Toniolo and Linder, Equation (3b), real

Percentage Accurate: 94.3% → 99.6%
Time: 11.3s
Alternatives: 25
Speedup: 1.2×

Specification

?
\[\begin{array}{l} \\ \frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \end{array} \]
(FPCore (kx ky th)
 :precision binary64
 (* (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0)))) (sin th)))
double code(double kx, double ky, double th) {
	return (sin(ky) / sqrt((pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))) * sin(th);
}
real(8) function code(kx, ky, th)
    real(8), intent (in) :: kx
    real(8), intent (in) :: ky
    real(8), intent (in) :: th
    code = (sin(ky) / sqrt(((sin(kx) ** 2.0d0) + (sin(ky) ** 2.0d0)))) * sin(th)
end function
public static double code(double kx, double ky, double th) {
	return (Math.sin(ky) / Math.sqrt((Math.pow(Math.sin(kx), 2.0) + Math.pow(Math.sin(ky), 2.0)))) * Math.sin(th);
}
def code(kx, ky, th):
	return (math.sin(ky) / math.sqrt((math.pow(math.sin(kx), 2.0) + math.pow(math.sin(ky), 2.0)))) * math.sin(th)
function code(kx, ky, th)
	return Float64(Float64(sin(ky) / sqrt(Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) * sin(th))
end
function tmp = code(kx, ky, th)
	tmp = (sin(ky) / sqrt(((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) * sin(th);
end
code[kx_, ky_, th_] := N[(N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 25 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 94.3% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \end{array} \]
(FPCore (kx ky th)
 :precision binary64
 (* (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0)))) (sin th)))
double code(double kx, double ky, double th) {
	return (sin(ky) / sqrt((pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))) * sin(th);
}
real(8) function code(kx, ky, th)
    real(8), intent (in) :: kx
    real(8), intent (in) :: ky
    real(8), intent (in) :: th
    code = (sin(ky) / sqrt(((sin(kx) ** 2.0d0) + (sin(ky) ** 2.0d0)))) * sin(th)
end function
public static double code(double kx, double ky, double th) {
	return (Math.sin(ky) / Math.sqrt((Math.pow(Math.sin(kx), 2.0) + Math.pow(Math.sin(ky), 2.0)))) * Math.sin(th);
}
def code(kx, ky, th):
	return (math.sin(ky) / math.sqrt((math.pow(math.sin(kx), 2.0) + math.pow(math.sin(ky), 2.0)))) * math.sin(th)
function code(kx, ky, th)
	return Float64(Float64(sin(ky) / sqrt(Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) * sin(th))
end
function tmp = code(kx, ky, th)
	tmp = (sin(ky) / sqrt(((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) * sin(th);
end
code[kx_, ky_, th_] := N[(N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th
\end{array}

Alternative 1: 99.6% accurate, 1.2× speedup?

\[\begin{array}{l} \\ \frac{\sin ky}{\frac{\mathsf{hypot}\left(\sin kx, \sin ky\right)}{\sin th}} \end{array} \]
(FPCore (kx ky th)
 :precision binary64
 (/ (sin ky) (/ (hypot (sin kx) (sin ky)) (sin th))))
double code(double kx, double ky, double th) {
	return sin(ky) / (hypot(sin(kx), sin(ky)) / sin(th));
}
public static double code(double kx, double ky, double th) {
	return Math.sin(ky) / (Math.hypot(Math.sin(kx), Math.sin(ky)) / Math.sin(th));
}
def code(kx, ky, th):
	return math.sin(ky) / (math.hypot(math.sin(kx), math.sin(ky)) / math.sin(th))
function code(kx, ky, th)
	return Float64(sin(ky) / Float64(hypot(sin(kx), sin(ky)) / sin(th)))
end
function tmp = code(kx, ky, th)
	tmp = sin(ky) / (hypot(sin(kx), sin(ky)) / sin(th));
end
code[kx_, ky_, th_] := N[(N[Sin[ky], $MachinePrecision] / N[(N[Sqrt[N[Sin[kx], $MachinePrecision] ^ 2 + N[Sin[ky], $MachinePrecision] ^ 2], $MachinePrecision] / N[Sin[th], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{\sin ky}{\frac{\mathsf{hypot}\left(\sin kx, \sin ky\right)}{\sin th}}
\end{array}
Derivation
  1. Initial program 93.7%

    \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
  2. Add Preprocessing
  3. Step-by-step derivation
    1. lift-/.f64N/A

      \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin th \]
    2. clear-numN/A

      \[\leadsto \color{blue}{\frac{1}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \cdot \sin th \]
    3. div-invN/A

      \[\leadsto \frac{1}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}} \cdot \frac{1}{\sin ky}}} \cdot \sin th \]
    4. associate-/r*N/A

      \[\leadsto \color{blue}{\frac{\frac{1}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \cdot \sin th \]
    5. lower-/.f64N/A

      \[\leadsto \color{blue}{\frac{\frac{1}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \cdot \sin th \]
    6. inv-powN/A

      \[\leadsto \frac{\color{blue}{{\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}^{-1}}}{\frac{1}{\sin ky}} \cdot \sin th \]
    7. lower-pow.f64N/A

      \[\leadsto \frac{\color{blue}{{\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}^{-1}}}{\frac{1}{\sin ky}} \cdot \sin th \]
    8. lift-sqrt.f64N/A

      \[\leadsto \frac{{\color{blue}{\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}}^{-1}}{\frac{1}{\sin ky}} \cdot \sin th \]
    9. lift-+.f64N/A

      \[\leadsto \frac{{\left(\sqrt{\color{blue}{{\sin kx}^{2} + {\sin ky}^{2}}}\right)}^{-1}}{\frac{1}{\sin ky}} \cdot \sin th \]
    10. +-commutativeN/A

      \[\leadsto \frac{{\left(\sqrt{\color{blue}{{\sin ky}^{2} + {\sin kx}^{2}}}\right)}^{-1}}{\frac{1}{\sin ky}} \cdot \sin th \]
    11. lift-pow.f64N/A

      \[\leadsto \frac{{\left(\sqrt{\color{blue}{{\sin ky}^{2}} + {\sin kx}^{2}}\right)}^{-1}}{\frac{1}{\sin ky}} \cdot \sin th \]
    12. unpow2N/A

      \[\leadsto \frac{{\left(\sqrt{\color{blue}{\sin ky \cdot \sin ky} + {\sin kx}^{2}}\right)}^{-1}}{\frac{1}{\sin ky}} \cdot \sin th \]
    13. lift-pow.f64N/A

      \[\leadsto \frac{{\left(\sqrt{\sin ky \cdot \sin ky + \color{blue}{{\sin kx}^{2}}}\right)}^{-1}}{\frac{1}{\sin ky}} \cdot \sin th \]
    14. unpow2N/A

      \[\leadsto \frac{{\left(\sqrt{\sin ky \cdot \sin ky + \color{blue}{\sin kx \cdot \sin kx}}\right)}^{-1}}{\frac{1}{\sin ky}} \cdot \sin th \]
    15. lower-hypot.f64N/A

      \[\leadsto \frac{{\color{blue}{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}}^{-1}}{\frac{1}{\sin ky}} \cdot \sin th \]
    16. inv-powN/A

      \[\leadsto \frac{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}{\color{blue}{{\sin ky}^{-1}}} \cdot \sin th \]
    17. lower-pow.f6499.5

      \[\leadsto \frac{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}{\color{blue}{{\sin ky}^{-1}}} \cdot \sin th \]
  4. Applied rewrites99.5%

    \[\leadsto \color{blue}{\frac{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}{{\sin ky}^{-1}}} \cdot \sin th \]
  5. Step-by-step derivation
    1. lift-*.f64N/A

      \[\leadsto \color{blue}{\frac{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}{{\sin ky}^{-1}} \cdot \sin th} \]
    2. lift-/.f64N/A

      \[\leadsto \color{blue}{\frac{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}{{\sin ky}^{-1}}} \cdot \sin th \]
    3. clear-numN/A

      \[\leadsto \color{blue}{\frac{1}{\frac{{\sin ky}^{-1}}{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}}} \cdot \sin th \]
    4. associate-*l/N/A

      \[\leadsto \color{blue}{\frac{1 \cdot \sin th}{\frac{{\sin ky}^{-1}}{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}}} \]
    5. lift-pow.f64N/A

      \[\leadsto \frac{1 \cdot \sin th}{\frac{{\sin ky}^{-1}}{\color{blue}{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}}} \]
    6. unpow-1N/A

      \[\leadsto \frac{1 \cdot \sin th}{\frac{{\sin ky}^{-1}}{\color{blue}{\frac{1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}}} \]
    7. associate-/r/N/A

      \[\leadsto \frac{1 \cdot \sin th}{\color{blue}{\frac{{\sin ky}^{-1}}{1} \cdot \mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
    8. times-fracN/A

      \[\leadsto \color{blue}{\frac{1}{\frac{{\sin ky}^{-1}}{1}} \cdot \frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
    9. clear-numN/A

      \[\leadsto \color{blue}{\frac{1}{{\sin ky}^{-1}}} \cdot \frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
    10. lift-pow.f64N/A

      \[\leadsto \frac{1}{\color{blue}{{\sin ky}^{-1}}} \cdot \frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
    11. unpow-1N/A

      \[\leadsto \frac{1}{\color{blue}{\frac{1}{\sin ky}}} \cdot \frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
    12. remove-double-divN/A

      \[\leadsto \color{blue}{\sin ky} \cdot \frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
    13. clear-numN/A

      \[\leadsto \sin ky \cdot \color{blue}{\frac{1}{\frac{\mathsf{hypot}\left(\sin ky, \sin kx\right)}{\sin th}}} \]
    14. un-div-invN/A

      \[\leadsto \color{blue}{\frac{\sin ky}{\frac{\mathsf{hypot}\left(\sin ky, \sin kx\right)}{\sin th}}} \]
    15. lower-/.f64N/A

      \[\leadsto \color{blue}{\frac{\sin ky}{\frac{\mathsf{hypot}\left(\sin ky, \sin kx\right)}{\sin th}}} \]
  6. Applied rewrites99.6%

    \[\leadsto \color{blue}{\frac{\sin ky}{\frac{\mathsf{hypot}\left(\sin kx, \sin ky\right)}{\sin th}}} \]
  7. Add Preprocessing

Alternative 2: 83.1% accurate, 0.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := {\sin ky}^{2}\\ t_2 := {\sin kx}^{2}\\ t_3 := \frac{\sin ky}{\sqrt{t\_2 + t\_1}}\\ t_4 := \left(\left(-th\right) \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}\\ \mathbf{if}\;t\_3 \leq -0.999:\\ \;\;\;\;\frac{\sin ky}{\sqrt{kx \cdot kx + t\_1}} \cdot \sin th\\ \mathbf{elif}\;t\_3 \leq -0.04:\\ \;\;\;\;t\_4\\ \mathbf{elif}\;t\_3 \leq 0.05:\\ \;\;\;\;\frac{\sin ky}{\sqrt{t\_2 + ky \cdot ky}} \cdot \sin th\\ \mathbf{elif}\;t\_3 \leq 0.8:\\ \;\;\;\;t\_4\\ \mathbf{elif}\;t\_3 \leq 2:\\ \;\;\;\;\sin th\\ \mathbf{else}:\\ \;\;\;\;\frac{\sin th \cdot \frac{1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)}}{{ky}^{-1}}\\ \end{array} \end{array} \]
(FPCore (kx ky th)
 :precision binary64
 (let* ((t_1 (pow (sin ky) 2.0))
        (t_2 (pow (sin kx) 2.0))
        (t_3 (/ (sin ky) (sqrt (+ t_2 t_1))))
        (t_4 (* (* (- th) (sin ky)) (/ -1.0 (hypot (sin ky) (sin kx))))))
   (if (<= t_3 -0.999)
     (* (/ (sin ky) (sqrt (+ (* kx kx) t_1))) (sin th))
     (if (<= t_3 -0.04)
       t_4
       (if (<= t_3 0.05)
         (* (/ (sin ky) (sqrt (+ t_2 (* ky ky)))) (sin th))
         (if (<= t_3 0.8)
           t_4
           (if (<= t_3 2.0)
             (sin th)
             (/
              (* (sin th) (/ 1.0 (hypot (sin kx) (sin ky))))
              (pow ky -1.0)))))))))
double code(double kx, double ky, double th) {
	double t_1 = pow(sin(ky), 2.0);
	double t_2 = pow(sin(kx), 2.0);
	double t_3 = sin(ky) / sqrt((t_2 + t_1));
	double t_4 = (-th * sin(ky)) * (-1.0 / hypot(sin(ky), sin(kx)));
	double tmp;
	if (t_3 <= -0.999) {
		tmp = (sin(ky) / sqrt(((kx * kx) + t_1))) * sin(th);
	} else if (t_3 <= -0.04) {
		tmp = t_4;
	} else if (t_3 <= 0.05) {
		tmp = (sin(ky) / sqrt((t_2 + (ky * ky)))) * sin(th);
	} else if (t_3 <= 0.8) {
		tmp = t_4;
	} else if (t_3 <= 2.0) {
		tmp = sin(th);
	} else {
		tmp = (sin(th) * (1.0 / hypot(sin(kx), sin(ky)))) / pow(ky, -1.0);
	}
	return tmp;
}
public static double code(double kx, double ky, double th) {
	double t_1 = Math.pow(Math.sin(ky), 2.0);
	double t_2 = Math.pow(Math.sin(kx), 2.0);
	double t_3 = Math.sin(ky) / Math.sqrt((t_2 + t_1));
	double t_4 = (-th * Math.sin(ky)) * (-1.0 / Math.hypot(Math.sin(ky), Math.sin(kx)));
	double tmp;
	if (t_3 <= -0.999) {
		tmp = (Math.sin(ky) / Math.sqrt(((kx * kx) + t_1))) * Math.sin(th);
	} else if (t_3 <= -0.04) {
		tmp = t_4;
	} else if (t_3 <= 0.05) {
		tmp = (Math.sin(ky) / Math.sqrt((t_2 + (ky * ky)))) * Math.sin(th);
	} else if (t_3 <= 0.8) {
		tmp = t_4;
	} else if (t_3 <= 2.0) {
		tmp = Math.sin(th);
	} else {
		tmp = (Math.sin(th) * (1.0 / Math.hypot(Math.sin(kx), Math.sin(ky)))) / Math.pow(ky, -1.0);
	}
	return tmp;
}
def code(kx, ky, th):
	t_1 = math.pow(math.sin(ky), 2.0)
	t_2 = math.pow(math.sin(kx), 2.0)
	t_3 = math.sin(ky) / math.sqrt((t_2 + t_1))
	t_4 = (-th * math.sin(ky)) * (-1.0 / math.hypot(math.sin(ky), math.sin(kx)))
	tmp = 0
	if t_3 <= -0.999:
		tmp = (math.sin(ky) / math.sqrt(((kx * kx) + t_1))) * math.sin(th)
	elif t_3 <= -0.04:
		tmp = t_4
	elif t_3 <= 0.05:
		tmp = (math.sin(ky) / math.sqrt((t_2 + (ky * ky)))) * math.sin(th)
	elif t_3 <= 0.8:
		tmp = t_4
	elif t_3 <= 2.0:
		tmp = math.sin(th)
	else:
		tmp = (math.sin(th) * (1.0 / math.hypot(math.sin(kx), math.sin(ky)))) / math.pow(ky, -1.0)
	return tmp
function code(kx, ky, th)
	t_1 = sin(ky) ^ 2.0
	t_2 = sin(kx) ^ 2.0
	t_3 = Float64(sin(ky) / sqrt(Float64(t_2 + t_1)))
	t_4 = Float64(Float64(Float64(-th) * sin(ky)) * Float64(-1.0 / hypot(sin(ky), sin(kx))))
	tmp = 0.0
	if (t_3 <= -0.999)
		tmp = Float64(Float64(sin(ky) / sqrt(Float64(Float64(kx * kx) + t_1))) * sin(th));
	elseif (t_3 <= -0.04)
		tmp = t_4;
	elseif (t_3 <= 0.05)
		tmp = Float64(Float64(sin(ky) / sqrt(Float64(t_2 + Float64(ky * ky)))) * sin(th));
	elseif (t_3 <= 0.8)
		tmp = t_4;
	elseif (t_3 <= 2.0)
		tmp = sin(th);
	else
		tmp = Float64(Float64(sin(th) * Float64(1.0 / hypot(sin(kx), sin(ky)))) / (ky ^ -1.0));
	end
	return tmp
end
function tmp_2 = code(kx, ky, th)
	t_1 = sin(ky) ^ 2.0;
	t_2 = sin(kx) ^ 2.0;
	t_3 = sin(ky) / sqrt((t_2 + t_1));
	t_4 = (-th * sin(ky)) * (-1.0 / hypot(sin(ky), sin(kx)));
	tmp = 0.0;
	if (t_3 <= -0.999)
		tmp = (sin(ky) / sqrt(((kx * kx) + t_1))) * sin(th);
	elseif (t_3 <= -0.04)
		tmp = t_4;
	elseif (t_3 <= 0.05)
		tmp = (sin(ky) / sqrt((t_2 + (ky * ky)))) * sin(th);
	elseif (t_3 <= 0.8)
		tmp = t_4;
	elseif (t_3 <= 2.0)
		tmp = sin(th);
	else
		tmp = (sin(th) * (1.0 / hypot(sin(kx), sin(ky)))) / (ky ^ -1.0);
	end
	tmp_2 = tmp;
end
code[kx_, ky_, th_] := Block[{t$95$1 = N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]}, Block[{t$95$2 = N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision]}, Block[{t$95$3 = N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(t$95$2 + t$95$1), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]}, Block[{t$95$4 = N[(N[((-th) * N[Sin[ky], $MachinePrecision]), $MachinePrecision] * N[(-1.0 / N[Sqrt[N[Sin[ky], $MachinePrecision] ^ 2 + N[Sin[kx], $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$3, -0.999], N[(N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[(kx * kx), $MachinePrecision] + t$95$1), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$3, -0.04], t$95$4, If[LessEqual[t$95$3, 0.05], N[(N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(t$95$2 + N[(ky * ky), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$3, 0.8], t$95$4, If[LessEqual[t$95$3, 2.0], N[Sin[th], $MachinePrecision], N[(N[(N[Sin[th], $MachinePrecision] * N[(1.0 / N[Sqrt[N[Sin[kx], $MachinePrecision] ^ 2 + N[Sin[ky], $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[Power[ky, -1.0], $MachinePrecision]), $MachinePrecision]]]]]]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := {\sin ky}^{2}\\
t_2 := {\sin kx}^{2}\\
t_3 := \frac{\sin ky}{\sqrt{t\_2 + t\_1}}\\
t_4 := \left(\left(-th\right) \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}\\
\mathbf{if}\;t\_3 \leq -0.999:\\
\;\;\;\;\frac{\sin ky}{\sqrt{kx \cdot kx + t\_1}} \cdot \sin th\\

\mathbf{elif}\;t\_3 \leq -0.04:\\
\;\;\;\;t\_4\\

\mathbf{elif}\;t\_3 \leq 0.05:\\
\;\;\;\;\frac{\sin ky}{\sqrt{t\_2 + ky \cdot ky}} \cdot \sin th\\

\mathbf{elif}\;t\_3 \leq 0.8:\\
\;\;\;\;t\_4\\

\mathbf{elif}\;t\_3 \leq 2:\\
\;\;\;\;\sin th\\

\mathbf{else}:\\
\;\;\;\;\frac{\sin th \cdot \frac{1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)}}{{ky}^{-1}}\\


\end{array}
\end{array}
Derivation
  1. Split input into 5 regimes
  2. if (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < -0.998999999999999999

    1. Initial program 85.1%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in kx around 0

      \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{{kx}^{2}} + {\sin ky}^{2}}} \cdot \sin th \]
    4. Step-by-step derivation
      1. unpow2N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{kx \cdot kx} + {\sin ky}^{2}}} \cdot \sin th \]
      2. lower-*.f6483.1

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{kx \cdot kx} + {\sin ky}^{2}}} \cdot \sin th \]
    5. Applied rewrites83.1%

      \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{kx \cdot kx} + {\sin ky}^{2}}} \cdot \sin th \]

    if -0.998999999999999999 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < -0.0400000000000000008 or 0.050000000000000003 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 0.80000000000000004

    1. Initial program 99.2%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
      2. lift-/.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin th \]
      3. associate-*l/N/A

        \[\leadsto \color{blue}{\frac{\sin ky \cdot \sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      4. frac-2negN/A

        \[\leadsto \color{blue}{\frac{\mathsf{neg}\left(\sin ky \cdot \sin th\right)}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      5. div-invN/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sin ky \cdot \sin th\right)\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      6. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sin ky \cdot \sin th\right)\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      7. distribute-lft-neg-inN/A

        \[\leadsto \color{blue}{\left(\left(\mathsf{neg}\left(\sin ky\right)\right) \cdot \sin th\right)} \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      8. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\left(\mathsf{neg}\left(\sin ky\right)\right) \cdot \sin th\right)} \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      9. lower-neg.f64N/A

        \[\leadsto \left(\color{blue}{\left(-\sin ky\right)} \cdot \sin th\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      10. neg-mul-1N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{1}{\color{blue}{-1 \cdot \sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      11. associate-/r*N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \color{blue}{\frac{\frac{1}{-1}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      12. metadata-evalN/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{\color{blue}{-1}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \]
      13. lower-/.f6499.4

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \color{blue}{\frac{-1}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      14. lift-sqrt.f64N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{-1}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
    4. Applied rewrites99.4%

      \[\leadsto \color{blue}{\left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
    5. Taylor expanded in th around 0

      \[\leadsto \color{blue}{\left(-1 \cdot \left(th \cdot \sin ky\right)\right)} \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
    6. Step-by-step derivation
      1. associate-*r*N/A

        \[\leadsto \color{blue}{\left(\left(-1 \cdot th\right) \cdot \sin ky\right)} \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      2. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\left(-1 \cdot th\right) \cdot \sin ky\right)} \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      3. mul-1-negN/A

        \[\leadsto \left(\color{blue}{\left(\mathsf{neg}\left(th\right)\right)} \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      4. lower-neg.f64N/A

        \[\leadsto \left(\color{blue}{\left(-th\right)} \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      5. lower-sin.f6447.4

        \[\leadsto \left(\left(-th\right) \cdot \color{blue}{\sin ky}\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
    7. Applied rewrites47.4%

      \[\leadsto \color{blue}{\left(\left(-th\right) \cdot \sin ky\right)} \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]

    if -0.0400000000000000008 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 0.050000000000000003

    1. Initial program 98.6%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in ky around 0

      \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{{ky}^{2}}}} \cdot \sin th \]
    4. Step-by-step derivation
      1. unpow2N/A

        \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{ky \cdot ky}}} \cdot \sin th \]
      2. lower-*.f6498.4

        \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{ky \cdot ky}}} \cdot \sin th \]
    5. Applied rewrites98.4%

      \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{ky \cdot ky}}} \cdot \sin th \]

    if 0.80000000000000004 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 2

    1. Initial program 99.0%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in kx around 0

      \[\leadsto \color{blue}{\sin th} \]
    4. Step-by-step derivation
      1. lower-sin.f6486.9

        \[\leadsto \color{blue}{\sin th} \]
    5. Applied rewrites86.9%

      \[\leadsto \color{blue}{\sin th} \]

    if 2 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))

    1. Initial program 2.6%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
      2. *-commutativeN/A

        \[\leadsto \color{blue}{\sin th \cdot \frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      3. lift-/.f64N/A

        \[\leadsto \sin th \cdot \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      4. clear-numN/A

        \[\leadsto \sin th \cdot \color{blue}{\frac{1}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
      5. un-div-invN/A

        \[\leadsto \color{blue}{\frac{\sin th}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
      6. div-invN/A

        \[\leadsto \frac{\sin th}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}} \cdot \frac{1}{\sin ky}}} \]
      7. associate-/r*N/A

        \[\leadsto \color{blue}{\frac{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \]
      8. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \]
    4. Applied rewrites99.6%

      \[\leadsto \color{blue}{\frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{{\sin ky}^{-1}}} \]
    5. Taylor expanded in ky around 0

      \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
    6. Step-by-step derivation
      1. lower-/.f6499.6

        \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
    7. Applied rewrites99.6%

