ABCF->ab-angle a

Percentage Accurate: 19.1% → 62.0%
Time: 13.8s
Alternatives: 12
Speedup: 16.9×

Specification

?
\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
real(8) function code(a, b, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) + sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 12 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 19.1% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
real(8) function code(a, b, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) + sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Alternative 1: 62.0% accurate, 0.3× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C\\ t_1 := -\sqrt{F}\\ t_2 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\ t_3 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\ t_4 := \frac{\sqrt{\left(2 \cdot \left(t\_3 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_3}\\ \mathbf{if}\;t\_4 \leq -1 \cdot 10^{-194}:\\ \;\;\;\;\frac{\left(\sqrt{t\_0 \cdot 2} \cdot t\_1\right) \cdot \sqrt{t\_2}}{t\_3}\\ \mathbf{elif}\;t\_4 \leq 0:\\ \;\;\;\;\frac{\sqrt{\left(\left(C + -0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right) + C\right) \cdot t\_2} \cdot \left(-\sqrt{F \cdot 2}\right)}{t\_3}\\ \mathbf{elif}\;t\_4 \leq \infty:\\ \;\;\;\;\sqrt{t\_0} \cdot \frac{\sqrt{\left(F \cdot 2\right) \cdot t\_2}}{\mathsf{fma}\left(-B\_m, B\_m, C \cdot \left(A \cdot 4\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;t\_1 \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (let* ((t_0 (+ (+ (hypot (- A C) B_m) A) C))
        (t_1 (- (sqrt F)))
        (t_2 (fma (* -4.0 C) A (* B_m B_m)))
        (t_3 (- (pow B_m 2.0) (* (* 4.0 A) C)))
        (t_4
         (/
          (sqrt
           (*
            (* 2.0 (* t_3 F))
            (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))))
          (- t_3))))
   (if (<= t_4 -1e-194)
     (/ (* (* (sqrt (* t_0 2.0)) t_1) (sqrt t_2)) t_3)
     (if (<= t_4 0.0)
       (/
        (*
         (sqrt (* (+ (+ C (* -0.5 (/ (* B_m B_m) A))) C) t_2))
         (- (sqrt (* F 2.0))))
        t_3)
       (if (<= t_4 INFINITY)
         (*
          (sqrt t_0)
          (/ (sqrt (* (* F 2.0) t_2)) (fma (- B_m) B_m (* C (* A 4.0)))))
         (* t_1 (sqrt (/ 2.0 B_m))))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double t_0 = (hypot((A - C), B_m) + A) + C;
	double t_1 = -sqrt(F);
	double t_2 = fma((-4.0 * C), A, (B_m * B_m));
	double t_3 = pow(B_m, 2.0) - ((4.0 * A) * C);
	double t_4 = sqrt(((2.0 * (t_3 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))))) / -t_3;
	double tmp;
	if (t_4 <= -1e-194) {
		tmp = ((sqrt((t_0 * 2.0)) * t_1) * sqrt(t_2)) / t_3;
	} else if (t_4 <= 0.0) {
		tmp = (sqrt((((C + (-0.5 * ((B_m * B_m) / A))) + C) * t_2)) * -sqrt((F * 2.0))) / t_3;
	} else if (t_4 <= ((double) INFINITY)) {
		tmp = sqrt(t_0) * (sqrt(((F * 2.0) * t_2)) / fma(-B_m, B_m, (C * (A * 4.0))));
	} else {
		tmp = t_1 * sqrt((2.0 / B_m));
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	t_0 = Float64(Float64(hypot(Float64(A - C), B_m) + A) + C)
	t_1 = Float64(-sqrt(F))
	t_2 = fma(Float64(-4.0 * C), A, Float64(B_m * B_m))
	t_3 = Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C))
	t_4 = Float64(sqrt(Float64(Float64(2.0 * Float64(t_3 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))))) / Float64(-t_3))
	tmp = 0.0
	if (t_4 <= -1e-194)
		tmp = Float64(Float64(Float64(sqrt(Float64(t_0 * 2.0)) * t_1) * sqrt(t_2)) / t_3);
	elseif (t_4 <= 0.0)
		tmp = Float64(Float64(sqrt(Float64(Float64(Float64(C + Float64(-0.5 * Float64(Float64(B_m * B_m) / A))) + C) * t_2)) * Float64(-sqrt(Float64(F * 2.0)))) / t_3);
	elseif (t_4 <= Inf)
		tmp = Float64(sqrt(t_0) * Float64(sqrt(Float64(Float64(F * 2.0) * t_2)) / fma(Float64(-B_m), B_m, Float64(C * Float64(A * 4.0)))));
	else
		tmp = Float64(t_1 * sqrt(Float64(2.0 / B_m)));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision]}, Block[{t$95$1 = (-N[Sqrt[F], $MachinePrecision])}, Block[{t$95$2 = N[(N[(-4.0 * C), $MachinePrecision] * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$4 = N[(N[Sqrt[N[(N[(2.0 * N[(t$95$3 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$3)), $MachinePrecision]}, If[LessEqual[t$95$4, -1e-194], N[(N[(N[(N[Sqrt[N[(t$95$0 * 2.0), $MachinePrecision]], $MachinePrecision] * t$95$1), $MachinePrecision] * N[Sqrt[t$95$2], $MachinePrecision]), $MachinePrecision] / t$95$3), $MachinePrecision], If[LessEqual[t$95$4, 0.0], N[(N[(N[Sqrt[N[(N[(N[(C + N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + C), $MachinePrecision] * t$95$2), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision])), $MachinePrecision] / t$95$3), $MachinePrecision], If[LessEqual[t$95$4, Infinity], N[(N[Sqrt[t$95$0], $MachinePrecision] * N[(N[Sqrt[N[(N[(F * 2.0), $MachinePrecision] * t$95$2), $MachinePrecision]], $MachinePrecision] / N[((-B$95$m) * B$95$m + N[(C * N[(A * 4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(t$95$1 * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]]]]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
t_0 := \left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C\\
t_1 := -\sqrt{F}\\
t_2 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\
t_3 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\
t_4 := \frac{\sqrt{\left(2 \cdot \left(t\_3 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_3}\\
\mathbf{if}\;t\_4 \leq -1 \cdot 10^{-194}:\\
\;\;\;\;\frac{\left(\sqrt{t\_0 \cdot 2} \cdot t\_1\right) \cdot \sqrt{t\_2}}{t\_3}\\

\mathbf{elif}\;t\_4 \leq 0:\\
\;\;\;\;\frac{\sqrt{\left(\left(C + -0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right) + C\right) \cdot t\_2} \cdot \left(-\sqrt{F \cdot 2}\right)}{t\_3}\\

\mathbf{elif}\;t\_4 \leq \infty:\\
\;\;\;\;\sqrt{t\_0} \cdot \frac{\sqrt{\left(F \cdot 2\right) \cdot t\_2}}{\mathsf{fma}\left(-B\_m, B\_m, C \cdot \left(A \cdot 4\right)\right)}\\

\mathbf{else}:\\
\;\;\;\;t\_1 \cdot \sqrt{\frac{2}{B\_m}}\\


\end{array}
\end{array}
Derivation
  1. Split input into 4 regimes
  2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -1.00000000000000002e-194

    1. Initial program 43.3%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. *-commutativeN/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. associate-*r*N/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2\right) \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. sqrt-prodN/A

        \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot \sqrt{\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      7. pow1/2N/A

        \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot \color{blue}{{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      8. lower-*.f64N/A

        \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot {\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Applied rewrites60.6%

      \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    5. Applied rewrites76.1%

      \[\leadsto \frac{\color{blue}{\left(\left(-\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot 2}\right) \cdot \sqrt{F}\right) \cdot \sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

    if -1.00000000000000002e-194 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -0.0

    1. Initial program 3.5%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. *-commutativeN/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. associate-*r*N/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2\right) \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. sqrt-prodN/A

        \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot \sqrt{\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      7. pow1/2N/A

        \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot \color{blue}{{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      8. lower-*.f64N/A

        \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot {\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Applied rewrites3.7%

      \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    5. Applied rewrites17.8%

      \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \sqrt{F \cdot 2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    6. Taylor expanded in A around -inf

      \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \sqrt{F \cdot 2}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    7. Step-by-step derivation
      1. lower-+.f64N/A

        \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \sqrt{F \cdot 2}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(\left(C + \color{blue}{\frac{-1}{2} \cdot \frac{{B}^{2}}{A}}\right) + C\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \sqrt{F \cdot 2}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. lower-/.f64N/A

        \[\leadsto \frac{-\sqrt{\left(\left(C + \frac{-1}{2} \cdot \color{blue}{\frac{{B}^{2}}{A}}\right) + C\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \sqrt{F \cdot 2}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. unpow2N/A

        \[\leadsto \frac{-\sqrt{\left(\left(C + \frac{-1}{2} \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \sqrt{F \cdot 2}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. lower-*.f6432.9

        \[\leadsto \frac{-\sqrt{\left(\left(C + -0.5 \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \sqrt{F \cdot 2}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    8. Applied rewrites32.9%

      \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(C + -0.5 \cdot \frac{B \cdot B}{A}\right)} + C\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \sqrt{F \cdot 2}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

    if -0.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

    1. Initial program 33.5%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. *-commutativeN/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. associate-*r*N/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2\right) \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. sqrt-prodN/A

        \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot \sqrt{\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      7. pow1/2N/A

        \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot \color{blue}{{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      8. lower-*.f64N/A

        \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot {\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Applied rewrites83.9%

      \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    5. Applied rewrites83.9%

      \[\leadsto \color{blue}{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C} \cdot \frac{\sqrt{\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}}{\mathsf{fma}\left(-B, B, C \cdot \left(A \cdot 4\right)\right)}} \]

    if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

    1. Initial program 0.0%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in B around inf

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
    4. Step-by-step derivation
      1. mul-1-negN/A

        \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
      2. *-commutativeN/A

        \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
      3. distribute-lft-neg-inN/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
      4. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
      5. lower-neg.f64N/A

        \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
      6. lower-sqrt.f64N/A

        \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
      7. lower-sqrt.f64N/A

        \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
      8. lower-/.f6419.4

        \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
    5. Applied rewrites19.4%

      \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
    6. Step-by-step derivation
      1. Applied rewrites19.4%

        \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
      2. Step-by-step derivation
        1. Applied rewrites23.1%

          \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
      3. Recombined 4 regimes into one program.
      4. Final simplification50.0%

        \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -1 \cdot 10^{-194}:\\ \;\;\;\;\frac{\left(\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot 2} \cdot \left(-\sqrt{F}\right)\right) \cdot \sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq 0:\\ \;\;\;\;\frac{\sqrt{\left(\left(C + -0.5 \cdot \frac{B \cdot B}{A}\right) + C\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \left(-\sqrt{F \cdot 2}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq \infty:\\ \;\;\;\;\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C} \cdot \frac{\sqrt{\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}}{\mathsf{fma}\left(-B, B, C \cdot \left(A \cdot 4\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
      5. Add Preprocessing

      Alternative 2: 59.6% accurate, 0.2× speedup?

