ABCF->ab-angle a

Percentage Accurate: 18.7% → 62.9%
Time: 12.1s
Alternatives: 18
Speedup: 16.9×

Specification

?
\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
real(8) function code(a, b, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) + sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 18 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 18.7% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
real(8) function code(a, b, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) + sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Alternative 1: 62.9% accurate, 0.3× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ t_1 := \mathsf{hypot}\left(A - C, B\_m\right)\\ t_2 := C \cdot \left(A \cdot 4\right)\\ t_3 := t\_2 - {B\_m}^{2}\\ t_4 := \frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right) \cdot \left(\left(F \cdot \left({B\_m}^{2} - t\_2\right)\right) \cdot 2\right)}}{t\_3}\\ \mathbf{if}\;t\_4 \leq -5 \cdot 10^{-195}:\\ \;\;\;\;\frac{\sqrt{F} \cdot \left(\sqrt{\left(\left(C + A\right) + t\_1\right) \cdot 2} \cdot \sqrt{\mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)}\right)}{t\_3}\\ \mathbf{elif}\;t\_4 \leq 0:\\ \;\;\;\;\frac{\sqrt{\left(t\_0 \cdot 2\right) \cdot \left(\left(\frac{B\_m \cdot B\_m}{A} \cdot -0.5 + C\right) + C\right)} \cdot \sqrt{F}}{t\_3}\\ \mathbf{elif}\;t\_4 \leq \infty:\\ \;\;\;\;\frac{\sqrt{\left(F \cdot 2\right) \cdot t\_0}}{t\_0} \cdot \frac{\sqrt{\left(t\_1 + A\right) + C}}{-1}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (let* ((t_0 (fma -4.0 (* C A) (* B_m B_m)))
        (t_1 (hypot (- A C) B_m))
        (t_2 (* C (* A 4.0)))
        (t_3 (- t_2 (pow B_m 2.0)))
        (t_4
         (/
          (sqrt
           (*
            (+ (+ C A) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))
            (* (* F (- (pow B_m 2.0) t_2)) 2.0)))
          t_3)))
   (if (<= t_4 -5e-195)
     (/
      (*
       (sqrt F)
       (*
        (sqrt (* (+ (+ C A) t_1) 2.0))
        (sqrt (fma (* C A) -4.0 (* B_m B_m)))))
      t_3)
     (if (<= t_4 0.0)
       (/
        (*
         (sqrt (* (* t_0 2.0) (+ (+ (* (/ (* B_m B_m) A) -0.5) C) C)))
         (sqrt F))
        t_3)
       (if (<= t_4 INFINITY)
         (* (/ (sqrt (* (* F 2.0) t_0)) t_0) (/ (sqrt (+ (+ t_1 A) C)) -1.0))
         (* (/ (sqrt (* (+ (hypot C B_m) C) 2.0)) B_m) (- (sqrt F))))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double t_0 = fma(-4.0, (C * A), (B_m * B_m));
	double t_1 = hypot((A - C), B_m);
	double t_2 = C * (A * 4.0);
	double t_3 = t_2 - pow(B_m, 2.0);
	double t_4 = sqrt((((C + A) + sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))) * ((F * (pow(B_m, 2.0) - t_2)) * 2.0))) / t_3;
	double tmp;
	if (t_4 <= -5e-195) {
		tmp = (sqrt(F) * (sqrt((((C + A) + t_1) * 2.0)) * sqrt(fma((C * A), -4.0, (B_m * B_m))))) / t_3;
	} else if (t_4 <= 0.0) {
		tmp = (sqrt(((t_0 * 2.0) * (((((B_m * B_m) / A) * -0.5) + C) + C))) * sqrt(F)) / t_3;
	} else if (t_4 <= ((double) INFINITY)) {
		tmp = (sqrt(((F * 2.0) * t_0)) / t_0) * (sqrt(((t_1 + A) + C)) / -1.0);
	} else {
		tmp = (sqrt(((hypot(C, B_m) + C) * 2.0)) / B_m) * -sqrt(F);
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	t_0 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
	t_1 = hypot(Float64(A - C), B_m)
	t_2 = Float64(C * Float64(A * 4.0))
	t_3 = Float64(t_2 - (B_m ^ 2.0))
	t_4 = Float64(sqrt(Float64(Float64(Float64(C + A) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))) * Float64(Float64(F * Float64((B_m ^ 2.0) - t_2)) * 2.0))) / t_3)
	tmp = 0.0
	if (t_4 <= -5e-195)
		tmp = Float64(Float64(sqrt(F) * Float64(sqrt(Float64(Float64(Float64(C + A) + t_1) * 2.0)) * sqrt(fma(Float64(C * A), -4.0, Float64(B_m * B_m))))) / t_3);
	elseif (t_4 <= 0.0)
		tmp = Float64(Float64(sqrt(Float64(Float64(t_0 * 2.0) * Float64(Float64(Float64(Float64(Float64(B_m * B_m) / A) * -0.5) + C) + C))) * sqrt(F)) / t_3);
	elseif (t_4 <= Inf)
		tmp = Float64(Float64(sqrt(Float64(Float64(F * 2.0) * t_0)) / t_0) * Float64(sqrt(Float64(Float64(t_1 + A) + C)) / -1.0));
	else
		tmp = Float64(Float64(sqrt(Float64(Float64(hypot(C, B_m) + C) * 2.0)) / B_m) * Float64(-sqrt(F)));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision]}, Block[{t$95$2 = N[(C * N[(A * 4.0), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = N[(t$95$2 - N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]}, Block[{t$95$4 = N[(N[Sqrt[N[(N[(N[(C + A), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[(N[(F * N[(N[Power[B$95$m, 2.0], $MachinePrecision] - t$95$2), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / t$95$3), $MachinePrecision]}, If[LessEqual[t$95$4, -5e-195], N[(N[(N[Sqrt[F], $MachinePrecision] * N[(N[Sqrt[N[(N[(N[(C + A), $MachinePrecision] + t$95$1), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] * N[Sqrt[N[(N[(C * A), $MachinePrecision] * -4.0 + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / t$95$3), $MachinePrecision], If[LessEqual[t$95$4, 0.0], N[(N[(N[Sqrt[N[(N[(t$95$0 * 2.0), $MachinePrecision] * N[(N[(N[(N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] * -0.5), $MachinePrecision] + C), $MachinePrecision] + C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision] / t$95$3), $MachinePrecision], If[LessEqual[t$95$4, Infinity], N[(N[(N[Sqrt[N[(N[(F * 2.0), $MachinePrecision] * t$95$0), $MachinePrecision]], $MachinePrecision] / t$95$0), $MachinePrecision] * N[(N[Sqrt[N[(N[(t$95$1 + A), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] / -1.0), $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / B$95$m), $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]]]]]]]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
t_1 := \mathsf{hypot}\left(A - C, B\_m\right)\\
t_2 := C \cdot \left(A \cdot 4\right)\\
t_3 := t\_2 - {B\_m}^{2}\\
t_4 := \frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right) \cdot \left(\left(F \cdot \left({B\_m}^{2} - t\_2\right)\right) \cdot 2\right)}}{t\_3}\\
\mathbf{if}\;t\_4 \leq -5 \cdot 10^{-195}:\\
\;\;\;\;\frac{\sqrt{F} \cdot \left(\sqrt{\left(\left(C + A\right) + t\_1\right) \cdot 2} \cdot \sqrt{\mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)}\right)}{t\_3}\\

\mathbf{elif}\;t\_4 \leq 0:\\
\;\;\;\;\frac{\sqrt{\left(t\_0 \cdot 2\right) \cdot \left(\left(\frac{B\_m \cdot B\_m}{A} \cdot -0.5 + C\right) + C\right)} \cdot \sqrt{F}}{t\_3}\\

\mathbf{elif}\;t\_4 \leq \infty:\\
\;\;\;\;\frac{\sqrt{\left(F \cdot 2\right) \cdot t\_0}}{t\_0} \cdot \frac{\sqrt{\left(t\_1 + A\right) + C}}{-1}\\

\mathbf{else}:\\
\;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 4 regimes
  2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -5.00000000000000009e-195

    1. Initial program 48.9%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. *-commutativeN/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. associate-*r*N/A

        \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      7. associate-*r*N/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      8. sqrt-prodN/A

        \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      9. pow1/2N/A

        \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \color{blue}{{F}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Applied rewrites46.8%

      \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    5. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)}} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)}} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. *-commutativeN/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right) \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. associate-*l*N/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \left(2 \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)\right)}} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. sqrt-prodN/A

        \[\leadsto \frac{-\color{blue}{\left(\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \cdot \sqrt{2 \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      7. pow1/2N/A

        \[\leadsto \frac{-\left(\color{blue}{{\left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}^{\frac{1}{2}}} \cdot \sqrt{2 \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}\right) \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      8. lower-*.f64N/A

        \[\leadsto \frac{-\color{blue}{\left({\left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}^{\frac{1}{2}} \cdot \sqrt{2 \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      9. pow1/2N/A

        \[\leadsto \frac{-\left(\color{blue}{\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \cdot \sqrt{2 \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}\right) \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      10. lower-sqrt.f64N/A

        \[\leadsto \frac{-\left(\color{blue}{\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \cdot \sqrt{2 \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}\right) \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      11. lift-fma.f64N/A

        \[\leadsto \frac{-\left(\sqrt{\color{blue}{-4 \cdot \left(C \cdot A\right) + B \cdot B}} \cdot \sqrt{2 \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}\right) \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      12. *-commutativeN/A

        \[\leadsto \frac{-\left(\sqrt{\color{blue}{\left(C \cdot A\right) \cdot -4} + B \cdot B} \cdot \sqrt{2 \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}\right) \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      13. lower-fma.f64N/A

        \[\leadsto \frac{-\left(\sqrt{\color{blue}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \cdot \sqrt{2 \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}\right) \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      14. lower-sqrt.f64N/A

        \[\leadsto \frac{-\left(\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \cdot \color{blue}{\sqrt{2 \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}}\right) \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      15. lower-*.f6476.8

        \[\leadsto \frac{-\left(\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \cdot \sqrt{\color{blue}{2 \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}}\right) \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    6. Applied rewrites75.8%

      \[\leadsto \frac{-\color{blue}{\left(\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \cdot \sqrt{2 \cdot \left(\mathsf{hypot}\left(A - C, B\right) + \left(C + A\right)\right)}\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

    if -5.00000000000000009e-195 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -0.0

    1. Initial program 3.5%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. *-commutativeN/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. associate-*r*N/A

        \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      7. associate-*r*N/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      8. sqrt-prodN/A

        \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      9. pow1/2N/A

        \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \color{blue}{{F}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Applied rewrites15.1%

      \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    5. Taylor expanded in A around -inf

      \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    6. Step-by-step derivation
      1. lower-+.f64N/A

        \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(\left(C + \color{blue}{\frac{-1}{2} \cdot \frac{{B}^{2}}{A}}\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. lower-/.f64N/A

        \[\leadsto \frac{-\sqrt{\left(\left(C + \frac{-1}{2} \cdot \color{blue}{\frac{{B}^{2}}{A}}\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. unpow2N/A

        \[\leadsto \frac{-\sqrt{\left(\left(C + \frac{-1}{2} \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. lower-*.f6421.4

        \[\leadsto \frac{-\sqrt{\left(\left(C + -0.5 \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    7. Applied rewrites21.4%

      \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(C + -0.5 \cdot \frac{B \cdot B}{A}\right)} + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

    if -0.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

    1. Initial program 34.6%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Applied rewrites72.7%

      \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{-1} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]

    if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

    1. Initial program 0.0%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in A around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. associate-*r*N/A

        \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
      2. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
      3. mul-1-negN/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
      4. lower-neg.f64N/A

        \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
      5. lower-/.f64N/A

        \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
      6. lower-sqrt.f64N/A

        \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
      7. lower-sqrt.f64N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
      8. *-commutativeN/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
      9. lower-*.f64N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
      10. +-commutativeN/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
      11. lower-+.f64N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
      12. +-commutativeN/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
      13. unpow2N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
      14. unpow2N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
      15. lower-hypot.f6419.7

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
    5. Applied rewrites19.7%

      \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
    6. Step-by-step derivation
      1. Applied rewrites33.5%

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
      2. Step-by-step derivation
        1. Applied rewrites33.6%

          \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
      3. Recombined 4 regimes into one program.
      4. Final simplification51.9%

        \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(\left(F \cdot \left({B}^{2} - C \cdot \left(A \cdot 4\right)\right)\right) \cdot 2\right)}}{C \cdot \left(A \cdot 4\right) - {B}^{2}} \leq -5 \cdot 10^{-195}:\\ \;\;\;\;\frac{\sqrt{F} \cdot \left(\sqrt{\left(\left(C + A\right) + \mathsf{hypot}\left(A - C, B\right)\right) \cdot 2} \cdot \sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}\right)}{C \cdot \left(A \cdot 4\right) - {B}^{2}}\\ \mathbf{elif}\;\frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(\left(F \cdot \left({B}^{2} - C \cdot \left(A \cdot 4\right)\right)\right) \cdot 2\right)}}{C \cdot \left(A \cdot 4\right) - {B}^{2}} \leq 0:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right) \cdot \left(\left(\frac{B \cdot B}{A} \cdot -0.5 + C\right) + C\right)} \cdot \sqrt{F}}{C \cdot \left(A \cdot 4\right) - {B}^{2}}\\ \mathbf{elif}\;\frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(\left(F \cdot \left({B}^{2} - C \cdot \left(A \cdot 4\right)\right)\right) \cdot 2\right)}}{C \cdot \left(A \cdot 4\right) - {B}^{2}} \leq \infty:\\ \;\;\;\;\frac{\sqrt{\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{-1}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2}}{B} \cdot \left(-\sqrt{F}\right)\\ \end{array} \]
      5. Add Preprocessing

      Alternative 2: 60.4% accurate, 0.3× speedup?

      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C\\ t_1 := C \cdot \left(A \cdot 4\right)\\ t_2 := t\_1 - {B\_m}^{2}\\ t_3 := \frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right) \cdot \left(\left(F \cdot \left({B\_m}^{2} - t\_1\right)\right) \cdot 2\right)}}{t\_2}\\ t_4 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ t_5 := t\_4 \cdot 2\\ \mathbf{if}\;t\_3 \leq -5 \cdot 10^{-195}:\\ \;\;\;\;\frac{\sqrt{t\_0 \cdot F} \cdot \sqrt{t\_5}}{t\_2}\\ \mathbf{elif}\;t\_3 \leq 0:\\ \;\;\;\;\frac{\sqrt{t\_5 \cdot \left(\left(\frac{B\_m \cdot B\_m}{A} \cdot -0.5 + C\right) + C\right)} \cdot \sqrt{F}}{t\_2}\\ \mathbf{elif}\;t\_3 \leq \infty:\\ \;\;\;\;\frac{\sqrt{\left(F \cdot 2\right) \cdot t\_4}}{t\_4} \cdot \frac{\sqrt{t\_0}}{-1}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\ \end{array} \end{array} \]
      B_m = (fabs.f64 B)
      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
      (FPCore (A B_m C F)
       :precision binary64
       (let* ((t_0 (+ (+ (hypot (- A C) B_m) A) C))
              (t_1 (* C (* A 4.0)))
              (t_2 (- t_1 (pow B_m 2.0)))
              (t_3
               (/
                (sqrt
                 (*
                  (+ (+ C A) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))
                  (* (* F (- (pow B_m 2.0) t_1)) 2.0)))
                t_2))
              (t_4 (fma -4.0 (* C A) (* B_m B_m)))
              (t_5 (* t_4 2.0)))
         (if (<= t_3 -5e-195)
           (/ (* (sqrt (* t_0 F)) (sqrt t_5)) t_2)
           (if (<= t_3 0.0)
             (/
              (* (sqrt (* t_5 (+ (+ (* (/ (* B_m B_m) A) -0.5) C) C))) (sqrt F))
              t_2)
             (if (<= t_3 INFINITY)
               (* (/ (sqrt (* (* F 2.0) t_4)) t_4) (/ (sqrt t_0) -1.0))
               (* (/ (sqrt (* (+ (hypot C B_m) C) 2.0)) B_m) (- (sqrt F))))))))
      B_m = fabs(B);
      assert(A < B_m && B_m < C && C < F);
      double code(double A, double B_m, double C, double F) {
      	double t_0 = (hypot((A - C), B_m) + A) + C;
      	double t_1 = C * (A * 4.0);
      	double t_2 = t_1 - pow(B_m, 2.0);
      	double t_3 = sqrt((((C + A) + sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))) * ((F * (pow(B_m, 2.0) - t_1)) * 2.0))) / t_2;
      	double t_4 = fma(-4.0, (C * A), (B_m * B_m));
      	double t_5 = t_4 * 2.0;
      	double tmp;
      	if (t_3 <= -5e-195) {
      		tmp = (sqrt((t_0 * F)) * sqrt(t_5)) / t_2;
      	} else if (t_3 <= 0.0) {
      		tmp = (sqrt((t_5 * (((((B_m * B_m) / A) * -0.5) + C) + C))) * sqrt(F)) / t_2;
      	} else if (t_3 <= ((double) INFINITY)) {
      		tmp = (sqrt(((F * 2.0) * t_4)) / t_4) * (sqrt(t_0) / -1.0);
      	} else {
      		tmp = (sqrt(((hypot(C, B_m) + C) * 2.0)) / B_m) * -sqrt(F);
      	}
      	return tmp;
      }
      
      B_m = abs(B)
      A, B_m, C, F = sort([A, B_m, C, F])
      function code(A, B_m, C, F)
      	t_0 = Float64(Float64(hypot(Float64(A - C), B_m) + A) + C)
      	t_1 = Float64(C * Float64(A * 4.0))
      	t_2 = Float64(t_1 - (B_m ^ 2.0))
      	t_3 = Float64(sqrt(Float64(Float64(Float64(C + A) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))) * Float64(Float64(F * Float64((B_m ^ 2.0) - t_1)) * 2.0))) / t_2)
      	t_4 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
      	t_5 = Float64(t_4 * 2.0)
      	tmp = 0.0
      	if (t_3 <= -5e-195)
      		tmp = Float64(Float64(sqrt(Float64(t_0 * F)) * sqrt(t_5)) / t_2);
      	elseif (t_3 <= 0.0)
      		tmp = Float64(Float64(sqrt(Float64(t_5 * Float64(Float64(Float64(Float64(Float64(B_m * B_m) / A) * -0.5) + C) + C))) * sqrt(F)) / t_2);
      	elseif (t_3 <= Inf)
      		tmp = Float64(Float64(sqrt(Float64(Float64(F * 2.0) * t_4)) / t_4) * Float64(sqrt(t_0) / -1.0));
      	else
      		tmp = Float64(Float64(sqrt(Float64(Float64(hypot(C, B_m) + C) * 2.0)) / B_m) * Float64(-sqrt(F)));
      	end
      	return tmp
      end
      