      \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
    8. Step-by-step derivation
      1. lift-/.f64N/A

        \[\leadsto \frac{\color{blue}{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}}{\frac{1}{ky}} \]
      2. frac-2negN/A

        \[\leadsto \frac{\color{blue}{\frac{\mathsf{neg}\left(\sin th\right)}{\mathsf{neg}\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}}}{\frac{1}{ky}} \]
      3. div-invN/A

        \[\leadsto \frac{\color{blue}{\left(\mathsf{neg}\left(\sin th\right)\right) \cdot \frac{1}{\mathsf{neg}\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}}}{\frac{1}{ky}} \]
      4. distribute-neg-frac2N/A

        \[\leadsto \frac{\left(\mathsf{neg}\left(\sin th\right)\right) \cdot \color{blue}{\left(\mathsf{neg}\left(\frac{1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}\right)\right)}}{\frac{1}{ky}} \]
      5. unpow-1N/A

        \[\leadsto \frac{\left(\mathsf{neg}\left(\sin th\right)\right) \cdot \left(\mathsf{neg}\left(\color{blue}{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}\right)\right)}{\frac{1}{ky}} \]
      6. lift-pow.f64N/A

        \[\leadsto \frac{\left(\mathsf{neg}\left(\sin th\right)\right) \cdot \left(\mathsf{neg}\left(\color{blue}{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}\right)\right)}{\frac{1}{ky}} \]
      7. lower-*.f64N/A

        \[\leadsto \frac{\color{blue}{\left(\mathsf{neg}\left(\sin th\right)\right) \cdot \left(\mathsf{neg}\left({\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}\right)\right)}}{\frac{1}{ky}} \]
      8. lower-neg.f64N/A

        \[\leadsto \frac{\color{blue}{\left(-\sin th\right)} \cdot \left(\mathsf{neg}\left({\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}\right)\right)}{\frac{1}{ky}} \]
      9. lift-pow.f64N/A

        \[\leadsto \frac{\left(-\sin th\right) \cdot \left(\mathsf{neg}\left(\color{blue}{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}\right)\right)}{\frac{1}{ky}} \]
      10. unpow-1N/A

        \[\leadsto \frac{\left(-\sin th\right) \cdot \left(\mathsf{neg}\left(\color{blue}{\frac{1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}\right)\right)}{\frac{1}{ky}} \]
      11. distribute-neg-fracN/A

        \[\leadsto \frac{\left(-\sin th\right) \cdot \color{blue}{\frac{\mathsf{neg}\left(1\right)}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}}{\frac{1}{ky}} \]
      12. metadata-evalN/A

        \[\leadsto \frac{\left(-\sin th\right) \cdot \frac{\color{blue}{-1}}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\frac{1}{ky}} \]
      13. lower-/.f6499.3

        \[\leadsto \frac{\left(-\sin th\right) \cdot \color{blue}{\frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}}{\frac{1}{ky}} \]
      14. lift-sin.f64N/A

        \[\leadsto \frac{\left(-\sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \color{blue}{\sin kx}\right)}}{\frac{1}{ky}} \]
      15. lift-hypot.f64N/A

        \[\leadsto \frac{\left(-\sin th\right) \cdot \frac{-1}{\color{blue}{\sqrt{\sin ky \cdot \sin ky + \sin kx \cdot \sin kx}}}}{\frac{1}{ky}} \]
      16. +-commutativeN/A

        \[\leadsto \frac{\left(-\sin th\right) \cdot \frac{-1}{\sqrt{\color{blue}{\sin kx \cdot \sin kx + \sin ky \cdot \sin ky}}}}{\frac{1}{ky}} \]
      17. lower-hypot.f64N/A

        \[\leadsto \frac{\left(-\sin th\right) \cdot \frac{-1}{\color{blue}{\mathsf{hypot}\left(\sin kx, \sin ky\right)}}}{\frac{1}{ky}} \]
      18. lift-sin.f6499.3

        \[\leadsto \frac{\left(-\sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\color{blue}{\sin kx}, \sin ky\right)}}{\frac{1}{ky}} \]
    9. Applied rewrites99.3%

      \[\leadsto \frac{\color{blue}{\left(-\sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)}}}{\frac{1}{ky}} \]
  3. Recombined 5 regimes into one program.
  4. Final simplification82.1%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq -0.999:\\ \;\;\;\;\frac{\sin ky}{\sqrt{kx \cdot kx + {\sin ky}^{2}}} \cdot \sin th\\ \mathbf{elif}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq -0.04:\\ \;\;\;\;\left(\left(-th\right) \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}\\ \mathbf{elif}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 0.05:\\ \;\;\;\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th\\ \mathbf{elif}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 0.8:\\ \;\;\;\;\left(\left(-th\right) \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}\\ \mathbf{elif}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 2:\\ \;\;\;\;\sin th\\ \mathbf{else}:\\ \;\;\;\;\frac{\sin th \cdot \frac{1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)}}{{ky}^{-1}}\\ \end{array} \]
  5. Add Preprocessing

Alternative 3: 83.1% accurate, 0.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := {\sin ky}^{2}\\ t_2 := \mathsf{hypot}\left(\sin ky, \sin kx\right)\\ t_3 := {\sin kx}^{2}\\ t_4 := \frac{\sin ky}{\sqrt{t\_3 + t\_1}}\\ t_5 := \left(\left(-th\right) \cdot \sin ky\right) \cdot \frac{-1}{t\_2}\\ \mathbf{if}\;t\_4 \leq -0.999:\\ \;\;\;\;\frac{\sin ky}{\sqrt{kx \cdot kx + t\_1}} \cdot \sin th\\ \mathbf{elif}\;t\_4 \leq -0.04:\\ \;\;\;\;t\_5\\ \mathbf{elif}\;t\_4 \leq 0.05:\\ \;\;\;\;\frac{\sin ky}{\sqrt{t\_3 + ky \cdot ky}} \cdot \sin th\\ \mathbf{elif}\;t\_4 \leq 0.8:\\ \;\;\;\;t\_5\\ \mathbf{elif}\;t\_4 \leq 2:\\ \;\;\;\;\sin th\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{\sin th}{t\_2}}{{ky}^{-1}}\\ \end{array} \end{array} \]
(FPCore (kx ky th)
 :precision binary64
 (let* ((t_1 (pow (sin ky) 2.0))
        (t_2 (hypot (sin ky) (sin kx)))
        (t_3 (pow (sin kx) 2.0))
        (t_4 (/ (sin ky) (sqrt (+ t_3 t_1))))
        (t_5 (* (* (- th) (sin ky)) (/ -1.0 t_2))))
   (if (<= t_4 -0.999)
     (* (/ (sin ky) (sqrt (+ (* kx kx) t_1))) (sin th))
     (if (<= t_4 -0.04)
       t_5
       (if (<= t_4 0.05)
         (* (/ (sin ky) (sqrt (+ t_3 (* ky ky)))) (sin th))
         (if (<= t_4 0.8)
           t_5
           (if (<= t_4 2.0) (sin th) (/ (/ (sin th) t_2) (pow ky -1.0)))))))))
double code(double kx, double ky, double th) {
	double t_1 = pow(sin(ky), 2.0);
	double t_2 = hypot(sin(ky), sin(kx));
	double t_3 = pow(sin(kx), 2.0);
	double t_4 = sin(ky) / sqrt((t_3 + t_1));
	double t_5 = (-th * sin(ky)) * (-1.0 / t_2);
	double tmp;
	if (t_4 <= -0.999) {
		tmp = (sin(ky) / sqrt(((kx * kx) + t_1))) * sin(th);
	} else if (t_4 <= -0.04) {
		tmp = t_5;
	} else if (t_4 <= 0.05) {
		tmp = (sin(ky) / sqrt((t_3 + (ky * ky)))) * sin(th);
	} else if (t_4 <= 0.8) {
		tmp = t_5;
	} else if (t_4 <= 2.0) {
		tmp = sin(th);
	} else {
		tmp = (sin(th) / t_2) / pow(ky, -1.0);
	}
	return tmp;
}
public static double code(double kx, double ky, double th) {
	double t_1 = Math.pow(Math.sin(ky), 2.0);
	double t_2 = Math.hypot(Math.sin(ky), Math.sin(kx));
	double t_3 = Math.pow(Math.sin(kx), 2.0);
	double t_4 = Math.sin(ky) / Math.sqrt((t_3 + t_1));
	double t_5 = (-th * Math.sin(ky)) * (-1.0 / t_2);
	double tmp;
	if (t_4 <= -0.999) {
		tmp = (Math.sin(ky) / Math.sqrt(((kx * kx) + t_1))) * Math.sin(th);
	} else if (t_4 <= -0.04) {
		tmp = t_5;
	} else if (t_4 <= 0.05) {
		tmp = (Math.sin(ky) / Math.sqrt((t_3 + (ky * ky)))) * Math.sin(th);
	} else if (t_4 <= 0.8) {
		tmp = t_5;
	} else if (t_4 <= 2.0) {
		tmp = Math.sin(th);
	} else {
		tmp = (Math.sin(th) / t_2) / Math.pow(ky, -1.0);
	}
	return tmp;
}
def code(kx, ky, th):
	t_1 = math.pow(math.sin(ky), 2.0)
	t_2 = math.hypot(math.sin(ky), math.sin(kx))
	t_3 = math.pow(math.sin(kx), 2.0)
	t_4 = math.sin(ky) / math.sqrt((t_3 + t_1))
	t_5 = (-th * math.sin(ky)) * (-1.0 / t_2)
	tmp = 0
	if t_4 <= -0.999:
		tmp = (math.sin(ky) / math.sqrt(((kx * kx) + t_1))) * math.sin(th)
	elif t_4 <= -0.04:
		tmp = t_5
	elif t_4 <= 0.05:
		tmp = (math.sin(ky) / math.sqrt((t_3 + (ky * ky)))) * math.sin(th)
	elif t_4 <= 0.8:
		tmp = t_5
	elif t_4 <= 2.0:
		tmp = math.sin(th)
	else:
		tmp = (math.sin(th) / t_2) / math.pow(ky, -1.0)
	return tmp
function code(kx, ky, th)
	t_1 = sin(ky) ^ 2.0
	t_2 = hypot(sin(ky), sin(kx))
	t_3 = sin(kx) ^ 2.0
	t_4 = Float64(sin(ky) / sqrt(Float64(t_3 + t_1)))
	t_5 = Float64(Float64(Float64(-th) * sin(ky)) * Float64(-1.0 / t_2))
	tmp = 0.0
	if (t_4 <= -0.999)
		tmp = Float64(Float64(sin(ky) / sqrt(Float64(Float64(kx * kx) + t_1))) * sin(th));
	elseif (t_4 <= -0.04)
		tmp = t_5;
	elseif (t_4 <= 0.05)
		tmp = Float64(Float64(sin(ky) / sqrt(Float64(t_3 + Float64(ky * ky)))) * sin(th));
	elseif (t_4 <= 0.8)
		tmp = t_5;
	elseif (t_4 <= 2.0)
		tmp = sin(th);
	else
		tmp = Float64(Float64(sin(th) / t_2) / (ky ^ -1.0));
	end
	return tmp
end
function tmp_2 = code(kx, ky, th)
	t_1 = sin(ky) ^ 2.0;
	t_2 = hypot(sin(ky), sin(kx));
	t_3 = sin(kx) ^ 2.0;
	t_4 = sin(ky) / sqrt((t_3 + t_1));
	t_5 = (-th * sin(ky)) * (-1.0 / t_2);
	tmp = 0.0;
	if (t_4 <= -0.999)
		tmp = (sin(ky) / sqrt(((kx * kx) + t_1))) * sin(th);
	elseif (t_4 <= -0.04)
		tmp = t_5;
	elseif (t_4 <= 0.05)
		tmp = (sin(ky) / sqrt((t_3 + (ky * ky)))) * sin(th);
	elseif (t_4 <= 0.8)
		tmp = t_5;
	elseif (t_4 <= 2.0)
		tmp = sin(th);
	else
		tmp = (sin(th) / t_2) / (ky ^ -1.0);
	end
	tmp_2 = tmp;
end
code[kx_, ky_, th_] := Block[{t$95$1 = N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]}, Block[{t$95$2 = N[Sqrt[N[Sin[ky], $MachinePrecision] ^ 2 + N[Sin[kx], $MachinePrecision] ^ 2], $MachinePrecision]}, Block[{t$95$3 = N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision]}, Block[{t$95$4 = N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(t$95$3 + t$95$1), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]}, Block[{t$95$5 = N[(N[((-th) * N[Sin[ky], $MachinePrecision]), $MachinePrecision] * N[(-1.0 / t$95$2), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$4, -0.999], N[(N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[(kx * kx), $MachinePrecision] + t$95$1), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$4, -0.04], t$95$5, If[LessEqual[t$95$4, 0.05], N[(N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(t$95$3 + N[(ky * ky), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$4, 0.8], t$95$5, If[LessEqual[t$95$4, 2.0], N[Sin[th], $MachinePrecision], N[(N[(N[Sin[th], $MachinePrecision] / t$95$2), $MachinePrecision] / N[Power[ky, -1.0], $MachinePrecision]), $MachinePrecision]]]]]]]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := {\sin ky}^{2}\\
t_2 := \mathsf{hypot}\left(\sin ky, \sin kx\right)\\
t_3 := {\sin kx}^{2}\\
t_4 := \frac{\sin ky}{\sqrt{t\_3 + t\_1}}\\
t_5 := \left(\left(-th\right) \cdot \sin ky\right) \cdot \frac{-1}{t\_2}\\
\mathbf{if}\;t\_4 \leq -0.999:\\
\;\;\;\;\frac{\sin ky}{\sqrt{kx \cdot kx + t\_1}} \cdot \sin th\\

\mathbf{elif}\;t\_4 \leq -0.04:\\
\;\;\;\;t\_5\\

\mathbf{elif}\;t\_4 \leq 0.05:\\
\;\;\;\;\frac{\sin ky}{\sqrt{t\_3 + ky \cdot ky}} \cdot \sin th\\

\mathbf{elif}\;t\_4 \leq 0.8:\\
\;\;\;\;t\_5\\

\mathbf{elif}\;t\_4 \leq 2:\\
\;\;\;\;\sin th\\

\mathbf{else}:\\
\;\;\;\;\frac{\frac{\sin th}{t\_2}}{{ky}^{-1}}\\


\end{array}
\end{array}
Derivation
  1. Split input into 5 regimes
  2. if (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < -0.998999999999999999

    1. Initial program 85.1%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in kx around 0

      \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{{kx}^{2}} + {\sin ky}^{2}}} \cdot \sin th \]
    4. Step-by-step derivation
      1. unpow2N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{kx \cdot kx} + {\sin ky}^{2}}} \cdot \sin th \]
      2. lower-*.f6483.1

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{kx \cdot kx} + {\sin ky}^{2}}} \cdot \sin th \]
    5. Applied rewrites83.1%

      \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{kx \cdot kx} + {\sin ky}^{2}}} \cdot \sin th \]

    if -0.998999999999999999 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < -0.0400000000000000008 or 0.050000000000000003 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 0.80000000000000004

    1. Initial program 99.2%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
      2. lift-/.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin th \]
      3. associate-*l/N/A

        \[\leadsto \color{blue}{\frac{\sin ky \cdot \sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      4. frac-2negN/A

        \[\leadsto \color{blue}{\frac{\mathsf{neg}\left(\sin ky \cdot \sin th\right)}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      5. div-invN/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sin ky \cdot \sin th\right)\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      6. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sin ky \cdot \sin th\right)\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      7. distribute-lft-neg-inN/A

        \[\leadsto \color{blue}{\left(\left(\mathsf{neg}\left(\sin ky\right)\right) \cdot \sin th\right)} \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      8. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\left(\mathsf{neg}\left(\sin ky\right)\right) \cdot \sin th\right)} \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      9. lower-neg.f64N/A

        \[\leadsto \left(\color{blue}{\left(-\sin ky\right)} \cdot \sin th\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      10. neg-mul-1N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{1}{\color{blue}{-1 \cdot \sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      11. associate-/r*N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \color{blue}{\frac{\frac{1}{-1}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      12. metadata-evalN/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{\color{blue}{-1}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \]
      13. lower-/.f6499.4

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \color{blue}{\frac{-1}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      14. lift-sqrt.f64N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{-1}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
    4. Applied rewrites99.4%

      \[\leadsto \color{blue}{\left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
    5. Taylor expanded in th around 0

      \[\leadsto \color{blue}{\left(-1 \cdot \left(th \cdot \sin ky\right)\right)} \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
    6. Step-by-step derivation
      1. associate-*r*N/A

        \[\leadsto \color{blue}{\left(\left(-1 \cdot th\right) \cdot \sin ky\right)} \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      2. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\left(-1 \cdot th\right) \cdot \sin ky\right)} \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      3. mul-1-negN/A

        \[\leadsto \left(\color{blue}{\left(\mathsf{neg}\left(th\right)\right)} \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      4. lower-neg.f64N/A

        \[\leadsto \left(\color{blue}{\left(-th\right)} \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      5. lower-sin.f6447.4

        \[\leadsto \left(\left(-th\right) \cdot \color{blue}{\sin ky}\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
    7. Applied rewrites47.4%

      \[\leadsto \color{blue}{\left(\left(-th\right) \cdot \sin ky\right)} \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]

    if -0.0400000000000000008 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 0.050000000000000003

    1. Initial program 98.6%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in ky around 0

      \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{{ky}^{2}}}} \cdot \sin th \]
    4. Step-by-step derivation
      1. unpow2N/A

        \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{ky \cdot ky}}} \cdot \sin th \]
      2. lower-*.f6498.4

        \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{ky \cdot ky}}} \cdot \sin th \]
    5. Applied rewrites98.4%

      \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{ky \cdot ky}}} \cdot \sin th \]

    if 0.80000000000000004 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 2

    1. Initial program 99.0%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in kx around 0

      \[\leadsto \color{blue}{\sin th} \]
    4. Step-by-step derivation
      1. lower-sin.f6486.9

        \[\leadsto \color{blue}{\sin th} \]
    5. Applied rewrites86.9%

      \[\leadsto \color{blue}{\sin th} \]

    if 2 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))

    1. Initial program 2.6%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
      2. *-commutativeN/A

        \[\leadsto \color{blue}{\sin th \cdot \frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      3. lift-/.f64N/A

        \[\leadsto \sin th \cdot \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      4. clear-numN/A

        \[\leadsto \sin th \cdot \color{blue}{\frac{1}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
      5. un-div-invN/A

        \[\leadsto \color{blue}{\frac{\sin th}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
      6. div-invN/A

        \[\leadsto \frac{\sin th}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}} \cdot \frac{1}{\sin ky}}} \]
      7. associate-/r*N/A

        \[\leadsto \color{blue}{\frac{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \]
      8. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \]
    4. Applied rewrites99.6%

      \[\leadsto \color{blue}{\frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{{\sin ky}^{-1}}} \]
    5. Taylor expanded in ky around 0

      \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
    6. Step-by-step derivation
      1. lower-/.f6499.6

        \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
    7. Applied rewrites99.6%

      \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
  3. Recombined 5 regimes into one program.
  4. Final simplification82.1%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq -0.999:\\ \;\;\;\;\frac{\sin ky}{\sqrt{kx \cdot kx + {\sin ky}^{2}}} \cdot \sin th\\ \mathbf{elif}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq -0.04:\\ \;\;\;\;\left(\left(-th\right) \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}\\ \mathbf{elif}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 0.05:\\ \;\;\;\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th\\ \mathbf{elif}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 0.8:\\ \;\;\;\;\left(\left(-th\right) \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}\\ \mathbf{elif}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 2:\\ \;\;\;\;\sin th\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{{ky}^{-1}}\\ \end{array} \]
  5. Add Preprocessing

Alternative 4: 83.1% accurate, 0.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := {\sin ky}^{2}\\ t_2 := \frac{\sin ky}{\sqrt{{\sin kx}^{2} + t\_1}}\\ t_3 := \mathsf{hypot}\left(\sin ky, \sin kx\right)\\ t_4 := \frac{\frac{\sin th}{t\_3}}{{ky}^{-1}}\\ t_5 := \left(\left(-th\right) \cdot \sin ky\right) \cdot \frac{-1}{t\_3}\\ \mathbf{if}\;t\_2 \leq -0.999:\\ \;\;\;\;\frac{\sin ky}{\sqrt{kx \cdot kx + t\_1}} \cdot \sin th\\ \mathbf{elif}\;t\_2 \leq -0.04:\\ \;\;\;\;t\_5\\ \mathbf{elif}\;t\_2 \leq 0.05:\\ \;\;\;\;t\_4\\ \mathbf{elif}\;t\_2 \leq 0.8:\\ \;\;\;\;t\_5\\ \mathbf{elif}\;t\_2 \leq 2:\\ \;\;\;\;\sin th\\ \mathbf{else}:\\ \;\;\;\;t\_4\\ \end{array} \end{array} \]
(FPCore (kx ky th)
 :precision binary64
 (let* ((t_1 (pow (sin ky) 2.0))
        (t_2 (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) t_1))))
        (t_3 (hypot (sin ky) (sin kx)))
        (t_4 (/ (/ (sin th) t_3) (pow ky -1.0)))
        (t_5 (* (* (- th) (sin ky)) (/ -1.0 t_3))))
   (if (<= t_2 -0.999)
     (* (/ (sin ky) (sqrt (+ (* kx kx) t_1))) (sin th))
     (if (<= t_2 -0.04)
       t_5
       (if (<= t_2 0.05)
         t_4
         (if (<= t_2 0.8) t_5 (if (<= t_2 2.0) (sin th) t_4)))))))
double code(double kx, double ky, double th) {
	double t_1 = pow(sin(ky), 2.0);
	double t_2 = sin(ky) / sqrt((pow(sin(kx), 2.0) + t_1));
	double t_3 = hypot(sin(ky), sin(kx));
	double t_4 = (sin(th) / t_3) / pow(ky, -1.0);
	double t_5 = (-th * sin(ky)) * (-1.0 / t_3);
	double tmp;
	if (t_2 <= -0.999) {
		tmp = (sin(ky) / sqrt(((kx * kx) + t_1))) * sin(th);
	} else if (t_2 <= -0.04) {
		tmp = t_5;
	} else if (t_2 <= 0.05) {
		tmp = t_4;
	} else if (t_2 <= 0.8) {
		tmp = t_5;
	} else if (t_2 <= 2.0) {
		tmp = sin(th);
	} else {
		tmp = t_4;
	}
	return tmp;
}
public static double code(double kx, double ky, double th) {
	double t_1 = Math.pow(Math.sin(ky), 2.0);
	double t_2 = Math.sin(ky) / Math.sqrt((Math.pow(Math.sin(kx), 2.0) + t_1));
	double t_3 = Math.hypot(Math.sin(ky), Math.sin(kx));
	double t_4 = (Math.sin(th) / t_3) / Math.pow(ky, -1.0);
	double t_5 = (-th * Math.sin(ky)) * (-1.0 / t_3);
	double tmp;
	if (t_2 <= -0.999) {
		tmp = (Math.sin(ky) / Math.sqrt(((kx * kx) + t_1))) * Math.sin(th);
	} else if (t_2 <= -0.04) {
		tmp = t_5;
	} else if (t_2 <= 0.05) {
		tmp = t_4;
	} else if (t_2 <= 0.8) {
		tmp = t_5;
	} else if (t_2 <= 2.0) {
		tmp = Math.sin(th);
	} else {
		tmp = t_4;
	}
	return tmp;
}
def code(kx, ky, th):
	t_1 = math.pow(math.sin(ky), 2.0)
	t_2 = math.sin(ky) / math.sqrt((math.pow(math.sin(kx), 2.0) + t_1))
	t_3 = math.hypot(math.sin(ky), math.sin(kx))
	t_4 = (math.sin(th) / t_3) / math.pow(ky, -1.0)
	t_5 = (-th * math.sin(ky)) * (-1.0 / t_3)
	tmp = 0
	if t_2 <= -0.999:
		tmp = (math.sin(ky) / math.sqrt(((kx * kx) + t_1))) * math.sin(th)
	elif t_2 <= -0.04:
		tmp = t_5
	elif t_2 <= 0.05:
		tmp = t_4
	elif t_2 <= 0.8:
		tmp = t_5
	elif t_2 <= 2.0:
		tmp = math.sin(th)
	else:
		tmp = t_4
	return tmp
function code(kx, ky, th)
	t_1 = sin(ky) ^ 2.0
	t_2 = Float64(sin(ky) / sqrt(Float64((sin(kx) ^ 2.0) + t_1)))
	t_3 = hypot(sin(ky), sin(kx))
	t_4 = Float64(Float64(sin(th) / t_3) / (ky ^ -1.0))
	t_5 = Float64(Float64(Float64(-th) * sin(ky)) * Float64(-1.0 / t_3))
	tmp = 0.0
	if (t_2 <= -0.999)
		tmp = Float64(Float64(sin(ky) / sqrt(Float64(Float64(kx * kx) + t_1))) * sin(th));
	elseif (t_2 <= -0.04)
		tmp = t_5;
	elseif (t_2 <= 0.05)
		tmp = t_4;
	elseif (t_2 <= 0.8)
		tmp = t_5;
	elseif (t_2 <= 2.0)
		tmp = sin(th);
	else
		tmp = t_4;
	end
	return tmp
end
function tmp_2 = code(kx, ky, th)
	t_1 = sin(ky) ^ 2.0;
	t_2 = sin(ky) / sqrt(((sin(kx) ^ 2.0) + t_1));
	t_3 = hypot(sin(ky), sin(kx));
	t_4 = (sin(th) / t_3) / (ky ^ -1.0);
	t_5 = (-th * sin(ky)) * (-1.0 / t_3);
	tmp = 0.0;
	if (t_2 <= -0.999)
		tmp = (sin(ky) / sqrt(((kx * kx) + t_1))) * sin(th);
	elseif (t_2 <= -0.04)
		tmp = t_5;
	elseif (t_2 <= 0.05)
		tmp = t_4;
	elseif (t_2 <= 0.8)
		tmp = t_5;
	elseif (t_2 <= 2.0)
		tmp = sin(th);
	else
		tmp = t_4;
	end
	tmp_2 = tmp;
end
code[kx_, ky_, th_] := Block[{t$95$1 = N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]}, Block[{t$95$2 = N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + t$95$1), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = N[Sqrt[N[Sin[ky], $MachinePrecision] ^ 2 + N[Sin[kx], $MachinePrecision] ^ 2], $MachinePrecision]}, Block[{t$95$4 = N[(N[(N[Sin[th], $MachinePrecision] / t$95$3), $MachinePrecision] / N[Power[ky, -1.0], $MachinePrecision]), $MachinePrecision]}, Block[{t$95$5 = N[(N[((-th) * N[Sin[ky], $MachinePrecision]), $MachinePrecision] * N[(-1.0 / t$95$3), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$2, -0.999], N[(N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[(kx * kx), $MachinePrecision] + t$95$1), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$2, -0.04], t$95$5, If[LessEqual[t$95$2, 0.05], t$95$4, If[LessEqual[t$95$2, 0.8], t$95$5, If[LessEqual[t$95$2, 2.0], N[Sin[th], $MachinePrecision], t$95$4]]]]]]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := {\sin ky}^{2}\\
t_2 := \frac{\sin ky}{\sqrt{{\sin kx}^{2} + t\_1}}\\
t_3 := \mathsf{hypot}\left(\sin ky, \sin kx\right)\\
t_4 := \frac{\frac{\sin th}{t\_3}}{{ky}^{-1}}\\
t_5 := \left(\left(-th\right) \cdot \sin ky\right) \cdot \frac{-1}{t\_3}\\
\mathbf{if}\;t\_2 \leq -0.999:\\
\;\;\;\;\frac{\sin ky}{\sqrt{kx \cdot kx + t\_1}} \cdot \sin th\\

\mathbf{elif}\;t\_2 \leq -0.04:\\
\;\;\;\;t\_5\\

\mathbf{elif}\;t\_2 \leq 0.05:\\
\;\;\;\;t\_4\\

\mathbf{elif}\;t\_2 \leq 0.8:\\
\;\;\;\;t\_5\\

\mathbf{elif}\;t\_2 \leq 2:\\
\;\;\;\;\sin th\\

\mathbf{else}:\\
\;\;\;\;t\_4\\


\end{array}
\end{array}
Derivation
  1. Split input into 4 regimes
  2. if (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < -0.998999999999999999

    1. Initial program 85.1%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in kx around 0

      \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{{kx}^{2}} + {\sin ky}^{2}}} \cdot \sin th \]
    4. Step-by-step derivation
      1. unpow2N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{kx \cdot kx} + {\sin ky}^{2}}} \cdot \sin th \]
      2. lower-*.f6483.1

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{kx \cdot kx} + {\sin ky}^{2}}} \cdot \sin th \]
    5. Applied rewrites83.1%

