expax (section 3.5)

Percentage Accurate: 54.6% → 100.0%
Time: 5.5s
Alternatives: 7
Speedup: 18.2×

Specification

?
\[710 > a \cdot x\]
\[\begin{array}{l} \\ e^{a \cdot x} - 1 \end{array} \]
(FPCore (a x) :precision binary64 (- (exp (* a x)) 1.0))
double code(double a, double x) {
	return exp((a * x)) - 1.0;
}
real(8) function code(a, x)
    real(8), intent (in) :: a
    real(8), intent (in) :: x
    code = exp((a * x)) - 1.0d0
end function
public static double code(double a, double x) {
	return Math.exp((a * x)) - 1.0;
}
def code(a, x):
	return math.exp((a * x)) - 1.0
function code(a, x)
	return Float64(exp(Float64(a * x)) - 1.0)
end
function tmp = code(a, x)
	tmp = exp((a * x)) - 1.0;
end
code[a_, x_] := N[(N[Exp[N[(a * x), $MachinePrecision]], $MachinePrecision] - 1.0), $MachinePrecision]
\begin{array}{l}

\\
e^{a \cdot x} - 1
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 7 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 54.6% accurate, 1.0× speedup?

\[\begin{array}{l} \\ e^{a \cdot x} - 1 \end{array} \]
(FPCore (a x) :precision binary64 (- (exp (* a x)) 1.0))
double code(double a, double x) {
	return exp((a * x)) - 1.0;
}
real(8) function code(a, x)
    real(8), intent (in) :: a
    real(8), intent (in) :: x
    code = exp((a * x)) - 1.0d0
end function
public static double code(double a, double x) {
	return Math.exp((a * x)) - 1.0;
}
def code(a, x):
	return math.exp((a * x)) - 1.0
function code(a, x)
	return Float64(exp(Float64(a * x)) - 1.0)
end
function tmp = code(a, x)
	tmp = exp((a * x)) - 1.0;
end
code[a_, x_] := N[(N[Exp[N[(a * x), $MachinePrecision]], $MachinePrecision] - 1.0), $MachinePrecision]
\begin{array}{l}

\\
e^{a \cdot x} - 1
\end{array}

Alternative 1: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \mathsf{expm1}\left(a \cdot x\right) \end{array} \]
(FPCore (a x) :precision binary64 (expm1 (* a x)))
double code(double a, double x) {
	return expm1((a * x));
}
public static double code(double a, double x) {
	return Math.expm1((a * x));
}
def code(a, x):
	return math.expm1((a * x))
function code(a, x)
	return expm1(Float64(a * x))
end
code[a_, x_] := N[(Exp[N[(a * x), $MachinePrecision]] - 1), $MachinePrecision]
\begin{array}{l}

\\
\mathsf{expm1}\left(a \cdot x\right)
\end{array}
Derivation
  1. Initial program 53.3%

    \[e^{a \cdot x} - 1 \]
  2. Add Preprocessing
  3. Step-by-step derivation
    1. lift--.f64N/A

      \[\leadsto \color{blue}{e^{a \cdot x} - 1} \]
    2. lift-exp.f64N/A

      \[\leadsto \color{blue}{e^{a \cdot x}} - 1 \]
    3. lower-expm1.f64100.0

      \[\leadsto \color{blue}{\mathsf{expm1}\left(a \cdot x\right)} \]
    4. lift-*.f64N/A

      \[\leadsto \mathsf{expm1}\left(\color{blue}{a \cdot x}\right) \]
    5. *-commutativeN/A

      \[\leadsto \mathsf{expm1}\left(\color{blue}{x \cdot a}\right) \]
    6. lower-*.f64100.0

      \[\leadsto \mathsf{expm1}\left(\color{blue}{x \cdot a}\right) \]
  4. Applied rewrites100.0%

    \[\leadsto \color{blue}{\mathsf{expm1}\left(x \cdot a\right)} \]
  5. Final simplification100.0%

