ABCF->ab-angle a

Percentage Accurate: 19.0% → 55.1%
Time: 17.6s
Alternatives: 13
Speedup: 18.2×

Specification

?
\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
real(8) function code(a, b, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) + sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 13 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 19.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
real(8) function code(a, b, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) + sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Alternative 1: 55.1% accurate, 2.6× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;B\_m \leq 2 \cdot 10^{+23}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(\mathsf{fma}\left(-4 \cdot A, C, B\_m \cdot B\_m\right) \cdot 2\right)} \cdot \left(-\sqrt{F}\right)}{{B\_m}^{2} - \left(4 \cdot A\right) \cdot C}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\_m\right) + C\right)} \cdot \sqrt{F}}{-B\_m}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (if (<= B_m 2e+23)
   (/
    (*
     (sqrt (* (* 2.0 C) (* (fma (* -4.0 A) C (* B_m B_m)) 2.0)))
     (- (sqrt F)))
    (- (pow B_m 2.0) (* (* 4.0 A) C)))
   (/ (* (sqrt (* 2.0 (+ (hypot C B_m) C))) (sqrt F)) (- B_m))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double tmp;
	if (B_m <= 2e+23) {
		tmp = (sqrt(((2.0 * C) * (fma((-4.0 * A), C, (B_m * B_m)) * 2.0))) * -sqrt(F)) / (pow(B_m, 2.0) - ((4.0 * A) * C));
	} else {
		tmp = (sqrt((2.0 * (hypot(C, B_m) + C))) * sqrt(F)) / -B_m;
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	tmp = 0.0
	if (B_m <= 2e+23)
		tmp = Float64(Float64(sqrt(Float64(Float64(2.0 * C) * Float64(fma(Float64(-4.0 * A), C, Float64(B_m * B_m)) * 2.0))) * Float64(-sqrt(F))) / Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C)));
	else
		tmp = Float64(Float64(sqrt(Float64(2.0 * Float64(hypot(C, B_m) + C))) * sqrt(F)) / Float64(-B_m));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := If[LessEqual[B$95$m, 2e+23], N[(N[(N[Sqrt[N[(N[(2.0 * C), $MachinePrecision] * N[(N[(N[(-4.0 * A), $MachinePrecision] * C + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision] / N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(2.0 * N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision] / (-B$95$m)), $MachinePrecision]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
\mathbf{if}\;B\_m \leq 2 \cdot 10^{+23}:\\
\;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(\mathsf{fma}\left(-4 \cdot A, C, B\_m \cdot B\_m\right) \cdot 2\right)} \cdot \left(-\sqrt{F}\right)}{{B\_m}^{2} - \left(4 \cdot A\right) \cdot C}\\

\mathbf{else}:\\
\;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\_m\right) + C\right)} \cdot \sqrt{F}}{-B\_m}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if B < 1.9999999999999998e23

    1. Initial program 19.4%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in C around -inf

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\color{blue}{{C}^{2} \cdot \left(1 + -1 \cdot \frac{-1 \cdot \frac{{A}^{2} + {B}^{2}}{C} + 2 \cdot A}{C}\right)}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\color{blue}{\left(1 + -1 \cdot \frac{-1 \cdot \frac{{A}^{2} + {B}^{2}}{C} + 2 \cdot A}{C}\right) \cdot {C}^{2}}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\color{blue}{\left(1 + -1 \cdot \frac{-1 \cdot \frac{{A}^{2} + {B}^{2}}{C} + 2 \cdot A}{C}\right) \cdot {C}^{2}}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    5. Applied rewrites12.8%

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\color{blue}{\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, A, \frac{\mathsf{fma}\left(B, B, A \cdot A\right)}{-C}\right)}{C}, -1, 1\right) \cdot \left(C \cdot C\right)}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    6. Applied rewrites12.8%

      \[\leadsto \frac{-\color{blue}{\sqrt{\left(\sqrt{\left(C \cdot C\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(A, 2, \frac{\mathsf{fma}\left(A, A, B \cdot B\right)}{-C}\right), \frac{-1}{C}, 1\right)} + \left(C + A\right)\right) \cdot \left(\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    7. Taylor expanded in A around -inf

      \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    8. Step-by-step derivation
      1. lower-*.f6415.4

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    9. Applied rewrites15.4%

      \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

    if 1.9999999999999998e23 < B

    1. Initial program 9.2%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in A around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. mul-1-negN/A

        \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
      2. distribute-lft-neg-inN/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
      3. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
      4. lower-neg.f64N/A

        \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
      5. lower-/.f64N/A

        \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
      6. lower-sqrt.f64N/A

        \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
      7. lower-sqrt.f64N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
      8. *-commutativeN/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
      9. lower-*.f64N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
      10. +-commutativeN/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
      11. lower-+.f64N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
      12. unpow2N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{B \cdot B} + {C}^{2}} + C\right) \cdot F} \]
      13. unpow2N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{B \cdot B + \color{blue}{C \cdot C}} + C\right) \cdot F} \]
      14. lower-hypot.f6451.0

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(B, C\right)} + C\right) \cdot F} \]
    5. Applied rewrites51.0%

      \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(B, C\right) + C\right) \cdot F}} \]
    6. Step-by-step derivation
      1. Applied rewrites51.0%

        \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]
      2. Step-by-step derivation
        1. Applied rewrites69.3%

          \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)} \cdot \sqrt{F}}{-\color{blue}{B}} \]
      3. Recombined 2 regimes into one program.
      4. Final simplification27.8%

        \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 2 \cdot 10^{+23}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right) \cdot 2\right)} \cdot \left(-\sqrt{F}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)} \cdot \sqrt{F}}{-B}\\ \end{array} \]
      5. Add Preprocessing

      Alternative 2: 46.9% accurate, 1.8× speedup?

      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;{B\_m}^{2} \leq 0.2:\\ \;\;\;\;\left(-\sqrt{2}\right) \cdot \sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\_m\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\_m\right) + C\right)} \cdot \sqrt{F}}{-B\_m}\\ \end{array} \end{array} \]
      B_m = (fabs.f64 B)
      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
      (FPCore (A B_m C F)
       :precision binary64
       (if (<= (pow B_m 2.0) 0.2)
         (*
          (- (sqrt 2.0))
          (sqrt
           (/ (* (+ (+ (hypot (- A C) B_m) C) A) F) (fma -4.0 (* C A) (* B_m B_m)))))
         (/ (* (sqrt (* 2.0 (+ (hypot C B_m) C))) (sqrt F)) (- B_m))))
      B_m = fabs(B);
      assert(A < B_m && B_m < C && C < F);
      double code(double A, double B_m, double C, double F) {
      	double tmp;
      	if (pow(B_m, 2.0) <= 0.2) {
      		tmp = -sqrt(2.0) * sqrt(((((hypot((A - C), B_m) + C) + A) * F) / fma(-4.0, (C * A), (B_m * B_m))));
      	} else {
      		tmp = (sqrt((2.0 * (hypot(C, B_m) + C))) * sqrt(F)) / -B_m;
      	}
      	return tmp;
      }
      
      B_m = abs(B)
      A, B_m, C, F = sort([A, B_m, C, F])
      function code(A, B_m, C, F)
      	tmp = 0.0
      	if ((B_m ^ 2.0) <= 0.2)
      		tmp = Float64(Float64(-sqrt(2.0)) * sqrt(Float64(Float64(Float64(Float64(hypot(Float64(A - C), B_m) + C) + A) * F) / fma(-4.0, Float64(C * A), Float64(B_m * B_m)))));
      	else
      		tmp = Float64(Float64(sqrt(Float64(2.0 * Float64(hypot(C, B_m) + C))) * sqrt(F)) / Float64(-B_m));
      	end
      	return tmp
      end
      
      B_m = N[Abs[B], $MachinePrecision]
      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
      code[A_, B$95$m_, C_, F_] := If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 0.2], N[((-N[Sqrt[2.0], $MachinePrecision]) * N[Sqrt[N[(N[(N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] + A), $MachinePrecision] * F), $MachinePrecision] / N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(2.0 * N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision] / (-B$95$m)), $MachinePrecision]]
      
      \begin{array}{l}
      B_m = \left|B\right|
      \\
      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
      \\
      \begin{array}{l}
      \mathbf{if}\;{B\_m}^{2} \leq 0.2:\\
      \;\;\;\;\left(-\sqrt{2}\right) \cdot \sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\_m\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)}}\\
      
      \mathbf{else}:\\
      \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\_m\right) + C\right)} \cdot \sqrt{F}}{-B\_m}\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if (pow.f64 B #s(literal 2 binary64)) < 0.20000000000000001

        1. Initial program 22.8%

          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. Add Preprocessing
        3. Taylor expanded in F around 0

          \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
        4. Step-by-step derivation
          1. mul-1-negN/A

            \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
          2. *-commutativeN/A

            \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}}\right) \]
          3. distribute-lft-neg-inN/A

            \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
          4. lower-*.f64N/A

            \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
          5. lower-neg.f64N/A

            \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \]
          6. lower-sqrt.f64N/A

            \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \]
          7. lower-sqrt.f64N/A

            \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
          8. lower-/.f64N/A

            \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
        5. Applied rewrites25.1%

          \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}} \]

        if 0.20000000000000001 < (pow.f64 B #s(literal 2 binary64))

        1. Initial program 11.6%

          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. Add Preprocessing
        3. Taylor expanded in A around 0

          \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
        4. Step-by-step derivation
          1. mul-1-negN/A

            \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
          2. distribute-lft-neg-inN/A

            \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
          3. lower-*.f64N/A

            \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
          4. lower-neg.f64N/A

            \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
          5. lower-/.f64N/A

            \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
          6. lower-sqrt.f64N/A

            \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
          7. lower-sqrt.f64N/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
          8. *-commutativeN/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
          9. lower-*.f64N/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
          10. +-commutativeN/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
          11. lower-+.f64N/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
          12. unpow2N/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{B \cdot B} + {C}^{2}} + C\right) \cdot F} \]
          13. unpow2N/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{B \cdot B + \color{blue}{C \cdot C}} + C\right) \cdot F} \]
          14. lower-hypot.f6424.1

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(B, C\right)} + C\right) \cdot F} \]
        5. Applied rewrites24.1%

          \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(B, C\right) + C\right) \cdot F}} \]
        6. Step-by-step derivation
          1. Applied rewrites24.1%

            \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]
          2. Step-by-step derivation
            1. Applied rewrites32.8%

              \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)} \cdot \sqrt{F}}{-\color{blue}{B}} \]
          3. Recombined 2 regimes into one program.
          4. Add Preprocessing

          Alternative 3: 46.3% accurate, 1.9× speedup?

