ABCF->ab-angle b

Percentage Accurate: 19.4% → 46.6%
Time: 25.1s
Alternatives: 8
Speedup: N/A×

Specification

?
\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (- (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
module fmin_fmax_functions
    implicit none
    private
    public fmax
    public fmin

    interface fmax
        module procedure fmax88
        module procedure fmax44
        module procedure fmax84
        module procedure fmax48
    end interface
    interface fmin
        module procedure fmin88
        module procedure fmin44
        module procedure fmin84
        module procedure fmin48
    end interface
contains
    real(8) function fmax88(x, y) result (res)
        real(8), intent (in) :: x
        real(8), intent (in) :: y
        res = merge(y, merge(x, max(x, y), y /= y), x /= x)
    end function
    real(4) function fmax44(x, y) result (res)
        real(4), intent (in) :: x
        real(4), intent (in) :: y
        res = merge(y, merge(x, max(x, y), y /= y), x /= x)
    end function
    real(8) function fmax84(x, y) result(res)
        real(8), intent (in) :: x
        real(4), intent (in) :: y
        res = merge(dble(y), merge(x, max(x, dble(y)), y /= y), x /= x)
    end function
    real(8) function fmax48(x, y) result(res)
        real(4), intent (in) :: x
        real(8), intent (in) :: y
        res = merge(y, merge(dble(x), max(dble(x), y), y /= y), x /= x)
    end function
    real(8) function fmin88(x, y) result (res)
        real(8), intent (in) :: x
        real(8), intent (in) :: y
        res = merge(y, merge(x, min(x, y), y /= y), x /= x)
    end function
    real(4) function fmin44(x, y) result (res)
        real(4), intent (in) :: x
        real(4), intent (in) :: y
        res = merge(y, merge(x, min(x, y), y /= y), x /= x)
    end function
    real(8) function fmin84(x, y) result(res)
        real(8), intent (in) :: x
        real(4), intent (in) :: y
        res = merge(dble(y), merge(x, min(x, dble(y)), y /= y), x /= x)
    end function
    real(8) function fmin48(x, y) result(res)
        real(4), intent (in) :: x
        real(8), intent (in) :: y
        res = merge(y, merge(dble(x), min(dble(x), y), y /= y), x /= x)
    end function
end module

real(8) function code(a, b, c, f)
use fmin_fmax_functions
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) - sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 8 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 19.4% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (- (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
module fmin_fmax_functions
    implicit none
    private
    public fmax
    public fmin

    interface fmax
        module procedure fmax88
        module procedure fmax44
        module procedure fmax84
        module procedure fmax48
    end interface
    interface fmin
        module procedure fmin88
        module procedure fmin44
        module procedure fmin84
        module procedure fmin48
    end interface
contains
    real(8) function fmax88(x, y) result (res)
        real(8), intent (in) :: x
        real(8), intent (in) :: y
        res = merge(y, merge(x, max(x, y), y /= y), x /= x)
    end function
    real(4) function fmax44(x, y) result (res)
        real(4), intent (in) :: x
        real(4), intent (in) :: y
        res = merge(y, merge(x, max(x, y), y /= y), x /= x)
    end function
    real(8) function fmax84(x, y) result(res)
        real(8), intent (in) :: x
        real(4), intent (in) :: y
        res = merge(dble(y), merge(x, max(x, dble(y)), y /= y), x /= x)
    end function
    real(8) function fmax48(x, y) result(res)
        real(4), intent (in) :: x
        real(8), intent (in) :: y
        res = merge(y, merge(dble(x), max(dble(x), y), y /= y), x /= x)
    end function
    real(8) function fmin88(x, y) result (res)
        real(8), intent (in) :: x
        real(8), intent (in) :: y
        res = merge(y, merge(x, min(x, y), y /= y), x /= x)
    end function
    real(4) function fmin44(x, y) result (res)
        real(4), intent (in) :: x
        real(4), intent (in) :: y
        res = merge(y, merge(x, min(x, y), y /= y), x /= x)
    end function
    real(8) function fmin84(x, y) result(res)
        real(8), intent (in) :: x
        real(4), intent (in) :: y
        res = merge(dble(y), merge(x, min(x, dble(y)), y /= y), x /= x)
    end function
    real(8) function fmin48(x, y) result(res)
        real(4), intent (in) :: x
        real(8), intent (in) :: y
        res = merge(y, merge(dble(x), min(dble(x), y), y /= y), x /= x)
    end function
end module

real(8) function code(a, b, c, f)
use fmin_fmax_functions
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) - sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Alternative 1: 46.6% accurate, N/A× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\ \mathbf{if}\;B\_m \leq 2.9 \cdot 10^{-17}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{B\_m \cdot B\_m}{C}\right) + A\right)}}{-t\_0}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2}}{-B\_m} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(A, B\_m\right)\right)}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (let* ((t_0 (- (pow B_m 2.0) (* (* 4.0 A) C))))
   (if (<= B_m 2.9e-17)
     (/
      (sqrt (* (* 2.0 (* t_0 F)) (+ (+ A (* -0.5 (/ (* B_m B_m) C))) A)))
      (- t_0))
     (* (/ (sqrt 2.0) (- B_m)) (sqrt (* F (- A (hypot A B_m))))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double t_0 = pow(B_m, 2.0) - ((4.0 * A) * C);
	double tmp;
	if (B_m <= 2.9e-17) {
		tmp = sqrt(((2.0 * (t_0 * F)) * ((A + (-0.5 * ((B_m * B_m) / C))) + A))) / -t_0;
	} else {
		tmp = (sqrt(2.0) / -B_m) * sqrt((F * (A - hypot(A, B_m))));
	}
	return tmp;
}
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	double t_0 = Math.pow(B_m, 2.0) - ((4.0 * A) * C);
	double tmp;
	if (B_m <= 2.9e-17) {
		tmp = Math.sqrt(((2.0 * (t_0 * F)) * ((A + (-0.5 * ((B_m * B_m) / C))) + A))) / -t_0;
	} else {
		tmp = (Math.sqrt(2.0) / -B_m) * Math.sqrt((F * (A - Math.hypot(A, B_m))));
	}
	return tmp;
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	t_0 = math.pow(B_m, 2.0) - ((4.0 * A) * C)
	tmp = 0
	if B_m <= 2.9e-17:
		tmp = math.sqrt(((2.0 * (t_0 * F)) * ((A + (-0.5 * ((B_m * B_m) / C))) + A))) / -t_0
	else:
		tmp = (math.sqrt(2.0) / -B_m) * math.sqrt((F * (A - math.hypot(A, B_m))))
	return tmp
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	t_0 = Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C))
	tmp = 0.0
	if (B_m <= 2.9e-17)
		tmp = Float64(sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + Float64(-0.5 * Float64(Float64(B_m * B_m) / C))) + A))) / Float64(-t_0));
	else
		tmp = Float64(Float64(sqrt(2.0) / Float64(-B_m)) * sqrt(Float64(F * Float64(A - hypot(A, B_m)))));
	end
	return tmp
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp_2 = code(A, B_m, C, F)
	t_0 = (B_m ^ 2.0) - ((4.0 * A) * C);
	tmp = 0.0;
	if (B_m <= 2.9e-17)
		tmp = sqrt(((2.0 * (t_0 * F)) * ((A + (-0.5 * ((B_m * B_m) / C))) + A))) / -t_0;
	else
		tmp = (sqrt(2.0) / -B_m) * sqrt((F * (A - hypot(A, B_m))));
	end
	tmp_2 = tmp;
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[B$95$m, 2.9e-17], N[(N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + A), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], N[(N[(N[Sqrt[2.0], $MachinePrecision] / (-B$95$m)), $MachinePrecision] * N[Sqrt[N[(F * N[(A - N[Sqrt[A ^ 2 + B$95$m ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
t_0 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\
\mathbf{if}\;B\_m \leq 2.9 \cdot 10^{-17}:\\
\;\;\;\;\frac{\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{B\_m \cdot B\_m}{C}\right) + A\right)}}{-t\_0}\\

\mathbf{else}:\\
\;\;\;\;\frac{\sqrt{2}}{-B\_m} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(A, B\_m\right)\right)}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if B < 2.9000000000000003e-17

    1. Initial program 16.0%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around inf

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Step-by-step derivation
      1. lower--.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - \color{blue}{-1 \cdot A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lower-+.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - \color{blue}{-1} \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. lower-/.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{{B}^{2}}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. unpow2N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{B \cdot B}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + \frac{-1}{2} \cdot \frac{B \cdot B}{C}\right) - -1 \cdot A\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      7. lower-*.f6417.8

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{B \cdot B}{C}\right) - -1 \cdot \color{blue}{A}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    5. Applied rewrites17.8%

