Toniolo and Linder, Equation (3b), real

Percentage Accurate: 93.8% → 99.7%
Time: 10.6s
Alternatives: 17
Speedup: 1.2×

Specification

?
\[\begin{array}{l} \\ \frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \end{array} \]
(FPCore (kx ky th)
 :precision binary64
 (* (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0)))) (sin th)))
double code(double kx, double ky, double th) {
	return (sin(ky) / sqrt((pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))) * sin(th);
}
real(8) function code(kx, ky, th)
    real(8), intent (in) :: kx
    real(8), intent (in) :: ky
    real(8), intent (in) :: th
    code = (sin(ky) / sqrt(((sin(kx) ** 2.0d0) + (sin(ky) ** 2.0d0)))) * sin(th)
end function
public static double code(double kx, double ky, double th) {
	return (Math.sin(ky) / Math.sqrt((Math.pow(Math.sin(kx), 2.0) + Math.pow(Math.sin(ky), 2.0)))) * Math.sin(th);
}
def code(kx, ky, th):
	return (math.sin(ky) / math.sqrt((math.pow(math.sin(kx), 2.0) + math.pow(math.sin(ky), 2.0)))) * math.sin(th)
function code(kx, ky, th)
	return Float64(Float64(sin(ky) / sqrt(Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) * sin(th))
end
function tmp = code(kx, ky, th)
	tmp = (sin(ky) / sqrt(((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) * sin(th);
end
code[kx_, ky_, th_] := N[(N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 17 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 93.8% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \end{array} \]
(FPCore (kx ky th)
 :precision binary64
 (* (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0)))) (sin th)))
double code(double kx, double ky, double th) {
	return (sin(ky) / sqrt((pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))) * sin(th);
}
real(8) function code(kx, ky, th)
    real(8), intent (in) :: kx
    real(8), intent (in) :: ky
    real(8), intent (in) :: th
    code = (sin(ky) / sqrt(((sin(kx) ** 2.0d0) + (sin(ky) ** 2.0d0)))) * sin(th)
end function
public static double code(double kx, double ky, double th) {
	return (Math.sin(ky) / Math.sqrt((Math.pow(Math.sin(kx), 2.0) + Math.pow(Math.sin(ky), 2.0)))) * Math.sin(th);
}
def code(kx, ky, th):
	return (math.sin(ky) / math.sqrt((math.pow(math.sin(kx), 2.0) + math.pow(math.sin(ky), 2.0)))) * math.sin(th)
function code(kx, ky, th)
	return Float64(Float64(sin(ky) / sqrt(Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) * sin(th))
end
function tmp = code(kx, ky, th)
	tmp = (sin(ky) / sqrt(((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) * sin(th);
end
code[kx_, ky_, th_] := N[(N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th
\end{array}

Alternative 1: 99.7% accurate, 1.2× speedup?

\[\begin{array}{l} \\ \frac{\sin th}{\frac{\mathsf{hypot}\left(\sin ky, \sin kx\right)}{\sin ky}} \end{array} \]
(FPCore (kx ky th)
 :precision binary64
 (/ (sin th) (/ (hypot (sin ky) (sin kx)) (sin ky))))
double code(double kx, double ky, double th) {
	return sin(th) / (hypot(sin(ky), sin(kx)) / sin(ky));
}
public static double code(double kx, double ky, double th) {
	return Math.sin(th) / (Math.hypot(Math.sin(ky), Math.sin(kx)) / Math.sin(ky));
}
def code(kx, ky, th):
	return math.sin(th) / (math.hypot(math.sin(ky), math.sin(kx)) / math.sin(ky))
function code(kx, ky, th)
	return Float64(sin(th) / Float64(hypot(sin(ky), sin(kx)) / sin(ky)))
end
function tmp = code(kx, ky, th)
	tmp = sin(th) / (hypot(sin(ky), sin(kx)) / sin(ky));
end
code[kx_, ky_, th_] := N[(N[Sin[th], $MachinePrecision] / N[(N[Sqrt[N[Sin[ky], $MachinePrecision] ^ 2 + N[Sin[kx], $MachinePrecision] ^ 2], $MachinePrecision] / N[Sin[ky], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{\sin th}{\frac{\mathsf{hypot}\left(\sin ky, \sin kx\right)}{\sin ky}}
\end{array}
Derivation
  1. Initial program 93.0%

    \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
  2. Add Preprocessing
  3. Step-by-step derivation
    1. lift-*.f64N/A

      \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
    2. *-commutativeN/A

      \[\leadsto \color{blue}{\sin th \cdot \frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
    3. lift-/.f64N/A

      \[\leadsto \sin th \cdot \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
    4. clear-numN/A

      \[\leadsto \sin th \cdot \color{blue}{\frac{1}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
    5. un-div-invN/A

      \[\leadsto \color{blue}{\frac{\sin th}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
    6. lower-/.f64N/A

      \[\leadsto \color{blue}{\frac{\sin th}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
    7. lower-/.f6492.9

      \[\leadsto \frac{\sin th}{\color{blue}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
    8. lift-sqrt.f64N/A

      \[\leadsto \frac{\sin th}{\frac{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\sin ky}} \]
    9. lift-+.f64N/A

      \[\leadsto \frac{\sin th}{\frac{\sqrt{\color{blue}{{\sin kx}^{2} + {\sin ky}^{2}}}}{\sin ky}} \]
    10. +-commutativeN/A

      \[\leadsto \frac{\sin th}{\frac{\sqrt{\color{blue}{{\sin ky}^{2} + {\sin kx}^{2}}}}{\sin ky}} \]
    11. lift-pow.f64N/A

      \[\leadsto \frac{\sin th}{\frac{\sqrt{\color{blue}{{\sin ky}^{2}} + {\sin kx}^{2}}}{\sin ky}} \]
    12. unpow2N/A

      \[\leadsto \frac{\sin th}{\frac{\sqrt{\color{blue}{\sin ky \cdot \sin ky} + {\sin kx}^{2}}}{\sin ky}} \]
    13. lift-pow.f64N/A

      \[\leadsto \frac{\sin th}{\frac{\sqrt{\sin ky \cdot \sin ky + \color{blue}{{\sin kx}^{2}}}}{\sin ky}} \]
    14. unpow2N/A

      \[\leadsto \frac{\sin th}{\frac{\sqrt{\sin ky \cdot \sin ky + \color{blue}{\sin kx \cdot \sin kx}}}{\sin ky}} \]
    15. lower-hypot.f6499.6

      \[\leadsto \frac{\sin th}{\frac{\color{blue}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\sin ky}} \]
  4. Applied rewrites99.6%

    \[\leadsto \color{blue}{\frac{\sin th}{\frac{\mathsf{hypot}\left(\sin ky, \sin kx\right)}{\sin ky}}} \]
  5. Add Preprocessing

Alternative 2: 83.2% accurate, 0.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := \left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \left(-ky\right)\right) \cdot \sin th\\ t_2 := {\sin ky}^{2}\\ t_3 := \frac{\sin ky}{\sqrt{{\sin kx}^{2} + t\_2}}\\ \mathbf{if}\;t\_3 \leq -0.99:\\ \;\;\;\;\frac{\sin ky}{\sqrt{kx \cdot kx + t\_2}} \cdot \sin th\\ \mathbf{elif}\;t\_3 \leq -0.01:\\ \;\;\;\;\left(\sin ky \cdot th\right) \cdot \sqrt{{\left(\mathsf{fma}\left(1 - \cos \left(2 \cdot kx\right), 0.5, t\_2\right)\right)}^{-1}}\\ \mathbf{elif}\;t\_3 \leq 0.15:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;t\_3 \leq 0.999999999981754:\\ \;\;\;\;\left(\left(-th\right) \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}\\ \mathbf{elif}\;t\_3 \leq 1:\\ \;\;\;\;\sin th\\ \mathbf{else}:\\ \;\;\;\;t\_1\\ \end{array} \end{array} \]
(FPCore (kx ky th)
 :precision binary64
 (let* ((t_1 (* (* (/ -1.0 (hypot (sin kx) (sin ky))) (- ky)) (sin th)))
        (t_2 (pow (sin ky) 2.0))
        (t_3 (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) t_2)))))
   (if (<= t_3 -0.99)
     (* (/ (sin ky) (sqrt (+ (* kx kx) t_2))) (sin th))
     (if (<= t_3 -0.01)
       (*
        (* (sin ky) th)
        (sqrt (pow (fma (- 1.0 (cos (* 2.0 kx))) 0.5 t_2) -1.0)))
       (if (<= t_3 0.15)
         t_1
         (if (<= t_3 0.999999999981754)
           (* (* (- th) (sin ky)) (/ -1.0 (hypot (sin ky) (sin kx))))
           (if (<= t_3 1.0) (sin th) t_1)))))))
double code(double kx, double ky, double th) {
	double t_1 = ((-1.0 / hypot(sin(kx), sin(ky))) * -ky) * sin(th);
	double t_2 = pow(sin(ky), 2.0);
	double t_3 = sin(ky) / sqrt((pow(sin(kx), 2.0) + t_2));
	double tmp;
	if (t_3 <= -0.99) {
		tmp = (sin(ky) / sqrt(((kx * kx) + t_2))) * sin(th);
	} else if (t_3 <= -0.01) {
		tmp = (sin(ky) * th) * sqrt(pow(fma((1.0 - cos((2.0 * kx))), 0.5, t_2), -1.0));
	} else if (t_3 <= 0.15) {
		tmp = t_1;
	} else if (t_3 <= 0.999999999981754) {
		tmp = (-th * sin(ky)) * (-1.0 / hypot(sin(ky), sin(kx)));
	} else if (t_3 <= 1.0) {
		tmp = sin(th);
	} else {
		tmp = t_1;
	}
	return tmp;
}
function code(kx, ky, th)
	t_1 = Float64(Float64(Float64(-1.0 / hypot(sin(kx), sin(ky))) * Float64(-ky)) * sin(th))
	t_2 = sin(ky) ^ 2.0
	t_3 = Float64(sin(ky) / sqrt(Float64((sin(kx) ^ 2.0) + t_2)))
	tmp = 0.0
	if (t_3 <= -0.99)
		tmp = Float64(Float64(sin(ky) / sqrt(Float64(Float64(kx * kx) + t_2))) * sin(th));
	elseif (t_3 <= -0.01)
		tmp = Float64(Float64(sin(ky) * th) * sqrt((fma(Float64(1.0 - cos(Float64(2.0 * kx))), 0.5, t_2) ^ -1.0)));
	elseif (t_3 <= 0.15)
		tmp = t_1;
	elseif (t_3 <= 0.999999999981754)
		tmp = Float64(Float64(Float64(-th) * sin(ky)) * Float64(-1.0 / hypot(sin(ky), sin(kx))));
	elseif (t_3 <= 1.0)
		tmp = sin(th);
	else
		tmp = t_1;
	end
	return tmp
end
code[kx_, ky_, th_] := Block[{t$95$1 = N[(N[(N[(-1.0 / N[Sqrt[N[Sin[kx], $MachinePrecision] ^ 2 + N[Sin[ky], $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision] * (-ky)), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]}, Block[{t$95$3 = N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + t$95$2), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$3, -0.99], N[(N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[(kx * kx), $MachinePrecision] + t$95$2), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$3, -0.01], N[(N[(N[Sin[ky], $MachinePrecision] * th), $MachinePrecision] * N[Sqrt[N[Power[N[(N[(1.0 - N[Cos[N[(2.0 * kx), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * 0.5 + t$95$2), $MachinePrecision], -1.0], $MachinePrecision]], $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$3, 0.15], t$95$1, If[LessEqual[t$95$3, 0.999999999981754], N[(N[((-th) * N[Sin[ky], $MachinePrecision]), $MachinePrecision] * N[(-1.0 / N[Sqrt[N[Sin[ky], $MachinePrecision] ^ 2 + N[Sin[kx], $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$3, 1.0], N[Sin[th], $MachinePrecision], t$95$1]]]]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := \left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \left(-ky\right)\right) \cdot \sin th\\
t_2 := {\sin ky}^{2}\\
t_3 := \frac{\sin ky}{\sqrt{{\sin kx}^{2} + t\_2}}\\
\mathbf{if}\;t\_3 \leq -0.99:\\
\;\;\;\;\frac{\sin ky}{\sqrt{kx \cdot kx + t\_2}} \cdot \sin th\\

\mathbf{elif}\;t\_3 \leq -0.01:\\
\;\;\;\;\left(\sin ky \cdot th\right) \cdot \sqrt{{\left(\mathsf{fma}\left(1 - \cos \left(2 \cdot kx\right), 0.5, t\_2\right)\right)}^{-1}}\\

\mathbf{elif}\;t\_3 \leq 0.15:\\
\;\;\;\;t\_1\\

\mathbf{elif}\;t\_3 \leq 0.999999999981754:\\
\;\;\;\;\left(\left(-th\right) \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}\\

\mathbf{elif}\;t\_3 \leq 1:\\
\;\;\;\;\sin th\\

\mathbf{else}:\\
\;\;\;\;t\_1\\


\end{array}
\end{array}
Derivation
  1. Split input into 5 regimes
  2. if (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < -0.98999999999999999

    1. Initial program 81.9%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in kx around 0

      \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{{kx}^{2}} + {\sin ky}^{2}}} \cdot \sin th \]
    4. Step-by-step derivation
      1. unpow2N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{kx \cdot kx} + {\sin ky}^{2}}} \cdot \sin th \]
      2. lower-*.f6477.3

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{kx \cdot kx} + {\sin ky}^{2}}} \cdot \sin th \]
    5. Applied rewrites77.3%

      \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{kx \cdot kx} + {\sin ky}^{2}}} \cdot \sin th \]

    if -0.98999999999999999 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < -0.0100000000000000002

    1. Initial program 99.3%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-pow.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{{\sin kx}^{2}} + {\sin ky}^{2}}} \cdot \sin th \]
      2. unpow2N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\sin kx \cdot \sin kx} + {\sin ky}^{2}}} \cdot \sin th \]
      3. lift-sin.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\sin kx} \cdot \sin kx + {\sin ky}^{2}}} \cdot \sin th \]
      4. lift-sin.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\sin kx \cdot \color{blue}{\sin kx} + {\sin ky}^{2}}} \cdot \sin th \]
      5. sin-multN/A

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\frac{\cos \left(kx - kx\right) - \cos \left(kx + kx\right)}{2}} + {\sin ky}^{2}}} \cdot \sin th \]
      6. clear-numN/A

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\frac{1}{\frac{2}{\cos \left(kx - kx\right) - \cos \left(kx + kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
      7. lower-/.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\frac{1}{\frac{2}{\cos \left(kx - kx\right) - \cos \left(kx + kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
      8. lower-/.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{\color{blue}{\frac{2}{\cos \left(kx - kx\right) - \cos \left(kx + kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
      9. cos-diffN/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{\frac{2}{\color{blue}{\left(\cos kx \cdot \cos kx + \sin kx \cdot \sin kx\right)} - \cos \left(kx + kx\right)}} + {\sin ky}^{2}}} \cdot \sin th \]
      10. cos-sin-sumN/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{\frac{2}{\color{blue}{1} - \cos \left(kx + kx\right)}} + {\sin ky}^{2}}} \cdot \sin th \]
      11. lower--.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{\frac{2}{\color{blue}{1 - \cos \left(kx + kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
      12. lower-cos.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{\frac{2}{1 - \color{blue}{\cos \left(kx + kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
      13. count-2N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{\frac{2}{1 - \cos \color{blue}{\left(2 \cdot kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
      14. lower-*.f6499.3

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{\frac{2}{1 - \cos \color{blue}{\left(2 \cdot kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
    4. Applied rewrites99.3%

      \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\frac{1}{\frac{2}{1 - \cos \left(2 \cdot kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
    5. Taylor expanded in th around 0

      \[\leadsto \color{blue}{\left(th \cdot \sin ky\right) \cdot \sqrt{\frac{1}{\frac{1}{2} \cdot \left(1 - \cos \left(2 \cdot kx\right)\right) + {\sin ky}^{2}}}} \]
    6. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(th \cdot \sin ky\right) \cdot \sqrt{\frac{1}{\frac{1}{2} \cdot \left(1 - \cos \left(2 \cdot kx\right)\right) + {\sin ky}^{2}}}} \]
      2. *-commutativeN/A

        \[\leadsto \color{blue}{\left(\sin ky \cdot th\right)} \cdot \sqrt{\frac{1}{\frac{1}{2} \cdot \left(1 - \cos \left(2 \cdot kx\right)\right) + {\sin ky}^{2}}} \]
      3. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\sin ky \cdot th\right)} \cdot \sqrt{\frac{1}{\frac{1}{2} \cdot \left(1 - \cos \left(2 \cdot kx\right)\right) + {\sin ky}^{2}}} \]
      4. lower-sin.f64N/A

        \[\leadsto \left(\color{blue}{\sin ky} \cdot th\right) \cdot \sqrt{\frac{1}{\frac{1}{2} \cdot \left(1 - \cos \left(2 \cdot kx\right)\right) + {\sin ky}^{2}}} \]
      5. lower-sqrt.f64N/A

        \[\leadsto \left(\sin ky \cdot th\right) \cdot \color{blue}{\sqrt{\frac{1}{\frac{1}{2} \cdot \left(1 - \cos \left(2 \cdot kx\right)\right) + {\sin ky}^{2}}}} \]
      6. lower-/.f64N/A

        \[\leadsto \left(\sin ky \cdot th\right) \cdot \sqrt{\color{blue}{\frac{1}{\frac{1}{2} \cdot \left(1 - \cos \left(2 \cdot kx\right)\right) + {\sin ky}^{2}}}} \]
      7. *-commutativeN/A

        \[\leadsto \left(\sin ky \cdot th\right) \cdot \sqrt{\frac{1}{\color{blue}{\left(1 - \cos \left(2 \cdot kx\right)\right) \cdot \frac{1}{2}} + {\sin ky}^{2}}} \]
      8. lower-fma.f64N/A

        \[\leadsto \left(\sin ky \cdot th\right) \cdot \sqrt{\frac{1}{\color{blue}{\mathsf{fma}\left(1 - \cos \left(2 \cdot kx\right), \frac{1}{2}, {\sin ky}^{2}\right)}}} \]
      9. lower--.f64N/A

        \[\leadsto \left(\sin ky \cdot th\right) \cdot \sqrt{\frac{1}{\mathsf{fma}\left(\color{blue}{1 - \cos \left(2 \cdot kx\right)}, \frac{1}{2}, {\sin ky}^{2}\right)}} \]
      10. lower-cos.f64N/A

        \[\leadsto \left(\sin ky \cdot th\right) \cdot \sqrt{\frac{1}{\mathsf{fma}\left(1 - \color{blue}{\cos \left(2 \cdot kx\right)}, \frac{1}{2}, {\sin ky}^{2}\right)}} \]
      11. lower-*.f64N/A

        \[\leadsto \left(\sin ky \cdot th\right) \cdot \sqrt{\frac{1}{\mathsf{fma}\left(1 - \cos \color{blue}{\left(2 \cdot kx\right)}, \frac{1}{2}, {\sin ky}^{2}\right)}} \]
      12. lower-pow.f64N/A

        \[\leadsto \left(\sin ky \cdot th\right) \cdot \sqrt{\frac{1}{\mathsf{fma}\left(1 - \cos \left(2 \cdot kx\right), \frac{1}{2}, \color{blue}{{\sin ky}^{2}}\right)}} \]
      13. lower-sin.f6445.2

        \[\leadsto \left(\sin ky \cdot th\right) \cdot \sqrt{\frac{1}{\mathsf{fma}\left(1 - \cos \left(2 \cdot kx\right), 0.5, {\color{blue}{\sin ky}}^{2}\right)}} \]
    7. Applied rewrites45.2%

      \[\leadsto \color{blue}{\left(\sin ky \cdot th\right) \cdot \sqrt{\frac{1}{\mathsf{fma}\left(1 - \cos \left(2 \cdot kx\right), 0.5, {\sin ky}^{2}\right)}}} \]

    if -0.0100000000000000002 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 0.149999999999999994 or 1 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))

