\
\mathbf{if}\;t\_0 \leq -5 \cdot 10^{-75}:\\
\;\;\;\;t\_2\\

\mathbf{elif}\;t\_0 \leq 0:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi}\\

\mathbf{else}:\\
\;\;\;\;t\_2\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (*.f64 #s(literal 180 binary64) (/.f64 (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))) (PI.f64))) < -4.99999999999999979e-75 or 0.0 < (*.f64 #s(literal 180 binary64) (/.f64 (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))) (PI.f64)))

    1. Initial program 58.2%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in A around -inf

      \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}}{\pi} \]
    4. Step-by-step derivation
      1. lower-atan.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
      2. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
    5. Applied rewrites86.9%

      \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]

    if -4.99999999999999979e-75 < (*.f64 #s(literal 180 binary64) (/.f64 (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))) (PI.f64))) < 0.0

    1. Initial program 16.8%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in A around -inf

      \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}}{\pi} \]
    4. Step-by-step derivation
      1. lower-atan.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
      2. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
    5. Applied rewrites16.8%

      \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
    6. Taylor expanded in B around 0

      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}{\pi} \]
    7. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
      2. lower-*.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
      3. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
      4. lift--.f6499.5

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi} \]
    8. Applied rewrites99.5%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi} \]
  3. Recombined 2 regimes into one program.
  4. Add Preprocessing

Alternative 2: 80.1% accurate, 1.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;A \leq -4.6 \cdot 10^{-15}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi}\\ \end{array} \end{array} \]
(FPCore (A B C)
 :precision binary64
 (if (<= A -4.6e-15)
   (* 180.0 (/ (atan (* (/ B (- C A)) -0.5)) PI))
   (* 180.0 (/ (atan (/ (- (- C A) (hypot C B)) B)) PI))))
double code(double A, double B, double C) {
	double tmp;
	if (A <= -4.6e-15) {
		tmp = 180.0 * (atan(((B / (C - A)) * -0.5)) / ((double) M_PI));
	} else {
		tmp = 180.0 * (atan((((C - A) - hypot(C, B)) / B)) / ((double) M_PI));
	}
	return tmp;
}
public static double code(double A, double B, double C) {
	double tmp;
	if (A <= -4.6e-15) {
		tmp = 180.0 * (Math.atan(((B / (C - A)) * -0.5)) / Math.PI);
	} else {
		tmp = 180.0 * (Math.atan((((C - A) - Math.hypot(C, B)) / B)) / Math.PI);
	}
	return tmp;
}
def code(A, B, C):
	tmp = 0
	if A <= -4.6e-15:
		tmp = 180.0 * (math.atan(((B / (C - A)) * -0.5)) / math.pi)
	else:
		tmp = 180.0 * (math.atan((((C - A) - math.hypot(C, B)) / B)) / math.pi)
	return tmp
function code(A, B, C)
	tmp = 0.0
	if (A <= -4.6e-15)
		tmp = Float64(180.0 * Float64(atan(Float64(Float64(B / Float64(C - A)) * -0.5)) / pi));
	else
		tmp = Float64(180.0 * Float64(atan(Float64(Float64(Float64(C - A) - hypot(C, B)) / B)) / pi));
	end
	return tmp
end
function tmp_2 = code(A, B, C)
	tmp = 0.0;
	if (A <= -4.6e-15)
		tmp = 180.0 * (atan(((B / (C - A)) * -0.5)) / pi);
	else
		tmp = 180.0 * (atan((((C - A) - hypot(C, B)) / B)) / pi);
	end
	tmp_2 = tmp;
end
code[A_, B_, C_] := If[LessEqual[A, -4.6e-15], N[(180.0 * N[(N[ArcTan[N[(N[(B / N[(C - A), $MachinePrecision]), $MachinePrecision] * -0.5), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(N[(N[(C - A), $MachinePrecision] - N[Sqrt[C ^ 2 + B ^ 2], $MachinePrecision]), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;A \leq -4.6 \cdot 10^{-15}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi}\\

\mathbf{else}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if A < -4.59999999999999981e-15

    1. Initial program 16.1%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in A around -inf

      \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}}{\pi} \]
    4. Step-by-step derivation
      1. lower-atan.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
      2. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
    5. Applied rewrites46.4%

      \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
    6. Taylor expanded in B around 0

      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}{\pi} \]
    7. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
      2. lower-*.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
      3. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
      4. lift--.f6478.9

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi} \]
    8. Applied rewrites78.9%

      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi} \]

    if -4.59999999999999981e-15 < A

    1. Initial program 65.4%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
    2. Add Preprocessing
    3. Taylor expanded in A around -inf

      \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}}{\pi} \]
    4. Step-by-step derivation
      1. lower-atan.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
      2. lower-/.f64N/A

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
    5. Applied rewrites88.6%

      \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
    6. Taylor expanded in A around 0

      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi} \]
    7. Step-by-step derivation
      1. Applied rewrites86.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi} \]
      2. Taylor expanded in C around 0

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi} \]
      3. Step-by-step derivation
        1. lift--.f6486.9

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi} \]
      4. Applied rewrites86.9%

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi} \]
    8. Recombined 2 regimes into one program.
    9. Add Preprocessing

    Alternative 3: 79.2% accurate, 0.4× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} t_0 := 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}\\ \mathbf{if}\;t\_0 \leq -40:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - B}{B}\right)}{\pi}\\ \mathbf{elif}\;t\_0 \leq 0:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\ \end{array} \end{array} \]
    (FPCore (A B C)
     :precision binary64
     (let* ((t_0
             (*
              180.0
              (/
               (atan
                (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
               PI))))
       (if (<= t_0 -40.0)
         (* 180.0 (/ (atan (/ (- (- C A) B) B)) PI))
         (if (<= t_0 0.0)
           (* 180.0 (/ (atan (* (/ B (- C A)) -0.5)) PI))
           (* 180.0 (/ (atan (+ 1.0 (/ (- C A) B))) PI))))))
    double code(double A, double B, double C) {
    	double t_0 = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / ((double) M_PI));
    	double tmp;
    	if (t_0 <= -40.0) {
    		tmp = 180.0 * (atan((((C - A) - B) / B)) / ((double) M_PI));
    	} else if (t_0 <= 0.0) {
    		tmp = 180.0 * (atan(((B / (C - A)) * -0.5)) / ((double) M_PI));
    	} else {
    		tmp = 180.0 * (atan((1.0 + ((C - A) / B))) / ((double) M_PI));
    	}
    	return tmp;
    }
    
    public static double code(double A, double B, double C) {
    	double t_0 = 180.0 * (Math.atan(((1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / Math.PI);
    	double tmp;
    	if (t_0 <= -40.0) {
    		tmp = 180.0 * (Math.atan((((C - A) - B) / B)) / Math.PI);
    	} else if (t_0 <= 0.0) {
    		tmp = 180.0 * (Math.atan(((B / (C - A)) * -0.5)) / Math.PI);
    	} else {
    		tmp = 180.0 * (Math.atan((1.0 + ((C - A) / B))) / Math.PI);
    	}
    	return tmp;
    }
    
    def code(A, B, C):
    	t_0 = 180.0 * (math.atan(((1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / math.pi)
    	tmp = 0
    	if t_0 <= -40.0:
    		tmp = 180.0 * (math.atan((((C - A) - B) / B)) / math.pi)
    	elif t_0 <= 0.0:
    		tmp = 180.0 * (math.atan(((B / (C - A)) * -0.5)) / math.pi)
    	else:
    		tmp = 180.0 * (math.atan((1.0 + ((C - A) / B))) / math.pi)
    	return tmp
    
    function code(A, B, C)
    	t_0 = Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))) / pi))
    	tmp = 0.0
    	if (t_0 <= -40.0)
    		tmp = Float64(180.0 * Float64(atan(Float64(Float64(Float64(C - A) - B) / B)) / pi));
    	elseif (t_0 <= 0.0)
    		tmp = Float64(180.0 * Float64(atan(Float64(Float64(B / Float64(C - A)) * -0.5)) / pi));
    	else
    		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + Float64(Float64(C - A) / B))) / pi));
    	end
    	return tmp
    end
    
    function tmp_2 = code(A, B, C)
    	t_0 = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / pi);
    	tmp = 0.0;
    	if (t_0 <= -40.0)
    		tmp = 180.0 * (atan((((C - A) - B) / B)) / pi);
    	elseif (t_0 <= 0.0)
    		tmp = 180.0 * (atan(((B / (C - A)) * -0.5)) / pi);
    	else
    		tmp = 180.0 * (atan((1.0 + ((C - A) / B))) / pi);
    	end
    	tmp_2 = tmp;
    end
    
    code[A_, B_, C_] := Block[{t$95$0 = N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, -40.0], N[(180.0 * N[(N[ArcTan[N[(N[(N[(C - A), $MachinePrecision] - B), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$0, 0.0], N[(180.0 * N[(N[ArcTan[N[(N[(B / N[(C - A), $MachinePrecision]), $MachinePrecision] * -0.5), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(1.0 + N[(N[(C - A), $MachinePrecision] / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    t_0 := 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}\\
    \mathbf{if}\;t\_0 \leq -40:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - B}{B}\right)}{\pi}\\
    
    \mathbf{elif}\;t\_0 \leq 0:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi}\\
    
    \mathbf{else}:\\
    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 3 regimes
    2. if (*.f64 #s(literal 180 binary64) (/.f64 (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))) (PI.f64))) < -40

      1. Initial program 54.9%

        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      2. Add Preprocessing
      3. Taylor expanded in A around -inf

        \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}}{\pi} \]
      4. Step-by-step derivation
        1. lower-atan.f64N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
        2. lower-/.f64N/A

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
      5. Applied rewrites86.7%

        \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
      6. Taylor expanded in A around 0

        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi} \]
      7. Step-by-step derivation
        1. Applied rewrites83.8%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi} \]
        2. Taylor expanded in C around 0

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi} \]
        3. Step-by-step derivation
          1. lift--.f6483.8

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi} \]
        4. Applied rewrites83.8%

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi} \]
        5. Taylor expanded in B around inf

          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - B}{B}\right)}{\pi} \]
        6. Step-by-step derivation
          1. Applied rewrites74.3%

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - B}{B}\right)}{\pi} \]

          if -40 < (*.f64 #s(literal 180 binary64) (/.f64 (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))) (PI.f64))) < 0.0

          1. Initial program 18.7%

            \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
          2. Add Preprocessing
          3. Taylor expanded in A around -inf

            \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}}{\pi} \]
          4. Step-by-step derivation
            1. lower-atan.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
            2. lower-/.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
          5. Applied rewrites21.6%

            \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
          6. Taylor expanded in B around 0

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1}{2} \cdot \frac{B}{C - A}\right)}{\pi} \]
          7. Step-by-step derivation
            1. *-commutativeN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
            2. lower-*.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
            3. lower-/.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot \frac{-1}{2}\right)}{\pi} \]
            4. lift--.f6495.0

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi} \]
          8. Applied rewrites95.0%

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C - A} \cdot -0.5\right)}{\pi} \]

          if 0.0 < (*.f64 #s(literal 180 binary64) (/.f64 (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))) (PI.f64)))

          1. Initial program 62.3%

            \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
          2. Add Preprocessing
          3. Taylor expanded in B around -inf

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
          4. Step-by-step derivation
            1. associate--l+N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
            2. div-subN/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
            3. lower-+.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
            4. lower-/.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
            5. lift--.f6479.5

