2cbrt (problem 3.3.4)

Percentage Accurate: 6.8% → 99.0%
Time: 7.9s
Alternatives: 6
Speedup: 1.9×

Specification

?
\[x > 1 \land x < 10^{+308}\]
\[\begin{array}{l} \\ \sqrt[3]{x + 1} - \sqrt[3]{x} \end{array} \]
(FPCore (x) :precision binary64 (- (cbrt (+ x 1.0)) (cbrt x)))
double code(double x) {
	return cbrt((x + 1.0)) - cbrt(x);
}
public static double code(double x) {
	return Math.cbrt((x + 1.0)) - Math.cbrt(x);
}
function code(x)
	return Float64(cbrt(Float64(x + 1.0)) - cbrt(x))
end
code[x_] := N[(N[Power[N[(x + 1.0), $MachinePrecision], 1/3], $MachinePrecision] - N[Power[x, 1/3], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\sqrt[3]{x + 1} - \sqrt[3]{x}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 6 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 6.8% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \sqrt[3]{x + 1} - \sqrt[3]{x} \end{array} \]
(FPCore (x) :precision binary64 (- (cbrt (+ x 1.0)) (cbrt x)))
double code(double x) {
	return cbrt((x + 1.0)) - cbrt(x);
}
public static double code(double x) {
	return Math.cbrt((x + 1.0)) - Math.cbrt(x);
}
function code(x)
	return Float64(cbrt(Float64(x + 1.0)) - cbrt(x))
end
code[x_] := N[(N[Power[N[(x + 1.0), $MachinePrecision], 1/3], $MachinePrecision] - N[Power[x, 1/3], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\sqrt[3]{x + 1} - \sqrt[3]{x}
\end{array}

Alternative 1: 99.0% accurate, 0.3× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\sqrt[3]{x + 1} - \sqrt[3]{x} \leq 0:\\ \;\;\;\;\frac{0.3333333333333333 \cdot \sqrt[3]{x}}{x}\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(1 + x\right) - x}{\mathsf{fma}\left(\sqrt[3]{x}, \sqrt[3]{1 + x} + \sqrt[3]{x}, e^{\mathsf{log1p}\left(x\right) \cdot 0.6666666666666666}\right)}\\ \end{array} \end{array} \]
(FPCore (x)
 :precision binary64
 (if (<= (- (cbrt (+ x 1.0)) (cbrt x)) 0.0)
   (/ (* 0.3333333333333333 (cbrt x)) x)
   (/
    (- (+ 1.0 x) x)
    (fma
     (cbrt x)
     (+ (cbrt (+ 1.0 x)) (cbrt x))
     (exp (* (log1p x) 0.6666666666666666))))))
double code(double x) {
	double tmp;
	if ((cbrt((x + 1.0)) - cbrt(x)) <= 0.0) {
		tmp = (0.3333333333333333 * cbrt(x)) / x;
	} else {
		tmp = ((1.0 + x) - x) / fma(cbrt(x), (cbrt((1.0 + x)) + cbrt(x)), exp((log1p(x) * 0.6666666666666666)));
	}
	return tmp;
}
function code(x)
	tmp = 0.0
	if (Float64(cbrt(Float64(x + 1.0)) - cbrt(x)) <= 0.0)
		tmp = Float64(Float64(0.3333333333333333 * cbrt(x)) / x);
	else
		tmp = Float64(Float64(Float64(1.0 + x) - x) / fma(cbrt(x), Float64(cbrt(Float64(1.0 + x)) + cbrt(x)), exp(Float64(log1p(x) * 0.6666666666666666))));
	end
	return tmp
end
code[x_] := If[LessEqual[N[(N[Power[N[(x + 1.0), $MachinePrecision], 1/3], $MachinePrecision] - N[Power[x, 1/3], $MachinePrecision]), $MachinePrecision], 0.0], N[(N[(0.3333333333333333 * N[Power[x, 1/3], $MachinePrecision]), $MachinePrecision] / x), $MachinePrecision], N[(N[(N[(1.0 + x), $MachinePrecision] - x), $MachinePrecision] / N[(N[Power[x, 1/3], $MachinePrecision] * N[(N[Power[N[(1.0 + x), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[x, 1/3], $MachinePrecision]), $MachinePrecision] + N[Exp[N[(N[Log[1 + x], $MachinePrecision] * 0.6666666666666666), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;\sqrt[3]{x + 1} - \sqrt[3]{x} \leq 0:\\
\;\;\;\;\frac{0.3333333333333333 \cdot \sqrt[3]{x}}{x}\\

