Quotient of sum of exps

Percentage Accurate: 99.1% → 99.1%
Time: 5.8s
Alternatives: 10
Speedup: 1.0×

Specification

?
\[\begin{array}{l} \\ \frac{e^{a}}{e^{a} + e^{b}} \end{array} \]
(FPCore (a b) :precision binary64 (/ (exp a) (+ (exp a) (exp b))))
double code(double a, double b) {
	return exp(a) / (exp(a) + exp(b));
}
real(8) function code(a, b)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    code = exp(a) / (exp(a) + exp(b))
end function
public static double code(double a, double b) {
	return Math.exp(a) / (Math.exp(a) + Math.exp(b));
}
def code(a, b):
	return math.exp(a) / (math.exp(a) + math.exp(b))
function code(a, b)
	return Float64(exp(a) / Float64(exp(a) + exp(b)))
end
function tmp = code(a, b)
	tmp = exp(a) / (exp(a) + exp(b));
end
code[a_, b_] := N[(N[Exp[a], $MachinePrecision] / N[(N[Exp[a], $MachinePrecision] + N[Exp[b], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{e^{a}}{e^{a} + e^{b}}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 10 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 99.1% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{e^{a}}{e^{a} + e^{b}} \end{array} \]
(FPCore (a b) :precision binary64 (/ (exp a) (+ (exp a) (exp b))))
double code(double a, double b) {
	return exp(a) / (exp(a) + exp(b));
}
real(8) function code(a, b)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    code = exp(a) / (exp(a) + exp(b))
end function
public static double code(double a, double b) {
	return Math.exp(a) / (Math.exp(a) + Math.exp(b));
}
def code(a, b):
	return math.exp(a) / (math.exp(a) + math.exp(b))
function code(a, b)
	return Float64(exp(a) / Float64(exp(a) + exp(b)))
end
function tmp = code(a, b)
	tmp = exp(a) / (exp(a) + exp(b));
end
code[a_, b_] := N[(N[Exp[a], $MachinePrecision] / N[(N[Exp[a], $MachinePrecision] + N[Exp[b], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{e^{a}}{e^{a} + e^{b}}
\end{array}

Alternative 1: 99.1% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{e^{a}}{e^{a} + e^{b}} \end{array} \]
(FPCore (a b) :precision binary64 (/ (exp a) (+ (exp a) (exp b))))
double code(double a, double b) {
	return exp(a) / (exp(a) + exp(b));
}
real(8) function code(a, b)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    code = exp(a) / (exp(a) + exp(b))
end function
public static double code(double a, double b) {
	return Math.exp(a) / (Math.exp(a) + Math.exp(b));
}
def code(a, b):
	return math.exp(a) / (math.exp(a) + math.exp(b))
function code(a, b)
	return Float64(exp(a) / Float64(exp(a) + exp(b)))
end
function tmp = code(a, b)
	tmp = exp(a) / (exp(a) + exp(b));
end
code[a_, b_] := N[(N[Exp[a], $MachinePrecision] / N[(N[Exp[a], $MachinePrecision] + N[Exp[b], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{e^{a}}{e^{a} + e^{b}}
\end{array}
Derivation
  1. Initial program 98.8%

    \[\frac{e^{a}}{e^{a} + e^{b}} \]
  2. Add Preprocessing
  3. Add Preprocessing

Alternative 2: 98.4% accurate, 1.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;a \leq -520000:\\ \;\;\;\;\frac{e^{a}}{2}\\ \mathbf{else}:\\ \;\;\;\;{\left(e^{b} + 1\right)}^{-1}\\ \end{array} \end{array} \]
(FPCore (a b)
 :precision binary64
 (if (<= a -520000.0) (/ (exp a) 2.0) (pow (+ (exp b) 1.0) -1.0)))
double code(double a, double b) {
	double tmp;
	if (a <= -520000.0) {
		tmp = exp(a) / 2.0;
	} else {
		tmp = pow((exp(b) + 1.0), -1.0);
	}
	return tmp;
}
real(8) function code(a, b)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8) :: tmp
    if (a <= (-520000.0d0)) then
        tmp = exp(a) / 2.0d0
    else
        tmp = (exp(b) + 1.0d0) ** (-1.0d0)
    end if
    code = tmp
end function
public static double code(double a, double b) {
	double tmp;
	if (a <= -520000.0) {
		tmp = Math.exp(a) / 2.0;
	} else {
		tmp = Math.pow((Math.exp(b) + 1.0), -1.0);
	}
	return tmp;
}
def code(a, b):
	tmp = 0
	if a <= -520000.0:
		tmp = math.exp(a) / 2.0
	else:
		tmp = math.pow((math.exp(b) + 1.0), -1.0)
	return tmp
function code(a, b)
	tmp = 0.0
	if (a <= -520000.0)
		tmp = Float64(exp(a) / 2.0);
	else
		tmp = Float64(exp(b) + 1.0) ^ -1.0;
	end
	return tmp
end
function tmp_2 = code(a, b)
	tmp = 0.0;
	if (a <= -520000.0)
		tmp = exp(a) / 2.0;
	else
		tmp = (exp(b) + 1.0) ^ -1.0;
	end
	tmp_2 = tmp;
end
code[a_, b_] := If[LessEqual[a, -520000.0], N[(N[Exp[a], $MachinePrecision] / 2.0), $MachinePrecision], N[Power[N[(N[Exp[b], $MachinePrecision] + 1.0), $MachinePrecision], -1.0], $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;a \leq -520000:\\
\;\;\;\;\frac{e^{a}}{2}\\

\mathbf{else}:\\
\;\;\;\;{\left(e^{b} + 1\right)}^{-1}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if a < -5.2e5

    1. Initial program 98.4%

      \[\frac{e^{a}}{e^{a} + e^{b}} \]
    2. Add Preprocessing
    3. Taylor expanded in b around 0

      \[\leadsto \frac{e^{a}}{\color{blue}{1 + e^{a}}} \]
    4. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
      2. lower-+.f64N/A

        \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
      3. lower-exp.f64100.0

        \[\leadsto \frac{e^{a}}{\color{blue}{e^{a}} + 1} \]
    5. Applied rewrites100.0%

      \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
    6. Taylor expanded in a around 0

      \[\leadsto \frac{e^{a}}{2} \]
    7. Step-by-step derivation
      1. Applied rewrites100.0%

        \[\leadsto \frac{e^{a}}{2} \]

      if -5.2e5 < a

      1. Initial program 99.0%

        \[\frac{e^{a}}{e^{a} + e^{b}} \]
      2. Add Preprocessing
      3. Taylor expanded in a around 0

        \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
      4. Step-by-step derivation
        1. lower-/.f64N/A

