2-ancestry mixing, positive discriminant

Percentage Accurate: 43.4% → 96.0%
Time: 8.8s
Alternatives: 3
Speedup: 2.6×

Specification

?
\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{2 \cdot a}\\ t_1 := \sqrt{g \cdot g - h \cdot h}\\ \sqrt[3]{t\_0 \cdot \left(\left(-g\right) + t\_1\right)} + \sqrt[3]{t\_0 \cdot \left(\left(-g\right) - t\_1\right)} \end{array} \end{array} \]
(FPCore (g h a)
 :precision binary64
 (let* ((t_0 (/ 1.0 (* 2.0 a))) (t_1 (sqrt (- (* g g) (* h h)))))
   (+ (cbrt (* t_0 (+ (- g) t_1))) (cbrt (* t_0 (- (- g) t_1))))))
double code(double g, double h, double a) {
	double t_0 = 1.0 / (2.0 * a);
	double t_1 = sqrt(((g * g) - (h * h)));
	return cbrt((t_0 * (-g + t_1))) + cbrt((t_0 * (-g - t_1)));
}
public static double code(double g, double h, double a) {
	double t_0 = 1.0 / (2.0 * a);
	double t_1 = Math.sqrt(((g * g) - (h * h)));
	return Math.cbrt((t_0 * (-g + t_1))) + Math.cbrt((t_0 * (-g - t_1)));
}
function code(g, h, a)
	t_0 = Float64(1.0 / Float64(2.0 * a))
	t_1 = sqrt(Float64(Float64(g * g) - Float64(h * h)))
	return Float64(cbrt(Float64(t_0 * Float64(Float64(-g) + t_1))) + cbrt(Float64(t_0 * Float64(Float64(-g) - t_1))))
end
code[g_, h_, a_] := Block[{t$95$0 = N[(1.0 / N[(2.0 * a), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[Sqrt[N[(N[(g * g), $MachinePrecision] - N[(h * h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, N[(N[Power[N[(t$95$0 * N[((-g) + t$95$1), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(t$95$0 * N[((-g) - t$95$1), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{1}{2 \cdot a}\\
t_1 := \sqrt{g \cdot g - h \cdot h}\\
\sqrt[3]{t\_0 \cdot \left(\left(-g\right) + t\_1\right)} + \sqrt[3]{t\_0 \cdot \left(\left(-g\right) - t\_1\right)}
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 3 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 43.4% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{2 \cdot a}\\ t_1 := \sqrt{g \cdot g - h \cdot h}\\ \sqrt[3]{t\_0 \cdot \left(\left(-g\right) + t\_1\right)} + \sqrt[3]{t\_0 \cdot \left(\left(-g\right) - t\_1\right)} \end{array} \end{array} \]
(FPCore (g h a)
 :precision binary64
 (let* ((t_0 (/ 1.0 (* 2.0 a))) (t_1 (sqrt (- (* g g) (* h h)))))
   (+ (cbrt (* t_0 (+ (- g) t_1))) (cbrt (* t_0 (- (- g) t_1))))))
double code(double g, double h, double a) {
	double t_0 = 1.0 / (2.0 * a);
	double t_1 = sqrt(((g * g) - (h * h)));
	return cbrt((t_0 * (-g + t_1))) + cbrt((t_0 * (-g - t_1)));
}
public static double code(double g, double h, double a) {
	double t_0 = 1.0 / (2.0 * a);
	double t_1 = Math.sqrt(((g * g) - (h * h)));
	return Math.cbrt((t_0 * (-g + t_1))) + Math.cbrt((t_0 * (-g - t_1)));
}
function code(g, h, a)
	t_0 = Float64(1.0 / Float64(2.0 * a))
	t_1 = sqrt(Float64(Float64(g * g) - Float64(h * h)))
	return Float64(cbrt(Float64(t_0 * Float64(Float64(-g) + t_1))) + cbrt(Float64(t_0 * Float64(Float64(-g) - t_1))))
end
code[g_, h_, a_] := Block[{t$95$0 = N[(1.0 / N[(2.0 * a), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[Sqrt[N[(N[(g * g), $MachinePrecision] - N[(h * h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, N[(N[Power[N[(t$95$0 * N[((-g) + t$95$1), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(t$95$0 * N[((-g) - t$95$1), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{1}{2 \cdot a}\\
t_1 := \sqrt{g \cdot g - h \cdot h}\\
\sqrt[3]{t\_0 \cdot \left(\left(-g\right) + t\_1\right)} + \sqrt[3]{t\_0 \cdot \left(\left(-g\right) - t\_1\right)}
\end{array}
\end{array}