\mathbf{else}:\\
\;\;\;\;\frac{\left(1 + x\right) - x}{\mathsf{fma}\left(\sqrt[3]{x}, \sqrt[3]{1 + x} + \sqrt[3]{x}, e^{\mathsf{log1p}\left(x\right) \cdot 0.6666666666666666}\right)}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (-.f64 (cbrt.f64 (+.f64 x #s(literal 1 binary64))) (cbrt.f64 x)) < 0.0

    1. Initial program 4.2%

      \[\sqrt[3]{x + 1} - \sqrt[3]{x} \]
    2. Add Preprocessing
    3. Taylor expanded in x around inf

      \[\leadsto \color{blue}{\frac{\frac{-1}{9} \cdot \sqrt[3]{x} + \left(\frac{5}{81} \cdot \sqrt[3]{\frac{1}{{x}^{2}}} + \frac{1}{3} \cdot \sqrt[3]{{x}^{4}}\right)}{{x}^{2}}} \]
    4. Step-by-step derivation
      1. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{\frac{-1}{9} \cdot \sqrt[3]{x} + \left(\frac{5}{81} \cdot \sqrt[3]{\frac{1}{{x}^{2}}} + \frac{1}{3} \cdot \sqrt[3]{{x}^{4}}\right)}{{x}^{2}}} \]
    5. Applied rewrites22.5%

      \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(\sqrt[3]{{x}^{4}}, 0.3333333333333333, \mathsf{fma}\left(\sqrt[3]{\frac{\frac{1}{x}}{x}}, 0.06172839506172839, -0.1111111111111111 \cdot \sqrt[3]{x}\right)\right)}{x \cdot x}} \]
    6. Applied rewrites73.1%

      \[\leadsto \frac{\frac{\mathsf{fma}\left(0.06172839506172839, {\left(\sqrt[3]{x}\right)}^{-2}, \mathsf{fma}\left(-0.1111111111111111, \sqrt[3]{x}, \left(\sqrt[3]{x} \cdot x\right) \cdot 0.3333333333333333\right)\right)}{x}}{\color{blue}{x}} \]
    7. Taylor expanded in x around inf

      \[\leadsto \frac{\frac{1}{3} \cdot \sqrt[3]{x}}{x} \]
    8. Step-by-step derivation
      1. Applied rewrites99.1%

        \[\leadsto \frac{0.3333333333333333 \cdot \sqrt[3]{x}}{x} \]

      if 0.0 < (-.f64 (cbrt.f64 (+.f64 x #s(literal 1 binary64))) (cbrt.f64 x))

      1. Initial program 55.9%

        \[\sqrt[3]{x + 1} - \sqrt[3]{x} \]
      2. Add Preprocessing
      3. Step-by-step derivation
        1. lift-+.f64N/A

          \[\leadsto \sqrt[3]{\color{blue}{x + 1}} - \sqrt[3]{x} \]
        2. rem-cube-cbrtN/A

          \[\leadsto \sqrt[3]{\color{blue}{{\left(\sqrt[3]{x}\right)}^{3}} + 1} - \sqrt[3]{x} \]
        3. lift-cbrt.f64N/A

          \[\leadsto \sqrt[3]{{\color{blue}{\left(\sqrt[3]{x}\right)}}^{3} + 1} - \sqrt[3]{x} \]
        4. sqr-powN/A

          \[\leadsto \sqrt[3]{\color{blue}{{\left(\sqrt[3]{x}\right)}^{\left(\frac{3}{2}\right)} \cdot {\left(\sqrt[3]{x}\right)}^{\left(\frac{3}{2}\right)}} + 1} - \sqrt[3]{x} \]
        5. lower-fma.f64N/A

          \[\leadsto \sqrt[3]{\color{blue}{\mathsf{fma}\left({\left(\sqrt[3]{x}\right)}^{\left(\frac{3}{2}\right)}, {\left(\sqrt[3]{x}\right)}^{\left(\frac{3}{2}\right)}, 1\right)}} - \sqrt[3]{x} \]
        6. lift-cbrt.f64N/A

          \[\leadsto \sqrt[3]{\mathsf{fma}\left({\color{blue}{\left(\sqrt[3]{x}\right)}}^{\left(\frac{3}{2}\right)}, {\left(\sqrt[3]{x}\right)}^{\left(\frac{3}{2}\right)}, 1\right)} - \sqrt[3]{x} \]
        7. pow1/3N/A

          \[\leadsto \sqrt[3]{\mathsf{fma}\left({\color{blue}{\left({x}^{\frac{1}{3}}\right)}}^{\left(\frac{3}{2}\right)}, {\left(\sqrt[3]{x}\right)}^{\left(\frac{3}{2}\right)}, 1\right)} - \sqrt[3]{x} \]
        8. pow-powN/A

