ABCF->ab-angle a

Percentage Accurate: 18.5% → 58.5%
Time: 16.4s
Alternatives: 18
Speedup: 16.9×

Specification

?
\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
real(8) function code(a, b, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) + sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 18 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 18.5% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
real(8) function code(a, b, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) + sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Alternative 1: 58.5% accurate, 1.6× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)}\\ t_1 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\ t_2 := -t\_1\\ \mathbf{if}\;B\_m \leq 4.7 \cdot 10^{-217}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot \left(t\_1 \cdot F\right)\right) \cdot \left(2 \cdot C\right)}}{t\_2}\\ \mathbf{elif}\;B\_m \leq 2.65 \cdot 10^{-42}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C\right) + C} \cdot t\_0}{t\_2}\\ \mathbf{elif}\;B\_m \leq 3.2 \cdot 10^{+57}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(B\_m, A - C\right) + A\right) + C} \cdot t\_0}{t\_2}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\_m\right) + C\right)}}{-B\_m} \cdot \sqrt{F}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (let* ((t_0 (sqrt (* (* 2.0 F) (fma -4.0 (* C A) (* B_m B_m)))))
        (t_1 (- (pow B_m 2.0) (* (* 4.0 A) C)))
        (t_2 (- t_1)))
   (if (<= B_m 4.7e-217)
     (/ (sqrt (* (* 2.0 (* t_1 F)) (* 2.0 C))) t_2)
     (if (<= B_m 2.65e-42)
       (/ (* (sqrt (+ (fma -0.5 (/ (* B_m B_m) A) C) C)) t_0) t_2)
       (if (<= B_m 3.2e+57)
         (/ (* (sqrt (+ (+ (hypot B_m (- A C)) A) C)) t_0) t_2)
         (* (/ (sqrt (* 2.0 (+ (hypot C B_m) C))) (- B_m)) (sqrt F)))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double t_0 = sqrt(((2.0 * F) * fma(-4.0, (C * A), (B_m * B_m))));
	double t_1 = pow(B_m, 2.0) - ((4.0 * A) * C);
	double t_2 = -t_1;
	double tmp;
	if (B_m <= 4.7e-217) {
		tmp = sqrt(((2.0 * (t_1 * F)) * (2.0 * C))) / t_2;
	} else if (B_m <= 2.65e-42) {
		tmp = (sqrt((fma(-0.5, ((B_m * B_m) / A), C) + C)) * t_0) / t_2;
	} else if (B_m <= 3.2e+57) {
		tmp = (sqrt(((hypot(B_m, (A - C)) + A) + C)) * t_0) / t_2;
	} else {
		tmp = (sqrt((2.0 * (hypot(C, B_m) + C))) / -B_m) * sqrt(F);
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	t_0 = sqrt(Float64(Float64(2.0 * F) * fma(-4.0, Float64(C * A), Float64(B_m * B_m))))
	t_1 = Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C))
	t_2 = Float64(-t_1)
	tmp = 0.0
	if (B_m <= 4.7e-217)
		tmp = Float64(sqrt(Float64(Float64(2.0 * Float64(t_1 * F)) * Float64(2.0 * C))) / t_2);
	elseif (B_m <= 2.65e-42)
		tmp = Float64(Float64(sqrt(Float64(fma(-0.5, Float64(Float64(B_m * B_m) / A), C) + C)) * t_0) / t_2);
	elseif (B_m <= 3.2e+57)
		tmp = Float64(Float64(sqrt(Float64(Float64(hypot(B_m, Float64(A - C)) + A) + C)) * t_0) / t_2);
	else
		tmp = Float64(Float64(sqrt(Float64(2.0 * Float64(hypot(C, B_m) + C))) / Float64(-B_m)) * sqrt(F));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[Sqrt[N[(N[(2.0 * F), $MachinePrecision] * N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, Block[{t$95$1 = N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = (-t$95$1)}, If[LessEqual[B$95$m, 4.7e-217], N[(N[Sqrt[N[(N[(2.0 * N[(t$95$1 * F), $MachinePrecision]), $MachinePrecision] * N[(2.0 * C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / t$95$2), $MachinePrecision], If[LessEqual[B$95$m, 2.65e-42], N[(N[(N[Sqrt[N[(N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] + C), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] * t$95$0), $MachinePrecision] / t$95$2), $MachinePrecision], If[LessEqual[B$95$m, 3.2e+57], N[(N[(N[Sqrt[N[(N[(N[Sqrt[B$95$m ^ 2 + N[(A - C), $MachinePrecision] ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] * t$95$0), $MachinePrecision] / t$95$2), $MachinePrecision], N[(N[(N[Sqrt[N[(2.0 * N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision]]]]]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
t_0 := \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)}\\
t_1 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\
t_2 := -t\_1\\
\mathbf{if}\;B\_m \leq 4.7 \cdot 10^{-217}:\\
\;\;\;\;\frac{\sqrt{\left(2 \cdot \left(t\_1 \cdot F\right)\right) \cdot \left(2 \cdot C\right)}}{t\_2}\\

\mathbf{elif}\;B\_m \leq 2.65 \cdot 10^{-42}:\\
\;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C\right) + C} \cdot t\_0}{t\_2}\\

\mathbf{elif}\;B\_m \leq 3.2 \cdot 10^{+57}:\\
\;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(B\_m, A - C\right) + A\right) + C} \cdot t\_0}{t\_2}\\

\mathbf{else}:\\
\;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\_m\right) + C\right)}}{-B\_m} \cdot \sqrt{F}\\


\end{array}
\end{array}
Derivation
  1. Split input into 4 regimes
  2. if B < 4.7000000000000003e-217

    1. Initial program 18.9%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in A around -inf

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Step-by-step derivation
      1. lower-*.f6416.3

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    5. Applied rewrites16.3%

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

    if 4.7000000000000003e-217 < B < 2.65e-42

    1. Initial program 18.5%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. pow1/2N/A

        \[\leadsto \frac{-\color{blue}{{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. lift-*.f64N/A

        \[\leadsto \frac{-{\color{blue}{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. *-commutativeN/A

        \[\leadsto \frac{-{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. unpow-prod-downN/A

        \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. lower-*.f64N/A

        \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Applied rewrites35.6%

      \[\leadsto \frac{-\color{blue}{\sqrt{\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    5. Taylor expanded in A around -inf

      \[\leadsto \frac{-\sqrt{\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    6. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + C\right)} + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lower-fma.f64N/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{A}, C\right)} + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. lower-/.f64N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{-1}{2}, \color{blue}{\frac{{B}^{2}}{A}}, C\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. unpow2N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{-1}{2}, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. lower-*.f6431.4

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-0.5, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    7. Applied rewrites31.4%

      \[\leadsto \frac{-\sqrt{\color{blue}{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right)} + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

    if 2.65e-42 < B < 3.20000000000000029e57

    1. Initial program 41.5%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. pow1/2N/A

        \[\leadsto \frac{-\color{blue}{{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. lift-*.f64N/A

        \[\leadsto \frac{-{\color{blue}{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. *-commutativeN/A

        \[\leadsto \frac{-{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. unpow-prod-downN/A

        \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. lower-*.f64N/A

        \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Applied rewrites61.0%

      \[\leadsto \frac{-\color{blue}{\sqrt{\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

    if 3.20000000000000029e57 < B

    1. Initial program 9.3%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. pow1/2N/A

        \[\leadsto \frac{-\color{blue}{{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. lift-*.f64N/A

        \[\leadsto \frac{-{\color{blue}{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. *-commutativeN/A

        \[\leadsto \frac{-{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. unpow-prod-downN/A

        \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. lower-*.f64N/A

        \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Applied rewrites15.4%

      \[\leadsto \frac{-\color{blue}{\sqrt{\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    5. Taylor expanded in A around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
    6. Step-by-step derivation
      1. associate-*r*N/A

        \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
      2. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
      3. mul-1-negN/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
      4. lower-neg.f64N/A

        \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
      5. lower-/.f64N/A

        \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
      6. lower-sqrt.f64N/A

        \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
      7. lower-sqrt.f64N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
      8. lower-*.f64N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
      9. +-commutativeN/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)}} \]
      10. lower-+.f64N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)}} \]
      11. +-commutativeN/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right)} \]
      12. unpow2N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right)} \]
      13. unpow2N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right)} \]
      14. lower-hypot.f6441.9

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right)} \]
    7. Applied rewrites41.9%

      \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}} \]
    8. Step-by-step derivation
      1. Applied rewrites63.0%

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
      2. Step-by-step derivation
        1. Applied rewrites63.1%

          \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
      3. Recombined 4 regimes into one program.
      4. Final simplification31.7%

        \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 4.7 \cdot 10^{-217}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(2 \cdot C\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{elif}\;B \leq 2.65 \cdot 10^{-42}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{elif}\;B \leq 3.2 \cdot 10^{+57}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \sqrt{F}\\ \end{array} \]
      5. Add Preprocessing

      Alternative 2: 52.6% accurate, 0.3× speedup?

      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C\right) + C\\ t_1 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\ t_2 := \frac{\sqrt{\left(2 \cdot \left(t\_1 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_1}\\ t_3 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;t\_2 \leq -1 \cdot 10^{+122}:\\ \;\;\;\;\frac{\left(-\sqrt{\mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)}\right) \cdot \sqrt{\left(t\_0 \cdot 2\right) \cdot F}}{t\_3}\\ \mathbf{elif}\;t\_2 \leq -4 \cdot 10^{-203}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot F\right) \cdot 2}}{-B\_m}\\ \mathbf{elif}\;t\_2 \leq \infty:\\ \;\;\;\;\frac{\sqrt{t\_0 \cdot \left(\left(2 \cdot F\right) \cdot t\_3\right)}}{-t\_3}\\ \mathbf{else}:\\ \;\;\;\;\frac{-\sqrt{F}}{\sqrt{B\_m \cdot 0.5}}\\ \end{array} \end{array} \]
      B_m = (fabs.f64 B)
      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
      (FPCore (A B_m C F)
       :precision binary64
       (let* ((t_0 (+ (fma -0.5 (/ (* B_m B_m) A) C) C))
              (t_1 (- (pow B_m 2.0) (* (* 4.0 A) C)))
              (t_2
               (/
                (sqrt
                 (*
                  (* 2.0 (* t_1 F))
                  (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))))
                (- t_1)))
              (t_3 (fma -4.0 (* C A) (* B_m B_m))))
         (if (<= t_2 -1e+122)
           (/
            (* (- (sqrt (fma (* C A) -4.0 (* B_m B_m)))) (sqrt (* (* t_0 2.0) F)))
            t_3)
           (if (<= t_2 -4e-203)
             (/ (sqrt (* (* (+ (hypot C B_m) C) F) 2.0)) (- B_m))
             (if (<= t_2 INFINITY)
               (/ (sqrt (* t_0 (* (* 2.0 F) t_3))) (- t_3))
               (/ (- (sqrt F)) (sqrt (* B_m 0.5))))))))
      B_m = fabs(B);
      assert(A < B_m && B_m < C && C < F);
      double code(double A, double B_m, double C, double F) {
      	double t_0 = fma(-0.5, ((B_m * B_m) / A), C) + C;
      	double t_1 = pow(B_m, 2.0) - ((4.0 * A) * C);
      	double t_2 = sqrt(((2.0 * (t_1 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))))) / -t_1;
      	double t_3 = fma(-4.0, (C * A), (B_m * B_m));
      	double tmp;
      	if (t_2 <= -1e+122) {
      		tmp = (-sqrt(fma((C * A), -4.0, (B_m * B_m))) * sqrt(((t_0 * 2.0) * F))) / t_3;
      	} else if (t_2 <= -4e-203) {
      		tmp = sqrt((((hypot(C, B_m) + C) * F) * 2.0)) / -B_m;
      	} else if (t_2 <= ((double) INFINITY)) {
      		tmp = sqrt((t_0 * ((2.0 * F) * t_3))) / -t_3;
      	} else {
      		tmp = -sqrt(F) / sqrt((B_m * 0.5));
      	}
      	return tmp;
      }
      
      B_m = abs(B)
      A, B_m, C, F = sort([A, B_m, C, F])
      function code(A, B_m, C, F)
      	t_0 = Float64(fma(-0.5, Float64(Float64(B_m * B_m) / A), C) + C)
      	t_1 = Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C))
      	t_2 = Float64(sqrt(Float64(Float64(2.0 * Float64(t_1 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))))) / Float64(-t_1))
      	t_3 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
      	tmp = 0.0
      	if (t_2 <= -1e+122)
      		tmp = Float64(Float64(Float64(-sqrt(fma(Float64(C * A), -4.0, Float64(B_m * B_m)))) * sqrt(Float64(Float64(t_0 * 2.0) * F))) / t_3);
      	elseif (t_2 <= -4e-203)
      		tmp = Float64(sqrt(Float64(Float64(Float64(hypot(C, B_m) + C) * F) * 2.0)) / Float64(-B_m));
      	elseif (t_2 <= Inf)
      		tmp = Float64(sqrt(Float64(t_0 * Float64(Float64(2.0 * F) * t_3))) / Float64(-t_3));
      	else
      		tmp = Float64(Float64(-sqrt(F)) / sqrt(Float64(B_m * 0.5)));
      	end
      	return tmp
      end
      
      B_m = N[Abs[B], $MachinePrecision]
      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
      code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] + C), $MachinePrecision] + C), $MachinePrecision]}, Block[{t$95$1 = N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(N[Sqrt[N[(N[(2.0 * N[(t$95$1 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$1)), $MachinePrecision]}, Block[{t$95$3 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$2, -1e+122], N[(N[((-N[Sqrt[N[(N[(C * A), $MachinePrecision] * -4.0 + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) * N[Sqrt[N[(N[(t$95$0 * 2.0), $MachinePrecision] * F), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / t$95$3), $MachinePrecision], If[LessEqual[t$95$2, -4e-203], N[(N[Sqrt[N[(N[(N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] * F), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision], If[LessEqual[t$95$2, Infinity], N[(N[Sqrt[N[(t$95$0 * N[(N[(2.0 * F), $MachinePrecision] * t$95$3), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$3)), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) / N[Sqrt[N[(B$95$m * 0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]]]]]
      
      \begin{array}{l}
      B_m = \left|B\right|
      \\
      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
      \\
      \begin{array}{l}
      t_0 := \mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C\right) + C\\
      t_1 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\
      t_2 := \frac{\sqrt{\left(2 \cdot \left(t\_1 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_1}\\
      t_3 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
      \mathbf{if}\;t\_2 \leq -1 \cdot 10^{+122}:\\
      \;\;\;\;\frac{\left(-\sqrt{\mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)}\right) \cdot \sqrt{\left(t\_0 \cdot 2\right) \cdot F}}{t\_3}\\
      
      \mathbf{elif}\;t\_2 \leq -4 \cdot 10^{-203}:\\
      \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot F\right) \cdot 2}}{-B\_m}\\
      
      \mathbf{elif}\;t\_2 \leq \infty:\\
      \;\;\;\;\frac{\sqrt{t\_0 \cdot \left(\left(2 \cdot F\right) \cdot t\_3\right)}}{-t\_3}\\
      
      \mathbf{else}:\\
      \;\;\;\;\frac{-\sqrt{F}}{\sqrt{B\_m \cdot 0.5}}\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 4 regimes
      2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -1.00000000000000001e122

        1. Initial program 9.7%

          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. Add Preprocessing
        3. Applied rewrites25.0%

          \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
        4. Applied rewrites48.6%

          \[\leadsto \frac{\color{blue}{\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \cdot \sqrt{\left(\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot 2\right) \cdot F}}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
        5. Taylor expanded in A around -inf

          \[\leadsto \frac{\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \cdot \sqrt{\left(\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot 2\right) \cdot F}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
        6. Step-by-step derivation
          1. +-commutativeN/A

            \[\leadsto \frac{\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \cdot \sqrt{\left(\left(\color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + C\right)} + C\right) \cdot 2\right) \cdot F}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
          2. lower-fma.f64N/A

            \[\leadsto \frac{\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \cdot \sqrt{\left(\left(\color{blue}{\mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{A}, C\right)} + C\right) \cdot 2\right) \cdot F}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
          3. lower-/.f64N/A

            \[\leadsto \frac{\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \cdot \sqrt{\left(\left(\mathsf{fma}\left(\frac{-1}{2}, \color{blue}{\frac{{B}^{2}}{A}}, C\right) + C\right) \cdot 2\right) \cdot F}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
          4. unpow2N/A

            \[\leadsto \frac{\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \cdot \sqrt{\left(\left(\mathsf{fma}\left(\frac{-1}{2}, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot 2\right) \cdot F}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
          5. lower-*.f6430.9

            \[\leadsto \frac{\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \cdot \sqrt{\left(\left(\mathsf{fma}\left(-0.5, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot 2\right) \cdot F}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
        7. Applied rewrites30.9%

          \[\leadsto \frac{\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \cdot \sqrt{\left(\left(\color{blue}{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right)} + C\right) \cdot 2\right) \cdot F}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]

        if -1.00000000000000001e122 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -4.0000000000000001e-203