Alternative 1: 96.0% accurate, 1.4× speedup?

\[\begin{array}{l} \\ \frac{-\sqrt[3]{g}}{\sqrt[3]{a}} \end{array} \]
(FPCore (g h a) :precision binary64 (/ (- (cbrt g)) (cbrt a)))
double code(double g, double h, double a) {
	return -cbrt(g) / cbrt(a);
}
public static double code(double g, double h, double a) {
	return -Math.cbrt(g) / Math.cbrt(a);
}
function code(g, h, a)
	return Float64(Float64(-cbrt(g)) / cbrt(a))
end
code[g_, h_, a_] := N[((-N[Power[g, 1/3], $MachinePrecision]) / N[Power[a, 1/3], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{-\sqrt[3]{g}}{\sqrt[3]{a}}
\end{array}
Derivation
  1. Initial program 40.6%

    \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
  2. Add Preprocessing
  3. Taylor expanded in g around -inf

    \[\leadsto \color{blue}{-1 \cdot \left(\sqrt[3]{\frac{g}{a}} \cdot \left(\sqrt[3]{\frac{1}{2}} \cdot \sqrt[3]{2}\right)\right)} \]
  4. Step-by-step derivation
    1. mul-1-negN/A

      \[\leadsto \mathsf{neg}\left(\sqrt[3]{\frac{g}{a}} \cdot \left(\sqrt[3]{\frac{1}{2}} \cdot \sqrt[3]{2}\right)\right) \]
    2. lower-neg.f64N/A

      \[\leadsto -\sqrt[3]{\frac{g}{a}} \cdot \left(\sqrt[3]{\frac{1}{2}} \cdot \sqrt[3]{2}\right) \]
    3. cbrt-unprodN/A

      \[\leadsto -\sqrt[3]{\frac{g}{a}} \cdot \sqrt[3]{\frac{1}{2} \cdot 2} \]
    4. metadata-evalN/A

      \[\leadsto -\sqrt[3]{\frac{g}{a}} \cdot \sqrt[3]{1} \]
    5. metadata-evalN/A

      \[\leadsto -\sqrt[3]{\frac{g}{a}} \cdot 1 \]
    6. lower-*.f64N/A

      \[\leadsto -\sqrt[3]{\frac{g}{a}} \cdot 1 \]
    7. lower-cbrt.f64N/A

      \[\leadsto -\sqrt[3]{\frac{g}{a}} \cdot 1 \]
    8. lower-/.f6472.4

      \[\leadsto -\sqrt[3]{\frac{g}{a}} \cdot 1 \]
  5. Applied rewrites72.4%

    \[\leadsto \color{blue}{-\sqrt[3]{\frac{g}{a}} \cdot 1} \]
  6. Step-by-step derivation
    1. lift-/.f64N/A

      \[\leadsto -\sqrt[3]{\frac{g}{a}} \cdot 1 \]
    2. lift-cbrt.f64N/A

      \[\leadsto -\sqrt[3]{\frac{g}{a}} \cdot 1 \]
    3. cbrt-divN/A

      \[\leadsto -\frac{\sqrt[3]{g}}{\sqrt[3]{a}} \cdot 1 \]
    4. lower-/.f64N/A

      \[\leadsto -\frac{\sqrt[3]{g}}{\sqrt[3]{a}} \cdot 1 \]
    5. lower-cbrt.f64N/A

      \[\leadsto -\frac{\sqrt[3]{g}}{\sqrt[3]{a}} \cdot 1 \]
    6. lower-cbrt.f6495.9

      \[\leadsto -\frac{\sqrt[3]{g}}{\sqrt[3]{a}} \cdot 1 \]
  7. Applied rewrites95.9%

    \[\leadsto -\frac{\sqrt[3]{g}}{\sqrt[3]{a}} \cdot 1 \]
  8. Final simplification95.9%

