Toniolo and Linder, Equation (3a)

Percentage Accurate: 98.6% → 99.0%
Time: 11.2s
Alternatives: 7
Speedup: 0.8×

Specification

?
\[\begin{array}{l} \\ \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \end{array} \]
(FPCore (l Om kx ky)
 :precision binary64
 (sqrt
  (*
   (/ 1.0 2.0)
   (+
    1.0
    (/
     1.0
     (sqrt
      (+
       1.0
       (*
        (pow (/ (* 2.0 l) Om) 2.0)
        (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0))))))))))
double code(double l, double Om, double kx, double ky) {
	return sqrt(((1.0 / 2.0) * (1.0 + (1.0 / sqrt((1.0 + (pow(((2.0 * l) / Om), 2.0) * (pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))))))));
}
real(8) function code(l, om, kx, ky)
    real(8), intent (in) :: l
    real(8), intent (in) :: om
    real(8), intent (in) :: kx
    real(8), intent (in) :: ky
    code = sqrt(((1.0d0 / 2.0d0) * (1.0d0 + (1.0d0 / sqrt((1.0d0 + ((((2.0d0 * l) / om) ** 2.0d0) * ((sin(kx) ** 2.0d0) + (sin(ky) ** 2.0d0)))))))))
end function
public static double code(double l, double Om, double kx, double ky) {
	return Math.sqrt(((1.0 / 2.0) * (1.0 + (1.0 / Math.sqrt((1.0 + (Math.pow(((2.0 * l) / Om), 2.0) * (Math.pow(Math.sin(kx), 2.0) + Math.pow(Math.sin(ky), 2.0)))))))));
}
def code(l, Om, kx, ky):
	return math.sqrt(((1.0 / 2.0) * (1.0 + (1.0 / math.sqrt((1.0 + (math.pow(((2.0 * l) / Om), 2.0) * (math.pow(math.sin(kx), 2.0) + math.pow(math.sin(ky), 2.0)))))))))
function code(l, Om, kx, ky)
	return sqrt(Float64(Float64(1.0 / 2.0) * Float64(1.0 + Float64(1.0 / sqrt(Float64(1.0 + Float64((Float64(Float64(2.0 * l) / Om) ^ 2.0) * Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))))))))
end
function tmp = code(l, Om, kx, ky)
	tmp = sqrt(((1.0 / 2.0) * (1.0 + (1.0 / sqrt((1.0 + ((((2.0 * l) / Om) ^ 2.0) * ((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))))))));
end
code[l_, Om_, kx_, ky_] := N[Sqrt[N[(N[(1.0 / 2.0), $MachinePrecision] * N[(1.0 + N[(1.0 / N[Sqrt[N[(1.0 + N[(N[Power[N[(N[(2.0 * l), $MachinePrecision] / Om), $MachinePrecision], 2.0], $MachinePrecision] * N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 7 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 98.6% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \end{array} \]
(FPCore (l Om kx ky)
 :precision binary64
 (sqrt
  (*
   (/ 1.0 2.0)
   (+
    1.0
    (/
     1.0
     (sqrt
      (+
       1.0
       (*
        (pow (/ (* 2.0 l) Om) 2.0)
        (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0))))))))))
double code(double l, double Om, double kx, double ky) {
	return sqrt(((1.0 / 2.0) * (1.0 + (1.0 / sqrt((1.0 + (pow(((2.0 * l) / Om), 2.0) * (pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))))))));
}
real(8) function code(l, om, kx, ky)
    real(8), intent (in) :: l
    real(8), intent (in) :: om
    real(8), intent (in) :: kx
    real(8), intent (in) :: ky
    code = sqrt(((1.0d0 / 2.0d0) * (1.0d0 + (1.0d0 / sqrt((1.0d0 + ((((2.0d0 * l) / om) ** 2.0d0) * ((sin(kx) ** 2.0d0) + (sin(ky) ** 2.0d0)))))))))
end function
public static double code(double l, double Om, double kx, double ky) {
	return Math.sqrt(((1.0 / 2.0) * (1.0 + (1.0 / Math.sqrt((1.0 + (Math.pow(((2.0 * l) / Om), 2.0) * (Math.pow(Math.sin(kx), 2.0) + Math.pow(Math.sin(ky), 2.0)))))))));
}
def code(l, Om, kx, ky):
	return math.sqrt(((1.0 / 2.0) * (1.0 + (1.0 / math.sqrt((1.0 + (math.pow(((2.0 * l) / Om), 2.0) * (math.pow(math.sin(kx), 2.0) + math.pow(math.sin(ky), 2.0)))))))))
function code(l, Om, kx, ky)
	return sqrt(Float64(Float64(1.0 / 2.0) * Float64(1.0 + Float64(1.0 / sqrt(Float64(1.0 + Float64((Float64(Float64(2.0 * l) / Om) ^ 2.0) * Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))))))))
end
function tmp = code(l, Om, kx, ky)
	tmp = sqrt(((1.0 / 2.0) * (1.0 + (1.0 / sqrt((1.0 + ((((2.0 * l) / Om) ^ 2.0) * ((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))))))));
end
code[l_, Om_, kx_, ky_] := N[Sqrt[N[(N[(1.0 / 2.0), $MachinePrecision] * N[(1.0 + N[(1.0 / N[Sqrt[N[(1.0 + N[(N[Power[N[(N[(2.0 * l), $MachinePrecision] / Om), $MachinePrecision], 2.0], $MachinePrecision] * N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)}
\end{array}

Alternative 1: 99.0% accurate, 0.6× speedup?

\[\begin{array}{l} ky_m = \left|ky\right| \\ kx_m = \left|kx\right| \\ [l, Om, kx_m, ky_m] = \mathsf{sort}([l, Om, kx_m, ky_m])\\ \\ \begin{array}{l} \mathbf{if}\;{\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx\_m}^{2} + {\sin ky\_m}^{2}\right) \leq 10^{+28}:\\ \;\;\;\;\sqrt{{2}^{-1} \cdot \left(1 + {\left(\sqrt{\mathsf{fma}\left(\frac{\ell \cdot 2}{Om}, \frac{\left(1 - \cos \left(ky\_m \cdot 2\right)\right) \cdot \ell}{2 \cdot Om} \cdot 2, 1\right)}\right)}^{-1}\right)}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{0.5}\\ \end{array} \end{array} \]
ky_m = (fabs.f64 ky)
kx_m = (fabs.f64 kx)
NOTE: l, Om, kx_m, and ky_m should be sorted in increasing order before calling this function.
(FPCore (l Om kx_m ky_m)
 :precision binary64
 (if (<=
      (*
       (pow (/ (* 2.0 l) Om) 2.0)
       (+ (pow (sin kx_m) 2.0) (pow (sin ky_m) 2.0)))
      1e+28)
   (sqrt
    (*
     (pow 2.0 -1.0)
     (+
      1.0
      (pow
       (sqrt
        (fma
         (/ (* l 2.0) Om)
         (* (/ (* (- 1.0 (cos (* ky_m 2.0))) l) (* 2.0 Om)) 2.0)
         1.0))
       -1.0))))
   (sqrt 0.5)))
ky_m = fabs(ky);
kx_m = fabs(kx);
assert(l < Om && Om < kx_m && kx_m < ky_m);
double code(double l, double Om, double kx_m, double ky_m) {
	double tmp;
	if ((pow(((2.0 * l) / Om), 2.0) * (pow(sin(kx_m), 2.0) + pow(sin(ky_m), 2.0))) <= 1e+28) {
		tmp = sqrt((pow(2.0, -1.0) * (1.0 + pow(sqrt(fma(((l * 2.0) / Om), ((((1.0 - cos((ky_m * 2.0))) * l) / (2.0 * Om)) * 2.0), 1.0)), -1.0))));
	} else {
		tmp = sqrt(0.5);
	}
	return tmp;
}
ky_m = abs(ky)
kx_m = abs(kx)
l, Om, kx_m, ky_m = sort([l, Om, kx_m, ky_m])
function code(l, Om, kx_m, ky_m)
	tmp = 0.0
	if (Float64((Float64(Float64(2.0 * l) / Om) ^ 2.0) * Float64((sin(kx_m) ^ 2.0) + (sin(ky_m) ^ 2.0))) <= 1e+28)
		tmp = sqrt(Float64((2.0 ^ -1.0) * Float64(1.0 + (sqrt(fma(Float64(Float64(l * 2.0) / Om), Float64(Float64(Float64(Float64(1.0 - cos(Float64(ky_m * 2.0))) * l) / Float64(2.0 * Om)) * 2.0), 1.0)) ^ -1.0))));
	else
		tmp = sqrt(0.5);
	end
	return tmp
end
ky_m = N[Abs[ky], $MachinePrecision]
kx_m = N[Abs[kx], $MachinePrecision]
NOTE: l, Om, kx_m, and ky_m should be sorted in increasing order before calling this function.
code[l_, Om_, kx$95$m_, ky$95$m_] := If[LessEqual[N[(N[Power[N[(N[(2.0 * l), $MachinePrecision] / Om), $MachinePrecision], 2.0], $MachinePrecision] * N[(N[Power[N[Sin[kx$95$m], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky$95$m], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 1e+28], N[Sqrt[N[(N[Power[2.0, -1.0], $MachinePrecision] * N[(1.0 + N[Power[N[Sqrt[N[(N[(N[(l * 2.0), $MachinePrecision] / Om), $MachinePrecision] * N[(N[(N[(N[(1.0 - N[Cos[N[(ky$95$m * 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * l), $MachinePrecision] / N[(2.0 * Om), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision] + 1.0), $MachinePrecision]], $MachinePrecision], -1.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision], N[Sqrt[0.5], $MachinePrecision]]
\begin{array}{l}
ky_m = \left|ky\right|
\\
kx_m = \left|kx\right|
\\
[l, Om, kx_m, ky_m] = \mathsf{sort}([l, Om, kx_m, ky_m])\\
\\
\begin{array}{l}
\mathbf{if}\;{\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx\_m}^{2} + {\sin ky\_m}^{2}\right) \leq 10^{+28}:\\
\;\;\;\;\sqrt{{2}^{-1} \cdot \left(1 + {\left(\sqrt{\mathsf{fma}\left(\frac{\ell \cdot 2}{Om}, \frac{\left(1 - \cos \left(ky\_m \cdot 2\right)\right) \cdot \ell}{2 \cdot Om} \cdot 2, 1\right)}\right)}^{-1}\right)}\\

