bug323 (missed optimization)

Percentage Accurate: 7.1% → 10.6%
Time: 7.0s
Alternatives: 7
Speedup: 0.9×

Specification

?
\[0 \leq x \land x \leq 0.5\]
\[\begin{array}{l} \\ \cos^{-1} \left(1 - x\right) \end{array} \]
(FPCore (x) :precision binary64 (acos (- 1.0 x)))
double code(double x) {
	return acos((1.0 - x));
}
real(8) function code(x)
    real(8), intent (in) :: x
    code = acos((1.0d0 - x))
end function
public static double code(double x) {
	return Math.acos((1.0 - x));
}
def code(x):
	return math.acos((1.0 - x))
function code(x)
	return acos(Float64(1.0 - x))
end
function tmp = code(x)
	tmp = acos((1.0 - x));
end
code[x_] := N[ArcCos[N[(1.0 - x), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\cos^{-1} \left(1 - x\right)
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 7 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 7.1% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \cos^{-1} \left(1 - x\right) \end{array} \]
(FPCore (x) :precision binary64 (acos (- 1.0 x)))
double code(double x) {
	return acos((1.0 - x));
}
real(8) function code(x)
    real(8), intent (in) :: x
    code = acos((1.0d0 - x))
end function
public static double code(double x) {
	return Math.acos((1.0 - x));
}
def code(x):
	return math.acos((1.0 - x))
function code(x)
	return acos(Float64(1.0 - x))
end
function tmp = code(x)
	tmp = acos((1.0 - x));
end
code[x_] := N[ArcCos[N[(1.0 - x), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\cos^{-1} \left(1 - x\right)
\end{array}

Alternative 1: 10.6% accurate, 0.1× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \sin^{-1} \left(1 - x\right)\\ \frac{\mathsf{fma}\left({\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}, \frac{\sqrt[3]{{\mathsf{PI}\left(\right)}^{3}}}{2}, {\sin^{-1} \left(-1 + x\right)}^{3}\right)}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, \mathsf{PI}\left(\right), t\_0\right), t\_0, \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot 0.25\right)} \end{array} \end{array} \]
(FPCore (x)
 :precision binary64
 (let* ((t_0 (asin (- 1.0 x))))
   (/
    (fma
     (pow (/ (PI) 2.0) 2.0)
     (/ (cbrt (pow (PI) 3.0)) 2.0)
     (pow (asin (+ -1.0 x)) 3.0))
    (fma (fma 0.5 (PI) t_0) t_0 (* (* (PI) (PI)) 0.25)))))
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \sin^{-1} \left(1 - x\right)\\
\frac{\mathsf{fma}\left({\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}, \frac{\sqrt[3]{{\mathsf{PI}\left(\right)}^{3}}}{2}, {\sin^{-1} \left(-1 + x\right)}^{3}\right)}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, \mathsf{PI}\left(\right), t\_0\right), t\_0, \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot 0.25\right)}
\end{array}
\end{array}
Derivation
  1. Initial program 6.4%

    \[\cos^{-1} \left(1 - x\right) \]
  2. Add Preprocessing
  3. Step-by-step derivation
    1. lift-acos.f64N/A

      \[\leadsto \color{blue}{\cos^{-1} \left(1 - x\right)} \]
    2. acos-asinN/A

      \[\leadsto \color{blue}{\frac{\mathsf{PI}\left(\right)}{2} - \sin^{-1} \left(1 - x\right)} \]
    3. flip3--N/A

      \[\leadsto \color{blue}{\frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - {\sin^{-1} \left(1 - x\right)}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} \left(1 - x\right) \cdot \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} \left(1 - x\right)\right)}} \]
    4. lower-/.f64N/A

      \[\leadsto \color{blue}{\frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - {\sin^{-1} \left(1 - x\right)}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} \left(1 - x\right) \cdot \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} \left(1 - x\right)\right)}} \]
    5. lower--.f64N/A

      \[\leadsto \frac{\color{blue}{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - {\sin^{-1} \left(1 - x\right)}^{3}}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} \left(1 - x\right) \cdot \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} \left(1 - x\right)\right)} \]
    6. lower-pow.f64N/A

      \[\leadsto \frac{\color{blue}{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3}} - {\sin^{-1} \left(1 - x\right)}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} \left(1 - x\right) \cdot \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} \left(1 - x\right)\right)} \]
    7. lower-/.f64N/A

      \[\leadsto \frac{{\color{blue}{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}}^{3} - {\sin^{-1} \left(1 - x\right)}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} \left(1 - x\right) \cdot \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} \left(1 - x\right)\right)} \]
    8. lower-PI.f64N/A

      \[\leadsto \frac{{\left(\frac{\color{blue}{\mathsf{PI}\left(\right)}}{2}\right)}^{3} - {\sin^{-1} \left(1 - x\right)}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} \left(1 - x\right) \cdot \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} \left(1 - x\right)\right)} \]
    9. lower-pow.f64N/A