    \[\leadsto \frac{-\sqrt[3]{g}}{\sqrt[3]{a}} \]
  9. Add Preprocessing

Alternative 2: 75.3% accurate, 0.7× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \sqrt{g \cdot g - h \cdot h}\\ t_1 := \frac{1}{2 \cdot a}\\ \mathbf{if}\;\sqrt[3]{t\_1 \cdot \left(\left(-g\right) + t\_0\right)} + \sqrt[3]{\left(-t\_1\right) \cdot \left(g + t\_0\right)} \leq -5 \cdot 10^{+98}:\\ \;\;\;\;g \cdot \left(0 + \sqrt[3]{\frac{-2}{a \cdot \left(g \cdot g\right)} \cdot 0.5}\right)\\ \mathbf{else}:\\ \;\;\;\;-\sqrt[3]{\frac{g}{a}}\\ \end{array} \end{array} \]
(FPCore (g h a)
 :precision binary64
 (let* ((t_0 (sqrt (- (* g g) (* h h)))) (t_1 (/ 1.0 (* 2.0 a))))
   (if (<=
        (+ (cbrt (* t_1 (+ (- g) t_0))) (cbrt (* (- t_1) (+ g t_0))))
        -5e+98)
     (* g (+ 0.0 (cbrt (* (/ -2.0 (* a (* g g))) 0.5))))
     (- (cbrt (/ g a))))))
double code(double g, double h, double a) {
	double t_0 = sqrt(((g * g) - (h * h)));
	double t_1 = 1.0 / (2.0 * a);
	double tmp;
	if ((cbrt((t_1 * (-g + t_0))) + cbrt((-t_1 * (g + t_0)))) <= -5e+98) {
		tmp = g * (0.0 + cbrt(((-2.0 / (a * (g * g))) * 0.5)));
	} else {
		tmp = -cbrt((g / a));
	}
	return tmp;
}
public static double code(double g, double h, double a) {
	double t_0 = Math.sqrt(((g * g) - (h * h)));
	double t_1 = 1.0 / (2.0 * a);
	double tmp;
	if ((Math.cbrt((t_1 * (-g + t_0))) + Math.cbrt((-t_1 * (g + t_0)))) <= -5e+98) {
		tmp = g * (0.0 + Math.cbrt(((-2.0 / (a * (g * g))) * 0.5)));
	} else {
		tmp = -Math.cbrt((g / a));
	}
	return tmp;
}
function code(g, h, a)
	t_0 = sqrt(Float64(Float64(g * g) - Float64(h * h)))
	t_1 = Float64(1.0 / Float64(2.0 * a))
	tmp = 0.0
	if (Float64(cbrt(Float64(t_1 * Float64(Float64(-g) + t_0))) + cbrt(Float64(Float64(-t_1) * Float64(g + t_0)))) <= -5e+98)
		tmp = Float64(g * Float64(0.0 + cbrt(Float64(Float64(-2.0 / Float64(a * Float64(g * g))) * 0.5))));
	else
		tmp = Float64(-cbrt(Float64(g / a)));
	end
	return tmp
end
code[g_, h_, a_] := Block[{t$95$0 = N[Sqrt[N[(N[(g * g), $MachinePrecision] - N[(h * h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, Block[{t$95$1 = N[(1.0 / N[(2.0 * a), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[(N[Power[N[(t$95$1 * N[((-g) + t$95$0), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[((-t$95$1) * N[(g + t$95$0), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision], -5e+98], N[(g * N[(0.0 + N[Power[N[(N[(-2.0 / N[(a * N[(g * g), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * 0.5), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], (-N[Power[N[(g / a), $MachinePrecision], 1/3], $MachinePrecision])]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \sqrt{g \cdot g - h \cdot h}\\
t_1 := \frac{1}{2 \cdot a}\\
\mathbf{if}\;\sqrt[3]{t\_1 \cdot \left(\left(-g\right) + t\_0\right)} + \sqrt[3]{\left(-t\_1\right) \cdot \left(g + t\_0\right)} \leq -5 \cdot 10^{+98}:\\
\;\;\;\;g \cdot \left(0 + \sqrt[3]{\frac{-2}{a \cdot \left(g \cdot g\right)} \cdot 0.5}\right)\\

\mathbf{else}:\\
\;\;\;\;-\sqrt[3]{\frac{g}{a}}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (+.f64 (cbrt.f64 (*.f64 (/.f64 #s(literal 1 binary64) (*.f64 #s(literal 2 binary64) a)) (+.f64 (neg.f64 g) (sqrt.f64 (-.f64 (*.f64 g g) (*.f64 h h)))))) (cbrt.f64 (*.f64 (/.f64 #s(literal 1 binary64) (*.f64 #s(literal 2 binary64) a)) (-.f64 (neg.f64 g) (sqrt.f64 (-.f64 (*.f64 g g) (*.f64 h h))))))) < -4.9999999999999998e98

