Data.Random.Distribution.Normal:normalF from random-fu-0.2.6.2

Percentage Accurate: 100.0% → 100.0%
Time: 6.4s
Alternatives: 11
Speedup: 1.0×

Specification

?
\[\begin{array}{l} \\ e^{\left(x \cdot y\right) \cdot y} \end{array} \]
(FPCore (x y) :precision binary64 (exp (* (* x y) y)))
double code(double x, double y) {
	return exp(((x * y) * y));
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = exp(((x * y) * y))
end function
public static double code(double x, double y) {
	return Math.exp(((x * y) * y));
}
def code(x, y):
	return math.exp(((x * y) * y))
function code(x, y)
	return exp(Float64(Float64(x * y) * y))
end
function tmp = code(x, y)
	tmp = exp(((x * y) * y));
end
code[x_, y_] := N[Exp[N[(N[(x * y), $MachinePrecision] * y), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
e^{\left(x \cdot y\right) \cdot y}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 11 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ e^{\left(x \cdot y\right) \cdot y} \end{array} \]
(FPCore (x y) :precision binary64 (exp (* (* x y) y)))
double code(double x, double y) {
	return exp(((x * y) * y));
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = exp(((x * y) * y))
end function
public static double code(double x, double y) {
	return Math.exp(((x * y) * y));
}
def code(x, y):
	return math.exp(((x * y) * y))
function code(x, y)
	return exp(Float64(Float64(x * y) * y))
end
function tmp = code(x, y)
	tmp = exp(((x * y) * y));
end
code[x_, y_] := N[Exp[N[(N[(x * y), $MachinePrecision] * y), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
e^{\left(x \cdot y\right) \cdot y}
\end{array}

Alternative 1: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ e^{\left(x \cdot y\right) \cdot y} \end{array} \]
(FPCore (x y) :precision binary64 (exp (* (* x y) y)))
double code(double x, double y) {
	return exp(((x * y) * y));
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = exp(((x * y) * y))
end function
public static double code(double x, double y) {
	return Math.exp(((x * y) * y));
}
def code(x, y):
	return math.exp(((x * y) * y))
function code(x, y)
	return exp(Float64(Float64(x * y) * y))
end
function tmp = code(x, y)
	tmp = exp(((x * y) * y));
end
code[x_, y_] := N[Exp[N[(N[(x * y), $MachinePrecision] * y), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
e^{\left(x \cdot y\right) \cdot y}
\end{array}
Derivation
  1. Initial program 100.0%

    \[e^{\left(x \cdot y\right) \cdot y} \]
  2. Add Preprocessing
  3. Add Preprocessing

Alternative 2: 73.5% accurate, 0.7× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{\left(x \cdot y\right) \cdot y} \leq 0:\\ \;\;\;\;\left(\sqrt{y} \cdot \sqrt{y \cdot \left(x \cdot x\right)}\right) \cdot y\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(x, x \cdot \left(\left(\mathsf{fma}\left(0.16666666666666666, \left(y \cdot y\right) \cdot x, 0.5\right) \cdot y\right) \cdot y\right), x\right) \cdot y, y, 1\right)\\ \end{array} \end{array} \]
(FPCore (x y)
 :precision binary64
 (if (<= (exp (* (* x y) y)) 0.0)
   (* (* (sqrt y) (sqrt (* y (* x x)))) y)
   (fma
    (*
     (fma x (* x (* (* (fma 0.16666666666666666 (* (* y y) x) 0.5) y) y)) x)
     y)
    y
    1.0)))
double code(double x, double y) {
	double tmp;
	if (exp(((x * y) * y)) <= 0.0) {
		tmp = (sqrt(y) * sqrt((y * (x * x)))) * y;
	} else {
		tmp = fma((fma(x, (x * ((fma(0.16666666666666666, ((y * y) * x), 0.5) * y) * y)), x) * y), y, 1.0);
	}
	return tmp;
}
function code(x, y)
	tmp = 0.0
	if (exp(Float64(Float64(x * y) * y)) <= 0.0)
		tmp = Float64(Float64(sqrt(y) * sqrt(Float64(y * Float64(x * x)))) * y);
	else
		tmp = fma(Float64(fma(x, Float64(x * Float64(Float64(fma(0.16666666666666666, Float64(Float64(y * y) * x), 0.5) * y) * y)), x) * y), y, 1.0);
	end
	return tmp
end
code[x_, y_] := If[LessEqual[N[Exp[N[(N[(x * y), $MachinePrecision] * y), $MachinePrecision]], $MachinePrecision], 0.0], N[(N[(N[Sqrt[y], $MachinePrecision] * N[Sqrt[N[(y * N[(x * x), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * y), $MachinePrecision], N[(N[(N[(x * N[(x * N[(N[(N[(0.16666666666666666 * N[(N[(y * y), $MachinePrecision] * x), $MachinePrecision] + 0.5), $MachinePrecision] * y), $MachinePrecision] * y), $MachinePrecision]), $MachinePrecision] + x), $MachinePrecision] * y), $MachinePrecision] * y + 1.0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;e^{\left(x \cdot y\right) \cdot y} \leq 0:\\
\;\;\;\;\left(\sqrt{y} \cdot \sqrt{y \cdot \left(x \cdot x\right)}\right) \cdot y\\

\mathbf{else}:\\
\;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(x, x \cdot \left(\left(\mathsf{fma}\left(0.16666666666666666, \left(y \cdot y\right) \cdot x, 0.5\right) \cdot y\right) \cdot y\right), x\right) \cdot y, y, 1\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (exp.f64 (*.f64 (*.f64 x y) y)) < 0.0

    1. Initial program 100.0%

      \[e^{\left(x \cdot y\right) \cdot y} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
    4. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
      2. *-commutativeN/A

        \[\leadsto \color{blue}{{y}^{2} \cdot x} + 1 \]
      3. lower-fma.f64N/A

        \[\leadsto \color{blue}{\mathsf{fma}\left({y}^{2}, x, 1\right)} \]
      4. unpow2N/A