          \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4 \cdot A, C, B\_m \cdot B\_m\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 2 \cdot 10^{-243}:\\ \;\;\;\;\frac{\sqrt{\left(\sqrt{\left(C \cdot C\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(A, 2, \frac{\mathsf{fma}\left(A, A, B\_m \cdot B\_m\right)}{-C}\right), \frac{-1}{C}, 1\right)} + \left(C + A\right)\right) \cdot \left(\left(2 \cdot F\right) \cdot t\_0\right)}}{-t\_0}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\_m\right) + C\right)} \cdot \sqrt{F}}{-B\_m}\\ \end{array} \end{array} \]
          B_m = (fabs.f64 B)
          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
          (FPCore (A B_m C F)
           :precision binary64
           (let* ((t_0 (fma (* -4.0 A) C (* B_m B_m))))
             (if (<= (pow B_m 2.0) 2e-243)
               (/
                (sqrt
                 (*
                  (+
                   (sqrt
                    (*
                     (* C C)
                     (fma (fma A 2.0 (/ (fma A A (* B_m B_m)) (- C))) (/ -1.0 C) 1.0)))
                   (+ C A))
                  (* (* 2.0 F) t_0)))
                (- t_0))
               (/ (* (sqrt (* 2.0 (+ (hypot C B_m) C))) (sqrt F)) (- B_m)))))
          B_m = fabs(B);
          assert(A < B_m && B_m < C && C < F);
          double code(double A, double B_m, double C, double F) {
          	double t_0 = fma((-4.0 * A), C, (B_m * B_m));
          	double tmp;
          	if (pow(B_m, 2.0) <= 2e-243) {
          		tmp = sqrt(((sqrt(((C * C) * fma(fma(A, 2.0, (fma(A, A, (B_m * B_m)) / -C)), (-1.0 / C), 1.0))) + (C + A)) * ((2.0 * F) * t_0))) / -t_0;
          	} else {
          		tmp = (sqrt((2.0 * (hypot(C, B_m) + C))) * sqrt(F)) / -B_m;
          	}
          	return tmp;
          }
          
          B_m = abs(B)
          A, B_m, C, F = sort([A, B_m, C, F])
          function code(A, B_m, C, F)
          	t_0 = fma(Float64(-4.0 * A), C, Float64(B_m * B_m))
          	tmp = 0.0
          	if ((B_m ^ 2.0) <= 2e-243)
          		tmp = Float64(sqrt(Float64(Float64(sqrt(Float64(Float64(C * C) * fma(fma(A, 2.0, Float64(fma(A, A, Float64(B_m * B_m)) / Float64(-C))), Float64(-1.0 / C), 1.0))) + Float64(C + A)) * Float64(Float64(2.0 * F) * t_0))) / Float64(-t_0));
          	else
          		tmp = Float64(Float64(sqrt(Float64(2.0 * Float64(hypot(C, B_m) + C))) * sqrt(F)) / Float64(-B_m));
          	end
          	return tmp
          end
          
          B_m = N[Abs[B], $MachinePrecision]
          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
          code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(-4.0 * A), $MachinePrecision] * C + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 2e-243], N[(N[Sqrt[N[(N[(N[Sqrt[N[(N[(C * C), $MachinePrecision] * N[(N[(A * 2.0 + N[(N[(A * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision] / (-C)), $MachinePrecision]), $MachinePrecision] * N[(-1.0 / C), $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] + N[(C + A), $MachinePrecision]), $MachinePrecision] * N[(N[(2.0 * F), $MachinePrecision] * t$95$0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], N[(N[(N[Sqrt[N[(2.0 * N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision] / (-B$95$m)), $MachinePrecision]]]
          
          \begin{array}{l}
          B_m = \left|B\right|
          \\
          [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
          \\
          \begin{array}{l}
          t_0 := \mathsf{fma}\left(-4 \cdot A, C, B\_m \cdot B\_m\right)\\
          \mathbf{if}\;{B\_m}^{2} \leq 2 \cdot 10^{-243}:\\
          \;\;\;\;\frac{\sqrt{\left(\sqrt{\left(C \cdot C\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(A, 2, \frac{\mathsf{fma}\left(A, A, B\_m \cdot B\_m\right)}{-C}\right), \frac{-1}{C}, 1\right)} + \left(C + A\right)\right) \cdot \left(\left(2 \cdot F\right) \cdot t\_0\right)}}{-t\_0}\\
          
          \mathbf{else}:\\
          \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\_m\right) + C\right)} \cdot \sqrt{F}}{-B\_m}\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if (pow.f64 B #s(literal 2 binary64)) < 1.99999999999999999e-243

            1. Initial program 19.9%

              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            2. Add Preprocessing
            3. Taylor expanded in C around -inf

              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\color{blue}{{C}^{2} \cdot \left(1 + -1 \cdot \frac{-1 \cdot \frac{{A}^{2} + {B}^{2}}{C} + 2 \cdot A}{C}\right)}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            4. Step-by-step derivation
              1. *-commutativeN/A

                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\color{blue}{\left(1 + -1 \cdot \frac{-1 \cdot \frac{{A}^{2} + {B}^{2}}{C} + 2 \cdot A}{C}\right) \cdot {C}^{2}}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              2. lower-*.f64N/A

                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\color{blue}{\left(1 + -1 \cdot \frac{-1 \cdot \frac{{A}^{2} + {B}^{2}}{C} + 2 \cdot A}{C}\right) \cdot {C}^{2}}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            5. Applied rewrites15.5%

              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\color{blue}{\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, A, \frac{\mathsf{fma}\left(B, B, A \cdot A\right)}{-C}\right)}{C}, -1, 1\right) \cdot \left(C \cdot C\right)}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            6. Applied rewrites15.5%

              \[\leadsto \color{blue}{\frac{\sqrt{\left(\sqrt{\left(C \cdot C\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(A, 2, \frac{\mathsf{fma}\left(A, A, B \cdot B\right)}{-C}\right), \frac{-1}{C}, 1\right)} + \left(C + A\right)\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}} \]

            if 1.99999999999999999e-243 < (pow.f64 B #s(literal 2 binary64))

            1. Initial program 15.8%

              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            2. Add Preprocessing
            3. Taylor expanded in A around 0

              \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
            4. Step-by-step derivation
              1. mul-1-negN/A

                \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
              2. distribute-lft-neg-inN/A

                \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
              3. lower-*.f64N/A

                \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
              4. lower-neg.f64N/A

                \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
              5. lower-/.f64N/A

                \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
              6. lower-sqrt.f64N/A

                \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
              7. lower-sqrt.f64N/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
              8. *-commutativeN/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
              9. lower-*.f64N/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
              10. +-commutativeN/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
              11. lower-+.f64N/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
              12. unpow2N/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{B \cdot B} + {C}^{2}} + C\right) \cdot F} \]
              13. unpow2N/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{B \cdot B + \color{blue}{C \cdot C}} + C\right) \cdot F} \]
              14. lower-hypot.f6422.6

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(B, C\right)} + C\right) \cdot F} \]
            5. Applied rewrites22.6%

              \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(B, C\right) + C\right) \cdot F}} \]
            6. Step-by-step derivation
              1. Applied rewrites22.7%

                \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]
              2. Step-by-step derivation
                1. Applied rewrites29.0%

                  \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)} \cdot \sqrt{F}}{-\color{blue}{B}} \]
              3. Recombined 2 regimes into one program.
              4. Add Preprocessing

              Alternative 4: 52.5% accurate, 2.6× speedup?

              \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;B\_m \leq 5.4 \cdot 10^{+22}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B\_m, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\right)}}{\mathsf{fma}\left(-B\_m, B\_m, \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\_m\right) + C\right)} \cdot \sqrt{F}}{-B\_m}\\ \end{array} \end{array} \]
              B_m = (fabs.f64 B)
              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
              (FPCore (A B_m C F)
               :precision binary64
               (if (<= B_m 5.4e+22)
                 (/
                  (sqrt
                   (*
                    (+ (+ (hypot B_m (- A C)) A) C)
                    (* (* 2.0 F) (fma -4.0 (* C A) (* B_m B_m)))))
                  (fma (- B_m) B_m (* (* 4.0 A) C)))
                 (/ (* (sqrt (* 2.0 (+ (hypot C B_m) C))) (sqrt F)) (- B_m))))
              B_m = fabs(B);
              assert(A < B_m && B_m < C && C < F);
              double code(double A, double B_m, double C, double F) {
              	double tmp;
              	if (B_m <= 5.4e+22) {
              		tmp = sqrt((((hypot(B_m, (A - C)) + A) + C) * ((2.0 * F) * fma(-4.0, (C * A), (B_m * B_m))))) / fma(-B_m, B_m, ((4.0 * A) * C));
              	} else {
              		tmp = (sqrt((2.0 * (hypot(C, B_m) + C))) * sqrt(F)) / -B_m;
              	}
              	return tmp;
              }
              
              B_m = abs(B)
              A, B_m, C, F = sort([A, B_m, C, F])
              function code(A, B_m, C, F)
              	tmp = 0.0
              	if (B_m <= 5.4e+22)
              		tmp = Float64(sqrt(Float64(Float64(Float64(hypot(B_m, Float64(A - C)) + A) + C) * Float64(Float64(2.0 * F) * fma(-4.0, Float64(C * A), Float64(B_m * B_m))))) / fma(Float64(-B_m), B_m, Float64(Float64(4.0 * A) * C)));
              	else
              		tmp = Float64(Float64(sqrt(Float64(2.0 * Float64(hypot(C, B_m) + C))) * sqrt(F)) / Float64(-B_m));
              	end
              	return tmp
              end
              
              B_m = N[Abs[B], $MachinePrecision]
              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
              code[A_, B$95$m_, C_, F_] := If[LessEqual[B$95$m, 5.4e+22], N[(N[Sqrt[N[(N[(N[(N[Sqrt[B$95$m ^ 2 + N[(A - C), $MachinePrecision] ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision] * N[(N[(2.0 * F), $MachinePrecision] * N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[((-B$95$m) * B$95$m + N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(2.0 * N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision] / (-B$95$m)), $MachinePrecision]]
              
              \begin{array}{l}
              B_m = \left|B\right|
              \\
              [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
              \\
              \begin{array}{l}
              \mathbf{if}\;B\_m \leq 5.4 \cdot 10^{+22}:\\
              \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B\_m, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\right)}}{\mathsf{fma}\left(-B\_m, B\_m, \left(4 \cdot A\right) \cdot C\right)}\\
              
              \mathbf{else}:\\
              \;\;\;\;\frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\_m\right) + C\right)} \cdot \sqrt{F}}{-B\_m}\\
              
              
              \end{array}
              \end{array}
              
              Derivation
              1. Split input into 2 regimes
              2. if B < 5.4000000000000004e22

                1. Initial program 19.4%

                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                2. Add Preprocessing
                3. Applied rewrites24.7%

                  \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)}} \]

                if 5.4000000000000004e22 < B

                1. Initial program 9.2%

                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                2. Add Preprocessing
                3. Taylor expanded in A around 0

                  \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                4. Step-by-step derivation
                  1. mul-1-negN/A

                    \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                  2. distribute-lft-neg-inN/A

                    \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                  3. lower-*.f64N/A

                    \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                  4. lower-neg.f64N/A

                    \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                  5. lower-/.f64N/A

                    \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                  6. lower-sqrt.f64N/A

                    \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                  7. lower-sqrt.f64N/A

                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                  8. *-commutativeN/A

                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                  9. lower-*.f64N/A

                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                  10. +-commutativeN/A

                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                  11. lower-+.f64N/A

                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                  12. unpow2N/A

                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{B \cdot B} + {C}^{2}} + C\right) \cdot F} \]
                  13. unpow2N/A

                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{B \cdot B + \color{blue}{C \cdot C}} + C\right) \cdot F} \]
                  14. lower-hypot.f6451.0

                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(B, C\right)} + C\right) \cdot F} \]
                5. Applied rewrites51.0%

                  \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(B, C\right) + C\right) \cdot F}} \]
                6. Step-by-step derivation
                  1. Applied rewrites51.0%

                    \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]
                  2. Step-by-step derivation
                    1. Applied rewrites69.3%

                      \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)} \cdot \sqrt{F}}{-\color{blue}{B}} \]
                  3. Recombined 2 regimes into one program.
                  4. Add Preprocessing

                  Alternative 5: 46.0% accurate, 3.1× speedup?