        1. Initial program 97.9%

          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. Add Preprocessing
        3. Step-by-step derivation
          1. lift-sqrt.f64N/A

            \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. pow1/2N/A

            \[\leadsto \frac{-\color{blue}{{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          3. lift-*.f64N/A

            \[\leadsto \frac{-{\color{blue}{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          4. *-commutativeN/A

            \[\leadsto \frac{-{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          5. unpow-prod-downN/A

            \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          6. lower-*.f64N/A

            \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        4. Applied rewrites97.9%

          \[\leadsto \frac{-\color{blue}{\sqrt{\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        5. Taylor expanded in A around 0

          \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
        6. Step-by-step derivation
          1. associate-*r*N/A

            \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
          2. lower-*.f64N/A

            \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
          3. mul-1-negN/A

            \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
          4. lower-neg.f64N/A

            \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
          5. lower-/.f64N/A

            \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
          6. lower-sqrt.f64N/A

            \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
          7. lower-sqrt.f64N/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
          8. lower-*.f64N/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
          9. +-commutativeN/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)}} \]
          10. lower-+.f64N/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)}} \]
          11. +-commutativeN/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right)} \]
          12. unpow2N/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right)} \]
          13. unpow2N/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right)} \]
          14. lower-hypot.f6429.8

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right)} \]
        7. Applied rewrites29.8%

          \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}} \]
        8. Step-by-step derivation
          1. Applied rewrites30.0%

            \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]

          if -4.0000000000000001e-203 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

          1. Initial program 22.2%

            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. Add Preprocessing
          3. Applied rewrites29.9%

            \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
          4. Taylor expanded in A around -inf

            \[\leadsto \frac{\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
          5. Step-by-step derivation
            1. +-commutativeN/A

              \[\leadsto \frac{\sqrt{\left(\color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
            2. lower-fma.f64N/A

              \[\leadsto \frac{\sqrt{\left(\color{blue}{\mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{A}, C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
            3. lower-/.f64N/A

              \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(\frac{-1}{2}, \color{blue}{\frac{{B}^{2}}{A}}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
            4. unpow2N/A

              \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(\frac{-1}{2}, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
            5. lower-*.f6433.2

              \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(-0.5, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
          6. Applied rewrites33.2%

            \[\leadsto \frac{\sqrt{\left(\color{blue}{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]

          if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

          1. Initial program 0.0%

            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. Add Preprocessing
          3. Taylor expanded in B around inf

            \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
          4. Step-by-step derivation
            1. mul-1-negN/A

              \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
            2. lower-neg.f64N/A

              \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
            3. lower-*.f64N/A

              \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
            4. lower-sqrt.f64N/A

              \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
            5. lower-/.f64N/A

              \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
            6. lower-sqrt.f6412.2

              \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
          5. Applied rewrites12.2%

            \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
          6. Step-by-step derivation
            1. Applied rewrites12.2%

              \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
            2. Step-by-step derivation
              1. Applied rewrites12.2%

                \[\leadsto -\sqrt{F \cdot \frac{2}{B}} \]
              2. Step-by-step derivation
                1. Applied rewrites21.4%

                  \[\leadsto -\frac{\sqrt{F}}{\sqrt{B \cdot 0.5}} \]
              3. Recombined 4 regimes into one program.
              4. Final simplification27.5%

                \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -1 \cdot 10^{+122}:\\ \;\;\;\;\frac{\left(-\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}\right) \cdot \sqrt{\left(\left(\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right) + C\right) \cdot 2\right) \cdot F}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -4 \cdot 10^{-203}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{-B}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq \infty:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{-\sqrt{F}}{\sqrt{B \cdot 0.5}}\\ \end{array} \]
              5. Add Preprocessing

              Alternative 3: 51.7% accurate, 0.3× speedup?

              \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\ t_1 := \frac{\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_0}\\ t_2 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ t_3 := -t\_2\\ t_4 := \mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C\right) + C\\ t_5 := \left(2 \cdot F\right) \cdot t\_2\\ \mathbf{if}\;t\_1 \leq -\infty:\\ \;\;\;\;\frac{\left(-\sqrt{\mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)}\right) \cdot \sqrt{\left(t\_4 \cdot 2\right) \cdot F}}{t\_2}\\ \mathbf{elif}\;t\_1 \leq -4 \cdot 10^{-203}:\\ \;\;\;\;\frac{\sqrt{\left(B\_m \cdot \left(\frac{A}{B\_m} + 1\right) + C\right) \cdot t\_5}}{t\_3}\\ \mathbf{elif}\;t\_1 \leq \infty:\\ \;\;\;\;\frac{\sqrt{t\_4 \cdot t\_5}}{t\_3}\\ \mathbf{else}:\\ \;\;\;\;\frac{-\sqrt{F}}{\sqrt{B\_m \cdot 0.5}}\\ \end{array} \end{array} \]
              B_m = (fabs.f64 B)
              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
              (FPCore (A B_m C F)
               :precision binary64
               (let* ((t_0 (- (pow B_m 2.0) (* (* 4.0 A) C)))
                      (t_1
                       (/
                        (sqrt
                         (*
                          (* 2.0 (* t_0 F))
                          (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))))
                        (- t_0)))
                      (t_2 (fma -4.0 (* C A) (* B_m B_m)))
                      (t_3 (- t_2))
                      (t_4 (+ (fma -0.5 (/ (* B_m B_m) A) C) C))
                      (t_5 (* (* 2.0 F) t_2)))
                 (if (<= t_1 (- INFINITY))
                   (/
                    (* (- (sqrt (fma (* C A) -4.0 (* B_m B_m)))) (sqrt (* (* t_4 2.0) F)))
                    t_2)
                   (if (<= t_1 -4e-203)
                     (/ (sqrt (* (+ (* B_m (+ (/ A B_m) 1.0)) C) t_5)) t_3)
                     (if (<= t_1 INFINITY)
                       (/ (sqrt (* t_4 t_5)) t_3)
                       (/ (- (sqrt F)) (sqrt (* B_m 0.5))))))))
              B_m = fabs(B);
              assert(A < B_m && B_m < C && C < F);
              double code(double A, double B_m, double C, double F) {
              	double t_0 = pow(B_m, 2.0) - ((4.0 * A) * C);
              	double t_1 = sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))))) / -t_0;
              	double t_2 = fma(-4.0, (C * A), (B_m * B_m));
              	double t_3 = -t_2;
              	double t_4 = fma(-0.5, ((B_m * B_m) / A), C) + C;
              	double t_5 = (2.0 * F) * t_2;
              	double tmp;
              	if (t_1 <= -((double) INFINITY)) {
              		tmp = (-sqrt(fma((C * A), -4.0, (B_m * B_m))) * sqrt(((t_4 * 2.0) * F))) / t_2;
              	} else if (t_1 <= -4e-203) {
              		tmp = sqrt((((B_m * ((A / B_m) + 1.0)) + C) * t_5)) / t_3;
              	} else if (t_1 <= ((double) INFINITY)) {
              		tmp = sqrt((t_4 * t_5)) / t_3;
              	} else {
              		tmp = -sqrt(F) / sqrt((B_m * 0.5));
              	}
              	return tmp;
              }
              
              B_m = abs(B)
              A, B_m, C, F = sort([A, B_m, C, F])
              function code(A, B_m, C, F)
              	t_0 = Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C))
              	t_1 = Float64(sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))))) / Float64(-t_0))
              	t_2 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
              	t_3 = Float64(-t_2)
              	t_4 = Float64(fma(-0.5, Float64(Float64(B_m * B_m) / A), C) + C)
              	t_5 = Float64(Float64(2.0 * F) * t_2)
              	tmp = 0.0
              	if (t_1 <= Float64(-Inf))
              		tmp = Float64(Float64(Float64(-sqrt(fma(Float64(C * A), -4.0, Float64(B_m * B_m)))) * sqrt(Float64(Float64(t_4 * 2.0) * F))) / t_2);
              	elseif (t_1 <= -4e-203)
              		tmp = Float64(sqrt(Float64(Float64(Float64(B_m * Float64(Float64(A / B_m) + 1.0)) + C) * t_5)) / t_3);
              	elseif (t_1 <= Inf)
              		tmp = Float64(sqrt(Float64(t_4 * t_5)) / t_3);
              	else
              		tmp = Float64(Float64(-sqrt(F)) / sqrt(Float64(B_m * 0.5)));
              	end
              	return tmp
              end
              
              B_m = N[Abs[B], $MachinePrecision]
              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
              code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision]}, Block[{t$95$2 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = (-t$95$2)}, Block[{t$95$4 = N[(N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] + C), $MachinePrecision] + C), $MachinePrecision]}, Block[{t$95$5 = N[(N[(2.0 * F), $MachinePrecision] * t$95$2), $MachinePrecision]}, If[LessEqual[t$95$1, (-Infinity)], N[(N[((-N[Sqrt[N[(N[(C * A), $MachinePrecision] * -4.0 + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) * N[Sqrt[N[(N[(t$95$4 * 2.0), $MachinePrecision] * F), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / t$95$2), $MachinePrecision], If[LessEqual[t$95$1, -4e-203], N[(N[Sqrt[N[(N[(N[(B$95$m * N[(N[(A / B$95$m), $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision] + C), $MachinePrecision] * t$95$5), $MachinePrecision]], $MachinePrecision] / t$95$3), $MachinePrecision], If[LessEqual[t$95$1, Infinity], N[(N[Sqrt[N[(t$95$4 * t$95$5), $MachinePrecision]], $MachinePrecision] / t$95$3), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) / N[Sqrt[N[(B$95$m * 0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]]]]]]]
              
              \begin{array}{l}
              B_m = \left|B\right|
              \\
              [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
              \\
              \begin{array}{l}
              t_0 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\
              t_1 := \frac{\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_0}\\
              t_2 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
              t_3 := -t\_2\\
              t_4 := \mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C\right) + C\\
              t_5 := \left(2 \cdot F\right) \cdot t\_2\\
              \mathbf{if}\;t\_1 \leq -\infty:\\
              \;\;\;\;\frac{\left(-\sqrt{\mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)}\right) \cdot \sqrt{\left(t\_4 \cdot 2\right) \cdot F}}{t\_2}\\
              
              \mathbf{elif}\;t\_1 \leq -4 \cdot 10^{-203}:\\
              \;\;\;\;\frac{\sqrt{\left(B\_m \cdot \left(\frac{A}{B\_m} + 1\right) + C\right) \cdot t\_5}}{t\_3}\\
              
              \mathbf{elif}\;t\_1 \leq \infty:\\
              \;\;\;\;\frac{\sqrt{t\_4 \cdot t\_5}}{t\_3}\\
              
              \mathbf{else}:\\
              \;\;\;\;\frac{-\sqrt{F}}{\sqrt{B\_m \cdot 0.5}}\\
              
              
              \end{array}
              \end{array}
              
              Derivation
              1. Split input into 4 regimes
              2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -inf.0

                1. Initial program 3.2%

                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                2. Add Preprocessing
                3. Applied rewrites19.7%

                  \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                4. Applied rewrites44.9%

                  \[\leadsto \frac{\color{blue}{\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \cdot \sqrt{\left(\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot 2\right) \cdot F}}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                5. Taylor expanded in A around -inf

                  \[\leadsto \frac{\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \cdot \sqrt{\left(\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot 2\right) \cdot F}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                6. Step-by-step derivation
                  1. +-commutativeN/A

                    \[\leadsto \frac{\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \cdot \sqrt{\left(\left(\color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + C\right)} + C\right) \cdot 2\right) \cdot F}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  2. lower-fma.f64N/A

                    \[\leadsto \frac{\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \cdot \sqrt{\left(\left(\color{blue}{\mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{A}, C\right)} + C\right) \cdot 2\right) \cdot F}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  3. lower-/.f64N/A

                    \[\leadsto \frac{\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \cdot \sqrt{\left(\left(\mathsf{fma}\left(\frac{-1}{2}, \color{blue}{\frac{{B}^{2}}{A}}, C\right) + C\right) \cdot 2\right) \cdot F}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  4. unpow2N/A

                    \[\leadsto \frac{\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \cdot \sqrt{\left(\left(\mathsf{fma}\left(\frac{-1}{2}, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot 2\right) \cdot F}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  5. lower-*.f6429.3

                    \[\leadsto \frac{\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \cdot \sqrt{\left(\left(\mathsf{fma}\left(-0.5, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot 2\right) \cdot F}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                7. Applied rewrites29.3%

                  \[\leadsto \frac{\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \cdot \sqrt{\left(\left(\color{blue}{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right)} + C\right) \cdot 2\right) \cdot F}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]

                if -inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -4.0000000000000001e-203

                1. Initial program 98.1%

                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                2. Add Preprocessing
                3. Applied rewrites98.1%

                  \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                4. Taylor expanded in B around inf

                  \[\leadsto \frac{\sqrt{\left(\color{blue}{B \cdot \left(1 + \frac{A}{B}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                5. Step-by-step derivation
                  1. lower-*.f64N/A

                    \[\leadsto \frac{\sqrt{\left(\color{blue}{B \cdot \left(1 + \frac{A}{B}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  2. +-commutativeN/A

                    \[\leadsto \frac{\sqrt{\left(B \cdot \color{blue}{\left(\frac{A}{B} + 1\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  3. lower-+.f64N/A

                    \[\leadsto \frac{\sqrt{\left(B \cdot \color{blue}{\left(\frac{A}{B} + 1\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  4. lower-/.f6429.7

                    \[\leadsto \frac{\sqrt{\left(B \cdot \left(\color{blue}{\frac{A}{B}} + 1\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                6. Applied rewrites29.7%

                  \[\leadsto \frac{\sqrt{\left(\color{blue}{B \cdot \left(\frac{A}{B} + 1\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]

                if -4.0000000000000001e-203 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

                1. Initial program 22.2%

                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                2. Add Preprocessing
                3. Applied rewrites29.9%

                  \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                4. Taylor expanded in A around -inf

                  \[\leadsto \frac{\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                5. Step-by-step derivation
                  1. +-commutativeN/A

                    \[\leadsto \frac{\sqrt{\left(\color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  2. lower-fma.f64N/A

                    \[\leadsto \frac{\sqrt{\left(\color{blue}{\mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{A}, C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  3. lower-/.f64N/A

                    \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(\frac{-1}{2}, \color{blue}{\frac{{B}^{2}}{A}}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  4. unpow2N/A

                    \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(\frac{-1}{2}, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  5. lower-*.f6433.2

                    \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(-0.5, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                6. Applied rewrites33.2%

                  \[\leadsto \frac{\sqrt{\left(\color{blue}{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]

                if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

                1. Initial program 0.0%

                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                2. Add Preprocessing
                3. Taylor expanded in B around inf

                  \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                4. Step-by-step derivation
                  1. mul-1-negN/A

                    \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                  2. lower-neg.f64N/A

                    \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                  3. lower-*.f64N/A

                    \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                  4. lower-sqrt.f64N/A

                    \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                  5. lower-/.f64N/A

                    \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                  6. lower-sqrt.f6412.2

                    \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                5. Applied rewrites12.2%

                  \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                6. Step-by-step derivation
                  1. Applied rewrites12.2%

                    \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                  2. Step-by-step derivation
                    1. Applied rewrites12.2%

                      \[\leadsto -\sqrt{F \cdot \frac{2}{B}} \]
                    2. Step-by-step derivation
                      1. Applied rewrites21.4%

                        \[\leadsto -\frac{\sqrt{F}}{\sqrt{B \cdot 0.5}} \]
                    3. Recombined 4 regimes into one program.
                    4. Final simplification27.1%

                      \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -\infty:\\ \;\;\;\;\frac{\left(-\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}\right) \cdot \sqrt{\left(\left(\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right) + C\right) \cdot 2\right) \cdot F}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -4 \cdot 10^{-203}:\\ \;\;\;\;\frac{\sqrt{\left(B \cdot \left(\frac{A}{B} + 1\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq \infty:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{-\sqrt{F}}{\sqrt{B \cdot 0.5}}\\ \end{array} \]
                    5. Add Preprocessing

                    Alternative 4: 58.3% accurate, 1.2× speedup?

