ABCF->ab-angle a

Percentage Accurate: 18.4% → 58.9%
Time: 17.1s
Alternatives: 16
Speedup: 16.9×

Specification

?
\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
real(8) function code(a, b, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) + sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 16 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 18.4% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
real(8) function code(a, b, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) + sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Alternative 1: 58.9% accurate, 1.6× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ t_1 := -\sqrt{F}\\ t_2 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\ \mathbf{if}\;B\_m \leq 4.3 \cdot 10^{-128}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot \left(t\_2 \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B\_m \cdot B\_m}{A}, -0.5, 2 \cdot C\right)}}{-t\_2}\\ \mathbf{elif}\;B\_m \leq 1.05 \cdot 10^{-85}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(t\_0 \cdot 2\right)} \cdot t\_1}{t\_2}\\ \mathbf{elif}\;B\_m \leq 7.2 \cdot 10^{+59}:\\ \;\;\;\;\sqrt{\left(2 \cdot F\right) \cdot t\_0} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}}{-t\_0}\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{\mathsf{hypot}\left(C, B\_m\right) + C} \cdot t\_1\right) \cdot \frac{\sqrt{2}}{B\_m}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (let* ((t_0 (fma -4.0 (* C A) (* B_m B_m)))
        (t_1 (- (sqrt F)))
        (t_2 (- (pow B_m 2.0) (* (* 4.0 A) C))))
   (if (<= B_m 4.3e-128)
     (/
      (sqrt (* (* 2.0 (* t_2 F)) (fma (/ (* B_m B_m) A) -0.5 (* 2.0 C))))
      (- t_2))
     (if (<= B_m 1.05e-85)
       (/ (* (sqrt (* (* 2.0 C) (* t_0 2.0))) t_1) t_2)
       (if (<= B_m 7.2e+59)
         (*
          (sqrt (* (* 2.0 F) t_0))
          (/ (sqrt (+ (+ (hypot (- A C) B_m) A) C)) (- t_0)))
         (* (* (sqrt (+ (hypot C B_m) C)) t_1) (/ (sqrt 2.0) B_m)))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double t_0 = fma(-4.0, (C * A), (B_m * B_m));
	double t_1 = -sqrt(F);
	double t_2 = pow(B_m, 2.0) - ((4.0 * A) * C);
	double tmp;
	if (B_m <= 4.3e-128) {
		tmp = sqrt(((2.0 * (t_2 * F)) * fma(((B_m * B_m) / A), -0.5, (2.0 * C)))) / -t_2;
	} else if (B_m <= 1.05e-85) {
		tmp = (sqrt(((2.0 * C) * (t_0 * 2.0))) * t_1) / t_2;
	} else if (B_m <= 7.2e+59) {
		tmp = sqrt(((2.0 * F) * t_0)) * (sqrt(((hypot((A - C), B_m) + A) + C)) / -t_0);
	} else {
		tmp = (sqrt((hypot(C, B_m) + C)) * t_1) * (sqrt(2.0) / B_m);
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	t_0 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
	t_1 = Float64(-sqrt(F))
	t_2 = Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C))
	tmp = 0.0
	if (B_m <= 4.3e-128)
		tmp = Float64(sqrt(Float64(Float64(2.0 * Float64(t_2 * F)) * fma(Float64(Float64(B_m * B_m) / A), -0.5, Float64(2.0 * C)))) / Float64(-t_2));
	elseif (B_m <= 1.05e-85)
		tmp = Float64(Float64(sqrt(Float64(Float64(2.0 * C) * Float64(t_0 * 2.0))) * t_1) / t_2);
	elseif (B_m <= 7.2e+59)
		tmp = Float64(sqrt(Float64(Float64(2.0 * F) * t_0)) * Float64(sqrt(Float64(Float64(hypot(Float64(A - C), B_m) + A) + C)) / Float64(-t_0)));
	else
		tmp = Float64(Float64(sqrt(Float64(hypot(C, B_m) + C)) * t_1) * Float64(sqrt(2.0) / B_m));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = (-N[Sqrt[F], $MachinePrecision])}, Block[{t$95$2 = N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[B$95$m, 4.3e-128], N[(N[Sqrt[N[(N[(2.0 * N[(t$95$2 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] * -0.5 + N[(2.0 * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$2)), $MachinePrecision], If[LessEqual[B$95$m, 1.05e-85], N[(N[(N[Sqrt[N[(N[(2.0 * C), $MachinePrecision] * N[(t$95$0 * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * t$95$1), $MachinePrecision] / t$95$2), $MachinePrecision], If[LessEqual[B$95$m, 7.2e+59], N[(N[Sqrt[N[(N[(2.0 * F), $MachinePrecision] * t$95$0), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] * t$95$1), $MachinePrecision] * N[(N[Sqrt[2.0], $MachinePrecision] / B$95$m), $MachinePrecision]), $MachinePrecision]]]]]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
t_1 := -\sqrt{F}\\
t_2 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\
\mathbf{if}\;B\_m \leq 4.3 \cdot 10^{-128}:\\
\;\;\;\;\frac{\sqrt{\left(2 \cdot \left(t\_2 \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B\_m \cdot B\_m}{A}, -0.5, 2 \cdot C\right)}}{-t\_2}\\

\mathbf{elif}\;B\_m \leq 1.05 \cdot 10^{-85}:\\
\;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(t\_0 \cdot 2\right)} \cdot t\_1}{t\_2}\\

\mathbf{elif}\;B\_m \leq 7.2 \cdot 10^{+59}:\\
\;\;\;\;\sqrt{\left(2 \cdot F\right) \cdot t\_0} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}}{-t\_0}\\

\mathbf{else}:\\
\;\;\;\;\left(\sqrt{\mathsf{hypot}\left(C, B\_m\right) + C} \cdot t\_1\right) \cdot \frac{\sqrt{2}}{B\_m}\\


\end{array}
\end{array}
Derivation
  1. Split input into 4 regimes
  2. if B < 4.29999999999999994e-128

    1. Initial program 17.3%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in A around -inf

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\color{blue}{\frac{{B}^{2}}{A} \cdot \frac{-1}{2}} + 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lower-fma.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{{B}^{2}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. lower-/.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\color{blue}{\frac{{B}^{2}}{A}}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. unpow2N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. lower-*.f6417.6

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, \color{blue}{2 \cdot C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    5. Applied rewrites17.6%

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

    if 4.29999999999999994e-128 < B < 1.05e-85

    1. Initial program 1.1%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. *-commutativeN/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. associate-*r*N/A

        \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      7. associate-*r*N/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      8. sqrt-prodN/A

        \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      9. pow1/2N/A

        \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \color{blue}{{F}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Applied rewrites8.9%

      \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    5. Taylor expanded in A around -inf

      \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    6. Step-by-step derivation
      1. lower-*.f6437.6

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    7. Applied rewrites37.6%

      \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

    if 1.05e-85 < B < 7.1999999999999997e59

    1. Initial program 32.5%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Applied rewrites60.2%

      \[\leadsto \color{blue}{\left(-\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]

    if 7.1999999999999997e59 < B

    1. Initial program 14.0%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in A around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. mul-1-negN/A

        \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
      2. lower-neg.f64N/A

        \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
      3. *-commutativeN/A

        \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}} \]
      4. lower-*.f64N/A

        \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}} \]
      5. lower-sqrt.f64N/A

        \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \cdot \frac{\sqrt{2}}{B} \]
      6. *-commutativeN/A

        \[\leadsto -\sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \cdot \frac{\sqrt{2}}{B} \]
      7. lower-*.f64N/A

        \[\leadsto -\sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \cdot \frac{\sqrt{2}}{B} \]
      8. +-commutativeN/A

        \[\leadsto -\sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \cdot \frac{\sqrt{2}}{B} \]
      9. lower-+.f64N/A

        \[\leadsto -\sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \cdot \frac{\sqrt{2}}{B} \]
      10. +-commutativeN/A

        \[\leadsto -\sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
      11. unpow2N/A

        \[\leadsto -\sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
      12. unpow2N/A

        \[\leadsto -\sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
      13. lower-hypot.f64N/A

        \[\leadsto -\sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
      14. lower-/.f64N/A

        \[\leadsto -\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \color{blue}{\frac{\sqrt{2}}{B}} \]
      15. lower-sqrt.f6454.9

        \[\leadsto -\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \frac{\color{blue}{\sqrt{2}}}{B} \]
    5. Applied rewrites54.9%

      \[\leadsto \color{blue}{-\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B}} \]
    6. Step-by-step derivation
      1. Applied rewrites78.3%

        \[\leadsto -\left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{B} \]
    7. Recombined 4 regimes into one program.
    8. Final simplification37.3%

      \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 4.3 \cdot 10^{-128}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, 2 \cdot C\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{elif}\;B \leq 1.05 \cdot 10^{-85}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \left(-\sqrt{F}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C}\\ \mathbf{elif}\;B \leq 7.2 \cdot 10^{+59}:\\ \;\;\;\;\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \left(-\sqrt{F}\right)\right) \cdot \frac{\sqrt{2}}{B}\\ \end{array} \]
    9. Add Preprocessing

    Alternative 2: 58.8% accurate, 1.8× speedup?

    \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ t_1 := -\sqrt{F}\\ t_2 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\ \mathbf{if}\;B\_m \leq 1.85 \cdot 10^{-132}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot \left(t\_2 \cdot F\right)\right) \cdot \left(2 \cdot C\right)}}{-t\_2}\\ \mathbf{elif}\;B\_m \leq 1.05 \cdot 10^{-85}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(t\_0 \cdot 2\right)} \cdot t\_1}{t\_2}\\ \mathbf{elif}\;B\_m \leq 7.2 \cdot 10^{+59}:\\ \;\;\;\;\sqrt{\left(2 \cdot F\right) \cdot t\_0} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}}{-t\_0}\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{\mathsf{hypot}\left(C, B\_m\right) + C} \cdot t\_1\right) \cdot \frac{\sqrt{2}}{B\_m}\\ \end{array} \end{array} \]
    B_m = (fabs.f64 B)
    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
    (FPCore (A B_m C F)
     :precision binary64
     (let* ((t_0 (fma -4.0 (* C A) (* B_m B_m)))
            (t_1 (- (sqrt F)))
            (t_2 (- (pow B_m 2.0) (* (* 4.0 A) C))))
       (if (<= B_m 1.85e-132)
         (/ (sqrt (* (* 2.0 (* t_2 F)) (* 2.0 C))) (- t_2))
         (if (<= B_m 1.05e-85)
           (/ (* (sqrt (* (* 2.0 C) (* t_0 2.0))) t_1) t_2)
           (if (<= B_m 7.2e+59)
             (*
              (sqrt (* (* 2.0 F) t_0))
              (/ (sqrt (+ (+ (hypot (- A C) B_m) A) C)) (- t_0)))
             (* (* (sqrt (+ (hypot C B_m) C)) t_1) (/ (sqrt 2.0) B_m)))))))
    B_m = fabs(B);
    assert(A < B_m && B_m < C && C < F);
    double code(double A, double B_m, double C, double F) {
    	double t_0 = fma(-4.0, (C * A), (B_m * B_m));
    	double t_1 = -sqrt(F);
    	double t_2 = pow(B_m, 2.0) - ((4.0 * A) * C);
    	double tmp;
    	if (B_m <= 1.85e-132) {
    		tmp = sqrt(((2.0 * (t_2 * F)) * (2.0 * C))) / -t_2;
    	} else if (B_m <= 1.05e-85) {
    		tmp = (sqrt(((2.0 * C) * (t_0 * 2.0))) * t_1) / t_2;
    	} else if (B_m <= 7.2e+59) {
    		tmp = sqrt(((2.0 * F) * t_0)) * (sqrt(((hypot((A - C), B_m) + A) + C)) / -t_0);
    	} else {
    		tmp = (sqrt((hypot(C, B_m) + C)) * t_1) * (sqrt(2.0) / B_m);
    	}
    	return tmp;
    }
    
    B_m = abs(B)
    A, B_m, C, F = sort([A, B_m, C, F])
    function code(A, B_m, C, F)
    	t_0 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
    	t_1 = Float64(-sqrt(F))
    	t_2 = Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C))
    	tmp = 0.0
    	if (B_m <= 1.85e-132)
    		tmp = Float64(sqrt(Float64(Float64(2.0 * Float64(t_2 * F)) * Float64(2.0 * C))) / Float64(-t_2));
    	elseif (B_m <= 1.05e-85)
    		tmp = Float64(Float64(sqrt(Float64(Float64(2.0 * C) * Float64(t_0 * 2.0))) * t_1) / t_2);
    	elseif (B_m <= 7.2e+59)
    		tmp = Float64(sqrt(Float64(Float64(2.0 * F) * t_0)) * Float64(sqrt(Float64(Float64(hypot(Float64(A - C), B_m) + A) + C)) / Float64(-t_0)));
    	else
    		tmp = Float64(Float64(sqrt(Float64(hypot(C, B_m) + C)) * t_1) * Float64(sqrt(2.0) / B_m));
    	end
    	return tmp
    end
    
    B_m = N[Abs[B], $MachinePrecision]
    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
    code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = (-N[Sqrt[F], $MachinePrecision])}, Block[{t$95$2 = N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[B$95$m, 1.85e-132], N[(N[Sqrt[N[(N[(2.0 * N[(t$95$2 * F), $MachinePrecision]), $MachinePrecision] * N[(2.0 * C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$2)), $MachinePrecision], If[LessEqual[B$95$m, 1.05e-85], N[(N[(N[Sqrt[N[(N[(2.0 * C), $MachinePrecision] * N[(t$95$0 * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * t$95$1), $MachinePrecision] / t$95$2), $MachinePrecision], If[LessEqual[B$95$m, 7.2e+59], N[(N[Sqrt[N[(N[(2.0 * F), $MachinePrecision] * t$95$0), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] * t$95$1), $MachinePrecision] * N[(N[Sqrt[2.0], $MachinePrecision] / B$95$m), $MachinePrecision]), $MachinePrecision]]]]]]]
    
    \begin{array}{l}
    B_m = \left|B\right|
    \\
    [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
    \\
    \begin{array}{l}
    t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
    t_1 := -\sqrt{F}\\
    t_2 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\
    \mathbf{if}\;B\_m \leq 1.85 \cdot 10^{-132}:\\
    \;\;\;\;\frac{\sqrt{\left(2 \cdot \left(t\_2 \cdot F\right)\right) \cdot \left(2 \cdot C\right)}}{-t\_2}\\
    
    \mathbf{elif}\;B\_m \leq 1.05 \cdot 10^{-85}:\\
    \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(t\_0 \cdot 2\right)} \cdot t\_1}{t\_2}\\
    
    \mathbf{elif}\;B\_m \leq 7.2 \cdot 10^{+59}:\\
    \;\;\;\;\sqrt{\left(2 \cdot F\right) \cdot t\_0} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}}{-t\_0}\\
    
    \mathbf{else}:\\
    \;\;\;\;\left(\sqrt{\mathsf{hypot}\left(C, B\_m\right) + C} \cdot t\_1\right) \cdot \frac{\sqrt{2}}{B\_m}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 4 regimes
    2. if B < 1.8500000000000001e-132

      1. Initial program 17.4%

        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. Add Preprocessing
      3. Taylor expanded in A around -inf

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. Step-by-step derivation
        1. lower-*.f6417.7

          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. Applied rewrites17.7%

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

      if 1.8500000000000001e-132 < B < 1.05e-85

      1. Initial program 1.3%

        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. Add Preprocessing
      3. Step-by-step derivation
        1. lift-sqrt.f64N/A

          \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. lift-*.f64N/A

          \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        3. *-commutativeN/A

          \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        4. lift-*.f64N/A

          \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        5. lift-*.f64N/A

          \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        6. associate-*r*N/A

          \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        7. associate-*r*N/A

          \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        8. sqrt-prodN/A

          \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        9. pow1/2N/A

          \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \color{blue}{{F}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. Applied rewrites10.1%

        \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. Taylor expanded in A around -inf

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. Step-by-step derivation
        1. lower-*.f6444.5

          \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      7. Applied rewrites44.5%

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

      if 1.05e-85 < B < 7.1999999999999997e59

      1. Initial program 32.5%

        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. Add Preprocessing
      3. Applied rewrites60.2%

        \[\leadsto \color{blue}{\left(-\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]

      if 7.1999999999999997e59 < B

      1. Initial program 14.0%

        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. Add Preprocessing
      3. Taylor expanded in A around 0

        \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
      4. Step-by-step derivation
        1. mul-1-negN/A

          \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
        2. lower-neg.f64N/A

          \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
        3. *-commutativeN/A

          \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}} \]
        4. lower-*.f64N/A

          \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}} \]
        5. lower-sqrt.f64N/A

          \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \cdot \frac{\sqrt{2}}{B} \]
        6. *-commutativeN/A

          \[\leadsto -\sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \cdot \frac{\sqrt{2}}{B} \]
        7. lower-*.f64N/A

          \[\leadsto -\sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \cdot \frac{\sqrt{2}}{B} \]
        8. +-commutativeN/A

          \[\leadsto -\sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \cdot \frac{\sqrt{2}}{B} \]
        9. lower-+.f64N/A

          \[\leadsto -\sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \cdot \frac{\sqrt{2}}{B} \]
        10. +-commutativeN/A

          \[\leadsto -\sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
        11. unpow2N/A

          \[\leadsto -\sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
        12. unpow2N/A

          \[\leadsto -\sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
        13. lower-hypot.f64N/A

          \[\leadsto -\sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
        14. lower-/.f64N/A

          \[\leadsto -\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \color{blue}{\frac{\sqrt{2}}{B}} \]
        15. lower-sqrt.f6454.9

          \[\leadsto -\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \frac{\color{blue}{\sqrt{2}}}{B} \]
      5. Applied rewrites54.9%

        \[\leadsto \color{blue}{-\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B}} \]
      6. Step-by-step derivation
        1. Applied rewrites78.3%

          \[\leadsto -\left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{B} \]
      7. Recombined 4 regimes into one program.
      8. Final simplification37.7%

        \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 1.85 \cdot 10^{-132}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(2 \cdot C\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{elif}\;B \leq 1.05 \cdot 10^{-85}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \left(-\sqrt{F}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C}\\ \mathbf{elif}\;B \leq 7.2 \cdot 10^{+59}:\\ \;\;\;\;\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \left(-\sqrt{F}\right)\right) \cdot \frac{\sqrt{2}}{B}\\ \end{array} \]
      9. Add Preprocessing

      Alternative 3: 58.8% accurate, 2.3× speedup?