    1. Initial program 91.9%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
      2. lift-/.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin th \]
      3. associate-*l/N/A

        \[\leadsto \color{blue}{\frac{\sin ky \cdot \sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      4. frac-2negN/A

        \[\leadsto \color{blue}{\frac{\mathsf{neg}\left(\sin ky \cdot \sin th\right)}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      5. div-invN/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sin ky \cdot \sin th\right)\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      6. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sin ky \cdot \sin th\right)\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      7. distribute-lft-neg-inN/A

        \[\leadsto \color{blue}{\left(\left(\mathsf{neg}\left(\sin ky\right)\right) \cdot \sin th\right)} \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      8. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\left(\mathsf{neg}\left(\sin ky\right)\right) \cdot \sin th\right)} \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      9. lower-neg.f64N/A

        \[\leadsto \left(\color{blue}{\left(-\sin ky\right)} \cdot \sin th\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      10. neg-mul-1N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{1}{\color{blue}{-1 \cdot \sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      11. associate-/r*N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \color{blue}{\frac{\frac{1}{-1}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      12. metadata-evalN/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{\color{blue}{-1}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \]
      13. lower-/.f6489.4

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \color{blue}{\frac{-1}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      14. lift-sqrt.f64N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{-1}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
    4. Applied rewrites97.1%

      \[\leadsto \color{blue}{\left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
    5. Taylor expanded in ky around 0

      \[\leadsto \left(\color{blue}{\left(ky \cdot \left(\frac{1}{6} \cdot {ky}^{2} - 1\right)\right)} \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
    6. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto \left(\color{blue}{\left(\left(\frac{1}{6} \cdot {ky}^{2} - 1\right) \cdot ky\right)} \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      2. lower-*.f64N/A

        \[\leadsto \left(\color{blue}{\left(\left(\frac{1}{6} \cdot {ky}^{2} - 1\right) \cdot ky\right)} \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      3. sub-negN/A

        \[\leadsto \left(\left(\color{blue}{\left(\frac{1}{6} \cdot {ky}^{2} + \left(\mathsf{neg}\left(1\right)\right)\right)} \cdot ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      4. metadata-evalN/A

        \[\leadsto \left(\left(\left(\frac{1}{6} \cdot {ky}^{2} + \color{blue}{-1}\right) \cdot ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      5. lower-fma.f64N/A

        \[\leadsto \left(\left(\color{blue}{\mathsf{fma}\left(\frac{1}{6}, {ky}^{2}, -1\right)} \cdot ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      6. unpow2N/A

        \[\leadsto \left(\left(\mathsf{fma}\left(\frac{1}{6}, \color{blue}{ky \cdot ky}, -1\right) \cdot ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      7. lower-*.f6495.1

        \[\leadsto \left(\left(\mathsf{fma}\left(0.16666666666666666, \color{blue}{ky \cdot ky}, -1\right) \cdot ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
    7. Applied rewrites95.1%

      \[\leadsto \left(\color{blue}{\left(\mathsf{fma}\left(0.16666666666666666, ky \cdot ky, -1\right) \cdot ky\right)} \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
    8. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{\left(\left(\mathsf{fma}\left(\frac{1}{6}, ky \cdot ky, -1\right) \cdot ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
      2. *-commutativeN/A

        \[\leadsto \color{blue}{\frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \cdot \left(\left(\mathsf{fma}\left(\frac{1}{6}, ky \cdot ky, -1\right) \cdot ky\right) \cdot \sin th\right)} \]
      3. lift-*.f64N/A

        \[\leadsto \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \cdot \color{blue}{\left(\left(\mathsf{fma}\left(\frac{1}{6}, ky \cdot ky, -1\right) \cdot ky\right) \cdot \sin th\right)} \]
      4. associate-*r*N/A

        \[\leadsto \color{blue}{\left(\frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \cdot \left(\mathsf{fma}\left(\frac{1}{6}, ky \cdot ky, -1\right) \cdot ky\right)\right) \cdot \sin th} \]
      5. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \cdot \left(\mathsf{fma}\left(\frac{1}{6}, ky \cdot ky, -1\right) \cdot ky\right)\right) \cdot \sin th} \]
    9. Applied rewrites97.7%

      \[\leadsto \color{blue}{\left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \left(\mathsf{fma}\left(ky \cdot ky, 0.16666666666666666, -1\right) \cdot ky\right)\right) \cdot \sin th} \]
    10. Taylor expanded in ky around 0

      \[\leadsto \left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \color{blue}{\left(-1 \cdot ky\right)}\right) \cdot \sin th \]
    11. Step-by-step derivation
      1. mul-1-negN/A

        \[\leadsto \left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \color{blue}{\left(\mathsf{neg}\left(ky\right)\right)}\right) \cdot \sin th \]
      2. lower-neg.f6497.7

        \[\leadsto \left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \color{blue}{\left(-ky\right)}\right) \cdot \sin th \]
    12. Applied rewrites97.7%

      \[\leadsto \left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \color{blue}{\left(-ky\right)}\right) \cdot \sin th \]

    if 0.149999999999999994 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 0.99999999998175404

    1. Initial program 97.5%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
      2. lift-/.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin th \]
      3. associate-*l/N/A

        \[\leadsto \color{blue}{\frac{\sin ky \cdot \sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      4. frac-2negN/A

        \[\leadsto \color{blue}{\frac{\mathsf{neg}\left(\sin ky \cdot \sin th\right)}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      5. div-invN/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sin ky \cdot \sin th\right)\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      6. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sin ky \cdot \sin th\right)\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      7. distribute-lft-neg-inN/A

        \[\leadsto \color{blue}{\left(\left(\mathsf{neg}\left(\sin ky\right)\right) \cdot \sin th\right)} \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      8. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\left(\mathsf{neg}\left(\sin ky\right)\right) \cdot \sin th\right)} \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      9. lower-neg.f64N/A

        \[\leadsto \left(\color{blue}{\left(-\sin ky\right)} \cdot \sin th\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      10. neg-mul-1N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{1}{\color{blue}{-1 \cdot \sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      11. associate-/r*N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \color{blue}{\frac{\frac{1}{-1}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      12. metadata-evalN/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{\color{blue}{-1}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \]
      13. lower-/.f6497.5

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \color{blue}{\frac{-1}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      14. lift-sqrt.f64N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{-1}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
    4. Applied rewrites99.2%

      \[\leadsto \color{blue}{\left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
    5. Taylor expanded in th around 0

      \[\leadsto \color{blue}{\left(-1 \cdot \left(th \cdot \sin ky\right)\right)} \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
    6. Step-by-step derivation
      1. associate-*r*N/A

        \[\leadsto \color{blue}{\left(\left(-1 \cdot th\right) \cdot \sin ky\right)} \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      2. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\left(-1 \cdot th\right) \cdot \sin ky\right)} \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      3. mul-1-negN/A

        \[\leadsto \left(\color{blue}{\left(\mathsf{neg}\left(th\right)\right)} \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      4. lower-neg.f64N/A

        \[\leadsto \left(\color{blue}{\left(-th\right)} \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      5. lower-sin.f6439.3

        \[\leadsto \left(\left(-th\right) \cdot \color{blue}{\sin ky}\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
    7. Applied rewrites39.3%

      \[\leadsto \color{blue}{\left(\left(-th\right) \cdot \sin ky\right)} \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]

    if 0.99999999998175404 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 1

    1. Initial program 100.0%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in kx around 0

      \[\leadsto \color{blue}{\sin th} \]
    4. Step-by-step derivation
      1. lower-sin.f64100.0

        \[\leadsto \color{blue}{\sin th} \]
    5. Applied rewrites100.0%

      \[\leadsto \color{blue}{\sin th} \]
  3. Recombined 5 regimes into one program.
  4. Final simplification81.1%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq -0.99:\\ \;\;\;\;\frac{\sin ky}{\sqrt{kx \cdot kx + {\sin ky}^{2}}} \cdot \sin th\\ \mathbf{elif}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq -0.01:\\ \;\;\;\;\left(\sin ky \cdot th\right) \cdot \sqrt{{\left(\mathsf{fma}\left(1 - \cos \left(2 \cdot kx\right), 0.5, {\sin ky}^{2}\right)\right)}^{-1}}\\ \mathbf{elif}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 0.15:\\ \;\;\;\;\left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \left(-ky\right)\right) \cdot \sin th\\ \mathbf{elif}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 0.999999999981754:\\ \;\;\;\;\left(\left(-th\right) \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}\\ \mathbf{elif}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 1:\\ \;\;\;\;\sin th\\ \mathbf{else}:\\ \;\;\;\;\left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \left(-ky\right)\right) \cdot \sin th\\ \end{array} \]
  5. Add Preprocessing

Alternative 3: 83.2% accurate, 0.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := \left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \left(-ky\right)\right) \cdot \sin th\\ t_2 := \left(\left(-th\right) \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}\\ t_3 := {\sin ky}^{2}\\ t_4 := \frac{\sin ky}{\sqrt{{\sin kx}^{2} + t\_3}}\\ \mathbf{if}\;t\_4 \leq -0.99:\\ \;\;\;\;\frac{\sin ky}{\sqrt{kx \cdot kx + t\_3}} \cdot \sin th\\ \mathbf{elif}\;t\_4 \leq -0.01:\\ \;\;\;\;t\_2\\ \mathbf{elif}\;t\_4 \leq 0.15:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;t\_4 \leq 0.999999999981754:\\ \;\;\;\;t\_2\\ \mathbf{elif}\;t\_4 \leq 1:\\ \;\;\;\;\sin th\\ \mathbf{else}:\\ \;\;\;\;t\_1\\ \end{array} \end{array} \]
(FPCore (kx ky th)
 :precision binary64
 (let* ((t_1 (* (* (/ -1.0 (hypot (sin kx) (sin ky))) (- ky)) (sin th)))
        (t_2 (* (* (- th) (sin ky)) (/ -1.0 (hypot (sin ky) (sin kx)))))
        (t_3 (pow (sin ky) 2.0))
        (t_4 (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) t_3)))))
   (if (<= t_4 -0.99)
     (* (/ (sin ky) (sqrt (+ (* kx kx) t_3))) (sin th))
     (if (<= t_4 -0.01)
       t_2
       (if (<= t_4 0.15)
         t_1
         (if (<= t_4 0.999999999981754)
           t_2
           (if (<= t_4 1.0) (sin th) t_1)))))))
double code(double kx, double ky, double th) {
	double t_1 = ((-1.0 / hypot(sin(kx), sin(ky))) * -ky) * sin(th);
	double t_2 = (-th * sin(ky)) * (-1.0 / hypot(sin(ky), sin(kx)));
	double t_3 = pow(sin(ky), 2.0);
	double t_4 = sin(ky) / sqrt((pow(sin(kx), 2.0) + t_3));
	double tmp;
	if (t_4 <= -0.99) {
		tmp = (sin(ky) / sqrt(((kx * kx) + t_3))) * sin(th);
	} else if (t_4 <= -0.01) {
		tmp = t_2;
	} else if (t_4 <= 0.15) {
		tmp = t_1;
	} else if (t_4 <= 0.999999999981754) {
		tmp = t_2;
	} else if (t_4 <= 1.0) {
		tmp = sin(th);
	} else {
		tmp = t_1;
	}
	return tmp;
}
public static double code(double kx, double ky, double th) {
	double t_1 = ((-1.0 / Math.hypot(Math.sin(kx), Math.sin(ky))) * -ky) * Math.sin(th);
	double t_2 = (-th * Math.sin(ky)) * (-1.0 / Math.hypot(Math.sin(ky), Math.sin(kx)));
	double t_3 = Math.pow(Math.sin(ky), 2.0);
	double t_4 = Math.sin(ky) / Math.sqrt((Math.pow(Math.sin(kx), 2.0) + t_3));
	double tmp;
	if (t_4 <= -0.99) {
		tmp = (Math.sin(ky) / Math.sqrt(((kx * kx) + t_3))) * Math.sin(th);
	} else if (t_4 <= -0.01) {
		tmp = t_2;
	} else if (t_4 <= 0.15) {
		tmp = t_1;
	} else if (t_4 <= 0.999999999981754) {
		tmp = t_2;
	} else if (t_4 <= 1.0) {
		tmp = Math.sin(th);
	} else {
		tmp = t_1;
	}
	return tmp;
}
def code(kx, ky, th):
	t_1 = ((-1.0 / math.hypot(math.sin(kx), math.sin(ky))) * -ky) * math.sin(th)
	t_2 = (-th * math.sin(ky)) * (-1.0 / math.hypot(math.sin(ky), math.sin(kx)))
	t_3 = math.pow(math.sin(ky), 2.0)
	t_4 = math.sin(ky) / math.sqrt((math.pow(math.sin(kx), 2.0) + t_3))
	tmp = 0
	if t_4 <= -0.99:
		tmp = (math.sin(ky) / math.sqrt(((kx * kx) + t_3))) * math.sin(th)
	elif t_4 <= -0.01:
		tmp = t_2
	elif t_4 <= 0.15:
		tmp = t_1
	elif t_4 <= 0.999999999981754:
		tmp = t_2
	elif t_4 <= 1.0:
		tmp = math.sin(th)
	else:
		tmp = t_1
	return tmp
function code(kx, ky, th)
	t_1 = Float64(Float64(Float64(-1.0 / hypot(sin(kx), sin(ky))) * Float64(-ky)) * sin(th))
	t_2 = Float64(Float64(Float64(-th) * sin(ky)) * Float64(-1.0 / hypot(sin(ky), sin(kx))))
	t_3 = sin(ky) ^ 2.0
	t_4 = Float64(sin(ky) / sqrt(Float64((sin(kx) ^ 2.0) + t_3)))
	tmp = 0.0
	if (t_4 <= -0.99)
		tmp = Float64(Float64(sin(ky) / sqrt(Float64(Float64(kx * kx) + t_3))) * sin(th));
	elseif (t_4 <= -0.01)
		tmp = t_2;
	elseif (t_4 <= 0.15)
		tmp = t_1;
	elseif (t_4 <= 0.999999999981754)
		tmp = t_2;
	elseif (t_4 <= 1.0)
		tmp = sin(th);
	else
		tmp = t_1;
	end
	return tmp
end
function tmp_2 = code(kx, ky, th)
	t_1 = ((-1.0 / hypot(sin(kx), sin(ky))) * -ky) * sin(th);
	t_2 = (-th * sin(ky)) * (-1.0 / hypot(sin(ky), sin(kx)));
	t_3 = sin(ky) ^ 2.0;
	t_4 = sin(ky) / sqrt(((sin(kx) ^ 2.0) + t_3));
	tmp = 0.0;
	if (t_4 <= -0.99)
		tmp = (sin(ky) / sqrt(((kx * kx) + t_3))) * sin(th);
	elseif (t_4 <= -0.01)
		tmp = t_2;
	elseif (t_4 <= 0.15)
		tmp = t_1;
	elseif (t_4 <= 0.999999999981754)
		tmp = t_2;
	elseif (t_4 <= 1.0)
		tmp = sin(th);
	else
		tmp = t_1;
	end
	tmp_2 = tmp;
end
code[kx_, ky_, th_] := Block[{t$95$1 = N[(N[(N[(-1.0 / N[Sqrt[N[Sin[kx], $MachinePrecision] ^ 2 + N[Sin[ky], $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision] * (-ky)), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(N[((-th) * N[Sin[ky], $MachinePrecision]), $MachinePrecision] * N[(-1.0 / N[Sqrt[N[Sin[ky], $MachinePrecision] ^ 2 + N[Sin[kx], $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]}, Block[{t$95$4 = N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + t$95$3), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$4, -0.99], N[(N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[(kx * kx), $MachinePrecision] + t$95$3), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$4, -0.01], t$95$2, If[LessEqual[t$95$4, 0.15], t$95$1, If[LessEqual[t$95$4, 0.999999999981754], t$95$2, If[LessEqual[t$95$4, 1.0], N[Sin[th], $MachinePrecision], t$95$1]]]]]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := \left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \left(-ky\right)\right) \cdot \sin th\\
t_2 := \left(\left(-th\right) \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}\\
t_3 := {\sin ky}^{2}\\
t_4 := \frac{\sin ky}{\sqrt{{\sin kx}^{2} + t\_3}}\\
\mathbf{if}\;t\_4 \leq -0.99:\\
\;\;\;\;\frac{\sin ky}{\sqrt{kx \cdot kx + t\_3}} \cdot \sin th\\

\mathbf{elif}\;t\_4 \leq -0.01:\\
\;\;\;\;t\_2\\

\mathbf{elif}\;t\_4 \leq 0.15:\\
\;\;\;\;t\_1\\

\mathbf{elif}\;t\_4 \leq 0.999999999981754:\\
\;\;\;\;t\_2\\

\mathbf{elif}\;t\_4 \leq 1:\\
\;\;\;\;\sin th\\

\mathbf{else}:\\
\;\;\;\;t\_1\\


\end{array}
\end{array}
Derivation
  1. Split input into 4 regimes
  2. if (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < -0.98999999999999999

    1. Initial program 81.9%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in kx around 0

      \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{{kx}^{2}} + {\sin ky}^{2}}} \cdot \sin th \]
    4. Step-by-step derivation
      1. unpow2N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{kx \cdot kx} + {\sin ky}^{2}}} \cdot \sin th \]
      2. lower-*.f6477.3

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{kx \cdot kx} + {\sin ky}^{2}}} \cdot \sin th \]
    5. Applied rewrites77.3%

      \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{kx \cdot kx} + {\sin ky}^{2}}} \cdot \sin th \]

    if -0.98999999999999999 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < -0.0100000000000000002 or 0.149999999999999994 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 0.99999999998175404

    1. Initial program 98.4%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
      2. lift-/.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin th \]
      3. associate-*l/N/A

        \[\leadsto \color{blue}{\frac{\sin ky \cdot \sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      4. frac-2negN/A

        \[\leadsto \color{blue}{\frac{\mathsf{neg}\left(\sin ky \cdot \sin th\right)}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      5. div-invN/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sin ky \cdot \sin th\right)\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      6. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sin ky \cdot \sin th\right)\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      7. distribute-lft-neg-inN/A

        \[\leadsto \color{blue}{\left(\left(\mathsf{neg}\left(\sin ky\right)\right) \cdot \sin th\right)} \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      8. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\left(\mathsf{neg}\left(\sin ky\right)\right) \cdot \sin th\right)} \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      9. lower-neg.f64N/A

        \[\leadsto \left(\color{blue}{\left(-\sin ky\right)} \cdot \sin th\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      10. neg-mul-1N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{1}{\color{blue}{-1 \cdot \sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      11. associate-/r*N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \color{blue}{\frac{\frac{1}{-1}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      12. metadata-evalN/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{\color{blue}{-1}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \]
      13. lower-/.f6498.3

