ABCF->ab-angle a

Percentage Accurate: 18.8% → 61.4%
Time: 14.2s
Alternatives: 15
Speedup: 16.9×

Specification

?
\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
real(8) function code(a, b, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) + sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 15 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 18.8% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
real(8) function code(a, b, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) + sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Alternative 1: 61.4% accurate, 0.3× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{hypot}\left(A - C, B\_m\right)\\ t_1 := C \cdot \left(A \cdot 4\right)\\ t_2 := t\_1 - {B\_m}^{2}\\ t_3 := \frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right) \cdot \left(\left(F \cdot \left({B\_m}^{2} - t\_1\right)\right) \cdot 2\right)}}{t\_2}\\ t_4 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;t\_3 \leq -5 \cdot 10^{-195}:\\ \;\;\;\;\frac{\left(\sqrt{F} \cdot \sqrt{\mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right) \cdot 2}\right) \cdot \sqrt{\left(C + A\right) + t\_0}}{t\_2}\\ \mathbf{elif}\;t\_3 \leq 0:\\ \;\;\;\;\frac{\sqrt{\left(\left(\frac{B\_m \cdot B\_m}{A} \cdot -0.5 + C\right) + C\right) \cdot F} \cdot \sqrt{t\_4 \cdot 2}}{t\_2}\\ \mathbf{elif}\;t\_3 \leq \infty:\\ \;\;\;\;\frac{\sqrt{\left(F \cdot 2\right) \cdot t\_4}}{t\_4} \cdot \frac{\sqrt{\left(t\_0 + A\right) + C}}{-1}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{-B\_m} \cdot \sqrt{F}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (let* ((t_0 (hypot (- A C) B_m))
        (t_1 (* C (* A 4.0)))
        (t_2 (- t_1 (pow B_m 2.0)))
        (t_3
         (/
          (sqrt
           (*
            (+ (+ C A) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))
            (* (* F (- (pow B_m 2.0) t_1)) 2.0)))
          t_2))
        (t_4 (fma -4.0 (* C A) (* B_m B_m))))
   (if (<= t_3 -5e-195)
     (/
      (*
       (* (sqrt F) (sqrt (* (fma (* C A) -4.0 (* B_m B_m)) 2.0)))
       (sqrt (+ (+ C A) t_0)))
      t_2)
     (if (<= t_3 0.0)
       (/
        (*
         (sqrt (* (+ (+ (* (/ (* B_m B_m) A) -0.5) C) C) F))
         (sqrt (* t_4 2.0)))
        t_2)
       (if (<= t_3 INFINITY)
         (* (/ (sqrt (* (* F 2.0) t_4)) t_4) (/ (sqrt (+ (+ t_0 A) C)) -1.0))
         (* (/ (sqrt (* (+ (hypot C B_m) C) 2.0)) (- B_m)) (sqrt F)))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double t_0 = hypot((A - C), B_m);
	double t_1 = C * (A * 4.0);
	double t_2 = t_1 - pow(B_m, 2.0);
	double t_3 = sqrt((((C + A) + sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))) * ((F * (pow(B_m, 2.0) - t_1)) * 2.0))) / t_2;
	double t_4 = fma(-4.0, (C * A), (B_m * B_m));
	double tmp;
	if (t_3 <= -5e-195) {
		tmp = ((sqrt(F) * sqrt((fma((C * A), -4.0, (B_m * B_m)) * 2.0))) * sqrt(((C + A) + t_0))) / t_2;
	} else if (t_3 <= 0.0) {
		tmp = (sqrt(((((((B_m * B_m) / A) * -0.5) + C) + C) * F)) * sqrt((t_4 * 2.0))) / t_2;
	} else if (t_3 <= ((double) INFINITY)) {
		tmp = (sqrt(((F * 2.0) * t_4)) / t_4) * (sqrt(((t_0 + A) + C)) / -1.0);
	} else {
		tmp = (sqrt(((hypot(C, B_m) + C) * 2.0)) / -B_m) * sqrt(F);
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	t_0 = hypot(Float64(A - C), B_m)
	t_1 = Float64(C * Float64(A * 4.0))
	t_2 = Float64(t_1 - (B_m ^ 2.0))
	t_3 = Float64(sqrt(Float64(Float64(Float64(C + A) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))) * Float64(Float64(F * Float64((B_m ^ 2.0) - t_1)) * 2.0))) / t_2)
	t_4 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
	tmp = 0.0
	if (t_3 <= -5e-195)
		tmp = Float64(Float64(Float64(sqrt(F) * sqrt(Float64(fma(Float64(C * A), -4.0, Float64(B_m * B_m)) * 2.0))) * sqrt(Float64(Float64(C + A) + t_0))) / t_2);
	elseif (t_3 <= 0.0)
		tmp = Float64(Float64(sqrt(Float64(Float64(Float64(Float64(Float64(Float64(B_m * B_m) / A) * -0.5) + C) + C) * F)) * sqrt(Float64(t_4 * 2.0))) / t_2);
	elseif (t_3 <= Inf)
		tmp = Float64(Float64(sqrt(Float64(Float64(F * 2.0) * t_4)) / t_4) * Float64(sqrt(Float64(Float64(t_0 + A) + C)) / -1.0));
	else
		tmp = Float64(Float64(sqrt(Float64(Float64(hypot(C, B_m) + C) * 2.0)) / Float64(-B_m)) * sqrt(F));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision]}, Block[{t$95$1 = N[(C * N[(A * 4.0), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(t$95$1 - N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = N[(N[Sqrt[N[(N[(N[(C + A), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[(N[(F * N[(N[Power[B$95$m, 2.0], $MachinePrecision] - t$95$1), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / t$95$2), $MachinePrecision]}, Block[{t$95$4 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$3, -5e-195], N[(N[(N[(N[Sqrt[F], $MachinePrecision] * N[Sqrt[N[(N[(N[(C * A), $MachinePrecision] * -4.0 + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sqrt[N[(N[(C + A), $MachinePrecision] + t$95$0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / t$95$2), $MachinePrecision], If[LessEqual[t$95$3, 0.0], N[(N[(N[Sqrt[N[(N[(N[(N[(N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] * -0.5), $MachinePrecision] + C), $MachinePrecision] + C), $MachinePrecision] * F), $MachinePrecision]], $MachinePrecision] * N[Sqrt[N[(t$95$4 * 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / t$95$2), $MachinePrecision], If[LessEqual[t$95$3, Infinity], N[(N[(N[Sqrt[N[(N[(F * 2.0), $MachinePrecision] * t$95$4), $MachinePrecision]], $MachinePrecision] / t$95$4), $MachinePrecision] * N[(N[Sqrt[N[(N[(t$95$0 + A), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] / -1.0), $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision]]]]]]]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
t_0 := \mathsf{hypot}\left(A - C, B\_m\right)\\
t_1 := C \cdot \left(A \cdot 4\right)\\
t_2 := t\_1 - {B\_m}^{2}\\
t_3 := \frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right) \cdot \left(\left(F \cdot \left({B\_m}^{2} - t\_1\right)\right) \cdot 2\right)}}{t\_2}\\
t_4 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
\mathbf{if}\;t\_3 \leq -5 \cdot 10^{-195}:\\
\;\;\;\;\frac{\left(\sqrt{F} \cdot \sqrt{\mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right) \cdot 2}\right) \cdot \sqrt{\left(C + A\right) + t\_0}}{t\_2}\\

\mathbf{elif}\;t\_3 \leq 0:\\
\;\;\;\;\frac{\sqrt{\left(\left(\frac{B\_m \cdot B\_m}{A} \cdot -0.5 + C\right) + C\right) \cdot F} \cdot \sqrt{t\_4 \cdot 2}}{t\_2}\\

\mathbf{elif}\;t\_3 \leq \infty:\\
\;\;\;\;\frac{\sqrt{\left(F \cdot 2\right) \cdot t\_4}}{t\_4} \cdot \frac{\sqrt{\left(t\_0 + A\right) + C}}{-1}\\

\mathbf{else}:\\
\;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{-B\_m} \cdot \sqrt{F}\\


\end{array}
\end{array}
Derivation
  1. Split input into 4 regimes
  2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -5.00000000000000009e-195

    1. Initial program 46.1%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)} \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. associate-*r*N/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)} \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. associate-*l*N/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot \left(F \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      7. sqrt-prodN/A

        \[\leadsto \frac{-\color{blue}{\sqrt{2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \cdot \sqrt{F \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      8. pow1/2N/A

        \[\leadsto \frac{-\color{blue}{{\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)}^{\frac{1}{2}}} \cdot \sqrt{F \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      9. lower-*.f64N/A

        \[\leadsto \frac{-\color{blue}{{\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)}^{\frac{1}{2}} \cdot \sqrt{F \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Applied rewrites67.3%

      \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2} \cdot \sqrt{F \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    5. Step-by-step derivation
      1. lift-neg.f64N/A

        \[\leadsto \frac{\color{blue}{\mathsf{neg}\left(\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2} \cdot \sqrt{F \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lift-*.f64N/A

        \[\leadsto \frac{\mathsf{neg}\left(\color{blue}{\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2} \cdot \sqrt{F \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. distribute-lft-neg-inN/A

        \[\leadsto \frac{\color{blue}{\left(\mathsf{neg}\left(\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2}\right)\right) \cdot \sqrt{F \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. lift-sqrt.f64N/A

        \[\leadsto \frac{\left(\mathsf{neg}\left(\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2}\right)\right) \cdot \color{blue}{\sqrt{F \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. pow1/2N/A

        \[\leadsto \frac{\left(\mathsf{neg}\left(\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2}\right)\right) \cdot \color{blue}{{\left(F \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. lift-*.f64N/A

        \[\leadsto \frac{\left(\mathsf{neg}\left(\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2}\right)\right) \cdot {\color{blue}{\left(F \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)\right)}}^{\frac{1}{2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      7. unpow-prod-downN/A

        \[\leadsto \frac{\left(\mathsf{neg}\left(\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2}\right)\right) \cdot \color{blue}{\left({F}^{\frac{1}{2}} \cdot {\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}^{\frac{1}{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      8. associate-*r*N/A

        \[\leadsto \frac{\color{blue}{\left(\left(\mathsf{neg}\left(\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2}\right)\right) \cdot {F}^{\frac{1}{2}}\right) \cdot {\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      9. lower-*.f64N/A

        \[\leadsto \frac{\color{blue}{\left(\left(\mathsf{neg}\left(\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2}\right)\right) \cdot {F}^{\frac{1}{2}}\right) \cdot {\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    6. Applied rewrites75.2%

      \[\leadsto \frac{\color{blue}{\left(\left(-\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2}\right) \cdot \sqrt{F}\right) \cdot \sqrt{\mathsf{hypot}\left(A - C, B\right) + \left(C + A\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

    if -5.00000000000000009e-195 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -0.0

    1. Initial program 3.5%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)} \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. associate-*r*N/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)} \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. associate-*l*N/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot \left(F \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      7. sqrt-prodN/A

        \[\leadsto \frac{-\color{blue}{\sqrt{2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \cdot \sqrt{F \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      8. pow1/2N/A

        \[\leadsto \frac{-\color{blue}{{\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)}^{\frac{1}{2}}} \cdot \sqrt{F \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      9. lower-*.f64N/A

        \[\leadsto \frac{-\color{blue}{{\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)}^{\frac{1}{2}} \cdot \sqrt{F \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Applied rewrites17.5%

      \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2} \cdot \sqrt{F \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    5. Taylor expanded in A around -inf

      \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2} \cdot \sqrt{F \cdot \left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    6. Step-by-step derivation
      1. lower-+.f64N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2} \cdot \sqrt{F \cdot \left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2} \cdot \sqrt{F \cdot \left(\left(C + \color{blue}{\frac{-1}{2} \cdot \frac{{B}^{2}}{A}}\right) + C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. lower-/.f64N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2} \cdot \sqrt{F \cdot \left(\left(C + \frac{-1}{2} \cdot \color{blue}{\frac{{B}^{2}}{A}}\right) + C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. unpow2N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2} \cdot \sqrt{F \cdot \left(\left(C + \frac{-1}{2} \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. lower-*.f6427.5

