2tan (problem 3.3.2)

Percentage Accurate: 62.5% → 99.7%
Time: 13.6s
Alternatives: 7
Speedup: 34.5×

Specification

?
\[\left(\left(-10000 \leq x \land x \leq 10000\right) \land 10^{-16} \cdot \left|x\right| < \varepsilon\right) \land \varepsilon < \left|x\right|\]
\[\begin{array}{l} \\ \tan \left(x + \varepsilon\right) - \tan x \end{array} \]
(FPCore (x eps) :precision binary64 (- (tan (+ x eps)) (tan x)))
double code(double x, double eps) {
	return tan((x + eps)) - tan(x);
}
real(8) function code(x, eps)
    real(8), intent (in) :: x
    real(8), intent (in) :: eps
    code = tan((x + eps)) - tan(x)
end function
public static double code(double x, double eps) {
	return Math.tan((x + eps)) - Math.tan(x);
}
def code(x, eps):
	return math.tan((x + eps)) - math.tan(x)
function code(x, eps)
	return Float64(tan(Float64(x + eps)) - tan(x))
end
function tmp = code(x, eps)
	tmp = tan((x + eps)) - tan(x);
end
code[x_, eps_] := N[(N[Tan[N[(x + eps), $MachinePrecision]], $MachinePrecision] - N[Tan[x], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\tan \left(x + \varepsilon\right) - \tan x
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 7 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 62.5% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \tan \left(x + \varepsilon\right) - \tan x \end{array} \]
(FPCore (x eps) :precision binary64 (- (tan (+ x eps)) (tan x)))
double code(double x, double eps) {
	return tan((x + eps)) - tan(x);
}
real(8) function code(x, eps)
    real(8), intent (in) :: x
    real(8), intent (in) :: eps
    code = tan((x + eps)) - tan(x)
end function
public static double code(double x, double eps) {
	return Math.tan((x + eps)) - Math.tan(x);
}
def code(x, eps):
	return math.tan((x + eps)) - math.tan(x)
function code(x, eps)
	return Float64(tan(Float64(x + eps)) - tan(x))
end
function tmp = code(x, eps)
	tmp = tan((x + eps)) - tan(x);
end
code[x_, eps_] := N[(N[Tan[N[(x + eps), $MachinePrecision]], $MachinePrecision] - N[Tan[x], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\tan \left(x + \varepsilon\right) - \tan x
\end{array}

Alternative 1: 99.7% accurate, 0.9× speedup?

\[\begin{array}{l} \\ \frac{\mathsf{fma}\left(-0.16666666666666666, \varepsilon \cdot \varepsilon, 1\right) \cdot \varepsilon}{\cos \left(\varepsilon + x\right) \cdot \cos x} \end{array} \]
(FPCore (x eps)
 :precision binary64
 (/
  (* (fma -0.16666666666666666 (* eps eps) 1.0) eps)
  (* (cos (+ eps x)) (cos x))))
double code(double x, double eps) {
	return (fma(-0.16666666666666666, (eps * eps), 1.0) * eps) / (cos((eps + x)) * cos(x));
}
function code(x, eps)
	return Float64(Float64(fma(-0.16666666666666666, Float64(eps * eps), 1.0) * eps) / Float64(cos(Float64(eps + x)) * cos(x)))
end
code[x_, eps_] := N[(N[(N[(-0.16666666666666666 * N[(eps * eps), $MachinePrecision] + 1.0), $MachinePrecision] * eps), $MachinePrecision] / N[(N[Cos[N[(eps + x), $MachinePrecision]], $MachinePrecision] * N[Cos[x], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{\mathsf{fma}\left(-0.16666666666666666, \varepsilon \cdot \varepsilon, 1\right) \cdot \varepsilon}{\cos \left(\varepsilon + x\right) \cdot \cos x}
\end{array}
Derivation
  1. Initial program 62.2%

    \[\tan \left(x + \varepsilon\right) - \tan x \]
  2. Add Preprocessing
  3. Step-by-step derivation
    1. lift--.f64N/A

      \[\leadsto \color{blue}{\tan \left(x + \varepsilon\right) - \tan x} \]
    2. lift-tan.f64N/A

      \[\leadsto \color{blue}{\tan \left(x + \varepsilon\right)} - \tan x \]
    3. tan-quotN/A

      \[\leadsto \color{blue}{\frac{\sin \left(x + \varepsilon\right)}{\cos \left(x + \varepsilon\right)}} - \tan x \]
    4. lift-tan.f64N/A

      \[\leadsto \frac{\sin \left(x + \varepsilon\right)}{\cos \left(x + \varepsilon\right)} - \color{blue}{\tan x} \]
    5. tan-quotN/A

      \[\leadsto \frac{\sin \left(x + \varepsilon\right)}{\cos \left(x + \varepsilon\right)} - \color{blue}{\frac{\sin x}{\cos x}} \]
    6. frac-subN/A

      \[\leadsto \color{blue}{\frac{\sin \left(x + \varepsilon\right) \cdot \cos x - \cos \left(x + \varepsilon\right) \cdot \sin x}{\cos \left(x + \varepsilon\right) \cdot \cos x}} \]
    7. lower-/.f64N/A

