symmetry log of sum of exp

Percentage Accurate: 53.1% → 99.0%
Time: 9.9s
Alternatives: 11
Speedup: 0.7×

Specification

?
\[\begin{array}{l} \\ \log \left(e^{a} + e^{b}\right) \end{array} \]
(FPCore (a b) :precision binary64 (log (+ (exp a) (exp b))))
double code(double a, double b) {
	return log((exp(a) + exp(b)));
}
real(8) function code(a, b)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    code = log((exp(a) + exp(b)))
end function
public static double code(double a, double b) {
	return Math.log((Math.exp(a) + Math.exp(b)));
}
def code(a, b):
	return math.log((math.exp(a) + math.exp(b)))
function code(a, b)
	return log(Float64(exp(a) + exp(b)))
end
function tmp = code(a, b)
	tmp = log((exp(a) + exp(b)));
end
code[a_, b_] := N[Log[N[(N[Exp[a], $MachinePrecision] + N[Exp[b], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\log \left(e^{a} + e^{b}\right)
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 11 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 53.1% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \log \left(e^{a} + e^{b}\right) \end{array} \]
(FPCore (a b) :precision binary64 (log (+ (exp a) (exp b))))
double code(double a, double b) {
	return log((exp(a) + exp(b)));
}
real(8) function code(a, b)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    code = log((exp(a) + exp(b)))
end function
public static double code(double a, double b) {
	return Math.log((Math.exp(a) + Math.exp(b)));
}
def code(a, b):
	return math.log((math.exp(a) + math.exp(b)))
function code(a, b)
	return log(Float64(exp(a) + exp(b)))
end
function tmp = code(a, b)
	tmp = log((exp(a) + exp(b)));
end
code[a_, b_] := N[Log[N[(N[Exp[a], $MachinePrecision] + N[Exp[b], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\log \left(e^{a} + e^{b}\right)
\end{array}

Alternative 1: 99.0% accurate, 0.7× speedup?

\[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \begin{array}{l} \mathbf{if}\;e^{a} \leq 0.9999999999999991:\\ \;\;\;\;\frac{b}{e^{a} + 1} + \mathsf{log1p}\left(e^{a}\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{log1p}\left(e^{b}\right)\\ \end{array} \end{array} \]
NOTE: a and b should be sorted in increasing order before calling this function.
(FPCore (a b)
 :precision binary64
 (if (<= (exp a) 0.9999999999999991)
   (+ (/ b (+ (exp a) 1.0)) (log1p (exp a)))
   (log1p (exp b))))
assert(a < b);
double code(double a, double b) {
	double tmp;
	if (exp(a) <= 0.9999999999999991) {
		tmp = (b / (exp(a) + 1.0)) + log1p(exp(a));
	} else {
		tmp = log1p(exp(b));
	}
	return tmp;
}
assert a < b;
public static double code(double a, double b) {
	double tmp;
	if (Math.exp(a) <= 0.9999999999999991) {
		tmp = (b / (Math.exp(a) + 1.0)) + Math.log1p(Math.exp(a));
	} else {
		tmp = Math.log1p(Math.exp(b));
	}
	return tmp;
}
[a, b] = sort([a, b])
def code(a, b):
	tmp = 0
	if math.exp(a) <= 0.9999999999999991:
		tmp = (b / (math.exp(a) + 1.0)) + math.log1p(math.exp(a))
	else:
		tmp = math.log1p(math.exp(b))
	return tmp
a, b = sort([a, b])
function code(a, b)
	tmp = 0.0
	if (exp(a) <= 0.9999999999999991)
		tmp = Float64(Float64(b / Float64(exp(a) + 1.0)) + log1p(exp(a)));
	else
		tmp = log1p(exp(b));
	end
	return tmp
end
NOTE: a and b should be sorted in increasing order before calling this function.
code[a_, b_] := If[LessEqual[N[Exp[a], $MachinePrecision], 0.9999999999999991], N[(N[(b / N[(N[Exp[a], $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision] + N[Log[1 + N[Exp[a], $MachinePrecision]], $MachinePrecision]), $MachinePrecision], N[Log[1 + N[Exp[b], $MachinePrecision]], $MachinePrecision]]
\begin{array}{l}
[a, b] = \mathsf{sort}([a, b])\\
\\
\begin{array}{l}
\mathbf{if}\;e^{a} \leq 0.9999999999999991:\\
\;\;\;\;\frac{b}{e^{a} + 1} + \mathsf{log1p}\left(e^{a}\right)\\

\mathbf{else}:\\
\;\;\;\;\mathsf{log1p}\left(e^{b}\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (exp.f64 a) < 0.99999999999999911

    1. Initial program 9.0%

      \[\log \left(e^{a} + e^{b}\right) \]
    2. Add Preprocessing
    3. Taylor expanded in b around 0

      \[\leadsto \color{blue}{\log \left(1 + e^{a}\right) + \frac{b}{1 + e^{a}}} \]
    4. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto \color{blue}{\frac{b}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
      2. *-rgt-identityN/A

        \[\leadsto \frac{\color{blue}{b \cdot 1}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
      3. associate-*r/N/A

        \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
      4. lower-+.f64N/A

        \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
      5. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{b \cdot 1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
      6. *-rgt-identityN/A

        \[\leadsto \frac{\color{blue}{b}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
      7. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{b}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
      8. +-commutativeN/A