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
          5. Applied rewrites79.5%

            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
        7. Recombined 3 regimes into one program.
        8. Add Preprocessing

        Alternative 4: 72.4% accurate, 0.4× speedup?

        \[\begin{array}{l} \\ \begin{array}{l} t_0 := 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}\\ \mathbf{if}\;t\_0 \leq -40:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - B}{B}\right)}{\pi}\\ \mathbf{elif}\;t\_0 \leq 0:\\ \;\;\;\;\frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \cdot 180\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\ \end{array} \end{array} \]
        (FPCore (A B C)
         :precision binary64
         (let* ((t_0
                 (*
                  180.0
                  (/
                   (atan
                    (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
                   PI))))
           (if (<= t_0 -40.0)
             (* 180.0 (/ (atan (/ (- (- C A) B) B)) PI))
             (if (<= t_0 0.0)
               (* (/ (atan (* (/ B A) 0.5)) PI) 180.0)
               (* 180.0 (/ (atan (+ 1.0 (/ (- C A) B))) PI))))))
        double code(double A, double B, double C) {
        	double t_0 = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / ((double) M_PI));
        	double tmp;
        	if (t_0 <= -40.0) {
        		tmp = 180.0 * (atan((((C - A) - B) / B)) / ((double) M_PI));
        	} else if (t_0 <= 0.0) {
        		tmp = (atan(((B / A) * 0.5)) / ((double) M_PI)) * 180.0;
        	} else {
        		tmp = 180.0 * (atan((1.0 + ((C - A) / B))) / ((double) M_PI));
        	}
        	return tmp;
        }
        
        public static double code(double A, double B, double C) {
        	double t_0 = 180.0 * (Math.atan(((1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / Math.PI);
        	double tmp;
        	if (t_0 <= -40.0) {
        		tmp = 180.0 * (Math.atan((((C - A) - B) / B)) / Math.PI);
        	} else if (t_0 <= 0.0) {
        		tmp = (Math.atan(((B / A) * 0.5)) / Math.PI) * 180.0;
        	} else {
        		tmp = 180.0 * (Math.atan((1.0 + ((C - A) / B))) / Math.PI);
        	}
        	return tmp;
        }
        
        def code(A, B, C):
        	t_0 = 180.0 * (math.atan(((1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / math.pi)
        	tmp = 0
        	if t_0 <= -40.0:
        		tmp = 180.0 * (math.atan((((C - A) - B) / B)) / math.pi)
        	elif t_0 <= 0.0:
        		tmp = (math.atan(((B / A) * 0.5)) / math.pi) * 180.0
        	else:
        		tmp = 180.0 * (math.atan((1.0 + ((C - A) / B))) / math.pi)
        	return tmp
        
        function code(A, B, C)
        	t_0 = Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))) / pi))
        	tmp = 0.0
        	if (t_0 <= -40.0)
        		tmp = Float64(180.0 * Float64(atan(Float64(Float64(Float64(C - A) - B) / B)) / pi));
        	elseif (t_0 <= 0.0)
        		tmp = Float64(Float64(atan(Float64(Float64(B / A) * 0.5)) / pi) * 180.0);
        	else
        		tmp = Float64(180.0 * Float64(atan(Float64(1.0 + Float64(Float64(C - A) / B))) / pi));
        	end
        	return tmp
        end
        
        function tmp_2 = code(A, B, C)
        	t_0 = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / pi);
        	tmp = 0.0;
        	if (t_0 <= -40.0)
        		tmp = 180.0 * (atan((((C - A) - B) / B)) / pi);
        	elseif (t_0 <= 0.0)
        		tmp = (atan(((B / A) * 0.5)) / pi) * 180.0;
        	else
        		tmp = 180.0 * (atan((1.0 + ((C - A) / B))) / pi);
        	end
        	tmp_2 = tmp;
        end
        
        code[A_, B_, C_] := Block[{t$95$0 = N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, -40.0], N[(180.0 * N[(N[ArcTan[N[(N[(N[(C - A), $MachinePrecision] - B), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$0, 0.0], N[(N[(N[ArcTan[N[(N[(B / A), $MachinePrecision] * 0.5), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision] * 180.0), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(1.0 + N[(N[(C - A), $MachinePrecision] / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]
        
        \begin{array}{l}
        
        \\
        \begin{array}{l}
        t_0 := 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}\\
        \mathbf{if}\;t\_0 \leq -40:\\
        \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - B}{B}\right)}{\pi}\\
        
        \mathbf{elif}\;t\_0 \leq 0:\\
        \;\;\;\;\frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \cdot 180\\
        
        \mathbf{else}:\\
        \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 3 regimes
        2. if (*.f64 #s(literal 180 binary64) (/.f64 (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))) (PI.f64))) < -40

          1. Initial program 54.9%

            \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
          2. Add Preprocessing
          3. Taylor expanded in A around -inf

            \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}}{\pi} \]
          4. Step-by-step derivation
            1. lower-atan.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
            2. lower-/.f64N/A

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
          5. Applied rewrites86.7%

            \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
          6. Taylor expanded in A around 0

            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi} \]
          7. Step-by-step derivation
            1. Applied rewrites83.8%

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi} \]
            2. Taylor expanded in C around 0

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi} \]
            3. Step-by-step derivation
              1. lift--.f6483.8

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi} \]
            4. Applied rewrites83.8%

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi} \]
            5. Taylor expanded in B around inf

              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - B}{B}\right)}{\pi} \]
            6. Step-by-step derivation
              1. Applied rewrites74.3%

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - B}{B}\right)}{\pi} \]

              if -40 < (*.f64 #s(literal 180 binary64) (/.f64 (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))) (PI.f64))) < 0.0

              1. Initial program 18.7%

                \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
              2. Add Preprocessing
              3. Taylor expanded in A around -inf

                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1}{2} \cdot \frac{B}{A}\right)}}{\pi} \]
              4. Step-by-step derivation
                1. *-commutativeN/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \color{blue}{\frac{1}{2}}\right)}{\pi} \]
                2. lower-*.f64N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \color{blue}{\frac{1}{2}}\right)}{\pi} \]
                3. lower-/.f6450.3

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \]
              5. Applied rewrites50.3%

                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{B}{A} \cdot 0.5\right)}}{\pi} \]
              6. Step-by-step derivation
                1. lift-*.f64N/A

                  \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                2. *-commutativeN/A

                  \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi} \cdot 180} \]
                3. lower-*.f6450.3

                  \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \cdot 180} \]
              7. Applied rewrites50.3%

                \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \cdot 180} \]

              if 0.0 < (*.f64 #s(literal 180 binary64) (/.f64 (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))) (PI.f64)))

              1. Initial program 62.3%

                \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
              2. Add Preprocessing
              3. Taylor expanded in B around -inf

                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
              4. Step-by-step derivation
                1. associate--l+N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
                2. div-subN/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                3. lower-+.f64N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
                4. lower-/.f64N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                5. lift--.f6479.5

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
              5. Applied rewrites79.5%

                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
            7. Recombined 3 regimes into one program.
            8. Add Preprocessing

            Alternative 5: 72.4% accurate, 0.4× speedup?

            \[\begin{array}{l} \\ \begin{array}{l} t_0 := 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}\\ \mathbf{if}\;t\_0 \leq -40:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - B}{B}\right)}{\pi}\\ \mathbf{elif}\;t\_0 \leq 0:\\ \;\;\;\;\frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \cdot 180\\ \mathbf{else}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{C - A}{B} + 1\right)}{\pi}\\ \end{array} \end{array} \]
            (FPCore (A B C)
             :precision binary64
             (let* ((t_0
                     (*
                      180.0
                      (/
                       (atan
                        (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
                       PI))))
               (if (<= t_0 -40.0)
                 (* 180.0 (/ (atan (/ (- (- C A) B) B)) PI))
                 (if (<= t_0 0.0)
                   (* (/ (atan (* (/ B A) 0.5)) PI) 180.0)
                   (/ (* 180.0 (atan (+ (/ (- C A) B) 1.0))) PI)))))
            double code(double A, double B, double C) {
            	double t_0 = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / ((double) M_PI));
            	double tmp;
            	if (t_0 <= -40.0) {
            		tmp = 180.0 * (atan((((C - A) - B) / B)) / ((double) M_PI));
            	} else if (t_0 <= 0.0) {
            		tmp = (atan(((B / A) * 0.5)) / ((double) M_PI)) * 180.0;
            	} else {
            		tmp = (180.0 * atan((((C - A) / B) + 1.0))) / ((double) M_PI);
            	}
            	return tmp;
            }
            
            public static double code(double A, double B, double C) {
            	double t_0 = 180.0 * (Math.atan(((1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / Math.PI);
            	double tmp;
            	if (t_0 <= -40.0) {
            		tmp = 180.0 * (Math.atan((((C - A) - B) / B)) / Math.PI);
            	} else if (t_0 <= 0.0) {
            		tmp = (Math.atan(((B / A) * 0.5)) / Math.PI) * 180.0;
            	} else {
            		tmp = (180.0 * Math.atan((((C - A) / B) + 1.0))) / Math.PI;
            	}
            	return tmp;
            }
            
            def code(A, B, C):
            	t_0 = 180.0 * (math.atan(((1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / math.pi)
            	tmp = 0
            	if t_0 <= -40.0:
            		tmp = 180.0 * (math.atan((((C - A) - B) / B)) / math.pi)
            	elif t_0 <= 0.0:
            		tmp = (math.atan(((B / A) * 0.5)) / math.pi) * 180.0
            	else:
            		tmp = (180.0 * math.atan((((C - A) / B) + 1.0))) / math.pi
            	return tmp
            
            function code(A, B, C)
            	t_0 = Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))) / pi))
            	tmp = 0.0
            	if (t_0 <= -40.0)
            		tmp = Float64(180.0 * Float64(atan(Float64(Float64(Float64(C - A) - B) / B)) / pi));
            	elseif (t_0 <= 0.0)
            		tmp = Float64(Float64(atan(Float64(Float64(B / A) * 0.5)) / pi) * 180.0);
            	else
            		tmp = Float64(Float64(180.0 * atan(Float64(Float64(Float64(C - A) / B) + 1.0))) / pi);
            	end
            	return tmp
            end
            
            function tmp_2 = code(A, B, C)
            	t_0 = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / pi);
            	tmp = 0.0;
            	if (t_0 <= -40.0)
            		tmp = 180.0 * (atan((((C - A) - B) / B)) / pi);
            	elseif (t_0 <= 0.0)
            		tmp = (atan(((B / A) * 0.5)) / pi) * 180.0;
            	else
            		tmp = (180.0 * atan((((C - A) / B) + 1.0))) / pi;
            	end
            	tmp_2 = tmp;
            end
            
            code[A_, B_, C_] := Block[{t$95$0 = N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, -40.0], N[(180.0 * N[(N[ArcTan[N[(N[(N[(C - A), $MachinePrecision] - B), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$0, 0.0], N[(N[(N[ArcTan[N[(N[(B / A), $MachinePrecision] * 0.5), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision] * 180.0), $MachinePrecision], N[(N[(180.0 * N[ArcTan[N[(N[(N[(C - A), $MachinePrecision] / B), $MachinePrecision] + 1.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision]]]]
            
            \begin{array}{l}
            
            \\
            \begin{array}{l}
            t_0 := 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}\\
            \mathbf{if}\;t\_0 \leq -40:\\
            \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - B}{B}\right)}{\pi}\\
            