      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ t_1 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\ t_2 := -\sqrt{F}\\ \mathbf{if}\;B\_m \leq 1.85 \cdot 10^{-132}:\\ \;\;\;\;\frac{\sqrt{C \cdot \mathsf{fma}\left(-16, \left(A \cdot C\right) \cdot F, 4 \cdot \left(\left(B\_m \cdot B\_m\right) \cdot F\right)\right)}}{-t\_1}\\ \mathbf{elif}\;B\_m \leq 1.05 \cdot 10^{-85}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(t\_0 \cdot 2\right)} \cdot t\_2}{t\_1}\\ \mathbf{elif}\;B\_m \leq 7.2 \cdot 10^{+59}:\\ \;\;\;\;\sqrt{\left(2 \cdot F\right) \cdot t\_0} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}}{-t\_0}\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{\mathsf{hypot}\left(C, B\_m\right) + C} \cdot t\_2\right) \cdot \frac{\sqrt{2}}{B\_m}\\ \end{array} \end{array} \]
      B_m = (fabs.f64 B)
      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
      (FPCore (A B_m C F)
       :precision binary64
       (let* ((t_0 (fma -4.0 (* C A) (* B_m B_m)))
              (t_1 (- (pow B_m 2.0) (* (* 4.0 A) C)))
              (t_2 (- (sqrt F))))
         (if (<= B_m 1.85e-132)
           (/
            (sqrt (* C (fma -16.0 (* (* A C) F) (* 4.0 (* (* B_m B_m) F)))))
            (- t_1))
           (if (<= B_m 1.05e-85)
             (/ (* (sqrt (* (* 2.0 C) (* t_0 2.0))) t_2) t_1)
             (if (<= B_m 7.2e+59)
               (*
                (sqrt (* (* 2.0 F) t_0))
                (/ (sqrt (+ (+ (hypot (- A C) B_m) A) C)) (- t_0)))
               (* (* (sqrt (+ (hypot C B_m) C)) t_2) (/ (sqrt 2.0) B_m)))))))
      B_m = fabs(B);
      assert(A < B_m && B_m < C && C < F);
      double code(double A, double B_m, double C, double F) {
      	double t_0 = fma(-4.0, (C * A), (B_m * B_m));
      	double t_1 = pow(B_m, 2.0) - ((4.0 * A) * C);
      	double t_2 = -sqrt(F);
      	double tmp;
      	if (B_m <= 1.85e-132) {
      		tmp = sqrt((C * fma(-16.0, ((A * C) * F), (4.0 * ((B_m * B_m) * F))))) / -t_1;
      	} else if (B_m <= 1.05e-85) {
      		tmp = (sqrt(((2.0 * C) * (t_0 * 2.0))) * t_2) / t_1;
      	} else if (B_m <= 7.2e+59) {
      		tmp = sqrt(((2.0 * F) * t_0)) * (sqrt(((hypot((A - C), B_m) + A) + C)) / -t_0);
      	} else {
      		tmp = (sqrt((hypot(C, B_m) + C)) * t_2) * (sqrt(2.0) / B_m);
      	}
      	return tmp;
      }
      
      B_m = abs(B)
      A, B_m, C, F = sort([A, B_m, C, F])
      function code(A, B_m, C, F)
      	t_0 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
      	t_1 = Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C))
      	t_2 = Float64(-sqrt(F))
      	tmp = 0.0
      	if (B_m <= 1.85e-132)
      		tmp = Float64(sqrt(Float64(C * fma(-16.0, Float64(Float64(A * C) * F), Float64(4.0 * Float64(Float64(B_m * B_m) * F))))) / Float64(-t_1));
      	elseif (B_m <= 1.05e-85)
      		tmp = Float64(Float64(sqrt(Float64(Float64(2.0 * C) * Float64(t_0 * 2.0))) * t_2) / t_1);
      	elseif (B_m <= 7.2e+59)
      		tmp = Float64(sqrt(Float64(Float64(2.0 * F) * t_0)) * Float64(sqrt(Float64(Float64(hypot(Float64(A - C), B_m) + A) + C)) / Float64(-t_0)));
      	else
      		tmp = Float64(Float64(sqrt(Float64(hypot(C, B_m) + C)) * t_2) * Float64(sqrt(2.0) / B_m));
      	end
      	return tmp
      end
      
      B_m = N[Abs[B], $MachinePrecision]
      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
      code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = (-N[Sqrt[F], $MachinePrecision])}, If[LessEqual[B$95$m, 1.85e-132], N[(N[Sqrt[N[(C * N[(-16.0 * N[(N[(A * C), $MachinePrecision] * F), $MachinePrecision] + N[(4.0 * N[(N[(B$95$m * B$95$m), $MachinePrecision] * F), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$1)), $MachinePrecision], If[LessEqual[B$95$m, 1.05e-85], N[(N[(N[Sqrt[N[(N[(2.0 * C), $MachinePrecision] * N[(t$95$0 * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * t$95$2), $MachinePrecision] / t$95$1), $MachinePrecision], If[LessEqual[B$95$m, 7.2e+59], N[(N[Sqrt[N[(N[(2.0 * F), $MachinePrecision] * t$95$0), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] * t$95$2), $MachinePrecision] * N[(N[Sqrt[2.0], $MachinePrecision] / B$95$m), $MachinePrecision]), $MachinePrecision]]]]]]]
      
      \begin{array}{l}
      B_m = \left|B\right|
      \\
      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
      \\
      \begin{array}{l}
      t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
      t_1 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\
      t_2 := -\sqrt{F}\\
      \mathbf{if}\;B\_m \leq 1.85 \cdot 10^{-132}:\\
      \;\;\;\;\frac{\sqrt{C \cdot \mathsf{fma}\left(-16, \left(A \cdot C\right) \cdot F, 4 \cdot \left(\left(B\_m \cdot B\_m\right) \cdot F\right)\right)}}{-t\_1}\\
      
      \mathbf{elif}\;B\_m \leq 1.05 \cdot 10^{-85}:\\
      \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(t\_0 \cdot 2\right)} \cdot t\_2}{t\_1}\\
      
      \mathbf{elif}\;B\_m \leq 7.2 \cdot 10^{+59}:\\
      \;\;\;\;\sqrt{\left(2 \cdot F\right) \cdot t\_0} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}}{-t\_0}\\
      
      \mathbf{else}:\\
      \;\;\;\;\left(\sqrt{\mathsf{hypot}\left(C, B\_m\right) + C} \cdot t\_2\right) \cdot \frac{\sqrt{2}}{B\_m}\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 4 regimes
      2. if B < 1.8500000000000001e-132

        1. Initial program 17.4%

          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. Add Preprocessing
        3. Taylor expanded in C around inf

          \[\leadsto \frac{-\sqrt{\color{blue}{{C}^{2} \cdot \left(-16 \cdot \left(A \cdot F\right) + 2 \cdot \frac{F \cdot \left(-4 \cdot \left(A \cdot \left(A + -1 \cdot A\right)\right) + 2 \cdot {B}^{2}\right)}{C}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        4. Step-by-step derivation
          1. *-commutativeN/A

            \[\leadsto \frac{-\sqrt{\color{blue}{\left(-16 \cdot \left(A \cdot F\right) + 2 \cdot \frac{F \cdot \left(-4 \cdot \left(A \cdot \left(A + -1 \cdot A\right)\right) + 2 \cdot {B}^{2}\right)}{C}\right) \cdot {C}^{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. lower-*.f64N/A

            \[\leadsto \frac{-\sqrt{\color{blue}{\left(-16 \cdot \left(A \cdot F\right) + 2 \cdot \frac{F \cdot \left(-4 \cdot \left(A \cdot \left(A + -1 \cdot A\right)\right) + 2 \cdot {B}^{2}\right)}{C}\right) \cdot {C}^{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        5. Applied rewrites11.9%

          \[\leadsto \frac{-\sqrt{\color{blue}{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        6. Taylor expanded in C around 0

          \[\leadsto \frac{-\sqrt{C \cdot \color{blue}{\left(-16 \cdot \left(A \cdot \left(C \cdot F\right)\right) + 4 \cdot \left({B}^{2} \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        7. Step-by-step derivation
          1. Applied rewrites17.7%

            \[\leadsto \frac{-\sqrt{C \cdot \color{blue}{\mathsf{fma}\left(-16, \left(A \cdot C\right) \cdot F, 4 \cdot \left(\left(B \cdot B\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

          if 1.8500000000000001e-132 < B < 1.05e-85

          1. Initial program 1.3%

            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. Add Preprocessing
          3. Step-by-step derivation
            1. lift-sqrt.f64N/A

              \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            2. lift-*.f64N/A

              \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            3. *-commutativeN/A

              \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            4. lift-*.f64N/A

              \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            5. lift-*.f64N/A

              \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            6. associate-*r*N/A

              \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            7. associate-*r*N/A

              \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            8. sqrt-prodN/A

              \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            9. pow1/2N/A

              \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \color{blue}{{F}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          4. Applied rewrites10.1%

            \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          5. Taylor expanded in A around -inf

            \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          6. Step-by-step derivation
            1. lower-*.f6444.5

              \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          7. Applied rewrites44.5%

            \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

          if 1.05e-85 < B < 7.1999999999999997e59

          1. Initial program 32.5%

            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. Add Preprocessing
          3. Applied rewrites60.2%

            \[\leadsto \color{blue}{\left(-\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]

          if 7.1999999999999997e59 < B

          1. Initial program 14.0%

            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. Add Preprocessing
          3. Taylor expanded in A around 0

            \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
          4. Step-by-step derivation
            1. mul-1-negN/A

              \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
            2. lower-neg.f64N/A

              \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
            3. *-commutativeN/A

              \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}} \]
            4. lower-*.f64N/A

              \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}} \]
            5. lower-sqrt.f64N/A

              \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \cdot \frac{\sqrt{2}}{B} \]
            6. *-commutativeN/A

              \[\leadsto -\sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \cdot \frac{\sqrt{2}}{B} \]
            7. lower-*.f64N/A

              \[\leadsto -\sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \cdot \frac{\sqrt{2}}{B} \]
            8. +-commutativeN/A

              \[\leadsto -\sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \cdot \frac{\sqrt{2}}{B} \]
            9. lower-+.f64N/A

              \[\leadsto -\sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \cdot \frac{\sqrt{2}}{B} \]
            10. +-commutativeN/A

              \[\leadsto -\sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
            11. unpow2N/A

              \[\leadsto -\sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
            12. unpow2N/A

              \[\leadsto -\sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
            13. lower-hypot.f64N/A

              \[\leadsto -\sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
            14. lower-/.f64N/A

              \[\leadsto -\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \color{blue}{\frac{\sqrt{2}}{B}} \]
            15. lower-sqrt.f6454.9

              \[\leadsto -\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \frac{\color{blue}{\sqrt{2}}}{B} \]
          5. Applied rewrites54.9%

            \[\leadsto \color{blue}{-\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B}} \]
          6. Step-by-step derivation
            1. Applied rewrites78.3%

              \[\leadsto -\left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{B} \]
          7. Recombined 4 regimes into one program.
          8. Final simplification37.7%

            \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 1.85 \cdot 10^{-132}:\\ \;\;\;\;\frac{\sqrt{C \cdot \mathsf{fma}\left(-16, \left(A \cdot C\right) \cdot F, 4 \cdot \left(\left(B \cdot B\right) \cdot F\right)\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{elif}\;B \leq 1.05 \cdot 10^{-85}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \left(-\sqrt{F}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C}\\ \mathbf{elif}\;B \leq 7.2 \cdot 10^{+59}:\\ \;\;\;\;\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \left(-\sqrt{F}\right)\right) \cdot \frac{\sqrt{2}}{B}\\ \end{array} \]
          9. Add Preprocessing

          Alternative 4: 55.4% accurate, 2.7× speedup?

          \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;B\_m \leq 1.7 \cdot 10^{+60}:\\ \;\;\;\;\frac{\sqrt{C \cdot \mathsf{fma}\left(-16, \left(A \cdot C\right) \cdot F, 4 \cdot \left(\left(B\_m \cdot B\_m\right) \cdot F\right)\right)}}{-\left({B\_m}^{2} - \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{\mathsf{hypot}\left(C, B\_m\right) + C} \cdot \left(-\sqrt{F}\right)\right) \cdot \frac{\sqrt{2}}{B\_m}\\ \end{array} \end{array} \]
          B_m = (fabs.f64 B)
          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
          (FPCore (A B_m C F)
           :precision binary64
           (if (<= B_m 1.7e+60)
             (/
              (sqrt (* C (fma -16.0 (* (* A C) F) (* 4.0 (* (* B_m B_m) F)))))
              (- (- (pow B_m 2.0) (* (* 4.0 A) C))))
             (* (* (sqrt (+ (hypot C B_m) C)) (- (sqrt F))) (/ (sqrt 2.0) B_m))))
          B_m = fabs(B);
          assert(A < B_m && B_m < C && C < F);
          double code(double A, double B_m, double C, double F) {
          	double tmp;
          	if (B_m <= 1.7e+60) {
          		tmp = sqrt((C * fma(-16.0, ((A * C) * F), (4.0 * ((B_m * B_m) * F))))) / -(pow(B_m, 2.0) - ((4.0 * A) * C));
          	} else {
          		tmp = (sqrt((hypot(C, B_m) + C)) * -sqrt(F)) * (sqrt(2.0) / B_m);
          	}
          	return tmp;
          }
          
          B_m = abs(B)
          A, B_m, C, F = sort([A, B_m, C, F])
          function code(A, B_m, C, F)
          	tmp = 0.0
          	if (B_m <= 1.7e+60)
          		tmp = Float64(sqrt(Float64(C * fma(-16.0, Float64(Float64(A * C) * F), Float64(4.0 * Float64(Float64(B_m * B_m) * F))))) / Float64(-Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C))));
          	else
          		tmp = Float64(Float64(sqrt(Float64(hypot(C, B_m) + C)) * Float64(-sqrt(F))) * Float64(sqrt(2.0) / B_m));
          	end
          	return tmp
          end
          
          B_m = N[Abs[B], $MachinePrecision]
          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
          code[A_, B$95$m_, C_, F_] := If[LessEqual[B$95$m, 1.7e+60], N[(N[Sqrt[N[(C * N[(-16.0 * N[(N[(A * C), $MachinePrecision] * F), $MachinePrecision] + N[(4.0 * N[(N[(B$95$m * B$95$m), $MachinePrecision] * F), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision])), $MachinePrecision], N[(N[(N[Sqrt[N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision] * N[(N[Sqrt[2.0], $MachinePrecision] / B$95$m), $MachinePrecision]), $MachinePrecision]]
          
          \begin{array}{l}
          B_m = \left|B\right|
          \\
          [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
          \\
          \begin{array}{l}
          \mathbf{if}\;B\_m \leq 1.7 \cdot 10^{+60}:\\
          \;\;\;\;\frac{\sqrt{C \cdot \mathsf{fma}\left(-16, \left(A \cdot C\right) \cdot F, 4 \cdot \left(\left(B\_m \cdot B\_m\right) \cdot F\right)\right)}}{-\left({B\_m}^{2} - \left(4 \cdot A\right) \cdot C\right)}\\
          
          \mathbf{else}:\\
          \;\;\;\;\left(\sqrt{\mathsf{hypot}\left(C, B\_m\right) + C} \cdot \left(-\sqrt{F}\right)\right) \cdot \frac{\sqrt{2}}{B\_m}\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if B < 1.7e60

            1. Initial program 18.8%

              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            2. Add Preprocessing
            3. Taylor expanded in C around inf

              \[\leadsto \frac{-\sqrt{\color{blue}{{C}^{2} \cdot \left(-16 \cdot \left(A \cdot F\right) + 2 \cdot \frac{F \cdot \left(-4 \cdot \left(A \cdot \left(A + -1 \cdot A\right)\right) + 2 \cdot {B}^{2}\right)}{C}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            4. Step-by-step derivation
              1. *-commutativeN/A

                \[\leadsto \frac{-\sqrt{\color{blue}{\left(-16 \cdot \left(A \cdot F\right) + 2 \cdot \frac{F \cdot \left(-4 \cdot \left(A \cdot \left(A + -1 \cdot A\right)\right) + 2 \cdot {B}^{2}\right)}{C}\right) \cdot {C}^{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              2. lower-*.f64N/A

                \[\leadsto \frac{-\sqrt{\color{blue}{\left(-16 \cdot \left(A \cdot F\right) + 2 \cdot \frac{F \cdot \left(-4 \cdot \left(A \cdot \left(A + -1 \cdot A\right)\right) + 2 \cdot {B}^{2}\right)}{C}\right) \cdot {C}^{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            5. Applied rewrites13.0%

              \[\leadsto \frac{-\sqrt{\color{blue}{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            6. Taylor expanded in C around 0

              \[\leadsto \frac{-\sqrt{C \cdot \color{blue}{\left(-16 \cdot \left(A \cdot \left(C \cdot F\right)\right) + 4 \cdot \left({B}^{2} \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            7. Step-by-step derivation
              1. Applied rewrites19.4%

                \[\leadsto \frac{-\sqrt{C \cdot \color{blue}{\mathsf{fma}\left(-16, \left(A \cdot C\right) \cdot F, 4 \cdot \left(\left(B \cdot B\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

              if 1.7e60 < B

              1. Initial program 14.2%

                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              2. Add Preprocessing
              3. Taylor expanded in A around 0

                \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
              4. Step-by-step derivation
                1. mul-1-negN/A

                  \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                2. lower-neg.f64N/A

                  \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                3. *-commutativeN/A

                  \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}} \]
                4. lower-*.f64N/A

                  \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}} \]
                5. lower-sqrt.f64N/A

                  \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \cdot \frac{\sqrt{2}}{B} \]
                6. *-commutativeN/A

                  \[\leadsto -\sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \cdot \frac{\sqrt{2}}{B} \]
                7. lower-*.f64N/A

                  \[\leadsto -\sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \cdot \frac{\sqrt{2}}{B} \]
                8. +-commutativeN/A

                  \[\leadsto -\sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                9. lower-+.f64N/A

                  \[\leadsto -\sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                10. +-commutativeN/A

                  \[\leadsto -\sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                11. unpow2N/A

                  \[\leadsto -\sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                12. unpow2N/A

                  \[\leadsto -\sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                13. lower-hypot.f64N/A

                  \[\leadsto -\sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                14. lower-/.f64N/A

                  \[\leadsto -\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \color{blue}{\frac{\sqrt{2}}{B}} \]
                15. lower-sqrt.f6455.8

                  \[\leadsto -\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \frac{\color{blue}{\sqrt{2}}}{B} \]
              5. Applied rewrites55.8%

                \[\leadsto \color{blue}{-\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B}} \]
              6. Step-by-step derivation
                1. Applied rewrites79.5%

                  \[\leadsto -\left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{B} \]
              7. Recombined 2 regimes into one program.
              8. Final simplification33.2%

                \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 1.7 \cdot 10^{+60}:\\ \;\;\;\;\frac{\sqrt{C \cdot \mathsf{fma}\left(-16, \left(A \cdot C\right) \cdot F, 4 \cdot \left(\left(B \cdot B\right) \cdot F\right)\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \left(-\sqrt{F}\right)\right) \cdot \frac{\sqrt{2}}{B}\\ \end{array} \]
              9. Add Preprocessing

              Alternative 5: 52.0% accurate, 2.8× speedup?