      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ t_1 := \left(4 \cdot A\right) \cdot C\\ t_2 := {B\_m}^{2} - t\_1\\ t_3 := \frac{\sqrt{\left(2 \cdot \left(t\_2 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_2}\\ t_4 := \left(C + -0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right) + C\\ t_5 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;t\_3 \leq -\infty:\\ \;\;\;\;\frac{\sqrt{t\_4 \cdot 2} \cdot \left(-\sqrt{F \cdot t\_0}\right)}{t\_2}\\ \mathbf{elif}\;t\_3 \leq -1 \cdot 10^{-194}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B\_m, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot t\_0\right)}}{\mathsf{fma}\left(-B\_m, B\_m, t\_1\right)}\\ \mathbf{elif}\;t\_3 \leq 0:\\ \;\;\;\;\frac{\sqrt{t\_4 \cdot t\_5} \cdot \left(-\sqrt{F \cdot 2}\right)}{t\_2}\\ \mathbf{elif}\;t\_3 \leq \infty:\\ \;\;\;\;\sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C} \cdot \frac{\sqrt{\left(F \cdot 2\right) \cdot t\_5}}{\mathsf{fma}\left(-B\_m, B\_m, C \cdot \left(A \cdot 4\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
      B_m = (fabs.f64 B)
      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
      (FPCore (A B_m C F)
       :precision binary64
       (let* ((t_0 (fma -4.0 (* C A) (* B_m B_m)))
              (t_1 (* (* 4.0 A) C))
              (t_2 (- (pow B_m 2.0) t_1))
              (t_3
               (/
                (sqrt
                 (*
                  (* 2.0 (* t_2 F))
                  (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))))
                (- t_2)))
              (t_4 (+ (+ C (* -0.5 (/ (* B_m B_m) A))) C))
              (t_5 (fma (* -4.0 C) A (* B_m B_m))))
         (if (<= t_3 (- INFINITY))
           (/ (* (sqrt (* t_4 2.0)) (- (sqrt (* F t_0)))) t_2)
           (if (<= t_3 -1e-194)
             (/
              (sqrt (* (+ (+ (hypot B_m (- A C)) A) C) (* (* 2.0 F) t_0)))
              (fma (- B_m) B_m t_1))
             (if (<= t_3 0.0)
               (/ (* (sqrt (* t_4 t_5)) (- (sqrt (* F 2.0)))) t_2)
               (if (<= t_3 INFINITY)
                 (*
                  (sqrt (+ (+ (hypot (- A C) B_m) A) C))
                  (/ (sqrt (* (* F 2.0) t_5)) (fma (- B_m) B_m (* C (* A 4.0)))))
                 (* (- (sqrt F)) (sqrt (/ 2.0 B_m)))))))))
      B_m = fabs(B);
      assert(A < B_m && B_m < C && C < F);
      double code(double A, double B_m, double C, double F) {
      	double t_0 = fma(-4.0, (C * A), (B_m * B_m));
      	double t_1 = (4.0 * A) * C;
      	double t_2 = pow(B_m, 2.0) - t_1;
      	double t_3 = sqrt(((2.0 * (t_2 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))))) / -t_2;
      	double t_4 = (C + (-0.5 * ((B_m * B_m) / A))) + C;
      	double t_5 = fma((-4.0 * C), A, (B_m * B_m));
      	double tmp;
      	if (t_3 <= -((double) INFINITY)) {
      		tmp = (sqrt((t_4 * 2.0)) * -sqrt((F * t_0))) / t_2;
      	} else if (t_3 <= -1e-194) {
      		tmp = sqrt((((hypot(B_m, (A - C)) + A) + C) * ((2.0 * F) * t_0))) / fma(-B_m, B_m, t_1);
      	} else if (t_3 <= 0.0) {
      		tmp = (sqrt((t_4 * t_5)) * -sqrt((F * 2.0))) / t_2;
      	} else if (t_3 <= ((double) INFINITY)) {
      		tmp = sqrt(((hypot((A - C), B_m) + A) + C)) * (sqrt(((F * 2.0) * t_5)) / fma(-B_m, B_m, (C * (A * 4.0))));
      	} else {
      		tmp = -sqrt(F) * sqrt((2.0 / B_m));
      	}
      	return tmp;
      }
      
      B_m = abs(B)
      A, B_m, C, F = sort([A, B_m, C, F])
      function code(A, B_m, C, F)
      	t_0 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
      	t_1 = Float64(Float64(4.0 * A) * C)
      	t_2 = Float64((B_m ^ 2.0) - t_1)
      	t_3 = Float64(sqrt(Float64(Float64(2.0 * Float64(t_2 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))))) / Float64(-t_2))
      	t_4 = Float64(Float64(C + Float64(-0.5 * Float64(Float64(B_m * B_m) / A))) + C)
      	t_5 = fma(Float64(-4.0 * C), A, Float64(B_m * B_m))
      	tmp = 0.0
      	if (t_3 <= Float64(-Inf))
      		tmp = Float64(Float64(sqrt(Float64(t_4 * 2.0)) * Float64(-sqrt(Float64(F * t_0)))) / t_2);
      	elseif (t_3 <= -1e-194)
      		tmp = Float64(sqrt(Float64(Float64(Float64(hypot(B_m, Float64(A - C)) + A) + C) * Float64(Float64(2.0 * F) * t_0))) / fma(Float64(-B_m), B_m, t_1));
      	elseif (t_3 <= 0.0)
      		tmp = Float64(Float64(sqrt(Float64(t_4 * t_5)) * Float64(-sqrt(Float64(F * 2.0)))) / t_2);
      	elseif (t_3 <= Inf)
      		tmp = Float64(sqrt(Float64(Float64(hypot(Float64(A - C), B_m) + A) + C)) * Float64(sqrt(Float64(Float64(F * 2.0) * t_5)) / fma(Float64(-B_m), B_m, Float64(C * Float64(A * 4.0)))));
      	else
      		tmp = Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)));
      	end
      	return tmp
      end
      
      B_m = N[Abs[B], $MachinePrecision]
      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
      code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]}, Block[{t$95$2 = N[(N[Power[B$95$m, 2.0], $MachinePrecision] - t$95$1), $MachinePrecision]}, Block[{t$95$3 = N[(N[Sqrt[N[(N[(2.0 * N[(t$95$2 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$2)), $MachinePrecision]}, Block[{t$95$4 = N[(N[(C + N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + C), $MachinePrecision]}, Block[{t$95$5 = N[(N[(-4.0 * C), $MachinePrecision] * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$3, (-Infinity)], N[(N[(N[Sqrt[N[(t$95$4 * 2.0), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[N[(F * t$95$0), $MachinePrecision]], $MachinePrecision])), $MachinePrecision] / t$95$2), $MachinePrecision], If[LessEqual[t$95$3, -1e-194], N[(N[Sqrt[N[(N[(N[(N[Sqrt[B$95$m ^ 2 + N[(A - C), $MachinePrecision] ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision] * N[(N[(2.0 * F), $MachinePrecision] * t$95$0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[((-B$95$m) * B$95$m + t$95$1), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$3, 0.0], N[(N[(N[Sqrt[N[(t$95$4 * t$95$5), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision])), $MachinePrecision] / t$95$2), $MachinePrecision], If[LessEqual[t$95$3, Infinity], N[(N[Sqrt[N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[N[(N[(F * 2.0), $MachinePrecision] * t$95$5), $MachinePrecision]], $MachinePrecision] / N[((-B$95$m) * B$95$m + N[(C * N[(A * 4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]]]]]]]]
      
      \begin{array}{l}
      B_m = \left|B\right|
      \\
      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
      \\
      \begin{array}{l}
      t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
      t_1 := \left(4 \cdot A\right) \cdot C\\
      t_2 := {B\_m}^{2} - t\_1\\
      t_3 := \frac{\sqrt{\left(2 \cdot \left(t\_2 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_2}\\
      t_4 := \left(C + -0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right) + C\\
      t_5 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\
      \mathbf{if}\;t\_3 \leq -\infty:\\
      \;\;\;\;\frac{\sqrt{t\_4 \cdot 2} \cdot \left(-\sqrt{F \cdot t\_0}\right)}{t\_2}\\
      
      \mathbf{elif}\;t\_3 \leq -1 \cdot 10^{-194}:\\
      \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B\_m, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot t\_0\right)}}{\mathsf{fma}\left(-B\_m, B\_m, t\_1\right)}\\
      
      \mathbf{elif}\;t\_3 \leq 0:\\
      \;\;\;\;\frac{\sqrt{t\_4 \cdot t\_5} \cdot \left(-\sqrt{F \cdot 2}\right)}{t\_2}\\
      
      \mathbf{elif}\;t\_3 \leq \infty:\\
      \;\;\;\;\sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C} \cdot \frac{\sqrt{\left(F \cdot 2\right) \cdot t\_5}}{\mathsf{fma}\left(-B\_m, B\_m, C \cdot \left(A \cdot 4\right)\right)}\\
      
      \mathbf{else}:\\
      \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 5 regimes
      2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -inf.0

        1. Initial program 3.4%

          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. Add Preprocessing
        3. Step-by-step derivation
          1. lift-sqrt.f64N/A

            \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. lift-*.f64N/A

            \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          3. *-commutativeN/A

            \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          4. lift-*.f64N/A

            \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          5. associate-*r*N/A

            \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2\right) \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          6. sqrt-prodN/A

            \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot \sqrt{\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          7. pow1/2N/A

            \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot \color{blue}{{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          8. lower-*.f64N/A

            \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot {\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        4. Applied rewrites33.0%

          \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        5. Taylor expanded in A around -inf

          \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        6. Step-by-step derivation
          1. lower-+.f64N/A

            \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. lower-*.f64N/A

            \[\leadsto \frac{-\sqrt{\left(\left(C + \color{blue}{\frac{-1}{2} \cdot \frac{{B}^{2}}{A}}\right) + C\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          3. lower-/.f64N/A

            \[\leadsto \frac{-\sqrt{\left(\left(C + \frac{-1}{2} \cdot \color{blue}{\frac{{B}^{2}}{A}}\right) + C\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          4. unpow2N/A

            \[\leadsto \frac{-\sqrt{\left(\left(C + \frac{-1}{2} \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          5. lower-*.f6427.9

            \[\leadsto \frac{-\sqrt{\left(\left(C + -0.5 \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        7. Applied rewrites27.9%

          \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(C + -0.5 \cdot \frac{B \cdot B}{A}\right)} + C\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

        if -inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -1.00000000000000002e-194

        1. Initial program 99.6%

          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. Add Preprocessing
        3. Applied rewrites99.5%

          \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)}} \]

        if -1.00000000000000002e-194 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -0.0

        1. Initial program 3.5%

          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. Add Preprocessing
        3. Step-by-step derivation
          1. lift-sqrt.f64N/A

            \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. lift-*.f64N/A

            \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          3. *-commutativeN/A

            \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          4. lift-*.f64N/A

            \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          5. associate-*r*N/A

            \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2\right) \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          6. sqrt-prodN/A

            \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot \sqrt{\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          7. pow1/2N/A

            \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot \color{blue}{{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          8. lower-*.f64N/A

            \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot {\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        4. Applied rewrites3.7%

          \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        5. Applied rewrites17.8%

          \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \sqrt{F \cdot 2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        6. Taylor expanded in A around -inf

          \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \sqrt{F \cdot 2}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        7. Step-by-step derivation
          1. lower-+.f64N/A

            \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \sqrt{F \cdot 2}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. lower-*.f64N/A

            \[\leadsto \frac{-\sqrt{\left(\left(C + \color{blue}{\frac{-1}{2} \cdot \frac{{B}^{2}}{A}}\right) + C\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \sqrt{F \cdot 2}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          3. lower-/.f64N/A

            \[\leadsto \frac{-\sqrt{\left(\left(C + \frac{-1}{2} \cdot \color{blue}{\frac{{B}^{2}}{A}}\right) + C\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \sqrt{F \cdot 2}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          4. unpow2N/A

            \[\leadsto \frac{-\sqrt{\left(\left(C + \frac{-1}{2} \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \sqrt{F \cdot 2}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          5. lower-*.f6432.9

            \[\leadsto \frac{-\sqrt{\left(\left(C + -0.5 \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \sqrt{F \cdot 2}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        8. Applied rewrites32.9%

          \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(C + -0.5 \cdot \frac{B \cdot B}{A}\right)} + C\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \sqrt{F \cdot 2}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

        if -0.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

        1. Initial program 33.5%

          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. Add Preprocessing
        3. Step-by-step derivation
          1. lift-sqrt.f64N/A

            \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. lift-*.f64N/A

            \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          3. *-commutativeN/A

            \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          4. lift-*.f64N/A

            \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          5. associate-*r*N/A

            \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2\right) \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          6. sqrt-prodN/A

            \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot \sqrt{\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          7. pow1/2N/A

            \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot \color{blue}{{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          8. lower-*.f64N/A

            \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot {\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        4. Applied rewrites83.9%

          \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        5. Applied rewrites83.9%

          \[\leadsto \color{blue}{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C} \cdot \frac{\sqrt{\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}}{\mathsf{fma}\left(-B, B, C \cdot \left(A \cdot 4\right)\right)}} \]

        if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

        1. Initial program 0.0%

          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. Add Preprocessing
        3. Taylor expanded in B around inf

          \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
        4. Step-by-step derivation
          1. mul-1-negN/A

            \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
          2. *-commutativeN/A

            \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
          3. distribute-lft-neg-inN/A

            \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
          4. lower-*.f64N/A

            \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
          5. lower-neg.f64N/A

            \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
          6. lower-sqrt.f64N/A

            \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
          7. lower-sqrt.f64N/A

            \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
          8. lower-/.f6419.4

            \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
        5. Applied rewrites19.4%

          \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
        6. Step-by-step derivation
          1. Applied rewrites19.4%

            \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
          2. Step-by-step derivation
            1. Applied rewrites23.1%

              \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
          3. Recombined 5 regimes into one program.
          4. Final simplification43.2%

            \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -\infty:\\ \;\;\;\;\frac{\sqrt{\left(\left(C + -0.5 \cdot \frac{B \cdot B}{A}\right) + C\right) \cdot 2} \cdot \left(-\sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -1 \cdot 10^{-194}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq 0:\\ \;\;\;\;\frac{\sqrt{\left(\left(C + -0.5 \cdot \frac{B \cdot B}{A}\right) + C\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \left(-\sqrt{F \cdot 2}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq \infty:\\ \;\;\;\;\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C} \cdot \frac{\sqrt{\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}}{\mathsf{fma}\left(-B, B, C \cdot \left(A \cdot 4\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
          5. Add Preprocessing

          Alternative 3: 59.1% accurate, 0.2× speedup?

