Compound Interest

Percentage Accurate: 28.6% → 93.2%
Time: 10.6s
Alternatives: 13
Speedup: 24.3×

Specification

?
\[\begin{array}{l} \\ 100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \end{array} \]
(FPCore (i n)
 :precision binary64
 (* 100.0 (/ (- (pow (+ 1.0 (/ i n)) n) 1.0) (/ i n))))
double code(double i, double n) {
	return 100.0 * ((pow((1.0 + (i / n)), n) - 1.0) / (i / n));
}
real(8) function code(i, n)
    real(8), intent (in) :: i
    real(8), intent (in) :: n
    code = 100.0d0 * ((((1.0d0 + (i / n)) ** n) - 1.0d0) / (i / n))
end function
public static double code(double i, double n) {
	return 100.0 * ((Math.pow((1.0 + (i / n)), n) - 1.0) / (i / n));
}
def code(i, n):
	return 100.0 * ((math.pow((1.0 + (i / n)), n) - 1.0) / (i / n))
function code(i, n)
	return Float64(100.0 * Float64(Float64((Float64(1.0 + Float64(i / n)) ^ n) - 1.0) / Float64(i / n)))
end
function tmp = code(i, n)
	tmp = 100.0 * ((((1.0 + (i / n)) ^ n) - 1.0) / (i / n));
end
code[i_, n_] := N[(100.0 * N[(N[(N[Power[N[(1.0 + N[(i / n), $MachinePrecision]), $MachinePrecision], n], $MachinePrecision] - 1.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 13 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 28.6% accurate, 1.0× speedup?

\[\begin{array}{l} \\ 100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \end{array} \]
(FPCore (i n)
 :precision binary64
 (* 100.0 (/ (- (pow (+ 1.0 (/ i n)) n) 1.0) (/ i n))))
double code(double i, double n) {
	return 100.0 * ((pow((1.0 + (i / n)), n) - 1.0) / (i / n));
}
real(8) function code(i, n)
    real(8), intent (in) :: i
    real(8), intent (in) :: n
    code = 100.0d0 * ((((1.0d0 + (i / n)) ** n) - 1.0d0) / (i / n))
end function
public static double code(double i, double n) {
	return 100.0 * ((Math.pow((1.0 + (i / n)), n) - 1.0) / (i / n));
}
def code(i, n):
	return 100.0 * ((math.pow((1.0 + (i / n)), n) - 1.0) / (i / n))
function code(i, n)
	return Float64(100.0 * Float64(Float64((Float64(1.0 + Float64(i / n)) ^ n) - 1.0) / Float64(i / n)))
end
function tmp = code(i, n)
	tmp = 100.0 * ((((1.0 + (i / n)) ^ n) - 1.0) / (i / n));
end
code[i_, n_] := N[(100.0 * N[(N[(N[Power[N[(1.0 + N[(i / n), $MachinePrecision]), $MachinePrecision], n], $MachinePrecision] - 1.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}
\end{array}

Alternative 1: 93.2% accurate, 0.3× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := {\left(1 + \frac{i}{n}\right)}^{n} - 1\\ t_1 := 100 \cdot \frac{t\_0}{\frac{i}{n}}\\ \mathbf{if}\;t\_1 \leq 0:\\ \;\;\;\;\left(\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right) \cdot \frac{100}{i}\right) \cdot n\\ \mathbf{elif}\;t\_1 \leq \infty:\\ \;\;\;\;\frac{100 \cdot t\_0}{i} \cdot n\\ \mathbf{else}:\\ \;\;\;\;100 \cdot n\\ \end{array} \end{array} \]
(FPCore (i n)
 :precision binary64
 (let* ((t_0 (- (pow (+ 1.0 (/ i n)) n) 1.0)) (t_1 (* 100.0 (/ t_0 (/ i n)))))
   (if (<= t_1 0.0)
     (* (* (expm1 (* (log1p (/ i n)) n)) (/ 100.0 i)) n)
     (if (<= t_1 INFINITY) (* (/ (* 100.0 t_0) i) n) (* 100.0 n)))))
double code(double i, double n) {
	double t_0 = pow((1.0 + (i / n)), n) - 1.0;
	double t_1 = 100.0 * (t_0 / (i / n));
	double tmp;
	if (t_1 <= 0.0) {
		tmp = (expm1((log1p((i / n)) * n)) * (100.0 / i)) * n;
	} else if (t_1 <= ((double) INFINITY)) {
		tmp = ((100.0 * t_0) / i) * n;
	} else {
		tmp = 100.0 * n;
	}
	return tmp;
}
public static double code(double i, double n) {
	double t_0 = Math.pow((1.0 + (i / n)), n) - 1.0;
	double t_1 = 100.0 * (t_0 / (i / n));
	double tmp;
	if (t_1 <= 0.0) {
		tmp = (Math.expm1((Math.log1p((i / n)) * n)) * (100.0 / i)) * n;
	} else if (t_1 <= Double.POSITIVE_INFINITY) {
		tmp = ((100.0 * t_0) / i) * n;
	} else {
		tmp = 100.0 * n;
	}
	return tmp;
}
def code(i, n):
	t_0 = math.pow((1.0 + (i / n)), n) - 1.0
	t_1 = 100.0 * (t_0 / (i / n))
	tmp = 0
	if t_1 <= 0.0:
		tmp = (math.expm1((math.log1p((i / n)) * n)) * (100.0 / i)) * n
	elif t_1 <= math.inf:
		tmp = ((100.0 * t_0) / i) * n
	else:
		tmp = 100.0 * n
	return tmp
function code(i, n)
	t_0 = Float64((Float64(1.0 + Float64(i / n)) ^ n) - 1.0)
	t_1 = Float64(100.0 * Float64(t_0 / Float64(i / n)))
	tmp = 0.0
	if (t_1 <= 0.0)
		tmp = Float64(Float64(expm1(Float64(log1p(Float64(i / n)) * n)) * Float64(100.0 / i)) * n);
	elseif (t_1 <= Inf)
		tmp = Float64(Float64(Float64(100.0 * t_0) / i) * n);
	else
		tmp = Float64(100.0 * n);
	end
	return tmp
end
code[i_, n_] := Block[{t$95$0 = N[(N[Power[N[(1.0 + N[(i / n), $MachinePrecision]), $MachinePrecision], n], $MachinePrecision] - 1.0), $MachinePrecision]}, Block[{t$95$1 = N[(100.0 * N[(t$95$0 / N[(i / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$1, 0.0], N[(N[(N[(Exp[N[(N[Log[1 + N[(i / n), $MachinePrecision]], $MachinePrecision] * n), $MachinePrecision]] - 1), $MachinePrecision] * N[(100.0 / i), $MachinePrecision]), $MachinePrecision] * n), $MachinePrecision], If[LessEqual[t$95$1, Infinity], N[(N[(N[(100.0 * t$95$0), $MachinePrecision] / i), $MachinePrecision] * n), $MachinePrecision], N[(100.0 * n), $MachinePrecision]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {\left(1 + \frac{i}{n}\right)}^{n} - 1\\
t_1 := 100 \cdot \frac{t\_0}{\frac{i}{n}}\\
\mathbf{if}\;t\_1 \leq 0:\\
\;\;\;\;\left(\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right) \cdot \frac{100}{i}\right) \cdot n\\

\mathbf{elif}\;t\_1 \leq \infty:\\
\;\;\;\;\frac{100 \cdot t\_0}{i} \cdot n\\

\mathbf{else}:\\
\;\;\;\;100 \cdot n\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (*.f64 #s(literal 100 binary64) (/.f64 (-.f64 (pow.f64 (+.f64 #s(literal 1 binary64) (/.f64 i n)) n) #s(literal 1 binary64)) (/.f64 i n))) < -0.0

    1. Initial program 26.1%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      2. lift-/.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      3. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\frac{i}{n}}} \]
      4. lift-/.f64N/A

        \[\leadsto \frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\color{blue}{\frac{i}{n}}} \]
      5. associate-/r/N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{i} \cdot n} \]
      6. lower-*.f64N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{i} \cdot n} \]
    4. Applied rewrites98.5%

      \[\leadsto \color{blue}{\left(\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right) \cdot \frac{100}{i}\right) \cdot n} \]

    if -0.0 < (*.f64 #s(literal 100 binary64) (/.f64 (-.f64 (pow.f64 (+.f64 #s(literal 1 binary64) (/.f64 i n)) n) #s(literal 1 binary64)) (/.f64 i n))) < +inf.0

    1. Initial program 99.6%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      2. lift-/.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      3. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\frac{i}{n}}} \]
      4. lift-/.f64N/A

        \[\leadsto \frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\color{blue}{\frac{i}{n}}} \]
      5. associate-/r/N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{i} \cdot n} \]
      6. lower-*.f64N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{i} \cdot n} \]
    4. Applied rewrites73.0%

      \[\leadsto \color{blue}{\left(\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right) \cdot \frac{100}{i}\right) \cdot n} \]
    5. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{\left(\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right) \cdot \frac{100}{i}\right)} \cdot n \]
      2. lift-/.f64N/A

        \[\leadsto \left(\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right) \cdot \color{blue}{\frac{100}{i}}\right) \cdot n \]
      3. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right) \cdot 100}{i}} \cdot n \]
      4. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right) \cdot 100}{i}} \cdot n \]
      5. *-commutativeN/A

        \[\leadsto \frac{\color{blue}{100 \cdot \mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right)}}{i} \cdot n \]
      6. lower-*.f6473.0

        \[\leadsto \frac{\color{blue}{100 \cdot \mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right)}}{i} \cdot n \]
    6. Applied rewrites73.0%

      \[\leadsto \color{blue}{\frac{100 \cdot \mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right)}{i}} \cdot n \]
    7. Step-by-step derivation
      1. lift-expm1.f64N/A

        \[\leadsto \frac{100 \cdot \color{blue}{\left(e^{\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n} - 1\right)}}{i} \cdot n \]
      2. lower--.f64N/A

        \[\leadsto \frac{100 \cdot \color{blue}{\left(e^{\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n} - 1\right)}}{i} \cdot n \]
      3. lift-*.f64N/A

        \[\leadsto \frac{100 \cdot \left(e^{\color{blue}{\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n}} - 1\right)}{i} \cdot n \]
      4. lift-log1p.f64N/A

        \[\leadsto \frac{100 \cdot \left(e^{\color{blue}{\log \left(1 + \frac{i}{n}\right)} \cdot n} - 1\right)}{i} \cdot n \]
      5. lift-/.f64N/A

        \[\leadsto \frac{100 \cdot \left(e^{\log \left(1 + \color{blue}{\frac{i}{n}}\right) \cdot n} - 1\right)}{i} \cdot n \]
      6. pow-to-expN/A

        \[\leadsto \frac{100 \cdot \left(\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n}} - 1\right)}{i} \cdot n \]
      7. lower-pow.f64N/A

        \[\leadsto \frac{100 \cdot \left(\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n}} - 1\right)}{i} \cdot n \]
      8. lift-/.f64N/A

        \[\leadsto \frac{100 \cdot \left({\left(1 + \color{blue}{\frac{i}{n}}\right)}^{n} - 1\right)}{i} \cdot n \]
      9. lower-+.f6499.7

        \[\leadsto \frac{100 \cdot \left({\color{blue}{\left(1 + \frac{i}{n}\right)}}^{n} - 1\right)}{i} \cdot n \]
    8. Applied rewrites99.7%

      \[\leadsto \frac{100 \cdot \color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}}{i} \cdot n \]

    if +inf.0 < (*.f64 #s(literal 100 binary64) (/.f64 (-.f64 (pow.f64 (+.f64 #s(literal 1 binary64) (/.f64 i n)) n) #s(literal 1 binary64)) (/.f64 i n)))