          \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
        2. +-commutativeN/A

          \[\leadsto \frac{1}{\color{blue}{e^{b} + 1}} \]
        3. lower-+.f64N/A

          \[\leadsto \frac{1}{\color{blue}{e^{b} + 1}} \]
        4. lower-exp.f6498.4

          \[\leadsto \frac{1}{\color{blue}{e^{b}} + 1} \]
      5. Applied rewrites98.4%

        \[\leadsto \color{blue}{\frac{1}{e^{b} + 1}} \]
    8. Recombined 2 regimes into one program.
    9. Final simplification98.8%

      \[\leadsto \begin{array}{l} \mathbf{if}\;a \leq -520000:\\ \;\;\;\;\frac{e^{a}}{2}\\ \mathbf{else}:\\ \;\;\;\;{\left(e^{b} + 1\right)}^{-1}\\ \end{array} \]
    10. Add Preprocessing

    Alternative 3: 77.3% accurate, 2.4× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;b \leq 120000:\\ \;\;\;\;\frac{e^{a}}{2}\\ \mathbf{elif}\;b \leq 1.05 \cdot 10^{+103}:\\ \;\;\;\;\frac{\left(a \cdot a\right) \cdot 0.5}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), a, 2\right)}\\ \mathbf{else}:\\ \;\;\;\;{\left(\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, b, 0.5\right), b, 1\right), b, 2\right)\right)}^{-1}\\ \end{array} \end{array} \]
    (FPCore (a b)
     :precision binary64
     (if (<= b 120000.0)
       (/ (exp a) 2.0)
       (if (<= b 1.05e+103)
         (/ (* (* a a) 0.5) (fma (fma 0.5 a 1.0) a 2.0))
         (pow (fma (fma (fma 0.16666666666666666 b 0.5) b 1.0) b 2.0) -1.0))))
    double code(double a, double b) {
    	double tmp;
    	if (b <= 120000.0) {
    		tmp = exp(a) / 2.0;
    	} else if (b <= 1.05e+103) {
    		tmp = ((a * a) * 0.5) / fma(fma(0.5, a, 1.0), a, 2.0);
    	} else {
    		tmp = pow(fma(fma(fma(0.16666666666666666, b, 0.5), b, 1.0), b, 2.0), -1.0);
    	}
    	return tmp;
    }
    
    function code(a, b)
    	tmp = 0.0
    	if (b <= 120000.0)
    		tmp = Float64(exp(a) / 2.0);
    	elseif (b <= 1.05e+103)
    		tmp = Float64(Float64(Float64(a * a) * 0.5) / fma(fma(0.5, a, 1.0), a, 2.0));
    	else
    		tmp = fma(fma(fma(0.16666666666666666, b, 0.5), b, 1.0), b, 2.0) ^ -1.0;
    	end
    	return tmp
    end
    
    code[a_, b_] := If[LessEqual[b, 120000.0], N[(N[Exp[a], $MachinePrecision] / 2.0), $MachinePrecision], If[LessEqual[b, 1.05e+103], N[(N[(N[(a * a), $MachinePrecision] * 0.5), $MachinePrecision] / N[(N[(0.5 * a + 1.0), $MachinePrecision] * a + 2.0), $MachinePrecision]), $MachinePrecision], N[Power[N[(N[(N[(0.16666666666666666 * b + 0.5), $MachinePrecision] * b + 1.0), $MachinePrecision] * b + 2.0), $MachinePrecision], -1.0], $MachinePrecision]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;b \leq 120000:\\
    \;\;\;\;\frac{e^{a}}{2}\\
    
    \mathbf{elif}\;b \leq 1.05 \cdot 10^{+103}:\\
    \;\;\;\;\frac{\left(a \cdot a\right) \cdot 0.5}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), a, 2\right)}\\
    
    \mathbf{else}:\\
    \;\;\;\;{\left(\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, b, 0.5\right), b, 1\right), b, 2\right)\right)}^{-1}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 3 regimes
    2. if b < 1.2e5

      1. Initial program 98.3%

        \[\frac{e^{a}}{e^{a} + e^{b}} \]
      2. Add Preprocessing
      3. Taylor expanded in b around 0

        \[\leadsto \frac{e^{a}}{\color{blue}{1 + e^{a}}} \]
      4. Step-by-step derivation
        1. +-commutativeN/A

          \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
        2. lower-+.f64N/A

          \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
        3. lower-exp.f6477.9

          \[\leadsto \frac{e^{a}}{\color{blue}{e^{a}} + 1} \]
      5. Applied rewrites77.9%

        \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
      6. Taylor expanded in a around 0

        \[\leadsto \frac{e^{a}}{2} \]
      7. Step-by-step derivation
        1. Applied rewrites77.1%

          \[\leadsto \frac{e^{a}}{2} \]

        if 1.2e5 < b < 1.0500000000000001e103

        1. Initial program 100.0%

          \[\frac{e^{a}}{e^{a} + e^{b}} \]
        2. Add Preprocessing
        3. Taylor expanded in b around 0

          \[\leadsto \frac{e^{a}}{\color{blue}{1 + e^{a}}} \]
        4. Step-by-step derivation
          1. +-commutativeN/A

            \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
          2. lower-+.f64N/A

            \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
          3. lower-exp.f6422.5

            \[\leadsto \frac{e^{a}}{\color{blue}{e^{a}} + 1} \]
        5. Applied rewrites22.5%

          \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
        6. Taylor expanded in a around 0

          \[\leadsto \frac{e^{a}}{2 + \color{blue}{a \cdot \left(1 + \frac{1}{2} \cdot a\right)}} \]
        7. Step-by-step derivation
          1. Applied rewrites22.5%

            \[\leadsto \frac{e^{a}}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), \color{blue}{a}, 2\right)} \]
          2. Taylor expanded in a around 0

            \[\leadsto \frac{\color{blue}{1 + a \cdot \left(1 + \frac{1}{2} \cdot a\right)}}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{2}, a, 1\right), a, 2\right)} \]
          3. Step-by-step derivation
            1. +-commutativeN/A

              \[\leadsto \frac{\color{blue}{a \cdot \left(1 + \frac{1}{2} \cdot a\right) + 1}}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{2}, a, 1\right), a, 2\right)} \]
            2. *-commutativeN/A

              \[\leadsto \frac{\color{blue}{\left(1 + \frac{1}{2} \cdot a\right) \cdot a} + 1}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{2}, a, 1\right), a, 2\right)} \]
            3. lower-fma.f64N/A

              \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(1 + \frac{1}{2} \cdot a, a, 1\right)}}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{2}, a, 1\right), a, 2\right)} \]
            4. +-commutativeN/A

              \[\leadsto \frac{\mathsf{fma}\left(\color{blue}{\frac{1}{2} \cdot a + 1}, a, 1\right)}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{2}, a, 1\right), a, 2\right)} \]
            5. lower-fma.f642.8

              \[\leadsto \frac{\mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(0.5, a, 1\right)}, a, 1\right)}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), a, 2\right)} \]
          4. Applied rewrites2.8%

