Toniolo and Linder, Equation (3a)

Percentage Accurate: 98.6% → 98.7%
Time: 9.5s
Alternatives: 5
Speedup: 0.7×

Specification

?
\[\begin{array}{l} \\ \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \end{array} \]
(FPCore (l Om kx ky)
 :precision binary64
 (sqrt
  (*
   (/ 1.0 2.0)
   (+
    1.0
    (/
     1.0
     (sqrt
      (+
       1.0
       (*
        (pow (/ (* 2.0 l) Om) 2.0)
        (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0))))))))))
double code(double l, double Om, double kx, double ky) {
	return sqrt(((1.0 / 2.0) * (1.0 + (1.0 / sqrt((1.0 + (pow(((2.0 * l) / Om), 2.0) * (pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))))))));
}
real(8) function code(l, om, kx, ky)
    real(8), intent (in) :: l
    real(8), intent (in) :: om
    real(8), intent (in) :: kx
    real(8), intent (in) :: ky
    code = sqrt(((1.0d0 / 2.0d0) * (1.0d0 + (1.0d0 / sqrt((1.0d0 + ((((2.0d0 * l) / om) ** 2.0d0) * ((sin(kx) ** 2.0d0) + (sin(ky) ** 2.0d0)))))))))
end function
public static double code(double l, double Om, double kx, double ky) {
	return Math.sqrt(((1.0 / 2.0) * (1.0 + (1.0 / Math.sqrt((1.0 + (Math.pow(((2.0 * l) / Om), 2.0) * (Math.pow(Math.sin(kx), 2.0) + Math.pow(Math.sin(ky), 2.0)))))))));
}
def code(l, Om, kx, ky):
	return math.sqrt(((1.0 / 2.0) * (1.0 + (1.0 / math.sqrt((1.0 + (math.pow(((2.0 * l) / Om), 2.0) * (math.pow(math.sin(kx), 2.0) + math.pow(math.sin(ky), 2.0)))))))))
function code(l, Om, kx, ky)
	return sqrt(Float64(Float64(1.0 / 2.0) * Float64(1.0 + Float64(1.0 / sqrt(Float64(1.0 + Float64((Float64(Float64(2.0 * l) / Om) ^ 2.0) * Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))))))))
end
function tmp = code(l, Om, kx, ky)
	tmp = sqrt(((1.0 / 2.0) * (1.0 + (1.0 / sqrt((1.0 + ((((2.0 * l) / Om) ^ 2.0) * ((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))))))));
end
code[l_, Om_, kx_, ky_] := N[Sqrt[N[(N[(1.0 / 2.0), $MachinePrecision] * N[(1.0 + N[(1.0 / N[Sqrt[N[(1.0 + N[(N[Power[N[(N[(2.0 * l), $MachinePrecision] / Om), $MachinePrecision], 2.0], $MachinePrecision] * N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 5 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 98.6% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \end{array} \]
(FPCore (l Om kx ky)
 :precision binary64
 (sqrt
  (*
   (/ 1.0 2.0)
   (+
    1.0
    (/
     1.0
     (sqrt
      (+
       1.0
       (*
        (pow (/ (* 2.0 l) Om) 2.0)
        (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0))))))))))
double code(double l, double Om, double kx, double ky) {
	return sqrt(((1.0 / 2.0) * (1.0 + (1.0 / sqrt((1.0 + (pow(((2.0 * l) / Om), 2.0) * (pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))))))));
}
real(8) function code(l, om, kx, ky)
    real(8), intent (in) :: l
    real(8), intent (in) :: om
    real(8), intent (in) :: kx
    real(8), intent (in) :: ky
    code = sqrt(((1.0d0 / 2.0d0) * (1.0d0 + (1.0d0 / sqrt((1.0d0 + ((((2.0d0 * l) / om) ** 2.0d0) * ((sin(kx) ** 2.0d0) + (sin(ky) ** 2.0d0)))))))))
end function
public static double code(double l, double Om, double kx, double ky) {
	return Math.sqrt(((1.0 / 2.0) * (1.0 + (1.0 / Math.sqrt((1.0 + (Math.pow(((2.0 * l) / Om), 2.0) * (Math.pow(Math.sin(kx), 2.0) + Math.pow(Math.sin(ky), 2.0)))))))));
}
def code(l, Om, kx, ky):
	return math.sqrt(((1.0 / 2.0) * (1.0 + (1.0 / math.sqrt((1.0 + (math.pow(((2.0 * l) / Om), 2.0) * (math.pow(math.sin(kx), 2.0) + math.pow(math.sin(ky), 2.0)))))))))
function code(l, Om, kx, ky)
	return sqrt(Float64(Float64(1.0 / 2.0) * Float64(1.0 + Float64(1.0 / sqrt(Float64(1.0 + Float64((Float64(Float64(2.0 * l) / Om) ^ 2.0) * Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))))))))
end
function tmp = code(l, Om, kx, ky)
	tmp = sqrt(((1.0 / 2.0) * (1.0 + (1.0 / sqrt((1.0 + ((((2.0 * l) / Om) ^ 2.0) * ((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))))))));
end
code[l_, Om_, kx_, ky_] := N[Sqrt[N[(N[(1.0 / 2.0), $MachinePrecision] * N[(1.0 + N[(1.0 / N[Sqrt[N[(1.0 + N[(N[Power[N[(N[(2.0 * l), $MachinePrecision] / Om), $MachinePrecision], 2.0], $MachinePrecision] * N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)}
\end{array}