      B_m = N[Abs[B], $MachinePrecision]
      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
      code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision]}, Block[{t$95$1 = N[(C * N[(A * 4.0), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(t$95$1 - N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = N[(N[Sqrt[N[(N[(N[(C + A), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[(N[(F * N[(N[Power[B$95$m, 2.0], $MachinePrecision] - t$95$1), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / t$95$2), $MachinePrecision]}, Block[{t$95$4 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$5 = N[(t$95$4 * 2.0), $MachinePrecision]}, If[LessEqual[t$95$3, -5e-195], N[(N[(N[Sqrt[N[(t$95$0 * F), $MachinePrecision]], $MachinePrecision] * N[Sqrt[t$95$5], $MachinePrecision]), $MachinePrecision] / t$95$2), $MachinePrecision], If[LessEqual[t$95$3, 0.0], N[(N[(N[Sqrt[N[(t$95$5 * N[(N[(N[(N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] * -0.5), $MachinePrecision] + C), $MachinePrecision] + C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision] / t$95$2), $MachinePrecision], If[LessEqual[t$95$3, Infinity], N[(N[(N[Sqrt[N[(N[(F * 2.0), $MachinePrecision] * t$95$4), $MachinePrecision]], $MachinePrecision] / t$95$4), $MachinePrecision] * N[(N[Sqrt[t$95$0], $MachinePrecision] / -1.0), $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / B$95$m), $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]]]]]]]]]]
      
      \begin{array}{l}
      B_m = \left|B\right|
      \\
      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
      \\
      \begin{array}{l}
      t_0 := \left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C\\
      t_1 := C \cdot \left(A \cdot 4\right)\\
      t_2 := t\_1 - {B\_m}^{2}\\
      t_3 := \frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right) \cdot \left(\left(F \cdot \left({B\_m}^{2} - t\_1\right)\right) \cdot 2\right)}}{t\_2}\\
      t_4 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
      t_5 := t\_4 \cdot 2\\
      \mathbf{if}\;t\_3 \leq -5 \cdot 10^{-195}:\\
      \;\;\;\;\frac{\sqrt{t\_0 \cdot F} \cdot \sqrt{t\_5}}{t\_2}\\
      
      \mathbf{elif}\;t\_3 \leq 0:\\
      \;\;\;\;\frac{\sqrt{t\_5 \cdot \left(\left(\frac{B\_m \cdot B\_m}{A} \cdot -0.5 + C\right) + C\right)} \cdot \sqrt{F}}{t\_2}\\
      
      \mathbf{elif}\;t\_3 \leq \infty:\\
      \;\;\;\;\frac{\sqrt{\left(F \cdot 2\right) \cdot t\_4}}{t\_4} \cdot \frac{\sqrt{t\_0}}{-1}\\
      
      \mathbf{else}:\\
      \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 4 regimes
      2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -5.00000000000000009e-195

        1. Initial program 48.9%

          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. Add Preprocessing
        3. Step-by-step derivation
          1. lift-sqrt.f64N/A

            \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. lift-*.f64N/A

            \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          3. lift-*.f64N/A

            \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)} \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          4. lift-*.f64N/A

            \[\leadsto \frac{-\sqrt{\left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          5. associate-*r*N/A

            \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)} \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          6. associate-*l*N/A

            \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot \left(F \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          7. sqrt-prodN/A

            \[\leadsto \frac{-\color{blue}{\sqrt{2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \cdot \sqrt{F \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          8. pow1/2N/A

            \[\leadsto \frac{-\color{blue}{{\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)}^{\frac{1}{2}}} \cdot \sqrt{F \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          9. lower-*.f64N/A

            \[\leadsto \frac{-\color{blue}{{\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)}^{\frac{1}{2}} \cdot \sqrt{F \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        4. Applied rewrites69.9%

          \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2} \cdot \sqrt{F \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

        if -5.00000000000000009e-195 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -0.0

        1. Initial program 3.5%

          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. Add Preprocessing
        3. Step-by-step derivation
          1. lift-sqrt.f64N/A

            \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. lift-*.f64N/A

            \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          3. *-commutativeN/A

            \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          4. lift-*.f64N/A

            \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          5. lift-*.f64N/A

            \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          6. associate-*r*N/A

            \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          7. associate-*r*N/A

            \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          8. sqrt-prodN/A

            \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          9. pow1/2N/A

            \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \color{blue}{{F}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        4. Applied rewrites15.1%

          \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        5. Taylor expanded in A around -inf

          \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        6. Step-by-step derivation
          1. lower-+.f64N/A

            \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. lower-*.f64N/A

            \[\leadsto \frac{-\sqrt{\left(\left(C + \color{blue}{\frac{-1}{2} \cdot \frac{{B}^{2}}{A}}\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          3. lower-/.f64N/A

            \[\leadsto \frac{-\sqrt{\left(\left(C + \frac{-1}{2} \cdot \color{blue}{\frac{{B}^{2}}{A}}\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          4. unpow2N/A

            \[\leadsto \frac{-\sqrt{\left(\left(C + \frac{-1}{2} \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          5. lower-*.f6421.4

            \[\leadsto \frac{-\sqrt{\left(\left(C + -0.5 \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        7. Applied rewrites21.4%

          \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(C + -0.5 \cdot \frac{B \cdot B}{A}\right)} + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

        if -0.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

        1. Initial program 34.6%

          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. Add Preprocessing
        3. Applied rewrites72.7%

          \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{-1} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]

        if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

        1. Initial program 0.0%

          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. Add Preprocessing
        3. Taylor expanded in A around 0

          \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
        4. Step-by-step derivation
          1. associate-*r*N/A

            \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
          2. lower-*.f64N/A

            \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
          3. mul-1-negN/A

            \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
          4. lower-neg.f64N/A

            \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
          5. lower-/.f64N/A

            \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
          6. lower-sqrt.f64N/A

            \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
          7. lower-sqrt.f64N/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
          8. *-commutativeN/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
          9. lower-*.f64N/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
          10. +-commutativeN/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
          11. lower-+.f64N/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
          12. +-commutativeN/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
          13. unpow2N/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
          14. unpow2N/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
          15. lower-hypot.f6419.7

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
        5. Applied rewrites19.7%

          \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
        6. Step-by-step derivation
          1. Applied rewrites33.5%

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
          2. Step-by-step derivation
            1. Applied rewrites33.6%

              \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
          3. Recombined 4 regimes into one program.
          4. Final simplification49.6%

            \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(\left(F \cdot \left({B}^{2} - C \cdot \left(A \cdot 4\right)\right)\right) \cdot 2\right)}}{C \cdot \left(A \cdot 4\right) - {B}^{2}} \leq -5 \cdot 10^{-195}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot F} \cdot \sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2}}{C \cdot \left(A \cdot 4\right) - {B}^{2}}\\ \mathbf{elif}\;\frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(\left(F \cdot \left({B}^{2} - C \cdot \left(A \cdot 4\right)\right)\right) \cdot 2\right)}}{C \cdot \left(A \cdot 4\right) - {B}^{2}} \leq 0:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right) \cdot \left(\left(\frac{B \cdot B}{A} \cdot -0.5 + C\right) + C\right)} \cdot \sqrt{F}}{C \cdot \left(A \cdot 4\right) - {B}^{2}}\\ \mathbf{elif}\;\frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(\left(F \cdot \left({B}^{2} - C \cdot \left(A \cdot 4\right)\right)\right) \cdot 2\right)}}{C \cdot \left(A \cdot 4\right) - {B}^{2}} \leq \infty:\\ \;\;\;\;\frac{\sqrt{\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{-1}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2}}{B} \cdot \left(-\sqrt{F}\right)\\ \end{array} \]
          5. Add Preprocessing

          Alternative 3: 59.6% accurate, 0.3× speedup?

          \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ t_1 := \sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}\\ t_2 := C \cdot \left(A \cdot 4\right)\\ t_3 := t\_2 - {B\_m}^{2}\\ t_4 := \frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right) \cdot \left(\left(F \cdot \left({B\_m}^{2} - t\_2\right)\right) \cdot 2\right)}}{t\_3}\\ t_5 := \sqrt{\left(F \cdot 2\right) \cdot t\_0}\\ \mathbf{if}\;t\_4 \leq -5 \cdot 10^{-195}:\\ \;\;\;\;\frac{t\_1}{t\_0} \cdot \frac{t\_5}{-1}\\ \mathbf{elif}\;t\_4 \leq 0:\\ \;\;\;\;\frac{\sqrt{\left(t\_0 \cdot 2\right) \cdot \left(\left(\frac{B\_m \cdot B\_m}{A} \cdot -0.5 + C\right) + C\right)} \cdot \sqrt{F}}{t\_3}\\ \mathbf{elif}\;t\_4 \leq \infty:\\ \;\;\;\;\frac{t\_5}{t\_0} \cdot \frac{t\_1}{-1}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\ \end{array} \end{array} \]
          B_m = (fabs.f64 B)
          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
          (FPCore (A B_m C F)
           :precision binary64
           (let* ((t_0 (fma -4.0 (* C A) (* B_m B_m)))
                  (t_1 (sqrt (+ (+ (hypot (- A C) B_m) A) C)))
                  (t_2 (* C (* A 4.0)))
                  (t_3 (- t_2 (pow B_m 2.0)))
                  (t_4
                   (/
                    (sqrt
                     (*
                      (+ (+ C A) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))
                      (* (* F (- (pow B_m 2.0) t_2)) 2.0)))
                    t_3))
                  (t_5 (sqrt (* (* F 2.0) t_0))))
             (if (<= t_4 -5e-195)
               (* (/ t_1 t_0) (/ t_5 -1.0))
               (if (<= t_4 0.0)
                 (/
                  (*
                   (sqrt (* (* t_0 2.0) (+ (+ (* (/ (* B_m B_m) A) -0.5) C) C)))
                   (sqrt F))
                  t_3)
                 (if (<= t_4 INFINITY)
                   (* (/ t_5 t_0) (/ t_1 -1.0))
                   (* (/ (sqrt (* (+ (hypot C B_m) C) 2.0)) B_m) (- (sqrt F))))))))
          B_m = fabs(B);
          assert(A < B_m && B_m < C && C < F);
          double code(double A, double B_m, double C, double F) {
          	double t_0 = fma(-4.0, (C * A), (B_m * B_m));
          	double t_1 = sqrt(((hypot((A - C), B_m) + A) + C));
          	double t_2 = C * (A * 4.0);
          	double t_3 = t_2 - pow(B_m, 2.0);
          	double t_4 = sqrt((((C + A) + sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))) * ((F * (pow(B_m, 2.0) - t_2)) * 2.0))) / t_3;
          	double t_5 = sqrt(((F * 2.0) * t_0));
          	double tmp;
          	if (t_4 <= -5e-195) {
          		tmp = (t_1 / t_0) * (t_5 / -1.0);
          	} else if (t_4 <= 0.0) {
          		tmp = (sqrt(((t_0 * 2.0) * (((((B_m * B_m) / A) * -0.5) + C) + C))) * sqrt(F)) / t_3;
          	} else if (t_4 <= ((double) INFINITY)) {
          		tmp = (t_5 / t_0) * (t_1 / -1.0);
          	} else {
          		tmp = (sqrt(((hypot(C, B_m) + C) * 2.0)) / B_m) * -sqrt(F);
          	}
          	return tmp;
          }
          
          B_m = abs(B)
          A, B_m, C, F = sort([A, B_m, C, F])
          function code(A, B_m, C, F)
          	t_0 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
          	t_1 = sqrt(Float64(Float64(hypot(Float64(A - C), B_m) + A) + C))
          	t_2 = Float64(C * Float64(A * 4.0))
          	t_3 = Float64(t_2 - (B_m ^ 2.0))
          	t_4 = Float64(sqrt(Float64(Float64(Float64(C + A) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))) * Float64(Float64(F * Float64((B_m ^ 2.0) - t_2)) * 2.0))) / t_3)
          	t_5 = sqrt(Float64(Float64(F * 2.0) * t_0))
          	tmp = 0.0
          	if (t_4 <= -5e-195)
          		tmp = Float64(Float64(t_1 / t_0) * Float64(t_5 / -1.0));
          	elseif (t_4 <= 0.0)
          		tmp = Float64(Float64(sqrt(Float64(Float64(t_0 * 2.0) * Float64(Float64(Float64(Float64(Float64(B_m * B_m) / A) * -0.5) + C) + C))) * sqrt(F)) / t_3);
          	elseif (t_4 <= Inf)
          		tmp = Float64(Float64(t_5 / t_0) * Float64(t_1 / -1.0));
          	else
          		tmp = Float64(Float64(sqrt(Float64(Float64(hypot(C, B_m) + C) * 2.0)) / B_m) * Float64(-sqrt(F)));
          	end
          	return tmp
          end
          
          B_m = N[Abs[B], $MachinePrecision]
          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
          code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[Sqrt[N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision]}, Block[{t$95$2 = N[(C * N[(A * 4.0), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = N[(t$95$2 - N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]}, Block[{t$95$4 = N[(N[Sqrt[N[(N[(N[(C + A), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[(N[(F * N[(N[Power[B$95$m, 2.0], $MachinePrecision] - t$95$2), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / t$95$3), $MachinePrecision]}, Block[{t$95$5 = N[Sqrt[N[(N[(F * 2.0), $MachinePrecision] * t$95$0), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[t$95$4, -5e-195], N[(N[(t$95$1 / t$95$0), $MachinePrecision] * N[(t$95$5 / -1.0), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$4, 0.0], N[(N[(N[Sqrt[N[(N[(t$95$0 * 2.0), $MachinePrecision] * N[(N[(N[(N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] * -0.5), $MachinePrecision] + C), $MachinePrecision] + C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision] / t$95$3), $MachinePrecision], If[LessEqual[t$95$4, Infinity], N[(N[(t$95$5 / t$95$0), $MachinePrecision] * N[(t$95$1 / -1.0), $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / B$95$m), $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]]]]]]]]]]
          
          \begin{array}{l}
          B_m = \left|B\right|
          \\
          [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
          \\
          \begin{array}{l}
          t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
          t_1 := \sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}\\
          t_2 := C \cdot \left(A \cdot 4\right)\\
          t_3 := t\_2 - {B\_m}^{2}\\
          t_4 := \frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right) \cdot \left(\left(F \cdot \left({B\_m}^{2} - t\_2\right)\right) \cdot 2\right)}}{t\_3}\\
          t_5 := \sqrt{\left(F \cdot 2\right) \cdot t\_0}\\
          \mathbf{if}\;t\_4 \leq -5 \cdot 10^{-195}:\\
          \;\;\;\;\frac{t\_1}{t\_0} \cdot \frac{t\_5}{-1}\\
          
          \mathbf{elif}\;t\_4 \leq 0:\\
          \;\;\;\;\frac{\sqrt{\left(t\_0 \cdot 2\right) \cdot \left(\left(\frac{B\_m \cdot B\_m}{A} \cdot -0.5 + C\right) + C\right)} \cdot \sqrt{F}}{t\_3}\\
          
          \mathbf{elif}\;t\_4 \leq \infty:\\
          \;\;\;\;\frac{t\_5}{t\_0} \cdot \frac{t\_1}{-1}\\
          
          \mathbf{else}:\\
          \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 4 regimes
          2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -5.00000000000000009e-195

            1. Initial program 48.9%

              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            2. Add Preprocessing
            3. Applied rewrites69.6%

              \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]

            if -5.00000000000000009e-195 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -0.0

            1. Initial program 3.5%

              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            2. Add Preprocessing
            3. Step-by-step derivation
              1. lift-sqrt.f64N/A

                \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              2. lift-*.f64N/A

                \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              3. *-commutativeN/A

                \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              4. lift-*.f64N/A

                \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              5. lift-*.f64N/A

                \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              6. associate-*r*N/A

                \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              7. associate-*r*N/A

                \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              8. sqrt-prodN/A

                \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              9. pow1/2N/A

                \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \color{blue}{{F}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            4. Applied rewrites15.1%

              \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            5. Taylor expanded in A around -inf

              \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            6. Step-by-step derivation
              1. lower-+.f64N/A

                \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              2. lower-*.f64N/A

                \[\leadsto \frac{-\sqrt{\left(\left(C + \color{blue}{\frac{-1}{2} \cdot \frac{{B}^{2}}{A}}\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              3. lower-/.f64N/A

                \[\leadsto \frac{-\sqrt{\left(\left(C + \frac{-1}{2} \cdot \color{blue}{\frac{{B}^{2}}{A}}\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              4. unpow2N/A

                \[\leadsto \frac{-\sqrt{\left(\left(C + \frac{-1}{2} \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              5. lower-*.f6421.4

                \[\leadsto \frac{-\sqrt{\left(\left(C + -0.5 \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            7. Applied rewrites21.4%

              \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(C + -0.5 \cdot \frac{B \cdot B}{A}\right)} + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

            if -0.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

            1. Initial program 34.6%

              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            2. Add Preprocessing
            3. Applied rewrites72.7%

              \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{-1} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]

            if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

            1. Initial program 0.0%

              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            2. Add Preprocessing
            3. Taylor expanded in A around 0

              \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
            4. Step-by-step derivation
              1. associate-*r*N/A

                \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
              2. lower-*.f64N/A

                \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
              3. mul-1-negN/A

                \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
              4. lower-neg.f64N/A

                \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
              5. lower-/.f64N/A

                \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
              6. lower-sqrt.f64N/A

                \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
              7. lower-sqrt.f64N/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
              8. *-commutativeN/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
              9. lower-*.f64N/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
              10. +-commutativeN/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
              11. lower-+.f64N/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
              12. +-commutativeN/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
              13. unpow2N/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
              14. unpow2N/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
              15. lower-hypot.f6419.7

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
            5. Applied rewrites19.7%

              \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
            6. Step-by-step derivation
              1. Applied rewrites33.5%

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
              2. Step-by-step derivation
                1. Applied rewrites33.6%

                  \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
              3. Recombined 4 regimes into one program.
              4. Final simplification49.5%

                \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(\left(F \cdot \left({B}^{2} - C \cdot \left(A \cdot 4\right)\right)\right) \cdot 2\right)}}{C \cdot \left(A \cdot 4\right) - {B}^{2}} \leq -5 \cdot 10^{-195}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \cdot \frac{\sqrt{\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1}\\ \mathbf{elif}\;\frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(\left(F \cdot \left({B}^{2} - C \cdot \left(A \cdot 4\right)\right)\right) \cdot 2\right)}}{C \cdot \left(A \cdot 4\right) - {B}^{2}} \leq 0:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right) \cdot \left(\left(\frac{B \cdot B}{A} \cdot -0.5 + C\right) + C\right)} \cdot \sqrt{F}}{C \cdot \left(A \cdot 4\right) - {B}^{2}}\\ \mathbf{elif}\;\frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(\left(F \cdot \left({B}^{2} - C \cdot \left(A \cdot 4\right)\right)\right) \cdot 2\right)}}{C \cdot \left(A \cdot 4\right) - {B}^{2}} \leq \infty:\\ \;\;\;\;\frac{\sqrt{\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{-1}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2}}{B} \cdot \left(-\sqrt{F}\right)\\ \end{array} \]
              5. Add Preprocessing

              Alternative 4: 57.1% accurate, 0.3× speedup?

