Diagrams.Solve.Polynomial:cubForm from diagrams-solve-0.1, B

Percentage Accurate: 99.8% → 99.8%
Time: 8.4s
Alternatives: 6
Speedup: 1.0×

Specification

?
\[\begin{array}{l} \\ \left(x \cdot 3\right) \cdot y - z \end{array} \]
(FPCore (x y z) :precision binary64 (- (* (* x 3.0) y) z))
double code(double x, double y, double z) {
	return ((x * 3.0) * y) - z;
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = ((x * 3.0d0) * y) - z
end function
public static double code(double x, double y, double z) {
	return ((x * 3.0) * y) - z;
}
def code(x, y, z):
	return ((x * 3.0) * y) - z
function code(x, y, z)
	return Float64(Float64(Float64(x * 3.0) * y) - z)
end
function tmp = code(x, y, z)
	tmp = ((x * 3.0) * y) - z;
end
code[x_, y_, z_] := N[(N[(N[(x * 3.0), $MachinePrecision] * y), $MachinePrecision] - z), $MachinePrecision]
\begin{array}{l}

\\
\left(x \cdot 3\right) \cdot y - z
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 6 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 99.8% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \left(x \cdot 3\right) \cdot y - z \end{array} \]
(FPCore (x y z) :precision binary64 (- (* (* x 3.0) y) z))
double code(double x, double y, double z) {
	return ((x * 3.0) * y) - z;
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = ((x * 3.0d0) * y) - z
end function
public static double code(double x, double y, double z) {
	return ((x * 3.0) * y) - z;
}
def code(x, y, z):
	return ((x * 3.0) * y) - z
function code(x, y, z)
	return Float64(Float64(Float64(x * 3.0) * y) - z)
end
function tmp = code(x, y, z)
	tmp = ((x * 3.0) * y) - z;
end
code[x_, y_, z_] := N[(N[(N[(x * 3.0), $MachinePrecision] * y), $MachinePrecision] - z), $MachinePrecision]
\begin{array}{l}

\\
\left(x \cdot 3\right) \cdot y - z
\end{array}

Alternative 1: 99.8% accurate, 1.0× speedup?

\[\begin{array}{l} [x, y, z] = \mathsf{sort}([x, y, z])\\ \\ \left(y \cdot 3\right) \cdot x - z \end{array} \]
NOTE: x, y, and z should be sorted in increasing order before calling this function.
(FPCore (x y z) :precision binary64 (- (* (* y 3.0) x) z))
assert(x < y && y < z);
double code(double x, double y, double z) {
	return ((y * 3.0) * x) - z;
}
NOTE: x, y, and z should be sorted in increasing order before calling this function.
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = ((y * 3.0d0) * x) - z
end function
assert x < y && y < z;
public static double code(double x, double y, double z) {
	return ((y * 3.0) * x) - z;
}
[x, y, z] = sort([x, y, z])
def code(x, y, z):
	return ((y * 3.0) * x) - z
x, y, z = sort([x, y, z])
function code(x, y, z)
	return Float64(Float64(Float64(y * 3.0) * x) - z)
end
x, y, z = num2cell(sort([x, y, z])){:}
function tmp = code(x, y, z)
	tmp = ((y * 3.0) * x) - z;
end
NOTE: x, y, and z should be sorted in increasing order before calling this function.
code[x_, y_, z_] := N[(N[(N[(y * 3.0), $MachinePrecision] * x), $MachinePrecision] - z), $MachinePrecision]
\begin{array}{l}
[x, y, z] = \mathsf{sort}([x, y, z])\\
\\
\left(y \cdot 3\right) \cdot x - z
\end{array}
Derivation
  1. Initial program 99.9%

    \[\left(x \cdot 3\right) \cdot y - z \]
  2. Add Preprocessing
  3. Step-by-step derivation
    1. lift-*.f64N/A

      \[\leadsto \color{blue}{\left(x \cdot 3\right) \cdot y} - z \]
    2. lift-*.f64N/A