Alternative 1: 98.7% accurate, 0.7× speedup?

\[\begin{array}{l} ky_m = \left|ky\right| \\ kx_m = \left|kx\right| \\ Om_m = \left|Om\right| \\ l_m = \left|\ell\right| \\ [l_m, Om_m, kx_m, ky_m] = \mathsf{sort}([l_m, Om_m, kx_m, ky_m])\\ \\ \begin{array}{l} \mathbf{if}\;{\left(\frac{2 \cdot l\_m}{Om\_m}\right)}^{2} \cdot \left({\sin kx\_m}^{2} + {\sin ky\_m}^{2}\right) \leq 50000:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(\sqrt{{\left(\mathsf{fma}\left(\frac{1 - \cos \left(ky\_m \cdot 2\right)}{Om\_m \cdot 2} \cdot \left(\frac{l\_m}{Om\_m} \cdot l\_m\right), 4, 1\right)\right)}^{-1}}, 0.5, 0.5\right)}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(\frac{Om\_m}{ky\_m \cdot l\_m}, 0.25, 0.5\right)}\\ \end{array} \end{array} \]
ky_m = (fabs.f64 ky)
kx_m = (fabs.f64 kx)
Om_m = (fabs.f64 Om)
l_m = (fabs.f64 l)
NOTE: l_m, Om_m, kx_m, and ky_m should be sorted in increasing order before calling this function.
(FPCore (l_m Om_m kx_m ky_m)
 :precision binary64
 (if (<=
      (*
       (pow (/ (* 2.0 l_m) Om_m) 2.0)
       (+ (pow (sin kx_m) 2.0) (pow (sin ky_m) 2.0)))
      50000.0)
   (sqrt
    (fma
     (sqrt
      (pow
       (fma
        (* (/ (- 1.0 (cos (* ky_m 2.0))) (* Om_m 2.0)) (* (/ l_m Om_m) l_m))
        4.0
        1.0)
       -1.0))
     0.5
     0.5))
   (sqrt (fma (/ Om_m (* ky_m l_m)) 0.25 0.5))))
ky_m = fabs(ky);
kx_m = fabs(kx);
Om_m = fabs(Om);
l_m = fabs(l);
assert(l_m < Om_m && Om_m < kx_m && kx_m < ky_m);
double code(double l_m, double Om_m, double kx_m, double ky_m) {
	double tmp;
	if ((pow(((2.0 * l_m) / Om_m), 2.0) * (pow(sin(kx_m), 2.0) + pow(sin(ky_m), 2.0))) <= 50000.0) {
		tmp = sqrt(fma(sqrt(pow(fma((((1.0 - cos((ky_m * 2.0))) / (Om_m * 2.0)) * ((l_m / Om_m) * l_m)), 4.0, 1.0), -1.0)), 0.5, 0.5));
	} else {
		tmp = sqrt(fma((Om_m / (ky_m * l_m)), 0.25, 0.5));
	}
	return tmp;
}
ky_m = abs(ky)
kx_m = abs(kx)
Om_m = abs(Om)
l_m = abs(l)
l_m, Om_m, kx_m, ky_m = sort([l_m, Om_m, kx_m, ky_m])
function code(l_m, Om_m, kx_m, ky_m)
	tmp = 0.0
	if (Float64((Float64(Float64(2.0 * l_m) / Om_m) ^ 2.0) * Float64((sin(kx_m) ^ 2.0) + (sin(ky_m) ^ 2.0))) <= 50000.0)
		tmp = sqrt(fma(sqrt((fma(Float64(Float64(Float64(1.0 - cos(Float64(ky_m * 2.0))) / Float64(Om_m * 2.0)) * Float64(Float64(l_m / Om_m) * l_m)), 4.0, 1.0) ^ -1.0)), 0.5, 0.5));
	else
		tmp = sqrt(fma(Float64(Om_m / Float64(ky_m * l_m)), 0.25, 0.5));
	end
	return tmp
end
ky_m = N[Abs[ky], $MachinePrecision]
kx_m = N[Abs[kx], $MachinePrecision]
Om_m = N[Abs[Om], $MachinePrecision]
l_m = N[Abs[l], $MachinePrecision]
NOTE: l_m, Om_m, kx_m, and ky_m should be sorted in increasing order before calling this function.
code[l$95$m_, Om$95$m_, kx$95$m_, ky$95$m_] := If[LessEqual[N[(N[Power[N[(N[(2.0 * l$95$m), $MachinePrecision] / Om$95$m), $MachinePrecision], 2.0], $MachinePrecision] * N[(N[Power[N[Sin[kx$95$m], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky$95$m], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 50000.0], N[Sqrt[N[(N[Sqrt[N[Power[N[(N[(N[(N[(1.0 - N[Cos[N[(ky$95$m * 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / N[(Om$95$m * 2.0), $MachinePrecision]), $MachinePrecision] * N[(N[(l$95$m / Om$95$m), $MachinePrecision] * l$95$m), $MachinePrecision]), $MachinePrecision] * 4.0 + 1.0), $MachinePrecision], -1.0], $MachinePrecision]], $MachinePrecision] * 0.5 + 0.5), $MachinePrecision]], $MachinePrecision], N[Sqrt[N[(N[(Om$95$m / N[(ky$95$m * l$95$m), $MachinePrecision]), $MachinePrecision] * 0.25 + 0.5), $MachinePrecision]], $MachinePrecision]]
\begin{array}{l}
ky_m = \left|ky\right|
\\
kx_m = \left|kx\right|
\\
Om_m = \left|Om\right|
\\
l_m = \left|\ell\right|
\\
[l_m, Om_m, kx_m, ky_m] = \mathsf{sort}([l_m, Om_m, kx_m, ky_m])\\
\\
\begin{array}{l}
\mathbf{if}\;{\left(\frac{2 \cdot l\_m}{Om\_m}\right)}^{2} \cdot \left({\sin kx\_m}^{2} + {\sin ky\_m}^{2}\right) \leq 50000:\\
\;\;\;\;\sqrt{\mathsf{fma}\left(\sqrt{{\left(\mathsf{fma}\left(\frac{1 - \cos \left(ky\_m \cdot 2\right)}{Om\_m \cdot 2} \cdot \left(\frac{l\_m}{Om\_m} \cdot l\_m\right), 4, 1\right)\right)}^{-1}}, 0.5, 0.5\right)}\\