      \[\leadsto \color{blue}{\frac{\sin \left(x + \varepsilon\right) \cdot \cos x - \cos \left(x + \varepsilon\right) \cdot \sin x}{\cos \left(x + \varepsilon\right) \cdot \cos x}} \]
    8. sin-diff-revN/A

      \[\leadsto \frac{\color{blue}{\sin \left(\left(x + \varepsilon\right) - x\right)}}{\cos \left(x + \varepsilon\right) \cdot \cos x} \]
    9. lower-sin.f64N/A

      \[\leadsto \frac{\color{blue}{\sin \left(\left(x + \varepsilon\right) - x\right)}}{\cos \left(x + \varepsilon\right) \cdot \cos x} \]
    10. lower--.f64N/A

      \[\leadsto \frac{\sin \color{blue}{\left(\left(x + \varepsilon\right) - x\right)}}{\cos \left(x + \varepsilon\right) \cdot \cos x} \]
    11. lift-+.f64N/A

      \[\leadsto \frac{\sin \left(\color{blue}{\left(x + \varepsilon\right)} - x\right)}{\cos \left(x + \varepsilon\right) \cdot \cos x} \]
    12. +-commutativeN/A

      \[\leadsto \frac{\sin \left(\color{blue}{\left(\varepsilon + x\right)} - x\right)}{\cos \left(x + \varepsilon\right) \cdot \cos x} \]
    13. lower-+.f64N/A

      \[\leadsto \frac{\sin \left(\color{blue}{\left(\varepsilon + x\right)} - x\right)}{\cos \left(x + \varepsilon\right) \cdot \cos x} \]
    14. lower-*.f64N/A

      \[\leadsto \frac{\sin \left(\left(\varepsilon + x\right) - x\right)}{\color{blue}{\cos \left(x + \varepsilon\right) \cdot \cos x}} \]
    15. lower-cos.f64N/A

      \[\leadsto \frac{\sin \left(\left(\varepsilon + x\right) - x\right)}{\color{blue}{\cos \left(x + \varepsilon\right)} \cdot \cos x} \]
    16. lift-+.f64N/A

      \[\leadsto \frac{\sin \left(\left(\varepsilon + x\right) - x\right)}{\cos \color{blue}{\left(x + \varepsilon\right)} \cdot \cos x} \]
    17. +-commutativeN/A

      \[\leadsto \frac{\sin \left(\left(\varepsilon + x\right) - x\right)}{\cos \color{blue}{\left(\varepsilon + x\right)} \cdot \cos x} \]
    18. lower-+.f64N/A

      \[\leadsto \frac{\sin \left(\left(\varepsilon + x\right) - x\right)}{\cos \color{blue}{\left(\varepsilon + x\right)} \cdot \cos x} \]
    19. lower-cos.f6462.2

      \[\leadsto \frac{\sin \left(\left(\varepsilon + x\right) - x\right)}{\cos \left(\varepsilon + x\right) \cdot \color{blue}{\cos x}} \]
  4. Applied rewrites62.2%

    \[\leadsto \color{blue}{\frac{\sin \left(\left(\varepsilon + x\right) - x\right)}{\cos \left(\varepsilon + x\right) \cdot \cos x}} \]
  5. Taylor expanded in eps around 0

    \[\leadsto \frac{\color{blue}{\varepsilon \cdot \left(1 + \frac{-1}{6} \cdot {\varepsilon}^{2}\right)}}{\cos \left(\varepsilon + x\right) \cdot \cos x} \]
  6. Step-by-step derivation
    1. *-commutativeN/A

      \[\leadsto \frac{\color{blue}{\left(1 + \frac{-1}{6} \cdot {\varepsilon}^{2}\right) \cdot \varepsilon}}{\cos \left(\varepsilon + x\right) \cdot \cos x} \]
    2. lower-*.f64N/A

      \[\leadsto \frac{\color{blue}{\left(1 + \frac{-1}{6} \cdot {\varepsilon}^{2}\right) \cdot \varepsilon}}{\cos \left(\varepsilon + x\right) \cdot \cos x} \]
    3. +-commutativeN/A

      \[\leadsto \frac{\color{blue}{\left(\frac{-1}{6} \cdot {\varepsilon}^{2} + 1\right)} \cdot \varepsilon}{\cos \left(\varepsilon + x\right) \cdot \cos x} \]
    4. lower-fma.f64N/A

      \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(\frac{-1}{6}, {\varepsilon}^{2}, 1\right)} \cdot \varepsilon}{\cos \left(\varepsilon + x\right) \cdot \cos x} \]
    5. unpow2N/A

      \[\leadsto \frac{\mathsf{fma}\left(\frac{-1}{6}, \color{blue}{\varepsilon \cdot \varepsilon}, 1\right) \cdot \varepsilon}{\cos \left(\varepsilon + x\right) \cdot \cos x} \]
    6. lower-*.f6499.7

      \[\leadsto \frac{\mathsf{fma}\left(-0.16666666666666666, \color{blue}{\varepsilon \cdot \varepsilon}, 1\right) \cdot \varepsilon}{\cos \left(\varepsilon + x\right) \cdot \cos x} \]
  7. Applied rewrites99.7%