      \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{kx \cdot kx} + {\sin ky}^{2}}} \cdot \sin th \]

    if -0.998999999999999999 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < -0.0400000000000000008 or 0.050000000000000003 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 0.80000000000000004

    1. Initial program 99.2%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
      2. lift-/.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin th \]
      3. associate-*l/N/A

        \[\leadsto \color{blue}{\frac{\sin ky \cdot \sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      4. frac-2negN/A

        \[\leadsto \color{blue}{\frac{\mathsf{neg}\left(\sin ky \cdot \sin th\right)}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      5. div-invN/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sin ky \cdot \sin th\right)\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      6. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sin ky \cdot \sin th\right)\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      7. distribute-lft-neg-inN/A

        \[\leadsto \color{blue}{\left(\left(\mathsf{neg}\left(\sin ky\right)\right) \cdot \sin th\right)} \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      8. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\left(\mathsf{neg}\left(\sin ky\right)\right) \cdot \sin th\right)} \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      9. lower-neg.f64N/A

        \[\leadsto \left(\color{blue}{\left(-\sin ky\right)} \cdot \sin th\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      10. neg-mul-1N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{1}{\color{blue}{-1 \cdot \sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      11. associate-/r*N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \color{blue}{\frac{\frac{1}{-1}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      12. metadata-evalN/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{\color{blue}{-1}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \]
      13. lower-/.f6499.4

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \color{blue}{\frac{-1}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      14. lift-sqrt.f64N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{-1}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
    4. Applied rewrites99.4%

      \[\leadsto \color{blue}{\left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
    5. Taylor expanded in th around 0

      \[\leadsto \color{blue}{\left(-1 \cdot \left(th \cdot \sin ky\right)\right)} \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
    6. Step-by-step derivation
      1. associate-*r*N/A

        \[\leadsto \color{blue}{\left(\left(-1 \cdot th\right) \cdot \sin ky\right)} \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      2. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\left(-1 \cdot th\right) \cdot \sin ky\right)} \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      3. mul-1-negN/A

        \[\leadsto \left(\color{blue}{\left(\mathsf{neg}\left(th\right)\right)} \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      4. lower-neg.f64N/A

        \[\leadsto \left(\color{blue}{\left(-th\right)} \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      5. lower-sin.f6447.4

        \[\leadsto \left(\left(-th\right) \cdot \color{blue}{\sin ky}\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
    7. Applied rewrites47.4%

      \[\leadsto \color{blue}{\left(\left(-th\right) \cdot \sin ky\right)} \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]

    if -0.0400000000000000008 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 0.050000000000000003 or 2 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))

    1. Initial program 92.5%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
      2. *-commutativeN/A

        \[\leadsto \color{blue}{\sin th \cdot \frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      3. lift-/.f64N/A

        \[\leadsto \sin th \cdot \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      4. clear-numN/A

        \[\leadsto \sin th \cdot \color{blue}{\frac{1}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
      5. un-div-invN/A

        \[\leadsto \color{blue}{\frac{\sin th}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
      6. div-invN/A

        \[\leadsto \frac{\sin th}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}} \cdot \frac{1}{\sin ky}}} \]
      7. associate-/r*N/A

        \[\leadsto \color{blue}{\frac{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \]
      8. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \]
    4. Applied rewrites99.4%

      \[\leadsto \color{blue}{\frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{{\sin ky}^{-1}}} \]
    5. Taylor expanded in ky around 0

      \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
    6. Step-by-step derivation
      1. lower-/.f6498.3

        \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
    7. Applied rewrites98.3%

      \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]

    if 0.80000000000000004 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 2

    1. Initial program 99.0%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in kx around 0

      \[\leadsto \color{blue}{\sin th} \]
    4. Step-by-step derivation
      1. lower-sin.f6486.9

        \[\leadsto \color{blue}{\sin th} \]
    5. Applied rewrites86.9%

      \[\leadsto \color{blue}{\sin th} \]
  3. Recombined 4 regimes into one program.
  4. Final simplification82.0%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq -0.999:\\ \;\;\;\;\frac{\sin ky}{\sqrt{kx \cdot kx + {\sin ky}^{2}}} \cdot \sin th\\ \mathbf{elif}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq -0.04:\\ \;\;\;\;\left(\left(-th\right) \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}\\ \mathbf{elif}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 0.05:\\ \;\;\;\;\frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{{ky}^{-1}}\\ \mathbf{elif}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 0.8:\\ \;\;\;\;\left(\left(-th\right) \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}\\ \mathbf{elif}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 2:\\ \;\;\;\;\sin th\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{{ky}^{-1}}\\ \end{array} \]
  5. Add Preprocessing

Alternative 5: 44.0% accurate, 0.7× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 4 \cdot 10^{-5}:\\ \;\;\;\;\frac{\left(-\sin th\right) \cdot \frac{-1}{\sin kx}}{{ky}^{-1}}\\ \mathbf{else}:\\ \;\;\;\;\sin th\\ \end{array} \end{array} \]
(FPCore (kx ky th)
 :precision binary64
 (if (<= (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0)))) 4e-5)
   (/ (* (- (sin th)) (/ -1.0 (sin kx))) (pow ky -1.0))
   (sin th)))
double code(double kx, double ky, double th) {
	double tmp;
	if ((sin(ky) / sqrt((pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))) <= 4e-5) {
		tmp = (-sin(th) * (-1.0 / sin(kx))) / pow(ky, -1.0);
	} else {
		tmp = sin(th);
	}
	return tmp;
}
real(8) function code(kx, ky, th)
    real(8), intent (in) :: kx
    real(8), intent (in) :: ky
    real(8), intent (in) :: th
    real(8) :: tmp
    if ((sin(ky) / sqrt(((sin(kx) ** 2.0d0) + (sin(ky) ** 2.0d0)))) <= 4d-5) then
        tmp = (-sin(th) * ((-1.0d0) / sin(kx))) / (ky ** (-1.0d0))
    else
        tmp = sin(th)
    end if
    code = tmp
end function
public static double code(double kx, double ky, double th) {
	double tmp;
	if ((Math.sin(ky) / Math.sqrt((Math.pow(Math.sin(kx), 2.0) + Math.pow(Math.sin(ky), 2.0)))) <= 4e-5) {
		tmp = (-Math.sin(th) * (-1.0 / Math.sin(kx))) / Math.pow(ky, -1.0);
	} else {
		tmp = Math.sin(th);
	}
	return tmp;
}
def code(kx, ky, th):
	tmp = 0
	if (math.sin(ky) / math.sqrt((math.pow(math.sin(kx), 2.0) + math.pow(math.sin(ky), 2.0)))) <= 4e-5:
		tmp = (-math.sin(th) * (-1.0 / math.sin(kx))) / math.pow(ky, -1.0)
	else:
		tmp = math.sin(th)
	return tmp
function code(kx, ky, th)
	tmp = 0.0
	if (Float64(sin(ky) / sqrt(Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) <= 4e-5)
		tmp = Float64(Float64(Float64(-sin(th)) * Float64(-1.0 / sin(kx))) / (ky ^ -1.0));
	else
		tmp = sin(th);
	end
	return tmp
end
function tmp_2 = code(kx, ky, th)
	tmp = 0.0;
	if ((sin(ky) / sqrt(((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) <= 4e-5)
		tmp = (-sin(th) * (-1.0 / sin(kx))) / (ky ^ -1.0);
	else
		tmp = sin(th);
	end
	tmp_2 = tmp;
end
code[kx_, ky_, th_] := If[LessEqual[N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 4e-5], N[(N[((-N[Sin[th], $MachinePrecision]) * N[(-1.0 / N[Sin[kx], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[Power[ky, -1.0], $MachinePrecision]), $MachinePrecision], N[Sin[th], $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 4 \cdot 10^{-5}:\\
\;\;\;\;\frac{\left(-\sin th\right) \cdot \frac{-1}{\sin kx}}{{ky}^{-1}}\\

\mathbf{else}:\\
\;\;\;\;\sin th\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 4.00000000000000033e-5

    1. Initial program 95.2%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
      2. *-commutativeN/A

        \[\leadsto \color{blue}{\sin th \cdot \frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      3. lift-/.f64N/A

        \[\leadsto \sin th \cdot \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      4. clear-numN/A

        \[\leadsto \sin th \cdot \color{blue}{\frac{1}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
      5. un-div-invN/A

        \[\leadsto \color{blue}{\frac{\sin th}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
      6. div-invN/A

        \[\leadsto \frac{\sin th}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}} \cdot \frac{1}{\sin ky}}} \]
      7. associate-/r*N/A

        \[\leadsto \color{blue}{\frac{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \]
      8. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \]
    4. Applied rewrites99.4%

      \[\leadsto \color{blue}{\frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{{\sin ky}^{-1}}} \]
    5. Taylor expanded in ky around 0

      \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
    6. Step-by-step derivation
      1. lower-/.f6466.8

        \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
    7. Applied rewrites66.8%

      \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
    8. Step-by-step derivation
      1. lift-/.f64N/A

        \[\leadsto \frac{\color{blue}{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}}{\frac{1}{ky}} \]
      2. frac-2negN/A

        \[\leadsto \frac{\color{blue}{\frac{\mathsf{neg}\left(\sin th\right)}{\mathsf{neg}\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}}}{\frac{1}{ky}} \]
      3. div-invN/A

        \[\leadsto \frac{\color{blue}{\left(\mathsf{neg}\left(\sin th\right)\right) \cdot \frac{1}{\mathsf{neg}\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}}}{\frac{1}{ky}} \]
      4. distribute-neg-frac2N/A

        \[\leadsto \frac{\left(\mathsf{neg}\left(\sin th\right)\right) \cdot \color{blue}{\left(\mathsf{neg}\left(\frac{1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}\right)\right)}}{\frac{1}{ky}} \]
      5. unpow-1N/A

        \[\leadsto \frac{\left(\mathsf{neg}\left(\sin th\right)\right) \cdot \left(\mathsf{neg}\left(\color{blue}{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}\right)\right)}{\frac{1}{ky}} \]
      6. lift-pow.f64N/A

        \[\leadsto \frac{\left(\mathsf{neg}\left(\sin th\right)\right) \cdot \left(\mathsf{neg}\left(\color{blue}{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}\right)\right)}{\frac{1}{ky}} \]
      7. lower-*.f64N/A

        \[\leadsto \frac{\color{blue}{\left(\mathsf{neg}\left(\sin th\right)\right) \cdot \left(\mathsf{neg}\left({\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}\right)\right)}}{\frac{1}{ky}} \]
      8. lower-neg.f64N/A

        \[\leadsto \frac{\color{blue}{\left(-\sin th\right)} \cdot \left(\mathsf{neg}\left({\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}\right)\right)}{\frac{1}{ky}} \]
      9. lift-pow.f64N/A

        \[\leadsto \frac{\left(-\sin th\right) \cdot \left(\mathsf{neg}\left(\color{blue}{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}\right)\right)}{\frac{1}{ky}} \]
      10. unpow-1N/A

        \[\leadsto \frac{\left(-\sin th\right) \cdot \left(\mathsf{neg}\left(\color{blue}{\frac{1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}\right)\right)}{\frac{1}{ky}} \]
      11. distribute-neg-fracN/A

        \[\leadsto \frac{\left(-\sin th\right) \cdot \color{blue}{\frac{\mathsf{neg}\left(1\right)}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}}{\frac{1}{ky}} \]
      12. metadata-evalN/A

        \[\leadsto \frac{\left(-\sin th\right) \cdot \frac{\color{blue}{-1}}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\frac{1}{ky}} \]
      13. lower-/.f6466.8

        \[\leadsto \frac{\left(-\sin th\right) \cdot \color{blue}{\frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}}{\frac{1}{ky}} \]
      14. lift-sin.f64N/A

        \[\leadsto \frac{\left(-\sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \color{blue}{\sin kx}\right)}}{\frac{1}{ky}} \]
      15. lift-hypot.f64N/A

        \[\leadsto \frac{\left(-\sin th\right) \cdot \frac{-1}{\color{blue}{\sqrt{\sin ky \cdot \sin ky + \sin kx \cdot \sin kx}}}}{\frac{1}{ky}} \]
      16. +-commutativeN/A

        \[\leadsto \frac{\left(-\sin th\right) \cdot \frac{-1}{\sqrt{\color{blue}{\sin kx \cdot \sin kx + \sin ky \cdot \sin ky}}}}{\frac{1}{ky}} \]
      17. lower-hypot.f64N/A

        \[\leadsto \frac{\left(-\sin th\right) \cdot \frac{-1}{\color{blue}{\mathsf{hypot}\left(\sin kx, \sin ky\right)}}}{\frac{1}{ky}} \]
      18. lift-sin.f6466.8

        \[\leadsto \frac{\left(-\sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\color{blue}{\sin kx}, \sin ky\right)}}{\frac{1}{ky}} \]
    9. Applied rewrites66.8%

      \[\leadsto \frac{\color{blue}{\left(-\sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)}}}{\frac{1}{ky}} \]
    10. Taylor expanded in ky around 0

      \[\leadsto \frac{\left(-\sin th\right) \cdot \color{blue}{\frac{-1}{\sin kx}}}{\frac{1}{ky}} \]
    11. Step-by-step derivation
      1. lower-/.f64N/A

        \[\leadsto \frac{\left(-\sin th\right) \cdot \color{blue}{\frac{-1}{\sin kx}}}{\frac{1}{ky}} \]
      2. lower-sin.f6437.4

        \[\leadsto \frac{\left(-\sin th\right) \cdot \frac{-1}{\color{blue}{\sin kx}}}{\frac{1}{ky}} \]
    12. Applied rewrites37.4%

      \[\leadsto \frac{\left(-\sin th\right) \cdot \color{blue}{\frac{-1}{\sin kx}}}{\frac{1}{ky}} \]

    if 4.00000000000000033e-5 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))

    1. Initial program 90.5%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in kx around 0

      \[\leadsto \color{blue}{\sin th} \]
    4. Step-by-step derivation
      1. lower-sin.f6456.6

        \[\leadsto \color{blue}{\sin th} \]
    5. Applied rewrites56.6%

      \[\leadsto \color{blue}{\sin th} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification43.4%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 4 \cdot 10^{-5}:\\ \;\;\;\;\frac{\left(-\sin th\right) \cdot \frac{-1}{\sin kx}}{{ky}^{-1}}\\ \mathbf{else}:\\ \;\;\;\;\sin th\\ \end{array} \]
  5. Add Preprocessing

Alternative 6: 44.0% accurate, 0.7× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 4 \cdot 10^{-5}:\\ \;\;\;\;\frac{\frac{\sin th}{\sin kx}}{{ky}^{-1}}\\ \mathbf{else}:\\ \;\;\;\;\sin th\\ \end{array} \end{array} \]
(FPCore (kx ky th)
 :precision binary64
 (if (<= (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0)))) 4e-5)
   (/ (/ (sin th) (sin kx)) (pow ky -1.0))
   (sin th)))
double code(double kx, double ky, double th) {
	double tmp;
	if ((sin(ky) / sqrt((pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))) <= 4e-5) {
		tmp = (sin(th) / sin(kx)) / pow(ky, -1.0);
	} else {
		tmp = sin(th);
	}
	return tmp;
}
real(8) function code(kx, ky, th)
    real(8), intent (in) :: kx
    real(8), intent (in) :: ky
    real(8), intent (in) :: th
    real(8) :: tmp
    if ((sin(ky) / sqrt(((sin(kx) ** 2.0d0) + (sin(ky) ** 2.0d0)))) <= 4d-5) then
        tmp = (sin(th) / sin(kx)) / (ky ** (-1.0d0))
    else
        tmp = sin(th)
    end if
    code = tmp
end function
public static double code(double kx, double ky, double th) {
	double tmp;
	if ((Math.sin(ky) / Math.sqrt((Math.pow(Math.sin(kx), 2.0) + Math.pow(Math.sin(ky), 2.0)))) <= 4e-5) {
		tmp = (Math.sin(th) / Math.sin(kx)) / Math.pow(ky, -1.0);
	} else {
		tmp = Math.sin(th);
	}
	return tmp;
}
def code(kx, ky, th):
	tmp = 0
	if (math.sin(ky) / math.sqrt((math.pow(math.sin(kx), 2.0) + math.pow(math.sin(ky), 2.0)))) <= 4e-5:
		tmp = (math.sin(th) / math.sin(kx)) / math.pow(ky, -1.0)
	else:
		tmp = math.sin(th)
	return tmp
function code(kx, ky, th)
	tmp = 0.0
	if (Float64(sin(ky) / sqrt(Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) <= 4e-5)
		tmp = Float64(Float64(sin(th) / sin(kx)) / (ky ^ -1.0));
	else
		tmp = sin(th);
	end
	return tmp
end
function tmp_2 = code(kx, ky, th)
	tmp = 0.0;
	if ((sin(ky) / sqrt(((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) <= 4e-5)
		tmp = (sin(th) / sin(kx)) / (ky ^ -1.0);
	else
		tmp = sin(th);
	end
	tmp_2 = tmp;
end
code[kx_, ky_, th_] := If[LessEqual[N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 4e-5], N[(N[(N[Sin[th], $MachinePrecision] / N[Sin[kx], $MachinePrecision]), $MachinePrecision] / N[Power[ky, -1.0], $MachinePrecision]), $MachinePrecision], N[Sin[th], $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 4 \cdot 10^{-5}:\\
\;\;\;\;\frac{\frac{\sin th}{\sin kx}}{{ky}^{-1}}\\

\mathbf{else}:\\
\;\;\;\;\sin th\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 4.00000000000000033e-5

    1. Initial program 95.2%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
      2. *-commutativeN/A

        \[\leadsto \color{blue}{\sin th \cdot \frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      3. lift-/.f64N/A

        \[\leadsto \sin th \cdot \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      4. clear-numN/A

        \[\leadsto \sin th \cdot \color{blue}{\frac{1}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
      5. un-div-invN/A

        \[\leadsto \color{blue}{\frac{\sin th}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
      6. div-invN/A

        \[\leadsto \frac{\sin th}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}} \cdot \frac{1}{\sin ky}}} \]
      7. associate-/r*N/A

        \[\leadsto \color{blue}{\frac{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \]
      8. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \]
    4. Applied rewrites99.4%

      \[\leadsto \color{blue}{\frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{{\sin ky}^{-1}}} \]
    5. Taylor expanded in ky around 0

      \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
    6. Step-by-step derivation
      1. lower-/.f6466.8

        \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
    7. Applied rewrites66.8%

      \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
    8. Taylor expanded in ky around 0

      \[\leadsto \frac{\color{blue}{\frac{\sin th}{\sin kx}}}{\frac{1}{ky}} \]
    9. Step-by-step derivation
      1. lower-/.f64N/A

        \[\leadsto \frac{\color{blue}{\frac{\sin th}{\sin kx}}}{\frac{1}{ky}} \]
      2. lower-sin.f64N/A

        \[\leadsto \frac{\frac{\color{blue}{\sin th}}{\sin kx}}{\frac{1}{ky}} \]
      3. lower-sin.f6437.4

        \[\leadsto \frac{\frac{\sin th}{\color{blue}{\sin kx}}}{\frac{1}{ky}} \]
    10. Applied rewrites37.4%

      \[\leadsto \frac{\color{blue}{\frac{\sin th}{\sin kx}}}{\frac{1}{ky}} \]

    if 4.00000000000000033e-5 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))

    1. Initial program 90.5%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in kx around 0

      \[\leadsto \color{blue}{\sin th} \]
    4. Step-by-step derivation
      1. lower-sin.f6456.6

        \[\leadsto \color{blue}{\sin th} \]
    5. Applied rewrites56.6%

      \[\leadsto \color{blue}{\sin th} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification43.4%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 4 \cdot 10^{-5}:\\ \;\;\;\;\frac{\frac{\sin th}{\sin kx}}{{ky}^{-1}}\\ \mathbf{else}:\\ \;\;\;\;\sin th\\ \end{array} \]
  5. Add Preprocessing

Alternative 7: 45.2% accurate, 0.7× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 4 \cdot 10^{-5}:\\ \;\;\;\;\frac{\sin ky}{\frac{\sin kx}{\sin th}}\\ \mathbf{else}:\\ \;\;\;\;\sin th\\ \end{array} \end{array} \]
(FPCore (kx ky th)
 :precision binary64
 (if (<= (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0)))) 4e-5)
   (/ (sin ky) (/ (sin kx) (sin th)))
   (sin th)))
double code(double kx, double ky, double th) {
	double tmp;
	if ((sin(ky) / sqrt((pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))) <= 4e-5) {
		tmp = sin(ky) / (sin(kx) / sin(th));
	} else {
		tmp = sin(th);
	}
	return tmp;
}
real(8) function code(kx, ky, th)
    real(8), intent (in) :: kx
    real(8), intent (in) :: ky
    real(8), intent (in) :: th
    real(8) :: tmp
    if ((sin(ky) / sqrt(((sin(kx) ** 2.0d0) + (sin(ky) ** 2.0d0)))) <= 4d-5) then
        tmp = sin(ky) / (sin(kx) / sin(th))
    else
        tmp = sin(th)
    end if
    code = tmp
end function
public static double code(double kx, double ky, double th) {
	double tmp;
	if ((Math.sin(ky) / Math.sqrt((Math.pow(Math.sin(kx), 2.0) + Math.pow(Math.sin(ky), 2.0)))) <= 4e-5) {
		tmp = Math.sin(ky) / (Math.sin(kx) / Math.sin(th));
	} else {
		tmp = Math.sin(th);
	}
	return tmp;
}
def code(kx, ky, th):
	tmp = 0
	if (math.sin(ky) / math.sqrt((math.pow(math.sin(kx), 2.0) + math.pow(math.sin(ky), 2.0)))) <= 4e-5:
		tmp = math.sin(ky) / (math.sin(kx) / math.sin(th))
	else:
		tmp = math.sin(th)
	return tmp
function code(kx, ky, th)
	tmp = 0.0
	if (Float64(sin(ky) / sqrt(Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) <= 4e-5)
		tmp = Float64(sin(ky) / Float64(sin(kx) / sin(th)));
	else
		tmp = sin(th);
	end
	return tmp
end
function tmp_2 = code(kx, ky, th)
	tmp = 0.0;
	if ((sin(ky) / sqrt(((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) <= 4e-5)
		tmp = sin(ky) / (sin(kx) / sin(th));
	else
		tmp = sin(th);
	end
	tmp_2 = tmp;
end
code[kx_, ky_, th_] := If[LessEqual[N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 4e-5], N[(N[Sin[ky], $MachinePrecision] / N[(N[Sin[kx], $MachinePrecision] / N[Sin[th], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[Sin[th], $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 4 \cdot 10^{-5}:\\
\;\;\;\;\frac{\sin ky}{\frac{\sin kx}{\sin th}}\\

\mathbf{else}:\\
\;\;\;\;\sin th\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 4.00000000000000033e-5

    1. Initial program 95.2%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-/.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin th \]
      2. clear-numN/A

        \[\leadsto \color{blue}{\frac{1}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \cdot \sin th \]
      3. div-invN/A

        \[\leadsto \frac{1}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}} \cdot \frac{1}{\sin ky}}} \cdot \sin th \]
      4. associate-/r*N/A

        \[\leadsto \color{blue}{\frac{\frac{1}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \cdot \sin th \]
      5. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{\frac{1}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \cdot \sin th \]
      6. inv-powN/A

        \[\leadsto \frac{\color{blue}{{\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}^{-1}}}{\frac{1}{\sin ky}} \cdot \sin th \]
      7. lower-pow.f64N/A

        \[\leadsto \frac{\color{blue}{{\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}^{-1}}}{\frac{1}{\sin ky}} \cdot \sin th \]
      8. lift-sqrt.f64N/A

        \[\leadsto \frac{{\color{blue}{\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}}^{-1}}{\frac{1}{\sin ky}} \cdot \sin th \]
      9. lift-+.f64N/A

        \[\leadsto \frac{{\left(\sqrt{\color{blue}{{\sin kx}^{2} + {\sin ky}^{2}}}\right)}^{-1}}{\frac{1}{\sin ky}} \cdot \sin th \]
      10. +-commutativeN/A

        \[\leadsto \frac{{\left(\sqrt{\color{blue}{{\sin ky}^{2} + {\sin kx}^{2}}}\right)}^{-1}}{\frac{1}{\sin ky}} \cdot \sin th \]
      11. lift-pow.f64N/A

        \[\leadsto \frac{{\left(\sqrt{\color{blue}{{\sin ky}^{2}} + {\sin kx}^{2}}\right)}^{-1}}{\frac{1}{\sin ky}} \cdot \sin th \]
      12. unpow2N/A

        \[\leadsto \frac{{\left(\sqrt{\color{blue}{\sin ky \cdot \sin ky} + {\sin kx}^{2}}\right)}^{-1}}{\frac{1}{\sin ky}} \cdot \sin th \]
      13. lift-pow.f64N/A

        \[\leadsto \frac{{\left(\sqrt{\sin ky \cdot \sin ky + \color{blue}{{\sin kx}^{2}}}\right)}^{-1}}{\frac{1}{\sin ky}} \cdot \sin th \]
      14. unpow2N/A

        \[\leadsto \frac{{\left(\sqrt{\sin ky \cdot \sin ky + \color{blue}{\sin kx \cdot \sin kx}}\right)}^{-1}}{\frac{1}{\sin ky}} \cdot \sin th \]
      15. lower-hypot.f64N/A

        \[\leadsto \frac{{\color{blue}{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}}^{-1}}{\frac{1}{\sin ky}} \cdot \sin th \]
      16. inv-powN/A

        \[\leadsto \frac{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}{\color{blue}{{\sin ky}^{-1}}} \cdot \sin th \]
      17. lower-pow.f6499.5

        \[\leadsto \frac{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}{\color{blue}{{\sin ky}^{-1}}} \cdot \sin th \]
    4. Applied rewrites99.5%

      \[\leadsto \color{blue}{\frac{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}{{\sin ky}^{-1}}} \cdot \sin th \]
    5. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{\frac{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}{{\sin ky}^{-1}} \cdot \sin th} \]
      2. lift-/.f64N/A

        \[\leadsto \color{blue}{\frac{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}{{\sin ky}^{-1}}} \cdot \sin th \]
      3. clear-numN/A

        \[\leadsto \color{blue}{\frac{1}{\frac{{\sin ky}^{-1}}{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}}} \cdot \sin th \]
      4. associate-*l/N/A

        \[\leadsto \color{blue}{\frac{1 \cdot \sin th}{\frac{{\sin ky}^{-1}}{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}}} \]
      5. lift-pow.f64N/A

        \[\leadsto \frac{1 \cdot \sin th}{\frac{{\sin ky}^{-1}}{\color{blue}{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}}} \]
      6. unpow-1N/A

        \[\leadsto \frac{1 \cdot \sin th}{\frac{{\sin ky}^{-1}}{\color{blue}{\frac{1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}}} \]
      7. associate-/r/N/A

        \[\leadsto \frac{1 \cdot \sin th}{\color{blue}{\frac{{\sin ky}^{-1}}{1} \cdot \mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
      8. times-fracN/A

        \[\leadsto \color{blue}{\frac{1}{\frac{{\sin ky}^{-1}}{1}} \cdot \frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
      9. clear-numN/A

        \[\leadsto \color{blue}{\frac{1}{{\sin ky}^{-1}}} \cdot \frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      10. lift-pow.f64N/A

        \[\leadsto \frac{1}{\color{blue}{{\sin ky}^{-1}}} \cdot \frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      11. unpow-1N/A

        \[\leadsto \frac{1}{\color{blue}{\frac{1}{\sin ky}}} \cdot \frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      12. remove-double-divN/A

        \[\leadsto \color{blue}{\sin ky} \cdot \frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      13. clear-numN/A

        \[\leadsto \sin ky \cdot \color{blue}{\frac{1}{\frac{\mathsf{hypot}\left(\sin ky, \sin kx\right)}{\sin th}}} \]
      14. un-div-invN/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\frac{\mathsf{hypot}\left(\sin ky, \sin kx\right)}{\sin th}}} \]
      15. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\frac{\mathsf{hypot}\left(\sin ky, \sin kx\right)}{\sin th}}} \]
    6. Applied rewrites99.6%

      \[\leadsto \color{blue}{\frac{\sin ky}{\frac{\mathsf{hypot}\left(\sin kx, \sin ky\right)}{\sin th}}} \]
    7. Taylor expanded in ky around 0

      \[\leadsto \frac{\sin ky}{\color{blue}{\frac{\sin kx}{\sin th}}} \]
    8. Step-by-step derivation
      1. lower-/.f64N/A

        \[\leadsto \frac{\sin ky}{\color{blue}{\frac{\sin kx}{\sin th}}} \]
      2. lower-sin.f64N/A

        \[\leadsto \frac{\sin ky}{\frac{\color{blue}{\sin kx}}{\sin th}} \]
      3. lower-sin.f6438.3

        \[\leadsto \frac{\sin ky}{\frac{\sin kx}{\color{blue}{\sin th}}} \]
    9. Applied rewrites38.3%

      \[\leadsto \frac{\sin ky}{\color{blue}{\frac{\sin kx}{\sin th}}} \]

    if 4.00000000000000033e-5 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))