          \[\leadsto \sqrt[3]{\mathsf{fma}\left(\color{blue}{{x}^{\left(\frac{1}{3} \cdot \frac{3}{2}\right)}}, {\left(\sqrt[3]{x}\right)}^{\left(\frac{3}{2}\right)}, 1\right)} - \sqrt[3]{x} \]
        9. metadata-evalN/A

          \[\leadsto \sqrt[3]{\mathsf{fma}\left({x}^{\left(\frac{1}{3} \cdot \color{blue}{\frac{3}{2}}\right)}, {\left(\sqrt[3]{x}\right)}^{\left(\frac{3}{2}\right)}, 1\right)} - \sqrt[3]{x} \]
        10. metadata-evalN/A

          \[\leadsto \sqrt[3]{\mathsf{fma}\left({x}^{\color{blue}{\frac{1}{2}}}, {\left(\sqrt[3]{x}\right)}^{\left(\frac{3}{2}\right)}, 1\right)} - \sqrt[3]{x} \]
        11. unpow1/2N/A

          \[\leadsto \sqrt[3]{\mathsf{fma}\left(\color{blue}{\sqrt{x}}, {\left(\sqrt[3]{x}\right)}^{\left(\frac{3}{2}\right)}, 1\right)} - \sqrt[3]{x} \]
        12. lower-sqrt.f64N/A

          \[\leadsto \sqrt[3]{\mathsf{fma}\left(\color{blue}{\sqrt{x}}, {\left(\sqrt[3]{x}\right)}^{\left(\frac{3}{2}\right)}, 1\right)} - \sqrt[3]{x} \]
        13. lift-cbrt.f64N/A

          \[\leadsto \sqrt[3]{\mathsf{fma}\left(\sqrt{x}, {\color{blue}{\left(\sqrt[3]{x}\right)}}^{\left(\frac{3}{2}\right)}, 1\right)} - \sqrt[3]{x} \]
        14. pow1/3N/A

          \[\leadsto \sqrt[3]{\mathsf{fma}\left(\sqrt{x}, {\color{blue}{\left({x}^{\frac{1}{3}}\right)}}^{\left(\frac{3}{2}\right)}, 1\right)} - \sqrt[3]{x} \]
        15. pow-powN/A

          \[\leadsto \sqrt[3]{\mathsf{fma}\left(\sqrt{x}, \color{blue}{{x}^{\left(\frac{1}{3} \cdot \frac{3}{2}\right)}}, 1\right)} - \sqrt[3]{x} \]
        16. metadata-evalN/A

          \[\leadsto \sqrt[3]{\mathsf{fma}\left(\sqrt{x}, {x}^{\left(\frac{1}{3} \cdot \color{blue}{\frac{3}{2}}\right)}, 1\right)} - \sqrt[3]{x} \]
        17. metadata-evalN/A

          \[\leadsto \sqrt[3]{\mathsf{fma}\left(\sqrt{x}, {x}^{\color{blue}{\frac{1}{2}}}, 1\right)} - \sqrt[3]{x} \]
        18. unpow1/2N/A

          \[\leadsto \sqrt[3]{\mathsf{fma}\left(\sqrt{x}, \color{blue}{\sqrt{x}}, 1\right)} - \sqrt[3]{x} \]
        19. lower-sqrt.f6454.6

          \[\leadsto \sqrt[3]{\mathsf{fma}\left(\sqrt{x}, \color{blue}{\sqrt{x}}, 1\right)} - \sqrt[3]{x} \]
      4. Applied rewrites54.6%

        \[\leadsto \sqrt[3]{\color{blue}{\mathsf{fma}\left(\sqrt{x}, \sqrt{x}, 1\right)}} - \sqrt[3]{x} \]
      5. Applied rewrites98.0%

        \[\leadsto \color{blue}{\frac{\left(1 + x\right) - x}{\mathsf{fma}\left(\sqrt[3]{x}, \sqrt[3]{1 + x} + \sqrt[3]{x}, e^{\mathsf{log1p}\left(x\right) \cdot 0.6666666666666666}\right)}} \]
    9. Recombined 2 regimes into one program.
    10. Add Preprocessing

