ABCF->ab-angle a

Percentage Accurate: 18.7% → 62.5%
Time: 15.2s
Alternatives: 14
Speedup: 16.9×

Specification

?
\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
real(8) function code(a, b, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) + sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 14 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 18.7% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
real(8) function code(a, b, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) + sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Alternative 1: 62.5% accurate, 0.3× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C\\ t_1 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\ t_2 := -t\_1\\ t_3 := \frac{\sqrt{\left(2 \cdot \left(t\_1 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{t\_2}\\ t_4 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;t\_3 \leq -2 \cdot 10^{-197}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(A \cdot C, -4, B\_m \cdot B\_m\right) \cdot 2} \cdot \sqrt{F}}{-1} \cdot \frac{\sqrt{t\_0}}{t\_4}\\ \mathbf{elif}\;t\_3 \leq 0:\\ \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{elif}\;t\_3 \leq \infty:\\ \;\;\;\;\frac{\sqrt{t\_0 \cdot 2} \cdot \sqrt{F \cdot t\_4}}{t\_2}\\ \mathbf{else}:\\ \;\;\;\;\left(-{B\_m}^{-0.5}\right) \cdot \sqrt{F \cdot 2}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (let* ((t_0 (+ (+ (hypot (- A C) B_m) A) C))
        (t_1 (- (pow B_m 2.0) (* (* 4.0 A) C)))
        (t_2 (- t_1))
        (t_3
         (/
          (sqrt
           (*
            (* 2.0 (* t_1 F))
            (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))))
          t_2))
        (t_4 (fma -4.0 (* C A) (* B_m B_m))))
   (if (<= t_3 -2e-197)
     (*
      (/ (* (sqrt (* (fma (* A C) -4.0 (* B_m B_m)) 2.0)) (sqrt F)) -1.0)
      (/ (sqrt t_0) t_4))
     (if (<= t_3 0.0)
       (* (sqrt (* -0.5 (/ F A))) (- (sqrt 2.0)))
       (if (<= t_3 INFINITY)
         (/ (* (sqrt (* t_0 2.0)) (sqrt (* F t_4))) t_2)
         (* (- (pow B_m -0.5)) (sqrt (* F 2.0))))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double t_0 = (hypot((A - C), B_m) + A) + C;
	double t_1 = pow(B_m, 2.0) - ((4.0 * A) * C);
	double t_2 = -t_1;
	double t_3 = sqrt(((2.0 * (t_1 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))))) / t_2;
	double t_4 = fma(-4.0, (C * A), (B_m * B_m));
	double tmp;
	if (t_3 <= -2e-197) {
		tmp = ((sqrt((fma((A * C), -4.0, (B_m * B_m)) * 2.0)) * sqrt(F)) / -1.0) * (sqrt(t_0) / t_4);
	} else if (t_3 <= 0.0) {
		tmp = sqrt((-0.5 * (F / A))) * -sqrt(2.0);
	} else if (t_3 <= ((double) INFINITY)) {
		tmp = (sqrt((t_0 * 2.0)) * sqrt((F * t_4))) / t_2;
	} else {
		tmp = -pow(B_m, -0.5) * sqrt((F * 2.0));
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	t_0 = Float64(Float64(hypot(Float64(A - C), B_m) + A) + C)
	t_1 = Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C))
	t_2 = Float64(-t_1)
	t_3 = Float64(sqrt(Float64(Float64(2.0 * Float64(t_1 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))))) / t_2)
	t_4 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
	tmp = 0.0
	if (t_3 <= -2e-197)
		tmp = Float64(Float64(Float64(sqrt(Float64(fma(Float64(A * C), -4.0, Float64(B_m * B_m)) * 2.0)) * sqrt(F)) / -1.0) * Float64(sqrt(t_0) / t_4));
	elseif (t_3 <= 0.0)
		tmp = Float64(sqrt(Float64(-0.5 * Float64(F / A))) * Float64(-sqrt(2.0)));
	elseif (t_3 <= Inf)
		tmp = Float64(Float64(sqrt(Float64(t_0 * 2.0)) * sqrt(Float64(F * t_4))) / t_2);
	else
		tmp = Float64(Float64(-(B_m ^ -0.5)) * sqrt(Float64(F * 2.0)));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision]}, Block[{t$95$1 = N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = (-t$95$1)}, Block[{t$95$3 = N[(N[Sqrt[N[(N[(2.0 * N[(t$95$1 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / t$95$2), $MachinePrecision]}, Block[{t$95$4 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$3, -2e-197], N[(N[(N[(N[Sqrt[N[(N[(N[(A * C), $MachinePrecision] * -4.0 + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision] / -1.0), $MachinePrecision] * N[(N[Sqrt[t$95$0], $MachinePrecision] / t$95$4), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$3, 0.0], N[(N[Sqrt[N[(-0.5 * N[(F / A), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[2.0], $MachinePrecision])), $MachinePrecision], If[LessEqual[t$95$3, Infinity], N[(N[(N[Sqrt[N[(t$95$0 * 2.0), $MachinePrecision]], $MachinePrecision] * N[Sqrt[N[(F * t$95$4), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / t$95$2), $MachinePrecision], N[((-N[Power[B$95$m, -0.5], $MachinePrecision]) * N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]]]]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
t_0 := \left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C\\
t_1 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\
t_2 := -t\_1\\
t_3 := \frac{\sqrt{\left(2 \cdot \left(t\_1 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{t\_2}\\
t_4 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
\mathbf{if}\;t\_3 \leq -2 \cdot 10^{-197}:\\
\;\;\;\;\frac{\sqrt{\mathsf{fma}\left(A \cdot C, -4, B\_m \cdot B\_m\right) \cdot 2} \cdot \sqrt{F}}{-1} \cdot \frac{\sqrt{t\_0}}{t\_4}\\

\mathbf{elif}\;t\_3 \leq 0:\\
\;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\

\mathbf{elif}\;t\_3 \leq \infty:\\
\;\;\;\;\frac{\sqrt{t\_0 \cdot 2} \cdot \sqrt{F \cdot t\_4}}{t\_2}\\

\mathbf{else}:\\
\;\;\;\;\left(-{B\_m}^{-0.5}\right) \cdot \sqrt{F \cdot 2}\\


\end{array}
\end{array}
Derivation
  1. Split input into 4 regimes
  2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -2e-197

    1. Initial program 37.0%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Applied rewrites64.9%

      \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
    4. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto \frac{\color{blue}{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      2. lift-*.f64N/A

        \[\leadsto \frac{\sqrt{\color{blue}{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      3. *-commutativeN/A

        \[\leadsto \frac{\sqrt{\color{blue}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \left(2 \cdot F\right)}}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      4. sqrt-prodN/A

        \[\leadsto \frac{\color{blue}{\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \cdot \sqrt{2 \cdot F}}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      5. lift-fma.f64N/A

        \[\leadsto \frac{\sqrt{\color{blue}{-4 \cdot \left(C \cdot A\right) + B \cdot B}} \cdot \sqrt{2 \cdot F}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      6. +-commutativeN/A

        \[\leadsto \frac{\sqrt{\color{blue}{B \cdot B + -4 \cdot \left(C \cdot A\right)}} \cdot \sqrt{2 \cdot F}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      7. metadata-evalN/A

        \[\leadsto \frac{\sqrt{B \cdot B + \color{blue}{\left(\mathsf{neg}\left(4\right)\right)} \cdot \left(C \cdot A\right)} \cdot \sqrt{2 \cdot F}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      8. cancel-sign-sub-invN/A

        \[\leadsto \frac{\sqrt{\color{blue}{B \cdot B - 4 \cdot \left(C \cdot A\right)}} \cdot \sqrt{2 \cdot F}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      9. lift-*.f64N/A

        \[\leadsto \frac{\sqrt{\color{blue}{B \cdot B} - 4 \cdot \left(C \cdot A\right)} \cdot \sqrt{2 \cdot F}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      10. pow2N/A

        \[\leadsto \frac{\sqrt{\color{blue}{{B}^{2}} - 4 \cdot \left(C \cdot A\right)} \cdot \sqrt{2 \cdot F}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      11. lift-pow.f64N/A

        \[\leadsto \frac{\sqrt{\color{blue}{{B}^{2}} - 4 \cdot \left(C \cdot A\right)} \cdot \sqrt{2 \cdot F}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      12. lift-*.f64N/A

        \[\leadsto \frac{\sqrt{{B}^{2} - 4 \cdot \color{blue}{\left(C \cdot A\right)}} \cdot \sqrt{2 \cdot F}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      13. *-commutativeN/A

        \[\leadsto \frac{\sqrt{{B}^{2} - 4 \cdot \color{blue}{\left(A \cdot C\right)}} \cdot \sqrt{2 \cdot F}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      14. associate-*l*N/A

        \[\leadsto \frac{\sqrt{{B}^{2} - \color{blue}{\left(4 \cdot A\right) \cdot C}} \cdot \sqrt{2 \cdot F}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      15. lift-*.f64N/A

        \[\leadsto \frac{\sqrt{{B}^{2} - \color{blue}{\left(4 \cdot A\right)} \cdot C} \cdot \sqrt{2 \cdot F}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      16. lift-*.f64N/A

        \[\leadsto \frac{\sqrt{{B}^{2} - \color{blue}{\left(4 \cdot A\right) \cdot C}} \cdot \sqrt{2 \cdot F}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      17. lift--.f64N/A

        \[\leadsto \frac{\sqrt{\color{blue}{{B}^{2} - \left(4 \cdot A\right) \cdot C}} \cdot \sqrt{2 \cdot F}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      18. sqrt-prodN/A

        \[\leadsto \frac{\color{blue}{\sqrt{\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot \left(2 \cdot F\right)}}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      19. lift-*.f64N/A

        \[\leadsto \frac{\sqrt{\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot \color{blue}{\left(2 \cdot F\right)}}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
    5. Applied rewrites79.2%

      \[\leadsto \frac{\color{blue}{\sqrt{\mathsf{fma}\left(A \cdot C, -4, B \cdot B\right) \cdot 2} \cdot \sqrt{F}}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]

    if -2e-197 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -0.0

    1. Initial program 3.8%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in F around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
    4. Step-by-step derivation
      1. associate-*r*N/A

        \[\leadsto \color{blue}{\left(-1 \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}\right) \cdot \sqrt{2}} \]
      2. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(-1 \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}\right) \cdot \sqrt{2}} \]
    5. Applied rewrites19.3%

      \[\leadsto \color{blue}{\left(-\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}\right) \cdot \sqrt{2}} \]
    6. Taylor expanded in A around -inf

      \[\leadsto \left(-\sqrt{\frac{-1}{2} \cdot \frac{F}{A}}\right) \cdot \sqrt{2} \]
    7. Step-by-step derivation
      1. Applied rewrites22.8%

        \[\leadsto \left(-\sqrt{-0.5 \cdot \frac{F}{A}}\right) \cdot \sqrt{2} \]

      if -0.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

      1. Initial program 49.3%

        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. Add Preprocessing
      3. Step-by-step derivation
        1. lift-sqrt.f64N/A

          \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. lift-*.f64N/A

          \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        3. *-commutativeN/A

          \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        4. lift-*.f64N/A

          \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        5. associate-*r*N/A

          \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2\right) \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        6. sqrt-prodN/A

          \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot \sqrt{\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        7. pow1/2N/A

          \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot \color{blue}{{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        8. lower-*.f64N/A

          \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot 2} \cdot {\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. Applied rewrites81.2%

        \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

      if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

      1. Initial program 0.0%

        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. Add Preprocessing
      3. Taylor expanded in B around inf

        \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
      4. Step-by-step derivation
        1. mul-1-negN/A

          \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
        2. lower-neg.f64N/A

          \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
        3. lower-*.f64N/A

          \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
        4. lower-sqrt.f64N/A

          \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
        5. lower-/.f64N/A

          \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
        6. lower-sqrt.f6423.3

          \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
      5. Applied rewrites23.3%

        \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
      6. Step-by-step derivation
        1. Applied rewrites28.8%

          \[\leadsto -\sqrt{F} \cdot \sqrt{{B}^{-1} \cdot 2} \]
        2. Step-by-step derivation
          1. Applied rewrites28.8%

            \[\leadsto -{B}^{-0.5} \cdot \sqrt{F \cdot 2} \]
        3. Recombined 4 regimes into one program.
        4. Final simplification49.7%

          \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -2 \cdot 10^{-197}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(A \cdot C, -4, B \cdot B\right) \cdot 2} \cdot \sqrt{F}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq 0:\\ \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq \infty:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot 2} \cdot \sqrt{F \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-{B}^{-0.5}\right) \cdot \sqrt{F \cdot 2}\\ \end{array} \]
        5. Add Preprocessing

        Alternative 2: 62.6% accurate, 0.3× speedup?

