Rosa's FloatVsDoubleBenchmark

Percentage Accurate: 69.8% → 99.5%
Time: 17.5s
Alternatives: 20
Speedup: 6.6×

Specification

?
\[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(3 \cdot x1\right) \cdot x1\\ t_1 := x1 \cdot x1 + 1\\ t_2 := \frac{\left(t\_0 + 2 \cdot x2\right) - x1}{t\_1}\\ x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot t\_2\right) \cdot \left(t\_2 - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot t\_2 - 6\right)\right) \cdot t\_1 + t\_0 \cdot t\_2\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(t\_0 - 2 \cdot x2\right) - x1}{t\_1}\right) \end{array} \end{array} \]
(FPCore (x1 x2)
 :precision binary64
 (let* ((t_0 (* (* 3.0 x1) x1))
        (t_1 (+ (* x1 x1) 1.0))
        (t_2 (/ (- (+ t_0 (* 2.0 x2)) x1) t_1)))
   (+
    x1
    (+
     (+
      (+
       (+
        (*
         (+
          (* (* (* 2.0 x1) t_2) (- t_2 3.0))
          (* (* x1 x1) (- (* 4.0 t_2) 6.0)))
         t_1)
        (* t_0 t_2))
       (* (* x1 x1) x1))
      x1)
     (* 3.0 (/ (- (- t_0 (* 2.0 x2)) x1) t_1))))))
double code(double x1, double x2) {
	double t_0 = (3.0 * x1) * x1;
	double t_1 = (x1 * x1) + 1.0;
	double t_2 = ((t_0 + (2.0 * x2)) - x1) / t_1;
	return x1 + (((((((((2.0 * x1) * t_2) * (t_2 - 3.0)) + ((x1 * x1) * ((4.0 * t_2) - 6.0))) * t_1) + (t_0 * t_2)) + ((x1 * x1) * x1)) + x1) + (3.0 * (((t_0 - (2.0 * x2)) - x1) / t_1)));
}
real(8) function code(x1, x2)
    real(8), intent (in) :: x1
    real(8), intent (in) :: x2
    real(8) :: t_0
    real(8) :: t_1
    real(8) :: t_2
    t_0 = (3.0d0 * x1) * x1
    t_1 = (x1 * x1) + 1.0d0
    t_2 = ((t_0 + (2.0d0 * x2)) - x1) / t_1
    code = x1 + (((((((((2.0d0 * x1) * t_2) * (t_2 - 3.0d0)) + ((x1 * x1) * ((4.0d0 * t_2) - 6.0d0))) * t_1) + (t_0 * t_2)) + ((x1 * x1) * x1)) + x1) + (3.0d0 * (((t_0 - (2.0d0 * x2)) - x1) / t_1)))
end function
public static double code(double x1, double x2) {
	double t_0 = (3.0 * x1) * x1;
	double t_1 = (x1 * x1) + 1.0;
	double t_2 = ((t_0 + (2.0 * x2)) - x1) / t_1;
	return x1 + (((((((((2.0 * x1) * t_2) * (t_2 - 3.0)) + ((x1 * x1) * ((4.0 * t_2) - 6.0))) * t_1) + (t_0 * t_2)) + ((x1 * x1) * x1)) + x1) + (3.0 * (((t_0 - (2.0 * x2)) - x1) / t_1)));
}
def code(x1, x2):
	t_0 = (3.0 * x1) * x1
	t_1 = (x1 * x1) + 1.0
	t_2 = ((t_0 + (2.0 * x2)) - x1) / t_1
	return x1 + (((((((((2.0 * x1) * t_2) * (t_2 - 3.0)) + ((x1 * x1) * ((4.0 * t_2) - 6.0))) * t_1) + (t_0 * t_2)) + ((x1 * x1) * x1)) + x1) + (3.0 * (((t_0 - (2.0 * x2)) - x1) / t_1)))
function code(x1, x2)
	t_0 = Float64(Float64(3.0 * x1) * x1)
	t_1 = Float64(Float64(x1 * x1) + 1.0)
	t_2 = Float64(Float64(Float64(t_0 + Float64(2.0 * x2)) - x1) / t_1)
	return Float64(x1 + Float64(Float64(Float64(Float64(Float64(Float64(Float64(Float64(Float64(2.0 * x1) * t_2) * Float64(t_2 - 3.0)) + Float64(Float64(x1 * x1) * Float64(Float64(4.0 * t_2) - 6.0))) * t_1) + Float64(t_0 * t_2)) + Float64(Float64(x1 * x1) * x1)) + x1) + Float64(3.0 * Float64(Float64(Float64(t_0 - Float64(2.0 * x2)) - x1) / t_1))))
end
function tmp = code(x1, x2)
	t_0 = (3.0 * x1) * x1;
	t_1 = (x1 * x1) + 1.0;
	t_2 = ((t_0 + (2.0 * x2)) - x1) / t_1;
	tmp = x1 + (((((((((2.0 * x1) * t_2) * (t_2 - 3.0)) + ((x1 * x1) * ((4.0 * t_2) - 6.0))) * t_1) + (t_0 * t_2)) + ((x1 * x1) * x1)) + x1) + (3.0 * (((t_0 - (2.0 * x2)) - x1) / t_1)));
end
code[x1_, x2_] := Block[{t$95$0 = N[(N[(3.0 * x1), $MachinePrecision] * x1), $MachinePrecision]}, Block[{t$95$1 = N[(N[(x1 * x1), $MachinePrecision] + 1.0), $MachinePrecision]}, Block[{t$95$2 = N[(N[(N[(t$95$0 + N[(2.0 * x2), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision] / t$95$1), $MachinePrecision]}, N[(x1 + N[(N[(N[(N[(N[(N[(N[(N[(N[(2.0 * x1), $MachinePrecision] * t$95$2), $MachinePrecision] * N[(t$95$2 - 3.0), $MachinePrecision]), $MachinePrecision] + N[(N[(x1 * x1), $MachinePrecision] * N[(N[(4.0 * t$95$2), $MachinePrecision] - 6.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * t$95$1), $MachinePrecision] + N[(t$95$0 * t$95$2), $MachinePrecision]), $MachinePrecision] + N[(N[(x1 * x1), $MachinePrecision] * x1), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision] + N[(3.0 * N[(N[(N[(t$95$0 - N[(2.0 * x2), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision] / t$95$1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \left(3 \cdot x1\right) \cdot x1\\
t_1 := x1 \cdot x1 + 1\\
t_2 := \frac{\left(t\_0 + 2 \cdot x2\right) - x1}{t\_1}\\
x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot t\_2\right) \cdot \left(t\_2 - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot t\_2 - 6\right)\right) \cdot t\_1 + t\_0 \cdot t\_2\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(t\_0 - 2 \cdot x2\right) - x1}{t\_1}\right)
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 20 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 69.8% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(3 \cdot x1\right) \cdot x1\\ t_1 := x1 \cdot x1 + 1\\ t_2 := \frac{\left(t\_0 + 2 \cdot x2\right) - x1}{t\_1}\\ x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot t\_2\right) \cdot \left(t\_2 - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot t\_2 - 6\right)\right) \cdot t\_1 + t\_0 \cdot t\_2\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(t\_0 - 2 \cdot x2\right) - x1}{t\_1}\right) \end{array} \end{array} \]
(FPCore (x1 x2)
 :precision binary64
 (let* ((t_0 (* (* 3.0 x1) x1))
        (t_1 (+ (* x1 x1) 1.0))
        (t_2 (/ (- (+ t_0 (* 2.0 x2)) x1) t_1)))
   (+
    x1
    (+
     (+
      (+
       (+
        (*
         (+
          (* (* (* 2.0 x1) t_2) (- t_2 3.0))
          (* (* x1 x1) (- (* 4.0 t_2) 6.0)))
         t_1)
        (* t_0 t_2))
       (* (* x1 x1) x1))
      x1)
     (* 3.0 (/ (- (- t_0 (* 2.0 x2)) x1) t_1))))))
double code(double x1, double x2) {
	double t_0 = (3.0 * x1) * x1;
	double t_1 = (x1 * x1) + 1.0;
	double t_2 = ((t_0 + (2.0 * x2)) - x1) / t_1;
	return x1 + (((((((((2.0 * x1) * t_2) * (t_2 - 3.0)) + ((x1 * x1) * ((4.0 * t_2) - 6.0))) * t_1) + (t_0 * t_2)) + ((x1 * x1) * x1)) + x1) + (3.0 * (((t_0 - (2.0 * x2)) - x1) / t_1)));
}
real(8) function code(x1, x2)
    real(8), intent (in) :: x1
    real(8), intent (in) :: x2
    real(8) :: t_0
    real(8) :: t_1
    real(8) :: t_2
    t_0 = (3.0d0 * x1) * x1
    t_1 = (x1 * x1) + 1.0d0
    t_2 = ((t_0 + (2.0d0 * x2)) - x1) / t_1
    code = x1 + (((((((((2.0d0 * x1) * t_2) * (t_2 - 3.0d0)) + ((x1 * x1) * ((4.0d0 * t_2) - 6.0d0))) * t_1) + (t_0 * t_2)) + ((x1 * x1) * x1)) + x1) + (3.0d0 * (((t_0 - (2.0d0 * x2)) - x1) / t_1)))
end function
public static double code(double x1, double x2) {
	double t_0 = (3.0 * x1) * x1;
	double t_1 = (x1 * x1) + 1.0;
	double t_2 = ((t_0 + (2.0 * x2)) - x1) / t_1;
	return x1 + (((((((((2.0 * x1) * t_2) * (t_2 - 3.0)) + ((x1 * x1) * ((4.0 * t_2) - 6.0))) * t_1) + (t_0 * t_2)) + ((x1 * x1) * x1)) + x1) + (3.0 * (((t_0 - (2.0 * x2)) - x1) / t_1)));
}
def code(x1, x2):
	t_0 = (3.0 * x1) * x1
	t_1 = (x1 * x1) + 1.0
	t_2 = ((t_0 + (2.0 * x2)) - x1) / t_1
	return x1 + (((((((((2.0 * x1) * t_2) * (t_2 - 3.0)) + ((x1 * x1) * ((4.0 * t_2) - 6.0))) * t_1) + (t_0 * t_2)) + ((x1 * x1) * x1)) + x1) + (3.0 * (((t_0 - (2.0 * x2)) - x1) / t_1)))
function code(x1, x2)
	t_0 = Float64(Float64(3.0 * x1) * x1)
	t_1 = Float64(Float64(x1 * x1) + 1.0)
	t_2 = Float64(Float64(Float64(t_0 + Float64(2.0 * x2)) - x1) / t_1)
	return Float64(x1 + Float64(Float64(Float64(Float64(Float64(Float64(Float64(Float64(Float64(2.0 * x1) * t_2) * Float64(t_2 - 3.0)) + Float64(Float64(x1 * x1) * Float64(Float64(4.0 * t_2) - 6.0))) * t_1) + Float64(t_0 * t_2)) + Float64(Float64(x1 * x1) * x1)) + x1) + Float64(3.0 * Float64(Float64(Float64(t_0 - Float64(2.0 * x2)) - x1) / t_1))))
end
function tmp = code(x1, x2)
	t_0 = (3.0 * x1) * x1;
	t_1 = (x1 * x1) + 1.0;
	t_2 = ((t_0 + (2.0 * x2)) - x1) / t_1;
	tmp = x1 + (((((((((2.0 * x1) * t_2) * (t_2 - 3.0)) + ((x1 * x1) * ((4.0 * t_2) - 6.0))) * t_1) + (t_0 * t_2)) + ((x1 * x1) * x1)) + x1) + (3.0 * (((t_0 - (2.0 * x2)) - x1) / t_1)));
end
code[x1_, x2_] := Block[{t$95$0 = N[(N[(3.0 * x1), $MachinePrecision] * x1), $MachinePrecision]}, Block[{t$95$1 = N[(N[(x1 * x1), $MachinePrecision] + 1.0), $MachinePrecision]}, Block[{t$95$2 = N[(N[(N[(t$95$0 + N[(2.0 * x2), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision] / t$95$1), $MachinePrecision]}, N[(x1 + N[(N[(N[(N[(N[(N[(N[(N[(N[(2.0 * x1), $MachinePrecision] * t$95$2), $MachinePrecision] * N[(t$95$2 - 3.0), $MachinePrecision]), $MachinePrecision] + N[(N[(x1 * x1), $MachinePrecision] * N[(N[(4.0 * t$95$2), $MachinePrecision] - 6.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * t$95$1), $MachinePrecision] + N[(t$95$0 * t$95$2), $MachinePrecision]), $MachinePrecision] + N[(N[(x1 * x1), $MachinePrecision] * x1), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision] + N[(3.0 * N[(N[(N[(t$95$0 - N[(2.0 * x2), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision] / t$95$1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \left(3 \cdot x1\right) \cdot x1\\
t_1 := x1 \cdot x1 + 1\\
t_2 := \frac{\left(t\_0 + 2 \cdot x2\right) - x1}{t\_1}\\
x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot t\_2\right) \cdot \left(t\_2 - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot t\_2 - 6\right)\right) \cdot t\_1 + t\_0 \cdot t\_2\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(t\_0 - 2 \cdot x2\right) - x1}{t\_1}\right)
\end{array}
\end{array}

Alternative 1: 99.5% accurate, 0.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(3 \cdot x1\right) \cdot x1\\ t_1 := x1 \cdot x1 + 1\\ t_2 := \frac{\left(t\_0 + 2 \cdot x2\right) - x1}{t\_1}\\ t_3 := x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot t\_2\right) \cdot \left(t\_2 - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot t\_2 - 6\right)\right) \cdot t\_1 + t\_0 \cdot t\_2\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(t\_0 - 2 \cdot x2\right) - x1}{t\_1}\right)\\ \mathbf{if}\;t\_3 \leq \infty:\\ \;\;\;\;t\_3\\ \mathbf{else}:\\ \;\;\;\;\left(\mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)\right) \cdot x1\right) \cdot x1\\ \end{array} \end{array} \]
(FPCore (x1 x2)
 :precision binary64
 (let* ((t_0 (* (* 3.0 x1) x1))
        (t_1 (+ (* x1 x1) 1.0))
        (t_2 (/ (- (+ t_0 (* 2.0 x2)) x1) t_1))
        (t_3
         (+
          x1
          (+
           (+
            (+
             (+
              (*
               (+
                (* (* (* 2.0 x1) t_2) (- t_2 3.0))
                (* (* x1 x1) (- (* 4.0 t_2) 6.0)))
               t_1)
              (* t_0 t_2))
             (* (* x1 x1) x1))
            x1)
           (* 3.0 (/ (- (- t_0 (* 2.0 x2)) x1) t_1))))))
   (if (<= t_3 INFINITY)
     t_3
     (*
      (* (fma (- (* 6.0 x1) 3.0) x1 (fma (- (* 2.0 x2) 3.0) 4.0 9.0)) x1)
      x1))))
double code(double x1, double x2) {
	double t_0 = (3.0 * x1) * x1;
	double t_1 = (x1 * x1) + 1.0;
	double t_2 = ((t_0 + (2.0 * x2)) - x1) / t_1;
	double t_3 = x1 + (((((((((2.0 * x1) * t_2) * (t_2 - 3.0)) + ((x1 * x1) * ((4.0 * t_2) - 6.0))) * t_1) + (t_0 * t_2)) + ((x1 * x1) * x1)) + x1) + (3.0 * (((t_0 - (2.0 * x2)) - x1) / t_1)));
	double tmp;
	if (t_3 <= ((double) INFINITY)) {
		tmp = t_3;
	} else {
		tmp = (fma(((6.0 * x1) - 3.0), x1, fma(((2.0 * x2) - 3.0), 4.0, 9.0)) * x1) * x1;
	}
	return tmp;
}
function code(x1, x2)
	t_0 = Float64(Float64(3.0 * x1) * x1)
	t_1 = Float64(Float64(x1 * x1) + 1.0)
	t_2 = Float64(Float64(Float64(t_0 + Float64(2.0 * x2)) - x1) / t_1)
	t_3 = Float64(x1 + Float64(Float64(Float64(Float64(Float64(Float64(Float64(Float64(Float64(2.0 * x1) * t_2) * Float64(t_2 - 3.0)) + Float64(Float64(x1 * x1) * Float64(Float64(4.0 * t_2) - 6.0))) * t_1) + Float64(t_0 * t_2)) + Float64(Float64(x1 * x1) * x1)) + x1) + Float64(3.0 * Float64(Float64(Float64(t_0 - Float64(2.0 * x2)) - x1) / t_1))))
	tmp = 0.0
	if (t_3 <= Inf)
		tmp = t_3;
	else
		tmp = Float64(Float64(fma(Float64(Float64(6.0 * x1) - 3.0), x1, fma(Float64(Float64(2.0 * x2) - 3.0), 4.0, 9.0)) * x1) * x1);
	end
	return tmp
end
code[x1_, x2_] := Block[{t$95$0 = N[(N[(3.0 * x1), $MachinePrecision] * x1), $MachinePrecision]}, Block[{t$95$1 = N[(N[(x1 * x1), $MachinePrecision] + 1.0), $MachinePrecision]}, Block[{t$95$2 = N[(N[(N[(t$95$0 + N[(2.0 * x2), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision] / t$95$1), $MachinePrecision]}, Block[{t$95$3 = N[(x1 + N[(N[(N[(N[(N[(N[(N[(N[(N[(2.0 * x1), $MachinePrecision] * t$95$2), $MachinePrecision] * N[(t$95$2 - 3.0), $MachinePrecision]), $MachinePrecision] + N[(N[(x1 * x1), $MachinePrecision] * N[(N[(4.0 * t$95$2), $MachinePrecision] - 6.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * t$95$1), $MachinePrecision] + N[(t$95$0 * t$95$2), $MachinePrecision]), $MachinePrecision] + N[(N[(x1 * x1), $MachinePrecision] * x1), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision] + N[(3.0 * N[(N[(N[(t$95$0 - N[(2.0 * x2), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision] / t$95$1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$3, Infinity], t$95$3, N[(N[(N[(N[(N[(6.0 * x1), $MachinePrecision] - 3.0), $MachinePrecision] * x1 + N[(N[(N[(2.0 * x2), $MachinePrecision] - 3.0), $MachinePrecision] * 4.0 + 9.0), $MachinePrecision]), $MachinePrecision] * x1), $MachinePrecision] * x1), $MachinePrecision]]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \left(3 \cdot x1\right) \cdot x1\\
t_1 := x1 \cdot x1 + 1\\
t_2 := \frac{\left(t\_0 + 2 \cdot x2\right) - x1}{t\_1}\\
t_3 := x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot t\_2\right) \cdot \left(t\_2 - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot t\_2 - 6\right)\right) \cdot t\_1 + t\_0 \cdot t\_2\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(t\_0 - 2 \cdot x2\right) - x1}{t\_1}\right)\\
\mathbf{if}\;t\_3 \leq \infty:\\
\;\;\;\;t\_3\\

\mathbf{else}:\\
\;\;\;\;\left(\mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)\right) \cdot x1\right) \cdot x1\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (+.f64 x1 (+.f64 (+.f64 (+.f64 (+.f64 (*.f64 (+.f64 (*.f64 (*.f64 (*.f64 #s(literal 2 binary64) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) (-.f64 (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) #s(literal 3 binary64))) (*.f64 (*.f64 x1 x1) (-.f64 (*.f64 #s(literal 4 binary64) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) #s(literal 6 binary64)))) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) (*.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))))) (*.f64 (*.f64 x1 x1) x1)) x1) (*.f64 #s(literal 3 binary64) (/.f64 (-.f64 (-.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))))) < +inf.0

    1. Initial program 99.6%

      \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
    2. Add Preprocessing

    if +inf.0 < (+.f64 x1 (+.f64 (+.f64 (+.f64 (+.f64 (*.f64 (+.f64 (*.f64 (*.f64 (*.f64 #s(literal 2 binary64) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) (-.f64 (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) #s(literal 3 binary64))) (*.f64 (*.f64 x1 x1) (-.f64 (*.f64 #s(literal 4 binary64) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) #s(literal 6 binary64)))) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) (*.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))))) (*.f64 (*.f64 x1 x1) x1)) x1) (*.f64 #s(literal 3 binary64) (/.f64 (-.f64 (-.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))))))

    1. Initial program 0.0%

      \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
    2. Add Preprocessing
    3. Taylor expanded in x1 around inf

      \[\leadsto \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
    4. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
      2. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
    5. Applied rewrites100.0%

      \[\leadsto \color{blue}{\left(\frac{\mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)}{x1 \cdot x1} + \left(6 - \frac{3}{x1}\right)\right) \cdot {x1}^{4}} \]
    6. Taylor expanded in x2 around inf

      \[\leadsto 8 \cdot \color{blue}{\left({x1}^{2} \cdot x2\right)} \]
    7. Step-by-step derivation
      1. Applied rewrites40.8%

        \[\leadsto \left(\left(x1 \cdot x1\right) \cdot x2\right) \cdot \color{blue}{8} \]
      2. Step-by-step derivation
        1. Applied rewrites31.4%

          \[\leadsto \left(\left(x2 \cdot x1\right) \cdot x1\right) \cdot 8 \]
        2. Taylor expanded in x1 around 0

          \[\leadsto {x1}^{2} \cdot \color{blue}{\left(9 + \left(4 \cdot \left(2 \cdot x2 - 3\right) + x1 \cdot \left(6 \cdot x1 - 3\right)\right)\right)} \]
        3. Step-by-step derivation
          1. Applied rewrites100.0%

            \[\leadsto \left(\mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)\right) \cdot x1\right) \cdot \color{blue}{x1} \]
        4. Recombined 2 regimes into one program.
        5. Add Preprocessing

        Alternative 2: 99.7% accurate, 0.6× speedup?

        \[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(3 \cdot x1\right) \cdot x1\\ t_1 := x1 \cdot x1 + 1\\ t_2 := \frac{\left(t\_0 + 2 \cdot x2\right) - x1}{t\_1}\\ t_3 := \mathsf{fma}\left(x1 \cdot x1, 3, 2 \cdot x2 - x1\right)\\ t_4 := \frac{t\_3}{\mathsf{fma}\left(x1, x1, 1\right)}\\ \mathbf{if}\;x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot t\_2\right) \cdot \left(t\_2 - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot t\_2 - 6\right)\right) \cdot t\_1 + t\_0 \cdot t\_2\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(t\_0 - 2 \cdot x2\right) - x1}{t\_1}\right) \leq \infty:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1 + \mathsf{fma}\left(\left(2 \cdot x1\right) \cdot t\_4, t\_4 - 3, \left(x1 \cdot x1\right) \cdot \left(t\_3 \cdot \frac{4}{\mathsf{fma}\left(x1, x1, 1\right)} - 6\right)\right), \left(3 \cdot x1\right) \cdot \left(3 \cdot x1\right)\right) + \mathsf{fma}\left(\mathsf{fma}\left(-2, x2, -x1\right), 3, x1\right)\\ \mathbf{else}:\\ \;\;\;\;\left(\mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)\right) \cdot x1\right) \cdot x1\\ \end{array} \end{array} \]
        (FPCore (x1 x2)
         :precision binary64
         (let* ((t_0 (* (* 3.0 x1) x1))
                (t_1 (+ (* x1 x1) 1.0))
                (t_2 (/ (- (+ t_0 (* 2.0 x2)) x1) t_1))
                (t_3 (fma (* x1 x1) 3.0 (- (* 2.0 x2) x1)))
                (t_4 (/ t_3 (fma x1 x1 1.0))))
           (if (<=
                (+
                 x1
                 (+
                  (+
                   (+
                    (+
                     (*
                      (+
                       (* (* (* 2.0 x1) t_2) (- t_2 3.0))
                       (* (* x1 x1) (- (* 4.0 t_2) 6.0)))
                      t_1)
                     (* t_0 t_2))
                    (* (* x1 x1) x1))
                   x1)
                  (* 3.0 (/ (- (- t_0 (* 2.0 x2)) x1) t_1))))
                INFINITY)
             (+
              (fma
               (fma x1 x1 1.0)
               (+
                x1
                (fma
                 (* (* 2.0 x1) t_4)
                 (- t_4 3.0)
                 (* (* x1 x1) (- (* t_3 (/ 4.0 (fma x1 x1 1.0))) 6.0))))
               (* (* 3.0 x1) (* 3.0 x1)))
              (fma (fma -2.0 x2 (- x1)) 3.0 x1))
             (*
              (* (fma (- (* 6.0 x1) 3.0) x1 (fma (- (* 2.0 x2) 3.0) 4.0 9.0)) x1)
              x1))))
        double code(double x1, double x2) {
        	double t_0 = (3.0 * x1) * x1;
        	double t_1 = (x1 * x1) + 1.0;
        	double t_2 = ((t_0 + (2.0 * x2)) - x1) / t_1;
        	double t_3 = fma((x1 * x1), 3.0, ((2.0 * x2) - x1));
        	double t_4 = t_3 / fma(x1, x1, 1.0);
        	double tmp;
        	if ((x1 + (((((((((2.0 * x1) * t_2) * (t_2 - 3.0)) + ((x1 * x1) * ((4.0 * t_2) - 6.0))) * t_1) + (t_0 * t_2)) + ((x1 * x1) * x1)) + x1) + (3.0 * (((t_0 - (2.0 * x2)) - x1) / t_1)))) <= ((double) INFINITY)) {
        		tmp = fma(fma(x1, x1, 1.0), (x1 + fma(((2.0 * x1) * t_4), (t_4 - 3.0), ((x1 * x1) * ((t_3 * (4.0 / fma(x1, x1, 1.0))) - 6.0)))), ((3.0 * x1) * (3.0 * x1))) + fma(fma(-2.0, x2, -x1), 3.0, x1);
        	} else {
        		tmp = (fma(((6.0 * x1) - 3.0), x1, fma(((2.0 * x2) - 3.0), 4.0, 9.0)) * x1) * x1;
        	}
        	return tmp;
        }
        
        function code(x1, x2)
        	t_0 = Float64(Float64(3.0 * x1) * x1)
        	t_1 = Float64(Float64(x1 * x1) + 1.0)
        	t_2 = Float64(Float64(Float64(t_0 + Float64(2.0 * x2)) - x1) / t_1)
        	t_3 = fma(Float64(x1 * x1), 3.0, Float64(Float64(2.0 * x2) - x1))
        	t_4 = Float64(t_3 / fma(x1, x1, 1.0))
        	tmp = 0.0
        	if (Float64(x1 + Float64(Float64(Float64(Float64(Float64(Float64(Float64(Float64(Float64(2.0 * x1) * t_2) * Float64(t_2 - 3.0)) + Float64(Float64(x1 * x1) * Float64(Float64(4.0 * t_2) - 6.0))) * t_1) + Float64(t_0 * t_2)) + Float64(Float64(x1 * x1) * x1)) + x1) + Float64(3.0 * Float64(Float64(Float64(t_0 - Float64(2.0 * x2)) - x1) / t_1)))) <= Inf)
        		tmp = Float64(fma(fma(x1, x1, 1.0), Float64(x1 + fma(Float64(Float64(2.0 * x1) * t_4), Float64(t_4 - 3.0), Float64(Float64(x1 * x1) * Float64(Float64(t_3 * Float64(4.0 / fma(x1, x1, 1.0))) - 6.0)))), Float64(Float64(3.0 * x1) * Float64(3.0 * x1))) + fma(fma(-2.0, x2, Float64(-x1)), 3.0, x1));
        	else
        		tmp = Float64(Float64(fma(Float64(Float64(6.0 * x1) - 3.0), x1, fma(Float64(Float64(2.0 * x2) - 3.0), 4.0, 9.0)) * x1) * x1);
        	end
        	return tmp
        end
        
        code[x1_, x2_] := Block[{t$95$0 = N[(N[(3.0 * x1), $MachinePrecision] * x1), $MachinePrecision]}, Block[{t$95$1 = N[(N[(x1 * x1), $MachinePrecision] + 1.0), $MachinePrecision]}, Block[{t$95$2 = N[(N[(N[(t$95$0 + N[(2.0 * x2), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision] / t$95$1), $MachinePrecision]}, Block[{t$95$3 = N[(N[(x1 * x1), $MachinePrecision] * 3.0 + N[(N[(2.0 * x2), $MachinePrecision] - x1), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$4 = N[(t$95$3 / N[(x1 * x1 + 1.0), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[(x1 + N[(N[(N[(N[(N[(N[(N[(N[(N[(2.0 * x1), $MachinePrecision] * t$95$2), $MachinePrecision] * N[(t$95$2 - 3.0), $MachinePrecision]), $MachinePrecision] + N[(N[(x1 * x1), $MachinePrecision] * N[(N[(4.0 * t$95$2), $MachinePrecision] - 6.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * t$95$1), $MachinePrecision] + N[(t$95$0 * t$95$2), $MachinePrecision]), $MachinePrecision] + N[(N[(x1 * x1), $MachinePrecision] * x1), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision] + N[(3.0 * N[(N[(N[(t$95$0 - N[(2.0 * x2), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision] / t$95$1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], Infinity], N[(N[(N[(x1 * x1 + 1.0), $MachinePrecision] * N[(x1 + N[(N[(N[(2.0 * x1), $MachinePrecision] * t$95$4), $MachinePrecision] * N[(t$95$4 - 3.0), $MachinePrecision] + N[(N[(x1 * x1), $MachinePrecision] * N[(N[(t$95$3 * N[(4.0 / N[(x1 * x1 + 1.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - 6.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(N[(3.0 * x1), $MachinePrecision] * N[(3.0 * x1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(N[(-2.0 * x2 + (-x1)), $MachinePrecision] * 3.0 + x1), $MachinePrecision]), $MachinePrecision], N[(N[(N[(N[(N[(6.0 * x1), $MachinePrecision] - 3.0), $MachinePrecision] * x1 + N[(N[(N[(2.0 * x2), $MachinePrecision] - 3.0), $MachinePrecision] * 4.0 + 9.0), $MachinePrecision]), $MachinePrecision] * x1), $MachinePrecision] * x1), $MachinePrecision]]]]]]]
        
        \begin{array}{l}
        
        \\
        \begin{array}{l}
        t_0 := \left(3 \cdot x1\right) \cdot x1\\
        t_1 := x1 \cdot x1 + 1\\
        t_2 := \frac{\left(t\_0 + 2 \cdot x2\right) - x1}{t\_1}\\
        t_3 := \mathsf{fma}\left(x1 \cdot x1, 3, 2 \cdot x2 - x1\right)\\
        t_4 := \frac{t\_3}{\mathsf{fma}\left(x1, x1, 1\right)}\\
        \mathbf{if}\;x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot t\_2\right) \cdot \left(t\_2 - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot t\_2 - 6\right)\right) \cdot t\_1 + t\_0 \cdot t\_2\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(t\_0 - 2 \cdot x2\right) - x1}{t\_1}\right) \leq \infty:\\
        \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1 + \mathsf{fma}\left(\left(2 \cdot x1\right) \cdot t\_4, t\_4 - 3, \left(x1 \cdot x1\right) \cdot \left(t\_3 \cdot \frac{4}{\mathsf{fma}\left(x1, x1, 1\right)} - 6\right)\right), \left(3 \cdot x1\right) \cdot \left(3 \cdot x1\right)\right) + \mathsf{fma}\left(\mathsf{fma}\left(-2, x2, -x1\right), 3, x1\right)\\
        
