2tan (problem 3.3.2)

Percentage Accurate: 62.5% → 99.9%
Time: 13.3s
Alternatives: 6
Speedup: 34.5×

Specification

?
\[\left(\left(-10000 \leq x \land x \leq 10000\right) \land 10^{-16} \cdot \left|x\right| < \varepsilon\right) \land \varepsilon < \left|x\right|\]
\[\begin{array}{l} \\ \tan \left(x + \varepsilon\right) - \tan x \end{array} \]
(FPCore (x eps) :precision binary64 (- (tan (+ x eps)) (tan x)))
double code(double x, double eps) {
	return tan((x + eps)) - tan(x);
}
real(8) function code(x, eps)
    real(8), intent (in) :: x
    real(8), intent (in) :: eps
    code = tan((x + eps)) - tan(x)
end function
public static double code(double x, double eps) {
	return Math.tan((x + eps)) - Math.tan(x);
}
def code(x, eps):
	return math.tan((x + eps)) - math.tan(x)
function code(x, eps)
	return Float64(tan(Float64(x + eps)) - tan(x))
end
function tmp = code(x, eps)
	tmp = tan((x + eps)) - tan(x);
end
code[x_, eps_] := N[(N[Tan[N[(x + eps), $MachinePrecision]], $MachinePrecision] - N[Tan[x], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\tan \left(x + \varepsilon\right) - \tan x
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 6 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 62.5% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \tan \left(x + \varepsilon\right) - \tan x \end{array} \]
(FPCore (x eps) :precision binary64 (- (tan (+ x eps)) (tan x)))
double code(double x, double eps) {
	return tan((x + eps)) - tan(x);
}
real(8) function code(x, eps)
    real(8), intent (in) :: x
    real(8), intent (in) :: eps
    code = tan((x + eps)) - tan(x)
end function
public static double code(double x, double eps) {
	return Math.tan((x + eps)) - Math.tan(x);
}
def code(x, eps):
	return math.tan((x + eps)) - math.tan(x)
function code(x, eps)
	return Float64(tan(Float64(x + eps)) - tan(x))
end
function tmp = code(x, eps)
	tmp = tan((x + eps)) - tan(x);
end
code[x_, eps_] := N[(N[Tan[N[(x + eps), $MachinePrecision]], $MachinePrecision] - N[Tan[x], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\tan \left(x + \varepsilon\right) - \tan x
\end{array}

Alternative 1: 99.9% accurate, 0.6× speedup?

\[\begin{array}{l} \\ \frac{\sin \varepsilon}{\cos \left(\varepsilon + x\right) \cdot \cos x} \end{array} \]
(FPCore (x eps) :precision binary64 (/ (sin eps) (* (cos (+ eps x)) (cos x))))
double code(double x, double eps) {
	return sin(eps) / (cos((eps + x)) * cos(x));
}
real(8) function code(x, eps)
    real(8), intent (in) :: x
    real(8), intent (in) :: eps
    code = sin(eps) / (cos((eps + x)) * cos(x))
end function
public static double code(double x, double eps) {
	return Math.sin(eps) / (Math.cos((eps + x)) * Math.cos(x));
}
def code(x, eps):
	return math.sin(eps) / (math.cos((eps + x)) * math.cos(x))
function code(x, eps)
	return Float64(sin(eps) / Float64(cos(Float64(eps + x)) * cos(x)))
end
function tmp = code(x, eps)
	tmp = sin(eps) / (cos((eps + x)) * cos(x));
end
code[x_, eps_] := N[(N[Sin[eps], $MachinePrecision] / N[(N[Cos[N[(eps + x), $MachinePrecision]], $MachinePrecision] * N[Cos[x], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{\sin \varepsilon}{\cos \left(\varepsilon + x\right) \cdot \cos x}
\end{array}
Derivation
  1. Initial program 59.0%

    \[\tan \left(x + \varepsilon\right) - \tan x \]
  2. Add Preprocessing
  3. Step-by-step derivation
    1. lift--.f64N/A

      \[\leadsto \color{blue}{\tan \left(x + \varepsilon\right) - \tan x} \]
    2. lift-tan.f64N/A

      \[\leadsto \color{blue}{\tan \left(x + \varepsilon\right)} - \tan x \]
    3. tan-quotN/A