\mathbf{else}:\\
\;\;\;\;\sqrt{0.5}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))) < 9.99999999999999958e27

    1. Initial program 100.0%

      \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in ky around 0

      \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \color{blue}{{ky}^{2} \cdot \left(1 + {ky}^{2} \cdot \left(\frac{2}{45} \cdot {ky}^{2} - \frac{1}{3}\right)\right)}\right)}}\right)} \]
    4. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \color{blue}{\left(1 + {ky}^{2} \cdot \left(\frac{2}{45} \cdot {ky}^{2} - \frac{1}{3}\right)\right) \cdot {ky}^{2}}\right)}}\right)} \]
      2. lower-*.f64N/A

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \color{blue}{\left(1 + {ky}^{2} \cdot \left(\frac{2}{45} \cdot {ky}^{2} - \frac{1}{3}\right)\right) \cdot {ky}^{2}}\right)}}\right)} \]
      3. +-commutativeN/A

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \color{blue}{\left({ky}^{2} \cdot \left(\frac{2}{45} \cdot {ky}^{2} - \frac{1}{3}\right) + 1\right)} \cdot {ky}^{2}\right)}}\right)} \]
      4. *-commutativeN/A

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \left(\color{blue}{\left(\frac{2}{45} \cdot {ky}^{2} - \frac{1}{3}\right) \cdot {ky}^{2}} + 1\right) \cdot {ky}^{2}\right)}}\right)} \]
      5. lower-fma.f64N/A

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \color{blue}{\mathsf{fma}\left(\frac{2}{45} \cdot {ky}^{2} - \frac{1}{3}, {ky}^{2}, 1\right)} \cdot {ky}^{2}\right)}}\right)} \]
      6. sub-negN/A

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\color{blue}{\frac{2}{45} \cdot {ky}^{2} + \left(\mathsf{neg}\left(\frac{1}{3}\right)\right)}, {ky}^{2}, 1\right) \cdot {ky}^{2}\right)}}\right)} \]
      7. metadata-evalN/A

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\frac{2}{45} \cdot {ky}^{2} + \color{blue}{\frac{-1}{3}}, {ky}^{2}, 1\right) \cdot {ky}^{2}\right)}}\right)} \]
      8. lower-fma.f64N/A

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(\frac{2}{45}, {ky}^{2}, \frac{-1}{3}\right)}, {ky}^{2}, 1\right) \cdot {ky}^{2}\right)}}\right)} \]
      9. unpow2N/A

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\mathsf{fma}\left(\frac{2}{45}, \color{blue}{ky \cdot ky}, \frac{-1}{3}\right), {ky}^{2}, 1\right) \cdot {ky}^{2}\right)}}\right)} \]
      10. lower-*.f64N/A

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\mathsf{fma}\left(\frac{2}{45}, \color{blue}{ky \cdot ky}, \frac{-1}{3}\right), {ky}^{2}, 1\right) \cdot {ky}^{2}\right)}}\right)} \]
      11. unpow2N/A

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\mathsf{fma}\left(\frac{2}{45}, ky \cdot ky, \frac{-1}{3}\right), \color{blue}{ky \cdot ky}, 1\right) \cdot {ky}^{2}\right)}}\right)} \]
      12. lower-*.f64N/A

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\mathsf{fma}\left(\frac{2}{45}, ky \cdot ky, \frac{-1}{3}\right), \color{blue}{ky \cdot ky}, 1\right) \cdot {ky}^{2}\right)}}\right)} \]
      13. unpow2N/A

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\mathsf{fma}\left(\frac{2}{45}, ky \cdot ky, \frac{-1}{3}\right), ky \cdot ky, 1\right) \cdot \color{blue}{\left(ky \cdot ky\right)}\right)}}\right)} \]
      14. lower-*.f6462.1

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\mathsf{fma}\left(0.044444444444444446, ky \cdot ky, -0.3333333333333333\right), ky \cdot ky, 1\right) \cdot \color{blue}{\left(ky \cdot ky\right)}\right)}}\right)} \]
    5. Applied rewrites62.1%

      \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(0.044444444444444446, ky \cdot ky, -0.3333333333333333\right), ky \cdot ky, 1\right) \cdot \left(ky \cdot ky\right)}\right)}}\right)} \]
    6. Step-by-step derivation
      1. lift-+.f64N/A

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\color{blue}{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\mathsf{fma}\left(\frac{2}{45}, ky \cdot ky, \frac{-1}{3}\right), ky \cdot ky, 1\right) \cdot \left(ky \cdot ky\right)\right)}}}\right)} \]
      2. +-commutativeN/A

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\color{blue}{{\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\mathsf{fma}\left(\frac{2}{45}, ky \cdot ky, \frac{-1}{3}\right), ky \cdot ky, 1\right) \cdot \left(ky \cdot ky\right)\right) + 1}}}\right)} \]
      3. lift-*.f64N/A

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\color{blue}{{\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\mathsf{fma}\left(\frac{2}{45}, ky \cdot ky, \frac{-1}{3}\right), ky \cdot ky, 1\right) \cdot \left(ky \cdot ky\right)\right)} + 1}}\right)} \]
      4. lift-pow.f64N/A

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\color{blue}{{\left(\frac{2 \cdot \ell}{Om}\right)}^{2}} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\mathsf{fma}\left(\frac{2}{45}, ky \cdot ky, \frac{-1}{3}\right), ky \cdot ky, 1\right) \cdot \left(ky \cdot ky\right)\right) + 1}}\right)} \]
      5. unpow2N/A

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\color{blue}{\left(\frac{2 \cdot \ell}{Om} \cdot \frac{2 \cdot \ell}{Om}\right)} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\mathsf{fma}\left(\frac{2}{45}, ky \cdot ky, \frac{-1}{3}\right), ky \cdot ky, 1\right) \cdot \left(ky \cdot ky\right)\right) + 1}}\right)} \]
      6. associate-*l*N/A

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\color{blue}{\frac{2 \cdot \ell}{Om} \cdot \left(\frac{2 \cdot \ell}{Om} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\mathsf{fma}\left(\frac{2}{45}, ky \cdot ky, \frac{-1}{3}\right), ky \cdot ky, 1\right) \cdot \left(ky \cdot ky\right)\right)\right)} + 1}}\right)} \]
      7. lower-fma.f64N/A

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\color{blue}{\mathsf{fma}\left(\frac{2 \cdot \ell}{Om}, \frac{2 \cdot \ell}{Om} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\mathsf{fma}\left(\frac{2}{45}, ky \cdot ky, \frac{-1}{3}\right), ky \cdot ky, 1\right) \cdot \left(ky \cdot ky\right)\right), 1\right)}}}\right)} \]
    7. Applied rewrites64.6%

      \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\color{blue}{\mathsf{fma}\left(\frac{\ell \cdot 2}{Om}, \frac{\ell \cdot 2}{Om} \cdot \mathsf{fma}\left(\sin kx, \sin kx, \left(\mathsf{fma}\left(\mathsf{fma}\left(0.044444444444444446, ky \cdot ky, -0.3333333333333333\right), ky \cdot ky, 1\right) \cdot ky\right) \cdot ky\right), 1\right)}}}\right)} \]
    8. Taylor expanded in kx around 0