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2} \cdot \sqrt{F \cdot \left(\left(C + -0.5 \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    7. Applied rewrites27.5%

      \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2} \cdot \sqrt{F \cdot \left(\color{blue}{\left(C + -0.5 \cdot \frac{B \cdot B}{A}\right)} + C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

    if -0.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

    1. Initial program 27.6%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Applied rewrites94.7%

      \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{-1} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]

    if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

    1. Initial program 0.0%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in A around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. associate-*r*N/A

        \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
      2. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
      3. mul-1-negN/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
      4. lower-neg.f64N/A

        \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
      5. lower-/.f64N/A

        \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
      6. lower-sqrt.f64N/A

        \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
      7. lower-sqrt.f64N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
      8. *-commutativeN/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
      9. lower-*.f64N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
      10. +-commutativeN/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
      11. lower-+.f64N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
      12. +-commutativeN/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
      13. unpow2N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
      14. unpow2N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
      15. lower-hypot.f6417.3

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
    5. Applied rewrites17.3%

      \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
    6. Step-by-step derivation
      1. Applied rewrites27.7%

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
      2. Step-by-step derivation
        1. Applied rewrites27.8%

          \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
      3. Recombined 4 regimes into one program.
      4. Final simplification50.6%

        \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(\left(F \cdot \left({B}^{2} - C \cdot \left(A \cdot 4\right)\right)\right) \cdot 2\right)}}{C \cdot \left(A \cdot 4\right) - {B}^{2}} \leq -5 \cdot 10^{-195}:\\ \;\;\;\;\frac{\left(\sqrt{F} \cdot \sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2}\right) \cdot \sqrt{\left(C + A\right) + \mathsf{hypot}\left(A - C, B\right)}}{C \cdot \left(A \cdot 4\right) - {B}^{2}}\\ \mathbf{elif}\;\frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(\left(F \cdot \left({B}^{2} - C \cdot \left(A \cdot 4\right)\right)\right) \cdot 2\right)}}{C \cdot \left(A \cdot 4\right) - {B}^{2}} \leq 0:\\ \;\;\;\;\frac{\sqrt{\left(\left(\frac{B \cdot B}{A} \cdot -0.5 + C\right) + C\right) \cdot F} \cdot \sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2}}{C \cdot \left(A \cdot 4\right) - {B}^{2}}\\ \mathbf{elif}\;\frac{\sqrt{\left(\left(C + A\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(\left(F \cdot \left({B}^{2} - C \cdot \left(A \cdot 4\right)\right)\right) \cdot 2\right)}}{C \cdot \left(A \cdot 4\right) - {B}^{2}} \leq \infty:\\ \;\;\;\;\frac{\sqrt{\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{-1}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2}}{-B} \cdot \sqrt{F}\\ \end{array} \]
      5. Add Preprocessing

      Alternative 2: 57.0% accurate, 1.9× speedup?

      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 2 \cdot 10^{-120}:\\ \;\;\;\;\frac{-1}{\frac{t\_0}{\sqrt{\left(\left(F \cdot 2\right) \cdot t\_0\right) \cdot \left(\left(\frac{B\_m \cdot B\_m}{A} \cdot -0.5 + C\right) + C\right)}}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{-B\_m} \cdot \sqrt{F}\\ \end{array} \end{array} \]
      B_m = (fabs.f64 B)
      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
      (FPCore (A B_m C F)
       :precision binary64
       (let* ((t_0 (fma -4.0 (* C A) (* B_m B_m))))
         (if (<= (pow B_m 2.0) 2e-120)
           (/
            -1.0
            (/
             t_0
             (sqrt (* (* (* F 2.0) t_0) (+ (+ (* (/ (* B_m B_m) A) -0.5) C) C)))))
           (* (/ (sqrt (* (+ (hypot C B_m) C) 2.0)) (- B_m)) (sqrt F)))))
      B_m = fabs(B);
      assert(A < B_m && B_m < C && C < F);
      double code(double A, double B_m, double C, double F) {
      	double t_0 = fma(-4.0, (C * A), (B_m * B_m));
      	double tmp;
      	if (pow(B_m, 2.0) <= 2e-120) {
      		tmp = -1.0 / (t_0 / sqrt((((F * 2.0) * t_0) * (((((B_m * B_m) / A) * -0.5) + C) + C))));
      	} else {
      		tmp = (sqrt(((hypot(C, B_m) + C) * 2.0)) / -B_m) * sqrt(F);
      	}
      	return tmp;
      }
      
      B_m = abs(B)
      A, B_m, C, F = sort([A, B_m, C, F])
      function code(A, B_m, C, F)
      	t_0 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
      	tmp = 0.0
      	if ((B_m ^ 2.0) <= 2e-120)
      		tmp = Float64(-1.0 / Float64(t_0 / sqrt(Float64(Float64(Float64(F * 2.0) * t_0) * Float64(Float64(Float64(Float64(Float64(B_m * B_m) / A) * -0.5) + C) + C)))));
      	else
      		tmp = Float64(Float64(sqrt(Float64(Float64(hypot(C, B_m) + C) * 2.0)) / Float64(-B_m)) * sqrt(F));
      	end
      	return tmp
      end
      
      B_m = N[Abs[B], $MachinePrecision]
      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
      code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 2e-120], N[(-1.0 / N[(t$95$0 / N[Sqrt[N[(N[(N[(F * 2.0), $MachinePrecision] * t$95$0), $MachinePrecision] * N[(N[(N[(N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] * -0.5), $MachinePrecision] + C), $MachinePrecision] + C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision]]]
      
      \begin{array}{l}
      B_m = \left|B\right|
      \\
      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
      \\
      \begin{array}{l}
      t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
      \mathbf{if}\;{B\_m}^{2} \leq 2 \cdot 10^{-120}:\\
      \;\;\;\;\frac{-1}{\frac{t\_0}{\sqrt{\left(\left(F \cdot 2\right) \cdot t\_0\right) \cdot \left(\left(\frac{B\_m \cdot B\_m}{A} \cdot -0.5 + C\right) + C\right)}}}\\
      
      \mathbf{else}:\\
      \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{-B\_m} \cdot \sqrt{F}\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if (pow.f64 B #s(literal 2 binary64)) < 1.99999999999999996e-120

        1. Initial program 22.3%

          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. Add Preprocessing
        3. Applied rewrites31.1%

          \[\leadsto \color{blue}{\frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}}} \]
        4. Taylor expanded in A around -inf

          \[\leadsto \frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}} \]
        5. Step-by-step derivation
          1. lower-+.f64N/A

            \[\leadsto \frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}} \]
          2. lower-*.f64N/A

            \[\leadsto \frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\left(C + \color{blue}{\frac{-1}{2} \cdot \frac{{B}^{2}}{A}}\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}} \]
          3. lower-/.f64N/A

            \[\leadsto \frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\left(C + \frac{-1}{2} \cdot \color{blue}{\frac{{B}^{2}}{A}}\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}} \]
          4. unpow2N/A

            \[\leadsto \frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\left(C + \frac{-1}{2} \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}} \]
          5. lower-*.f6424.5

            \[\leadsto \frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\left(C + -0.5 \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}} \]
        6. Applied rewrites24.5%

          \[\leadsto \frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\color{blue}{\left(C + -0.5 \cdot \frac{B \cdot B}{A}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}} \]

        if 1.99999999999999996e-120 < (pow.f64 B #s(literal 2 binary64))

        1. Initial program 17.9%

          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. Add Preprocessing
        3. Taylor expanded in A around 0

          \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
        4. Step-by-step derivation
          1. associate-*r*N/A

            \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
          2. lower-*.f64N/A

            \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
          3. mul-1-negN/A

            \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
          4. lower-neg.f64N/A

            \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
          5. lower-/.f64N/A

            \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
          6. lower-sqrt.f64N/A

            \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
          7. lower-sqrt.f64N/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
          8. *-commutativeN/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
          9. lower-*.f64N/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
          10. +-commutativeN/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
          11. lower-+.f64N/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
          12. +-commutativeN/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
          13. unpow2N/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
          14. unpow2N/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
          15. lower-hypot.f6420.5

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
        5. Applied rewrites20.5%

          \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
        6. Step-by-step derivation
          1. Applied rewrites30.1%

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
          2. Step-by-step derivation
            1. Applied rewrites30.2%

              \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
          3. Recombined 2 regimes into one program.
          4. Final simplification27.9%

            \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 2 \cdot 10^{-120}:\\ \;\;\;\;\frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right) \cdot \left(\left(\frac{B \cdot B}{A} \cdot -0.5 + C\right) + C\right)}}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2}}{-B} \cdot \sqrt{F}\\ \end{array} \]
          5. Add Preprocessing

          Alternative 3: 51.8% accurate, 2.3× speedup?

          \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 2 \cdot 10^{+123}:\\ \;\;\;\;\frac{-1}{\frac{t\_0}{\sqrt{\left(\left(F \cdot 2\right) \cdot t\_0\right) \cdot \left(\left(\frac{B\_m \cdot B\_m}{A} \cdot -0.5 + C\right) + C\right)}}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(C + B\_m\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\ \end{array} \end{array} \]
          B_m = (fabs.f64 B)
          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
          (FPCore (A B_m C F)
           :precision binary64
           (let* ((t_0 (fma -4.0 (* C A) (* B_m B_m))))
             (if (<= (pow B_m 2.0) 2e+123)
               (/
                -1.0
                (/
                 t_0
                 (sqrt (* (* (* F 2.0) t_0) (+ (+ (* (/ (* B_m B_m) A) -0.5) C) C)))))
               (* (/ (sqrt (* (+ C B_m) 2.0)) B_m) (- (sqrt F))))))
          B_m = fabs(B);
          assert(A < B_m && B_m < C && C < F);
          double code(double A, double B_m, double C, double F) {
          	double t_0 = fma(-4.0, (C * A), (B_m * B_m));
          	double tmp;
          	if (pow(B_m, 2.0) <= 2e+123) {
          		tmp = -1.0 / (t_0 / sqrt((((F * 2.0) * t_0) * (((((B_m * B_m) / A) * -0.5) + C) + C))));
          	} else {
          		tmp = (sqrt(((C + B_m) * 2.0)) / B_m) * -sqrt(F);
          	}
          	return tmp;
          }
          
          B_m = abs(B)
          A, B_m, C, F = sort([A, B_m, C, F])
          function code(A, B_m, C, F)
          	t_0 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
          	tmp = 0.0
          	if ((B_m ^ 2.0) <= 2e+123)
          		tmp = Float64(-1.0 / Float64(t_0 / sqrt(Float64(Float64(Float64(F * 2.0) * t_0) * Float64(Float64(Float64(Float64(Float64(B_m * B_m) / A) * -0.5) + C) + C)))));
          	else
          		tmp = Float64(Float64(sqrt(Float64(Float64(C + B_m) * 2.0)) / B_m) * Float64(-sqrt(F)));
          	end
          	return tmp
          end
          
          B_m = N[Abs[B], $MachinePrecision]
          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
          code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 2e+123], N[(-1.0 / N[(t$95$0 / N[Sqrt[N[(N[(N[(F * 2.0), $MachinePrecision] * t$95$0), $MachinePrecision] * N[(N[(N[(N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] * -0.5), $MachinePrecision] + C), $MachinePrecision] + C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(N[(C + B$95$m), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / B$95$m), $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]]]
          
          \begin{array}{l}
          B_m = \left|B\right|
          \\
          [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
          \\
          \begin{array}{l}
          t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
          \mathbf{if}\;{B\_m}^{2} \leq 2 \cdot 10^{+123}:\\
          \;\;\;\;\frac{-1}{\frac{t\_0}{\sqrt{\left(\left(F \cdot 2\right) \cdot t\_0\right) \cdot \left(\left(\frac{B\_m \cdot B\_m}{A} \cdot -0.5 + C\right) + C\right)}}}\\
          
          \mathbf{else}:\\
          \;\;\;\;\frac{\sqrt{\left(C + B\_m\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if (pow.f64 B #s(literal 2 binary64)) < 1.99999999999999996e123