            \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), a, 1\right)}}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), a, 2\right)} \]
          5. Taylor expanded in a around inf

            \[\leadsto \frac{\frac{1}{2} \cdot \color{blue}{{a}^{2}}}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{2}, a, 1\right), a, 2\right)} \]
          6. Step-by-step derivation
            1. Applied rewrites53.9%

              \[\leadsto \frac{\left(a \cdot a\right) \cdot \color{blue}{0.5}}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), a, 2\right)} \]

            if 1.0500000000000001e103 < b

            1. Initial program 100.0%

              \[\frac{e^{a}}{e^{a} + e^{b}} \]
            2. Add Preprocessing
            3. Taylor expanded in a around 0

              \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
            4. Step-by-step derivation
              1. lower-/.f64N/A

                \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
              2. +-commutativeN/A

                \[\leadsto \frac{1}{\color{blue}{e^{b} + 1}} \]
              3. lower-+.f64N/A

                \[\leadsto \frac{1}{\color{blue}{e^{b} + 1}} \]
              4. lower-exp.f64100.0

                \[\leadsto \frac{1}{\color{blue}{e^{b}} + 1} \]
            5. Applied rewrites100.0%

              \[\leadsto \color{blue}{\frac{1}{e^{b} + 1}} \]
            6. Taylor expanded in b around 0

              \[\leadsto \frac{1}{2 + \color{blue}{b \cdot \left(1 + b \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot b\right)\right)}} \]
            7. Step-by-step derivation
              1. Applied rewrites100.0%

                \[\leadsto \frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, b, 0.5\right), b, 1\right), \color{blue}{b}, 2\right)} \]
            8. Recombined 3 regimes into one program.
            9. Final simplification78.4%

              \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq 120000:\\ \;\;\;\;\frac{e^{a}}{2}\\ \mathbf{elif}\;b \leq 1.05 \cdot 10^{+103}:\\ \;\;\;\;\frac{\left(a \cdot a\right) \cdot 0.5}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), a, 2\right)}\\ \mathbf{else}:\\ \;\;\;\;{\left(\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, b, 0.5\right), b, 1\right), b, 2\right)\right)}^{-1}\\ \end{array} \]
            10. Add Preprocessing

            Alternative 4: 71.9% accurate, 2.4× speedup?

            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;b \leq 105000:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, a, 0.5\right), a, 1\right), a, 2\right)}\\ \mathbf{elif}\;b \leq 1.05 \cdot 10^{+103}:\\ \;\;\;\;\frac{\left(a \cdot a\right) \cdot 0.5}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), a, 2\right)}\\ \mathbf{else}:\\ \;\;\;\;{\left(\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, b, 0.5\right), b, 1\right), b, 2\right)\right)}^{-1}\\ \end{array} \end{array} \]
            (FPCore (a b)
             :precision binary64
             (if (<= b 105000.0)
               (/ 1.0 (fma (fma (fma 0.16666666666666666 a 0.5) a 1.0) a 2.0))
               (if (<= b 1.05e+103)
                 (/ (* (* a a) 0.5) (fma (fma 0.5 a 1.0) a 2.0))
                 (pow (fma (fma (fma 0.16666666666666666 b 0.5) b 1.0) b 2.0) -1.0))))
            double code(double a, double b) {
            	double tmp;
            	if (b <= 105000.0) {
            		tmp = 1.0 / fma(fma(fma(0.16666666666666666, a, 0.5), a, 1.0), a, 2.0);
            	} else if (b <= 1.05e+103) {
            		tmp = ((a * a) * 0.5) / fma(fma(0.5, a, 1.0), a, 2.0);
            	} else {
            		tmp = pow(fma(fma(fma(0.16666666666666666, b, 0.5), b, 1.0), b, 2.0), -1.0);
            	}
            	return tmp;
            }
            
            function code(a, b)
            	tmp = 0.0
            	if (b <= 105000.0)
            		tmp = Float64(1.0 / fma(fma(fma(0.16666666666666666, a, 0.5), a, 1.0), a, 2.0));
            	elseif (b <= 1.05e+103)
            		tmp = Float64(Float64(Float64(a * a) * 0.5) / fma(fma(0.5, a, 1.0), a, 2.0));
            	else
            		tmp = fma(fma(fma(0.16666666666666666, b, 0.5), b, 1.0), b, 2.0) ^ -1.0;
            	end
            	return tmp
            end
            
            code[a_, b_] := If[LessEqual[b, 105000.0], N[(1.0 / N[(N[(N[(0.16666666666666666 * a + 0.5), $MachinePrecision] * a + 1.0), $MachinePrecision] * a + 2.0), $MachinePrecision]), $MachinePrecision], If[LessEqual[b, 1.05e+103], N[(N[(N[(a * a), $MachinePrecision] * 0.5), $MachinePrecision] / N[(N[(0.5 * a + 1.0), $MachinePrecision] * a + 2.0), $MachinePrecision]), $MachinePrecision], N[Power[N[(N[(N[(0.16666666666666666 * b + 0.5), $MachinePrecision] * b + 1.0), $MachinePrecision] * b + 2.0), $MachinePrecision], -1.0], $MachinePrecision]]]
            
            \begin{array}{l}
            
            \\
            \begin{array}{l}
            \mathbf{if}\;b \leq 105000:\\
            \;\;\;\;\frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, a, 0.5\right), a, 1\right), a, 2\right)}\\
            
            \mathbf{elif}\;b \leq 1.05 \cdot 10^{+103}:\\
            \;\;\;\;\frac{\left(a \cdot a\right) \cdot 0.5}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), a, 2\right)}\\
            
            \mathbf{else}:\\
            \;\;\;\;{\left(\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, b, 0.5\right), b, 1\right), b, 2\right)\right)}^{-1}\\
            
            
            \end{array}
            \end{array}
            
            Derivation
            1. Split input into 3 regimes
            2. if b < 105000

              1. Initial program 98.3%

                \[\frac{e^{a}}{e^{a} + e^{b}} \]
              2. Add Preprocessing
              3. Taylor expanded in b around 0

                \[\leadsto \frac{e^{a}}{\color{blue}{1 + e^{a}}} \]
              4. Step-by-step derivation
                1. +-commutativeN/A

                  \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
                2. lower-+.f64N/A

                  \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
                3. lower-exp.f6477.9

                  \[\leadsto \frac{e^{a}}{\color{blue}{e^{a}} + 1} \]
              5. Applied rewrites77.9%

                \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
              6. Taylor expanded in a around 0

                \[\leadsto \frac{e^{a}}{2 + \color{blue}{a \cdot \left(1 + a \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot a\right)\right)}} \]
              7. Step-by-step derivation
                1. Applied rewrites77.9%

                  \[\leadsto \frac{e^{a}}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, a, 0.5\right), a, 1\right), \color{blue}{a}, 2\right)} \]
                2. Taylor expanded in a around 0

                  \[\leadsto \frac{\color{blue}{1}}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{6}, a, \frac{1}{2}\right), a, 1\right), a, 2\right)} \]
                3. Step-by-step derivation
                  1. Applied rewrites71.0%

                    \[\leadsto \frac{\color{blue}{1}}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, a, 0.5\right), a, 1\right), a, 2\right)} \]

                  if 105000 < b < 1.0500000000000001e103

                  1. Initial program 100.0%

                    \[\frac{e^{a}}{e^{a} + e^{b}} \]
                  2. Add Preprocessing
                  3. Taylor expanded in b around 0

                    \[\leadsto \frac{e^{a}}{\color{blue}{1 + e^{a}}} \]
                  4. Step-by-step derivation
                    1. +-commutativeN/A

