Diagrams.Solve.Polynomial:cubForm from diagrams-solve-0.1, I

Percentage Accurate: 91.2% → 91.2%
Time: 1.7s
Alternatives: 6
Speedup: 1.0×

Specification

?
\[\mathsf{TRUE}\left(\right)\]
\[\begin{array}{l} \\ \frac{x \cdot y - \left(z \cdot 9\right) \cdot t}{a \cdot 2} \end{array} \]
(FPCore (x y z t a)
 :precision binary64
 (/ (- (* x y) (* (* z 9.0) t)) (* a 2.0)))
double code(double x, double y, double z, double t, double a) {
	return ((x * y) - ((z * 9.0) * t)) / (a * 2.0);
}
real(8) function code(x, y, z, t, a)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    code = ((x * y) - ((z * 9.0d0) * t)) / (a * 2.0d0)
end function
public static double code(double x, double y, double z, double t, double a) {
	return ((x * y) - ((z * 9.0) * t)) / (a * 2.0);
}
def code(x, y, z, t, a):
	return ((x * y) - ((z * 9.0) * t)) / (a * 2.0)
function code(x, y, z, t, a)
	return Float64(Float64(Float64(x * y) - Float64(Float64(z * 9.0) * t)) / Float64(a * 2.0))
end
function tmp = code(x, y, z, t, a)
	tmp = ((x * y) - ((z * 9.0) * t)) / (a * 2.0);
end
code[x_, y_, z_, t_, a_] := N[(N[(N[(x * y), $MachinePrecision] - N[(N[(z * 9.0), $MachinePrecision] * t), $MachinePrecision]), $MachinePrecision] / N[(a * 2.0), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{x \cdot y - \left(z \cdot 9\right) \cdot t}{a \cdot 2}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 6 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 91.2% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{x \cdot y - \left(z \cdot 9\right) \cdot t}{a \cdot 2} \end{array} \]
(FPCore (x y z t a)
 :precision binary64
 (/ (- (* x y) (* (* z 9.0) t)) (* a 2.0)))
double code(double x, double y, double z, double t, double a) {
	return ((x * y) - ((z * 9.0) * t)) / (a * 2.0);
}
real(8) function code(x, y, z, t, a)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    code = ((x * y) - ((z * 9.0d0) * t)) / (a * 2.0d0)
end function
public static double code(double x, double y, double z, double t, double a) {
	return ((x * y) - ((z * 9.0) * t)) / (a * 2.0);
}
def code(x, y, z, t, a):
	return ((x * y) - ((z * 9.0) * t)) / (a * 2.0)
function code(x, y, z, t, a)
	return Float64(Float64(Float64(x * y) - Float64(Float64(z * 9.0) * t)) / Float64(a * 2.0))
end
function tmp = code(x, y, z, t, a)
	tmp = ((x * y) - ((z * 9.0) * t)) / (a * 2.0);
end
code[x_, y_, z_, t_, a_] := N[(N[(N[(x * y), $MachinePrecision] - N[(N[(z * 9.0), $MachinePrecision] * t), $MachinePrecision]), $MachinePrecision] / N[(a * 2.0), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{x \cdot y - \left(z \cdot 9\right) \cdot t}{a \cdot 2}
\end{array}

Alternative 1: 91.2% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{x \cdot y - \left(z \cdot 9\right) \cdot t}{a \cdot 2} \end{array} \]
(FPCore (x y z t a)
 :precision binary64
 (/ (- (* x y) (* (* z 9.0) t)) (* a 2.0)))
double code(double x, double y, double z, double t, double a) {
	return ((x * y) - ((z * 9.0) * t)) / (a * 2.0);
}
real(8) function code(x, y, z, t, a)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    code = ((x * y) - ((z * 9.0d0) * t)) / (a * 2.0d0)
end function
public static double code(double x, double y, double z, double t, double a) {
	return ((x * y) - ((z * 9.0) * t)) / (a * 2.0);
}
def code(x, y, z, t, a):
	return ((x * y) - ((z * 9.0) * t)) / (a * 2.0)
function code(x, y, z, t, a)
	return Float64(Float64(Float64(x * y) - Float64(Float64(z * 9.0) * t)) / Float64(a * 2.0))
end
function tmp = code(x, y, z, t, a)
	tmp = ((x * y) - ((z * 9.0) * t)) / (a * 2.0);
end
code[x_, y_, z_, t_, a_] := N[(N[(N[(x * y), $MachinePrecision] - N[(N[(z * 9.0), $MachinePrecision] * t), $MachinePrecision]), $MachinePrecision] / N[(a * 2.0), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{x \cdot y - \left(z \cdot 9\right) \cdot t}{a \cdot 2}
\end{array}
Derivation
  1. Initial program 93.0%