            1. Initial program 25.7%

              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            2. Add Preprocessing
            3. Applied rewrites34.4%

              \[\leadsto \color{blue}{\frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}}} \]
            4. Taylor expanded in A around -inf

              \[\leadsto \frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}} \]
            5. Step-by-step derivation
              1. lower-+.f64N/A

                \[\leadsto \frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}} \]
              2. lower-*.f64N/A

                \[\leadsto \frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\left(C + \color{blue}{\frac{-1}{2} \cdot \frac{{B}^{2}}{A}}\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}} \]
              3. lower-/.f64N/A

                \[\leadsto \frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\left(C + \frac{-1}{2} \cdot \color{blue}{\frac{{B}^{2}}{A}}\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}} \]
              4. unpow2N/A

                \[\leadsto \frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\left(C + \frac{-1}{2} \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}} \]
              5. lower-*.f6422.3

                \[\leadsto \frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\left(C + -0.5 \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}} \]
            6. Applied rewrites22.3%

              \[\leadsto \frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\color{blue}{\left(C + -0.5 \cdot \frac{B \cdot B}{A}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}} \]

            if 1.99999999999999996e123 < (pow.f64 B #s(literal 2 binary64))

            1. Initial program 10.4%

              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            2. Add Preprocessing
            3. Taylor expanded in A around 0

              \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
            4. Step-by-step derivation
              1. associate-*r*N/A

                \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
              2. lower-*.f64N/A

                \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
              3. mul-1-negN/A

                \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
              4. lower-neg.f64N/A

                \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
              5. lower-/.f64N/A

                \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
              6. lower-sqrt.f64N/A

                \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
              7. lower-sqrt.f64N/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
              8. *-commutativeN/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
              9. lower-*.f64N/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
              10. +-commutativeN/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
              11. lower-+.f64N/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
              12. +-commutativeN/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
              13. unpow2N/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
              14. unpow2N/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
              15. lower-hypot.f6426.4

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
            5. Applied rewrites26.4%

              \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
            6. Step-by-step derivation
              1. Applied rewrites39.8%

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
              2. Step-by-step derivation
                1. Applied rewrites39.9%

                  \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                2. Taylor expanded in C around 0

                  \[\leadsto \frac{\sqrt{2 \cdot \left(B + C\right)}}{-B} \cdot \sqrt{F} \]
                3. Step-by-step derivation
                  1. Applied rewrites36.5%

                    \[\leadsto \frac{\sqrt{2 \cdot \left(C + B\right)}}{-B} \cdot \sqrt{F} \]
                4. Recombined 2 regimes into one program.
                5. Final simplification27.9%

                  \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 2 \cdot 10^{+123}:\\ \;\;\;\;\frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right) \cdot \left(\left(\frac{B \cdot B}{A} \cdot -0.5 + C\right) + C\right)}}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(C + B\right) \cdot 2}}{B} \cdot \left(-\sqrt{F}\right)\\ \end{array} \]
                6. Add Preprocessing

                Alternative 4: 55.9% accurate, 2.4× speedup?

                \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)\\ t_1 := -t\_0\\ \mathbf{if}\;B\_m \leq 1.7 \cdot 10^{-225}:\\ \;\;\;\;\frac{\sqrt{\left(\left(C \cdot 2\right) \cdot \left(t\_0 \cdot 2\right)\right) \cdot F}}{t\_1}\\ \mathbf{elif}\;B\_m \leq 58000000000:\\ \;\;\;\;\frac{\sqrt{\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)} \cdot \sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}}{t\_1}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{-B\_m} \cdot \sqrt{F}\\ \end{array} \end{array} \]
                B_m = (fabs.f64 B)
                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                (FPCore (A B_m C F)
                 :precision binary64
                 (let* ((t_0 (fma (* C A) -4.0 (* B_m B_m))) (t_1 (- t_0)))
                   (if (<= B_m 1.7e-225)
                     (/ (sqrt (* (* (* C 2.0) (* t_0 2.0)) F)) t_1)
                     (if (<= B_m 58000000000.0)
                       (/
                        (*
                         (sqrt (* (* F 2.0) (fma -4.0 (* C A) (* B_m B_m))))
                         (sqrt (+ (+ (hypot (- A C) B_m) A) C)))
                        t_1)
                       (* (/ (sqrt (* (+ (hypot C B_m) C) 2.0)) (- B_m)) (sqrt F))))))
                B_m = fabs(B);
                assert(A < B_m && B_m < C && C < F);
                double code(double A, double B_m, double C, double F) {
                	double t_0 = fma((C * A), -4.0, (B_m * B_m));
                	double t_1 = -t_0;
                	double tmp;
                	if (B_m <= 1.7e-225) {
                		tmp = sqrt((((C * 2.0) * (t_0 * 2.0)) * F)) / t_1;
                	} else if (B_m <= 58000000000.0) {
                		tmp = (sqrt(((F * 2.0) * fma(-4.0, (C * A), (B_m * B_m)))) * sqrt(((hypot((A - C), B_m) + A) + C))) / t_1;
                	} else {
                		tmp = (sqrt(((hypot(C, B_m) + C) * 2.0)) / -B_m) * sqrt(F);
                	}
                	return tmp;
                }
                
                B_m = abs(B)
                A, B_m, C, F = sort([A, B_m, C, F])
                function code(A, B_m, C, F)
                	t_0 = fma(Float64(C * A), -4.0, Float64(B_m * B_m))
                	t_1 = Float64(-t_0)
                	tmp = 0.0
                	if (B_m <= 1.7e-225)
                		tmp = Float64(sqrt(Float64(Float64(Float64(C * 2.0) * Float64(t_0 * 2.0)) * F)) / t_1);
                	elseif (B_m <= 58000000000.0)
                		tmp = Float64(Float64(sqrt(Float64(Float64(F * 2.0) * fma(-4.0, Float64(C * A), Float64(B_m * B_m)))) * sqrt(Float64(Float64(hypot(Float64(A - C), B_m) + A) + C))) / t_1);
                	else
                		tmp = Float64(Float64(sqrt(Float64(Float64(hypot(C, B_m) + C) * 2.0)) / Float64(-B_m)) * sqrt(F));
                	end
                	return tmp
                end
                
                B_m = N[Abs[B], $MachinePrecision]
                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(C * A), $MachinePrecision] * -4.0 + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = (-t$95$0)}, If[LessEqual[B$95$m, 1.7e-225], N[(N[Sqrt[N[(N[(N[(C * 2.0), $MachinePrecision] * N[(t$95$0 * 2.0), $MachinePrecision]), $MachinePrecision] * F), $MachinePrecision]], $MachinePrecision] / t$95$1), $MachinePrecision], If[LessEqual[B$95$m, 58000000000.0], N[(N[(N[Sqrt[N[(N[(F * 2.0), $MachinePrecision] * N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[Sqrt[N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / t$95$1), $MachinePrecision], N[(N[(N[Sqrt[N[(N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision]]]]]
                
                \begin{array}{l}
                B_m = \left|B\right|
                \\
                [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                \\
                \begin{array}{l}
                t_0 := \mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)\\
                t_1 := -t\_0\\
                \mathbf{if}\;B\_m \leq 1.7 \cdot 10^{-225}:\\
                \;\;\;\;\frac{\sqrt{\left(\left(C \cdot 2\right) \cdot \left(t\_0 \cdot 2\right)\right) \cdot F}}{t\_1}\\
                
                \mathbf{elif}\;B\_m \leq 58000000000:\\
                \;\;\;\;\frac{\sqrt{\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)} \cdot \sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}}{t\_1}\\
                
                \mathbf{else}:\\
                \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{-B\_m} \cdot \sqrt{F}\\
                
                
                \end{array}
                \end{array}
                
                Derivation
                1. Split input into 3 regimes
                2. if B < 1.7e-225

                  1. Initial program 18.5%

                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  2. Add Preprocessing
                  3. Applied rewrites23.7%

                    \[\leadsto \color{blue}{\frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}}} \]
                  4. Applied rewrites18.3%

                    \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + \left(C + A\right)\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \]
                  5. Taylor expanded in C around inf

                    \[\leadsto \frac{\sqrt{\left(\color{blue}{\left(C \cdot \left(2 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)\right)} \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]
                  6. Step-by-step derivation
                    1. distribute-lft1-inN/A

                      \[\leadsto \frac{\sqrt{\left(\left(C \cdot \left(2 + \color{blue}{\left(-1 + 1\right) \cdot \frac{A}{C}}\right)\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]
                    2. metadata-evalN/A

                      \[\leadsto \frac{\sqrt{\left(\left(C \cdot \left(2 + \color{blue}{0} \cdot \frac{A}{C}\right)\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]
                    3. mul0-lftN/A

                      \[\leadsto \frac{\sqrt{\left(\left(C \cdot \left(2 + \color{blue}{0}\right)\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]
                    4. metadata-evalN/A

                      \[\leadsto \frac{\sqrt{\left(\left(C \cdot \color{blue}{2}\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]
                    5. lower-*.f6412.3

                      \[\leadsto \frac{\sqrt{\left(\color{blue}{\left(C \cdot 2\right)} \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]
                  7. Applied rewrites12.3%

                    \[\leadsto \frac{\sqrt{\left(\color{blue}{\left(C \cdot 2\right)} \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]

                  if 1.7e-225 < B < 5.8e10

                  1. Initial program 30.4%

                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  2. Add Preprocessing
                  3. Applied rewrites41.8%

                    \[\leadsto \color{blue}{\frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}}} \]
                  4. Applied rewrites31.7%

                    \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + \left(C + A\right)\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \]
                  5. Applied rewrites59.5%

                    \[\leadsto \frac{\color{blue}{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C} \cdot \sqrt{\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]

                  if 5.8e10 < B

                  1. Initial program 13.3%

                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  2. Add Preprocessing
                  3. Taylor expanded in A around 0

                    \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                  4. Step-by-step derivation
                    1. associate-*r*N/A

                      \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                    2. lower-*.f64N/A

                      \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                    3. mul-1-negN/A

                      \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                    4. lower-neg.f64N/A

                      \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                    5. lower-/.f64N/A

                      \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                    6. lower-sqrt.f64N/A

                      \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                    7. lower-sqrt.f64N/A

                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                    8. *-commutativeN/A

                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                    9. lower-*.f64N/A

                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                    10. +-commutativeN/A

                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                    11. lower-+.f64N/A

                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                    12. +-commutativeN/A

                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                    13. unpow2N/A

                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                    14. unpow2N/A

                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                    15. lower-hypot.f6448.8

                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                  5. Applied rewrites48.8%

                    \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                  6. Step-by-step derivation
                    1. Applied rewrites74.5%

                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                    2. Step-by-step derivation
                      1. Applied rewrites74.8%

                        \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                    3. Recombined 3 regimes into one program.
                    4. Final simplification35.2%

                      \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 1.7 \cdot 10^{-225}:\\ \;\;\;\;\frac{\sqrt{\left(\left(C \cdot 2\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}\\ \mathbf{elif}\;B \leq 58000000000:\\ \;\;\;\;\frac{\sqrt{\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \cdot \sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2}}{-B} \cdot \sqrt{F}\\ \end{array} \]
                    5. Add Preprocessing

                    Alternative 5: 55.9% accurate, 2.4× speedup?