                    \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ t_1 := \left(2 \cdot F\right) \cdot t\_0\\ \mathbf{if}\;{B\_m}^{2} \leq 10^{-283}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot t\_1}}{-t\_0}\\ \mathbf{elif}\;{B\_m}^{2} \leq 10^{+115}:\\ \;\;\;\;\frac{\sqrt{t\_1}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(B\_m, A - C\right) + A\right) + C}}{t\_0}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\_m\right) + C\right)}}{-B\_m} \cdot \sqrt{F}\\ \end{array} \end{array} \]
                    B_m = (fabs.f64 B)
                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                    (FPCore (A B_m C F)
                     :precision binary64
                     (let* ((t_0 (fma -4.0 (* C A) (* B_m B_m))) (t_1 (* (* 2.0 F) t_0)))
                       (if (<= (pow B_m 2.0) 1e-283)
                         (/ (sqrt (* (* 2.0 C) t_1)) (- t_0))
                         (if (<= (pow B_m 2.0) 1e+115)
                           (* (/ (sqrt t_1) -1.0) (/ (sqrt (+ (+ (hypot B_m (- A C)) A) C)) t_0))
                           (* (/ (sqrt (* 2.0 (+ (hypot C B_m) C))) (- B_m)) (sqrt F))))))
                    B_m = fabs(B);
                    assert(A < B_m && B_m < C && C < F);
                    double code(double A, double B_m, double C, double F) {
                    	double t_0 = fma(-4.0, (C * A), (B_m * B_m));
                    	double t_1 = (2.0 * F) * t_0;
                    	double tmp;
                    	if (pow(B_m, 2.0) <= 1e-283) {
                    		tmp = sqrt(((2.0 * C) * t_1)) / -t_0;
                    	} else if (pow(B_m, 2.0) <= 1e+115) {
                    		tmp = (sqrt(t_1) / -1.0) * (sqrt(((hypot(B_m, (A - C)) + A) + C)) / t_0);
                    	} else {
                    		tmp = (sqrt((2.0 * (hypot(C, B_m) + C))) / -B_m) * sqrt(F);
                    	}
                    	return tmp;
                    }
                    
                    B_m = abs(B)
                    A, B_m, C, F = sort([A, B_m, C, F])
                    function code(A, B_m, C, F)
                    	t_0 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
                    	t_1 = Float64(Float64(2.0 * F) * t_0)
                    	tmp = 0.0
                    	if ((B_m ^ 2.0) <= 1e-283)
                    		tmp = Float64(sqrt(Float64(Float64(2.0 * C) * t_1)) / Float64(-t_0));
                    	elseif ((B_m ^ 2.0) <= 1e+115)
                    		tmp = Float64(Float64(sqrt(t_1) / -1.0) * Float64(sqrt(Float64(Float64(hypot(B_m, Float64(A - C)) + A) + C)) / t_0));
                    	else
                    		tmp = Float64(Float64(sqrt(Float64(2.0 * Float64(hypot(C, B_m) + C))) / Float64(-B_m)) * sqrt(F));
                    	end
                    	return tmp
                    end
                    
                    B_m = N[Abs[B], $MachinePrecision]
                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                    code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(2.0 * F), $MachinePrecision] * t$95$0), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e-283], N[(N[Sqrt[N[(N[(2.0 * C), $MachinePrecision] * t$95$1), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e+115], N[(N[(N[Sqrt[t$95$1], $MachinePrecision] / -1.0), $MachinePrecision] * N[(N[Sqrt[N[(N[(N[Sqrt[B$95$m ^ 2 + N[(A - C), $MachinePrecision] ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] / t$95$0), $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(2.0 * N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision]]]]]
                    
                    \begin{array}{l}
                    B_m = \left|B\right|
                    \\
                    [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                    \\
                    \begin{array}{l}
                    t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
                    t_1 := \left(2 \cdot F\right) \cdot t\_0\\
                    \mathbf{if}\;{B\_m}^{2} \leq 10^{-283}:\\
                    \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot t\_1}}{-t\_0}\\
                    
                    \mathbf{elif}\;{B\_m}^{2} \leq 10^{+115}:\\
                    \;\;\;\;\frac{\sqrt{t\_1}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(B\_m, A - C\right) + A\right) + C}}{t\_0}\\
                    
                    \mathbf{else}:\\
                    \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\_m\right) + C\right)}}{-B\_m} \cdot \sqrt{F}\\
                    
                    
                    \end{array}
                    \end{array}
                    
                    Derivation
                    1. Split input into 3 regimes
                    2. if (pow.f64 B #s(literal 2 binary64)) < 9.99999999999999947e-284

                      1. Initial program 22.4%

                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      2. Add Preprocessing
                      3. Applied rewrites32.4%

                        \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                      4. Taylor expanded in A around -inf

                        \[\leadsto \frac{\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                      5. Step-by-step derivation
                        1. lower-*.f6434.6

                          \[\leadsto \frac{\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                      6. Applied rewrites34.6%

                        \[\leadsto \frac{\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]

                      if 9.99999999999999947e-284 < (pow.f64 B #s(literal 2 binary64)) < 1e115

                      1. Initial program 29.2%

                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      2. Add Preprocessing
                      3. Applied rewrites55.5%

                        \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]

                      if 1e115 < (pow.f64 B #s(literal 2 binary64))

                      1. Initial program 9.4%

                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      2. Add Preprocessing
                      3. Step-by-step derivation
                        1. lift-sqrt.f64N/A

                          \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        2. pow1/2N/A

                          \[\leadsto \frac{-\color{blue}{{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        3. lift-*.f64N/A

                          \[\leadsto \frac{-{\color{blue}{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        4. *-commutativeN/A

                          \[\leadsto \frac{-{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        5. unpow-prod-downN/A

                          \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        6. lower-*.f64N/A

                          \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      4. Applied rewrites15.0%

                        \[\leadsto \frac{-\color{blue}{\sqrt{\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      5. Taylor expanded in A around 0

                        \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                      6. Step-by-step derivation
                        1. associate-*r*N/A

                          \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                        2. lower-*.f64N/A

                          \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                        3. mul-1-negN/A

                          \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                        4. lower-neg.f64N/A

                          \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                        5. lower-/.f64N/A

                          \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                        6. lower-sqrt.f64N/A

                          \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                        7. lower-sqrt.f64N/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                        8. lower-*.f64N/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                        9. +-commutativeN/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)}} \]
                        10. lower-+.f64N/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)}} \]
                        11. +-commutativeN/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right)} \]
                        12. unpow2N/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right)} \]
                        13. unpow2N/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right)} \]
                        14. lower-hypot.f6420.4

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right)} \]
                      7. Applied rewrites20.4%

                        \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}} \]
                      8. Step-by-step derivation
                        1. Applied rewrites30.2%

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                        2. Step-by-step derivation
                          1. Applied rewrites30.3%

                            \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                        3. Recombined 3 regimes into one program.
                        4. Final simplification39.9%

                          \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 10^{-283}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{elif}\;{B}^{2} \leq 10^{+115}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \sqrt{F}\\ \end{array} \]
                        5. Add Preprocessing

                        Alternative 5: 58.1% accurate, 1.2× speedup?

                        \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ t_1 := \mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 2 \cdot 10^{-295}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(\left(2 \cdot F\right) \cdot t\_0\right)}}{-t\_0}\\ \mathbf{elif}\;{B\_m}^{2} \leq 10^{+115}:\\ \;\;\;\;\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C\right) \cdot 2} \cdot \frac{\sqrt{t\_1 \cdot F}}{-t\_1}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\_m\right) + C\right)}}{-B\_m} \cdot \sqrt{F}\\ \end{array} \end{array} \]
                        B_m = (fabs.f64 B)
                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                        (FPCore (A B_m C F)
                         :precision binary64
                         (let* ((t_0 (fma -4.0 (* C A) (* B_m B_m)))
                                (t_1 (fma (* C A) -4.0 (* B_m B_m))))
                           (if (<= (pow B_m 2.0) 2e-295)
                             (/ (sqrt (* (* 2.0 C) (* (* 2.0 F) t_0))) (- t_0))
                             (if (<= (pow B_m 2.0) 1e+115)
                               (*
                                (sqrt (* (+ (+ (hypot (- A C) B_m) A) C) 2.0))
                                (/ (sqrt (* t_1 F)) (- t_1)))
                               (* (/ (sqrt (* 2.0 (+ (hypot C B_m) C))) (- B_m)) (sqrt F))))))
                        B_m = fabs(B);
                        assert(A < B_m && B_m < C && C < F);
                        double code(double A, double B_m, double C, double F) {
                        	double t_0 = fma(-4.0, (C * A), (B_m * B_m));
                        	double t_1 = fma((C * A), -4.0, (B_m * B_m));
                        	double tmp;
                        	if (pow(B_m, 2.0) <= 2e-295) {
                        		tmp = sqrt(((2.0 * C) * ((2.0 * F) * t_0))) / -t_0;
                        	} else if (pow(B_m, 2.0) <= 1e+115) {
                        		tmp = sqrt((((hypot((A - C), B_m) + A) + C) * 2.0)) * (sqrt((t_1 * F)) / -t_1);
                        	} else {
                        		tmp = (sqrt((2.0 * (hypot(C, B_m) + C))) / -B_m) * sqrt(F);
                        	}
                        	return tmp;
                        }
                        
                        B_m = abs(B)
                        A, B_m, C, F = sort([A, B_m, C, F])
                        function code(A, B_m, C, F)
                        	t_0 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
                        	t_1 = fma(Float64(C * A), -4.0, Float64(B_m * B_m))
                        	tmp = 0.0
                        	if ((B_m ^ 2.0) <= 2e-295)
                        		tmp = Float64(sqrt(Float64(Float64(2.0 * C) * Float64(Float64(2.0 * F) * t_0))) / Float64(-t_0));
                        	elseif ((B_m ^ 2.0) <= 1e+115)
                        		tmp = Float64(sqrt(Float64(Float64(Float64(hypot(Float64(A - C), B_m) + A) + C) * 2.0)) * Float64(sqrt(Float64(t_1 * F)) / Float64(-t_1)));
                        	else
                        		tmp = Float64(Float64(sqrt(Float64(2.0 * Float64(hypot(C, B_m) + C))) / Float64(-B_m)) * sqrt(F));
                        	end
                        	return tmp
                        end
                        
                        B_m = N[Abs[B], $MachinePrecision]
                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                        code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(C * A), $MachinePrecision] * -4.0 + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 2e-295], N[(N[Sqrt[N[(N[(2.0 * C), $MachinePrecision] * N[(N[(2.0 * F), $MachinePrecision] * t$95$0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e+115], N[(N[Sqrt[N[(N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[N[(t$95$1 * F), $MachinePrecision]], $MachinePrecision] / (-t$95$1)), $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(2.0 * N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision]]]]]
                        
                        \begin{array}{l}
                        B_m = \left|B\right|
                        \\
                        [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                        \\
                        \begin{array}{l}
                        t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
                        t_1 := \mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)\\
                        \mathbf{if}\;{B\_m}^{2} \leq 2 \cdot 10^{-295}:\\
                        \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(\left(2 \cdot F\right) \cdot t\_0\right)}}{-t\_0}\\
                        
                        \mathbf{elif}\;{B\_m}^{2} \leq 10^{+115}:\\
                        \;\;\;\;\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C\right) \cdot 2} \cdot \frac{\sqrt{t\_1 \cdot F}}{-t\_1}\\
                        
                        \mathbf{else}:\\
                        \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\_m\right) + C\right)}}{-B\_m} \cdot \sqrt{F}\\
                        
                        
                        \end{array}
                        \end{array}
                        
                        Derivation
                        1. Split input into 3 regimes
                        2. if (pow.f64 B #s(literal 2 binary64)) < 2.00000000000000012e-295

                          1. Initial program 23.4%

                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          2. Add Preprocessing
                          3. Applied rewrites33.9%

                            \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                          4. Taylor expanded in A around -inf

                            \[\leadsto \frac{\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                          5. Step-by-step derivation
                            1. lower-*.f6436.2

                              \[\leadsto \frac{\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                          6. Applied rewrites36.2%

                            \[\leadsto \frac{\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]

                          if 2.00000000000000012e-295 < (pow.f64 B #s(literal 2 binary64)) < 1e115

                          1. Initial program 28.3%

                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          2. Add Preprocessing
                          3. Applied rewrites36.1%

                            \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                          4. Applied rewrites53.5%

                            \[\leadsto \color{blue}{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot 2} \cdot \frac{-\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot F}}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \]

                          if 1e115 < (pow.f64 B #s(literal 2 binary64))

                          1. Initial program 9.4%

                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          2. Add Preprocessing
                          3. Step-by-step derivation
                            1. lift-sqrt.f64N/A

                              \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            2. pow1/2N/A

                              \[\leadsto \frac{-\color{blue}{{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            3. lift-*.f64N/A

                              \[\leadsto \frac{-{\color{blue}{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            4. *-commutativeN/A

                              \[\leadsto \frac{-{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            5. unpow-prod-downN/A

                              \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            6. lower-*.f64N/A

                              \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          4. Applied rewrites15.0%

                            \[\leadsto \frac{-\color{blue}{\sqrt{\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          5. Taylor expanded in A around 0

                            \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                          6. Step-by-step derivation
                            1. associate-*r*N/A

                              \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                            2. lower-*.f64N/A

                              \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                            3. mul-1-negN/A

                              \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                            4. lower-neg.f64N/A

                              \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                            5. lower-/.f64N/A

                              \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                            6. lower-sqrt.f64N/A

                              \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                            7. lower-sqrt.f64N/A

                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                            8. lower-*.f64N/A

                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                            9. +-commutativeN/A

                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)}} \]
                            10. lower-+.f64N/A

                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)}} \]
                            11. +-commutativeN/A

                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right)} \]
                            12. unpow2N/A

                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right)} \]
                            13. unpow2N/A

                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right)} \]
                            14. lower-hypot.f6420.4

                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right)} \]
                          7. Applied rewrites20.4%

                            \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}} \]
                          8. Step-by-step derivation
                            1. Applied rewrites30.2%

                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                            2. Step-by-step derivation
                              1. Applied rewrites30.3%

                                \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                            3. Recombined 3 regimes into one program.
                            4. Final simplification39.9%

                              \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 2 \cdot 10^{-295}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{elif}\;{B}^{2} \leq 10^{+115}:\\ \;\;\;\;\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot 2} \cdot \frac{\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \sqrt{F}\\ \end{array} \]
                            5. Add Preprocessing

                            Alternative 6: 58.5% accurate, 1.8× speedup?