      \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\mathsf{fma}\left(\frac{\ell \cdot 2}{Om}, \color{blue}{2 \cdot \frac{\ell \cdot {\sin ky}^{2}}{Om}}, 1\right)}}\right)} \]
    9. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\mathsf{fma}\left(\frac{\ell \cdot 2}{Om}, \color{blue}{\frac{\ell \cdot {\sin ky}^{2}}{Om} \cdot 2}, 1\right)}}\right)} \]
      2. lower-*.f64N/A

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\mathsf{fma}\left(\frac{\ell \cdot 2}{Om}, \color{blue}{\frac{\ell \cdot {\sin ky}^{2}}{Om} \cdot 2}, 1\right)}}\right)} \]
      3. lower-/.f64N/A

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\mathsf{fma}\left(\frac{\ell \cdot 2}{Om}, \color{blue}{\frac{\ell \cdot {\sin ky}^{2}}{Om}} \cdot 2, 1\right)}}\right)} \]
      4. *-commutativeN/A

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\mathsf{fma}\left(\frac{\ell \cdot 2}{Om}, \frac{\color{blue}{{\sin ky}^{2} \cdot \ell}}{Om} \cdot 2, 1\right)}}\right)} \]
      5. lower-*.f64N/A

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\mathsf{fma}\left(\frac{\ell \cdot 2}{Om}, \frac{\color{blue}{{\sin ky}^{2} \cdot \ell}}{Om} \cdot 2, 1\right)}}\right)} \]
      6. lower-pow.f64N/A

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\mathsf{fma}\left(\frac{\ell \cdot 2}{Om}, \frac{\color{blue}{{\sin ky}^{2}} \cdot \ell}{Om} \cdot 2, 1\right)}}\right)} \]
      7. lower-sin.f6497.5

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\mathsf{fma}\left(\frac{\ell \cdot 2}{Om}, \frac{{\color{blue}{\sin ky}}^{2} \cdot \ell}{Om} \cdot 2, 1\right)}}\right)} \]
    10. Applied rewrites97.5%

      \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\mathsf{fma}\left(\frac{\ell \cdot 2}{Om}, \color{blue}{\frac{{\sin ky}^{2} \cdot \ell}{Om} \cdot 2}, 1\right)}}\right)} \]
    11. Step-by-step derivation
      1. Applied rewrites97.3%

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\mathsf{fma}\left(\frac{\ell \cdot 2}{Om}, \frac{\left(1 - \cos \left(ky \cdot 2\right)\right) \cdot \ell}{2 \cdot Om} \cdot 2, 1\right)}}\right)} \]

      if 9.99999999999999958e27 < (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))

      1. Initial program 96.0%

        \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
      2. Add Preprocessing
      3. Taylor expanded in l around inf

        \[\leadsto \sqrt{\color{blue}{\frac{1}{2}}} \]
      4. Step-by-step derivation
        1. Applied rewrites100.0%

          \[\leadsto \sqrt{\color{blue}{0.5}} \]
      5. Recombined 2 regimes into one program.
      6. Final simplification98.3%

        \[\leadsto \begin{array}{l} \mathbf{if}\;{\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right) \leq 10^{+28}:\\ \;\;\;\;\sqrt{{2}^{-1} \cdot \left(1 + {\left(\sqrt{\mathsf{fma}\left(\frac{\ell \cdot 2}{Om}, \frac{\left(1 - \cos \left(ky \cdot 2\right)\right) \cdot \ell}{2 \cdot Om} \cdot 2, 1\right)}\right)}^{-1}\right)}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{0.5}\\ \end{array} \]
      7. Add Preprocessing

      Alternative 2: 98.6% accurate, 0.6× speedup?

      \[\begin{array}{l} ky_m = \left|ky\right| \\ kx_m = \left|kx\right| \\ [l, Om, kx_m, ky_m] = \mathsf{sort}([l, Om, kx_m, ky_m])\\ \\ \sqrt{{2}^{-1} \cdot \left(1 + {\left({\left({\left(\mathsf{fma}\left(\mathsf{fma}\left(\sin ky\_m, \sin ky\_m, {\sin kx\_m}^{2}\right), {\left(\frac{-2 \cdot \ell}{Om}\right)}^{2}, 1\right)\right)}^{0.25}\right)}^{2}\right)}^{-1}\right)} \end{array} \]
      ky_m = (fabs.f64 ky)
      kx_m = (fabs.f64 kx)
      NOTE: l, Om, kx_m, and ky_m should be sorted in increasing order before calling this function.
      (FPCore (l Om kx_m ky_m)
       :precision binary64
       (sqrt
        (*
         (pow 2.0 -1.0)
         (+
          1.0
          (pow
           (pow
            (pow
             (fma
              (fma (sin ky_m) (sin ky_m) (pow (sin kx_m) 2.0))
              (pow (/ (* -2.0 l) Om) 2.0)
              1.0)
             0.25)
            2.0)
           -1.0)))))
      ky_m = fabs(ky);
      kx_m = fabs(kx);
      assert(l < Om && Om < kx_m && kx_m < ky_m);
      double code(double l, double Om, double kx_m, double ky_m) {
      	return sqrt((pow(2.0, -1.0) * (1.0 + pow(pow(pow(fma(fma(sin(ky_m), sin(ky_m), pow(sin(kx_m), 2.0)), pow(((-2.0 * l) / Om), 2.0), 1.0), 0.25), 2.0), -1.0))));
      }
      
      ky_m = abs(ky)
      kx_m = abs(kx)
      l, Om, kx_m, ky_m = sort([l, Om, kx_m, ky_m])
      function code(l, Om, kx_m, ky_m)
      	return sqrt(Float64((2.0 ^ -1.0) * Float64(1.0 + (((fma(fma(sin(ky_m), sin(ky_m), (sin(kx_m) ^ 2.0)), (Float64(Float64(-2.0 * l) / Om) ^ 2.0), 1.0) ^ 0.25) ^ 2.0) ^ -1.0))))
      end
      
      ky_m = N[Abs[ky], $MachinePrecision]
      kx_m = N[Abs[kx], $MachinePrecision]
      NOTE: l, Om, kx_m, and ky_m should be sorted in increasing order before calling this function.
      code[l_, Om_, kx$95$m_, ky$95$m_] := N[Sqrt[N[(N[Power[2.0, -1.0], $MachinePrecision] * N[(1.0 + N[Power[N[Power[N[Power[N[(N[(N[Sin[ky$95$m], $MachinePrecision] * N[Sin[ky$95$m], $MachinePrecision] + N[Power[N[Sin[kx$95$m], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision] * N[Power[N[(N[(-2.0 * l), $MachinePrecision] / Om), $MachinePrecision], 2.0], $MachinePrecision] + 1.0), $MachinePrecision], 0.25], $MachinePrecision], 2.0], $MachinePrecision], -1.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
      
      \begin{array}{l}
      ky_m = \left|ky\right|
      \\
      kx_m = \left|kx\right|
      \\
      [l, Om, kx_m, ky_m] = \mathsf{sort}([l, Om, kx_m, ky_m])\\
      \\
      \sqrt{{2}^{-1} \cdot \left(1 + {\left({\left({\left(\mathsf{fma}\left(\mathsf{fma}\left(\sin ky\_m, \sin ky\_m, {\sin kx\_m}^{2}\right), {\left(\frac{-2 \cdot \ell}{Om}\right)}^{2}, 1\right)\right)}^{0.25}\right)}^{2}\right)}^{-1}\right)}
      \end{array}
      
      Derivation
      1. Initial program 98.4%

        \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
      2. Add Preprocessing
      3. Step-by-step derivation
        1. lift-sqrt.f64N/A

          \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\color{blue}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}}\right)} \]
        2. pow1/2N/A

          \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\color{blue}{{\left(1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)\right)}^{\frac{1}{2}}}}\right)} \]
        3. metadata-evalN/A

          \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{{\left(1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)\right)}^{\color{blue}{\left(\frac{1}{2}\right)}}}\right)} \]
        4. lift-/.f64N/A

          \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{{\left(1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)\right)}^{\color{blue}{\left(\frac{1}{2}\right)}}}\right)} \]
        5. sqr-powN/A

          \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\color{blue}{{\left(1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)\right)}^{\left(\frac{\frac{1}{2}}{2}\right)} \cdot {\left(1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)\right)}^{\left(\frac{\frac{1}{2}}{2}\right)}}}\right)} \]
        6. pow2N/A

          \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\color{blue}{{\left({\left(1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)\right)}^{\left(\frac{\frac{1}{2}}{2}\right)}\right)}^{2}}}\right)} \]
        7. lower-pow.f64N/A

          \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\color{blue}{{\left({\left(1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)\right)}^{\left(\frac{\frac{1}{2}}{2}\right)}\right)}^{2}}}\right)} \]
      4. Applied rewrites98.4%