    Alternative 2: 98.5% accurate, 0.5× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 2.5 \cdot 10^{+17}:\\ \;\;\;\;{\left(\mathsf{fma}\left(\sqrt[3]{x \cdot x}, 3 - \frac{0.2222222222222222}{x \cdot x}, \sqrt[3]{{x}^{-1}}\right)\right)}^{-1}\\ \mathbf{else}:\\ \;\;\;\;\frac{0.3333333333333333 \cdot \sqrt[3]{x}}{x}\\ \end{array} \end{array} \]
    (FPCore (x)
     :precision binary64
     (if (<= x 2.5e+17)
       (pow
        (fma
         (cbrt (* x x))
         (- 3.0 (/ 0.2222222222222222 (* x x)))
         (cbrt (pow x -1.0)))
        -1.0)
       (/ (* 0.3333333333333333 (cbrt x)) x)))
    double code(double x) {
    	double tmp;
    	if (x <= 2.5e+17) {
    		tmp = pow(fma(cbrt((x * x)), (3.0 - (0.2222222222222222 / (x * x))), cbrt(pow(x, -1.0))), -1.0);
    	} else {
    		tmp = (0.3333333333333333 * cbrt(x)) / x;
    	}
    	return tmp;
    }
    
    function code(x)
    	tmp = 0.0
    	if (x <= 2.5e+17)
    		tmp = fma(cbrt(Float64(x * x)), Float64(3.0 - Float64(0.2222222222222222 / Float64(x * x))), cbrt((x ^ -1.0))) ^ -1.0;
    	else
    		tmp = Float64(Float64(0.3333333333333333 * cbrt(x)) / x);
    	end
    	return tmp
    end
    
    code[x_] := If[LessEqual[x, 2.5e+17], N[Power[N[(N[Power[N[(x * x), $MachinePrecision], 1/3], $MachinePrecision] * N[(3.0 - N[(0.2222222222222222 / N[(x * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[Power[N[Power[x, -1.0], $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision], -1.0], $MachinePrecision], N[(N[(0.3333333333333333 * N[Power[x, 1/3], $MachinePrecision]), $MachinePrecision] / x), $MachinePrecision]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;x \leq 2.5 \cdot 10^{+17}:\\
    \;\;\;\;{\left(\mathsf{fma}\left(\sqrt[3]{x \cdot x}, 3 - \frac{0.2222222222222222}{x \cdot x}, \sqrt[3]{{x}^{-1}}\right)\right)}^{-1}\\
    
    \mathbf{else}:\\
    \;\;\;\;\frac{0.3333333333333333 \cdot \sqrt[3]{x}}{x}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 2 regimes
    2. if x < 2.5e17

      1. Initial program 50.0%

        \[\sqrt[3]{x + 1} - \sqrt[3]{x} \]
      2. Add Preprocessing
      3. Taylor expanded in x around inf

        \[\leadsto \color{blue}{\frac{\frac{-1}{9} \cdot \sqrt[3]{x} + \left(\frac{5}{81} \cdot \sqrt[3]{\frac{1}{{x}^{2}}} + \frac{1}{3} \cdot \sqrt[3]{{x}^{4}}\right)}{{x}^{2}}} \]
      4. Step-by-step derivation
        1. lower-/.f64N/A

          \[\leadsto \color{blue}{\frac{\frac{-1}{9} \cdot \sqrt[3]{x} + \left(\frac{5}{81} \cdot \sqrt[3]{\frac{1}{{x}^{2}}} + \frac{1}{3} \cdot \sqrt[3]{{x}^{4}}\right)}{{x}^{2}}} \]
      5. Applied rewrites93.4%

        \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(\sqrt[3]{{x}^{4}}, 0.3333333333333333, \mathsf{fma}\left(\sqrt[3]{\frac{\frac{1}{x}}{x}}, 0.06172839506172839, -0.1111111111111111 \cdot \sqrt[3]{x}\right)\right)}{x \cdot x}} \]
      6. Taylor expanded in x around inf

        \[\leadsto \frac{\frac{1}{3} \cdot \sqrt[3]{{x}^{4}}}{\color{blue}{x} \cdot x} \]
      7. Step-by-step derivation
        1. Applied rewrites68.8%

          \[\leadsto \frac{\sqrt[3]{{x}^{4}} \cdot 0.3333333333333333}{\color{blue}{x} \cdot x} \]
        2. Step-by-step derivation
          1. Applied rewrites68.9%

            \[\leadsto \frac{1}{\color{blue}{\frac{x}{\frac{\left(0.3333333333333333 \cdot \sqrt[3]{x}\right) \cdot x}{x}}}} \]
          2. Taylor expanded in x around inf

            \[\leadsto \frac{1}{\left(-1 \cdot \frac{\frac{-1}{3} \cdot \sqrt[3]{{x}^{2}} + \frac{5}{9} \cdot \sqrt[3]{{x}^{2}}}{{x}^{2}} + 3 \cdot \sqrt[3]{{x}^{2}}\right) - \color{blue}{-1 \cdot \sqrt[3]{\frac{1}{x}}}} \]
          3. Step-by-step derivation
            1. Applied rewrites94.1%