      \[\leadsto \color{blue}{\left(x \cdot 3\right)} \cdot y - z \]
    3. associate-*l*N/A

      \[\leadsto \color{blue}{x \cdot \left(3 \cdot y\right)} - z \]
    4. *-commutativeN/A

      \[\leadsto \color{blue}{\left(3 \cdot y\right) \cdot x} - z \]
    5. lower-*.f64N/A

      \[\leadsto \color{blue}{\left(3 \cdot y\right) \cdot x} - z \]
    6. *-commutativeN/A

      \[\leadsto \color{blue}{\left(y \cdot 3\right)} \cdot x - z \]
    7. lower-*.f6499.8

      \[\leadsto \color{blue}{\left(y \cdot 3\right)} \cdot x - z \]
  4. Applied rewrites99.8%

    \[\leadsto \color{blue}{\left(y \cdot 3\right) \cdot x} - z \]
  5. Add Preprocessing

Alternative 2: 77.4% accurate, 0.3× speedup?

\[\begin{array}{l} [x, y, z] = \mathsf{sort}([x, y, z])\\ \\ \begin{array}{l} t_0 := \left(x \cdot 3\right) \cdot y\\ \mathbf{if}\;t\_0 \leq -1 \cdot 10^{-73} \lor \neg \left(t\_0 \leq 10^{+73}\right):\\ \;\;\;\;\left(3 \cdot y\right) \cdot x\\ \mathbf{else}:\\ \;\;\;\;-z\\ \end{array} \end{array} \]
NOTE: x, y, and z should be sorted in increasing order before calling this function.
(FPCore (x y z)
 :precision binary64
 (let* ((t_0 (* (* x 3.0) y)))
   (if (or (<= t_0 -1e-73) (not (<= t_0 1e+73))) (* (* 3.0 y) x) (- z))))
assert(x < y && y < z);
double code(double x, double y, double z) {
	double t_0 = (x * 3.0) * y;
	double tmp;
	if ((t_0 <= -1e-73) || !(t_0 <= 1e+73)) {
		tmp = (3.0 * y) * x;
	} else {
		tmp = -z;
	}
	return tmp;
}
NOTE: x, y, and z should be sorted in increasing order before calling this function.
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8) :: t_0
    real(8) :: tmp
    t_0 = (x * 3.0d0) * y
    if ((t_0 <= (-1d-73)) .or. (.not. (t_0 <= 1d+73))) then
        tmp = (3.0d0 * y) * x
    else
        tmp = -z
    end if
    code = tmp
end function
assert x < y && y < z;
public static double code(double x, double y, double z) {
	double t_0 = (x * 3.0) * y;
	double tmp;
	if ((t_0 <= -1e-73) || !(t_0 <= 1e+73)) {
		tmp = (3.0 * y) * x;
	} else {
		tmp = -z;
	}
	return tmp;
}
[x, y, z] = sort([x, y, z])
def code(x, y, z):
	t_0 = (x * 3.0) * y
	tmp = 0
	if (t_0 <= -1e-73) or not (t_0 <= 1e+73):
		tmp = (3.0 * y) * x
	else:
		tmp = -z
	return tmp
x, y, z = sort([x, y, z])
function code(x, y, z)
	t_0 = Float64(Float64(x * 3.0) * y)
	tmp = 0.0
	if ((t_0 <= -1e-73) || !(t_0 <= 1e+73))
		tmp = Float64(Float64(3.0 * y) * x);
	else
		tmp = Float64(-z);
	end
	return tmp
end
x, y, z = num2cell(sort([x, y, z])){:}
function tmp_2 = code(x, y, z)
	t_0 = (x * 3.0) * y;
	tmp = 0.0;
	if ((t_0 <= -1e-73) || ~((t_0 <= 1e+73)))
		tmp = (3.0 * y) * x;
	else
		tmp = -z;
	end
	tmp_2 = tmp;
end
NOTE: x, y, and z should be sorted in increasing order before calling this function.
code[x_, y_, z_] := Block[{t$95$0 = N[(N[(x * 3.0), $MachinePrecision] * y), $MachinePrecision]}, If[Or[LessEqual[t$95$0, -1e-73], N[Not[LessEqual[t$95$0, 1e+73]], $MachinePrecision]], N[(N[(3.0 * y), $MachinePrecision] * x), $MachinePrecision], (-z)]]
\begin{array}{l}
[x, y, z] = \mathsf{sort}([x, y, z])\\
\\
\begin{array}{l}
t_0 := \left(x \cdot 3\right) \cdot y\\
\mathbf{if}\;t\_0 \leq -1 \cdot 10^{-73} \lor \neg \left(t\_0 \leq 10^{+73}\right):\\
\;\;\;\;\left(3 \cdot y\right) \cdot x\\