        \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}\\ t_1 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\ t_2 := \frac{\sqrt{\left(2 \cdot \left(t\_1 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_1}\\ t_3 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;t\_2 \leq -2 \cdot 10^{-197}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(A \cdot C, -4, B\_m \cdot B\_m\right) \cdot 2} \cdot \sqrt{F}}{-1} \cdot \frac{t\_0}{t\_3}\\ \mathbf{elif}\;t\_2 \leq 0:\\ \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{elif}\;t\_2 \leq \infty:\\ \;\;\;\;\frac{t\_0}{-1} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot t\_3}}{t\_3}\\ \mathbf{else}:\\ \;\;\;\;\left(-{B\_m}^{-0.5}\right) \cdot \sqrt{F \cdot 2}\\ \end{array} \end{array} \]
        B_m = (fabs.f64 B)
        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
        (FPCore (A B_m C F)
         :precision binary64
         (let* ((t_0 (sqrt (+ (+ (hypot (- A C) B_m) A) C)))
                (t_1 (- (pow B_m 2.0) (* (* 4.0 A) C)))
                (t_2
                 (/
                  (sqrt
                   (*
                    (* 2.0 (* t_1 F))
                    (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))))
                  (- t_1)))
                (t_3 (fma -4.0 (* C A) (* B_m B_m))))
           (if (<= t_2 -2e-197)
             (*
              (/ (* (sqrt (* (fma (* A C) -4.0 (* B_m B_m)) 2.0)) (sqrt F)) -1.0)
              (/ t_0 t_3))
             (if (<= t_2 0.0)
               (* (sqrt (* -0.5 (/ F A))) (- (sqrt 2.0)))
               (if (<= t_2 INFINITY)
                 (* (/ t_0 -1.0) (/ (sqrt (* (* 2.0 F) t_3)) t_3))
                 (* (- (pow B_m -0.5)) (sqrt (* F 2.0))))))))
        B_m = fabs(B);
        assert(A < B_m && B_m < C && C < F);
        double code(double A, double B_m, double C, double F) {
        	double t_0 = sqrt(((hypot((A - C), B_m) + A) + C));
        	double t_1 = pow(B_m, 2.0) - ((4.0 * A) * C);
        	double t_2 = sqrt(((2.0 * (t_1 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))))) / -t_1;
        	double t_3 = fma(-4.0, (C * A), (B_m * B_m));
        	double tmp;
        	if (t_2 <= -2e-197) {
        		tmp = ((sqrt((fma((A * C), -4.0, (B_m * B_m)) * 2.0)) * sqrt(F)) / -1.0) * (t_0 / t_3);
        	} else if (t_2 <= 0.0) {
        		tmp = sqrt((-0.5 * (F / A))) * -sqrt(2.0);
        	} else if (t_2 <= ((double) INFINITY)) {
        		tmp = (t_0 / -1.0) * (sqrt(((2.0 * F) * t_3)) / t_3);
        	} else {
        		tmp = -pow(B_m, -0.5) * sqrt((F * 2.0));
        	}
        	return tmp;
        }
        
        B_m = abs(B)
        A, B_m, C, F = sort([A, B_m, C, F])
        function code(A, B_m, C, F)
        	t_0 = sqrt(Float64(Float64(hypot(Float64(A - C), B_m) + A) + C))
        	t_1 = Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C))
        	t_2 = Float64(sqrt(Float64(Float64(2.0 * Float64(t_1 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))))) / Float64(-t_1))
        	t_3 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
        	tmp = 0.0
        	if (t_2 <= -2e-197)
        		tmp = Float64(Float64(Float64(sqrt(Float64(fma(Float64(A * C), -4.0, Float64(B_m * B_m)) * 2.0)) * sqrt(F)) / -1.0) * Float64(t_0 / t_3));
        	elseif (t_2 <= 0.0)
        		tmp = Float64(sqrt(Float64(-0.5 * Float64(F / A))) * Float64(-sqrt(2.0)));
        	elseif (t_2 <= Inf)
        		tmp = Float64(Float64(t_0 / -1.0) * Float64(sqrt(Float64(Float64(2.0 * F) * t_3)) / t_3));
        	else
        		tmp = Float64(Float64(-(B_m ^ -0.5)) * sqrt(Float64(F * 2.0)));
        	end
        	return tmp
        end
        
        B_m = N[Abs[B], $MachinePrecision]
        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
        code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[Sqrt[N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision]}, Block[{t$95$1 = N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(N[Sqrt[N[(N[(2.0 * N[(t$95$1 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$1)), $MachinePrecision]}, Block[{t$95$3 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$2, -2e-197], N[(N[(N[(N[Sqrt[N[(N[(N[(A * C), $MachinePrecision] * -4.0 + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision] / -1.0), $MachinePrecision] * N[(t$95$0 / t$95$3), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$2, 0.0], N[(N[Sqrt[N[(-0.5 * N[(F / A), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[2.0], $MachinePrecision])), $MachinePrecision], If[LessEqual[t$95$2, Infinity], N[(N[(t$95$0 / -1.0), $MachinePrecision] * N[(N[Sqrt[N[(N[(2.0 * F), $MachinePrecision] * t$95$3), $MachinePrecision]], $MachinePrecision] / t$95$3), $MachinePrecision]), $MachinePrecision], N[((-N[Power[B$95$m, -0.5], $MachinePrecision]) * N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]]]]]
        
        \begin{array}{l}
        B_m = \left|B\right|
        \\
        [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
        \\
        \begin{array}{l}
        t_0 := \sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}\\
        t_1 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\
        t_2 := \frac{\sqrt{\left(2 \cdot \left(t\_1 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_1}\\
        t_3 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
        \mathbf{if}\;t\_2 \leq -2 \cdot 10^{-197}:\\
        \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(A \cdot C, -4, B\_m \cdot B\_m\right) \cdot 2} \cdot \sqrt{F}}{-1} \cdot \frac{t\_0}{t\_3}\\
        
        \mathbf{elif}\;t\_2 \leq 0:\\
        \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\
        
        \mathbf{elif}\;t\_2 \leq \infty:\\
        \;\;\;\;\frac{t\_0}{-1} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot t\_3}}{t\_3}\\
        
        \mathbf{else}:\\
        \;\;\;\;\left(-{B\_m}^{-0.5}\right) \cdot \sqrt{F \cdot 2}\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 4 regimes
        2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -2e-197

          1. Initial program 37.0%

            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. Add Preprocessing
          3. Applied rewrites64.9%

            \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
          4. Step-by-step derivation
            1. lift-sqrt.f64N/A

              \[\leadsto \frac{\color{blue}{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
            2. lift-*.f64N/A

              \[\leadsto \frac{\sqrt{\color{blue}{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
            3. *-commutativeN/A

              \[\leadsto \frac{\sqrt{\color{blue}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot \left(2 \cdot F\right)}}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
            4. sqrt-prodN/A

              \[\leadsto \frac{\color{blue}{\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \cdot \sqrt{2 \cdot F}}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
            5. lift-fma.f64N/A

              \[\leadsto \frac{\sqrt{\color{blue}{-4 \cdot \left(C \cdot A\right) + B \cdot B}} \cdot \sqrt{2 \cdot F}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
            6. +-commutativeN/A

              \[\leadsto \frac{\sqrt{\color{blue}{B \cdot B + -4 \cdot \left(C \cdot A\right)}} \cdot \sqrt{2 \cdot F}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
            7. metadata-evalN/A

              \[\leadsto \frac{\sqrt{B \cdot B + \color{blue}{\left(\mathsf{neg}\left(4\right)\right)} \cdot \left(C \cdot A\right)} \cdot \sqrt{2 \cdot F}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
            8. cancel-sign-sub-invN/A

              \[\leadsto \frac{\sqrt{\color{blue}{B \cdot B - 4 \cdot \left(C \cdot A\right)}} \cdot \sqrt{2 \cdot F}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
            9. lift-*.f64N/A

              \[\leadsto \frac{\sqrt{\color{blue}{B \cdot B} - 4 \cdot \left(C \cdot A\right)} \cdot \sqrt{2 \cdot F}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
            10. pow2N/A

              \[\leadsto \frac{\sqrt{\color{blue}{{B}^{2}} - 4 \cdot \left(C \cdot A\right)} \cdot \sqrt{2 \cdot F}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
            11. lift-pow.f64N/A

              \[\leadsto \frac{\sqrt{\color{blue}{{B}^{2}} - 4 \cdot \left(C \cdot A\right)} \cdot \sqrt{2 \cdot F}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
            12. lift-*.f64N/A

              \[\leadsto \frac{\sqrt{{B}^{2} - 4 \cdot \color{blue}{\left(C \cdot A\right)}} \cdot \sqrt{2 \cdot F}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
            13. *-commutativeN/A

              \[\leadsto \frac{\sqrt{{B}^{2} - 4 \cdot \color{blue}{\left(A \cdot C\right)}} \cdot \sqrt{2 \cdot F}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
            14. associate-*l*N/A

              \[\leadsto \frac{\sqrt{{B}^{2} - \color{blue}{\left(4 \cdot A\right) \cdot C}} \cdot \sqrt{2 \cdot F}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
            15. lift-*.f64N/A

              \[\leadsto \frac{\sqrt{{B}^{2} - \color{blue}{\left(4 \cdot A\right)} \cdot C} \cdot \sqrt{2 \cdot F}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
            16. lift-*.f64N/A

              \[\leadsto \frac{\sqrt{{B}^{2} - \color{blue}{\left(4 \cdot A\right) \cdot C}} \cdot \sqrt{2 \cdot F}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
            17. lift--.f64N/A

              \[\leadsto \frac{\sqrt{\color{blue}{{B}^{2} - \left(4 \cdot A\right) \cdot C}} \cdot \sqrt{2 \cdot F}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
            18. sqrt-prodN/A

              \[\leadsto \frac{\color{blue}{\sqrt{\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot \left(2 \cdot F\right)}}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
            19. lift-*.f64N/A

              \[\leadsto \frac{\sqrt{\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot \color{blue}{\left(2 \cdot F\right)}}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
          5. Applied rewrites79.2%

            \[\leadsto \frac{\color{blue}{\sqrt{\mathsf{fma}\left(A \cdot C, -4, B \cdot B\right) \cdot 2} \cdot \sqrt{F}}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]

          if -2e-197 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -0.0

          1. Initial program 3.8%

            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. Add Preprocessing
          3. Taylor expanded in F around 0

            \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
          4. Step-by-step derivation
            1. associate-*r*N/A

              \[\leadsto \color{blue}{\left(-1 \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}\right) \cdot \sqrt{2}} \]
            2. lower-*.f64N/A

              \[\leadsto \color{blue}{\left(-1 \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}\right) \cdot \sqrt{2}} \]
          5. Applied rewrites19.3%

            \[\leadsto \color{blue}{\left(-\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}\right) \cdot \sqrt{2}} \]
          6. Taylor expanded in A around -inf

            \[\leadsto \left(-\sqrt{\frac{-1}{2} \cdot \frac{F}{A}}\right) \cdot \sqrt{2} \]
          7. Step-by-step derivation
            1. Applied rewrites22.8%

              \[\leadsto \left(-\sqrt{-0.5 \cdot \frac{F}{A}}\right) \cdot \sqrt{2} \]

            if -0.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

            1. Initial program 49.3%

              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            2. Add Preprocessing
            3. Applied rewrites80.9%

              \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{-1} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]

            if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

            1. Initial program 0.0%

              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            2. Add Preprocessing
            3. Taylor expanded in B around inf

              \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
            4. Step-by-step derivation
              1. mul-1-negN/A

                \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
              2. lower-neg.f64N/A

                \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
              3. lower-*.f64N/A

                \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
              4. lower-sqrt.f64N/A

                \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
              5. lower-/.f64N/A

                \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
              6. lower-sqrt.f6423.3

                \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
            5. Applied rewrites23.3%

              \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
            6. Step-by-step derivation
              1. Applied rewrites28.8%

                \[\leadsto -\sqrt{F} \cdot \sqrt{{B}^{-1} \cdot 2} \]
              2. Step-by-step derivation
                1. Applied rewrites28.8%

                  \[\leadsto -{B}^{-0.5} \cdot \sqrt{F \cdot 2} \]
              3. Recombined 4 regimes into one program.
              4. Final simplification49.7%

                \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -2 \cdot 10^{-197}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(A \cdot C, -4, B \cdot B\right) \cdot 2} \cdot \sqrt{F}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq 0:\\ \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq \infty:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{-1} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-{B}^{-0.5}\right) \cdot \sqrt{F \cdot 2}\\ \end{array} \]
              5. Add Preprocessing

              Alternative 3: 62.6% accurate, 0.3× speedup?

              \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}\\ t_1 := \sqrt{F \cdot 2}\\ t_2 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\ t_3 := \frac{\sqrt{\left(2 \cdot \left(t\_2 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_2}\\ t_4 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;t\_3 \leq -2 \cdot 10^{-197}:\\ \;\;\;\;\left(t\_1 \cdot \left(-\sqrt{\mathsf{fma}\left(A \cdot C, -4, B\_m \cdot B\_m\right)}\right)\right) \cdot \frac{t\_0}{t\_4}\\ \mathbf{elif}\;t\_3 \leq 0:\\ \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{elif}\;t\_3 \leq \infty:\\ \;\;\;\;\frac{t\_0}{-1} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot t\_4}}{t\_4}\\ \mathbf{else}:\\ \;\;\;\;\left(-{B\_m}^{-0.5}\right) \cdot t\_1\\ \end{array} \end{array} \]
              B_m = (fabs.f64 B)
              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
              (FPCore (A B_m C F)
               :precision binary64
               (let* ((t_0 (sqrt (+ (+ (hypot (- A C) B_m) A) C)))
                      (t_1 (sqrt (* F 2.0)))
                      (t_2 (- (pow B_m 2.0) (* (* 4.0 A) C)))
                      (t_3
                       (/
                        (sqrt
                         (*
                          (* 2.0 (* t_2 F))
                          (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))))
                        (- t_2)))
                      (t_4 (fma -4.0 (* C A) (* B_m B_m))))
                 (if (<= t_3 -2e-197)
                   (* (* t_1 (- (sqrt (fma (* A C) -4.0 (* B_m B_m))))) (/ t_0 t_4))
                   (if (<= t_3 0.0)
                     (* (sqrt (* -0.5 (/ F A))) (- (sqrt 2.0)))
                     (if (<= t_3 INFINITY)
                       (* (/ t_0 -1.0) (/ (sqrt (* (* 2.0 F) t_4)) t_4))
                       (* (- (pow B_m -0.5)) t_1))))))
              B_m = fabs(B);
              assert(A < B_m && B_m < C && C < F);
              double code(double A, double B_m, double C, double F) {
              	double t_0 = sqrt(((hypot((A - C), B_m) + A) + C));
              	double t_1 = sqrt((F * 2.0));
              	double t_2 = pow(B_m, 2.0) - ((4.0 * A) * C);
              	double t_3 = sqrt(((2.0 * (t_2 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))))) / -t_2;
              	double t_4 = fma(-4.0, (C * A), (B_m * B_m));
              	double tmp;
              	if (t_3 <= -2e-197) {
              		tmp = (t_1 * -sqrt(fma((A * C), -4.0, (B_m * B_m)))) * (t_0 / t_4);
              	} else if (t_3 <= 0.0) {
              		tmp = sqrt((-0.5 * (F / A))) * -sqrt(2.0);
              	} else if (t_3 <= ((double) INFINITY)) {
              		tmp = (t_0 / -1.0) * (sqrt(((2.0 * F) * t_4)) / t_4);
              	} else {
              		tmp = -pow(B_m, -0.5) * t_1;
              	}
              	return tmp;
              }
              
              B_m = abs(B)
              A, B_m, C, F = sort([A, B_m, C, F])
              function code(A, B_m, C, F)
              	t_0 = sqrt(Float64(Float64(hypot(Float64(A - C), B_m) + A) + C))
              	t_1 = sqrt(Float64(F * 2.0))
              	t_2 = Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C))
              	t_3 = Float64(sqrt(Float64(Float64(2.0 * Float64(t_2 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))))) / Float64(-t_2))
              	t_4 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
              	tmp = 0.0
              	if (t_3 <= -2e-197)
              		tmp = Float64(Float64(t_1 * Float64(-sqrt(fma(Float64(A * C), -4.0, Float64(B_m * B_m))))) * Float64(t_0 / t_4));
              	elseif (t_3 <= 0.0)
              		tmp = Float64(sqrt(Float64(-0.5 * Float64(F / A))) * Float64(-sqrt(2.0)));
              	elseif (t_3 <= Inf)
              		tmp = Float64(Float64(t_0 / -1.0) * Float64(sqrt(Float64(Float64(2.0 * F) * t_4)) / t_4));
              	else
              		tmp = Float64(Float64(-(B_m ^ -0.5)) * t_1);
              	end
              	return tmp
              end
              