                  \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{hypot}\left(C, B\_m\right) + C\\ t_1 := \mathsf{fma}\left(-4 \cdot A, C, B\_m \cdot B\_m\right)\\ \mathbf{if}\;F \leq -1.02 \cdot 10^{-264}:\\ \;\;\;\;\frac{\sqrt{\left(\sqrt{\left(C \cdot C\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(A, 2, \frac{\mathsf{fma}\left(A, A, B\_m \cdot B\_m\right)}{-C}\right), \frac{-1}{C}, 1\right)} + \left(C + A\right)\right) \cdot \left(\left(2 \cdot F\right) \cdot t\_1\right)}}{-t\_1}\\ \mathbf{elif}\;F \leq 9.5 \cdot 10^{+22}:\\ \;\;\;\;\frac{\sqrt{\left(t\_0 \cdot F\right) \cdot 2}}{-B\_m}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{F}}{-B\_m} \cdot \sqrt{t\_0 \cdot 2}\\ \end{array} \end{array} \]
                  B_m = (fabs.f64 B)
                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                  (FPCore (A B_m C F)
                   :precision binary64
                   (let* ((t_0 (+ (hypot C B_m) C)) (t_1 (fma (* -4.0 A) C (* B_m B_m))))
                     (if (<= F -1.02e-264)
                       (/
                        (sqrt
                         (*
                          (+
                           (sqrt
                            (*
                             (* C C)
                             (fma (fma A 2.0 (/ (fma A A (* B_m B_m)) (- C))) (/ -1.0 C) 1.0)))
                           (+ C A))
                          (* (* 2.0 F) t_1)))
                        (- t_1))
                       (if (<= F 9.5e+22)
                         (/ (sqrt (* (* t_0 F) 2.0)) (- B_m))
                         (* (/ (sqrt F) (- B_m)) (sqrt (* t_0 2.0)))))))
                  B_m = fabs(B);
                  assert(A < B_m && B_m < C && C < F);
                  double code(double A, double B_m, double C, double F) {
                  	double t_0 = hypot(C, B_m) + C;
                  	double t_1 = fma((-4.0 * A), C, (B_m * B_m));
                  	double tmp;
                  	if (F <= -1.02e-264) {
                  		tmp = sqrt(((sqrt(((C * C) * fma(fma(A, 2.0, (fma(A, A, (B_m * B_m)) / -C)), (-1.0 / C), 1.0))) + (C + A)) * ((2.0 * F) * t_1))) / -t_1;
                  	} else if (F <= 9.5e+22) {
                  		tmp = sqrt(((t_0 * F) * 2.0)) / -B_m;
                  	} else {
                  		tmp = (sqrt(F) / -B_m) * sqrt((t_0 * 2.0));
                  	}
                  	return tmp;
                  }
                  
                  B_m = abs(B)
                  A, B_m, C, F = sort([A, B_m, C, F])
                  function code(A, B_m, C, F)
                  	t_0 = Float64(hypot(C, B_m) + C)
                  	t_1 = fma(Float64(-4.0 * A), C, Float64(B_m * B_m))
                  	tmp = 0.0
                  	if (F <= -1.02e-264)
                  		tmp = Float64(sqrt(Float64(Float64(sqrt(Float64(Float64(C * C) * fma(fma(A, 2.0, Float64(fma(A, A, Float64(B_m * B_m)) / Float64(-C))), Float64(-1.0 / C), 1.0))) + Float64(C + A)) * Float64(Float64(2.0 * F) * t_1))) / Float64(-t_1));
                  	elseif (F <= 9.5e+22)
                  		tmp = Float64(sqrt(Float64(Float64(t_0 * F) * 2.0)) / Float64(-B_m));
                  	else
                  		tmp = Float64(Float64(sqrt(F) / Float64(-B_m)) * sqrt(Float64(t_0 * 2.0)));
                  	end
                  	return tmp
                  end
                  
                  B_m = N[Abs[B], $MachinePrecision]
                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                  code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision]}, Block[{t$95$1 = N[(N[(-4.0 * A), $MachinePrecision] * C + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[F, -1.02e-264], N[(N[Sqrt[N[(N[(N[Sqrt[N[(N[(C * C), $MachinePrecision] * N[(N[(A * 2.0 + N[(N[(A * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision] / (-C)), $MachinePrecision]), $MachinePrecision] * N[(-1.0 / C), $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] + N[(C + A), $MachinePrecision]), $MachinePrecision] * N[(N[(2.0 * F), $MachinePrecision] * t$95$1), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$1)), $MachinePrecision], If[LessEqual[F, 9.5e+22], N[(N[Sqrt[N[(N[(t$95$0 * F), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision], N[(N[(N[Sqrt[F], $MachinePrecision] / (-B$95$m)), $MachinePrecision] * N[Sqrt[N[(t$95$0 * 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]]
                  
                  \begin{array}{l}
                  B_m = \left|B\right|
                  \\
                  [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                  \\
                  \begin{array}{l}
                  t_0 := \mathsf{hypot}\left(C, B\_m\right) + C\\
                  t_1 := \mathsf{fma}\left(-4 \cdot A, C, B\_m \cdot B\_m\right)\\
                  \mathbf{if}\;F \leq -1.02 \cdot 10^{-264}:\\
                  \;\;\;\;\frac{\sqrt{\left(\sqrt{\left(C \cdot C\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(A, 2, \frac{\mathsf{fma}\left(A, A, B\_m \cdot B\_m\right)}{-C}\right), \frac{-1}{C}, 1\right)} + \left(C + A\right)\right) \cdot \left(\left(2 \cdot F\right) \cdot t\_1\right)}}{-t\_1}\\
                  
                  \mathbf{elif}\;F \leq 9.5 \cdot 10^{+22}:\\
                  \;\;\;\;\frac{\sqrt{\left(t\_0 \cdot F\right) \cdot 2}}{-B\_m}\\
                  
                  \mathbf{else}:\\
                  \;\;\;\;\frac{\sqrt{F}}{-B\_m} \cdot \sqrt{t\_0 \cdot 2}\\
                  
                  
                  \end{array}
                  \end{array}
                  
                  Derivation
                  1. Split input into 3 regimes
                  2. if F < -1.01999999999999992e-264

                    1. Initial program 35.0%

                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    2. Add Preprocessing
                    3. Taylor expanded in C around -inf

                      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\color{blue}{{C}^{2} \cdot \left(1 + -1 \cdot \frac{-1 \cdot \frac{{A}^{2} + {B}^{2}}{C} + 2 \cdot A}{C}\right)}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    4. Step-by-step derivation
                      1. *-commutativeN/A

                        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\color{blue}{\left(1 + -1 \cdot \frac{-1 \cdot \frac{{A}^{2} + {B}^{2}}{C} + 2 \cdot A}{C}\right) \cdot {C}^{2}}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      2. lower-*.f64N/A

                        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\color{blue}{\left(1 + -1 \cdot \frac{-1 \cdot \frac{{A}^{2} + {B}^{2}}{C} + 2 \cdot A}{C}\right) \cdot {C}^{2}}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    5. Applied rewrites23.6%

                      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\color{blue}{\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, A, \frac{\mathsf{fma}\left(B, B, A \cdot A\right)}{-C}\right)}{C}, -1, 1\right) \cdot \left(C \cdot C\right)}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    6. Applied rewrites23.6%

                      \[\leadsto \color{blue}{\frac{\sqrt{\left(\sqrt{\left(C \cdot C\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(A, 2, \frac{\mathsf{fma}\left(A, A, B \cdot B\right)}{-C}\right), \frac{-1}{C}, 1\right)} + \left(C + A\right)\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}} \]

                    if -1.01999999999999992e-264 < F < 9.49999999999999937e22

                    1. Initial program 15.8%

                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    2. Add Preprocessing
                    3. Taylor expanded in A around 0

                      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                    4. Step-by-step derivation
                      1. mul-1-negN/A

                        \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                      2. distribute-lft-neg-inN/A

                        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                      3. lower-*.f64N/A

                        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                      4. lower-neg.f64N/A

                        \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                      5. lower-/.f64N/A

                        \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                      6. lower-sqrt.f64N/A

                        \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                      7. lower-sqrt.f64N/A

                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                      8. *-commutativeN/A

                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                      9. lower-*.f64N/A

                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                      10. +-commutativeN/A

                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                      11. lower-+.f64N/A

                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                      12. unpow2N/A

                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{B \cdot B} + {C}^{2}} + C\right) \cdot F} \]
                      13. unpow2N/A

                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{B \cdot B + \color{blue}{C \cdot C}} + C\right) \cdot F} \]
                      14. lower-hypot.f6428.3

                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(B, C\right)} + C\right) \cdot F} \]
                    5. Applied rewrites28.3%

                      \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(B, C\right) + C\right) \cdot F}} \]
                    6. Step-by-step derivation
                      1. Applied rewrites28.3%

                        \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]

                      if 9.49999999999999937e22 < F

                      1. Initial program 13.7%

                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      2. Add Preprocessing
                      3. Taylor expanded in A around 0

                        \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                      4. Step-by-step derivation
                        1. mul-1-negN/A

                          \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                        2. distribute-lft-neg-inN/A

                          \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                        3. lower-*.f64N/A

                          \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                        4. lower-neg.f64N/A

                          \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                        5. lower-/.f64N/A

                          \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                        6. lower-sqrt.f64N/A

                          \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                        7. lower-sqrt.f64N/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                        8. *-commutativeN/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                        9. lower-*.f64N/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                        10. +-commutativeN/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                        11. lower-+.f64N/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                        12. unpow2N/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{B \cdot B} + {C}^{2}} + C\right) \cdot F} \]
                        13. unpow2N/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{B \cdot B + \color{blue}{C \cdot C}} + C\right) \cdot F} \]
                        14. lower-hypot.f647.0

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(B, C\right)} + C\right) \cdot F} \]
                      5. Applied rewrites7.0%

                        \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(B, C\right) + C\right) \cdot F}} \]
                      6. Step-by-step derivation
                        1. Applied rewrites7.1%

                          \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]
                        2. Step-by-step derivation
                          1. Applied rewrites18.2%

                            \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)} \cdot \sqrt{F}}{-\color{blue}{B}} \]
                          2. Step-by-step derivation
                            1. Applied rewrites18.0%

                              \[\leadsto \frac{\sqrt{F}}{-B} \cdot \color{blue}{\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2}} \]
                          3. Recombined 3 regimes into one program.
                          4. Add Preprocessing

                          Alternative 6: 43.1% accurate, 3.3× speedup?

