Numeric.SpecFunctions:invIncompleteBetaWorker from math-functions-0.1.5.2, F

Percentage Accurate: 78.3% → 99.5%
Time: 8.2s
Alternatives: 6
Speedup: 1.8×

Specification

?
\[\begin{array}{l} \\ \frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \end{array} \]
(FPCore (x y) :precision binary64 (/ (exp (* x (log (/ x (+ x y))))) x))
double code(double x, double y) {
	return exp((x * log((x / (x + y))))) / x;
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = exp((x * log((x / (x + y))))) / x
end function
public static double code(double x, double y) {
	return Math.exp((x * Math.log((x / (x + y))))) / x;
}
def code(x, y):
	return math.exp((x * math.log((x / (x + y))))) / x
function code(x, y)
	return Float64(exp(Float64(x * log(Float64(x / Float64(x + y))))) / x)
end
function tmp = code(x, y)
	tmp = exp((x * log((x / (x + y))))) / x;
end
code[x_, y_] := N[(N[Exp[N[(x * N[Log[N[(x / N[(x + y), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / x), $MachinePrecision]
\begin{array}{l}

\\
\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 6 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 78.3% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \end{array} \]
(FPCore (x y) :precision binary64 (/ (exp (* x (log (/ x (+ x y))))) x))
double code(double x, double y) {
	return exp((x * log((x / (x + y))))) / x;
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = exp((x * log((x / (x + y))))) / x
end function
public static double code(double x, double y) {
	return Math.exp((x * Math.log((x / (x + y))))) / x;
}
def code(x, y):
	return math.exp((x * math.log((x / (x + y))))) / x
function code(x, y)
	return Float64(exp(Float64(x * log(Float64(x / Float64(x + y))))) / x)
end
function tmp = code(x, y)
	tmp = exp((x * log((x / (x + y))))) / x;
end
code[x_, y_] := N[(N[Exp[N[(x * N[Log[N[(x / N[(x + y), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / x), $MachinePrecision]
\begin{array}{l}

\\
\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x}
\end{array}

Alternative 1: 99.5% accurate, 1.8× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq -16.5 \lor \neg \left(x \leq 1.3\right):\\ \;\;\;\;\frac{e^{-y}}{x}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{x}\\ \end{array} \end{array} \]
(FPCore (x y)
 :precision binary64
 (if (or (<= x -16.5) (not (<= x 1.3))) (/ (exp (- y)) x) (/ 1.0 x)))
double code(double x, double y) {
	double tmp;
	if ((x <= -16.5) || !(x <= 1.3)) {
		tmp = exp(-y) / x;
	} else {
		tmp = 1.0 / x;
	}
	return tmp;
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8) :: tmp
    if ((x <= (-16.5d0)) .or. (.not. (x <= 1.3d0))) then
        tmp = exp(-y) / x
    else
        tmp = 1.0d0 / x
    end if
    code = tmp
end function
public static double code(double x, double y) {
	double tmp;
	if ((x <= -16.5) || !(x <= 1.3)) {
		tmp = Math.exp(-y) / x;
	} else {
		tmp = 1.0 / x;
	}
	return tmp;
}
def code(x, y):
	tmp = 0
	if (x <= -16.5) or not (x <= 1.3):
		tmp = math.exp(-y) / x
	else:
		tmp = 1.0 / x
	return tmp
function code(x, y)
	tmp = 0.0
	if ((x <= -16.5) || !(x <= 1.3))
		tmp = Float64(exp(Float64(-y)) / x);
	else
		tmp = Float64(1.0 / x);
	end
	return tmp
end
function tmp_2 = code(x, y)
	tmp = 0.0;
	if ((x <= -16.5) || ~((x <= 1.3)))
		tmp = exp(-y) / x;
	else
		tmp = 1.0 / x;
	end
	tmp_2 = tmp;
end
code[x_, y_] := If[Or[LessEqual[x, -16.5], N[Not[LessEqual[x, 1.3]], $MachinePrecision]], N[(N[Exp[(-y)], $MachinePrecision] / x), $MachinePrecision], N[(1.0 / x), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;x \leq -16.5 \lor \neg \left(x \leq 1.3\right):\\
\;\;\;\;\frac{e^{-y}}{x}\\

\mathbf{else}:\\
\;\;\;\;\frac{1}{x}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if x < -16.5 or 1.30000000000000004 < x

    1. Initial program 72.6%

      \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
    2. Add Preprocessing
    3. Taylor expanded in x around inf

      \[\leadsto \frac{e^{\color{blue}{-1 \cdot y}}}{x} \]
    4. Step-by-step derivation
      1. mul-1-negN/A

        \[\leadsto \frac{e^{\color{blue}{\mathsf{neg}\left(y\right)}}}{x} \]
      2. lower-neg.f64100.0

        \[\leadsto \frac{e^{\color{blue}{-y}}}{x} \]
    5. Applied rewrites100.0%

      \[\leadsto \frac{e^{\color{blue}{-y}}}{x} \]

    if -16.5 < x < 1.30000000000000004

    1. Initial program 84.9%

      \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \frac{\color{blue}{1}}{x} \]
    4. Step-by-step derivation
      1. Applied rewrites98.6%

        \[\leadsto \frac{\color{blue}{1}}{x} \]
    5. Recombined 2 regimes into one program.
    6. Final simplification99.5%

