ABCF->ab-angle a

Percentage Accurate: 18.7% → 62.8%
Time: 15.3s
Alternatives: 21
Speedup: 16.9×

Specification

?
\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
real(8) function code(a, b, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) + sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 21 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 18.7% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
real(8) function code(a, b, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) + sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Alternative 1: 62.8% accurate, 0.2× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \frac{B\_m \cdot B\_m}{A}\\ t_1 := \mathsf{fma}\left(-0.5, t\_0, C \cdot 2\right)\\ t_2 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ t_3 := -\sqrt{F}\\ t_4 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\ t_5 := \frac{\sqrt{\left(2 \cdot \left(t\_4 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_4}\\ t_6 := \mathsf{fma}\left(-4 \cdot A, C, B\_m \cdot B\_m\right)\\ \mathbf{if}\;t\_5 \leq -5 \cdot 10^{+180}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(t\_0, -0.5, C \cdot 2\right)} \cdot \left(\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right) \cdot 2} \cdot t\_3\right)}{t\_4}\\ \mathbf{elif}\;t\_5 \leq -1 \cdot 10^{-200}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot F\right) \cdot t\_2}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}}{t\_2}\\ \mathbf{elif}\;t\_5 \leq 0:\\ \;\;\;\;\sqrt{t\_1 \cdot 2} \cdot \left(\sqrt{t\_6} \cdot \frac{t\_3}{t\_6}\right)\\ \mathbf{elif}\;t\_5 \leq \infty:\\ \;\;\;\;\frac{\left(-\sqrt{\mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right) \cdot F}\right) \cdot \sqrt{2 \cdot t\_1}}{t\_4}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{F \cdot 2} \cdot \frac{\sqrt{\mathsf{hypot}\left(C, B\_m\right) + C}}{-B\_m}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (let* ((t_0 (/ (* B_m B_m) A))
        (t_1 (fma -0.5 t_0 (* C 2.0)))
        (t_2 (fma -4.0 (* C A) (* B_m B_m)))
        (t_3 (- (sqrt F)))
        (t_4 (- (pow B_m 2.0) (* (* 4.0 A) C)))
        (t_5
         (/
          (sqrt
           (*
            (* 2.0 (* t_4 F))
            (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))))
          (- t_4)))
        (t_6 (fma (* -4.0 A) C (* B_m B_m))))
   (if (<= t_5 -5e+180)
     (/
      (*
       (sqrt (fma t_0 -0.5 (* C 2.0)))
       (* (sqrt (* (fma (* -4.0 C) A (* B_m B_m)) 2.0)) t_3))
      t_4)
     (if (<= t_5 -1e-200)
       (*
        (/ (sqrt (* (* 2.0 F) t_2)) -1.0)
        (/ (sqrt (+ (+ (hypot (- A C) B_m) A) C)) t_2))
       (if (<= t_5 0.0)
         (* (sqrt (* t_1 2.0)) (* (sqrt t_6) (/ t_3 t_6)))
         (if (<= t_5 INFINITY)
           (/
            (*
             (- (sqrt (* (fma (* C A) -4.0 (* B_m B_m)) F)))
             (sqrt (* 2.0 t_1)))
            t_4)
           (* (sqrt (* F 2.0)) (/ (sqrt (+ (hypot C B_m) C)) (- B_m)))))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double t_0 = (B_m * B_m) / A;
	double t_1 = fma(-0.5, t_0, (C * 2.0));
	double t_2 = fma(-4.0, (C * A), (B_m * B_m));
	double t_3 = -sqrt(F);
	double t_4 = pow(B_m, 2.0) - ((4.0 * A) * C);
	double t_5 = sqrt(((2.0 * (t_4 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))))) / -t_4;
	double t_6 = fma((-4.0 * A), C, (B_m * B_m));
	double tmp;
	if (t_5 <= -5e+180) {
		tmp = (sqrt(fma(t_0, -0.5, (C * 2.0))) * (sqrt((fma((-4.0 * C), A, (B_m * B_m)) * 2.0)) * t_3)) / t_4;
	} else if (t_5 <= -1e-200) {
		tmp = (sqrt(((2.0 * F) * t_2)) / -1.0) * (sqrt(((hypot((A - C), B_m) + A) + C)) / t_2);
	} else if (t_5 <= 0.0) {
		tmp = sqrt((t_1 * 2.0)) * (sqrt(t_6) * (t_3 / t_6));
	} else if (t_5 <= ((double) INFINITY)) {
		tmp = (-sqrt((fma((C * A), -4.0, (B_m * B_m)) * F)) * sqrt((2.0 * t_1))) / t_4;
	} else {
		tmp = sqrt((F * 2.0)) * (sqrt((hypot(C, B_m) + C)) / -B_m);
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	t_0 = Float64(Float64(B_m * B_m) / A)
	t_1 = fma(-0.5, t_0, Float64(C * 2.0))
	t_2 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
	t_3 = Float64(-sqrt(F))
	t_4 = Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C))
	t_5 = Float64(sqrt(Float64(Float64(2.0 * Float64(t_4 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))))) / Float64(-t_4))
	t_6 = fma(Float64(-4.0 * A), C, Float64(B_m * B_m))
	tmp = 0.0
	if (t_5 <= -5e+180)
		tmp = Float64(Float64(sqrt(fma(t_0, -0.5, Float64(C * 2.0))) * Float64(sqrt(Float64(fma(Float64(-4.0 * C), A, Float64(B_m * B_m)) * 2.0)) * t_3)) / t_4);
	elseif (t_5 <= -1e-200)
		tmp = Float64(Float64(sqrt(Float64(Float64(2.0 * F) * t_2)) / -1.0) * Float64(sqrt(Float64(Float64(hypot(Float64(A - C), B_m) + A) + C)) / t_2));
	elseif (t_5 <= 0.0)
		tmp = Float64(sqrt(Float64(t_1 * 2.0)) * Float64(sqrt(t_6) * Float64(t_3 / t_6)));
	elseif (t_5 <= Inf)
		tmp = Float64(Float64(Float64(-sqrt(Float64(fma(Float64(C * A), -4.0, Float64(B_m * B_m)) * F))) * sqrt(Float64(2.0 * t_1))) / t_4);
	else
		tmp = Float64(sqrt(Float64(F * 2.0)) * Float64(sqrt(Float64(hypot(C, B_m) + C)) / Float64(-B_m)));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision]}, Block[{t$95$1 = N[(-0.5 * t$95$0 + N[(C * 2.0), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = (-N[Sqrt[F], $MachinePrecision])}, Block[{t$95$4 = N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$5 = N[(N[Sqrt[N[(N[(2.0 * N[(t$95$4 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$4)), $MachinePrecision]}, Block[{t$95$6 = N[(N[(-4.0 * A), $MachinePrecision] * C + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$5, -5e+180], N[(N[(N[Sqrt[N[(t$95$0 * -0.5 + N[(C * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[N[(N[(N[(-4.0 * C), $MachinePrecision] * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] * t$95$3), $MachinePrecision]), $MachinePrecision] / t$95$4), $MachinePrecision], If[LessEqual[t$95$5, -1e-200], N[(N[(N[Sqrt[N[(N[(2.0 * F), $MachinePrecision] * t$95$2), $MachinePrecision]], $MachinePrecision] / -1.0), $MachinePrecision] * N[(N[Sqrt[N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] / t$95$2), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$5, 0.0], N[(N[Sqrt[N[(t$95$1 * 2.0), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[t$95$6], $MachinePrecision] * N[(t$95$3 / t$95$6), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$5, Infinity], N[(N[((-N[Sqrt[N[(N[(N[(C * A), $MachinePrecision] * -4.0 + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision] * F), $MachinePrecision]], $MachinePrecision]) * N[Sqrt[N[(2.0 * t$95$1), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / t$95$4), $MachinePrecision], N[(N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision]), $MachinePrecision]]]]]]]]]]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
t_0 := \frac{B\_m \cdot B\_m}{A}\\
t_1 := \mathsf{fma}\left(-0.5, t\_0, C \cdot 2\right)\\
t_2 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
t_3 := -\sqrt{F}\\
t_4 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\
t_5 := \frac{\sqrt{\left(2 \cdot \left(t\_4 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_4}\\
t_6 := \mathsf{fma}\left(-4 \cdot A, C, B\_m \cdot B\_m\right)\\
\mathbf{if}\;t\_5 \leq -5 \cdot 10^{+180}:\\
\;\;\;\;\frac{\sqrt{\mathsf{fma}\left(t\_0, -0.5, C \cdot 2\right)} \cdot \left(\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right) \cdot 2} \cdot t\_3\right)}{t\_4}\\

\mathbf{elif}\;t\_5 \leq -1 \cdot 10^{-200}:\\
\;\;\;\;\frac{\sqrt{\left(2 \cdot F\right) \cdot t\_2}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}}{t\_2}\\

\mathbf{elif}\;t\_5 \leq 0:\\
\;\;\;\;\sqrt{t\_1 \cdot 2} \cdot \left(\sqrt{t\_6} \cdot \frac{t\_3}{t\_6}\right)\\

\mathbf{elif}\;t\_5 \leq \infty:\\
\;\;\;\;\frac{\left(-\sqrt{\mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right) \cdot F}\right) \cdot \sqrt{2 \cdot t\_1}}{t\_4}\\

\mathbf{else}:\\
\;\;\;\;\sqrt{F \cdot 2} \cdot \frac{\sqrt{\mathsf{hypot}\left(C, B\_m\right) + C}}{-B\_m}\\


\end{array}
\end{array}
Derivation
  1. Split input into 5 regimes
  2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -4.9999999999999996e180

    1. Initial program 5.4%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in A around -inf

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\color{blue}{\frac{{B}^{2}}{A} \cdot \frac{-1}{2}} + 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lower-fma.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{{B}^{2}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. lower-/.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\color{blue}{\frac{{B}^{2}}{A}}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. unpow2N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. lower-*.f6412.9

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, \color{blue}{2 \cdot C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    5. Applied rewrites12.9%

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    6. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. *-commutativeN/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. associate-*r*N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      7. associate-*r*N/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    7. Applied rewrites19.4%

      \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    8. Applied rewrites34.7%

      \[\leadsto \frac{\color{blue}{\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, C \cdot 2\right)} \cdot \left(\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2} \cdot \left(-\sqrt{F}\right)\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

    if -4.9999999999999996e180 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -9.9999999999999998e-201

    1. Initial program 98.1%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Applied rewrites98.2%

      \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]

    if -9.9999999999999998e-201 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -0.0

    1. Initial program 3.4%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in A around -inf

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\color{blue}{\frac{{B}^{2}}{A} \cdot \frac{-1}{2}} + 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lower-fma.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{{B}^{2}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. lower-/.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\color{blue}{\frac{{B}^{2}}{A}}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. unpow2N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. lower-*.f6418.8

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, \color{blue}{2 \cdot C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    5. Applied rewrites18.8%

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    6. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. *-commutativeN/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. lift-*.f64N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. associate-*r*N/A

        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      7. associate-*r*N/A

        \[\leadsto \frac{-\sqrt{\color{blue}{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    7. Applied rewrites21.6%

      \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    8. Applied rewrites21.4%

      \[\leadsto \color{blue}{\sqrt{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, C \cdot 2\right) \cdot 2\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \left(\left(-\sqrt{F}\right) \cdot {\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)\right)}^{-1}\right)} \]
    9. Applied rewrites20.5%

      \[\leadsto \color{blue}{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot 2} \cdot \left(\sqrt{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)} \cdot \frac{-\sqrt{F}}{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}\right)} \]

    if -0.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

    1. Initial program 53.9%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in A around -inf

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\color{blue}{\frac{{B}^{2}}{A} \cdot \frac{-1}{2}} + 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      2. lower-fma.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{{B}^{2}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      3. lower-/.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\color{blue}{\frac{{B}^{2}}{A}}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      4. unpow2N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      5. lower-*.f64N/A

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
      6. lower-*.f6435.0

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, \color{blue}{2 \cdot C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    5. Applied rewrites35.0%

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    6. Applied rewrites34.9%

      \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot F} \cdot \sqrt{2 \cdot \mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

    if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

    1. Initial program 0.0%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in A around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. associate-*r*N/A

        \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
      2. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
      3. mul-1-negN/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
      4. lower-neg.f64N/A

        \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
      5. lower-/.f64N/A

        \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
      6. lower-sqrt.f64N/A

        \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
      7. lower-sqrt.f64N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
      8. *-commutativeN/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
      9. lower-*.f64N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
      10. +-commutativeN/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
      11. lower-+.f64N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
      12. +-commutativeN/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
      13. unpow2N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
      14. unpow2N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
      15. lower-hypot.f6417.7

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
    5. Applied rewrites17.7%

      \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
    6. Step-by-step derivation
      1. Applied rewrites17.8%

        \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]
      2. Step-by-step derivation
        1. Applied rewrites28.7%

          \[\leadsto \frac{\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \sqrt{F \cdot 2}}{-\color{blue}{B}} \]
        2. Step-by-step derivation
          1. Applied rewrites28.7%

            \[\leadsto \sqrt{F \cdot 2} \cdot \color{blue}{\frac{\sqrt{\mathsf{hypot}\left(C, B\right) + C}}{-B}} \]
        3. Recombined 5 regimes into one program.
        4. Final simplification40.2%

          \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -5 \cdot 10^{+180}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, C \cdot 2\right)} \cdot \left(\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot 2} \cdot \left(-\sqrt{F}\right)\right)}{{B}^{2} - \left(4 \cdot A\right) \cdot C}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -1 \cdot 10^{-200}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq 0:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot 2} \cdot \left(\sqrt{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)} \cdot \frac{-\sqrt{F}}{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}\right)\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq \infty:\\ \;\;\;\;\frac{\left(-\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot F}\right) \cdot \sqrt{2 \cdot \mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{F \cdot 2} \cdot \frac{\sqrt{\mathsf{hypot}\left(C, B\right) + C}}{-B}\\ \end{array} \]
        5. Add Preprocessing

        Alternative 2: 62.4% accurate, 0.2× speedup?

        \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C \cdot 2\right)\\ t_1 := \mathsf{fma}\left(-4 \cdot A, C, B\_m \cdot B\_m\right)\\ t_2 := \sqrt{t\_0 \cdot 2} \cdot \left(\sqrt{t\_1} \cdot \frac{-\sqrt{F}}{t\_1}\right)\\ t_3 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\ t_4 := \frac{\sqrt{\left(2 \cdot \left(t\_3 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_3}\\ t_5 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;t\_4 \leq -\infty:\\ \;\;\;\;t\_2\\ \mathbf{elif}\;t\_4 \leq -1 \cdot 10^{-200}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}}{-1} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot t\_5}}{t\_5}\\ \mathbf{elif}\;t\_4 \leq 0:\\ \;\;\;\;t\_2\\ \mathbf{elif}\;t\_4 \leq \infty:\\ \;\;\;\;\frac{\left(-\sqrt{\mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right) \cdot F}\right) \cdot \sqrt{2 \cdot t\_0}}{t\_3}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{F \cdot 2} \cdot \frac{\sqrt{\mathsf{hypot}\left(C, B\_m\right) + C}}{-B\_m}\\ \end{array} \end{array} \]
        B_m = (fabs.f64 B)
        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
        (FPCore (A B_m C F)
         :precision binary64
         (let* ((t_0 (fma -0.5 (/ (* B_m B_m) A) (* C 2.0)))
                (t_1 (fma (* -4.0 A) C (* B_m B_m)))
                (t_2 (* (sqrt (* t_0 2.0)) (* (sqrt t_1) (/ (- (sqrt F)) t_1))))
                (t_3 (- (pow B_m 2.0) (* (* 4.0 A) C)))
                (t_4
                 (/
                  (sqrt
                   (*
                    (* 2.0 (* t_3 F))
                    (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))))
                  (- t_3)))
                (t_5 (fma -4.0 (* C A) (* B_m B_m))))
           (if (<= t_4 (- INFINITY))
             t_2
             (if (<= t_4 -1e-200)
               (*
                (/ (sqrt (+ (+ (hypot (- A C) B_m) A) C)) -1.0)
                (/ (sqrt (* (* 2.0 F) t_5)) t_5))
               (if (<= t_4 0.0)
                 t_2
                 (if (<= t_4 INFINITY)
                   (/
                    (*
                     (- (sqrt (* (fma (* C A) -4.0 (* B_m B_m)) F)))
                     (sqrt (* 2.0 t_0)))
                    t_3)
                   (* (sqrt (* F 2.0)) (/ (sqrt (+ (hypot C B_m) C)) (- B_m)))))))))
        B_m = fabs(B);
        assert(A < B_m && B_m < C && C < F);
        double code(double A, double B_m, double C, double F) {
        	double t_0 = fma(-0.5, ((B_m * B_m) / A), (C * 2.0));
        	double t_1 = fma((-4.0 * A), C, (B_m * B_m));
        	double t_2 = sqrt((t_0 * 2.0)) * (sqrt(t_1) * (-sqrt(F) / t_1));
        	double t_3 = pow(B_m, 2.0) - ((4.0 * A) * C);
        	double t_4 = sqrt(((2.0 * (t_3 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))))) / -t_3;
        	double t_5 = fma(-4.0, (C * A), (B_m * B_m));
        	double tmp;
        	if (t_4 <= -((double) INFINITY)) {
        		tmp = t_2;
        	} else if (t_4 <= -1e-200) {
        		tmp = (sqrt(((hypot((A - C), B_m) + A) + C)) / -1.0) * (sqrt(((2.0 * F) * t_5)) / t_5);
        	} else if (t_4 <= 0.0) {
        		tmp = t_2;
        	} else if (t_4 <= ((double) INFINITY)) {
        		tmp = (-sqrt((fma((C * A), -4.0, (B_m * B_m)) * F)) * sqrt((2.0 * t_0))) / t_3;
        	} else {
        		tmp = sqrt((F * 2.0)) * (sqrt((hypot(C, B_m) + C)) / -B_m);
        	}
        	return tmp;
        }
        
        B_m = abs(B)
        A, B_m, C, F = sort([A, B_m, C, F])
        function code(A, B_m, C, F)
        	t_0 = fma(-0.5, Float64(Float64(B_m * B_m) / A), Float64(C * 2.0))
        	t_1 = fma(Float64(-4.0 * A), C, Float64(B_m * B_m))
        	t_2 = Float64(sqrt(Float64(t_0 * 2.0)) * Float64(sqrt(t_1) * Float64(Float64(-sqrt(F)) / t_1)))
        	t_3 = Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C))
        	t_4 = Float64(sqrt(Float64(Float64(2.0 * Float64(t_3 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))))) / Float64(-t_3))
        	t_5 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
        	tmp = 0.0
        	if (t_4 <= Float64(-Inf))
        		tmp = t_2;
        	elseif (t_4 <= -1e-200)
        		tmp = Float64(Float64(sqrt(Float64(Float64(hypot(Float64(A - C), B_m) + A) + C)) / -1.0) * Float64(sqrt(Float64(Float64(2.0 * F) * t_5)) / t_5));
        	elseif (t_4 <= 0.0)
        		tmp = t_2;
        	elseif (t_4 <= Inf)
        		tmp = Float64(Float64(Float64(-sqrt(Float64(fma(Float64(C * A), -4.0, Float64(B_m * B_m)) * F))) * sqrt(Float64(2.0 * t_0))) / t_3);
        	else
        		tmp = Float64(sqrt(Float64(F * 2.0)) * Float64(sqrt(Float64(hypot(C, B_m) + C)) / Float64(-B_m)));
        	end
        	return tmp
        end
        
        B_m = N[Abs[B], $MachinePrecision]
        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
        code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] + N[(C * 2.0), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(-4.0 * A), $MachinePrecision] * C + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(N[Sqrt[N[(t$95$0 * 2.0), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[t$95$1], $MachinePrecision] * N[((-N[Sqrt[F], $MachinePrecision]) / t$95$1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$4 = N[(N[Sqrt[N[(N[(2.0 * N[(t$95$3 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$3)), $MachinePrecision]}, Block[{t$95$5 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$4, (-Infinity)], t$95$2, If[LessEqual[t$95$4, -1e-200], N[(N[(N[Sqrt[N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] / -1.0), $MachinePrecision] * N[(N[Sqrt[N[(N[(2.0 * F), $MachinePrecision] * t$95$5), $MachinePrecision]], $MachinePrecision] / t$95$5), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$4, 0.0], t$95$2, If[LessEqual[t$95$4, Infinity], N[(N[((-N[Sqrt[N[(N[(N[(C * A), $MachinePrecision] * -4.0 + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision] * F), $MachinePrecision]], $MachinePrecision]) * N[Sqrt[N[(2.0 * t$95$0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / t$95$3), $MachinePrecision], N[(N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision]), $MachinePrecision]]]]]]]]]]]
        
        \begin{array}{l}
        B_m = \left|B\right|
        \\
        [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
        \\
        \begin{array}{l}
        t_0 := \mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C \cdot 2\right)\\
        t_1 := \mathsf{fma}\left(-4 \cdot A, C, B\_m \cdot B\_m\right)\\
        t_2 := \sqrt{t\_0 \cdot 2} \cdot \left(\sqrt{t\_1} \cdot \frac{-\sqrt{F}}{t\_1}\right)\\
        t_3 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\
        t_4 := \frac{\sqrt{\left(2 \cdot \left(t\_3 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_3}\\
        t_5 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
        \mathbf{if}\;t\_4 \leq -\infty:\\
        \;\;\;\;t\_2\\
        
        \mathbf{elif}\;t\_4 \leq -1 \cdot 10^{-200}:\\
        \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}}{-1} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot t\_5}}{t\_5}\\
        
        \mathbf{elif}\;t\_4 \leq 0:\\
        \;\;\;\;t\_2\\
        
        \mathbf{elif}\;t\_4 \leq \infty:\\
        \;\;\;\;\frac{\left(-\sqrt{\mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right) \cdot F}\right) \cdot \sqrt{2 \cdot t\_0}}{t\_3}\\
        
        \mathbf{else}:\\
        \;\;\;\;\sqrt{F \cdot 2} \cdot \frac{\sqrt{\mathsf{hypot}\left(C, B\_m\right) + C}}{-B\_m}\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 4 regimes
        2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -inf.0 or -9.9999999999999998e-201 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -0.0

          1. Initial program 3.3%

            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. Add Preprocessing
          3. Taylor expanded in A around -inf

            \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          4. Step-by-step derivation
            1. *-commutativeN/A

              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\color{blue}{\frac{{B}^{2}}{A} \cdot \frac{-1}{2}} + 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            2. lower-fma.f64N/A

              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{{B}^{2}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            3. lower-/.f64N/A

              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\color{blue}{\frac{{B}^{2}}{A}}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            4. unpow2N/A

              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            5. lower-*.f64N/A

              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            6. lower-*.f6415.2

              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, \color{blue}{2 \cdot C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          5. Applied rewrites15.2%