      \[\leadsto \frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - \color{blue}{{\sin^{-1} \left(1 - x\right)}^{3}}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} \left(1 - x\right) \cdot \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} \left(1 - x\right)\right)} \]
    10. lower-asin.f64N/A

      \[\leadsto \frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - {\color{blue}{\sin^{-1} \left(1 - x\right)}}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} \left(1 - x\right) \cdot \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} \left(1 - x\right)\right)} \]
    11. +-commutativeN/A

      \[\leadsto \frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - {\sin^{-1} \left(1 - x\right)}^{3}}{\color{blue}{\left(\sin^{-1} \left(1 - x\right) \cdot \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} \left(1 - x\right)\right) + \frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2}}} \]
  4. Applied rewrites6.4%

    \[\leadsto \color{blue}{\frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - {\sin^{-1} \left(1 - x\right)}^{3}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)}} \]
  5. Step-by-step derivation
    1. lift--.f64N/A

      \[\leadsto \frac{\color{blue}{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - {\sin^{-1} \left(1 - x\right)}^{3}}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
    2. lift-pow.f64N/A

      \[\leadsto \frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - \color{blue}{{\sin^{-1} \left(1 - x\right)}^{3}}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
    3. cube-multN/A

      \[\leadsto \frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - \color{blue}{\sin^{-1} \left(1 - x\right) \cdot \left(\sin^{-1} \left(1 - x\right) \cdot \sin^{-1} \left(1 - x\right)\right)}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
    4. unpow2N/A

      \[\leadsto \frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - \sin^{-1} \left(1 - x\right) \cdot \color{blue}{{\sin^{-1} \left(1 - x\right)}^{2}}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
    5. lift-pow.f64N/A

      \[\leadsto \frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - \sin^{-1} \left(1 - x\right) \cdot \color{blue}{{\sin^{-1} \left(1 - x\right)}^{2}}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
    6. fp-cancel-sub-sign-invN/A

      \[\leadsto \frac{\color{blue}{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} + \left(\mathsf{neg}\left(\sin^{-1} \left(1 - x\right)\right)\right) \cdot {\sin^{-1} \left(1 - x\right)}^{2}}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
    7. lift-pow.f64N/A

      \[\leadsto \frac{\color{blue}{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3}} + \left(\mathsf{neg}\left(\sin^{-1} \left(1 - x\right)\right)\right) \cdot {\sin^{-1} \left(1 - x\right)}^{2}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
    8. unpow3N/A

      \[\leadsto \frac{\color{blue}{\left(\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2}\right) \cdot \frac{\mathsf{PI}\left(\right)}{2}} + \left(\mathsf{neg}\left(\sin^{-1} \left(1 - x\right)\right)\right) \cdot {\sin^{-1} \left(1 - x\right)}^{2}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
    9. unpow2N/A

      \[\leadsto \frac{\color{blue}{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\mathsf{neg}\left(\sin^{-1} \left(1 - x\right)\right)\right) \cdot {\sin^{-1} \left(1 - x\right)}^{2}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
    10. lift-pow.f64N/A

      \[\leadsto \frac{\color{blue}{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\mathsf{neg}\left(\sin^{-1} \left(1 - x\right)\right)\right) \cdot {\sin^{-1} \left(1 - x\right)}^{2}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
    11. lift-pow.f64N/A

      \[\leadsto \frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\mathsf{neg}\left(\sin^{-1} \left(1 - x\right)\right)\right) \cdot \color{blue}{{\sin^{-1} \left(1 - x\right)}^{2}}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
    12. unpow2N/A

      \[\leadsto \frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\mathsf{neg}\left(\sin^{-1} \left(1 - x\right)\right)\right) \cdot \color{blue}{\left(\sin^{-1} \left(1 - x\right) \cdot \sin^{-1} \left(1 - x\right)\right)}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
    13. sqr-neg-revN/A

      \[\leadsto \frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\mathsf{neg}\left(\sin^{-1} \left(1 - x\right)\right)\right) \cdot \color{blue}{\left(\left(\mathsf{neg}\left(\sin^{-1} \left(1 - x\right)\right)\right) \cdot \left(\mathsf{neg}\left(\sin^{-1} \left(1 - x\right)\right)\right)\right)}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
    14. cube-unmultN/A

      \[\leadsto \frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \color{blue}{{\left(\mathsf{neg}\left(\sin^{-1} \left(1 - x\right)\right)\right)}^{3}}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
    15. cube-neg-revN/A

      \[\leadsto \frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \color{blue}{\left(\mathsf{neg}\left({\sin^{-1} \left(1 - x\right)}^{3}\right)\right)}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
    16. lift-pow.f64N/A

      \[\leadsto \frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\mathsf{neg}\left(\color{blue}{{\sin^{-1} \left(1 - x\right)}^{3}}\right)\right)}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
  6. Applied rewrites10.2%

    \[\leadsto \frac{\color{blue}{\mathsf{fma}\left({\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}, \frac{\mathsf{PI}\left(\right)}{2}, {\sin^{-1} \left(-\left(1 - x\right)\right)}^{3}\right)}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
  7. Taylor expanded in x around 0