          \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\ t_1 := \left(C + -0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right) + C\\ t_2 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ t_3 := \left(4 \cdot A\right) \cdot C\\ t_4 := \mathsf{fma}\left(-B\_m, B\_m, t\_3\right)\\ t_5 := {B\_m}^{2} - t\_3\\ t_6 := \frac{\sqrt{\left(2 \cdot \left(t\_5 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_5}\\ \mathbf{if}\;t\_6 \leq -\infty:\\ \;\;\;\;\frac{\sqrt{t\_1 \cdot 2} \cdot \left(-\sqrt{F \cdot t\_2}\right)}{t\_5}\\ \mathbf{elif}\;t\_6 \leq -1 \cdot 10^{-194}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B\_m, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot t\_2\right)}}{t\_4}\\ \mathbf{elif}\;t\_6 \leq 10^{+177}:\\ \;\;\;\;\frac{\sqrt{t\_0 \cdot \left(\left(F \cdot t\_1\right) \cdot 2\right)}}{t\_4}\\ \mathbf{elif}\;t\_6 \leq \infty:\\ \;\;\;\;\sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C} \cdot \frac{\sqrt{\left(F \cdot 2\right) \cdot t\_0}}{\mathsf{fma}\left(-B\_m, B\_m, C \cdot \left(A \cdot 4\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
          B_m = (fabs.f64 B)
          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
          (FPCore (A B_m C F)
           :precision binary64
           (let* ((t_0 (fma (* -4.0 C) A (* B_m B_m)))
                  (t_1 (+ (+ C (* -0.5 (/ (* B_m B_m) A))) C))
                  (t_2 (fma -4.0 (* C A) (* B_m B_m)))
                  (t_3 (* (* 4.0 A) C))
                  (t_4 (fma (- B_m) B_m t_3))
                  (t_5 (- (pow B_m 2.0) t_3))
                  (t_6
                   (/
                    (sqrt
                     (*
                      (* 2.0 (* t_5 F))
                      (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))))
                    (- t_5))))
             (if (<= t_6 (- INFINITY))
               (/ (* (sqrt (* t_1 2.0)) (- (sqrt (* F t_2)))) t_5)
               (if (<= t_6 -1e-194)
                 (/ (sqrt (* (+ (+ (hypot B_m (- A C)) A) C) (* (* 2.0 F) t_2))) t_4)
                 (if (<= t_6 1e+177)
                   (/ (sqrt (* t_0 (* (* F t_1) 2.0))) t_4)
                   (if (<= t_6 INFINITY)
                     (*
                      (sqrt (+ (+ (hypot (- A C) B_m) A) C))
                      (/ (sqrt (* (* F 2.0) t_0)) (fma (- B_m) B_m (* C (* A 4.0)))))
                     (* (- (sqrt F)) (sqrt (/ 2.0 B_m)))))))))
          B_m = fabs(B);
          assert(A < B_m && B_m < C && C < F);
          double code(double A, double B_m, double C, double F) {
          	double t_0 = fma((-4.0 * C), A, (B_m * B_m));
          	double t_1 = (C + (-0.5 * ((B_m * B_m) / A))) + C;
          	double t_2 = fma(-4.0, (C * A), (B_m * B_m));
          	double t_3 = (4.0 * A) * C;
          	double t_4 = fma(-B_m, B_m, t_3);
          	double t_5 = pow(B_m, 2.0) - t_3;
          	double t_6 = sqrt(((2.0 * (t_5 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))))) / -t_5;
          	double tmp;
          	if (t_6 <= -((double) INFINITY)) {
          		tmp = (sqrt((t_1 * 2.0)) * -sqrt((F * t_2))) / t_5;
          	} else if (t_6 <= -1e-194) {
          		tmp = sqrt((((hypot(B_m, (A - C)) + A) + C) * ((2.0 * F) * t_2))) / t_4;
          	} else if (t_6 <= 1e+177) {
          		tmp = sqrt((t_0 * ((F * t_1) * 2.0))) / t_4;
          	} else if (t_6 <= ((double) INFINITY)) {
          		tmp = sqrt(((hypot((A - C), B_m) + A) + C)) * (sqrt(((F * 2.0) * t_0)) / fma(-B_m, B_m, (C * (A * 4.0))));
          	} else {
          		tmp = -sqrt(F) * sqrt((2.0 / B_m));
          	}
          	return tmp;
          }
          
          B_m = abs(B)
          A, B_m, C, F = sort([A, B_m, C, F])
          function code(A, B_m, C, F)
          	t_0 = fma(Float64(-4.0 * C), A, Float64(B_m * B_m))
          	t_1 = Float64(Float64(C + Float64(-0.5 * Float64(Float64(B_m * B_m) / A))) + C)
          	t_2 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
          	t_3 = Float64(Float64(4.0 * A) * C)
          	t_4 = fma(Float64(-B_m), B_m, t_3)
          	t_5 = Float64((B_m ^ 2.0) - t_3)
          	t_6 = Float64(sqrt(Float64(Float64(2.0 * Float64(t_5 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))))) / Float64(-t_5))
          	tmp = 0.0
          	if (t_6 <= Float64(-Inf))
          		tmp = Float64(Float64(sqrt(Float64(t_1 * 2.0)) * Float64(-sqrt(Float64(F * t_2)))) / t_5);
          	elseif (t_6 <= -1e-194)
          		tmp = Float64(sqrt(Float64(Float64(Float64(hypot(B_m, Float64(A - C)) + A) + C) * Float64(Float64(2.0 * F) * t_2))) / t_4);
          	elseif (t_6 <= 1e+177)
          		tmp = Float64(sqrt(Float64(t_0 * Float64(Float64(F * t_1) * 2.0))) / t_4);
          	elseif (t_6 <= Inf)
          		tmp = Float64(sqrt(Float64(Float64(hypot(Float64(A - C), B_m) + A) + C)) * Float64(sqrt(Float64(Float64(F * 2.0) * t_0)) / fma(Float64(-B_m), B_m, Float64(C * Float64(A * 4.0)))));
          	else
          		tmp = Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)));
          	end
          	return tmp
          end
          
          B_m = N[Abs[B], $MachinePrecision]
          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
          code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(-4.0 * C), $MachinePrecision] * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(C + N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + C), $MachinePrecision]}, Block[{t$95$2 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]}, Block[{t$95$4 = N[((-B$95$m) * B$95$m + t$95$3), $MachinePrecision]}, Block[{t$95$5 = N[(N[Power[B$95$m, 2.0], $MachinePrecision] - t$95$3), $MachinePrecision]}, Block[{t$95$6 = N[(N[Sqrt[N[(N[(2.0 * N[(t$95$5 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$5)), $MachinePrecision]}, If[LessEqual[t$95$6, (-Infinity)], N[(N[(N[Sqrt[N[(t$95$1 * 2.0), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[N[(F * t$95$2), $MachinePrecision]], $MachinePrecision])), $MachinePrecision] / t$95$5), $MachinePrecision], If[LessEqual[t$95$6, -1e-194], N[(N[Sqrt[N[(N[(N[(N[Sqrt[B$95$m ^ 2 + N[(A - C), $MachinePrecision] ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision] * N[(N[(2.0 * F), $MachinePrecision] * t$95$2), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / t$95$4), $MachinePrecision], If[LessEqual[t$95$6, 1e+177], N[(N[Sqrt[N[(t$95$0 * N[(N[(F * t$95$1), $MachinePrecision] * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / t$95$4), $MachinePrecision], If[LessEqual[t$95$6, Infinity], N[(N[Sqrt[N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[N[(N[(F * 2.0), $MachinePrecision] * t$95$0), $MachinePrecision]], $MachinePrecision] / N[((-B$95$m) * B$95$m + N[(C * N[(A * 4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]]]]]]]]]
          
          \begin{array}{l}
          B_m = \left|B\right|
          \\
          [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
          \\
          \begin{array}{l}
          t_0 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\
          t_1 := \left(C + -0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right) + C\\
          t_2 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
          t_3 := \left(4 \cdot A\right) \cdot C\\
          t_4 := \mathsf{fma}\left(-B\_m, B\_m, t\_3\right)\\
          t_5 := {B\_m}^{2} - t\_3\\
          t_6 := \frac{\sqrt{\left(2 \cdot \left(t\_5 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_5}\\
          \mathbf{if}\;t\_6 \leq -\infty:\\
          \;\;\;\;\frac{\sqrt{t\_1 \cdot 2} \cdot \left(-\sqrt{F \cdot t\_2}\right)}{t\_5}\\
          
          \mathbf{elif}\;t\_6 \leq -1 \cdot 10^{-194}:\\
          \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B\_m, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot t\_2\right)}}{t\_4}\\
          
          \mathbf{elif}\;t\_6 \leq 10^{+177}:\\
          \;\;\;\;\frac{\sqrt{t\_0 \cdot \left(\left(F \cdot t\_1\right) \cdot 2\right)}}{t\_4}\\
          
          \mathbf{elif}\;t\_6 \leq \infty:\\
          \;\;\;\;\sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C} \cdot \frac{\sqrt{\left(F \cdot 2\right) \cdot t\_0}}{\mathsf{fma}\left(-B\_m, B\_m, C \cdot \left(A \cdot 4\right)\right)}\\
          
          \mathbf{else}:\\
          \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 5 regimes
          2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -inf.0

            1. Initial program 3.4%

              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            2. Add Preprocessing
            3. Step-by-step derivation
              1. lift-sqrt.f64N/A

                \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              2. lift-*.f64N/A

                \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              3. *-commutativeN/A

                \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              4. lift-*.f64N/A

                \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              5. associate-*r*N/A

                \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2\right) \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              6. sqrt-prodN/A

                \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot \sqrt{\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              7. pow1/2N/A

                \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot \color{blue}{{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              8. lower-*.f64N/A

                \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot {\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            4. Applied rewrites33.0%

              \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            5. Taylor expanded in A around -inf

              \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            6. Step-by-step derivation
              1. lower-+.f64N/A

                \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              2. lower-*.f64N/A

                \[\leadsto \frac{-\sqrt{\left(\left(C + \color{blue}{\frac{-1}{2} \cdot \frac{{B}^{2}}{A}}\right) + C\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              3. lower-/.f64N/A

                \[\leadsto \frac{-\sqrt{\left(\left(C + \frac{-1}{2} \cdot \color{blue}{\frac{{B}^{2}}{A}}\right) + C\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              4. unpow2N/A

                \[\leadsto \frac{-\sqrt{\left(\left(C + \frac{-1}{2} \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              5. lower-*.f6427.9

                \[\leadsto \frac{-\sqrt{\left(\left(C + -0.5 \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            7. Applied rewrites27.9%

              \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(C + -0.5 \cdot \frac{B \cdot B}{A}\right)} + C\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

            if -inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -1.00000000000000002e-194

            1. Initial program 99.6%

              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            2. Add Preprocessing
            3. Applied rewrites99.5%

              \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)}} \]

            if -1.00000000000000002e-194 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < 1e177

            1. Initial program 19.5%

              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            2. Add Preprocessing
            3. Applied rewrites22.2%

              \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)}} \]
            4. Applied rewrites22.2%

              \[\leadsto \frac{\sqrt{\color{blue}{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)\right) \cdot 2\right)}}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
            5. Taylor expanded in A around -inf

              \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
            6. Step-by-step derivation
              1. lower-+.f64N/A

                \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
              2. lower-*.f64N/A

                \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(C + \color{blue}{\frac{-1}{2} \cdot \frac{{B}^{2}}{A}}\right) + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
              3. lower-/.f64N/A

                \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(C + \frac{-1}{2} \cdot \color{blue}{\frac{{B}^{2}}{A}}\right) + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
              4. unpow2N/A

                \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(C + \frac{-1}{2} \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
              5. lower-*.f6429.0

                \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(C + -0.5 \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
            7. Applied rewrites29.0%

              \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\color{blue}{\left(C + -0.5 \cdot \frac{B \cdot B}{A}\right)} + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]

            if 1e177 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

            1. Initial program 3.6%

              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            2. Add Preprocessing
            3. Step-by-step derivation
              1. lift-sqrt.f64N/A

                \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              2. lift-*.f64N/A

                \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              3. *-commutativeN/A

                \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              4. lift-*.f64N/A

                \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              5. associate-*r*N/A

                \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2\right) \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              6. sqrt-prodN/A

                \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot \sqrt{\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              7. pow1/2N/A

                \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot \color{blue}{{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              8. lower-*.f64N/A

                \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot {\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            4. Applied rewrites82.2%

              \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            5. Applied rewrites82.5%

              \[\leadsto \color{blue}{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C} \cdot \frac{\sqrt{\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}}{\mathsf{fma}\left(-B, B, C \cdot \left(A \cdot 4\right)\right)}} \]

            if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

            1. Initial program 0.0%

              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            2. Add Preprocessing
            3. Taylor expanded in B around inf

              \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
            4. Step-by-step derivation
              1. mul-1-negN/A

                \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
              2. *-commutativeN/A

                \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
              3. distribute-lft-neg-inN/A

                \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
              4. lower-*.f64N/A

                \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
              5. lower-neg.f64N/A

                \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
              6. lower-sqrt.f64N/A

                \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
              7. lower-sqrt.f64N/A

                \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
              8. lower-/.f6419.4

                \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
            5. Applied rewrites19.4%

              \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
            6. Step-by-step derivation
              1. Applied rewrites19.4%

                \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
              2. Step-by-step derivation
                1. Applied rewrites23.1%

                  \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
              3. Recombined 5 regimes into one program.
              4. Final simplification40.8%

                \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -\infty:\\ \;\;\;\;\frac{\sqrt{\left(\left(C + -0.5 \cdot \frac{B \cdot B}{A}\right) + C\right) \cdot 2} \cdot \left(-\sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -1 \cdot 10^{-194}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq 10^{+177}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(C + -0.5 \cdot \frac{B \cdot B}{A}\right) + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq \infty:\\ \;\;\;\;\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C} \cdot \frac{\sqrt{\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}}{\mathsf{fma}\left(-B, B, C \cdot \left(A \cdot 4\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
              5. Add Preprocessing

              Alternative 4: 59.2% accurate, 0.2× speedup?