\mathbf{else}:\\
\;\;\;\;\sqrt{\mathsf{fma}\left(\frac{Om\_m}{ky\_m \cdot l\_m}, 0.25, 0.5\right)}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))) < 5e4

    1. Initial program 100.0%

      \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in kx around 0

      \[\leadsto \sqrt{\color{blue}{\frac{1}{2} \cdot \left(1 + \sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}}\right)}} \]
    4. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto \sqrt{\frac{1}{2} \cdot \color{blue}{\left(\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} + 1\right)}} \]
      2. distribute-rgt-inN/A

        \[\leadsto \sqrt{\color{blue}{\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} \cdot \frac{1}{2} + 1 \cdot \frac{1}{2}}} \]
      3. metadata-evalN/A

        \[\leadsto \sqrt{\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} \cdot \frac{1}{2} + \color{blue}{\frac{1}{2}}} \]
      4. lower-fma.f64N/A

        \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}}, \frac{1}{2}, \frac{1}{2}\right)}} \]
    5. Applied rewrites95.8%

      \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\sqrt{\frac{1}{\mathsf{fma}\left(\frac{{\sin ky}^{2}}{Om} \cdot \frac{\ell \cdot \ell}{Om}, 4, 1\right)}}, 0.5, 0.5\right)}} \]
    6. Step-by-step derivation
      1. Applied rewrites100.0%

        \[\leadsto \sqrt{\mathsf{fma}\left(\sqrt{\frac{1}{\mathsf{fma}\left(\frac{{\sin ky}^{2}}{Om} \cdot \left(\frac{\ell}{Om} \cdot \ell\right), 4, 1\right)}}, 0.5, 0.5\right)} \]
      2. Step-by-step derivation
        1. Applied rewrites100.0%

          \[\leadsto \sqrt{\mathsf{fma}\left(\sqrt{\frac{1}{\mathsf{fma}\left(\frac{1 - \cos \left(ky \cdot 2\right)}{Om \cdot 2} \cdot \left(\frac{\ell}{Om} \cdot \ell\right), 4, 1\right)}}, 0.5, 0.5\right)} \]

        if 5e4 < (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))

        1. Initial program 95.8%

          \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
        2. Add Preprocessing
        3. Taylor expanded in kx around 0

          \[\leadsto \sqrt{\color{blue}{\frac{1}{2} \cdot \left(1 + \sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}}\right)}} \]
        4. Step-by-step derivation
          1. +-commutativeN/A

            \[\leadsto \sqrt{\frac{1}{2} \cdot \color{blue}{\left(\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} + 1\right)}} \]
          2. distribute-rgt-inN/A

            \[\leadsto \sqrt{\color{blue}{\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} \cdot \frac{1}{2} + 1 \cdot \frac{1}{2}}} \]
          3. metadata-evalN/A

            \[\leadsto \sqrt{\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} \cdot \frac{1}{2} + \color{blue}{\frac{1}{2}}} \]
          4. lower-fma.f64N/A

            \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}}, \frac{1}{2}, \frac{1}{2}\right)}} \]
        5. Applied rewrites76.2%

          \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\sqrt{\frac{1}{\mathsf{fma}\left(\frac{{\sin ky}^{2}}{Om} \cdot \frac{\ell \cdot \ell}{Om}, 4, 1\right)}}, 0.5, 0.5\right)}} \]
        6. Taylor expanded in l around inf

          \[\leadsto \sqrt{\frac{1}{2} + \color{blue}{\frac{1}{4} \cdot \frac{Om}{\ell \cdot \sin ky}}} \]
        7. Step-by-step derivation
          1. Applied rewrites85.4%

            \[\leadsto \sqrt{\mathsf{fma}\left(\frac{Om}{\sin ky \cdot \ell}, \color{blue}{0.25}, 0.5\right)} \]
          2. Taylor expanded in ky around 0

            \[\leadsto \sqrt{\mathsf{fma}\left(\frac{Om}{ky \cdot \ell}, \frac{1}{4}, \frac{1}{2}\right)} \]
          3. Step-by-step derivation
            1. Applied rewrites85.5%

              \[\leadsto \sqrt{\mathsf{fma}\left(\frac{Om}{ky \cdot \ell}, 0.25, 0.5\right)} \]
          4. Recombined 2 regimes into one program.
          5. Final simplification93.2%

            \[\leadsto \begin{array}{l} \mathbf{if}\;{\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right) \leq 50000:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(\sqrt{{\left(\mathsf{fma}\left(\frac{1 - \cos \left(ky \cdot 2\right)}{Om \cdot 2} \cdot \left(\frac{\ell}{Om} \cdot \ell\right), 4, 1\right)\right)}^{-1}}, 0.5, 0.5\right)}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(\frac{Om}{ky \cdot \ell}, 0.25, 0.5\right)}\\ \end{array} \]
          6. Add Preprocessing