                            \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ t_1 := \sqrt{\left(2 \cdot F\right) \cdot t\_0}\\ t_2 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\ t_3 := -t\_2\\ \mathbf{if}\;B\_m \leq 4.7 \cdot 10^{-217}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot \left(t\_2 \cdot F\right)\right) \cdot \left(2 \cdot C\right)}}{t\_3}\\ \mathbf{elif}\;B\_m \leq 2.65 \cdot 10^{-42}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C\right) + C} \cdot t\_1}{t\_3}\\ \mathbf{elif}\;B\_m \leq 3.2 \cdot 10^{+57}:\\ \;\;\;\;\frac{t\_1}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(B\_m, A - C\right) + A\right) + C}}{t\_0}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\_m\right) + C\right)}}{-B\_m} \cdot \sqrt{F}\\ \end{array} \end{array} \]
                            B_m = (fabs.f64 B)
                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                            (FPCore (A B_m C F)
                             :precision binary64
                             (let* ((t_0 (fma -4.0 (* C A) (* B_m B_m)))
                                    (t_1 (sqrt (* (* 2.0 F) t_0)))
                                    (t_2 (- (pow B_m 2.0) (* (* 4.0 A) C)))
                                    (t_3 (- t_2)))
                               (if (<= B_m 4.7e-217)
                                 (/ (sqrt (* (* 2.0 (* t_2 F)) (* 2.0 C))) t_3)
                                 (if (<= B_m 2.65e-42)
                                   (/ (* (sqrt (+ (fma -0.5 (/ (* B_m B_m) A) C) C)) t_1) t_3)
                                   (if (<= B_m 3.2e+57)
                                     (* (/ t_1 -1.0) (/ (sqrt (+ (+ (hypot B_m (- A C)) A) C)) t_0))
                                     (* (/ (sqrt (* 2.0 (+ (hypot C B_m) C))) (- B_m)) (sqrt F)))))))
                            B_m = fabs(B);
                            assert(A < B_m && B_m < C && C < F);
                            double code(double A, double B_m, double C, double F) {
                            	double t_0 = fma(-4.0, (C * A), (B_m * B_m));
                            	double t_1 = sqrt(((2.0 * F) * t_0));
                            	double t_2 = pow(B_m, 2.0) - ((4.0 * A) * C);
                            	double t_3 = -t_2;
                            	double tmp;
                            	if (B_m <= 4.7e-217) {
                            		tmp = sqrt(((2.0 * (t_2 * F)) * (2.0 * C))) / t_3;
                            	} else if (B_m <= 2.65e-42) {
                            		tmp = (sqrt((fma(-0.5, ((B_m * B_m) / A), C) + C)) * t_1) / t_3;
                            	} else if (B_m <= 3.2e+57) {
                            		tmp = (t_1 / -1.0) * (sqrt(((hypot(B_m, (A - C)) + A) + C)) / t_0);
                            	} else {
                            		tmp = (sqrt((2.0 * (hypot(C, B_m) + C))) / -B_m) * sqrt(F);
                            	}
                            	return tmp;
                            }
                            
                            B_m = abs(B)
                            A, B_m, C, F = sort([A, B_m, C, F])
                            function code(A, B_m, C, F)
                            	t_0 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
                            	t_1 = sqrt(Float64(Float64(2.0 * F) * t_0))
                            	t_2 = Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C))
                            	t_3 = Float64(-t_2)
                            	tmp = 0.0
                            	if (B_m <= 4.7e-217)
                            		tmp = Float64(sqrt(Float64(Float64(2.0 * Float64(t_2 * F)) * Float64(2.0 * C))) / t_3);
                            	elseif (B_m <= 2.65e-42)
                            		tmp = Float64(Float64(sqrt(Float64(fma(-0.5, Float64(Float64(B_m * B_m) / A), C) + C)) * t_1) / t_3);
                            	elseif (B_m <= 3.2e+57)
                            		tmp = Float64(Float64(t_1 / -1.0) * Float64(sqrt(Float64(Float64(hypot(B_m, Float64(A - C)) + A) + C)) / t_0));
                            	else
                            		tmp = Float64(Float64(sqrt(Float64(2.0 * Float64(hypot(C, B_m) + C))) / Float64(-B_m)) * sqrt(F));
                            	end
                            	return tmp
                            end
                            
                            B_m = N[Abs[B], $MachinePrecision]
                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                            code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[Sqrt[N[(N[(2.0 * F), $MachinePrecision] * t$95$0), $MachinePrecision]], $MachinePrecision]}, Block[{t$95$2 = N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = (-t$95$2)}, If[LessEqual[B$95$m, 4.7e-217], N[(N[Sqrt[N[(N[(2.0 * N[(t$95$2 * F), $MachinePrecision]), $MachinePrecision] * N[(2.0 * C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / t$95$3), $MachinePrecision], If[LessEqual[B$95$m, 2.65e-42], N[(N[(N[Sqrt[N[(N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] + C), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] * t$95$1), $MachinePrecision] / t$95$3), $MachinePrecision], If[LessEqual[B$95$m, 3.2e+57], N[(N[(t$95$1 / -1.0), $MachinePrecision] * N[(N[Sqrt[N[(N[(N[Sqrt[B$95$m ^ 2 + N[(A - C), $MachinePrecision] ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] / t$95$0), $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(2.0 * N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision]]]]]]]]
                            
                            \begin{array}{l}
                            B_m = \left|B\right|
                            \\
                            [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                            \\
                            \begin{array}{l}
                            t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
                            t_1 := \sqrt{\left(2 \cdot F\right) \cdot t\_0}\\
                            t_2 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\
                            t_3 := -t\_2\\
                            \mathbf{if}\;B\_m \leq 4.7 \cdot 10^{-217}:\\
                            \;\;\;\;\frac{\sqrt{\left(2 \cdot \left(t\_2 \cdot F\right)\right) \cdot \left(2 \cdot C\right)}}{t\_3}\\
                            
                            \mathbf{elif}\;B\_m \leq 2.65 \cdot 10^{-42}:\\
                            \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C\right) + C} \cdot t\_1}{t\_3}\\
                            
                            \mathbf{elif}\;B\_m \leq 3.2 \cdot 10^{+57}:\\
                            \;\;\;\;\frac{t\_1}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(B\_m, A - C\right) + A\right) + C}}{t\_0}\\
                            
                            \mathbf{else}:\\
                            \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\_m\right) + C\right)}}{-B\_m} \cdot \sqrt{F}\\
                            
                            
                            \end{array}
                            \end{array}
                            
                            Derivation
                            1. Split input into 4 regimes
                            2. if B < 4.7000000000000003e-217

                              1. Initial program 18.9%

                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              2. Add Preprocessing
                              3. Taylor expanded in A around -inf

                                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              4. Step-by-step derivation
                                1. lower-*.f6416.3

                                  \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              5. Applied rewrites16.3%

                                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

                              if 4.7000000000000003e-217 < B < 2.65e-42

                              1. Initial program 18.5%

                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              2. Add Preprocessing
                              3. Step-by-step derivation
                                1. lift-sqrt.f64N/A

                                  \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                2. pow1/2N/A

                                  \[\leadsto \frac{-\color{blue}{{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                3. lift-*.f64N/A

                                  \[\leadsto \frac{-{\color{blue}{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                4. *-commutativeN/A

                                  \[\leadsto \frac{-{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                5. unpow-prod-downN/A

                                  \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                6. lower-*.f64N/A

                                  \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              4. Applied rewrites35.6%

                                \[\leadsto \frac{-\color{blue}{\sqrt{\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              5. Taylor expanded in A around -inf

                                \[\leadsto \frac{-\sqrt{\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              6. Step-by-step derivation
                                1. +-commutativeN/A

                                  \[\leadsto \frac{-\sqrt{\color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + C\right)} + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                2. lower-fma.f64N/A

                                  \[\leadsto \frac{-\sqrt{\color{blue}{\mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{A}, C\right)} + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                3. lower-/.f64N/A

                                  \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{-1}{2}, \color{blue}{\frac{{B}^{2}}{A}}, C\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                4. unpow2N/A

                                  \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{-1}{2}, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                5. lower-*.f6431.4

                                  \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-0.5, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              7. Applied rewrites31.4%

                                \[\leadsto \frac{-\sqrt{\color{blue}{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right)} + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

                              if 2.65e-42 < B < 3.20000000000000029e57

                              1. Initial program 41.5%

                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              2. Add Preprocessing
                              3. Applied rewrites61.1%

                                \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]

                              if 3.20000000000000029e57 < B

                              1. Initial program 9.3%

                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              2. Add Preprocessing
                              3. Step-by-step derivation
                                1. lift-sqrt.f64N/A

                                  \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                2. pow1/2N/A

                                  \[\leadsto \frac{-\color{blue}{{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                3. lift-*.f64N/A

                                  \[\leadsto \frac{-{\color{blue}{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                4. *-commutativeN/A

                                  \[\leadsto \frac{-{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                5. unpow-prod-downN/A

                                  \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                6. lower-*.f64N/A

                                  \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              4. Applied rewrites15.4%

                                \[\leadsto \frac{-\color{blue}{\sqrt{\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              5. Taylor expanded in A around 0

                                \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                              6. Step-by-step derivation
                                1. associate-*r*N/A

                                  \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                2. lower-*.f64N/A

                                  \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                3. mul-1-negN/A

                                  \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                4. lower-neg.f64N/A

                                  \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                5. lower-/.f64N/A

                                  \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                6. lower-sqrt.f64N/A

                                  \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                7. lower-sqrt.f64N/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                8. lower-*.f64N/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                9. +-commutativeN/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)}} \]
                                10. lower-+.f64N/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)}} \]
                                11. +-commutativeN/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right)} \]
                                12. unpow2N/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right)} \]
                                13. unpow2N/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right)} \]
                                14. lower-hypot.f6441.9

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right)} \]
                              7. Applied rewrites41.9%

                                \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}} \]
                              8. Step-by-step derivation
                                1. Applied rewrites63.0%

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                                2. Step-by-step derivation
                                  1. Applied rewrites63.1%

                                    \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                                3. Recombined 4 regimes into one program.
                                4. Final simplification31.7%

                                  \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 4.7 \cdot 10^{-217}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(2 \cdot C\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{elif}\;B \leq 2.65 \cdot 10^{-42}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{elif}\;B \leq 3.2 \cdot 10^{+57}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \sqrt{F}\\ \end{array} \]
                                5. Add Preprocessing

                                Alternative 7: 57.2% accurate, 1.9× speedup?

                                \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 5 \cdot 10^{-42}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot t\_0\right)}}{-t\_0}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\_m\right) + C\right)}}{-B\_m} \cdot \sqrt{F}\\ \end{array} \end{array} \]
                                B_m = (fabs.f64 B)
                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                (FPCore (A B_m C F)
                                 :precision binary64
                                 (let* ((t_0 (fma -4.0 (* C A) (* B_m B_m))))
                                   (if (<= (pow B_m 2.0) 5e-42)
                                     (/
                                      (sqrt (* (+ (fma -0.5 (/ (* B_m B_m) A) C) C) (* (* 2.0 F) t_0)))
                                      (- t_0))
                                     (* (/ (sqrt (* 2.0 (+ (hypot C B_m) C))) (- B_m)) (sqrt F)))))
                                B_m = fabs(B);
                                assert(A < B_m && B_m < C && C < F);
                                double code(double A, double B_m, double C, double F) {
                                	double t_0 = fma(-4.0, (C * A), (B_m * B_m));
                                	double tmp;
                                	if (pow(B_m, 2.0) <= 5e-42) {
                                		tmp = sqrt(((fma(-0.5, ((B_m * B_m) / A), C) + C) * ((2.0 * F) * t_0))) / -t_0;
                                	} else {
                                		tmp = (sqrt((2.0 * (hypot(C, B_m) + C))) / -B_m) * sqrt(F);
                                	}
                                	return tmp;
                                }
                                
                                B_m = abs(B)
                                A, B_m, C, F = sort([A, B_m, C, F])
                                function code(A, B_m, C, F)
                                	t_0 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
                                	tmp = 0.0
                                	if ((B_m ^ 2.0) <= 5e-42)
                                		tmp = Float64(sqrt(Float64(Float64(fma(-0.5, Float64(Float64(B_m * B_m) / A), C) + C) * Float64(Float64(2.0 * F) * t_0))) / Float64(-t_0));
                                	else
                                		tmp = Float64(Float64(sqrt(Float64(2.0 * Float64(hypot(C, B_m) + C))) / Float64(-B_m)) * sqrt(F));
                                	end
                                	return tmp
                                end
                                
                                B_m = N[Abs[B], $MachinePrecision]
                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 5e-42], N[(N[Sqrt[N[(N[(N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] + C), $MachinePrecision] + C), $MachinePrecision] * N[(N[(2.0 * F), $MachinePrecision] * t$95$0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], N[(N[(N[Sqrt[N[(2.0 * N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision]]]
                                
                                \begin{array}{l}
                                B_m = \left|B\right|
                                \\
                                [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                \\
                                \begin{array}{l}
                                t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
                                \mathbf{if}\;{B\_m}^{2} \leq 5 \cdot 10^{-42}:\\
                                \;\;\;\;\frac{\sqrt{\left(\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot t\_0\right)}}{-t\_0}\\
                                
                                \mathbf{else}:\\
                                \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\_m\right) + C\right)}}{-B\_m} \cdot \sqrt{F}\\
                                
                                
                                \end{array}
                                \end{array}
                                
                                Derivation
                                1. Split input into 2 regimes
                                2. if (pow.f64 B #s(literal 2 binary64)) < 5.00000000000000003e-42

                                  1. Initial program 20.3%

                                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                  2. Add Preprocessing
                                  3. Applied rewrites29.9%

                                    \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                                  4. Taylor expanded in A around -inf

                                    \[\leadsto \frac{\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                  5. Step-by-step derivation
                                    1. +-commutativeN/A

                                      \[\leadsto \frac{\sqrt{\left(\color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                    2. lower-fma.f64N/A

                                      \[\leadsto \frac{\sqrt{\left(\color{blue}{\mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{A}, C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                    3. lower-/.f64N/A

                                      \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(\frac{-1}{2}, \color{blue}{\frac{{B}^{2}}{A}}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                    4. unpow2N/A

                                      \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(\frac{-1}{2}, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                    5. lower-*.f6428.0

                                      \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(-0.5, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                  6. Applied rewrites28.0%

                                    \[\leadsto \frac{\sqrt{\left(\color{blue}{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]

                                  if 5.00000000000000003e-42 < (pow.f64 B #s(literal 2 binary64))

                                  1. Initial program 18.8%

                                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                  2. Add Preprocessing
                                  3. Step-by-step derivation
                                    1. lift-sqrt.f64N/A

                                      \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    2. pow1/2N/A

                                      \[\leadsto \frac{-\color{blue}{{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    3. lift-*.f64N/A

                                      \[\leadsto \frac{-{\color{blue}{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    4. *-commutativeN/A

                                      \[\leadsto \frac{-{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    5. unpow-prod-downN/A

                                      \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    6. lower-*.f64N/A

                                      \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                  4. Applied rewrites28.1%

                                    \[\leadsto \frac{-\color{blue}{\sqrt{\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                  5. Taylor expanded in A around 0

                                    \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                  6. Step-by-step derivation
                                    1. associate-*r*N/A

                                      \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                    2. lower-*.f64N/A

                                      \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                    3. mul-1-negN/A

                                      \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                    4. lower-neg.f64N/A

                                      \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                    5. lower-/.f64N/A

                                      \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                    6. lower-sqrt.f64N/A

                                      \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                    7. lower-sqrt.f64N/A

                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                    8. lower-*.f64N/A

                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                    9. +-commutativeN/A

                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)}} \]
                                    10. lower-+.f64N/A

                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)}} \]
                                    11. +-commutativeN/A

                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right)} \]
                                    12. unpow2N/A

                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right)} \]
                                    13. unpow2N/A

                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right)} \]
                                    14. lower-hypot.f6420.2

                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right)} \]
                                  7. Applied rewrites20.2%

                                    \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}} \]
                                  8. Step-by-step derivation
                                    1. Applied rewrites28.2%

                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                                    2. Step-by-step derivation
                                      1. Applied rewrites28.3%

                                        \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                                    3. Recombined 2 regimes into one program.
                                    4. Add Preprocessing

                                    Alternative 8: 58.5% accurate, 2.3× speedup?

                                    \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ t_1 := \left(2 \cdot F\right) \cdot t\_0\\ t_2 := \sqrt{t\_1}\\ \mathbf{if}\;B\_m \leq 4.7 \cdot 10^{-217}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot t\_1}}{-t\_0}\\ \mathbf{elif}\;B\_m \leq 2.65 \cdot 10^{-42}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C\right) + C} \cdot t\_2}{-\left({B\_m}^{2} - \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{elif}\;B\_m \leq 3.2 \cdot 10^{+57}:\\ \;\;\;\;\frac{t\_2}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(B\_m, A - C\right) + A\right) + C}}{t\_0}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\_m\right) + C\right)}}{-B\_m} \cdot \sqrt{F}\\ \end{array} \end{array} \]
                                    B_m = (fabs.f64 B)
                                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                    (FPCore (A B_m C F)
                                     :precision binary64
                                     (let* ((t_0 (fma -4.0 (* C A) (* B_m B_m)))
                                            (t_1 (* (* 2.0 F) t_0))
                                            (t_2 (sqrt t_1)))
                                       (if (<= B_m 4.7e-217)
                                         (/ (sqrt (* (* 2.0 C) t_1)) (- t_0))
                                         (if (<= B_m 2.65e-42)
                                           (/
                                            (* (sqrt (+ (fma -0.5 (/ (* B_m B_m) A) C) C)) t_2)
                                            (- (- (pow B_m 2.0) (* (* 4.0 A) C))))
                                           (if (<= B_m 3.2e+57)
                                             (* (/ t_2 -1.0) (/ (sqrt (+ (+ (hypot B_m (- A C)) A) C)) t_0))
                                             (* (/ (sqrt (* 2.0 (+ (hypot C B_m) C))) (- B_m)) (sqrt F)))))))
                                    B_m = fabs(B);
                                    assert(A < B_m && B_m < C && C < F);
                                    double code(double A, double B_m, double C, double F) {
                                    	double t_0 = fma(-4.0, (C * A), (B_m * B_m));
                                    	double t_1 = (2.0 * F) * t_0;
                                    	double t_2 = sqrt(t_1);
                                    	double tmp;
                                    	if (B_m <= 4.7e-217) {
                                    		tmp = sqrt(((2.0 * C) * t_1)) / -t_0;
                                    	} else if (B_m <= 2.65e-42) {
                                    		tmp = (sqrt((fma(-0.5, ((B_m * B_m) / A), C) + C)) * t_2) / -(pow(B_m, 2.0) - ((4.0 * A) * C));
                                    	} else if (B_m <= 3.2e+57) {
                                    		tmp = (t_2 / -1.0) * (sqrt(((hypot(B_m, (A - C)) + A) + C)) / t_0);
                                    	} else {
                                    		tmp = (sqrt((2.0 * (hypot(C, B_m) + C))) / -B_m) * sqrt(F);
                                    	}
                                    	return tmp;
                                    }
                                    