              \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ t_1 := \left(F \cdot 2\right) \cdot t\_0\\ t_2 := \sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}\\ t_3 := C \cdot \left(A \cdot 4\right)\\ t_4 := \frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right) \cdot \left(\left(F \cdot \left({B\_m}^{2} - t\_3\right)\right) \cdot 2\right)}}{t\_3 - {B\_m}^{2}}\\ t_5 := \sqrt{t\_1}\\ \mathbf{if}\;t\_4 \leq -5 \cdot 10^{-195}:\\ \;\;\;\;\frac{t\_2}{t\_0} \cdot \frac{t\_5}{-1}\\ \mathbf{elif}\;t\_4 \leq 0:\\ \;\;\;\;\frac{t\_0 \cdot 0 - \sqrt{\left(\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C\right) + C\right) \cdot t\_1} \cdot t\_0}{t\_0 \cdot t\_0}\\ \mathbf{elif}\;t\_4 \leq \infty:\\ \;\;\;\;\frac{t\_5}{t\_0} \cdot \frac{t\_2}{-1}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\ \end{array} \end{array} \]
              B_m = (fabs.f64 B)
              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
              (FPCore (A B_m C F)
               :precision binary64
               (let* ((t_0 (fma -4.0 (* C A) (* B_m B_m)))
                      (t_1 (* (* F 2.0) t_0))
                      (t_2 (sqrt (+ (+ (hypot (- A C) B_m) A) C)))
                      (t_3 (* C (* A 4.0)))
                      (t_4
                       (/
                        (sqrt
                         (*
                          (+ (+ C A) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))
                          (* (* F (- (pow B_m 2.0) t_3)) 2.0)))
                        (- t_3 (pow B_m 2.0))))
                      (t_5 (sqrt t_1)))
                 (if (<= t_4 -5e-195)
                   (* (/ t_2 t_0) (/ t_5 -1.0))
                   (if (<= t_4 0.0)
                     (/
                      (-
                       (* t_0 0.0)
                       (* (sqrt (* (+ (fma -0.5 (/ (* B_m B_m) A) C) C) t_1)) t_0))
                      (* t_0 t_0))
                     (if (<= t_4 INFINITY)
                       (* (/ t_5 t_0) (/ t_2 -1.0))
                       (* (/ (sqrt (* (+ (hypot C B_m) C) 2.0)) B_m) (- (sqrt F))))))))
              B_m = fabs(B);
              assert(A < B_m && B_m < C && C < F);
              double code(double A, double B_m, double C, double F) {
              	double t_0 = fma(-4.0, (C * A), (B_m * B_m));
              	double t_1 = (F * 2.0) * t_0;
              	double t_2 = sqrt(((hypot((A - C), B_m) + A) + C));
              	double t_3 = C * (A * 4.0);
              	double t_4 = sqrt((((C + A) + sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))) * ((F * (pow(B_m, 2.0) - t_3)) * 2.0))) / (t_3 - pow(B_m, 2.0));
              	double t_5 = sqrt(t_1);
              	double tmp;
              	if (t_4 <= -5e-195) {
              		tmp = (t_2 / t_0) * (t_5 / -1.0);
              	} else if (t_4 <= 0.0) {
              		tmp = ((t_0 * 0.0) - (sqrt(((fma(-0.5, ((B_m * B_m) / A), C) + C) * t_1)) * t_0)) / (t_0 * t_0);
              	} else if (t_4 <= ((double) INFINITY)) {
              		tmp = (t_5 / t_0) * (t_2 / -1.0);
              	} else {
              		tmp = (sqrt(((hypot(C, B_m) + C) * 2.0)) / B_m) * -sqrt(F);
              	}
              	return tmp;
              }
              
              B_m = abs(B)
              A, B_m, C, F = sort([A, B_m, C, F])
              function code(A, B_m, C, F)
              	t_0 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
              	t_1 = Float64(Float64(F * 2.0) * t_0)
              	t_2 = sqrt(Float64(Float64(hypot(Float64(A - C), B_m) + A) + C))
              	t_3 = Float64(C * Float64(A * 4.0))
              	t_4 = Float64(sqrt(Float64(Float64(Float64(C + A) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))) * Float64(Float64(F * Float64((B_m ^ 2.0) - t_3)) * 2.0))) / Float64(t_3 - (B_m ^ 2.0)))
              	t_5 = sqrt(t_1)
              	tmp = 0.0
              	if (t_4 <= -5e-195)
              		tmp = Float64(Float64(t_2 / t_0) * Float64(t_5 / -1.0));
              	elseif (t_4 <= 0.0)
              		tmp = Float64(Float64(Float64(t_0 * 0.0) - Float64(sqrt(Float64(Float64(fma(-0.5, Float64(Float64(B_m * B_m) / A), C) + C) * t_1)) * t_0)) / Float64(t_0 * t_0));
              	elseif (t_4 <= Inf)
              		tmp = Float64(Float64(t_5 / t_0) * Float64(t_2 / -1.0));
              	else
              		tmp = Float64(Float64(sqrt(Float64(Float64(hypot(C, B_m) + C) * 2.0)) / B_m) * Float64(-sqrt(F)));
              	end
              	return tmp
              end
              
              B_m = N[Abs[B], $MachinePrecision]
              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
              code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(F * 2.0), $MachinePrecision] * t$95$0), $MachinePrecision]}, Block[{t$95$2 = N[Sqrt[N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision]}, Block[{t$95$3 = N[(C * N[(A * 4.0), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$4 = N[(N[Sqrt[N[(N[(N[(C + A), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[(N[(F * N[(N[Power[B$95$m, 2.0], $MachinePrecision] - t$95$3), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[(t$95$3 - N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$5 = N[Sqrt[t$95$1], $MachinePrecision]}, If[LessEqual[t$95$4, -5e-195], N[(N[(t$95$2 / t$95$0), $MachinePrecision] * N[(t$95$5 / -1.0), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$4, 0.0], N[(N[(N[(t$95$0 * 0.0), $MachinePrecision] - N[(N[Sqrt[N[(N[(N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] + C), $MachinePrecision] + C), $MachinePrecision] * t$95$1), $MachinePrecision]], $MachinePrecision] * t$95$0), $MachinePrecision]), $MachinePrecision] / N[(t$95$0 * t$95$0), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$4, Infinity], N[(N[(t$95$5 / t$95$0), $MachinePrecision] * N[(t$95$2 / -1.0), $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / B$95$m), $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]]]]]]]]]]
              
              \begin{array}{l}
              B_m = \left|B\right|
              \\
              [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
              \\
              \begin{array}{l}
              t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
              t_1 := \left(F \cdot 2\right) \cdot t\_0\\
              t_2 := \sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}\\
              t_3 := C \cdot \left(A \cdot 4\right)\\
              t_4 := \frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right) \cdot \left(\left(F \cdot \left({B\_m}^{2} - t\_3\right)\right) \cdot 2\right)}}{t\_3 - {B\_m}^{2}}\\
              t_5 := \sqrt{t\_1}\\
              \mathbf{if}\;t\_4 \leq -5 \cdot 10^{-195}:\\
              \;\;\;\;\frac{t\_2}{t\_0} \cdot \frac{t\_5}{-1}\\
              
              \mathbf{elif}\;t\_4 \leq 0:\\
              \;\;\;\;\frac{t\_0 \cdot 0 - \sqrt{\left(\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C\right) + C\right) \cdot t\_1} \cdot t\_0}{t\_0 \cdot t\_0}\\
              
              \mathbf{elif}\;t\_4 \leq \infty:\\
              \;\;\;\;\frac{t\_5}{t\_0} \cdot \frac{t\_2}{-1}\\
              
              \mathbf{else}:\\
              \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\
              
              
              \end{array}
              \end{array}
              
              Derivation
              1. Split input into 4 regimes
              2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -5.00000000000000009e-195

                1. Initial program 48.9%

                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                2. Add Preprocessing
                3. Applied rewrites69.6%

                  \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]

                if -5.00000000000000009e-195 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -0.0

                1. Initial program 3.5%

                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                2. Add Preprocessing
                3. Applied rewrites3.8%

                  \[\leadsto \color{blue}{\frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                4. Taylor expanded in B around inf

                  \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{B \cdot \left(1 + \frac{A}{B}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                5. Step-by-step derivation
                  1. lower-*.f64N/A

                    \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{B \cdot \left(1 + \frac{A}{B}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  2. lower-+.f64N/A

                    \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(B \cdot \color{blue}{\left(1 + \frac{A}{B}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  3. lower-/.f641.6

                    \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(B \cdot \left(1 + \color{blue}{\frac{A}{B}}\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                6. Applied rewrites1.6%

                  \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{B \cdot \left(1 + \frac{A}{B}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                7. Taylor expanded in A around -inf

                  \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                8. Step-by-step derivation
                  1. +-commutativeN/A

                    \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  2. lower-fma.f64N/A

                    \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{\mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{A}, C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  3. lower-/.f64N/A

                    \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\mathsf{fma}\left(\frac{-1}{2}, \color{blue}{\frac{{B}^{2}}{A}}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  4. unpow2N/A

                    \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\mathsf{fma}\left(\frac{-1}{2}, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  5. lower-*.f6419.7

                    \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\mathsf{fma}\left(-0.5, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                9. Applied rewrites19.7%

                  \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]

                if -0.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

                1. Initial program 34.6%

                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                2. Add Preprocessing
                3. Applied rewrites72.7%

                  \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{-1} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]

                if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

                1. Initial program 0.0%

                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                2. Add Preprocessing
                3. Taylor expanded in A around 0

                  \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                4. Step-by-step derivation
                  1. associate-*r*N/A

                    \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                  2. lower-*.f64N/A

                    \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                  3. mul-1-negN/A

                    \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                  4. lower-neg.f64N/A

                    \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                  5. lower-/.f64N/A

                    \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                  6. lower-sqrt.f64N/A

                    \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                  7. lower-sqrt.f64N/A

                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                  8. *-commutativeN/A

                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                  9. lower-*.f64N/A

                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                  10. +-commutativeN/A

                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                  11. lower-+.f64N/A

                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                  12. +-commutativeN/A

                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                  13. unpow2N/A

                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                  14. unpow2N/A

                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                  15. lower-hypot.f6419.7

                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                5. Applied rewrites19.7%

                  \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                6. Step-by-step derivation
                  1. Applied rewrites33.5%

                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                  2. Step-by-step derivation
                    1. Applied rewrites33.6%

                      \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                  3. Recombined 4 regimes into one program.
                  4. Final simplification49.2%

                    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(\left(F \cdot \left({B}^{2} - C \cdot \left(A \cdot 4\right)\right)\right) \cdot 2\right)}}{C \cdot \left(A \cdot 4\right) - {B}^{2}} \leq -5 \cdot 10^{-195}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \cdot \frac{\sqrt{\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1}\\ \mathbf{elif}\;\frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(\left(F \cdot \left({B}^{2} - C \cdot \left(A \cdot 4\right)\right)\right) \cdot 2\right)}}{C \cdot \left(A \cdot 4\right) - {B}^{2}} \leq 0:\\ \;\;\;\;\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 0 - \sqrt{\left(\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right) + C\right) \cdot \left(\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)} \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(\left(F \cdot \left({B}^{2} - C \cdot \left(A \cdot 4\right)\right)\right) \cdot 2\right)}}{C \cdot \left(A \cdot 4\right) - {B}^{2}} \leq \infty:\\ \;\;\;\;\frac{\sqrt{\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{-1}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2}}{B} \cdot \left(-\sqrt{F}\right)\\ \end{array} \]
                  5. Add Preprocessing

                  Alternative 5: 57.1% accurate, 0.3× speedup?

                  \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ t_1 := C \cdot \left(A \cdot 4\right)\\ t_2 := \frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right) \cdot \left(\left(F \cdot \left({B\_m}^{2} - t\_1\right)\right) \cdot 2\right)}}{t\_1 - {B\_m}^{2}}\\ t_3 := \left(F \cdot 2\right) \cdot t\_0\\ t_4 := \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}}{t\_0} \cdot \frac{\sqrt{t\_3}}{-1}\\ \mathbf{if}\;t\_2 \leq -5 \cdot 10^{-195}:\\ \;\;\;\;t\_4\\ \mathbf{elif}\;t\_2 \leq 0:\\ \;\;\;\;\frac{t\_0 \cdot 0 - \sqrt{\left(\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C\right) + C\right) \cdot t\_3} \cdot t\_0}{t\_0 \cdot t\_0}\\ \mathbf{elif}\;t\_2 \leq \infty:\\ \;\;\;\;t\_4\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\ \end{array} \end{array} \]
                  B_m = (fabs.f64 B)
                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                  (FPCore (A B_m C F)
                   :precision binary64
                   (let* ((t_0 (fma -4.0 (* C A) (* B_m B_m)))
                          (t_1 (* C (* A 4.0)))
                          (t_2
                           (/
                            (sqrt
                             (*
                              (+ (+ C A) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))
                              (* (* F (- (pow B_m 2.0) t_1)) 2.0)))
                            (- t_1 (pow B_m 2.0))))
                          (t_3 (* (* F 2.0) t_0))
                          (t_4
                           (*
                            (/ (sqrt (+ (+ (hypot (- A C) B_m) A) C)) t_0)
                            (/ (sqrt t_3) -1.0))))
                     (if (<= t_2 -5e-195)
                       t_4
                       (if (<= t_2 0.0)
                         (/
                          (-
                           (* t_0 0.0)
                           (* (sqrt (* (+ (fma -0.5 (/ (* B_m B_m) A) C) C) t_3)) t_0))
                          (* t_0 t_0))
                         (if (<= t_2 INFINITY)
                           t_4
                           (* (/ (sqrt (* (+ (hypot C B_m) C) 2.0)) B_m) (- (sqrt F))))))))
                  B_m = fabs(B);
                  assert(A < B_m && B_m < C && C < F);
                  double code(double A, double B_m, double C, double F) {
                  	double t_0 = fma(-4.0, (C * A), (B_m * B_m));
                  	double t_1 = C * (A * 4.0);
                  	double t_2 = sqrt((((C + A) + sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))) * ((F * (pow(B_m, 2.0) - t_1)) * 2.0))) / (t_1 - pow(B_m, 2.0));
                  	double t_3 = (F * 2.0) * t_0;
                  	double t_4 = (sqrt(((hypot((A - C), B_m) + A) + C)) / t_0) * (sqrt(t_3) / -1.0);
                  	double tmp;
                  	if (t_2 <= -5e-195) {
                  		tmp = t_4;
                  	} else if (t_2 <= 0.0) {
                  		tmp = ((t_0 * 0.0) - (sqrt(((fma(-0.5, ((B_m * B_m) / A), C) + C) * t_3)) * t_0)) / (t_0 * t_0);
                  	} else if (t_2 <= ((double) INFINITY)) {
                  		tmp = t_4;
                  	} else {
                  		tmp = (sqrt(((hypot(C, B_m) + C) * 2.0)) / B_m) * -sqrt(F);
                  	}
                  	return tmp;
                  }
                  
                  B_m = abs(B)
                  A, B_m, C, F = sort([A, B_m, C, F])
                  function code(A, B_m, C, F)
                  	t_0 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
                  	t_1 = Float64(C * Float64(A * 4.0))
                  	t_2 = Float64(sqrt(Float64(Float64(Float64(C + A) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))) * Float64(Float64(F * Float64((B_m ^ 2.0) - t_1)) * 2.0))) / Float64(t_1 - (B_m ^ 2.0)))
                  	t_3 = Float64(Float64(F * 2.0) * t_0)
                  	t_4 = Float64(Float64(sqrt(Float64(Float64(hypot(Float64(A - C), B_m) + A) + C)) / t_0) * Float64(sqrt(t_3) / -1.0))
                  	tmp = 0.0
                  	if (t_2 <= -5e-195)
                  		tmp = t_4;
                  	elseif (t_2 <= 0.0)
                  		tmp = Float64(Float64(Float64(t_0 * 0.0) - Float64(sqrt(Float64(Float64(fma(-0.5, Float64(Float64(B_m * B_m) / A), C) + C) * t_3)) * t_0)) / Float64(t_0 * t_0));
                  	elseif (t_2 <= Inf)
                  		tmp = t_4;
                  	else
                  		tmp = Float64(Float64(sqrt(Float64(Float64(hypot(C, B_m) + C) * 2.0)) / B_m) * Float64(-sqrt(F)));
                  	end
                  	return tmp
                  end
                  
                  B_m = N[Abs[B], $MachinePrecision]
                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                  code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(C * N[(A * 4.0), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(N[Sqrt[N[(N[(N[(C + A), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[(N[(F * N[(N[Power[B$95$m, 2.0], $MachinePrecision] - t$95$1), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[(t$95$1 - N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = N[(N[(F * 2.0), $MachinePrecision] * t$95$0), $MachinePrecision]}, Block[{t$95$4 = N[(N[(N[Sqrt[N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] / t$95$0), $MachinePrecision] * N[(N[Sqrt[t$95$3], $MachinePrecision] / -1.0), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$2, -5e-195], t$95$4, If[LessEqual[t$95$2, 0.0], N[(N[(N[(t$95$0 * 0.0), $MachinePrecision] - N[(N[Sqrt[N[(N[(N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] + C), $MachinePrecision] + C), $MachinePrecision] * t$95$3), $MachinePrecision]], $MachinePrecision] * t$95$0), $MachinePrecision]), $MachinePrecision] / N[(t$95$0 * t$95$0), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$2, Infinity], t$95$4, N[(N[(N[Sqrt[N[(N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / B$95$m), $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]]]]]]]]]
                  