      \[\leadsto \color{blue}{\frac{\sin \left(x + \varepsilon\right)}{\cos \left(x + \varepsilon\right)}} - \tan x \]
    4. lift-tan.f64N/A

      \[\leadsto \frac{\sin \left(x + \varepsilon\right)}{\cos \left(x + \varepsilon\right)} - \color{blue}{\tan x} \]
    5. tan-quotN/A

      \[\leadsto \frac{\sin \left(x + \varepsilon\right)}{\cos \left(x + \varepsilon\right)} - \color{blue}{\frac{\sin x}{\cos x}} \]
    6. frac-subN/A

      \[\leadsto \color{blue}{\frac{\sin \left(x + \varepsilon\right) \cdot \cos x - \cos \left(x + \varepsilon\right) \cdot \sin x}{\cos \left(x + \varepsilon\right) \cdot \cos x}} \]
    7. lower-/.f64N/A

      \[\leadsto \color{blue}{\frac{\sin \left(x + \varepsilon\right) \cdot \cos x - \cos \left(x + \varepsilon\right) \cdot \sin x}{\cos \left(x + \varepsilon\right) \cdot \cos x}} \]
    8. sin-diffN/A

      \[\leadsto \frac{\color{blue}{\sin \left(\left(x + \varepsilon\right) - x\right)}}{\cos \left(x + \varepsilon\right) \cdot \cos x} \]
    9. lower-sin.f64N/A

      \[\leadsto \frac{\color{blue}{\sin \left(\left(x + \varepsilon\right) - x\right)}}{\cos \left(x + \varepsilon\right) \cdot \cos x} \]
    10. lower--.f64N/A

      \[\leadsto \frac{\sin \color{blue}{\left(\left(x + \varepsilon\right) - x\right)}}{\cos \left(x + \varepsilon\right) \cdot \cos x} \]
    11. lift-+.f64N/A

      \[\leadsto \frac{\sin \left(\color{blue}{\left(x + \varepsilon\right)} - x\right)}{\cos \left(x + \varepsilon\right) \cdot \cos x} \]
    12. +-commutativeN/A

      \[\leadsto \frac{\sin \left(\color{blue}{\left(\varepsilon + x\right)} - x\right)}{\cos \left(x + \varepsilon\right) \cdot \cos x} \]
    13. lower-+.f64N/A

      \[\leadsto \frac{\sin \left(\color{blue}{\left(\varepsilon + x\right)} - x\right)}{\cos \left(x + \varepsilon\right) \cdot \cos x} \]
    14. lower-*.f64N/A

      \[\leadsto \frac{\sin \left(\left(\varepsilon + x\right) - x\right)}{\color{blue}{\cos \left(x + \varepsilon\right) \cdot \cos x}} \]
    15. lower-cos.f64N/A

      \[\leadsto \frac{\sin \left(\left(\varepsilon + x\right) - x\right)}{\color{blue}{\cos \left(x + \varepsilon\right)} \cdot \cos x} \]
    16. lift-+.f64N/A

      \[\leadsto \frac{\sin \left(\left(\varepsilon + x\right) - x\right)}{\cos \color{blue}{\left(x + \varepsilon\right)} \cdot \cos x} \]
    17. +-commutativeN/A

      \[\leadsto \frac{\sin \left(\left(\varepsilon + x\right) - x\right)}{\cos \color{blue}{\left(\varepsilon + x\right)} \cdot \cos x} \]
    18. lower-+.f64N/A

      \[\leadsto \frac{\sin \left(\left(\varepsilon + x\right) - x\right)}{\cos \color{blue}{\left(\varepsilon + x\right)} \cdot \cos x} \]
    19. lower-cos.f6459.0

      \[\leadsto \frac{\sin \left(\left(\varepsilon + x\right) - x\right)}{\cos \left(\varepsilon + x\right) \cdot \color{blue}{\cos x}} \]
  4. Applied rewrites59.0%

    \[\leadsto \color{blue}{\frac{\sin \left(\left(\varepsilon + x\right) - x\right)}{\cos \left(\varepsilon + x\right) \cdot \cos x}} \]
  5. Taylor expanded in eps around -inf

    \[\leadsto \frac{\color{blue}{\sin \left(\mathsf{neg}\left(-1 \cdot \varepsilon\right)\right)}}{\cos \left(\varepsilon + x\right) \cdot \cos x} \]
  6. Step-by-step derivation
    1. mul-1-negN/A