                                    B_m = abs(B)
                                    A, B_m, C, F = sort([A, B_m, C, F])
                                    function code(A, B_m, C, F)
                                    	t_0 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
                                    	t_1 = Float64(Float64(2.0 * F) * t_0)
                                    	t_2 = sqrt(t_1)
                                    	tmp = 0.0
                                    	if (B_m <= 4.7e-217)
                                    		tmp = Float64(sqrt(Float64(Float64(2.0 * C) * t_1)) / Float64(-t_0));
                                    	elseif (B_m <= 2.65e-42)
                                    		tmp = Float64(Float64(sqrt(Float64(fma(-0.5, Float64(Float64(B_m * B_m) / A), C) + C)) * t_2) / Float64(-Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C))));
                                    	elseif (B_m <= 3.2e+57)
                                    		tmp = Float64(Float64(t_2 / -1.0) * Float64(sqrt(Float64(Float64(hypot(B_m, Float64(A - C)) + A) + C)) / t_0));
                                    	else
                                    		tmp = Float64(Float64(sqrt(Float64(2.0 * Float64(hypot(C, B_m) + C))) / Float64(-B_m)) * sqrt(F));
                                    	end
                                    	return tmp
                                    end
                                    
                                    B_m = N[Abs[B], $MachinePrecision]
                                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                    code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(2.0 * F), $MachinePrecision] * t$95$0), $MachinePrecision]}, Block[{t$95$2 = N[Sqrt[t$95$1], $MachinePrecision]}, If[LessEqual[B$95$m, 4.7e-217], N[(N[Sqrt[N[(N[(2.0 * C), $MachinePrecision] * t$95$1), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], If[LessEqual[B$95$m, 2.65e-42], N[(N[(N[Sqrt[N[(N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] + C), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] * t$95$2), $MachinePrecision] / (-N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision])), $MachinePrecision], If[LessEqual[B$95$m, 3.2e+57], N[(N[(t$95$2 / -1.0), $MachinePrecision] * N[(N[Sqrt[N[(N[(N[Sqrt[B$95$m ^ 2 + N[(A - C), $MachinePrecision] ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] / t$95$0), $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(2.0 * N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision]]]]]]]
                                    
                                    \begin{array}{l}
                                    B_m = \left|B\right|
                                    \\
                                    [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                    \\
                                    \begin{array}{l}
                                    t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
                                    t_1 := \left(2 \cdot F\right) \cdot t\_0\\
                                    t_2 := \sqrt{t\_1}\\
                                    \mathbf{if}\;B\_m \leq 4.7 \cdot 10^{-217}:\\
                                    \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot t\_1}}{-t\_0}\\
                                    
                                    \mathbf{elif}\;B\_m \leq 2.65 \cdot 10^{-42}:\\
                                    \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C\right) + C} \cdot t\_2}{-\left({B\_m}^{2} - \left(4 \cdot A\right) \cdot C\right)}\\
                                    
                                    \mathbf{elif}\;B\_m \leq 3.2 \cdot 10^{+57}:\\
                                    \;\;\;\;\frac{t\_2}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(B\_m, A - C\right) + A\right) + C}}{t\_0}\\
                                    
                                    \mathbf{else}:\\
                                    \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\_m\right) + C\right)}}{-B\_m} \cdot \sqrt{F}\\
                                    
                                    
                                    \end{array}
                                    \end{array}
                                    
                                    Derivation
                                    1. Split input into 4 regimes
                                    2. if B < 4.7000000000000003e-217

                                      1. Initial program 18.9%

                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                      2. Add Preprocessing
                                      3. Applied rewrites27.4%

                                        \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                                      4. Taylor expanded in A around -inf

                                        \[\leadsto \frac{\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                      5. Step-by-step derivation
                                        1. lower-*.f6416.2

                                          \[\leadsto \frac{\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                      6. Applied rewrites16.2%

                                        \[\leadsto \frac{\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]

                                      if 4.7000000000000003e-217 < B < 2.65e-42

                                      1. Initial program 18.5%

                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                      2. Add Preprocessing
                                      3. Step-by-step derivation
                                        1. lift-sqrt.f64N/A

                                          \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                        2. pow1/2N/A

                                          \[\leadsto \frac{-\color{blue}{{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                        3. lift-*.f64N/A

                                          \[\leadsto \frac{-{\color{blue}{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                        4. *-commutativeN/A

                                          \[\leadsto \frac{-{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                        5. unpow-prod-downN/A

                                          \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                        6. lower-*.f64N/A

                                          \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                      4. Applied rewrites35.6%

                                        \[\leadsto \frac{-\color{blue}{\sqrt{\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                      5. Taylor expanded in A around -inf

                                        \[\leadsto \frac{-\sqrt{\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                      6. Step-by-step derivation
                                        1. +-commutativeN/A

                                          \[\leadsto \frac{-\sqrt{\color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + C\right)} + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                        2. lower-fma.f64N/A

                                          \[\leadsto \frac{-\sqrt{\color{blue}{\mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{A}, C\right)} + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                        3. lower-/.f64N/A

                                          \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{-1}{2}, \color{blue}{\frac{{B}^{2}}{A}}, C\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                        4. unpow2N/A

                                          \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{-1}{2}, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                        5. lower-*.f6431.4

                                          \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-0.5, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                      7. Applied rewrites31.4%

                                        \[\leadsto \frac{-\sqrt{\color{blue}{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right)} + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

                                      if 2.65e-42 < B < 3.20000000000000029e57

                                      1. Initial program 41.5%

                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                      2. Add Preprocessing
                                      3. Applied rewrites61.1%

                                        \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]

                                      if 3.20000000000000029e57 < B

                                      1. Initial program 9.3%

                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                      2. Add Preprocessing
                                      3. Step-by-step derivation
                                        1. lift-sqrt.f64N/A

                                          \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                        2. pow1/2N/A

                                          \[\leadsto \frac{-\color{blue}{{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                        3. lift-*.f64N/A

                                          \[\leadsto \frac{-{\color{blue}{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                        4. *-commutativeN/A

                                          \[\leadsto \frac{-{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                        5. unpow-prod-downN/A

                                          \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                        6. lower-*.f64N/A

                                          \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                      4. Applied rewrites15.4%

                                        \[\leadsto \frac{-\color{blue}{\sqrt{\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                      5. Taylor expanded in A around 0

                                        \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                      6. Step-by-step derivation
                                        1. associate-*r*N/A

                                          \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                        2. lower-*.f64N/A

                                          \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                        3. mul-1-negN/A

                                          \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                        4. lower-neg.f64N/A

                                          \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                        5. lower-/.f64N/A

                                          \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                        6. lower-sqrt.f64N/A

                                          \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                        7. lower-sqrt.f64N/A

                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                        8. lower-*.f64N/A

                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                        9. +-commutativeN/A

                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)}} \]
                                        10. lower-+.f64N/A

                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)}} \]
                                        11. +-commutativeN/A

                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right)} \]
                                        12. unpow2N/A

                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right)} \]
                                        13. unpow2N/A

                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right)} \]
                                        14. lower-hypot.f6441.9

                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right)} \]
                                      7. Applied rewrites41.9%

                                        \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}} \]
                                      8. Step-by-step derivation
                                        1. Applied rewrites63.0%

                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                                        2. Step-by-step derivation
                                          1. Applied rewrites63.1%

                                            \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                                        3. Recombined 4 regimes into one program.
                                        4. Final simplification31.7%

                                          \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 4.7 \cdot 10^{-217}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{elif}\;B \leq 2.65 \cdot 10^{-42}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{elif}\;B \leq 3.2 \cdot 10^{+57}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \sqrt{F}\\ \end{array} \]
                                        5. Add Preprocessing

                                        Alternative 9: 58.2% accurate, 2.3× speedup?

                                        \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ t_1 := \left(2 \cdot F\right) \cdot t\_0\\ \mathbf{if}\;B\_m \leq 1.75 \cdot 10^{-146}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot t\_1}}{-t\_0}\\ \mathbf{elif}\;B\_m \leq 3.2 \cdot 10^{+57}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(B\_m, A - C\right) + A\right) + C}}{-1} \cdot \frac{\sqrt{t\_1}}{t\_0}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\_m\right) + C\right)}}{-B\_m} \cdot \sqrt{F}\\ \end{array} \end{array} \]
                                        B_m = (fabs.f64 B)
                                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                        (FPCore (A B_m C F)
                                         :precision binary64
                                         (let* ((t_0 (fma -4.0 (* C A) (* B_m B_m))) (t_1 (* (* 2.0 F) t_0)))
                                           (if (<= B_m 1.75e-146)
                                             (/ (sqrt (* (* 2.0 C) t_1)) (- t_0))
                                             (if (<= B_m 3.2e+57)
                                               (* (/ (sqrt (+ (+ (hypot B_m (- A C)) A) C)) -1.0) (/ (sqrt t_1) t_0))
                                               (* (/ (sqrt (* 2.0 (+ (hypot C B_m) C))) (- B_m)) (sqrt F))))))
                                        B_m = fabs(B);
                                        assert(A < B_m && B_m < C && C < F);
                                        double code(double A, double B_m, double C, double F) {
                                        	double t_0 = fma(-4.0, (C * A), (B_m * B_m));
                                        	double t_1 = (2.0 * F) * t_0;
                                        	double tmp;
                                        	if (B_m <= 1.75e-146) {
                                        		tmp = sqrt(((2.0 * C) * t_1)) / -t_0;
                                        	} else if (B_m <= 3.2e+57) {
                                        		tmp = (sqrt(((hypot(B_m, (A - C)) + A) + C)) / -1.0) * (sqrt(t_1) / t_0);
                                        	} else {
                                        		tmp = (sqrt((2.0 * (hypot(C, B_m) + C))) / -B_m) * sqrt(F);
                                        	}
                                        	return tmp;
                                        }
                                        
                                        B_m = abs(B)
                                        A, B_m, C, F = sort([A, B_m, C, F])
                                        function code(A, B_m, C, F)
                                        	t_0 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
                                        	t_1 = Float64(Float64(2.0 * F) * t_0)
                                        	tmp = 0.0
                                        	if (B_m <= 1.75e-146)
                                        		tmp = Float64(sqrt(Float64(Float64(2.0 * C) * t_1)) / Float64(-t_0));
                                        	elseif (B_m <= 3.2e+57)
                                        		tmp = Float64(Float64(sqrt(Float64(Float64(hypot(B_m, Float64(A - C)) + A) + C)) / -1.0) * Float64(sqrt(t_1) / t_0));
                                        	else
                                        		tmp = Float64(Float64(sqrt(Float64(2.0 * Float64(hypot(C, B_m) + C))) / Float64(-B_m)) * sqrt(F));
                                        	end
                                        	return tmp
                                        end
                                        
                                        B_m = N[Abs[B], $MachinePrecision]
                                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                        code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(2.0 * F), $MachinePrecision] * t$95$0), $MachinePrecision]}, If[LessEqual[B$95$m, 1.75e-146], N[(N[Sqrt[N[(N[(2.0 * C), $MachinePrecision] * t$95$1), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], If[LessEqual[B$95$m, 3.2e+57], N[(N[(N[Sqrt[N[(N[(N[Sqrt[B$95$m ^ 2 + N[(A - C), $MachinePrecision] ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] / -1.0), $MachinePrecision] * N[(N[Sqrt[t$95$1], $MachinePrecision] / t$95$0), $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(2.0 * N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision]]]]]
                                        
                                        \begin{array}{l}
                                        B_m = \left|B\right|
                                        \\
                                        [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                        \\
                                        \begin{array}{l}
                                        t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
                                        t_1 := \left(2 \cdot F\right) \cdot t\_0\\
                                        \mathbf{if}\;B\_m \leq 1.75 \cdot 10^{-146}:\\
                                        \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot t\_1}}{-t\_0}\\
                                        
                                        \mathbf{elif}\;B\_m \leq 3.2 \cdot 10^{+57}:\\
                                        \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(B\_m, A - C\right) + A\right) + C}}{-1} \cdot \frac{\sqrt{t\_1}}{t\_0}\\
                                        
                                        \mathbf{else}:\\
                                        \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\_m\right) + C\right)}}{-B\_m} \cdot \sqrt{F}\\
                                        
                                        
                                        \end{array}
                                        \end{array}
                                        
                                        Derivation
                                        1. Split input into 3 regimes
                                        2. if B < 1.7500000000000001e-146

                                          1. Initial program 20.2%

                                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                          2. Add Preprocessing
                                          3. Applied rewrites28.2%

                                            \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                                          4. Taylor expanded in A around -inf

                                            \[\leadsto \frac{\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                          5. Step-by-step derivation
                                            1. lower-*.f6417.8

                                              \[\leadsto \frac{\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                          6. Applied rewrites17.8%

                                            \[\leadsto \frac{\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]

                                          if 1.7500000000000001e-146 < B < 3.20000000000000029e57

                                          1. Initial program 26.5%

                                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                          2. Add Preprocessing
                                          3. Applied rewrites48.2%

                                            \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C}}{-1} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]

                                          if 3.20000000000000029e57 < B

                                          1. Initial program 9.3%

                                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                          2. Add Preprocessing
                                          3. Step-by-step derivation
                                            1. lift-sqrt.f64N/A

                                              \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            2. pow1/2N/A

                                              \[\leadsto \frac{-\color{blue}{{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            3. lift-*.f64N/A

                                              \[\leadsto \frac{-{\color{blue}{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            4. *-commutativeN/A

                                              \[\leadsto \frac{-{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            5. unpow-prod-downN/A

                                              \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            6. lower-*.f64N/A

                                              \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                          4. Applied rewrites15.4%

                                            \[\leadsto \frac{-\color{blue}{\sqrt{\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                          5. Taylor expanded in A around 0

                                            \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                          6. Step-by-step derivation
                                            1. associate-*r*N/A

                                              \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                            2. lower-*.f64N/A

                                              \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                            3. mul-1-negN/A

                                              \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                            4. lower-neg.f64N/A

                                              \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                            5. lower-/.f64N/A

                                              \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                            6. lower-sqrt.f64N/A

                                              \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                            7. lower-sqrt.f64N/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                            8. lower-*.f64N/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                            9. +-commutativeN/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)}} \]
                                            10. lower-+.f64N/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)}} \]
                                            11. +-commutativeN/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right)} \]
                                            12. unpow2N/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right)} \]
                                            13. unpow2N/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right)} \]
                                            14. lower-hypot.f6441.9

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right)} \]
                                          7. Applied rewrites41.9%

                                            \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}} \]
                                          8. Step-by-step derivation
                                            1. Applied rewrites63.0%

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                                            2. Step-by-step derivation
                                              1. Applied rewrites63.1%

                                                \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                                            3. Recombined 3 regimes into one program.
                                            4. Final simplification32.3%

                                              \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 1.75 \cdot 10^{-146}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{elif}\;B \leq 3.2 \cdot 10^{+57}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C}}{-1} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \sqrt{F}\\ \end{array} \]
                                            5. Add Preprocessing

                                            Alternative 10: 51.1% accurate, 2.4× speedup?