      \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -16.5 \lor \neg \left(x \leq 1.3\right):\\ \;\;\;\;\frac{e^{-y}}{x}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{x}\\ \end{array} \]
    7. Add Preprocessing

    Alternative 2: 76.9% accurate, 3.1× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \leq -22:\\ \;\;\;\;\frac{\mathsf{fma}\left(\left(\frac{\left(-0.16666666666666666 \cdot x - 0.5\right) \cdot x - 0.3333333333333333}{x} \cdot \frac{y}{x}\right) \cdot y - 1, y, 1\right)}{x}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{x}\\ \end{array} \end{array} \]
    (FPCore (x y)
     :precision binary64
     (if (<= y -22.0)
       (/
        (fma
         (-
          (*
           (*
            (/ (- (* (- (* -0.16666666666666666 x) 0.5) x) 0.3333333333333333) x)
            (/ y x))
           y)
          1.0)
         y
         1.0)
        x)
       (/ 1.0 x)))
    double code(double x, double y) {
    	double tmp;
    	if (y <= -22.0) {
    		tmp = fma(((((((((-0.16666666666666666 * x) - 0.5) * x) - 0.3333333333333333) / x) * (y / x)) * y) - 1.0), y, 1.0) / x;
    	} else {
    		tmp = 1.0 / x;
    	}
    	return tmp;
    }
    
    function code(x, y)
    	tmp = 0.0
    	if (y <= -22.0)
    		tmp = Float64(fma(Float64(Float64(Float64(Float64(Float64(Float64(Float64(Float64(-0.16666666666666666 * x) - 0.5) * x) - 0.3333333333333333) / x) * Float64(y / x)) * y) - 1.0), y, 1.0) / x);
    	else
    		tmp = Float64(1.0 / x);
    	end
    	return tmp
    end
    
    code[x_, y_] := If[LessEqual[y, -22.0], N[(N[(N[(N[(N[(N[(N[(N[(N[(N[(-0.16666666666666666 * x), $MachinePrecision] - 0.5), $MachinePrecision] * x), $MachinePrecision] - 0.3333333333333333), $MachinePrecision] / x), $MachinePrecision] * N[(y / x), $MachinePrecision]), $MachinePrecision] * y), $MachinePrecision] - 1.0), $MachinePrecision] * y + 1.0), $MachinePrecision] / x), $MachinePrecision], N[(1.0 / x), $MachinePrecision]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;y \leq -22:\\
    \;\;\;\;\frac{\mathsf{fma}\left(\left(\frac{\left(-0.16666666666666666 \cdot x - 0.5\right) \cdot x - 0.3333333333333333}{x} \cdot \frac{y}{x}\right) \cdot y - 1, y, 1\right)}{x}\\
    
    \mathbf{else}:\\
    \;\;\;\;\frac{1}{x}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 2 regimes
    2. if y < -22

      1. Initial program 39.2%

        \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
      2. Add Preprocessing
      3. Taylor expanded in y around 0

        \[\leadsto \frac{\color{blue}{1 + y \cdot \left(y \cdot \left(\frac{1}{2} + \left(-1 \cdot \left(y \cdot \left(\frac{1}{6} + \left(\frac{1}{3} \cdot \frac{1}{{x}^{2}} + \frac{1}{2} \cdot \frac{1}{x}\right)\right)\right) + \frac{1}{2} \cdot \frac{1}{x}\right)\right) - 1\right)}}{x} \]
      4. Step-by-step derivation
        1. +-commutativeN/A

          \[\leadsto \frac{\color{blue}{y \cdot \left(y \cdot \left(\frac{1}{2} + \left(-1 \cdot \left(y \cdot \left(\frac{1}{6} + \left(\frac{1}{3} \cdot \frac{1}{{x}^{2}} + \frac{1}{2} \cdot \frac{1}{x}\right)\right)\right) + \frac{1}{2} \cdot \frac{1}{x}\right)\right) - 1\right) + 1}}{x} \]
        2. *-commutativeN/A

          \[\leadsto \frac{\color{blue}{\left(y \cdot \left(\frac{1}{2} + \left(-1 \cdot \left(y \cdot \left(\frac{1}{6} + \left(\frac{1}{3} \cdot \frac{1}{{x}^{2}} + \frac{1}{2} \cdot \frac{1}{x}\right)\right)\right) + \frac{1}{2} \cdot \frac{1}{x}\right)\right) - 1\right) \cdot y} + 1}{x} \]
        3. lower-fma.f64N/A

          \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(y \cdot \left(\frac{1}{2} + \left(-1 \cdot \left(y \cdot \left(\frac{1}{6} + \left(\frac{1}{3} \cdot \frac{1}{{x}^{2}} + \frac{1}{2} \cdot \frac{1}{x}\right)\right)\right) + \frac{1}{2} \cdot \frac{1}{x}\right)\right) - 1, y, 1\right)}}{x} \]
      5. Applied rewrites51.1%