        \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
      5. lower-*.f641.9

        \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
    5. Applied rewrites1.9%

      \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, x, 1\right)} \]
    6. Taylor expanded in x around inf

      \[\leadsto x \cdot \color{blue}{{y}^{2}} \]
    7. Step-by-step derivation
      1. Applied rewrites1.9%

        \[\leadsto \left(y \cdot y\right) \cdot \color{blue}{x} \]
      2. Step-by-step derivation
        1. Applied rewrites2.1%

          \[\leadsto \left(y \cdot x\right) \cdot y \]
        2. Step-by-step derivation
          1. Applied rewrites11.9%

            \[\leadsto \left(\sqrt{y} \cdot \sqrt{y \cdot \left(x \cdot x\right)}\right) \cdot y \]

          if 0.0 < (exp.f64 (*.f64 (*.f64 x y) y))

          1. Initial program 100.0%

            \[e^{\left(x \cdot y\right) \cdot y} \]
          2. Add Preprocessing
          3. Taylor expanded in x around 0

            \[\leadsto \color{blue}{1} \]
          4. Step-by-step derivation
            1. Applied rewrites69.8%

              \[\leadsto \color{blue}{1} \]
            2. Taylor expanded in y around 0

              \[\leadsto \color{blue}{1 + {y}^{2} \cdot \left(x + {y}^{2} \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot {y}^{2}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right)} \]
            3. Step-by-step derivation
              1. +-commutativeN/A

                \[\leadsto \color{blue}{{y}^{2} \cdot \left(x + {y}^{2} \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot {y}^{2}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) + 1} \]
              2. *-commutativeN/A

                \[\leadsto \color{blue}{\left(x + {y}^{2} \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot {y}^{2}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) \cdot {y}^{2}} + 1 \]
              3. unpow2N/A

                \[\leadsto \left(x + {y}^{2} \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot {y}^{2}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) \cdot \color{blue}{\left(y \cdot y\right)} + 1 \]
              4. associate-*r*N/A

                \[\leadsto \color{blue}{\left(\left(x + {y}^{2} \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot {y}^{2}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) \cdot y\right) \cdot y} + 1 \]
              5. lower-fma.f64N/A

                \[\leadsto \color{blue}{\mathsf{fma}\left(\left(x + {y}^{2} \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot {y}^{2}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) \cdot y, y, 1\right)} \]
            4. Applied rewrites85.5%

              \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\left(x \cdot x\right) \cdot \mathsf{fma}\left(0.16666666666666666, \left(y \cdot y\right) \cdot x, 0.5\right), y \cdot y, x\right) \cdot y, y, 1\right)} \]
            5. Step-by-step derivation
              1. Applied rewrites98.9%

                \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(x, x \cdot \left(\left(\mathsf{fma}\left(0.16666666666666666, \left(y \cdot y\right) \cdot x, 0.5\right) \cdot y\right) \cdot y\right), x\right) \cdot y, y, 1\right) \]
            6. Recombined 2 regimes into one program.
            7. Add Preprocessing

            Alternative 3: 71.8% accurate, 0.7× speedup?

            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{\left(x \cdot y\right) \cdot y} \leq 0:\\ \;\;\;\;\left(\sqrt{y} \cdot \sqrt{y \cdot \left(x \cdot x\right)}\right) \cdot y\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(0.5, \left(y \cdot y\right) \cdot x, 1\right) \cdot x, 1\right)\\ \end{array} \end{array} \]
            (FPCore (x y)
             :precision binary64
             (if (<= (exp (* (* x y) y)) 0.0)
               (* (* (sqrt y) (sqrt (* y (* x x)))) y)
               (fma (* y y) (* (fma 0.5 (* (* y y) x) 1.0) x) 1.0)))
            double code(double x, double y) {
            	double tmp;
            	if (exp(((x * y) * y)) <= 0.0) {
            		tmp = (sqrt(y) * sqrt((y * (x * x)))) * y;
            	} else {
            		tmp = fma((y * y), (fma(0.5, ((y * y) * x), 1.0) * x), 1.0);
            	}
            	return tmp;
            }
            
            function code(x, y)
            	tmp = 0.0
            	if (exp(Float64(Float64(x * y) * y)) <= 0.0)
            		tmp = Float64(Float64(sqrt(y) * sqrt(Float64(y * Float64(x * x)))) * y);
            	else
            		tmp = fma(Float64(y * y), Float64(fma(0.5, Float64(Float64(y * y) * x), 1.0) * x), 1.0);
            	end
            	return tmp
            end
            
            code[x_, y_] := If[LessEqual[N[Exp[N[(N[(x * y), $MachinePrecision] * y), $MachinePrecision]], $MachinePrecision], 0.0], N[(N[(N[Sqrt[y], $MachinePrecision] * N[Sqrt[N[(y * N[(x * x), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * y), $MachinePrecision], N[(N[(y * y), $MachinePrecision] * N[(N[(0.5 * N[(N[(y * y), $MachinePrecision] * x), $MachinePrecision] + 1.0), $MachinePrecision] * x), $MachinePrecision] + 1.0), $MachinePrecision]]
            
            \begin{array}{l}
            
            \\
            \begin{array}{l}
            \mathbf{if}\;e^{\left(x \cdot y\right) \cdot y} \leq 0:\\
            \;\;\;\;\left(\sqrt{y} \cdot \sqrt{y \cdot \left(x \cdot x\right)}\right) \cdot y\\
            
            \mathbf{else}:\\
            \;\;\;\;\mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(0.5, \left(y \cdot y\right) \cdot x, 1\right) \cdot x, 1\right)\\
            
            
            \end{array}
            \end{array}
            
            Derivation
            1. Split input into 2 regimes
            2. if (exp.f64 (*.f64 (*.f64 x y) y)) < 0.0

