Given's Rotation SVD example

Percentage Accurate: 79.6% → 99.9%
Time: 8.5s
Alternatives: 6
Speedup: 0.5×

Specification

?
\[10^{-150} < \left|x\right| \land \left|x\right| < 10^{+150}\]
\[\begin{array}{l} \\ \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \end{array} \]
(FPCore (p x)
 :precision binary64
 (sqrt (* 0.5 (+ 1.0 (/ x (sqrt (+ (* (* 4.0 p) p) (* x x))))))))
double code(double p, double x) {
	return sqrt((0.5 * (1.0 + (x / sqrt((((4.0 * p) * p) + (x * x)))))));
}
real(8) function code(p, x)
    real(8), intent (in) :: p
    real(8), intent (in) :: x
    code = sqrt((0.5d0 * (1.0d0 + (x / sqrt((((4.0d0 * p) * p) + (x * x)))))))
end function
public static double code(double p, double x) {
	return Math.sqrt((0.5 * (1.0 + (x / Math.sqrt((((4.0 * p) * p) + (x * x)))))));
}
def code(p, x):
	return math.sqrt((0.5 * (1.0 + (x / math.sqrt((((4.0 * p) * p) + (x * x)))))))
function code(p, x)
	return sqrt(Float64(0.5 * Float64(1.0 + Float64(x / sqrt(Float64(Float64(Float64(4.0 * p) * p) + Float64(x * x)))))))
end
function tmp = code(p, x)
	tmp = sqrt((0.5 * (1.0 + (x / sqrt((((4.0 * p) * p) + (x * x)))))));
end
code[p_, x_] := N[Sqrt[N[(0.5 * N[(1.0 + N[(x / N[Sqrt[N[(N[(N[(4.0 * p), $MachinePrecision] * p), $MachinePrecision] + N[(x * x), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 6 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 79.6% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \end{array} \]
(FPCore (p x)
 :precision binary64
 (sqrt (* 0.5 (+ 1.0 (/ x (sqrt (+ (* (* 4.0 p) p) (* x x))))))))
double code(double p, double x) {
	return sqrt((0.5 * (1.0 + (x / sqrt((((4.0 * p) * p) + (x * x)))))));
}
real(8) function code(p, x)
    real(8), intent (in) :: p
    real(8), intent (in) :: x
    code = sqrt((0.5d0 * (1.0d0 + (x / sqrt((((4.0d0 * p) * p) + (x * x)))))))
end function
public static double code(double p, double x) {
	return Math.sqrt((0.5 * (1.0 + (x / Math.sqrt((((4.0 * p) * p) + (x * x)))))));
}
def code(p, x):
	return math.sqrt((0.5 * (1.0 + (x / math.sqrt((((4.0 * p) * p) + (x * x)))))))
function code(p, x)
	return sqrt(Float64(0.5 * Float64(1.0 + Float64(x / sqrt(Float64(Float64(Float64(4.0 * p) * p) + Float64(x * x)))))))
end
function tmp = code(p, x)
	tmp = sqrt((0.5 * (1.0 + (x / sqrt((((4.0 * p) * p) + (x * x)))))));
end
code[p_, x_] := N[Sqrt[N[(0.5 * N[(1.0 + N[(x / N[Sqrt[N[(N[(N[(4.0 * p), $MachinePrecision] * p), $MachinePrecision] + N[(x * x), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}
\end{array}

Alternative 1: 99.9% accurate, 0.2× speedup?

\[\begin{array}{l} p_m = \left|p\right| \\ \begin{array}{l} t_0 := \left(4 \cdot p\_m\right) \cdot p\_m\\ \mathbf{if}\;\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{t\_0 + x \cdot x}}\right)} \leq 10^{-5}:\\ \;\;\;\;\frac{-p\_m}{x}\\ \mathbf{else}:\\ \;\;\;\;e^{\log \left(\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(x, x, t\_0\right)}}, 0.5, 0.5\right)\right) \cdot 0.5}\\ \end{array} \end{array} \]
p_m = (fabs.f64 p)
(FPCore (p_m x)
 :precision binary64
 (let* ((t_0 (* (* 4.0 p_m) p_m)))
   (if (<= (sqrt (* 0.5 (+ 1.0 (/ x (sqrt (+ t_0 (* x x))))))) 1e-5)
     (/ (- p_m) x)
     (exp (* (log (fma (/ x (sqrt (fma x x t_0))) 0.5 0.5)) 0.5)))))
p_m = fabs(p);
double code(double p_m, double x) {
	double t_0 = (4.0 * p_m) * p_m;
	double tmp;
	if (sqrt((0.5 * (1.0 + (x / sqrt((t_0 + (x * x))))))) <= 1e-5) {
		tmp = -p_m / x;
	} else {
		tmp = exp((log(fma((x / sqrt(fma(x, x, t_0))), 0.5, 0.5)) * 0.5));
	}
	return tmp;
}
p_m = abs(p)
function code(p_m, x)
	t_0 = Float64(Float64(4.0 * p_m) * p_m)
	tmp = 0.0
	if (sqrt(Float64(0.5 * Float64(1.0 + Float64(x / sqrt(Float64(t_0 + Float64(x * x))))))) <= 1e-5)
		tmp = Float64(Float64(-p_m) / x);
	else
		tmp = exp(Float64(log(fma(Float64(x / sqrt(fma(x, x, t_0))), 0.5, 0.5)) * 0.5));
	end
	return tmp
end
p_m = N[Abs[p], $MachinePrecision]
code[p$95$m_, x_] := Block[{t$95$0 = N[(N[(4.0 * p$95$m), $MachinePrecision] * p$95$m), $MachinePrecision]}, If[LessEqual[N[Sqrt[N[(0.5 * N[(1.0 + N[(x / N[Sqrt[N[(t$95$0 + N[(x * x), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision], 1e-5], N[((-p$95$m) / x), $MachinePrecision], N[Exp[N[(N[Log[N[(N[(x / N[Sqrt[N[(x * x + t$95$0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * 0.5 + 0.5), $MachinePrecision]], $MachinePrecision] * 0.5), $MachinePrecision]], $MachinePrecision]]]
\begin{array}{l}
p_m = \left|p\right|

\\
\begin{array}{l}
t_0 := \left(4 \cdot p\_m\right) \cdot p\_m\\
\mathbf{if}\;\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{t\_0 + x \cdot x}}\right)} \leq 10^{-5}:\\
\;\;\;\;\frac{-p\_m}{x}\\

\mathbf{else}:\\
\;\;\;\;e^{\log \left(\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(x, x, t\_0\right)}}, 0.5, 0.5\right)\right) \cdot 0.5}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (sqrt.f64 (*.f64 #s(literal 1/2 binary64) (+.f64 #s(literal 1 binary64) (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x))))))) < 1.00000000000000008e-5

    1. Initial program 13.6%

      \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in x around -inf

      \[\leadsto \color{blue}{-1 \cdot \frac{p \cdot \left(\sqrt{\frac{1}{2}} \cdot \sqrt{2}\right)}{x}} \]
    4. Step-by-step derivation
      1. mul-1-negN/A

