Diagrams.Solve.Polynomial:cubForm from diagrams-solve-0.1, B

Percentage Accurate: 99.8% → 99.8%
Time: 6.2s
Alternatives: 6
Speedup: 1.0×

Specification

?
\[\begin{array}{l} \\ \left(x \cdot 3\right) \cdot y - z \end{array} \]
(FPCore (x y z) :precision binary64 (- (* (* x 3.0) y) z))
double code(double x, double y, double z) {
	return ((x * 3.0) * y) - z;
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = ((x * 3.0d0) * y) - z
end function
public static double code(double x, double y, double z) {
	return ((x * 3.0) * y) - z;
}
def code(x, y, z):
	return ((x * 3.0) * y) - z
function code(x, y, z)
	return Float64(Float64(Float64(x * 3.0) * y) - z)
end
function tmp = code(x, y, z)
	tmp = ((x * 3.0) * y) - z;
end
code[x_, y_, z_] := N[(N[(N[(x * 3.0), $MachinePrecision] * y), $MachinePrecision] - z), $MachinePrecision]
\begin{array}{l}

\\
\left(x \cdot 3\right) \cdot y - z
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 6 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 99.8% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \left(x \cdot 3\right) \cdot y - z \end{array} \]
(FPCore (x y z) :precision binary64 (- (* (* x 3.0) y) z))
double code(double x, double y, double z) {
	return ((x * 3.0) * y) - z;
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = ((x * 3.0d0) * y) - z
end function
public static double code(double x, double y, double z) {
	return ((x * 3.0) * y) - z;
}
def code(x, y, z):
	return ((x * 3.0) * y) - z
function code(x, y, z)
	return Float64(Float64(Float64(x * 3.0) * y) - z)
end
function tmp = code(x, y, z)
	tmp = ((x * 3.0) * y) - z;
end
code[x_, y_, z_] := N[(N[(N[(x * 3.0), $MachinePrecision] * y), $MachinePrecision] - z), $MachinePrecision]
\begin{array}{l}

\\
\left(x \cdot 3\right) \cdot y - z
\end{array}

Alternative 1: 99.8% accurate, 1.0× speedup?

\[\begin{array}{l} [x, y, z] = \mathsf{sort}([x, y, z])\\ \\ \left(y \cdot 3\right) \cdot x - z \end{array} \]
NOTE: x, y, and z should be sorted in increasing order before calling this function.
(FPCore (x y z) :precision binary64 (- (* (* y 3.0) x) z))
assert(x < y && y < z);
double code(double x, double y, double z) {
	return ((y * 3.0) * x) - z;
}
NOTE: x, y, and z should be sorted in increasing order before calling this function.
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = ((y * 3.0d0) * x) - z
end function
assert x < y && y < z;
public static double code(double x, double y, double z) {
	return ((y * 3.0) * x) - z;
}
[x, y, z] = sort([x, y, z])
def code(x, y, z):
	return ((y * 3.0) * x) - z
x, y, z = sort([x, y, z])
function code(x, y, z)
	return Float64(Float64(Float64(y * 3.0) * x) - z)
end
x, y, z = num2cell(sort([x, y, z])){:}
function tmp = code(x, y, z)
	tmp = ((y * 3.0) * x) - z;
end
NOTE: x, y, and z should be sorted in increasing order before calling this function.
code[x_, y_, z_] := N[(N[(N[(y * 3.0), $MachinePrecision] * x), $MachinePrecision] - z), $MachinePrecision]
\begin{array}{l}
[x, y, z] = \mathsf{sort}([x, y, z])\\
\\
\left(y \cdot 3\right) \cdot x - z
\end{array}
Derivation
  1. Initial program 99.8%

    \[\left(x \cdot 3\right) \cdot y - z \]
  2. Add Preprocessing
  3. Step-by-step derivation
    1. lift-*.f64N/A

      \[\leadsto \color{blue}{\left(x \cdot 3\right) \cdot y} - z \]
    2. lift-*.f64N/A

      \[\leadsto \color{blue}{\left(x \cdot 3\right)} \cdot y - z \]
    3. associate-*l*N/A

      \[\leadsto \color{blue}{x \cdot \left(3 \cdot y\right)} - z \]
    4. *-commutativeN/A

      \[\leadsto \color{blue}{\left(3 \cdot y\right) \cdot x} - z \]
    5. lower-*.f64N/A

      \[\leadsto \color{blue}{\left(3 \cdot y\right) \cdot x} - z \]
    6. *-commutativeN/A

      \[\leadsto \color{blue}{\left(y \cdot 3\right)} \cdot x - z \]
    7. lower-*.f6499.9

      \[\leadsto \color{blue}{\left(y \cdot 3\right)} \cdot x - z \]
  4. Applied rewrites99.9%

    \[\leadsto \color{blue}{\left(y \cdot 3\right) \cdot x} - z \]
  5. Add Preprocessing

Alternative 2: 79.2% accurate, 0.3× speedup?