            \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          6. Step-by-step derivation
            1. lift-sqrt.f64N/A

              \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            2. lift-*.f64N/A

              \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            3. *-commutativeN/A

              \[\leadsto \frac{-\sqrt{\color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            4. lift-*.f64N/A

              \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            5. lift-*.f64N/A

              \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            6. associate-*r*N/A

              \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            7. associate-*r*N/A

              \[\leadsto \frac{-\sqrt{\color{blue}{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          7. Applied rewrites19.7%

            \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          8. Applied rewrites19.6%

            \[\leadsto \color{blue}{\sqrt{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, C \cdot 2\right) \cdot 2\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \left(\left(-\sqrt{F}\right) \cdot {\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)\right)}^{-1}\right)} \]
          9. Applied rewrites25.3%

            \[\leadsto \color{blue}{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot 2} \cdot \left(\sqrt{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)} \cdot \frac{-\sqrt{F}}{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}\right)} \]

          if -inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -9.9999999999999998e-201

          1. Initial program 98.1%

            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. Add Preprocessing
          3. Applied rewrites98.2%

            \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{-1} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]

          if -0.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

          1. Initial program 53.9%

            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. Add Preprocessing
          3. Taylor expanded in A around -inf

            \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          4. Step-by-step derivation
            1. *-commutativeN/A

              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\color{blue}{\frac{{B}^{2}}{A} \cdot \frac{-1}{2}} + 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            2. lower-fma.f64N/A

              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{{B}^{2}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            3. lower-/.f64N/A

              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\color{blue}{\frac{{B}^{2}}{A}}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            4. unpow2N/A

              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            5. lower-*.f64N/A

              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            6. lower-*.f6435.0

              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, \color{blue}{2 \cdot C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          5. Applied rewrites35.0%

            \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          6. Applied rewrites34.9%

            \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot F} \cdot \sqrt{2 \cdot \mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

          if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

          1. Initial program 0.0%

            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. Add Preprocessing
          3. Taylor expanded in A around 0

            \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
          4. Step-by-step derivation
            1. associate-*r*N/A

              \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
            2. lower-*.f64N/A

              \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
            3. mul-1-negN/A

              \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
            4. lower-neg.f64N/A

              \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
            5. lower-/.f64N/A

              \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
            6. lower-sqrt.f64N/A

              \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
            7. lower-sqrt.f64N/A

              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
            8. *-commutativeN/A

              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
            9. lower-*.f64N/A

              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
            10. +-commutativeN/A

              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
            11. lower-+.f64N/A

              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
            12. +-commutativeN/A

              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
            13. unpow2N/A

              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
            14. unpow2N/A

              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
            15. lower-hypot.f6417.7

              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
          5. Applied rewrites17.7%

            \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
          6. Step-by-step derivation
            1. Applied rewrites17.8%

              \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]
            2. Step-by-step derivation
              1. Applied rewrites28.7%

                \[\leadsto \frac{\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \sqrt{F \cdot 2}}{-\color{blue}{B}} \]
              2. Step-by-step derivation
                1. Applied rewrites28.7%

                  \[\leadsto \sqrt{F \cdot 2} \cdot \color{blue}{\frac{\sqrt{\mathsf{hypot}\left(C, B\right) + C}}{-B}} \]
              3. Recombined 4 regimes into one program.
              4. Final simplification39.9%

                \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -\infty:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot 2} \cdot \left(\sqrt{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)} \cdot \frac{-\sqrt{F}}{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}\right)\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -1 \cdot 10^{-200}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{-1} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq 0:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot 2} \cdot \left(\sqrt{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)} \cdot \frac{-\sqrt{F}}{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}\right)\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq \infty:\\ \;\;\;\;\frac{\left(-\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot F}\right) \cdot \sqrt{2 \cdot \mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{F \cdot 2} \cdot \frac{\sqrt{\mathsf{hypot}\left(C, B\right) + C}}{-B}\\ \end{array} \]
              5. Add Preprocessing

              Alternative 3: 62.4% accurate, 0.2× speedup?

              \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4 \cdot A, C, B\_m \cdot B\_m\right)\\ t_1 := \sqrt{\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C \cdot 2\right) \cdot 2} \cdot \left(\sqrt{t\_0} \cdot \frac{-\sqrt{F}}{t\_0}\right)\\ t_2 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\ t_3 := \frac{\sqrt{\left(2 \cdot \left(t\_2 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_2}\\ t_4 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ t_5 := \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}}{-1} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot t\_4}}{t\_4}\\ \mathbf{if}\;t\_3 \leq -\infty:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;t\_3 \leq -1 \cdot 10^{-200}:\\ \;\;\;\;t\_5\\ \mathbf{elif}\;t\_3 \leq 0:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;t\_3 \leq \infty:\\ \;\;\;\;t\_5\\ \mathbf{else}:\\ \;\;\;\;\sqrt{F \cdot 2} \cdot \frac{\sqrt{\mathsf{hypot}\left(C, B\_m\right) + C}}{-B\_m}\\ \end{array} \end{array} \]
              B_m = (fabs.f64 B)
              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
              (FPCore (A B_m C F)
               :precision binary64
               (let* ((t_0 (fma (* -4.0 A) C (* B_m B_m)))
                      (t_1
                       (*
                        (sqrt (* (fma -0.5 (/ (* B_m B_m) A) (* C 2.0)) 2.0))
                        (* (sqrt t_0) (/ (- (sqrt F)) t_0))))
                      (t_2 (- (pow B_m 2.0) (* (* 4.0 A) C)))
                      (t_3
                       (/
                        (sqrt
                         (*
                          (* 2.0 (* t_2 F))
                          (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))))
                        (- t_2)))
                      (t_4 (fma -4.0 (* C A) (* B_m B_m)))
                      (t_5
                       (*
                        (/ (sqrt (+ (+ (hypot (- A C) B_m) A) C)) -1.0)
                        (/ (sqrt (* (* 2.0 F) t_4)) t_4))))
                 (if (<= t_3 (- INFINITY))
                   t_1
                   (if (<= t_3 -1e-200)
                     t_5
                     (if (<= t_3 0.0)
                       t_1
                       (if (<= t_3 INFINITY)
                         t_5
                         (* (sqrt (* F 2.0)) (/ (sqrt (+ (hypot C B_m) C)) (- B_m)))))))))
              B_m = fabs(B);
              assert(A < B_m && B_m < C && C < F);
              double code(double A, double B_m, double C, double F) {
              	double t_0 = fma((-4.0 * A), C, (B_m * B_m));
              	double t_1 = sqrt((fma(-0.5, ((B_m * B_m) / A), (C * 2.0)) * 2.0)) * (sqrt(t_0) * (-sqrt(F) / t_0));
              	double t_2 = pow(B_m, 2.0) - ((4.0 * A) * C);
              	double t_3 = sqrt(((2.0 * (t_2 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))))) / -t_2;
              	double t_4 = fma(-4.0, (C * A), (B_m * B_m));
              	double t_5 = (sqrt(((hypot((A - C), B_m) + A) + C)) / -1.0) * (sqrt(((2.0 * F) * t_4)) / t_4);
              	double tmp;
              	if (t_3 <= -((double) INFINITY)) {
              		tmp = t_1;
              	} else if (t_3 <= -1e-200) {
              		tmp = t_5;
              	} else if (t_3 <= 0.0) {
              		tmp = t_1;
              	} else if (t_3 <= ((double) INFINITY)) {
              		tmp = t_5;
              	} else {
              		tmp = sqrt((F * 2.0)) * (sqrt((hypot(C, B_m) + C)) / -B_m);
              	}
              	return tmp;
              }
              
              B_m = abs(B)
              A, B_m, C, F = sort([A, B_m, C, F])
              function code(A, B_m, C, F)
              	t_0 = fma(Float64(-4.0 * A), C, Float64(B_m * B_m))
              	t_1 = Float64(sqrt(Float64(fma(-0.5, Float64(Float64(B_m * B_m) / A), Float64(C * 2.0)) * 2.0)) * Float64(sqrt(t_0) * Float64(Float64(-sqrt(F)) / t_0)))
              	t_2 = Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C))
              	t_3 = Float64(sqrt(Float64(Float64(2.0 * Float64(t_2 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))))) / Float64(-t_2))
              	t_4 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
              	t_5 = Float64(Float64(sqrt(Float64(Float64(hypot(Float64(A - C), B_m) + A) + C)) / -1.0) * Float64(sqrt(Float64(Float64(2.0 * F) * t_4)) / t_4))
              	tmp = 0.0
              	if (t_3 <= Float64(-Inf))
              		tmp = t_1;
              	elseif (t_3 <= -1e-200)
              		tmp = t_5;
              	elseif (t_3 <= 0.0)
              		tmp = t_1;
              	elseif (t_3 <= Inf)
              		tmp = t_5;
              	else
              		tmp = Float64(sqrt(Float64(F * 2.0)) * Float64(sqrt(Float64(hypot(C, B_m) + C)) / Float64(-B_m)));
              	end
              	return tmp
              end
              
              B_m = N[Abs[B], $MachinePrecision]
              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
              code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(-4.0 * A), $MachinePrecision] * C + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[Sqrt[N[(N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] + N[(C * 2.0), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[t$95$0], $MachinePrecision] * N[((-N[Sqrt[F], $MachinePrecision]) / t$95$0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = N[(N[Sqrt[N[(N[(2.0 * N[(t$95$2 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$2)), $MachinePrecision]}, Block[{t$95$4 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$5 = N[(N[(N[Sqrt[N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] / -1.0), $MachinePrecision] * N[(N[Sqrt[N[(N[(2.0 * F), $MachinePrecision] * t$95$4), $MachinePrecision]], $MachinePrecision] / t$95$4), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$3, (-Infinity)], t$95$1, If[LessEqual[t$95$3, -1e-200], t$95$5, If[LessEqual[t$95$3, 0.0], t$95$1, If[LessEqual[t$95$3, Infinity], t$95$5, N[(N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision]), $MachinePrecision]]]]]]]]]]]
              
              \begin{array}{l}
              B_m = \left|B\right|
              \\
              [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
              \\
              \begin{array}{l}
              t_0 := \mathsf{fma}\left(-4 \cdot A, C, B\_m \cdot B\_m\right)\\
              t_1 := \sqrt{\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C \cdot 2\right) \cdot 2} \cdot \left(\sqrt{t\_0} \cdot \frac{-\sqrt{F}}{t\_0}\right)\\
              t_2 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\
              t_3 := \frac{\sqrt{\left(2 \cdot \left(t\_2 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_2}\\
              t_4 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
              t_5 := \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}}{-1} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot t\_4}}{t\_4}\\
              \mathbf{if}\;t\_3 \leq -\infty:\\
              \;\;\;\;t\_1\\
              
              \mathbf{elif}\;t\_3 \leq -1 \cdot 10^{-200}:\\
              \;\;\;\;t\_5\\
              
              \mathbf{elif}\;t\_3 \leq 0:\\
              \;\;\;\;t\_1\\
              
              \mathbf{elif}\;t\_3 \leq \infty:\\
              \;\;\;\;t\_5\\
              
              \mathbf{else}:\\
              \;\;\;\;\sqrt{F \cdot 2} \cdot \frac{\sqrt{\mathsf{hypot}\left(C, B\_m\right) + C}}{-B\_m}\\
              
              
              \end{array}
              \end{array}
              
              Derivation
              1. Split input into 3 regimes
              2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -inf.0 or -9.9999999999999998e-201 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -0.0

                1. Initial program 3.3%

                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                2. Add Preprocessing
                3. Taylor expanded in A around -inf

                  \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                4. Step-by-step derivation
                  1. *-commutativeN/A

                    \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\color{blue}{\frac{{B}^{2}}{A} \cdot \frac{-1}{2}} + 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  2. lower-fma.f64N/A

                    \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{{B}^{2}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  3. lower-/.f64N/A

                    \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\color{blue}{\frac{{B}^{2}}{A}}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  4. unpow2N/A

                    \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  5. lower-*.f64N/A

                    \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  6. lower-*.f6415.2

                    \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, \color{blue}{2 \cdot C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                5. Applied rewrites15.2%

                  \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                6. Step-by-step derivation
                  1. lift-sqrt.f64N/A

                    \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  2. lift-*.f64N/A

                    \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  3. *-commutativeN/A

                    \[\leadsto \frac{-\sqrt{\color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  4. lift-*.f64N/A

                    \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  5. lift-*.f64N/A

                    \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  6. associate-*r*N/A

                    \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  7. associate-*r*N/A

                    \[\leadsto \frac{-\sqrt{\color{blue}{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                7. Applied rewrites19.7%

                  \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                8. Applied rewrites19.6%

                  \[\leadsto \color{blue}{\sqrt{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, C \cdot 2\right) \cdot 2\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \left(\left(-\sqrt{F}\right) \cdot {\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)\right)}^{-1}\right)} \]
                9. Applied rewrites25.3%

                  \[\leadsto \color{blue}{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot 2} \cdot \left(\sqrt{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)} \cdot \frac{-\sqrt{F}}{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}\right)} \]

                if -inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -9.9999999999999998e-201 or -0.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

                1. Initial program 84.8%

                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                2. Add Preprocessing
                3. Applied rewrites94.0%

                  \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{-1} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]

                if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

                1. Initial program 0.0%

                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                2. Add Preprocessing
                3. Taylor expanded in A around 0

                  \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                4. Step-by-step derivation
                  1. associate-*r*N/A

                    \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                  2. lower-*.f64N/A

                    \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                  3. mul-1-negN/A

                    \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                  4. lower-neg.f64N/A

                    \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                  5. lower-/.f64N/A

                    \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                  6. lower-sqrt.f64N/A

                    \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                  7. lower-sqrt.f64N/A

                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                  8. *-commutativeN/A

                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                  9. lower-*.f64N/A

                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                  10. +-commutativeN/A

                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                  11. lower-+.f64N/A

                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                  12. +-commutativeN/A

                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                  13. unpow2N/A

                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                  14. unpow2N/A

                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                  15. lower-hypot.f6417.7

                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                5. Applied rewrites17.7%

                  \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                6. Step-by-step derivation
                  1. Applied rewrites17.8%

                    \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]
                  2. Step-by-step derivation
                    1. Applied rewrites28.7%

                      \[\leadsto \frac{\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \sqrt{F \cdot 2}}{-\color{blue}{B}} \]
                    2. Step-by-step derivation
                      1. Applied rewrites28.7%

                        \[\leadsto \sqrt{F \cdot 2} \cdot \color{blue}{\frac{\sqrt{\mathsf{hypot}\left(C, B\right) + C}}{-B}} \]
                    3. Recombined 3 regimes into one program.
                    4. Final simplification43.5%

                      \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -\infty:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot 2} \cdot \left(\sqrt{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)} \cdot \frac{-\sqrt{F}}{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}\right)\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -1 \cdot 10^{-200}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{-1} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq 0:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot 2} \cdot \left(\sqrt{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)} \cdot \frac{-\sqrt{F}}{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}\right)\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq \infty:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{-1} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{F \cdot 2} \cdot \frac{\sqrt{\mathsf{hypot}\left(C, B\right) + C}}{-B}\\ \end{array} \]
                    5. Add Preprocessing

                    Alternative 4: 62.4% accurate, 0.2× speedup?

                    \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4 \cdot A, C, B\_m \cdot B\_m\right)\\ t_1 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\ t_2 := \sqrt{\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C \cdot 2\right) \cdot 2} \cdot \left(\sqrt{t\_0} \cdot \frac{-\sqrt{F}}{t\_0}\right)\\ t_3 := \frac{\sqrt{\left(2 \cdot \left(t\_1 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_1}\\ t_4 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ t_5 := \frac{\sqrt{\left(2 \cdot F\right) \cdot t\_4}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}}{t\_4}\\ \mathbf{if}\;t\_3 \leq -\infty:\\ \;\;\;\;t\_2\\ \mathbf{elif}\;t\_3 \leq -1 \cdot 10^{-200}:\\ \;\;\;\;t\_5\\ \mathbf{elif}\;t\_3 \leq 0:\\ \;\;\;\;t\_2\\ \mathbf{elif}\;t\_3 \leq \infty:\\ \;\;\;\;t\_5\\ \mathbf{else}:\\ \;\;\;\;\sqrt{F \cdot 2} \cdot \frac{\sqrt{\mathsf{hypot}\left(C, B\_m\right) + C}}{-B\_m}\\ \end{array} \end{array} \]
                    B_m = (fabs.f64 B)
                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                    (FPCore (A B_m C F)
                     :precision binary64
                     (let* ((t_0 (fma (* -4.0 A) C (* B_m B_m)))
                            (t_1 (- (pow B_m 2.0) (* (* 4.0 A) C)))
                            (t_2
                             (*
                              (sqrt (* (fma -0.5 (/ (* B_m B_m) A) (* C 2.0)) 2.0))
                              (* (sqrt t_0) (/ (- (sqrt F)) t_0))))
                            (t_3
                             (/
                              (sqrt
                               (*
                                (* 2.0 (* t_1 F))
                                (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))))
                              (- t_1)))
                            (t_4 (fma -4.0 (* C A) (* B_m B_m)))
                            (t_5
                             (*
                              (/ (sqrt (* (* 2.0 F) t_4)) -1.0)
                              (/ (sqrt (+ (+ (hypot (- A C) B_m) A) C)) t_4))))
                       (if (<= t_3 (- INFINITY))
                         t_2
                         (if (<= t_3 -1e-200)
                           t_5
                           (if (<= t_3 0.0)
                             t_2
                             (if (<= t_3 INFINITY)
                               t_5
                               (* (sqrt (* F 2.0)) (/ (sqrt (+ (hypot C B_m) C)) (- B_m)))))))))
                    B_m = fabs(B);
                    assert(A < B_m && B_m < C && C < F);
                    double code(double A, double B_m, double C, double F) {
                    	double t_0 = fma((-4.0 * A), C, (B_m * B_m));
                    	double t_1 = pow(B_m, 2.0) - ((4.0 * A) * C);
                    	double t_2 = sqrt((fma(-0.5, ((B_m * B_m) / A), (C * 2.0)) * 2.0)) * (sqrt(t_0) * (-sqrt(F) / t_0));
                    	double t_3 = sqrt(((2.0 * (t_1 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))))) / -t_1;
                    	double t_4 = fma(-4.0, (C * A), (B_m * B_m));
                    	double t_5 = (sqrt(((2.0 * F) * t_4)) / -1.0) * (sqrt(((hypot((A - C), B_m) + A) + C)) / t_4);
                    	double tmp;
                    	if (t_3 <= -((double) INFINITY)) {
                    		tmp = t_2;
                    	} else if (t_3 <= -1e-200) {
                    		tmp = t_5;
                    	} else if (t_3 <= 0.0) {
                    		tmp = t_2;
                    	} else if (t_3 <= ((double) INFINITY)) {
                    		tmp = t_5;
                    	} else {
                    		tmp = sqrt((F * 2.0)) * (sqrt((hypot(C, B_m) + C)) / -B_m);
                    	}
                    	return tmp;
                    }
                    
                    B_m = abs(B)
                    A, B_m, C, F = sort([A, B_m, C, F])
                    function code(A, B_m, C, F)
                    	t_0 = fma(Float64(-4.0 * A), C, Float64(B_m * B_m))
                    	t_1 = Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C))
                    	t_2 = Float64(sqrt(Float64(fma(-0.5, Float64(Float64(B_m * B_m) / A), Float64(C * 2.0)) * 2.0)) * Float64(sqrt(t_0) * Float64(Float64(-sqrt(F)) / t_0)))
                    	t_3 = Float64(sqrt(Float64(Float64(2.0 * Float64(t_1 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))))) / Float64(-t_1))
                    	t_4 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
                    	t_5 = Float64(Float64(sqrt(Float64(Float64(2.0 * F) * t_4)) / -1.0) * Float64(sqrt(Float64(Float64(hypot(Float64(A - C), B_m) + A) + C)) / t_4))
                    	tmp = 0.0
                    	if (t_3 <= Float64(-Inf))
                    		tmp = t_2;
                    	elseif (t_3 <= -1e-200)
                    		tmp = t_5;
                    	elseif (t_3 <= 0.0)
                    		tmp = t_2;
                    	elseif (t_3 <= Inf)
                    		tmp = t_5;
                    	else
                    		tmp = Float64(sqrt(Float64(F * 2.0)) * Float64(sqrt(Float64(hypot(C, B_m) + C)) / Float64(-B_m)));
                    	end
                    	return tmp
                    end
                    
                    B_m = N[Abs[B], $MachinePrecision]
                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                    code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(-4.0 * A), $MachinePrecision] * C + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(N[Sqrt[N[(N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] + N[(C * 2.0), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[t$95$0], $MachinePrecision] * N[((-N[Sqrt[F], $MachinePrecision]) / t$95$0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = N[(N[Sqrt[N[(N[(2.0 * N[(t$95$1 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$1)), $MachinePrecision]}, Block[{t$95$4 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$5 = N[(N[(N[Sqrt[N[(N[(2.0 * F), $MachinePrecision] * t$95$4), $MachinePrecision]], $MachinePrecision] / -1.0), $MachinePrecision] * N[(N[Sqrt[N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] / t$95$4), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$3, (-Infinity)], t$95$2, If[LessEqual[t$95$3, -1e-200], t$95$5, If[LessEqual[t$95$3, 0.0], t$95$2, If[LessEqual[t$95$3, Infinity], t$95$5, N[(N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision]), $MachinePrecision]]]]]]]]]]]
                    
                    \begin{array}{l}
                    B_m = \left|B\right|
                    \\
                    [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                    \\
                    \begin{array}{l}
                    t_0 := \mathsf{fma}\left(-4 \cdot A, C, B\_m \cdot B\_m\right)\\
                    t_1 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\
                    t_2 := \sqrt{\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C \cdot 2\right) \cdot 2} \cdot \left(\sqrt{t\_0} \cdot \frac{-\sqrt{F}}{t\_0}\right)\\
                    t_3 := \frac{\sqrt{\left(2 \cdot \left(t\_1 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_1}\\
                    t_4 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
                    t_5 := \frac{\sqrt{\left(2 \cdot F\right) \cdot t\_4}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}}{t\_4}\\
                    \mathbf{if}\;t\_3 \leq -\infty:\\
                    \;\;\;\;t\_2\\
                    
                    \mathbf{elif}\;t\_3 \leq -1 \cdot 10^{-200}:\\
                    \;\;\;\;t\_5\\
                    
                    \mathbf{elif}\;t\_3 \leq 0:\\
                    \;\;\;\;t\_2\\
                    
                    \mathbf{elif}\;t\_3 \leq \infty:\\
                    \;\;\;\;t\_5\\
                    
                    \mathbf{else}:\\
                    \;\;\;\;\sqrt{F \cdot 2} \cdot \frac{\sqrt{\mathsf{hypot}\left(C, B\_m\right) + C}}{-B\_m}\\
                    