          Alternative 2: 97.8% accurate, 1.0× speedup?

          \[\begin{array}{l} ky_m = \left|ky\right| \\ kx_m = \left|kx\right| \\ Om_m = \left|Om\right| \\ l_m = \left|\ell\right| \\ [l_m, Om_m, kx_m, ky_m] = \mathsf{sort}([l_m, Om_m, kx_m, ky_m])\\ \\ \begin{array}{l} \mathbf{if}\;{\left(\frac{2 \cdot l\_m}{Om\_m}\right)}^{2} \cdot \left({\sin kx\_m}^{2} + {\sin ky\_m}^{2}\right) \leq 10^{-20}:\\ \;\;\;\;\sqrt{1}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(\frac{Om\_m}{ky\_m \cdot l\_m}, 0.25, 0.5\right)}\\ \end{array} \end{array} \]
          ky_m = (fabs.f64 ky)
          kx_m = (fabs.f64 kx)
          Om_m = (fabs.f64 Om)
          l_m = (fabs.f64 l)
          NOTE: l_m, Om_m, kx_m, and ky_m should be sorted in increasing order before calling this function.
          (FPCore (l_m Om_m kx_m ky_m)
           :precision binary64
           (if (<=
                (*
                 (pow (/ (* 2.0 l_m) Om_m) 2.0)
                 (+ (pow (sin kx_m) 2.0) (pow (sin ky_m) 2.0)))
                1e-20)
             (sqrt 1.0)
             (sqrt (fma (/ Om_m (* ky_m l_m)) 0.25 0.5))))
          ky_m = fabs(ky);
          kx_m = fabs(kx);
          Om_m = fabs(Om);
          l_m = fabs(l);
          assert(l_m < Om_m && Om_m < kx_m && kx_m < ky_m);
          double code(double l_m, double Om_m, double kx_m, double ky_m) {
          	double tmp;
          	if ((pow(((2.0 * l_m) / Om_m), 2.0) * (pow(sin(kx_m), 2.0) + pow(sin(ky_m), 2.0))) <= 1e-20) {
          		tmp = sqrt(1.0);
          	} else {
          		tmp = sqrt(fma((Om_m / (ky_m * l_m)), 0.25, 0.5));
          	}
          	return tmp;
          }
          
          ky_m = abs(ky)
          kx_m = abs(kx)
          Om_m = abs(Om)
          l_m = abs(l)
          l_m, Om_m, kx_m, ky_m = sort([l_m, Om_m, kx_m, ky_m])
          function code(l_m, Om_m, kx_m, ky_m)
          	tmp = 0.0
          	if (Float64((Float64(Float64(2.0 * l_m) / Om_m) ^ 2.0) * Float64((sin(kx_m) ^ 2.0) + (sin(ky_m) ^ 2.0))) <= 1e-20)
          		tmp = sqrt(1.0);
          	else
          		tmp = sqrt(fma(Float64(Om_m / Float64(ky_m * l_m)), 0.25, 0.5));
          	end
          	return tmp
          end
          
          ky_m = N[Abs[ky], $MachinePrecision]
          kx_m = N[Abs[kx], $MachinePrecision]
          Om_m = N[Abs[Om], $MachinePrecision]
          l_m = N[Abs[l], $MachinePrecision]
          NOTE: l_m, Om_m, kx_m, and ky_m should be sorted in increasing order before calling this function.
          code[l$95$m_, Om$95$m_, kx$95$m_, ky$95$m_] := If[LessEqual[N[(N[Power[N[(N[(2.0 * l$95$m), $MachinePrecision] / Om$95$m), $MachinePrecision], 2.0], $MachinePrecision] * N[(N[Power[N[Sin[kx$95$m], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky$95$m], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 1e-20], N[Sqrt[1.0], $MachinePrecision], N[Sqrt[N[(N[(Om$95$m / N[(ky$95$m * l$95$m), $MachinePrecision]), $MachinePrecision] * 0.25 + 0.5), $MachinePrecision]], $MachinePrecision]]
          
          \begin{array}{l}
          ky_m = \left|ky\right|
          \\
          kx_m = \left|kx\right|
          \\
          Om_m = \left|Om\right|
          \\
          l_m = \left|\ell\right|
          \\
          [l_m, Om_m, kx_m, ky_m] = \mathsf{sort}([l_m, Om_m, kx_m, ky_m])\\
          \\
          \begin{array}{l}
          \mathbf{if}\;{\left(\frac{2 \cdot l\_m}{Om\_m}\right)}^{2} \cdot \left({\sin kx\_m}^{2} + {\sin ky\_m}^{2}\right) \leq 10^{-20}:\\
          \;\;\;\;\sqrt{1}\\
          
          \mathbf{else}:\\
          \;\;\;\;\sqrt{\mathsf{fma}\left(\frac{Om\_m}{ky\_m \cdot l\_m}, 0.25, 0.5\right)}\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))) < 9.99999999999999945e-21

            1. Initial program 100.0%

              \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
            2. Add Preprocessing
            3. Taylor expanded in l around 0

              \[\leadsto \sqrt{\color{blue}{1}} \]
            4. Step-by-step derivation
              1. Applied rewrites100.0%

                \[\leadsto \sqrt{\color{blue}{1}} \]

              if 9.99999999999999945e-21 < (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))