\[\begin{array}{l} [x, y, z] = \mathsf{sort}([x, y, z])\\ \\ \begin{array}{l} t_0 := \left(x \cdot 3\right) \cdot y\\ \mathbf{if}\;t\_0 \leq -780000000000 \lor \neg \left(t\_0 \leq 7.6 \cdot 10^{-57}\right):\\ \;\;\;\;t\_0\\ \mathbf{else}:\\ \;\;\;\;-z\\ \end{array} \end{array} \]
NOTE: x, y, and z should be sorted in increasing order before calling this function.
(FPCore (x y z)
 :precision binary64
 (let* ((t_0 (* (* x 3.0) y)))
   (if (or (<= t_0 -780000000000.0) (not (<= t_0 7.6e-57))) t_0 (- z))))
assert(x < y && y < z);
double code(double x, double y, double z) {
	double t_0 = (x * 3.0) * y;
	double tmp;
	if ((t_0 <= -780000000000.0) || !(t_0 <= 7.6e-57)) {
		tmp = t_0;
	} else {
		tmp = -z;
	}
	return tmp;
}
NOTE: x, y, and z should be sorted in increasing order before calling this function.
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8) :: t_0
    real(8) :: tmp
    t_0 = (x * 3.0d0) * y
    if ((t_0 <= (-780000000000.0d0)) .or. (.not. (t_0 <= 7.6d-57))) then
        tmp = t_0
    else
        tmp = -z
    end if
    code = tmp
end function
assert x < y && y < z;
public static double code(double x, double y, double z) {
	double t_0 = (x * 3.0) * y;
	double tmp;
	if ((t_0 <= -780000000000.0) || !(t_0 <= 7.6e-57)) {
		tmp = t_0;
	} else {
		tmp = -z;
	}
	return tmp;
}
[x, y, z] = sort([x, y, z])
def code(x, y, z):
	t_0 = (x * 3.0) * y
	tmp = 0
	if (t_0 <= -780000000000.0) or not (t_0 <= 7.6e-57):
		tmp = t_0
	else:
		tmp = -z
	return tmp
x, y, z = sort([x, y, z])
function code(x, y, z)
	t_0 = Float64(Float64(x * 3.0) * y)
	tmp = 0.0
	if ((t_0 <= -780000000000.0) || !(t_0 <= 7.6e-57))
		tmp = t_0;
	else
		tmp = Float64(-z);
	end
	return tmp
end
x, y, z = num2cell(sort([x, y, z])){:}
function tmp_2 = code(x, y, z)
	t_0 = (x * 3.0) * y;
	tmp = 0.0;
	if ((t_0 <= -780000000000.0) || ~((t_0 <= 7.6e-57)))
		tmp = t_0;
	else
		tmp = -z;
	end
	tmp_2 = tmp;
end
NOTE: x, y, and z should be sorted in increasing order before calling this function.
code[x_, y_, z_] := Block[{t$95$0 = N[(N[(x * 3.0), $MachinePrecision] * y), $MachinePrecision]}, If[Or[LessEqual[t$95$0, -780000000000.0], N[Not[LessEqual[t$95$0, 7.6e-57]], $MachinePrecision]], t$95$0, (-z)]]
\begin{array}{l}
[x, y, z] = \mathsf{sort}([x, y, z])\\
\\
\begin{array}{l}
t_0 := \left(x \cdot 3\right) \cdot y\\
\mathbf{if}\;t\_0 \leq -780000000000 \lor \neg \left(t\_0 \leq 7.6 \cdot 10^{-57}\right):\\
\;\;\;\;t\_0\\

\mathbf{else}:\\
\;\;\;\;-z\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (*.f64 (*.f64 x #s(literal 3 binary64)) y) < -7.8e11 or 7.5999999999999995e-57 < (*.f64 (*.f64 x #s(literal 3 binary64)) y)

    1. Initial program 99.7%

      \[\left(x \cdot 3\right) \cdot y - z \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{\left(x \cdot 3\right) \cdot y} - z \]
      2. lift-*.f64N/A

        \[\leadsto \color{blue}{\left(x \cdot 3\right)} \cdot y - z \]
      3. associate-*l*N/A

        \[\leadsto \color{blue}{x \cdot \left(3 \cdot y\right)} - z \]
      4. *-commutativeN/A

        \[\leadsto \color{blue}{\left(3 \cdot y\right) \cdot x} - z \]
      5. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(3 \cdot y\right) \cdot x} - z \]
      6. *-commutativeN/A

        \[\leadsto \color{blue}{\left(y \cdot 3\right)} \cdot x - z \]
      7. lower-*.f6499.8

        \[\leadsto \color{blue}{\left(y \cdot 3\right)} \cdot x - z \]
    4. Applied rewrites99.8%

      \[\leadsto \color{blue}{\left(y \cdot 3\right) \cdot x} - z \]
    5. Taylor expanded in x around inf

      \[\leadsto \color{blue}{x \cdot \left(-1 \cdot \frac{z}{x} + 3 \cdot y\right)} \]
    6. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto \color{blue}{\left(-1 \cdot \frac{z}{x} + 3 \cdot y\right) \cdot x} \]
      2. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(-1 \cdot \frac{z}{x} + 3 \cdot y\right) \cdot x} \]
      3. +-commutativeN/A

        \[\leadsto \color{blue}{\left(3 \cdot y + -1 \cdot \frac{z}{x}\right)} \cdot x \]
      4. lower-fma.f64N/A

        \[\leadsto \color{blue}{\mathsf{fma}\left(3, y, -1 \cdot \frac{z}{x}\right)} \cdot x \]
      5. associate-*r/N/A

        \[\leadsto \mathsf{fma}\left(3, y, \color{blue}{\frac{-1 \cdot z}{x}}\right) \cdot x \]
      6. lower-/.f64N/A

        \[\leadsto \mathsf{fma}\left(3, y, \color{blue}{\frac{-1 \cdot z}{x}}\right) \cdot x \]
      7. mul-1-negN/A

        \[\leadsto \mathsf{fma}\left(3, y, \frac{\color{blue}{\mathsf{neg}\left(z\right)}}{x}\right) \cdot x \]
      8. lower-neg.f6497.8