                  \begin{array}{l}
                  B_m = \left|B\right|
                  \\
                  [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                  \\
                  \begin{array}{l}
                  t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
                  t_1 := C \cdot \left(A \cdot 4\right)\\
                  t_2 := \frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right) \cdot \left(\left(F \cdot \left({B\_m}^{2} - t\_1\right)\right) \cdot 2\right)}}{t\_1 - {B\_m}^{2}}\\
                  t_3 := \left(F \cdot 2\right) \cdot t\_0\\
                  t_4 := \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}}{t\_0} \cdot \frac{\sqrt{t\_3}}{-1}\\
                  \mathbf{if}\;t\_2 \leq -5 \cdot 10^{-195}:\\
                  \;\;\;\;t\_4\\
                  
                  \mathbf{elif}\;t\_2 \leq 0:\\
                  \;\;\;\;\frac{t\_0 \cdot 0 - \sqrt{\left(\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C\right) + C\right) \cdot t\_3} \cdot t\_0}{t\_0 \cdot t\_0}\\
                  
                  \mathbf{elif}\;t\_2 \leq \infty:\\
                  \;\;\;\;t\_4\\
                  
                  \mathbf{else}:\\
                  \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\
                  
                  
                  \end{array}
                  \end{array}
                  
                  Derivation
                  1. Split input into 3 regimes
                  2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -5.00000000000000009e-195 or -0.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

                    1. Initial program 46.0%

                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    2. Add Preprocessing
                    3. Applied rewrites70.2%

                      \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]

                    if -5.00000000000000009e-195 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -0.0

                    1. Initial program 3.5%

                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    2. Add Preprocessing
                    3. Applied rewrites3.8%

                      \[\leadsto \color{blue}{\frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                    4. Taylor expanded in B around inf

                      \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{B \cdot \left(1 + \frac{A}{B}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                    5. Step-by-step derivation
                      1. lower-*.f64N/A

                        \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{B \cdot \left(1 + \frac{A}{B}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                      2. lower-+.f64N/A

                        \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(B \cdot \color{blue}{\left(1 + \frac{A}{B}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                      3. lower-/.f641.6

                        \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(B \cdot \left(1 + \color{blue}{\frac{A}{B}}\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                    6. Applied rewrites1.6%

                      \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{B \cdot \left(1 + \frac{A}{B}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                    7. Taylor expanded in A around -inf

                      \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                    8. Step-by-step derivation
                      1. +-commutativeN/A

                        \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                      2. lower-fma.f64N/A

                        \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{\mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{A}, C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                      3. lower-/.f64N/A

                        \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\mathsf{fma}\left(\frac{-1}{2}, \color{blue}{\frac{{B}^{2}}{A}}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                      4. unpow2N/A

                        \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\mathsf{fma}\left(\frac{-1}{2}, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                      5. lower-*.f6419.7

                        \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\mathsf{fma}\left(-0.5, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                    9. Applied rewrites19.7%

                      \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]

                    if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

                    1. Initial program 0.0%

                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    2. Add Preprocessing
                    3. Taylor expanded in A around 0

                      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                    4. Step-by-step derivation
                      1. associate-*r*N/A

                        \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                      2. lower-*.f64N/A

                        \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                      3. mul-1-negN/A

                        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                      4. lower-neg.f64N/A

                        \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                      5. lower-/.f64N/A

                        \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                      6. lower-sqrt.f64N/A

                        \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                      7. lower-sqrt.f64N/A

                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                      8. *-commutativeN/A

                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                      9. lower-*.f64N/A

                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                      10. +-commutativeN/A

                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                      11. lower-+.f64N/A

                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                      12. +-commutativeN/A

                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                      13. unpow2N/A

                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                      14. unpow2N/A

                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                      15. lower-hypot.f6419.7

                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                    5. Applied rewrites19.7%

                      \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                    6. Step-by-step derivation
                      1. Applied rewrites33.5%

                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                      2. Step-by-step derivation
                        1. Applied rewrites33.6%

                          \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                      3. Recombined 3 regimes into one program.
                      4. Final simplification49.2%

                        \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(\left(F \cdot \left({B}^{2} - C \cdot \left(A \cdot 4\right)\right)\right) \cdot 2\right)}}{C \cdot \left(A \cdot 4\right) - {B}^{2}} \leq -5 \cdot 10^{-195}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \cdot \frac{\sqrt{\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1}\\ \mathbf{elif}\;\frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(\left(F \cdot \left({B}^{2} - C \cdot \left(A \cdot 4\right)\right)\right) \cdot 2\right)}}{C \cdot \left(A \cdot 4\right) - {B}^{2}} \leq 0:\\ \;\;\;\;\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 0 - \sqrt{\left(\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right) + C\right) \cdot \left(\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)} \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(\left(F \cdot \left({B}^{2} - C \cdot \left(A \cdot 4\right)\right)\right) \cdot 2\right)}}{C \cdot \left(A \cdot 4\right) - {B}^{2}} \leq \infty:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \cdot \frac{\sqrt{\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2}}{B} \cdot \left(-\sqrt{F}\right)\\ \end{array} \]
                      5. Add Preprocessing

                      Alternative 6: 54.1% accurate, 0.3× speedup?

                      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{hypot}\left(A - C, B\_m\right)\\ t_1 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ t_2 := \left(F \cdot 2\right) \cdot t\_1\\ t_3 := C \cdot \left(A \cdot 4\right)\\ t_4 := \frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right) \cdot \left(\left(F \cdot \left({B\_m}^{2} - t\_3\right)\right) \cdot 2\right)}}{t\_3 - {B\_m}^{2}}\\ \mathbf{if}\;t\_4 \leq -\infty:\\ \;\;\;\;\sqrt{\frac{\left(\left(t\_0 + C\right) + A\right) \cdot F}{t\_1}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{elif}\;t\_4 \leq -5 \cdot 10^{-195}:\\ \;\;\;\;\frac{\sqrt{t\_2 \cdot \left(\left(t\_0 + A\right) + C\right)}}{-t\_1}\\ \mathbf{elif}\;t\_4 \leq \infty:\\ \;\;\;\;\frac{t\_1 \cdot 0 - \sqrt{\left(\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C\right) + C\right) \cdot t\_2} \cdot t\_1}{t\_1 \cdot t\_1}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\ \end{array} \end{array} \]
                      B_m = (fabs.f64 B)
                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                      (FPCore (A B_m C F)
                       :precision binary64
                       (let* ((t_0 (hypot (- A C) B_m))
                              (t_1 (fma -4.0 (* C A) (* B_m B_m)))
                              (t_2 (* (* F 2.0) t_1))
                              (t_3 (* C (* A 4.0)))
                              (t_4
                               (/
                                (sqrt
                                 (*
                                  (+ (+ C A) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))
                                  (* (* F (- (pow B_m 2.0) t_3)) 2.0)))
                                (- t_3 (pow B_m 2.0)))))
                         (if (<= t_4 (- INFINITY))
                           (* (sqrt (/ (* (+ (+ t_0 C) A) F) t_1)) (- (sqrt 2.0)))
                           (if (<= t_4 -5e-195)
                             (/ (sqrt (* t_2 (+ (+ t_0 A) C))) (- t_1))
                             (if (<= t_4 INFINITY)
                               (/
                                (-
                                 (* t_1 0.0)
                                 (* (sqrt (* (+ (fma -0.5 (/ (* B_m B_m) A) C) C) t_2)) t_1))
                                (* t_1 t_1))
                               (* (/ (sqrt (* (+ (hypot C B_m) C) 2.0)) B_m) (- (sqrt F))))))))
                      B_m = fabs(B);
                      assert(A < B_m && B_m < C && C < F);
                      double code(double A, double B_m, double C, double F) {
                      	double t_0 = hypot((A - C), B_m);
                      	double t_1 = fma(-4.0, (C * A), (B_m * B_m));
                      	double t_2 = (F * 2.0) * t_1;
                      	double t_3 = C * (A * 4.0);
                      	double t_4 = sqrt((((C + A) + sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))) * ((F * (pow(B_m, 2.0) - t_3)) * 2.0))) / (t_3 - pow(B_m, 2.0));
                      	double tmp;
                      	if (t_4 <= -((double) INFINITY)) {
                      		tmp = sqrt(((((t_0 + C) + A) * F) / t_1)) * -sqrt(2.0);
                      	} else if (t_4 <= -5e-195) {
                      		tmp = sqrt((t_2 * ((t_0 + A) + C))) / -t_1;
                      	} else if (t_4 <= ((double) INFINITY)) {
                      		tmp = ((t_1 * 0.0) - (sqrt(((fma(-0.5, ((B_m * B_m) / A), C) + C) * t_2)) * t_1)) / (t_1 * t_1);
                      	} else {
                      		tmp = (sqrt(((hypot(C, B_m) + C) * 2.0)) / B_m) * -sqrt(F);
                      	}
                      	return tmp;
                      }
                      
                      B_m = abs(B)
                      A, B_m, C, F = sort([A, B_m, C, F])
                      function code(A, B_m, C, F)
                      	t_0 = hypot(Float64(A - C), B_m)
                      	t_1 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
                      	t_2 = Float64(Float64(F * 2.0) * t_1)
                      	t_3 = Float64(C * Float64(A * 4.0))
                      	t_4 = Float64(sqrt(Float64(Float64(Float64(C + A) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))) * Float64(Float64(F * Float64((B_m ^ 2.0) - t_3)) * 2.0))) / Float64(t_3 - (B_m ^ 2.0)))
                      	tmp = 0.0
                      	if (t_4 <= Float64(-Inf))
                      		tmp = Float64(sqrt(Float64(Float64(Float64(Float64(t_0 + C) + A) * F) / t_1)) * Float64(-sqrt(2.0)));
                      	elseif (t_4 <= -5e-195)
                      		tmp = Float64(sqrt(Float64(t_2 * Float64(Float64(t_0 + A) + C))) / Float64(-t_1));
                      	elseif (t_4 <= Inf)
                      		tmp = Float64(Float64(Float64(t_1 * 0.0) - Float64(sqrt(Float64(Float64(fma(-0.5, Float64(Float64(B_m * B_m) / A), C) + C) * t_2)) * t_1)) / Float64(t_1 * t_1));
                      	else
                      		tmp = Float64(Float64(sqrt(Float64(Float64(hypot(C, B_m) + C) * 2.0)) / B_m) * Float64(-sqrt(F)));
                      	end
                      	return tmp
                      end
                      
                      B_m = N[Abs[B], $MachinePrecision]
                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                      code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision]}, Block[{t$95$1 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(N[(F * 2.0), $MachinePrecision] * t$95$1), $MachinePrecision]}, Block[{t$95$3 = N[(C * N[(A * 4.0), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$4 = N[(N[Sqrt[N[(N[(N[(C + A), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[(N[(F * N[(N[Power[B$95$m, 2.0], $MachinePrecision] - t$95$3), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[(t$95$3 - N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$4, (-Infinity)], N[(N[Sqrt[N[(N[(N[(N[(t$95$0 + C), $MachinePrecision] + A), $MachinePrecision] * F), $MachinePrecision] / t$95$1), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[2.0], $MachinePrecision])), $MachinePrecision], If[LessEqual[t$95$4, -5e-195], N[(N[Sqrt[N[(t$95$2 * N[(N[(t$95$0 + A), $MachinePrecision] + C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$1)), $MachinePrecision], If[LessEqual[t$95$4, Infinity], N[(N[(N[(t$95$1 * 0.0), $MachinePrecision] - N[(N[Sqrt[N[(N[(N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] + C), $MachinePrecision] + C), $MachinePrecision] * t$95$2), $MachinePrecision]], $MachinePrecision] * t$95$1), $MachinePrecision]), $MachinePrecision] / N[(t$95$1 * t$95$1), $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / B$95$m), $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]]]]]]]]]
                      
                      \begin{array}{l}
                      B_m = \left|B\right|
                      \\
                      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                      \\
                      \begin{array}{l}
                      t_0 := \mathsf{hypot}\left(A - C, B\_m\right)\\
                      t_1 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
                      t_2 := \left(F \cdot 2\right) \cdot t\_1\\
                      t_3 := C \cdot \left(A \cdot 4\right)\\
                      t_4 := \frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right) \cdot \left(\left(F \cdot \left({B\_m}^{2} - t\_3\right)\right) \cdot 2\right)}}{t\_3 - {B\_m}^{2}}\\
                      \mathbf{if}\;t\_4 \leq -\infty:\\
                      \;\;\;\;\sqrt{\frac{\left(\left(t\_0 + C\right) + A\right) \cdot F}{t\_1}} \cdot \left(-\sqrt{2}\right)\\
                      
                      \mathbf{elif}\;t\_4 \leq -5 \cdot 10^{-195}:\\
                      \;\;\;\;\frac{\sqrt{t\_2 \cdot \left(\left(t\_0 + A\right) + C\right)}}{-t\_1}\\
                      
                      \mathbf{elif}\;t\_4 \leq \infty:\\
                      \;\;\;\;\frac{t\_1 \cdot 0 - \sqrt{\left(\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C\right) + C\right) \cdot t\_2} \cdot t\_1}{t\_1 \cdot t\_1}\\
                      
                      \mathbf{else}:\\
                      \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\
                      
                      
                      \end{array}
                      \end{array}
                      
                      Derivation
                      1. Split input into 4 regimes
                      2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -inf.0

                        1. Initial program 3.2%

                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        2. Add Preprocessing
                        3. Taylor expanded in F around 0

                          \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                        4. Step-by-step derivation
                          1. mul-1-negN/A

                            \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                          2. *-commutativeN/A

                            \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}}\right) \]
                          3. distribute-lft-neg-inN/A

                            \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                          4. lower-*.f64N/A

                            \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                          5. lower-neg.f64N/A

                            \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \]
                          6. lower-sqrt.f64N/A

                            \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \]
                          7. lower-sqrt.f64N/A

                            \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                          8. lower-/.f64N/A

                            \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                        5. Applied rewrites43.7%

                          \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}} \]

                        if -inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -5.00000000000000009e-195

                        1. Initial program 99.4%

                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        2. Add Preprocessing
                        3. Applied rewrites99.3%

                          \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]

                        if -5.00000000000000009e-195 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

                        1. Initial program 15.6%

                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        2. Add Preprocessing
                        3. Applied rewrites16.6%

                          \[\leadsto \color{blue}{\frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                        4. Taylor expanded in B around inf

                          \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{B \cdot \left(1 + \frac{A}{B}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                        5. Step-by-step derivation
                          1. lower-*.f64N/A

                            \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{B \cdot \left(1 + \frac{A}{B}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                          2. lower-+.f64N/A

                            \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(B \cdot \color{blue}{\left(1 + \frac{A}{B}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                          3. lower-/.f643.7

                            \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(B \cdot \left(1 + \color{blue}{\frac{A}{B}}\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                        6. Applied rewrites3.7%

                          \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{B \cdot \left(1 + \frac{A}{B}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                        7. Taylor expanded in A around -inf

                          \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                        8. Step-by-step derivation
                          1. +-commutativeN/A

                            \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                          2. lower-fma.f64N/A

                            \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{\mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{A}, C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                          3. lower-/.f64N/A

                            \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\mathsf{fma}\left(\frac{-1}{2}, \color{blue}{\frac{{B}^{2}}{A}}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                          4. unpow2N/A

                            \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\mathsf{fma}\left(\frac{-1}{2}, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                          5. lower-*.f6417.6

                            \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\mathsf{fma}\left(-0.5, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                        9. Applied rewrites17.6%

                          \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]

                        if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

                        1. Initial program 0.0%

                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        2. Add Preprocessing
                        3. Taylor expanded in A around 0

                          \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                        4. Step-by-step derivation
                          1. associate-*r*N/A

                            \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                          2. lower-*.f64N/A

                            \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                          3. mul-1-negN/A

                            \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                          4. lower-neg.f64N/A

                            \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                          5. lower-/.f64N/A

                            \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                          6. lower-sqrt.f64N/A

                            \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                          7. lower-sqrt.f64N/A

                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                          8. *-commutativeN/A

                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                          9. lower-*.f64N/A

                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                          10. +-commutativeN/A

                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                          11. lower-+.f64N/A

                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                          12. +-commutativeN/A

                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                          13. unpow2N/A

                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                          14. unpow2N/A

                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                          15. lower-hypot.f6419.7

                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                        5. Applied rewrites19.7%

                          \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                        6. Step-by-step derivation
                          1. Applied rewrites33.5%

                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                          2. Step-by-step derivation
                            1. Applied rewrites33.6%

                              \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                          3. Recombined 4 regimes into one program.
                          4. Final simplification43.7%

                            \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(\left(F \cdot \left({B}^{2} - C \cdot \left(A \cdot 4\right)\right)\right) \cdot 2\right)}}{C \cdot \left(A \cdot 4\right) - {B}^{2}} \leq -\infty:\\ \;\;\;\;\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{elif}\;\frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(\left(F \cdot \left({B}^{2} - C \cdot \left(A \cdot 4\right)\right)\right) \cdot 2\right)}}{C \cdot \left(A \cdot 4\right) - {B}^{2}} \leq -5 \cdot 10^{-195}:\\ \;\;\;\;\frac{\sqrt{\left(\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right) \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(\left(F \cdot \left({B}^{2} - C \cdot \left(A \cdot 4\right)\right)\right) \cdot 2\right)}}{C \cdot \left(A \cdot 4\right) - {B}^{2}} \leq \infty:\\ \;\;\;\;\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 0 - \sqrt{\left(\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right) + C\right) \cdot \left(\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)} \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2}}{B} \cdot \left(-\sqrt{F}\right)\\ \end{array} \]
                          5. Add Preprocessing

                          Alternative 7: 52.5% accurate, 0.3× speedup?

