Compound Interest

Percentage Accurate: 28.9% → 94.6%
Time: 11.4s
Alternatives: 15
Speedup: 24.3×

Specification

?
\[\begin{array}{l} \\ 100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \end{array} \]
(FPCore (i n)
 :precision binary64
 (* 100.0 (/ (- (pow (+ 1.0 (/ i n)) n) 1.0) (/ i n))))
double code(double i, double n) {
	return 100.0 * ((pow((1.0 + (i / n)), n) - 1.0) / (i / n));
}
real(8) function code(i, n)
    real(8), intent (in) :: i
    real(8), intent (in) :: n
    code = 100.0d0 * ((((1.0d0 + (i / n)) ** n) - 1.0d0) / (i / n))
end function
public static double code(double i, double n) {
	return 100.0 * ((Math.pow((1.0 + (i / n)), n) - 1.0) / (i / n));
}
def code(i, n):
	return 100.0 * ((math.pow((1.0 + (i / n)), n) - 1.0) / (i / n))
function code(i, n)
	return Float64(100.0 * Float64(Float64((Float64(1.0 + Float64(i / n)) ^ n) - 1.0) / Float64(i / n)))
end
function tmp = code(i, n)
	tmp = 100.0 * ((((1.0 + (i / n)) ^ n) - 1.0) / (i / n));
end
code[i_, n_] := N[(100.0 * N[(N[(N[Power[N[(1.0 + N[(i / n), $MachinePrecision]), $MachinePrecision], n], $MachinePrecision] - 1.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 15 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 28.9% accurate, 1.0× speedup?

\[\begin{array}{l} \\ 100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \end{array} \]
(FPCore (i n)
 :precision binary64
 (* 100.0 (/ (- (pow (+ 1.0 (/ i n)) n) 1.0) (/ i n))))
double code(double i, double n) {
	return 100.0 * ((pow((1.0 + (i / n)), n) - 1.0) / (i / n));
}
real(8) function code(i, n)
    real(8), intent (in) :: i
    real(8), intent (in) :: n
    code = 100.0d0 * ((((1.0d0 + (i / n)) ** n) - 1.0d0) / (i / n))
end function
public static double code(double i, double n) {
	return 100.0 * ((Math.pow((1.0 + (i / n)), n) - 1.0) / (i / n));
}
def code(i, n):
	return 100.0 * ((math.pow((1.0 + (i / n)), n) - 1.0) / (i / n))
function code(i, n)
	return Float64(100.0 * Float64(Float64((Float64(1.0 + Float64(i / n)) ^ n) - 1.0) / Float64(i / n)))
end
function tmp = code(i, n)
	tmp = 100.0 * ((((1.0 + (i / n)) ^ n) - 1.0) / (i / n));
end
code[i_, n_] := N[(100.0 * N[(N[(N[Power[N[(1.0 + N[(i / n), $MachinePrecision]), $MachinePrecision], n], $MachinePrecision] - 1.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}
\end{array}

Alternative 1: 94.6% accurate, 0.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := 1 + \frac{i}{n}\\ t_1 := \frac{{t\_0}^{n} - 1}{\frac{i}{n}}\\ \mathbf{if}\;t\_1 \leq 0:\\ \;\;\;\;\frac{\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right) \cdot 100}{\frac{i}{n}}\\ \mathbf{elif}\;t\_1 \leq \infty:\\ \;\;\;\;\frac{\mathsf{expm1}\left(\frac{n}{2} \cdot \log \left({t\_0}^{2}\right)\right) \cdot 100}{\frac{i}{n}}\\ \mathbf{else}:\\ \;\;\;\;100 \cdot n\\ \end{array} \end{array} \]
(FPCore (i n)
 :precision binary64
 (let* ((t_0 (+ 1.0 (/ i n))) (t_1 (/ (- (pow t_0 n) 1.0) (/ i n))))
   (if (<= t_1 0.0)
     (/ (* (expm1 (* (log1p (/ i n)) n)) 100.0) (/ i n))
     (if (<= t_1 INFINITY)
       (/ (* (expm1 (* (/ n 2.0) (log (pow t_0 2.0)))) 100.0) (/ i n))
       (* 100.0 n)))))
double code(double i, double n) {
	double t_0 = 1.0 + (i / n);
	double t_1 = (pow(t_0, n) - 1.0) / (i / n);
	double tmp;
	if (t_1 <= 0.0) {
		tmp = (expm1((log1p((i / n)) * n)) * 100.0) / (i / n);
	} else if (t_1 <= ((double) INFINITY)) {
		tmp = (expm1(((n / 2.0) * log(pow(t_0, 2.0)))) * 100.0) / (i / n);
	} else {
		tmp = 100.0 * n;
	}
	return tmp;
}
public static double code(double i, double n) {
	double t_0 = 1.0 + (i / n);
	double t_1 = (Math.pow(t_0, n) - 1.0) / (i / n);
	double tmp;
	if (t_1 <= 0.0) {
		tmp = (Math.expm1((Math.log1p((i / n)) * n)) * 100.0) / (i / n);
	} else if (t_1 <= Double.POSITIVE_INFINITY) {
		tmp = (Math.expm1(((n / 2.0) * Math.log(Math.pow(t_0, 2.0)))) * 100.0) / (i / n);
	} else {
		tmp = 100.0 * n;
	}
	return tmp;
}
def code(i, n):
	t_0 = 1.0 + (i / n)
	t_1 = (math.pow(t_0, n) - 1.0) / (i / n)
	tmp = 0
	if t_1 <= 0.0:
		tmp = (math.expm1((math.log1p((i / n)) * n)) * 100.0) / (i / n)
	elif t_1 <= math.inf:
		tmp = (math.expm1(((n / 2.0) * math.log(math.pow(t_0, 2.0)))) * 100.0) / (i / n)
	else:
		tmp = 100.0 * n
	return tmp
function code(i, n)
	t_0 = Float64(1.0 + Float64(i / n))
	t_1 = Float64(Float64((t_0 ^ n) - 1.0) / Float64(i / n))
	tmp = 0.0
	if (t_1 <= 0.0)
		tmp = Float64(Float64(expm1(Float64(log1p(Float64(i / n)) * n)) * 100.0) / Float64(i / n));
	elseif (t_1 <= Inf)
		tmp = Float64(Float64(expm1(Float64(Float64(n / 2.0) * log((t_0 ^ 2.0)))) * 100.0) / Float64(i / n));
	else
		tmp = Float64(100.0 * n);
	end
	return tmp
end
code[i_, n_] := Block[{t$95$0 = N[(1.0 + N[(i / n), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(N[Power[t$95$0, n], $MachinePrecision] - 1.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$1, 0.0], N[(N[(N[(Exp[N[(N[Log[1 + N[(i / n), $MachinePrecision]], $MachinePrecision] * n), $MachinePrecision]] - 1), $MachinePrecision] * 100.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$1, Infinity], N[(N[(N[(Exp[N[(N[(n / 2.0), $MachinePrecision] * N[Log[N[Power[t$95$0, 2.0], $MachinePrecision]], $MachinePrecision]), $MachinePrecision]] - 1), $MachinePrecision] * 100.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision], N[(100.0 * n), $MachinePrecision]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := 1 + \frac{i}{n}\\
t_1 := \frac{{t\_0}^{n} - 1}{\frac{i}{n}}\\
\mathbf{if}\;t\_1 \leq 0:\\
\;\;\;\;\frac{\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right) \cdot 100}{\frac{i}{n}}\\

\mathbf{elif}\;t\_1 \leq \infty:\\
\;\;\;\;\frac{\mathsf{expm1}\left(\frac{n}{2} \cdot \log \left({t\_0}^{2}\right)\right) \cdot 100}{\frac{i}{n}}\\

\mathbf{else}:\\
\;\;\;\;100 \cdot n\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (/.f64 (-.f64 (pow.f64 (+.f64 #s(literal 1 binary64) (/.f64 i n)) n) #s(literal 1 binary64)) (/.f64 i n)) < -0.0

    1. Initial program 27.3%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      2. lift-/.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      3. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\frac{i}{n}}} \]
      4. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\frac{i}{n}}} \]
      5. *-commutativeN/A

        \[\leadsto \frac{\color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right) \cdot 100}}{\frac{i}{n}} \]
      6. lower-*.f6427.3

        \[\leadsto \frac{\color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right) \cdot 100}}{\frac{i}{n}} \]
      7. lift--.f64N/A

        \[\leadsto \frac{\color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)} \cdot 100}{\frac{i}{n}} \]
      8. lift-pow.f64N/A

        \[\leadsto \frac{\left(\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n}} - 1\right) \cdot 100}{\frac{i}{n}} \]
      9. pow-to-expN/A

        \[\leadsto \frac{\left(\color{blue}{e^{\log \left(1 + \frac{i}{n}\right) \cdot n}} - 1\right) \cdot 100}{\frac{i}{n}} \]
      10. lower-expm1.f64N/A

        \[\leadsto \frac{\color{blue}{\mathsf{expm1}\left(\log \left(1 + \frac{i}{n}\right) \cdot n\right)} \cdot 100}{\frac{i}{n}} \]
      11. lower-*.f64N/A

        \[\leadsto \frac{\mathsf{expm1}\left(\color{blue}{\log \left(1 + \frac{i}{n}\right) \cdot n}\right) \cdot 100}{\frac{i}{n}} \]
      12. lift-+.f64N/A

        \[\leadsto \frac{\mathsf{expm1}\left(\log \color{blue}{\left(1 + \frac{i}{n}\right)} \cdot n\right) \cdot 100}{\frac{i}{n}} \]
      13. lower-log1p.f6498.0

        \[\leadsto \frac{\mathsf{expm1}\left(\color{blue}{\mathsf{log1p}\left(\frac{i}{n}\right)} \cdot n\right) \cdot 100}{\frac{i}{n}} \]
    4. Applied rewrites98.0%

      \[\leadsto \color{blue}{\frac{\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right) \cdot 100}{\frac{i}{n}}} \]

    if -0.0 < (/.f64 (-.f64 (pow.f64 (+.f64 #s(literal 1 binary64) (/.f64 i n)) n) #s(literal 1 binary64)) (/.f64 i n)) < +inf.0

    1. Initial program 97.5%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      2. lift-/.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      3. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\frac{i}{n}}} \]
      4. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\frac{i}{n}}} \]
      5. *-commutativeN/A

        \[\leadsto \frac{\color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right) \cdot 100}}{\frac{i}{n}} \]
      6. lower-*.f6497.5

        \[\leadsto \frac{\color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right) \cdot 100}}{\frac{i}{n}} \]
      7. lift--.f64N/A

        \[\leadsto \frac{\color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)} \cdot 100}{\frac{i}{n}} \]
      8. lift-pow.f64N/A

        \[\leadsto \frac{\left(\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n}} - 1\right) \cdot 100}{\frac{i}{n}} \]
      9. pow-to-expN/A

        \[\leadsto \frac{\left(\color{blue}{e^{\log \left(1 + \frac{i}{n}\right) \cdot n}} - 1\right) \cdot 100}{\frac{i}{n}} \]
      10. lower-expm1.f64N/A

        \[\leadsto \frac{\color{blue}{\mathsf{expm1}\left(\log \left(1 + \frac{i}{n}\right) \cdot n\right)} \cdot 100}{\frac{i}{n}} \]
      11. lower-*.f64N/A

        \[\leadsto \frac{\mathsf{expm1}\left(\color{blue}{\log \left(1 + \frac{i}{n}\right) \cdot n}\right) \cdot 100}{\frac{i}{n}} \]
      12. lift-+.f64N/A

        \[\leadsto \frac{\mathsf{expm1}\left(\log \color{blue}{\left(1 + \frac{i}{n}\right)} \cdot n\right) \cdot 100}{\frac{i}{n}} \]
      13. lower-log1p.f6465.1

        \[\leadsto \frac{\mathsf{expm1}\left(\color{blue}{\mathsf{log1p}\left(\frac{i}{n}\right)} \cdot n\right) \cdot 100}{\frac{i}{n}} \]
    4. Applied rewrites65.1%

      \[\leadsto \color{blue}{\frac{\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right) \cdot 100}{\frac{i}{n}}} \]
    5. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \frac{\mathsf{expm1}\left(\color{blue}{\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n}\right) \cdot 100}{\frac{i}{n}} \]
      2. *-commutativeN/A

        \[\leadsto \frac{\mathsf{expm1}\left(\color{blue}{n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)}\right) \cdot 100}{\frac{i}{n}} \]
      3. lift-log1p.f64N/A

        \[\leadsto \frac{\mathsf{expm1}\left(n \cdot \color{blue}{\log \left(1 + \frac{i}{n}\right)}\right) \cdot 100}{\frac{i}{n}} \]
      4. log-pow-revN/A

        \[\leadsto \frac{\mathsf{expm1}\left(\color{blue}{\log \left({\left(1 + \frac{i}{n}\right)}^{n}\right)}\right) \cdot 100}{\frac{i}{n}} \]
      5. sqr-powN/A

        \[\leadsto \frac{\mathsf{expm1}\left(\log \color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{\left(\frac{n}{2}\right)} \cdot {\left(1 + \frac{i}{n}\right)}^{\left(\frac{n}{2}\right)}\right)}\right) \cdot 100}{\frac{i}{n}} \]
      6. pow-prod-downN/A

        \[\leadsto \frac{\mathsf{expm1}\left(\log \color{blue}{\left({\left(\left(1 + \frac{i}{n}\right) \cdot \left(1 + \frac{i}{n}\right)\right)}^{\left(\frac{n}{2}\right)}\right)}\right) \cdot 100}{\frac{i}{n}} \]
      7. log-powN/A

        \[\leadsto \frac{\mathsf{expm1}\left(\color{blue}{\frac{n}{2} \cdot \log \left(\left(1 + \frac{i}{n}\right) \cdot \left(1 + \frac{i}{n}\right)\right)}\right) \cdot 100}{\frac{i}{n}} \]
      8. lower-*.f64N/A

        \[\leadsto \frac{\mathsf{expm1}\left(\color{blue}{\frac{n}{2} \cdot \log \left(\left(1 + \frac{i}{n}\right) \cdot \left(1 + \frac{i}{n}\right)\right)}\right) \cdot 100}{\frac{i}{n}} \]
      9. lower-/.f64N/A

        \[\leadsto \frac{\mathsf{expm1}\left(\color{blue}{\frac{n}{2}} \cdot \log \left(\left(1 + \frac{i}{n}\right) \cdot \left(1 + \frac{i}{n}\right)\right)\right) \cdot 100}{\frac{i}{n}} \]
      10. lower-log.f64N/A

        \[\leadsto \frac{\mathsf{expm1}\left(\frac{n}{2} \cdot \color{blue}{\log \left(\left(1 + \frac{i}{n}\right) \cdot \left(1 + \frac{i}{n}\right)\right)}\right) \cdot 100}{\frac{i}{n}} \]
      11. pow2N/A

        \[\leadsto \frac{\mathsf{expm1}\left(\frac{n}{2} \cdot \log \color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{2}\right)}\right) \cdot 100}{\frac{i}{n}} \]
      12. lower-pow.f64N/A

        \[\leadsto \frac{\mathsf{expm1}\left(\frac{n}{2} \cdot \log \color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{2}\right)}\right) \cdot 100}{\frac{i}{n}} \]
      13. lower-+.f6499.7

        \[\leadsto \frac{\mathsf{expm1}\left(\frac{n}{2} \cdot \log \left({\color{blue}{\left(1 + \frac{i}{n}\right)}}^{2}\right)\right) \cdot 100}{\frac{i}{n}} \]
    6. Applied rewrites99.7%

      \[\leadsto \frac{\mathsf{expm1}\left(\color{blue}{\frac{n}{2} \cdot \log \left({\left(1 + \frac{i}{n}\right)}^{2}\right)}\right) \cdot 100}{\frac{i}{n}} \]

    if +inf.0 < (/.f64 (-.f64 (pow.f64 (+.f64 #s(literal 1 binary64) (/.f64 i n)) n) #s(literal 1 binary64)) (/.f64 i n))

