symmetry log of sum of exp

Percentage Accurate: 53.1% → 98.6%
Time: 12.0s
Alternatives: 14
Speedup: 1.4×

Specification

?
\[\begin{array}{l} \\ \log \left(e^{a} + e^{b}\right) \end{array} \]
(FPCore (a b) :precision binary64 (log (+ (exp a) (exp b))))
double code(double a, double b) {
	return log((exp(a) + exp(b)));
}
real(8) function code(a, b)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    code = log((exp(a) + exp(b)))
end function
public static double code(double a, double b) {
	return Math.log((Math.exp(a) + Math.exp(b)));
}
def code(a, b):
	return math.log((math.exp(a) + math.exp(b)))
function code(a, b)
	return log(Float64(exp(a) + exp(b)))
end
function tmp = code(a, b)
	tmp = log((exp(a) + exp(b)));
end
code[a_, b_] := N[Log[N[(N[Exp[a], $MachinePrecision] + N[Exp[b], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\log \left(e^{a} + e^{b}\right)
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 14 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 53.1% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \log \left(e^{a} + e^{b}\right) \end{array} \]
(FPCore (a b) :precision binary64 (log (+ (exp a) (exp b))))
double code(double a, double b) {
	return log((exp(a) + exp(b)));
}
real(8) function code(a, b)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    code = log((exp(a) + exp(b)))
end function
public static double code(double a, double b) {
	return Math.log((Math.exp(a) + Math.exp(b)));
}
def code(a, b):
	return math.log((math.exp(a) + math.exp(b)))
function code(a, b)
	return log(Float64(exp(a) + exp(b)))
end
function tmp = code(a, b)
	tmp = log((exp(a) + exp(b)));
end
code[a_, b_] := N[Log[N[(N[Exp[a], $MachinePrecision] + N[Exp[b], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\log \left(e^{a} + e^{b}\right)
\end{array}

Alternative 1: 98.6% accurate, 0.7× speedup?

\[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \begin{array}{l} \mathbf{if}\;e^{a} \leq 0:\\ \;\;\;\;\frac{b}{1 + e^{a}}\\ \mathbf{else}:\\ \;\;\;\;\log \left(e^{a} + e^{b}\right)\\ \end{array} \end{array} \]
NOTE: a and b should be sorted in increasing order before calling this function.
(FPCore (a b)
 :precision binary64
 (if (<= (exp a) 0.0) (/ b (+ 1.0 (exp a))) (log (+ (exp a) (exp b)))))
assert(a < b);
double code(double a, double b) {
	double tmp;
	if (exp(a) <= 0.0) {
		tmp = b / (1.0 + exp(a));
	} else {
		tmp = log((exp(a) + exp(b)));
	}
	return tmp;
}
NOTE: a and b should be sorted in increasing order before calling this function.
real(8) function code(a, b)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8) :: tmp
    if (exp(a) <= 0.0d0) then
        tmp = b / (1.0d0 + exp(a))
    else
        tmp = log((exp(a) + exp(b)))
    end if
    code = tmp
end function
assert a < b;
public static double code(double a, double b) {
	double tmp;
	if (Math.exp(a) <= 0.0) {
		tmp = b / (1.0 + Math.exp(a));
	} else {
		tmp = Math.log((Math.exp(a) + Math.exp(b)));
	}
	return tmp;
}
[a, b] = sort([a, b])
def code(a, b):
	tmp = 0
	if math.exp(a) <= 0.0:
		tmp = b / (1.0 + math.exp(a))
	else:
		tmp = math.log((math.exp(a) + math.exp(b)))
	return tmp
a, b = sort([a, b])
function code(a, b)
	tmp = 0.0
	if (exp(a) <= 0.0)
		tmp = Float64(b / Float64(1.0 + exp(a)));
	else
		tmp = log(Float64(exp(a) + exp(b)));
	end
	return tmp
end
a, b = num2cell(sort([a, b])){:}
function tmp_2 = code(a, b)
	tmp = 0.0;
	if (exp(a) <= 0.0)
		tmp = b / (1.0 + exp(a));
	else
		tmp = log((exp(a) + exp(b)));
	end
	tmp_2 = tmp;
end
NOTE: a and b should be sorted in increasing order before calling this function.
code[a_, b_] := If[LessEqual[N[Exp[a], $MachinePrecision], 0.0], N[(b / N[(1.0 + N[Exp[a], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[Log[N[(N[Exp[a], $MachinePrecision] + N[Exp[b], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]]
\begin{array}{l}
[a, b] = \mathsf{sort}([a, b])\\
\\
\begin{array}{l}
\mathbf{if}\;e^{a} \leq 0:\\
\;\;\;\;\frac{b}{1 + e^{a}}\\

\mathbf{else}:\\
\;\;\;\;\log \left(e^{a} + e^{b}\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (exp.f64 a) < 0.0

    1. Initial program 11.7%

      \[\log \left(e^{a} + e^{b}\right) \]
    2. Add Preprocessing
    3. Taylor expanded in b around 0

      \[\leadsto \color{blue}{\log \left(1 + e^{a}\right) + \frac{b}{1 + e^{a}}} \]
    4. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto \color{blue}{\frac{b}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
      2. *-rgt-identityN/A

        \[\leadsto \frac{\color{blue}{b \cdot 1}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
      3. associate-*r/N/A

        \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
      4. lower-+.f64N/A

        \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
      5. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{b \cdot 1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
      6. *-rgt-identityN/A

        \[\leadsto \frac{\color{blue}{b}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
      7. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{b}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
      8. +-commutativeN/A

        \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
      9. lower-+.f64N/A

        \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
      10. lower-exp.f64N/A

        \[\leadsto \frac{b}{\color{blue}{e^{a}} + 1} + \log \left(1 + e^{a}\right) \]
      11. lower-log1p.f64N/A

        \[\leadsto \frac{b}{e^{a} + 1} + \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
      12. lower-exp.f64100.0

        \[\leadsto \frac{b}{e^{a} + 1} + \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]
    5. Applied rewrites100.0%

      \[\leadsto \color{blue}{\frac{b}{e^{a} + 1} + \mathsf{log1p}\left(e^{a}\right)} \]
    6. Step-by-step derivation
      1. Applied rewrites54.3%

        \[\leadsto \left({\left(\frac{b}{1 + e^{a}}\right)}^{2} - {\left(\mathsf{log1p}\left(e^{a}\right)\right)}^{2}\right) \cdot \color{blue}{{\left(\frac{b}{1 + e^{a}} - \mathsf{log1p}\left(e^{a}\right)\right)}^{-1}} \]
      2. Step-by-step derivation
        1. Applied rewrites54.3%

          \[\leadsto \left({\left(\frac{b}{1 + e^{a}}\right)}^{2} - {\left(e^{2}\right)}^{\log \left(\mathsf{log1p}\left(e^{a}\right)\right)}\right) \cdot {\left(\frac{b}{1 + e^{a}} - \color{blue}{\mathsf{log1p}\left(e^{a}\right)}\right)}^{-1} \]
        2. Taylor expanded in b around inf

          \[\leadsto \frac{b}{\color{blue}{1 + e^{a}}} \]
        3. Step-by-step derivation
          1. Applied rewrites100.0%

            \[\leadsto \frac{b}{\color{blue}{1 + e^{a}}} \]

          if 0.0 < (exp.f64 a)

          1. Initial program 71.6%

            \[\log \left(e^{a} + e^{b}\right) \]
          2. Add Preprocessing
        4. Recombined 2 regimes into one program.
        5. Add Preprocessing

        Alternative 2: 98.2% accurate, 0.9× speedup?

        \[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \begin{array}{l} \mathbf{if}\;e^{a} \leq 0:\\ \;\;\;\;\frac{b}{1 + e^{a}}\\ \mathbf{else}:\\ \;\;\;\;\log \left(e^{a} + \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, b, 0.5\right), b, 1\right), b, 1\right)\right)\\ \end{array} \end{array} \]
        NOTE: a and b should be sorted in increasing order before calling this function.
        (FPCore (a b)
         :precision binary64
         (if (<= (exp a) 0.0)
           (/ b (+ 1.0 (exp a)))
           (log (+ (exp a) (fma (fma (fma 0.16666666666666666 b 0.5) b 1.0) b 1.0)))))
        assert(a < b);
        double code(double a, double b) {
        	double tmp;
        	if (exp(a) <= 0.0) {
        		tmp = b / (1.0 + exp(a));
        	} else {
        		tmp = log((exp(a) + fma(fma(fma(0.16666666666666666, b, 0.5), b, 1.0), b, 1.0)));
        	}
        	return tmp;
        }
        
        a, b = sort([a, b])
        function code(a, b)
        	tmp = 0.0
        	if (exp(a) <= 0.0)
        		tmp = Float64(b / Float64(1.0 + exp(a)));
        	else
        		tmp = log(Float64(exp(a) + fma(fma(fma(0.16666666666666666, b, 0.5), b, 1.0), b, 1.0)));
        	end
        	return tmp
        end
        
        NOTE: a and b should be sorted in increasing order before calling this function.
        code[a_, b_] := If[LessEqual[N[Exp[a], $MachinePrecision], 0.0], N[(b / N[(1.0 + N[Exp[a], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[Log[N[(N[Exp[a], $MachinePrecision] + N[(N[(N[(0.16666666666666666 * b + 0.5), $MachinePrecision] * b + 1.0), $MachinePrecision] * b + 1.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]]
        
        \begin{array}{l}
        [a, b] = \mathsf{sort}([a, b])\\
        \\
        \begin{array}{l}
        \mathbf{if}\;e^{a} \leq 0:\\
        \;\;\;\;\frac{b}{1 + e^{a}}\\
        
        \mathbf{else}:\\
        \;\;\;\;\log \left(e^{a} + \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, b, 0.5\right), b, 1\right), b, 1\right)\right)\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 2 regimes
        2. if (exp.f64 a) < 0.0

          1. Initial program 11.7%

            \[\log \left(e^{a} + e^{b}\right) \]
          2. Add Preprocessing
          3. Taylor expanded in b around 0

            \[\leadsto \color{blue}{\log \left(1 + e^{a}\right) + \frac{b}{1 + e^{a}}} \]
          4. Step-by-step derivation
            1. +-commutativeN/A

              \[\leadsto \color{blue}{\frac{b}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
            2. *-rgt-identityN/A

              \[\leadsto \frac{\color{blue}{b \cdot 1}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
            3. associate-*r/N/A

              \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
            4. lower-+.f64N/A