        \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
      9. lower-+.f64N/A

        \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
      10. lower-exp.f64N/A

        \[\leadsto \frac{b}{\color{blue}{e^{a}} + 1} + \log \left(1 + e^{a}\right) \]
      11. lower-log1p.f64N/A

        \[\leadsto \frac{b}{e^{a} + 1} + \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
      12. lower-exp.f6498.8

        \[\leadsto \frac{b}{e^{a} + 1} + \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]
    5. Applied rewrites98.8%

      \[\leadsto \color{blue}{\frac{b}{e^{a} + 1} + \mathsf{log1p}\left(e^{a}\right)} \]

    if 0.99999999999999911 < (exp.f64 a)

    1. Initial program 69.9%

      \[\log \left(e^{a} + e^{b}\right) \]
    2. Add Preprocessing
    3. Taylor expanded in a around 0

      \[\leadsto \color{blue}{\log \left(1 + e^{b}\right)} \]
    4. Step-by-step derivation
      1. lower-log1p.f64N/A

        \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{b}\right)} \]
      2. lower-exp.f6466.3

        \[\leadsto \mathsf{log1p}\left(\color{blue}{e^{b}}\right) \]
    5. Applied rewrites66.3%

      \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{b}\right)} \]
  3. Recombined 2 regimes into one program.
  4. Add Preprocessing

Alternative 2: 58.1% accurate, 0.7× speedup?

\[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \begin{array}{l} \mathbf{if}\;e^{a} + e^{b} \leq 1.9999999999999991:\\ \;\;\;\;0.5 \cdot b + \mathsf{log1p}\left(e^{a}\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{log1p}\left(e^{b}\right)\\ \end{array} \end{array} \]
NOTE: a and b should be sorted in increasing order before calling this function.
(FPCore (a b)
 :precision binary64
 (if (<= (+ (exp a) (exp b)) 1.9999999999999991)
   (+ (* 0.5 b) (log1p (exp a)))
   (log1p (exp b))))
assert(a < b);
double code(double a, double b) {
	double tmp;
	if ((exp(a) + exp(b)) <= 1.9999999999999991) {
		tmp = (0.5 * b) + log1p(exp(a));
	} else {
		tmp = log1p(exp(b));
	}
	return tmp;
}
assert a < b;
public static double code(double a, double b) {
	double tmp;
	if ((Math.exp(a) + Math.exp(b)) <= 1.9999999999999991) {
		tmp = (0.5 * b) + Math.log1p(Math.exp(a));
	} else {
		tmp = Math.log1p(Math.exp(b));
	}
	return tmp;
}
[a, b] = sort([a, b])
def code(a, b):
	tmp = 0
	if (math.exp(a) + math.exp(b)) <= 1.9999999999999991:
		tmp = (0.5 * b) + math.log1p(math.exp(a))
	else:
		tmp = math.log1p(math.exp(b))
	return tmp
a, b = sort([a, b])
function code(a, b)
	tmp = 0.0
	if (Float64(exp(a) + exp(b)) <= 1.9999999999999991)
		tmp = Float64(Float64(0.5 * b) + log1p(exp(a)));
	else
		tmp = log1p(exp(b));
	end
	return tmp
end
NOTE: a and b should be sorted in increasing order before calling this function.
code[a_, b_] := If[LessEqual[N[(N[Exp[a], $MachinePrecision] + N[Exp[b], $MachinePrecision]), $MachinePrecision], 1.9999999999999991], N[(N[(0.5 * b), $MachinePrecision] + N[Log[1 + N[Exp[a], $MachinePrecision]], $MachinePrecision]), $MachinePrecision], N[Log[1 + N[Exp[b], $MachinePrecision]], $MachinePrecision]]
\begin{array}{l}
[a, b] = \mathsf{sort}([a, b])\\
\\
\begin{array}{l}
\mathbf{if}\;e^{a} + e^{b} \leq 1.9999999999999991:\\
\;\;\;\;0.5 \cdot b + \mathsf{log1p}\left(e^{a}\right)\\

\mathbf{else}:\\
\;\;\;\;\mathsf{log1p}\left(e^{b}\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (+.f64 (exp.f64 a) (exp.f64 b)) < 1.9999999999999991

    1. Initial program 9.5%

      \[\log \left(e^{a} + e^{b}\right) \]
    2. Add Preprocessing
    3. Taylor expanded in b around 0

      \[\leadsto \color{blue}{\log \left(1 + e^{a}\right) + \frac{b}{1 + e^{a}}} \]
    4. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto \color{blue}{\frac{b}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
      2. *-rgt-identityN/A

        \[\leadsto \frac{\color{blue}{b \cdot 1}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
      3. associate-*r/N/A

        \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
      4. lower-+.f64N/A

        \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
      5. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{b \cdot 1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
      6. *-rgt-identityN/A

        \[\leadsto \frac{\color{blue}{b}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
      7. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{b}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
      8. +-commutativeN/A

        \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
      9. lower-+.f64N/A

        \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
      10. lower-exp.f64N/A

        \[\leadsto \frac{b}{\color{blue}{e^{a}} + 1} + \log \left(1 + e^{a}\right) \]
      11. lower-log1p.f64N/A

        \[\leadsto \frac{b}{e^{a} + 1} + \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
      12. lower-exp.f6459.6

        \[\leadsto \frac{b}{e^{a} + 1} + \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]
    5. Applied rewrites59.6%

      \[\leadsto \color{blue}{\frac{b}{e^{a} + 1} + \mathsf{log1p}\left(e^{a}\right)} \]
    6. Taylor expanded in a around 0

      \[\leadsto \frac{1}{2} \cdot b + \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]
    7. Step-by-step derivation
      1. Applied rewrites13.7%

        \[\leadsto 0.5 \cdot b + \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]

      if 1.9999999999999991 < (+.f64 (exp.f64 a) (exp.f64 b))