                          \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ t_1 := C \cdot \left(A \cdot 4\right)\\ t_2 := \frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right) \cdot \left(\left(F \cdot \left({B\_m}^{2} - t\_1\right)\right) \cdot 2\right)}}{t\_1 - {B\_m}^{2}}\\ t_3 := -\sqrt{2}\\ \mathbf{if}\;t\_2 \leq -1 \cdot 10^{-146}:\\ \;\;\;\;\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\_m\right) + C\right) + A\right) \cdot F}{t\_0}} \cdot t\_3\\ \mathbf{elif}\;t\_2 \leq -5 \cdot 10^{-195}:\\ \;\;\;\;\sqrt{\left(\mathsf{hypot}\left(A, B\_m\right) + A\right) \cdot F} \cdot \frac{t\_3}{B\_m}\\ \mathbf{elif}\;t\_2 \leq \infty:\\ \;\;\;\;\frac{t\_0 \cdot 0 - \sqrt{\left(\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C\right) + C\right) \cdot \left(\left(F \cdot 2\right) \cdot t\_0\right)} \cdot t\_0}{t\_0 \cdot t\_0}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\ \end{array} \end{array} \]
                          B_m = (fabs.f64 B)
                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                          (FPCore (A B_m C F)
                           :precision binary64
                           (let* ((t_0 (fma -4.0 (* C A) (* B_m B_m)))
                                  (t_1 (* C (* A 4.0)))
                                  (t_2
                                   (/
                                    (sqrt
                                     (*
                                      (+ (+ C A) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))
                                      (* (* F (- (pow B_m 2.0) t_1)) 2.0)))
                                    (- t_1 (pow B_m 2.0))))
                                  (t_3 (- (sqrt 2.0))))
                             (if (<= t_2 -1e-146)
                               (* (sqrt (/ (* (+ (+ (hypot (- A C) B_m) C) A) F) t_0)) t_3)
                               (if (<= t_2 -5e-195)
                                 (* (sqrt (* (+ (hypot A B_m) A) F)) (/ t_3 B_m))
                                 (if (<= t_2 INFINITY)
                                   (/
                                    (-
                                     (* t_0 0.0)
                                     (*
                                      (sqrt (* (+ (fma -0.5 (/ (* B_m B_m) A) C) C) (* (* F 2.0) t_0)))
                                      t_0))
                                    (* t_0 t_0))
                                   (* (/ (sqrt (* (+ (hypot C B_m) C) 2.0)) B_m) (- (sqrt F))))))))
                          B_m = fabs(B);
                          assert(A < B_m && B_m < C && C < F);
                          double code(double A, double B_m, double C, double F) {
                          	double t_0 = fma(-4.0, (C * A), (B_m * B_m));
                          	double t_1 = C * (A * 4.0);
                          	double t_2 = sqrt((((C + A) + sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))) * ((F * (pow(B_m, 2.0) - t_1)) * 2.0))) / (t_1 - pow(B_m, 2.0));
                          	double t_3 = -sqrt(2.0);
                          	double tmp;
                          	if (t_2 <= -1e-146) {
                          		tmp = sqrt(((((hypot((A - C), B_m) + C) + A) * F) / t_0)) * t_3;
                          	} else if (t_2 <= -5e-195) {
                          		tmp = sqrt(((hypot(A, B_m) + A) * F)) * (t_3 / B_m);
                          	} else if (t_2 <= ((double) INFINITY)) {
                          		tmp = ((t_0 * 0.0) - (sqrt(((fma(-0.5, ((B_m * B_m) / A), C) + C) * ((F * 2.0) * t_0))) * t_0)) / (t_0 * t_0);
                          	} else {
                          		tmp = (sqrt(((hypot(C, B_m) + C) * 2.0)) / B_m) * -sqrt(F);
                          	}
                          	return tmp;
                          }
                          
                          B_m = abs(B)
                          A, B_m, C, F = sort([A, B_m, C, F])
                          function code(A, B_m, C, F)
                          	t_0 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
                          	t_1 = Float64(C * Float64(A * 4.0))
                          	t_2 = Float64(sqrt(Float64(Float64(Float64(C + A) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))) * Float64(Float64(F * Float64((B_m ^ 2.0) - t_1)) * 2.0))) / Float64(t_1 - (B_m ^ 2.0)))
                          	t_3 = Float64(-sqrt(2.0))
                          	tmp = 0.0
                          	if (t_2 <= -1e-146)
                          		tmp = Float64(sqrt(Float64(Float64(Float64(Float64(hypot(Float64(A - C), B_m) + C) + A) * F) / t_0)) * t_3);
                          	elseif (t_2 <= -5e-195)
                          		tmp = Float64(sqrt(Float64(Float64(hypot(A, B_m) + A) * F)) * Float64(t_3 / B_m));
                          	elseif (t_2 <= Inf)
                          		tmp = Float64(Float64(Float64(t_0 * 0.0) - Float64(sqrt(Float64(Float64(fma(-0.5, Float64(Float64(B_m * B_m) / A), C) + C) * Float64(Float64(F * 2.0) * t_0))) * t_0)) / Float64(t_0 * t_0));
                          	else
                          		tmp = Float64(Float64(sqrt(Float64(Float64(hypot(C, B_m) + C) * 2.0)) / B_m) * Float64(-sqrt(F)));
                          	end
                          	return tmp
                          end
                          
                          B_m = N[Abs[B], $MachinePrecision]
                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                          code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(C * N[(A * 4.0), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(N[Sqrt[N[(N[(N[(C + A), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[(N[(F * N[(N[Power[B$95$m, 2.0], $MachinePrecision] - t$95$1), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[(t$95$1 - N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = (-N[Sqrt[2.0], $MachinePrecision])}, If[LessEqual[t$95$2, -1e-146], N[(N[Sqrt[N[(N[(N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] + A), $MachinePrecision] * F), $MachinePrecision] / t$95$0), $MachinePrecision]], $MachinePrecision] * t$95$3), $MachinePrecision], If[LessEqual[t$95$2, -5e-195], N[(N[Sqrt[N[(N[(N[Sqrt[A ^ 2 + B$95$m ^ 2], $MachinePrecision] + A), $MachinePrecision] * F), $MachinePrecision]], $MachinePrecision] * N[(t$95$3 / B$95$m), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$2, Infinity], N[(N[(N[(t$95$0 * 0.0), $MachinePrecision] - N[(N[Sqrt[N[(N[(N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] + C), $MachinePrecision] + C), $MachinePrecision] * N[(N[(F * 2.0), $MachinePrecision] * t$95$0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * t$95$0), $MachinePrecision]), $MachinePrecision] / N[(t$95$0 * t$95$0), $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / B$95$m), $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]]]]]]]]
                          
                          \begin{array}{l}
                          B_m = \left|B\right|
                          \\
                          [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                          \\
                          \begin{array}{l}
                          t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
                          t_1 := C \cdot \left(A \cdot 4\right)\\
                          t_2 := \frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right) \cdot \left(\left(F \cdot \left({B\_m}^{2} - t\_1\right)\right) \cdot 2\right)}}{t\_1 - {B\_m}^{2}}\\
                          t_3 := -\sqrt{2}\\
                          \mathbf{if}\;t\_2 \leq -1 \cdot 10^{-146}:\\
                          \;\;\;\;\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\_m\right) + C\right) + A\right) \cdot F}{t\_0}} \cdot t\_3\\
                          
                          \mathbf{elif}\;t\_2 \leq -5 \cdot 10^{-195}:\\
                          \;\;\;\;\sqrt{\left(\mathsf{hypot}\left(A, B\_m\right) + A\right) \cdot F} \cdot \frac{t\_3}{B\_m}\\
                          
                          \mathbf{elif}\;t\_2 \leq \infty:\\
                          \;\;\;\;\frac{t\_0 \cdot 0 - \sqrt{\left(\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C\right) + C\right) \cdot \left(\left(F \cdot 2\right) \cdot t\_0\right)} \cdot t\_0}{t\_0 \cdot t\_0}\\
                          
                          \mathbf{else}:\\
                          \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\
                          
                          
                          \end{array}
                          \end{array}
                          
                          Derivation
                          1. Split input into 4 regimes
                          2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -1.00000000000000003e-146

                            1. Initial program 45.6%

                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            2. Add Preprocessing
                            3. Taylor expanded in F around 0

                              \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                            4. Step-by-step derivation
                              1. mul-1-negN/A

                                \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                              2. *-commutativeN/A

                                \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}}\right) \]
                              3. distribute-lft-neg-inN/A

                                \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                              4. lower-*.f64N/A

                                \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                              5. lower-neg.f64N/A

                                \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \]
                              6. lower-sqrt.f64N/A

                                \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \]
                              7. lower-sqrt.f64N/A

                                \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                              8. lower-/.f64N/A

                                \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                            5. Applied rewrites66.2%

                              \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}} \]

                            if -1.00000000000000003e-146 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -5.00000000000000009e-195

                            1. Initial program 99.7%

                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            2. Add Preprocessing
                            3. Taylor expanded in C around 0

                              \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}\right)} \]
                            4. Step-by-step derivation
                              1. associate-*r*N/A

                                \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}} \]
                              2. lower-*.f64N/A

                                \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}} \]
                              3. mul-1-negN/A

                                \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \]
                              4. lower-neg.f64N/A

                                \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \]
                              5. lower-/.f64N/A

                                \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \]
                              6. lower-sqrt.f64N/A

                                \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \]
                              7. lower-sqrt.f64N/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(A + \sqrt{{A}^{2} + {B}^{2}}\right)}} \]
                              8. *-commutativeN/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(A + \sqrt{{A}^{2} + {B}^{2}}\right) \cdot F}} \]
                              9. lower-*.f64N/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(A + \sqrt{{A}^{2} + {B}^{2}}\right) \cdot F}} \]
                              10. +-commutativeN/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{A}^{2} + {B}^{2}} + A\right)} \cdot F} \]
                              11. lower-+.f64N/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{A}^{2} + {B}^{2}} + A\right)} \cdot F} \]
                              12. unpow2N/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{A \cdot A} + {B}^{2}} + A\right) \cdot F} \]
                              13. unpow2N/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{A \cdot A + \color{blue}{B \cdot B}} + A\right) \cdot F} \]
                              14. lower-hypot.f6467.3

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(A, B\right)} + A\right) \cdot F} \]
                            5. Applied rewrites67.3%

                              \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(A, B\right) + A\right) \cdot F}} \]

                            if -5.00000000000000009e-195 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

                            1. Initial program 15.6%

                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            2. Add Preprocessing
                            3. Applied rewrites16.6%

                              \[\leadsto \color{blue}{\frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                            4. Taylor expanded in B around inf

                              \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{B \cdot \left(1 + \frac{A}{B}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                            5. Step-by-step derivation
                              1. lower-*.f64N/A

                                \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{B \cdot \left(1 + \frac{A}{B}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                              2. lower-+.f64N/A

                                \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(B \cdot \color{blue}{\left(1 + \frac{A}{B}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                              3. lower-/.f643.7

                                \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(B \cdot \left(1 + \color{blue}{\frac{A}{B}}\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                            6. Applied rewrites3.7%

                              \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{B \cdot \left(1 + \frac{A}{B}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                            7. Taylor expanded in A around -inf

                              \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                            8. Step-by-step derivation
                              1. +-commutativeN/A

                                \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                              2. lower-fma.f64N/A

                                \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{\mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{A}, C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                              3. lower-/.f64N/A

                                \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\mathsf{fma}\left(\frac{-1}{2}, \color{blue}{\frac{{B}^{2}}{A}}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                              4. unpow2N/A

                                \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\mathsf{fma}\left(\frac{-1}{2}, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                              5. lower-*.f6417.6

                                \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\mathsf{fma}\left(-0.5, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                            9. Applied rewrites17.6%

                              \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]

                            if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

                            1. Initial program 0.0%

                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            2. Add Preprocessing
                            3. Taylor expanded in A around 0

                              \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                            4. Step-by-step derivation
                              1. associate-*r*N/A

                                \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                              2. lower-*.f64N/A

                                \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                              3. mul-1-negN/A

                                \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                              4. lower-neg.f64N/A

                                \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                              5. lower-/.f64N/A

                                \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                              6. lower-sqrt.f64N/A

                                \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                              7. lower-sqrt.f64N/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                              8. *-commutativeN/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                              9. lower-*.f64N/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                              10. +-commutativeN/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                              11. lower-+.f64N/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                              12. +-commutativeN/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                              13. unpow2N/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                              14. unpow2N/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                              15. lower-hypot.f6419.7

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                            5. Applied rewrites19.7%

                              \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                            6. Step-by-step derivation
                              1. Applied rewrites33.5%

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                              2. Step-by-step derivation
                                1. Applied rewrites33.6%

                                  \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                              3. Recombined 4 regimes into one program.
                              4. Final simplification42.2%

                                \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(\left(F \cdot \left({B}^{2} - C \cdot \left(A \cdot 4\right)\right)\right) \cdot 2\right)}}{C \cdot \left(A \cdot 4\right) - {B}^{2}} \leq -1 \cdot 10^{-146}:\\ \;\;\;\;\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{elif}\;\frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(\left(F \cdot \left({B}^{2} - C \cdot \left(A \cdot 4\right)\right)\right) \cdot 2\right)}}{C \cdot \left(A \cdot 4\right) - {B}^{2}} \leq -5 \cdot 10^{-195}:\\ \;\;\;\;\sqrt{\left(\mathsf{hypot}\left(A, B\right) + A\right) \cdot F} \cdot \frac{-\sqrt{2}}{B}\\ \mathbf{elif}\;\frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(\left(F \cdot \left({B}^{2} - C \cdot \left(A \cdot 4\right)\right)\right) \cdot 2\right)}}{C \cdot \left(A \cdot 4\right) - {B}^{2}} \leq \infty:\\ \;\;\;\;\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 0 - \sqrt{\left(\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right) + C\right) \cdot \left(\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)} \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2}}{B} \cdot \left(-\sqrt{F}\right)\\ \end{array} \]
                              5. Add Preprocessing

                              Alternative 8: 50.1% accurate, 0.4× speedup?

                              \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}\\ t_1 := C \cdot \left(A \cdot 4\right)\\ t_2 := \frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right) \cdot \left(\left(F \cdot \left({B\_m}^{2} - t\_1\right)\right) \cdot 2\right)}}{t\_1 - {B\_m}^{2}}\\ t_3 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;t\_2 \leq -5 \cdot 10^{-195}:\\ \;\;\;\;\frac{\sqrt{F}}{-B\_m} \cdot t\_0\\ \mathbf{elif}\;t\_2 \leq \infty:\\ \;\;\;\;\frac{t\_3 \cdot 0 - \sqrt{\left(\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C\right) + C\right) \cdot \left(\left(F \cdot 2\right) \cdot t\_3\right)} \cdot t\_3}{t\_3 \cdot t\_3}\\ \mathbf{else}:\\ \;\;\;\;\frac{t\_0}{B\_m} \cdot \left(-\sqrt{F}\right)\\ \end{array} \end{array} \]
                              B_m = (fabs.f64 B)
                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                              (FPCore (A B_m C F)
                               :precision binary64
                               (let* ((t_0 (sqrt (* (+ (hypot C B_m) C) 2.0)))
                                      (t_1 (* C (* A 4.0)))
                                      (t_2
                                       (/
                                        (sqrt
                                         (*
                                          (+ (+ C A) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))
                                          (* (* F (- (pow B_m 2.0) t_1)) 2.0)))
                                        (- t_1 (pow B_m 2.0))))
                                      (t_3 (fma -4.0 (* C A) (* B_m B_m))))
                                 (if (<= t_2 -5e-195)
                                   (* (/ (sqrt F) (- B_m)) t_0)
                                   (if (<= t_2 INFINITY)
                                     (/
                                      (-
                                       (* t_3 0.0)
                                       (*
                                        (sqrt (* (+ (fma -0.5 (/ (* B_m B_m) A) C) C) (* (* F 2.0) t_3)))
                                        t_3))
                                      (* t_3 t_3))
                                     (* (/ t_0 B_m) (- (sqrt F)))))))
                              B_m = fabs(B);
                              assert(A < B_m && B_m < C && C < F);
                              double code(double A, double B_m, double C, double F) {
                              	double t_0 = sqrt(((hypot(C, B_m) + C) * 2.0));
                              	double t_1 = C * (A * 4.0);
                              	double t_2 = sqrt((((C + A) + sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))) * ((F * (pow(B_m, 2.0) - t_1)) * 2.0))) / (t_1 - pow(B_m, 2.0));
                              	double t_3 = fma(-4.0, (C * A), (B_m * B_m));
                              	double tmp;
                              	if (t_2 <= -5e-195) {
                              		tmp = (sqrt(F) / -B_m) * t_0;
                              	} else if (t_2 <= ((double) INFINITY)) {
                              		tmp = ((t_3 * 0.0) - (sqrt(((fma(-0.5, ((B_m * B_m) / A), C) + C) * ((F * 2.0) * t_3))) * t_3)) / (t_3 * t_3);
                              	} else {
                              		tmp = (t_0 / B_m) * -sqrt(F);
                              	}
                              	return tmp;
                              }
                              
                              B_m = abs(B)
                              A, B_m, C, F = sort([A, B_m, C, F])
                              function code(A, B_m, C, F)
                              	t_0 = sqrt(Float64(Float64(hypot(C, B_m) + C) * 2.0))
                              	t_1 = Float64(C * Float64(A * 4.0))
                              	t_2 = Float64(sqrt(Float64(Float64(Float64(C + A) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))) * Float64(Float64(F * Float64((B_m ^ 2.0) - t_1)) * 2.0))) / Float64(t_1 - (B_m ^ 2.0)))
                              	t_3 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
                              	tmp = 0.0
                              	if (t_2 <= -5e-195)
                              		tmp = Float64(Float64(sqrt(F) / Float64(-B_m)) * t_0);
                              	elseif (t_2 <= Inf)
                              		tmp = Float64(Float64(Float64(t_3 * 0.0) - Float64(sqrt(Float64(Float64(fma(-0.5, Float64(Float64(B_m * B_m) / A), C) + C) * Float64(Float64(F * 2.0) * t_3))) * t_3)) / Float64(t_3 * t_3));
                              	else
                              		tmp = Float64(Float64(t_0 / B_m) * Float64(-sqrt(F)));
                              	end
                              	return tmp
                              end
                              
                              B_m = N[Abs[B], $MachinePrecision]
                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                              code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[Sqrt[N[(N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision]}, Block[{t$95$1 = N[(C * N[(A * 4.0), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(N[Sqrt[N[(N[(N[(C + A), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[(N[(F * N[(N[Power[B$95$m, 2.0], $MachinePrecision] - t$95$1), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[(t$95$1 - N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$2, -5e-195], N[(N[(N[Sqrt[F], $MachinePrecision] / (-B$95$m)), $MachinePrecision] * t$95$0), $MachinePrecision], If[LessEqual[t$95$2, Infinity], N[(N[(N[(t$95$3 * 0.0), $MachinePrecision] - N[(N[Sqrt[N[(N[(N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] + C), $MachinePrecision] + C), $MachinePrecision] * N[(N[(F * 2.0), $MachinePrecision] * t$95$3), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * t$95$3), $MachinePrecision]), $MachinePrecision] / N[(t$95$3 * t$95$3), $MachinePrecision]), $MachinePrecision], N[(N[(t$95$0 / B$95$m), $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]]]]]]]
                              