              \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
            5. associate-*r/N/A

              \[\leadsto \color{blue}{\frac{b \cdot 1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
            6. *-rgt-identityN/A

              \[\leadsto \frac{\color{blue}{b}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
            7. lower-/.f64N/A

              \[\leadsto \color{blue}{\frac{b}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
            8. +-commutativeN/A

              \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
            9. lower-+.f64N/A

              \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
            10. lower-exp.f64N/A

              \[\leadsto \frac{b}{\color{blue}{e^{a}} + 1} + \log \left(1 + e^{a}\right) \]
            11. lower-log1p.f64N/A

              \[\leadsto \frac{b}{e^{a} + 1} + \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
            12. lower-exp.f64100.0

              \[\leadsto \frac{b}{e^{a} + 1} + \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]
          5. Applied rewrites100.0%

            \[\leadsto \color{blue}{\frac{b}{e^{a} + 1} + \mathsf{log1p}\left(e^{a}\right)} \]
          6. Step-by-step derivation
            1. Applied rewrites54.3%

              \[\leadsto \left({\left(\frac{b}{1 + e^{a}}\right)}^{2} - {\left(\mathsf{log1p}\left(e^{a}\right)\right)}^{2}\right) \cdot \color{blue}{{\left(\frac{b}{1 + e^{a}} - \mathsf{log1p}\left(e^{a}\right)\right)}^{-1}} \]
            2. Step-by-step derivation
              1. Applied rewrites54.3%

                \[\leadsto \left({\left(\frac{b}{1 + e^{a}}\right)}^{2} - {\left(e^{2}\right)}^{\log \left(\mathsf{log1p}\left(e^{a}\right)\right)}\right) \cdot {\left(\frac{b}{1 + e^{a}} - \color{blue}{\mathsf{log1p}\left(e^{a}\right)}\right)}^{-1} \]
              2. Taylor expanded in b around inf

                \[\leadsto \frac{b}{\color{blue}{1 + e^{a}}} \]
              3. Step-by-step derivation
                1. Applied rewrites100.0%

                  \[\leadsto \frac{b}{\color{blue}{1 + e^{a}}} \]

                if 0.0 < (exp.f64 a)

                1. Initial program 71.6%

                  \[\log \left(e^{a} + e^{b}\right) \]
                2. Add Preprocessing
                3. Taylor expanded in b around 0

                  \[\leadsto \log \left(e^{a} + \color{blue}{\left(1 + b \cdot \left(1 + b \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot b\right)\right)\right)}\right) \]
                4. Step-by-step derivation
                  1. +-commutativeN/A

                    \[\leadsto \log \left(e^{a} + \color{blue}{\left(b \cdot \left(1 + b \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot b\right)\right) + 1\right)}\right) \]
                  2. *-commutativeN/A

                    \[\leadsto \log \left(e^{a} + \left(\color{blue}{\left(1 + b \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot b\right)\right) \cdot b} + 1\right)\right) \]
                  3. lower-fma.f64N/A

                    \[\leadsto \log \left(e^{a} + \color{blue}{\mathsf{fma}\left(1 + b \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot b\right), b, 1\right)}\right) \]
                  4. +-commutativeN/A

                    \[\leadsto \log \left(e^{a} + \mathsf{fma}\left(\color{blue}{b \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot b\right) + 1}, b, 1\right)\right) \]
                  5. *-commutativeN/A

                    \[\leadsto \log \left(e^{a} + \mathsf{fma}\left(\color{blue}{\left(\frac{1}{2} + \frac{1}{6} \cdot b\right) \cdot b} + 1, b, 1\right)\right) \]
                  6. lower-fma.f64N/A

                    \[\leadsto \log \left(e^{a} + \mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(\frac{1}{2} + \frac{1}{6} \cdot b, b, 1\right)}, b, 1\right)\right) \]
                  7. +-commutativeN/A

                    \[\leadsto \log \left(e^{a} + \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\frac{1}{6} \cdot b + \frac{1}{2}}, b, 1\right), b, 1\right)\right) \]
                  8. lower-fma.f6468.2

                    \[\leadsto \log \left(e^{a} + \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(0.16666666666666666, b, 0.5\right)}, b, 1\right), b, 1\right)\right) \]
                5. Applied rewrites68.2%

                  \[\leadsto \log \left(e^{a} + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, b, 0.5\right), b, 1\right), b, 1\right)}\right) \]
              4. Recombined 2 regimes into one program.
              5. Add Preprocessing

              Alternative 3: 98.2% accurate, 1.0× speedup?

              \[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \frac{b}{e^{a} + 1} + \mathsf{log1p}\left(e^{a}\right) \end{array} \]
              NOTE: a and b should be sorted in increasing order before calling this function.
              (FPCore (a b) :precision binary64 (+ (/ b (+ (exp a) 1.0)) (log1p (exp a))))
              assert(a < b);
              double code(double a, double b) {
              	return (b / (exp(a) + 1.0)) + log1p(exp(a));
              }
              
              assert a < b;
              public static double code(double a, double b) {
              	return (b / (Math.exp(a) + 1.0)) + Math.log1p(Math.exp(a));
              }
              
              [a, b] = sort([a, b])
              def code(a, b):
              	return (b / (math.exp(a) + 1.0)) + math.log1p(math.exp(a))
              
              a, b = sort([a, b])
              function code(a, b)
              	return Float64(Float64(b / Float64(exp(a) + 1.0)) + log1p(exp(a)))
              end
              
              NOTE: a and b should be sorted in increasing order before calling this function.
              code[a_, b_] := N[(N[(b / N[(N[Exp[a], $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision] + N[Log[1 + N[Exp[a], $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
              
              \begin{array}{l}
              [a, b] = \mathsf{sort}([a, b])\\
              \\
              \frac{b}{e^{a} + 1} + \mathsf{log1p}\left(e^{a}\right)
              \end{array}
              
              Derivation
              1. Initial program 59.9%

                \[\log \left(e^{a} + e^{b}\right) \]
              2. Add Preprocessing
              3. Taylor expanded in b around 0

                \[\leadsto \color{blue}{\log \left(1 + e^{a}\right) + \frac{b}{1 + e^{a}}} \]
              4. Step-by-step derivation
                1. +-commutativeN/A

                  \[\leadsto \color{blue}{\frac{b}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
                2. *-rgt-identityN/A

                  \[\leadsto \frac{\color{blue}{b \cdot 1}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
                3. associate-*r/N/A

                  \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                4. lower-+.f64N/A

                  \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
                5. associate-*r/N/A

                  \[\leadsto \color{blue}{\frac{b \cdot 1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                6. *-rgt-identityN/A

                  \[\leadsto \frac{\color{blue}{b}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
                7. lower-/.f64N/A

                  \[\leadsto \color{blue}{\frac{b}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                8. +-commutativeN/A

                  \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
                9. lower-+.f64N/A

                  \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
                10. lower-exp.f64N/A

                  \[\leadsto \frac{b}{\color{blue}{e^{a}} + 1} + \log \left(1 + e^{a}\right) \]
                11. lower-log1p.f64N/A

                  \[\leadsto \frac{b}{e^{a} + 1} + \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
                12. lower-exp.f6475.2

                  \[\leadsto \frac{b}{e^{a} + 1} + \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]
              5. Applied rewrites75.2%

                \[\leadsto \color{blue}{\frac{b}{e^{a} + 1} + \mathsf{log1p}\left(e^{a}\right)} \]
              6. Add Preprocessing

              Alternative 4: 98.2% accurate, 1.0× speedup?

              \[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \begin{array}{l} \mathbf{if}\;e^{a} \leq 0:\\ \;\;\;\;\frac{b}{1 + e^{a}}\\ \mathbf{else}:\\ \;\;\;\;0.5 \cdot b + \mathsf{log1p}\left(e^{a}\right)\\ \end{array} \end{array} \]
              NOTE: a and b should be sorted in increasing order before calling this function.
              (FPCore (a b)
               :precision binary64
               (if (<= (exp a) 0.0) (/ b (+ 1.0 (exp a))) (+ (* 0.5 b) (log1p (exp a)))))
              assert(a < b);
              double code(double a, double b) {
              	double tmp;
              	if (exp(a) <= 0.0) {
              		tmp = b / (1.0 + exp(a));
              	} else {
              		tmp = (0.5 * b) + log1p(exp(a));
              	}
              	return tmp;
              }
              
              assert a < b;
              public static double code(double a, double b) {
              	double tmp;
              	if (Math.exp(a) <= 0.0) {
              		tmp = b / (1.0 + Math.exp(a));
              	} else {
              		tmp = (0.5 * b) + Math.log1p(Math.exp(a));
              	}
              	return tmp;
              }
              
              [a, b] = sort([a, b])
              def code(a, b):
              	tmp = 0
              	if math.exp(a) <= 0.0:
              		tmp = b / (1.0 + math.exp(a))
              	else:
              		tmp = (0.5 * b) + math.log1p(math.exp(a))
              	return tmp
              
              a, b = sort([a, b])
              function code(a, b)
              	tmp = 0.0
              	if (exp(a) <= 0.0)
              		tmp = Float64(b / Float64(1.0 + exp(a)));
              	else
              		tmp = Float64(Float64(0.5 * b) + log1p(exp(a)));
              	end
              	return tmp
              end
              
              NOTE: a and b should be sorted in increasing order before calling this function.
              code[a_, b_] := If[LessEqual[N[Exp[a], $MachinePrecision], 0.0], N[(b / N[(1.0 + N[Exp[a], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(0.5 * b), $MachinePrecision] + N[Log[1 + N[Exp[a], $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]
              
              \begin{array}{l}
              [a, b] = \mathsf{sort}([a, b])\\
              \\
              \begin{array}{l}
              \mathbf{if}\;e^{a} \leq 0:\\
              \;\;\;\;\frac{b}{1 + e^{a}}\\
              
              \mathbf{else}:\\
              \;\;\;\;0.5 \cdot b + \mathsf{log1p}\left(e^{a}\right)\\
              
              
              \end{array}
              \end{array}
              
              Derivation
              1. Split input into 2 regimes
              2. if (exp.f64 a) < 0.0

                1. Initial program 11.7%

                  \[\log \left(e^{a} + e^{b}\right) \]
                2. Add Preprocessing
                3. Taylor expanded in b around 0

                  \[\leadsto \color{blue}{\log \left(1 + e^{a}\right) + \frac{b}{1 + e^{a}}} \]
                4. Step-by-step derivation
                  1. +-commutativeN/A

                    \[\leadsto \color{blue}{\frac{b}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
                  2. *-rgt-identityN/A

                    \[\leadsto \frac{\color{blue}{b \cdot 1}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
                  3. associate-*r/N/A