                    
                    \end{array}
                    \end{array}
                    
                    Derivation
                    1. Split input into 3 regimes
                    2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -inf.0 or -9.9999999999999998e-201 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -0.0

                      1. Initial program 3.3%

                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      2. Add Preprocessing
                      3. Taylor expanded in A around -inf

                        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      4. Step-by-step derivation
                        1. *-commutativeN/A

                          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\color{blue}{\frac{{B}^{2}}{A} \cdot \frac{-1}{2}} + 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        2. lower-fma.f64N/A

                          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{{B}^{2}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        3. lower-/.f64N/A

                          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\color{blue}{\frac{{B}^{2}}{A}}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        4. unpow2N/A

                          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        5. lower-*.f64N/A

                          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        6. lower-*.f6415.2

                          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, \color{blue}{2 \cdot C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      5. Applied rewrites15.2%

                        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      6. Step-by-step derivation
                        1. lift-sqrt.f64N/A

                          \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        2. lift-*.f64N/A

                          \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        3. *-commutativeN/A

                          \[\leadsto \frac{-\sqrt{\color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        4. lift-*.f64N/A

                          \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        5. lift-*.f64N/A

                          \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        6. associate-*r*N/A

                          \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        7. associate-*r*N/A

                          \[\leadsto \frac{-\sqrt{\color{blue}{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      7. Applied rewrites19.7%

                        \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      8. Applied rewrites19.6%

                        \[\leadsto \color{blue}{\sqrt{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, C \cdot 2\right) \cdot 2\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \left(\left(-\sqrt{F}\right) \cdot {\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)\right)}^{-1}\right)} \]
                      9. Applied rewrites25.3%

                        \[\leadsto \color{blue}{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot 2} \cdot \left(\sqrt{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)} \cdot \frac{-\sqrt{F}}{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}\right)} \]

                      if -inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -9.9999999999999998e-201 or -0.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

                      1. Initial program 84.8%

                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      2. Add Preprocessing
                      3. Applied rewrites93.9%

                        \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]

                      if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

                      1. Initial program 0.0%

                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      2. Add Preprocessing
                      3. Taylor expanded in A around 0

                        \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                      4. Step-by-step derivation
                        1. associate-*r*N/A

                          \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                        2. lower-*.f64N/A

                          \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                        3. mul-1-negN/A

                          \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                        4. lower-neg.f64N/A

                          \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                        5. lower-/.f64N/A

                          \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                        6. lower-sqrt.f64N/A

                          \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                        7. lower-sqrt.f64N/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                        8. *-commutativeN/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                        9. lower-*.f64N/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                        10. +-commutativeN/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                        11. lower-+.f64N/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                        12. +-commutativeN/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                        13. unpow2N/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                        14. unpow2N/A

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                        15. lower-hypot.f6417.7

                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                      5. Applied rewrites17.7%

                        \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                      6. Step-by-step derivation
                        1. Applied rewrites17.8%

                          \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]
                        2. Step-by-step derivation
                          1. Applied rewrites28.7%

                            \[\leadsto \frac{\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \sqrt{F \cdot 2}}{-\color{blue}{B}} \]
                          2. Step-by-step derivation
                            1. Applied rewrites28.7%

                              \[\leadsto \sqrt{F \cdot 2} \cdot \color{blue}{\frac{\sqrt{\mathsf{hypot}\left(C, B\right) + C}}{-B}} \]
                          3. Recombined 3 regimes into one program.
                          4. Final simplification43.5%

                            \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -\infty:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot 2} \cdot \left(\sqrt{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)} \cdot \frac{-\sqrt{F}}{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}\right)\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -1 \cdot 10^{-200}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq 0:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot 2} \cdot \left(\sqrt{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)} \cdot \frac{-\sqrt{F}}{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}\right)\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq \infty:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{F \cdot 2} \cdot \frac{\sqrt{\mathsf{hypot}\left(C, B\right) + C}}{-B}\\ \end{array} \]
                          5. Add Preprocessing

                          Alternative 5: 60.6% accurate, 0.2× speedup?

                          \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C \cdot 2\right)\\ t_1 := \mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)\\ t_2 := \mathsf{fma}\left(-4 \cdot A, C, B\_m \cdot B\_m\right)\\ t_3 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ t_4 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\ t_5 := \frac{\sqrt{\left(2 \cdot \left(t\_4 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_4}\\ t_6 := \sqrt{t\_0 \cdot 2} \cdot \left(\sqrt{t\_2} \cdot \frac{-\sqrt{F}}{t\_2}\right)\\ \mathbf{if}\;t\_5 \leq -\infty:\\ \;\;\;\;t\_6\\ \mathbf{elif}\;t\_5 \leq -1 \cdot 10^{-200}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot t\_3\right)}}{-t\_3}\\ \mathbf{elif}\;t\_5 \leq 0:\\ \;\;\;\;t\_6\\ \mathbf{elif}\;t\_5 \leq \infty:\\ \;\;\;\;\frac{-1}{\frac{t\_1}{\sqrt{t\_0 \cdot \left(\left(t\_1 \cdot F\right) \cdot 2\right)}}}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{F \cdot 2} \cdot \frac{\sqrt{\mathsf{hypot}\left(C, B\_m\right) + C}}{-B\_m}\\ \end{array} \end{array} \]
                          B_m = (fabs.f64 B)
                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                          (FPCore (A B_m C F)
                           :precision binary64
                           (let* ((t_0 (fma -0.5 (/ (* B_m B_m) A) (* C 2.0)))
                                  (t_1 (fma (* C A) -4.0 (* B_m B_m)))
                                  (t_2 (fma (* -4.0 A) C (* B_m B_m)))
                                  (t_3 (fma -4.0 (* C A) (* B_m B_m)))
                                  (t_4 (- (pow B_m 2.0) (* (* 4.0 A) C)))
                                  (t_5
                                   (/
                                    (sqrt
                                     (*
                                      (* 2.0 (* t_4 F))
                                      (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))))
                                    (- t_4)))
                                  (t_6 (* (sqrt (* t_0 2.0)) (* (sqrt t_2) (/ (- (sqrt F)) t_2)))))
                             (if (<= t_5 (- INFINITY))
                               t_6
                               (if (<= t_5 -1e-200)
                                 (/ (sqrt (* (+ (+ (hypot (- A C) B_m) A) C) (* (* 2.0 F) t_3))) (- t_3))
                                 (if (<= t_5 0.0)
                                   t_6
                                   (if (<= t_5 INFINITY)
                                     (/ -1.0 (/ t_1 (sqrt (* t_0 (* (* t_1 F) 2.0)))))
                                     (* (sqrt (* F 2.0)) (/ (sqrt (+ (hypot C B_m) C)) (- B_m)))))))))
                          B_m = fabs(B);
                          assert(A < B_m && B_m < C && C < F);
                          double code(double A, double B_m, double C, double F) {
                          	double t_0 = fma(-0.5, ((B_m * B_m) / A), (C * 2.0));
                          	double t_1 = fma((C * A), -4.0, (B_m * B_m));
                          	double t_2 = fma((-4.0 * A), C, (B_m * B_m));
                          	double t_3 = fma(-4.0, (C * A), (B_m * B_m));
                          	double t_4 = pow(B_m, 2.0) - ((4.0 * A) * C);
                          	double t_5 = sqrt(((2.0 * (t_4 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))))) / -t_4;
                          	double t_6 = sqrt((t_0 * 2.0)) * (sqrt(t_2) * (-sqrt(F) / t_2));
                          	double tmp;
                          	if (t_5 <= -((double) INFINITY)) {
                          		tmp = t_6;
                          	} else if (t_5 <= -1e-200) {
                          		tmp = sqrt((((hypot((A - C), B_m) + A) + C) * ((2.0 * F) * t_3))) / -t_3;
                          	} else if (t_5 <= 0.0) {
                          		tmp = t_6;
                          	} else if (t_5 <= ((double) INFINITY)) {
                          		tmp = -1.0 / (t_1 / sqrt((t_0 * ((t_1 * F) * 2.0))));
                          	} else {
                          		tmp = sqrt((F * 2.0)) * (sqrt((hypot(C, B_m) + C)) / -B_m);
                          	}
                          	return tmp;
                          }
                          
                          B_m = abs(B)
                          A, B_m, C, F = sort([A, B_m, C, F])
                          function code(A, B_m, C, F)
                          	t_0 = fma(-0.5, Float64(Float64(B_m * B_m) / A), Float64(C * 2.0))
                          	t_1 = fma(Float64(C * A), -4.0, Float64(B_m * B_m))
                          	t_2 = fma(Float64(-4.0 * A), C, Float64(B_m * B_m))
                          	t_3 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
                          	t_4 = Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C))
                          	t_5 = Float64(sqrt(Float64(Float64(2.0 * Float64(t_4 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))))) / Float64(-t_4))
                          	t_6 = Float64(sqrt(Float64(t_0 * 2.0)) * Float64(sqrt(t_2) * Float64(Float64(-sqrt(F)) / t_2)))
                          	tmp = 0.0
                          	if (t_5 <= Float64(-Inf))
                          		tmp = t_6;
                          	elseif (t_5 <= -1e-200)
                          		tmp = Float64(sqrt(Float64(Float64(Float64(hypot(Float64(A - C), B_m) + A) + C) * Float64(Float64(2.0 * F) * t_3))) / Float64(-t_3));
                          	elseif (t_5 <= 0.0)
                          		tmp = t_6;
                          	elseif (t_5 <= Inf)
                          		tmp = Float64(-1.0 / Float64(t_1 / sqrt(Float64(t_0 * Float64(Float64(t_1 * F) * 2.0)))));
                          	else
                          		tmp = Float64(sqrt(Float64(F * 2.0)) * Float64(sqrt(Float64(hypot(C, B_m) + C)) / Float64(-B_m)));
                          	end
                          	return tmp
                          end
                          
                          B_m = N[Abs[B], $MachinePrecision]
                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                          code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] + N[(C * 2.0), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(C * A), $MachinePrecision] * -4.0 + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(N[(-4.0 * A), $MachinePrecision] * C + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$4 = N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$5 = N[(N[Sqrt[N[(N[(2.0 * N[(t$95$4 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$4)), $MachinePrecision]}, Block[{t$95$6 = N[(N[Sqrt[N[(t$95$0 * 2.0), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[t$95$2], $MachinePrecision] * N[((-N[Sqrt[F], $MachinePrecision]) / t$95$2), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$5, (-Infinity)], t$95$6, If[LessEqual[t$95$5, -1e-200], N[(N[Sqrt[N[(N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision] * N[(N[(2.0 * F), $MachinePrecision] * t$95$3), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$3)), $MachinePrecision], If[LessEqual[t$95$5, 0.0], t$95$6, If[LessEqual[t$95$5, Infinity], N[(-1.0 / N[(t$95$1 / N[Sqrt[N[(t$95$0 * N[(N[(t$95$1 * F), $MachinePrecision] * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision]), $MachinePrecision]]]]]]]]]]]]
                          
                          \begin{array}{l}
                          B_m = \left|B\right|
                          \\
                          [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                          \\
                          \begin{array}{l}
                          t_0 := \mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C \cdot 2\right)\\
                          t_1 := \mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)\\
                          t_2 := \mathsf{fma}\left(-4 \cdot A, C, B\_m \cdot B\_m\right)\\
                          t_3 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
                          t_4 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\
                          t_5 := \frac{\sqrt{\left(2 \cdot \left(t\_4 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_4}\\
                          t_6 := \sqrt{t\_0 \cdot 2} \cdot \left(\sqrt{t\_2} \cdot \frac{-\sqrt{F}}{t\_2}\right)\\
                          \mathbf{if}\;t\_5 \leq -\infty:\\
                          \;\;\;\;t\_6\\
                          
                          \mathbf{elif}\;t\_5 \leq -1 \cdot 10^{-200}:\\
                          \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot t\_3\right)}}{-t\_3}\\
                          
                          \mathbf{elif}\;t\_5 \leq 0:\\
                          \;\;\;\;t\_6\\
                          
                          \mathbf{elif}\;t\_5 \leq \infty:\\
                          \;\;\;\;\frac{-1}{\frac{t\_1}{\sqrt{t\_0 \cdot \left(\left(t\_1 \cdot F\right) \cdot 2\right)}}}\\
                          
                          \mathbf{else}:\\
                          \;\;\;\;\sqrt{F \cdot 2} \cdot \frac{\sqrt{\mathsf{hypot}\left(C, B\_m\right) + C}}{-B\_m}\\
                          
                          
                          \end{array}
                          \end{array}
                          
                          Derivation
                          1. Split input into 4 regimes
                          2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -inf.0 or -9.9999999999999998e-201 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -0.0

                            1. Initial program 3.3%

                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            2. Add Preprocessing
                            3. Taylor expanded in A around -inf

                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            4. Step-by-step derivation
                              1. *-commutativeN/A

                                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\color{blue}{\frac{{B}^{2}}{A} \cdot \frac{-1}{2}} + 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              2. lower-fma.f64N/A

                                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{{B}^{2}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              3. lower-/.f64N/A

                                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\color{blue}{\frac{{B}^{2}}{A}}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              4. unpow2N/A

                                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              5. lower-*.f64N/A

                                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              6. lower-*.f6415.2

                                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, \color{blue}{2 \cdot C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            5. Applied rewrites15.2%

                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            6. Step-by-step derivation
                              1. lift-sqrt.f64N/A

                                \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              2. lift-*.f64N/A

                                \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              3. *-commutativeN/A

                                \[\leadsto \frac{-\sqrt{\color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              4. lift-*.f64N/A

                                \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              5. lift-*.f64N/A

                                \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              6. associate-*r*N/A

                                \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              7. associate-*r*N/A

                                \[\leadsto \frac{-\sqrt{\color{blue}{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            7. Applied rewrites19.7%

                              \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            8. Applied rewrites19.6%

                              \[\leadsto \color{blue}{\sqrt{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, C \cdot 2\right) \cdot 2\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \left(\left(-\sqrt{F}\right) \cdot {\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)\right)}^{-1}\right)} \]
                            9. Applied rewrites25.3%

                              \[\leadsto \color{blue}{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot 2} \cdot \left(\sqrt{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)} \cdot \frac{-\sqrt{F}}{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}\right)} \]

                            if -inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -9.9999999999999998e-201

                            1. Initial program 98.1%

                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            2. Add Preprocessing
                            3. Applied rewrites98.1%

                              \[\leadsto \color{blue}{\frac{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]

                            if -0.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

                            1. Initial program 53.9%

                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            2. Add Preprocessing
                            3. Taylor expanded in A around -inf

                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            4. Step-by-step derivation
                              1. *-commutativeN/A

                                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\color{blue}{\frac{{B}^{2}}{A} \cdot \frac{-1}{2}} + 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              2. lower-fma.f64N/A

                                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{{B}^{2}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              3. lower-/.f64N/A

                                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\color{blue}{\frac{{B}^{2}}{A}}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              4. unpow2N/A

                                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              5. lower-*.f64N/A

                                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              6. lower-*.f6435.0

                                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, \color{blue}{2 \cdot C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            5. Applied rewrites35.0%

                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            6. Applied rewrites35.0%

                              \[\leadsto \color{blue}{\frac{1}{\frac{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot \left(\left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot F\right) \cdot 2\right)}}}} \]

                            if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

                            1. Initial program 0.0%

                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            2. Add Preprocessing
                            3. Taylor expanded in A around 0

                              \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                            4. Step-by-step derivation
                              1. associate-*r*N/A

                                \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                              2. lower-*.f64N/A

                                \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                              3. mul-1-negN/A

                                \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                              4. lower-neg.f64N/A

                                \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                              5. lower-/.f64N/A

                                \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                              6. lower-sqrt.f64N/A

                                \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                              7. lower-sqrt.f64N/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                              8. *-commutativeN/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                              9. lower-*.f64N/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                              10. +-commutativeN/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                              11. lower-+.f64N/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                              12. +-commutativeN/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                              13. unpow2N/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                              14. unpow2N/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                              15. lower-hypot.f6417.7

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                            5. Applied rewrites17.7%

                              \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                            6. Step-by-step derivation
                              1. Applied rewrites17.8%

                                \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]
                              2. Step-by-step derivation
                                1. Applied rewrites28.7%

                                  \[\leadsto \frac{\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \sqrt{F \cdot 2}}{-\color{blue}{B}} \]
                                2. Step-by-step derivation
                                  1. Applied rewrites28.7%

                                    \[\leadsto \sqrt{F \cdot 2} \cdot \color{blue}{\frac{\sqrt{\mathsf{hypot}\left(C, B\right) + C}}{-B}} \]
                                3. Recombined 4 regimes into one program.
                                4. Final simplification39.9%

                                  \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -\infty:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot 2} \cdot \left(\sqrt{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)} \cdot \frac{-\sqrt{F}}{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}\right)\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -1 \cdot 10^{-200}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}{-\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq 0:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot 2} \cdot \left(\sqrt{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)} \cdot \frac{-\sqrt{F}}{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}\right)\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq \infty:\\ \;\;\;\;\frac{-1}{\frac{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot \left(\left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot F\right) \cdot 2\right)}}}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{F \cdot 2} \cdot \frac{\sqrt{\mathsf{hypot}\left(C, B\right) + C}}{-B}\\ \end{array} \]
                                5. Add Preprocessing

                                Alternative 6: 53.8% accurate, 0.2× speedup?

                                \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4 \cdot A, C, B\_m \cdot B\_m\right)\\ t_1 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\ t_2 := \frac{\sqrt{\left(2 \cdot \left(t\_1 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_1}\\ t_3 := \mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C \cdot 2\right)\\ t_4 := \sqrt{t\_3 \cdot 2} \cdot \left(\sqrt{t\_0} \cdot \frac{-\sqrt{F}}{t\_0}\right)\\ t_5 := \mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)\\ \mathbf{if}\;t\_2 \leq -1 \cdot 10^{+52}:\\ \;\;\;\;t\_4\\ \mathbf{elif}\;t\_2 \leq -1 \cdot 10^{-200}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot F\right) \cdot 2}}{-B\_m}\\ \mathbf{elif}\;t\_2 \leq 0:\\ \;\;\;\;t\_4\\ \mathbf{elif}\;t\_2 \leq \infty:\\ \;\;\;\;\frac{-1}{\frac{t\_5}{\sqrt{t\_3 \cdot \left(\left(t\_5 \cdot F\right) \cdot 2\right)}}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{C + B\_m} \cdot \sqrt{F \cdot 2}}{-B\_m}\\ \end{array} \end{array} \]
                                B_m = (fabs.f64 B)
                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                (FPCore (A B_m C F)
                                 :precision binary64
                                 (let* ((t_0 (fma (* -4.0 A) C (* B_m B_m)))
                                        (t_1 (- (pow B_m 2.0) (* (* 4.0 A) C)))
                                        (t_2
                                         (/
                                          (sqrt
                                           (*
                                            (* 2.0 (* t_1 F))
                                            (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))))
                                          (- t_1)))
                                        (t_3 (fma -0.5 (/ (* B_m B_m) A) (* C 2.0)))
                                        (t_4 (* (sqrt (* t_3 2.0)) (* (sqrt t_0) (/ (- (sqrt F)) t_0))))
                                        (t_5 (fma (* C A) -4.0 (* B_m B_m))))
                                   (if (<= t_2 -1e+52)
                                     t_4
                                     (if (<= t_2 -1e-200)
                                       (/ (sqrt (* (* (+ (hypot C B_m) C) F) 2.0)) (- B_m))
                                       (if (<= t_2 0.0)
                                         t_4
                                         (if (<= t_2 INFINITY)
                                           (/ -1.0 (/ t_5 (sqrt (* t_3 (* (* t_5 F) 2.0)))))
                                           (/ (* (sqrt (+ C B_m)) (sqrt (* F 2.0))) (- B_m))))))))
                                B_m = fabs(B);
                                assert(A < B_m && B_m < C && C < F);
                                double code(double A, double B_m, double C, double F) {
                                	double t_0 = fma((-4.0 * A), C, (B_m * B_m));
                                	double t_1 = pow(B_m, 2.0) - ((4.0 * A) * C);
                                	double t_2 = sqrt(((2.0 * (t_1 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))))) / -t_1;
                                	double t_3 = fma(-0.5, ((B_m * B_m) / A), (C * 2.0));
                                	double t_4 = sqrt((t_3 * 2.0)) * (sqrt(t_0) * (-sqrt(F) / t_0));
                                	double t_5 = fma((C * A), -4.0, (B_m * B_m));
                                	double tmp;
                                	if (t_2 <= -1e+52) {
                                		tmp = t_4;
                                	} else if (t_2 <= -1e-200) {
                                		tmp = sqrt((((hypot(C, B_m) + C) * F) * 2.0)) / -B_m;
                                	} else if (t_2 <= 0.0) {
                                		tmp = t_4;
                                	} else if (t_2 <= ((double) INFINITY)) {
                                		tmp = -1.0 / (t_5 / sqrt((t_3 * ((t_5 * F) * 2.0))));
                                	} else {
                                		tmp = (sqrt((C + B_m)) * sqrt((F * 2.0))) / -B_m;
                                	}
                                	return tmp;
                                }
                                
                                B_m = abs(B)
                                A, B_m, C, F = sort([A, B_m, C, F])
                                function code(A, B_m, C, F)
                                	t_0 = fma(Float64(-4.0 * A), C, Float64(B_m * B_m))
                                	t_1 = Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C))
                                	t_2 = Float64(sqrt(Float64(Float64(2.0 * Float64(t_1 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))))) / Float64(-t_1))
                                	t_3 = fma(-0.5, Float64(Float64(B_m * B_m) / A), Float64(C * 2.0))
                                	t_4 = Float64(sqrt(Float64(t_3 * 2.0)) * Float64(sqrt(t_0) * Float64(Float64(-sqrt(F)) / t_0)))
                                	t_5 = fma(Float64(C * A), -4.0, Float64(B_m * B_m))
                                	tmp = 0.0
                                	if (t_2 <= -1e+52)
                                		tmp = t_4;
                                	elseif (t_2 <= -1e-200)
                                		tmp = Float64(sqrt(Float64(Float64(Float64(hypot(C, B_m) + C) * F) * 2.0)) / Float64(-B_m));
                                	elseif (t_2 <= 0.0)
                                		tmp = t_4;
                                	elseif (t_2 <= Inf)
                                		tmp = Float64(-1.0 / Float64(t_5 / sqrt(Float64(t_3 * Float64(Float64(t_5 * F) * 2.0)))));
                                	else
                                		tmp = Float64(Float64(sqrt(Float64(C + B_m)) * sqrt(Float64(F * 2.0))) / Float64(-B_m));
                                	end
                                	return tmp
                                end
                                