                              \begin{array}{l}
                              B_m = \left|B\right|
                              \\
                              [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                              \\
                              \begin{array}{l}
                              t_0 := \sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}\\
                              t_1 := C \cdot \left(A \cdot 4\right)\\
                              t_2 := \frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right) \cdot \left(\left(F \cdot \left({B\_m}^{2} - t\_1\right)\right) \cdot 2\right)}}{t\_1 - {B\_m}^{2}}\\
                              t_3 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
                              \mathbf{if}\;t\_2 \leq -5 \cdot 10^{-195}:\\
                              \;\;\;\;\frac{\sqrt{F}}{-B\_m} \cdot t\_0\\
                              
                              \mathbf{elif}\;t\_2 \leq \infty:\\
                              \;\;\;\;\frac{t\_3 \cdot 0 - \sqrt{\left(\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C\right) + C\right) \cdot \left(\left(F \cdot 2\right) \cdot t\_3\right)} \cdot t\_3}{t\_3 \cdot t\_3}\\
                              
                              \mathbf{else}:\\
                              \;\;\;\;\frac{t\_0}{B\_m} \cdot \left(-\sqrt{F}\right)\\
                              
                              
                              \end{array}
                              \end{array}
                              
                              Derivation
                              1. Split input into 3 regimes
                              2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -5.00000000000000009e-195

                                1. Initial program 48.9%

                                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                2. Add Preprocessing
                                3. Taylor expanded in A around 0

                                  \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                4. Step-by-step derivation
                                  1. associate-*r*N/A

                                    \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                  2. lower-*.f64N/A

                                    \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                  3. mul-1-negN/A

                                    \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                  4. lower-neg.f64N/A

                                    \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                  5. lower-/.f64N/A

                                    \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                  6. lower-sqrt.f64N/A

                                    \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                  7. lower-sqrt.f64N/A

                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                  8. *-commutativeN/A

                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                  9. lower-*.f64N/A

                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                  10. +-commutativeN/A

                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                  11. lower-+.f64N/A

                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                  12. +-commutativeN/A

                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                                  13. unpow2N/A

                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                                  14. unpow2N/A

                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                                  15. lower-hypot.f6423.2

                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                                5. Applied rewrites23.2%

                                  \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                                6. Step-by-step derivation
                                  1. Applied rewrites23.2%

                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                                  2. Step-by-step derivation
                                    1. Applied rewrites23.2%

                                      \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                                    2. Step-by-step derivation
                                      1. Applied rewrites23.1%

                                        \[\leadsto \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2} \cdot \color{blue}{\frac{\sqrt{F}}{-B}} \]

                                      if -5.00000000000000009e-195 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

                                      1. Initial program 15.6%

                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                      2. Add Preprocessing
                                      3. Applied rewrites16.6%

                                        \[\leadsto \color{blue}{\frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                                      4. Taylor expanded in B around inf

                                        \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{B \cdot \left(1 + \frac{A}{B}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                      5. Step-by-step derivation
                                        1. lower-*.f64N/A

                                          \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{B \cdot \left(1 + \frac{A}{B}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                        2. lower-+.f64N/A

                                          \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(B \cdot \color{blue}{\left(1 + \frac{A}{B}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                        3. lower-/.f643.7

                                          \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(B \cdot \left(1 + \color{blue}{\frac{A}{B}}\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                      6. Applied rewrites3.7%

                                        \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{B \cdot \left(1 + \frac{A}{B}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                      7. Taylor expanded in A around -inf

                                        \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                      8. Step-by-step derivation
                                        1. +-commutativeN/A

                                          \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                        2. lower-fma.f64N/A

                                          \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{\mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{A}, C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                        3. lower-/.f64N/A

                                          \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\mathsf{fma}\left(\frac{-1}{2}, \color{blue}{\frac{{B}^{2}}{A}}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                        4. unpow2N/A

                                          \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\mathsf{fma}\left(\frac{-1}{2}, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                        5. lower-*.f6417.6

                                          \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\mathsf{fma}\left(-0.5, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                      9. Applied rewrites17.6%

                                        \[\leadsto \frac{0 \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) - \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \sqrt{\left(\color{blue}{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]

                                      if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

                                      1. Initial program 0.0%

                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                      2. Add Preprocessing
                                      3. Taylor expanded in A around 0

                                        \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                      4. Step-by-step derivation
                                        1. associate-*r*N/A

                                          \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                        2. lower-*.f64N/A

                                          \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                        3. mul-1-negN/A

                                          \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                        4. lower-neg.f64N/A

                                          \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                        5. lower-/.f64N/A

                                          \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                        6. lower-sqrt.f64N/A

                                          \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                        7. lower-sqrt.f64N/A

                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                        8. *-commutativeN/A

                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                        9. lower-*.f64N/A

                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                        10. +-commutativeN/A

                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                        11. lower-+.f64N/A

                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                        12. +-commutativeN/A

                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                                        13. unpow2N/A

                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                                        14. unpow2N/A

                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                                        15. lower-hypot.f6419.7

                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                                      5. Applied rewrites19.7%

                                        \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                                      6. Step-by-step derivation
                                        1. Applied rewrites33.5%

                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                                        2. Step-by-step derivation
                                          1. Applied rewrites33.6%

                                            \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                                        3. Recombined 3 regimes into one program.
                                        4. Final simplification25.5%

                                          \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(\left(F \cdot \left({B}^{2} - C \cdot \left(A \cdot 4\right)\right)\right) \cdot 2\right)}}{C \cdot \left(A \cdot 4\right) - {B}^{2}} \leq -5 \cdot 10^{-195}:\\ \;\;\;\;\frac{\sqrt{F}}{-B} \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2}\\ \mathbf{elif}\;\frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(\left(F \cdot \left({B}^{2} - C \cdot \left(A \cdot 4\right)\right)\right) \cdot 2\right)}}{C \cdot \left(A \cdot 4\right) - {B}^{2}} \leq \infty:\\ \;\;\;\;\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 0 - \sqrt{\left(\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right) + C\right) \cdot \left(\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)} \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2}}{B} \cdot \left(-\sqrt{F}\right)\\ \end{array} \]
                                        5. Add Preprocessing

                                        Alternative 9: 42.0% accurate, 3.2× speedup?

                                        \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{hypot}\left(C, B\_m\right) + C\\ \mathbf{if}\;F \leq 2 \cdot 10^{-14}:\\ \;\;\;\;\frac{\sqrt{\left(t\_0 \cdot F\right) \cdot 2}}{-B\_m}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{F}}{-B\_m} \cdot \sqrt{t\_0 \cdot 2}\\ \end{array} \end{array} \]
                                        B_m = (fabs.f64 B)
                                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                        (FPCore (A B_m C F)
                                         :precision binary64
                                         (let* ((t_0 (+ (hypot C B_m) C)))
                                           (if (<= F 2e-14)
                                             (/ (sqrt (* (* t_0 F) 2.0)) (- B_m))
                                             (* (/ (sqrt F) (- B_m)) (sqrt (* t_0 2.0))))))
                                        B_m = fabs(B);
                                        assert(A < B_m && B_m < C && C < F);
                                        double code(double A, double B_m, double C, double F) {
                                        	double t_0 = hypot(C, B_m) + C;
                                        	double tmp;
                                        	if (F <= 2e-14) {
                                        		tmp = sqrt(((t_0 * F) * 2.0)) / -B_m;
                                        	} else {
                                        		tmp = (sqrt(F) / -B_m) * sqrt((t_0 * 2.0));
                                        	}
                                        	return tmp;
                                        }
                                        
                                        B_m = Math.abs(B);
                                        assert A < B_m && B_m < C && C < F;
                                        public static double code(double A, double B_m, double C, double F) {
                                        	double t_0 = Math.hypot(C, B_m) + C;
                                        	double tmp;
                                        	if (F <= 2e-14) {
                                        		tmp = Math.sqrt(((t_0 * F) * 2.0)) / -B_m;
                                        	} else {
                                        		tmp = (Math.sqrt(F) / -B_m) * Math.sqrt((t_0 * 2.0));
                                        	}
                                        	return tmp;
                                        }
                                        
                                        B_m = math.fabs(B)
                                        [A, B_m, C, F] = sort([A, B_m, C, F])
                                        def code(A, B_m, C, F):
                                        	t_0 = math.hypot(C, B_m) + C
                                        	tmp = 0
                                        	if F <= 2e-14:
                                        		tmp = math.sqrt(((t_0 * F) * 2.0)) / -B_m
                                        	else:
                                        		tmp = (math.sqrt(F) / -B_m) * math.sqrt((t_0 * 2.0))
                                        	return tmp
                                        
                                        B_m = abs(B)
                                        A, B_m, C, F = sort([A, B_m, C, F])
                                        function code(A, B_m, C, F)
                                        	t_0 = Float64(hypot(C, B_m) + C)
                                        	tmp = 0.0
                                        	if (F <= 2e-14)
                                        		tmp = Float64(sqrt(Float64(Float64(t_0 * F) * 2.0)) / Float64(-B_m));
                                        	else
                                        		tmp = Float64(Float64(sqrt(F) / Float64(-B_m)) * sqrt(Float64(t_0 * 2.0)));
                                        	end
                                        	return tmp
                                        end
                                        
                                        B_m = abs(B);
                                        A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                        function tmp_2 = code(A, B_m, C, F)
                                        	t_0 = hypot(C, B_m) + C;
                                        	tmp = 0.0;
                                        	if (F <= 2e-14)
                                        		tmp = sqrt(((t_0 * F) * 2.0)) / -B_m;
                                        	else
                                        		tmp = (sqrt(F) / -B_m) * sqrt((t_0 * 2.0));
                                        	end
                                        	tmp_2 = tmp;
                                        end
                                        
                                        B_m = N[Abs[B], $MachinePrecision]
                                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                        code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision]}, If[LessEqual[F, 2e-14], N[(N[Sqrt[N[(N[(t$95$0 * F), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision], N[(N[(N[Sqrt[F], $MachinePrecision] / (-B$95$m)), $MachinePrecision] * N[Sqrt[N[(t$95$0 * 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]
                                        
                                        \begin{array}{l}
                                        B_m = \left|B\right|
                                        \\
                                        [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                        \\
                                        \begin{array}{l}
                                        t_0 := \mathsf{hypot}\left(C, B\_m\right) + C\\
                                        \mathbf{if}\;F \leq 2 \cdot 10^{-14}:\\
                                        \;\;\;\;\frac{\sqrt{\left(t\_0 \cdot F\right) \cdot 2}}{-B\_m}\\
                                        
                                        \mathbf{else}:\\
                                        \;\;\;\;\frac{\sqrt{F}}{-B\_m} \cdot \sqrt{t\_0 \cdot 2}\\
                                        
                                        
                                        \end{array}
                                        \end{array}
                                        
                                        Derivation
                                        1. Split input into 2 regimes
                                        2. if F < 2e-14

                                          1. Initial program 32.8%

                                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                          2. Add Preprocessing
                                          3. Taylor expanded in A around 0

                                            \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                          4. Step-by-step derivation
                                            1. associate-*r*N/A

                                              \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                            2. lower-*.f64N/A

                                              \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                            3. mul-1-negN/A

                                              \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                            4. lower-neg.f64N/A

                                              \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                            5. lower-/.f64N/A

                                              \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                            6. lower-sqrt.f64N/A

                                              \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                            7. lower-sqrt.f64N/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                            8. *-commutativeN/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                            9. lower-*.f64N/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                            10. +-commutativeN/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                            11. lower-+.f64N/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                            12. +-commutativeN/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                                            13. unpow2N/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                                            14. unpow2N/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                                            15. lower-hypot.f6420.9

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                                          5. Applied rewrites20.9%

                                            \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                                          6. Step-by-step derivation
                                            1. Applied rewrites20.9%

                                              \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]

                                            if 2e-14 < F

                                            1. Initial program 9.7%

                                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            2. Add Preprocessing
                                            3. Taylor expanded in A around 0

                                              \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                            4. Step-by-step derivation
                                              1. associate-*r*N/A

                                                \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                              2. lower-*.f64N/A

                                                \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                              3. mul-1-negN/A

                                                \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                              4. lower-neg.f64N/A

                                                \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                              5. lower-/.f64N/A

                                                \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                              6. lower-sqrt.f64N/A

                                                \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                              7. lower-sqrt.f64N/A

                                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                              8. *-commutativeN/A

                                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                              9. lower-*.f64N/A

                                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                              10. +-commutativeN/A

                                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                              11. lower-+.f64N/A

                                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                              12. +-commutativeN/A

                                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                                              13. unpow2N/A

                                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                                              14. unpow2N/A

                                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                                              15. lower-hypot.f6411.3

                                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                                            5. Applied rewrites11.3%

                                              \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                                            6. Step-by-step derivation
                                              1. Applied rewrites21.9%

                                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                                              2. Step-by-step derivation
                                                1. Applied rewrites22.1%

                                                  \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                                                2. Step-by-step derivation
                                                  1. Applied rewrites21.8%

                                                    \[\leadsto \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2} \cdot \color{blue}{\frac{\sqrt{F}}{-B}} \]
                                                3. Recombined 2 regimes into one program.
                                                4. Final simplification21.3%

                                                  \[\leadsto \begin{array}{l} \mathbf{if}\;F \leq 2 \cdot 10^{-14}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{-B}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{F}}{-B} \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2}\\ \end{array} \]
                                                5. Add Preprocessing

                                                Alternative 10: 42.5% accurate, 3.3× speedup?

                                                \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right) \end{array} \]
                                                B_m = (fabs.f64 B)
                                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                (FPCore (A B_m C F)
                                                 :precision binary64
                                                 (* (/ (sqrt (* (+ (hypot C B_m) C) 2.0)) B_m) (- (sqrt F))))
                                                B_m = fabs(B);
                                                assert(A < B_m && B_m < C && C < F);
                                                double code(double A, double B_m, double C, double F) {
                                                	return (sqrt(((hypot(C, B_m) + C) * 2.0)) / B_m) * -sqrt(F);
                                                }
                                                
                                                B_m = Math.abs(B);
                                                assert A < B_m && B_m < C && C < F;
                                                public static double code(double A, double B_m, double C, double F) {
                                                	return (Math.sqrt(((Math.hypot(C, B_m) + C) * 2.0)) / B_m) * -Math.sqrt(F);
                                                }
                                                
                                                B_m = math.fabs(B)
                                                [A, B_m, C, F] = sort([A, B_m, C, F])
                                                def code(A, B_m, C, F):
                                                	return (math.sqrt(((math.hypot(C, B_m) + C) * 2.0)) / B_m) * -math.sqrt(F)
                                                
                                                B_m = abs(B)
                                                A, B_m, C, F = sort([A, B_m, C, F])
                                                function code(A, B_m, C, F)
                                                	return Float64(Float64(sqrt(Float64(Float64(hypot(C, B_m) + C) * 2.0)) / B_m) * Float64(-sqrt(F)))
                                                end
                                                
                                                B_m = abs(B);
                                                A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                function tmp = code(A, B_m, C, F)
                                                	tmp = (sqrt(((hypot(C, B_m) + C) * 2.0)) / B_m) * -sqrt(F);
                                                end
                                                
                                                B_m = N[Abs[B], $MachinePrecision]
                                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                code[A_, B$95$m_, C_, F_] := N[(N[(N[Sqrt[N[(N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / B$95$m), $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]
                                                
                                                \begin{array}{l}
                                                B_m = \left|B\right|
                                                \\
                                                [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                \\
                                                \frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)
                                                \end{array}
                                                
                                                Derivation
                                                1. Initial program 22.8%

                                                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                2. Add Preprocessing
                                                3. Taylor expanded in A around 0

                                                  \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                4. Step-by-step derivation
                                                  1. associate-*r*N/A

                                                    \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                  2. lower-*.f64N/A

                                                    \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                  3. mul-1-negN/A

                                                    \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                  4. lower-neg.f64N/A

                                                    \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                  5. lower-/.f64N/A

                                                    \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                  6. lower-sqrt.f64N/A

                                                    \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                  7. lower-sqrt.f64N/A

                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                  8. *-commutativeN/A

                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                  9. lower-*.f64N/A

                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                  10. +-commutativeN/A

                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                  11. lower-+.f64N/A

                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                  12. +-commutativeN/A

                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                                                  13. unpow2N/A

                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                                                  14. unpow2N/A

                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                                                  15. lower-hypot.f6416.7

                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                                                5. Applied rewrites16.7%

                                                  \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                                                6. Step-by-step derivation
                                                  1. Applied rewrites22.3%

                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                                                  2. Step-by-step derivation
                                                    1. Applied rewrites22.4%

                                                      \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                                                    2. Final simplification22.4%

                                                      \[\leadsto \frac{\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2}}{B} \cdot \left(-\sqrt{F}\right) \]
                                                    3. Add Preprocessing

                                                    Alternative 11: 38.7% accurate, 3.4× speedup?