              1. Initial program 95.9%

                \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
              2. Add Preprocessing
              3. Taylor expanded in kx around 0

                \[\leadsto \sqrt{\color{blue}{\frac{1}{2} \cdot \left(1 + \sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}}\right)}} \]
              4. Step-by-step derivation
                1. +-commutativeN/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \color{blue}{\left(\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} + 1\right)}} \]
                2. distribute-rgt-inN/A

                  \[\leadsto \sqrt{\color{blue}{\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} \cdot \frac{1}{2} + 1 \cdot \frac{1}{2}}} \]
                3. metadata-evalN/A

                  \[\leadsto \sqrt{\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} \cdot \frac{1}{2} + \color{blue}{\frac{1}{2}}} \]
                4. lower-fma.f64N/A

                  \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}}, \frac{1}{2}, \frac{1}{2}\right)}} \]
              5. Applied rewrites75.8%

                \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\sqrt{\frac{1}{\mathsf{fma}\left(\frac{{\sin ky}^{2}}{Om} \cdot \frac{\ell \cdot \ell}{Om}, 4, 1\right)}}, 0.5, 0.5\right)}} \]
              6. Taylor expanded in l around inf

                \[\leadsto \sqrt{\frac{1}{2} + \color{blue}{\frac{1}{4} \cdot \frac{Om}{\ell \cdot \sin ky}}} \]
              7. Step-by-step derivation
                1. Applied rewrites85.1%

                  \[\leadsto \sqrt{\mathsf{fma}\left(\frac{Om}{\sin ky \cdot \ell}, \color{blue}{0.25}, 0.5\right)} \]
                2. Taylor expanded in ky around 0

                  \[\leadsto \sqrt{\mathsf{fma}\left(\frac{Om}{ky \cdot \ell}, \frac{1}{4}, \frac{1}{2}\right)} \]
                3. Step-by-step derivation
                  1. Applied rewrites85.0%

                    \[\leadsto \sqrt{\mathsf{fma}\left(\frac{Om}{ky \cdot \ell}, 0.25, 0.5\right)} \]
                4. Recombined 2 regimes into one program.
                5. Add Preprocessing

                Alternative 3: 98.4% accurate, 1.1× speedup?

                \[\begin{array}{l} ky_m = \left|ky\right| \\ kx_m = \left|kx\right| \\ Om_m = \left|Om\right| \\ l_m = \left|\ell\right| \\ [l_m, Om_m, kx_m, ky_m] = \mathsf{sort}([l_m, Om_m, kx_m, ky_m])\\ \\ \begin{array}{l} \mathbf{if}\;{\left(\frac{2 \cdot l\_m}{Om\_m}\right)}^{2} \cdot \left({\sin kx\_m}^{2} + {\sin ky\_m}^{2}\right) \leq 3.8:\\ \;\;\;\;\sqrt{1}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{0.5}\\ \end{array} \end{array} \]
                ky_m = (fabs.f64 ky)
                kx_m = (fabs.f64 kx)
                Om_m = (fabs.f64 Om)
                l_m = (fabs.f64 l)
                NOTE: l_m, Om_m, kx_m, and ky_m should be sorted in increasing order before calling this function.
                (FPCore (l_m Om_m kx_m ky_m)
                 :precision binary64
                 (if (<=
                      (*
                       (pow (/ (* 2.0 l_m) Om_m) 2.0)
                       (+ (pow (sin kx_m) 2.0) (pow (sin ky_m) 2.0)))
                      3.8)
                   (sqrt 1.0)
                   (sqrt 0.5)))
                ky_m = fabs(ky);
                kx_m = fabs(kx);
                Om_m = fabs(Om);
                l_m = fabs(l);
                assert(l_m < Om_m && Om_m < kx_m && kx_m < ky_m);
                double code(double l_m, double Om_m, double kx_m, double ky_m) {
                	double tmp;
                	if ((pow(((2.0 * l_m) / Om_m), 2.0) * (pow(sin(kx_m), 2.0) + pow(sin(ky_m), 2.0))) <= 3.8) {
                		tmp = sqrt(1.0);
                	} else {
                		tmp = sqrt(0.5);
                	}
                	return tmp;
                }
                
                ky_m = abs(ky)
                kx_m = abs(kx)
                Om_m = abs(om)
                l_m = abs(l)
                NOTE: l_m, Om_m, kx_m, and ky_m should be sorted in increasing order before calling this function.
                real(8) function code(l_m, om_m, kx_m, ky_m)
                    real(8), intent (in) :: l_m
                    real(8), intent (in) :: om_m
                    real(8), intent (in) :: kx_m
                    real(8), intent (in) :: ky_m
                    real(8) :: tmp
                    if (((((2.0d0 * l_m) / om_m) ** 2.0d0) * ((sin(kx_m) ** 2.0d0) + (sin(ky_m) ** 2.0d0))) <= 3.8d0) then
                        tmp = sqrt(1.0d0)
                    else
                        tmp = sqrt(0.5d0)
                    end if
                    code = tmp
                end function
                