        \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{p \cdot \left(\sqrt{\frac{1}{2}} \cdot \sqrt{2}\right)}{x}\right)} \]
      2. associate-/l*N/A

        \[\leadsto \mathsf{neg}\left(\color{blue}{p \cdot \frac{\sqrt{\frac{1}{2}} \cdot \sqrt{2}}{x}}\right) \]
      3. distribute-lft-neg-inN/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(p\right)\right) \cdot \frac{\sqrt{\frac{1}{2}} \cdot \sqrt{2}}{x}} \]
      4. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(p\right)\right) \cdot \frac{\sqrt{\frac{1}{2}} \cdot \sqrt{2}}{x}} \]
      5. lower-neg.f64N/A

        \[\leadsto \color{blue}{\left(-p\right)} \cdot \frac{\sqrt{\frac{1}{2}} \cdot \sqrt{2}}{x} \]
      6. *-commutativeN/A

        \[\leadsto \left(-p\right) \cdot \frac{\color{blue}{\sqrt{2} \cdot \sqrt{\frac{1}{2}}}}{x} \]
      7. associate-/l*N/A

        \[\leadsto \left(-p\right) \cdot \color{blue}{\left(\sqrt{2} \cdot \frac{\sqrt{\frac{1}{2}}}{x}\right)} \]
      8. lower-*.f64N/A

        \[\leadsto \left(-p\right) \cdot \color{blue}{\left(\sqrt{2} \cdot \frac{\sqrt{\frac{1}{2}}}{x}\right)} \]
      9. lower-sqrt.f64N/A

        \[\leadsto \left(-p\right) \cdot \left(\color{blue}{\sqrt{2}} \cdot \frac{\sqrt{\frac{1}{2}}}{x}\right) \]
      10. lower-/.f64N/A

        \[\leadsto \left(-p\right) \cdot \left(\sqrt{2} \cdot \color{blue}{\frac{\sqrt{\frac{1}{2}}}{x}}\right) \]
      11. lower-sqrt.f6450.2

        \[\leadsto \left(-p\right) \cdot \left(\sqrt{2} \cdot \frac{\color{blue}{\sqrt{0.5}}}{x}\right) \]
    5. Applied rewrites50.2%

      \[\leadsto \color{blue}{\left(-p\right) \cdot \left(\sqrt{2} \cdot \frac{\sqrt{0.5}}{x}\right)} \]
    6. Step-by-step derivation
      1. Applied rewrites50.6%

        \[\leadsto \color{blue}{\frac{-p}{x}} \]

      if 1.00000000000000008e-5 < (sqrt.f64 (*.f64 #s(literal 1/2 binary64) (+.f64 #s(literal 1 binary64) (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x)))))))

      1. Initial program 99.8%

        \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
      2. Add Preprocessing
      3. Step-by-step derivation
        1. lift-+.f64N/A

          \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{\left(4 \cdot p\right) \cdot p + x \cdot x}}}\right)} \]
        2. +-commutativeN/A

          \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{x \cdot x + \left(4 \cdot p\right) \cdot p}}}\right)} \]
        3. lift-*.f64N/A

          \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{x \cdot x} + \left(4 \cdot p\right) \cdot p}}\right)} \]
        4. lower-fma.f6499.9

          \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{\mathsf{fma}\left(x, x, \left(4 \cdot p\right) \cdot p\right)}}}\right)} \]
        5. lift-*.f64N/A

          \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \color{blue}{\left(4 \cdot p\right)} \cdot p\right)}}\right)} \]
        6. *-commutativeN/A

          \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \color{blue}{\left(p \cdot 4\right)} \cdot p\right)}}\right)} \]
        7. lower-*.f6499.9

          \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \color{blue}{\left(p \cdot 4\right)} \cdot p\right)}}\right)} \]
      4. Applied rewrites99.9%

        \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}}\right)} \]
      5. Step-by-step derivation
        1. lift-sqrt.f64N/A

          \[\leadsto \color{blue}{\sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}\right)}} \]
        2. pow1/2N/A

          \[\leadsto \color{blue}{{\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}\right)\right)}^{\frac{1}{2}}} \]
        3. pow-to-expN/A

          \[\leadsto \color{blue}{e^{\log \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}\right)\right) \cdot \frac{1}{2}}} \]
        4. lower-exp.f64N/A

          \[\leadsto \color{blue}{e^{\log \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}\right)\right) \cdot \frac{1}{2}}} \]
        5. lower-*.f64N/A

          \[\leadsto e^{\color{blue}{\log \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}\right)\right) \cdot \frac{1}{2}}} \]
      6. Applied rewrites99.9%

        \[\leadsto \color{blue}{e^{\log \left(\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(4 \cdot p\right) \cdot p\right)}}, 0.5, 0.5\right)\right) \cdot 0.5}} \]
    7. Recombined 2 regimes into one program.
    8. Final simplification86.4%

      \[\leadsto \begin{array}{l} \mathbf{if}\;\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \leq 10^{-5}:\\ \;\;\;\;\frac{-p}{x}\\ \mathbf{else}:\\ \;\;\;\;e^{\log \left(\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(4 \cdot p\right) \cdot p\right)}}, 0.5, 0.5\right)\right) \cdot 0.5}\\ \end{array} \]
    9. Add Preprocessing

    Alternative 2: 98.4% accurate, 0.4× speedup?

    \[\begin{array}{l} p_m = \left|p\right| \\ \begin{array}{l} t_0 := \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\_m\right) \cdot p\_m + x \cdot x}}\right)}\\ \mathbf{if}\;t\_0 \leq 0.2:\\ \;\;\;\;\frac{-p\_m}{x}\\ \mathbf{elif}\;t\_0 \leq 0.7071067811865476:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(\frac{x}{p\_m}, 0.25, 0.5\right)}\\ \mathbf{else}:\\ \;\;\;\;1\\ \end{array} \end{array} \]
    p_m = (fabs.f64 p)
    (FPCore (p_m x)
     :precision binary64
     (let* ((t_0
             (sqrt (* 0.5 (+ 1.0 (/ x (sqrt (+ (* (* 4.0 p_m) p_m) (* x x)))))))))
       (if (<= t_0 0.2)
         (/ (- p_m) x)
         (if (<= t_0 0.7071067811865476) (sqrt (fma (/ x p_m) 0.25 0.5)) 1.0))))
    p_m = fabs(p);
    double code(double p_m, double x) {
    	double t_0 = sqrt((0.5 * (1.0 + (x / sqrt((((4.0 * p_m) * p_m) + (x * x)))))));
    	double tmp;
    	if (t_0 <= 0.2) {
    		tmp = -p_m / x;
    	} else if (t_0 <= 0.7071067811865476) {
    		tmp = sqrt(fma((x / p_m), 0.25, 0.5));
    	} else {
    		tmp = 1.0;
    	}
    	return tmp;
    }
    
    p_m = abs(p)
    function code(p_m, x)
    	t_0 = sqrt(Float64(0.5 * Float64(1.0 + Float64(x / sqrt(Float64(Float64(Float64(4.0 * p_m) * p_m) + Float64(x * x)))))))
    	tmp = 0.0
    	if (t_0 <= 0.2)
    		tmp = Float64(Float64(-p_m) / x);
    	elseif (t_0 <= 0.7071067811865476)
    		tmp = sqrt(fma(Float64(x / p_m), 0.25, 0.5));
    	else
    		tmp = 1.0;
    	end
    	return tmp
    end
    
    p_m = N[Abs[p], $MachinePrecision]
    code[p$95$m_, x_] := Block[{t$95$0 = N[Sqrt[N[(0.5 * N[(1.0 + N[(x / N[Sqrt[N[(N[(N[(4.0 * p$95$m), $MachinePrecision] * p$95$m), $MachinePrecision] + N[(x * x), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[t$95$0, 0.2], N[((-p$95$m) / x), $MachinePrecision], If[LessEqual[t$95$0, 0.7071067811865476], N[Sqrt[N[(N[(x / p$95$m), $MachinePrecision] * 0.25 + 0.5), $MachinePrecision]], $MachinePrecision], 1.0]]]
    
    \begin{array}{l}
    p_m = \left|p\right|
    
    \\
    \begin{array}{l}
    t_0 := \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\_m\right) \cdot p\_m + x \cdot x}}\right)}\\
    \mathbf{if}\;t\_0 \leq 0.2:\\
    \;\;\;\;\frac{-p\_m}{x}\\
    