            \mathbf{elif}\;t\_0 \leq 0:\\
            \;\;\;\;\frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \cdot 180\\
            
            \mathbf{else}:\\
            \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{C - A}{B} + 1\right)}{\pi}\\
            
            
            \end{array}
            \end{array}
            
            Derivation
            1. Split input into 3 regimes
            2. if (*.f64 #s(literal 180 binary64) (/.f64 (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))) (PI.f64))) < -40

              1. Initial program 54.9%

                \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
              2. Add Preprocessing
              3. Taylor expanded in A around -inf

                \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}}{\pi} \]
              4. Step-by-step derivation
                1. lower-atan.f64N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
                2. lower-/.f64N/A

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
              5. Applied rewrites86.7%

                \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
              6. Taylor expanded in A around 0

                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi} \]
              7. Step-by-step derivation
                1. Applied rewrites83.8%

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi} \]
                2. Taylor expanded in C around 0

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi} \]
                3. Step-by-step derivation
                  1. lift--.f6483.8

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi} \]
                4. Applied rewrites83.8%

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi} \]
                5. Taylor expanded in B around inf

                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - B}{B}\right)}{\pi} \]
                6. Step-by-step derivation
                  1. Applied rewrites74.3%

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - B}{B}\right)}{\pi} \]

                  if -40 < (*.f64 #s(literal 180 binary64) (/.f64 (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))) (PI.f64))) < 0.0

                  1. Initial program 18.7%

                    \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                  2. Add Preprocessing
                  3. Taylor expanded in A around -inf

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1}{2} \cdot \frac{B}{A}\right)}}{\pi} \]
                  4. Step-by-step derivation
                    1. *-commutativeN/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \color{blue}{\frac{1}{2}}\right)}{\pi} \]
                    2. lower-*.f64N/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \color{blue}{\frac{1}{2}}\right)}{\pi} \]
                    3. lower-/.f6450.3

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \]
                  5. Applied rewrites50.3%

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{B}{A} \cdot 0.5\right)}}{\pi} \]
                  6. Step-by-step derivation
                    1. lift-*.f64N/A

                      \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                    2. *-commutativeN/A

                      \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi} \cdot 180} \]
                    3. lower-*.f6450.3

                      \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \cdot 180} \]
                  7. Applied rewrites50.3%

                    \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \cdot 180} \]

                  if 0.0 < (*.f64 #s(literal 180 binary64) (/.f64 (atan.f64 (*.f64 (/.f64 #s(literal 1 binary64) B) (-.f64 (-.f64 C A) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64))))))) (PI.f64)))

                  1. Initial program 62.3%

                    \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                  2. Add Preprocessing
                  3. Taylor expanded in B around -inf

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
                  4. Step-by-step derivation
                    1. associate--l+N/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
                    2. div-subN/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                    3. lower-+.f64N/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
                    4. lower-/.f64N/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                    5. lift--.f6479.5

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
                  5. Applied rewrites79.5%

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
                  6. Step-by-step derivation
                    1. lift-*.f64N/A

                      \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}} \]
                    2. lift-/.f64N/A

                      \[\leadsto 180 \cdot \color{blue}{\frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}} \]
                    3. associate-*r/N/A

                      \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}} \]
                    4. lower-/.f64N/A

                      \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi}} \]
                  7. Applied rewrites79.5%

                    \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{C - A}{B} + 1\right)}{\pi}} \]
                7. Recombined 3 regimes into one program.
                8. Add Preprocessing

                Alternative 6: 60.4% accurate, 2.3× speedup?

                \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;A \leq -6.6 \cdot 10^{+24}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - B}{B}\right)}{\pi}\\ \end{array} \end{array} \]
                (FPCore (A B C)
                 :precision binary64
                 (if (<= A -6.6e+24)
                   (/ (* 180.0 (atan (* (/ B A) 0.5))) PI)
                   (* 180.0 (/ (atan (/ (- (- C A) B) B)) PI))))
                double code(double A, double B, double C) {
                	double tmp;
                	if (A <= -6.6e+24) {
                		tmp = (180.0 * atan(((B / A) * 0.5))) / ((double) M_PI);
                	} else {
                		tmp = 180.0 * (atan((((C - A) - B) / B)) / ((double) M_PI));
                	}
                	return tmp;
                }
                
                public static double code(double A, double B, double C) {
                	double tmp;
                	if (A <= -6.6e+24) {
                		tmp = (180.0 * Math.atan(((B / A) * 0.5))) / Math.PI;
                	} else {
                		tmp = 180.0 * (Math.atan((((C - A) - B) / B)) / Math.PI);
                	}
                	return tmp;
                }
                
                def code(A, B, C):
                	tmp = 0
                	if A <= -6.6e+24:
                		tmp = (180.0 * math.atan(((B / A) * 0.5))) / math.pi
                	else:
                		tmp = 180.0 * (math.atan((((C - A) - B) / B)) / math.pi)
                	return tmp
                
                function code(A, B, C)
                	tmp = 0.0
                	if (A <= -6.6e+24)
                		tmp = Float64(Float64(180.0 * atan(Float64(Float64(B / A) * 0.5))) / pi);
                	else
                		tmp = Float64(180.0 * Float64(atan(Float64(Float64(Float64(C - A) - B) / B)) / pi));
                	end
                	return tmp
                end
                
                function tmp_2 = code(A, B, C)
                	tmp = 0.0;
                	if (A <= -6.6e+24)
                		tmp = (180.0 * atan(((B / A) * 0.5))) / pi;
                	else
                		tmp = 180.0 * (atan((((C - A) - B) / B)) / pi);
                	end
                	tmp_2 = tmp;
                end
                
                code[A_, B_, C_] := If[LessEqual[A, -6.6e+24], N[(N[(180.0 * N[ArcTan[N[(N[(B / A), $MachinePrecision] * 0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(N[(N[(C - A), $MachinePrecision] - B), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]
                
                \begin{array}{l}
                
                \\
                \begin{array}{l}
                \mathbf{if}\;A \leq -6.6 \cdot 10^{+24}:\\
                \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi}\\
                
                \mathbf{else}:\\
                \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - B}{B}\right)}{\pi}\\
                
                
                \end{array}
                \end{array}
                
                Derivation
                1. Split input into 2 regimes
                2. if A < -6.5999999999999998e24

                  1. Initial program 13.9%

                    \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                  2. Add Preprocessing
                  3. Taylor expanded in A around -inf

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1}{2} \cdot \frac{B}{A}\right)}}{\pi} \]
                  4. Step-by-step derivation
                    1. *-commutativeN/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \color{blue}{\frac{1}{2}}\right)}{\pi} \]
                    2. lower-*.f64N/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \color{blue}{\frac{1}{2}}\right)}{\pi} \]
                    3. lower-/.f6474.1

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \]
                  5. Applied rewrites74.1%

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{B}{A} \cdot 0.5\right)}}{\pi} \]
                  6. Step-by-step derivation
                    1. lift-*.f64N/A

                      \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                    2. lift-/.f64N/A

                      \[\leadsto 180 \cdot \color{blue}{\frac{\tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                    3. associate-*r/N/A

                      \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                    4. lower-/.f64N/A

                      \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                    5. lower-*.f6474.2

                      \[\leadsto \frac{\color{blue}{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}}{\pi} \]
                  7. Applied rewrites74.2%

                    \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi}} \]

                  if -6.5999999999999998e24 < A

                  1. Initial program 64.3%

                    \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                  2. Add Preprocessing
                  3. Taylor expanded in A around -inf

                    \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}}{\pi} \]
                  4. Step-by-step derivation
                    1. lower-atan.f64N/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
                    2. lower-/.f64N/A

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C + -1 \cdot A\right) - \sqrt{{B}^{2} + {\left(C + -1 \cdot A\right)}^{2}}}{B}\right)}{\pi} \]
                  5. Applied rewrites87.6%

                    \[\leadsto 180 \cdot \frac{\color{blue}{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(\left(-A\right) + C, B\right)}{B}\right)}}{\pi} \]
                  6. Taylor expanded in A around 0

                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi} \]
                  7. Step-by-step derivation
                    1. Applied rewrites85.9%

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-A\right) + C\right) - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi} \]
                    2. Taylor expanded in C around 0

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi} \]
                    3. Step-by-step derivation
                      1. lift--.f6485.9

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi} \]
                    4. Applied rewrites85.9%

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(C, B\right)}{B}\right)}{\pi} \]
                    5. Taylor expanded in B around inf

                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - B}{B}\right)}{\pi} \]
                    6. Step-by-step derivation
                      1. Applied rewrites66.0%

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - B}{B}\right)}{\pi} \]
                    7. Recombined 2 regimes into one program.
                    8. Add Preprocessing

                    Alternative 7: 59.5% accurate, 2.0× speedup?

                    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;C \leq -2.3 \cdot 10^{-18}:\\ \;\;\;\;\frac{\tan^{-1} \left(\frac{C}{B} + 1\right)}{\pi} \cdot 180\\ \mathbf{elif}\;C \leq -1.6 \cdot 10^{-81}:\\ \;\;\;\;\frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \cdot 180\\ \mathbf{elif}\;C \leq 3.5 \cdot 10^{-96}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B}{C} \cdot -0.5\right)}{\pi}\\ \end{array} \end{array} \]
                    (FPCore (A B C)
                     :precision binary64
                     (if (<= C -2.3e-18)
                       (* (/ (atan (+ (/ C B) 1.0)) PI) 180.0)
                       (if (<= C -1.6e-81)
                         (* (/ (atan (* (/ B A) 0.5)) PI) 180.0)
                         (if (<= C 3.5e-96)
                           (* 180.0 (/ (atan (- 1.0 (/ A B))) PI))
                           (* 180.0 (/ (atan (* (/ B C) -0.5)) PI))))))
                    double code(double A, double B, double C) {
                    	double tmp;
                    	if (C <= -2.3e-18) {
                    		tmp = (atan(((C / B) + 1.0)) / ((double) M_PI)) * 180.0;
                    	} else if (C <= -1.6e-81) {
                    		tmp = (atan(((B / A) * 0.5)) / ((double) M_PI)) * 180.0;
                    	} else if (C <= 3.5e-96) {
                    		tmp = 180.0 * (atan((1.0 - (A / B))) / ((double) M_PI));
                    	} else {
                    		tmp = 180.0 * (atan(((B / C) * -0.5)) / ((double) M_PI));
                    	}
                    	return tmp;
                    }
                    
                    public static double code(double A, double B, double C) {
                    	double tmp;
                    	if (C <= -2.3e-18) {
                    		tmp = (Math.atan(((C / B) + 1.0)) / Math.PI) * 180.0;
                    	} else if (C <= -1.6e-81) {
                    		tmp = (Math.atan(((B / A) * 0.5)) / Math.PI) * 180.0;
                    	} else if (C <= 3.5e-96) {
                    		tmp = 180.0 * (Math.atan((1.0 - (A / B))) / Math.PI);
                    	} else {
                    		tmp = 180.0 * (Math.atan(((B / C) * -0.5)) / Math.PI);
                    	}
                    	return tmp;
                    }
                    
                    def code(A, B, C):
                    	tmp = 0
                    	if C <= -2.3e-18:
                    		tmp = (math.atan(((C / B) + 1.0)) / math.pi) * 180.0
                    	elif C <= -1.6e-81:
                    		tmp = (math.atan(((B / A) * 0.5)) / math.pi) * 180.0
                    	elif C <= 3.5e-96:
                    		tmp = 180.0 * (math.atan((1.0 - (A / B))) / math.pi)
                    	else:
                    		tmp = 180.0 * (math.atan(((B / C) * -0.5)) / math.pi)
                    	return tmp
                    