    \[\leadsto \mathsf{expm1}\left(a \cdot x\right) \]
  6. Add Preprocessing

Alternative 2: 99.1% accurate, 2.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;a \cdot x \leq -1000:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(a, x, -1\right) \cdot x, a, 1\right)} - 1\\ \mathbf{else}:\\ \;\;\;\;\left(\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.041666666666666664 \cdot x, a, 0.16666666666666666\right), a \cdot x, 0.5\right) \cdot x, a, 1\right) \cdot a\right) \cdot x\\ \end{array} \end{array} \]
(FPCore (a x)
 :precision binary64
 (if (<= (* a x) -1000.0)
   (- (/ 1.0 (fma (* (fma a x -1.0) x) a 1.0)) 1.0)
   (*
    (*
     (fma
      (*
       (fma (fma (* 0.041666666666666664 x) a 0.16666666666666666) (* a x) 0.5)
       x)
      a
      1.0)
     a)
    x)))
double code(double a, double x) {
	double tmp;
	if ((a * x) <= -1000.0) {
		tmp = (1.0 / fma((fma(a, x, -1.0) * x), a, 1.0)) - 1.0;
	} else {
		tmp = (fma((fma(fma((0.041666666666666664 * x), a, 0.16666666666666666), (a * x), 0.5) * x), a, 1.0) * a) * x;
	}
	return tmp;
}
function code(a, x)
	tmp = 0.0
	if (Float64(a * x) <= -1000.0)
		tmp = Float64(Float64(1.0 / fma(Float64(fma(a, x, -1.0) * x), a, 1.0)) - 1.0);
	else
		tmp = Float64(Float64(fma(Float64(fma(fma(Float64(0.041666666666666664 * x), a, 0.16666666666666666), Float64(a * x), 0.5) * x), a, 1.0) * a) * x);
	end
	return tmp
end
code[a_, x_] := If[LessEqual[N[(a * x), $MachinePrecision], -1000.0], N[(N[(1.0 / N[(N[(N[(a * x + -1.0), $MachinePrecision] * x), $MachinePrecision] * a + 1.0), $MachinePrecision]), $MachinePrecision] - 1.0), $MachinePrecision], N[(N[(N[(N[(N[(N[(N[(0.041666666666666664 * x), $MachinePrecision] * a + 0.16666666666666666), $MachinePrecision] * N[(a * x), $MachinePrecision] + 0.5), $MachinePrecision] * x), $MachinePrecision] * a + 1.0), $MachinePrecision] * a), $MachinePrecision] * x), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;a \cdot x \leq -1000:\\
\;\;\;\;\frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(a, x, -1\right) \cdot x, a, 1\right)} - 1\\

\mathbf{else}:\\
\;\;\;\;\left(\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.041666666666666664 \cdot x, a, 0.16666666666666666\right), a \cdot x, 0.5\right) \cdot x, a, 1\right) \cdot a\right) \cdot x\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (*.f64 a x) < -1e3

    1. Initial program 100.0%

      \[e^{a \cdot x} - 1 \]
    2. Add Preprocessing
    3. Taylor expanded in a around 0

      \[\leadsto \color{blue}{\left(1 + a \cdot x\right)} - 1 \]
    4. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto \color{blue}{\left(a \cdot x + 1\right)} - 1 \]
      2. *-commutativeN/A

        \[\leadsto \left(\color{blue}{x \cdot a} + 1\right) - 1 \]
      3. lower-fma.f644.9

        \[\leadsto \color{blue}{\mathsf{fma}\left(x, a, 1\right)} - 1 \]
    5. Applied rewrites4.9%

      \[\leadsto \color{blue}{\mathsf{fma}\left(x, a, 1\right)} - 1 \]
    6. Step-by-step derivation
      1. Applied rewrites4.9%

        \[\leadsto \frac{1}{\color{blue}{\frac{1}{\mathsf{fma}\left(a, x, 1\right)}}} - 1 \]
      2. Taylor expanded in a around 0

        \[\leadsto \frac{1}{1 + \color{blue}{a \cdot \left(a \cdot {x}^{2} - x\right)}} - 1 \]
      3. Step-by-step derivation
        1. Applied rewrites99.5%

          \[\leadsto \frac{1}{\mathsf{fma}\left(x \cdot \mathsf{fma}\left(a, x, -1\right), \color{blue}{a}, 1\right)} - 1 \]

        if -1e3 < (*.f64 a x)