                      \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
                    2. lower-+.f64N/A

                      \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
                    3. lower-exp.f6422.5

                      \[\leadsto \frac{e^{a}}{\color{blue}{e^{a}} + 1} \]
                  5. Applied rewrites22.5%

                    \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
                  6. Taylor expanded in a around 0

                    \[\leadsto \frac{e^{a}}{2 + \color{blue}{a \cdot \left(1 + \frac{1}{2} \cdot a\right)}} \]
                  7. Step-by-step derivation
                    1. Applied rewrites22.5%

                      \[\leadsto \frac{e^{a}}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), \color{blue}{a}, 2\right)} \]
                    2. Taylor expanded in a around 0

                      \[\leadsto \frac{\color{blue}{1 + a \cdot \left(1 + \frac{1}{2} \cdot a\right)}}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{2}, a, 1\right), a, 2\right)} \]
                    3. Step-by-step derivation
                      1. +-commutativeN/A

                        \[\leadsto \frac{\color{blue}{a \cdot \left(1 + \frac{1}{2} \cdot a\right) + 1}}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{2}, a, 1\right), a, 2\right)} \]
                      2. *-commutativeN/A

                        \[\leadsto \frac{\color{blue}{\left(1 + \frac{1}{2} \cdot a\right) \cdot a} + 1}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{2}, a, 1\right), a, 2\right)} \]
                      3. lower-fma.f64N/A

                        \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(1 + \frac{1}{2} \cdot a, a, 1\right)}}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{2}, a, 1\right), a, 2\right)} \]
                      4. +-commutativeN/A

                        \[\leadsto \frac{\mathsf{fma}\left(\color{blue}{\frac{1}{2} \cdot a + 1}, a, 1\right)}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{2}, a, 1\right), a, 2\right)} \]
                      5. lower-fma.f642.8

                        \[\leadsto \frac{\mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(0.5, a, 1\right)}, a, 1\right)}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), a, 2\right)} \]
                    4. Applied rewrites2.8%

                      \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), a, 1\right)}}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), a, 2\right)} \]
                    5. Taylor expanded in a around inf

                      \[\leadsto \frac{\frac{1}{2} \cdot \color{blue}{{a}^{2}}}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{2}, a, 1\right), a, 2\right)} \]
                    6. Step-by-step derivation
                      1. Applied rewrites53.9%

                        \[\leadsto \frac{\left(a \cdot a\right) \cdot \color{blue}{0.5}}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), a, 2\right)} \]

                      if 1.0500000000000001e103 < b

                      1. Initial program 100.0%

                        \[\frac{e^{a}}{e^{a} + e^{b}} \]
                      2. Add Preprocessing
                      3. Taylor expanded in a around 0

                        \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                      4. Step-by-step derivation
                        1. lower-/.f64N/A

                          \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                        2. +-commutativeN/A

                          \[\leadsto \frac{1}{\color{blue}{e^{b} + 1}} \]
                        3. lower-+.f64N/A

                          \[\leadsto \frac{1}{\color{blue}{e^{b} + 1}} \]
                        4. lower-exp.f64100.0

                          \[\leadsto \frac{1}{\color{blue}{e^{b}} + 1} \]
                      5. Applied rewrites100.0%

                        \[\leadsto \color{blue}{\frac{1}{e^{b} + 1}} \]
                      6. Taylor expanded in b around 0

                        \[\leadsto \frac{1}{2 + \color{blue}{b \cdot \left(1 + b \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot b\right)\right)}} \]
                      7. Step-by-step derivation
                        1. Applied rewrites100.0%

                          \[\leadsto \frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, b, 0.5\right), b, 1\right), \color{blue}{b}, 2\right)} \]
                      8. Recombined 3 regimes into one program.
                      9. Final simplification74.1%

                        \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq 105000:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, a, 0.5\right), a, 1\right), a, 2\right)}\\ \mathbf{elif}\;b \leq 1.05 \cdot 10^{+103}:\\ \;\;\;\;\frac{\left(a \cdot a\right) \cdot 0.5}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), a, 2\right)}\\ \mathbf{else}:\\ \;\;\;\;{\left(\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, b, 0.5\right), b, 1\right), b, 2\right)\right)}^{-1}\\ \end{array} \]
                      10. Add Preprocessing

                      Alternative 5: 70.8% accurate, 2.5× speedup?

                      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;b \leq 4.8 \cdot 10^{+82}:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, a, 0.5\right), a, 1\right), a, 2\right)}\\ \mathbf{else}:\\ \;\;\;\;{\left(\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, b, 0.5\right), b, 1\right), b, 2\right)\right)}^{-1}\\ \end{array} \end{array} \]
                      (FPCore (a b)
                       :precision binary64
                       (if (<= b 4.8e+82)
                         (/ 1.0 (fma (fma (fma 0.16666666666666666 a 0.5) a 1.0) a 2.0))
                         (pow (fma (fma (fma 0.16666666666666666 b 0.5) b 1.0) b 2.0) -1.0)))
                      double code(double a, double b) {
                      	double tmp;
                      	if (b <= 4.8e+82) {
                      		tmp = 1.0 / fma(fma(fma(0.16666666666666666, a, 0.5), a, 1.0), a, 2.0);
                      	} else {
                      		tmp = pow(fma(fma(fma(0.16666666666666666, b, 0.5), b, 1.0), b, 2.0), -1.0);
                      	}
                      	return tmp;
                      }
                      
                      function code(a, b)
                      	tmp = 0.0
                      	if (b <= 4.8e+82)
                      		tmp = Float64(1.0 / fma(fma(fma(0.16666666666666666, a, 0.5), a, 1.0), a, 2.0));
                      	else
                      		tmp = fma(fma(fma(0.16666666666666666, b, 0.5), b, 1.0), b, 2.0) ^ -1.0;
                      	end
                      	return tmp
                      end
                      
                      code[a_, b_] := If[LessEqual[b, 4.8e+82], N[(1.0 / N[(N[(N[(0.16666666666666666 * a + 0.5), $MachinePrecision] * a + 1.0), $MachinePrecision] * a + 2.0), $MachinePrecision]), $MachinePrecision], N[Power[N[(N[(N[(0.16666666666666666 * b + 0.5), $MachinePrecision] * b + 1.0), $MachinePrecision] * b + 2.0), $MachinePrecision], -1.0], $MachinePrecision]]
                      
                      \begin{array}{l}
                      
                      \\
                      \begin{array}{l}
                      \mathbf{if}\;b \leq 4.8 \cdot 10^{+82}:\\
                      \;\;\;\;\frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, a, 0.5\right), a, 1\right), a, 2\right)}\\
                      