      \[\leadsto \frac{\sin \left(\mathsf{neg}\left(\color{blue}{\left(\mathsf{neg}\left(\varepsilon\right)\right)}\right)\right)}{\cos \left(\varepsilon + x\right) \cdot \cos x} \]
    2. remove-double-negN/A

      \[\leadsto \frac{\sin \color{blue}{\varepsilon}}{\cos \left(\varepsilon + x\right) \cdot \cos x} \]
    3. lower-sin.f6499.9

      \[\leadsto \frac{\color{blue}{\sin \varepsilon}}{\cos \left(\varepsilon + x\right) \cdot \cos x} \]
  7. Applied rewrites99.9%

    \[\leadsto \frac{\color{blue}{\sin \varepsilon}}{\cos \left(\varepsilon + x\right) \cdot \cos x} \]
  8. Add Preprocessing

Alternative 2: 98.2% accurate, 1.5× speedup?

\[\begin{array}{l} \\ \mathsf{fma}\left(\varepsilon \cdot \mathsf{fma}\left(\mathsf{fma}\left(1.3333333333333333, \varepsilon \cdot \varepsilon, 1\right), x, \varepsilon\right), x, \mathsf{fma}\left({\varepsilon}^{3}, 0.3333333333333333, \varepsilon\right)\right) \end{array} \]
(FPCore (x eps)
 :precision binary64
 (fma
  (* eps (fma (fma 1.3333333333333333 (* eps eps) 1.0) x eps))
  x
  (fma (pow eps 3.0) 0.3333333333333333 eps)))
double code(double x, double eps) {
	return fma((eps * fma(fma(1.3333333333333333, (eps * eps), 1.0), x, eps)), x, fma(pow(eps, 3.0), 0.3333333333333333, eps));
}
function code(x, eps)
	return fma(Float64(eps * fma(fma(1.3333333333333333, Float64(eps * eps), 1.0), x, eps)), x, fma((eps ^ 3.0), 0.3333333333333333, eps))
end
code[x_, eps_] := N[(N[(eps * N[(N[(1.3333333333333333 * N[(eps * eps), $MachinePrecision] + 1.0), $MachinePrecision] * x + eps), $MachinePrecision]), $MachinePrecision] * x + N[(N[Power[eps, 3.0], $MachinePrecision] * 0.3333333333333333 + eps), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\mathsf{fma}\left(\varepsilon \cdot \mathsf{fma}\left(\mathsf{fma}\left(1.3333333333333333, \varepsilon \cdot \varepsilon, 1\right), x, \varepsilon\right), x, \mathsf{fma}\left({\varepsilon}^{3}, 0.3333333333333333, \varepsilon\right)\right)
\end{array}
Derivation
  1. Initial program 59.0%

    \[\tan \left(x + \varepsilon\right) - \tan x \]
  2. Add Preprocessing
  3. Taylor expanded in eps around 0

    \[\leadsto \color{blue}{\varepsilon \cdot \left(\left(1 + \varepsilon \cdot \left(-1 \cdot \left(\varepsilon \cdot \left(\frac{1}{6} + \left(-1 \cdot \frac{{\sin x}^{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{{\cos x}^{2}} + \left(\frac{-1}{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right) + \frac{1}{6} \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)\right)\right)\right) - -1 \cdot \frac{\sin x \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{\cos x}\right)\right) - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)} \]
  4. Applied rewrites99.2%

    \[\leadsto \color{blue}{\mathsf{fma}\left(\left(\frac{\mathsf{fma}\left(\sin x, \sin x, \frac{{\sin x}^{4}}{{\cos x}^{2}}\right)}{{\cos x}^{2}} - \mathsf{fma}\left(\frac{\sin x}{{\cos x}^{2}}, \sin x, 1\right) \cdot -0.3333333333333333\right) \cdot \varepsilon, \varepsilon, \mathsf{fma}\left(\frac{\sin x}{{\cos x}^{2}}, \sin x, 1\right) \cdot \left(\frac{\sin x \cdot \varepsilon}{\cos x} + 1\right)\right) \cdot \varepsilon} \]
  5. Taylor expanded in x around 0

    \[\leadsto \left(1 + \frac{1}{3} \cdot {\varepsilon}^{2}\right) \cdot \varepsilon \]
  6. Step-by-step derivation
    1. Applied rewrites98.5%