        1. Initial program 26.7%

          \[e^{a \cdot x} - 1 \]
        2. Add Preprocessing
        3. Taylor expanded in a around 0

          \[\leadsto \color{blue}{a \cdot \left(x + a \cdot \left(\frac{1}{2} \cdot {x}^{2} + a \cdot \left(\frac{1}{24} \cdot \left(a \cdot {x}^{4}\right) + \frac{1}{6} \cdot {x}^{3}\right)\right)\right)} \]
        4. Applied rewrites99.7%

          \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.041666666666666664 \cdot x, a, 0.16666666666666666\right), x \cdot a, 0.5\right) \cdot x, a, 1\right) \cdot \left(x \cdot a\right)} \]
        5. Step-by-step derivation
          1. Applied rewrites99.7%

            \[\leadsto \color{blue}{\left(\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.041666666666666664 \cdot x, a, 0.16666666666666666\right), a \cdot x, 0.5\right) \cdot x, a, 1\right) \cdot a\right) \cdot x} \]
        6. Recombined 2 regimes into one program.
        7. Final simplification99.6%

          \[\leadsto \begin{array}{l} \mathbf{if}\;a \cdot x \leq -1000:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(a, x, -1\right) \cdot x, a, 1\right)} - 1\\ \mathbf{else}:\\ \;\;\;\;\left(\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.041666666666666664 \cdot x, a, 0.16666666666666666\right), a \cdot x, 0.5\right) \cdot x, a, 1\right) \cdot a\right) \cdot x\\ \end{array} \]
        8. Add Preprocessing

        Alternative 3: 99.0% accurate, 2.5× speedup?

        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;a \cdot x \leq -1000:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(a, x, -1\right) \cdot x, a, 1\right)} - 1\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666 \cdot x, a, 0.5\right) \cdot a, x, 1\right) \cdot \left(a \cdot x\right)\\ \end{array} \end{array} \]
        (FPCore (a x)
         :precision binary64
         (if (<= (* a x) -1000.0)
           (- (/ 1.0 (fma (* (fma a x -1.0) x) a 1.0)) 1.0)
           (* (fma (* (fma (* 0.16666666666666666 x) a 0.5) a) x 1.0) (* a x))))
        double code(double a, double x) {
        	double tmp;
        	if ((a * x) <= -1000.0) {
        		tmp = (1.0 / fma((fma(a, x, -1.0) * x), a, 1.0)) - 1.0;
        	} else {
        		tmp = fma((fma((0.16666666666666666 * x), a, 0.5) * a), x, 1.0) * (a * x);
        	}
        	return tmp;
        }
        
        function code(a, x)
        	tmp = 0.0
        	if (Float64(a * x) <= -1000.0)
        		tmp = Float64(Float64(1.0 / fma(Float64(fma(a, x, -1.0) * x), a, 1.0)) - 1.0);
        	else
        		tmp = Float64(fma(Float64(fma(Float64(0.16666666666666666 * x), a, 0.5) * a), x, 1.0) * Float64(a * x));
        	end
        	return tmp
        end
        
        code[a_, x_] := If[LessEqual[N[(a * x), $MachinePrecision], -1000.0], N[(N[(1.0 / N[(N[(N[(a * x + -1.0), $MachinePrecision] * x), $MachinePrecision] * a + 1.0), $MachinePrecision]), $MachinePrecision] - 1.0), $MachinePrecision], N[(N[(N[(N[(N[(0.16666666666666666 * x), $MachinePrecision] * a + 0.5), $MachinePrecision] * a), $MachinePrecision] * x + 1.0), $MachinePrecision] * N[(a * x), $MachinePrecision]), $MachinePrecision]]
        
        \begin{array}{l}
        
        \\
        \begin{array}{l}
        \mathbf{if}\;a \cdot x \leq -1000:\\
        \;\;\;\;\frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(a, x, -1\right) \cdot x, a, 1\right)} - 1\\
        
        \mathbf{else}:\\
        \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666 \cdot x, a, 0.5\right) \cdot a, x, 1\right) \cdot \left(a \cdot x\right)\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 2 regimes
        2. if (*.f64 a x) < -1e3