                      \mathbf{else}:\\
                      \;\;\;\;{\left(\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, b, 0.5\right), b, 1\right), b, 2\right)\right)}^{-1}\\
                      
                      
                      \end{array}
                      \end{array}
                      
                      Derivation
                      1. Split input into 2 regimes
                      2. if b < 4.79999999999999996e82

                        1. Initial program 98.5%

                          \[\frac{e^{a}}{e^{a} + e^{b}} \]
                        2. Add Preprocessing
                        3. Taylor expanded in b around 0

                          \[\leadsto \frac{e^{a}}{\color{blue}{1 + e^{a}}} \]
                        4. Step-by-step derivation
                          1. +-commutativeN/A

                            \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
                          2. lower-+.f64N/A

                            \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
                          3. lower-exp.f6471.4

                            \[\leadsto \frac{e^{a}}{\color{blue}{e^{a}} + 1} \]
                        5. Applied rewrites71.4%

                          \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
                        6. Taylor expanded in a around 0

                          \[\leadsto \frac{e^{a}}{2 + \color{blue}{a \cdot \left(1 + a \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot a\right)\right)}} \]
                        7. Step-by-step derivation
                          1. Applied rewrites71.4%

                            \[\leadsto \frac{e^{a}}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, a, 0.5\right), a, 1\right), \color{blue}{a}, 2\right)} \]
                          2. Taylor expanded in a around 0

                            \[\leadsto \frac{\color{blue}{1}}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{6}, a, \frac{1}{2}\right), a, 1\right), a, 2\right)} \]
                          3. Step-by-step derivation
                            1. Applied rewrites64.8%

                              \[\leadsto \frac{\color{blue}{1}}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, a, 0.5\right), a, 1\right), a, 2\right)} \]

                            if 4.79999999999999996e82 < b

                            1. Initial program 100.0%

                              \[\frac{e^{a}}{e^{a} + e^{b}} \]
                            2. Add Preprocessing
                            3. Taylor expanded in a around 0

                              \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                            4. Step-by-step derivation
                              1. lower-/.f64N/A

                                \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                              2. +-commutativeN/A

                                \[\leadsto \frac{1}{\color{blue}{e^{b} + 1}} \]
                              3. lower-+.f64N/A

                                \[\leadsto \frac{1}{\color{blue}{e^{b} + 1}} \]
                              4. lower-exp.f64100.0

                                \[\leadsto \frac{1}{\color{blue}{e^{b}} + 1} \]
                            5. Applied rewrites100.0%

                              \[\leadsto \color{blue}{\frac{1}{e^{b} + 1}} \]
                            6. Taylor expanded in b around 0

                              \[\leadsto \frac{1}{2 + \color{blue}{b \cdot \left(1 + b \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot b\right)\right)}} \]
                            7. Step-by-step derivation
                              1. Applied rewrites87.6%

                                \[\leadsto \frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, b, 0.5\right), b, 1\right), \color{blue}{b}, 2\right)} \]
                            8. Recombined 2 regimes into one program.
                            9. Final simplification69.4%

                              \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq 4.8 \cdot 10^{+82}:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, a, 0.5\right), a, 1\right), a, 2\right)}\\ \mathbf{else}:\\ \;\;\;\;{\left(\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, b, 0.5\right), b, 1\right), b, 2\right)\right)}^{-1}\\ \end{array} \]
                            10. Add Preprocessing

                            Alternative 6: 67.9% accurate, 2.5× speedup?

                            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;b \leq 3.3 \cdot 10^{+82}:\\ \;\;\;\;\frac{1 + a}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), a, 2\right)}\\ \mathbf{else}:\\ \;\;\;\;{\left(\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, b, 0.5\right), b, 1\right), b, 2\right)\right)}^{-1}\\ \end{array} \end{array} \]
                            (FPCore (a b)
                             :precision binary64
                             (if (<= b 3.3e+82)
                               (/ (+ 1.0 a) (fma (fma 0.5 a 1.0) a 2.0))
                               (pow (fma (fma (fma 0.16666666666666666 b 0.5) b 1.0) b 2.0) -1.0)))
                            double code(double a, double b) {
                            	double tmp;
                            	if (b <= 3.3e+82) {
                            		tmp = (1.0 + a) / fma(fma(0.5, a, 1.0), a, 2.0);
                            	} else {
                            		tmp = pow(fma(fma(fma(0.16666666666666666, b, 0.5), b, 1.0), b, 2.0), -1.0);
                            	}
                            	return tmp;
                            }
                            
                            function code(a, b)
                            	tmp = 0.0
                            	if (b <= 3.3e+82)
                            		tmp = Float64(Float64(1.0 + a) / fma(fma(0.5, a, 1.0), a, 2.0));
                            	else
                            		tmp = fma(fma(fma(0.16666666666666666, b, 0.5), b, 1.0), b, 2.0) ^ -1.0;
                            	end
                            	return tmp
                            end
                            
                            code[a_, b_] := If[LessEqual[b, 3.3e+82], N[(N[(1.0 + a), $MachinePrecision] / N[(N[(0.5 * a + 1.0), $MachinePrecision] * a + 2.0), $MachinePrecision]), $MachinePrecision], N[Power[N[(N[(N[(0.16666666666666666 * b + 0.5), $MachinePrecision] * b + 1.0), $MachinePrecision] * b + 2.0), $MachinePrecision], -1.0], $MachinePrecision]]
                            
                            \begin{array}{l}
                            
                            \\
                            \begin{array}{l}
                            \mathbf{if}\;b \leq 3.3 \cdot 10^{+82}:\\
                            \;\;\;\;\frac{1 + a}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), a, 2\right)}\\
                            
                            \mathbf{else}:\\
                            \;\;\;\;{\left(\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, b, 0.5\right), b, 1\right), b, 2\right)\right)}^{-1}\\
                            
                            
                            \end{array}
                            \end{array}
                            
                            Derivation
                            1. Split input into 2 regimes
                            2. if b < 3.2999999999999998e82

                              1. Initial program 98.5%

                                \[\frac{e^{a}}{e^{a} + e^{b}} \]
                              2. Add Preprocessing
                              3. Taylor expanded in b around 0

                                \[\leadsto \frac{e^{a}}{\color{blue}{1 + e^{a}}} \]
                              4. Step-by-step derivation
                                1. +-commutativeN/A

                                  \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
                                2. lower-+.f64N/A

                                  \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
                                3. lower-exp.f6471.4

                                  \[\leadsto \frac{e^{a}}{\color{blue}{e^{a}} + 1} \]
                              5. Applied rewrites71.4%

                                \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
                              6. Taylor expanded in a around 0

                                \[\leadsto \frac{e^{a}}{2 + \color{blue}{a \cdot \left(1 + \frac{1}{2} \cdot a\right)}} \]
                              7. Step-by-step derivation
                                1. Applied rewrites71.4%