\mathbf{else}:\\
\;\;\;\;-z\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (*.f64 (*.f64 x #s(literal 3 binary64)) y) < -9.99999999999999997e-74 or 9.99999999999999983e72 < (*.f64 (*.f64 x #s(literal 3 binary64)) y)

    1. Initial program 99.9%

      \[\left(x \cdot 3\right) \cdot y - z \]
    2. Add Preprocessing
    3. Applied rewrites99.7%

      \[\leadsto \color{blue}{-\mathsf{fma}\left(-3, y \cdot x, z\right)} \]
    4. Taylor expanded in x around inf

      \[\leadsto -\color{blue}{-3 \cdot \left(x \cdot y\right)} \]
    5. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto -\color{blue}{-3 \cdot \left(x \cdot y\right)} \]
      2. lower-*.f6483.7

        \[\leadsto --3 \cdot \color{blue}{\left(x \cdot y\right)} \]
    6. Applied rewrites83.7%

      \[\leadsto -\color{blue}{-3 \cdot \left(x \cdot y\right)} \]
    7. Taylor expanded in x around inf

      \[\leadsto \color{blue}{3 \cdot \left(x \cdot y\right)} \]
    8. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto \color{blue}{\left(x \cdot y\right) \cdot 3} \]
      2. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(x \cdot y\right) \cdot 3} \]
      3. lower-*.f6483.7

        \[\leadsto \color{blue}{\left(x \cdot y\right)} \cdot 3 \]
    9. Applied rewrites83.7%

      \[\leadsto \color{blue}{\left(x \cdot y\right) \cdot 3} \]
    10. Step-by-step derivation
      1. Applied rewrites83.8%

        \[\leadsto \left(3 \cdot y\right) \cdot \color{blue}{x} \]

      if -9.99999999999999997e-74 < (*.f64 (*.f64 x #s(literal 3 binary64)) y) < 9.99999999999999983e72

      1. Initial program 100.0%

        \[\left(x \cdot 3\right) \cdot y - z \]
      2. Add Preprocessing
      3. Taylor expanded in x around 0

        \[\leadsto \color{blue}{-1 \cdot z} \]
      4. Step-by-step derivation
        1. mul-1-negN/A

          \[\leadsto \color{blue}{\mathsf{neg}\left(z\right)} \]
        2. lower-neg.f6484.2

          \[\leadsto \color{blue}{-z} \]
      5. Applied rewrites84.2%

        \[\leadsto \color{blue}{-z} \]
    11. Recombined 2 regimes into one program.
    12. Final simplification84.0%

      \[\leadsto \begin{array}{l} \mathbf{if}\;\left(x \cdot 3\right) \cdot y \leq -1 \cdot 10^{-73} \lor \neg \left(\left(x \cdot 3\right) \cdot y \leq 10^{+73}\right):\\ \;\;\;\;\left(3 \cdot y\right) \cdot x\\ \mathbf{else}:\\ \;\;\;\;-z\\ \end{array} \]
    13. Add Preprocessing

    Alternative 3: 77.4% accurate, 0.3× speedup?