      1. Initial program 98.3%

        \[\log \left(e^{a} + e^{b}\right) \]
      2. Add Preprocessing
      3. Taylor expanded in a around 0

        \[\leadsto \color{blue}{\log \left(1 + e^{b}\right)} \]
      4. Step-by-step derivation
        1. lower-log1p.f64N/A

          \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{b}\right)} \]
        2. lower-exp.f6493.4

          \[\leadsto \mathsf{log1p}\left(\color{blue}{e^{b}}\right) \]
      5. Applied rewrites93.4%

        \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{b}\right)} \]
    8. Recombined 2 regimes into one program.
    9. Add Preprocessing

    Alternative 3: 52.2% accurate, 0.7× speedup?

    \[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \begin{array}{l} \mathbf{if}\;e^{a} + e^{b} \leq 1.9999999999999991:\\ \;\;\;\;\log \left(e^{a} + \left(1 + b\right)\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{log1p}\left(e^{b}\right)\\ \end{array} \end{array} \]
    NOTE: a and b should be sorted in increasing order before calling this function.
    (FPCore (a b)
     :precision binary64
     (if (<= (+ (exp a) (exp b)) 1.9999999999999991)
       (log (+ (exp a) (+ 1.0 b)))
       (log1p (exp b))))
    assert(a < b);
    double code(double a, double b) {
    	double tmp;
    	if ((exp(a) + exp(b)) <= 1.9999999999999991) {
    		tmp = log((exp(a) + (1.0 + b)));
    	} else {
    		tmp = log1p(exp(b));
    	}
    	return tmp;
    }
    
    assert a < b;
    public static double code(double a, double b) {
    	double tmp;
    	if ((Math.exp(a) + Math.exp(b)) <= 1.9999999999999991) {
    		tmp = Math.log((Math.exp(a) + (1.0 + b)));
    	} else {
    		tmp = Math.log1p(Math.exp(b));
    	}
    	return tmp;
    }
    
    [a, b] = sort([a, b])
    def code(a, b):
    	tmp = 0
    	if (math.exp(a) + math.exp(b)) <= 1.9999999999999991:
    		tmp = math.log((math.exp(a) + (1.0 + b)))
    	else:
    		tmp = math.log1p(math.exp(b))
    	return tmp
    
    a, b = sort([a, b])
    function code(a, b)
    	tmp = 0.0
    	if (Float64(exp(a) + exp(b)) <= 1.9999999999999991)
    		tmp = log(Float64(exp(a) + Float64(1.0 + b)));
    	else
    		tmp = log1p(exp(b));
    	end
    	return tmp
    end
    
    NOTE: a and b should be sorted in increasing order before calling this function.
    code[a_, b_] := If[LessEqual[N[(N[Exp[a], $MachinePrecision] + N[Exp[b], $MachinePrecision]), $MachinePrecision], 1.9999999999999991], N[Log[N[(N[Exp[a], $MachinePrecision] + N[(1.0 + b), $MachinePrecision]), $MachinePrecision]], $MachinePrecision], N[Log[1 + N[Exp[b], $MachinePrecision]], $MachinePrecision]]
    
    \begin{array}{l}
    [a, b] = \mathsf{sort}([a, b])\\
    \\
    \begin{array}{l}
    \mathbf{if}\;e^{a} + e^{b} \leq 1.9999999999999991:\\
    \;\;\;\;\log \left(e^{a} + \left(1 + b\right)\right)\\
    
    \mathbf{else}:\\
    \;\;\;\;\mathsf{log1p}\left(e^{b}\right)\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 2 regimes
    2. if (+.f64 (exp.f64 a) (exp.f64 b)) < 1.9999999999999991

      1. Initial program 9.5%

        \[\log \left(e^{a} + e^{b}\right) \]
      2. Add Preprocessing
      3. Taylor expanded in b around 0

        \[\leadsto \log \left(e^{a} + \color{blue}{\left(1 + b\right)}\right) \]
      4. Step-by-step derivation
        1. lower-+.f645.5

          \[\leadsto \log \left(e^{a} + \color{blue}{\left(1 + b\right)}\right) \]
      5. Applied rewrites5.5%

        \[\leadsto \log \left(e^{a} + \color{blue}{\left(1 + b\right)}\right) \]

      if 1.9999999999999991 < (+.f64 (exp.f64 a) (exp.f64 b))

      1. Initial program 98.3%

        \[\log \left(e^{a} + e^{b}\right) \]
      2. Add Preprocessing
      3. Taylor expanded in a around 0

        \[\leadsto \color{blue}{\log \left(1 + e^{b}\right)} \]
      4. Step-by-step derivation
        1. lower-log1p.f64N/A

          \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{b}\right)} \]
        2. lower-exp.f6493.4

          \[\leadsto \mathsf{log1p}\left(\color{blue}{e^{b}}\right) \]
      5. Applied rewrites93.4%

        \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{b}\right)} \]
    3. Recombined 2 regimes into one program.
    4. Add Preprocessing

    Alternative 4: 58.7% accurate, 0.7× speedup?