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\left(A + -0.5 \cdot \frac{B \cdot B}{C}\right) - -1 \cdot A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

    if 2.9000000000000003e-17 < B

    1. Initial program 20.1%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \color{blue}{\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
      2. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \color{blue}{\sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      3. lower-/.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      4. lower-sqrt.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F} \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      5. lower-sqrt.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      6. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      7. lower--.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      8. unpow2N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{A \cdot A + {B}^{2}}\right)}\right) \]
      9. unpow2N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{A \cdot A + B \cdot B}\right)}\right) \]
      10. lower-hypot.f6447.9

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(A, B\right)\right)}\right) \]
    5. Applied rewrites47.9%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(A, B\right)\right)}\right)} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification25.6%

    \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 2.9 \cdot 10^{-17}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + -0.5 \cdot \frac{B \cdot B}{C}\right) + A\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2}}{-B} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(A, B\right)\right)}\\ \end{array} \]
  5. Add Preprocessing

Alternative 2: 45.1% accurate, N/A× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;B\_m \leq 10^{-32}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-8, A \cdot \left(C \cdot \left(F \cdot \left(A + A\right)\right)\right), 2 \cdot \left(\left(B\_m \cdot B\_m\right) \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) + A\right)\right)\right)\right)}}{-\left({B\_m}^{2} - \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2}}{-B\_m} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(A, B\_m\right)\right)}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (if (<= B_m 1e-32)
   (/
    (sqrt
     (fma
      -8.0
      (* A (* C (* F (+ A A))))
      (* 2.0 (* (* B_m B_m) (* F (+ (+ A (* 2.0 A)) A))))))
    (- (- (pow B_m 2.0) (* (* 4.0 A) C))))
   (* (/ (sqrt 2.0) (- B_m)) (sqrt (* F (- A (hypot A B_m)))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double tmp;
	if (B_m <= 1e-32) {
		tmp = sqrt(fma(-8.0, (A * (C * (F * (A + A)))), (2.0 * ((B_m * B_m) * (F * ((A + (2.0 * A)) + A)))))) / -(pow(B_m, 2.0) - ((4.0 * A) * C));
	} else {
		tmp = (sqrt(2.0) / -B_m) * sqrt((F * (A - hypot(A, B_m))));
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	tmp = 0.0
	if (B_m <= 1e-32)
		tmp = Float64(sqrt(fma(-8.0, Float64(A * Float64(C * Float64(F * Float64(A + A)))), Float64(2.0 * Float64(Float64(B_m * B_m) * Float64(F * Float64(Float64(A + Float64(2.0 * A)) + A)))))) / Float64(-Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C))));
	else
		tmp = Float64(Float64(sqrt(2.0) / Float64(-B_m)) * sqrt(Float64(F * Float64(A - hypot(A, B_m)))));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := If[LessEqual[B$95$m, 1e-32], N[(N[Sqrt[N[(-8.0 * N[(A * N[(C * N[(F * N[(A + A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(2.0 * N[(N[(B$95$m * B$95$m), $MachinePrecision] * N[(F * N[(N[(A + N[(2.0 * A), $MachinePrecision]), $MachinePrecision] + A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision])), $MachinePrecision], N[(N[(N[Sqrt[2.0], $MachinePrecision] / (-B$95$m)), $MachinePrecision] * N[Sqrt[N[(F * N[(A - N[Sqrt[A ^ 2 + B$95$m ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
\mathbf{if}\;B\_m \leq 10^{-32}:\\
\;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-8, A \cdot \left(C \cdot \left(F \cdot \left(A + A\right)\right)\right), 2 \cdot \left(\left(B\_m \cdot B\_m\right) \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) + A\right)\right)\right)\right)}}{-\left({B\_m}^{2} - \left(4 \cdot A\right) \cdot C\right)}\\

\mathbf{else}:\\
\;\;\;\;\frac{\sqrt{2}}{-B\_m} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(A, B\_m\right)\right)}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if B < 1.00000000000000006e-32

    1. Initial program 16.0%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in A around inf

      \[\leadsto \frac{-\sqrt{\color{blue}{-8 \cdot \left(A \cdot \left(C \cdot \left(F \cdot \left(C - -1 \cdot C\right)\right)\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{-8 \cdot \color{blue}{\left(A \cdot \left(C \cdot \left(F \cdot \left(C - -1 \cdot C\right)\right)\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{-8 \cdot \left(A \cdot \color{blue}{\left(C \cdot \left(F \cdot \left(C - -1 \cdot C\right)\right)\right)}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{-8 \cdot \left(A \cdot \left(C \cdot \color{blue}{\left(F \cdot \left(C - -1 \cdot C\right)\right)}\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{-8 \cdot \left(A \cdot \left(C \cdot \left(F \cdot \color{blue}{\left(C - -1 \cdot C\right)}\right)\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. lower--.f64N/A

        \[\leadsto \frac{-\sqrt{-8 \cdot \left(A \cdot \left(C \cdot \left(F \cdot \left(C - \color{blue}{-1 \cdot C}\right)\right)\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. lower-*.f649.9

        \[\leadsto \frac{-\sqrt{-8 \cdot \left(A \cdot \left(C \cdot \left(F \cdot \left(C - -1 \cdot \color{blue}{C}\right)\right)\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    5. Applied rewrites9.9%

      \[\leadsto \frac{-\sqrt{\color{blue}{-8 \cdot \left(A \cdot \left(C \cdot \left(F \cdot \left(C - -1 \cdot C\right)\right)\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    6. Taylor expanded in C around inf

      \[\leadsto \frac{-\sqrt{\color{blue}{C \cdot \left(-8 \cdot \left(A \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right) + 2 \cdot \frac{F \cdot \left(2 \cdot \left(A \cdot {B}^{2}\right) + {B}^{2} \cdot \left(A - -1 \cdot A\right)\right)}{C}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    7. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{C \cdot \color{blue}{\left(-8 \cdot \left(A \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right) + 2 \cdot \frac{F \cdot \left(2 \cdot \left(A \cdot {B}^{2}\right) + {B}^{2} \cdot \left(A - -1 \cdot A\right)\right)}{C}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lower-fma.f64N/A

        \[\leadsto \frac{-\sqrt{C \cdot \mathsf{fma}\left(-8, \color{blue}{A \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)}, 2 \cdot \frac{F \cdot \left(2 \cdot \left(A \cdot {B}^{2}\right) + {B}^{2} \cdot \left(A - -1 \cdot A\right)\right)}{C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{C \cdot \mathsf{fma}\left(-8, A \cdot \color{blue}{\left(F \cdot \left(A - -1 \cdot A\right)\right)}, 2 \cdot \frac{F \cdot \left(2 \cdot \left(A \cdot {B}^{2}\right) + {B}^{2} \cdot \left(A - -1 \cdot A\right)\right)}{C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{C \cdot \mathsf{fma}\left(-8, A \cdot \left(F \cdot \color{blue}{\left(A - -1 \cdot A\right)}\right), 2 \cdot \frac{F \cdot \left(2 \cdot \left(A \cdot {B}^{2}\right) + {B}^{2} \cdot \left(A - -1 \cdot A\right)\right)}{C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. lower--.f64N/A

        \[\leadsto \frac{-\sqrt{C \cdot \mathsf{fma}\left(-8, A \cdot \left(F \cdot \left(A - \color{blue}{-1 \cdot A}\right)\right), 2 \cdot \frac{F \cdot \left(2 \cdot \left(A \cdot {B}^{2}\right) + {B}^{2} \cdot \left(A - -1 \cdot A\right)\right)}{C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{C \cdot \mathsf{fma}\left(-8, A \cdot \left(F \cdot \left(A - -1 \cdot \color{blue}{A}\right)\right), 2 \cdot \frac{F \cdot \left(2 \cdot \left(A \cdot {B}^{2}\right) + {B}^{2} \cdot \left(A - -1 \cdot A\right)\right)}{C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      7. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{C \cdot \mathsf{fma}\left(-8, A \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right), 2 \cdot \frac{F \cdot \left(2 \cdot \left(A \cdot {B}^{2}\right) + {B}^{2} \cdot \left(A - -1 \cdot A\right)\right)}{C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    8. Applied rewrites14.3%

      \[\leadsto \frac{-\sqrt{\color{blue}{C \cdot \mathsf{fma}\left(-8, A \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right), 2 \cdot \frac{F \cdot \mathsf{fma}\left(2, A \cdot \left(B \cdot B\right), \left(B \cdot B\right) \cdot \left(A - -1 \cdot A\right)\right)}{C}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    9. Taylor expanded in B around 0