      \[\leadsto \mathsf{fma}\left(\varepsilon \cdot \varepsilon, 0.3333333333333333, 1\right) \cdot \varepsilon \]
    2. Taylor expanded in x around 0

      \[\leadsto \varepsilon \cdot \left(1 + \frac{1}{3} \cdot {\varepsilon}^{2}\right) + \color{blue}{x \cdot \left(\varepsilon \cdot \left(x \cdot \left(1 + \frac{4}{3} \cdot {\varepsilon}^{2}\right)\right) + {\varepsilon}^{2}\right)} \]
    3. Step-by-step derivation
      1. Applied rewrites98.9%

        \[\leadsto \mathsf{fma}\left(\varepsilon \cdot \mathsf{fma}\left(\mathsf{fma}\left(1.3333333333333333, \varepsilon \cdot \varepsilon, 1\right), x, \varepsilon\right), \color{blue}{x}, \mathsf{fma}\left({\varepsilon}^{3}, 0.3333333333333333, \varepsilon\right)\right) \]
      2. Add Preprocessing

      Alternative 3: 98.2% accurate, 8.6× speedup?

      \[\begin{array}{l} \\ \mathsf{fma}\left(\mathsf{fma}\left(0.3333333333333333, \varepsilon, x\right), \varepsilon, \mathsf{fma}\left(x, x, 1\right)\right) \cdot \varepsilon \end{array} \]
      (FPCore (x eps)
       :precision binary64
       (* (fma (fma 0.3333333333333333 eps x) eps (fma x x 1.0)) eps))
      double code(double x, double eps) {
      	return fma(fma(0.3333333333333333, eps, x), eps, fma(x, x, 1.0)) * eps;
      }
      
      function code(x, eps)
      	return Float64(fma(fma(0.3333333333333333, eps, x), eps, fma(x, x, 1.0)) * eps)
      end
      
      code[x_, eps_] := N[(N[(N[(0.3333333333333333 * eps + x), $MachinePrecision] * eps + N[(x * x + 1.0), $MachinePrecision]), $MachinePrecision] * eps), $MachinePrecision]
      
      \begin{array}{l}
      
      \\
      \mathsf{fma}\left(\mathsf{fma}\left(0.3333333333333333, \varepsilon, x\right), \varepsilon, \mathsf{fma}\left(x, x, 1\right)\right) \cdot \varepsilon
      \end{array}
      
      Derivation
      1. Initial program 59.0%

        \[\tan \left(x + \varepsilon\right) - \tan x \]
      2. Add Preprocessing
      3. Taylor expanded in eps around 0

        \[\leadsto \color{blue}{\varepsilon \cdot \left(\left(1 + \varepsilon \cdot \left(-1 \cdot \left(\varepsilon \cdot \left(\frac{1}{6} + \left(-1 \cdot \frac{{\sin x}^{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{{\cos x}^{2}} + \left(\frac{-1}{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right) + \frac{1}{6} \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)\right)\right)\right) - -1 \cdot \frac{\sin x \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{\cos x}\right)\right) - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)} \]
      4. Applied rewrites99.2%

        \[\leadsto \color{blue}{\mathsf{fma}\left(\left(\frac{\mathsf{fma}\left(\sin x, \sin x, \frac{{\sin x}^{4}}{{\cos x}^{2}}\right)}{{\cos x}^{2}} - \mathsf{fma}\left(\frac{\sin x}{{\cos x}^{2}}, \sin x, 1\right) \cdot -0.3333333333333333\right) \cdot \varepsilon, \varepsilon, \mathsf{fma}\left(\frac{\sin x}{{\cos x}^{2}}, \sin x, 1\right) \cdot \left(\frac{\sin x \cdot \varepsilon}{\cos x} + 1\right)\right) \cdot \varepsilon} \]
      5. Taylor expanded in x around 0

        \[\leadsto \left(1 + \left(\frac{1}{3} \cdot {\varepsilon}^{2} + x \cdot \left(\varepsilon + x \cdot \left(1 + \frac{4}{3} \cdot {\varepsilon}^{2}\right)\right)\right)\right) \cdot \varepsilon \]
      6. Step-by-step derivation
        1. Applied rewrites98.9%