        \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\color{blue}{{\left({\left(\mathsf{fma}\left(\mathsf{fma}\left(\sin ky, \sin ky, {\sin kx}^{2}\right), {\left(\frac{-2 \cdot \ell}{Om}\right)}^{2}, 1\right)\right)}^{0.25}\right)}^{2}}}\right)} \]
      5. Final simplification98.4%

        \[\leadsto \sqrt{{2}^{-1} \cdot \left(1 + {\left({\left({\left(\mathsf{fma}\left(\mathsf{fma}\left(\sin ky, \sin ky, {\sin kx}^{2}\right), {\left(\frac{-2 \cdot \ell}{Om}\right)}^{2}, 1\right)\right)}^{0.25}\right)}^{2}\right)}^{-1}\right)} \]
      6. Add Preprocessing

      Alternative 3: 98.6% accurate, 0.8× speedup?

      \[\begin{array}{l} ky_m = \left|ky\right| \\ kx_m = \left|kx\right| \\ [l, Om, kx_m, ky_m] = \mathsf{sort}([l, Om, kx_m, ky_m])\\ \\ \sqrt{{2}^{-1} \cdot \left(1 + {\left(\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx\_m}^{2} + {\sin ky\_m}^{2}\right)}\right)}^{-1}\right)} \end{array} \]
      ky_m = (fabs.f64 ky)
      kx_m = (fabs.f64 kx)
      NOTE: l, Om, kx_m, and ky_m should be sorted in increasing order before calling this function.
      (FPCore (l Om kx_m ky_m)
       :precision binary64
       (sqrt
        (*
         (pow 2.0 -1.0)
         (+
          1.0
          (pow
           (sqrt
            (+
             1.0
             (*
              (pow (/ (* 2.0 l) Om) 2.0)
              (+ (pow (sin kx_m) 2.0) (pow (sin ky_m) 2.0)))))
           -1.0)))))
      ky_m = fabs(ky);
      kx_m = fabs(kx);
      assert(l < Om && Om < kx_m && kx_m < ky_m);
      double code(double l, double Om, double kx_m, double ky_m) {
      	return sqrt((pow(2.0, -1.0) * (1.0 + pow(sqrt((1.0 + (pow(((2.0 * l) / Om), 2.0) * (pow(sin(kx_m), 2.0) + pow(sin(ky_m), 2.0))))), -1.0))));
      }
      
      ky_m = abs(ky)
      kx_m = abs(kx)
      NOTE: l, Om, kx_m, and ky_m should be sorted in increasing order before calling this function.
      real(8) function code(l, om, kx_m, ky_m)
          real(8), intent (in) :: l
          real(8), intent (in) :: om
          real(8), intent (in) :: kx_m
          real(8), intent (in) :: ky_m
          code = sqrt(((2.0d0 ** (-1.0d0)) * (1.0d0 + (sqrt((1.0d0 + ((((2.0d0 * l) / om) ** 2.0d0) * ((sin(kx_m) ** 2.0d0) + (sin(ky_m) ** 2.0d0))))) ** (-1.0d0)))))
      end function
      
      ky_m = Math.abs(ky);
      kx_m = Math.abs(kx);
      assert l < Om && Om < kx_m && kx_m < ky_m;
      public static double code(double l, double Om, double kx_m, double ky_m) {
      	return Math.sqrt((Math.pow(2.0, -1.0) * (1.0 + Math.pow(Math.sqrt((1.0 + (Math.pow(((2.0 * l) / Om), 2.0) * (Math.pow(Math.sin(kx_m), 2.0) + Math.pow(Math.sin(ky_m), 2.0))))), -1.0))));
      }
      
      ky_m = math.fabs(ky)
      kx_m = math.fabs(kx)
      [l, Om, kx_m, ky_m] = sort([l, Om, kx_m, ky_m])
      def code(l, Om, kx_m, ky_m):
      	return math.sqrt((math.pow(2.0, -1.0) * (1.0 + math.pow(math.sqrt((1.0 + (math.pow(((2.0 * l) / Om), 2.0) * (math.pow(math.sin(kx_m), 2.0) + math.pow(math.sin(ky_m), 2.0))))), -1.0))))
      
      ky_m = abs(ky)
      kx_m = abs(kx)
      l, Om, kx_m, ky_m = sort([l, Om, kx_m, ky_m])
      function code(l, Om, kx_m, ky_m)
      	return sqrt(Float64((2.0 ^ -1.0) * Float64(1.0 + (sqrt(Float64(1.0 + Float64((Float64(Float64(2.0 * l) / Om) ^ 2.0) * Float64((sin(kx_m) ^ 2.0) + (sin(ky_m) ^ 2.0))))) ^ -1.0))))
      end
      
      ky_m = abs(ky);
      kx_m = abs(kx);
      l, Om, kx_m, ky_m = num2cell(sort([l, Om, kx_m, ky_m])){:}
      function tmp = code(l, Om, kx_m, ky_m)
      	tmp = sqrt(((2.0 ^ -1.0) * (1.0 + (sqrt((1.0 + ((((2.0 * l) / Om) ^ 2.0) * ((sin(kx_m) ^ 2.0) + (sin(ky_m) ^ 2.0))))) ^ -1.0))));
      end
      
      ky_m = N[Abs[ky], $MachinePrecision]
      kx_m = N[Abs[kx], $MachinePrecision]
      NOTE: l, Om, kx_m, and ky_m should be sorted in increasing order before calling this function.
      code[l_, Om_, kx$95$m_, ky$95$m_] := N[Sqrt[N[(N[Power[2.0, -1.0], $MachinePrecision] * N[(1.0 + N[Power[N[Sqrt[N[(1.0 + N[(N[Power[N[(N[(2.0 * l), $MachinePrecision] / Om), $MachinePrecision], 2.0], $MachinePrecision] * N[(N[Power[N[Sin[kx$95$m], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky$95$m], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision], -1.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
      
      \begin{array}{l}
      ky_m = \left|ky\right|
      \\
      kx_m = \left|kx\right|
      \\
      [l, Om, kx_m, ky_m] = \mathsf{sort}([l, Om, kx_m, ky_m])\\
      \\
      \sqrt{{2}^{-1} \cdot \left(1 + {\left(\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx\_m}^{2} + {\sin ky\_m}^{2}\right)}\right)}^{-1}\right)}
      \end{array}
      
      Derivation
      1. Initial program 98.4%

        \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
      2. Add Preprocessing
      3. Final simplification98.4%

        \[\leadsto \sqrt{{2}^{-1} \cdot \left(1 + {\left(\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}\right)}^{-1}\right)} \]
      4. Add Preprocessing

      Alternative 4: 98.2% accurate, 0.9× speedup?

      \[\begin{array}{l} ky_m = \left|ky\right| \\ kx_m = \left|kx\right| \\ [l, Om, kx_m, ky_m] = \mathsf{sort}([l, Om, kx_m, ky_m])\\ \\ \begin{array}{l} \mathbf{if}\;{\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx\_m}^{2} + {\sin ky\_m}^{2}\right) \leq 5 \cdot 10^{-9}:\\ \;\;\;\;\sqrt{1}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\frac{0.5}{\sin ky\_m \cdot \frac{\ell \cdot 2}{Om}} + 0.5}\\ \end{array} \end{array} \]
      ky_m = (fabs.f64 ky)
      kx_m = (fabs.f64 kx)
      NOTE: l, Om, kx_m, and ky_m should be sorted in increasing order before calling this function.
      (FPCore (l Om kx_m ky_m)
       :precision binary64
       (if (<=
            (*
             (pow (/ (* 2.0 l) Om) 2.0)
             (+ (pow (sin kx_m) 2.0) (pow (sin ky_m) 2.0)))
            5e-9)
         (sqrt 1.0)
         (sqrt (+ (/ 0.5 (* (sin ky_m) (/ (* l 2.0) Om))) 0.5))))
      ky_m = fabs(ky);
      kx_m = fabs(kx);
      assert(l < Om && Om < kx_m && kx_m < ky_m);
      double code(double l, double Om, double kx_m, double ky_m) {
      	double tmp;
      	if ((pow(((2.0 * l) / Om), 2.0) * (pow(sin(kx_m), 2.0) + pow(sin(ky_m), 2.0))) <= 5e-9) {
      		tmp = sqrt(1.0);
      	} else {
      		tmp = sqrt(((0.5 / (sin(ky_m) * ((l * 2.0) / Om))) + 0.5));
      	}
      	return tmp;
      }
      
      ky_m = abs(ky)
      kx_m = abs(kx)
      NOTE: l, Om, kx_m, and ky_m should be sorted in increasing order before calling this function.
      real(8) function code(l, om, kx_m, ky_m)
          real(8), intent (in) :: l
          real(8), intent (in) :: om
          real(8), intent (in) :: kx_m
          real(8), intent (in) :: ky_m
          real(8) :: tmp
          if (((((2.0d0 * l) / om) ** 2.0d0) * ((sin(kx_m) ** 2.0d0) + (sin(ky_m) ** 2.0d0))) <= 5d-9) then
              tmp = sqrt(1.0d0)
          else
              tmp = sqrt(((0.5d0 / (sin(ky_m) * ((l * 2.0d0) / om))) + 0.5d0))
          end if
          code = tmp
      end function
      