    \[\leadsto \frac{\mathsf{fma}\left({\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}, \frac{\mathsf{PI}\left(\right)}{2}, {\sin^{-1} \left(-\left(1 - x\right)\right)}^{3}\right)}{\color{blue}{\frac{1}{4} \cdot {\mathsf{PI}\left(\right)}^{2} + \sin^{-1} \left(1 - x\right) \cdot \left(\sin^{-1} \left(1 - x\right) + \frac{1}{2} \cdot \mathsf{PI}\left(\right)\right)}} \]
  8. Applied rewrites10.2%

    \[\leadsto \frac{\mathsf{fma}\left({\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}, \frac{\mathsf{PI}\left(\right)}{2}, {\sin^{-1} \left(-\left(1 - x\right)\right)}^{3}\right)}{\color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, \mathsf{PI}\left(\right), \sin^{-1} \left(1 - x\right)\right), \sin^{-1} \left(1 - x\right), \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot 0.25\right)}} \]
  9. Step-by-step derivation
    1. unpow1N/A

      \[\leadsto \frac{\mathsf{fma}\left({\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}, \frac{\color{blue}{{\mathsf{PI}\left(\right)}^{1}}}{2}, {\sin^{-1} \left(-\left(1 - x\right)\right)}^{3}\right)}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{2}, \mathsf{PI}\left(\right), \sin^{-1} \left(1 - x\right)\right), \sin^{-1} \left(1 - x\right), \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}\right)} \]
    2. metadata-evalN/A

      \[\leadsto \frac{\mathsf{fma}\left({\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}, \frac{{\mathsf{PI}\left(\right)}^{\color{blue}{\left(3 \cdot \frac{1}{3}\right)}}}{2}, {\sin^{-1} \left(-\left(1 - x\right)\right)}^{3}\right)}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{2}, \mathsf{PI}\left(\right), \sin^{-1} \left(1 - x\right)\right), \sin^{-1} \left(1 - x\right), \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}\right)} \]
    3. pow-powN/A

      \[\leadsto \frac{\mathsf{fma}\left({\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}, \frac{\color{blue}{{\left({\mathsf{PI}\left(\right)}^{3}\right)}^{\frac{1}{3}}}}{2}, {\sin^{-1} \left(-\left(1 - x\right)\right)}^{3}\right)}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{2}, \mathsf{PI}\left(\right), \sin^{-1} \left(1 - x\right)\right), \sin^{-1} \left(1 - x\right), \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}\right)} \]
    4. pow1/3N/A

      \[\leadsto \frac{\mathsf{fma}\left({\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}, \frac{\color{blue}{\sqrt[3]{{\mathsf{PI}\left(\right)}^{3}}}}{2}, {\sin^{-1} \left(-\left(1 - x\right)\right)}^{3}\right)}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{2}, \mathsf{PI}\left(\right), \sin^{-1} \left(1 - x\right)\right), \sin^{-1} \left(1 - x\right), \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}\right)} \]
    5. lower-cbrt.f64N/A

      \[\leadsto \frac{\mathsf{fma}\left({\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}, \frac{\color{blue}{\sqrt[3]{{\mathsf{PI}\left(\right)}^{3}}}}{2}, {\sin^{-1} \left(-\left(1 - x\right)\right)}^{3}\right)}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{2}, \mathsf{PI}\left(\right), \sin^{-1} \left(1 - x\right)\right), \sin^{-1} \left(1 - x\right), \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot \frac{1}{4}\right)} \]
    6. lower-pow.f6410.2

      \[\leadsto \frac{\mathsf{fma}\left({\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}, \frac{\sqrt[3]{\color{blue}{{\mathsf{PI}\left(\right)}^{3}}}}{2}, {\sin^{-1} \left(-\left(1 - x\right)\right)}^{3}\right)}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, \mathsf{PI}\left(\right), \sin^{-1} \left(1 - x\right)\right), \sin^{-1} \left(1 - x\right), \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot 0.25\right)} \]
  10. Applied rewrites10.2%

    \[\leadsto \frac{\mathsf{fma}\left({\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}, \frac{\color{blue}{\sqrt[3]{{\mathsf{PI}\left(\right)}^{3}}}}{2}, {\sin^{-1} \left(-\left(1 - x\right)\right)}^{3}\right)}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, \mathsf{PI}\left(\right), \sin^{-1} \left(1 - x\right)\right), \sin^{-1} \left(1 - x\right), \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot 0.25\right)} \]
  11. Final simplification10.2%

    \[\leadsto \frac{\mathsf{fma}\left({\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}, \frac{\sqrt[3]{{\mathsf{PI}\left(\right)}^{3}}}{2}, {\sin^{-1} \left(-1 + x\right)}^{3}\right)}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, \mathsf{PI}\left(\right), \sin^{-1} \left(1 - x\right)\right), \sin^{-1} \left(1 - x\right), \left(\mathsf{PI}\left(\right) \cdot \mathsf{PI}\left(\right)\right) \cdot 0.25\right)} \]
  12. Add Preprocessing