    \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(-0.16666666666666666, \varepsilon \cdot \varepsilon, 1\right) \cdot \varepsilon}}{\cos \left(\varepsilon + x\right) \cdot \cos x} \]
  8. Add Preprocessing

Alternative 2: 99.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \left({\tan x}^{2} + 1\right) \cdot \varepsilon \end{array} \]
(FPCore (x eps) :precision binary64 (* (+ (pow (tan x) 2.0) 1.0) eps))
double code(double x, double eps) {
	return (pow(tan(x), 2.0) + 1.0) * eps;
}
real(8) function code(x, eps)
    real(8), intent (in) :: x
    real(8), intent (in) :: eps
    code = ((tan(x) ** 2.0d0) + 1.0d0) * eps
end function
public static double code(double x, double eps) {
	return (Math.pow(Math.tan(x), 2.0) + 1.0) * eps;
}
def code(x, eps):
	return (math.pow(math.tan(x), 2.0) + 1.0) * eps
function code(x, eps)
	return Float64(Float64((tan(x) ^ 2.0) + 1.0) * eps)
end
function tmp = code(x, eps)
	tmp = ((tan(x) ^ 2.0) + 1.0) * eps;
end
code[x_, eps_] := N[(N[(N[Power[N[Tan[x], $MachinePrecision], 2.0], $MachinePrecision] + 1.0), $MachinePrecision] * eps), $MachinePrecision]
\begin{array}{l}

\\
\left({\tan x}^{2} + 1\right) \cdot \varepsilon
\end{array}
Derivation
  1. Initial program 62.2%

    \[\tan \left(x + \varepsilon\right) - \tan x \]
  2. Add Preprocessing
  3. Taylor expanded in eps around 0

    \[\leadsto \color{blue}{\varepsilon \cdot \left(\left(1 + \varepsilon \cdot \left(\varepsilon \cdot \left(-1 \cdot \left(\varepsilon \cdot \left(\frac{-1}{2} \cdot \frac{\sin x \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{\cos x} + \left(\frac{1}{6} \cdot \frac{\sin x \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{\cos x} + \frac{\sin x \cdot \left(\frac{1}{6} + \left(-1 \cdot \frac{{\sin x}^{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{{\cos x}^{2}} + \left(\frac{-1}{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right) + \frac{1}{6} \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)\right)\right)}{\cos x}\right)\right)\right) - \left(\frac{1}{6} + \left(-1 \cdot \frac{{\sin x}^{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{{\cos x}^{2}} + \left(\frac{-1}{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right) + \frac{1}{6} \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)\right)\right)\right) - -1 \cdot \frac{\sin x \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{\cos x}\right)\right) - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)} \]
  4. Applied rewrites99.6%

    \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\left(-1 \cdot \varepsilon\right) \cdot \frac{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1 \cdot {\sin x}^{2}}{{\cos x}^{2}}, -1, -1\right), {\sin x}^{2}, {\sin x}^{2} \cdot 0.16666666666666666\right)}{{\cos x}^{2}} + \left(\mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, -0.5, -0.5\right) + 0.16666666666666666\right), \sin x, \left(\mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, 1, 1\right) \cdot \sin x\right) \cdot -0.3333333333333333\right)}{\cos x} - \left(\frac{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1 \cdot {\sin x}^{2}}{{\cos x}^{2}}, -1, -1\right), {\sin x}^{2}, {\sin x}^{2} \cdot 0.16666666666666666\right)}{{\cos x}^{2}} + \left(\mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, -0.5, -0.5\right) + 0.16666666666666666\right)\right), \varepsilon, \left(\mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, 1, 1\right) \cdot \frac{\sin x}{\cos x}\right) \cdot 1\right), \varepsilon, \mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, 1, 1\right)\right) \cdot \varepsilon} \]
  5. Taylor expanded in eps around 0

    \[\leadsto \left(1 + \frac{{\sin x}^{2}}{{\cos x}^{2}}\right) \cdot \varepsilon \]
  6. Step-by-step derivation
    1. Applied rewrites99.2%

      \[\leadsto \left(\frac{{\sin x}^{2}}{{\cos x}^{2}} + 1\right) \cdot \varepsilon \]
    2. Step-by-step derivation
      1. Applied rewrites99.2%

        \[\leadsto \left({\tan x}^{2} + 1\right) \cdot \varepsilon \]
      2. Add Preprocessing

      Alternative 3: 98.4% accurate, 4.0× speedup?