    1. Initial program 0.0%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Taylor expanded in i around 0

      \[\leadsto \color{blue}{100 \cdot n} \]
    4. Step-by-step derivation
      1. lower-*.f6474.6

        \[\leadsto \color{blue}{100 \cdot n} \]
    5. Applied rewrites74.6%

      \[\leadsto \color{blue}{100 \cdot n} \]
  3. Recombined 3 regimes into one program.
  4. Add Preprocessing

Alternative 2: 94.6% accurate, 0.3× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\\ \mathbf{if}\;t\_0 \leq 0:\\ \;\;\;\;\frac{\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right) \cdot 100}{\frac{i}{n}}\\ \mathbf{elif}\;t\_0 \leq \infty:\\ \;\;\;\;100 \cdot \mathsf{fma}\left(\frac{{\left(\frac{i}{n} + 1\right)}^{n}}{i}, n, \frac{-1}{i} \cdot n\right)\\ \mathbf{else}:\\ \;\;\;\;100 \cdot n\\ \end{array} \end{array} \]
(FPCore (i n)
 :precision binary64
 (let* ((t_0 (/ (- (pow (+ 1.0 (/ i n)) n) 1.0) (/ i n))))
   (if (<= t_0 0.0)
     (/ (* (expm1 (* (log1p (/ i n)) n)) 100.0) (/ i n))
     (if (<= t_0 INFINITY)
       (* 100.0 (fma (/ (pow (+ (/ i n) 1.0) n) i) n (* (/ -1.0 i) n)))
       (* 100.0 n)))))
double code(double i, double n) {
	double t_0 = (pow((1.0 + (i / n)), n) - 1.0) / (i / n);
	double tmp;
	if (t_0 <= 0.0) {
		tmp = (expm1((log1p((i / n)) * n)) * 100.0) / (i / n);
	} else if (t_0 <= ((double) INFINITY)) {
		tmp = 100.0 * fma((pow(((i / n) + 1.0), n) / i), n, ((-1.0 / i) * n));
	} else {
		tmp = 100.0 * n;
	}
	return tmp;
}
function code(i, n)
	t_0 = Float64(Float64((Float64(1.0 + Float64(i / n)) ^ n) - 1.0) / Float64(i / n))
	tmp = 0.0
	if (t_0 <= 0.0)
		tmp = Float64(Float64(expm1(Float64(log1p(Float64(i / n)) * n)) * 100.0) / Float64(i / n));
	elseif (t_0 <= Inf)
		tmp = Float64(100.0 * fma(Float64((Float64(Float64(i / n) + 1.0) ^ n) / i), n, Float64(Float64(-1.0 / i) * n)));
	else
		tmp = Float64(100.0 * n);
	end
	return tmp
end
code[i_, n_] := Block[{t$95$0 = N[(N[(N[Power[N[(1.0 + N[(i / n), $MachinePrecision]), $MachinePrecision], n], $MachinePrecision] - 1.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, 0.0], N[(N[(N[(Exp[N[(N[Log[1 + N[(i / n), $MachinePrecision]], $MachinePrecision] * n), $MachinePrecision]] - 1), $MachinePrecision] * 100.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$0, Infinity], N[(100.0 * N[(N[(N[Power[N[(N[(i / n), $MachinePrecision] + 1.0), $MachinePrecision], n], $MachinePrecision] / i), $MachinePrecision] * n + N[(N[(-1.0 / i), $MachinePrecision] * n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(100.0 * n), $MachinePrecision]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\\
\mathbf{if}\;t\_0 \leq 0:\\
\;\;\;\;\frac{\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right) \cdot 100}{\frac{i}{n}}\\

\mathbf{elif}\;t\_0 \leq \infty:\\
\;\;\;\;100 \cdot \mathsf{fma}\left(\frac{{\left(\frac{i}{n} + 1\right)}^{n}}{i}, n, \frac{-1}{i} \cdot n\right)\\

\mathbf{else}:\\
\;\;\;\;100 \cdot n\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (/.f64 (-.f64 (pow.f64 (+.f64 #s(literal 1 binary64) (/.f64 i n)) n) #s(literal 1 binary64)) (/.f64 i n)) < -0.0

    1. Initial program 27.3%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      2. lift-/.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      3. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\frac{i}{n}}} \]
      4. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\frac{i}{n}}} \]
      5. *-commutativeN/A

        \[\leadsto \frac{\color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right) \cdot 100}}{\frac{i}{n}} \]
      6. lower-*.f6427.3

        \[\leadsto \frac{\color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right) \cdot 100}}{\frac{i}{n}} \]
      7. lift--.f64N/A

        \[\leadsto \frac{\color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)} \cdot 100}{\frac{i}{n}} \]
      8. lift-pow.f64N/A

        \[\leadsto \frac{\left(\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n}} - 1\right) \cdot 100}{\frac{i}{n}} \]
      9. pow-to-expN/A

        \[\leadsto \frac{\left(\color{blue}{e^{\log \left(1 + \frac{i}{n}\right) \cdot n}} - 1\right) \cdot 100}{\frac{i}{n}} \]
      10. lower-expm1.f64N/A

        \[\leadsto \frac{\color{blue}{\mathsf{expm1}\left(\log \left(1 + \frac{i}{n}\right) \cdot n\right)} \cdot 100}{\frac{i}{n}} \]
      11. lower-*.f64N/A

        \[\leadsto \frac{\mathsf{expm1}\left(\color{blue}{\log \left(1 + \frac{i}{n}\right) \cdot n}\right) \cdot 100}{\frac{i}{n}} \]
      12. lift-+.f64N/A

        \[\leadsto \frac{\mathsf{expm1}\left(\log \color{blue}{\left(1 + \frac{i}{n}\right)} \cdot n\right) \cdot 100}{\frac{i}{n}} \]
      13. lower-log1p.f6498.0

        \[\leadsto \frac{\mathsf{expm1}\left(\color{blue}{\mathsf{log1p}\left(\frac{i}{n}\right)} \cdot n\right) \cdot 100}{\frac{i}{n}} \]
    4. Applied rewrites98.0%

      \[\leadsto \color{blue}{\frac{\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right) \cdot 100}{\frac{i}{n}}} \]

    if -0.0 < (/.f64 (-.f64 (pow.f64 (+.f64 #s(literal 1 binary64) (/.f64 i n)) n) #s(literal 1 binary64)) (/.f64 i n)) < +inf.0

    1. Initial program 97.5%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-/.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      2. lift--.f64N/A

        \[\leadsto 100 \cdot \frac{\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n} - 1}}{\frac{i}{n}} \]
      3. div-subN/A

        \[\leadsto 100 \cdot \color{blue}{\left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{\frac{i}{n}} - \frac{1}{\frac{i}{n}}\right)} \]
      4. lift-/.f64N/A

        \[\leadsto 100 \cdot \left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{\frac{i}{n}} - \frac{1}{\color{blue}{\frac{i}{n}}}\right) \]
      5. associate-/r/N/A

        \[\leadsto 100 \cdot \left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{\frac{i}{n}} - \color{blue}{\frac{1}{i} \cdot n}\right) \]
      6. fp-cancel-sub-sign-invN/A

        \[\leadsto 100 \cdot \color{blue}{\left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{\frac{i}{n}} + \left(\mathsf{neg}\left(\frac{1}{i}\right)\right) \cdot n\right)} \]
      7. lift-/.f64N/A

        \[\leadsto 100 \cdot \left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{\color{blue}{\frac{i}{n}}} + \left(\mathsf{neg}\left(\frac{1}{i}\right)\right) \cdot n\right) \]
      8. associate-/r/N/A

        \[\leadsto 100 \cdot \left(\color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot n} + \left(\mathsf{neg}\left(\frac{1}{i}\right)\right) \cdot n\right) \]
      9. lower-fma.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i}, n, \left(\mathsf{neg}\left(\frac{1}{i}\right)\right) \cdot n\right)} \]
      10. lower-/.f64N/A

        \[\leadsto 100 \cdot \mathsf{fma}\left(\color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i}}, n, \left(\mathsf{neg}\left(\frac{1}{i}\right)\right) \cdot n\right) \]
      11. lift-+.f64N/A

        \[\leadsto 100 \cdot \mathsf{fma}\left(\frac{{\color{blue}{\left(1 + \frac{i}{n}\right)}}^{n}}{i}, n, \left(\mathsf{neg}\left(\frac{1}{i}\right)\right) \cdot n\right) \]
      12. +-commutativeN/A

        \[\leadsto 100 \cdot \mathsf{fma}\left(\frac{{\color{blue}{\left(\frac{i}{n} + 1\right)}}^{n}}{i}, n, \left(\mathsf{neg}\left(\frac{1}{i}\right)\right) \cdot n\right) \]
      13. lower-+.f64N/A

        \[\leadsto 100 \cdot \mathsf{fma}\left(\frac{{\color{blue}{\left(\frac{i}{n} + 1\right)}}^{n}}{i}, n, \left(\mathsf{neg}\left(\frac{1}{i}\right)\right) \cdot n\right) \]
      14. distribute-frac-neg2N/A

        \[\leadsto 100 \cdot \mathsf{fma}\left(\frac{{\left(\frac{i}{n} + 1\right)}^{n}}{i}, n, \color{blue}{\frac{1}{\mathsf{neg}\left(i\right)}} \cdot n\right) \]
      15. lower-*.f64N/A

        \[\leadsto 100 \cdot \mathsf{fma}\left(\frac{{\left(\frac{i}{n} + 1\right)}^{n}}{i}, n, \color{blue}{\frac{1}{\mathsf{neg}\left(i\right)} \cdot n}\right) \]
      16. frac-2negN/A

        \[\leadsto 100 \cdot \mathsf{fma}\left(\frac{{\left(\frac{i}{n} + 1\right)}^{n}}{i}, n, \color{blue}{\frac{\mathsf{neg}\left(1\right)}{\mathsf{neg}\left(\left(\mathsf{neg}\left(i\right)\right)\right)}} \cdot n\right) \]
      17. metadata-evalN/A

        \[\leadsto 100 \cdot \mathsf{fma}\left(\frac{{\left(\frac{i}{n} + 1\right)}^{n}}{i}, n, \frac{\color{blue}{-1}}{\mathsf{neg}\left(\left(\mathsf{neg}\left(i\right)\right)\right)} \cdot n\right) \]
      18. remove-double-negN/A

        \[\leadsto 100 \cdot \mathsf{fma}\left(\frac{{\left(\frac{i}{n} + 1\right)}^{n}}{i}, n, \frac{-1}{\color{blue}{i}} \cdot n\right) \]
      19. lower-/.f6497.7

        \[\leadsto 100 \cdot \mathsf{fma}\left(\frac{{\left(\frac{i}{n} + 1\right)}^{n}}{i}, n, \color{blue}{\frac{-1}{i}} \cdot n\right) \]
    4. Applied rewrites97.7%

      \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(\frac{{\left(\frac{i}{n} + 1\right)}^{n}}{i}, n, \frac{-1}{i} \cdot n\right)} \]

    if +inf.0 < (/.f64 (-.f64 (pow.f64 (+.f64 #s(literal 1 binary64) (/.f64 i n)) n) #s(literal 1 binary64)) (/.f64 i n))

    1. Initial program 0.0%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Taylor expanded in i around 0

      \[\leadsto \color{blue}{100 \cdot n} \]
    4. Step-by-step derivation
      1. lower-*.f6474.6

        \[\leadsto \color{blue}{100 \cdot n} \]
    5. Applied rewrites74.6%

      \[\leadsto \color{blue}{100 \cdot n} \]
  3. Recombined 3 regimes into one program.
  4. Add Preprocessing