      \[\leadsto \frac{-\sqrt{-8 \cdot \left(A \cdot \left(C \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right)\right) + \color{blue}{2 \cdot \left({B}^{2} \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) - -1 \cdot A\right)\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    10. Step-by-step derivation
      1. lower-fma.f64N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-8, A \cdot \color{blue}{\left(C \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right)}, 2 \cdot \left({B}^{2} \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) - -1 \cdot A\right)\right)\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-8, A \cdot \left(C \cdot \color{blue}{\left(F \cdot \left(A - -1 \cdot A\right)\right)}\right), 2 \cdot \left({B}^{2} \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) - -1 \cdot A\right)\right)\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-8, A \cdot \left(C \cdot \left(F \cdot \color{blue}{\left(A - -1 \cdot A\right)}\right)\right), 2 \cdot \left({B}^{2} \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) - -1 \cdot A\right)\right)\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-8, A \cdot \left(C \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right), 2 \cdot \left({B}^{2} \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) - -1 \cdot A\right)\right)\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. lift--.f64N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-8, A \cdot \left(C \cdot \left(F \cdot \left(A - -1 \cdot \color{blue}{A}\right)\right)\right), 2 \cdot \left({B}^{2} \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) - -1 \cdot A\right)\right)\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-8, A \cdot \left(C \cdot \left(F \cdot \left(A - \color{blue}{-1 \cdot A}\right)\right)\right), 2 \cdot \left({B}^{2} \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) - -1 \cdot A\right)\right)\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      7. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-8, A \cdot \left(C \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right), 2 \cdot \left({B}^{2} \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) - -1 \cdot A\right)\right)\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      8. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-8, A \cdot \left(C \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right), 2 \cdot \left({B}^{2} \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) - -1 \cdot A\right)\right)\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      9. pow2N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-8, A \cdot \left(C \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right), 2 \cdot \left(\left(B \cdot B\right) \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) - -1 \cdot A\right)\right)\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      10. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-8, A \cdot \left(C \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right), 2 \cdot \left(\left(B \cdot B\right) \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) - -1 \cdot A\right)\right)\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      11. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-8, A \cdot \left(C \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right), 2 \cdot \left(\left(B \cdot B\right) \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) - -1 \cdot A\right)\right)\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    11. Applied rewrites15.9%

      \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-8, \color{blue}{A \cdot \left(C \cdot \left(F \cdot \left(A - -1 \cdot A\right)\right)\right)}, 2 \cdot \left(\left(B \cdot B\right) \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) - -1 \cdot A\right)\right)\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

    if 1.00000000000000006e-32 < B

    1. Initial program 19.8%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \color{blue}{\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
      2. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \color{blue}{\sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      3. lower-/.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      4. lower-sqrt.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F} \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      5. lower-sqrt.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      6. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      7. lower--.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      8. unpow2N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{A \cdot A + {B}^{2}}\right)}\right) \]
      9. unpow2N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{A \cdot A + B \cdot B}\right)}\right) \]
      10. lower-hypot.f6446.0

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(A, B\right)\right)}\right) \]
    5. Applied rewrites46.0%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(A, B\right)\right)}\right)} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification24.4%

    \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 10^{-32}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-8, A \cdot \left(C \cdot \left(F \cdot \left(A + A\right)\right)\right), 2 \cdot \left(\left(B \cdot B\right) \cdot \left(F \cdot \left(\left(A + 2 \cdot A\right) + A\right)\right)\right)\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2}}{-B} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(A, B\right)\right)}\\ \end{array} \]
  5. Add Preprocessing

Alternative 3: 41.4% accurate, N/A× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;{B\_m}^{2} \leq 10^{-182}:\\ \;\;\;\;\sqrt{\left(-0.5 \cdot \frac{F}{C}\right) \cdot 2}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2}}{-B\_m} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(A, B\_m\right)\right)}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (if (<= (pow B_m 2.0) 1e-182)
   (sqrt (* (* -0.5 (/ F C)) 2.0))
   (* (/ (sqrt 2.0) (- B_m)) (sqrt (* F (- A (hypot A B_m)))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double tmp;
	if (pow(B_m, 2.0) <= 1e-182) {
		tmp = sqrt(((-0.5 * (F / C)) * 2.0));
	} else {
		tmp = (sqrt(2.0) / -B_m) * sqrt((F * (A - hypot(A, B_m))));
	}
	return tmp;
}
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	double tmp;
	if (Math.pow(B_m, 2.0) <= 1e-182) {
		tmp = Math.sqrt(((-0.5 * (F / C)) * 2.0));
	} else {
		tmp = (Math.sqrt(2.0) / -B_m) * Math.sqrt((F * (A - Math.hypot(A, B_m))));
	}
	return tmp;
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	tmp = 0
	if math.pow(B_m, 2.0) <= 1e-182:
		tmp = math.sqrt(((-0.5 * (F / C)) * 2.0))
	else:
		tmp = (math.sqrt(2.0) / -B_m) * math.sqrt((F * (A - math.hypot(A, B_m))))
	return tmp
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	tmp = 0.0
	if ((B_m ^ 2.0) <= 1e-182)
		tmp = sqrt(Float64(Float64(-0.5 * Float64(F / C)) * 2.0));
	else
		tmp = Float64(Float64(sqrt(2.0) / Float64(-B_m)) * sqrt(Float64(F * Float64(A - hypot(A, B_m)))));
	end
	return tmp
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp_2 = code(A, B_m, C, F)
	tmp = 0.0;
	if ((B_m ^ 2.0) <= 1e-182)
		tmp = sqrt(((-0.5 * (F / C)) * 2.0));
	else
		tmp = (sqrt(2.0) / -B_m) * sqrt((F * (A - hypot(A, B_m))));
	end
	tmp_2 = tmp;
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e-182], N[Sqrt[N[(N[(-0.5 * N[(F / C), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision], N[(N[(N[Sqrt[2.0], $MachinePrecision] / (-B$95$m)), $MachinePrecision] * N[Sqrt[N[(F * N[(A - N[Sqrt[A ^ 2 + B$95$m ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
\mathbf{if}\;{B\_m}^{2} \leq 10^{-182}:\\
\;\;\;\;\sqrt{\left(-0.5 \cdot \frac{F}{C}\right) \cdot 2}\\

\mathbf{else}:\\
\;\;\;\;\frac{\sqrt{2}}{-B\_m} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(A, B\_m\right)\right)}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (pow.f64 B #s(literal 2 binary64)) < 1e-182

    1. Initial program 11.4%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around -inf

      \[\leadsto \color{blue}{\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \left(\sqrt{-2} \cdot \sqrt{-1}\right)} \]
    4. Step-by-step derivation
      1. sqrt-unprodN/A

        \[\leadsto \sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{-2 \cdot -1} \]
      2. metadata-evalN/A

        \[\leadsto \sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2} \]
      3. sqrt-unprodN/A

        \[\leadsto \sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)} \cdot 2} \]
    5. Applied rewrites15.8%

      \[\leadsto \color{blue}{\sqrt{\frac{F \cdot \left(\left(A + C\right) - \mathsf{hypot}\left(B, A - C\right)\right)}{B \cdot B - 4 \cdot \left(A \cdot C\right)} \cdot 2}} \]
    6. Taylor expanded in A around -inf

      \[\leadsto \sqrt{\left(\frac{-1}{2} \cdot \frac{F}{C}\right) \cdot 2} \]
    7. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto \sqrt{\left(\frac{-1}{2} \cdot \frac{F}{C}\right) \cdot 2} \]
      2. lower-/.f6420.6

        \[\leadsto \sqrt{\left(-0.5 \cdot \frac{F}{C}\right) \cdot 2} \]
    8. Applied rewrites20.6%

      \[\leadsto \sqrt{\left(-0.5 \cdot \frac{F}{C}\right) \cdot 2} \]

    if 1e-182 < (pow.f64 B #s(literal 2 binary64))

    1. Initial program 19.5%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \color{blue}{\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
      2. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \color{blue}{\sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      3. lower-/.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      4. lower-sqrt.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F} \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      5. lower-sqrt.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      6. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      7. lower--.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      8. unpow2N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{A \cdot A + {B}^{2}}\right)}\right) \]
      9. unpow2N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{A \cdot A + B \cdot B}\right)}\right) \]
      10. lower-hypot.f6421.1

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(A, B\right)\right)}\right) \]
    5. Applied rewrites21.1%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(A, B\right)\right)}\right)} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification20.9%

    \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 10^{-182}:\\ \;\;\;\;\sqrt{\left(-0.5 \cdot \frac{F}{C}\right) \cdot 2}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2}}{-B} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(A, B\right)\right)}\\ \end{array} \]
  5. Add Preprocessing