    \[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \begin{array}{l} \mathbf{if}\;e^{b} \leq 1.00000000000002:\\ \;\;\;\;0.5 \cdot b + \mathsf{log1p}\left(e^{a}\right)\\ \mathbf{else}:\\ \;\;\;\;\log \left(e^{a} + e^{b}\right)\\ \end{array} \end{array} \]
    NOTE: a and b should be sorted in increasing order before calling this function.
    (FPCore (a b)
     :precision binary64
     (if (<= (exp b) 1.00000000000002)
       (+ (* 0.5 b) (log1p (exp a)))
       (log (+ (exp a) (exp b)))))
    assert(a < b);
    double code(double a, double b) {
    	double tmp;
    	if (exp(b) <= 1.00000000000002) {
    		tmp = (0.5 * b) + log1p(exp(a));
    	} else {
    		tmp = log((exp(a) + exp(b)));
    	}
    	return tmp;
    }
    
    assert a < b;
    public static double code(double a, double b) {
    	double tmp;
    	if (Math.exp(b) <= 1.00000000000002) {
    		tmp = (0.5 * b) + Math.log1p(Math.exp(a));
    	} else {
    		tmp = Math.log((Math.exp(a) + Math.exp(b)));
    	}
    	return tmp;
    }
    
    [a, b] = sort([a, b])
    def code(a, b):
    	tmp = 0
    	if math.exp(b) <= 1.00000000000002:
    		tmp = (0.5 * b) + math.log1p(math.exp(a))
    	else:
    		tmp = math.log((math.exp(a) + math.exp(b)))
    	return tmp
    
    a, b = sort([a, b])
    function code(a, b)
    	tmp = 0.0
    	if (exp(b) <= 1.00000000000002)
    		tmp = Float64(Float64(0.5 * b) + log1p(exp(a)));
    	else
    		tmp = log(Float64(exp(a) + exp(b)));
    	end
    	return tmp
    end
    
    NOTE: a and b should be sorted in increasing order before calling this function.
    code[a_, b_] := If[LessEqual[N[Exp[b], $MachinePrecision], 1.00000000000002], N[(N[(0.5 * b), $MachinePrecision] + N[Log[1 + N[Exp[a], $MachinePrecision]], $MachinePrecision]), $MachinePrecision], N[Log[N[(N[Exp[a], $MachinePrecision] + N[Exp[b], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]]
    
    \begin{array}{l}
    [a, b] = \mathsf{sort}([a, b])\\
    \\
    \begin{array}{l}
    \mathbf{if}\;e^{b} \leq 1.00000000000002:\\
    \;\;\;\;0.5 \cdot b + \mathsf{log1p}\left(e^{a}\right)\\
    
    \mathbf{else}:\\
    \;\;\;\;\log \left(e^{a} + e^{b}\right)\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 2 regimes
    2. if (exp.f64 b) < 1.00000000000002

      1. Initial program 49.5%

        \[\log \left(e^{a} + e^{b}\right) \]
      2. Add Preprocessing
      3. Taylor expanded in b around 0

        \[\leadsto \color{blue}{\log \left(1 + e^{a}\right) + \frac{b}{1 + e^{a}}} \]
      4. Step-by-step derivation
        1. +-commutativeN/A

          \[\leadsto \color{blue}{\frac{b}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
        2. *-rgt-identityN/A

          \[\leadsto \frac{\color{blue}{b \cdot 1}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
        3. associate-*r/N/A

          \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
        4. lower-+.f64N/A

          \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
        5. associate-*r/N/A

          \[\leadsto \color{blue}{\frac{b \cdot 1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
        6. *-rgt-identityN/A

          \[\leadsto \frac{\color{blue}{b}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
        7. lower-/.f64N/A

          \[\leadsto \color{blue}{\frac{b}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
        8. +-commutativeN/A

          \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
        9. lower-+.f64N/A

          \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
        10. lower-exp.f64N/A

          \[\leadsto \frac{b}{\color{blue}{e^{a}} + 1} + \log \left(1 + e^{a}\right) \]
        11. lower-log1p.f64N/A

          \[\leadsto \frac{b}{e^{a} + 1} + \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
        12. lower-exp.f6476.9

          \[\leadsto \frac{b}{e^{a} + 1} + \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]
      5. Applied rewrites76.9%

        \[\leadsto \color{blue}{\frac{b}{e^{a} + 1} + \mathsf{log1p}\left(e^{a}\right)} \]
      6. Taylor expanded in a around 0

        \[\leadsto \frac{1}{2} \cdot b + \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]
      7. Step-by-step derivation
        1. Applied rewrites51.8%

          \[\leadsto 0.5 \cdot b + \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]

        if 1.00000000000002 < (exp.f64 b)

        1. Initial program 72.4%

          \[\log \left(e^{a} + e^{b}\right) \]
        2. Add Preprocessing
      8. Recombined 2 regimes into one program.
      9. Add Preprocessing

      Alternative 5: 51.6% accurate, 1.5× speedup?

      \[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \begin{array}{l} \mathbf{if}\;b \leq 2.9 \cdot 10^{-94}:\\ \;\;\;\;\mathsf{log1p}\left(e^{a}\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{log1p}\left(e^{b}\right)\\ \end{array} \end{array} \]
      NOTE: a and b should be sorted in increasing order before calling this function.
      (FPCore (a b)
       :precision binary64
       (if (<= b 2.9e-94) (log1p (exp a)) (log1p (exp b))))
      assert(a < b);
      double code(double a, double b) {
      	double tmp;
      	if (b <= 2.9e-94) {
      		tmp = log1p(exp(a));
      	} else {
      		tmp = log1p(exp(b));
      	}
      	return tmp;
      }
      
      assert a < b;
      public static double code(double a, double b) {
      	double tmp;
      	if (b <= 2.9e-94) {
      		tmp = Math.log1p(Math.exp(a));
      	} else {
      		tmp = Math.log1p(Math.exp(b));
      	}
      	return tmp;
      }
      