                    function code(A, B, C)
                    	tmp = 0.0
                    	if (C <= -2.3e-18)
                    		tmp = Float64(Float64(atan(Float64(Float64(C / B) + 1.0)) / pi) * 180.0);
                    	elseif (C <= -1.6e-81)
                    		tmp = Float64(Float64(atan(Float64(Float64(B / A) * 0.5)) / pi) * 180.0);
                    	elseif (C <= 3.5e-96)
                    		tmp = Float64(180.0 * Float64(atan(Float64(1.0 - Float64(A / B))) / pi));
                    	else
                    		tmp = Float64(180.0 * Float64(atan(Float64(Float64(B / C) * -0.5)) / pi));
                    	end
                    	return tmp
                    end
                    
                    function tmp_2 = code(A, B, C)
                    	tmp = 0.0;
                    	if (C <= -2.3e-18)
                    		tmp = (atan(((C / B) + 1.0)) / pi) * 180.0;
                    	elseif (C <= -1.6e-81)
                    		tmp = (atan(((B / A) * 0.5)) / pi) * 180.0;
                    	elseif (C <= 3.5e-96)
                    		tmp = 180.0 * (atan((1.0 - (A / B))) / pi);
                    	else
                    		tmp = 180.0 * (atan(((B / C) * -0.5)) / pi);
                    	end
                    	tmp_2 = tmp;
                    end
                    
                    code[A_, B_, C_] := If[LessEqual[C, -2.3e-18], N[(N[(N[ArcTan[N[(N[(C / B), $MachinePrecision] + 1.0), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision] * 180.0), $MachinePrecision], If[LessEqual[C, -1.6e-81], N[(N[(N[ArcTan[N[(N[(B / A), $MachinePrecision] * 0.5), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision] * 180.0), $MachinePrecision], If[LessEqual[C, 3.5e-96], N[(180.0 * N[(N[ArcTan[N[(1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(N[(B / C), $MachinePrecision] * -0.5), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]
                    
                    \begin{array}{l}
                    
                    \\
                    \begin{array}{l}
                    \mathbf{if}\;C \leq -2.3 \cdot 10^{-18}:\\
                    \;\;\;\;\frac{\tan^{-1} \left(\frac{C}{B} + 1\right)}{\pi} \cdot 180\\
                    
                    \mathbf{elif}\;C \leq -1.6 \cdot 10^{-81}:\\
                    \;\;\;\;\frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \cdot 180\\
                    
                    \mathbf{elif}\;C \leq 3.5 \cdot 10^{-96}:\\
                    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\
                    
                    \mathbf{else}:\\
                    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B}{C} \cdot -0.5\right)}{\pi}\\
                    
                    
                    \end{array}
                    \end{array}
                    
                    Derivation
                    1. Split input into 4 regimes
                    2. if C < -2.3000000000000001e-18

                      1. Initial program 81.4%

                        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                      2. Add Preprocessing
                      3. Taylor expanded in B around -inf

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
                      4. Step-by-step derivation
                        1. associate--l+N/A

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
                        2. div-subN/A

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                        3. lower-+.f64N/A

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
                        4. lower-/.f64N/A

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                        5. lift--.f6482.9

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
                      5. Applied rewrites82.9%

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
                      6. Taylor expanded in A around 0

                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi} \]
                      7. Step-by-step derivation
                        1. Applied rewrites82.9%

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi} \]
                        2. Step-by-step derivation
                          1. lift-*.f64N/A

                            \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi}} \]
                          2. *-commutativeN/A

                            \[\leadsto \color{blue}{\frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi} \cdot 180} \]
                          3. lower-*.f6482.9

                            \[\leadsto \color{blue}{\frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi} \cdot 180} \]
                          4. lift-+.f64N/A

                            \[\leadsto \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C}{B}}\right)}{\pi} \cdot 180 \]
                          5. +-commutativeN/A

                            \[\leadsto \frac{\tan^{-1} \left(\frac{C}{B} + \color{blue}{1}\right)}{\pi} \cdot 180 \]
                          6. lower-+.f6482.9

                            \[\leadsto \frac{\tan^{-1} \left(\frac{C}{B} + \color{blue}{1}\right)}{\pi} \cdot 180 \]
                        3. Applied rewrites82.9%

                          \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{C}{B} + 1\right)}{\pi} \cdot 180} \]

                        if -2.3000000000000001e-18 < C < -1.6e-81

                        1. Initial program 49.1%

                          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                        2. Add Preprocessing
                        3. Taylor expanded in A around -inf

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1}{2} \cdot \frac{B}{A}\right)}}{\pi} \]
                        4. Step-by-step derivation
                          1. *-commutativeN/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \color{blue}{\frac{1}{2}}\right)}{\pi} \]
                          2. lower-*.f64N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \color{blue}{\frac{1}{2}}\right)}{\pi} \]
                          3. lower-/.f6472.1

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \]
                        5. Applied rewrites72.1%

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{B}{A} \cdot 0.5\right)}}{\pi} \]
                        6. Step-by-step derivation
                          1. lift-*.f64N/A

                            \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                          2. *-commutativeN/A

                            \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi} \cdot 180} \]
                          3. lower-*.f6472.1

                            \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \cdot 180} \]
                        7. Applied rewrites72.1%

                          \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \cdot 180} \]

                        if -1.6e-81 < C < 3.4999999999999999e-96

                        1. Initial program 61.3%

                          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                        2. Add Preprocessing
                        3. Taylor expanded in B around -inf

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
                        4. Step-by-step derivation
                          1. associate--l+N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
                          2. div-subN/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                          3. lower-+.f64N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
                          4. lower-/.f64N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                          5. lift--.f6451.5

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
                        5. Applied rewrites51.5%

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
                        6. Taylor expanded in C around 0

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]
                        7. Step-by-step derivation
                          1. lower--.f64N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{\color{blue}{B}}\right)}{\pi} \]
                          2. lift-/.f6450.3

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi} \]
                        8. Applied rewrites50.3%

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]

                        if 3.4999999999999999e-96 < C

                        1. Initial program 21.5%

                          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                        2. Add Preprocessing
                        3. Taylor expanded in C around inf

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + -1 \cdot A}{B} + \frac{-1}{2} \cdot \frac{B}{C}\right)}}{\pi} \]
                        4. Step-by-step derivation
                          1. +-commutativeN/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1}{2} \cdot \frac{B}{C} + \color{blue}{-1 \cdot \frac{A + -1 \cdot A}{B}}\right)}{\pi} \]
                          2. *-commutativeN/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C} \cdot \frac{-1}{2} + \color{blue}{-1} \cdot \frac{A + -1 \cdot A}{B}\right)}{\pi} \]
                          3. lower-fma.f64N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\mathsf{fma}\left(\frac{B}{C}, \color{blue}{\frac{-1}{2}}, -1 \cdot \frac{A + -1 \cdot A}{B}\right)\right)}{\pi} \]
                          4. lower-/.f64N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\mathsf{fma}\left(\frac{B}{C}, \frac{-1}{2}, -1 \cdot \frac{A + -1 \cdot A}{B}\right)\right)}{\pi} \]
                          5. mul-1-negN/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\mathsf{fma}\left(\frac{B}{C}, \frac{-1}{2}, \mathsf{neg}\left(\frac{A + -1 \cdot A}{B}\right)\right)\right)}{\pi} \]
                          6. lower-neg.f64N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\mathsf{fma}\left(\frac{B}{C}, \frac{-1}{2}, -\frac{A + -1 \cdot A}{B}\right)\right)}{\pi} \]
                          7. lower-/.f64N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\mathsf{fma}\left(\frac{B}{C}, \frac{-1}{2}, -\frac{A + -1 \cdot A}{B}\right)\right)}{\pi} \]
                          8. distribute-rgt1-inN/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\mathsf{fma}\left(\frac{B}{C}, \frac{-1}{2}, -\frac{\left(-1 + 1\right) \cdot A}{B}\right)\right)}{\pi} \]
                          9. metadata-evalN/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\mathsf{fma}\left(\frac{B}{C}, \frac{-1}{2}, -\frac{0 \cdot A}{B}\right)\right)}{\pi} \]
                          10. lower-*.f6461.7

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\mathsf{fma}\left(\frac{B}{C}, -0.5, -\frac{0 \cdot A}{B}\right)\right)}{\pi} \]
                        5. Applied rewrites61.7%

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\mathsf{fma}\left(\frac{B}{C}, -0.5, -\frac{0 \cdot A}{B}\right)\right)}}{\pi} \]
                        6. Taylor expanded in A around 0

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1}{2} \cdot \color{blue}{\frac{B}{C}}\right)}{\pi} \]
                        7. Step-by-step derivation
                          1. *-commutativeN/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C} \cdot \frac{-1}{2}\right)}{\pi} \]
                          2. lower-*.f64N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C} \cdot \frac{-1}{2}\right)}{\pi} \]
                          3. lift-/.f6461.7

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C} \cdot -0.5\right)}{\pi} \]
                        8. Applied rewrites61.7%

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{C} \cdot \color{blue}{-0.5}\right)}{\pi} \]
                      8. Recombined 4 regimes into one program.
                      9. Add Preprocessing

                      Alternative 8: 59.5% accurate, 2.2× speedup?

                      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;A \leq -3.9 \cdot 10^{+15}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi}\\ \mathbf{elif}\;A \leq 4.5 \cdot 10^{-125}:\\ \;\;\;\;\frac{\tan^{-1} \left(\frac{C}{B} + 1\right)}{\pi} \cdot 180\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \end{array} \end{array} \]
                      (FPCore (A B C)
                       :precision binary64
                       (if (<= A -3.9e+15)
                         (/ (* 180.0 (atan (* (/ B A) 0.5))) PI)
                         (if (<= A 4.5e-125)
                           (* (/ (atan (+ (/ C B) 1.0)) PI) 180.0)
                           (* 180.0 (/ (atan (- 1.0 (/ A B))) PI)))))
                      double code(double A, double B, double C) {
                      	double tmp;
                      	if (A <= -3.9e+15) {
                      		tmp = (180.0 * atan(((B / A) * 0.5))) / ((double) M_PI);
                      	} else if (A <= 4.5e-125) {
                      		tmp = (atan(((C / B) + 1.0)) / ((double) M_PI)) * 180.0;
                      	} else {
                      		tmp = 180.0 * (atan((1.0 - (A / B))) / ((double) M_PI));
                      	}
                      	return tmp;
                      }
                      
                      public static double code(double A, double B, double C) {
                      	double tmp;
                      	if (A <= -3.9e+15) {
                      		tmp = (180.0 * Math.atan(((B / A) * 0.5))) / Math.PI;
                      	} else if (A <= 4.5e-125) {
                      		tmp = (Math.atan(((C / B) + 1.0)) / Math.PI) * 180.0;
                      	} else {
                      		tmp = 180.0 * (Math.atan((1.0 - (A / B))) / Math.PI);
                      	}
                      	return tmp;
                      }
                      
                      def code(A, B, C):
                      	tmp = 0
                      	if A <= -3.9e+15:
                      		tmp = (180.0 * math.atan(((B / A) * 0.5))) / math.pi
                      	elif A <= 4.5e-125:
                      		tmp = (math.atan(((C / B) + 1.0)) / math.pi) * 180.0
                      	else:
                      		tmp = 180.0 * (math.atan((1.0 - (A / B))) / math.pi)
                      	return tmp
                      
                      function code(A, B, C)
                      	tmp = 0.0
                      	if (A <= -3.9e+15)
                      		tmp = Float64(Float64(180.0 * atan(Float64(Float64(B / A) * 0.5))) / pi);
                      	elseif (A <= 4.5e-125)
                      		tmp = Float64(Float64(atan(Float64(Float64(C / B) + 1.0)) / pi) * 180.0);
                      	else
                      		tmp = Float64(180.0 * Float64(atan(Float64(1.0 - Float64(A / B))) / pi));
                      	end
                      	return tmp
                      end
                      
                      function tmp_2 = code(A, B, C)
                      	tmp = 0.0;
                      	if (A <= -3.9e+15)
                      		tmp = (180.0 * atan(((B / A) * 0.5))) / pi;
                      	elseif (A <= 4.5e-125)
                      		tmp = (atan(((C / B) + 1.0)) / pi) * 180.0;
                      	else
                      		tmp = 180.0 * (atan((1.0 - (A / B))) / pi);
                      	end
                      	tmp_2 = tmp;
                      end
                      
                      code[A_, B_, C_] := If[LessEqual[A, -3.9e+15], N[(N[(180.0 * N[ArcTan[N[(N[(B / A), $MachinePrecision] * 0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision], If[LessEqual[A, 4.5e-125], N[(N[(N[ArcTan[N[(N[(C / B), $MachinePrecision] + 1.0), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision] * 180.0), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]
                      