              \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := -\sqrt{F}\\ \mathbf{if}\;B\_m \leq 3 \cdot 10^{-278}:\\ \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{elif}\;B\_m \leq 2.7 \cdot 10^{-155}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\left(C \cdot C\right) \cdot F\right) \cdot A\right) \cdot -16}}{-\left({B\_m}^{2} - \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{elif}\;B\_m \leq 8 \cdot 10^{+50}:\\ \;\;\;\;\left(t\_0 \cdot \sqrt{\frac{C \cdot 2}{\mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)}}\right) \cdot \sqrt{2}\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{\mathsf{hypot}\left(C, B\_m\right) + C} \cdot t\_0\right) \cdot \frac{\sqrt{2}}{B\_m}\\ \end{array} \end{array} \]
              B_m = (fabs.f64 B)
              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
              (FPCore (A B_m C F)
               :precision binary64
               (let* ((t_0 (- (sqrt F))))
                 (if (<= B_m 3e-278)
                   (* (sqrt (* -0.5 (/ F A))) (- (sqrt 2.0)))
                   (if (<= B_m 2.7e-155)
                     (/
                      (sqrt (* (* (* (* C C) F) A) -16.0))
                      (- (- (pow B_m 2.0) (* (* 4.0 A) C))))
                     (if (<= B_m 8e+50)
                       (*
                        (* t_0 (sqrt (/ (* C 2.0) (fma -4.0 (* C A) (* B_m B_m)))))
                        (sqrt 2.0))
                       (* (* (sqrt (+ (hypot C B_m) C)) t_0) (/ (sqrt 2.0) B_m)))))))
              B_m = fabs(B);
              assert(A < B_m && B_m < C && C < F);
              double code(double A, double B_m, double C, double F) {
              	double t_0 = -sqrt(F);
              	double tmp;
              	if (B_m <= 3e-278) {
              		tmp = sqrt((-0.5 * (F / A))) * -sqrt(2.0);
              	} else if (B_m <= 2.7e-155) {
              		tmp = sqrt(((((C * C) * F) * A) * -16.0)) / -(pow(B_m, 2.0) - ((4.0 * A) * C));
              	} else if (B_m <= 8e+50) {
              		tmp = (t_0 * sqrt(((C * 2.0) / fma(-4.0, (C * A), (B_m * B_m))))) * sqrt(2.0);
              	} else {
              		tmp = (sqrt((hypot(C, B_m) + C)) * t_0) * (sqrt(2.0) / B_m);
              	}
              	return tmp;
              }
              
              B_m = abs(B)
              A, B_m, C, F = sort([A, B_m, C, F])
              function code(A, B_m, C, F)
              	t_0 = Float64(-sqrt(F))
              	tmp = 0.0
              	if (B_m <= 3e-278)
              		tmp = Float64(sqrt(Float64(-0.5 * Float64(F / A))) * Float64(-sqrt(2.0)));
              	elseif (B_m <= 2.7e-155)
              		tmp = Float64(sqrt(Float64(Float64(Float64(Float64(C * C) * F) * A) * -16.0)) / Float64(-Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C))));
              	elseif (B_m <= 8e+50)
              		tmp = Float64(Float64(t_0 * sqrt(Float64(Float64(C * 2.0) / fma(-4.0, Float64(C * A), Float64(B_m * B_m))))) * sqrt(2.0));
              	else
              		tmp = Float64(Float64(sqrt(Float64(hypot(C, B_m) + C)) * t_0) * Float64(sqrt(2.0) / B_m));
              	end
              	return tmp
              end
              
              B_m = N[Abs[B], $MachinePrecision]
              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
              code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = (-N[Sqrt[F], $MachinePrecision])}, If[LessEqual[B$95$m, 3e-278], N[(N[Sqrt[N[(-0.5 * N[(F / A), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[2.0], $MachinePrecision])), $MachinePrecision], If[LessEqual[B$95$m, 2.7e-155], N[(N[Sqrt[N[(N[(N[(N[(C * C), $MachinePrecision] * F), $MachinePrecision] * A), $MachinePrecision] * -16.0), $MachinePrecision]], $MachinePrecision] / (-N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision])), $MachinePrecision], If[LessEqual[B$95$m, 8e+50], N[(N[(t$95$0 * N[Sqrt[N[(N[(C * 2.0), $MachinePrecision] / N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] * t$95$0), $MachinePrecision] * N[(N[Sqrt[2.0], $MachinePrecision] / B$95$m), $MachinePrecision]), $MachinePrecision]]]]]
              
              \begin{array}{l}
              B_m = \left|B\right|
              \\
              [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
              \\
              \begin{array}{l}
              t_0 := -\sqrt{F}\\
              \mathbf{if}\;B\_m \leq 3 \cdot 10^{-278}:\\
              \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\
              
              \mathbf{elif}\;B\_m \leq 2.7 \cdot 10^{-155}:\\
              \;\;\;\;\frac{\sqrt{\left(\left(\left(C \cdot C\right) \cdot F\right) \cdot A\right) \cdot -16}}{-\left({B\_m}^{2} - \left(4 \cdot A\right) \cdot C\right)}\\
              
              \mathbf{elif}\;B\_m \leq 8 \cdot 10^{+50}:\\
              \;\;\;\;\left(t\_0 \cdot \sqrt{\frac{C \cdot 2}{\mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)}}\right) \cdot \sqrt{2}\\
              
              \mathbf{else}:\\
              \;\;\;\;\left(\sqrt{\mathsf{hypot}\left(C, B\_m\right) + C} \cdot t\_0\right) \cdot \frac{\sqrt{2}}{B\_m}\\
              
              
              \end{array}
              \end{array}
              
              Derivation
              1. Split input into 4 regimes
              2. if B < 3e-278

                1. Initial program 15.9%

                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                2. Add Preprocessing
                3. Taylor expanded in F around 0

                  \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                4. Step-by-step derivation
                  1. mul-1-negN/A

                    \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                  2. lower-neg.f64N/A

                    \[\leadsto \color{blue}{-\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}} \]
                  3. lower-*.f64N/A

                    \[\leadsto -\color{blue}{\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}} \]
                5. Applied rewrites19.0%

                  \[\leadsto \color{blue}{-\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \cdot \sqrt{2}} \]
                6. Taylor expanded in A around -inf

                  \[\leadsto -\sqrt{\frac{-1}{2} \cdot \frac{F}{A}} \cdot \sqrt{2} \]
                7. Step-by-step derivation
                  1. Applied rewrites14.8%

                    \[\leadsto -\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \sqrt{2} \]

                  if 3e-278 < B < 2.69999999999999981e-155

                  1. Initial program 27.8%

                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  2. Add Preprocessing
                  3. Taylor expanded in A around -inf

                    \[\leadsto \frac{-\sqrt{\color{blue}{-16 \cdot \left(A \cdot \left({C}^{2} \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  4. Step-by-step derivation
                    1. *-commutativeN/A

                      \[\leadsto \frac{-\sqrt{\color{blue}{\left(A \cdot \left({C}^{2} \cdot F\right)\right) \cdot -16}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    2. lower-*.f64N/A

                      \[\leadsto \frac{-\sqrt{\color{blue}{\left(A \cdot \left({C}^{2} \cdot F\right)\right) \cdot -16}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    3. *-commutativeN/A

                      \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left({C}^{2} \cdot F\right) \cdot A\right)} \cdot -16}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    4. lower-*.f64N/A

                      \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left({C}^{2} \cdot F\right) \cdot A\right)} \cdot -16}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    5. lower-*.f64N/A

                      \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left({C}^{2} \cdot F\right)} \cdot A\right) \cdot -16}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    6. unpow2N/A

                      \[\leadsto \frac{-\sqrt{\left(\left(\color{blue}{\left(C \cdot C\right)} \cdot F\right) \cdot A\right) \cdot -16}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    7. lower-*.f6428.1

                      \[\leadsto \frac{-\sqrt{\left(\left(\color{blue}{\left(C \cdot C\right)} \cdot F\right) \cdot A\right) \cdot -16}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  5. Applied rewrites28.1%

                    \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(\left(C \cdot C\right) \cdot F\right) \cdot A\right) \cdot -16}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

                  if 2.69999999999999981e-155 < B < 8.0000000000000006e50

                  1. Initial program 23.0%

                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  2. Add Preprocessing
                  3. Taylor expanded in F around 0

                    \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                  4. Step-by-step derivation
                    1. mul-1-negN/A

                      \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                    2. lower-neg.f64N/A

                      \[\leadsto \color{blue}{-\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}} \]
                    3. lower-*.f64N/A

                      \[\leadsto -\color{blue}{\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}} \]
                  5. Applied rewrites27.4%

                    \[\leadsto \color{blue}{-\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \cdot \sqrt{2}} \]
                  6. Taylor expanded in A around -inf

                    \[\leadsto -\sqrt{\frac{\left(2 \cdot C\right) \cdot F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \cdot \sqrt{2} \]
                  7. Step-by-step derivation
                    1. Applied rewrites9.1%

                      \[\leadsto -\sqrt{\frac{\left(2 \cdot C\right) \cdot F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \cdot \sqrt{2} \]
                    2. Step-by-step derivation
                      1. Applied rewrites25.3%

                        \[\leadsto -\left(\sqrt{F} \cdot \sqrt{\frac{C \cdot 2}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}\right) \cdot \sqrt{2} \]

                      if 8.0000000000000006e50 < B

                      1. Initial program 15.4%

                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      2. Add Preprocessing
                      3. Taylor expanded in A around 0

                        \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                      4. Step-by-step derivation
                        1. mul-1-negN/A

                          \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                        2. lower-neg.f64N/A

                          \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                        3. *-commutativeN/A

                          \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}} \]
                        4. lower-*.f64N/A

                          \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}} \]
                        5. lower-sqrt.f64N/A

                          \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \cdot \frac{\sqrt{2}}{B} \]
                        6. *-commutativeN/A

                          \[\leadsto -\sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \cdot \frac{\sqrt{2}}{B} \]
                        7. lower-*.f64N/A

                          \[\leadsto -\sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \cdot \frac{\sqrt{2}}{B} \]
                        8. +-commutativeN/A

                          \[\leadsto -\sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                        9. lower-+.f64N/A

                          \[\leadsto -\sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                        10. +-commutativeN/A

                          \[\leadsto -\sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                        11. unpow2N/A

                          \[\leadsto -\sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                        12. unpow2N/A

                          \[\leadsto -\sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                        13. lower-hypot.f64N/A

                          \[\leadsto -\sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                        14. lower-/.f64N/A

                          \[\leadsto -\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \color{blue}{\frac{\sqrt{2}}{B}} \]
                        15. lower-sqrt.f6455.7

                          \[\leadsto -\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \frac{\color{blue}{\sqrt{2}}}{B} \]
                      5. Applied rewrites55.7%

                        \[\leadsto \color{blue}{-\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B}} \]
                      6. Step-by-step derivation
                        1. Applied rewrites78.6%

                          \[\leadsto -\left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{B} \]
                      7. Recombined 4 regimes into one program.
                      8. Final simplification32.7%

                        \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 3 \cdot 10^{-278}:\\ \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{elif}\;B \leq 2.7 \cdot 10^{-155}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\left(C \cdot C\right) \cdot F\right) \cdot A\right) \cdot -16}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{elif}\;B \leq 8 \cdot 10^{+50}:\\ \;\;\;\;\left(\left(-\sqrt{F}\right) \cdot \sqrt{\frac{C \cdot 2}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}\right) \cdot \sqrt{2}\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \left(-\sqrt{F}\right)\right) \cdot \frac{\sqrt{2}}{B}\\ \end{array} \]
                      9. Add Preprocessing

                      Alternative 6: 52.0% accurate, 2.8× speedup?

                      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := -\sqrt{F}\\ \mathbf{if}\;B\_m \leq 8.4 \cdot 10^{-280}:\\ \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{elif}\;B\_m \leq 2.35 \cdot 10^{-155}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(0, -4, \left(B\_m \cdot B\_m\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{-\mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(A \cdot C\right)\right)}\\ \mathbf{elif}\;B\_m \leq 8 \cdot 10^{+50}:\\ \;\;\;\;\left(t\_0 \cdot \sqrt{\frac{C \cdot 2}{\mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)}}\right) \cdot \sqrt{2}\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{\mathsf{hypot}\left(C, B\_m\right) + C} \cdot t\_0\right) \cdot \frac{\sqrt{2}}{B\_m}\\ \end{array} \end{array} \]
                      B_m = (fabs.f64 B)
                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                      (FPCore (A B_m C F)
                       :precision binary64
                       (let* ((t_0 (- (sqrt F))))
                         (if (<= B_m 8.4e-280)
                           (* (sqrt (* -0.5 (/ F A))) (- (sqrt 2.0)))
                           (if (<= B_m 2.35e-155)
                             (/
                              (sqrt
                               (*
                                (fma
                                 (/ (* (fma 0.0 -4.0 (* (* B_m B_m) 2.0)) F) C)
                                 2.0
                                 (* (* F A) -16.0))
                                (* C C)))
                              (- (fma B_m B_m (* -4.0 (* A C)))))
                             (if (<= B_m 8e+50)
                               (*
                                (* t_0 (sqrt (/ (* C 2.0) (fma -4.0 (* C A) (* B_m B_m)))))
                                (sqrt 2.0))
                               (* (* (sqrt (+ (hypot C B_m) C)) t_0) (/ (sqrt 2.0) B_m)))))))
                      B_m = fabs(B);
                      assert(A < B_m && B_m < C && C < F);
                      double code(double A, double B_m, double C, double F) {
                      	double t_0 = -sqrt(F);
                      	double tmp;
                      	if (B_m <= 8.4e-280) {
                      		tmp = sqrt((-0.5 * (F / A))) * -sqrt(2.0);
                      	} else if (B_m <= 2.35e-155) {
                      		tmp = sqrt((fma(((fma(0.0, -4.0, ((B_m * B_m) * 2.0)) * F) / C), 2.0, ((F * A) * -16.0)) * (C * C))) / -fma(B_m, B_m, (-4.0 * (A * C)));
                      	} else if (B_m <= 8e+50) {
                      		tmp = (t_0 * sqrt(((C * 2.0) / fma(-4.0, (C * A), (B_m * B_m))))) * sqrt(2.0);
                      	} else {
                      		tmp = (sqrt((hypot(C, B_m) + C)) * t_0) * (sqrt(2.0) / B_m);
                      	}
                      	return tmp;
                      }
                      
                      B_m = abs(B)
                      A, B_m, C, F = sort([A, B_m, C, F])
                      function code(A, B_m, C, F)
                      	t_0 = Float64(-sqrt(F))
                      	tmp = 0.0
                      	if (B_m <= 8.4e-280)
                      		tmp = Float64(sqrt(Float64(-0.5 * Float64(F / A))) * Float64(-sqrt(2.0)));
                      	elseif (B_m <= 2.35e-155)
                      		tmp = Float64(sqrt(Float64(fma(Float64(Float64(fma(0.0, -4.0, Float64(Float64(B_m * B_m) * 2.0)) * F) / C), 2.0, Float64(Float64(F * A) * -16.0)) * Float64(C * C))) / Float64(-fma(B_m, B_m, Float64(-4.0 * Float64(A * C)))));
                      	elseif (B_m <= 8e+50)
                      		tmp = Float64(Float64(t_0 * sqrt(Float64(Float64(C * 2.0) / fma(-4.0, Float64(C * A), Float64(B_m * B_m))))) * sqrt(2.0));
                      	else
                      		tmp = Float64(Float64(sqrt(Float64(hypot(C, B_m) + C)) * t_0) * Float64(sqrt(2.0) / B_m));
                      	end
                      	return tmp
                      end
                      
                      B_m = N[Abs[B], $MachinePrecision]
                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                      code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = (-N[Sqrt[F], $MachinePrecision])}, If[LessEqual[B$95$m, 8.4e-280], N[(N[Sqrt[N[(-0.5 * N[(F / A), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[2.0], $MachinePrecision])), $MachinePrecision], If[LessEqual[B$95$m, 2.35e-155], N[(N[Sqrt[N[(N[(N[(N[(N[(0.0 * -4.0 + N[(N[(B$95$m * B$95$m), $MachinePrecision] * 2.0), $MachinePrecision]), $MachinePrecision] * F), $MachinePrecision] / C), $MachinePrecision] * 2.0 + N[(N[(F * A), $MachinePrecision] * -16.0), $MachinePrecision]), $MachinePrecision] * N[(C * C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-N[(B$95$m * B$95$m + N[(-4.0 * N[(A * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision])), $MachinePrecision], If[LessEqual[B$95$m, 8e+50], N[(N[(t$95$0 * N[Sqrt[N[(N[(C * 2.0), $MachinePrecision] / N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] * t$95$0), $MachinePrecision] * N[(N[Sqrt[2.0], $MachinePrecision] / B$95$m), $MachinePrecision]), $MachinePrecision]]]]]
                      
                      \begin{array}{l}
                      B_m = \left|B\right|
                      \\
                      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                      \\
                      \begin{array}{l}
                      t_0 := -\sqrt{F}\\
                      \mathbf{if}\;B\_m \leq 8.4 \cdot 10^{-280}:\\
                      \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\
                      