    \[\frac{x \cdot y - \left(z \cdot 9\right) \cdot t}{a \cdot 2} \]
  2. Add Preprocessing
  3. Add Preprocessing

Alternative 2: 67.4% accurate, 0.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := \left(z \cdot 9\right) \cdot t\\ t_2 := \frac{a \cdot 2 - t\_1}{a \cdot 2}\\ \mathbf{if}\;t\_1 \leq -1 \cdot 10^{+64}:\\ \;\;\;\;t\_2\\ \mathbf{elif}\;t\_1 \leq 2 \cdot 10^{+34}:\\ \;\;\;\;\frac{x \cdot y}{a \cdot 2}\\ \mathbf{else}:\\ \;\;\;\;t\_2\\ \end{array} \end{array} \]
(FPCore (x y z t a)
 :precision binary64
 (let* ((t_1 (* (* z 9.0) t)) (t_2 (/ (- (* a 2.0) t_1) (* a 2.0))))
   (if (<= t_1 -1e+64) t_2 (if (<= t_1 2e+34) (/ (* x y) (* a 2.0)) t_2))))
double code(double x, double y, double z, double t, double a) {
	double t_1 = (z * 9.0) * t;
	double t_2 = ((a * 2.0) - t_1) / (a * 2.0);
	double tmp;
	if (t_1 <= -1e+64) {
		tmp = t_2;
	} else if (t_1 <= 2e+34) {
		tmp = (x * y) / (a * 2.0);
	} else {
		tmp = t_2;
	}
	return tmp;
}
real(8) function code(x, y, z, t, a)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    real(8) :: t_1
    real(8) :: t_2
    real(8) :: tmp
    t_1 = (z * 9.0d0) * t
    t_2 = ((a * 2.0d0) - t_1) / (a * 2.0d0)
    if (t_1 <= (-1d+64)) then
        tmp = t_2
    else if (t_1 <= 2d+34) then
        tmp = (x * y) / (a * 2.0d0)
    else
        tmp = t_2
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t, double a) {
	double t_1 = (z * 9.0) * t;
	double t_2 = ((a * 2.0) - t_1) / (a * 2.0);
	double tmp;
	if (t_1 <= -1e+64) {
		tmp = t_2;
	} else if (t_1 <= 2e+34) {
		tmp = (x * y) / (a * 2.0);
	} else {
		tmp = t_2;
	}
	return tmp;
}
def code(x, y, z, t, a):
	t_1 = (z * 9.0) * t
	t_2 = ((a * 2.0) - t_1) / (a * 2.0)
	tmp = 0
	if t_1 <= -1e+64:
		tmp = t_2
	elif t_1 <= 2e+34:
		tmp = (x * y) / (a * 2.0)
	else:
		tmp = t_2
	return tmp
function code(x, y, z, t, a)
	t_1 = Float64(Float64(z * 9.0) * t)
	t_2 = Float64(Float64(Float64(a * 2.0) - t_1) / Float64(a * 2.0))
	tmp = 0.0
	if (t_1 <= -1e+64)
		tmp = t_2;
	elseif (t_1 <= 2e+34)
		tmp = Float64(Float64(x * y) / Float64(a * 2.0));
	else
		tmp = t_2;
	end
	return tmp
end
function tmp_2 = code(x, y, z, t, a)
	t_1 = (z * 9.0) * t;
	t_2 = ((a * 2.0) - t_1) / (a * 2.0);
	tmp = 0.0;
	if (t_1 <= -1e+64)
		tmp = t_2;
	elseif (t_1 <= 2e+34)
		tmp = (x * y) / (a * 2.0);
	else
		tmp = t_2;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_, a_] := Block[{t$95$1 = N[(N[(z * 9.0), $MachinePrecision] * t), $MachinePrecision]}, Block[{t$95$2 = N[(N[(N[(a * 2.0), $MachinePrecision] - t$95$1), $MachinePrecision] / N[(a * 2.0), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$1, -1e+64], t$95$2, If[LessEqual[t$95$1, 2e+34], N[(N[(x * y), $MachinePrecision] / N[(a * 2.0), $MachinePrecision]), $MachinePrecision], t$95$2]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := \left(z \cdot 9\right) \cdot t\\
t_2 := \frac{a \cdot 2 - t\_1}{a \cdot 2}\\
\mathbf{if}\;t\_1 \leq -1 \cdot 10^{+64}:\\
\;\;\;\;t\_2\\