                          \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4 \cdot A, C, B\_m \cdot B\_m\right)\\ \mathbf{if}\;F \leq -1.02 \cdot 10^{-264}:\\ \;\;\;\;\frac{\sqrt{\left(\sqrt{\left(C \cdot C\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(A, 2, \frac{\mathsf{fma}\left(A, A, B\_m \cdot B\_m\right)}{-C}\right), \frac{-1}{C}, 1\right)} + \left(C + A\right)\right) \cdot \left(\left(2 \cdot F\right) \cdot t\_0\right)}}{-t\_0}\\ \mathbf{elif}\;F \leq 2.7 \cdot 10^{+27}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot F\right) \cdot 2}}{-B\_m}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2}}{B\_m} \cdot \left(\sqrt{C + B\_m} \cdot \left(-\sqrt{F}\right)\right)\\ \end{array} \end{array} \]
                          B_m = (fabs.f64 B)
                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                          (FPCore (A B_m C F)
                           :precision binary64
                           (let* ((t_0 (fma (* -4.0 A) C (* B_m B_m))))
                             (if (<= F -1.02e-264)
                               (/
                                (sqrt
                                 (*
                                  (+
                                   (sqrt
                                    (*
                                     (* C C)
                                     (fma (fma A 2.0 (/ (fma A A (* B_m B_m)) (- C))) (/ -1.0 C) 1.0)))
                                   (+ C A))
                                  (* (* 2.0 F) t_0)))
                                (- t_0))
                               (if (<= F 2.7e+27)
                                 (/ (sqrt (* (* (+ (hypot C B_m) C) F) 2.0)) (- B_m))
                                 (* (/ (sqrt 2.0) B_m) (* (sqrt (+ C B_m)) (- (sqrt F))))))))
                          B_m = fabs(B);
                          assert(A < B_m && B_m < C && C < F);
                          double code(double A, double B_m, double C, double F) {
                          	double t_0 = fma((-4.0 * A), C, (B_m * B_m));
                          	double tmp;
                          	if (F <= -1.02e-264) {
                          		tmp = sqrt(((sqrt(((C * C) * fma(fma(A, 2.0, (fma(A, A, (B_m * B_m)) / -C)), (-1.0 / C), 1.0))) + (C + A)) * ((2.0 * F) * t_0))) / -t_0;
                          	} else if (F <= 2.7e+27) {
                          		tmp = sqrt((((hypot(C, B_m) + C) * F) * 2.0)) / -B_m;
                          	} else {
                          		tmp = (sqrt(2.0) / B_m) * (sqrt((C + B_m)) * -sqrt(F));
                          	}
                          	return tmp;
                          }
                          
                          B_m = abs(B)
                          A, B_m, C, F = sort([A, B_m, C, F])
                          function code(A, B_m, C, F)
                          	t_0 = fma(Float64(-4.0 * A), C, Float64(B_m * B_m))
                          	tmp = 0.0
                          	if (F <= -1.02e-264)
                          		tmp = Float64(sqrt(Float64(Float64(sqrt(Float64(Float64(C * C) * fma(fma(A, 2.0, Float64(fma(A, A, Float64(B_m * B_m)) / Float64(-C))), Float64(-1.0 / C), 1.0))) + Float64(C + A)) * Float64(Float64(2.0 * F) * t_0))) / Float64(-t_0));
                          	elseif (F <= 2.7e+27)
                          		tmp = Float64(sqrt(Float64(Float64(Float64(hypot(C, B_m) + C) * F) * 2.0)) / Float64(-B_m));
                          	else
                          		tmp = Float64(Float64(sqrt(2.0) / B_m) * Float64(sqrt(Float64(C + B_m)) * Float64(-sqrt(F))));
                          	end
                          	return tmp
                          end
                          
                          B_m = N[Abs[B], $MachinePrecision]
                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                          code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(-4.0 * A), $MachinePrecision] * C + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[F, -1.02e-264], N[(N[Sqrt[N[(N[(N[Sqrt[N[(N[(C * C), $MachinePrecision] * N[(N[(A * 2.0 + N[(N[(A * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision] / (-C)), $MachinePrecision]), $MachinePrecision] * N[(-1.0 / C), $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] + N[(C + A), $MachinePrecision]), $MachinePrecision] * N[(N[(2.0 * F), $MachinePrecision] * t$95$0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], If[LessEqual[F, 2.7e+27], N[(N[Sqrt[N[(N[(N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] * F), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision], N[(N[(N[Sqrt[2.0], $MachinePrecision] / B$95$m), $MachinePrecision] * N[(N[Sqrt[N[(C + B$95$m), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]), $MachinePrecision]]]]
                          
                          \begin{array}{l}
                          B_m = \left|B\right|
                          \\
                          [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                          \\
                          \begin{array}{l}
                          t_0 := \mathsf{fma}\left(-4 \cdot A, C, B\_m \cdot B\_m\right)\\
                          \mathbf{if}\;F \leq -1.02 \cdot 10^{-264}:\\
                          \;\;\;\;\frac{\sqrt{\left(\sqrt{\left(C \cdot C\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(A, 2, \frac{\mathsf{fma}\left(A, A, B\_m \cdot B\_m\right)}{-C}\right), \frac{-1}{C}, 1\right)} + \left(C + A\right)\right) \cdot \left(\left(2 \cdot F\right) \cdot t\_0\right)}}{-t\_0}\\
                          
                          \mathbf{elif}\;F \leq 2.7 \cdot 10^{+27}:\\
                          \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot F\right) \cdot 2}}{-B\_m}\\
                          
                          \mathbf{else}:\\
                          \;\;\;\;\frac{\sqrt{2}}{B\_m} \cdot \left(\sqrt{C + B\_m} \cdot \left(-\sqrt{F}\right)\right)\\
                          
                          
                          \end{array}
                          \end{array}
                          
                          Derivation
                          1. Split input into 3 regimes
                          2. if F < -1.01999999999999992e-264

                            1. Initial program 35.0%

                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            2. Add Preprocessing
                            3. Taylor expanded in C around -inf

                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\color{blue}{{C}^{2} \cdot \left(1 + -1 \cdot \frac{-1 \cdot \frac{{A}^{2} + {B}^{2}}{C} + 2 \cdot A}{C}\right)}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            4. Step-by-step derivation
                              1. *-commutativeN/A

                                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\color{blue}{\left(1 + -1 \cdot \frac{-1 \cdot \frac{{A}^{2} + {B}^{2}}{C} + 2 \cdot A}{C}\right) \cdot {C}^{2}}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              2. lower-*.f64N/A

                                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\color{blue}{\left(1 + -1 \cdot \frac{-1 \cdot \frac{{A}^{2} + {B}^{2}}{C} + 2 \cdot A}{C}\right) \cdot {C}^{2}}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            5. Applied rewrites23.6%

                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{\color{blue}{\mathsf{fma}\left(\frac{\mathsf{fma}\left(2, A, \frac{\mathsf{fma}\left(B, B, A \cdot A\right)}{-C}\right)}{C}, -1, 1\right) \cdot \left(C \cdot C\right)}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            6. Applied rewrites23.6%

                              \[\leadsto \color{blue}{\frac{\sqrt{\left(\sqrt{\left(C \cdot C\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(A, 2, \frac{\mathsf{fma}\left(A, A, B \cdot B\right)}{-C}\right), \frac{-1}{C}, 1\right)} + \left(C + A\right)\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}} \]

                            if -1.01999999999999992e-264 < F < 2.6999999999999997e27

                            1. Initial program 15.7%

                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            2. Add Preprocessing
                            3. Taylor expanded in A around 0

                              \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                            4. Step-by-step derivation
                              1. mul-1-negN/A

                                \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                              2. distribute-lft-neg-inN/A

                                \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                              3. lower-*.f64N/A

                                \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                              4. lower-neg.f64N/A

                                \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                              5. lower-/.f64N/A

                                \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                              6. lower-sqrt.f64N/A

                                \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                              7. lower-sqrt.f64N/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                              8. *-commutativeN/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                              9. lower-*.f64N/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                              10. +-commutativeN/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                              11. lower-+.f64N/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                              12. unpow2N/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{B \cdot B} + {C}^{2}} + C\right) \cdot F} \]
                              13. unpow2N/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{B \cdot B + \color{blue}{C \cdot C}} + C\right) \cdot F} \]
                              14. lower-hypot.f6428.1

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(B, C\right)} + C\right) \cdot F} \]
                            5. Applied rewrites28.1%

                              \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(B, C\right) + C\right) \cdot F}} \]
                            6. Step-by-step derivation
                              1. Applied rewrites28.1%

                                \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]

                              if 2.6999999999999997e27 < F

                              1. Initial program 13.9%

                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              2. Add Preprocessing
                              3. Taylor expanded in A around 0

                                \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                              4. Step-by-step derivation
                                1. mul-1-negN/A

                                  \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                2. distribute-lft-neg-inN/A

                                  \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                3. lower-*.f64N/A

                                  \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                4. lower-neg.f64N/A

                                  \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                5. lower-/.f64N/A

                                  \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                6. lower-sqrt.f64N/A

                                  \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                7. lower-sqrt.f64N/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                8. *-commutativeN/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                9. lower-*.f64N/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                10. +-commutativeN/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                11. lower-+.f64N/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                12. unpow2N/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{B \cdot B} + {C}^{2}} + C\right) \cdot F} \]
                                13. unpow2N/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{B \cdot B + \color{blue}{C \cdot C}} + C\right) \cdot F} \]
                                14. lower-hypot.f647.1

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(B, C\right)} + C\right) \cdot F} \]
                              5. Applied rewrites7.1%

                                \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(B, C\right) + C\right) \cdot F}} \]
                              6. Step-by-step derivation
                                1. Applied rewrites18.3%

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                                2. Taylor expanded in C around 0

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{B + C} \cdot \sqrt{F}\right) \]
                                3. Step-by-step derivation
                                  1. Applied rewrites14.4%

                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{C + B} \cdot \sqrt{F}\right) \]
                                4. Recombined 3 regimes into one program.
                                5. Final simplification22.2%

                                  \[\leadsto \begin{array}{l} \mathbf{if}\;F \leq -1.02 \cdot 10^{-264}:\\ \;\;\;\;\frac{\sqrt{\left(\sqrt{\left(C \cdot C\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(A, 2, \frac{\mathsf{fma}\left(A, A, B \cdot B\right)}{-C}\right), \frac{-1}{C}, 1\right)} + \left(C + A\right)\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}\\ \mathbf{elif}\;F \leq 2.7 \cdot 10^{+27}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{-B}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2}}{B} \cdot \left(\sqrt{C + B} \cdot \left(-\sqrt{F}\right)\right)\\ \end{array} \]
                                6. Add Preprocessing

                                Alternative 7: 39.7% accurate, 3.4× speedup?