              \[\leadsto \frac{1}{\mathsf{fma}\left(\sqrt[3]{x \cdot x}, \color{blue}{3 - \frac{0.2222222222222222}{x \cdot x}}, \sqrt[3]{\frac{1}{x}}\right)} \]

            if 2.5e17 < x

            1. Initial program 4.2%

              \[\sqrt[3]{x + 1} - \sqrt[3]{x} \]
            2. Add Preprocessing
            3. Taylor expanded in x around inf

              \[\leadsto \color{blue}{\frac{\frac{-1}{9} \cdot \sqrt[3]{x} + \left(\frac{5}{81} \cdot \sqrt[3]{\frac{1}{{x}^{2}}} + \frac{1}{3} \cdot \sqrt[3]{{x}^{4}}\right)}{{x}^{2}}} \]
            4. Step-by-step derivation
              1. lower-/.f64N/A

                \[\leadsto \color{blue}{\frac{\frac{-1}{9} \cdot \sqrt[3]{x} + \left(\frac{5}{81} \cdot \sqrt[3]{\frac{1}{{x}^{2}}} + \frac{1}{3} \cdot \sqrt[3]{{x}^{4}}\right)}{{x}^{2}}} \]
            5. Applied rewrites21.9%

              \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(\sqrt[3]{{x}^{4}}, 0.3333333333333333, \mathsf{fma}\left(\sqrt[3]{\frac{\frac{1}{x}}{x}}, 0.06172839506172839, -0.1111111111111111 \cdot \sqrt[3]{x}\right)\right)}{x \cdot x}} \]
            6. Applied rewrites72.9%

              \[\leadsto \frac{\frac{\mathsf{fma}\left(0.06172839506172839, {\left(\sqrt[3]{x}\right)}^{-2}, \mathsf{fma}\left(-0.1111111111111111, \sqrt[3]{x}, \left(\sqrt[3]{x} \cdot x\right) \cdot 0.3333333333333333\right)\right)}{x}}{\color{blue}{x}} \]
            7. Taylor expanded in x around inf

              \[\leadsto \frac{\frac{1}{3} \cdot \sqrt[3]{x}}{x} \]
            8. Step-by-step derivation
              1. Applied rewrites99.1%

                \[\leadsto \frac{0.3333333333333333 \cdot \sqrt[3]{x}}{x} \]
            9. Recombined 2 regimes into one program.
            10. Final simplification98.8%

              \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq 2.5 \cdot 10^{+17}:\\ \;\;\;\;{\left(\mathsf{fma}\left(\sqrt[3]{x \cdot x}, 3 - \frac{0.2222222222222222}{x \cdot x}, \sqrt[3]{{x}^{-1}}\right)\right)}^{-1}\\ \mathbf{else}:\\ \;\;\;\;\frac{0.3333333333333333 \cdot \sqrt[3]{x}}{x}\\ \end{array} \]
            11. Add Preprocessing

            Alternative 3: 97.2% accurate, 1.8× speedup?

            \[\begin{array}{l} \\ \frac{0.3333333333333333 \cdot \sqrt[3]{x}}{x} \end{array} \]
            (FPCore (x) :precision binary64 (/ (* 0.3333333333333333 (cbrt x)) x))
            double code(double x) {
            	return (0.3333333333333333 * cbrt(x)) / x;
            }
            
            public static double code(double x) {
            	return (0.3333333333333333 * Math.cbrt(x)) / x;
            }
            
            function code(x)
            	return Float64(Float64(0.3333333333333333 * cbrt(x)) / x)
            end
            
            code[x_] := N[(N[(0.3333333333333333 * N[Power[x, 1/3], $MachinePrecision]), $MachinePrecision] / x), $MachinePrecision]
            
            \begin{array}{l}
            
            \\
            \frac{0.3333333333333333 \cdot \sqrt[3]{x}}{x}
            \end{array}
            
            Derivation
            1. Initial program 7.4%

              \[\sqrt[3]{x + 1} - \sqrt[3]{x} \]
            2. Add Preprocessing
            3. Taylor expanded in x around inf

              \[\leadsto \color{blue}{\frac{\frac{-1}{9} \cdot \sqrt[3]{x} + \left(\frac{5}{81} \cdot \sqrt[3]{\frac{1}{{x}^{2}}} + \frac{1}{3} \cdot \sqrt[3]{{x}^{4}}\right)}{{x}^{2}}} \]
            4. Step-by-step derivation
              1. lower-/.f64N/A

                \[\leadsto \color{blue}{\frac{\frac{-1}{9} \cdot \sqrt[3]{x} + \left(\frac{5}{81} \cdot \sqrt[3]{\frac{1}{{x}^{2}}} + \frac{1}{3} \cdot \sqrt[3]{{x}^{4}}\right)}{{x}^{2}}} \]
            5. Applied rewrites26.9%