      [a, b] = sort([a, b])
      def code(a, b):
      	tmp = 0
      	if b <= 2.9e-94:
      		tmp = math.log1p(math.exp(a))
      	else:
      		tmp = math.log1p(math.exp(b))
      	return tmp
      
      a, b = sort([a, b])
      function code(a, b)
      	tmp = 0.0
      	if (b <= 2.9e-94)
      		tmp = log1p(exp(a));
      	else
      		tmp = log1p(exp(b));
      	end
      	return tmp
      end
      
      NOTE: a and b should be sorted in increasing order before calling this function.
      code[a_, b_] := If[LessEqual[b, 2.9e-94], N[Log[1 + N[Exp[a], $MachinePrecision]], $MachinePrecision], N[Log[1 + N[Exp[b], $MachinePrecision]], $MachinePrecision]]
      
      \begin{array}{l}
      [a, b] = \mathsf{sort}([a, b])\\
      \\
      \begin{array}{l}
      \mathbf{if}\;b \leq 2.9 \cdot 10^{-94}:\\
      \;\;\;\;\mathsf{log1p}\left(e^{a}\right)\\
      
      \mathbf{else}:\\
      \;\;\;\;\mathsf{log1p}\left(e^{b}\right)\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if b < 2.89999999999999995e-94

        1. Initial program 48.2%

          \[\log \left(e^{a} + e^{b}\right) \]
        2. Add Preprocessing
        3. Taylor expanded in b around 0

          \[\leadsto \color{blue}{\log \left(1 + e^{a}\right)} \]
        4. Step-by-step derivation
          1. lower-log1p.f64N/A

            \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
          2. lower-exp.f6446.6

            \[\leadsto \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]
        5. Applied rewrites46.6%

          \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]

        if 2.89999999999999995e-94 < b

        1. Initial program 64.6%

          \[\log \left(e^{a} + e^{b}\right) \]
        2. Add Preprocessing
        3. Taylor expanded in a around 0

          \[\leadsto \color{blue}{\log \left(1 + e^{b}\right)} \]
        4. Step-by-step derivation
          1. lower-log1p.f64N/A

            \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{b}\right)} \]
          2. lower-exp.f6460.5

            \[\leadsto \mathsf{log1p}\left(\color{blue}{e^{b}}\right) \]
        5. Applied rewrites60.5%

          \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{b}\right)} \]
      3. Recombined 2 regimes into one program.
      4. Add Preprocessing

      Alternative 6: 51.2% accurate, 1.5× speedup?

      \[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \begin{array}{l} \mathbf{if}\;b \leq 2.9 \cdot 10^{-94}:\\ \;\;\;\;\mathsf{log1p}\left(e^{a}\right)\\ \mathbf{else}:\\ \;\;\;\;\log \left(1 + \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, b, 0.5\right), b, 1\right), b, 1\right)\right)\\ \end{array} \end{array} \]
      NOTE: a and b should be sorted in increasing order before calling this function.
      (FPCore (a b)
       :precision binary64
       (if (<= b 2.9e-94)
         (log1p (exp a))
         (log (+ 1.0 (fma (fma (fma 0.16666666666666666 b 0.5) b 1.0) b 1.0)))))
      assert(a < b);
      double code(double a, double b) {
      	double tmp;
      	if (b <= 2.9e-94) {
      		tmp = log1p(exp(a));
      	} else {
      		tmp = log((1.0 + fma(fma(fma(0.16666666666666666, b, 0.5), b, 1.0), b, 1.0)));
      	}
      	return tmp;
      }
      
      a, b = sort([a, b])
      function code(a, b)
      	tmp = 0.0
      	if (b <= 2.9e-94)
      		tmp = log1p(exp(a));
      	else
      		tmp = log(Float64(1.0 + fma(fma(fma(0.16666666666666666, b, 0.5), b, 1.0), b, 1.0)));
      	end
      	return tmp
      end
      
      NOTE: a and b should be sorted in increasing order before calling this function.
      code[a_, b_] := If[LessEqual[b, 2.9e-94], N[Log[1 + N[Exp[a], $MachinePrecision]], $MachinePrecision], N[Log[N[(1.0 + N[(N[(N[(0.16666666666666666 * b + 0.5), $MachinePrecision] * b + 1.0), $MachinePrecision] * b + 1.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]]
      
      \begin{array}{l}
      [a, b] = \mathsf{sort}([a, b])\\
      \\
      \begin{array}{l}
      \mathbf{if}\;b \leq 2.9 \cdot 10^{-94}:\\
      \;\;\;\;\mathsf{log1p}\left(e^{a}\right)\\
      
      \mathbf{else}:\\
      \;\;\;\;\log \left(1 + \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, b, 0.5\right), b, 1\right), b, 1\right)\right)\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if b < 2.89999999999999995e-94

        1. Initial program 48.2%

          \[\log \left(e^{a} + e^{b}\right) \]
        2. Add Preprocessing
        3. Taylor expanded in b around 0

          \[\leadsto \color{blue}{\log \left(1 + e^{a}\right)} \]
        4. Step-by-step derivation
          1. lower-log1p.f64N/A

            \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
          2. lower-exp.f6446.6

            \[\leadsto \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]
        5. Applied rewrites46.6%