        \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\left(0.16666666666666666 - \frac{-0.3333333333333333}{x \cdot x}\right) - \frac{-0.5}{x}, -y, \frac{0.5}{x} + 0.5\right) \cdot y - 1, y, 1\right)}}{x} \]
      6. Taylor expanded in x around 0

        \[\leadsto \frac{\mathsf{fma}\left(\frac{\frac{-1}{3} \cdot y + x \cdot \left(\frac{1}{2} + \left(\frac{-1}{2} \cdot y + x \cdot \left(\frac{1}{2} + \frac{-1}{6} \cdot y\right)\right)\right)}{{x}^{2}} \cdot y - 1, y, 1\right)}{x} \]
      7. Step-by-step derivation
        1. Applied rewrites18.0%

          \[\leadsto \frac{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(-0.16666666666666666, y, 0.5\right), x, \mathsf{fma}\left(-0.5, y, 0.5\right)\right), x, -0.3333333333333333 \cdot y\right)}{x \cdot x} \cdot y - 1, y, 1\right)}{x} \]
        2. Taylor expanded in y around inf

          \[\leadsto \frac{\mathsf{fma}\left(\frac{y \cdot \left(x \cdot \left(\frac{-1}{6} \cdot x - \frac{1}{2}\right) - \frac{1}{3}\right)}{{x}^{2}} \cdot y - 1, y, 1\right)}{x} \]
        3. Step-by-step derivation
          1. Applied rewrites66.9%

            \[\leadsto \frac{\mathsf{fma}\left(\left(\frac{\left(-0.16666666666666666 \cdot x - 0.5\right) \cdot x - 0.3333333333333333}{x} \cdot \frac{y}{x}\right) \cdot y - 1, y, 1\right)}{x} \]

          if -22 < y

          1. Initial program 84.5%

            \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
          2. Add Preprocessing
          3. Taylor expanded in x around 0

            \[\leadsto \frac{\color{blue}{1}}{x} \]
          4. Step-by-step derivation
            1. Applied rewrites81.1%

              \[\leadsto \frac{\color{blue}{1}}{x} \]
          5. Recombined 2 regimes into one program.
          6. Add Preprocessing

          Alternative 3: 76.5% accurate, 5.1× speedup?

          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \leq -8 \cdot 10^{+64}:\\ \;\;\;\;\frac{\frac{\left(\mathsf{fma}\left(0.5, x, 0.5\right) \cdot y\right) \cdot y}{x}}{x}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{x}\\ \end{array} \end{array} \]
          (FPCore (x y)
           :precision binary64
           (if (<= y -8e+64) (/ (/ (* (* (fma 0.5 x 0.5) y) y) x) x) (/ 1.0 x)))
          double code(double x, double y) {
          	double tmp;
          	if (y <= -8e+64) {
          		tmp = (((fma(0.5, x, 0.5) * y) * y) / x) / x;
          	} else {
          		tmp = 1.0 / x;
          	}
          	return tmp;
          }
          
          function code(x, y)
          	tmp = 0.0
          	if (y <= -8e+64)
          		tmp = Float64(Float64(Float64(Float64(fma(0.5, x, 0.5) * y) * y) / x) / x);
          	else
          		tmp = Float64(1.0 / x);
          	end
          	return tmp
          end
          
          code[x_, y_] := If[LessEqual[y, -8e+64], N[(N[(N[(N[(N[(0.5 * x + 0.5), $MachinePrecision] * y), $MachinePrecision] * y), $MachinePrecision] / x), $MachinePrecision] / x), $MachinePrecision], N[(1.0 / x), $MachinePrecision]]
          
          \begin{array}{l}
          
          \\
          \begin{array}{l}
          \mathbf{if}\;y \leq -8 \cdot 10^{+64}:\\
          \;\;\;\;\frac{\frac{\left(\mathsf{fma}\left(0.5, x, 0.5\right) \cdot y\right) \cdot y}{x}}{x}\\
          
          \mathbf{else}:\\
          \;\;\;\;\frac{1}{x}\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if y < -8.00000000000000017e64

            1. Initial program 45.5%

              \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
            2. Add Preprocessing
            3. Taylor expanded in y around 0

              \[\leadsto \frac{\color{blue}{1 + y \cdot \left(y \cdot \left(\frac{1}{2} + \frac{1}{2} \cdot \frac{1}{x}\right) - 1\right)}}{x} \]
            4. Step-by-step derivation
              1. +-commutativeN/A

                \[\leadsto \frac{\color{blue}{y \cdot \left(y \cdot \left(\frac{1}{2} + \frac{1}{2} \cdot \frac{1}{x}\right) - 1\right) + 1}}{x} \]
              2. *-commutativeN/A

                \[\leadsto \frac{\color{blue}{\left(y \cdot \left(\frac{1}{2} + \frac{1}{2} \cdot \frac{1}{x}\right) - 1\right) \cdot y} + 1}{x} \]
              3. lower-fma.f64N/A