      \[\begin{array}{l} \\ \left(\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.19682539682539682, x \cdot x, 0.37777777777777777\right), x \cdot x, 0.6666666666666666\right), x \cdot x, 1\right) \cdot \left(x \cdot x\right) + 1\right) \cdot \varepsilon \end{array} \]
      (FPCore (x eps)
       :precision binary64
       (*
        (+
         (*
          (fma
           (fma
            (fma 0.19682539682539682 (* x x) 0.37777777777777777)
            (* x x)
            0.6666666666666666)
           (* x x)
           1.0)
          (* x x))
         1.0)
        eps))
      double code(double x, double eps) {
      	return ((fma(fma(fma(0.19682539682539682, (x * x), 0.37777777777777777), (x * x), 0.6666666666666666), (x * x), 1.0) * (x * x)) + 1.0) * eps;
      }
      
      function code(x, eps)
      	return Float64(Float64(Float64(fma(fma(fma(0.19682539682539682, Float64(x * x), 0.37777777777777777), Float64(x * x), 0.6666666666666666), Float64(x * x), 1.0) * Float64(x * x)) + 1.0) * eps)
      end
      
      code[x_, eps_] := N[(N[(N[(N[(N[(N[(0.19682539682539682 * N[(x * x), $MachinePrecision] + 0.37777777777777777), $MachinePrecision] * N[(x * x), $MachinePrecision] + 0.6666666666666666), $MachinePrecision] * N[(x * x), $MachinePrecision] + 1.0), $MachinePrecision] * N[(x * x), $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision] * eps), $MachinePrecision]
      
      \begin{array}{l}
      
      \\
      \left(\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.19682539682539682, x \cdot x, 0.37777777777777777\right), x \cdot x, 0.6666666666666666\right), x \cdot x, 1\right) \cdot \left(x \cdot x\right) + 1\right) \cdot \varepsilon
      \end{array}
      
      Derivation
      1. Initial program 62.2%

        \[\tan \left(x + \varepsilon\right) - \tan x \]
      2. Add Preprocessing
      3. Taylor expanded in eps around 0

        \[\leadsto \color{blue}{\varepsilon \cdot \left(\left(1 + \varepsilon \cdot \left(\varepsilon \cdot \left(-1 \cdot \left(\varepsilon \cdot \left(\frac{-1}{2} \cdot \frac{\sin x \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{\cos x} + \left(\frac{1}{6} \cdot \frac{\sin x \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{\cos x} + \frac{\sin x \cdot \left(\frac{1}{6} + \left(-1 \cdot \frac{{\sin x}^{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{{\cos x}^{2}} + \left(\frac{-1}{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right) + \frac{1}{6} \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)\right)\right)}{\cos x}\right)\right)\right) - \left(\frac{1}{6} + \left(-1 \cdot \frac{{\sin x}^{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{{\cos x}^{2}} + \left(\frac{-1}{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right) + \frac{1}{6} \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)\right)\right)\right) - -1 \cdot \frac{\sin x \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{\cos x}\right)\right) - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)} \]
      4. Applied rewrites99.6%

        \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\left(-1 \cdot \varepsilon\right) \cdot \frac{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1 \cdot {\sin x}^{2}}{{\cos x}^{2}}, -1, -1\right), {\sin x}^{2}, {\sin x}^{2} \cdot 0.16666666666666666\right)}{{\cos x}^{2}} + \left(\mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, -0.5, -0.5\right) + 0.16666666666666666\right), \sin x, \left(\mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, 1, 1\right) \cdot \sin x\right) \cdot -0.3333333333333333\right)}{\cos x} - \left(\frac{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1 \cdot {\sin x}^{2}}{{\cos x}^{2}}, -1, -1\right), {\sin x}^{2}, {\sin x}^{2} \cdot 0.16666666666666666\right)}{{\cos x}^{2}} + \left(\mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, -0.5, -0.5\right) + 0.16666666666666666\right)\right), \varepsilon, \left(\mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, 1, 1\right) \cdot \frac{\sin x}{\cos x}\right) \cdot 1\right), \varepsilon, \mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, 1, 1\right)\right) \cdot \varepsilon} \]
      5. Taylor expanded in eps around 0

        \[\leadsto \left(1 + \frac{{\sin x}^{2}}{{\cos x}^{2}}\right) \cdot \varepsilon \]
      6. Step-by-step derivation
        1. Applied rewrites99.2%

          \[\leadsto \left(\frac{{\sin x}^{2}}{{\cos x}^{2}} + 1\right) \cdot \varepsilon \]
        2. Taylor expanded in x around 0

          \[\leadsto \left({x}^{2} \cdot \left(1 + {x}^{2} \cdot \left(\frac{2}{3} + {x}^{2} \cdot \left(\frac{17}{45} + \frac{62}{315} \cdot {x}^{2}\right)\right)\right) + 1\right) \cdot \varepsilon \]
        3. Step-by-step derivation
          1. Applied rewrites98.9%

            \[\leadsto \left(\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.19682539682539682, x \cdot x, 0.37777777777777777\right), x \cdot x, 0.6666666666666666\right), x \cdot x, 1\right) \cdot \left(x \cdot x\right) + 1\right) \cdot \varepsilon \]
          2. Add Preprocessing

          Alternative 4: 98.3% accurate, 5.3× speedup?