              B_m = N[Abs[B], $MachinePrecision]
              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
              code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[Sqrt[N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision]}, Block[{t$95$1 = N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision]}, Block[{t$95$2 = N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = N[(N[Sqrt[N[(N[(2.0 * N[(t$95$2 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$2)), $MachinePrecision]}, Block[{t$95$4 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$3, -2e-197], N[(N[(t$95$1 * (-N[Sqrt[N[(N[(A * C), $MachinePrecision] * -4.0 + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision])), $MachinePrecision] * N[(t$95$0 / t$95$4), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$3, 0.0], N[(N[Sqrt[N[(-0.5 * N[(F / A), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[2.0], $MachinePrecision])), $MachinePrecision], If[LessEqual[t$95$3, Infinity], N[(N[(t$95$0 / -1.0), $MachinePrecision] * N[(N[Sqrt[N[(N[(2.0 * F), $MachinePrecision] * t$95$4), $MachinePrecision]], $MachinePrecision] / t$95$4), $MachinePrecision]), $MachinePrecision], N[((-N[Power[B$95$m, -0.5], $MachinePrecision]) * t$95$1), $MachinePrecision]]]]]]]]]
              
              \begin{array}{l}
              B_m = \left|B\right|
              \\
              [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
              \\
              \begin{array}{l}
              t_0 := \sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}\\
              t_1 := \sqrt{F \cdot 2}\\
              t_2 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\
              t_3 := \frac{\sqrt{\left(2 \cdot \left(t\_2 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_2}\\
              t_4 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
              \mathbf{if}\;t\_3 \leq -2 \cdot 10^{-197}:\\
              \;\;\;\;\left(t\_1 \cdot \left(-\sqrt{\mathsf{fma}\left(A \cdot C, -4, B\_m \cdot B\_m\right)}\right)\right) \cdot \frac{t\_0}{t\_4}\\
              
              \mathbf{elif}\;t\_3 \leq 0:\\
              \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\
              
              \mathbf{elif}\;t\_3 \leq \infty:\\
              \;\;\;\;\frac{t\_0}{-1} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot t\_4}}{t\_4}\\
              
              \mathbf{else}:\\
              \;\;\;\;\left(-{B\_m}^{-0.5}\right) \cdot t\_1\\
              
              
              \end{array}
              \end{array}
              
              Derivation
              1. Split input into 4 regimes
              2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -2e-197

                1. Initial program 37.0%

                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                2. Add Preprocessing
                3. Applied rewrites64.9%

                  \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                4. Step-by-step derivation
                  1. lift-/.f64N/A

                    \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1}} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  2. frac-2negN/A

                    \[\leadsto \color{blue}{\frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\right)}{\mathsf{neg}\left(-1\right)}} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  3. metadata-evalN/A

                    \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\right)}{\color{blue}{1}} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  4. /-rgt-identityN/A

                    \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\right)\right)} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  5. lift-sqrt.f64N/A

                    \[\leadsto \left(\mathsf{neg}\left(\color{blue}{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  6. pow1/2N/A

                    \[\leadsto \left(\mathsf{neg}\left(\color{blue}{{\left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}^{\frac{1}{2}}}\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  7. lift-*.f64N/A

                    \[\leadsto \left(\mathsf{neg}\left({\color{blue}{\left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}^{\frac{1}{2}}\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  8. unpow-prod-downN/A

                    \[\leadsto \left(\mathsf{neg}\left(\color{blue}{{\left(2 \cdot F\right)}^{\frac{1}{2}} \cdot {\left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}^{\frac{1}{2}}}\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  9. distribute-rgt-neg-inN/A

                    \[\leadsto \color{blue}{\left({\left(2 \cdot F\right)}^{\frac{1}{2}} \cdot \left(\mathsf{neg}\left({\left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)\right)\right)} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  10. lower-*.f64N/A

                    \[\leadsto \color{blue}{\left({\left(2 \cdot F\right)}^{\frac{1}{2}} \cdot \left(\mathsf{neg}\left({\left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)\right)\right)} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  11. pow1/2N/A

                    \[\leadsto \left(\color{blue}{\sqrt{2 \cdot F}} \cdot \left(\mathsf{neg}\left({\left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  12. lower-sqrt.f64N/A

                    \[\leadsto \left(\color{blue}{\sqrt{2 \cdot F}} \cdot \left(\mathsf{neg}\left({\left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  13. lift-*.f64N/A

                    \[\leadsto \left(\sqrt{\color{blue}{2 \cdot F}} \cdot \left(\mathsf{neg}\left({\left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  14. *-commutativeN/A

                    \[\leadsto \left(\sqrt{\color{blue}{F \cdot 2}} \cdot \left(\mathsf{neg}\left({\left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  15. lower-*.f64N/A

                    \[\leadsto \left(\sqrt{\color{blue}{F \cdot 2}} \cdot \left(\mathsf{neg}\left({\left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  16. lower-neg.f64N/A

                    \[\leadsto \left(\sqrt{F \cdot 2} \cdot \color{blue}{\left(-{\left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)}\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  17. pow1/2N/A

                    \[\leadsto \left(\sqrt{F \cdot 2} \cdot \left(-\color{blue}{\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  18. lift-fma.f64N/A

                    \[\leadsto \left(\sqrt{F \cdot 2} \cdot \left(-\sqrt{\color{blue}{-4 \cdot \left(C \cdot A\right) + B \cdot B}}\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  19. +-commutativeN/A

                    \[\leadsto \left(\sqrt{F \cdot 2} \cdot \left(-\sqrt{\color{blue}{B \cdot B + -4 \cdot \left(C \cdot A\right)}}\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  20. metadata-evalN/A

                    \[\leadsto \left(\sqrt{F \cdot 2} \cdot \left(-\sqrt{B \cdot B + \color{blue}{\left(\mathsf{neg}\left(4\right)\right)} \cdot \left(C \cdot A\right)}\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  21. cancel-sign-sub-invN/A

                    \[\leadsto \left(\sqrt{F \cdot 2} \cdot \left(-\sqrt{\color{blue}{B \cdot B - 4 \cdot \left(C \cdot A\right)}}\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                5. Applied rewrites79.2%

                  \[\leadsto \color{blue}{\left(\sqrt{F \cdot 2} \cdot \left(-\sqrt{\mathsf{fma}\left(A \cdot C, -4, B \cdot B\right)}\right)\right)} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]

                if -2e-197 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -0.0

                1. Initial program 3.8%

                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                2. Add Preprocessing
                3. Taylor expanded in F around 0

                  \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                4. Step-by-step derivation
                  1. associate-*r*N/A

                    \[\leadsto \color{blue}{\left(-1 \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}\right) \cdot \sqrt{2}} \]
                  2. lower-*.f64N/A

                    \[\leadsto \color{blue}{\left(-1 \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}\right) \cdot \sqrt{2}} \]
                5. Applied rewrites19.3%

                  \[\leadsto \color{blue}{\left(-\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}\right) \cdot \sqrt{2}} \]
                6. Taylor expanded in A around -inf

                  \[\leadsto \left(-\sqrt{\frac{-1}{2} \cdot \frac{F}{A}}\right) \cdot \sqrt{2} \]
                7. Step-by-step derivation
                  1. Applied rewrites22.8%

                    \[\leadsto \left(-\sqrt{-0.5 \cdot \frac{F}{A}}\right) \cdot \sqrt{2} \]

                  if -0.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

                  1. Initial program 49.3%

                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  2. Add Preprocessing
                  3. Applied rewrites80.9%

                    \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{-1} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]

                  if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

                  1. Initial program 0.0%

                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  2. Add Preprocessing
                  3. Taylor expanded in B around inf

                    \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                  4. Step-by-step derivation
                    1. mul-1-negN/A

                      \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                    2. lower-neg.f64N/A

                      \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                    3. lower-*.f64N/A

                      \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                    4. lower-sqrt.f64N/A

                      \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                    5. lower-/.f64N/A

                      \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                    6. lower-sqrt.f6423.3

                      \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                  5. Applied rewrites23.3%

                    \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                  6. Step-by-step derivation
                    1. Applied rewrites28.8%

                      \[\leadsto -\sqrt{F} \cdot \sqrt{{B}^{-1} \cdot 2} \]
                    2. Step-by-step derivation
                      1. Applied rewrites28.8%

                        \[\leadsto -{B}^{-0.5} \cdot \sqrt{F \cdot 2} \]
                    3. Recombined 4 regimes into one program.
                    4. Final simplification49.7%

                      \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -2 \cdot 10^{-197}:\\ \;\;\;\;\left(\sqrt{F \cdot 2} \cdot \left(-\sqrt{\mathsf{fma}\left(A \cdot C, -4, B \cdot B\right)}\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq 0:\\ \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq \infty:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{-1} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-{B}^{-0.5}\right) \cdot \sqrt{F \cdot 2}\\ \end{array} \]
                    5. Add Preprocessing

                    Alternative 4: 61.9% accurate, 0.3× speedup?

                    \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ t_1 := \mathsf{hypot}\left(A - C, B\_m\right)\\ t_2 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\ t_3 := \frac{\sqrt{\left(2 \cdot \left(t\_2 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_2}\\ \mathbf{if}\;t\_3 \leq -2 \cdot 10^{-197}:\\ \;\;\;\;\left(\left(-\sqrt{F}\right) \cdot \sqrt{\frac{\left(t\_1 + C\right) + A}{\mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)}}\right) \cdot \sqrt{2}\\ \mathbf{elif}\;t\_3 \leq 0:\\ \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{elif}\;t\_3 \leq \infty:\\ \;\;\;\;\frac{\sqrt{\left(t\_1 + A\right) + C}}{-1} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot t\_0}}{t\_0}\\ \mathbf{else}:\\ \;\;\;\;\left(-{B\_m}^{-0.5}\right) \cdot \sqrt{F \cdot 2}\\ \end{array} \end{array} \]
                    B_m = (fabs.f64 B)
                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                    (FPCore (A B_m C F)
                     :precision binary64
                     (let* ((t_0 (fma -4.0 (* C A) (* B_m B_m)))
                            (t_1 (hypot (- A C) B_m))
                            (t_2 (- (pow B_m 2.0) (* (* 4.0 A) C)))
                            (t_3
                             (/
                              (sqrt
                               (*
                                (* 2.0 (* t_2 F))
                                (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))))
                              (- t_2))))
                       (if (<= t_3 -2e-197)
                         (*
                          (*
                           (- (sqrt F))
                           (sqrt (/ (+ (+ t_1 C) A) (fma (* -4.0 C) A (* B_m B_m)))))
                          (sqrt 2.0))
                         (if (<= t_3 0.0)
                           (* (sqrt (* -0.5 (/ F A))) (- (sqrt 2.0)))
                           (if (<= t_3 INFINITY)
                             (* (/ (sqrt (+ (+ t_1 A) C)) -1.0) (/ (sqrt (* (* 2.0 F) t_0)) t_0))
                             (* (- (pow B_m -0.5)) (sqrt (* F 2.0))))))))
                    B_m = fabs(B);
                    assert(A < B_m && B_m < C && C < F);
                    double code(double A, double B_m, double C, double F) {
                    	double t_0 = fma(-4.0, (C * A), (B_m * B_m));
                    	double t_1 = hypot((A - C), B_m);
                    	double t_2 = pow(B_m, 2.0) - ((4.0 * A) * C);
                    	double t_3 = sqrt(((2.0 * (t_2 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))))) / -t_2;
                    	double tmp;
                    	if (t_3 <= -2e-197) {
                    		tmp = (-sqrt(F) * sqrt((((t_1 + C) + A) / fma((-4.0 * C), A, (B_m * B_m))))) * sqrt(2.0);
                    	} else if (t_3 <= 0.0) {
                    		tmp = sqrt((-0.5 * (F / A))) * -sqrt(2.0);
                    	} else if (t_3 <= ((double) INFINITY)) {
                    		tmp = (sqrt(((t_1 + A) + C)) / -1.0) * (sqrt(((2.0 * F) * t_0)) / t_0);
                    	} else {
                    		tmp = -pow(B_m, -0.5) * sqrt((F * 2.0));
                    	}
                    	return tmp;
                    }
                    
                    B_m = abs(B)
                    A, B_m, C, F = sort([A, B_m, C, F])
                    function code(A, B_m, C, F)
                    	t_0 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
                    	t_1 = hypot(Float64(A - C), B_m)
                    	t_2 = Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C))
                    	t_3 = Float64(sqrt(Float64(Float64(2.0 * Float64(t_2 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))))) / Float64(-t_2))
                    	tmp = 0.0
                    	if (t_3 <= -2e-197)
                    		tmp = Float64(Float64(Float64(-sqrt(F)) * sqrt(Float64(Float64(Float64(t_1 + C) + A) / fma(Float64(-4.0 * C), A, Float64(B_m * B_m))))) * sqrt(2.0));
                    	elseif (t_3 <= 0.0)
                    		tmp = Float64(sqrt(Float64(-0.5 * Float64(F / A))) * Float64(-sqrt(2.0)));
                    	elseif (t_3 <= Inf)
                    		tmp = Float64(Float64(sqrt(Float64(Float64(t_1 + A) + C)) / -1.0) * Float64(sqrt(Float64(Float64(2.0 * F) * t_0)) / t_0));
                    	else
                    		tmp = Float64(Float64(-(B_m ^ -0.5)) * sqrt(Float64(F * 2.0)));
                    	end
                    	return tmp
                    end
                    
                    B_m = N[Abs[B], $MachinePrecision]
                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                    code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision]}, Block[{t$95$2 = N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = N[(N[Sqrt[N[(N[(2.0 * N[(t$95$2 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$2)), $MachinePrecision]}, If[LessEqual[t$95$3, -2e-197], N[(N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(N[(N[(t$95$1 + C), $MachinePrecision] + A), $MachinePrecision] / N[(N[(-4.0 * C), $MachinePrecision] * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$3, 0.0], N[(N[Sqrt[N[(-0.5 * N[(F / A), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[2.0], $MachinePrecision])), $MachinePrecision], If[LessEqual[t$95$3, Infinity], N[(N[(N[Sqrt[N[(N[(t$95$1 + A), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] / -1.0), $MachinePrecision] * N[(N[Sqrt[N[(N[(2.0 * F), $MachinePrecision] * t$95$0), $MachinePrecision]], $MachinePrecision] / t$95$0), $MachinePrecision]), $MachinePrecision], N[((-N[Power[B$95$m, -0.5], $MachinePrecision]) * N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]]]]]
                    
                    \begin{array}{l}
                    B_m = \left|B\right|
                    \\
                    [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                    \\
                    \begin{array}{l}
                    t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
                    t_1 := \mathsf{hypot}\left(A - C, B\_m\right)\\
                    t_2 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\
                    t_3 := \frac{\sqrt{\left(2 \cdot \left(t\_2 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_2}\\
                    \mathbf{if}\;t\_3 \leq -2 \cdot 10^{-197}:\\
                    \;\;\;\;\left(\left(-\sqrt{F}\right) \cdot \sqrt{\frac{\left(t\_1 + C\right) + A}{\mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)}}\right) \cdot \sqrt{2}\\
                    