    1. Initial program 90.5%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in kx around 0

      \[\leadsto \color{blue}{\sin th} \]
    4. Step-by-step derivation
      1. lower-sin.f6456.6

        \[\leadsto \color{blue}{\sin th} \]
    5. Applied rewrites56.6%

      \[\leadsto \color{blue}{\sin th} \]
  3. Recombined 2 regimes into one program.
  4. Add Preprocessing

Alternative 8: 45.2% accurate, 0.7× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 4 \cdot 10^{-5}:\\ \;\;\;\;\frac{\sin ky}{\sin kx} \cdot \sin th\\ \mathbf{else}:\\ \;\;\;\;\sin th\\ \end{array} \end{array} \]
(FPCore (kx ky th)
 :precision binary64
 (if (<= (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0)))) 4e-5)
   (* (/ (sin ky) (sin kx)) (sin th))
   (sin th)))
double code(double kx, double ky, double th) {
	double tmp;
	if ((sin(ky) / sqrt((pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))) <= 4e-5) {
		tmp = (sin(ky) / sin(kx)) * sin(th);
	} else {
		tmp = sin(th);
	}
	return tmp;
}
real(8) function code(kx, ky, th)
    real(8), intent (in) :: kx
    real(8), intent (in) :: ky
    real(8), intent (in) :: th
    real(8) :: tmp
    if ((sin(ky) / sqrt(((sin(kx) ** 2.0d0) + (sin(ky) ** 2.0d0)))) <= 4d-5) then
        tmp = (sin(ky) / sin(kx)) * sin(th)
    else
        tmp = sin(th)
    end if
    code = tmp
end function
public static double code(double kx, double ky, double th) {
	double tmp;
	if ((Math.sin(ky) / Math.sqrt((Math.pow(Math.sin(kx), 2.0) + Math.pow(Math.sin(ky), 2.0)))) <= 4e-5) {
		tmp = (Math.sin(ky) / Math.sin(kx)) * Math.sin(th);
	} else {
		tmp = Math.sin(th);
	}
	return tmp;
}
def code(kx, ky, th):
	tmp = 0
	if (math.sin(ky) / math.sqrt((math.pow(math.sin(kx), 2.0) + math.pow(math.sin(ky), 2.0)))) <= 4e-5:
		tmp = (math.sin(ky) / math.sin(kx)) * math.sin(th)
	else:
		tmp = math.sin(th)
	return tmp
function code(kx, ky, th)
	tmp = 0.0
	if (Float64(sin(ky) / sqrt(Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) <= 4e-5)
		tmp = Float64(Float64(sin(ky) / sin(kx)) * sin(th));
	else
		tmp = sin(th);
	end
	return tmp
end
function tmp_2 = code(kx, ky, th)
	tmp = 0.0;
	if ((sin(ky) / sqrt(((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) <= 4e-5)
		tmp = (sin(ky) / sin(kx)) * sin(th);
	else
		tmp = sin(th);
	end
	tmp_2 = tmp;
end
code[kx_, ky_, th_] := If[LessEqual[N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 4e-5], N[(N[(N[Sin[ky], $MachinePrecision] / N[Sin[kx], $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision], N[Sin[th], $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 4 \cdot 10^{-5}:\\
\;\;\;\;\frac{\sin ky}{\sin kx} \cdot \sin th\\

\mathbf{else}:\\
\;\;\;\;\sin th\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 4.00000000000000033e-5

    1. Initial program 95.2%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in ky around 0

      \[\leadsto \frac{\sin ky}{\color{blue}{\sin kx}} \cdot \sin th \]
    4. Step-by-step derivation
      1. lower-sin.f6438.3

        \[\leadsto \frac{\sin ky}{\color{blue}{\sin kx}} \cdot \sin th \]
    5. Applied rewrites38.3%

      \[\leadsto \frac{\sin ky}{\color{blue}{\sin kx}} \cdot \sin th \]

    if 4.00000000000000033e-5 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))

    1. Initial program 90.5%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in kx around 0

      \[\leadsto \color{blue}{\sin th} \]
    4. Step-by-step derivation
      1. lower-sin.f6456.6

        \[\leadsto \color{blue}{\sin th} \]
    5. Applied rewrites56.6%

      \[\leadsto \color{blue}{\sin th} \]
  3. Recombined 2 regimes into one program.
  4. Add Preprocessing

Alternative 9: 44.3% accurate, 0.8× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 4 \cdot 10^{-5}:\\ \;\;\;\;\frac{\frac{\sin th}{\sin kx}}{\frac{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.00205026455026455, ky \cdot ky, 0.019444444444444445\right), ky \cdot ky, 0.16666666666666666\right), ky \cdot ky, 1\right)}{ky}}\\ \mathbf{else}:\\ \;\;\;\;\sin th\\ \end{array} \end{array} \]
(FPCore (kx ky th)
 :precision binary64
 (if (<= (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0)))) 4e-5)
   (/
    (/ (sin th) (sin kx))
    (/
     (fma
      (fma
       (fma 0.00205026455026455 (* ky ky) 0.019444444444444445)
       (* ky ky)
       0.16666666666666666)
      (* ky ky)
      1.0)
     ky))
   (sin th)))
double code(double kx, double ky, double th) {
	double tmp;
	if ((sin(ky) / sqrt((pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))) <= 4e-5) {
		tmp = (sin(th) / sin(kx)) / (fma(fma(fma(0.00205026455026455, (ky * ky), 0.019444444444444445), (ky * ky), 0.16666666666666666), (ky * ky), 1.0) / ky);
	} else {
		tmp = sin(th);
	}
	return tmp;
}
function code(kx, ky, th)
	tmp = 0.0
	if (Float64(sin(ky) / sqrt(Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) <= 4e-5)
		tmp = Float64(Float64(sin(th) / sin(kx)) / Float64(fma(fma(fma(0.00205026455026455, Float64(ky * ky), 0.019444444444444445), Float64(ky * ky), 0.16666666666666666), Float64(ky * ky), 1.0) / ky));
	else
		tmp = sin(th);
	end
	return tmp
end
code[kx_, ky_, th_] := If[LessEqual[N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 4e-5], N[(N[(N[Sin[th], $MachinePrecision] / N[Sin[kx], $MachinePrecision]), $MachinePrecision] / N[(N[(N[(N[(0.00205026455026455 * N[(ky * ky), $MachinePrecision] + 0.019444444444444445), $MachinePrecision] * N[(ky * ky), $MachinePrecision] + 0.16666666666666666), $MachinePrecision] * N[(ky * ky), $MachinePrecision] + 1.0), $MachinePrecision] / ky), $MachinePrecision]), $MachinePrecision], N[Sin[th], $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 4 \cdot 10^{-5}:\\
\;\;\;\;\frac{\frac{\sin th}{\sin kx}}{\frac{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.00205026455026455, ky \cdot ky, 0.019444444444444445\right), ky \cdot ky, 0.16666666666666666\right), ky \cdot ky, 1\right)}{ky}}\\

\mathbf{else}:\\
\;\;\;\;\sin th\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 4.00000000000000033e-5

    1. Initial program 95.2%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
      2. *-commutativeN/A

        \[\leadsto \color{blue}{\sin th \cdot \frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      3. lift-/.f64N/A

        \[\leadsto \sin th \cdot \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      4. clear-numN/A

        \[\leadsto \sin th \cdot \color{blue}{\frac{1}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
      5. un-div-invN/A

        \[\leadsto \color{blue}{\frac{\sin th}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
      6. div-invN/A

        \[\leadsto \frac{\sin th}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}} \cdot \frac{1}{\sin ky}}} \]
      7. associate-/r*N/A

        \[\leadsto \color{blue}{\frac{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \]
      8. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \]
    4. Applied rewrites99.4%

      \[\leadsto \color{blue}{\frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{{\sin ky}^{-1}}} \]
    5. Taylor expanded in ky around 0

      \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
    6. Step-by-step derivation
      1. lower-/.f6466.8

        \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
    7. Applied rewrites66.8%

      \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
    8. Taylor expanded in ky around 0

      \[\leadsto \frac{\color{blue}{\frac{\sin th}{\sin kx}}}{\frac{1}{ky}} \]
    9. Step-by-step derivation
      1. lower-/.f64N/A

        \[\leadsto \frac{\color{blue}{\frac{\sin th}{\sin kx}}}{\frac{1}{ky}} \]
      2. lower-sin.f64N/A

        \[\leadsto \frac{\frac{\color{blue}{\sin th}}{\sin kx}}{\frac{1}{ky}} \]
      3. lower-sin.f6437.4

        \[\leadsto \frac{\frac{\sin th}{\color{blue}{\sin kx}}}{\frac{1}{ky}} \]
    10. Applied rewrites37.4%

      \[\leadsto \frac{\color{blue}{\frac{\sin th}{\sin kx}}}{\frac{1}{ky}} \]
    11. Taylor expanded in ky around 0

      \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\color{blue}{\frac{1 + {ky}^{2} \cdot \left(\frac{1}{6} + {ky}^{2} \cdot \left(\frac{7}{360} + \frac{31}{15120} \cdot {ky}^{2}\right)\right)}{ky}}} \]
    12. Step-by-step derivation
      1. lower-/.f64N/A

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\color{blue}{\frac{1 + {ky}^{2} \cdot \left(\frac{1}{6} + {ky}^{2} \cdot \left(\frac{7}{360} + \frac{31}{15120} \cdot {ky}^{2}\right)\right)}{ky}}} \]
      2. +-commutativeN/A

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\frac{\color{blue}{{ky}^{2} \cdot \left(\frac{1}{6} + {ky}^{2} \cdot \left(\frac{7}{360} + \frac{31}{15120} \cdot {ky}^{2}\right)\right) + 1}}{ky}} \]
      3. *-commutativeN/A

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\frac{\color{blue}{\left(\frac{1}{6} + {ky}^{2} \cdot \left(\frac{7}{360} + \frac{31}{15120} \cdot {ky}^{2}\right)\right) \cdot {ky}^{2}} + 1}{ky}} \]
      4. lower-fma.f64N/A

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\frac{\color{blue}{\mathsf{fma}\left(\frac{1}{6} + {ky}^{2} \cdot \left(\frac{7}{360} + \frac{31}{15120} \cdot {ky}^{2}\right), {ky}^{2}, 1\right)}}{ky}} \]
      5. +-commutativeN/A

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\frac{\mathsf{fma}\left(\color{blue}{{ky}^{2} \cdot \left(\frac{7}{360} + \frac{31}{15120} \cdot {ky}^{2}\right) + \frac{1}{6}}, {ky}^{2}, 1\right)}{ky}} \]
      6. *-commutativeN/A

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\frac{\mathsf{fma}\left(\color{blue}{\left(\frac{7}{360} + \frac{31}{15120} \cdot {ky}^{2}\right) \cdot {ky}^{2}} + \frac{1}{6}, {ky}^{2}, 1\right)}{ky}} \]
      7. lower-fma.f64N/A

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\frac{\mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(\frac{7}{360} + \frac{31}{15120} \cdot {ky}^{2}, {ky}^{2}, \frac{1}{6}\right)}, {ky}^{2}, 1\right)}{ky}} \]
      8. +-commutativeN/A

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\frac{\mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\frac{31}{15120} \cdot {ky}^{2} + \frac{7}{360}}, {ky}^{2}, \frac{1}{6}\right), {ky}^{2}, 1\right)}{ky}} \]
      9. lower-fma.f64N/A

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\frac{\mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(\frac{31}{15120}, {ky}^{2}, \frac{7}{360}\right)}, {ky}^{2}, \frac{1}{6}\right), {ky}^{2}, 1\right)}{ky}} \]
      10. unpow2N/A

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\frac{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{31}{15120}, \color{blue}{ky \cdot ky}, \frac{7}{360}\right), {ky}^{2}, \frac{1}{6}\right), {ky}^{2}, 1\right)}{ky}} \]
      11. lower-*.f64N/A

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\frac{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{31}{15120}, \color{blue}{ky \cdot ky}, \frac{7}{360}\right), {ky}^{2}, \frac{1}{6}\right), {ky}^{2}, 1\right)}{ky}} \]
      12. unpow2N/A

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\frac{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{31}{15120}, ky \cdot ky, \frac{7}{360}\right), \color{blue}{ky \cdot ky}, \frac{1}{6}\right), {ky}^{2}, 1\right)}{ky}} \]
      13. lower-*.f64N/A

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\frac{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{31}{15120}, ky \cdot ky, \frac{7}{360}\right), \color{blue}{ky \cdot ky}, \frac{1}{6}\right), {ky}^{2}, 1\right)}{ky}} \]
      14. unpow2N/A

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\frac{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{31}{15120}, ky \cdot ky, \frac{7}{360}\right), ky \cdot ky, \frac{1}{6}\right), \color{blue}{ky \cdot ky}, 1\right)}{ky}} \]
      15. lower-*.f6437.8

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\frac{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.00205026455026455, ky \cdot ky, 0.019444444444444445\right), ky \cdot ky, 0.16666666666666666\right), \color{blue}{ky \cdot ky}, 1\right)}{ky}} \]
    13. Applied rewrites37.8%

      \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\color{blue}{\frac{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.00205026455026455, ky \cdot ky, 0.019444444444444445\right), ky \cdot ky, 0.16666666666666666\right), ky \cdot ky, 1\right)}{ky}}} \]

    if 4.00000000000000033e-5 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))

    1. Initial program 90.5%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in kx around 0

      \[\leadsto \color{blue}{\sin th} \]
    4. Step-by-step derivation
      1. lower-sin.f6456.6

        \[\leadsto \color{blue}{\sin th} \]
    5. Applied rewrites56.6%

      \[\leadsto \color{blue}{\sin th} \]
  3. Recombined 2 regimes into one program.
  4. Add Preprocessing

Alternative 10: 44.3% accurate, 0.8× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 4 \cdot 10^{-5}:\\ \;\;\;\;\frac{\frac{\sin th}{\sin kx}}{\frac{\mathsf{fma}\left(\mathsf{fma}\left(0.019444444444444445, ky \cdot ky, 0.16666666666666666\right), ky \cdot ky, 1\right)}{ky}}\\ \mathbf{else}:\\ \;\;\;\;\sin th\\ \end{array} \end{array} \]
(FPCore (kx ky th)
 :precision binary64
 (if (<= (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0)))) 4e-5)
   (/
    (/ (sin th) (sin kx))
    (/
     (fma
      (fma 0.019444444444444445 (* ky ky) 0.16666666666666666)
      (* ky ky)
      1.0)
     ky))
   (sin th)))
double code(double kx, double ky, double th) {
	double tmp;
	if ((sin(ky) / sqrt((pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))) <= 4e-5) {
		tmp = (sin(th) / sin(kx)) / (fma(fma(0.019444444444444445, (ky * ky), 0.16666666666666666), (ky * ky), 1.0) / ky);
	} else {
		tmp = sin(th);
	}
	return tmp;
}
function code(kx, ky, th)
	tmp = 0.0
	if (Float64(sin(ky) / sqrt(Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) <= 4e-5)
		tmp = Float64(Float64(sin(th) / sin(kx)) / Float64(fma(fma(0.019444444444444445, Float64(ky * ky), 0.16666666666666666), Float64(ky * ky), 1.0) / ky));
	else
		tmp = sin(th);
	end
	return tmp
end
code[kx_, ky_, th_] := If[LessEqual[N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 4e-5], N[(N[(N[Sin[th], $MachinePrecision] / N[Sin[kx], $MachinePrecision]), $MachinePrecision] / N[(N[(N[(0.019444444444444445 * N[(ky * ky), $MachinePrecision] + 0.16666666666666666), $MachinePrecision] * N[(ky * ky), $MachinePrecision] + 1.0), $MachinePrecision] / ky), $MachinePrecision]), $MachinePrecision], N[Sin[th], $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 4 \cdot 10^{-5}:\\
\;\;\;\;\frac{\frac{\sin th}{\sin kx}}{\frac{\mathsf{fma}\left(\mathsf{fma}\left(0.019444444444444445, ky \cdot ky, 0.16666666666666666\right), ky \cdot ky, 1\right)}{ky}}\\

\mathbf{else}:\\
\;\;\;\;\sin th\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 4.00000000000000033e-5

    1. Initial program 95.2%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
      2. *-commutativeN/A

        \[\leadsto \color{blue}{\sin th \cdot \frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      3. lift-/.f64N/A

        \[\leadsto \sin th \cdot \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      4. clear-numN/A

        \[\leadsto \sin th \cdot \color{blue}{\frac{1}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
      5. un-div-invN/A

        \[\leadsto \color{blue}{\frac{\sin th}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
      6. div-invN/A

        \[\leadsto \frac{\sin th}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}} \cdot \frac{1}{\sin ky}}} \]
      7. associate-/r*N/A

        \[\leadsto \color{blue}{\frac{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \]
      8. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \]
    4. Applied rewrites99.4%

      \[\leadsto \color{blue}{\frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{{\sin ky}^{-1}}} \]
    5. Taylor expanded in ky around 0

      \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
    6. Step-by-step derivation
      1. lower-/.f6466.8

        \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
    7. Applied rewrites66.8%

      \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
    8. Taylor expanded in ky around 0

      \[\leadsto \frac{\color{blue}{\frac{\sin th}{\sin kx}}}{\frac{1}{ky}} \]
    9. Step-by-step derivation
      1. lower-/.f64N/A

        \[\leadsto \frac{\color{blue}{\frac{\sin th}{\sin kx}}}{\frac{1}{ky}} \]
      2. lower-sin.f64N/A

        \[\leadsto \frac{\frac{\color{blue}{\sin th}}{\sin kx}}{\frac{1}{ky}} \]
      3. lower-sin.f6437.4

        \[\leadsto \frac{\frac{\sin th}{\color{blue}{\sin kx}}}{\frac{1}{ky}} \]
    10. Applied rewrites37.4%

      \[\leadsto \frac{\color{blue}{\frac{\sin th}{\sin kx}}}{\frac{1}{ky}} \]
    11. Taylor expanded in ky around 0

      \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\color{blue}{\frac{1 + {ky}^{2} \cdot \left(\frac{1}{6} + \frac{7}{360} \cdot {ky}^{2}\right)}{ky}}} \]
    12. Step-by-step derivation
      1. lower-/.f64N/A

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\color{blue}{\frac{1 + {ky}^{2} \cdot \left(\frac{1}{6} + \frac{7}{360} \cdot {ky}^{2}\right)}{ky}}} \]
      2. +-commutativeN/A

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\frac{\color{blue}{{ky}^{2} \cdot \left(\frac{1}{6} + \frac{7}{360} \cdot {ky}^{2}\right) + 1}}{ky}} \]
      3. *-commutativeN/A

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\frac{\color{blue}{\left(\frac{1}{6} + \frac{7}{360} \cdot {ky}^{2}\right) \cdot {ky}^{2}} + 1}{ky}} \]
      4. lower-fma.f64N/A

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\frac{\color{blue}{\mathsf{fma}\left(\frac{1}{6} + \frac{7}{360} \cdot {ky}^{2}, {ky}^{2}, 1\right)}}{ky}} \]
      5. +-commutativeN/A

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\frac{\mathsf{fma}\left(\color{blue}{\frac{7}{360} \cdot {ky}^{2} + \frac{1}{6}}, {ky}^{2}, 1\right)}{ky}} \]
      6. lower-fma.f64N/A

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\frac{\mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(\frac{7}{360}, {ky}^{2}, \frac{1}{6}\right)}, {ky}^{2}, 1\right)}{ky}} \]
      7. unpow2N/A

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\frac{\mathsf{fma}\left(\mathsf{fma}\left(\frac{7}{360}, \color{blue}{ky \cdot ky}, \frac{1}{6}\right), {ky}^{2}, 1\right)}{ky}} \]
      8. lower-*.f64N/A

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\frac{\mathsf{fma}\left(\mathsf{fma}\left(\frac{7}{360}, \color{blue}{ky \cdot ky}, \frac{1}{6}\right), {ky}^{2}, 1\right)}{ky}} \]
      9. unpow2N/A

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\frac{\mathsf{fma}\left(\mathsf{fma}\left(\frac{7}{360}, ky \cdot ky, \frac{1}{6}\right), \color{blue}{ky \cdot ky}, 1\right)}{ky}} \]
      10. lower-*.f6437.9

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\frac{\mathsf{fma}\left(\mathsf{fma}\left(0.019444444444444445, ky \cdot ky, 0.16666666666666666\right), \color{blue}{ky \cdot ky}, 1\right)}{ky}} \]
    13. Applied rewrites37.9%

      \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\color{blue}{\frac{\mathsf{fma}\left(\mathsf{fma}\left(0.019444444444444445, ky \cdot ky, 0.16666666666666666\right), ky \cdot ky, 1\right)}{ky}}} \]

    if 4.00000000000000033e-5 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))

    1. Initial program 90.5%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in kx around 0

      \[\leadsto \color{blue}{\sin th} \]
    4. Step-by-step derivation
      1. lower-sin.f6456.6

        \[\leadsto \color{blue}{\sin th} \]
    5. Applied rewrites56.6%

      \[\leadsto \color{blue}{\sin th} \]
  3. Recombined 2 regimes into one program.
  4. Add Preprocessing

Alternative 11: 44.4% accurate, 0.8× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 4 \cdot 10^{-5}:\\ \;\;\;\;\frac{\frac{\sin th}{\sin kx}}{\frac{\mathsf{fma}\left(ky \cdot ky, 0.16666666666666666, 1\right)}{ky}}\\ \mathbf{else}:\\ \;\;\;\;\sin th\\ \end{array} \end{array} \]
(FPCore (kx ky th)
 :precision binary64
 (if (<= (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0)))) 4e-5)
   (/ (/ (sin th) (sin kx)) (/ (fma (* ky ky) 0.16666666666666666 1.0) ky))
   (sin th)))
double code(double kx, double ky, double th) {
	double tmp;
	if ((sin(ky) / sqrt((pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))) <= 4e-5) {
		tmp = (sin(th) / sin(kx)) / (fma((ky * ky), 0.16666666666666666, 1.0) / ky);
	} else {
		tmp = sin(th);
	}
	return tmp;
}
function code(kx, ky, th)
	tmp = 0.0
	if (Float64(sin(ky) / sqrt(Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) <= 4e-5)
		tmp = Float64(Float64(sin(th) / sin(kx)) / Float64(fma(Float64(ky * ky), 0.16666666666666666, 1.0) / ky));
	else
		tmp = sin(th);
	end
	return tmp
end
code[kx_, ky_, th_] := If[LessEqual[N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 4e-5], N[(N[(N[Sin[th], $MachinePrecision] / N[Sin[kx], $MachinePrecision]), $MachinePrecision] / N[(N[(N[(ky * ky), $MachinePrecision] * 0.16666666666666666 + 1.0), $MachinePrecision] / ky), $MachinePrecision]), $MachinePrecision], N[Sin[th], $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 4 \cdot 10^{-5}:\\
\;\;\;\;\frac{\frac{\sin th}{\sin kx}}{\frac{\mathsf{fma}\left(ky \cdot ky, 0.16666666666666666, 1\right)}{ky}}\\

\mathbf{else}:\\
\;\;\;\;\sin th\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 4.00000000000000033e-5

    1. Initial program 95.2%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
      2. *-commutativeN/A

        \[\leadsto \color{blue}{\sin th \cdot \frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      3. lift-/.f64N/A

        \[\leadsto \sin th \cdot \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      4. clear-numN/A

        \[\leadsto \sin th \cdot \color{blue}{\frac{1}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
      5. un-div-invN/A

        \[\leadsto \color{blue}{\frac{\sin th}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
      6. div-invN/A

        \[\leadsto \frac{\sin th}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}} \cdot \frac{1}{\sin ky}}} \]
      7. associate-/r*N/A

        \[\leadsto \color{blue}{\frac{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \]
      8. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \]
    4. Applied rewrites99.4%

      \[\leadsto \color{blue}{\frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{{\sin ky}^{-1}}} \]
    5. Taylor expanded in ky around 0