              1. Initial program 100.0%

                \[e^{\left(x \cdot y\right) \cdot y} \]
              2. Add Preprocessing
              3. Taylor expanded in x around 0

                \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
              4. Step-by-step derivation
                1. +-commutativeN/A

                  \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
                2. *-commutativeN/A

                  \[\leadsto \color{blue}{{y}^{2} \cdot x} + 1 \]
                3. lower-fma.f64N/A

                  \[\leadsto \color{blue}{\mathsf{fma}\left({y}^{2}, x, 1\right)} \]
                4. unpow2N/A

                  \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
                5. lower-*.f641.9

                  \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
              5. Applied rewrites1.9%

                \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, x, 1\right)} \]
              6. Taylor expanded in x around inf

                \[\leadsto x \cdot \color{blue}{{y}^{2}} \]
              7. Step-by-step derivation
                1. Applied rewrites1.9%

                  \[\leadsto \left(y \cdot y\right) \cdot \color{blue}{x} \]
                2. Step-by-step derivation
                  1. Applied rewrites2.1%

                    \[\leadsto \left(y \cdot x\right) \cdot y \]
                  2. Step-by-step derivation
                    1. Applied rewrites11.9%

                      \[\leadsto \left(\sqrt{y} \cdot \sqrt{y \cdot \left(x \cdot x\right)}\right) \cdot y \]

                    if 0.0 < (exp.f64 (*.f64 (*.f64 x y) y))

                    1. Initial program 100.0%

                      \[e^{\left(x \cdot y\right) \cdot y} \]
                    2. Add Preprocessing
                    3. Taylor expanded in x around 0

                      \[\leadsto \color{blue}{1} \]
                    4. Step-by-step derivation
                      1. Applied rewrites69.8%

                        \[\leadsto \color{blue}{1} \]
                      2. Taylor expanded in y around 0

                        \[\leadsto \color{blue}{1 + {y}^{2} \cdot \left(x + {y}^{2} \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot {y}^{2}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right)} \]
                      3. Step-by-step derivation
                        1. +-commutativeN/A

                          \[\leadsto \color{blue}{{y}^{2} \cdot \left(x + {y}^{2} \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot {y}^{2}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) + 1} \]
                        2. *-commutativeN/A

                          \[\leadsto \color{blue}{\left(x + {y}^{2} \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot {y}^{2}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) \cdot {y}^{2}} + 1 \]
                        3. unpow2N/A

                          \[\leadsto \left(x + {y}^{2} \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot {y}^{2}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) \cdot \color{blue}{\left(y \cdot y\right)} + 1 \]
                        4. associate-*r*N/A

                          \[\leadsto \color{blue}{\left(\left(x + {y}^{2} \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot {y}^{2}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) \cdot y\right) \cdot y} + 1 \]
                        5. lower-fma.f64N/A

                          \[\leadsto \color{blue}{\mathsf{fma}\left(\left(x + {y}^{2} \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot {y}^{2}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) \cdot y, y, 1\right)} \]
                      4. Applied rewrites85.5%

                        \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\left(x \cdot x\right) \cdot \mathsf{fma}\left(0.16666666666666666, \left(y \cdot y\right) \cdot x, 0.5\right), y \cdot y, x\right) \cdot y, y, 1\right)} \]
                      5. Taylor expanded in x around 0

                        \[\leadsto \mathsf{fma}\left(\left(x \cdot \left(1 + \frac{1}{2} \cdot \left(x \cdot {y}^{2}\right)\right)\right) \cdot y, y, 1\right) \]
                      6. Step-by-step derivation
                        1. Applied rewrites96.2%

                          \[\leadsto \mathsf{fma}\left(\left(\mathsf{fma}\left(0.5, \left(y \cdot y\right) \cdot x, 1\right) \cdot x\right) \cdot y, y, 1\right) \]
                        2. Step-by-step derivation
                          1. Applied rewrites96.2%

                            \[\leadsto \mathsf{fma}\left(y \cdot y, \color{blue}{\mathsf{fma}\left(0.5, \left(y \cdot y\right) \cdot x, 1\right) \cdot x}, 1\right) \]
                        3. Recombined 2 regimes into one program.
                        4. Add Preprocessing

                        Alternative 4: 58.7% accurate, 0.8× speedup?

                        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{\left(x \cdot y\right) \cdot y} \leq 2:\\ \;\;\;\;\mathsf{fma}\left(y \cdot x, y, 1\right)\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\left(\left(y \cdot y\right) \cdot x\right) \cdot x} \cdot y\\ \end{array} \end{array} \]
                        (FPCore (x y)
                         :precision binary64
                         (if (<= (exp (* (* x y) y)) 2.0)
                           (fma (* y x) y 1.0)
                           (* (sqrt (* (* (* y y) x) x)) y)))
                        double code(double x, double y) {
                        	double tmp;
                        	if (exp(((x * y) * y)) <= 2.0) {
                        		tmp = fma((y * x), y, 1.0);
                        	} else {
                        		tmp = sqrt((((y * y) * x) * x)) * y;
                        	}
                        	return tmp;
                        }
                        
                        function code(x, y)
                        	tmp = 0.0
                        	if (exp(Float64(Float64(x * y) * y)) <= 2.0)
                        		tmp = fma(Float64(y * x), y, 1.0);
                        	else
                        		tmp = Float64(sqrt(Float64(Float64(Float64(y * y) * x) * x)) * y);
                        	end
                        	return tmp
                        end
                        
                        code[x_, y_] := If[LessEqual[N[Exp[N[(N[(x * y), $MachinePrecision] * y), $MachinePrecision]], $MachinePrecision], 2.0], N[(N[(y * x), $MachinePrecision] * y + 1.0), $MachinePrecision], N[(N[Sqrt[N[(N[(N[(y * y), $MachinePrecision] * x), $MachinePrecision] * x), $MachinePrecision]], $MachinePrecision] * y), $MachinePrecision]]
                        