                      \mathbf{elif}\;B\_m \leq 2.35 \cdot 10^{-155}:\\
                      \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(0, -4, \left(B\_m \cdot B\_m\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{-\mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(A \cdot C\right)\right)}\\
                      
                      \mathbf{elif}\;B\_m \leq 8 \cdot 10^{+50}:\\
                      \;\;\;\;\left(t\_0 \cdot \sqrt{\frac{C \cdot 2}{\mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)}}\right) \cdot \sqrt{2}\\
                      
                      \mathbf{else}:\\
                      \;\;\;\;\left(\sqrt{\mathsf{hypot}\left(C, B\_m\right) + C} \cdot t\_0\right) \cdot \frac{\sqrt{2}}{B\_m}\\
                      
                      
                      \end{array}
                      \end{array}
                      
                      Derivation
                      1. Split input into 4 regimes
                      2. if B < 8.40000000000000003e-280

                        1. Initial program 15.9%

                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        2. Add Preprocessing
                        3. Taylor expanded in F around 0

                          \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                        4. Step-by-step derivation
                          1. mul-1-negN/A

                            \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                          2. lower-neg.f64N/A

                            \[\leadsto \color{blue}{-\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}} \]
                          3. lower-*.f64N/A

                            \[\leadsto -\color{blue}{\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}} \]
                        5. Applied rewrites19.0%

                          \[\leadsto \color{blue}{-\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \cdot \sqrt{2}} \]
                        6. Taylor expanded in A around -inf

                          \[\leadsto -\sqrt{\frac{-1}{2} \cdot \frac{F}{A}} \cdot \sqrt{2} \]
                        7. Step-by-step derivation
                          1. Applied rewrites14.8%

                            \[\leadsto -\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \sqrt{2} \]

                          if 8.40000000000000003e-280 < B < 2.3499999999999999e-155

                          1. Initial program 27.8%

                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          2. Add Preprocessing
                          3. Taylor expanded in C around inf

                            \[\leadsto \frac{-\sqrt{\color{blue}{{C}^{2} \cdot \left(-16 \cdot \left(A \cdot F\right) + 2 \cdot \frac{F \cdot \left(-4 \cdot \left(A \cdot \left(A + -1 \cdot A\right)\right) + 2 \cdot {B}^{2}\right)}{C}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          4. Step-by-step derivation
                            1. *-commutativeN/A

                              \[\leadsto \frac{-\sqrt{\color{blue}{\left(-16 \cdot \left(A \cdot F\right) + 2 \cdot \frac{F \cdot \left(-4 \cdot \left(A \cdot \left(A + -1 \cdot A\right)\right) + 2 \cdot {B}^{2}\right)}{C}\right) \cdot {C}^{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            2. lower-*.f64N/A

                              \[\leadsto \frac{-\sqrt{\color{blue}{\left(-16 \cdot \left(A \cdot F\right) + 2 \cdot \frac{F \cdot \left(-4 \cdot \left(A \cdot \left(A + -1 \cdot A\right)\right) + 2 \cdot {B}^{2}\right)}{C}\right) \cdot {C}^{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          5. Applied rewrites23.3%

                            \[\leadsto \frac{-\sqrt{\color{blue}{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          6. Taylor expanded in B around 0

                            \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{\color{blue}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \]
                          7. Step-by-step derivation
                            1. fp-cancel-sub-sign-invN/A

                              \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{\color{blue}{{B}^{2} + \left(\mathsf{neg}\left(4\right)\right) \cdot \left(A \cdot C\right)}} \]
                            2. unpow2N/A

                              \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{\color{blue}{B \cdot B} + \left(\mathsf{neg}\left(4\right)\right) \cdot \left(A \cdot C\right)} \]
                            3. metadata-evalN/A

                              \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{B \cdot B + \color{blue}{-4} \cdot \left(A \cdot C\right)} \]
                            4. lower-fma.f64N/A

                              \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{\color{blue}{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}} \]
                            5. lower-*.f64N/A

                              \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{\mathsf{fma}\left(B, B, \color{blue}{-4 \cdot \left(A \cdot C\right)}\right)} \]
                            6. lower-*.f6423.3

                              \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{\mathsf{fma}\left(B, B, -4 \cdot \color{blue}{\left(A \cdot C\right)}\right)} \]
                          8. Applied rewrites23.3%

                            \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{\color{blue}{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}} \]

                          if 2.3499999999999999e-155 < B < 8.0000000000000006e50

                          1. Initial program 23.0%

                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          2. Add Preprocessing
                          3. Taylor expanded in F around 0

                            \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                          4. Step-by-step derivation
                            1. mul-1-negN/A

                              \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                            2. lower-neg.f64N/A

                              \[\leadsto \color{blue}{-\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}} \]
                            3. lower-*.f64N/A

                              \[\leadsto -\color{blue}{\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}} \]
                          5. Applied rewrites27.4%

                            \[\leadsto \color{blue}{-\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \cdot \sqrt{2}} \]
                          6. Taylor expanded in A around -inf

                            \[\leadsto -\sqrt{\frac{\left(2 \cdot C\right) \cdot F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \cdot \sqrt{2} \]
                          7. Step-by-step derivation
                            1. Applied rewrites9.1%

                              \[\leadsto -\sqrt{\frac{\left(2 \cdot C\right) \cdot F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \cdot \sqrt{2} \]
                            2. Step-by-step derivation
                              1. Applied rewrites25.3%

                                \[\leadsto -\left(\sqrt{F} \cdot \sqrt{\frac{C \cdot 2}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}\right) \cdot \sqrt{2} \]

                              if 8.0000000000000006e50 < B

                              1. Initial program 15.4%

                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              2. Add Preprocessing
                              3. Taylor expanded in A around 0

                                \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                              4. Step-by-step derivation
                                1. mul-1-negN/A

                                  \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                2. lower-neg.f64N/A

                                  \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                3. *-commutativeN/A

                                  \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}} \]
                                4. lower-*.f64N/A

                                  \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}} \]
                                5. lower-sqrt.f64N/A

                                  \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \cdot \frac{\sqrt{2}}{B} \]
                                6. *-commutativeN/A

                                  \[\leadsto -\sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \cdot \frac{\sqrt{2}}{B} \]
                                7. lower-*.f64N/A

                                  \[\leadsto -\sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \cdot \frac{\sqrt{2}}{B} \]
                                8. +-commutativeN/A

                                  \[\leadsto -\sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                9. lower-+.f64N/A

                                  \[\leadsto -\sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                10. +-commutativeN/A

                                  \[\leadsto -\sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                11. unpow2N/A

                                  \[\leadsto -\sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                12. unpow2N/A

                                  \[\leadsto -\sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                13. lower-hypot.f64N/A

                                  \[\leadsto -\sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                14. lower-/.f64N/A

                                  \[\leadsto -\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \color{blue}{\frac{\sqrt{2}}{B}} \]
                                15. lower-sqrt.f6455.7

                                  \[\leadsto -\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \frac{\color{blue}{\sqrt{2}}}{B} \]
                              5. Applied rewrites55.7%

                                \[\leadsto \color{blue}{-\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B}} \]
                              6. Step-by-step derivation
                                1. Applied rewrites78.6%

                                  \[\leadsto -\left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{B} \]
                              7. Recombined 4 regimes into one program.
                              8. Final simplification32.3%

                                \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 8.4 \cdot 10^{-280}:\\ \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{elif}\;B \leq 2.35 \cdot 10^{-155}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(0, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{-\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}\\ \mathbf{elif}\;B \leq 8 \cdot 10^{+50}:\\ \;\;\;\;\left(\left(-\sqrt{F}\right) \cdot \sqrt{\frac{C \cdot 2}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}\right) \cdot \sqrt{2}\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \left(-\sqrt{F}\right)\right) \cdot \frac{\sqrt{2}}{B}\\ \end{array} \]
                              9. Add Preprocessing

                              Alternative 7: 50.8% accurate, 2.9× speedup?

                              \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := -\sqrt{F}\\ \mathbf{if}\;B\_m \leq 8.4 \cdot 10^{-280}:\\ \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{elif}\;B\_m \leq 2.35 \cdot 10^{-155}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(0, -4, \left(B\_m \cdot B\_m\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{-\mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(A \cdot C\right)\right)}\\ \mathbf{elif}\;B\_m \leq 8 \cdot 10^{+50}:\\ \;\;\;\;\left(t\_0 \cdot \sqrt{\frac{C \cdot 2}{\mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)}}\right) \cdot \sqrt{2}\\ \mathbf{elif}\;B\_m \leq 1.8 \cdot 10^{+206}:\\ \;\;\;\;\sqrt{\mathsf{hypot}\left(C, B\_m\right) + C} \cdot \frac{\sqrt{F \cdot 2}}{-B\_m}\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{B\_m + C} \cdot t\_0\right) \cdot \frac{\sqrt{2}}{B\_m}\\ \end{array} \end{array} \]
                              B_m = (fabs.f64 B)
                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                              (FPCore (A B_m C F)
                               :precision binary64
                               (let* ((t_0 (- (sqrt F))))
                                 (if (<= B_m 8.4e-280)
                                   (* (sqrt (* -0.5 (/ F A))) (- (sqrt 2.0)))
                                   (if (<= B_m 2.35e-155)
                                     (/
                                      (sqrt
                                       (*
                                        (fma
                                         (/ (* (fma 0.0 -4.0 (* (* B_m B_m) 2.0)) F) C)
                                         2.0
                                         (* (* F A) -16.0))
                                        (* C C)))
                                      (- (fma B_m B_m (* -4.0 (* A C)))))
                                     (if (<= B_m 8e+50)
                                       (*
                                        (* t_0 (sqrt (/ (* C 2.0) (fma -4.0 (* C A) (* B_m B_m)))))
                                        (sqrt 2.0))
                                       (if (<= B_m 1.8e+206)
                                         (* (sqrt (+ (hypot C B_m) C)) (/ (sqrt (* F 2.0)) (- B_m)))
                                         (* (* (sqrt (+ B_m C)) t_0) (/ (sqrt 2.0) B_m))))))))
                              B_m = fabs(B);
                              assert(A < B_m && B_m < C && C < F);
                              double code(double A, double B_m, double C, double F) {
                              	double t_0 = -sqrt(F);
                              	double tmp;
                              	if (B_m <= 8.4e-280) {
                              		tmp = sqrt((-0.5 * (F / A))) * -sqrt(2.0);
                              	} else if (B_m <= 2.35e-155) {
                              		tmp = sqrt((fma(((fma(0.0, -4.0, ((B_m * B_m) * 2.0)) * F) / C), 2.0, ((F * A) * -16.0)) * (C * C))) / -fma(B_m, B_m, (-4.0 * (A * C)));
                              	} else if (B_m <= 8e+50) {
                              		tmp = (t_0 * sqrt(((C * 2.0) / fma(-4.0, (C * A), (B_m * B_m))))) * sqrt(2.0);
                              	} else if (B_m <= 1.8e+206) {
                              		tmp = sqrt((hypot(C, B_m) + C)) * (sqrt((F * 2.0)) / -B_m);
                              	} else {
                              		tmp = (sqrt((B_m + C)) * t_0) * (sqrt(2.0) / B_m);
                              	}
                              	return tmp;
                              }
                              
                              B_m = abs(B)
                              A, B_m, C, F = sort([A, B_m, C, F])
                              function code(A, B_m, C, F)
                              	t_0 = Float64(-sqrt(F))
                              	tmp = 0.0
                              	if (B_m <= 8.4e-280)
                              		tmp = Float64(sqrt(Float64(-0.5 * Float64(F / A))) * Float64(-sqrt(2.0)));
                              	elseif (B_m <= 2.35e-155)
                              		tmp = Float64(sqrt(Float64(fma(Float64(Float64(fma(0.0, -4.0, Float64(Float64(B_m * B_m) * 2.0)) * F) / C), 2.0, Float64(Float64(F * A) * -16.0)) * Float64(C * C))) / Float64(-fma(B_m, B_m, Float64(-4.0 * Float64(A * C)))));
                              	elseif (B_m <= 8e+50)
                              		tmp = Float64(Float64(t_0 * sqrt(Float64(Float64(C * 2.0) / fma(-4.0, Float64(C * A), Float64(B_m * B_m))))) * sqrt(2.0));
                              	elseif (B_m <= 1.8e+206)
                              		tmp = Float64(sqrt(Float64(hypot(C, B_m) + C)) * Float64(sqrt(Float64(F * 2.0)) / Float64(-B_m)));
                              	else
                              		tmp = Float64(Float64(sqrt(Float64(B_m + C)) * t_0) * Float64(sqrt(2.0) / B_m));
                              	end
                              	return tmp
                              end
                              
                              B_m = N[Abs[B], $MachinePrecision]
                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                              code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = (-N[Sqrt[F], $MachinePrecision])}, If[LessEqual[B$95$m, 8.4e-280], N[(N[Sqrt[N[(-0.5 * N[(F / A), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[2.0], $MachinePrecision])), $MachinePrecision], If[LessEqual[B$95$m, 2.35e-155], N[(N[Sqrt[N[(N[(N[(N[(N[(0.0 * -4.0 + N[(N[(B$95$m * B$95$m), $MachinePrecision] * 2.0), $MachinePrecision]), $MachinePrecision] * F), $MachinePrecision] / C), $MachinePrecision] * 2.0 + N[(N[(F * A), $MachinePrecision] * -16.0), $MachinePrecision]), $MachinePrecision] * N[(C * C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-N[(B$95$m * B$95$m + N[(-4.0 * N[(A * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision])), $MachinePrecision], If[LessEqual[B$95$m, 8e+50], N[(N[(t$95$0 * N[Sqrt[N[(N[(C * 2.0), $MachinePrecision] / N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision], If[LessEqual[B$95$m, 1.8e+206], N[(N[Sqrt[N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(B$95$m + C), $MachinePrecision]], $MachinePrecision] * t$95$0), $MachinePrecision] * N[(N[Sqrt[2.0], $MachinePrecision] / B$95$m), $MachinePrecision]), $MachinePrecision]]]]]]
                              
                              \begin{array}{l}
                              B_m = \left|B\right|
                              \\
                              [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                              \\
                              \begin{array}{l}
                              t_0 := -\sqrt{F}\\
                              \mathbf{if}\;B\_m \leq 8.4 \cdot 10^{-280}:\\
                              \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\
                              
                              \mathbf{elif}\;B\_m \leq 2.35 \cdot 10^{-155}:\\
                              \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(0, -4, \left(B\_m \cdot B\_m\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{-\mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(A \cdot C\right)\right)}\\
                              
                              \mathbf{elif}\;B\_m \leq 8 \cdot 10^{+50}:\\
                              \;\;\;\;\left(t\_0 \cdot \sqrt{\frac{C \cdot 2}{\mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)}}\right) \cdot \sqrt{2}\\
                              
                              \mathbf{elif}\;B\_m \leq 1.8 \cdot 10^{+206}:\\
                              \;\;\;\;\sqrt{\mathsf{hypot}\left(C, B\_m\right) + C} \cdot \frac{\sqrt{F \cdot 2}}{-B\_m}\\
                              
                              \mathbf{else}:\\
                              \;\;\;\;\left(\sqrt{B\_m + C} \cdot t\_0\right) \cdot \frac{\sqrt{2}}{B\_m}\\
                              
                              
                              \end{array}
                              \end{array}
                              
                              Derivation
                              1. Split input into 5 regimes
                              2. if B < 8.40000000000000003e-280

                                1. Initial program 15.9%

                                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                2. Add Preprocessing
                                3. Taylor expanded in F around 0

                                  \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                4. Step-by-step derivation
                                  1. mul-1-negN/A

                                    \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                  2. lower-neg.f64N/A

                                    \[\leadsto \color{blue}{-\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}} \]
                                  3. lower-*.f64N/A

                                    \[\leadsto -\color{blue}{\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}} \]
                                5. Applied rewrites19.0%

                                  \[\leadsto \color{blue}{-\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \cdot \sqrt{2}} \]
                                6. Taylor expanded in A around -inf

                                  \[\leadsto -\sqrt{\frac{-1}{2} \cdot \frac{F}{A}} \cdot \sqrt{2} \]
                                7. Step-by-step derivation
                                  1. Applied rewrites14.8%

                                    \[\leadsto -\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \sqrt{2} \]

                                  if 8.40000000000000003e-280 < B < 2.3499999999999999e-155

                                  1. Initial program 27.8%

                                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in C around inf

                                    \[\leadsto \frac{-\sqrt{\color{blue}{{C}^{2} \cdot \left(-16 \cdot \left(A \cdot F\right) + 2 \cdot \frac{F \cdot \left(-4 \cdot \left(A \cdot \left(A + -1 \cdot A\right)\right) + 2 \cdot {B}^{2}\right)}{C}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                  4. Step-by-step derivation
                                    1. *-commutativeN/A

                                      \[\leadsto \frac{-\sqrt{\color{blue}{\left(-16 \cdot \left(A \cdot F\right) + 2 \cdot \frac{F \cdot \left(-4 \cdot \left(A \cdot \left(A + -1 \cdot A\right)\right) + 2 \cdot {B}^{2}\right)}{C}\right) \cdot {C}^{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    2. lower-*.f64N/A

                                      \[\leadsto \frac{-\sqrt{\color{blue}{\left(-16 \cdot \left(A \cdot F\right) + 2 \cdot \frac{F \cdot \left(-4 \cdot \left(A \cdot \left(A + -1 \cdot A\right)\right) + 2 \cdot {B}^{2}\right)}{C}\right) \cdot {C}^{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                  5. Applied rewrites23.3%

                                    \[\leadsto \frac{-\sqrt{\color{blue}{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                  6. Taylor expanded in B around 0

                                    \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{\color{blue}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \]
                                  7. Step-by-step derivation
                                    1. fp-cancel-sub-sign-invN/A

                                      \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{\color{blue}{{B}^{2} + \left(\mathsf{neg}\left(4\right)\right) \cdot \left(A \cdot C\right)}} \]
                                    2. unpow2N/A

                                      \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{\color{blue}{B \cdot B} + \left(\mathsf{neg}\left(4\right)\right) \cdot \left(A \cdot C\right)} \]
                                    3. metadata-evalN/A

                                      \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{B \cdot B + \color{blue}{-4} \cdot \left(A \cdot C\right)} \]
                                    4. lower-fma.f64N/A