\mathbf{elif}\;t\_1 \leq 2 \cdot 10^{+34}:\\
\;\;\;\;\frac{x \cdot y}{a \cdot 2}\\

\mathbf{else}:\\
\;\;\;\;t\_2\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (*.f64 (*.f64 z #s(literal 9 binary64)) t) < -1.00000000000000002e64 or 1.99999999999999989e34 < (*.f64 (*.f64 z #s(literal 9 binary64)) t)

    1. Initial program 88.3%

      \[\frac{x \cdot y - \left(z \cdot 9\right) \cdot t}{a \cdot 2} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \frac{\color{blue}{x \cdot y} - \left(z \cdot 9\right) \cdot t}{a \cdot 2} \]
    4. Applied rewrites62.5%

      \[\leadsto \frac{\color{blue}{a \cdot 2} - \left(z \cdot 9\right) \cdot t}{a \cdot 2} \]

    if -1.00000000000000002e64 < (*.f64 (*.f64 z #s(literal 9 binary64)) t) < 1.99999999999999989e34

    1. Initial program 97.4%

      \[\frac{x \cdot y - \left(z \cdot 9\right) \cdot t}{a \cdot 2} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \frac{\color{blue}{-9 \cdot \left(t \cdot z\right)}}{a \cdot 2} \]
    4. Applied rewrites78.0%

      \[\leadsto \frac{\color{blue}{x \cdot y}}{a \cdot 2} \]
  3. Recombined 2 regimes into one program.
  4. Add Preprocessing