              \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \left(4 \cdot A\right) \cdot C\\ t_1 := \mathsf{fma}\left(-B\_m, B\_m, t\_0\right)\\ t_2 := {B\_m}^{2} - t\_0\\ t_3 := \frac{\sqrt{\left(2 \cdot \left(t\_2 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_2}\\ t_4 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ t_5 := \frac{\sqrt{\left(2 \cdot C\right) \cdot 2} \cdot \left(-\sqrt{F \cdot t\_4}\right)}{t\_2}\\ \mathbf{if}\;t\_3 \leq -\infty:\\ \;\;\;\;t\_5\\ \mathbf{elif}\;t\_3 \leq -1 \cdot 10^{-194}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B\_m, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot t\_4\right)}}{t\_1}\\ \mathbf{elif}\;t\_3 \leq 5 \cdot 10^{-16}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right) \cdot \left(\left(F \cdot \left(\left(C + -0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right) + C\right)\right) \cdot 2\right)}}{t\_1}\\ \mathbf{elif}\;t\_3 \leq \infty:\\ \;\;\;\;t\_5\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
              B_m = (fabs.f64 B)
              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
              (FPCore (A B_m C F)
               :precision binary64
               (let* ((t_0 (* (* 4.0 A) C))
                      (t_1 (fma (- B_m) B_m t_0))
                      (t_2 (- (pow B_m 2.0) t_0))
                      (t_3
                       (/
                        (sqrt
                         (*
                          (* 2.0 (* t_2 F))
                          (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))))
                        (- t_2)))
                      (t_4 (fma -4.0 (* C A) (* B_m B_m)))
                      (t_5 (/ (* (sqrt (* (* 2.0 C) 2.0)) (- (sqrt (* F t_4)))) t_2)))
                 (if (<= t_3 (- INFINITY))
                   t_5
                   (if (<= t_3 -1e-194)
                     (/ (sqrt (* (+ (+ (hypot B_m (- A C)) A) C) (* (* 2.0 F) t_4))) t_1)
                     (if (<= t_3 5e-16)
                       (/
                        (sqrt
                         (*
                          (fma (* -4.0 C) A (* B_m B_m))
                          (* (* F (+ (+ C (* -0.5 (/ (* B_m B_m) A))) C)) 2.0)))
                        t_1)
                       (if (<= t_3 INFINITY) t_5 (* (- (sqrt F)) (sqrt (/ 2.0 B_m)))))))))
              B_m = fabs(B);
              assert(A < B_m && B_m < C && C < F);
              double code(double A, double B_m, double C, double F) {
              	double t_0 = (4.0 * A) * C;
              	double t_1 = fma(-B_m, B_m, t_0);
              	double t_2 = pow(B_m, 2.0) - t_0;
              	double t_3 = sqrt(((2.0 * (t_2 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))))) / -t_2;
              	double t_4 = fma(-4.0, (C * A), (B_m * B_m));
              	double t_5 = (sqrt(((2.0 * C) * 2.0)) * -sqrt((F * t_4))) / t_2;
              	double tmp;
              	if (t_3 <= -((double) INFINITY)) {
              		tmp = t_5;
              	} else if (t_3 <= -1e-194) {
              		tmp = sqrt((((hypot(B_m, (A - C)) + A) + C) * ((2.0 * F) * t_4))) / t_1;
              	} else if (t_3 <= 5e-16) {
              		tmp = sqrt((fma((-4.0 * C), A, (B_m * B_m)) * ((F * ((C + (-0.5 * ((B_m * B_m) / A))) + C)) * 2.0))) / t_1;
              	} else if (t_3 <= ((double) INFINITY)) {
              		tmp = t_5;
              	} else {
              		tmp = -sqrt(F) * sqrt((2.0 / B_m));
              	}
              	return tmp;
              }
              
              B_m = abs(B)
              A, B_m, C, F = sort([A, B_m, C, F])
              function code(A, B_m, C, F)
              	t_0 = Float64(Float64(4.0 * A) * C)
              	t_1 = fma(Float64(-B_m), B_m, t_0)
              	t_2 = Float64((B_m ^ 2.0) - t_0)
              	t_3 = Float64(sqrt(Float64(Float64(2.0 * Float64(t_2 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))))) / Float64(-t_2))
              	t_4 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
              	t_5 = Float64(Float64(sqrt(Float64(Float64(2.0 * C) * 2.0)) * Float64(-sqrt(Float64(F * t_4)))) / t_2)
              	tmp = 0.0
              	if (t_3 <= Float64(-Inf))
              		tmp = t_5;
              	elseif (t_3 <= -1e-194)
              		tmp = Float64(sqrt(Float64(Float64(Float64(hypot(B_m, Float64(A - C)) + A) + C) * Float64(Float64(2.0 * F) * t_4))) / t_1);
              	elseif (t_3 <= 5e-16)
              		tmp = Float64(sqrt(Float64(fma(Float64(-4.0 * C), A, Float64(B_m * B_m)) * Float64(Float64(F * Float64(Float64(C + Float64(-0.5 * Float64(Float64(B_m * B_m) / A))) + C)) * 2.0))) / t_1);
              	elseif (t_3 <= Inf)
              		tmp = t_5;
              	else
              		tmp = Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)));
              	end
              	return tmp
              end
              
              B_m = N[Abs[B], $MachinePrecision]
              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
              code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]}, Block[{t$95$1 = N[((-B$95$m) * B$95$m + t$95$0), $MachinePrecision]}, Block[{t$95$2 = N[(N[Power[B$95$m, 2.0], $MachinePrecision] - t$95$0), $MachinePrecision]}, Block[{t$95$3 = N[(N[Sqrt[N[(N[(2.0 * N[(t$95$2 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$2)), $MachinePrecision]}, Block[{t$95$4 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$5 = N[(N[(N[Sqrt[N[(N[(2.0 * C), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[N[(F * t$95$4), $MachinePrecision]], $MachinePrecision])), $MachinePrecision] / t$95$2), $MachinePrecision]}, If[LessEqual[t$95$3, (-Infinity)], t$95$5, If[LessEqual[t$95$3, -1e-194], N[(N[Sqrt[N[(N[(N[(N[Sqrt[B$95$m ^ 2 + N[(A - C), $MachinePrecision] ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision] * N[(N[(2.0 * F), $MachinePrecision] * t$95$4), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / t$95$1), $MachinePrecision], If[LessEqual[t$95$3, 5e-16], N[(N[Sqrt[N[(N[(N[(-4.0 * C), $MachinePrecision] * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision] * N[(N[(F * N[(N[(C + N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + C), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / t$95$1), $MachinePrecision], If[LessEqual[t$95$3, Infinity], t$95$5, N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]]]]]]]]
              
              \begin{array}{l}
              B_m = \left|B\right|
              \\
              [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
              \\
              \begin{array}{l}
              t_0 := \left(4 \cdot A\right) \cdot C\\
              t_1 := \mathsf{fma}\left(-B\_m, B\_m, t\_0\right)\\
              t_2 := {B\_m}^{2} - t\_0\\
              t_3 := \frac{\sqrt{\left(2 \cdot \left(t\_2 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_2}\\
              t_4 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
              t_5 := \frac{\sqrt{\left(2 \cdot C\right) \cdot 2} \cdot \left(-\sqrt{F \cdot t\_4}\right)}{t\_2}\\
              \mathbf{if}\;t\_3 \leq -\infty:\\
              \;\;\;\;t\_5\\
              
              \mathbf{elif}\;t\_3 \leq -1 \cdot 10^{-194}:\\
              \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B\_m, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot t\_4\right)}}{t\_1}\\
              
              \mathbf{elif}\;t\_3 \leq 5 \cdot 10^{-16}:\\
              \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right) \cdot \left(\left(F \cdot \left(\left(C + -0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right) + C\right)\right) \cdot 2\right)}}{t\_1}\\
              
              \mathbf{elif}\;t\_3 \leq \infty:\\
              \;\;\;\;t\_5\\
              
              \mathbf{else}:\\
              \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\
              
              
              \end{array}
              \end{array}
              
              Derivation
              1. Split input into 4 regimes
              2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -inf.0 or 5.0000000000000004e-16 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

                1. Initial program 9.7%

                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                2. Add Preprocessing
                3. Step-by-step derivation
                  1. lift-sqrt.f64N/A

                    \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  2. lift-*.f64N/A

                    \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  3. *-commutativeN/A

                    \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  4. lift-*.f64N/A

                    \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  5. associate-*r*N/A

                    \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2\right) \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  6. sqrt-prodN/A

                    \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot \sqrt{\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  7. pow1/2N/A

                    \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot \color{blue}{{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  8. lower-*.f64N/A

                    \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot {\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                4. Applied rewrites48.2%

                  \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                5. Taylor expanded in A around -inf

                  \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                6. Step-by-step derivation
                  1. lower-*.f6427.7

                    \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                7. Applied rewrites27.7%

                  \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

                if -inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -1.00000000000000002e-194

                1. Initial program 99.6%

                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                2. Add Preprocessing
                3. Applied rewrites99.5%

                  \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)}} \]

                if -1.00000000000000002e-194 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < 5.0000000000000004e-16

                1. Initial program 9.9%

                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                2. Add Preprocessing
                3. Applied rewrites13.0%

                  \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)}} \]
                4. Applied rewrites13.0%

                  \[\leadsto \frac{\sqrt{\color{blue}{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)\right) \cdot 2\right)}}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                5. Taylor expanded in A around -inf

                  \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                6. Step-by-step derivation
                  1. lower-+.f64N/A

                    \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                  2. lower-*.f64N/A

                    \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(C + \color{blue}{\frac{-1}{2} \cdot \frac{{B}^{2}}{A}}\right) + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                  3. lower-/.f64N/A

                    \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(C + \frac{-1}{2} \cdot \color{blue}{\frac{{B}^{2}}{A}}\right) + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                  4. unpow2N/A

                    \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(C + \frac{-1}{2} \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                  5. lower-*.f6429.5

                    \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(C + -0.5 \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                7. Applied rewrites29.5%

                  \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\color{blue}{\left(C + -0.5 \cdot \frac{B \cdot B}{A}\right)} + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]

                if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

                1. Initial program 0.0%

                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                2. Add Preprocessing
                3. Taylor expanded in B around inf

                  \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                4. Step-by-step derivation
                  1. mul-1-negN/A

                    \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                  2. *-commutativeN/A

                    \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                  3. distribute-lft-neg-inN/A

                    \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                  4. lower-*.f64N/A

                    \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                  5. lower-neg.f64N/A

                    \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
                  6. lower-sqrt.f64N/A

                    \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
                  7. lower-sqrt.f64N/A

                    \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
                  8. lower-/.f6419.4

                    \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                5. Applied rewrites19.4%

                  \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
                6. Step-by-step derivation
                  1. Applied rewrites19.4%

                    \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                  2. Step-by-step derivation
                    1. Applied rewrites23.1%

                      \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                  3. Recombined 4 regimes into one program.
                  4. Final simplification37.2%

                    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -\infty:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot 2} \cdot \left(-\sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -1 \cdot 10^{-194}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq 5 \cdot 10^{-16}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(C + -0.5 \cdot \frac{B \cdot B}{A}\right) + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq \infty:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot 2} \cdot \left(-\sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
                  5. Add Preprocessing

                  Alternative 5: 58.7% accurate, 0.3× speedup?