                      \begin{array}{l}
                      
                      \\
                      \begin{array}{l}
                      \mathbf{if}\;A \leq -3.9 \cdot 10^{+15}:\\
                      \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi}\\
                      
                      \mathbf{elif}\;A \leq 4.5 \cdot 10^{-125}:\\
                      \;\;\;\;\frac{\tan^{-1} \left(\frac{C}{B} + 1\right)}{\pi} \cdot 180\\
                      
                      \mathbf{else}:\\
                      \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\
                      
                      
                      \end{array}
                      \end{array}
                      
                      Derivation
                      1. Split input into 3 regimes
                      2. if A < -3.9e15

                        1. Initial program 13.9%

                          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                        2. Add Preprocessing
                        3. Taylor expanded in A around -inf

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1}{2} \cdot \frac{B}{A}\right)}}{\pi} \]
                        4. Step-by-step derivation
                          1. *-commutativeN/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \color{blue}{\frac{1}{2}}\right)}{\pi} \]
                          2. lower-*.f64N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \color{blue}{\frac{1}{2}}\right)}{\pi} \]
                          3. lower-/.f6474.1

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \]
                        5. Applied rewrites74.1%

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{B}{A} \cdot 0.5\right)}}{\pi} \]
                        6. Step-by-step derivation
                          1. lift-*.f64N/A

                            \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                          2. lift-/.f64N/A

                            \[\leadsto 180 \cdot \color{blue}{\frac{\tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                          3. associate-*r/N/A

                            \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                          4. lower-/.f64N/A

                            \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                          5. lower-*.f6474.2

                            \[\leadsto \frac{\color{blue}{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}}{\pi} \]
                        7. Applied rewrites74.2%

                          \[\leadsto \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi}} \]

                        if -3.9e15 < A < 4.50000000000000012e-125

                        1. Initial program 54.1%

                          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                        2. Add Preprocessing
                        3. Taylor expanded in B around -inf

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
                        4. Step-by-step derivation
                          1. associate--l+N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
                          2. div-subN/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                          3. lower-+.f64N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
                          4. lower-/.f64N/A

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                          5. lift--.f6445.1

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
                        5. Applied rewrites45.1%

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
                        6. Taylor expanded in A around 0

                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi} \]
                        7. Step-by-step derivation
                          1. Applied rewrites45.1%

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi} \]
                          2. Step-by-step derivation
                            1. lift-*.f64N/A

                              \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi}} \]
                            2. *-commutativeN/A

                              \[\leadsto \color{blue}{\frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi} \cdot 180} \]
                            3. lower-*.f6445.1

                              \[\leadsto \color{blue}{\frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi} \cdot 180} \]
                            4. lift-+.f64N/A

                              \[\leadsto \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C}{B}}\right)}{\pi} \cdot 180 \]
                            5. +-commutativeN/A

                              \[\leadsto \frac{\tan^{-1} \left(\frac{C}{B} + \color{blue}{1}\right)}{\pi} \cdot 180 \]
                            6. lower-+.f6445.1

                              \[\leadsto \frac{\tan^{-1} \left(\frac{C}{B} + \color{blue}{1}\right)}{\pi} \cdot 180 \]
                          3. Applied rewrites45.1%

                            \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{C}{B} + 1\right)}{\pi} \cdot 180} \]

                          if 4.50000000000000012e-125 < A

                          1. Initial program 74.8%

                            \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                          2. Add Preprocessing
                          3. Taylor expanded in B around -inf

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
                          4. Step-by-step derivation
                            1. associate--l+N/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
                            2. div-subN/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                            3. lower-+.f64N/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
                            4. lower-/.f64N/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                            5. lift--.f6470.8

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
                          5. Applied rewrites70.8%

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
                          6. Taylor expanded in C around 0

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]
                          7. Step-by-step derivation
                            1. lower--.f64N/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{\color{blue}{B}}\right)}{\pi} \]
                            2. lift-/.f6465.8

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi} \]
                          8. Applied rewrites65.8%

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]
                        8. Recombined 3 regimes into one program.
                        9. Add Preprocessing

                        Alternative 9: 58.8% accurate, 2.2× speedup?

                        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;A \leq -3.9 \cdot 10^{+15}:\\ \;\;\;\;\frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \cdot 180\\ \mathbf{elif}\;A \leq 4.5 \cdot 10^{-125}:\\ \;\;\;\;\frac{\tan^{-1} \left(\frac{C}{B} + 1\right)}{\pi} \cdot 180\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \end{array} \end{array} \]
                        (FPCore (A B C)
                         :precision binary64
                         (if (<= A -3.9e+15)
                           (* (/ (atan (* (/ B A) 0.5)) PI) 180.0)
                           (if (<= A 4.5e-125)
                             (* (/ (atan (+ (/ C B) 1.0)) PI) 180.0)
                             (* 180.0 (/ (atan (- 1.0 (/ A B))) PI)))))
                        double code(double A, double B, double C) {
                        	double tmp;
                        	if (A <= -3.9e+15) {
                        		tmp = (atan(((B / A) * 0.5)) / ((double) M_PI)) * 180.0;
                        	} else if (A <= 4.5e-125) {
                        		tmp = (atan(((C / B) + 1.0)) / ((double) M_PI)) * 180.0;
                        	} else {
                        		tmp = 180.0 * (atan((1.0 - (A / B))) / ((double) M_PI));
                        	}
                        	return tmp;
                        }
                        
                        public static double code(double A, double B, double C) {
                        	double tmp;
                        	if (A <= -3.9e+15) {
                        		tmp = (Math.atan(((B / A) * 0.5)) / Math.PI) * 180.0;
                        	} else if (A <= 4.5e-125) {
                        		tmp = (Math.atan(((C / B) + 1.0)) / Math.PI) * 180.0;
                        	} else {
                        		tmp = 180.0 * (Math.atan((1.0 - (A / B))) / Math.PI);
                        	}
                        	return tmp;
                        }
                        
                        def code(A, B, C):
                        	tmp = 0
                        	if A <= -3.9e+15:
                        		tmp = (math.atan(((B / A) * 0.5)) / math.pi) * 180.0
                        	elif A <= 4.5e-125:
                        		tmp = (math.atan(((C / B) + 1.0)) / math.pi) * 180.0
                        	else:
                        		tmp = 180.0 * (math.atan((1.0 - (A / B))) / math.pi)
                        	return tmp
                        
                        function code(A, B, C)
                        	tmp = 0.0
                        	if (A <= -3.9e+15)
                        		tmp = Float64(Float64(atan(Float64(Float64(B / A) * 0.5)) / pi) * 180.0);
                        	elseif (A <= 4.5e-125)
                        		tmp = Float64(Float64(atan(Float64(Float64(C / B) + 1.0)) / pi) * 180.0);
                        	else
                        		tmp = Float64(180.0 * Float64(atan(Float64(1.0 - Float64(A / B))) / pi));
                        	end
                        	return tmp
                        end
                        
                        function tmp_2 = code(A, B, C)
                        	tmp = 0.0;
                        	if (A <= -3.9e+15)
                        		tmp = (atan(((B / A) * 0.5)) / pi) * 180.0;
                        	elseif (A <= 4.5e-125)
                        		tmp = (atan(((C / B) + 1.0)) / pi) * 180.0;
                        	else
                        		tmp = 180.0 * (atan((1.0 - (A / B))) / pi);
                        	end
                        	tmp_2 = tmp;
                        end
                        
                        code[A_, B_, C_] := If[LessEqual[A, -3.9e+15], N[(N[(N[ArcTan[N[(N[(B / A), $MachinePrecision] * 0.5), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision] * 180.0), $MachinePrecision], If[LessEqual[A, 4.5e-125], N[(N[(N[ArcTan[N[(N[(C / B), $MachinePrecision] + 1.0), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision] * 180.0), $MachinePrecision], N[(180.0 * N[(N[ArcTan[N[(1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]
                        
                        \begin{array}{l}
                        
                        \\
                        \begin{array}{l}
                        \mathbf{if}\;A \leq -3.9 \cdot 10^{+15}:\\
                        \;\;\;\;\frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \cdot 180\\
                        
                        \mathbf{elif}\;A \leq 4.5 \cdot 10^{-125}:\\
                        \;\;\;\;\frac{\tan^{-1} \left(\frac{C}{B} + 1\right)}{\pi} \cdot 180\\
                        
                        \mathbf{else}:\\
                        \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\
                        
                        
                        \end{array}
                        \end{array}
                        
                        Derivation
                        1. Split input into 3 regimes
                        2. if A < -3.9e15

                          1. Initial program 13.9%

                            \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                          2. Add Preprocessing
                          3. Taylor expanded in A around -inf

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{1}{2} \cdot \frac{B}{A}\right)}}{\pi} \]
                          4. Step-by-step derivation
                            1. *-commutativeN/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \color{blue}{\frac{1}{2}}\right)}{\pi} \]
                            2. lower-*.f64N/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \color{blue}{\frac{1}{2}}\right)}{\pi} \]
                            3. lower-/.f6474.1

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \]
                          5. Applied rewrites74.1%

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{B}{A} \cdot 0.5\right)}}{\pi} \]
                          6. Step-by-step derivation
                            1. lift-*.f64N/A

                              \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi}} \]
                            2. *-commutativeN/A

                              \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{B}{A} \cdot \frac{1}{2}\right)}{\pi} \cdot 180} \]
                            3. lower-*.f6474.1

                              \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \cdot 180} \]
                          7. Applied rewrites74.1%

                            \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{B}{A} \cdot 0.5\right)}{\pi} \cdot 180} \]

                          if -3.9e15 < A < 4.50000000000000012e-125

                          1. Initial program 54.1%

                            \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                          2. Add Preprocessing
                          3. Taylor expanded in B around -inf

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
                          4. Step-by-step derivation
                            1. associate--l+N/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
                            2. div-subN/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                            3. lower-+.f64N/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
                            4. lower-/.f64N/A

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                            5. lift--.f6445.1

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
                          5. Applied rewrites45.1%