                                  \[\leadsto \frac{e^{a}}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), \color{blue}{a}, 2\right)} \]
                                2. Taylor expanded in a around 0

                                  \[\leadsto \frac{\color{blue}{1 + a}}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{2}, a, 1\right), a, 2\right)} \]
                                3. Step-by-step derivation
                                  1. lower-+.f6461.8

                                    \[\leadsto \frac{\color{blue}{1 + a}}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), a, 2\right)} \]
                                4. Applied rewrites61.8%

                                  \[\leadsto \frac{\color{blue}{1 + a}}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), a, 2\right)} \]

                                if 3.2999999999999998e82 < b

                                1. Initial program 100.0%

                                  \[\frac{e^{a}}{e^{a} + e^{b}} \]
                                2. Add Preprocessing
                                3. Taylor expanded in a around 0

                                  \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                                4. Step-by-step derivation
                                  1. lower-/.f64N/A

                                    \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                                  2. +-commutativeN/A

                                    \[\leadsto \frac{1}{\color{blue}{e^{b} + 1}} \]
                                  3. lower-+.f64N/A

                                    \[\leadsto \frac{1}{\color{blue}{e^{b} + 1}} \]
                                  4. lower-exp.f64100.0

                                    \[\leadsto \frac{1}{\color{blue}{e^{b}} + 1} \]
                                5. Applied rewrites100.0%

                                  \[\leadsto \color{blue}{\frac{1}{e^{b} + 1}} \]
                                6. Taylor expanded in b around 0

                                  \[\leadsto \frac{1}{2 + \color{blue}{b \cdot \left(1 + b \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot b\right)\right)}} \]
                                7. Step-by-step derivation
                                  1. Applied rewrites87.6%

                                    \[\leadsto \frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, b, 0.5\right), b, 1\right), \color{blue}{b}, 2\right)} \]
                                8. Recombined 2 regimes into one program.
                                9. Final simplification67.1%

                                  \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq 3.3 \cdot 10^{+82}:\\ \;\;\;\;\frac{1 + a}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), a, 2\right)}\\ \mathbf{else}:\\ \;\;\;\;{\left(\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, b, 0.5\right), b, 1\right), b, 2\right)\right)}^{-1}\\ \end{array} \]
                                10. Add Preprocessing

                                Alternative 7: 63.5% accurate, 2.6× speedup?

                                \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;b \leq 3.3 \cdot 10^{+82}:\\ \;\;\;\;\frac{1 + a}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), a, 2\right)}\\ \mathbf{else}:\\ \;\;\;\;{\left(\mathsf{fma}\left(\mathsf{fma}\left(0.5, b, 1\right), b, 2\right)\right)}^{-1}\\ \end{array} \end{array} \]
                                (FPCore (a b)
                                 :precision binary64
                                 (if (<= b 3.3e+82)
                                   (/ (+ 1.0 a) (fma (fma 0.5 a 1.0) a 2.0))
                                   (pow (fma (fma 0.5 b 1.0) b 2.0) -1.0)))
                                double code(double a, double b) {
                                	double tmp;
                                	if (b <= 3.3e+82) {
                                		tmp = (1.0 + a) / fma(fma(0.5, a, 1.0), a, 2.0);
                                	} else {
                                		tmp = pow(fma(fma(0.5, b, 1.0), b, 2.0), -1.0);
                                	}
                                	return tmp;
                                }
                                
                                function code(a, b)
                                	tmp = 0.0
                                	if (b <= 3.3e+82)
                                		tmp = Float64(Float64(1.0 + a) / fma(fma(0.5, a, 1.0), a, 2.0));
                                	else
                                		tmp = fma(fma(0.5, b, 1.0), b, 2.0) ^ -1.0;
                                	end
                                	return tmp
                                end
                                
                                code[a_, b_] := If[LessEqual[b, 3.3e+82], N[(N[(1.0 + a), $MachinePrecision] / N[(N[(0.5 * a + 1.0), $MachinePrecision] * a + 2.0), $MachinePrecision]), $MachinePrecision], N[Power[N[(N[(0.5 * b + 1.0), $MachinePrecision] * b + 2.0), $MachinePrecision], -1.0], $MachinePrecision]]
                                
                                \begin{array}{l}
                                
                                \\
                                \begin{array}{l}
                                \mathbf{if}\;b \leq 3.3 \cdot 10^{+82}:\\
                                \;\;\;\;\frac{1 + a}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), a, 2\right)}\\
                                
                                \mathbf{else}:\\
                                \;\;\;\;{\left(\mathsf{fma}\left(\mathsf{fma}\left(0.5, b, 1\right), b, 2\right)\right)}^{-1}\\
                                
                                
                                \end{array}
                                \end{array}
                                
                                Derivation
                                1. Split input into 2 regimes
                                2. if b < 3.2999999999999998e82

                                  1. Initial program 98.5%

                                    \[\frac{e^{a}}{e^{a} + e^{b}} \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in b around 0

                                    \[\leadsto \frac{e^{a}}{\color{blue}{1 + e^{a}}} \]
                                  4. Step-by-step derivation
                                    1. +-commutativeN/A

                                      \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
                                    2. lower-+.f64N/A

                                      \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
                                    3. lower-exp.f6471.4

                                      \[\leadsto \frac{e^{a}}{\color{blue}{e^{a}} + 1} \]
                                  5. Applied rewrites71.4%

                                    \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
                                  6. Taylor expanded in a around 0

                                    \[\leadsto \frac{e^{a}}{2 + \color{blue}{a \cdot \left(1 + \frac{1}{2} \cdot a\right)}} \]
                                  7. Step-by-step derivation
                                    1. Applied rewrites71.4%

                                      \[\leadsto \frac{e^{a}}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), \color{blue}{a}, 2\right)} \]
                                    2. Taylor expanded in a around 0

                                      \[\leadsto \frac{\color{blue}{1 + a}}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{2}, a, 1\right), a, 2\right)} \]
                                    3. Step-by-step derivation
                                      1. lower-+.f6461.8

                                        \[\leadsto \frac{\color{blue}{1 + a}}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), a, 2\right)} \]
                                    4. Applied rewrites61.8%

                                      \[\leadsto \frac{\color{blue}{1 + a}}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), a, 2\right)} \]

                                    if 3.2999999999999998e82 < b

                                    1. Initial program 100.0%

                                      \[\frac{e^{a}}{e^{a} + e^{b}} \]
                                    2. Add Preprocessing
                                    3. Taylor expanded in a around 0

                                      \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                                    4. Step-by-step derivation
                                      1. lower-/.f64N/A

                                        \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                                      2. +-commutativeN/A

                                        \[\leadsto \frac{1}{\color{blue}{e^{b} + 1}} \]
                                      3. lower-+.f64N/A

                                        \[\leadsto \frac{1}{\color{blue}{e^{b} + 1}} \]
                                      4. lower-exp.f64100.0

                                        \[\leadsto \frac{1}{\color{blue}{e^{b}} + 1} \]
                                    5. Applied rewrites100.0%

                                      \[\leadsto \color{blue}{\frac{1}{e^{b} + 1}} \]
                                    6. Taylor expanded in b around 0

                                      \[\leadsto \frac{1}{2 + \color{blue}{b \cdot \left(1 + \frac{1}{2} \cdot b\right)}} \]
                                    7. Step-by-step derivation
                                      1. Applied rewrites74.7%

                                        \[\leadsto \frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, b, 1\right), \color{blue}{b}, 2\right)} \]
                                    8. Recombined 2 regimes into one program.
                                    9. Final simplification64.4%

                                      \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq 3.3 \cdot 10^{+82}:\\ \;\;\;\;\frac{1 + a}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), a, 2\right)}\\ \mathbf{else}:\\ \;\;\;\;{\left(\mathsf{fma}\left(\mathsf{fma}\left(0.5, b, 1\right), b, 2\right)\right)}^{-1}\\ \end{array} \]
                                    10. Add Preprocessing

                                    Alternative 8: 63.2% accurate, 2.6× speedup?

