2nthrt (problem 3.4.6)

Percentage Accurate: 54.0% → 91.4%
Time: 22.2s
Alternatives: 11
Speedup: 1.0×

Specification

?
\[\begin{array}{l} \\ {\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \end{array} \]
(FPCore (x n)
 :precision binary64
 (- (pow (+ x 1.0) (/ 1.0 n)) (pow x (/ 1.0 n))))
double code(double x, double n) {
	return pow((x + 1.0), (1.0 / n)) - pow(x, (1.0 / n));
}
real(8) function code(x, n)
    real(8), intent (in) :: x
    real(8), intent (in) :: n
    code = ((x + 1.0d0) ** (1.0d0 / n)) - (x ** (1.0d0 / n))
end function
public static double code(double x, double n) {
	return Math.pow((x + 1.0), (1.0 / n)) - Math.pow(x, (1.0 / n));
}
def code(x, n):
	return math.pow((x + 1.0), (1.0 / n)) - math.pow(x, (1.0 / n))
function code(x, n)
	return Float64((Float64(x + 1.0) ^ Float64(1.0 / n)) - (x ^ Float64(1.0 / n)))
end
function tmp = code(x, n)
	tmp = ((x + 1.0) ^ (1.0 / n)) - (x ^ (1.0 / n));
end
code[x_, n_] := N[(N[Power[N[(x + 1.0), $MachinePrecision], N[(1.0 / n), $MachinePrecision]], $MachinePrecision] - N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 11 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 54.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ {\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \end{array} \]
(FPCore (x n)
 :precision binary64
 (- (pow (+ x 1.0) (/ 1.0 n)) (pow x (/ 1.0 n))))
double code(double x, double n) {
	return pow((x + 1.0), (1.0 / n)) - pow(x, (1.0 / n));
}
real(8) function code(x, n)
    real(8), intent (in) :: x
    real(8), intent (in) :: n
    code = ((x + 1.0d0) ** (1.0d0 / n)) - (x ** (1.0d0 / n))
end function
public static double code(double x, double n) {
	return Math.pow((x + 1.0), (1.0 / n)) - Math.pow(x, (1.0 / n));
}
def code(x, n):
	return math.pow((x + 1.0), (1.0 / n)) - math.pow(x, (1.0 / n))
function code(x, n)
	return Float64((Float64(x + 1.0) ^ Float64(1.0 / n)) - (x ^ Float64(1.0 / n)))
end
function tmp = code(x, n)
	tmp = ((x + 1.0) ^ (1.0 / n)) - (x ^ (1.0 / n));
end
code[x_, n_] := N[(N[Power[N[(x + 1.0), $MachinePrecision], N[(1.0 / n), $MachinePrecision]], $MachinePrecision] - N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)}
\end{array}

Alternative 1: 91.4% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 0.82:\\ \;\;\;\;\frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{{x}^{\left({n}^{-1}\right)}}{x}}{n}\\ \end{array} \end{array} \]
(FPCore (x n)
 :precision binary64
 (if (<= x 0.82)
   (- (/ x n) (expm1 (/ (log x) n)))
   (/ (/ (pow x (pow n -1.0)) x) n)))
double code(double x, double n) {
	double tmp;
	if (x <= 0.82) {
		tmp = (x / n) - expm1((log(x) / n));
	} else {
		tmp = (pow(x, pow(n, -1.0)) / x) / n;
	}
	return tmp;
}
public static double code(double x, double n) {
	double tmp;
	if (x <= 0.82) {
		tmp = (x / n) - Math.expm1((Math.log(x) / n));
	} else {
		tmp = (Math.pow(x, Math.pow(n, -1.0)) / x) / n;
	}
	return tmp;
}
def code(x, n):
	tmp = 0
	if x <= 0.82:
		tmp = (x / n) - math.expm1((math.log(x) / n))
	else:
		tmp = (math.pow(x, math.pow(n, -1.0)) / x) / n
	return tmp
function code(x, n)
	tmp = 0.0
	if (x <= 0.82)
		tmp = Float64(Float64(x / n) - expm1(Float64(log(x) / n)));
	else
		tmp = Float64(Float64((x ^ (n ^ -1.0)) / x) / n);
	end
	return tmp
end
code[x_, n_] := If[LessEqual[x, 0.82], N[(N[(x / n), $MachinePrecision] - N[(Exp[N[(N[Log[x], $MachinePrecision] / n), $MachinePrecision]] - 1), $MachinePrecision]), $MachinePrecision], N[(N[(N[Power[x, N[Power[n, -1.0], $MachinePrecision]], $MachinePrecision] / x), $MachinePrecision] / n), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;x \leq 0.82:\\
\;\;\;\;\frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)\\

\mathbf{else}:\\
\;\;\;\;\frac{\frac{{x}^{\left({n}^{-1}\right)}}{x}}{n}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if x < 0.819999999999999951

    1. Initial program 43.1%

      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \color{blue}{\left(1 + \frac{x}{n}\right) - e^{\frac{\log x}{n}}} \]
    4. Step-by-step derivation
      1. associate--l+N/A

        \[\leadsto \color{blue}{1 + \left(\frac{x}{n} - e^{\frac{\log x}{n}}\right)} \]
      2. +-commutativeN/A

        \[\leadsto \color{blue}{\left(\frac{x}{n} - e^{\frac{\log x}{n}}\right) + 1} \]
      3. *-rgt-identityN/A

        \[\leadsto \left(\frac{\color{blue}{x \cdot 1}}{n} - e^{\frac{\log x}{n}}\right) + 1 \]
      4. associate-*r/N/A

        \[\leadsto \left(\color{blue}{x \cdot \frac{1}{n}} - e^{\frac{\log x}{n}}\right) + 1 \]
      5. remove-double-negN/A

        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\frac{\color{blue}{\mathsf{neg}\left(\left(\mathsf{neg}\left(\log x\right)\right)\right)}}{n}}\right) + 1 \]
      6. mul-1-negN/A

        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\frac{\mathsf{neg}\left(\color{blue}{-1 \cdot \log x}\right)}{n}}\right) + 1 \]
      7. distribute-neg-fracN/A

        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\color{blue}{\mathsf{neg}\left(\frac{-1 \cdot \log x}{n}\right)}}\right) + 1 \]
      8. mul-1-negN/A

        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\mathsf{neg}\left(\frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}\right)}\right) + 1 \]
      9. log-recN/A

        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\mathsf{neg}\left(\frac{\color{blue}{\log \left(\frac{1}{x}\right)}}{n}\right)}\right) + 1 \]
      10. mul-1-negN/A

        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\color{blue}{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}\right) + 1 \]
      11. associate-+l-N/A

        \[\leadsto \color{blue}{x \cdot \frac{1}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right)} \]
      12. lower--.f64N/A

        \[\leadsto \color{blue}{x \cdot \frac{1}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right)} \]
      13. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{x \cdot 1}{n}} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
      14. *-rgt-identityN/A

        \[\leadsto \frac{\color{blue}{x}}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
      15. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{x}{n}} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
    5. Applied rewrites83.5%

      \[\leadsto \color{blue}{\frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)} \]

    if 0.819999999999999951 < x

    1. Initial program 62.5%

      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in x around inf

      \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
    4. Step-by-step derivation
      1. associate-/l/N/A

        \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
      2. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
      3. lower-/.f64N/A

        \[\leadsto \frac{\color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}}{n} \]
      4. log-recN/A

        \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{x}}{n} \]
      5. mul-1-negN/A

        \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{x}}{n} \]
      6. associate-*r/N/A

        \[\leadsto \frac{\frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{x}}{n} \]
      7. associate-*r*N/A

        \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{x}}{n} \]
      8. metadata-evalN/A

        \[\leadsto \frac{\frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{x}}{n} \]
      9. *-commutativeN/A

        \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{x}}{n} \]
      10. associate-/l*N/A

        \[\leadsto \frac{\frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{x}}{n} \]
      11. exp-to-powN/A