          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(1.3333333333333333, \varepsilon \cdot \varepsilon, 1\right), x, \varepsilon\right), x, \mathsf{fma}\left(\varepsilon \cdot \varepsilon, 0.3333333333333333, 1\right)\right) \cdot \varepsilon \]
        2. Taylor expanded in eps around 0

          \[\leadsto \left(1 + \left(\varepsilon \cdot \left(x + \varepsilon \cdot \left(\frac{1}{3} + \frac{4}{3} \cdot {x}^{2}\right)\right) + {x}^{2}\right)\right) \cdot \varepsilon \]
        3. Step-by-step derivation
          1. Applied rewrites98.9%

            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(x \cdot x, 1.3333333333333333, 0.3333333333333333\right), \varepsilon, x\right), \varepsilon, \mathsf{fma}\left(x, x, 1\right)\right) \cdot \varepsilon \]
          2. Taylor expanded in x around 0

            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{3}, \varepsilon, x\right), \varepsilon, \mathsf{fma}\left(x, x, 1\right)\right) \cdot \varepsilon \]
          3. Step-by-step derivation
            1. Applied rewrites98.9%

              \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(0.3333333333333333, \varepsilon, x\right), \varepsilon, \mathsf{fma}\left(x, x, 1\right)\right) \cdot \varepsilon \]
            2. Add Preprocessing

            Alternative 4: 98.2% accurate, 13.8× speedup?

            \[\begin{array}{l} \\ \mathsf{fma}\left(x, x + \varepsilon, 1\right) \cdot \varepsilon \end{array} \]
            (FPCore (x eps) :precision binary64 (* (fma x (+ x eps) 1.0) eps))
            double code(double x, double eps) {
            	return fma(x, (x + eps), 1.0) * eps;
            }
            
            function code(x, eps)
            	return Float64(fma(x, Float64(x + eps), 1.0) * eps)
            end
            
            code[x_, eps_] := N[(N[(x * N[(x + eps), $MachinePrecision] + 1.0), $MachinePrecision] * eps), $MachinePrecision]
            
            \begin{array}{l}
            
            \\
            \mathsf{fma}\left(x, x + \varepsilon, 1\right) \cdot \varepsilon
            \end{array}
            
            Derivation
            1. Initial program 59.0%

              \[\tan \left(x + \varepsilon\right) - \tan x \]
            2. Add Preprocessing
            3. Taylor expanded in eps around 0

              \[\leadsto \color{blue}{\varepsilon \cdot \left(\left(1 + \varepsilon \cdot \left(-1 \cdot \left(\varepsilon \cdot \left(\frac{1}{6} + \left(-1 \cdot \frac{{\sin x}^{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{{\cos x}^{2}} + \left(\frac{-1}{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right) + \frac{1}{6} \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)\right)\right)\right) - -1 \cdot \frac{\sin x \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{\cos x}\right)\right) - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)} \]
            4. Applied rewrites99.2%

              \[\leadsto \color{blue}{\mathsf{fma}\left(\left(\frac{\mathsf{fma}\left(\sin x, \sin x, \frac{{\sin x}^{4}}{{\cos x}^{2}}\right)}{{\cos x}^{2}} - \mathsf{fma}\left(\frac{\sin x}{{\cos x}^{2}}, \sin x, 1\right) \cdot -0.3333333333333333\right) \cdot \varepsilon, \varepsilon, \mathsf{fma}\left(\frac{\sin x}{{\cos x}^{2}}, \sin x, 1\right) \cdot \left(\frac{\sin x \cdot \varepsilon}{\cos x} + 1\right)\right) \cdot \varepsilon} \]
            5. Taylor expanded in x around 0

              \[\leadsto \left(1 + \left(\frac{1}{3} \cdot {\varepsilon}^{2} + x \cdot \left(\varepsilon + x \cdot \left(1 + \frac{4}{3} \cdot {\varepsilon}^{2}\right)\right)\right)\right) \cdot \varepsilon \]
            6. Step-by-step derivation
              1. Applied rewrites98.9%

                \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(1.3333333333333333, \varepsilon \cdot \varepsilon, 1\right), x, \varepsilon\right), x, \mathsf{fma}\left(\varepsilon \cdot \varepsilon, 0.3333333333333333, 1\right)\right) \cdot \varepsilon \]
              2. Taylor expanded in eps around 0

                \[\leadsto \left(1 + \left(\varepsilon \cdot x + {x}^{2}\right)\right) \cdot \varepsilon \]
              3. Step-by-step derivation
                1. Applied rewrites98.8%

                  \[\leadsto \mathsf{fma}\left(x, x + \varepsilon, 1\right) \cdot \varepsilon \]
                2. Add Preprocessing