    \mathbf{elif}\;t\_0 \leq 0.7071067811865476:\\
    \;\;\;\;\sqrt{\mathsf{fma}\left(\frac{x}{p\_m}, 0.25, 0.5\right)}\\
    
    \mathbf{else}:\\
    \;\;\;\;1\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 3 regimes
    2. if (sqrt.f64 (*.f64 #s(literal 1/2 binary64) (+.f64 #s(literal 1 binary64) (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x))))))) < 0.20000000000000001

      1. Initial program 15.9%

        \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
      2. Add Preprocessing
      3. Taylor expanded in x around -inf

        \[\leadsto \color{blue}{-1 \cdot \frac{p \cdot \left(\sqrt{\frac{1}{2}} \cdot \sqrt{2}\right)}{x}} \]
      4. Step-by-step derivation
        1. mul-1-negN/A

          \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{p \cdot \left(\sqrt{\frac{1}{2}} \cdot \sqrt{2}\right)}{x}\right)} \]
        2. associate-/l*N/A

          \[\leadsto \mathsf{neg}\left(\color{blue}{p \cdot \frac{\sqrt{\frac{1}{2}} \cdot \sqrt{2}}{x}}\right) \]
        3. distribute-lft-neg-inN/A

          \[\leadsto \color{blue}{\left(\mathsf{neg}\left(p\right)\right) \cdot \frac{\sqrt{\frac{1}{2}} \cdot \sqrt{2}}{x}} \]
        4. lower-*.f64N/A

          \[\leadsto \color{blue}{\left(\mathsf{neg}\left(p\right)\right) \cdot \frac{\sqrt{\frac{1}{2}} \cdot \sqrt{2}}{x}} \]
        5. lower-neg.f64N/A

          \[\leadsto \color{blue}{\left(-p\right)} \cdot \frac{\sqrt{\frac{1}{2}} \cdot \sqrt{2}}{x} \]
        6. *-commutativeN/A

          \[\leadsto \left(-p\right) \cdot \frac{\color{blue}{\sqrt{2} \cdot \sqrt{\frac{1}{2}}}}{x} \]
        7. associate-/l*N/A

          \[\leadsto \left(-p\right) \cdot \color{blue}{\left(\sqrt{2} \cdot \frac{\sqrt{\frac{1}{2}}}{x}\right)} \]
        8. lower-*.f64N/A

          \[\leadsto \left(-p\right) \cdot \color{blue}{\left(\sqrt{2} \cdot \frac{\sqrt{\frac{1}{2}}}{x}\right)} \]
        9. lower-sqrt.f64N/A

          \[\leadsto \left(-p\right) \cdot \left(\color{blue}{\sqrt{2}} \cdot \frac{\sqrt{\frac{1}{2}}}{x}\right) \]
        10. lower-/.f64N/A

          \[\leadsto \left(-p\right) \cdot \left(\sqrt{2} \cdot \color{blue}{\frac{\sqrt{\frac{1}{2}}}{x}}\right) \]
        11. lower-sqrt.f6449.3

          \[\leadsto \left(-p\right) \cdot \left(\sqrt{2} \cdot \frac{\color{blue}{\sqrt{0.5}}}{x}\right) \]
      5. Applied rewrites49.3%

        \[\leadsto \color{blue}{\left(-p\right) \cdot \left(\sqrt{2} \cdot \frac{\sqrt{0.5}}{x}\right)} \]
      6. Step-by-step derivation
        1. Applied rewrites49.7%

          \[\leadsto \color{blue}{\frac{-p}{x}} \]

        if 0.20000000000000001 < (sqrt.f64 (*.f64 #s(literal 1/2 binary64) (+.f64 #s(literal 1 binary64) (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x))))))) < 0.707106781186547573

        1. Initial program 99.8%

          \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
        2. Add Preprocessing
        3. Taylor expanded in p around inf

          \[\leadsto \sqrt{\color{blue}{\frac{1}{2} + \frac{1}{4} \cdot \frac{x}{p}}} \]
        4. Step-by-step derivation
          1. +-commutativeN/A

            \[\leadsto \sqrt{\color{blue}{\frac{1}{4} \cdot \frac{x}{p} + \frac{1}{2}}} \]
          2. *-commutativeN/A

            \[\leadsto \sqrt{\color{blue}{\frac{x}{p} \cdot \frac{1}{4}} + \frac{1}{2}} \]
          3. lower-fma.f64N/A

            \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\frac{x}{p}, \frac{1}{4}, \frac{1}{2}\right)}} \]
          4. lower-/.f6498.4

            \[\leadsto \sqrt{\mathsf{fma}\left(\color{blue}{\frac{x}{p}}, 0.25, 0.5\right)} \]
        5. Applied rewrites98.4%

          \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\frac{x}{p}, 0.25, 0.5\right)}} \]

        if 0.707106781186547573 < (sqrt.f64 (*.f64 #s(literal 1/2 binary64) (+.f64 #s(literal 1 binary64) (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x)))))))

        1. Initial program 100.0%

          \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
        2. Add Preprocessing
        3. Step-by-step derivation
          1. lift-+.f64N/A

            \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{\left(4 \cdot p\right) \cdot p + x \cdot x}}}\right)} \]
          2. +-commutativeN/A

            \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{x \cdot x + \left(4 \cdot p\right) \cdot p}}}\right)} \]
          3. lift-*.f64N/A

            \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{x \cdot x} + \left(4 \cdot p\right) \cdot p}}\right)} \]
          4. lower-fma.f64100.0

            \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{\mathsf{fma}\left(x, x, \left(4 \cdot p\right) \cdot p\right)}}}\right)} \]
          5. lift-*.f64N/A

            \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \color{blue}{\left(4 \cdot p\right)} \cdot p\right)}}\right)} \]
          6. *-commutativeN/A

            \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \color{blue}{\left(p \cdot 4\right)} \cdot p\right)}}\right)} \]
          7. lower-*.f64100.0

            \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \color{blue}{\left(p \cdot 4\right)} \cdot p\right)}}\right)} \]
        4. Applied rewrites100.0%