                  \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\ t_1 := -t\_0\\ t_2 := \frac{\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{t\_1}\\ t_3 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;t\_2 \leq -1 \cdot 10^{-194}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right) \cdot 2} \cdot \sqrt{F \cdot \left(\left(\mathsf{hypot}\left(B\_m, A - C\right) + A\right) + C\right)}}{t\_1}\\ \mathbf{elif}\;t\_2 \leq 0:\\ \;\;\;\;\frac{\sqrt{\left(\left(C + -0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right) + C\right) \cdot t\_3} \cdot \left(-\sqrt{F \cdot 2}\right)}{t\_0}\\ \mathbf{elif}\;t\_2 \leq \infty:\\ \;\;\;\;\sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C} \cdot \frac{\sqrt{\left(F \cdot 2\right) \cdot t\_3}}{\mathsf{fma}\left(-B\_m, B\_m, C \cdot \left(A \cdot 4\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
                  B_m = (fabs.f64 B)
                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                  (FPCore (A B_m C F)
                   :precision binary64
                   (let* ((t_0 (- (pow B_m 2.0) (* (* 4.0 A) C)))
                          (t_1 (- t_0))
                          (t_2
                           (/
                            (sqrt
                             (*
                              (* 2.0 (* t_0 F))
                              (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))))
                            t_1))
                          (t_3 (fma (* -4.0 C) A (* B_m B_m))))
                     (if (<= t_2 -1e-194)
                       (/
                        (*
                         (sqrt (* (fma -4.0 (* C A) (* B_m B_m)) 2.0))
                         (sqrt (* F (+ (+ (hypot B_m (- A C)) A) C))))
                        t_1)
                       (if (<= t_2 0.0)
                         (/
                          (*
                           (sqrt (* (+ (+ C (* -0.5 (/ (* B_m B_m) A))) C) t_3))
                           (- (sqrt (* F 2.0))))
                          t_0)
                         (if (<= t_2 INFINITY)
                           (*
                            (sqrt (+ (+ (hypot (- A C) B_m) A) C))
                            (/ (sqrt (* (* F 2.0) t_3)) (fma (- B_m) B_m (* C (* A 4.0)))))
                           (* (- (sqrt F)) (sqrt (/ 2.0 B_m))))))))
                  B_m = fabs(B);
                  assert(A < B_m && B_m < C && C < F);
                  double code(double A, double B_m, double C, double F) {
                  	double t_0 = pow(B_m, 2.0) - ((4.0 * A) * C);
                  	double t_1 = -t_0;
                  	double t_2 = sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))))) / t_1;
                  	double t_3 = fma((-4.0 * C), A, (B_m * B_m));
                  	double tmp;
                  	if (t_2 <= -1e-194) {
                  		tmp = (sqrt((fma(-4.0, (C * A), (B_m * B_m)) * 2.0)) * sqrt((F * ((hypot(B_m, (A - C)) + A) + C)))) / t_1;
                  	} else if (t_2 <= 0.0) {
                  		tmp = (sqrt((((C + (-0.5 * ((B_m * B_m) / A))) + C) * t_3)) * -sqrt((F * 2.0))) / t_0;
                  	} else if (t_2 <= ((double) INFINITY)) {
                  		tmp = sqrt(((hypot((A - C), B_m) + A) + C)) * (sqrt(((F * 2.0) * t_3)) / fma(-B_m, B_m, (C * (A * 4.0))));
                  	} else {
                  		tmp = -sqrt(F) * sqrt((2.0 / B_m));
                  	}
                  	return tmp;
                  }
                  
                  B_m = abs(B)
                  A, B_m, C, F = sort([A, B_m, C, F])
                  function code(A, B_m, C, F)
                  	t_0 = Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C))
                  	t_1 = Float64(-t_0)
                  	t_2 = Float64(sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))))) / t_1)
                  	t_3 = fma(Float64(-4.0 * C), A, Float64(B_m * B_m))
                  	tmp = 0.0
                  	if (t_2 <= -1e-194)
                  		tmp = Float64(Float64(sqrt(Float64(fma(-4.0, Float64(C * A), Float64(B_m * B_m)) * 2.0)) * sqrt(Float64(F * Float64(Float64(hypot(B_m, Float64(A - C)) + A) + C)))) / t_1);
                  	elseif (t_2 <= 0.0)
                  		tmp = Float64(Float64(sqrt(Float64(Float64(Float64(C + Float64(-0.5 * Float64(Float64(B_m * B_m) / A))) + C) * t_3)) * Float64(-sqrt(Float64(F * 2.0)))) / t_0);
                  	elseif (t_2 <= Inf)
                  		tmp = Float64(sqrt(Float64(Float64(hypot(Float64(A - C), B_m) + A) + C)) * Float64(sqrt(Float64(Float64(F * 2.0) * t_3)) / fma(Float64(-B_m), B_m, Float64(C * Float64(A * 4.0)))));
                  	else
                  		tmp = Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)));
                  	end
                  	return tmp
                  end
                  
                  B_m = N[Abs[B], $MachinePrecision]
                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                  code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = (-t$95$0)}, Block[{t$95$2 = N[(N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / t$95$1), $MachinePrecision]}, Block[{t$95$3 = N[(N[(-4.0 * C), $MachinePrecision] * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$2, -1e-194], N[(N[(N[Sqrt[N[(N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] * N[Sqrt[N[(F * N[(N[(N[Sqrt[B$95$m ^ 2 + N[(A - C), $MachinePrecision] ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / t$95$1), $MachinePrecision], If[LessEqual[t$95$2, 0.0], N[(N[(N[Sqrt[N[(N[(N[(C + N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + C), $MachinePrecision] * t$95$3), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision])), $MachinePrecision] / t$95$0), $MachinePrecision], If[LessEqual[t$95$2, Infinity], N[(N[Sqrt[N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[N[(N[(F * 2.0), $MachinePrecision] * t$95$3), $MachinePrecision]], $MachinePrecision] / N[((-B$95$m) * B$95$m + N[(C * N[(A * 4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]]]]]
                  
                  \begin{array}{l}
                  B_m = \left|B\right|
                  \\
                  [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                  \\
                  \begin{array}{l}
                  t_0 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\
                  t_1 := -t\_0\\
                  t_2 := \frac{\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{t\_1}\\
                  t_3 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\
                  \mathbf{if}\;t\_2 \leq -1 \cdot 10^{-194}:\\
                  \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right) \cdot 2} \cdot \sqrt{F \cdot \left(\left(\mathsf{hypot}\left(B\_m, A - C\right) + A\right) + C\right)}}{t\_1}\\
                  
                  \mathbf{elif}\;t\_2 \leq 0:\\
                  \;\;\;\;\frac{\sqrt{\left(\left(C + -0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right) + C\right) \cdot t\_3} \cdot \left(-\sqrt{F \cdot 2}\right)}{t\_0}\\
                  
                  \mathbf{elif}\;t\_2 \leq \infty:\\
                  \;\;\;\;\sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C} \cdot \frac{\sqrt{\left(F \cdot 2\right) \cdot t\_3}}{\mathsf{fma}\left(-B\_m, B\_m, C \cdot \left(A \cdot 4\right)\right)}\\
                  
                  \mathbf{else}:\\
                  \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\
                  
                  
                  \end{array}
                  \end{array}
                  
                  Derivation
                  1. Split input into 4 regimes
                  2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -1.00000000000000002e-194

                    1. Initial program 43.3%

                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    2. Add Preprocessing
                    3. Step-by-step derivation
                      1. lift-sqrt.f64N/A

                        \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      2. lift-*.f64N/A

                        \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      3. lift-*.f64N/A

                        \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)} \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      4. lift-*.f64N/A

                        \[\leadsto \frac{-\sqrt{\left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      5. associate-*r*N/A

                        \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)} \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      6. associate-*l*N/A

                        \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot \left(F \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      7. sqrt-prodN/A

                        \[\leadsto \frac{-\color{blue}{\sqrt{2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \cdot \sqrt{F \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      8. pow1/2N/A

                        \[\leadsto \frac{-\color{blue}{{\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)}^{\frac{1}{2}}} \cdot \sqrt{F \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      9. lower-*.f64N/A

                        \[\leadsto \frac{-\color{blue}{{\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)}^{\frac{1}{2}} \cdot \sqrt{F \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    4. Applied rewrites61.9%

                      \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2} \cdot \sqrt{F \cdot \left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

                    if -1.00000000000000002e-194 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -0.0

                    1. Initial program 3.5%

                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    2. Add Preprocessing
                    3. Step-by-step derivation
                      1. lift-sqrt.f64N/A

                        \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      2. lift-*.f64N/A

                        \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      3. *-commutativeN/A

                        \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      4. lift-*.f64N/A

                        \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      5. associate-*r*N/A

                        \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2\right) \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      6. sqrt-prodN/A

                        \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot \sqrt{\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      7. pow1/2N/A

                        \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot \color{blue}{{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      8. lower-*.f64N/A

                        \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot {\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    4. Applied rewrites3.7%

                      \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    5. Applied rewrites17.8%

                      \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \sqrt{F \cdot 2}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    6. Taylor expanded in A around -inf

                      \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \sqrt{F \cdot 2}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    7. Step-by-step derivation
                      1. lower-+.f64N/A

                        \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \sqrt{F \cdot 2}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      2. lower-*.f64N/A

                        \[\leadsto \frac{-\sqrt{\left(\left(C + \color{blue}{\frac{-1}{2} \cdot \frac{{B}^{2}}{A}}\right) + C\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \sqrt{F \cdot 2}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      3. lower-/.f64N/A

                        \[\leadsto \frac{-\sqrt{\left(\left(C + \frac{-1}{2} \cdot \color{blue}{\frac{{B}^{2}}{A}}\right) + C\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \sqrt{F \cdot 2}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      4. unpow2N/A

                        \[\leadsto \frac{-\sqrt{\left(\left(C + \frac{-1}{2} \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \sqrt{F \cdot 2}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      5. lower-*.f6432.9

                        \[\leadsto \frac{-\sqrt{\left(\left(C + -0.5 \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \sqrt{F \cdot 2}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    8. Applied rewrites32.9%

                      \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(C + -0.5 \cdot \frac{B \cdot B}{A}\right)} + C\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \sqrt{F \cdot 2}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

                    if -0.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

                    1. Initial program 33.5%

                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    2. Add Preprocessing
                    3. Step-by-step derivation
                      1. lift-sqrt.f64N/A

                        \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      2. lift-*.f64N/A

                        \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      3. *-commutativeN/A

                        \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      4. lift-*.f64N/A

                        \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      5. associate-*r*N/A

                        \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2\right) \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      6. sqrt-prodN/A

                        \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot \sqrt{\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      7. pow1/2N/A

                        \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot \color{blue}{{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      8. lower-*.f64N/A

                        \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot {\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    4. Applied rewrites83.9%

                      \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    5. Applied rewrites83.9%

                      \[\leadsto \color{blue}{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C} \cdot \frac{\sqrt{\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}}{\mathsf{fma}\left(-B, B, C \cdot \left(A \cdot 4\right)\right)}} \]

                    if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

                    1. Initial program 0.0%

                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    2. Add Preprocessing
                    3. Taylor expanded in B around inf

                      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                    4. Step-by-step derivation
                      1. mul-1-negN/A

                        \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                      2. *-commutativeN/A

                        \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                      3. distribute-lft-neg-inN/A

                        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                      4. lower-*.f64N/A

                        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                      5. lower-neg.f64N/A

                        \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
                      6. lower-sqrt.f64N/A

                        \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
                      7. lower-sqrt.f64N/A

                        \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
                      8. lower-/.f6419.4

                        \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                    5. Applied rewrites19.4%

                      \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
                    6. Step-by-step derivation
                      1. Applied rewrites19.4%

                        \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                      2. Step-by-step derivation
                        1. Applied rewrites23.1%

                          \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                      3. Recombined 4 regimes into one program.
                      4. Final simplification44.8%

                        \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -1 \cdot 10^{-194}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2} \cdot \sqrt{F \cdot \left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq 0:\\ \;\;\;\;\frac{\sqrt{\left(\left(C + -0.5 \cdot \frac{B \cdot B}{A}\right) + C\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \left(-\sqrt{F \cdot 2}\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq \infty:\\ \;\;\;\;\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C} \cdot \frac{\sqrt{\left(F \cdot 2\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}}{\mathsf{fma}\left(-B, B, C \cdot \left(A \cdot 4\right)\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
                      5. Add Preprocessing

                      Alternative 6: 53.6% accurate, 1.2× speedup?