        \[\leadsto \mathsf{fma}\left(3, y, \frac{\color{blue}{-z}}{x}\right) \cdot x \]
    7. Applied rewrites97.8%

      \[\leadsto \color{blue}{\mathsf{fma}\left(3, y, \frac{-z}{x}\right) \cdot x} \]
    8. Taylor expanded in x around inf

      \[\leadsto 3 \cdot \color{blue}{\left(x \cdot y\right)} \]
    9. Step-by-step derivation
      1. Applied rewrites79.1%

        \[\leadsto \left(x \cdot y\right) \cdot \color{blue}{3} \]
      2. Step-by-step derivation
        1. Applied rewrites79.2%

          \[\leadsto \left(x \cdot 3\right) \cdot y \]

        if -7.8e11 < (*.f64 (*.f64 x #s(literal 3 binary64)) y) < 7.5999999999999995e-57

        1. Initial program 100.0%

          \[\left(x \cdot 3\right) \cdot y - z \]
        2. Add Preprocessing
        3. Taylor expanded in x around 0

          \[\leadsto \color{blue}{-1 \cdot z} \]
        4. Step-by-step derivation
          1. mul-1-negN/A

            \[\leadsto \color{blue}{\mathsf{neg}\left(z\right)} \]
          2. lower-neg.f6487.7

            \[\leadsto \color{blue}{-z} \]
        5. Applied rewrites87.7%

          \[\leadsto \color{blue}{-z} \]
      3. Recombined 2 regimes into one program.
      4. Final simplification83.1%

        \[\leadsto \begin{array}{l} \mathbf{if}\;\left(x \cdot 3\right) \cdot y \leq -780000000000 \lor \neg \left(\left(x \cdot 3\right) \cdot y \leq 7.6 \cdot 10^{-57}\right):\\ \;\;\;\;\left(x \cdot 3\right) \cdot y\\ \mathbf{else}:\\ \;\;\;\;-z\\ \end{array} \]
      5. Add Preprocessing

      Alternative 3: 79.2% accurate, 0.3× speedup?

      \[\begin{array}{l} [x, y, z] = \mathsf{sort}([x, y, z])\\ \\ \begin{array}{l} t_0 := \left(x \cdot 3\right) \cdot y\\ \mathbf{if}\;t\_0 \leq -2000000000000:\\ \;\;\;\;\left(3 \cdot y\right) \cdot x\\ \mathbf{elif}\;t\_0 \leq 4 \cdot 10^{-57}:\\ \;\;\;\;-z\\ \mathbf{else}:\\ \;\;\;\;\left(x \cdot y\right) \cdot 3\\ \end{array} \end{array} \]
      NOTE: x, y, and z should be sorted in increasing order before calling this function.
      (FPCore (x y z)
       :precision binary64
       (let* ((t_0 (* (* x 3.0) y)))
         (if (<= t_0 -2000000000000.0)
           (* (* 3.0 y) x)
           (if (<= t_0 4e-57) (- z) (* (* x y) 3.0)))))
      assert(x < y && y < z);
      double code(double x, double y, double z) {
      	double t_0 = (x * 3.0) * y;
      	double tmp;
      	if (t_0 <= -2000000000000.0) {
      		tmp = (3.0 * y) * x;
      	} else if (t_0 <= 4e-57) {
      		tmp = -z;
      	} else {
      		tmp = (x * y) * 3.0;
      	}
      	return tmp;
      }
      
      NOTE: x, y, and z should be sorted in increasing order before calling this function.
      real(8) function code(x, y, z)
          real(8), intent (in) :: x
          real(8), intent (in) :: y
          real(8), intent (in) :: z
          real(8) :: t_0
          real(8) :: tmp
          t_0 = (x * 3.0d0) * y
          if (t_0 <= (-2000000000000.0d0)) then
              tmp = (3.0d0 * y) * x
          else if (t_0 <= 4d-57) then
              tmp = -z
          else
              tmp = (x * y) * 3.0d0
          end if
          code = tmp
      end function
      
      assert x < y && y < z;
      public static double code(double x, double y, double z) {
      	double t_0 = (x * 3.0) * y;
      	double tmp;
      	if (t_0 <= -2000000000000.0) {
      		tmp = (3.0 * y) * x;
      	} else if (t_0 <= 4e-57) {
      		tmp = -z;
      	} else {
      		tmp = (x * y) * 3.0;
      	}
      	return tmp;
      }
      
      [x, y, z] = sort([x, y, z])
      def code(x, y, z):
      	t_0 = (x * 3.0) * y
      	tmp = 0
      	if t_0 <= -2000000000000.0:
      		tmp = (3.0 * y) * x
      	elif t_0 <= 4e-57:
      		tmp = -z
      	else:
      		tmp = (x * y) * 3.0
      	return tmp
      
      x, y, z = sort([x, y, z])
      function code(x, y, z)
      	t_0 = Float64(Float64(x * 3.0) * y)
      	tmp = 0.0
      	if (t_0 <= -2000000000000.0)
      		tmp = Float64(Float64(3.0 * y) * x);
      	elseif (t_0 <= 4e-57)
      		tmp = Float64(-z);
      	else
      		tmp = Float64(Float64(x * y) * 3.0);
      	end
      	return tmp
      end
      
      x, y, z = num2cell(sort([x, y, z])){:}
      function tmp_2 = code(x, y, z)
      	t_0 = (x * 3.0) * y;
      	tmp = 0.0;
      	if (t_0 <= -2000000000000.0)
      		tmp = (3.0 * y) * x;
      	elseif (t_0 <= 4e-57)
      		tmp = -z;
      	else
      		tmp = (x * y) * 3.0;
      	end
      	tmp_2 = tmp;
      end
      