                    \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)\\ t_1 := -t\_0\\ \mathbf{if}\;B\_m \leq 1.2 \cdot 10^{-224}:\\ \;\;\;\;\frac{\sqrt{\left(\left(C \cdot 2\right) \cdot \left(t\_0 \cdot 2\right)\right) \cdot F}}{t\_1}\\ \mathbf{elif}\;B\_m \leq 58000000000:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C\right) \cdot 2} \cdot \sqrt{\mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right) \cdot F}}{t\_1}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{-B\_m} \cdot \sqrt{F}\\ \end{array} \end{array} \]
                    B_m = (fabs.f64 B)
                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                    (FPCore (A B_m C F)
                     :precision binary64
                     (let* ((t_0 (fma (* C A) -4.0 (* B_m B_m))) (t_1 (- t_0)))
                       (if (<= B_m 1.2e-224)
                         (/ (sqrt (* (* (* C 2.0) (* t_0 2.0)) F)) t_1)
                         (if (<= B_m 58000000000.0)
                           (/
                            (*
                             (sqrt (* (+ (+ (hypot (- A C) B_m) A) C) 2.0))
                             (sqrt (* (fma -4.0 (* C A) (* B_m B_m)) F)))
                            t_1)
                           (* (/ (sqrt (* (+ (hypot C B_m) C) 2.0)) (- B_m)) (sqrt F))))))
                    B_m = fabs(B);
                    assert(A < B_m && B_m < C && C < F);
                    double code(double A, double B_m, double C, double F) {
                    	double t_0 = fma((C * A), -4.0, (B_m * B_m));
                    	double t_1 = -t_0;
                    	double tmp;
                    	if (B_m <= 1.2e-224) {
                    		tmp = sqrt((((C * 2.0) * (t_0 * 2.0)) * F)) / t_1;
                    	} else if (B_m <= 58000000000.0) {
                    		tmp = (sqrt((((hypot((A - C), B_m) + A) + C) * 2.0)) * sqrt((fma(-4.0, (C * A), (B_m * B_m)) * F))) / t_1;
                    	} else {
                    		tmp = (sqrt(((hypot(C, B_m) + C) * 2.0)) / -B_m) * sqrt(F);
                    	}
                    	return tmp;
                    }
                    
                    B_m = abs(B)
                    A, B_m, C, F = sort([A, B_m, C, F])
                    function code(A, B_m, C, F)
                    	t_0 = fma(Float64(C * A), -4.0, Float64(B_m * B_m))
                    	t_1 = Float64(-t_0)
                    	tmp = 0.0
                    	if (B_m <= 1.2e-224)
                    		tmp = Float64(sqrt(Float64(Float64(Float64(C * 2.0) * Float64(t_0 * 2.0)) * F)) / t_1);
                    	elseif (B_m <= 58000000000.0)
                    		tmp = Float64(Float64(sqrt(Float64(Float64(Float64(hypot(Float64(A - C), B_m) + A) + C) * 2.0)) * sqrt(Float64(fma(-4.0, Float64(C * A), Float64(B_m * B_m)) * F))) / t_1);
                    	else
                    		tmp = Float64(Float64(sqrt(Float64(Float64(hypot(C, B_m) + C) * 2.0)) / Float64(-B_m)) * sqrt(F));
                    	end
                    	return tmp
                    end
                    
                    B_m = N[Abs[B], $MachinePrecision]
                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                    code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(C * A), $MachinePrecision] * -4.0 + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = (-t$95$0)}, If[LessEqual[B$95$m, 1.2e-224], N[(N[Sqrt[N[(N[(N[(C * 2.0), $MachinePrecision] * N[(t$95$0 * 2.0), $MachinePrecision]), $MachinePrecision] * F), $MachinePrecision]], $MachinePrecision] / t$95$1), $MachinePrecision], If[LessEqual[B$95$m, 58000000000.0], N[(N[(N[Sqrt[N[(N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] * N[Sqrt[N[(N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision] * F), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / t$95$1), $MachinePrecision], N[(N[(N[Sqrt[N[(N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision]]]]]
                    
                    \begin{array}{l}
                    B_m = \left|B\right|
                    \\
                    [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                    \\
                    \begin{array}{l}
                    t_0 := \mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)\\
                    t_1 := -t\_0\\
                    \mathbf{if}\;B\_m \leq 1.2 \cdot 10^{-224}:\\
                    \;\;\;\;\frac{\sqrt{\left(\left(C \cdot 2\right) \cdot \left(t\_0 \cdot 2\right)\right) \cdot F}}{t\_1}\\
                    
                    \mathbf{elif}\;B\_m \leq 58000000000:\\
                    \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C\right) \cdot 2} \cdot \sqrt{\mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right) \cdot F}}{t\_1}\\
                    
                    \mathbf{else}:\\
                    \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{-B\_m} \cdot \sqrt{F}\\
                    
                    
                    \end{array}
                    \end{array}
                    
                    Derivation
                    1. Split input into 3 regimes
                    2. if B < 1.20000000000000007e-224

                      1. Initial program 18.5%

                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      2. Add Preprocessing
                      3. Applied rewrites23.7%

                        \[\leadsto \color{blue}{\frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}}} \]
                      4. Applied rewrites18.3%

                        \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + \left(C + A\right)\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \]
                      5. Taylor expanded in C around inf

                        \[\leadsto \frac{\sqrt{\left(\color{blue}{\left(C \cdot \left(2 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)\right)} \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]
                      6. Step-by-step derivation
                        1. distribute-lft1-inN/A

                          \[\leadsto \frac{\sqrt{\left(\left(C \cdot \left(2 + \color{blue}{\left(-1 + 1\right) \cdot \frac{A}{C}}\right)\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]
                        2. metadata-evalN/A

                          \[\leadsto \frac{\sqrt{\left(\left(C \cdot \left(2 + \color{blue}{0} \cdot \frac{A}{C}\right)\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]
                        3. mul0-lftN/A

                          \[\leadsto \frac{\sqrt{\left(\left(C \cdot \left(2 + \color{blue}{0}\right)\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]
                        4. metadata-evalN/A

                          \[\leadsto \frac{\sqrt{\left(\left(C \cdot \color{blue}{2}\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]
                        5. lower-*.f6412.3

                          \[\leadsto \frac{\sqrt{\left(\color{blue}{\left(C \cdot 2\right)} \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]
                      7. Applied rewrites12.3%

                        \[\leadsto \frac{\sqrt{\left(\color{blue}{\left(C \cdot 2\right)} \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]

                      if 1.20000000000000007e-224 < B < 5.8e10

                      1. Initial program 30.4%

                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      2. Add Preprocessing
                      3. Applied rewrites41.8%

                        \[\leadsto \color{blue}{\frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}}} \]
                      4. Applied rewrites31.7%

                        \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + \left(C + A\right)\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \]
                      5. Applied rewrites59.3%

                        \[\leadsto \frac{\color{blue}{\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot F} \cdot \sqrt{2 \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]

                      if 5.8e10 < B

                      1. Initial program 13.3%

                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      2. Add Preprocessing
                      3. Taylor expanded in A around 0

                        \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                      4. Step-by-step derivation
                        1. associate-*r*N/A

                          \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                        2. lower-*.f64N/A

                          \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                        3. mul-1-negN/A

                          \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                        4. lower-neg.f64N/A

                          \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                        5. lower-/.f64N/A

                          \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                        6. lower-sqrt.f64N/A

                          \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                        7. lower-sqrt.f64N/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                        8. *-commutativeN/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                        9. lower-*.f64N/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                        10. +-commutativeN/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                        11. lower-+.f64N/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                        12. +-commutativeN/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                        13. unpow2N/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                        14. unpow2N/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                        15. lower-hypot.f6448.8

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                      5. Applied rewrites48.8%

                        \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                      6. Step-by-step derivation
                        1. Applied rewrites74.5%

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                        2. Step-by-step derivation
                          1. Applied rewrites74.8%

                            \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                        3. Recombined 3 regimes into one program.
                        4. Final simplification35.1%

                          \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 1.2 \cdot 10^{-224}:\\ \;\;\;\;\frac{\sqrt{\left(\left(C \cdot 2\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}\\ \mathbf{elif}\;B \leq 58000000000:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot 2} \cdot \sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2}}{-B} \cdot \sqrt{F}\\ \end{array} \]
                        5. Add Preprocessing

                        Alternative 6: 57.0% accurate, 2.4× speedup?

                        \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;B\_m \leq 7.2 \cdot 10^{-109}:\\ \;\;\;\;\frac{-1}{\frac{t\_0}{\sqrt{\left(\left(F \cdot 2\right) \cdot t\_0\right) \cdot \left(\left(\frac{B\_m \cdot B\_m}{A} \cdot -0.5 + C\right) + C\right)}}}\\ \mathbf{elif}\;B\_m \leq 1.8:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C\right) \cdot F} \cdot \sqrt{t\_0 \cdot 2}}{-\mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(C \cdot A\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{-B\_m} \cdot \sqrt{F}\\ \end{array} \end{array} \]
                        B_m = (fabs.f64 B)
                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                        (FPCore (A B_m C F)
                         :precision binary64
                         (let* ((t_0 (fma -4.0 (* C A) (* B_m B_m))))
                           (if (<= B_m 7.2e-109)
                             (/
                              -1.0
                              (/
                               t_0
                               (sqrt (* (* (* F 2.0) t_0) (+ (+ (* (/ (* B_m B_m) A) -0.5) C) C)))))
                             (if (<= B_m 1.8)
                               (/
                                (* (sqrt (* (+ (+ (hypot (- A C) B_m) A) C) F)) (sqrt (* t_0 2.0)))
                                (- (fma B_m B_m (* -4.0 (* C A)))))
                               (* (/ (sqrt (* (+ (hypot C B_m) C) 2.0)) (- B_m)) (sqrt F))))))
                        B_m = fabs(B);
                        assert(A < B_m && B_m < C && C < F);
                        double code(double A, double B_m, double C, double F) {
                        	double t_0 = fma(-4.0, (C * A), (B_m * B_m));
                        	double tmp;
                        	if (B_m <= 7.2e-109) {
                        		tmp = -1.0 / (t_0 / sqrt((((F * 2.0) * t_0) * (((((B_m * B_m) / A) * -0.5) + C) + C))));
                        	} else if (B_m <= 1.8) {
                        		tmp = (sqrt((((hypot((A - C), B_m) + A) + C) * F)) * sqrt((t_0 * 2.0))) / -fma(B_m, B_m, (-4.0 * (C * A)));
                        	} else {
                        		tmp = (sqrt(((hypot(C, B_m) + C) * 2.0)) / -B_m) * sqrt(F);
                        	}
                        	return tmp;
                        }
                        
                        B_m = abs(B)
                        A, B_m, C, F = sort([A, B_m, C, F])
                        function code(A, B_m, C, F)
                        	t_0 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
                        	tmp = 0.0
                        	if (B_m <= 7.2e-109)
                        		tmp = Float64(-1.0 / Float64(t_0 / sqrt(Float64(Float64(Float64(F * 2.0) * t_0) * Float64(Float64(Float64(Float64(Float64(B_m * B_m) / A) * -0.5) + C) + C)))));
                        	elseif (B_m <= 1.8)
                        		tmp = Float64(Float64(sqrt(Float64(Float64(Float64(hypot(Float64(A - C), B_m) + A) + C) * F)) * sqrt(Float64(t_0 * 2.0))) / Float64(-fma(B_m, B_m, Float64(-4.0 * Float64(C * A)))));
                        	else
                        		tmp = Float64(Float64(sqrt(Float64(Float64(hypot(C, B_m) + C) * 2.0)) / Float64(-B_m)) * sqrt(F));
                        	end
                        	return tmp
                        end
                        
                        B_m = N[Abs[B], $MachinePrecision]
                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                        code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[B$95$m, 7.2e-109], N[(-1.0 / N[(t$95$0 / N[Sqrt[N[(N[(N[(F * 2.0), $MachinePrecision] * t$95$0), $MachinePrecision] * N[(N[(N[(N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] * -0.5), $MachinePrecision] + C), $MachinePrecision] + C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[B$95$m, 1.8], N[(N[(N[Sqrt[N[(N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision] * F), $MachinePrecision]], $MachinePrecision] * N[Sqrt[N[(t$95$0 * 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / (-N[(B$95$m * B$95$m + N[(-4.0 * N[(C * A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision])), $MachinePrecision], N[(N[(N[Sqrt[N[(N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision]]]]
                        
                        \begin{array}{l}
                        B_m = \left|B\right|
                        \\
                        [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                        \\
                        \begin{array}{l}
                        t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
                        \mathbf{if}\;B\_m \leq 7.2 \cdot 10^{-109}:\\
                        \;\;\;\;\frac{-1}{\frac{t\_0}{\sqrt{\left(\left(F \cdot 2\right) \cdot t\_0\right) \cdot \left(\left(\frac{B\_m \cdot B\_m}{A} \cdot -0.5 + C\right) + C\right)}}}\\
                        