                    \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                  4. lower-+.f64N/A

                    \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
                  5. associate-*r/N/A

                    \[\leadsto \color{blue}{\frac{b \cdot 1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                  6. *-rgt-identityN/A

                    \[\leadsto \frac{\color{blue}{b}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
                  7. lower-/.f64N/A

                    \[\leadsto \color{blue}{\frac{b}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                  8. +-commutativeN/A

                    \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
                  9. lower-+.f64N/A

                    \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
                  10. lower-exp.f64N/A

                    \[\leadsto \frac{b}{\color{blue}{e^{a}} + 1} + \log \left(1 + e^{a}\right) \]
                  11. lower-log1p.f64N/A

                    \[\leadsto \frac{b}{e^{a} + 1} + \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
                  12. lower-exp.f64100.0

                    \[\leadsto \frac{b}{e^{a} + 1} + \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]
                5. Applied rewrites100.0%

                  \[\leadsto \color{blue}{\frac{b}{e^{a} + 1} + \mathsf{log1p}\left(e^{a}\right)} \]
                6. Step-by-step derivation
                  1. Applied rewrites54.3%

                    \[\leadsto \left({\left(\frac{b}{1 + e^{a}}\right)}^{2} - {\left(\mathsf{log1p}\left(e^{a}\right)\right)}^{2}\right) \cdot \color{blue}{{\left(\frac{b}{1 + e^{a}} - \mathsf{log1p}\left(e^{a}\right)\right)}^{-1}} \]
                  2. Step-by-step derivation
                    1. Applied rewrites54.3%

                      \[\leadsto \left({\left(\frac{b}{1 + e^{a}}\right)}^{2} - {\left(e^{2}\right)}^{\log \left(\mathsf{log1p}\left(e^{a}\right)\right)}\right) \cdot {\left(\frac{b}{1 + e^{a}} - \color{blue}{\mathsf{log1p}\left(e^{a}\right)}\right)}^{-1} \]
                    2. Taylor expanded in b around inf

                      \[\leadsto \frac{b}{\color{blue}{1 + e^{a}}} \]
                    3. Step-by-step derivation
                      1. Applied rewrites100.0%

                        \[\leadsto \frac{b}{\color{blue}{1 + e^{a}}} \]

                      if 0.0 < (exp.f64 a)

                      1. Initial program 71.6%

                        \[\log \left(e^{a} + e^{b}\right) \]
                      2. Add Preprocessing
                      3. Taylor expanded in b around 0

                        \[\leadsto \color{blue}{\log \left(1 + e^{a}\right) + \frac{b}{1 + e^{a}}} \]
                      4. Step-by-step derivation
                        1. +-commutativeN/A

                          \[\leadsto \color{blue}{\frac{b}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
                        2. *-rgt-identityN/A

                          \[\leadsto \frac{\color{blue}{b \cdot 1}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
                        3. associate-*r/N/A

                          \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                        4. lower-+.f64N/A

                          \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
                        5. associate-*r/N/A

                          \[\leadsto \color{blue}{\frac{b \cdot 1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                        6. *-rgt-identityN/A

                          \[\leadsto \frac{\color{blue}{b}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
                        7. lower-/.f64N/A

                          \[\leadsto \color{blue}{\frac{b}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                        8. +-commutativeN/A

                          \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
                        9. lower-+.f64N/A

                          \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
                        10. lower-exp.f64N/A

                          \[\leadsto \frac{b}{\color{blue}{e^{a}} + 1} + \log \left(1 + e^{a}\right) \]
                        11. lower-log1p.f64N/A

                          \[\leadsto \frac{b}{e^{a} + 1} + \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
                        12. lower-exp.f6469.2

                          \[\leadsto \frac{b}{e^{a} + 1} + \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]
                      5. Applied rewrites69.2%

                        \[\leadsto \color{blue}{\frac{b}{e^{a} + 1} + \mathsf{log1p}\left(e^{a}\right)} \]
                      6. Taylor expanded in a around 0

                        \[\leadsto \frac{1}{2} \cdot b + \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]
                      7. Step-by-step derivation
                        1. Applied rewrites69.1%

                          \[\leadsto 0.5 \cdot b + \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]
                      8. Recombined 2 regimes into one program.
                      9. Add Preprocessing

                      Alternative 5: 97.5% accurate, 1.0× speedup?

                      \[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \begin{array}{l} \mathbf{if}\;e^{a} \leq 0:\\ \;\;\;\;\frac{b}{1 + e^{a}}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{log1p}\left(e^{a}\right)\\ \end{array} \end{array} \]
                      NOTE: a and b should be sorted in increasing order before calling this function.
                      (FPCore (a b)
                       :precision binary64
                       (if (<= (exp a) 0.0) (/ b (+ 1.0 (exp a))) (log1p (exp a))))
                      assert(a < b);
                      double code(double a, double b) {
                      	double tmp;
                      	if (exp(a) <= 0.0) {
                      		tmp = b / (1.0 + exp(a));
                      	} else {
                      		tmp = log1p(exp(a));
                      	}
                      	return tmp;
                      }
                      
                      assert a < b;
                      public static double code(double a, double b) {
                      	double tmp;
                      	if (Math.exp(a) <= 0.0) {
                      		tmp = b / (1.0 + Math.exp(a));
                      	} else {
                      		tmp = Math.log1p(Math.exp(a));
                      	}
                      	return tmp;
                      }
                      
                      [a, b] = sort([a, b])
                      def code(a, b):
                      	tmp = 0
                      	if math.exp(a) <= 0.0:
                      		tmp = b / (1.0 + math.exp(a))
                      	else:
                      		tmp = math.log1p(math.exp(a))
                      	return tmp
                      
                      a, b = sort([a, b])
                      function code(a, b)
                      	tmp = 0.0
                      	if (exp(a) <= 0.0)
                      		tmp = Float64(b / Float64(1.0 + exp(a)));
                      	else
                      		tmp = log1p(exp(a));
                      	end
                      	return tmp
                      end
                      
                      NOTE: a and b should be sorted in increasing order before calling this function.
                      code[a_, b_] := If[LessEqual[N[Exp[a], $MachinePrecision], 0.0], N[(b / N[(1.0 + N[Exp[a], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[Log[1 + N[Exp[a], $MachinePrecision]], $MachinePrecision]]
                      
                      \begin{array}{l}
                      [a, b] = \mathsf{sort}([a, b])\\
                      \\
                      \begin{array}{l}
                      \mathbf{if}\;e^{a} \leq 0:\\
                      \;\;\;\;\frac{b}{1 + e^{a}}\\
                      
                      \mathbf{else}:\\
                      \;\;\;\;\mathsf{log1p}\left(e^{a}\right)\\
                      
                      
                      \end{array}
                      \end{array}
                      
                      Derivation
                      1. Split input into 2 regimes
                      2. if (exp.f64 a) < 0.0

                        1. Initial program 11.7%

                          \[\log \left(e^{a} + e^{b}\right) \]
                        2. Add Preprocessing
                        3. Taylor expanded in b around 0

                          \[\leadsto \color{blue}{\log \left(1 + e^{a}\right) + \frac{b}{1 + e^{a}}} \]
                        4. Step-by-step derivation
                          1. +-commutativeN/A

                            \[\leadsto \color{blue}{\frac{b}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
                          2. *-rgt-identityN/A

                            \[\leadsto \frac{\color{blue}{b \cdot 1}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
                          3. associate-*r/N/A

                            \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                          4. lower-+.f64N/A

                            \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
                          5. associate-*r/N/A

                            \[\leadsto \color{blue}{\frac{b \cdot 1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                          6. *-rgt-identityN/A

                            \[\leadsto \frac{\color{blue}{b}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
                          7. lower-/.f64N/A

                            \[\leadsto \color{blue}{\frac{b}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                          8. +-commutativeN/A

                            \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
                          9. lower-+.f64N/A

                            \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
                          10. lower-exp.f64N/A

                            \[\leadsto \frac{b}{\color{blue}{e^{a}} + 1} + \log \left(1 + e^{a}\right) \]
                          11. lower-log1p.f64N/A

                            \[\leadsto \frac{b}{e^{a} + 1} + \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
                          12. lower-exp.f64100.0

                            \[\leadsto \frac{b}{e^{a} + 1} + \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]
                        5. Applied rewrites100.0%

                          \[\leadsto \color{blue}{\frac{b}{e^{a} + 1} + \mathsf{log1p}\left(e^{a}\right)} \]
                        6. Step-by-step derivation
                          1. Applied rewrites54.3%

                            \[\leadsto \left({\left(\frac{b}{1 + e^{a}}\right)}^{2} - {\left(\mathsf{log1p}\left(e^{a}\right)\right)}^{2}\right) \cdot \color{blue}{{\left(\frac{b}{1 + e^{a}} - \mathsf{log1p}\left(e^{a}\right)\right)}^{-1}} \]
                          2. Step-by-step derivation
                            1. Applied rewrites54.3%

                              \[\leadsto \left({\left(\frac{b}{1 + e^{a}}\right)}^{2} - {\left(e^{2}\right)}^{\log \left(\mathsf{log1p}\left(e^{a}\right)\right)}\right) \cdot {\left(\frac{b}{1 + e^{a}} - \color{blue}{\mathsf{log1p}\left(e^{a}\right)}\right)}^{-1} \]
                            2. Taylor expanded in b around inf

                              \[\leadsto \frac{b}{\color{blue}{1 + e^{a}}} \]
                            3. Step-by-step derivation
                              1. Applied rewrites100.0%

                                \[\leadsto \frac{b}{\color{blue}{1 + e^{a}}} \]

                              if 0.0 < (exp.f64 a)

                              1. Initial program 71.6%

                                \[\log \left(e^{a} + e^{b}\right) \]
                              2. Add Preprocessing
                              3. Taylor expanded in b around 0

                                \[\leadsto \color{blue}{\log \left(1 + e^{a}\right)} \]
                              4. Step-by-step derivation
                                1. lower-log1p.f64N/A

                                  \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
                                2. lower-exp.f6468.5

                                  \[\leadsto \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]
                              5. Applied rewrites68.5%

                                \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
                            4. Recombined 2 regimes into one program.
                            5. Add Preprocessing

                            Alternative 6: 97.6% accurate, 1.3× speedup?