    1. Initial program 0.0%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Taylor expanded in i around 0

      \[\leadsto \color{blue}{100 \cdot n} \]
    4. Step-by-step derivation
      1. lower-*.f6482.5

        \[\leadsto \color{blue}{100 \cdot n} \]
    5. Applied rewrites82.5%

      \[\leadsto \color{blue}{100 \cdot n} \]
  3. Recombined 3 regimes into one program.
  4. Add Preprocessing

Alternative 2: 81.4% accurate, 0.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{\mathsf{expm1}\left(i\right)}{i}\\ \mathbf{if}\;n \leq -1.05 \cdot 10^{-191}:\\ \;\;\;\;100 \cdot \left(t\_0 \cdot n\right)\\ \mathbf{elif}\;n \leq -2 \cdot 10^{-310}:\\ \;\;\;\;\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{i} \cdot n\\ \mathbf{elif}\;n \leq 1.8 \cdot 10^{-112}:\\ \;\;\;\;\left(\left(\left(\log i - \log n\right) \cdot n\right) \cdot \frac{100}{i}\right) \cdot n\\ \mathbf{else}:\\ \;\;\;\;\left(t\_0 \cdot 100\right) \cdot n\\ \end{array} \end{array} \]
(FPCore (i n)
 :precision binary64
 (let* ((t_0 (/ (expm1 i) i)))
   (if (<= n -1.05e-191)
     (* 100.0 (* t_0 n))
     (if (<= n -2e-310)
       (* (/ (* 100.0 (- (pow (+ 1.0 (/ i n)) n) 1.0)) i) n)
       (if (<= n 1.8e-112)
         (* (* (* (- (log i) (log n)) n) (/ 100.0 i)) n)
         (* (* t_0 100.0) n))))))
double code(double i, double n) {
	double t_0 = expm1(i) / i;
	double tmp;
	if (n <= -1.05e-191) {
		tmp = 100.0 * (t_0 * n);
	} else if (n <= -2e-310) {
		tmp = ((100.0 * (pow((1.0 + (i / n)), n) - 1.0)) / i) * n;
	} else if (n <= 1.8e-112) {
		tmp = (((log(i) - log(n)) * n) * (100.0 / i)) * n;
	} else {
		tmp = (t_0 * 100.0) * n;
	}
	return tmp;
}
public static double code(double i, double n) {
	double t_0 = Math.expm1(i) / i;
	double tmp;
	if (n <= -1.05e-191) {
		tmp = 100.0 * (t_0 * n);
	} else if (n <= -2e-310) {
		tmp = ((100.0 * (Math.pow((1.0 + (i / n)), n) - 1.0)) / i) * n;
	} else if (n <= 1.8e-112) {
		tmp = (((Math.log(i) - Math.log(n)) * n) * (100.0 / i)) * n;
	} else {
		tmp = (t_0 * 100.0) * n;
	}
	return tmp;
}
def code(i, n):
	t_0 = math.expm1(i) / i
	tmp = 0
	if n <= -1.05e-191:
		tmp = 100.0 * (t_0 * n)
	elif n <= -2e-310:
		tmp = ((100.0 * (math.pow((1.0 + (i / n)), n) - 1.0)) / i) * n
	elif n <= 1.8e-112:
		tmp = (((math.log(i) - math.log(n)) * n) * (100.0 / i)) * n
	else:
		tmp = (t_0 * 100.0) * n
	return tmp
function code(i, n)
	t_0 = Float64(expm1(i) / i)
	tmp = 0.0
	if (n <= -1.05e-191)
		tmp = Float64(100.0 * Float64(t_0 * n));
	elseif (n <= -2e-310)
		tmp = Float64(Float64(Float64(100.0 * Float64((Float64(1.0 + Float64(i / n)) ^ n) - 1.0)) / i) * n);
	elseif (n <= 1.8e-112)
		tmp = Float64(Float64(Float64(Float64(log(i) - log(n)) * n) * Float64(100.0 / i)) * n);
	else
		tmp = Float64(Float64(t_0 * 100.0) * n);
	end
	return tmp
end
code[i_, n_] := Block[{t$95$0 = N[(N[(Exp[i] - 1), $MachinePrecision] / i), $MachinePrecision]}, If[LessEqual[n, -1.05e-191], N[(100.0 * N[(t$95$0 * n), $MachinePrecision]), $MachinePrecision], If[LessEqual[n, -2e-310], N[(N[(N[(100.0 * N[(N[Power[N[(1.0 + N[(i / n), $MachinePrecision]), $MachinePrecision], n], $MachinePrecision] - 1.0), $MachinePrecision]), $MachinePrecision] / i), $MachinePrecision] * n), $MachinePrecision], If[LessEqual[n, 1.8e-112], N[(N[(N[(N[(N[Log[i], $MachinePrecision] - N[Log[n], $MachinePrecision]), $MachinePrecision] * n), $MachinePrecision] * N[(100.0 / i), $MachinePrecision]), $MachinePrecision] * n), $MachinePrecision], N[(N[(t$95$0 * 100.0), $MachinePrecision] * n), $MachinePrecision]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{\mathsf{expm1}\left(i\right)}{i}\\
\mathbf{if}\;n \leq -1.05 \cdot 10^{-191}:\\
\;\;\;\;100 \cdot \left(t\_0 \cdot n\right)\\

\mathbf{elif}\;n \leq -2 \cdot 10^{-310}:\\
\;\;\;\;\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{i} \cdot n\\

\mathbf{elif}\;n \leq 1.8 \cdot 10^{-112}:\\
\;\;\;\;\left(\left(\left(\log i - \log n\right) \cdot n\right) \cdot \frac{100}{i}\right) \cdot n\\

\mathbf{else}:\\
\;\;\;\;\left(t\_0 \cdot 100\right) \cdot n\\


\end{array}
\end{array}
Derivation
  1. Split input into 4 regimes
  2. if n < -1.04999999999999993e-191

    1. Initial program 22.6%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Taylor expanded in n around inf

      \[\leadsto 100 \cdot \color{blue}{\frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
    4. Step-by-step derivation
      1. associate-/l*N/A

        \[\leadsto 100 \cdot \color{blue}{\left(n \cdot \frac{e^{i} - 1}{i}\right)} \]
      2. *-commutativeN/A

        \[\leadsto 100 \cdot \color{blue}{\left(\frac{e^{i} - 1}{i} \cdot n\right)} \]
      3. lower-*.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\left(\frac{e^{i} - 1}{i} \cdot n\right)} \]
      4. lower-/.f64N/A

        \[\leadsto 100 \cdot \left(\color{blue}{\frac{e^{i} - 1}{i}} \cdot n\right) \]
      5. lower-expm1.f6485.7

        \[\leadsto 100 \cdot \left(\frac{\color{blue}{\mathsf{expm1}\left(i\right)}}{i} \cdot n\right) \]
    5. Applied rewrites85.7%

      \[\leadsto 100 \cdot \color{blue}{\left(\frac{\mathsf{expm1}\left(i\right)}{i} \cdot n\right)} \]

    if -1.04999999999999993e-191 < n < -1.999999999999994e-310

    1. Initial program 78.1%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      2. lift-/.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      3. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\frac{i}{n}}} \]
      4. lift-/.f64N/A

        \[\leadsto \frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\color{blue}{\frac{i}{n}}} \]
      5. associate-/r/N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{i} \cdot n} \]
      6. lower-*.f64N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{i} \cdot n} \]
    4. Applied rewrites99.9%

      \[\leadsto \color{blue}{\left(\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right) \cdot \frac{100}{i}\right) \cdot n} \]
    5. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{\left(\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right) \cdot \frac{100}{i}\right)} \cdot n \]
      2. lift-/.f64N/A

        \[\leadsto \left(\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right) \cdot \color{blue}{\frac{100}{i}}\right) \cdot n \]
      3. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right) \cdot 100}{i}} \cdot n \]
      4. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right) \cdot 100}{i}} \cdot n \]
      5. *-commutativeN/A

        \[\leadsto \frac{\color{blue}{100 \cdot \mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right)}}{i} \cdot n \]
      6. lower-*.f6499.8

        \[\leadsto \frac{\color{blue}{100 \cdot \mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right)}}{i} \cdot n \]
    6. Applied rewrites99.8%

      \[\leadsto \color{blue}{\frac{100 \cdot \mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right)}{i}} \cdot n \]
    7. Step-by-step derivation
      1. lift-expm1.f64N/A

        \[\leadsto \frac{100 \cdot \color{blue}{\left(e^{\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n} - 1\right)}}{i} \cdot n \]
      2. lower--.f64N/A

        \[\leadsto \frac{100 \cdot \color{blue}{\left(e^{\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n} - 1\right)}}{i} \cdot n \]
      3. lift-*.f64N/A

        \[\leadsto \frac{100 \cdot \left(e^{\color{blue}{\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n}} - 1\right)}{i} \cdot n \]
      4. lift-log1p.f64N/A

        \[\leadsto \frac{100 \cdot \left(e^{\color{blue}{\log \left(1 + \frac{i}{n}\right)} \cdot n} - 1\right)}{i} \cdot n \]
      5. lift-/.f64N/A

        \[\leadsto \frac{100 \cdot \left(e^{\log \left(1 + \color{blue}{\frac{i}{n}}\right) \cdot n} - 1\right)}{i} \cdot n \]
      6. pow-to-expN/A

        \[\leadsto \frac{100 \cdot \left(\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n}} - 1\right)}{i} \cdot n \]
      7. lower-pow.f64N/A

        \[\leadsto \frac{100 \cdot \left(\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n}} - 1\right)}{i} \cdot n \]
      8. lift-/.f64N/A

        \[\leadsto \frac{100 \cdot \left({\left(1 + \color{blue}{\frac{i}{n}}\right)}^{n} - 1\right)}{i} \cdot n \]
      9. lower-+.f6478.1

        \[\leadsto \frac{100 \cdot \left({\color{blue}{\left(1 + \frac{i}{n}\right)}}^{n} - 1\right)}{i} \cdot n \]
    8. Applied rewrites78.1%

      \[\leadsto \frac{100 \cdot \color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}}{i} \cdot n \]

    if -1.999999999999994e-310 < n < 1.8e-112

    1. Initial program 34.8%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      2. lift-/.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      3. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\frac{i}{n}}} \]
      4. lift-/.f64N/A