                                B_m = N[Abs[B], $MachinePrecision]
                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(-4.0 * A), $MachinePrecision] * C + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(N[Sqrt[N[(N[(2.0 * N[(t$95$1 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$1)), $MachinePrecision]}, Block[{t$95$3 = N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] + N[(C * 2.0), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$4 = N[(N[Sqrt[N[(t$95$3 * 2.0), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[t$95$0], $MachinePrecision] * N[((-N[Sqrt[F], $MachinePrecision]) / t$95$0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$5 = N[(N[(C * A), $MachinePrecision] * -4.0 + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$2, -1e+52], t$95$4, If[LessEqual[t$95$2, -1e-200], N[(N[Sqrt[N[(N[(N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] * F), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision], If[LessEqual[t$95$2, 0.0], t$95$4, If[LessEqual[t$95$2, Infinity], N[(-1.0 / N[(t$95$5 / N[Sqrt[N[(t$95$3 * N[(N[(t$95$5 * F), $MachinePrecision] * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(C + B$95$m), $MachinePrecision]], $MachinePrecision] * N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / (-B$95$m)), $MachinePrecision]]]]]]]]]]]
                                
                                \begin{array}{l}
                                B_m = \left|B\right|
                                \\
                                [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                \\
                                \begin{array}{l}
                                t_0 := \mathsf{fma}\left(-4 \cdot A, C, B\_m \cdot B\_m\right)\\
                                t_1 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\
                                t_2 := \frac{\sqrt{\left(2 \cdot \left(t\_1 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_1}\\
                                t_3 := \mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C \cdot 2\right)\\
                                t_4 := \sqrt{t\_3 \cdot 2} \cdot \left(\sqrt{t\_0} \cdot \frac{-\sqrt{F}}{t\_0}\right)\\
                                t_5 := \mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)\\
                                \mathbf{if}\;t\_2 \leq -1 \cdot 10^{+52}:\\
                                \;\;\;\;t\_4\\
                                
                                \mathbf{elif}\;t\_2 \leq -1 \cdot 10^{-200}:\\
                                \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot F\right) \cdot 2}}{-B\_m}\\
                                
                                \mathbf{elif}\;t\_2 \leq 0:\\
                                \;\;\;\;t\_4\\
                                
                                \mathbf{elif}\;t\_2 \leq \infty:\\
                                \;\;\;\;\frac{-1}{\frac{t\_5}{\sqrt{t\_3 \cdot \left(\left(t\_5 \cdot F\right) \cdot 2\right)}}}\\
                                
                                \mathbf{else}:\\
                                \;\;\;\;\frac{\sqrt{C + B\_m} \cdot \sqrt{F \cdot 2}}{-B\_m}\\
                                
                                
                                \end{array}
                                \end{array}
                                
                                Derivation
                                1. Split input into 4 regimes
                                2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -9.9999999999999999e51 or -9.9999999999999998e-201 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -0.0

                                  1. Initial program 15.3%

                                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in A around -inf

                                    \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                  4. Step-by-step derivation
                                    1. *-commutativeN/A

                                      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\color{blue}{\frac{{B}^{2}}{A} \cdot \frac{-1}{2}} + 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    2. lower-fma.f64N/A

                                      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{{B}^{2}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    3. lower-/.f64N/A

                                      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\color{blue}{\frac{{B}^{2}}{A}}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    4. unpow2N/A

                                      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    5. lower-*.f64N/A

                                      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    6. lower-*.f6418.8

                                      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, \color{blue}{2 \cdot C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                  5. Applied rewrites18.8%

                                    \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                  6. Step-by-step derivation
                                    1. lift-sqrt.f64N/A

                                      \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    2. lift-*.f64N/A

                                      \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    3. *-commutativeN/A

                                      \[\leadsto \frac{-\sqrt{\color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    4. lift-*.f64N/A

                                      \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    5. lift-*.f64N/A

                                      \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    6. associate-*r*N/A

                                      \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    7. associate-*r*N/A

                                      \[\leadsto \frac{-\sqrt{\color{blue}{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                  7. Applied rewrites22.8%

                                    \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                  8. Applied rewrites22.6%

                                    \[\leadsto \color{blue}{\sqrt{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, C \cdot 2\right) \cdot 2\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \left(\left(-\sqrt{F}\right) \cdot {\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)\right)}^{-1}\right)} \]
                                  9. Applied rewrites27.6%

                                    \[\leadsto \color{blue}{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot 2} \cdot \left(\sqrt{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)} \cdot \frac{-\sqrt{F}}{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}\right)} \]

                                  if -9.9999999999999999e51 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -9.9999999999999998e-201

                                  1. Initial program 99.2%

                                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in A around 0

                                    \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                  4. Step-by-step derivation
                                    1. associate-*r*N/A

                                      \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                    2. lower-*.f64N/A

                                      \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                    3. mul-1-negN/A

                                      \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                    4. lower-neg.f64N/A

                                      \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                    5. lower-/.f64N/A

                                      \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                    6. lower-sqrt.f64N/A

                                      \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                    7. lower-sqrt.f64N/A

                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                    8. *-commutativeN/A

                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                    9. lower-*.f64N/A

                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                    10. +-commutativeN/A

                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                    11. lower-+.f64N/A

                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                    12. +-commutativeN/A

                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                                    13. unpow2N/A

                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                                    14. unpow2N/A

                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                                    15. lower-hypot.f6444.4

                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                                  5. Applied rewrites44.4%

                                    \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                                  6. Step-by-step derivation
                                    1. Applied rewrites44.5%

                                      \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]

                                    if -0.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

                                    1. Initial program 53.9%

                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    2. Add Preprocessing
                                    3. Taylor expanded in A around -inf

                                      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    4. Step-by-step derivation
                                      1. *-commutativeN/A

                                        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\color{blue}{\frac{{B}^{2}}{A} \cdot \frac{-1}{2}} + 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                      2. lower-fma.f64N/A

                                        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{{B}^{2}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                      3. lower-/.f64N/A

                                        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\color{blue}{\frac{{B}^{2}}{A}}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                      4. unpow2N/A

                                        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                      5. lower-*.f64N/A

                                        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                      6. lower-*.f6435.0

                                        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, \color{blue}{2 \cdot C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    5. Applied rewrites35.0%

                                      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    6. Applied rewrites35.0%

                                      \[\leadsto \color{blue}{\frac{1}{\frac{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot \left(\left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot F\right) \cdot 2\right)}}}} \]

                                    if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

                                    1. Initial program 0.0%

                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    2. Add Preprocessing
                                    3. Taylor expanded in A around 0

                                      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                    4. Step-by-step derivation
                                      1. associate-*r*N/A

                                        \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                      2. lower-*.f64N/A

                                        \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                      3. mul-1-negN/A

                                        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                      4. lower-neg.f64N/A

                                        \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                      5. lower-/.f64N/A

                                        \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                      6. lower-sqrt.f64N/A

                                        \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                      7. lower-sqrt.f64N/A

                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                      8. *-commutativeN/A

                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                      9. lower-*.f64N/A

                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                      10. +-commutativeN/A

                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                      11. lower-+.f64N/A

                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                      12. +-commutativeN/A

                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                                      13. unpow2N/A

                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                                      14. unpow2N/A

                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                                      15. lower-hypot.f6417.7

                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                                    5. Applied rewrites17.7%

                                      \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                                    6. Step-by-step derivation
                                      1. Applied rewrites17.8%

                                        \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]
                                      2. Step-by-step derivation
                                        1. Applied rewrites28.7%

                                          \[\leadsto \frac{\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \sqrt{F \cdot 2}}{-\color{blue}{B}} \]
                                        2. Taylor expanded in C around 0

                                          \[\leadsto \frac{\sqrt{B + C} \cdot \sqrt{F \cdot 2}}{-B} \]
                                        3. Step-by-step derivation
                                          1. Applied rewrites23.2%

                                            \[\leadsto \frac{\sqrt{C + B} \cdot \sqrt{F \cdot 2}}{-B} \]
                                        4. Recombined 4 regimes into one program.
                                        5. Final simplification28.4%

                                          \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -1 \cdot 10^{+52}:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot 2} \cdot \left(\sqrt{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)} \cdot \frac{-\sqrt{F}}{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}\right)\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -1 \cdot 10^{-200}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{-B}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq 0:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot 2} \cdot \left(\sqrt{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)} \cdot \frac{-\sqrt{F}}{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}\right)\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq \infty:\\ \;\;\;\;\frac{-1}{\frac{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot \left(\left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot F\right) \cdot 2\right)}}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{C + B} \cdot \sqrt{F \cdot 2}}{-B}\\ \end{array} \]
                                        6. Add Preprocessing

                                        Alternative 7: 53.2% accurate, 1.4× speedup?

                                        \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4 \cdot A, C, B\_m \cdot B\_m\right)\\ t_1 := \mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C \cdot 2\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 10^{-243}:\\ \;\;\;\;\sqrt{t\_1 \cdot 2} \cdot \left(\sqrt{t\_0} \cdot \frac{-\sqrt{F}}{t\_0}\right)\\ \mathbf{elif}\;{B\_m}^{2} \leq 200:\\ \;\;\;\;\frac{\sqrt{\left(\left(t\_0 \cdot t\_1\right) \cdot 2\right) \cdot F}}{-t\_0}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\mathsf{hypot}\left(C, B\_m\right) + C} \cdot \left(-\sqrt{F \cdot 2}\right)}{B\_m}\\ \end{array} \end{array} \]
                                        B_m = (fabs.f64 B)
                                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                        (FPCore (A B_m C F)
                                         :precision binary64
                                         (let* ((t_0 (fma (* -4.0 A) C (* B_m B_m)))
                                                (t_1 (fma -0.5 (/ (* B_m B_m) A) (* C 2.0))))
                                           (if (<= (pow B_m 2.0) 1e-243)
                                             (* (sqrt (* t_1 2.0)) (* (sqrt t_0) (/ (- (sqrt F)) t_0)))
                                             (if (<= (pow B_m 2.0) 200.0)
                                               (/ (sqrt (* (* (* t_0 t_1) 2.0) F)) (- t_0))
                                               (/ (* (sqrt (+ (hypot C B_m) C)) (- (sqrt (* F 2.0)))) B_m)))))
                                        B_m = fabs(B);
                                        assert(A < B_m && B_m < C && C < F);
                                        double code(double A, double B_m, double C, double F) {
                                        	double t_0 = fma((-4.0 * A), C, (B_m * B_m));
                                        	double t_1 = fma(-0.5, ((B_m * B_m) / A), (C * 2.0));
                                        	double tmp;
                                        	if (pow(B_m, 2.0) <= 1e-243) {
                                        		tmp = sqrt((t_1 * 2.0)) * (sqrt(t_0) * (-sqrt(F) / t_0));
                                        	} else if (pow(B_m, 2.0) <= 200.0) {
                                        		tmp = sqrt((((t_0 * t_1) * 2.0) * F)) / -t_0;
                                        	} else {
                                        		tmp = (sqrt((hypot(C, B_m) + C)) * -sqrt((F * 2.0))) / B_m;
                                        	}
                                        	return tmp;
                                        }
                                        
                                        B_m = abs(B)
                                        A, B_m, C, F = sort([A, B_m, C, F])
                                        function code(A, B_m, C, F)
                                        	t_0 = fma(Float64(-4.0 * A), C, Float64(B_m * B_m))
                                        	t_1 = fma(-0.5, Float64(Float64(B_m * B_m) / A), Float64(C * 2.0))
                                        	tmp = 0.0
                                        	if ((B_m ^ 2.0) <= 1e-243)
                                        		tmp = Float64(sqrt(Float64(t_1 * 2.0)) * Float64(sqrt(t_0) * Float64(Float64(-sqrt(F)) / t_0)));
                                        	elseif ((B_m ^ 2.0) <= 200.0)
                                        		tmp = Float64(sqrt(Float64(Float64(Float64(t_0 * t_1) * 2.0) * F)) / Float64(-t_0));
                                        	else
                                        		tmp = Float64(Float64(sqrt(Float64(hypot(C, B_m) + C)) * Float64(-sqrt(Float64(F * 2.0)))) / B_m);
                                        	end
                                        	return tmp
                                        end
                                        
                                        B_m = N[Abs[B], $MachinePrecision]
                                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                        code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(-4.0 * A), $MachinePrecision] * C + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] + N[(C * 2.0), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e-243], N[(N[Sqrt[N[(t$95$1 * 2.0), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[t$95$0], $MachinePrecision] * N[((-N[Sqrt[F], $MachinePrecision]) / t$95$0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 200.0], N[(N[Sqrt[N[(N[(N[(t$95$0 * t$95$1), $MachinePrecision] * 2.0), $MachinePrecision] * F), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], N[(N[(N[Sqrt[N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision])), $MachinePrecision] / B$95$m), $MachinePrecision]]]]]
                                        
                                        \begin{array}{l}
                                        B_m = \left|B\right|
                                        \\
                                        [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                        \\
                                        \begin{array}{l}
                                        t_0 := \mathsf{fma}\left(-4 \cdot A, C, B\_m \cdot B\_m\right)\\
                                        t_1 := \mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C \cdot 2\right)\\
                                        \mathbf{if}\;{B\_m}^{2} \leq 10^{-243}:\\
                                        \;\;\;\;\sqrt{t\_1 \cdot 2} \cdot \left(\sqrt{t\_0} \cdot \frac{-\sqrt{F}}{t\_0}\right)\\
                                        
                                        \mathbf{elif}\;{B\_m}^{2} \leq 200:\\
                                        \;\;\;\;\frac{\sqrt{\left(\left(t\_0 \cdot t\_1\right) \cdot 2\right) \cdot F}}{-t\_0}\\
                                        
                                        \mathbf{else}:\\
                                        \;\;\;\;\frac{\sqrt{\mathsf{hypot}\left(C, B\_m\right) + C} \cdot \left(-\sqrt{F \cdot 2}\right)}{B\_m}\\
                                        
                                        
                                        \end{array}
                                        \end{array}
                                        
                                        Derivation
                                        1. Split input into 3 regimes
                                        2. if (pow.f64 B #s(literal 2 binary64)) < 9.99999999999999995e-244

                                          1. Initial program 17.7%

                                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                          2. Add Preprocessing
                                          3. Taylor expanded in A around -inf

                                            \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                          4. Step-by-step derivation
                                            1. *-commutativeN/A

                                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\color{blue}{\frac{{B}^{2}}{A} \cdot \frac{-1}{2}} + 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            2. lower-fma.f64N/A

                                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{{B}^{2}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            3. lower-/.f64N/A

                                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\color{blue}{\frac{{B}^{2}}{A}}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            4. unpow2N/A

                                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            5. lower-*.f64N/A

                                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            6. lower-*.f6417.3

                                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, \color{blue}{2 \cdot C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                          5. Applied rewrites17.3%

                                            \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                          6. Step-by-step derivation
                                            1. lift-sqrt.f64N/A

                                              \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            2. lift-*.f64N/A

                                              \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            3. *-commutativeN/A

                                              \[\leadsto \frac{-\sqrt{\color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            4. lift-*.f64N/A

                                              \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            5. lift-*.f64N/A

                                              \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            6. associate-*r*N/A

                                              \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            7. associate-*r*N/A

                                              \[\leadsto \frac{-\sqrt{\color{blue}{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                          7. Applied rewrites17.6%

                                            \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                          8. Applied rewrites17.4%

                                            \[\leadsto \color{blue}{\sqrt{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, C \cdot 2\right) \cdot 2\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \left(\left(-\sqrt{F}\right) \cdot {\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)\right)}^{-1}\right)} \]
                                          9. Applied rewrites21.5%

                                            \[\leadsto \color{blue}{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot 2} \cdot \left(\sqrt{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)} \cdot \frac{-\sqrt{F}}{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}\right)} \]

                                          if 9.99999999999999995e-244 < (pow.f64 B #s(literal 2 binary64)) < 200

                                          1. Initial program 35.7%

                                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                          2. Add Preprocessing
                                          3. Taylor expanded in A around -inf

                                            \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                          4. Step-by-step derivation
                                            1. *-commutativeN/A

                                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\color{blue}{\frac{{B}^{2}}{A} \cdot \frac{-1}{2}} + 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            2. lower-fma.f64N/A

                                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{{B}^{2}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            3. lower-/.f64N/A

                                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\color{blue}{\frac{{B}^{2}}{A}}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            4. unpow2N/A

                                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            5. lower-*.f64N/A

                                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            6. lower-*.f6425.5

                                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, \color{blue}{2 \cdot C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                          5. Applied rewrites25.5%

                                            \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                          6. Step-by-step derivation
                                            1. lift-sqrt.f64N/A

                                              \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            2. lift-*.f64N/A

                                              \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            3. *-commutativeN/A

                                              \[\leadsto \frac{-\sqrt{\color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            4. lift-*.f64N/A

                                              \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            5. lift-*.f64N/A

                                              \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            6. associate-*r*N/A

                                              \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            7. associate-*r*N/A

                                              \[\leadsto \frac{-\sqrt{\color{blue}{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                          7. Applied rewrites22.5%

                                            \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                          8. Applied rewrites22.5%

                                            \[\leadsto \color{blue}{\sqrt{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, C \cdot 2\right) \cdot 2\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \left(\left(-\sqrt{F}\right) \cdot {\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)\right)}^{-1}\right)} \]
                                          9. Applied rewrites25.3%

                                            \[\leadsto \color{blue}{\frac{-\sqrt{\left(\left(\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right) \cdot \mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right)\right) \cdot 2\right) \cdot F}}{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}} \]

                                          if 200 < (pow.f64 B #s(literal 2 binary64))

                                          1. Initial program 18.8%

                                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                          2. Add Preprocessing
                                          3. Taylor expanded in A around 0

                                            \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                          4. Step-by-step derivation
                                            1. associate-*r*N/A

                                              \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                            2. lower-*.f64N/A

                                              \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                            3. mul-1-negN/A

                                              \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                            4. lower-neg.f64N/A

                                              \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                            5. lower-/.f64N/A

                                              \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                            6. lower-sqrt.f64N/A

                                              \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                            7. lower-sqrt.f64N/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                            8. *-commutativeN/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                            9. lower-*.f64N/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                            10. +-commutativeN/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                            11. lower-+.f64N/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                            12. +-commutativeN/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                                            13. unpow2N/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                                            14. unpow2N/A

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                                            15. lower-hypot.f6427.0

                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                                          5. Applied rewrites27.0%

                                            \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                                          6. Step-by-step derivation
                                            1. Applied rewrites27.0%

                                              \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]
                                            2. Step-by-step derivation
                                              1. Applied rewrites36.8%

                                                \[\leadsto \frac{\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \sqrt{F \cdot 2}}{-\color{blue}{B}} \]
                                            3. Recombined 3 regimes into one program.
                                            4. Final simplification29.6%

                                              \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 10^{-243}:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot 2} \cdot \left(\sqrt{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)} \cdot \frac{-\sqrt{F}}{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}\right)\\ \mathbf{elif}\;{B}^{2} \leq 200:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right) \cdot \mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right)\right) \cdot 2\right) \cdot F}}{-\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \left(-\sqrt{F \cdot 2}\right)}{B}\\ \end{array} \]
                                            5. Add Preprocessing

                                            Alternative 8: 53.2% accurate, 1.4× speedup?

                                            \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4 \cdot A, C, B\_m \cdot B\_m\right)\\ t_1 := \mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C \cdot 2\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 10^{-243}:\\ \;\;\;\;\sqrt{t\_1 \cdot 2} \cdot \left(\sqrt{t\_0} \cdot \frac{-\sqrt{F}}{t\_0}\right)\\ \mathbf{elif}\;{B\_m}^{2} \leq 200:\\ \;\;\;\;\frac{\sqrt{\left(\left(t\_0 \cdot t\_1\right) \cdot 2\right) \cdot F}}{-t\_0}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{F \cdot 2} \cdot \frac{\sqrt{\mathsf{hypot}\left(C, B\_m\right) + C}}{-B\_m}\\ \end{array} \end{array} \]
                                            B_m = (fabs.f64 B)
                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                            (FPCore (A B_m C F)
                                             :precision binary64
                                             (let* ((t_0 (fma (* -4.0 A) C (* B_m B_m)))
                                                    (t_1 (fma -0.5 (/ (* B_m B_m) A) (* C 2.0))))
                                               (if (<= (pow B_m 2.0) 1e-243)
                                                 (* (sqrt (* t_1 2.0)) (* (sqrt t_0) (/ (- (sqrt F)) t_0)))
                                                 (if (<= (pow B_m 2.0) 200.0)
                                                   (/ (sqrt (* (* (* t_0 t_1) 2.0) F)) (- t_0))
                                                   (* (sqrt (* F 2.0)) (/ (sqrt (+ (hypot C B_m) C)) (- B_m)))))))
                                            B_m = fabs(B);
                                            assert(A < B_m && B_m < C && C < F);
                                            double code(double A, double B_m, double C, double F) {
                                            	double t_0 = fma((-4.0 * A), C, (B_m * B_m));
                                            	double t_1 = fma(-0.5, ((B_m * B_m) / A), (C * 2.0));
                                            	double tmp;
                                            	if (pow(B_m, 2.0) <= 1e-243) {
                                            		tmp = sqrt((t_1 * 2.0)) * (sqrt(t_0) * (-sqrt(F) / t_0));
                                            	} else if (pow(B_m, 2.0) <= 200.0) {
                                            		tmp = sqrt((((t_0 * t_1) * 2.0) * F)) / -t_0;
                                            	} else {
                                            		tmp = sqrt((F * 2.0)) * (sqrt((hypot(C, B_m) + C)) / -B_m);
                                            	}
                                            	return tmp;
                                            }
                                            
                                            B_m = abs(B)
                                            A, B_m, C, F = sort([A, B_m, C, F])
                                            function code(A, B_m, C, F)
                                            	t_0 = fma(Float64(-4.0 * A), C, Float64(B_m * B_m))
                                            	t_1 = fma(-0.5, Float64(Float64(B_m * B_m) / A), Float64(C * 2.0))
                                            	tmp = 0.0
                                            	if ((B_m ^ 2.0) <= 1e-243)
                                            		tmp = Float64(sqrt(Float64(t_1 * 2.0)) * Float64(sqrt(t_0) * Float64(Float64(-sqrt(F)) / t_0)));
                                            	elseif ((B_m ^ 2.0) <= 200.0)
                                            		tmp = Float64(sqrt(Float64(Float64(Float64(t_0 * t_1) * 2.0) * F)) / Float64(-t_0));
                                            	else
                                            		tmp = Float64(sqrt(Float64(F * 2.0)) * Float64(sqrt(Float64(hypot(C, B_m) + C)) / Float64(-B_m)));
                                            	end
                                            	return tmp
                                            end
                                            