          \[\begin{array}{l} \\ \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.37777777777777777, x \cdot x, 0.6666666666666666\right), x \cdot x, 1\right), x \cdot x, 1\right) \cdot \varepsilon \end{array} \]
          (FPCore (x eps)
           :precision binary64
           (*
            (fma
             (fma (fma 0.37777777777777777 (* x x) 0.6666666666666666) (* x x) 1.0)
             (* x x)
             1.0)
            eps))
          double code(double x, double eps) {
          	return fma(fma(fma(0.37777777777777777, (x * x), 0.6666666666666666), (x * x), 1.0), (x * x), 1.0) * eps;
          }
          
          function code(x, eps)
          	return Float64(fma(fma(fma(0.37777777777777777, Float64(x * x), 0.6666666666666666), Float64(x * x), 1.0), Float64(x * x), 1.0) * eps)
          end
          
          code[x_, eps_] := N[(N[(N[(N[(0.37777777777777777 * N[(x * x), $MachinePrecision] + 0.6666666666666666), $MachinePrecision] * N[(x * x), $MachinePrecision] + 1.0), $MachinePrecision] * N[(x * x), $MachinePrecision] + 1.0), $MachinePrecision] * eps), $MachinePrecision]
          
          \begin{array}{l}
          
          \\
          \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.37777777777777777, x \cdot x, 0.6666666666666666\right), x \cdot x, 1\right), x \cdot x, 1\right) \cdot \varepsilon
          \end{array}
          
          Derivation
          1. Initial program 62.2%

            \[\tan \left(x + \varepsilon\right) - \tan x \]
          2. Add Preprocessing
          3. Taylor expanded in eps around 0

            \[\leadsto \color{blue}{\varepsilon \cdot \left(\left(1 + \varepsilon \cdot \left(\varepsilon \cdot \left(-1 \cdot \left(\varepsilon \cdot \left(\frac{-1}{2} \cdot \frac{\sin x \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{\cos x} + \left(\frac{1}{6} \cdot \frac{\sin x \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{\cos x} + \frac{\sin x \cdot \left(\frac{1}{6} + \left(-1 \cdot \frac{{\sin x}^{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{{\cos x}^{2}} + \left(\frac{-1}{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right) + \frac{1}{6} \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)\right)\right)}{\cos x}\right)\right)\right) - \left(\frac{1}{6} + \left(-1 \cdot \frac{{\sin x}^{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{{\cos x}^{2}} + \left(\frac{-1}{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right) + \frac{1}{6} \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)\right)\right)\right) - -1 \cdot \frac{\sin x \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{\cos x}\right)\right) - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)} \]
          4. Applied rewrites99.6%

            \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\left(-1 \cdot \varepsilon\right) \cdot \frac{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1 \cdot {\sin x}^{2}}{{\cos x}^{2}}, -1, -1\right), {\sin x}^{2}, {\sin x}^{2} \cdot 0.16666666666666666\right)}{{\cos x}^{2}} + \left(\mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, -0.5, -0.5\right) + 0.16666666666666666\right), \sin x, \left(\mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, 1, 1\right) \cdot \sin x\right) \cdot -0.3333333333333333\right)}{\cos x} - \left(\frac{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1 \cdot {\sin x}^{2}}{{\cos x}^{2}}, -1, -1\right), {\sin x}^{2}, {\sin x}^{2} \cdot 0.16666666666666666\right)}{{\cos x}^{2}} + \left(\mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, -0.5, -0.5\right) + 0.16666666666666666\right)\right), \varepsilon, \left(\mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, 1, 1\right) \cdot \frac{\sin x}{\cos x}\right) \cdot 1\right), \varepsilon, \mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, 1, 1\right)\right) \cdot \varepsilon} \]
          5. Taylor expanded in eps around 0

            \[\leadsto \left(1 + \frac{{\sin x}^{2}}{{\cos x}^{2}}\right) \cdot \varepsilon \]
          6. Step-by-step derivation
            1. Applied rewrites99.2%

              \[\leadsto \left(\frac{{\sin x}^{2}}{{\cos x}^{2}} + 1\right) \cdot \varepsilon \]
            2. Taylor expanded in x around 0

              \[\leadsto \left({x}^{2} + 1\right) \cdot \varepsilon \]
            3. Step-by-step derivation
              1. Applied rewrites98.5%

                \[\leadsto \left(x \cdot x + 1\right) \cdot \varepsilon \]
              2. Taylor expanded in x around 0

                \[\leadsto \left(1 + {x}^{2} \cdot \left(1 + {x}^{2} \cdot \left(\frac{2}{3} + \frac{17}{45} \cdot {x}^{2}\right)\right)\right) \cdot \varepsilon \]
              3. Step-by-step derivation
                1. Applied rewrites98.9%

                  \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.37777777777777777, x \cdot x, 0.6666666666666666\right), x \cdot x, 1\right), x \cdot x, 1\right) \cdot \varepsilon \]
                2. Add Preprocessing

                Alternative 5: 98.3% accurate, 7.4× speedup?