    1. Initial program 21.4%

      \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in a around 0

      \[\leadsto \color{blue}{\frac{\sqrt[3]{{a}^{2} \cdot \left(g + \sqrt{{g}^{2} - {h}^{2}}\right)} \cdot \sqrt[3]{\frac{-1}{2}} + \sqrt[3]{{a}^{2} \cdot \left(\sqrt{{g}^{2} - {h}^{2}} - g\right)} \cdot \sqrt[3]{\frac{1}{2}}}{a}} \]
    4. Step-by-step derivation
      1. lower-/.f64N/A

        \[\leadsto \frac{\sqrt[3]{{a}^{2} \cdot \left(g + \sqrt{{g}^{2} - {h}^{2}}\right)} \cdot \sqrt[3]{\frac{-1}{2}} + \sqrt[3]{{a}^{2} \cdot \left(\sqrt{{g}^{2} - {h}^{2}} - g\right)} \cdot \sqrt[3]{\frac{1}{2}}}{\color{blue}{a}} \]
    5. Applied rewrites7.1%

      \[\leadsto \color{blue}{\frac{\sqrt[3]{\left(\left(\sqrt{\left(g + h\right) \cdot \left(g - h\right)} - g\right) \cdot \left(a \cdot a\right)\right) \cdot 0.5} + \sqrt[3]{\left(\left(\sqrt{\left(g + h\right) \cdot \left(g - h\right)} + g\right) \cdot \left(a \cdot a\right)\right) \cdot -0.5}}{a}} \]
    6. Taylor expanded in a around -inf

      \[\leadsto -1 \cdot \color{blue}{\left(\sqrt[3]{\frac{g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}}{a}} \cdot \left(\sqrt[3]{-1} \cdot \sqrt[3]{\frac{-1}{2}}\right) + \sqrt[3]{\frac{\sqrt{\left(g + h\right) \cdot \left(g - h\right)} - g}{a}} \cdot \left(\sqrt[3]{-1} \cdot \sqrt[3]{\frac{1}{2}}\right)\right)} \]
    7. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\sqrt[3]{\frac{g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}}{a}} \cdot \left(\sqrt[3]{-1} \cdot \sqrt[3]{\frac{-1}{2}}\right) + \color{blue}{\sqrt[3]{\frac{\sqrt{\left(g + h\right) \cdot \left(g - h\right)} - g}{a}} \cdot \left(\sqrt[3]{-1} \cdot \sqrt[3]{\frac{1}{2}}\right)}\right) \]
      2. lower-+.f64N/A

        \[\leadsto -1 \cdot \left(\sqrt[3]{\frac{g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}}{a}} \cdot \left(\sqrt[3]{-1} \cdot \sqrt[3]{\frac{-1}{2}}\right) + \sqrt[3]{\frac{\sqrt{\left(g + h\right) \cdot \left(g - h\right)} - g}{a}} \cdot \color{blue}{\left(\sqrt[3]{-1} \cdot \sqrt[3]{\frac{1}{2}}\right)}\right) \]
    8. Applied rewrites21.3%

      \[\leadsto -1 \cdot \color{blue}{\left(\sqrt[3]{\frac{g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}}{a}} \cdot \sqrt[3]{0.5} + \sqrt[3]{\frac{\sqrt{\left(g + h\right) \cdot \left(g - h\right)} - g}{a}} \cdot \sqrt[3]{-0.5}\right)} \]
    9. Taylor expanded in g around -inf

      \[\leadsto g \cdot \left(\sqrt[3]{\frac{1 + {\left(\sqrt{-1}\right)}^{2}}{a \cdot {g}^{2}}} \cdot \sqrt[3]{\frac{-1}{2}} + \color{blue}{\sqrt[3]{\frac{{\left(\sqrt{-1}\right)}^{2} - 1}{a \cdot {g}^{2}}} \cdot \sqrt[3]{\frac{1}{2}}}\right) \]
    10. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto g \cdot \left(\sqrt[3]{\frac{1 + {\left(\sqrt{-1}\right)}^{2}}{a \cdot {g}^{2}}} \cdot \sqrt[3]{\frac{-1}{2}} + \sqrt[3]{\frac{{\left(\sqrt{-1}\right)}^{2} - 1}{a \cdot {g}^{2}}} \cdot \color{blue}{\sqrt[3]{\frac{1}{2}}}\right) \]
      2. lower-+.f64N/A