                \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(y \cdot \left(\frac{1}{2} + \frac{1}{2} \cdot \frac{1}{x}\right) - 1, y, 1\right)}}{x} \]
              4. lower--.f64N/A

                \[\leadsto \frac{\mathsf{fma}\left(\color{blue}{y \cdot \left(\frac{1}{2} + \frac{1}{2} \cdot \frac{1}{x}\right) - 1}, y, 1\right)}{x} \]
              5. *-commutativeN/A

                \[\leadsto \frac{\mathsf{fma}\left(\color{blue}{\left(\frac{1}{2} + \frac{1}{2} \cdot \frac{1}{x}\right) \cdot y} - 1, y, 1\right)}{x} \]
              6. lower-*.f64N/A

                \[\leadsto \frac{\mathsf{fma}\left(\color{blue}{\left(\frac{1}{2} + \frac{1}{2} \cdot \frac{1}{x}\right) \cdot y} - 1, y, 1\right)}{x} \]
              7. +-commutativeN/A

                \[\leadsto \frac{\mathsf{fma}\left(\color{blue}{\left(\frac{1}{2} \cdot \frac{1}{x} + \frac{1}{2}\right)} \cdot y - 1, y, 1\right)}{x} \]
              8. lower-+.f64N/A

                \[\leadsto \frac{\mathsf{fma}\left(\color{blue}{\left(\frac{1}{2} \cdot \frac{1}{x} + \frac{1}{2}\right)} \cdot y - 1, y, 1\right)}{x} \]
              9. associate-*r/N/A

                \[\leadsto \frac{\mathsf{fma}\left(\left(\color{blue}{\frac{\frac{1}{2} \cdot 1}{x}} + \frac{1}{2}\right) \cdot y - 1, y, 1\right)}{x} \]
              10. metadata-evalN/A

                \[\leadsto \frac{\mathsf{fma}\left(\left(\frac{\color{blue}{\frac{1}{2}}}{x} + \frac{1}{2}\right) \cdot y - 1, y, 1\right)}{x} \]
              11. lower-/.f6457.4

                \[\leadsto \frac{\mathsf{fma}\left(\left(\color{blue}{\frac{0.5}{x}} + 0.5\right) \cdot y - 1, y, 1\right)}{x} \]
            5. Applied rewrites57.4%

              \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(\left(\frac{0.5}{x} + 0.5\right) \cdot y - 1, y, 1\right)}}{x} \]
            6. Taylor expanded in x around 0

              \[\leadsto \frac{\frac{\frac{1}{2} \cdot {y}^{2} + x \cdot \left(1 + y \cdot \left(\frac{1}{2} \cdot y - 1\right)\right)}{\color{blue}{x}}}{x} \]
            7. Step-by-step derivation
              1. Applied rewrites44.1%

                \[\leadsto \frac{\frac{\mathsf{fma}\left(\mathsf{fma}\left(0.5 \cdot y - 1, y, 1\right), x, \left(y \cdot y\right) \cdot 0.5\right)}{\color{blue}{x}}}{x} \]
              2. Taylor expanded in y around inf

                \[\leadsto \frac{\frac{{y}^{2} \cdot \left(\frac{1}{2} + \frac{1}{2} \cdot x\right)}{x}}{x} \]
              3. Step-by-step derivation
                1. Applied rewrites78.5%

                  \[\leadsto \frac{\frac{\left(\mathsf{fma}\left(0.5, x, 0.5\right) \cdot y\right) \cdot y}{x}}{x} \]

                if -8.00000000000000017e64 < y

                1. Initial program 81.4%

                  \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
                2. Add Preprocessing
                3. Taylor expanded in x around 0

                  \[\leadsto \frac{\color{blue}{1}}{x} \]
                4. Step-by-step derivation
                  1. Applied rewrites77.7%

                    \[\leadsto \frac{\color{blue}{1}}{x} \]
                5. Recombined 2 regimes into one program.
                6. Add Preprocessing

                Alternative 4: 76.7% accurate, 6.8× speedup?

                \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \leq -1.3 \cdot 10^{+111}:\\ \;\;\;\;\frac{\mathsf{fma}\left(-0.16666666666666666 \cdot \left(y \cdot y\right), y, 1\right)}{x}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{x}\\ \end{array} \end{array} \]
                (FPCore (x y)
                 :precision binary64
                 (if (<= y -1.3e+111)
                   (/ (fma (* -0.16666666666666666 (* y y)) y 1.0) x)
                   (/ 1.0 x)))
                double code(double x, double y) {
                	double tmp;
                	if (y <= -1.3e+111) {
                		tmp = fma((-0.16666666666666666 * (y * y)), y, 1.0) / x;
                	} else {
                		tmp = 1.0 / x;
                	}
                	return tmp;
                }
                