      ky_m = Math.abs(ky);
      kx_m = Math.abs(kx);
      assert l < Om && Om < kx_m && kx_m < ky_m;
      public static double code(double l, double Om, double kx_m, double ky_m) {
      	double tmp;
      	if ((Math.pow(((2.0 * l) / Om), 2.0) * (Math.pow(Math.sin(kx_m), 2.0) + Math.pow(Math.sin(ky_m), 2.0))) <= 5e-9) {
      		tmp = Math.sqrt(1.0);
      	} else {
      		tmp = Math.sqrt(((0.5 / (Math.sin(ky_m) * ((l * 2.0) / Om))) + 0.5));
      	}
      	return tmp;
      }
      
      ky_m = math.fabs(ky)
      kx_m = math.fabs(kx)
      [l, Om, kx_m, ky_m] = sort([l, Om, kx_m, ky_m])
      def code(l, Om, kx_m, ky_m):
      	tmp = 0
      	if (math.pow(((2.0 * l) / Om), 2.0) * (math.pow(math.sin(kx_m), 2.0) + math.pow(math.sin(ky_m), 2.0))) <= 5e-9:
      		tmp = math.sqrt(1.0)
      	else:
      		tmp = math.sqrt(((0.5 / (math.sin(ky_m) * ((l * 2.0) / Om))) + 0.5))
      	return tmp
      
      ky_m = abs(ky)
      kx_m = abs(kx)
      l, Om, kx_m, ky_m = sort([l, Om, kx_m, ky_m])
      function code(l, Om, kx_m, ky_m)
      	tmp = 0.0
      	if (Float64((Float64(Float64(2.0 * l) / Om) ^ 2.0) * Float64((sin(kx_m) ^ 2.0) + (sin(ky_m) ^ 2.0))) <= 5e-9)
      		tmp = sqrt(1.0);
      	else
      		tmp = sqrt(Float64(Float64(0.5 / Float64(sin(ky_m) * Float64(Float64(l * 2.0) / Om))) + 0.5));
      	end
      	return tmp
      end
      
      ky_m = abs(ky);
      kx_m = abs(kx);
      l, Om, kx_m, ky_m = num2cell(sort([l, Om, kx_m, ky_m])){:}
      function tmp_2 = code(l, Om, kx_m, ky_m)
      	tmp = 0.0;
      	if (((((2.0 * l) / Om) ^ 2.0) * ((sin(kx_m) ^ 2.0) + (sin(ky_m) ^ 2.0))) <= 5e-9)
      		tmp = sqrt(1.0);
      	else
      		tmp = sqrt(((0.5 / (sin(ky_m) * ((l * 2.0) / Om))) + 0.5));
      	end
      	tmp_2 = tmp;
      end
      
      ky_m = N[Abs[ky], $MachinePrecision]
      kx_m = N[Abs[kx], $MachinePrecision]
      NOTE: l, Om, kx_m, and ky_m should be sorted in increasing order before calling this function.
      code[l_, Om_, kx$95$m_, ky$95$m_] := If[LessEqual[N[(N[Power[N[(N[(2.0 * l), $MachinePrecision] / Om), $MachinePrecision], 2.0], $MachinePrecision] * N[(N[Power[N[Sin[kx$95$m], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky$95$m], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 5e-9], N[Sqrt[1.0], $MachinePrecision], N[Sqrt[N[(N[(0.5 / N[(N[Sin[ky$95$m], $MachinePrecision] * N[(N[(l * 2.0), $MachinePrecision] / Om), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + 0.5), $MachinePrecision]], $MachinePrecision]]
      
      \begin{array}{l}
      ky_m = \left|ky\right|
      \\
      kx_m = \left|kx\right|
      \\
      [l, Om, kx_m, ky_m] = \mathsf{sort}([l, Om, kx_m, ky_m])\\
      \\
      \begin{array}{l}
      \mathbf{if}\;{\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx\_m}^{2} + {\sin ky\_m}^{2}\right) \leq 5 \cdot 10^{-9}:\\
      \;\;\;\;\sqrt{1}\\
      
      \mathbf{else}:\\
      \;\;\;\;\sqrt{\frac{0.5}{\sin ky\_m \cdot \frac{\ell \cdot 2}{Om}} + 0.5}\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))) < 5.0000000000000001e-9

        1. Initial program 100.0%

          \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
        2. Add Preprocessing
        3. Taylor expanded in l around 0

          \[\leadsto \sqrt{\color{blue}{1}} \]
        4. Step-by-step derivation
          1. Applied rewrites99.8%

            \[\leadsto \sqrt{\color{blue}{1}} \]

          if 5.0000000000000001e-9 < (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))

          1. Initial program 96.2%

            \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
          2. Add Preprocessing
          3. Step-by-step derivation
            1. lift-sqrt.f64N/A

              \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\color{blue}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}}\right)} \]
            2. pow1/2N/A

              \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\color{blue}{{\left(1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)\right)}^{\frac{1}{2}}}}\right)} \]
            3. metadata-evalN/A

              \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{{\left(1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)\right)}^{\color{blue}{\left(\frac{1}{2}\right)}}}\right)} \]
            4. lift-/.f64N/A

              \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{{\left(1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)\right)}^{\color{blue}{\left(\frac{1}{2}\right)}}}\right)} \]
            5. sqr-powN/A

              \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\color{blue}{{\left(1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)\right)}^{\left(\frac{\frac{1}{2}}{2}\right)} \cdot {\left(1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)\right)}^{\left(\frac{\frac{1}{2}}{2}\right)}}}\right)} \]
            6. pow2N/A

              \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\color{blue}{{\left({\left(1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)\right)}^{\left(\frac{\frac{1}{2}}{2}\right)}\right)}^{2}}}\right)} \]
            7. lower-pow.f64N/A

              \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\color{blue}{{\left({\left(1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)\right)}^{\left(\frac{\frac{1}{2}}{2}\right)}\right)}^{2}}}\right)} \]
          4. Applied rewrites96.2%

            \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\color{blue}{{\left({\left(\mathsf{fma}\left(\mathsf{fma}\left(\sin ky, \sin ky, {\sin kx}^{2}\right), {\left(\frac{-2 \cdot \ell}{Om}\right)}^{2}, 1\right)\right)}^{0.25}\right)}^{2}}}\right)} \]
          5. Taylor expanded in l around inf

            \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\color{blue}{2 \cdot \left(\frac{\ell}{Om} \cdot \sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}}\right)} \]
          6. Step-by-step derivation
            1. associate-*r*N/A

              \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\color{blue}{\left(2 \cdot \frac{\ell}{Om}\right) \cdot \sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}\right)} \]
            2. lower-*.f64N/A

              \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\color{blue}{\left(2 \cdot \frac{\ell}{Om}\right) \cdot \sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}\right)} \]
            3. lower-*.f64N/A

              \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\color{blue}{\left(2 \cdot \frac{\ell}{Om}\right)} \cdot \sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}\right)} \]
            4. lower-/.f64N/A

              \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\left(2 \cdot \color{blue}{\frac{\ell}{Om}}\right) \cdot \sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}\right)} \]
            5. +-commutativeN/A

              \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\left(2 \cdot \frac{\ell}{Om}\right) \cdot \sqrt{\color{blue}{{\sin ky}^{2} + {\sin kx}^{2}}}}\right)} \]
            6. unpow2N/A

              \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\left(2 \cdot \frac{\ell}{Om}\right) \cdot \sqrt{\color{blue}{\sin ky \cdot \sin ky} + {\sin kx}^{2}}}\right)} \]
            7. unpow2N/A

              \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\left(2 \cdot \frac{\ell}{Om}\right) \cdot \sqrt{\sin ky \cdot \sin ky + \color{blue}{\sin kx \cdot \sin kx}}}\right)} \]
            8. lower-hypot.f64N/A

              \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\left(2 \cdot \frac{\ell}{Om}\right) \cdot \color{blue}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}\right)} \]
            9. lower-sin.f64N/A

              \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\left(2 \cdot \frac{\ell}{Om}\right) \cdot \mathsf{hypot}\left(\color{blue}{\sin ky}, \sin kx\right)}\right)} \]
            10. lower-sin.f6497.8

              \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\left(2 \cdot \frac{\ell}{Om}\right) \cdot \mathsf{hypot}\left(\sin ky, \color{blue}{\sin kx}\right)}\right)} \]
          7. Applied rewrites97.8%