                                            B_m = N[Abs[B], $MachinePrecision]
                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                            code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(-4.0 * A), $MachinePrecision] * C + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] + N[(C * 2.0), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e-243], N[(N[Sqrt[N[(t$95$1 * 2.0), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[t$95$0], $MachinePrecision] * N[((-N[Sqrt[F], $MachinePrecision]) / t$95$0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 200.0], N[(N[Sqrt[N[(N[(N[(t$95$0 * t$95$1), $MachinePrecision] * 2.0), $MachinePrecision] * F), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], N[(N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision]), $MachinePrecision]]]]]
                                            
                                            \begin{array}{l}
                                            B_m = \left|B\right|
                                            \\
                                            [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                            \\
                                            \begin{array}{l}
                                            t_0 := \mathsf{fma}\left(-4 \cdot A, C, B\_m \cdot B\_m\right)\\
                                            t_1 := \mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C \cdot 2\right)\\
                                            \mathbf{if}\;{B\_m}^{2} \leq 10^{-243}:\\
                                            \;\;\;\;\sqrt{t\_1 \cdot 2} \cdot \left(\sqrt{t\_0} \cdot \frac{-\sqrt{F}}{t\_0}\right)\\
                                            
                                            \mathbf{elif}\;{B\_m}^{2} \leq 200:\\
                                            \;\;\;\;\frac{\sqrt{\left(\left(t\_0 \cdot t\_1\right) \cdot 2\right) \cdot F}}{-t\_0}\\
                                            
                                            \mathbf{else}:\\
                                            \;\;\;\;\sqrt{F \cdot 2} \cdot \frac{\sqrt{\mathsf{hypot}\left(C, B\_m\right) + C}}{-B\_m}\\
                                            
                                            
                                            \end{array}
                                            \end{array}
                                            
                                            Derivation
                                            1. Split input into 3 regimes
                                            2. if (pow.f64 B #s(literal 2 binary64)) < 9.99999999999999995e-244

                                              1. Initial program 17.7%

                                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              2. Add Preprocessing
                                              3. Taylor expanded in A around -inf

                                                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              4. Step-by-step derivation
                                                1. *-commutativeN/A

                                                  \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\color{blue}{\frac{{B}^{2}}{A} \cdot \frac{-1}{2}} + 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                2. lower-fma.f64N/A

                                                  \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{{B}^{2}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                3. lower-/.f64N/A

                                                  \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\color{blue}{\frac{{B}^{2}}{A}}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                4. unpow2N/A

                                                  \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                5. lower-*.f64N/A

                                                  \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                6. lower-*.f6417.3

                                                  \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, \color{blue}{2 \cdot C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              5. Applied rewrites17.3%

                                                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              6. Step-by-step derivation
                                                1. lift-sqrt.f64N/A

                                                  \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                2. lift-*.f64N/A

                                                  \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                3. *-commutativeN/A

                                                  \[\leadsto \frac{-\sqrt{\color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                4. lift-*.f64N/A

                                                  \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                5. lift-*.f64N/A

                                                  \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                6. associate-*r*N/A

                                                  \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                7. associate-*r*N/A

                                                  \[\leadsto \frac{-\sqrt{\color{blue}{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              7. Applied rewrites17.6%

                                                \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              8. Applied rewrites17.4%

                                                \[\leadsto \color{blue}{\sqrt{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, C \cdot 2\right) \cdot 2\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \left(\left(-\sqrt{F}\right) \cdot {\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)\right)}^{-1}\right)} \]
                                              9. Applied rewrites21.5%

                                                \[\leadsto \color{blue}{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot 2} \cdot \left(\sqrt{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)} \cdot \frac{-\sqrt{F}}{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}\right)} \]

                                              if 9.99999999999999995e-244 < (pow.f64 B #s(literal 2 binary64)) < 200

                                              1. Initial program 35.7%

                                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              2. Add Preprocessing
                                              3. Taylor expanded in A around -inf

                                                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              4. Step-by-step derivation
                                                1. *-commutativeN/A

                                                  \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\color{blue}{\frac{{B}^{2}}{A} \cdot \frac{-1}{2}} + 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                2. lower-fma.f64N/A

                                                  \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{{B}^{2}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                3. lower-/.f64N/A

                                                  \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\color{blue}{\frac{{B}^{2}}{A}}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                4. unpow2N/A

                                                  \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                5. lower-*.f64N/A

                                                  \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                6. lower-*.f6425.5

                                                  \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, \color{blue}{2 \cdot C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              5. Applied rewrites25.5%

                                                \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              6. Step-by-step derivation
                                                1. lift-sqrt.f64N/A

                                                  \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                2. lift-*.f64N/A

                                                  \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                3. *-commutativeN/A

                                                  \[\leadsto \frac{-\sqrt{\color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                4. lift-*.f64N/A

                                                  \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                5. lift-*.f64N/A

                                                  \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                6. associate-*r*N/A

                                                  \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                7. associate-*r*N/A

                                                  \[\leadsto \frac{-\sqrt{\color{blue}{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              7. Applied rewrites22.5%

                                                \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              8. Applied rewrites22.5%

                                                \[\leadsto \color{blue}{\sqrt{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, C \cdot 2\right) \cdot 2\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \left(\left(-\sqrt{F}\right) \cdot {\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)\right)}^{-1}\right)} \]
                                              9. Applied rewrites25.3%

                                                \[\leadsto \color{blue}{\frac{-\sqrt{\left(\left(\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right) \cdot \mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right)\right) \cdot 2\right) \cdot F}}{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}} \]

                                              if 200 < (pow.f64 B #s(literal 2 binary64))

                                              1. Initial program 18.8%

                                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                              2. Add Preprocessing
                                              3. Taylor expanded in A around 0

                                                \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                              4. Step-by-step derivation
                                                1. associate-*r*N/A

                                                  \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                2. lower-*.f64N/A

                                                  \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                3. mul-1-negN/A

                                                  \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                4. lower-neg.f64N/A

                                                  \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                5. lower-/.f64N/A

                                                  \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                6. lower-sqrt.f64N/A

                                                  \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                7. lower-sqrt.f64N/A

                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                8. *-commutativeN/A

                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                9. lower-*.f64N/A

                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                10. +-commutativeN/A

                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                11. lower-+.f64N/A

                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                12. +-commutativeN/A

                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                                                13. unpow2N/A

                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                                                14. unpow2N/A

                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                                                15. lower-hypot.f6427.0

                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                                              5. Applied rewrites27.0%

                                                \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                                              6. Step-by-step derivation
                                                1. Applied rewrites27.0%

                                                  \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]
                                                2. Step-by-step derivation
                                                  1. Applied rewrites36.8%

                                                    \[\leadsto \frac{\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \sqrt{F \cdot 2}}{-\color{blue}{B}} \]
                                                  2. Step-by-step derivation
                                                    1. Applied rewrites36.9%

                                                      \[\leadsto \sqrt{F \cdot 2} \cdot \color{blue}{\frac{\sqrt{\mathsf{hypot}\left(C, B\right) + C}}{-B}} \]
                                                  3. Recombined 3 regimes into one program.
                                                  4. Final simplification29.6%

                                                    \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 10^{-243}:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot 2} \cdot \left(\sqrt{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)} \cdot \frac{-\sqrt{F}}{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}\right)\\ \mathbf{elif}\;{B}^{2} \leq 200:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right) \cdot \mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right)\right) \cdot 2\right) \cdot F}}{-\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{F \cdot 2} \cdot \frac{\sqrt{\mathsf{hypot}\left(C, B\right) + C}}{-B}\\ \end{array} \]
                                                  5. Add Preprocessing

                                                  Alternative 9: 49.7% accurate, 2.3× speedup?

                                                  \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 10^{+73}:\\ \;\;\;\;\sqrt{\left(\mathsf{fma}\left(\frac{B\_m \cdot B\_m}{A}, -0.5, C \cdot 2\right) \cdot 2\right) \cdot t\_0} \cdot \frac{-\sqrt{F}}{t\_0}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{C + B\_m} \cdot \sqrt{F \cdot 2}}{-B\_m}\\ \end{array} \end{array} \]
                                                  B_m = (fabs.f64 B)
                                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                  (FPCore (A B_m C F)
                                                   :precision binary64
                                                   (let* ((t_0 (fma (* -4.0 C) A (* B_m B_m))))
                                                     (if (<= (pow B_m 2.0) 1e+73)
                                                       (*
                                                        (sqrt (* (* (fma (/ (* B_m B_m) A) -0.5 (* C 2.0)) 2.0) t_0))
                                                        (/ (- (sqrt F)) t_0))
                                                       (/ (* (sqrt (+ C B_m)) (sqrt (* F 2.0))) (- B_m)))))
                                                  B_m = fabs(B);
                                                  assert(A < B_m && B_m < C && C < F);
                                                  double code(double A, double B_m, double C, double F) {
                                                  	double t_0 = fma((-4.0 * C), A, (B_m * B_m));
                                                  	double tmp;
                                                  	if (pow(B_m, 2.0) <= 1e+73) {
                                                  		tmp = sqrt(((fma(((B_m * B_m) / A), -0.5, (C * 2.0)) * 2.0) * t_0)) * (-sqrt(F) / t_0);
                                                  	} else {
                                                  		tmp = (sqrt((C + B_m)) * sqrt((F * 2.0))) / -B_m;
                                                  	}
                                                  	return tmp;
                                                  }
                                                  
                                                  B_m = abs(B)
                                                  A, B_m, C, F = sort([A, B_m, C, F])
                                                  function code(A, B_m, C, F)
                                                  	t_0 = fma(Float64(-4.0 * C), A, Float64(B_m * B_m))
                                                  	tmp = 0.0
                                                  	if ((B_m ^ 2.0) <= 1e+73)
                                                  		tmp = Float64(sqrt(Float64(Float64(fma(Float64(Float64(B_m * B_m) / A), -0.5, Float64(C * 2.0)) * 2.0) * t_0)) * Float64(Float64(-sqrt(F)) / t_0));
                                                  	else
                                                  		tmp = Float64(Float64(sqrt(Float64(C + B_m)) * sqrt(Float64(F * 2.0))) / Float64(-B_m));
                                                  	end
                                                  	return tmp
                                                  end
                                                  
                                                  B_m = N[Abs[B], $MachinePrecision]
                                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                  code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(-4.0 * C), $MachinePrecision] * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e+73], N[(N[Sqrt[N[(N[(N[(N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] * -0.5 + N[(C * 2.0), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision] * t$95$0), $MachinePrecision]], $MachinePrecision] * N[((-N[Sqrt[F], $MachinePrecision]) / t$95$0), $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(C + B$95$m), $MachinePrecision]], $MachinePrecision] * N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / (-B$95$m)), $MachinePrecision]]]
                                                  
                                                  \begin{array}{l}
                                                  B_m = \left|B\right|
                                                  \\
                                                  [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                  \\
                                                  \begin{array}{l}
                                                  t_0 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\
                                                  \mathbf{if}\;{B\_m}^{2} \leq 10^{+73}:\\
                                                  \;\;\;\;\sqrt{\left(\mathsf{fma}\left(\frac{B\_m \cdot B\_m}{A}, -0.5, C \cdot 2\right) \cdot 2\right) \cdot t\_0} \cdot \frac{-\sqrt{F}}{t\_0}\\
                                                  
                                                  \mathbf{else}:\\
                                                  \;\;\;\;\frac{\sqrt{C + B\_m} \cdot \sqrt{F \cdot 2}}{-B\_m}\\
                                                  
                                                  
                                                  \end{array}
                                                  \end{array}
                                                  
                                                  Derivation
                                                  1. Split input into 2 regimes
                                                  2. if (pow.f64 B #s(literal 2 binary64)) < 9.99999999999999983e72

                                                    1. Initial program 27.0%

                                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                    2. Add Preprocessing
                                                    3. Taylor expanded in A around -inf

                                                      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                    4. Step-by-step derivation
                                                      1. *-commutativeN/A

                                                        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\color{blue}{\frac{{B}^{2}}{A} \cdot \frac{-1}{2}} + 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      2. lower-fma.f64N/A

                                                        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{{B}^{2}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      3. lower-/.f64N/A

                                                        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\color{blue}{\frac{{B}^{2}}{A}}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      4. unpow2N/A

                                                        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      5. lower-*.f64N/A

                                                        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      6. lower-*.f6419.1

                                                        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, \color{blue}{2 \cdot C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                    5. Applied rewrites19.1%

                                                      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                    6. Step-by-step derivation
                                                      1. lift-sqrt.f64N/A

                                                        \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      2. lift-*.f64N/A

                                                        \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      3. *-commutativeN/A

                                                        \[\leadsto \frac{-\sqrt{\color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      4. lift-*.f64N/A

                                                        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      5. lift-*.f64N/A

                                                        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      6. associate-*r*N/A

                                                        \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      7. associate-*r*N/A

                                                        \[\leadsto \frac{-\sqrt{\color{blue}{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                    7. Applied rewrites18.8%

                                                      \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                    8. Applied rewrites18.7%

                                                      \[\leadsto \color{blue}{\sqrt{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, C \cdot 2\right) \cdot 2\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \frac{-\sqrt{F}}{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}} \]

                                                    if 9.99999999999999983e72 < (pow.f64 B #s(literal 2 binary64))

                                                    1. Initial program 14.9%

                                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                    2. Add Preprocessing
                                                    3. Taylor expanded in A around 0

                                                      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                    4. Step-by-step derivation
                                                      1. associate-*r*N/A

                                                        \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                      2. lower-*.f64N/A

                                                        \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                      3. mul-1-negN/A

                                                        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                      4. lower-neg.f64N/A

                                                        \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                      5. lower-/.f64N/A

                                                        \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                      6. lower-sqrt.f64N/A

                                                        \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                      7. lower-sqrt.f64N/A

                                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                      8. *-commutativeN/A

                                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                      9. lower-*.f64N/A

                                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                      10. +-commutativeN/A

                                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                      11. lower-+.f64N/A

                                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                      12. +-commutativeN/A

                                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                                                      13. unpow2N/A

                                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                                                      14. unpow2N/A

                                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                                                      15. lower-hypot.f6428.1

                                                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                                                    5. Applied rewrites28.1%

                                                      \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                                                    6. Step-by-step derivation
                                                      1. Applied rewrites28.2%

                                                        \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]
                                                      2. Step-by-step derivation
                                                        1. Applied rewrites39.6%

                                                          \[\leadsto \frac{\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \sqrt{F \cdot 2}}{-\color{blue}{B}} \]
                                                        2. Taylor expanded in C around 0

                                                          \[\leadsto \frac{\sqrt{B + C} \cdot \sqrt{F \cdot 2}}{-B} \]
                                                        3. Step-by-step derivation
                                                          1. Applied rewrites33.2%

                                                            \[\leadsto \frac{\sqrt{C + B} \cdot \sqrt{F \cdot 2}}{-B} \]
                                                        4. Recombined 2 regimes into one program.
                                                        5. Add Preprocessing

                                                        Alternative 10: 52.4% accurate, 2.4× speedup?

                                                        \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 200:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C \cdot 2\right) \cdot \left(\left(t\_0 \cdot F\right) \cdot 2\right)}}{-t\_0}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{C + B\_m} \cdot \sqrt{F \cdot 2}}{-B\_m}\\ \end{array} \end{array} \]
                                                        B_m = (fabs.f64 B)
                                                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                        (FPCore (A B_m C F)
                                                         :precision binary64
                                                         (let* ((t_0 (fma (* C A) -4.0 (* B_m B_m))))
                                                           (if (<= (pow B_m 2.0) 200.0)
                                                             (/
                                                              (sqrt (* (fma -0.5 (/ (* B_m B_m) A) (* C 2.0)) (* (* t_0 F) 2.0)))
                                                              (- t_0))
                                                             (/ (* (sqrt (+ C B_m)) (sqrt (* F 2.0))) (- B_m)))))
                                                        B_m = fabs(B);
                                                        assert(A < B_m && B_m < C && C < F);
                                                        double code(double A, double B_m, double C, double F) {
                                                        	double t_0 = fma((C * A), -4.0, (B_m * B_m));
                                                        	double tmp;
                                                        	if (pow(B_m, 2.0) <= 200.0) {
                                                        		tmp = sqrt((fma(-0.5, ((B_m * B_m) / A), (C * 2.0)) * ((t_0 * F) * 2.0))) / -t_0;
                                                        	} else {
                                                        		tmp = (sqrt((C + B_m)) * sqrt((F * 2.0))) / -B_m;
                                                        	}
                                                        	return tmp;
                                                        }
                                                        
                                                        B_m = abs(B)
                                                        A, B_m, C, F = sort([A, B_m, C, F])
                                                        function code(A, B_m, C, F)
                                                        	t_0 = fma(Float64(C * A), -4.0, Float64(B_m * B_m))
                                                        	tmp = 0.0
                                                        	if ((B_m ^ 2.0) <= 200.0)
                                                        		tmp = Float64(sqrt(Float64(fma(-0.5, Float64(Float64(B_m * B_m) / A), Float64(C * 2.0)) * Float64(Float64(t_0 * F) * 2.0))) / Float64(-t_0));
                                                        	else
                                                        		tmp = Float64(Float64(sqrt(Float64(C + B_m)) * sqrt(Float64(F * 2.0))) / Float64(-B_m));
                                                        	end
                                                        	return tmp
                                                        end
                                                        
                                                        B_m = N[Abs[B], $MachinePrecision]
                                                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                        code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(C * A), $MachinePrecision] * -4.0 + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 200.0], N[(N[Sqrt[N[(N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] + N[(C * 2.0), $MachinePrecision]), $MachinePrecision] * N[(N[(t$95$0 * F), $MachinePrecision] * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], N[(N[(N[Sqrt[N[(C + B$95$m), $MachinePrecision]], $MachinePrecision] * N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / (-B$95$m)), $MachinePrecision]]]
                                                        
                                                        \begin{array}{l}
                                                        B_m = \left|B\right|
                                                        \\
                                                        [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                        \\
                                                        \begin{array}{l}
                                                        t_0 := \mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)\\
                                                        \mathbf{if}\;{B\_m}^{2} \leq 200:\\
                                                        \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C \cdot 2\right) \cdot \left(\left(t\_0 \cdot F\right) \cdot 2\right)}}{-t\_0}\\
                                                        
                                                        \mathbf{else}:\\
                                                        \;\;\;\;\frac{\sqrt{C + B\_m} \cdot \sqrt{F \cdot 2}}{-B\_m}\\
                                                        
                                                        
                                                        \end{array}
                                                        \end{array}
                                                        
                                                        Derivation
                                                        1. Split input into 2 regimes
                                                        2. if (pow.f64 B #s(literal 2 binary64)) < 200

                                                          1. Initial program 25.0%

                                                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                          2. Add Preprocessing
                                                          3. Taylor expanded in A around -inf

                                                            \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                          4. Step-by-step derivation
                                                            1. *-commutativeN/A

                                                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\color{blue}{\frac{{B}^{2}}{A} \cdot \frac{-1}{2}} + 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                            2. lower-fma.f64N/A

                                                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{{B}^{2}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                            3. lower-/.f64N/A

                                                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\color{blue}{\frac{{B}^{2}}{A}}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                            4. unpow2N/A

                                                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                            5. lower-*.f64N/A

                                                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                            6. lower-*.f6420.7

                                                              \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, \color{blue}{2 \cdot C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                          5. Applied rewrites20.7%

                                                            \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                          6. Applied rewrites20.7%

                                                            \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot \left(\left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot F\right) \cdot 2\right)}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \]

                                                          if 200 < (pow.f64 B #s(literal 2 binary64))

                                                          1. Initial program 18.8%

                                                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                          2. Add Preprocessing
                                                          3. Taylor expanded in A around 0

                                                            \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                          4. Step-by-step derivation
                                                            1. associate-*r*N/A

                                                              \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                            2. lower-*.f64N/A

                                                              \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                            3. mul-1-negN/A

                                                              \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                            4. lower-neg.f64N/A

                                                              \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                            5. lower-/.f64N/A

                                                              \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                            6. lower-sqrt.f64N/A

                                                              \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                            7. lower-sqrt.f64N/A

                                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                            8. *-commutativeN/A

                                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                            9. lower-*.f64N/A

                                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                            10. +-commutativeN/A

                                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                            11. lower-+.f64N/A

                                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                            12. +-commutativeN/A

                                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                                                            13. unpow2N/A

                                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                                                            14. unpow2N/A

                                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                                                            15. lower-hypot.f6427.0

                                                              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                                                          5. Applied rewrites27.0%

                                                            \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                                                          6. Step-by-step derivation
                                                            1. Applied rewrites27.0%

                                                              \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]
                                                            2. Step-by-step derivation
                                                              1. Applied rewrites36.8%

                                                                \[\leadsto \frac{\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \sqrt{F \cdot 2}}{-\color{blue}{B}} \]
                                                              2. Taylor expanded in C around 0

                                                                \[\leadsto \frac{\sqrt{B + C} \cdot \sqrt{F \cdot 2}}{-B} \]
                                                              3. Step-by-step derivation
                                                                1. Applied rewrites30.4%

                                                                  \[\leadsto \frac{\sqrt{C + B} \cdot \sqrt{F \cdot 2}}{-B} \]
                                                              4. Recombined 2 regimes into one program.
                                                              5. Add Preprocessing

                                                              Alternative 11: 49.9% accurate, 2.4× speedup?