                function code(x, y)
                	tmp = 0.0
                	if (y <= -1.3e+111)
                		tmp = Float64(fma(Float64(-0.16666666666666666 * Float64(y * y)), y, 1.0) / x);
                	else
                		tmp = Float64(1.0 / x);
                	end
                	return tmp
                end
                
                code[x_, y_] := If[LessEqual[y, -1.3e+111], N[(N[(N[(-0.16666666666666666 * N[(y * y), $MachinePrecision]), $MachinePrecision] * y + 1.0), $MachinePrecision] / x), $MachinePrecision], N[(1.0 / x), $MachinePrecision]]
                
                \begin{array}{l}
                
                \\
                \begin{array}{l}
                \mathbf{if}\;y \leq -1.3 \cdot 10^{+111}:\\
                \;\;\;\;\frac{\mathsf{fma}\left(-0.16666666666666666 \cdot \left(y \cdot y\right), y, 1\right)}{x}\\
                
                \mathbf{else}:\\
                \;\;\;\;\frac{1}{x}\\
                
                
                \end{array}
                \end{array}
                
                Derivation
                1. Split input into 2 regimes
                2. if y < -1.2999999999999999e111

                  1. Initial program 55.4%

                    \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
                  2. Add Preprocessing
                  3. Taylor expanded in y around 0

                    \[\leadsto \frac{\color{blue}{1 + y \cdot \left(y \cdot \left(\frac{1}{2} + \left(-1 \cdot \left(y \cdot \left(\frac{1}{6} + \left(\frac{1}{3} \cdot \frac{1}{{x}^{2}} + \frac{1}{2} \cdot \frac{1}{x}\right)\right)\right) + \frac{1}{2} \cdot \frac{1}{x}\right)\right) - 1\right)}}{x} \]
                  4. Step-by-step derivation
                    1. +-commutativeN/A

                      \[\leadsto \frac{\color{blue}{y \cdot \left(y \cdot \left(\frac{1}{2} + \left(-1 \cdot \left(y \cdot \left(\frac{1}{6} + \left(\frac{1}{3} \cdot \frac{1}{{x}^{2}} + \frac{1}{2} \cdot \frac{1}{x}\right)\right)\right) + \frac{1}{2} \cdot \frac{1}{x}\right)\right) - 1\right) + 1}}{x} \]
                    2. *-commutativeN/A

                      \[\leadsto \frac{\color{blue}{\left(y \cdot \left(\frac{1}{2} + \left(-1 \cdot \left(y \cdot \left(\frac{1}{6} + \left(\frac{1}{3} \cdot \frac{1}{{x}^{2}} + \frac{1}{2} \cdot \frac{1}{x}\right)\right)\right) + \frac{1}{2} \cdot \frac{1}{x}\right)\right) - 1\right) \cdot y} + 1}{x} \]
                    3. lower-fma.f64N/A

                      \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(y \cdot \left(\frac{1}{2} + \left(-1 \cdot \left(y \cdot \left(\frac{1}{6} + \left(\frac{1}{3} \cdot \frac{1}{{x}^{2}} + \frac{1}{2} \cdot \frac{1}{x}\right)\right)\right) + \frac{1}{2} \cdot \frac{1}{x}\right)\right) - 1, y, 1\right)}}{x} \]
                  5. Applied rewrites82.0%

                    \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\left(0.16666666666666666 - \frac{-0.3333333333333333}{x \cdot x}\right) - \frac{-0.5}{x}, -y, \frac{0.5}{x} + 0.5\right) \cdot y - 1, y, 1\right)}}{x} \]
                  6. Taylor expanded in x around inf

                    \[\leadsto \frac{\mathsf{fma}\left(\left(\frac{1}{2} + \frac{-1}{6} \cdot y\right) \cdot y - 1, y, 1\right)}{x} \]
                  7. Step-by-step derivation
                    1. Applied rewrites82.0%

                      \[\leadsto \frac{\mathsf{fma}\left(\mathsf{fma}\left(-0.16666666666666666, y, 0.5\right) \cdot y - 1, y, 1\right)}{x} \]
                    2. Taylor expanded in y around inf

                      \[\leadsto \frac{\mathsf{fma}\left(-1 \cdot \left({y}^{2} \cdot \left(\frac{1}{6} + \left(\frac{1}{3} \cdot \frac{1}{{x}^{2}} + \frac{1}{2} \cdot \frac{1}{x}\right)\right)\right), y, 1\right)}{x} \]
                    3. Step-by-step derivation
                      1. Applied rewrites82.0%

                        \[\leadsto \frac{\mathsf{fma}\left(\left(-\left(\left(0.16666666666666666 + \frac{0.5}{x}\right) + \frac{0.3333333333333333}{x \cdot x}\right)\right) \cdot \left(y \cdot y\right), y, 1\right)}{x} \]
                      2. Taylor expanded in x around inf

                        \[\leadsto \frac{\mathsf{fma}\left(\frac{-1}{6} \cdot \left(y \cdot y\right), y, 1\right)}{x} \]
                      3. Step-by-step derivation
                        1. Applied rewrites82.0%

                          \[\leadsto \frac{\mathsf{fma}\left(-0.16666666666666666 \cdot \left(y \cdot y\right), y, 1\right)}{x} \]

                        if -1.2999999999999999e111 < y

                        1. Initial program 79.4%

                          \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
                        2. Add Preprocessing
                        3. Taylor expanded in x around 0

                          \[\leadsto \frac{\color{blue}{1}}{x} \]
                        4. Step-by-step derivation
                          1. Applied rewrites76.2%

                            \[\leadsto \frac{\color{blue}{1}}{x} \]
                        5. Recombined 2 regimes into one program.
                        6. Add Preprocessing

                        Alternative 5: 75.0% accurate, 7.2× speedup?