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \color{blue}{\frac{-1}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      14. lift-sqrt.f64N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{-1}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
    4. Applied rewrites99.1%

      \[\leadsto \color{blue}{\left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
    5. Taylor expanded in th around 0

      \[\leadsto \color{blue}{\left(-1 \cdot \left(th \cdot \sin ky\right)\right)} \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
    6. Step-by-step derivation
      1. associate-*r*N/A

        \[\leadsto \color{blue}{\left(\left(-1 \cdot th\right) \cdot \sin ky\right)} \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      2. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\left(-1 \cdot th\right) \cdot \sin ky\right)} \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      3. mul-1-negN/A

        \[\leadsto \left(\color{blue}{\left(\mathsf{neg}\left(th\right)\right)} \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      4. lower-neg.f64N/A

        \[\leadsto \left(\color{blue}{\left(-th\right)} \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      5. lower-sin.f6441.9

        \[\leadsto \left(\left(-th\right) \cdot \color{blue}{\sin ky}\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
    7. Applied rewrites41.9%

      \[\leadsto \color{blue}{\left(\left(-th\right) \cdot \sin ky\right)} \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]

    if -0.0100000000000000002 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 0.149999999999999994 or 1 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))

    1. Initial program 91.9%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
      2. lift-/.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin th \]
      3. associate-*l/N/A

        \[\leadsto \color{blue}{\frac{\sin ky \cdot \sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      4. frac-2negN/A

        \[\leadsto \color{blue}{\frac{\mathsf{neg}\left(\sin ky \cdot \sin th\right)}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      5. div-invN/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sin ky \cdot \sin th\right)\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      6. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sin ky \cdot \sin th\right)\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      7. distribute-lft-neg-inN/A

        \[\leadsto \color{blue}{\left(\left(\mathsf{neg}\left(\sin ky\right)\right) \cdot \sin th\right)} \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      8. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\left(\mathsf{neg}\left(\sin ky\right)\right) \cdot \sin th\right)} \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      9. lower-neg.f64N/A

        \[\leadsto \left(\color{blue}{\left(-\sin ky\right)} \cdot \sin th\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      10. neg-mul-1N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{1}{\color{blue}{-1 \cdot \sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      11. associate-/r*N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \color{blue}{\frac{\frac{1}{-1}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      12. metadata-evalN/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{\color{blue}{-1}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \]
      13. lower-/.f6489.4

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \color{blue}{\frac{-1}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      14. lift-sqrt.f64N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{-1}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
    4. Applied rewrites97.1%

      \[\leadsto \color{blue}{\left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
    5. Taylor expanded in ky around 0

      \[\leadsto \left(\color{blue}{\left(ky \cdot \left(\frac{1}{6} \cdot {ky}^{2} - 1\right)\right)} \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
    6. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto \left(\color{blue}{\left(\left(\frac{1}{6} \cdot {ky}^{2} - 1\right) \cdot ky\right)} \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      2. lower-*.f64N/A

        \[\leadsto \left(\color{blue}{\left(\left(\frac{1}{6} \cdot {ky}^{2} - 1\right) \cdot ky\right)} \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      3. sub-negN/A

        \[\leadsto \left(\left(\color{blue}{\left(\frac{1}{6} \cdot {ky}^{2} + \left(\mathsf{neg}\left(1\right)\right)\right)} \cdot ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      4. metadata-evalN/A

        \[\leadsto \left(\left(\left(\frac{1}{6} \cdot {ky}^{2} + \color{blue}{-1}\right) \cdot ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      5. lower-fma.f64N/A

        \[\leadsto \left(\left(\color{blue}{\mathsf{fma}\left(\frac{1}{6}, {ky}^{2}, -1\right)} \cdot ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      6. unpow2N/A

        \[\leadsto \left(\left(\mathsf{fma}\left(\frac{1}{6}, \color{blue}{ky \cdot ky}, -1\right) \cdot ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      7. lower-*.f6495.1

        \[\leadsto \left(\left(\mathsf{fma}\left(0.16666666666666666, \color{blue}{ky \cdot ky}, -1\right) \cdot ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
    7. Applied rewrites95.1%

      \[\leadsto \left(\color{blue}{\left(\mathsf{fma}\left(0.16666666666666666, ky \cdot ky, -1\right) \cdot ky\right)} \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
    8. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{\left(\left(\mathsf{fma}\left(\frac{1}{6}, ky \cdot ky, -1\right) \cdot ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
      2. *-commutativeN/A

        \[\leadsto \color{blue}{\frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \cdot \left(\left(\mathsf{fma}\left(\frac{1}{6}, ky \cdot ky, -1\right) \cdot ky\right) \cdot \sin th\right)} \]
      3. lift-*.f64N/A

        \[\leadsto \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \cdot \color{blue}{\left(\left(\mathsf{fma}\left(\frac{1}{6}, ky \cdot ky, -1\right) \cdot ky\right) \cdot \sin th\right)} \]
      4. associate-*r*N/A

        \[\leadsto \color{blue}{\left(\frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \cdot \left(\mathsf{fma}\left(\frac{1}{6}, ky \cdot ky, -1\right) \cdot ky\right)\right) \cdot \sin th} \]
      5. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \cdot \left(\mathsf{fma}\left(\frac{1}{6}, ky \cdot ky, -1\right) \cdot ky\right)\right) \cdot \sin th} \]
    9. Applied rewrites97.7%

      \[\leadsto \color{blue}{\left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \left(\mathsf{fma}\left(ky \cdot ky, 0.16666666666666666, -1\right) \cdot ky\right)\right) \cdot \sin th} \]
    10. Taylor expanded in ky around 0

      \[\leadsto \left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \color{blue}{\left(-1 \cdot ky\right)}\right) \cdot \sin th \]
    11. Step-by-step derivation
      1. mul-1-negN/A

        \[\leadsto \left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \color{blue}{\left(\mathsf{neg}\left(ky\right)\right)}\right) \cdot \sin th \]
      2. lower-neg.f6497.7

        \[\leadsto \left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \color{blue}{\left(-ky\right)}\right) \cdot \sin th \]
    12. Applied rewrites97.7%

      \[\leadsto \left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \color{blue}{\left(-ky\right)}\right) \cdot \sin th \]

    if 0.99999999998175404 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 1

    1. Initial program 100.0%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in kx around 0

      \[\leadsto \color{blue}{\sin th} \]
    4. Step-by-step derivation
      1. lower-sin.f64100.0

        \[\leadsto \color{blue}{\sin th} \]
    5. Applied rewrites100.0%

      \[\leadsto \color{blue}{\sin th} \]
  3. Recombined 4 regimes into one program.
  4. Add Preprocessing

Alternative 4: 75.1% accurate, 0.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := \left(\left(-th\right) \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}\\ t_2 := \frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}\\ t_3 := \left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \left(-ky\right)\right) \cdot \sin th\\ \mathbf{if}\;t\_2 \leq -0.01:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;t\_2 \leq 0.15:\\ \;\;\;\;t\_3\\ \mathbf{elif}\;t\_2 \leq 0.999999999981754:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;t\_2 \leq 1:\\ \;\;\;\;\sin th\\ \mathbf{else}:\\ \;\;\;\;t\_3\\ \end{array} \end{array} \]
(FPCore (kx ky th)
 :precision binary64
 (let* ((t_1 (* (* (- th) (sin ky)) (/ -1.0 (hypot (sin ky) (sin kx)))))
        (t_2 (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0)))))
        (t_3 (* (* (/ -1.0 (hypot (sin kx) (sin ky))) (- ky)) (sin th))))
   (if (<= t_2 -0.01)
     t_1
     (if (<= t_2 0.15)
       t_3
       (if (<= t_2 0.999999999981754) t_1 (if (<= t_2 1.0) (sin th) t_3))))))
double code(double kx, double ky, double th) {
	double t_1 = (-th * sin(ky)) * (-1.0 / hypot(sin(ky), sin(kx)));
	double t_2 = sin(ky) / sqrt((pow(sin(kx), 2.0) + pow(sin(ky), 2.0)));
	double t_3 = ((-1.0 / hypot(sin(kx), sin(ky))) * -ky) * sin(th);
	double tmp;
	if (t_2 <= -0.01) {
		tmp = t_1;
	} else if (t_2 <= 0.15) {
		tmp = t_3;
	} else if (t_2 <= 0.999999999981754) {
		tmp = t_1;
	} else if (t_2 <= 1.0) {
		tmp = sin(th);
	} else {
		tmp = t_3;
	}
	return tmp;
}
public static double code(double kx, double ky, double th) {
	double t_1 = (-th * Math.sin(ky)) * (-1.0 / Math.hypot(Math.sin(ky), Math.sin(kx)));
	double t_2 = Math.sin(ky) / Math.sqrt((Math.pow(Math.sin(kx), 2.0) + Math.pow(Math.sin(ky), 2.0)));
	double t_3 = ((-1.0 / Math.hypot(Math.sin(kx), Math.sin(ky))) * -ky) * Math.sin(th);
	double tmp;
	if (t_2 <= -0.01) {
		tmp = t_1;
	} else if (t_2 <= 0.15) {
		tmp = t_3;
	} else if (t_2 <= 0.999999999981754) {
		tmp = t_1;
	} else if (t_2 <= 1.0) {
		tmp = Math.sin(th);
	} else {
		tmp = t_3;
	}
	return tmp;
}
def code(kx, ky, th):
	t_1 = (-th * math.sin(ky)) * (-1.0 / math.hypot(math.sin(ky), math.sin(kx)))
	t_2 = math.sin(ky) / math.sqrt((math.pow(math.sin(kx), 2.0) + math.pow(math.sin(ky), 2.0)))
	t_3 = ((-1.0 / math.hypot(math.sin(kx), math.sin(ky))) * -ky) * math.sin(th)
	tmp = 0
	if t_2 <= -0.01:
		tmp = t_1
	elif t_2 <= 0.15:
		tmp = t_3
	elif t_2 <= 0.999999999981754:
		tmp = t_1
	elif t_2 <= 1.0:
		tmp = math.sin(th)
	else:
		tmp = t_3
	return tmp
function code(kx, ky, th)
	t_1 = Float64(Float64(Float64(-th) * sin(ky)) * Float64(-1.0 / hypot(sin(ky), sin(kx))))
	t_2 = Float64(sin(ky) / sqrt(Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0))))
	t_3 = Float64(Float64(Float64(-1.0 / hypot(sin(kx), sin(ky))) * Float64(-ky)) * sin(th))
	tmp = 0.0
	if (t_2 <= -0.01)
		tmp = t_1;
	elseif (t_2 <= 0.15)
		tmp = t_3;
	elseif (t_2 <= 0.999999999981754)
		tmp = t_1;
	elseif (t_2 <= 1.0)
		tmp = sin(th);
	else
		tmp = t_3;
	end
	return tmp
end
function tmp_2 = code(kx, ky, th)
	t_1 = (-th * sin(ky)) * (-1.0 / hypot(sin(ky), sin(kx)));
	t_2 = sin(ky) / sqrt(((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)));
	t_3 = ((-1.0 / hypot(sin(kx), sin(ky))) * -ky) * sin(th);
	tmp = 0.0;
	if (t_2 <= -0.01)
		tmp = t_1;
	elseif (t_2 <= 0.15)
		tmp = t_3;
	elseif (t_2 <= 0.999999999981754)
		tmp = t_1;
	elseif (t_2 <= 1.0)
		tmp = sin(th);
	else
		tmp = t_3;
	end
	tmp_2 = tmp;
end
code[kx_, ky_, th_] := Block[{t$95$1 = N[(N[((-th) * N[Sin[ky], $MachinePrecision]), $MachinePrecision] * N[(-1.0 / N[Sqrt[N[Sin[ky], $MachinePrecision] ^ 2 + N[Sin[kx], $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = N[(N[(N[(-1.0 / N[Sqrt[N[Sin[kx], $MachinePrecision] ^ 2 + N[Sin[ky], $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision] * (-ky)), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$2, -0.01], t$95$1, If[LessEqual[t$95$2, 0.15], t$95$3, If[LessEqual[t$95$2, 0.999999999981754], t$95$1, If[LessEqual[t$95$2, 1.0], N[Sin[th], $MachinePrecision], t$95$3]]]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := \left(\left(-th\right) \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}\\
t_2 := \frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}\\
t_3 := \left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \left(-ky\right)\right) \cdot \sin th\\
\mathbf{if}\;t\_2 \leq -0.01:\\
\;\;\;\;t\_1\\

\mathbf{elif}\;t\_2 \leq 0.15:\\
\;\;\;\;t\_3\\

\mathbf{elif}\;t\_2 \leq 0.999999999981754:\\
\;\;\;\;t\_1\\

\mathbf{elif}\;t\_2 \leq 1:\\
\;\;\;\;\sin th\\

\mathbf{else}:\\
\;\;\;\;t\_3\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < -0.0100000000000000002 or 0.149999999999999994 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 0.99999999998175404

    1. Initial program 90.9%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
      2. lift-/.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin th \]
      3. associate-*l/N/A

        \[\leadsto \color{blue}{\frac{\sin ky \cdot \sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      4. frac-2negN/A

        \[\leadsto \color{blue}{\frac{\mathsf{neg}\left(\sin ky \cdot \sin th\right)}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      5. div-invN/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sin ky \cdot \sin th\right)\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      6. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sin ky \cdot \sin th\right)\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      7. distribute-lft-neg-inN/A

        \[\leadsto \color{blue}{\left(\left(\mathsf{neg}\left(\sin ky\right)\right) \cdot \sin th\right)} \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      8. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\left(\mathsf{neg}\left(\sin ky\right)\right) \cdot \sin th\right)} \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      9. lower-neg.f64N/A

        \[\leadsto \left(\color{blue}{\left(-\sin ky\right)} \cdot \sin th\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      10. neg-mul-1N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{1}{\color{blue}{-1 \cdot \sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      11. associate-/r*N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \color{blue}{\frac{\frac{1}{-1}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      12. metadata-evalN/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{\color{blue}{-1}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \]
      13. lower-/.f6489.2

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \color{blue}{\frac{-1}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      14. lift-sqrt.f64N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{-1}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
    4. Applied rewrites95.1%

      \[\leadsto \color{blue}{\left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
    5. Taylor expanded in th around 0

      \[\leadsto \color{blue}{\left(-1 \cdot \left(th \cdot \sin ky\right)\right)} \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
    6. Step-by-step derivation
      1. associate-*r*N/A

        \[\leadsto \color{blue}{\left(\left(-1 \cdot th\right) \cdot \sin ky\right)} \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      2. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\left(-1 \cdot th\right) \cdot \sin ky\right)} \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      3. mul-1-negN/A

        \[\leadsto \left(\color{blue}{\left(\mathsf{neg}\left(th\right)\right)} \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      4. lower-neg.f64N/A

        \[\leadsto \left(\color{blue}{\left(-th\right)} \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      5. lower-sin.f6440.2

        \[\leadsto \left(\left(-th\right) \cdot \color{blue}{\sin ky}\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
    7. Applied rewrites40.2%

      \[\leadsto \color{blue}{\left(\left(-th\right) \cdot \sin ky\right)} \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]

    if -0.0100000000000000002 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 0.149999999999999994 or 1 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))

    1. Initial program 91.9%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
      2. lift-/.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin th \]
      3. associate-*l/N/A

        \[\leadsto \color{blue}{\frac{\sin ky \cdot \sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      4. frac-2negN/A

        \[\leadsto \color{blue}{\frac{\mathsf{neg}\left(\sin ky \cdot \sin th\right)}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      5. div-invN/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sin ky \cdot \sin th\right)\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      6. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sin ky \cdot \sin th\right)\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      7. distribute-lft-neg-inN/A

        \[\leadsto \color{blue}{\left(\left(\mathsf{neg}\left(\sin ky\right)\right) \cdot \sin th\right)} \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      8. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\left(\mathsf{neg}\left(\sin ky\right)\right) \cdot \sin th\right)} \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      9. lower-neg.f64N/A

        \[\leadsto \left(\color{blue}{\left(-\sin ky\right)} \cdot \sin th\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      10. neg-mul-1N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{1}{\color{blue}{-1 \cdot \sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      11. associate-/r*N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \color{blue}{\frac{\frac{1}{-1}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      12. metadata-evalN/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{\color{blue}{-1}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \]
      13. lower-/.f6489.4

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \color{blue}{\frac{-1}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      14. lift-sqrt.f64N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{-1}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
    4. Applied rewrites97.1%

      \[\leadsto \color{blue}{\left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
    5. Taylor expanded in ky around 0

      \[\leadsto \left(\color{blue}{\left(ky \cdot \left(\frac{1}{6} \cdot {ky}^{2} - 1\right)\right)} \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
    6. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto \left(\color{blue}{\left(\left(\frac{1}{6} \cdot {ky}^{2} - 1\right) \cdot ky\right)} \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      2. lower-*.f64N/A

        \[\leadsto \left(\color{blue}{\left(\left(\frac{1}{6} \cdot {ky}^{2} - 1\right) \cdot ky\right)} \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      3. sub-negN/A

        \[\leadsto \left(\left(\color{blue}{\left(\frac{1}{6} \cdot {ky}^{2} + \left(\mathsf{neg}\left(1\right)\right)\right)} \cdot ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      4. metadata-evalN/A

        \[\leadsto \left(\left(\left(\frac{1}{6} \cdot {ky}^{2} + \color{blue}{-1}\right) \cdot ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      5. lower-fma.f64N/A

        \[\leadsto \left(\left(\color{blue}{\mathsf{fma}\left(\frac{1}{6}, {ky}^{2}, -1\right)} \cdot ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      6. unpow2N/A

        \[\leadsto \left(\left(\mathsf{fma}\left(\frac{1}{6}, \color{blue}{ky \cdot ky}, -1\right) \cdot ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      7. lower-*.f6495.1

        \[\leadsto \left(\left(\mathsf{fma}\left(0.16666666666666666, \color{blue}{ky \cdot ky}, -1\right) \cdot ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
    7. Applied rewrites95.1%

      \[\leadsto \left(\color{blue}{\left(\mathsf{fma}\left(0.16666666666666666, ky \cdot ky, -1\right) \cdot ky\right)} \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
    8. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{\left(\left(\mathsf{fma}\left(\frac{1}{6}, ky \cdot ky, -1\right) \cdot ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
      2. *-commutativeN/A

        \[\leadsto \color{blue}{\frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \cdot \left(\left(\mathsf{fma}\left(\frac{1}{6}, ky \cdot ky, -1\right) \cdot ky\right) \cdot \sin th\right)} \]
      3. lift-*.f64N/A

        \[\leadsto \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \cdot \color{blue}{\left(\left(\mathsf{fma}\left(\frac{1}{6}, ky \cdot ky, -1\right) \cdot ky\right) \cdot \sin th\right)} \]
      4. associate-*r*N/A

        \[\leadsto \color{blue}{\left(\frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \cdot \left(\mathsf{fma}\left(\frac{1}{6}, ky \cdot ky, -1\right) \cdot ky\right)\right) \cdot \sin th} \]
      5. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \cdot \left(\mathsf{fma}\left(\frac{1}{6}, ky \cdot ky, -1\right) \cdot ky\right)\right) \cdot \sin th} \]
    9. Applied rewrites97.7%

      \[\leadsto \color{blue}{\left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \left(\mathsf{fma}\left(ky \cdot ky, 0.16666666666666666, -1\right) \cdot ky\right)\right) \cdot \sin th} \]
    10. Taylor expanded in ky around 0

      \[\leadsto \left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \color{blue}{\left(-1 \cdot ky\right)}\right) \cdot \sin th \]
    11. Step-by-step derivation
      1. mul-1-negN/A

        \[\leadsto \left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \color{blue}{\left(\mathsf{neg}\left(ky\right)\right)}\right) \cdot \sin th \]
      2. lower-neg.f6497.7

        \[\leadsto \left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \color{blue}{\left(-ky\right)}\right) \cdot \sin th \]
    12. Applied rewrites97.7%

      \[\leadsto \left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \color{blue}{\left(-ky\right)}\right) \cdot \sin th \]

    if 0.99999999998175404 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 1

    1. Initial program 100.0%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in kx around 0

      \[\leadsto \color{blue}{\sin th} \]
    4. Step-by-step derivation
      1. lower-sin.f64100.0

        \[\leadsto \color{blue}{\sin th} \]
    5. Applied rewrites100.0%

      \[\leadsto \color{blue}{\sin th} \]
  3. Recombined 3 regimes into one program.
  4. Add Preprocessing