                Alternative 5: 98.1% accurate, 17.3× speedup?

                \[\begin{array}{l} \\ \mathsf{fma}\left(x, x, 1\right) \cdot \varepsilon \end{array} \]
                (FPCore (x eps) :precision binary64 (* (fma x x 1.0) eps))
                double code(double x, double eps) {
                	return fma(x, x, 1.0) * eps;
                }
                
                function code(x, eps)
                	return Float64(fma(x, x, 1.0) * eps)
                end
                
                code[x_, eps_] := N[(N[(x * x + 1.0), $MachinePrecision] * eps), $MachinePrecision]
                
                \begin{array}{l}
                
                \\
                \mathsf{fma}\left(x, x, 1\right) \cdot \varepsilon
                \end{array}
                
                Derivation
                1. Initial program 59.0%

                  \[\tan \left(x + \varepsilon\right) - \tan x \]
                2. Add Preprocessing
                3. Taylor expanded in eps around 0

                  \[\leadsto \color{blue}{\varepsilon \cdot \left(\left(1 + \varepsilon \cdot \left(-1 \cdot \left(\varepsilon \cdot \left(\frac{1}{6} + \left(-1 \cdot \frac{{\sin x}^{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{{\cos x}^{2}} + \left(\frac{-1}{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right) + \frac{1}{6} \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)\right)\right)\right) - -1 \cdot \frac{\sin x \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{\cos x}\right)\right) - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)} \]
                4. Applied rewrites99.2%

                  \[\leadsto \color{blue}{\mathsf{fma}\left(\left(\frac{\mathsf{fma}\left(\sin x, \sin x, \frac{{\sin x}^{4}}{{\cos x}^{2}}\right)}{{\cos x}^{2}} - \mathsf{fma}\left(\frac{\sin x}{{\cos x}^{2}}, \sin x, 1\right) \cdot -0.3333333333333333\right) \cdot \varepsilon, \varepsilon, \mathsf{fma}\left(\frac{\sin x}{{\cos x}^{2}}, \sin x, 1\right) \cdot \left(\frac{\sin x \cdot \varepsilon}{\cos x} + 1\right)\right) \cdot \varepsilon} \]
                5. Taylor expanded in x around 0

                  \[\leadsto \left(1 + \left(\frac{1}{3} \cdot {\varepsilon}^{2} + x \cdot \left(\varepsilon + x \cdot \left(1 + \frac{4}{3} \cdot {\varepsilon}^{2}\right)\right)\right)\right) \cdot \varepsilon \]
                6. Step-by-step derivation
                  1. Applied rewrites98.9%

                    \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(1.3333333333333333, \varepsilon \cdot \varepsilon, 1\right), x, \varepsilon\right), x, \mathsf{fma}\left(\varepsilon \cdot \varepsilon, 0.3333333333333333, 1\right)\right) \cdot \varepsilon \]
                  2. Taylor expanded in eps around 0

                    \[\leadsto \left(1 + {x}^{2}\right) \cdot \varepsilon \]
                  3. Step-by-step derivation
                    1. Applied rewrites98.8%

                      \[\leadsto \mathsf{fma}\left(x, x, 1\right) \cdot \varepsilon \]
                    2. Add Preprocessing

                    Alternative 6: 97.7% accurate, 34.5× speedup?

                    \[\begin{array}{l} \\ 1 \cdot \varepsilon \end{array} \]
                    (FPCore (x eps) :precision binary64 (* 1.0 eps))
                    double code(double x, double eps) {
                    	return 1.0 * eps;
                    }
                    
                    real(8) function code(x, eps)
                        real(8), intent (in) :: x
                        real(8), intent (in) :: eps
                        code = 1.0d0 * eps
                    end function
                    
                    public static double code(double x, double eps) {
                    	return 1.0 * eps;
                    }
                    
                    def code(x, eps):
                    	return 1.0 * eps
                    
                    function code(x, eps)
                    	return Float64(1.0 * eps)
                    end
                    
                    function tmp = code(x, eps)
                    	tmp = 1.0 * eps;
                    end
                    
                    code[x_, eps_] := N[(1.0 * eps), $MachinePrecision]
                    