                        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \leq -1 \cdot 10^{+113}:\\ \;\;\;\;\frac{\mathsf{fma}\left(0.5 \cdot y - 1, y, 1\right)}{x}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{x}\\ \end{array} \end{array} \]
                        (FPCore (x y)
                         :precision binary64
                         (if (<= y -1e+113) (/ (fma (- (* 0.5 y) 1.0) y 1.0) x) (/ 1.0 x)))
                        double code(double x, double y) {
                        	double tmp;
                        	if (y <= -1e+113) {
                        		tmp = fma(((0.5 * y) - 1.0), y, 1.0) / x;
                        	} else {
                        		tmp = 1.0 / x;
                        	}
                        	return tmp;
                        }
                        
                        function code(x, y)
                        	tmp = 0.0
                        	if (y <= -1e+113)
                        		tmp = Float64(fma(Float64(Float64(0.5 * y) - 1.0), y, 1.0) / x);
                        	else
                        		tmp = Float64(1.0 / x);
                        	end
                        	return tmp
                        end
                        
                        code[x_, y_] := If[LessEqual[y, -1e+113], N[(N[(N[(N[(0.5 * y), $MachinePrecision] - 1.0), $MachinePrecision] * y + 1.0), $MachinePrecision] / x), $MachinePrecision], N[(1.0 / x), $MachinePrecision]]
                        
                        \begin{array}{l}
                        
                        \\
                        \begin{array}{l}
                        \mathbf{if}\;y \leq -1 \cdot 10^{+113}:\\
                        \;\;\;\;\frac{\mathsf{fma}\left(0.5 \cdot y - 1, y, 1\right)}{x}\\
                        
                        \mathbf{else}:\\
                        \;\;\;\;\frac{1}{x}\\
                        
                        
                        \end{array}
                        \end{array}
                        
                        Derivation
                        1. Split input into 2 regimes
                        2. if y < -1e113

                          1. Initial program 55.4%

                            \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
                          2. Add Preprocessing
                          3. Taylor expanded in y around 0

                            \[\leadsto \frac{\color{blue}{1 + y \cdot \left(y \cdot \left(\frac{1}{2} + \frac{1}{2} \cdot \frac{1}{x}\right) - 1\right)}}{x} \]
                          4. Step-by-step derivation
                            1. +-commutativeN/A

                              \[\leadsto \frac{\color{blue}{y \cdot \left(y \cdot \left(\frac{1}{2} + \frac{1}{2} \cdot \frac{1}{x}\right) - 1\right) + 1}}{x} \]
                            2. *-commutativeN/A

                              \[\leadsto \frac{\color{blue}{\left(y \cdot \left(\frac{1}{2} + \frac{1}{2} \cdot \frac{1}{x}\right) - 1\right) \cdot y} + 1}{x} \]
                            3. lower-fma.f64N/A

                              \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(y \cdot \left(\frac{1}{2} + \frac{1}{2} \cdot \frac{1}{x}\right) - 1, y, 1\right)}}{x} \]
                            4. lower--.f64N/A

                              \[\leadsto \frac{\mathsf{fma}\left(\color{blue}{y \cdot \left(\frac{1}{2} + \frac{1}{2} \cdot \frac{1}{x}\right) - 1}, y, 1\right)}{x} \]
                            5. *-commutativeN/A

                              \[\leadsto \frac{\mathsf{fma}\left(\color{blue}{\left(\frac{1}{2} + \frac{1}{2} \cdot \frac{1}{x}\right) \cdot y} - 1, y, 1\right)}{x} \]
                            6. lower-*.f64N/A

                              \[\leadsto \frac{\mathsf{fma}\left(\color{blue}{\left(\frac{1}{2} + \frac{1}{2} \cdot \frac{1}{x}\right) \cdot y} - 1, y, 1\right)}{x} \]
                            7. +-commutativeN/A

                              \[\leadsto \frac{\mathsf{fma}\left(\color{blue}{\left(\frac{1}{2} \cdot \frac{1}{x} + \frac{1}{2}\right)} \cdot y - 1, y, 1\right)}{x} \]
                            8. lower-+.f64N/A

                              \[\leadsto \frac{\mathsf{fma}\left(\color{blue}{\left(\frac{1}{2} \cdot \frac{1}{x} + \frac{1}{2}\right)} \cdot y - 1, y, 1\right)}{x} \]
                            9. associate-*r/N/A