Alternative 5: 73.9% accurate, 0.3× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := \left(\left(-th\right) \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}\\ t_2 := {\sin kx}^{2}\\ t_3 := \frac{\sin ky}{\sqrt{t\_2 + {\sin ky}^{2}}}\\ \mathbf{if}\;t\_3 \leq -0.01:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;t\_3 \leq 5 \cdot 10^{-8}:\\ \;\;\;\;\frac{\mathsf{fma}\left(\mathsf{fma}\left(0.008333333333333333, ky \cdot ky, -0.16666666666666666\right), ky \cdot ky, 1\right) \cdot ky}{\sqrt{t\_2 + ky \cdot ky}} \cdot \sin th\\ \mathbf{elif}\;t\_3 \leq 0.999999999981754:\\ \;\;\;\;t\_1\\ \mathbf{else}:\\ \;\;\;\;\sin th\\ \end{array} \end{array} \]
(FPCore (kx ky th)
 :precision binary64
 (let* ((t_1 (* (* (- th) (sin ky)) (/ -1.0 (hypot (sin ky) (sin kx)))))
        (t_2 (pow (sin kx) 2.0))
        (t_3 (/ (sin ky) (sqrt (+ t_2 (pow (sin ky) 2.0))))))
   (if (<= t_3 -0.01)
     t_1
     (if (<= t_3 5e-8)
       (*
        (/
         (*
          (fma
           (fma 0.008333333333333333 (* ky ky) -0.16666666666666666)
           (* ky ky)
           1.0)
          ky)
         (sqrt (+ t_2 (* ky ky))))
        (sin th))
       (if (<= t_3 0.999999999981754) t_1 (sin th))))))
double code(double kx, double ky, double th) {
	double t_1 = (-th * sin(ky)) * (-1.0 / hypot(sin(ky), sin(kx)));
	double t_2 = pow(sin(kx), 2.0);
	double t_3 = sin(ky) / sqrt((t_2 + pow(sin(ky), 2.0)));
	double tmp;
	if (t_3 <= -0.01) {
		tmp = t_1;
	} else if (t_3 <= 5e-8) {
		tmp = ((fma(fma(0.008333333333333333, (ky * ky), -0.16666666666666666), (ky * ky), 1.0) * ky) / sqrt((t_2 + (ky * ky)))) * sin(th);
	} else if (t_3 <= 0.999999999981754) {
		tmp = t_1;
	} else {
		tmp = sin(th);
	}
	return tmp;
}
function code(kx, ky, th)
	t_1 = Float64(Float64(Float64(-th) * sin(ky)) * Float64(-1.0 / hypot(sin(ky), sin(kx))))
	t_2 = sin(kx) ^ 2.0
	t_3 = Float64(sin(ky) / sqrt(Float64(t_2 + (sin(ky) ^ 2.0))))
	tmp = 0.0
	if (t_3 <= -0.01)
		tmp = t_1;
	elseif (t_3 <= 5e-8)
		tmp = Float64(Float64(Float64(fma(fma(0.008333333333333333, Float64(ky * ky), -0.16666666666666666), Float64(ky * ky), 1.0) * ky) / sqrt(Float64(t_2 + Float64(ky * ky)))) * sin(th));
	elseif (t_3 <= 0.999999999981754)
		tmp = t_1;
	else
		tmp = sin(th);
	end
	return tmp
end
code[kx_, ky_, th_] := Block[{t$95$1 = N[(N[((-th) * N[Sin[ky], $MachinePrecision]), $MachinePrecision] * N[(-1.0 / N[Sqrt[N[Sin[ky], $MachinePrecision] ^ 2 + N[Sin[kx], $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision]}, Block[{t$95$3 = N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(t$95$2 + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$3, -0.01], t$95$1, If[LessEqual[t$95$3, 5e-8], N[(N[(N[(N[(N[(0.008333333333333333 * N[(ky * ky), $MachinePrecision] + -0.16666666666666666), $MachinePrecision] * N[(ky * ky), $MachinePrecision] + 1.0), $MachinePrecision] * ky), $MachinePrecision] / N[Sqrt[N[(t$95$2 + N[(ky * ky), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$3, 0.999999999981754], t$95$1, N[Sin[th], $MachinePrecision]]]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := \left(\left(-th\right) \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}\\
t_2 := {\sin kx}^{2}\\
t_3 := \frac{\sin ky}{\sqrt{t\_2 + {\sin ky}^{2}}}\\
\mathbf{if}\;t\_3 \leq -0.01:\\
\;\;\;\;t\_1\\

\mathbf{elif}\;t\_3 \leq 5 \cdot 10^{-8}:\\
\;\;\;\;\frac{\mathsf{fma}\left(\mathsf{fma}\left(0.008333333333333333, ky \cdot ky, -0.16666666666666666\right), ky \cdot ky, 1\right) \cdot ky}{\sqrt{t\_2 + ky \cdot ky}} \cdot \sin th\\

\mathbf{elif}\;t\_3 \leq 0.999999999981754:\\
\;\;\;\;t\_1\\

\mathbf{else}:\\
\;\;\;\;\sin th\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < -0.0100000000000000002 or 4.9999999999999998e-8 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 0.99999999998175404

    1. Initial program 91.0%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
      2. lift-/.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin th \]
      3. associate-*l/N/A

        \[\leadsto \color{blue}{\frac{\sin ky \cdot \sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      4. frac-2negN/A

        \[\leadsto \color{blue}{\frac{\mathsf{neg}\left(\sin ky \cdot \sin th\right)}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      5. div-invN/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sin ky \cdot \sin th\right)\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      6. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sin ky \cdot \sin th\right)\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
      7. distribute-lft-neg-inN/A

        \[\leadsto \color{blue}{\left(\left(\mathsf{neg}\left(\sin ky\right)\right) \cdot \sin th\right)} \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      8. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\left(\mathsf{neg}\left(\sin ky\right)\right) \cdot \sin th\right)} \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      9. lower-neg.f64N/A

        \[\leadsto \left(\color{blue}{\left(-\sin ky\right)} \cdot \sin th\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
      10. neg-mul-1N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{1}{\color{blue}{-1 \cdot \sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      11. associate-/r*N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \color{blue}{\frac{\frac{1}{-1}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      12. metadata-evalN/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{\color{blue}{-1}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \]
      13. lower-/.f6489.4

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \color{blue}{\frac{-1}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      14. lift-sqrt.f64N/A

        \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{-1}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
    4. Applied rewrites95.2%

      \[\leadsto \color{blue}{\left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
    5. Taylor expanded in th around 0

      \[\leadsto \color{blue}{\left(-1 \cdot \left(th \cdot \sin ky\right)\right)} \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
    6. Step-by-step derivation
      1. associate-*r*N/A

        \[\leadsto \color{blue}{\left(\left(-1 \cdot th\right) \cdot \sin ky\right)} \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      2. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(\left(-1 \cdot th\right) \cdot \sin ky\right)} \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      3. mul-1-negN/A

        \[\leadsto \left(\color{blue}{\left(\mathsf{neg}\left(th\right)\right)} \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      4. lower-neg.f64N/A

        \[\leadsto \left(\color{blue}{\left(-th\right)} \cdot \sin ky\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
      5. lower-sin.f6440.4

        \[\leadsto \left(\left(-th\right) \cdot \color{blue}{\sin ky}\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
    7. Applied rewrites40.4%

      \[\leadsto \color{blue}{\left(\left(-th\right) \cdot \sin ky\right)} \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]

    if -0.0100000000000000002 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 4.9999999999999998e-8

    1. Initial program 98.8%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in ky around 0

      \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{{ky}^{2}}}} \cdot \sin th \]
    4. Step-by-step derivation
      1. unpow2N/A

        \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{ky \cdot ky}}} \cdot \sin th \]
      2. lower-*.f6498.8

        \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{ky \cdot ky}}} \cdot \sin th \]
    5. Applied rewrites98.8%

      \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{ky \cdot ky}}} \cdot \sin th \]
    6. Taylor expanded in ky around 0

      \[\leadsto \frac{\color{blue}{ky \cdot \left(1 + {ky}^{2} \cdot \left(\frac{1}{120} \cdot {ky}^{2} - \frac{1}{6}\right)\right)}}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
    7. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto \frac{\color{blue}{\left(1 + {ky}^{2} \cdot \left(\frac{1}{120} \cdot {ky}^{2} - \frac{1}{6}\right)\right) \cdot ky}}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
      2. lower-*.f64N/A

        \[\leadsto \frac{\color{blue}{\left(1 + {ky}^{2} \cdot \left(\frac{1}{120} \cdot {ky}^{2} - \frac{1}{6}\right)\right) \cdot ky}}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
      3. +-commutativeN/A

        \[\leadsto \frac{\color{blue}{\left({ky}^{2} \cdot \left(\frac{1}{120} \cdot {ky}^{2} - \frac{1}{6}\right) + 1\right)} \cdot ky}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
      4. *-commutativeN/A

        \[\leadsto \frac{\left(\color{blue}{\left(\frac{1}{120} \cdot {ky}^{2} - \frac{1}{6}\right) \cdot {ky}^{2}} + 1\right) \cdot ky}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
      5. lower-fma.f64N/A

        \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(\frac{1}{120} \cdot {ky}^{2} - \frac{1}{6}, {ky}^{2}, 1\right)} \cdot ky}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
      6. sub-negN/A

        \[\leadsto \frac{\mathsf{fma}\left(\color{blue}{\frac{1}{120} \cdot {ky}^{2} + \left(\mathsf{neg}\left(\frac{1}{6}\right)\right)}, {ky}^{2}, 1\right) \cdot ky}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
      7. metadata-evalN/A

        \[\leadsto \frac{\mathsf{fma}\left(\frac{1}{120} \cdot {ky}^{2} + \color{blue}{\frac{-1}{6}}, {ky}^{2}, 1\right) \cdot ky}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
      8. lower-fma.f64N/A

        \[\leadsto \frac{\mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(\frac{1}{120}, {ky}^{2}, \frac{-1}{6}\right)}, {ky}^{2}, 1\right) \cdot ky}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
      9. unpow2N/A

        \[\leadsto \frac{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{120}, \color{blue}{ky \cdot ky}, \frac{-1}{6}\right), {ky}^{2}, 1\right) \cdot ky}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
      10. lower-*.f64N/A

        \[\leadsto \frac{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{120}, \color{blue}{ky \cdot ky}, \frac{-1}{6}\right), {ky}^{2}, 1\right) \cdot ky}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
      11. unpow2N/A

        \[\leadsto \frac{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{120}, ky \cdot ky, \frac{-1}{6}\right), \color{blue}{ky \cdot ky}, 1\right) \cdot ky}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
      12. lower-*.f6498.8

        \[\leadsto \frac{\mathsf{fma}\left(\mathsf{fma}\left(0.008333333333333333, ky \cdot ky, -0.16666666666666666\right), \color{blue}{ky \cdot ky}, 1\right) \cdot ky}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
    8. Applied rewrites98.8%

      \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(0.008333333333333333, ky \cdot ky, -0.16666666666666666\right), ky \cdot ky, 1\right) \cdot ky}}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]

    if 0.99999999998175404 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))

    1. Initial program 87.6%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in kx around 0

      \[\leadsto \color{blue}{\sin th} \]
    4. Step-by-step derivation
      1. lower-sin.f6496.6

        \[\leadsto \color{blue}{\sin th} \]
    5. Applied rewrites96.6%

      \[\leadsto \color{blue}{\sin th} \]
  3. Recombined 3 regimes into one program.
  4. Add Preprocessing

Alternative 6: 58.4% accurate, 0.4× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := {\sin kx}^{2}\\ t_2 := \frac{\sin ky}{\sqrt{t\_1 + {\sin ky}^{2}}}\\ \mathbf{if}\;t\_2 \leq -0.01:\\ \;\;\;\;\frac{\sin ky}{\sqrt{0.5} \cdot \sqrt{1 - \cos \left(2 \cdot kx\right)}} \cdot \sin th\\ \mathbf{elif}\;t\_2 \leq 5 \cdot 10^{-8}:\\ \;\;\;\;\frac{\mathsf{fma}\left(\mathsf{fma}\left(0.008333333333333333, ky \cdot ky, -0.16666666666666666\right), ky \cdot ky, 1\right) \cdot ky}{\sqrt{t\_1 + ky \cdot ky}} \cdot \sin th\\ \mathbf{else}:\\ \;\;\;\;\sin th\\ \end{array} \end{array} \]
(FPCore (kx ky th)
 :precision binary64
 (let* ((t_1 (pow (sin kx) 2.0))
        (t_2 (/ (sin ky) (sqrt (+ t_1 (pow (sin ky) 2.0))))))
   (if (<= t_2 -0.01)
     (* (/ (sin ky) (* (sqrt 0.5) (sqrt (- 1.0 (cos (* 2.0 kx)))))) (sin th))
     (if (<= t_2 5e-8)
       (*
        (/
         (*
          (fma
           (fma 0.008333333333333333 (* ky ky) -0.16666666666666666)
           (* ky ky)
           1.0)
          ky)
         (sqrt (+ t_1 (* ky ky))))
        (sin th))
       (sin th)))))
double code(double kx, double ky, double th) {
	double t_1 = pow(sin(kx), 2.0);
	double t_2 = sin(ky) / sqrt((t_1 + pow(sin(ky), 2.0)));
	double tmp;
	if (t_2 <= -0.01) {
		tmp = (sin(ky) / (sqrt(0.5) * sqrt((1.0 - cos((2.0 * kx)))))) * sin(th);
	} else if (t_2 <= 5e-8) {
		tmp = ((fma(fma(0.008333333333333333, (ky * ky), -0.16666666666666666), (ky * ky), 1.0) * ky) / sqrt((t_1 + (ky * ky)))) * sin(th);
	} else {
		tmp = sin(th);
	}
	return tmp;
}
function code(kx, ky, th)
	t_1 = sin(kx) ^ 2.0
	t_2 = Float64(sin(ky) / sqrt(Float64(t_1 + (sin(ky) ^ 2.0))))
	tmp = 0.0
	if (t_2 <= -0.01)
		tmp = Float64(Float64(sin(ky) / Float64(sqrt(0.5) * sqrt(Float64(1.0 - cos(Float64(2.0 * kx)))))) * sin(th));
	elseif (t_2 <= 5e-8)
		tmp = Float64(Float64(Float64(fma(fma(0.008333333333333333, Float64(ky * ky), -0.16666666666666666), Float64(ky * ky), 1.0) * ky) / sqrt(Float64(t_1 + Float64(ky * ky)))) * sin(th));
	else
		tmp = sin(th);
	end
	return tmp
end
code[kx_, ky_, th_] := Block[{t$95$1 = N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision]}, Block[{t$95$2 = N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(t$95$1 + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$2, -0.01], N[(N[(N[Sin[ky], $MachinePrecision] / N[(N[Sqrt[0.5], $MachinePrecision] * N[Sqrt[N[(1.0 - N[Cos[N[(2.0 * kx), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$2, 5e-8], N[(N[(N[(N[(N[(0.008333333333333333 * N[(ky * ky), $MachinePrecision] + -0.16666666666666666), $MachinePrecision] * N[(ky * ky), $MachinePrecision] + 1.0), $MachinePrecision] * ky), $MachinePrecision] / N[Sqrt[N[(t$95$1 + N[(ky * ky), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision], N[Sin[th], $MachinePrecision]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := {\sin kx}^{2}\\
t_2 := \frac{\sin ky}{\sqrt{t\_1 + {\sin ky}^{2}}}\\
\mathbf{if}\;t\_2 \leq -0.01:\\
\;\;\;\;\frac{\sin ky}{\sqrt{0.5} \cdot \sqrt{1 - \cos \left(2 \cdot kx\right)}} \cdot \sin th\\

\mathbf{elif}\;t\_2 \leq 5 \cdot 10^{-8}:\\
\;\;\;\;\frac{\mathsf{fma}\left(\mathsf{fma}\left(0.008333333333333333, ky \cdot ky, -0.16666666666666666\right), ky \cdot ky, 1\right) \cdot ky}{\sqrt{t\_1 + ky \cdot ky}} \cdot \sin th\\

\mathbf{else}:\\
\;\;\;\;\sin th\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < -0.0100000000000000002

    1. Initial program 88.2%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-pow.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{{\sin kx}^{2}} + {\sin ky}^{2}}} \cdot \sin th \]
      2. unpow2N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\sin kx \cdot \sin kx} + {\sin ky}^{2}}} \cdot \sin th \]
      3. lift-sin.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\sin kx} \cdot \sin kx + {\sin ky}^{2}}} \cdot \sin th \]
      4. lift-sin.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\sin kx \cdot \color{blue}{\sin kx} + {\sin ky}^{2}}} \cdot \sin th \]
      5. sin-multN/A

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\frac{\cos \left(kx - kx\right) - \cos \left(kx + kx\right)}{2}} + {\sin ky}^{2}}} \cdot \sin th \]
      6. clear-numN/A

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\frac{1}{\frac{2}{\cos \left(kx - kx\right) - \cos \left(kx + kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
      7. lower-/.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\frac{1}{\frac{2}{\cos \left(kx - kx\right) - \cos \left(kx + kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
      8. lower-/.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{\color{blue}{\frac{2}{\cos \left(kx - kx\right) - \cos \left(kx + kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
      9. cos-diffN/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{\frac{2}{\color{blue}{\left(\cos kx \cdot \cos kx + \sin kx \cdot \sin kx\right)} - \cos \left(kx + kx\right)}} + {\sin ky}^{2}}} \cdot \sin th \]
      10. cos-sin-sumN/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{\frac{2}{\color{blue}{1} - \cos \left(kx + kx\right)}} + {\sin ky}^{2}}} \cdot \sin th \]
      11. lower--.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{\frac{2}{\color{blue}{1 - \cos \left(kx + kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
      12. lower-cos.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{\frac{2}{1 - \color{blue}{\cos \left(kx + kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
      13. count-2N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{\frac{2}{1 - \cos \color{blue}{\left(2 \cdot kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
      14. lower-*.f6488.2

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{\frac{2}{1 - \cos \color{blue}{\left(2 \cdot kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
    4. Applied rewrites88.2%

      \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\frac{1}{\frac{2}{1 - \cos \left(2 \cdot kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
    5. Taylor expanded in ky around 0

      \[\leadsto \frac{\sin ky}{\color{blue}{\sqrt{\frac{1}{2}} \cdot \sqrt{1 - \cos \left(2 \cdot kx\right)}}} \cdot \sin th \]
    6. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto \frac{\sin ky}{\color{blue}{\sqrt{\frac{1}{2}} \cdot \sqrt{1 - \cos \left(2 \cdot kx\right)}}} \cdot \sin th \]
      2. lower-sqrt.f64N/A

        \[\leadsto \frac{\sin ky}{\color{blue}{\sqrt{\frac{1}{2}}} \cdot \sqrt{1 - \cos \left(2 \cdot kx\right)}} \cdot \sin th \]
      3. lower-sqrt.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{2}} \cdot \color{blue}{\sqrt{1 - \cos \left(2 \cdot kx\right)}}} \cdot \sin th \]
      4. lower--.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{2}} \cdot \sqrt{\color{blue}{1 - \cos \left(2 \cdot kx\right)}}} \cdot \sin th \]
      5. lower-cos.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{2}} \cdot \sqrt{1 - \color{blue}{\cos \left(2 \cdot kx\right)}}} \cdot \sin th \]
      6. lower-*.f649.8

        \[\leadsto \frac{\sin ky}{\sqrt{0.5} \cdot \sqrt{1 - \cos \color{blue}{\left(2 \cdot kx\right)}}} \cdot \sin th \]
    7. Applied rewrites9.8%

      \[\leadsto \frac{\sin ky}{\color{blue}{\sqrt{0.5} \cdot \sqrt{1 - \cos \left(2 \cdot kx\right)}}} \cdot \sin th \]

    if -0.0100000000000000002 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 4.9999999999999998e-8