                      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 2 \cdot 10^{-95}:\\ \;\;\;\;\frac{\sqrt{t\_0 \cdot \left(\left(F \cdot \left(\left(C + -0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right) + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B\_m, B\_m, \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{elif}\;{B\_m}^{2} \leq 4 \cdot 10^{+71}:\\ \;\;\;\;\left(-\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C\right) \cdot 2}\right) \cdot \frac{\sqrt{F \cdot t\_0}}{t\_0}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
                      B_m = (fabs.f64 B)
                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                      (FPCore (A B_m C F)
                       :precision binary64
                       (let* ((t_0 (fma (* -4.0 C) A (* B_m B_m))))
                         (if (<= (pow B_m 2.0) 2e-95)
                           (/
                            (sqrt (* t_0 (* (* F (+ (+ C (* -0.5 (/ (* B_m B_m) A))) C)) 2.0)))
                            (fma (- B_m) B_m (* (* 4.0 A) C)))
                           (if (<= (pow B_m 2.0) 4e+71)
                             (*
                              (- (sqrt (* (+ (+ (hypot (- A C) B_m) A) C) 2.0)))
                              (/ (sqrt (* F t_0)) t_0))
                             (* (- (sqrt F)) (sqrt (/ 2.0 B_m)))))))
                      B_m = fabs(B);
                      assert(A < B_m && B_m < C && C < F);
                      double code(double A, double B_m, double C, double F) {
                      	double t_0 = fma((-4.0 * C), A, (B_m * B_m));
                      	double tmp;
                      	if (pow(B_m, 2.0) <= 2e-95) {
                      		tmp = sqrt((t_0 * ((F * ((C + (-0.5 * ((B_m * B_m) / A))) + C)) * 2.0))) / fma(-B_m, B_m, ((4.0 * A) * C));
                      	} else if (pow(B_m, 2.0) <= 4e+71) {
                      		tmp = -sqrt((((hypot((A - C), B_m) + A) + C) * 2.0)) * (sqrt((F * t_0)) / t_0);
                      	} else {
                      		tmp = -sqrt(F) * sqrt((2.0 / B_m));
                      	}
                      	return tmp;
                      }
                      
                      B_m = abs(B)
                      A, B_m, C, F = sort([A, B_m, C, F])
                      function code(A, B_m, C, F)
                      	t_0 = fma(Float64(-4.0 * C), A, Float64(B_m * B_m))
                      	tmp = 0.0
                      	if ((B_m ^ 2.0) <= 2e-95)
                      		tmp = Float64(sqrt(Float64(t_0 * Float64(Float64(F * Float64(Float64(C + Float64(-0.5 * Float64(Float64(B_m * B_m) / A))) + C)) * 2.0))) / fma(Float64(-B_m), B_m, Float64(Float64(4.0 * A) * C)));
                      	elseif ((B_m ^ 2.0) <= 4e+71)
                      		tmp = Float64(Float64(-sqrt(Float64(Float64(Float64(hypot(Float64(A - C), B_m) + A) + C) * 2.0))) * Float64(sqrt(Float64(F * t_0)) / t_0));
                      	else
                      		tmp = Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)));
                      	end
                      	return tmp
                      end
                      
                      B_m = N[Abs[B], $MachinePrecision]
                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                      code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(-4.0 * C), $MachinePrecision] * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 2e-95], N[(N[Sqrt[N[(t$95$0 * N[(N[(F * N[(N[(C + N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + C), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[((-B$95$m) * B$95$m + N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 4e+71], N[((-N[Sqrt[N[(N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision]) * N[(N[Sqrt[N[(F * t$95$0), $MachinePrecision]], $MachinePrecision] / t$95$0), $MachinePrecision]), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]
                      
                      \begin{array}{l}
                      B_m = \left|B\right|
                      \\
                      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                      \\
                      \begin{array}{l}
                      t_0 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\
                      \mathbf{if}\;{B\_m}^{2} \leq 2 \cdot 10^{-95}:\\
                      \;\;\;\;\frac{\sqrt{t\_0 \cdot \left(\left(F \cdot \left(\left(C + -0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right) + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B\_m, B\_m, \left(4 \cdot A\right) \cdot C\right)}\\
                      
                      \mathbf{elif}\;{B\_m}^{2} \leq 4 \cdot 10^{+71}:\\
                      \;\;\;\;\left(-\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C\right) \cdot 2}\right) \cdot \frac{\sqrt{F \cdot t\_0}}{t\_0}\\
                      
                      \mathbf{else}:\\
                      \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\
                      
                      
                      \end{array}
                      \end{array}
                      
                      Derivation
                      1. Split input into 3 regimes
                      2. if (pow.f64 B #s(literal 2 binary64)) < 1.99999999999999998e-95

                        1. Initial program 18.2%

                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        2. Add Preprocessing
                        3. Applied rewrites26.7%

                          \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)}} \]
                        4. Applied rewrites26.1%

                          \[\leadsto \frac{\sqrt{\color{blue}{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)\right) \cdot 2\right)}}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                        5. Taylor expanded in A around -inf

                          \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                        6. Step-by-step derivation
                          1. lower-+.f64N/A

                            \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                          2. lower-*.f64N/A

                            \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(C + \color{blue}{\frac{-1}{2} \cdot \frac{{B}^{2}}{A}}\right) + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                          3. lower-/.f64N/A

                            \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(C + \frac{-1}{2} \cdot \color{blue}{\frac{{B}^{2}}{A}}\right) + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                          4. unpow2N/A

                            \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(C + \frac{-1}{2} \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                          5. lower-*.f6424.7

                            \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(C + -0.5 \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                        7. Applied rewrites24.7%

                          \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\color{blue}{\left(C + -0.5 \cdot \frac{B \cdot B}{A}\right)} + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]

                        if 1.99999999999999998e-95 < (pow.f64 B #s(literal 2 binary64)) < 4.0000000000000002e71

                        1. Initial program 46.0%

                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        2. Add Preprocessing
                        3. Step-by-step derivation
                          1. lift-sqrt.f64N/A

                            \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          2. lift-*.f64N/A

                            \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          3. *-commutativeN/A

                            \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          4. lift-*.f64N/A

                            \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          5. associate-*r*N/A

                            \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2\right) \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          6. sqrt-prodN/A

                            \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot \sqrt{\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          7. pow1/2N/A

                            \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot \color{blue}{{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          8. lower-*.f64N/A

                            \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot {\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        4. Applied rewrites59.7%

                          \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        5. Applied rewrites59.7%

                          \[\leadsto \color{blue}{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot 2} \cdot \frac{-\sqrt{F \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}}{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}} \]

                        if 4.0000000000000002e71 < (pow.f64 B #s(literal 2 binary64))

                        1. Initial program 14.2%

                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        2. Add Preprocessing
                        3. Taylor expanded in B around inf

                          \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                        4. Step-by-step derivation
                          1. mul-1-negN/A

                            \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                          2. *-commutativeN/A

                            \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                          3. distribute-lft-neg-inN/A

                            \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                          4. lower-*.f64N/A

                            \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                          5. lower-neg.f64N/A

                            \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
                          6. lower-sqrt.f64N/A

                            \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
                          7. lower-sqrt.f64N/A

                            \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
                          8. lower-/.f6431.8

                            \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                        5. Applied rewrites31.8%

                          \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
                        6. Step-by-step derivation
                          1. Applied rewrites31.9%

                            \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                          2. Step-by-step derivation
                            1. Applied rewrites36.0%

                              \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                          3. Recombined 3 regimes into one program.
                          4. Final simplification33.3%

                            \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 2 \cdot 10^{-95}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(C + -0.5 \cdot \frac{B \cdot B}{A}\right) + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{elif}\;{B}^{2} \leq 4 \cdot 10^{+71}:\\ \;\;\;\;\left(-\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot 2}\right) \cdot \frac{\sqrt{F \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}}{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
                          5. Add Preprocessing

                          Alternative 7: 53.6% accurate, 1.2× speedup?

                          \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 2 \cdot 10^{-95}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right) \cdot \left(\left(F \cdot \left(\left(C + -0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right) + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B\_m, B\_m, \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{elif}\;{B\_m}^{2} \leq 4 \cdot 10^{+71}:\\ \;\;\;\;\sqrt{\left(2 \cdot F\right) \cdot t\_0} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(B\_m, A - C\right) + A\right) + C}}{-t\_0}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
                          B_m = (fabs.f64 B)
                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                          (FPCore (A B_m C F)
                           :precision binary64
                           (let* ((t_0 (fma -4.0 (* C A) (* B_m B_m))))
                             (if (<= (pow B_m 2.0) 2e-95)
                               (/
                                (sqrt
                                 (*
                                  (fma (* -4.0 C) A (* B_m B_m))
                                  (* (* F (+ (+ C (* -0.5 (/ (* B_m B_m) A))) C)) 2.0)))
                                (fma (- B_m) B_m (* (* 4.0 A) C)))
                               (if (<= (pow B_m 2.0) 4e+71)
                                 (*
                                  (sqrt (* (* 2.0 F) t_0))
                                  (/ (sqrt (+ (+ (hypot B_m (- A C)) A) C)) (- t_0)))
                                 (* (- (sqrt F)) (sqrt (/ 2.0 B_m)))))))
                          B_m = fabs(B);
                          assert(A < B_m && B_m < C && C < F);
                          double code(double A, double B_m, double C, double F) {
                          	double t_0 = fma(-4.0, (C * A), (B_m * B_m));
                          	double tmp;
                          	if (pow(B_m, 2.0) <= 2e-95) {
                          		tmp = sqrt((fma((-4.0 * C), A, (B_m * B_m)) * ((F * ((C + (-0.5 * ((B_m * B_m) / A))) + C)) * 2.0))) / fma(-B_m, B_m, ((4.0 * A) * C));
                          	} else if (pow(B_m, 2.0) <= 4e+71) {
                          		tmp = sqrt(((2.0 * F) * t_0)) * (sqrt(((hypot(B_m, (A - C)) + A) + C)) / -t_0);
                          	} else {
                          		tmp = -sqrt(F) * sqrt((2.0 / B_m));
                          	}
                          	return tmp;
                          }
                          
                          B_m = abs(B)
                          A, B_m, C, F = sort([A, B_m, C, F])
                          function code(A, B_m, C, F)
                          	t_0 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
                          	tmp = 0.0
                          	if ((B_m ^ 2.0) <= 2e-95)
                          		tmp = Float64(sqrt(Float64(fma(Float64(-4.0 * C), A, Float64(B_m * B_m)) * Float64(Float64(F * Float64(Float64(C + Float64(-0.5 * Float64(Float64(B_m * B_m) / A))) + C)) * 2.0))) / fma(Float64(-B_m), B_m, Float64(Float64(4.0 * A) * C)));
                          	elseif ((B_m ^ 2.0) <= 4e+71)
                          		tmp = Float64(sqrt(Float64(Float64(2.0 * F) * t_0)) * Float64(sqrt(Float64(Float64(hypot(B_m, Float64(A - C)) + A) + C)) / Float64(-t_0)));
                          	else
                          		tmp = Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)));
                          	end
                          	return tmp
                          end
                          
                          B_m = N[Abs[B], $MachinePrecision]
                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                          code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 2e-95], N[(N[Sqrt[N[(N[(N[(-4.0 * C), $MachinePrecision] * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision] * N[(N[(F * N[(N[(C + N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + C), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[((-B$95$m) * B$95$m + N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 4e+71], N[(N[Sqrt[N[(N[(2.0 * F), $MachinePrecision] * t$95$0), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[N[(N[(N[Sqrt[B$95$m ^ 2 + N[(A - C), $MachinePrecision] ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision]), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]
                          
                          \begin{array}{l}
                          B_m = \left|B\right|
                          \\
                          [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                          \\
                          \begin{array}{l}
                          t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
                          \mathbf{if}\;{B\_m}^{2} \leq 2 \cdot 10^{-95}:\\
                          \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right) \cdot \left(\left(F \cdot \left(\left(C + -0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right) + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B\_m, B\_m, \left(4 \cdot A\right) \cdot C\right)}\\
                          
                          \mathbf{elif}\;{B\_m}^{2} \leq 4 \cdot 10^{+71}:\\
                          \;\;\;\;\sqrt{\left(2 \cdot F\right) \cdot t\_0} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(B\_m, A - C\right) + A\right) + C}}{-t\_0}\\
                          
                          \mathbf{else}:\\
                          \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\
                          
                          
                          \end{array}
                          \end{array}
                          
                          Derivation
                          1. Split input into 3 regimes
                          2. if (pow.f64 B #s(literal 2 binary64)) < 1.99999999999999998e-95

                            1. Initial program 18.2%

                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            2. Add Preprocessing
                            3. Applied rewrites26.7%

                              \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)}} \]
                            4. Applied rewrites26.1%

                              \[\leadsto \frac{\sqrt{\color{blue}{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)\right) \cdot 2\right)}}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                            5. Taylor expanded in A around -inf

                              \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                            6. Step-by-step derivation
                              1. lower-+.f64N/A

                                \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                              2. lower-*.f64N/A

                                \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(C + \color{blue}{\frac{-1}{2} \cdot \frac{{B}^{2}}{A}}\right) + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                              3. lower-/.f64N/A

                                \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(C + \frac{-1}{2} \cdot \color{blue}{\frac{{B}^{2}}{A}}\right) + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                              4. unpow2N/A

                                \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(C + \frac{-1}{2} \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                              5. lower-*.f6424.7

                                \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(C + -0.5 \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                            7. Applied rewrites24.7%

                              \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\color{blue}{\left(C + -0.5 \cdot \frac{B \cdot B}{A}\right)} + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]

                            if 1.99999999999999998e-95 < (pow.f64 B #s(literal 2 binary64)) < 4.0000000000000002e71

                            1. Initial program 46.0%

                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            2. Add Preprocessing
                            3. Applied rewrites59.4%

                              \[\leadsto \color{blue}{\left(-\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]

                            if 4.0000000000000002e71 < (pow.f64 B #s(literal 2 binary64))

                            1. Initial program 14.2%

                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            2. Add Preprocessing
                            3. Taylor expanded in B around inf

                              \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                            4. Step-by-step derivation
                              1. mul-1-negN/A

                                \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                              2. *-commutativeN/A

                                \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                              3. distribute-lft-neg-inN/A

                                \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                              4. lower-*.f64N/A

                                \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                              5. lower-neg.f64N/A

                                \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
                              6. lower-sqrt.f64N/A

                                \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
                              7. lower-sqrt.f64N/A

                                \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
                              8. lower-/.f6431.8

                                \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                            5. Applied rewrites31.8%

                              \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
                            6. Step-by-step derivation
                              1. Applied rewrites31.9%

                                \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                              2. Step-by-step derivation
                                1. Applied rewrites36.0%

                                  \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                              3. Recombined 3 regimes into one program.
                              4. Final simplification33.3%

                                \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 2 \cdot 10^{-95}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(C + -0.5 \cdot \frac{B \cdot B}{A}\right) + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{elif}\;{B}^{2} \leq 4 \cdot 10^{+71}:\\ \;\;\;\;\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
                              5. Add Preprocessing

                              Alternative 8: 52.7% accurate, 1.2× speedup?