Alternative 3: 93.9% accurate, 0.3× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\\ \mathbf{if}\;t\_0 \leq 0:\\ \;\;\;\;100 \cdot \left(\frac{\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right)}{i} \cdot n\right)\\ \mathbf{elif}\;t\_0 \leq \infty:\\ \;\;\;\;100 \cdot \mathsf{fma}\left(\frac{{\left(\frac{i}{n} + 1\right)}^{n}}{i}, n, \frac{-1}{i} \cdot n\right)\\ \mathbf{else}:\\ \;\;\;\;100 \cdot n\\ \end{array} \end{array} \]
(FPCore (i n)
 :precision binary64
 (let* ((t_0 (/ (- (pow (+ 1.0 (/ i n)) n) 1.0) (/ i n))))
   (if (<= t_0 0.0)
     (* 100.0 (* (/ (expm1 (* (log1p (/ i n)) n)) i) n))
     (if (<= t_0 INFINITY)
       (* 100.0 (fma (/ (pow (+ (/ i n) 1.0) n) i) n (* (/ -1.0 i) n)))
       (* 100.0 n)))))
double code(double i, double n) {
	double t_0 = (pow((1.0 + (i / n)), n) - 1.0) / (i / n);
	double tmp;
	if (t_0 <= 0.0) {
		tmp = 100.0 * ((expm1((log1p((i / n)) * n)) / i) * n);
	} else if (t_0 <= ((double) INFINITY)) {
		tmp = 100.0 * fma((pow(((i / n) + 1.0), n) / i), n, ((-1.0 / i) * n));
	} else {
		tmp = 100.0 * n;
	}
	return tmp;
}
function code(i, n)
	t_0 = Float64(Float64((Float64(1.0 + Float64(i / n)) ^ n) - 1.0) / Float64(i / n))
	tmp = 0.0
	if (t_0 <= 0.0)
		tmp = Float64(100.0 * Float64(Float64(expm1(Float64(log1p(Float64(i / n)) * n)) / i) * n));
	elseif (t_0 <= Inf)
		tmp = Float64(100.0 * fma(Float64((Float64(Float64(i / n) + 1.0) ^ n) / i), n, Float64(Float64(-1.0 / i) * n)));
	else
		tmp = Float64(100.0 * n);
	end
	return tmp
end
code[i_, n_] := Block[{t$95$0 = N[(N[(N[Power[N[(1.0 + N[(i / n), $MachinePrecision]), $MachinePrecision], n], $MachinePrecision] - 1.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, 0.0], N[(100.0 * N[(N[(N[(Exp[N[(N[Log[1 + N[(i / n), $MachinePrecision]], $MachinePrecision] * n), $MachinePrecision]] - 1), $MachinePrecision] / i), $MachinePrecision] * n), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$0, Infinity], N[(100.0 * N[(N[(N[Power[N[(N[(i / n), $MachinePrecision] + 1.0), $MachinePrecision], n], $MachinePrecision] / i), $MachinePrecision] * n + N[(N[(-1.0 / i), $MachinePrecision] * n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(100.0 * n), $MachinePrecision]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}\\
\mathbf{if}\;t\_0 \leq 0:\\
\;\;\;\;100 \cdot \left(\frac{\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right)}{i} \cdot n\right)\\

\mathbf{elif}\;t\_0 \leq \infty:\\
\;\;\;\;100 \cdot \mathsf{fma}\left(\frac{{\left(\frac{i}{n} + 1\right)}^{n}}{i}, n, \frac{-1}{i} \cdot n\right)\\

\mathbf{else}:\\
\;\;\;\;100 \cdot n\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (/.f64 (-.f64 (pow.f64 (+.f64 #s(literal 1 binary64) (/.f64 i n)) n) #s(literal 1 binary64)) (/.f64 i n)) < -0.0

    1. Initial program 27.3%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-/.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      2. lift-/.f64N/A

        \[\leadsto 100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\color{blue}{\frac{i}{n}}} \]
      3. associate-/r/N/A

        \[\leadsto 100 \cdot \color{blue}{\left(\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{i} \cdot n\right)} \]
      4. lower-*.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\left(\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{i} \cdot n\right)} \]
      5. lower-/.f6427.3

        \[\leadsto 100 \cdot \left(\color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{i}} \cdot n\right) \]
      6. lift--.f64N/A

        \[\leadsto 100 \cdot \left(\frac{\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n} - 1}}{i} \cdot n\right) \]
      7. lift-pow.f64N/A

        \[\leadsto 100 \cdot \left(\frac{\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n}} - 1}{i} \cdot n\right) \]
      8. pow-to-expN/A

        \[\leadsto 100 \cdot \left(\frac{\color{blue}{e^{\log \left(1 + \frac{i}{n}\right) \cdot n}} - 1}{i} \cdot n\right) \]
      9. lower-expm1.f64N/A

        \[\leadsto 100 \cdot \left(\frac{\color{blue}{\mathsf{expm1}\left(\log \left(1 + \frac{i}{n}\right) \cdot n\right)}}{i} \cdot n\right) \]
      10. lower-*.f64N/A

        \[\leadsto 100 \cdot \left(\frac{\mathsf{expm1}\left(\color{blue}{\log \left(1 + \frac{i}{n}\right) \cdot n}\right)}{i} \cdot n\right) \]
      11. lift-+.f64N/A

        \[\leadsto 100 \cdot \left(\frac{\mathsf{expm1}\left(\log \color{blue}{\left(1 + \frac{i}{n}\right)} \cdot n\right)}{i} \cdot n\right) \]
      12. lower-log1p.f6497.2

        \[\leadsto 100 \cdot \left(\frac{\mathsf{expm1}\left(\color{blue}{\mathsf{log1p}\left(\frac{i}{n}\right)} \cdot n\right)}{i} \cdot n\right) \]
    4. Applied rewrites97.2%

      \[\leadsto 100 \cdot \color{blue}{\left(\frac{\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right)}{i} \cdot n\right)} \]

    if -0.0 < (/.f64 (-.f64 (pow.f64 (+.f64 #s(literal 1 binary64) (/.f64 i n)) n) #s(literal 1 binary64)) (/.f64 i n)) < +inf.0

    1. Initial program 97.5%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-/.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      2. lift--.f64N/A

        \[\leadsto 100 \cdot \frac{\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n} - 1}}{\frac{i}{n}} \]
      3. div-subN/A

        \[\leadsto 100 \cdot \color{blue}{\left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{\frac{i}{n}} - \frac{1}{\frac{i}{n}}\right)} \]
      4. lift-/.f64N/A

        \[\leadsto 100 \cdot \left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{\frac{i}{n}} - \frac{1}{\color{blue}{\frac{i}{n}}}\right) \]
      5. associate-/r/N/A

        \[\leadsto 100 \cdot \left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{\frac{i}{n}} - \color{blue}{\frac{1}{i} \cdot n}\right) \]
      6. fp-cancel-sub-sign-invN/A

        \[\leadsto 100 \cdot \color{blue}{\left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{\frac{i}{n}} + \left(\mathsf{neg}\left(\frac{1}{i}\right)\right) \cdot n\right)} \]
      7. lift-/.f64N/A

        \[\leadsto 100 \cdot \left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{\color{blue}{\frac{i}{n}}} + \left(\mathsf{neg}\left(\frac{1}{i}\right)\right) \cdot n\right) \]
      8. associate-/r/N/A

        \[\leadsto 100 \cdot \left(\color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot n} + \left(\mathsf{neg}\left(\frac{1}{i}\right)\right) \cdot n\right) \]
      9. lower-fma.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i}, n, \left(\mathsf{neg}\left(\frac{1}{i}\right)\right) \cdot n\right)} \]
      10. lower-/.f64N/A

        \[\leadsto 100 \cdot \mathsf{fma}\left(\color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i}}, n, \left(\mathsf{neg}\left(\frac{1}{i}\right)\right) \cdot n\right) \]
      11. lift-+.f64N/A

        \[\leadsto 100 \cdot \mathsf{fma}\left(\frac{{\color{blue}{\left(1 + \frac{i}{n}\right)}}^{n}}{i}, n, \left(\mathsf{neg}\left(\frac{1}{i}\right)\right) \cdot n\right) \]
      12. +-commutativeN/A

        \[\leadsto 100 \cdot \mathsf{fma}\left(\frac{{\color{blue}{\left(\frac{i}{n} + 1\right)}}^{n}}{i}, n, \left(\mathsf{neg}\left(\frac{1}{i}\right)\right) \cdot n\right) \]
      13. lower-+.f64N/A

        \[\leadsto 100 \cdot \mathsf{fma}\left(\frac{{\color{blue}{\left(\frac{i}{n} + 1\right)}}^{n}}{i}, n, \left(\mathsf{neg}\left(\frac{1}{i}\right)\right) \cdot n\right) \]
      14. distribute-frac-neg2N/A

        \[\leadsto 100 \cdot \mathsf{fma}\left(\frac{{\left(\frac{i}{n} + 1\right)}^{n}}{i}, n, \color{blue}{\frac{1}{\mathsf{neg}\left(i\right)}} \cdot n\right) \]
      15. lower-*.f64N/A

        \[\leadsto 100 \cdot \mathsf{fma}\left(\frac{{\left(\frac{i}{n} + 1\right)}^{n}}{i}, n, \color{blue}{\frac{1}{\mathsf{neg}\left(i\right)} \cdot n}\right) \]
      16. frac-2negN/A

        \[\leadsto 100 \cdot \mathsf{fma}\left(\frac{{\left(\frac{i}{n} + 1\right)}^{n}}{i}, n, \color{blue}{\frac{\mathsf{neg}\left(1\right)}{\mathsf{neg}\left(\left(\mathsf{neg}\left(i\right)\right)\right)}} \cdot n\right) \]
      17. metadata-evalN/A

        \[\leadsto 100 \cdot \mathsf{fma}\left(\frac{{\left(\frac{i}{n} + 1\right)}^{n}}{i}, n, \frac{\color{blue}{-1}}{\mathsf{neg}\left(\left(\mathsf{neg}\left(i\right)\right)\right)} \cdot n\right) \]
      18. remove-double-negN/A

        \[\leadsto 100 \cdot \mathsf{fma}\left(\frac{{\left(\frac{i}{n} + 1\right)}^{n}}{i}, n, \frac{-1}{\color{blue}{i}} \cdot n\right) \]
      19. lower-/.f6497.7

        \[\leadsto 100 \cdot \mathsf{fma}\left(\frac{{\left(\frac{i}{n} + 1\right)}^{n}}{i}, n, \color{blue}{\frac{-1}{i}} \cdot n\right) \]
    4. Applied rewrites97.7%

      \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(\frac{{\left(\frac{i}{n} + 1\right)}^{n}}{i}, n, \frac{-1}{i} \cdot n\right)} \]

    if +inf.0 < (/.f64 (-.f64 (pow.f64 (+.f64 #s(literal 1 binary64) (/.f64 i n)) n) #s(literal 1 binary64)) (/.f64 i n))

    1. Initial program 0.0%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Taylor expanded in i around 0

      \[\leadsto \color{blue}{100 \cdot n} \]
    4. Step-by-step derivation
      1. lower-*.f6474.6

        \[\leadsto \color{blue}{100 \cdot n} \]
    5. Applied rewrites74.6%

      \[\leadsto \color{blue}{100 \cdot n} \]
  3. Recombined 3 regimes into one program.
  4. Add Preprocessing

Alternative 4: 80.4% accurate, 0.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{\mathsf{expm1}\left(i\right)}{i}\\ \mathbf{if}\;n \leq -5 \cdot 10^{-311}:\\ \;\;\;\;\left(t\_0 \cdot 100\right) \cdot n\\ \mathbf{elif}\;n \leq 2.55 \cdot 10^{-142}:\\ \;\;\;\;100 \cdot \left(\left(n \cdot \frac{\mathsf{fma}\left(\log n, -1, \log i\right)}{i}\right) \cdot n\right)\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \left(t\_0 \cdot n\right)\\ \end{array} \end{array} \]
(FPCore (i n)
 :precision binary64
 (let* ((t_0 (/ (expm1 i) i)))
   (if (<= n -5e-311)
     (* (* t_0 100.0) n)
     (if (<= n 2.55e-142)
       (* 100.0 (* (* n (/ (fma (log n) -1.0 (log i)) i)) n))
       (* 100.0 (* t_0 n))))))
double code(double i, double n) {
	double t_0 = expm1(i) / i;
	double tmp;
	if (n <= -5e-311) {
		tmp = (t_0 * 100.0) * n;
	} else if (n <= 2.55e-142) {
		tmp = 100.0 * ((n * (fma(log(n), -1.0, log(i)) / i)) * n);
	} else {
		tmp = 100.0 * (t_0 * n);
	}
	return tmp;
}
function code(i, n)
	t_0 = Float64(expm1(i) / i)
	tmp = 0.0
	if (n <= -5e-311)
		tmp = Float64(Float64(t_0 * 100.0) * n);
	elseif (n <= 2.55e-142)
		tmp = Float64(100.0 * Float64(Float64(n * Float64(fma(log(n), -1.0, log(i)) / i)) * n));
	else
		tmp = Float64(100.0 * Float64(t_0 * n));
	end
	return tmp
end
code[i_, n_] := Block[{t$95$0 = N[(N[(Exp[i] - 1), $MachinePrecision] / i), $MachinePrecision]}, If[LessEqual[n, -5e-311], N[(N[(t$95$0 * 100.0), $MachinePrecision] * n), $MachinePrecision], If[LessEqual[n, 2.55e-142], N[(100.0 * N[(N[(n * N[(N[(N[Log[n], $MachinePrecision] * -1.0 + N[Log[i], $MachinePrecision]), $MachinePrecision] / i), $MachinePrecision]), $MachinePrecision] * n), $MachinePrecision]), $MachinePrecision], N[(100.0 * N[(t$95$0 * n), $MachinePrecision]), $MachinePrecision]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{\mathsf{expm1}\left(i\right)}{i}\\
\mathbf{if}\;n \leq -5 \cdot 10^{-311}:\\
\;\;\;\;\left(t\_0 \cdot 100\right) \cdot n\\

\mathbf{elif}\;n \leq 2.55 \cdot 10^{-142}:\\
\;\;\;\;100 \cdot \left(\left(n \cdot \frac{\mathsf{fma}\left(\log n, -1, \log i\right)}{i}\right) \cdot n\right)\\