Alternative 2: 10.7% accurate, 0.3× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \sin^{-1} \left(1 - x\right)\\ \frac{-\mathsf{fma}\left(t\_0, t\_0, \left(-0.25 \cdot \mathsf{PI}\left(\right)\right) \cdot \mathsf{PI}\left(\right)\right)}{\mathsf{fma}\left(0.5, \mathsf{PI}\left(\right), t\_0\right)} \end{array} \end{array} \]
(FPCore (x)
 :precision binary64
 (let* ((t_0 (asin (- 1.0 x))))
   (/ (- (fma t_0 t_0 (* (* -0.25 (PI)) (PI)))) (fma 0.5 (PI) t_0))))
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \sin^{-1} \left(1 - x\right)\\
\frac{-\mathsf{fma}\left(t\_0, t\_0, \left(-0.25 \cdot \mathsf{PI}\left(\right)\right) \cdot \mathsf{PI}\left(\right)\right)}{\mathsf{fma}\left(0.5, \mathsf{PI}\left(\right), t\_0\right)}
\end{array}
\end{array}
Derivation
  1. Initial program 6.4%

    \[\cos^{-1} \left(1 - x\right) \]
  2. Add Preprocessing
  3. Step-by-step derivation
    1. lift-acos.f64N/A

      \[\leadsto \color{blue}{\cos^{-1} \left(1 - x\right)} \]
    2. acos-asinN/A

      \[\leadsto \color{blue}{\frac{\mathsf{PI}\left(\right)}{2} - \sin^{-1} \left(1 - x\right)} \]
    3. flip--N/A

      \[\leadsto \color{blue}{\frac{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} - \sin^{-1} \left(1 - x\right) \cdot \sin^{-1} \left(1 - x\right)}{\frac{\mathsf{PI}\left(\right)}{2} + \sin^{-1} \left(1 - x\right)}} \]
    4. div-subN/A

      \[\leadsto \color{blue}{\frac{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2}}{\frac{\mathsf{PI}\left(\right)}{2} + \sin^{-1} \left(1 - x\right)} - \frac{\sin^{-1} \left(1 - x\right) \cdot \sin^{-1} \left(1 - x\right)}{\frac{\mathsf{PI}\left(\right)}{2} + \sin^{-1} \left(1 - x\right)}} \]
    5. lower--.f64N/A

      \[\leadsto \color{blue}{\frac{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2}}{\frac{\mathsf{PI}\left(\right)}{2} + \sin^{-1} \left(1 - x\right)} - \frac{\sin^{-1} \left(1 - x\right) \cdot \sin^{-1} \left(1 - x\right)}{\frac{\mathsf{PI}\left(\right)}{2} + \sin^{-1} \left(1 - x\right)}} \]
  4. Applied rewrites6.4%

    \[\leadsto \color{blue}{\frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}}{\sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}} - \frac{{\sin^{-1} \left(1 - x\right)}^{2}}{\sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}}} \]
  5. Taylor expanded in x around 0

    \[\leadsto \color{blue}{\frac{1}{4} \cdot \frac{{\mathsf{PI}\left(\right)}^{2}}{\sin^{-1} \left(1 - x\right) + \frac{1}{2} \cdot \mathsf{PI}\left(\right)} - \frac{{\sin^{-1} \left(1 - x\right)}^{2}}{\sin^{-1} \left(1 - x\right) + \frac{1}{2} \cdot \mathsf{PI}\left(\right)}} \]
  6. Applied rewrites4.6%

    \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(-0.25 \cdot \mathsf{PI}\left(\right), \mathsf{PI}\left(\right), {\sin^{-1} \left(1 - x\right)}^{2}\right)}{-\mathsf{fma}\left(0.5, \mathsf{PI}\left(\right), \sin^{-1} \left(1 - x\right)\right)}} \]
  7. Step-by-step derivation
    1. Applied rewrites10.2%

      \[\leadsto \frac{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right), \left(-0.25 \cdot \mathsf{PI}\left(\right)\right) \cdot \mathsf{PI}\left(\right)\right)}{-\color{blue}{\mathsf{fma}\left(0.5, \mathsf{PI}\left(\right), \sin^{-1} \left(1 - x\right)\right)}} \]
    2. Final simplification10.2%

      \[\leadsto \frac{-\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right), \left(-0.25 \cdot \mathsf{PI}\left(\right)\right) \cdot \mathsf{PI}\left(\right)\right)}{\mathsf{fma}\left(0.5, \mathsf{PI}\left(\right), \sin^{-1} \left(1 - x\right)\right)} \]
    3. Add Preprocessing

    Alternative 3: 10.7% accurate, 0.4× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} t_0 := \sqrt{\mathsf{PI}\left(\right)}\\ t_1 := \sqrt{\sin^{-1} \left(1 - x\right)}\\ \mathsf{fma}\left(t\_0, \frac{t\_0}{2}, \left(-t\_1\right) \cdot t\_1\right) \end{array} \end{array} \]
    (FPCore (x)
     :precision binary64
     (let* ((t_0 (sqrt (PI))) (t_1 (sqrt (asin (- 1.0 x)))))
       (fma t_0 (/ t_0 2.0) (* (- t_1) t_1))))
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    t_0 := \sqrt{\mathsf{PI}\left(\right)}\\
    t_1 := \sqrt{\sin^{-1} \left(1 - x\right)}\\
    \mathsf{fma}\left(t\_0, \frac{t\_0}{2}, \left(-t\_1\right) \cdot t\_1\right)
    \end{array}
    \end{array}
    