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
                          6. Taylor expanded in A around 0

                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi} \]
                          7. Step-by-step derivation
                            1. Applied rewrites45.1%

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi} \]
                            2. Step-by-step derivation
                              1. lift-*.f64N/A

                                \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi}} \]
                              2. *-commutativeN/A

                                \[\leadsto \color{blue}{\frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi} \cdot 180} \]
                              3. lower-*.f6445.1

                                \[\leadsto \color{blue}{\frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi} \cdot 180} \]
                              4. lift-+.f64N/A

                                \[\leadsto \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C}{B}}\right)}{\pi} \cdot 180 \]
                              5. +-commutativeN/A

                                \[\leadsto \frac{\tan^{-1} \left(\frac{C}{B} + \color{blue}{1}\right)}{\pi} \cdot 180 \]
                              6. lower-+.f6445.1

                                \[\leadsto \frac{\tan^{-1} \left(\frac{C}{B} + \color{blue}{1}\right)}{\pi} \cdot 180 \]
                            3. Applied rewrites45.1%

                              \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{C}{B} + 1\right)}{\pi} \cdot 180} \]

                            if 4.50000000000000012e-125 < A

                            1. Initial program 74.8%

                              \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                            2. Add Preprocessing
                            3. Taylor expanded in B around -inf

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
                            4. Step-by-step derivation
                              1. associate--l+N/A

                                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
                              2. div-subN/A

                                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                              3. lower-+.f64N/A

                                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
                              4. lower-/.f64N/A

                                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                              5. lift--.f6470.8

                                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
                            5. Applied rewrites70.8%

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
                            6. Taylor expanded in C around 0

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]
                            7. Step-by-step derivation
                              1. lower--.f64N/A

                                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{\color{blue}{B}}\right)}{\pi} \]
                              2. lift-/.f6465.8

                                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi} \]
                            8. Applied rewrites65.8%

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]
                          8. Recombined 3 regimes into one program.
                          9. Add Preprocessing

                          Alternative 10: 50.6% accurate, 2.4× speedup?

                          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq 5.6 \cdot 10^{-228}:\\ \;\;\;\;\frac{\tan^{-1} \left(\frac{C}{B} + 1\right)}{\pi} \cdot 180\\ \mathbf{elif}\;B \leq 4.3 \cdot 10^{-148}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{0}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
                          (FPCore (A B C)
                           :precision binary64
                           (if (<= B 5.6e-228)
                             (* (/ (atan (+ (/ C B) 1.0)) PI) 180.0)
                             (if (<= B 4.3e-148)
                               (* 180.0 (/ (atan (/ 0.0 B)) PI))
                               (* 180.0 (/ (atan -1.0) PI)))))
                          double code(double A, double B, double C) {
                          	double tmp;
                          	if (B <= 5.6e-228) {
                          		tmp = (atan(((C / B) + 1.0)) / ((double) M_PI)) * 180.0;
                          	} else if (B <= 4.3e-148) {
                          		tmp = 180.0 * (atan((0.0 / B)) / ((double) M_PI));
                          	} else {
                          		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
                          	}
                          	return tmp;
                          }
                          
                          public static double code(double A, double B, double C) {
                          	double tmp;
                          	if (B <= 5.6e-228) {
                          		tmp = (Math.atan(((C / B) + 1.0)) / Math.PI) * 180.0;
                          	} else if (B <= 4.3e-148) {
                          		tmp = 180.0 * (Math.atan((0.0 / B)) / Math.PI);
                          	} else {
                          		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
                          	}
                          	return tmp;
                          }
                          
                          def code(A, B, C):
                          	tmp = 0
                          	if B <= 5.6e-228:
                          		tmp = (math.atan(((C / B) + 1.0)) / math.pi) * 180.0
                          	elif B <= 4.3e-148:
                          		tmp = 180.0 * (math.atan((0.0 / B)) / math.pi)
                          	else:
                          		tmp = 180.0 * (math.atan(-1.0) / math.pi)
                          	return tmp
                          
                          function code(A, B, C)
                          	tmp = 0.0
                          	if (B <= 5.6e-228)
                          		tmp = Float64(Float64(atan(Float64(Float64(C / B) + 1.0)) / pi) * 180.0);
                          	elseif (B <= 4.3e-148)
                          		tmp = Float64(180.0 * Float64(atan(Float64(0.0 / B)) / pi));
                          	else
                          		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
                          	end
                          	return tmp
                          end
                          
                          function tmp_2 = code(A, B, C)
                          	tmp = 0.0;
                          	if (B <= 5.6e-228)
                          		tmp = (atan(((C / B) + 1.0)) / pi) * 180.0;
                          	elseif (B <= 4.3e-148)
                          		tmp = 180.0 * (atan((0.0 / B)) / pi);
                          	else
                          		tmp = 180.0 * (atan(-1.0) / pi);
                          	end
                          	tmp_2 = tmp;
                          end
                          
                          code[A_, B_, C_] := If[LessEqual[B, 5.6e-228], N[(N[(N[ArcTan[N[(N[(C / B), $MachinePrecision] + 1.0), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision] * 180.0), $MachinePrecision], If[LessEqual[B, 4.3e-148], N[(180.0 * N[(N[ArcTan[N[(0.0 / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]
                          
                          \begin{array}{l}
                          
                          \\
                          \begin{array}{l}
                          \mathbf{if}\;B \leq 5.6 \cdot 10^{-228}:\\
                          \;\;\;\;\frac{\tan^{-1} \left(\frac{C}{B} + 1\right)}{\pi} \cdot 180\\
                          
                          \mathbf{elif}\;B \leq 4.3 \cdot 10^{-148}:\\
                          \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{0}{B}\right)}{\pi}\\
                          
                          \mathbf{else}:\\
                          \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
                          
                          
                          \end{array}
                          \end{array}
                          
                          Derivation
                          1. Split input into 3 regimes
                          2. if B < 5.6000000000000005e-228

                            1. Initial program 58.8%

                              \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                            2. Add Preprocessing
                            3. Taylor expanded in B around -inf

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
                            4. Step-by-step derivation
                              1. associate--l+N/A

                                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
                              2. div-subN/A

                                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                              3. lower-+.f64N/A

                                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
                              4. lower-/.f64N/A

                                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                              5. lift--.f6469.3

                                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
                            5. Applied rewrites69.3%

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
                            6. Taylor expanded in A around 0

                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi} \]
                            7. Step-by-step derivation
                              1. Applied rewrites58.9%

                                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi} \]
                              2. Step-by-step derivation
                                1. lift-*.f64N/A

                                  \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi}} \]
                                2. *-commutativeN/A

                                  \[\leadsto \color{blue}{\frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi} \cdot 180} \]
                                3. lower-*.f6458.9

                                  \[\leadsto \color{blue}{\frac{\tan^{-1} \left(1 + \frac{C}{B}\right)}{\pi} \cdot 180} \]
                                4. lift-+.f64N/A

                                  \[\leadsto \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C}{B}}\right)}{\pi} \cdot 180 \]
                                5. +-commutativeN/A

                                  \[\leadsto \frac{\tan^{-1} \left(\frac{C}{B} + \color{blue}{1}\right)}{\pi} \cdot 180 \]
                                6. lower-+.f6458.9

                                  \[\leadsto \frac{\tan^{-1} \left(\frac{C}{B} + \color{blue}{1}\right)}{\pi} \cdot 180 \]
                              3. Applied rewrites58.9%

                                \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{C}{B} + 1\right)}{\pi} \cdot 180} \]

                              if 5.6000000000000005e-228 < B < 4.2999999999999998e-148

                              1. Initial program 20.3%

                                \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                              2. Add Preprocessing
                              3. Taylor expanded in B around inf

                                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                              4. Step-by-step derivation
                                1. Applied rewrites5.9%

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                2. Taylor expanded in C around inf

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + -1 \cdot A}{B}\right)}}{\pi} \]
                                3. Step-by-step derivation
                                  1. associate-*r/N/A

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1 \cdot \left(A + -1 \cdot A\right)}{\color{blue}{B}}\right)}{\pi} \]
                                  2. *-commutativeN/A

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(A + -1 \cdot A\right) \cdot -1}{B}\right)}{\pi} \]
                                  3. distribute-rgt1-inN/A

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-1 + 1\right) \cdot A\right) \cdot -1}{B}\right)}{\pi} \]
                                  4. metadata-evalN/A

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(0 \cdot A\right) \cdot -1}{B}\right)}{\pi} \]
                                  5. mul0-lftN/A

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{0 \cdot -1}{B}\right)}{\pi} \]
                                  6. metadata-evalN/A

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{0}{B}\right)}{\pi} \]
                                  7. mul0-lftN/A

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{0 \cdot A}{B}\right)}{\pi} \]
                                  8. lift-/.f64N/A

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{0 \cdot A}{\color{blue}{B}}\right)}{\pi} \]
                                  9. mul0-lft58.1

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{0}{B}\right)}{\pi} \]
                                4. Applied rewrites58.1%

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0}{B}\right)}}{\pi} \]

                                if 4.2999999999999998e-148 < B

                                1. Initial program 50.9%

                                  \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                2. Add Preprocessing
                                3. Taylor expanded in B around inf

                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                4. Step-by-step derivation
                                  1. Applied rewrites51.4%

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                5. Recombined 3 regimes into one program.
                                6. Add Preprocessing

                                Alternative 11: 50.3% accurate, 2.4× speedup?

                                \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq 8.5 \cdot 10^{-228}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\ \mathbf{elif}\;B \leq 4.3 \cdot 10^{-148}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{0}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
                                (FPCore (A B C)
                                 :precision binary64
                                 (if (<= B 8.5e-228)
                                   (* 180.0 (/ (atan (- 1.0 (/ A B))) PI))
                                   (if (<= B 4.3e-148)
                                     (* 180.0 (/ (atan (/ 0.0 B)) PI))
                                     (* 180.0 (/ (atan -1.0) PI)))))
                                double code(double A, double B, double C) {
                                	double tmp;
                                	if (B <= 8.5e-228) {
                                		tmp = 180.0 * (atan((1.0 - (A / B))) / ((double) M_PI));
                                	} else if (B <= 4.3e-148) {
                                		tmp = 180.0 * (atan((0.0 / B)) / ((double) M_PI));
                                	} else {
                                		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
                                	}
                                	return tmp;
                                }
                                
                                public static double code(double A, double B, double C) {
                                	double tmp;
                                	if (B <= 8.5e-228) {
                                		tmp = 180.0 * (Math.atan((1.0 - (A / B))) / Math.PI);
                                	} else if (B <= 4.3e-148) {
                                		tmp = 180.0 * (Math.atan((0.0 / B)) / Math.PI);
                                	} else {
                                		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
                                	}
                                	return tmp;
                                }
                                
                                def code(A, B, C):
                                	tmp = 0
                                	if B <= 8.5e-228:
                                		tmp = 180.0 * (math.atan((1.0 - (A / B))) / math.pi)
                                	elif B <= 4.3e-148:
                                		tmp = 180.0 * (math.atan((0.0 / B)) / math.pi)
                                	else:
                                		tmp = 180.0 * (math.atan(-1.0) / math.pi)
                                	return tmp
                                
                                function code(A, B, C)
                                	tmp = 0.0
                                	if (B <= 8.5e-228)
                                		tmp = Float64(180.0 * Float64(atan(Float64(1.0 - Float64(A / B))) / pi));
                                	elseif (B <= 4.3e-148)
                                		tmp = Float64(180.0 * Float64(atan(Float64(0.0 / B)) / pi));
                                	else
                                		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
                                	end
                                	return tmp
                                end
                                