          1. Initial program 100.0%

            \[e^{a \cdot x} - 1 \]
          2. Add Preprocessing
          3. Taylor expanded in a around 0

            \[\leadsto \color{blue}{\left(1 + a \cdot x\right)} - 1 \]
          4. Step-by-step derivation
            1. +-commutativeN/A

              \[\leadsto \color{blue}{\left(a \cdot x + 1\right)} - 1 \]
            2. *-commutativeN/A

              \[\leadsto \left(\color{blue}{x \cdot a} + 1\right) - 1 \]
            3. lower-fma.f644.9

              \[\leadsto \color{blue}{\mathsf{fma}\left(x, a, 1\right)} - 1 \]
          5. Applied rewrites4.9%

            \[\leadsto \color{blue}{\mathsf{fma}\left(x, a, 1\right)} - 1 \]
          6. Step-by-step derivation
            1. Applied rewrites4.9%

              \[\leadsto \frac{1}{\color{blue}{\frac{1}{\mathsf{fma}\left(a, x, 1\right)}}} - 1 \]
            2. Taylor expanded in a around 0

              \[\leadsto \frac{1}{1 + \color{blue}{a \cdot \left(a \cdot {x}^{2} - x\right)}} - 1 \]
            3. Step-by-step derivation
              1. Applied rewrites99.5%

                \[\leadsto \frac{1}{\mathsf{fma}\left(x \cdot \mathsf{fma}\left(a, x, -1\right), \color{blue}{a}, 1\right)} - 1 \]

              if -1e3 < (*.f64 a x)

              1. Initial program 26.7%

                \[e^{a \cdot x} - 1 \]
              2. Add Preprocessing
              3. Taylor expanded in a around 0

                \[\leadsto \color{blue}{a \cdot \left(x + a \cdot \left(\frac{1}{6} \cdot \left(a \cdot {x}^{3}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right)} \]
              4. Applied rewrites99.5%

                \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666 \cdot x, a, 0.5\right) \cdot a, x, 1\right) \cdot \left(x \cdot a\right)} \]
            4. Recombined 2 regimes into one program.
            5. Final simplification99.5%

              \[\leadsto \begin{array}{l} \mathbf{if}\;a \cdot x \leq -1000:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(a, x, -1\right) \cdot x, a, 1\right)} - 1\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666 \cdot x, a, 0.5\right) \cdot a, x, 1\right) \cdot \left(a \cdot x\right)\\ \end{array} \]
            6. Add Preprocessing

            Alternative 4: 98.7% accurate, 2.5× speedup?

            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;a \cdot x \leq -1000:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(a, x, -1\right) \cdot x, a, 1\right)} - 1\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(0.5 \cdot a, x, 1\right) \cdot \left(a \cdot x\right)\\ \end{array} \end{array} \]
            (FPCore (a x)
             :precision binary64
             (if (<= (* a x) -1000.0)
               (- (/ 1.0 (fma (* (fma a x -1.0) x) a 1.0)) 1.0)
               (* (fma (* 0.5 a) x 1.0) (* a x))))
            double code(double a, double x) {
            	double tmp;
            	if ((a * x) <= -1000.0) {
            		tmp = (1.0 / fma((fma(a, x, -1.0) * x), a, 1.0)) - 1.0;
            	} else {
            		tmp = fma((0.5 * a), x, 1.0) * (a * x);
            	}
            	return tmp;
            }
            
            function code(a, x)
            	tmp = 0.0
            	if (Float64(a * x) <= -1000.0)
            		tmp = Float64(Float64(1.0 / fma(Float64(fma(a, x, -1.0) * x), a, 1.0)) - 1.0);
            	else
            		tmp = Float64(fma(Float64(0.5 * a), x, 1.0) * Float64(a * x));
            	end
            	return tmp
            end
            
            code[a_, x_] := If[LessEqual[N[(a * x), $MachinePrecision], -1000.0], N[(N[(1.0 / N[(N[(N[(a * x + -1.0), $MachinePrecision] * x), $MachinePrecision] * a + 1.0), $MachinePrecision]), $MachinePrecision] - 1.0), $MachinePrecision], N[(N[(N[(0.5 * a), $MachinePrecision] * x + 1.0), $MachinePrecision] * N[(a * x), $MachinePrecision]), $MachinePrecision]]
            
            \begin{array}{l}
            
            \\
            \begin{array}{l}
            \mathbf{if}\;a \cdot x \leq -1000:\\
            \;\;\;\;\frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(a, x, -1\right) \cdot x, a, 1\right)} - 1\\
            