                              \[\leadsto \frac{\mathsf{fma}\left(\left(\color{blue}{\frac{\frac{1}{2} \cdot 1}{x}} + \frac{1}{2}\right) \cdot y - 1, y, 1\right)}{x} \]
                            10. metadata-evalN/A

                              \[\leadsto \frac{\mathsf{fma}\left(\left(\frac{\color{blue}{\frac{1}{2}}}{x} + \frac{1}{2}\right) \cdot y - 1, y, 1\right)}{x} \]
                            11. lower-/.f6470.1

                              \[\leadsto \frac{\mathsf{fma}\left(\left(\color{blue}{\frac{0.5}{x}} + 0.5\right) \cdot y - 1, y, 1\right)}{x} \]
                          5. Applied rewrites70.1%

                            \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(\left(\frac{0.5}{x} + 0.5\right) \cdot y - 1, y, 1\right)}}{x} \]
                          6. Taylor expanded in x around inf

                            \[\leadsto \frac{\mathsf{fma}\left(\frac{1}{2} \cdot y - 1, y, 1\right)}{x} \]
                          7. Step-by-step derivation
                            1. Applied rewrites71.2%

                              \[\leadsto \frac{\mathsf{fma}\left(0.5 \cdot y - 1, y, 1\right)}{x} \]

                            if -1e113 < y

                            1. Initial program 79.4%

                              \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
                            2. Add Preprocessing
                            3. Taylor expanded in x around 0

                              \[\leadsto \frac{\color{blue}{1}}{x} \]
                            4. Step-by-step derivation
                              1. Applied rewrites76.2%

                                \[\leadsto \frac{\color{blue}{1}}{x} \]
                            5. Recombined 2 regimes into one program.
                            6. Add Preprocessing

                            Alternative 6: 75.1% accurate, 19.3× speedup?

                            \[\begin{array}{l} \\ \frac{1}{x} \end{array} \]
                            (FPCore (x y) :precision binary64 (/ 1.0 x))
                            double code(double x, double y) {
                            	return 1.0 / x;
                            }
                            
                            real(8) function code(x, y)
                                real(8), intent (in) :: x
                                real(8), intent (in) :: y
                                code = 1.0d0 / x
                            end function
                            
                            public static double code(double x, double y) {
                            	return 1.0 / x;
                            }
                            
                            def code(x, y):
                            	return 1.0 / x
                            
                            function code(x, y)
                            	return Float64(1.0 / x)
                            end
                            
                            function tmp = code(x, y)
                            	tmp = 1.0 / x;
                            end
                            
                            code[x_, y_] := N[(1.0 / x), $MachinePrecision]
                            
                            \begin{array}{l}
                            
                            \\
                            \frac{1}{x}
                            \end{array}
                            
                            Derivation
                            1. Initial program 76.9%

                              \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
                            2. Add Preprocessing
                            3. Taylor expanded in x around 0

                              \[\leadsto \frac{\color{blue}{1}}{x} \]
                            4. Step-by-step derivation
                              1. Applied rewrites70.4%

                                \[\leadsto \frac{\color{blue}{1}}{x} \]
                              2. Add Preprocessing

                              Developer Target 1: 78.0% accurate, 0.7× speedup?

                              \[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{e^{\frac{-1}{y}}}{x}\\ t_1 := \frac{{\left(\frac{x}{y + x}\right)}^{x}}{x}\\ \mathbf{if}\;y < -3.7311844206647956 \cdot 10^{+94}:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;y < 2.817959242728288 \cdot 10^{+37}:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;y < 2.347387415166998 \cdot 10^{+178}:\\ \;\;\;\;\log \left(e^{t\_1}\right)\\ \mathbf{else}:\\ \;\;\;\;t\_0\\ \end{array} \end{array} \]
                              (FPCore (x y)
                               :precision binary64
                               (let* ((t_0 (/ (exp (/ -1.0 y)) x)) (t_1 (/ (pow (/ x (+ y x)) x) x)))
                                 (if (< y -3.7311844206647956e+94)
                                   t_0
                                   (if (< y 2.817959242728288e+37)
                                     t_1
                                     (if (< y 2.347387415166998e+178) (log (exp t_1)) t_0)))))
                              double code(double x, double y) {
                              	double t_0 = exp((-1.0 / y)) / x;
                              	double t_1 = pow((x / (y + x)), x) / x;
                              	double tmp;
                              	if (y < -3.7311844206647956e+94) {
                              		tmp = t_0;
                              	} else if (y < 2.817959242728288e+37) {
                              		tmp = t_1;
                              	} else if (y < 2.347387415166998e+178) {
                              		tmp = log(exp(t_1));
                              	} else {
                              		tmp = t_0;
                              	}
                              	return tmp;
                              }
                              