                                function tmp_2 = code(A, B, C)
                                	tmp = 0.0;
                                	if (B <= 8.5e-228)
                                		tmp = 180.0 * (atan((1.0 - (A / B))) / pi);
                                	elseif (B <= 4.3e-148)
                                		tmp = 180.0 * (atan((0.0 / B)) / pi);
                                	else
                                		tmp = 180.0 * (atan(-1.0) / pi);
                                	end
                                	tmp_2 = tmp;
                                end
                                
                                code[A_, B_, C_] := If[LessEqual[B, 8.5e-228], N[(180.0 * N[(N[ArcTan[N[(1.0 - N[(A / B), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[B, 4.3e-148], N[(180.0 * N[(N[ArcTan[N[(0.0 / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]
                                
                                \begin{array}{l}
                                
                                \\
                                \begin{array}{l}
                                \mathbf{if}\;B \leq 8.5 \cdot 10^{-228}:\\
                                \;\;\;\;180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi}\\
                                
                                \mathbf{elif}\;B \leq 4.3 \cdot 10^{-148}:\\
                                \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{0}{B}\right)}{\pi}\\
                                
                                \mathbf{else}:\\
                                \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
                                
                                
                                \end{array}
                                \end{array}
                                
                                Derivation
                                1. Split input into 3 regimes
                                2. if B < 8.49999999999999947e-228

                                  1. Initial program 58.8%

                                    \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in B around -inf

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
                                  4. Step-by-step derivation
                                    1. associate--l+N/A

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
                                    2. div-subN/A

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                                    3. lower-+.f64N/A

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
                                    4. lower-/.f64N/A

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                                    5. lift--.f6469.3

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
                                  5. Applied rewrites69.3%

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
                                  6. Taylor expanded in C around 0

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]
                                  7. Step-by-step derivation
                                    1. lower--.f64N/A

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{\color{blue}{B}}\right)}{\pi} \]
                                    2. lift-/.f6455.6

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \frac{A}{B}\right)}{\pi} \]
                                  8. Applied rewrites55.6%

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 - \color{blue}{\frac{A}{B}}\right)}{\pi} \]

                                  if 8.49999999999999947e-228 < B < 4.2999999999999998e-148

                                  1. Initial program 20.3%

                                    \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in B around inf

                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                  4. Step-by-step derivation
                                    1. Applied rewrites5.9%

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                    2. Taylor expanded in C around inf

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + -1 \cdot A}{B}\right)}}{\pi} \]
                                    3. Step-by-step derivation
                                      1. associate-*r/N/A

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1 \cdot \left(A + -1 \cdot A\right)}{\color{blue}{B}}\right)}{\pi} \]
                                      2. *-commutativeN/A

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(A + -1 \cdot A\right) \cdot -1}{B}\right)}{\pi} \]
                                      3. distribute-rgt1-inN/A

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-1 + 1\right) \cdot A\right) \cdot -1}{B}\right)}{\pi} \]
                                      4. metadata-evalN/A

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(0 \cdot A\right) \cdot -1}{B}\right)}{\pi} \]
                                      5. mul0-lftN/A

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{0 \cdot -1}{B}\right)}{\pi} \]
                                      6. metadata-evalN/A

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{0}{B}\right)}{\pi} \]
                                      7. mul0-lftN/A

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{0 \cdot A}{B}\right)}{\pi} \]
                                      8. lift-/.f64N/A

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{0 \cdot A}{\color{blue}{B}}\right)}{\pi} \]
                                      9. mul0-lft58.1

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{0}{B}\right)}{\pi} \]
                                    4. Applied rewrites58.1%

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0}{B}\right)}}{\pi} \]

                                    if 4.2999999999999998e-148 < B

                                    1. Initial program 50.9%

                                      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                    2. Add Preprocessing
                                    3. Taylor expanded in B around inf

                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                    4. Step-by-step derivation
                                      1. Applied rewrites51.4%

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                    5. Recombined 3 regimes into one program.
                                    6. Add Preprocessing

                                    Alternative 12: 46.7% accurate, 2.1× speedup?

                                    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq -0.41:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\ \mathbf{elif}\;B \leq 5.6 \cdot 10^{-228}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C}{B}\right)}{\pi}\\ \mathbf{elif}\;B \leq 4.3 \cdot 10^{-148}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{0}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
                                    (FPCore (A B C)
                                     :precision binary64
                                     (if (<= B -0.41)
                                       (* 180.0 (/ (atan 1.0) PI))
                                       (if (<= B 5.6e-228)
                                         (* 180.0 (/ (atan (/ C B)) PI))
                                         (if (<= B 4.3e-148)
                                           (* 180.0 (/ (atan (/ 0.0 B)) PI))
                                           (* 180.0 (/ (atan -1.0) PI))))))
                                    double code(double A, double B, double C) {
                                    	double tmp;
                                    	if (B <= -0.41) {
                                    		tmp = 180.0 * (atan(1.0) / ((double) M_PI));
                                    	} else if (B <= 5.6e-228) {
                                    		tmp = 180.0 * (atan((C / B)) / ((double) M_PI));
                                    	} else if (B <= 4.3e-148) {
                                    		tmp = 180.0 * (atan((0.0 / B)) / ((double) M_PI));
                                    	} else {
                                    		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
                                    	}
                                    	return tmp;
                                    }
                                    
                                    public static double code(double A, double B, double C) {
                                    	double tmp;
                                    	if (B <= -0.41) {
                                    		tmp = 180.0 * (Math.atan(1.0) / Math.PI);
                                    	} else if (B <= 5.6e-228) {
                                    		tmp = 180.0 * (Math.atan((C / B)) / Math.PI);
                                    	} else if (B <= 4.3e-148) {
                                    		tmp = 180.0 * (Math.atan((0.0 / B)) / Math.PI);
                                    	} else {
                                    		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
                                    	}
                                    	return tmp;
                                    }
                                    
                                    def code(A, B, C):
                                    	tmp = 0
                                    	if B <= -0.41:
                                    		tmp = 180.0 * (math.atan(1.0) / math.pi)
                                    	elif B <= 5.6e-228:
                                    		tmp = 180.0 * (math.atan((C / B)) / math.pi)
                                    	elif B <= 4.3e-148:
                                    		tmp = 180.0 * (math.atan((0.0 / B)) / math.pi)
                                    	else:
                                    		tmp = 180.0 * (math.atan(-1.0) / math.pi)
                                    	return tmp
                                    
                                    function code(A, B, C)
                                    	tmp = 0.0
                                    	if (B <= -0.41)
                                    		tmp = Float64(180.0 * Float64(atan(1.0) / pi));
                                    	elseif (B <= 5.6e-228)
                                    		tmp = Float64(180.0 * Float64(atan(Float64(C / B)) / pi));
                                    	elseif (B <= 4.3e-148)
                                    		tmp = Float64(180.0 * Float64(atan(Float64(0.0 / B)) / pi));
                                    	else
                                    		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
                                    	end
                                    	return tmp
                                    end
                                    
                                    function tmp_2 = code(A, B, C)
                                    	tmp = 0.0;
                                    	if (B <= -0.41)
                                    		tmp = 180.0 * (atan(1.0) / pi);
                                    	elseif (B <= 5.6e-228)
                                    		tmp = 180.0 * (atan((C / B)) / pi);
                                    	elseif (B <= 4.3e-148)
                                    		tmp = 180.0 * (atan((0.0 / B)) / pi);
                                    	else
                                    		tmp = 180.0 * (atan(-1.0) / pi);
                                    	end
                                    	tmp_2 = tmp;
                                    end
                                    
                                    code[A_, B_, C_] := If[LessEqual[B, -0.41], N[(180.0 * N[(N[ArcTan[1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[B, 5.6e-228], N[(180.0 * N[(N[ArcTan[N[(C / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[B, 4.3e-148], N[(180.0 * N[(N[ArcTan[N[(0.0 / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]]
                                    
                                    \begin{array}{l}
                                    
                                    \\
                                    \begin{array}{l}
                                    \mathbf{if}\;B \leq -0.41:\\
                                    \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\
                                    
                                    \mathbf{elif}\;B \leq 5.6 \cdot 10^{-228}:\\
                                    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C}{B}\right)}{\pi}\\
                                    
                                    \mathbf{elif}\;B \leq 4.3 \cdot 10^{-148}:\\
                                    \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{0}{B}\right)}{\pi}\\
                                    
                                    \mathbf{else}:\\
                                    \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
                                    
                                    
                                    \end{array}
                                    \end{array}
                                    
                                    Derivation
                                    1. Split input into 4 regimes
                                    2. if B < -0.409999999999999976

                                      1. Initial program 43.4%

                                        \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                      2. Add Preprocessing
                                      3. Taylor expanded in B around -inf

                                        \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\pi} \]
                                      4. Step-by-step derivation
                                        1. Applied rewrites57.7%

                                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\pi} \]

                                        if -0.409999999999999976 < B < 5.6000000000000005e-228

                                        1. Initial program 70.2%

                                          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                        2. Add Preprocessing
                                        3. Taylor expanded in B around -inf

                                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
                                        4. Step-by-step derivation
                                          1. associate--l+N/A

                                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
                                          2. div-subN/A

                                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                                          3. lower-+.f64N/A

                                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
                                          4. lower-/.f64N/A

                                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                                          5. lift--.f6465.9

                                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
                                        5. Applied rewrites65.9%

                                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
                                        6. Taylor expanded in C around inf

                                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C}{\color{blue}{B}}\right)}{\pi} \]
                                        7. Step-by-step derivation
                                          1. lower-/.f6444.7

                                            \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C}{B}\right)}{\pi} \]
                                        8. Applied rewrites44.7%

                                          \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C}{\color{blue}{B}}\right)}{\pi} \]

                                        if 5.6000000000000005e-228 < B < 4.2999999999999998e-148

                                        1. Initial program 20.3%

                                          \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                        2. Add Preprocessing
                                        3. Taylor expanded in B around inf

                                          \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                        4. Step-by-step derivation
                                          1. Applied rewrites5.9%

                                            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                          2. Taylor expanded in C around inf

                                            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(-1 \cdot \frac{A + -1 \cdot A}{B}\right)}}{\pi} \]
                                          3. Step-by-step derivation
                                            1. associate-*r/N/A

                                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{-1 \cdot \left(A + -1 \cdot A\right)}{\color{blue}{B}}\right)}{\pi} \]
                                            2. *-commutativeN/A

                                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(A + -1 \cdot A\right) \cdot -1}{B}\right)}{\pi} \]
                                            3. distribute-rgt1-inN/A

                                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(\left(-1 + 1\right) \cdot A\right) \cdot -1}{B}\right)}{\pi} \]
                                            4. metadata-evalN/A

                                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{\left(0 \cdot A\right) \cdot -1}{B}\right)}{\pi} \]
                                            5. mul0-lftN/A

                                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{0 \cdot -1}{B}\right)}{\pi} \]
                                            6. metadata-evalN/A

                                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{0}{B}\right)}{\pi} \]
                                            7. mul0-lftN/A

                                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{0 \cdot A}{B}\right)}{\pi} \]
                                            8. lift-/.f64N/A

                                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{0 \cdot A}{\color{blue}{B}}\right)}{\pi} \]
                                            9. mul0-lft58.1

                                              \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{0}{B}\right)}{\pi} \]
                                          4. Applied rewrites58.1%

                                            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\frac{0}{B}\right)}}{\pi} \]

                                          if 4.2999999999999998e-148 < B

                                          1. Initial program 50.9%

                                            \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                          2. Add Preprocessing
                                          3. Taylor expanded in B around inf

                                            \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                          4. Step-by-step derivation
                                            1. Applied rewrites51.4%

                                              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                          5. Recombined 4 regimes into one program.
                                          6. Add Preprocessing

                                          Alternative 13: 46.1% accurate, 2.4× speedup?