      \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
    6. Step-by-step derivation
      1. lower-/.f6466.8

        \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
    7. Applied rewrites66.8%

      \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
    8. Taylor expanded in ky around 0

      \[\leadsto \frac{\color{blue}{\frac{\sin th}{\sin kx}}}{\frac{1}{ky}} \]
    9. Step-by-step derivation
      1. lower-/.f64N/A

        \[\leadsto \frac{\color{blue}{\frac{\sin th}{\sin kx}}}{\frac{1}{ky}} \]
      2. lower-sin.f64N/A

        \[\leadsto \frac{\frac{\color{blue}{\sin th}}{\sin kx}}{\frac{1}{ky}} \]
      3. lower-sin.f6437.4

        \[\leadsto \frac{\frac{\sin th}{\color{blue}{\sin kx}}}{\frac{1}{ky}} \]
    10. Applied rewrites37.4%

      \[\leadsto \frac{\color{blue}{\frac{\sin th}{\sin kx}}}{\frac{1}{ky}} \]
    11. Taylor expanded in ky around 0

      \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\color{blue}{\frac{1 + \frac{1}{6} \cdot {ky}^{2}}{ky}}} \]
    12. Step-by-step derivation
      1. lower-/.f64N/A

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\color{blue}{\frac{1 + \frac{1}{6} \cdot {ky}^{2}}{ky}}} \]
      2. +-commutativeN/A

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\frac{\color{blue}{\frac{1}{6} \cdot {ky}^{2} + 1}}{ky}} \]
      3. *-commutativeN/A

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\frac{\color{blue}{{ky}^{2} \cdot \frac{1}{6}} + 1}{ky}} \]
      4. lower-fma.f64N/A

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\frac{\color{blue}{\mathsf{fma}\left({ky}^{2}, \frac{1}{6}, 1\right)}}{ky}} \]
      5. unpow2N/A

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\frac{\mathsf{fma}\left(\color{blue}{ky \cdot ky}, \frac{1}{6}, 1\right)}{ky}} \]
      6. lower-*.f6437.8

        \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\frac{\mathsf{fma}\left(\color{blue}{ky \cdot ky}, 0.16666666666666666, 1\right)}{ky}} \]
    13. Applied rewrites37.8%

      \[\leadsto \frac{\frac{\sin th}{\sin kx}}{\color{blue}{\frac{\mathsf{fma}\left(ky \cdot ky, 0.16666666666666666, 1\right)}{ky}}} \]

    if 4.00000000000000033e-5 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))

    1. Initial program 90.5%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in kx around 0

      \[\leadsto \color{blue}{\sin th} \]
    4. Step-by-step derivation
      1. lower-sin.f6456.6

        \[\leadsto \color{blue}{\sin th} \]
    5. Applied rewrites56.6%

      \[\leadsto \color{blue}{\sin th} \]
  3. Recombined 2 regimes into one program.
  4. Add Preprocessing

Alternative 12: 35.4% accurate, 0.8× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 4 \cdot 10^{-27}:\\ \;\;\;\;\frac{\frac{\sin th}{kx}}{{ky}^{-1}}\\ \mathbf{else}:\\ \;\;\;\;\sin th\\ \end{array} \end{array} \]
(FPCore (kx ky th)
 :precision binary64
 (if (<= (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0)))) 4e-27)
   (/ (/ (sin th) kx) (pow ky -1.0))
   (sin th)))
double code(double kx, double ky, double th) {
	double tmp;
	if ((sin(ky) / sqrt((pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))) <= 4e-27) {
		tmp = (sin(th) / kx) / pow(ky, -1.0);
	} else {
		tmp = sin(th);
	}
	return tmp;
}
real(8) function code(kx, ky, th)
    real(8), intent (in) :: kx
    real(8), intent (in) :: ky
    real(8), intent (in) :: th
    real(8) :: tmp
    if ((sin(ky) / sqrt(((sin(kx) ** 2.0d0) + (sin(ky) ** 2.0d0)))) <= 4d-27) then
        tmp = (sin(th) / kx) / (ky ** (-1.0d0))
    else
        tmp = sin(th)
    end if
    code = tmp
end function
public static double code(double kx, double ky, double th) {
	double tmp;
	if ((Math.sin(ky) / Math.sqrt((Math.pow(Math.sin(kx), 2.0) + Math.pow(Math.sin(ky), 2.0)))) <= 4e-27) {
		tmp = (Math.sin(th) / kx) / Math.pow(ky, -1.0);
	} else {
		tmp = Math.sin(th);
	}
	return tmp;
}
def code(kx, ky, th):
	tmp = 0
	if (math.sin(ky) / math.sqrt((math.pow(math.sin(kx), 2.0) + math.pow(math.sin(ky), 2.0)))) <= 4e-27:
		tmp = (math.sin(th) / kx) / math.pow(ky, -1.0)
	else:
		tmp = math.sin(th)
	return tmp
function code(kx, ky, th)
	tmp = 0.0
	if (Float64(sin(ky) / sqrt(Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) <= 4e-27)
		tmp = Float64(Float64(sin(th) / kx) / (ky ^ -1.0));
	else
		tmp = sin(th);
	end
	return tmp
end
function tmp_2 = code(kx, ky, th)
	tmp = 0.0;
	if ((sin(ky) / sqrt(((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) <= 4e-27)
		tmp = (sin(th) / kx) / (ky ^ -1.0);
	else
		tmp = sin(th);
	end
	tmp_2 = tmp;
end
code[kx_, ky_, th_] := If[LessEqual[N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 4e-27], N[(N[(N[Sin[th], $MachinePrecision] / kx), $MachinePrecision] / N[Power[ky, -1.0], $MachinePrecision]), $MachinePrecision], N[Sin[th], $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 4 \cdot 10^{-27}:\\
\;\;\;\;\frac{\frac{\sin th}{kx}}{{ky}^{-1}}\\

\mathbf{else}:\\
\;\;\;\;\sin th\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 4.0000000000000002e-27

    1. Initial program 95.1%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
      2. *-commutativeN/A

        \[\leadsto \color{blue}{\sin th \cdot \frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      3. lift-/.f64N/A

        \[\leadsto \sin th \cdot \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      4. clear-numN/A

        \[\leadsto \sin th \cdot \color{blue}{\frac{1}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
      5. un-div-invN/A

        \[\leadsto \color{blue}{\frac{\sin th}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
      6. div-invN/A

        \[\leadsto \frac{\sin th}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}} \cdot \frac{1}{\sin ky}}} \]
      7. associate-/r*N/A

        \[\leadsto \color{blue}{\frac{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \]
      8. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \]
    4. Applied rewrites99.4%

      \[\leadsto \color{blue}{\frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{{\sin ky}^{-1}}} \]
    5. Taylor expanded in ky around 0

      \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
    6. Step-by-step derivation
      1. lower-/.f6466.0

        \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
    7. Applied rewrites66.0%

      \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
    8. Taylor expanded in ky around 0

      \[\leadsto \frac{\color{blue}{\frac{\sin th}{\sin kx}}}{\frac{1}{ky}} \]
    9. Step-by-step derivation
      1. lower-/.f64N/A

        \[\leadsto \frac{\color{blue}{\frac{\sin th}{\sin kx}}}{\frac{1}{ky}} \]
      2. lower-sin.f64N/A

        \[\leadsto \frac{\frac{\color{blue}{\sin th}}{\sin kx}}{\frac{1}{ky}} \]
      3. lower-sin.f6437.3

        \[\leadsto \frac{\frac{\sin th}{\color{blue}{\sin kx}}}{\frac{1}{ky}} \]
    10. Applied rewrites37.3%

      \[\leadsto \frac{\color{blue}{\frac{\sin th}{\sin kx}}}{\frac{1}{ky}} \]
    11. Taylor expanded in kx around 0

      \[\leadsto \frac{\frac{\sin th}{\color{blue}{kx}}}{\frac{1}{ky}} \]
    12. Step-by-step derivation
      1. Applied rewrites21.2%

        \[\leadsto \frac{\frac{\sin th}{\color{blue}{kx}}}{\frac{1}{ky}} \]

      if 4.0000000000000002e-27 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))

      1. Initial program 91.0%

        \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
      2. Add Preprocessing
      3. Taylor expanded in kx around 0

        \[\leadsto \color{blue}{\sin th} \]
      4. Step-by-step derivation
        1. lower-sin.f6454.4

          \[\leadsto \color{blue}{\sin th} \]
      5. Applied rewrites54.4%

        \[\leadsto \color{blue}{\sin th} \]
    13. Recombined 2 regimes into one program.
    14. Final simplification32.0%

      \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 4 \cdot 10^{-27}:\\ \;\;\;\;\frac{\frac{\sin th}{kx}}{{ky}^{-1}}\\ \mathbf{else}:\\ \;\;\;\;\sin th\\ \end{array} \]
    15. Add Preprocessing

    Alternative 13: 35.5% accurate, 0.8× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 4 \cdot 10^{-5}:\\ \;\;\;\;\frac{\frac{th}{\sin kx}}{{ky}^{-1}}\\ \mathbf{else}:\\ \;\;\;\;\sin th\\ \end{array} \end{array} \]
    (FPCore (kx ky th)
     :precision binary64
     (if (<= (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0)))) 4e-5)
       (/ (/ th (sin kx)) (pow ky -1.0))
       (sin th)))
    double code(double kx, double ky, double th) {
    	double tmp;
    	if ((sin(ky) / sqrt((pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))) <= 4e-5) {
    		tmp = (th / sin(kx)) / pow(ky, -1.0);
    	} else {
    		tmp = sin(th);
    	}
    	return tmp;
    }
    
    real(8) function code(kx, ky, th)
        real(8), intent (in) :: kx
        real(8), intent (in) :: ky
        real(8), intent (in) :: th
        real(8) :: tmp
        if ((sin(ky) / sqrt(((sin(kx) ** 2.0d0) + (sin(ky) ** 2.0d0)))) <= 4d-5) then
            tmp = (th / sin(kx)) / (ky ** (-1.0d0))
        else
            tmp = sin(th)
        end if
        code = tmp
    end function
    
    public static double code(double kx, double ky, double th) {
    	double tmp;
    	if ((Math.sin(ky) / Math.sqrt((Math.pow(Math.sin(kx), 2.0) + Math.pow(Math.sin(ky), 2.0)))) <= 4e-5) {
    		tmp = (th / Math.sin(kx)) / Math.pow(ky, -1.0);
    	} else {
    		tmp = Math.sin(th);
    	}
    	return tmp;
    }
    
    def code(kx, ky, th):
    	tmp = 0
    	if (math.sin(ky) / math.sqrt((math.pow(math.sin(kx), 2.0) + math.pow(math.sin(ky), 2.0)))) <= 4e-5:
    		tmp = (th / math.sin(kx)) / math.pow(ky, -1.0)
    	else:
    		tmp = math.sin(th)
    	return tmp
    
    function code(kx, ky, th)
    	tmp = 0.0
    	if (Float64(sin(ky) / sqrt(Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) <= 4e-5)
    		tmp = Float64(Float64(th / sin(kx)) / (ky ^ -1.0));
    	else
    		tmp = sin(th);
    	end
    	return tmp
    end
    
    function tmp_2 = code(kx, ky, th)
    	tmp = 0.0;
    	if ((sin(ky) / sqrt(((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) <= 4e-5)
    		tmp = (th / sin(kx)) / (ky ^ -1.0);
    	else
    		tmp = sin(th);
    	end
    	tmp_2 = tmp;
    end
    
    code[kx_, ky_, th_] := If[LessEqual[N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 4e-5], N[(N[(th / N[Sin[kx], $MachinePrecision]), $MachinePrecision] / N[Power[ky, -1.0], $MachinePrecision]), $MachinePrecision], N[Sin[th], $MachinePrecision]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 4 \cdot 10^{-5}:\\
    \;\;\;\;\frac{\frac{th}{\sin kx}}{{ky}^{-1}}\\
    
    \mathbf{else}:\\
    \;\;\;\;\sin th\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 2 regimes
    2. if (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 4.00000000000000033e-5

      1. Initial program 95.2%

        \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
      2. Add Preprocessing
      3. Step-by-step derivation
        1. lift-*.f64N/A

          \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
        2. *-commutativeN/A

          \[\leadsto \color{blue}{\sin th \cdot \frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
        3. lift-/.f64N/A

          \[\leadsto \sin th \cdot \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
        4. clear-numN/A

          \[\leadsto \sin th \cdot \color{blue}{\frac{1}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
        5. un-div-invN/A

          \[\leadsto \color{blue}{\frac{\sin th}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
        6. div-invN/A

          \[\leadsto \frac{\sin th}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}} \cdot \frac{1}{\sin ky}}} \]
        7. associate-/r*N/A

          \[\leadsto \color{blue}{\frac{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \]
        8. lower-/.f64N/A

          \[\leadsto \color{blue}{\frac{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \]
      4. Applied rewrites99.4%

        \[\leadsto \color{blue}{\frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{{\sin ky}^{-1}}} \]
      5. Taylor expanded in ky around 0

        \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
      6. Step-by-step derivation
        1. lower-/.f6466.8

          \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
      7. Applied rewrites66.8%

        \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
      8. Taylor expanded in ky around 0

        \[\leadsto \frac{\color{blue}{\frac{\sin th}{\sin kx}}}{\frac{1}{ky}} \]
      9. Step-by-step derivation
        1. lower-/.f64N/A

          \[\leadsto \frac{\color{blue}{\frac{\sin th}{\sin kx}}}{\frac{1}{ky}} \]
        2. lower-sin.f64N/A

          \[\leadsto \frac{\frac{\color{blue}{\sin th}}{\sin kx}}{\frac{1}{ky}} \]
        3. lower-sin.f6437.4

          \[\leadsto \frac{\frac{\sin th}{\color{blue}{\sin kx}}}{\frac{1}{ky}} \]
      10. Applied rewrites37.4%

        \[\leadsto \frac{\color{blue}{\frac{\sin th}{\sin kx}}}{\frac{1}{ky}} \]
      11. Taylor expanded in th around 0

        \[\leadsto \frac{\frac{th}{\color{blue}{\sin kx}}}{\frac{1}{ky}} \]
      12. Step-by-step derivation
        1. Applied rewrites23.5%

          \[\leadsto \frac{\frac{th}{\color{blue}{\sin kx}}}{\frac{1}{ky}} \]

        if 4.00000000000000033e-5 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))

        1. Initial program 90.5%

          \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
        2. Add Preprocessing
        3. Taylor expanded in kx around 0

          \[\leadsto \color{blue}{\sin th} \]
        4. Step-by-step derivation
          1. lower-sin.f6456.6

            \[\leadsto \color{blue}{\sin th} \]
        5. Applied rewrites56.6%

          \[\leadsto \color{blue}{\sin th} \]
      13. Recombined 2 regimes into one program.
      14. Final simplification33.7%

        \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 4 \cdot 10^{-5}:\\ \;\;\;\;\frac{\frac{th}{\sin kx}}{{ky}^{-1}}\\ \mathbf{else}:\\ \;\;\;\;\sin th\\ \end{array} \]
      15. Add Preprocessing

      Alternative 14: 44.0% accurate, 0.8× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 4 \cdot 10^{-5}:\\ \;\;\;\;\frac{\sin th}{\frac{\sin kx}{ky}}\\ \mathbf{else}:\\ \;\;\;\;\sin th\\ \end{array} \end{array} \]
      (FPCore (kx ky th)
       :precision binary64
       (if (<= (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0)))) 4e-5)
         (/ (sin th) (/ (sin kx) ky))
         (sin th)))
      double code(double kx, double ky, double th) {
      	double tmp;
      	if ((sin(ky) / sqrt((pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))) <= 4e-5) {
      		tmp = sin(th) / (sin(kx) / ky);
      	} else {
      		tmp = sin(th);
      	}
      	return tmp;
      }
      
      real(8) function code(kx, ky, th)
          real(8), intent (in) :: kx
          real(8), intent (in) :: ky
          real(8), intent (in) :: th
          real(8) :: tmp
          if ((sin(ky) / sqrt(((sin(kx) ** 2.0d0) + (sin(ky) ** 2.0d0)))) <= 4d-5) then
              tmp = sin(th) / (sin(kx) / ky)
          else
              tmp = sin(th)
          end if
          code = tmp
      end function
      
      public static double code(double kx, double ky, double th) {
      	double tmp;
      	if ((Math.sin(ky) / Math.sqrt((Math.pow(Math.sin(kx), 2.0) + Math.pow(Math.sin(ky), 2.0)))) <= 4e-5) {
      		tmp = Math.sin(th) / (Math.sin(kx) / ky);
      	} else {
      		tmp = Math.sin(th);
      	}
      	return tmp;
      }
      
      def code(kx, ky, th):
      	tmp = 0
      	if (math.sin(ky) / math.sqrt((math.pow(math.sin(kx), 2.0) + math.pow(math.sin(ky), 2.0)))) <= 4e-5:
      		tmp = math.sin(th) / (math.sin(kx) / ky)
      	else:
      		tmp = math.sin(th)
      	return tmp
      
      function code(kx, ky, th)
      	tmp = 0.0
      	if (Float64(sin(ky) / sqrt(Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) <= 4e-5)
      		tmp = Float64(sin(th) / Float64(sin(kx) / ky));
      	else
      		tmp = sin(th);
      	end
      	return tmp
      end
      
      function tmp_2 = code(kx, ky, th)
      	tmp = 0.0;
      	if ((sin(ky) / sqrt(((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) <= 4e-5)
      		tmp = sin(th) / (sin(kx) / ky);
      	else
      		tmp = sin(th);
      	end
      	tmp_2 = tmp;
      end
      
      code[kx_, ky_, th_] := If[LessEqual[N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 4e-5], N[(N[Sin[th], $MachinePrecision] / N[(N[Sin[kx], $MachinePrecision] / ky), $MachinePrecision]), $MachinePrecision], N[Sin[th], $MachinePrecision]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 4 \cdot 10^{-5}:\\
      \;\;\;\;\frac{\sin th}{\frac{\sin kx}{ky}}\\
      
      \mathbf{else}:\\
      \;\;\;\;\sin th\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 4.00000000000000033e-5

        1. Initial program 95.2%

          \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
        2. Add Preprocessing
        3. Step-by-step derivation
          1. lift-*.f64N/A

            \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
          2. *-commutativeN/A

            \[\leadsto \color{blue}{\sin th \cdot \frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
          3. lift-/.f64N/A

            \[\leadsto \sin th \cdot \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
          4. clear-numN/A

            \[\leadsto \sin th \cdot \color{blue}{\frac{1}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
          5. un-div-invN/A

            \[\leadsto \color{blue}{\frac{\sin th}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
          6. lower-/.f64N/A

            \[\leadsto \color{blue}{\frac{\sin th}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
          7. lower-/.f6495.2

            \[\leadsto \frac{\sin th}{\color{blue}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
          8. lift-sqrt.f64N/A

            \[\leadsto \frac{\sin th}{\frac{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\sin ky}} \]
          9. lift-+.f64N/A

            \[\leadsto \frac{\sin th}{\frac{\sqrt{\color{blue}{{\sin kx}^{2} + {\sin ky}^{2}}}}{\sin ky}} \]
          10. +-commutativeN/A

            \[\leadsto \frac{\sin th}{\frac{\sqrt{\color{blue}{{\sin ky}^{2} + {\sin kx}^{2}}}}{\sin ky}} \]
          11. lift-pow.f64N/A

            \[\leadsto \frac{\sin th}{\frac{\sqrt{\color{blue}{{\sin ky}^{2}} + {\sin kx}^{2}}}{\sin ky}} \]
          12. unpow2N/A

            \[\leadsto \frac{\sin th}{\frac{\sqrt{\color{blue}{\sin ky \cdot \sin ky} + {\sin kx}^{2}}}{\sin ky}} \]
          13. lift-pow.f64N/A

            \[\leadsto \frac{\sin th}{\frac{\sqrt{\sin ky \cdot \sin ky + \color{blue}{{\sin kx}^{2}}}}{\sin ky}} \]
          14. unpow2N/A

            \[\leadsto \frac{\sin th}{\frac{\sqrt{\sin ky \cdot \sin ky + \color{blue}{\sin kx \cdot \sin kx}}}{\sin ky}} \]
          15. lower-hypot.f6499.6

            \[\leadsto \frac{\sin th}{\frac{\color{blue}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\sin ky}} \]
        4. Applied rewrites99.6%

          \[\leadsto \color{blue}{\frac{\sin th}{\frac{\mathsf{hypot}\left(\sin ky, \sin kx\right)}{\sin ky}}} \]
        5. Taylor expanded in ky around 0

          \[\leadsto \frac{\sin th}{\color{blue}{\frac{\sin kx}{ky}}} \]
        6. Step-by-step derivation
          1. lower-/.f64N/A

            \[\leadsto \frac{\sin th}{\color{blue}{\frac{\sin kx}{ky}}} \]
          2. lower-sin.f6437.5

            \[\leadsto \frac{\sin th}{\frac{\color{blue}{\sin kx}}{ky}} \]
        7. Applied rewrites37.5%

          \[\leadsto \frac{\sin th}{\color{blue}{\frac{\sin kx}{ky}}} \]

        if 4.00000000000000033e-5 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))

        1. Initial program 90.5%

          \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
        2. Add Preprocessing
        3. Taylor expanded in kx around 0

          \[\leadsto \color{blue}{\sin th} \]
        4. Step-by-step derivation
          1. lower-sin.f6456.6

            \[\leadsto \color{blue}{\sin th} \]
        5. Applied rewrites56.6%

          \[\leadsto \color{blue}{\sin th} \]
      3. Recombined 2 regimes into one program.
      4. Add Preprocessing

      Alternative 15: 44.0% accurate, 0.8× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 4 \cdot 10^{-5}:\\ \;\;\;\;\frac{ky}{\sin kx} \cdot \sin th\\ \mathbf{else}:\\ \;\;\;\;\sin th\\ \end{array} \end{array} \]
      (FPCore (kx ky th)
       :precision binary64
       (if (<= (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0)))) 4e-5)
         (* (/ ky (sin kx)) (sin th))
         (sin th)))
      double code(double kx, double ky, double th) {
      	double tmp;
      	if ((sin(ky) / sqrt((pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))) <= 4e-5) {
      		tmp = (ky / sin(kx)) * sin(th);
      	} else {
      		tmp = sin(th);
      	}
      	return tmp;
      }
      
      real(8) function code(kx, ky, th)
          real(8), intent (in) :: kx
          real(8), intent (in) :: ky
          real(8), intent (in) :: th
          real(8) :: tmp
          if ((sin(ky) / sqrt(((sin(kx) ** 2.0d0) + (sin(ky) ** 2.0d0)))) <= 4d-5) then
              tmp = (ky / sin(kx)) * sin(th)
          else
              tmp = sin(th)
          end if
          code = tmp
      end function
      
      public static double code(double kx, double ky, double th) {
      	double tmp;
      	if ((Math.sin(ky) / Math.sqrt((Math.pow(Math.sin(kx), 2.0) + Math.pow(Math.sin(ky), 2.0)))) <= 4e-5) {
      		tmp = (ky / Math.sin(kx)) * Math.sin(th);
      	} else {
      		tmp = Math.sin(th);
      	}
      	return tmp;
      }
      
      def code(kx, ky, th):
      	tmp = 0
      	if (math.sin(ky) / math.sqrt((math.pow(math.sin(kx), 2.0) + math.pow(math.sin(ky), 2.0)))) <= 4e-5:
      		tmp = (ky / math.sin(kx)) * math.sin(th)
      	else:
      		tmp = math.sin(th)
      	return tmp
      
      function code(kx, ky, th)
      	tmp = 0.0
      	if (Float64(sin(ky) / sqrt(Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) <= 4e-5)
      		tmp = Float64(Float64(ky / sin(kx)) * sin(th));
      	else
      		tmp = sin(th);
      	end
      	return tmp
      end
      
      function tmp_2 = code(kx, ky, th)
      	tmp = 0.0;
      	if ((sin(ky) / sqrt(((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) <= 4e-5)
      		tmp = (ky / sin(kx)) * sin(th);
      	else
      		tmp = sin(th);
      	end
      	tmp_2 = tmp;
      end
      
      code[kx_, ky_, th_] := If[LessEqual[N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 4e-5], N[(N[(ky / N[Sin[kx], $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision], N[Sin[th], $MachinePrecision]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 4 \cdot 10^{-5}:\\
      \;\;\;\;\frac{ky}{\sin kx} \cdot \sin th\\
      
      \mathbf{else}:\\
      \;\;\;\;\sin th\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 4.00000000000000033e-5

        1. Initial program 95.2%

          \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
        2. Add Preprocessing
        3. Taylor expanded in ky around 0

          \[\leadsto \color{blue}{\frac{ky}{\sin kx}} \cdot \sin th \]
        4. Step-by-step derivation
          1. lower-/.f64N/A

            \[\leadsto \color{blue}{\frac{ky}{\sin kx}} \cdot \sin th \]
          2. lower-sin.f6437.5

            \[\leadsto \frac{ky}{\color{blue}{\sin kx}} \cdot \sin th \]
        5. Applied rewrites37.5%

          \[\leadsto \color{blue}{\frac{ky}{\sin kx}} \cdot \sin th \]

        if 4.00000000000000033e-5 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))

        1. Initial program 90.5%

          \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
        2. Add Preprocessing
        3. Taylor expanded in kx around 0

          \[\leadsto \color{blue}{\sin th} \]
        4. Step-by-step derivation
          1. lower-sin.f6456.6

            \[\leadsto \color{blue}{\sin th} \]
        5. Applied rewrites56.6%

          \[\leadsto \color{blue}{\sin th} \]
      3. Recombined 2 regimes into one program.
      4. Add Preprocessing

      Alternative 16: 30.6% accurate, 1.0× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 10^{-79}:\\ \;\;\;\;{th}^{3} \cdot -0.16666666666666666\\ \mathbf{else}:\\ \;\;\;\;\sin th\\ \end{array} \end{array} \]
      (FPCore (kx ky th)
       :precision binary64
       (if (<= (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0)))) 1e-79)
         (* (pow th 3.0) -0.16666666666666666)
         (sin th)))
      double code(double kx, double ky, double th) {
      	double tmp;
      	if ((sin(ky) / sqrt((pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))) <= 1e-79) {
      		tmp = pow(th, 3.0) * -0.16666666666666666;
      	} else {
      		tmp = sin(th);
      	}
      	return tmp;
      }
      
      real(8) function code(kx, ky, th)
          real(8), intent (in) :: kx
          real(8), intent (in) :: ky
          real(8), intent (in) :: th
          real(8) :: tmp
          if ((sin(ky) / sqrt(((sin(kx) ** 2.0d0) + (sin(ky) ** 2.0d0)))) <= 1d-79) then
              tmp = (th ** 3.0d0) * (-0.16666666666666666d0)
          else
              tmp = sin(th)
          end if
          code = tmp
      end function
      
      public static double code(double kx, double ky, double th) {
      	double tmp;
      	if ((Math.sin(ky) / Math.sqrt((Math.pow(Math.sin(kx), 2.0) + Math.pow(Math.sin(ky), 2.0)))) <= 1e-79) {
      		tmp = Math.pow(th, 3.0) * -0.16666666666666666;
      	} else {
      		tmp = Math.sin(th);
      	}
      	return tmp;
      }
      
      def code(kx, ky, th):
      	tmp = 0
      	if (math.sin(ky) / math.sqrt((math.pow(math.sin(kx), 2.0) + math.pow(math.sin(ky), 2.0)))) <= 1e-79:
      		tmp = math.pow(th, 3.0) * -0.16666666666666666
      	else:
      		tmp = math.sin(th)
      	return tmp
      
      function code(kx, ky, th)
      	tmp = 0.0
      	if (Float64(sin(ky) / sqrt(Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) <= 1e-79)
      		tmp = Float64((th ^ 3.0) * -0.16666666666666666);
      	else
      		tmp = sin(th);
      	end
      	return tmp
      end
      
      function tmp_2 = code(kx, ky, th)
      	tmp = 0.0;
      	if ((sin(ky) / sqrt(((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) <= 1e-79)
      		tmp = (th ^ 3.0) * -0.16666666666666666;
      	else
      		tmp = sin(th);
      	end
      	tmp_2 = tmp;
      end
      
      code[kx_, ky_, th_] := If[LessEqual[N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 1e-79], N[(N[Power[th, 3.0], $MachinePrecision] * -0.16666666666666666), $MachinePrecision], N[Sin[th], $MachinePrecision]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 10^{-79}:\\
      \;\;\;\;{th}^{3} \cdot -0.16666666666666666\\
      
      \mathbf{else}:\\
      \;\;\;\;\sin th\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 1e-79

        1. Initial program 94.7%

          \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
        2. Add Preprocessing
        3. Taylor expanded in kx around 0

          \[\leadsto \color{blue}{\sin th} \]
        4. Step-by-step derivation
          1. lower-sin.f643.2

            \[\leadsto \color{blue}{\sin th} \]
        5. Applied rewrites3.2%

          \[\leadsto \color{blue}{\sin th} \]
        6. Taylor expanded in th around 0

          \[\leadsto th \cdot \color{blue}{\left(1 + \frac{-1}{6} \cdot {th}^{2}\right)} \]
        7. Step-by-step derivation
          1. Applied rewrites3.2%

            \[\leadsto \mathsf{fma}\left({th}^{3}, \color{blue}{-0.16666666666666666}, th\right) \]
          2. Taylor expanded in th around inf

            \[\leadsto \frac{-1}{6} \cdot {th}^{\color{blue}{3}} \]
          3. Step-by-step derivation
            1. Applied rewrites13.6%

              \[\leadsto {th}^{3} \cdot -0.16666666666666666 \]

            if 1e-79 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))

            1. Initial program 92.1%

              \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
            2. Add Preprocessing
            3. Taylor expanded in kx around 0

              \[\leadsto \color{blue}{\sin th} \]
            4. Step-by-step derivation
              1. lower-sin.f6448.0

                \[\leadsto \color{blue}{\sin th} \]
            5. Applied rewrites48.0%

              \[\leadsto \color{blue}{\sin th} \]
          4. Recombined 2 regimes into one program.
          5. Add Preprocessing

          Alternative 17: 74.9% accurate, 1.2× speedup?