                                                    \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;F \leq 0.00022:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot F\right) \cdot 2}}{-B\_m}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(C + B\_m\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\ \end{array} \end{array} \]
                                                    B_m = (fabs.f64 B)
                                                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                    (FPCore (A B_m C F)
                                                     :precision binary64
                                                     (if (<= F 0.00022)
                                                       (/ (sqrt (* (* (+ (hypot C B_m) C) F) 2.0)) (- B_m))
                                                       (* (/ (sqrt (* (+ C B_m) 2.0)) B_m) (- (sqrt F)))))
                                                    B_m = fabs(B);
                                                    assert(A < B_m && B_m < C && C < F);
                                                    double code(double A, double B_m, double C, double F) {
                                                    	double tmp;
                                                    	if (F <= 0.00022) {
                                                    		tmp = sqrt((((hypot(C, B_m) + C) * F) * 2.0)) / -B_m;
                                                    	} else {
                                                    		tmp = (sqrt(((C + B_m) * 2.0)) / B_m) * -sqrt(F);
                                                    	}
                                                    	return tmp;
                                                    }
                                                    
                                                    B_m = Math.abs(B);
                                                    assert A < B_m && B_m < C && C < F;
                                                    public static double code(double A, double B_m, double C, double F) {
                                                    	double tmp;
                                                    	if (F <= 0.00022) {
                                                    		tmp = Math.sqrt((((Math.hypot(C, B_m) + C) * F) * 2.0)) / -B_m;
                                                    	} else {
                                                    		tmp = (Math.sqrt(((C + B_m) * 2.0)) / B_m) * -Math.sqrt(F);
                                                    	}
                                                    	return tmp;
                                                    }
                                                    
                                                    B_m = math.fabs(B)
                                                    [A, B_m, C, F] = sort([A, B_m, C, F])
                                                    def code(A, B_m, C, F):
                                                    	tmp = 0
                                                    	if F <= 0.00022:
                                                    		tmp = math.sqrt((((math.hypot(C, B_m) + C) * F) * 2.0)) / -B_m
                                                    	else:
                                                    		tmp = (math.sqrt(((C + B_m) * 2.0)) / B_m) * -math.sqrt(F)
                                                    	return tmp
                                                    
                                                    B_m = abs(B)
                                                    A, B_m, C, F = sort([A, B_m, C, F])
                                                    function code(A, B_m, C, F)
                                                    	tmp = 0.0
                                                    	if (F <= 0.00022)
                                                    		tmp = Float64(sqrt(Float64(Float64(Float64(hypot(C, B_m) + C) * F) * 2.0)) / Float64(-B_m));
                                                    	else
                                                    		tmp = Float64(Float64(sqrt(Float64(Float64(C + B_m) * 2.0)) / B_m) * Float64(-sqrt(F)));
                                                    	end
                                                    	return tmp
                                                    end
                                                    
                                                    B_m = abs(B);
                                                    A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                    function tmp_2 = code(A, B_m, C, F)
                                                    	tmp = 0.0;
                                                    	if (F <= 0.00022)
                                                    		tmp = sqrt((((hypot(C, B_m) + C) * F) * 2.0)) / -B_m;
                                                    	else
                                                    		tmp = (sqrt(((C + B_m) * 2.0)) / B_m) * -sqrt(F);
                                                    	end
                                                    	tmp_2 = tmp;
                                                    end
                                                    
                                                    B_m = N[Abs[B], $MachinePrecision]
                                                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                    code[A_, B$95$m_, C_, F_] := If[LessEqual[F, 0.00022], N[(N[Sqrt[N[(N[(N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] * F), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision], N[(N[(N[Sqrt[N[(N[(C + B$95$m), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / B$95$m), $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]]
                                                    
                                                    \begin{array}{l}
                                                    B_m = \left|B\right|
                                                    \\
                                                    [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                    \\
                                                    \begin{array}{l}
                                                    \mathbf{if}\;F \leq 0.00022:\\
                                                    \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot F\right) \cdot 2}}{-B\_m}\\
                                                    
                                                    \mathbf{else}:\\
                                                    \;\;\;\;\frac{\sqrt{\left(C + B\_m\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\
                                                    
                                                    
                                                    \end{array}
                                                    \end{array}
                                                    
                                                    Derivation
                                                    1. Split input into 2 regimes
                                                    2. if F < 2.20000000000000008e-4

                                                      1. Initial program 31.8%

                                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      2. Add Preprocessing
                                                      3. Taylor expanded in A around 0

                                                        \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                      4. Step-by-step derivation
                                                        1. associate-*r*N/A

                                                          \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                        2. lower-*.f64N/A

                                                          \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                        3. mul-1-negN/A

                                                          \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                        4. lower-neg.f64N/A

                                                          \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                        5. lower-/.f64N/A

                                                          \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                        6. lower-sqrt.f64N/A

                                                          \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                        7. lower-sqrt.f64N/A

                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                        8. *-commutativeN/A

                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                        9. lower-*.f64N/A

                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                        10. +-commutativeN/A

                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                        11. lower-+.f64N/A

                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                        12. +-commutativeN/A

                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                                                        13. unpow2N/A

                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                                                        14. unpow2N/A

                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                                                        15. lower-hypot.f6420.6

                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                                                      5. Applied rewrites20.6%

                                                        \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                                                      6. Step-by-step derivation
                                                        1. Applied rewrites20.7%

                                                          \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]

                                                        if 2.20000000000000008e-4 < F

                                                        1. Initial program 10.1%

                                                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                        2. Add Preprocessing
                                                        3. Taylor expanded in A around 0

                                                          \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                        4. Step-by-step derivation
                                                          1. associate-*r*N/A

                                                            \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                          2. lower-*.f64N/A

                                                            \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                          3. mul-1-negN/A

                                                            \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                          4. lower-neg.f64N/A

                                                            \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                          5. lower-/.f64N/A

                                                            \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                          6. lower-sqrt.f64N/A

                                                            \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                          7. lower-sqrt.f64N/A

                                                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                          8. *-commutativeN/A

                                                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                          9. lower-*.f64N/A

                                                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                          10. +-commutativeN/A

                                                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                          11. lower-+.f64N/A

                                                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                          12. +-commutativeN/A

                                                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                                                          13. unpow2N/A

                                                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                                                          14. unpow2N/A

                                                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                                                          15. lower-hypot.f6411.2

                                                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                                                        5. Applied rewrites11.2%

                                                          \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                                                        6. Step-by-step derivation
                                                          1. Applied rewrites22.3%

                                                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                                                          2. Step-by-step derivation
                                                            1. Applied rewrites22.5%

                                                              \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                                                            2. Taylor expanded in C around 0

                                                              \[\leadsto \frac{\sqrt{2 \cdot \left(B + C\right)}}{-B} \cdot \sqrt{F} \]
                                                            3. Step-by-step derivation
                                                              1. Applied rewrites19.6%

                                                                \[\leadsto \frac{\sqrt{2 \cdot \left(C + B\right)}}{-B} \cdot \sqrt{F} \]
                                                            4. Recombined 2 regimes into one program.
                                                            5. Final simplification20.2%

                                                              \[\leadsto \begin{array}{l} \mathbf{if}\;F \leq 0.00022:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{-B}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(C + B\right) \cdot 2}}{B} \cdot \left(-\sqrt{F}\right)\\ \end{array} \]
                                                            6. Add Preprocessing

                                                            Alternative 12: 37.0% accurate, 9.8× speedup?

                                                            \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;C \leq 1.46 \cdot 10^{+212}:\\ \;\;\;\;\frac{\sqrt{F \cdot 2}}{-\sqrt{B\_m}}\\ \mathbf{else}:\\ \;\;\;\;\left(\frac{2}{-B\_m} \cdot \sqrt{C}\right) \cdot \sqrt{F}\\ \end{array} \end{array} \]
                                                            B_m = (fabs.f64 B)
                                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                            (FPCore (A B_m C F)
                                                             :precision binary64
                                                             (if (<= C 1.46e+212)
                                                               (/ (sqrt (* F 2.0)) (- (sqrt B_m)))
                                                               (* (* (/ 2.0 (- B_m)) (sqrt C)) (sqrt F))))
                                                            B_m = fabs(B);
                                                            assert(A < B_m && B_m < C && C < F);
                                                            double code(double A, double B_m, double C, double F) {
                                                            	double tmp;
                                                            	if (C <= 1.46e+212) {
                                                            		tmp = sqrt((F * 2.0)) / -sqrt(B_m);
                                                            	} else {
                                                            		tmp = ((2.0 / -B_m) * sqrt(C)) * sqrt(F);
                                                            	}
                                                            	return tmp;
                                                            }
                                                            
                                                            B_m = abs(b)
                                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                            real(8) function code(a, b_m, c, f)
                                                                real(8), intent (in) :: a
                                                                real(8), intent (in) :: b_m
                                                                real(8), intent (in) :: c
                                                                real(8), intent (in) :: f
                                                                real(8) :: tmp
                                                                if (c <= 1.46d+212) then
                                                                    tmp = sqrt((f * 2.0d0)) / -sqrt(b_m)
                                                                else
                                                                    tmp = ((2.0d0 / -b_m) * sqrt(c)) * sqrt(f)
                                                                end if
                                                                code = tmp
                                                            end function
                                                            
                                                            B_m = Math.abs(B);
                                                            assert A < B_m && B_m < C && C < F;
                                                            public static double code(double A, double B_m, double C, double F) {
                                                            	double tmp;
                                                            	if (C <= 1.46e+212) {
                                                            		tmp = Math.sqrt((F * 2.0)) / -Math.sqrt(B_m);
                                                            	} else {
                                                            		tmp = ((2.0 / -B_m) * Math.sqrt(C)) * Math.sqrt(F);
                                                            	}
                                                            	return tmp;
                                                            }
                                                            
                                                            B_m = math.fabs(B)
                                                            [A, B_m, C, F] = sort([A, B_m, C, F])
                                                            def code(A, B_m, C, F):
                                                            	tmp = 0
                                                            	if C <= 1.46e+212:
                                                            		tmp = math.sqrt((F * 2.0)) / -math.sqrt(B_m)
                                                            	else:
                                                            		tmp = ((2.0 / -B_m) * math.sqrt(C)) * math.sqrt(F)
                                                            	return tmp
                                                            
                                                            B_m = abs(B)
                                                            A, B_m, C, F = sort([A, B_m, C, F])
                                                            function code(A, B_m, C, F)
                                                            	tmp = 0.0
                                                            	if (C <= 1.46e+212)
                                                            		tmp = Float64(sqrt(Float64(F * 2.0)) / Float64(-sqrt(B_m)));
                                                            	else
                                                            		tmp = Float64(Float64(Float64(2.0 / Float64(-B_m)) * sqrt(C)) * sqrt(F));
                                                            	end
                                                            	return tmp
                                                            end
                                                            
                                                            B_m = abs(B);
                                                            A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                            function tmp_2 = code(A, B_m, C, F)
                                                            	tmp = 0.0;
                                                            	if (C <= 1.46e+212)
                                                            		tmp = sqrt((F * 2.0)) / -sqrt(B_m);
                                                            	else
                                                            		tmp = ((2.0 / -B_m) * sqrt(C)) * sqrt(F);
                                                            	end
                                                            	tmp_2 = tmp;
                                                            end
                                                            
                                                            B_m = N[Abs[B], $MachinePrecision]
                                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                            code[A_, B$95$m_, C_, F_] := If[LessEqual[C, 1.46e+212], N[(N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision] / (-N[Sqrt[B$95$m], $MachinePrecision])), $MachinePrecision], N[(N[(N[(2.0 / (-B$95$m)), $MachinePrecision] * N[Sqrt[C], $MachinePrecision]), $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision]]
                                                            
                                                            \begin{array}{l}
                                                            B_m = \left|B\right|
                                                            \\
                                                            [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                            \\
                                                            \begin{array}{l}
                                                            \mathbf{if}\;C \leq 1.46 \cdot 10^{+212}:\\
                                                            \;\;\;\;\frac{\sqrt{F \cdot 2}}{-\sqrt{B\_m}}\\
                                                            
                                                            \mathbf{else}:\\
                                                            \;\;\;\;\left(\frac{2}{-B\_m} \cdot \sqrt{C}\right) \cdot \sqrt{F}\\
                                                            
                                                            
                                                            \end{array}
                                                            \end{array}
                                                            
                                                            Derivation
                                                            1. Split input into 2 regimes
                                                            2. if C < 1.46e212

                                                              1. Initial program 25.0%

                                                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                              2. Add Preprocessing
                                                              3. Taylor expanded in B around inf

                                                                \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                              4. Step-by-step derivation
                                                                1. mul-1-negN/A

                                                                  \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                2. *-commutativeN/A

                                                                  \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                3. distribute-lft-neg-inN/A

                                                                  \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                4. lower-*.f64N/A

                                                                  \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                5. lower-neg.f64N/A

                                                                  \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
                                                                6. lower-sqrt.f64N/A

                                                                  \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
                                                                7. lower-sqrt.f64N/A

                                                                  \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
                                                                8. lower-/.f6414.9

                                                                  \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                              5. Applied rewrites14.9%

                                                                \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                              6. Step-by-step derivation
                                                                1. Applied rewrites15.0%

                                                                  \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                2. Step-by-step derivation
                                                                  1. Applied rewrites20.5%

                                                                    \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]

                                                                  if 1.46e212 < C

                                                                  1. Initial program 1.6%

                                                                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                  2. Add Preprocessing
                                                                  3. Taylor expanded in A around 0

                                                                    \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                  4. Step-by-step derivation
                                                                    1. associate-*r*N/A

                                                                      \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                    2. lower-*.f64N/A

                                                                      \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                    3. mul-1-negN/A

                                                                      \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                    4. lower-neg.f64N/A

                                                                      \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                    5. lower-/.f64N/A

                                                                      \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                    6. lower-sqrt.f64N/A

                                                                      \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                    7. lower-sqrt.f64N/A

                                                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                    8. *-commutativeN/A

                                                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                                    9. lower-*.f64N/A

                                                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                                    10. +-commutativeN/A

                                                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                                    11. lower-+.f64N/A

                                                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                                    12. +-commutativeN/A

                                                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                                                                    13. unpow2N/A

                                                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                                                                    14. unpow2N/A

                                                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                                                                    15. lower-hypot.f6413.2

                                                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                                                                  5. Applied rewrites13.2%

                                                                    \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                                                                  6. Step-by-step derivation
                                                                    1. Applied rewrites21.4%

                                                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                                                                    2. Step-by-step derivation
                                                                      1. Applied rewrites21.4%

                                                                        \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                                                                      2. Taylor expanded in B around 0

                                                                        \[\leadsto \left(-1 \cdot \left(\frac{{\left(\sqrt{2}\right)}^{2}}{B} \cdot \sqrt{C}\right)\right) \cdot \sqrt{\color{blue}{F}} \]
                                                                      3. Step-by-step derivation
                                                                        1. Applied rewrites13.8%

                                                                          \[\leadsto \left(-\frac{2}{B} \cdot \sqrt{C}\right) \cdot \sqrt{\color{blue}{F}} \]
                                                                      4. Recombined 2 regimes into one program.
                                                                      5. Final simplification19.9%

                                                                        \[\leadsto \begin{array}{l} \mathbf{if}\;C \leq 1.46 \cdot 10^{+212}:\\ \;\;\;\;\frac{\sqrt{F \cdot 2}}{-\sqrt{B}}\\ \mathbf{else}:\\ \;\;\;\;\left(\frac{2}{-B} \cdot \sqrt{C}\right) \cdot \sqrt{F}\\ \end{array} \]
                                                                      6. Add Preprocessing

                                                                      Alternative 13: 35.9% accurate, 10.4× speedup?

                                                                      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \frac{\sqrt{\left(C + B\_m\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right) \end{array} \]
                                                                      B_m = (fabs.f64 B)
                                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                      (FPCore (A B_m C F)
                                                                       :precision binary64
                                                                       (* (/ (sqrt (* (+ C B_m) 2.0)) B_m) (- (sqrt F))))
                                                                      B_m = fabs(B);
                                                                      assert(A < B_m && B_m < C && C < F);
                                                                      double code(double A, double B_m, double C, double F) {
                                                                      	return (sqrt(((C + B_m) * 2.0)) / B_m) * -sqrt(F);
                                                                      }
                                                                      
                                                                      B_m = abs(b)
                                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                      real(8) function code(a, b_m, c, f)
                                                                          real(8), intent (in) :: a
                                                                          real(8), intent (in) :: b_m
                                                                          real(8), intent (in) :: c
                                                                          real(8), intent (in) :: f
                                                                          code = (sqrt(((c + b_m) * 2.0d0)) / b_m) * -sqrt(f)
                                                                      end function
                                                                      
                                                                      B_m = Math.abs(B);
                                                                      assert A < B_m && B_m < C && C < F;
                                                                      public static double code(double A, double B_m, double C, double F) {
                                                                      	return (Math.sqrt(((C + B_m) * 2.0)) / B_m) * -Math.sqrt(F);
                                                                      }
                                                                      
                                                                      B_m = math.fabs(B)
                                                                      [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                      def code(A, B_m, C, F):
                                                                      	return (math.sqrt(((C + B_m) * 2.0)) / B_m) * -math.sqrt(F)
                                                                      
                                                                      B_m = abs(B)
                                                                      A, B_m, C, F = sort([A, B_m, C, F])
                                                                      function code(A, B_m, C, F)
                                                                      	return Float64(Float64(sqrt(Float64(Float64(C + B_m) * 2.0)) / B_m) * Float64(-sqrt(F)))
                                                                      end
                                                                      
                                                                      B_m = abs(B);
                                                                      A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                      function tmp = code(A, B_m, C, F)
                                                                      	tmp = (sqrt(((C + B_m) * 2.0)) / B_m) * -sqrt(F);
                                                                      end
                                                                      
                                                                      B_m = N[Abs[B], $MachinePrecision]
                                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                      code[A_, B$95$m_, C_, F_] := N[(N[(N[Sqrt[N[(N[(C + B$95$m), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / B$95$m), $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]
                                                                      
                                                                      \begin{array}{l}
                                                                      B_m = \left|B\right|
                                                                      \\
                                                                      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                      \\
                                                                      \frac{\sqrt{\left(C + B\_m\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)
                                                                      \end{array}
                                                                      
                                                                      Derivation
                                                                      1. Initial program 22.8%

                                                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                      2. Add Preprocessing
                                                                      3. Taylor expanded in A around 0

                                                                        \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                      4. Step-by-step derivation
                                                                        1. associate-*r*N/A

                                                                          \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                        2. lower-*.f64N/A

                                                                          \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                        3. mul-1-negN/A

                                                                          \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                        4. lower-neg.f64N/A

                                                                          \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                        5. lower-/.f64N/A

                                                                          \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                        6. lower-sqrt.f64N/A

                                                                          \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                        7. lower-sqrt.f64N/A

                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                        8. *-commutativeN/A

                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                                        9. lower-*.f64N/A

                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                                        10. +-commutativeN/A

                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                                        11. lower-+.f64N/A

                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                                        12. +-commutativeN/A

                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                                                                        13. unpow2N/A

                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                                                                        14. unpow2N/A

                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                                                                        15. lower-hypot.f6416.7

                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                                                                      5. Applied rewrites16.7%

                                                                        \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                                                                      6. Step-by-step derivation
                                                                        1. Applied rewrites22.3%

                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                                                                        2. Step-by-step derivation
                                                                          1. Applied rewrites22.4%

                                                                            \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                                                                          2. Taylor expanded in C around 0

                                                                            \[\leadsto \frac{\sqrt{2 \cdot \left(B + C\right)}}{-B} \cdot \sqrt{F} \]
                                                                          3. Step-by-step derivation
                                                                            1. Applied rewrites19.4%

                                                                              \[\leadsto \frac{\sqrt{2 \cdot \left(C + B\right)}}{-B} \cdot \sqrt{F} \]
                                                                            2. Final simplification19.4%

                                                                              \[\leadsto \frac{\sqrt{\left(C + B\right) \cdot 2}}{B} \cdot \left(-\sqrt{F}\right) \]
                                                                            3. Add Preprocessing

                                                                            Alternative 14: 35.3% accurate, 12.6× speedup?