          \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]

        if 2.89999999999999995e-94 < b

        1. Initial program 64.6%

          \[\log \left(e^{a} + e^{b}\right) \]
        2. Add Preprocessing
        3. Taylor expanded in a around 0

          \[\leadsto \log \left(\color{blue}{1} + e^{b}\right) \]
        4. Step-by-step derivation
          1. Applied rewrites60.4%

            \[\leadsto \log \left(\color{blue}{1} + e^{b}\right) \]
          2. Taylor expanded in b around 0

            \[\leadsto \log \left(1 + \color{blue}{\left(1 + b \cdot \left(1 + b \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot b\right)\right)\right)}\right) \]
          3. Step-by-step derivation
            1. +-commutativeN/A

              \[\leadsto \log \left(1 + \color{blue}{\left(b \cdot \left(1 + b \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot b\right)\right) + 1\right)}\right) \]
            2. *-commutativeN/A

              \[\leadsto \log \left(1 + \left(\color{blue}{\left(1 + b \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot b\right)\right) \cdot b} + 1\right)\right) \]
            3. lower-fma.f64N/A

              \[\leadsto \log \left(1 + \color{blue}{\mathsf{fma}\left(1 + b \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot b\right), b, 1\right)}\right) \]
            4. +-commutativeN/A

              \[\leadsto \log \left(1 + \mathsf{fma}\left(\color{blue}{b \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot b\right) + 1}, b, 1\right)\right) \]
            5. *-commutativeN/A

              \[\leadsto \log \left(1 + \mathsf{fma}\left(\color{blue}{\left(\frac{1}{2} + \frac{1}{6} \cdot b\right) \cdot b} + 1, b, 1\right)\right) \]
            6. lower-fma.f64N/A

              \[\leadsto \log \left(1 + \mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(\frac{1}{2} + \frac{1}{6} \cdot b, b, 1\right)}, b, 1\right)\right) \]
            7. +-commutativeN/A

              \[\leadsto \log \left(1 + \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\frac{1}{6} \cdot b + \frac{1}{2}}, b, 1\right), b, 1\right)\right) \]
            8. lower-fma.f6456.1

              \[\leadsto \log \left(1 + \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(0.16666666666666666, b, 0.5\right)}, b, 1\right), b, 1\right)\right) \]
          4. Applied rewrites56.1%

            \[\leadsto \log \left(1 + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, b, 0.5\right), b, 1\right), b, 1\right)}\right) \]
        5. Recombined 2 regimes into one program.
        6. Add Preprocessing

        Alternative 7: 49.1% accurate, 2.5× speedup?

        \[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \log \left(1 + \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, b, 0.5\right), b, 1\right), b, 1\right)\right) \end{array} \]
        NOTE: a and b should be sorted in increasing order before calling this function.
        (FPCore (a b)
         :precision binary64
         (log (+ 1.0 (fma (fma (fma 0.16666666666666666 b 0.5) b 1.0) b 1.0))))
        assert(a < b);
        double code(double a, double b) {
        	return log((1.0 + fma(fma(fma(0.16666666666666666, b, 0.5), b, 1.0), b, 1.0)));
        }
        
        a, b = sort([a, b])
        function code(a, b)
        	return log(Float64(1.0 + fma(fma(fma(0.16666666666666666, b, 0.5), b, 1.0), b, 1.0)))
        end
        
        NOTE: a and b should be sorted in increasing order before calling this function.
        code[a_, b_] := N[Log[N[(1.0 + N[(N[(N[(0.16666666666666666 * b + 0.5), $MachinePrecision] * b + 1.0), $MachinePrecision] * b + 1.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
        
        \begin{array}{l}
        [a, b] = \mathsf{sort}([a, b])\\
        \\
        \log \left(1 + \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, b, 0.5\right), b, 1\right), b, 1\right)\right)
        \end{array}
        
        Derivation
        1. Initial program 50.4%

          \[\log \left(e^{a} + e^{b}\right) \]
        2. Add Preprocessing
        3. Taylor expanded in a around 0

          \[\leadsto \log \left(\color{blue}{1} + e^{b}\right) \]
        4. Step-by-step derivation
          1. Applied rewrites47.0%

            \[\leadsto \log \left(\color{blue}{1} + e^{b}\right) \]
          2. Taylor expanded in b around 0

            \[\leadsto \log \left(1 + \color{blue}{\left(1 + b \cdot \left(1 + b \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot b\right)\right)\right)}\right) \]
          3. Step-by-step derivation
            1. +-commutativeN/A

              \[\leadsto \log \left(1 + \color{blue}{\left(b \cdot \left(1 + b \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot b\right)\right) + 1\right)}\right) \]
            2. *-commutativeN/A

              \[\leadsto \log \left(1 + \left(\color{blue}{\left(1 + b \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot b\right)\right) \cdot b} + 1\right)\right) \]
            3. lower-fma.f64N/A

              \[\leadsto \log \left(1 + \color{blue}{\mathsf{fma}\left(1 + b \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot b\right), b, 1\right)}\right) \]
            4. +-commutativeN/A

              \[\leadsto \log \left(1 + \mathsf{fma}\left(\color{blue}{b \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot b\right) + 1}, b, 1\right)\right) \]
            5. *-commutativeN/A

              \[\leadsto \log \left(1 + \mathsf{fma}\left(\color{blue}{\left(\frac{1}{2} + \frac{1}{6} \cdot b\right) \cdot b} + 1, b, 1\right)\right) \]
            6. lower-fma.f64N/A

              \[\leadsto \log \left(1 + \mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(\frac{1}{2} + \frac{1}{6} \cdot b, b, 1\right)}, b, 1\right)\right) \]
            7. +-commutativeN/A

              \[\leadsto \log \left(1 + \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\frac{1}{6} \cdot b + \frac{1}{2}}, b, 1\right), b, 1\right)\right) \]
            8. lower-fma.f6444.8

              \[\leadsto \log \left(1 + \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(0.16666666666666666, b, 0.5\right)}, b, 1\right), b, 1\right)\right) \]
          4. Applied rewrites44.8%

            \[\leadsto \log \left(1 + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, b, 0.5\right), b, 1\right), b, 1\right)}\right) \]
          5. Add Preprocessing