      NOTE: x, y, and z should be sorted in increasing order before calling this function.
      code[x_, y_, z_] := Block[{t$95$0 = N[(N[(x * 3.0), $MachinePrecision] * y), $MachinePrecision]}, If[LessEqual[t$95$0, -2000000000000.0], N[(N[(3.0 * y), $MachinePrecision] * x), $MachinePrecision], If[LessEqual[t$95$0, 4e-57], (-z), N[(N[(x * y), $MachinePrecision] * 3.0), $MachinePrecision]]]]
      
      \begin{array}{l}
      [x, y, z] = \mathsf{sort}([x, y, z])\\
      \\
      \begin{array}{l}
      t_0 := \left(x \cdot 3\right) \cdot y\\
      \mathbf{if}\;t\_0 \leq -2000000000000:\\
      \;\;\;\;\left(3 \cdot y\right) \cdot x\\
      
      \mathbf{elif}\;t\_0 \leq 4 \cdot 10^{-57}:\\
      \;\;\;\;-z\\
      
      \mathbf{else}:\\
      \;\;\;\;\left(x \cdot y\right) \cdot 3\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 3 regimes
      2. if (*.f64 (*.f64 x #s(literal 3 binary64)) y) < -2e12

        1. Initial program 99.8%

          \[\left(x \cdot 3\right) \cdot y - z \]
        2. Add Preprocessing
        3. Step-by-step derivation
          1. lift-*.f64N/A

            \[\leadsto \color{blue}{\left(x \cdot 3\right) \cdot y} - z \]
          2. lift-*.f64N/A

            \[\leadsto \color{blue}{\left(x \cdot 3\right)} \cdot y - z \]
          3. associate-*l*N/A

            \[\leadsto \color{blue}{x \cdot \left(3 \cdot y\right)} - z \]
          4. *-commutativeN/A

            \[\leadsto \color{blue}{\left(3 \cdot y\right) \cdot x} - z \]
          5. lower-*.f64N/A

            \[\leadsto \color{blue}{\left(3 \cdot y\right) \cdot x} - z \]
          6. *-commutativeN/A

            \[\leadsto \color{blue}{\left(y \cdot 3\right)} \cdot x - z \]
          7. lower-*.f6499.8

            \[\leadsto \color{blue}{\left(y \cdot 3\right)} \cdot x - z \]
        4. Applied rewrites99.8%

          \[\leadsto \color{blue}{\left(y \cdot 3\right) \cdot x} - z \]
        5. Taylor expanded in x around inf

          \[\leadsto \color{blue}{x \cdot \left(-1 \cdot \frac{z}{x} + 3 \cdot y\right)} \]
        6. Step-by-step derivation
          1. *-commutativeN/A

            \[\leadsto \color{blue}{\left(-1 \cdot \frac{z}{x} + 3 \cdot y\right) \cdot x} \]
          2. lower-*.f64N/A

            \[\leadsto \color{blue}{\left(-1 \cdot \frac{z}{x} + 3 \cdot y\right) \cdot x} \]
          3. +-commutativeN/A

            \[\leadsto \color{blue}{\left(3 \cdot y + -1 \cdot \frac{z}{x}\right)} \cdot x \]
          4. lower-fma.f64N/A

            \[\leadsto \color{blue}{\mathsf{fma}\left(3, y, -1 \cdot \frac{z}{x}\right)} \cdot x \]
          5. associate-*r/N/A

            \[\leadsto \mathsf{fma}\left(3, y, \color{blue}{\frac{-1 \cdot z}{x}}\right) \cdot x \]
          6. lower-/.f64N/A

            \[\leadsto \mathsf{fma}\left(3, y, \color{blue}{\frac{-1 \cdot z}{x}}\right) \cdot x \]
          7. mul-1-negN/A

            \[\leadsto \mathsf{fma}\left(3, y, \frac{\color{blue}{\mathsf{neg}\left(z\right)}}{x}\right) \cdot x \]
          8. lower-neg.f6499.9

            \[\leadsto \mathsf{fma}\left(3, y, \frac{\color{blue}{-z}}{x}\right) \cdot x \]
        7. Applied rewrites99.9%

          \[\leadsto \color{blue}{\mathsf{fma}\left(3, y, \frac{-z}{x}\right) \cdot x} \]
        8. Taylor expanded in x around inf

          \[\leadsto \left(3 \cdot y\right) \cdot x \]
        9. Step-by-step derivation
          1. Applied rewrites82.2%

            \[\leadsto \left(3 \cdot y\right) \cdot x \]

          if -2e12 < (*.f64 (*.f64 x #s(literal 3 binary64)) y) < 3.99999999999999982e-57

          1. Initial program 100.0%

            \[\left(x \cdot 3\right) \cdot y - z \]
          2. Add Preprocessing
          3. Taylor expanded in x around 0

            \[\leadsto \color{blue}{-1 \cdot z} \]
          4. Step-by-step derivation
            1. mul-1-negN/A

              \[\leadsto \color{blue}{\mathsf{neg}\left(z\right)} \]
            2. lower-neg.f6487.7

              \[\leadsto \color{blue}{-z} \]
          5. Applied rewrites87.7%

            \[\leadsto \color{blue}{-z} \]

          if 3.99999999999999982e-57 < (*.f64 (*.f64 x #s(literal 3 binary64)) y)