          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;ky \leq 7.1 \cdot 10^{-6}:\\ \;\;\;\;\frac{\sin th \cdot \frac{1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)}}{{ky}^{-1}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sin th \cdot \sin ky}{\frac{\sqrt{\mathsf{fma}\left(1 - \cos \left(2 \cdot ky\right), 2, 2 \cdot \left(1 - \cos \left(2 \cdot kx\right)\right)\right)}}{2}}\\ \end{array} \end{array} \]
          (FPCore (kx ky th)
           :precision binary64
           (if (<= ky 7.1e-6)
             (/ (* (sin th) (/ 1.0 (hypot (sin kx) (sin ky)))) (pow ky -1.0))
             (/
              (* (sin th) (sin ky))
              (/
               (sqrt (fma (- 1.0 (cos (* 2.0 ky))) 2.0 (* 2.0 (- 1.0 (cos (* 2.0 kx))))))
               2.0))))
          double code(double kx, double ky, double th) {
          	double tmp;
          	if (ky <= 7.1e-6) {
          		tmp = (sin(th) * (1.0 / hypot(sin(kx), sin(ky)))) / pow(ky, -1.0);
          	} else {
          		tmp = (sin(th) * sin(ky)) / (sqrt(fma((1.0 - cos((2.0 * ky))), 2.0, (2.0 * (1.0 - cos((2.0 * kx)))))) / 2.0);
          	}
          	return tmp;
          }
          
          function code(kx, ky, th)
          	tmp = 0.0
          	if (ky <= 7.1e-6)
          		tmp = Float64(Float64(sin(th) * Float64(1.0 / hypot(sin(kx), sin(ky)))) / (ky ^ -1.0));
          	else
          		tmp = Float64(Float64(sin(th) * sin(ky)) / Float64(sqrt(fma(Float64(1.0 - cos(Float64(2.0 * ky))), 2.0, Float64(2.0 * Float64(1.0 - cos(Float64(2.0 * kx)))))) / 2.0));
          	end
          	return tmp
          end
          
          code[kx_, ky_, th_] := If[LessEqual[ky, 7.1e-6], N[(N[(N[Sin[th], $MachinePrecision] * N[(1.0 / N[Sqrt[N[Sin[kx], $MachinePrecision] ^ 2 + N[Sin[ky], $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[Power[ky, -1.0], $MachinePrecision]), $MachinePrecision], N[(N[(N[Sin[th], $MachinePrecision] * N[Sin[ky], $MachinePrecision]), $MachinePrecision] / N[(N[Sqrt[N[(N[(1.0 - N[Cos[N[(2.0 * ky), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * 2.0 + N[(2.0 * N[(1.0 - N[Cos[N[(2.0 * kx), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / 2.0), $MachinePrecision]), $MachinePrecision]]
          
          \begin{array}{l}
          
          \\
          \begin{array}{l}
          \mathbf{if}\;ky \leq 7.1 \cdot 10^{-6}:\\
          \;\;\;\;\frac{\sin th \cdot \frac{1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)}}{{ky}^{-1}}\\
          
          \mathbf{else}:\\
          \;\;\;\;\frac{\sin th \cdot \sin ky}{\frac{\sqrt{\mathsf{fma}\left(1 - \cos \left(2 \cdot ky\right), 2, 2 \cdot \left(1 - \cos \left(2 \cdot kx\right)\right)\right)}}{2}}\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if ky < 7.0999999999999998e-6

            1. Initial program 91.9%

              \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
            2. Add Preprocessing
            3. Step-by-step derivation
              1. lift-*.f64N/A

                \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
              2. *-commutativeN/A

                \[\leadsto \color{blue}{\sin th \cdot \frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
              3. lift-/.f64N/A

                \[\leadsto \sin th \cdot \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
              4. clear-numN/A

                \[\leadsto \sin th \cdot \color{blue}{\frac{1}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
              5. un-div-invN/A

                \[\leadsto \color{blue}{\frac{\sin th}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
              6. div-invN/A

                \[\leadsto \frac{\sin th}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}} \cdot \frac{1}{\sin ky}}} \]
              7. associate-/r*N/A

                \[\leadsto \color{blue}{\frac{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \]
              8. lower-/.f64N/A

                \[\leadsto \color{blue}{\frac{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \]
            4. Applied rewrites99.4%

              \[\leadsto \color{blue}{\frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{{\sin ky}^{-1}}} \]
            5. Taylor expanded in ky around 0

              \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
            6. Step-by-step derivation
              1. lower-/.f6471.7

                \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
            7. Applied rewrites71.7%

              \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
            8. Step-by-step derivation
              1. lift-/.f64N/A

                \[\leadsto \frac{\color{blue}{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}}{\frac{1}{ky}} \]
              2. frac-2negN/A

                \[\leadsto \frac{\color{blue}{\frac{\mathsf{neg}\left(\sin th\right)}{\mathsf{neg}\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}}}{\frac{1}{ky}} \]
              3. div-invN/A

                \[\leadsto \frac{\color{blue}{\left(\mathsf{neg}\left(\sin th\right)\right) \cdot \frac{1}{\mathsf{neg}\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}}}{\frac{1}{ky}} \]
              4. distribute-neg-frac2N/A

                \[\leadsto \frac{\left(\mathsf{neg}\left(\sin th\right)\right) \cdot \color{blue}{\left(\mathsf{neg}\left(\frac{1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}\right)\right)}}{\frac{1}{ky}} \]
              5. unpow-1N/A

                \[\leadsto \frac{\left(\mathsf{neg}\left(\sin th\right)\right) \cdot \left(\mathsf{neg}\left(\color{blue}{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}\right)\right)}{\frac{1}{ky}} \]
              6. lift-pow.f64N/A

                \[\leadsto \frac{\left(\mathsf{neg}\left(\sin th\right)\right) \cdot \left(\mathsf{neg}\left(\color{blue}{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}\right)\right)}{\frac{1}{ky}} \]
              7. lower-*.f64N/A

                \[\leadsto \frac{\color{blue}{\left(\mathsf{neg}\left(\sin th\right)\right) \cdot \left(\mathsf{neg}\left({\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}\right)\right)}}{\frac{1}{ky}} \]
              8. lower-neg.f64N/A

                \[\leadsto \frac{\color{blue}{\left(-\sin th\right)} \cdot \left(\mathsf{neg}\left({\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}\right)\right)}{\frac{1}{ky}} \]
              9. lift-pow.f64N/A

                \[\leadsto \frac{\left(-\sin th\right) \cdot \left(\mathsf{neg}\left(\color{blue}{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}\right)\right)}{\frac{1}{ky}} \]
              10. unpow-1N/A

                \[\leadsto \frac{\left(-\sin th\right) \cdot \left(\mathsf{neg}\left(\color{blue}{\frac{1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}\right)\right)}{\frac{1}{ky}} \]
              11. distribute-neg-fracN/A

                \[\leadsto \frac{\left(-\sin th\right) \cdot \color{blue}{\frac{\mathsf{neg}\left(1\right)}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}}{\frac{1}{ky}} \]
              12. metadata-evalN/A

                \[\leadsto \frac{\left(-\sin th\right) \cdot \frac{\color{blue}{-1}}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\frac{1}{ky}} \]
              13. lower-/.f6471.7

                \[\leadsto \frac{\left(-\sin th\right) \cdot \color{blue}{\frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}}{\frac{1}{ky}} \]
              14. lift-sin.f64N/A

                \[\leadsto \frac{\left(-\sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \color{blue}{\sin kx}\right)}}{\frac{1}{ky}} \]
              15. lift-hypot.f64N/A

                \[\leadsto \frac{\left(-\sin th\right) \cdot \frac{-1}{\color{blue}{\sqrt{\sin ky \cdot \sin ky + \sin kx \cdot \sin kx}}}}{\frac{1}{ky}} \]
              16. +-commutativeN/A

                \[\leadsto \frac{\left(-\sin th\right) \cdot \frac{-1}{\sqrt{\color{blue}{\sin kx \cdot \sin kx + \sin ky \cdot \sin ky}}}}{\frac{1}{ky}} \]
              17. lower-hypot.f64N/A

                \[\leadsto \frac{\left(-\sin th\right) \cdot \frac{-1}{\color{blue}{\mathsf{hypot}\left(\sin kx, \sin ky\right)}}}{\frac{1}{ky}} \]
              18. lift-sin.f6471.7

                \[\leadsto \frac{\left(-\sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\color{blue}{\sin kx}, \sin ky\right)}}{\frac{1}{ky}} \]
            9. Applied rewrites71.7%

              \[\leadsto \frac{\color{blue}{\left(-\sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)}}}{\frac{1}{ky}} \]

            if 7.0999999999999998e-6 < ky

            1. Initial program 99.5%

              \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
            2. Add Preprocessing
            3. Step-by-step derivation
              1. lift-*.f64N/A

                \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
              2. lift-/.f64N/A

                \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin th \]
              3. associate-*l/N/A

                \[\leadsto \color{blue}{\frac{\sin ky \cdot \sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
              4. lower-/.f64N/A

                \[\leadsto \color{blue}{\frac{\sin ky \cdot \sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
              5. *-commutativeN/A

                \[\leadsto \frac{\color{blue}{\sin th \cdot \sin ky}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \]
              6. lower-*.f6499.4

                \[\leadsto \frac{\color{blue}{\sin th \cdot \sin ky}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \]
              7. lift-sqrt.f64N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
              8. lift-+.f64N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\color{blue}{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
              9. +-commutativeN/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\color{blue}{{\sin ky}^{2} + {\sin kx}^{2}}}} \]
              10. lift-pow.f64N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\color{blue}{{\sin ky}^{2}} + {\sin kx}^{2}}} \]
              11. unpow2N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\color{blue}{\sin ky \cdot \sin ky} + {\sin kx}^{2}}} \]
              12. lift-pow.f64N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\sin ky \cdot \sin ky + \color{blue}{{\sin kx}^{2}}}} \]
              13. unpow2N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\sin ky \cdot \sin ky + \color{blue}{\sin kx \cdot \sin kx}}} \]
              14. lower-hypot.f6499.4

                \[\leadsto \frac{\sin th \cdot \sin ky}{\color{blue}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
            4. Applied rewrites99.4%

              \[\leadsto \color{blue}{\frac{\sin th \cdot \sin ky}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
            5. Step-by-step derivation
              1. lift-sin.f64N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\mathsf{hypot}\left(\sin ky, \color{blue}{\sin kx}\right)} \]
              2. lift-hypot.f64N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\color{blue}{\sqrt{\sin ky \cdot \sin ky + \sin kx \cdot \sin kx}}} \]
              3. lift-sin.f64N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\color{blue}{\sin ky} \cdot \sin ky + \sin kx \cdot \sin kx}} \]
              4. lift-sin.f64N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\sin ky \cdot \color{blue}{\sin ky} + \sin kx \cdot \sin kx}} \]
              5. sin-multN/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\color{blue}{\frac{\cos \left(ky - ky\right) - \cos \left(ky + ky\right)}{2}} + \sin kx \cdot \sin kx}} \]
              6. sin-multN/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\frac{\cos \left(ky - ky\right) - \cos \left(ky + ky\right)}{2} + \color{blue}{\frac{\cos \left(kx - kx\right) - \cos \left(kx + kx\right)}{2}}}} \]
              7. frac-addN/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\color{blue}{\frac{\left(\cos \left(ky - ky\right) - \cos \left(ky + ky\right)\right) \cdot 2 + 2 \cdot \left(\cos \left(kx - kx\right) - \cos \left(kx + kx\right)\right)}{2 \cdot 2}}}} \]
              8. metadata-evalN/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\frac{\left(\cos \left(ky - ky\right) - \cos \left(ky + ky\right)\right) \cdot 2 + 2 \cdot \left(\cos \left(kx - kx\right) - \cos \left(kx + kx\right)\right)}{\color{blue}{4}}}} \]
              9. metadata-evalN/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\frac{\left(\cos \left(ky - ky\right) - \cos \left(ky + ky\right)\right) \cdot 2 + 2 \cdot \left(\cos \left(kx - kx\right) - \cos \left(kx + kx\right)\right)}{\color{blue}{2 + 2}}}} \]
              10. sqrt-divN/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\color{blue}{\frac{\sqrt{\left(\cos \left(ky - ky\right) - \cos \left(ky + ky\right)\right) \cdot 2 + 2 \cdot \left(\cos \left(kx - kx\right) - \cos \left(kx + kx\right)\right)}}{\sqrt{2 + 2}}}} \]
              11. metadata-evalN/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\frac{\sqrt{\left(\cos \left(ky - ky\right) - \cos \left(ky + ky\right)\right) \cdot 2 + 2 \cdot \left(\cos \left(kx - kx\right) - \cos \left(kx + kx\right)\right)}}{\sqrt{\color{blue}{4}}}} \]
              12. metadata-evalN/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\frac{\sqrt{\left(\cos \left(ky - ky\right) - \cos \left(ky + ky\right)\right) \cdot 2 + 2 \cdot \left(\cos \left(kx - kx\right) - \cos \left(kx + kx\right)\right)}}{\color{blue}{2}}} \]
            6. Applied rewrites97.3%

              \[\leadsto \frac{\sin th \cdot \sin ky}{\color{blue}{\frac{\sqrt{\mathsf{fma}\left(1 - \cos \left(2 \cdot ky\right), 2, 2 \cdot \left(1 - \cos \left(2 \cdot kx\right)\right)\right)}}{2}}} \]
          3. Recombined 2 regimes into one program.
          4. Final simplification77.8%

            \[\leadsto \begin{array}{l} \mathbf{if}\;ky \leq 7.1 \cdot 10^{-6}:\\ \;\;\;\;\frac{\sin th \cdot \frac{1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)}}{{ky}^{-1}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sin th \cdot \sin ky}{\frac{\sqrt{\mathsf{fma}\left(1 - \cos \left(2 \cdot ky\right), 2, 2 \cdot \left(1 - \cos \left(2 \cdot kx\right)\right)\right)}}{2}}\\ \end{array} \]
          5. Add Preprocessing

          Alternative 18: 74.9% accurate, 1.2× speedup?

          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;ky \leq 7.1 \cdot 10^{-6}:\\ \;\;\;\;\frac{\sin th \cdot \frac{1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)}}{{ky}^{-1}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sin ky}{\frac{\sqrt{\mathsf{fma}\left(1 - \cos \left(ky \cdot 2\right), 2, 2 \cdot \left(1 - \cos \left(2 \cdot kx\right)\right)\right)}}{2}} \cdot \sin th\\ \end{array} \end{array} \]
          (FPCore (kx ky th)
           :precision binary64
           (if (<= ky 7.1e-6)
             (/ (* (sin th) (/ 1.0 (hypot (sin kx) (sin ky)))) (pow ky -1.0))
             (*
              (/
               (sin ky)
               (/
                (sqrt
                 (fma (- 1.0 (cos (* ky 2.0))) 2.0 (* 2.0 (- 1.0 (cos (* 2.0 kx))))))
                2.0))
              (sin th))))
          double code(double kx, double ky, double th) {
          	double tmp;
          	if (ky <= 7.1e-6) {
          		tmp = (sin(th) * (1.0 / hypot(sin(kx), sin(ky)))) / pow(ky, -1.0);
          	} else {
          		tmp = (sin(ky) / (sqrt(fma((1.0 - cos((ky * 2.0))), 2.0, (2.0 * (1.0 - cos((2.0 * kx)))))) / 2.0)) * sin(th);
          	}
          	return tmp;
          }
          
          function code(kx, ky, th)
          	tmp = 0.0
          	if (ky <= 7.1e-6)
          		tmp = Float64(Float64(sin(th) * Float64(1.0 / hypot(sin(kx), sin(ky)))) / (ky ^ -1.0));
          	else
          		tmp = Float64(Float64(sin(ky) / Float64(sqrt(fma(Float64(1.0 - cos(Float64(ky * 2.0))), 2.0, Float64(2.0 * Float64(1.0 - cos(Float64(2.0 * kx)))))) / 2.0)) * sin(th));
          	end
          	return tmp
          end
          
          code[kx_, ky_, th_] := If[LessEqual[ky, 7.1e-6], N[(N[(N[Sin[th], $MachinePrecision] * N[(1.0 / N[Sqrt[N[Sin[kx], $MachinePrecision] ^ 2 + N[Sin[ky], $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[Power[ky, -1.0], $MachinePrecision]), $MachinePrecision], N[(N[(N[Sin[ky], $MachinePrecision] / N[(N[Sqrt[N[(N[(1.0 - N[Cos[N[(ky * 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * 2.0 + N[(2.0 * N[(1.0 - N[Cos[N[(2.0 * kx), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / 2.0), $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision]]
          
          \begin{array}{l}
          
          \\
          \begin{array}{l}
          \mathbf{if}\;ky \leq 7.1 \cdot 10^{-6}:\\
          \;\;\;\;\frac{\sin th \cdot \frac{1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)}}{{ky}^{-1}}\\
          
          \mathbf{else}:\\
          \;\;\;\;\frac{\sin ky}{\frac{\sqrt{\mathsf{fma}\left(1 - \cos \left(ky \cdot 2\right), 2, 2 \cdot \left(1 - \cos \left(2 \cdot kx\right)\right)\right)}}{2}} \cdot \sin th\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if ky < 7.0999999999999998e-6

            1. Initial program 91.9%

              \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
            2. Add Preprocessing
            3. Step-by-step derivation
              1. lift-*.f64N/A

                \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
              2. *-commutativeN/A

                \[\leadsto \color{blue}{\sin th \cdot \frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
              3. lift-/.f64N/A

                \[\leadsto \sin th \cdot \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
              4. clear-numN/A

                \[\leadsto \sin th \cdot \color{blue}{\frac{1}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
              5. un-div-invN/A

                \[\leadsto \color{blue}{\frac{\sin th}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
              6. div-invN/A

                \[\leadsto \frac{\sin th}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}} \cdot \frac{1}{\sin ky}}} \]
              7. associate-/r*N/A

                \[\leadsto \color{blue}{\frac{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \]
              8. lower-/.f64N/A

                \[\leadsto \color{blue}{\frac{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \]
            4. Applied rewrites99.4%

              \[\leadsto \color{blue}{\frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{{\sin ky}^{-1}}} \]
            5. Taylor expanded in ky around 0

              \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
            6. Step-by-step derivation
              1. lower-/.f6471.7

                \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
            7. Applied rewrites71.7%

              \[\leadsto \frac{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\color{blue}{\frac{1}{ky}}} \]
            8. Step-by-step derivation
              1. lift-/.f64N/A

                \[\leadsto \frac{\color{blue}{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}}{\frac{1}{ky}} \]
              2. frac-2negN/A

                \[\leadsto \frac{\color{blue}{\frac{\mathsf{neg}\left(\sin th\right)}{\mathsf{neg}\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}}}{\frac{1}{ky}} \]
              3. div-invN/A

                \[\leadsto \frac{\color{blue}{\left(\mathsf{neg}\left(\sin th\right)\right) \cdot \frac{1}{\mathsf{neg}\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}}}{\frac{1}{ky}} \]
              4. distribute-neg-frac2N/A

                \[\leadsto \frac{\left(\mathsf{neg}\left(\sin th\right)\right) \cdot \color{blue}{\left(\mathsf{neg}\left(\frac{1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}\right)\right)}}{\frac{1}{ky}} \]
              5. unpow-1N/A

                \[\leadsto \frac{\left(\mathsf{neg}\left(\sin th\right)\right) \cdot \left(\mathsf{neg}\left(\color{blue}{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}\right)\right)}{\frac{1}{ky}} \]
              6. lift-pow.f64N/A

                \[\leadsto \frac{\left(\mathsf{neg}\left(\sin th\right)\right) \cdot \left(\mathsf{neg}\left(\color{blue}{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}\right)\right)}{\frac{1}{ky}} \]
              7. lower-*.f64N/A

                \[\leadsto \frac{\color{blue}{\left(\mathsf{neg}\left(\sin th\right)\right) \cdot \left(\mathsf{neg}\left({\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}\right)\right)}}{\frac{1}{ky}} \]
              8. lower-neg.f64N/A

                \[\leadsto \frac{\color{blue}{\left(-\sin th\right)} \cdot \left(\mathsf{neg}\left({\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}\right)\right)}{\frac{1}{ky}} \]
              9. lift-pow.f64N/A

                \[\leadsto \frac{\left(-\sin th\right) \cdot \left(\mathsf{neg}\left(\color{blue}{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}\right)\right)}{\frac{1}{ky}} \]
              10. unpow-1N/A

                \[\leadsto \frac{\left(-\sin th\right) \cdot \left(\mathsf{neg}\left(\color{blue}{\frac{1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}\right)\right)}{\frac{1}{ky}} \]
              11. distribute-neg-fracN/A

                \[\leadsto \frac{\left(-\sin th\right) \cdot \color{blue}{\frac{\mathsf{neg}\left(1\right)}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}}{\frac{1}{ky}} \]
              12. metadata-evalN/A

                \[\leadsto \frac{\left(-\sin th\right) \cdot \frac{\color{blue}{-1}}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\frac{1}{ky}} \]
              13. lower-/.f6471.7

                \[\leadsto \frac{\left(-\sin th\right) \cdot \color{blue}{\frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}}{\frac{1}{ky}} \]
              14. lift-sin.f64N/A

                \[\leadsto \frac{\left(-\sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \color{blue}{\sin kx}\right)}}{\frac{1}{ky}} \]
              15. lift-hypot.f64N/A

                \[\leadsto \frac{\left(-\sin th\right) \cdot \frac{-1}{\color{blue}{\sqrt{\sin ky \cdot \sin ky + \sin kx \cdot \sin kx}}}}{\frac{1}{ky}} \]
              16. +-commutativeN/A

                \[\leadsto \frac{\left(-\sin th\right) \cdot \frac{-1}{\sqrt{\color{blue}{\sin kx \cdot \sin kx + \sin ky \cdot \sin ky}}}}{\frac{1}{ky}} \]
              17. lower-hypot.f64N/A

                \[\leadsto \frac{\left(-\sin th\right) \cdot \frac{-1}{\color{blue}{\mathsf{hypot}\left(\sin kx, \sin ky\right)}}}{\frac{1}{ky}} \]
              18. lift-sin.f6471.7

                \[\leadsto \frac{\left(-\sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\color{blue}{\sin kx}, \sin ky\right)}}{\frac{1}{ky}} \]
            9. Applied rewrites71.7%

              \[\leadsto \frac{\color{blue}{\left(-\sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)}}}{\frac{1}{ky}} \]

            if 7.0999999999999998e-6 < ky

            1. Initial program 99.5%

              \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
            2. Add Preprocessing
            3. Step-by-step derivation
              1. lift-sqrt.f64N/A

                \[\leadsto \frac{\sin ky}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin th \]
              2. lift-+.f64N/A

                \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin th \]
              3. +-commutativeN/A