        \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
      12. lower-pow.f64N/A

        \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
      13. lower-/.f6498.6

        \[\leadsto \frac{\frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{x}}{n} \]
    5. Applied rewrites98.6%

      \[\leadsto \color{blue}{\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification89.1%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq 0.82:\\ \;\;\;\;\frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{{x}^{\left({n}^{-1}\right)}}{x}}{n}\\ \end{array} \]
  5. Add Preprocessing

Alternative 2: 68.6% accurate, 0.3× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := {x}^{\left({n}^{-1}\right)}\\ t_1 := \frac{\frac{t\_0}{x}}{n}\\ t_2 := \frac{x - \log x}{n}\\ \mathbf{if}\;{n}^{-1} \leq -5 \cdot 10^{-165}:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;{n}^{-1} \leq -5 \cdot 10^{-213}:\\ \;\;\;\;t\_2\\ \mathbf{elif}\;{n}^{-1} \leq -2 \cdot 10^{-259}:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;{n}^{-1} \leq 2 \cdot 10^{-12}:\\ \;\;\;\;t\_2\\ \mathbf{elif}\;{n}^{-1} \leq 4 \cdot 10^{+176}:\\ \;\;\;\;\mathsf{fma}\left(\frac{\mathsf{fma}\left(\frac{0.5}{n} - 0.5, x, 1\right)}{n}, x, 1\right) - t\_0\\ \mathbf{else}:\\ \;\;\;\;\left(\frac{x}{n \cdot n} \cdot 0.5\right) \cdot x\\ \end{array} \end{array} \]
(FPCore (x n)
 :precision binary64
 (let* ((t_0 (pow x (pow n -1.0)))
        (t_1 (/ (/ t_0 x) n))
        (t_2 (/ (- x (log x)) n)))
   (if (<= (pow n -1.0) -5e-165)
     t_1
     (if (<= (pow n -1.0) -5e-213)
       t_2
       (if (<= (pow n -1.0) -2e-259)
         t_1
         (if (<= (pow n -1.0) 2e-12)
           t_2
           (if (<= (pow n -1.0) 4e+176)
             (- (fma (/ (fma (- (/ 0.5 n) 0.5) x 1.0) n) x 1.0) t_0)
             (* (* (/ x (* n n)) 0.5) x))))))))
double code(double x, double n) {
	double t_0 = pow(x, pow(n, -1.0));
	double t_1 = (t_0 / x) / n;
	double t_2 = (x - log(x)) / n;
	double tmp;
	if (pow(n, -1.0) <= -5e-165) {
		tmp = t_1;
	} else if (pow(n, -1.0) <= -5e-213) {
		tmp = t_2;
	} else if (pow(n, -1.0) <= -2e-259) {
		tmp = t_1;
	} else if (pow(n, -1.0) <= 2e-12) {
		tmp = t_2;
	} else if (pow(n, -1.0) <= 4e+176) {
		tmp = fma((fma(((0.5 / n) - 0.5), x, 1.0) / n), x, 1.0) - t_0;
	} else {
		tmp = ((x / (n * n)) * 0.5) * x;
	}
	return tmp;
}
function code(x, n)
	t_0 = x ^ (n ^ -1.0)
	t_1 = Float64(Float64(t_0 / x) / n)
	t_2 = Float64(Float64(x - log(x)) / n)
	tmp = 0.0
	if ((n ^ -1.0) <= -5e-165)
		tmp = t_1;
	elseif ((n ^ -1.0) <= -5e-213)
		tmp = t_2;
	elseif ((n ^ -1.0) <= -2e-259)
		tmp = t_1;
	elseif ((n ^ -1.0) <= 2e-12)
		tmp = t_2;
	elseif ((n ^ -1.0) <= 4e+176)
		tmp = Float64(fma(Float64(fma(Float64(Float64(0.5 / n) - 0.5), x, 1.0) / n), x, 1.0) - t_0);
	else
		tmp = Float64(Float64(Float64(x / Float64(n * n)) * 0.5) * x);
	end
	return tmp
end
code[x_, n_] := Block[{t$95$0 = N[Power[x, N[Power[n, -1.0], $MachinePrecision]], $MachinePrecision]}, Block[{t$95$1 = N[(N[(t$95$0 / x), $MachinePrecision] / n), $MachinePrecision]}, Block[{t$95$2 = N[(N[(x - N[Log[x], $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision]}, If[LessEqual[N[Power[n, -1.0], $MachinePrecision], -5e-165], t$95$1, If[LessEqual[N[Power[n, -1.0], $MachinePrecision], -5e-213], t$95$2, If[LessEqual[N[Power[n, -1.0], $MachinePrecision], -2e-259], t$95$1, If[LessEqual[N[Power[n, -1.0], $MachinePrecision], 2e-12], t$95$2, If[LessEqual[N[Power[n, -1.0], $MachinePrecision], 4e+176], N[(N[(N[(N[(N[(N[(0.5 / n), $MachinePrecision] - 0.5), $MachinePrecision] * x + 1.0), $MachinePrecision] / n), $MachinePrecision] * x + 1.0), $MachinePrecision] - t$95$0), $MachinePrecision], N[(N[(N[(x / N[(n * n), $MachinePrecision]), $MachinePrecision] * 0.5), $MachinePrecision] * x), $MachinePrecision]]]]]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {x}^{\left({n}^{-1}\right)}\\
t_1 := \frac{\frac{t\_0}{x}}{n}\\
t_2 := \frac{x - \log x}{n}\\
\mathbf{if}\;{n}^{-1} \leq -5 \cdot 10^{-165}:\\
\;\;\;\;t\_1\\

\mathbf{elif}\;{n}^{-1} \leq -5 \cdot 10^{-213}:\\
\;\;\;\;t\_2\\

\mathbf{elif}\;{n}^{-1} \leq -2 \cdot 10^{-259}:\\
\;\;\;\;t\_1\\

\mathbf{elif}\;{n}^{-1} \leq 2 \cdot 10^{-12}:\\
\;\;\;\;t\_2\\

\mathbf{elif}\;{n}^{-1} \leq 4 \cdot 10^{+176}:\\
\;\;\;\;\mathsf{fma}\left(\frac{\mathsf{fma}\left(\frac{0.5}{n} - 0.5, x, 1\right)}{n}, x, 1\right) - t\_0\\

\mathbf{else}:\\
\;\;\;\;\left(\frac{x}{n \cdot n} \cdot 0.5\right) \cdot x\\


\end{array}
\end{array}
Derivation
  1. Split input into 4 regimes
  2. if (/.f64 #s(literal 1 binary64) n) < -4.99999999999999981e-165 or -4.99999999999999977e-213 < (/.f64 #s(literal 1 binary64) n) < -2.0000000000000001e-259

    1. Initial program 74.6%

      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in x around inf

      \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
    4. Step-by-step derivation
      1. associate-/l/N/A

        \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
      2. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
      3. lower-/.f64N/A

        \[\leadsto \frac{\color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}}{n} \]
      4. log-recN/A

        \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{x}}{n} \]
      5. mul-1-negN/A

        \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{x}}{n} \]
      6. associate-*r/N/A

        \[\leadsto \frac{\frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{x}}{n} \]
      7. associate-*r*N/A

        \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{x}}{n} \]
      8. metadata-evalN/A

        \[\leadsto \frac{\frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{x}}{n} \]
      9. *-commutativeN/A

        \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{x}}{n} \]
      10. associate-/l*N/A

        \[\leadsto \frac{\frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{x}}{n} \]
      11. exp-to-powN/A

        \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
      12. lower-pow.f64N/A

        \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
      13. lower-/.f6486.1

        \[\leadsto \frac{\frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{x}}{n} \]
    5. Applied rewrites86.1%

      \[\leadsto \color{blue}{\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}} \]

    if -4.99999999999999981e-165 < (/.f64 #s(literal 1 binary64) n) < -4.99999999999999977e-213 or -2.0000000000000001e-259 < (/.f64 #s(literal 1 binary64) n) < 1.99999999999999996e-12