                        \begin{array}{l}
                        
                        \\
                        \begin{array}{l}
                        \mathbf{if}\;e^{\left(x \cdot y\right) \cdot y} \leq 2:\\
                        \;\;\;\;\mathsf{fma}\left(y \cdot x, y, 1\right)\\
                        
                        \mathbf{else}:\\
                        \;\;\;\;\sqrt{\left(\left(y \cdot y\right) \cdot x\right) \cdot x} \cdot y\\
                        
                        
                        \end{array}
                        \end{array}
                        
                        Derivation
                        1. Split input into 2 regimes
                        2. if (exp.f64 (*.f64 (*.f64 x y) y)) < 2

                          1. Initial program 100.0%

                            \[e^{\left(x \cdot y\right) \cdot y} \]
                          2. Add Preprocessing
                          3. Taylor expanded in x around 0

                            \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
                          4. Step-by-step derivation
                            1. +-commutativeN/A

                              \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
                            2. *-commutativeN/A

                              \[\leadsto \color{blue}{{y}^{2} \cdot x} + 1 \]
                            3. lower-fma.f64N/A

                              \[\leadsto \color{blue}{\mathsf{fma}\left({y}^{2}, x, 1\right)} \]
                            4. unpow2N/A

                              \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
                            5. lower-*.f6464.4

                              \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
                          5. Applied rewrites64.4%

                            \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, x, 1\right)} \]
                          6. Step-by-step derivation
                            1. Applied rewrites64.5%

                              \[\leadsto \mathsf{fma}\left(y \cdot x, \color{blue}{y}, 1\right) \]

                            if 2 < (exp.f64 (*.f64 (*.f64 x y) y))

                            1. Initial program 100.0%

                              \[e^{\left(x \cdot y\right) \cdot y} \]
                            2. Add Preprocessing
                            3. Taylor expanded in x around 0

                              \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
                            4. Step-by-step derivation
                              1. +-commutativeN/A

                                \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
                              2. *-commutativeN/A

                                \[\leadsto \color{blue}{{y}^{2} \cdot x} + 1 \]
                              3. lower-fma.f64N/A

                                \[\leadsto \color{blue}{\mathsf{fma}\left({y}^{2}, x, 1\right)} \]
                              4. unpow2N/A

                                \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
                              5. lower-*.f6466.3

                                \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
                            5. Applied rewrites66.3%

                              \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, x, 1\right)} \]
                            6. Taylor expanded in x around inf

                              \[\leadsto x \cdot \color{blue}{{y}^{2}} \]
                            7. Step-by-step derivation
                              1. Applied rewrites66.3%

                                \[\leadsto \left(y \cdot y\right) \cdot \color{blue}{x} \]
                              2. Step-by-step derivation
                                1. Applied rewrites29.3%

                                  \[\leadsto \sqrt{\left(\left(y \cdot y\right) \cdot x\right) \cdot x} \cdot y \]
                              3. Recombined 2 regimes into one program.
                              4. Add Preprocessing

                              Alternative 5: 65.5% accurate, 0.9× speedup?

                              \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{\left(x \cdot y\right) \cdot y} \leq 2:\\ \;\;\;\;\mathsf{fma}\left(y \cdot x, y, 1\right)\\ \mathbf{else}:\\ \;\;\;\;\left(y \cdot y\right) \cdot x\\ \end{array} \end{array} \]
                              (FPCore (x y)
                               :precision binary64
                               (if (<= (exp (* (* x y) y)) 2.0) (fma (* y x) y 1.0) (* (* y y) x)))
                              double code(double x, double y) {
                              	double tmp;
                              	if (exp(((x * y) * y)) <= 2.0) {
                              		tmp = fma((y * x), y, 1.0);
                              	} else {
                              		tmp = (y * y) * x;
                              	}
                              	return tmp;
                              }
                              
                              function code(x, y)
                              	tmp = 0.0
                              	if (exp(Float64(Float64(x * y) * y)) <= 2.0)
                              		tmp = fma(Float64(y * x), y, 1.0);
                              	else
                              		tmp = Float64(Float64(y * y) * x);
                              	end
                              	return tmp
                              end
                              
                              code[x_, y_] := If[LessEqual[N[Exp[N[(N[(x * y), $MachinePrecision] * y), $MachinePrecision]], $MachinePrecision], 2.0], N[(N[(y * x), $MachinePrecision] * y + 1.0), $MachinePrecision], N[(N[(y * y), $MachinePrecision] * x), $MachinePrecision]]
                              
                              \begin{array}{l}
                              
                              \\
                              \begin{array}{l}
                              \mathbf{if}\;e^{\left(x \cdot y\right) \cdot y} \leq 2:\\
                              \;\;\;\;\mathsf{fma}\left(y \cdot x, y, 1\right)\\
                              
                              \mathbf{else}:\\
                              \;\;\;\;\left(y \cdot y\right) \cdot x\\
                              
                              
                              \end{array}
                              \end{array}
                              
                              Derivation
                              1. Split input into 2 regimes
                              2. if (exp.f64 (*.f64 (*.f64 x y) y)) < 2

                                1. Initial program 100.0%

                                  \[e^{\left(x \cdot y\right) \cdot y} \]
                                2. Add Preprocessing
                                3. Taylor expanded in x around 0

                                  \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
                                4. Step-by-step derivation
                                  1. +-commutativeN/A

                                    \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
                                  2. *-commutativeN/A

                                    \[\leadsto \color{blue}{{y}^{2} \cdot x} + 1 \]
                                  3. lower-fma.f64N/A

                                    \[\leadsto \color{blue}{\mathsf{fma}\left({y}^{2}, x, 1\right)} \]
                                  4. unpow2N/A

                                    \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
                                  5. lower-*.f6464.4

                                    \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
                                5. Applied rewrites64.4%