                    \begin{array}{l}
                    
                    \\
                    1 \cdot \varepsilon
                    \end{array}
                    
                    Derivation
                    1. Initial program 59.0%

                      \[\tan \left(x + \varepsilon\right) - \tan x \]
                    2. Add Preprocessing
                    3. Taylor expanded in eps around 0

                      \[\leadsto \color{blue}{\varepsilon \cdot \left(\left(1 + \varepsilon \cdot \left(-1 \cdot \left(\varepsilon \cdot \left(\frac{1}{6} + \left(-1 \cdot \frac{{\sin x}^{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{{\cos x}^{2}} + \left(\frac{-1}{2} \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right) + \frac{1}{6} \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)\right)\right)\right) - -1 \cdot \frac{\sin x \cdot \left(1 - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)}{\cos x}\right)\right) - -1 \cdot \frac{{\sin x}^{2}}{{\cos x}^{2}}\right)} \]
                    4. Applied rewrites99.2%

                      \[\leadsto \color{blue}{\mathsf{fma}\left(\left(\frac{\mathsf{fma}\left(\sin x, \sin x, \frac{{\sin x}^{4}}{{\cos x}^{2}}\right)}{{\cos x}^{2}} - \mathsf{fma}\left(\frac{\sin x}{{\cos x}^{2}}, \sin x, 1\right) \cdot -0.3333333333333333\right) \cdot \varepsilon, \varepsilon, \mathsf{fma}\left(\frac{\sin x}{{\cos x}^{2}}, \sin x, 1\right) \cdot \left(\frac{\sin x \cdot \varepsilon}{\cos x} + 1\right)\right) \cdot \varepsilon} \]
                    5. Taylor expanded in x around 0

                      \[\leadsto \left(1 + \frac{1}{3} \cdot {\varepsilon}^{2}\right) \cdot \varepsilon \]
                    6. Step-by-step derivation
                      1. Applied rewrites98.5%

                        \[\leadsto \mathsf{fma}\left(\varepsilon \cdot \varepsilon, 0.3333333333333333, 1\right) \cdot \varepsilon \]
                      2. Taylor expanded in eps around 0

                        \[\leadsto 1 \cdot \varepsilon \]
                      3. Step-by-step derivation
                        1. Applied rewrites98.5%

                          \[\leadsto 1 \cdot \varepsilon \]
                        2. Add Preprocessing

                        Developer Target 1: 98.9% accurate, 1.0× speedup?

                        \[\begin{array}{l} \\ \varepsilon + \left(\varepsilon \cdot \tan x\right) \cdot \tan x \end{array} \]
                        (FPCore (x eps) :precision binary64 (+ eps (* (* eps (tan x)) (tan x))))
                        double code(double x, double eps) {
                        	return eps + ((eps * tan(x)) * tan(x));
                        }
                        
                        real(8) function code(x, eps)
                            real(8), intent (in) :: x
                            real(8), intent (in) :: eps
                            code = eps + ((eps * tan(x)) * tan(x))
                        end function
                        
                        public static double code(double x, double eps) {
                        	return eps + ((eps * Math.tan(x)) * Math.tan(x));
                        }
                        
                        def code(x, eps):
                        	return eps + ((eps * math.tan(x)) * math.tan(x))
                        
                        function code(x, eps)
                        	return Float64(eps + Float64(Float64(eps * tan(x)) * tan(x)))
                        end
                        
                        function tmp = code(x, eps)
                        	tmp = eps + ((eps * tan(x)) * tan(x));
                        end
                        
                        code[x_, eps_] := N[(eps + N[(N[(eps * N[Tan[x], $MachinePrecision]), $MachinePrecision] * N[Tan[x], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
                        
                        \begin{array}{l}
                        
                        \\
                        \varepsilon + \left(\varepsilon \cdot \tan x\right) \cdot \tan x
                        \end{array}
                        

                        Reproduce

                        ?
                        herbie shell --seed 2024307 
                        (FPCore (x eps)
                          :name "2tan (problem 3.3.2)"
                          :precision binary64
                          :pre (and (and (and (<= -10000.0 x) (<= x 10000.0)) (< (* 1e-16 (fabs x)) eps)) (< eps (fabs x)))
                        
                          :alt
                          (! :herbie-platform default (+ eps (* eps (tan x) (tan x))))
                        
                          (- (tan (+ x eps)) (tan x)))