                                                              \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4 \cdot A, C, B\_m \cdot B\_m\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 200:\\ \;\;\;\;\frac{\sqrt{\left(\left(t\_0 \cdot \mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C \cdot 2\right)\right) \cdot 2\right) \cdot F}}{-t\_0}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{C + B\_m} \cdot \sqrt{F \cdot 2}}{-B\_m}\\ \end{array} \end{array} \]
                                                              B_m = (fabs.f64 B)
                                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                              (FPCore (A B_m C F)
                                                               :precision binary64
                                                               (let* ((t_0 (fma (* -4.0 A) C (* B_m B_m))))
                                                                 (if (<= (pow B_m 2.0) 200.0)
                                                                   (/
                                                                    (sqrt (* (* (* t_0 (fma -0.5 (/ (* B_m B_m) A) (* C 2.0))) 2.0) F))
                                                                    (- t_0))
                                                                   (/ (* (sqrt (+ C B_m)) (sqrt (* F 2.0))) (- B_m)))))
                                                              B_m = fabs(B);
                                                              assert(A < B_m && B_m < C && C < F);
                                                              double code(double A, double B_m, double C, double F) {
                                                              	double t_0 = fma((-4.0 * A), C, (B_m * B_m));
                                                              	double tmp;
                                                              	if (pow(B_m, 2.0) <= 200.0) {
                                                              		tmp = sqrt((((t_0 * fma(-0.5, ((B_m * B_m) / A), (C * 2.0))) * 2.0) * F)) / -t_0;
                                                              	} else {
                                                              		tmp = (sqrt((C + B_m)) * sqrt((F * 2.0))) / -B_m;
                                                              	}
                                                              	return tmp;
                                                              }
                                                              
                                                              B_m = abs(B)
                                                              A, B_m, C, F = sort([A, B_m, C, F])
                                                              function code(A, B_m, C, F)
                                                              	t_0 = fma(Float64(-4.0 * A), C, Float64(B_m * B_m))
                                                              	tmp = 0.0
                                                              	if ((B_m ^ 2.0) <= 200.0)
                                                              		tmp = Float64(sqrt(Float64(Float64(Float64(t_0 * fma(-0.5, Float64(Float64(B_m * B_m) / A), Float64(C * 2.0))) * 2.0) * F)) / Float64(-t_0));
                                                              	else
                                                              		tmp = Float64(Float64(sqrt(Float64(C + B_m)) * sqrt(Float64(F * 2.0))) / Float64(-B_m));
                                                              	end
                                                              	return tmp
                                                              end
                                                              
                                                              B_m = N[Abs[B], $MachinePrecision]
                                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                              code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(-4.0 * A), $MachinePrecision] * C + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 200.0], N[(N[Sqrt[N[(N[(N[(t$95$0 * N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] + N[(C * 2.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision] * F), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], N[(N[(N[Sqrt[N[(C + B$95$m), $MachinePrecision]], $MachinePrecision] * N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / (-B$95$m)), $MachinePrecision]]]
                                                              
                                                              \begin{array}{l}
                                                              B_m = \left|B\right|
                                                              \\
                                                              [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                              \\
                                                              \begin{array}{l}
                                                              t_0 := \mathsf{fma}\left(-4 \cdot A, C, B\_m \cdot B\_m\right)\\
                                                              \mathbf{if}\;{B\_m}^{2} \leq 200:\\
                                                              \;\;\;\;\frac{\sqrt{\left(\left(t\_0 \cdot \mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C \cdot 2\right)\right) \cdot 2\right) \cdot F}}{-t\_0}\\
                                                              
                                                              \mathbf{else}:\\
                                                              \;\;\;\;\frac{\sqrt{C + B\_m} \cdot \sqrt{F \cdot 2}}{-B\_m}\\
                                                              
                                                              
                                                              \end{array}
                                                              \end{array}
                                                              
                                                              Derivation
                                                              1. Split input into 2 regimes
                                                              2. if (pow.f64 B #s(literal 2 binary64)) < 200

                                                                1. Initial program 25.0%

                                                                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                2. Add Preprocessing
                                                                3. Taylor expanded in A around -inf

                                                                  \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                4. Step-by-step derivation
                                                                  1. *-commutativeN/A

                                                                    \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\color{blue}{\frac{{B}^{2}}{A} \cdot \frac{-1}{2}} + 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                  2. lower-fma.f64N/A

                                                                    \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{{B}^{2}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                  3. lower-/.f64N/A

                                                                    \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\color{blue}{\frac{{B}^{2}}{A}}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                  4. unpow2N/A

                                                                    \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                  5. lower-*.f64N/A

                                                                    \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                  6. lower-*.f6420.7

                                                                    \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, \color{blue}{2 \cdot C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                5. Applied rewrites20.7%

                                                                  \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                6. Step-by-step derivation
                                                                  1. lift-sqrt.f64N/A

                                                                    \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                  2. lift-*.f64N/A

                                                                    \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                  3. *-commutativeN/A

                                                                    \[\leadsto \frac{-\sqrt{\color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                  4. lift-*.f64N/A

                                                                    \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                  5. lift-*.f64N/A

                                                                    \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                  6. associate-*r*N/A

                                                                    \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                  7. associate-*r*N/A

                                                                    \[\leadsto \frac{-\sqrt{\color{blue}{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                7. Applied rewrites19.6%

                                                                  \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                8. Applied rewrites19.5%

                                                                  \[\leadsto \color{blue}{\sqrt{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, C \cdot 2\right) \cdot 2\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \left(\left(-\sqrt{F}\right) \cdot {\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)\right)}^{-1}\right)} \]
                                                                9. Applied rewrites19.1%

                                                                  \[\leadsto \color{blue}{\frac{-\sqrt{\left(\left(\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right) \cdot \mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right)\right) \cdot 2\right) \cdot F}}{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}} \]

                                                                if 200 < (pow.f64 B #s(literal 2 binary64))

                                                                1. Initial program 18.8%

                                                                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                2. Add Preprocessing
                                                                3. Taylor expanded in A around 0

                                                                  \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                4. Step-by-step derivation
                                                                  1. associate-*r*N/A

                                                                    \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                  2. lower-*.f64N/A

                                                                    \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                  3. mul-1-negN/A

                                                                    \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                  4. lower-neg.f64N/A

                                                                    \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                  5. lower-/.f64N/A

                                                                    \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                  6. lower-sqrt.f64N/A

                                                                    \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                  7. lower-sqrt.f64N/A

                                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                  8. *-commutativeN/A

                                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                                  9. lower-*.f64N/A

                                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                                  10. +-commutativeN/A

                                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                                  11. lower-+.f64N/A

                                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                                  12. +-commutativeN/A

                                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                                                                  13. unpow2N/A

                                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                                                                  14. unpow2N/A

                                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                                                                  15. lower-hypot.f6427.0

                                                                    \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                                                                5. Applied rewrites27.0%

                                                                  \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                                                                6. Step-by-step derivation
                                                                  1. Applied rewrites27.0%

                                                                    \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]
                                                                  2. Step-by-step derivation
                                                                    1. Applied rewrites36.8%

                                                                      \[\leadsto \frac{\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \sqrt{F \cdot 2}}{-\color{blue}{B}} \]
                                                                    2. Taylor expanded in C around 0

                                                                      \[\leadsto \frac{\sqrt{B + C} \cdot \sqrt{F \cdot 2}}{-B} \]
                                                                    3. Step-by-step derivation
                                                                      1. Applied rewrites30.4%

                                                                        \[\leadsto \frac{\sqrt{C + B} \cdot \sqrt{F \cdot 2}}{-B} \]
                                                                    4. Recombined 2 regimes into one program.
                                                                    5. Final simplification24.4%

                                                                      \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 200:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right) \cdot \mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right)\right) \cdot 2\right) \cdot F}}{-\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{C + B} \cdot \sqrt{F \cdot 2}}{-B}\\ \end{array} \]
                                                                    6. Add Preprocessing

                                                                    Alternative 12: 48.2% accurate, 4.0× speedup?

                                                                    \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4 \cdot A, C, B\_m \cdot B\_m\right)\\ t_1 := \mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C \cdot 2\right)\\ \mathbf{if}\;B\_m \leq 1.1 \cdot 10^{-121}:\\ \;\;\;\;\sqrt{t\_1 \cdot 2} \cdot \left(\sqrt{t\_0} \cdot \frac{-\sqrt{F}}{t\_0}\right)\\ \mathbf{elif}\;B\_m \leq 20:\\ \;\;\;\;\frac{\sqrt{\left(\left(t\_0 \cdot t\_1\right) \cdot 2\right) \cdot F}}{-t\_0}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{C + B\_m} \cdot \sqrt{F \cdot 2}}{-B\_m}\\ \end{array} \end{array} \]
                                                                    B_m = (fabs.f64 B)
                                                                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                    (FPCore (A B_m C F)
                                                                     :precision binary64
                                                                     (let* ((t_0 (fma (* -4.0 A) C (* B_m B_m)))
                                                                            (t_1 (fma -0.5 (/ (* B_m B_m) A) (* C 2.0))))
                                                                       (if (<= B_m 1.1e-121)
                                                                         (* (sqrt (* t_1 2.0)) (* (sqrt t_0) (/ (- (sqrt F)) t_0)))
                                                                         (if (<= B_m 20.0)
                                                                           (/ (sqrt (* (* (* t_0 t_1) 2.0) F)) (- t_0))
                                                                           (/ (* (sqrt (+ C B_m)) (sqrt (* F 2.0))) (- B_m))))))
                                                                    B_m = fabs(B);
                                                                    assert(A < B_m && B_m < C && C < F);
                                                                    double code(double A, double B_m, double C, double F) {
                                                                    	double t_0 = fma((-4.0 * A), C, (B_m * B_m));
                                                                    	double t_1 = fma(-0.5, ((B_m * B_m) / A), (C * 2.0));
                                                                    	double tmp;
                                                                    	if (B_m <= 1.1e-121) {
                                                                    		tmp = sqrt((t_1 * 2.0)) * (sqrt(t_0) * (-sqrt(F) / t_0));
                                                                    	} else if (B_m <= 20.0) {
                                                                    		tmp = sqrt((((t_0 * t_1) * 2.0) * F)) / -t_0;
                                                                    	} else {
                                                                    		tmp = (sqrt((C + B_m)) * sqrt((F * 2.0))) / -B_m;
                                                                    	}
                                                                    	return tmp;
                                                                    }
                                                                    
                                                                    B_m = abs(B)
                                                                    A, B_m, C, F = sort([A, B_m, C, F])
                                                                    function code(A, B_m, C, F)
                                                                    	t_0 = fma(Float64(-4.0 * A), C, Float64(B_m * B_m))
                                                                    	t_1 = fma(-0.5, Float64(Float64(B_m * B_m) / A), Float64(C * 2.0))
                                                                    	tmp = 0.0
                                                                    	if (B_m <= 1.1e-121)
                                                                    		tmp = Float64(sqrt(Float64(t_1 * 2.0)) * Float64(sqrt(t_0) * Float64(Float64(-sqrt(F)) / t_0)));
                                                                    	elseif (B_m <= 20.0)
                                                                    		tmp = Float64(sqrt(Float64(Float64(Float64(t_0 * t_1) * 2.0) * F)) / Float64(-t_0));
                                                                    	else
                                                                    		tmp = Float64(Float64(sqrt(Float64(C + B_m)) * sqrt(Float64(F * 2.0))) / Float64(-B_m));
                                                                    	end
                                                                    	return tmp
                                                                    end
                                                                    
                                                                    B_m = N[Abs[B], $MachinePrecision]
                                                                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                    code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(-4.0 * A), $MachinePrecision] * C + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] + N[(C * 2.0), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[B$95$m, 1.1e-121], N[(N[Sqrt[N[(t$95$1 * 2.0), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[t$95$0], $MachinePrecision] * N[((-N[Sqrt[F], $MachinePrecision]) / t$95$0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[B$95$m, 20.0], N[(N[Sqrt[N[(N[(N[(t$95$0 * t$95$1), $MachinePrecision] * 2.0), $MachinePrecision] * F), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], N[(N[(N[Sqrt[N[(C + B$95$m), $MachinePrecision]], $MachinePrecision] * N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / (-B$95$m)), $MachinePrecision]]]]]
                                                                    
                                                                    \begin{array}{l}
                                                                    B_m = \left|B\right|
                                                                    \\
                                                                    [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                    \\
                                                                    \begin{array}{l}
                                                                    t_0 := \mathsf{fma}\left(-4 \cdot A, C, B\_m \cdot B\_m\right)\\
                                                                    t_1 := \mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C \cdot 2\right)\\
                                                                    \mathbf{if}\;B\_m \leq 1.1 \cdot 10^{-121}:\\
                                                                    \;\;\;\;\sqrt{t\_1 \cdot 2} \cdot \left(\sqrt{t\_0} \cdot \frac{-\sqrt{F}}{t\_0}\right)\\
                                                                    
                                                                    \mathbf{elif}\;B\_m \leq 20:\\
                                                                    \;\;\;\;\frac{\sqrt{\left(\left(t\_0 \cdot t\_1\right) \cdot 2\right) \cdot F}}{-t\_0}\\
                                                                    
                                                                    \mathbf{else}:\\
                                                                    \;\;\;\;\frac{\sqrt{C + B\_m} \cdot \sqrt{F \cdot 2}}{-B\_m}\\
                                                                    
                                                                    
                                                                    \end{array}
                                                                    \end{array}
                                                                    
                                                                    Derivation
                                                                    1. Split input into 3 regimes
                                                                    2. if B < 1.10000000000000011e-121

                                                                      1. Initial program 19.7%

                                                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                      2. Add Preprocessing
                                                                      3. Taylor expanded in A around -inf

                                                                        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                      4. Step-by-step derivation
                                                                        1. *-commutativeN/A

                                                                          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\color{blue}{\frac{{B}^{2}}{A} \cdot \frac{-1}{2}} + 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                        2. lower-fma.f64N/A

                                                                          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{{B}^{2}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                        3. lower-/.f64N/A

                                                                          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\color{blue}{\frac{{B}^{2}}{A}}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                        4. unpow2N/A

                                                                          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                        5. lower-*.f64N/A

                                                                          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                        6. lower-*.f6411.6

                                                                          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, \color{blue}{2 \cdot C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                      5. Applied rewrites11.6%

                                                                        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                      6. Step-by-step derivation
                                                                        1. lift-sqrt.f64N/A

                                                                          \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                        2. lift-*.f64N/A

                                                                          \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                        3. *-commutativeN/A

                                                                          \[\leadsto \frac{-\sqrt{\color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                        4. lift-*.f64N/A

                                                                          \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                        5. lift-*.f64N/A

                                                                          \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                        6. associate-*r*N/A

                                                                          \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                        7. associate-*r*N/A

                                                                          \[\leadsto \frac{-\sqrt{\color{blue}{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                      7. Applied rewrites11.5%

                                                                        \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                      8. Applied rewrites11.4%

                                                                        \[\leadsto \color{blue}{\sqrt{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, C \cdot 2\right) \cdot 2\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \left(\left(-\sqrt{F}\right) \cdot {\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)\right)}^{-1}\right)} \]
                                                                      9. Applied rewrites13.5%

                                                                        \[\leadsto \color{blue}{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot 2} \cdot \left(\sqrt{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)} \cdot \frac{-\sqrt{F}}{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}\right)} \]

                                                                      if 1.10000000000000011e-121 < B < 20

                                                                      1. Initial program 35.6%

                                                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                      2. Add Preprocessing
                                                                      3. Taylor expanded in A around -inf

                                                                        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                      4. Step-by-step derivation
                                                                        1. *-commutativeN/A

                                                                          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\color{blue}{\frac{{B}^{2}}{A} \cdot \frac{-1}{2}} + 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                        2. lower-fma.f64N/A

                                                                          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{{B}^{2}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                        3. lower-/.f64N/A

                                                                          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\color{blue}{\frac{{B}^{2}}{A}}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                        4. unpow2N/A

                                                                          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                        5. lower-*.f64N/A

                                                                          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{\color{blue}{B \cdot B}}{A}, \frac{-1}{2}, 2 \cdot C\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                        6. lower-*.f6427.5

                                                                          \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, \color{blue}{2 \cdot C}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                      5. Applied rewrites27.5%

                                                                        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                      6. Step-by-step derivation
                                                                        1. lift-sqrt.f64N/A

                                                                          \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                        2. lift-*.f64N/A

                                                                          \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                        3. *-commutativeN/A

                                                                          \[\leadsto \frac{-\sqrt{\color{blue}{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                        4. lift-*.f64N/A

                                                                          \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                        5. lift-*.f64N/A

                                                                          \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                        6. associate-*r*N/A

                                                                          \[\leadsto \frac{-\sqrt{\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                        7. associate-*r*N/A

                                                                          \[\leadsto \frac{-\sqrt{\color{blue}{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, \frac{-1}{2}, 2 \cdot C\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                      7. Applied rewrites29.2%

                                                                        \[\leadsto \frac{-\color{blue}{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot \left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                      8. Applied rewrites29.1%

                                                                        \[\leadsto \color{blue}{\sqrt{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, C \cdot 2\right) \cdot 2\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \left(\left(-\sqrt{F}\right) \cdot {\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)\right)}^{-1}\right)} \]
                                                                      9. Applied rewrites30.1%

                                                                        \[\leadsto \color{blue}{\frac{-\sqrt{\left(\left(\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right) \cdot \mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right)\right) \cdot 2\right) \cdot F}}{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}} \]

                                                                      if 20 < B

                                                                      1. Initial program 20.5%

                                                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                      2. Add Preprocessing
                                                                      3. Taylor expanded in A around 0

                                                                        \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                      4. Step-by-step derivation
                                                                        1. associate-*r*N/A

                                                                          \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                        2. lower-*.f64N/A

                                                                          \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                        3. mul-1-negN/A

                                                                          \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                        4. lower-neg.f64N/A

                                                                          \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                        5. lower-/.f64N/A

                                                                          \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                        6. lower-sqrt.f64N/A

                                                                          \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                        7. lower-sqrt.f64N/A

                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                        8. *-commutativeN/A

                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                                        9. lower-*.f64N/A

                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                                        10. +-commutativeN/A

                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                                        11. lower-+.f64N/A

                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                                        12. +-commutativeN/A

                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                                                                        13. unpow2N/A

                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                                                                        14. unpow2N/A

                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                                                                        15. lower-hypot.f6451.7

                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                                                                      5. Applied rewrites51.7%

                                                                        \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                                                                      6. Step-by-step derivation
                                                                        1. Applied rewrites51.8%

                                                                          \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]
                                                                        2. Step-by-step derivation
                                                                          1. Applied rewrites71.3%

                                                                            \[\leadsto \frac{\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \sqrt{F \cdot 2}}{-\color{blue}{B}} \]
                                                                          2. Taylor expanded in C around 0

                                                                            \[\leadsto \frac{\sqrt{B + C} \cdot \sqrt{F \cdot 2}}{-B} \]
                                                                          3. Step-by-step derivation
                                                                            1. Applied rewrites61.2%

                                                                              \[\leadsto \frac{\sqrt{C + B} \cdot \sqrt{F \cdot 2}}{-B} \]
                                                                          4. Recombined 3 regimes into one program.
                                                                          5. Final simplification26.9%

                                                                            \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 1.1 \cdot 10^{-121}:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right) \cdot 2} \cdot \left(\sqrt{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)} \cdot \frac{-\sqrt{F}}{\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}\right)\\ \mathbf{elif}\;B \leq 20:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right) \cdot \mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C \cdot 2\right)\right) \cdot 2\right) \cdot F}}{-\mathsf{fma}\left(-4 \cdot A, C, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{C + B} \cdot \sqrt{F \cdot 2}}{-B}\\ \end{array} \]
                                                                          6. Add Preprocessing

                                                                          Alternative 13: 37.8% accurate, 7.6× speedup?

                                                                          \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \sqrt{F \cdot 2}\\ \mathbf{if}\;C \leq 6.5 \cdot 10^{+220}:\\ \;\;\;\;\frac{\sqrt{C + B\_m} \cdot t\_0}{-B\_m}\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(\sqrt{C} \cdot \sqrt{2}\right) \cdot t\_0}{-B\_m}\\ \end{array} \end{array} \]
                                                                          B_m = (fabs.f64 B)
                                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                          (FPCore (A B_m C F)
                                                                           :precision binary64
                                                                           (let* ((t_0 (sqrt (* F 2.0))))
                                                                             (if (<= C 6.5e+220)
                                                                               (/ (* (sqrt (+ C B_m)) t_0) (- B_m))
                                                                               (/ (* (* (sqrt C) (sqrt 2.0)) t_0) (- B_m)))))
                                                                          B_m = fabs(B);
                                                                          assert(A < B_m && B_m < C && C < F);
                                                                          double code(double A, double B_m, double C, double F) {
                                                                          	double t_0 = sqrt((F * 2.0));
                                                                          	double tmp;
                                                                          	if (C <= 6.5e+220) {
                                                                          		tmp = (sqrt((C + B_m)) * t_0) / -B_m;
                                                                          	} else {
                                                                          		tmp = ((sqrt(C) * sqrt(2.0)) * t_0) / -B_m;
                                                                          	}
                                                                          	return tmp;
                                                                          }
                                                                          
                                                                          B_m = abs(b)
                                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                          real(8) function code(a, b_m, c, f)
                                                                              real(8), intent (in) :: a
                                                                              real(8), intent (in) :: b_m
                                                                              real(8), intent (in) :: c
                                                                              real(8), intent (in) :: f
                                                                              real(8) :: t_0
                                                                              real(8) :: tmp
                                                                              t_0 = sqrt((f * 2.0d0))
                                                                              if (c <= 6.5d+220) then
                                                                                  tmp = (sqrt((c + b_m)) * t_0) / -b_m
                                                                              else
                                                                                  tmp = ((sqrt(c) * sqrt(2.0d0)) * t_0) / -b_m
                                                                              end if
                                                                              code = tmp
                                                                          end function
                                                                          
                                                                          B_m = Math.abs(B);
                                                                          assert A < B_m && B_m < C && C < F;
                                                                          public static double code(double A, double B_m, double C, double F) {
                                                                          	double t_0 = Math.sqrt((F * 2.0));
                                                                          	double tmp;
                                                                          	if (C <= 6.5e+220) {
                                                                          		tmp = (Math.sqrt((C + B_m)) * t_0) / -B_m;
                                                                          	} else {
                                                                          		tmp = ((Math.sqrt(C) * Math.sqrt(2.0)) * t_0) / -B_m;
                                                                          	}
                                                                          	return tmp;
                                                                          }
                                                                          
                                                                          B_m = math.fabs(B)
                                                                          [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                          def code(A, B_m, C, F):
                                                                          	t_0 = math.sqrt((F * 2.0))
                                                                          	tmp = 0
                                                                          	if C <= 6.5e+220:
                                                                          		tmp = (math.sqrt((C + B_m)) * t_0) / -B_m
                                                                          	else:
                                                                          		tmp = ((math.sqrt(C) * math.sqrt(2.0)) * t_0) / -B_m
                                                                          	return tmp
                                                                          
                                                                          B_m = abs(B)
                                                                          A, B_m, C, F = sort([A, B_m, C, F])
                                                                          function code(A, B_m, C, F)
                                                                          	t_0 = sqrt(Float64(F * 2.0))
                                                                          	tmp = 0.0
                                                                          	if (C <= 6.5e+220)
                                                                          		tmp = Float64(Float64(sqrt(Float64(C + B_m)) * t_0) / Float64(-B_m));
                                                                          	else
                                                                          		tmp = Float64(Float64(Float64(sqrt(C) * sqrt(2.0)) * t_0) / Float64(-B_m));
                                                                          	end
                                                                          	return tmp
                                                                          end
                                                                          
                                                                          B_m = abs(B);
                                                                          A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                          function tmp_2 = code(A, B_m, C, F)
                                                                          	t_0 = sqrt((F * 2.0));
                                                                          	tmp = 0.0;
                                                                          	if (C <= 6.5e+220)
                                                                          		tmp = (sqrt((C + B_m)) * t_0) / -B_m;
                                                                          	else
                                                                          		tmp = ((sqrt(C) * sqrt(2.0)) * t_0) / -B_m;
                                                                          	end
                                                                          	tmp_2 = tmp;
                                                                          end
                                                                          
                                                                          B_m = N[Abs[B], $MachinePrecision]
                                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                          code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[C, 6.5e+220], N[(N[(N[Sqrt[N[(C + B$95$m), $MachinePrecision]], $MachinePrecision] * t$95$0), $MachinePrecision] / (-B$95$m)), $MachinePrecision], N[(N[(N[(N[Sqrt[C], $MachinePrecision] * N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision] * t$95$0), $MachinePrecision] / (-B$95$m)), $MachinePrecision]]]
                                                                          