                                  \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, x, 1\right)} \]
                                6. Step-by-step derivation
                                  1. Applied rewrites64.5%

                                    \[\leadsto \mathsf{fma}\left(y \cdot x, \color{blue}{y}, 1\right) \]

                                  if 2 < (exp.f64 (*.f64 (*.f64 x y) y))

                                  1. Initial program 100.0%

                                    \[e^{\left(x \cdot y\right) \cdot y} \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in x around 0

                                    \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
                                  4. Step-by-step derivation
                                    1. +-commutativeN/A

                                      \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
                                    2. *-commutativeN/A

                                      \[\leadsto \color{blue}{{y}^{2} \cdot x} + 1 \]
                                    3. lower-fma.f64N/A

                                      \[\leadsto \color{blue}{\mathsf{fma}\left({y}^{2}, x, 1\right)} \]
                                    4. unpow2N/A

                                      \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
                                    5. lower-*.f6466.3

                                      \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
                                  5. Applied rewrites66.3%

                                    \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, x, 1\right)} \]
                                  6. Taylor expanded in x around inf

                                    \[\leadsto x \cdot \color{blue}{{y}^{2}} \]
                                  7. Step-by-step derivation
                                    1. Applied rewrites66.3%

                                      \[\leadsto \left(y \cdot y\right) \cdot \color{blue}{x} \]
                                  8. Recombined 2 regimes into one program.
                                  9. Add Preprocessing

                                  Alternative 6: 70.2% accurate, 3.4× speedup?

                                  \[\begin{array}{l} \\ \mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(0.5, \left(y \cdot y\right) \cdot x, 1\right) \cdot x, 1\right) \end{array} \]
                                  (FPCore (x y)
                                   :precision binary64
                                   (fma (* y y) (* (fma 0.5 (* (* y y) x) 1.0) x) 1.0))
                                  double code(double x, double y) {
                                  	return fma((y * y), (fma(0.5, ((y * y) * x), 1.0) * x), 1.0);
                                  }
                                  
                                  function code(x, y)
                                  	return fma(Float64(y * y), Float64(fma(0.5, Float64(Float64(y * y) * x), 1.0) * x), 1.0)
                                  end
                                  
                                  code[x_, y_] := N[(N[(y * y), $MachinePrecision] * N[(N[(0.5 * N[(N[(y * y), $MachinePrecision] * x), $MachinePrecision] + 1.0), $MachinePrecision] * x), $MachinePrecision] + 1.0), $MachinePrecision]
                                  
                                  \begin{array}{l}
                                  
                                  \\
                                  \mathsf{fma}\left(y \cdot y, \mathsf{fma}\left(0.5, \left(y \cdot y\right) \cdot x, 1\right) \cdot x, 1\right)
                                  \end{array}
                                  
                                  Derivation
                                  1. Initial program 100.0%

                                    \[e^{\left(x \cdot y\right) \cdot y} \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in x around 0

                                    \[\leadsto \color{blue}{1} \]
                                  4. Step-by-step derivation
                                    1. Applied rewrites51.0%

                                      \[\leadsto \color{blue}{1} \]
                                    2. Taylor expanded in y around 0

                                      \[\leadsto \color{blue}{1 + {y}^{2} \cdot \left(x + {y}^{2} \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot {y}^{2}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right)} \]
                                    3. Step-by-step derivation
                                      1. +-commutativeN/A

                                        \[\leadsto \color{blue}{{y}^{2} \cdot \left(x + {y}^{2} \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot {y}^{2}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) + 1} \]
                                      2. *-commutativeN/A

                                        \[\leadsto \color{blue}{\left(x + {y}^{2} \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot {y}^{2}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) \cdot {y}^{2}} + 1 \]
                                      3. unpow2N/A

                                        \[\leadsto \left(x + {y}^{2} \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot {y}^{2}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) \cdot \color{blue}{\left(y \cdot y\right)} + 1 \]
                                      4. associate-*r*N/A

                                        \[\leadsto \color{blue}{\left(\left(x + {y}^{2} \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot {y}^{2}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) \cdot y\right) \cdot y} + 1 \]
                                      5. lower-fma.f64N/A

                                        \[\leadsto \color{blue}{\mathsf{fma}\left(\left(x + {y}^{2} \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot {y}^{2}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) \cdot y, y, 1\right)} \]
                                    4. Applied rewrites61.9%

                                      \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\left(x \cdot x\right) \cdot \mathsf{fma}\left(0.16666666666666666, \left(y \cdot y\right) \cdot x, 0.5\right), y \cdot y, x\right) \cdot y, y, 1\right)} \]
                                    5. Taylor expanded in x around 0

                                      \[\leadsto \mathsf{fma}\left(\left(x \cdot \left(1 + \frac{1}{2} \cdot \left(x \cdot {y}^{2}\right)\right)\right) \cdot y, y, 1\right) \]
                                    6. Step-by-step derivation
                                      1. Applied rewrites69.7%

                                        \[\leadsto \mathsf{fma}\left(\left(\mathsf{fma}\left(0.5, \left(y \cdot y\right) \cdot x, 1\right) \cdot x\right) \cdot y, y, 1\right) \]
                                      2. Step-by-step derivation
                                        1. Applied rewrites69.7%

                                          \[\leadsto \mathsf{fma}\left(y \cdot y, \color{blue}{\mathsf{fma}\left(0.5, \left(y \cdot y\right) \cdot x, 1\right) \cdot x}, 1\right) \]
                                        2. Add Preprocessing

                                        Alternative 7: 69.8% accurate, 3.5× speedup?