          1. Initial program 99.7%

            \[\left(x \cdot 3\right) \cdot y - z \]
          2. Add Preprocessing
          3. Step-by-step derivation
            1. lift-*.f64N/A

              \[\leadsto \color{blue}{\left(x \cdot 3\right) \cdot y} - z \]
            2. lift-*.f64N/A

              \[\leadsto \color{blue}{\left(x \cdot 3\right)} \cdot y - z \]
            3. associate-*l*N/A

              \[\leadsto \color{blue}{x \cdot \left(3 \cdot y\right)} - z \]
            4. *-commutativeN/A

              \[\leadsto \color{blue}{\left(3 \cdot y\right) \cdot x} - z \]
            5. lower-*.f64N/A

              \[\leadsto \color{blue}{\left(3 \cdot y\right) \cdot x} - z \]
            6. *-commutativeN/A

              \[\leadsto \color{blue}{\left(y \cdot 3\right)} \cdot x - z \]
            7. lower-*.f6499.7

              \[\leadsto \color{blue}{\left(y \cdot 3\right)} \cdot x - z \]
          4. Applied rewrites99.7%

            \[\leadsto \color{blue}{\left(y \cdot 3\right) \cdot x} - z \]
          5. Taylor expanded in x around inf

            \[\leadsto \color{blue}{x \cdot \left(-1 \cdot \frac{z}{x} + 3 \cdot y\right)} \]
          6. Step-by-step derivation
            1. *-commutativeN/A

              \[\leadsto \color{blue}{\left(-1 \cdot \frac{z}{x} + 3 \cdot y\right) \cdot x} \]
            2. lower-*.f64N/A

              \[\leadsto \color{blue}{\left(-1 \cdot \frac{z}{x} + 3 \cdot y\right) \cdot x} \]
            3. +-commutativeN/A

              \[\leadsto \color{blue}{\left(3 \cdot y + -1 \cdot \frac{z}{x}\right)} \cdot x \]
            4. lower-fma.f64N/A

              \[\leadsto \color{blue}{\mathsf{fma}\left(3, y, -1 \cdot \frac{z}{x}\right)} \cdot x \]
            5. associate-*r/N/A

              \[\leadsto \mathsf{fma}\left(3, y, \color{blue}{\frac{-1 \cdot z}{x}}\right) \cdot x \]
            6. lower-/.f64N/A

              \[\leadsto \mathsf{fma}\left(3, y, \color{blue}{\frac{-1 \cdot z}{x}}\right) \cdot x \]
            7. mul-1-negN/A

              \[\leadsto \mathsf{fma}\left(3, y, \frac{\color{blue}{\mathsf{neg}\left(z\right)}}{x}\right) \cdot x \]
            8. lower-neg.f6495.8

              \[\leadsto \mathsf{fma}\left(3, y, \frac{\color{blue}{-z}}{x}\right) \cdot x \]
          7. Applied rewrites95.8%

            \[\leadsto \color{blue}{\mathsf{fma}\left(3, y, \frac{-z}{x}\right) \cdot x} \]
          8. Taylor expanded in x around inf

            \[\leadsto 3 \cdot \color{blue}{\left(x \cdot y\right)} \]
          9. Step-by-step derivation
            1. Applied rewrites76.4%

              \[\leadsto \left(x \cdot y\right) \cdot \color{blue}{3} \]
          10. Recombined 3 regimes into one program.
          11. Final simplification83.1%

            \[\leadsto \begin{array}{l} \mathbf{if}\;\left(x \cdot 3\right) \cdot y \leq -2000000000000:\\ \;\;\;\;\left(3 \cdot y\right) \cdot x\\ \mathbf{elif}\;\left(x \cdot 3\right) \cdot y \leq 4 \cdot 10^{-57}:\\ \;\;\;\;-z\\ \mathbf{else}:\\ \;\;\;\;\left(x \cdot y\right) \cdot 3\\ \end{array} \]
          12. Add Preprocessing

          Alternative 4: 79.2% accurate, 0.3× speedup?

          \[\begin{array}{l} [x, y, z] = \mathsf{sort}([x, y, z])\\ \\ \begin{array}{l} t_0 := \left(x \cdot 3\right) \cdot y\\ \mathbf{if}\;t\_0 \leq -2000000000000:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;t\_0 \leq 4 \cdot 10^{-57}:\\ \;\;\;\;-z\\ \mathbf{else}:\\ \;\;\;\;\left(x \cdot y\right) \cdot 3\\ \end{array} \end{array} \]
          NOTE: x, y, and z should be sorted in increasing order before calling this function.
          (FPCore (x y z)
           :precision binary64
           (let* ((t_0 (* (* x 3.0) y)))
             (if (<= t_0 -2000000000000.0)
               t_0
               (if (<= t_0 4e-57) (- z) (* (* x y) 3.0)))))
          assert(x < y && y < z);
          double code(double x, double y, double z) {
          	double t_0 = (x * 3.0) * y;
          	double tmp;
          	if (t_0 <= -2000000000000.0) {
          		tmp = t_0;
          	} else if (t_0 <= 4e-57) {
          		tmp = -z;
          	} else {
          		tmp = (x * y) * 3.0;
          	}
          	return tmp;
          }
          
          NOTE: x, y, and z should be sorted in increasing order before calling this function.
          real(8) function code(x, y, z)
              real(8), intent (in) :: x
              real(8), intent (in) :: y
              real(8), intent (in) :: z
              real(8) :: t_0
              real(8) :: tmp
              t_0 = (x * 3.0d0) * y
              if (t_0 <= (-2000000000000.0d0)) then
                  tmp = t_0
              else if (t_0 <= 4d-57) then
                  tmp = -z
              else
                  tmp = (x * y) * 3.0d0
              end if
              code = tmp
          end function
          
          assert x < y && y < z;
          public static double code(double x, double y, double z) {
          	double t_0 = (x * 3.0) * y;
          	double tmp;
          	if (t_0 <= -2000000000000.0) {
          		tmp = t_0;
          	} else if (t_0 <= 4e-57) {
          		tmp = -z;
          	} else {
          		tmp = (x * y) * 3.0;
          	}
          	return tmp;
          }
          