    \[\begin{array}{l} [x, y, z] = \mathsf{sort}([x, y, z])\\ \\ \begin{array}{l} t_0 := \left(x \cdot 3\right) \cdot y\\ \mathbf{if}\;t\_0 \leq -1 \cdot 10^{-73}:\\ \;\;\;\;\left(3 \cdot x\right) \cdot y\\ \mathbf{elif}\;t\_0 \leq 10^{+73}:\\ \;\;\;\;-z\\ \mathbf{else}:\\ \;\;\;\;\left(3 \cdot y\right) \cdot x\\ \end{array} \end{array} \]
    NOTE: x, y, and z should be sorted in increasing order before calling this function.
    (FPCore (x y z)
     :precision binary64
     (let* ((t_0 (* (* x 3.0) y)))
       (if (<= t_0 -1e-73)
         (* (* 3.0 x) y)
         (if (<= t_0 1e+73) (- z) (* (* 3.0 y) x)))))
    assert(x < y && y < z);
    double code(double x, double y, double z) {
    	double t_0 = (x * 3.0) * y;
    	double tmp;
    	if (t_0 <= -1e-73) {
    		tmp = (3.0 * x) * y;
    	} else if (t_0 <= 1e+73) {
    		tmp = -z;
    	} else {
    		tmp = (3.0 * y) * x;
    	}
    	return tmp;
    }
    
    NOTE: x, y, and z should be sorted in increasing order before calling this function.
    real(8) function code(x, y, z)
        real(8), intent (in) :: x
        real(8), intent (in) :: y
        real(8), intent (in) :: z
        real(8) :: t_0
        real(8) :: tmp
        t_0 = (x * 3.0d0) * y
        if (t_0 <= (-1d-73)) then
            tmp = (3.0d0 * x) * y
        else if (t_0 <= 1d+73) then
            tmp = -z
        else
            tmp = (3.0d0 * y) * x
        end if
        code = tmp
    end function
    
    assert x < y && y < z;
    public static double code(double x, double y, double z) {
    	double t_0 = (x * 3.0) * y;
    	double tmp;
    	if (t_0 <= -1e-73) {
    		tmp = (3.0 * x) * y;
    	} else if (t_0 <= 1e+73) {
    		tmp = -z;
    	} else {
    		tmp = (3.0 * y) * x;
    	}
    	return tmp;
    }
    
    [x, y, z] = sort([x, y, z])
    def code(x, y, z):
    	t_0 = (x * 3.0) * y
    	tmp = 0
    	if t_0 <= -1e-73:
    		tmp = (3.0 * x) * y
    	elif t_0 <= 1e+73:
    		tmp = -z
    	else:
    		tmp = (3.0 * y) * x
    	return tmp
    
    x, y, z = sort([x, y, z])
    function code(x, y, z)
    	t_0 = Float64(Float64(x * 3.0) * y)
    	tmp = 0.0
    	if (t_0 <= -1e-73)
    		tmp = Float64(Float64(3.0 * x) * y);
    	elseif (t_0 <= 1e+73)
    		tmp = Float64(-z);
    	else
    		tmp = Float64(Float64(3.0 * y) * x);
    	end
    	return tmp
    end
    
    x, y, z = num2cell(sort([x, y, z])){:}
    function tmp_2 = code(x, y, z)
    	t_0 = (x * 3.0) * y;
    	tmp = 0.0;
    	if (t_0 <= -1e-73)
    		tmp = (3.0 * x) * y;
    	elseif (t_0 <= 1e+73)
    		tmp = -z;
    	else
    		tmp = (3.0 * y) * x;
    	end
    	tmp_2 = tmp;
    end
    
    NOTE: x, y, and z should be sorted in increasing order before calling this function.
    code[x_, y_, z_] := Block[{t$95$0 = N[(N[(x * 3.0), $MachinePrecision] * y), $MachinePrecision]}, If[LessEqual[t$95$0, -1e-73], N[(N[(3.0 * x), $MachinePrecision] * y), $MachinePrecision], If[LessEqual[t$95$0, 1e+73], (-z), N[(N[(3.0 * y), $MachinePrecision] * x), $MachinePrecision]]]]
    
    \begin{array}{l}
    [x, y, z] = \mathsf{sort}([x, y, z])\\
    \\
    \begin{array}{l}
    t_0 := \left(x \cdot 3\right) \cdot y\\
    \mathbf{if}\;t\_0 \leq -1 \cdot 10^{-73}:\\
    \;\;\;\;\left(3 \cdot x\right) \cdot y\\
    