                                        \[\begin{array}{l} \\ \mathsf{fma}\left(\left(\left(\left(\left(y \cdot y\right) \cdot x\right) \cdot x\right) \cdot 0.5\right) \cdot y, y, 1\right) \end{array} \]
                                        (FPCore (x y)
                                         :precision binary64
                                         (fma (* (* (* (* (* y y) x) x) 0.5) y) y 1.0))
                                        double code(double x, double y) {
                                        	return fma((((((y * y) * x) * x) * 0.5) * y), y, 1.0);
                                        }
                                        
                                        function code(x, y)
                                        	return fma(Float64(Float64(Float64(Float64(Float64(y * y) * x) * x) * 0.5) * y), y, 1.0)
                                        end
                                        
                                        code[x_, y_] := N[(N[(N[(N[(N[(N[(y * y), $MachinePrecision] * x), $MachinePrecision] * x), $MachinePrecision] * 0.5), $MachinePrecision] * y), $MachinePrecision] * y + 1.0), $MachinePrecision]
                                        
                                        \begin{array}{l}
                                        
                                        \\
                                        \mathsf{fma}\left(\left(\left(\left(\left(y \cdot y\right) \cdot x\right) \cdot x\right) \cdot 0.5\right) \cdot y, y, 1\right)
                                        \end{array}
                                        
                                        Derivation
                                        1. Initial program 100.0%

                                          \[e^{\left(x \cdot y\right) \cdot y} \]
                                        2. Add Preprocessing
                                        3. Taylor expanded in x around 0

                                          \[\leadsto \color{blue}{1} \]
                                        4. Step-by-step derivation
                                          1. Applied rewrites51.0%

                                            \[\leadsto \color{blue}{1} \]
                                          2. Taylor expanded in y around 0

                                            \[\leadsto \color{blue}{1 + {y}^{2} \cdot \left(x + {y}^{2} \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot {y}^{2}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right)} \]
                                          3. Step-by-step derivation
                                            1. +-commutativeN/A

                                              \[\leadsto \color{blue}{{y}^{2} \cdot \left(x + {y}^{2} \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot {y}^{2}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) + 1} \]
                                            2. *-commutativeN/A

                                              \[\leadsto \color{blue}{\left(x + {y}^{2} \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot {y}^{2}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) \cdot {y}^{2}} + 1 \]
                                            3. unpow2N/A

                                              \[\leadsto \left(x + {y}^{2} \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot {y}^{2}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) \cdot \color{blue}{\left(y \cdot y\right)} + 1 \]
                                            4. associate-*r*N/A

                                              \[\leadsto \color{blue}{\left(\left(x + {y}^{2} \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot {y}^{2}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) \cdot y\right) \cdot y} + 1 \]
                                            5. lower-fma.f64N/A

                                              \[\leadsto \color{blue}{\mathsf{fma}\left(\left(x + {y}^{2} \cdot \left(\frac{1}{6} \cdot \left({x}^{3} \cdot {y}^{2}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right) \cdot y, y, 1\right)} \]
                                          4. Applied rewrites61.9%

                                            \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\left(x \cdot x\right) \cdot \mathsf{fma}\left(0.16666666666666666, \left(y \cdot y\right) \cdot x, 0.5\right), y \cdot y, x\right) \cdot y, y, 1\right)} \]
                                          5. Taylor expanded in x around 0

                                            \[\leadsto \mathsf{fma}\left(\left(x \cdot \left(1 + \frac{1}{2} \cdot \left(x \cdot {y}^{2}\right)\right)\right) \cdot y, y, 1\right) \]
                                          6. Step-by-step derivation
                                            1. Applied rewrites69.7%

                                              \[\leadsto \mathsf{fma}\left(\left(\mathsf{fma}\left(0.5, \left(y \cdot y\right) \cdot x, 1\right) \cdot x\right) \cdot y, y, 1\right) \]
                                            2. Taylor expanded in x around inf

                                              \[\leadsto \mathsf{fma}\left(\left(\frac{1}{2} \cdot \left({x}^{2} \cdot {y}^{2}\right)\right) \cdot y, y, 1\right) \]
                                            3. Step-by-step derivation
                                              1. Applied rewrites69.3%

                                                \[\leadsto \mathsf{fma}\left(\left(\left(\left(\left(y \cdot y\right) \cdot x\right) \cdot x\right) \cdot 0.5\right) \cdot y, y, 1\right) \]
                                              2. Add Preprocessing

                                              Alternative 8: 65.1% accurate, 4.1× speedup?

                                              \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\left(x \cdot y\right) \cdot y \leq 5 \cdot 10^{-20}:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\left(y \cdot y\right) \cdot x\\ \end{array} \end{array} \]
                                              (FPCore (x y)
                                               :precision binary64
                                               (if (<= (* (* x y) y) 5e-20) 1.0 (* (* y y) x)))
                                              double code(double x, double y) {
                                              	double tmp;
                                              	if (((x * y) * y) <= 5e-20) {
                                              		tmp = 1.0;
                                              	} else {
                                              		tmp = (y * y) * x;
                                              	}
                                              	return tmp;
                                              }
                                              
                                              real(8) function code(x, y)
                                                  real(8), intent (in) :: x
                                                  real(8), intent (in) :: y
                                                  real(8) :: tmp
                                                  if (((x * y) * y) <= 5d-20) then
                                                      tmp = 1.0d0
                                                  else
                                                      tmp = (y * y) * x
                                                  end if
                                                  code = tmp
                                              end function
                                              
                                              public static double code(double x, double y) {
                                              	double tmp;
                                              	if (((x * y) * y) <= 5e-20) {
                                              		tmp = 1.0;
                                              	} else {
                                              		tmp = (y * y) * x;
                                              	}
                                              	return tmp;
                                              }
                                              
                                              def code(x, y):
                                              	tmp = 0
                                              	if ((x * y) * y) <= 5e-20:
                                              		tmp = 1.0
                                              	else:
                                              		tmp = (y * y) * x
                                              	return tmp
                                              
                                              function code(x, y)
                                              	tmp = 0.0
                                              	if (Float64(Float64(x * y) * y) <= 5e-20)
                                              		tmp = 1.0;
                                              	else
                                              		tmp = Float64(Float64(y * y) * x);
                                              	end
                                              	return tmp
                                              end
                                              