          Alternative 8: 49.0% accurate, 2.6× speedup?

          \[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \log \left(1 + \mathsf{fma}\left(\mathsf{fma}\left(0.5, b, 1\right), b, 1\right)\right) \end{array} \]
          NOTE: a and b should be sorted in increasing order before calling this function.
          (FPCore (a b) :precision binary64 (log (+ 1.0 (fma (fma 0.5 b 1.0) b 1.0))))
          assert(a < b);
          double code(double a, double b) {
          	return log((1.0 + fma(fma(0.5, b, 1.0), b, 1.0)));
          }
          
          a, b = sort([a, b])
          function code(a, b)
          	return log(Float64(1.0 + fma(fma(0.5, b, 1.0), b, 1.0)))
          end
          
          NOTE: a and b should be sorted in increasing order before calling this function.
          code[a_, b_] := N[Log[N[(1.0 + N[(N[(0.5 * b + 1.0), $MachinePrecision] * b + 1.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
          
          \begin{array}{l}
          [a, b] = \mathsf{sort}([a, b])\\
          \\
          \log \left(1 + \mathsf{fma}\left(\mathsf{fma}\left(0.5, b, 1\right), b, 1\right)\right)
          \end{array}
          
          Derivation
          1. Initial program 50.4%

            \[\log \left(e^{a} + e^{b}\right) \]
          2. Add Preprocessing
          3. Taylor expanded in b around 0

            \[\leadsto \log \left(e^{a} + \color{blue}{\left(1 + b \cdot \left(1 + \frac{1}{2} \cdot b\right)\right)}\right) \]
          4. Step-by-step derivation
            1. +-commutativeN/A

              \[\leadsto \log \left(e^{a} + \color{blue}{\left(b \cdot \left(1 + \frac{1}{2} \cdot b\right) + 1\right)}\right) \]
            2. *-commutativeN/A

              \[\leadsto \log \left(e^{a} + \left(\color{blue}{\left(1 + \frac{1}{2} \cdot b\right) \cdot b} + 1\right)\right) \]
            3. lower-fma.f64N/A

              \[\leadsto \log \left(e^{a} + \color{blue}{\mathsf{fma}\left(1 + \frac{1}{2} \cdot b, b, 1\right)}\right) \]
            4. +-commutativeN/A

              \[\leadsto \log \left(e^{a} + \mathsf{fma}\left(\color{blue}{\frac{1}{2} \cdot b + 1}, b, 1\right)\right) \]
            5. lower-fma.f6448.0

              \[\leadsto \log \left(e^{a} + \mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(0.5, b, 1\right)}, b, 1\right)\right) \]
          5. Applied rewrites48.0%

            \[\leadsto \log \left(e^{a} + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, b, 1\right), b, 1\right)}\right) \]
          6. Taylor expanded in a around 0

            \[\leadsto \log \left(\color{blue}{1} + \mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{2}, b, 1\right), b, 1\right)\right) \]
          7. Step-by-step derivation
            1. Applied rewrites45.3%

              \[\leadsto \log \left(\color{blue}{1} + \mathsf{fma}\left(\mathsf{fma}\left(0.5, b, 1\right), b, 1\right)\right) \]
            2. Add Preprocessing

            Alternative 9: 49.1% accurate, 2.8× speedup?

            \[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \mathsf{fma}\left(0.5, b, \log 2\right) \end{array} \]
            NOTE: a and b should be sorted in increasing order before calling this function.
            (FPCore (a b) :precision binary64 (fma 0.5 b (log 2.0)))
            assert(a < b);
            double code(double a, double b) {
            	return fma(0.5, b, log(2.0));
            }
            
            a, b = sort([a, b])
            function code(a, b)
            	return fma(0.5, b, log(2.0))
            end
            
            NOTE: a and b should be sorted in increasing order before calling this function.
            code[a_, b_] := N[(0.5 * b + N[Log[2.0], $MachinePrecision]), $MachinePrecision]
            
            \begin{array}{l}
            [a, b] = \mathsf{sort}([a, b])\\
            \\
            \mathsf{fma}\left(0.5, b, \log 2\right)
            \end{array}
            
            Derivation
            1. Initial program 50.4%

              \[\log \left(e^{a} + e^{b}\right) \]
            2. Add Preprocessing
            3. Taylor expanded in b around 0

              \[\leadsto \color{blue}{\log \left(1 + e^{a}\right) + \frac{b}{1 + e^{a}}} \]
            4. Step-by-step derivation
              1. +-commutativeN/A

                \[\leadsto \color{blue}{\frac{b}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
              2. *-rgt-identityN/A

                \[\leadsto \frac{\color{blue}{b \cdot 1}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
              3. associate-*r/N/A

                \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
              4. lower-+.f64N/A

                \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
              5. associate-*r/N/A

                \[\leadsto \color{blue}{\frac{b \cdot 1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
              6. *-rgt-identityN/A

                \[\leadsto \frac{\color{blue}{b}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
              7. lower-/.f64N/A

                \[\leadsto \color{blue}{\frac{b}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
              8. +-commutativeN/A