    \mathbf{elif}\;t\_0 \leq 10^{+73}:\\
    \;\;\;\;-z\\
    
    \mathbf{else}:\\
    \;\;\;\;\left(3 \cdot y\right) \cdot x\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 3 regimes
    2. if (*.f64 (*.f64 x #s(literal 3 binary64)) y) < -9.99999999999999997e-74

      1. Initial program 99.9%

        \[\left(x \cdot 3\right) \cdot y - z \]
      2. Add Preprocessing
      3. Applied rewrites99.7%

        \[\leadsto \color{blue}{-\mathsf{fma}\left(-3, y \cdot x, z\right)} \]
      4. Taylor expanded in x around inf

        \[\leadsto -\color{blue}{-3 \cdot \left(x \cdot y\right)} \]
      5. Step-by-step derivation
        1. lower-*.f64N/A

          \[\leadsto -\color{blue}{-3 \cdot \left(x \cdot y\right)} \]
        2. lower-*.f6478.9

          \[\leadsto --3 \cdot \color{blue}{\left(x \cdot y\right)} \]
      6. Applied rewrites78.9%

        \[\leadsto -\color{blue}{-3 \cdot \left(x \cdot y\right)} \]
      7. Taylor expanded in x around inf

        \[\leadsto \color{blue}{3 \cdot \left(x \cdot y\right)} \]
      8. Step-by-step derivation
        1. *-commutativeN/A

          \[\leadsto \color{blue}{\left(x \cdot y\right) \cdot 3} \]
        2. lower-*.f64N/A

          \[\leadsto \color{blue}{\left(x \cdot y\right) \cdot 3} \]
        3. lower-*.f6478.9

          \[\leadsto \color{blue}{\left(x \cdot y\right)} \cdot 3 \]
      9. Applied rewrites78.9%

        \[\leadsto \color{blue}{\left(x \cdot y\right) \cdot 3} \]
      10. Applied rewrites79.2%

        \[\leadsto \color{blue}{\left(3 \cdot x\right) \cdot y} \]

      if -9.99999999999999997e-74 < (*.f64 (*.f64 x #s(literal 3 binary64)) y) < 9.99999999999999983e72

      1. Initial program 100.0%

        \[\left(x \cdot 3\right) \cdot y - z \]
      2. Add Preprocessing
      3. Taylor expanded in x around 0

        \[\leadsto \color{blue}{-1 \cdot z} \]
      4. Step-by-step derivation
        1. mul-1-negN/A

          \[\leadsto \color{blue}{\mathsf{neg}\left(z\right)} \]
        2. lower-neg.f6484.2

          \[\leadsto \color{blue}{-z} \]
      5. Applied rewrites84.2%

        \[\leadsto \color{blue}{-z} \]

      if 9.99999999999999983e72 < (*.f64 (*.f64 x #s(literal 3 binary64)) y)

      1. Initial program 99.9%

        \[\left(x \cdot 3\right) \cdot y - z \]
      2. Add Preprocessing
      3. Applied rewrites99.7%

        \[\leadsto \color{blue}{-\mathsf{fma}\left(-3, y \cdot x, z\right)} \]
      4. Taylor expanded in x around inf

        \[\leadsto -\color{blue}{-3 \cdot \left(x \cdot y\right)} \]
      5. Step-by-step derivation
        1. lower-*.f64N/A

          \[\leadsto -\color{blue}{-3 \cdot \left(x \cdot y\right)} \]
        2. lower-*.f6491.8

          \[\leadsto --3 \cdot \color{blue}{\left(x \cdot y\right)} \]
      6. Applied rewrites91.8%

        \[\leadsto -\color{blue}{-3 \cdot \left(x \cdot y\right)} \]
      7. Taylor expanded in x around inf