                                \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;F \leq 2.7 \cdot 10^{+27}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot F\right) \cdot 2}}{-B\_m}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2}}{B\_m} \cdot \left(\sqrt{C + B\_m} \cdot \left(-\sqrt{F}\right)\right)\\ \end{array} \end{array} \]
                                B_m = (fabs.f64 B)
                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                (FPCore (A B_m C F)
                                 :precision binary64
                                 (if (<= F 2.7e+27)
                                   (/ (sqrt (* (* (+ (hypot C B_m) C) F) 2.0)) (- B_m))
                                   (* (/ (sqrt 2.0) B_m) (* (sqrt (+ C B_m)) (- (sqrt F))))))
                                B_m = fabs(B);
                                assert(A < B_m && B_m < C && C < F);
                                double code(double A, double B_m, double C, double F) {
                                	double tmp;
                                	if (F <= 2.7e+27) {
                                		tmp = sqrt((((hypot(C, B_m) + C) * F) * 2.0)) / -B_m;
                                	} else {
                                		tmp = (sqrt(2.0) / B_m) * (sqrt((C + B_m)) * -sqrt(F));
                                	}
                                	return tmp;
                                }
                                
                                B_m = Math.abs(B);
                                assert A < B_m && B_m < C && C < F;
                                public static double code(double A, double B_m, double C, double F) {
                                	double tmp;
                                	if (F <= 2.7e+27) {
                                		tmp = Math.sqrt((((Math.hypot(C, B_m) + C) * F) * 2.0)) / -B_m;
                                	} else {
                                		tmp = (Math.sqrt(2.0) / B_m) * (Math.sqrt((C + B_m)) * -Math.sqrt(F));
                                	}
                                	return tmp;
                                }
                                
                                B_m = math.fabs(B)
                                [A, B_m, C, F] = sort([A, B_m, C, F])
                                def code(A, B_m, C, F):
                                	tmp = 0
                                	if F <= 2.7e+27:
                                		tmp = math.sqrt((((math.hypot(C, B_m) + C) * F) * 2.0)) / -B_m
                                	else:
                                		tmp = (math.sqrt(2.0) / B_m) * (math.sqrt((C + B_m)) * -math.sqrt(F))
                                	return tmp
                                
                                B_m = abs(B)
                                A, B_m, C, F = sort([A, B_m, C, F])
                                function code(A, B_m, C, F)
                                	tmp = 0.0
                                	if (F <= 2.7e+27)
                                		tmp = Float64(sqrt(Float64(Float64(Float64(hypot(C, B_m) + C) * F) * 2.0)) / Float64(-B_m));
                                	else
                                		tmp = Float64(Float64(sqrt(2.0) / B_m) * Float64(sqrt(Float64(C + B_m)) * Float64(-sqrt(F))));
                                	end
                                	return tmp
                                end
                                
                                B_m = abs(B);
                                A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                function tmp_2 = code(A, B_m, C, F)
                                	tmp = 0.0;
                                	if (F <= 2.7e+27)
                                		tmp = sqrt((((hypot(C, B_m) + C) * F) * 2.0)) / -B_m;
                                	else
                                		tmp = (sqrt(2.0) / B_m) * (sqrt((C + B_m)) * -sqrt(F));
                                	end
                                	tmp_2 = tmp;
                                end
                                
                                B_m = N[Abs[B], $MachinePrecision]
                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                code[A_, B$95$m_, C_, F_] := If[LessEqual[F, 2.7e+27], N[(N[Sqrt[N[(N[(N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] * F), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision], N[(N[(N[Sqrt[2.0], $MachinePrecision] / B$95$m), $MachinePrecision] * N[(N[Sqrt[N[(C + B$95$m), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]), $MachinePrecision]]
                                
                                \begin{array}{l}
                                B_m = \left|B\right|
                                \\
                                [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                \\
                                \begin{array}{l}
                                \mathbf{if}\;F \leq 2.7 \cdot 10^{+27}:\\
                                \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot F\right) \cdot 2}}{-B\_m}\\
                                
                                \mathbf{else}:\\
                                \;\;\;\;\frac{\sqrt{2}}{B\_m} \cdot \left(\sqrt{C + B\_m} \cdot \left(-\sqrt{F}\right)\right)\\
                                
                                
                                \end{array}
                                \end{array}
                                
                                Derivation
                                1. Split input into 2 regimes
                                2. if F < 2.6999999999999997e27

                                  1. Initial program 19.1%

                                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in A around 0

                                    \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                  4. Step-by-step derivation
                                    1. mul-1-negN/A

                                      \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                    2. distribute-lft-neg-inN/A

                                      \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                    3. lower-*.f64N/A

                                      \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                    4. lower-neg.f64N/A

                                      \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                    5. lower-/.f64N/A

                                      \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                    6. lower-sqrt.f64N/A

                                      \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                    7. lower-sqrt.f64N/A

                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                    8. *-commutativeN/A

                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                    9. lower-*.f64N/A

                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                    10. +-commutativeN/A

                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                    11. lower-+.f64N/A

                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                    12. unpow2N/A

                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{B \cdot B} + {C}^{2}} + C\right) \cdot F} \]
                                    13. unpow2N/A

                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{B \cdot B + \color{blue}{C \cdot C}} + C\right) \cdot F} \]
                                    14. lower-hypot.f6423.2

                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(B, C\right)} + C\right) \cdot F} \]
                                  5. Applied rewrites23.2%

                                    \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(B, C\right) + C\right) \cdot F}} \]
                                  6. Step-by-step derivation
                                    1. Applied rewrites23.2%

                                      \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]

                                    if 2.6999999999999997e27 < F

                                    1. Initial program 13.9%

                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    2. Add Preprocessing
                                    3. Taylor expanded in A around 0

                                      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                    4. Step-by-step derivation
                                      1. mul-1-negN/A

                                        \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                      2. distribute-lft-neg-inN/A

                                        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                      3. lower-*.f64N/A

                                        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                      4. lower-neg.f64N/A

                                        \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                      5. lower-/.f64N/A

                                        \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                      6. lower-sqrt.f64N/A

                                        \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                      7. lower-sqrt.f64N/A

                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                      8. *-commutativeN/A

                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                      9. lower-*.f64N/A

                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                      10. +-commutativeN/A

                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                      11. lower-+.f64N/A

                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                      12. unpow2N/A

                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{B \cdot B} + {C}^{2}} + C\right) \cdot F} \]
                                      13. unpow2N/A

                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{B \cdot B + \color{blue}{C \cdot C}} + C\right) \cdot F} \]
                                      14. lower-hypot.f647.1

                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(B, C\right)} + C\right) \cdot F} \]
                                    5. Applied rewrites7.1%

                                      \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(B, C\right) + C\right) \cdot F}} \]
                                    6. Step-by-step derivation
                                      1. Applied rewrites18.3%

                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                                      2. Taylor expanded in C around 0

                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{B + C} \cdot \sqrt{F}\right) \]
                                      3. Step-by-step derivation
                                        1. Applied rewrites14.4%

                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{C + B} \cdot \sqrt{F}\right) \]
                                      4. Recombined 2 regimes into one program.
                                      5. Final simplification19.7%

                                        \[\leadsto \begin{array}{l} \mathbf{if}\;F \leq 2.7 \cdot 10^{+27}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{-B}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2}}{B} \cdot \left(\sqrt{C + B} \cdot \left(-\sqrt{F}\right)\right)\\ \end{array} \]
                                      6. Add Preprocessing

                                      Alternative 8: 37.9% accurate, 7.6× speedup?

                                      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := -\sqrt{F}\\ \mathbf{if}\;C \leq 6.2 \cdot 10^{+195}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(C + B\_m\right)} \cdot t\_0}{B\_m}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2}}{B\_m} \cdot \left(\sqrt{C \cdot 2} \cdot t\_0\right)\\ \end{array} \end{array} \]
                                      B_m = (fabs.f64 B)
                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                      (FPCore (A B_m C F)
                                       :precision binary64
                                       (let* ((t_0 (- (sqrt F))))
                                         (if (<= C 6.2e+195)
                                           (/ (* (sqrt (* 2.0 (+ C B_m))) t_0) B_m)
                                           (* (/ (sqrt 2.0) B_m) (* (sqrt (* C 2.0)) t_0)))))
                                      B_m = fabs(B);
                                      assert(A < B_m && B_m < C && C < F);
                                      double code(double A, double B_m, double C, double F) {
                                      	double t_0 = -sqrt(F);
                                      	double tmp;
                                      	if (C <= 6.2e+195) {
                                      		tmp = (sqrt((2.0 * (C + B_m))) * t_0) / B_m;
                                      	} else {
                                      		tmp = (sqrt(2.0) / B_m) * (sqrt((C * 2.0)) * t_0);
                                      	}
                                      	return tmp;
                                      }
                                      
                                      B_m = abs(b)
                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                      real(8) function code(a, b_m, c, f)
                                          real(8), intent (in) :: a
                                          real(8), intent (in) :: b_m
                                          real(8), intent (in) :: c
                                          real(8), intent (in) :: f
                                          real(8) :: t_0
                                          real(8) :: tmp
                                          t_0 = -sqrt(f)
                                          if (c <= 6.2d+195) then
                                              tmp = (sqrt((2.0d0 * (c + b_m))) * t_0) / b_m
                                          else
                                              tmp = (sqrt(2.0d0) / b_m) * (sqrt((c * 2.0d0)) * t_0)
                                          end if
                                          code = tmp
                                      end function
                                      
                                      B_m = Math.abs(B);
                                      assert A < B_m && B_m < C && C < F;
                                      public static double code(double A, double B_m, double C, double F) {
                                      	double t_0 = -Math.sqrt(F);
                                      	double tmp;
                                      	if (C <= 6.2e+195) {
                                      		tmp = (Math.sqrt((2.0 * (C + B_m))) * t_0) / B_m;
                                      	} else {
                                      		tmp = (Math.sqrt(2.0) / B_m) * (Math.sqrt((C * 2.0)) * t_0);
                                      	}
                                      	return tmp;
                                      }
                                      
                                      B_m = math.fabs(B)
                                      [A, B_m, C, F] = sort([A, B_m, C, F])
                                      def code(A, B_m, C, F):
                                      	t_0 = -math.sqrt(F)
                                      	tmp = 0
                                      	if C <= 6.2e+195:
                                      		tmp = (math.sqrt((2.0 * (C + B_m))) * t_0) / B_m
                                      	else:
                                      		tmp = (math.sqrt(2.0) / B_m) * (math.sqrt((C * 2.0)) * t_0)
                                      	return tmp
                                      
                                      B_m = abs(B)
                                      A, B_m, C, F = sort([A, B_m, C, F])
                                      function code(A, B_m, C, F)
                                      	t_0 = Float64(-sqrt(F))
                                      	tmp = 0.0
                                      	if (C <= 6.2e+195)
                                      		tmp = Float64(Float64(sqrt(Float64(2.0 * Float64(C + B_m))) * t_0) / B_m);
                                      	else
                                      		tmp = Float64(Float64(sqrt(2.0) / B_m) * Float64(sqrt(Float64(C * 2.0)) * t_0));
                                      	end
                                      	return tmp
                                      end
                                      