                            \[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \begin{array}{l} \mathbf{if}\;e^{a} \leq 0:\\ \;\;\;\;\frac{b}{1 + e^{a}}\\ \mathbf{else}:\\ \;\;\;\;\log \left(\mathsf{fma}\left(\mathsf{fma}\left(0.5, b, 1\right), b, \mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), a, 2\right)\right)\right)\\ \end{array} \end{array} \]
                            NOTE: a and b should be sorted in increasing order before calling this function.
                            (FPCore (a b)
                             :precision binary64
                             (if (<= (exp a) 0.0)
                               (/ b (+ 1.0 (exp a)))
                               (log (fma (fma 0.5 b 1.0) b (fma (fma 0.5 a 1.0) a 2.0)))))
                            assert(a < b);
                            double code(double a, double b) {
                            	double tmp;
                            	if (exp(a) <= 0.0) {
                            		tmp = b / (1.0 + exp(a));
                            	} else {
                            		tmp = log(fma(fma(0.5, b, 1.0), b, fma(fma(0.5, a, 1.0), a, 2.0)));
                            	}
                            	return tmp;
                            }
                            
                            a, b = sort([a, b])
                            function code(a, b)
                            	tmp = 0.0
                            	if (exp(a) <= 0.0)
                            		tmp = Float64(b / Float64(1.0 + exp(a)));
                            	else
                            		tmp = log(fma(fma(0.5, b, 1.0), b, fma(fma(0.5, a, 1.0), a, 2.0)));
                            	end
                            	return tmp
                            end
                            
                            NOTE: a and b should be sorted in increasing order before calling this function.
                            code[a_, b_] := If[LessEqual[N[Exp[a], $MachinePrecision], 0.0], N[(b / N[(1.0 + N[Exp[a], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[Log[N[(N[(0.5 * b + 1.0), $MachinePrecision] * b + N[(N[(0.5 * a + 1.0), $MachinePrecision] * a + 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]]
                            
                            \begin{array}{l}
                            [a, b] = \mathsf{sort}([a, b])\\
                            \\
                            \begin{array}{l}
                            \mathbf{if}\;e^{a} \leq 0:\\
                            \;\;\;\;\frac{b}{1 + e^{a}}\\
                            
                            \mathbf{else}:\\
                            \;\;\;\;\log \left(\mathsf{fma}\left(\mathsf{fma}\left(0.5, b, 1\right), b, \mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), a, 2\right)\right)\right)\\
                            
                            
                            \end{array}
                            \end{array}
                            
                            Derivation
                            1. Split input into 2 regimes
                            2. if (exp.f64 a) < 0.0

                              1. Initial program 11.7%

                                \[\log \left(e^{a} + e^{b}\right) \]
                              2. Add Preprocessing
                              3. Taylor expanded in b around 0

                                \[\leadsto \color{blue}{\log \left(1 + e^{a}\right) + \frac{b}{1 + e^{a}}} \]
                              4. Step-by-step derivation
                                1. +-commutativeN/A

                                  \[\leadsto \color{blue}{\frac{b}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
                                2. *-rgt-identityN/A

                                  \[\leadsto \frac{\color{blue}{b \cdot 1}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
                                3. associate-*r/N/A

                                  \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                                4. lower-+.f64N/A

                                  \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
                                5. associate-*r/N/A

                                  \[\leadsto \color{blue}{\frac{b \cdot 1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                                6. *-rgt-identityN/A

                                  \[\leadsto \frac{\color{blue}{b}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
                                7. lower-/.f64N/A

                                  \[\leadsto \color{blue}{\frac{b}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                                8. +-commutativeN/A

                                  \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
                                9. lower-+.f64N/A

                                  \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
                                10. lower-exp.f64N/A

                                  \[\leadsto \frac{b}{\color{blue}{e^{a}} + 1} + \log \left(1 + e^{a}\right) \]
                                11. lower-log1p.f64N/A

                                  \[\leadsto \frac{b}{e^{a} + 1} + \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
                                12. lower-exp.f64100.0

                                  \[\leadsto \frac{b}{e^{a} + 1} + \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]
                              5. Applied rewrites100.0%

                                \[\leadsto \color{blue}{\frac{b}{e^{a} + 1} + \mathsf{log1p}\left(e^{a}\right)} \]
                              6. Step-by-step derivation
                                1. Applied rewrites54.3%

                                  \[\leadsto \left({\left(\frac{b}{1 + e^{a}}\right)}^{2} - {\left(\mathsf{log1p}\left(e^{a}\right)\right)}^{2}\right) \cdot \color{blue}{{\left(\frac{b}{1 + e^{a}} - \mathsf{log1p}\left(e^{a}\right)\right)}^{-1}} \]
                                2. Step-by-step derivation
                                  1. Applied rewrites54.3%

                                    \[\leadsto \left({\left(\frac{b}{1 + e^{a}}\right)}^{2} - {\left(e^{2}\right)}^{\log \left(\mathsf{log1p}\left(e^{a}\right)\right)}\right) \cdot {\left(\frac{b}{1 + e^{a}} - \color{blue}{\mathsf{log1p}\left(e^{a}\right)}\right)}^{-1} \]
                                  2. Taylor expanded in b around inf

                                    \[\leadsto \frac{b}{\color{blue}{1 + e^{a}}} \]
                                  3. Step-by-step derivation
                                    1. Applied rewrites100.0%

                                      \[\leadsto \frac{b}{\color{blue}{1 + e^{a}}} \]

                                    if 0.0 < (exp.f64 a)

                                    1. Initial program 71.6%

                                      \[\log \left(e^{a} + e^{b}\right) \]
                                    2. Add Preprocessing
                                    3. Taylor expanded in b around 0

                                      \[\leadsto \log \color{blue}{\left(1 + \left(e^{a} + b \cdot \left(1 + \frac{1}{2} \cdot b\right)\right)\right)} \]
                                    4. Step-by-step derivation
                                      1. associate-+r+N/A

                                        \[\leadsto \log \color{blue}{\left(\left(1 + e^{a}\right) + b \cdot \left(1 + \frac{1}{2} \cdot b\right)\right)} \]
                                      2. +-commutativeN/A

                                        \[\leadsto \log \color{blue}{\left(b \cdot \left(1 + \frac{1}{2} \cdot b\right) + \left(1 + e^{a}\right)\right)} \]
                                      3. *-commutativeN/A

                                        \[\leadsto \log \left(\color{blue}{\left(1 + \frac{1}{2} \cdot b\right) \cdot b} + \left(1 + e^{a}\right)\right) \]
                                      4. lower-fma.f64N/A

                                        \[\leadsto \log \color{blue}{\left(\mathsf{fma}\left(1 + \frac{1}{2} \cdot b, b, 1 + e^{a}\right)\right)} \]
                                      5. +-commutativeN/A

                                        \[\leadsto \log \left(\mathsf{fma}\left(\color{blue}{\frac{1}{2} \cdot b + 1}, b, 1 + e^{a}\right)\right) \]
                                      6. lower-fma.f64N/A

                                        \[\leadsto \log \left(\mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(\frac{1}{2}, b, 1\right)}, b, 1 + e^{a}\right)\right) \]
                                      7. +-commutativeN/A

                                        \[\leadsto \log \left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{2}, b, 1\right), b, \color{blue}{e^{a} + 1}\right)\right) \]
                                      8. lower-+.f64N/A

                                        \[\leadsto \log \left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{2}, b, 1\right), b, \color{blue}{e^{a} + 1}\right)\right) \]
                                      9. lower-exp.f6469.0

                                        \[\leadsto \log \left(\mathsf{fma}\left(\mathsf{fma}\left(0.5, b, 1\right), b, \color{blue}{e^{a}} + 1\right)\right) \]
                                    5. Applied rewrites69.0%

                                      \[\leadsto \log \color{blue}{\left(\mathsf{fma}\left(\mathsf{fma}\left(0.5, b, 1\right), b, e^{a} + 1\right)\right)} \]
                                    6. Taylor expanded in a around 0

                                      \[\leadsto \log \left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{2}, b, 1\right), b, 2 + a \cdot \left(1 + \frac{1}{2} \cdot a\right)\right)\right) \]
                                    7. Step-by-step derivation
                                      1. Applied rewrites66.9%

                                        \[\leadsto \log \left(\mathsf{fma}\left(\mathsf{fma}\left(0.5, b, 1\right), b, \mathsf{fma}\left(\mathsf{fma}\left(0.5, a, 1\right), a, 2\right)\right)\right) \]
                                    8. Recombined 2 regimes into one program.
                                    9. Add Preprocessing

                                    Alternative 7: 97.5% accurate, 1.4× speedup?

                                    \[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \begin{array}{l} \mathbf{if}\;e^{a} \leq 0.05:\\ \;\;\;\;\frac{b}{1 + e^{a}}\\ \mathbf{else}:\\ \;\;\;\;\log \left(\mathsf{fma}\left(\mathsf{fma}\left(0.5, b, 1\right), b, 2 + a\right)\right)\\ \end{array} \end{array} \]
                                    NOTE: a and b should be sorted in increasing order before calling this function.
                                    (FPCore (a b)
                                     :precision binary64
                                     (if (<= (exp a) 0.05)
                                       (/ b (+ 1.0 (exp a)))
                                       (log (fma (fma 0.5 b 1.0) b (+ 2.0 a)))))
                                    assert(a < b);
                                    double code(double a, double b) {
                                    	double tmp;
                                    	if (exp(a) <= 0.05) {
                                    		tmp = b / (1.0 + exp(a));
                                    	} else {
                                    		tmp = log(fma(fma(0.5, b, 1.0), b, (2.0 + a)));
                                    	}
                                    	return tmp;
                                    }
                                    
                                    a, b = sort([a, b])
                                    function code(a, b)
                                    	tmp = 0.0
                                    	if (exp(a) <= 0.05)
                                    		tmp = Float64(b / Float64(1.0 + exp(a)));
                                    	else
                                    		tmp = log(fma(fma(0.5, b, 1.0), b, Float64(2.0 + a)));
                                    	end
                                    	return tmp
                                    end
                                    
                                    NOTE: a and b should be sorted in increasing order before calling this function.
                                    code[a_, b_] := If[LessEqual[N[Exp[a], $MachinePrecision], 0.05], N[(b / N[(1.0 + N[Exp[a], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[Log[N[(N[(0.5 * b + 1.0), $MachinePrecision] * b + N[(2.0 + a), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]]
                                    