Alternative 3: 53.1% accurate, 0.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := \left(z \cdot 9\right) \cdot t\\ \mathbf{if}\;t\_1 \leq -1 \cdot 10^{+293}:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;t\_1 \leq 2 \cdot 10^{+303}:\\ \;\;\;\;\frac{x \cdot y}{a \cdot 2}\\ \mathbf{else}:\\ \;\;\;\;a \cdot 2 - t\_1\\ \end{array} \end{array} \]
(FPCore (x y z t a)
 :precision binary64
 (let* ((t_1 (* (* z 9.0) t)))
   (if (<= t_1 -1e+293)
     t_1
     (if (<= t_1 2e+303) (/ (* x y) (* a 2.0)) (- (* a 2.0) t_1)))))
double code(double x, double y, double z, double t, double a) {
	double t_1 = (z * 9.0) * t;
	double tmp;
	if (t_1 <= -1e+293) {
		tmp = t_1;
	} else if (t_1 <= 2e+303) {
		tmp = (x * y) / (a * 2.0);
	} else {
		tmp = (a * 2.0) - t_1;
	}
	return tmp;
}
real(8) function code(x, y, z, t, a)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    real(8) :: t_1
    real(8) :: tmp
    t_1 = (z * 9.0d0) * t
    if (t_1 <= (-1d+293)) then
        tmp = t_1
    else if (t_1 <= 2d+303) then
        tmp = (x * y) / (a * 2.0d0)
    else
        tmp = (a * 2.0d0) - t_1
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t, double a) {
	double t_1 = (z * 9.0) * t;
	double tmp;
	if (t_1 <= -1e+293) {
		tmp = t_1;
	} else if (t_1 <= 2e+303) {
		tmp = (x * y) / (a * 2.0);
	} else {
		tmp = (a * 2.0) - t_1;
	}
	return tmp;
}
def code(x, y, z, t, a):
	t_1 = (z * 9.0) * t
	tmp = 0
	if t_1 <= -1e+293:
		tmp = t_1
	elif t_1 <= 2e+303:
		tmp = (x * y) / (a * 2.0)
	else:
		tmp = (a * 2.0) - t_1
	return tmp
function code(x, y, z, t, a)
	t_1 = Float64(Float64(z * 9.0) * t)
	tmp = 0.0
	if (t_1 <= -1e+293)
		tmp = t_1;
	elseif (t_1 <= 2e+303)
		tmp = Float64(Float64(x * y) / Float64(a * 2.0));
	else
		tmp = Float64(Float64(a * 2.0) - t_1);
	end
	return tmp
end
function tmp_2 = code(x, y, z, t, a)
	t_1 = (z * 9.0) * t;
	tmp = 0.0;
	if (t_1 <= -1e+293)
		tmp = t_1;
	elseif (t_1 <= 2e+303)
		tmp = (x * y) / (a * 2.0);
	else
		tmp = (a * 2.0) - t_1;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_, a_] := Block[{t$95$1 = N[(N[(z * 9.0), $MachinePrecision] * t), $MachinePrecision]}, If[LessEqual[t$95$1, -1e+293], t$95$1, If[LessEqual[t$95$1, 2e+303], N[(N[(x * y), $MachinePrecision] / N[(a * 2.0), $MachinePrecision]), $MachinePrecision], N[(N[(a * 2.0), $MachinePrecision] - t$95$1), $MachinePrecision]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := \left(z \cdot 9\right) \cdot t\\
\mathbf{if}\;t\_1 \leq -1 \cdot 10^{+293}:\\
\;\;\;\;t\_1\\

\mathbf{elif}\;t\_1 \leq 2 \cdot 10^{+303}:\\
\;\;\;\;\frac{x \cdot y}{a \cdot 2}\\

\mathbf{else}:\\
\;\;\;\;a \cdot 2 - t\_1\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (*.f64 (*.f64 z #s(literal 9 binary64)) t) < -9.9999999999999992e292

    1. Initial program 72.5%

      \[\frac{x \cdot y - \left(z \cdot 9\right) \cdot t}{a \cdot 2} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \color{blue}{\frac{-9}{2} \cdot \frac{t \cdot z}{a} + \frac{1}{2} \cdot \frac{x \cdot y}{a}} \]
    4. Applied rewrites25.6%

      \[\leadsto \color{blue}{x \cdot y - \left(z \cdot 9\right) \cdot t} \]
    5. Taylor expanded in x around 0

      \[\leadsto x \cdot y - \color{blue}{9 \cdot \left(t \cdot z\right)} \]
    6. Applied rewrites34.4%

      \[\leadsto \left(z \cdot 9\right) \cdot \color{blue}{t} \]

    if -9.9999999999999992e292 < (*.f64 (*.f64 z #s(literal 9 binary64)) t) < 2e303

    1. Initial program 96.2%

      \[\frac{x \cdot y - \left(z \cdot 9\right) \cdot t}{a \cdot 2} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \frac{\color{blue}{-9 \cdot \left(t \cdot z\right)}}{a \cdot 2} \]
    4. Applied rewrites58.3%

      \[\leadsto \frac{\color{blue}{x \cdot y}}{a \cdot 2} \]

    if 2e303 < (*.f64 (*.f64 z #s(literal 9 binary64)) t)