    1. Initial program 98.8%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in ky around 0

      \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{{ky}^{2}}}} \cdot \sin th \]
    4. Step-by-step derivation
      1. unpow2N/A

        \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{ky \cdot ky}}} \cdot \sin th \]
      2. lower-*.f6498.8

        \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{ky \cdot ky}}} \cdot \sin th \]
    5. Applied rewrites98.8%

      \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{ky \cdot ky}}} \cdot \sin th \]
    6. Taylor expanded in ky around 0

      \[\leadsto \frac{\color{blue}{ky \cdot \left(1 + {ky}^{2} \cdot \left(\frac{1}{120} \cdot {ky}^{2} - \frac{1}{6}\right)\right)}}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
    7. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto \frac{\color{blue}{\left(1 + {ky}^{2} \cdot \left(\frac{1}{120} \cdot {ky}^{2} - \frac{1}{6}\right)\right) \cdot ky}}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
      2. lower-*.f64N/A

        \[\leadsto \frac{\color{blue}{\left(1 + {ky}^{2} \cdot \left(\frac{1}{120} \cdot {ky}^{2} - \frac{1}{6}\right)\right) \cdot ky}}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
      3. +-commutativeN/A

        \[\leadsto \frac{\color{blue}{\left({ky}^{2} \cdot \left(\frac{1}{120} \cdot {ky}^{2} - \frac{1}{6}\right) + 1\right)} \cdot ky}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
      4. *-commutativeN/A

        \[\leadsto \frac{\left(\color{blue}{\left(\frac{1}{120} \cdot {ky}^{2} - \frac{1}{6}\right) \cdot {ky}^{2}} + 1\right) \cdot ky}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
      5. lower-fma.f64N/A

        \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(\frac{1}{120} \cdot {ky}^{2} - \frac{1}{6}, {ky}^{2}, 1\right)} \cdot ky}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
      6. sub-negN/A

        \[\leadsto \frac{\mathsf{fma}\left(\color{blue}{\frac{1}{120} \cdot {ky}^{2} + \left(\mathsf{neg}\left(\frac{1}{6}\right)\right)}, {ky}^{2}, 1\right) \cdot ky}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
      7. metadata-evalN/A

        \[\leadsto \frac{\mathsf{fma}\left(\frac{1}{120} \cdot {ky}^{2} + \color{blue}{\frac{-1}{6}}, {ky}^{2}, 1\right) \cdot ky}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
      8. lower-fma.f64N/A

        \[\leadsto \frac{\mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(\frac{1}{120}, {ky}^{2}, \frac{-1}{6}\right)}, {ky}^{2}, 1\right) \cdot ky}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
      9. unpow2N/A

        \[\leadsto \frac{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{120}, \color{blue}{ky \cdot ky}, \frac{-1}{6}\right), {ky}^{2}, 1\right) \cdot ky}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
      10. lower-*.f64N/A

        \[\leadsto \frac{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{120}, \color{blue}{ky \cdot ky}, \frac{-1}{6}\right), {ky}^{2}, 1\right) \cdot ky}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
      11. unpow2N/A

        \[\leadsto \frac{\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{120}, ky \cdot ky, \frac{-1}{6}\right), \color{blue}{ky \cdot ky}, 1\right) \cdot ky}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
      12. lower-*.f6498.8

        \[\leadsto \frac{\mathsf{fma}\left(\mathsf{fma}\left(0.008333333333333333, ky \cdot ky, -0.16666666666666666\right), \color{blue}{ky \cdot ky}, 1\right) \cdot ky}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
    8. Applied rewrites98.8%

      \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(0.008333333333333333, ky \cdot ky, -0.16666666666666666\right), ky \cdot ky, 1\right) \cdot ky}}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]

    if 4.9999999999999998e-8 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))

    1. Initial program 91.5%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in kx around 0

      \[\leadsto \color{blue}{\sin th} \]
    4. Step-by-step derivation
      1. lower-sin.f6469.6

        \[\leadsto \color{blue}{\sin th} \]
    5. Applied rewrites69.6%

      \[\leadsto \color{blue}{\sin th} \]
  3. Recombined 3 regimes into one program.
  4. Add Preprocessing

Alternative 7: 58.4% accurate, 0.4× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := {\sin kx}^{2}\\ t_2 := \frac{\sin ky}{\sqrt{t\_1 + {\sin ky}^{2}}}\\ \mathbf{if}\;t\_2 \leq -0.01:\\ \;\;\;\;\frac{\sin ky}{\sqrt{0.5} \cdot \sqrt{1 - \cos \left(2 \cdot kx\right)}} \cdot \sin th\\ \mathbf{elif}\;t\_2 \leq 5 \cdot 10^{-8}:\\ \;\;\;\;\frac{\mathsf{fma}\left(-0.16666666666666666, ky \cdot ky, 1\right) \cdot ky}{\sqrt{t\_1 + ky \cdot ky}} \cdot \sin th\\ \mathbf{else}:\\ \;\;\;\;\sin th\\ \end{array} \end{array} \]
(FPCore (kx ky th)
 :precision binary64
 (let* ((t_1 (pow (sin kx) 2.0))
        (t_2 (/ (sin ky) (sqrt (+ t_1 (pow (sin ky) 2.0))))))
   (if (<= t_2 -0.01)
     (* (/ (sin ky) (* (sqrt 0.5) (sqrt (- 1.0 (cos (* 2.0 kx)))))) (sin th))
     (if (<= t_2 5e-8)
       (*
        (/
         (* (fma -0.16666666666666666 (* ky ky) 1.0) ky)
         (sqrt (+ t_1 (* ky ky))))
        (sin th))
       (sin th)))))
double code(double kx, double ky, double th) {
	double t_1 = pow(sin(kx), 2.0);
	double t_2 = sin(ky) / sqrt((t_1 + pow(sin(ky), 2.0)));
	double tmp;
	if (t_2 <= -0.01) {
		tmp = (sin(ky) / (sqrt(0.5) * sqrt((1.0 - cos((2.0 * kx)))))) * sin(th);
	} else if (t_2 <= 5e-8) {
		tmp = ((fma(-0.16666666666666666, (ky * ky), 1.0) * ky) / sqrt((t_1 + (ky * ky)))) * sin(th);
	} else {
		tmp = sin(th);
	}
	return tmp;
}
function code(kx, ky, th)
	t_1 = sin(kx) ^ 2.0
	t_2 = Float64(sin(ky) / sqrt(Float64(t_1 + (sin(ky) ^ 2.0))))
	tmp = 0.0
	if (t_2 <= -0.01)
		tmp = Float64(Float64(sin(ky) / Float64(sqrt(0.5) * sqrt(Float64(1.0 - cos(Float64(2.0 * kx)))))) * sin(th));
	elseif (t_2 <= 5e-8)
		tmp = Float64(Float64(Float64(fma(-0.16666666666666666, Float64(ky * ky), 1.0) * ky) / sqrt(Float64(t_1 + Float64(ky * ky)))) * sin(th));
	else
		tmp = sin(th);
	end
	return tmp
end
code[kx_, ky_, th_] := Block[{t$95$1 = N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision]}, Block[{t$95$2 = N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(t$95$1 + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$2, -0.01], N[(N[(N[Sin[ky], $MachinePrecision] / N[(N[Sqrt[0.5], $MachinePrecision] * N[Sqrt[N[(1.0 - N[Cos[N[(2.0 * kx), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$2, 5e-8], N[(N[(N[(N[(-0.16666666666666666 * N[(ky * ky), $MachinePrecision] + 1.0), $MachinePrecision] * ky), $MachinePrecision] / N[Sqrt[N[(t$95$1 + N[(ky * ky), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision], N[Sin[th], $MachinePrecision]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := {\sin kx}^{2}\\
t_2 := \frac{\sin ky}{\sqrt{t\_1 + {\sin ky}^{2}}}\\
\mathbf{if}\;t\_2 \leq -0.01:\\
\;\;\;\;\frac{\sin ky}{\sqrt{0.5} \cdot \sqrt{1 - \cos \left(2 \cdot kx\right)}} \cdot \sin th\\

\mathbf{elif}\;t\_2 \leq 5 \cdot 10^{-8}:\\
\;\;\;\;\frac{\mathsf{fma}\left(-0.16666666666666666, ky \cdot ky, 1\right) \cdot ky}{\sqrt{t\_1 + ky \cdot ky}} \cdot \sin th\\

\mathbf{else}:\\
\;\;\;\;\sin th\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < -0.0100000000000000002

    1. Initial program 88.2%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-pow.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{{\sin kx}^{2}} + {\sin ky}^{2}}} \cdot \sin th \]
      2. unpow2N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\sin kx \cdot \sin kx} + {\sin ky}^{2}}} \cdot \sin th \]
      3. lift-sin.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\sin kx} \cdot \sin kx + {\sin ky}^{2}}} \cdot \sin th \]
      4. lift-sin.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\sin kx \cdot \color{blue}{\sin kx} + {\sin ky}^{2}}} \cdot \sin th \]
      5. sin-multN/A

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\frac{\cos \left(kx - kx\right) - \cos \left(kx + kx\right)}{2}} + {\sin ky}^{2}}} \cdot \sin th \]
      6. clear-numN/A

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\frac{1}{\frac{2}{\cos \left(kx - kx\right) - \cos \left(kx + kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
      7. lower-/.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\frac{1}{\frac{2}{\cos \left(kx - kx\right) - \cos \left(kx + kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
      8. lower-/.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{\color{blue}{\frac{2}{\cos \left(kx - kx\right) - \cos \left(kx + kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
      9. cos-diffN/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{\frac{2}{\color{blue}{\left(\cos kx \cdot \cos kx + \sin kx \cdot \sin kx\right)} - \cos \left(kx + kx\right)}} + {\sin ky}^{2}}} \cdot \sin th \]
      10. cos-sin-sumN/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{\frac{2}{\color{blue}{1} - \cos \left(kx + kx\right)}} + {\sin ky}^{2}}} \cdot \sin th \]
      11. lower--.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{\frac{2}{\color{blue}{1 - \cos \left(kx + kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
      12. lower-cos.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{\frac{2}{1 - \color{blue}{\cos \left(kx + kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
      13. count-2N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{\frac{2}{1 - \cos \color{blue}{\left(2 \cdot kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
      14. lower-*.f6488.2

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{\frac{2}{1 - \cos \color{blue}{\left(2 \cdot kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
    4. Applied rewrites88.2%

      \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\frac{1}{\frac{2}{1 - \cos \left(2 \cdot kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
    5. Taylor expanded in ky around 0

      \[\leadsto \frac{\sin ky}{\color{blue}{\sqrt{\frac{1}{2}} \cdot \sqrt{1 - \cos \left(2 \cdot kx\right)}}} \cdot \sin th \]
    6. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto \frac{\sin ky}{\color{blue}{\sqrt{\frac{1}{2}} \cdot \sqrt{1 - \cos \left(2 \cdot kx\right)}}} \cdot \sin th \]
      2. lower-sqrt.f64N/A

        \[\leadsto \frac{\sin ky}{\color{blue}{\sqrt{\frac{1}{2}}} \cdot \sqrt{1 - \cos \left(2 \cdot kx\right)}} \cdot \sin th \]
      3. lower-sqrt.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{2}} \cdot \color{blue}{\sqrt{1 - \cos \left(2 \cdot kx\right)}}} \cdot \sin th \]
      4. lower--.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{2}} \cdot \sqrt{\color{blue}{1 - \cos \left(2 \cdot kx\right)}}} \cdot \sin th \]
      5. lower-cos.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{2}} \cdot \sqrt{1 - \color{blue}{\cos \left(2 \cdot kx\right)}}} \cdot \sin th \]
      6. lower-*.f649.8

        \[\leadsto \frac{\sin ky}{\sqrt{0.5} \cdot \sqrt{1 - \cos \color{blue}{\left(2 \cdot kx\right)}}} \cdot \sin th \]
    7. Applied rewrites9.8%

      \[\leadsto \frac{\sin ky}{\color{blue}{\sqrt{0.5} \cdot \sqrt{1 - \cos \left(2 \cdot kx\right)}}} \cdot \sin th \]

    if -0.0100000000000000002 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 4.9999999999999998e-8

    1. Initial program 98.8%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in ky around 0

      \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{{ky}^{2}}}} \cdot \sin th \]
    4. Step-by-step derivation
      1. unpow2N/A

        \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{ky \cdot ky}}} \cdot \sin th \]
      2. lower-*.f6498.8

        \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{ky \cdot ky}}} \cdot \sin th \]
    5. Applied rewrites98.8%

      \[\leadsto \frac{\sin ky}{\sqrt{{\sin kx}^{2} + \color{blue}{ky \cdot ky}}} \cdot \sin th \]
    6. Taylor expanded in ky around 0

      \[\leadsto \frac{\color{blue}{ky \cdot \left(1 + \frac{-1}{6} \cdot {ky}^{2}\right)}}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
    7. Step-by-step derivation
      1. *-commutativeN/A

        \[\leadsto \frac{\color{blue}{\left(1 + \frac{-1}{6} \cdot {ky}^{2}\right) \cdot ky}}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
      2. lower-*.f64N/A

        \[\leadsto \frac{\color{blue}{\left(1 + \frac{-1}{6} \cdot {ky}^{2}\right) \cdot ky}}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
      3. +-commutativeN/A

        \[\leadsto \frac{\color{blue}{\left(\frac{-1}{6} \cdot {ky}^{2} + 1\right)} \cdot ky}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
      4. lower-fma.f64N/A

        \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(\frac{-1}{6}, {ky}^{2}, 1\right)} \cdot ky}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
      5. unpow2N/A

        \[\leadsto \frac{\mathsf{fma}\left(\frac{-1}{6}, \color{blue}{ky \cdot ky}, 1\right) \cdot ky}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
      6. lower-*.f6498.8

        \[\leadsto \frac{\mathsf{fma}\left(-0.16666666666666666, \color{blue}{ky \cdot ky}, 1\right) \cdot ky}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]
    8. Applied rewrites98.8%

      \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(-0.16666666666666666, ky \cdot ky, 1\right) \cdot ky}}{\sqrt{{\sin kx}^{2} + ky \cdot ky}} \cdot \sin th \]

    if 4.9999999999999998e-8 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))

    1. Initial program 91.5%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in kx around 0

      \[\leadsto \color{blue}{\sin th} \]
    4. Step-by-step derivation
      1. lower-sin.f6469.6

        \[\leadsto \color{blue}{\sin th} \]
    5. Applied rewrites69.6%

      \[\leadsto \color{blue}{\sin th} \]
  3. Recombined 3 regimes into one program.
  4. Add Preprocessing

Alternative 8: 48.7% accurate, 0.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := \frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}\\ \mathbf{if}\;t\_1 \leq 2 \cdot 10^{-184}:\\ \;\;\;\;\frac{\sin ky}{\sqrt{0.5} \cdot \sqrt{1 - \cos \left(2 \cdot kx\right)}} \cdot \sin th\\ \mathbf{elif}\;t\_1 \leq 5 \cdot 10^{-8}:\\ \;\;\;\;\frac{ky}{\sin kx} \cdot \sin th\\ \mathbf{else}:\\ \;\;\;\;\sin th\\ \end{array} \end{array} \]
(FPCore (kx ky th)
 :precision binary64
 (let* ((t_1 (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0))))))
   (if (<= t_1 2e-184)
     (* (/ (sin ky) (* (sqrt 0.5) (sqrt (- 1.0 (cos (* 2.0 kx)))))) (sin th))
     (if (<= t_1 5e-8) (* (/ ky (sin kx)) (sin th)) (sin th)))))
double code(double kx, double ky, double th) {
	double t_1 = sin(ky) / sqrt((pow(sin(kx), 2.0) + pow(sin(ky), 2.0)));
	double tmp;
	if (t_1 <= 2e-184) {
		tmp = (sin(ky) / (sqrt(0.5) * sqrt((1.0 - cos((2.0 * kx)))))) * sin(th);
	} else if (t_1 <= 5e-8) {
		tmp = (ky / sin(kx)) * sin(th);
	} else {
		tmp = sin(th);
	}
	return tmp;
}
real(8) function code(kx, ky, th)
    real(8), intent (in) :: kx
    real(8), intent (in) :: ky
    real(8), intent (in) :: th
    real(8) :: t_1
    real(8) :: tmp
    t_1 = sin(ky) / sqrt(((sin(kx) ** 2.0d0) + (sin(ky) ** 2.0d0)))
    if (t_1 <= 2d-184) then
        tmp = (sin(ky) / (sqrt(0.5d0) * sqrt((1.0d0 - cos((2.0d0 * kx)))))) * sin(th)
    else if (t_1 <= 5d-8) then
        tmp = (ky / sin(kx)) * sin(th)
    else
        tmp = sin(th)
    end if
    code = tmp
end function
public static double code(double kx, double ky, double th) {
	double t_1 = Math.sin(ky) / Math.sqrt((Math.pow(Math.sin(kx), 2.0) + Math.pow(Math.sin(ky), 2.0)));
	double tmp;
	if (t_1 <= 2e-184) {
		tmp = (Math.sin(ky) / (Math.sqrt(0.5) * Math.sqrt((1.0 - Math.cos((2.0 * kx)))))) * Math.sin(th);
	} else if (t_1 <= 5e-8) {
		tmp = (ky / Math.sin(kx)) * Math.sin(th);
	} else {
		tmp = Math.sin(th);
	}
	return tmp;
}
def code(kx, ky, th):
	t_1 = math.sin(ky) / math.sqrt((math.pow(math.sin(kx), 2.0) + math.pow(math.sin(ky), 2.0)))
	tmp = 0
	if t_1 <= 2e-184:
		tmp = (math.sin(ky) / (math.sqrt(0.5) * math.sqrt((1.0 - math.cos((2.0 * kx)))))) * math.sin(th)
	elif t_1 <= 5e-8:
		tmp = (ky / math.sin(kx)) * math.sin(th)
	else:
		tmp = math.sin(th)
	return tmp
function code(kx, ky, th)
	t_1 = Float64(sin(ky) / sqrt(Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0))))
	tmp = 0.0
	if (t_1 <= 2e-184)
		tmp = Float64(Float64(sin(ky) / Float64(sqrt(0.5) * sqrt(Float64(1.0 - cos(Float64(2.0 * kx)))))) * sin(th));
	elseif (t_1 <= 5e-8)
		tmp = Float64(Float64(ky / sin(kx)) * sin(th));
	else
		tmp = sin(th);
	end
	return tmp
end
function tmp_2 = code(kx, ky, th)
	t_1 = sin(ky) / sqrt(((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)));
	tmp = 0.0;
	if (t_1 <= 2e-184)
		tmp = (sin(ky) / (sqrt(0.5) * sqrt((1.0 - cos((2.0 * kx)))))) * sin(th);
	elseif (t_1 <= 5e-8)
		tmp = (ky / sin(kx)) * sin(th);
	else
		tmp = sin(th);
	end
	tmp_2 = tmp;
end
code[kx_, ky_, th_] := Block[{t$95$1 = N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$1, 2e-184], N[(N[(N[Sin[ky], $MachinePrecision] / N[(N[Sqrt[0.5], $MachinePrecision] * N[Sqrt[N[(1.0 - N[Cos[N[(2.0 * kx), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$1, 5e-8], N[(N[(ky / N[Sin[kx], $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision], N[Sin[th], $MachinePrecision]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := \frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}\\
\mathbf{if}\;t\_1 \leq 2 \cdot 10^{-184}:\\
\;\;\;\;\frac{\sin ky}{\sqrt{0.5} \cdot \sqrt{1 - \cos \left(2 \cdot kx\right)}} \cdot \sin th\\