                                          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq -0.41:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\ \mathbf{elif}\;B \leq 9 \cdot 10^{-97}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
                                          (FPCore (A B C)
                                           :precision binary64
                                           (if (<= B -0.41)
                                             (* 180.0 (/ (atan 1.0) PI))
                                             (if (<= B 9e-97)
                                               (* 180.0 (/ (atan (/ C B)) PI))
                                               (* 180.0 (/ (atan -1.0) PI)))))
                                          double code(double A, double B, double C) {
                                          	double tmp;
                                          	if (B <= -0.41) {
                                          		tmp = 180.0 * (atan(1.0) / ((double) M_PI));
                                          	} else if (B <= 9e-97) {
                                          		tmp = 180.0 * (atan((C / B)) / ((double) M_PI));
                                          	} else {
                                          		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
                                          	}
                                          	return tmp;
                                          }
                                          
                                          public static double code(double A, double B, double C) {
                                          	double tmp;
                                          	if (B <= -0.41) {
                                          		tmp = 180.0 * (Math.atan(1.0) / Math.PI);
                                          	} else if (B <= 9e-97) {
                                          		tmp = 180.0 * (Math.atan((C / B)) / Math.PI);
                                          	} else {
                                          		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
                                          	}
                                          	return tmp;
                                          }
                                          
                                          def code(A, B, C):
                                          	tmp = 0
                                          	if B <= -0.41:
                                          		tmp = 180.0 * (math.atan(1.0) / math.pi)
                                          	elif B <= 9e-97:
                                          		tmp = 180.0 * (math.atan((C / B)) / math.pi)
                                          	else:
                                          		tmp = 180.0 * (math.atan(-1.0) / math.pi)
                                          	return tmp
                                          
                                          function code(A, B, C)
                                          	tmp = 0.0
                                          	if (B <= -0.41)
                                          		tmp = Float64(180.0 * Float64(atan(1.0) / pi));
                                          	elseif (B <= 9e-97)
                                          		tmp = Float64(180.0 * Float64(atan(Float64(C / B)) / pi));
                                          	else
                                          		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
                                          	end
                                          	return tmp
                                          end
                                          
                                          function tmp_2 = code(A, B, C)
                                          	tmp = 0.0;
                                          	if (B <= -0.41)
                                          		tmp = 180.0 * (atan(1.0) / pi);
                                          	elseif (B <= 9e-97)
                                          		tmp = 180.0 * (atan((C / B)) / pi);
                                          	else
                                          		tmp = 180.0 * (atan(-1.0) / pi);
                                          	end
                                          	tmp_2 = tmp;
                                          end
                                          
                                          code[A_, B_, C_] := If[LessEqual[B, -0.41], N[(180.0 * N[(N[ArcTan[1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], If[LessEqual[B, 9e-97], N[(180.0 * N[(N[ArcTan[N[(C / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]]
                                          
                                          \begin{array}{l}
                                          
                                          \\
                                          \begin{array}{l}
                                          \mathbf{if}\;B \leq -0.41:\\
                                          \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\
                                          
                                          \mathbf{elif}\;B \leq 9 \cdot 10^{-97}:\\
                                          \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{C}{B}\right)}{\pi}\\
                                          
                                          \mathbf{else}:\\
                                          \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
                                          
                                          
                                          \end{array}
                                          \end{array}
                                          
                                          Derivation
                                          1. Split input into 3 regimes
                                          2. if B < -0.409999999999999976

                                            1. Initial program 43.4%

                                              \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                            2. Add Preprocessing
                                            3. Taylor expanded in B around -inf

                                              \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\pi} \]
                                            4. Step-by-step derivation
                                              1. Applied rewrites57.7%

                                                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\pi} \]

                                              if -0.409999999999999976 < B < 9.0000000000000002e-97

                                              1. Initial program 63.2%

                                                \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                              2. Add Preprocessing
                                              3. Taylor expanded in B around -inf

                                                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(\left(1 + \frac{C}{B}\right) - \frac{A}{B}\right)}}{\pi} \]
                                              4. Step-by-step derivation
                                                1. associate--l+N/A

                                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\left(\frac{C}{B} - \frac{A}{B}\right)}\right)}{\pi} \]
                                                2. div-subN/A

                                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                                                3. lower-+.f64N/A

                                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \color{blue}{\frac{C - A}{B}}\right)}{\pi} \]
                                                4. lower-/.f64N/A

                                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{\color{blue}{B}}\right)}{\pi} \]
                                                5. lift--.f6457.9

                                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(1 + \frac{C - A}{B}\right)}{\pi} \]
                                              5. Applied rewrites57.9%

                                                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{\left(1 + \frac{C - A}{B}\right)}}{\pi} \]
                                              6. Taylor expanded in C around inf

                                                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C}{\color{blue}{B}}\right)}{\pi} \]
                                              7. Step-by-step derivation
                                                1. lower-/.f6441.3

                                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C}{B}\right)}{\pi} \]
                                              8. Applied rewrites41.3%

                                                \[\leadsto 180 \cdot \frac{\tan^{-1} \left(\frac{C}{\color{blue}{B}}\right)}{\pi} \]

                                              if 9.0000000000000002e-97 < B

                                              1. Initial program 47.3%

                                                \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                              2. Add Preprocessing
                                              3. Taylor expanded in B around inf

                                                \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                              4. Step-by-step derivation
                                                1. Applied rewrites53.8%

                                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                              5. Recombined 3 regimes into one program.
                                              6. Add Preprocessing

                                              Alternative 14: 39.8% accurate, 3.3× speedup?

                                              \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;B \leq -1.45 \cdot 10^{-301}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\ \end{array} \end{array} \]
                                              (FPCore (A B C)
                                               :precision binary64
                                               (if (<= B -1.45e-301)
                                                 (* 180.0 (/ (atan 1.0) PI))
                                                 (* 180.0 (/ (atan -1.0) PI))))
                                              double code(double A, double B, double C) {
                                              	double tmp;
                                              	if (B <= -1.45e-301) {
                                              		tmp = 180.0 * (atan(1.0) / ((double) M_PI));
                                              	} else {
                                              		tmp = 180.0 * (atan(-1.0) / ((double) M_PI));
                                              	}
                                              	return tmp;
                                              }
                                              
                                              public static double code(double A, double B, double C) {
                                              	double tmp;
                                              	if (B <= -1.45e-301) {
                                              		tmp = 180.0 * (Math.atan(1.0) / Math.PI);
                                              	} else {
                                              		tmp = 180.0 * (Math.atan(-1.0) / Math.PI);
                                              	}
                                              	return tmp;
                                              }
                                              
                                              def code(A, B, C):
                                              	tmp = 0
                                              	if B <= -1.45e-301:
                                              		tmp = 180.0 * (math.atan(1.0) / math.pi)
                                              	else:
                                              		tmp = 180.0 * (math.atan(-1.0) / math.pi)
                                              	return tmp
                                              
                                              function code(A, B, C)
                                              	tmp = 0.0
                                              	if (B <= -1.45e-301)
                                              		tmp = Float64(180.0 * Float64(atan(1.0) / pi));
                                              	else
                                              		tmp = Float64(180.0 * Float64(atan(-1.0) / pi));
                                              	end
                                              	return tmp
                                              end
                                              
                                              function tmp_2 = code(A, B, C)
                                              	tmp = 0.0;
                                              	if (B <= -1.45e-301)
                                              		tmp = 180.0 * (atan(1.0) / pi);
                                              	else
                                              		tmp = 180.0 * (atan(-1.0) / pi);
                                              	end
                                              	tmp_2 = tmp;
                                              end
                                              
                                              code[A_, B_, C_] := If[LessEqual[B, -1.45e-301], N[(180.0 * N[(N[ArcTan[1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]]
                                              
                                              \begin{array}{l}
                                              
                                              \\
                                              \begin{array}{l}
                                              \mathbf{if}\;B \leq -1.45 \cdot 10^{-301}:\\
                                              \;\;\;\;180 \cdot \frac{\tan^{-1} 1}{\pi}\\
                                              
                                              \mathbf{else}:\\
                                              \;\;\;\;180 \cdot \frac{\tan^{-1} -1}{\pi}\\
                                              
                                              
                                              \end{array}
                                              \end{array}
                                              
                                              Derivation
                                              1. Split input into 2 regimes
                                              2. if B < -1.44999999999999992e-301

                                                1. Initial program 56.2%

                                                  \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                                2. Add Preprocessing
                                                3. Taylor expanded in B around -inf

                                                  \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\pi} \]
                                                4. Step-by-step derivation
                                                  1. Applied rewrites39.1%

                                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{1}}{\pi} \]

                                                  if -1.44999999999999992e-301 < B

                                                  1. Initial program 50.2%

                                                    \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                                  2. Add Preprocessing
                                                  3. Taylor expanded in B around inf

                                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                                  4. Step-by-step derivation
                                                    1. Applied rewrites40.3%

                                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                                  5. Recombined 2 regimes into one program.
                                                  6. Add Preprocessing

                                                  Alternative 15: 20.5% accurate, 4.1× speedup?

                                                  \[\begin{array}{l} \\ 180 \cdot \frac{\tan^{-1} -1}{\pi} \end{array} \]
                                                  (FPCore (A B C) :precision binary64 (* 180.0 (/ (atan -1.0) PI)))
                                                  double code(double A, double B, double C) {
                                                  	return 180.0 * (atan(-1.0) / ((double) M_PI));
                                                  }
                                                  
                                                  public static double code(double A, double B, double C) {
                                                  	return 180.0 * (Math.atan(-1.0) / Math.PI);
                                                  }
                                                  
                                                  def code(A, B, C):
                                                  	return 180.0 * (math.atan(-1.0) / math.pi)
                                                  
                                                  function code(A, B, C)
                                                  	return Float64(180.0 * Float64(atan(-1.0) / pi))
                                                  end
                                                  
                                                  function tmp = code(A, B, C)
                                                  	tmp = 180.0 * (atan(-1.0) / pi);
                                                  end
                                                  
                                                  code[A_, B_, C_] := N[(180.0 * N[(N[ArcTan[-1.0], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]
                                                  
                                                  \begin{array}{l}
                                                  
                                                  \\
                                                  180 \cdot \frac{\tan^{-1} -1}{\pi}
                                                  \end{array}
                                                  
                                                  Derivation
                                                  1. Initial program 52.9%

                                                    \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
                                                  2. Add Preprocessing
                                                  3. Taylor expanded in B around inf

                                                    \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                                  4. Step-by-step derivation
                                                    1. Applied rewrites23.0%

                                                      \[\leadsto 180 \cdot \frac{\tan^{-1} \color{blue}{-1}}{\pi} \]
                                                    2. Add Preprocessing

                                                    Reproduce

                                                    ?
                                                    herbie shell --seed 2025064 
                                                    (FPCore (A B C)
                                                      :name "ABCF->ab-angle angle"
                                                      :precision binary64
                                                      (* 180.0 (/ (atan (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))) PI)))