    1. Initial program 21.5%

      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \color{blue}{\left(1 + \frac{x}{n}\right) - e^{\frac{\log x}{n}}} \]
    4. Step-by-step derivation
      1. associate--l+N/A

        \[\leadsto \color{blue}{1 + \left(\frac{x}{n} - e^{\frac{\log x}{n}}\right)} \]
      2. +-commutativeN/A

        \[\leadsto \color{blue}{\left(\frac{x}{n} - e^{\frac{\log x}{n}}\right) + 1} \]
      3. *-rgt-identityN/A

        \[\leadsto \left(\frac{\color{blue}{x \cdot 1}}{n} - e^{\frac{\log x}{n}}\right) + 1 \]
      4. associate-*r/N/A

        \[\leadsto \left(\color{blue}{x \cdot \frac{1}{n}} - e^{\frac{\log x}{n}}\right) + 1 \]
      5. remove-double-negN/A

        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\frac{\color{blue}{\mathsf{neg}\left(\left(\mathsf{neg}\left(\log x\right)\right)\right)}}{n}}\right) + 1 \]
      6. mul-1-negN/A

        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\frac{\mathsf{neg}\left(\color{blue}{-1 \cdot \log x}\right)}{n}}\right) + 1 \]
      7. distribute-neg-fracN/A

        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\color{blue}{\mathsf{neg}\left(\frac{-1 \cdot \log x}{n}\right)}}\right) + 1 \]
      8. mul-1-negN/A

        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\mathsf{neg}\left(\frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}\right)}\right) + 1 \]
      9. log-recN/A

        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\mathsf{neg}\left(\frac{\color{blue}{\log \left(\frac{1}{x}\right)}}{n}\right)}\right) + 1 \]
      10. mul-1-negN/A

        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\color{blue}{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}\right) + 1 \]
      11. associate-+l-N/A

        \[\leadsto \color{blue}{x \cdot \frac{1}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right)} \]
      12. lower--.f64N/A

        \[\leadsto \color{blue}{x \cdot \frac{1}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right)} \]
      13. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{x \cdot 1}{n}} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
      14. *-rgt-identityN/A

        \[\leadsto \frac{\color{blue}{x}}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
      15. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{x}{n}} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
    5. Applied rewrites62.7%

      \[\leadsto \color{blue}{\frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)} \]
    6. Taylor expanded in n around inf

      \[\leadsto \frac{x - \log x}{\color{blue}{n}} \]
    7. Step-by-step derivation
      1. Applied rewrites62.6%

        \[\leadsto \frac{x - \log x}{\color{blue}{n}} \]

      if 1.99999999999999996e-12 < (/.f64 #s(literal 1 binary64) n) < 4e176

      1. Initial program 72.2%

        \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
      2. Add Preprocessing
      3. Taylor expanded in x around 0

        \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right)} - {x}^{\left(\frac{1}{n}\right)} \]
      4. Step-by-step derivation
        1. +-commutativeN/A

          \[\leadsto \color{blue}{\left(x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) + 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
        2. *-commutativeN/A

          \[\leadsto \left(\color{blue}{\left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) \cdot x} + 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
        3. lower-fma.f64N/A

          \[\leadsto \color{blue}{\mathsf{fma}\left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}, x, 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
        4. *-commutativeN/A

          \[\leadsto \mathsf{fma}\left(\color{blue}{\left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) \cdot x} + \frac{1}{n}, x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
        5. lower-fma.f64N/A

          \[\leadsto \mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right)}, x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
        6. lower--.f64N/A

          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
        7. associate-*r/N/A

          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\frac{\frac{1}{2} \cdot 1}{{n}^{2}}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
        8. metadata-evalN/A

          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\color{blue}{\frac{1}{2}}}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
        9. lower-/.f64N/A

          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\frac{\frac{1}{2}}{{n}^{2}}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
        10. unpow2N/A

          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{\color{blue}{n \cdot n}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
        11. lower-*.f64N/A

          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{\color{blue}{n \cdot n}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
        12. associate-*r/N/A

          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{n \cdot n} - \color{blue}{\frac{\frac{1}{2} \cdot 1}{n}}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
        13. metadata-evalN/A

          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{n \cdot n} - \frac{\color{blue}{\frac{1}{2}}}{n}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
        14. lower-/.f64N/A

          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{n \cdot n} - \color{blue}{\frac{\frac{1}{2}}{n}}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
        15. lower-/.f6457.8

          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, x, \color{blue}{\frac{1}{n}}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
      5. Applied rewrites57.8%

        \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, x, \frac{1}{n}\right), x, 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
      6. Taylor expanded in n around inf

        \[\leadsto \mathsf{fma}\left(\frac{1 + \left(\frac{-1}{2} \cdot x + \frac{1}{2} \cdot \frac{x}{n}\right)}{n}, x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
      7. Step-by-step derivation
        1. Applied rewrites65.3%

          \[\leadsto \mathsf{fma}\left(\frac{\mathsf{fma}\left(\frac{0.5}{n} - 0.5, x, 1\right)}{n}, x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]

        if 4e176 < (/.f64 #s(literal 1 binary64) n)

        1. Initial program 8.2%

          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
        2. Add Preprocessing
        3. Taylor expanded in x around 0

          \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right) - e^{\frac{\log x}{n}}} \]
        4. Applied rewrites57.9%

          \[\leadsto \color{blue}{\mathsf{fma}\left(x \cdot x, \frac{0.5}{n \cdot n} - \frac{0.5}{n}, \frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)\right)} \]
        5. Taylor expanded in n around 0

          \[\leadsto \frac{\frac{1}{2} \cdot {x}^{2} + n \cdot \left(x + \frac{-1}{2} \cdot {x}^{2}\right)}{\color{blue}{{n}^{2}}} \]
        6. Step-by-step derivation
          1. Applied rewrites34.2%

            \[\leadsto \frac{\frac{\mathsf{fma}\left(\mathsf{fma}\left(-0.5, x, 1\right) \cdot n, x, \left(0.5 \cdot x\right) \cdot x\right)}{n}}{\color{blue}{n}} \]
          2. Taylor expanded in x around 0

            \[\leadsto x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \color{blue}{\frac{1}{n}}\right) \]
          3. Step-by-step derivation
            1. Applied rewrites94.9%

              \[\leadsto \mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, x, \frac{1}{n}\right) \cdot x \]
            2. Taylor expanded in n around 0

              \[\leadsto \left(\frac{1}{2} \cdot \frac{x}{{n}^{2}}\right) \cdot x \]
            3. Step-by-step derivation
              1. Applied rewrites94.9%

                \[\leadsto \left(\frac{x}{n \cdot n} \cdot 0.5\right) \cdot x \]
            4. Recombined 4 regimes into one program.
            5. Final simplification76.2%

              \[\leadsto \begin{array}{l} \mathbf{if}\;{n}^{-1} \leq -5 \cdot 10^{-165}:\\ \;\;\;\;\frac{\frac{{x}^{\left({n}^{-1}\right)}}{x}}{n}\\ \mathbf{elif}\;{n}^{-1} \leq -5 \cdot 10^{-213}:\\ \;\;\;\;\frac{x - \log x}{n}\\ \mathbf{elif}\;{n}^{-1} \leq -2 \cdot 10^{-259}:\\ \;\;\;\;\frac{\frac{{x}^{\left({n}^{-1}\right)}}{x}}{n}\\ \mathbf{elif}\;{n}^{-1} \leq 2 \cdot 10^{-12}:\\ \;\;\;\;\frac{x - \log x}{n}\\ \mathbf{elif}\;{n}^{-1} \leq 4 \cdot 10^{+176}:\\ \;\;\;\;\mathsf{fma}\left(\frac{\mathsf{fma}\left(\frac{0.5}{n} - 0.5, x, 1\right)}{n}, x, 1\right) - {x}^{\left({n}^{-1}\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(\frac{x}{n \cdot n} \cdot 0.5\right) \cdot x\\ \end{array} \]
            6. Add Preprocessing