                \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{{\sin ky}^{2} + {\sin kx}^{2}}}} \cdot \sin th \]
              4. lift-pow.f64N/A

                \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{{\sin ky}^{2}} + {\sin kx}^{2}}} \cdot \sin th \]
              5. unpow2N/A

                \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\sin ky \cdot \sin ky} + {\sin kx}^{2}}} \cdot \sin th \]
              6. lift-sin.f64N/A

                \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\sin ky} \cdot \sin ky + {\sin kx}^{2}}} \cdot \sin th \]
              7. lift-sin.f64N/A

                \[\leadsto \frac{\sin ky}{\sqrt{\sin ky \cdot \color{blue}{\sin ky} + {\sin kx}^{2}}} \cdot \sin th \]
              8. sin-multN/A

                \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\frac{\cos \left(ky - ky\right) - \cos \left(ky + ky\right)}{2}} + {\sin kx}^{2}}} \cdot \sin th \]
              9. lift-pow.f64N/A

                \[\leadsto \frac{\sin ky}{\sqrt{\frac{\cos \left(ky - ky\right) - \cos \left(ky + ky\right)}{2} + \color{blue}{{\sin kx}^{2}}}} \cdot \sin th \]
              10. unpow2N/A

                \[\leadsto \frac{\sin ky}{\sqrt{\frac{\cos \left(ky - ky\right) - \cos \left(ky + ky\right)}{2} + \color{blue}{\sin kx \cdot \sin kx}}} \cdot \sin th \]
              11. lift-sin.f64N/A

                \[\leadsto \frac{\sin ky}{\sqrt{\frac{\cos \left(ky - ky\right) - \cos \left(ky + ky\right)}{2} + \color{blue}{\sin kx} \cdot \sin kx}} \cdot \sin th \]
              12. lift-sin.f64N/A

                \[\leadsto \frac{\sin ky}{\sqrt{\frac{\cos \left(ky - ky\right) - \cos \left(ky + ky\right)}{2} + \sin kx \cdot \color{blue}{\sin kx}}} \cdot \sin th \]
              13. sin-multN/A

                \[\leadsto \frac{\sin ky}{\sqrt{\frac{\cos \left(ky - ky\right) - \cos \left(ky + ky\right)}{2} + \color{blue}{\frac{\cos \left(kx - kx\right) - \cos \left(kx + kx\right)}{2}}}} \cdot \sin th \]
              14. frac-addN/A

                \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\frac{\left(\cos \left(ky - ky\right) - \cos \left(ky + ky\right)\right) \cdot 2 + 2 \cdot \left(\cos \left(kx - kx\right) - \cos \left(kx + kx\right)\right)}{2 \cdot 2}}}} \cdot \sin th \]
              15. metadata-evalN/A

                \[\leadsto \frac{\sin ky}{\sqrt{\frac{\left(\cos \left(ky - ky\right) - \cos \left(ky + ky\right)\right) \cdot 2 + 2 \cdot \left(\cos \left(kx - kx\right) - \cos \left(kx + kx\right)\right)}{\color{blue}{4}}}} \cdot \sin th \]
              16. metadata-evalN/A

                \[\leadsto \frac{\sin ky}{\sqrt{\frac{\left(\cos \left(ky - ky\right) - \cos \left(ky + ky\right)\right) \cdot 2 + 2 \cdot \left(\cos \left(kx - kx\right) - \cos \left(kx + kx\right)\right)}{\color{blue}{2 + 2}}}} \cdot \sin th \]
              17. sqrt-divN/A

                \[\leadsto \frac{\sin ky}{\color{blue}{\frac{\sqrt{\left(\cos \left(ky - ky\right) - \cos \left(ky + ky\right)\right) \cdot 2 + 2 \cdot \left(\cos \left(kx - kx\right) - \cos \left(kx + kx\right)\right)}}{\sqrt{2 + 2}}}} \cdot \sin th \]
            4. Applied rewrites97.3%

              \[\leadsto \frac{\sin ky}{\color{blue}{\frac{\sqrt{\mathsf{fma}\left(1 - \cos \left(ky \cdot 2\right), 2, 2 \cdot \left(1 - \cos \left(2 \cdot kx\right)\right)\right)}}{2}}} \cdot \sin th \]
          3. Recombined 2 regimes into one program.
          4. Final simplification77.8%

            \[\leadsto \begin{array}{l} \mathbf{if}\;ky \leq 7.1 \cdot 10^{-6}:\\ \;\;\;\;\frac{\sin th \cdot \frac{1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)}}{{ky}^{-1}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sin ky}{\frac{\sqrt{\mathsf{fma}\left(1 - \cos \left(ky \cdot 2\right), 2, 2 \cdot \left(1 - \cos \left(2 \cdot kx\right)\right)\right)}}{2}} \cdot \sin th\\ \end{array} \]
          5. Add Preprocessing

          Alternative 19: 99.6% accurate, 1.2× speedup?

          \[\begin{array}{l} \\ \frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \cdot \sin ky \end{array} \]
          (FPCore (kx ky th)
           :precision binary64
           (* (/ (sin th) (hypot (sin ky) (sin kx))) (sin ky)))
          double code(double kx, double ky, double th) {
          	return (sin(th) / hypot(sin(ky), sin(kx))) * sin(ky);
          }
          
          public static double code(double kx, double ky, double th) {
          	return (Math.sin(th) / Math.hypot(Math.sin(ky), Math.sin(kx))) * Math.sin(ky);
          }
          
          def code(kx, ky, th):
          	return (math.sin(th) / math.hypot(math.sin(ky), math.sin(kx))) * math.sin(ky)
          
          function code(kx, ky, th)
          	return Float64(Float64(sin(th) / hypot(sin(ky), sin(kx))) * sin(ky))
          end
          
          function tmp = code(kx, ky, th)
          	tmp = (sin(th) / hypot(sin(ky), sin(kx))) * sin(ky);
          end
          
          code[kx_, ky_, th_] := N[(N[(N[Sin[th], $MachinePrecision] / N[Sqrt[N[Sin[ky], $MachinePrecision] ^ 2 + N[Sin[kx], $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision] * N[Sin[ky], $MachinePrecision]), $MachinePrecision]
          
          \begin{array}{l}
          
          \\
          \frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \cdot \sin ky
          \end{array}
          
          Derivation
          1. Initial program 93.7%

            \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
          2. Add Preprocessing
          3. Step-by-step derivation
            1. lift-*.f64N/A

              \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
            2. lift-/.f64N/A

              \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin th \]
            3. associate-*l/N/A

              \[\leadsto \color{blue}{\frac{\sin ky \cdot \sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
            4. associate-/l*N/A

              \[\leadsto \color{blue}{\sin ky \cdot \frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
            5. *-commutativeN/A

              \[\leadsto \color{blue}{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin ky} \]
            6. lower-*.f64N/A

              \[\leadsto \color{blue}{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin ky} \]
            7. lower-/.f6493.6

              \[\leadsto \color{blue}{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin ky \]
            8. lift-sqrt.f64N/A

              \[\leadsto \frac{\sin th}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin ky \]
            9. lift-+.f64N/A

              \[\leadsto \frac{\sin th}{\sqrt{\color{blue}{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin ky \]
            10. +-commutativeN/A

              \[\leadsto \frac{\sin th}{\sqrt{\color{blue}{{\sin ky}^{2} + {\sin kx}^{2}}}} \cdot \sin ky \]
            11. lift-pow.f64N/A

              \[\leadsto \frac{\sin th}{\sqrt{\color{blue}{{\sin ky}^{2}} + {\sin kx}^{2}}} \cdot \sin ky \]
            12. unpow2N/A

              \[\leadsto \frac{\sin th}{\sqrt{\color{blue}{\sin ky \cdot \sin ky} + {\sin kx}^{2}}} \cdot \sin ky \]
            13. lift-pow.f64N/A

              \[\leadsto \frac{\sin th}{\sqrt{\sin ky \cdot \sin ky + \color{blue}{{\sin kx}^{2}}}} \cdot \sin ky \]
            14. unpow2N/A

              \[\leadsto \frac{\sin th}{\sqrt{\sin ky \cdot \sin ky + \color{blue}{\sin kx \cdot \sin kx}}} \cdot \sin ky \]
            15. lower-hypot.f6499.4

              \[\leadsto \frac{\sin th}{\color{blue}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \cdot \sin ky \]
          4. Applied rewrites99.4%

            \[\leadsto \color{blue}{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \cdot \sin ky} \]
          5. Add Preprocessing

          Alternative 20: 63.0% accurate, 1.5× speedup?

          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;th \leq 5.9 \cdot 10^{-5}:\\ \;\;\;\;\frac{\sin ky}{\frac{\mathsf{hypot}\left(\sin kx, \sin ky\right)}{th}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sin th \cdot ky}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}\\ \end{array} \end{array} \]
          (FPCore (kx ky th)
           :precision binary64
           (if (<= th 5.9e-5)
             (/ (sin ky) (/ (hypot (sin kx) (sin ky)) th))
             (/ (* (sin th) ky) (hypot (sin ky) (sin kx)))))
          double code(double kx, double ky, double th) {
          	double tmp;
          	if (th <= 5.9e-5) {
          		tmp = sin(ky) / (hypot(sin(kx), sin(ky)) / th);
          	} else {
          		tmp = (sin(th) * ky) / hypot(sin(ky), sin(kx));
          	}
          	return tmp;
          }
          
          public static double code(double kx, double ky, double th) {
          	double tmp;
          	if (th <= 5.9e-5) {
          		tmp = Math.sin(ky) / (Math.hypot(Math.sin(kx), Math.sin(ky)) / th);
          	} else {
          		tmp = (Math.sin(th) * ky) / Math.hypot(Math.sin(ky), Math.sin(kx));
          	}
          	return tmp;
          }
          
          def code(kx, ky, th):
          	tmp = 0
          	if th <= 5.9e-5:
          		tmp = math.sin(ky) / (math.hypot(math.sin(kx), math.sin(ky)) / th)
          	else:
          		tmp = (math.sin(th) * ky) / math.hypot(math.sin(ky), math.sin(kx))
          	return tmp
          
          function code(kx, ky, th)
          	tmp = 0.0
          	if (th <= 5.9e-5)
          		tmp = Float64(sin(ky) / Float64(hypot(sin(kx), sin(ky)) / th));
          	else
          		tmp = Float64(Float64(sin(th) * ky) / hypot(sin(ky), sin(kx)));
          	end
          	return tmp
          end
          
          function tmp_2 = code(kx, ky, th)
          	tmp = 0.0;
          	if (th <= 5.9e-5)
          		tmp = sin(ky) / (hypot(sin(kx), sin(ky)) / th);
          	else
          		tmp = (sin(th) * ky) / hypot(sin(ky), sin(kx));
          	end
          	tmp_2 = tmp;
          end
          
          code[kx_, ky_, th_] := If[LessEqual[th, 5.9e-5], N[(N[Sin[ky], $MachinePrecision] / N[(N[Sqrt[N[Sin[kx], $MachinePrecision] ^ 2 + N[Sin[ky], $MachinePrecision] ^ 2], $MachinePrecision] / th), $MachinePrecision]), $MachinePrecision], N[(N[(N[Sin[th], $MachinePrecision] * ky), $MachinePrecision] / N[Sqrt[N[Sin[ky], $MachinePrecision] ^ 2 + N[Sin[kx], $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision]]
          
          \begin{array}{l}
          
          \\
          \begin{array}{l}
          \mathbf{if}\;th \leq 5.9 \cdot 10^{-5}:\\
          \;\;\;\;\frac{\sin ky}{\frac{\mathsf{hypot}\left(\sin kx, \sin ky\right)}{th}}\\
          
          \mathbf{else}:\\
          \;\;\;\;\frac{\sin th \cdot ky}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if th < 5.8999999999999998e-5

            1. Initial program 94.6%

              \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
            2. Add Preprocessing
            3. Step-by-step derivation
              1. lift-/.f64N/A

                \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin th \]
              2. clear-numN/A

                \[\leadsto \color{blue}{\frac{1}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \cdot \sin th \]
              3. div-invN/A

                \[\leadsto \frac{1}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}} \cdot \frac{1}{\sin ky}}} \cdot \sin th \]
              4. associate-/r*N/A

                \[\leadsto \color{blue}{\frac{\frac{1}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \cdot \sin th \]
              5. lower-/.f64N/A

                \[\leadsto \color{blue}{\frac{\frac{1}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\frac{1}{\sin ky}}} \cdot \sin th \]
              6. inv-powN/A

                \[\leadsto \frac{\color{blue}{{\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}^{-1}}}{\frac{1}{\sin ky}} \cdot \sin th \]
              7. lower-pow.f64N/A

                \[\leadsto \frac{\color{blue}{{\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}^{-1}}}{\frac{1}{\sin ky}} \cdot \sin th \]
              8. lift-sqrt.f64N/A

                \[\leadsto \frac{{\color{blue}{\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}}^{-1}}{\frac{1}{\sin ky}} \cdot \sin th \]
              9. lift-+.f64N/A

                \[\leadsto \frac{{\left(\sqrt{\color{blue}{{\sin kx}^{2} + {\sin ky}^{2}}}\right)}^{-1}}{\frac{1}{\sin ky}} \cdot \sin th \]
              10. +-commutativeN/A

                \[\leadsto \frac{{\left(\sqrt{\color{blue}{{\sin ky}^{2} + {\sin kx}^{2}}}\right)}^{-1}}{\frac{1}{\sin ky}} \cdot \sin th \]
              11. lift-pow.f64N/A

                \[\leadsto \frac{{\left(\sqrt{\color{blue}{{\sin ky}^{2}} + {\sin kx}^{2}}\right)}^{-1}}{\frac{1}{\sin ky}} \cdot \sin th \]
              12. unpow2N/A

                \[\leadsto \frac{{\left(\sqrt{\color{blue}{\sin ky \cdot \sin ky} + {\sin kx}^{2}}\right)}^{-1}}{\frac{1}{\sin ky}} \cdot \sin th \]
              13. lift-pow.f64N/A

                \[\leadsto \frac{{\left(\sqrt{\sin ky \cdot \sin ky + \color{blue}{{\sin kx}^{2}}}\right)}^{-1}}{\frac{1}{\sin ky}} \cdot \sin th \]
              14. unpow2N/A

                \[\leadsto \frac{{\left(\sqrt{\sin ky \cdot \sin ky + \color{blue}{\sin kx \cdot \sin kx}}\right)}^{-1}}{\frac{1}{\sin ky}} \cdot \sin th \]
              15. lower-hypot.f64N/A

                \[\leadsto \frac{{\color{blue}{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}}^{-1}}{\frac{1}{\sin ky}} \cdot \sin th \]
              16. inv-powN/A

                \[\leadsto \frac{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}{\color{blue}{{\sin ky}^{-1}}} \cdot \sin th \]
              17. lower-pow.f6499.5

                \[\leadsto \frac{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}{\color{blue}{{\sin ky}^{-1}}} \cdot \sin th \]
            4. Applied rewrites99.5%

              \[\leadsto \color{blue}{\frac{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}{{\sin ky}^{-1}}} \cdot \sin th \]
            5. Step-by-step derivation
              1. lift-*.f64N/A

                \[\leadsto \color{blue}{\frac{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}{{\sin ky}^{-1}} \cdot \sin th} \]
              2. lift-/.f64N/A

                \[\leadsto \color{blue}{\frac{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}{{\sin ky}^{-1}}} \cdot \sin th \]
              3. clear-numN/A

                \[\leadsto \color{blue}{\frac{1}{\frac{{\sin ky}^{-1}}{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}}} \cdot \sin th \]
              4. associate-*l/N/A

                \[\leadsto \color{blue}{\frac{1 \cdot \sin th}{\frac{{\sin ky}^{-1}}{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}}} \]
              5. lift-pow.f64N/A

                \[\leadsto \frac{1 \cdot \sin th}{\frac{{\sin ky}^{-1}}{\color{blue}{{\left(\mathsf{hypot}\left(\sin ky, \sin kx\right)\right)}^{-1}}}} \]
              6. unpow-1N/A

                \[\leadsto \frac{1 \cdot \sin th}{\frac{{\sin ky}^{-1}}{\color{blue}{\frac{1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}}} \]
              7. associate-/r/N/A

                \[\leadsto \frac{1 \cdot \sin th}{\color{blue}{\frac{{\sin ky}^{-1}}{1} \cdot \mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
              8. times-fracN/A

                \[\leadsto \color{blue}{\frac{1}{\frac{{\sin ky}^{-1}}{1}} \cdot \frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
              9. clear-numN/A

                \[\leadsto \color{blue}{\frac{1}{{\sin ky}^{-1}}} \cdot \frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
              10. lift-pow.f64N/A

                \[\leadsto \frac{1}{\color{blue}{{\sin ky}^{-1}}} \cdot \frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
              11. unpow-1N/A

                \[\leadsto \frac{1}{\color{blue}{\frac{1}{\sin ky}}} \cdot \frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
              12. remove-double-divN/A

                \[\leadsto \color{blue}{\sin ky} \cdot \frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
              13. clear-numN/A

                \[\leadsto \sin ky \cdot \color{blue}{\frac{1}{\frac{\mathsf{hypot}\left(\sin ky, \sin kx\right)}{\sin th}}} \]
              14. un-div-invN/A

                \[\leadsto \color{blue}{\frac{\sin ky}{\frac{\mathsf{hypot}\left(\sin ky, \sin kx\right)}{\sin th}}} \]
              15. lower-/.f64N/A

                \[\leadsto \color{blue}{\frac{\sin ky}{\frac{\mathsf{hypot}\left(\sin ky, \sin kx\right)}{\sin th}}} \]
            6. Applied rewrites99.6%

              \[\leadsto \color{blue}{\frac{\sin ky}{\frac{\mathsf{hypot}\left(\sin kx, \sin ky\right)}{\sin th}}} \]
            7. Taylor expanded in th around 0

              \[\leadsto \frac{\sin ky}{\color{blue}{\frac{1}{th} \cdot \sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
            8. Step-by-step derivation
              1. associate-*l/N/A

                \[\leadsto \frac{\sin ky}{\color{blue}{\frac{1 \cdot \sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{th}}} \]
              2. *-lft-identityN/A

                \[\leadsto \frac{\sin ky}{\frac{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{th}} \]
              3. lower-/.f64N/A

                \[\leadsto \frac{\sin ky}{\color{blue}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{th}}} \]
              4. unpow2N/A

                \[\leadsto \frac{\sin ky}{\frac{\sqrt{\color{blue}{\sin kx \cdot \sin kx} + {\sin ky}^{2}}}{th}} \]
              5. unpow2N/A

                \[\leadsto \frac{\sin ky}{\frac{\sqrt{\sin kx \cdot \sin kx + \color{blue}{\sin ky \cdot \sin ky}}}{th}} \]
              6. lower-hypot.f64N/A

                \[\leadsto \frac{\sin ky}{\frac{\color{blue}{\mathsf{hypot}\left(\sin kx, \sin ky\right)}}{th}} \]
              7. lower-sin.f64N/A

                \[\leadsto \frac{\sin ky}{\frac{\mathsf{hypot}\left(\color{blue}{\sin kx}, \sin ky\right)}{th}} \]
              8. lower-sin.f6461.0

                \[\leadsto \frac{\sin ky}{\frac{\mathsf{hypot}\left(\sin kx, \color{blue}{\sin ky}\right)}{th}} \]
            9. Applied rewrites61.0%

              \[\leadsto \frac{\sin ky}{\color{blue}{\frac{\mathsf{hypot}\left(\sin kx, \sin ky\right)}{th}}} \]

            if 5.8999999999999998e-5 < th

            1. Initial program 91.3%

              \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
            2. Add Preprocessing
            3. Step-by-step derivation
              1. lift-*.f64N/A

                \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
              2. lift-/.f64N/A

                \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin th \]
              3. associate-*l/N/A

                \[\leadsto \color{blue}{\frac{\sin ky \cdot \sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
              4. lower-/.f64N/A

                \[\leadsto \color{blue}{\frac{\sin ky \cdot \sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
              5. *-commutativeN/A

                \[\leadsto \frac{\color{blue}{\sin th \cdot \sin ky}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \]
              6. lower-*.f6491.2

                \[\leadsto \frac{\color{blue}{\sin th \cdot \sin ky}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \]
              7. lift-sqrt.f64N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
              8. lift-+.f64N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\color{blue}{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
              9. +-commutativeN/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\color{blue}{{\sin ky}^{2} + {\sin kx}^{2}}}} \]
              10. lift-pow.f64N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\color{blue}{{\sin ky}^{2}} + {\sin kx}^{2}}} \]
              11. unpow2N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\color{blue}{\sin ky \cdot \sin ky} + {\sin kx}^{2}}} \]
              12. lift-pow.f64N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\sin ky \cdot \sin ky + \color{blue}{{\sin kx}^{2}}}} \]
              13. unpow2N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\sin ky \cdot \sin ky + \color{blue}{\sin kx \cdot \sin kx}}} \]
              14. lower-hypot.f6499.5

                \[\leadsto \frac{\sin th \cdot \sin ky}{\color{blue}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
            4. Applied rewrites99.5%

              \[\leadsto \color{blue}{\frac{\sin th \cdot \sin ky}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
            5. Taylor expanded in ky around 0

              \[\leadsto \frac{\color{blue}{ky \cdot \sin th}}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
            6. Step-by-step derivation
              1. *-commutativeN/A

                \[\leadsto \frac{\color{blue}{\sin th \cdot ky}}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
              2. lower-*.f64N/A

                \[\leadsto \frac{\color{blue}{\sin th \cdot ky}}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
              3. lower-sin.f6460.3

                \[\leadsto \frac{\color{blue}{\sin th} \cdot ky}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
            7. Applied rewrites60.3%

              \[\leadsto \frac{\color{blue}{\sin th \cdot ky}}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
          3. Recombined 2 regimes into one program.
          4. Add Preprocessing

          Alternative 21: 59.4% accurate, 1.5× speedup?

          \[\begin{array}{l} \\ \begin{array}{l} t_1 := \mathsf{hypot}\left(\sin ky, \sin kx\right)\\ \mathbf{if}\;th \leq 5.9 \cdot 10^{-5}:\\ \;\;\;\;\frac{\sin ky \cdot th}{t\_1}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sin th \cdot ky}{t\_1}\\ \end{array} \end{array} \]
          (FPCore (kx ky th)
           :precision binary64
           (let* ((t_1 (hypot (sin ky) (sin kx))))
             (if (<= th 5.9e-5) (/ (* (sin ky) th) t_1) (/ (* (sin th) ky) t_1))))
          double code(double kx, double ky, double th) {
          	double t_1 = hypot(sin(ky), sin(kx));
          	double tmp;
          	if (th <= 5.9e-5) {
          		tmp = (sin(ky) * th) / t_1;
          	} else {
          		tmp = (sin(th) * ky) / t_1;
          	}
          	return tmp;
          }
          
          public static double code(double kx, double ky, double th) {
          	double t_1 = Math.hypot(Math.sin(ky), Math.sin(kx));
          	double tmp;
          	if (th <= 5.9e-5) {
          		tmp = (Math.sin(ky) * th) / t_1;
          	} else {
          		tmp = (Math.sin(th) * ky) / t_1;
          	}
          	return tmp;
          }
          
          def code(kx, ky, th):
          	t_1 = math.hypot(math.sin(ky), math.sin(kx))
          	tmp = 0
          	if th <= 5.9e-5:
          		tmp = (math.sin(ky) * th) / t_1
          	else:
          		tmp = (math.sin(th) * ky) / t_1
          	return tmp
          
          function code(kx, ky, th)
          	t_1 = hypot(sin(ky), sin(kx))
          	tmp = 0.0
          	if (th <= 5.9e-5)
          		tmp = Float64(Float64(sin(ky) * th) / t_1);
          	else
          		tmp = Float64(Float64(sin(th) * ky) / t_1);
          	end
          	return tmp
          end
          
          function tmp_2 = code(kx, ky, th)
          	t_1 = hypot(sin(ky), sin(kx));
          	tmp = 0.0;
          	if (th <= 5.9e-5)
          		tmp = (sin(ky) * th) / t_1;
          	else
          		tmp = (sin(th) * ky) / t_1;
          	end
          	tmp_2 = tmp;
          end
          
          code[kx_, ky_, th_] := Block[{t$95$1 = N[Sqrt[N[Sin[ky], $MachinePrecision] ^ 2 + N[Sin[kx], $MachinePrecision] ^ 2], $MachinePrecision]}, If[LessEqual[th, 5.9e-5], N[(N[(N[Sin[ky], $MachinePrecision] * th), $MachinePrecision] / t$95$1), $MachinePrecision], N[(N[(N[Sin[th], $MachinePrecision] * ky), $MachinePrecision] / t$95$1), $MachinePrecision]]]
          
          \begin{array}{l}
          
          \\
          \begin{array}{l}
          t_1 := \mathsf{hypot}\left(\sin ky, \sin kx\right)\\
          \mathbf{if}\;th \leq 5.9 \cdot 10^{-5}:\\
          \;\;\;\;\frac{\sin ky \cdot th}{t\_1}\\
          
          \mathbf{else}:\\
          \;\;\;\;\frac{\sin th \cdot ky}{t\_1}\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if th < 5.8999999999999998e-5

            1. Initial program 94.6%

              \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
            2. Add Preprocessing
            3. Step-by-step derivation
              1. lift-*.f64N/A

                \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
              2. lift-/.f64N/A

                \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin th \]
              3. associate-*l/N/A

                \[\leadsto \color{blue}{\frac{\sin ky \cdot \sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
              4. lower-/.f64N/A

                \[\leadsto \color{blue}{\frac{\sin ky \cdot \sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
              5. *-commutativeN/A

                \[\leadsto \frac{\color{blue}{\sin th \cdot \sin ky}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \]
              6. lower-*.f6492.9

                \[\leadsto \frac{\color{blue}{\sin th \cdot \sin ky}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \]
              7. lift-sqrt.f64N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
              8. lift-+.f64N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\color{blue}{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
              9. +-commutativeN/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\color{blue}{{\sin ky}^{2} + {\sin kx}^{2}}}} \]
              10. lift-pow.f64N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\color{blue}{{\sin ky}^{2}} + {\sin kx}^{2}}} \]
              11. unpow2N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\color{blue}{\sin ky \cdot \sin ky} + {\sin kx}^{2}}} \]
              12. lift-pow.f64N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\sin ky \cdot \sin ky + \color{blue}{{\sin kx}^{2}}}} \]
              13. unpow2N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\sin ky \cdot \sin ky + \color{blue}{\sin kx \cdot \sin kx}}} \]
              14. lower-hypot.f6496.7

                \[\leadsto \frac{\sin th \cdot \sin ky}{\color{blue}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
            4. Applied rewrites96.7%

              \[\leadsto \color{blue}{\frac{\sin th \cdot \sin ky}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
            5. Taylor expanded in th around 0

              \[\leadsto \frac{\color{blue}{th \cdot \sin ky}}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
            6. Step-by-step derivation
              1. *-commutativeN/A

                \[\leadsto \frac{\color{blue}{\sin ky \cdot th}}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
              2. lower-*.f64N/A

                \[\leadsto \frac{\color{blue}{\sin ky \cdot th}}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
              3. lower-sin.f6458.2

                \[\leadsto \frac{\color{blue}{\sin ky} \cdot th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
            7. Applied rewrites58.2%

              \[\leadsto \frac{\color{blue}{\sin ky \cdot th}}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]

            if 5.8999999999999998e-5 < th

            1. Initial program 91.3%

              \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
            2. Add Preprocessing
            3. Step-by-step derivation
              1. lift-*.f64N/A

                \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
              2. lift-/.f64N/A

                \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin th \]
              3. associate-*l/N/A

                \[\leadsto \color{blue}{\frac{\sin ky \cdot \sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
              4. lower-/.f64N/A

                \[\leadsto \color{blue}{\frac{\sin ky \cdot \sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
              5. *-commutativeN/A

                \[\leadsto \frac{\color{blue}{\sin th \cdot \sin ky}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \]
              6. lower-*.f6491.2

                \[\leadsto \frac{\color{blue}{\sin th \cdot \sin ky}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \]
              7. lift-sqrt.f64N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
              8. lift-+.f64N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\color{blue}{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
              9. +-commutativeN/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\color{blue}{{\sin ky}^{2} + {\sin kx}^{2}}}} \]
              10. lift-pow.f64N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\color{blue}{{\sin ky}^{2}} + {\sin kx}^{2}}} \]
              11. unpow2N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\color{blue}{\sin ky \cdot \sin ky} + {\sin kx}^{2}}} \]
              12. lift-pow.f64N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\sin ky \cdot \sin ky + \color{blue}{{\sin kx}^{2}}}} \]
              13. unpow2N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\sin ky \cdot \sin ky + \color{blue}{\sin kx \cdot \sin kx}}} \]
              14. lower-hypot.f6499.5

                \[\leadsto \frac{\sin th \cdot \sin ky}{\color{blue}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
            4. Applied rewrites99.5%

              \[\leadsto \color{blue}{\frac{\sin th \cdot \sin ky}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
            5. Taylor expanded in ky around 0

              \[\leadsto \frac{\color{blue}{ky \cdot \sin th}}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
            6. Step-by-step derivation
              1. *-commutativeN/A

                \[\leadsto \frac{\color{blue}{\sin th \cdot ky}}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
              2. lower-*.f64N/A

                \[\leadsto \frac{\color{blue}{\sin th \cdot ky}}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
              3. lower-sin.f6460.3

                \[\leadsto \frac{\color{blue}{\sin th} \cdot ky}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
            7. Applied rewrites60.3%

              \[\leadsto \frac{\color{blue}{\sin th \cdot ky}}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
          3. Recombined 2 regimes into one program.
          4. Add Preprocessing

          Alternative 22: 55.9% accurate, 1.5× speedup?