\mathbf{elif}\;t\_1 \leq 5 \cdot 10^{-8}:\\
\;\;\;\;\frac{ky}{\sin kx} \cdot \sin th\\

\mathbf{else}:\\
\;\;\;\;\sin th\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 2.0000000000000001e-184

    1. Initial program 92.8%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-pow.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{{\sin kx}^{2}} + {\sin ky}^{2}}} \cdot \sin th \]
      2. unpow2N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\sin kx \cdot \sin kx} + {\sin ky}^{2}}} \cdot \sin th \]
      3. lift-sin.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\sin kx} \cdot \sin kx + {\sin ky}^{2}}} \cdot \sin th \]
      4. lift-sin.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\sin kx \cdot \color{blue}{\sin kx} + {\sin ky}^{2}}} \cdot \sin th \]
      5. sin-multN/A

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\frac{\cos \left(kx - kx\right) - \cos \left(kx + kx\right)}{2}} + {\sin ky}^{2}}} \cdot \sin th \]
      6. clear-numN/A

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\frac{1}{\frac{2}{\cos \left(kx - kx\right) - \cos \left(kx + kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
      7. lower-/.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\frac{1}{\frac{2}{\cos \left(kx - kx\right) - \cos \left(kx + kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
      8. lower-/.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{\color{blue}{\frac{2}{\cos \left(kx - kx\right) - \cos \left(kx + kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
      9. cos-diffN/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{\frac{2}{\color{blue}{\left(\cos kx \cdot \cos kx + \sin kx \cdot \sin kx\right)} - \cos \left(kx + kx\right)}} + {\sin ky}^{2}}} \cdot \sin th \]
      10. cos-sin-sumN/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{\frac{2}{\color{blue}{1} - \cos \left(kx + kx\right)}} + {\sin ky}^{2}}} \cdot \sin th \]
      11. lower--.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{\frac{2}{\color{blue}{1 - \cos \left(kx + kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
      12. lower-cos.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{\frac{2}{1 - \color{blue}{\cos \left(kx + kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
      13. count-2N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{\frac{2}{1 - \cos \color{blue}{\left(2 \cdot kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
      14. lower-*.f6480.9

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{\frac{2}{1 - \cos \color{blue}{\left(2 \cdot kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
    4. Applied rewrites80.9%

      \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\frac{1}{\frac{2}{1 - \cos \left(2 \cdot kx\right)}}} + {\sin ky}^{2}}} \cdot \sin th \]
    5. Taylor expanded in ky around 0

      \[\leadsto \frac{\sin ky}{\color{blue}{\sqrt{\frac{1}{2}} \cdot \sqrt{1 - \cos \left(2 \cdot kx\right)}}} \cdot \sin th \]
    6. Step-by-step derivation
      1. lower-*.f64N/A

        \[\leadsto \frac{\sin ky}{\color{blue}{\sqrt{\frac{1}{2}} \cdot \sqrt{1 - \cos \left(2 \cdot kx\right)}}} \cdot \sin th \]
      2. lower-sqrt.f64N/A

        \[\leadsto \frac{\sin ky}{\color{blue}{\sqrt{\frac{1}{2}}} \cdot \sqrt{1 - \cos \left(2 \cdot kx\right)}} \cdot \sin th \]
      3. lower-sqrt.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{2}} \cdot \color{blue}{\sqrt{1 - \cos \left(2 \cdot kx\right)}}} \cdot \sin th \]
      4. lower--.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{2}} \cdot \sqrt{\color{blue}{1 - \cos \left(2 \cdot kx\right)}}} \cdot \sin th \]
      5. lower-cos.f64N/A

        \[\leadsto \frac{\sin ky}{\sqrt{\frac{1}{2}} \cdot \sqrt{1 - \color{blue}{\cos \left(2 \cdot kx\right)}}} \cdot \sin th \]
      6. lower-*.f6434.0

        \[\leadsto \frac{\sin ky}{\sqrt{0.5} \cdot \sqrt{1 - \cos \color{blue}{\left(2 \cdot kx\right)}}} \cdot \sin th \]
    7. Applied rewrites34.0%

      \[\leadsto \frac{\sin ky}{\color{blue}{\sqrt{0.5} \cdot \sqrt{1 - \cos \left(2 \cdot kx\right)}}} \cdot \sin th \]

    if 2.0000000000000001e-184 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 4.9999999999999998e-8

    1. Initial program 97.4%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in ky around 0

      \[\leadsto \color{blue}{\frac{ky}{\sin kx}} \cdot \sin th \]
    4. Step-by-step derivation
      1. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{ky}{\sin kx}} \cdot \sin th \]
      2. lower-sin.f6454.1

        \[\leadsto \frac{ky}{\color{blue}{\sin kx}} \cdot \sin th \]
    5. Applied rewrites54.1%

      \[\leadsto \color{blue}{\frac{ky}{\sin kx}} \cdot \sin th \]

    if 4.9999999999999998e-8 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))

    1. Initial program 91.5%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in kx around 0

      \[\leadsto \color{blue}{\sin th} \]
    4. Step-by-step derivation
      1. lower-sin.f6469.6

        \[\leadsto \color{blue}{\sin th} \]
    5. Applied rewrites69.6%

      \[\leadsto \color{blue}{\sin th} \]
  3. Recombined 3 regimes into one program.
  4. Add Preprocessing

Alternative 9: 45.7% accurate, 0.7× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 5 \cdot 10^{-8}:\\ \;\;\;\;\frac{\sin ky}{\sin kx} \cdot \sin th\\ \mathbf{else}:\\ \;\;\;\;\sin th\\ \end{array} \end{array} \]
(FPCore (kx ky th)
 :precision binary64
 (if (<= (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0)))) 5e-8)
   (* (/ (sin ky) (sin kx)) (sin th))
   (sin th)))
double code(double kx, double ky, double th) {
	double tmp;
	if ((sin(ky) / sqrt((pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))) <= 5e-8) {
		tmp = (sin(ky) / sin(kx)) * sin(th);
	} else {
		tmp = sin(th);
	}
	return tmp;
}
real(8) function code(kx, ky, th)
    real(8), intent (in) :: kx
    real(8), intent (in) :: ky
    real(8), intent (in) :: th
    real(8) :: tmp
    if ((sin(ky) / sqrt(((sin(kx) ** 2.0d0) + (sin(ky) ** 2.0d0)))) <= 5d-8) then
        tmp = (sin(ky) / sin(kx)) * sin(th)
    else
        tmp = sin(th)
    end if
    code = tmp
end function
public static double code(double kx, double ky, double th) {
	double tmp;
	if ((Math.sin(ky) / Math.sqrt((Math.pow(Math.sin(kx), 2.0) + Math.pow(Math.sin(ky), 2.0)))) <= 5e-8) {
		tmp = (Math.sin(ky) / Math.sin(kx)) * Math.sin(th);
	} else {
		tmp = Math.sin(th);
	}
	return tmp;
}
def code(kx, ky, th):
	tmp = 0
	if (math.sin(ky) / math.sqrt((math.pow(math.sin(kx), 2.0) + math.pow(math.sin(ky), 2.0)))) <= 5e-8:
		tmp = (math.sin(ky) / math.sin(kx)) * math.sin(th)
	else:
		tmp = math.sin(th)
	return tmp
function code(kx, ky, th)
	tmp = 0.0
	if (Float64(sin(ky) / sqrt(Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) <= 5e-8)
		tmp = Float64(Float64(sin(ky) / sin(kx)) * sin(th));
	else
		tmp = sin(th);
	end
	return tmp
end
function tmp_2 = code(kx, ky, th)
	tmp = 0.0;
	if ((sin(ky) / sqrt(((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) <= 5e-8)
		tmp = (sin(ky) / sin(kx)) * sin(th);
	else
		tmp = sin(th);
	end
	tmp_2 = tmp;
end
code[kx_, ky_, th_] := If[LessEqual[N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 5e-8], N[(N[(N[Sin[ky], $MachinePrecision] / N[Sin[kx], $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision], N[Sin[th], $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 5 \cdot 10^{-8}:\\
\;\;\;\;\frac{\sin ky}{\sin kx} \cdot \sin th\\

\mathbf{else}:\\
\;\;\;\;\sin th\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 4.9999999999999998e-8

    1. Initial program 93.8%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in ky around 0

      \[\leadsto \frac{\sin ky}{\color{blue}{\sin kx}} \cdot \sin th \]
    4. Step-by-step derivation
      1. lower-sin.f6438.3

        \[\leadsto \frac{\sin ky}{\color{blue}{\sin kx}} \cdot \sin th \]
    5. Applied rewrites38.3%

      \[\leadsto \frac{\sin ky}{\color{blue}{\sin kx}} \cdot \sin th \]

    if 4.9999999999999998e-8 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))

    1. Initial program 91.5%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in kx around 0

      \[\leadsto \color{blue}{\sin th} \]
    4. Step-by-step derivation
      1. lower-sin.f6469.6

        \[\leadsto \color{blue}{\sin th} \]
    5. Applied rewrites69.6%

      \[\leadsto \color{blue}{\sin th} \]
  3. Recombined 2 regimes into one program.
  4. Add Preprocessing

Alternative 10: 44.6% accurate, 0.8× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 5 \cdot 10^{-8}:\\ \;\;\;\;\frac{ky}{\sin kx} \cdot \sin th\\ \mathbf{else}:\\ \;\;\;\;\sin th\\ \end{array} \end{array} \]
(FPCore (kx ky th)
 :precision binary64
 (if (<= (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0)))) 5e-8)
   (* (/ ky (sin kx)) (sin th))
   (sin th)))
double code(double kx, double ky, double th) {
	double tmp;
	if ((sin(ky) / sqrt((pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))) <= 5e-8) {
		tmp = (ky / sin(kx)) * sin(th);
	} else {
		tmp = sin(th);
	}
	return tmp;
}
real(8) function code(kx, ky, th)
    real(8), intent (in) :: kx
    real(8), intent (in) :: ky
    real(8), intent (in) :: th
    real(8) :: tmp
    if ((sin(ky) / sqrt(((sin(kx) ** 2.0d0) + (sin(ky) ** 2.0d0)))) <= 5d-8) then
        tmp = (ky / sin(kx)) * sin(th)
    else
        tmp = sin(th)
    end if
    code = tmp
end function
public static double code(double kx, double ky, double th) {
	double tmp;
	if ((Math.sin(ky) / Math.sqrt((Math.pow(Math.sin(kx), 2.0) + Math.pow(Math.sin(ky), 2.0)))) <= 5e-8) {
		tmp = (ky / Math.sin(kx)) * Math.sin(th);
	} else {
		tmp = Math.sin(th);
	}
	return tmp;
}
def code(kx, ky, th):
	tmp = 0
	if (math.sin(ky) / math.sqrt((math.pow(math.sin(kx), 2.0) + math.pow(math.sin(ky), 2.0)))) <= 5e-8:
		tmp = (ky / math.sin(kx)) * math.sin(th)
	else:
		tmp = math.sin(th)
	return tmp
function code(kx, ky, th)
	tmp = 0.0
	if (Float64(sin(ky) / sqrt(Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) <= 5e-8)
		tmp = Float64(Float64(ky / sin(kx)) * sin(th));
	else
		tmp = sin(th);
	end
	return tmp
end
function tmp_2 = code(kx, ky, th)
	tmp = 0.0;
	if ((sin(ky) / sqrt(((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) <= 5e-8)
		tmp = (ky / sin(kx)) * sin(th);
	else
		tmp = sin(th);
	end
	tmp_2 = tmp;
end
code[kx_, ky_, th_] := If[LessEqual[N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 5e-8], N[(N[(ky / N[Sin[kx], $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision], N[Sin[th], $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 5 \cdot 10^{-8}:\\
\;\;\;\;\frac{ky}{\sin kx} \cdot \sin th\\

\mathbf{else}:\\
\;\;\;\;\sin th\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 4.9999999999999998e-8

    1. Initial program 93.8%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in ky around 0

      \[\leadsto \color{blue}{\frac{ky}{\sin kx}} \cdot \sin th \]
    4. Step-by-step derivation
      1. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{ky}{\sin kx}} \cdot \sin th \]
      2. lower-sin.f6436.5

        \[\leadsto \frac{ky}{\color{blue}{\sin kx}} \cdot \sin th \]
    5. Applied rewrites36.5%

      \[\leadsto \color{blue}{\frac{ky}{\sin kx}} \cdot \sin th \]

    if 4.9999999999999998e-8 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))

    1. Initial program 91.5%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Taylor expanded in kx around 0

      \[\leadsto \color{blue}{\sin th} \]
    4. Step-by-step derivation
      1. lower-sin.f6469.6

        \[\leadsto \color{blue}{\sin th} \]
    5. Applied rewrites69.6%

      \[\leadsto \color{blue}{\sin th} \]
  3. Recombined 2 regimes into one program.
  4. Add Preprocessing

Alternative 11: 31.3% accurate, 0.9× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 5 \cdot 10^{-62}:\\ \;\;\;\;\frac{\sin th}{\mathsf{fma}\left(\frac{0.5}{ky \cdot ky}, kx \cdot kx, 1\right)}\\ \mathbf{else}:\\ \;\;\;\;\sin th\\ \end{array} \end{array} \]
(FPCore (kx ky th)
 :precision binary64
 (if (<= (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0)))) 5e-62)
   (/ (sin th) (fma (/ 0.5 (* ky ky)) (* kx kx) 1.0))
   (sin th)))
double code(double kx, double ky, double th) {
	double tmp;
	if ((sin(ky) / sqrt((pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))) <= 5e-62) {
		tmp = sin(th) / fma((0.5 / (ky * ky)), (kx * kx), 1.0);
	} else {
		tmp = sin(th);
	}
	return tmp;
}
function code(kx, ky, th)
	tmp = 0.0
	if (Float64(sin(ky) / sqrt(Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) <= 5e-62)
		tmp = Float64(sin(th) / fma(Float64(0.5 / Float64(ky * ky)), Float64(kx * kx), 1.0));
	else
		tmp = sin(th);
	end
	return tmp
end
code[kx_, ky_, th_] := If[LessEqual[N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 5e-62], N[(N[Sin[th], $MachinePrecision] / N[(N[(0.5 / N[(ky * ky), $MachinePrecision]), $MachinePrecision] * N[(kx * kx), $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision], N[Sin[th], $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 5 \cdot 10^{-62}:\\
\;\;\;\;\frac{\sin th}{\mathsf{fma}\left(\frac{0.5}{ky \cdot ky}, kx \cdot kx, 1\right)}\\

\mathbf{else}:\\
\;\;\;\;\sin th\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 5.0000000000000002e-62

    1. Initial program 93.5%

      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-*.f64N/A

        \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
      2. *-commutativeN/A

        \[\leadsto \color{blue}{\sin th \cdot \frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      3. lift-/.f64N/A

        \[\leadsto \sin th \cdot \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
      4. clear-numN/A

        \[\leadsto \sin th \cdot \color{blue}{\frac{1}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
      5. un-div-invN/A

        \[\leadsto \color{blue}{\frac{\sin th}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
      6. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{\sin th}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
      7. lower-/.f6493.5

        \[\leadsto \frac{\sin th}{\color{blue}{\frac{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}{\sin ky}}} \]
      8. lift-sqrt.f64N/A

        \[\leadsto \frac{\sin th}{\frac{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}}{\sin ky}} \]
      9. lift-+.f64N/A

        \[\leadsto \frac{\sin th}{\frac{\sqrt{\color{blue}{{\sin kx}^{2} + {\sin ky}^{2}}}}{\sin ky}} \]
      10. +-commutativeN/A

        \[\leadsto \frac{\sin th}{\frac{\sqrt{\color{blue}{{\sin ky}^{2} + {\sin kx}^{2}}}}{\sin ky}} \]
      11. lift-pow.f64N/A

        \[\leadsto \frac{\sin th}{\frac{\sqrt{\color{blue}{{\sin ky}^{2}} + {\sin kx}^{2}}}{\sin ky}} \]
      12. unpow2N/A

        \[\leadsto \frac{\sin th}{\frac{\sqrt{\color{blue}{\sin ky \cdot \sin ky} + {\sin kx}^{2}}}{\sin ky}} \]
      13. lift-pow.f64N/A

        \[\leadsto \frac{\sin th}{\frac{\sqrt{\sin ky \cdot \sin ky + \color{blue}{{\sin kx}^{2}}}}{\sin ky}} \]
      14. unpow2N/A

        \[\leadsto \frac{\sin th}{\frac{\sqrt{\sin ky \cdot \sin ky + \color{blue}{\sin kx \cdot \sin kx}}}{\sin ky}} \]
      15. lower-hypot.f6499.6

        \[\leadsto \frac{\sin th}{\frac{\color{blue}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}}{\sin ky}} \]
    4. Applied rewrites99.6%

      \[\leadsto \color{blue}{\frac{\sin th}{\frac{\mathsf{hypot}\left(\sin ky, \sin kx\right)}{\sin ky}}} \]
    5. Taylor expanded in kx around 0

      \[\leadsto \frac{\sin th}{\color{blue}{1 + \frac{1}{2} \cdot \frac{{kx}^{2}}{{\sin ky}^{2}}}} \]
    6. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto \frac{\sin th}{\color{blue}{\frac{1}{2} \cdot \frac{{kx}^{2}}{{\sin ky}^{2}} + 1}} \]
      2. associate-*r/N/A

        \[\leadsto \frac{\sin th}{\color{blue}{\frac{\frac{1}{2} \cdot {kx}^{2}}{{\sin ky}^{2}}} + 1} \]
      3. associate-*l/N/A

        \[\leadsto \frac{\sin th}{\color{blue}{\frac{\frac{1}{2}}{{\sin ky}^{2}} \cdot {kx}^{2}} + 1} \]
      4. metadata-evalN/A

        \[\leadsto \frac{\sin th}{\frac{\color{blue}{\frac{1}{2} \cdot 1}}{{\sin ky}^{2}} \cdot {kx}^{2} + 1} \]
      5. associate-*r/N/A

        \[\leadsto \frac{\sin th}{\color{blue}{\left(\frac{1}{2} \cdot \frac{1}{{\sin ky}^{2}}\right)} \cdot {kx}^{2} + 1} \]
      6. lower-fma.f64N/A

        \[\leadsto \frac{\sin th}{\color{blue}{\mathsf{fma}\left(\frac{1}{2} \cdot \frac{1}{{\sin ky}^{2}}, {kx}^{2}, 1\right)}} \]
      7. associate-*r/N/A

        \[\leadsto \frac{\sin th}{\mathsf{fma}\left(\color{blue}{\frac{\frac{1}{2} \cdot 1}{{\sin ky}^{2}}}, {kx}^{2}, 1\right)} \]
      8. metadata-evalN/A

        \[\leadsto \frac{\sin th}{\mathsf{fma}\left(\frac{\color{blue}{\frac{1}{2}}}{{\sin ky}^{2}}, {kx}^{2}, 1\right)} \]
      9. lower-/.f64N/A

        \[\leadsto \frac{\sin th}{\mathsf{fma}\left(\color{blue}{\frac{\frac{1}{2}}{{\sin ky}^{2}}}, {kx}^{2}, 1\right)} \]
      10. lower-pow.f64N/A

        \[\leadsto \frac{\sin th}{\mathsf{fma}\left(\frac{\frac{1}{2}}{\color{blue}{{\sin ky}^{2}}}, {kx}^{2}, 1\right)} \]
      11. lower-sin.f64N/A

        \[\leadsto \frac{\sin th}{\mathsf{fma}\left(\frac{\frac{1}{2}}{{\color{blue}{\sin ky}}^{2}}, {kx}^{2}, 1\right)} \]
      12. unpow2N/A

        \[\leadsto \frac{\sin th}{\mathsf{fma}\left(\frac{\frac{1}{2}}{{\sin ky}^{2}}, \color{blue}{kx \cdot kx}, 1\right)} \]
      13. lower-*.f6418.0

        \[\leadsto \frac{\sin th}{\mathsf{fma}\left(\frac{0.5}{{\sin ky}^{2}}, \color{blue}{kx \cdot kx}, 1\right)} \]
    7. Applied rewrites18.0%

      \[\leadsto \frac{\sin th}{\color{blue}{\mathsf{fma}\left(\frac{0.5}{{\sin ky}^{2}}, kx \cdot kx, 1\right)}} \]
    8. Taylor expanded in ky around 0

      \[\leadsto \frac{\sin th}{\mathsf{fma}\left(\frac{\frac{1}{2}}{{ky}^{2}}, kx \cdot kx, 1\right)} \]
    9. Step-by-step derivation
      1. Applied rewrites17.8%

        \[\leadsto \frac{\sin th}{\mathsf{fma}\left(\frac{0.5}{ky \cdot ky}, kx \cdot kx, 1\right)} \]

      if 5.0000000000000002e-62 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))