                                      \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{\color{blue}{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}} \]
                                    5. lower-*.f64N/A

                                      \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{\mathsf{fma}\left(B, B, \color{blue}{-4 \cdot \left(A \cdot C\right)}\right)} \]
                                    6. lower-*.f6423.3

                                      \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{\mathsf{fma}\left(B, B, -4 \cdot \color{blue}{\left(A \cdot C\right)}\right)} \]
                                  8. Applied rewrites23.3%

                                    \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{\color{blue}{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}} \]

                                  if 2.3499999999999999e-155 < B < 8.0000000000000006e50

                                  1. Initial program 23.0%

                                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in F around 0

                                    \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                  4. Step-by-step derivation
                                    1. mul-1-negN/A

                                      \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                    2. lower-neg.f64N/A

                                      \[\leadsto \color{blue}{-\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}} \]
                                    3. lower-*.f64N/A

                                      \[\leadsto -\color{blue}{\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}} \]
                                  5. Applied rewrites27.4%

                                    \[\leadsto \color{blue}{-\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \cdot \sqrt{2}} \]
                                  6. Taylor expanded in A around -inf

                                    \[\leadsto -\sqrt{\frac{\left(2 \cdot C\right) \cdot F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \cdot \sqrt{2} \]
                                  7. Step-by-step derivation
                                    1. Applied rewrites9.1%

                                      \[\leadsto -\sqrt{\frac{\left(2 \cdot C\right) \cdot F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \cdot \sqrt{2} \]
                                    2. Step-by-step derivation
                                      1. Applied rewrites25.3%

                                        \[\leadsto -\left(\sqrt{F} \cdot \sqrt{\frac{C \cdot 2}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}\right) \cdot \sqrt{2} \]

                                      if 8.0000000000000006e50 < B < 1.80000000000000014e206

                                      1. Initial program 24.8%

                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                      2. Add Preprocessing
                                      3. Taylor expanded in A around 0

                                        \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                      4. Step-by-step derivation
                                        1. mul-1-negN/A

                                          \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                        2. lower-neg.f64N/A

                                          \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                        3. *-commutativeN/A

                                          \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}} \]
                                        4. lower-*.f64N/A

                                          \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}} \]
                                        5. lower-sqrt.f64N/A

                                          \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \cdot \frac{\sqrt{2}}{B} \]
                                        6. *-commutativeN/A

                                          \[\leadsto -\sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \cdot \frac{\sqrt{2}}{B} \]
                                        7. lower-*.f64N/A

                                          \[\leadsto -\sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \cdot \frac{\sqrt{2}}{B} \]
                                        8. +-commutativeN/A

                                          \[\leadsto -\sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                        9. lower-+.f64N/A

                                          \[\leadsto -\sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                        10. +-commutativeN/A

                                          \[\leadsto -\sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                        11. unpow2N/A

                                          \[\leadsto -\sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                        12. unpow2N/A

                                          \[\leadsto -\sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                        13. lower-hypot.f64N/A

                                          \[\leadsto -\sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                        14. lower-/.f64N/A

                                          \[\leadsto -\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \color{blue}{\frac{\sqrt{2}}{B}} \]
                                        15. lower-sqrt.f6454.6

                                          \[\leadsto -\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \frac{\color{blue}{\sqrt{2}}}{B} \]
                                      5. Applied rewrites54.6%

                                        \[\leadsto \color{blue}{-\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B}} \]
                                      6. Step-by-step derivation
                                        1. Applied rewrites72.3%

                                          \[\leadsto -\left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{B} \]
                                        2. Step-by-step derivation
                                          1. Applied rewrites69.8%

                                            \[\leadsto \sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\left(-\frac{\sqrt{F \cdot 2}}{B}\right)} \]

                                          if 1.80000000000000014e206 < B

                                          1. Initial program 0.0%

                                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                          2. Add Preprocessing
                                          3. Taylor expanded in A around 0

                                            \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                          4. Step-by-step derivation
                                            1. mul-1-negN/A

                                              \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                            2. lower-neg.f64N/A

                                              \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                            3. *-commutativeN/A

                                              \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}} \]
                                            4. lower-*.f64N/A

                                              \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}} \]
                                            5. lower-sqrt.f64N/A

                                              \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \cdot \frac{\sqrt{2}}{B} \]
                                            6. *-commutativeN/A

                                              \[\leadsto -\sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \cdot \frac{\sqrt{2}}{B} \]
                                            7. lower-*.f64N/A

                                              \[\leadsto -\sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \cdot \frac{\sqrt{2}}{B} \]
                                            8. +-commutativeN/A

                                              \[\leadsto -\sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                            9. lower-+.f64N/A

                                              \[\leadsto -\sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                            10. +-commutativeN/A

                                              \[\leadsto -\sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                            11. unpow2N/A

                                              \[\leadsto -\sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                            12. unpow2N/A

                                              \[\leadsto -\sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                            13. lower-hypot.f64N/A

                                              \[\leadsto -\sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                            14. lower-/.f64N/A

                                              \[\leadsto -\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \color{blue}{\frac{\sqrt{2}}{B}} \]
                                            15. lower-sqrt.f6457.6

                                              \[\leadsto -\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \frac{\color{blue}{\sqrt{2}}}{B} \]
                                          5. Applied rewrites57.6%

                                            \[\leadsto \color{blue}{-\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B}} \]
                                          6. Step-by-step derivation
                                            1. Applied rewrites89.0%

                                              \[\leadsto -\left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{B} \]
                                            2. Taylor expanded in C around 0

                                              \[\leadsto -\left(\sqrt{B + C} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{B} \]
                                            3. Step-by-step derivation
                                              1. Applied rewrites78.7%

                                                \[\leadsto -\left(\sqrt{B + C} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{B} \]
                                            4. Recombined 5 regimes into one program.
                                            5. Final simplification31.0%

                                              \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 8.4 \cdot 10^{-280}:\\ \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{elif}\;B \leq 2.35 \cdot 10^{-155}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(0, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{-\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}\\ \mathbf{elif}\;B \leq 8 \cdot 10^{+50}:\\ \;\;\;\;\left(\left(-\sqrt{F}\right) \cdot \sqrt{\frac{C \cdot 2}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}\right) \cdot \sqrt{2}\\ \mathbf{elif}\;B \leq 1.8 \cdot 10^{+206}:\\ \;\;\;\;\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \frac{\sqrt{F \cdot 2}}{-B}\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{B + C} \cdot \left(-\sqrt{F}\right)\right) \cdot \frac{\sqrt{2}}{B}\\ \end{array} \]
                                            6. Add Preprocessing

                                            Alternative 8: 47.8% accurate, 4.5× speedup?

                                            \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := -\sqrt{F}\\ \mathbf{if}\;B\_m \leq 8.4 \cdot 10^{-280}:\\ \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{elif}\;B\_m \leq 2.35 \cdot 10^{-155}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(0, -4, \left(B\_m \cdot B\_m\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{-\mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(A \cdot C\right)\right)}\\ \mathbf{elif}\;B\_m \leq 1.55 \cdot 10^{+56}:\\ \;\;\;\;\left(t\_0 \cdot \sqrt{\frac{C \cdot 2}{\mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)}}\right) \cdot \sqrt{2}\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{B\_m + C} \cdot t\_0\right) \cdot \frac{\sqrt{2}}{B\_m}\\ \end{array} \end{array} \]
                                            B_m = (fabs.f64 B)
                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                            (FPCore (A B_m C F)
                                             :precision binary64
                                             (let* ((t_0 (- (sqrt F))))
                                               (if (<= B_m 8.4e-280)
                                                 (* (sqrt (* -0.5 (/ F A))) (- (sqrt 2.0)))
                                                 (if (<= B_m 2.35e-155)
                                                   (/
                                                    (sqrt
                                                     (*
                                                      (fma
                                                       (/ (* (fma 0.0 -4.0 (* (* B_m B_m) 2.0)) F) C)
                                                       2.0
                                                       (* (* F A) -16.0))
                                                      (* C C)))
                                                    (- (fma B_m B_m (* -4.0 (* A C)))))
                                                   (if (<= B_m 1.55e+56)
                                                     (*
                                                      (* t_0 (sqrt (/ (* C 2.0) (fma -4.0 (* C A) (* B_m B_m)))))
                                                      (sqrt 2.0))
                                                     (* (* (sqrt (+ B_m C)) t_0) (/ (sqrt 2.0) B_m)))))))
                                            B_m = fabs(B);
                                            assert(A < B_m && B_m < C && C < F);
                                            double code(double A, double B_m, double C, double F) {
                                            	double t_0 = -sqrt(F);
                                            	double tmp;
                                            	if (B_m <= 8.4e-280) {
                                            		tmp = sqrt((-0.5 * (F / A))) * -sqrt(2.0);
                                            	} else if (B_m <= 2.35e-155) {
                                            		tmp = sqrt((fma(((fma(0.0, -4.0, ((B_m * B_m) * 2.0)) * F) / C), 2.0, ((F * A) * -16.0)) * (C * C))) / -fma(B_m, B_m, (-4.0 * (A * C)));
                                            	} else if (B_m <= 1.55e+56) {
                                            		tmp = (t_0 * sqrt(((C * 2.0) / fma(-4.0, (C * A), (B_m * B_m))))) * sqrt(2.0);
                                            	} else {
                                            		tmp = (sqrt((B_m + C)) * t_0) * (sqrt(2.0) / B_m);
                                            	}
                                            	return tmp;
                                            }
                                            
                                            B_m = abs(B)
                                            A, B_m, C, F = sort([A, B_m, C, F])
                                            function code(A, B_m, C, F)
                                            	t_0 = Float64(-sqrt(F))
                                            	tmp = 0.0
                                            	if (B_m <= 8.4e-280)
                                            		tmp = Float64(sqrt(Float64(-0.5 * Float64(F / A))) * Float64(-sqrt(2.0)));
                                            	elseif (B_m <= 2.35e-155)
                                            		tmp = Float64(sqrt(Float64(fma(Float64(Float64(fma(0.0, -4.0, Float64(Float64(B_m * B_m) * 2.0)) * F) / C), 2.0, Float64(Float64(F * A) * -16.0)) * Float64(C * C))) / Float64(-fma(B_m, B_m, Float64(-4.0 * Float64(A * C)))));
                                            	elseif (B_m <= 1.55e+56)
                                            		tmp = Float64(Float64(t_0 * sqrt(Float64(Float64(C * 2.0) / fma(-4.0, Float64(C * A), Float64(B_m * B_m))))) * sqrt(2.0));
                                            	else
                                            		tmp = Float64(Float64(sqrt(Float64(B_m + C)) * t_0) * Float64(sqrt(2.0) / B_m));
                                            	end
                                            	return tmp
                                            end
                                            
                                            B_m = N[Abs[B], $MachinePrecision]
                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                            code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = (-N[Sqrt[F], $MachinePrecision])}, If[LessEqual[B$95$m, 8.4e-280], N[(N[Sqrt[N[(-0.5 * N[(F / A), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[2.0], $MachinePrecision])), $MachinePrecision], If[LessEqual[B$95$m, 2.35e-155], N[(N[Sqrt[N[(N[(N[(N[(N[(0.0 * -4.0 + N[(N[(B$95$m * B$95$m), $MachinePrecision] * 2.0), $MachinePrecision]), $MachinePrecision] * F), $MachinePrecision] / C), $MachinePrecision] * 2.0 + N[(N[(F * A), $MachinePrecision] * -16.0), $MachinePrecision]), $MachinePrecision] * N[(C * C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-N[(B$95$m * B$95$m + N[(-4.0 * N[(A * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision])), $MachinePrecision], If[LessEqual[B$95$m, 1.55e+56], N[(N[(t$95$0 * N[Sqrt[N[(N[(C * 2.0), $MachinePrecision] / N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(B$95$m + C), $MachinePrecision]], $MachinePrecision] * t$95$0), $MachinePrecision] * N[(N[Sqrt[2.0], $MachinePrecision] / B$95$m), $MachinePrecision]), $MachinePrecision]]]]]
                                            
                                            \begin{array}{l}
                                            B_m = \left|B\right|
                                            \\
                                            [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                            \\
                                            \begin{array}{l}
                                            t_0 := -\sqrt{F}\\
                                            \mathbf{if}\;B\_m \leq 8.4 \cdot 10^{-280}:\\
                                            \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\
                                            
                                            \mathbf{elif}\;B\_m \leq 2.35 \cdot 10^{-155}:\\
                                            \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(0, -4, \left(B\_m \cdot B\_m\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{-\mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(A \cdot C\right)\right)}\\
                                            
                                            \mathbf{elif}\;B\_m \leq 1.55 \cdot 10^{+56}:\\
                                            \;\;\;\;\left(t\_0 \cdot \sqrt{\frac{C \cdot 2}{\mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)}}\right) \cdot \sqrt{2}\\
                                            
                                            \mathbf{else}:\\
                                            \;\;\;\;\left(\sqrt{B\_m + C} \cdot t\_0\right) \cdot \frac{\sqrt{2}}{B\_m}\\
                                            
                                            
                                            \end{array}
                                            \end{array}
                                            
                                            Derivation
                                            1. Split input into 4 regimes
                                            2. if B < 8.40000000000000003e-280

                                              1. Initial program 15.9%

                                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              2. Add Preprocessing
                                              3. Taylor expanded in F around 0

                                                \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                              4. Step-by-step derivation
                                                1. mul-1-negN/A

                                                  \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                                2. lower-neg.f64N/A

                                                  \[\leadsto \color{blue}{-\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}} \]
                                                3. lower-*.f64N/A

                                                  \[\leadsto -\color{blue}{\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}} \]
                                              5. Applied rewrites19.0%

                                                \[\leadsto \color{blue}{-\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \cdot \sqrt{2}} \]
                                              6. Taylor expanded in A around -inf

                                                \[\leadsto -\sqrt{\frac{-1}{2} \cdot \frac{F}{A}} \cdot \sqrt{2} \]
                                              7. Step-by-step derivation
                                                1. Applied rewrites14.8%

                                                  \[\leadsto -\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \sqrt{2} \]

                                                if 8.40000000000000003e-280 < B < 2.3499999999999999e-155

                                                1. Initial program 27.8%

                                                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                2. Add Preprocessing
                                                3. Taylor expanded in C around inf

                                                  \[\leadsto \frac{-\sqrt{\color{blue}{{C}^{2} \cdot \left(-16 \cdot \left(A \cdot F\right) + 2 \cdot \frac{F \cdot \left(-4 \cdot \left(A \cdot \left(A + -1 \cdot A\right)\right) + 2 \cdot {B}^{2}\right)}{C}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                4. Step-by-step derivation
                                                  1. *-commutativeN/A

                                                    \[\leadsto \frac{-\sqrt{\color{blue}{\left(-16 \cdot \left(A \cdot F\right) + 2 \cdot \frac{F \cdot \left(-4 \cdot \left(A \cdot \left(A + -1 \cdot A\right)\right) + 2 \cdot {B}^{2}\right)}{C}\right) \cdot {C}^{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                  2. lower-*.f64N/A

                                                    \[\leadsto \frac{-\sqrt{\color{blue}{\left(-16 \cdot \left(A \cdot F\right) + 2 \cdot \frac{F \cdot \left(-4 \cdot \left(A \cdot \left(A + -1 \cdot A\right)\right) + 2 \cdot {B}^{2}\right)}{C}\right) \cdot {C}^{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                5. Applied rewrites23.3%

                                                  \[\leadsto \frac{-\sqrt{\color{blue}{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                6. Taylor expanded in B around 0

                                                  \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{\color{blue}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \]
                                                7. Step-by-step derivation
                                                  1. fp-cancel-sub-sign-invN/A

                                                    \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{\color{blue}{{B}^{2} + \left(\mathsf{neg}\left(4\right)\right) \cdot \left(A \cdot C\right)}} \]
                                                  2. unpow2N/A

                                                    \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{\color{blue}{B \cdot B} + \left(\mathsf{neg}\left(4\right)\right) \cdot \left(A \cdot C\right)} \]
                                                  3. metadata-evalN/A

                                                    \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{B \cdot B + \color{blue}{-4} \cdot \left(A \cdot C\right)} \]
                                                  4. lower-fma.f64N/A

                                                    \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{\color{blue}{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}} \]
                                                  5. lower-*.f64N/A

                                                    \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{\mathsf{fma}\left(B, B, \color{blue}{-4 \cdot \left(A \cdot C\right)}\right)} \]
                                                  6. lower-*.f6423.3

                                                    \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{\mathsf{fma}\left(B, B, -4 \cdot \color{blue}{\left(A \cdot C\right)}\right)} \]
                                                8. Applied rewrites23.3%

                                                  \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{\color{blue}{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}} \]

                                                if 2.3499999999999999e-155 < B < 1.55000000000000002e56

                                                1. Initial program 23.0%

                                                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                2. Add Preprocessing
                                                3. Taylor expanded in F around 0

                                                  \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                                4. Step-by-step derivation
                                                  1. mul-1-negN/A

                                                    \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                                  2. lower-neg.f64N/A

                                                    \[\leadsto \color{blue}{-\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}} \]
                                                  3. lower-*.f64N/A

                                                    \[\leadsto -\color{blue}{\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}} \]
                                                5. Applied rewrites27.4%

                                                  \[\leadsto \color{blue}{-\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \cdot \sqrt{2}} \]
                                                6. Taylor expanded in A around -inf

                                                  \[\leadsto -\sqrt{\frac{\left(2 \cdot C\right) \cdot F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \cdot \sqrt{2} \]
                                                7. Step-by-step derivation
                                                  1. Applied rewrites9.1%

                                                    \[\leadsto -\sqrt{\frac{\left(2 \cdot C\right) \cdot F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \cdot \sqrt{2} \]
                                                  2. Step-by-step derivation
                                                    1. Applied rewrites25.3%

                                                      \[\leadsto -\left(\sqrt{F} \cdot \sqrt{\frac{C \cdot 2}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}\right) \cdot \sqrt{2} \]

                                                    if 1.55000000000000002e56 < B

                                                    1. Initial program 15.4%

                                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                    2. Add Preprocessing
                                                    3. Taylor expanded in A around 0

                                                      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                    4. Step-by-step derivation
                                                      1. mul-1-negN/A

                                                        \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                      2. lower-neg.f64N/A

                                                        \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                      3. *-commutativeN/A

                                                        \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}} \]
                                                      4. lower-*.f64N/A

                                                        \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}} \]
                                                      5. lower-sqrt.f64N/A

                                                        \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \cdot \frac{\sqrt{2}}{B} \]
                                                      6. *-commutativeN/A

                                                        \[\leadsto -\sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \cdot \frac{\sqrt{2}}{B} \]
                                                      7. lower-*.f64N/A

                                                        \[\leadsto -\sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \cdot \frac{\sqrt{2}}{B} \]
                                                      8. +-commutativeN/A

                                                        \[\leadsto -\sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                                      9. lower-+.f64N/A

                                                        \[\leadsto -\sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                                      10. +-commutativeN/A

                                                        \[\leadsto -\sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                                      11. unpow2N/A

                                                        \[\leadsto -\sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                                      12. unpow2N/A

                                                        \[\leadsto -\sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                                      13. lower-hypot.f64N/A

                                                        \[\leadsto -\sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                                      14. lower-/.f64N/A

                                                        \[\leadsto -\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \color{blue}{\frac{\sqrt{2}}{B}} \]
                                                      15. lower-sqrt.f6455.7

                                                        \[\leadsto -\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \frac{\color{blue}{\sqrt{2}}}{B} \]
                                                    5. Applied rewrites55.7%

                                                      \[\leadsto \color{blue}{-\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B}} \]
                                                    6. Step-by-step derivation
                                                      1. Applied rewrites78.6%

                                                        \[\leadsto -\left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{B} \]
                                                      2. Taylor expanded in C around 0

                                                        \[\leadsto -\left(\sqrt{B + C} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{B} \]
                                                      3. Step-by-step derivation
                                                        1. Applied rewrites69.0%

                                                          \[\leadsto -\left(\sqrt{B + C} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{B} \]
                                                      4. Recombined 4 regimes into one program.
                                                      5. Final simplification30.0%

                                                        \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 8.4 \cdot 10^{-280}:\\ \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{elif}\;B \leq 2.35 \cdot 10^{-155}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(\frac{\mathsf{fma}\left(0, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}{-\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}\\ \mathbf{elif}\;B \leq 1.55 \cdot 10^{+56}:\\ \;\;\;\;\left(\left(-\sqrt{F}\right) \cdot \sqrt{\frac{C \cdot 2}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}\right) \cdot \sqrt{2}\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{B + C} \cdot \left(-\sqrt{F}\right)\right) \cdot \frac{\sqrt{2}}{B}\\ \end{array} \]
                                                      6. Add Preprocessing

                                                      Alternative 9: 47.7% accurate, 4.7× speedup?