                                            \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 5 \cdot 10^{-42}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot t\_0\right)}}{-t\_0}\\ \mathbf{else}:\\ \;\;\;\;\frac{-\sqrt{F}}{\sqrt{B\_m \cdot 0.5}}\\ \end{array} \end{array} \]
                                            B_m = (fabs.f64 B)
                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                            (FPCore (A B_m C F)
                                             :precision binary64
                                             (let* ((t_0 (fma -4.0 (* C A) (* B_m B_m))))
                                               (if (<= (pow B_m 2.0) 5e-42)
                                                 (/
                                                  (sqrt (* (+ (fma -0.5 (/ (* B_m B_m) A) C) C) (* (* 2.0 F) t_0)))
                                                  (- t_0))
                                                 (/ (- (sqrt F)) (sqrt (* B_m 0.5))))))
                                            B_m = fabs(B);
                                            assert(A < B_m && B_m < C && C < F);
                                            double code(double A, double B_m, double C, double F) {
                                            	double t_0 = fma(-4.0, (C * A), (B_m * B_m));
                                            	double tmp;
                                            	if (pow(B_m, 2.0) <= 5e-42) {
                                            		tmp = sqrt(((fma(-0.5, ((B_m * B_m) / A), C) + C) * ((2.0 * F) * t_0))) / -t_0;
                                            	} else {
                                            		tmp = -sqrt(F) / sqrt((B_m * 0.5));
                                            	}
                                            	return tmp;
                                            }
                                            
                                            B_m = abs(B)
                                            A, B_m, C, F = sort([A, B_m, C, F])
                                            function code(A, B_m, C, F)
                                            	t_0 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
                                            	tmp = 0.0
                                            	if ((B_m ^ 2.0) <= 5e-42)
                                            		tmp = Float64(sqrt(Float64(Float64(fma(-0.5, Float64(Float64(B_m * B_m) / A), C) + C) * Float64(Float64(2.0 * F) * t_0))) / Float64(-t_0));
                                            	else
                                            		tmp = Float64(Float64(-sqrt(F)) / sqrt(Float64(B_m * 0.5)));
                                            	end
                                            	return tmp
                                            end
                                            
                                            B_m = N[Abs[B], $MachinePrecision]
                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                            code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 5e-42], N[(N[Sqrt[N[(N[(N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] + C), $MachinePrecision] + C), $MachinePrecision] * N[(N[(2.0 * F), $MachinePrecision] * t$95$0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) / N[Sqrt[N[(B$95$m * 0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]
                                            
                                            \begin{array}{l}
                                            B_m = \left|B\right|
                                            \\
                                            [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                            \\
                                            \begin{array}{l}
                                            t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
                                            \mathbf{if}\;{B\_m}^{2} \leq 5 \cdot 10^{-42}:\\
                                            \;\;\;\;\frac{\sqrt{\left(\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot t\_0\right)}}{-t\_0}\\
                                            
                                            \mathbf{else}:\\
                                            \;\;\;\;\frac{-\sqrt{F}}{\sqrt{B\_m \cdot 0.5}}\\
                                            
                                            
                                            \end{array}
                                            \end{array}
                                            
                                            Derivation
                                            1. Split input into 2 regimes
                                            2. if (pow.f64 B #s(literal 2 binary64)) < 5.00000000000000003e-42

                                              1. Initial program 20.3%

                                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              2. Add Preprocessing
                                              3. Applied rewrites29.9%

                                                \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                                              4. Taylor expanded in A around -inf

                                                \[\leadsto \frac{\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                              5. Step-by-step derivation
                                                1. +-commutativeN/A

                                                  \[\leadsto \frac{\sqrt{\left(\color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                2. lower-fma.f64N/A

                                                  \[\leadsto \frac{\sqrt{\left(\color{blue}{\mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{A}, C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                3. lower-/.f64N/A

                                                  \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(\frac{-1}{2}, \color{blue}{\frac{{B}^{2}}{A}}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                4. unpow2N/A

                                                  \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(\frac{-1}{2}, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                5. lower-*.f6428.0

                                                  \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(-0.5, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                              6. Applied rewrites28.0%

                                                \[\leadsto \frac{\sqrt{\left(\color{blue}{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]

                                              if 5.00000000000000003e-42 < (pow.f64 B #s(literal 2 binary64))

                                              1. Initial program 18.8%

                                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              2. Add Preprocessing
                                              3. Taylor expanded in B around inf

                                                \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                              4. Step-by-step derivation
                                                1. mul-1-negN/A

                                                  \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                2. lower-neg.f64N/A

                                                  \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                3. lower-*.f64N/A

                                                  \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                4. lower-sqrt.f64N/A

                                                  \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                5. lower-/.f64N/A

                                                  \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                6. lower-sqrt.f6418.3

                                                  \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                              5. Applied rewrites18.3%

                                                \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                              6. Step-by-step derivation
                                                1. Applied rewrites18.4%

                                                  \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                2. Step-by-step derivation
                                                  1. Applied rewrites18.4%

                                                    \[\leadsto -\sqrt{F \cdot \frac{2}{B}} \]
                                                  2. Step-by-step derivation
                                                    1. Applied rewrites25.2%

                                                      \[\leadsto -\frac{\sqrt{F}}{\sqrt{B \cdot 0.5}} \]
                                                  3. Recombined 2 regimes into one program.
                                                  4. Final simplification26.5%

                                                    \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 5 \cdot 10^{-42}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{-\sqrt{F}}{\sqrt{B \cdot 0.5}}\\ \end{array} \]
                                                  5. Add Preprocessing

                                                  Alternative 11: 57.0% accurate, 2.5× speedup?

                                                  \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ t_1 := -t\_0\\ t_2 := \left(2 \cdot F\right) \cdot t\_0\\ \mathbf{if}\;B\_m \leq 4.7 \cdot 10^{-217}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot t\_2}}{t\_1}\\ \mathbf{elif}\;B\_m \leq 3.9 \cdot 10^{-25}:\\ \;\;\;\;\frac{\sqrt{C + C} \cdot \sqrt{t\_2}}{-\left({B\_m}^{2} - \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{elif}\;B\_m \leq 6.2 \cdot 10^{+57}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B\_m, A - C\right) + A\right) + C\right) \cdot t\_2}}{t\_1}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\_m\right) + C\right)}}{-B\_m} \cdot \sqrt{F}\\ \end{array} \end{array} \]
                                                  B_m = (fabs.f64 B)
                                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                  (FPCore (A B_m C F)
                                                   :precision binary64
                                                   (let* ((t_0 (fma -4.0 (* C A) (* B_m B_m)))
                                                          (t_1 (- t_0))
                                                          (t_2 (* (* 2.0 F) t_0)))
                                                     (if (<= B_m 4.7e-217)
                                                       (/ (sqrt (* (* 2.0 C) t_2)) t_1)
                                                       (if (<= B_m 3.9e-25)
                                                         (/ (* (sqrt (+ C C)) (sqrt t_2)) (- (- (pow B_m 2.0) (* (* 4.0 A) C))))
                                                         (if (<= B_m 6.2e+57)
                                                           (/ (sqrt (* (+ (+ (hypot B_m (- A C)) A) C) t_2)) t_1)
                                                           (* (/ (sqrt (* 2.0 (+ (hypot C B_m) C))) (- B_m)) (sqrt F)))))))
                                                  B_m = fabs(B);
                                                  assert(A < B_m && B_m < C && C < F);
                                                  double code(double A, double B_m, double C, double F) {
                                                  	double t_0 = fma(-4.0, (C * A), (B_m * B_m));
                                                  	double t_1 = -t_0;
                                                  	double t_2 = (2.0 * F) * t_0;
                                                  	double tmp;
                                                  	if (B_m <= 4.7e-217) {
                                                  		tmp = sqrt(((2.0 * C) * t_2)) / t_1;
                                                  	} else if (B_m <= 3.9e-25) {
                                                  		tmp = (sqrt((C + C)) * sqrt(t_2)) / -(pow(B_m, 2.0) - ((4.0 * A) * C));
                                                  	} else if (B_m <= 6.2e+57) {
                                                  		tmp = sqrt((((hypot(B_m, (A - C)) + A) + C) * t_2)) / t_1;
                                                  	} else {
                                                  		tmp = (sqrt((2.0 * (hypot(C, B_m) + C))) / -B_m) * sqrt(F);
                                                  	}
                                                  	return tmp;
                                                  }
                                                  
                                                  B_m = abs(B)
                                                  A, B_m, C, F = sort([A, B_m, C, F])
                                                  function code(A, B_m, C, F)
                                                  	t_0 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
                                                  	t_1 = Float64(-t_0)
                                                  	t_2 = Float64(Float64(2.0 * F) * t_0)
                                                  	tmp = 0.0
                                                  	if (B_m <= 4.7e-217)
                                                  		tmp = Float64(sqrt(Float64(Float64(2.0 * C) * t_2)) / t_1);
                                                  	elseif (B_m <= 3.9e-25)
                                                  		tmp = Float64(Float64(sqrt(Float64(C + C)) * sqrt(t_2)) / Float64(-Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C))));
                                                  	elseif (B_m <= 6.2e+57)
                                                  		tmp = Float64(sqrt(Float64(Float64(Float64(hypot(B_m, Float64(A - C)) + A) + C) * t_2)) / t_1);
                                                  	else
                                                  		tmp = Float64(Float64(sqrt(Float64(2.0 * Float64(hypot(C, B_m) + C))) / Float64(-B_m)) * sqrt(F));
                                                  	end
                                                  	return tmp
                                                  end
                                                  
                                                  B_m = N[Abs[B], $MachinePrecision]
                                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                  code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = (-t$95$0)}, Block[{t$95$2 = N[(N[(2.0 * F), $MachinePrecision] * t$95$0), $MachinePrecision]}, If[LessEqual[B$95$m, 4.7e-217], N[(N[Sqrt[N[(N[(2.0 * C), $MachinePrecision] * t$95$2), $MachinePrecision]], $MachinePrecision] / t$95$1), $MachinePrecision], If[LessEqual[B$95$m, 3.9e-25], N[(N[(N[Sqrt[N[(C + C), $MachinePrecision]], $MachinePrecision] * N[Sqrt[t$95$2], $MachinePrecision]), $MachinePrecision] / (-N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision])), $MachinePrecision], If[LessEqual[B$95$m, 6.2e+57], N[(N[Sqrt[N[(N[(N[(N[Sqrt[B$95$m ^ 2 + N[(A - C), $MachinePrecision] ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision] * t$95$2), $MachinePrecision]], $MachinePrecision] / t$95$1), $MachinePrecision], N[(N[(N[Sqrt[N[(2.0 * N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision]]]]]]]
                                                  
                                                  \begin{array}{l}
                                                  B_m = \left|B\right|
                                                  \\
                                                  [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                  \\
                                                  \begin{array}{l}
                                                  t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
                                                  t_1 := -t\_0\\
                                                  t_2 := \left(2 \cdot F\right) \cdot t\_0\\
                                                  \mathbf{if}\;B\_m \leq 4.7 \cdot 10^{-217}:\\
                                                  \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot t\_2}}{t\_1}\\
                                                  
                                                  \mathbf{elif}\;B\_m \leq 3.9 \cdot 10^{-25}:\\
                                                  \;\;\;\;\frac{\sqrt{C + C} \cdot \sqrt{t\_2}}{-\left({B\_m}^{2} - \left(4 \cdot A\right) \cdot C\right)}\\
                                                  
                                                  \mathbf{elif}\;B\_m \leq 6.2 \cdot 10^{+57}:\\
                                                  \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B\_m, A - C\right) + A\right) + C\right) \cdot t\_2}}{t\_1}\\
                                                  
                                                  \mathbf{else}:\\
                                                  \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\_m\right) + C\right)}}{-B\_m} \cdot \sqrt{F}\\
                                                  
                                                  
                                                  \end{array}
                                                  \end{array}
                                                  
                                                  Derivation
                                                  1. Split input into 4 regimes
                                                  2. if B < 4.7000000000000003e-217

                                                    1. Initial program 18.9%

                                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                    2. Add Preprocessing
                                                    3. Applied rewrites27.4%

                                                      \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                                                    4. Taylor expanded in A around -inf

                                                      \[\leadsto \frac{\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                    5. Step-by-step derivation
                                                      1. lower-*.f6416.2

                                                        \[\leadsto \frac{\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                    6. Applied rewrites16.2%

                                                      \[\leadsto \frac{\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]

                                                    if 4.7000000000000003e-217 < B < 3.9e-25

                                                    1. Initial program 21.3%

                                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                    2. Add Preprocessing
                                                    3. Step-by-step derivation
                                                      1. lift-sqrt.f64N/A

                                                        \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      2. pow1/2N/A

                                                        \[\leadsto \frac{-\color{blue}{{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      3. lift-*.f64N/A

                                                        \[\leadsto \frac{-{\color{blue}{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      4. *-commutativeN/A

                                                        \[\leadsto \frac{-{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      5. unpow-prod-downN/A

                                                        \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      6. lower-*.f64N/A

                                                        \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                    4. Applied rewrites40.9%

                                                      \[\leadsto \frac{-\color{blue}{\sqrt{\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                    5. Taylor expanded in C around inf

                                                      \[\leadsto \frac{-\sqrt{\color{blue}{C \cdot \left(1 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)} + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                    6. Step-by-step derivation
                                                      1. distribute-lft1-inN/A

                                                        \[\leadsto \frac{-\sqrt{C \cdot \left(1 + \color{blue}{\left(-1 + 1\right) \cdot \frac{A}{C}}\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      2. metadata-evalN/A

                                                        \[\leadsto \frac{-\sqrt{C \cdot \left(1 + \color{blue}{0} \cdot \frac{A}{C}\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      3. mul0-lftN/A

                                                        \[\leadsto \frac{-\sqrt{C \cdot \left(1 + \color{blue}{0}\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      4. metadata-evalN/A

                                                        \[\leadsto \frac{-\sqrt{C \cdot \color{blue}{1} + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      5. *-rgt-identity28.0

                                                        \[\leadsto \frac{-\sqrt{\color{blue}{C} + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                    7. Applied rewrites28.0%

                                                      \[\leadsto \frac{-\sqrt{\color{blue}{C} + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

                                                    if 3.9e-25 < B < 6.20000000000000026e57

                                                    1. Initial program 39.9%

                                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                    2. Add Preprocessing
                                                    3. Applied rewrites46.7%

                                                      \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]

                                                    if 6.20000000000000026e57 < B

                                                    1. Initial program 9.5%

                                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                    2. Add Preprocessing
                                                    3. Step-by-step derivation
                                                      1. lift-sqrt.f64N/A

                                                        \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      2. pow1/2N/A

                                                        \[\leadsto \frac{-\color{blue}{{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      3. lift-*.f64N/A

                                                        \[\leadsto \frac{-{\color{blue}{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      4. *-commutativeN/A

                                                        \[\leadsto \frac{-{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      5. unpow-prod-downN/A

                                                        \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      6. lower-*.f64N/A

                                                        \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                    4. Applied rewrites15.7%

                                                      \[\leadsto \frac{-\color{blue}{\sqrt{\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                    5. Taylor expanded in A around 0

                                                      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                    6. Step-by-step derivation
                                                      1. associate-*r*N/A

                                                        \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                      2. lower-*.f64N/A

                                                        \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                      3. mul-1-negN/A

                                                        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                      4. lower-neg.f64N/A

                                                        \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                      5. lower-/.f64N/A

                                                        \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                      6. lower-sqrt.f64N/A

                                                        \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                      7. lower-sqrt.f64N/A

                                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                      8. lower-*.f64N/A

                                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                      9. +-commutativeN/A

                                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)}} \]
                                                      10. lower-+.f64N/A

                                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)}} \]
                                                      11. +-commutativeN/A

                                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right)} \]
                                                      12. unpow2N/A

                                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right)} \]
                                                      13. unpow2N/A

                                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right)} \]
                                                      14. lower-hypot.f6442.7

                                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right)} \]
                                                    7. Applied rewrites42.7%

                                                      \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}} \]
                                                    8. Step-by-step derivation
                                                      1. Applied rewrites64.3%

                                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                                                      2. Step-by-step derivation
                                                        1. Applied rewrites64.4%

                                                          \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                                                      3. Recombined 4 regimes into one program.
                                                      4. Final simplification29.5%

                                                        \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 4.7 \cdot 10^{-217}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{elif}\;B \leq 3.9 \cdot 10^{-25}:\\ \;\;\;\;\frac{\sqrt{C + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{elif}\;B \leq 6.2 \cdot 10^{+57}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \sqrt{F}\\ \end{array} \]
                                                      5. Add Preprocessing

                                                      Alternative 12: 51.2% accurate, 2.7× speedup?