            Alternative 3: 68.7% accurate, 0.3× speedup?

            \[\begin{array}{l} \\ \begin{array}{l} t_0 := {x}^{\left({n}^{-1}\right)}\\ t_1 := \frac{\frac{t\_0}{x}}{n}\\ t_2 := \frac{x - \log x}{n}\\ \mathbf{if}\;{n}^{-1} \leq -5 \cdot 10^{-165}:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;{n}^{-1} \leq -5 \cdot 10^{-213}:\\ \;\;\;\;t\_2\\ \mathbf{elif}\;{n}^{-1} \leq -2 \cdot 10^{-259}:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;{n}^{-1} \leq 2 \cdot 10^{-12}:\\ \;\;\;\;t\_2\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, x, {n}^{-1}\right), x, 1\right) - t\_0\\ \end{array} \end{array} \]
            (FPCore (x n)
             :precision binary64
             (let* ((t_0 (pow x (pow n -1.0)))
                    (t_1 (/ (/ t_0 x) n))
                    (t_2 (/ (- x (log x)) n)))
               (if (<= (pow n -1.0) -5e-165)
                 t_1
                 (if (<= (pow n -1.0) -5e-213)
                   t_2
                   (if (<= (pow n -1.0) -2e-259)
                     t_1
                     (if (<= (pow n -1.0) 2e-12)
                       t_2
                       (-
                        (fma (fma (- (/ 0.5 (* n n)) (/ 0.5 n)) x (pow n -1.0)) x 1.0)
                        t_0)))))))
            double code(double x, double n) {
            	double t_0 = pow(x, pow(n, -1.0));
            	double t_1 = (t_0 / x) / n;
            	double t_2 = (x - log(x)) / n;
            	double tmp;
            	if (pow(n, -1.0) <= -5e-165) {
            		tmp = t_1;
            	} else if (pow(n, -1.0) <= -5e-213) {
            		tmp = t_2;
            	} else if (pow(n, -1.0) <= -2e-259) {
            		tmp = t_1;
            	} else if (pow(n, -1.0) <= 2e-12) {
            		tmp = t_2;
            	} else {
            		tmp = fma(fma(((0.5 / (n * n)) - (0.5 / n)), x, pow(n, -1.0)), x, 1.0) - t_0;
            	}
            	return tmp;
            }
            
            function code(x, n)
            	t_0 = x ^ (n ^ -1.0)
            	t_1 = Float64(Float64(t_0 / x) / n)
            	t_2 = Float64(Float64(x - log(x)) / n)
            	tmp = 0.0
            	if ((n ^ -1.0) <= -5e-165)
            		tmp = t_1;
            	elseif ((n ^ -1.0) <= -5e-213)
            		tmp = t_2;
            	elseif ((n ^ -1.0) <= -2e-259)
            		tmp = t_1;
            	elseif ((n ^ -1.0) <= 2e-12)
            		tmp = t_2;
            	else
            		tmp = Float64(fma(fma(Float64(Float64(0.5 / Float64(n * n)) - Float64(0.5 / n)), x, (n ^ -1.0)), x, 1.0) - t_0);
            	end
            	return tmp
            end
            
            code[x_, n_] := Block[{t$95$0 = N[Power[x, N[Power[n, -1.0], $MachinePrecision]], $MachinePrecision]}, Block[{t$95$1 = N[(N[(t$95$0 / x), $MachinePrecision] / n), $MachinePrecision]}, Block[{t$95$2 = N[(N[(x - N[Log[x], $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision]}, If[LessEqual[N[Power[n, -1.0], $MachinePrecision], -5e-165], t$95$1, If[LessEqual[N[Power[n, -1.0], $MachinePrecision], -5e-213], t$95$2, If[LessEqual[N[Power[n, -1.0], $MachinePrecision], -2e-259], t$95$1, If[LessEqual[N[Power[n, -1.0], $MachinePrecision], 2e-12], t$95$2, N[(N[(N[(N[(N[(0.5 / N[(n * n), $MachinePrecision]), $MachinePrecision] - N[(0.5 / n), $MachinePrecision]), $MachinePrecision] * x + N[Power[n, -1.0], $MachinePrecision]), $MachinePrecision] * x + 1.0), $MachinePrecision] - t$95$0), $MachinePrecision]]]]]]]]
            
            \begin{array}{l}
            
            \\
            \begin{array}{l}
            t_0 := {x}^{\left({n}^{-1}\right)}\\
            t_1 := \frac{\frac{t\_0}{x}}{n}\\
            t_2 := \frac{x - \log x}{n}\\
            \mathbf{if}\;{n}^{-1} \leq -5 \cdot 10^{-165}:\\
            \;\;\;\;t\_1\\
            
            \mathbf{elif}\;{n}^{-1} \leq -5 \cdot 10^{-213}:\\
            \;\;\;\;t\_2\\
            
            \mathbf{elif}\;{n}^{-1} \leq -2 \cdot 10^{-259}:\\
            \;\;\;\;t\_1\\
            
            \mathbf{elif}\;{n}^{-1} \leq 2 \cdot 10^{-12}:\\
            \;\;\;\;t\_2\\
            
            \mathbf{else}:\\
            \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, x, {n}^{-1}\right), x, 1\right) - t\_0\\
            
            
            \end{array}
            \end{array}
            
            Derivation
            1. Split input into 3 regimes
            2. if (/.f64 #s(literal 1 binary64) n) < -4.99999999999999981e-165 or -4.99999999999999977e-213 < (/.f64 #s(literal 1 binary64) n) < -2.0000000000000001e-259

              1. Initial program 74.6%

                \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
              2. Add Preprocessing
              3. Taylor expanded in x around inf

                \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
              4. Step-by-step derivation
                1. associate-/l/N/A

                  \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                2. lower-/.f64N/A

                  \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                3. lower-/.f64N/A

                  \[\leadsto \frac{\color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}}{n} \]
                4. log-recN/A

                  \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{x}}{n} \]
                5. mul-1-negN/A

                  \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{x}}{n} \]
                6. associate-*r/N/A

                  \[\leadsto \frac{\frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{x}}{n} \]
                7. associate-*r*N/A

                  \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{x}}{n} \]
                8. metadata-evalN/A

                  \[\leadsto \frac{\frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{x}}{n} \]
                9. *-commutativeN/A

                  \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{x}}{n} \]
                10. associate-/l*N/A

                  \[\leadsto \frac{\frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{x}}{n} \]
                11. exp-to-powN/A

                  \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                12. lower-pow.f64N/A

                  \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                13. lower-/.f6486.1

                  \[\leadsto \frac{\frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{x}}{n} \]
              5. Applied rewrites86.1%

                \[\leadsto \color{blue}{\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}} \]

              if -4.99999999999999981e-165 < (/.f64 #s(literal 1 binary64) n) < -4.99999999999999977e-213 or -2.0000000000000001e-259 < (/.f64 #s(literal 1 binary64) n) < 1.99999999999999996e-12