                              real(8) function code(x, y)
                                  real(8), intent (in) :: x
                                  real(8), intent (in) :: y
                                  real(8) :: t_0
                                  real(8) :: t_1
                                  real(8) :: tmp
                                  t_0 = exp(((-1.0d0) / y)) / x
                                  t_1 = ((x / (y + x)) ** x) / x
                                  if (y < (-3.7311844206647956d+94)) then
                                      tmp = t_0
                                  else if (y < 2.817959242728288d+37) then
                                      tmp = t_1
                                  else if (y < 2.347387415166998d+178) then
                                      tmp = log(exp(t_1))
                                  else
                                      tmp = t_0
                                  end if
                                  code = tmp
                              end function
                              
                              public static double code(double x, double y) {
                              	double t_0 = Math.exp((-1.0 / y)) / x;
                              	double t_1 = Math.pow((x / (y + x)), x) / x;
                              	double tmp;
                              	if (y < -3.7311844206647956e+94) {
                              		tmp = t_0;
                              	} else if (y < 2.817959242728288e+37) {
                              		tmp = t_1;
                              	} else if (y < 2.347387415166998e+178) {
                              		tmp = Math.log(Math.exp(t_1));
                              	} else {
                              		tmp = t_0;
                              	}
                              	return tmp;
                              }
                              
                              def code(x, y):
                              	t_0 = math.exp((-1.0 / y)) / x
                              	t_1 = math.pow((x / (y + x)), x) / x
                              	tmp = 0
                              	if y < -3.7311844206647956e+94:
                              		tmp = t_0
                              	elif y < 2.817959242728288e+37:
                              		tmp = t_1
                              	elif y < 2.347387415166998e+178:
                              		tmp = math.log(math.exp(t_1))
                              	else:
                              		tmp = t_0
                              	return tmp
                              
                              function code(x, y)
                              	t_0 = Float64(exp(Float64(-1.0 / y)) / x)
                              	t_1 = Float64((Float64(x / Float64(y + x)) ^ x) / x)
                              	tmp = 0.0
                              	if (y < -3.7311844206647956e+94)
                              		tmp = t_0;
                              	elseif (y < 2.817959242728288e+37)
                              		tmp = t_1;
                              	elseif (y < 2.347387415166998e+178)
                              		tmp = log(exp(t_1));
                              	else
                              		tmp = t_0;
                              	end
                              	return tmp
                              end
                              
                              function tmp_2 = code(x, y)
                              	t_0 = exp((-1.0 / y)) / x;
                              	t_1 = ((x / (y + x)) ^ x) / x;
                              	tmp = 0.0;
                              	if (y < -3.7311844206647956e+94)
                              		tmp = t_0;
                              	elseif (y < 2.817959242728288e+37)
                              		tmp = t_1;
                              	elseif (y < 2.347387415166998e+178)
                              		tmp = log(exp(t_1));
                              	else
                              		tmp = t_0;
                              	end
                              	tmp_2 = tmp;
                              end
                              
                              code[x_, y_] := Block[{t$95$0 = N[(N[Exp[N[(-1.0 / y), $MachinePrecision]], $MachinePrecision] / x), $MachinePrecision]}, Block[{t$95$1 = N[(N[Power[N[(x / N[(y + x), $MachinePrecision]), $MachinePrecision], x], $MachinePrecision] / x), $MachinePrecision]}, If[Less[y, -3.7311844206647956e+94], t$95$0, If[Less[y, 2.817959242728288e+37], t$95$1, If[Less[y, 2.347387415166998e+178], N[Log[N[Exp[t$95$1], $MachinePrecision]], $MachinePrecision], t$95$0]]]]]
                              
                              \begin{array}{l}
                              
                              \\
                              \begin{array}{l}
                              t_0 := \frac{e^{\frac{-1}{y}}}{x}\\
                              t_1 := \frac{{\left(\frac{x}{y + x}\right)}^{x}}{x}\\
                              \mathbf{if}\;y < -3.7311844206647956 \cdot 10^{+94}:\\
                              \;\;\;\;t\_0\\
                              
                              \mathbf{elif}\;y < 2.817959242728288 \cdot 10^{+37}:\\
                              \;\;\;\;t\_1\\
                              
                              \mathbf{elif}\;y < 2.347387415166998 \cdot 10^{+178}:\\
                              \;\;\;\;\log \left(e^{t\_1}\right)\\
                              
                              \mathbf{else}:\\
                              \;\;\;\;t\_0\\
                              
                              
                              \end{array}
                              \end{array}
                              

                              Reproduce

                              ?
                              herbie shell --seed 2024329 
                              (FPCore (x y)
                                :name "Numeric.SpecFunctions:invIncompleteBetaWorker from math-functions-0.1.5.2, F"
                                :precision binary64
                              
                                :alt
                                (! :herbie-platform default (if (< y -37311844206647956000000000000000000000000000000000000000000000000000000000000000000000000000000) (/ (exp (/ -1 y)) x) (if (< y 28179592427282880000000000000000000000) (/ (pow (/ x (+ y x)) x) x) (if (< y 23473874151669980000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000) (log (exp (/ (pow (/ x (+ y x)) x) x))) (/ (exp (/ -1 y)) x)))))
                              
                                (/ (exp (* x (log (/ x (+ x y))))) x))