                                                                          \begin{array}{l}
                                                                          B_m = \left|B\right|
                                                                          \\
                                                                          [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                          \\
                                                                          \begin{array}{l}
                                                                          t_0 := \sqrt{F \cdot 2}\\
                                                                          \mathbf{if}\;C \leq 6.5 \cdot 10^{+220}:\\
                                                                          \;\;\;\;\frac{\sqrt{C + B\_m} \cdot t\_0}{-B\_m}\\
                                                                          
                                                                          \mathbf{else}:\\
                                                                          \;\;\;\;\frac{\left(\sqrt{C} \cdot \sqrt{2}\right) \cdot t\_0}{-B\_m}\\
                                                                          
                                                                          
                                                                          \end{array}
                                                                          \end{array}
                                                                          
                                                                          Derivation
                                                                          1. Split input into 2 regimes
                                                                          2. if C < 6.5000000000000001e220

                                                                            1. Initial program 23.4%

                                                                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                            2. Add Preprocessing
                                                                            3. Taylor expanded in A around 0

                                                                              \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                            4. Step-by-step derivation
                                                                              1. associate-*r*N/A

                                                                                \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                              2. lower-*.f64N/A

                                                                                \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                              3. mul-1-negN/A

                                                                                \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                              4. lower-neg.f64N/A

                                                                                \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                              5. lower-/.f64N/A

                                                                                \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                              6. lower-sqrt.f64N/A

                                                                                \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                              7. lower-sqrt.f64N/A

                                                                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                              8. *-commutativeN/A

                                                                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                                              9. lower-*.f64N/A

                                                                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                                              10. +-commutativeN/A

                                                                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                                              11. lower-+.f64N/A

                                                                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                                              12. +-commutativeN/A

                                                                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                                                                              13. unpow2N/A

                                                                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                                                                              14. unpow2N/A

                                                                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                                                                              15. lower-hypot.f6415.5

                                                                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                                                                            5. Applied rewrites15.5%

                                                                              \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                                                                            6. Step-by-step derivation
                                                                              1. Applied rewrites15.5%

                                                                                \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]
                                                                              2. Step-by-step derivation
                                                                                1. Applied rewrites21.2%

                                                                                  \[\leadsto \frac{\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \sqrt{F \cdot 2}}{-\color{blue}{B}} \]
                                                                                2. Taylor expanded in C around 0

                                                                                  \[\leadsto \frac{\sqrt{B + C} \cdot \sqrt{F \cdot 2}}{-B} \]
                                                                                3. Step-by-step derivation
                                                                                  1. Applied rewrites18.4%

                                                                                    \[\leadsto \frac{\sqrt{C + B} \cdot \sqrt{F \cdot 2}}{-B} \]

                                                                                  if 6.5000000000000001e220 < C

                                                                                  1. Initial program 1.6%

                                                                                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                  2. Add Preprocessing
                                                                                  3. Taylor expanded in A around 0

                                                                                    \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                                  4. Step-by-step derivation
                                                                                    1. associate-*r*N/A

                                                                                      \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                                    2. lower-*.f64N/A

                                                                                      \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                                    3. mul-1-negN/A

                                                                                      \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                                    4. lower-neg.f64N/A

                                                                                      \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                                    5. lower-/.f64N/A

                                                                                      \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                                    6. lower-sqrt.f64N/A

                                                                                      \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                                    7. lower-sqrt.f64N/A

                                                                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                                    8. *-commutativeN/A

                                                                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                                                    9. lower-*.f64N/A

                                                                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                                                    10. +-commutativeN/A

                                                                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                                                    11. lower-+.f64N/A

                                                                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                                                    12. +-commutativeN/A

                                                                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                                                                                    13. unpow2N/A

                                                                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                                                                                    14. unpow2N/A

                                                                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                                                                                    15. lower-hypot.f6422.0

                                                                                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                                                                                  5. Applied rewrites22.0%

                                                                                    \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                                                                                  6. Step-by-step derivation
                                                                                    1. Applied rewrites22.1%

                                                                                      \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]
                                                                                    2. Step-by-step derivation
                                                                                      1. Applied rewrites34.9%

                                                                                        \[\leadsto \frac{\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \sqrt{F \cdot 2}}{-\color{blue}{B}} \]
                                                                                      2. Taylor expanded in B around 0

                                                                                        \[\leadsto \frac{\left(\sqrt{C} \cdot \sqrt{2}\right) \cdot \sqrt{F \cdot 2}}{-B} \]
                                                                                      3. Step-by-step derivation
                                                                                        1. Applied rewrites29.8%

                                                                                          \[\leadsto \frac{\left(\sqrt{C} \cdot \sqrt{2}\right) \cdot \sqrt{F \cdot 2}}{-B} \]
                                                                                      4. Recombined 2 regimes into one program.
                                                                                      5. Add Preprocessing

                                                                                      Alternative 14: 36.5% accurate, 10.4× speedup?

                                                                                      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \frac{\sqrt{C + B\_m} \cdot \sqrt{F \cdot 2}}{-B\_m} \end{array} \]
                                                                                      B_m = (fabs.f64 B)
                                                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                      (FPCore (A B_m C F)
                                                                                       :precision binary64
                                                                                       (/ (* (sqrt (+ C B_m)) (sqrt (* F 2.0))) (- B_m)))
                                                                                      B_m = fabs(B);
                                                                                      assert(A < B_m && B_m < C && C < F);
                                                                                      double code(double A, double B_m, double C, double F) {
                                                                                      	return (sqrt((C + B_m)) * sqrt((F * 2.0))) / -B_m;
                                                                                      }
                                                                                      
                                                                                      B_m = abs(b)
                                                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                      real(8) function code(a, b_m, c, f)
                                                                                          real(8), intent (in) :: a
                                                                                          real(8), intent (in) :: b_m
                                                                                          real(8), intent (in) :: c
                                                                                          real(8), intent (in) :: f
                                                                                          code = (sqrt((c + b_m)) * sqrt((f * 2.0d0))) / -b_m
                                                                                      end function
                                                                                      
                                                                                      B_m = Math.abs(B);
                                                                                      assert A < B_m && B_m < C && C < F;
                                                                                      public static double code(double A, double B_m, double C, double F) {
                                                                                      	return (Math.sqrt((C + B_m)) * Math.sqrt((F * 2.0))) / -B_m;
                                                                                      }
                                                                                      
                                                                                      B_m = math.fabs(B)
                                                                                      [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                                      def code(A, B_m, C, F):
                                                                                      	return (math.sqrt((C + B_m)) * math.sqrt((F * 2.0))) / -B_m
                                                                                      
                                                                                      B_m = abs(B)
                                                                                      A, B_m, C, F = sort([A, B_m, C, F])
                                                                                      function code(A, B_m, C, F)
                                                                                      	return Float64(Float64(sqrt(Float64(C + B_m)) * sqrt(Float64(F * 2.0))) / Float64(-B_m))
                                                                                      end
                                                                                      
                                                                                      B_m = abs(B);
                                                                                      A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                                      function tmp = code(A, B_m, C, F)
                                                                                      	tmp = (sqrt((C + B_m)) * sqrt((F * 2.0))) / -B_m;
                                                                                      end
                                                                                      
                                                                                      B_m = N[Abs[B], $MachinePrecision]
                                                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                      code[A_, B$95$m_, C_, F_] := N[(N[(N[Sqrt[N[(C + B$95$m), $MachinePrecision]], $MachinePrecision] * N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / (-B$95$m)), $MachinePrecision]
                                                                                      
                                                                                      \begin{array}{l}
                                                                                      B_m = \left|B\right|
                                                                                      \\
                                                                                      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                                      \\
                                                                                      \frac{\sqrt{C + B\_m} \cdot \sqrt{F \cdot 2}}{-B\_m}
                                                                                      \end{array}
                                                                                      
                                                                                      Derivation
                                                                                      1. Initial program 22.1%

                                                                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                      2. Add Preprocessing
                                                                                      3. Taylor expanded in A around 0

                                                                                        \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                                      4. Step-by-step derivation
                                                                                        1. associate-*r*N/A

                                                                                          \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                                        2. lower-*.f64N/A

                                                                                          \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                                        3. mul-1-negN/A

                                                                                          \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                                        4. lower-neg.f64N/A

                                                                                          \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                                        5. lower-/.f64N/A

                                                                                          \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                                        6. lower-sqrt.f64N/A

                                                                                          \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                                        7. lower-sqrt.f64N/A

                                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                                        8. *-commutativeN/A

                                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                                                        9. lower-*.f64N/A

                                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                                                        10. +-commutativeN/A

                                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                                                        11. lower-+.f64N/A

                                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                                                        12. +-commutativeN/A

                                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                                                                                        13. unpow2N/A

                                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                                                                                        14. unpow2N/A

                                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                                                                                        15. lower-hypot.f6415.9

                                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                                                                                      5. Applied rewrites15.9%

                                                                                        \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                                                                                      6. Step-by-step derivation
                                                                                        1. Applied rewrites15.9%

                                                                                          \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]
                                                                                        2. Step-by-step derivation
                                                                                          1. Applied rewrites22.0%

                                                                                            \[\leadsto \frac{\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \sqrt{F \cdot 2}}{-\color{blue}{B}} \]
                                                                                          2. Taylor expanded in C around 0

                                                                                            \[\leadsto \frac{\sqrt{B + C} \cdot \sqrt{F \cdot 2}}{-B} \]
                                                                                          3. Step-by-step derivation
                                                                                            1. Applied rewrites17.9%

                                                                                              \[\leadsto \frac{\sqrt{C + B} \cdot \sqrt{F \cdot 2}}{-B} \]
                                                                                            2. Add Preprocessing

                                                                                            Alternative 15: 35.2% accurate, 11.4× speedup?

                                                                                            \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;F \leq 5.6 \cdot 10^{+16}:\\ \;\;\;\;\frac{\sqrt{\left(\left(C + B\_m\right) \cdot F\right) \cdot 2}}{-B\_m}\\ \mathbf{else}:\\ \;\;\;\;-\sqrt{\frac{2}{\frac{B\_m}{F}}}\\ \end{array} \end{array} \]
                                                                                            B_m = (fabs.f64 B)
                                                                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                            (FPCore (A B_m C F)
                                                                                             :precision binary64
                                                                                             (if (<= F 5.6e+16)
                                                                                               (/ (sqrt (* (* (+ C B_m) F) 2.0)) (- B_m))
                                                                                               (- (sqrt (/ 2.0 (/ B_m F))))))
                                                                                            B_m = fabs(B);
                                                                                            assert(A < B_m && B_m < C && C < F);
                                                                                            double code(double A, double B_m, double C, double F) {
                                                                                            	double tmp;
                                                                                            	if (F <= 5.6e+16) {
                                                                                            		tmp = sqrt((((C + B_m) * F) * 2.0)) / -B_m;
                                                                                            	} else {
                                                                                            		tmp = -sqrt((2.0 / (B_m / F)));
                                                                                            	}
                                                                                            	return tmp;
                                                                                            }
                                                                                            
                                                                                            B_m = abs(b)
                                                                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                            real(8) function code(a, b_m, c, f)
                                                                                                real(8), intent (in) :: a
                                                                                                real(8), intent (in) :: b_m
                                                                                                real(8), intent (in) :: c
                                                                                                real(8), intent (in) :: f
                                                                                                real(8) :: tmp
                                                                                                if (f <= 5.6d+16) then
                                                                                                    tmp = sqrt((((c + b_m) * f) * 2.0d0)) / -b_m
                                                                                                else
                                                                                                    tmp = -sqrt((2.0d0 / (b_m / f)))
                                                                                                end if
                                                                                                code = tmp
                                                                                            end function
                                                                                            
                                                                                            B_m = Math.abs(B);
                                                                                            assert A < B_m && B_m < C && C < F;
                                                                                            public static double code(double A, double B_m, double C, double F) {
                                                                                            	double tmp;
                                                                                            	if (F <= 5.6e+16) {
                                                                                            		tmp = Math.sqrt((((C + B_m) * F) * 2.0)) / -B_m;
                                                                                            	} else {
                                                                                            		tmp = -Math.sqrt((2.0 / (B_m / F)));
                                                                                            	}
                                                                                            	return tmp;
                                                                                            }
                                                                                            
                                                                                            B_m = math.fabs(B)
                                                                                            [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                                            def code(A, B_m, C, F):
                                                                                            	tmp = 0
                                                                                            	if F <= 5.6e+16:
                                                                                            		tmp = math.sqrt((((C + B_m) * F) * 2.0)) / -B_m
                                                                                            	else:
                                                                                            		tmp = -math.sqrt((2.0 / (B_m / F)))
                                                                                            	return tmp
                                                                                            
                                                                                            B_m = abs(B)
                                                                                            A, B_m, C, F = sort([A, B_m, C, F])
                                                                                            function code(A, B_m, C, F)
                                                                                            	tmp = 0.0
                                                                                            	if (F <= 5.6e+16)
                                                                                            		tmp = Float64(sqrt(Float64(Float64(Float64(C + B_m) * F) * 2.0)) / Float64(-B_m));
                                                                                            	else
                                                                                            		tmp = Float64(-sqrt(Float64(2.0 / Float64(B_m / F))));
                                                                                            	end
                                                                                            	return tmp
                                                                                            end
                                                                                            
                                                                                            B_m = abs(B);
                                                                                            A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                                            function tmp_2 = code(A, B_m, C, F)
                                                                                            	tmp = 0.0;
                                                                                            	if (F <= 5.6e+16)
                                                                                            		tmp = sqrt((((C + B_m) * F) * 2.0)) / -B_m;
                                                                                            	else
                                                                                            		tmp = -sqrt((2.0 / (B_m / F)));
                                                                                            	end
                                                                                            	tmp_2 = tmp;
                                                                                            end
                                                                                            
                                                                                            B_m = N[Abs[B], $MachinePrecision]
                                                                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                            code[A_, B$95$m_, C_, F_] := If[LessEqual[F, 5.6e+16], N[(N[Sqrt[N[(N[(N[(C + B$95$m), $MachinePrecision] * F), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision], (-N[Sqrt[N[(2.0 / N[(B$95$m / F), $MachinePrecision]), $MachinePrecision]], $MachinePrecision])]
                                                                                            
                                                                                            \begin{array}{l}
                                                                                            B_m = \left|B\right|
                                                                                            \\
                                                                                            [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                                            \\
                                                                                            \begin{array}{l}
                                                                                            \mathbf{if}\;F \leq 5.6 \cdot 10^{+16}:\\
                                                                                            \;\;\;\;\frac{\sqrt{\left(\left(C + B\_m\right) \cdot F\right) \cdot 2}}{-B\_m}\\
                                                                                            
                                                                                            \mathbf{else}:\\
                                                                                            \;\;\;\;-\sqrt{\frac{2}{\frac{B\_m}{F}}}\\
                                                                                            
                                                                                            
                                                                                            \end{array}
                                                                                            \end{array}
                                                                                            
                                                                                            Derivation
                                                                                            1. Split input into 2 regimes
                                                                                            2. if F < 5.6e16

                                                                                              1. Initial program 27.5%

                                                                                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                              2. Add Preprocessing
                                                                                              3. Taylor expanded in A around 0

                                                                                                \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                                              4. Step-by-step derivation
                                                                                                1. associate-*r*N/A

                                                                                                  \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                                                2. lower-*.f64N/A

                                                                                                  \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                                                3. mul-1-negN/A

                                                                                                  \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                                                4. lower-neg.f64N/A

                                                                                                  \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                                                5. lower-/.f64N/A

                                                                                                  \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                                                6. lower-sqrt.f64N/A

                                                                                                  \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                                                7. lower-sqrt.f64N/A

                                                                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                                                8. *-commutativeN/A

                                                                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                                                                9. lower-*.f64N/A

                                                                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                                                                10. +-commutativeN/A

                                                                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                                                                11. lower-+.f64N/A

                                                                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                                                                12. +-commutativeN/A

                                                                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                                                                                                13. unpow2N/A

                                                                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                                                                                                14. unpow2N/A

                                                                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                                                                                                15. lower-hypot.f6419.2

                                                                                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                                                                                              5. Applied rewrites19.2%

                                                                                                \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                                                                                              6. Step-by-step derivation
                                                                                                1. Applied rewrites19.3%

                                                                                                  \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]
                                                                                                2. Taylor expanded in C around 0

                                                                                                  \[\leadsto \frac{\sqrt{\left(\left(B + C\right) \cdot F\right) \cdot 2}}{-B} \]
                                                                                                3. Step-by-step derivation
                                                                                                  1. Applied rewrites14.6%

                                                                                                    \[\leadsto \frac{\sqrt{\left(\left(C + B\right) \cdot F\right) \cdot 2}}{-B} \]

                                                                                                  if 5.6e16 < F

                                                                                                  1. Initial program 14.1%

                                                                                                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                  2. Add Preprocessing
                                                                                                  3. Taylor expanded in B around inf

                                                                                                    \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                  4. Step-by-step derivation
                                                                                                    1. mul-1-negN/A

                                                                                                      \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                    2. lower-neg.f64N/A

                                                                                                      \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                                    3. lower-*.f64N/A

                                                                                                      \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                                    4. lower-sqrt.f64N/A

                                                                                                      \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                                                    5. lower-/.f64N/A

                                                                                                      \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                                                    6. lower-sqrt.f6419.8

                                                                                                      \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                                                                  5. Applied rewrites19.8%

                                                                                                    \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                                  6. Step-by-step derivation
                                                                                                    1. Applied rewrites19.9%

                                                                                                      \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                                                    2. Step-by-step derivation
                                                                                                      1. Applied rewrites19.9%

                                                                                                        \[\leadsto -\sqrt{\frac{2}{\frac{B}{F}}} \]
                                                                                                    3. Recombined 2 regimes into one program.
                                                                                                    4. Add Preprocessing

                                                                                                    Alternative 16: 34.8% accurate, 12.3× speedup?

                                                                                                    \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;F \leq 5 \cdot 10^{-42}:\\ \;\;\;\;\frac{\sqrt{2 \cdot \left(B\_m \cdot F\right)}}{-B\_m}\\ \mathbf{else}:\\ \;\;\;\;-\sqrt{\frac{F}{B\_m} \cdot 2}\\ \end{array} \end{array} \]
                                                                                                    B_m = (fabs.f64 B)
                                                                                                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                    (FPCore (A B_m C F)
                                                                                                     :precision binary64
                                                                                                     (if (<= F 5e-42)
                                                                                                       (/ (sqrt (* 2.0 (* B_m F))) (- B_m))
                                                                                                       (- (sqrt (* (/ F B_m) 2.0)))))
                                                                                                    B_m = fabs(B);
                                                                                                    assert(A < B_m && B_m < C && C < F);
                                                                                                    double code(double A, double B_m, double C, double F) {
                                                                                                    	double tmp;
                                                                                                    	if (F <= 5e-42) {
                                                                                                    		tmp = sqrt((2.0 * (B_m * F))) / -B_m;
                                                                                                    	} else {
                                                                                                    		tmp = -sqrt(((F / B_m) * 2.0));
                                                                                                    	}
                                                                                                    	return tmp;
                                                                                                    }
                                                                                                    
                                                                                                    B_m = abs(b)
                                                                                                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                    real(8) function code(a, b_m, c, f)
                                                                                                        real(8), intent (in) :: a
                                                                                                        real(8), intent (in) :: b_m
                                                                                                        real(8), intent (in) :: c
                                                                                                        real(8), intent (in) :: f
                                                                                                        real(8) :: tmp
                                                                                                        if (f <= 5d-42) then
                                                                                                            tmp = sqrt((2.0d0 * (b_m * f))) / -b_m
                                                                                                        else
                                                                                                            tmp = -sqrt(((f / b_m) * 2.0d0))
                                                                                                        end if
                                                                                                        code = tmp
                                                                                                    end function
                                                                                                    
                                                                                                    B_m = Math.abs(B);
                                                                                                    assert A < B_m && B_m < C && C < F;
                                                                                                    public static double code(double A, double B_m, double C, double F) {
                                                                                                    	double tmp;
                                                                                                    	if (F <= 5e-42) {
                                                                                                    		tmp = Math.sqrt((2.0 * (B_m * F))) / -B_m;
                                                                                                    	} else {
                                                                                                    		tmp = -Math.sqrt(((F / B_m) * 2.0));
                                                                                                    	}
                                                                                                    	return tmp;
                                                                                                    }
                                                                                                    
                                                                                                    B_m = math.fabs(B)
                                                                                                    [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                                                    def code(A, B_m, C, F):
                                                                                                    	tmp = 0
                                                                                                    	if F <= 5e-42:
                                                                                                    		tmp = math.sqrt((2.0 * (B_m * F))) / -B_m
                                                                                                    	else:
                                                                                                    		tmp = -math.sqrt(((F / B_m) * 2.0))
                                                                                                    	return tmp
                                                                                                    
                                                                                                    B_m = abs(B)
                                                                                                    A, B_m, C, F = sort([A, B_m, C, F])
                                                                                                    function code(A, B_m, C, F)
                                                                                                    	tmp = 0.0
                                                                                                    	if (F <= 5e-42)
                                                                                                    		tmp = Float64(sqrt(Float64(2.0 * Float64(B_m * F))) / Float64(-B_m));
                                                                                                    	else
                                                                                                    		tmp = Float64(-sqrt(Float64(Float64(F / B_m) * 2.0)));
                                                                                                    	end
                                                                                                    	return tmp
                                                                                                    end
                                                                                                    
                                                                                                    B_m = abs(B);
                                                                                                    A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                                                    function tmp_2 = code(A, B_m, C, F)
                                                                                                    	tmp = 0.0;
                                                                                                    	if (F <= 5e-42)
                                                                                                    		tmp = sqrt((2.0 * (B_m * F))) / -B_m;
                                                                                                    	else
                                                                                                    		tmp = -sqrt(((F / B_m) * 2.0));
                                                                                                    	end
                                                                                                    	tmp_2 = tmp;
                                                                                                    end
                                                                                                    
                                                                                                    B_m = N[Abs[B], $MachinePrecision]
                                                                                                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                    code[A_, B$95$m_, C_, F_] := If[LessEqual[F, 5e-42], N[(N[Sqrt[N[(2.0 * N[(B$95$m * F), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision], (-N[Sqrt[N[(N[(F / B$95$m), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision])]
                                                                                                    
                                                                                                    \begin{array}{l}
                                                                                                    B_m = \left|B\right|
                                                                                                    \\
                                                                                                    [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                                                    \\
                                                                                                    \begin{array}{l}
                                                                                                    \mathbf{if}\;F \leq 5 \cdot 10^{-42}:\\
                                                                                                    \;\;\;\;\frac{\sqrt{2 \cdot \left(B\_m \cdot F\right)}}{-B\_m}\\
                                                                                                    
                                                                                                    \mathbf{else}:\\
                                                                                                    \;\;\;\;-\sqrt{\frac{F}{B\_m} \cdot 2}\\
                                                                                                    
                                                                                                    
                                                                                                    \end{array}
                                                                                                    \end{array}
                                                                                                    
                                                                                                    Derivation
                                                                                                    1. Split input into 2 regimes
                                                                                                    2. if F < 5.00000000000000003e-42

                                                                                                      1. Initial program 26.7%

                                                                                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                      2. Add Preprocessing
                                                                                                      3. Taylor expanded in A around 0

                                                                                                        \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                                                                      4. Step-by-step derivation
                                                                                                        1. associate-*r*N/A

                                                                                                          \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                                                        2. lower-*.f64N/A

                                                                                                          \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                                                        3. mul-1-negN/A

                                                                                                          \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                                                        4. lower-neg.f64N/A

                                                                                                          \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                                                        5. lower-/.f64N/A

                                                                                                          \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                                                        6. lower-sqrt.f64N/A

                                                                                                          \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                                                                        7. lower-sqrt.f64N/A

                                                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                                                                        8. *-commutativeN/A

                                                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                                                                        9. lower-*.f64N/A

                                                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                                                                        10. +-commutativeN/A

                                                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                                                                        11. lower-+.f64N/A

                                                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                                                                        12. +-commutativeN/A

                                                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                                                                                                        13. unpow2N/A

                                                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                                                                                                        14. unpow2N/A

                                                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                                                                                                        15. lower-hypot.f6416.7

                                                                                                          \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                                                                                                      5. Applied rewrites16.7%

                                                                                                        \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                                                                                                      6. Step-by-step derivation
                                                                                                        1. Applied rewrites16.8%

                                                                                                          \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]
                                                                                                        2. Taylor expanded in B around inf

                                                                                                          \[\leadsto \frac{\sqrt{2 \cdot \left(B \cdot F\right)}}{-B} \]
                                                                                                        3. Step-by-step derivation
                                                                                                          1. Applied rewrites13.1%

                                                                                                            \[\leadsto \frac{\sqrt{2 \cdot \left(B \cdot F\right)}}{-B} \]

                                                                                                          if 5.00000000000000003e-42 < F

                                                                                                          1. Initial program 17.3%

                                                                                                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                          2. Add Preprocessing
                                                                                                          3. Taylor expanded in B around inf

                                                                                                            \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                          4. Step-by-step derivation
                                                                                                            1. mul-1-negN/A

                                                                                                              \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                            2. lower-neg.f64N/A

                                                                                                              \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                                            3. lower-*.f64N/A

                                                                                                              \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                                            4. lower-sqrt.f64N/A

                                                                                                              \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                                                            5. lower-/.f64N/A

                                                                                                              \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                                                            6. lower-sqrt.f6421.5

                                                                                                              \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                                                                          5. Applied rewrites21.5%

                                                                                                            \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                                          6. Step-by-step derivation
                                                                                                            1. Applied rewrites21.6%

                                                                                                              \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                                                          7. Recombined 2 regimes into one program.
                                                                                                          8. Add Preprocessing

                                                                                                          Alternative 17: 35.7% accurate, 12.6× speedup?