Alternative 4: 41.8% accurate, N/A× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\ t_1 := \frac{\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_0}\\ \mathbf{if}\;t\_1 \leq 0:\\ \;\;\;\;-\sqrt{\frac{F \cdot \left(\left(A + C\right) - \mathsf{hypot}\left(B\_m, A - C\right)\right)}{B\_m \cdot B\_m - 4 \cdot \left(A \cdot C\right)} \cdot 2}\\ \mathbf{elif}\;t\_1 \leq \infty:\\ \;\;\;\;\sqrt{\left(-0.5 \cdot \frac{F}{C}\right) \cdot 2}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2}}{-B\_m} \cdot \sqrt{F \cdot \left(-B\_m\right)}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (let* ((t_0 (- (pow B_m 2.0) (* (* 4.0 A) C)))
        (t_1
         (/
          (sqrt
           (*
            (* 2.0 (* t_0 F))
            (- (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))))
          (- t_0))))
   (if (<= t_1 0.0)
     (-
      (sqrt
       (*
        (/
         (* F (- (+ A C) (hypot B_m (- A C))))
         (- (* B_m B_m) (* 4.0 (* A C))))
        2.0)))
     (if (<= t_1 INFINITY)
       (sqrt (* (* -0.5 (/ F C)) 2.0))
       (* (/ (sqrt 2.0) (- B_m)) (sqrt (* F (- B_m))))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double t_0 = pow(B_m, 2.0) - ((4.0 * A) * C);
	double t_1 = sqrt(((2.0 * (t_0 * F)) * ((A + C) - sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))))) / -t_0;
	double tmp;
	if (t_1 <= 0.0) {
		tmp = -sqrt((((F * ((A + C) - hypot(B_m, (A - C)))) / ((B_m * B_m) - (4.0 * (A * C)))) * 2.0));
	} else if (t_1 <= ((double) INFINITY)) {
		tmp = sqrt(((-0.5 * (F / C)) * 2.0));
	} else {
		tmp = (sqrt(2.0) / -B_m) * sqrt((F * -B_m));
	}
	return tmp;
}
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	double t_0 = Math.pow(B_m, 2.0) - ((4.0 * A) * C);
	double t_1 = Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B_m, 2.0)))))) / -t_0;
	double tmp;
	if (t_1 <= 0.0) {
		tmp = -Math.sqrt((((F * ((A + C) - Math.hypot(B_m, (A - C)))) / ((B_m * B_m) - (4.0 * (A * C)))) * 2.0));
	} else if (t_1 <= Double.POSITIVE_INFINITY) {
		tmp = Math.sqrt(((-0.5 * (F / C)) * 2.0));
	} else {
		tmp = (Math.sqrt(2.0) / -B_m) * Math.sqrt((F * -B_m));
	}
	return tmp;
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	t_0 = math.pow(B_m, 2.0) - ((4.0 * A) * C)
	t_1 = math.sqrt(((2.0 * (t_0 * F)) * ((A + C) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B_m, 2.0)))))) / -t_0
	tmp = 0
	if t_1 <= 0.0:
		tmp = -math.sqrt((((F * ((A + C) - math.hypot(B_m, (A - C)))) / ((B_m * B_m) - (4.0 * (A * C)))) * 2.0))
	elif t_1 <= math.inf:
		tmp = math.sqrt(((-0.5 * (F / C)) * 2.0))
	else:
		tmp = (math.sqrt(2.0) / -B_m) * math.sqrt((F * -B_m))
	return tmp
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	t_0 = Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C))
	t_1 = Float64(sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))))) / Float64(-t_0))
	tmp = 0.0
	if (t_1 <= 0.0)
		tmp = Float64(-sqrt(Float64(Float64(Float64(F * Float64(Float64(A + C) - hypot(B_m, Float64(A - C)))) / Float64(Float64(B_m * B_m) - Float64(4.0 * Float64(A * C)))) * 2.0)));
	elseif (t_1 <= Inf)
		tmp = sqrt(Float64(Float64(-0.5 * Float64(F / C)) * 2.0));
	else
		tmp = Float64(Float64(sqrt(2.0) / Float64(-B_m)) * sqrt(Float64(F * Float64(-B_m))));
	end
	return tmp
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp_2 = code(A, B_m, C, F)
	t_0 = (B_m ^ 2.0) - ((4.0 * A) * C);
	t_1 = sqrt(((2.0 * (t_0 * F)) * ((A + C) - sqrt((((A - C) ^ 2.0) + (B_m ^ 2.0)))))) / -t_0;
	tmp = 0.0;
	if (t_1 <= 0.0)
		tmp = -sqrt((((F * ((A + C) - hypot(B_m, (A - C)))) / ((B_m * B_m) - (4.0 * (A * C)))) * 2.0));
	elseif (t_1 <= Inf)
		tmp = sqrt(((-0.5 * (F / C)) * 2.0));
	else
		tmp = (sqrt(2.0) / -B_m) * sqrt((F * -B_m));
	end
	tmp_2 = tmp;
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision]}, If[LessEqual[t$95$1, 0.0], (-N[Sqrt[N[(N[(N[(F * N[(N[(A + C), $MachinePrecision] - N[Sqrt[B$95$m ^ 2 + N[(A - C), $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(N[(B$95$m * B$95$m), $MachinePrecision] - N[(4.0 * N[(A * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision]), If[LessEqual[t$95$1, Infinity], N[Sqrt[N[(N[(-0.5 * N[(F / C), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision], N[(N[(N[Sqrt[2.0], $MachinePrecision] / (-B$95$m)), $MachinePrecision] * N[Sqrt[N[(F * (-B$95$m)), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
t_0 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\
t_1 := \frac{\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_0}\\
\mathbf{if}\;t\_1 \leq 0:\\
\;\;\;\;-\sqrt{\frac{F \cdot \left(\left(A + C\right) - \mathsf{hypot}\left(B\_m, A - C\right)\right)}{B\_m \cdot B\_m - 4 \cdot \left(A \cdot C\right)} \cdot 2}\\

\mathbf{elif}\;t\_1 \leq \infty:\\
\;\;\;\;\sqrt{\left(-0.5 \cdot \frac{F}{C}\right) \cdot 2}\\

\mathbf{else}:\\
\;\;\;\;\frac{\sqrt{2}}{-B\_m} \cdot \sqrt{F \cdot \left(-B\_m\right)}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (-.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -0.0

    1. Initial program 31.8%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    4. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \color{blue}{\left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
      2. sqrt-unprodN/A

        \[\leadsto -1 \cdot \sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)} \cdot 2} \]
      3. lower-sqrt.f64N/A

        \[\leadsto -1 \cdot \sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)} \cdot 2} \]
      4. lower-*.f64N/A

        \[\leadsto -1 \cdot \sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)} \cdot 2} \]
    5. Applied rewrites44.8%

      \[\leadsto \color{blue}{-1 \cdot \sqrt{\frac{F \cdot \left(\left(A + C\right) - \mathsf{hypot}\left(B, A - C\right)\right)}{B \cdot B - 4 \cdot \left(A \cdot C\right)} \cdot 2}} \]

    if -0.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (-.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

    1. Initial program 35.7%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around -inf

      \[\leadsto \color{blue}{\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \left(\sqrt{-2} \cdot \sqrt{-1}\right)} \]
    4. Step-by-step derivation
      1. sqrt-unprodN/A

        \[\leadsto \sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{-2 \cdot -1} \]
      2. metadata-evalN/A

        \[\leadsto \sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2} \]
      3. sqrt-unprodN/A

        \[\leadsto \sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)} \cdot 2} \]
    5. Applied rewrites77.2%

      \[\leadsto \color{blue}{\sqrt{\frac{F \cdot \left(\left(A + C\right) - \mathsf{hypot}\left(B, A - C\right)\right)}{B \cdot B - 4 \cdot \left(A \cdot C\right)} \cdot 2}} \]
    6. Taylor expanded in A around -inf

      \[\leadsto \sqrt{\left(\frac{-1}{2} \cdot \frac{F}{C}\right) \cdot 2} \]
    7. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto \sqrt{\left(\frac{-1}{2} \cdot \frac{F}{C}\right) \cdot 2} \]
      2. lower-/.f6436.2

        \[\leadsto \sqrt{\left(-0.5 \cdot \frac{F}{C}\right) \cdot 2} \]
    8. Applied rewrites36.2%

      \[\leadsto \sqrt{\left(-0.5 \cdot \frac{F}{C}\right) \cdot 2} \]

    if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (-.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

    1. Initial program 0.0%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \color{blue}{\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
      2. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \color{blue}{\sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      3. lower-/.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}}\right) \]
      4. lower-sqrt.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{\color{blue}{F} \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      5. lower-sqrt.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      6. lower-*.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      7. lower--.f64N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}\right) \]
      8. unpow2N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{A \cdot A + {B}^{2}}\right)}\right) \]
      9. unpow2N/A

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{A \cdot A + B \cdot B}\right)}\right) \]
      10. lower-hypot.f6417.6

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(A, B\right)\right)}\right) \]
    5. Applied rewrites17.6%

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(A, B\right)\right)}\right)} \]
    6. Taylor expanded in A around 0

      \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(-1 \cdot B\right)}\right) \]
    7. Step-by-step derivation
      1. lower-*.f6415.5