              1. Initial program 21.5%

                \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
              2. Add Preprocessing
              3. Taylor expanded in x around 0

                \[\leadsto \color{blue}{\left(1 + \frac{x}{n}\right) - e^{\frac{\log x}{n}}} \]
              4. Step-by-step derivation
                1. associate--l+N/A

                  \[\leadsto \color{blue}{1 + \left(\frac{x}{n} - e^{\frac{\log x}{n}}\right)} \]
                2. +-commutativeN/A

                  \[\leadsto \color{blue}{\left(\frac{x}{n} - e^{\frac{\log x}{n}}\right) + 1} \]
                3. *-rgt-identityN/A

                  \[\leadsto \left(\frac{\color{blue}{x \cdot 1}}{n} - e^{\frac{\log x}{n}}\right) + 1 \]
                4. associate-*r/N/A

                  \[\leadsto \left(\color{blue}{x \cdot \frac{1}{n}} - e^{\frac{\log x}{n}}\right) + 1 \]
                5. remove-double-negN/A

                  \[\leadsto \left(x \cdot \frac{1}{n} - e^{\frac{\color{blue}{\mathsf{neg}\left(\left(\mathsf{neg}\left(\log x\right)\right)\right)}}{n}}\right) + 1 \]
                6. mul-1-negN/A

                  \[\leadsto \left(x \cdot \frac{1}{n} - e^{\frac{\mathsf{neg}\left(\color{blue}{-1 \cdot \log x}\right)}{n}}\right) + 1 \]
                7. distribute-neg-fracN/A

                  \[\leadsto \left(x \cdot \frac{1}{n} - e^{\color{blue}{\mathsf{neg}\left(\frac{-1 \cdot \log x}{n}\right)}}\right) + 1 \]
                8. mul-1-negN/A

                  \[\leadsto \left(x \cdot \frac{1}{n} - e^{\mathsf{neg}\left(\frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}\right)}\right) + 1 \]
                9. log-recN/A

                  \[\leadsto \left(x \cdot \frac{1}{n} - e^{\mathsf{neg}\left(\frac{\color{blue}{\log \left(\frac{1}{x}\right)}}{n}\right)}\right) + 1 \]
                10. mul-1-negN/A

                  \[\leadsto \left(x \cdot \frac{1}{n} - e^{\color{blue}{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}\right) + 1 \]
                11. associate-+l-N/A

                  \[\leadsto \color{blue}{x \cdot \frac{1}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right)} \]
                12. lower--.f64N/A

                  \[\leadsto \color{blue}{x \cdot \frac{1}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right)} \]
                13. associate-*r/N/A

                  \[\leadsto \color{blue}{\frac{x \cdot 1}{n}} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
                14. *-rgt-identityN/A

                  \[\leadsto \frac{\color{blue}{x}}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
                15. lower-/.f64N/A

                  \[\leadsto \color{blue}{\frac{x}{n}} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
              5. Applied rewrites62.7%

                \[\leadsto \color{blue}{\frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)} \]
              6. Taylor expanded in n around inf

                \[\leadsto \frac{x - \log x}{\color{blue}{n}} \]
              7. Step-by-step derivation
                1. Applied rewrites62.6%

                  \[\leadsto \frac{x - \log x}{\color{blue}{n}} \]

                if 1.99999999999999996e-12 < (/.f64 #s(literal 1 binary64) n)

                1. Initial program 45.2%

                  \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                2. Add Preprocessing
                3. Taylor expanded in x around 0

                  \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                4. Step-by-step derivation
                  1. +-commutativeN/A

                    \[\leadsto \color{blue}{\left(x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) + 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                  2. *-commutativeN/A

                    \[\leadsto \left(\color{blue}{\left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) \cdot x} + 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                  3. lower-fma.f64N/A

                    \[\leadsto \color{blue}{\mathsf{fma}\left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}, x, 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                  4. *-commutativeN/A

                    \[\leadsto \mathsf{fma}\left(\color{blue}{\left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) \cdot x} + \frac{1}{n}, x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                  5. lower-fma.f64N/A

                    \[\leadsto \mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right)}, x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                  6. lower--.f64N/A

                    \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                  7. associate-*r/N/A

                    \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\frac{\frac{1}{2} \cdot 1}{{n}^{2}}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                  8. metadata-evalN/A

                    \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\color{blue}{\frac{1}{2}}}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                  9. lower-/.f64N/A

                    \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\frac{\frac{1}{2}}{{n}^{2}}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                  10. unpow2N/A

                    \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{\color{blue}{n \cdot n}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                  11. lower-*.f64N/A

                    \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{\color{blue}{n \cdot n}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                  12. associate-*r/N/A

                    \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{n \cdot n} - \color{blue}{\frac{\frac{1}{2} \cdot 1}{n}}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                  13. metadata-evalN/A

                    \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{n \cdot n} - \frac{\color{blue}{\frac{1}{2}}}{n}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                  14. lower-/.f64N/A

                    \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{n \cdot n} - \color{blue}{\frac{\frac{1}{2}}{n}}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                  15. lower-/.f6473.4

                    \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, x, \color{blue}{\frac{1}{n}}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                5. Applied rewrites73.4%

                  \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, x, \frac{1}{n}\right), x, 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
              8. Recombined 3 regimes into one program.
              9. Final simplification75.4%

                \[\leadsto \begin{array}{l} \mathbf{if}\;{n}^{-1} \leq -5 \cdot 10^{-165}:\\ \;\;\;\;\frac{\frac{{x}^{\left({n}^{-1}\right)}}{x}}{n}\\ \mathbf{elif}\;{n}^{-1} \leq -5 \cdot 10^{-213}:\\ \;\;\;\;\frac{x - \log x}{n}\\ \mathbf{elif}\;{n}^{-1} \leq -2 \cdot 10^{-259}:\\ \;\;\;\;\frac{\frac{{x}^{\left({n}^{-1}\right)}}{x}}{n}\\ \mathbf{elif}\;{n}^{-1} \leq 2 \cdot 10^{-12}:\\ \;\;\;\;\frac{x - \log x}{n}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, x, {n}^{-1}\right), x, 1\right) - {x}^{\left({n}^{-1}\right)}\\ \end{array} \]
              10. Add Preprocessing

              Alternative 4: 68.5% accurate, 0.3× speedup?

              \[\begin{array}{l} \\ \begin{array}{l} t_0 := {x}^{\left({n}^{-1}\right)}\\ t_1 := \frac{\frac{t\_0}{x}}{n}\\ t_2 := \frac{x - \log x}{n}\\ \mathbf{if}\;{n}^{-1} \leq -5 \cdot 10^{-165}:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;{n}^{-1} \leq -5 \cdot 10^{-213}:\\ \;\;\;\;t\_2\\ \mathbf{elif}\;{n}^{-1} \leq -2 \cdot 10^{-259}:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;{n}^{-1} \leq 5 \cdot 10^{-16}:\\ \;\;\;\;t\_2\\ \mathbf{elif}\;{n}^{-1} \leq 4 \cdot 10^{+176}:\\ \;\;\;\;\left(\frac{x}{n} + 1\right) - t\_0\\ \mathbf{else}:\\ \;\;\;\;\left(\frac{x}{n \cdot n} \cdot 0.5\right) \cdot x\\ \end{array} \end{array} \]
              (FPCore (x n)
               :precision binary64
               (let* ((t_0 (pow x (pow n -1.0)))
                      (t_1 (/ (/ t_0 x) n))
                      (t_2 (/ (- x (log x)) n)))
                 (if (<= (pow n -1.0) -5e-165)
                   t_1
                   (if (<= (pow n -1.0) -5e-213)
                     t_2
                     (if (<= (pow n -1.0) -2e-259)
                       t_1
                       (if (<= (pow n -1.0) 5e-16)
                         t_2
                         (if (<= (pow n -1.0) 4e+176)
                           (- (+ (/ x n) 1.0) t_0)
                           (* (* (/ x (* n n)) 0.5) x))))))))
              double code(double x, double n) {
              	double t_0 = pow(x, pow(n, -1.0));
              	double t_1 = (t_0 / x) / n;
              	double t_2 = (x - log(x)) / n;
              	double tmp;
              	if (pow(n, -1.0) <= -5e-165) {
              		tmp = t_1;
              	} else if (pow(n, -1.0) <= -5e-213) {
              		tmp = t_2;
              	} else if (pow(n, -1.0) <= -2e-259) {
              		tmp = t_1;
              	} else if (pow(n, -1.0) <= 5e-16) {
              		tmp = t_2;
              	} else if (pow(n, -1.0) <= 4e+176) {
              		tmp = ((x / n) + 1.0) - t_0;
              	} else {
              		tmp = ((x / (n * n)) * 0.5) * x;
              	}
              	return tmp;
              }
              