                                      B_m = abs(B);
                                      A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                      function tmp_2 = code(A, B_m, C, F)
                                      	t_0 = -sqrt(F);
                                      	tmp = 0.0;
                                      	if (C <= 6.2e+195)
                                      		tmp = (sqrt((2.0 * (C + B_m))) * t_0) / B_m;
                                      	else
                                      		tmp = (sqrt(2.0) / B_m) * (sqrt((C * 2.0)) * t_0);
                                      	end
                                      	tmp_2 = tmp;
                                      end
                                      
                                      B_m = N[Abs[B], $MachinePrecision]
                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                      code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = (-N[Sqrt[F], $MachinePrecision])}, If[LessEqual[C, 6.2e+195], N[(N[(N[Sqrt[N[(2.0 * N[(C + B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * t$95$0), $MachinePrecision] / B$95$m), $MachinePrecision], N[(N[(N[Sqrt[2.0], $MachinePrecision] / B$95$m), $MachinePrecision] * N[(N[Sqrt[N[(C * 2.0), $MachinePrecision]], $MachinePrecision] * t$95$0), $MachinePrecision]), $MachinePrecision]]]
                                      
                                      \begin{array}{l}
                                      B_m = \left|B\right|
                                      \\
                                      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                      \\
                                      \begin{array}{l}
                                      t_0 := -\sqrt{F}\\
                                      \mathbf{if}\;C \leq 6.2 \cdot 10^{+195}:\\
                                      \;\;\;\;\frac{\sqrt{2 \cdot \left(C + B\_m\right)} \cdot t\_0}{B\_m}\\
                                      
                                      \mathbf{else}:\\
                                      \;\;\;\;\frac{\sqrt{2}}{B\_m} \cdot \left(\sqrt{C \cdot 2} \cdot t\_0\right)\\
                                      
                                      
                                      \end{array}
                                      \end{array}
                                      
                                      Derivation
                                      1. Split input into 2 regimes
                                      2. if C < 6.2000000000000004e195

                                        1. Initial program 19.0%

                                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                        2. Add Preprocessing
                                        3. Taylor expanded in A around 0

                                          \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                        4. Step-by-step derivation
                                          1. mul-1-negN/A

                                            \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                          2. distribute-lft-neg-inN/A

                                            \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                          3. lower-*.f64N/A

                                            \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                          4. lower-neg.f64N/A

                                            \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                          5. lower-/.f64N/A

                                            \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                          6. lower-sqrt.f64N/A

                                            \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                          7. lower-sqrt.f64N/A

                                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                          8. *-commutativeN/A

                                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                          9. lower-*.f64N/A

                                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                          10. +-commutativeN/A

                                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                          11. lower-+.f64N/A

                                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                          12. unpow2N/A

                                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{B \cdot B} + {C}^{2}} + C\right) \cdot F} \]
                                          13. unpow2N/A

                                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{B \cdot B + \color{blue}{C \cdot C}} + C\right) \cdot F} \]
                                          14. lower-hypot.f6417.1

                                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(B, C\right)} + C\right) \cdot F} \]
                                        5. Applied rewrites17.1%

                                          \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(B, C\right) + C\right) \cdot F}} \]
                                        6. Step-by-step derivation
                                          1. Applied rewrites17.1%

                                            \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]
                                          2. Step-by-step derivation
                                            1. Applied rewrites21.3%

                                              \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)} \cdot \sqrt{F}}{-\color{blue}{B}} \]
                                            2. Taylor expanded in C around 0

                                              \[\leadsto \frac{\sqrt{2 \cdot \left(B + C\right)} \cdot \sqrt{F}}{-B} \]
                                            3. Step-by-step derivation
                                              1. Applied rewrites17.9%

                                                \[\leadsto \frac{\sqrt{2 \cdot \left(C + B\right)} \cdot \sqrt{F}}{-B} \]

                                              if 6.2000000000000004e195 < C

                                              1. Initial program 2.3%

                                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              2. Add Preprocessing
                                              3. Taylor expanded in A around 0

                                                \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                              4. Step-by-step derivation
                                                1. mul-1-negN/A

                                                  \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                2. distribute-lft-neg-inN/A

                                                  \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                3. lower-*.f64N/A

                                                  \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                4. lower-neg.f64N/A

                                                  \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                5. lower-/.f64N/A

                                                  \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                6. lower-sqrt.f64N/A

                                                  \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                7. lower-sqrt.f64N/A

                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                8. *-commutativeN/A

                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                9. lower-*.f64N/A

                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                10. +-commutativeN/A

                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                11. lower-+.f64N/A

                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                12. unpow2N/A

                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{B \cdot B} + {C}^{2}} + C\right) \cdot F} \]
                                                13. unpow2N/A

                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{B \cdot B + \color{blue}{C \cdot C}} + C\right) \cdot F} \]
                                                14. lower-hypot.f6414.7

                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(B, C\right)} + C\right) \cdot F} \]
                                              5. Applied rewrites14.7%

                                                \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(B, C\right) + C\right) \cdot F}} \]
                                              6. Step-by-step derivation
                                                1. Applied rewrites21.3%

                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                                                2. Taylor expanded in B around 0

                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{2 \cdot C} \cdot \sqrt{F}\right) \]
                                                3. Step-by-step derivation
                                                  1. Applied rewrites15.3%

                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{C \cdot 2} \cdot \sqrt{F}\right) \]
                                                4. Recombined 2 regimes into one program.
                                                5. Final simplification17.6%

                                                  \[\leadsto \begin{array}{l} \mathbf{if}\;C \leq 6.2 \cdot 10^{+195}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(C + B\right)} \cdot \left(-\sqrt{F}\right)}{B}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{2}}{B} \cdot \left(\sqrt{C \cdot 2} \cdot \left(-\sqrt{F}\right)\right)\\ \end{array} \]
                                                6. Add Preprocessing

                                                Alternative 9: 36.3% accurate, 10.4× speedup?

                                                \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \frac{\sqrt{2 \cdot \left(C + B\_m\right)} \cdot \left(-\sqrt{F}\right)}{B\_m} \end{array} \]
                                                B_m = (fabs.f64 B)
                                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                (FPCore (A B_m C F)
                                                 :precision binary64
                                                 (/ (* (sqrt (* 2.0 (+ C B_m))) (- (sqrt F))) B_m))
                                                B_m = fabs(B);
                                                assert(A < B_m && B_m < C && C < F);
                                                double code(double A, double B_m, double C, double F) {
                                                	return (sqrt((2.0 * (C + B_m))) * -sqrt(F)) / B_m;
                                                }
                                                
                                                B_m = abs(b)
                                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                real(8) function code(a, b_m, c, f)
                                                    real(8), intent (in) :: a
                                                    real(8), intent (in) :: b_m
                                                    real(8), intent (in) :: c
                                                    real(8), intent (in) :: f
                                                    code = (sqrt((2.0d0 * (c + b_m))) * -sqrt(f)) / b_m
                                                end function
                                                
                                                B_m = Math.abs(B);
                                                assert A < B_m && B_m < C && C < F;
                                                public static double code(double A, double B_m, double C, double F) {
                                                	return (Math.sqrt((2.0 * (C + B_m))) * -Math.sqrt(F)) / B_m;
                                                }
                                                
                                                B_m = math.fabs(B)
                                                [A, B_m, C, F] = sort([A, B_m, C, F])
                                                def code(A, B_m, C, F):
                                                	return (math.sqrt((2.0 * (C + B_m))) * -math.sqrt(F)) / B_m
                                                
                                                B_m = abs(B)
                                                A, B_m, C, F = sort([A, B_m, C, F])
                                                function code(A, B_m, C, F)
                                                	return Float64(Float64(sqrt(Float64(2.0 * Float64(C + B_m))) * Float64(-sqrt(F))) / B_m)
                                                end
                                                
                                                B_m = abs(B);
                                                A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                function tmp = code(A, B_m, C, F)
                                                	tmp = (sqrt((2.0 * (C + B_m))) * -sqrt(F)) / B_m;
                                                end
                                                
                                                B_m = N[Abs[B], $MachinePrecision]
                                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                code[A_, B$95$m_, C_, F_] := N[(N[(N[Sqrt[N[(2.0 * N[(C + B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision] / B$95$m), $MachinePrecision]
                                                
                                                \begin{array}{l}
                                                B_m = \left|B\right|
                                                \\
                                                [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                \\
                                                \frac{\sqrt{2 \cdot \left(C + B\_m\right)} \cdot \left(-\sqrt{F}\right)}{B\_m}
                                                \end{array}
                                                
                                                Derivation
                                                1. Initial program 17.0%

                                                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                2. Add Preprocessing
                                                3. Taylor expanded in A around 0

                                                  \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                4. Step-by-step derivation
                                                  1. mul-1-negN/A

                                                    \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                  2. distribute-lft-neg-inN/A

                                                    \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                  3. lower-*.f64N/A

                                                    \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                  4. lower-neg.f64N/A

                                                    \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                  5. lower-/.f64N/A

                                                    \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                  6. lower-sqrt.f64N/A

                                                    \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                  7. lower-sqrt.f64N/A

                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                  8. *-commutativeN/A

                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                  9. lower-*.f64N/A

                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                  10. +-commutativeN/A

                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                  11. lower-+.f64N/A

                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                  12. unpow2N/A

                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{B \cdot B} + {C}^{2}} + C\right) \cdot F} \]
                                                  13. unpow2N/A

                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{B \cdot B + \color{blue}{C \cdot C}} + C\right) \cdot F} \]
                                                  14. lower-hypot.f6416.8

                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(B, C\right)} + C\right) \cdot F} \]
                                                5. Applied rewrites16.8%

                                                  \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(B, C\right) + C\right) \cdot F}} \]
                                                6. Step-by-step derivation
                                                  1. Applied rewrites16.8%

                                                    \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]
                                                  2. Step-by-step derivation
                                                    1. Applied rewrites21.3%

                                                      \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)} \cdot \sqrt{F}}{-\color{blue}{B}} \]
                                                    2. Taylor expanded in C around 0

                                                      \[\leadsto \frac{\sqrt{2 \cdot \left(B + C\right)} \cdot \sqrt{F}}{-B} \]
                                                    3. Step-by-step derivation
                                                      1. Applied rewrites17.1%

                                                        \[\leadsto \frac{\sqrt{2 \cdot \left(C + B\right)} \cdot \sqrt{F}}{-B} \]
                                                      2. Final simplification17.1%

                                                        \[\leadsto \frac{\sqrt{2 \cdot \left(C + B\right)} \cdot \left(-\sqrt{F}\right)}{B} \]
                                                      3. Add Preprocessing

                                                      Alternative 10: 35.2% accurate, 11.4× speedup?