                                                      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 4 \cdot 10^{-54}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(\left(2 \cdot F\right) \cdot t\_0\right)}}{-t\_0}\\ \mathbf{else}:\\ \;\;\;\;\frac{-\sqrt{F}}{\sqrt{B\_m \cdot 0.5}}\\ \end{array} \end{array} \]
                                                      B_m = (fabs.f64 B)
                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                      (FPCore (A B_m C F)
                                                       :precision binary64
                                                       (let* ((t_0 (fma -4.0 (* C A) (* B_m B_m))))
                                                         (if (<= (pow B_m 2.0) 4e-54)
                                                           (/ (sqrt (* (* 2.0 C) (* (* 2.0 F) t_0))) (- t_0))
                                                           (/ (- (sqrt F)) (sqrt (* B_m 0.5))))))
                                                      B_m = fabs(B);
                                                      assert(A < B_m && B_m < C && C < F);
                                                      double code(double A, double B_m, double C, double F) {
                                                      	double t_0 = fma(-4.0, (C * A), (B_m * B_m));
                                                      	double tmp;
                                                      	if (pow(B_m, 2.0) <= 4e-54) {
                                                      		tmp = sqrt(((2.0 * C) * ((2.0 * F) * t_0))) / -t_0;
                                                      	} else {
                                                      		tmp = -sqrt(F) / sqrt((B_m * 0.5));
                                                      	}
                                                      	return tmp;
                                                      }
                                                      
                                                      B_m = abs(B)
                                                      A, B_m, C, F = sort([A, B_m, C, F])
                                                      function code(A, B_m, C, F)
                                                      	t_0 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
                                                      	tmp = 0.0
                                                      	if ((B_m ^ 2.0) <= 4e-54)
                                                      		tmp = Float64(sqrt(Float64(Float64(2.0 * C) * Float64(Float64(2.0 * F) * t_0))) / Float64(-t_0));
                                                      	else
                                                      		tmp = Float64(Float64(-sqrt(F)) / sqrt(Float64(B_m * 0.5)));
                                                      	end
                                                      	return tmp
                                                      end
                                                      
                                                      B_m = N[Abs[B], $MachinePrecision]
                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                      code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 4e-54], N[(N[Sqrt[N[(N[(2.0 * C), $MachinePrecision] * N[(N[(2.0 * F), $MachinePrecision] * t$95$0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) / N[Sqrt[N[(B$95$m * 0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]
                                                      
                                                      \begin{array}{l}
                                                      B_m = \left|B\right|
                                                      \\
                                                      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                      \\
                                                      \begin{array}{l}
                                                      t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
                                                      \mathbf{if}\;{B\_m}^{2} \leq 4 \cdot 10^{-54}:\\
                                                      \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(\left(2 \cdot F\right) \cdot t\_0\right)}}{-t\_0}\\
                                                      
                                                      \mathbf{else}:\\
                                                      \;\;\;\;\frac{-\sqrt{F}}{\sqrt{B\_m \cdot 0.5}}\\
                                                      
                                                      
                                                      \end{array}
                                                      \end{array}
                                                      
                                                      Derivation
                                                      1. Split input into 2 regimes
                                                      2. if (pow.f64 B #s(literal 2 binary64)) < 4.0000000000000001e-54

                                                        1. Initial program 20.0%

                                                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                        2. Add Preprocessing
                                                        3. Applied rewrites29.9%

                                                          \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                                                        4. Taylor expanded in A around -inf

                                                          \[\leadsto \frac{\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                        5. Step-by-step derivation
                                                          1. lower-*.f6428.7

                                                            \[\leadsto \frac{\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                        6. Applied rewrites28.7%

                                                          \[\leadsto \frac{\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]

                                                        if 4.0000000000000001e-54 < (pow.f64 B #s(literal 2 binary64))

                                                        1. Initial program 19.0%

                                                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                        2. Add Preprocessing
                                                        3. Taylor expanded in B around inf

                                                          \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                        4. Step-by-step derivation
                                                          1. mul-1-negN/A

                                                            \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                          2. lower-neg.f64N/A

                                                            \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                          3. lower-*.f64N/A

                                                            \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                          4. lower-sqrt.f64N/A

                                                            \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                          5. lower-/.f64N/A

                                                            \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                          6. lower-sqrt.f6417.8

                                                            \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                        5. Applied rewrites17.8%

                                                          \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                        6. Step-by-step derivation
                                                          1. Applied rewrites17.9%

                                                            \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                          2. Step-by-step derivation
                                                            1. Applied rewrites17.8%

                                                              \[\leadsto -\sqrt{F \cdot \frac{2}{B}} \]
                                                            2. Step-by-step derivation
                                                              1. Applied rewrites24.5%

                                                                \[\leadsto -\frac{\sqrt{F}}{\sqrt{B \cdot 0.5}} \]
                                                            3. Recombined 2 regimes into one program.
                                                            4. Final simplification26.4%

                                                              \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 4 \cdot 10^{-54}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{-\sqrt{F}}{\sqrt{B \cdot 0.5}}\\ \end{array} \]
                                                            5. Add Preprocessing

                                                            Alternative 13: 57.7% accurate, 2.7× speedup?

                                                            \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;B\_m \leq 2.1 \cdot 10^{-38}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot t\_0\right)}}{-t\_0}\\ \mathbf{elif}\;B\_m \leq 2.1 \cdot 10^{+31}:\\ \;\;\;\;\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\_m\right) + C\right) + A\right) \cdot F}{t\_0}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\_m\right) + C\right)}}{-B\_m} \cdot \sqrt{F}\\ \end{array} \end{array} \]
                                                            B_m = (fabs.f64 B)
                                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                            (FPCore (A B_m C F)
                                                             :precision binary64
                                                             (let* ((t_0 (fma -4.0 (* C A) (* B_m B_m))))
                                                               (if (<= B_m 2.1e-38)
                                                                 (/
                                                                  (sqrt (* (+ (fma -0.5 (/ (* B_m B_m) A) C) C) (* (* 2.0 F) t_0)))
                                                                  (- t_0))
                                                                 (if (<= B_m 2.1e+31)
                                                                   (* (sqrt (/ (* (+ (+ (hypot (- A C) B_m) C) A) F) t_0)) (- (sqrt 2.0)))
                                                                   (* (/ (sqrt (* 2.0 (+ (hypot C B_m) C))) (- B_m)) (sqrt F))))))
                                                            B_m = fabs(B);
                                                            assert(A < B_m && B_m < C && C < F);
                                                            double code(double A, double B_m, double C, double F) {
                                                            	double t_0 = fma(-4.0, (C * A), (B_m * B_m));
                                                            	double tmp;
                                                            	if (B_m <= 2.1e-38) {
                                                            		tmp = sqrt(((fma(-0.5, ((B_m * B_m) / A), C) + C) * ((2.0 * F) * t_0))) / -t_0;
                                                            	} else if (B_m <= 2.1e+31) {
                                                            		tmp = sqrt(((((hypot((A - C), B_m) + C) + A) * F) / t_0)) * -sqrt(2.0);
                                                            	} else {
                                                            		tmp = (sqrt((2.0 * (hypot(C, B_m) + C))) / -B_m) * sqrt(F);
                                                            	}
                                                            	return tmp;
                                                            }
                                                            
                                                            B_m = abs(B)
                                                            A, B_m, C, F = sort([A, B_m, C, F])
                                                            function code(A, B_m, C, F)
                                                            	t_0 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
                                                            	tmp = 0.0
                                                            	if (B_m <= 2.1e-38)
                                                            		tmp = Float64(sqrt(Float64(Float64(fma(-0.5, Float64(Float64(B_m * B_m) / A), C) + C) * Float64(Float64(2.0 * F) * t_0))) / Float64(-t_0));
                                                            	elseif (B_m <= 2.1e+31)
                                                            		tmp = Float64(sqrt(Float64(Float64(Float64(Float64(hypot(Float64(A - C), B_m) + C) + A) * F) / t_0)) * Float64(-sqrt(2.0)));
                                                            	else
                                                            		tmp = Float64(Float64(sqrt(Float64(2.0 * Float64(hypot(C, B_m) + C))) / Float64(-B_m)) * sqrt(F));
                                                            	end
                                                            	return tmp
                                                            end
                                                            
                                                            B_m = N[Abs[B], $MachinePrecision]
                                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                            code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[B$95$m, 2.1e-38], N[(N[Sqrt[N[(N[(N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] + C), $MachinePrecision] + C), $MachinePrecision] * N[(N[(2.0 * F), $MachinePrecision] * t$95$0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], If[LessEqual[B$95$m, 2.1e+31], N[(N[Sqrt[N[(N[(N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] + A), $MachinePrecision] * F), $MachinePrecision] / t$95$0), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[2.0], $MachinePrecision])), $MachinePrecision], N[(N[(N[Sqrt[N[(2.0 * N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision]]]]
                                                            
                                                            \begin{array}{l}
                                                            B_m = \left|B\right|
                                                            \\
                                                            [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                            \\
                                                            \begin{array}{l}
                                                            t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
                                                            \mathbf{if}\;B\_m \leq 2.1 \cdot 10^{-38}:\\
                                                            \;\;\;\;\frac{\sqrt{\left(\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot t\_0\right)}}{-t\_0}\\
                                                            
                                                            \mathbf{elif}\;B\_m \leq 2.1 \cdot 10^{+31}:\\
                                                            \;\;\;\;\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\_m\right) + C\right) + A\right) \cdot F}{t\_0}} \cdot \left(-\sqrt{2}\right)\\
                                                            
                                                            \mathbf{else}:\\
                                                            \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\_m\right) + C\right)}}{-B\_m} \cdot \sqrt{F}\\
                                                            
                                                            
                                                            \end{array}
                                                            \end{array}
                                                            
                                                            Derivation
                                                            1. Split input into 3 regimes
                                                            2. if B < 2.10000000000000013e-38

                                                              1. Initial program 18.7%

                                                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                              2. Add Preprocessing
                                                              3. Applied rewrites25.8%

                                                                \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                                                              4. Taylor expanded in A around -inf

                                                                \[\leadsto \frac{\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                              5. Step-by-step derivation
                                                                1. +-commutativeN/A

                                                                  \[\leadsto \frac{\sqrt{\left(\color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                                2. lower-fma.f64N/A

                                                                  \[\leadsto \frac{\sqrt{\left(\color{blue}{\mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{A}, C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                                3. lower-/.f64N/A

                                                                  \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(\frac{-1}{2}, \color{blue}{\frac{{B}^{2}}{A}}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                                4. unpow2N/A

                                                                  \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(\frac{-1}{2}, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                                5. lower-*.f6418.2

                                                                  \[\leadsto \frac{\sqrt{\left(\mathsf{fma}\left(-0.5, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                              6. Applied rewrites18.2%

                                                                \[\leadsto \frac{\sqrt{\left(\color{blue}{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]

                                                              if 2.10000000000000013e-38 < B < 2.09999999999999979e31

                                                              1. Initial program 56.4%

                                                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                              2. Add Preprocessing
                                                              3. Taylor expanded in F around 0

                                                                \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                                              4. Step-by-step derivation
                                                                1. associate-*r*N/A

                                                                  \[\leadsto \color{blue}{\left(-1 \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}\right) \cdot \sqrt{2}} \]
                                                                2. lower-*.f64N/A

                                                                  \[\leadsto \color{blue}{\left(-1 \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}\right) \cdot \sqrt{2}} \]
                                                              5. Applied rewrites63.4%

                                                                \[\leadsto \color{blue}{\left(-\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}\right) \cdot \sqrt{2}} \]

                                                              if 2.09999999999999979e31 < B

                                                              1. Initial program 11.6%

                                                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                              2. Add Preprocessing
                                                              3. Step-by-step derivation
                                                                1. lift-sqrt.f64N/A

                                                                  \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                2. pow1/2N/A

                                                                  \[\leadsto \frac{-\color{blue}{{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                3. lift-*.f64N/A

                                                                  \[\leadsto \frac{-{\color{blue}{\left(\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                4. *-commutativeN/A

                                                                  \[\leadsto \frac{-{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                5. unpow-prod-downN/A

                                                                  \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                6. lower-*.f64N/A

                                                                  \[\leadsto \frac{-\color{blue}{{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}^{\frac{1}{2}} \cdot {\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                              4. Applied rewrites20.8%

                                                                \[\leadsto \frac{-\color{blue}{\sqrt{\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C} \cdot \sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                              5. Taylor expanded in A around 0

                                                                \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                              6. Step-by-step derivation
                                                                1. associate-*r*N/A

                                                                  \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                2. lower-*.f64N/A

                                                                  \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                3. mul-1-negN/A

                                                                  \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                4. lower-neg.f64N/A

                                                                  \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                5. lower-/.f64N/A

                                                                  \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                6. lower-sqrt.f64N/A

                                                                  \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                7. lower-sqrt.f64N/A

                                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                8. lower-*.f64N/A

                                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                9. +-commutativeN/A

                                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)}} \]
                                                                10. lower-+.f64N/A

                                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)}} \]
                                                                11. +-commutativeN/A

                                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right)} \]
                                                                12. unpow2N/A

                                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right)} \]
                                                                13. unpow2N/A

                                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right)} \]
                                                                14. lower-hypot.f6439.2

                                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right)} \]
                                                              7. Applied rewrites39.2%

                                                                \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}} \]
                                                              8. Step-by-step derivation
                                                                1. Applied rewrites58.6%

                                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                                                                2. Step-by-step derivation
                                                                  1. Applied rewrites58.7%

                                                                    \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                                                                3. Recombined 3 regimes into one program.
                                                                4. Final simplification29.9%

                                                                  \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 2.1 \cdot 10^{-38}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{elif}\;B \leq 2.1 \cdot 10^{+31}:\\ \;\;\;\;\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \sqrt{F}\\ \end{array} \]
                                                                5. Add Preprocessing

                                                                Alternative 14: 44.5% accurate, 7.4× speedup?

                                                                \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;B\_m \leq 1.02 \cdot 10^{-48}:\\ \;\;\;\;\frac{\sqrt{-16 \cdot \left(\left(A \cdot \left(C \cdot C\right)\right) \cdot F\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{-\sqrt{F}}{\sqrt{B\_m \cdot 0.5}}\\ \end{array} \end{array} \]
                                                                B_m = (fabs.f64 B)
                                                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                (FPCore (A B_m C F)
                                                                 :precision binary64
                                                                 (if (<= B_m 1.02e-48)
                                                                   (/ (sqrt (* -16.0 (* (* A (* C C)) F))) (- (fma -4.0 (* C A) (* B_m B_m))))
                                                                   (/ (- (sqrt F)) (sqrt (* B_m 0.5)))))
                                                                B_m = fabs(B);
                                                                assert(A < B_m && B_m < C && C < F);
                                                                double code(double A, double B_m, double C, double F) {
                                                                	double tmp;
                                                                	if (B_m <= 1.02e-48) {
                                                                		tmp = sqrt((-16.0 * ((A * (C * C)) * F))) / -fma(-4.0, (C * A), (B_m * B_m));
                                                                	} else {
                                                                		tmp = -sqrt(F) / sqrt((B_m * 0.5));
                                                                	}
                                                                	return tmp;
                                                                }
                                                                
                                                                B_m = abs(B)
                                                                A, B_m, C, F = sort([A, B_m, C, F])
                                                                function code(A, B_m, C, F)
                                                                	tmp = 0.0
                                                                	if (B_m <= 1.02e-48)
                                                                		tmp = Float64(sqrt(Float64(-16.0 * Float64(Float64(A * Float64(C * C)) * F))) / Float64(-fma(-4.0, Float64(C * A), Float64(B_m * B_m))));
                                                                	else
                                                                		tmp = Float64(Float64(-sqrt(F)) / sqrt(Float64(B_m * 0.5)));
                                                                	end
                                                                	return tmp
                                                                end
                                                                
                                                                B_m = N[Abs[B], $MachinePrecision]
                                                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                code[A_, B$95$m_, C_, F_] := If[LessEqual[B$95$m, 1.02e-48], N[(N[Sqrt[N[(-16.0 * N[(N[(A * N[(C * C), $MachinePrecision]), $MachinePrecision] * F), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision])), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) / N[Sqrt[N[(B$95$m * 0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]
                                                                
                                                                \begin{array}{l}
                                                                B_m = \left|B\right|
                                                                \\
                                                                [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                \\
                                                                \begin{array}{l}
                                                                \mathbf{if}\;B\_m \leq 1.02 \cdot 10^{-48}:\\
                                                                \;\;\;\;\frac{\sqrt{-16 \cdot \left(\left(A \cdot \left(C \cdot C\right)\right) \cdot F\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)}\\
                                                                
                                                                \mathbf{else}:\\
                                                                \;\;\;\;\frac{-\sqrt{F}}{\sqrt{B\_m \cdot 0.5}}\\
                                                                
                                                                
                                                                \end{array}
                                                                \end{array}
                                                                
                                                                Derivation
                                                                1. Split input into 2 regimes
                                                                2. if B < 1.02000000000000005e-48

                                                                  1. Initial program 19.1%

                                                                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                  2. Add Preprocessing
                                                                  3. Applied rewrites26.4%

                                                                    \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                                                                  4. Taylor expanded in A around -inf

                                                                    \[\leadsto \frac{\sqrt{\color{blue}{-16 \cdot \left(A \cdot \left({C}^{2} \cdot F\right)\right)}}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                                  5. Step-by-step derivation
                                                                    1. lower-*.f64N/A

                                                                      \[\leadsto \frac{\sqrt{\color{blue}{-16 \cdot \left(A \cdot \left({C}^{2} \cdot F\right)\right)}}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                                    2. associate-*r*N/A

                                                                      \[\leadsto \frac{\sqrt{-16 \cdot \color{blue}{\left(\left(A \cdot {C}^{2}\right) \cdot F\right)}}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                                    3. lower-*.f64N/A