            \mathbf{else}:\\
            \;\;\;\;\mathsf{fma}\left(0.5 \cdot a, x, 1\right) \cdot \left(a \cdot x\right)\\
            
            
            \end{array}
            \end{array}
            
            Derivation
            1. Split input into 2 regimes
            2. if (*.f64 a x) < -1e3

              1. Initial program 100.0%

                \[e^{a \cdot x} - 1 \]
              2. Add Preprocessing
              3. Taylor expanded in a around 0

                \[\leadsto \color{blue}{\left(1 + a \cdot x\right)} - 1 \]
              4. Step-by-step derivation
                1. +-commutativeN/A

                  \[\leadsto \color{blue}{\left(a \cdot x + 1\right)} - 1 \]
                2. *-commutativeN/A

                  \[\leadsto \left(\color{blue}{x \cdot a} + 1\right) - 1 \]
                3. lower-fma.f644.9

                  \[\leadsto \color{blue}{\mathsf{fma}\left(x, a, 1\right)} - 1 \]
              5. Applied rewrites4.9%

                \[\leadsto \color{blue}{\mathsf{fma}\left(x, a, 1\right)} - 1 \]
              6. Step-by-step derivation
                1. Applied rewrites4.9%

                  \[\leadsto \frac{1}{\color{blue}{\frac{1}{\mathsf{fma}\left(a, x, 1\right)}}} - 1 \]
                2. Taylor expanded in a around 0

                  \[\leadsto \frac{1}{1 + \color{blue}{a \cdot \left(a \cdot {x}^{2} - x\right)}} - 1 \]
                3. Step-by-step derivation
                  1. Applied rewrites99.5%

                    \[\leadsto \frac{1}{\mathsf{fma}\left(x \cdot \mathsf{fma}\left(a, x, -1\right), \color{blue}{a}, 1\right)} - 1 \]

                  if -1e3 < (*.f64 a x)

                  1. Initial program 26.7%

                    \[e^{a \cdot x} - 1 \]
                  2. Add Preprocessing
                  3. Taylor expanded in a around 0

                    \[\leadsto \color{blue}{a \cdot \left(x + a \cdot \left(\frac{1}{6} \cdot \left(a \cdot {x}^{3}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right)} \]
                  4. Applied rewrites99.5%

                    \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666 \cdot x, a, 0.5\right) \cdot a, x, 1\right) \cdot \left(x \cdot a\right)} \]
                  5. Taylor expanded in a around 0

                    \[\leadsto \mathsf{fma}\left(\frac{1}{2} \cdot a, x, 1\right) \cdot \left(x \cdot a\right) \]
                  6. Step-by-step derivation
                    1. Applied rewrites99.2%

                      \[\leadsto \mathsf{fma}\left(0.5 \cdot a, x, 1\right) \cdot \left(x \cdot a\right) \]
                  7. Recombined 2 regimes into one program.
                  8. Final simplification99.3%

                    \[\leadsto \begin{array}{l} \mathbf{if}\;a \cdot x \leq -1000:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(a, x, -1\right) \cdot x, a, 1\right)} - 1\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(0.5 \cdot a, x, 1\right) \cdot \left(a \cdot x\right)\\ \end{array} \]
                  9. Add Preprocessing

                  Alternative 5: 98.4% accurate, 3.2× speedup?

                  \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;a \cdot x \leq -1000:\\ \;\;\;\;\frac{1}{1 - a \cdot x} - 1\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(0.5 \cdot a, x, 1\right) \cdot \left(a \cdot x\right)\\ \end{array} \end{array} \]
                  (FPCore (a x)
                   :precision binary64
                   (if (<= (* a x) -1000.0)
                     (- (/ 1.0 (- 1.0 (* a x))) 1.0)
                     (* (fma (* 0.5 a) x 1.0) (* a x))))
                  double code(double a, double x) {
                  	double tmp;
                  	if ((a * x) <= -1000.0) {
                  		tmp = (1.0 / (1.0 - (a * x))) - 1.0;
                  	} else {
                  		tmp = fma((0.5 * a), x, 1.0) * (a * x);
                  	}
                  	return tmp;
                  }
                  