              real(8) function code(x, n)
                  real(8), intent (in) :: x
                  real(8), intent (in) :: n
                  real(8) :: t_0
                  real(8) :: t_1
                  real(8) :: t_2
                  real(8) :: tmp
                  t_0 = x ** (n ** (-1.0d0))
                  t_1 = (t_0 / x) / n
                  t_2 = (x - log(x)) / n
                  if ((n ** (-1.0d0)) <= (-5d-165)) then
                      tmp = t_1
                  else if ((n ** (-1.0d0)) <= (-5d-213)) then
                      tmp = t_2
                  else if ((n ** (-1.0d0)) <= (-2d-259)) then
                      tmp = t_1
                  else if ((n ** (-1.0d0)) <= 5d-16) then
                      tmp = t_2
                  else if ((n ** (-1.0d0)) <= 4d+176) then
                      tmp = ((x / n) + 1.0d0) - t_0
                  else
                      tmp = ((x / (n * n)) * 0.5d0) * x
                  end if
                  code = tmp
              end function
              
              public static double code(double x, double n) {
              	double t_0 = Math.pow(x, Math.pow(n, -1.0));
              	double t_1 = (t_0 / x) / n;
              	double t_2 = (x - Math.log(x)) / n;
              	double tmp;
              	if (Math.pow(n, -1.0) <= -5e-165) {
              		tmp = t_1;
              	} else if (Math.pow(n, -1.0) <= -5e-213) {
              		tmp = t_2;
              	} else if (Math.pow(n, -1.0) <= -2e-259) {
              		tmp = t_1;
              	} else if (Math.pow(n, -1.0) <= 5e-16) {
              		tmp = t_2;
              	} else if (Math.pow(n, -1.0) <= 4e+176) {
              		tmp = ((x / n) + 1.0) - t_0;
              	} else {
              		tmp = ((x / (n * n)) * 0.5) * x;
              	}
              	return tmp;
              }
              
              def code(x, n):
              	t_0 = math.pow(x, math.pow(n, -1.0))
              	t_1 = (t_0 / x) / n
              	t_2 = (x - math.log(x)) / n
              	tmp = 0
              	if math.pow(n, -1.0) <= -5e-165:
              		tmp = t_1
              	elif math.pow(n, -1.0) <= -5e-213:
              		tmp = t_2
              	elif math.pow(n, -1.0) <= -2e-259:
              		tmp = t_1
              	elif math.pow(n, -1.0) <= 5e-16:
              		tmp = t_2
              	elif math.pow(n, -1.0) <= 4e+176:
              		tmp = ((x / n) + 1.0) - t_0
              	else:
              		tmp = ((x / (n * n)) * 0.5) * x
              	return tmp
              
              function code(x, n)
              	t_0 = x ^ (n ^ -1.0)
              	t_1 = Float64(Float64(t_0 / x) / n)
              	t_2 = Float64(Float64(x - log(x)) / n)
              	tmp = 0.0
              	if ((n ^ -1.0) <= -5e-165)
              		tmp = t_1;
              	elseif ((n ^ -1.0) <= -5e-213)
              		tmp = t_2;
              	elseif ((n ^ -1.0) <= -2e-259)
              		tmp = t_1;
              	elseif ((n ^ -1.0) <= 5e-16)
              		tmp = t_2;
              	elseif ((n ^ -1.0) <= 4e+176)
              		tmp = Float64(Float64(Float64(x / n) + 1.0) - t_0);
              	else
              		tmp = Float64(Float64(Float64(x / Float64(n * n)) * 0.5) * x);
              	end
              	return tmp
              end
              
              function tmp_2 = code(x, n)
              	t_0 = x ^ (n ^ -1.0);
              	t_1 = (t_0 / x) / n;
              	t_2 = (x - log(x)) / n;
              	tmp = 0.0;
              	if ((n ^ -1.0) <= -5e-165)
              		tmp = t_1;
              	elseif ((n ^ -1.0) <= -5e-213)
              		tmp = t_2;
              	elseif ((n ^ -1.0) <= -2e-259)
              		tmp = t_1;
              	elseif ((n ^ -1.0) <= 5e-16)
              		tmp = t_2;
              	elseif ((n ^ -1.0) <= 4e+176)
              		tmp = ((x / n) + 1.0) - t_0;
              	else
              		tmp = ((x / (n * n)) * 0.5) * x;
              	end
              	tmp_2 = tmp;
              end
              
              code[x_, n_] := Block[{t$95$0 = N[Power[x, N[Power[n, -1.0], $MachinePrecision]], $MachinePrecision]}, Block[{t$95$1 = N[(N[(t$95$0 / x), $MachinePrecision] / n), $MachinePrecision]}, Block[{t$95$2 = N[(N[(x - N[Log[x], $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision]}, If[LessEqual[N[Power[n, -1.0], $MachinePrecision], -5e-165], t$95$1, If[LessEqual[N[Power[n, -1.0], $MachinePrecision], -5e-213], t$95$2, If[LessEqual[N[Power[n, -1.0], $MachinePrecision], -2e-259], t$95$1, If[LessEqual[N[Power[n, -1.0], $MachinePrecision], 5e-16], t$95$2, If[LessEqual[N[Power[n, -1.0], $MachinePrecision], 4e+176], N[(N[(N[(x / n), $MachinePrecision] + 1.0), $MachinePrecision] - t$95$0), $MachinePrecision], N[(N[(N[(x / N[(n * n), $MachinePrecision]), $MachinePrecision] * 0.5), $MachinePrecision] * x), $MachinePrecision]]]]]]]]]
              
              \begin{array}{l}
              
              \\
              \begin{array}{l}
              t_0 := {x}^{\left({n}^{-1}\right)}\\
              t_1 := \frac{\frac{t\_0}{x}}{n}\\
              t_2 := \frac{x - \log x}{n}\\
              \mathbf{if}\;{n}^{-1} \leq -5 \cdot 10^{-165}:\\
              \;\;\;\;t\_1\\
              
              \mathbf{elif}\;{n}^{-1} \leq -5 \cdot 10^{-213}:\\
              \;\;\;\;t\_2\\
              
              \mathbf{elif}\;{n}^{-1} \leq -2 \cdot 10^{-259}:\\
              \;\;\;\;t\_1\\
              
              \mathbf{elif}\;{n}^{-1} \leq 5 \cdot 10^{-16}:\\
              \;\;\;\;t\_2\\
              
              \mathbf{elif}\;{n}^{-1} \leq 4 \cdot 10^{+176}:\\
              \;\;\;\;\left(\frac{x}{n} + 1\right) - t\_0\\
              
              \mathbf{else}:\\
              \;\;\;\;\left(\frac{x}{n \cdot n} \cdot 0.5\right) \cdot x\\
              
              
              \end{array}
              \end{array}
              
              Derivation
              1. Split input into 4 regimes
              2. if (/.f64 #s(literal 1 binary64) n) < -4.99999999999999981e-165 or -4.99999999999999977e-213 < (/.f64 #s(literal 1 binary64) n) < -2.0000000000000001e-259

                1. Initial program 74.6%

                  \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                2. Add Preprocessing
                3. Taylor expanded in x around inf

                  \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                4. Step-by-step derivation
                  1. associate-/l/N/A

                    \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                  2. lower-/.f64N/A

                    \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                  3. lower-/.f64N/A

                    \[\leadsto \frac{\color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}}{n} \]
                  4. log-recN/A

                    \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{x}}{n} \]
                  5. mul-1-negN/A

                    \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{x}}{n} \]
                  6. associate-*r/N/A

                    \[\leadsto \frac{\frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{x}}{n} \]
                  7. associate-*r*N/A

                    \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{x}}{n} \]
                  8. metadata-evalN/A

                    \[\leadsto \frac{\frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{x}}{n} \]
                  9. *-commutativeN/A

                    \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{x}}{n} \]
                  10. associate-/l*N/A

                    \[\leadsto \frac{\frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{x}}{n} \]
                  11. exp-to-powN/A