      1. Initial program 92.1%

        \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
      2. Add Preprocessing
      3. Taylor expanded in kx around 0

        \[\leadsto \color{blue}{\sin th} \]
      4. Step-by-step derivation
        1. lower-sin.f6463.4

          \[\leadsto \color{blue}{\sin th} \]
      5. Applied rewrites63.4%

        \[\leadsto \color{blue}{\sin th} \]
    10. Recombined 2 regimes into one program.
    11. Add Preprocessing

    Alternative 12: 15.6% accurate, 1.0× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \leq 10^{-302}:\\ \;\;\;\;\left(\left(-0.16666666666666666 \cdot th\right) \cdot th\right) \cdot th\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(th \cdot th, 0.008333333333333333, -0.16666666666666666\right), th \cdot th, 1\right) \cdot th\\ \end{array} \end{array} \]
    (FPCore (kx ky th)
     :precision binary64
     (if (<=
          (*
           (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0))))
           (sin th))
          1e-302)
       (* (* (* -0.16666666666666666 th) th) th)
       (*
        (fma
         (fma (* th th) 0.008333333333333333 -0.16666666666666666)
         (* th th)
         1.0)
        th)))
    double code(double kx, double ky, double th) {
    	double tmp;
    	if (((sin(ky) / sqrt((pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))) * sin(th)) <= 1e-302) {
    		tmp = ((-0.16666666666666666 * th) * th) * th;
    	} else {
    		tmp = fma(fma((th * th), 0.008333333333333333, -0.16666666666666666), (th * th), 1.0) * th;
    	}
    	return tmp;
    }
    
    function code(kx, ky, th)
    	tmp = 0.0
    	if (Float64(Float64(sin(ky) / sqrt(Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) * sin(th)) <= 1e-302)
    		tmp = Float64(Float64(Float64(-0.16666666666666666 * th) * th) * th);
    	else
    		tmp = Float64(fma(fma(Float64(th * th), 0.008333333333333333, -0.16666666666666666), Float64(th * th), 1.0) * th);
    	end
    	return tmp
    end
    
    code[kx_, ky_, th_] := If[LessEqual[N[(N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision], 1e-302], N[(N[(N[(-0.16666666666666666 * th), $MachinePrecision] * th), $MachinePrecision] * th), $MachinePrecision], N[(N[(N[(N[(th * th), $MachinePrecision] * 0.008333333333333333 + -0.16666666666666666), $MachinePrecision] * N[(th * th), $MachinePrecision] + 1.0), $MachinePrecision] * th), $MachinePrecision]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \leq 10^{-302}:\\
    \;\;\;\;\left(\left(-0.16666666666666666 \cdot th\right) \cdot th\right) \cdot th\\
    
    \mathbf{else}:\\
    \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(th \cdot th, 0.008333333333333333, -0.16666666666666666\right), th \cdot th, 1\right) \cdot th\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 2 regimes
    2. if (*.f64 (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) (sin.f64 th)) < 9.9999999999999996e-303

      1. Initial program 94.0%

        \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
      2. Add Preprocessing
      3. Taylor expanded in kx around 0

        \[\leadsto \color{blue}{\sin th} \]
      4. Step-by-step derivation
        1. lower-sin.f6425.5

          \[\leadsto \color{blue}{\sin th} \]
      5. Applied rewrites25.5%

        \[\leadsto \color{blue}{\sin th} \]
      6. Taylor expanded in th around 0

        \[\leadsto th \cdot \color{blue}{\left(1 + \frac{-1}{6} \cdot {th}^{2}\right)} \]
      7. Step-by-step derivation
        1. Applied rewrites13.6%

          \[\leadsto \mathsf{fma}\left(th \cdot th, -0.16666666666666666, 1\right) \cdot \color{blue}{th} \]
        2. Taylor expanded in th around inf

          \[\leadsto \left(\frac{-1}{6} \cdot {th}^{2}\right) \cdot th \]
        3. Step-by-step derivation
          1. Applied rewrites19.1%

            \[\leadsto \left(\left(th \cdot th\right) \cdot -0.16666666666666666\right) \cdot th \]
          2. Step-by-step derivation
            1. Applied rewrites19.1%

              \[\leadsto \left(\left(-0.16666666666666666 \cdot th\right) \cdot th\right) \cdot th \]

            if 9.9999999999999996e-303 < (*.f64 (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) (sin.f64 th))

            1. Initial program 91.8%

              \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
            2. Add Preprocessing
            3. Taylor expanded in kx around 0

              \[\leadsto \color{blue}{\sin th} \]
            4. Step-by-step derivation
              1. lower-sin.f6428.0

                \[\leadsto \color{blue}{\sin th} \]
            5. Applied rewrites28.0%

              \[\leadsto \color{blue}{\sin th} \]
            6. Taylor expanded in th around 0

              \[\leadsto th \cdot \color{blue}{\left(1 + {th}^{2} \cdot \left(\frac{1}{120} \cdot {th}^{2} - \frac{1}{6}\right)\right)} \]
            7. Step-by-step derivation
              1. Applied rewrites14.6%

                \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(th \cdot th, 0.008333333333333333, -0.16666666666666666\right), th \cdot th, 1\right) \cdot \color{blue}{th} \]
            8. Recombined 2 regimes into one program.
            9. Add Preprocessing

            Alternative 13: 15.6% accurate, 1.0× speedup?

            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \leq 10^{-302}:\\ \;\;\;\;\left(\left(-0.16666666666666666 \cdot th\right) \cdot th\right) \cdot th\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(-0.16666666666666666 \cdot th, th, 1\right) \cdot th\\ \end{array} \end{array} \]
            (FPCore (kx ky th)
             :precision binary64
             (if (<=
                  (*
                   (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0))))
                   (sin th))
                  1e-302)
               (* (* (* -0.16666666666666666 th) th) th)
               (* (fma (* -0.16666666666666666 th) th 1.0) th)))
            double code(double kx, double ky, double th) {
            	double tmp;
            	if (((sin(ky) / sqrt((pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))) * sin(th)) <= 1e-302) {
            		tmp = ((-0.16666666666666666 * th) * th) * th;
            	} else {
            		tmp = fma((-0.16666666666666666 * th), th, 1.0) * th;
            	}
            	return tmp;
            }
            
            function code(kx, ky, th)
            	tmp = 0.0
            	if (Float64(Float64(sin(ky) / sqrt(Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) * sin(th)) <= 1e-302)
            		tmp = Float64(Float64(Float64(-0.16666666666666666 * th) * th) * th);
            	else
            		tmp = Float64(fma(Float64(-0.16666666666666666 * th), th, 1.0) * th);
            	end
            	return tmp
            end
            
            code[kx_, ky_, th_] := If[LessEqual[N[(N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision], 1e-302], N[(N[(N[(-0.16666666666666666 * th), $MachinePrecision] * th), $MachinePrecision] * th), $MachinePrecision], N[(N[(N[(-0.16666666666666666 * th), $MachinePrecision] * th + 1.0), $MachinePrecision] * th), $MachinePrecision]]
            
            \begin{array}{l}
            
            \\
            \begin{array}{l}
            \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \leq 10^{-302}:\\
            \;\;\;\;\left(\left(-0.16666666666666666 \cdot th\right) \cdot th\right) \cdot th\\
            
            \mathbf{else}:\\
            \;\;\;\;\mathsf{fma}\left(-0.16666666666666666 \cdot th, th, 1\right) \cdot th\\
            
            
            \end{array}
            \end{array}
            
            Derivation
            1. Split input into 2 regimes
            2. if (*.f64 (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) (sin.f64 th)) < 9.9999999999999996e-303

              1. Initial program 94.0%

                \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
              2. Add Preprocessing
              3. Taylor expanded in kx around 0

                \[\leadsto \color{blue}{\sin th} \]
              4. Step-by-step derivation
                1. lower-sin.f6425.5

                  \[\leadsto \color{blue}{\sin th} \]
              5. Applied rewrites25.5%

                \[\leadsto \color{blue}{\sin th} \]
              6. Taylor expanded in th around 0

                \[\leadsto th \cdot \color{blue}{\left(1 + \frac{-1}{6} \cdot {th}^{2}\right)} \]
              7. Step-by-step derivation
                1. Applied rewrites13.6%

                  \[\leadsto \mathsf{fma}\left(th \cdot th, -0.16666666666666666, 1\right) \cdot \color{blue}{th} \]
                2. Taylor expanded in th around inf

                  \[\leadsto \left(\frac{-1}{6} \cdot {th}^{2}\right) \cdot th \]
                3. Step-by-step derivation
                  1. Applied rewrites19.1%

                    \[\leadsto \left(\left(th \cdot th\right) \cdot -0.16666666666666666\right) \cdot th \]
                  2. Step-by-step derivation
                    1. Applied rewrites19.1%

                      \[\leadsto \left(\left(-0.16666666666666666 \cdot th\right) \cdot th\right) \cdot th \]

                    if 9.9999999999999996e-303 < (*.f64 (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) (sin.f64 th))

                    1. Initial program 91.8%

                      \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
                    2. Add Preprocessing
                    3. Taylor expanded in kx around 0

                      \[\leadsto \color{blue}{\sin th} \]
                    4. Step-by-step derivation
                      1. lower-sin.f6428.0

                        \[\leadsto \color{blue}{\sin th} \]
                    5. Applied rewrites28.0%

                      \[\leadsto \color{blue}{\sin th} \]
                    6. Taylor expanded in th around 0

                      \[\leadsto th \cdot \color{blue}{\left(1 + \frac{-1}{6} \cdot {th}^{2}\right)} \]
                    7. Step-by-step derivation
                      1. Applied rewrites14.9%

                        \[\leadsto \mathsf{fma}\left(th \cdot th, -0.16666666666666666, 1\right) \cdot \color{blue}{th} \]
                      2. Step-by-step derivation
                        1. Applied rewrites14.9%

                          \[\leadsto \mathsf{fma}\left(-0.16666666666666666 \cdot th, th, 1\right) \cdot th \]
                      3. Recombined 2 regimes into one program.
                      4. Add Preprocessing

                      Alternative 14: 30.9% accurate, 1.0× speedup?

                      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 5 \cdot 10^{-62}:\\ \;\;\;\;\left(\left(-0.16666666666666666 \cdot th\right) \cdot th\right) \cdot th\\ \mathbf{else}:\\ \;\;\;\;\sin th\\ \end{array} \end{array} \]
                      (FPCore (kx ky th)
                       :precision binary64
                       (if (<= (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0)))) 5e-62)
                         (* (* (* -0.16666666666666666 th) th) th)
                         (sin th)))
                      double code(double kx, double ky, double th) {
                      	double tmp;
                      	if ((sin(ky) / sqrt((pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))) <= 5e-62) {
                      		tmp = ((-0.16666666666666666 * th) * th) * th;
                      	} else {
                      		tmp = sin(th);
                      	}
                      	return tmp;
                      }
                      
                      real(8) function code(kx, ky, th)
                          real(8), intent (in) :: kx
                          real(8), intent (in) :: ky
                          real(8), intent (in) :: th
                          real(8) :: tmp
                          if ((sin(ky) / sqrt(((sin(kx) ** 2.0d0) + (sin(ky) ** 2.0d0)))) <= 5d-62) then
                              tmp = (((-0.16666666666666666d0) * th) * th) * th
                          else
                              tmp = sin(th)
                          end if
                          code = tmp
                      end function
                      
                      public static double code(double kx, double ky, double th) {
                      	double tmp;
                      	if ((Math.sin(ky) / Math.sqrt((Math.pow(Math.sin(kx), 2.0) + Math.pow(Math.sin(ky), 2.0)))) <= 5e-62) {
                      		tmp = ((-0.16666666666666666 * th) * th) * th;
                      	} else {
                      		tmp = Math.sin(th);
                      	}
                      	return tmp;
                      }
                      
                      def code(kx, ky, th):
                      	tmp = 0
                      	if (math.sin(ky) / math.sqrt((math.pow(math.sin(kx), 2.0) + math.pow(math.sin(ky), 2.0)))) <= 5e-62:
                      		tmp = ((-0.16666666666666666 * th) * th) * th
                      	else:
                      		tmp = math.sin(th)
                      	return tmp
                      
                      function code(kx, ky, th)
                      	tmp = 0.0
                      	if (Float64(sin(ky) / sqrt(Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) <= 5e-62)
                      		tmp = Float64(Float64(Float64(-0.16666666666666666 * th) * th) * th);
                      	else
                      		tmp = sin(th);
                      	end
                      	return tmp
                      end
                      
                      function tmp_2 = code(kx, ky, th)
                      	tmp = 0.0;
                      	if ((sin(ky) / sqrt(((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))) <= 5e-62)
                      		tmp = ((-0.16666666666666666 * th) * th) * th;
                      	else
                      		tmp = sin(th);
                      	end
                      	tmp_2 = tmp;
                      end
                      
                      code[kx_, ky_, th_] := If[LessEqual[N[(N[Sin[ky], $MachinePrecision] / N[Sqrt[N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 5e-62], N[(N[(N[(-0.16666666666666666 * th), $MachinePrecision] * th), $MachinePrecision] * th), $MachinePrecision], N[Sin[th], $MachinePrecision]]
                      
                      \begin{array}{l}
                      
                      \\
                      \begin{array}{l}
                      \mathbf{if}\;\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \leq 5 \cdot 10^{-62}:\\
                      \;\;\;\;\left(\left(-0.16666666666666666 \cdot th\right) \cdot th\right) \cdot th\\
                      
                      \mathbf{else}:\\
                      \;\;\;\;\sin th\\
                      
                      
                      \end{array}
                      \end{array}
                      
                      Derivation
                      1. Split input into 2 regimes
                      2. if (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))) < 5.0000000000000002e-62

                        1. Initial program 93.5%

                          \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
                        2. Add Preprocessing
                        3. Taylor expanded in kx around 0

                          \[\leadsto \color{blue}{\sin th} \]
                        4. Step-by-step derivation
                          1. lower-sin.f643.5

                            \[\leadsto \color{blue}{\sin th} \]
                        5. Applied rewrites3.5%

                          \[\leadsto \color{blue}{\sin th} \]
                        6. Taylor expanded in th around 0

                          \[\leadsto th \cdot \color{blue}{\left(1 + \frac{-1}{6} \cdot {th}^{2}\right)} \]
                        7. Step-by-step derivation
                          1. Applied rewrites3.4%

                            \[\leadsto \mathsf{fma}\left(th \cdot th, -0.16666666666666666, 1\right) \cdot \color{blue}{th} \]
                          2. Taylor expanded in th around inf

                            \[\leadsto \left(\frac{-1}{6} \cdot {th}^{2}\right) \cdot th \]
                          3. Step-by-step derivation
                            1. Applied rewrites16.9%

                              \[\leadsto \left(\left(th \cdot th\right) \cdot -0.16666666666666666\right) \cdot th \]
                            2. Step-by-step derivation
                              1. Applied rewrites16.9%

                                \[\leadsto \left(\left(-0.16666666666666666 \cdot th\right) \cdot th\right) \cdot th \]

                              if 5.0000000000000002e-62 < (/.f64 (sin.f64 ky) (sqrt.f64 (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))

                              1. Initial program 92.1%

                                \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
                              2. Add Preprocessing
                              3. Taylor expanded in kx around 0

                                \[\leadsto \color{blue}{\sin th} \]
                              4. Step-by-step derivation
                                1. lower-sin.f6463.4

                                  \[\leadsto \color{blue}{\sin th} \]
                              5. Applied rewrites63.4%

                                \[\leadsto \color{blue}{\sin th} \]
                            3. Recombined 2 regimes into one program.
                            4. Add Preprocessing

                            Alternative 15: 99.6% accurate, 1.2× speedup?

                            \[\begin{array}{l} \\ \frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \cdot \sin ky \end{array} \]
                            (FPCore (kx ky th)
                             :precision binary64
                             (* (/ (sin th) (hypot (sin ky) (sin kx))) (sin ky)))
                            double code(double kx, double ky, double th) {
                            	return (sin(th) / hypot(sin(ky), sin(kx))) * sin(ky);
                            }
                            
                            public static double code(double kx, double ky, double th) {
                            	return (Math.sin(th) / Math.hypot(Math.sin(ky), Math.sin(kx))) * Math.sin(ky);
                            }
                            
                            def code(kx, ky, th):
                            	return (math.sin(th) / math.hypot(math.sin(ky), math.sin(kx))) * math.sin(ky)
                            
                            function code(kx, ky, th)
                            	return Float64(Float64(sin(th) / hypot(sin(ky), sin(kx))) * sin(ky))
                            end
                            
                            function tmp = code(kx, ky, th)
                            	tmp = (sin(th) / hypot(sin(ky), sin(kx))) * sin(ky);
                            end
                            
                            code[kx_, ky_, th_] := N[(N[(N[Sin[th], $MachinePrecision] / N[Sqrt[N[Sin[ky], $MachinePrecision] ^ 2 + N[Sin[kx], $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision] * N[Sin[ky], $MachinePrecision]), $MachinePrecision]
                            
                            \begin{array}{l}
                            
                            \\
                            \frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \cdot \sin ky
                            \end{array}
                            
                            Derivation
                            1. Initial program 93.0%

                              \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
                            2. Add Preprocessing
                            3. Step-by-step derivation
                              1. lift-*.f64N/A

                                \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
                              2. lift-/.f64N/A

                                \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin th \]
                              3. associate-*l/N/A

                                \[\leadsto \color{blue}{\frac{\sin ky \cdot \sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
                              4. associate-/l*N/A

                                \[\leadsto \color{blue}{\sin ky \cdot \frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
                              5. *-commutativeN/A

                                \[\leadsto \color{blue}{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin ky} \]
                              6. lower-*.f64N/A

                                \[\leadsto \color{blue}{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin ky} \]
                              7. lower-/.f6492.9

                                \[\leadsto \color{blue}{\frac{\sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin ky \]
                              8. lift-sqrt.f64N/A

                                \[\leadsto \frac{\sin th}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin ky \]
                              9. lift-+.f64N/A

                                \[\leadsto \frac{\sin th}{\sqrt{\color{blue}{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin ky \]
                              10. +-commutativeN/A

                                \[\leadsto \frac{\sin th}{\sqrt{\color{blue}{{\sin ky}^{2} + {\sin kx}^{2}}}} \cdot \sin ky \]
                              11. lift-pow.f64N/A

                                \[\leadsto \frac{\sin th}{\sqrt{\color{blue}{{\sin ky}^{2}} + {\sin kx}^{2}}} \cdot \sin ky \]
                              12. unpow2N/A

                                \[\leadsto \frac{\sin th}{\sqrt{\color{blue}{\sin ky \cdot \sin ky} + {\sin kx}^{2}}} \cdot \sin ky \]
                              13. lift-pow.f64N/A

                                \[\leadsto \frac{\sin th}{\sqrt{\sin ky \cdot \sin ky + \color{blue}{{\sin kx}^{2}}}} \cdot \sin ky \]
                              14. unpow2N/A

                                \[\leadsto \frac{\sin th}{\sqrt{\sin ky \cdot \sin ky + \color{blue}{\sin kx \cdot \sin kx}}} \cdot \sin ky \]
                              15. lower-hypot.f6499.6

                                \[\leadsto \frac{\sin th}{\color{blue}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \cdot \sin ky \]
                            4. Applied rewrites99.6%

                              \[\leadsto \color{blue}{\frac{\sin th}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \cdot \sin ky} \]
                            5. Add Preprocessing

                            Alternative 16: 76.9% accurate, 1.3× speedup?