    1. Initial program 74.7%

      \[\frac{x \cdot y - \left(z \cdot 9\right) \cdot t}{a \cdot 2} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \color{blue}{\frac{-9}{2} \cdot \frac{t \cdot z}{a} + \frac{1}{2} \cdot \frac{x \cdot y}{a}} \]
    4. Applied rewrites46.7%

      \[\leadsto \color{blue}{x \cdot y - \left(z \cdot 9\right) \cdot t} \]
    5. Taylor expanded in y around inf

      \[\leadsto y \cdot \color{blue}{\left(x + -9 \cdot \frac{t \cdot z}{y}\right)} \]
    6. Applied rewrites46.7%

      \[\leadsto a \cdot 2 - \color{blue}{\left(z \cdot 9\right) \cdot t} \]
  3. Recombined 3 regimes into one program.
  4. Add Preprocessing

Alternative 4: 17.1% accurate, 1.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := \left(z \cdot 9\right) \cdot t\\ \mathbf{if}\;a \cdot 2 \leq -5 \cdot 10^{-311}:\\ \;\;\;\;t\_1\\ \mathbf{else}:\\ \;\;\;\;x \cdot y - t\_1\\ \end{array} \end{array} \]
(FPCore (x y z t a)
 :precision binary64
 (let* ((t_1 (* (* z 9.0) t)))
   (if (<= (* a 2.0) -5e-311) t_1 (- (* x y) t_1))))
double code(double x, double y, double z, double t, double a) {
	double t_1 = (z * 9.0) * t;
	double tmp;
	if ((a * 2.0) <= -5e-311) {
		tmp = t_1;
	} else {
		tmp = (x * y) - t_1;
	}
	return tmp;
}
real(8) function code(x, y, z, t, a)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    real(8) :: t_1
    real(8) :: tmp
    t_1 = (z * 9.0d0) * t
    if ((a * 2.0d0) <= (-5d-311)) then
        tmp = t_1
    else
        tmp = (x * y) - t_1
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t, double a) {
	double t_1 = (z * 9.0) * t;
	double tmp;
	if ((a * 2.0) <= -5e-311) {
		tmp = t_1;
	} else {
		tmp = (x * y) - t_1;
	}
	return tmp;
}
def code(x, y, z, t, a):
	t_1 = (z * 9.0) * t
	tmp = 0
	if (a * 2.0) <= -5e-311:
		tmp = t_1
	else:
		tmp = (x * y) - t_1
	return tmp
function code(x, y, z, t, a)
	t_1 = Float64(Float64(z * 9.0) * t)
	tmp = 0.0
	if (Float64(a * 2.0) <= -5e-311)
		tmp = t_1;
	else
		tmp = Float64(Float64(x * y) - t_1);
	end
	return tmp
end
function tmp_2 = code(x, y, z, t, a)
	t_1 = (z * 9.0) * t;
	tmp = 0.0;
	if ((a * 2.0) <= -5e-311)
		tmp = t_1;
	else
		tmp = (x * y) - t_1;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_, a_] := Block[{t$95$1 = N[(N[(z * 9.0), $MachinePrecision] * t), $MachinePrecision]}, If[LessEqual[N[(a * 2.0), $MachinePrecision], -5e-311], t$95$1, N[(N[(x * y), $MachinePrecision] - t$95$1), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := \left(z \cdot 9\right) \cdot t\\
\mathbf{if}\;a \cdot 2 \leq -5 \cdot 10^{-311}:\\
\;\;\;\;t\_1\\

\mathbf{else}:\\
\;\;\;\;x \cdot y - t\_1\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (*.f64 a #s(literal 2 binary64)) < -5.00000000000023e-311

    1. Initial program 89.4%

      \[\frac{x \cdot y - \left(z \cdot 9\right) \cdot t}{a \cdot 2} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \color{blue}{\frac{-9}{2} \cdot \frac{t \cdot z}{a} + \frac{1}{2} \cdot \frac{x \cdot y}{a}} \]
    4. Applied rewrites2.0%

      \[\leadsto \color{blue}{x \cdot y - \left(z \cdot 9\right) \cdot t} \]
    5. Taylor expanded in x around 0

      \[\leadsto x \cdot y - \color{blue}{9 \cdot \left(t \cdot z\right)} \]
    6. Applied rewrites16.4%

      \[\leadsto \left(z \cdot 9\right) \cdot \color{blue}{t} \]

    if -5.00000000000023e-311 < (*.f64 a #s(literal 2 binary64))