                    \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                  12. lower-pow.f64N/A

                    \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                  13. lower-/.f6486.1

                    \[\leadsto \frac{\frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                5. Applied rewrites86.1%

                  \[\leadsto \color{blue}{\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}} \]

                if -4.99999999999999981e-165 < (/.f64 #s(literal 1 binary64) n) < -4.99999999999999977e-213 or -2.0000000000000001e-259 < (/.f64 #s(literal 1 binary64) n) < 5.0000000000000004e-16

                1. Initial program 21.7%

                  \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                2. Add Preprocessing
                3. Taylor expanded in x around 0

                  \[\leadsto \color{blue}{\left(1 + \frac{x}{n}\right) - e^{\frac{\log x}{n}}} \]
                4. Step-by-step derivation
                  1. associate--l+N/A

                    \[\leadsto \color{blue}{1 + \left(\frac{x}{n} - e^{\frac{\log x}{n}}\right)} \]
                  2. +-commutativeN/A

                    \[\leadsto \color{blue}{\left(\frac{x}{n} - e^{\frac{\log x}{n}}\right) + 1} \]
                  3. *-rgt-identityN/A

                    \[\leadsto \left(\frac{\color{blue}{x \cdot 1}}{n} - e^{\frac{\log x}{n}}\right) + 1 \]
                  4. associate-*r/N/A

                    \[\leadsto \left(\color{blue}{x \cdot \frac{1}{n}} - e^{\frac{\log x}{n}}\right) + 1 \]
                  5. remove-double-negN/A

                    \[\leadsto \left(x \cdot \frac{1}{n} - e^{\frac{\color{blue}{\mathsf{neg}\left(\left(\mathsf{neg}\left(\log x\right)\right)\right)}}{n}}\right) + 1 \]
                  6. mul-1-negN/A

                    \[\leadsto \left(x \cdot \frac{1}{n} - e^{\frac{\mathsf{neg}\left(\color{blue}{-1 \cdot \log x}\right)}{n}}\right) + 1 \]
                  7. distribute-neg-fracN/A

                    \[\leadsto \left(x \cdot \frac{1}{n} - e^{\color{blue}{\mathsf{neg}\left(\frac{-1 \cdot \log x}{n}\right)}}\right) + 1 \]
                  8. mul-1-negN/A

                    \[\leadsto \left(x \cdot \frac{1}{n} - e^{\mathsf{neg}\left(\frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}\right)}\right) + 1 \]
                  9. log-recN/A

                    \[\leadsto \left(x \cdot \frac{1}{n} - e^{\mathsf{neg}\left(\frac{\color{blue}{\log \left(\frac{1}{x}\right)}}{n}\right)}\right) + 1 \]
                  10. mul-1-negN/A

                    \[\leadsto \left(x \cdot \frac{1}{n} - e^{\color{blue}{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}\right) + 1 \]
                  11. associate-+l-N/A

                    \[\leadsto \color{blue}{x \cdot \frac{1}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right)} \]
                  12. lower--.f64N/A

                    \[\leadsto \color{blue}{x \cdot \frac{1}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right)} \]
                  13. associate-*r/N/A

                    \[\leadsto \color{blue}{\frac{x \cdot 1}{n}} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
                  14. *-rgt-identityN/A

                    \[\leadsto \frac{\color{blue}{x}}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
                  15. lower-/.f64N/A

                    \[\leadsto \color{blue}{\frac{x}{n}} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
                5. Applied rewrites63.4%

                  \[\leadsto \color{blue}{\frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)} \]
                6. Taylor expanded in n around inf

                  \[\leadsto \frac{x - \log x}{\color{blue}{n}} \]
                7. Step-by-step derivation
                  1. Applied rewrites63.3%

                    \[\leadsto \frac{x - \log x}{\color{blue}{n}} \]

                  if 5.0000000000000004e-16 < (/.f64 #s(literal 1 binary64) n) < 4e176

                  1. Initial program 69.7%

                    \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                  2. Add Preprocessing
                  3. Taylor expanded in x around 0

                    \[\leadsto \color{blue}{\left(1 + \frac{x}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                  4. Step-by-step derivation
                    1. +-commutativeN/A

                      \[\leadsto \color{blue}{\left(\frac{x}{n} + 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                    2. *-rgt-identityN/A

                      \[\leadsto \left(\frac{\color{blue}{x \cdot 1}}{n} + 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                    3. associate-*r/N/A

                      \[\leadsto \left(\color{blue}{x \cdot \frac{1}{n}} + 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                    4. lower-+.f64N/A

                      \[\leadsto \color{blue}{\left(x \cdot \frac{1}{n} + 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                    5. associate-*r/N/A

                      \[\leadsto \left(\color{blue}{\frac{x \cdot 1}{n}} + 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                    6. *-rgt-identityN/A

                      \[\leadsto \left(\frac{\color{blue}{x}}{n} + 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                    7. lower-/.f6462.7

                      \[\leadsto \left(\color{blue}{\frac{x}{n}} + 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                  5. Applied rewrites62.7%

                    \[\leadsto \color{blue}{\left(\frac{x}{n} + 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]

                  if 4e176 < (/.f64 #s(literal 1 binary64) n)

                  1. Initial program 8.2%

                    \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                  2. Add Preprocessing
                  3. Taylor expanded in x around 0

                    \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right) - e^{\frac{\log x}{n}}} \]
                  4. Applied rewrites57.9%

                    \[\leadsto \color{blue}{\mathsf{fma}\left(x \cdot x, \frac{0.5}{n \cdot n} - \frac{0.5}{n}, \frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)\right)} \]
                  5. Taylor expanded in n around 0

                    \[\leadsto \frac{\frac{1}{2} \cdot {x}^{2} + n \cdot \left(x + \frac{-1}{2} \cdot {x}^{2}\right)}{\color{blue}{{n}^{2}}} \]
                  6. Step-by-step derivation
                    1. Applied rewrites34.2%

                      \[\leadsto \frac{\frac{\mathsf{fma}\left(\mathsf{fma}\left(-0.5, x, 1\right) \cdot n, x, \left(0.5 \cdot x\right) \cdot x\right)}{n}}{\color{blue}{n}} \]
                    2. Taylor expanded in x around 0

                      \[\leadsto x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \color{blue}{\frac{1}{n}}\right) \]
                    3. Step-by-step derivation
                      1. Applied rewrites94.9%

                        \[\leadsto \mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, x, \frac{1}{n}\right) \cdot x \]
                      2. Taylor expanded in n around 0

                        \[\leadsto \left(\frac{1}{2} \cdot \frac{x}{{n}^{2}}\right) \cdot x \]
                      3. Step-by-step derivation
                        1. Applied rewrites94.9%

                          \[\leadsto \left(\frac{x}{n \cdot n} \cdot 0.5\right) \cdot x \]
                      4. Recombined 4 regimes into one program.
                      5. Final simplification76.2%

                        \[\leadsto \begin{array}{l} \mathbf{if}\;{n}^{-1} \leq -5 \cdot 10^{-165}:\\ \;\;\;\;\frac{\frac{{x}^{\left({n}^{-1}\right)}}{x}}{n}\\ \mathbf{elif}\;{n}^{-1} \leq -5 \cdot 10^{-213}:\\ \;\;\;\;\frac{x - \log x}{n}\\ \mathbf{elif}\;{n}^{-1} \leq -2 \cdot 10^{-259}:\\ \;\;\;\;\frac{\frac{{x}^{\left({n}^{-1}\right)}}{x}}{n}\\ \mathbf{elif}\;{n}^{-1} \leq 5 \cdot 10^{-16}:\\ \;\;\;\;\frac{x - \log x}{n}\\ \mathbf{elif}\;{n}^{-1} \leq 4 \cdot 10^{+176}:\\ \;\;\;\;\left(\frac{x}{n} + 1\right) - {x}^{\left({n}^{-1}\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(\frac{x}{n \cdot n} \cdot 0.5\right) \cdot x\\ \end{array} \]
                      6. Add Preprocessing