          \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}}\right)} \]
        5. Step-by-step derivation
          1. lift-sqrt.f64N/A

            \[\leadsto \color{blue}{\sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}\right)}} \]
          2. pow1/2N/A

            \[\leadsto \color{blue}{{\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}\right)\right)}^{\frac{1}{2}}} \]
          3. pow-to-expN/A

            \[\leadsto \color{blue}{e^{\log \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}\right)\right) \cdot \frac{1}{2}}} \]
          4. lower-exp.f64N/A

            \[\leadsto \color{blue}{e^{\log \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}\right)\right) \cdot \frac{1}{2}}} \]
          5. lower-*.f64N/A

            \[\leadsto e^{\color{blue}{\log \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}\right)\right) \cdot \frac{1}{2}}} \]
        6. Applied rewrites100.0%

          \[\leadsto \color{blue}{e^{\log \left(\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(4 \cdot p\right) \cdot p\right)}}, 0.5, 0.5\right)\right) \cdot 0.5}} \]
        7. Taylor expanded in p around 0

          \[\leadsto \color{blue}{1} \]
        8. Step-by-step derivation
          1. Applied rewrites100.0%

            \[\leadsto \color{blue}{1} \]
        9. Recombined 3 regimes into one program.
        10. Final simplification85.2%

          \[\leadsto \begin{array}{l} \mathbf{if}\;\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \leq 0.2:\\ \;\;\;\;\frac{-p}{x}\\ \mathbf{elif}\;\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \leq 0.7071067811865476:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(\frac{x}{p}, 0.25, 0.5\right)}\\ \mathbf{else}:\\ \;\;\;\;1\\ \end{array} \]
        11. Add Preprocessing

        Alternative 3: 98.0% accurate, 0.4× speedup?

        \[\begin{array}{l} p_m = \left|p\right| \\ \begin{array}{l} t_0 := \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\_m\right) \cdot p\_m + x \cdot x}}\right)}\\ \mathbf{if}\;t\_0 \leq 0.2:\\ \;\;\;\;\frac{-p\_m}{x}\\ \mathbf{elif}\;t\_0 \leq 0.7071067811865476:\\ \;\;\;\;\sqrt{0.5}\\ \mathbf{else}:\\ \;\;\;\;1\\ \end{array} \end{array} \]
        p_m = (fabs.f64 p)
        (FPCore (p_m x)
         :precision binary64
         (let* ((t_0
                 (sqrt (* 0.5 (+ 1.0 (/ x (sqrt (+ (* (* 4.0 p_m) p_m) (* x x)))))))))
           (if (<= t_0 0.2)
             (/ (- p_m) x)
             (if (<= t_0 0.7071067811865476) (sqrt 0.5) 1.0))))
        p_m = fabs(p);
        double code(double p_m, double x) {
        	double t_0 = sqrt((0.5 * (1.0 + (x / sqrt((((4.0 * p_m) * p_m) + (x * x)))))));
        	double tmp;
        	if (t_0 <= 0.2) {
        		tmp = -p_m / x;
        	} else if (t_0 <= 0.7071067811865476) {
        		tmp = sqrt(0.5);
        	} else {
        		tmp = 1.0;
        	}
        	return tmp;
        }
        
        p_m = abs(p)
        real(8) function code(p_m, x)
            real(8), intent (in) :: p_m
            real(8), intent (in) :: x
            real(8) :: t_0
            real(8) :: tmp
            t_0 = sqrt((0.5d0 * (1.0d0 + (x / sqrt((((4.0d0 * p_m) * p_m) + (x * x)))))))
            if (t_0 <= 0.2d0) then
                tmp = -p_m / x
            else if (t_0 <= 0.7071067811865476d0) then
                tmp = sqrt(0.5d0)
            else
                tmp = 1.0d0
            end if
            code = tmp
        end function
        
        p_m = Math.abs(p);
        public static double code(double p_m, double x) {
        	double t_0 = Math.sqrt((0.5 * (1.0 + (x / Math.sqrt((((4.0 * p_m) * p_m) + (x * x)))))));
        	double tmp;
        	if (t_0 <= 0.2) {
        		tmp = -p_m / x;
        	} else if (t_0 <= 0.7071067811865476) {
        		tmp = Math.sqrt(0.5);
        	} else {
        		tmp = 1.0;
        	}
        	return tmp;
        }
        
        p_m = math.fabs(p)
        def code(p_m, x):
        	t_0 = math.sqrt((0.5 * (1.0 + (x / math.sqrt((((4.0 * p_m) * p_m) + (x * x)))))))
        	tmp = 0
        	if t_0 <= 0.2:
        		tmp = -p_m / x
        	elif t_0 <= 0.7071067811865476:
        		tmp = math.sqrt(0.5)
        	else:
        		tmp = 1.0
        	return tmp
        
        p_m = abs(p)
        function code(p_m, x)
        	t_0 = sqrt(Float64(0.5 * Float64(1.0 + Float64(x / sqrt(Float64(Float64(Float64(4.0 * p_m) * p_m) + Float64(x * x)))))))
        	tmp = 0.0
        	if (t_0 <= 0.2)
        		tmp = Float64(Float64(-p_m) / x);
        	elseif (t_0 <= 0.7071067811865476)
        		tmp = sqrt(0.5);
        	else
        		tmp = 1.0;
        	end
        	return tmp
        end
        
        p_m = abs(p);
        function tmp_2 = code(p_m, x)
        	t_0 = sqrt((0.5 * (1.0 + (x / sqrt((((4.0 * p_m) * p_m) + (x * x)))))));
        	tmp = 0.0;
        	if (t_0 <= 0.2)
        		tmp = -p_m / x;
        	elseif (t_0 <= 0.7071067811865476)
        		tmp = sqrt(0.5);
        	else
        		tmp = 1.0;
        	end
        	tmp_2 = tmp;
        end
        
        p_m = N[Abs[p], $MachinePrecision]
        code[p$95$m_, x_] := Block[{t$95$0 = N[Sqrt[N[(0.5 * N[(1.0 + N[(x / N[Sqrt[N[(N[(N[(4.0 * p$95$m), $MachinePrecision] * p$95$m), $MachinePrecision] + N[(x * x), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[t$95$0, 0.2], N[((-p$95$m) / x), $MachinePrecision], If[LessEqual[t$95$0, 0.7071067811865476], N[Sqrt[0.5], $MachinePrecision], 1.0]]]
        
        \begin{array}{l}
        p_m = \left|p\right|
        
        \\
        \begin{array}{l}
        t_0 := \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\_m\right) \cdot p\_m + x \cdot x}}\right)}\\
        \mathbf{if}\;t\_0 \leq 0.2:\\
        \;\;\;\;\frac{-p\_m}{x}\\
        
        \mathbf{elif}\;t\_0 \leq 0.7071067811865476:\\
        \;\;\;\;\sqrt{0.5}\\
        
        \mathbf{else}:\\
        \;\;\;\;1\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 3 regimes
        2. if (sqrt.f64 (*.f64 #s(literal 1/2 binary64) (+.f64 #s(literal 1 binary64) (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x))))))) < 0.20000000000000001

          1. Initial program 15.9%

            \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
          2. Add Preprocessing
          3. Taylor expanded in x around -inf

            \[\leadsto \color{blue}{-1 \cdot \frac{p \cdot \left(\sqrt{\frac{1}{2}} \cdot \sqrt{2}\right)}{x}} \]
          4. Step-by-step derivation
            1. mul-1-negN/A