    Derivation
    1. Initial program 6.4%

      \[\cos^{-1} \left(1 - x\right) \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-acos.f64N/A

        \[\leadsto \color{blue}{\cos^{-1} \left(1 - x\right)} \]
      2. acos-asinN/A

        \[\leadsto \color{blue}{\frac{\mathsf{PI}\left(\right)}{2} - \sin^{-1} \left(1 - x\right)} \]
      3. flip3--N/A

        \[\leadsto \color{blue}{\frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - {\sin^{-1} \left(1 - x\right)}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} \left(1 - x\right) \cdot \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} \left(1 - x\right)\right)}} \]
      4. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - {\sin^{-1} \left(1 - x\right)}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} \left(1 - x\right) \cdot \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} \left(1 - x\right)\right)}} \]
      5. lower--.f64N/A

        \[\leadsto \frac{\color{blue}{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - {\sin^{-1} \left(1 - x\right)}^{3}}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} \left(1 - x\right) \cdot \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} \left(1 - x\right)\right)} \]
      6. lower-pow.f64N/A

        \[\leadsto \frac{\color{blue}{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3}} - {\sin^{-1} \left(1 - x\right)}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} \left(1 - x\right) \cdot \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} \left(1 - x\right)\right)} \]
      7. lower-/.f64N/A

        \[\leadsto \frac{{\color{blue}{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}}^{3} - {\sin^{-1} \left(1 - x\right)}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} \left(1 - x\right) \cdot \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} \left(1 - x\right)\right)} \]
      8. lower-PI.f64N/A

        \[\leadsto \frac{{\left(\frac{\color{blue}{\mathsf{PI}\left(\right)}}{2}\right)}^{3} - {\sin^{-1} \left(1 - x\right)}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} \left(1 - x\right) \cdot \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} \left(1 - x\right)\right)} \]
      9. lower-pow.f64N/A

        \[\leadsto \frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - \color{blue}{{\sin^{-1} \left(1 - x\right)}^{3}}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} \left(1 - x\right) \cdot \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} \left(1 - x\right)\right)} \]
      10. lower-asin.f64N/A

        \[\leadsto \frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - {\color{blue}{\sin^{-1} \left(1 - x\right)}}^{3}}{\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\sin^{-1} \left(1 - x\right) \cdot \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} \left(1 - x\right)\right)} \]
      11. +-commutativeN/A

        \[\leadsto \frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - {\sin^{-1} \left(1 - x\right)}^{3}}{\color{blue}{\left(\sin^{-1} \left(1 - x\right) \cdot \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2} \cdot \sin^{-1} \left(1 - x\right)\right) + \frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2}}} \]
    4. Applied rewrites6.4%

      \[\leadsto \color{blue}{\frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - {\sin^{-1} \left(1 - x\right)}^{3}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)}} \]
    5. Step-by-step derivation
      1. lift--.f64N/A

        \[\leadsto \frac{\color{blue}{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - {\sin^{-1} \left(1 - x\right)}^{3}}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
      2. lift-pow.f64N/A

        \[\leadsto \frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - \color{blue}{{\sin^{-1} \left(1 - x\right)}^{3}}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
      3. cube-multN/A

        \[\leadsto \frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - \color{blue}{\sin^{-1} \left(1 - x\right) \cdot \left(\sin^{-1} \left(1 - x\right) \cdot \sin^{-1} \left(1 - x\right)\right)}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
      4. unpow2N/A

        \[\leadsto \frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - \sin^{-1} \left(1 - x\right) \cdot \color{blue}{{\sin^{-1} \left(1 - x\right)}^{2}}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
      5. lift-pow.f64N/A

        \[\leadsto \frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} - \sin^{-1} \left(1 - x\right) \cdot \color{blue}{{\sin^{-1} \left(1 - x\right)}^{2}}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
      6. fp-cancel-sub-sign-invN/A

        \[\leadsto \frac{\color{blue}{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3} + \left(\mathsf{neg}\left(\sin^{-1} \left(1 - x\right)\right)\right) \cdot {\sin^{-1} \left(1 - x\right)}^{2}}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
      7. lift-pow.f64N/A

        \[\leadsto \frac{\color{blue}{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{3}} + \left(\mathsf{neg}\left(\sin^{-1} \left(1 - x\right)\right)\right) \cdot {\sin^{-1} \left(1 - x\right)}^{2}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
      8. unpow3N/A