                    \mathbf{elif}\;t\_3 \leq 0:\\
                    \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\
                    
                    \mathbf{elif}\;t\_3 \leq \infty:\\
                    \;\;\;\;\frac{\sqrt{\left(t\_1 + A\right) + C}}{-1} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot t\_0}}{t\_0}\\
                    
                    \mathbf{else}:\\
                    \;\;\;\;\left(-{B\_m}^{-0.5}\right) \cdot \sqrt{F \cdot 2}\\
                    
                    
                    \end{array}
                    \end{array}
                    
                    Derivation
                    1. Split input into 4 regimes
                    2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -2e-197

                      1. Initial program 37.0%

                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      2. Add Preprocessing
                      3. Taylor expanded in F around 0

                        \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                      4. Step-by-step derivation
                        1. associate-*r*N/A

                          \[\leadsto \color{blue}{\left(-1 \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}\right) \cdot \sqrt{2}} \]
                        2. lower-*.f64N/A

                          \[\leadsto \color{blue}{\left(-1 \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}\right) \cdot \sqrt{2}} \]
                      5. Applied rewrites60.0%

                        \[\leadsto \color{blue}{\left(-\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}\right) \cdot \sqrt{2}} \]
                      6. Step-by-step derivation
                        1. Applied rewrites79.0%

                          \[\leadsto \left(-\sqrt{F} \cdot \sqrt{\frac{\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A}{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}}\right) \cdot \sqrt{2} \]

                        if -2e-197 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -0.0

                        1. Initial program 3.8%

                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        2. Add Preprocessing
                        3. Taylor expanded in F around 0

                          \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                        4. Step-by-step derivation
                          1. associate-*r*N/A

                            \[\leadsto \color{blue}{\left(-1 \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}\right) \cdot \sqrt{2}} \]
                          2. lower-*.f64N/A

                            \[\leadsto \color{blue}{\left(-1 \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}\right) \cdot \sqrt{2}} \]
                        5. Applied rewrites19.3%

                          \[\leadsto \color{blue}{\left(-\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}\right) \cdot \sqrt{2}} \]
                        6. Taylor expanded in A around -inf

                          \[\leadsto \left(-\sqrt{\frac{-1}{2} \cdot \frac{F}{A}}\right) \cdot \sqrt{2} \]
                        7. Step-by-step derivation
                          1. Applied rewrites22.8%

                            \[\leadsto \left(-\sqrt{-0.5 \cdot \frac{F}{A}}\right) \cdot \sqrt{2} \]

                          if -0.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

                          1. Initial program 49.3%

                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          2. Add Preprocessing
                          3. Applied rewrites80.9%

                            \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{-1} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]

                          if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

                          1. Initial program 0.0%

                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          2. Add Preprocessing
                          3. Taylor expanded in B around inf

                            \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                          4. Step-by-step derivation
                            1. mul-1-negN/A

                              \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                            2. lower-neg.f64N/A

                              \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                            3. lower-*.f64N/A

                              \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                            4. lower-sqrt.f64N/A

                              \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                            5. lower-/.f64N/A

                              \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                            6. lower-sqrt.f6423.3

                              \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                          5. Applied rewrites23.3%

                            \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                          6. Step-by-step derivation
                            1. Applied rewrites28.8%

                              \[\leadsto -\sqrt{F} \cdot \sqrt{{B}^{-1} \cdot 2} \]
                            2. Step-by-step derivation
                              1. Applied rewrites28.8%

                                \[\leadsto -{B}^{-0.5} \cdot \sqrt{F \cdot 2} \]
                            3. Recombined 4 regimes into one program.
                            4. Final simplification49.6%

                              \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -2 \cdot 10^{-197}:\\ \;\;\;\;\left(\left(-\sqrt{F}\right) \cdot \sqrt{\frac{\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A}{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}}\right) \cdot \sqrt{2}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq 0:\\ \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq \infty:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{-1} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-{B}^{-0.5}\right) \cdot \sqrt{F \cdot 2}\\ \end{array} \]
                            5. Add Preprocessing

                            Alternative 5: 61.8% accurate, 0.3× speedup?

                            \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\ t_1 := \frac{\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_0}\\ \mathbf{if}\;t\_1 \leq -2 \cdot 10^{-197}:\\ \;\;\;\;\left(\left(-\sqrt{F}\right) \cdot \sqrt{\frac{\left(\mathsf{hypot}\left(A - C, B\_m\right) + C\right) + A}{\mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)}}\right) \cdot \sqrt{2}\\ \mathbf{elif}\;t\_1 \leq 0:\\ \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{elif}\;t\_1 \leq \infty:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)}}{-1} \cdot \left(\left(-0.25 \cdot \frac{\sqrt{2}}{A}\right) \cdot \sqrt{{C}^{-1}}\right)\\ \mathbf{else}:\\ \;\;\;\;\left(-{B\_m}^{-0.5}\right) \cdot \sqrt{F \cdot 2}\\ \end{array} \end{array} \]
                            B_m = (fabs.f64 B)
                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                            (FPCore (A B_m C F)
                             :precision binary64
                             (let* ((t_0 (- (pow B_m 2.0) (* (* 4.0 A) C)))
                                    (t_1
                                     (/
                                      (sqrt
                                       (*
                                        (* 2.0 (* t_0 F))
                                        (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))))
                                      (- t_0))))
                               (if (<= t_1 -2e-197)
                                 (*
                                  (*
                                   (- (sqrt F))
                                   (sqrt
                                    (/ (+ (+ (hypot (- A C) B_m) C) A) (fma (* -4.0 C) A (* B_m B_m)))))
                                  (sqrt 2.0))
                                 (if (<= t_1 0.0)
                                   (* (sqrt (* -0.5 (/ F A))) (- (sqrt 2.0)))
                                   (if (<= t_1 INFINITY)
                                     (*
                                      (/ (sqrt (* (* 2.0 F) (fma -4.0 (* C A) (* B_m B_m)))) -1.0)
                                      (* (* -0.25 (/ (sqrt 2.0) A)) (sqrt (pow C -1.0))))
                                     (* (- (pow B_m -0.5)) (sqrt (* F 2.0))))))))
                            B_m = fabs(B);
                            assert(A < B_m && B_m < C && C < F);
                            double code(double A, double B_m, double C, double F) {
                            	double t_0 = pow(B_m, 2.0) - ((4.0 * A) * C);
                            	double t_1 = sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))))) / -t_0;
                            	double tmp;
                            	if (t_1 <= -2e-197) {
                            		tmp = (-sqrt(F) * sqrt((((hypot((A - C), B_m) + C) + A) / fma((-4.0 * C), A, (B_m * B_m))))) * sqrt(2.0);
                            	} else if (t_1 <= 0.0) {
                            		tmp = sqrt((-0.5 * (F / A))) * -sqrt(2.0);
                            	} else if (t_1 <= ((double) INFINITY)) {
                            		tmp = (sqrt(((2.0 * F) * fma(-4.0, (C * A), (B_m * B_m)))) / -1.0) * ((-0.25 * (sqrt(2.0) / A)) * sqrt(pow(C, -1.0)));
                            	} else {
                            		tmp = -pow(B_m, -0.5) * sqrt((F * 2.0));
                            	}
                            	return tmp;
                            }
                            
                            B_m = abs(B)
                            A, B_m, C, F = sort([A, B_m, C, F])
                            function code(A, B_m, C, F)
                            	t_0 = Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C))
                            	t_1 = Float64(sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))))) / Float64(-t_0))
                            	tmp = 0.0
                            	if (t_1 <= -2e-197)
                            		tmp = Float64(Float64(Float64(-sqrt(F)) * sqrt(Float64(Float64(Float64(hypot(Float64(A - C), B_m) + C) + A) / fma(Float64(-4.0 * C), A, Float64(B_m * B_m))))) * sqrt(2.0));
                            	elseif (t_1 <= 0.0)
                            		tmp = Float64(sqrt(Float64(-0.5 * Float64(F / A))) * Float64(-sqrt(2.0)));
                            	elseif (t_1 <= Inf)
                            		tmp = Float64(Float64(sqrt(Float64(Float64(2.0 * F) * fma(-4.0, Float64(C * A), Float64(B_m * B_m)))) / -1.0) * Float64(Float64(-0.25 * Float64(sqrt(2.0) / A)) * sqrt((C ^ -1.0))));
                            	else
                            		tmp = Float64(Float64(-(B_m ^ -0.5)) * sqrt(Float64(F * 2.0)));
                            	end
                            	return tmp
                            end
                            
                            B_m = N[Abs[B], $MachinePrecision]
                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                            code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision]}, If[LessEqual[t$95$1, -2e-197], N[(N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] + A), $MachinePrecision] / N[(N[(-4.0 * C), $MachinePrecision] * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$1, 0.0], N[(N[Sqrt[N[(-0.5 * N[(F / A), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[2.0], $MachinePrecision])), $MachinePrecision], If[LessEqual[t$95$1, Infinity], N[(N[(N[Sqrt[N[(N[(2.0 * F), $MachinePrecision] * N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / -1.0), $MachinePrecision] * N[(N[(-0.25 * N[(N[Sqrt[2.0], $MachinePrecision] / A), $MachinePrecision]), $MachinePrecision] * N[Sqrt[N[Power[C, -1.0], $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[((-N[Power[B$95$m, -0.5], $MachinePrecision]) * N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]]]
                            
                            \begin{array}{l}
                            B_m = \left|B\right|
                            \\
                            [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                            \\
                            \begin{array}{l}
                            t_0 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\
                            t_1 := \frac{\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_0}\\
                            \mathbf{if}\;t\_1 \leq -2 \cdot 10^{-197}:\\
                            \;\;\;\;\left(\left(-\sqrt{F}\right) \cdot \sqrt{\frac{\left(\mathsf{hypot}\left(A - C, B\_m\right) + C\right) + A}{\mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)}}\right) \cdot \sqrt{2}\\
                            
                            \mathbf{elif}\;t\_1 \leq 0:\\
                            \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\
                            
                            \mathbf{elif}\;t\_1 \leq \infty:\\
                            \;\;\;\;\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)}}{-1} \cdot \left(\left(-0.25 \cdot \frac{\sqrt{2}}{A}\right) \cdot \sqrt{{C}^{-1}}\right)\\
                            
                            \mathbf{else}:\\
                            \;\;\;\;\left(-{B\_m}^{-0.5}\right) \cdot \sqrt{F \cdot 2}\\
                            
                            
                            \end{array}
                            \end{array}
                            
                            Derivation
                            1. Split input into 4 regimes
                            2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -2e-197

                              1. Initial program 37.0%

                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              2. Add Preprocessing
                              3. Taylor expanded in F around 0

                                \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                              4. Step-by-step derivation
                                1. associate-*r*N/A

                                  \[\leadsto \color{blue}{\left(-1 \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}\right) \cdot \sqrt{2}} \]
                                2. lower-*.f64N/A

                                  \[\leadsto \color{blue}{\left(-1 \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}\right) \cdot \sqrt{2}} \]
                              5. Applied rewrites60.0%

                                \[\leadsto \color{blue}{\left(-\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}\right) \cdot \sqrt{2}} \]
                              6. Step-by-step derivation
                                1. Applied rewrites79.0%

                                  \[\leadsto \left(-\sqrt{F} \cdot \sqrt{\frac{\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A}{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}}\right) \cdot \sqrt{2} \]

                                if -2e-197 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -0.0

                                1. Initial program 3.8%

                                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                2. Add Preprocessing
                                3. Taylor expanded in F around 0

                                  \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                4. Step-by-step derivation
                                  1. associate-*r*N/A

                                    \[\leadsto \color{blue}{\left(-1 \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}\right) \cdot \sqrt{2}} \]
                                  2. lower-*.f64N/A

                                    \[\leadsto \color{blue}{\left(-1 \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}\right) \cdot \sqrt{2}} \]
                                5. Applied rewrites19.3%

                                  \[\leadsto \color{blue}{\left(-\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}\right) \cdot \sqrt{2}} \]
                                6. Taylor expanded in A around -inf

                                  \[\leadsto \left(-\sqrt{\frac{-1}{2} \cdot \frac{F}{A}}\right) \cdot \sqrt{2} \]
                                7. Step-by-step derivation
                                  1. Applied rewrites22.8%

                                    \[\leadsto \left(-\sqrt{-0.5 \cdot \frac{F}{A}}\right) \cdot \sqrt{2} \]

                                  if -0.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

                                  1. Initial program 49.3%

                                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                  2. Add Preprocessing
                                  3. Applied rewrites80.7%

                                    \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                                  4. Taylor expanded in A around -inf

                                    \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \color{blue}{\left(\frac{-1}{4} \cdot \left(\frac{\sqrt{2}}{A} \cdot \sqrt{\frac{1}{C}}\right)\right)} \]
                                  5. Step-by-step derivation
                                    1. associate-*r*N/A

                                      \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \color{blue}{\left(\left(\frac{-1}{4} \cdot \frac{\sqrt{2}}{A}\right) \cdot \sqrt{\frac{1}{C}}\right)} \]
                                    2. lower-*.f64N/A

                                      \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \color{blue}{\left(\left(\frac{-1}{4} \cdot \frac{\sqrt{2}}{A}\right) \cdot \sqrt{\frac{1}{C}}\right)} \]
                                    3. lower-*.f64N/A

                                      \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \left(\color{blue}{\left(\frac{-1}{4} \cdot \frac{\sqrt{2}}{A}\right)} \cdot \sqrt{\frac{1}{C}}\right) \]
                                    4. lower-/.f64N/A

                                      \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \left(\left(\frac{-1}{4} \cdot \color{blue}{\frac{\sqrt{2}}{A}}\right) \cdot \sqrt{\frac{1}{C}}\right) \]
                                    5. lower-sqrt.f64N/A

                                      \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \left(\left(\frac{-1}{4} \cdot \frac{\color{blue}{\sqrt{2}}}{A}\right) \cdot \sqrt{\frac{1}{C}}\right) \]
                                    6. lower-sqrt.f64N/A

                                      \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \left(\left(\frac{-1}{4} \cdot \frac{\sqrt{2}}{A}\right) \cdot \color{blue}{\sqrt{\frac{1}{C}}}\right) \]
                                    7. lower-/.f6463.3

                                      \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \left(\left(-0.25 \cdot \frac{\sqrt{2}}{A}\right) \cdot \sqrt{\color{blue}{\frac{1}{C}}}\right) \]
                                  6. Applied rewrites63.3%

                                    \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \color{blue}{\left(\left(-0.25 \cdot \frac{\sqrt{2}}{A}\right) \cdot \sqrt{\frac{1}{C}}\right)} \]

                                  if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

                                  1. Initial program 0.0%

                                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in B around inf

                                    \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                  4. Step-by-step derivation
                                    1. mul-1-negN/A

                                      \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                    2. lower-neg.f64N/A

                                      \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                    3. lower-*.f64N/A

                                      \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                    4. lower-sqrt.f64N/A

                                      \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                    5. lower-/.f64N/A

                                      \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                    6. lower-sqrt.f6423.3

                                      \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                  5. Applied rewrites23.3%

                                    \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                  6. Step-by-step derivation
                                    1. Applied rewrites28.8%

                                      \[\leadsto -\sqrt{F} \cdot \sqrt{{B}^{-1} \cdot 2} \]
                                    2. Step-by-step derivation
                                      1. Applied rewrites28.8%

                                        \[\leadsto -{B}^{-0.5} \cdot \sqrt{F \cdot 2} \]
                                    3. Recombined 4 regimes into one program.
                                    4. Final simplification48.2%

                                      \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -2 \cdot 10^{-197}:\\ \;\;\;\;\left(\left(-\sqrt{F}\right) \cdot \sqrt{\frac{\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A}{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}}\right) \cdot \sqrt{2}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq 0:\\ \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq \infty:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \left(\left(-0.25 \cdot \frac{\sqrt{2}}{A}\right) \cdot \sqrt{{C}^{-1}}\right)\\ \mathbf{else}:\\ \;\;\;\;\left(-{B}^{-0.5}\right) \cdot \sqrt{F \cdot 2}\\ \end{array} \]
                                    5. Add Preprocessing

                                    Alternative 6: 55.7% accurate, 1.3× speedup?