                                    \begin{array}{l}
                                    [a, b] = \mathsf{sort}([a, b])\\
                                    \\
                                    \begin{array}{l}
                                    \mathbf{if}\;e^{a} \leq 0.05:\\
                                    \;\;\;\;\frac{b}{1 + e^{a}}\\
                                    
                                    \mathbf{else}:\\
                                    \;\;\;\;\log \left(\mathsf{fma}\left(\mathsf{fma}\left(0.5, b, 1\right), b, 2 + a\right)\right)\\
                                    
                                    
                                    \end{array}
                                    \end{array}
                                    
                                    Derivation
                                    1. Split input into 2 regimes
                                    2. if (exp.f64 a) < 0.050000000000000003

                                      1. Initial program 16.0%

                                        \[\log \left(e^{a} + e^{b}\right) \]
                                      2. Add Preprocessing
                                      3. Taylor expanded in b around 0

                                        \[\leadsto \color{blue}{\log \left(1 + e^{a}\right) + \frac{b}{1 + e^{a}}} \]
                                      4. Step-by-step derivation
                                        1. +-commutativeN/A

                                          \[\leadsto \color{blue}{\frac{b}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
                                        2. *-rgt-identityN/A

                                          \[\leadsto \frac{\color{blue}{b \cdot 1}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
                                        3. associate-*r/N/A

                                          \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                                        4. lower-+.f64N/A

                                          \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
                                        5. associate-*r/N/A

                                          \[\leadsto \color{blue}{\frac{b \cdot 1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                                        6. *-rgt-identityN/A

                                          \[\leadsto \frac{\color{blue}{b}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
                                        7. lower-/.f64N/A

                                          \[\leadsto \color{blue}{\frac{b}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                                        8. +-commutativeN/A

                                          \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
                                        9. lower-+.f64N/A

                                          \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
                                        10. lower-exp.f64N/A

                                          \[\leadsto \frac{b}{\color{blue}{e^{a}} + 1} + \log \left(1 + e^{a}\right) \]
                                        11. lower-log1p.f64N/A

                                          \[\leadsto \frac{b}{e^{a} + 1} + \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
                                        12. lower-exp.f6498.1

                                          \[\leadsto \frac{b}{e^{a} + 1} + \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]
                                      5. Applied rewrites98.1%

                                        \[\leadsto \color{blue}{\frac{b}{e^{a} + 1} + \mathsf{log1p}\left(e^{a}\right)} \]
                                      6. Step-by-step derivation
                                        1. Applied rewrites55.0%

                                          \[\leadsto \left({\left(\frac{b}{1 + e^{a}}\right)}^{2} - {\left(\mathsf{log1p}\left(e^{a}\right)\right)}^{2}\right) \cdot \color{blue}{{\left(\frac{b}{1 + e^{a}} - \mathsf{log1p}\left(e^{a}\right)\right)}^{-1}} \]
                                        2. Step-by-step derivation
                                          1. Applied rewrites55.0%

                                            \[\leadsto \left({\left(\frac{b}{1 + e^{a}}\right)}^{2} - {\left(e^{2}\right)}^{\log \left(\mathsf{log1p}\left(e^{a}\right)\right)}\right) \cdot {\left(\frac{b}{1 + e^{a}} - \color{blue}{\mathsf{log1p}\left(e^{a}\right)}\right)}^{-1} \]
                                          2. Taylor expanded in b around inf

                                            \[\leadsto \frac{b}{\color{blue}{1 + e^{a}}} \]
                                          3. Step-by-step derivation
                                            1. Applied rewrites94.5%

                                              \[\leadsto \frac{b}{\color{blue}{1 + e^{a}}} \]

                                            if 0.050000000000000003 < (exp.f64 a)

                                            1. Initial program 71.4%

                                              \[\log \left(e^{a} + e^{b}\right) \]
                                            2. Add Preprocessing
                                            3. Taylor expanded in b around 0

                                              \[\leadsto \log \color{blue}{\left(1 + \left(e^{a} + b \cdot \left(1 + \frac{1}{2} \cdot b\right)\right)\right)} \]
                                            4. Step-by-step derivation
                                              1. associate-+r+N/A

                                                \[\leadsto \log \color{blue}{\left(\left(1 + e^{a}\right) + b \cdot \left(1 + \frac{1}{2} \cdot b\right)\right)} \]
                                              2. +-commutativeN/A

                                                \[\leadsto \log \color{blue}{\left(b \cdot \left(1 + \frac{1}{2} \cdot b\right) + \left(1 + e^{a}\right)\right)} \]
                                              3. *-commutativeN/A

                                                \[\leadsto \log \left(\color{blue}{\left(1 + \frac{1}{2} \cdot b\right) \cdot b} + \left(1 + e^{a}\right)\right) \]
                                              4. lower-fma.f64N/A

                                                \[\leadsto \log \color{blue}{\left(\mathsf{fma}\left(1 + \frac{1}{2} \cdot b, b, 1 + e^{a}\right)\right)} \]
                                              5. +-commutativeN/A

                                                \[\leadsto \log \left(\mathsf{fma}\left(\color{blue}{\frac{1}{2} \cdot b + 1}, b, 1 + e^{a}\right)\right) \]
                                              6. lower-fma.f64N/A

                                                \[\leadsto \log \left(\mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(\frac{1}{2}, b, 1\right)}, b, 1 + e^{a}\right)\right) \]
                                              7. +-commutativeN/A

                                                \[\leadsto \log \left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{2}, b, 1\right), b, \color{blue}{e^{a} + 1}\right)\right) \]
                                              8. lower-+.f64N/A

                                                \[\leadsto \log \left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{2}, b, 1\right), b, \color{blue}{e^{a} + 1}\right)\right) \]
                                              9. lower-exp.f6469.3

                                                \[\leadsto \log \left(\mathsf{fma}\left(\mathsf{fma}\left(0.5, b, 1\right), b, \color{blue}{e^{a}} + 1\right)\right) \]
                                            5. Applied rewrites69.3%

                                              \[\leadsto \log \color{blue}{\left(\mathsf{fma}\left(\mathsf{fma}\left(0.5, b, 1\right), b, e^{a} + 1\right)\right)} \]
                                            6. Taylor expanded in a around 0

                                              \[\leadsto \log \left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{2}, b, 1\right), b, 2 + a\right)\right) \]
                                            7. Step-by-step derivation
                                              1. Applied rewrites67.3%

                                                \[\leadsto \log \left(\mathsf{fma}\left(\mathsf{fma}\left(0.5, b, 1\right), b, 2 + a\right)\right) \]
                                            8. Recombined 2 regimes into one program.
                                            9. Add Preprocessing

                                            Alternative 8: 97.3% accurate, 1.4× speedup?

                                            \[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \begin{array}{l} \mathbf{if}\;e^{a} \leq 0.05:\\ \;\;\;\;\frac{b}{1 + e^{a}}\\ \mathbf{else}:\\ \;\;\;\;\log \left(\left(1 + a\right) + \left(1 + b\right)\right)\\ \end{array} \end{array} \]
                                            NOTE: a and b should be sorted in increasing order before calling this function.
                                            (FPCore (a b)
                                             :precision binary64
                                             (if (<= (exp a) 0.05) (/ b (+ 1.0 (exp a))) (log (+ (+ 1.0 a) (+ 1.0 b)))))
                                            assert(a < b);
                                            double code(double a, double b) {
                                            	double tmp;
                                            	if (exp(a) <= 0.05) {
                                            		tmp = b / (1.0 + exp(a));
                                            	} else {
                                            		tmp = log(((1.0 + a) + (1.0 + b)));
                                            	}
                                            	return tmp;
                                            }
                                            
                                            NOTE: a and b should be sorted in increasing order before calling this function.
                                            real(8) function code(a, b)
                                                real(8), intent (in) :: a
                                                real(8), intent (in) :: b
                                                real(8) :: tmp
                                                if (exp(a) <= 0.05d0) then
                                                    tmp = b / (1.0d0 + exp(a))
                                                else
                                                    tmp = log(((1.0d0 + a) + (1.0d0 + b)))
                                                end if
                                                code = tmp
                                            end function
                                            
                                            assert a < b;
                                            public static double code(double a, double b) {
                                            	double tmp;
                                            	if (Math.exp(a) <= 0.05) {
                                            		tmp = b / (1.0 + Math.exp(a));
                                            	} else {
                                            		tmp = Math.log(((1.0 + a) + (1.0 + b)));
                                            	}
                                            	return tmp;
                                            }
                                            
                                            [a, b] = sort([a, b])
                                            def code(a, b):
                                            	tmp = 0
                                            	if math.exp(a) <= 0.05:
                                            		tmp = b / (1.0 + math.exp(a))
                                            	else:
                                            		tmp = math.log(((1.0 + a) + (1.0 + b)))
                                            	return tmp
                                            
                                            a, b = sort([a, b])
                                            function code(a, b)
                                            	tmp = 0.0
                                            	if (exp(a) <= 0.05)
                                            		tmp = Float64(b / Float64(1.0 + exp(a)));
                                            	else
                                            		tmp = log(Float64(Float64(1.0 + a) + Float64(1.0 + b)));
                                            	end
                                            	return tmp
                                            end
                                            
                                            a, b = num2cell(sort([a, b])){:}
                                            function tmp_2 = code(a, b)
                                            	tmp = 0.0;
                                            	if (exp(a) <= 0.05)
                                            		tmp = b / (1.0 + exp(a));
                                            	else
                                            		tmp = log(((1.0 + a) + (1.0 + b)));
                                            	end
                                            	tmp_2 = tmp;
                                            end
                                            
                                            NOTE: a and b should be sorted in increasing order before calling this function.
                                            code[a_, b_] := If[LessEqual[N[Exp[a], $MachinePrecision], 0.05], N[(b / N[(1.0 + N[Exp[a], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[Log[N[(N[(1.0 + a), $MachinePrecision] + N[(1.0 + b), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]]
                                            
                                            \begin{array}{l}
                                            [a, b] = \mathsf{sort}([a, b])\\
                                            \\
                                            \begin{array}{l}
                                            \mathbf{if}\;e^{a} \leq 0.05:\\
                                            \;\;\;\;\frac{b}{1 + e^{a}}\\
                                            
                                            \mathbf{else}:\\
                                            \;\;\;\;\log \left(\left(1 + a\right) + \left(1 + b\right)\right)\\
                                            
                                            
                                            \end{array}
                                            \end{array}
                                            
                                            Derivation
                                            1. Split input into 2 regimes
                                            2. if (exp.f64 a) < 0.050000000000000003