          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;th \leq 9.5:\\ \;\;\;\;\frac{\sin ky \cdot th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sin ky}{\sqrt{\left(0.5 - \cos \left(2 \cdot kx\right) \cdot 0.5\right) + ky \cdot ky}} \cdot \sin th\\ \end{array} \end{array} \]
          (FPCore (kx ky th)
           :precision binary64
           (if (<= th 9.5)
             (/ (* (sin ky) th) (hypot (sin ky) (sin kx)))
             (*
              (/ (sin ky) (sqrt (+ (- 0.5 (* (cos (* 2.0 kx)) 0.5)) (* ky ky))))
              (sin th))))
          double code(double kx, double ky, double th) {
          	double tmp;
          	if (th <= 9.5) {
          		tmp = (sin(ky) * th) / hypot(sin(ky), sin(kx));
          	} else {
          		tmp = (sin(ky) / sqrt(((0.5 - (cos((2.0 * kx)) * 0.5)) + (ky * ky)))) * sin(th);
          	}
          	return tmp;
          }
          
          public static double code(double kx, double ky, double th) {
          	double tmp;
          	if (th <= 9.5) {
          		tmp = (Math.sin(ky) * th) / Math.hypot(Math.sin(ky), Math.sin(kx));
          	} else {
          		tmp = (Math.sin(ky) / Math.sqrt(((0.5 - (Math.cos((2.0 * kx)) * 0.5)) + (ky * ky)))) * Math.sin(th);
          	}
          	return tmp;
          }
          
          def code(kx, ky, th):
          	tmp = 0
          	if th <= 9.5:
          		tmp = (math.sin(ky) * th) / math.hypot(math.sin(ky), math.sin(kx))
          	else:
          		tmp = (math.sin(ky) / math.sqrt(((0.5 - (math.cos((2.0 * kx)) * 0.5)) + (ky * ky)))) * math.sin(th)
          	return tmp
          
          function code(kx, ky, th)
          	tmp = 0.0
          	if (th <= 9.5)
          		tmp = Float64(Float64(sin(ky) * th) / hypot(sin(ky), sin(kx)));
          	else
          		tmp = Float64(Float64(sin(ky) / sqrt(Float64(Float64(0.5 - Float64(cos(Float64(2.0 * kx)) * 0.5)) + Float64(ky * ky)))) * sin(th));
          	end
          	return tmp
          end
          
          function tmp_2 = code(kx, ky, th)
          	tmp = 0.0;
          	if (th <= 9.5)
          		tmp = (sin(ky) * th) / hypot(sin(ky), sin(kx));
          	else
          		tmp = (sin(ky) / sqrt(((0.5 - (cos((2.0 * kx)) * 0.5)) + (ky * ky)))) * sin(th);
          	end
          	tmp_2 = tmp;
          end
          
          code[kx_, ky_, th_] := If[LessEqual[th, 9.5], N[(N[(N[Sin[ky], $MachinePrecision] * th), $MachinePrecision] / N[Sqrt[N[Sin[ky], $MachinePrecision] ^ 2 + N[Sin[kx], $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision], N[(N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[(0.5 - N[(N[Cos[N[(2.0 * kx), $MachinePrecision]], $MachinePrecision] * 0.5), $MachinePrecision]), $MachinePrecision] + N[(ky * ky), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision]]
          
          \begin{array}{l}
          
          \\
          \begin{array}{l}
          \mathbf{if}\;th \leq 9.5:\\
          \;\;\;\;\frac{\sin ky \cdot th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}\\
          
          \mathbf{else}:\\
          \;\;\;\;\frac{\sin ky}{\sqrt{\left(0.5 - \cos \left(2 \cdot kx\right) \cdot 0.5\right) + ky \cdot ky}} \cdot \sin th\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if th < 9.5

            1. Initial program 93.9%

              \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
            2. Add Preprocessing
            3. Step-by-step derivation
              1. lift-*.f64N/A

                \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
              2. lift-/.f64N/A

                \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin th \]
              3. associate-*l/N/A

                \[\leadsto \color{blue}{\frac{\sin ky \cdot \sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
              4. lower-/.f64N/A

                \[\leadsto \color{blue}{\frac{\sin ky \cdot \sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
              5. *-commutativeN/A

                \[\leadsto \frac{\color{blue}{\sin th \cdot \sin ky}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \]
              6. lower-*.f6492.3

                \[\leadsto \frac{\color{blue}{\sin th \cdot \sin ky}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \]
              7. lift-sqrt.f64N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
              8. lift-+.f64N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\color{blue}{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
              9. +-commutativeN/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\color{blue}{{\sin ky}^{2} + {\sin kx}^{2}}}} \]
              10. lift-pow.f64N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\color{blue}{{\sin ky}^{2}} + {\sin kx}^{2}}} \]
              11. unpow2N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\color{blue}{\sin ky \cdot \sin ky} + {\sin kx}^{2}}} \]
              12. lift-pow.f64N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\sin ky \cdot \sin ky + \color{blue}{{\sin kx}^{2}}}} \]
              13. unpow2N/A

                \[\leadsto \frac{\sin th \cdot \sin ky}{\sqrt{\sin ky \cdot \sin ky + \color{blue}{\sin kx \cdot \sin kx}}} \]
              14. lower-hypot.f6496.8

                \[\leadsto \frac{\sin th \cdot \sin ky}{\color{blue}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
            4. Applied rewrites96.8%

              \[\leadsto \color{blue}{\frac{\sin th \cdot \sin ky}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
            5. Taylor expanded in th around 0

              \[\leadsto \frac{\color{blue}{th \cdot \sin ky}}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
            6. Step-by-step derivation
              1. *-commutativeN/A

                \[\leadsto \frac{\color{blue}{\sin ky \cdot th}}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
              2. lower-*.f64N/A

                \[\leadsto \frac{\color{blue}{\sin ky \cdot th}}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
              3. lower-sin.f6457.7

                \[\leadsto \frac{\color{blue}{\sin ky} \cdot th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
            7. Applied rewrites57.7%

              \[\leadsto \frac{\color{blue}{\sin ky \cdot th}}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]

            if 9.5 < th

            1. Initial program 93.2%

              \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
            2. Add Preprocessing
            3. Taylor expanded in ky around 0

              \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{{ky}^{2}}}} \cdot \sin th \]
            4. Step-by-step derivation
              1. unpow2N/A

                \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{ky \cdot ky}}} \cdot \sin th \]
              2. lower-*.f6453.2

                \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{ky \cdot ky}}} \cdot \sin th \]
            5. Applied rewrites53.2%

              \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{ky \cdot ky}}} \cdot \sin th \]
            6. Step-by-step derivation
              1. lift-pow.f64N/A

                \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{{\sin kx}^{2}} + ky \cdot ky}} \cdot \sin th \]
              2. pow2N/A

                \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\sin kx \cdot \sin kx} + ky \cdot ky}} \cdot \sin th \]
              3. lift-sin.f64N/A

                \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\sin kx} \cdot \sin kx + ky \cdot ky}} \cdot \sin th \]
              4. lift-sin.f64N/A

                \[\leadsto \frac{\sin ky}{\sqrt{\sin kx \cdot \color{blue}{\sin kx} + ky \cdot ky}} \cdot \sin th \]
              5. sqr-sin-aN/A

                \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\left(\frac{1}{2} - \frac{1}{2} \cdot \cos \left(2 \cdot kx\right)\right)} + ky \cdot ky}} \cdot \sin th \]
              6. lower--.f64N/A

                \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\left(\frac{1}{2} - \frac{1}{2} \cdot \cos \left(2 \cdot kx\right)\right)} + ky \cdot ky}} \cdot \sin th \]
              7. count-2N/A

                \[\leadsto \frac{\sin ky}{\sqrt{\left(\frac{1}{2} - \frac{1}{2} \cdot \cos \color{blue}{\left(kx + kx\right)}\right) + ky \cdot ky}} \cdot \sin th \]
              8. *-commutativeN/A

                \[\leadsto \frac{\sin ky}{\sqrt{\left(\frac{1}{2} - \color{blue}{\cos \left(kx + kx\right) \cdot \frac{1}{2}}\right) + ky \cdot ky}} \cdot \sin th \]
              9. lower-*.f64N/A

                \[\leadsto \frac{\sin ky}{\sqrt{\left(\frac{1}{2} - \color{blue}{\cos \left(kx + kx\right) \cdot \frac{1}{2}}\right) + ky \cdot ky}} \cdot \sin th \]
              10. lower-cos.f64N/A

                \[\leadsto \frac{\sin ky}{\sqrt{\left(\frac{1}{2} - \color{blue}{\cos \left(kx + kx\right)} \cdot \frac{1}{2}\right) + ky \cdot ky}} \cdot \sin th \]
              11. count-2N/A

                \[\leadsto \frac{\sin ky}{\sqrt{\left(\frac{1}{2} - \cos \color{blue}{\left(2 \cdot kx\right)} \cdot \frac{1}{2}\right) + ky \cdot ky}} \cdot \sin th \]
              12. lower-*.f6448.3

                \[\leadsto \frac{\sin ky}{\sqrt{\left(0.5 - \cos \color{blue}{\left(2 \cdot kx\right)} \cdot 0.5\right) + ky \cdot ky}} \cdot \sin th \]
            7. Applied rewrites48.3%

              \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\left(0.5 - \cos \left(2 \cdot kx\right) \cdot 0.5\right)} + ky \cdot ky}} \cdot \sin th \]
          3. Recombined 2 regimes into one program.
          4. Add Preprocessing

          Alternative 23: 37.0% accurate, 1.8× speedup?

          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;kx \leq 8.5 \cdot 10^{-173}:\\ \;\;\;\;\sin th\\ \mathbf{elif}\;kx \leq 2.4 \cdot 10^{-7}:\\ \;\;\;\;\frac{\sin ky}{\sqrt{kx \cdot kx + ky \cdot ky}} \cdot \sin th\\ \mathbf{else}:\\ \;\;\;\;\frac{\sin ky}{\sqrt{\left(0.5 - \cos \left(2 \cdot kx\right) \cdot 0.5\right) + ky \cdot ky}} \cdot \sin th\\ \end{array} \end{array} \]
          (FPCore (kx ky th)
           :precision binary64
           (if (<= kx 8.5e-173)
             (sin th)
             (if (<= kx 2.4e-7)
               (* (/ (sin ky) (sqrt (+ (* kx kx) (* ky ky)))) (sin th))
               (*
                (/ (sin ky) (sqrt (+ (- 0.5 (* (cos (* 2.0 kx)) 0.5)) (* ky ky))))
                (sin th)))))
          double code(double kx, double ky, double th) {
          	double tmp;
          	if (kx <= 8.5e-173) {
          		tmp = sin(th);
          	} else if (kx <= 2.4e-7) {
          		tmp = (sin(ky) / sqrt(((kx * kx) + (ky * ky)))) * sin(th);
          	} else {
          		tmp = (sin(ky) / sqrt(((0.5 - (cos((2.0 * kx)) * 0.5)) + (ky * ky)))) * sin(th);
          	}
          	return tmp;
          }
          
          real(8) function code(kx, ky, th)
              real(8), intent (in) :: kx
              real(8), intent (in) :: ky
              real(8), intent (in) :: th
              real(8) :: tmp
              if (kx <= 8.5d-173) then
                  tmp = sin(th)
              else if (kx <= 2.4d-7) then
                  tmp = (sin(ky) / sqrt(((kx * kx) + (ky * ky)))) * sin(th)
              else
                  tmp = (sin(ky) / sqrt(((0.5d0 - (cos((2.0d0 * kx)) * 0.5d0)) + (ky * ky)))) * sin(th)
              end if
              code = tmp
          end function
          
          public static double code(double kx, double ky, double th) {
          	double tmp;
          	if (kx <= 8.5e-173) {
          		tmp = Math.sin(th);
          	} else if (kx <= 2.4e-7) {
          		tmp = (Math.sin(ky) / Math.sqrt(((kx * kx) + (ky * ky)))) * Math.sin(th);
          	} else {
          		tmp = (Math.sin(ky) / Math.sqrt(((0.5 - (Math.cos((2.0 * kx)) * 0.5)) + (ky * ky)))) * Math.sin(th);
          	}
          	return tmp;
          }
          
          def code(kx, ky, th):
          	tmp = 0
          	if kx <= 8.5e-173:
          		tmp = math.sin(th)
          	elif kx <= 2.4e-7:
          		tmp = (math.sin(ky) / math.sqrt(((kx * kx) + (ky * ky)))) * math.sin(th)
          	else:
          		tmp = (math.sin(ky) / math.sqrt(((0.5 - (math.cos((2.0 * kx)) * 0.5)) + (ky * ky)))) * math.sin(th)
          	return tmp
          
          function code(kx, ky, th)
          	tmp = 0.0
          	if (kx <= 8.5e-173)
          		tmp = sin(th);
          	elseif (kx <= 2.4e-7)
          		tmp = Float64(Float64(sin(ky) / sqrt(Float64(Float64(kx * kx) + Float64(ky * ky)))) * sin(th));
          	else
          		tmp = Float64(Float64(sin(ky) / sqrt(Float64(Float64(0.5 - Float64(cos(Float64(2.0 * kx)) * 0.5)) + Float64(ky * ky)))) * sin(th));
          	end
          	return tmp
          end
          
          function tmp_2 = code(kx, ky, th)
          	tmp = 0.0;
          	if (kx <= 8.5e-173)
          		tmp = sin(th);
          	elseif (kx <= 2.4e-7)
          		tmp = (sin(ky) / sqrt(((kx * kx) + (ky * ky)))) * sin(th);
          	else
          		tmp = (sin(ky) / sqrt(((0.5 - (cos((2.0 * kx)) * 0.5)) + (ky * ky)))) * sin(th);
          	end
          	tmp_2 = tmp;
          end
          
          code[kx_, ky_, th_] := If[LessEqual[kx, 8.5e-173], N[Sin[th], $MachinePrecision], If[LessEqual[kx, 2.4e-7], N[(N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[(kx * kx), $MachinePrecision] + N[(ky * ky), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision], N[(N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[(0.5 - N[(N[Cos[N[(2.0 * kx), $MachinePrecision]], $MachinePrecision] * 0.5), $MachinePrecision]), $MachinePrecision] + N[(ky * ky), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision]]]
          
          \begin{array}{l}
          
          \\
          \begin{array}{l}
          \mathbf{if}\;kx \leq 8.5 \cdot 10^{-173}:\\
          \;\;\;\;\sin th\\
          
          \mathbf{elif}\;kx \leq 2.4 \cdot 10^{-7}:\\
          \;\;\;\;\frac{\sin ky}{\sqrt{kx \cdot kx + ky \cdot ky}} \cdot \sin th\\
          
          \mathbf{else}:\\
          \;\;\;\;\frac{\sin ky}{\sqrt{\left(0.5 - \cos \left(2 \cdot kx\right) \cdot 0.5\right) + ky \cdot ky}} \cdot \sin th\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 3 regimes
          2. if kx < 8.4999999999999996e-173

            1. Initial program 91.4%

              \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
            2. Add Preprocessing
            3. Taylor expanded in kx around 0

              \[\leadsto \color{blue}{\sin th} \]
            4. Step-by-step derivation
              1. lower-sin.f6423.9

                \[\leadsto \color{blue}{\sin th} \]
            5. Applied rewrites23.9%

              \[\leadsto \color{blue}{\sin th} \]

            if 8.4999999999999996e-173 < kx < 2.39999999999999979e-7

            1. Initial program 92.3%

              \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
            2. Add Preprocessing
            3. Taylor expanded in ky around 0

              \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{{ky}^{2}}}} \cdot \sin th \]
            4. Step-by-step derivation
              1. unpow2N/A

                \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{ky \cdot ky}}} \cdot \sin th \]
              2. lower-*.f6458.4

                \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{ky \cdot ky}}} \cdot \sin th \]
            5. Applied rewrites58.4%

              \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{ky \cdot ky}}} \cdot \sin th \]
            6. Taylor expanded in kx around 0

              \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{{kx}^{2}} + ky \cdot ky}} \cdot \sin th \]
            7. Step-by-step derivation
              1. unpow2N/A

                \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{kx \cdot kx} + ky \cdot ky}} \cdot \sin th \]
              2. lower-*.f6458.4

                \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{kx \cdot kx} + ky \cdot ky}} \cdot \sin th \]
            8. Applied rewrites58.4%

              \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{kx \cdot kx} + ky \cdot ky}} \cdot \sin th \]

            if 2.39999999999999979e-7 < kx

            1. Initial program 99.3%

              \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
            2. Add Preprocessing
            3. Taylor expanded in ky around 0

              \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{{ky}^{2}}}} \cdot \sin th \]
            4. Step-by-step derivation
              1. unpow2N/A

                \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{ky \cdot ky}}} \cdot \sin th \]
              2. lower-*.f6456.6

                \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{ky \cdot ky}}} \cdot \sin th \]
            5. Applied rewrites56.6%

              \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{ky \cdot ky}}} \cdot \sin th \]
            6. Step-by-step derivation
              1. lift-pow.f64N/A

                \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{{\sin kx}^{2}} + ky \cdot ky}} \cdot \sin th \]
              2. pow2N/A

                \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\sin kx \cdot \sin kx} + ky \cdot ky}} \cdot \sin th \]
              3. lift-sin.f64N/A

                \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\sin kx} \cdot \sin kx + ky \cdot ky}} \cdot \sin th \]
              4. lift-sin.f64N/A

                \[\leadsto \frac{\sin ky}{\sqrt{\sin kx \cdot \color{blue}{\sin kx} + ky \cdot ky}} \cdot \sin th \]
              5. sqr-sin-aN/A

                \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\left(\frac{1}{2} - \frac{1}{2} \cdot \cos \left(2 \cdot kx\right)\right)} + ky \cdot ky}} \cdot \sin th \]
              6. lower--.f64N/A

                \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\left(\frac{1}{2} - \frac{1}{2} \cdot \cos \left(2 \cdot kx\right)\right)} + ky \cdot ky}} \cdot \sin th \]
              7. count-2N/A

                \[\leadsto \frac{\sin ky}{\sqrt{\left(\frac{1}{2} - \frac{1}{2} \cdot \cos \color{blue}{\left(kx + kx\right)}\right) + ky \cdot ky}} \cdot \sin th \]
              8. *-commutativeN/A

                \[\leadsto \frac{\sin ky}{\sqrt{\left(\frac{1}{2} - \color{blue}{\cos \left(kx + kx\right) \cdot \frac{1}{2}}\right) + ky \cdot ky}} \cdot \sin th \]
              9. lower-*.f64N/A

                \[\leadsto \frac{\sin ky}{\sqrt{\left(\frac{1}{2} - \color{blue}{\cos \left(kx + kx\right) \cdot \frac{1}{2}}\right) + ky \cdot ky}} \cdot \sin th \]
              10. lower-cos.f64N/A

                \[\leadsto \frac{\sin ky}{\sqrt{\left(\frac{1}{2} - \color{blue}{\cos \left(kx + kx\right)} \cdot \frac{1}{2}\right) + ky \cdot ky}} \cdot \sin th \]
              11. count-2N/A

                \[\leadsto \frac{\sin ky}{\sqrt{\left(\frac{1}{2} - \cos \color{blue}{\left(2 \cdot kx\right)} \cdot \frac{1}{2}\right) + ky \cdot ky}} \cdot \sin th \]
              12. lower-*.f6456.3

                \[\leadsto \frac{\sin ky}{\sqrt{\left(0.5 - \cos \color{blue}{\left(2 \cdot kx\right)} \cdot 0.5\right) + ky \cdot ky}} \cdot \sin th \]
            7. Applied rewrites56.3%

              \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\left(0.5 - \cos \left(2 \cdot kx\right) \cdot 0.5\right)} + ky \cdot ky}} \cdot \sin th \]
          3. Recombined 3 regimes into one program.
          4. Add Preprocessing

          Alternative 24: 23.3% accurate, 6.3× speedup?

          \[\begin{array}{l} \\ \sin th \end{array} \]
          (FPCore (kx ky th) :precision binary64 (sin th))
          double code(double kx, double ky, double th) {
          	return sin(th);
          }
          
          real(8) function code(kx, ky, th)
              real(8), intent (in) :: kx
              real(8), intent (in) :: ky
              real(8), intent (in) :: th
              code = sin(th)
          end function
          
          public static double code(double kx, double ky, double th) {
          	return Math.sin(th);
          }
          
          def code(kx, ky, th):
          	return math.sin(th)
          
          function code(kx, ky, th)
          	return sin(th)
          end
          
          function tmp = code(kx, ky, th)
          	tmp = sin(th);
          end
          
          code[kx_, ky_, th_] := N[Sin[th], $MachinePrecision]
          
          \begin{array}{l}
          
          \\
          \sin th
          \end{array}
          
          Derivation
          1. Initial program 93.7%

            \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
          2. Add Preprocessing
          3. Taylor expanded in kx around 0

            \[\leadsto \color{blue}{\sin th} \]
          4. Step-by-step derivation
            1. lower-sin.f6420.0

              \[\leadsto \color{blue}{\sin th} \]
          5. Applied rewrites20.0%

            \[\leadsto \color{blue}{\sin th} \]
          6. Add Preprocessing

          Alternative 25: 12.6% accurate, 37.2× speedup?

          \[\begin{array}{l} \\ \mathsf{fma}\left(-0.16666666666666666 \cdot \left(th \cdot th\right), th, th\right) \end{array} \]
          (FPCore (kx ky th)
           :precision binary64
           (fma (* -0.16666666666666666 (* th th)) th th))
          double code(double kx, double ky, double th) {
          	return fma((-0.16666666666666666 * (th * th)), th, th);
          }
          
          function code(kx, ky, th)
          	return fma(Float64(-0.16666666666666666 * Float64(th * th)), th, th)
          end
          
          code[kx_, ky_, th_] := N[(N[(-0.16666666666666666 * N[(th * th), $MachinePrecision]), $MachinePrecision] * th + th), $MachinePrecision]
          
          \begin{array}{l}
          
          \\
          \mathsf{fma}\left(-0.16666666666666666 \cdot \left(th \cdot th\right), th, th\right)
          \end{array}
          
          Derivation
          1. Initial program 93.7%

            \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
          2. Add Preprocessing
          3. Taylor expanded in kx around 0

            \[\leadsto \color{blue}{\sin th} \]
          4. Step-by-step derivation
            1. lower-sin.f6420.0

              \[\leadsto \color{blue}{\sin th} \]
          5. Applied rewrites20.0%

            \[\leadsto \color{blue}{\sin th} \]
          6. Taylor expanded in th around 0

            \[\leadsto th \cdot \color{blue}{\left(1 + \frac{-1}{6} \cdot {th}^{2}\right)} \]
          7. Step-by-step derivation
            1. Applied rewrites11.0%

              \[\leadsto \mathsf{fma}\left({th}^{3}, \color{blue}{-0.16666666666666666}, th\right) \]
            2. Step-by-step derivation
              1. Applied rewrites11.0%

                \[\leadsto \mathsf{fma}\left(-0.16666666666666666 \cdot \left(th \cdot th\right), th, th\right) \]
              2. Add Preprocessing

              Reproduce

              ?
              herbie shell --seed 2024322 
              (FPCore (kx ky th)
                :name "Toniolo and Linder, Equation (3b), real"
                :precision binary64
                (* (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0)))) (sin th)))