                ky_m = Math.abs(ky);
                kx_m = Math.abs(kx);
                Om_m = Math.abs(Om);
                l_m = Math.abs(l);
                assert l_m < Om_m && Om_m < kx_m && kx_m < ky_m;
                public static double code(double l_m, double Om_m, double kx_m, double ky_m) {
                	double tmp;
                	if ((Math.pow(((2.0 * l_m) / Om_m), 2.0) * (Math.pow(Math.sin(kx_m), 2.0) + Math.pow(Math.sin(ky_m), 2.0))) <= 3.8) {
                		tmp = Math.sqrt(1.0);
                	} else {
                		tmp = Math.sqrt(0.5);
                	}
                	return tmp;
                }
                
                ky_m = math.fabs(ky)
                kx_m = math.fabs(kx)
                Om_m = math.fabs(Om)
                l_m = math.fabs(l)
                [l_m, Om_m, kx_m, ky_m] = sort([l_m, Om_m, kx_m, ky_m])
                def code(l_m, Om_m, kx_m, ky_m):
                	tmp = 0
                	if (math.pow(((2.0 * l_m) / Om_m), 2.0) * (math.pow(math.sin(kx_m), 2.0) + math.pow(math.sin(ky_m), 2.0))) <= 3.8:
                		tmp = math.sqrt(1.0)
                	else:
                		tmp = math.sqrt(0.5)
                	return tmp
                
                ky_m = abs(ky)
                kx_m = abs(kx)
                Om_m = abs(Om)
                l_m = abs(l)
                l_m, Om_m, kx_m, ky_m = sort([l_m, Om_m, kx_m, ky_m])
                function code(l_m, Om_m, kx_m, ky_m)
                	tmp = 0.0
                	if (Float64((Float64(Float64(2.0 * l_m) / Om_m) ^ 2.0) * Float64((sin(kx_m) ^ 2.0) + (sin(ky_m) ^ 2.0))) <= 3.8)
                		tmp = sqrt(1.0);
                	else
                		tmp = sqrt(0.5);
                	end
                	return tmp
                end
                
                ky_m = abs(ky);
                kx_m = abs(kx);
                Om_m = abs(Om);
                l_m = abs(l);
                l_m, Om_m, kx_m, ky_m = num2cell(sort([l_m, Om_m, kx_m, ky_m])){:}
                function tmp_2 = code(l_m, Om_m, kx_m, ky_m)
                	tmp = 0.0;
                	if (((((2.0 * l_m) / Om_m) ^ 2.0) * ((sin(kx_m) ^ 2.0) + (sin(ky_m) ^ 2.0))) <= 3.8)
                		tmp = sqrt(1.0);
                	else
                		tmp = sqrt(0.5);
                	end
                	tmp_2 = tmp;
                end
                
                ky_m = N[Abs[ky], $MachinePrecision]
                kx_m = N[Abs[kx], $MachinePrecision]
                Om_m = N[Abs[Om], $MachinePrecision]
                l_m = N[Abs[l], $MachinePrecision]
                NOTE: l_m, Om_m, kx_m, and ky_m should be sorted in increasing order before calling this function.
                code[l$95$m_, Om$95$m_, kx$95$m_, ky$95$m_] := If[LessEqual[N[(N[Power[N[(N[(2.0 * l$95$m), $MachinePrecision] / Om$95$m), $MachinePrecision], 2.0], $MachinePrecision] * N[(N[Power[N[Sin[kx$95$m], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky$95$m], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 3.8], N[Sqrt[1.0], $MachinePrecision], N[Sqrt[0.5], $MachinePrecision]]
                
                \begin{array}{l}
                ky_m = \left|ky\right|
                \\
                kx_m = \left|kx\right|
                \\
                Om_m = \left|Om\right|
                \\
                l_m = \left|\ell\right|
                \\
                [l_m, Om_m, kx_m, ky_m] = \mathsf{sort}([l_m, Om_m, kx_m, ky_m])\\
                \\
                \begin{array}{l}
                \mathbf{if}\;{\left(\frac{2 \cdot l\_m}{Om\_m}\right)}^{2} \cdot \left({\sin kx\_m}^{2} + {\sin ky\_m}^{2}\right) \leq 3.8:\\
                \;\;\;\;\sqrt{1}\\
                
                \mathbf{else}:\\
                \;\;\;\;\sqrt{0.5}\\
                
                
                \end{array}
                \end{array}
                
                Derivation
                1. Split input into 2 regimes
                2. if (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))) < 3.7999999999999998

                  1. Initial program 100.0%

                    \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
                  2. Add Preprocessing
                  3. Taylor expanded in l around 0

                    \[\leadsto \sqrt{\color{blue}{1}} \]
                  4. Step-by-step derivation
                    1. Applied rewrites100.0%

                      \[\leadsto \sqrt{\color{blue}{1}} \]

                    if 3.7999999999999998 < (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))

                    1. Initial program 95.9%

                      \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
                    2. Add Preprocessing
                    3. Taylor expanded in l around inf

                      \[\leadsto \sqrt{\color{blue}{\frac{1}{2}}} \]
                    4. Step-by-step derivation
                      1. Applied rewrites96.8%

                        \[\leadsto \sqrt{\color{blue}{0.5}} \]
                    5. Recombined 2 regimes into one program.
                    6. Add Preprocessing

                    Alternative 4: 98.1% accurate, 1.6× speedup?