        \[\leadsto \frac{\color{blue}{\left(\frac{\mathsf{PI}\left(\right)}{2} \cdot \frac{\mathsf{PI}\left(\right)}{2}\right) \cdot \frac{\mathsf{PI}\left(\right)}{2}} + \left(\mathsf{neg}\left(\sin^{-1} \left(1 - x\right)\right)\right) \cdot {\sin^{-1} \left(1 - x\right)}^{2}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
      9. unpow2N/A

        \[\leadsto \frac{\color{blue}{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\mathsf{neg}\left(\sin^{-1} \left(1 - x\right)\right)\right) \cdot {\sin^{-1} \left(1 - x\right)}^{2}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
      10. lift-pow.f64N/A

        \[\leadsto \frac{\color{blue}{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\mathsf{neg}\left(\sin^{-1} \left(1 - x\right)\right)\right) \cdot {\sin^{-1} \left(1 - x\right)}^{2}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
      11. lift-pow.f64N/A

        \[\leadsto \frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\mathsf{neg}\left(\sin^{-1} \left(1 - x\right)\right)\right) \cdot \color{blue}{{\sin^{-1} \left(1 - x\right)}^{2}}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
      12. unpow2N/A

        \[\leadsto \frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\mathsf{neg}\left(\sin^{-1} \left(1 - x\right)\right)\right) \cdot \color{blue}{\left(\sin^{-1} \left(1 - x\right) \cdot \sin^{-1} \left(1 - x\right)\right)}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
      13. sqr-neg-revN/A

        \[\leadsto \frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\mathsf{neg}\left(\sin^{-1} \left(1 - x\right)\right)\right) \cdot \color{blue}{\left(\left(\mathsf{neg}\left(\sin^{-1} \left(1 - x\right)\right)\right) \cdot \left(\mathsf{neg}\left(\sin^{-1} \left(1 - x\right)\right)\right)\right)}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
      14. cube-unmultN/A

        \[\leadsto \frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \color{blue}{{\left(\mathsf{neg}\left(\sin^{-1} \left(1 - x\right)\right)\right)}^{3}}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
      15. cube-neg-revN/A

        \[\leadsto \frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \color{blue}{\left(\mathsf{neg}\left({\sin^{-1} \left(1 - x\right)}^{3}\right)\right)}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
      16. lift-pow.f64N/A

        \[\leadsto \frac{{\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2} \cdot \frac{\mathsf{PI}\left(\right)}{2} + \left(\mathsf{neg}\left(\color{blue}{{\sin^{-1} \left(1 - x\right)}^{3}}\right)\right)}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
    6. Applied rewrites10.2%

      \[\leadsto \frac{\color{blue}{\mathsf{fma}\left({\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}, \frac{\mathsf{PI}\left(\right)}{2}, {\sin^{-1} \left(-\left(1 - x\right)\right)}^{3}\right)}}{\mathsf{fma}\left(\sin^{-1} \left(1 - x\right), \sin^{-1} \left(1 - x\right) + \frac{\mathsf{PI}\left(\right)}{2}, {\left(\frac{\mathsf{PI}\left(\right)}{2}\right)}^{2}\right)} \]
    7. Applied rewrites10.2%

      \[\leadsto \color{blue}{\mathsf{fma}\left(\sqrt{\mathsf{PI}\left(\right)}, \frac{\sqrt{\mathsf{PI}\left(\right)}}{2}, \left(-\sqrt{\sin^{-1} \left(1 - x\right)}\right) \cdot \sqrt{\sin^{-1} \left(1 - x\right)}\right)} \]
    8. Add Preprocessing

    Alternative 4: 10.6% accurate, 0.5× speedup?

    \[\begin{array}{l} \\ \frac{\mathsf{PI}\left(\right)}{2} - {\left(\sqrt{\sin^{-1} \left(1 - x\right)}\right)}^{2} \end{array} \]
    (FPCore (x)
     :precision binary64
     (- (/ (PI) 2.0) (pow (sqrt (asin (- 1.0 x))) 2.0)))
    \begin{array}{l}
    
    \\
    \frac{\mathsf{PI}\left(\right)}{2} - {\left(\sqrt{\sin^{-1} \left(1 - x\right)}\right)}^{2}
    \end{array}
    
    Derivation
    1. Initial program 6.4%

      \[\cos^{-1} \left(1 - x\right) \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-acos.f64N/A

        \[\leadsto \color{blue}{\cos^{-1} \left(1 - x\right)} \]
      2. acos-asinN/A

        \[\leadsto \color{blue}{\frac{\mathsf{PI}\left(\right)}{2} - \sin^{-1} \left(1 - x\right)} \]
      3. lower--.f64N/A

        \[\leadsto \color{blue}{\frac{\mathsf{PI}\left(\right)}{2} - \sin^{-1} \left(1 - x\right)} \]
      4. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{\mathsf{PI}\left(\right)}{2}} - \sin^{-1} \left(1 - x\right) \]
      5. lower-PI.f64N/A

        \[\leadsto \frac{\color{blue}{\mathsf{PI}\left(\right)}}{2} - \sin^{-1} \left(1 - x\right) \]
      6. lower-asin.f646.4