    1. Initial program 95.7%

      \[\frac{x \cdot y - \left(z \cdot 9\right) \cdot t}{a \cdot 2} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \color{blue}{\frac{-9}{2} \cdot \frac{t \cdot z}{a} + \frac{1}{2} \cdot \frac{x \cdot y}{a}} \]
    4. Applied rewrites22.0%

      \[\leadsto \color{blue}{x \cdot y - \left(z \cdot 9\right) \cdot t} \]
  3. Recombined 2 regimes into one program.
  4. Add Preprocessing

Alternative 5: 13.6% accurate, 1.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;a \cdot 2 \leq -5 \cdot 10^{-311}:\\ \;\;\;\;\left(z \cdot 9\right) \cdot t\\ \mathbf{else}:\\ \;\;\;\;x \cdot y\\ \end{array} \end{array} \]
(FPCore (x y z t a)
 :precision binary64
 (if (<= (* a 2.0) -5e-311) (* (* z 9.0) t) (* x y)))
double code(double x, double y, double z, double t, double a) {
	double tmp;
	if ((a * 2.0) <= -5e-311) {
		tmp = (z * 9.0) * t;
	} else {
		tmp = x * y;
	}
	return tmp;
}
real(8) function code(x, y, z, t, a)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    real(8) :: tmp
    if ((a * 2.0d0) <= (-5d-311)) then
        tmp = (z * 9.0d0) * t
    else
        tmp = x * y
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t, double a) {
	double tmp;
	if ((a * 2.0) <= -5e-311) {
		tmp = (z * 9.0) * t;
	} else {
		tmp = x * y;
	}
	return tmp;
}
def code(x, y, z, t, a):
	tmp = 0
	if (a * 2.0) <= -5e-311:
		tmp = (z * 9.0) * t
	else:
		tmp = x * y
	return tmp
function code(x, y, z, t, a)
	tmp = 0.0
	if (Float64(a * 2.0) <= -5e-311)
		tmp = Float64(Float64(z * 9.0) * t);
	else
		tmp = Float64(x * y);
	end
	return tmp
end
function tmp_2 = code(x, y, z, t, a)
	tmp = 0.0;
	if ((a * 2.0) <= -5e-311)
		tmp = (z * 9.0) * t;
	else
		tmp = x * y;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_, a_] := If[LessEqual[N[(a * 2.0), $MachinePrecision], -5e-311], N[(N[(z * 9.0), $MachinePrecision] * t), $MachinePrecision], N[(x * y), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;a \cdot 2 \leq -5 \cdot 10^{-311}:\\
\;\;\;\;\left(z \cdot 9\right) \cdot t\\

\mathbf{else}:\\
\;\;\;\;x \cdot y\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (*.f64 a #s(literal 2 binary64)) < -5.00000000000023e-311

    1. Initial program 89.4%

      \[\frac{x \cdot y - \left(z \cdot 9\right) \cdot t}{a \cdot 2} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \color{blue}{\frac{-9}{2} \cdot \frac{t \cdot z}{a} + \frac{1}{2} \cdot \frac{x \cdot y}{a}} \]
    4. Applied rewrites2.0%

      \[\leadsto \color{blue}{x \cdot y - \left(z \cdot 9\right) \cdot t} \]
    5. Taylor expanded in x around 0

      \[\leadsto x \cdot y - \color{blue}{9 \cdot \left(t \cdot z\right)} \]
    6. Applied rewrites16.4%

      \[\leadsto \left(z \cdot 9\right) \cdot \color{blue}{t} \]

    if -5.00000000000023e-311 < (*.f64 a #s(literal 2 binary64))

    1. Initial program 95.7%

      \[\frac{x \cdot y - \left(z \cdot 9\right) \cdot t}{a \cdot 2} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \color{blue}{\frac{-9}{2} \cdot \frac{t \cdot z}{a} + \frac{1}{2} \cdot \frac{x \cdot y}{a}} \]
    4. Applied rewrites22.0%

      \[\leadsto \color{blue}{x \cdot y - \left(z \cdot 9\right) \cdot t} \]
    5. Taylor expanded in x around 0

      \[\leadsto -9 \cdot \color{blue}{\left(t \cdot z\right)} \]
    6. Applied rewrites16.2%

      \[\leadsto x \cdot \color{blue}{y} \]
  3. Recombined 2 regimes into one program.
  4. Add Preprocessing