        \[\leadsto \frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\color{blue}{\frac{i}{n}}} \]
      5. associate-/r/N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{i} \cdot n} \]
      6. lower-*.f64N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{i} \cdot n} \]
    4. Applied rewrites71.7%

      \[\leadsto \color{blue}{\left(\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right) \cdot \frac{100}{i}\right) \cdot n} \]
    5. Taylor expanded in n around 0

      \[\leadsto \left(\color{blue}{\left(n \cdot \left(\log i + -1 \cdot \log n\right)\right)} \cdot \frac{100}{i}\right) \cdot n \]
    6. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto \left(\color{blue}{\left(\left(\log i + -1 \cdot \log n\right) \cdot n\right)} \cdot \frac{100}{i}\right) \cdot n \]
      2. lower-*.f64N/A

        \[\leadsto \left(\color{blue}{\left(\left(\log i + -1 \cdot \log n\right) \cdot n\right)} \cdot \frac{100}{i}\right) \cdot n \]
      3. fp-cancel-sign-sub-invN/A

        \[\leadsto \left(\left(\color{blue}{\left(\log i - \left(\mathsf{neg}\left(-1\right)\right) \cdot \log n\right)} \cdot n\right) \cdot \frac{100}{i}\right) \cdot n \]
      4. metadata-evalN/A

        \[\leadsto \left(\left(\left(\log i - \color{blue}{1} \cdot \log n\right) \cdot n\right) \cdot \frac{100}{i}\right) \cdot n \]
      5. *-lft-identityN/A

        \[\leadsto \left(\left(\left(\log i - \color{blue}{\log n}\right) \cdot n\right) \cdot \frac{100}{i}\right) \cdot n \]
      6. lower--.f64N/A

        \[\leadsto \left(\left(\color{blue}{\left(\log i - \log n\right)} \cdot n\right) \cdot \frac{100}{i}\right) \cdot n \]
      7. lower-log.f64N/A

        \[\leadsto \left(\left(\left(\color{blue}{\log i} - \log n\right) \cdot n\right) \cdot \frac{100}{i}\right) \cdot n \]
      8. lower-log.f6483.3

        \[\leadsto \left(\left(\left(\log i - \color{blue}{\log n}\right) \cdot n\right) \cdot \frac{100}{i}\right) \cdot n \]
    7. Applied rewrites83.3%

      \[\leadsto \left(\color{blue}{\left(\left(\log i - \log n\right) \cdot n\right)} \cdot \frac{100}{i}\right) \cdot n \]

    if 1.8e-112 < n

    1. Initial program 23.5%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Taylor expanded in n around inf

      \[\leadsto \color{blue}{100 \cdot \frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
    4. Step-by-step derivation
      1. associate-/l*N/A

        \[\leadsto 100 \cdot \color{blue}{\left(n \cdot \frac{e^{i} - 1}{i}\right)} \]
      2. *-commutativeN/A

        \[\leadsto 100 \cdot \color{blue}{\left(\frac{e^{i} - 1}{i} \cdot n\right)} \]
      3. associate-*l*N/A

        \[\leadsto \color{blue}{\left(100 \cdot \frac{e^{i} - 1}{i}\right) \cdot n} \]
      4. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(100 \cdot \frac{e^{i} - 1}{i}\right) \cdot n} \]
      5. *-commutativeN/A

        \[\leadsto \color{blue}{\left(\frac{e^{i} - 1}{i} \cdot 100\right)} \cdot n \]
      6. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\frac{e^{i} - 1}{i} \cdot 100\right)} \cdot n \]
      7. lower-/.f64N/A

        \[\leadsto \left(\color{blue}{\frac{e^{i} - 1}{i}} \cdot 100\right) \cdot n \]
      8. lower-expm1.f6487.8

        \[\leadsto \left(\frac{\color{blue}{\mathsf{expm1}\left(i\right)}}{i} \cdot 100\right) \cdot n \]
    5. Applied rewrites87.8%

      \[\leadsto \color{blue}{\left(\frac{\mathsf{expm1}\left(i\right)}{i} \cdot 100\right) \cdot n} \]
  3. Recombined 4 regimes into one program.
  4. Add Preprocessing

Alternative 3: 81.4% accurate, 0.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{\mathsf{expm1}\left(i\right)}{i}\\ \mathbf{if}\;n \leq -1.05 \cdot 10^{-191}:\\ \;\;\;\;100 \cdot \left(t\_0 \cdot n\right)\\ \mathbf{elif}\;n \leq -2 \cdot 10^{-310}:\\ \;\;\;\;\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{i} \cdot n\\ \mathbf{elif}\;n \leq 1.8 \cdot 10^{-112}:\\ \;\;\;\;\left(\left(n \cdot \frac{\log i - \log n}{i}\right) \cdot 100\right) \cdot n\\ \mathbf{else}:\\ \;\;\;\;\left(t\_0 \cdot 100\right) \cdot n\\ \end{array} \end{array} \]
(FPCore (i n)
 :precision binary64
 (let* ((t_0 (/ (expm1 i) i)))
   (if (<= n -1.05e-191)
     (* 100.0 (* t_0 n))
     (if (<= n -2e-310)
       (* (/ (* 100.0 (- (pow (+ 1.0 (/ i n)) n) 1.0)) i) n)
       (if (<= n 1.8e-112)
         (* (* (* n (/ (- (log i) (log n)) i)) 100.0) n)
         (* (* t_0 100.0) n))))))
double code(double i, double n) {
	double t_0 = expm1(i) / i;
	double tmp;
	if (n <= -1.05e-191) {
		tmp = 100.0 * (t_0 * n);
	} else if (n <= -2e-310) {
		tmp = ((100.0 * (pow((1.0 + (i / n)), n) - 1.0)) / i) * n;
	} else if (n <= 1.8e-112) {
		tmp = ((n * ((log(i) - log(n)) / i)) * 100.0) * n;
	} else {
		tmp = (t_0 * 100.0) * n;
	}
	return tmp;
}
public static double code(double i, double n) {
	double t_0 = Math.expm1(i) / i;
	double tmp;
	if (n <= -1.05e-191) {
		tmp = 100.0 * (t_0 * n);
	} else if (n <= -2e-310) {
		tmp = ((100.0 * (Math.pow((1.0 + (i / n)), n) - 1.0)) / i) * n;
	} else if (n <= 1.8e-112) {
		tmp = ((n * ((Math.log(i) - Math.log(n)) / i)) * 100.0) * n;
	} else {
		tmp = (t_0 * 100.0) * n;
	}
	return tmp;
}
def code(i, n):
	t_0 = math.expm1(i) / i
	tmp = 0
	if n <= -1.05e-191:
		tmp = 100.0 * (t_0 * n)
	elif n <= -2e-310:
		tmp = ((100.0 * (math.pow((1.0 + (i / n)), n) - 1.0)) / i) * n
	elif n <= 1.8e-112:
		tmp = ((n * ((math.log(i) - math.log(n)) / i)) * 100.0) * n
	else:
		tmp = (t_0 * 100.0) * n
	return tmp
function code(i, n)
	t_0 = Float64(expm1(i) / i)
	tmp = 0.0
	if (n <= -1.05e-191)
		tmp = Float64(100.0 * Float64(t_0 * n));
	elseif (n <= -2e-310)
		tmp = Float64(Float64(Float64(100.0 * Float64((Float64(1.0 + Float64(i / n)) ^ n) - 1.0)) / i) * n);
	elseif (n <= 1.8e-112)
		tmp = Float64(Float64(Float64(n * Float64(Float64(log(i) - log(n)) / i)) * 100.0) * n);
	else
		tmp = Float64(Float64(t_0 * 100.0) * n);
	end
	return tmp
end
code[i_, n_] := Block[{t$95$0 = N[(N[(Exp[i] - 1), $MachinePrecision] / i), $MachinePrecision]}, If[LessEqual[n, -1.05e-191], N[(100.0 * N[(t$95$0 * n), $MachinePrecision]), $MachinePrecision], If[LessEqual[n, -2e-310], N[(N[(N[(100.0 * N[(N[Power[N[(1.0 + N[(i / n), $MachinePrecision]), $MachinePrecision], n], $MachinePrecision] - 1.0), $MachinePrecision]), $MachinePrecision] / i), $MachinePrecision] * n), $MachinePrecision], If[LessEqual[n, 1.8e-112], N[(N[(N[(n * N[(N[(N[Log[i], $MachinePrecision] - N[Log[n], $MachinePrecision]), $MachinePrecision] / i), $MachinePrecision]), $MachinePrecision] * 100.0), $MachinePrecision] * n), $MachinePrecision], N[(N[(t$95$0 * 100.0), $MachinePrecision] * n), $MachinePrecision]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{\mathsf{expm1}\left(i\right)}{i}\\
\mathbf{if}\;n \leq -1.05 \cdot 10^{-191}:\\
\;\;\;\;100 \cdot \left(t\_0 \cdot n\right)\\

\mathbf{elif}\;n \leq -2 \cdot 10^{-310}:\\
\;\;\;\;\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{i} \cdot n\\

\mathbf{elif}\;n \leq 1.8 \cdot 10^{-112}:\\
\;\;\;\;\left(\left(n \cdot \frac{\log i - \log n}{i}\right) \cdot 100\right) \cdot n\\

\mathbf{else}:\\
\;\;\;\;\left(t\_0 \cdot 100\right) \cdot n\\


\end{array}
\end{array}
Derivation
  1. Split input into 4 regimes
  2. if n < -1.04999999999999993e-191

    1. Initial program 22.6%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Taylor expanded in n around inf

      \[\leadsto 100 \cdot \color{blue}{\frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
    4. Step-by-step derivation
      1. associate-/l*N/A

        \[\leadsto 100 \cdot \color{blue}{\left(n \cdot \frac{e^{i} - 1}{i}\right)} \]
      2. *-commutativeN/A

        \[\leadsto 100 \cdot \color{blue}{\left(\frac{e^{i} - 1}{i} \cdot n\right)} \]
      3. lower-*.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\left(\frac{e^{i} - 1}{i} \cdot n\right)} \]
      4. lower-/.f64N/A

        \[\leadsto 100 \cdot \left(\color{blue}{\frac{e^{i} - 1}{i}} \cdot n\right) \]
      5. lower-expm1.f6485.7

        \[\leadsto 100 \cdot \left(\frac{\color{blue}{\mathsf{expm1}\left(i\right)}}{i} \cdot n\right) \]
    5. Applied rewrites85.7%

      \[\leadsto 100 \cdot \color{blue}{\left(\frac{\mathsf{expm1}\left(i\right)}{i} \cdot n\right)} \]

    if -1.04999999999999993e-191 < n < -1.999999999999994e-310

    1. Initial program 78.1%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      2. lift-/.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      3. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\frac{i}{n}}} \]
      4. lift-/.f64N/A

        \[\leadsto \frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\color{blue}{\frac{i}{n}}} \]
      5. associate-/r/N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{i} \cdot n} \]
      6. lower-*.f64N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{i} \cdot n} \]
    4. Applied rewrites99.9%

      \[\leadsto \color{blue}{\left(\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right) \cdot \frac{100}{i}\right) \cdot n} \]
    5. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{\left(\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right) \cdot \frac{100}{i}\right)} \cdot n \]
      2. lift-/.f64N/A