                            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;ky \leq 5.4 \cdot 10^{-6}:\\ \;\;\;\;\left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \left(-ky\right)\right) \cdot \sin th\\ \mathbf{else}:\\ \;\;\;\;\frac{\sin ky}{\frac{\sqrt{\mathsf{fma}\left(1 - \cos \left(ky \cdot 2\right), 2, 2 \cdot \left(1 - \cos \left(2 \cdot kx\right)\right)\right)}}{2}} \cdot \sin th\\ \end{array} \end{array} \]
                            (FPCore (kx ky th)
                             :precision binary64
                             (if (<= ky 5.4e-6)
                               (* (* (/ -1.0 (hypot (sin kx) (sin ky))) (- ky)) (sin th))
                               (*
                                (/
                                 (sin ky)
                                 (/
                                  (sqrt
                                   (fma (- 1.0 (cos (* ky 2.0))) 2.0 (* 2.0 (- 1.0 (cos (* 2.0 kx))))))
                                  2.0))
                                (sin th))))
                            double code(double kx, double ky, double th) {
                            	double tmp;
                            	if (ky <= 5.4e-6) {
                            		tmp = ((-1.0 / hypot(sin(kx), sin(ky))) * -ky) * sin(th);
                            	} else {
                            		tmp = (sin(ky) / (sqrt(fma((1.0 - cos((ky * 2.0))), 2.0, (2.0 * (1.0 - cos((2.0 * kx)))))) / 2.0)) * sin(th);
                            	}
                            	return tmp;
                            }
                            
                            function code(kx, ky, th)
                            	tmp = 0.0
                            	if (ky <= 5.4e-6)
                            		tmp = Float64(Float64(Float64(-1.0 / hypot(sin(kx), sin(ky))) * Float64(-ky)) * sin(th));
                            	else
                            		tmp = Float64(Float64(sin(ky) / Float64(sqrt(fma(Float64(1.0 - cos(Float64(ky * 2.0))), 2.0, Float64(2.0 * Float64(1.0 - cos(Float64(2.0 * kx)))))) / 2.0)) * sin(th));
                            	end
                            	return tmp
                            end
                            
                            code[kx_, ky_, th_] := If[LessEqual[ky, 5.4e-6], N[(N[(N[(-1.0 / N[Sqrt[N[Sin[kx], $MachinePrecision] ^ 2 + N[Sin[ky], $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision] * (-ky)), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision], N[(N[(N[Sin[ky], $MachinePrecision] / N[(N[Sqrt[N[(N[(1.0 - N[Cos[N[(ky * 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * 2.0 + N[(2.0 * N[(1.0 - N[Cos[N[(2.0 * kx), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / 2.0), $MachinePrecision]), $MachinePrecision] * N[Sin[th], $MachinePrecision]), $MachinePrecision]]
                            
                            \begin{array}{l}
                            
                            \\
                            \begin{array}{l}
                            \mathbf{if}\;ky \leq 5.4 \cdot 10^{-6}:\\
                            \;\;\;\;\left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \left(-ky\right)\right) \cdot \sin th\\
                            
                            \mathbf{else}:\\
                            \;\;\;\;\frac{\sin ky}{\frac{\sqrt{\mathsf{fma}\left(1 - \cos \left(ky \cdot 2\right), 2, 2 \cdot \left(1 - \cos \left(2 \cdot kx\right)\right)\right)}}{2}} \cdot \sin th\\
                            
                            
                            \end{array}
                            \end{array}
                            
                            Derivation
                            1. Split input into 2 regimes
                            2. if ky < 5.39999999999999997e-6

                              1. Initial program 90.9%

                                \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
                              2. Add Preprocessing
                              3. Step-by-step derivation
                                1. lift-*.f64N/A

                                  \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th} \]
                                2. lift-/.f64N/A

                                  \[\leadsto \color{blue}{\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin th \]
                                3. associate-*l/N/A

                                  \[\leadsto \color{blue}{\frac{\sin ky \cdot \sin th}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
                                4. frac-2negN/A

                                  \[\leadsto \color{blue}{\frac{\mathsf{neg}\left(\sin ky \cdot \sin th\right)}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
                                5. div-invN/A

                                  \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sin ky \cdot \sin th\right)\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
                                6. lower-*.f64N/A

                                  \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sin ky \cdot \sin th\right)\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)}} \]
                                7. distribute-lft-neg-inN/A

                                  \[\leadsto \color{blue}{\left(\left(\mathsf{neg}\left(\sin ky\right)\right) \cdot \sin th\right)} \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
                                8. lower-*.f64N/A

                                  \[\leadsto \color{blue}{\left(\left(\mathsf{neg}\left(\sin ky\right)\right) \cdot \sin th\right)} \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
                                9. lower-neg.f64N/A

                                  \[\leadsto \left(\color{blue}{\left(-\sin ky\right)} \cdot \sin th\right) \cdot \frac{1}{\mathsf{neg}\left(\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}\right)} \]
                                10. neg-mul-1N/A

                                  \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{1}{\color{blue}{-1 \cdot \sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
                                11. associate-/r*N/A

                                  \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \color{blue}{\frac{\frac{1}{-1}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
                                12. metadata-evalN/A

                                  \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{\color{blue}{-1}}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \]
                                13. lower-/.f6487.6

                                  \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \color{blue}{\frac{-1}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
                                14. lift-sqrt.f64N/A

                                  \[\leadsto \left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{-1}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \]
                              4. Applied rewrites94.8%

                                \[\leadsto \color{blue}{\left(\left(-\sin ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
                              5. Taylor expanded in ky around 0

                                \[\leadsto \left(\color{blue}{\left(ky \cdot \left(\frac{1}{6} \cdot {ky}^{2} - 1\right)\right)} \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
                              6. Step-by-step derivation
                                1. *-commutativeN/A

                                  \[\leadsto \left(\color{blue}{\left(\left(\frac{1}{6} \cdot {ky}^{2} - 1\right) \cdot ky\right)} \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
                                2. lower-*.f64N/A

                                  \[\leadsto \left(\color{blue}{\left(\left(\frac{1}{6} \cdot {ky}^{2} - 1\right) \cdot ky\right)} \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
                                3. sub-negN/A

                                  \[\leadsto \left(\left(\color{blue}{\left(\frac{1}{6} \cdot {ky}^{2} + \left(\mathsf{neg}\left(1\right)\right)\right)} \cdot ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
                                4. metadata-evalN/A

                                  \[\leadsto \left(\left(\left(\frac{1}{6} \cdot {ky}^{2} + \color{blue}{-1}\right) \cdot ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
                                5. lower-fma.f64N/A

                                  \[\leadsto \left(\left(\color{blue}{\mathsf{fma}\left(\frac{1}{6}, {ky}^{2}, -1\right)} \cdot ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
                                6. unpow2N/A

                                  \[\leadsto \left(\left(\mathsf{fma}\left(\frac{1}{6}, \color{blue}{ky \cdot ky}, -1\right) \cdot ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
                                7. lower-*.f6461.4

                                  \[\leadsto \left(\left(\mathsf{fma}\left(0.16666666666666666, \color{blue}{ky \cdot ky}, -1\right) \cdot ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
                              7. Applied rewrites61.4%

                                \[\leadsto \left(\color{blue}{\left(\mathsf{fma}\left(0.16666666666666666, ky \cdot ky, -1\right) \cdot ky\right)} \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \]
                              8. Step-by-step derivation
                                1. lift-*.f64N/A

                                  \[\leadsto \color{blue}{\left(\left(\mathsf{fma}\left(\frac{1}{6}, ky \cdot ky, -1\right) \cdot ky\right) \cdot \sin th\right) \cdot \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)}} \]
                                2. *-commutativeN/A

                                  \[\leadsto \color{blue}{\frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \cdot \left(\left(\mathsf{fma}\left(\frac{1}{6}, ky \cdot ky, -1\right) \cdot ky\right) \cdot \sin th\right)} \]
                                3. lift-*.f64N/A

                                  \[\leadsto \frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \cdot \color{blue}{\left(\left(\mathsf{fma}\left(\frac{1}{6}, ky \cdot ky, -1\right) \cdot ky\right) \cdot \sin th\right)} \]
                                4. associate-*r*N/A

                                  \[\leadsto \color{blue}{\left(\frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \cdot \left(\mathsf{fma}\left(\frac{1}{6}, ky \cdot ky, -1\right) \cdot ky\right)\right) \cdot \sin th} \]
                                5. lower-*.f64N/A

                                  \[\leadsto \color{blue}{\left(\frac{-1}{\mathsf{hypot}\left(\sin ky, \sin kx\right)} \cdot \left(\mathsf{fma}\left(\frac{1}{6}, ky \cdot ky, -1\right) \cdot ky\right)\right) \cdot \sin th} \]
                              9. Applied rewrites66.2%

                                \[\leadsto \color{blue}{\left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \left(\mathsf{fma}\left(ky \cdot ky, 0.16666666666666666, -1\right) \cdot ky\right)\right) \cdot \sin th} \]
                              10. Taylor expanded in ky around 0

                                \[\leadsto \left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \color{blue}{\left(-1 \cdot ky\right)}\right) \cdot \sin th \]
                              11. Step-by-step derivation
                                1. mul-1-negN/A

                                  \[\leadsto \left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \color{blue}{\left(\mathsf{neg}\left(ky\right)\right)}\right) \cdot \sin th \]
                                2. lower-neg.f6466.5

                                  \[\leadsto \left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \color{blue}{\left(-ky\right)}\right) \cdot \sin th \]
                              12. Applied rewrites66.5%

                                \[\leadsto \left(\frac{-1}{\mathsf{hypot}\left(\sin kx, \sin ky\right)} \cdot \color{blue}{\left(-ky\right)}\right) \cdot \sin th \]

                              if 5.39999999999999997e-6 < ky

                              1. Initial program 99.7%

                                \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
                              2. Add Preprocessing
                              3. Step-by-step derivation
                                1. lift-sqrt.f64N/A

                                  \[\leadsto \frac{\sin ky}{\color{blue}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin th \]
                                2. lift-+.f64N/A

                                  \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{{\sin kx}^{2} + {\sin ky}^{2}}}} \cdot \sin th \]
                                3. +-commutativeN/A

                                  \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{{\sin ky}^{2} + {\sin kx}^{2}}}} \cdot \sin th \]
                                4. lift-pow.f64N/A

                                  \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{{\sin ky}^{2}} + {\sin kx}^{2}}} \cdot \sin th \]
                                5. unpow2N/A

                                  \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\sin ky \cdot \sin ky} + {\sin kx}^{2}}} \cdot \sin th \]
                                6. lift-sin.f64N/A

                                  \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\sin ky} \cdot \sin ky + {\sin kx}^{2}}} \cdot \sin th \]
                                7. lift-sin.f64N/A

                                  \[\leadsto \frac{\sin ky}{\sqrt{\sin ky \cdot \color{blue}{\sin ky} + {\sin kx}^{2}}} \cdot \sin th \]
                                8. sin-multN/A

                                  \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\frac{\cos \left(ky - ky\right) - \cos \left(ky + ky\right)}{2}} + {\sin kx}^{2}}} \cdot \sin th \]
                                9. lift-pow.f64N/A

                                  \[\leadsto \frac{\sin ky}{\sqrt{\frac{\cos \left(ky - ky\right) - \cos \left(ky + ky\right)}{2} + \color{blue}{{\sin kx}^{2}}}} \cdot \sin th \]
                                10. unpow2N/A

                                  \[\leadsto \frac{\sin ky}{\sqrt{\frac{\cos \left(ky - ky\right) - \cos \left(ky + ky\right)}{2} + \color{blue}{\sin kx \cdot \sin kx}}} \cdot \sin th \]
                                11. lift-sin.f64N/A

                                  \[\leadsto \frac{\sin ky}{\sqrt{\frac{\cos \left(ky - ky\right) - \cos \left(ky + ky\right)}{2} + \color{blue}{\sin kx} \cdot \sin kx}} \cdot \sin th \]
                                12. lift-sin.f64N/A

                                  \[\leadsto \frac{\sin ky}{\sqrt{\frac{\cos \left(ky - ky\right) - \cos \left(ky + ky\right)}{2} + \sin kx \cdot \color{blue}{\sin kx}}} \cdot \sin th \]
                                13. sin-multN/A

                                  \[\leadsto \frac{\sin ky}{\sqrt{\frac{\cos \left(ky - ky\right) - \cos \left(ky + ky\right)}{2} + \color{blue}{\frac{\cos \left(kx - kx\right) - \cos \left(kx + kx\right)}{2}}}} \cdot \sin th \]
                                14. frac-addN/A

                                  \[\leadsto \frac{\sin ky}{\sqrt{\color{blue}{\frac{\left(\cos \left(ky - ky\right) - \cos \left(ky + ky\right)\right) \cdot 2 + 2 \cdot \left(\cos \left(kx - kx\right) - \cos \left(kx + kx\right)\right)}{2 \cdot 2}}}} \cdot \sin th \]
                                15. metadata-evalN/A

                                  \[\leadsto \frac{\sin ky}{\sqrt{\frac{\left(\cos \left(ky - ky\right) - \cos \left(ky + ky\right)\right) \cdot 2 + 2 \cdot \left(\cos \left(kx - kx\right) - \cos \left(kx + kx\right)\right)}{\color{blue}{4}}}} \cdot \sin th \]
                                16. metadata-evalN/A

                                  \[\leadsto \frac{\sin ky}{\sqrt{\frac{\left(\cos \left(ky - ky\right) - \cos \left(ky + ky\right)\right) \cdot 2 + 2 \cdot \left(\cos \left(kx - kx\right) - \cos \left(kx + kx\right)\right)}{\color{blue}{2 + 2}}}} \cdot \sin th \]
                                17. sqrt-divN/A

                                  \[\leadsto \frac{\sin ky}{\color{blue}{\frac{\sqrt{\left(\cos \left(ky - ky\right) - \cos \left(ky + ky\right)\right) \cdot 2 + 2 \cdot \left(\cos \left(kx - kx\right) - \cos \left(kx + kx\right)\right)}}{\sqrt{2 + 2}}}} \cdot \sin th \]
                              4. Applied rewrites98.2%

                                \[\leadsto \frac{\sin ky}{\color{blue}{\frac{\sqrt{\mathsf{fma}\left(1 - \cos \left(ky \cdot 2\right), 2, 2 \cdot \left(1 - \cos \left(2 \cdot kx\right)\right)\right)}}{2}}} \cdot \sin th \]
                            3. Recombined 2 regimes into one program.
                            4. Add Preprocessing

                            Alternative 17: 11.0% accurate, 39.5× speedup?

                            \[\begin{array}{l} \\ \left(\left(-0.16666666666666666 \cdot th\right) \cdot th\right) \cdot th \end{array} \]
                            (FPCore (kx ky th)
                             :precision binary64
                             (* (* (* -0.16666666666666666 th) th) th))
                            double code(double kx, double ky, double th) {
                            	return ((-0.16666666666666666 * th) * th) * th;
                            }
                            
                            real(8) function code(kx, ky, th)
                                real(8), intent (in) :: kx
                                real(8), intent (in) :: ky
                                real(8), intent (in) :: th
                                code = (((-0.16666666666666666d0) * th) * th) * th
                            end function
                            
                            public static double code(double kx, double ky, double th) {
                            	return ((-0.16666666666666666 * th) * th) * th;
                            }
                            
                            def code(kx, ky, th):
                            	return ((-0.16666666666666666 * th) * th) * th
                            
                            function code(kx, ky, th)
                            	return Float64(Float64(Float64(-0.16666666666666666 * th) * th) * th)
                            end
                            
                            function tmp = code(kx, ky, th)
                            	tmp = ((-0.16666666666666666 * th) * th) * th;
                            end
                            
                            code[kx_, ky_, th_] := N[(N[(N[(-0.16666666666666666 * th), $MachinePrecision] * th), $MachinePrecision] * th), $MachinePrecision]
                            
                            \begin{array}{l}
                            
                            \\
                            \left(\left(-0.16666666666666666 \cdot th\right) \cdot th\right) \cdot th
                            \end{array}
                            
                            Derivation
                            1. Initial program 93.0%

                              \[\frac{\sin ky}{\sqrt{{\sin kx}^{2} + {\sin ky}^{2}}} \cdot \sin th \]
                            2. Add Preprocessing
                            3. Taylor expanded in kx around 0

                              \[\leadsto \color{blue}{\sin th} \]
                            4. Step-by-step derivation
                              1. lower-sin.f6426.7

                                \[\leadsto \color{blue}{\sin th} \]
                            5. Applied rewrites26.7%

                              \[\leadsto \color{blue}{\sin th} \]
                            6. Taylor expanded in th around 0

                              \[\leadsto th \cdot \color{blue}{\left(1 + \frac{-1}{6} \cdot {th}^{2}\right)} \]
                            7. Step-by-step derivation
                              1. Applied rewrites14.2%

                                \[\leadsto \mathsf{fma}\left(th \cdot th, -0.16666666666666666, 1\right) \cdot \color{blue}{th} \]
                              2. Taylor expanded in th around inf

                                \[\leadsto \left(\frac{-1}{6} \cdot {th}^{2}\right) \cdot th \]
                              3. Step-by-step derivation
                                1. Applied rewrites11.8%

                                  \[\leadsto \left(\left(th \cdot th\right) \cdot -0.16666666666666666\right) \cdot th \]
                                2. Step-by-step derivation
                                  1. Applied rewrites11.8%

                                    \[\leadsto \left(\left(-0.16666666666666666 \cdot th\right) \cdot th\right) \cdot th \]
                                  2. Add Preprocessing

                                  Reproduce

                                  ?
                                  herbie shell --seed 2024303 
                                  (FPCore (kx ky th)
                                    :name "Toniolo and Linder, Equation (3b), real"
                                    :precision binary64
                                    (* (/ (sin ky) (sqrt (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0)))) (sin th)))