                                    \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 10^{-82}:\\ \;\;\;\;\frac{\sqrt{\left(C + C\right) \cdot \left(\left(t\_0 \cdot 2\right) \cdot F\right)}}{-t\_0}\\ \mathbf{elif}\;{B\_m}^{2} \leq 2 \cdot 10^{+279}:\\ \;\;\;\;\sqrt{F \cdot \frac{\left(\mathsf{hypot}\left(A - C, B\_m\right) + C\right) + A}{t\_0}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\frac{2}{B\_m}} \cdot \left(-\sqrt{F}\right)\\ \end{array} \end{array} \]
                                    B_m = (fabs.f64 B)
                                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                    (FPCore (A B_m C F)
                                     :precision binary64
                                     (let* ((t_0 (fma (* -4.0 C) A (* B_m B_m))))
                                       (if (<= (pow B_m 2.0) 1e-82)
                                         (/ (sqrt (* (+ C C) (* (* t_0 2.0) F))) (- t_0))
                                         (if (<= (pow B_m 2.0) 2e+279)
                                           (* (sqrt (* F (/ (+ (+ (hypot (- A C) B_m) C) A) t_0))) (- (sqrt 2.0)))
                                           (* (sqrt (/ 2.0 B_m)) (- (sqrt F)))))))
                                    B_m = fabs(B);
                                    assert(A < B_m && B_m < C && C < F);
                                    double code(double A, double B_m, double C, double F) {
                                    	double t_0 = fma((-4.0 * C), A, (B_m * B_m));
                                    	double tmp;
                                    	if (pow(B_m, 2.0) <= 1e-82) {
                                    		tmp = sqrt(((C + C) * ((t_0 * 2.0) * F))) / -t_0;
                                    	} else if (pow(B_m, 2.0) <= 2e+279) {
                                    		tmp = sqrt((F * (((hypot((A - C), B_m) + C) + A) / t_0))) * -sqrt(2.0);
                                    	} else {
                                    		tmp = sqrt((2.0 / B_m)) * -sqrt(F);
                                    	}
                                    	return tmp;
                                    }
                                    
                                    B_m = abs(B)
                                    A, B_m, C, F = sort([A, B_m, C, F])
                                    function code(A, B_m, C, F)
                                    	t_0 = fma(Float64(-4.0 * C), A, Float64(B_m * B_m))
                                    	tmp = 0.0
                                    	if ((B_m ^ 2.0) <= 1e-82)
                                    		tmp = Float64(sqrt(Float64(Float64(C + C) * Float64(Float64(t_0 * 2.0) * F))) / Float64(-t_0));
                                    	elseif ((B_m ^ 2.0) <= 2e+279)
                                    		tmp = Float64(sqrt(Float64(F * Float64(Float64(Float64(hypot(Float64(A - C), B_m) + C) + A) / t_0))) * Float64(-sqrt(2.0)));
                                    	else
                                    		tmp = Float64(sqrt(Float64(2.0 / B_m)) * Float64(-sqrt(F)));
                                    	end
                                    	return tmp
                                    end
                                    
                                    B_m = N[Abs[B], $MachinePrecision]
                                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                    code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(-4.0 * C), $MachinePrecision] * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e-82], N[(N[Sqrt[N[(N[(C + C), $MachinePrecision] * N[(N[(t$95$0 * 2.0), $MachinePrecision] * F), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 2e+279], N[(N[Sqrt[N[(F * N[(N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] + A), $MachinePrecision] / t$95$0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[2.0], $MachinePrecision])), $MachinePrecision], N[(N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]]]]
                                    
                                    \begin{array}{l}
                                    B_m = \left|B\right|
                                    \\
                                    [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                    \\
                                    \begin{array}{l}
                                    t_0 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\
                                    \mathbf{if}\;{B\_m}^{2} \leq 10^{-82}:\\
                                    \;\;\;\;\frac{\sqrt{\left(C + C\right) \cdot \left(\left(t\_0 \cdot 2\right) \cdot F\right)}}{-t\_0}\\
                                    
                                    \mathbf{elif}\;{B\_m}^{2} \leq 2 \cdot 10^{+279}:\\
                                    \;\;\;\;\sqrt{F \cdot \frac{\left(\mathsf{hypot}\left(A - C, B\_m\right) + C\right) + A}{t\_0}} \cdot \left(-\sqrt{2}\right)\\
                                    
                                    \mathbf{else}:\\
                                    \;\;\;\;\sqrt{\frac{2}{B\_m}} \cdot \left(-\sqrt{F}\right)\\
                                    
                                    
                                    \end{array}
                                    \end{array}
                                    
                                    Derivation
                                    1. Split input into 3 regimes
                                    2. if (pow.f64 B #s(literal 2 binary64)) < 1e-82

                                      1. Initial program 22.0%

                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                      2. Add Preprocessing
                                      3. Applied rewrites35.7%

                                        \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                                      4. Taylor expanded in B around inf

                                        \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{B \cdot \left(1 + \frac{A}{B}\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                      5. Step-by-step derivation
                                        1. lower-*.f64N/A

                                          \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{B \cdot \left(1 + \frac{A}{B}\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                        2. lower-+.f64N/A

                                          \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{B \cdot \color{blue}{\left(1 + \frac{A}{B}\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                        3. lower-/.f646.3

                                          \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{B \cdot \left(1 + \color{blue}{\frac{A}{B}}\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                      6. Applied rewrites6.3%

                                        \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{B \cdot \left(1 + \frac{A}{B}\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                      7. Applied rewrites7.4%

                                        \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{fma}\left(A, 1, B\right) + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}} \]
                                      8. Taylor expanded in C around inf

                                        \[\leadsto \frac{\sqrt{\left(\color{blue}{C \cdot \left(1 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)} + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                      9. Step-by-step derivation
                                        1. distribute-lft1-inN/A

                                          \[\leadsto \frac{\sqrt{\left(C \cdot \left(1 + \color{blue}{\left(-1 + 1\right) \cdot \frac{A}{C}}\right) + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                        2. metadata-evalN/A

                                          \[\leadsto \frac{\sqrt{\left(C \cdot \left(1 + \color{blue}{0} \cdot \frac{A}{C}\right) + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                        3. mul0-lftN/A

                                          \[\leadsto \frac{\sqrt{\left(C \cdot \left(1 + \color{blue}{0}\right) + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                        4. metadata-evalN/A

                                          \[\leadsto \frac{\sqrt{\left(C \cdot \color{blue}{1} + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                        5. *-rgt-identity27.4

                                          \[\leadsto \frac{\sqrt{\left(\color{blue}{C} + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                      10. Applied rewrites27.4%

                                        \[\leadsto \frac{\sqrt{\left(\color{blue}{C} + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]

                                      if 1e-82 < (pow.f64 B #s(literal 2 binary64)) < 2.00000000000000012e279

                                      1. Initial program 25.8%

                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                      2. Add Preprocessing
                                      3. Taylor expanded in F around 0

                                        \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                      4. Step-by-step derivation
                                        1. associate-*r*N/A

                                          \[\leadsto \color{blue}{\left(-1 \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}\right) \cdot \sqrt{2}} \]
                                        2. lower-*.f64N/A

                                          \[\leadsto \color{blue}{\left(-1 \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}\right) \cdot \sqrt{2}} \]
                                      5. Applied rewrites46.1%

                                        \[\leadsto \color{blue}{\left(-\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}\right) \cdot \sqrt{2}} \]
                                      6. Step-by-step derivation
                                        1. Applied rewrites52.1%

                                          \[\leadsto \left(-\sqrt{F \cdot \frac{\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A}{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}}\right) \cdot \sqrt{2} \]

                                        if 2.00000000000000012e279 < (pow.f64 B #s(literal 2 binary64))

                                        1. Initial program 1.6%

                                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                        2. Add Preprocessing
                                        3. Taylor expanded in B around inf

                                          \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                        4. Step-by-step derivation
                                          1. mul-1-negN/A

                                            \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                          2. lower-neg.f64N/A

                                            \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                          3. lower-*.f64N/A

                                            \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                          4. lower-sqrt.f64N/A

                                            \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                          5. lower-/.f64N/A

                                            \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                          6. lower-sqrt.f6442.0

                                            \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                        5. Applied rewrites42.0%

                                          \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                        6. Step-by-step derivation
                                          1. Applied rewrites50.9%

                                            \[\leadsto -\sqrt{F} \cdot \sqrt{{B}^{-1} \cdot 2} \]
                                          2. Step-by-step derivation
                                            1. Applied rewrites50.9%

                                              \[\leadsto \sqrt{\frac{2}{B}} \cdot \color{blue}{\left(-\sqrt{F}\right)} \]
                                          3. Recombined 3 regimes into one program.
                                          4. Final simplification40.4%

                                            \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 10^{-82}:\\ \;\;\;\;\frac{\sqrt{\left(C + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}\\ \mathbf{elif}\;{B}^{2} \leq 2 \cdot 10^{+279}:\\ \;\;\;\;\sqrt{F \cdot \frac{\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A}{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\frac{2}{B}} \cdot \left(-\sqrt{F}\right)\\ \end{array} \]
                                          5. Add Preprocessing

                                          Alternative 7: 52.7% accurate, 1.3× speedup?

                                          \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 10^{-82}:\\ \;\;\;\;\frac{\sqrt{\left(C + C\right) \cdot \left(\left(t\_0 \cdot 2\right) \cdot F\right)}}{-t\_0}\\ \mathbf{elif}\;{B\_m}^{2} \leq 2 \cdot 10^{+279}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B\_m, C\right) + C\right) \cdot F\right) \cdot 2} \cdot B\_m}{-\mathsf{fma}\left(A \cdot C, -4, B\_m \cdot B\_m\right)}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\frac{2}{B\_m}} \cdot \left(-\sqrt{F}\right)\\ \end{array} \end{array} \]
                                          B_m = (fabs.f64 B)
                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                          (FPCore (A B_m C F)
                                           :precision binary64
                                           (let* ((t_0 (fma (* -4.0 C) A (* B_m B_m))))
                                             (if (<= (pow B_m 2.0) 1e-82)
                                               (/ (sqrt (* (+ C C) (* (* t_0 2.0) F))) (- t_0))
                                               (if (<= (pow B_m 2.0) 2e+279)
                                                 (/
                                                  (* (sqrt (* (* (+ (hypot B_m C) C) F) 2.0)) B_m)
                                                  (- (fma (* A C) -4.0 (* B_m B_m))))
                                                 (* (sqrt (/ 2.0 B_m)) (- (sqrt F)))))))
                                          B_m = fabs(B);
                                          assert(A < B_m && B_m < C && C < F);
                                          double code(double A, double B_m, double C, double F) {
                                          	double t_0 = fma((-4.0 * C), A, (B_m * B_m));
                                          	double tmp;
                                          	if (pow(B_m, 2.0) <= 1e-82) {
                                          		tmp = sqrt(((C + C) * ((t_0 * 2.0) * F))) / -t_0;
                                          	} else if (pow(B_m, 2.0) <= 2e+279) {
                                          		tmp = (sqrt((((hypot(B_m, C) + C) * F) * 2.0)) * B_m) / -fma((A * C), -4.0, (B_m * B_m));
                                          	} else {
                                          		tmp = sqrt((2.0 / B_m)) * -sqrt(F);
                                          	}
                                          	return tmp;
                                          }
                                          
                                          B_m = abs(B)
                                          A, B_m, C, F = sort([A, B_m, C, F])
                                          function code(A, B_m, C, F)
                                          	t_0 = fma(Float64(-4.0 * C), A, Float64(B_m * B_m))
                                          	tmp = 0.0
                                          	if ((B_m ^ 2.0) <= 1e-82)
                                          		tmp = Float64(sqrt(Float64(Float64(C + C) * Float64(Float64(t_0 * 2.0) * F))) / Float64(-t_0));
                                          	elseif ((B_m ^ 2.0) <= 2e+279)
                                          		tmp = Float64(Float64(sqrt(Float64(Float64(Float64(hypot(B_m, C) + C) * F) * 2.0)) * B_m) / Float64(-fma(Float64(A * C), -4.0, Float64(B_m * B_m))));
                                          	else
                                          		tmp = Float64(sqrt(Float64(2.0 / B_m)) * Float64(-sqrt(F)));
                                          	end
                                          	return tmp
                                          end
                                          
                                          B_m = N[Abs[B], $MachinePrecision]
                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                          code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(-4.0 * C), $MachinePrecision] * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e-82], N[(N[Sqrt[N[(N[(C + C), $MachinePrecision] * N[(N[(t$95$0 * 2.0), $MachinePrecision] * F), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 2e+279], N[(N[(N[Sqrt[N[(N[(N[(N[Sqrt[B$95$m ^ 2 + C ^ 2], $MachinePrecision] + C), $MachinePrecision] * F), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] * B$95$m), $MachinePrecision] / (-N[(N[(A * C), $MachinePrecision] * -4.0 + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision])), $MachinePrecision], N[(N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]]]]
                                          
                                          \begin{array}{l}
                                          B_m = \left|B\right|
                                          \\
                                          [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                          \\
                                          \begin{array}{l}
                                          t_0 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\
                                          \mathbf{if}\;{B\_m}^{2} \leq 10^{-82}:\\
                                          \;\;\;\;\frac{\sqrt{\left(C + C\right) \cdot \left(\left(t\_0 \cdot 2\right) \cdot F\right)}}{-t\_0}\\
                                          