        \[\leadsto \left(\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right) \cdot \color{blue}{\frac{100}{i}}\right) \cdot n \]
      3. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right) \cdot 100}{i}} \cdot n \]
      4. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right) \cdot 100}{i}} \cdot n \]
      5. *-commutativeN/A

        \[\leadsto \frac{\color{blue}{100 \cdot \mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right)}}{i} \cdot n \]
      6. lower-*.f6499.8

        \[\leadsto \frac{\color{blue}{100 \cdot \mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right)}}{i} \cdot n \]
    6. Applied rewrites99.8%

      \[\leadsto \color{blue}{\frac{100 \cdot \mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right)}{i}} \cdot n \]
    7. Step-by-step derivation
      1. lift-expm1.f64N/A

        \[\leadsto \frac{100 \cdot \color{blue}{\left(e^{\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n} - 1\right)}}{i} \cdot n \]
      2. lower--.f64N/A

        \[\leadsto \frac{100 \cdot \color{blue}{\left(e^{\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n} - 1\right)}}{i} \cdot n \]
      3. lift-*.f64N/A

        \[\leadsto \frac{100 \cdot \left(e^{\color{blue}{\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n}} - 1\right)}{i} \cdot n \]
      4. lift-log1p.f64N/A

        \[\leadsto \frac{100 \cdot \left(e^{\color{blue}{\log \left(1 + \frac{i}{n}\right)} \cdot n} - 1\right)}{i} \cdot n \]
      5. lift-/.f64N/A

        \[\leadsto \frac{100 \cdot \left(e^{\log \left(1 + \color{blue}{\frac{i}{n}}\right) \cdot n} - 1\right)}{i} \cdot n \]
      6. pow-to-expN/A

        \[\leadsto \frac{100 \cdot \left(\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n}} - 1\right)}{i} \cdot n \]
      7. lower-pow.f64N/A

        \[\leadsto \frac{100 \cdot \left(\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n}} - 1\right)}{i} \cdot n \]
      8. lift-/.f64N/A

        \[\leadsto \frac{100 \cdot \left({\left(1 + \color{blue}{\frac{i}{n}}\right)}^{n} - 1\right)}{i} \cdot n \]
      9. lower-+.f6478.1

        \[\leadsto \frac{100 \cdot \left({\color{blue}{\left(1 + \frac{i}{n}\right)}}^{n} - 1\right)}{i} \cdot n \]
    8. Applied rewrites78.1%

      \[\leadsto \frac{100 \cdot \color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}}{i} \cdot n \]

    if -1.999999999999994e-310 < n < 1.8e-112

    1. Initial program 34.8%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      2. lift-/.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      3. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\frac{i}{n}}} \]
      4. lift-/.f64N/A

        \[\leadsto \frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\color{blue}{\frac{i}{n}}} \]
      5. associate-/r/N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{i} \cdot n} \]
      6. lower-*.f64N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{i} \cdot n} \]
    4. Applied rewrites71.7%

      \[\leadsto \color{blue}{\left(\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right) \cdot \frac{100}{i}\right) \cdot n} \]
    5. Taylor expanded in n around 0

      \[\leadsto \color{blue}{\left(100 \cdot \frac{n \cdot \left(\log i + -1 \cdot \log n\right)}{i}\right)} \cdot n \]
    6. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto \color{blue}{\left(\frac{n \cdot \left(\log i + -1 \cdot \log n\right)}{i} \cdot 100\right)} \cdot n \]
      2. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\frac{n \cdot \left(\log i + -1 \cdot \log n\right)}{i} \cdot 100\right)} \cdot n \]
      3. associate-/l*N/A

        \[\leadsto \left(\color{blue}{\left(n \cdot \frac{\log i + -1 \cdot \log n}{i}\right)} \cdot 100\right) \cdot n \]
      4. lower-*.f64N/A

        \[\leadsto \left(\color{blue}{\left(n \cdot \frac{\log i + -1 \cdot \log n}{i}\right)} \cdot 100\right) \cdot n \]
      5. lower-/.f64N/A

        \[\leadsto \left(\left(n \cdot \color{blue}{\frac{\log i + -1 \cdot \log n}{i}}\right) \cdot 100\right) \cdot n \]
      6. fp-cancel-sign-sub-invN/A

        \[\leadsto \left(\left(n \cdot \frac{\color{blue}{\log i - \left(\mathsf{neg}\left(-1\right)\right) \cdot \log n}}{i}\right) \cdot 100\right) \cdot n \]
      7. metadata-evalN/A

        \[\leadsto \left(\left(n \cdot \frac{\log i - \color{blue}{1} \cdot \log n}{i}\right) \cdot 100\right) \cdot n \]
      8. *-lft-identityN/A

        \[\leadsto \left(\left(n \cdot \frac{\log i - \color{blue}{\log n}}{i}\right) \cdot 100\right) \cdot n \]
      9. lower--.f64N/A

        \[\leadsto \left(\left(n \cdot \frac{\color{blue}{\log i - \log n}}{i}\right) \cdot 100\right) \cdot n \]
      10. lower-log.f64N/A

        \[\leadsto \left(\left(n \cdot \frac{\color{blue}{\log i} - \log n}{i}\right) \cdot 100\right) \cdot n \]
      11. lower-log.f6483.1

        \[\leadsto \left(\left(n \cdot \frac{\log i - \color{blue}{\log n}}{i}\right) \cdot 100\right) \cdot n \]
    7. Applied rewrites83.1%

      \[\leadsto \color{blue}{\left(\left(n \cdot \frac{\log i - \log n}{i}\right) \cdot 100\right)} \cdot n \]

    if 1.8e-112 < n

    1. Initial program 23.5%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Taylor expanded in n around inf

      \[\leadsto \color{blue}{100 \cdot \frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
    4. Step-by-step derivation
      1. associate-/l*N/A

        \[\leadsto 100 \cdot \color{blue}{\left(n \cdot \frac{e^{i} - 1}{i}\right)} \]
      2. *-commutativeN/A

        \[\leadsto 100 \cdot \color{blue}{\left(\frac{e^{i} - 1}{i} \cdot n\right)} \]
      3. associate-*l*N/A

        \[\leadsto \color{blue}{\left(100 \cdot \frac{e^{i} - 1}{i}\right) \cdot n} \]
      4. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(100 \cdot \frac{e^{i} - 1}{i}\right) \cdot n} \]
      5. *-commutativeN/A

        \[\leadsto \color{blue}{\left(\frac{e^{i} - 1}{i} \cdot 100\right)} \cdot n \]
      6. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\frac{e^{i} - 1}{i} \cdot 100\right)} \cdot n \]
      7. lower-/.f64N/A

        \[\leadsto \left(\color{blue}{\frac{e^{i} - 1}{i}} \cdot 100\right) \cdot n \]
      8. lower-expm1.f6487.8

        \[\leadsto \left(\frac{\color{blue}{\mathsf{expm1}\left(i\right)}}{i} \cdot 100\right) \cdot n \]
    5. Applied rewrites87.8%

      \[\leadsto \color{blue}{\left(\frac{\mathsf{expm1}\left(i\right)}{i} \cdot 100\right) \cdot n} \]
  3. Recombined 4 regimes into one program.
  4. Add Preprocessing

Alternative 4: 80.2% accurate, 1.1× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;n \leq -1.05 \cdot 10^{-190} \lor \neg \left(n \leq 8 \cdot 10^{-113}\right):\\ \;\;\;\;\left(\frac{\mathsf{expm1}\left(i\right)}{i} \cdot 100\right) \cdot n\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{1 - 1}{\frac{i}{n}}\\ \end{array} \end{array} \]
(FPCore (i n)
 :precision binary64
 (if (or (<= n -1.05e-190) (not (<= n 8e-113)))
   (* (* (/ (expm1 i) i) 100.0) n)
   (* 100.0 (/ (- 1.0 1.0) (/ i n)))))
double code(double i, double n) {
	double tmp;
	if ((n <= -1.05e-190) || !(n <= 8e-113)) {
		tmp = ((expm1(i) / i) * 100.0) * n;
	} else {
		tmp = 100.0 * ((1.0 - 1.0) / (i / n));
	}
	return tmp;
}
public static double code(double i, double n) {
	double tmp;
	if ((n <= -1.05e-190) || !(n <= 8e-113)) {
		tmp = ((Math.expm1(i) / i) * 100.0) * n;
	} else {
		tmp = 100.0 * ((1.0 - 1.0) / (i / n));
	}
	return tmp;
}
def code(i, n):
	tmp = 0
	if (n <= -1.05e-190) or not (n <= 8e-113):
		tmp = ((math.expm1(i) / i) * 100.0) * n
	else:
		tmp = 100.0 * ((1.0 - 1.0) / (i / n))
	return tmp
function code(i, n)
	tmp = 0.0
	if ((n <= -1.05e-190) || !(n <= 8e-113))
		tmp = Float64(Float64(Float64(expm1(i) / i) * 100.0) * n);
	else
		tmp = Float64(100.0 * Float64(Float64(1.0 - 1.0) / Float64(i / n)));
	end
	return tmp
end
code[i_, n_] := If[Or[LessEqual[n, -1.05e-190], N[Not[LessEqual[n, 8e-113]], $MachinePrecision]], N[(N[(N[(N[(Exp[i] - 1), $MachinePrecision] / i), $MachinePrecision] * 100.0), $MachinePrecision] * n), $MachinePrecision], N[(100.0 * N[(N[(1.0 - 1.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;n \leq -1.05 \cdot 10^{-190} \lor \neg \left(n \leq 8 \cdot 10^{-113}\right):\\
\;\;\;\;\left(\frac{\mathsf{expm1}\left(i\right)}{i} \cdot 100\right) \cdot n\\

\mathbf{else}:\\
\;\;\;\;100 \cdot \frac{1 - 1}{\frac{i}{n}}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if n < -1.04999999999999996e-190 or 7.99999999999999983e-113 < n