                        \mathbf{elif}\;B\_m \leq 1.8:\\
                        \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C\right) \cdot F} \cdot \sqrt{t\_0 \cdot 2}}{-\mathsf{fma}\left(B\_m, B\_m, -4 \cdot \left(C \cdot A\right)\right)}\\
                        
                        \mathbf{else}:\\
                        \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{-B\_m} \cdot \sqrt{F}\\
                        
                        
                        \end{array}
                        \end{array}
                        
                        Derivation
                        1. Split input into 3 regimes
                        2. if B < 7.2000000000000001e-109

                          1. Initial program 21.5%

                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          2. Add Preprocessing
                          3. Applied rewrites27.8%

                            \[\leadsto \color{blue}{\frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}}} \]
                          4. Taylor expanded in A around -inf

                            \[\leadsto \frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}} \]
                          5. Step-by-step derivation
                            1. lower-+.f64N/A

                              \[\leadsto \frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}} \]
                            2. lower-*.f64N/A

                              \[\leadsto \frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\left(C + \color{blue}{\frac{-1}{2} \cdot \frac{{B}^{2}}{A}}\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}} \]
                            3. lower-/.f64N/A

                              \[\leadsto \frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\left(C + \frac{-1}{2} \cdot \color{blue}{\frac{{B}^{2}}{A}}\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}} \]
                            4. unpow2N/A

                              \[\leadsto \frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\left(C + \frac{-1}{2} \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}} \]
                            5. lower-*.f6417.9

                              \[\leadsto \frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\left(C + -0.5 \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}} \]
                          6. Applied rewrites17.9%

                            \[\leadsto \frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\color{blue}{\left(C + -0.5 \cdot \frac{B \cdot B}{A}\right)} + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}} \]

                          if 7.2000000000000001e-109 < B < 1.80000000000000004

                          1. Initial program 23.1%

                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          2. Add Preprocessing
                          3. Step-by-step derivation
                            1. lift-sqrt.f64N/A

                              \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            2. lift-*.f64N/A

                              \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            3. lift-*.f64N/A

                              \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)} \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            4. lift-*.f64N/A

                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            5. associate-*r*N/A

                              \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)} \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            6. associate-*l*N/A

                              \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot \left(F \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            7. sqrt-prodN/A

                              \[\leadsto \frac{-\color{blue}{\sqrt{2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \cdot \sqrt{F \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            8. pow1/2N/A

                              \[\leadsto \frac{-\color{blue}{{\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)}^{\frac{1}{2}}} \cdot \sqrt{F \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            9. lower-*.f64N/A

                              \[\leadsto \frac{-\color{blue}{{\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)}^{\frac{1}{2}} \cdot \sqrt{F \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          4. Applied rewrites38.9%

                            \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2} \cdot \sqrt{F \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          5. Taylor expanded in B around 0

                            \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2} \cdot \sqrt{F \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}}{\color{blue}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \]
                          6. Step-by-step derivation
                            1. cancel-sign-sub-invN/A

                              \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2} \cdot \sqrt{F \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}}{\color{blue}{{B}^{2} + \left(\mathsf{neg}\left(4\right)\right) \cdot \left(A \cdot C\right)}} \]
                            2. unpow2N/A

                              \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2} \cdot \sqrt{F \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}}{\color{blue}{B \cdot B} + \left(\mathsf{neg}\left(4\right)\right) \cdot \left(A \cdot C\right)} \]
                            3. metadata-evalN/A

                              \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2} \cdot \sqrt{F \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}}{B \cdot B + \color{blue}{-4} \cdot \left(A \cdot C\right)} \]
                            4. lower-fma.f64N/A

                              \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2} \cdot \sqrt{F \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}}{\color{blue}{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}} \]
                            5. lower-*.f64N/A

                              \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2} \cdot \sqrt{F \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}}{\mathsf{fma}\left(B, B, \color{blue}{-4 \cdot \left(A \cdot C\right)}\right)} \]
                            6. lower-*.f6438.9

                              \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2} \cdot \sqrt{F \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}}{\mathsf{fma}\left(B, B, -4 \cdot \color{blue}{\left(A \cdot C\right)}\right)} \]
                          7. Applied rewrites38.9%

                            \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2} \cdot \sqrt{F \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)}}{\color{blue}{\mathsf{fma}\left(B, B, -4 \cdot \left(A \cdot C\right)\right)}} \]

                          if 1.80000000000000004 < B

                          1. Initial program 13.0%

                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          2. Add Preprocessing
                          3. Taylor expanded in A around 0

                            \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                          4. Step-by-step derivation
                            1. associate-*r*N/A

                              \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                            2. lower-*.f64N/A

                              \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                            3. mul-1-negN/A

                              \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                            4. lower-neg.f64N/A

                              \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                            5. lower-/.f64N/A

                              \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                            6. lower-sqrt.f64N/A

                              \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                            7. lower-sqrt.f64N/A

                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                            8. *-commutativeN/A

                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                            9. lower-*.f64N/A

                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                            10. +-commutativeN/A

                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                            11. lower-+.f64N/A

                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                            12. +-commutativeN/A

                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                            13. unpow2N/A

                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                            14. unpow2N/A

                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                            15. lower-hypot.f6447.3

                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                          5. Applied rewrites47.3%

                            \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                          6. Step-by-step derivation
                            1. Applied rewrites72.1%

                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                            2. Step-by-step derivation
                              1. Applied rewrites72.3%

                                \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                            3. Recombined 3 regimes into one program.
                            4. Final simplification31.7%

                              \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 7.2 \cdot 10^{-109}:\\ \;\;\;\;\frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right) \cdot \left(\left(\frac{B \cdot B}{A} \cdot -0.5 + C\right) + C\right)}}}\\ \mathbf{elif}\;B \leq 1.8:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot F} \cdot \sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2}}{-\mathsf{fma}\left(B, B, -4 \cdot \left(C \cdot A\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2}}{-B} \cdot \sqrt{F}\\ \end{array} \]
                            5. Add Preprocessing

                            Alternative 7: 50.4% accurate, 2.7× speedup?

                            \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 10^{+23}:\\ \;\;\;\;\frac{\sqrt{\left(\left(C \cdot 2\right) \cdot \left(t\_0 \cdot 2\right)\right) \cdot F}}{-t\_0}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(C + B\_m\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\ \end{array} \end{array} \]
                            B_m = (fabs.f64 B)
                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                            (FPCore (A B_m C F)
                             :precision binary64
                             (let* ((t_0 (fma (* C A) -4.0 (* B_m B_m))))
                               (if (<= (pow B_m 2.0) 1e+23)
                                 (/ (sqrt (* (* (* C 2.0) (* t_0 2.0)) F)) (- t_0))
                                 (* (/ (sqrt (* (+ C B_m) 2.0)) B_m) (- (sqrt F))))))
                            B_m = fabs(B);
                            assert(A < B_m && B_m < C && C < F);
                            double code(double A, double B_m, double C, double F) {
                            	double t_0 = fma((C * A), -4.0, (B_m * B_m));
                            	double tmp;
                            	if (pow(B_m, 2.0) <= 1e+23) {
                            		tmp = sqrt((((C * 2.0) * (t_0 * 2.0)) * F)) / -t_0;
                            	} else {
                            		tmp = (sqrt(((C + B_m) * 2.0)) / B_m) * -sqrt(F);
                            	}
                            	return tmp;
                            }
                            
                            B_m = abs(B)
                            A, B_m, C, F = sort([A, B_m, C, F])
                            function code(A, B_m, C, F)
                            	t_0 = fma(Float64(C * A), -4.0, Float64(B_m * B_m))
                            	tmp = 0.0
                            	if ((B_m ^ 2.0) <= 1e+23)
                            		tmp = Float64(sqrt(Float64(Float64(Float64(C * 2.0) * Float64(t_0 * 2.0)) * F)) / Float64(-t_0));
                            	else
                            		tmp = Float64(Float64(sqrt(Float64(Float64(C + B_m) * 2.0)) / B_m) * Float64(-sqrt(F)));
                            	end
                            	return tmp
                            end
                            
                            B_m = N[Abs[B], $MachinePrecision]
                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                            code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(C * A), $MachinePrecision] * -4.0 + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e+23], N[(N[Sqrt[N[(N[(N[(C * 2.0), $MachinePrecision] * N[(t$95$0 * 2.0), $MachinePrecision]), $MachinePrecision] * F), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], N[(N[(N[Sqrt[N[(N[(C + B$95$m), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / B$95$m), $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]]]
                            
                            \begin{array}{l}
                            B_m = \left|B\right|
                            \\
                            [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                            \\
                            \begin{array}{l}
                            t_0 := \mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)\\
                            \mathbf{if}\;{B\_m}^{2} \leq 10^{+23}:\\
                            \;\;\;\;\frac{\sqrt{\left(\left(C \cdot 2\right) \cdot \left(t\_0 \cdot 2\right)\right) \cdot F}}{-t\_0}\\
                            
                            \mathbf{else}:\\
                            \;\;\;\;\frac{\sqrt{\left(C + B\_m\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\
                            
                            
                            \end{array}
                            \end{array}
                            
                            Derivation
                            1. Split input into 2 regimes
                            2. if (pow.f64 B #s(literal 2 binary64)) < 9.9999999999999992e22

                              1. Initial program 25.5%

                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              2. Add Preprocessing
                              3. Applied rewrites35.2%

                                \[\leadsto \color{blue}{\frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}}} \]
                              4. Applied rewrites27.8%

                                \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + \left(C + A\right)\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \]
                              5. Taylor expanded in C around inf

                                \[\leadsto \frac{\sqrt{\left(\color{blue}{\left(C \cdot \left(2 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)\right)} \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]
                              6. Step-by-step derivation
                                1. distribute-lft1-inN/A

                                  \[\leadsto \frac{\sqrt{\left(\left(C \cdot \left(2 + \color{blue}{\left(-1 + 1\right) \cdot \frac{A}{C}}\right)\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]
                                2. metadata-evalN/A

                                  \[\leadsto \frac{\sqrt{\left(\left(C \cdot \left(2 + \color{blue}{0} \cdot \frac{A}{C}\right)\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]
                                3. mul0-lftN/A

                                  \[\leadsto \frac{\sqrt{\left(\left(C \cdot \left(2 + \color{blue}{0}\right)\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]
                                4. metadata-evalN/A

                                  \[\leadsto \frac{\sqrt{\left(\left(C \cdot \color{blue}{2}\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]
                                5. lower-*.f6419.3

                                  \[\leadsto \frac{\sqrt{\left(\color{blue}{\left(C \cdot 2\right)} \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]
                              7. Applied rewrites19.3%

                                \[\leadsto \frac{\sqrt{\left(\color{blue}{\left(C \cdot 2\right)} \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]

                              if 9.9999999999999992e22 < (pow.f64 B #s(literal 2 binary64))

                              1. Initial program 13.1%

                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              2. Add Preprocessing
                              3. Taylor expanded in A around 0

                                \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                              4. Step-by-step derivation
                                1. associate-*r*N/A

                                  \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                2. lower-*.f64N/A

                                  \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                3. mul-1-negN/A

                                  \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                4. lower-neg.f64N/A

                                  \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                5. lower-/.f64N/A

                                  \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                6. lower-sqrt.f64N/A

                                  \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                7. lower-sqrt.f64N/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                8. *-commutativeN/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                9. lower-*.f64N/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                10. +-commutativeN/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                11. lower-+.f64N/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                12. +-commutativeN/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                                13. unpow2N/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                                14. unpow2N/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                                15. lower-hypot.f6423.6

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                              5. Applied rewrites23.6%

                                \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                              6. Step-by-step derivation
                                1. Applied rewrites35.7%

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                                2. Step-by-step derivation
                                  1. Applied rewrites35.8%

                                    \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                                  2. Taylor expanded in C around 0

                                    \[\leadsto \frac{\sqrt{2 \cdot \left(B + C\right)}}{-B} \cdot \sqrt{F} \]
                                  3. Step-by-step derivation
                                    1. Applied rewrites31.3%

                                      \[\leadsto \frac{\sqrt{2 \cdot \left(C + B\right)}}{-B} \cdot \sqrt{F} \]
                                  4. Recombined 2 regimes into one program.
                                  5. Final simplification24.9%

                                    \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 10^{+23}:\\ \;\;\;\;\frac{\sqrt{\left(\left(C \cdot 2\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(C + B\right) \cdot 2}}{B} \cdot \left(-\sqrt{F}\right)\\ \end{array} \]
                                  6. Add Preprocessing

                                  Alternative 8: 45.2% accurate, 2.9× speedup?