                                              1. Initial program 16.0%

                                                \[\log \left(e^{a} + e^{b}\right) \]
                                              2. Add Preprocessing
                                              3. Taylor expanded in b around 0

                                                \[\leadsto \color{blue}{\log \left(1 + e^{a}\right) + \frac{b}{1 + e^{a}}} \]
                                              4. Step-by-step derivation
                                                1. +-commutativeN/A

                                                  \[\leadsto \color{blue}{\frac{b}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
                                                2. *-rgt-identityN/A

                                                  \[\leadsto \frac{\color{blue}{b \cdot 1}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
                                                3. associate-*r/N/A

                                                  \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                                                4. lower-+.f64N/A

                                                  \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
                                                5. associate-*r/N/A

                                                  \[\leadsto \color{blue}{\frac{b \cdot 1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                                                6. *-rgt-identityN/A

                                                  \[\leadsto \frac{\color{blue}{b}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
                                                7. lower-/.f64N/A

                                                  \[\leadsto \color{blue}{\frac{b}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                                                8. +-commutativeN/A

                                                  \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
                                                9. lower-+.f64N/A

                                                  \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
                                                10. lower-exp.f64N/A

                                                  \[\leadsto \frac{b}{\color{blue}{e^{a}} + 1} + \log \left(1 + e^{a}\right) \]
                                                11. lower-log1p.f64N/A

                                                  \[\leadsto \frac{b}{e^{a} + 1} + \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
                                                12. lower-exp.f6498.1

                                                  \[\leadsto \frac{b}{e^{a} + 1} + \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]
                                              5. Applied rewrites98.1%

                                                \[\leadsto \color{blue}{\frac{b}{e^{a} + 1} + \mathsf{log1p}\left(e^{a}\right)} \]
                                              6. Step-by-step derivation
                                                1. Applied rewrites55.0%

                                                  \[\leadsto \left({\left(\frac{b}{1 + e^{a}}\right)}^{2} - {\left(\mathsf{log1p}\left(e^{a}\right)\right)}^{2}\right) \cdot \color{blue}{{\left(\frac{b}{1 + e^{a}} - \mathsf{log1p}\left(e^{a}\right)\right)}^{-1}} \]
                                                2. Step-by-step derivation
                                                  1. Applied rewrites55.0%

                                                    \[\leadsto \left({\left(\frac{b}{1 + e^{a}}\right)}^{2} - {\left(e^{2}\right)}^{\log \left(\mathsf{log1p}\left(e^{a}\right)\right)}\right) \cdot {\left(\frac{b}{1 + e^{a}} - \color{blue}{\mathsf{log1p}\left(e^{a}\right)}\right)}^{-1} \]
                                                  2. Taylor expanded in b around inf

                                                    \[\leadsto \frac{b}{\color{blue}{1 + e^{a}}} \]
                                                  3. Step-by-step derivation
                                                    1. Applied rewrites94.5%

                                                      \[\leadsto \frac{b}{\color{blue}{1 + e^{a}}} \]

                                                    if 0.050000000000000003 < (exp.f64 a)

                                                    1. Initial program 71.4%

                                                      \[\log \left(e^{a} + e^{b}\right) \]
                                                    2. Add Preprocessing
                                                    3. Taylor expanded in a around 0

                                                      \[\leadsto \log \left(\color{blue}{\left(1 + a\right)} + e^{b}\right) \]
                                                    4. Step-by-step derivation
                                                      1. lower-+.f6469.2

                                                        \[\leadsto \log \left(\color{blue}{\left(1 + a\right)} + e^{b}\right) \]
                                                    5. Applied rewrites69.2%

                                                      \[\leadsto \log \left(\color{blue}{\left(1 + a\right)} + e^{b}\right) \]
                                                    6. Taylor expanded in b around 0

                                                      \[\leadsto \log \left(\left(1 + a\right) + \color{blue}{\left(1 + b\right)}\right) \]
                                                    7. Step-by-step derivation
                                                      1. lower-+.f6466.4

                                                        \[\leadsto \log \left(\left(1 + a\right) + \color{blue}{\left(1 + b\right)}\right) \]
                                                    8. Applied rewrites66.4%

                                                      \[\leadsto \log \left(\left(1 + a\right) + \color{blue}{\left(1 + b\right)}\right) \]
                                                  4. Recombined 2 regimes into one program.
                                                  5. Add Preprocessing

                                                  Alternative 9: 98.0% accurate, 1.4× speedup?

                                                  \[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \begin{array}{l} \mathbf{if}\;a \leq -36:\\ \;\;\;\;\frac{b}{1 + e^{a}}\\ \mathbf{else}:\\ \;\;\;\;\log \left(e^{a} + \left(1 + b\right)\right)\\ \end{array} \end{array} \]
                                                  NOTE: a and b should be sorted in increasing order before calling this function.
                                                  (FPCore (a b)
                                                   :precision binary64
                                                   (if (<= a -36.0) (/ b (+ 1.0 (exp a))) (log (+ (exp a) (+ 1.0 b)))))
                                                  assert(a < b);
                                                  double code(double a, double b) {
                                                  	double tmp;
                                                  	if (a <= -36.0) {
                                                  		tmp = b / (1.0 + exp(a));
                                                  	} else {
                                                  		tmp = log((exp(a) + (1.0 + b)));
                                                  	}
                                                  	return tmp;
                                                  }
                                                  
                                                  NOTE: a and b should be sorted in increasing order before calling this function.
                                                  real(8) function code(a, b)
                                                      real(8), intent (in) :: a
                                                      real(8), intent (in) :: b
                                                      real(8) :: tmp
                                                      if (a <= (-36.0d0)) then
                                                          tmp = b / (1.0d0 + exp(a))
                                                      else
                                                          tmp = log((exp(a) + (1.0d0 + b)))
                                                      end if
                                                      code = tmp
                                                  end function
                                                  
                                                  assert a < b;
                                                  public static double code(double a, double b) {
                                                  	double tmp;
                                                  	if (a <= -36.0) {
                                                  		tmp = b / (1.0 + Math.exp(a));
                                                  	} else {
                                                  		tmp = Math.log((Math.exp(a) + (1.0 + b)));
                                                  	}
                                                  	return tmp;
                                                  }
                                                  
                                                  [a, b] = sort([a, b])
                                                  def code(a, b):
                                                  	tmp = 0
                                                  	if a <= -36.0:
                                                  		tmp = b / (1.0 + math.exp(a))
                                                  	else:
                                                  		tmp = math.log((math.exp(a) + (1.0 + b)))
                                                  	return tmp
                                                  
                                                  a, b = sort([a, b])
                                                  function code(a, b)
                                                  	tmp = 0.0
                                                  	if (a <= -36.0)
                                                  		tmp = Float64(b / Float64(1.0 + exp(a)));
                                                  	else
                                                  		tmp = log(Float64(exp(a) + Float64(1.0 + b)));
                                                  	end
                                                  	return tmp
                                                  end
                                                  
                                                  a, b = num2cell(sort([a, b])){:}
                                                  function tmp_2 = code(a, b)
                                                  	tmp = 0.0;
                                                  	if (a <= -36.0)
                                                  		tmp = b / (1.0 + exp(a));
                                                  	else
                                                  		tmp = log((exp(a) + (1.0 + b)));
                                                  	end
                                                  	tmp_2 = tmp;
                                                  end
                                                  
                                                  NOTE: a and b should be sorted in increasing order before calling this function.
                                                  code[a_, b_] := If[LessEqual[a, -36.0], N[(b / N[(1.0 + N[Exp[a], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[Log[N[(N[Exp[a], $MachinePrecision] + N[(1.0 + b), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]]
                                                  
                                                  \begin{array}{l}
                                                  [a, b] = \mathsf{sort}([a, b])\\
                                                  \\
                                                  \begin{array}{l}
                                                  \mathbf{if}\;a \leq -36:\\
                                                  \;\;\;\;\frac{b}{1 + e^{a}}\\
                                                  
                                                  \mathbf{else}:\\
                                                  \;\;\;\;\log \left(e^{a} + \left(1 + b\right)\right)\\
                                                  
                                                  
                                                  \end{array}
                                                  \end{array}
                                                  
                                                  Derivation
                                                  1. Split input into 2 regimes
                                                  2. if a < -36

                                                    1. Initial program 13.5%

                                                      \[\log \left(e^{a} + e^{b}\right) \]
                                                    2. Add Preprocessing
                                                    3. Taylor expanded in b around 0

                                                      \[\leadsto \color{blue}{\log \left(1 + e^{a}\right) + \frac{b}{1 + e^{a}}} \]
                                                    4. Step-by-step derivation
                                                      1. +-commutativeN/A

                                                        \[\leadsto \color{blue}{\frac{b}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
                                                      2. *-rgt-identityN/A

                                                        \[\leadsto \frac{\color{blue}{b \cdot 1}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
                                                      3. associate-*r/N/A

                                                        \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                                                      4. lower-+.f64N/A

                                                        \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
                                                      5. associate-*r/N/A

                                                        \[\leadsto \color{blue}{\frac{b \cdot 1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                                                      6. *-rgt-identityN/A

                                                        \[\leadsto \frac{\color{blue}{b}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
                                                      7. lower-/.f64N/A

                                                        \[\leadsto \color{blue}{\frac{b}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                                                      8. +-commutativeN/A

                                                        \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
                                                      9. lower-+.f64N/A

                                                        \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
                                                      10. lower-exp.f64N/A

                                                        \[\leadsto \frac{b}{\color{blue}{e^{a}} + 1} + \log \left(1 + e^{a}\right) \]
                                                      11. lower-log1p.f64N/A

                                                        \[\leadsto \frac{b}{e^{a} + 1} + \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
                                                      12. lower-exp.f6498.1

                                                        \[\leadsto \frac{b}{e^{a} + 1} + \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]
                                                    5. Applied rewrites98.1%

                                                      \[\leadsto \color{blue}{\frac{b}{e^{a} + 1} + \mathsf{log1p}\left(e^{a}\right)} \]
                                                    6. Step-by-step derivation
                                                      1. Applied rewrites53.3%

                                                        \[\leadsto \left({\left(\frac{b}{1 + e^{a}}\right)}^{2} - {\left(\mathsf{log1p}\left(e^{a}\right)\right)}^{2}\right) \cdot \color{blue}{{\left(\frac{b}{1 + e^{a}} - \mathsf{log1p}\left(e^{a}\right)\right)}^{-1}} \]
                                                      2. Step-by-step derivation
                                                        1. Applied rewrites53.3%