                    \[\begin{array}{l} ky_m = \left|ky\right| \\ kx_m = \left|kx\right| \\ Om_m = \left|Om\right| \\ l_m = \left|\ell\right| \\ [l_m, Om_m, kx_m, ky_m] = \mathsf{sort}([l_m, Om_m, kx_m, ky_m])\\ \\ \sqrt{\mathsf{fma}\left(\sqrt{{\left(\mathsf{fma}\left(\frac{{\sin ky\_m}^{2}}{Om\_m} \cdot \left(\frac{l\_m}{Om\_m} \cdot l\_m\right), 4, 1\right)\right)}^{-1}}, 0.5, 0.5\right)} \end{array} \]
                    ky_m = (fabs.f64 ky)
                    kx_m = (fabs.f64 kx)
                    Om_m = (fabs.f64 Om)
                    l_m = (fabs.f64 l)
                    NOTE: l_m, Om_m, kx_m, and ky_m should be sorted in increasing order before calling this function.
                    (FPCore (l_m Om_m kx_m ky_m)
                     :precision binary64
                     (sqrt
                      (fma
                       (sqrt
                        (pow
                         (fma (* (/ (pow (sin ky_m) 2.0) Om_m) (* (/ l_m Om_m) l_m)) 4.0 1.0)
                         -1.0))
                       0.5
                       0.5)))
                    ky_m = fabs(ky);
                    kx_m = fabs(kx);
                    Om_m = fabs(Om);
                    l_m = fabs(l);
                    assert(l_m < Om_m && Om_m < kx_m && kx_m < ky_m);
                    double code(double l_m, double Om_m, double kx_m, double ky_m) {
                    	return sqrt(fma(sqrt(pow(fma(((pow(sin(ky_m), 2.0) / Om_m) * ((l_m / Om_m) * l_m)), 4.0, 1.0), -1.0)), 0.5, 0.5));
                    }
                    
                    ky_m = abs(ky)
                    kx_m = abs(kx)
                    Om_m = abs(Om)
                    l_m = abs(l)
                    l_m, Om_m, kx_m, ky_m = sort([l_m, Om_m, kx_m, ky_m])
                    function code(l_m, Om_m, kx_m, ky_m)
                    	return sqrt(fma(sqrt((fma(Float64(Float64((sin(ky_m) ^ 2.0) / Om_m) * Float64(Float64(l_m / Om_m) * l_m)), 4.0, 1.0) ^ -1.0)), 0.5, 0.5))
                    end
                    
                    ky_m = N[Abs[ky], $MachinePrecision]
                    kx_m = N[Abs[kx], $MachinePrecision]
                    Om_m = N[Abs[Om], $MachinePrecision]
                    l_m = N[Abs[l], $MachinePrecision]
                    NOTE: l_m, Om_m, kx_m, and ky_m should be sorted in increasing order before calling this function.
                    code[l$95$m_, Om$95$m_, kx$95$m_, ky$95$m_] := N[Sqrt[N[(N[Sqrt[N[Power[N[(N[(N[(N[Power[N[Sin[ky$95$m], $MachinePrecision], 2.0], $MachinePrecision] / Om$95$m), $MachinePrecision] * N[(N[(l$95$m / Om$95$m), $MachinePrecision] * l$95$m), $MachinePrecision]), $MachinePrecision] * 4.0 + 1.0), $MachinePrecision], -1.0], $MachinePrecision]], $MachinePrecision] * 0.5 + 0.5), $MachinePrecision]], $MachinePrecision]
                    
                    \begin{array}{l}
                    ky_m = \left|ky\right|
                    \\
                    kx_m = \left|kx\right|
                    \\
                    Om_m = \left|Om\right|
                    \\
                    l_m = \left|\ell\right|
                    \\
                    [l_m, Om_m, kx_m, ky_m] = \mathsf{sort}([l_m, Om_m, kx_m, ky_m])\\
                    \\
                    \sqrt{\mathsf{fma}\left(\sqrt{{\left(\mathsf{fma}\left(\frac{{\sin ky\_m}^{2}}{Om\_m} \cdot \left(\frac{l\_m}{Om\_m} \cdot l\_m\right), 4, 1\right)\right)}^{-1}}, 0.5, 0.5\right)}
                    \end{array}
                    
                    Derivation
                    1. Initial program 98.0%

                      \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
                    2. Add Preprocessing
                    3. Taylor expanded in kx around 0

                      \[\leadsto \sqrt{\color{blue}{\frac{1}{2} \cdot \left(1 + \sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}}\right)}} \]
                    4. Step-by-step derivation
                      1. +-commutativeN/A

                        \[\leadsto \sqrt{\frac{1}{2} \cdot \color{blue}{\left(\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} + 1\right)}} \]
                      2. distribute-rgt-inN/A

                        \[\leadsto \sqrt{\color{blue}{\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} \cdot \frac{1}{2} + 1 \cdot \frac{1}{2}}} \]
                      3. metadata-evalN/A

                        \[\leadsto \sqrt{\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} \cdot \frac{1}{2} + \color{blue}{\frac{1}{2}}} \]
                      4. lower-fma.f64N/A

                        \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}}, \frac{1}{2}, \frac{1}{2}\right)}} \]
                    5. Applied rewrites86.6%

                      \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\sqrt{\frac{1}{\mathsf{fma}\left(\frac{{\sin ky}^{2}}{Om} \cdot \frac{\ell \cdot \ell}{Om}, 4, 1\right)}}, 0.5, 0.5\right)}} \]
                    6. Step-by-step derivation
                      1. Applied rewrites90.6%

                        \[\leadsto \sqrt{\mathsf{fma}\left(\sqrt{\frac{1}{\mathsf{fma}\left(\frac{{\sin ky}^{2}}{Om} \cdot \left(\frac{\ell}{Om} \cdot \ell\right), 4, 1\right)}}, 0.5, 0.5\right)} \]
                      2. Final simplification90.6%