                                                                      \[\leadsto \frac{\sqrt{-16 \cdot \color{blue}{\left(\left(A \cdot {C}^{2}\right) \cdot F\right)}}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                                    4. lower-*.f64N/A

                                                                      \[\leadsto \frac{\sqrt{-16 \cdot \left(\color{blue}{\left(A \cdot {C}^{2}\right)} \cdot F\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                                    5. unpow2N/A

                                                                      \[\leadsto \frac{\sqrt{-16 \cdot \left(\left(A \cdot \color{blue}{\left(C \cdot C\right)}\right) \cdot F\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                                    6. lower-*.f6412.5

                                                                      \[\leadsto \frac{\sqrt{-16 \cdot \left(\left(A \cdot \color{blue}{\left(C \cdot C\right)}\right) \cdot F\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                                  6. Applied rewrites12.5%

                                                                    \[\leadsto \frac{\sqrt{\color{blue}{-16 \cdot \left(\left(A \cdot \left(C \cdot C\right)\right) \cdot F\right)}}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]

                                                                  if 1.02000000000000005e-48 < B

                                                                  1. Initial program 20.3%

                                                                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                  2. Add Preprocessing
                                                                  3. Taylor expanded in B around inf

                                                                    \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                  4. Step-by-step derivation
                                                                    1. mul-1-negN/A

                                                                      \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                    2. lower-neg.f64N/A

                                                                      \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                    3. lower-*.f64N/A

                                                                      \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                    4. lower-sqrt.f64N/A

                                                                      \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                    5. lower-/.f64N/A

                                                                      \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                    6. lower-sqrt.f6434.7

                                                                      \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                                  5. Applied rewrites34.7%

                                                                    \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                  6. Step-by-step derivation
                                                                    1. Applied rewrites34.9%

                                                                      \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                    2. Step-by-step derivation
                                                                      1. Applied rewrites34.9%

                                                                        \[\leadsto -\sqrt{F \cdot \frac{2}{B}} \]
                                                                      2. Step-by-step derivation
                                                                        1. Applied rewrites48.3%

                                                                          \[\leadsto -\frac{\sqrt{F}}{\sqrt{B \cdot 0.5}} \]
                                                                      3. Recombined 2 regimes into one program.
                                                                      4. Final simplification23.3%

                                                                        \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 1.02 \cdot 10^{-48}:\\ \;\;\;\;\frac{\sqrt{-16 \cdot \left(\left(A \cdot \left(C \cdot C\right)\right) \cdot F\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{-\sqrt{F}}{\sqrt{B \cdot 0.5}}\\ \end{array} \]
                                                                      5. Add Preprocessing

                                                                      Alternative 15: 35.7% accurate, 12.6× speedup?

                                                                      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \frac{-\sqrt{F}}{\sqrt{B\_m \cdot 0.5}} \end{array} \]
                                                                      B_m = (fabs.f64 B)
                                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                      (FPCore (A B_m C F) :precision binary64 (/ (- (sqrt F)) (sqrt (* B_m 0.5))))
                                                                      B_m = fabs(B);
                                                                      assert(A < B_m && B_m < C && C < F);
                                                                      double code(double A, double B_m, double C, double F) {
                                                                      	return -sqrt(F) / sqrt((B_m * 0.5));
                                                                      }
                                                                      
                                                                      B_m = abs(b)
                                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                      real(8) function code(a, b_m, c, f)
                                                                          real(8), intent (in) :: a
                                                                          real(8), intent (in) :: b_m
                                                                          real(8), intent (in) :: c
                                                                          real(8), intent (in) :: f
                                                                          code = -sqrt(f) / sqrt((b_m * 0.5d0))
                                                                      end function
                                                                      
                                                                      B_m = Math.abs(B);
                                                                      assert A < B_m && B_m < C && C < F;
                                                                      public static double code(double A, double B_m, double C, double F) {
                                                                      	return -Math.sqrt(F) / Math.sqrt((B_m * 0.5));
                                                                      }
                                                                      
                                                                      B_m = math.fabs(B)
                                                                      [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                      def code(A, B_m, C, F):
                                                                      	return -math.sqrt(F) / math.sqrt((B_m * 0.5))
                                                                      
                                                                      B_m = abs(B)
                                                                      A, B_m, C, F = sort([A, B_m, C, F])
                                                                      function code(A, B_m, C, F)
                                                                      	return Float64(Float64(-sqrt(F)) / sqrt(Float64(B_m * 0.5)))
                                                                      end
                                                                      
                                                                      B_m = abs(B);
                                                                      A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                      function tmp = code(A, B_m, C, F)
                                                                      	tmp = -sqrt(F) / sqrt((B_m * 0.5));
                                                                      end
                                                                      
                                                                      B_m = N[Abs[B], $MachinePrecision]
                                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                      code[A_, B$95$m_, C_, F_] := N[((-N[Sqrt[F], $MachinePrecision]) / N[Sqrt[N[(B$95$m * 0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
                                                                      
                                                                      \begin{array}{l}
                                                                      B_m = \left|B\right|
                                                                      \\
                                                                      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                      \\
                                                                      \frac{-\sqrt{F}}{\sqrt{B\_m \cdot 0.5}}
                                                                      \end{array}
                                                                      
                                                                      Derivation
                                                                      1. Initial program 19.5%

                                                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                      2. Add Preprocessing
                                                                      3. Taylor expanded in B around inf

                                                                        \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                      4. Step-by-step derivation
                                                                        1. mul-1-negN/A

                                                                          \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                        2. lower-neg.f64N/A

                                                                          \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                        3. lower-*.f64N/A

                                                                          \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                        4. lower-sqrt.f64N/A

                                                                          \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                        5. lower-/.f64N/A

                                                                          \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                        6. lower-sqrt.f6412.4

                                                                          \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                                      5. Applied rewrites12.4%

                                                                        \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                      6. Step-by-step derivation
                                                                        1. Applied rewrites12.5%

                                                                          \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                        2. Step-by-step derivation
                                                                          1. Applied rewrites12.5%

                                                                            \[\leadsto -\sqrt{F \cdot \frac{2}{B}} \]
                                                                          2. Step-by-step derivation
                                                                            1. Applied rewrites16.1%

                                                                              \[\leadsto -\frac{\sqrt{F}}{\sqrt{B \cdot 0.5}} \]
                                                                            2. Final simplification16.1%

                                                                              \[\leadsto \frac{-\sqrt{F}}{\sqrt{B \cdot 0.5}} \]
                                                                            3. Add Preprocessing

                                                                            Alternative 16: 35.7% accurate, 12.6× speedup?

                                                                            \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}} \end{array} \]
                                                                            B_m = (fabs.f64 B)
                                                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                            (FPCore (A B_m C F) :precision binary64 (* (- (sqrt F)) (sqrt (/ 2.0 B_m))))
                                                                            B_m = fabs(B);
                                                                            assert(A < B_m && B_m < C && C < F);
                                                                            double code(double A, double B_m, double C, double F) {
                                                                            	return -sqrt(F) * sqrt((2.0 / B_m));
                                                                            }
                                                                            
                                                                            B_m = abs(b)
                                                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                            real(8) function code(a, b_m, c, f)
                                                                                real(8), intent (in) :: a
                                                                                real(8), intent (in) :: b_m
                                                                                real(8), intent (in) :: c
                                                                                real(8), intent (in) :: f
                                                                                code = -sqrt(f) * sqrt((2.0d0 / b_m))
                                                                            end function
                                                                            
                                                                            B_m = Math.abs(B);
                                                                            assert A < B_m && B_m < C && C < F;
                                                                            public static double code(double A, double B_m, double C, double F) {
                                                                            	return -Math.sqrt(F) * Math.sqrt((2.0 / B_m));
                                                                            }
                                                                            
                                                                            B_m = math.fabs(B)
                                                                            [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                            def code(A, B_m, C, F):
                                                                            	return -math.sqrt(F) * math.sqrt((2.0 / B_m))
                                                                            
                                                                            B_m = abs(B)
                                                                            A, B_m, C, F = sort([A, B_m, C, F])
                                                                            function code(A, B_m, C, F)
                                                                            	return Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)))
                                                                            end
                                                                            
                                                                            B_m = abs(B);
                                                                            A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                            function tmp = code(A, B_m, C, F)
                                                                            	tmp = -sqrt(F) * sqrt((2.0 / B_m));
                                                                            end
                                                                            
                                                                            B_m = N[Abs[B], $MachinePrecision]
                                                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                            code[A_, B$95$m_, C_, F_] := N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
                                                                            
                                                                            \begin{array}{l}
                                                                            B_m = \left|B\right|
                                                                            \\
                                                                            [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                            \\
                                                                            \left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}
                                                                            \end{array}
                                                                            
                                                                            Derivation
                                                                            1. Initial program 19.5%

                                                                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                            2. Add Preprocessing
                                                                            3. Taylor expanded in B around inf

                                                                              \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                            4. Step-by-step derivation
                                                                              1. mul-1-negN/A

                                                                                \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                              2. lower-neg.f64N/A

                                                                                \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                              3. lower-*.f64N/A

                                                                                \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                              4. lower-sqrt.f64N/A

                                                                                \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                              5. lower-/.f64N/A

                                                                                \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                              6. lower-sqrt.f6412.4

                                                                                \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                                            5. Applied rewrites12.4%

                                                                              \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                            6. Step-by-step derivation
                                                                              1. Applied rewrites16.1%

                                                                                \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
                                                                              2. Step-by-step derivation
                                                                                1. Applied rewrites16.1%

                                                                                  \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                                                                2. Final simplification16.1%

                                                                                  \[\leadsto \left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}} \]
                                                                                3. Add Preprocessing

                                                                                Alternative 17: 27.4% accurate, 16.9× speedup?

                                                                                \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ -\sqrt{\frac{F}{B\_m} \cdot 2} \end{array} \]
                                                                                B_m = (fabs.f64 B)
                                                                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                (FPCore (A B_m C F) :precision binary64 (- (sqrt (* (/ F B_m) 2.0))))
                                                                                B_m = fabs(B);
                                                                                assert(A < B_m && B_m < C && C < F);
                                                                                double code(double A, double B_m, double C, double F) {
                                                                                	return -sqrt(((F / B_m) * 2.0));
                                                                                }
                                                                                
                                                                                B_m = abs(b)
                                                                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                real(8) function code(a, b_m, c, f)
                                                                                    real(8), intent (in) :: a
                                                                                    real(8), intent (in) :: b_m
                                                                                    real(8), intent (in) :: c
                                                                                    real(8), intent (in) :: f
                                                                                    code = -sqrt(((f / b_m) * 2.0d0))
                                                                                end function
                                                                                
                                                                                B_m = Math.abs(B);
                                                                                assert A < B_m && B_m < C && C < F;
                                                                                public static double code(double A, double B_m, double C, double F) {
                                                                                	return -Math.sqrt(((F / B_m) * 2.0));
                                                                                }
                                                                                
                                                                                B_m = math.fabs(B)
                                                                                [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                                def code(A, B_m, C, F):
                                                                                	return -math.sqrt(((F / B_m) * 2.0))
                                                                                
                                                                                B_m = abs(B)
                                                                                A, B_m, C, F = sort([A, B_m, C, F])
                                                                                function code(A, B_m, C, F)
                                                                                	return Float64(-sqrt(Float64(Float64(F / B_m) * 2.0)))
                                                                                end
                                                                                
                                                                                B_m = abs(B);
                                                                                A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                                function tmp = code(A, B_m, C, F)
                                                                                	tmp = -sqrt(((F / B_m) * 2.0));
                                                                                end
                                                                                
                                                                                B_m = N[Abs[B], $MachinePrecision]
                                                                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                code[A_, B$95$m_, C_, F_] := (-N[Sqrt[N[(N[(F / B$95$m), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision])
                                                                                
                                                                                \begin{array}{l}
                                                                                B_m = \left|B\right|
                                                                                \\
                                                                                [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                                \\
                                                                                -\sqrt{\frac{F}{B\_m} \cdot 2}
                                                                                \end{array}
                                                                                
                                                                                Derivation
                                                                                1. Initial program 19.5%

                                                                                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                2. Add Preprocessing
                                                                                3. Taylor expanded in B around inf

                                                                                  \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                4. Step-by-step derivation
                                                                                  1. mul-1-negN/A

                                                                                    \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                  2. lower-neg.f64N/A

                                                                                    \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                  3. lower-*.f64N/A

                                                                                    \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                  4. lower-sqrt.f64N/A

                                                                                    \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                                  5. lower-/.f64N/A

                                                                                    \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                                  6. lower-sqrt.f6412.4

                                                                                    \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                                                5. Applied rewrites12.4%

                                                                                  \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                6. Step-by-step derivation
                                                                                  1. Applied rewrites12.5%

                                                                                    \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                                  2. Add Preprocessing

                                                                                  Alternative 18: 27.4% accurate, 16.9× speedup?

                                                                                  \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ -\sqrt{F \cdot \frac{2}{B\_m}} \end{array} \]
                                                                                  B_m = (fabs.f64 B)
                                                                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                  (FPCore (A B_m C F) :precision binary64 (- (sqrt (* F (/ 2.0 B_m)))))
                                                                                  B_m = fabs(B);
                                                                                  assert(A < B_m && B_m < C && C < F);
                                                                                  double code(double A, double B_m, double C, double F) {
                                                                                  	return -sqrt((F * (2.0 / B_m)));
                                                                                  }
                                                                                  
                                                                                  B_m = abs(b)
                                                                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                  real(8) function code(a, b_m, c, f)
                                                                                      real(8), intent (in) :: a
                                                                                      real(8), intent (in) :: b_m
                                                                                      real(8), intent (in) :: c
                                                                                      real(8), intent (in) :: f
                                                                                      code = -sqrt((f * (2.0d0 / b_m)))
                                                                                  end function
                                                                                  
                                                                                  B_m = Math.abs(B);
                                                                                  assert A < B_m && B_m < C && C < F;
                                                                                  public static double code(double A, double B_m, double C, double F) {
                                                                                  	return -Math.sqrt((F * (2.0 / B_m)));
                                                                                  }
                                                                                  
                                                                                  B_m = math.fabs(B)
                                                                                  [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                                  def code(A, B_m, C, F):
                                                                                  	return -math.sqrt((F * (2.0 / B_m)))
                                                                                  
                                                                                  B_m = abs(B)
                                                                                  A, B_m, C, F = sort([A, B_m, C, F])
                                                                                  function code(A, B_m, C, F)
                                                                                  	return Float64(-sqrt(Float64(F * Float64(2.0 / B_m))))
                                                                                  end
                                                                                  
                                                                                  B_m = abs(B);
                                                                                  A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                                  function tmp = code(A, B_m, C, F)
                                                                                  	tmp = -sqrt((F * (2.0 / B_m)));
                                                                                  end
                                                                                  
                                                                                  B_m = N[Abs[B], $MachinePrecision]
                                                                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                  code[A_, B$95$m_, C_, F_] := (-N[Sqrt[N[(F * N[(2.0 / B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision])
                                                                                  
                                                                                  \begin{array}{l}
                                                                                  B_m = \left|B\right|
                                                                                  \\
                                                                                  [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                                  \\
                                                                                  -\sqrt{F \cdot \frac{2}{B\_m}}
                                                                                  \end{array}
                                                                                  
                                                                                  Derivation
                                                                                  1. Initial program 19.5%

                                                                                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                  2. Add Preprocessing
                                                                                  3. Taylor expanded in B around inf

                                                                                    \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                  4. Step-by-step derivation
                                                                                    1. mul-1-negN/A

                                                                                      \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                    2. lower-neg.f64N/A

                                                                                      \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                    3. lower-*.f64N/A

                                                                                      \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                    4. lower-sqrt.f64N/A

                                                                                      \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                                    5. lower-/.f64N/A

                                                                                      \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                                    6. lower-sqrt.f6412.4

                                                                                      \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                                                  5. Applied rewrites12.4%

                                                                                    \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                  6. Step-by-step derivation
                                                                                    1. Applied rewrites12.5%

                                                                                      \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                                    2. Step-by-step derivation
                                                                                      1. Applied rewrites12.5%

                                                                                        \[\leadsto -\sqrt{F \cdot \frac{2}{B}} \]
                                                                                      2. Add Preprocessing

                                                                                      Reproduce

                                                                                      ?
                                                                                      herbie shell --seed 2024342 
                                                                                      (FPCore (A B C F)
                                                                                        :name "ABCF->ab-angle a"
                                                                                        :precision binary64
                                                                                        (/ (- (sqrt (* (* 2.0 (* (- (pow B 2.0) (* (* 4.0 A) C)) F)) (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))) (- (pow B 2.0) (* (* 4.0 A) C))))