              \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{p \cdot \left(\sqrt{\frac{1}{2}} \cdot \sqrt{2}\right)}{x}\right)} \]
            2. associate-/l*N/A

              \[\leadsto \mathsf{neg}\left(\color{blue}{p \cdot \frac{\sqrt{\frac{1}{2}} \cdot \sqrt{2}}{x}}\right) \]
            3. distribute-lft-neg-inN/A

              \[\leadsto \color{blue}{\left(\mathsf{neg}\left(p\right)\right) \cdot \frac{\sqrt{\frac{1}{2}} \cdot \sqrt{2}}{x}} \]
            4. lower-*.f64N/A

              \[\leadsto \color{blue}{\left(\mathsf{neg}\left(p\right)\right) \cdot \frac{\sqrt{\frac{1}{2}} \cdot \sqrt{2}}{x}} \]
            5. lower-neg.f64N/A

              \[\leadsto \color{blue}{\left(-p\right)} \cdot \frac{\sqrt{\frac{1}{2}} \cdot \sqrt{2}}{x} \]
            6. *-commutativeN/A

              \[\leadsto \left(-p\right) \cdot \frac{\color{blue}{\sqrt{2} \cdot \sqrt{\frac{1}{2}}}}{x} \]
            7. associate-/l*N/A

              \[\leadsto \left(-p\right) \cdot \color{blue}{\left(\sqrt{2} \cdot \frac{\sqrt{\frac{1}{2}}}{x}\right)} \]
            8. lower-*.f64N/A

              \[\leadsto \left(-p\right) \cdot \color{blue}{\left(\sqrt{2} \cdot \frac{\sqrt{\frac{1}{2}}}{x}\right)} \]
            9. lower-sqrt.f64N/A

              \[\leadsto \left(-p\right) \cdot \left(\color{blue}{\sqrt{2}} \cdot \frac{\sqrt{\frac{1}{2}}}{x}\right) \]
            10. lower-/.f64N/A

              \[\leadsto \left(-p\right) \cdot \left(\sqrt{2} \cdot \color{blue}{\frac{\sqrt{\frac{1}{2}}}{x}}\right) \]
            11. lower-sqrt.f6449.3

              \[\leadsto \left(-p\right) \cdot \left(\sqrt{2} \cdot \frac{\color{blue}{\sqrt{0.5}}}{x}\right) \]
          5. Applied rewrites49.3%

            \[\leadsto \color{blue}{\left(-p\right) \cdot \left(\sqrt{2} \cdot \frac{\sqrt{0.5}}{x}\right)} \]
          6. Step-by-step derivation
            1. Applied rewrites49.7%

              \[\leadsto \color{blue}{\frac{-p}{x}} \]

            if 0.20000000000000001 < (sqrt.f64 (*.f64 #s(literal 1/2 binary64) (+.f64 #s(literal 1 binary64) (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x))))))) < 0.707106781186547573

            1. Initial program 99.8%

              \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
            2. Add Preprocessing
            3. Taylor expanded in p around inf

              \[\leadsto \sqrt{\color{blue}{\frac{1}{2}}} \]
            4. Step-by-step derivation
              1. Applied rewrites97.8%

                \[\leadsto \sqrt{\color{blue}{0.5}} \]

              if 0.707106781186547573 < (sqrt.f64 (*.f64 #s(literal 1/2 binary64) (+.f64 #s(literal 1 binary64) (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x)))))))

              1. Initial program 100.0%

                \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
              2. Add Preprocessing
              3. Step-by-step derivation
                1. lift-+.f64N/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{\left(4 \cdot p\right) \cdot p + x \cdot x}}}\right)} \]
                2. +-commutativeN/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{x \cdot x + \left(4 \cdot p\right) \cdot p}}}\right)} \]
                3. lift-*.f64N/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{x \cdot x} + \left(4 \cdot p\right) \cdot p}}\right)} \]
                4. lower-fma.f64100.0

                  \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{\mathsf{fma}\left(x, x, \left(4 \cdot p\right) \cdot p\right)}}}\right)} \]
                5. lift-*.f64N/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \color{blue}{\left(4 \cdot p\right)} \cdot p\right)}}\right)} \]
                6. *-commutativeN/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \color{blue}{\left(p \cdot 4\right)} \cdot p\right)}}\right)} \]
                7. lower-*.f64100.0

                  \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \color{blue}{\left(p \cdot 4\right)} \cdot p\right)}}\right)} \]
              4. Applied rewrites100.0%

                \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}}\right)} \]
              5. Step-by-step derivation
                1. lift-sqrt.f64N/A

                  \[\leadsto \color{blue}{\sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}\right)}} \]
                2. pow1/2N/A

                  \[\leadsto \color{blue}{{\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}\right)\right)}^{\frac{1}{2}}} \]
                3. pow-to-expN/A

                  \[\leadsto \color{blue}{e^{\log \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}\right)\right) \cdot \frac{1}{2}}} \]
                4. lower-exp.f64N/A

                  \[\leadsto \color{blue}{e^{\log \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}\right)\right) \cdot \frac{1}{2}}} \]
                5. lower-*.f64N/A

                  \[\leadsto e^{\color{blue}{\log \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}\right)\right) \cdot \frac{1}{2}}} \]
              6. Applied rewrites100.0%

                \[\leadsto \color{blue}{e^{\log \left(\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(4 \cdot p\right) \cdot p\right)}}, 0.5, 0.5\right)\right) \cdot 0.5}} \]
              7. Taylor expanded in p around 0

                \[\leadsto \color{blue}{1} \]
              8. Step-by-step derivation
                1. Applied rewrites100.0%

                  \[\leadsto \color{blue}{1} \]
              9. Recombined 3 regimes into one program.
              10. Final simplification84.9%

                \[\leadsto \begin{array}{l} \mathbf{if}\;\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \leq 0.2:\\ \;\;\;\;\frac{-p}{x}\\ \mathbf{elif}\;\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \leq 0.7071067811865476:\\ \;\;\;\;\sqrt{0.5}\\ \mathbf{else}:\\ \;\;\;\;1\\ \end{array} \]
              11. Add Preprocessing

              Alternative 4: 99.9% accurate, 0.5× speedup?

              \[\begin{array}{l} p_m = \left|p\right| \\ \begin{array}{l} t_0 := \left(4 \cdot p\_m\right) \cdot p\_m\\ \mathbf{if}\;\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{t\_0 + x \cdot x}}\right)} \leq 10^{-5}:\\ \;\;\;\;\frac{-p\_m}{x}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(x, x, t\_0\right)}}, 0.5, 0.5\right)}\\ \end{array} \end{array} \]
              p_m = (fabs.f64 p)
              (FPCore (p_m x)
               :precision binary64
               (let* ((t_0 (* (* 4.0 p_m) p_m)))
                 (if (<= (sqrt (* 0.5 (+ 1.0 (/ x (sqrt (+ t_0 (* x x))))))) 1e-5)
                   (/ (- p_m) x)
                   (sqrt (fma (/ x (sqrt (fma x x t_0))) 0.5 0.5)))))
              p_m = fabs(p);
              double code(double p_m, double x) {
              	double t_0 = (4.0 * p_m) * p_m;
              	double tmp;
              	if (sqrt((0.5 * (1.0 + (x / sqrt((t_0 + (x * x))))))) <= 1e-5) {
              		tmp = -p_m / x;
              	} else {
              		tmp = sqrt(fma((x / sqrt(fma(x, x, t_0))), 0.5, 0.5));
              	}
              	return tmp;
              }
              