                                          \mathbf{elif}\;{B\_m}^{2} \leq 2 \cdot 10^{+279}:\\
                                          \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B\_m, C\right) + C\right) \cdot F\right) \cdot 2} \cdot B\_m}{-\mathsf{fma}\left(A \cdot C, -4, B\_m \cdot B\_m\right)}\\
                                          
                                          \mathbf{else}:\\
                                          \;\;\;\;\sqrt{\frac{2}{B\_m}} \cdot \left(-\sqrt{F}\right)\\
                                          
                                          
                                          \end{array}
                                          \end{array}
                                          
                                          Derivation
                                          1. Split input into 3 regimes
                                          2. if (pow.f64 B #s(literal 2 binary64)) < 1e-82

                                            1. Initial program 22.0%

                                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            2. Add Preprocessing
                                            3. Applied rewrites35.7%

                                              \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                                            4. Taylor expanded in B around inf

                                              \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{B \cdot \left(1 + \frac{A}{B}\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                            5. Step-by-step derivation
                                              1. lower-*.f64N/A

                                                \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{B \cdot \left(1 + \frac{A}{B}\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                              2. lower-+.f64N/A

                                                \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{B \cdot \color{blue}{\left(1 + \frac{A}{B}\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                              3. lower-/.f646.3

                                                \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{B \cdot \left(1 + \color{blue}{\frac{A}{B}}\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                            6. Applied rewrites6.3%

                                              \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{B \cdot \left(1 + \frac{A}{B}\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                            7. Applied rewrites7.4%

                                              \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{fma}\left(A, 1, B\right) + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}} \]
                                            8. Taylor expanded in C around inf

                                              \[\leadsto \frac{\sqrt{\left(\color{blue}{C \cdot \left(1 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)} + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                            9. Step-by-step derivation
                                              1. distribute-lft1-inN/A

                                                \[\leadsto \frac{\sqrt{\left(C \cdot \left(1 + \color{blue}{\left(-1 + 1\right) \cdot \frac{A}{C}}\right) + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                              2. metadata-evalN/A

                                                \[\leadsto \frac{\sqrt{\left(C \cdot \left(1 + \color{blue}{0} \cdot \frac{A}{C}\right) + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                              3. mul0-lftN/A

                                                \[\leadsto \frac{\sqrt{\left(C \cdot \left(1 + \color{blue}{0}\right) + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                              4. metadata-evalN/A

                                                \[\leadsto \frac{\sqrt{\left(C \cdot \color{blue}{1} + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                              5. *-rgt-identity27.4

                                                \[\leadsto \frac{\sqrt{\left(\color{blue}{C} + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                            10. Applied rewrites27.4%

                                              \[\leadsto \frac{\sqrt{\left(\color{blue}{C} + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]

                                            if 1e-82 < (pow.f64 B #s(literal 2 binary64)) < 2.00000000000000012e279

                                            1. Initial program 25.8%

                                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            2. Add Preprocessing
                                            3. Taylor expanded in A around 0

                                              \[\leadsto \frac{-\color{blue}{\left(B \cdot \sqrt{2}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            4. Step-by-step derivation
                                              1. lower-*.f64N/A

                                                \[\leadsto \frac{-\color{blue}{\left(B \cdot \sqrt{2}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              2. *-commutativeN/A

                                                \[\leadsto \frac{-\color{blue}{\left(\sqrt{2} \cdot B\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              3. lower-*.f64N/A

                                                \[\leadsto \frac{-\color{blue}{\left(\sqrt{2} \cdot B\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              4. lower-sqrt.f64N/A

                                                \[\leadsto \frac{-\left(\color{blue}{\sqrt{2}} \cdot B\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              5. lower-sqrt.f64N/A

                                                \[\leadsto \frac{-\left(\sqrt{2} \cdot B\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              6. *-commutativeN/A

                                                \[\leadsto \frac{-\left(\sqrt{2} \cdot B\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              7. lower-*.f64N/A

                                                \[\leadsto \frac{-\left(\sqrt{2} \cdot B\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              8. +-commutativeN/A

                                                \[\leadsto \frac{-\left(\sqrt{2} \cdot B\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              9. lower-+.f64N/A

                                                \[\leadsto \frac{-\left(\sqrt{2} \cdot B\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              10. +-commutativeN/A

                                                \[\leadsto \frac{-\left(\sqrt{2} \cdot B\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              11. unpow2N/A

                                                \[\leadsto \frac{-\left(\sqrt{2} \cdot B\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              12. unpow2N/A

                                                \[\leadsto \frac{-\left(\sqrt{2} \cdot B\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              13. lower-hypot.f6419.4

                                                \[\leadsto \frac{-\left(\sqrt{2} \cdot B\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            5. Applied rewrites19.4%

                                              \[\leadsto \frac{-\color{blue}{\left(\sqrt{2} \cdot B\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            6. Step-by-step derivation
                                              1. Applied rewrites19.5%

                                                \[\leadsto \color{blue}{\frac{-\sqrt{\left(\left(\mathsf{hypot}\left(B, C\right) + C\right) \cdot F\right) \cdot 2} \cdot B}{\mathsf{fma}\left(A \cdot C, -4, B \cdot B\right)}} \]

                                              if 2.00000000000000012e279 < (pow.f64 B #s(literal 2 binary64))

                                              1. Initial program 1.6%

                                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              2. Add Preprocessing
                                              3. Taylor expanded in B around inf

                                                \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                              4. Step-by-step derivation
                                                1. mul-1-negN/A

                                                  \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                2. lower-neg.f64N/A

                                                  \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                3. lower-*.f64N/A

                                                  \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                4. lower-sqrt.f64N/A

                                                  \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                5. lower-/.f64N/A

                                                  \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                6. lower-sqrt.f6442.0

                                                  \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                              5. Applied rewrites42.0%

                                                \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                              6. Step-by-step derivation
                                                1. Applied rewrites50.9%

                                                  \[\leadsto -\sqrt{F} \cdot \sqrt{{B}^{-1} \cdot 2} \]
                                                2. Step-by-step derivation
                                                  1. Applied rewrites50.9%

                                                    \[\leadsto \sqrt{\frac{2}{B}} \cdot \color{blue}{\left(-\sqrt{F}\right)} \]
                                                3. Recombined 3 regimes into one program.
                                                4. Final simplification32.0%

                                                  \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 10^{-82}:\\ \;\;\;\;\frac{\sqrt{\left(C + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}\\ \mathbf{elif}\;{B}^{2} \leq 2 \cdot 10^{+279}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(B, C\right) + C\right) \cdot F\right) \cdot 2} \cdot B}{-\mathsf{fma}\left(A \cdot C, -4, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\frac{2}{B}} \cdot \left(-\sqrt{F}\right)\\ \end{array} \]
                                                5. Add Preprocessing

                                                Alternative 8: 50.1% accurate, 2.7× speedup?

                                                \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 5 \cdot 10^{+177}:\\ \;\;\;\;\frac{\sqrt{\left(C + C\right) \cdot \left(\left(t\_0 \cdot 2\right) \cdot F\right)}}{-t\_0}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\frac{2}{B\_m}} \cdot \left(-\sqrt{F}\right)\\ \end{array} \end{array} \]
                                                B_m = (fabs.f64 B)
                                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                (FPCore (A B_m C F)
                                                 :precision binary64
                                                 (let* ((t_0 (fma (* -4.0 C) A (* B_m B_m))))
                                                   (if (<= (pow B_m 2.0) 5e+177)
                                                     (/ (sqrt (* (+ C C) (* (* t_0 2.0) F))) (- t_0))
                                                     (* (sqrt (/ 2.0 B_m)) (- (sqrt F))))))
                                                B_m = fabs(B);
                                                assert(A < B_m && B_m < C && C < F);
                                                double code(double A, double B_m, double C, double F) {
                                                	double t_0 = fma((-4.0 * C), A, (B_m * B_m));
                                                	double tmp;
                                                	if (pow(B_m, 2.0) <= 5e+177) {
                                                		tmp = sqrt(((C + C) * ((t_0 * 2.0) * F))) / -t_0;
                                                	} else {
                                                		tmp = sqrt((2.0 / B_m)) * -sqrt(F);
                                                	}
                                                	return tmp;
                                                }
                                                
                                                B_m = abs(B)
                                                A, B_m, C, F = sort([A, B_m, C, F])
                                                function code(A, B_m, C, F)
                                                	t_0 = fma(Float64(-4.0 * C), A, Float64(B_m * B_m))
                                                	tmp = 0.0
                                                	if ((B_m ^ 2.0) <= 5e+177)
                                                		tmp = Float64(sqrt(Float64(Float64(C + C) * Float64(Float64(t_0 * 2.0) * F))) / Float64(-t_0));
                                                	else
                                                		tmp = Float64(sqrt(Float64(2.0 / B_m)) * Float64(-sqrt(F)));
                                                	end
                                                	return tmp
                                                end
                                                
                                                B_m = N[Abs[B], $MachinePrecision]
                                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(-4.0 * C), $MachinePrecision] * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 5e+177], N[(N[Sqrt[N[(N[(C + C), $MachinePrecision] * N[(N[(t$95$0 * 2.0), $MachinePrecision] * F), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], N[(N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]]]
                                                
                                                \begin{array}{l}
                                                B_m = \left|B\right|
                                                \\
                                                [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                \\
                                                \begin{array}{l}
                                                t_0 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\
                                                \mathbf{if}\;{B\_m}^{2} \leq 5 \cdot 10^{+177}:\\
                                                \;\;\;\;\frac{\sqrt{\left(C + C\right) \cdot \left(\left(t\_0 \cdot 2\right) \cdot F\right)}}{-t\_0}\\
                                                
                                                \mathbf{else}:\\
                                                \;\;\;\;\sqrt{\frac{2}{B\_m}} \cdot \left(-\sqrt{F}\right)\\
                                                
                                                
                                                \end{array}
                                                \end{array}
                                                
                                                Derivation
                                                1. Split input into 2 regimes
                                                2. if (pow.f64 B #s(literal 2 binary64)) < 5.0000000000000003e177

                                                  1. Initial program 23.5%

                                                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                  2. Add Preprocessing
                                                  3. Applied rewrites37.6%

                                                    \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                                                  4. Taylor expanded in B around inf

                                                    \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{B \cdot \left(1 + \frac{A}{B}\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                  5. Step-by-step derivation
                                                    1. lower-*.f64N/A

                                                      \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{B \cdot \left(1 + \frac{A}{B}\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                    2. lower-+.f64N/A

                                                      \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{B \cdot \color{blue}{\left(1 + \frac{A}{B}\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                    3. lower-/.f648.9

                                                      \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{B \cdot \left(1 + \color{blue}{\frac{A}{B}}\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                  6. Applied rewrites8.9%

                                                    \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{B \cdot \left(1 + \frac{A}{B}\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                  7. Applied rewrites9.8%

                                                    \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{fma}\left(A, 1, B\right) + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}} \]
                                                  8. Taylor expanded in C around inf

                                                    \[\leadsto \frac{\sqrt{\left(\color{blue}{C \cdot \left(1 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)} + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                                  9. Step-by-step derivation
                                                    1. distribute-lft1-inN/A

                                                      \[\leadsto \frac{\sqrt{\left(C \cdot \left(1 + \color{blue}{\left(-1 + 1\right) \cdot \frac{A}{C}}\right) + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                                    2. metadata-evalN/A

                                                      \[\leadsto \frac{\sqrt{\left(C \cdot \left(1 + \color{blue}{0} \cdot \frac{A}{C}\right) + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                                    3. mul0-lftN/A

                                                      \[\leadsto \frac{\sqrt{\left(C \cdot \left(1 + \color{blue}{0}\right) + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                                    4. metadata-evalN/A

                                                      \[\leadsto \frac{\sqrt{\left(C \cdot \color{blue}{1} + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                                    5. *-rgt-identity24.0

                                                      \[\leadsto \frac{\sqrt{\left(\color{blue}{C} + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                                  10. Applied rewrites24.0%

                                                    \[\leadsto \frac{\sqrt{\left(\color{blue}{C} + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]

                                                  if 5.0000000000000003e177 < (pow.f64 B #s(literal 2 binary64))

                                                  1. Initial program 6.0%

                                                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                  2. Add Preprocessing
                                                  3. Taylor expanded in B around inf

                                                    \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                  4. Step-by-step derivation
                                                    1. mul-1-negN/A

                                                      \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                    2. lower-neg.f64N/A

                                                      \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                    3. lower-*.f64N/A

                                                      \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                    4. lower-sqrt.f64N/A

                                                      \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                    5. lower-/.f64N/A

                                                      \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                    6. lower-sqrt.f6435.5

                                                      \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                  5. Applied rewrites35.5%

                                                    \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                  6. Step-by-step derivation
                                                    1. Applied rewrites42.4%

                                                      \[\leadsto -\sqrt{F} \cdot \sqrt{{B}^{-1} \cdot 2} \]
                                                    2. Step-by-step derivation
                                                      1. Applied rewrites42.4%

                                                        \[\leadsto \sqrt{\frac{2}{B}} \cdot \color{blue}{\left(-\sqrt{F}\right)} \]
                                                    3. Recombined 2 regimes into one program.
                                                    4. Add Preprocessing

                                                    Alternative 9: 52.3% accurate, 2.9× speedup?