                                                          \[\leadsto \left({\left(\frac{b}{1 + e^{a}}\right)}^{2} - {\left(e^{2}\right)}^{\log \left(\mathsf{log1p}\left(e^{a}\right)\right)}\right) \cdot {\left(\frac{b}{1 + e^{a}} - \color{blue}{\mathsf{log1p}\left(e^{a}\right)}\right)}^{-1} \]
                                                        2. Taylor expanded in b around inf

                                                          \[\leadsto \frac{b}{\color{blue}{1 + e^{a}}} \]
                                                        3. Step-by-step derivation
                                                          1. Applied rewrites98.1%

                                                            \[\leadsto \frac{b}{\color{blue}{1 + e^{a}}} \]

                                                          if -36 < a

                                                          1. Initial program 71.5%

                                                            \[\log \left(e^{a} + e^{b}\right) \]
                                                          2. Add Preprocessing
                                                          3. Taylor expanded in b around 0

                                                            \[\leadsto \log \left(e^{a} + \color{blue}{\left(1 + b\right)}\right) \]
                                                          4. Step-by-step derivation
                                                            1. lower-+.f6468.5

                                                              \[\leadsto \log \left(e^{a} + \color{blue}{\left(1 + b\right)}\right) \]
                                                          5. Applied rewrites68.5%

                                                            \[\leadsto \log \left(e^{a} + \color{blue}{\left(1 + b\right)}\right) \]
                                                        4. Recombined 2 regimes into one program.
                                                        5. Add Preprocessing

                                                        Alternative 10: 97.9% accurate, 1.4× speedup?

                                                        \[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \begin{array}{l} \mathbf{if}\;a \leq -1.05:\\ \;\;\;\;\frac{b}{1 + e^{a}}\\ \mathbf{else}:\\ \;\;\;\;\log \left(\left(1 + a\right) + e^{b}\right)\\ \end{array} \end{array} \]
                                                        NOTE: a and b should be sorted in increasing order before calling this function.
                                                        (FPCore (a b)
                                                         :precision binary64
                                                         (if (<= a -1.05) (/ b (+ 1.0 (exp a))) (log (+ (+ 1.0 a) (exp b)))))
                                                        assert(a < b);
                                                        double code(double a, double b) {
                                                        	double tmp;
                                                        	if (a <= -1.05) {
                                                        		tmp = b / (1.0 + exp(a));
                                                        	} else {
                                                        		tmp = log(((1.0 + a) + exp(b)));
                                                        	}
                                                        	return tmp;
                                                        }
                                                        
                                                        NOTE: a and b should be sorted in increasing order before calling this function.
                                                        real(8) function code(a, b)
                                                            real(8), intent (in) :: a
                                                            real(8), intent (in) :: b
                                                            real(8) :: tmp
                                                            if (a <= (-1.05d0)) then
                                                                tmp = b / (1.0d0 + exp(a))
                                                            else
                                                                tmp = log(((1.0d0 + a) + exp(b)))
                                                            end if
                                                            code = tmp
                                                        end function
                                                        
                                                        assert a < b;
                                                        public static double code(double a, double b) {
                                                        	double tmp;
                                                        	if (a <= -1.05) {
                                                        		tmp = b / (1.0 + Math.exp(a));
                                                        	} else {
                                                        		tmp = Math.log(((1.0 + a) + Math.exp(b)));
                                                        	}
                                                        	return tmp;
                                                        }
                                                        
                                                        [a, b] = sort([a, b])
                                                        def code(a, b):
                                                        	tmp = 0
                                                        	if a <= -1.05:
                                                        		tmp = b / (1.0 + math.exp(a))
                                                        	else:
                                                        		tmp = math.log(((1.0 + a) + math.exp(b)))
                                                        	return tmp
                                                        
                                                        a, b = sort([a, b])
                                                        function code(a, b)
                                                        	tmp = 0.0
                                                        	if (a <= -1.05)
                                                        		tmp = Float64(b / Float64(1.0 + exp(a)));
                                                        	else
                                                        		tmp = log(Float64(Float64(1.0 + a) + exp(b)));
                                                        	end
                                                        	return tmp
                                                        end
                                                        
                                                        a, b = num2cell(sort([a, b])){:}
                                                        function tmp_2 = code(a, b)
                                                        	tmp = 0.0;
                                                        	if (a <= -1.05)
                                                        		tmp = b / (1.0 + exp(a));
                                                        	else
                                                        		tmp = log(((1.0 + a) + exp(b)));
                                                        	end
                                                        	tmp_2 = tmp;
                                                        end
                                                        
                                                        NOTE: a and b should be sorted in increasing order before calling this function.
                                                        code[a_, b_] := If[LessEqual[a, -1.05], N[(b / N[(1.0 + N[Exp[a], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[Log[N[(N[(1.0 + a), $MachinePrecision] + N[Exp[b], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]]
                                                        
                                                        \begin{array}{l}
                                                        [a, b] = \mathsf{sort}([a, b])\\
                                                        \\
                                                        \begin{array}{l}
                                                        \mathbf{if}\;a \leq -1.05:\\
                                                        \;\;\;\;\frac{b}{1 + e^{a}}\\
                                                        
                                                        \mathbf{else}:\\
                                                        \;\;\;\;\log \left(\left(1 + a\right) + e^{b}\right)\\
                                                        
                                                        
                                                        \end{array}
                                                        \end{array}
                                                        
                                                        Derivation
                                                        1. Split input into 2 regimes
                                                        2. if a < -1.05000000000000004

                                                          1. Initial program 16.0%

                                                            \[\log \left(e^{a} + e^{b}\right) \]
                                                          2. Add Preprocessing
                                                          3. Taylor expanded in b around 0

                                                            \[\leadsto \color{blue}{\log \left(1 + e^{a}\right) + \frac{b}{1 + e^{a}}} \]
                                                          4. Step-by-step derivation
                                                            1. +-commutativeN/A

                                                              \[\leadsto \color{blue}{\frac{b}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
                                                            2. *-rgt-identityN/A

                                                              \[\leadsto \frac{\color{blue}{b \cdot 1}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
                                                            3. associate-*r/N/A

                                                              \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                                                            4. lower-+.f64N/A

                                                              \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
                                                            5. associate-*r/N/A

                                                              \[\leadsto \color{blue}{\frac{b \cdot 1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                                                            6. *-rgt-identityN/A

                                                              \[\leadsto \frac{\color{blue}{b}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
                                                            7. lower-/.f64N/A

                                                              \[\leadsto \color{blue}{\frac{b}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                                                            8. +-commutativeN/A

                                                              \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
                                                            9. lower-+.f64N/A

                                                              \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
                                                            10. lower-exp.f64N/A

                                                              \[\leadsto \frac{b}{\color{blue}{e^{a}} + 1} + \log \left(1 + e^{a}\right) \]
                                                            11. lower-log1p.f64N/A

                                                              \[\leadsto \frac{b}{e^{a} + 1} + \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
                                                            12. lower-exp.f6498.1

                                                              \[\leadsto \frac{b}{e^{a} + 1} + \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]
                                                          5. Applied rewrites98.1%

                                                            \[\leadsto \color{blue}{\frac{b}{e^{a} + 1} + \mathsf{log1p}\left(e^{a}\right)} \]
                                                          6. Step-by-step derivation
                                                            1. Applied rewrites55.0%

                                                              \[\leadsto \left({\left(\frac{b}{1 + e^{a}}\right)}^{2} - {\left(\mathsf{log1p}\left(e^{a}\right)\right)}^{2}\right) \cdot \color{blue}{{\left(\frac{b}{1 + e^{a}} - \mathsf{log1p}\left(e^{a}\right)\right)}^{-1}} \]
                                                            2. Step-by-step derivation
                                                              1. Applied rewrites55.0%

                                                                \[\leadsto \left({\left(\frac{b}{1 + e^{a}}\right)}^{2} - {\left(e^{2}\right)}^{\log \left(\mathsf{log1p}\left(e^{a}\right)\right)}\right) \cdot {\left(\frac{b}{1 + e^{a}} - \color{blue}{\mathsf{log1p}\left(e^{a}\right)}\right)}^{-1} \]
                                                              2. Taylor expanded in b around inf

                                                                \[\leadsto \frac{b}{\color{blue}{1 + e^{a}}} \]
                                                              3. Step-by-step derivation
                                                                1. Applied rewrites94.5%

                                                                  \[\leadsto \frac{b}{\color{blue}{1 + e^{a}}} \]

                                                                if -1.05000000000000004 < a

                                                                1. Initial program 71.4%

                                                                  \[\log \left(e^{a} + e^{b}\right) \]
                                                                2. Add Preprocessing
                                                                3. Taylor expanded in a around 0

                                                                  \[\leadsto \log \left(\color{blue}{\left(1 + a\right)} + e^{b}\right) \]
                                                                4. Step-by-step derivation
                                                                  1. lower-+.f6469.2

                                                                    \[\leadsto \log \left(\color{blue}{\left(1 + a\right)} + e^{b}\right) \]
                                                                5. Applied rewrites69.2%

                                                                  \[\leadsto \log \left(\color{blue}{\left(1 + a\right)} + e^{b}\right) \]
                                                              4. Recombined 2 regimes into one program.
                                                              5. Add Preprocessing

                                                              Alternative 11: 49.0% accurate, 2.8× speedup?