                \[\begin{array}{l} \\ \mathsf{fma}\left(\mathsf{fma}\left(0.6666666666666666, x \cdot x, 1\right), x \cdot x, 1\right) \cdot \varepsilon \end{array} \]
                (FPCore (x eps)
                 :precision binary64
                 (* (fma (fma 0.6666666666666666 (* x x) 1.0) (* x x) 1.0) eps))
                double code(double x, double eps) {
                	return fma(fma(0.6666666666666666, (x * x), 1.0), (x * x), 1.0) * eps;
                }
                
                function code(x, eps)
                	return Float64(fma(fma(0.6666666666666666, Float64(x * x), 1.0), Float64(x * x), 1.0) * eps)
                end
                
                code[x_, eps_] := N[(N[(N[(0.6666666666666666 * N[(x * x), $MachinePrecision] + 1.0), $MachinePrecision] * N[(x * x), $MachinePrecision] + 1.0), $MachinePrecision] * eps), $MachinePrecision]
                
                \begin{array}{l}
                
                \\
                \mathsf{fma}\left(\mathsf{fma}\left(0.6666666666666666, x \cdot x, 1\right), x \cdot x, 1\right) \cdot \varepsilon
                \end{array}
                
                Derivation
                1. Initial program 62.2%

                  \[\tan \left(x + \varepsilon\right) - \tan x \]
                2. Add Preprocessing
                3. Taylor expanded in eps around 0

                  \[\leadsto \color{blue}{\varepsilon \cdot \left(\left(1 + \varepsilon \cdot \left(\varepsilon \cdot \left(-1 \cdot \left(\varepsilon \cdot \left(\frac{-1}{2} \cdot \frac{\sin x \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{\cos x} + \left(\frac{1}{6} \cdot \frac{\sin x \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{\cos x} + \frac{\sin x \cdot \left(\frac{1}{6} + \left(-1 \cdot \frac{{\sin x}^{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{{\cos x}^{2}} + \left(\frac{-1}{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right) + \frac{1}{6} \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)\right)\right)}{\cos x}\right)\right)\right) - \left(\frac{1}{6} + \left(-1 \cdot \frac{{\sin x}^{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{{\cos x}^{2}} + \left(\frac{-1}{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right) + \frac{1}{6} \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)\right)\right)\right) - -1 \cdot \frac{\sin x \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{\cos x}\right)\right) - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)} \]
                4. Applied rewrites99.6%

                  \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\left(-1 \cdot \varepsilon\right) \cdot \frac{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1 \cdot {\sin x}^{2}}{{\cos x}^{2}}, -1, -1\right), {\sin x}^{2}, {\sin x}^{2} \cdot 0.16666666666666666\right)}{{\cos x}^{2}} + \left(\mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, -0.5, -0.5\right) + 0.16666666666666666\right), \sin x, \left(\mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, 1, 1\right) \cdot \sin x\right) \cdot -0.3333333333333333\right)}{\cos x} - \left(\frac{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1 \cdot {\sin x}^{2}}{{\cos x}^{2}}, -1, -1\right), {\sin x}^{2}, {\sin x}^{2} \cdot 0.16666666666666666\right)}{{\cos x}^{2}} + \left(\mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, -0.5, -0.5\right) + 0.16666666666666666\right)\right), \varepsilon, \left(\mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, 1, 1\right) \cdot \frac{\sin x}{\cos x}\right) \cdot 1\right), \varepsilon, \mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, 1, 1\right)\right) \cdot \varepsilon} \]
                5. Taylor expanded in eps around 0

                  \[\leadsto \left(1 + \frac{{\sin x}^{2}}{{\cos x}^{2}}\right) \cdot \varepsilon \]
                6. Step-by-step derivation
                  1. Applied rewrites99.2%

                    \[\leadsto \left(\frac{{\sin x}^{2}}{{\cos x}^{2}} + 1\right) \cdot \varepsilon \]
                  2. Taylor expanded in x around 0

                    \[\leadsto \left({x}^{2} + 1\right) \cdot \varepsilon \]
                  3. Step-by-step derivation
                    1. Applied rewrites98.5%

                      \[\leadsto \left(x \cdot x + 1\right) \cdot \varepsilon \]
                    2. Taylor expanded in x around 0

                      \[\leadsto \left(1 + {x}^{2} \cdot \left(1 + \frac{2}{3} \cdot {x}^{2}\right)\right) \cdot \varepsilon \]
                    3. Step-by-step derivation
                      1. Applied rewrites98.8%

                        \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(0.6666666666666666, x \cdot x, 1\right), x \cdot x, 1\right) \cdot \varepsilon \]
                      2. Add Preprocessing

                      Alternative 6: 98.2% accurate, 17.3× speedup?

                      \[\begin{array}{l} \\ \mathsf{fma}\left(x, x, 1\right) \cdot \varepsilon \end{array} \]
                      (FPCore (x eps) :precision binary64 (* (fma x x 1.0) eps))
                      double code(double x, double eps) {
                      	return fma(x, x, 1.0) * eps;
                      }
                      
                      function code(x, eps)
                      	return Float64(fma(x, x, 1.0) * eps)
                      end
                      
                      code[x_, eps_] := N[(N[(x * x + 1.0), $MachinePrecision] * eps), $MachinePrecision]
                      