\mathbf{else}:\\
\;\;\;\;100 \cdot \left(t\_0 \cdot n\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if n < -5.00000000000023e-311

    1. Initial program 32.4%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Taylor expanded in n around inf

      \[\leadsto \color{blue}{100 \cdot \frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
    4. Step-by-step derivation
      1. associate-/l*N/A

        \[\leadsto 100 \cdot \color{blue}{\left(n \cdot \frac{e^{i} - 1}{i}\right)} \]
      2. *-commutativeN/A

        \[\leadsto 100 \cdot \color{blue}{\left(\frac{e^{i} - 1}{i} \cdot n\right)} \]
      3. associate-*l*N/A

        \[\leadsto \color{blue}{\left(100 \cdot \frac{e^{i} - 1}{i}\right) \cdot n} \]
      4. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(100 \cdot \frac{e^{i} - 1}{i}\right) \cdot n} \]
      5. *-commutativeN/A

        \[\leadsto \color{blue}{\left(\frac{e^{i} - 1}{i} \cdot 100\right)} \cdot n \]
      6. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\frac{e^{i} - 1}{i} \cdot 100\right)} \cdot n \]
      7. lower-/.f64N/A

        \[\leadsto \left(\color{blue}{\frac{e^{i} - 1}{i}} \cdot 100\right) \cdot n \]
      8. lower-expm1.f6478.8

        \[\leadsto \left(\frac{\color{blue}{\mathsf{expm1}\left(i\right)}}{i} \cdot 100\right) \cdot n \]
    5. Applied rewrites78.8%

      \[\leadsto \color{blue}{\left(\frac{\mathsf{expm1}\left(i\right)}{i} \cdot 100\right) \cdot n} \]

    if -5.00000000000023e-311 < n < 2.55e-142

    1. Initial program 32.9%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-/.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
      2. lift-/.f64N/A

        \[\leadsto 100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\color{blue}{\frac{i}{n}}} \]
      3. associate-/r/N/A

        \[\leadsto 100 \cdot \color{blue}{\left(\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{i} \cdot n\right)} \]
      4. lower-*.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\left(\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{i} \cdot n\right)} \]
      5. lower-/.f6433.4

        \[\leadsto 100 \cdot \left(\color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{i}} \cdot n\right) \]
      6. lift--.f64N/A

        \[\leadsto 100 \cdot \left(\frac{\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n} - 1}}{i} \cdot n\right) \]
      7. lift-pow.f64N/A

        \[\leadsto 100 \cdot \left(\frac{\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n}} - 1}{i} \cdot n\right) \]
      8. pow-to-expN/A

        \[\leadsto 100 \cdot \left(\frac{\color{blue}{e^{\log \left(1 + \frac{i}{n}\right) \cdot n}} - 1}{i} \cdot n\right) \]
      9. lower-expm1.f64N/A

        \[\leadsto 100 \cdot \left(\frac{\color{blue}{\mathsf{expm1}\left(\log \left(1 + \frac{i}{n}\right) \cdot n\right)}}{i} \cdot n\right) \]
      10. lower-*.f64N/A

        \[\leadsto 100 \cdot \left(\frac{\mathsf{expm1}\left(\color{blue}{\log \left(1 + \frac{i}{n}\right) \cdot n}\right)}{i} \cdot n\right) \]
      11. lift-+.f64N/A

        \[\leadsto 100 \cdot \left(\frac{\mathsf{expm1}\left(\log \color{blue}{\left(1 + \frac{i}{n}\right)} \cdot n\right)}{i} \cdot n\right) \]
      12. lower-log1p.f6469.8

        \[\leadsto 100 \cdot \left(\frac{\mathsf{expm1}\left(\color{blue}{\mathsf{log1p}\left(\frac{i}{n}\right)} \cdot n\right)}{i} \cdot n\right) \]
    4. Applied rewrites69.8%

      \[\leadsto 100 \cdot \color{blue}{\left(\frac{\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right)}{i} \cdot n\right)} \]
    5. Taylor expanded in n around 0

      \[\leadsto 100 \cdot \left(\color{blue}{\frac{n \cdot \left(\log i + -1 \cdot \log n\right)}{i}} \cdot n\right) \]
    6. Step-by-step derivation
      1. associate-/l*N/A

        \[\leadsto 100 \cdot \left(\color{blue}{\left(n \cdot \frac{\log i + -1 \cdot \log n}{i}\right)} \cdot n\right) \]
      2. lower-*.f64N/A

        \[\leadsto 100 \cdot \left(\color{blue}{\left(n \cdot \frac{\log i + -1 \cdot \log n}{i}\right)} \cdot n\right) \]
      3. lower-/.f64N/A

        \[\leadsto 100 \cdot \left(\left(n \cdot \color{blue}{\frac{\log i + -1 \cdot \log n}{i}}\right) \cdot n\right) \]
      4. +-commutativeN/A

        \[\leadsto 100 \cdot \left(\left(n \cdot \frac{\color{blue}{-1 \cdot \log n + \log i}}{i}\right) \cdot n\right) \]
      5. *-commutativeN/A

        \[\leadsto 100 \cdot \left(\left(n \cdot \frac{\color{blue}{\log n \cdot -1} + \log i}{i}\right) \cdot n\right) \]
      6. lower-fma.f64N/A

        \[\leadsto 100 \cdot \left(\left(n \cdot \frac{\color{blue}{\mathsf{fma}\left(\log n, -1, \log i\right)}}{i}\right) \cdot n\right) \]
      7. lower-log.f64N/A

        \[\leadsto 100 \cdot \left(\left(n \cdot \frac{\mathsf{fma}\left(\color{blue}{\log n}, -1, \log i\right)}{i}\right) \cdot n\right) \]
      8. lower-log.f6475.2

        \[\leadsto 100 \cdot \left(\left(n \cdot \frac{\mathsf{fma}\left(\log n, -1, \color{blue}{\log i}\right)}{i}\right) \cdot n\right) \]
    7. Applied rewrites75.2%

      \[\leadsto 100 \cdot \left(\color{blue}{\left(n \cdot \frac{\mathsf{fma}\left(\log n, -1, \log i\right)}{i}\right)} \cdot n\right) \]

    if 2.55e-142 < n

    1. Initial program 22.6%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Taylor expanded in n around inf

      \[\leadsto 100 \cdot \color{blue}{\frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
    4. Step-by-step derivation
      1. associate-/l*N/A

        \[\leadsto 100 \cdot \color{blue}{\left(n \cdot \frac{e^{i} - 1}{i}\right)} \]
      2. *-commutativeN/A

        \[\leadsto 100 \cdot \color{blue}{\left(\frac{e^{i} - 1}{i} \cdot n\right)} \]
      3. lower-*.f64N/A

        \[\leadsto 100 \cdot \color{blue}{\left(\frac{e^{i} - 1}{i} \cdot n\right)} \]
      4. lower-/.f64N/A

        \[\leadsto 100 \cdot \left(\color{blue}{\frac{e^{i} - 1}{i}} \cdot n\right) \]
      5. lower-expm1.f6485.5

        \[\leadsto 100 \cdot \left(\frac{\color{blue}{\mathsf{expm1}\left(i\right)}}{i} \cdot n\right) \]
    5. Applied rewrites85.5%

      \[\leadsto 100 \cdot \color{blue}{\left(\frac{\mathsf{expm1}\left(i\right)}{i} \cdot n\right)} \]
  3. Recombined 3 regimes into one program.
  4. Add Preprocessing

Alternative 5: 80.4% accurate, 1.1× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;n \leq -1.75 \cdot 10^{-134} \lor \neg \left(n \leq 4.4 \cdot 10^{-181}\right):\\ \;\;\;\;\left(\frac{\mathsf{expm1}\left(i\right)}{i} \cdot 100\right) \cdot n\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{1 - 1}{\frac{i}{n}}\\ \end{array} \end{array} \]
(FPCore (i n)
 :precision binary64
 (if (or (<= n -1.75e-134) (not (<= n 4.4e-181)))
   (* (* (/ (expm1 i) i) 100.0) n)
   (* 100.0 (/ (- 1.0 1.0) (/ i n)))))
double code(double i, double n) {
	double tmp;
	if ((n <= -1.75e-134) || !(n <= 4.4e-181)) {
		tmp = ((expm1(i) / i) * 100.0) * n;
	} else {
		tmp = 100.0 * ((1.0 - 1.0) / (i / n));
	}
	return tmp;
}
public static double code(double i, double n) {
	double tmp;
	if ((n <= -1.75e-134) || !(n <= 4.4e-181)) {
		tmp = ((Math.expm1(i) / i) * 100.0) * n;
	} else {
		tmp = 100.0 * ((1.0 - 1.0) / (i / n));
	}
	return tmp;
}
def code(i, n):
	tmp = 0
	if (n <= -1.75e-134) or not (n <= 4.4e-181):
		tmp = ((math.expm1(i) / i) * 100.0) * n
	else:
		tmp = 100.0 * ((1.0 - 1.0) / (i / n))
	return tmp
function code(i, n)
	tmp = 0.0
	if ((n <= -1.75e-134) || !(n <= 4.4e-181))
		tmp = Float64(Float64(Float64(expm1(i) / i) * 100.0) * n);
	else
		tmp = Float64(100.0 * Float64(Float64(1.0 - 1.0) / Float64(i / n)));
	end
	return tmp
end
code[i_, n_] := If[Or[LessEqual[n, -1.75e-134], N[Not[LessEqual[n, 4.4e-181]], $MachinePrecision]], N[(N[(N[(N[(Exp[i] - 1), $MachinePrecision] / i), $MachinePrecision] * 100.0), $MachinePrecision] * n), $MachinePrecision], N[(100.0 * N[(N[(1.0 - 1.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;n \leq -1.75 \cdot 10^{-134} \lor \neg \left(n \leq 4.4 \cdot 10^{-181}\right):\\
\;\;\;\;\left(\frac{\mathsf{expm1}\left(i\right)}{i} \cdot 100\right) \cdot n\\

\mathbf{else}:\\
\;\;\;\;100 \cdot \frac{1 - 1}{\frac{i}{n}}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if n < -1.7499999999999999e-134 or 4.39999999999999994e-181 < n

    1. Initial program 23.9%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Taylor expanded in n around inf

      \[\leadsto \color{blue}{100 \cdot \frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
    4. Step-by-step derivation
      1. associate-/l*N/A

        \[\leadsto 100 \cdot \color{blue}{\left(n \cdot \frac{e^{i} - 1}{i}\right)} \]
      2. *-commutativeN/A

        \[\leadsto 100 \cdot \color{blue}{\left(\frac{e^{i} - 1}{i} \cdot n\right)} \]
      3. associate-*l*N/A

        \[\leadsto \color{blue}{\left(100 \cdot \frac{e^{i} - 1}{i}\right) \cdot n} \]
      4. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(100 \cdot \frac{e^{i} - 1}{i}\right) \cdot n} \]
      5. *-commutativeN/A

        \[\leadsto \color{blue}{\left(\frac{e^{i} - 1}{i} \cdot 100\right)} \cdot n \]
      6. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\frac{e^{i} - 1}{i} \cdot 100\right)} \cdot n \]
      7. lower-/.f64N/A

        \[\leadsto \left(\color{blue}{\frac{e^{i} - 1}{i}} \cdot 100\right) \cdot n \]
      8. lower-expm1.f6483.5

        \[\leadsto \left(\frac{\color{blue}{\mathsf{expm1}\left(i\right)}}{i} \cdot 100\right) \cdot n \]
    5. Applied rewrites83.5%

      \[\leadsto \color{blue}{\left(\frac{\mathsf{expm1}\left(i\right)}{i} \cdot 100\right) \cdot n} \]

    if -1.7499999999999999e-134 < n < 4.39999999999999994e-181

    1. Initial program 48.5%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Add Preprocessing
    3. Taylor expanded in i around 0

      \[\leadsto 100 \cdot \frac{\color{blue}{1} - 1}{\frac{i}{n}} \]
    4. Step-by-step derivation
      1. Applied rewrites67.8%

        \[\leadsto 100 \cdot \frac{\color{blue}{1} - 1}{\frac{i}{n}} \]
    5. Recombined 2 regimes into one program.
    6. Final simplification80.3%

      \[\leadsto \begin{array}{l} \mathbf{if}\;n \leq -1.75 \cdot 10^{-134} \lor \neg \left(n \leq 4.4 \cdot 10^{-181}\right):\\ \;\;\;\;\left(\frac{\mathsf{expm1}\left(i\right)}{i} \cdot 100\right) \cdot n\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{1 - 1}{\frac{i}{n}}\\ \end{array} \]
    7. Add Preprocessing

    Alternative 6: 66.1% accurate, 2.6× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;n \leq -2.8 \cdot 10^{-134} \lor \neg \left(n \leq 4.4 \cdot 10^{-181}\right):\\ \;\;\;\;100 \cdot \left(\frac{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.041666666666666664, i, 0.16666666666666666\right), i, 0.5\right), i, 1\right) \cdot i}{i} \cdot n\right)\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{1 - 1}{\frac{i}{n}}\\ \end{array} \end{array} \]
    (FPCore (i n)
     :precision binary64
     (if (or (<= n -2.8e-134) (not (<= n 4.4e-181)))
       (*
        100.0
        (*
         (/
          (*
           (fma (fma (fma 0.041666666666666664 i 0.16666666666666666) i 0.5) i 1.0)
           i)
          i)
         n))
       (* 100.0 (/ (- 1.0 1.0) (/ i n)))))
    double code(double i, double n) {
    	double tmp;
    	if ((n <= -2.8e-134) || !(n <= 4.4e-181)) {
    		tmp = 100.0 * (((fma(fma(fma(0.041666666666666664, i, 0.16666666666666666), i, 0.5), i, 1.0) * i) / i) * n);
    	} else {
    		tmp = 100.0 * ((1.0 - 1.0) / (i / n));
    	}
    	return tmp;
    }
    
    function code(i, n)
    	tmp = 0.0
    	if ((n <= -2.8e-134) || !(n <= 4.4e-181))
    		tmp = Float64(100.0 * Float64(Float64(Float64(fma(fma(fma(0.041666666666666664, i, 0.16666666666666666), i, 0.5), i, 1.0) * i) / i) * n));
    	else
    		tmp = Float64(100.0 * Float64(Float64(1.0 - 1.0) / Float64(i / n)));
    	end
    	return tmp
    end
    
    code[i_, n_] := If[Or[LessEqual[n, -2.8e-134], N[Not[LessEqual[n, 4.4e-181]], $MachinePrecision]], N[(100.0 * N[(N[(N[(N[(N[(N[(0.041666666666666664 * i + 0.16666666666666666), $MachinePrecision] * i + 0.5), $MachinePrecision] * i + 1.0), $MachinePrecision] * i), $MachinePrecision] / i), $MachinePrecision] * n), $MachinePrecision]), $MachinePrecision], N[(100.0 * N[(N[(1.0 - 1.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;n \leq -2.8 \cdot 10^{-134} \lor \neg \left(n \leq 4.4 \cdot 10^{-181}\right):\\
    \;\;\;\;100 \cdot \left(\frac{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.041666666666666664, i, 0.16666666666666666\right), i, 0.5\right), i, 1\right) \cdot i}{i} \cdot n\right)\\
    