            \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\color{blue}{\left(2 \cdot \frac{\ell}{Om}\right) \cdot \mathsf{hypot}\left(\sin ky, \sin kx\right)}}\right)} \]
          8. Step-by-step derivation
            1. lift-*.f64N/A

              \[\leadsto \sqrt{\color{blue}{\frac{1}{2} \cdot \left(1 + \frac{1}{\left(2 \cdot \frac{\ell}{Om}\right) \cdot \mathsf{hypot}\left(\sin ky, \sin kx\right)}\right)}} \]
            2. *-commutativeN/A

              \[\leadsto \sqrt{\color{blue}{\left(1 + \frac{1}{\left(2 \cdot \frac{\ell}{Om}\right) \cdot \mathsf{hypot}\left(\sin ky, \sin kx\right)}\right) \cdot \frac{1}{2}}} \]
            3. lift-+.f64N/A

              \[\leadsto \sqrt{\color{blue}{\left(1 + \frac{1}{\left(2 \cdot \frac{\ell}{Om}\right) \cdot \mathsf{hypot}\left(\sin ky, \sin kx\right)}\right)} \cdot \frac{1}{2}} \]
            4. +-commutativeN/A

              \[\leadsto \sqrt{\color{blue}{\left(\frac{1}{\left(2 \cdot \frac{\ell}{Om}\right) \cdot \mathsf{hypot}\left(\sin ky, \sin kx\right)} + 1\right)} \cdot \frac{1}{2}} \]
            5. distribute-rgt1-inN/A

              \[\leadsto \sqrt{\color{blue}{\frac{1}{2} + \frac{1}{\left(2 \cdot \frac{\ell}{Om}\right) \cdot \mathsf{hypot}\left(\sin ky, \sin kx\right)} \cdot \frac{1}{2}}} \]
            6. +-commutativeN/A

              \[\leadsto \sqrt{\color{blue}{\frac{1}{\left(2 \cdot \frac{\ell}{Om}\right) \cdot \mathsf{hypot}\left(\sin ky, \sin kx\right)} \cdot \frac{1}{2} + \frac{1}{2}}} \]
          9. Applied rewrites97.8%

            \[\leadsto \sqrt{\color{blue}{\frac{0.5}{\mathsf{hypot}\left(\sin kx, \sin ky\right) \cdot \frac{\ell \cdot 2}{Om}} + 0.5}} \]
          10. Taylor expanded in kx around 0

            \[\leadsto \sqrt{\frac{\frac{1}{2}}{\sin ky \cdot \frac{\color{blue}{\ell \cdot 2}}{Om}} + \frac{1}{2}} \]
          11. Step-by-step derivation
            1. Applied rewrites82.0%

              \[\leadsto \sqrt{\frac{0.5}{\sin ky \cdot \frac{\color{blue}{\ell \cdot 2}}{Om}} + 0.5} \]
          12. Recombined 2 regimes into one program.
          13. Add Preprocessing

          Alternative 5: 98.1% accurate, 1.1× speedup?

          \[\begin{array}{l} ky_m = \left|ky\right| \\ kx_m = \left|kx\right| \\ [l, Om, kx_m, ky_m] = \mathsf{sort}([l, Om, kx_m, ky_m])\\ \\ \begin{array}{l} \mathbf{if}\;{\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx\_m}^{2} + {\sin ky\_m}^{2}\right) \leq 5 \cdot 10^{-9}:\\ \;\;\;\;\sqrt{1}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{0.5}\\ \end{array} \end{array} \]
          ky_m = (fabs.f64 ky)
          kx_m = (fabs.f64 kx)
          NOTE: l, Om, kx_m, and ky_m should be sorted in increasing order before calling this function.
          (FPCore (l Om kx_m ky_m)
           :precision binary64
           (if (<=
                (*
                 (pow (/ (* 2.0 l) Om) 2.0)
                 (+ (pow (sin kx_m) 2.0) (pow (sin ky_m) 2.0)))
                5e-9)
             (sqrt 1.0)
             (sqrt 0.5)))
          ky_m = fabs(ky);
          kx_m = fabs(kx);
          assert(l < Om && Om < kx_m && kx_m < ky_m);
          double code(double l, double Om, double kx_m, double ky_m) {
          	double tmp;
          	if ((pow(((2.0 * l) / Om), 2.0) * (pow(sin(kx_m), 2.0) + pow(sin(ky_m), 2.0))) <= 5e-9) {
          		tmp = sqrt(1.0);
          	} else {
          		tmp = sqrt(0.5);
          	}
          	return tmp;
          }
          
          ky_m = abs(ky)
          kx_m = abs(kx)
          NOTE: l, Om, kx_m, and ky_m should be sorted in increasing order before calling this function.
          real(8) function code(l, om, kx_m, ky_m)
              real(8), intent (in) :: l
              real(8), intent (in) :: om
              real(8), intent (in) :: kx_m
              real(8), intent (in) :: ky_m
              real(8) :: tmp
              if (((((2.0d0 * l) / om) ** 2.0d0) * ((sin(kx_m) ** 2.0d0) + (sin(ky_m) ** 2.0d0))) <= 5d-9) then
                  tmp = sqrt(1.0d0)
              else
                  tmp = sqrt(0.5d0)
              end if
              code = tmp
          end function
          
          ky_m = Math.abs(ky);
          kx_m = Math.abs(kx);
          assert l < Om && Om < kx_m && kx_m < ky_m;
          public static double code(double l, double Om, double kx_m, double ky_m) {
          	double tmp;
          	if ((Math.pow(((2.0 * l) / Om), 2.0) * (Math.pow(Math.sin(kx_m), 2.0) + Math.pow(Math.sin(ky_m), 2.0))) <= 5e-9) {
          		tmp = Math.sqrt(1.0);
          	} else {
          		tmp = Math.sqrt(0.5);
          	}
          	return tmp;
          }
          
          ky_m = math.fabs(ky)
          kx_m = math.fabs(kx)
          [l, Om, kx_m, ky_m] = sort([l, Om, kx_m, ky_m])
          def code(l, Om, kx_m, ky_m):
          	tmp = 0
          	if (math.pow(((2.0 * l) / Om), 2.0) * (math.pow(math.sin(kx_m), 2.0) + math.pow(math.sin(ky_m), 2.0))) <= 5e-9:
          		tmp = math.sqrt(1.0)
          	else:
          		tmp = math.sqrt(0.5)
          	return tmp
          
          ky_m = abs(ky)
          kx_m = abs(kx)
          l, Om, kx_m, ky_m = sort([l, Om, kx_m, ky_m])
          function code(l, Om, kx_m, ky_m)
          	tmp = 0.0
          	if (Float64((Float64(Float64(2.0 * l) / Om) ^ 2.0) * Float64((sin(kx_m) ^ 2.0) + (sin(ky_m) ^ 2.0))) <= 5e-9)
          		tmp = sqrt(1.0);
          	else
          		tmp = sqrt(0.5);
          	end
          	return tmp
          end
          
          ky_m = abs(ky);
          kx_m = abs(kx);
          l, Om, kx_m, ky_m = num2cell(sort([l, Om, kx_m, ky_m])){:}
          function tmp_2 = code(l, Om, kx_m, ky_m)
          	tmp = 0.0;
          	if (((((2.0 * l) / Om) ^ 2.0) * ((sin(kx_m) ^ 2.0) + (sin(ky_m) ^ 2.0))) <= 5e-9)
          		tmp = sqrt(1.0);
          	else
          		tmp = sqrt(0.5);
          	end
          	tmp_2 = tmp;
          end
          
          ky_m = N[Abs[ky], $MachinePrecision]
          kx_m = N[Abs[kx], $MachinePrecision]
          NOTE: l, Om, kx_m, and ky_m should be sorted in increasing order before calling this function.
          code[l_, Om_, kx$95$m_, ky$95$m_] := If[LessEqual[N[(N[Power[N[(N[(2.0 * l), $MachinePrecision] / Om), $MachinePrecision], 2.0], $MachinePrecision] * N[(N[Power[N[Sin[kx$95$m], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky$95$m], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 5e-9], N[Sqrt[1.0], $MachinePrecision], N[Sqrt[0.5], $MachinePrecision]]
          
          \begin{array}{l}
          ky_m = \left|ky\right|
          \\
          kx_m = \left|kx\right|
          \\
          [l, Om, kx_m, ky_m] = \mathsf{sort}([l, Om, kx_m, ky_m])\\
          \\
          \begin{array}{l}
          \mathbf{if}\;{\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx\_m}^{2} + {\sin ky\_m}^{2}\right) \leq 5 \cdot 10^{-9}:\\
          \;\;\;\;\sqrt{1}\\
          
          \mathbf{else}:\\
          \;\;\;\;\sqrt{0.5}\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))) < 5.0000000000000001e-9