        \mathbf{else}:\\
        \;\;\;\;\left(\mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)\right) \cdot x1\right) \cdot x1\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 2 regimes
        2. if (+.f64 x1 (+.f64 (+.f64 (+.f64 (+.f64 (*.f64 (+.f64 (*.f64 (*.f64 (*.f64 #s(literal 2 binary64) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) (-.f64 (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) #s(literal 3 binary64))) (*.f64 (*.f64 x1 x1) (-.f64 (*.f64 #s(literal 4 binary64) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) #s(literal 6 binary64)))) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) (*.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))))) (*.f64 (*.f64 x1 x1) x1)) x1) (*.f64 #s(literal 3 binary64) (/.f64 (-.f64 (-.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))))) < +inf.0

          1. Initial program 99.6%

            \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
          2. Add Preprocessing
          3. Taylor expanded in x1 around inf

            \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{3}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
          4. Step-by-step derivation
            1. Applied rewrites98.8%

              \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{3}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
            2. Taylor expanded in x1 around 0

              \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\left(-2 \cdot x2 + -1 \cdot x1\right)}\right) \]
            3. Step-by-step derivation
              1. mul-1-negN/A

                \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \left(-2 \cdot x2 + \color{blue}{\left(\mathsf{neg}\left(x1\right)\right)}\right)\right) \]
              2. lower-fma.f64N/A

                \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\mathsf{fma}\left(-2, x2, \mathsf{neg}\left(x1\right)\right)}\right) \]
              3. lower-neg.f6499.0

                \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, \color{blue}{-x1}\right)\right) \]
            4. Applied rewrites99.0%

              \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\mathsf{fma}\left(-2, x2, -x1\right)}\right) \]
            5. Applied rewrites90.0%

              \[\leadsto x1 + \left(\color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(\left(\frac{\mathsf{fma}\left(x2, 2, \left(3 \cdot x1\right) \cdot x1\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)} - 3\right) \cdot \frac{\mathsf{fma}\left(x2, 2, \left(3 \cdot x1\right) \cdot x1\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)}, x1 \cdot 2, \left(\frac{4 \cdot \left(\mathsf{fma}\left(x2, 2, \left(3 \cdot x1\right) \cdot x1\right) - x1\right)}{\mathsf{fma}\left(x1, x1, 1\right)} - 6\right) \cdot \left(x1 \cdot x1\right)\right), \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right)} + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
            6. Applied rewrites99.2%

              \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1 + \mathsf{fma}\left(\left(2 \cdot x1\right) \cdot \frac{\mathsf{fma}\left(x1 \cdot x1, 3, 2 \cdot x2 - x1\right)}{\mathsf{fma}\left(x1, x1, 1\right)}, \frac{\mathsf{fma}\left(x1 \cdot x1, 3, 2 \cdot x2 - x1\right)}{\mathsf{fma}\left(x1, x1, 1\right)} - 3, \left(x1 \cdot x1\right) \cdot \left(\mathsf{fma}\left(x1 \cdot x1, 3, 2 \cdot x2 - x1\right) \cdot \frac{4}{\mathsf{fma}\left(x1, x1, 1\right)} - 6\right)\right), \left(3 \cdot x1\right) \cdot \left(3 \cdot x1\right)\right) + \mathsf{fma}\left(\mathsf{fma}\left(-2, x2, -x1\right), 3, x1\right)} \]

            if +inf.0 < (+.f64 x1 (+.f64 (+.f64 (+.f64 (+.f64 (*.f64 (+.f64 (*.f64 (*.f64 (*.f64 #s(literal 2 binary64) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) (-.f64 (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) #s(literal 3 binary64))) (*.f64 (*.f64 x1 x1) (-.f64 (*.f64 #s(literal 4 binary64) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) #s(literal 6 binary64)))) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) (*.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))))) (*.f64 (*.f64 x1 x1) x1)) x1) (*.f64 #s(literal 3 binary64) (/.f64 (-.f64 (-.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))))))

            1. Initial program 0.0%

              \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
            2. Add Preprocessing
            3. Taylor expanded in x1 around inf

              \[\leadsto \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
            4. Step-by-step derivation
              1. *-commutativeN/A

                \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
              2. lower-*.f64N/A

                \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
            5. Applied rewrites100.0%

              \[\leadsto \color{blue}{\left(\frac{\mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)}{x1 \cdot x1} + \left(6 - \frac{3}{x1}\right)\right) \cdot {x1}^{4}} \]
            6. Taylor expanded in x2 around inf

              \[\leadsto 8 \cdot \color{blue}{\left({x1}^{2} \cdot x2\right)} \]
            7. Step-by-step derivation
              1. Applied rewrites40.8%

                \[\leadsto \left(\left(x1 \cdot x1\right) \cdot x2\right) \cdot \color{blue}{8} \]
              2. Step-by-step derivation
                1. Applied rewrites31.4%

                  \[\leadsto \left(\left(x2 \cdot x1\right) \cdot x1\right) \cdot 8 \]
                2. Taylor expanded in x1 around 0

                  \[\leadsto {x1}^{2} \cdot \color{blue}{\left(9 + \left(4 \cdot \left(2 \cdot x2 - 3\right) + x1 \cdot \left(6 \cdot x1 - 3\right)\right)\right)} \]
                3. Step-by-step derivation
                  1. Applied rewrites100.0%

                    \[\leadsto \left(\mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)\right) \cdot x1\right) \cdot \color{blue}{x1} \]
                4. Recombined 2 regimes into one program.
                5. Add Preprocessing

                Alternative 3: 41.9% accurate, 0.9× speedup?

                \[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(3 \cdot x1\right) \cdot x1\\ t_1 := x1 \cdot x1 + 1\\ t_2 := \frac{\left(t\_0 + 2 \cdot x2\right) - x1}{t\_1}\\ \mathbf{if}\;x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot t\_2\right) \cdot \left(t\_2 - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot t\_2 - 6\right)\right) \cdot t\_1 + t\_0 \cdot t\_2\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(t\_0 - 2 \cdot x2\right) - x1}{t\_1}\right) \leq 10^{+305}:\\ \;\;\;\;-6 \cdot x2\\ \mathbf{else}:\\ \;\;\;\;\left(\left(x1 \cdot x1\right) \cdot x2\right) \cdot 8\\ \end{array} \end{array} \]
                (FPCore (x1 x2)
                 :precision binary64
                 (let* ((t_0 (* (* 3.0 x1) x1))
                        (t_1 (+ (* x1 x1) 1.0))
                        (t_2 (/ (- (+ t_0 (* 2.0 x2)) x1) t_1)))
                   (if (<=
                        (+
                         x1
                         (+
                          (+
                           (+
                            (+
                             (*
                              (+
                               (* (* (* 2.0 x1) t_2) (- t_2 3.0))
                               (* (* x1 x1) (- (* 4.0 t_2) 6.0)))
                              t_1)
                             (* t_0 t_2))
                            (* (* x1 x1) x1))
                           x1)
                          (* 3.0 (/ (- (- t_0 (* 2.0 x2)) x1) t_1))))
                        1e+305)
                     (* -6.0 x2)
                     (* (* (* x1 x1) x2) 8.0))))
                double code(double x1, double x2) {
                	double t_0 = (3.0 * x1) * x1;
                	double t_1 = (x1 * x1) + 1.0;
                	double t_2 = ((t_0 + (2.0 * x2)) - x1) / t_1;
                	double tmp;
                	if ((x1 + (((((((((2.0 * x1) * t_2) * (t_2 - 3.0)) + ((x1 * x1) * ((4.0 * t_2) - 6.0))) * t_1) + (t_0 * t_2)) + ((x1 * x1) * x1)) + x1) + (3.0 * (((t_0 - (2.0 * x2)) - x1) / t_1)))) <= 1e+305) {
                		tmp = -6.0 * x2;
                	} else {
                		tmp = ((x1 * x1) * x2) * 8.0;
                	}
                	return tmp;
                }
                
                real(8) function code(x1, x2)
                    real(8), intent (in) :: x1
                    real(8), intent (in) :: x2
                    real(8) :: t_0
                    real(8) :: t_1
                    real(8) :: t_2
                    real(8) :: tmp
                    t_0 = (3.0d0 * x1) * x1
                    t_1 = (x1 * x1) + 1.0d0
                    t_2 = ((t_0 + (2.0d0 * x2)) - x1) / t_1
                    if ((x1 + (((((((((2.0d0 * x1) * t_2) * (t_2 - 3.0d0)) + ((x1 * x1) * ((4.0d0 * t_2) - 6.0d0))) * t_1) + (t_0 * t_2)) + ((x1 * x1) * x1)) + x1) + (3.0d0 * (((t_0 - (2.0d0 * x2)) - x1) / t_1)))) <= 1d+305) then
                        tmp = (-6.0d0) * x2
                    else
                        tmp = ((x1 * x1) * x2) * 8.0d0
                    end if
                    code = tmp
                end function
                
                public static double code(double x1, double x2) {
                	double t_0 = (3.0 * x1) * x1;
                	double t_1 = (x1 * x1) + 1.0;
                	double t_2 = ((t_0 + (2.0 * x2)) - x1) / t_1;
                	double tmp;
                	if ((x1 + (((((((((2.0 * x1) * t_2) * (t_2 - 3.0)) + ((x1 * x1) * ((4.0 * t_2) - 6.0))) * t_1) + (t_0 * t_2)) + ((x1 * x1) * x1)) + x1) + (3.0 * (((t_0 - (2.0 * x2)) - x1) / t_1)))) <= 1e+305) {
                		tmp = -6.0 * x2;
                	} else {
                		tmp = ((x1 * x1) * x2) * 8.0;
                	}
                	return tmp;
                }
                
                def code(x1, x2):
                	t_0 = (3.0 * x1) * x1
                	t_1 = (x1 * x1) + 1.0
                	t_2 = ((t_0 + (2.0 * x2)) - x1) / t_1
                	tmp = 0
                	if (x1 + (((((((((2.0 * x1) * t_2) * (t_2 - 3.0)) + ((x1 * x1) * ((4.0 * t_2) - 6.0))) * t_1) + (t_0 * t_2)) + ((x1 * x1) * x1)) + x1) + (3.0 * (((t_0 - (2.0 * x2)) - x1) / t_1)))) <= 1e+305:
                		tmp = -6.0 * x2
                	else:
                		tmp = ((x1 * x1) * x2) * 8.0
                	return tmp
                
                function code(x1, x2)
                	t_0 = Float64(Float64(3.0 * x1) * x1)
                	t_1 = Float64(Float64(x1 * x1) + 1.0)
                	t_2 = Float64(Float64(Float64(t_0 + Float64(2.0 * x2)) - x1) / t_1)
                	tmp = 0.0
                	if (Float64(x1 + Float64(Float64(Float64(Float64(Float64(Float64(Float64(Float64(Float64(2.0 * x1) * t_2) * Float64(t_2 - 3.0)) + Float64(Float64(x1 * x1) * Float64(Float64(4.0 * t_2) - 6.0))) * t_1) + Float64(t_0 * t_2)) + Float64(Float64(x1 * x1) * x1)) + x1) + Float64(3.0 * Float64(Float64(Float64(t_0 - Float64(2.0 * x2)) - x1) / t_1)))) <= 1e+305)
                		tmp = Float64(-6.0 * x2);
                	else
                		tmp = Float64(Float64(Float64(x1 * x1) * x2) * 8.0);
                	end
                	return tmp
                end
                
                function tmp_2 = code(x1, x2)
                	t_0 = (3.0 * x1) * x1;
                	t_1 = (x1 * x1) + 1.0;
                	t_2 = ((t_0 + (2.0 * x2)) - x1) / t_1;
                	tmp = 0.0;
                	if ((x1 + (((((((((2.0 * x1) * t_2) * (t_2 - 3.0)) + ((x1 * x1) * ((4.0 * t_2) - 6.0))) * t_1) + (t_0 * t_2)) + ((x1 * x1) * x1)) + x1) + (3.0 * (((t_0 - (2.0 * x2)) - x1) / t_1)))) <= 1e+305)
                		tmp = -6.0 * x2;
                	else
                		tmp = ((x1 * x1) * x2) * 8.0;
                	end
                	tmp_2 = tmp;
                end
                
                code[x1_, x2_] := Block[{t$95$0 = N[(N[(3.0 * x1), $MachinePrecision] * x1), $MachinePrecision]}, Block[{t$95$1 = N[(N[(x1 * x1), $MachinePrecision] + 1.0), $MachinePrecision]}, Block[{t$95$2 = N[(N[(N[(t$95$0 + N[(2.0 * x2), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision] / t$95$1), $MachinePrecision]}, If[LessEqual[N[(x1 + N[(N[(N[(N[(N[(N[(N[(N[(N[(2.0 * x1), $MachinePrecision] * t$95$2), $MachinePrecision] * N[(t$95$2 - 3.0), $MachinePrecision]), $MachinePrecision] + N[(N[(x1 * x1), $MachinePrecision] * N[(N[(4.0 * t$95$2), $MachinePrecision] - 6.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * t$95$1), $MachinePrecision] + N[(t$95$0 * t$95$2), $MachinePrecision]), $MachinePrecision] + N[(N[(x1 * x1), $MachinePrecision] * x1), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision] + N[(3.0 * N[(N[(N[(t$95$0 - N[(2.0 * x2), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision] / t$95$1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 1e+305], N[(-6.0 * x2), $MachinePrecision], N[(N[(N[(x1 * x1), $MachinePrecision] * x2), $MachinePrecision] * 8.0), $MachinePrecision]]]]]
                
                \begin{array}{l}
                
                \\
                \begin{array}{l}
                t_0 := \left(3 \cdot x1\right) \cdot x1\\
                t_1 := x1 \cdot x1 + 1\\
                t_2 := \frac{\left(t\_0 + 2 \cdot x2\right) - x1}{t\_1}\\
                \mathbf{if}\;x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot t\_2\right) \cdot \left(t\_2 - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot t\_2 - 6\right)\right) \cdot t\_1 + t\_0 \cdot t\_2\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(t\_0 - 2 \cdot x2\right) - x1}{t\_1}\right) \leq 10^{+305}:\\
                \;\;\;\;-6 \cdot x2\\
                
                \mathbf{else}:\\
                \;\;\;\;\left(\left(x1 \cdot x1\right) \cdot x2\right) \cdot 8\\
                
                
                \end{array}
                \end{array}
                
                Derivation
                1. Split input into 2 regimes
                2. if (+.f64 x1 (+.f64 (+.f64 (+.f64 (+.f64 (*.f64 (+.f64 (*.f64 (*.f64 (*.f64 #s(literal 2 binary64) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) (-.f64 (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) #s(literal 3 binary64))) (*.f64 (*.f64 x1 x1) (-.f64 (*.f64 #s(literal 4 binary64) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) #s(literal 6 binary64)))) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) (*.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))))) (*.f64 (*.f64 x1 x1) x1)) x1) (*.f64 #s(literal 3 binary64) (/.f64 (-.f64 (-.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))))) < 9.9999999999999994e304

                  1. Initial program 99.5%

                    \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                  2. Add Preprocessing
                  3. Taylor expanded in x1 around 0

                    \[\leadsto \color{blue}{-6 \cdot x2} \]
                  4. Step-by-step derivation
                    1. lower-*.f6448.7

                      \[\leadsto \color{blue}{-6 \cdot x2} \]
                  5. Applied rewrites48.7%

                    \[\leadsto \color{blue}{-6 \cdot x2} \]

                  if 9.9999999999999994e304 < (+.f64 x1 (+.f64 (+.f64 (+.f64 (+.f64 (*.f64 (+.f64 (*.f64 (*.f64 (*.f64 #s(literal 2 binary64) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) (-.f64 (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) #s(literal 3 binary64))) (*.f64 (*.f64 x1 x1) (-.f64 (*.f64 #s(literal 4 binary64) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64)))) #s(literal 6 binary64)))) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))) (*.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (/.f64 (-.f64 (+.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))))) (*.f64 (*.f64 x1 x1) x1)) x1) (*.f64 #s(literal 3 binary64) (/.f64 (-.f64 (-.f64 (*.f64 (*.f64 #s(literal 3 binary64) x1) x1) (*.f64 #s(literal 2 binary64) x2)) x1) (+.f64 (*.f64 x1 x1) #s(literal 1 binary64))))))

                  1. Initial program 30.1%

                    \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                  2. Add Preprocessing
                  3. Taylor expanded in x1 around inf

                    \[\leadsto \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                  4. Step-by-step derivation
                    1. *-commutativeN/A

                      \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                    2. lower-*.f64N/A

                      \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                  5. Applied rewrites94.7%

                    \[\leadsto \color{blue}{\left(\frac{\mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)}{x1 \cdot x1} + \left(6 - \frac{3}{x1}\right)\right) \cdot {x1}^{4}} \]
                  6. Taylor expanded in x2 around inf

                    \[\leadsto 8 \cdot \color{blue}{\left({x1}^{2} \cdot x2\right)} \]
                  7. Step-by-step derivation
                    1. Applied rewrites35.1%

                      \[\leadsto \left(\left(x1 \cdot x1\right) \cdot x2\right) \cdot \color{blue}{8} \]
                  8. Recombined 2 regimes into one program.
                  9. Add Preprocessing

                  Alternative 4: 95.9% accurate, 1.5× speedup?

                  \[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(3 \cdot x1\right) \cdot x1\\ t_1 := x1 \cdot x1 + 1\\ t_2 := \frac{\left(t\_0 + 2 \cdot x2\right) - x1}{t\_1}\\ t_3 := 2 \cdot x2 - 3\\ t_4 := \mathsf{fma}\left(t\_3, 4, 9\right)\\ \mathbf{if}\;x1 \leq -9.5 \cdot 10^{+66}:\\ \;\;\;\;\mathsf{fma}\left(6 \cdot x1 - 3, x1, t\_4\right) \cdot \left(x1 \cdot x1\right)\\ \mathbf{elif}\;x1 \leq 8200:\\ \;\;\;\;x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot t\_2\right) \cdot t\_3 + \left(x1 \cdot x1\right) \cdot \left(4 \cdot t\_2 - 6\right)\right) \cdot t\_1 + t\_0 \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right)\\ \mathbf{else}:\\ \;\;\;\;\left(6 - \frac{3 - \frac{\mathsf{fma}\left(\frac{-1 + t\_3 \cdot -6}{x1}, -1, t\_4\right)}{x1}}{x1}\right) \cdot {x1}^{4}\\ \end{array} \end{array} \]
                  (FPCore (x1 x2)
                   :precision binary64
                   (let* ((t_0 (* (* 3.0 x1) x1))
                          (t_1 (+ (* x1 x1) 1.0))
                          (t_2 (/ (- (+ t_0 (* 2.0 x2)) x1) t_1))
                          (t_3 (- (* 2.0 x2) 3.0))
                          (t_4 (fma t_3 4.0 9.0)))
                     (if (<= x1 -9.5e+66)
                       (* (fma (- (* 6.0 x1) 3.0) x1 t_4) (* x1 x1))
                       (if (<= x1 8200.0)
                         (+
                          x1
                          (+
                           (+
                            (+
                             (+
                              (*
                               (+ (* (* (* 2.0 x1) t_2) t_3) (* (* x1 x1) (- (* 4.0 t_2) 6.0)))
                               t_1)
                              (* t_0 3.0))
                             (* (* x1 x1) x1))
                            x1)
                           (* 3.0 (fma -2.0 x2 (- x1)))))
                         (*
                          (-
                           6.0
                           (/ (- 3.0 (/ (fma (/ (+ -1.0 (* t_3 -6.0)) x1) -1.0 t_4) x1)) x1))
                          (pow x1 4.0))))))
                  double code(double x1, double x2) {
                  	double t_0 = (3.0 * x1) * x1;
                  	double t_1 = (x1 * x1) + 1.0;
                  	double t_2 = ((t_0 + (2.0 * x2)) - x1) / t_1;
                  	double t_3 = (2.0 * x2) - 3.0;
                  	double t_4 = fma(t_3, 4.0, 9.0);
                  	double tmp;
                  	if (x1 <= -9.5e+66) {
                  		tmp = fma(((6.0 * x1) - 3.0), x1, t_4) * (x1 * x1);
                  	} else if (x1 <= 8200.0) {
                  		tmp = x1 + (((((((((2.0 * x1) * t_2) * t_3) + ((x1 * x1) * ((4.0 * t_2) - 6.0))) * t_1) + (t_0 * 3.0)) + ((x1 * x1) * x1)) + x1) + (3.0 * fma(-2.0, x2, -x1)));
                  	} else {
                  		tmp = (6.0 - ((3.0 - (fma(((-1.0 + (t_3 * -6.0)) / x1), -1.0, t_4) / x1)) / x1)) * pow(x1, 4.0);
                  	}
                  	return tmp;
                  }
                  
                  function code(x1, x2)
                  	t_0 = Float64(Float64(3.0 * x1) * x1)
                  	t_1 = Float64(Float64(x1 * x1) + 1.0)
                  	t_2 = Float64(Float64(Float64(t_0 + Float64(2.0 * x2)) - x1) / t_1)
                  	t_3 = Float64(Float64(2.0 * x2) - 3.0)
                  	t_4 = fma(t_3, 4.0, 9.0)
                  	tmp = 0.0
                  	if (x1 <= -9.5e+66)
                  		tmp = Float64(fma(Float64(Float64(6.0 * x1) - 3.0), x1, t_4) * Float64(x1 * x1));
                  	elseif (x1 <= 8200.0)
                  		tmp = Float64(x1 + Float64(Float64(Float64(Float64(Float64(Float64(Float64(Float64(Float64(2.0 * x1) * t_2) * t_3) + Float64(Float64(x1 * x1) * Float64(Float64(4.0 * t_2) - 6.0))) * t_1) + Float64(t_0 * 3.0)) + Float64(Float64(x1 * x1) * x1)) + x1) + Float64(3.0 * fma(-2.0, x2, Float64(-x1)))));
                  	else
                  		tmp = Float64(Float64(6.0 - Float64(Float64(3.0 - Float64(fma(Float64(Float64(-1.0 + Float64(t_3 * -6.0)) / x1), -1.0, t_4) / x1)) / x1)) * (x1 ^ 4.0));
                  	end
                  	return tmp
                  end
                  
                  code[x1_, x2_] := Block[{t$95$0 = N[(N[(3.0 * x1), $MachinePrecision] * x1), $MachinePrecision]}, Block[{t$95$1 = N[(N[(x1 * x1), $MachinePrecision] + 1.0), $MachinePrecision]}, Block[{t$95$2 = N[(N[(N[(t$95$0 + N[(2.0 * x2), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision] / t$95$1), $MachinePrecision]}, Block[{t$95$3 = N[(N[(2.0 * x2), $MachinePrecision] - 3.0), $MachinePrecision]}, Block[{t$95$4 = N[(t$95$3 * 4.0 + 9.0), $MachinePrecision]}, If[LessEqual[x1, -9.5e+66], N[(N[(N[(N[(6.0 * x1), $MachinePrecision] - 3.0), $MachinePrecision] * x1 + t$95$4), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision], If[LessEqual[x1, 8200.0], N[(x1 + N[(N[(N[(N[(N[(N[(N[(N[(N[(2.0 * x1), $MachinePrecision] * t$95$2), $MachinePrecision] * t$95$3), $MachinePrecision] + N[(N[(x1 * x1), $MachinePrecision] * N[(N[(4.0 * t$95$2), $MachinePrecision] - 6.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * t$95$1), $MachinePrecision] + N[(t$95$0 * 3.0), $MachinePrecision]), $MachinePrecision] + N[(N[(x1 * x1), $MachinePrecision] * x1), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision] + N[(3.0 * N[(-2.0 * x2 + (-x1)), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(6.0 - N[(N[(3.0 - N[(N[(N[(N[(-1.0 + N[(t$95$3 * -6.0), $MachinePrecision]), $MachinePrecision] / x1), $MachinePrecision] * -1.0 + t$95$4), $MachinePrecision] / x1), $MachinePrecision]), $MachinePrecision] / x1), $MachinePrecision]), $MachinePrecision] * N[Power[x1, 4.0], $MachinePrecision]), $MachinePrecision]]]]]]]]
                  
                  \begin{array}{l}
                  
                  \\
                  \begin{array}{l}
                  t_0 := \left(3 \cdot x1\right) \cdot x1\\
                  t_1 := x1 \cdot x1 + 1\\
                  t_2 := \frac{\left(t\_0 + 2 \cdot x2\right) - x1}{t\_1}\\
                  t_3 := 2 \cdot x2 - 3\\
                  t_4 := \mathsf{fma}\left(t\_3, 4, 9\right)\\
                  \mathbf{if}\;x1 \leq -9.5 \cdot 10^{+66}:\\
                  \;\;\;\;\mathsf{fma}\left(6 \cdot x1 - 3, x1, t\_4\right) \cdot \left(x1 \cdot x1\right)\\
                  
                  \mathbf{elif}\;x1 \leq 8200:\\
                  \;\;\;\;x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot t\_2\right) \cdot t\_3 + \left(x1 \cdot x1\right) \cdot \left(4 \cdot t\_2 - 6\right)\right) \cdot t\_1 + t\_0 \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right)\\
                  
                  \mathbf{else}:\\
                  \;\;\;\;\left(6 - \frac{3 - \frac{\mathsf{fma}\left(\frac{-1 + t\_3 \cdot -6}{x1}, -1, t\_4\right)}{x1}}{x1}\right) \cdot {x1}^{4}\\
                  
                  
                  \end{array}
                  \end{array}
                  
                  Derivation
                  1. Split input into 3 regimes
                  2. if x1 < -9.50000000000000051e66

                    1. Initial program 16.0%

                      \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                    2. Add Preprocessing
                    3. Taylor expanded in x1 around inf

                      \[\leadsto \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                    4. Step-by-step derivation
                      1. *-commutativeN/A

                        \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                      2. lower-*.f64N/A

                        \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                    5. Applied rewrites100.0%

                      \[\leadsto \color{blue}{\left(\frac{\mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)}{x1 \cdot x1} + \left(6 - \frac{3}{x1}\right)\right) \cdot {x1}^{4}} \]
                    6. Taylor expanded in x1 around 0

                      \[\leadsto {x1}^{2} \cdot \color{blue}{\left(9 + \left(4 \cdot \left(2 \cdot x2 - 3\right) + x1 \cdot \left(6 \cdot x1 - 3\right)\right)\right)} \]
                    7. Step-by-step derivation
                      1. Applied rewrites100.0%

                        \[\leadsto \mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)\right) \cdot \color{blue}{\left(x1 \cdot x1\right)} \]

                      if -9.50000000000000051e66 < x1 < 8200

                      1. Initial program 99.6%

                        \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                      2. Add Preprocessing
                      3. Taylor expanded in x1 around inf

                        \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{3}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                      4. Step-by-step derivation
                        1. Applied rewrites98.7%

                          \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{3}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                        2. Taylor expanded in x1 around 0

                          \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\left(-2 \cdot x2 + -1 \cdot x1\right)}\right) \]
                        3. Step-by-step derivation
                          1. mul-1-negN/A

                            \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \left(-2 \cdot x2 + \color{blue}{\left(\mathsf{neg}\left(x1\right)\right)}\right)\right) \]
                          2. lower-fma.f64N/A

                            \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\mathsf{fma}\left(-2, x2, \mathsf{neg}\left(x1\right)\right)}\right) \]
                          3. lower-neg.f6499.6

                            \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, \color{blue}{-x1}\right)\right) \]
                        4. Applied rewrites99.6%

                          \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\mathsf{fma}\left(-2, x2, -x1\right)}\right) \]
                        5. Taylor expanded in x1 around 0

                          \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \color{blue}{\left(2 \cdot x2 - 3\right)} + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                        6. Step-by-step derivation
                          1. lower--.f64N/A

                            \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \color{blue}{\left(2 \cdot x2 - 3\right)} + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                          2. lower-*.f6498.3

                            \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\color{blue}{2 \cdot x2} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                        7. Applied rewrites98.3%

                          \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \color{blue}{\left(2 \cdot x2 - 3\right)} + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]

                        if 8200 < x1

                        1. Initial program 52.7%

                          \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                        2. Add Preprocessing
                        3. Taylor expanded in x1 around -inf

                          \[\leadsto \color{blue}{{x1}^{4} \cdot \left(6 + -1 \cdot \frac{3 + -1 \cdot \frac{9 + \left(-1 \cdot \frac{1 + -2 \cdot \left(1 + 3 \cdot \left(2 \cdot x2 - 3\right)\right)}{x1} + 4 \cdot \left(2 \cdot x2 - 3\right)\right)}{x1}}{x1}\right)} \]
                        4. Step-by-step derivation
                          1. *-commutativeN/A

                            \[\leadsto \color{blue}{\left(6 + -1 \cdot \frac{3 + -1 \cdot \frac{9 + \left(-1 \cdot \frac{1 + -2 \cdot \left(1 + 3 \cdot \left(2 \cdot x2 - 3\right)\right)}{x1} + 4 \cdot \left(2 \cdot x2 - 3\right)\right)}{x1}}{x1}\right) \cdot {x1}^{4}} \]
                          2. lower-*.f64N/A

                            \[\leadsto \color{blue}{\left(6 + -1 \cdot \frac{3 + -1 \cdot \frac{9 + \left(-1 \cdot \frac{1 + -2 \cdot \left(1 + 3 \cdot \left(2 \cdot x2 - 3\right)\right)}{x1} + 4 \cdot \left(2 \cdot x2 - 3\right)\right)}{x1}}{x1}\right) \cdot {x1}^{4}} \]
                        5. Applied rewrites96.4%

                          \[\leadsto \color{blue}{\left(6 - \frac{3 - \frac{\mathsf{fma}\left(\frac{-1 + \left(2 \cdot x2 - 3\right) \cdot -6}{x1}, -1, \mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)\right)}{x1}}{x1}\right) \cdot {x1}^{4}} \]
                      5. Recombined 3 regimes into one program.
                      6. Add Preprocessing

                      Alternative 5: 90.6% accurate, 1.5× speedup?