                  function code(a, x)
                  	tmp = 0.0
                  	if (Float64(a * x) <= -1000.0)
                  		tmp = Float64(Float64(1.0 / Float64(1.0 - Float64(a * x))) - 1.0);
                  	else
                  		tmp = Float64(fma(Float64(0.5 * a), x, 1.0) * Float64(a * x));
                  	end
                  	return tmp
                  end
                  
                  code[a_, x_] := If[LessEqual[N[(a * x), $MachinePrecision], -1000.0], N[(N[(1.0 / N[(1.0 - N[(a * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - 1.0), $MachinePrecision], N[(N[(N[(0.5 * a), $MachinePrecision] * x + 1.0), $MachinePrecision] * N[(a * x), $MachinePrecision]), $MachinePrecision]]
                  
                  \begin{array}{l}
                  
                  \\
                  \begin{array}{l}
                  \mathbf{if}\;a \cdot x \leq -1000:\\
                  \;\;\;\;\frac{1}{1 - a \cdot x} - 1\\
                  
                  \mathbf{else}:\\
                  \;\;\;\;\mathsf{fma}\left(0.5 \cdot a, x, 1\right) \cdot \left(a \cdot x\right)\\
                  
                  
                  \end{array}
                  \end{array}
                  
                  Derivation
                  1. Split input into 2 regimes
                  2. if (*.f64 a x) < -1e3

                    1. Initial program 100.0%

                      \[e^{a \cdot x} - 1 \]
                    2. Add Preprocessing
                    3. Taylor expanded in a around 0

                      \[\leadsto \color{blue}{\left(1 + a \cdot x\right)} - 1 \]
                    4. Step-by-step derivation
                      1. +-commutativeN/A

                        \[\leadsto \color{blue}{\left(a \cdot x + 1\right)} - 1 \]
                      2. *-commutativeN/A

                        \[\leadsto \left(\color{blue}{x \cdot a} + 1\right) - 1 \]
                      3. lower-fma.f644.9

                        \[\leadsto \color{blue}{\mathsf{fma}\left(x, a, 1\right)} - 1 \]
                    5. Applied rewrites4.9%

                      \[\leadsto \color{blue}{\mathsf{fma}\left(x, a, 1\right)} - 1 \]
                    6. Step-by-step derivation
                      1. Applied rewrites4.9%

                        \[\leadsto \frac{1}{\color{blue}{\frac{1}{\mathsf{fma}\left(a, x, 1\right)}}} - 1 \]
                      2. Taylor expanded in a around 0

                        \[\leadsto \frac{1}{1 + \color{blue}{-1 \cdot \left(a \cdot x\right)}} - 1 \]
                      3. Step-by-step derivation
                        1. Applied rewrites98.0%

                          \[\leadsto \frac{1}{1 - \color{blue}{a \cdot x}} - 1 \]

                        if -1e3 < (*.f64 a x)

                        1. Initial program 26.7%

                          \[e^{a \cdot x} - 1 \]
                        2. Add Preprocessing
                        3. Taylor expanded in a around 0

                          \[\leadsto \color{blue}{a \cdot \left(x + a \cdot \left(\frac{1}{6} \cdot \left(a \cdot {x}^{3}\right) + \frac{1}{2} \cdot {x}^{2}\right)\right)} \]
                        4. Applied rewrites99.5%

                          \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666 \cdot x, a, 0.5\right) \cdot a, x, 1\right) \cdot \left(x \cdot a\right)} \]
                        5. Taylor expanded in a around 0

                          \[\leadsto \mathsf{fma}\left(\frac{1}{2} \cdot a, x, 1\right) \cdot \left(x \cdot a\right) \]
                        6. Step-by-step derivation
                          1. Applied rewrites99.2%

                            \[\leadsto \mathsf{fma}\left(0.5 \cdot a, x, 1\right) \cdot \left(x \cdot a\right) \]
                        7. Recombined 2 regimes into one program.
                        8. Final simplification98.8%

                          \[\leadsto \begin{array}{l} \mathbf{if}\;a \cdot x \leq -1000:\\ \;\;\;\;\frac{1}{1 - a \cdot x} - 1\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(0.5 \cdot a, x, 1\right) \cdot \left(a \cdot x\right)\\ \end{array} \]
                        9. Add Preprocessing

                        Alternative 6: 66.8% accurate, 18.2× speedup?