        \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(-1 \cdot B\right)}\right) \]
    8. Applied rewrites15.5%

      \[\leadsto -1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(-1 \cdot B\right)}\right) \]
  3. Recombined 3 regimes into one program.
  4. Final simplification30.3%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq 0:\\ \;\;\;\;-\sqrt{\frac{F \cdot \left(\left(A + C\right) - \mathsf{hypot}\left(B, A - C\right)\right)}{B \cdot B - 4 \cdot \left(A \cdot C\right)} \cdot 2}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq \infty:\\ \;\;\;\;\sqrt{\left(-0.5 \cdot \frac{F}{C}\right) \cdot 2}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2}}{-B} \cdot \sqrt{F \cdot \left(-B\right)}\\ \end{array} \]
  5. Add Preprocessing

Alternative 5: 38.4% accurate, N/A× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\ t_1 := \frac{\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_0}\\ \mathbf{if}\;t\_1 \leq 0:\\ \;\;\;\;-\sqrt{\frac{F \cdot \left(\left(A + C\right) - \mathsf{hypot}\left(B\_m, A - C\right)\right)}{B\_m \cdot B\_m - 4 \cdot \left(A \cdot C\right)} \cdot 2}\\ \mathbf{elif}\;t\_1 \leq \infty:\\ \;\;\;\;\sqrt{\left(-0.5 \cdot \frac{F}{C}\right) \cdot 2}\\ \mathbf{else}:\\ \;\;\;\;A \cdot \left(\frac{\sqrt{2}}{\left(-A\right) \cdot B\_m} \cdot \sqrt{F \cdot \left(C - \mathsf{hypot}\left(B\_m, C\right)\right)}\right)\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (let* ((t_0 (- (pow B_m 2.0) (* (* 4.0 A) C)))
        (t_1
         (/
          (sqrt
           (*
            (* 2.0 (* t_0 F))
            (- (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))))
          (- t_0))))
   (if (<= t_1 0.0)
     (-
      (sqrt
       (*
        (/
         (* F (- (+ A C) (hypot B_m (- A C))))
         (- (* B_m B_m) (* 4.0 (* A C))))
        2.0)))
     (if (<= t_1 INFINITY)
       (sqrt (* (* -0.5 (/ F C)) 2.0))
       (*
        A
        (* (/ (sqrt 2.0) (* (- A) B_m)) (sqrt (* F (- C (hypot B_m C))))))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double t_0 = pow(B_m, 2.0) - ((4.0 * A) * C);
	double t_1 = sqrt(((2.0 * (t_0 * F)) * ((A + C) - sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))))) / -t_0;
	double tmp;
	if (t_1 <= 0.0) {
		tmp = -sqrt((((F * ((A + C) - hypot(B_m, (A - C)))) / ((B_m * B_m) - (4.0 * (A * C)))) * 2.0));
	} else if (t_1 <= ((double) INFINITY)) {
		tmp = sqrt(((-0.5 * (F / C)) * 2.0));
	} else {
		tmp = A * ((sqrt(2.0) / (-A * B_m)) * sqrt((F * (C - hypot(B_m, C)))));
	}
	return tmp;
}
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	double t_0 = Math.pow(B_m, 2.0) - ((4.0 * A) * C);
	double t_1 = Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B_m, 2.0)))))) / -t_0;
	double tmp;
	if (t_1 <= 0.0) {
		tmp = -Math.sqrt((((F * ((A + C) - Math.hypot(B_m, (A - C)))) / ((B_m * B_m) - (4.0 * (A * C)))) * 2.0));
	} else if (t_1 <= Double.POSITIVE_INFINITY) {
		tmp = Math.sqrt(((-0.5 * (F / C)) * 2.0));
	} else {
		tmp = A * ((Math.sqrt(2.0) / (-A * B_m)) * Math.sqrt((F * (C - Math.hypot(B_m, C)))));
	}
	return tmp;
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	t_0 = math.pow(B_m, 2.0) - ((4.0 * A) * C)
	t_1 = math.sqrt(((2.0 * (t_0 * F)) * ((A + C) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B_m, 2.0)))))) / -t_0
	tmp = 0
	if t_1 <= 0.0:
		tmp = -math.sqrt((((F * ((A + C) - math.hypot(B_m, (A - C)))) / ((B_m * B_m) - (4.0 * (A * C)))) * 2.0))
	elif t_1 <= math.inf:
		tmp = math.sqrt(((-0.5 * (F / C)) * 2.0))
	else:
		tmp = A * ((math.sqrt(2.0) / (-A * B_m)) * math.sqrt((F * (C - math.hypot(B_m, C)))))
	return tmp
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	t_0 = Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C))
	t_1 = Float64(sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))))) / Float64(-t_0))
	tmp = 0.0
	if (t_1 <= 0.0)
		tmp = Float64(-sqrt(Float64(Float64(Float64(F * Float64(Float64(A + C) - hypot(B_m, Float64(A - C)))) / Float64(Float64(B_m * B_m) - Float64(4.0 * Float64(A * C)))) * 2.0)));
	elseif (t_1 <= Inf)
		tmp = sqrt(Float64(Float64(-0.5 * Float64(F / C)) * 2.0));
	else
		tmp = Float64(A * Float64(Float64(sqrt(2.0) / Float64(Float64(-A) * B_m)) * sqrt(Float64(F * Float64(C - hypot(B_m, C))))));
	end
	return tmp
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp_2 = code(A, B_m, C, F)
	t_0 = (B_m ^ 2.0) - ((4.0 * A) * C);
	t_1 = sqrt(((2.0 * (t_0 * F)) * ((A + C) - sqrt((((A - C) ^ 2.0) + (B_m ^ 2.0)))))) / -t_0;
	tmp = 0.0;
	if (t_1 <= 0.0)
		tmp = -sqrt((((F * ((A + C) - hypot(B_m, (A - C)))) / ((B_m * B_m) - (4.0 * (A * C)))) * 2.0));
	elseif (t_1 <= Inf)
		tmp = sqrt(((-0.5 * (F / C)) * 2.0));
	else
		tmp = A * ((sqrt(2.0) / (-A * B_m)) * sqrt((F * (C - hypot(B_m, C)))));
	end
	tmp_2 = tmp;
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision]}, If[LessEqual[t$95$1, 0.0], (-N[Sqrt[N[(N[(N[(F * N[(N[(A + C), $MachinePrecision] - N[Sqrt[B$95$m ^ 2 + N[(A - C), $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(N[(B$95$m * B$95$m), $MachinePrecision] - N[(4.0 * N[(A * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision]), If[LessEqual[t$95$1, Infinity], N[Sqrt[N[(N[(-0.5 * N[(F / C), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision], N[(A * N[(N[(N[Sqrt[2.0], $MachinePrecision] / N[((-A) * B$95$m), $MachinePrecision]), $MachinePrecision] * N[Sqrt[N[(F * N[(C - N[Sqrt[B$95$m ^ 2 + C ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
t_0 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\
t_1 := \frac{\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_0}\\
\mathbf{if}\;t\_1 \leq 0:\\
\;\;\;\;-\sqrt{\frac{F \cdot \left(\left(A + C\right) - \mathsf{hypot}\left(B\_m, A - C\right)\right)}{B\_m \cdot B\_m - 4 \cdot \left(A \cdot C\right)} \cdot 2}\\

\mathbf{elif}\;t\_1 \leq \infty:\\
\;\;\;\;\sqrt{\left(-0.5 \cdot \frac{F}{C}\right) \cdot 2}\\

\mathbf{else}:\\
\;\;\;\;A \cdot \left(\frac{\sqrt{2}}{\left(-A\right) \cdot B\_m} \cdot \sqrt{F \cdot \left(C - \mathsf{hypot}\left(B\_m, C\right)\right)}\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (-.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -0.0

    1. Initial program 31.8%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    4. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -1 \cdot \color{blue}{\left(\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
      2. sqrt-unprodN/A

        \[\leadsto -1 \cdot \sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)} \cdot 2} \]
      3. lower-sqrt.f64N/A

        \[\leadsto -1 \cdot \sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)} \cdot 2} \]
      4. lower-*.f64N/A

        \[\leadsto -1 \cdot \sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)} \cdot 2} \]
    5. Applied rewrites44.8%

      \[\leadsto \color{blue}{-1 \cdot \sqrt{\frac{F \cdot \left(\left(A + C\right) - \mathsf{hypot}\left(B, A - C\right)\right)}{B \cdot B - 4 \cdot \left(A \cdot C\right)} \cdot 2}} \]

    if -0.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (-.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