    1. Initial program 23.0%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Taylor expanded in n around inf

      \[\leadsto \color{blue}{100 \cdot \frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
    4. Step-by-step derivation
      1. associate-/l*N/A

        \[\leadsto 100 \cdot \color{blue}{\left(n \cdot \frac{e^{i} - 1}{i}\right)} \]
      2. *-commutativeN/A

        \[\leadsto 100 \cdot \color{blue}{\left(\frac{e^{i} - 1}{i} \cdot n\right)} \]
      3. associate-*l*N/A

        \[\leadsto \color{blue}{\left(100 \cdot \frac{e^{i} - 1}{i}\right) \cdot n} \]
      4. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(100 \cdot \frac{e^{i} - 1}{i}\right) \cdot n} \]
      5. *-commutativeN/A

        \[\leadsto \color{blue}{\left(\frac{e^{i} - 1}{i} \cdot 100\right)} \cdot n \]
      6. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\frac{e^{i} - 1}{i} \cdot 100\right)} \cdot n \]
      7. lower-/.f64N/A

        \[\leadsto \left(\color{blue}{\frac{e^{i} - 1}{i}} \cdot 100\right) \cdot n \]
      8. lower-expm1.f6486.6

        \[\leadsto \left(\frac{\color{blue}{\mathsf{expm1}\left(i\right)}}{i} \cdot 100\right) \cdot n \]
    5. Applied rewrites86.6%

      \[\leadsto \color{blue}{\left(\frac{\mathsf{expm1}\left(i\right)}{i} \cdot 100\right) \cdot n} \]

    if -1.04999999999999996e-190 < n < 7.99999999999999983e-113

    1. Initial program 52.8%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Taylor expanded in i around 0

      \[\leadsto 100 \cdot \frac{\color{blue}{1} - 1}{\frac{i}{n}} \]
    4. Step-by-step derivation
      1. Applied rewrites69.5%

        \[\leadsto 100 \cdot \frac{\color{blue}{1} - 1}{\frac{i}{n}} \]
    5. Recombined 2 regimes into one program.
    6. Final simplification83.4%

      \[\leadsto \begin{array}{l} \mathbf{if}\;n \leq -1.05 \cdot 10^{-190} \lor \neg \left(n \leq 8 \cdot 10^{-113}\right):\\ \;\;\;\;\left(\frac{\mathsf{expm1}\left(i\right)}{i} \cdot 100\right) \cdot n\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{1 - 1}{\frac{i}{n}}\\ \end{array} \]
    7. Add Preprocessing

    Alternative 5: 80.2% accurate, 1.1× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{\mathsf{expm1}\left(i\right)}{i}\\ \mathbf{if}\;n \leq -1.05 \cdot 10^{-190}:\\ \;\;\;\;100 \cdot \left(t\_0 \cdot n\right)\\ \mathbf{elif}\;n \leq 8 \cdot 10^{-113}:\\ \;\;\;\;100 \cdot \frac{1 - 1}{\frac{i}{n}}\\ \mathbf{else}:\\ \;\;\;\;\left(t\_0 \cdot 100\right) \cdot n\\ \end{array} \end{array} \]
    (FPCore (i n)
     :precision binary64
     (let* ((t_0 (/ (expm1 i) i)))
       (if (<= n -1.05e-190)
         (* 100.0 (* t_0 n))
         (if (<= n 8e-113)
           (* 100.0 (/ (- 1.0 1.0) (/ i n)))
           (* (* t_0 100.0) n)))))
    double code(double i, double n) {
    	double t_0 = expm1(i) / i;
    	double tmp;
    	if (n <= -1.05e-190) {
    		tmp = 100.0 * (t_0 * n);
    	} else if (n <= 8e-113) {
    		tmp = 100.0 * ((1.0 - 1.0) / (i / n));
    	} else {
    		tmp = (t_0 * 100.0) * n;
    	}
    	return tmp;
    }
    
    public static double code(double i, double n) {
    	double t_0 = Math.expm1(i) / i;
    	double tmp;
    	if (n <= -1.05e-190) {
    		tmp = 100.0 * (t_0 * n);
    	} else if (n <= 8e-113) {
    		tmp = 100.0 * ((1.0 - 1.0) / (i / n));
    	} else {
    		tmp = (t_0 * 100.0) * n;
    	}
    	return tmp;
    }
    
    def code(i, n):
    	t_0 = math.expm1(i) / i
    	tmp = 0
    	if n <= -1.05e-190:
    		tmp = 100.0 * (t_0 * n)
    	elif n <= 8e-113:
    		tmp = 100.0 * ((1.0 - 1.0) / (i / n))
    	else:
    		tmp = (t_0 * 100.0) * n
    	return tmp
    
    function code(i, n)
    	t_0 = Float64(expm1(i) / i)
    	tmp = 0.0
    	if (n <= -1.05e-190)
    		tmp = Float64(100.0 * Float64(t_0 * n));
    	elseif (n <= 8e-113)
    		tmp = Float64(100.0 * Float64(Float64(1.0 - 1.0) / Float64(i / n)));
    	else
    		tmp = Float64(Float64(t_0 * 100.0) * n);
    	end
    	return tmp
    end
    
    code[i_, n_] := Block[{t$95$0 = N[(N[(Exp[i] - 1), $MachinePrecision] / i), $MachinePrecision]}, If[LessEqual[n, -1.05e-190], N[(100.0 * N[(t$95$0 * n), $MachinePrecision]), $MachinePrecision], If[LessEqual[n, 8e-113], N[(100.0 * N[(N[(1.0 - 1.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(t$95$0 * 100.0), $MachinePrecision] * n), $MachinePrecision]]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    t_0 := \frac{\mathsf{expm1}\left(i\right)}{i}\\
    \mathbf{if}\;n \leq -1.05 \cdot 10^{-190}:\\
    \;\;\;\;100 \cdot \left(t\_0 \cdot n\right)\\
    
    \mathbf{elif}\;n \leq 8 \cdot 10^{-113}:\\
    \;\;\;\;100 \cdot \frac{1 - 1}{\frac{i}{n}}\\
    
    \mathbf{else}:\\
    \;\;\;\;\left(t\_0 \cdot 100\right) \cdot n\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 3 regimes
    2. if n < -1.04999999999999996e-190

      1. Initial program 22.6%

        \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
      2. Add Preprocessing
      3. Taylor expanded in n around inf

        \[\leadsto 100 \cdot \color{blue}{\frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
      4. Step-by-step derivation
        1. associate-/l*N/A

          \[\leadsto 100 \cdot \color{blue}{\left(n \cdot \frac{e^{i} - 1}{i}\right)} \]
        2. *-commutativeN/A

          \[\leadsto 100 \cdot \color{blue}{\left(\frac{e^{i} - 1}{i} \cdot n\right)} \]
        3. lower-*.f64N/A

          \[\leadsto 100 \cdot \color{blue}{\left(\frac{e^{i} - 1}{i} \cdot n\right)} \]
        4. lower-/.f64N/A

          \[\leadsto 100 \cdot \left(\color{blue}{\frac{e^{i} - 1}{i}} \cdot n\right) \]
        5. lower-expm1.f6485.7

          \[\leadsto 100 \cdot \left(\frac{\color{blue}{\mathsf{expm1}\left(i\right)}}{i} \cdot n\right) \]
      5. Applied rewrites85.7%

        \[\leadsto 100 \cdot \color{blue}{\left(\frac{\mathsf{expm1}\left(i\right)}{i} \cdot n\right)} \]

      if -1.04999999999999996e-190 < n < 7.99999999999999983e-113

      1. Initial program 52.8%

        \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
      2. Add Preprocessing
      3. Taylor expanded in i around 0

        \[\leadsto 100 \cdot \frac{\color{blue}{1} - 1}{\frac{i}{n}} \]
      4. Step-by-step derivation
        1. Applied rewrites69.5%

          \[\leadsto 100 \cdot \frac{\color{blue}{1} - 1}{\frac{i}{n}} \]

        if 7.99999999999999983e-113 < n

        1. Initial program 23.5%

          \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
        2. Add Preprocessing
        3. Taylor expanded in n around inf

          \[\leadsto \color{blue}{100 \cdot \frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
        4. Step-by-step derivation
          1. associate-/l*N/A

            \[\leadsto 100 \cdot \color{blue}{\left(n \cdot \frac{e^{i} - 1}{i}\right)} \]
          2. *-commutativeN/A

            \[\leadsto 100 \cdot \color{blue}{\left(\frac{e^{i} - 1}{i} \cdot n\right)} \]
          3. associate-*l*N/A

            \[\leadsto \color{blue}{\left(100 \cdot \frac{e^{i} - 1}{i}\right) \cdot n} \]
          4. lower-*.f64N/A

            \[\leadsto \color{blue}{\left(100 \cdot \frac{e^{i} - 1}{i}\right) \cdot n} \]
          5. *-commutativeN/A

            \[\leadsto \color{blue}{\left(\frac{e^{i} - 1}{i} \cdot 100\right)} \cdot n \]
          6. lower-*.f64N/A

            \[\leadsto \color{blue}{\left(\frac{e^{i} - 1}{i} \cdot 100\right)} \cdot n \]
          7. lower-/.f64N/A

            \[\leadsto \left(\color{blue}{\frac{e^{i} - 1}{i}} \cdot 100\right) \cdot n \]
          8. lower-expm1.f6487.8

            \[\leadsto \left(\frac{\color{blue}{\mathsf{expm1}\left(i\right)}}{i} \cdot 100\right) \cdot n \]
        5. Applied rewrites87.8%

          \[\leadsto \color{blue}{\left(\frac{\mathsf{expm1}\left(i\right)}{i} \cdot 100\right) \cdot n} \]
      5. Recombined 3 regimes into one program.
      6. Add Preprocessing

      Alternative 6: 64.3% accurate, 2.9× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;n \leq -1.2 \cdot 10^{-190}:\\ \;\;\;\;100 \cdot \mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right) \cdot n, i, n\right)\\ \mathbf{elif}\;n \leq 8 \cdot 10^{-113}:\\ \;\;\;\;100 \cdot \frac{1 - 1}{\frac{i}{n}}\\ \mathbf{else}:\\ \;\;\;\;\left(100 \cdot \frac{\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right), i, 1\right) \cdot i}{i}\right) \cdot n\\ \end{array} \end{array} \]
      (FPCore (i n)
       :precision binary64
       (if (<= n -1.2e-190)
         (* 100.0 (fma (* (fma 0.16666666666666666 i 0.5) n) i n))
         (if (<= n 8e-113)
           (* 100.0 (/ (- 1.0 1.0) (/ i n)))
           (* (* 100.0 (/ (* (fma (fma 0.16666666666666666 i 0.5) i 1.0) i) i)) n))))
      double code(double i, double n) {
      	double tmp;
      	if (n <= -1.2e-190) {
      		tmp = 100.0 * fma((fma(0.16666666666666666, i, 0.5) * n), i, n);
      	} else if (n <= 8e-113) {
      		tmp = 100.0 * ((1.0 - 1.0) / (i / n));
      	} else {
      		tmp = (100.0 * ((fma(fma(0.16666666666666666, i, 0.5), i, 1.0) * i) / i)) * n;
      	}
      	return tmp;
      }
      
      function code(i, n)
      	tmp = 0.0
      	if (n <= -1.2e-190)
      		tmp = Float64(100.0 * fma(Float64(fma(0.16666666666666666, i, 0.5) * n), i, n));
      	elseif (n <= 8e-113)
      		tmp = Float64(100.0 * Float64(Float64(1.0 - 1.0) / Float64(i / n)));
      	else
      		tmp = Float64(Float64(100.0 * Float64(Float64(fma(fma(0.16666666666666666, i, 0.5), i, 1.0) * i) / i)) * n);
      	end
      	return tmp
      end
      
      code[i_, n_] := If[LessEqual[n, -1.2e-190], N[(100.0 * N[(N[(N[(0.16666666666666666 * i + 0.5), $MachinePrecision] * n), $MachinePrecision] * i + n), $MachinePrecision]), $MachinePrecision], If[LessEqual[n, 8e-113], N[(100.0 * N[(N[(1.0 - 1.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(100.0 * N[(N[(N[(N[(0.16666666666666666 * i + 0.5), $MachinePrecision] * i + 1.0), $MachinePrecision] * i), $MachinePrecision] / i), $MachinePrecision]), $MachinePrecision] * n), $MachinePrecision]]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      \mathbf{if}\;n \leq -1.2 \cdot 10^{-190}:\\
      \;\;\;\;100 \cdot \mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right) \cdot n, i, n\right)\\
      