                                  \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;{B\_m}^{2} \leq 5 \cdot 10^{-141}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\left(C \cdot C\right) \cdot A\right) \cdot -16\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(C + B\_m\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\ \end{array} \end{array} \]
                                  B_m = (fabs.f64 B)
                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                  (FPCore (A B_m C F)
                                   :precision binary64
                                   (if (<= (pow B_m 2.0) 5e-141)
                                     (/ (sqrt (* (* (* (* C C) A) -16.0) F)) (- (fma (* C A) -4.0 (* B_m B_m))))
                                     (* (/ (sqrt (* (+ C B_m) 2.0)) B_m) (- (sqrt F)))))
                                  B_m = fabs(B);
                                  assert(A < B_m && B_m < C && C < F);
                                  double code(double A, double B_m, double C, double F) {
                                  	double tmp;
                                  	if (pow(B_m, 2.0) <= 5e-141) {
                                  		tmp = sqrt(((((C * C) * A) * -16.0) * F)) / -fma((C * A), -4.0, (B_m * B_m));
                                  	} else {
                                  		tmp = (sqrt(((C + B_m) * 2.0)) / B_m) * -sqrt(F);
                                  	}
                                  	return tmp;
                                  }
                                  
                                  B_m = abs(B)
                                  A, B_m, C, F = sort([A, B_m, C, F])
                                  function code(A, B_m, C, F)
                                  	tmp = 0.0
                                  	if ((B_m ^ 2.0) <= 5e-141)
                                  		tmp = Float64(sqrt(Float64(Float64(Float64(Float64(C * C) * A) * -16.0) * F)) / Float64(-fma(Float64(C * A), -4.0, Float64(B_m * B_m))));
                                  	else
                                  		tmp = Float64(Float64(sqrt(Float64(Float64(C + B_m) * 2.0)) / B_m) * Float64(-sqrt(F)));
                                  	end
                                  	return tmp
                                  end
                                  
                                  B_m = N[Abs[B], $MachinePrecision]
                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                  code[A_, B$95$m_, C_, F_] := If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 5e-141], N[(N[Sqrt[N[(N[(N[(N[(C * C), $MachinePrecision] * A), $MachinePrecision] * -16.0), $MachinePrecision] * F), $MachinePrecision]], $MachinePrecision] / (-N[(N[(C * A), $MachinePrecision] * -4.0 + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision])), $MachinePrecision], N[(N[(N[Sqrt[N[(N[(C + B$95$m), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / B$95$m), $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]]
                                  
                                  \begin{array}{l}
                                  B_m = \left|B\right|
                                  \\
                                  [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                  \\
                                  \begin{array}{l}
                                  \mathbf{if}\;{B\_m}^{2} \leq 5 \cdot 10^{-141}:\\
                                  \;\;\;\;\frac{\sqrt{\left(\left(\left(C \cdot C\right) \cdot A\right) \cdot -16\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)}\\
                                  
                                  \mathbf{else}:\\
                                  \;\;\;\;\frac{\sqrt{\left(C + B\_m\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\
                                  
                                  
                                  \end{array}
                                  \end{array}
                                  
                                  Derivation
                                  1. Split input into 2 regimes
                                  2. if (pow.f64 B #s(literal 2 binary64)) < 4.9999999999999999e-141

                                    1. Initial program 21.9%

                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    2. Add Preprocessing
                                    3. Applied rewrites30.7%

                                      \[\leadsto \color{blue}{\frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}}} \]
                                    4. Applied rewrites23.0%

                                      \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + \left(C + A\right)\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \]
                                    5. Taylor expanded in A around -inf

                                      \[\leadsto \frac{\sqrt{\color{blue}{\left(-16 \cdot \left(A \cdot {C}^{2}\right)\right)} \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]
                                    6. Step-by-step derivation
                                      1. lower-*.f64N/A

                                        \[\leadsto \frac{\sqrt{\color{blue}{\left(-16 \cdot \left(A \cdot {C}^{2}\right)\right)} \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]
                                      2. lower-*.f64N/A

                                        \[\leadsto \frac{\sqrt{\left(-16 \cdot \color{blue}{\left(A \cdot {C}^{2}\right)}\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]
                                      3. unpow2N/A

                                        \[\leadsto \frac{\sqrt{\left(-16 \cdot \left(A \cdot \color{blue}{\left(C \cdot C\right)}\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]
                                      4. lower-*.f6416.8

                                        \[\leadsto \frac{\sqrt{\left(-16 \cdot \left(A \cdot \color{blue}{\left(C \cdot C\right)}\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]
                                    7. Applied rewrites16.8%

                                      \[\leadsto \frac{\sqrt{\color{blue}{\left(-16 \cdot \left(A \cdot \left(C \cdot C\right)\right)\right)} \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]

                                    if 4.9999999999999999e-141 < (pow.f64 B #s(literal 2 binary64))

                                    1. Initial program 18.2%

                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    2. Add Preprocessing
                                    3. Taylor expanded in A around 0

                                      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                    4. Step-by-step derivation
                                      1. associate-*r*N/A

                                        \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                      2. lower-*.f64N/A

                                        \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                      3. mul-1-negN/A

                                        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                      4. lower-neg.f64N/A

                                        \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                      5. lower-/.f64N/A

                                        \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                      6. lower-sqrt.f64N/A

                                        \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                      7. lower-sqrt.f64N/A

                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                      8. *-commutativeN/A

                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                      9. lower-*.f64N/A

                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                      10. +-commutativeN/A

                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                      11. lower-+.f64N/A

                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                      12. +-commutativeN/A

                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                                      13. unpow2N/A

                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                                      14. unpow2N/A

                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                                      15. lower-hypot.f6420.8

                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                                    5. Applied rewrites20.8%

                                      \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                                    6. Step-by-step derivation
                                      1. Applied rewrites30.2%

                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                                      2. Step-by-step derivation
                                        1. Applied rewrites30.3%

                                          \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                                        2. Taylor expanded in C around 0

                                          \[\leadsto \frac{\sqrt{2 \cdot \left(B + C\right)}}{-B} \cdot \sqrt{F} \]
                                        3. Step-by-step derivation
                                          1. Applied rewrites26.0%

                                            \[\leadsto \frac{\sqrt{2 \cdot \left(C + B\right)}}{-B} \cdot \sqrt{F} \]
                                        4. Recombined 2 regimes into one program.
                                        5. Final simplification22.3%

                                          \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 5 \cdot 10^{-141}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\left(C \cdot C\right) \cdot A\right) \cdot -16\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(C + B\right) \cdot 2}}{B} \cdot \left(-\sqrt{F}\right)\\ \end{array} \]
                                        6. Add Preprocessing

                                        Alternative 9: 45.2% accurate, 2.9× speedup?

                                        \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;{B\_m}^{2} \leq 5 \cdot 10^{-141}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\left(C \cdot C\right) \cdot F\right) \cdot A\right) \cdot -16}}{-\mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(C + B\_m\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\ \end{array} \end{array} \]
                                        B_m = (fabs.f64 B)
                                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                        (FPCore (A B_m C F)
                                         :precision binary64
                                         (if (<= (pow B_m 2.0) 5e-141)
                                           (/ (sqrt (* (* (* (* C C) F) A) -16.0)) (- (fma (* C A) -4.0 (* B_m B_m))))
                                           (* (/ (sqrt (* (+ C B_m) 2.0)) B_m) (- (sqrt F)))))
                                        B_m = fabs(B);
                                        assert(A < B_m && B_m < C && C < F);
                                        double code(double A, double B_m, double C, double F) {
                                        	double tmp;
                                        	if (pow(B_m, 2.0) <= 5e-141) {
                                        		tmp = sqrt(((((C * C) * F) * A) * -16.0)) / -fma((C * A), -4.0, (B_m * B_m));
                                        	} else {
                                        		tmp = (sqrt(((C + B_m) * 2.0)) / B_m) * -sqrt(F);
                                        	}
                                        	return tmp;
                                        }
                                        
                                        B_m = abs(B)
                                        A, B_m, C, F = sort([A, B_m, C, F])
                                        function code(A, B_m, C, F)
                                        	tmp = 0.0
                                        	if ((B_m ^ 2.0) <= 5e-141)
                                        		tmp = Float64(sqrt(Float64(Float64(Float64(Float64(C * C) * F) * A) * -16.0)) / Float64(-fma(Float64(C * A), -4.0, Float64(B_m * B_m))));
                                        	else
                                        		tmp = Float64(Float64(sqrt(Float64(Float64(C + B_m) * 2.0)) / B_m) * Float64(-sqrt(F)));
                                        	end
                                        	return tmp
                                        end
                                        
                                        B_m = N[Abs[B], $MachinePrecision]
                                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                        code[A_, B$95$m_, C_, F_] := If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 5e-141], N[(N[Sqrt[N[(N[(N[(N[(C * C), $MachinePrecision] * F), $MachinePrecision] * A), $MachinePrecision] * -16.0), $MachinePrecision]], $MachinePrecision] / (-N[(N[(C * A), $MachinePrecision] * -4.0 + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision])), $MachinePrecision], N[(N[(N[Sqrt[N[(N[(C + B$95$m), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / B$95$m), $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]]
                                        
                                        \begin{array}{l}
                                        B_m = \left|B\right|
                                        \\
                                        [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                        \\
                                        \begin{array}{l}
                                        \mathbf{if}\;{B\_m}^{2} \leq 5 \cdot 10^{-141}:\\
                                        \;\;\;\;\frac{\sqrt{\left(\left(\left(C \cdot C\right) \cdot F\right) \cdot A\right) \cdot -16}}{-\mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)}\\
                                        
                                        \mathbf{else}:\\
                                        \;\;\;\;\frac{\sqrt{\left(C + B\_m\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\
                                        
                                        
                                        \end{array}
                                        \end{array}
                                        
                                        Derivation
                                        1. Split input into 2 regimes
                                        2. if (pow.f64 B #s(literal 2 binary64)) < 4.9999999999999999e-141

                                          1. Initial program 21.9%

                                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                          2. Add Preprocessing
                                          3. Applied rewrites30.7%

                                            \[\leadsto \color{blue}{\frac{-1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}}} \]
                                          4. Applied rewrites23.0%

                                            \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + \left(C + A\right)\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)\right) \cdot F}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \]
                                          5. Taylor expanded in A around -inf

                                            \[\leadsto \frac{\sqrt{\color{blue}{-16 \cdot \left(A \cdot \left({C}^{2} \cdot F\right)\right)}}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]
                                          6. Step-by-step derivation
                                            1. lower-*.f64N/A

                                              \[\leadsto \frac{\sqrt{\color{blue}{-16 \cdot \left(A \cdot \left({C}^{2} \cdot F\right)\right)}}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]
                                            2. lower-*.f64N/A

                                              \[\leadsto \frac{\sqrt{-16 \cdot \color{blue}{\left(A \cdot \left({C}^{2} \cdot F\right)\right)}}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]
                                            3. lower-*.f64N/A

                                              \[\leadsto \frac{\sqrt{-16 \cdot \left(A \cdot \color{blue}{\left({C}^{2} \cdot F\right)}\right)}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]
                                            4. unpow2N/A

                                              \[\leadsto \frac{\sqrt{-16 \cdot \left(A \cdot \left(\color{blue}{\left(C \cdot C\right)} \cdot F\right)\right)}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]
                                            5. lower-*.f6417.3

                                              \[\leadsto \frac{\sqrt{-16 \cdot \left(A \cdot \left(\color{blue}{\left(C \cdot C\right)} \cdot F\right)\right)}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]
                                          7. Applied rewrites17.3%

                                            \[\leadsto \frac{\sqrt{\color{blue}{-16 \cdot \left(A \cdot \left(\left(C \cdot C\right) \cdot F\right)\right)}}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \]