                      \[\begin{array}{l} \\ \begin{array}{l} t_0 := 2 \cdot x2 - 3\\ t_1 := \mathsf{fma}\left(t\_0, 4, 9\right)\\ \mathbf{if}\;x1 \leq -42000000:\\ \;\;\;\;\mathsf{fma}\left(6 \cdot x1 - 3, x1, t\_1\right) \cdot \left(x1 \cdot x1\right)\\ \mathbf{elif}\;x1 \leq 8500:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \left(\left(x2 \cdot x2\right) \cdot 8\right) \cdot \frac{x1}{\mathsf{fma}\left(x1, x1, 1\right)}\right) + \mathsf{fma}\left(\frac{\mathsf{fma}\left(-2, x2, \left(3 \cdot x1\right) \cdot x1\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)}, 3, x1\right)\\ \mathbf{else}:\\ \;\;\;\;\left(6 - \frac{3 - \frac{\mathsf{fma}\left(\frac{-1 + t\_0 \cdot -6}{x1}, -1, t\_1\right)}{x1}}{x1}\right) \cdot {x1}^{4}\\ \end{array} \end{array} \]
                      (FPCore (x1 x2)
                       :precision binary64
                       (let* ((t_0 (- (* 2.0 x2) 3.0)) (t_1 (fma t_0 4.0 9.0)))
                         (if (<= x1 -42000000.0)
                           (* (fma (- (* 6.0 x1) 3.0) x1 t_1) (* x1 x1))
                           (if (<= x1 8500.0)
                             (+
                              (fma (fma x1 x1 1.0) x1 (* (* (* x2 x2) 8.0) (/ x1 (fma x1 x1 1.0))))
                              (fma
                               (/ (- (fma -2.0 x2 (* (* 3.0 x1) x1)) x1) (fma x1 x1 1.0))
                               3.0
                               x1))
                             (*
                              (-
                               6.0
                               (/ (- 3.0 (/ (fma (/ (+ -1.0 (* t_0 -6.0)) x1) -1.0 t_1) x1)) x1))
                              (pow x1 4.0))))))
                      double code(double x1, double x2) {
                      	double t_0 = (2.0 * x2) - 3.0;
                      	double t_1 = fma(t_0, 4.0, 9.0);
                      	double tmp;
                      	if (x1 <= -42000000.0) {
                      		tmp = fma(((6.0 * x1) - 3.0), x1, t_1) * (x1 * x1);
                      	} else if (x1 <= 8500.0) {
                      		tmp = fma(fma(x1, x1, 1.0), x1, (((x2 * x2) * 8.0) * (x1 / fma(x1, x1, 1.0)))) + fma(((fma(-2.0, x2, ((3.0 * x1) * x1)) - x1) / fma(x1, x1, 1.0)), 3.0, x1);
                      	} else {
                      		tmp = (6.0 - ((3.0 - (fma(((-1.0 + (t_0 * -6.0)) / x1), -1.0, t_1) / x1)) / x1)) * pow(x1, 4.0);
                      	}
                      	return tmp;
                      }
                      
                      function code(x1, x2)
                      	t_0 = Float64(Float64(2.0 * x2) - 3.0)
                      	t_1 = fma(t_0, 4.0, 9.0)
                      	tmp = 0.0
                      	if (x1 <= -42000000.0)
                      		tmp = Float64(fma(Float64(Float64(6.0 * x1) - 3.0), x1, t_1) * Float64(x1 * x1));
                      	elseif (x1 <= 8500.0)
                      		tmp = Float64(fma(fma(x1, x1, 1.0), x1, Float64(Float64(Float64(x2 * x2) * 8.0) * Float64(x1 / fma(x1, x1, 1.0)))) + fma(Float64(Float64(fma(-2.0, x2, Float64(Float64(3.0 * x1) * x1)) - x1) / fma(x1, x1, 1.0)), 3.0, x1));
                      	else
                      		tmp = Float64(Float64(6.0 - Float64(Float64(3.0 - Float64(fma(Float64(Float64(-1.0 + Float64(t_0 * -6.0)) / x1), -1.0, t_1) / x1)) / x1)) * (x1 ^ 4.0));
                      	end
                      	return tmp
                      end
                      
                      code[x1_, x2_] := Block[{t$95$0 = N[(N[(2.0 * x2), $MachinePrecision] - 3.0), $MachinePrecision]}, Block[{t$95$1 = N[(t$95$0 * 4.0 + 9.0), $MachinePrecision]}, If[LessEqual[x1, -42000000.0], N[(N[(N[(N[(6.0 * x1), $MachinePrecision] - 3.0), $MachinePrecision] * x1 + t$95$1), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision], If[LessEqual[x1, 8500.0], N[(N[(N[(x1 * x1 + 1.0), $MachinePrecision] * x1 + N[(N[(N[(x2 * x2), $MachinePrecision] * 8.0), $MachinePrecision] * N[(x1 / N[(x1 * x1 + 1.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(N[(N[(N[(-2.0 * x2 + N[(N[(3.0 * x1), $MachinePrecision] * x1), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision] / N[(x1 * x1 + 1.0), $MachinePrecision]), $MachinePrecision] * 3.0 + x1), $MachinePrecision]), $MachinePrecision], N[(N[(6.0 - N[(N[(3.0 - N[(N[(N[(N[(-1.0 + N[(t$95$0 * -6.0), $MachinePrecision]), $MachinePrecision] / x1), $MachinePrecision] * -1.0 + t$95$1), $MachinePrecision] / x1), $MachinePrecision]), $MachinePrecision] / x1), $MachinePrecision]), $MachinePrecision] * N[Power[x1, 4.0], $MachinePrecision]), $MachinePrecision]]]]]
                      
                      \begin{array}{l}
                      
                      \\
                      \begin{array}{l}
                      t_0 := 2 \cdot x2 - 3\\
                      t_1 := \mathsf{fma}\left(t\_0, 4, 9\right)\\
                      \mathbf{if}\;x1 \leq -42000000:\\
                      \;\;\;\;\mathsf{fma}\left(6 \cdot x1 - 3, x1, t\_1\right) \cdot \left(x1 \cdot x1\right)\\
                      
                      \mathbf{elif}\;x1 \leq 8500:\\
                      \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \left(\left(x2 \cdot x2\right) \cdot 8\right) \cdot \frac{x1}{\mathsf{fma}\left(x1, x1, 1\right)}\right) + \mathsf{fma}\left(\frac{\mathsf{fma}\left(-2, x2, \left(3 \cdot x1\right) \cdot x1\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)}, 3, x1\right)\\
                      
                      \mathbf{else}:\\
                      \;\;\;\;\left(6 - \frac{3 - \frac{\mathsf{fma}\left(\frac{-1 + t\_0 \cdot -6}{x1}, -1, t\_1\right)}{x1}}{x1}\right) \cdot {x1}^{4}\\
                      
                      
                      \end{array}
                      \end{array}
                      
                      Derivation
                      1. Split input into 3 regimes
                      2. if x1 < -4.2e7

                        1. Initial program 24.1%

                          \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                        2. Add Preprocessing
                        3. Taylor expanded in x1 around inf

                          \[\leadsto \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                        4. Step-by-step derivation
                          1. *-commutativeN/A

                            \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                          2. lower-*.f64N/A

                            \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                        5. Applied rewrites96.7%

                          \[\leadsto \color{blue}{\left(\frac{\mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)}{x1 \cdot x1} + \left(6 - \frac{3}{x1}\right)\right) \cdot {x1}^{4}} \]
                        6. Taylor expanded in x1 around 0

                          \[\leadsto {x1}^{2} \cdot \color{blue}{\left(9 + \left(4 \cdot \left(2 \cdot x2 - 3\right) + x1 \cdot \left(6 \cdot x1 - 3\right)\right)\right)} \]
                        7. Step-by-step derivation
                          1. Applied rewrites96.8%

                            \[\leadsto \mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)\right) \cdot \color{blue}{\left(x1 \cdot x1\right)} \]

                          if -4.2e7 < x1 < 8500

                          1. Initial program 99.6%

                            \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                          2. Add Preprocessing
                          3. Taylor expanded in x2 around inf

                            \[\leadsto x1 + \left(\left(\left(\color{blue}{8 \cdot \frac{x1 \cdot {x2}^{2}}{1 + {x1}^{2}}} + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                          4. Step-by-step derivation
                            1. associate-*r/N/A

                              \[\leadsto x1 + \left(\left(\left(\color{blue}{\frac{8 \cdot \left(x1 \cdot {x2}^{2}\right)}{1 + {x1}^{2}}} + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                            2. lower-/.f64N/A

                              \[\leadsto x1 + \left(\left(\left(\color{blue}{\frac{8 \cdot \left(x1 \cdot {x2}^{2}\right)}{1 + {x1}^{2}}} + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                            3. lower-*.f64N/A

                              \[\leadsto x1 + \left(\left(\left(\frac{\color{blue}{8 \cdot \left(x1 \cdot {x2}^{2}\right)}}{1 + {x1}^{2}} + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                            4. *-commutativeN/A

                              \[\leadsto x1 + \left(\left(\left(\frac{8 \cdot \color{blue}{\left({x2}^{2} \cdot x1\right)}}{1 + {x1}^{2}} + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                            5. lower-*.f64N/A

                              \[\leadsto x1 + \left(\left(\left(\frac{8 \cdot \color{blue}{\left({x2}^{2} \cdot x1\right)}}{1 + {x1}^{2}} + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                            6. unpow2N/A

                              \[\leadsto x1 + \left(\left(\left(\frac{8 \cdot \left(\color{blue}{\left(x2 \cdot x2\right)} \cdot x1\right)}{1 + {x1}^{2}} + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                            7. lower-*.f64N/A

                              \[\leadsto x1 + \left(\left(\left(\frac{8 \cdot \left(\color{blue}{\left(x2 \cdot x2\right)} \cdot x1\right)}{1 + {x1}^{2}} + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                            8. +-commutativeN/A

                              \[\leadsto x1 + \left(\left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\color{blue}{{x1}^{2} + 1}} + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                            9. unpow2N/A

                              \[\leadsto x1 + \left(\left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\color{blue}{x1 \cdot x1} + 1} + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                            10. lower-fma.f6486.5

                              \[\leadsto x1 + \left(\left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\color{blue}{\mathsf{fma}\left(x1, x1, 1\right)}} + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                          5. Applied rewrites86.5%

                            \[\leadsto x1 + \left(\left(\left(\color{blue}{\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\mathsf{fma}\left(x1, x1, 1\right)}} + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                          6. Applied rewrites86.7%

                            \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \left(\left(x2 \cdot x2\right) \cdot 8\right) \cdot \frac{x1}{\mathsf{fma}\left(x1, x1, 1\right)}\right) + \mathsf{fma}\left(\frac{\mathsf{fma}\left(-2, x2, \left(3 \cdot x1\right) \cdot x1\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)}, 3, x1\right)} \]

                          if 8500 < x1

                          1. Initial program 52.7%

                            \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                          2. Add Preprocessing
                          3. Taylor expanded in x1 around -inf

                            \[\leadsto \color{blue}{{x1}^{4} \cdot \left(6 + -1 \cdot \frac{3 + -1 \cdot \frac{9 + \left(-1 \cdot \frac{1 + -2 \cdot \left(1 + 3 \cdot \left(2 \cdot x2 - 3\right)\right)}{x1} + 4 \cdot \left(2 \cdot x2 - 3\right)\right)}{x1}}{x1}\right)} \]
                          4. Step-by-step derivation
                            1. *-commutativeN/A

                              \[\leadsto \color{blue}{\left(6 + -1 \cdot \frac{3 + -1 \cdot \frac{9 + \left(-1 \cdot \frac{1 + -2 \cdot \left(1 + 3 \cdot \left(2 \cdot x2 - 3\right)\right)}{x1} + 4 \cdot \left(2 \cdot x2 - 3\right)\right)}{x1}}{x1}\right) \cdot {x1}^{4}} \]
                            2. lower-*.f64N/A

                              \[\leadsto \color{blue}{\left(6 + -1 \cdot \frac{3 + -1 \cdot \frac{9 + \left(-1 \cdot \frac{1 + -2 \cdot \left(1 + 3 \cdot \left(2 \cdot x2 - 3\right)\right)}{x1} + 4 \cdot \left(2 \cdot x2 - 3\right)\right)}{x1}}{x1}\right) \cdot {x1}^{4}} \]
                          5. Applied rewrites96.4%

                            \[\leadsto \color{blue}{\left(6 - \frac{3 - \frac{\mathsf{fma}\left(\frac{-1 + \left(2 \cdot x2 - 3\right) \cdot -6}{x1}, -1, \mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)\right)}{x1}}{x1}\right) \cdot {x1}^{4}} \]
                        8. Recombined 3 regimes into one program.
                        9. Add Preprocessing

                        Alternative 6: 90.6% accurate, 2.9× speedup?

                        \[\begin{array}{l} \\ \begin{array}{l} t_0 := \mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)\right)\\ \mathbf{if}\;x1 \leq -42000000:\\ \;\;\;\;t\_0 \cdot \left(x1 \cdot x1\right)\\ \mathbf{elif}\;x1 \leq 8500:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \left(\left(x2 \cdot x2\right) \cdot 8\right) \cdot \frac{x1}{\mathsf{fma}\left(x1, x1, 1\right)}\right) + \mathsf{fma}\left(\frac{\mathsf{fma}\left(-2, x2, \left(3 \cdot x1\right) \cdot x1\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)}, 3, x1\right)\\ \mathbf{else}:\\ \;\;\;\;\left(t\_0 \cdot x1\right) \cdot x1\\ \end{array} \end{array} \]
                        (FPCore (x1 x2)
                         :precision binary64
                         (let* ((t_0 (fma (- (* 6.0 x1) 3.0) x1 (fma (- (* 2.0 x2) 3.0) 4.0 9.0))))
                           (if (<= x1 -42000000.0)
                             (* t_0 (* x1 x1))
                             (if (<= x1 8500.0)
                               (+
                                (fma (fma x1 x1 1.0) x1 (* (* (* x2 x2) 8.0) (/ x1 (fma x1 x1 1.0))))
                                (fma
                                 (/ (- (fma -2.0 x2 (* (* 3.0 x1) x1)) x1) (fma x1 x1 1.0))
                                 3.0
                                 x1))
                               (* (* t_0 x1) x1)))))
                        double code(double x1, double x2) {
                        	double t_0 = fma(((6.0 * x1) - 3.0), x1, fma(((2.0 * x2) - 3.0), 4.0, 9.0));
                        	double tmp;
                        	if (x1 <= -42000000.0) {
                        		tmp = t_0 * (x1 * x1);
                        	} else if (x1 <= 8500.0) {
                        		tmp = fma(fma(x1, x1, 1.0), x1, (((x2 * x2) * 8.0) * (x1 / fma(x1, x1, 1.0)))) + fma(((fma(-2.0, x2, ((3.0 * x1) * x1)) - x1) / fma(x1, x1, 1.0)), 3.0, x1);
                        	} else {
                        		tmp = (t_0 * x1) * x1;
                        	}
                        	return tmp;
                        }
                        
                        function code(x1, x2)
                        	t_0 = fma(Float64(Float64(6.0 * x1) - 3.0), x1, fma(Float64(Float64(2.0 * x2) - 3.0), 4.0, 9.0))
                        	tmp = 0.0
                        	if (x1 <= -42000000.0)
                        		tmp = Float64(t_0 * Float64(x1 * x1));
                        	elseif (x1 <= 8500.0)
                        		tmp = Float64(fma(fma(x1, x1, 1.0), x1, Float64(Float64(Float64(x2 * x2) * 8.0) * Float64(x1 / fma(x1, x1, 1.0)))) + fma(Float64(Float64(fma(-2.0, x2, Float64(Float64(3.0 * x1) * x1)) - x1) / fma(x1, x1, 1.0)), 3.0, x1));
                        	else
                        		tmp = Float64(Float64(t_0 * x1) * x1);
                        	end
                        	return tmp
                        end
                        
                        code[x1_, x2_] := Block[{t$95$0 = N[(N[(N[(6.0 * x1), $MachinePrecision] - 3.0), $MachinePrecision] * x1 + N[(N[(N[(2.0 * x2), $MachinePrecision] - 3.0), $MachinePrecision] * 4.0 + 9.0), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[x1, -42000000.0], N[(t$95$0 * N[(x1 * x1), $MachinePrecision]), $MachinePrecision], If[LessEqual[x1, 8500.0], N[(N[(N[(x1 * x1 + 1.0), $MachinePrecision] * x1 + N[(N[(N[(x2 * x2), $MachinePrecision] * 8.0), $MachinePrecision] * N[(x1 / N[(x1 * x1 + 1.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(N[(N[(N[(-2.0 * x2 + N[(N[(3.0 * x1), $MachinePrecision] * x1), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision] / N[(x1 * x1 + 1.0), $MachinePrecision]), $MachinePrecision] * 3.0 + x1), $MachinePrecision]), $MachinePrecision], N[(N[(t$95$0 * x1), $MachinePrecision] * x1), $MachinePrecision]]]]
                        
                        \begin{array}{l}
                        
                        \\
                        \begin{array}{l}
                        t_0 := \mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)\right)\\
                        \mathbf{if}\;x1 \leq -42000000:\\
                        \;\;\;\;t\_0 \cdot \left(x1 \cdot x1\right)\\
                        
                        \mathbf{elif}\;x1 \leq 8500:\\
                        \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \left(\left(x2 \cdot x2\right) \cdot 8\right) \cdot \frac{x1}{\mathsf{fma}\left(x1, x1, 1\right)}\right) + \mathsf{fma}\left(\frac{\mathsf{fma}\left(-2, x2, \left(3 \cdot x1\right) \cdot x1\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)}, 3, x1\right)\\
                        
                        \mathbf{else}:\\
                        \;\;\;\;\left(t\_0 \cdot x1\right) \cdot x1\\
                        
                        
                        \end{array}
                        \end{array}
                        
                        Derivation
                        1. Split input into 3 regimes
                        2. if x1 < -4.2e7

                          1. Initial program 24.1%

                            \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                          2. Add Preprocessing
                          3. Taylor expanded in x1 around inf

                            \[\leadsto \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                          4. Step-by-step derivation
                            1. *-commutativeN/A

                              \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                            2. lower-*.f64N/A

                              \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                          5. Applied rewrites96.7%

                            \[\leadsto \color{blue}{\left(\frac{\mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)}{x1 \cdot x1} + \left(6 - \frac{3}{x1}\right)\right) \cdot {x1}^{4}} \]
                          6. Taylor expanded in x1 around 0

                            \[\leadsto {x1}^{2} \cdot \color{blue}{\left(9 + \left(4 \cdot \left(2 \cdot x2 - 3\right) + x1 \cdot \left(6 \cdot x1 - 3\right)\right)\right)} \]
                          7. Step-by-step derivation
                            1. Applied rewrites96.8%

                              \[\leadsto \mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)\right) \cdot \color{blue}{\left(x1 \cdot x1\right)} \]

                            if -4.2e7 < x1 < 8500

                            1. Initial program 99.6%

                              \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                            2. Add Preprocessing
                            3. Taylor expanded in x2 around inf

                              \[\leadsto x1 + \left(\left(\left(\color{blue}{8 \cdot \frac{x1 \cdot {x2}^{2}}{1 + {x1}^{2}}} + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                            4. Step-by-step derivation
                              1. associate-*r/N/A

                                \[\leadsto x1 + \left(\left(\left(\color{blue}{\frac{8 \cdot \left(x1 \cdot {x2}^{2}\right)}{1 + {x1}^{2}}} + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                              2. lower-/.f64N/A

                                \[\leadsto x1 + \left(\left(\left(\color{blue}{\frac{8 \cdot \left(x1 \cdot {x2}^{2}\right)}{1 + {x1}^{2}}} + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                              3. lower-*.f64N/A

                                \[\leadsto x1 + \left(\left(\left(\frac{\color{blue}{8 \cdot \left(x1 \cdot {x2}^{2}\right)}}{1 + {x1}^{2}} + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                              4. *-commutativeN/A

                                \[\leadsto x1 + \left(\left(\left(\frac{8 \cdot \color{blue}{\left({x2}^{2} \cdot x1\right)}}{1 + {x1}^{2}} + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                              5. lower-*.f64N/A

                                \[\leadsto x1 + \left(\left(\left(\frac{8 \cdot \color{blue}{\left({x2}^{2} \cdot x1\right)}}{1 + {x1}^{2}} + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                              6. unpow2N/A

                                \[\leadsto x1 + \left(\left(\left(\frac{8 \cdot \left(\color{blue}{\left(x2 \cdot x2\right)} \cdot x1\right)}{1 + {x1}^{2}} + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                              7. lower-*.f64N/A

                                \[\leadsto x1 + \left(\left(\left(\frac{8 \cdot \left(\color{blue}{\left(x2 \cdot x2\right)} \cdot x1\right)}{1 + {x1}^{2}} + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                              8. +-commutativeN/A

                                \[\leadsto x1 + \left(\left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\color{blue}{{x1}^{2} + 1}} + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                              9. unpow2N/A

                                \[\leadsto x1 + \left(\left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\color{blue}{x1 \cdot x1} + 1} + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                              10. lower-fma.f6486.5

                                \[\leadsto x1 + \left(\left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\color{blue}{\mathsf{fma}\left(x1, x1, 1\right)}} + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                            5. Applied rewrites86.5%

                              \[\leadsto x1 + \left(\left(\left(\color{blue}{\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\mathsf{fma}\left(x1, x1, 1\right)}} + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                            6. Applied rewrites86.7%

                              \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \left(\left(x2 \cdot x2\right) \cdot 8\right) \cdot \frac{x1}{\mathsf{fma}\left(x1, x1, 1\right)}\right) + \mathsf{fma}\left(\frac{\mathsf{fma}\left(-2, x2, \left(3 \cdot x1\right) \cdot x1\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)}, 3, x1\right)} \]

                            if 8500 < x1

                            1. Initial program 52.7%

                              \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                            2. Add Preprocessing
                            3. Taylor expanded in x1 around inf

                              \[\leadsto \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                            4. Step-by-step derivation
                              1. *-commutativeN/A

                                \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                              2. lower-*.f64N/A

                                \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                            5. Applied rewrites95.8%

                              \[\leadsto \color{blue}{\left(\frac{\mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)}{x1 \cdot x1} + \left(6 - \frac{3}{x1}\right)\right) \cdot {x1}^{4}} \]
                            6. Taylor expanded in x2 around inf

                              \[\leadsto 8 \cdot \color{blue}{\left({x1}^{2} \cdot x2\right)} \]
                            7. Step-by-step derivation
                              1. Applied rewrites36.9%

                                \[\leadsto \left(\left(x1 \cdot x1\right) \cdot x2\right) \cdot \color{blue}{8} \]
                              2. Step-by-step derivation
                                1. Applied rewrites30.2%

                                  \[\leadsto \left(\left(x2 \cdot x1\right) \cdot x1\right) \cdot 8 \]
                                2. Taylor expanded in x1 around 0

                                  \[\leadsto {x1}^{2} \cdot \color{blue}{\left(9 + \left(4 \cdot \left(2 \cdot x2 - 3\right) + x1 \cdot \left(6 \cdot x1 - 3\right)\right)\right)} \]
                                3. Step-by-step derivation
                                  1. Applied rewrites95.9%

                                    \[\leadsto \left(\mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)\right) \cdot x1\right) \cdot \color{blue}{x1} \]
                                4. Recombined 3 regimes into one program.
                                5. Add Preprocessing

                                Alternative 7: 91.7% accurate, 2.9× speedup?

                                \[\begin{array}{l} \\ \begin{array}{l} t_0 := 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\\ t_1 := 2 \cdot x2 - 3\\ t_2 := \mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(t\_1, 4, 9\right)\right)\\ \mathbf{if}\;x1 \leq -27:\\ \;\;\;\;t\_2 \cdot \left(x1 \cdot x1\right)\\ \mathbf{elif}\;x1 \leq -1.5 \cdot 10^{-229}:\\ \;\;\;\;x1 + \left(\left(\mathsf{fma}\left(-22 \cdot x1, x1, \left(t\_1 \cdot x2\right) \cdot 4\right) \cdot x1 + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right)\\ \mathbf{elif}\;x1 \leq 4.8 \cdot 10^{-180}:\\ \;\;\;\;x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\left(6 \cdot x1\right) \cdot x1, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + t\_0\right)\\ \mathbf{elif}\;x1 \leq 8500:\\ \;\;\;\;x1 + \left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\mathsf{fma}\left(x1, x1, 1\right)} + x1\right) + t\_0\right)\\ \mathbf{else}:\\ \;\;\;\;\left(t\_2 \cdot x1\right) \cdot x1\\ \end{array} \end{array} \]
                                (FPCore (x1 x2)
                                 :precision binary64
                                 (let* ((t_0 (* 3.0 (fma -2.0 x2 (- x1))))
                                        (t_1 (- (* 2.0 x2) 3.0))
                                        (t_2 (fma (- (* 6.0 x1) 3.0) x1 (fma t_1 4.0 9.0))))
                                   (if (<= x1 -27.0)
                                     (* t_2 (* x1 x1))
                                     (if (<= x1 -1.5e-229)
                                       (+
                                        x1
                                        (+
                                         (+ (* (fma (* -22.0 x1) x1 (* (* t_1 x2) 4.0)) x1) x1)
                                         (*
                                          3.0
                                          (/ (- (- (* (* 3.0 x1) x1) (* 2.0 x2)) x1) (+ (* x1 x1) 1.0)))))
                                       (if (<= x1 4.8e-180)
                                         (+
                                          x1
                                          (+
                                           (fma
                                            (fma x1 x1 1.0)
                                            x1
                                            (fma (* (* 6.0 x1) x1) (fma x1 x1 1.0) (* (* 3.0 3.0) (* x1 x1))))
                                           t_0))
                                         (if (<= x1 8500.0)
                                           (+ x1 (+ (+ (/ (* 8.0 (* (* x2 x2) x1)) (fma x1 x1 1.0)) x1) t_0))
                                           (* (* t_2 x1) x1)))))))
                                double code(double x1, double x2) {
                                	double t_0 = 3.0 * fma(-2.0, x2, -x1);
                                	double t_1 = (2.0 * x2) - 3.0;
                                	double t_2 = fma(((6.0 * x1) - 3.0), x1, fma(t_1, 4.0, 9.0));
                                	double tmp;
                                	if (x1 <= -27.0) {
                                		tmp = t_2 * (x1 * x1);
                                	} else if (x1 <= -1.5e-229) {
                                		tmp = x1 + (((fma((-22.0 * x1), x1, ((t_1 * x2) * 4.0)) * x1) + x1) + (3.0 * (((((3.0 * x1) * x1) - (2.0 * x2)) - x1) / ((x1 * x1) + 1.0))));
                                	} else if (x1 <= 4.8e-180) {
                                		tmp = x1 + (fma(fma(x1, x1, 1.0), x1, fma(((6.0 * x1) * x1), fma(x1, x1, 1.0), ((3.0 * 3.0) * (x1 * x1)))) + t_0);
                                	} else if (x1 <= 8500.0) {
                                		tmp = x1 + ((((8.0 * ((x2 * x2) * x1)) / fma(x1, x1, 1.0)) + x1) + t_0);
                                	} else {
                                		tmp = (t_2 * x1) * x1;
                                	}
                                	return tmp;
                                }
                                
                                function code(x1, x2)
                                	t_0 = Float64(3.0 * fma(-2.0, x2, Float64(-x1)))
                                	t_1 = Float64(Float64(2.0 * x2) - 3.0)
                                	t_2 = fma(Float64(Float64(6.0 * x1) - 3.0), x1, fma(t_1, 4.0, 9.0))
                                	tmp = 0.0
                                	if (x1 <= -27.0)
                                		tmp = Float64(t_2 * Float64(x1 * x1));
                                	elseif (x1 <= -1.5e-229)
                                		tmp = Float64(x1 + Float64(Float64(Float64(fma(Float64(-22.0 * x1), x1, Float64(Float64(t_1 * x2) * 4.0)) * x1) + x1) + Float64(3.0 * Float64(Float64(Float64(Float64(Float64(3.0 * x1) * x1) - Float64(2.0 * x2)) - x1) / Float64(Float64(x1 * x1) + 1.0)))));
                                	elseif (x1 <= 4.8e-180)
                                		tmp = Float64(x1 + Float64(fma(fma(x1, x1, 1.0), x1, fma(Float64(Float64(6.0 * x1) * x1), fma(x1, x1, 1.0), Float64(Float64(3.0 * 3.0) * Float64(x1 * x1)))) + t_0));
                                	elseif (x1 <= 8500.0)
                                		tmp = Float64(x1 + Float64(Float64(Float64(Float64(8.0 * Float64(Float64(x2 * x2) * x1)) / fma(x1, x1, 1.0)) + x1) + t_0));
                                	else
                                		tmp = Float64(Float64(t_2 * x1) * x1);
                                	end
                                	return tmp
                                end
                                
                                code[x1_, x2_] := Block[{t$95$0 = N[(3.0 * N[(-2.0 * x2 + (-x1)), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(2.0 * x2), $MachinePrecision] - 3.0), $MachinePrecision]}, Block[{t$95$2 = N[(N[(N[(6.0 * x1), $MachinePrecision] - 3.0), $MachinePrecision] * x1 + N[(t$95$1 * 4.0 + 9.0), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[x1, -27.0], N[(t$95$2 * N[(x1 * x1), $MachinePrecision]), $MachinePrecision], If[LessEqual[x1, -1.5e-229], N[(x1 + N[(N[(N[(N[(N[(-22.0 * x1), $MachinePrecision] * x1 + N[(N[(t$95$1 * x2), $MachinePrecision] * 4.0), $MachinePrecision]), $MachinePrecision] * x1), $MachinePrecision] + x1), $MachinePrecision] + N[(3.0 * N[(N[(N[(N[(N[(3.0 * x1), $MachinePrecision] * x1), $MachinePrecision] - N[(2.0 * x2), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision] / N[(N[(x1 * x1), $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[x1, 4.8e-180], N[(x1 + N[(N[(N[(x1 * x1 + 1.0), $MachinePrecision] * x1 + N[(N[(N[(6.0 * x1), $MachinePrecision] * x1), $MachinePrecision] * N[(x1 * x1 + 1.0), $MachinePrecision] + N[(N[(3.0 * 3.0), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + t$95$0), $MachinePrecision]), $MachinePrecision], If[LessEqual[x1, 8500.0], N[(x1 + N[(N[(N[(N[(8.0 * N[(N[(x2 * x2), $MachinePrecision] * x1), $MachinePrecision]), $MachinePrecision] / N[(x1 * x1 + 1.0), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision] + t$95$0), $MachinePrecision]), $MachinePrecision], N[(N[(t$95$2 * x1), $MachinePrecision] * x1), $MachinePrecision]]]]]]]]
                                
                                \begin{array}{l}
                                
                                \\
                                \begin{array}{l}
                                t_0 := 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\\
                                t_1 := 2 \cdot x2 - 3\\
                                t_2 := \mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(t\_1, 4, 9\right)\right)\\
                                \mathbf{if}\;x1 \leq -27:\\
                                \;\;\;\;t\_2 \cdot \left(x1 \cdot x1\right)\\
                                
                                \mathbf{elif}\;x1 \leq -1.5 \cdot 10^{-229}:\\
                                \;\;\;\;x1 + \left(\left(\mathsf{fma}\left(-22 \cdot x1, x1, \left(t\_1 \cdot x2\right) \cdot 4\right) \cdot x1 + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right)\\
                                
                                \mathbf{elif}\;x1 \leq 4.8 \cdot 10^{-180}:\\
                                \;\;\;\;x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\left(6 \cdot x1\right) \cdot x1, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + t\_0\right)\\
                                
                                \mathbf{elif}\;x1 \leq 8500:\\
                                \;\;\;\;x1 + \left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\mathsf{fma}\left(x1, x1, 1\right)} + x1\right) + t\_0\right)\\
                                
                                \mathbf{else}:\\
                                \;\;\;\;\left(t\_2 \cdot x1\right) \cdot x1\\
                                
                                
                                \end{array}
                                \end{array}
                                
                                Derivation
                                1. Split input into 5 regimes
                                2. if x1 < -27

                                  1. Initial program 24.1%

                                    \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in x1 around inf

                                    \[\leadsto \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                                  4. Step-by-step derivation
                                    1. *-commutativeN/A

                                      \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                    2. lower-*.f64N/A

                                      \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                  5. Applied rewrites96.7%

                                    \[\leadsto \color{blue}{\left(\frac{\mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)}{x1 \cdot x1} + \left(6 - \frac{3}{x1}\right)\right) \cdot {x1}^{4}} \]
                                  6. Taylor expanded in x1 around 0

                                    \[\leadsto {x1}^{2} \cdot \color{blue}{\left(9 + \left(4 \cdot \left(2 \cdot x2 - 3\right) + x1 \cdot \left(6 \cdot x1 - 3\right)\right)\right)} \]
                                  7. Step-by-step derivation
                                    1. Applied rewrites96.8%

                                      \[\leadsto \mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)\right) \cdot \color{blue}{\left(x1 \cdot x1\right)} \]

                                    if -27 < x1 < -1.50000000000000001e-229

                                    1. Initial program 99.4%

                                      \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                    2. Add Preprocessing
                                    3. Taylor expanded in x1 around 0