              \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(\sqrt[3]{{x}^{4}}, 0.3333333333333333, \mathsf{fma}\left(\sqrt[3]{\frac{\frac{1}{x}}{x}}, 0.06172839506172839, -0.1111111111111111 \cdot \sqrt[3]{x}\right)\right)}{x \cdot x}} \]
            6. Applied rewrites74.4%

              \[\leadsto \frac{\frac{\mathsf{fma}\left(0.06172839506172839, {\left(\sqrt[3]{x}\right)}^{-2}, \mathsf{fma}\left(-0.1111111111111111, \sqrt[3]{x}, \left(\sqrt[3]{x} \cdot x\right) \cdot 0.3333333333333333\right)\right)}{x}}{\color{blue}{x}} \]
            7. Taylor expanded in x around inf

              \[\leadsto \frac{\frac{1}{3} \cdot \sqrt[3]{x}}{x} \]
            8. Step-by-step derivation
              1. Applied rewrites97.0%

                \[\leadsto \frac{0.3333333333333333 \cdot \sqrt[3]{x}}{x} \]
              2. Add Preprocessing

              Alternative 4: 88.9% accurate, 1.9× speedup?

              \[\begin{array}{l} \\ {x}^{-0.6666666666666666} \cdot 0.3333333333333333 \end{array} \]
              (FPCore (x)
               :precision binary64
               (* (pow x -0.6666666666666666) 0.3333333333333333))
              double code(double x) {
              	return pow(x, -0.6666666666666666) * 0.3333333333333333;
              }
              
              real(8) function code(x)
                  real(8), intent (in) :: x
                  code = (x ** (-0.6666666666666666d0)) * 0.3333333333333333d0
              end function
              
              public static double code(double x) {
              	return Math.pow(x, -0.6666666666666666) * 0.3333333333333333;
              }
              
              def code(x):
              	return math.pow(x, -0.6666666666666666) * 0.3333333333333333
              
              function code(x)
              	return Float64((x ^ -0.6666666666666666) * 0.3333333333333333)
              end
              
              function tmp = code(x)
              	tmp = (x ^ -0.6666666666666666) * 0.3333333333333333;
              end
              
              code[x_] := N[(N[Power[x, -0.6666666666666666], $MachinePrecision] * 0.3333333333333333), $MachinePrecision]
              
              \begin{array}{l}
              
              \\
              {x}^{-0.6666666666666666} \cdot 0.3333333333333333
              \end{array}
              
              Derivation
              1. Initial program 7.4%

                \[\sqrt[3]{x + 1} - \sqrt[3]{x} \]
              2. Add Preprocessing
              3. Taylor expanded in x around inf

                \[\leadsto \color{blue}{\frac{1}{3} \cdot \sqrt[3]{\frac{1}{{x}^{2}}}} \]
              4. Step-by-step derivation
                1. *-commutativeN/A

                  \[\leadsto \color{blue}{\sqrt[3]{\frac{1}{{x}^{2}}} \cdot \frac{1}{3}} \]
                2. lower-*.f64N/A

                  \[\leadsto \color{blue}{\sqrt[3]{\frac{1}{{x}^{2}}} \cdot \frac{1}{3}} \]
                3. metadata-evalN/A

                  \[\leadsto \sqrt[3]{\frac{\color{blue}{-1 \cdot -1}}{{x}^{2}}} \cdot \frac{1}{3} \]
                4. associate-*r/N/A

                  \[\leadsto \sqrt[3]{\color{blue}{-1 \cdot \frac{-1}{{x}^{2}}}} \cdot \frac{1}{3} \]
                5. lower-cbrt.f64N/A

                  \[\leadsto \color{blue}{\sqrt[3]{-1 \cdot \frac{-1}{{x}^{2}}}} \cdot \frac{1}{3} \]
                6. unpow2N/A

                  \[\leadsto \sqrt[3]{-1 \cdot \frac{-1}{\color{blue}{x \cdot x}}} \cdot \frac{1}{3} \]
                7. associate-/r*N/A

                  \[\leadsto \sqrt[3]{-1 \cdot \color{blue}{\frac{\frac{-1}{x}}{x}}} \cdot \frac{1}{3} \]
                8. associate-*r/N/A

                  \[\leadsto \sqrt[3]{\color{blue}{\frac{-1 \cdot \frac{-1}{x}}{x}}} \cdot \frac{1}{3} \]
                9. lower-/.f64N/A