    \mathbf{else}:\\
    \;\;\;\;100 \cdot \frac{1 - 1}{\frac{i}{n}}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 2 regimes
    2. if n < -2.7999999999999999e-134 or 4.39999999999999994e-181 < n

      1. Initial program 23.9%

        \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
      2. Add Preprocessing
      3. Taylor expanded in n around inf

        \[\leadsto 100 \cdot \frac{\color{blue}{e^{i} - 1}}{\frac{i}{n}} \]
      4. Step-by-step derivation
        1. lower-expm1.f6468.0

          \[\leadsto 100 \cdot \frac{\color{blue}{\mathsf{expm1}\left(i\right)}}{\frac{i}{n}} \]
      5. Applied rewrites68.0%

        \[\leadsto 100 \cdot \frac{\color{blue}{\mathsf{expm1}\left(i\right)}}{\frac{i}{n}} \]
      6. Step-by-step derivation
        1. lift-/.f64N/A

          \[\leadsto 100 \cdot \color{blue}{\frac{\mathsf{expm1}\left(i\right)}{\frac{i}{n}}} \]
        2. lift-/.f64N/A

          \[\leadsto 100 \cdot \frac{\mathsf{expm1}\left(i\right)}{\color{blue}{\frac{i}{n}}} \]
        3. associate-/r/N/A

          \[\leadsto 100 \cdot \color{blue}{\left(\frac{\mathsf{expm1}\left(i\right)}{i} \cdot n\right)} \]
        4. lower-*.f64N/A

          \[\leadsto 100 \cdot \color{blue}{\left(\frac{\mathsf{expm1}\left(i\right)}{i} \cdot n\right)} \]
        5. lower-/.f6483.5

          \[\leadsto 100 \cdot \left(\color{blue}{\frac{\mathsf{expm1}\left(i\right)}{i}} \cdot n\right) \]
      7. Applied rewrites83.5%

        \[\leadsto 100 \cdot \color{blue}{\left(\frac{\mathsf{expm1}\left(i\right)}{i} \cdot n\right)} \]
      8. Taylor expanded in i around 0

        \[\leadsto 100 \cdot \left(\frac{i \cdot \color{blue}{\left(1 + i \cdot \left(\frac{1}{2} + i \cdot \left(\frac{1}{6} + \frac{1}{24} \cdot i\right)\right)\right)}}{i} \cdot n\right) \]
      9. Step-by-step derivation
        1. Applied rewrites65.3%

          \[\leadsto 100 \cdot \left(\frac{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.041666666666666664, i, 0.16666666666666666\right), i, 0.5\right), i, 1\right) \cdot \color{blue}{i}}{i} \cdot n\right) \]

        if -2.7999999999999999e-134 < n < 4.39999999999999994e-181

        1. Initial program 48.5%

          \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
        2. Add Preprocessing
        3. Taylor expanded in i around 0

          \[\leadsto 100 \cdot \frac{\color{blue}{1} - 1}{\frac{i}{n}} \]
        4. Step-by-step derivation
          1. Applied rewrites67.8%

            \[\leadsto 100 \cdot \frac{\color{blue}{1} - 1}{\frac{i}{n}} \]
        5. Recombined 2 regimes into one program.
        6. Final simplification65.8%

          \[\leadsto \begin{array}{l} \mathbf{if}\;n \leq -2.8 \cdot 10^{-134} \lor \neg \left(n \leq 4.4 \cdot 10^{-181}\right):\\ \;\;\;\;100 \cdot \left(\frac{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.041666666666666664, i, 0.16666666666666666\right), i, 0.5\right), i, 1\right) \cdot i}{i} \cdot n\right)\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{1 - 1}{\frac{i}{n}}\\ \end{array} \]
        7. Add Preprocessing

        Alternative 7: 66.4% accurate, 2.9× speedup?

        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;n \leq -2.8 \cdot 10^{-134}:\\ \;\;\;\;100 \cdot \mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right) \cdot n, i, n\right)\\ \mathbf{elif}\;n \leq 1.9 \cdot 10^{-182}:\\ \;\;\;\;100 \cdot \frac{1 - 1}{\frac{i}{n}}\\ \mathbf{elif}\;n \leq 5.6 \cdot 10^{-24}:\\ \;\;\;\;\frac{100 \cdot i}{\frac{i}{n}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(100 \cdot n\right) \cdot \left(\mathsf{fma}\left(0.5, i, 1\right) \cdot i\right)}{i}\\ \end{array} \end{array} \]
        (FPCore (i n)
         :precision binary64
         (if (<= n -2.8e-134)
           (* 100.0 (fma (* (fma 0.16666666666666666 i 0.5) n) i n))
           (if (<= n 1.9e-182)
             (* 100.0 (/ (- 1.0 1.0) (/ i n)))
             (if (<= n 5.6e-24)
               (/ (* 100.0 i) (/ i n))
               (/ (* (* 100.0 n) (* (fma 0.5 i 1.0) i)) i)))))
        double code(double i, double n) {
        	double tmp;
        	if (n <= -2.8e-134) {
        		tmp = 100.0 * fma((fma(0.16666666666666666, i, 0.5) * n), i, n);
        	} else if (n <= 1.9e-182) {
        		tmp = 100.0 * ((1.0 - 1.0) / (i / n));
        	} else if (n <= 5.6e-24) {
        		tmp = (100.0 * i) / (i / n);
        	} else {
        		tmp = ((100.0 * n) * (fma(0.5, i, 1.0) * i)) / i;
        	}
        	return tmp;
        }
        
        function code(i, n)
        	tmp = 0.0
        	if (n <= -2.8e-134)
        		tmp = Float64(100.0 * fma(Float64(fma(0.16666666666666666, i, 0.5) * n), i, n));
        	elseif (n <= 1.9e-182)
        		tmp = Float64(100.0 * Float64(Float64(1.0 - 1.0) / Float64(i / n)));
        	elseif (n <= 5.6e-24)
        		tmp = Float64(Float64(100.0 * i) / Float64(i / n));
        	else
        		tmp = Float64(Float64(Float64(100.0 * n) * Float64(fma(0.5, i, 1.0) * i)) / i);
        	end
        	return tmp
        end
        
        code[i_, n_] := If[LessEqual[n, -2.8e-134], N[(100.0 * N[(N[(N[(0.16666666666666666 * i + 0.5), $MachinePrecision] * n), $MachinePrecision] * i + n), $MachinePrecision]), $MachinePrecision], If[LessEqual[n, 1.9e-182], N[(100.0 * N[(N[(1.0 - 1.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[n, 5.6e-24], N[(N[(100.0 * i), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision], N[(N[(N[(100.0 * n), $MachinePrecision] * N[(N[(0.5 * i + 1.0), $MachinePrecision] * i), $MachinePrecision]), $MachinePrecision] / i), $MachinePrecision]]]]
        
        \begin{array}{l}
        
        \\
        \begin{array}{l}
        \mathbf{if}\;n \leq -2.8 \cdot 10^{-134}:\\
        \;\;\;\;100 \cdot \mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right) \cdot n, i, n\right)\\
        
        \mathbf{elif}\;n \leq 1.9 \cdot 10^{-182}:\\
        \;\;\;\;100 \cdot \frac{1 - 1}{\frac{i}{n}}\\
        
        \mathbf{elif}\;n \leq 5.6 \cdot 10^{-24}:\\
        \;\;\;\;\frac{100 \cdot i}{\frac{i}{n}}\\
        
        \mathbf{else}:\\
        \;\;\;\;\frac{\left(100 \cdot n\right) \cdot \left(\mathsf{fma}\left(0.5, i, 1\right) \cdot i\right)}{i}\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 4 regimes
        2. if n < -2.7999999999999999e-134

          1. Initial program 24.7%

            \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
          2. Add Preprocessing
          3. Taylor expanded in i around 0

            \[\leadsto 100 \cdot \color{blue}{\left(n + i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right)\right)} \]
          4. Step-by-step derivation
            1. +-commutativeN/A

              \[\leadsto 100 \cdot \color{blue}{\left(i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n\right)} \]
            2. *-commutativeN/A

              \[\leadsto 100 \cdot \left(\color{blue}{\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) \cdot i} + n\right) \]
            3. lower-fma.f64N/A

              \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right), i, n\right)} \]
          5. Applied rewrites55.4%

            \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(n \cdot i, \left(\frac{0.3333333333333333}{n \cdot n} + 0.16666666666666666\right) - \frac{0.5}{n}, \left(0.5 - \frac{0.5}{n}\right) \cdot n\right), i, n\right)} \]
          6. Taylor expanded in n around inf

            \[\leadsto 100 \cdot \mathsf{fma}\left(n \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot i\right), i, n\right) \]
          7. Step-by-step derivation
            1. Applied rewrites55.4%

              \[\leadsto 100 \cdot \mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right) \cdot n, i, n\right) \]

            if -2.7999999999999999e-134 < n < 1.9000000000000002e-182

            1. Initial program 48.5%

              \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
            2. Add Preprocessing
            3. Taylor expanded in i around 0

              \[\leadsto 100 \cdot \frac{\color{blue}{1} - 1}{\frac{i}{n}} \]
            4. Step-by-step derivation
              1. Applied rewrites67.8%

                \[\leadsto 100 \cdot \frac{\color{blue}{1} - 1}{\frac{i}{n}} \]

              if 1.9000000000000002e-182 < n < 5.6000000000000003e-24

              1. Initial program 17.1%

                \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
              2. Add Preprocessing
              3. Step-by-step derivation
                1. lift-*.f64N/A

                  \[\leadsto \color{blue}{100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
                2. lift-/.f64N/A

                  \[\leadsto 100 \cdot \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
                3. associate-*r/N/A

                  \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\frac{i}{n}}} \]
                4. lower-/.f64N/A

                  \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\frac{i}{n}}} \]
                5. *-commutativeN/A

                  \[\leadsto \frac{\color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right) \cdot 100}}{\frac{i}{n}} \]
                6. lower-*.f6417.1

                  \[\leadsto \frac{\color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right) \cdot 100}}{\frac{i}{n}} \]
                7. lift--.f64N/A

                  \[\leadsto \frac{\color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)} \cdot 100}{\frac{i}{n}} \]
                8. lift-pow.f64N/A

                  \[\leadsto \frac{\left(\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n}} - 1\right) \cdot 100}{\frac{i}{n}} \]
                9. pow-to-expN/A

                  \[\leadsto \frac{\left(\color{blue}{e^{\log \left(1 + \frac{i}{n}\right) \cdot n}} - 1\right) \cdot 100}{\frac{i}{n}} \]
                10. lower-expm1.f64N/A

                  \[\leadsto \frac{\color{blue}{\mathsf{expm1}\left(\log \left(1 + \frac{i}{n}\right) \cdot n\right)} \cdot 100}{\frac{i}{n}} \]
                11. lower-*.f64N/A

                  \[\leadsto \frac{\mathsf{expm1}\left(\color{blue}{\log \left(1 + \frac{i}{n}\right) \cdot n}\right) \cdot 100}{\frac{i}{n}} \]
                12. lift-+.f64N/A

                  \[\leadsto \frac{\mathsf{expm1}\left(\log \color{blue}{\left(1 + \frac{i}{n}\right)} \cdot n\right) \cdot 100}{\frac{i}{n}} \]
                13. lower-log1p.f6492.7

                  \[\leadsto \frac{\mathsf{expm1}\left(\color{blue}{\mathsf{log1p}\left(\frac{i}{n}\right)} \cdot n\right) \cdot 100}{\frac{i}{n}} \]
              4. Applied rewrites92.7%

                \[\leadsto \color{blue}{\frac{\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right) \cdot 100}{\frac{i}{n}}} \]
              5. Taylor expanded in i around 0

                \[\leadsto \frac{\color{blue}{100 \cdot i}}{\frac{i}{n}} \]
              6. Step-by-step derivation
                1. lower-*.f6460.5

                  \[\leadsto \frac{\color{blue}{100 \cdot i}}{\frac{i}{n}} \]
              7. Applied rewrites60.5%

                \[\leadsto \frac{\color{blue}{100 \cdot i}}{\frac{i}{n}} \]

              if 5.6000000000000003e-24 < n

              1. Initial program 25.5%

                \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
              2. Add Preprocessing
              3. Taylor expanded in n around inf

                \[\leadsto 100 \cdot \frac{\color{blue}{e^{i} - 1}}{\frac{i}{n}} \]
              4. Step-by-step derivation
                1. lower-expm1.f6474.2

                  \[\leadsto 100 \cdot \frac{\color{blue}{\mathsf{expm1}\left(i\right)}}{\frac{i}{n}} \]
              5. Applied rewrites74.2%

                \[\leadsto 100 \cdot \frac{\color{blue}{\mathsf{expm1}\left(i\right)}}{\frac{i}{n}} \]
              6. Step-by-step derivation
                1. lift-/.f64N/A