          [x, y, z] = sort([x, y, z])
          def code(x, y, z):
          	t_0 = (x * 3.0) * y
          	tmp = 0
          	if t_0 <= -2000000000000.0:
          		tmp = t_0
          	elif t_0 <= 4e-57:
          		tmp = -z
          	else:
          		tmp = (x * y) * 3.0
          	return tmp
          
          x, y, z = sort([x, y, z])
          function code(x, y, z)
          	t_0 = Float64(Float64(x * 3.0) * y)
          	tmp = 0.0
          	if (t_0 <= -2000000000000.0)
          		tmp = t_0;
          	elseif (t_0 <= 4e-57)
          		tmp = Float64(-z);
          	else
          		tmp = Float64(Float64(x * y) * 3.0);
          	end
          	return tmp
          end
          
          x, y, z = num2cell(sort([x, y, z])){:}
          function tmp_2 = code(x, y, z)
          	t_0 = (x * 3.0) * y;
          	tmp = 0.0;
          	if (t_0 <= -2000000000000.0)
          		tmp = t_0;
          	elseif (t_0 <= 4e-57)
          		tmp = -z;
          	else
          		tmp = (x * y) * 3.0;
          	end
          	tmp_2 = tmp;
          end
          
          NOTE: x, y, and z should be sorted in increasing order before calling this function.
          code[x_, y_, z_] := Block[{t$95$0 = N[(N[(x * 3.0), $MachinePrecision] * y), $MachinePrecision]}, If[LessEqual[t$95$0, -2000000000000.0], t$95$0, If[LessEqual[t$95$0, 4e-57], (-z), N[(N[(x * y), $MachinePrecision] * 3.0), $MachinePrecision]]]]
          
          \begin{array}{l}
          [x, y, z] = \mathsf{sort}([x, y, z])\\
          \\
          \begin{array}{l}
          t_0 := \left(x \cdot 3\right) \cdot y\\
          \mathbf{if}\;t\_0 \leq -2000000000000:\\
          \;\;\;\;t\_0\\
          
          \mathbf{elif}\;t\_0 \leq 4 \cdot 10^{-57}:\\
          \;\;\;\;-z\\
          
          \mathbf{else}:\\
          \;\;\;\;\left(x \cdot y\right) \cdot 3\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 3 regimes
          2. if (*.f64 (*.f64 x #s(literal 3 binary64)) y) < -2e12

            1. Initial program 99.8%

              \[\left(x \cdot 3\right) \cdot y - z \]
            2. Add Preprocessing
            3. Step-by-step derivation
              1. lift-*.f64N/A

                \[\leadsto \color{blue}{\left(x \cdot 3\right) \cdot y} - z \]
              2. lift-*.f64N/A

                \[\leadsto \color{blue}{\left(x \cdot 3\right)} \cdot y - z \]
              3. associate-*l*N/A

                \[\leadsto \color{blue}{x \cdot \left(3 \cdot y\right)} - z \]
              4. *-commutativeN/A

                \[\leadsto \color{blue}{\left(3 \cdot y\right) \cdot x} - z \]
              5. lower-*.f64N/A

                \[\leadsto \color{blue}{\left(3 \cdot y\right) \cdot x} - z \]
              6. *-commutativeN/A

                \[\leadsto \color{blue}{\left(y \cdot 3\right)} \cdot x - z \]
              7. lower-*.f6499.8

                \[\leadsto \color{blue}{\left(y \cdot 3\right)} \cdot x - z \]
            4. Applied rewrites99.8%

              \[\leadsto \color{blue}{\left(y \cdot 3\right) \cdot x} - z \]
            5. Taylor expanded in x around inf

              \[\leadsto \color{blue}{x \cdot \left(-1 \cdot \frac{z}{x} + 3 \cdot y\right)} \]
            6. Step-by-step derivation
              1. *-commutativeN/A

                \[\leadsto \color{blue}{\left(-1 \cdot \frac{z}{x} + 3 \cdot y\right) \cdot x} \]
              2. lower-*.f64N/A

                \[\leadsto \color{blue}{\left(-1 \cdot \frac{z}{x} + 3 \cdot y\right) \cdot x} \]
              3. +-commutativeN/A

                \[\leadsto \color{blue}{\left(3 \cdot y + -1 \cdot \frac{z}{x}\right)} \cdot x \]
              4. lower-fma.f64N/A

                \[\leadsto \color{blue}{\mathsf{fma}\left(3, y, -1 \cdot \frac{z}{x}\right)} \cdot x \]
              5. associate-*r/N/A

                \[\leadsto \mathsf{fma}\left(3, y, \color{blue}{\frac{-1 \cdot z}{x}}\right) \cdot x \]
              6. lower-/.f64N/A

                \[\leadsto \mathsf{fma}\left(3, y, \color{blue}{\frac{-1 \cdot z}{x}}\right) \cdot x \]
              7. mul-1-negN/A

                \[\leadsto \mathsf{fma}\left(3, y, \frac{\color{blue}{\mathsf{neg}\left(z\right)}}{x}\right) \cdot x \]
              8. lower-neg.f6499.9

                \[\leadsto \mathsf{fma}\left(3, y, \frac{\color{blue}{-z}}{x}\right) \cdot x \]
            7. Applied rewrites99.9%