                              \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-B\_m, B\_m, \left(4 \cdot A\right) \cdot C\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 2 \cdot 10^{-95}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right) \cdot \left(\left(F \cdot \left(\left(C + -0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right) + C\right)\right) \cdot 2\right)}}{t\_0}\\ \mathbf{elif}\;{B\_m}^{2} \leq 2 \cdot 10^{+51}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B\_m, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\right)}}{t\_0}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
                              B_m = (fabs.f64 B)
                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                              (FPCore (A B_m C F)
                               :precision binary64
                               (let* ((t_0 (fma (- B_m) B_m (* (* 4.0 A) C))))
                                 (if (<= (pow B_m 2.0) 2e-95)
                                   (/
                                    (sqrt
                                     (*
                                      (fma (* -4.0 C) A (* B_m B_m))
                                      (* (* F (+ (+ C (* -0.5 (/ (* B_m B_m) A))) C)) 2.0)))
                                    t_0)
                                   (if (<= (pow B_m 2.0) 2e+51)
                                     (/
                                      (sqrt
                                       (*
                                        (+ (+ (hypot B_m (- A C)) A) C)
                                        (* (* 2.0 F) (fma -4.0 (* C A) (* B_m B_m)))))
                                      t_0)
                                     (* (- (sqrt F)) (sqrt (/ 2.0 B_m)))))))
                              B_m = fabs(B);
                              assert(A < B_m && B_m < C && C < F);
                              double code(double A, double B_m, double C, double F) {
                              	double t_0 = fma(-B_m, B_m, ((4.0 * A) * C));
                              	double tmp;
                              	if (pow(B_m, 2.0) <= 2e-95) {
                              		tmp = sqrt((fma((-4.0 * C), A, (B_m * B_m)) * ((F * ((C + (-0.5 * ((B_m * B_m) / A))) + C)) * 2.0))) / t_0;
                              	} else if (pow(B_m, 2.0) <= 2e+51) {
                              		tmp = sqrt((((hypot(B_m, (A - C)) + A) + C) * ((2.0 * F) * fma(-4.0, (C * A), (B_m * B_m))))) / t_0;
                              	} else {
                              		tmp = -sqrt(F) * sqrt((2.0 / B_m));
                              	}
                              	return tmp;
                              }
                              
                              B_m = abs(B)
                              A, B_m, C, F = sort([A, B_m, C, F])
                              function code(A, B_m, C, F)
                              	t_0 = fma(Float64(-B_m), B_m, Float64(Float64(4.0 * A) * C))
                              	tmp = 0.0
                              	if ((B_m ^ 2.0) <= 2e-95)
                              		tmp = Float64(sqrt(Float64(fma(Float64(-4.0 * C), A, Float64(B_m * B_m)) * Float64(Float64(F * Float64(Float64(C + Float64(-0.5 * Float64(Float64(B_m * B_m) / A))) + C)) * 2.0))) / t_0);
                              	elseif ((B_m ^ 2.0) <= 2e+51)
                              		tmp = Float64(sqrt(Float64(Float64(Float64(hypot(B_m, Float64(A - C)) + A) + C) * Float64(Float64(2.0 * F) * fma(-4.0, Float64(C * A), Float64(B_m * B_m))))) / t_0);
                              	else
                              		tmp = Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)));
                              	end
                              	return tmp
                              end
                              
                              B_m = N[Abs[B], $MachinePrecision]
                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                              code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[((-B$95$m) * B$95$m + N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 2e-95], N[(N[Sqrt[N[(N[(N[(-4.0 * C), $MachinePrecision] * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision] * N[(N[(F * N[(N[(C + N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + C), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / t$95$0), $MachinePrecision], If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 2e+51], N[(N[Sqrt[N[(N[(N[(N[Sqrt[B$95$m ^ 2 + N[(A - C), $MachinePrecision] ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision] * N[(N[(2.0 * F), $MachinePrecision] * N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / t$95$0), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]
                              
                              \begin{array}{l}
                              B_m = \left|B\right|
                              \\
                              [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                              \\
                              \begin{array}{l}
                              t_0 := \mathsf{fma}\left(-B\_m, B\_m, \left(4 \cdot A\right) \cdot C\right)\\
                              \mathbf{if}\;{B\_m}^{2} \leq 2 \cdot 10^{-95}:\\
                              \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right) \cdot \left(\left(F \cdot \left(\left(C + -0.5 \cdot \frac{B\_m \cdot B\_m}{A}\right) + C\right)\right) \cdot 2\right)}}{t\_0}\\
                              
                              \mathbf{elif}\;{B\_m}^{2} \leq 2 \cdot 10^{+51}:\\
                              \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B\_m, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\right)}}{t\_0}\\
                              
                              \mathbf{else}:\\
                              \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\
                              
                              
                              \end{array}
                              \end{array}
                              
                              Derivation
                              1. Split input into 3 regimes
                              2. if (pow.f64 B #s(literal 2 binary64)) < 1.99999999999999998e-95

                                1. Initial program 18.2%

                                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                2. Add Preprocessing
                                3. Applied rewrites26.7%

                                  \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)}} \]
                                4. Applied rewrites26.1%

                                  \[\leadsto \frac{\sqrt{\color{blue}{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right)\right) \cdot 2\right)}}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                                5. Taylor expanded in A around -inf

                                  \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                                6. Step-by-step derivation
                                  1. lower-+.f64N/A

                                    \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                                  2. lower-*.f64N/A

                                    \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(C + \color{blue}{\frac{-1}{2} \cdot \frac{{B}^{2}}{A}}\right) + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                                  3. lower-/.f64N/A

                                    \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(C + \frac{-1}{2} \cdot \color{blue}{\frac{{B}^{2}}{A}}\right) + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                                  4. unpow2N/A

                                    \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(C + \frac{-1}{2} \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                                  5. lower-*.f6424.7

                                    \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(C + -0.5 \cdot \frac{\color{blue}{B \cdot B}}{A}\right) + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                                7. Applied rewrites24.7%

                                  \[\leadsto \frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\color{blue}{\left(C + -0.5 \cdot \frac{B \cdot B}{A}\right)} + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]

                                if 1.99999999999999998e-95 < (pow.f64 B #s(literal 2 binary64)) < 2e51

                                1. Initial program 50.9%

                                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                2. Add Preprocessing
                                3. Applied rewrites55.0%

                                  \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)}} \]

                                if 2e51 < (pow.f64 B #s(literal 2 binary64))

                                1. Initial program 13.9%

                                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                2. Add Preprocessing
                                3. Taylor expanded in B around inf

                                  \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                4. Step-by-step derivation
                                  1. mul-1-negN/A

                                    \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                  2. *-commutativeN/A

                                    \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                  3. distribute-lft-neg-inN/A

                                    \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                  4. lower-*.f64N/A

                                    \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                  5. lower-neg.f64N/A

                                    \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
                                  6. lower-sqrt.f64N/A

                                    \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
                                  7. lower-sqrt.f64N/A

                                    \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
                                  8. lower-/.f6431.0

                                    \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                5. Applied rewrites31.0%

                                  \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
                                6. Step-by-step derivation
                                  1. Applied rewrites31.1%

                                    \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                  2. Step-by-step derivation
                                    1. Applied rewrites35.1%

                                      \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                  3. Recombined 3 regimes into one program.
                                  4. Final simplification32.2%

                                    \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 2 \cdot 10^{-95}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(\left(F \cdot \left(\left(C + -0.5 \cdot \frac{B \cdot B}{A}\right) + C\right)\right) \cdot 2\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{elif}\;{B}^{2} \leq 2 \cdot 10^{+51}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
                                  5. Add Preprocessing

                                  Alternative 9: 51.7% accurate, 2.7× speedup?

                                  \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;{B\_m}^{2} \leq 2 \cdot 10^{+21}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\right)}}{\mathsf{fma}\left(-B\_m, B\_m, \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
                                  B_m = (fabs.f64 B)
                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                  (FPCore (A B_m C F)
                                   :precision binary64
                                   (if (<= (pow B_m 2.0) 2e+21)
                                     (/
                                      (sqrt (* (* 2.0 C) (* (* 2.0 F) (fma -4.0 (* C A) (* B_m B_m)))))
                                      (fma (- B_m) B_m (* (* 4.0 A) C)))
                                     (* (- (sqrt F)) (sqrt (/ 2.0 B_m)))))
                                  B_m = fabs(B);
                                  assert(A < B_m && B_m < C && C < F);
                                  double code(double A, double B_m, double C, double F) {
                                  	double tmp;
                                  	if (pow(B_m, 2.0) <= 2e+21) {
                                  		tmp = sqrt(((2.0 * C) * ((2.0 * F) * fma(-4.0, (C * A), (B_m * B_m))))) / fma(-B_m, B_m, ((4.0 * A) * C));
                                  	} else {
                                  		tmp = -sqrt(F) * sqrt((2.0 / B_m));
                                  	}
                                  	return tmp;
                                  }
                                  
                                  B_m = abs(B)
                                  A, B_m, C, F = sort([A, B_m, C, F])
                                  function code(A, B_m, C, F)
                                  	tmp = 0.0
                                  	if ((B_m ^ 2.0) <= 2e+21)
                                  		tmp = Float64(sqrt(Float64(Float64(2.0 * C) * Float64(Float64(2.0 * F) * fma(-4.0, Float64(C * A), Float64(B_m * B_m))))) / fma(Float64(-B_m), B_m, Float64(Float64(4.0 * A) * C)));
                                  	else
                                  		tmp = Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)));
                                  	end
                                  	return tmp
                                  end
                                  
                                  B_m = N[Abs[B], $MachinePrecision]
                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                  code[A_, B$95$m_, C_, F_] := If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 2e+21], N[(N[Sqrt[N[(N[(2.0 * C), $MachinePrecision] * N[(N[(2.0 * F), $MachinePrecision] * N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[((-B$95$m) * B$95$m + N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]
                                  
                                  \begin{array}{l}
                                  B_m = \left|B\right|
                                  \\
                                  [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                  \\
                                  \begin{array}{l}
                                  \mathbf{if}\;{B\_m}^{2} \leq 2 \cdot 10^{+21}:\\
                                  \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\right)}}{\mathsf{fma}\left(-B\_m, B\_m, \left(4 \cdot A\right) \cdot C\right)}\\
                                  
                                  \mathbf{else}:\\
                                  \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\
                                  
                                  
                                  \end{array}
                                  \end{array}
                                  
                                  Derivation
                                  1. Split input into 2 regimes
                                  2. if (pow.f64 B #s(literal 2 binary64)) < 2e21

                                    1. Initial program 22.8%

                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    2. Add Preprocessing
                                    3. Applied rewrites30.9%

                                      \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)}} \]
                                    4. Taylor expanded in A around -inf

                                      \[\leadsto \frac{\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                                    5. Step-by-step derivation
                                      1. lower-*.f6424.0

                                        \[\leadsto \frac{\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                                    6. Applied rewrites24.0%

                                      \[\leadsto \frac{\sqrt{\color{blue}{\left(2 \cdot C\right)} \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]

                                    if 2e21 < (pow.f64 B #s(literal 2 binary64))

                                    1. Initial program 15.8%

                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    2. Add Preprocessing
                                    3. Taylor expanded in B around inf

                                      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                    4. Step-by-step derivation
                                      1. mul-1-negN/A

                                        \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                      2. *-commutativeN/A

                                        \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                      3. distribute-lft-neg-inN/A

                                        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                      4. lower-*.f64N/A

                                        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                      5. lower-neg.f64N/A

                                        \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
                                      6. lower-sqrt.f64N/A

                                        \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
                                      7. lower-sqrt.f64N/A

                                        \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
                                      8. lower-/.f6431.1

                                        \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                    5. Applied rewrites31.1%

                                      \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
                                    6. Step-by-step derivation
                                      1. Applied rewrites31.2%

                                        \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                      2. Step-by-step derivation
                                        1. Applied rewrites35.0%

                                          \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                      3. Recombined 2 regimes into one program.
                                      4. Final simplification28.9%

                                        \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 2 \cdot 10^{+21}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
                                      5. Add Preprocessing

                                      Alternative 10: 43.7% accurate, 2.9× speedup?