                  \[\leadsto 100 \cdot \color{blue}{\frac{\mathsf{expm1}\left(i\right)}{\frac{i}{n}}} \]
                2. lift-/.f64N/A

                  \[\leadsto 100 \cdot \frac{\mathsf{expm1}\left(i\right)}{\color{blue}{\frac{i}{n}}} \]
                3. associate-/r/N/A

                  \[\leadsto 100 \cdot \color{blue}{\left(\frac{\mathsf{expm1}\left(i\right)}{i} \cdot n\right)} \]
                4. associate-*l/N/A

                  \[\leadsto 100 \cdot \color{blue}{\frac{\mathsf{expm1}\left(i\right) \cdot n}{i}} \]
                5. lower-/.f64N/A

                  \[\leadsto 100 \cdot \color{blue}{\frac{\mathsf{expm1}\left(i\right) \cdot n}{i}} \]
                6. lower-*.f6494.3

                  \[\leadsto 100 \cdot \frac{\color{blue}{\mathsf{expm1}\left(i\right) \cdot n}}{i} \]
              7. Applied rewrites94.3%

                \[\leadsto 100 \cdot \color{blue}{\frac{\mathsf{expm1}\left(i\right) \cdot n}{i}} \]
              8. Step-by-step derivation
                1. lift-*.f64N/A

                  \[\leadsto \color{blue}{100 \cdot \frac{\mathsf{expm1}\left(i\right) \cdot n}{i}} \]
                2. lift-/.f64N/A

                  \[\leadsto 100 \cdot \color{blue}{\frac{\mathsf{expm1}\left(i\right) \cdot n}{i}} \]
                3. associate-*r/N/A

                  \[\leadsto \color{blue}{\frac{100 \cdot \left(\mathsf{expm1}\left(i\right) \cdot n\right)}{i}} \]
                4. lower-/.f64N/A

                  \[\leadsto \color{blue}{\frac{100 \cdot \left(\mathsf{expm1}\left(i\right) \cdot n\right)}{i}} \]
                5. lift-*.f64N/A

                  \[\leadsto \frac{100 \cdot \color{blue}{\left(\mathsf{expm1}\left(i\right) \cdot n\right)}}{i} \]
                6. *-commutativeN/A

                  \[\leadsto \frac{100 \cdot \color{blue}{\left(n \cdot \mathsf{expm1}\left(i\right)\right)}}{i} \]
                7. associate-*r*N/A

                  \[\leadsto \frac{\color{blue}{\left(100 \cdot n\right) \cdot \mathsf{expm1}\left(i\right)}}{i} \]
                8. lower-*.f64N/A

                  \[\leadsto \frac{\color{blue}{\left(100 \cdot n\right) \cdot \mathsf{expm1}\left(i\right)}}{i} \]
                9. lower-*.f6493.1

                  \[\leadsto \frac{\color{blue}{\left(100 \cdot n\right)} \cdot \mathsf{expm1}\left(i\right)}{i} \]
              9. Applied rewrites93.1%

                \[\leadsto \color{blue}{\frac{\left(100 \cdot n\right) \cdot \mathsf{expm1}\left(i\right)}{i}} \]
              10. Taylor expanded in i around 0

                \[\leadsto \frac{\left(100 \cdot n\right) \cdot \left(i \cdot \color{blue}{\left(1 + \frac{1}{2} \cdot i\right)}\right)}{i} \]
              11. Step-by-step derivation
                1. Applied rewrites80.5%

                  \[\leadsto \frac{\left(100 \cdot n\right) \cdot \left(\mathsf{fma}\left(0.5, i, 1\right) \cdot \color{blue}{i}\right)}{i} \]
              12. Recombined 4 regimes into one program.
              13. Add Preprocessing

              Alternative 8: 64.3% accurate, 3.4× speedup?

              \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;n \leq -2.8 \cdot 10^{-134}:\\ \;\;\;\;100 \cdot \mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right) \cdot n, i, n\right)\\ \mathbf{elif}\;n \leq 4.4 \cdot 10^{-181}:\\ \;\;\;\;100 \cdot \frac{1 - 1}{\frac{i}{n}}\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right), i, 1\right) \cdot n\right)\\ \end{array} \end{array} \]
              (FPCore (i n)
               :precision binary64
               (if (<= n -2.8e-134)
                 (* 100.0 (fma (* (fma 0.16666666666666666 i 0.5) n) i n))
                 (if (<= n 4.4e-181)
                   (* 100.0 (/ (- 1.0 1.0) (/ i n)))
                   (* 100.0 (* (fma (fma 0.16666666666666666 i 0.5) i 1.0) n)))))
              double code(double i, double n) {
              	double tmp;
              	if (n <= -2.8e-134) {
              		tmp = 100.0 * fma((fma(0.16666666666666666, i, 0.5) * n), i, n);
              	} else if (n <= 4.4e-181) {
              		tmp = 100.0 * ((1.0 - 1.0) / (i / n));
              	} else {
              		tmp = 100.0 * (fma(fma(0.16666666666666666, i, 0.5), i, 1.0) * n);
              	}
              	return tmp;
              }
              
              function code(i, n)
              	tmp = 0.0
              	if (n <= -2.8e-134)
              		tmp = Float64(100.0 * fma(Float64(fma(0.16666666666666666, i, 0.5) * n), i, n));
              	elseif (n <= 4.4e-181)
              		tmp = Float64(100.0 * Float64(Float64(1.0 - 1.0) / Float64(i / n)));
              	else
              		tmp = Float64(100.0 * Float64(fma(fma(0.16666666666666666, i, 0.5), i, 1.0) * n));
              	end
              	return tmp
              end
              
              code[i_, n_] := If[LessEqual[n, -2.8e-134], N[(100.0 * N[(N[(N[(0.16666666666666666 * i + 0.5), $MachinePrecision] * n), $MachinePrecision] * i + n), $MachinePrecision]), $MachinePrecision], If[LessEqual[n, 4.4e-181], N[(100.0 * N[(N[(1.0 - 1.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(100.0 * N[(N[(N[(0.16666666666666666 * i + 0.5), $MachinePrecision] * i + 1.0), $MachinePrecision] * n), $MachinePrecision]), $MachinePrecision]]]
              
              \begin{array}{l}
              
              \\
              \begin{array}{l}
              \mathbf{if}\;n \leq -2.8 \cdot 10^{-134}:\\
              \;\;\;\;100 \cdot \mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right) \cdot n, i, n\right)\\
              
              \mathbf{elif}\;n \leq 4.4 \cdot 10^{-181}:\\
              \;\;\;\;100 \cdot \frac{1 - 1}{\frac{i}{n}}\\
              
              \mathbf{else}:\\
              \;\;\;\;100 \cdot \left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right), i, 1\right) \cdot n\right)\\
              
              
              \end{array}
              \end{array}
              
              Derivation
              1. Split input into 3 regimes
              2. if n < -2.7999999999999999e-134

                1. Initial program 24.7%

                  \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                2. Add Preprocessing
                3. Taylor expanded in i around 0

                  \[\leadsto 100 \cdot \color{blue}{\left(n + i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right)\right)} \]
                4. Step-by-step derivation
                  1. +-commutativeN/A

                    \[\leadsto 100 \cdot \color{blue}{\left(i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n\right)} \]
                  2. *-commutativeN/A

                    \[\leadsto 100 \cdot \left(\color{blue}{\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) \cdot i} + n\right) \]
                  3. lower-fma.f64N/A

                    \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right), i, n\right)} \]
                5. Applied rewrites55.4%

                  \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(n \cdot i, \left(\frac{0.3333333333333333}{n \cdot n} + 0.16666666666666666\right) - \frac{0.5}{n}, \left(0.5 - \frac{0.5}{n}\right) \cdot n\right), i, n\right)} \]
                6. Taylor expanded in n around inf

                  \[\leadsto 100 \cdot \mathsf{fma}\left(n \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot i\right), i, n\right) \]
                7. Step-by-step derivation
                  1. Applied rewrites55.4%

                    \[\leadsto 100 \cdot \mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right) \cdot n, i, n\right) \]

                  if -2.7999999999999999e-134 < n < 4.39999999999999994e-181

                  1. Initial program 48.5%

                    \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                  2. Add Preprocessing
                  3. Taylor expanded in i around 0

                    \[\leadsto 100 \cdot \frac{\color{blue}{1} - 1}{\frac{i}{n}} \]
                  4. Step-by-step derivation
                    1. Applied rewrites67.8%

                      \[\leadsto 100 \cdot \frac{\color{blue}{1} - 1}{\frac{i}{n}} \]

                    if 4.39999999999999994e-181 < n

                    1. Initial program 23.0%

                      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                    2. Add Preprocessing
                    3. Taylor expanded in i around 0

                      \[\leadsto 100 \cdot \color{blue}{\left(n + i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right)\right)} \]
                    4. Step-by-step derivation
                      1. +-commutativeN/A

                        \[\leadsto 100 \cdot \color{blue}{\left(i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n\right)} \]
                      2. *-commutativeN/A

                        \[\leadsto 100 \cdot \left(\color{blue}{\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) \cdot i} + n\right) \]
                      3. lower-fma.f64N/A

                        \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right), i, n\right)} \]
                    5. Applied rewrites66.7%

                      \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(n \cdot i, \left(\frac{0.3333333333333333}{n \cdot n} + 0.16666666666666666\right) - \frac{0.5}{n}, \left(0.5 - \frac{0.5}{n}\right) \cdot n\right), i, n\right)} \]
                    6. Taylor expanded in n around inf

                      \[\leadsto 100 \cdot \left(n \cdot \color{blue}{\left(1 + i \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot i\right)\right)}\right) \]
                    7. Step-by-step derivation
                      1. Applied rewrites70.3%

                        \[\leadsto 100 \cdot \left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right), i, 1\right) \cdot \color{blue}{n}\right) \]
                    8. Recombined 3 regimes into one program.
                    9. Add Preprocessing

                    Alternative 9: 64.0% accurate, 3.6× speedup?

                    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;n \leq -6.5 \cdot 10^{+46}:\\ \;\;\;\;100 \cdot \mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right) \cdot n, i, n\right)\\ \mathbf{elif}\;n \leq 1.75 \cdot 10^{-31}:\\ \;\;\;\;\frac{100 \cdot i}{\frac{i}{n}}\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right), i, 1\right) \cdot n\right)\\ \end{array} \end{array} \]
                    (FPCore (i n)
                     :precision binary64
                     (if (<= n -6.5e+46)
                       (* 100.0 (fma (* (fma 0.16666666666666666 i 0.5) n) i n))
                       (if (<= n 1.75e-31)
                         (/ (* 100.0 i) (/ i n))
                         (* 100.0 (* (fma (fma 0.16666666666666666 i 0.5) i 1.0) n)))))
                    double code(double i, double n) {
                    	double tmp;
                    	if (n <= -6.5e+46) {
                    		tmp = 100.0 * fma((fma(0.16666666666666666, i, 0.5) * n), i, n);
                    	} else if (n <= 1.75e-31) {
                    		tmp = (100.0 * i) / (i / n);
                    	} else {
                    		tmp = 100.0 * (fma(fma(0.16666666666666666, i, 0.5), i, 1.0) * n);
                    	}
                    	return tmp;
                    }
                    
                    function code(i, n)
                    	tmp = 0.0
                    	if (n <= -6.5e+46)
                    		tmp = Float64(100.0 * fma(Float64(fma(0.16666666666666666, i, 0.5) * n), i, n));
                    	elseif (n <= 1.75e-31)
                    		tmp = Float64(Float64(100.0 * i) / Float64(i / n));
                    	else
                    		tmp = Float64(100.0 * Float64(fma(fma(0.16666666666666666, i, 0.5), i, 1.0) * n));
                    	end
                    	return tmp
                    end
                    
                    code[i_, n_] := If[LessEqual[n, -6.5e+46], N[(100.0 * N[(N[(N[(0.16666666666666666 * i + 0.5), $MachinePrecision] * n), $MachinePrecision] * i + n), $MachinePrecision]), $MachinePrecision], If[LessEqual[n, 1.75e-31], N[(N[(100.0 * i), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision], N[(100.0 * N[(N[(N[(0.16666666666666666 * i + 0.5), $MachinePrecision] * i + 1.0), $MachinePrecision] * n), $MachinePrecision]), $MachinePrecision]]]
                    
                    \begin{array}{l}
                    
                    \\
                    \begin{array}{l}
                    \mathbf{if}\;n \leq -6.5 \cdot 10^{+46}:\\
                    \;\;\;\;100 \cdot \mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right) \cdot n, i, n\right)\\
                    
                    \mathbf{elif}\;n \leq 1.75 \cdot 10^{-31}:\\
                    \;\;\;\;\frac{100 \cdot i}{\frac{i}{n}}\\
                    
                    \mathbf{else}:\\
                    \;\;\;\;100 \cdot \left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right), i, 1\right) \cdot n\right)\\
                    
                    
                    \end{array}
                    \end{array}
                    
                    Derivation
                    1. Split input into 3 regimes
                    2. if n < -6.50000000000000008e46

                      1. Initial program 26.6%

                        \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                      2. Add Preprocessing
                      3. Taylor expanded in i around 0

                        \[\leadsto 100 \cdot \color{blue}{\left(n + i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right)\right)} \]
                      4. Step-by-step derivation
                        1. +-commutativeN/A

                          \[\leadsto 100 \cdot \color{blue}{\left(i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n\right)} \]
                        2. *-commutativeN/A

                          \[\leadsto 100 \cdot \left(\color{blue}{\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) \cdot i} + n\right) \]
                        3. lower-fma.f64N/A

                          \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right), i, n\right)} \]
                      5. Applied rewrites50.1%

                        \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(n \cdot i, \left(\frac{0.3333333333333333}{n \cdot n} + 0.16666666666666666\right) - \frac{0.5}{n}, \left(0.5 - \frac{0.5}{n}\right) \cdot n\right), i, n\right)} \]
                      6. Taylor expanded in n around inf