                  \[\leadsto \sqrt[3]{\color{blue}{\frac{-1 \cdot \frac{-1}{x}}{x}}} \cdot \frac{1}{3} \]
                10. associate-*r/N/A

                  \[\leadsto \sqrt[3]{\frac{\color{blue}{\frac{-1 \cdot -1}{x}}}{x}} \cdot \frac{1}{3} \]
                11. metadata-evalN/A

                  \[\leadsto \sqrt[3]{\frac{\frac{\color{blue}{1}}{x}}{x}} \cdot \frac{1}{3} \]
                12. lower-/.f6451.9

                  \[\leadsto \sqrt[3]{\frac{\color{blue}{\frac{1}{x}}}{x}} \cdot 0.3333333333333333 \]
              5. Applied rewrites51.9%

                \[\leadsto \color{blue}{\sqrt[3]{\frac{\frac{1}{x}}{x}} \cdot 0.3333333333333333} \]
              6. Step-by-step derivation
                1. Applied rewrites88.7%

                  \[\leadsto {x}^{-0.6666666666666666} \cdot 0.3333333333333333 \]
                2. Add Preprocessing

                Alternative 5: 5.3% accurate, 2.0× speedup?

                \[\begin{array}{l} \\ 1 - \sqrt[3]{-x} \end{array} \]
                (FPCore (x) :precision binary64 (- 1.0 (cbrt (- x))))
                double code(double x) {
                	return 1.0 - cbrt(-x);
                }
                
                public static double code(double x) {
                	return 1.0 - Math.cbrt(-x);
                }
                
                function code(x)
                	return Float64(1.0 - cbrt(Float64(-x)))
                end
                
                code[x_] := N[(1.0 - N[Power[(-x), 1/3], $MachinePrecision]), $MachinePrecision]
                
                \begin{array}{l}
                
                \\
                1 - \sqrt[3]{-x}
                \end{array}
                
                Derivation
                1. Initial program 7.4%

                  \[\sqrt[3]{x + 1} - \sqrt[3]{x} \]
                2. Add Preprocessing
                3. Taylor expanded in x around 0

                  \[\leadsto \color{blue}{1} - \sqrt[3]{x} \]
                4. Step-by-step derivation
                  1. Applied rewrites1.8%

                    \[\leadsto \color{blue}{1} - \sqrt[3]{x} \]
                  2. Step-by-step derivation
                    1. lift-cbrt.f64N/A

                      \[\leadsto 1 - \color{blue}{\sqrt[3]{x}} \]
                    2. pow1/3N/A

                      \[\leadsto 1 - \color{blue}{{x}^{\frac{1}{3}}} \]
                    3. lower-pow.f641.8

                      \[\leadsto 1 - \color{blue}{{x}^{0.3333333333333333}} \]
                  3. Applied rewrites1.8%

                    \[\leadsto 1 - \color{blue}{{x}^{0.3333333333333333}} \]
                  4. Step-by-step derivation
                    1. lift-pow.f64N/A

                      \[\leadsto 1 - \color{blue}{{x}^{\frac{1}{3}}} \]
                    2. metadata-evalN/A

                      \[\leadsto 1 - {x}^{\color{blue}{\left(2 \cdot \frac{1}{6}\right)}} \]
                    3. pow-powN/A

                      \[\leadsto 1 - \color{blue}{{\left({x}^{2}\right)}^{\frac{1}{6}}} \]
                    4. pow2N/A

                      \[\leadsto 1 - {\color{blue}{\left(x \cdot x\right)}}^{\frac{1}{6}} \]
                    5. sqr-negN/A

                      \[\leadsto 1 - {\color{blue}{\left(\left(\mathsf{neg}\left(x\right)\right) \cdot \left(\mathsf{neg}\left(x\right)\right)\right)}}^{\frac{1}{6}} \]
                    6. lift-neg.f64N/A

                      \[\leadsto 1 - {\left(\color{blue}{\left(-x\right)} \cdot \left(\mathsf{neg}\left(x\right)\right)\right)}^{\frac{1}{6}} \]
                    7. lift-neg.f64N/A

                      \[\leadsto 1 - {\left(\left(-x\right) \cdot \color{blue}{\left(-x\right)}\right)}^{\frac{1}{6}} \]
                    8. unpow-prod-downN/A

                      \[\leadsto 1 - \color{blue}{{\left(-x\right)}^{\frac{1}{6}} \cdot {\left(-x\right)}^{\frac{1}{6}}} \]
                    9. pow-prod-upN/A

                      \[\leadsto 1 - \color{blue}{{\left(-x\right)}^{\left(\frac{1}{6} + \frac{1}{6}\right)}} \]
                    10. metadata-evalN/A

                      \[\leadsto 1 - {\left(-x\right)}^{\color{blue}{\frac{1}{3}}} \]
                    11. pow1/3N/A

                      \[\leadsto 1 - \color{blue}{\sqrt[3]{-x}} \]
                    12. lift-cbrt.f645.4

                      \[\leadsto 1 - \color{blue}{\sqrt[3]{-x}} \]
                  5. Applied rewrites5.4%

                    \[\leadsto 1 - \color{blue}{\sqrt[3]{-x}} \]
                  6. Add Preprocessing