                                                      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ t_1 := -\sqrt{F}\\ \mathbf{if}\;B\_m \leq 2.6 \cdot 10^{-264}:\\ \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{elif}\;B\_m \leq 2.35 \cdot 10^{-155}:\\ \;\;\;\;\frac{\sqrt{\left(C \cdot C\right) \cdot \mathsf{fma}\left(2 \cdot \left(\left(B\_m \cdot B\_m\right) \cdot 2\right), \frac{F}{C}, -16 \cdot \left(F \cdot A\right)\right)}}{-t\_0}\\ \mathbf{elif}\;B\_m \leq 1.55 \cdot 10^{+56}:\\ \;\;\;\;\left(t\_1 \cdot \sqrt{\frac{C \cdot 2}{t\_0}}\right) \cdot \sqrt{2}\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{B\_m + C} \cdot t\_1\right) \cdot \frac{\sqrt{2}}{B\_m}\\ \end{array} \end{array} \]
                                                      B_m = (fabs.f64 B)
                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                      (FPCore (A B_m C F)
                                                       :precision binary64
                                                       (let* ((t_0 (fma -4.0 (* C A) (* B_m B_m))) (t_1 (- (sqrt F))))
                                                         (if (<= B_m 2.6e-264)
                                                           (* (sqrt (* -0.5 (/ F A))) (- (sqrt 2.0)))
                                                           (if (<= B_m 2.35e-155)
                                                             (/
                                                              (sqrt
                                                               (*
                                                                (* C C)
                                                                (fma (* 2.0 (* (* B_m B_m) 2.0)) (/ F C) (* -16.0 (* F A)))))
                                                              (- t_0))
                                                             (if (<= B_m 1.55e+56)
                                                               (* (* t_1 (sqrt (/ (* C 2.0) t_0))) (sqrt 2.0))
                                                               (* (* (sqrt (+ B_m C)) t_1) (/ (sqrt 2.0) B_m)))))))
                                                      B_m = fabs(B);
                                                      assert(A < B_m && B_m < C && C < F);
                                                      double code(double A, double B_m, double C, double F) {
                                                      	double t_0 = fma(-4.0, (C * A), (B_m * B_m));
                                                      	double t_1 = -sqrt(F);
                                                      	double tmp;
                                                      	if (B_m <= 2.6e-264) {
                                                      		tmp = sqrt((-0.5 * (F / A))) * -sqrt(2.0);
                                                      	} else if (B_m <= 2.35e-155) {
                                                      		tmp = sqrt(((C * C) * fma((2.0 * ((B_m * B_m) * 2.0)), (F / C), (-16.0 * (F * A))))) / -t_0;
                                                      	} else if (B_m <= 1.55e+56) {
                                                      		tmp = (t_1 * sqrt(((C * 2.0) / t_0))) * sqrt(2.0);
                                                      	} else {
                                                      		tmp = (sqrt((B_m + C)) * t_1) * (sqrt(2.0) / B_m);
                                                      	}
                                                      	return tmp;
                                                      }
                                                      
                                                      B_m = abs(B)
                                                      A, B_m, C, F = sort([A, B_m, C, F])
                                                      function code(A, B_m, C, F)
                                                      	t_0 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
                                                      	t_1 = Float64(-sqrt(F))
                                                      	tmp = 0.0
                                                      	if (B_m <= 2.6e-264)
                                                      		tmp = Float64(sqrt(Float64(-0.5 * Float64(F / A))) * Float64(-sqrt(2.0)));
                                                      	elseif (B_m <= 2.35e-155)
                                                      		tmp = Float64(sqrt(Float64(Float64(C * C) * fma(Float64(2.0 * Float64(Float64(B_m * B_m) * 2.0)), Float64(F / C), Float64(-16.0 * Float64(F * A))))) / Float64(-t_0));
                                                      	elseif (B_m <= 1.55e+56)
                                                      		tmp = Float64(Float64(t_1 * sqrt(Float64(Float64(C * 2.0) / t_0))) * sqrt(2.0));
                                                      	else
                                                      		tmp = Float64(Float64(sqrt(Float64(B_m + C)) * t_1) * Float64(sqrt(2.0) / B_m));
                                                      	end
                                                      	return tmp
                                                      end
                                                      
                                                      B_m = N[Abs[B], $MachinePrecision]
                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                      code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = (-N[Sqrt[F], $MachinePrecision])}, If[LessEqual[B$95$m, 2.6e-264], N[(N[Sqrt[N[(-0.5 * N[(F / A), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[2.0], $MachinePrecision])), $MachinePrecision], If[LessEqual[B$95$m, 2.35e-155], N[(N[Sqrt[N[(N[(C * C), $MachinePrecision] * N[(N[(2.0 * N[(N[(B$95$m * B$95$m), $MachinePrecision] * 2.0), $MachinePrecision]), $MachinePrecision] * N[(F / C), $MachinePrecision] + N[(-16.0 * N[(F * A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], If[LessEqual[B$95$m, 1.55e+56], N[(N[(t$95$1 * N[Sqrt[N[(N[(C * 2.0), $MachinePrecision] / t$95$0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(B$95$m + C), $MachinePrecision]], $MachinePrecision] * t$95$1), $MachinePrecision] * N[(N[Sqrt[2.0], $MachinePrecision] / B$95$m), $MachinePrecision]), $MachinePrecision]]]]]]
                                                      
                                                      \begin{array}{l}
                                                      B_m = \left|B\right|
                                                      \\
                                                      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                      \\
                                                      \begin{array}{l}
                                                      t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
                                                      t_1 := -\sqrt{F}\\
                                                      \mathbf{if}\;B\_m \leq 2.6 \cdot 10^{-264}:\\
                                                      \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\
                                                      
                                                      \mathbf{elif}\;B\_m \leq 2.35 \cdot 10^{-155}:\\
                                                      \;\;\;\;\frac{\sqrt{\left(C \cdot C\right) \cdot \mathsf{fma}\left(2 \cdot \left(\left(B\_m \cdot B\_m\right) \cdot 2\right), \frac{F}{C}, -16 \cdot \left(F \cdot A\right)\right)}}{-t\_0}\\
                                                      
                                                      \mathbf{elif}\;B\_m \leq 1.55 \cdot 10^{+56}:\\
                                                      \;\;\;\;\left(t\_1 \cdot \sqrt{\frac{C \cdot 2}{t\_0}}\right) \cdot \sqrt{2}\\
                                                      
                                                      \mathbf{else}:\\
                                                      \;\;\;\;\left(\sqrt{B\_m + C} \cdot t\_1\right) \cdot \frac{\sqrt{2}}{B\_m}\\
                                                      
                                                      
                                                      \end{array}
                                                      \end{array}
                                                      
                                                      Derivation
                                                      1. Split input into 4 regimes
                                                      2. if B < 2.6000000000000002e-264

                                                        1. Initial program 15.7%

                                                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                        2. Add Preprocessing
                                                        3. Taylor expanded in F around 0

                                                          \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                                        4. Step-by-step derivation
                                                          1. mul-1-negN/A

                                                            \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                                          2. lower-neg.f64N/A

                                                            \[\leadsto \color{blue}{-\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}} \]
                                                          3. lower-*.f64N/A

                                                            \[\leadsto -\color{blue}{\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}} \]
                                                        5. Applied rewrites18.8%

                                                          \[\leadsto \color{blue}{-\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \cdot \sqrt{2}} \]
                                                        6. Taylor expanded in A around -inf

                                                          \[\leadsto -\sqrt{\frac{-1}{2} \cdot \frac{F}{A}} \cdot \sqrt{2} \]
                                                        7. Step-by-step derivation
                                                          1. Applied rewrites14.7%

                                                            \[\leadsto -\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \sqrt{2} \]

                                                          if 2.6000000000000002e-264 < B < 2.3499999999999999e-155

                                                          1. Initial program 30.6%

                                                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                          2. Add Preprocessing
                                                          3. Taylor expanded in C around inf

                                                            \[\leadsto \frac{-\sqrt{\color{blue}{{C}^{2} \cdot \left(-16 \cdot \left(A \cdot F\right) + 2 \cdot \frac{F \cdot \left(-4 \cdot \left(A \cdot \left(A + -1 \cdot A\right)\right) + 2 \cdot {B}^{2}\right)}{C}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                          4. Step-by-step derivation
                                                            1. *-commutativeN/A

                                                              \[\leadsto \frac{-\sqrt{\color{blue}{\left(-16 \cdot \left(A \cdot F\right) + 2 \cdot \frac{F \cdot \left(-4 \cdot \left(A \cdot \left(A + -1 \cdot A\right)\right) + 2 \cdot {B}^{2}\right)}{C}\right) \cdot {C}^{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                            2. lower-*.f64N/A

                                                              \[\leadsto \frac{-\sqrt{\color{blue}{\left(-16 \cdot \left(A \cdot F\right) + 2 \cdot \frac{F \cdot \left(-4 \cdot \left(A \cdot \left(A + -1 \cdot A\right)\right) + 2 \cdot {B}^{2}\right)}{C}\right) \cdot {C}^{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                          5. Applied rewrites19.9%

                                                            \[\leadsto \frac{-\sqrt{\color{blue}{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\left(0 \cdot A\right) \cdot A, -4, \left(B \cdot B\right) \cdot 2\right) \cdot F}{C}, 2, \left(F \cdot A\right) \cdot -16\right) \cdot \left(C \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                          6. Applied rewrites19.9%

                                                            \[\leadsto \color{blue}{\frac{\sqrt{\left(C \cdot C\right) \cdot \mathsf{fma}\left(2 \cdot \left(\left(B \cdot B\right) \cdot 2\right), \frac{F}{C}, -16 \cdot \left(F \cdot A\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]

                                                          if 2.3499999999999999e-155 < B < 1.55000000000000002e56

                                                          1. Initial program 23.0%

                                                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                          2. Add Preprocessing
                                                          3. Taylor expanded in F around 0

                                                            \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                                          4. Step-by-step derivation
                                                            1. mul-1-negN/A

                                                              \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                                            2. lower-neg.f64N/A

                                                              \[\leadsto \color{blue}{-\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}} \]
                                                            3. lower-*.f64N/A

                                                              \[\leadsto -\color{blue}{\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}} \]
                                                          5. Applied rewrites27.4%

                                                            \[\leadsto \color{blue}{-\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \cdot \sqrt{2}} \]
                                                          6. Taylor expanded in A around -inf

                                                            \[\leadsto -\sqrt{\frac{\left(2 \cdot C\right) \cdot F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \cdot \sqrt{2} \]
                                                          7. Step-by-step derivation
                                                            1. Applied rewrites9.1%

                                                              \[\leadsto -\sqrt{\frac{\left(2 \cdot C\right) \cdot F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \cdot \sqrt{2} \]
                                                            2. Step-by-step derivation
                                                              1. Applied rewrites25.3%

                                                                \[\leadsto -\left(\sqrt{F} \cdot \sqrt{\frac{C \cdot 2}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}\right) \cdot \sqrt{2} \]

                                                              if 1.55000000000000002e56 < B

                                                              1. Initial program 15.4%

                                                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                              2. Add Preprocessing
                                                              3. Taylor expanded in A around 0

                                                                \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                              4. Step-by-step derivation
                                                                1. mul-1-negN/A

                                                                  \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                2. lower-neg.f64N/A

                                                                  \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                3. *-commutativeN/A

                                                                  \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}} \]
                                                                4. lower-*.f64N/A

                                                                  \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}} \]
                                                                5. lower-sqrt.f64N/A

                                                                  \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \cdot \frac{\sqrt{2}}{B} \]
                                                                6. *-commutativeN/A

                                                                  \[\leadsto -\sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \cdot \frac{\sqrt{2}}{B} \]
                                                                7. lower-*.f64N/A

                                                                  \[\leadsto -\sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \cdot \frac{\sqrt{2}}{B} \]
                                                                8. +-commutativeN/A

                                                                  \[\leadsto -\sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                                                9. lower-+.f64N/A

                                                                  \[\leadsto -\sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                                                10. +-commutativeN/A

                                                                  \[\leadsto -\sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                                                11. unpow2N/A

                                                                  \[\leadsto -\sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                                                12. unpow2N/A

                                                                  \[\leadsto -\sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                                                13. lower-hypot.f64N/A

                                                                  \[\leadsto -\sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                                                14. lower-/.f64N/A

                                                                  \[\leadsto -\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \color{blue}{\frac{\sqrt{2}}{B}} \]
                                                                15. lower-sqrt.f6455.7

                                                                  \[\leadsto -\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \frac{\color{blue}{\sqrt{2}}}{B} \]
                                                              5. Applied rewrites55.7%

                                                                \[\leadsto \color{blue}{-\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B}} \]
                                                              6. Step-by-step derivation
                                                                1. Applied rewrites78.6%

                                                                  \[\leadsto -\left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{B} \]
                                                                2. Taylor expanded in C around 0

                                                                  \[\leadsto -\left(\sqrt{B + C} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{B} \]
                                                                3. Step-by-step derivation
                                                                  1. Applied rewrites69.0%

                                                                    \[\leadsto -\left(\sqrt{B + C} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{B} \]
                                                                4. Recombined 4 regimes into one program.
                                                                5. Final simplification29.6%

                                                                  \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 2.6 \cdot 10^{-264}:\\ \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{elif}\;B \leq 2.35 \cdot 10^{-155}:\\ \;\;\;\;\frac{\sqrt{\left(C \cdot C\right) \cdot \mathsf{fma}\left(2 \cdot \left(\left(B \cdot B\right) \cdot 2\right), \frac{F}{C}, -16 \cdot \left(F \cdot A\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{elif}\;B \leq 1.55 \cdot 10^{+56}:\\ \;\;\;\;\left(\left(-\sqrt{F}\right) \cdot \sqrt{\frac{C \cdot 2}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}\right) \cdot \sqrt{2}\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{B + C} \cdot \left(-\sqrt{F}\right)\right) \cdot \frac{\sqrt{2}}{B}\\ \end{array} \]
                                                                6. Add Preprocessing

                                                                Alternative 10: 49.6% accurate, 6.1× speedup?