                                              function tmp_2 = code(x, y)
                                              	tmp = 0.0;
                                              	if (((x * y) * y) <= 5e-20)
                                              		tmp = 1.0;
                                              	else
                                              		tmp = (y * y) * x;
                                              	end
                                              	tmp_2 = tmp;
                                              end
                                              
                                              code[x_, y_] := If[LessEqual[N[(N[(x * y), $MachinePrecision] * y), $MachinePrecision], 5e-20], 1.0, N[(N[(y * y), $MachinePrecision] * x), $MachinePrecision]]
                                              
                                              \begin{array}{l}
                                              
                                              \\
                                              \begin{array}{l}
                                              \mathbf{if}\;\left(x \cdot y\right) \cdot y \leq 5 \cdot 10^{-20}:\\
                                              \;\;\;\;1\\
                                              
                                              \mathbf{else}:\\
                                              \;\;\;\;\left(y \cdot y\right) \cdot x\\
                                              
                                              
                                              \end{array}
                                              \end{array}
                                              
                                              Derivation
                                              1. Split input into 2 regimes
                                              2. if (*.f64 (*.f64 x y) y) < 4.9999999999999999e-20

                                                1. Initial program 100.0%

                                                  \[e^{\left(x \cdot y\right) \cdot y} \]
                                                2. Add Preprocessing
                                                3. Taylor expanded in x around 0

                                                  \[\leadsto \color{blue}{1} \]
                                                4. Step-by-step derivation
                                                  1. Applied rewrites64.4%

                                                    \[\leadsto \color{blue}{1} \]

                                                  if 4.9999999999999999e-20 < (*.f64 (*.f64 x y) y)

                                                  1. Initial program 100.0%

                                                    \[e^{\left(x \cdot y\right) \cdot y} \]
                                                  2. Add Preprocessing
                                                  3. Taylor expanded in x around 0

                                                    \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
                                                  4. Step-by-step derivation
                                                    1. +-commutativeN/A

                                                      \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
                                                    2. *-commutativeN/A

                                                      \[\leadsto \color{blue}{{y}^{2} \cdot x} + 1 \]
                                                    3. lower-fma.f64N/A

                                                      \[\leadsto \color{blue}{\mathsf{fma}\left({y}^{2}, x, 1\right)} \]
                                                    4. unpow2N/A

                                                      \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
                                                    5. lower-*.f6466.3

                                                      \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
                                                  5. Applied rewrites66.3%

                                                    \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, x, 1\right)} \]
                                                  6. Taylor expanded in x around inf

                                                    \[\leadsto x \cdot \color{blue}{{y}^{2}} \]
                                                  7. Step-by-step derivation
                                                    1. Applied rewrites66.3%

                                                      \[\leadsto \left(y \cdot y\right) \cdot \color{blue}{x} \]
                                                  8. Recombined 2 regimes into one program.
                                                  9. Add Preprocessing

                                                  Alternative 9: 62.1% accurate, 4.1× speedup?

                                                  \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\left(x \cdot y\right) \cdot y \leq 5 \cdot 10^{-20}:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\left(y \cdot x\right) \cdot y\\ \end{array} \end{array} \]
                                                  (FPCore (x y)
                                                   :precision binary64
                                                   (if (<= (* (* x y) y) 5e-20) 1.0 (* (* y x) y)))
                                                  double code(double x, double y) {
                                                  	double tmp;
                                                  	if (((x * y) * y) <= 5e-20) {
                                                  		tmp = 1.0;
                                                  	} else {
                                                  		tmp = (y * x) * y;
                                                  	}
                                                  	return tmp;
                                                  }
                                                  
                                                  real(8) function code(x, y)
                                                      real(8), intent (in) :: x
                                                      real(8), intent (in) :: y
                                                      real(8) :: tmp
                                                      if (((x * y) * y) <= 5d-20) then
                                                          tmp = 1.0d0
                                                      else
                                                          tmp = (y * x) * y
                                                      end if
                                                      code = tmp
                                                  end function
                                                  
                                                  public static double code(double x, double y) {
                                                  	double tmp;
                                                  	if (((x * y) * y) <= 5e-20) {
                                                  		tmp = 1.0;
                                                  	} else {
                                                  		tmp = (y * x) * y;
                                                  	}
                                                  	return tmp;
                                                  }
                                                  
                                                  def code(x, y):
                                                  	tmp = 0
                                                  	if ((x * y) * y) <= 5e-20:
                                                  		tmp = 1.0
                                                  	else:
                                                  		tmp = (y * x) * y
                                                  	return tmp
                                                  
                                                  function code(x, y)
                                                  	tmp = 0.0
                                                  	if (Float64(Float64(x * y) * y) <= 5e-20)
                                                  		tmp = 1.0;
                                                  	else
                                                  		tmp = Float64(Float64(y * x) * y);
                                                  	end
                                                  	return tmp
                                                  end
                                                  
                                                  function tmp_2 = code(x, y)
                                                  	tmp = 0.0;
                                                  	if (((x * y) * y) <= 5e-20)
                                                  		tmp = 1.0;
                                                  	else
                                                  		tmp = (y * x) * y;
                                                  	end
                                                  	tmp_2 = tmp;
                                                  end
                                                  
                                                  code[x_, y_] := If[LessEqual[N[(N[(x * y), $MachinePrecision] * y), $MachinePrecision], 5e-20], 1.0, N[(N[(y * x), $MachinePrecision] * y), $MachinePrecision]]
                                                  
                                                  \begin{array}{l}
                                                  
                                                  \\
                                                  \begin{array}{l}
                                                  \mathbf{if}\;\left(x \cdot y\right) \cdot y \leq 5 \cdot 10^{-20}:\\
                                                  \;\;\;\;1\\
                                                  
                                                  \mathbf{else}:\\
                                                  \;\;\;\;\left(y \cdot x\right) \cdot y\\
                                                  