        \[\leadsto \frac{\mathsf{PI}\left(\right)}{2} - \color{blue}{\sin^{-1} \left(1 - x\right)} \]
    4. Applied rewrites6.4%

      \[\leadsto \color{blue}{\frac{\mathsf{PI}\left(\right)}{2} - \sin^{-1} \left(1 - x\right)} \]
    5. Step-by-step derivation
      1. unpow1N/A

        \[\leadsto \frac{\mathsf{PI}\left(\right)}{2} - \color{blue}{{\sin^{-1} \left(1 - x\right)}^{1}} \]
      2. sqr-powN/A

        \[\leadsto \frac{\mathsf{PI}\left(\right)}{2} - \color{blue}{{\sin^{-1} \left(1 - x\right)}^{\left(\frac{1}{2}\right)} \cdot {\sin^{-1} \left(1 - x\right)}^{\left(\frac{1}{2}\right)}} \]
      3. pow2N/A

        \[\leadsto \frac{\mathsf{PI}\left(\right)}{2} - \color{blue}{{\left({\sin^{-1} \left(1 - x\right)}^{\left(\frac{1}{2}\right)}\right)}^{2}} \]
      4. lower-pow.f64N/A

        \[\leadsto \frac{\mathsf{PI}\left(\right)}{2} - \color{blue}{{\left({\sin^{-1} \left(1 - x\right)}^{\left(\frac{1}{2}\right)}\right)}^{2}} \]
      5. metadata-evalN/A

        \[\leadsto \frac{\mathsf{PI}\left(\right)}{2} - {\left({\sin^{-1} \left(1 - x\right)}^{\color{blue}{\frac{1}{2}}}\right)}^{2} \]
      6. unpow1/2N/A

        \[\leadsto \frac{\mathsf{PI}\left(\right)}{2} - {\color{blue}{\left(\sqrt{\sin^{-1} \left(1 - x\right)}\right)}}^{2} \]
      7. lower-sqrt.f6410.1

        \[\leadsto \frac{\mathsf{PI}\left(\right)}{2} - {\color{blue}{\left(\sqrt{\sin^{-1} \left(1 - x\right)}\right)}}^{2} \]
    6. Applied rewrites10.1%

      \[\leadsto \frac{\mathsf{PI}\left(\right)}{2} - \color{blue}{{\left(\sqrt{\sin^{-1} \left(1 - x\right)}\right)}^{2}} \]
    7. Add Preprocessing

    Alternative 5: 9.7% accurate, 0.9× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 5.6 \cdot 10^{-17}:\\ \;\;\;\;\cos^{-1} \left(-x\right)\\ \mathbf{else}:\\ \;\;\;\;\cos^{-1} \left(1 - x\right)\\ \end{array} \end{array} \]
    (FPCore (x)
     :precision binary64
     (if (<= x 5.6e-17) (acos (- x)) (acos (- 1.0 x))))
    double code(double x) {
    	double tmp;
    	if (x <= 5.6e-17) {
    		tmp = acos(-x);
    	} else {
    		tmp = acos((1.0 - x));
    	}
    	return tmp;
    }
    
    real(8) function code(x)
        real(8), intent (in) :: x
        real(8) :: tmp
        if (x <= 5.6d-17) then
            tmp = acos(-x)
        else
            tmp = acos((1.0d0 - x))
        end if
        code = tmp
    end function
    
    public static double code(double x) {
    	double tmp;
    	if (x <= 5.6e-17) {
    		tmp = Math.acos(-x);
    	} else {
    		tmp = Math.acos((1.0 - x));
    	}
    	return tmp;
    }
    
    def code(x):
    	tmp = 0
    	if x <= 5.6e-17:
    		tmp = math.acos(-x)
    	else:
    		tmp = math.acos((1.0 - x))
    	return tmp
    
    function code(x)
    	tmp = 0.0
    	if (x <= 5.6e-17)
    		tmp = acos(Float64(-x));
    	else
    		tmp = acos(Float64(1.0 - x));
    	end
    	return tmp
    end
    
    function tmp_2 = code(x)
    	tmp = 0.0;
    	if (x <= 5.6e-17)
    		tmp = acos(-x);
    	else
    		tmp = acos((1.0 - x));
    	end
    	tmp_2 = tmp;
    end
    
    code[x_] := If[LessEqual[x, 5.6e-17], N[ArcCos[(-x)], $MachinePrecision], N[ArcCos[N[(1.0 - x), $MachinePrecision]], $MachinePrecision]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;x \leq 5.6 \cdot 10^{-17}:\\
    \;\;\;\;\cos^{-1} \left(-x\right)\\
    
    \mathbf{else}:\\
    \;\;\;\;\cos^{-1} \left(1 - x\right)\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 2 regimes
    2. if x < 5.5999999999999998e-17