                                                                \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := -\sqrt{F}\\ \mathbf{if}\;B\_m \leq 1.55 \cdot 10^{+56}:\\ \;\;\;\;\left(t\_0 \cdot \sqrt{\frac{C \cdot 2}{\mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)}}\right) \cdot \sqrt{2}\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{B\_m + C} \cdot t\_0\right) \cdot \frac{\sqrt{2}}{B\_m}\\ \end{array} \end{array} \]
                                                                B_m = (fabs.f64 B)
                                                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                (FPCore (A B_m C F)
                                                                 :precision binary64
                                                                 (let* ((t_0 (- (sqrt F))))
                                                                   (if (<= B_m 1.55e+56)
                                                                     (* (* t_0 (sqrt (/ (* C 2.0) (fma -4.0 (* C A) (* B_m B_m))))) (sqrt 2.0))
                                                                     (* (* (sqrt (+ B_m C)) t_0) (/ (sqrt 2.0) B_m)))))
                                                                B_m = fabs(B);
                                                                assert(A < B_m && B_m < C && C < F);
                                                                double code(double A, double B_m, double C, double F) {
                                                                	double t_0 = -sqrt(F);
                                                                	double tmp;
                                                                	if (B_m <= 1.55e+56) {
                                                                		tmp = (t_0 * sqrt(((C * 2.0) / fma(-4.0, (C * A), (B_m * B_m))))) * sqrt(2.0);
                                                                	} else {
                                                                		tmp = (sqrt((B_m + C)) * t_0) * (sqrt(2.0) / B_m);
                                                                	}
                                                                	return tmp;
                                                                }
                                                                
                                                                B_m = abs(B)
                                                                A, B_m, C, F = sort([A, B_m, C, F])
                                                                function code(A, B_m, C, F)
                                                                	t_0 = Float64(-sqrt(F))
                                                                	tmp = 0.0
                                                                	if (B_m <= 1.55e+56)
                                                                		tmp = Float64(Float64(t_0 * sqrt(Float64(Float64(C * 2.0) / fma(-4.0, Float64(C * A), Float64(B_m * B_m))))) * sqrt(2.0));
                                                                	else
                                                                		tmp = Float64(Float64(sqrt(Float64(B_m + C)) * t_0) * Float64(sqrt(2.0) / B_m));
                                                                	end
                                                                	return tmp
                                                                end
                                                                
                                                                B_m = N[Abs[B], $MachinePrecision]
                                                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = (-N[Sqrt[F], $MachinePrecision])}, If[LessEqual[B$95$m, 1.55e+56], N[(N[(t$95$0 * N[Sqrt[N[(N[(C * 2.0), $MachinePrecision] / N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(B$95$m + C), $MachinePrecision]], $MachinePrecision] * t$95$0), $MachinePrecision] * N[(N[Sqrt[2.0], $MachinePrecision] / B$95$m), $MachinePrecision]), $MachinePrecision]]]
                                                                
                                                                \begin{array}{l}
                                                                B_m = \left|B\right|
                                                                \\
                                                                [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                \\
                                                                \begin{array}{l}
                                                                t_0 := -\sqrt{F}\\
                                                                \mathbf{if}\;B\_m \leq 1.55 \cdot 10^{+56}:\\
                                                                \;\;\;\;\left(t\_0 \cdot \sqrt{\frac{C \cdot 2}{\mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)}}\right) \cdot \sqrt{2}\\
                                                                
                                                                \mathbf{else}:\\
                                                                \;\;\;\;\left(\sqrt{B\_m + C} \cdot t\_0\right) \cdot \frac{\sqrt{2}}{B\_m}\\
                                                                
                                                                
                                                                \end{array}
                                                                \end{array}
                                                                
                                                                Derivation
                                                                1. Split input into 2 regimes
                                                                2. if B < 1.55000000000000002e56

                                                                  1. Initial program 18.5%

                                                                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                  2. Add Preprocessing
                                                                  3. Taylor expanded in F around 0

                                                                    \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                                                  4. Step-by-step derivation
                                                                    1. mul-1-negN/A

                                                                      \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                                                    2. lower-neg.f64N/A

                                                                      \[\leadsto \color{blue}{-\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}} \]
                                                                    3. lower-*.f64N/A

                                                                      \[\leadsto -\color{blue}{\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}} \]
                                                                  5. Applied rewrites20.3%

                                                                    \[\leadsto \color{blue}{-\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \cdot \sqrt{2}} \]
                                                                  6. Taylor expanded in A around -inf

                                                                    \[\leadsto -\sqrt{\frac{\left(2 \cdot C\right) \cdot F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \cdot \sqrt{2} \]
                                                                  7. Step-by-step derivation
                                                                    1. Applied rewrites10.8%

                                                                      \[\leadsto -\sqrt{\frac{\left(2 \cdot C\right) \cdot F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \cdot \sqrt{2} \]
                                                                    2. Step-by-step derivation
                                                                      1. Applied rewrites18.3%

                                                                        \[\leadsto -\left(\sqrt{F} \cdot \sqrt{\frac{C \cdot 2}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}\right) \cdot \sqrt{2} \]

                                                                      if 1.55000000000000002e56 < B

                                                                      1. Initial program 15.4%

                                                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                      2. Add Preprocessing
                                                                      3. Taylor expanded in A around 0

                                                                        \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                      4. Step-by-step derivation
                                                                        1. mul-1-negN/A

                                                                          \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                        2. lower-neg.f64N/A

                                                                          \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                        3. *-commutativeN/A

                                                                          \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}} \]
                                                                        4. lower-*.f64N/A

                                                                          \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}} \]
                                                                        5. lower-sqrt.f64N/A

                                                                          \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \cdot \frac{\sqrt{2}}{B} \]
                                                                        6. *-commutativeN/A

                                                                          \[\leadsto -\sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \cdot \frac{\sqrt{2}}{B} \]
                                                                        7. lower-*.f64N/A

                                                                          \[\leadsto -\sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \cdot \frac{\sqrt{2}}{B} \]
                                                                        8. +-commutativeN/A

                                                                          \[\leadsto -\sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                                                        9. lower-+.f64N/A

                                                                          \[\leadsto -\sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                                                        10. +-commutativeN/A

                                                                          \[\leadsto -\sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                                                        11. unpow2N/A

                                                                          \[\leadsto -\sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                                                        12. unpow2N/A

                                                                          \[\leadsto -\sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                                                        13. lower-hypot.f64N/A

                                                                          \[\leadsto -\sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                                                        14. lower-/.f64N/A

                                                                          \[\leadsto -\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \color{blue}{\frac{\sqrt{2}}{B}} \]
                                                                        15. lower-sqrt.f6455.7

                                                                          \[\leadsto -\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \frac{\color{blue}{\sqrt{2}}}{B} \]
                                                                      5. Applied rewrites55.7%

                                                                        \[\leadsto \color{blue}{-\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B}} \]
                                                                      6. Step-by-step derivation
                                                                        1. Applied rewrites78.6%

                                                                          \[\leadsto -\left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{B} \]
                                                                        2. Taylor expanded in C around 0

                                                                          \[\leadsto -\left(\sqrt{B + C} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{B} \]
                                                                        3. Step-by-step derivation
                                                                          1. Applied rewrites69.0%

                                                                            \[\leadsto -\left(\sqrt{B + C} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{B} \]
                                                                        4. Recombined 2 regimes into one program.
                                                                        5. Final simplification30.4%

                                                                          \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 1.55 \cdot 10^{+56}:\\ \;\;\;\;\left(\left(-\sqrt{F}\right) \cdot \sqrt{\frac{C \cdot 2}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}\right) \cdot \sqrt{2}\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{B + C} \cdot \left(-\sqrt{F}\right)\right) \cdot \frac{\sqrt{2}}{B}\\ \end{array} \]
                                                                        6. Add Preprocessing

                                                                        Alternative 11: 49.3% accurate, 7.8× speedup?

                                                                        \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;B\_m \leq 9.5 \cdot 10^{+42}:\\ \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{B\_m + C} \cdot \left(-\sqrt{F}\right)\right) \cdot \frac{\sqrt{2}}{B\_m}\\ \end{array} \end{array} \]
                                                                        B_m = (fabs.f64 B)
                                                                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                        (FPCore (A B_m C F)
                                                                         :precision binary64
                                                                         (if (<= B_m 9.5e+42)
                                                                           (* (sqrt (* -0.5 (/ F A))) (- (sqrt 2.0)))
                                                                           (* (* (sqrt (+ B_m C)) (- (sqrt F))) (/ (sqrt 2.0) B_m))))
                                                                        B_m = fabs(B);
                                                                        assert(A < B_m && B_m < C && C < F);
                                                                        double code(double A, double B_m, double C, double F) {
                                                                        	double tmp;
                                                                        	if (B_m <= 9.5e+42) {
                                                                        		tmp = sqrt((-0.5 * (F / A))) * -sqrt(2.0);
                                                                        	} else {
                                                                        		tmp = (sqrt((B_m + C)) * -sqrt(F)) * (sqrt(2.0) / B_m);
                                                                        	}
                                                                        	return tmp;
                                                                        }
                                                                        
                                                                        B_m = abs(b)
                                                                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                        real(8) function code(a, b_m, c, f)
                                                                            real(8), intent (in) :: a
                                                                            real(8), intent (in) :: b_m
                                                                            real(8), intent (in) :: c
                                                                            real(8), intent (in) :: f
                                                                            real(8) :: tmp
                                                                            if (b_m <= 9.5d+42) then
                                                                                tmp = sqrt(((-0.5d0) * (f / a))) * -sqrt(2.0d0)
                                                                            else
                                                                                tmp = (sqrt((b_m + c)) * -sqrt(f)) * (sqrt(2.0d0) / b_m)
                                                                            end if
                                                                            code = tmp
                                                                        end function
                                                                        
                                                                        B_m = Math.abs(B);
                                                                        assert A < B_m && B_m < C && C < F;
                                                                        public static double code(double A, double B_m, double C, double F) {
                                                                        	double tmp;
                                                                        	if (B_m <= 9.5e+42) {
                                                                        		tmp = Math.sqrt((-0.5 * (F / A))) * -Math.sqrt(2.0);
                                                                        	} else {
                                                                        		tmp = (Math.sqrt((B_m + C)) * -Math.sqrt(F)) * (Math.sqrt(2.0) / B_m);
                                                                        	}
                                                                        	return tmp;
                                                                        }
                                                                        
                                                                        B_m = math.fabs(B)
                                                                        [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                        def code(A, B_m, C, F):
                                                                        	tmp = 0
                                                                        	if B_m <= 9.5e+42:
                                                                        		tmp = math.sqrt((-0.5 * (F / A))) * -math.sqrt(2.0)
                                                                        	else:
                                                                        		tmp = (math.sqrt((B_m + C)) * -math.sqrt(F)) * (math.sqrt(2.0) / B_m)
                                                                        	return tmp
                                                                        
                                                                        B_m = abs(B)
                                                                        A, B_m, C, F = sort([A, B_m, C, F])
                                                                        function code(A, B_m, C, F)
                                                                        	tmp = 0.0
                                                                        	if (B_m <= 9.5e+42)
                                                                        		tmp = Float64(sqrt(Float64(-0.5 * Float64(F / A))) * Float64(-sqrt(2.0)));
                                                                        	else
                                                                        		tmp = Float64(Float64(sqrt(Float64(B_m + C)) * Float64(-sqrt(F))) * Float64(sqrt(2.0) / B_m));
                                                                        	end
                                                                        	return tmp
                                                                        end
                                                                        
                                                                        B_m = abs(B);
                                                                        A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                        function tmp_2 = code(A, B_m, C, F)
                                                                        	tmp = 0.0;
                                                                        	if (B_m <= 9.5e+42)
                                                                        		tmp = sqrt((-0.5 * (F / A))) * -sqrt(2.0);
                                                                        	else
                                                                        		tmp = (sqrt((B_m + C)) * -sqrt(F)) * (sqrt(2.0) / B_m);
                                                                        	end
                                                                        	tmp_2 = tmp;
                                                                        end
                                                                        
                                                                        B_m = N[Abs[B], $MachinePrecision]
                                                                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                        code[A_, B$95$m_, C_, F_] := If[LessEqual[B$95$m, 9.5e+42], N[(N[Sqrt[N[(-0.5 * N[(F / A), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[2.0], $MachinePrecision])), $MachinePrecision], N[(N[(N[Sqrt[N[(B$95$m + C), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision] * N[(N[Sqrt[2.0], $MachinePrecision] / B$95$m), $MachinePrecision]), $MachinePrecision]]
                                                                        
                                                                        \begin{array}{l}
                                                                        B_m = \left|B\right|
                                                                        \\
                                                                        [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                        \\
                                                                        \begin{array}{l}
                                                                        \mathbf{if}\;B\_m \leq 9.5 \cdot 10^{+42}:\\
                                                                        \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\
                                                                        
                                                                        \mathbf{else}:\\
                                                                        \;\;\;\;\left(\sqrt{B\_m + C} \cdot \left(-\sqrt{F}\right)\right) \cdot \frac{\sqrt{2}}{B\_m}\\
                                                                        
                                                                        
                                                                        \end{array}
                                                                        \end{array}
                                                                        
                                                                        Derivation
                                                                        1. Split input into 2 regimes
                                                                        2. if B < 9.50000000000000019e42

                                                                          1. Initial program 18.2%

                                                                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                          2. Add Preprocessing
                                                                          3. Taylor expanded in F around 0

                                                                            \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                                                          4. Step-by-step derivation
                                                                            1. mul-1-negN/A

                                                                              \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                                                            2. lower-neg.f64N/A

                                                                              \[\leadsto \color{blue}{-\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}} \]
                                                                            3. lower-*.f64N/A

                                                                              \[\leadsto -\color{blue}{\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}} \]
                                                                          5. Applied rewrites20.0%

                                                                            \[\leadsto \color{blue}{-\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \cdot \sqrt{2}} \]
                                                                          6. Taylor expanded in A around -inf

                                                                            \[\leadsto -\sqrt{\frac{-1}{2} \cdot \frac{F}{A}} \cdot \sqrt{2} \]
                                                                          7. Step-by-step derivation
                                                                            1. Applied rewrites15.1%

                                                                              \[\leadsto -\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \sqrt{2} \]

                                                                            if 9.50000000000000019e42 < B

                                                                            1. Initial program 16.5%

                                                                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                            2. Add Preprocessing
                                                                            3. Taylor expanded in A around 0

                                                                              \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                            4. Step-by-step derivation
                                                                              1. mul-1-negN/A

                                                                                \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                              2. lower-neg.f64N/A

                                                                                \[\leadsto \color{blue}{-\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                              3. *-commutativeN/A

                                                                                \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}} \]
                                                                              4. lower-*.f64N/A

                                                                                \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \cdot \frac{\sqrt{2}}{B}} \]
                                                                              5. lower-sqrt.f64N/A

                                                                                \[\leadsto -\color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \cdot \frac{\sqrt{2}}{B} \]
                                                                              6. *-commutativeN/A

                                                                                \[\leadsto -\sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \cdot \frac{\sqrt{2}}{B} \]
                                                                              7. lower-*.f64N/A

                                                                                \[\leadsto -\sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \cdot \frac{\sqrt{2}}{B} \]
                                                                              8. +-commutativeN/A

                                                                                \[\leadsto -\sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                                                              9. lower-+.f64N/A

                                                                                \[\leadsto -\sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                                                              10. +-commutativeN/A

                                                                                \[\leadsto -\sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                                                              11. unpow2N/A

                                                                                \[\leadsto -\sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                                                              12. unpow2N/A

                                                                                \[\leadsto -\sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                                                              13. lower-hypot.f64N/A

                                                                                \[\leadsto -\sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B} \]
                                                                              14. lower-/.f64N/A

                                                                                \[\leadsto -\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \color{blue}{\frac{\sqrt{2}}{B}} \]
                                                                              15. lower-sqrt.f6455.6

                                                                                \[\leadsto -\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \frac{\color{blue}{\sqrt{2}}}{B} \]
                                                                            5. Applied rewrites55.6%

                                                                              \[\leadsto \color{blue}{-\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F} \cdot \frac{\sqrt{2}}{B}} \]
                                                                            6. Step-by-step derivation
                                                                              1. Applied rewrites77.8%

                                                                                \[\leadsto -\left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{B} \]
                                                                              2. Taylor expanded in C around 0

                                                                                \[\leadsto -\left(\sqrt{B + C} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{B} \]
                                                                              3. Step-by-step derivation
                                                                                1. Applied rewrites68.5%

                                                                                  \[\leadsto -\left(\sqrt{B + C} \cdot \sqrt{F}\right) \cdot \frac{\sqrt{2}}{B} \]
                                                                              4. Recombined 2 regimes into one program.
                                                                              5. Final simplification28.3%

                                                                                \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 9.5 \cdot 10^{+42}:\\ \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{else}:\\ \;\;\;\;\left(\sqrt{B + C} \cdot \left(-\sqrt{F}\right)\right) \cdot \frac{\sqrt{2}}{B}\\ \end{array} \]
                                                                              6. Add Preprocessing

                                                                              Alternative 12: 48.7% accurate, 9.8× speedup?

                                                                              \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;B\_m \leq 9.5 \cdot 10^{+42}:\\ \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{F \cdot 2}}{-\sqrt{B\_m}}\\ \end{array} \end{array} \]
                                                                              B_m = (fabs.f64 B)
                                                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                              (FPCore (A B_m C F)
                                                                               :precision binary64
                                                                               (if (<= B_m 9.5e+42)
                                                                                 (* (sqrt (* -0.5 (/ F A))) (- (sqrt 2.0)))
                                                                                 (/ (sqrt (* F 2.0)) (- (sqrt B_m)))))
                                                                              B_m = fabs(B);
                                                                              assert(A < B_m && B_m < C && C < F);
                                                                              double code(double A, double B_m, double C, double F) {
                                                                              	double tmp;
                                                                              	if (B_m <= 9.5e+42) {
                                                                              		tmp = sqrt((-0.5 * (F / A))) * -sqrt(2.0);
                                                                              	} else {
                                                                              		tmp = sqrt((F * 2.0)) / -sqrt(B_m);
                                                                              	}
                                                                              	return tmp;
                                                                              }
                                                                              
                                                                              B_m = abs(b)
                                                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                              real(8) function code(a, b_m, c, f)
                                                                                  real(8), intent (in) :: a
                                                                                  real(8), intent (in) :: b_m
                                                                                  real(8), intent (in) :: c
                                                                                  real(8), intent (in) :: f
                                                                                  real(8) :: tmp
                                                                                  if (b_m <= 9.5d+42) then
                                                                                      tmp = sqrt(((-0.5d0) * (f / a))) * -sqrt(2.0d0)
                                                                                  else
                                                                                      tmp = sqrt((f * 2.0d0)) / -sqrt(b_m)
                                                                                  end if
                                                                                  code = tmp
                                                                              end function
                                                                              
                                                                              B_m = Math.abs(B);
                                                                              assert A < B_m && B_m < C && C < F;
                                                                              public static double code(double A, double B_m, double C, double F) {
                                                                              	double tmp;
                                                                              	if (B_m <= 9.5e+42) {
                                                                              		tmp = Math.sqrt((-0.5 * (F / A))) * -Math.sqrt(2.0);
                                                                              	} else {
                                                                              		tmp = Math.sqrt((F * 2.0)) / -Math.sqrt(B_m);
                                                                              	}
                                                                              	return tmp;
                                                                              }
                                                                              
                                                                              B_m = math.fabs(B)
                                                                              [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                              def code(A, B_m, C, F):
                                                                              	tmp = 0
                                                                              	if B_m <= 9.5e+42:
                                                                              		tmp = math.sqrt((-0.5 * (F / A))) * -math.sqrt(2.0)
                                                                              	else:
                                                                              		tmp = math.sqrt((F * 2.0)) / -math.sqrt(B_m)
                                                                              	return tmp
                                                                              