      \mathbf{elif}\;n \leq 8 \cdot 10^{-113}:\\
      \;\;\;\;100 \cdot \frac{1 - 1}{\frac{i}{n}}\\
      
      \mathbf{else}:\\
      \;\;\;\;\left(100 \cdot \frac{\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right), i, 1\right) \cdot i}{i}\right) \cdot n\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 3 regimes
      2. if n < -1.2e-190

        1. Initial program 22.6%

          \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
        2. Add Preprocessing
        3. Taylor expanded in i around 0

          \[\leadsto 100 \cdot \color{blue}{\left(n + i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right)\right)} \]
        4. Step-by-step derivation
          1. +-commutativeN/A

            \[\leadsto 100 \cdot \color{blue}{\left(i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n\right)} \]
          2. *-commutativeN/A

            \[\leadsto 100 \cdot \left(\color{blue}{\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) \cdot i} + n\right) \]
          3. lower-fma.f64N/A

            \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right), i, n\right)} \]
        5. Applied rewrites57.7%

          \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(n \cdot i, \left(\frac{0.3333333333333333}{n \cdot n} + 0.16666666666666666\right) - \frac{0.5}{n}, \left(0.5 - \frac{0.5}{n}\right) \cdot n\right), i, n\right)} \]
        6. Taylor expanded in n around inf

          \[\leadsto 100 \cdot \mathsf{fma}\left(n \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot i\right), i, n\right) \]
        7. Step-by-step derivation
          1. Applied rewrites60.1%

            \[\leadsto 100 \cdot \mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right) \cdot n, i, n\right) \]

          if -1.2e-190 < n < 7.99999999999999983e-113

          1. Initial program 52.8%

            \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
          2. Add Preprocessing
          3. Taylor expanded in i around 0

            \[\leadsto 100 \cdot \frac{\color{blue}{1} - 1}{\frac{i}{n}} \]
          4. Step-by-step derivation
            1. Applied rewrites69.5%

              \[\leadsto 100 \cdot \frac{\color{blue}{1} - 1}{\frac{i}{n}} \]

            if 7.99999999999999983e-113 < n

            1. Initial program 23.5%

              \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
            2. Add Preprocessing
            3. Taylor expanded in n around inf

              \[\leadsto 100 \cdot \frac{\color{blue}{e^{i} - 1}}{\frac{i}{n}} \]
            4. Step-by-step derivation
              1. lower-expm1.f6467.6

                \[\leadsto 100 \cdot \frac{\color{blue}{\mathsf{expm1}\left(i\right)}}{\frac{i}{n}} \]
            5. Applied rewrites67.6%

              \[\leadsto 100 \cdot \frac{\color{blue}{\mathsf{expm1}\left(i\right)}}{\frac{i}{n}} \]
            6. Taylor expanded in i around 0

              \[\leadsto 100 \cdot \frac{i \cdot \color{blue}{\left(1 + i \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot i\right)\right)}}{\frac{i}{n}} \]
            7. Step-by-step derivation
              1. Applied rewrites52.4%

                \[\leadsto 100 \cdot \frac{\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right), i, 1\right) \cdot \color{blue}{i}}{\frac{i}{n}} \]
              2. Step-by-step derivation
                1. lift-*.f64N/A

                  \[\leadsto \color{blue}{100 \cdot \frac{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{6}, i, \frac{1}{2}\right), i, 1\right) \cdot i}{\frac{i}{n}}} \]
                2. lift-/.f64N/A

                  \[\leadsto 100 \cdot \color{blue}{\frac{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{6}, i, \frac{1}{2}\right), i, 1\right) \cdot i}{\frac{i}{n}}} \]
                3. lift-/.f64N/A

                  \[\leadsto 100 \cdot \frac{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{6}, i, \frac{1}{2}\right), i, 1\right) \cdot i}{\color{blue}{\frac{i}{n}}} \]
                4. associate-/r/N/A

                  \[\leadsto 100 \cdot \color{blue}{\left(\frac{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{6}, i, \frac{1}{2}\right), i, 1\right) \cdot i}{i} \cdot n\right)} \]
                5. associate-*r*N/A

                  \[\leadsto \color{blue}{\left(100 \cdot \frac{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{6}, i, \frac{1}{2}\right), i, 1\right) \cdot i}{i}\right) \cdot n} \]
                6. lower-*.f64N/A

                  \[\leadsto \color{blue}{\left(100 \cdot \frac{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{6}, i, \frac{1}{2}\right), i, 1\right) \cdot i}{i}\right) \cdot n} \]
                7. lower-*.f64N/A

                  \[\leadsto \color{blue}{\left(100 \cdot \frac{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{6}, i, \frac{1}{2}\right), i, 1\right) \cdot i}{i}\right)} \cdot n \]
                8. lower-/.f6472.5

                  \[\leadsto \left(100 \cdot \color{blue}{\frac{\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right), i, 1\right) \cdot i}{i}}\right) \cdot n \]
              3. Applied rewrites72.5%

                \[\leadsto \color{blue}{\left(100 \cdot \frac{\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right), i, 1\right) \cdot i}{i}\right) \cdot n} \]
            8. Recombined 3 regimes into one program.
            9. Final simplification66.5%

              \[\leadsto \begin{array}{l} \mathbf{if}\;n \leq -1.2 \cdot 10^{-190}:\\ \;\;\;\;100 \cdot \mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right) \cdot n, i, n\right)\\ \mathbf{elif}\;n \leq 8 \cdot 10^{-113}:\\ \;\;\;\;100 \cdot \frac{1 - 1}{\frac{i}{n}}\\ \mathbf{else}:\\ \;\;\;\;\left(100 \cdot \frac{\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right), i, 1\right) \cdot i}{i}\right) \cdot n\\ \end{array} \]
            10. Add Preprocessing

            Alternative 7: 64.0% accurate, 3.4× speedup?

            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;n \leq -1.2 \cdot 10^{-190} \lor \neg \left(n \leq 8 \cdot 10^{-113}\right):\\ \;\;\;\;100 \cdot \mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right) \cdot n, i, n\right)\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{1 - 1}{\frac{i}{n}}\\ \end{array} \end{array} \]
            (FPCore (i n)
             :precision binary64
             (if (or (<= n -1.2e-190) (not (<= n 8e-113)))
               (* 100.0 (fma (* (fma 0.16666666666666666 i 0.5) n) i n))
               (* 100.0 (/ (- 1.0 1.0) (/ i n)))))
            double code(double i, double n) {
            	double tmp;
            	if ((n <= -1.2e-190) || !(n <= 8e-113)) {
            		tmp = 100.0 * fma((fma(0.16666666666666666, i, 0.5) * n), i, n);
            	} else {
            		tmp = 100.0 * ((1.0 - 1.0) / (i / n));
            	}
            	return tmp;
            }
            
            function code(i, n)
            	tmp = 0.0
            	if ((n <= -1.2e-190) || !(n <= 8e-113))
            		tmp = Float64(100.0 * fma(Float64(fma(0.16666666666666666, i, 0.5) * n), i, n));
            	else
            		tmp = Float64(100.0 * Float64(Float64(1.0 - 1.0) / Float64(i / n)));
            	end
            	return tmp
            end
            
            code[i_, n_] := If[Or[LessEqual[n, -1.2e-190], N[Not[LessEqual[n, 8e-113]], $MachinePrecision]], N[(100.0 * N[(N[(N[(0.16666666666666666 * i + 0.5), $MachinePrecision] * n), $MachinePrecision] * i + n), $MachinePrecision]), $MachinePrecision], N[(100.0 * N[(N[(1.0 - 1.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
            
            \begin{array}{l}
            
            \\
            \begin{array}{l}
            \mathbf{if}\;n \leq -1.2 \cdot 10^{-190} \lor \neg \left(n \leq 8 \cdot 10^{-113}\right):\\
            \;\;\;\;100 \cdot \mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right) \cdot n, i, n\right)\\
            
            \mathbf{else}:\\
            \;\;\;\;100 \cdot \frac{1 - 1}{\frac{i}{n}}\\
            
            
            \end{array}
            \end{array}
            
            Derivation
            1. Split input into 2 regimes
            2. if n < -1.2e-190 or 7.99999999999999983e-113 < n

              1. Initial program 23.0%

                \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
              2. Add Preprocessing
              3. Taylor expanded in i around 0

                \[\leadsto 100 \cdot \color{blue}{\left(n + i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right)\right)} \]
              4. Step-by-step derivation
                1. +-commutativeN/A

                  \[\leadsto 100 \cdot \color{blue}{\left(i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n\right)} \]
                2. *-commutativeN/A

                  \[\leadsto 100 \cdot \left(\color{blue}{\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) \cdot i} + n\right) \]
                3. lower-fma.f64N/A

                  \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right), i, n\right)} \]
              5. Applied rewrites64.1%

                \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(n \cdot i, \left(\frac{0.3333333333333333}{n \cdot n} + 0.16666666666666666\right) - \frac{0.5}{n}, \left(0.5 - \frac{0.5}{n}\right) \cdot n\right), i, n\right)} \]
              6. Taylor expanded in n around inf

                \[\leadsto 100 \cdot \mathsf{fma}\left(n \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot i\right), i, n\right) \]
              7. Step-by-step derivation
                1. Applied rewrites65.4%

                  \[\leadsto 100 \cdot \mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right) \cdot n, i, n\right) \]

                if -1.2e-190 < n < 7.99999999999999983e-113

                1. Initial program 52.8%

                  \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                2. Add Preprocessing
                3. Taylor expanded in i around 0

                  \[\leadsto 100 \cdot \frac{\color{blue}{1} - 1}{\frac{i}{n}} \]
                4. Step-by-step derivation
                  1. Applied rewrites69.5%

                    \[\leadsto 100 \cdot \frac{\color{blue}{1} - 1}{\frac{i}{n}} \]
                5. Recombined 2 regimes into one program.
                6. Final simplification66.2%

                  \[\leadsto \begin{array}{l} \mathbf{if}\;n \leq -1.2 \cdot 10^{-190} \lor \neg \left(n \leq 8 \cdot 10^{-113}\right):\\ \;\;\;\;100 \cdot \mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right) \cdot n, i, n\right)\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{1 - 1}{\frac{i}{n}}\\ \end{array} \]
                7. Add Preprocessing

                Alternative 8: 56.2% accurate, 5.4× speedup?