Alternative 6: 9.0% accurate, 5.8× speedup?

\[\begin{array}{l} \\ x \cdot y \end{array} \]
(FPCore (x y z t a) :precision binary64 (* x y))
double code(double x, double y, double z, double t, double a) {
	return x * y;
}
real(8) function code(x, y, z, t, a)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    code = x * y
end function
public static double code(double x, double y, double z, double t, double a) {
	return x * y;
}
def code(x, y, z, t, a):
	return x * y
function code(x, y, z, t, a)
	return Float64(x * y)
end
function tmp = code(x, y, z, t, a)
	tmp = x * y;
end
code[x_, y_, z_, t_, a_] := N[(x * y), $MachinePrecision]
\begin{array}{l}

\\
x \cdot y
\end{array}
Derivation
  1. Initial program 93.0%

    \[\frac{x \cdot y - \left(z \cdot 9\right) \cdot t}{a \cdot 2} \]
  2. Add Preprocessing
  3. Taylor expanded in x around 0

    \[\leadsto \color{blue}{\frac{-9}{2} \cdot \frac{t \cdot z}{a} + \frac{1}{2} \cdot \frac{x \cdot y}{a}} \]
  4. Applied rewrites13.3%

    \[\leadsto \color{blue}{x \cdot y - \left(z \cdot 9\right) \cdot t} \]
  5. Taylor expanded in x around 0

    \[\leadsto -9 \cdot \color{blue}{\left(t \cdot z\right)} \]
  6. Applied rewrites11.9%