                                    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;b \leq 3.3 \cdot 10^{+82}:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(0.5 \cdot a, a, 2\right)}\\ \mathbf{else}:\\ \;\;\;\;{\left(\mathsf{fma}\left(\mathsf{fma}\left(0.5, b, 1\right), b, 2\right)\right)}^{-1}\\ \end{array} \end{array} \]
                                    (FPCore (a b)
                                     :precision binary64
                                     (if (<= b 3.3e+82)
                                       (/ 1.0 (fma (* 0.5 a) a 2.0))
                                       (pow (fma (fma 0.5 b 1.0) b 2.0) -1.0)))
                                    double code(double a, double b) {
                                    	double tmp;
                                    	if (b <= 3.3e+82) {
                                    		tmp = 1.0 / fma((0.5 * a), a, 2.0);
                                    	} else {
                                    		tmp = pow(fma(fma(0.5, b, 1.0), b, 2.0), -1.0);
                                    	}
                                    	return tmp;
                                    }
                                    
                                    function code(a, b)
                                    	tmp = 0.0
                                    	if (b <= 3.3e+82)
                                    		tmp = Float64(1.0 / fma(Float64(0.5 * a), a, 2.0));
                                    	else
                                    		tmp = fma(fma(0.5, b, 1.0), b, 2.0) ^ -1.0;
                                    	end
                                    	return tmp
                                    end
                                    
                                    code[a_, b_] := If[LessEqual[b, 3.3e+82], N[(1.0 / N[(N[(0.5 * a), $MachinePrecision] * a + 2.0), $MachinePrecision]), $MachinePrecision], N[Power[N[(N[(0.5 * b + 1.0), $MachinePrecision] * b + 2.0), $MachinePrecision], -1.0], $MachinePrecision]]
                                    
                                    \begin{array}{l}
                                    
                                    \\
                                    \begin{array}{l}
                                    \mathbf{if}\;b \leq 3.3 \cdot 10^{+82}:\\
                                    \;\;\;\;\frac{1}{\mathsf{fma}\left(0.5 \cdot a, a, 2\right)}\\
                                    
                                    \mathbf{else}:\\
                                    \;\;\;\;{\left(\mathsf{fma}\left(\mathsf{fma}\left(0.5, b, 1\right), b, 2\right)\right)}^{-1}\\
                                    
                                    
                                    \end{array}
                                    \end{array}
                                    
                                    Derivation
                                    1. Split input into 2 regimes
                                    2. if b < 3.2999999999999998e82

                                      1. Initial program 98.5%

                                        \[\frac{e^{a}}{e^{a} + e^{b}} \]
                                      2. Add Preprocessing
                                      3. Taylor expanded in b around 0

                                        \[\leadsto \frac{e^{a}}{\color{blue}{1 + e^{a}}} \]
                                      4. Step-by-step derivation
                                        1. +-commutativeN/A

                                          \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
                                        2. lower-+.f64N/A

                                          \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
                                        3. lower-exp.f6471.4

                                          \[\leadsto \frac{e^{a}}{\color{blue}{e^{a}} + 1} \]
                                      5. Applied rewrites71.4%

                                        \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
                                      6. Taylor expanded in a around 0

                                        \[\leadsto \frac{e^{a}}{2 + \color{blue}{a \cdot \left(1 + \frac{1}{2} \cdot a\right)}} \]
                                      7. Step-by-step derivation
                                        1. Applied rewrites71.4%

                                          \[\leadsto \frac{e^{a}}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), \color{blue}{a}, 2\right)} \]
                                        2. Taylor expanded in a around 0

                                          \[\leadsto \frac{\color{blue}{1}}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{2}, a, 1\right), a, 2\right)} \]
                                        3. Step-by-step derivation
                                          1. Applied rewrites61.5%

                                            \[\leadsto \frac{\color{blue}{1}}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), a, 2\right)} \]
                                          2. Taylor expanded in a around inf

                                            \[\leadsto \frac{1}{\mathsf{fma}\left(\frac{1}{2} \cdot a, a, 2\right)} \]
                                          3. Step-by-step derivation
                                            1. Applied rewrites61.6%

                                              \[\leadsto \frac{1}{\mathsf{fma}\left(0.5 \cdot a, a, 2\right)} \]

                                            if 3.2999999999999998e82 < b

                                            1. Initial program 100.0%

                                              \[\frac{e^{a}}{e^{a} + e^{b}} \]
                                            2. Add Preprocessing
                                            3. Taylor expanded in a around 0

                                              \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                                            4. Step-by-step derivation
                                              1. lower-/.f64N/A

                                                \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                                              2. +-commutativeN/A

                                                \[\leadsto \frac{1}{\color{blue}{e^{b} + 1}} \]
                                              3. lower-+.f64N/A

                                                \[\leadsto \frac{1}{\color{blue}{e^{b} + 1}} \]
                                              4. lower-exp.f64100.0

                                                \[\leadsto \frac{1}{\color{blue}{e^{b}} + 1} \]
                                            5. Applied rewrites100.0%

                                              \[\leadsto \color{blue}{\frac{1}{e^{b} + 1}} \]
                                            6. Taylor expanded in b around 0

                                              \[\leadsto \frac{1}{2 + \color{blue}{b \cdot \left(1 + \frac{1}{2} \cdot b\right)}} \]
                                            7. Step-by-step derivation
                                              1. Applied rewrites74.7%

                                                \[\leadsto \frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, b, 1\right), \color{blue}{b}, 2\right)} \]
                                            8. Recombined 2 regimes into one program.
                                            9. Final simplification64.2%

                                              \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq 3.3 \cdot 10^{+82}:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(0.5 \cdot a, a, 2\right)}\\ \mathbf{else}:\\ \;\;\;\;{\left(\mathsf{fma}\left(\mathsf{fma}\left(0.5, b, 1\right), b, 2\right)\right)}^{-1}\\ \end{array} \]
                                            10. Add Preprocessing

                                            Alternative 9: 53.0% accurate, 13.7× speedup?