                \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;i \leq 4.5 \cdot 10^{+27}:\\ \;\;\;\;100 \cdot n\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \left(\left(\left(i \cdot i\right) \cdot n\right) \cdot 0.16666666666666666\right)\\ \end{array} \end{array} \]
                (FPCore (i n)
                 :precision binary64
                 (if (<= i 4.5e+27)
                   (* 100.0 n)
                   (* 100.0 (* (* (* i i) n) 0.16666666666666666))))
                double code(double i, double n) {
                	double tmp;
                	if (i <= 4.5e+27) {
                		tmp = 100.0 * n;
                	} else {
                		tmp = 100.0 * (((i * i) * n) * 0.16666666666666666);
                	}
                	return tmp;
                }
                
                real(8) function code(i, n)
                    real(8), intent (in) :: i
                    real(8), intent (in) :: n
                    real(8) :: tmp
                    if (i <= 4.5d+27) then
                        tmp = 100.0d0 * n
                    else
                        tmp = 100.0d0 * (((i * i) * n) * 0.16666666666666666d0)
                    end if
                    code = tmp
                end function
                
                public static double code(double i, double n) {
                	double tmp;
                	if (i <= 4.5e+27) {
                		tmp = 100.0 * n;
                	} else {
                		tmp = 100.0 * (((i * i) * n) * 0.16666666666666666);
                	}
                	return tmp;
                }
                
                def code(i, n):
                	tmp = 0
                	if i <= 4.5e+27:
                		tmp = 100.0 * n
                	else:
                		tmp = 100.0 * (((i * i) * n) * 0.16666666666666666)
                	return tmp
                
                function code(i, n)
                	tmp = 0.0
                	if (i <= 4.5e+27)
                		tmp = Float64(100.0 * n);
                	else
                		tmp = Float64(100.0 * Float64(Float64(Float64(i * i) * n) * 0.16666666666666666));
                	end
                	return tmp
                end
                
                function tmp_2 = code(i, n)
                	tmp = 0.0;
                	if (i <= 4.5e+27)
                		tmp = 100.0 * n;
                	else
                		tmp = 100.0 * (((i * i) * n) * 0.16666666666666666);
                	end
                	tmp_2 = tmp;
                end
                
                code[i_, n_] := If[LessEqual[i, 4.5e+27], N[(100.0 * n), $MachinePrecision], N[(100.0 * N[(N[(N[(i * i), $MachinePrecision] * n), $MachinePrecision] * 0.16666666666666666), $MachinePrecision]), $MachinePrecision]]
                
                \begin{array}{l}
                
                \\
                \begin{array}{l}
                \mathbf{if}\;i \leq 4.5 \cdot 10^{+27}:\\
                \;\;\;\;100 \cdot n\\
                
                \mathbf{else}:\\
                \;\;\;\;100 \cdot \left(\left(\left(i \cdot i\right) \cdot n\right) \cdot 0.16666666666666666\right)\\
                
                
                \end{array}
                \end{array}
                
                Derivation
                1. Split input into 2 regimes
                2. if i < 4.4999999999999999e27

                  1. Initial program 22.3%

                    \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                  2. Add Preprocessing
                  3. Taylor expanded in i around 0

                    \[\leadsto \color{blue}{100 \cdot n} \]
                  4. Step-by-step derivation
                    1. lower-*.f6460.7

                      \[\leadsto \color{blue}{100 \cdot n} \]
                  5. Applied rewrites60.7%

                    \[\leadsto \color{blue}{100 \cdot n} \]

                  if 4.4999999999999999e27 < i

                  1. Initial program 51.6%

                    \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                  2. Add Preprocessing
                  3. Taylor expanded in i around 0

                    \[\leadsto 100 \cdot \color{blue}{\left(n + i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right)\right)} \]
                  4. Step-by-step derivation
                    1. +-commutativeN/A

                      \[\leadsto 100 \cdot \color{blue}{\left(i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n\right)} \]
                    2. *-commutativeN/A

                      \[\leadsto 100 \cdot \left(\color{blue}{\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) \cdot i} + n\right) \]
                    3. lower-fma.f64N/A

                      \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right), i, n\right)} \]
                  5. Applied rewrites40.2%

                    \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(n \cdot i, \left(\frac{0.3333333333333333}{n \cdot n} + 0.16666666666666666\right) - \frac{0.5}{n}, \left(0.5 - \frac{0.5}{n}\right) \cdot n\right), i, n\right)} \]
                  6. Taylor expanded in n around inf

                    \[\leadsto 100 \cdot \left(n \cdot \color{blue}{\left(1 + i \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot i\right)\right)}\right) \]
                  7. Step-by-step derivation
                    1. Applied rewrites40.2%

                      \[\leadsto 100 \cdot \left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right), i, 1\right) \cdot \color{blue}{n}\right) \]
                    2. Taylor expanded in i around inf

                      \[\leadsto 100 \cdot \left(\frac{1}{6} \cdot \left({i}^{2} \cdot \color{blue}{n}\right)\right) \]
                    3. Step-by-step derivation
                      1. Applied rewrites40.2%

                        \[\leadsto 100 \cdot \left(\left(\left(i \cdot i\right) \cdot n\right) \cdot 0.16666666666666666\right) \]
                    4. Recombined 2 regimes into one program.
                    5. Add Preprocessing

                    Alternative 9: 56.4% accurate, 6.3× speedup?

                    \[\begin{array}{l} \\ 100 \cdot \mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right) \cdot n, i, n\right) \end{array} \]
                    (FPCore (i n)
                     :precision binary64
                     (* 100.0 (fma (* (fma 0.16666666666666666 i 0.5) n) i n)))
                    double code(double i, double n) {
                    	return 100.0 * fma((fma(0.16666666666666666, i, 0.5) * n), i, n);
                    }
                    
                    function code(i, n)
                    	return Float64(100.0 * fma(Float64(fma(0.16666666666666666, i, 0.5) * n), i, n))
                    end
                    
                    code[i_, n_] := N[(100.0 * N[(N[(N[(0.16666666666666666 * i + 0.5), $MachinePrecision] * n), $MachinePrecision] * i + n), $MachinePrecision]), $MachinePrecision]
                    
                    \begin{array}{l}
                    
                    \\
                    100 \cdot \mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right) \cdot n, i, n\right)
                    \end{array}
                    
                    Derivation
                    1. Initial program 28.6%

                      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                    2. Add Preprocessing
                    3. Taylor expanded in i around 0

                      \[\leadsto 100 \cdot \color{blue}{\left(n + i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right)\right)} \]
                    4. Step-by-step derivation
                      1. +-commutativeN/A

                        \[\leadsto 100 \cdot \color{blue}{\left(i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n\right)} \]
                      2. *-commutativeN/A

                        \[\leadsto 100 \cdot \left(\color{blue}{\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) \cdot i} + n\right) \]
                      3. lower-fma.f64N/A

                        \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right), i, n\right)} \]
                    5. Applied rewrites53.0%

                      \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(n \cdot i, \left(\frac{0.3333333333333333}{n \cdot n} + 0.16666666666666666\right) - \frac{0.5}{n}, \left(0.5 - \frac{0.5}{n}\right) \cdot n\right), i, n\right)} \]
                    6. Taylor expanded in n around inf

                      \[\leadsto 100 \cdot \mathsf{fma}\left(n \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot i\right), i, n\right) \]
                    7. Step-by-step derivation
                      1. Applied rewrites56.3%

                        \[\leadsto 100 \cdot \mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right) \cdot n, i, n\right) \]
                      2. Add Preprocessing

                      Alternative 10: 56.4% accurate, 6.3× speedup?

                      \[\begin{array}{l} \\ 100 \cdot \left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right), i, 1\right) \cdot n\right) \end{array} \]
                      (FPCore (i n)
                       :precision binary64
                       (* 100.0 (* (fma (fma 0.16666666666666666 i 0.5) i 1.0) n)))
                      double code(double i, double n) {
                      	return 100.0 * (fma(fma(0.16666666666666666, i, 0.5), i, 1.0) * n);
                      }
                      
                      function code(i, n)
                      	return Float64(100.0 * Float64(fma(fma(0.16666666666666666, i, 0.5), i, 1.0) * n))
                      end
                      
                      code[i_, n_] := N[(100.0 * N[(N[(N[(0.16666666666666666 * i + 0.5), $MachinePrecision] * i + 1.0), $MachinePrecision] * n), $MachinePrecision]), $MachinePrecision]
                      
                      \begin{array}{l}
                      
                      \\
                      100 \cdot \left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right), i, 1\right) \cdot n\right)
                      \end{array}
                      
                      Derivation
                      1. Initial program 28.6%

                        \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                      2. Add Preprocessing
                      3. Taylor expanded in i around 0

                        \[\leadsto 100 \cdot \color{blue}{\left(n + i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right)\right)} \]
                      4. Step-by-step derivation
                        1. +-commutativeN/A

                          \[\leadsto 100 \cdot \color{blue}{\left(i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n\right)} \]
                        2. *-commutativeN/A

                          \[\leadsto 100 \cdot \left(\color{blue}{\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) \cdot i} + n\right) \]
                        3. lower-fma.f64N/A

                          \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right), i, n\right)} \]
                      5. Applied rewrites53.0%

                        \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(n \cdot i, \left(\frac{0.3333333333333333}{n \cdot n} + 0.16666666666666666\right) - \frac{0.5}{n}, \left(0.5 - \frac{0.5}{n}\right) \cdot n\right), i, n\right)} \]
                      6. Taylor expanded in n around inf

                        \[\leadsto 100 \cdot \left(n \cdot \color{blue}{\left(1 + i \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot i\right)\right)}\right) \]
                      7. Step-by-step derivation
                        1. Applied rewrites56.2%

                          \[\leadsto 100 \cdot \left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right), i, 1\right) \cdot \color{blue}{n}\right) \]
                        2. Add Preprocessing

                        Alternative 11: 55.9% accurate, 6.6× speedup?

                        \[\begin{array}{l} \\ 100 \cdot \left(\mathsf{fma}\left(0.16666666666666666 \cdot i, i, 1\right) \cdot n\right) \end{array} \]
                        (FPCore (i n)
                         :precision binary64
                         (* 100.0 (* (fma (* 0.16666666666666666 i) i 1.0) n)))
                        double code(double i, double n) {
                        	return 100.0 * (fma((0.16666666666666666 * i), i, 1.0) * n);
                        }
                        
                        function code(i, n)
                        	return Float64(100.0 * Float64(fma(Float64(0.16666666666666666 * i), i, 1.0) * n))
                        end
                        
                        code[i_, n_] := N[(100.0 * N[(N[(N[(0.16666666666666666 * i), $MachinePrecision] * i + 1.0), $MachinePrecision] * n), $MachinePrecision]), $MachinePrecision]
                        
                        \begin{array}{l}
                        
                        \\
                        100 \cdot \left(\mathsf{fma}\left(0.16666666666666666 \cdot i, i, 1\right) \cdot n\right)
                        \end{array}
                        
                        Derivation
                        1. Initial program 28.6%

                          \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                        2. Add Preprocessing
                        3. Taylor expanded in i around 0

                          \[\leadsto 100 \cdot \color{blue}{\left(n + i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right)\right)} \]
                        4. Step-by-step derivation
                          1. +-commutativeN/A

                            \[\leadsto 100 \cdot \color{blue}{\left(i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n\right)} \]
                          2. *-commutativeN/A

                            \[\leadsto 100 \cdot \left(\color{blue}{\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) \cdot i} + n\right) \]
                          3. lower-fma.f64N/A

                            \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right), i, n\right)} \]
                        5. Applied rewrites53.0%

                          \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(n \cdot i, \left(\frac{0.3333333333333333}{n \cdot n} + 0.16666666666666666\right) - \frac{0.5}{n}, \left(0.5 - \frac{0.5}{n}\right) \cdot n\right), i, n\right)} \]
                        6. Taylor expanded in n around inf

                          \[\leadsto 100 \cdot \left(n \cdot \color{blue}{\left(1 + i \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot i\right)\right)}\right) \]
                        7. Step-by-step derivation
                          1. Applied rewrites56.2%

                            \[\leadsto 100 \cdot \left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right), i, 1\right) \cdot \color{blue}{n}\right) \]
                          2. Taylor expanded in i around inf

                            \[\leadsto 100 \cdot \left(\mathsf{fma}\left(\frac{1}{6} \cdot i, i, 1\right) \cdot n\right) \]
                          3. Step-by-step derivation
                            1. Applied rewrites55.9%

                              \[\leadsto 100 \cdot \left(\mathsf{fma}\left(0.16666666666666666 \cdot i, i, 1\right) \cdot n\right) \]
                            2. Add Preprocessing

                            Alternative 12: 54.2% accurate, 8.6× speedup?