            1. Initial program 100.0%

              \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
            2. Add Preprocessing
            3. Taylor expanded in l around 0

              \[\leadsto \sqrt{\color{blue}{1}} \]
            4. Step-by-step derivation
              1. Applied rewrites99.8%

                \[\leadsto \sqrt{\color{blue}{1}} \]

              if 5.0000000000000001e-9 < (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))

              1. Initial program 96.2%

                \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
              2. Add Preprocessing
              3. Taylor expanded in l around inf

                \[\leadsto \sqrt{\color{blue}{\frac{1}{2}}} \]
              4. Step-by-step derivation
                1. Applied rewrites97.4%

                  \[\leadsto \sqrt{\color{blue}{0.5}} \]
              5. Recombined 2 regimes into one program.
              6. Add Preprocessing

              Alternative 6: 98.5% accurate, 1.2× speedup?

              \[\begin{array}{l} ky_m = \left|ky\right| \\ kx_m = \left|kx\right| \\ [l, Om, kx_m, ky_m] = \mathsf{sort}([l, Om, kx_m, ky_m])\\ \\ \sqrt{{2}^{-1} \cdot \left(1 + {\left(\sqrt{\mathsf{fma}\left(\frac{\ell \cdot 2}{Om}, \frac{{\sin ky\_m}^{2} \cdot \ell}{Om} \cdot 2, 1\right)}\right)}^{-1}\right)} \end{array} \]
              ky_m = (fabs.f64 ky)
              kx_m = (fabs.f64 kx)
              NOTE: l, Om, kx_m, and ky_m should be sorted in increasing order before calling this function.
              (FPCore (l Om kx_m ky_m)
               :precision binary64
               (sqrt
                (*
                 (pow 2.0 -1.0)
                 (+
                  1.0
                  (pow
                   (sqrt
                    (fma (/ (* l 2.0) Om) (* (/ (* (pow (sin ky_m) 2.0) l) Om) 2.0) 1.0))
                   -1.0)))))
              ky_m = fabs(ky);
              kx_m = fabs(kx);
              assert(l < Om && Om < kx_m && kx_m < ky_m);
              double code(double l, double Om, double kx_m, double ky_m) {
              	return sqrt((pow(2.0, -1.0) * (1.0 + pow(sqrt(fma(((l * 2.0) / Om), (((pow(sin(ky_m), 2.0) * l) / Om) * 2.0), 1.0)), -1.0))));
              }
              
              ky_m = abs(ky)
              kx_m = abs(kx)
              l, Om, kx_m, ky_m = sort([l, Om, kx_m, ky_m])
              function code(l, Om, kx_m, ky_m)
              	return sqrt(Float64((2.0 ^ -1.0) * Float64(1.0 + (sqrt(fma(Float64(Float64(l * 2.0) / Om), Float64(Float64(Float64((sin(ky_m) ^ 2.0) * l) / Om) * 2.0), 1.0)) ^ -1.0))))
              end
              
              ky_m = N[Abs[ky], $MachinePrecision]
              kx_m = N[Abs[kx], $MachinePrecision]
              NOTE: l, Om, kx_m, and ky_m should be sorted in increasing order before calling this function.
              code[l_, Om_, kx$95$m_, ky$95$m_] := N[Sqrt[N[(N[Power[2.0, -1.0], $MachinePrecision] * N[(1.0 + N[Power[N[Sqrt[N[(N[(N[(l * 2.0), $MachinePrecision] / Om), $MachinePrecision] * N[(N[(N[(N[Power[N[Sin[ky$95$m], $MachinePrecision], 2.0], $MachinePrecision] * l), $MachinePrecision] / Om), $MachinePrecision] * 2.0), $MachinePrecision] + 1.0), $MachinePrecision]], $MachinePrecision], -1.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
              
              \begin{array}{l}
              ky_m = \left|ky\right|
              \\
              kx_m = \left|kx\right|
              \\
              [l, Om, kx_m, ky_m] = \mathsf{sort}([l, Om, kx_m, ky_m])\\
              \\
              \sqrt{{2}^{-1} \cdot \left(1 + {\left(\sqrt{\mathsf{fma}\left(\frac{\ell \cdot 2}{Om}, \frac{{\sin ky\_m}^{2} \cdot \ell}{Om} \cdot 2, 1\right)}\right)}^{-1}\right)}
              \end{array}
              
              Derivation
              1. Initial program 98.4%

                \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
              2. Add Preprocessing
              3. Taylor expanded in ky around 0

                \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \color{blue}{{ky}^{2} \cdot \left(1 + {ky}^{2} \cdot \left(\frac{2}{45} \cdot {ky}^{2} - \frac{1}{3}\right)\right)}\right)}}\right)} \]
              4. Step-by-step derivation
                1. *-commutativeN/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \color{blue}{\left(1 + {ky}^{2} \cdot \left(\frac{2}{45} \cdot {ky}^{2} - \frac{1}{3}\right)\right) \cdot {ky}^{2}}\right)}}\right)} \]
                2. lower-*.f64N/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \color{blue}{\left(1 + {ky}^{2} \cdot \left(\frac{2}{45} \cdot {ky}^{2} - \frac{1}{3}\right)\right) \cdot {ky}^{2}}\right)}}\right)} \]
                3. +-commutativeN/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \color{blue}{\left({ky}^{2} \cdot \left(\frac{2}{45} \cdot {ky}^{2} - \frac{1}{3}\right) + 1\right)} \cdot {ky}^{2}\right)}}\right)} \]
                4. *-commutativeN/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \left(\color{blue}{\left(\frac{2}{45} \cdot {ky}^{2} - \frac{1}{3}\right) \cdot {ky}^{2}} + 1\right) \cdot {ky}^{2}\right)}}\right)} \]
                5. lower-fma.f64N/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \color{blue}{\mathsf{fma}\left(\frac{2}{45} \cdot {ky}^{2} - \frac{1}{3}, {ky}^{2}, 1\right)} \cdot {ky}^{2}\right)}}\right)} \]
                6. sub-negN/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\color{blue}{\frac{2}{45} \cdot {ky}^{2} + \left(\mathsf{neg}\left(\frac{1}{3}\right)\right)}, {ky}^{2}, 1\right) \cdot {ky}^{2}\right)}}\right)} \]
                7. metadata-evalN/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\frac{2}{45} \cdot {ky}^{2} + \color{blue}{\frac{-1}{3}}, {ky}^{2}, 1\right) \cdot {ky}^{2}\right)}}\right)} \]
                8. lower-fma.f64N/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(\frac{2}{45}, {ky}^{2}, \frac{-1}{3}\right)}, {ky}^{2}, 1\right) \cdot {ky}^{2}\right)}}\right)} \]
                9. unpow2N/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\mathsf{fma}\left(\frac{2}{45}, \color{blue}{ky \cdot ky}, \frac{-1}{3}\right), {ky}^{2}, 1\right) \cdot {ky}^{2}\right)}}\right)} \]
                10. lower-*.f64N/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\mathsf{fma}\left(\frac{2}{45}, \color{blue}{ky \cdot ky}, \frac{-1}{3}\right), {ky}^{2}, 1\right) \cdot {ky}^{2}\right)}}\right)} \]
                11. unpow2N/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\mathsf{fma}\left(\frac{2}{45}, ky \cdot ky, \frac{-1}{3}\right), \color{blue}{ky \cdot ky}, 1\right) \cdot {ky}^{2}\right)}}\right)} \]
                12. lower-*.f64N/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\mathsf{fma}\left(\frac{2}{45}, ky \cdot ky, \frac{-1}{3}\right), \color{blue}{ky \cdot ky}, 1\right) \cdot {ky}^{2}\right)}}\right)} \]
                13. unpow2N/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\mathsf{fma}\left(\frac{2}{45}, ky \cdot ky, \frac{-1}{3}\right), ky \cdot ky, 1\right) \cdot \color{blue}{\left(ky \cdot ky\right)}\right)}}\right)} \]
                14. lower-*.f6475.2

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\mathsf{fma}\left(0.044444444444444446, ky \cdot ky, -0.3333333333333333\right), ky \cdot ky, 1\right) \cdot \color{blue}{\left(ky \cdot ky\right)}\right)}}\right)} \]
              5. Applied rewrites75.2%