        \[\leadsto g \cdot \left(\sqrt[3]{\frac{1 + {\left(\sqrt{-1}\right)}^{2}}{a \cdot {g}^{2}}} \cdot \sqrt[3]{\frac{-1}{2}} + \sqrt[3]{\frac{{\left(\sqrt{-1}\right)}^{2} - 1}{a \cdot {g}^{2}}} \cdot \sqrt[3]{\frac{1}{2}}\right) \]
    11. Applied rewrites99.1%

      \[\leadsto g \cdot \left(\sqrt[3]{\frac{0}{a \cdot \left(g \cdot g\right)} \cdot -0.5} + \color{blue}{\sqrt[3]{\frac{-2}{a \cdot \left(g \cdot g\right)} \cdot 0.5}}\right) \]
    12. Taylor expanded in g around 0

      \[\leadsto g \cdot \left(0 + \sqrt[3]{\frac{-2}{a \cdot \left(g \cdot g\right)} \cdot \frac{1}{2}}\right) \]
    13. Step-by-step derivation
      1. Applied rewrites99.1%

        \[\leadsto g \cdot \left(0 + \sqrt[3]{\frac{-2}{a \cdot \left(g \cdot g\right)} \cdot 0.5}\right) \]

      if -4.9999999999999998e98 < (+.f64 (cbrt.f64 (*.f64 (/.f64 #s(literal 1 binary64) (*.f64 #s(literal 2 binary64) a)) (+.f64 (neg.f64 g) (sqrt.f64 (-.f64 (*.f64 g g) (*.f64 h h)))))) (cbrt.f64 (*.f64 (/.f64 #s(literal 1 binary64) (*.f64 #s(literal 2 binary64) a)) (-.f64 (neg.f64 g) (sqrt.f64 (-.f64 (*.f64 g g) (*.f64 h h)))))))

      1. Initial program 41.4%

        \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
      2. Add Preprocessing
      3. Taylor expanded in g around -inf

        \[\leadsto \color{blue}{-1 \cdot \left(\sqrt[3]{\frac{g}{a}} \cdot \left(\sqrt[3]{\frac{1}{2}} \cdot \sqrt[3]{2}\right)\right)} \]
      4. Step-by-step derivation
        1. mul-1-negN/A

          \[\leadsto \mathsf{neg}\left(\sqrt[3]{\frac{g}{a}} \cdot \left(\sqrt[3]{\frac{1}{2}} \cdot \sqrt[3]{2}\right)\right) \]
        2. lower-neg.f64N/A

          \[\leadsto -\sqrt[3]{\frac{g}{a}} \cdot \left(\sqrt[3]{\frac{1}{2}} \cdot \sqrt[3]{2}\right) \]
        3. cbrt-unprodN/A

          \[\leadsto -\sqrt[3]{\frac{g}{a}} \cdot \sqrt[3]{\frac{1}{2} \cdot 2} \]
        4. metadata-evalN/A

          \[\leadsto -\sqrt[3]{\frac{g}{a}} \cdot \sqrt[3]{1} \]
        5. metadata-evalN/A

          \[\leadsto -\sqrt[3]{\frac{g}{a}} \cdot 1 \]
        6. lower-*.f64N/A

          \[\leadsto -\sqrt[3]{\frac{g}{a}} \cdot 1 \]
        7. lower-cbrt.f64N/A

          \[\leadsto -\sqrt[3]{\frac{g}{a}} \cdot 1 \]
        8. lower-/.f6474.7

          \[\leadsto -\sqrt[3]{\frac{g}{a}} \cdot 1 \]
      5. Applied rewrites74.7%

        \[\leadsto \color{blue}{-\sqrt[3]{\frac{g}{a}} \cdot 1} \]
      6. Taylor expanded in g around 0

        \[\leadsto -\sqrt[3]{\frac{g}{a}} \]
      7. Step-by-step derivation
        1. lift-cbrt.f64N/A