                                                                            \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \frac{\sqrt{F \cdot 2}}{-\sqrt{B\_m}} \end{array} \]
                                                                            B_m = (fabs.f64 B)
                                                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                            (FPCore (A B_m C F) :precision binary64 (/ (sqrt (* F 2.0)) (- (sqrt B_m))))
                                                                            B_m = fabs(B);
                                                                            assert(A < B_m && B_m < C && C < F);
                                                                            double code(double A, double B_m, double C, double F) {
                                                                            	return sqrt((F * 2.0)) / -sqrt(B_m);
                                                                            }
                                                                            
                                                                            B_m = abs(b)
                                                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                            real(8) function code(a, b_m, c, f)
                                                                                real(8), intent (in) :: a
                                                                                real(8), intent (in) :: b_m
                                                                                real(8), intent (in) :: c
                                                                                real(8), intent (in) :: f
                                                                                code = sqrt((f * 2.0d0)) / -sqrt(b_m)
                                                                            end function
                                                                            
                                                                            B_m = Math.abs(B);
                                                                            assert A < B_m && B_m < C && C < F;
                                                                            public static double code(double A, double B_m, double C, double F) {
                                                                            	return Math.sqrt((F * 2.0)) / -Math.sqrt(B_m);
                                                                            }
                                                                            
                                                                            B_m = math.fabs(B)
                                                                            [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                            def code(A, B_m, C, F):
                                                                            	return math.sqrt((F * 2.0)) / -math.sqrt(B_m)
                                                                            
                                                                            B_m = abs(B)
                                                                            A, B_m, C, F = sort([A, B_m, C, F])
                                                                            function code(A, B_m, C, F)
                                                                            	return Float64(sqrt(Float64(F * 2.0)) / Float64(-sqrt(B_m)))
                                                                            end
                                                                            
                                                                            B_m = abs(B);
                                                                            A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                            function tmp = code(A, B_m, C, F)
                                                                            	tmp = sqrt((F * 2.0)) / -sqrt(B_m);
                                                                            end
                                                                            
                                                                            B_m = N[Abs[B], $MachinePrecision]
                                                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                            code[A_, B$95$m_, C_, F_] := N[(N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision] / (-N[Sqrt[B$95$m], $MachinePrecision])), $MachinePrecision]
                                                                            
                                                                            \begin{array}{l}
                                                                            B_m = \left|B\right|
                                                                            \\
                                                                            [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                            \\
                                                                            \frac{\sqrt{F \cdot 2}}{-\sqrt{B\_m}}
                                                                            \end{array}
                                                                            
                                                                            Derivation
                                                                            1. Initial program 22.8%

                                                                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                            2. Add Preprocessing
                                                                            3. Taylor expanded in B around inf

                                                                              \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                            4. Step-by-step derivation
                                                                              1. mul-1-negN/A

                                                                                \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                              2. *-commutativeN/A

                                                                                \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                              3. distribute-lft-neg-inN/A

                                                                                \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                              4. lower-*.f64N/A

                                                                                \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                              5. lower-neg.f64N/A

                                                                                \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
                                                                              6. lower-sqrt.f64N/A

                                                                                \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
                                                                              7. lower-sqrt.f64N/A

                                                                                \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
                                                                              8. lower-/.f6413.8

                                                                                \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                                            5. Applied rewrites13.8%

                                                                              \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                            6. Step-by-step derivation
                                                                              1. Applied rewrites13.8%

                                                                                \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                              2. Step-by-step derivation
                                                                                1. Applied rewrites19.5%

                                                                                  \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
                                                                                2. Final simplification19.5%

                                                                                  \[\leadsto \frac{\sqrt{F \cdot 2}}{-\sqrt{B}} \]
                                                                                3. Add Preprocessing

                                                                                Alternative 15: 35.3% accurate, 12.6× speedup?

                                                                                \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \frac{-\sqrt{F}}{\sqrt{0.5 \cdot B\_m}} \end{array} \]
                                                                                B_m = (fabs.f64 B)
                                                                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                (FPCore (A B_m C F) :precision binary64 (/ (- (sqrt F)) (sqrt (* 0.5 B_m))))
                                                                                B_m = fabs(B);
                                                                                assert(A < B_m && B_m < C && C < F);
                                                                                double code(double A, double B_m, double C, double F) {
                                                                                	return -sqrt(F) / sqrt((0.5 * B_m));
                                                                                }
                                                                                
                                                                                B_m = abs(b)
                                                                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                real(8) function code(a, b_m, c, f)
                                                                                    real(8), intent (in) :: a
                                                                                    real(8), intent (in) :: b_m
                                                                                    real(8), intent (in) :: c
                                                                                    real(8), intent (in) :: f
                                                                                    code = -sqrt(f) / sqrt((0.5d0 * b_m))
                                                                                end function
                                                                                
                                                                                B_m = Math.abs(B);
                                                                                assert A < B_m && B_m < C && C < F;
                                                                                public static double code(double A, double B_m, double C, double F) {
                                                                                	return -Math.sqrt(F) / Math.sqrt((0.5 * B_m));
                                                                                }
                                                                                
                                                                                B_m = math.fabs(B)
                                                                                [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                                def code(A, B_m, C, F):
                                                                                	return -math.sqrt(F) / math.sqrt((0.5 * B_m))
                                                                                
                                                                                B_m = abs(B)
                                                                                A, B_m, C, F = sort([A, B_m, C, F])
                                                                                function code(A, B_m, C, F)
                                                                                	return Float64(Float64(-sqrt(F)) / sqrt(Float64(0.5 * B_m)))
                                                                                end
                                                                                
                                                                                B_m = abs(B);
                                                                                A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                                function tmp = code(A, B_m, C, F)
                                                                                	tmp = -sqrt(F) / sqrt((0.5 * B_m));
                                                                                end
                                                                                
                                                                                B_m = N[Abs[B], $MachinePrecision]
                                                                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                code[A_, B$95$m_, C_, F_] := N[((-N[Sqrt[F], $MachinePrecision]) / N[Sqrt[N[(0.5 * B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
                                                                                
                                                                                \begin{array}{l}
                                                                                B_m = \left|B\right|
                                                                                \\
                                                                                [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                                \\
                                                                                \frac{-\sqrt{F}}{\sqrt{0.5 \cdot B\_m}}
                                                                                \end{array}
                                                                                
                                                                                Derivation
                                                                                1. Initial program 22.8%

                                                                                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                2. Add Preprocessing
                                                                                3. Taylor expanded in B around inf

                                                                                  \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                4. Step-by-step derivation
                                                                                  1. mul-1-negN/A

                                                                                    \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                  2. *-commutativeN/A

                                                                                    \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                                  3. distribute-lft-neg-inN/A

                                                                                    \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                                  4. lower-*.f64N/A

                                                                                    \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                                  5. lower-neg.f64N/A

                                                                                    \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
                                                                                  6. lower-sqrt.f64N/A

                                                                                    \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
                                                                                  7. lower-sqrt.f64N/A

                                                                                    \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
                                                                                  8. lower-/.f6413.8

                                                                                    \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                                                5. Applied rewrites13.8%

                                                                                  \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                                6. Step-by-step derivation
                                                                                  1. Applied rewrites13.8%

                                                                                    \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                                  2. Step-by-step derivation
                                                                                    1. Applied rewrites13.9%

                                                                                      \[\leadsto -\sqrt{F \cdot \frac{2}{B}} \]
                                                                                    2. Step-by-step derivation
                                                                                      1. Applied rewrites19.5%

                                                                                        \[\leadsto -\frac{\sqrt{F}}{\sqrt{B \cdot 0.5}} \]
                                                                                      2. Final simplification19.5%

                                                                                        \[\leadsto \frac{-\sqrt{F}}{\sqrt{0.5 \cdot B}} \]
                                                                                      3. Add Preprocessing

                                                                                      Alternative 16: 35.3% accurate, 12.6× speedup?

                                                                                      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}} \end{array} \]
                                                                                      B_m = (fabs.f64 B)
                                                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                      (FPCore (A B_m C F) :precision binary64 (* (- (sqrt F)) (sqrt (/ 2.0 B_m))))
                                                                                      B_m = fabs(B);
                                                                                      assert(A < B_m && B_m < C && C < F);
                                                                                      double code(double A, double B_m, double C, double F) {
                                                                                      	return -sqrt(F) * sqrt((2.0 / B_m));
                                                                                      }
                                                                                      
                                                                                      B_m = abs(b)
                                                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                      real(8) function code(a, b_m, c, f)
                                                                                          real(8), intent (in) :: a
                                                                                          real(8), intent (in) :: b_m
                                                                                          real(8), intent (in) :: c
                                                                                          real(8), intent (in) :: f
                                                                                          code = -sqrt(f) * sqrt((2.0d0 / b_m))
                                                                                      end function
                                                                                      
                                                                                      B_m = Math.abs(B);
                                                                                      assert A < B_m && B_m < C && C < F;
                                                                                      public static double code(double A, double B_m, double C, double F) {
                                                                                      	return -Math.sqrt(F) * Math.sqrt((2.0 / B_m));
                                                                                      }
                                                                                      
                                                                                      B_m = math.fabs(B)
                                                                                      [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                                      def code(A, B_m, C, F):
                                                                                      	return -math.sqrt(F) * math.sqrt((2.0 / B_m))
                                                                                      
                                                                                      B_m = abs(B)
                                                                                      A, B_m, C, F = sort([A, B_m, C, F])
                                                                                      function code(A, B_m, C, F)
                                                                                      	return Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)))
                                                                                      end
                                                                                      
                                                                                      B_m = abs(B);
                                                                                      A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                                      function tmp = code(A, B_m, C, F)
                                                                                      	tmp = -sqrt(F) * sqrt((2.0 / B_m));
                                                                                      end
                                                                                      
                                                                                      B_m = N[Abs[B], $MachinePrecision]
                                                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                      code[A_, B$95$m_, C_, F_] := N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
                                                                                      
                                                                                      \begin{array}{l}
                                                                                      B_m = \left|B\right|
                                                                                      \\
                                                                                      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                                      \\
                                                                                      \left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}
                                                                                      \end{array}
                                                                                      
                                                                                      Derivation
                                                                                      1. Initial program 22.8%

                                                                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                      2. Add Preprocessing
                                                                                      3. Taylor expanded in B around inf

                                                                                        \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                      4. Step-by-step derivation
                                                                                        1. mul-1-negN/A

                                                                                          \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                        2. *-commutativeN/A

                                                                                          \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                                        3. distribute-lft-neg-inN/A

                                                                                          \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                                        4. lower-*.f64N/A

                                                                                          \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                                        5. lower-neg.f64N/A

                                                                                          \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
                                                                                        6. lower-sqrt.f64N/A

                                                                                          \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
                                                                                        7. lower-sqrt.f64N/A

                                                                                          \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
                                                                                        8. lower-/.f6413.8

                                                                                          \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                                                      5. Applied rewrites13.8%

                                                                                        \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                                      6. Step-by-step derivation
                                                                                        1. Applied rewrites13.8%

                                                                                          \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                                        2. Step-by-step derivation
                                                                                          1. Applied rewrites19.6%

                                                                                            \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                                                                          2. Final simplification19.6%

                                                                                            \[\leadsto \left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}} \]
                                                                                          3. Add Preprocessing

                                                                                          Alternative 17: 27.3% accurate, 16.9× speedup?

                                                                                          \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ -\sqrt{\frac{F}{B\_m} \cdot 2} \end{array} \]
                                                                                          B_m = (fabs.f64 B)
                                                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                          (FPCore (A B_m C F) :precision binary64 (- (sqrt (* (/ F B_m) 2.0))))
                                                                                          B_m = fabs(B);
                                                                                          assert(A < B_m && B_m < C && C < F);
                                                                                          double code(double A, double B_m, double C, double F) {
                                                                                          	return -sqrt(((F / B_m) * 2.0));
                                                                                          }
                                                                                          
                                                                                          B_m = abs(b)
                                                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                          real(8) function code(a, b_m, c, f)
                                                                                              real(8), intent (in) :: a
                                                                                              real(8), intent (in) :: b_m
                                                                                              real(8), intent (in) :: c
                                                                                              real(8), intent (in) :: f
                                                                                              code = -sqrt(((f / b_m) * 2.0d0))
                                                                                          end function
                                                                                          
                                                                                          B_m = Math.abs(B);
                                                                                          assert A < B_m && B_m < C && C < F;
                                                                                          public static double code(double A, double B_m, double C, double F) {
                                                                                          	return -Math.sqrt(((F / B_m) * 2.0));
                                                                                          }
                                                                                          
                                                                                          B_m = math.fabs(B)
                                                                                          [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                                          def code(A, B_m, C, F):
                                                                                          	return -math.sqrt(((F / B_m) * 2.0))
                                                                                          
                                                                                          B_m = abs(B)
                                                                                          A, B_m, C, F = sort([A, B_m, C, F])
                                                                                          function code(A, B_m, C, F)
                                                                                          	return Float64(-sqrt(Float64(Float64(F / B_m) * 2.0)))
                                                                                          end
                                                                                          
                                                                                          B_m = abs(B);
                                                                                          A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                                          function tmp = code(A, B_m, C, F)
                                                                                          	tmp = -sqrt(((F / B_m) * 2.0));
                                                                                          end
                                                                                          
                                                                                          B_m = N[Abs[B], $MachinePrecision]
                                                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                          code[A_, B$95$m_, C_, F_] := (-N[Sqrt[N[(N[(F / B$95$m), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision])
                                                                                          
                                                                                          \begin{array}{l}
                                                                                          B_m = \left|B\right|
                                                                                          \\
                                                                                          [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                                          \\
                                                                                          -\sqrt{\frac{F}{B\_m} \cdot 2}
                                                                                          \end{array}
                                                                                          
                                                                                          Derivation
                                                                                          1. Initial program 22.8%

                                                                                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                          2. Add Preprocessing
                                                                                          3. Taylor expanded in B around inf

                                                                                            \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                          4. Step-by-step derivation
                                                                                            1. mul-1-negN/A

                                                                                              \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                            2. *-commutativeN/A

                                                                                              \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                                            3. distribute-lft-neg-inN/A

                                                                                              \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                                            4. lower-*.f64N/A

                                                                                              \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                                            5. lower-neg.f64N/A

                                                                                              \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
                                                                                            6. lower-sqrt.f64N/A

                                                                                              \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
                                                                                            7. lower-sqrt.f64N/A

                                                                                              \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
                                                                                            8. lower-/.f6413.8

                                                                                              \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                                                          5. Applied rewrites13.8%

                                                                                            \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                                          6. Step-by-step derivation
                                                                                            1. Applied rewrites13.8%

                                                                                              \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                                            2. Add Preprocessing

                                                                                            Alternative 18: 27.3% accurate, 16.9× speedup?

                                                                                            \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ -\sqrt{\frac{2}{B\_m} \cdot F} \end{array} \]
                                                                                            B_m = (fabs.f64 B)
                                                                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                            (FPCore (A B_m C F) :precision binary64 (- (sqrt (* (/ 2.0 B_m) F))))
                                                                                            B_m = fabs(B);
                                                                                            assert(A < B_m && B_m < C && C < F);
                                                                                            double code(double A, double B_m, double C, double F) {
                                                                                            	return -sqrt(((2.0 / B_m) * F));
                                                                                            }
                                                                                            
                                                                                            B_m = abs(b)
                                                                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                            real(8) function code(a, b_m, c, f)
                                                                                                real(8), intent (in) :: a
                                                                                                real(8), intent (in) :: b_m
                                                                                                real(8), intent (in) :: c
                                                                                                real(8), intent (in) :: f
                                                                                                code = -sqrt(((2.0d0 / b_m) * f))
                                                                                            end function
                                                                                            
                                                                                            B_m = Math.abs(B);
                                                                                            assert A < B_m && B_m < C && C < F;
                                                                                            public static double code(double A, double B_m, double C, double F) {
                                                                                            	return -Math.sqrt(((2.0 / B_m) * F));
                                                                                            }
                                                                                            
                                                                                            B_m = math.fabs(B)
                                                                                            [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                                            def code(A, B_m, C, F):
                                                                                            	return -math.sqrt(((2.0 / B_m) * F))
                                                                                            
                                                                                            B_m = abs(B)
                                                                                            A, B_m, C, F = sort([A, B_m, C, F])
                                                                                            function code(A, B_m, C, F)
                                                                                            	return Float64(-sqrt(Float64(Float64(2.0 / B_m) * F)))
                                                                                            end
                                                                                            
                                                                                            B_m = abs(B);
                                                                                            A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                                            function tmp = code(A, B_m, C, F)
                                                                                            	tmp = -sqrt(((2.0 / B_m) * F));
                                                                                            end
                                                                                            
                                                                                            B_m = N[Abs[B], $MachinePrecision]
                                                                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                            code[A_, B$95$m_, C_, F_] := (-N[Sqrt[N[(N[(2.0 / B$95$m), $MachinePrecision] * F), $MachinePrecision]], $MachinePrecision])
                                                                                            
                                                                                            \begin{array}{l}
                                                                                            B_m = \left|B\right|
                                                                                            \\
                                                                                            [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                                            \\
                                                                                            -\sqrt{\frac{2}{B\_m} \cdot F}
                                                                                            \end{array}
                                                                                            
                                                                                            Derivation
                                                                                            1. Initial program 22.8%

                                                                                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                            2. Add Preprocessing
                                                                                            3. Taylor expanded in B around inf

                                                                                              \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                            4. Step-by-step derivation
                                                                                              1. mul-1-negN/A

                                                                                                \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                              2. *-commutativeN/A

                                                                                                \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                                              3. distribute-lft-neg-inN/A

                                                                                                \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                                              4. lower-*.f64N/A

                                                                                                \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                                              5. lower-neg.f64N/A

                                                                                                \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
                                                                                              6. lower-sqrt.f64N/A

                                                                                                \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
                                                                                              7. lower-sqrt.f64N/A

                                                                                                \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
                                                                                              8. lower-/.f6413.8

                                                                                                \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                                                            5. Applied rewrites13.8%

                                                                                              \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                                            6. Step-by-step derivation
                                                                                              1. Applied rewrites13.8%

                                                                                                \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                                              2. Step-by-step derivation
                                                                                                1. Applied rewrites13.9%

                                                                                                  \[\leadsto -\sqrt{F \cdot \frac{2}{B}} \]
                                                                                                2. Final simplification13.9%

                                                                                                  \[\leadsto -\sqrt{\frac{2}{B} \cdot F} \]
                                                                                                3. Add Preprocessing

                                                                                                Reproduce

                                                                                                ?
                                                                                                herbie shell --seed 2024332 
                                                                                                (FPCore (A B C F)
                                                                                                  :name "ABCF->ab-angle a"
                                                                                                  :precision binary64
                                                                                                  (/ (- (sqrt (* (* 2.0 (* (- (pow B 2.0) (* (* 4.0 A) C)) F)) (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))) (- (pow B 2.0) (* (* 4.0 A) C))))