                      \begin{array}{l}
                      
                      \\
                      \mathsf{fma}\left(x, x, 1\right) \cdot \varepsilon
                      \end{array}
                      
                      Derivation
                      1. Initial program 62.2%

                        \[\tan \left(x + \varepsilon\right) - \tan x \]
                      2. Add Preprocessing
                      3. Taylor expanded in eps around 0

                        \[\leadsto \color{blue}{\varepsilon \cdot \left(\left(1 + \varepsilon \cdot \left(\varepsilon \cdot \left(-1 \cdot \left(\varepsilon \cdot \left(\frac{-1}{2} \cdot \frac{\sin x \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{\cos x} + \left(\frac{1}{6} \cdot \frac{\sin x \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{\cos x} + \frac{\sin x \cdot \left(\frac{1}{6} + \left(-1 \cdot \frac{{\sin x}^{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{{\cos x}^{2}} + \left(\frac{-1}{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right) + \frac{1}{6} \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)\right)\right)}{\cos x}\right)\right)\right) - \left(\frac{1}{6} + \left(-1 \cdot \frac{{\sin x}^{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{{\cos x}^{2}} + \left(\frac{-1}{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right) + \frac{1}{6} \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)\right)\right)\right) - -1 \cdot \frac{\sin x \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{\cos x}\right)\right) - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)} \]
                      4. Applied rewrites99.6%

                        \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\left(-1 \cdot \varepsilon\right) \cdot \frac{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1 \cdot {\sin x}^{2}}{{\cos x}^{2}}, -1, -1\right), {\sin x}^{2}, {\sin x}^{2} \cdot 0.16666666666666666\right)}{{\cos x}^{2}} + \left(\mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, -0.5, -0.5\right) + 0.16666666666666666\right), \sin x, \left(\mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, 1, 1\right) \cdot \sin x\right) \cdot -0.3333333333333333\right)}{\cos x} - \left(\frac{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1 \cdot {\sin x}^{2}}{{\cos x}^{2}}, -1, -1\right), {\sin x}^{2}, {\sin x}^{2} \cdot 0.16666666666666666\right)}{{\cos x}^{2}} + \left(\mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, -0.5, -0.5\right) + 0.16666666666666666\right)\right), \varepsilon, \left(\mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, 1, 1\right) \cdot \frac{\sin x}{\cos x}\right) \cdot 1\right), \varepsilon, \mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, 1, 1\right)\right) \cdot \varepsilon} \]
                      5. Taylor expanded in eps around 0

                        \[\leadsto \left(1 + \frac{{\sin x}^{2}}{{\cos x}^{2}}\right) \cdot \varepsilon \]
                      6. Step-by-step derivation
                        1. Applied rewrites99.2%

                          \[\leadsto \left(\frac{{\sin x}^{2}}{{\cos x}^{2}} + 1\right) \cdot \varepsilon \]
                        2. Taylor expanded in x around 0

                          \[\leadsto \left({x}^{2} + 1\right) \cdot \varepsilon \]
                        3. Step-by-step derivation
                          1. Applied rewrites98.5%

                            \[\leadsto \left(x \cdot x + 1\right) \cdot \varepsilon \]
                          2. Taylor expanded in x around 0

                            \[\leadsto \left(1 + {x}^{2}\right) \cdot \varepsilon \]
                          3. Step-by-step derivation
                            1. Applied rewrites98.5%

                              \[\leadsto \mathsf{fma}\left(x, x, 1\right) \cdot \varepsilon \]
                            2. Add Preprocessing

                            Alternative 7: 97.8% accurate, 34.5× speedup?

                            \[\begin{array}{l} \\ 1 \cdot \varepsilon \end{array} \]
                            (FPCore (x eps) :precision binary64 (* 1.0 eps))
                            double code(double x, double eps) {
                            	return 1.0 * eps;
                            }
                            
                            real(8) function code(x, eps)
                                real(8), intent (in) :: x
                                real(8), intent (in) :: eps
                                code = 1.0d0 * eps
                            end function
                            
                            public static double code(double x, double eps) {
                            	return 1.0 * eps;
                            }
                            
                            def code(x, eps):
                            	return 1.0 * eps
                            
                            function code(x, eps)
                            	return Float64(1.0 * eps)
                            end
                            
                            function tmp = code(x, eps)
                            	tmp = 1.0 * eps;
                            end
                            
                            code[x_, eps_] := N[(1.0 * eps), $MachinePrecision]
                            
                            \begin{array}{l}
                            
                            \\
                            1 \cdot \varepsilon
                            \end{array}
                            
                            Derivation
                            1. Initial program 62.2%

                              \[\tan \left(x + \varepsilon\right) - \tan x \]
                            2. Add Preprocessing
                            3. Taylor expanded in eps around 0