                        \[\begin{array}{l} \\ a \cdot x \end{array} \]
                        (FPCore (a x) :precision binary64 (* a x))
                        double code(double a, double x) {
                        	return a * x;
                        }
                        
                        real(8) function code(a, x)
                            real(8), intent (in) :: a
                            real(8), intent (in) :: x
                            code = a * x
                        end function
                        
                        public static double code(double a, double x) {
                        	return a * x;
                        }
                        
                        def code(a, x):
                        	return a * x
                        
                        function code(a, x)
                        	return Float64(a * x)
                        end
                        
                        function tmp = code(a, x)
                        	tmp = a * x;
                        end
                        
                        code[a_, x_] := N[(a * x), $MachinePrecision]
                        
                        \begin{array}{l}
                        
                        \\
                        a \cdot x
                        \end{array}
                        
                        Derivation
                        1. Initial program 53.3%

                          \[e^{a \cdot x} - 1 \]
                        2. Add Preprocessing
                        3. Taylor expanded in a around 0

                          \[\leadsto \color{blue}{a \cdot x} \]
                        4. Step-by-step derivation
                          1. *-commutativeN/A

                            \[\leadsto \color{blue}{x \cdot a} \]
                          2. lower-*.f6464.2

                            \[\leadsto \color{blue}{x \cdot a} \]
                        5. Applied rewrites64.2%

                          \[\leadsto \color{blue}{x \cdot a} \]
                        6. Final simplification64.2%

                          \[\leadsto a \cdot x \]
                        7. Add Preprocessing

                        Alternative 7: 20.1% accurate, 27.3× speedup?

                        \[\begin{array}{l} \\ 1 - 1 \end{array} \]
                        (FPCore (a x) :precision binary64 (- 1.0 1.0))
                        double code(double a, double x) {
                        	return 1.0 - 1.0;
                        }
                        
                        real(8) function code(a, x)
                            real(8), intent (in) :: a
                            real(8), intent (in) :: x
                            code = 1.0d0 - 1.0d0
                        end function
                        
                        public static double code(double a, double x) {
                        	return 1.0 - 1.0;
                        }
                        
                        def code(a, x):
                        	return 1.0 - 1.0
                        
                        function code(a, x)
                        	return Float64(1.0 - 1.0)
                        end
                        
                        function tmp = code(a, x)
                        	tmp = 1.0 - 1.0;
                        end
                        
                        code[a_, x_] := N[(1.0 - 1.0), $MachinePrecision]
                        
                        \begin{array}{l}
                        
                        \\
                        1 - 1
                        \end{array}
                        
                        Derivation
                        1. Initial program 53.3%

                          \[e^{a \cdot x} - 1 \]
                        2. Add Preprocessing
                        3. Taylor expanded in a around 0

                          \[\leadsto \color{blue}{1} - 1 \]
                        4. Step-by-step derivation
                          1. Applied rewrites16.2%

                            \[\leadsto \color{blue}{1} - 1 \]
                          2. Add Preprocessing

                          Developer Target 1: 100.0% accurate, 1.0× speedup?

                          \[\begin{array}{l} \\ \mathsf{expm1}\left(a \cdot x\right) \end{array} \]
                          (FPCore (a x) :precision binary64 (expm1 (* a x)))
                          double code(double a, double x) {
                          	return expm1((a * x));
                          }
                          
                          public static double code(double a, double x) {
                          	return Math.expm1((a * x));
                          }
                          
                          def code(a, x):
                          	return math.expm1((a * x))
                          
                          function code(a, x)
                          	return expm1(Float64(a * x))
                          end
                          
                          code[a_, x_] := N[(Exp[N[(a * x), $MachinePrecision]] - 1), $MachinePrecision]
                          
                          \begin{array}{l}
                          
                          \\
                          \mathsf{expm1}\left(a \cdot x\right)
                          \end{array}
                          

                          Reproduce

                          ?
                          herbie shell --seed 2024304 
                          (FPCore (a x)
                            :name "expax (section 3.5)"
                            :precision binary64
                            :pre (> 710.0 (* a x))
                          
                            :alt
                            (! :herbie-platform default (expm1 (* a x)))
                          
                            (- (exp (* a x)) 1.0))