    1. Initial program 35.7%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around -inf

      \[\leadsto \color{blue}{\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \left(\sqrt{-2} \cdot \sqrt{-1}\right)} \]
    4. Step-by-step derivation
      1. sqrt-unprodN/A

        \[\leadsto \sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{-2 \cdot -1} \]
      2. metadata-evalN/A

        \[\leadsto \sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2} \]
      3. sqrt-unprodN/A

        \[\leadsto \sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)} \cdot 2} \]
    5. Applied rewrites77.2%

      \[\leadsto \color{blue}{\sqrt{\frac{F \cdot \left(\left(A + C\right) - \mathsf{hypot}\left(B, A - C\right)\right)}{B \cdot B - 4 \cdot \left(A \cdot C\right)} \cdot 2}} \]
    6. Taylor expanded in A around -inf

      \[\leadsto \sqrt{\left(\frac{-1}{2} \cdot \frac{F}{C}\right) \cdot 2} \]
    7. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto \sqrt{\left(\frac{-1}{2} \cdot \frac{F}{C}\right) \cdot 2} \]
      2. lower-/.f6436.2

        \[\leadsto \sqrt{\left(-0.5 \cdot \frac{F}{C}\right) \cdot 2} \]
    8. Applied rewrites36.2%

      \[\leadsto \sqrt{\left(-0.5 \cdot \frac{F}{C}\right) \cdot 2} \]

    if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (-.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

    1. Initial program 0.0%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in A around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)}\right) + \frac{-1}{2} \cdot \left(\left(A \cdot \left(B \cdot \left(\sqrt{2} \cdot \left(\frac{F \cdot \left(1 - -1 \cdot \left(C \cdot \sqrt{\frac{1}{{B}^{2} + {C}^{2}}}\right)\right)}{{B}^{2}} - -4 \cdot \frac{C \cdot \left(F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)\right)}{{B}^{4}}\right)\right)\right)\right) \cdot \sqrt{\frac{1}{F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)}}\right)} \]
    4. Applied rewrites14.2%

      \[\leadsto \color{blue}{\mathsf{fma}\left(-1, \frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C - \mathsf{hypot}\left(B, C\right)\right)}, -0.5 \cdot \left(\left(A \cdot \left(B \cdot \left(\sqrt{2} \cdot \left(\frac{F \cdot \left(1 - -1 \cdot \left(C \cdot \frac{1}{\mathsf{hypot}\left(B, C\right)}\right)\right)}{B \cdot B} - -4 \cdot \frac{C \cdot \left(F \cdot \left(C - \mathsf{hypot}\left(B, C\right)\right)\right)}{{B}^{4}}\right)\right)\right)\right) \cdot \frac{1}{\sqrt{F \cdot \left(C - \mathsf{hypot}\left(B, C\right)\right)}}\right)\right)} \]
    5. Taylor expanded in A around inf

      \[\leadsto A \cdot \color{blue}{\left(-1 \cdot \left(\frac{\sqrt{2}}{A \cdot B} \cdot \sqrt{F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)}\right) + \frac{-1}{2} \cdot \left(\left(B \cdot \left(\sqrt{2} \cdot \left(\frac{F \cdot \left(1 - -1 \cdot \left(C \cdot \sqrt{\frac{1}{{B}^{2} + {C}^{2}}}\right)\right)}{{B}^{2}} - -4 \cdot \frac{C \cdot \left(F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)\right)}{{B}^{4}}\right)\right)\right) \cdot \sqrt{\frac{1}{F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)}}\right)\right)} \]
    6. Applied rewrites8.0%

      \[\leadsto A \cdot \color{blue}{\mathsf{fma}\left(-1, \frac{\sqrt{2}}{A \cdot B} \cdot \sqrt{F \cdot \left(C - \mathsf{hypot}\left(B, C\right)\right)}, -0.5 \cdot \left(\left(B \cdot \left(\sqrt{2} \cdot \left(\frac{F \cdot \left(1 - -1 \cdot \left(C \cdot {\left(\mathsf{hypot}\left(B, C\right)\right)}^{-1}\right)\right)}{B \cdot B} - -4 \cdot \frac{C \cdot \left(F \cdot \left(C - \mathsf{hypot}\left(B, C\right)\right)\right)}{{B}^{4}}\right)\right)\right) \cdot {\left(\sqrt{F \cdot \left(C - \mathsf{hypot}\left(B, C\right)\right)}\right)}^{-1}\right)\right)} \]
    7. Taylor expanded in A around 0

      \[\leadsto A \cdot \left(-1 \cdot \left(\frac{\sqrt{2}}{A \cdot B} \cdot \color{blue}{\sqrt{F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)}}\right)\right) \]
    8. Step-by-step derivation
      1. sqrt-prodN/A

        \[\leadsto A \cdot \left(-1 \cdot \left(\frac{\sqrt{2}}{A \cdot B} \cdot \left(\sqrt{F} \cdot \sqrt{C - \sqrt{{B}^{2} + {C}^{2}}}\right)\right)\right) \]
      2. pow2N/A

        \[\leadsto A \cdot \left(-1 \cdot \left(\frac{\sqrt{2}}{A \cdot B} \cdot \left(\sqrt{F} \cdot \sqrt{C - \sqrt{B \cdot B + {C}^{2}}}\right)\right)\right) \]
      3. pow2N/A

        \[\leadsto A \cdot \left(-1 \cdot \left(\frac{\sqrt{2}}{A \cdot B} \cdot \left(\sqrt{F} \cdot \sqrt{C - \sqrt{B \cdot B + C \cdot C}}\right)\right)\right) \]
    9. Applied rewrites11.2%

      \[\leadsto A \cdot \left(-1 \cdot \left(\frac{\sqrt{2}}{A \cdot B} \cdot \color{blue}{\sqrt{F \cdot \left(C - \mathsf{hypot}\left(B, C\right)\right)}}\right)\right) \]
  3. Recombined 3 regimes into one program.
  4. Final simplification28.2%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq 0:\\ \;\;\;\;-\sqrt{\frac{F \cdot \left(\left(A + C\right) - \mathsf{hypot}\left(B, A - C\right)\right)}{B \cdot B - 4 \cdot \left(A \cdot C\right)} \cdot 2}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq \infty:\\ \;\;\;\;\sqrt{\left(-0.5 \cdot \frac{F}{C}\right) \cdot 2}\\ \mathbf{else}:\\ \;\;\;\;A \cdot \left(\frac{\sqrt{2}}{\left(-A\right) \cdot B} \cdot \sqrt{F \cdot \left(C - \mathsf{hypot}\left(B, C\right)\right)}\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 6: 33.4% accurate, N/A× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;{B\_m}^{2} \leq 2 \cdot 10^{-34}:\\ \;\;\;\;\sqrt{\left(-0.5 \cdot \frac{F}{C}\right) \cdot 2}\\ \mathbf{else}:\\ \;\;\;\;A \cdot \left(\frac{\sqrt{2}}{\left(-A\right) \cdot B\_m} \cdot \sqrt{F \cdot \left(C - \mathsf{hypot}\left(B\_m, C\right)\right)}\right)\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (if (<= (pow B_m 2.0) 2e-34)
   (sqrt (* (* -0.5 (/ F C)) 2.0))
   (* A (* (/ (sqrt 2.0) (* (- A) B_m)) (sqrt (* F (- C (hypot B_m C))))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double tmp;
	if (pow(B_m, 2.0) <= 2e-34) {
		tmp = sqrt(((-0.5 * (F / C)) * 2.0));
	} else {
		tmp = A * ((sqrt(2.0) / (-A * B_m)) * sqrt((F * (C - hypot(B_m, C)))));
	}
	return tmp;
}
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	double tmp;
	if (Math.pow(B_m, 2.0) <= 2e-34) {
		tmp = Math.sqrt(((-0.5 * (F / C)) * 2.0));
	} else {
		tmp = A * ((Math.sqrt(2.0) / (-A * B_m)) * Math.sqrt((F * (C - Math.hypot(B_m, C)))));
	}
	return tmp;
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	tmp = 0
	if math.pow(B_m, 2.0) <= 2e-34:
		tmp = math.sqrt(((-0.5 * (F / C)) * 2.0))
	else:
		tmp = A * ((math.sqrt(2.0) / (-A * B_m)) * math.sqrt((F * (C - math.hypot(B_m, C)))))
	return tmp
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	tmp = 0.0
	if ((B_m ^ 2.0) <= 2e-34)
		tmp = sqrt(Float64(Float64(-0.5 * Float64(F / C)) * 2.0));
	else
		tmp = Float64(A * Float64(Float64(sqrt(2.0) / Float64(Float64(-A) * B_m)) * sqrt(Float64(F * Float64(C - hypot(B_m, C))))));
	end
	return tmp
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp_2 = code(A, B_m, C, F)
	tmp = 0.0;
	if ((B_m ^ 2.0) <= 2e-34)
		tmp = sqrt(((-0.5 * (F / C)) * 2.0));
	else
		tmp = A * ((sqrt(2.0) / (-A * B_m)) * sqrt((F * (C - hypot(B_m, C)))));
	end
	tmp_2 = tmp;
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 2e-34], N[Sqrt[N[(N[(-0.5 * N[(F / C), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision], N[(A * N[(N[(N[Sqrt[2.0], $MachinePrecision] / N[((-A) * B$95$m), $MachinePrecision]), $MachinePrecision] * N[Sqrt[N[(F * N[(C - N[Sqrt[B$95$m ^ 2 + C ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
\mathbf{if}\;{B\_m}^{2} \leq 2 \cdot 10^{-34}:\\
\;\;\;\;\sqrt{\left(-0.5 \cdot \frac{F}{C}\right) \cdot 2}\\