                                                  
                                                  \end{array}
                                                  \end{array}
                                                  
                                                  Derivation
                                                  1. Split input into 2 regimes
                                                  2. if (*.f64 (*.f64 x y) y) < 4.9999999999999999e-20

                                                    1. Initial program 100.0%

                                                      \[e^{\left(x \cdot y\right) \cdot y} \]
                                                    2. Add Preprocessing
                                                    3. Taylor expanded in x around 0

                                                      \[\leadsto \color{blue}{1} \]
                                                    4. Step-by-step derivation
                                                      1. Applied rewrites64.4%

                                                        \[\leadsto \color{blue}{1} \]

                                                      if 4.9999999999999999e-20 < (*.f64 (*.f64 x y) y)

                                                      1. Initial program 100.0%

                                                        \[e^{\left(x \cdot y\right) \cdot y} \]
                                                      2. Add Preprocessing
                                                      3. Taylor expanded in x around 0

                                                        \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
                                                      4. Step-by-step derivation
                                                        1. +-commutativeN/A

                                                          \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
                                                        2. *-commutativeN/A

                                                          \[\leadsto \color{blue}{{y}^{2} \cdot x} + 1 \]
                                                        3. lower-fma.f64N/A

                                                          \[\leadsto \color{blue}{\mathsf{fma}\left({y}^{2}, x, 1\right)} \]
                                                        4. unpow2N/A

                                                          \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
                                                        5. lower-*.f6466.3

                                                          \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
                                                      5. Applied rewrites66.3%

                                                        \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, x, 1\right)} \]
                                                      6. Taylor expanded in x around inf

                                                        \[\leadsto x \cdot \color{blue}{{y}^{2}} \]
                                                      7. Step-by-step derivation
                                                        1. Applied rewrites66.3%

                                                          \[\leadsto \left(y \cdot y\right) \cdot \color{blue}{x} \]
                                                        2. Step-by-step derivation
                                                          1. Applied rewrites51.1%

                                                            \[\leadsto \left(y \cdot x\right) \cdot y \]
                                                        3. Recombined 2 regimes into one program.
                                                        4. Add Preprocessing

                                                        Alternative 10: 65.5% accurate, 9.3× speedup?

                                                        \[\begin{array}{l} \\ \mathsf{fma}\left(y \cdot y, x, 1\right) \end{array} \]
                                                        (FPCore (x y) :precision binary64 (fma (* y y) x 1.0))
                                                        double code(double x, double y) {
                                                        	return fma((y * y), x, 1.0);
                                                        }
                                                        
                                                        function code(x, y)
                                                        	return fma(Float64(y * y), x, 1.0)
                                                        end
                                                        
                                                        code[x_, y_] := N[(N[(y * y), $MachinePrecision] * x + 1.0), $MachinePrecision]
                                                        
                                                        \begin{array}{l}
                                                        
                                                        \\
                                                        \mathsf{fma}\left(y \cdot y, x, 1\right)
                                                        \end{array}
                                                        
                                                        Derivation
                                                        1. Initial program 100.0%

                                                          \[e^{\left(x \cdot y\right) \cdot y} \]
                                                        2. Add Preprocessing
                                                        3. Taylor expanded in x around 0

                                                          \[\leadsto \color{blue}{1 + x \cdot {y}^{2}} \]
                                                        4. Step-by-step derivation
                                                          1. +-commutativeN/A

                                                            \[\leadsto \color{blue}{x \cdot {y}^{2} + 1} \]
                                                          2. *-commutativeN/A

                                                            \[\leadsto \color{blue}{{y}^{2} \cdot x} + 1 \]
                                                          3. lower-fma.f64N/A

                                                            \[\leadsto \color{blue}{\mathsf{fma}\left({y}^{2}, x, 1\right)} \]
                                                          4. unpow2N/A

                                                            \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
                                                          5. lower-*.f6464.8

                                                            \[\leadsto \mathsf{fma}\left(\color{blue}{y \cdot y}, x, 1\right) \]
                                                        5. Applied rewrites64.8%

                                                          \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot y, x, 1\right)} \]
                                                        6. Add Preprocessing

                                                        Alternative 11: 49.5% accurate, 111.0× speedup?

                                                        \[\begin{array}{l} \\ 1 \end{array} \]
                                                        (FPCore (x y) :precision binary64 1.0)
                                                        double code(double x, double y) {
                                                        	return 1.0;
                                                        }
                                                        
                                                        real(8) function code(x, y)
                                                            real(8), intent (in) :: x
                                                            real(8), intent (in) :: y
                                                            code = 1.0d0
                                                        end function
                                                        
                                                        public static double code(double x, double y) {
                                                        	return 1.0;
                                                        }
                                                        
                                                        def code(x, y):
                                                        	return 1.0
                                                        
                                                        function code(x, y)
                                                        	return 1.0
                                                        end
                                                        
                                                        function tmp = code(x, y)
                                                        	tmp = 1.0;
                                                        end
                                                        
                                                        code[x_, y_] := 1.0
                                                        
                                                        \begin{array}{l}
                                                        
                                                        \\
                                                        1
                                                        \end{array}
                                                        
                                                        Derivation
                                                        1. Initial program 100.0%

                                                          \[e^{\left(x \cdot y\right) \cdot y} \]
                                                        2. Add Preprocessing
                                                        3. Taylor expanded in x around 0

                                                          \[\leadsto \color{blue}{1} \]
                                                        4. Step-by-step derivation
                                                          1. Applied rewrites51.0%

                                                            \[\leadsto \color{blue}{1} \]
                                                          2. Add Preprocessing

                                                          Reproduce

                                                          ?
                                                          herbie shell --seed 2024326 
                                                          (FPCore (x y)
                                                            :name "Data.Random.Distribution.Normal:normalF from random-fu-0.2.6.2"
                                                            :precision binary64
                                                            (exp (* (* x y) y)))