                        \[\leadsto 100 \cdot \mathsf{fma}\left(n \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot i\right), i, n\right) \]
                      7. Step-by-step derivation
                        1. Applied rewrites50.1%

                          \[\leadsto 100 \cdot \mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right) \cdot n, i, n\right) \]

                        if -6.50000000000000008e46 < n < 1.74999999999999993e-31

                        1. Initial program 32.0%

                          \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                        2. Add Preprocessing
                        3. Step-by-step derivation
                          1. lift-*.f64N/A

                            \[\leadsto \color{blue}{100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
                          2. lift-/.f64N/A

                            \[\leadsto 100 \cdot \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}} \]
                          3. associate-*r/N/A

                            \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\frac{i}{n}}} \]
                          4. lower-/.f64N/A

                            \[\leadsto \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\frac{i}{n}}} \]
                          5. *-commutativeN/A

                            \[\leadsto \frac{\color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right) \cdot 100}}{\frac{i}{n}} \]
                          6. lower-*.f6432.0

                            \[\leadsto \frac{\color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right) \cdot 100}}{\frac{i}{n}} \]
                          7. lift--.f64N/A

                            \[\leadsto \frac{\color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)} \cdot 100}{\frac{i}{n}} \]
                          8. lift-pow.f64N/A

                            \[\leadsto \frac{\left(\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n}} - 1\right) \cdot 100}{\frac{i}{n}} \]
                          9. pow-to-expN/A

                            \[\leadsto \frac{\left(\color{blue}{e^{\log \left(1 + \frac{i}{n}\right) \cdot n}} - 1\right) \cdot 100}{\frac{i}{n}} \]
                          10. lower-expm1.f64N/A

                            \[\leadsto \frac{\color{blue}{\mathsf{expm1}\left(\log \left(1 + \frac{i}{n}\right) \cdot n\right)} \cdot 100}{\frac{i}{n}} \]
                          11. lower-*.f64N/A

                            \[\leadsto \frac{\mathsf{expm1}\left(\color{blue}{\log \left(1 + \frac{i}{n}\right) \cdot n}\right) \cdot 100}{\frac{i}{n}} \]
                          12. lift-+.f64N/A

                            \[\leadsto \frac{\mathsf{expm1}\left(\log \color{blue}{\left(1 + \frac{i}{n}\right)} \cdot n\right) \cdot 100}{\frac{i}{n}} \]
                          13. lower-log1p.f6489.8

                            \[\leadsto \frac{\mathsf{expm1}\left(\color{blue}{\mathsf{log1p}\left(\frac{i}{n}\right)} \cdot n\right) \cdot 100}{\frac{i}{n}} \]
                        4. Applied rewrites89.8%

                          \[\leadsto \color{blue}{\frac{\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n\right) \cdot 100}{\frac{i}{n}}} \]
                        5. Taylor expanded in i around 0

                          \[\leadsto \frac{\color{blue}{100 \cdot i}}{\frac{i}{n}} \]
                        6. Step-by-step derivation
                          1. lower-*.f6460.2

                            \[\leadsto \frac{\color{blue}{100 \cdot i}}{\frac{i}{n}} \]
                        7. Applied rewrites60.2%

                          \[\leadsto \frac{\color{blue}{100 \cdot i}}{\frac{i}{n}} \]

                        if 1.74999999999999993e-31 < n

                        1. Initial program 25.5%

                          \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                        2. Add Preprocessing
                        3. Taylor expanded in i around 0

                          \[\leadsto 100 \cdot \color{blue}{\left(n + i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right)\right)} \]
                        4. Step-by-step derivation
                          1. +-commutativeN/A

                            \[\leadsto 100 \cdot \color{blue}{\left(i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n\right)} \]
                          2. *-commutativeN/A

                            \[\leadsto 100 \cdot \left(\color{blue}{\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) \cdot i} + n\right) \]
                          3. lower-fma.f64N/A

                            \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right), i, n\right)} \]
                        5. Applied rewrites77.3%

                          \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(n \cdot i, \left(\frac{0.3333333333333333}{n \cdot n} + 0.16666666666666666\right) - \frac{0.5}{n}, \left(0.5 - \frac{0.5}{n}\right) \cdot n\right), i, n\right)} \]
                        6. Taylor expanded in n around inf

                          \[\leadsto 100 \cdot \left(n \cdot \color{blue}{\left(1 + i \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot i\right)\right)}\right) \]
                        7. Step-by-step derivation
                          1. Applied rewrites77.3%

                            \[\leadsto 100 \cdot \left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right), i, 1\right) \cdot \color{blue}{n}\right) \]
                        8. Recombined 3 regimes into one program.
                        9. Add Preprocessing

                        Alternative 10: 56.6% accurate, 6.3× speedup?

                        \[\begin{array}{l} \\ 100 \cdot \mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right) \cdot n, i, n\right) \end{array} \]
                        (FPCore (i n)
                         :precision binary64
                         (* 100.0 (fma (* (fma 0.16666666666666666 i 0.5) n) i n)))
                        double code(double i, double n) {
                        	return 100.0 * fma((fma(0.16666666666666666, i, 0.5) * n), i, n);
                        }
                        
                        function code(i, n)
                        	return Float64(100.0 * fma(Float64(fma(0.16666666666666666, i, 0.5) * n), i, n))
                        end
                        
                        code[i_, n_] := N[(100.0 * N[(N[(N[(0.16666666666666666 * i + 0.5), $MachinePrecision] * n), $MachinePrecision] * i + n), $MachinePrecision]), $MachinePrecision]
                        
                        \begin{array}{l}
                        
                        \\
                        100 \cdot \mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right) \cdot n, i, n\right)
                        \end{array}
                        
                        Derivation
                        1. Initial program 28.9%

                          \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                        2. Add Preprocessing
                        3. Taylor expanded in i around 0

                          \[\leadsto 100 \cdot \color{blue}{\left(n + i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right)\right)} \]
                        4. Step-by-step derivation
                          1. +-commutativeN/A

                            \[\leadsto 100 \cdot \color{blue}{\left(i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n\right)} \]
                          2. *-commutativeN/A

                            \[\leadsto 100 \cdot \left(\color{blue}{\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) \cdot i} + n\right) \]
                          3. lower-fma.f64N/A

                            \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right), i, n\right)} \]
                        5. Applied rewrites48.8%

                          \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(n \cdot i, \left(\frac{0.3333333333333333}{n \cdot n} + 0.16666666666666666\right) - \frac{0.5}{n}, \left(0.5 - \frac{0.5}{n}\right) \cdot n\right), i, n\right)} \]
                        6. Taylor expanded in n around inf

                          \[\leadsto 100 \cdot \mathsf{fma}\left(n \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot i\right), i, n\right) \]
                        7. Step-by-step derivation
                          1. Applied rewrites54.4%

                            \[\leadsto 100 \cdot \mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right) \cdot n, i, n\right) \]
                          2. Add Preprocessing

                          Alternative 11: 56.6% accurate, 6.3× speedup?

                          \[\begin{array}{l} \\ 100 \cdot \left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right), i, 1\right) \cdot n\right) \end{array} \]
                          (FPCore (i n)
                           :precision binary64
                           (* 100.0 (* (fma (fma 0.16666666666666666 i 0.5) i 1.0) n)))
                          double code(double i, double n) {
                          	return 100.0 * (fma(fma(0.16666666666666666, i, 0.5), i, 1.0) * n);
                          }
                          
                          function code(i, n)
                          	return Float64(100.0 * Float64(fma(fma(0.16666666666666666, i, 0.5), i, 1.0) * n))
                          end
                          
                          code[i_, n_] := N[(100.0 * N[(N[(N[(0.16666666666666666 * i + 0.5), $MachinePrecision] * i + 1.0), $MachinePrecision] * n), $MachinePrecision]), $MachinePrecision]
                          
                          \begin{array}{l}
                          
                          \\
                          100 \cdot \left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right), i, 1\right) \cdot n\right)
                          \end{array}
                          
                          Derivation
                          1. Initial program 28.9%

                            \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                          2. Add Preprocessing
                          3. Taylor expanded in i around 0

                            \[\leadsto 100 \cdot \color{blue}{\left(n + i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right)\right)} \]
                          4. Step-by-step derivation
                            1. +-commutativeN/A

                              \[\leadsto 100 \cdot \color{blue}{\left(i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n\right)} \]
                            2. *-commutativeN/A

                              \[\leadsto 100 \cdot \left(\color{blue}{\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) \cdot i} + n\right) \]
                            3. lower-fma.f64N/A

                              \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right), i, n\right)} \]
                          5. Applied rewrites48.8%

                            \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(n \cdot i, \left(\frac{0.3333333333333333}{n \cdot n} + 0.16666666666666666\right) - \frac{0.5}{n}, \left(0.5 - \frac{0.5}{n}\right) \cdot n\right), i, n\right)} \]
                          6. Taylor expanded in n around inf

                            \[\leadsto 100 \cdot \left(n \cdot \color{blue}{\left(1 + i \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot i\right)\right)}\right) \]
                          7. Step-by-step derivation
                            1. Applied rewrites54.4%

                              \[\leadsto 100 \cdot \left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right), i, 1\right) \cdot \color{blue}{n}\right) \]
                            2. Add Preprocessing

                            Alternative 12: 54.1% accurate, 6.6× speedup?

                            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;i \leq 2:\\ \;\;\;\;100 \cdot n\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \left(\left(n \cdot i\right) \cdot 0.5\right)\\ \end{array} \end{array} \]
                            (FPCore (i n)
                             :precision binary64
                             (if (<= i 2.0) (* 100.0 n) (* 100.0 (* (* n i) 0.5))))
                            double code(double i, double n) {
                            	double tmp;
                            	if (i <= 2.0) {
                            		tmp = 100.0 * n;
                            	} else {
                            		tmp = 100.0 * ((n * i) * 0.5);
                            	}
                            	return tmp;
                            }
                            
                            real(8) function code(i, n)
                                real(8), intent (in) :: i
                                real(8), intent (in) :: n
                                real(8) :: tmp
                                if (i <= 2.0d0) then
                                    tmp = 100.0d0 * n
                                else
                                    tmp = 100.0d0 * ((n * i) * 0.5d0)
                                end if
                                code = tmp
                            end function
                            
                            public static double code(double i, double n) {
                            	double tmp;
                            	if (i <= 2.0) {
                            		tmp = 100.0 * n;
                            	} else {
                            		tmp = 100.0 * ((n * i) * 0.5);
                            	}
                            	return tmp;
                            }
                            
                            def code(i, n):
                            	tmp = 0
                            	if i <= 2.0:
                            		tmp = 100.0 * n
                            	else:
                            		tmp = 100.0 * ((n * i) * 0.5)
                            	return tmp
                            
                            function code(i, n)
                            	tmp = 0.0
                            	if (i <= 2.0)
                            		tmp = Float64(100.0 * n);
                            	else
                            		tmp = Float64(100.0 * Float64(Float64(n * i) * 0.5));
                            	end
                            	return tmp
                            end
                            
                            function tmp_2 = code(i, n)
                            	tmp = 0.0;
                            	if (i <= 2.0)
                            		tmp = 100.0 * n;
                            	else
                            		tmp = 100.0 * ((n * i) * 0.5);
                            	end
                            	tmp_2 = tmp;
                            end
                            
                            code[i_, n_] := If[LessEqual[i, 2.0], N[(100.0 * n), $MachinePrecision], N[(100.0 * N[(N[(n * i), $MachinePrecision] * 0.5), $MachinePrecision]), $MachinePrecision]]
                            
                            \begin{array}{l}
                            
                            \\
                            \begin{array}{l}
                            \mathbf{if}\;i \leq 2:\\
                            \;\;\;\;100 \cdot n\\
                            
                            \mathbf{else}:\\
                            \;\;\;\;100 \cdot \left(\left(n \cdot i\right) \cdot 0.5\right)\\
                            
                            
                            \end{array}
                            \end{array}
                            
                            Derivation
                            1. Split input into 2 regimes
                            2. if i < 2

                              1. Initial program 23.0%

                                \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                              2. Add Preprocessing
                              3. Taylor expanded in i around 0

                                \[\leadsto \color{blue}{100 \cdot n} \]
                              4. Step-by-step derivation
                                1. lower-*.f6461.7

                                  \[\leadsto \color{blue}{100 \cdot n} \]
                              5. Applied rewrites61.7%

                                \[\leadsto \color{blue}{100 \cdot n} \]

                              if 2 < i

                              1. Initial program 46.2%

                                \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                              2. Add Preprocessing
                              3. Taylor expanded in i around 0

                                \[\leadsto 100 \cdot \color{blue}{\left(n + i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right)\right)} \]
                              4. Step-by-step derivation
                                1. +-commutativeN/A

                                  \[\leadsto 100 \cdot \color{blue}{\left(i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n\right)} \]
                                2. *-commutativeN/A

                                  \[\leadsto 100 \cdot \left(\color{blue}{\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) \cdot i} + n\right) \]
                                3. lower-fma.f64N/A

                                  \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right), i, n\right)} \]
                              5. Applied rewrites31.5%

                                \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(n \cdot i, \left(\frac{0.3333333333333333}{n \cdot n} + 0.16666666666666666\right) - \frac{0.5}{n}, \left(0.5 - \frac{0.5}{n}\right) \cdot n\right), i, n\right)} \]
                              6. Taylor expanded in n around inf

                                \[\leadsto 100 \cdot \left(n \cdot \color{blue}{\left(1 + i \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot i\right)\right)}\right) \]
                              7. Step-by-step derivation
                                1. Applied rewrites32.0%

                                  \[\leadsto 100 \cdot \left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right), i, 1\right) \cdot \color{blue}{n}\right) \]
                                2. Taylor expanded in i around inf

                                  \[\leadsto 100 \cdot \left({i}^{2} \cdot \left(\frac{1}{6} \cdot n + \color{blue}{\frac{1}{2} \cdot \frac{n}{i}}\right)\right) \]
                                3. Step-by-step derivation
                                  1. Applied rewrites32.0%

                                    \[\leadsto 100 \cdot \left(\mathsf{fma}\left(\frac{n}{i}, 0.5, 0.16666666666666666 \cdot n\right) \cdot \left(i \cdot \color{blue}{i}\right)\right) \]
                                  2. Taylor expanded in i around 0

                                    \[\leadsto 100 \cdot \left(\frac{1}{2} \cdot \left(i \cdot n\right)\right) \]
                                  3. Step-by-step derivation
                                    1. Applied rewrites26.5%

                                      \[\leadsto 100 \cdot \left(\left(n \cdot i\right) \cdot 0.5\right) \]
                                  4. Recombined 2 regimes into one program.
                                  5. Add Preprocessing

                                  Alternative 13: 56.2% accurate, 6.6× speedup?