\mathbf{else}:\\
\;\;\;\;A \cdot \left(\frac{\sqrt{2}}{\left(-A\right) \cdot B\_m} \cdot \sqrt{F \cdot \left(C - \mathsf{hypot}\left(B\_m, C\right)\right)}\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (pow.f64 B #s(literal 2 binary64)) < 1.99999999999999986e-34

    1. Initial program 17.5%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around -inf

      \[\leadsto \color{blue}{\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \left(\sqrt{-2} \cdot \sqrt{-1}\right)} \]
    4. Step-by-step derivation
      1. sqrt-unprodN/A

        \[\leadsto \sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{-2 \cdot -1} \]
      2. metadata-evalN/A

        \[\leadsto \sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2} \]
      3. sqrt-unprodN/A

        \[\leadsto \sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)} \cdot 2} \]
    5. Applied rewrites14.8%

      \[\leadsto \color{blue}{\sqrt{\frac{F \cdot \left(\left(A + C\right) - \mathsf{hypot}\left(B, A - C\right)\right)}{B \cdot B - 4 \cdot \left(A \cdot C\right)} \cdot 2}} \]
    6. Taylor expanded in A around -inf

      \[\leadsto \sqrt{\left(\frac{-1}{2} \cdot \frac{F}{C}\right) \cdot 2} \]
    7. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto \sqrt{\left(\frac{-1}{2} \cdot \frac{F}{C}\right) \cdot 2} \]
      2. lower-/.f6417.1

        \[\leadsto \sqrt{\left(-0.5 \cdot \frac{F}{C}\right) \cdot 2} \]
    8. Applied rewrites17.1%

      \[\leadsto \sqrt{\left(-0.5 \cdot \frac{F}{C}\right) \cdot 2} \]

    if 1.99999999999999986e-34 < (pow.f64 B #s(literal 2 binary64))

    1. Initial program 16.7%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in A around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)}\right) + \frac{-1}{2} \cdot \left(\left(A \cdot \left(B \cdot \left(\sqrt{2} \cdot \left(\frac{F \cdot \left(1 - -1 \cdot \left(C \cdot \sqrt{\frac{1}{{B}^{2} + {C}^{2}}}\right)\right)}{{B}^{2}} - -4 \cdot \frac{C \cdot \left(F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)\right)}{{B}^{4}}\right)\right)\right)\right) \cdot \sqrt{\frac{1}{F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)}}\right)} \]
    4. Applied rewrites21.4%

      \[\leadsto \color{blue}{\mathsf{fma}\left(-1, \frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C - \mathsf{hypot}\left(B, C\right)\right)}, -0.5 \cdot \left(\left(A \cdot \left(B \cdot \left(\sqrt{2} \cdot \left(\frac{F \cdot \left(1 - -1 \cdot \left(C \cdot \frac{1}{\mathsf{hypot}\left(B, C\right)}\right)\right)}{B \cdot B} - -4 \cdot \frac{C \cdot \left(F \cdot \left(C - \mathsf{hypot}\left(B, C\right)\right)\right)}{{B}^{4}}\right)\right)\right)\right) \cdot \frac{1}{\sqrt{F \cdot \left(C - \mathsf{hypot}\left(B, C\right)\right)}}\right)\right)} \]
    5. Taylor expanded in A around inf

      \[\leadsto A \cdot \color{blue}{\left(-1 \cdot \left(\frac{\sqrt{2}}{A \cdot B} \cdot \sqrt{F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)}\right) + \frac{-1}{2} \cdot \left(\left(B \cdot \left(\sqrt{2} \cdot \left(\frac{F \cdot \left(1 - -1 \cdot \left(C \cdot \sqrt{\frac{1}{{B}^{2} + {C}^{2}}}\right)\right)}{{B}^{2}} - -4 \cdot \frac{C \cdot \left(F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)\right)}{{B}^{4}}\right)\right)\right) \cdot \sqrt{\frac{1}{F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)}}\right)\right)} \]
    6. Applied rewrites15.8%

      \[\leadsto A \cdot \color{blue}{\mathsf{fma}\left(-1, \frac{\sqrt{2}}{A \cdot B} \cdot \sqrt{F \cdot \left(C - \mathsf{hypot}\left(B, C\right)\right)}, -0.5 \cdot \left(\left(B \cdot \left(\sqrt{2} \cdot \left(\frac{F \cdot \left(1 - -1 \cdot \left(C \cdot {\left(\mathsf{hypot}\left(B, C\right)\right)}^{-1}\right)\right)}{B \cdot B} - -4 \cdot \frac{C \cdot \left(F \cdot \left(C - \mathsf{hypot}\left(B, C\right)\right)\right)}{{B}^{4}}\right)\right)\right) \cdot {\left(\sqrt{F \cdot \left(C - \mathsf{hypot}\left(B, C\right)\right)}\right)}^{-1}\right)\right)} \]
    7. Taylor expanded in A around 0

      \[\leadsto A \cdot \left(-1 \cdot \left(\frac{\sqrt{2}}{A \cdot B} \cdot \color{blue}{\sqrt{F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)}}\right)\right) \]
    8. Step-by-step derivation
      1. sqrt-prodN/A

        \[\leadsto A \cdot \left(-1 \cdot \left(\frac{\sqrt{2}}{A \cdot B} \cdot \left(\sqrt{F} \cdot \sqrt{C - \sqrt{{B}^{2} + {C}^{2}}}\right)\right)\right) \]
      2. pow2N/A

        \[\leadsto A \cdot \left(-1 \cdot \left(\frac{\sqrt{2}}{A \cdot B} \cdot \left(\sqrt{F} \cdot \sqrt{C - \sqrt{B \cdot B + {C}^{2}}}\right)\right)\right) \]
      3. pow2N/A

        \[\leadsto A \cdot \left(-1 \cdot \left(\frac{\sqrt{2}}{A \cdot B} \cdot \left(\sqrt{F} \cdot \sqrt{C - \sqrt{B \cdot B + C \cdot C}}\right)\right)\right) \]
    9. Applied rewrites18.6%

      \[\leadsto A \cdot \left(-1 \cdot \left(\frac{\sqrt{2}}{A \cdot B} \cdot \color{blue}{\sqrt{F \cdot \left(C - \mathsf{hypot}\left(B, C\right)\right)}}\right)\right) \]
  3. Recombined 2 regimes into one program.
  4. Final simplification18.0%

    \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 2 \cdot 10^{-34}:\\ \;\;\;\;\sqrt{\left(-0.5 \cdot \frac{F}{C}\right) \cdot 2}\\ \mathbf{else}:\\ \;\;\;\;A \cdot \left(\frac{\sqrt{2}}{\left(-A\right) \cdot B} \cdot \sqrt{F \cdot \left(C - \mathsf{hypot}\left(B, C\right)\right)}\right)\\ \end{array} \]
  5. Add Preprocessing

Alternative 7: 21.2% accurate, N/A× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ A \cdot \left(\frac{\sqrt{2}}{\left(-A\right) \cdot B\_m} \cdot \sqrt{F \cdot \left(C - \mathsf{hypot}\left(B\_m, C\right)\right)}\right) \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (* A (* (/ (sqrt 2.0) (* (- A) B_m)) (sqrt (* F (- C (hypot B_m C)))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	return A * ((sqrt(2.0) / (-A * B_m)) * sqrt((F * (C - hypot(B_m, C)))));
}
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	return A * ((Math.sqrt(2.0) / (-A * B_m)) * Math.sqrt((F * (C - Math.hypot(B_m, C)))));
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	return A * ((math.sqrt(2.0) / (-A * B_m)) * math.sqrt((F * (C - math.hypot(B_m, C)))))
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	return Float64(A * Float64(Float64(sqrt(2.0) / Float64(Float64(-A) * B_m)) * sqrt(Float64(F * Float64(C - hypot(B_m, C))))))
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp = code(A, B_m, C, F)
	tmp = A * ((sqrt(2.0) / (-A * B_m)) * sqrt((F * (C - hypot(B_m, C)))));
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := N[(A * N[(N[(N[Sqrt[2.0], $MachinePrecision] / N[((-A) * B$95$m), $MachinePrecision]), $MachinePrecision] * N[Sqrt[N[(F * N[(C - N[Sqrt[B$95$m ^ 2 + C ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
A \cdot \left(\frac{\sqrt{2}}{\left(-A\right) \cdot B\_m} \cdot \sqrt{F \cdot \left(C - \mathsf{hypot}\left(B\_m, C\right)\right)}\right)
\end{array}
Derivation
  1. Initial program 17.1%