                                                    \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;B\_m \leq 9 \cdot 10^{+49}:\\ \;\;\;\;\frac{\sqrt{\left(C + C\right) \cdot \left(\left(t\_0 \cdot 2\right) \cdot F\right)}}{-t\_0}\\ \mathbf{elif}\;B\_m \leq 4.6 \cdot 10^{+155}:\\ \;\;\;\;\sqrt{\frac{F}{B\_m} \cdot \frac{\mathsf{hypot}\left(C, B\_m\right) + C}{B\_m}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{else}:\\ \;\;\;\;\left(-{B\_m}^{-0.5}\right) \cdot \sqrt{F \cdot 2}\\ \end{array} \end{array} \]
                                                    B_m = (fabs.f64 B)
                                                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                    (FPCore (A B_m C F)
                                                     :precision binary64
                                                     (let* ((t_0 (fma (* -4.0 C) A (* B_m B_m))))
                                                       (if (<= B_m 9e+49)
                                                         (/ (sqrt (* (+ C C) (* (* t_0 2.0) F))) (- t_0))
                                                         (if (<= B_m 4.6e+155)
                                                           (* (sqrt (* (/ F B_m) (/ (+ (hypot C B_m) C) B_m))) (- (sqrt 2.0)))
                                                           (* (- (pow B_m -0.5)) (sqrt (* F 2.0)))))))
                                                    B_m = fabs(B);
                                                    assert(A < B_m && B_m < C && C < F);
                                                    double code(double A, double B_m, double C, double F) {
                                                    	double t_0 = fma((-4.0 * C), A, (B_m * B_m));
                                                    	double tmp;
                                                    	if (B_m <= 9e+49) {
                                                    		tmp = sqrt(((C + C) * ((t_0 * 2.0) * F))) / -t_0;
                                                    	} else if (B_m <= 4.6e+155) {
                                                    		tmp = sqrt(((F / B_m) * ((hypot(C, B_m) + C) / B_m))) * -sqrt(2.0);
                                                    	} else {
                                                    		tmp = -pow(B_m, -0.5) * sqrt((F * 2.0));
                                                    	}
                                                    	return tmp;
                                                    }
                                                    
                                                    B_m = abs(B)
                                                    A, B_m, C, F = sort([A, B_m, C, F])
                                                    function code(A, B_m, C, F)
                                                    	t_0 = fma(Float64(-4.0 * C), A, Float64(B_m * B_m))
                                                    	tmp = 0.0
                                                    	if (B_m <= 9e+49)
                                                    		tmp = Float64(sqrt(Float64(Float64(C + C) * Float64(Float64(t_0 * 2.0) * F))) / Float64(-t_0));
                                                    	elseif (B_m <= 4.6e+155)
                                                    		tmp = Float64(sqrt(Float64(Float64(F / B_m) * Float64(Float64(hypot(C, B_m) + C) / B_m))) * Float64(-sqrt(2.0)));
                                                    	else
                                                    		tmp = Float64(Float64(-(B_m ^ -0.5)) * sqrt(Float64(F * 2.0)));
                                                    	end
                                                    	return tmp
                                                    end
                                                    
                                                    B_m = N[Abs[B], $MachinePrecision]
                                                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                    code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(-4.0 * C), $MachinePrecision] * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[B$95$m, 9e+49], N[(N[Sqrt[N[(N[(C + C), $MachinePrecision] * N[(N[(t$95$0 * 2.0), $MachinePrecision] * F), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], If[LessEqual[B$95$m, 4.6e+155], N[(N[Sqrt[N[(N[(F / B$95$m), $MachinePrecision] * N[(N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] / B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[2.0], $MachinePrecision])), $MachinePrecision], N[((-N[Power[B$95$m, -0.5], $MachinePrecision]) * N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]
                                                    
                                                    \begin{array}{l}
                                                    B_m = \left|B\right|
                                                    \\
                                                    [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                    \\
                                                    \begin{array}{l}
                                                    t_0 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\
                                                    \mathbf{if}\;B\_m \leq 9 \cdot 10^{+49}:\\
                                                    \;\;\;\;\frac{\sqrt{\left(C + C\right) \cdot \left(\left(t\_0 \cdot 2\right) \cdot F\right)}}{-t\_0}\\
                                                    
                                                    \mathbf{elif}\;B\_m \leq 4.6 \cdot 10^{+155}:\\
                                                    \;\;\;\;\sqrt{\frac{F}{B\_m} \cdot \frac{\mathsf{hypot}\left(C, B\_m\right) + C}{B\_m}} \cdot \left(-\sqrt{2}\right)\\
                                                    
                                                    \mathbf{else}:\\
                                                    \;\;\;\;\left(-{B\_m}^{-0.5}\right) \cdot \sqrt{F \cdot 2}\\
                                                    
                                                    
                                                    \end{array}
                                                    \end{array}
                                                    
                                                    Derivation
                                                    1. Split input into 3 regimes
                                                    2. if B < 8.99999999999999965e49

                                                      1. Initial program 21.6%

                                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      2. Add Preprocessing
                                                      3. Applied rewrites34.2%

                                                        \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                                                      4. Taylor expanded in B around inf

                                                        \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{B \cdot \left(1 + \frac{A}{B}\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                      5. Step-by-step derivation
                                                        1. lower-*.f64N/A

                                                          \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{B \cdot \left(1 + \frac{A}{B}\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                        2. lower-+.f64N/A

                                                          \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{B \cdot \color{blue}{\left(1 + \frac{A}{B}\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                        3. lower-/.f647.3

                                                          \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{B \cdot \left(1 + \color{blue}{\frac{A}{B}}\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                      6. Applied rewrites7.3%

                                                        \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{B \cdot \left(1 + \frac{A}{B}\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                      7. Applied rewrites7.8%

                                                        \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{fma}\left(A, 1, B\right) + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}} \]
                                                      8. Taylor expanded in C around inf

                                                        \[\leadsto \frac{\sqrt{\left(\color{blue}{C \cdot \left(1 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)} + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                                      9. Step-by-step derivation
                                                        1. distribute-lft1-inN/A

                                                          \[\leadsto \frac{\sqrt{\left(C \cdot \left(1 + \color{blue}{\left(-1 + 1\right) \cdot \frac{A}{C}}\right) + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                                        2. metadata-evalN/A

                                                          \[\leadsto \frac{\sqrt{\left(C \cdot \left(1 + \color{blue}{0} \cdot \frac{A}{C}\right) + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                                        3. mul0-lftN/A

                                                          \[\leadsto \frac{\sqrt{\left(C \cdot \left(1 + \color{blue}{0}\right) + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                                        4. metadata-evalN/A

                                                          \[\leadsto \frac{\sqrt{\left(C \cdot \color{blue}{1} + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                                        5. *-rgt-identity18.6

                                                          \[\leadsto \frac{\sqrt{\left(\color{blue}{C} + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                                      10. Applied rewrites18.6%

                                                        \[\leadsto \frac{\sqrt{\left(\color{blue}{C} + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]

                                                      if 8.99999999999999965e49 < B < 4.59999999999999996e155

                                                      1. Initial program 8.3%

                                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      2. Add Preprocessing
                                                      3. Taylor expanded in F around 0

                                                        \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                                      4. Step-by-step derivation
                                                        1. associate-*r*N/A

                                                          \[\leadsto \color{blue}{\left(-1 \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}\right) \cdot \sqrt{2}} \]
                                                        2. lower-*.f64N/A

                                                          \[\leadsto \color{blue}{\left(-1 \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}\right) \cdot \sqrt{2}} \]
                                                      5. Applied rewrites55.3%

                                                        \[\leadsto \color{blue}{\left(-\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}\right) \cdot \sqrt{2}} \]
                                                      6. Taylor expanded in A around 0

                                                        \[\leadsto \left(-\sqrt{\frac{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}{{B}^{2}}}\right) \cdot \sqrt{2} \]
                                                      7. Step-by-step derivation
                                                        1. Applied rewrites66.1%

                                                          \[\leadsto \left(-\sqrt{\frac{F}{B} \cdot \frac{\mathsf{hypot}\left(C, B\right) + C}{B}}\right) \cdot \sqrt{2} \]

                                                        if 4.59999999999999996e155 < B

                                                        1. Initial program 0.0%

                                                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                        2. Add Preprocessing
                                                        3. Taylor expanded in B around inf

                                                          \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                        4. Step-by-step derivation
                                                          1. mul-1-negN/A

                                                            \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                          2. lower-neg.f64N/A

                                                            \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                          3. lower-*.f64N/A

                                                            \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                          4. lower-sqrt.f64N/A

                                                            \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                          5. lower-/.f64N/A

                                                            \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                          6. lower-sqrt.f6462.9

                                                            \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                        5. Applied rewrites62.9%

                                                          \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                        6. Step-by-step derivation
                                                          1. Applied rewrites79.4%

                                                            \[\leadsto -\sqrt{F} \cdot \sqrt{{B}^{-1} \cdot 2} \]
                                                          2. Step-by-step derivation
                                                            1. Applied rewrites79.4%

                                                              \[\leadsto -{B}^{-0.5} \cdot \sqrt{F \cdot 2} \]
                                                          3. Recombined 3 regimes into one program.
                                                          4. Final simplification31.5%

                                                            \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 9 \cdot 10^{+49}:\\ \;\;\;\;\frac{\sqrt{\left(C + C\right) \cdot \left(\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2\right) \cdot F\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}\\ \mathbf{elif}\;B \leq 4.6 \cdot 10^{+155}:\\ \;\;\;\;\sqrt{\frac{F}{B} \cdot \frac{\mathsf{hypot}\left(C, B\right) + C}{B}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{else}:\\ \;\;\;\;\left(-{B}^{-0.5}\right) \cdot \sqrt{F \cdot 2}\\ \end{array} \]
                                                          5. Add Preprocessing

                                                          Alternative 10: 47.0% accurate, 9.8× speedup?

                                                          \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;B\_m \leq 6 \cdot 10^{+88}:\\ \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\frac{2}{B\_m}} \cdot \left(-\sqrt{F}\right)\\ \end{array} \end{array} \]
                                                          B_m = (fabs.f64 B)
                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                          (FPCore (A B_m C F)
                                                           :precision binary64
                                                           (if (<= B_m 6e+88)
                                                             (* (sqrt (* -0.5 (/ F A))) (- (sqrt 2.0)))
                                                             (* (sqrt (/ 2.0 B_m)) (- (sqrt F)))))
                                                          B_m = fabs(B);
                                                          assert(A < B_m && B_m < C && C < F);
                                                          double code(double A, double B_m, double C, double F) {
                                                          	double tmp;
                                                          	if (B_m <= 6e+88) {
                                                          		tmp = sqrt((-0.5 * (F / A))) * -sqrt(2.0);
                                                          	} else {
                                                          		tmp = sqrt((2.0 / B_m)) * -sqrt(F);
                                                          	}
                                                          	return tmp;
                                                          }
                                                          
                                                          B_m = abs(b)
                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                          real(8) function code(a, b_m, c, f)
                                                              real(8), intent (in) :: a
                                                              real(8), intent (in) :: b_m
                                                              real(8), intent (in) :: c
                                                              real(8), intent (in) :: f
                                                              real(8) :: tmp
                                                              if (b_m <= 6d+88) then
                                                                  tmp = sqrt(((-0.5d0) * (f / a))) * -sqrt(2.0d0)
                                                              else
                                                                  tmp = sqrt((2.0d0 / b_m)) * -sqrt(f)
                                                              end if
                                                              code = tmp
                                                          end function
                                                          
                                                          B_m = Math.abs(B);
                                                          assert A < B_m && B_m < C && C < F;
                                                          public static double code(double A, double B_m, double C, double F) {
                                                          	double tmp;
                                                          	if (B_m <= 6e+88) {
                                                          		tmp = Math.sqrt((-0.5 * (F / A))) * -Math.sqrt(2.0);
                                                          	} else {
                                                          		tmp = Math.sqrt((2.0 / B_m)) * -Math.sqrt(F);
                                                          	}
                                                          	return tmp;
                                                          }
                                                          
                                                          B_m = math.fabs(B)
                                                          [A, B_m, C, F] = sort([A, B_m, C, F])
                                                          def code(A, B_m, C, F):
                                                          	tmp = 0
                                                          	if B_m <= 6e+88:
                                                          		tmp = math.sqrt((-0.5 * (F / A))) * -math.sqrt(2.0)
                                                          	else:
                                                          		tmp = math.sqrt((2.0 / B_m)) * -math.sqrt(F)
                                                          	return tmp
                                                          
                                                          B_m = abs(B)
                                                          A, B_m, C, F = sort([A, B_m, C, F])
                                                          function code(A, B_m, C, F)
                                                          	tmp = 0.0
                                                          	if (B_m <= 6e+88)
                                                          		tmp = Float64(sqrt(Float64(-0.5 * Float64(F / A))) * Float64(-sqrt(2.0)));
                                                          	else
                                                          		tmp = Float64(sqrt(Float64(2.0 / B_m)) * Float64(-sqrt(F)));
                                                          	end
                                                          	return tmp
                                                          end
                                                          
                                                          B_m = abs(B);
                                                          A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                          function tmp_2 = code(A, B_m, C, F)
                                                          	tmp = 0.0;
                                                          	if (B_m <= 6e+88)
                                                          		tmp = sqrt((-0.5 * (F / A))) * -sqrt(2.0);
                                                          	else
                                                          		tmp = sqrt((2.0 / B_m)) * -sqrt(F);
                                                          	end
                                                          	tmp_2 = tmp;
                                                          end
                                                          
                                                          B_m = N[Abs[B], $MachinePrecision]
                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                          code[A_, B$95$m_, C_, F_] := If[LessEqual[B$95$m, 6e+88], N[(N[Sqrt[N[(-0.5 * N[(F / A), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[2.0], $MachinePrecision])), $MachinePrecision], N[(N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]]
                                                          
                                                          \begin{array}{l}
                                                          B_m = \left|B\right|
                                                          \\
                                                          [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                          \\
                                                          \begin{array}{l}
                                                          \mathbf{if}\;B\_m \leq 6 \cdot 10^{+88}:\\
                                                          \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\
                                                          
                                                          \mathbf{else}:\\
                                                          \;\;\;\;\sqrt{\frac{2}{B\_m}} \cdot \left(-\sqrt{F}\right)\\
                                                          
                                                          
                                                          \end{array}
                                                          \end{array}
                                                          
                                                          Derivation
                                                          1. Split input into 2 regimes
                                                          2. if B < 6.00000000000000011e88

                                                            1. Initial program 21.7%

                                                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                            2. Add Preprocessing
                                                            3. Taylor expanded in F around 0

                                                              \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                                            4. Step-by-step derivation
                                                              1. associate-*r*N/A

                                                                \[\leadsto \color{blue}{\left(-1 \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}\right) \cdot \sqrt{2}} \]
                                                              2. lower-*.f64N/A

                                                                \[\leadsto \color{blue}{\left(-1 \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}\right) \cdot \sqrt{2}} \]
                                                            5. Applied rewrites27.3%

                                                              \[\leadsto \color{blue}{\left(-\sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}\right) \cdot \sqrt{2}} \]
                                                            6. Taylor expanded in A around -inf

                                                              \[\leadsto \left(-\sqrt{\frac{-1}{2} \cdot \frac{F}{A}}\right) \cdot \sqrt{2} \]
                                                            7. Step-by-step derivation
                                                              1. Applied rewrites14.3%

                                                                \[\leadsto \left(-\sqrt{-0.5 \cdot \frac{F}{A}}\right) \cdot \sqrt{2} \]

                                                              if 6.00000000000000011e88 < B

                                                              1. Initial program 0.6%

                                                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                              2. Add Preprocessing
                                                              3. Taylor expanded in B around inf

                                                                \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                              4. Step-by-step derivation
                                                                1. mul-1-negN/A

                                                                  \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                2. lower-neg.f64N/A

                                                                  \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                3. lower-*.f64N/A

                                                                  \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                4. lower-sqrt.f64N/A

                                                                  \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                5. lower-/.f64N/A

                                                                  \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                6. lower-sqrt.f6459.6

                                                                  \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                              5. Applied rewrites59.6%

                                                                \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                              6. Step-by-step derivation
                                                                1. Applied rewrites72.3%

                                                                  \[\leadsto -\sqrt{F} \cdot \sqrt{{B}^{-1} \cdot 2} \]
                                                                2. Step-by-step derivation
                                                                  1. Applied rewrites72.3%

                                                                    \[\leadsto \sqrt{\frac{2}{B}} \cdot \color{blue}{\left(-\sqrt{F}\right)} \]
                                                                3. Recombined 2 regimes into one program.
                                                                4. Final simplification26.6%

                                                                  \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 6 \cdot 10^{+88}:\\ \;\;\;\;\sqrt{-0.5 \cdot \frac{F}{A}} \cdot \left(-\sqrt{2}\right)\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\frac{2}{B}} \cdot \left(-\sqrt{F}\right)\\ \end{array} \]
                                                                5. Add Preprocessing

                                                                Alternative 11: 36.0% accurate, 12.6× speedup?