                                          if 4.9999999999999999e-141 < (pow.f64 B #s(literal 2 binary64))

                                          1. Initial program 18.2%

                                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                          2. Add Preprocessing
                                          3. Taylor expanded in A around 0

                                            \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                          4. Step-by-step derivation
                                            1. associate-*r*N/A

                                              \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                            2. lower-*.f64N/A

                                              \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                            3. mul-1-negN/A

                                              \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                            4. lower-neg.f64N/A

                                              \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                            5. lower-/.f64N/A

                                              \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                            6. lower-sqrt.f64N/A

                                              \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                            7. lower-sqrt.f64N/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                            8. *-commutativeN/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                            9. lower-*.f64N/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                            10. +-commutativeN/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                            11. lower-+.f64N/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                            12. +-commutativeN/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                                            13. unpow2N/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                                            14. unpow2N/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                                            15. lower-hypot.f6420.8

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                                          5. Applied rewrites20.8%

                                            \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                                          6. Step-by-step derivation
                                            1. Applied rewrites30.2%

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                                            2. Step-by-step derivation
                                              1. Applied rewrites30.3%

                                                \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                                              2. Taylor expanded in C around 0

                                                \[\leadsto \frac{\sqrt{2 \cdot \left(B + C\right)}}{-B} \cdot \sqrt{F} \]
                                              3. Step-by-step derivation
                                                1. Applied rewrites26.0%

                                                  \[\leadsto \frac{\sqrt{2 \cdot \left(C + B\right)}}{-B} \cdot \sqrt{F} \]
                                              4. Recombined 2 regimes into one program.
                                              5. Final simplification22.5%

                                                \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 5 \cdot 10^{-141}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\left(C \cdot C\right) \cdot F\right) \cdot A\right) \cdot -16}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(C + B\right) \cdot 2}}{B} \cdot \left(-\sqrt{F}\right)\\ \end{array} \]
                                              6. Add Preprocessing

                                              Alternative 10: 36.6% accurate, 10.4× speedup?

                                              \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \frac{\sqrt{\left(C + B\_m\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right) \end{array} \]
                                              B_m = (fabs.f64 B)
                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                              (FPCore (A B_m C F)
                                               :precision binary64
                                               (* (/ (sqrt (* (+ C B_m) 2.0)) B_m) (- (sqrt F))))
                                              B_m = fabs(B);
                                              assert(A < B_m && B_m < C && C < F);
                                              double code(double A, double B_m, double C, double F) {
                                              	return (sqrt(((C + B_m) * 2.0)) / B_m) * -sqrt(F);
                                              }
                                              
                                              B_m = abs(b)
                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                              real(8) function code(a, b_m, c, f)
                                                  real(8), intent (in) :: a
                                                  real(8), intent (in) :: b_m
                                                  real(8), intent (in) :: c
                                                  real(8), intent (in) :: f
                                                  code = (sqrt(((c + b_m) * 2.0d0)) / b_m) * -sqrt(f)
                                              end function
                                              
                                              B_m = Math.abs(B);
                                              assert A < B_m && B_m < C && C < F;
                                              public static double code(double A, double B_m, double C, double F) {
                                              	return (Math.sqrt(((C + B_m) * 2.0)) / B_m) * -Math.sqrt(F);
                                              }
                                              
                                              B_m = math.fabs(B)
                                              [A, B_m, C, F] = sort([A, B_m, C, F])
                                              def code(A, B_m, C, F):
                                              	return (math.sqrt(((C + B_m) * 2.0)) / B_m) * -math.sqrt(F)
                                              
                                              B_m = abs(B)
                                              A, B_m, C, F = sort([A, B_m, C, F])
                                              function code(A, B_m, C, F)
                                              	return Float64(Float64(sqrt(Float64(Float64(C + B_m) * 2.0)) / B_m) * Float64(-sqrt(F)))
                                              end
                                              
                                              B_m = abs(B);
                                              A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                              function tmp = code(A, B_m, C, F)
                                              	tmp = (sqrt(((C + B_m) * 2.0)) / B_m) * -sqrt(F);
                                              end
                                              
                                              B_m = N[Abs[B], $MachinePrecision]
                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                              code[A_, B$95$m_, C_, F_] := N[(N[(N[Sqrt[N[(N[(C + B$95$m), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / B$95$m), $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]
                                              
                                              \begin{array}{l}
                                              B_m = \left|B\right|
                                              \\
                                              [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                              \\
                                              \frac{\sqrt{\left(C + B\_m\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)
                                              \end{array}
                                              
                                              Derivation
                                              1. Initial program 19.7%

                                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              2. Add Preprocessing
                                              3. Taylor expanded in A around 0

                                                \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                              4. Step-by-step derivation
                                                1. associate-*r*N/A

                                                  \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                2. lower-*.f64N/A

                                                  \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                3. mul-1-negN/A

                                                  \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                4. lower-neg.f64N/A

                                                  \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                5. lower-/.f64N/A

                                                  \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                6. lower-sqrt.f64N/A

                                                  \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                7. lower-sqrt.f64N/A

                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                8. *-commutativeN/A

                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                9. lower-*.f64N/A

                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                10. +-commutativeN/A

                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                11. lower-+.f64N/A

                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                12. +-commutativeN/A

                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                                                13. unpow2N/A

                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                                                14. unpow2N/A

                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                                                15. lower-hypot.f6414.1

                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                                              5. Applied rewrites14.1%

                                                \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                                              6. Step-by-step derivation
                                                1. Applied rewrites19.8%

                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                                                2. Step-by-step derivation
                                                  1. Applied rewrites19.9%

                                                    \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                                                  2. Taylor expanded in C around 0

                                                    \[\leadsto \frac{\sqrt{2 \cdot \left(B + C\right)}}{-B} \cdot \sqrt{F} \]
                                                  3. Step-by-step derivation
                                                    1. Applied rewrites16.3%

                                                      \[\leadsto \frac{\sqrt{2 \cdot \left(C + B\right)}}{-B} \cdot \sqrt{F} \]
                                                    2. Final simplification16.3%

                                                      \[\leadsto \frac{\sqrt{\left(C + B\right) \cdot 2}}{B} \cdot \left(-\sqrt{F}\right) \]
                                                    3. Add Preprocessing

                                                    Alternative 11: 36.0% accurate, 12.6× speedup?

                                                    \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \frac{\sqrt{F \cdot 2}}{-\sqrt{B\_m}} \end{array} \]
                                                    B_m = (fabs.f64 B)
                                                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                    (FPCore (A B_m C F) :precision binary64 (/ (sqrt (* F 2.0)) (- (sqrt B_m))))
                                                    B_m = fabs(B);
                                                    assert(A < B_m && B_m < C && C < F);
                                                    double code(double A, double B_m, double C, double F) {
                                                    	return sqrt((F * 2.0)) / -sqrt(B_m);
                                                    }
                                                    
                                                    B_m = abs(b)
                                                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                    real(8) function code(a, b_m, c, f)
                                                        real(8), intent (in) :: a
                                                        real(8), intent (in) :: b_m
                                                        real(8), intent (in) :: c
                                                        real(8), intent (in) :: f
                                                        code = sqrt((f * 2.0d0)) / -sqrt(b_m)
                                                    end function
                                                    
                                                    B_m = Math.abs(B);
                                                    assert A < B_m && B_m < C && C < F;
                                                    public static double code(double A, double B_m, double C, double F) {
                                                    	return Math.sqrt((F * 2.0)) / -Math.sqrt(B_m);
                                                    }
                                                    
                                                    B_m = math.fabs(B)
                                                    [A, B_m, C, F] = sort([A, B_m, C, F])
                                                    def code(A, B_m, C, F):
                                                    	return math.sqrt((F * 2.0)) / -math.sqrt(B_m)
                                                    
                                                    B_m = abs(B)
                                                    A, B_m, C, F = sort([A, B_m, C, F])
                                                    function code(A, B_m, C, F)
                                                    	return Float64(sqrt(Float64(F * 2.0)) / Float64(-sqrt(B_m)))
                                                    end
                                                    
                                                    B_m = abs(B);
                                                    A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                    function tmp = code(A, B_m, C, F)
                                                    	tmp = sqrt((F * 2.0)) / -sqrt(B_m);
                                                    end
                                                    
                                                    B_m = N[Abs[B], $MachinePrecision]
                                                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                    code[A_, B$95$m_, C_, F_] := N[(N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision] / (-N[Sqrt[B$95$m], $MachinePrecision])), $MachinePrecision]
                                                    
                                                    \begin{array}{l}
                                                    B_m = \left|B\right|
                                                    \\
                                                    [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                    \\
                                                    \frac{\sqrt{F \cdot 2}}{-\sqrt{B\_m}}
                                                    \end{array}
                                                    
                                                    Derivation
                                                    1. Initial program 19.7%

                                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                    2. Add Preprocessing
                                                    3. Taylor expanded in B around inf

                                                      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                    4. Step-by-step derivation
                                                      1. mul-1-negN/A

                                                        \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                      2. *-commutativeN/A

                                                        \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                      3. distribute-lft-neg-inN/A

                                                        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                      4. lower-*.f64N/A

                                                        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                      5. lower-neg.f64N/A

                                                        \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
                                                      6. lower-sqrt.f64N/A

                                                        \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
                                                      7. lower-sqrt.f64N/A

                                                        \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
                                                      8. lower-/.f6412.8

                                                        \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                    5. Applied rewrites12.8%

                                                      \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                    6. Step-by-step derivation
                                                      1. Applied rewrites12.8%

                                                        \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                      2. Step-by-step derivation
                                                        1. Applied rewrites16.7%

                                                          \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
                                                        2. Final simplification16.7%

                                                          \[\leadsto \frac{\sqrt{F \cdot 2}}{-\sqrt{B}} \]
                                                        3. Add Preprocessing

                                                        Alternative 12: 36.1% accurate, 12.6× speedup?

                                                        \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \frac{-\sqrt{F}}{\sqrt{0.5 \cdot B\_m}} \end{array} \]
                                                        B_m = (fabs.f64 B)
                                                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                        (FPCore (A B_m C F) :precision binary64 (/ (- (sqrt F)) (sqrt (* 0.5 B_m))))
                                                        B_m = fabs(B);
                                                        assert(A < B_m && B_m < C && C < F);
                                                        double code(double A, double B_m, double C, double F) {
                                                        	return -sqrt(F) / sqrt((0.5 * B_m));
                                                        }
                                                        
                                                        B_m = abs(b)
                                                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                        real(8) function code(a, b_m, c, f)
                                                            real(8), intent (in) :: a
                                                            real(8), intent (in) :: b_m
                                                            real(8), intent (in) :: c
                                                            real(8), intent (in) :: f
                                                            code = -sqrt(f) / sqrt((0.5d0 * b_m))
                                                        end function
                                                        
                                                        B_m = Math.abs(B);
                                                        assert A < B_m && B_m < C && C < F;
                                                        public static double code(double A, double B_m, double C, double F) {
                                                        	return -Math.sqrt(F) / Math.sqrt((0.5 * B_m));
                                                        }
                                                        
                                                        B_m = math.fabs(B)
                                                        [A, B_m, C, F] = sort([A, B_m, C, F])
                                                        def code(A, B_m, C, F):
                                                        	return -math.sqrt(F) / math.sqrt((0.5 * B_m))
                                                        
                                                        B_m = abs(B)
                                                        A, B_m, C, F = sort([A, B_m, C, F])
                                                        function code(A, B_m, C, F)
                                                        	return Float64(Float64(-sqrt(F)) / sqrt(Float64(0.5 * B_m)))
                                                        end
                                                        
                                                        B_m = abs(B);
                                                        A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                        function tmp = code(A, B_m, C, F)
                                                        	tmp = -sqrt(F) / sqrt((0.5 * B_m));
                                                        end
                                                        
                                                        B_m = N[Abs[B], $MachinePrecision]
                                                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                        code[A_, B$95$m_, C_, F_] := N[((-N[Sqrt[F], $MachinePrecision]) / N[Sqrt[N[(0.5 * B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
                                                        
                                                        \begin{array}{l}
                                                        B_m = \left|B\right|
                                                        \\
                                                        [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                        \\
                                                        \frac{-\sqrt{F}}{\sqrt{0.5 \cdot B\_m}}
                                                        \end{array}
                                                        
                                                        Derivation
                                                        1. Initial program 19.7%

                                                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                        2. Add Preprocessing
                                                        3. Taylor expanded in B around inf

                                                          \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                        4. Step-by-step derivation
                                                          1. mul-1-negN/A

                                                            \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                          2. *-commutativeN/A

                                                            \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                          3. distribute-lft-neg-inN/A

                                                            \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                          4. lower-*.f64N/A

                                                            \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                          5. lower-neg.f64N/A

                                                            \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
                                                          6. lower-sqrt.f64N/A

                                                            \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
                                                          7. lower-sqrt.f64N/A

                                                            \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
                                                          8. lower-/.f6412.8

                                                            \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                        5. Applied rewrites12.8%

                                                          \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                        6. Step-by-step derivation
                                                          1. Applied rewrites12.8%

                                                            \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                          2. Step-by-step derivation
                                                            1. Applied rewrites12.8%

                                                              \[\leadsto -\sqrt{F \cdot \frac{2}{B}} \]
                                                            2. Step-by-step derivation
                                                              1. Applied rewrites16.7%

                                                                \[\leadsto -\frac{\sqrt{F}}{\sqrt{B \cdot 0.5}} \]
                                                              2. Final simplification16.7%

                                                                \[\leadsto \frac{-\sqrt{F}}{\sqrt{0.5 \cdot B}} \]
                                                              3. Add Preprocessing

                                                              Alternative 13: 36.0% accurate, 12.6× speedup?