                                            \[\begin{array}{l} \\ \frac{1}{\mathsf{fma}\left(0.5 \cdot a, a, 2\right)} \end{array} \]
                                            (FPCore (a b) :precision binary64 (/ 1.0 (fma (* 0.5 a) a 2.0)))
                                            double code(double a, double b) {
                                            	return 1.0 / fma((0.5 * a), a, 2.0);
                                            }
                                            
                                            function code(a, b)
                                            	return Float64(1.0 / fma(Float64(0.5 * a), a, 2.0))
                                            end
                                            
                                            code[a_, b_] := N[(1.0 / N[(N[(0.5 * a), $MachinePrecision] * a + 2.0), $MachinePrecision]), $MachinePrecision]
                                            
                                            \begin{array}{l}
                                            
                                            \\
                                            \frac{1}{\mathsf{fma}\left(0.5 \cdot a, a, 2\right)}
                                            \end{array}
                                            
                                            Derivation
                                            1. Initial program 98.8%

                                              \[\frac{e^{a}}{e^{a} + e^{b}} \]
                                            2. Add Preprocessing
                                            3. Taylor expanded in b around 0

                                              \[\leadsto \frac{e^{a}}{\color{blue}{1 + e^{a}}} \]
                                            4. Step-by-step derivation
                                              1. +-commutativeN/A

                                                \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
                                              2. lower-+.f64N/A

                                                \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
                                              3. lower-exp.f6464.3

                                                \[\leadsto \frac{e^{a}}{\color{blue}{e^{a}} + 1} \]
                                            5. Applied rewrites64.3%

                                              \[\leadsto \frac{e^{a}}{\color{blue}{e^{a} + 1}} \]
                                            6. Taylor expanded in a around 0

                                              \[\leadsto \frac{e^{a}}{2 + \color{blue}{a \cdot \left(1 + \frac{1}{2} \cdot a\right)}} \]
                                            7. Step-by-step derivation
                                              1. Applied rewrites64.3%

                                                \[\leadsto \frac{e^{a}}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), \color{blue}{a}, 2\right)} \]
                                              2. Taylor expanded in a around 0

                                                \[\leadsto \frac{\color{blue}{1}}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{2}, a, 1\right), a, 2\right)} \]
                                              3. Step-by-step derivation
                                                1. Applied rewrites52.8%

                                                  \[\leadsto \frac{\color{blue}{1}}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), a, 2\right)} \]
                                                2. Taylor expanded in a around inf

                                                  \[\leadsto \frac{1}{\mathsf{fma}\left(\frac{1}{2} \cdot a, a, 2\right)} \]
                                                3. Step-by-step derivation
                                                  1. Applied rewrites52.8%

                                                    \[\leadsto \frac{1}{\mathsf{fma}\left(0.5 \cdot a, a, 2\right)} \]
                                                  2. Add Preprocessing

                                                  Alternative 10: 39.4% accurate, 315.0× speedup?

                                                  \[\begin{array}{l} \\ 0.5 \end{array} \]
                                                  (FPCore (a b) :precision binary64 0.5)
                                                  double code(double a, double b) {
                                                  	return 0.5;
                                                  }
                                                  
                                                  real(8) function code(a, b)
                                                      real(8), intent (in) :: a
                                                      real(8), intent (in) :: b
                                                      code = 0.5d0
                                                  end function
                                                  
                                                  public static double code(double a, double b) {
                                                  	return 0.5;
                                                  }
                                                  
                                                  def code(a, b):
                                                  	return 0.5
                                                  
                                                  function code(a, b)
                                                  	return 0.5
                                                  end
                                                  
                                                  function tmp = code(a, b)
                                                  	tmp = 0.5;
                                                  end
                                                  
                                                  code[a_, b_] := 0.5
                                                  
                                                  \begin{array}{l}
                                                  
                                                  \\
                                                  0.5
                                                  \end{array}
                                                  
                                                  Derivation
                                                  1. Initial program 98.8%

                                                    \[\frac{e^{a}}{e^{a} + e^{b}} \]
                                                  2. Add Preprocessing
                                                  3. Taylor expanded in a around 0

                                                    \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                                                  4. Step-by-step derivation
                                                    1. lower-/.f64N/A

                                                      \[\leadsto \color{blue}{\frac{1}{1 + e^{b}}} \]
                                                    2. +-commutativeN/A

                                                      \[\leadsto \frac{1}{\color{blue}{e^{b} + 1}} \]
                                                    3. lower-+.f64N/A

                                                      \[\leadsto \frac{1}{\color{blue}{e^{b} + 1}} \]
                                                    4. lower-exp.f6482.9

                                                      \[\leadsto \frac{1}{\color{blue}{e^{b}} + 1} \]
                                                  5. Applied rewrites82.9%

                                                    \[\leadsto \color{blue}{\frac{1}{e^{b} + 1}} \]
                                                  6. Taylor expanded in b around 0

                                                    \[\leadsto \frac{1}{2} \]
                                                  7. Step-by-step derivation
                                                    1. Applied rewrites39.7%

                                                      \[\leadsto 0.5 \]
                                                    2. Add Preprocessing

                                                    Developer Target 1: 100.0% accurate, 2.7× speedup?

                                                    \[\begin{array}{l} \\ \frac{1}{1 + e^{b - a}} \end{array} \]
                                                    (FPCore (a b) :precision binary64 (/ 1.0 (+ 1.0 (exp (- b a)))))
                                                    double code(double a, double b) {
                                                    	return 1.0 / (1.0 + exp((b - a)));
                                                    }
                                                    
                                                    real(8) function code(a, b)
                                                        real(8), intent (in) :: a
                                                        real(8), intent (in) :: b
                                                        code = 1.0d0 / (1.0d0 + exp((b - a)))
                                                    end function
                                                    
                                                    public static double code(double a, double b) {
                                                    	return 1.0 / (1.0 + Math.exp((b - a)));
                                                    }
                                                    
                                                    def code(a, b):
                                                    	return 1.0 / (1.0 + math.exp((b - a)))
                                                    
                                                    function code(a, b)
                                                    	return Float64(1.0 / Float64(1.0 + exp(Float64(b - a))))
                                                    end
                                                    
                                                    function tmp = code(a, b)
                                                    	tmp = 1.0 / (1.0 + exp((b - a)));
                                                    end
                                                    
                                                    code[a_, b_] := N[(1.0 / N[(1.0 + N[Exp[N[(b - a), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
                                                    
                                                    \begin{array}{l}
                                                    
                                                    \\
                                                    \frac{1}{1 + e^{b - a}}
                                                    \end{array}
                                                    

                                                    Reproduce

                                                    ?
                                                    herbie shell --seed 2024339 
                                                    (FPCore (a b)
                                                      :name "Quotient of sum of exps"
                                                      :precision binary64
                                                    
                                                      :alt
                                                      (! :herbie-platform default (/ 1 (+ 1 (exp (- b a)))))
                                                    
                                                      (/ (exp a) (+ (exp a) (exp b))))