                              \[\leadsto \color{blue}{\varepsilon \cdot \left(\left(1 + \varepsilon \cdot \left(\varepsilon \cdot \left(-1 \cdot \left(\varepsilon \cdot \left(\frac{-1}{2} \cdot \frac{\sin x \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{\cos x} + \left(\frac{1}{6} \cdot \frac{\sin x \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{\cos x} + \frac{\sin x \cdot \left(\frac{1}{6} + \left(-1 \cdot \frac{{\sin x}^{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{{\cos x}^{2}} + \left(\frac{-1}{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right) + \frac{1}{6} \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)\right)\right)}{\cos x}\right)\right)\right) - \left(\frac{1}{6} + \left(-1 \cdot \frac{{\sin x}^{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{{\cos x}^{2}} + \left(\frac{-1}{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right) + \frac{1}{6} \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)\right)\right)\right) - -1 \cdot \frac{\sin x \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{\cos x}\right)\right) - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)} \]
                            4. Applied rewrites99.6%

                              \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\left(-1 \cdot \varepsilon\right) \cdot \frac{\mathsf{fma}\left(\frac{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1 \cdot {\sin x}^{2}}{{\cos x}^{2}}, -1, -1\right), {\sin x}^{2}, {\sin x}^{2} \cdot 0.16666666666666666\right)}{{\cos x}^{2}} + \left(\mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, -0.5, -0.5\right) + 0.16666666666666666\right), \sin x, \left(\mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, 1, 1\right) \cdot \sin x\right) \cdot -0.3333333333333333\right)}{\cos x} - \left(\frac{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1 \cdot {\sin x}^{2}}{{\cos x}^{2}}, -1, -1\right), {\sin x}^{2}, {\sin x}^{2} \cdot 0.16666666666666666\right)}{{\cos x}^{2}} + \left(\mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, -0.5, -0.5\right) + 0.16666666666666666\right)\right), \varepsilon, \left(\mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, 1, 1\right) \cdot \frac{\sin x}{\cos x}\right) \cdot 1\right), \varepsilon, \mathsf{fma}\left(\frac{{\sin x}^{2}}{{\cos x}^{2}}, 1, 1\right)\right) \cdot \varepsilon} \]
                            5. Taylor expanded in eps around 0

                              \[\leadsto \left(1 + \frac{{\sin x}^{2}}{{\cos x}^{2}}\right) \cdot \varepsilon \]
                            6. Step-by-step derivation
                              1. Applied rewrites99.2%

                                \[\leadsto \left(\frac{{\sin x}^{2}}{{\cos x}^{2}} + 1\right) \cdot \varepsilon \]
                              2. Taylor expanded in x around 0

                                \[\leadsto \left({x}^{2} + 1\right) \cdot \varepsilon \]
                              3. Step-by-step derivation
                                1. Applied rewrites98.5%

                                  \[\leadsto \left(x \cdot x + 1\right) \cdot \varepsilon \]
                                2. Taylor expanded in x around 0

                                  \[\leadsto 1 \cdot \varepsilon \]
                                3. Step-by-step derivation
                                  1. Applied rewrites97.9%

                                    \[\leadsto 1 \cdot \varepsilon \]
                                  2. Add Preprocessing

                                  Developer Target 1: 99.0% accurate, 1.0× speedup?

                                  \[\begin{array}{l} \\ \varepsilon + \left(\varepsilon \cdot \tan x\right) \cdot \tan x \end{array} \]
                                  (FPCore (x eps) :precision binary64 (+ eps (* (* eps (tan x)) (tan x))))
                                  double code(double x, double eps) {
                                  	return eps + ((eps * tan(x)) * tan(x));
                                  }
                                  
                                  real(8) function code(x, eps)
                                      real(8), intent (in) :: x
                                      real(8), intent (in) :: eps
                                      code = eps + ((eps * tan(x)) * tan(x))
                                  end function
                                  
                                  public static double code(double x, double eps) {
                                  	return eps + ((eps * Math.tan(x)) * Math.tan(x));
                                  }
                                  
                                  def code(x, eps):
                                  	return eps + ((eps * math.tan(x)) * math.tan(x))
                                  
                                  function code(x, eps)
                                  	return Float64(eps + Float64(Float64(eps * tan(x)) * tan(x)))
                                  end
                                  
                                  function tmp = code(x, eps)
                                  	tmp = eps + ((eps * tan(x)) * tan(x));
                                  end
                                  
                                  code[x_, eps_] := N[(eps + N[(N[(eps * N[Tan[x], $MachinePrecision]), $MachinePrecision] * N[Tan[x], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
                                  
                                  \begin{array}{l}
                                  
                                  \\
                                  \varepsilon + \left(\varepsilon \cdot \tan x\right) \cdot \tan x
                                  \end{array}
                                  

                                  Reproduce

                                  ?
                                  herbie shell --seed 2024313 
                                  (FPCore (x eps)
                                    :name "2tan (problem 3.3.2)"
                                    :precision binary64
                                    :pre (and (and (and (<= -10000.0 x) (<= x 10000.0)) (< (* 1e-16 (fabs x)) eps)) (< eps (fabs x)))
                                  
                                    :alt
                                    (! :herbie-platform default (+ eps (* eps (tan x) (tan x))))
                                  
                                    (- (tan (+ x eps)) (tan x)))