                \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(0.044444444444444446, ky \cdot ky, -0.3333333333333333\right), ky \cdot ky, 1\right) \cdot \left(ky \cdot ky\right)}\right)}}\right)} \]
              6. Step-by-step derivation
                1. lift-+.f64N/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\color{blue}{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\mathsf{fma}\left(\frac{2}{45}, ky \cdot ky, \frac{-1}{3}\right), ky \cdot ky, 1\right) \cdot \left(ky \cdot ky\right)\right)}}}\right)} \]
                2. +-commutativeN/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\color{blue}{{\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\mathsf{fma}\left(\frac{2}{45}, ky \cdot ky, \frac{-1}{3}\right), ky \cdot ky, 1\right) \cdot \left(ky \cdot ky\right)\right) + 1}}}\right)} \]
                3. lift-*.f64N/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\color{blue}{{\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\mathsf{fma}\left(\frac{2}{45}, ky \cdot ky, \frac{-1}{3}\right), ky \cdot ky, 1\right) \cdot \left(ky \cdot ky\right)\right)} + 1}}\right)} \]
                4. lift-pow.f64N/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\color{blue}{{\left(\frac{2 \cdot \ell}{Om}\right)}^{2}} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\mathsf{fma}\left(\frac{2}{45}, ky \cdot ky, \frac{-1}{3}\right), ky \cdot ky, 1\right) \cdot \left(ky \cdot ky\right)\right) + 1}}\right)} \]
                5. unpow2N/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\color{blue}{\left(\frac{2 \cdot \ell}{Om} \cdot \frac{2 \cdot \ell}{Om}\right)} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\mathsf{fma}\left(\frac{2}{45}, ky \cdot ky, \frac{-1}{3}\right), ky \cdot ky, 1\right) \cdot \left(ky \cdot ky\right)\right) + 1}}\right)} \]
                6. associate-*l*N/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\color{blue}{\frac{2 \cdot \ell}{Om} \cdot \left(\frac{2 \cdot \ell}{Om} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\mathsf{fma}\left(\frac{2}{45}, ky \cdot ky, \frac{-1}{3}\right), ky \cdot ky, 1\right) \cdot \left(ky \cdot ky\right)\right)\right)} + 1}}\right)} \]
                7. lower-fma.f64N/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\color{blue}{\mathsf{fma}\left(\frac{2 \cdot \ell}{Om}, \frac{2 \cdot \ell}{Om} \cdot \left({\sin kx}^{2} + \mathsf{fma}\left(\mathsf{fma}\left(\frac{2}{45}, ky \cdot ky, \frac{-1}{3}\right), ky \cdot ky, 1\right) \cdot \left(ky \cdot ky\right)\right), 1\right)}}}\right)} \]
              7. Applied rewrites76.9%

                \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\color{blue}{\mathsf{fma}\left(\frac{\ell \cdot 2}{Om}, \frac{\ell \cdot 2}{Om} \cdot \mathsf{fma}\left(\sin kx, \sin kx, \left(\mathsf{fma}\left(\mathsf{fma}\left(0.044444444444444446, ky \cdot ky, -0.3333333333333333\right), ky \cdot ky, 1\right) \cdot ky\right) \cdot ky\right), 1\right)}}}\right)} \]
              8. Taylor expanded in kx around 0

                \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\mathsf{fma}\left(\frac{\ell \cdot 2}{Om}, \color{blue}{2 \cdot \frac{\ell \cdot {\sin ky}^{2}}{Om}}, 1\right)}}\right)} \]
              9. Step-by-step derivation
                1. *-commutativeN/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\mathsf{fma}\left(\frac{\ell \cdot 2}{Om}, \color{blue}{\frac{\ell \cdot {\sin ky}^{2}}{Om} \cdot 2}, 1\right)}}\right)} \]
                2. lower-*.f64N/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\mathsf{fma}\left(\frac{\ell \cdot 2}{Om}, \color{blue}{\frac{\ell \cdot {\sin ky}^{2}}{Om} \cdot 2}, 1\right)}}\right)} \]
                3. lower-/.f64N/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\mathsf{fma}\left(\frac{\ell \cdot 2}{Om}, \color{blue}{\frac{\ell \cdot {\sin ky}^{2}}{Om}} \cdot 2, 1\right)}}\right)} \]
                4. *-commutativeN/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\mathsf{fma}\left(\frac{\ell \cdot 2}{Om}, \frac{\color{blue}{{\sin ky}^{2} \cdot \ell}}{Om} \cdot 2, 1\right)}}\right)} \]
                5. lower-*.f64N/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\mathsf{fma}\left(\frac{\ell \cdot 2}{Om}, \frac{\color{blue}{{\sin ky}^{2} \cdot \ell}}{Om} \cdot 2, 1\right)}}\right)} \]
                6. lower-pow.f64N/A

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\mathsf{fma}\left(\frac{\ell \cdot 2}{Om}, \frac{\color{blue}{{\sin ky}^{2}} \cdot \ell}{Om} \cdot 2, 1\right)}}\right)} \]
                7. lower-sin.f6490.0

                  \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\mathsf{fma}\left(\frac{\ell \cdot 2}{Om}, \frac{{\color{blue}{\sin ky}}^{2} \cdot \ell}{Om} \cdot 2, 1\right)}}\right)} \]
              10. Applied rewrites90.0%

                \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\mathsf{fma}\left(\frac{\ell \cdot 2}{Om}, \color{blue}{\frac{{\sin ky}^{2} \cdot \ell}{Om} \cdot 2}, 1\right)}}\right)} \]
              11. Final simplification90.0%

                \[\leadsto \sqrt{{2}^{-1} \cdot \left(1 + {\left(\sqrt{\mathsf{fma}\left(\frac{\ell \cdot 2}{Om}, \frac{{\sin ky}^{2} \cdot \ell}{Om} \cdot 2, 1\right)}\right)}^{-1}\right)} \]
              12. Add Preprocessing

              Alternative 7: 56.2% accurate, 52.8× speedup?

              \[\begin{array}{l} ky_m = \left|ky\right| \\ kx_m = \left|kx\right| \\ [l, Om, kx_m, ky_m] = \mathsf{sort}([l, Om, kx_m, ky_m])\\ \\ \sqrt{0.5} \end{array} \]
              ky_m = (fabs.f64 ky)
              kx_m = (fabs.f64 kx)
              NOTE: l, Om, kx_m, and ky_m should be sorted in increasing order before calling this function.
              (FPCore (l Om kx_m ky_m) :precision binary64 (sqrt 0.5))
              ky_m = fabs(ky);
              kx_m = fabs(kx);
              assert(l < Om && Om < kx_m && kx_m < ky_m);
              double code(double l, double Om, double kx_m, double ky_m) {
              	return sqrt(0.5);
              }
              
              ky_m = abs(ky)
              kx_m = abs(kx)
              NOTE: l, Om, kx_m, and ky_m should be sorted in increasing order before calling this function.
              real(8) function code(l, om, kx_m, ky_m)
                  real(8), intent (in) :: l
                  real(8), intent (in) :: om
                  real(8), intent (in) :: kx_m
                  real(8), intent (in) :: ky_m
                  code = sqrt(0.5d0)
              end function
              
              ky_m = Math.abs(ky);
              kx_m = Math.abs(kx);
              assert l < Om && Om < kx_m && kx_m < ky_m;
              public static double code(double l, double Om, double kx_m, double ky_m) {
              	return Math.sqrt(0.5);
              }
              
              ky_m = math.fabs(ky)
              kx_m = math.fabs(kx)
              [l, Om, kx_m, ky_m] = sort([l, Om, kx_m, ky_m])
              def code(l, Om, kx_m, ky_m):
              	return math.sqrt(0.5)
              
              ky_m = abs(ky)
              kx_m = abs(kx)
              l, Om, kx_m, ky_m = sort([l, Om, kx_m, ky_m])
              function code(l, Om, kx_m, ky_m)
              	return sqrt(0.5)
              end
              
              ky_m = abs(ky);
              kx_m = abs(kx);
              l, Om, kx_m, ky_m = num2cell(sort([l, Om, kx_m, ky_m])){:}
              function tmp = code(l, Om, kx_m, ky_m)
              	tmp = sqrt(0.5);
              end
              
              ky_m = N[Abs[ky], $MachinePrecision]
              kx_m = N[Abs[kx], $MachinePrecision]
              NOTE: l, Om, kx_m, and ky_m should be sorted in increasing order before calling this function.
              code[l_, Om_, kx$95$m_, ky$95$m_] := N[Sqrt[0.5], $MachinePrecision]
              
              \begin{array}{l}
              ky_m = \left|ky\right|
              \\
              kx_m = \left|kx\right|
              \\
              [l, Om, kx_m, ky_m] = \mathsf{sort}([l, Om, kx_m, ky_m])\\
              \\
              \sqrt{0.5}
              \end{array}
              
              Derivation
              1. Initial program 98.4%

                \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
              2. Add Preprocessing
              3. Taylor expanded in l around inf

                \[\leadsto \sqrt{\color{blue}{\frac{1}{2}}} \]
              4. Step-by-step derivation
                1. Applied rewrites51.7%

                  \[\leadsto \sqrt{\color{blue}{0.5}} \]
                2. Add Preprocessing

                Reproduce

                ?
                herbie shell --seed 2024305 
                (FPCore (l Om kx ky)
                  :name "Toniolo and Linder, Equation (3a)"
                  :precision binary64
                  (sqrt (* (/ 1.0 2.0) (+ 1.0 (/ 1.0 (sqrt (+ 1.0 (* (pow (/ (* 2.0 l) Om) 2.0) (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0))))))))))