                                      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;{B\_m}^{2} \leq 2 \cdot 10^{-90}:\\ \;\;\;\;\frac{\sqrt{-16 \cdot \left(A \cdot \left(\left(C \cdot C\right) \cdot F\right)\right)}}{\mathsf{fma}\left(-B\_m, B\_m, \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
                                      B_m = (fabs.f64 B)
                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                      (FPCore (A B_m C F)
                                       :precision binary64
                                       (if (<= (pow B_m 2.0) 2e-90)
                                         (/ (sqrt (* -16.0 (* A (* (* C C) F)))) (fma (- B_m) B_m (* (* 4.0 A) C)))
                                         (* (- (sqrt F)) (sqrt (/ 2.0 B_m)))))
                                      B_m = fabs(B);
                                      assert(A < B_m && B_m < C && C < F);
                                      double code(double A, double B_m, double C, double F) {
                                      	double tmp;
                                      	if (pow(B_m, 2.0) <= 2e-90) {
                                      		tmp = sqrt((-16.0 * (A * ((C * C) * F)))) / fma(-B_m, B_m, ((4.0 * A) * C));
                                      	} else {
                                      		tmp = -sqrt(F) * sqrt((2.0 / B_m));
                                      	}
                                      	return tmp;
                                      }
                                      
                                      B_m = abs(B)
                                      A, B_m, C, F = sort([A, B_m, C, F])
                                      function code(A, B_m, C, F)
                                      	tmp = 0.0
                                      	if ((B_m ^ 2.0) <= 2e-90)
                                      		tmp = Float64(sqrt(Float64(-16.0 * Float64(A * Float64(Float64(C * C) * F)))) / fma(Float64(-B_m), B_m, Float64(Float64(4.0 * A) * C)));
                                      	else
                                      		tmp = Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)));
                                      	end
                                      	return tmp
                                      end
                                      
                                      B_m = N[Abs[B], $MachinePrecision]
                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                      code[A_, B$95$m_, C_, F_] := If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 2e-90], N[(N[Sqrt[N[(-16.0 * N[(A * N[(N[(C * C), $MachinePrecision] * F), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[((-B$95$m) * B$95$m + N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]
                                      
                                      \begin{array}{l}
                                      B_m = \left|B\right|
                                      \\
                                      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                      \\
                                      \begin{array}{l}
                                      \mathbf{if}\;{B\_m}^{2} \leq 2 \cdot 10^{-90}:\\
                                      \;\;\;\;\frac{\sqrt{-16 \cdot \left(A \cdot \left(\left(C \cdot C\right) \cdot F\right)\right)}}{\mathsf{fma}\left(-B\_m, B\_m, \left(4 \cdot A\right) \cdot C\right)}\\
                                      
                                      \mathbf{else}:\\
                                      \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\
                                      
                                      
                                      \end{array}
                                      \end{array}
                                      
                                      Derivation
                                      1. Split input into 2 regimes
                                      2. if (pow.f64 B #s(literal 2 binary64)) < 1.99999999999999999e-90

                                        1. Initial program 18.1%

                                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                        2. Add Preprocessing
                                        3. Applied rewrites26.5%

                                          \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, A - C\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)}} \]
                                        4. Taylor expanded in C around 0

                                          \[\leadsto \frac{\sqrt{\color{blue}{\left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                                        5. Step-by-step derivation
                                          1. lower-+.f64N/A

                                            \[\leadsto \frac{\sqrt{\color{blue}{\left(A + \sqrt{{A}^{2} + {B}^{2}}\right)} \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                                          2. unpow2N/A

                                            \[\leadsto \frac{\sqrt{\left(A + \sqrt{\color{blue}{A \cdot A} + {B}^{2}}\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                                          3. unpow2N/A

                                            \[\leadsto \frac{\sqrt{\left(A + \sqrt{A \cdot A + \color{blue}{B \cdot B}}\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                                          4. lower-hypot.f6416.5

                                            \[\leadsto \frac{\sqrt{\left(A + \color{blue}{\mathsf{hypot}\left(A, B\right)}\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                                        6. Applied rewrites16.5%

                                          \[\leadsto \frac{\sqrt{\color{blue}{\left(A + \mathsf{hypot}\left(A, B\right)\right)} \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                                        7. Taylor expanded in A around -inf

                                          \[\leadsto \frac{\sqrt{\color{blue}{-16 \cdot \left(A \cdot \left({C}^{2} \cdot F\right)\right)}}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                                        8. Step-by-step derivation
                                          1. lower-*.f64N/A

                                            \[\leadsto \frac{\sqrt{\color{blue}{-16 \cdot \left(A \cdot \left({C}^{2} \cdot F\right)\right)}}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                                          2. lower-*.f64N/A

                                            \[\leadsto \frac{\sqrt{-16 \cdot \color{blue}{\left(A \cdot \left({C}^{2} \cdot F\right)\right)}}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                                          3. lower-*.f64N/A

                                            \[\leadsto \frac{\sqrt{-16 \cdot \left(A \cdot \color{blue}{\left({C}^{2} \cdot F\right)}\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                                          4. unpow2N/A

                                            \[\leadsto \frac{\sqrt{-16 \cdot \left(A \cdot \left(\color{blue}{\left(C \cdot C\right)} \cdot F\right)\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                                          5. lower-*.f6414.3

                                            \[\leadsto \frac{\sqrt{-16 \cdot \left(A \cdot \left(\color{blue}{\left(C \cdot C\right)} \cdot F\right)\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]
                                        9. Applied rewrites14.3%

                                          \[\leadsto \frac{\sqrt{\color{blue}{-16 \cdot \left(A \cdot \left(\left(C \cdot C\right) \cdot F\right)\right)}}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)} \]

                                        if 1.99999999999999999e-90 < (pow.f64 B #s(literal 2 binary64))

                                        1. Initial program 21.2%

                                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                        2. Add Preprocessing
                                        3. Taylor expanded in B around inf

                                          \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                        4. Step-by-step derivation
                                          1. mul-1-negN/A

                                            \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                          2. *-commutativeN/A

                                            \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                          3. distribute-lft-neg-inN/A

                                            \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                          4. lower-*.f64N/A

                                            \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                          5. lower-neg.f64N/A

                                            \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
                                          6. lower-sqrt.f64N/A

                                            \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
                                          7. lower-sqrt.f64N/A

                                            \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
                                          8. lower-/.f6428.1

                                            \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                        5. Applied rewrites28.1%

                                          \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
                                        6. Step-by-step derivation
                                          1. Applied rewrites28.2%

                                            \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                          2. Step-by-step derivation
                                            1. Applied rewrites31.4%

                                              \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                          3. Recombined 2 regimes into one program.
                                          4. Final simplification23.2%

                                            \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 2 \cdot 10^{-90}:\\ \;\;\;\;\frac{\sqrt{-16 \cdot \left(A \cdot \left(\left(C \cdot C\right) \cdot F\right)\right)}}{\mathsf{fma}\left(-B, B, \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
                                          5. Add Preprocessing

                                          Alternative 11: 35.8% accurate, 12.6× speedup?

                                          \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}} \end{array} \]
                                          B_m = (fabs.f64 B)
                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                          (FPCore (A B_m C F) :precision binary64 (* (- (sqrt F)) (sqrt (/ 2.0 B_m))))
                                          B_m = fabs(B);
                                          assert(A < B_m && B_m < C && C < F);
                                          double code(double A, double B_m, double C, double F) {
                                          	return -sqrt(F) * sqrt((2.0 / B_m));
                                          }
                                          
                                          B_m = abs(b)
                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                          real(8) function code(a, b_m, c, f)
                                              real(8), intent (in) :: a
                                              real(8), intent (in) :: b_m
                                              real(8), intent (in) :: c
                                              real(8), intent (in) :: f
                                              code = -sqrt(f) * sqrt((2.0d0 / b_m))
                                          end function
                                          
                                          B_m = Math.abs(B);
                                          assert A < B_m && B_m < C && C < F;
                                          public static double code(double A, double B_m, double C, double F) {
                                          	return -Math.sqrt(F) * Math.sqrt((2.0 / B_m));
                                          }
                                          
                                          B_m = math.fabs(B)
                                          [A, B_m, C, F] = sort([A, B_m, C, F])
                                          def code(A, B_m, C, F):
                                          	return -math.sqrt(F) * math.sqrt((2.0 / B_m))
                                          
                                          B_m = abs(B)
                                          A, B_m, C, F = sort([A, B_m, C, F])
                                          function code(A, B_m, C, F)
                                          	return Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)))
                                          end
                                          
                                          B_m = abs(B);
                                          A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                          function tmp = code(A, B_m, C, F)
                                          	tmp = -sqrt(F) * sqrt((2.0 / B_m));
                                          end
                                          
                                          B_m = N[Abs[B], $MachinePrecision]
                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                          code[A_, B$95$m_, C_, F_] := N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
                                          
                                          \begin{array}{l}
                                          B_m = \left|B\right|
                                          \\
                                          [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                          \\
                                          \left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}
                                          \end{array}
                                          
                                          Derivation
                                          1. Initial program 19.7%

                                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                          2. Add Preprocessing
                                          3. Taylor expanded in B around inf

                                            \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                          4. Step-by-step derivation
                                            1. mul-1-negN/A

                                              \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                            2. *-commutativeN/A

                                              \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                            3. distribute-lft-neg-inN/A

                                              \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                            4. lower-*.f64N/A

                                              \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                            5. lower-neg.f64N/A

                                              \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
                                            6. lower-sqrt.f64N/A

                                              \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
                                            7. lower-sqrt.f64N/A

                                              \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
                                            8. lower-/.f6416.3

                                              \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                          5. Applied rewrites16.3%

                                            \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
                                          6. Step-by-step derivation
                                            1. Applied rewrites16.3%

                                              \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                            2. Step-by-step derivation
                                              1. Applied rewrites18.4%

                                                \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                              2. Final simplification18.4%

                                                \[\leadsto \left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}} \]
                                              3. Add Preprocessing

                                              Alternative 12: 27.2% accurate, 16.9× speedup?

                                              \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ -\sqrt{F \cdot \frac{2}{B\_m}} \end{array} \]
                                              B_m = (fabs.f64 B)
                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                              (FPCore (A B_m C F) :precision binary64 (- (sqrt (* F (/ 2.0 B_m)))))
                                              B_m = fabs(B);
                                              assert(A < B_m && B_m < C && C < F);
                                              double code(double A, double B_m, double C, double F) {
                                              	return -sqrt((F * (2.0 / B_m)));
                                              }
                                              
                                              B_m = abs(b)
                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                              real(8) function code(a, b_m, c, f)
                                                  real(8), intent (in) :: a
                                                  real(8), intent (in) :: b_m
                                                  real(8), intent (in) :: c
                                                  real(8), intent (in) :: f
                                                  code = -sqrt((f * (2.0d0 / b_m)))
                                              end function
                                              
                                              B_m = Math.abs(B);
                                              assert A < B_m && B_m < C && C < F;
                                              public static double code(double A, double B_m, double C, double F) {
                                              	return -Math.sqrt((F * (2.0 / B_m)));
                                              }
                                              
                                              B_m = math.fabs(B)
                                              [A, B_m, C, F] = sort([A, B_m, C, F])
                                              def code(A, B_m, C, F):
                                              	return -math.sqrt((F * (2.0 / B_m)))
                                              
                                              B_m = abs(B)
                                              A, B_m, C, F = sort([A, B_m, C, F])
                                              function code(A, B_m, C, F)
                                              	return Float64(-sqrt(Float64(F * Float64(2.0 / B_m))))
                                              end
                                              
                                              B_m = abs(B);
                                              A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                              function tmp = code(A, B_m, C, F)
                                              	tmp = -sqrt((F * (2.0 / B_m)));
                                              end
                                              
                                              B_m = N[Abs[B], $MachinePrecision]
                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                              code[A_, B$95$m_, C_, F_] := (-N[Sqrt[N[(F * N[(2.0 / B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision])
                                              
                                              \begin{array}{l}
                                              B_m = \left|B\right|
                                              \\
                                              [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                              \\
                                              -\sqrt{F \cdot \frac{2}{B\_m}}
                                              \end{array}
                                              
                                              Derivation
                                              1. Initial program 19.7%

                                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              2. Add Preprocessing
                                              3. Taylor expanded in B around inf

                                                \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                              4. Step-by-step derivation
                                                1. mul-1-negN/A

                                                  \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                2. *-commutativeN/A

                                                  \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                3. distribute-lft-neg-inN/A

                                                  \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                4. lower-*.f64N/A

                                                  \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                5. lower-neg.f64N/A

                                                  \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
                                                6. lower-sqrt.f64N/A

                                                  \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
                                                7. lower-sqrt.f64N/A

                                                  \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
                                                8. lower-/.f6416.3

                                                  \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                              5. Applied rewrites16.3%

                                                \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
                                              6. Step-by-step derivation
                                                1. Applied rewrites16.3%

                                                  \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                2. Step-by-step derivation
                                                  1. Applied rewrites16.3%

                                                    \[\leadsto -\sqrt{F \cdot \frac{2}{B}} \]
                                                  2. Add Preprocessing

                                                  Reproduce

                                                  ?
                                                  herbie shell --seed 2024326 
                                                  (FPCore (A B C F)
                                                    :name "ABCF->ab-angle a"
                                                    :precision binary64
                                                    (/ (- (sqrt (* (* 2.0 (* (- (pow B 2.0) (* (* 4.0 A) C)) F)) (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))) (- (pow B 2.0) (* (* 4.0 A) C))))