                                                                                                          \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \frac{\sqrt{F \cdot 2}}{-\sqrt{B\_m}} \end{array} \]
                                                                                                          B_m = (fabs.f64 B)
                                                                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                          (FPCore (A B_m C F) :precision binary64 (/ (sqrt (* F 2.0)) (- (sqrt B_m))))
                                                                                                          B_m = fabs(B);
                                                                                                          assert(A < B_m && B_m < C && C < F);
                                                                                                          double code(double A, double B_m, double C, double F) {
                                                                                                          	return sqrt((F * 2.0)) / -sqrt(B_m);
                                                                                                          }
                                                                                                          
                                                                                                          B_m = abs(b)
                                                                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                          real(8) function code(a, b_m, c, f)
                                                                                                              real(8), intent (in) :: a
                                                                                                              real(8), intent (in) :: b_m
                                                                                                              real(8), intent (in) :: c
                                                                                                              real(8), intent (in) :: f
                                                                                                              code = sqrt((f * 2.0d0)) / -sqrt(b_m)
                                                                                                          end function
                                                                                                          
                                                                                                          B_m = Math.abs(B);
                                                                                                          assert A < B_m && B_m < C && C < F;
                                                                                                          public static double code(double A, double B_m, double C, double F) {
                                                                                                          	return Math.sqrt((F * 2.0)) / -Math.sqrt(B_m);
                                                                                                          }
                                                                                                          
                                                                                                          B_m = math.fabs(B)
                                                                                                          [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                                                          def code(A, B_m, C, F):
                                                                                                          	return math.sqrt((F * 2.0)) / -math.sqrt(B_m)
                                                                                                          
                                                                                                          B_m = abs(B)
                                                                                                          A, B_m, C, F = sort([A, B_m, C, F])
                                                                                                          function code(A, B_m, C, F)
                                                                                                          	return Float64(sqrt(Float64(F * 2.0)) / Float64(-sqrt(B_m)))
                                                                                                          end
                                                                                                          
                                                                                                          B_m = abs(B);
                                                                                                          A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                                                          function tmp = code(A, B_m, C, F)
                                                                                                          	tmp = sqrt((F * 2.0)) / -sqrt(B_m);
                                                                                                          end
                                                                                                          
                                                                                                          B_m = N[Abs[B], $MachinePrecision]
                                                                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                          code[A_, B$95$m_, C_, F_] := N[(N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision] / (-N[Sqrt[B$95$m], $MachinePrecision])), $MachinePrecision]
                                                                                                          
                                                                                                          \begin{array}{l}
                                                                                                          B_m = \left|B\right|
                                                                                                          \\
                                                                                                          [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                                                          \\
                                                                                                          \frac{\sqrt{F \cdot 2}}{-\sqrt{B\_m}}
                                                                                                          \end{array}
                                                                                                          
                                                                                                          Derivation
                                                                                                          1. Initial program 22.1%

                                                                                                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                          2. Add Preprocessing
                                                                                                          3. Taylor expanded in B around inf

                                                                                                            \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                          4. Step-by-step derivation
                                                                                                            1. mul-1-negN/A

                                                                                                              \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                            2. lower-neg.f64N/A

                                                                                                              \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                                            3. lower-*.f64N/A

                                                                                                              \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                                            4. lower-sqrt.f64N/A

                                                                                                              \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                                                            5. lower-/.f64N/A

                                                                                                              \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                                                            6. lower-sqrt.f6415.7

                                                                                                              \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                                                                          5. Applied rewrites15.7%

                                                                                                            \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                                          6. Step-by-step derivation
                                                                                                            1. Applied rewrites18.2%

                                                                                                              \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
                                                                                                            2. Final simplification18.2%

                                                                                                              \[\leadsto \frac{\sqrt{F \cdot 2}}{-\sqrt{B}} \]
                                                                                                            3. Add Preprocessing

                                                                                                            Alternative 18: 35.7% accurate, 12.6× speedup?

                                                                                                            \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \frac{-\sqrt{F}}{\sqrt{B\_m \cdot 0.5}} \end{array} \]
                                                                                                            B_m = (fabs.f64 B)
                                                                                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                            (FPCore (A B_m C F) :precision binary64 (/ (- (sqrt F)) (sqrt (* B_m 0.5))))
                                                                                                            B_m = fabs(B);
                                                                                                            assert(A < B_m && B_m < C && C < F);
                                                                                                            double code(double A, double B_m, double C, double F) {
                                                                                                            	return -sqrt(F) / sqrt((B_m * 0.5));
                                                                                                            }
                                                                                                            
                                                                                                            B_m = abs(b)
                                                                                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                            real(8) function code(a, b_m, c, f)
                                                                                                                real(8), intent (in) :: a
                                                                                                                real(8), intent (in) :: b_m
                                                                                                                real(8), intent (in) :: c
                                                                                                                real(8), intent (in) :: f
                                                                                                                code = -sqrt(f) / sqrt((b_m * 0.5d0))
                                                                                                            end function
                                                                                                            
                                                                                                            B_m = Math.abs(B);
                                                                                                            assert A < B_m && B_m < C && C < F;
                                                                                                            public static double code(double A, double B_m, double C, double F) {
                                                                                                            	return -Math.sqrt(F) / Math.sqrt((B_m * 0.5));
                                                                                                            }
                                                                                                            
                                                                                                            B_m = math.fabs(B)
                                                                                                            [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                                                            def code(A, B_m, C, F):
                                                                                                            	return -math.sqrt(F) / math.sqrt((B_m * 0.5))
                                                                                                            
                                                                                                            B_m = abs(B)
                                                                                                            A, B_m, C, F = sort([A, B_m, C, F])
                                                                                                            function code(A, B_m, C, F)
                                                                                                            	return Float64(Float64(-sqrt(F)) / sqrt(Float64(B_m * 0.5)))
                                                                                                            end
                                                                                                            
                                                                                                            B_m = abs(B);
                                                                                                            A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                                                            function tmp = code(A, B_m, C, F)
                                                                                                            	tmp = -sqrt(F) / sqrt((B_m * 0.5));
                                                                                                            end
                                                                                                            
                                                                                                            B_m = N[Abs[B], $MachinePrecision]
                                                                                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                            code[A_, B$95$m_, C_, F_] := N[((-N[Sqrt[F], $MachinePrecision]) / N[Sqrt[N[(B$95$m * 0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
                                                                                                            
                                                                                                            \begin{array}{l}
                                                                                                            B_m = \left|B\right|
                                                                                                            \\
                                                                                                            [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                                                            \\
                                                                                                            \frac{-\sqrt{F}}{\sqrt{B\_m \cdot 0.5}}
                                                                                                            \end{array}
                                                                                                            
                                                                                                            Derivation
                                                                                                            1. Initial program 22.1%

                                                                                                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                            2. Add Preprocessing
                                                                                                            3. Taylor expanded in B around inf

                                                                                                              \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                            4. Step-by-step derivation
                                                                                                              1. mul-1-negN/A

                                                                                                                \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                              2. lower-neg.f64N/A

                                                                                                                \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                                              3. lower-*.f64N/A

                                                                                                                \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                                              4. lower-sqrt.f64N/A

                                                                                                                \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                                                              5. lower-/.f64N/A

                                                                                                                \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                                                              6. lower-sqrt.f6415.7

                                                                                                                \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                                                                            5. Applied rewrites15.7%

                                                                                                              \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                                            6. Step-by-step derivation
                                                                                                              1. Applied rewrites15.8%

                                                                                                                \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                                                              2. Step-by-step derivation
                                                                                                                1. Applied rewrites15.7%

                                                                                                                  \[\leadsto -\sqrt{F \cdot \frac{2}{B}} \]
                                                                                                                2. Step-by-step derivation
                                                                                                                  1. Applied rewrites18.2%

                                                                                                                    \[\leadsto -\frac{\sqrt{F}}{\sqrt{B \cdot 0.5}} \]
                                                                                                                  2. Final simplification18.2%

                                                                                                                    \[\leadsto \frac{-\sqrt{F}}{\sqrt{B \cdot 0.5}} \]
                                                                                                                  3. Add Preprocessing

                                                                                                                  Alternative 19: 35.7% accurate, 12.6× speedup?

                                                                                                                  \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}} \end{array} \]
                                                                                                                  B_m = (fabs.f64 B)
                                                                                                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                                  (FPCore (A B_m C F) :precision binary64 (* (- (sqrt F)) (sqrt (/ 2.0 B_m))))
                                                                                                                  B_m = fabs(B);
                                                                                                                  assert(A < B_m && B_m < C && C < F);
                                                                                                                  double code(double A, double B_m, double C, double F) {
                                                                                                                  	return -sqrt(F) * sqrt((2.0 / B_m));
                                                                                                                  }
                                                                                                                  
                                                                                                                  B_m = abs(b)
                                                                                                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                                  real(8) function code(a, b_m, c, f)
                                                                                                                      real(8), intent (in) :: a
                                                                                                                      real(8), intent (in) :: b_m
                                                                                                                      real(8), intent (in) :: c
                                                                                                                      real(8), intent (in) :: f
                                                                                                                      code = -sqrt(f) * sqrt((2.0d0 / b_m))
                                                                                                                  end function
                                                                                                                  
                                                                                                                  B_m = Math.abs(B);
                                                                                                                  assert A < B_m && B_m < C && C < F;
                                                                                                                  public static double code(double A, double B_m, double C, double F) {
                                                                                                                  	return -Math.sqrt(F) * Math.sqrt((2.0 / B_m));
                                                                                                                  }
                                                                                                                  
                                                                                                                  B_m = math.fabs(B)
                                                                                                                  [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                                                                  def code(A, B_m, C, F):
                                                                                                                  	return -math.sqrt(F) * math.sqrt((2.0 / B_m))
                                                                                                                  
                                                                                                                  B_m = abs(B)
                                                                                                                  A, B_m, C, F = sort([A, B_m, C, F])
                                                                                                                  function code(A, B_m, C, F)
                                                                                                                  	return Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)))
                                                                                                                  end
                                                                                                                  
                                                                                                                  B_m = abs(B);
                                                                                                                  A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                                                                  function tmp = code(A, B_m, C, F)
                                                                                                                  	tmp = -sqrt(F) * sqrt((2.0 / B_m));
                                                                                                                  end
                                                                                                                  
                                                                                                                  B_m = N[Abs[B], $MachinePrecision]
                                                                                                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                                  code[A_, B$95$m_, C_, F_] := N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
                                                                                                                  
                                                                                                                  \begin{array}{l}
                                                                                                                  B_m = \left|B\right|
                                                                                                                  \\
                                                                                                                  [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                                                                  \\
                                                                                                                  \left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}
                                                                                                                  \end{array}
                                                                                                                  
                                                                                                                  Derivation
                                                                                                                  1. Initial program 22.1%

                                                                                                                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                  2. Add Preprocessing
                                                                                                                  3. Taylor expanded in B around inf

                                                                                                                    \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                                  4. Step-by-step derivation
                                                                                                                    1. mul-1-negN/A

                                                                                                                      \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                                    2. lower-neg.f64N/A

                                                                                                                      \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                                                    3. lower-*.f64N/A

                                                                                                                      \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                                                    4. lower-sqrt.f64N/A

                                                                                                                      \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                                                                    5. lower-/.f64N/A

                                                                                                                      \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                                                                    6. lower-sqrt.f6415.7

                                                                                                                      \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                                                                                  5. Applied rewrites15.7%

                                                                                                                    \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                                                  6. Step-by-step derivation
                                                                                                                    1. Applied rewrites15.8%

                                                                                                                      \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                                                                    2. Step-by-step derivation
                                                                                                                      1. Applied rewrites18.2%

                                                                                                                        \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                                                                                                      2. Final simplification18.2%

                                                                                                                        \[\leadsto \left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}} \]
                                                                                                                      3. Add Preprocessing

                                                                                                                      Alternative 20: 27.4% accurate, 16.9× speedup?

                                                                                                                      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ -\sqrt{\frac{F}{B\_m} \cdot 2} \end{array} \]
                                                                                                                      B_m = (fabs.f64 B)
                                                                                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                                      (FPCore (A B_m C F) :precision binary64 (- (sqrt (* (/ F B_m) 2.0))))
                                                                                                                      B_m = fabs(B);
                                                                                                                      assert(A < B_m && B_m < C && C < F);
                                                                                                                      double code(double A, double B_m, double C, double F) {
                                                                                                                      	return -sqrt(((F / B_m) * 2.0));
                                                                                                                      }
                                                                                                                      
                                                                                                                      B_m = abs(b)
                                                                                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                                      real(8) function code(a, b_m, c, f)
                                                                                                                          real(8), intent (in) :: a
                                                                                                                          real(8), intent (in) :: b_m
                                                                                                                          real(8), intent (in) :: c
                                                                                                                          real(8), intent (in) :: f
                                                                                                                          code = -sqrt(((f / b_m) * 2.0d0))
                                                                                                                      end function
                                                                                                                      
                                                                                                                      B_m = Math.abs(B);
                                                                                                                      assert A < B_m && B_m < C && C < F;
                                                                                                                      public static double code(double A, double B_m, double C, double F) {
                                                                                                                      	return -Math.sqrt(((F / B_m) * 2.0));
                                                                                                                      }
                                                                                                                      
                                                                                                                      B_m = math.fabs(B)
                                                                                                                      [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                                                                      def code(A, B_m, C, F):
                                                                                                                      	return -math.sqrt(((F / B_m) * 2.0))
                                                                                                                      
                                                                                                                      B_m = abs(B)
                                                                                                                      A, B_m, C, F = sort([A, B_m, C, F])
                                                                                                                      function code(A, B_m, C, F)
                                                                                                                      	return Float64(-sqrt(Float64(Float64(F / B_m) * 2.0)))
                                                                                                                      end
                                                                                                                      
                                                                                                                      B_m = abs(B);
                                                                                                                      A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                                                                      function tmp = code(A, B_m, C, F)
                                                                                                                      	tmp = -sqrt(((F / B_m) * 2.0));
                                                                                                                      end
                                                                                                                      
                                                                                                                      B_m = N[Abs[B], $MachinePrecision]
                                                                                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                                      code[A_, B$95$m_, C_, F_] := (-N[Sqrt[N[(N[(F / B$95$m), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision])
                                                                                                                      
                                                                                                                      \begin{array}{l}
                                                                                                                      B_m = \left|B\right|
                                                                                                                      \\
                                                                                                                      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                                                                      \\
                                                                                                                      -\sqrt{\frac{F}{B\_m} \cdot 2}
                                                                                                                      \end{array}
                                                                                                                      
                                                                                                                      Derivation
                                                                                                                      1. Initial program 22.1%

                                                                                                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                      2. Add Preprocessing
                                                                                                                      3. Taylor expanded in B around inf

                                                                                                                        \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                                      4. Step-by-step derivation
                                                                                                                        1. mul-1-negN/A

                                                                                                                          \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                                        2. lower-neg.f64N/A

                                                                                                                          \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                                                        3. lower-*.f64N/A

                                                                                                                          \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                                                        4. lower-sqrt.f64N/A

                                                                                                                          \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                                                                        5. lower-/.f64N/A

                                                                                                                          \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                                                                        6. lower-sqrt.f6415.7

                                                                                                                          \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                                                                                      5. Applied rewrites15.7%

                                                                                                                        \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                                                      6. Step-by-step derivation
                                                                                                                        1. Applied rewrites15.8%

                                                                                                                          \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                                                                        2. Add Preprocessing

                                                                                                                        Alternative 21: 27.4% accurate, 16.9× speedup?

                                                                                                                        \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ -\sqrt{F \cdot \frac{2}{B\_m}} \end{array} \]
                                                                                                                        B_m = (fabs.f64 B)
                                                                                                                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                                        (FPCore (A B_m C F) :precision binary64 (- (sqrt (* F (/ 2.0 B_m)))))
                                                                                                                        B_m = fabs(B);
                                                                                                                        assert(A < B_m && B_m < C && C < F);
                                                                                                                        double code(double A, double B_m, double C, double F) {
                                                                                                                        	return -sqrt((F * (2.0 / B_m)));
                                                                                                                        }
                                                                                                                        
                                                                                                                        B_m = abs(b)
                                                                                                                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                                        real(8) function code(a, b_m, c, f)
                                                                                                                            real(8), intent (in) :: a
                                                                                                                            real(8), intent (in) :: b_m
                                                                                                                            real(8), intent (in) :: c
                                                                                                                            real(8), intent (in) :: f
                                                                                                                            code = -sqrt((f * (2.0d0 / b_m)))
                                                                                                                        end function
                                                                                                                        
                                                                                                                        B_m = Math.abs(B);
                                                                                                                        assert A < B_m && B_m < C && C < F;
                                                                                                                        public static double code(double A, double B_m, double C, double F) {
                                                                                                                        	return -Math.sqrt((F * (2.0 / B_m)));
                                                                                                                        }
                                                                                                                        
                                                                                                                        B_m = math.fabs(B)
                                                                                                                        [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                                                                        def code(A, B_m, C, F):
                                                                                                                        	return -math.sqrt((F * (2.0 / B_m)))
                                                                                                                        
                                                                                                                        B_m = abs(B)
                                                                                                                        A, B_m, C, F = sort([A, B_m, C, F])
                                                                                                                        function code(A, B_m, C, F)
                                                                                                                        	return Float64(-sqrt(Float64(F * Float64(2.0 / B_m))))
                                                                                                                        end
                                                                                                                        
                                                                                                                        B_m = abs(B);
                                                                                                                        A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                                                                        function tmp = code(A, B_m, C, F)
                                                                                                                        	tmp = -sqrt((F * (2.0 / B_m)));
                                                                                                                        end
                                                                                                                        
                                                                                                                        B_m = N[Abs[B], $MachinePrecision]
                                                                                                                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                                                                        code[A_, B$95$m_, C_, F_] := (-N[Sqrt[N[(F * N[(2.0 / B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision])
                                                                                                                        
                                                                                                                        \begin{array}{l}
                                                                                                                        B_m = \left|B\right|
                                                                                                                        \\
                                                                                                                        [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                                                                        \\
                                                                                                                        -\sqrt{F \cdot \frac{2}{B\_m}}
                                                                                                                        \end{array}
                                                                                                                        
                                                                                                                        Derivation
                                                                                                                        1. Initial program 22.1%

                                                                                                                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                                                                        2. Add Preprocessing
                                                                                                                        3. Taylor expanded in B around inf

                                                                                                                          \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                                        4. Step-by-step derivation
                                                                                                                          1. mul-1-negN/A

                                                                                                                            \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                                                                          2. lower-neg.f64N/A

                                                                                                                            \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                                                          3. lower-*.f64N/A

                                                                                                                            \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                                                          4. lower-sqrt.f64N/A

                                                                                                                            \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                                                                          5. lower-/.f64N/A

                                                                                                                            \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                                                                          6. lower-sqrt.f6415.7

                                                                                                                            \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                                                                                        5. Applied rewrites15.7%

                                                                                                                          \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                                                                        6. Step-by-step derivation
                                                                                                                          1. Applied rewrites15.8%

                                                                                                                            \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                                                                          2. Step-by-step derivation
                                                                                                                            1. Applied rewrites15.7%

                                                                                                                              \[\leadsto -\sqrt{F \cdot \frac{2}{B}} \]
                                                                                                                            2. Add Preprocessing

                                                                                                                            Reproduce

                                                                                                                            ?
                                                                                                                            herbie shell --seed 2024307 
                                                                                                                            (FPCore (A B C F)
                                                                                                                              :name "ABCF->ab-angle a"
                                                                                                                              :precision binary64
                                                                                                                              (/ (- (sqrt (* (* 2.0 (* (- (pow B 2.0) (* (* 4.0 A) C)) F)) (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))) (- (pow B 2.0) (* (* 4.0 A) C))))