          \[\leadsto -\sqrt[3]{\frac{g}{a}} \]
        2. lift-/.f6474.7

          \[\leadsto -\sqrt[3]{\frac{g}{a}} \]
      8. Applied rewrites74.7%

        \[\leadsto -\sqrt[3]{\frac{g}{a}} \]
    14. Recombined 2 regimes into one program.
    15. Final simplification75.7%

      \[\leadsto \begin{array}{l} \mathbf{if}\;\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\left(-\frac{1}{2 \cdot a}\right) \cdot \left(g + \sqrt{g \cdot g - h \cdot h}\right)} \leq -5 \cdot 10^{+98}:\\ \;\;\;\;g \cdot \left(0 + \sqrt[3]{\frac{-2}{a \cdot \left(g \cdot g\right)} \cdot 0.5}\right)\\ \mathbf{else}:\\ \;\;\;\;-\sqrt[3]{\frac{g}{a}}\\ \end{array} \]
    16. Add Preprocessing

    Alternative 3: 73.5% accurate, 2.6× speedup?

    \[\begin{array}{l} \\ -\sqrt[3]{\frac{g}{a}} \end{array} \]
    (FPCore (g h a) :precision binary64 (- (cbrt (/ g a))))
    double code(double g, double h, double a) {
    	return -cbrt((g / a));
    }
    
    public static double code(double g, double h, double a) {
    	return -Math.cbrt((g / a));
    }
    
    function code(g, h, a)
    	return Float64(-cbrt(Float64(g / a)))
    end
    
    code[g_, h_, a_] := (-N[Power[N[(g / a), $MachinePrecision], 1/3], $MachinePrecision])
    
    \begin{array}{l}
    
    \\
    -\sqrt[3]{\frac{g}{a}}
    \end{array}
    
    Derivation
    1. Initial program 40.6%

      \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in g around -inf

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt[3]{\frac{g}{a}} \cdot \left(\sqrt[3]{\frac{1}{2}} \cdot \sqrt[3]{2}\right)\right)} \]
    4. Step-by-step derivation
      1. mul-1-negN/A

        \[\leadsto \mathsf{neg}\left(\sqrt[3]{\frac{g}{a}} \cdot \left(\sqrt[3]{\frac{1}{2}} \cdot \sqrt[3]{2}\right)\right) \]
      2. lower-neg.f64N/A

        \[\leadsto -\sqrt[3]{\frac{g}{a}} \cdot \left(\sqrt[3]{\frac{1}{2}} \cdot \sqrt[3]{2}\right) \]
      3. cbrt-unprodN/A

        \[\leadsto -\sqrt[3]{\frac{g}{a}} \cdot \sqrt[3]{\frac{1}{2} \cdot 2} \]
      4. metadata-evalN/A

        \[\leadsto -\sqrt[3]{\frac{g}{a}} \cdot \sqrt[3]{1} \]
      5. metadata-evalN/A

        \[\leadsto -\sqrt[3]{\frac{g}{a}} \cdot 1 \]
      6. lower-*.f64N/A

        \[\leadsto -\sqrt[3]{\frac{g}{a}} \cdot 1 \]
      7. lower-cbrt.f64N/A

        \[\leadsto -\sqrt[3]{\frac{g}{a}} \cdot 1 \]
      8. lower-/.f6472.4

        \[\leadsto -\sqrt[3]{\frac{g}{a}} \cdot 1 \]
    5. Applied rewrites72.4%

      \[\leadsto \color{blue}{-\sqrt[3]{\frac{g}{a}} \cdot 1} \]
    6. Taylor expanded in g around 0

      \[\leadsto -\sqrt[3]{\frac{g}{a}} \]
    7. Step-by-step derivation
      1. lift-cbrt.f64N/A

        \[\leadsto -\sqrt[3]{\frac{g}{a}} \]
      2. lift-/.f6472.4

        \[\leadsto -\sqrt[3]{\frac{g}{a}} \]
    8. Applied rewrites72.4%

      \[\leadsto -\sqrt[3]{\frac{g}{a}} \]
    9. Add Preprocessing

    Reproduce

    ?
    herbie shell --seed 2025058 
    (FPCore (g h a)
      :name "2-ancestry mixing, positive discriminant"
      :precision binary64
      (+ (cbrt (* (/ 1.0 (* 2.0 a)) (+ (- g) (sqrt (- (* g g) (* h h)))))) (cbrt (* (/ 1.0 (* 2.0 a)) (- (- g) (sqrt (- (* g g) (* h h))))))))