    \[\leadsto x \cdot \color{blue}{y} \]
  7. Add Preprocessing

Developer Target 1: 93.8% accurate, 0.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;a < -2.090464557976709 \cdot 10^{+86}:\\ \;\;\;\;0.5 \cdot \frac{y \cdot x}{a} - 4.5 \cdot \frac{t}{\frac{a}{z}}\\ \mathbf{elif}\;a < 2.144030707833976 \cdot 10^{+99}:\\ \;\;\;\;\frac{x \cdot y - z \cdot \left(9 \cdot t\right)}{a \cdot 2}\\ \mathbf{else}:\\ \;\;\;\;\frac{y}{a} \cdot \left(x \cdot 0.5\right) - \frac{t}{a} \cdot \left(z \cdot 4.5\right)\\ \end{array} \end{array} \]
(FPCore (x y z t a)
 :precision binary64
 (if (< a -2.090464557976709e+86)
   (- (* 0.5 (/ (* y x) a)) (* 4.5 (/ t (/ a z))))
   (if (< a 2.144030707833976e+99)
     (/ (- (* x y) (* z (* 9.0 t))) (* a 2.0))
     (- (* (/ y a) (* x 0.5)) (* (/ t a) (* z 4.5))))))
double code(double x, double y, double z, double t, double a) {
	double tmp;
	if (a < -2.090464557976709e+86) {
		tmp = (0.5 * ((y * x) / a)) - (4.5 * (t / (a / z)));
	} else if (a < 2.144030707833976e+99) {
		tmp = ((x * y) - (z * (9.0 * t))) / (a * 2.0);
	} else {
		tmp = ((y / a) * (x * 0.5)) - ((t / a) * (z * 4.5));
	}
	return tmp;
}
real(8) function code(x, y, z, t, a)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    real(8) :: tmp
    if (a < (-2.090464557976709d+86)) then
        tmp = (0.5d0 * ((y * x) / a)) - (4.5d0 * (t / (a / z)))
    else if (a < 2.144030707833976d+99) then
        tmp = ((x * y) - (z * (9.0d0 * t))) / (a * 2.0d0)
    else
        tmp = ((y / a) * (x * 0.5d0)) - ((t / a) * (z * 4.5d0))
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t, double a) {
	double tmp;
	if (a < -2.090464557976709e+86) {
		tmp = (0.5 * ((y * x) / a)) - (4.5 * (t / (a / z)));
	} else if (a < 2.144030707833976e+99) {
		tmp = ((x * y) - (z * (9.0 * t))) / (a * 2.0);
	} else {
		tmp = ((y / a) * (x * 0.5)) - ((t / a) * (z * 4.5));
	}
	return tmp;
}
def code(x, y, z, t, a):
	tmp = 0
	if a < -2.090464557976709e+86:
		tmp = (0.5 * ((y * x) / a)) - (4.5 * (t / (a / z)))
	elif a < 2.144030707833976e+99:
		tmp = ((x * y) - (z * (9.0 * t))) / (a * 2.0)
	else:
		tmp = ((y / a) * (x * 0.5)) - ((t / a) * (z * 4.5))
	return tmp
function code(x, y, z, t, a)
	tmp = 0.0
	if (a < -2.090464557976709e+86)
		tmp = Float64(Float64(0.5 * Float64(Float64(y * x) / a)) - Float64(4.5 * Float64(t / Float64(a / z))));
	elseif (a < 2.144030707833976e+99)
		tmp = Float64(Float64(Float64(x * y) - Float64(z * Float64(9.0 * t))) / Float64(a * 2.0));
	else
		tmp = Float64(Float64(Float64(y / a) * Float64(x * 0.5)) - Float64(Float64(t / a) * Float64(z * 4.5)));
	end
	return tmp
end
function tmp_2 = code(x, y, z, t, a)
	tmp = 0.0;
	if (a < -2.090464557976709e+86)
		tmp = (0.5 * ((y * x) / a)) - (4.5 * (t / (a / z)));
	elseif (a < 2.144030707833976e+99)
		tmp = ((x * y) - (z * (9.0 * t))) / (a * 2.0);
	else
		tmp = ((y / a) * (x * 0.5)) - ((t / a) * (z * 4.5));
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_, a_] := If[Less[a, -2.090464557976709e+86], N[(N[(0.5 * N[(N[(y * x), $MachinePrecision] / a), $MachinePrecision]), $MachinePrecision] - N[(4.5 * N[(t / N[(a / z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[Less[a, 2.144030707833976e+99], N[(N[(N[(x * y), $MachinePrecision] - N[(z * N[(9.0 * t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(a * 2.0), $MachinePrecision]), $MachinePrecision], N[(N[(N[(y / a), $MachinePrecision] * N[(x * 0.5), $MachinePrecision]), $MachinePrecision] - N[(N[(t / a), $MachinePrecision] * N[(z * 4.5), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;a < -2.090464557976709 \cdot 10^{+86}:\\
\;\;\;\;0.5 \cdot \frac{y \cdot x}{a} - 4.5 \cdot \frac{t}{\frac{a}{z}}\\

\mathbf{elif}\;a < 2.144030707833976 \cdot 10^{+99}:\\
\;\;\;\;\frac{x \cdot y - z \cdot \left(9 \cdot t\right)}{a \cdot 2}\\

\mathbf{else}:\\
\;\;\;\;\frac{y}{a} \cdot \left(x \cdot 0.5\right) - \frac{t}{a} \cdot \left(z \cdot 4.5\right)\\


\end{array}
\end{array}

Reproduce

?
herbie shell --seed 2024321 
(FPCore (x y z t a)
  :name "Diagrams.Solve.Polynomial:cubForm  from diagrams-solve-0.1, I"
  :precision binary64
  :pre (TRUE)

  :alt
  (! :herbie-platform default (if (< a -209046455797670900000000000000000000000000000000000000000000000000000000000000000000000) (- (* 1/2 (/ (* y x) a)) (* 9/2 (/ t (/ a z)))) (if (< a 2144030707833976000000000000000000000000000000000000000000000000000000000000000000000000000000000000) (/ (- (* x y) (* z (* 9 t))) (* a 2)) (- (* (/ y a) (* x 1/2)) (* (/ t a) (* z 9/2))))))

  (/ (- (* x y) (* (* z 9.0) t)) (* a 2.0)))