                                                      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;F \leq 2 \cdot 10^{+23}:\\ \;\;\;\;\frac{\sqrt{\left(\left(C + B\_m\right) \cdot F\right) \cdot 2}}{-B\_m}\\ \mathbf{else}:\\ \;\;\;\;-\sqrt{\frac{F + F}{B\_m}}\\ \end{array} \end{array} \]
                                                      B_m = (fabs.f64 B)
                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                      (FPCore (A B_m C F)
                                                       :precision binary64
                                                       (if (<= F 2e+23)
                                                         (/ (sqrt (* (* (+ C B_m) F) 2.0)) (- B_m))
                                                         (- (sqrt (/ (+ F F) B_m)))))
                                                      B_m = fabs(B);
                                                      assert(A < B_m && B_m < C && C < F);
                                                      double code(double A, double B_m, double C, double F) {
                                                      	double tmp;
                                                      	if (F <= 2e+23) {
                                                      		tmp = sqrt((((C + B_m) * F) * 2.0)) / -B_m;
                                                      	} else {
                                                      		tmp = -sqrt(((F + F) / B_m));
                                                      	}
                                                      	return tmp;
                                                      }
                                                      
                                                      B_m = abs(b)
                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                      real(8) function code(a, b_m, c, f)
                                                          real(8), intent (in) :: a
                                                          real(8), intent (in) :: b_m
                                                          real(8), intent (in) :: c
                                                          real(8), intent (in) :: f
                                                          real(8) :: tmp
                                                          if (f <= 2d+23) then
                                                              tmp = sqrt((((c + b_m) * f) * 2.0d0)) / -b_m
                                                          else
                                                              tmp = -sqrt(((f + f) / b_m))
                                                          end if
                                                          code = tmp
                                                      end function
                                                      
                                                      B_m = Math.abs(B);
                                                      assert A < B_m && B_m < C && C < F;
                                                      public static double code(double A, double B_m, double C, double F) {
                                                      	double tmp;
                                                      	if (F <= 2e+23) {
                                                      		tmp = Math.sqrt((((C + B_m) * F) * 2.0)) / -B_m;
                                                      	} else {
                                                      		tmp = -Math.sqrt(((F + F) / B_m));
                                                      	}
                                                      	return tmp;
                                                      }
                                                      
                                                      B_m = math.fabs(B)
                                                      [A, B_m, C, F] = sort([A, B_m, C, F])
                                                      def code(A, B_m, C, F):
                                                      	tmp = 0
                                                      	if F <= 2e+23:
                                                      		tmp = math.sqrt((((C + B_m) * F) * 2.0)) / -B_m
                                                      	else:
                                                      		tmp = -math.sqrt(((F + F) / B_m))
                                                      	return tmp
                                                      
                                                      B_m = abs(B)
                                                      A, B_m, C, F = sort([A, B_m, C, F])
                                                      function code(A, B_m, C, F)
                                                      	tmp = 0.0
                                                      	if (F <= 2e+23)
                                                      		tmp = Float64(sqrt(Float64(Float64(Float64(C + B_m) * F) * 2.0)) / Float64(-B_m));
                                                      	else
                                                      		tmp = Float64(-sqrt(Float64(Float64(F + F) / B_m)));
                                                      	end
                                                      	return tmp
                                                      end
                                                      
                                                      B_m = abs(B);
                                                      A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                      function tmp_2 = code(A, B_m, C, F)
                                                      	tmp = 0.0;
                                                      	if (F <= 2e+23)
                                                      		tmp = sqrt((((C + B_m) * F) * 2.0)) / -B_m;
                                                      	else
                                                      		tmp = -sqrt(((F + F) / B_m));
                                                      	end
                                                      	tmp_2 = tmp;
                                                      end
                                                      
                                                      B_m = N[Abs[B], $MachinePrecision]
                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                      code[A_, B$95$m_, C_, F_] := If[LessEqual[F, 2e+23], N[(N[Sqrt[N[(N[(N[(C + B$95$m), $MachinePrecision] * F), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision], (-N[Sqrt[N[(N[(F + F), $MachinePrecision] / B$95$m), $MachinePrecision]], $MachinePrecision])]
                                                      
                                                      \begin{array}{l}
                                                      B_m = \left|B\right|
                                                      \\
                                                      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                      \\
                                                      \begin{array}{l}
                                                      \mathbf{if}\;F \leq 2 \cdot 10^{+23}:\\
                                                      \;\;\;\;\frac{\sqrt{\left(\left(C + B\_m\right) \cdot F\right) \cdot 2}}{-B\_m}\\
                                                      
                                                      \mathbf{else}:\\
                                                      \;\;\;\;-\sqrt{\frac{F + F}{B\_m}}\\
                                                      
                                                      
                                                      \end{array}
                                                      \end{array}
                                                      
                                                      Derivation
                                                      1. Split input into 2 regimes
                                                      2. if F < 1.9999999999999998e23

                                                        1. Initial program 19.2%

                                                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                        2. Add Preprocessing
                                                        3. Taylor expanded in A around 0

                                                          \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                        4. Step-by-step derivation
                                                          1. mul-1-negN/A

                                                            \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                          2. distribute-lft-neg-inN/A

                                                            \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                          3. lower-*.f64N/A

                                                            \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                          4. lower-neg.f64N/A

                                                            \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                          5. lower-/.f64N/A

                                                            \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                          6. lower-sqrt.f64N/A

                                                            \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                          7. lower-sqrt.f64N/A

                                                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                          8. *-commutativeN/A

                                                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                          9. lower-*.f64N/A

                                                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                          10. +-commutativeN/A

                                                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                          11. lower-+.f64N/A

                                                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                          12. unpow2N/A

                                                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{B \cdot B} + {C}^{2}} + C\right) \cdot F} \]
                                                          13. unpow2N/A

                                                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{B \cdot B + \color{blue}{C \cdot C}} + C\right) \cdot F} \]
                                                          14. lower-hypot.f6423.4

                                                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(B, C\right)} + C\right) \cdot F} \]
                                                        5. Applied rewrites23.4%

                                                          \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(B, C\right) + C\right) \cdot F}} \]
                                                        6. Step-by-step derivation
                                                          1. Applied rewrites23.4%

                                                            \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]
                                                          2. Taylor expanded in C around 0

                                                            \[\leadsto \frac{\sqrt{\left(\left(B + C\right) \cdot F\right) \cdot 2}}{-B} \]
                                                          3. Step-by-step derivation
                                                            1. Applied rewrites19.1%

                                                              \[\leadsto \frac{\sqrt{\left(\left(C + B\right) \cdot F\right) \cdot 2}}{-B} \]

                                                            if 1.9999999999999998e23 < F

                                                            1. Initial program 13.7%

                                                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                            2. Add Preprocessing
                                                            3. Taylor expanded in B around inf

                                                              \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                            4. Step-by-step derivation
                                                              1. mul-1-negN/A

                                                                \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                              2. *-commutativeN/A

                                                                \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                              3. distribute-lft-neg-inN/A

                                                                \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                              4. lower-*.f64N/A

                                                                \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                              5. lower-neg.f64N/A

                                                                \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
                                                              6. lower-sqrt.f64N/A

                                                                \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
                                                              7. lower-sqrt.f64N/A

                                                                \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
                                                              8. lower-/.f6414.2

                                                                \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                            5. Applied rewrites14.2%

                                                              \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                            6. Step-by-step derivation
                                                              1. Applied rewrites14.3%

                                                                \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                              2. Step-by-step derivation
                                                                1. Applied rewrites14.3%

                                                                  \[\leadsto -\sqrt{\frac{F + F}{B}} \]
                                                              3. Recombined 2 regimes into one program.
                                                              4. Add Preprocessing

                                                              Alternative 11: 34.9% accurate, 12.3× speedup?

                                                              \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;F \leq 4.5 \cdot 10^{-32}:\\ \;\;\;\;\frac{\sqrt{\left(F \cdot B\_m\right) \cdot 2}}{-B\_m}\\ \mathbf{else}:\\ \;\;\;\;-\sqrt{\frac{F + F}{B\_m}}\\ \end{array} \end{array} \]
                                                              B_m = (fabs.f64 B)
                                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                              (FPCore (A B_m C F)
                                                               :precision binary64
                                                               (if (<= F 4.5e-32)
                                                                 (/ (sqrt (* (* F B_m) 2.0)) (- B_m))
                                                                 (- (sqrt (/ (+ F F) B_m)))))
                                                              B_m = fabs(B);
                                                              assert(A < B_m && B_m < C && C < F);
                                                              double code(double A, double B_m, double C, double F) {
                                                              	double tmp;
                                                              	if (F <= 4.5e-32) {
                                                              		tmp = sqrt(((F * B_m) * 2.0)) / -B_m;
                                                              	} else {
                                                              		tmp = -sqrt(((F + F) / B_m));
                                                              	}
                                                              	return tmp;
                                                              }
                                                              
                                                              B_m = abs(b)
                                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                              real(8) function code(a, b_m, c, f)
                                                                  real(8), intent (in) :: a
                                                                  real(8), intent (in) :: b_m
                                                                  real(8), intent (in) :: c
                                                                  real(8), intent (in) :: f
                                                                  real(8) :: tmp
                                                                  if (f <= 4.5d-32) then
                                                                      tmp = sqrt(((f * b_m) * 2.0d0)) / -b_m
                                                                  else
                                                                      tmp = -sqrt(((f + f) / b_m))
                                                                  end if
                                                                  code = tmp
                                                              end function
                                                              
                                                              B_m = Math.abs(B);
                                                              assert A < B_m && B_m < C && C < F;
                                                              public static double code(double A, double B_m, double C, double F) {
                                                              	double tmp;
                                                              	if (F <= 4.5e-32) {
                                                              		tmp = Math.sqrt(((F * B_m) * 2.0)) / -B_m;
                                                              	} else {
                                                              		tmp = -Math.sqrt(((F + F) / B_m));
                                                              	}
                                                              	return tmp;
                                                              }
                                                              
                                                              B_m = math.fabs(B)
                                                              [A, B_m, C, F] = sort([A, B_m, C, F])
                                                              def code(A, B_m, C, F):
                                                              	tmp = 0
                                                              	if F <= 4.5e-32:
                                                              		tmp = math.sqrt(((F * B_m) * 2.0)) / -B_m
                                                              	else:
                                                              		tmp = -math.sqrt(((F + F) / B_m))
                                                              	return tmp
                                                              
                                                              B_m = abs(B)
                                                              A, B_m, C, F = sort([A, B_m, C, F])
                                                              function code(A, B_m, C, F)
                                                              	tmp = 0.0
                                                              	if (F <= 4.5e-32)
                                                              		tmp = Float64(sqrt(Float64(Float64(F * B_m) * 2.0)) / Float64(-B_m));
                                                              	else
                                                              		tmp = Float64(-sqrt(Float64(Float64(F + F) / B_m)));
                                                              	end
                                                              	return tmp
                                                              end
                                                              
                                                              B_m = abs(B);
                                                              A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                              function tmp_2 = code(A, B_m, C, F)
                                                              	tmp = 0.0;
                                                              	if (F <= 4.5e-32)
                                                              		tmp = sqrt(((F * B_m) * 2.0)) / -B_m;
                                                              	else
                                                              		tmp = -sqrt(((F + F) / B_m));
                                                              	end
                                                              	tmp_2 = tmp;
                                                              end
                                                              
                                                              B_m = N[Abs[B], $MachinePrecision]
                                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                              code[A_, B$95$m_, C_, F_] := If[LessEqual[F, 4.5e-32], N[(N[Sqrt[N[(N[(F * B$95$m), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision], (-N[Sqrt[N[(N[(F + F), $MachinePrecision] / B$95$m), $MachinePrecision]], $MachinePrecision])]
                                                              