    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
  2. Add Preprocessing
  3. Taylor expanded in A around 0

    \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)}\right) + \frac{-1}{2} \cdot \left(\left(A \cdot \left(B \cdot \left(\sqrt{2} \cdot \left(\frac{F \cdot \left(1 - -1 \cdot \left(C \cdot \sqrt{\frac{1}{{B}^{2} + {C}^{2}}}\right)\right)}{{B}^{2}} - -4 \cdot \frac{C \cdot \left(F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)\right)}{{B}^{4}}\right)\right)\right)\right) \cdot \sqrt{\frac{1}{F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)}}\right)} \]
  4. Applied rewrites12.8%

    \[\leadsto \color{blue}{\mathsf{fma}\left(-1, \frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C - \mathsf{hypot}\left(B, C\right)\right)}, -0.5 \cdot \left(\left(A \cdot \left(B \cdot \left(\sqrt{2} \cdot \left(\frac{F \cdot \left(1 - -1 \cdot \left(C \cdot \frac{1}{\mathsf{hypot}\left(B, C\right)}\right)\right)}{B \cdot B} - -4 \cdot \frac{C \cdot \left(F \cdot \left(C - \mathsf{hypot}\left(B, C\right)\right)\right)}{{B}^{4}}\right)\right)\right)\right) \cdot \frac{1}{\sqrt{F \cdot \left(C - \mathsf{hypot}\left(B, C\right)\right)}}\right)\right)} \]
  5. Taylor expanded in A around inf

    \[\leadsto A \cdot \color{blue}{\left(-1 \cdot \left(\frac{\sqrt{2}}{A \cdot B} \cdot \sqrt{F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)}\right) + \frac{-1}{2} \cdot \left(\left(B \cdot \left(\sqrt{2} \cdot \left(\frac{F \cdot \left(1 - -1 \cdot \left(C \cdot \sqrt{\frac{1}{{B}^{2} + {C}^{2}}}\right)\right)}{{B}^{2}} - -4 \cdot \frac{C \cdot \left(F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)\right)}{{B}^{4}}\right)\right)\right) \cdot \sqrt{\frac{1}{F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)}}\right)\right)} \]
  6. Applied rewrites9.5%

    \[\leadsto A \cdot \color{blue}{\mathsf{fma}\left(-1, \frac{\sqrt{2}}{A \cdot B} \cdot \sqrt{F \cdot \left(C - \mathsf{hypot}\left(B, C\right)\right)}, -0.5 \cdot \left(\left(B \cdot \left(\sqrt{2} \cdot \left(\frac{F \cdot \left(1 - -1 \cdot \left(C \cdot {\left(\mathsf{hypot}\left(B, C\right)\right)}^{-1}\right)\right)}{B \cdot B} - -4 \cdot \frac{C \cdot \left(F \cdot \left(C - \mathsf{hypot}\left(B, C\right)\right)\right)}{{B}^{4}}\right)\right)\right) \cdot {\left(\sqrt{F \cdot \left(C - \mathsf{hypot}\left(B, C\right)\right)}\right)}^{-1}\right)\right)} \]
  7. Taylor expanded in A around 0

    \[\leadsto A \cdot \left(-1 \cdot \left(\frac{\sqrt{2}}{A \cdot B} \cdot \color{blue}{\sqrt{F \cdot \left(C - \sqrt{{B}^{2} + {C}^{2}}\right)}}\right)\right) \]
  8. Step-by-step derivation
    1. sqrt-prodN/A

      \[\leadsto A \cdot \left(-1 \cdot \left(\frac{\sqrt{2}}{A \cdot B} \cdot \left(\sqrt{F} \cdot \sqrt{C - \sqrt{{B}^{2} + {C}^{2}}}\right)\right)\right) \]
    2. pow2N/A

      \[\leadsto A \cdot \left(-1 \cdot \left(\frac{\sqrt{2}}{A \cdot B} \cdot \left(\sqrt{F} \cdot \sqrt{C - \sqrt{B \cdot B + {C}^{2}}}\right)\right)\right) \]
    3. pow2N/A

      \[\leadsto A \cdot \left(-1 \cdot \left(\frac{\sqrt{2}}{A \cdot B} \cdot \left(\sqrt{F} \cdot \sqrt{C - \sqrt{B \cdot B + C \cdot C}}\right)\right)\right) \]
  9. Applied rewrites11.8%

    \[\leadsto A \cdot \left(-1 \cdot \left(\frac{\sqrt{2}}{A \cdot B} \cdot \color{blue}{\sqrt{F \cdot \left(C - \mathsf{hypot}\left(B, C\right)\right)}}\right)\right) \]
  10. Final simplification11.8%

    \[\leadsto A \cdot \left(\frac{\sqrt{2}}{\left(-A\right) \cdot B} \cdot \sqrt{F \cdot \left(C - \mathsf{hypot}\left(B, C\right)\right)}\right) \]
  11. Add Preprocessing

Alternative 8: 2.0% accurate, N/A× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \frac{\sqrt{2}}{B\_m} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(A, B\_m\right)\right)} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (* (/ (sqrt 2.0) B_m) (sqrt (* F (- A (hypot A B_m))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	return (sqrt(2.0) / B_m) * sqrt((F * (A - hypot(A, B_m))));
}
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	return (Math.sqrt(2.0) / B_m) * Math.sqrt((F * (A - Math.hypot(A, B_m))));
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	return (math.sqrt(2.0) / B_m) * math.sqrt((F * (A - math.hypot(A, B_m))))
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	return Float64(Float64(sqrt(2.0) / B_m) * sqrt(Float64(F * Float64(A - hypot(A, B_m)))))
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp = code(A, B_m, C, F)
	tmp = (sqrt(2.0) / B_m) * sqrt((F * (A - hypot(A, B_m))));
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := N[(N[(N[Sqrt[2.0], $MachinePrecision] / B$95$m), $MachinePrecision] * N[Sqrt[N[(F * N[(A - N[Sqrt[A ^ 2 + B$95$m ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\frac{\sqrt{2}}{B\_m} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(A, B\_m\right)\right)}
\end{array}
Derivation
  1. Initial program 17.1%

    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
  2. Add Preprocessing
  3. Taylor expanded in F around -inf

    \[\leadsto \color{blue}{\sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \left(\sqrt{-2} \cdot \sqrt{-1}\right)} \]
  4. Step-by-step derivation
    1. sqrt-unprodN/A

      \[\leadsto \sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{-2 \cdot -1} \]
    2. metadata-evalN/A

      \[\leadsto \sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2} \]
    3. sqrt-unprodN/A

      \[\leadsto \sqrt{\frac{F \cdot \left(\left(A + C\right) - \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)} \cdot 2} \]
  5. Applied rewrites8.9%

    \[\leadsto \color{blue}{\sqrt{\frac{F \cdot \left(\left(A + C\right) - \mathsf{hypot}\left(B, A - C\right)\right)}{B \cdot B - 4 \cdot \left(A \cdot C\right)} \cdot 2}} \]
  6. Taylor expanded in C around 0

    \[\leadsto \frac{\sqrt{2}}{B} \cdot \color{blue}{\sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)}} \]
  7. Step-by-step derivation
    1. lift-sqrt.f64N/A

      \[\leadsto \frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)} \]
    2. lift-/.f64N/A

      \[\leadsto \frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{{A}^{2} + {B}^{2}}\right)} \]
    3. pow2N/A

      \[\leadsto \frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{A \cdot A + {B}^{2}}\right)} \]
    4. pow2N/A

      \[\leadsto \frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \sqrt{A \cdot A + B \cdot B}\right)} \]
    5. lift-hypot.f64N/A

      \[\leadsto \frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(A, B\right)\right)} \]
    6. lift--.f64N/A

      \[\leadsto \frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(A, B\right)\right)} \]
    7. lift-*.f64N/A

      \[\leadsto \frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(A, B\right)\right)} \]
    8. lift-sqrt.f64N/A

      \[\leadsto \frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(A, B\right)\right)} \]
    9. lift-*.f6417.5

      \[\leadsto \frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A - \mathsf{hypot}\left(A, B\right)\right)} \]
  8. Applied rewrites17.5%

    \[\leadsto \frac{\sqrt{2}}{B} \cdot \color{blue}{\sqrt{F \cdot \left(A - \mathsf{hypot}\left(A, B\right)\right)}} \]
  9. Add Preprocessing

Reproduce

?
herbie shell --seed 2025057 
(FPCore (A B C F)
  :name "ABCF->ab-angle b"
  :precision binary64
  (/ (- (sqrt (* (* 2.0 (* (- (pow B 2.0) (* (* 4.0 A) C)) F)) (- (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))) (- (pow B 2.0) (* (* 4.0 A) C))))