                            \[\begin{array}{l} \\ 100 \cdot \left(\mathsf{fma}\left(0.5, i, 1\right) \cdot n\right) \end{array} \]
                            (FPCore (i n) :precision binary64 (* 100.0 (* (fma 0.5 i 1.0) n)))
                            double code(double i, double n) {
                            	return 100.0 * (fma(0.5, i, 1.0) * n);
                            }
                            
                            function code(i, n)
                            	return Float64(100.0 * Float64(fma(0.5, i, 1.0) * n))
                            end
                            
                            code[i_, n_] := N[(100.0 * N[(N[(0.5 * i + 1.0), $MachinePrecision] * n), $MachinePrecision]), $MachinePrecision]
                            
                            \begin{array}{l}
                            
                            \\
                            100 \cdot \left(\mathsf{fma}\left(0.5, i, 1\right) \cdot n\right)
                            \end{array}
                            
                            Derivation
                            1. Initial program 28.6%

                              \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                            2. Add Preprocessing
                            3. Taylor expanded in i around 0

                              \[\leadsto 100 \cdot \color{blue}{\left(n + i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right)\right)} \]
                            4. Step-by-step derivation
                              1. +-commutativeN/A

                                \[\leadsto 100 \cdot \color{blue}{\left(i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n\right)} \]
                              2. *-commutativeN/A

                                \[\leadsto 100 \cdot \left(\color{blue}{\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) \cdot i} + n\right) \]
                              3. lower-fma.f64N/A

                                \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right), i, n\right)} \]
                            5. Applied rewrites53.0%

                              \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(n \cdot i, \left(\frac{0.3333333333333333}{n \cdot n} + 0.16666666666666666\right) - \frac{0.5}{n}, \left(0.5 - \frac{0.5}{n}\right) \cdot n\right), i, n\right)} \]
                            6. Taylor expanded in n around inf

                              \[\leadsto 100 \cdot \left(n \cdot \color{blue}{\left(1 + i \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot i\right)\right)}\right) \]
                            7. Step-by-step derivation
                              1. Applied rewrites56.2%

                                \[\leadsto 100 \cdot \left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right), i, 1\right) \cdot \color{blue}{n}\right) \]
                              2. Taylor expanded in i around 0

                                \[\leadsto 100 \cdot \left(\mathsf{fma}\left(\frac{1}{2}, i, 1\right) \cdot n\right) \]
                              3. Step-by-step derivation
                                1. Applied rewrites54.0%

                                  \[\leadsto 100 \cdot \left(\mathsf{fma}\left(0.5, i, 1\right) \cdot n\right) \]
                                2. Add Preprocessing

                                Alternative 13: 49.0% accurate, 24.3× speedup?

                                \[\begin{array}{l} \\ 100 \cdot n \end{array} \]
                                (FPCore (i n) :precision binary64 (* 100.0 n))
                                double code(double i, double n) {
                                	return 100.0 * n;
                                }
                                
                                real(8) function code(i, n)
                                    real(8), intent (in) :: i
                                    real(8), intent (in) :: n
                                    code = 100.0d0 * n
                                end function
                                
                                public static double code(double i, double n) {
                                	return 100.0 * n;
                                }
                                
                                def code(i, n):
                                	return 100.0 * n
                                
                                function code(i, n)
                                	return Float64(100.0 * n)
                                end
                                
                                function tmp = code(i, n)
                                	tmp = 100.0 * n;
                                end
                                
                                code[i_, n_] := N[(100.0 * n), $MachinePrecision]
                                
                                \begin{array}{l}
                                
                                \\
                                100 \cdot n
                                \end{array}
                                
                                Derivation
                                1. Initial program 28.6%

                                  \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                                2. Add Preprocessing
                                3. Taylor expanded in i around 0

                                  \[\leadsto \color{blue}{100 \cdot n} \]
                                4. Step-by-step derivation
                                  1. lower-*.f6448.7

                                    \[\leadsto \color{blue}{100 \cdot n} \]
                                5. Applied rewrites48.7%

                                  \[\leadsto \color{blue}{100 \cdot n} \]
                                6. Add Preprocessing

                                Developer Target 1: 34.1% accurate, 0.5× speedup?

                                \[\begin{array}{l} \\ \begin{array}{l} t_0 := 1 + \frac{i}{n}\\ 100 \cdot \frac{e^{n \cdot \begin{array}{l} \mathbf{if}\;t\_0 = 1:\\ \;\;\;\;\frac{i}{n}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{i}{n} \cdot \log t\_0}{\left(\frac{i}{n} + 1\right) - 1}\\ \end{array}} - 1}{\frac{i}{n}} \end{array} \end{array} \]
                                (FPCore (i n)
                                 :precision binary64
                                 (let* ((t_0 (+ 1.0 (/ i n))))
                                   (*
                                    100.0
                                    (/
                                     (-
                                      (exp
                                       (*
                                        n
                                        (if (== t_0 1.0)
                                          (/ i n)
                                          (/ (* (/ i n) (log t_0)) (- (+ (/ i n) 1.0) 1.0)))))
                                      1.0)
                                     (/ i n)))))
                                double code(double i, double n) {
                                	double t_0 = 1.0 + (i / n);
                                	double tmp;
                                	if (t_0 == 1.0) {
                                		tmp = i / n;
                                	} else {
                                		tmp = ((i / n) * log(t_0)) / (((i / n) + 1.0) - 1.0);
                                	}
                                	return 100.0 * ((exp((n * tmp)) - 1.0) / (i / n));
                                }
                                
                                real(8) function code(i, n)
                                    real(8), intent (in) :: i
                                    real(8), intent (in) :: n
                                    real(8) :: t_0
                                    real(8) :: tmp
                                    t_0 = 1.0d0 + (i / n)
                                    if (t_0 == 1.0d0) then
                                        tmp = i / n
                                    else
                                        tmp = ((i / n) * log(t_0)) / (((i / n) + 1.0d0) - 1.0d0)
                                    end if
                                    code = 100.0d0 * ((exp((n * tmp)) - 1.0d0) / (i / n))
                                end function
                                
                                public static double code(double i, double n) {
                                	double t_0 = 1.0 + (i / n);
                                	double tmp;
                                	if (t_0 == 1.0) {
                                		tmp = i / n;
                                	} else {
                                		tmp = ((i / n) * Math.log(t_0)) / (((i / n) + 1.0) - 1.0);
                                	}
                                	return 100.0 * ((Math.exp((n * tmp)) - 1.0) / (i / n));
                                }
                                
                                def code(i, n):
                                	t_0 = 1.0 + (i / n)
                                	tmp = 0
                                	if t_0 == 1.0:
                                		tmp = i / n
                                	else:
                                		tmp = ((i / n) * math.log(t_0)) / (((i / n) + 1.0) - 1.0)
                                	return 100.0 * ((math.exp((n * tmp)) - 1.0) / (i / n))
                                
                                function code(i, n)
                                	t_0 = Float64(1.0 + Float64(i / n))
                                	tmp = 0.0
                                	if (t_0 == 1.0)
                                		tmp = Float64(i / n);
                                	else
                                		tmp = Float64(Float64(Float64(i / n) * log(t_0)) / Float64(Float64(Float64(i / n) + 1.0) - 1.0));
                                	end
                                	return Float64(100.0 * Float64(Float64(exp(Float64(n * tmp)) - 1.0) / Float64(i / n)))
                                end
                                
                                function tmp_2 = code(i, n)
                                	t_0 = 1.0 + (i / n);
                                	tmp = 0.0;
                                	if (t_0 == 1.0)
                                		tmp = i / n;
                                	else
                                		tmp = ((i / n) * log(t_0)) / (((i / n) + 1.0) - 1.0);
                                	end
                                	tmp_2 = 100.0 * ((exp((n * tmp)) - 1.0) / (i / n));
                                end
                                
                                code[i_, n_] := Block[{t$95$0 = N[(1.0 + N[(i / n), $MachinePrecision]), $MachinePrecision]}, N[(100.0 * N[(N[(N[Exp[N[(n * If[Equal[t$95$0, 1.0], N[(i / n), $MachinePrecision], N[(N[(N[(i / n), $MachinePrecision] * N[Log[t$95$0], $MachinePrecision]), $MachinePrecision] / N[(N[(N[(i / n), $MachinePrecision] + 1.0), $MachinePrecision] - 1.0), $MachinePrecision]), $MachinePrecision]]), $MachinePrecision]], $MachinePrecision] - 1.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
                                
                                \begin{array}{l}
                                
                                \\
                                \begin{array}{l}
                                t_0 := 1 + \frac{i}{n}\\
                                100 \cdot \frac{e^{n \cdot \begin{array}{l}
                                \mathbf{if}\;t\_0 = 1:\\
                                \;\;\;\;\frac{i}{n}\\
                                
                                \mathbf{else}:\\
                                \;\;\;\;\frac{\frac{i}{n} \cdot \log t\_0}{\left(\frac{i}{n} + 1\right) - 1}\\
                                
                                
                                \end{array}} - 1}{\frac{i}{n}}
                                \end{array}
                                \end{array}
                                

                                Reproduce

                                ?
                                herbie shell --seed 2024343 
                                (FPCore (i n)
                                  :name "Compound Interest"
                                  :precision binary64
                                
                                  :alt
                                  (! :herbie-platform default (let ((lnbase (if (== (+ 1 (/ i n)) 1) (/ i n) (/ (* (/ i n) (log (+ 1 (/ i n)))) (- (+ (/ i n) 1) 1))))) (* 100 (/ (- (exp (* n lnbase)) 1) (/ i n)))))
                                
                                  (* 100.0 (/ (- (pow (+ 1.0 (/ i n)) n) 1.0) (/ i n))))