                        \[\leadsto \sqrt{\mathsf{fma}\left(\sqrt{{\left(\mathsf{fma}\left(\frac{{\sin ky}^{2}}{Om} \cdot \left(\frac{\ell}{Om} \cdot \ell\right), 4, 1\right)\right)}^{-1}}, 0.5, 0.5\right)} \]
                      3. Add Preprocessing

                      Alternative 5: 55.7% accurate, 52.8× speedup?

                      \[\begin{array}{l} ky_m = \left|ky\right| \\ kx_m = \left|kx\right| \\ Om_m = \left|Om\right| \\ l_m = \left|\ell\right| \\ [l_m, Om_m, kx_m, ky_m] = \mathsf{sort}([l_m, Om_m, kx_m, ky_m])\\ \\ \sqrt{0.5} \end{array} \]
                      ky_m = (fabs.f64 ky)
                      kx_m = (fabs.f64 kx)
                      Om_m = (fabs.f64 Om)
                      l_m = (fabs.f64 l)
                      NOTE: l_m, Om_m, kx_m, and ky_m should be sorted in increasing order before calling this function.
                      (FPCore (l_m Om_m kx_m ky_m) :precision binary64 (sqrt 0.5))
                      ky_m = fabs(ky);
                      kx_m = fabs(kx);
                      Om_m = fabs(Om);
                      l_m = fabs(l);
                      assert(l_m < Om_m && Om_m < kx_m && kx_m < ky_m);
                      double code(double l_m, double Om_m, double kx_m, double ky_m) {
                      	return sqrt(0.5);
                      }
                      
                      ky_m = abs(ky)
                      kx_m = abs(kx)
                      Om_m = abs(om)
                      l_m = abs(l)
                      NOTE: l_m, Om_m, kx_m, and ky_m should be sorted in increasing order before calling this function.
                      real(8) function code(l_m, om_m, kx_m, ky_m)
                          real(8), intent (in) :: l_m
                          real(8), intent (in) :: om_m
                          real(8), intent (in) :: kx_m
                          real(8), intent (in) :: ky_m
                          code = sqrt(0.5d0)
                      end function
                      
                      ky_m = Math.abs(ky);
                      kx_m = Math.abs(kx);
                      Om_m = Math.abs(Om);
                      l_m = Math.abs(l);
                      assert l_m < Om_m && Om_m < kx_m && kx_m < ky_m;
                      public static double code(double l_m, double Om_m, double kx_m, double ky_m) {
                      	return Math.sqrt(0.5);
                      }
                      
                      ky_m = math.fabs(ky)
                      kx_m = math.fabs(kx)
                      Om_m = math.fabs(Om)
                      l_m = math.fabs(l)
                      [l_m, Om_m, kx_m, ky_m] = sort([l_m, Om_m, kx_m, ky_m])
                      def code(l_m, Om_m, kx_m, ky_m):
                      	return math.sqrt(0.5)
                      
                      ky_m = abs(ky)
                      kx_m = abs(kx)
                      Om_m = abs(Om)
                      l_m = abs(l)
                      l_m, Om_m, kx_m, ky_m = sort([l_m, Om_m, kx_m, ky_m])
                      function code(l_m, Om_m, kx_m, ky_m)
                      	return sqrt(0.5)
                      end
                      
                      ky_m = abs(ky);
                      kx_m = abs(kx);
                      Om_m = abs(Om);
                      l_m = abs(l);
                      l_m, Om_m, kx_m, ky_m = num2cell(sort([l_m, Om_m, kx_m, ky_m])){:}
                      function tmp = code(l_m, Om_m, kx_m, ky_m)
                      	tmp = sqrt(0.5);
                      end
                      
                      ky_m = N[Abs[ky], $MachinePrecision]
                      kx_m = N[Abs[kx], $MachinePrecision]
                      Om_m = N[Abs[Om], $MachinePrecision]
                      l_m = N[Abs[l], $MachinePrecision]
                      NOTE: l_m, Om_m, kx_m, and ky_m should be sorted in increasing order before calling this function.
                      code[l$95$m_, Om$95$m_, kx$95$m_, ky$95$m_] := N[Sqrt[0.5], $MachinePrecision]
                      
                      \begin{array}{l}
                      ky_m = \left|ky\right|
                      \\
                      kx_m = \left|kx\right|
                      \\
                      Om_m = \left|Om\right|
                      \\
                      l_m = \left|\ell\right|
                      \\
                      [l_m, Om_m, kx_m, ky_m] = \mathsf{sort}([l_m, Om_m, kx_m, ky_m])\\
                      \\
                      \sqrt{0.5}
                      \end{array}
                      
                      Derivation
                      1. Initial program 98.0%

                        \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
                      2. Add Preprocessing
                      3. Taylor expanded in l around inf

                        \[\leadsto \sqrt{\color{blue}{\frac{1}{2}}} \]
                      4. Step-by-step derivation
                        1. Applied rewrites56.3%

                          \[\leadsto \sqrt{\color{blue}{0.5}} \]
                        2. Add Preprocessing

                        Reproduce

                        ?
                        herbie shell --seed 2024307 
                        (FPCore (l Om kx ky)
                          :name "Toniolo and Linder, Equation (3a)"
                          :precision binary64
                          (sqrt (* (/ 1.0 2.0) (+ 1.0 (/ 1.0 (sqrt (+ 1.0 (* (pow (/ (* 2.0 l) Om) 2.0) (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0))))))))))