                                                              \[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \mathsf{fma}\left(0.5, b, \log 2\right) \end{array} \]
                                                              NOTE: a and b should be sorted in increasing order before calling this function.
                                                              (FPCore (a b) :precision binary64 (fma 0.5 b (log 2.0)))
                                                              assert(a < b);
                                                              double code(double a, double b) {
                                                              	return fma(0.5, b, log(2.0));
                                                              }
                                                              
                                                              a, b = sort([a, b])
                                                              function code(a, b)
                                                              	return fma(0.5, b, log(2.0))
                                                              end
                                                              
                                                              NOTE: a and b should be sorted in increasing order before calling this function.
                                                              code[a_, b_] := N[(0.5 * b + N[Log[2.0], $MachinePrecision]), $MachinePrecision]
                                                              
                                                              \begin{array}{l}
                                                              [a, b] = \mathsf{sort}([a, b])\\
                                                              \\
                                                              \mathsf{fma}\left(0.5, b, \log 2\right)
                                                              \end{array}
                                                              
                                                              Derivation
                                                              1. Initial program 59.9%

                                                                \[\log \left(e^{a} + e^{b}\right) \]
                                                              2. Add Preprocessing
                                                              3. Taylor expanded in b around 0

                                                                \[\leadsto \color{blue}{\log \left(1 + e^{a}\right) + \frac{b}{1 + e^{a}}} \]
                                                              4. Step-by-step derivation
                                                                1. +-commutativeN/A

                                                                  \[\leadsto \color{blue}{\frac{b}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
                                                                2. *-rgt-identityN/A

                                                                  \[\leadsto \frac{\color{blue}{b \cdot 1}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
                                                                3. associate-*r/N/A

                                                                  \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                                                                4. lower-+.f64N/A

                                                                  \[\leadsto \color{blue}{b \cdot \frac{1}{1 + e^{a}} + \log \left(1 + e^{a}\right)} \]
                                                                5. associate-*r/N/A

                                                                  \[\leadsto \color{blue}{\frac{b \cdot 1}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                                                                6. *-rgt-identityN/A

                                                                  \[\leadsto \frac{\color{blue}{b}}{1 + e^{a}} + \log \left(1 + e^{a}\right) \]
                                                                7. lower-/.f64N/A

                                                                  \[\leadsto \color{blue}{\frac{b}{1 + e^{a}}} + \log \left(1 + e^{a}\right) \]
                                                                8. +-commutativeN/A

                                                                  \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
                                                                9. lower-+.f64N/A

                                                                  \[\leadsto \frac{b}{\color{blue}{e^{a} + 1}} + \log \left(1 + e^{a}\right) \]
                                                                10. lower-exp.f64N/A

                                                                  \[\leadsto \frac{b}{\color{blue}{e^{a}} + 1} + \log \left(1 + e^{a}\right) \]
                                                                11. lower-log1p.f64N/A

                                                                  \[\leadsto \frac{b}{e^{a} + 1} + \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
                                                                12. lower-exp.f6475.2

                                                                  \[\leadsto \frac{b}{e^{a} + 1} + \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]
                                                              5. Applied rewrites75.2%

                                                                \[\leadsto \color{blue}{\frac{b}{e^{a} + 1} + \mathsf{log1p}\left(e^{a}\right)} \]
                                                              6. Taylor expanded in a around 0

                                                                \[\leadsto \log 2 + \color{blue}{\frac{1}{2} \cdot b} \]
                                                              7. Step-by-step derivation
                                                                1. Applied rewrites53.6%

                                                                  \[\leadsto \mathsf{fma}\left(0.5, \color{blue}{b}, \log 2\right) \]
                                                                2. Add Preprocessing

                                                                Alternative 12: 47.9% accurate, 2.8× speedup?

                                                                \[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \mathsf{fma}\left(0.5, a, \log 2\right) \end{array} \]
                                                                NOTE: a and b should be sorted in increasing order before calling this function.
                                                                (FPCore (a b) :precision binary64 (fma 0.5 a (log 2.0)))
                                                                assert(a < b);
                                                                double code(double a, double b) {
                                                                	return fma(0.5, a, log(2.0));
                                                                }
                                                                
                                                                a, b = sort([a, b])
                                                                function code(a, b)
                                                                	return fma(0.5, a, log(2.0))
                                                                end
                                                                
                                                                NOTE: a and b should be sorted in increasing order before calling this function.
                                                                code[a_, b_] := N[(0.5 * a + N[Log[2.0], $MachinePrecision]), $MachinePrecision]
                                                                
                                                                \begin{array}{l}
                                                                [a, b] = \mathsf{sort}([a, b])\\
                                                                \\
                                                                \mathsf{fma}\left(0.5, a, \log 2\right)
                                                                \end{array}
                                                                
                                                                Derivation
                                                                1. Initial program 59.9%

                                                                  \[\log \left(e^{a} + e^{b}\right) \]
                                                                2. Add Preprocessing
                                                                3. Taylor expanded in b around 0

                                                                  \[\leadsto \color{blue}{\log \left(1 + e^{a}\right)} \]
                                                                4. Step-by-step derivation
                                                                  1. lower-log1p.f64N/A

                                                                    \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
                                                                  2. lower-exp.f6456.2

                                                                    \[\leadsto \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]
                                                                5. Applied rewrites56.2%

                                                                  \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
                                                                6. Taylor expanded in a around 0

                                                                  \[\leadsto \log 2 + \color{blue}{\frac{1}{2} \cdot a} \]
                                                                7. Step-by-step derivation
                                                                  1. Applied rewrites53.6%

                                                                    \[\leadsto \mathsf{fma}\left(0.5, \color{blue}{a}, \log 2\right) \]
                                                                  2. Add Preprocessing

                                                                  Alternative 13: 48.2% accurate, 3.0× speedup?

                                                                  \[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \mathsf{log1p}\left(1\right) \end{array} \]
                                                                  NOTE: a and b should be sorted in increasing order before calling this function.
                                                                  (FPCore (a b) :precision binary64 (log1p 1.0))
                                                                  assert(a < b);
                                                                  double code(double a, double b) {
                                                                  	return log1p(1.0);
                                                                  }
                                                                  
                                                                  assert a < b;
                                                                  public static double code(double a, double b) {
                                                                  	return Math.log1p(1.0);
                                                                  }
                                                                  
                                                                  [a, b] = sort([a, b])
                                                                  def code(a, b):
                                                                  	return math.log1p(1.0)
                                                                  
                                                                  a, b = sort([a, b])
                                                                  function code(a, b)
                                                                  	return log1p(1.0)
                                                                  end
                                                                  
                                                                  NOTE: a and b should be sorted in increasing order before calling this function.
                                                                  code[a_, b_] := N[Log[1 + 1.0], $MachinePrecision]
                                                                  
                                                                  \begin{array}{l}
                                                                  [a, b] = \mathsf{sort}([a, b])\\
                                                                  \\
                                                                  \mathsf{log1p}\left(1\right)
                                                                  \end{array}
                                                                  
                                                                  Derivation
                                                                  1. Initial program 59.9%

                                                                    \[\log \left(e^{a} + e^{b}\right) \]
                                                                  2. Add Preprocessing
                                                                  3. Taylor expanded in b around 0

                                                                    \[\leadsto \color{blue}{\log \left(1 + e^{a}\right)} \]
                                                                  4. Step-by-step derivation
                                                                    1. lower-log1p.f64N/A

                                                                      \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
                                                                    2. lower-exp.f6456.2

                                                                      \[\leadsto \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]
                                                                  5. Applied rewrites56.2%

                                                                    \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
                                                                  6. Taylor expanded in a around 0

                                                                    \[\leadsto \mathsf{log1p}\left(1\right) \]
                                                                  7. Step-by-step derivation
                                                                    1. Applied rewrites53.2%

                                                                      \[\leadsto \mathsf{log1p}\left(1\right) \]
                                                                    2. Add Preprocessing

                                                                    Alternative 14: 3.2% accurate, 27.6× speedup?

                                                                    \[\begin{array}{l} [a, b] = \mathsf{sort}([a, b])\\ \\ \left(a \cdot a\right) \cdot 0.125 \end{array} \]
                                                                    NOTE: a and b should be sorted in increasing order before calling this function.
                                                                    (FPCore (a b) :precision binary64 (* (* a a) 0.125))
                                                                    assert(a < b);
                                                                    double code(double a, double b) {
                                                                    	return (a * a) * 0.125;
                                                                    }
                                                                    
                                                                    NOTE: a and b should be sorted in increasing order before calling this function.
                                                                    real(8) function code(a, b)
                                                                        real(8), intent (in) :: a
                                                                        real(8), intent (in) :: b
                                                                        code = (a * a) * 0.125d0
                                                                    end function
                                                                    
                                                                    assert a < b;
                                                                    public static double code(double a, double b) {
                                                                    	return (a * a) * 0.125;
                                                                    }
                                                                    
                                                                    [a, b] = sort([a, b])
                                                                    def code(a, b):
                                                                    	return (a * a) * 0.125
                                                                    
                                                                    a, b = sort([a, b])
                                                                    function code(a, b)
                                                                    	return Float64(Float64(a * a) * 0.125)
                                                                    end
                                                                    
                                                                    a, b = num2cell(sort([a, b])){:}
                                                                    function tmp = code(a, b)
                                                                    	tmp = (a * a) * 0.125;
                                                                    end
                                                                    
                                                                    NOTE: a and b should be sorted in increasing order before calling this function.
                                                                    code[a_, b_] := N[(N[(a * a), $MachinePrecision] * 0.125), $MachinePrecision]
                                                                    
                                                                    \begin{array}{l}
                                                                    [a, b] = \mathsf{sort}([a, b])\\
                                                                    \\
                                                                    \left(a \cdot a\right) \cdot 0.125
                                                                    \end{array}
                                                                    
                                                                    Derivation
                                                                    1. Initial program 59.9%

                                                                      \[\log \left(e^{a} + e^{b}\right) \]
                                                                    2. Add Preprocessing
                                                                    3. Taylor expanded in b around 0

                                                                      \[\leadsto \color{blue}{\log \left(1 + e^{a}\right)} \]
                                                                    4. Step-by-step derivation
                                                                      1. lower-log1p.f64N/A

                                                                        \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
                                                                      2. lower-exp.f6456.2

                                                                        \[\leadsto \mathsf{log1p}\left(\color{blue}{e^{a}}\right) \]
                                                                    5. Applied rewrites56.2%

                                                                      \[\leadsto \color{blue}{\mathsf{log1p}\left(e^{a}\right)} \]
                                                                    6. Taylor expanded in a around 0

                                                                      \[\leadsto \log 2 + \color{blue}{a \cdot \left(\frac{1}{2} + \frac{1}{8} \cdot a\right)} \]
                                                                    7. Step-by-step derivation
                                                                      1. Applied rewrites53.9%

                                                                        \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(0.125, a, 0.5\right), \color{blue}{a}, \log 2\right) \]
                                                                      2. Taylor expanded in a around inf

                                                                        \[\leadsto \frac{1}{8} \cdot {a}^{\color{blue}{2}} \]
                                                                      3. Step-by-step derivation
                                                                        1. Applied rewrites4.6%

                                                                          \[\leadsto \left(a \cdot a\right) \cdot 0.125 \]
                                                                        2. Add Preprocessing

                                                                        Reproduce

                                                                        ?
                                                                        herbie shell --seed 2024322 
                                                                        (FPCore (a b)
                                                                          :name "symmetry log of sum of exp"
                                                                          :precision binary64
                                                                          (log (+ (exp a) (exp b))))