                                      \[\leadsto x1 + \left(\left(\color{blue}{x1 \cdot \left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(6 \cdot x2 + \left(8 \cdot x2 + x1 \cdot \left(\left(2 \cdot \left(\left(1 + \left(2 \cdot \left(x2 \cdot \left(3 + -2 \cdot x2\right)\right) + 3 \cdot \left(2 \cdot x2 - 3\right)\right)\right) - 2 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right)\right) + 4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right)\right) - 6\right)\right)\right)\right) - 6\right)\right)} + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                    4. Applied rewrites71.1%

                                      \[\leadsto x1 + \left(\left(\color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(-4, x2, \mathsf{fma}\left(-2, 2 \cdot x2 - 3, \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(2 \cdot \mathsf{fma}\left(-2, x2, 3\right), x2, \mathsf{fma}\left(2 \cdot x2 - 3, 3, 1\right)\right) - \left(\left(2 \cdot x2 - 3\right) \cdot x2\right) \cdot 2, 2, \left(\left(2 \cdot x2 - 3\right) \cdot x2\right) \cdot 4 - 6\right), x1, x2 \cdot 14\right)\right)\right) - 6, x1, \left(\left(2 \cdot x2 - 3\right) \cdot x2\right) \cdot 4\right) \cdot x1} + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                    5. Taylor expanded in x2 around 0

                                      \[\leadsto x1 + \left(\left(\mathsf{fma}\left(-22 \cdot x1, x1, \left(\left(2 \cdot x2 - 3\right) \cdot x2\right) \cdot 4\right) \cdot x1 + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                    6. Step-by-step derivation
                                      1. Applied rewrites92.6%

                                        \[\leadsto x1 + \left(\left(\mathsf{fma}\left(-22 \cdot x1, x1, \left(\left(2 \cdot x2 - 3\right) \cdot x2\right) \cdot 4\right) \cdot x1 + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]

                                      if -1.50000000000000001e-229 < x1 < 4.79999999999999959e-180

                                      1. Initial program 99.7%

                                        \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                      2. Add Preprocessing
                                      3. Taylor expanded in x1 around inf

                                        \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{3}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                      4. Step-by-step derivation
                                        1. Applied rewrites99.7%

                                          \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{3}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                        2. Taylor expanded in x1 around 0

                                          \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\left(-2 \cdot x2 + -1 \cdot x1\right)}\right) \]
                                        3. Step-by-step derivation
                                          1. mul-1-negN/A

                                            \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \left(-2 \cdot x2 + \color{blue}{\left(\mathsf{neg}\left(x1\right)\right)}\right)\right) \]
                                          2. lower-fma.f64N/A

                                            \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\mathsf{fma}\left(-2, x2, \mathsf{neg}\left(x1\right)\right)}\right) \]
                                          3. lower-neg.f6499.7

                                            \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, \color{blue}{-x1}\right)\right) \]
                                        4. Applied rewrites99.7%

                                          \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\mathsf{fma}\left(-2, x2, -x1\right)}\right) \]
                                        5. Applied rewrites73.1%

                                          \[\leadsto x1 + \left(\color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(\left(\frac{\mathsf{fma}\left(x2, 2, \left(3 \cdot x1\right) \cdot x1\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)} - 3\right) \cdot \frac{\mathsf{fma}\left(x2, 2, \left(3 \cdot x1\right) \cdot x1\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)}, x1 \cdot 2, \left(\frac{4 \cdot \left(\mathsf{fma}\left(x2, 2, \left(3 \cdot x1\right) \cdot x1\right) - x1\right)}{\mathsf{fma}\left(x1, x1, 1\right)} - 6\right) \cdot \left(x1 \cdot x1\right)\right), \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right)} + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                        6. Taylor expanded in x1 around inf

                                          \[\leadsto x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\color{blue}{6 \cdot {x1}^{2}}, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                        7. Step-by-step derivation
                                          1. unpow2N/A

                                            \[\leadsto x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(6 \cdot \color{blue}{\left(x1 \cdot x1\right)}, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                          2. associate-*r*N/A

                                            \[\leadsto x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\color{blue}{\left(6 \cdot x1\right) \cdot x1}, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                          3. lower-*.f64N/A

                                            \[\leadsto x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\color{blue}{\left(6 \cdot x1\right) \cdot x1}, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                          4. lower-*.f6492.9

                                            \[\leadsto x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\color{blue}{\left(6 \cdot x1\right)} \cdot x1, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                        8. Applied rewrites92.9%

                                          \[\leadsto x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\color{blue}{\left(6 \cdot x1\right) \cdot x1}, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]

                                        if 4.79999999999999959e-180 < x1 < 8500

                                        1. Initial program 99.6%

                                          \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                        2. Add Preprocessing
                                        3. Taylor expanded in x1 around inf

                                          \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{3}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                        4. Step-by-step derivation
                                          1. Applied rewrites99.6%

                                            \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{3}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                          2. Taylor expanded in x1 around 0

                                            \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\left(-2 \cdot x2 + -1 \cdot x1\right)}\right) \]
                                          3. Step-by-step derivation
                                            1. mul-1-negN/A

                                              \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \left(-2 \cdot x2 + \color{blue}{\left(\mathsf{neg}\left(x1\right)\right)}\right)\right) \]
                                            2. lower-fma.f64N/A

                                              \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\mathsf{fma}\left(-2, x2, \mathsf{neg}\left(x1\right)\right)}\right) \]
                                            3. lower-neg.f6499.6

                                              \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, \color{blue}{-x1}\right)\right) \]
                                          4. Applied rewrites99.6%

                                            \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\mathsf{fma}\left(-2, x2, -x1\right)}\right) \]
                                          5. Taylor expanded in x2 around inf

                                            \[\leadsto x1 + \left(\left(\color{blue}{8 \cdot \frac{x1 \cdot {x2}^{2}}{1 + {x1}^{2}}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                          6. Step-by-step derivation
                                            1. associate-*r/N/A

                                              \[\leadsto x1 + \left(\left(\color{blue}{\frac{8 \cdot \left(x1 \cdot {x2}^{2}\right)}{1 + {x1}^{2}}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                            2. lower-/.f64N/A

                                              \[\leadsto x1 + \left(\left(\color{blue}{\frac{8 \cdot \left(x1 \cdot {x2}^{2}\right)}{1 + {x1}^{2}}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                            3. lower-*.f64N/A

                                              \[\leadsto x1 + \left(\left(\frac{\color{blue}{8 \cdot \left(x1 \cdot {x2}^{2}\right)}}{1 + {x1}^{2}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                            4. *-commutativeN/A

                                              \[\leadsto x1 + \left(\left(\frac{8 \cdot \color{blue}{\left({x2}^{2} \cdot x1\right)}}{1 + {x1}^{2}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                            5. lower-*.f64N/A

                                              \[\leadsto x1 + \left(\left(\frac{8 \cdot \color{blue}{\left({x2}^{2} \cdot x1\right)}}{1 + {x1}^{2}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                            6. unpow2N/A

                                              \[\leadsto x1 + \left(\left(\frac{8 \cdot \left(\color{blue}{\left(x2 \cdot x2\right)} \cdot x1\right)}{1 + {x1}^{2}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                            7. lower-*.f64N/A

                                              \[\leadsto x1 + \left(\left(\frac{8 \cdot \left(\color{blue}{\left(x2 \cdot x2\right)} \cdot x1\right)}{1 + {x1}^{2}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                            8. +-commutativeN/A

                                              \[\leadsto x1 + \left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\color{blue}{{x1}^{2} + 1}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                            9. unpow2N/A

                                              \[\leadsto x1 + \left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\color{blue}{x1 \cdot x1} + 1} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                            10. lower-fma.f6494.0

                                              \[\leadsto x1 + \left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\color{blue}{\mathsf{fma}\left(x1, x1, 1\right)}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                          7. Applied rewrites94.0%

                                            \[\leadsto x1 + \left(\left(\color{blue}{\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\mathsf{fma}\left(x1, x1, 1\right)}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]

                                          if 8500 < x1

                                          1. Initial program 52.7%

                                            \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                          2. Add Preprocessing
                                          3. Taylor expanded in x1 around inf

                                            \[\leadsto \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                                          4. Step-by-step derivation
                                            1. *-commutativeN/A

                                              \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                            2. lower-*.f64N/A

                                              \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                          5. Applied rewrites95.8%

                                            \[\leadsto \color{blue}{\left(\frac{\mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)}{x1 \cdot x1} + \left(6 - \frac{3}{x1}\right)\right) \cdot {x1}^{4}} \]
                                          6. Taylor expanded in x2 around inf

                                            \[\leadsto 8 \cdot \color{blue}{\left({x1}^{2} \cdot x2\right)} \]
                                          7. Step-by-step derivation
                                            1. Applied rewrites36.9%

                                              \[\leadsto \left(\left(x1 \cdot x1\right) \cdot x2\right) \cdot \color{blue}{8} \]
                                            2. Step-by-step derivation
                                              1. Applied rewrites30.2%

                                                \[\leadsto \left(\left(x2 \cdot x1\right) \cdot x1\right) \cdot 8 \]
                                              2. Taylor expanded in x1 around 0

                                                \[\leadsto {x1}^{2} \cdot \color{blue}{\left(9 + \left(4 \cdot \left(2 \cdot x2 - 3\right) + x1 \cdot \left(6 \cdot x1 - 3\right)\right)\right)} \]
                                              3. Step-by-step derivation
                                                1. Applied rewrites95.9%

                                                  \[\leadsto \left(\mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)\right) \cdot x1\right) \cdot \color{blue}{x1} \]
                                              4. Recombined 5 regimes into one program.
                                              5. Add Preprocessing

                                              Alternative 8: 91.7% accurate, 3.2× speedup?

                                              \[\begin{array}{l} \\ \begin{array}{l} t_0 := 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\\ t_1 := 2 \cdot x2 - 3\\ t_2 := \mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(t\_1, 4, 9\right)\right)\\ \mathbf{if}\;x1 \leq -27:\\ \;\;\;\;t\_2 \cdot \left(x1 \cdot x1\right)\\ \mathbf{elif}\;x1 \leq -1.5 \cdot 10^{-229}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-4, x2, \mathsf{fma}\left(-2, t\_1, \mathsf{fma}\left(3 - -2 \cdot x2, 3, x2 \cdot 14\right) - 6\right)\right), x1, \left(t\_1 \cdot x2\right) \cdot 4 - 1\right), x1, -6 \cdot x2\right)\\ \mathbf{elif}\;x1 \leq 4.8 \cdot 10^{-180}:\\ \;\;\;\;x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\left(6 \cdot x1\right) \cdot x1, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + t\_0\right)\\ \mathbf{elif}\;x1 \leq 8500:\\ \;\;\;\;x1 + \left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\mathsf{fma}\left(x1, x1, 1\right)} + x1\right) + t\_0\right)\\ \mathbf{else}:\\ \;\;\;\;\left(t\_2 \cdot x1\right) \cdot x1\\ \end{array} \end{array} \]
                                              (FPCore (x1 x2)
                                               :precision binary64
                                               (let* ((t_0 (* 3.0 (fma -2.0 x2 (- x1))))
                                                      (t_1 (- (* 2.0 x2) 3.0))
                                                      (t_2 (fma (- (* 6.0 x1) 3.0) x1 (fma t_1 4.0 9.0))))
                                                 (if (<= x1 -27.0)
                                                   (* t_2 (* x1 x1))
                                                   (if (<= x1 -1.5e-229)
                                                     (fma
                                                      (fma
                                                       (fma
                                                        -4.0
                                                        x2
                                                        (fma -2.0 t_1 (- (fma (- 3.0 (* -2.0 x2)) 3.0 (* x2 14.0)) 6.0)))
                                                       x1
                                                       (- (* (* t_1 x2) 4.0) 1.0))
                                                      x1
                                                      (* -6.0 x2))
                                                     (if (<= x1 4.8e-180)
                                                       (+
                                                        x1
                                                        (+
                                                         (fma
                                                          (fma x1 x1 1.0)
                                                          x1
                                                          (fma (* (* 6.0 x1) x1) (fma x1 x1 1.0) (* (* 3.0 3.0) (* x1 x1))))
                                                         t_0))
                                                       (if (<= x1 8500.0)
                                                         (+ x1 (+ (+ (/ (* 8.0 (* (* x2 x2) x1)) (fma x1 x1 1.0)) x1) t_0))
                                                         (* (* t_2 x1) x1)))))))
                                              double code(double x1, double x2) {
                                              	double t_0 = 3.0 * fma(-2.0, x2, -x1);
                                              	double t_1 = (2.0 * x2) - 3.0;
                                              	double t_2 = fma(((6.0 * x1) - 3.0), x1, fma(t_1, 4.0, 9.0));
                                              	double tmp;
                                              	if (x1 <= -27.0) {
                                              		tmp = t_2 * (x1 * x1);
                                              	} else if (x1 <= -1.5e-229) {
                                              		tmp = fma(fma(fma(-4.0, x2, fma(-2.0, t_1, (fma((3.0 - (-2.0 * x2)), 3.0, (x2 * 14.0)) - 6.0))), x1, (((t_1 * x2) * 4.0) - 1.0)), x1, (-6.0 * x2));
                                              	} else if (x1 <= 4.8e-180) {
                                              		tmp = x1 + (fma(fma(x1, x1, 1.0), x1, fma(((6.0 * x1) * x1), fma(x1, x1, 1.0), ((3.0 * 3.0) * (x1 * x1)))) + t_0);
                                              	} else if (x1 <= 8500.0) {
                                              		tmp = x1 + ((((8.0 * ((x2 * x2) * x1)) / fma(x1, x1, 1.0)) + x1) + t_0);
                                              	} else {
                                              		tmp = (t_2 * x1) * x1;
                                              	}
                                              	return tmp;
                                              }
                                              
                                              function code(x1, x2)
                                              	t_0 = Float64(3.0 * fma(-2.0, x2, Float64(-x1)))
                                              	t_1 = Float64(Float64(2.0 * x2) - 3.0)
                                              	t_2 = fma(Float64(Float64(6.0 * x1) - 3.0), x1, fma(t_1, 4.0, 9.0))
                                              	tmp = 0.0
                                              	if (x1 <= -27.0)
                                              		tmp = Float64(t_2 * Float64(x1 * x1));
                                              	elseif (x1 <= -1.5e-229)
                                              		tmp = fma(fma(fma(-4.0, x2, fma(-2.0, t_1, Float64(fma(Float64(3.0 - Float64(-2.0 * x2)), 3.0, Float64(x2 * 14.0)) - 6.0))), x1, Float64(Float64(Float64(t_1 * x2) * 4.0) - 1.0)), x1, Float64(-6.0 * x2));
                                              	elseif (x1 <= 4.8e-180)
                                              		tmp = Float64(x1 + Float64(fma(fma(x1, x1, 1.0), x1, fma(Float64(Float64(6.0 * x1) * x1), fma(x1, x1, 1.0), Float64(Float64(3.0 * 3.0) * Float64(x1 * x1)))) + t_0));
                                              	elseif (x1 <= 8500.0)
                                              		tmp = Float64(x1 + Float64(Float64(Float64(Float64(8.0 * Float64(Float64(x2 * x2) * x1)) / fma(x1, x1, 1.0)) + x1) + t_0));
                                              	else
                                              		tmp = Float64(Float64(t_2 * x1) * x1);
                                              	end
                                              	return tmp
                                              end
                                              
                                              code[x1_, x2_] := Block[{t$95$0 = N[(3.0 * N[(-2.0 * x2 + (-x1)), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(2.0 * x2), $MachinePrecision] - 3.0), $MachinePrecision]}, Block[{t$95$2 = N[(N[(N[(6.0 * x1), $MachinePrecision] - 3.0), $MachinePrecision] * x1 + N[(t$95$1 * 4.0 + 9.0), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[x1, -27.0], N[(t$95$2 * N[(x1 * x1), $MachinePrecision]), $MachinePrecision], If[LessEqual[x1, -1.5e-229], N[(N[(N[(-4.0 * x2 + N[(-2.0 * t$95$1 + N[(N[(N[(3.0 - N[(-2.0 * x2), $MachinePrecision]), $MachinePrecision] * 3.0 + N[(x2 * 14.0), $MachinePrecision]), $MachinePrecision] - 6.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * x1 + N[(N[(N[(t$95$1 * x2), $MachinePrecision] * 4.0), $MachinePrecision] - 1.0), $MachinePrecision]), $MachinePrecision] * x1 + N[(-6.0 * x2), $MachinePrecision]), $MachinePrecision], If[LessEqual[x1, 4.8e-180], N[(x1 + N[(N[(N[(x1 * x1 + 1.0), $MachinePrecision] * x1 + N[(N[(N[(6.0 * x1), $MachinePrecision] * x1), $MachinePrecision] * N[(x1 * x1 + 1.0), $MachinePrecision] + N[(N[(3.0 * 3.0), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + t$95$0), $MachinePrecision]), $MachinePrecision], If[LessEqual[x1, 8500.0], N[(x1 + N[(N[(N[(N[(8.0 * N[(N[(x2 * x2), $MachinePrecision] * x1), $MachinePrecision]), $MachinePrecision] / N[(x1 * x1 + 1.0), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision] + t$95$0), $MachinePrecision]), $MachinePrecision], N[(N[(t$95$2 * x1), $MachinePrecision] * x1), $MachinePrecision]]]]]]]]
                                              
                                              \begin{array}{l}
                                              
                                              \\
                                              \begin{array}{l}
                                              t_0 := 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\\
                                              t_1 := 2 \cdot x2 - 3\\
                                              t_2 := \mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(t\_1, 4, 9\right)\right)\\
                                              \mathbf{if}\;x1 \leq -27:\\
                                              \;\;\;\;t\_2 \cdot \left(x1 \cdot x1\right)\\
                                              
                                              \mathbf{elif}\;x1 \leq -1.5 \cdot 10^{-229}:\\
                                              \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-4, x2, \mathsf{fma}\left(-2, t\_1, \mathsf{fma}\left(3 - -2 \cdot x2, 3, x2 \cdot 14\right) - 6\right)\right), x1, \left(t\_1 \cdot x2\right) \cdot 4 - 1\right), x1, -6 \cdot x2\right)\\
                                              
                                              \mathbf{elif}\;x1 \leq 4.8 \cdot 10^{-180}:\\
                                              \;\;\;\;x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\left(6 \cdot x1\right) \cdot x1, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + t\_0\right)\\
                                              
                                              \mathbf{elif}\;x1 \leq 8500:\\
                                              \;\;\;\;x1 + \left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\mathsf{fma}\left(x1, x1, 1\right)} + x1\right) + t\_0\right)\\
                                              
                                              \mathbf{else}:\\
                                              \;\;\;\;\left(t\_2 \cdot x1\right) \cdot x1\\
                                              
                                              
                                              \end{array}
                                              \end{array}
                                              
                                              Derivation
                                              1. Split input into 5 regimes
                                              2. if x1 < -27

                                                1. Initial program 24.1%

                                                  \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                2. Add Preprocessing
                                                3. Taylor expanded in x1 around inf

                                                  \[\leadsto \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                                                4. Step-by-step derivation
                                                  1. *-commutativeN/A

                                                    \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                  2. lower-*.f64N/A

                                                    \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                5. Applied rewrites96.7%

                                                  \[\leadsto \color{blue}{\left(\frac{\mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)}{x1 \cdot x1} + \left(6 - \frac{3}{x1}\right)\right) \cdot {x1}^{4}} \]
                                                6. Taylor expanded in x1 around 0

                                                  \[\leadsto {x1}^{2} \cdot \color{blue}{\left(9 + \left(4 \cdot \left(2 \cdot x2 - 3\right) + x1 \cdot \left(6 \cdot x1 - 3\right)\right)\right)} \]
                                                7. Step-by-step derivation
                                                  1. Applied rewrites96.8%

                                                    \[\leadsto \mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)\right) \cdot \color{blue}{\left(x1 \cdot x1\right)} \]

                                                  if -27 < x1 < -1.50000000000000001e-229

                                                  1. Initial program 99.4%

                                                    \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                  2. Add Preprocessing
                                                  3. Taylor expanded in x1 around 0

                                                    \[\leadsto \color{blue}{-6 \cdot x2 + x1 \cdot \left(\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + x1 \cdot \left(\left(2 \cdot \left(-2 \cdot x2 + -1 \cdot \left(2 \cdot x2 - 3\right)\right) + \left(3 \cdot \left(3 - -2 \cdot x2\right) + \left(6 \cdot x2 + 8 \cdot x2\right)\right)\right) - 6\right)\right) - 1\right)} \]
                                                  4. Applied rewrites92.5%

                                                    \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-4, x2, \mathsf{fma}\left(-2, 2 \cdot x2 - 3, \mathsf{fma}\left(3 - -2 \cdot x2, 3, x2 \cdot 14\right) - 6\right)\right), x1, \left(\left(2 \cdot x2 - 3\right) \cdot x2\right) \cdot 4 - 1\right), x1, -6 \cdot x2\right)} \]

                                                  if -1.50000000000000001e-229 < x1 < 4.79999999999999959e-180

                                                  1. Initial program 99.7%

                                                    \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                  2. Add Preprocessing
                                                  3. Taylor expanded in x1 around inf

                                                    \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{3}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                  4. Step-by-step derivation
                                                    1. Applied rewrites99.7%

                                                      \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{3}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                    2. Taylor expanded in x1 around 0

                                                      \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\left(-2 \cdot x2 + -1 \cdot x1\right)}\right) \]
                                                    3. Step-by-step derivation
                                                      1. mul-1-negN/A

                                                        \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \left(-2 \cdot x2 + \color{blue}{\left(\mathsf{neg}\left(x1\right)\right)}\right)\right) \]
                                                      2. lower-fma.f64N/A

                                                        \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\mathsf{fma}\left(-2, x2, \mathsf{neg}\left(x1\right)\right)}\right) \]
                                                      3. lower-neg.f6499.7

                                                        \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, \color{blue}{-x1}\right)\right) \]
                                                    4. Applied rewrites99.7%

                                                      \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\mathsf{fma}\left(-2, x2, -x1\right)}\right) \]
                                                    5. Applied rewrites73.1%

                                                      \[\leadsto x1 + \left(\color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(\left(\frac{\mathsf{fma}\left(x2, 2, \left(3 \cdot x1\right) \cdot x1\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)} - 3\right) \cdot \frac{\mathsf{fma}\left(x2, 2, \left(3 \cdot x1\right) \cdot x1\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)}, x1 \cdot 2, \left(\frac{4 \cdot \left(\mathsf{fma}\left(x2, 2, \left(3 \cdot x1\right) \cdot x1\right) - x1\right)}{\mathsf{fma}\left(x1, x1, 1\right)} - 6\right) \cdot \left(x1 \cdot x1\right)\right), \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right)} + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                    6. Taylor expanded in x1 around inf

                                                      \[\leadsto x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\color{blue}{6 \cdot {x1}^{2}}, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                    7. Step-by-step derivation
                                                      1. unpow2N/A

                                                        \[\leadsto x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(6 \cdot \color{blue}{\left(x1 \cdot x1\right)}, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                      2. associate-*r*N/A

                                                        \[\leadsto x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\color{blue}{\left(6 \cdot x1\right) \cdot x1}, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                      3. lower-*.f64N/A

                                                        \[\leadsto x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\color{blue}{\left(6 \cdot x1\right) \cdot x1}, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                      4. lower-*.f6492.9

                                                        \[\leadsto x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\color{blue}{\left(6 \cdot x1\right)} \cdot x1, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                    8. Applied rewrites92.9%

                                                      \[\leadsto x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\color{blue}{\left(6 \cdot x1\right) \cdot x1}, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]

                                                    if 4.79999999999999959e-180 < x1 < 8500

                                                    1. Initial program 99.6%

                                                      \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                    2. Add Preprocessing
                                                    3. Taylor expanded in x1 around inf

                                                      \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{3}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                    4. Step-by-step derivation
                                                      1. Applied rewrites99.6%

                                                        \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{3}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                      2. Taylor expanded in x1 around 0

                                                        \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\left(-2 \cdot x2 + -1 \cdot x1\right)}\right) \]
                                                      3. Step-by-step derivation
                                                        1. mul-1-negN/A

                                                          \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \left(-2 \cdot x2 + \color{blue}{\left(\mathsf{neg}\left(x1\right)\right)}\right)\right) \]
                                                        2. lower-fma.f64N/A

                                                          \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\mathsf{fma}\left(-2, x2, \mathsf{neg}\left(x1\right)\right)}\right) \]
                                                        3. lower-neg.f6499.6

                                                          \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, \color{blue}{-x1}\right)\right) \]
                                                      4. Applied rewrites99.6%

                                                        \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\mathsf{fma}\left(-2, x2, -x1\right)}\right) \]
                                                      5. Taylor expanded in x2 around inf

                                                        \[\leadsto x1 + \left(\left(\color{blue}{8 \cdot \frac{x1 \cdot {x2}^{2}}{1 + {x1}^{2}}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                      6. Step-by-step derivation
                                                        1. associate-*r/N/A

                                                          \[\leadsto x1 + \left(\left(\color{blue}{\frac{8 \cdot \left(x1 \cdot {x2}^{2}\right)}{1 + {x1}^{2}}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                        2. lower-/.f64N/A

                                                          \[\leadsto x1 + \left(\left(\color{blue}{\frac{8 \cdot \left(x1 \cdot {x2}^{2}\right)}{1 + {x1}^{2}}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                        3. lower-*.f64N/A

                                                          \[\leadsto x1 + \left(\left(\frac{\color{blue}{8 \cdot \left(x1 \cdot {x2}^{2}\right)}}{1 + {x1}^{2}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                        4. *-commutativeN/A

                                                          \[\leadsto x1 + \left(\left(\frac{8 \cdot \color{blue}{\left({x2}^{2} \cdot x1\right)}}{1 + {x1}^{2}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                        5. lower-*.f64N/A

                                                          \[\leadsto x1 + \left(\left(\frac{8 \cdot \color{blue}{\left({x2}^{2} \cdot x1\right)}}{1 + {x1}^{2}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                        6. unpow2N/A

                                                          \[\leadsto x1 + \left(\left(\frac{8 \cdot \left(\color{blue}{\left(x2 \cdot x2\right)} \cdot x1\right)}{1 + {x1}^{2}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                        7. lower-*.f64N/A

                                                          \[\leadsto x1 + \left(\left(\frac{8 \cdot \left(\color{blue}{\left(x2 \cdot x2\right)} \cdot x1\right)}{1 + {x1}^{2}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                        8. +-commutativeN/A

                                                          \[\leadsto x1 + \left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\color{blue}{{x1}^{2} + 1}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                        9. unpow2N/A

                                                          \[\leadsto x1 + \left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\color{blue}{x1 \cdot x1} + 1} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                        10. lower-fma.f6494.0

                                                          \[\leadsto x1 + \left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\color{blue}{\mathsf{fma}\left(x1, x1, 1\right)}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                      7. Applied rewrites94.0%

                                                        \[\leadsto x1 + \left(\left(\color{blue}{\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\mathsf{fma}\left(x1, x1, 1\right)}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]

                                                      if 8500 < x1

                                                      1. Initial program 52.7%

                                                        \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                      2. Add Preprocessing
                                                      3. Taylor expanded in x1 around inf

                                                        \[\leadsto \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                                                      4. Step-by-step derivation
                                                        1. *-commutativeN/A

                                                          \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                        2. lower-*.f64N/A

                                                          \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                      5. Applied rewrites95.8%

                                                        \[\leadsto \color{blue}{\left(\frac{\mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)}{x1 \cdot x1} + \left(6 - \frac{3}{x1}\right)\right) \cdot {x1}^{4}} \]
                                                      6. Taylor expanded in x2 around inf

                                                        \[\leadsto 8 \cdot \color{blue}{\left({x1}^{2} \cdot x2\right)} \]
                                                      7. Step-by-step derivation
                                                        1. Applied rewrites36.9%

                                                          \[\leadsto \left(\left(x1 \cdot x1\right) \cdot x2\right) \cdot \color{blue}{8} \]
                                                        2. Step-by-step derivation
                                                          1. Applied rewrites30.2%

                                                            \[\leadsto \left(\left(x2 \cdot x1\right) \cdot x1\right) \cdot 8 \]
                                                          2. Taylor expanded in x1 around 0

                                                            \[\leadsto {x1}^{2} \cdot \color{blue}{\left(9 + \left(4 \cdot \left(2 \cdot x2 - 3\right) + x1 \cdot \left(6 \cdot x1 - 3\right)\right)\right)} \]
                                                          3. Step-by-step derivation
                                                            1. Applied rewrites95.9%

                                                              \[\leadsto \left(\mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)\right) \cdot x1\right) \cdot \color{blue}{x1} \]
                                                          4. Recombined 5 regimes into one program.
                                                          5. Add Preprocessing

                                                          Alternative 9: 91.6% accurate, 3.4× speedup?