              \[\leadsto \color{blue}{\mathsf{fma}\left(3, y, \frac{-z}{x}\right) \cdot x} \]
            8. Taylor expanded in x around inf

              \[\leadsto 3 \cdot \color{blue}{\left(x \cdot y\right)} \]
            9. Step-by-step derivation
              1. Applied rewrites82.1%

                \[\leadsto \left(x \cdot y\right) \cdot \color{blue}{3} \]
              2. Step-by-step derivation
                1. Applied rewrites82.2%

                  \[\leadsto \left(x \cdot 3\right) \cdot y \]

                if -2e12 < (*.f64 (*.f64 x #s(literal 3 binary64)) y) < 3.99999999999999982e-57

                1. Initial program 100.0%

                  \[\left(x \cdot 3\right) \cdot y - z \]
                2. Add Preprocessing
                3. Taylor expanded in x around 0

                  \[\leadsto \color{blue}{-1 \cdot z} \]
                4. Step-by-step derivation
                  1. mul-1-negN/A

                    \[\leadsto \color{blue}{\mathsf{neg}\left(z\right)} \]
                  2. lower-neg.f6487.7

                    \[\leadsto \color{blue}{-z} \]
                5. Applied rewrites87.7%

                  \[\leadsto \color{blue}{-z} \]

                if 3.99999999999999982e-57 < (*.f64 (*.f64 x #s(literal 3 binary64)) y)

                1. Initial program 99.7%

                  \[\left(x \cdot 3\right) \cdot y - z \]
                2. Add Preprocessing
                3. Step-by-step derivation
                  1. lift-*.f64N/A

                    \[\leadsto \color{blue}{\left(x \cdot 3\right) \cdot y} - z \]
                  2. lift-*.f64N/A

                    \[\leadsto \color{blue}{\left(x \cdot 3\right)} \cdot y - z \]
                  3. associate-*l*N/A

                    \[\leadsto \color{blue}{x \cdot \left(3 \cdot y\right)} - z \]
                  4. *-commutativeN/A

                    \[\leadsto \color{blue}{\left(3 \cdot y\right) \cdot x} - z \]
                  5. lower-*.f64N/A

                    \[\leadsto \color{blue}{\left(3 \cdot y\right) \cdot x} - z \]
                  6. *-commutativeN/A

                    \[\leadsto \color{blue}{\left(y \cdot 3\right)} \cdot x - z \]
                  7. lower-*.f6499.7

                    \[\leadsto \color{blue}{\left(y \cdot 3\right)} \cdot x - z \]
                4. Applied rewrites99.7%

                  \[\leadsto \color{blue}{\left(y \cdot 3\right) \cdot x} - z \]
                5. Taylor expanded in x around inf

                  \[\leadsto \color{blue}{x \cdot \left(-1 \cdot \frac{z}{x} + 3 \cdot y\right)} \]
                6. Step-by-step derivation
                  1. *-commutativeN/A

                    \[\leadsto \color{blue}{\left(-1 \cdot \frac{z}{x} + 3 \cdot y\right) \cdot x} \]
                  2. lower-*.f64N/A

                    \[\leadsto \color{blue}{\left(-1 \cdot \frac{z}{x} + 3 \cdot y\right) \cdot x} \]
                  3. +-commutativeN/A

                    \[\leadsto \color{blue}{\left(3 \cdot y + -1 \cdot \frac{z}{x}\right)} \cdot x \]
                  4. lower-fma.f64N/A

                    \[\leadsto \color{blue}{\mathsf{fma}\left(3, y, -1 \cdot \frac{z}{x}\right)} \cdot x \]
                  5. associate-*r/N/A

                    \[\leadsto \mathsf{fma}\left(3, y, \color{blue}{\frac{-1 \cdot z}{x}}\right) \cdot x \]
                  6. lower-/.f64N/A

                    \[\leadsto \mathsf{fma}\left(3, y, \color{blue}{\frac{-1 \cdot z}{x}}\right) \cdot x \]
                  7. mul-1-negN/A

                    \[\leadsto \mathsf{fma}\left(3, y, \frac{\color{blue}{\mathsf{neg}\left(z\right)}}{x}\right) \cdot x \]
                  8. lower-neg.f6495.8

                    \[\leadsto \mathsf{fma}\left(3, y, \frac{\color{blue}{-z}}{x}\right) \cdot x \]
                7. Applied rewrites95.8%

                  \[\leadsto \color{blue}{\mathsf{fma}\left(3, y, \frac{-z}{x}\right) \cdot x} \]
                8. Taylor expanded in x around inf

                  \[\leadsto 3 \cdot \color{blue}{\left(x \cdot y\right)} \]
                9. Step-by-step derivation
                  1. Applied rewrites76.4%

                    \[\leadsto \left(x \cdot y\right) \cdot \color{blue}{3} \]
                10. Recombined 3 regimes into one program.
                11. Final simplification83.1%

                  \[\leadsto \begin{array}{l} \mathbf{if}\;\left(x \cdot 3\right) \cdot y \leq -2000000000000:\\ \;\;\;\;\left(x \cdot 3\right) \cdot y\\ \mathbf{elif}\;\left(x \cdot 3\right) \cdot y \leq 4 \cdot 10^{-57}:\\ \;\;\;\;-z\\ \mathbf{else}:\\ \;\;\;\;\left(x \cdot y\right) \cdot 3\\ \end{array} \]
                12. Add Preprocessing

                Alternative 5: 99.8% accurate, 1.0× speedup?