      1. Initial program 3.8%

        \[\cos^{-1} \left(1 - x\right) \]
      2. Add Preprocessing
      3. Taylor expanded in x around inf

        \[\leadsto \cos^{-1} \color{blue}{\left(-1 \cdot x\right)} \]
      4. Step-by-step derivation
        1. mul-1-negN/A

          \[\leadsto \cos^{-1} \color{blue}{\left(\mathsf{neg}\left(x\right)\right)} \]
        2. lower-neg.f646.6

          \[\leadsto \cos^{-1} \color{blue}{\left(-x\right)} \]
      5. Applied rewrites6.6%

        \[\leadsto \cos^{-1} \color{blue}{\left(-x\right)} \]

      if 5.5999999999999998e-17 < x

      1. Initial program 77.5%

        \[\cos^{-1} \left(1 - x\right) \]
      2. Add Preprocessing
    3. Recombined 2 regimes into one program.
    4. Add Preprocessing

    Alternative 6: 7.0% accurate, 1.0× speedup?

    \[\begin{array}{l} \\ \cos^{-1} \left(-x\right) \end{array} \]
    (FPCore (x) :precision binary64 (acos (- x)))
    double code(double x) {
    	return acos(-x);
    }
    
    real(8) function code(x)
        real(8), intent (in) :: x
        code = acos(-x)
    end function
    
    public static double code(double x) {
    	return Math.acos(-x);
    }
    
    def code(x):
    	return math.acos(-x)
    
    function code(x)
    	return acos(Float64(-x))
    end
    
    function tmp = code(x)
    	tmp = acos(-x);
    end
    
    code[x_] := N[ArcCos[(-x)], $MachinePrecision]
    
    \begin{array}{l}
    
    \\
    \cos^{-1} \left(-x\right)
    \end{array}
    
    Derivation
    1. Initial program 6.4%

      \[\cos^{-1} \left(1 - x\right) \]
    2. Add Preprocessing
    3. Taylor expanded in x around inf

      \[\leadsto \cos^{-1} \color{blue}{\left(-1 \cdot x\right)} \]
    4. Step-by-step derivation
      1. mul-1-negN/A

        \[\leadsto \cos^{-1} \color{blue}{\left(\mathsf{neg}\left(x\right)\right)} \]
      2. lower-neg.f646.9

        \[\leadsto \cos^{-1} \color{blue}{\left(-x\right)} \]
    5. Applied rewrites6.9%

      \[\leadsto \cos^{-1} \color{blue}{\left(-x\right)} \]
    6. Add Preprocessing

    Alternative 7: 3.8% accurate, 1.0× speedup?

    \[\begin{array}{l} \\ \cos^{-1} 1 \end{array} \]
    (FPCore (x) :precision binary64 (acos 1.0))
    double code(double x) {
    	return acos(1.0);
    }
    
    real(8) function code(x)
        real(8), intent (in) :: x
        code = acos(1.0d0)
    end function
    
    public static double code(double x) {
    	return Math.acos(1.0);
    }
    
    def code(x):
    	return math.acos(1.0)
    
    function code(x)
    	return acos(1.0)
    end
    
    function tmp = code(x)
    	tmp = acos(1.0);
    end
    
    code[x_] := N[ArcCos[1.0], $MachinePrecision]
    
    \begin{array}{l}
    
    \\
    \cos^{-1} 1
    \end{array}
    
    Derivation
    1. Initial program 6.4%

      \[\cos^{-1} \left(1 - x\right) \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \cos^{-1} \color{blue}{1} \]
    4. Step-by-step derivation
      1. Applied rewrites3.8%

        \[\leadsto \cos^{-1} \color{blue}{1} \]
      2. Add Preprocessing

      Developer Target 1: 100.0% accurate, 0.8× speedup?

      \[\begin{array}{l} \\ 2 \cdot \sin^{-1} \left(\sqrt{\frac{x}{2}}\right) \end{array} \]
      (FPCore (x) :precision binary64 (* 2.0 (asin (sqrt (/ x 2.0)))))
      double code(double x) {
      	return 2.0 * asin(sqrt((x / 2.0)));
      }
      
      real(8) function code(x)
          real(8), intent (in) :: x
          code = 2.0d0 * asin(sqrt((x / 2.0d0)))
      end function
      
      public static double code(double x) {
      	return 2.0 * Math.asin(Math.sqrt((x / 2.0)));
      }
      
      def code(x):
      	return 2.0 * math.asin(math.sqrt((x / 2.0)))
      
      function code(x)
      	return Float64(2.0 * asin(sqrt(Float64(x / 2.0))))
      end
      
      function tmp = code(x)
      	tmp = 2.0 * asin(sqrt((x / 2.0)));
      end
      
      code[x_] := N[(2.0 * N[ArcSin[N[Sqrt[N[(x / 2.0), $MachinePrecision]], $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
      
      \begin{array}{l}
      
      \\
      2 \cdot \sin^{-1} \left(\sqrt{\frac{x}{2}}\right)
      \end{array}
      

      Reproduce

      ?
      herbie shell --seed 2024340 
      (FPCore (x)
        :name "bug323 (missed optimization)"
        :precision binary64
        :pre (and (<= 0.0 x) (<= x 0.5))
      
        :alt
        (! :herbie-platform default (* 2 (asin (sqrt (/ x 2)))))
      
        (acos (- 1.0 x)))