                                                          \[\begin{array}{l} \\ \begin{array}{l} t_0 := 2 \cdot x2 - 3\\ t_1 := \mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(t\_0, 4, 9\right)\right)\\ t_2 := 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\\ \mathbf{if}\;x1 \leq -27:\\ \;\;\;\;t\_1 \cdot \left(x1 \cdot x1\right)\\ \mathbf{elif}\;x1 \leq -1.5 \cdot 10^{-229}:\\ \;\;\;\;x1 + \left(\mathsf{fma}\left(t\_0 \cdot x2, 4, 1\right) \cdot x1 + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right)\\ \mathbf{elif}\;x1 \leq 4.8 \cdot 10^{-180}:\\ \;\;\;\;x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\left(6 \cdot x1\right) \cdot x1, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + t\_2\right)\\ \mathbf{elif}\;x1 \leq 8500:\\ \;\;\;\;x1 + \left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\mathsf{fma}\left(x1, x1, 1\right)} + x1\right) + t\_2\right)\\ \mathbf{else}:\\ \;\;\;\;\left(t\_1 \cdot x1\right) \cdot x1\\ \end{array} \end{array} \]
                                                          (FPCore (x1 x2)
                                                           :precision binary64
                                                           (let* ((t_0 (- (* 2.0 x2) 3.0))
                                                                  (t_1 (fma (- (* 6.0 x1) 3.0) x1 (fma t_0 4.0 9.0)))
                                                                  (t_2 (* 3.0 (fma -2.0 x2 (- x1)))))
                                                             (if (<= x1 -27.0)
                                                               (* t_1 (* x1 x1))
                                                               (if (<= x1 -1.5e-229)
                                                                 (+
                                                                  x1
                                                                  (+
                                                                   (* (fma (* t_0 x2) 4.0 1.0) x1)
                                                                   (*
                                                                    3.0
                                                                    (/ (- (- (* (* 3.0 x1) x1) (* 2.0 x2)) x1) (+ (* x1 x1) 1.0)))))
                                                                 (if (<= x1 4.8e-180)
                                                                   (+
                                                                    x1
                                                                    (+
                                                                     (fma
                                                                      (fma x1 x1 1.0)
                                                                      x1
                                                                      (fma (* (* 6.0 x1) x1) (fma x1 x1 1.0) (* (* 3.0 3.0) (* x1 x1))))
                                                                     t_2))
                                                                   (if (<= x1 8500.0)
                                                                     (+ x1 (+ (+ (/ (* 8.0 (* (* x2 x2) x1)) (fma x1 x1 1.0)) x1) t_2))
                                                                     (* (* t_1 x1) x1)))))))
                                                          double code(double x1, double x2) {
                                                          	double t_0 = (2.0 * x2) - 3.0;
                                                          	double t_1 = fma(((6.0 * x1) - 3.0), x1, fma(t_0, 4.0, 9.0));
                                                          	double t_2 = 3.0 * fma(-2.0, x2, -x1);
                                                          	double tmp;
                                                          	if (x1 <= -27.0) {
                                                          		tmp = t_1 * (x1 * x1);
                                                          	} else if (x1 <= -1.5e-229) {
                                                          		tmp = x1 + ((fma((t_0 * x2), 4.0, 1.0) * x1) + (3.0 * (((((3.0 * x1) * x1) - (2.0 * x2)) - x1) / ((x1 * x1) + 1.0))));
                                                          	} else if (x1 <= 4.8e-180) {
                                                          		tmp = x1 + (fma(fma(x1, x1, 1.0), x1, fma(((6.0 * x1) * x1), fma(x1, x1, 1.0), ((3.0 * 3.0) * (x1 * x1)))) + t_2);
                                                          	} else if (x1 <= 8500.0) {
                                                          		tmp = x1 + ((((8.0 * ((x2 * x2) * x1)) / fma(x1, x1, 1.0)) + x1) + t_2);
                                                          	} else {
                                                          		tmp = (t_1 * x1) * x1;
                                                          	}
                                                          	return tmp;
                                                          }
                                                          
                                                          function code(x1, x2)
                                                          	t_0 = Float64(Float64(2.0 * x2) - 3.0)
                                                          	t_1 = fma(Float64(Float64(6.0 * x1) - 3.0), x1, fma(t_0, 4.0, 9.0))
                                                          	t_2 = Float64(3.0 * fma(-2.0, x2, Float64(-x1)))
                                                          	tmp = 0.0
                                                          	if (x1 <= -27.0)
                                                          		tmp = Float64(t_1 * Float64(x1 * x1));
                                                          	elseif (x1 <= -1.5e-229)
                                                          		tmp = Float64(x1 + Float64(Float64(fma(Float64(t_0 * x2), 4.0, 1.0) * x1) + Float64(3.0 * Float64(Float64(Float64(Float64(Float64(3.0 * x1) * x1) - Float64(2.0 * x2)) - x1) / Float64(Float64(x1 * x1) + 1.0)))));
                                                          	elseif (x1 <= 4.8e-180)
                                                          		tmp = Float64(x1 + Float64(fma(fma(x1, x1, 1.0), x1, fma(Float64(Float64(6.0 * x1) * x1), fma(x1, x1, 1.0), Float64(Float64(3.0 * 3.0) * Float64(x1 * x1)))) + t_2));
                                                          	elseif (x1 <= 8500.0)
                                                          		tmp = Float64(x1 + Float64(Float64(Float64(Float64(8.0 * Float64(Float64(x2 * x2) * x1)) / fma(x1, x1, 1.0)) + x1) + t_2));
                                                          	else
                                                          		tmp = Float64(Float64(t_1 * x1) * x1);
                                                          	end
                                                          	return tmp
                                                          end
                                                          
                                                          code[x1_, x2_] := Block[{t$95$0 = N[(N[(2.0 * x2), $MachinePrecision] - 3.0), $MachinePrecision]}, Block[{t$95$1 = N[(N[(N[(6.0 * x1), $MachinePrecision] - 3.0), $MachinePrecision] * x1 + N[(t$95$0 * 4.0 + 9.0), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(3.0 * N[(-2.0 * x2 + (-x1)), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[x1, -27.0], N[(t$95$1 * N[(x1 * x1), $MachinePrecision]), $MachinePrecision], If[LessEqual[x1, -1.5e-229], N[(x1 + N[(N[(N[(N[(t$95$0 * x2), $MachinePrecision] * 4.0 + 1.0), $MachinePrecision] * x1), $MachinePrecision] + N[(3.0 * N[(N[(N[(N[(N[(3.0 * x1), $MachinePrecision] * x1), $MachinePrecision] - N[(2.0 * x2), $MachinePrecision]), $MachinePrecision] - x1), $MachinePrecision] / N[(N[(x1 * x1), $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[x1, 4.8e-180], N[(x1 + N[(N[(N[(x1 * x1 + 1.0), $MachinePrecision] * x1 + N[(N[(N[(6.0 * x1), $MachinePrecision] * x1), $MachinePrecision] * N[(x1 * x1 + 1.0), $MachinePrecision] + N[(N[(3.0 * 3.0), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + t$95$2), $MachinePrecision]), $MachinePrecision], If[LessEqual[x1, 8500.0], N[(x1 + N[(N[(N[(N[(8.0 * N[(N[(x2 * x2), $MachinePrecision] * x1), $MachinePrecision]), $MachinePrecision] / N[(x1 * x1 + 1.0), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision] + t$95$2), $MachinePrecision]), $MachinePrecision], N[(N[(t$95$1 * x1), $MachinePrecision] * x1), $MachinePrecision]]]]]]]]
                                                          
                                                          \begin{array}{l}
                                                          
                                                          \\
                                                          \begin{array}{l}
                                                          t_0 := 2 \cdot x2 - 3\\
                                                          t_1 := \mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(t\_0, 4, 9\right)\right)\\
                                                          t_2 := 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\\
                                                          \mathbf{if}\;x1 \leq -27:\\
                                                          \;\;\;\;t\_1 \cdot \left(x1 \cdot x1\right)\\
                                                          
                                                          \mathbf{elif}\;x1 \leq -1.5 \cdot 10^{-229}:\\
                                                          \;\;\;\;x1 + \left(\mathsf{fma}\left(t\_0 \cdot x2, 4, 1\right) \cdot x1 + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right)\\
                                                          
                                                          \mathbf{elif}\;x1 \leq 4.8 \cdot 10^{-180}:\\
                                                          \;\;\;\;x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\left(6 \cdot x1\right) \cdot x1, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + t\_2\right)\\
                                                          
                                                          \mathbf{elif}\;x1 \leq 8500:\\
                                                          \;\;\;\;x1 + \left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\mathsf{fma}\left(x1, x1, 1\right)} + x1\right) + t\_2\right)\\
                                                          
                                                          \mathbf{else}:\\
                                                          \;\;\;\;\left(t\_1 \cdot x1\right) \cdot x1\\
                                                          
                                                          
                                                          \end{array}
                                                          \end{array}
                                                          
                                                          Derivation
                                                          1. Split input into 5 regimes
                                                          2. if x1 < -27

                                                            1. Initial program 24.1%

                                                              \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                            2. Add Preprocessing
                                                            3. Taylor expanded in x1 around inf

                                                              \[\leadsto \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                                                            4. Step-by-step derivation
                                                              1. *-commutativeN/A

                                                                \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                              2. lower-*.f64N/A

                                                                \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                            5. Applied rewrites96.7%

                                                              \[\leadsto \color{blue}{\left(\frac{\mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)}{x1 \cdot x1} + \left(6 - \frac{3}{x1}\right)\right) \cdot {x1}^{4}} \]
                                                            6. Taylor expanded in x1 around 0

                                                              \[\leadsto {x1}^{2} \cdot \color{blue}{\left(9 + \left(4 \cdot \left(2 \cdot x2 - 3\right) + x1 \cdot \left(6 \cdot x1 - 3\right)\right)\right)} \]
                                                            7. Step-by-step derivation
                                                              1. Applied rewrites96.8%

                                                                \[\leadsto \mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)\right) \cdot \color{blue}{\left(x1 \cdot x1\right)} \]

                                                              if -27 < x1 < -1.50000000000000001e-229

                                                              1. Initial program 99.4%

                                                                \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                              2. Add Preprocessing
                                                              3. Taylor expanded in x1 around inf

                                                                \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{3}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                              4. Step-by-step derivation
                                                                1. Applied rewrites97.2%

                                                                  \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{3}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                2. Taylor expanded in x1 around 0

                                                                  \[\leadsto x1 + \left(\color{blue}{x1 \cdot \left(1 + 4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right)\right)} + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                3. Step-by-step derivation
                                                                  1. *-commutativeN/A

                                                                    \[\leadsto x1 + \left(\color{blue}{\left(1 + 4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right)\right) \cdot x1} + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                  2. lower-*.f64N/A

                                                                    \[\leadsto x1 + \left(\color{blue}{\left(1 + 4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right)\right) \cdot x1} + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                  3. +-commutativeN/A

                                                                    \[\leadsto x1 + \left(\color{blue}{\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) + 1\right)} \cdot x1 + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                  4. *-commutativeN/A

                                                                    \[\leadsto x1 + \left(\left(\color{blue}{\left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) \cdot 4} + 1\right) \cdot x1 + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                  5. lower-fma.f64N/A

                                                                    \[\leadsto x1 + \left(\color{blue}{\mathsf{fma}\left(x2 \cdot \left(2 \cdot x2 - 3\right), 4, 1\right)} \cdot x1 + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                  6. *-commutativeN/A

                                                                    \[\leadsto x1 + \left(\mathsf{fma}\left(\color{blue}{\left(2 \cdot x2 - 3\right) \cdot x2}, 4, 1\right) \cdot x1 + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                  7. lower-*.f64N/A

                                                                    \[\leadsto x1 + \left(\mathsf{fma}\left(\color{blue}{\left(2 \cdot x2 - 3\right) \cdot x2}, 4, 1\right) \cdot x1 + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                  8. lower--.f64N/A

                                                                    \[\leadsto x1 + \left(\mathsf{fma}\left(\color{blue}{\left(2 \cdot x2 - 3\right)} \cdot x2, 4, 1\right) \cdot x1 + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                  9. lower-*.f6492.0

                                                                    \[\leadsto x1 + \left(\mathsf{fma}\left(\left(\color{blue}{2 \cdot x2} - 3\right) \cdot x2, 4, 1\right) \cdot x1 + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                4. Applied rewrites92.0%

                                                                  \[\leadsto x1 + \left(\color{blue}{\mathsf{fma}\left(\left(2 \cdot x2 - 3\right) \cdot x2, 4, 1\right) \cdot x1} + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]

                                                                if -1.50000000000000001e-229 < x1 < 4.79999999999999959e-180

                                                                1. Initial program 99.7%

                                                                  \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                2. Add Preprocessing
                                                                3. Taylor expanded in x1 around inf

                                                                  \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{3}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                4. Step-by-step derivation
                                                                  1. Applied rewrites99.7%

                                                                    \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{3}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                  2. Taylor expanded in x1 around 0

                                                                    \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\left(-2 \cdot x2 + -1 \cdot x1\right)}\right) \]
                                                                  3. Step-by-step derivation
                                                                    1. mul-1-negN/A

                                                                      \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \left(-2 \cdot x2 + \color{blue}{\left(\mathsf{neg}\left(x1\right)\right)}\right)\right) \]
                                                                    2. lower-fma.f64N/A

                                                                      \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\mathsf{fma}\left(-2, x2, \mathsf{neg}\left(x1\right)\right)}\right) \]
                                                                    3. lower-neg.f6499.7

                                                                      \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, \color{blue}{-x1}\right)\right) \]
                                                                  4. Applied rewrites99.7%

                                                                    \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\mathsf{fma}\left(-2, x2, -x1\right)}\right) \]
                                                                  5. Applied rewrites73.1%

                                                                    \[\leadsto x1 + \left(\color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(\left(\frac{\mathsf{fma}\left(x2, 2, \left(3 \cdot x1\right) \cdot x1\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)} - 3\right) \cdot \frac{\mathsf{fma}\left(x2, 2, \left(3 \cdot x1\right) \cdot x1\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)}, x1 \cdot 2, \left(\frac{4 \cdot \left(\mathsf{fma}\left(x2, 2, \left(3 \cdot x1\right) \cdot x1\right) - x1\right)}{\mathsf{fma}\left(x1, x1, 1\right)} - 6\right) \cdot \left(x1 \cdot x1\right)\right), \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right)} + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                  6. Taylor expanded in x1 around inf

                                                                    \[\leadsto x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\color{blue}{6 \cdot {x1}^{2}}, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                  7. Step-by-step derivation
                                                                    1. unpow2N/A

                                                                      \[\leadsto x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(6 \cdot \color{blue}{\left(x1 \cdot x1\right)}, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                    2. associate-*r*N/A

                                                                      \[\leadsto x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\color{blue}{\left(6 \cdot x1\right) \cdot x1}, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                    3. lower-*.f64N/A

                                                                      \[\leadsto x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\color{blue}{\left(6 \cdot x1\right) \cdot x1}, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                    4. lower-*.f6492.9

                                                                      \[\leadsto x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\color{blue}{\left(6 \cdot x1\right)} \cdot x1, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                  8. Applied rewrites92.9%

                                                                    \[\leadsto x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\color{blue}{\left(6 \cdot x1\right) \cdot x1}, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]

                                                                  if 4.79999999999999959e-180 < x1 < 8500

                                                                  1. Initial program 99.6%

                                                                    \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                  2. Add Preprocessing
                                                                  3. Taylor expanded in x1 around inf

                                                                    \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{3}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                  4. Step-by-step derivation
                                                                    1. Applied rewrites99.6%

                                                                      \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{3}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                    2. Taylor expanded in x1 around 0

                                                                      \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\left(-2 \cdot x2 + -1 \cdot x1\right)}\right) \]
                                                                    3. Step-by-step derivation
                                                                      1. mul-1-negN/A

                                                                        \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \left(-2 \cdot x2 + \color{blue}{\left(\mathsf{neg}\left(x1\right)\right)}\right)\right) \]
                                                                      2. lower-fma.f64N/A

                                                                        \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\mathsf{fma}\left(-2, x2, \mathsf{neg}\left(x1\right)\right)}\right) \]
                                                                      3. lower-neg.f6499.6

                                                                        \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, \color{blue}{-x1}\right)\right) \]
                                                                    4. Applied rewrites99.6%

                                                                      \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\mathsf{fma}\left(-2, x2, -x1\right)}\right) \]
                                                                    5. Taylor expanded in x2 around inf

                                                                      \[\leadsto x1 + \left(\left(\color{blue}{8 \cdot \frac{x1 \cdot {x2}^{2}}{1 + {x1}^{2}}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                    6. Step-by-step derivation
                                                                      1. associate-*r/N/A

                                                                        \[\leadsto x1 + \left(\left(\color{blue}{\frac{8 \cdot \left(x1 \cdot {x2}^{2}\right)}{1 + {x1}^{2}}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                      2. lower-/.f64N/A

                                                                        \[\leadsto x1 + \left(\left(\color{blue}{\frac{8 \cdot \left(x1 \cdot {x2}^{2}\right)}{1 + {x1}^{2}}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                      3. lower-*.f64N/A

                                                                        \[\leadsto x1 + \left(\left(\frac{\color{blue}{8 \cdot \left(x1 \cdot {x2}^{2}\right)}}{1 + {x1}^{2}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                      4. *-commutativeN/A

                                                                        \[\leadsto x1 + \left(\left(\frac{8 \cdot \color{blue}{\left({x2}^{2} \cdot x1\right)}}{1 + {x1}^{2}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                      5. lower-*.f64N/A

                                                                        \[\leadsto x1 + \left(\left(\frac{8 \cdot \color{blue}{\left({x2}^{2} \cdot x1\right)}}{1 + {x1}^{2}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                      6. unpow2N/A

                                                                        \[\leadsto x1 + \left(\left(\frac{8 \cdot \left(\color{blue}{\left(x2 \cdot x2\right)} \cdot x1\right)}{1 + {x1}^{2}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                      7. lower-*.f64N/A

                                                                        \[\leadsto x1 + \left(\left(\frac{8 \cdot \left(\color{blue}{\left(x2 \cdot x2\right)} \cdot x1\right)}{1 + {x1}^{2}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                      8. +-commutativeN/A

                                                                        \[\leadsto x1 + \left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\color{blue}{{x1}^{2} + 1}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                      9. unpow2N/A

                                                                        \[\leadsto x1 + \left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\color{blue}{x1 \cdot x1} + 1} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                      10. lower-fma.f6494.0

                                                                        \[\leadsto x1 + \left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\color{blue}{\mathsf{fma}\left(x1, x1, 1\right)}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                    7. Applied rewrites94.0%

                                                                      \[\leadsto x1 + \left(\left(\color{blue}{\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\mathsf{fma}\left(x1, x1, 1\right)}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]

                                                                    if 8500 < x1

                                                                    1. Initial program 52.7%

                                                                      \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                    2. Add Preprocessing
                                                                    3. Taylor expanded in x1 around inf

                                                                      \[\leadsto \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                                                                    4. Step-by-step derivation
                                                                      1. *-commutativeN/A

                                                                        \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                      2. lower-*.f64N/A

                                                                        \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                    5. Applied rewrites95.8%

                                                                      \[\leadsto \color{blue}{\left(\frac{\mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)}{x1 \cdot x1} + \left(6 - \frac{3}{x1}\right)\right) \cdot {x1}^{4}} \]
                                                                    6. Taylor expanded in x2 around inf

                                                                      \[\leadsto 8 \cdot \color{blue}{\left({x1}^{2} \cdot x2\right)} \]
                                                                    7. Step-by-step derivation
                                                                      1. Applied rewrites36.9%

                                                                        \[\leadsto \left(\left(x1 \cdot x1\right) \cdot x2\right) \cdot \color{blue}{8} \]
                                                                      2. Step-by-step derivation
                                                                        1. Applied rewrites30.2%

                                                                          \[\leadsto \left(\left(x2 \cdot x1\right) \cdot x1\right) \cdot 8 \]
                                                                        2. Taylor expanded in x1 around 0

                                                                          \[\leadsto {x1}^{2} \cdot \color{blue}{\left(9 + \left(4 \cdot \left(2 \cdot x2 - 3\right) + x1 \cdot \left(6 \cdot x1 - 3\right)\right)\right)} \]
                                                                        3. Step-by-step derivation
                                                                          1. Applied rewrites95.9%

                                                                            \[\leadsto \left(\mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)\right) \cdot x1\right) \cdot \color{blue}{x1} \]
                                                                        4. Recombined 5 regimes into one program.
                                                                        5. Add Preprocessing

                                                                        Alternative 10: 91.6% accurate, 3.4× speedup?

                                                                        \[\begin{array}{l} \\ \begin{array}{l} t_0 := 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\\ t_1 := 2 \cdot x2 - 3\\ t_2 := \mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(t\_1, 4, 9\right)\right)\\ \mathbf{if}\;x1 \leq -27:\\ \;\;\;\;t\_2 \cdot \left(x1 \cdot x1\right)\\ \mathbf{elif}\;x1 \leq -1.5 \cdot 10^{-229}:\\ \;\;\;\;\mathsf{fma}\left(\left(t\_1 \cdot x2\right) \cdot 4 - 1, x1, -6 \cdot x2\right)\\ \mathbf{elif}\;x1 \leq 4.8 \cdot 10^{-180}:\\ \;\;\;\;x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\left(6 \cdot x1\right) \cdot x1, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + t\_0\right)\\ \mathbf{elif}\;x1 \leq 8500:\\ \;\;\;\;x1 + \left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\mathsf{fma}\left(x1, x1, 1\right)} + x1\right) + t\_0\right)\\ \mathbf{else}:\\ \;\;\;\;\left(t\_2 \cdot x1\right) \cdot x1\\ \end{array} \end{array} \]
                                                                        (FPCore (x1 x2)
                                                                         :precision binary64
                                                                         (let* ((t_0 (* 3.0 (fma -2.0 x2 (- x1))))
                                                                                (t_1 (- (* 2.0 x2) 3.0))
                                                                                (t_2 (fma (- (* 6.0 x1) 3.0) x1 (fma t_1 4.0 9.0))))
                                                                           (if (<= x1 -27.0)
                                                                             (* t_2 (* x1 x1))
                                                                             (if (<= x1 -1.5e-229)
                                                                               (fma (- (* (* t_1 x2) 4.0) 1.0) x1 (* -6.0 x2))
                                                                               (if (<= x1 4.8e-180)
                                                                                 (+
                                                                                  x1
                                                                                  (+
                                                                                   (fma
                                                                                    (fma x1 x1 1.0)
                                                                                    x1
                                                                                    (fma (* (* 6.0 x1) x1) (fma x1 x1 1.0) (* (* 3.0 3.0) (* x1 x1))))
                                                                                   t_0))
                                                                                 (if (<= x1 8500.0)
                                                                                   (+ x1 (+ (+ (/ (* 8.0 (* (* x2 x2) x1)) (fma x1 x1 1.0)) x1) t_0))
                                                                                   (* (* t_2 x1) x1)))))))
                                                                        double code(double x1, double x2) {
                                                                        	double t_0 = 3.0 * fma(-2.0, x2, -x1);
                                                                        	double t_1 = (2.0 * x2) - 3.0;
                                                                        	double t_2 = fma(((6.0 * x1) - 3.0), x1, fma(t_1, 4.0, 9.0));
                                                                        	double tmp;
                                                                        	if (x1 <= -27.0) {
                                                                        		tmp = t_2 * (x1 * x1);
                                                                        	} else if (x1 <= -1.5e-229) {
                                                                        		tmp = fma((((t_1 * x2) * 4.0) - 1.0), x1, (-6.0 * x2));
                                                                        	} else if (x1 <= 4.8e-180) {
                                                                        		tmp = x1 + (fma(fma(x1, x1, 1.0), x1, fma(((6.0 * x1) * x1), fma(x1, x1, 1.0), ((3.0 * 3.0) * (x1 * x1)))) + t_0);
                                                                        	} else if (x1 <= 8500.0) {
                                                                        		tmp = x1 + ((((8.0 * ((x2 * x2) * x1)) / fma(x1, x1, 1.0)) + x1) + t_0);
                                                                        	} else {
                                                                        		tmp = (t_2 * x1) * x1;
                                                                        	}
                                                                        	return tmp;
                                                                        }
                                                                        
                                                                        function code(x1, x2)
                                                                        	t_0 = Float64(3.0 * fma(-2.0, x2, Float64(-x1)))
                                                                        	t_1 = Float64(Float64(2.0 * x2) - 3.0)
                                                                        	t_2 = fma(Float64(Float64(6.0 * x1) - 3.0), x1, fma(t_1, 4.0, 9.0))
                                                                        	tmp = 0.0
                                                                        	if (x1 <= -27.0)
                                                                        		tmp = Float64(t_2 * Float64(x1 * x1));
                                                                        	elseif (x1 <= -1.5e-229)
                                                                        		tmp = fma(Float64(Float64(Float64(t_1 * x2) * 4.0) - 1.0), x1, Float64(-6.0 * x2));
                                                                        	elseif (x1 <= 4.8e-180)
                                                                        		tmp = Float64(x1 + Float64(fma(fma(x1, x1, 1.0), x1, fma(Float64(Float64(6.0 * x1) * x1), fma(x1, x1, 1.0), Float64(Float64(3.0 * 3.0) * Float64(x1 * x1)))) + t_0));
                                                                        	elseif (x1 <= 8500.0)
                                                                        		tmp = Float64(x1 + Float64(Float64(Float64(Float64(8.0 * Float64(Float64(x2 * x2) * x1)) / fma(x1, x1, 1.0)) + x1) + t_0));
                                                                        	else
                                                                        		tmp = Float64(Float64(t_2 * x1) * x1);
                                                                        	end
                                                                        	return tmp
                                                                        end
                                                                        
                                                                        code[x1_, x2_] := Block[{t$95$0 = N[(3.0 * N[(-2.0 * x2 + (-x1)), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(2.0 * x2), $MachinePrecision] - 3.0), $MachinePrecision]}, Block[{t$95$2 = N[(N[(N[(6.0 * x1), $MachinePrecision] - 3.0), $MachinePrecision] * x1 + N[(t$95$1 * 4.0 + 9.0), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[x1, -27.0], N[(t$95$2 * N[(x1 * x1), $MachinePrecision]), $MachinePrecision], If[LessEqual[x1, -1.5e-229], N[(N[(N[(N[(t$95$1 * x2), $MachinePrecision] * 4.0), $MachinePrecision] - 1.0), $MachinePrecision] * x1 + N[(-6.0 * x2), $MachinePrecision]), $MachinePrecision], If[LessEqual[x1, 4.8e-180], N[(x1 + N[(N[(N[(x1 * x1 + 1.0), $MachinePrecision] * x1 + N[(N[(N[(6.0 * x1), $MachinePrecision] * x1), $MachinePrecision] * N[(x1 * x1 + 1.0), $MachinePrecision] + N[(N[(3.0 * 3.0), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + t$95$0), $MachinePrecision]), $MachinePrecision], If[LessEqual[x1, 8500.0], N[(x1 + N[(N[(N[(N[(8.0 * N[(N[(x2 * x2), $MachinePrecision] * x1), $MachinePrecision]), $MachinePrecision] / N[(x1 * x1 + 1.0), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision] + t$95$0), $MachinePrecision]), $MachinePrecision], N[(N[(t$95$2 * x1), $MachinePrecision] * x1), $MachinePrecision]]]]]]]]
                                                                        
                                                                        \begin{array}{l}
                                                                        
                                                                        \\
                                                                        \begin{array}{l}
                                                                        t_0 := 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\\
                                                                        t_1 := 2 \cdot x2 - 3\\
                                                                        t_2 := \mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(t\_1, 4, 9\right)\right)\\
                                                                        \mathbf{if}\;x1 \leq -27:\\
                                                                        \;\;\;\;t\_2 \cdot \left(x1 \cdot x1\right)\\
                                                                        
                                                                        \mathbf{elif}\;x1 \leq -1.5 \cdot 10^{-229}:\\
                                                                        \;\;\;\;\mathsf{fma}\left(\left(t\_1 \cdot x2\right) \cdot 4 - 1, x1, -6 \cdot x2\right)\\
                                                                        
                                                                        \mathbf{elif}\;x1 \leq 4.8 \cdot 10^{-180}:\\
                                                                        \;\;\;\;x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\left(6 \cdot x1\right) \cdot x1, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + t\_0\right)\\
                                                                        
                                                                        \mathbf{elif}\;x1 \leq 8500:\\
                                                                        \;\;\;\;x1 + \left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\mathsf{fma}\left(x1, x1, 1\right)} + x1\right) + t\_0\right)\\
                                                                        
                                                                        \mathbf{else}:\\
                                                                        \;\;\;\;\left(t\_2 \cdot x1\right) \cdot x1\\
                                                                        
                                                                        
                                                                        \end{array}
                                                                        \end{array}
                                                                        
                                                                        Derivation
                                                                        1. Split input into 5 regimes
                                                                        2. if x1 < -27

                                                                          1. Initial program 24.1%

                                                                            \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                          2. Add Preprocessing
                                                                          3. Taylor expanded in x1 around inf

                                                                            \[\leadsto \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                                                                          4. Step-by-step derivation
                                                                            1. *-commutativeN/A

                                                                              \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                            2. lower-*.f64N/A

                                                                              \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                          5. Applied rewrites96.7%

                                                                            \[\leadsto \color{blue}{\left(\frac{\mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)}{x1 \cdot x1} + \left(6 - \frac{3}{x1}\right)\right) \cdot {x1}^{4}} \]
                                                                          6. Taylor expanded in x1 around 0

                                                                            \[\leadsto {x1}^{2} \cdot \color{blue}{\left(9 + \left(4 \cdot \left(2 \cdot x2 - 3\right) + x1 \cdot \left(6 \cdot x1 - 3\right)\right)\right)} \]
                                                                          7. Step-by-step derivation
                                                                            1. Applied rewrites96.8%

                                                                              \[\leadsto \mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)\right) \cdot \color{blue}{\left(x1 \cdot x1\right)} \]

                                                                            if -27 < x1 < -1.50000000000000001e-229

                                                                            1. Initial program 99.4%

                                                                              \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                            2. Add Preprocessing
                                                                            3. Taylor expanded in x1 around 0

                                                                              \[\leadsto \color{blue}{-6 \cdot x2 + x1 \cdot \left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 1\right)} \]
                                                                            4. Step-by-step derivation
                                                                              1. +-commutativeN/A

                                                                                \[\leadsto \color{blue}{x1 \cdot \left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 1\right) + -6 \cdot x2} \]
                                                                              2. *-commutativeN/A

                                                                                \[\leadsto \color{blue}{\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 1\right) \cdot x1} + -6 \cdot x2 \]
                                                                              3. lower-fma.f64N/A

                                                                                \[\leadsto \color{blue}{\mathsf{fma}\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 1, x1, -6 \cdot x2\right)} \]
                                                                              4. lower--.f64N/A

                                                                                \[\leadsto \mathsf{fma}\left(\color{blue}{4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 1}, x1, -6 \cdot x2\right) \]
                                                                              5. *-commutativeN/A

                                                                                \[\leadsto \mathsf{fma}\left(\color{blue}{\left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) \cdot 4} - 1, x1, -6 \cdot x2\right) \]
                                                                              6. lower-*.f64N/A

                                                                                \[\leadsto \mathsf{fma}\left(\color{blue}{\left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) \cdot 4} - 1, x1, -6 \cdot x2\right) \]
                                                                              7. *-commutativeN/A

                                                                                \[\leadsto \mathsf{fma}\left(\color{blue}{\left(\left(2 \cdot x2 - 3\right) \cdot x2\right)} \cdot 4 - 1, x1, -6 \cdot x2\right) \]
                                                                              8. lower-*.f64N/A

                                                                                \[\leadsto \mathsf{fma}\left(\color{blue}{\left(\left(2 \cdot x2 - 3\right) \cdot x2\right)} \cdot 4 - 1, x1, -6 \cdot x2\right) \]
                                                                              9. lower--.f64N/A

                                                                                \[\leadsto \mathsf{fma}\left(\left(\color{blue}{\left(2 \cdot x2 - 3\right)} \cdot x2\right) \cdot 4 - 1, x1, -6 \cdot x2\right) \]
                                                                              10. lower-*.f64N/A

                                                                                \[\leadsto \mathsf{fma}\left(\left(\left(\color{blue}{2 \cdot x2} - 3\right) \cdot x2\right) \cdot 4 - 1, x1, -6 \cdot x2\right) \]
                                                                              11. lower-*.f6490.8

                                                                                \[\leadsto \mathsf{fma}\left(\left(\left(2 \cdot x2 - 3\right) \cdot x2\right) \cdot 4 - 1, x1, \color{blue}{-6 \cdot x2}\right) \]
                                                                            5. Applied rewrites90.8%

                                                                              \[\leadsto \color{blue}{\mathsf{fma}\left(\left(\left(2 \cdot x2 - 3\right) \cdot x2\right) \cdot 4 - 1, x1, -6 \cdot x2\right)} \]

                                                                            if -1.50000000000000001e-229 < x1 < 4.79999999999999959e-180

                                                                            1. Initial program 99.7%

                                                                              \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                            2. Add Preprocessing
                                                                            3. Taylor expanded in x1 around inf

                                                                              \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{3}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                            4. Step-by-step derivation
                                                                              1. Applied rewrites99.7%

                                                                                \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{3}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                              2. Taylor expanded in x1 around 0

                                                                                \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\left(-2 \cdot x2 + -1 \cdot x1\right)}\right) \]
                                                                              3. Step-by-step derivation
                                                                                1. mul-1-negN/A

                                                                                  \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \left(-2 \cdot x2 + \color{blue}{\left(\mathsf{neg}\left(x1\right)\right)}\right)\right) \]
                                                                                2. lower-fma.f64N/A

                                                                                  \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\mathsf{fma}\left(-2, x2, \mathsf{neg}\left(x1\right)\right)}\right) \]
                                                                                3. lower-neg.f6499.7

                                                                                  \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, \color{blue}{-x1}\right)\right) \]
                                                                              4. Applied rewrites99.7%

                                                                                \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\mathsf{fma}\left(-2, x2, -x1\right)}\right) \]
                                                                              5. Applied rewrites73.1%