                \[\begin{array}{l} [x, y, z] = \mathsf{sort}([x, y, z])\\ \\ \left(x \cdot 3\right) \cdot y - z \end{array} \]
                NOTE: x, y, and z should be sorted in increasing order before calling this function.
                (FPCore (x y z) :precision binary64 (- (* (* x 3.0) y) z))
                assert(x < y && y < z);
                double code(double x, double y, double z) {
                	return ((x * 3.0) * y) - z;
                }
                
                NOTE: x, y, and z should be sorted in increasing order before calling this function.
                real(8) function code(x, y, z)
                    real(8), intent (in) :: x
                    real(8), intent (in) :: y
                    real(8), intent (in) :: z
                    code = ((x * 3.0d0) * y) - z
                end function
                
                assert x < y && y < z;
                public static double code(double x, double y, double z) {
                	return ((x * 3.0) * y) - z;
                }
                
                [x, y, z] = sort([x, y, z])
                def code(x, y, z):
                	return ((x * 3.0) * y) - z
                
                x, y, z = sort([x, y, z])
                function code(x, y, z)
                	return Float64(Float64(Float64(x * 3.0) * y) - z)
                end
                
                x, y, z = num2cell(sort([x, y, z])){:}
                function tmp = code(x, y, z)
                	tmp = ((x * 3.0) * y) - z;
                end
                
                NOTE: x, y, and z should be sorted in increasing order before calling this function.
                code[x_, y_, z_] := N[(N[(N[(x * 3.0), $MachinePrecision] * y), $MachinePrecision] - z), $MachinePrecision]
                
                \begin{array}{l}
                [x, y, z] = \mathsf{sort}([x, y, z])\\
                \\
                \left(x \cdot 3\right) \cdot y - z
                \end{array}
                
                Derivation
                1. Initial program 99.8%

                  \[\left(x \cdot 3\right) \cdot y - z \]
                2. Add Preprocessing
                3. Add Preprocessing

                Alternative 6: 51.6% accurate, 4.7× speedup?

                \[\begin{array}{l} [x, y, z] = \mathsf{sort}([x, y, z])\\ \\ -z \end{array} \]
                NOTE: x, y, and z should be sorted in increasing order before calling this function.
                (FPCore (x y z) :precision binary64 (- z))
                assert(x < y && y < z);
                double code(double x, double y, double z) {
                	return -z;
                }
                
                NOTE: x, y, and z should be sorted in increasing order before calling this function.
                real(8) function code(x, y, z)
                    real(8), intent (in) :: x
                    real(8), intent (in) :: y
                    real(8), intent (in) :: z
                    code = -z
                end function
                
                assert x < y && y < z;
                public static double code(double x, double y, double z) {
                	return -z;
                }
                
                [x, y, z] = sort([x, y, z])
                def code(x, y, z):
                	return -z
                
                x, y, z = sort([x, y, z])
                function code(x, y, z)
                	return Float64(-z)
                end
                
                x, y, z = num2cell(sort([x, y, z])){:}
                function tmp = code(x, y, z)
                	tmp = -z;
                end
                
                NOTE: x, y, and z should be sorted in increasing order before calling this function.
                code[x_, y_, z_] := (-z)
                
                \begin{array}{l}
                [x, y, z] = \mathsf{sort}([x, y, z])\\
                \\
                -z
                \end{array}
                
                Derivation
                1. Initial program 99.8%

                  \[\left(x \cdot 3\right) \cdot y - z \]
                2. Add Preprocessing
                3. Taylor expanded in x around 0

                  \[\leadsto \color{blue}{-1 \cdot z} \]
                4. Step-by-step derivation
                  1. mul-1-negN/A

                    \[\leadsto \color{blue}{\mathsf{neg}\left(z\right)} \]
                  2. lower-neg.f6452.6

                    \[\leadsto \color{blue}{-z} \]
                5. Applied rewrites52.6%

                  \[\leadsto \color{blue}{-z} \]
                6. Final simplification52.6%

                  \[\leadsto -z \]
                7. Add Preprocessing

                Developer Target 1: 99.8% accurate, 1.0× speedup?

                \[\begin{array}{l} \\ x \cdot \left(3 \cdot y\right) - z \end{array} \]
                (FPCore (x y z) :precision binary64 (- (* x (* 3.0 y)) z))
                double code(double x, double y, double z) {
                	return (x * (3.0 * y)) - z;
                }
                
                real(8) function code(x, y, z)
                    real(8), intent (in) :: x
                    real(8), intent (in) :: y
                    real(8), intent (in) :: z
                    code = (x * (3.0d0 * y)) - z
                end function
                
                public static double code(double x, double y, double z) {
                	return (x * (3.0 * y)) - z;
                }
                
                def code(x, y, z):
                	return (x * (3.0 * y)) - z
                
                function code(x, y, z)
                	return Float64(Float64(x * Float64(3.0 * y)) - z)
                end
                
                function tmp = code(x, y, z)
                	tmp = (x * (3.0 * y)) - z;
                end
                
                code[x_, y_, z_] := N[(N[(x * N[(3.0 * y), $MachinePrecision]), $MachinePrecision] - z), $MachinePrecision]
                
                \begin{array}{l}
                
                \\
                x \cdot \left(3 \cdot y\right) - z
                \end{array}
                

                Reproduce

                ?
                herbie shell --seed 2024324 
                (FPCore (x y z)
                  :name "Diagrams.Solve.Polynomial:cubForm  from diagrams-solve-0.1, B"
                  :precision binary64
                
                  :alt
                  (! :herbie-platform default (- (* x (* 3 y)) z))
                
                  (- (* (* x 3.0) y) z))