                                  \[\begin{array}{l} \\ 100 \cdot \left(\mathsf{fma}\left(0.16666666666666666 \cdot i, i, 1\right) \cdot n\right) \end{array} \]
                                  (FPCore (i n)
                                   :precision binary64
                                   (* 100.0 (* (fma (* 0.16666666666666666 i) i 1.0) n)))
                                  double code(double i, double n) {
                                  	return 100.0 * (fma((0.16666666666666666 * i), i, 1.0) * n);
                                  }
                                  
                                  function code(i, n)
                                  	return Float64(100.0 * Float64(fma(Float64(0.16666666666666666 * i), i, 1.0) * n))
                                  end
                                  
                                  code[i_, n_] := N[(100.0 * N[(N[(N[(0.16666666666666666 * i), $MachinePrecision] * i + 1.0), $MachinePrecision] * n), $MachinePrecision]), $MachinePrecision]
                                  
                                  \begin{array}{l}
                                  
                                  \\
                                  100 \cdot \left(\mathsf{fma}\left(0.16666666666666666 \cdot i, i, 1\right) \cdot n\right)
                                  \end{array}
                                  
                                  Derivation
                                  1. Initial program 28.9%

                                    \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in i around 0

                                    \[\leadsto 100 \cdot \color{blue}{\left(n + i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right)\right)} \]
                                  4. Step-by-step derivation
                                    1. +-commutativeN/A

                                      \[\leadsto 100 \cdot \color{blue}{\left(i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n\right)} \]
                                    2. *-commutativeN/A

                                      \[\leadsto 100 \cdot \left(\color{blue}{\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) \cdot i} + n\right) \]
                                    3. lower-fma.f64N/A

                                      \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right), i, n\right)} \]
                                  5. Applied rewrites48.8%

                                    \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(n \cdot i, \left(\frac{0.3333333333333333}{n \cdot n} + 0.16666666666666666\right) - \frac{0.5}{n}, \left(0.5 - \frac{0.5}{n}\right) \cdot n\right), i, n\right)} \]
                                  6. Taylor expanded in n around inf

                                    \[\leadsto 100 \cdot \left(n \cdot \color{blue}{\left(1 + i \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot i\right)\right)}\right) \]
                                  7. Step-by-step derivation
                                    1. Applied rewrites54.4%

                                      \[\leadsto 100 \cdot \left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right), i, 1\right) \cdot \color{blue}{n}\right) \]
                                    2. Taylor expanded in i around inf

                                      \[\leadsto 100 \cdot \left(\mathsf{fma}\left(\frac{1}{6} \cdot i, i, 1\right) \cdot n\right) \]
                                    3. Step-by-step derivation
                                      1. Applied rewrites53.8%

                                        \[\leadsto 100 \cdot \left(\mathsf{fma}\left(0.16666666666666666 \cdot i, i, 1\right) \cdot n\right) \]
                                      2. Add Preprocessing

                                      Alternative 14: 54.2% accurate, 8.6× speedup?

                                      \[\begin{array}{l} \\ 100 \cdot \mathsf{fma}\left(n \cdot i, 0.5, n\right) \end{array} \]
                                      (FPCore (i n) :precision binary64 (* 100.0 (fma (* n i) 0.5 n)))
                                      double code(double i, double n) {
                                      	return 100.0 * fma((n * i), 0.5, n);
                                      }
                                      
                                      function code(i, n)
                                      	return Float64(100.0 * fma(Float64(n * i), 0.5, n))
                                      end
                                      
                                      code[i_, n_] := N[(100.0 * N[(N[(n * i), $MachinePrecision] * 0.5 + n), $MachinePrecision]), $MachinePrecision]
                                      
                                      \begin{array}{l}
                                      
                                      \\
                                      100 \cdot \mathsf{fma}\left(n \cdot i, 0.5, n\right)
                                      \end{array}
                                      
                                      Derivation
                                      1. Initial program 28.9%

                                        \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                                      2. Add Preprocessing
                                      3. Taylor expanded in i around 0

                                        \[\leadsto 100 \cdot \color{blue}{\left(n + i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right)\right)} \]
                                      4. Step-by-step derivation
                                        1. +-commutativeN/A

                                          \[\leadsto 100 \cdot \color{blue}{\left(i \cdot \left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n\right)} \]
                                        2. *-commutativeN/A

                                          \[\leadsto 100 \cdot \left(\color{blue}{\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right)\right) \cdot i} + n\right) \]
                                        3. lower-fma.f64N/A

                                          \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(i \cdot \left(n \cdot \left(\left(\frac{1}{6} + \frac{1}{3} \cdot \frac{1}{{n}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{n}\right)\right) + n \cdot \left(\frac{1}{2} - \frac{1}{2} \cdot \frac{1}{n}\right), i, n\right)} \]
                                      5. Applied rewrites48.8%

                                        \[\leadsto 100 \cdot \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(n \cdot i, \left(\frac{0.3333333333333333}{n \cdot n} + 0.16666666666666666\right) - \frac{0.5}{n}, \left(0.5 - \frac{0.5}{n}\right) \cdot n\right), i, n\right)} \]
                                      6. Taylor expanded in n around inf

                                        \[\leadsto 100 \cdot \left(n \cdot \color{blue}{\left(1 + i \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot i\right)\right)}\right) \]
                                      7. Step-by-step derivation
                                        1. Applied rewrites54.4%

                                          \[\leadsto 100 \cdot \left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, i, 0.5\right), i, 1\right) \cdot \color{blue}{n}\right) \]
                                        2. Taylor expanded in i around 0

                                          \[\leadsto 100 \cdot \left(n + \frac{1}{2} \cdot \color{blue}{\left(i \cdot n\right)}\right) \]
                                        3. Step-by-step derivation
                                          1. Applied rewrites53.0%

                                            \[\leadsto 100 \cdot \mathsf{fma}\left(n \cdot i, 0.5, n\right) \]
                                          2. Add Preprocessing

                                          Alternative 15: 48.6% accurate, 24.3× speedup?

                                          \[\begin{array}{l} \\ 100 \cdot n \end{array} \]
                                          (FPCore (i n) :precision binary64 (* 100.0 n))
                                          double code(double i, double n) {
                                          	return 100.0 * n;
                                          }
                                          
                                          real(8) function code(i, n)
                                              real(8), intent (in) :: i
                                              real(8), intent (in) :: n
                                              code = 100.0d0 * n
                                          end function
                                          
                                          public static double code(double i, double n) {
                                          	return 100.0 * n;
                                          }
                                          
                                          def code(i, n):
                                          	return 100.0 * n
                                          
                                          function code(i, n)
                                          	return Float64(100.0 * n)
                                          end
                                          
                                          function tmp = code(i, n)
                                          	tmp = 100.0 * n;
                                          end
                                          
                                          code[i_, n_] := N[(100.0 * n), $MachinePrecision]
                                          
                                          \begin{array}{l}
                                          
                                          \\
                                          100 \cdot n
                                          \end{array}
                                          
                                          Derivation
                                          1. Initial program 28.9%

                                            \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
                                          2. Add Preprocessing
                                          3. Taylor expanded in i around 0

                                            \[\leadsto \color{blue}{100 \cdot n} \]
                                          4. Step-by-step derivation
                                            1. lower-*.f6447.5

                                              \[\leadsto \color{blue}{100 \cdot n} \]
                                          5. Applied rewrites47.5%

                                            \[\leadsto \color{blue}{100 \cdot n} \]
                                          6. Add Preprocessing

                                          Developer Target 1: 35.5% accurate, 0.5× speedup?

                                          \[\begin{array}{l} \\ \begin{array}{l} t_0 := 1 + \frac{i}{n}\\ 100 \cdot \frac{e^{n \cdot \begin{array}{l} \mathbf{if}\;t\_0 = 1:\\ \;\;\;\;\frac{i}{n}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{i}{n} \cdot \log t\_0}{\left(\frac{i}{n} + 1\right) - 1}\\ \end{array}} - 1}{\frac{i}{n}} \end{array} \end{array} \]
                                          (FPCore (i n)
                                           :precision binary64
                                           (let* ((t_0 (+ 1.0 (/ i n))))
                                             (*
                                              100.0
                                              (/
                                               (-
                                                (exp
                                                 (*
                                                  n
                                                  (if (== t_0 1.0)
                                                    (/ i n)
                                                    (/ (* (/ i n) (log t_0)) (- (+ (/ i n) 1.0) 1.0)))))
                                                1.0)
                                               (/ i n)))))
                                          double code(double i, double n) {
                                          	double t_0 = 1.0 + (i / n);
                                          	double tmp;
                                          	if (t_0 == 1.0) {
                                          		tmp = i / n;
                                          	} else {
                                          		tmp = ((i / n) * log(t_0)) / (((i / n) + 1.0) - 1.0);
                                          	}
                                          	return 100.0 * ((exp((n * tmp)) - 1.0) / (i / n));
                                          }
                                          
                                          real(8) function code(i, n)
                                              real(8), intent (in) :: i
                                              real(8), intent (in) :: n
                                              real(8) :: t_0
                                              real(8) :: tmp
                                              t_0 = 1.0d0 + (i / n)
                                              if (t_0 == 1.0d0) then
                                                  tmp = i / n
                                              else
                                                  tmp = ((i / n) * log(t_0)) / (((i / n) + 1.0d0) - 1.0d0)
                                              end if
                                              code = 100.0d0 * ((exp((n * tmp)) - 1.0d0) / (i / n))
                                          end function
                                          
                                          public static double code(double i, double n) {
                                          	double t_0 = 1.0 + (i / n);
                                          	double tmp;
                                          	if (t_0 == 1.0) {
                                          		tmp = i / n;
                                          	} else {
                                          		tmp = ((i / n) * Math.log(t_0)) / (((i / n) + 1.0) - 1.0);
                                          	}
                                          	return 100.0 * ((Math.exp((n * tmp)) - 1.0) / (i / n));
                                          }
                                          
                                          def code(i, n):
                                          	t_0 = 1.0 + (i / n)
                                          	tmp = 0
                                          	if t_0 == 1.0:
                                          		tmp = i / n
                                          	else:
                                          		tmp = ((i / n) * math.log(t_0)) / (((i / n) + 1.0) - 1.0)
                                          	return 100.0 * ((math.exp((n * tmp)) - 1.0) / (i / n))
                                          
                                          function code(i, n)
                                          	t_0 = Float64(1.0 + Float64(i / n))
                                          	tmp = 0.0
                                          	if (t_0 == 1.0)
                                          		tmp = Float64(i / n);
                                          	else
                                          		tmp = Float64(Float64(Float64(i / n) * log(t_0)) / Float64(Float64(Float64(i / n) + 1.0) - 1.0));
                                          	end
                                          	return Float64(100.0 * Float64(Float64(exp(Float64(n * tmp)) - 1.0) / Float64(i / n)))
                                          end
                                          
                                          function tmp_2 = code(i, n)
                                          	t_0 = 1.0 + (i / n);
                                          	tmp = 0.0;
                                          	if (t_0 == 1.0)
                                          		tmp = i / n;
                                          	else
                                          		tmp = ((i / n) * log(t_0)) / (((i / n) + 1.0) - 1.0);
                                          	end
                                          	tmp_2 = 100.0 * ((exp((n * tmp)) - 1.0) / (i / n));
                                          end
                                          
                                          code[i_, n_] := Block[{t$95$0 = N[(1.0 + N[(i / n), $MachinePrecision]), $MachinePrecision]}, N[(100.0 * N[(N[(N[Exp[N[(n * If[Equal[t$95$0, 1.0], N[(i / n), $MachinePrecision], N[(N[(N[(i / n), $MachinePrecision] * N[Log[t$95$0], $MachinePrecision]), $MachinePrecision] / N[(N[(N[(i / n), $MachinePrecision] + 1.0), $MachinePrecision] - 1.0), $MachinePrecision]), $MachinePrecision]]), $MachinePrecision]], $MachinePrecision] - 1.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
                                          
                                          \begin{array}{l}
                                          
                                          \\
                                          \begin{array}{l}
                                          t_0 := 1 + \frac{i}{n}\\
                                          100 \cdot \frac{e^{n \cdot \begin{array}{l}
                                          \mathbf{if}\;t\_0 = 1:\\
                                          \;\;\;\;\frac{i}{n}\\
                                          
                                          \mathbf{else}:\\
                                          \;\;\;\;\frac{\frac{i}{n} \cdot \log t\_0}{\left(\frac{i}{n} + 1\right) - 1}\\
                                          
                                          
                                          \end{array}} - 1}{\frac{i}{n}}
                                          \end{array}
                                          \end{array}
                                          

                                          Reproduce

                                          ?
                                          herbie shell --seed 2024326 
                                          (FPCore (i n)
                                            :name "Compound Interest"
                                            :precision binary64
                                          
                                            :alt
                                            (! :herbie-platform default (let ((lnbase (if (== (+ 1 (/ i n)) 1) (/ i n) (/ (* (/ i n) (log (+ 1 (/ i n)))) (- (+ (/ i n) 1) 1))))) (* 100 (/ (- (exp (* n lnbase)) 1) (/ i n)))))
                                          
                                            (* 100.0 (/ (- (pow (+ 1.0 (/ i n)) n) 1.0) (/ i n))))