                                                                              B_m = abs(B)
                                                                              A, B_m, C, F = sort([A, B_m, C, F])
                                                                              function code(A, B_m, C, F)
                                                                              	tmp = 0.0
                                                                              	if (B_m <= 9.5e+42)
                                                                              		tmp = Float64(sqrt(Float64(-0.5 * Float64(F / A))) * Float64(-sqrt(2.0)));
                                                                              	else
                                                                              		tmp = Float64(sqrt(Float64(F * 2.0)) / Float64(-sqrt(B_m)));
                                                                              	end
                                                                              	return tmp
                                                                              end
                                                                              
                                                                              B_m = abs(B);
                                                                              A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                              function tmp_2 = code(A, B_m, C, F)
                                                                              	tmp = 0.0;
                                                                              	if (B_m <= 9.5e+42)
                                                                              		tmp = sqrt((-0.5 * (F / A))) * -sqrt(2.0);
                                                                              	else
                                                                              		tmp = sqrt((F * 2.0)) / -sqrt(B_m);
                                                                              	end
                                                                              	tmp_2 = tmp;
                                                                              end
                                                                              
                                                                              B_m = N[Abs[B], $MachinePrecision]
                                                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                              code[A_, B$95$m_, C_, F_] := If[LessEqual[B$95$m, 9.5e+42], N[(N[Sqrt[N[(-0.5 * N[(F / A), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[2.0], $MachinePrecision])), $MachinePrecision], N[(N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision] / (-N[Sqrt[B$95$m], $MachinePrecision])), $MachinePrecision]]
                                                                              
                                                                              \begin{array}{l}
                                                                              B_m = \left|B\right|
                                                                              \\
                                                                              [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                              \\
                                                                              \begin{array}{l}
                                                                              \mathbf{if}\;B\_m \leq 9.5 \cdot 10^{+42}:\\
                                                                              \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\
                                                                              
                                                                              \mathbf{else}:\\
                                                                              \;\;\;\;\frac{\sqrt{F \cdot 2}}{-\sqrt{B\_m}}\\
                                                                              
                                                                              
                                                                              \end{array}
                                                                              \end{array}
                                                                              
                                                                              Derivation
                                                                              1. Split input into 2 regimes
                                                                              2. if B < 9.50000000000000019e42

                                                                                1. Initial program 18.2%

                                                                                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                2. Add Preprocessing
                                                                                3. Taylor expanded in F around 0

                                                                                  \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                                                                4. Step-by-step derivation
                                                                                  1. mul-1-negN/A

                                                                                    \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                                                                  2. lower-neg.f64N/A

                                                                                    \[\leadsto \color{blue}{-\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}} \]
                                                                                  3. lower-*.f64N/A

                                                                                    \[\leadsto -\color{blue}{\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}} \]
                                                                                5. Applied rewrites20.0%

                                                                                  \[\leadsto \color{blue}{-\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \cdot \sqrt{2}} \]
                                                                                6. Taylor expanded in A around -inf

                                                                                  \[\leadsto -\sqrt{\frac{-1}{2} \cdot \frac{F}{A}} \cdot \sqrt{2} \]
                                                                                7. Step-by-step derivation
                                                                                  1. Applied rewrites15.1%

                                                                                    \[\leadsto -\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \sqrt{2} \]

                                                                                  if 9.50000000000000019e42 < B

                                                                                  1. Initial program 16.5%

                                                                                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                  2. Add Preprocessing
                                                                                  3. Taylor expanded in B around inf

                                                                                    \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                  4. Step-by-step derivation
                                                                                    1. mul-1-negN/A

                                                                                      \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                    2. lower-neg.f64N/A

                                                                                      \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                    3. lower-*.f64N/A

                                                                                      \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                    4. lower-sqrt.f64N/A

                                                                                      \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                                    5. lower-/.f64N/A

                                                                                      \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                                    6. lower-sqrt.f6447.8

                                                                                      \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                                                  5. Applied rewrites47.8%

                                                                                    \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                  6. Step-by-step derivation
                                                                                    1. Applied rewrites68.1%

                                                                                      \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
                                                                                  7. Recombined 2 regimes into one program.
                                                                                  8. Final simplification28.2%

                                                                                    \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 9.5 \cdot 10^{+42}:\\ \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{F \cdot 2}}{-\sqrt{B}}\\ \end{array} \]
                                                                                  9. Add Preprocessing

                                                                                  Alternative 13: 35.1% accurate, 12.6× speedup?

                                                                                  \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \frac{\sqrt{F \cdot 2}}{-\sqrt{B\_m}} \end{array} \]
                                                                                  B_m = (fabs.f64 B)
                                                                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                  (FPCore (A B_m C F) :precision binary64 (/ (sqrt (* F 2.0)) (- (sqrt B_m))))
                                                                                  B_m = fabs(B);
                                                                                  assert(A < B_m && B_m < C && C < F);
                                                                                  double code(double A, double B_m, double C, double F) {
                                                                                  	return sqrt((F * 2.0)) / -sqrt(B_m);
                                                                                  }
                                                                                  
                                                                                  B_m = abs(b)
                                                                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                  real(8) function code(a, b_m, c, f)
                                                                                      real(8), intent (in) :: a
                                                                                      real(8), intent (in) :: b_m
                                                                                      real(8), intent (in) :: c
                                                                                      real(8), intent (in) :: f
                                                                                      code = sqrt((f * 2.0d0)) / -sqrt(b_m)
                                                                                  end function
                                                                                  
                                                                                  B_m = Math.abs(B);
                                                                                  assert A < B_m && B_m < C && C < F;
                                                                                  public static double code(double A, double B_m, double C, double F) {
                                                                                  	return Math.sqrt((F * 2.0)) / -Math.sqrt(B_m);
                                                                                  }
                                                                                  
                                                                                  B_m = math.fabs(B)
                                                                                  [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                                  def code(A, B_m, C, F):
                                                                                  	return math.sqrt((F * 2.0)) / -math.sqrt(B_m)
                                                                                  
                                                                                  B_m = abs(B)
                                                                                  A, B_m, C, F = sort([A, B_m, C, F])
                                                                                  function code(A, B_m, C, F)
                                                                                  	return Float64(sqrt(Float64(F * 2.0)) / Float64(-sqrt(B_m)))
                                                                                  end
                                                                                  
                                                                                  B_m = abs(B);
                                                                                  A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                                  function tmp = code(A, B_m, C, F)
                                                                                  	tmp = sqrt((F * 2.0)) / -sqrt(B_m);
                                                                                  end
                                                                                  
                                                                                  B_m = N[Abs[B], $MachinePrecision]
                                                                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                  code[A_, B$95$m_, C_, F_] := N[(N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision] / (-N[Sqrt[B$95$m], $MachinePrecision])), $MachinePrecision]
                                                                                  
                                                                                  \begin{array}{l}
                                                                                  B_m = \left|B\right|
                                                                                  \\
                                                                                  [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                                  \\
                                                                                  \frac{\sqrt{F \cdot 2}}{-\sqrt{B\_m}}
                                                                                  \end{array}
                                                                                  
                                                                                  Derivation
                                                                                  1. Initial program 17.8%

                                                                                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                  2. Add Preprocessing
                                                                                  3. Taylor expanded in B around inf

                                                                                    \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                  4. Step-by-step derivation
                                                                                    1. mul-1-negN/A

                                                                                      \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                    2. lower-neg.f64N/A

                                                                                      \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                    3. lower-*.f64N/A

                                                                                      \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                    4. lower-sqrt.f64N/A

                                                                                      \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                                    5. lower-/.f64N/A

                                                                                      \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                                    6. lower-sqrt.f6414.4

                                                                                      \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                                                  5. Applied rewrites14.4%

                                                                                    \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                  6. Step-by-step derivation
                                                                                    1. Applied rewrites18.9%

                                                                                      \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
                                                                                    2. Final simplification18.9%

                                                                                      \[\leadsto \frac{\sqrt{F \cdot 2}}{-\sqrt{B}} \]
                                                                                    3. Add Preprocessing

                                                                                    Alternative 14: 35.1% accurate, 12.6× speedup?

                                                                                    \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}} \end{array} \]
                                                                                    B_m = (fabs.f64 B)
                                                                                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                    (FPCore (A B_m C F) :precision binary64 (* (- (sqrt F)) (sqrt (/ 2.0 B_m))))
                                                                                    B_m = fabs(B);
                                                                                    assert(A < B_m && B_m < C && C < F);
                                                                                    double code(double A, double B_m, double C, double F) {
                                                                                    	return -sqrt(F) * sqrt((2.0 / B_m));
                                                                                    }
                                                                                    
                                                                                    B_m = abs(b)
                                                                                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                    real(8) function code(a, b_m, c, f)
                                                                                        real(8), intent (in) :: a
                                                                                        real(8), intent (in) :: b_m
                                                                                        real(8), intent (in) :: c
                                                                                        real(8), intent (in) :: f
                                                                                        code = -sqrt(f) * sqrt((2.0d0 / b_m))
                                                                                    end function
                                                                                    
                                                                                    B_m = Math.abs(B);
                                                                                    assert A < B_m && B_m < C && C < F;
                                                                                    public static double code(double A, double B_m, double C, double F) {
                                                                                    	return -Math.sqrt(F) * Math.sqrt((2.0 / B_m));
                                                                                    }
                                                                                    
                                                                                    B_m = math.fabs(B)
                                                                                    [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                                    def code(A, B_m, C, F):
                                                                                    	return -math.sqrt(F) * math.sqrt((2.0 / B_m))
                                                                                    
                                                                                    B_m = abs(B)
                                                                                    A, B_m, C, F = sort([A, B_m, C, F])
                                                                                    function code(A, B_m, C, F)
                                                                                    	return Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)))
                                                                                    end
                                                                                    
                                                                                    B_m = abs(B);
                                                                                    A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                                    function tmp = code(A, B_m, C, F)
                                                                                    	tmp = -sqrt(F) * sqrt((2.0 / B_m));
                                                                                    end
                                                                                    
                                                                                    B_m = N[Abs[B], $MachinePrecision]
                                                                                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                    code[A_, B$95$m_, C_, F_] := N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
                                                                                    
                                                                                    \begin{array}{l}
                                                                                    B_m = \left|B\right|
                                                                                    \\
                                                                                    [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                                    \\
                                                                                    \left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}
                                                                                    \end{array}
                                                                                    
                                                                                    Derivation
                                                                                    1. Initial program 17.8%

                                                                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                    2. Add Preprocessing
                                                                                    3. Taylor expanded in B around inf

                                                                                      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                    4. Step-by-step derivation
                                                                                      1. mul-1-negN/A

                                                                                        \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                      2. lower-neg.f64N/A

                                                                                        \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                      3. lower-*.f64N/A

                                                                                        \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                      4. lower-sqrt.f64N/A

                                                                                        \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                                      5. lower-/.f64N/A

                                                                                        \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                                      6. lower-sqrt.f6414.4

                                                                                        \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                                                    5. Applied rewrites14.4%

                                                                                      \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                    6. Step-by-step derivation
                                                                                      1. Applied rewrites14.5%

                                                                                        \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                                      2. Step-by-step derivation
                                                                                        1. Applied rewrites18.9%

                                                                                          \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                                                                        2. Final simplification18.9%

                                                                                          \[\leadsto \left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}} \]
                                                                                        3. Add Preprocessing

                                                                                        Alternative 15: 27.7% accurate, 16.9× speedup?

                                                                                        \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ -\sqrt{\frac{F}{B\_m} \cdot 2} \end{array} \]
                                                                                        B_m = (fabs.f64 B)
                                                                                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                        (FPCore (A B_m C F) :precision binary64 (- (sqrt (* (/ F B_m) 2.0))))
                                                                                        B_m = fabs(B);
                                                                                        assert(A < B_m && B_m < C && C < F);
                                                                                        double code(double A, double B_m, double C, double F) {
                                                                                        	return -sqrt(((F / B_m) * 2.0));
                                                                                        }
                                                                                        
                                                                                        B_m = abs(b)
                                                                                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                        real(8) function code(a, b_m, c, f)
                                                                                            real(8), intent (in) :: a
                                                                                            real(8), intent (in) :: b_m
                                                                                            real(8), intent (in) :: c
                                                                                            real(8), intent (in) :: f
                                                                                            code = -sqrt(((f / b_m) * 2.0d0))
                                                                                        end function
                                                                                        
                                                                                        B_m = Math.abs(B);
                                                                                        assert A < B_m && B_m < C && C < F;
                                                                                        public static double code(double A, double B_m, double C, double F) {
                                                                                        	return -Math.sqrt(((F / B_m) * 2.0));
                                                                                        }
                                                                                        
                                                                                        B_m = math.fabs(B)
                                                                                        [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                                        def code(A, B_m, C, F):
                                                                                        	return -math.sqrt(((F / B_m) * 2.0))
                                                                                        
                                                                                        B_m = abs(B)
                                                                                        A, B_m, C, F = sort([A, B_m, C, F])
                                                                                        function code(A, B_m, C, F)
                                                                                        	return Float64(-sqrt(Float64(Float64(F / B_m) * 2.0)))
                                                                                        end
                                                                                        
                                                                                        B_m = abs(B);
                                                                                        A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                                        function tmp = code(A, B_m, C, F)
                                                                                        	tmp = -sqrt(((F / B_m) * 2.0));
                                                                                        end
                                                                                        
                                                                                        B_m = N[Abs[B], $MachinePrecision]
                                                                                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                        code[A_, B$95$m_, C_, F_] := (-N[Sqrt[N[(N[(F / B$95$m), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision])
                                                                                        
                                                                                        \begin{array}{l}
                                                                                        B_m = \left|B\right|
                                                                                        \\
                                                                                        [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                                        \\
                                                                                        -\sqrt{\frac{F}{B\_m} \cdot 2}
                                                                                        \end{array}
                                                                                        
                                                                                        Derivation
                                                                                        1. Initial program 17.8%

                                                                                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                        2. Add Preprocessing
                                                                                        3. Taylor expanded in B around inf

                                                                                          \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                        4. Step-by-step derivation
                                                                                          1. mul-1-negN/A

                                                                                            \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                          2. lower-neg.f64N/A

                                                                                            \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                          3. lower-*.f64N/A

                                                                                            \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                          4. lower-sqrt.f64N/A

                                                                                            \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                                          5. lower-/.f64N/A

                                                                                            \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                                          6. lower-sqrt.f6414.4

                                                                                            \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                                                        5. Applied rewrites14.4%

                                                                                          \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                        6. Step-by-step derivation
                                                                                          1. Applied rewrites14.5%

                                                                                            \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                                          2. Add Preprocessing

                                                                                          Alternative 16: 27.7% accurate, 16.9× speedup?

                                                                                          \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ -\sqrt{F \cdot \frac{2}{B\_m}} \end{array} \]
                                                                                          B_m = (fabs.f64 B)
                                                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                          (FPCore (A B_m C F) :precision binary64 (- (sqrt (* F (/ 2.0 B_m)))))
                                                                                          B_m = fabs(B);
                                                                                          assert(A < B_m && B_m < C && C < F);
                                                                                          double code(double A, double B_m, double C, double F) {
                                                                                          	return -sqrt((F * (2.0 / B_m)));
                                                                                          }
                                                                                          
                                                                                          B_m = abs(b)
                                                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                          real(8) function code(a, b_m, c, f)
                                                                                              real(8), intent (in) :: a
                                                                                              real(8), intent (in) :: b_m
                                                                                              real(8), intent (in) :: c
                                                                                              real(8), intent (in) :: f
                                                                                              code = -sqrt((f * (2.0d0 / b_m)))
                                                                                          end function
                                                                                          
                                                                                          B_m = Math.abs(B);
                                                                                          assert A < B_m && B_m < C && C < F;
                                                                                          public static double code(double A, double B_m, double C, double F) {
                                                                                          	return -Math.sqrt((F * (2.0 / B_m)));
                                                                                          }
                                                                                          
                                                                                          B_m = math.fabs(B)
                                                                                          [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                                          def code(A, B_m, C, F):
                                                                                          	return -math.sqrt((F * (2.0 / B_m)))
                                                                                          
                                                                                          B_m = abs(B)
                                                                                          A, B_m, C, F = sort([A, B_m, C, F])
                                                                                          function code(A, B_m, C, F)
                                                                                          	return Float64(-sqrt(Float64(F * Float64(2.0 / B_m))))
                                                                                          end
                                                                                          
                                                                                          B_m = abs(B);
                                                                                          A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                                          function tmp = code(A, B_m, C, F)
                                                                                          	tmp = -sqrt((F * (2.0 / B_m)));
                                                                                          end
                                                                                          
                                                                                          B_m = N[Abs[B], $MachinePrecision]
                                                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                          code[A_, B$95$m_, C_, F_] := (-N[Sqrt[N[(F * N[(2.0 / B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision])
                                                                                          
                                                                                          \begin{array}{l}
                                                                                          B_m = \left|B\right|
                                                                                          \\
                                                                                          [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                                          \\
                                                                                          -\sqrt{F \cdot \frac{2}{B\_m}}
                                                                                          \end{array}
                                                                                          
                                                                                          Derivation
                                                                                          1. Initial program 17.8%

                                                                                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                          2. Add Preprocessing
                                                                                          3. Taylor expanded in B around inf

                                                                                            \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                          4. Step-by-step derivation
                                                                                            1. mul-1-negN/A

                                                                                              \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                            2. lower-neg.f64N/A

                                                                                              \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                            3. lower-*.f64N/A

                                                                                              \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                            4. lower-sqrt.f64N/A

                                                                                              \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                                            5. lower-/.f64N/A

                                                                                              \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                                            6. lower-sqrt.f6414.4

                                                                                              \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                                                          5. Applied rewrites14.4%

                                                                                            \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                          6. Step-by-step derivation
                                                                                            1. Applied rewrites14.5%

                                                                                              \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                                            2. Step-by-step derivation
                                                                                              1. Applied rewrites14.4%

                                                                                                \[\leadsto -\sqrt{F \cdot \frac{2}{B}} \]
                                                                                              2. Add Preprocessing

                                                                                              Reproduce

                                                                                              ?
                                                                                              herbie shell --seed 2024339 
                                                                                              (FPCore (A B C F)
                                                                                                :name "ABCF->ab-angle a"
                                                                                                :precision binary64
                                                                                                (/ (- (sqrt (* (* 2.0 (* (- (pow B 2.0) (* (* 4.0 A) C)) F)) (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))) (- (pow B 2.0) (* (* 4.0 A) C))))