              p_m = abs(p)
              function code(p_m, x)
              	t_0 = Float64(Float64(4.0 * p_m) * p_m)
              	tmp = 0.0
              	if (sqrt(Float64(0.5 * Float64(1.0 + Float64(x / sqrt(Float64(t_0 + Float64(x * x))))))) <= 1e-5)
              		tmp = Float64(Float64(-p_m) / x);
              	else
              		tmp = sqrt(fma(Float64(x / sqrt(fma(x, x, t_0))), 0.5, 0.5));
              	end
              	return tmp
              end
              
              p_m = N[Abs[p], $MachinePrecision]
              code[p$95$m_, x_] := Block[{t$95$0 = N[(N[(4.0 * p$95$m), $MachinePrecision] * p$95$m), $MachinePrecision]}, If[LessEqual[N[Sqrt[N[(0.5 * N[(1.0 + N[(x / N[Sqrt[N[(t$95$0 + N[(x * x), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision], 1e-5], N[((-p$95$m) / x), $MachinePrecision], N[Sqrt[N[(N[(x / N[Sqrt[N[(x * x + t$95$0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * 0.5 + 0.5), $MachinePrecision]], $MachinePrecision]]]
              
              \begin{array}{l}
              p_m = \left|p\right|
              
              \\
              \begin{array}{l}
              t_0 := \left(4 \cdot p\_m\right) \cdot p\_m\\
              \mathbf{if}\;\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{t\_0 + x \cdot x}}\right)} \leq 10^{-5}:\\
              \;\;\;\;\frac{-p\_m}{x}\\
              
              \mathbf{else}:\\
              \;\;\;\;\sqrt{\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(x, x, t\_0\right)}}, 0.5, 0.5\right)}\\
              
              
              \end{array}
              \end{array}
              
              Derivation
              1. Split input into 2 regimes
              2. if (sqrt.f64 (*.f64 #s(literal 1/2 binary64) (+.f64 #s(literal 1 binary64) (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x))))))) < 1.00000000000000008e-5

                1. Initial program 13.6%

                  \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
                2. Add Preprocessing
                3. Taylor expanded in x around -inf

                  \[\leadsto \color{blue}{-1 \cdot \frac{p \cdot \left(\sqrt{\frac{1}{2}} \cdot \sqrt{2}\right)}{x}} \]
                4. Step-by-step derivation
                  1. mul-1-negN/A

                    \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{p \cdot \left(\sqrt{\frac{1}{2}} \cdot \sqrt{2}\right)}{x}\right)} \]
                  2. associate-/l*N/A

                    \[\leadsto \mathsf{neg}\left(\color{blue}{p \cdot \frac{\sqrt{\frac{1}{2}} \cdot \sqrt{2}}{x}}\right) \]
                  3. distribute-lft-neg-inN/A

                    \[\leadsto \color{blue}{\left(\mathsf{neg}\left(p\right)\right) \cdot \frac{\sqrt{\frac{1}{2}} \cdot \sqrt{2}}{x}} \]
                  4. lower-*.f64N/A

                    \[\leadsto \color{blue}{\left(\mathsf{neg}\left(p\right)\right) \cdot \frac{\sqrt{\frac{1}{2}} \cdot \sqrt{2}}{x}} \]
                  5. lower-neg.f64N/A

                    \[\leadsto \color{blue}{\left(-p\right)} \cdot \frac{\sqrt{\frac{1}{2}} \cdot \sqrt{2}}{x} \]
                  6. *-commutativeN/A

                    \[\leadsto \left(-p\right) \cdot \frac{\color{blue}{\sqrt{2} \cdot \sqrt{\frac{1}{2}}}}{x} \]
                  7. associate-/l*N/A

                    \[\leadsto \left(-p\right) \cdot \color{blue}{\left(\sqrt{2} \cdot \frac{\sqrt{\frac{1}{2}}}{x}\right)} \]
                  8. lower-*.f64N/A

                    \[\leadsto \left(-p\right) \cdot \color{blue}{\left(\sqrt{2} \cdot \frac{\sqrt{\frac{1}{2}}}{x}\right)} \]
                  9. lower-sqrt.f64N/A

                    \[\leadsto \left(-p\right) \cdot \left(\color{blue}{\sqrt{2}} \cdot \frac{\sqrt{\frac{1}{2}}}{x}\right) \]
                  10. lower-/.f64N/A

                    \[\leadsto \left(-p\right) \cdot \left(\sqrt{2} \cdot \color{blue}{\frac{\sqrt{\frac{1}{2}}}{x}}\right) \]
                  11. lower-sqrt.f6450.2

                    \[\leadsto \left(-p\right) \cdot \left(\sqrt{2} \cdot \frac{\color{blue}{\sqrt{0.5}}}{x}\right) \]
                5. Applied rewrites50.2%

                  \[\leadsto \color{blue}{\left(-p\right) \cdot \left(\sqrt{2} \cdot \frac{\sqrt{0.5}}{x}\right)} \]
                6. Step-by-step derivation
                  1. Applied rewrites50.6%

                    \[\leadsto \color{blue}{\frac{-p}{x}} \]

                  if 1.00000000000000008e-5 < (sqrt.f64 (*.f64 #s(literal 1/2 binary64) (+.f64 #s(literal 1 binary64) (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x)))))))

                  1. Initial program 99.8%

                    \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
                  2. Add Preprocessing
                  3. Step-by-step derivation
                    1. lift-+.f64N/A

                      \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{\left(4 \cdot p\right) \cdot p + x \cdot x}}}\right)} \]
                    2. +-commutativeN/A

                      \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{x \cdot x + \left(4 \cdot p\right) \cdot p}}}\right)} \]
                    3. lift-*.f64N/A

                      \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{x \cdot x} + \left(4 \cdot p\right) \cdot p}}\right)} \]
                    4. lower-fma.f6499.9

                      \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{\mathsf{fma}\left(x, x, \left(4 \cdot p\right) \cdot p\right)}}}\right)} \]
                    5. lift-*.f64N/A

                      \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \color{blue}{\left(4 \cdot p\right)} \cdot p\right)}}\right)} \]
                    6. *-commutativeN/A

                      \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \color{blue}{\left(p \cdot 4\right)} \cdot p\right)}}\right)} \]
                    7. lower-*.f6499.9

                      \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \color{blue}{\left(p \cdot 4\right)} \cdot p\right)}}\right)} \]
                  4. Applied rewrites99.9%

                    \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}}\right)} \]
                  5. Step-by-step derivation
                    1. lift-*.f64N/A

                      \[\leadsto \sqrt{\color{blue}{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}\right)}} \]
                    2. lift-+.f64N/A

                      \[\leadsto \sqrt{\frac{1}{2} \cdot \color{blue}{\left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}\right)}} \]
                    3. distribute-rgt-inN/A

                      \[\leadsto \sqrt{\color{blue}{1 \cdot \frac{1}{2} + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}} \cdot \frac{1}{2}}} \]
                    4. metadata-evalN/A

                      \[\leadsto \sqrt{\color{blue}{\frac{1}{2}} + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}} \cdot \frac{1}{2}} \]
                    5. +-commutativeN/A

                      \[\leadsto \sqrt{\color{blue}{\frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}} \cdot \frac{1}{2} + \frac{1}{2}}} \]
                    6. lower-fma.f6499.9