                                                                                \[\leadsto x1 + \left(\color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(\left(\frac{\mathsf{fma}\left(x2, 2, \left(3 \cdot x1\right) \cdot x1\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)} - 3\right) \cdot \frac{\mathsf{fma}\left(x2, 2, \left(3 \cdot x1\right) \cdot x1\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)}, x1 \cdot 2, \left(\frac{4 \cdot \left(\mathsf{fma}\left(x2, 2, \left(3 \cdot x1\right) \cdot x1\right) - x1\right)}{\mathsf{fma}\left(x1, x1, 1\right)} - 6\right) \cdot \left(x1 \cdot x1\right)\right), \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right)} + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                              6. Taylor expanded in x1 around inf

                                                                                \[\leadsto x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\color{blue}{6 \cdot {x1}^{2}}, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                              7. Step-by-step derivation
                                                                                1. unpow2N/A

                                                                                  \[\leadsto x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(6 \cdot \color{blue}{\left(x1 \cdot x1\right)}, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                                2. associate-*r*N/A

                                                                                  \[\leadsto x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\color{blue}{\left(6 \cdot x1\right) \cdot x1}, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                                3. lower-*.f64N/A

                                                                                  \[\leadsto x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\color{blue}{\left(6 \cdot x1\right) \cdot x1}, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                                4. lower-*.f6492.9

                                                                                  \[\leadsto x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\color{blue}{\left(6 \cdot x1\right)} \cdot x1, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                              8. Applied rewrites92.9%

                                                                                \[\leadsto x1 + \left(\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\color{blue}{\left(6 \cdot x1\right) \cdot x1}, \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]

                                                                              if 4.79999999999999959e-180 < x1 < 8500

                                                                              1. Initial program 99.6%

                                                                                \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                              2. Add Preprocessing
                                                                              3. Taylor expanded in x1 around inf

                                                                                \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{3}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                              4. Step-by-step derivation
                                                                                1. Applied rewrites99.6%

                                                                                  \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{3}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                2. Taylor expanded in x1 around 0

                                                                                  \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\left(-2 \cdot x2 + -1 \cdot x1\right)}\right) \]
                                                                                3. Step-by-step derivation
                                                                                  1. mul-1-negN/A

                                                                                    \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \left(-2 \cdot x2 + \color{blue}{\left(\mathsf{neg}\left(x1\right)\right)}\right)\right) \]
                                                                                  2. lower-fma.f64N/A

                                                                                    \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\mathsf{fma}\left(-2, x2, \mathsf{neg}\left(x1\right)\right)}\right) \]
                                                                                  3. lower-neg.f6499.6

                                                                                    \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, \color{blue}{-x1}\right)\right) \]
                                                                                4. Applied rewrites99.6%

                                                                                  \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\mathsf{fma}\left(-2, x2, -x1\right)}\right) \]
                                                                                5. Taylor expanded in x2 around inf

                                                                                  \[\leadsto x1 + \left(\left(\color{blue}{8 \cdot \frac{x1 \cdot {x2}^{2}}{1 + {x1}^{2}}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                                6. Step-by-step derivation
                                                                                  1. associate-*r/N/A

                                                                                    \[\leadsto x1 + \left(\left(\color{blue}{\frac{8 \cdot \left(x1 \cdot {x2}^{2}\right)}{1 + {x1}^{2}}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                                  2. lower-/.f64N/A

                                                                                    \[\leadsto x1 + \left(\left(\color{blue}{\frac{8 \cdot \left(x1 \cdot {x2}^{2}\right)}{1 + {x1}^{2}}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                                  3. lower-*.f64N/A

                                                                                    \[\leadsto x1 + \left(\left(\frac{\color{blue}{8 \cdot \left(x1 \cdot {x2}^{2}\right)}}{1 + {x1}^{2}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                                  4. *-commutativeN/A

                                                                                    \[\leadsto x1 + \left(\left(\frac{8 \cdot \color{blue}{\left({x2}^{2} \cdot x1\right)}}{1 + {x1}^{2}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                                  5. lower-*.f64N/A

                                                                                    \[\leadsto x1 + \left(\left(\frac{8 \cdot \color{blue}{\left({x2}^{2} \cdot x1\right)}}{1 + {x1}^{2}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                                  6. unpow2N/A

                                                                                    \[\leadsto x1 + \left(\left(\frac{8 \cdot \left(\color{blue}{\left(x2 \cdot x2\right)} \cdot x1\right)}{1 + {x1}^{2}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                                  7. lower-*.f64N/A

                                                                                    \[\leadsto x1 + \left(\left(\frac{8 \cdot \left(\color{blue}{\left(x2 \cdot x2\right)} \cdot x1\right)}{1 + {x1}^{2}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                                  8. +-commutativeN/A

                                                                                    \[\leadsto x1 + \left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\color{blue}{{x1}^{2} + 1}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                                  9. unpow2N/A

                                                                                    \[\leadsto x1 + \left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\color{blue}{x1 \cdot x1} + 1} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                                  10. lower-fma.f6494.0

                                                                                    \[\leadsto x1 + \left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\color{blue}{\mathsf{fma}\left(x1, x1, 1\right)}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                                7. Applied rewrites94.0%

                                                                                  \[\leadsto x1 + \left(\left(\color{blue}{\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\mathsf{fma}\left(x1, x1, 1\right)}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]

                                                                                if 8500 < x1

                                                                                1. Initial program 52.7%

                                                                                  \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                2. Add Preprocessing
                                                                                3. Taylor expanded in x1 around inf

                                                                                  \[\leadsto \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                                                                                4. Step-by-step derivation
                                                                                  1. *-commutativeN/A

                                                                                    \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                  2. lower-*.f64N/A

                                                                                    \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                5. Applied rewrites95.8%

                                                                                  \[\leadsto \color{blue}{\left(\frac{\mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)}{x1 \cdot x1} + \left(6 - \frac{3}{x1}\right)\right) \cdot {x1}^{4}} \]
                                                                                6. Taylor expanded in x2 around inf

                                                                                  \[\leadsto 8 \cdot \color{blue}{\left({x1}^{2} \cdot x2\right)} \]
                                                                                7. Step-by-step derivation
                                                                                  1. Applied rewrites36.9%

                                                                                    \[\leadsto \left(\left(x1 \cdot x1\right) \cdot x2\right) \cdot \color{blue}{8} \]
                                                                                  2. Step-by-step derivation
                                                                                    1. Applied rewrites30.2%

                                                                                      \[\leadsto \left(\left(x2 \cdot x1\right) \cdot x1\right) \cdot 8 \]
                                                                                    2. Taylor expanded in x1 around 0

                                                                                      \[\leadsto {x1}^{2} \cdot \color{blue}{\left(9 + \left(4 \cdot \left(2 \cdot x2 - 3\right) + x1 \cdot \left(6 \cdot x1 - 3\right)\right)\right)} \]
                                                                                    3. Step-by-step derivation
                                                                                      1. Applied rewrites95.9%

                                                                                        \[\leadsto \left(\mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)\right) \cdot x1\right) \cdot \color{blue}{x1} \]
                                                                                    4. Recombined 5 regimes into one program.
                                                                                    5. Add Preprocessing

                                                                                    Alternative 11: 90.2% accurate, 4.4× speedup?

                                                                                    \[\begin{array}{l} \\ \begin{array}{l} t_0 := \mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)\right)\\ \mathbf{if}\;x1 \leq -3700000:\\ \;\;\;\;t\_0 \cdot \left(x1 \cdot x1\right)\\ \mathbf{elif}\;x1 \leq 8500:\\ \;\;\;\;x1 + \left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\mathsf{fma}\left(x1, x1, 1\right)} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right)\\ \mathbf{else}:\\ \;\;\;\;\left(t\_0 \cdot x1\right) \cdot x1\\ \end{array} \end{array} \]
                                                                                    (FPCore (x1 x2)
                                                                                     :precision binary64
                                                                                     (let* ((t_0 (fma (- (* 6.0 x1) 3.0) x1 (fma (- (* 2.0 x2) 3.0) 4.0 9.0))))
                                                                                       (if (<= x1 -3700000.0)
                                                                                         (* t_0 (* x1 x1))
                                                                                         (if (<= x1 8500.0)
                                                                                           (+
                                                                                            x1
                                                                                            (+
                                                                                             (+ (/ (* 8.0 (* (* x2 x2) x1)) (fma x1 x1 1.0)) x1)
                                                                                             (* 3.0 (fma -2.0 x2 (- x1)))))
                                                                                           (* (* t_0 x1) x1)))))
                                                                                    double code(double x1, double x2) {
                                                                                    	double t_0 = fma(((6.0 * x1) - 3.0), x1, fma(((2.0 * x2) - 3.0), 4.0, 9.0));
                                                                                    	double tmp;
                                                                                    	if (x1 <= -3700000.0) {
                                                                                    		tmp = t_0 * (x1 * x1);
                                                                                    	} else if (x1 <= 8500.0) {
                                                                                    		tmp = x1 + ((((8.0 * ((x2 * x2) * x1)) / fma(x1, x1, 1.0)) + x1) + (3.0 * fma(-2.0, x2, -x1)));
                                                                                    	} else {
                                                                                    		tmp = (t_0 * x1) * x1;
                                                                                    	}
                                                                                    	return tmp;
                                                                                    }
                                                                                    
                                                                                    function code(x1, x2)
                                                                                    	t_0 = fma(Float64(Float64(6.0 * x1) - 3.0), x1, fma(Float64(Float64(2.0 * x2) - 3.0), 4.0, 9.0))
                                                                                    	tmp = 0.0
                                                                                    	if (x1 <= -3700000.0)
                                                                                    		tmp = Float64(t_0 * Float64(x1 * x1));
                                                                                    	elseif (x1 <= 8500.0)
                                                                                    		tmp = Float64(x1 + Float64(Float64(Float64(Float64(8.0 * Float64(Float64(x2 * x2) * x1)) / fma(x1, x1, 1.0)) + x1) + Float64(3.0 * fma(-2.0, x2, Float64(-x1)))));
                                                                                    	else
                                                                                    		tmp = Float64(Float64(t_0 * x1) * x1);
                                                                                    	end
                                                                                    	return tmp
                                                                                    end
                                                                                    
                                                                                    code[x1_, x2_] := Block[{t$95$0 = N[(N[(N[(6.0 * x1), $MachinePrecision] - 3.0), $MachinePrecision] * x1 + N[(N[(N[(2.0 * x2), $MachinePrecision] - 3.0), $MachinePrecision] * 4.0 + 9.0), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[x1, -3700000.0], N[(t$95$0 * N[(x1 * x1), $MachinePrecision]), $MachinePrecision], If[LessEqual[x1, 8500.0], N[(x1 + N[(N[(N[(N[(8.0 * N[(N[(x2 * x2), $MachinePrecision] * x1), $MachinePrecision]), $MachinePrecision] / N[(x1 * x1 + 1.0), $MachinePrecision]), $MachinePrecision] + x1), $MachinePrecision] + N[(3.0 * N[(-2.0 * x2 + (-x1)), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(t$95$0 * x1), $MachinePrecision] * x1), $MachinePrecision]]]]
                                                                                    
                                                                                    \begin{array}{l}
                                                                                    
                                                                                    \\
                                                                                    \begin{array}{l}
                                                                                    t_0 := \mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)\right)\\
                                                                                    \mathbf{if}\;x1 \leq -3700000:\\
                                                                                    \;\;\;\;t\_0 \cdot \left(x1 \cdot x1\right)\\
                                                                                    
                                                                                    \mathbf{elif}\;x1 \leq 8500:\\
                                                                                    \;\;\;\;x1 + \left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\mathsf{fma}\left(x1, x1, 1\right)} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right)\\
                                                                                    
                                                                                    \mathbf{else}:\\
                                                                                    \;\;\;\;\left(t\_0 \cdot x1\right) \cdot x1\\
                                                                                    
                                                                                    
                                                                                    \end{array}
                                                                                    \end{array}
                                                                                    
                                                                                    Derivation
                                                                                    1. Split input into 3 regimes
                                                                                    2. if x1 < -3.7e6

                                                                                      1. Initial program 24.1%

                                                                                        \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                      2. Add Preprocessing
                                                                                      3. Taylor expanded in x1 around inf

                                                                                        \[\leadsto \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                                                                                      4. Step-by-step derivation
                                                                                        1. *-commutativeN/A

                                                                                          \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                        2. lower-*.f64N/A

                                                                                          \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                      5. Applied rewrites96.7%

                                                                                        \[\leadsto \color{blue}{\left(\frac{\mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)}{x1 \cdot x1} + \left(6 - \frac{3}{x1}\right)\right) \cdot {x1}^{4}} \]
                                                                                      6. Taylor expanded in x1 around 0

                                                                                        \[\leadsto {x1}^{2} \cdot \color{blue}{\left(9 + \left(4 \cdot \left(2 \cdot x2 - 3\right) + x1 \cdot \left(6 \cdot x1 - 3\right)\right)\right)} \]
                                                                                      7. Step-by-step derivation
                                                                                        1. Applied rewrites96.8%

                                                                                          \[\leadsto \mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)\right) \cdot \color{blue}{\left(x1 \cdot x1\right)} \]

                                                                                        if -3.7e6 < x1 < 8500

                                                                                        1. Initial program 99.6%

                                                                                          \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                        2. Add Preprocessing
                                                                                        3. Taylor expanded in x1 around inf

                                                                                          \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{3}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                        4. Step-by-step derivation
                                                                                          1. Applied rewrites98.6%

                                                                                            \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{3}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                          2. Taylor expanded in x1 around 0

                                                                                            \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\left(-2 \cdot x2 + -1 \cdot x1\right)}\right) \]
                                                                                          3. Step-by-step derivation
                                                                                            1. mul-1-negN/A

                                                                                              \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \left(-2 \cdot x2 + \color{blue}{\left(\mathsf{neg}\left(x1\right)\right)}\right)\right) \]
                                                                                            2. lower-fma.f64N/A

                                                                                              \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\mathsf{fma}\left(-2, x2, \mathsf{neg}\left(x1\right)\right)}\right) \]
                                                                                            3. lower-neg.f6499.6

                                                                                              \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, \color{blue}{-x1}\right)\right) \]
                                                                                          4. Applied rewrites99.6%

                                                                                            \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\mathsf{fma}\left(-2, x2, -x1\right)}\right) \]
                                                                                          5. Taylor expanded in x2 around inf

                                                                                            \[\leadsto x1 + \left(\left(\color{blue}{8 \cdot \frac{x1 \cdot {x2}^{2}}{1 + {x1}^{2}}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                                          6. Step-by-step derivation
                                                                                            1. associate-*r/N/A

                                                                                              \[\leadsto x1 + \left(\left(\color{blue}{\frac{8 \cdot \left(x1 \cdot {x2}^{2}\right)}{1 + {x1}^{2}}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                                            2. lower-/.f64N/A

                                                                                              \[\leadsto x1 + \left(\left(\color{blue}{\frac{8 \cdot \left(x1 \cdot {x2}^{2}\right)}{1 + {x1}^{2}}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                                            3. lower-*.f64N/A

                                                                                              \[\leadsto x1 + \left(\left(\frac{\color{blue}{8 \cdot \left(x1 \cdot {x2}^{2}\right)}}{1 + {x1}^{2}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                                            4. *-commutativeN/A

                                                                                              \[\leadsto x1 + \left(\left(\frac{8 \cdot \color{blue}{\left({x2}^{2} \cdot x1\right)}}{1 + {x1}^{2}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                                            5. lower-*.f64N/A

                                                                                              \[\leadsto x1 + \left(\left(\frac{8 \cdot \color{blue}{\left({x2}^{2} \cdot x1\right)}}{1 + {x1}^{2}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                                            6. unpow2N/A

                                                                                              \[\leadsto x1 + \left(\left(\frac{8 \cdot \left(\color{blue}{\left(x2 \cdot x2\right)} \cdot x1\right)}{1 + {x1}^{2}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                                            7. lower-*.f64N/A

                                                                                              \[\leadsto x1 + \left(\left(\frac{8 \cdot \left(\color{blue}{\left(x2 \cdot x2\right)} \cdot x1\right)}{1 + {x1}^{2}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                                            8. +-commutativeN/A

                                                                                              \[\leadsto x1 + \left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\color{blue}{{x1}^{2} + 1}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                                            9. unpow2N/A

                                                                                              \[\leadsto x1 + \left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\color{blue}{x1 \cdot x1} + 1} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                                            10. lower-fma.f6485.8

                                                                                              \[\leadsto x1 + \left(\left(\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\color{blue}{\mathsf{fma}\left(x1, x1, 1\right)}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                                          7. Applied rewrites85.8%

                                                                                            \[\leadsto x1 + \left(\left(\color{blue}{\frac{8 \cdot \left(\left(x2 \cdot x2\right) \cdot x1\right)}{\mathsf{fma}\left(x1, x1, 1\right)}} + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]

                                                                                          if 8500 < x1

                                                                                          1. Initial program 52.7%

                                                                                            \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                          2. Add Preprocessing
                                                                                          3. Taylor expanded in x1 around inf

                                                                                            \[\leadsto \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                                                                                          4. Step-by-step derivation
                                                                                            1. *-commutativeN/A

                                                                                              \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                            2. lower-*.f64N/A

                                                                                              \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                          5. Applied rewrites95.8%

                                                                                            \[\leadsto \color{blue}{\left(\frac{\mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)}{x1 \cdot x1} + \left(6 - \frac{3}{x1}\right)\right) \cdot {x1}^{4}} \]
                                                                                          6. Taylor expanded in x2 around inf

                                                                                            \[\leadsto 8 \cdot \color{blue}{\left({x1}^{2} \cdot x2\right)} \]
                                                                                          7. Step-by-step derivation
                                                                                            1. Applied rewrites36.9%

                                                                                              \[\leadsto \left(\left(x1 \cdot x1\right) \cdot x2\right) \cdot \color{blue}{8} \]
                                                                                            2. Step-by-step derivation
                                                                                              1. Applied rewrites30.2%

                                                                                                \[\leadsto \left(\left(x2 \cdot x1\right) \cdot x1\right) \cdot 8 \]
                                                                                              2. Taylor expanded in x1 around 0

                                                                                                \[\leadsto {x1}^{2} \cdot \color{blue}{\left(9 + \left(4 \cdot \left(2 \cdot x2 - 3\right) + x1 \cdot \left(6 \cdot x1 - 3\right)\right)\right)} \]
                                                                                              3. Step-by-step derivation
                                                                                                1. Applied rewrites95.9%

                                                                                                  \[\leadsto \left(\mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)\right) \cdot x1\right) \cdot \color{blue}{x1} \]
                                                                                              4. Recombined 3 regimes into one program.
                                                                                              5. Add Preprocessing

                                                                                              Alternative 12: 90.0% accurate, 5.8× speedup?

                                                                                              \[\begin{array}{l} \\ \begin{array}{l} t_0 := 2 \cdot x2 - 3\\ t_1 := \mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(t\_0, 4, 9\right)\right)\\ \mathbf{if}\;x1 \leq -27:\\ \;\;\;\;t\_1 \cdot \left(x1 \cdot x1\right)\\ \mathbf{elif}\;x1 \leq 8200:\\ \;\;\;\;\mathsf{fma}\left(\left(t\_0 \cdot x2\right) \cdot 4 - 1, x1, -6 \cdot x2\right)\\ \mathbf{else}:\\ \;\;\;\;\left(t\_1 \cdot x1\right) \cdot x1\\ \end{array} \end{array} \]
                                                                                              (FPCore (x1 x2)
                                                                                               :precision binary64
                                                                                               (let* ((t_0 (- (* 2.0 x2) 3.0))
                                                                                                      (t_1 (fma (- (* 6.0 x1) 3.0) x1 (fma t_0 4.0 9.0))))
                                                                                                 (if (<= x1 -27.0)
                                                                                                   (* t_1 (* x1 x1))
                                                                                                   (if (<= x1 8200.0)
                                                                                                     (fma (- (* (* t_0 x2) 4.0) 1.0) x1 (* -6.0 x2))
                                                                                                     (* (* t_1 x1) x1)))))
                                                                                              double code(double x1, double x2) {
                                                                                              	double t_0 = (2.0 * x2) - 3.0;
                                                                                              	double t_1 = fma(((6.0 * x1) - 3.0), x1, fma(t_0, 4.0, 9.0));
                                                                                              	double tmp;
                                                                                              	if (x1 <= -27.0) {
                                                                                              		tmp = t_1 * (x1 * x1);
                                                                                              	} else if (x1 <= 8200.0) {
                                                                                              		tmp = fma((((t_0 * x2) * 4.0) - 1.0), x1, (-6.0 * x2));
                                                                                              	} else {
                                                                                              		tmp = (t_1 * x1) * x1;
                                                                                              	}
                                                                                              	return tmp;
                                                                                              }
                                                                                              
                                                                                              function code(x1, x2)
                                                                                              	t_0 = Float64(Float64(2.0 * x2) - 3.0)
                                                                                              	t_1 = fma(Float64(Float64(6.0 * x1) - 3.0), x1, fma(t_0, 4.0, 9.0))
                                                                                              	tmp = 0.0
                                                                                              	if (x1 <= -27.0)
                                                                                              		tmp = Float64(t_1 * Float64(x1 * x1));
                                                                                              	elseif (x1 <= 8200.0)
                                                                                              		tmp = fma(Float64(Float64(Float64(t_0 * x2) * 4.0) - 1.0), x1, Float64(-6.0 * x2));
                                                                                              	else
                                                                                              		tmp = Float64(Float64(t_1 * x1) * x1);
                                                                                              	end
                                                                                              	return tmp
                                                                                              end
                                                                                              
                                                                                              code[x1_, x2_] := Block[{t$95$0 = N[(N[(2.0 * x2), $MachinePrecision] - 3.0), $MachinePrecision]}, Block[{t$95$1 = N[(N[(N[(6.0 * x1), $MachinePrecision] - 3.0), $MachinePrecision] * x1 + N[(t$95$0 * 4.0 + 9.0), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[x1, -27.0], N[(t$95$1 * N[(x1 * x1), $MachinePrecision]), $MachinePrecision], If[LessEqual[x1, 8200.0], N[(N[(N[(N[(t$95$0 * x2), $MachinePrecision] * 4.0), $MachinePrecision] - 1.0), $MachinePrecision] * x1 + N[(-6.0 * x2), $MachinePrecision]), $MachinePrecision], N[(N[(t$95$1 * x1), $MachinePrecision] * x1), $MachinePrecision]]]]]
                                                                                              
                                                                                              \begin{array}{l}
                                                                                              
                                                                                              \\
                                                                                              \begin{array}{l}
                                                                                              t_0 := 2 \cdot x2 - 3\\
                                                                                              t_1 := \mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(t\_0, 4, 9\right)\right)\\
                                                                                              \mathbf{if}\;x1 \leq -27:\\
                                                                                              \;\;\;\;t\_1 \cdot \left(x1 \cdot x1\right)\\
                                                                                              
                                                                                              \mathbf{elif}\;x1 \leq 8200:\\
                                                                                              \;\;\;\;\mathsf{fma}\left(\left(t\_0 \cdot x2\right) \cdot 4 - 1, x1, -6 \cdot x2\right)\\
                                                                                              
                                                                                              \mathbf{else}:\\
                                                                                              \;\;\;\;\left(t\_1 \cdot x1\right) \cdot x1\\
                                                                                              
                                                                                              
                                                                                              \end{array}
                                                                                              \end{array}
                                                                                              
                                                                                              Derivation
                                                                                              1. Split input into 3 regimes
                                                                                              2. if x1 < -27

                                                                                                1. Initial program 24.1%

                                                                                                  \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                2. Add Preprocessing
                                                                                                3. Taylor expanded in x1 around inf

                                                                                                  \[\leadsto \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                                                                                                4. Step-by-step derivation
                                                                                                  1. *-commutativeN/A

                                                                                                    \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                                  2. lower-*.f64N/A

                                                                                                    \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                                5. Applied rewrites96.7%

                                                                                                  \[\leadsto \color{blue}{\left(\frac{\mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)}{x1 \cdot x1} + \left(6 - \frac{3}{x1}\right)\right) \cdot {x1}^{4}} \]
                                                                                                6. Taylor expanded in x1 around 0

                                                                                                  \[\leadsto {x1}^{2} \cdot \color{blue}{\left(9 + \left(4 \cdot \left(2 \cdot x2 - 3\right) + x1 \cdot \left(6 \cdot x1 - 3\right)\right)\right)} \]
                                                                                                7. Step-by-step derivation
                                                                                                  1. Applied rewrites96.8%

                                                                                                    \[\leadsto \mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)\right) \cdot \color{blue}{\left(x1 \cdot x1\right)} \]

                                                                                                  if -27 < x1 < 8200

                                                                                                  1. Initial program 99.6%

                                                                                                    \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                  2. Add Preprocessing
                                                                                                  3. Taylor expanded in x1 around 0

                                                                                                    \[\leadsto \color{blue}{-6 \cdot x2 + x1 \cdot \left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 1\right)} \]
                                                                                                  4. Step-by-step derivation
                                                                                                    1. +-commutativeN/A

                                                                                                      \[\leadsto \color{blue}{x1 \cdot \left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 1\right) + -6 \cdot x2} \]
                                                                                                    2. *-commutativeN/A

                                                                                                      \[\leadsto \color{blue}{\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 1\right) \cdot x1} + -6 \cdot x2 \]
                                                                                                    3. lower-fma.f64N/A

                                                                                                      \[\leadsto \color{blue}{\mathsf{fma}\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 1, x1, -6 \cdot x2\right)} \]
                                                                                                    4. lower--.f64N/A

                                                                                                      \[\leadsto \mathsf{fma}\left(\color{blue}{4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 1}, x1, -6 \cdot x2\right) \]
                                                                                                    5. *-commutativeN/A

                                                                                                      \[\leadsto \mathsf{fma}\left(\color{blue}{\left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) \cdot 4} - 1, x1, -6 \cdot x2\right) \]
                                                                                                    6. lower-*.f64N/A

                                                                                                      \[\leadsto \mathsf{fma}\left(\color{blue}{\left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) \cdot 4} - 1, x1, -6 \cdot x2\right) \]
                                                                                                    7. *-commutativeN/A

                                                                                                      \[\leadsto \mathsf{fma}\left(\color{blue}{\left(\left(2 \cdot x2 - 3\right) \cdot x2\right)} \cdot 4 - 1, x1, -6 \cdot x2\right) \]
                                                                                                    8. lower-*.f64N/A

                                                                                                      \[\leadsto \mathsf{fma}\left(\color{blue}{\left(\left(2 \cdot x2 - 3\right) \cdot x2\right)} \cdot 4 - 1, x1, -6 \cdot x2\right) \]
                                                                                                    9. lower--.f64N/A

                                                                                                      \[\leadsto \mathsf{fma}\left(\left(\color{blue}{\left(2 \cdot x2 - 3\right)} \cdot x2\right) \cdot 4 - 1, x1, -6 \cdot x2\right) \]
                                                                                                    10. lower-*.f64N/A

                                                                                                      \[\leadsto \mathsf{fma}\left(\left(\left(\color{blue}{2 \cdot x2} - 3\right) \cdot x2\right) \cdot 4 - 1, x1, -6 \cdot x2\right) \]
                                                                                                    11. lower-*.f6485.2

                                                                                                      \[\leadsto \mathsf{fma}\left(\left(\left(2 \cdot x2 - 3\right) \cdot x2\right) \cdot 4 - 1, x1, \color{blue}{-6 \cdot x2}\right) \]
                                                                                                  5. Applied rewrites85.2%

                                                                                                    \[\leadsto \color{blue}{\mathsf{fma}\left(\left(\left(2 \cdot x2 - 3\right) \cdot x2\right) \cdot 4 - 1, x1, -6 \cdot x2\right)} \]

                                                                                                  if 8200 < x1

                                                                                                  1. Initial program 52.7%

                                                                                                    \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                  2. Add Preprocessing
                                                                                                  3. Taylor expanded in x1 around inf

                                                                                                    \[\leadsto \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                                                                                                  4. Step-by-step derivation
                                                                                                    1. *-commutativeN/A

                                                                                                      \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                                    2. lower-*.f64N/A

                                                                                                      \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                                  5. Applied rewrites95.8%

                                                                                                    \[\leadsto \color{blue}{\left(\frac{\mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)}{x1 \cdot x1} + \left(6 - \frac{3}{x1}\right)\right) \cdot {x1}^{4}} \]
                                                                                                  6. Taylor expanded in x2 around inf

                                                                                                    \[\leadsto 8 \cdot \color{blue}{\left({x1}^{2} \cdot x2\right)} \]
                                                                                                  7. Step-by-step derivation
                                                                                                    1. Applied rewrites36.9%

                                                                                                      \[\leadsto \left(\left(x1 \cdot x1\right) \cdot x2\right) \cdot \color{blue}{8} \]
                                                                                                    2. Step-by-step derivation
                                                                                                      1. Applied rewrites30.2%

                                                                                                        \[\leadsto \left(\left(x2 \cdot x1\right) \cdot x1\right) \cdot 8 \]
                                                                                                      2. Taylor expanded in x1 around 0

                                                                                                        \[\leadsto {x1}^{2} \cdot \color{blue}{\left(9 + \left(4 \cdot \left(2 \cdot x2 - 3\right) + x1 \cdot \left(6 \cdot x1 - 3\right)\right)\right)} \]
                                                                                                      3. Step-by-step derivation
                                                                                                        1. Applied rewrites95.9%

                                                                                                          \[\leadsto \left(\mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)\right) \cdot x1\right) \cdot \color{blue}{x1} \]
                                                                                                      4. Recombined 3 regimes into one program.
                                                                                                      5. Add Preprocessing

                                                                                                      Alternative 13: 89.1% accurate, 5.8× speedup?