        \[\leadsto \color{blue}{3 \cdot \left(x \cdot y\right)} \]
      8. Step-by-step derivation
        1. *-commutativeN/A

          \[\leadsto \color{blue}{\left(x \cdot y\right) \cdot 3} \]
        2. lower-*.f64N/A

          \[\leadsto \color{blue}{\left(x \cdot y\right) \cdot 3} \]
        3. lower-*.f6491.8

          \[\leadsto \color{blue}{\left(x \cdot y\right)} \cdot 3 \]
      9. Applied rewrites91.8%

        \[\leadsto \color{blue}{\left(x \cdot y\right) \cdot 3} \]
      10. Step-by-step derivation
        1. Applied rewrites91.8%

          \[\leadsto \left(3 \cdot y\right) \cdot \color{blue}{x} \]
      11. Recombined 3 regimes into one program.
      12. Add Preprocessing

      Alternative 4: 99.8% accurate, 1.0× speedup?

      \[\begin{array}{l} [x, y, z] = \mathsf{sort}([x, y, z])\\ \\ \left(x \cdot 3\right) \cdot y - z \end{array} \]
      NOTE: x, y, and z should be sorted in increasing order before calling this function.
      (FPCore (x y z) :precision binary64 (- (* (* x 3.0) y) z))
      assert(x < y && y < z);
      double code(double x, double y, double z) {
      	return ((x * 3.0) * y) - z;
      }
      
      NOTE: x, y, and z should be sorted in increasing order before calling this function.
      real(8) function code(x, y, z)
          real(8), intent (in) :: x
          real(8), intent (in) :: y
          real(8), intent (in) :: z
          code = ((x * 3.0d0) * y) - z
      end function
      
      assert x < y && y < z;
      public static double code(double x, double y, double z) {
      	return ((x * 3.0) * y) - z;
      }
      
      [x, y, z] = sort([x, y, z])
      def code(x, y, z):
      	return ((x * 3.0) * y) - z
      
      x, y, z = sort([x, y, z])
      function code(x, y, z)
      	return Float64(Float64(Float64(x * 3.0) * y) - z)
      end
      
      x, y, z = num2cell(sort([x, y, z])){:}
      function tmp = code(x, y, z)
      	tmp = ((x * 3.0) * y) - z;
      end
      
      NOTE: x, y, and z should be sorted in increasing order before calling this function.
      code[x_, y_, z_] := N[(N[(N[(x * 3.0), $MachinePrecision] * y), $MachinePrecision] - z), $MachinePrecision]
      
      \begin{array}{l}
      [x, y, z] = \mathsf{sort}([x, y, z])\\
      \\
      \left(x \cdot 3\right) \cdot y - z
      \end{array}
      
      Derivation
      1. Initial program 99.9%

        \[\left(x \cdot 3\right) \cdot y - z \]
      2. Add Preprocessing
      3. Add Preprocessing

      Alternative 5: 99.8% accurate, 1.0× speedup?

      \[\begin{array}{l} [x, y, z] = \mathsf{sort}([x, y, z])\\ \\ -\mathsf{fma}\left(-3, y \cdot x, z\right) \end{array} \]
      NOTE: x, y, and z should be sorted in increasing order before calling this function.
      (FPCore (x y z) :precision binary64 (- (fma -3.0 (* y x) z)))
      assert(x < y && y < z);
      double code(double x, double y, double z) {
      	return -fma(-3.0, (y * x), z);
      }
      
      x, y, z = sort([x, y, z])
      function code(x, y, z)
      	return Float64(-fma(-3.0, Float64(y * x), z))
      end
      
      NOTE: x, y, and z should be sorted in increasing order before calling this function.
      code[x_, y_, z_] := (-N[(-3.0 * N[(y * x), $MachinePrecision] + z), $MachinePrecision])
      
      \begin{array}{l}
      [x, y, z] = \mathsf{sort}([x, y, z])\\
      \\
      -\mathsf{fma}\left(-3, y \cdot x, z\right)
      \end{array}
      