                \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
              9. lower-+.f64N/A

                \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
              10. lower-exp.f64N/A

                \[\leadsto \frac{b}{\color{blue}{e^{a}} + 1} + \log \left(1 + e^{a}\right) \]
              11. lower-log1p.f64N/A

                \[\leadsto \frac{b}{e^{a} + 1} + \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
              12. lower-exp.f6477.0

                \[\leadsto \frac{b}{e^{a} + 1} + \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]
            5. Applied rewrites77.0%

              \[\leadsto \color{blue}{\frac{b}{e^{a} + 1} + \mathsf{log1p}\left(e^{a}\right)} \]
            6. Taylor expanded in a around 0

              \[\leadsto \log 2 + \color{blue}{\frac{1}{2} \cdot b} \]
            7. Step-by-step derivation
              1. Applied rewrites45.1%

                \[\leadsto \mathsf{fma}\left(0.5, \color{blue}{b}, \log 2\right) \]
              2. Add Preprocessing

              Alternative 10: 48.4% accurate, 3.0× speedup?

              \[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \mathsf{log1p}\left(1\right) \end{array} \]
              NOTE: a and b should be sorted in increasing order before calling this function.
              (FPCore (a b) :precision binary64 (log1p 1.0))
              assert(a < b);
              double code(double a, double b) {
              	return log1p(1.0);
              }
              
              assert a < b;
              public static double code(double a, double b) {
              	return Math.log1p(1.0);
              }
              
              [a, b] = sort([a, b])
              def code(a, b):
              	return math.log1p(1.0)
              
              a, b = sort([a, b])
              function code(a, b)
              	return log1p(1.0)
              end
              
              NOTE: a and b should be sorted in increasing order before calling this function.
              code[a_, b_] := N[Log[1 + 1.0], $MachinePrecision]
              
              \begin{array}{l}
              [a, b] = \mathsf{sort}([a, b])\\
              \\
              \mathsf{log1p}\left(1\right)
              \end{array}
              
              Derivation
              1. Initial program 50.4%

                \[\log \left(e^{a} + e^{b}\right) \]
              2. Add Preprocessing
              3. Taylor expanded in b around 0

                \[\leadsto \color{blue}{\log \left(1 + e^{a}\right)} \]
              4. Step-by-step derivation
                1. lower-log1p.f64N/A

                  \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
                2. lower-exp.f6447.2

                  \[\leadsto \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]
              5. Applied rewrites47.2%

                \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
              6. Taylor expanded in a around 0

                \[\leadsto \mathsf{log1p}\left(1\right) \]
              7. Step-by-step derivation
                1. Applied rewrites44.7%

                  \[\leadsto \mathsf{log1p}\left(1\right) \]
                2. Add Preprocessing

                Alternative 11: 3.1% accurate, 27.6× speedup?

                \[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \left(a \cdot a\right) \cdot 0.125 \end{array} \]
                NOTE: a and b should be sorted in increasing order before calling this function.
                (FPCore (a b) :precision binary64 (* (* a a) 0.125))
                assert(a < b);
                double code(double a, double b) {
                	return (a * a) * 0.125;
                }
                
                NOTE: a and b should be sorted in increasing order before calling this function.
                real(8) function code(a, b)
                    real(8), intent (in) :: a
                    real(8), intent (in) :: b
                    code = (a * a) * 0.125d0
                end function
                
                assert a < b;
                public static double code(double a, double b) {
                	return (a * a) * 0.125;
                }
                
                [a, b] = sort([a, b])
                def code(a, b):
                	return (a * a) * 0.125
                
                a, b = sort([a, b])
                function code(a, b)
                	return Float64(Float64(a * a) * 0.125)
                end
                
                a, b = num2cell(sort([a, b])){:}
                function tmp = code(a, b)
                	tmp = (a * a) * 0.125;
                end
                
                NOTE: a and b should be sorted in increasing order before calling this function.
                code[a_, b_] := N[(N[(a * a), $MachinePrecision] * 0.125), $MachinePrecision]
                
                \begin{array}{l}
                [a, b] = \mathsf{sort}([a, b])\\
                \\
                \left(a \cdot a\right) \cdot 0.125
                \end{array}
                
                Derivation
                1. Initial program 50.4%

                  \[\log \left(e^{a} + e^{b}\right) \]
                2. Add Preprocessing
                3. Taylor expanded in b around 0

                  \[\leadsto \color{blue}{\log \left(1 + e^{a}\right)} \]
                4. Step-by-step derivation
                  1. lower-log1p.f64N/A

                    \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
                  2. lower-exp.f6447.2

                    \[\leadsto \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]
                5. Applied rewrites47.2%

                  \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
                6. Taylor expanded in a around 0

                  \[\leadsto \log 2 + \color{blue}{a \cdot \left(\frac{1}{2} + \frac{1}{8} \cdot a\right)} \]
                7. Step-by-step derivation
                  1. Applied rewrites45.1%

                    \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(0.125, a, 0.5\right), \color{blue}{a}, \log 2\right) \]
                  2. Taylor expanded in a around inf

                    \[\leadsto \frac{1}{8} \cdot {a}^{\color{blue}{2}} \]
                  3. Step-by-step derivation
                    1. Applied rewrites4.3%

                      \[\leadsto \left(a \cdot a\right) \cdot 0.125 \]
                    2. Add Preprocessing

                    Reproduce

                    ?
                    herbie shell --seed 2024323 
                    (FPCore (a b)
                      :name "symmetry log of sum of exp"
                      :precision binary64
                      (log (+ (exp a) (exp b))))