                  Alternative 6: 1.8% accurate, 2.0× speedup?

                  \[\begin{array}{l} \\ 1 - \sqrt[3]{x} \end{array} \]
                  (FPCore (x) :precision binary64 (- 1.0 (cbrt x)))
                  double code(double x) {
                  	return 1.0 - cbrt(x);
                  }
                  
                  public static double code(double x) {
                  	return 1.0 - Math.cbrt(x);
                  }
                  
                  function code(x)
                  	return Float64(1.0 - cbrt(x))
                  end
                  
                  code[x_] := N[(1.0 - N[Power[x, 1/3], $MachinePrecision]), $MachinePrecision]
                  
                  \begin{array}{l}
                  
                  \\
                  1 - \sqrt[3]{x}
                  \end{array}
                  
                  Derivation
                  1. Initial program 7.4%

                    \[\sqrt[3]{x + 1} - \sqrt[3]{x} \]
                  2. Add Preprocessing
                  3. Taylor expanded in x around 0

                    \[\leadsto \color{blue}{1} - \sqrt[3]{x} \]
                  4. Step-by-step derivation
                    1. Applied rewrites1.8%

                      \[\leadsto \color{blue}{1} - \sqrt[3]{x} \]
                    2. Add Preprocessing

                    Developer Target 1: 98.4% accurate, 0.3× speedup?

                    \[\begin{array}{l} \\ \begin{array}{l} t_0 := \sqrt[3]{x + 1}\\ \frac{1}{\left(t\_0 \cdot t\_0 + \sqrt[3]{x} \cdot t\_0\right) + \sqrt[3]{x} \cdot \sqrt[3]{x}} \end{array} \end{array} \]
                    (FPCore (x)
                     :precision binary64
                     (let* ((t_0 (cbrt (+ x 1.0))))
                       (/ 1.0 (+ (+ (* t_0 t_0) (* (cbrt x) t_0)) (* (cbrt x) (cbrt x))))))
                    double code(double x) {
                    	double t_0 = cbrt((x + 1.0));
                    	return 1.0 / (((t_0 * t_0) + (cbrt(x) * t_0)) + (cbrt(x) * cbrt(x)));
                    }
                    
                    public static double code(double x) {
                    	double t_0 = Math.cbrt((x + 1.0));
                    	return 1.0 / (((t_0 * t_0) + (Math.cbrt(x) * t_0)) + (Math.cbrt(x) * Math.cbrt(x)));
                    }
                    
                    function code(x)
                    	t_0 = cbrt(Float64(x + 1.0))
                    	return Float64(1.0 / Float64(Float64(Float64(t_0 * t_0) + Float64(cbrt(x) * t_0)) + Float64(cbrt(x) * cbrt(x))))
                    end
                    
                    code[x_] := Block[{t$95$0 = N[Power[N[(x + 1.0), $MachinePrecision], 1/3], $MachinePrecision]}, N[(1.0 / N[(N[(N[(t$95$0 * t$95$0), $MachinePrecision] + N[(N[Power[x, 1/3], $MachinePrecision] * t$95$0), $MachinePrecision]), $MachinePrecision] + N[(N[Power[x, 1/3], $MachinePrecision] * N[Power[x, 1/3], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
                    
                    \begin{array}{l}
                    
                    \\
                    \begin{array}{l}
                    t_0 := \sqrt[3]{x + 1}\\
                    \frac{1}{\left(t\_0 \cdot t\_0 + \sqrt[3]{x} \cdot t\_0\right) + \sqrt[3]{x} \cdot \sqrt[3]{x}}
                    \end{array}
                    \end{array}
                    

                    Reproduce

                    ?
                    herbie shell --seed 2024342 
                    (FPCore (x)
                      :name "2cbrt (problem 3.3.4)"
                      :precision binary64
                      :pre (and (> x 1.0) (< x 1e+308))
                    
                      :alt
                      (! :herbie-platform default (/ 1 (+ (* (cbrt (+ x 1)) (cbrt (+ x 1))) (* (cbrt x) (cbrt (+ x 1))) (* (cbrt x) (cbrt x)))))
                    
                      (- (cbrt (+ x 1.0)) (cbrt x)))