                      \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}, 0.5, 0.5\right)}} \]
                    7. lift-*.f64N/A

                      \[\leadsto \sqrt{\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(x, x, \color{blue}{\left(p \cdot 4\right)} \cdot p\right)}}, \frac{1}{2}, \frac{1}{2}\right)} \]
                    8. *-commutativeN/A

                      \[\leadsto \sqrt{\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(x, x, \color{blue}{\left(4 \cdot p\right)} \cdot p\right)}}, \frac{1}{2}, \frac{1}{2}\right)} \]
                    9. lower-*.f6499.9

                      \[\leadsto \sqrt{\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(x, x, \color{blue}{\left(4 \cdot p\right)} \cdot p\right)}}, 0.5, 0.5\right)} \]
                  6. Applied rewrites99.9%

                    \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(4 \cdot p\right) \cdot p\right)}}, 0.5, 0.5\right)}} \]
                7. Recombined 2 regimes into one program.
                8. Final simplification86.4%

                  \[\leadsto \begin{array}{l} \mathbf{if}\;\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \leq 10^{-5}:\\ \;\;\;\;\frac{-p}{x}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(4 \cdot p\right) \cdot p\right)}}, 0.5, 0.5\right)}\\ \end{array} \]
                9. Add Preprocessing

                Alternative 5: 74.8% accurate, 0.8× speedup?

                \[\begin{array}{l} p_m = \left|p\right| \\ \begin{array}{l} \mathbf{if}\;\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\_m\right) \cdot p\_m + x \cdot x}}\right)} \leq 0.7071067811865476:\\ \;\;\;\;\sqrt{0.5}\\ \mathbf{else}:\\ \;\;\;\;1\\ \end{array} \end{array} \]
                p_m = (fabs.f64 p)
                (FPCore (p_m x)
                 :precision binary64
                 (if (<=
                      (sqrt (* 0.5 (+ 1.0 (/ x (sqrt (+ (* (* 4.0 p_m) p_m) (* x x)))))))
                      0.7071067811865476)
                   (sqrt 0.5)
                   1.0))
                p_m = fabs(p);
                double code(double p_m, double x) {
                	double tmp;
                	if (sqrt((0.5 * (1.0 + (x / sqrt((((4.0 * p_m) * p_m) + (x * x))))))) <= 0.7071067811865476) {
                		tmp = sqrt(0.5);
                	} else {
                		tmp = 1.0;
                	}
                	return tmp;
                }
                
                p_m = abs(p)
                real(8) function code(p_m, x)
                    real(8), intent (in) :: p_m
                    real(8), intent (in) :: x
                    real(8) :: tmp
                    if (sqrt((0.5d0 * (1.0d0 + (x / sqrt((((4.0d0 * p_m) * p_m) + (x * x))))))) <= 0.7071067811865476d0) then
                        tmp = sqrt(0.5d0)
                    else
                        tmp = 1.0d0
                    end if
                    code = tmp
                end function
                
                p_m = Math.abs(p);
                public static double code(double p_m, double x) {
                	double tmp;
                	if (Math.sqrt((0.5 * (1.0 + (x / Math.sqrt((((4.0 * p_m) * p_m) + (x * x))))))) <= 0.7071067811865476) {
                		tmp = Math.sqrt(0.5);
                	} else {
                		tmp = 1.0;
                	}
                	return tmp;
                }
                
                p_m = math.fabs(p)
                def code(p_m, x):
                	tmp = 0
                	if math.sqrt((0.5 * (1.0 + (x / math.sqrt((((4.0 * p_m) * p_m) + (x * x))))))) <= 0.7071067811865476:
                		tmp = math.sqrt(0.5)
                	else:
                		tmp = 1.0
                	return tmp
                
                p_m = abs(p)
                function code(p_m, x)
                	tmp = 0.0
                	if (sqrt(Float64(0.5 * Float64(1.0 + Float64(x / sqrt(Float64(Float64(Float64(4.0 * p_m) * p_m) + Float64(x * x))))))) <= 0.7071067811865476)
                		tmp = sqrt(0.5);
                	else
                		tmp = 1.0;
                	end
                	return tmp
                end
                
                p_m = abs(p);
                function tmp_2 = code(p_m, x)
                	tmp = 0.0;
                	if (sqrt((0.5 * (1.0 + (x / sqrt((((4.0 * p_m) * p_m) + (x * x))))))) <= 0.7071067811865476)
                		tmp = sqrt(0.5);
                	else
                		tmp = 1.0;
                	end
                	tmp_2 = tmp;
                end
                
                p_m = N[Abs[p], $MachinePrecision]
                code[p$95$m_, x_] := If[LessEqual[N[Sqrt[N[(0.5 * N[(1.0 + N[(x / N[Sqrt[N[(N[(N[(4.0 * p$95$m), $MachinePrecision] * p$95$m), $MachinePrecision] + N[(x * x), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision], 0.7071067811865476], N[Sqrt[0.5], $MachinePrecision], 1.0]
                
                \begin{array}{l}
                p_m = \left|p\right|
                
                \\
                \begin{array}{l}
                \mathbf{if}\;\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\_m\right) \cdot p\_m + x \cdot x}}\right)} \leq 0.7071067811865476:\\
                \;\;\;\;\sqrt{0.5}\\
                
                \mathbf{else}:\\
                \;\;\;\;1\\
                
                
                \end{array}
                \end{array}
                
                Derivation
                1. Split input into 2 regimes
                2. if (sqrt.f64 (*.f64 #s(literal 1/2 binary64) (+.f64 #s(literal 1 binary64) (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x))))))) < 0.707106781186547573

                  1. Initial program 66.2%

                    \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
                  2. Add Preprocessing
                  3. Taylor expanded in p around inf

                    \[\leadsto \sqrt{\color{blue}{\frac{1}{2}}} \]
                  4. Step-by-step derivation
                    1. Applied rewrites60.8%

                      \[\leadsto \sqrt{\color{blue}{0.5}} \]

                    if 0.707106781186547573 < (sqrt.f64 (*.f64 #s(literal 1/2 binary64) (+.f64 #s(literal 1 binary64) (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x)))))))

                    1. Initial program 100.0%

                      \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
                    2. Add Preprocessing
                    3. Step-by-step derivation
                      1. lift-+.f64N/A

                        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{\left(4 \cdot p\right) \cdot p + x \cdot x}}}\right)} \]
                      2. +-commutativeN/A

                        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{x \cdot x + \left(4 \cdot p\right) \cdot p}}}\right)} \]
                      3. lift-*.f64N/A

                        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{x \cdot x} + \left(4 \cdot p\right) \cdot p}}\right)} \]
                      4. lower-fma.f64100.0

                        \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{\mathsf{fma}\left(x, x, \left(4 \cdot p\right) \cdot p\right)}}}\right)} \]
                      5. lift-*.f64N/A

                        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \color{blue}{\left(4 \cdot p\right)} \cdot p\right)}}\right)} \]
                      6. *-commutativeN/A

                        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \color{blue}{\left(p \cdot 4\right)} \cdot p\right)}}\right)} \]
                      7. lower-*.f64100.0

                        \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \color{blue}{\left(p \cdot 4\right)} \cdot p\right)}}\right)} \]
                    4. Applied rewrites100.0%

                      \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}}\right)} \]
                    5. Step-by-step derivation
                      1. lift-sqrt.f64N/A

                        \[\leadsto \color{blue}{\sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}\right)}} \]
                      2. pow1/2N/A

                        \[\leadsto \color{blue}{{\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}\right)\right)}^{\frac{1}{2}}} \]
                      3. pow-to-expN/A