      Derivation
      1. Initial program 99.9%

        \[\left(x \cdot 3\right) \cdot y - z \]
      2. Add Preprocessing
      3. Applied rewrites99.8%

        \[\leadsto \color{blue}{-\mathsf{fma}\left(-3, y \cdot x, z\right)} \]
      4. Add Preprocessing

      Alternative 6: 51.9% accurate, 4.7× speedup?

      \[\begin{array}{l} [x, y, z] = \mathsf{sort}([x, y, z])\\ \\ -z \end{array} \]
      NOTE: x, y, and z should be sorted in increasing order before calling this function.
      (FPCore (x y z) :precision binary64 (- z))
      assert(x < y && y < z);
      double code(double x, double y, double z) {
      	return -z;
      }
      
      NOTE: x, y, and z should be sorted in increasing order before calling this function.
      real(8) function code(x, y, z)
          real(8), intent (in) :: x
          real(8), intent (in) :: y
          real(8), intent (in) :: z
          code = -z
      end function
      
      assert x < y && y < z;
      public static double code(double x, double y, double z) {
      	return -z;
      }
      
      [x, y, z] = sort([x, y, z])
      def code(x, y, z):
      	return -z
      
      x, y, z = sort([x, y, z])
      function code(x, y, z)
      	return Float64(-z)
      end
      
      x, y, z = num2cell(sort([x, y, z])){:}
      function tmp = code(x, y, z)
      	tmp = -z;
      end
      
      NOTE: x, y, and z should be sorted in increasing order before calling this function.
      code[x_, y_, z_] := (-z)
      
      \begin{array}{l}
      [x, y, z] = \mathsf{sort}([x, y, z])\\
      \\
      -z
      \end{array}
      
      Derivation
      1. Initial program 99.9%

        \[\left(x \cdot 3\right) \cdot y - z \]
      2. Add Preprocessing
      3. Taylor expanded in x around 0

        \[\leadsto \color{blue}{-1 \cdot z} \]
      4. Step-by-step derivation
        1. mul-1-negN/A

          \[\leadsto \color{blue}{\mathsf{neg}\left(z\right)} \]
        2. lower-neg.f6450.5

          \[\leadsto \color{blue}{-z} \]
      5. Applied rewrites50.5%

        \[\leadsto \color{blue}{-z} \]
      6. Add Preprocessing

      Developer Target 1: 99.8% accurate, 1.0× speedup?

      \[\begin{array}{l} \\ x \cdot \left(3 \cdot y\right) - z \end{array} \]
      (FPCore (x y z) :precision binary64 (- (* x (* 3.0 y)) z))
      double code(double x, double y, double z) {
      	return (x * (3.0 * y)) - z;
      }
      
      real(8) function code(x, y, z)
          real(8), intent (in) :: x
          real(8), intent (in) :: y
          real(8), intent (in) :: z
          code = (x * (3.0d0 * y)) - z
      end function
      
      public static double code(double x, double y, double z) {
      	return (x * (3.0 * y)) - z;
      }
      
      def code(x, y, z):
      	return (x * (3.0 * y)) - z
      
      function code(x, y, z)
      	return Float64(Float64(x * Float64(3.0 * y)) - z)
      end
      
      function tmp = code(x, y, z)
      	tmp = (x * (3.0 * y)) - z;
      end
      
      code[x_, y_, z_] := N[(N[(x * N[(3.0 * y), $MachinePrecision]), $MachinePrecision] - z), $MachinePrecision]
      
      \begin{array}{l}
      
      \\
      x \cdot \left(3 \cdot y\right) - z
      \end{array}
      

      Reproduce

      ?
      herbie shell --seed 2024332 
      (FPCore (x y z)
        :name "Diagrams.Solve.Polynomial:cubForm  from diagrams-solve-0.1, B"
        :precision binary64
      
        :alt
        (! :herbie-platform default (- (* x (* 3 y)) z))
      
        (- (* (* x 3.0) y) z))