                                                                \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \sqrt{\frac{2}{B\_m}} \cdot \left(-\sqrt{F}\right) \end{array} \]
                                                                B_m = (fabs.f64 B)
                                                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                (FPCore (A B_m C F) :precision binary64 (* (sqrt (/ 2.0 B_m)) (- (sqrt F))))
                                                                B_m = fabs(B);
                                                                assert(A < B_m && B_m < C && C < F);
                                                                double code(double A, double B_m, double C, double F) {
                                                                	return sqrt((2.0 / B_m)) * -sqrt(F);
                                                                }
                                                                
                                                                B_m = abs(b)
                                                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                real(8) function code(a, b_m, c, f)
                                                                    real(8), intent (in) :: a
                                                                    real(8), intent (in) :: b_m
                                                                    real(8), intent (in) :: c
                                                                    real(8), intent (in) :: f
                                                                    code = sqrt((2.0d0 / b_m)) * -sqrt(f)
                                                                end function
                                                                
                                                                B_m = Math.abs(B);
                                                                assert A < B_m && B_m < C && C < F;
                                                                public static double code(double A, double B_m, double C, double F) {
                                                                	return Math.sqrt((2.0 / B_m)) * -Math.sqrt(F);
                                                                }
                                                                
                                                                B_m = math.fabs(B)
                                                                [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                def code(A, B_m, C, F):
                                                                	return math.sqrt((2.0 / B_m)) * -math.sqrt(F)
                                                                
                                                                B_m = abs(B)
                                                                A, B_m, C, F = sort([A, B_m, C, F])
                                                                function code(A, B_m, C, F)
                                                                	return Float64(sqrt(Float64(2.0 / B_m)) * Float64(-sqrt(F)))
                                                                end
                                                                
                                                                B_m = abs(B);
                                                                A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                function tmp = code(A, B_m, C, F)
                                                                	tmp = sqrt((2.0 / B_m)) * -sqrt(F);
                                                                end
                                                                
                                                                B_m = N[Abs[B], $MachinePrecision]
                                                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                code[A_, B$95$m_, C_, F_] := N[(N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]
                                                                
                                                                \begin{array}{l}
                                                                B_m = \left|B\right|
                                                                \\
                                                                [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                \\
                                                                \sqrt{\frac{2}{B\_m}} \cdot \left(-\sqrt{F}\right)
                                                                \end{array}
                                                                
                                                                Derivation
                                                                1. Initial program 17.2%

                                                                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                2. Add Preprocessing
                                                                3. Taylor expanded in B around inf

                                                                  \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                4. Step-by-step derivation
                                                                  1. mul-1-negN/A

                                                                    \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                  2. lower-neg.f64N/A

                                                                    \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                  3. lower-*.f64N/A

                                                                    \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                  4. lower-sqrt.f64N/A

                                                                    \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                  5. lower-/.f64N/A

                                                                    \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                  6. lower-sqrt.f6416.6

                                                                    \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                                5. Applied rewrites16.6%

                                                                  \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                6. Step-by-step derivation
                                                                  1. Applied rewrites19.0%

                                                                    \[\leadsto -\sqrt{F} \cdot \sqrt{{B}^{-1} \cdot 2} \]
                                                                  2. Step-by-step derivation
                                                                    1. Applied rewrites19.0%

                                                                      \[\leadsto \sqrt{\frac{2}{B}} \cdot \color{blue}{\left(-\sqrt{F}\right)} \]
                                                                    2. Add Preprocessing

                                                                    Alternative 12: 36.0% accurate, 12.6× speedup?

                                                                    \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \frac{\sqrt{F \cdot 2}}{-\sqrt{B\_m}} \end{array} \]
                                                                    B_m = (fabs.f64 B)
                                                                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                    (FPCore (A B_m C F) :precision binary64 (/ (sqrt (* F 2.0)) (- (sqrt B_m))))
                                                                    B_m = fabs(B);
                                                                    assert(A < B_m && B_m < C && C < F);
                                                                    double code(double A, double B_m, double C, double F) {
                                                                    	return sqrt((F * 2.0)) / -sqrt(B_m);
                                                                    }
                                                                    
                                                                    B_m = abs(b)
                                                                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                    real(8) function code(a, b_m, c, f)
                                                                        real(8), intent (in) :: a
                                                                        real(8), intent (in) :: b_m
                                                                        real(8), intent (in) :: c
                                                                        real(8), intent (in) :: f
                                                                        code = sqrt((f * 2.0d0)) / -sqrt(b_m)
                                                                    end function
                                                                    
                                                                    B_m = Math.abs(B);
                                                                    assert A < B_m && B_m < C && C < F;
                                                                    public static double code(double A, double B_m, double C, double F) {
                                                                    	return Math.sqrt((F * 2.0)) / -Math.sqrt(B_m);
                                                                    }
                                                                    
                                                                    B_m = math.fabs(B)
                                                                    [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                    def code(A, B_m, C, F):
                                                                    	return math.sqrt((F * 2.0)) / -math.sqrt(B_m)
                                                                    
                                                                    B_m = abs(B)
                                                                    A, B_m, C, F = sort([A, B_m, C, F])
                                                                    function code(A, B_m, C, F)
                                                                    	return Float64(sqrt(Float64(F * 2.0)) / Float64(-sqrt(B_m)))
                                                                    end
                                                                    
                                                                    B_m = abs(B);
                                                                    A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                    function tmp = code(A, B_m, C, F)
                                                                    	tmp = sqrt((F * 2.0)) / -sqrt(B_m);
                                                                    end
                                                                    
                                                                    B_m = N[Abs[B], $MachinePrecision]
                                                                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                    code[A_, B$95$m_, C_, F_] := N[(N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision] / (-N[Sqrt[B$95$m], $MachinePrecision])), $MachinePrecision]
                                                                    
                                                                    \begin{array}{l}
                                                                    B_m = \left|B\right|
                                                                    \\
                                                                    [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                    \\
                                                                    \frac{\sqrt{F \cdot 2}}{-\sqrt{B\_m}}
                                                                    \end{array}
                                                                    
                                                                    Derivation
                                                                    1. Initial program 17.2%

                                                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                    2. Add Preprocessing
                                                                    3. Taylor expanded in B around inf

                                                                      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                    4. Step-by-step derivation
                                                                      1. mul-1-negN/A

                                                                        \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                      2. lower-neg.f64N/A

                                                                        \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                      3. lower-*.f64N/A

                                                                        \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                      4. lower-sqrt.f64N/A

                                                                        \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                      5. lower-/.f64N/A

                                                                        \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                      6. lower-sqrt.f6416.6

                                                                        \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                                    5. Applied rewrites16.6%

                                                                      \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                    6. Step-by-step derivation
                                                                      1. Applied rewrites19.0%

                                                                        \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
                                                                      2. Final simplification19.0%

                                                                        \[\leadsto \frac{\sqrt{F \cdot 2}}{-\sqrt{B}} \]
                                                                      3. Add Preprocessing

                                                                      Alternative 13: 36.0% accurate, 12.6× speedup?

                                                                      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \frac{-\sqrt{F}}{\sqrt{B\_m \cdot 0.5}} \end{array} \]
                                                                      B_m = (fabs.f64 B)
                                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                      (FPCore (A B_m C F) :precision binary64 (/ (- (sqrt F)) (sqrt (* B_m 0.5))))
                                                                      B_m = fabs(B);
                                                                      assert(A < B_m && B_m < C && C < F);
                                                                      double code(double A, double B_m, double C, double F) {
                                                                      	return -sqrt(F) / sqrt((B_m * 0.5));
                                                                      }
                                                                      
                                                                      B_m = abs(b)
                                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                      real(8) function code(a, b_m, c, f)
                                                                          real(8), intent (in) :: a
                                                                          real(8), intent (in) :: b_m
                                                                          real(8), intent (in) :: c
                                                                          real(8), intent (in) :: f
                                                                          code = -sqrt(f) / sqrt((b_m * 0.5d0))
                                                                      end function
                                                                      
                                                                      B_m = Math.abs(B);
                                                                      assert A < B_m && B_m < C && C < F;
                                                                      public static double code(double A, double B_m, double C, double F) {
                                                                      	return -Math.sqrt(F) / Math.sqrt((B_m * 0.5));
                                                                      }
                                                                      
                                                                      B_m = math.fabs(B)
                                                                      [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                      def code(A, B_m, C, F):
                                                                      	return -math.sqrt(F) / math.sqrt((B_m * 0.5))
                                                                      
                                                                      B_m = abs(B)
                                                                      A, B_m, C, F = sort([A, B_m, C, F])
                                                                      function code(A, B_m, C, F)
                                                                      	return Float64(Float64(-sqrt(F)) / sqrt(Float64(B_m * 0.5)))
                                                                      end
                                                                      
                                                                      B_m = abs(B);
                                                                      A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                      function tmp = code(A, B_m, C, F)
                                                                      	tmp = -sqrt(F) / sqrt((B_m * 0.5));
                                                                      end
                                                                      
                                                                      B_m = N[Abs[B], $MachinePrecision]
                                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                      code[A_, B$95$m_, C_, F_] := N[((-N[Sqrt[F], $MachinePrecision]) / N[Sqrt[N[(B$95$m * 0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
                                                                      
                                                                      \begin{array}{l}
                                                                      B_m = \left|B\right|
                                                                      \\
                                                                      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                      \\
                                                                      \frac{-\sqrt{F}}{\sqrt{B\_m \cdot 0.5}}
                                                                      \end{array}
                                                                      
                                                                      Derivation
                                                                      1. Initial program 17.2%

                                                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                      2. Add Preprocessing
                                                                      3. Taylor expanded in B around inf

                                                                        \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                      4. Step-by-step derivation
                                                                        1. mul-1-negN/A

                                                                          \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                        2. lower-neg.f64N/A

                                                                          \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                        3. lower-*.f64N/A

                                                                          \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                        4. lower-sqrt.f64N/A

                                                                          \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                        5. lower-/.f64N/A

                                                                          \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                        6. lower-sqrt.f6416.6

                                                                          \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                                      5. Applied rewrites16.6%

                                                                        \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                      6. Step-by-step derivation
                                                                        1. Applied rewrites16.7%

                                                                          \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                        2. Step-by-step derivation
                                                                          1. Applied rewrites16.7%

                                                                            \[\leadsto -\sqrt{\frac{2}{B} \cdot F} \]
                                                                          2. Step-by-step derivation
                                                                            1. Applied rewrites19.1%

                                                                              \[\leadsto -\frac{\sqrt{F}}{\sqrt{B \cdot 0.5}} \]
                                                                            2. Final simplification19.1%

                                                                              \[\leadsto \frac{-\sqrt{F}}{\sqrt{B \cdot 0.5}} \]
                                                                            3. Add Preprocessing

                                                                            Alternative 14: 27.9% accurate, 16.9× speedup?

                                                                            \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ -\sqrt{\frac{2}{B\_m} \cdot F} \end{array} \]
                                                                            B_m = (fabs.f64 B)
                                                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                            (FPCore (A B_m C F) :precision binary64 (- (sqrt (* (/ 2.0 B_m) F))))
                                                                            B_m = fabs(B);
                                                                            assert(A < B_m && B_m < C && C < F);
                                                                            double code(double A, double B_m, double C, double F) {
                                                                            	return -sqrt(((2.0 / B_m) * F));
                                                                            }
                                                                            
                                                                            B_m = abs(b)
                                                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                            real(8) function code(a, b_m, c, f)
                                                                                real(8), intent (in) :: a
                                                                                real(8), intent (in) :: b_m
                                                                                real(8), intent (in) :: c
                                                                                real(8), intent (in) :: f
                                                                                code = -sqrt(((2.0d0 / b_m) * f))
                                                                            end function
                                                                            
                                                                            B_m = Math.abs(B);
                                                                            assert A < B_m && B_m < C && C < F;
                                                                            public static double code(double A, double B_m, double C, double F) {
                                                                            	return -Math.sqrt(((2.0 / B_m) * F));
                                                                            }
                                                                            
                                                                            B_m = math.fabs(B)
                                                                            [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                            def code(A, B_m, C, F):
                                                                            	return -math.sqrt(((2.0 / B_m) * F))
                                                                            
                                                                            B_m = abs(B)
                                                                            A, B_m, C, F = sort([A, B_m, C, F])
                                                                            function code(A, B_m, C, F)
                                                                            	return Float64(-sqrt(Float64(Float64(2.0 / B_m) * F)))
                                                                            end
                                                                            
                                                                            B_m = abs(B);
                                                                            A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                            function tmp = code(A, B_m, C, F)
                                                                            	tmp = -sqrt(((2.0 / B_m) * F));
                                                                            end
                                                                            
                                                                            B_m = N[Abs[B], $MachinePrecision]
                                                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                            code[A_, B$95$m_, C_, F_] := (-N[Sqrt[N[(N[(2.0 / B$95$m), $MachinePrecision] * F), $MachinePrecision]], $MachinePrecision])
                                                                            
                                                                            \begin{array}{l}
                                                                            B_m = \left|B\right|
                                                                            \\
                                                                            [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                            \\
                                                                            -\sqrt{\frac{2}{B\_m} \cdot F}
                                                                            \end{array}
                                                                            
                                                                            Derivation
                                                                            1. Initial program 17.2%

                                                                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                            2. Add Preprocessing
                                                                            3. Taylor expanded in B around inf

                                                                              \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                            4. Step-by-step derivation
                                                                              1. mul-1-negN/A

                                                                                \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                              2. lower-neg.f64N/A

                                                                                \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                              3. lower-*.f64N/A

                                                                                \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                              4. lower-sqrt.f64N/A

                                                                                \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                              5. lower-/.f64N/A

                                                                                \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                              6. lower-sqrt.f6416.6

                                                                                \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                                            5. Applied rewrites16.6%

                                                                              \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                            6. Step-by-step derivation
                                                                              1. Applied rewrites16.7%

                                                                                \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                              2. Step-by-step derivation
                                                                                1. Applied rewrites16.7%

                                                                                  \[\leadsto -\sqrt{\frac{2}{B} \cdot F} \]
                                                                                2. Add Preprocessing

                                                                                Reproduce

                                                                                ?
                                                                                herbie shell --seed 2024313 
                                                                                (FPCore (A B C F)
                                                                                  :name "ABCF->ab-angle a"
                                                                                  :precision binary64
                                                                                  (/ (- (sqrt (* (* 2.0 (* (- (pow B 2.0) (* (* 4.0 A) C)) F)) (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))) (- (pow B 2.0) (* (* 4.0 A) C))))