                                                              \begin{array}{l}
                                                              B_m = \left|B\right|
                                                              \\
                                                              [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                              \\
                                                              \begin{array}{l}
                                                              \mathbf{if}\;F \leq 4.5 \cdot 10^{-32}:\\
                                                              \;\;\;\;\frac{\sqrt{\left(F \cdot B\_m\right) \cdot 2}}{-B\_m}\\
                                                              
                                                              \mathbf{else}:\\
                                                              \;\;\;\;-\sqrt{\frac{F + F}{B\_m}}\\
                                                              
                                                              
                                                              \end{array}
                                                              \end{array}
                                                              
                                                              Derivation
                                                              1. Split input into 2 regimes
                                                              2. if F < 4.50000000000000005e-32

                                                                1. Initial program 16.7%

                                                                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                2. Add Preprocessing
                                                                3. Taylor expanded in A around 0

                                                                  \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                4. Step-by-step derivation
                                                                  1. mul-1-negN/A

                                                                    \[\leadsto \color{blue}{\mathsf{neg}\left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                  2. distribute-lft-neg-inN/A

                                                                    \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                  3. lower-*.f64N/A

                                                                    \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                  4. lower-neg.f64N/A

                                                                    \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                  5. lower-/.f64N/A

                                                                    \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                  6. lower-sqrt.f64N/A

                                                                    \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                  7. lower-sqrt.f64N/A

                                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                  8. *-commutativeN/A

                                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                                  9. lower-*.f64N/A

                                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                                  10. +-commutativeN/A

                                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                                  11. lower-+.f64N/A

                                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                                  12. unpow2N/A

                                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{B \cdot B} + {C}^{2}} + C\right) \cdot F} \]
                                                                  13. unpow2N/A

                                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{B \cdot B + \color{blue}{C \cdot C}} + C\right) \cdot F} \]
                                                                  14. lower-hypot.f6422.0

                                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(B, C\right)} + C\right) \cdot F} \]
                                                                5. Applied rewrites22.0%

                                                                  \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(B, C\right) + C\right) \cdot F}} \]
                                                                6. Step-by-step derivation
                                                                  1. Applied rewrites22.0%

                                                                    \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]
                                                                  2. Taylor expanded in B around inf

                                                                    \[\leadsto \frac{\sqrt{2 \cdot \left(B \cdot F\right)}}{-B} \]
                                                                  3. Step-by-step derivation
                                                                    1. Applied rewrites19.3%

                                                                      \[\leadsto \frac{\sqrt{\left(F \cdot B\right) \cdot 2}}{-B} \]

                                                                    if 4.50000000000000005e-32 < F

                                                                    1. Initial program 17.4%

                                                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                    2. Add Preprocessing
                                                                    3. Taylor expanded in B around inf

                                                                      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                    4. Step-by-step derivation
                                                                      1. mul-1-negN/A

                                                                        \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                      2. *-commutativeN/A

                                                                        \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                      3. distribute-lft-neg-inN/A

                                                                        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                      4. lower-*.f64N/A

                                                                        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                      5. lower-neg.f64N/A

                                                                        \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
                                                                      6. lower-sqrt.f64N/A

                                                                        \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
                                                                      7. lower-sqrt.f64N/A

                                                                        \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
                                                                      8. lower-/.f6416.2

                                                                        \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                                    5. Applied rewrites16.2%

                                                                      \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                    6. Step-by-step derivation
                                                                      1. Applied rewrites16.3%

                                                                        \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                      2. Step-by-step derivation
                                                                        1. Applied rewrites16.3%

                                                                          \[\leadsto -\sqrt{\frac{F + F}{B}} \]
                                                                      3. Recombined 2 regimes into one program.
                                                                      4. Add Preprocessing

                                                                      Alternative 12: 35.7% accurate, 12.6× speedup?

                                                                      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \frac{\sqrt{F \cdot 2}}{-\sqrt{B\_m}} \end{array} \]
                                                                      B_m = (fabs.f64 B)
                                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                      (FPCore (A B_m C F) :precision binary64 (/ (sqrt (* F 2.0)) (- (sqrt B_m))))
                                                                      B_m = fabs(B);
                                                                      assert(A < B_m && B_m < C && C < F);
                                                                      double code(double A, double B_m, double C, double F) {
                                                                      	return sqrt((F * 2.0)) / -sqrt(B_m);
                                                                      }
                                                                      
                                                                      B_m = abs(b)
                                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                      real(8) function code(a, b_m, c, f)
                                                                          real(8), intent (in) :: a
                                                                          real(8), intent (in) :: b_m
                                                                          real(8), intent (in) :: c
                                                                          real(8), intent (in) :: f
                                                                          code = sqrt((f * 2.0d0)) / -sqrt(b_m)
                                                                      end function
                                                                      
                                                                      B_m = Math.abs(B);
                                                                      assert A < B_m && B_m < C && C < F;
                                                                      public static double code(double A, double B_m, double C, double F) {
                                                                      	return Math.sqrt((F * 2.0)) / -Math.sqrt(B_m);
                                                                      }
                                                                      
                                                                      B_m = math.fabs(B)
                                                                      [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                      def code(A, B_m, C, F):
                                                                      	return math.sqrt((F * 2.0)) / -math.sqrt(B_m)
                                                                      
                                                                      B_m = abs(B)
                                                                      A, B_m, C, F = sort([A, B_m, C, F])
                                                                      function code(A, B_m, C, F)
                                                                      	return Float64(sqrt(Float64(F * 2.0)) / Float64(-sqrt(B_m)))
                                                                      end
                                                                      
                                                                      B_m = abs(B);
                                                                      A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                      function tmp = code(A, B_m, C, F)
                                                                      	tmp = sqrt((F * 2.0)) / -sqrt(B_m);
                                                                      end
                                                                      
                                                                      B_m = N[Abs[B], $MachinePrecision]
                                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                      code[A_, B$95$m_, C_, F_] := N[(N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision] / (-N[Sqrt[B$95$m], $MachinePrecision])), $MachinePrecision]
                                                                      
                                                                      \begin{array}{l}
                                                                      B_m = \left|B\right|
                                                                      \\
                                                                      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                      \\
                                                                      \frac{\sqrt{F \cdot 2}}{-\sqrt{B\_m}}
                                                                      \end{array}
                                                                      
                                                                      Derivation
                                                                      1. Initial program 17.0%

                                                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                      2. Add Preprocessing
                                                                      3. Taylor expanded in B around inf

                                                                        \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                      4. Step-by-step derivation
                                                                        1. mul-1-negN/A

                                                                          \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                        2. *-commutativeN/A

                                                                          \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                        3. distribute-lft-neg-inN/A

                                                                          \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                        4. lower-*.f64N/A

                                                                          \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                        5. lower-neg.f64N/A

                                                                          \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
                                                                        6. lower-sqrt.f64N/A

                                                                          \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
                                                                        7. lower-sqrt.f64N/A

                                                                          \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
                                                                        8. lower-/.f6412.0

                                                                          \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                                      5. Applied rewrites12.0%

                                                                        \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                      6. Step-by-step derivation
                                                                        1. Applied rewrites12.1%

                                                                          \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                        2. Step-by-step derivation
                                                                          1. Applied rewrites17.2%

                                                                            \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
                                                                          2. Final simplification17.2%

                                                                            \[\leadsto \frac{\sqrt{F \cdot 2}}{-\sqrt{B}} \]
                                                                          3. Add Preprocessing

                                                                          Alternative 13: 27.8% accurate, 18.2× speedup?

                                                                          \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ -\sqrt{\frac{F + F}{B\_m}} \end{array} \]
                                                                          B_m = (fabs.f64 B)
                                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                          (FPCore (A B_m C F) :precision binary64 (- (sqrt (/ (+ F F) B_m))))
                                                                          B_m = fabs(B);
                                                                          assert(A < B_m && B_m < C && C < F);
                                                                          double code(double A, double B_m, double C, double F) {
                                                                          	return -sqrt(((F + F) / B_m));
                                                                          }
                                                                          
                                                                          B_m = abs(b)
                                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                          real(8) function code(a, b_m, c, f)
                                                                              real(8), intent (in) :: a
                                                                              real(8), intent (in) :: b_m
                                                                              real(8), intent (in) :: c
                                                                              real(8), intent (in) :: f
                                                                              code = -sqrt(((f + f) / b_m))
                                                                          end function
                                                                          
                                                                          B_m = Math.abs(B);
                                                                          assert A < B_m && B_m < C && C < F;
                                                                          public static double code(double A, double B_m, double C, double F) {
                                                                          	return -Math.sqrt(((F + F) / B_m));
                                                                          }
                                                                          
                                                                          B_m = math.fabs(B)
                                                                          [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                          def code(A, B_m, C, F):
                                                                          	return -math.sqrt(((F + F) / B_m))
                                                                          
                                                                          B_m = abs(B)
                                                                          A, B_m, C, F = sort([A, B_m, C, F])
                                                                          function code(A, B_m, C, F)
                                                                          	return Float64(-sqrt(Float64(Float64(F + F) / B_m)))
                                                                          end
                                                                          
                                                                          B_m = abs(B);
                                                                          A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                          function tmp = code(A, B_m, C, F)
                                                                          	tmp = -sqrt(((F + F) / B_m));
                                                                          end
                                                                          
                                                                          B_m = N[Abs[B], $MachinePrecision]
                                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                          code[A_, B$95$m_, C_, F_] := (-N[Sqrt[N[(N[(F + F), $MachinePrecision] / B$95$m), $MachinePrecision]], $MachinePrecision])
                                                                          
                                                                          \begin{array}{l}
                                                                          B_m = \left|B\right|
                                                                          \\
                                                                          [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                          \\
                                                                          -\sqrt{\frac{F + F}{B\_m}}
                                                                          \end{array}
                                                                          
                                                                          Derivation
                                                                          1. Initial program 17.0%

                                                                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                          2. Add Preprocessing
                                                                          3. Taylor expanded in B around inf

                                                                            \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                          4. Step-by-step derivation
                                                                            1. mul-1-negN/A

                                                                              \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                            2. *-commutativeN/A

                                                                              \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                            3. distribute-lft-neg-inN/A

                                                                              \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                            4. lower-*.f64N/A

                                                                              \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                            5. lower-neg.f64N/A

                                                                              \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
                                                                            6. lower-sqrt.f64N/A

                                                                              \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
                                                                            7. lower-sqrt.f64N/A

                                                                              \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
                                                                            8. lower-/.f6412.0

                                                                              \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                                          5. Applied rewrites12.0%

                                                                            \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                          6. Step-by-step derivation
                                                                            1. Applied rewrites12.1%

                                                                              \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                            2. Step-by-step derivation
                                                                              1. Applied rewrites12.1%

                                                                                \[\leadsto -\sqrt{\frac{F + F}{B}} \]
                                                                              2. Add Preprocessing

                                                                              Reproduce

                                                                              ?
                                                                              herbie shell --seed 2024337 
                                                                              (FPCore (A B C F)
                                                                                :name "ABCF->ab-angle a"
                                                                                :precision binary64
                                                                                (/ (- (sqrt (* (* 2.0 (* (- (pow B 2.0) (* (* 4.0 A) C)) F)) (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))) (- (pow B 2.0) (* (* 4.0 A) C))))