                        \[\leadsto \color{blue}{e^{\log \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}\right)\right) \cdot \frac{1}{2}}} \]
                      4. lower-exp.f64N/A

                        \[\leadsto \color{blue}{e^{\log \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}\right)\right) \cdot \frac{1}{2}}} \]
                      5. lower-*.f64N/A

                        \[\leadsto e^{\color{blue}{\log \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}\right)\right) \cdot \frac{1}{2}}} \]
                    6. Applied rewrites100.0%

                      \[\leadsto \color{blue}{e^{\log \left(\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(4 \cdot p\right) \cdot p\right)}}, 0.5, 0.5\right)\right) \cdot 0.5}} \]
                    7. Taylor expanded in p around 0

                      \[\leadsto \color{blue}{1} \]
                    8. Step-by-step derivation
                      1. Applied rewrites100.0%

                        \[\leadsto \color{blue}{1} \]
                    9. Recombined 2 regimes into one program.
                    10. Add Preprocessing

                    Alternative 6: 36.1% accurate, 58.0× speedup?

                    \[\begin{array}{l} p_m = \left|p\right| \\ 1 \end{array} \]
                    p_m = (fabs.f64 p)
                    (FPCore (p_m x) :precision binary64 1.0)
                    p_m = fabs(p);
                    double code(double p_m, double x) {
                    	return 1.0;
                    }
                    
                    p_m = abs(p)
                    real(8) function code(p_m, x)
                        real(8), intent (in) :: p_m
                        real(8), intent (in) :: x
                        code = 1.0d0
                    end function
                    
                    p_m = Math.abs(p);
                    public static double code(double p_m, double x) {
                    	return 1.0;
                    }
                    
                    p_m = math.fabs(p)
                    def code(p_m, x):
                    	return 1.0
                    
                    p_m = abs(p)
                    function code(p_m, x)
                    	return 1.0
                    end
                    
                    p_m = abs(p);
                    function tmp = code(p_m, x)
                    	tmp = 1.0;
                    end
                    
                    p_m = N[Abs[p], $MachinePrecision]
                    code[p$95$m_, x_] := 1.0
                    
                    \begin{array}{l}
                    p_m = \left|p\right|
                    
                    \\
                    1
                    \end{array}
                    
                    Derivation
                    1. Initial program 76.3%

                      \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
                    2. Add Preprocessing
                    3. Step-by-step derivation
                      1. lift-+.f64N/A

                        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{\left(4 \cdot p\right) \cdot p + x \cdot x}}}\right)} \]
                      2. +-commutativeN/A

                        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{x \cdot x + \left(4 \cdot p\right) \cdot p}}}\right)} \]
                      3. lift-*.f64N/A

                        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{x \cdot x} + \left(4 \cdot p\right) \cdot p}}\right)} \]
                      4. lower-fma.f6476.3

                        \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{\mathsf{fma}\left(x, x, \left(4 \cdot p\right) \cdot p\right)}}}\right)} \]
                      5. lift-*.f64N/A

                        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \color{blue}{\left(4 \cdot p\right)} \cdot p\right)}}\right)} \]
                      6. *-commutativeN/A

                        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \color{blue}{\left(p \cdot 4\right)} \cdot p\right)}}\right)} \]
                      7. lower-*.f6476.3

                        \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \color{blue}{\left(p \cdot 4\right)} \cdot p\right)}}\right)} \]
                    4. Applied rewrites76.3%

                      \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\color{blue}{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}}\right)} \]
                    5. Step-by-step derivation
                      1. lift-sqrt.f64N/A

                        \[\leadsto \color{blue}{\sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}\right)}} \]
                      2. pow1/2N/A

                        \[\leadsto \color{blue}{{\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}\right)\right)}^{\frac{1}{2}}} \]
                      3. pow-to-expN/A

                        \[\leadsto \color{blue}{e^{\log \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}\right)\right) \cdot \frac{1}{2}}} \]
                      4. lower-exp.f64N/A

                        \[\leadsto \color{blue}{e^{\log \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}\right)\right) \cdot \frac{1}{2}}} \]
                      5. lower-*.f64N/A

                        \[\leadsto e^{\color{blue}{\log \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(p \cdot 4\right) \cdot p\right)}}\right)\right) \cdot \frac{1}{2}}} \]
                    6. Applied rewrites76.3%

                      \[\leadsto \color{blue}{e^{\log \left(\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(x, x, \left(4 \cdot p\right) \cdot p\right)}}, 0.5, 0.5\right)\right) \cdot 0.5}} \]
                    7. Taylor expanded in p around 0

                      \[\leadsto \color{blue}{1} \]
                    8. Step-by-step derivation
                      1. Applied rewrites39.6%

                        \[\leadsto \color{blue}{1} \]
                      2. Add Preprocessing

                      Developer Target 1: 79.6% accurate, 0.2× speedup?

                      \[\begin{array}{l} \\ \sqrt{0.5 + \frac{\mathsf{copysign}\left(0.5, x\right)}{\mathsf{hypot}\left(1, \frac{2 \cdot p}{x}\right)}} \end{array} \]
                      (FPCore (p x)
                       :precision binary64
                       (sqrt (+ 0.5 (/ (copysign 0.5 x) (hypot 1.0 (/ (* 2.0 p) x))))))
                      double code(double p, double x) {
                      	return sqrt((0.5 + (copysign(0.5, x) / hypot(1.0, ((2.0 * p) / x)))));
                      }
                      
                      public static double code(double p, double x) {
                      	return Math.sqrt((0.5 + (Math.copySign(0.5, x) / Math.hypot(1.0, ((2.0 * p) / x)))));
                      }
                      
                      def code(p, x):
                      	return math.sqrt((0.5 + (math.copysign(0.5, x) / math.hypot(1.0, ((2.0 * p) / x)))))
                      
                      function code(p, x)
                      	return sqrt(Float64(0.5 + Float64(copysign(0.5, x) / hypot(1.0, Float64(Float64(2.0 * p) / x)))))
                      end
                      
                      function tmp = code(p, x)
                      	tmp = sqrt((0.5 + ((sign(x) * abs(0.5)) / hypot(1.0, ((2.0 * p) / x)))));
                      end
                      
                      code[p_, x_] := N[Sqrt[N[(0.5 + N[(N[With[{TMP1 = Abs[0.5], TMP2 = Sign[x]}, TMP1 * If[TMP2 == 0, 1, TMP2]], $MachinePrecision] / N[Sqrt[1.0 ^ 2 + N[(N[(2.0 * p), $MachinePrecision] / x), $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
                      
                      \begin{array}{l}
                      
                      \\
                      \sqrt{0.5 + \frac{\mathsf{copysign}\left(0.5, x\right)}{\mathsf{hypot}\left(1, \frac{2 \cdot p}{x}\right)}}
                      \end{array}
                      

                      Reproduce

                      ?
                      herbie shell --seed 2024337 
                      (FPCore (p x)
                        :name "Given's Rotation SVD example"
                        :precision binary64
                        :pre (and (< 1e-150 (fabs x)) (< (fabs x) 1e+150))
                      
                        :alt
                        (! :herbie-platform default (sqrt (+ 1/2 (/ (copysign 1/2 x) (hypot 1 (/ (* 2 p) x))))))
                      
                        (sqrt (* 0.5 (+ 1.0 (/ x (sqrt (+ (* (* 4.0 p) p) (* x x))))))))