                                                              \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}} \end{array} \]
                                                              B_m = (fabs.f64 B)
                                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                              (FPCore (A B_m C F) :precision binary64 (* (- (sqrt F)) (sqrt (/ 2.0 B_m))))
                                                              B_m = fabs(B);
                                                              assert(A < B_m && B_m < C && C < F);
                                                              double code(double A, double B_m, double C, double F) {
                                                              	return -sqrt(F) * sqrt((2.0 / B_m));
                                                              }
                                                              
                                                              B_m = abs(b)
                                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                              real(8) function code(a, b_m, c, f)
                                                                  real(8), intent (in) :: a
                                                                  real(8), intent (in) :: b_m
                                                                  real(8), intent (in) :: c
                                                                  real(8), intent (in) :: f
                                                                  code = -sqrt(f) * sqrt((2.0d0 / b_m))
                                                              end function
                                                              
                                                              B_m = Math.abs(B);
                                                              assert A < B_m && B_m < C && C < F;
                                                              public static double code(double A, double B_m, double C, double F) {
                                                              	return -Math.sqrt(F) * Math.sqrt((2.0 / B_m));
                                                              }
                                                              
                                                              B_m = math.fabs(B)
                                                              [A, B_m, C, F] = sort([A, B_m, C, F])
                                                              def code(A, B_m, C, F):
                                                              	return -math.sqrt(F) * math.sqrt((2.0 / B_m))
                                                              
                                                              B_m = abs(B)
                                                              A, B_m, C, F = sort([A, B_m, C, F])
                                                              function code(A, B_m, C, F)
                                                              	return Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)))
                                                              end
                                                              
                                                              B_m = abs(B);
                                                              A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                              function tmp = code(A, B_m, C, F)
                                                              	tmp = -sqrt(F) * sqrt((2.0 / B_m));
                                                              end
                                                              
                                                              B_m = N[Abs[B], $MachinePrecision]
                                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                              code[A_, B$95$m_, C_, F_] := N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
                                                              
                                                              \begin{array}{l}
                                                              B_m = \left|B\right|
                                                              \\
                                                              [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                              \\
                                                              \left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}
                                                              \end{array}
                                                              
                                                              Derivation
                                                              1. Initial program 19.7%

                                                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                              2. Add Preprocessing
                                                              3. Taylor expanded in B around inf

                                                                \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                              4. Step-by-step derivation
                                                                1. mul-1-negN/A

                                                                  \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                2. *-commutativeN/A

                                                                  \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                3. distribute-lft-neg-inN/A

                                                                  \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                4. lower-*.f64N/A

                                                                  \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                5. lower-neg.f64N/A

                                                                  \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
                                                                6. lower-sqrt.f64N/A

                                                                  \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
                                                                7. lower-sqrt.f64N/A

                                                                  \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
                                                                8. lower-/.f6412.8

                                                                  \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                              5. Applied rewrites12.8%

                                                                \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                              6. Step-by-step derivation
                                                                1. Applied rewrites12.8%

                                                                  \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                2. Step-by-step derivation
                                                                  1. Applied rewrites16.6%

                                                                    \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                                                  2. Final simplification16.6%

                                                                    \[\leadsto \left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}} \]
                                                                  3. Add Preprocessing

                                                                  Alternative 14: 27.5% accurate, 16.9× speedup?

                                                                  \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ -\sqrt{\frac{F}{B\_m} \cdot 2} \end{array} \]
                                                                  B_m = (fabs.f64 B)
                                                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                  (FPCore (A B_m C F) :precision binary64 (- (sqrt (* (/ F B_m) 2.0))))
                                                                  B_m = fabs(B);
                                                                  assert(A < B_m && B_m < C && C < F);
                                                                  double code(double A, double B_m, double C, double F) {
                                                                  	return -sqrt(((F / B_m) * 2.0));
                                                                  }
                                                                  
                                                                  B_m = abs(b)
                                                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                  real(8) function code(a, b_m, c, f)
                                                                      real(8), intent (in) :: a
                                                                      real(8), intent (in) :: b_m
                                                                      real(8), intent (in) :: c
                                                                      real(8), intent (in) :: f
                                                                      code = -sqrt(((f / b_m) * 2.0d0))
                                                                  end function
                                                                  
                                                                  B_m = Math.abs(B);
                                                                  assert A < B_m && B_m < C && C < F;
                                                                  public static double code(double A, double B_m, double C, double F) {
                                                                  	return -Math.sqrt(((F / B_m) * 2.0));
                                                                  }
                                                                  
                                                                  B_m = math.fabs(B)
                                                                  [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                  def code(A, B_m, C, F):
                                                                  	return -math.sqrt(((F / B_m) * 2.0))
                                                                  
                                                                  B_m = abs(B)
                                                                  A, B_m, C, F = sort([A, B_m, C, F])
                                                                  function code(A, B_m, C, F)
                                                                  	return Float64(-sqrt(Float64(Float64(F / B_m) * 2.0)))
                                                                  end
                                                                  
                                                                  B_m = abs(B);
                                                                  A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                  function tmp = code(A, B_m, C, F)
                                                                  	tmp = -sqrt(((F / B_m) * 2.0));
                                                                  end
                                                                  
                                                                  B_m = N[Abs[B], $MachinePrecision]
                                                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                  code[A_, B$95$m_, C_, F_] := (-N[Sqrt[N[(N[(F / B$95$m), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision])
                                                                  
                                                                  \begin{array}{l}
                                                                  B_m = \left|B\right|
                                                                  \\
                                                                  [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                  \\
                                                                  -\sqrt{\frac{F}{B\_m} \cdot 2}
                                                                  \end{array}
                                                                  
                                                                  Derivation
                                                                  1. Initial program 19.7%

                                                                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                  2. Add Preprocessing
                                                                  3. Taylor expanded in B around inf

                                                                    \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                  4. Step-by-step derivation
                                                                    1. mul-1-negN/A

                                                                      \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                    2. *-commutativeN/A

                                                                      \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                    3. distribute-lft-neg-inN/A

                                                                      \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                    4. lower-*.f64N/A

                                                                      \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                    5. lower-neg.f64N/A

                                                                      \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
                                                                    6. lower-sqrt.f64N/A

                                                                      \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
                                                                    7. lower-sqrt.f64N/A

                                                                      \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
                                                                    8. lower-/.f6412.8

                                                                      \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                                  5. Applied rewrites12.8%

                                                                    \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                  6. Step-by-step derivation
                                                                    1. Applied rewrites12.8%

                                                                      \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                    2. Add Preprocessing

                                                                    Alternative 15: 27.5% accurate, 16.9× speedup?

                                                                    \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ -\sqrt{\frac{2}{B\_m} \cdot F} \end{array} \]
                                                                    B_m = (fabs.f64 B)
                                                                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                    (FPCore (A B_m C F) :precision binary64 (- (sqrt (* (/ 2.0 B_m) F))))
                                                                    B_m = fabs(B);
                                                                    assert(A < B_m && B_m < C && C < F);
                                                                    double code(double A, double B_m, double C, double F) {
                                                                    	return -sqrt(((2.0 / B_m) * F));
                                                                    }
                                                                    
                                                                    B_m = abs(b)
                                                                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                    real(8) function code(a, b_m, c, f)
                                                                        real(8), intent (in) :: a
                                                                        real(8), intent (in) :: b_m
                                                                        real(8), intent (in) :: c
                                                                        real(8), intent (in) :: f
                                                                        code = -sqrt(((2.0d0 / b_m) * f))
                                                                    end function
                                                                    
                                                                    B_m = Math.abs(B);
                                                                    assert A < B_m && B_m < C && C < F;
                                                                    public static double code(double A, double B_m, double C, double F) {
                                                                    	return -Math.sqrt(((2.0 / B_m) * F));
                                                                    }
                                                                    
                                                                    B_m = math.fabs(B)
                                                                    [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                    def code(A, B_m, C, F):
                                                                    	return -math.sqrt(((2.0 / B_m) * F))
                                                                    
                                                                    B_m = abs(B)
                                                                    A, B_m, C, F = sort([A, B_m, C, F])
                                                                    function code(A, B_m, C, F)
                                                                    	return Float64(-sqrt(Float64(Float64(2.0 / B_m) * F)))
                                                                    end
                                                                    
                                                                    B_m = abs(B);
                                                                    A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                    function tmp = code(A, B_m, C, F)
                                                                    	tmp = -sqrt(((2.0 / B_m) * F));
                                                                    end
                                                                    
                                                                    B_m = N[Abs[B], $MachinePrecision]
                                                                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                    code[A_, B$95$m_, C_, F_] := (-N[Sqrt[N[(N[(2.0 / B$95$m), $MachinePrecision] * F), $MachinePrecision]], $MachinePrecision])
                                                                    
                                                                    \begin{array}{l}
                                                                    B_m = \left|B\right|
                                                                    \\
                                                                    [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                    \\
                                                                    -\sqrt{\frac{2}{B\_m} \cdot F}
                                                                    \end{array}
                                                                    
                                                                    Derivation
                                                                    1. Initial program 19.7%

                                                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                    2. Add Preprocessing
                                                                    3. Taylor expanded in B around inf

                                                                      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                    4. Step-by-step derivation
                                                                      1. mul-1-negN/A

                                                                        \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                      2. *-commutativeN/A

                                                                        \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                                      3. distribute-lft-neg-inN/A

                                                                        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                      4. lower-*.f64N/A

                                                                        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                      5. lower-neg.f64N/A

                                                                        \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
                                                                      6. lower-sqrt.f64N/A

                                                                        \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
                                                                      7. lower-sqrt.f64N/A

                                                                        \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
                                                                      8. lower-/.f6412.8

                                                                        \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                                    5. Applied rewrites12.8%

                                                                      \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                                    6. Step-by-step derivation
                                                                      1. Applied rewrites12.8%

                                                                        \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                      2. Step-by-step derivation
                                                                        1. Applied rewrites12.8%

                                                                          \[\leadsto -\sqrt{F \cdot \frac{2}{B}} \]
                                                                        2. Final simplification12.8%

                                                                          \[\leadsto -\sqrt{\frac{2}{B} \cdot F} \]
                                                                        3. Add Preprocessing

                                                                        Reproduce

                                                                        ?
                                                                        herbie shell --seed 2024331 
                                                                        (FPCore (A B C F)
                                                                          :name "ABCF->ab-angle a"
                                                                          :precision binary64
                                                                          (/ (- (sqrt (* (* 2.0 (* (- (pow B 2.0) (* (* 4.0 A) C)) F)) (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))) (- (pow B 2.0) (* (* 4.0 A) C))))