                                                                                                      \[\begin{array}{l} \\ \begin{array}{l} t_0 := 2 \cdot x2 - 3\\ \mathbf{if}\;x1 \leq -27000:\\ \;\;\;\;\left(\left(6 - \frac{3}{x1}\right) \cdot \left(x1 \cdot x1\right)\right) \cdot \left(x1 \cdot x1\right)\\ \mathbf{elif}\;x1 \leq 8200:\\ \;\;\;\;\mathsf{fma}\left(\left(t\_0 \cdot x2\right) \cdot 4 - 1, x1, -6 \cdot x2\right)\\ \mathbf{else}:\\ \;\;\;\;\left(\mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(t\_0, 4, 9\right)\right) \cdot x1\right) \cdot x1\\ \end{array} \end{array} \]
                                                                                                      (FPCore (x1 x2)
                                                                                                       :precision binary64
                                                                                                       (let* ((t_0 (- (* 2.0 x2) 3.0)))
                                                                                                         (if (<= x1 -27000.0)
                                                                                                           (* (* (- 6.0 (/ 3.0 x1)) (* x1 x1)) (* x1 x1))
                                                                                                           (if (<= x1 8200.0)
                                                                                                             (fma (- (* (* t_0 x2) 4.0) 1.0) x1 (* -6.0 x2))
                                                                                                             (* (* (fma (- (* 6.0 x1) 3.0) x1 (fma t_0 4.0 9.0)) x1) x1)))))
                                                                                                      double code(double x1, double x2) {
                                                                                                      	double t_0 = (2.0 * x2) - 3.0;
                                                                                                      	double tmp;
                                                                                                      	if (x1 <= -27000.0) {
                                                                                                      		tmp = ((6.0 - (3.0 / x1)) * (x1 * x1)) * (x1 * x1);
                                                                                                      	} else if (x1 <= 8200.0) {
                                                                                                      		tmp = fma((((t_0 * x2) * 4.0) - 1.0), x1, (-6.0 * x2));
                                                                                                      	} else {
                                                                                                      		tmp = (fma(((6.0 * x1) - 3.0), x1, fma(t_0, 4.0, 9.0)) * x1) * x1;
                                                                                                      	}
                                                                                                      	return tmp;
                                                                                                      }
                                                                                                      
                                                                                                      function code(x1, x2)
                                                                                                      	t_0 = Float64(Float64(2.0 * x2) - 3.0)
                                                                                                      	tmp = 0.0
                                                                                                      	if (x1 <= -27000.0)
                                                                                                      		tmp = Float64(Float64(Float64(6.0 - Float64(3.0 / x1)) * Float64(x1 * x1)) * Float64(x1 * x1));
                                                                                                      	elseif (x1 <= 8200.0)
                                                                                                      		tmp = fma(Float64(Float64(Float64(t_0 * x2) * 4.0) - 1.0), x1, Float64(-6.0 * x2));
                                                                                                      	else
                                                                                                      		tmp = Float64(Float64(fma(Float64(Float64(6.0 * x1) - 3.0), x1, fma(t_0, 4.0, 9.0)) * x1) * x1);
                                                                                                      	end
                                                                                                      	return tmp
                                                                                                      end
                                                                                                      
                                                                                                      code[x1_, x2_] := Block[{t$95$0 = N[(N[(2.0 * x2), $MachinePrecision] - 3.0), $MachinePrecision]}, If[LessEqual[x1, -27000.0], N[(N[(N[(6.0 - N[(3.0 / x1), $MachinePrecision]), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision], If[LessEqual[x1, 8200.0], N[(N[(N[(N[(t$95$0 * x2), $MachinePrecision] * 4.0), $MachinePrecision] - 1.0), $MachinePrecision] * x1 + N[(-6.0 * x2), $MachinePrecision]), $MachinePrecision], N[(N[(N[(N[(N[(6.0 * x1), $MachinePrecision] - 3.0), $MachinePrecision] * x1 + N[(t$95$0 * 4.0 + 9.0), $MachinePrecision]), $MachinePrecision] * x1), $MachinePrecision] * x1), $MachinePrecision]]]]
                                                                                                      
                                                                                                      \begin{array}{l}
                                                                                                      
                                                                                                      \\
                                                                                                      \begin{array}{l}
                                                                                                      t_0 := 2 \cdot x2 - 3\\
                                                                                                      \mathbf{if}\;x1 \leq -27000:\\
                                                                                                      \;\;\;\;\left(\left(6 - \frac{3}{x1}\right) \cdot \left(x1 \cdot x1\right)\right) \cdot \left(x1 \cdot x1\right)\\
                                                                                                      
                                                                                                      \mathbf{elif}\;x1 \leq 8200:\\
                                                                                                      \;\;\;\;\mathsf{fma}\left(\left(t\_0 \cdot x2\right) \cdot 4 - 1, x1, -6 \cdot x2\right)\\
                                                                                                      
                                                                                                      \mathbf{else}:\\
                                                                                                      \;\;\;\;\left(\mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(t\_0, 4, 9\right)\right) \cdot x1\right) \cdot x1\\
                                                                                                      
                                                                                                      
                                                                                                      \end{array}
                                                                                                      \end{array}
                                                                                                      
                                                                                                      Derivation
                                                                                                      1. Split input into 3 regimes
                                                                                                      2. if x1 < -27000

                                                                                                        1. Initial program 24.1%

                                                                                                          \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                        2. Add Preprocessing
                                                                                                        3. Taylor expanded in x1 around inf

                                                                                                          \[\leadsto \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                                                                                                        4. Step-by-step derivation
                                                                                                          1. *-commutativeN/A

                                                                                                            \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                                          2. lower-*.f64N/A

                                                                                                            \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                                        5. Applied rewrites96.7%

                                                                                                          \[\leadsto \color{blue}{\left(\frac{\mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)}{x1 \cdot x1} + \left(6 - \frac{3}{x1}\right)\right) \cdot {x1}^{4}} \]
                                                                                                        6. Step-by-step derivation
                                                                                                          1. Applied rewrites96.7%

                                                                                                            \[\leadsto \left(\left(\left(6 - \frac{3}{x1}\right) + \frac{\frac{\mathsf{fma}\left(x2 \cdot 2 - 3, 4, 9\right)}{x1}}{x1}\right) \cdot \left(x1 \cdot x1\right)\right) \cdot \color{blue}{\left(x1 \cdot x1\right)} \]
                                                                                                          2. Taylor expanded in x1 around inf

                                                                                                            \[\leadsto \left(\left(6 - 3 \cdot \frac{1}{x1}\right) \cdot \left(x1 \cdot x1\right)\right) \cdot \left(x1 \cdot x1\right) \]
                                                                                                          3. Step-by-step derivation
                                                                                                            1. Applied rewrites96.7%

                                                                                                              \[\leadsto \left(\left(6 - \frac{3}{x1}\right) \cdot \left(x1 \cdot x1\right)\right) \cdot \left(x1 \cdot x1\right) \]

                                                                                                            if -27000 < x1 < 8200

                                                                                                            1. Initial program 99.6%

                                                                                                              \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                            2. Add Preprocessing
                                                                                                            3. Taylor expanded in x1 around 0

                                                                                                              \[\leadsto \color{blue}{-6 \cdot x2 + x1 \cdot \left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 1\right)} \]
                                                                                                            4. Step-by-step derivation
                                                                                                              1. +-commutativeN/A

                                                                                                                \[\leadsto \color{blue}{x1 \cdot \left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 1\right) + -6 \cdot x2} \]
                                                                                                              2. *-commutativeN/A

                                                                                                                \[\leadsto \color{blue}{\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 1\right) \cdot x1} + -6 \cdot x2 \]
                                                                                                              3. lower-fma.f64N/A

                                                                                                                \[\leadsto \color{blue}{\mathsf{fma}\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 1, x1, -6 \cdot x2\right)} \]
                                                                                                              4. lower--.f64N/A

                                                                                                                \[\leadsto \mathsf{fma}\left(\color{blue}{4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 1}, x1, -6 \cdot x2\right) \]
                                                                                                              5. *-commutativeN/A

                                                                                                                \[\leadsto \mathsf{fma}\left(\color{blue}{\left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) \cdot 4} - 1, x1, -6 \cdot x2\right) \]
                                                                                                              6. lower-*.f64N/A

                                                                                                                \[\leadsto \mathsf{fma}\left(\color{blue}{\left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) \cdot 4} - 1, x1, -6 \cdot x2\right) \]
                                                                                                              7. *-commutativeN/A

                                                                                                                \[\leadsto \mathsf{fma}\left(\color{blue}{\left(\left(2 \cdot x2 - 3\right) \cdot x2\right)} \cdot 4 - 1, x1, -6 \cdot x2\right) \]
                                                                                                              8. lower-*.f64N/A

                                                                                                                \[\leadsto \mathsf{fma}\left(\color{blue}{\left(\left(2 \cdot x2 - 3\right) \cdot x2\right)} \cdot 4 - 1, x1, -6 \cdot x2\right) \]
                                                                                                              9. lower--.f64N/A

                                                                                                                \[\leadsto \mathsf{fma}\left(\left(\color{blue}{\left(2 \cdot x2 - 3\right)} \cdot x2\right) \cdot 4 - 1, x1, -6 \cdot x2\right) \]
                                                                                                              10. lower-*.f64N/A

                                                                                                                \[\leadsto \mathsf{fma}\left(\left(\left(\color{blue}{2 \cdot x2} - 3\right) \cdot x2\right) \cdot 4 - 1, x1, -6 \cdot x2\right) \]
                                                                                                              11. lower-*.f6485.2

                                                                                                                \[\leadsto \mathsf{fma}\left(\left(\left(2 \cdot x2 - 3\right) \cdot x2\right) \cdot 4 - 1, x1, \color{blue}{-6 \cdot x2}\right) \]
                                                                                                            5. Applied rewrites85.2%

                                                                                                              \[\leadsto \color{blue}{\mathsf{fma}\left(\left(\left(2 \cdot x2 - 3\right) \cdot x2\right) \cdot 4 - 1, x1, -6 \cdot x2\right)} \]

                                                                                                            if 8200 < x1

                                                                                                            1. Initial program 52.7%

                                                                                                              \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                            2. Add Preprocessing
                                                                                                            3. Taylor expanded in x1 around inf

                                                                                                              \[\leadsto \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                                                                                                            4. Step-by-step derivation
                                                                                                              1. *-commutativeN/A

                                                                                                                \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                                              2. lower-*.f64N/A

                                                                                                                \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                                            5. Applied rewrites95.8%

                                                                                                              \[\leadsto \color{blue}{\left(\frac{\mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)}{x1 \cdot x1} + \left(6 - \frac{3}{x1}\right)\right) \cdot {x1}^{4}} \]
                                                                                                            6. Taylor expanded in x2 around inf

                                                                                                              \[\leadsto 8 \cdot \color{blue}{\left({x1}^{2} \cdot x2\right)} \]
                                                                                                            7. Step-by-step derivation
                                                                                                              1. Applied rewrites36.9%

                                                                                                                \[\leadsto \left(\left(x1 \cdot x1\right) \cdot x2\right) \cdot \color{blue}{8} \]
                                                                                                              2. Step-by-step derivation
                                                                                                                1. Applied rewrites30.2%

                                                                                                                  \[\leadsto \left(\left(x2 \cdot x1\right) \cdot x1\right) \cdot 8 \]
                                                                                                                2. Taylor expanded in x1 around 0

                                                                                                                  \[\leadsto {x1}^{2} \cdot \color{blue}{\left(9 + \left(4 \cdot \left(2 \cdot x2 - 3\right) + x1 \cdot \left(6 \cdot x1 - 3\right)\right)\right)} \]
                                                                                                                3. Step-by-step derivation
                                                                                                                  1. Applied rewrites95.9%

                                                                                                                    \[\leadsto \left(\mathsf{fma}\left(6 \cdot x1 - 3, x1, \mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)\right) \cdot x1\right) \cdot \color{blue}{x1} \]
                                                                                                                4. Recombined 3 regimes into one program.
                                                                                                                5. Add Preprocessing

                                                                                                                Alternative 14: 88.3% accurate, 6.3× speedup?

                                                                                                                \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x1 \leq -27000 \lor \neg \left(x1 \leq 8200\right):\\ \;\;\;\;\left(\left(6 - \frac{3}{x1}\right) \cdot \left(x1 \cdot x1\right)\right) \cdot \left(x1 \cdot x1\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\left(\left(2 \cdot x2 - 3\right) \cdot x2\right) \cdot 4 - 1, x1, -6 \cdot x2\right)\\ \end{array} \end{array} \]
                                                                                                                (FPCore (x1 x2)
                                                                                                                 :precision binary64
                                                                                                                 (if (or (<= x1 -27000.0) (not (<= x1 8200.0)))
                                                                                                                   (* (* (- 6.0 (/ 3.0 x1)) (* x1 x1)) (* x1 x1))
                                                                                                                   (fma (- (* (* (- (* 2.0 x2) 3.0) x2) 4.0) 1.0) x1 (* -6.0 x2))))
                                                                                                                double code(double x1, double x2) {
                                                                                                                	double tmp;
                                                                                                                	if ((x1 <= -27000.0) || !(x1 <= 8200.0)) {
                                                                                                                		tmp = ((6.0 - (3.0 / x1)) * (x1 * x1)) * (x1 * x1);
                                                                                                                	} else {
                                                                                                                		tmp = fma((((((2.0 * x2) - 3.0) * x2) * 4.0) - 1.0), x1, (-6.0 * x2));
                                                                                                                	}
                                                                                                                	return tmp;
                                                                                                                }
                                                                                                                
                                                                                                                function code(x1, x2)
                                                                                                                	tmp = 0.0
                                                                                                                	if ((x1 <= -27000.0) || !(x1 <= 8200.0))
                                                                                                                		tmp = Float64(Float64(Float64(6.0 - Float64(3.0 / x1)) * Float64(x1 * x1)) * Float64(x1 * x1));
                                                                                                                	else
                                                                                                                		tmp = fma(Float64(Float64(Float64(Float64(Float64(2.0 * x2) - 3.0) * x2) * 4.0) - 1.0), x1, Float64(-6.0 * x2));
                                                                                                                	end
                                                                                                                	return tmp
                                                                                                                end
                                                                                                                
                                                                                                                code[x1_, x2_] := If[Or[LessEqual[x1, -27000.0], N[Not[LessEqual[x1, 8200.0]], $MachinePrecision]], N[(N[(N[(6.0 - N[(3.0 / x1), $MachinePrecision]), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision], N[(N[(N[(N[(N[(N[(2.0 * x2), $MachinePrecision] - 3.0), $MachinePrecision] * x2), $MachinePrecision] * 4.0), $MachinePrecision] - 1.0), $MachinePrecision] * x1 + N[(-6.0 * x2), $MachinePrecision]), $MachinePrecision]]
                                                                                                                
                                                                                                                \begin{array}{l}
                                                                                                                
                                                                                                                \\
                                                                                                                \begin{array}{l}
                                                                                                                \mathbf{if}\;x1 \leq -27000 \lor \neg \left(x1 \leq 8200\right):\\
                                                                                                                \;\;\;\;\left(\left(6 - \frac{3}{x1}\right) \cdot \left(x1 \cdot x1\right)\right) \cdot \left(x1 \cdot x1\right)\\
                                                                                                                
                                                                                                                \mathbf{else}:\\
                                                                                                                \;\;\;\;\mathsf{fma}\left(\left(\left(2 \cdot x2 - 3\right) \cdot x2\right) \cdot 4 - 1, x1, -6 \cdot x2\right)\\
                                                                                                                
                                                                                                                
                                                                                                                \end{array}
                                                                                                                \end{array}
                                                                                                                
                                                                                                                Derivation
                                                                                                                1. Split input into 2 regimes
                                                                                                                2. if x1 < -27000 or 8200 < x1

                                                                                                                  1. Initial program 39.1%

                                                                                                                    \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                  2. Add Preprocessing
                                                                                                                  3. Taylor expanded in x1 around inf

                                                                                                                    \[\leadsto \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                                                                                                                  4. Step-by-step derivation
                                                                                                                    1. *-commutativeN/A

                                                                                                                      \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                                                    2. lower-*.f64N/A

                                                                                                                      \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                                                  5. Applied rewrites96.2%

                                                                                                                    \[\leadsto \color{blue}{\left(\frac{\mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)}{x1 \cdot x1} + \left(6 - \frac{3}{x1}\right)\right) \cdot {x1}^{4}} \]
                                                                                                                  6. Step-by-step derivation
                                                                                                                    1. Applied rewrites96.2%

                                                                                                                      \[\leadsto \left(\left(\left(6 - \frac{3}{x1}\right) + \frac{\frac{\mathsf{fma}\left(x2 \cdot 2 - 3, 4, 9\right)}{x1}}{x1}\right) \cdot \left(x1 \cdot x1\right)\right) \cdot \color{blue}{\left(x1 \cdot x1\right)} \]
                                                                                                                    2. Taylor expanded in x1 around inf

                                                                                                                      \[\leadsto \left(\left(6 - 3 \cdot \frac{1}{x1}\right) \cdot \left(x1 \cdot x1\right)\right) \cdot \left(x1 \cdot x1\right) \]
                                                                                                                    3. Step-by-step derivation
                                                                                                                      1. Applied rewrites93.5%

                                                                                                                        \[\leadsto \left(\left(6 - \frac{3}{x1}\right) \cdot \left(x1 \cdot x1\right)\right) \cdot \left(x1 \cdot x1\right) \]

                                                                                                                      if -27000 < x1 < 8200

                                                                                                                      1. Initial program 99.6%

                                                                                                                        \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                      2. Add Preprocessing
                                                                                                                      3. Taylor expanded in x1 around 0

                                                                                                                        \[\leadsto \color{blue}{-6 \cdot x2 + x1 \cdot \left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 1\right)} \]
                                                                                                                      4. Step-by-step derivation
                                                                                                                        1. +-commutativeN/A

                                                                                                                          \[\leadsto \color{blue}{x1 \cdot \left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 1\right) + -6 \cdot x2} \]
                                                                                                                        2. *-commutativeN/A

                                                                                                                          \[\leadsto \color{blue}{\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 1\right) \cdot x1} + -6 \cdot x2 \]
                                                                                                                        3. lower-fma.f64N/A

                                                                                                                          \[\leadsto \color{blue}{\mathsf{fma}\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 1, x1, -6 \cdot x2\right)} \]
                                                                                                                        4. lower--.f64N/A

                                                                                                                          \[\leadsto \mathsf{fma}\left(\color{blue}{4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 1}, x1, -6 \cdot x2\right) \]
                                                                                                                        5. *-commutativeN/A

                                                                                                                          \[\leadsto \mathsf{fma}\left(\color{blue}{\left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) \cdot 4} - 1, x1, -6 \cdot x2\right) \]
                                                                                                                        6. lower-*.f64N/A

                                                                                                                          \[\leadsto \mathsf{fma}\left(\color{blue}{\left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) \cdot 4} - 1, x1, -6 \cdot x2\right) \]
                                                                                                                        7. *-commutativeN/A

                                                                                                                          \[\leadsto \mathsf{fma}\left(\color{blue}{\left(\left(2 \cdot x2 - 3\right) \cdot x2\right)} \cdot 4 - 1, x1, -6 \cdot x2\right) \]
                                                                                                                        8. lower-*.f64N/A

                                                                                                                          \[\leadsto \mathsf{fma}\left(\color{blue}{\left(\left(2 \cdot x2 - 3\right) \cdot x2\right)} \cdot 4 - 1, x1, -6 \cdot x2\right) \]
                                                                                                                        9. lower--.f64N/A

                                                                                                                          \[\leadsto \mathsf{fma}\left(\left(\color{blue}{\left(2 \cdot x2 - 3\right)} \cdot x2\right) \cdot 4 - 1, x1, -6 \cdot x2\right) \]
                                                                                                                        10. lower-*.f64N/A

                                                                                                                          \[\leadsto \mathsf{fma}\left(\left(\left(\color{blue}{2 \cdot x2} - 3\right) \cdot x2\right) \cdot 4 - 1, x1, -6 \cdot x2\right) \]
                                                                                                                        11. lower-*.f6485.2

                                                                                                                          \[\leadsto \mathsf{fma}\left(\left(\left(2 \cdot x2 - 3\right) \cdot x2\right) \cdot 4 - 1, x1, \color{blue}{-6 \cdot x2}\right) \]
                                                                                                                      5. Applied rewrites85.2%

                                                                                                                        \[\leadsto \color{blue}{\mathsf{fma}\left(\left(\left(2 \cdot x2 - 3\right) \cdot x2\right) \cdot 4 - 1, x1, -6 \cdot x2\right)} \]
                                                                                                                    4. Recombined 2 regimes into one program.
                                                                                                                    5. Final simplification89.4%

                                                                                                                      \[\leadsto \begin{array}{l} \mathbf{if}\;x1 \leq -27000 \lor \neg \left(x1 \leq 8200\right):\\ \;\;\;\;\left(\left(6 - \frac{3}{x1}\right) \cdot \left(x1 \cdot x1\right)\right) \cdot \left(x1 \cdot x1\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\left(\left(2 \cdot x2 - 3\right) \cdot x2\right) \cdot 4 - 1, x1, -6 \cdot x2\right)\\ \end{array} \]
                                                                                                                    6. Add Preprocessing

                                                                                                                    Alternative 15: 88.2% accurate, 6.6× speedup?

                                                                                                                    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x1 \leq -3700000 \lor \neg \left(x1 \leq 8200\right):\\ \;\;\;\;6 \cdot \left(\left(\left(x1 \cdot x1\right) \cdot \left|x1\right|\right) \cdot \left|x1\right|\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\left(\left(2 \cdot x2 - 3\right) \cdot x2\right) \cdot 4 - 1, x1, -6 \cdot x2\right)\\ \end{array} \end{array} \]
                                                                                                                    (FPCore (x1 x2)
                                                                                                                     :precision binary64
                                                                                                                     (if (or (<= x1 -3700000.0) (not (<= x1 8200.0)))
                                                                                                                       (* 6.0 (* (* (* x1 x1) (fabs x1)) (fabs x1)))
                                                                                                                       (fma (- (* (* (- (* 2.0 x2) 3.0) x2) 4.0) 1.0) x1 (* -6.0 x2))))
                                                                                                                    double code(double x1, double x2) {
                                                                                                                    	double tmp;
                                                                                                                    	if ((x1 <= -3700000.0) || !(x1 <= 8200.0)) {
                                                                                                                    		tmp = 6.0 * (((x1 * x1) * fabs(x1)) * fabs(x1));
                                                                                                                    	} else {
                                                                                                                    		tmp = fma((((((2.0 * x2) - 3.0) * x2) * 4.0) - 1.0), x1, (-6.0 * x2));
                                                                                                                    	}
                                                                                                                    	return tmp;
                                                                                                                    }
                                                                                                                    
                                                                                                                    function code(x1, x2)
                                                                                                                    	tmp = 0.0
                                                                                                                    	if ((x1 <= -3700000.0) || !(x1 <= 8200.0))
                                                                                                                    		tmp = Float64(6.0 * Float64(Float64(Float64(x1 * x1) * abs(x1)) * abs(x1)));
                                                                                                                    	else
                                                                                                                    		tmp = fma(Float64(Float64(Float64(Float64(Float64(2.0 * x2) - 3.0) * x2) * 4.0) - 1.0), x1, Float64(-6.0 * x2));
                                                                                                                    	end
                                                                                                                    	return tmp
                                                                                                                    end
                                                                                                                    
                                                                                                                    code[x1_, x2_] := If[Or[LessEqual[x1, -3700000.0], N[Not[LessEqual[x1, 8200.0]], $MachinePrecision]], N[(6.0 * N[(N[(N[(x1 * x1), $MachinePrecision] * N[Abs[x1], $MachinePrecision]), $MachinePrecision] * N[Abs[x1], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(N[(N[(N[(N[(2.0 * x2), $MachinePrecision] - 3.0), $MachinePrecision] * x2), $MachinePrecision] * 4.0), $MachinePrecision] - 1.0), $MachinePrecision] * x1 + N[(-6.0 * x2), $MachinePrecision]), $MachinePrecision]]
                                                                                                                    
                                                                                                                    \begin{array}{l}
                                                                                                                    
                                                                                                                    \\
                                                                                                                    \begin{array}{l}
                                                                                                                    \mathbf{if}\;x1 \leq -3700000 \lor \neg \left(x1 \leq 8200\right):\\
                                                                                                                    \;\;\;\;6 \cdot \left(\left(\left(x1 \cdot x1\right) \cdot \left|x1\right|\right) \cdot \left|x1\right|\right)\\
                                                                                                                    
                                                                                                                    \mathbf{else}:\\
                                                                                                                    \;\;\;\;\mathsf{fma}\left(\left(\left(2 \cdot x2 - 3\right) \cdot x2\right) \cdot 4 - 1, x1, -6 \cdot x2\right)\\
                                                                                                                    
                                                                                                                    
                                                                                                                    \end{array}
                                                                                                                    \end{array}
                                                                                                                    
                                                                                                                    Derivation
                                                                                                                    1. Split input into 2 regimes
                                                                                                                    2. if x1 < -3.7e6 or 8200 < x1

                                                                                                                      1. Initial program 39.1%

                                                                                                                        \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                      2. Add Preprocessing
                                                                                                                      3. Taylor expanded in x1 around inf

                                                                                                                        \[\leadsto \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                                                                                                                      4. Step-by-step derivation
                                                                                                                        1. *-commutativeN/A

                                                                                                                          \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                                                        2. lower-*.f64N/A

                                                                                                                          \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                                                      5. Applied rewrites96.2%

                                                                                                                        \[\leadsto \color{blue}{\left(\frac{\mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)}{x1 \cdot x1} + \left(6 - \frac{3}{x1}\right)\right) \cdot {x1}^{4}} \]
                                                                                                                      6. Taylor expanded in x1 around inf

                                                                                                                        \[\leadsto 6 \cdot {\color{blue}{x1}}^{4} \]
                                                                                                                      7. Step-by-step derivation
                                                                                                                        1. Applied rewrites92.5%

                                                                                                                          \[\leadsto 6 \cdot {\color{blue}{x1}}^{4} \]
                                                                                                                        2. Step-by-step derivation
                                                                                                                          1. Applied rewrites92.5%

                                                                                                                            \[\leadsto 6 \cdot \left(\left(\left(x1 \cdot x1\right) \cdot \left|x1\right|\right) \cdot \color{blue}{\left|x1\right|}\right) \]

                                                                                                                          if -3.7e6 < x1 < 8200

                                                                                                                          1. Initial program 99.6%

                                                                                                                            \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                          2. Add Preprocessing
                                                                                                                          3. Taylor expanded in x1 around 0

                                                                                                                            \[\leadsto \color{blue}{-6 \cdot x2 + x1 \cdot \left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 1\right)} \]
                                                                                                                          4. Step-by-step derivation
                                                                                                                            1. +-commutativeN/A

                                                                                                                              \[\leadsto \color{blue}{x1 \cdot \left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 1\right) + -6 \cdot x2} \]
                                                                                                                            2. *-commutativeN/A

                                                                                                                              \[\leadsto \color{blue}{\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 1\right) \cdot x1} + -6 \cdot x2 \]
                                                                                                                            3. lower-fma.f64N/A

                                                                                                                              \[\leadsto \color{blue}{\mathsf{fma}\left(4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 1, x1, -6 \cdot x2\right)} \]
                                                                                                                            4. lower--.f64N/A

                                                                                                                              \[\leadsto \mathsf{fma}\left(\color{blue}{4 \cdot \left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) - 1}, x1, -6 \cdot x2\right) \]
                                                                                                                            5. *-commutativeN/A

                                                                                                                              \[\leadsto \mathsf{fma}\left(\color{blue}{\left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) \cdot 4} - 1, x1, -6 \cdot x2\right) \]
                                                                                                                            6. lower-*.f64N/A

                                                                                                                              \[\leadsto \mathsf{fma}\left(\color{blue}{\left(x2 \cdot \left(2 \cdot x2 - 3\right)\right) \cdot 4} - 1, x1, -6 \cdot x2\right) \]
                                                                                                                            7. *-commutativeN/A

                                                                                                                              \[\leadsto \mathsf{fma}\left(\color{blue}{\left(\left(2 \cdot x2 - 3\right) \cdot x2\right)} \cdot 4 - 1, x1, -6 \cdot x2\right) \]
                                                                                                                            8. lower-*.f64N/A

                                                                                                                              \[\leadsto \mathsf{fma}\left(\color{blue}{\left(\left(2 \cdot x2 - 3\right) \cdot x2\right)} \cdot 4 - 1, x1, -6 \cdot x2\right) \]
                                                                                                                            9. lower--.f64N/A

                                                                                                                              \[\leadsto \mathsf{fma}\left(\left(\color{blue}{\left(2 \cdot x2 - 3\right)} \cdot x2\right) \cdot 4 - 1, x1, -6 \cdot x2\right) \]
                                                                                                                            10. lower-*.f64N/A

                                                                                                                              \[\leadsto \mathsf{fma}\left(\left(\left(\color{blue}{2 \cdot x2} - 3\right) \cdot x2\right) \cdot 4 - 1, x1, -6 \cdot x2\right) \]
                                                                                                                            11. lower-*.f6485.2

                                                                                                                              \[\leadsto \mathsf{fma}\left(\left(\left(2 \cdot x2 - 3\right) \cdot x2\right) \cdot 4 - 1, x1, \color{blue}{-6 \cdot x2}\right) \]
                                                                                                                          5. Applied rewrites85.2%

                                                                                                                            \[\leadsto \color{blue}{\mathsf{fma}\left(\left(\left(2 \cdot x2 - 3\right) \cdot x2\right) \cdot 4 - 1, x1, -6 \cdot x2\right)} \]
                                                                                                                        3. Recombined 2 regimes into one program.
                                                                                                                        4. Final simplification88.9%

                                                                                                                          \[\leadsto \begin{array}{l} \mathbf{if}\;x1 \leq -3700000 \lor \neg \left(x1 \leq 8200\right):\\ \;\;\;\;6 \cdot \left(\left(\left(x1 \cdot x1\right) \cdot \left|x1\right|\right) \cdot \left|x1\right|\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\left(\left(2 \cdot x2 - 3\right) \cdot x2\right) \cdot 4 - 1, x1, -6 \cdot x2\right)\\ \end{array} \]
                                                                                                                        5. Add Preprocessing

                                                                                                                        Alternative 16: 69.7% accurate, 8.0× speedup?

                                                                                                                        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x1 \leq -4.6 \cdot 10^{-17} \lor \neg \left(x1 \leq 8.2 \cdot 10^{-42}\right):\\ \;\;\;\;6 \cdot \left(\left(\left(x1 \cdot x1\right) \cdot \left|x1\right|\right) \cdot \left|x1\right|\right)\\ \mathbf{else}:\\ \;\;\;\;-6 \cdot x2\\ \end{array} \end{array} \]
                                                                                                                        (FPCore (x1 x2)
                                                                                                                         :precision binary64
                                                                                                                         (if (or (<= x1 -4.6e-17) (not (<= x1 8.2e-42)))
                                                                                                                           (* 6.0 (* (* (* x1 x1) (fabs x1)) (fabs x1)))
                                                                                                                           (* -6.0 x2)))
                                                                                                                        double code(double x1, double x2) {
                                                                                                                        	double tmp;
                                                                                                                        	if ((x1 <= -4.6e-17) || !(x1 <= 8.2e-42)) {
                                                                                                                        		tmp = 6.0 * (((x1 * x1) * fabs(x1)) * fabs(x1));
                                                                                                                        	} else {
                                                                                                                        		tmp = -6.0 * x2;
                                                                                                                        	}
                                                                                                                        	return tmp;
                                                                                                                        }
                                                                                                                        
                                                                                                                        real(8) function code(x1, x2)
                                                                                                                            real(8), intent (in) :: x1
                                                                                                                            real(8), intent (in) :: x2
                                                                                                                            real(8) :: tmp
                                                                                                                            if ((x1 <= (-4.6d-17)) .or. (.not. (x1 <= 8.2d-42))) then
                                                                                                                                tmp = 6.0d0 * (((x1 * x1) * abs(x1)) * abs(x1))
                                                                                                                            else
                                                                                                                                tmp = (-6.0d0) * x2
                                                                                                                            end if
                                                                                                                            code = tmp
                                                                                                                        end function
                                                                                                                        
                                                                                                                        public static double code(double x1, double x2) {
                                                                                                                        	double tmp;
                                                                                                                        	if ((x1 <= -4.6e-17) || !(x1 <= 8.2e-42)) {
                                                                                                                        		tmp = 6.0 * (((x1 * x1) * Math.abs(x1)) * Math.abs(x1));
                                                                                                                        	} else {
                                                                                                                        		tmp = -6.0 * x2;
                                                                                                                        	}
                                                                                                                        	return tmp;
                                                                                                                        }
                                                                                                                        
                                                                                                                        def code(x1, x2):
                                                                                                                        	tmp = 0
                                                                                                                        	if (x1 <= -4.6e-17) or not (x1 <= 8.2e-42):
                                                                                                                        		tmp = 6.0 * (((x1 * x1) * math.fabs(x1)) * math.fabs(x1))
                                                                                                                        	else:
                                                                                                                        		tmp = -6.0 * x2
                                                                                                                        	return tmp
                                                                                                                        
                                                                                                                        function code(x1, x2)
                                                                                                                        	tmp = 0.0
                                                                                                                        	if ((x1 <= -4.6e-17) || !(x1 <= 8.2e-42))
                                                                                                                        		tmp = Float64(6.0 * Float64(Float64(Float64(x1 * x1) * abs(x1)) * abs(x1)));
                                                                                                                        	else
                                                                                                                        		tmp = Float64(-6.0 * x2);
                                                                                                                        	end
                                                                                                                        	return tmp
                                                                                                                        end
                                                                                                                        
                                                                                                                        function tmp_2 = code(x1, x2)
                                                                                                                        	tmp = 0.0;
                                                                                                                        	if ((x1 <= -4.6e-17) || ~((x1 <= 8.2e-42)))
                                                                                                                        		tmp = 6.0 * (((x1 * x1) * abs(x1)) * abs(x1));
                                                                                                                        	else
                                                                                                                        		tmp = -6.0 * x2;
                                                                                                                        	end
                                                                                                                        	tmp_2 = tmp;
                                                                                                                        end
                                                                                                                        
                                                                                                                        code[x1_, x2_] := If[Or[LessEqual[x1, -4.6e-17], N[Not[LessEqual[x1, 8.2e-42]], $MachinePrecision]], N[(6.0 * N[(N[(N[(x1 * x1), $MachinePrecision] * N[Abs[x1], $MachinePrecision]), $MachinePrecision] * N[Abs[x1], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(-6.0 * x2), $MachinePrecision]]
                                                                                                                        
                                                                                                                        \begin{array}{l}
                                                                                                                        
                                                                                                                        \\
                                                                                                                        \begin{array}{l}
                                                                                                                        \mathbf{if}\;x1 \leq -4.6 \cdot 10^{-17} \lor \neg \left(x1 \leq 8.2 \cdot 10^{-42}\right):\\
                                                                                                                        \;\;\;\;6 \cdot \left(\left(\left(x1 \cdot x1\right) \cdot \left|x1\right|\right) \cdot \left|x1\right|\right)\\
                                                                                                                        
                                                                                                                        \mathbf{else}:\\
                                                                                                                        \;\;\;\;-6 \cdot x2\\
                                                                                                                        
                                                                                                                        
                                                                                                                        \end{array}
                                                                                                                        \end{array}
                                                                                                                        
                                                                                                                        Derivation
                                                                                                                        1. Split input into 2 regimes
                                                                                                                        2. if x1 < -4.60000000000000018e-17 or 8.2000000000000003e-42 < x1

                                                                                                                          1. Initial program 44.2%

                                                                                                                            \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                          2. Add Preprocessing
                                                                                                                          3. Taylor expanded in x1 around inf

                                                                                                                            \[\leadsto \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                                                                                                                          4. Step-by-step derivation
                                                                                                                            1. *-commutativeN/A

                                                                                                                              \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                                                            2. lower-*.f64N/A

                                                                                                                              \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                                                          5. Applied rewrites89.8%

                                                                                                                            \[\leadsto \color{blue}{\left(\frac{\mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)}{x1 \cdot x1} + \left(6 - \frac{3}{x1}\right)\right) \cdot {x1}^{4}} \]
                                                                                                                          6. Taylor expanded in x1 around inf

                                                                                                                            \[\leadsto 6 \cdot {\color{blue}{x1}}^{4} \]
                                                                                                                          7. Step-by-step derivation
                                                                                                                            1. Applied rewrites85.0%

                                                                                                                              \[\leadsto 6 \cdot {\color{blue}{x1}}^{4} \]
                                                                                                                            2. Step-by-step derivation
                                                                                                                              1. Applied rewrites85.0%

                                                                                                                                \[\leadsto 6 \cdot \left(\left(\left(x1 \cdot x1\right) \cdot \left|x1\right|\right) \cdot \color{blue}{\left|x1\right|}\right) \]

                                                                                                                              if -4.60000000000000018e-17 < x1 < 8.2000000000000003e-42

                                                                                                                              1. Initial program 99.6%

                                                                                                                                \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                              2. Add Preprocessing
                                                                                                                              3. Taylor expanded in x1 around 0

                                                                                                                                \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                                              4. Step-by-step derivation
                                                                                                                                1. lower-*.f6460.3

                                                                                                                                  \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                                              5. Applied rewrites60.3%

                                                                                                                                \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                                            3. Recombined 2 regimes into one program.
                                                                                                                            4. Final simplification74.0%

                                                                                                                              \[\leadsto \begin{array}{l} \mathbf{if}\;x1 \leq -4.6 \cdot 10^{-17} \lor \neg \left(x1 \leq 8.2 \cdot 10^{-42}\right):\\ \;\;\;\;6 \cdot \left(\left(\left(x1 \cdot x1\right) \cdot \left|x1\right|\right) \cdot \left|x1\right|\right)\\ \mathbf{else}:\\ \;\;\;\;-6 \cdot x2\\ \end{array} \]
                                                                                                                            5. Add Preprocessing

                                                                                                                            Alternative 17: 69.7% accurate, 9.0× speedup?

                                                                                                                            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x1 \leq -4.6 \cdot 10^{-17} \lor \neg \left(x1 \leq 8.2 \cdot 10^{-42}\right):\\ \;\;\;\;6 \cdot \left(\left(x1 \cdot x1\right) \cdot \left(x1 \cdot x1\right)\right)\\ \mathbf{else}:\\ \;\;\;\;-6 \cdot x2\\ \end{array} \end{array} \]
                                                                                                                            (FPCore (x1 x2)
                                                                                                                             :precision binary64
                                                                                                                             (if (or (<= x1 -4.6e-17) (not (<= x1 8.2e-42)))
                                                                                                                               (* 6.0 (* (* x1 x1) (* x1 x1)))
                                                                                                                               (* -6.0 x2)))
                                                                                                                            double code(double x1, double x2) {
                                                                                                                            	double tmp;
                                                                                                                            	if ((x1 <= -4.6e-17) || !(x1 <= 8.2e-42)) {
                                                                                                                            		tmp = 6.0 * ((x1 * x1) * (x1 * x1));
                                                                                                                            	} else {
                                                                                                                            		tmp = -6.0 * x2;
                                                                                                                            	}
                                                                                                                            	return tmp;
                                                                                                                            }
                                                                                                                            
                                                                                                                            real(8) function code(x1, x2)
                                                                                                                                real(8), intent (in) :: x1
                                                                                                                                real(8), intent (in) :: x2
                                                                                                                                real(8) :: tmp
                                                                                                                                if ((x1 <= (-4.6d-17)) .or. (.not. (x1 <= 8.2d-42))) then
                                                                                                                                    tmp = 6.0d0 * ((x1 * x1) * (x1 * x1))
                                                                                                                                else
                                                                                                                                    tmp = (-6.0d0) * x2
                                                                                                                                end if
                                                                                                                                code = tmp
                                                                                                                            end function
                                                                                                                            
                                                                                                                            public static double code(double x1, double x2) {
                                                                                                                            	double tmp;
                                                                                                                            	if ((x1 <= -4.6e-17) || !(x1 <= 8.2e-42)) {
                                                                                                                            		tmp = 6.0 * ((x1 * x1) * (x1 * x1));
                                                                                                                            	} else {
                                                                                                                            		tmp = -6.0 * x2;
                                                                                                                            	}
                                                                                                                            	return tmp;
                                                                                                                            }
                                                                                                                            
                                                                                                                            def code(x1, x2):
                                                                                                                            	tmp = 0
                                                                                                                            	if (x1 <= -4.6e-17) or not (x1 <= 8.2e-42):
                                                                                                                            		tmp = 6.0 * ((x1 * x1) * (x1 * x1))
                                                                                                                            	else:
                                                                                                                            		tmp = -6.0 * x2
                                                                                                                            	return tmp
                                                                                                                            
                                                                                                                            function code(x1, x2)
                                                                                                                            	tmp = 0.0
                                                                                                                            	if ((x1 <= -4.6e-17) || !(x1 <= 8.2e-42))
                                                                                                                            		tmp = Float64(6.0 * Float64(Float64(x1 * x1) * Float64(x1 * x1)));
                                                                                                                            	else
                                                                                                                            		tmp = Float64(-6.0 * x2);
                                                                                                                            	end
                                                                                                                            	return tmp
                                                                                                                            end
                                                                                                                            
                                                                                                                            function tmp_2 = code(x1, x2)
                                                                                                                            	tmp = 0.0;
                                                                                                                            	if ((x1 <= -4.6e-17) || ~((x1 <= 8.2e-42)))
                                                                                                                            		tmp = 6.0 * ((x1 * x1) * (x1 * x1));
                                                                                                                            	else
                                                                                                                            		tmp = -6.0 * x2;
                                                                                                                            	end
                                                                                                                            	tmp_2 = tmp;
                                                                                                                            end
                                                                                                                            
                                                                                                                            code[x1_, x2_] := If[Or[LessEqual[x1, -4.6e-17], N[Not[LessEqual[x1, 8.2e-42]], $MachinePrecision]], N[(6.0 * N[(N[(x1 * x1), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(-6.0 * x2), $MachinePrecision]]
                                                                                                                            
                                                                                                                            \begin{array}{l}
                                                                                                                            
                                                                                                                            \\
                                                                                                                            \begin{array}{l}
                                                                                                                            \mathbf{if}\;x1 \leq -4.6 \cdot 10^{-17} \lor \neg \left(x1 \leq 8.2 \cdot 10^{-42}\right):\\
                                                                                                                            \;\;\;\;6 \cdot \left(\left(x1 \cdot x1\right) \cdot \left(x1 \cdot x1\right)\right)\\
                                                                                                                            
                                                                                                                            \mathbf{else}:\\
                                                                                                                            \;\;\;\;-6 \cdot x2\\
                                                                                                                            
                                                                                                                            
                                                                                                                            \end{array}
                                                                                                                            \end{array}
                                                                                                                            
                                                                                                                            Derivation
                                                                                                                            1. Split input into 2 regimes
                                                                                                                            2. if x1 < -4.60000000000000018e-17 or 8.2000000000000003e-42 < x1

                                                                                                                              1. Initial program 44.2%

                                                                                                                                \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                              2. Add Preprocessing
                                                                                                                              3. Taylor expanded in x1 around inf

                                                                                                                                \[\leadsto \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                                                                                                                              4. Step-by-step derivation
                                                                                                                                1. *-commutativeN/A

                                                                                                                                  \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                                                                2. lower-*.f64N/A

                                                                                                                                  \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                                                              5. Applied rewrites89.8%

                                                                                                                                \[\leadsto \color{blue}{\left(\frac{\mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)}{x1 \cdot x1} + \left(6 - \frac{3}{x1}\right)\right) \cdot {x1}^{4}} \]
                                                                                                                              6. Taylor expanded in x1 around inf

                                                                                                                                \[\leadsto 6 \cdot {\color{blue}{x1}}^{4} \]
                                                                                                                              7. Step-by-step derivation
                                                                                                                                1. Applied rewrites85.0%

                                                                                                                                  \[\leadsto 6 \cdot {\color{blue}{x1}}^{4} \]
                                                                                                                                2. Step-by-step derivation
                                                                                                                                  1. Applied rewrites85.0%

                                                                                                                                    \[\leadsto 6 \cdot \left(\left(x1 \cdot x1\right) \cdot \color{blue}{\left(x1 \cdot x1\right)}\right) \]

                                                                                                                                  if -4.60000000000000018e-17 < x1 < 8.2000000000000003e-42

                                                                                                                                  1. Initial program 99.6%

                                                                                                                                    \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                                  2. Add Preprocessing
                                                                                                                                  3. Taylor expanded in x1 around 0

                                                                                                                                    \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                                                  4. Step-by-step derivation
                                                                                                                                    1. lower-*.f6460.3

                                                                                                                                      \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                                                  5. Applied rewrites60.3%

                                                                                                                                    \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                                                3. Recombined 2 regimes into one program.
                                                                                                                                4. Final simplification74.0%

                                                                                                                                  \[\leadsto \begin{array}{l} \mathbf{if}\;x1 \leq -4.6 \cdot 10^{-17} \lor \neg \left(x1 \leq 8.2 \cdot 10^{-42}\right):\\ \;\;\;\;6 \cdot \left(\left(x1 \cdot x1\right) \cdot \left(x1 \cdot x1\right)\right)\\ \mathbf{else}:\\ \;\;\;\;-6 \cdot x2\\ \end{array} \]
                                                                                                                                5. Add Preprocessing

                                                                                                                                Alternative 18: 69.7% accurate, 9.0× speedup?

                                                                                                                                \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x1 \leq -4.6 \cdot 10^{-17}:\\ \;\;\;\;6 \cdot \left(\left(x1 \cdot x1\right) \cdot \left(x1 \cdot x1\right)\right)\\ \mathbf{elif}\;x1 \leq 8.2 \cdot 10^{-42}:\\ \;\;\;\;-6 \cdot x2\\ \mathbf{else}:\\ \;\;\;\;\left(6 \cdot \left(x1 \cdot x1\right)\right) \cdot \left(x1 \cdot x1\right)\\ \end{array} \end{array} \]
                                                                                                                                (FPCore (x1 x2)
                                                                                                                                 :precision binary64
                                                                                                                                 (if (<= x1 -4.6e-17)
                                                                                                                                   (* 6.0 (* (* x1 x1) (* x1 x1)))
                                                                                                                                   (if (<= x1 8.2e-42) (* -6.0 x2) (* (* 6.0 (* x1 x1)) (* x1 x1)))))
                                                                                                                                double code(double x1, double x2) {
                                                                                                                                	double tmp;
                                                                                                                                	if (x1 <= -4.6e-17) {
                                                                                                                                		tmp = 6.0 * ((x1 * x1) * (x1 * x1));
                                                                                                                                	} else if (x1 <= 8.2e-42) {
                                                                                                                                		tmp = -6.0 * x2;
                                                                                                                                	} else {
                                                                                                                                		tmp = (6.0 * (x1 * x1)) * (x1 * x1);
                                                                                                                                	}
                                                                                                                                	return tmp;
                                                                                                                                }
                                                                                                                                
                                                                                                                                real(8) function code(x1, x2)
                                                                                                                                    real(8), intent (in) :: x1
                                                                                                                                    real(8), intent (in) :: x2
                                                                                                                                    real(8) :: tmp
                                                                                                                                    if (x1 <= (-4.6d-17)) then
                                                                                                                                        tmp = 6.0d0 * ((x1 * x1) * (x1 * x1))
                                                                                                                                    else if (x1 <= 8.2d-42) then
                                                                                                                                        tmp = (-6.0d0) * x2
                                                                                                                                    else
                                                                                                                                        tmp = (6.0d0 * (x1 * x1)) * (x1 * x1)
                                                                                                                                    end if
                                                                                                                                    code = tmp
                                                                                                                                end function
                                                                                                                                
                                                                                                                                public static double code(double x1, double x2) {
                                                                                                                                	double tmp;
                                                                                                                                	if (x1 <= -4.6e-17) {
                                                                                                                                		tmp = 6.0 * ((x1 * x1) * (x1 * x1));
                                                                                                                                	} else if (x1 <= 8.2e-42) {
                                                                                                                                		tmp = -6.0 * x2;
                                                                                                                                	} else {
                                                                                                                                		tmp = (6.0 * (x1 * x1)) * (x1 * x1);
                                                                                                                                	}
                                                                                                                                	return tmp;
                                                                                                                                }
                                                                                                                                
                                                                                                                                def code(x1, x2):
                                                                                                                                	tmp = 0
                                                                                                                                	if x1 <= -4.6e-17:
                                                                                                                                		tmp = 6.0 * ((x1 * x1) * (x1 * x1))
                                                                                                                                	elif x1 <= 8.2e-42:
                                                                                                                                		tmp = -6.0 * x2
                                                                                                                                	else:
                                                                                                                                		tmp = (6.0 * (x1 * x1)) * (x1 * x1)
                                                                                                                                	return tmp
                                                                                                                                
                                                                                                                                function code(x1, x2)
                                                                                                                                	tmp = 0.0
                                                                                                                                	if (x1 <= -4.6e-17)
                                                                                                                                		tmp = Float64(6.0 * Float64(Float64(x1 * x1) * Float64(x1 * x1)));
                                                                                                                                	elseif (x1 <= 8.2e-42)
                                                                                                                                		tmp = Float64(-6.0 * x2);
                                                                                                                                	else
                                                                                                                                		tmp = Float64(Float64(6.0 * Float64(x1 * x1)) * Float64(x1 * x1));
                                                                                                                                	end
                                                                                                                                	return tmp
                                                                                                                                end
                                                                                                                                
                                                                                                                                function tmp_2 = code(x1, x2)
                                                                                                                                	tmp = 0.0;
                                                                                                                                	if (x1 <= -4.6e-17)
                                                                                                                                		tmp = 6.0 * ((x1 * x1) * (x1 * x1));
                                                                                                                                	elseif (x1 <= 8.2e-42)
                                                                                                                                		tmp = -6.0 * x2;
                                                                                                                                	else
                                                                                                                                		tmp = (6.0 * (x1 * x1)) * (x1 * x1);
                                                                                                                                	end
                                                                                                                                	tmp_2 = tmp;
                                                                                                                                end
                                                                                                                                
                                                                                                                                code[x1_, x2_] := If[LessEqual[x1, -4.6e-17], N[(6.0 * N[(N[(x1 * x1), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[x1, 8.2e-42], N[(-6.0 * x2), $MachinePrecision], N[(N[(6.0 * N[(x1 * x1), $MachinePrecision]), $MachinePrecision] * N[(x1 * x1), $MachinePrecision]), $MachinePrecision]]]
                                                                                                                                
                                                                                                                                \begin{array}{l}
                                                                                                                                
                                                                                                                                \\
                                                                                                                                \begin{array}{l}
                                                                                                                                \mathbf{if}\;x1 \leq -4.6 \cdot 10^{-17}:\\
                                                                                                                                \;\;\;\;6 \cdot \left(\left(x1 \cdot x1\right) \cdot \left(x1 \cdot x1\right)\right)\\
                                                                                                                                
                                                                                                                                \mathbf{elif}\;x1 \leq 8.2 \cdot 10^{-42}:\\
                                                                                                                                \;\;\;\;-6 \cdot x2\\
                                                                                                                                
                                                                                                                                \mathbf{else}:\\
                                                                                                                                \;\;\;\;\left(6 \cdot \left(x1 \cdot x1\right)\right) \cdot \left(x1 \cdot x1\right)\\
                                                                                                                                
                                                                                                                                
                                                                                                                                \end{array}
                                                                                                                                \end{array}
                                                                                                                                
                                                                                                                                Derivation
                                                                                                                                1. Split input into 3 regimes
                                                                                                                                2. if x1 < -4.60000000000000018e-17

                                                                                                                                  1. Initial program 28.7%

                                                                                                                                    \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                                  2. Add Preprocessing
                                                                                                                                  3. Taylor expanded in x1 around inf

                                                                                                                                    \[\leadsto \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                                                                                                                                  4. Step-by-step derivation
                                                                                                                                    1. *-commutativeN/A

                                                                                                                                      \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                                                                    2. lower-*.f64N/A

                                                                                                                                      \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                                                                  5. Applied rewrites91.0%

                                                                                                                                    \[\leadsto \color{blue}{\left(\frac{\mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)}{x1 \cdot x1} + \left(6 - \frac{3}{x1}\right)\right) \cdot {x1}^{4}} \]
                                                                                                                                  6. Taylor expanded in x1 around inf

                                                                                                                                    \[\leadsto 6 \cdot {\color{blue}{x1}}^{4} \]
                                                                                                                                  7. Step-by-step derivation
                                                                                                                                    1. Applied rewrites91.1%

                                                                                                                                      \[\leadsto 6 \cdot {\color{blue}{x1}}^{4} \]
                                                                                                                                    2. Step-by-step derivation
                                                                                                                                      1. Applied rewrites91.1%

                                                                                                                                        \[\leadsto 6 \cdot \left(\left(x1 \cdot x1\right) \cdot \color{blue}{\left(x1 \cdot x1\right)}\right) \]

                                                                                                                                      if -4.60000000000000018e-17 < x1 < 8.2000000000000003e-42

                                                                                                                                      1. Initial program 99.6%

                                                                                                                                        \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                                      2. Add Preprocessing
                                                                                                                                      3. Taylor expanded in x1 around 0

                                                                                                                                        \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                                                      4. Step-by-step derivation
                                                                                                                                        1. lower-*.f6460.3

                                                                                                                                          \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                                                      5. Applied rewrites60.3%

                                                                                                                                        \[\leadsto \color{blue}{-6 \cdot x2} \]

                                                                                                                                      if 8.2000000000000003e-42 < x1

                                                                                                                                      1. Initial program 57.7%

                                                                                                                                        \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                                      2. Add Preprocessing
                                                                                                                                      3. Taylor expanded in x1 around inf

                                                                                                                                        \[\leadsto \color{blue}{{x1}^{4} \cdot \left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right)} \]
                                                                                                                                      4. Step-by-step derivation
                                                                                                                                        1. *-commutativeN/A

                                                                                                                                          \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                                                                        2. lower-*.f64N/A

                                                                                                                                          \[\leadsto \color{blue}{\left(\left(6 + \left(4 \cdot \frac{2 \cdot x2 - 3}{{x1}^{2}} + \frac{9}{{x1}^{2}}\right)\right) - 3 \cdot \frac{1}{x1}\right) \cdot {x1}^{4}} \]
                                                                                                                                      5. Applied rewrites88.7%

                                                                                                                                        \[\leadsto \color{blue}{\left(\frac{\mathsf{fma}\left(2 \cdot x2 - 3, 4, 9\right)}{x1 \cdot x1} + \left(6 - \frac{3}{x1}\right)\right) \cdot {x1}^{4}} \]
                                                                                                                                      6. Taylor expanded in x1 around inf

                                                                                                                                        \[\leadsto 6 \cdot {\color{blue}{x1}}^{4} \]
                                                                                                                                      7. Step-by-step derivation
                                                                                                                                        1. Applied rewrites79.8%

                                                                                                                                          \[\leadsto 6 \cdot {\color{blue}{x1}}^{4} \]
                                                                                                                                        2. Step-by-step derivation
                                                                                                                                          1. Applied rewrites79.7%

                                                                                                                                            \[\leadsto \left(6 \cdot \left(x1 \cdot x1\right)\right) \cdot \color{blue}{\left(x1 \cdot x1\right)} \]
                                                                                                                                        3. Recombined 3 regimes into one program.
                                                                                                                                        4. Final simplification74.0%

                                                                                                                                          \[\leadsto \begin{array}{l} \mathbf{if}\;x1 \leq -4.6 \cdot 10^{-17}:\\ \;\;\;\;6 \cdot \left(\left(x1 \cdot x1\right) \cdot \left(x1 \cdot x1\right)\right)\\ \mathbf{elif}\;x1 \leq 8.2 \cdot 10^{-42}:\\ \;\;\;\;-6 \cdot x2\\ \mathbf{else}:\\ \;\;\;\;\left(6 \cdot \left(x1 \cdot x1\right)\right) \cdot \left(x1 \cdot x1\right)\\ \end{array} \]
                                                                                                                                        5. Add Preprocessing

                                                                                                                                        Alternative 19: 26.5% accurate, 33.1× speedup?

                                                                                                                                        \[\begin{array}{l} \\ x1 + -6 \cdot x2 \end{array} \]
                                                                                                                                        (FPCore (x1 x2) :precision binary64 (+ x1 (* -6.0 x2)))
                                                                                                                                        double code(double x1, double x2) {
                                                                                                                                        	return x1 + (-6.0 * x2);
                                                                                                                                        }
                                                                                                                                        
                                                                                                                                        real(8) function code(x1, x2)
                                                                                                                                            real(8), intent (in) :: x1
                                                                                                                                            real(8), intent (in) :: x2
                                                                                                                                            code = x1 + ((-6.0d0) * x2)
                                                                                                                                        end function
                                                                                                                                        
                                                                                                                                        public static double code(double x1, double x2) {
                                                                                                                                        	return x1 + (-6.0 * x2);
                                                                                                                                        }
                                                                                                                                        
                                                                                                                                        def code(x1, x2):
                                                                                                                                        	return x1 + (-6.0 * x2)
                                                                                                                                        
                                                                                                                                        function code(x1, x2)
                                                                                                                                        	return Float64(x1 + Float64(-6.0 * x2))
                                                                                                                                        end
                                                                                                                                        
                                                                                                                                        function tmp = code(x1, x2)
                                                                                                                                        	tmp = x1 + (-6.0 * x2);
                                                                                                                                        end
                                                                                                                                        
                                                                                                                                        code[x1_, x2_] := N[(x1 + N[(-6.0 * x2), $MachinePrecision]), $MachinePrecision]
                                                                                                                                        
                                                                                                                                        \begin{array}{l}
                                                                                                                                        
                                                                                                                                        \\
                                                                                                                                        x1 + -6 \cdot x2
                                                                                                                                        \end{array}
                                                                                                                                        
                                                                                                                                        Derivation
                                                                                                                                        1. Initial program 68.9%

                                                                                                                                          \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                                        2. Add Preprocessing
                                                                                                                                        3. Taylor expanded in x1 around inf

                                                                                                                                          \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{3}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                                        4. Step-by-step derivation
                                                                                                                                          1. Applied rewrites68.3%

                                                                                                                                            \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \color{blue}{3}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                                          2. Taylor expanded in x1 around 0

                                                                                                                                            \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\left(-2 \cdot x2 + -1 \cdot x1\right)}\right) \]
                                                                                                                                          3. Step-by-step derivation
                                                                                                                                            1. mul-1-negN/A

                                                                                                                                              \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \left(-2 \cdot x2 + \color{blue}{\left(\mathsf{neg}\left(x1\right)\right)}\right)\right) \]
                                                                                                                                            2. lower-fma.f64N/A

                                                                                                                                              \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\mathsf{fma}\left(-2, x2, \mathsf{neg}\left(x1\right)\right)}\right) \]
                                                                                                                                            3. lower-neg.f6468.5

                                                                                                                                              \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \mathsf{fma}\left(-2, x2, \color{blue}{-x1}\right)\right) \]
                                                                                                                                          4. Applied rewrites68.5%

                                                                                                                                            \[\leadsto x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot 3\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \color{blue}{\mathsf{fma}\left(-2, x2, -x1\right)}\right) \]
                                                                                                                                          5. Applied rewrites66.1%

                                                                                                                                            \[\leadsto x1 + \left(\color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(x1, x1, 1\right), x1, \mathsf{fma}\left(\mathsf{fma}\left(\left(\frac{\mathsf{fma}\left(x2, 2, \left(3 \cdot x1\right) \cdot x1\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)} - 3\right) \cdot \frac{\mathsf{fma}\left(x2, 2, \left(3 \cdot x1\right) \cdot x1\right) - x1}{\mathsf{fma}\left(x1, x1, 1\right)}, x1 \cdot 2, \left(\frac{4 \cdot \left(\mathsf{fma}\left(x2, 2, \left(3 \cdot x1\right) \cdot x1\right) - x1\right)}{\mathsf{fma}\left(x1, x1, 1\right)} - 6\right) \cdot \left(x1 \cdot x1\right)\right), \mathsf{fma}\left(x1, x1, 1\right), \left(3 \cdot 3\right) \cdot \left(x1 \cdot x1\right)\right)\right)} + 3 \cdot \mathsf{fma}\left(-2, x2, -x1\right)\right) \]
                                                                                                                                          6. Taylor expanded in x1 around 0

                                                                                                                                            \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                                          7. Step-by-step derivation
                                                                                                                                            1. lower-*.f6428.3

                                                                                                                                              \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                                          8. Applied rewrites28.3%

                                                                                                                                            \[\leadsto x1 + \color{blue}{-6 \cdot x2} \]
                                                                                                                                          9. Add Preprocessing

                                                                                                                                          Alternative 20: 26.3% accurate, 49.7× speedup?

                                                                                                                                          \[\begin{array}{l} \\ -6 \cdot x2 \end{array} \]
                                                                                                                                          (FPCore (x1 x2) :precision binary64 (* -6.0 x2))
                                                                                                                                          double code(double x1, double x2) {
                                                                                                                                          	return -6.0 * x2;
                                                                                                                                          }
                                                                                                                                          
                                                                                                                                          real(8) function code(x1, x2)
                                                                                                                                              real(8), intent (in) :: x1
                                                                                                                                              real(8), intent (in) :: x2
                                                                                                                                              code = (-6.0d0) * x2
                                                                                                                                          end function
                                                                                                                                          
                                                                                                                                          public static double code(double x1, double x2) {
                                                                                                                                          	return -6.0 * x2;
                                                                                                                                          }
                                                                                                                                          
                                                                                                                                          def code(x1, x2):
                                                                                                                                          	return -6.0 * x2
                                                                                                                                          
                                                                                                                                          function code(x1, x2)
                                                                                                                                          	return Float64(-6.0 * x2)
                                                                                                                                          end
                                                                                                                                          
                                                                                                                                          function tmp = code(x1, x2)
                                                                                                                                          	tmp = -6.0 * x2;
                                                                                                                                          end
                                                                                                                                          
                                                                                                                                          code[x1_, x2_] := N[(-6.0 * x2), $MachinePrecision]
                                                                                                                                          
                                                                                                                                          \begin{array}{l}
                                                                                                                                          
                                                                                                                                          \\
                                                                                                                                          -6 \cdot x2
                                                                                                                                          \end{array}
                                                                                                                                          
                                                                                                                                          Derivation
                                                                                                                                          1. Initial program 68.9%

                                                                                                                                            \[x1 + \left(\left(\left(\left(\left(\left(\left(2 \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \cdot \left(\frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 3\right) + \left(x1 \cdot x1\right) \cdot \left(4 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1} - 6\right)\right) \cdot \left(x1 \cdot x1 + 1\right) + \left(\left(3 \cdot x1\right) \cdot x1\right) \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 + 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) + \left(x1 \cdot x1\right) \cdot x1\right) + x1\right) + 3 \cdot \frac{\left(\left(3 \cdot x1\right) \cdot x1 - 2 \cdot x2\right) - x1}{x1 \cdot x1 + 1}\right) \]
                                                                                                                                          2. Add Preprocessing
                                                                                                                                          3. Taylor expanded in x1 around 0

                                                                                                                                            \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                                                          4. Step-by-step derivation
                                                                                                                                            1. lower-*.f6428.2

                                                                                                                                              \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                                                          5. Applied rewrites28.2%

                                                                                                                                            \[\leadsto \color{blue}{-6 \cdot x2} \]
                                                                                                                                          6. Add Preprocessing

                                                                                                                                          Reproduce

                                                                                                                                          ?
                                                                                                                                          herbie shell --seed 2024337 
                                                                                                                                          (FPCore (x1 x2)
                                                                                                                                            :name "Rosa's FloatVsDoubleBenchmark"
                                                                                                                                            :precision binary64
                                                                                                                                            (+ x1 (+ (+ (+ (+ (* (+ (* (* (* 2.0 x1) (/ (- (+ (* (* 3.0 x1) x1) (* 2.0 x2)) x1) (+ (* x1 x1) 1.0))) (- (/ (- (+ (* (* 3.0 x1) x1) (* 2.0 x2)) x1) (+ (* x1 x1) 1.0)) 3.0)) (* (* x1 x1) (- (* 4.0 (/ (- (+ (* (* 3.0 x1) x1) (* 2.0 x2)) x1) (+ (* x1 x1) 1.0))) 6.0))) (+ (* x1 x1) 1.0)) (* (* (* 3.0 x1) x1) (/ (- (+ (* (* 3.0 x1) x1) (* 2.0 x2)) x1) (+ (* x1 x1) 1.0)))) (* (* x1 x1) x1)) x1) (* 3.0 (/ (- (- (* (* 3.0 x1) x1) (* 2.0 x2)) x1) (+ (* x1 x1) 1.0))))))