                      Alternative 5: 80.5% accurate, 0.4× speedup?

                      \[\begin{array}{l} \\ \begin{array}{l} t_0 := {x}^{\left({n}^{-1}\right)}\\ \mathbf{if}\;{n}^{-1} \leq -5 \cdot 10^{-165}:\\ \;\;\;\;\frac{\frac{t\_0}{x}}{n}\\ \mathbf{elif}\;{n}^{-1} \leq 2 \cdot 10^{-12}:\\ \;\;\;\;\frac{\mathsf{log1p}\left(x\right) - \log x}{n}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, x, {n}^{-1}\right), x, 1\right) - t\_0\\ \end{array} \end{array} \]
                      (FPCore (x n)
                       :precision binary64
                       (let* ((t_0 (pow x (pow n -1.0))))
                         (if (<= (pow n -1.0) -5e-165)
                           (/ (/ t_0 x) n)
                           (if (<= (pow n -1.0) 2e-12)
                             (/ (- (log1p x) (log x)) n)
                             (-
                              (fma (fma (- (/ 0.5 (* n n)) (/ 0.5 n)) x (pow n -1.0)) x 1.0)
                              t_0)))))
                      double code(double x, double n) {
                      	double t_0 = pow(x, pow(n, -1.0));
                      	double tmp;
                      	if (pow(n, -1.0) <= -5e-165) {
                      		tmp = (t_0 / x) / n;
                      	} else if (pow(n, -1.0) <= 2e-12) {
                      		tmp = (log1p(x) - log(x)) / n;
                      	} else {
                      		tmp = fma(fma(((0.5 / (n * n)) - (0.5 / n)), x, pow(n, -1.0)), x, 1.0) - t_0;
                      	}
                      	return tmp;
                      }
                      
                      function code(x, n)
                      	t_0 = x ^ (n ^ -1.0)
                      	tmp = 0.0
                      	if ((n ^ -1.0) <= -5e-165)
                      		tmp = Float64(Float64(t_0 / x) / n);
                      	elseif ((n ^ -1.0) <= 2e-12)
                      		tmp = Float64(Float64(log1p(x) - log(x)) / n);
                      	else
                      		tmp = Float64(fma(fma(Float64(Float64(0.5 / Float64(n * n)) - Float64(0.5 / n)), x, (n ^ -1.0)), x, 1.0) - t_0);
                      	end
                      	return tmp
                      end
                      
                      code[x_, n_] := Block[{t$95$0 = N[Power[x, N[Power[n, -1.0], $MachinePrecision]], $MachinePrecision]}, If[LessEqual[N[Power[n, -1.0], $MachinePrecision], -5e-165], N[(N[(t$95$0 / x), $MachinePrecision] / n), $MachinePrecision], If[LessEqual[N[Power[n, -1.0], $MachinePrecision], 2e-12], N[(N[(N[Log[1 + x], $MachinePrecision] - N[Log[x], $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision], N[(N[(N[(N[(N[(0.5 / N[(n * n), $MachinePrecision]), $MachinePrecision] - N[(0.5 / n), $MachinePrecision]), $MachinePrecision] * x + N[Power[n, -1.0], $MachinePrecision]), $MachinePrecision] * x + 1.0), $MachinePrecision] - t$95$0), $MachinePrecision]]]]
                      
                      \begin{array}{l}
                      
                      \\
                      \begin{array}{l}
                      t_0 := {x}^{\left({n}^{-1}\right)}\\
                      \mathbf{if}\;{n}^{-1} \leq -5 \cdot 10^{-165}:\\
                      \;\;\;\;\frac{\frac{t\_0}{x}}{n}\\
                      
                      \mathbf{elif}\;{n}^{-1} \leq 2 \cdot 10^{-12}:\\
                      \;\;\;\;\frac{\mathsf{log1p}\left(x\right) - \log x}{n}\\
                      
                      \mathbf{else}:\\
                      \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, x, {n}^{-1}\right), x, 1\right) - t\_0\\
                      
                      
                      \end{array}
                      \end{array}
                      
                      Derivation
                      1. Split input into 3 regimes
                      2. if (/.f64 #s(literal 1 binary64) n) < -4.99999999999999981e-165

                        1. Initial program 76.7%

                          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                        2. Add Preprocessing
                        3. Taylor expanded in x around inf

                          \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                        4. Step-by-step derivation
                          1. associate-/l/N/A

                            \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                          2. lower-/.f64N/A

                            \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                          3. lower-/.f64N/A

                            \[\leadsto \frac{\color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}}{n} \]
                          4. log-recN/A

                            \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{x}}{n} \]
                          5. mul-1-negN/A

                            \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{x}}{n} \]
                          6. associate-*r/N/A

                            \[\leadsto \frac{\frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{x}}{n} \]
                          7. associate-*r*N/A

                            \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{x}}{n} \]
                          8. metadata-evalN/A

                            \[\leadsto \frac{\frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{x}}{n} \]
                          9. *-commutativeN/A

                            \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{x}}{n} \]
                          10. associate-/l*N/A

                            \[\leadsto \frac{\frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{x}}{n} \]
                          11. exp-to-powN/A

                            \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                          12. lower-pow.f64N/A

                            \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                          13. lower-/.f6487.9

                            \[\leadsto \frac{\frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                        5. Applied rewrites87.9%

                          \[\leadsto \color{blue}{\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}} \]

                        if -4.99999999999999981e-165 < (/.f64 #s(literal 1 binary64) n) < 1.99999999999999996e-12

                        1. Initial program 27.8%

                          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                        2. Add Preprocessing
                        3. Taylor expanded in n around inf

                          \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                        4. Step-by-step derivation
                          1. lower-/.f64N/A

                            \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                          2. lower--.f64N/A

                            \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                          3. lower-log1p.f64N/A

                            \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                          4. lower-log.f6480.5

                            \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                        5. Applied rewrites80.5%

                          \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]

                        if 1.99999999999999996e-12 < (/.f64 #s(literal 1 binary64) n)

                        1. Initial program 45.2%

                          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                        2. Add Preprocessing
                        3. Taylor expanded in x around 0

                          \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                        4. Step-by-step derivation
                          1. +-commutativeN/A

                            \[\leadsto \color{blue}{\left(x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) + 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                          2. *-commutativeN/A

                            \[\leadsto \left(\color{blue}{\left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) \cdot x} + 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                          3. lower-fma.f64N/A

                            \[\leadsto \color{blue}{\mathsf{fma}\left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}, x, 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                          4. *-commutativeN/A

                            \[\leadsto \mathsf{fma}\left(\color{blue}{\left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) \cdot x} + \frac{1}{n}, x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                          5. lower-fma.f64N/A

                            \[\leadsto \mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right)}, x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                          6. lower--.f64N/A

                            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                          7. associate-*r/N/A

                            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\frac{\frac{1}{2} \cdot 1}{{n}^{2}}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                          8. metadata-evalN/A

                            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\color{blue}{\frac{1}{2}}}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                          9. lower-/.f64N/A

                            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\frac{\frac{1}{2}}{{n}^{2}}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                          10. unpow2N/A

                            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{\color{blue}{n \cdot n}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                          11. lower-*.f64N/A

                            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{\color{blue}{n \cdot n}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                          12. associate-*r/N/A

                            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{n \cdot n} - \color{blue}{\frac{\frac{1}{2} \cdot 1}{n}}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                          13. metadata-evalN/A

                            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{n \cdot n} - \frac{\color{blue}{\frac{1}{2}}}{n}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                          14. lower-/.f64N/A

                            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{n \cdot n} - \color{blue}{\frac{\frac{1}{2}}{n}}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                          15. lower-/.f6473.4

                            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, x, \color{blue}{\frac{1}{n}}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                        5. Applied rewrites73.4%

                          \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, x, \frac{1}{n}\right), x, 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                      3. Recombined 3 regimes into one program.
                      4. Final simplification82.2%

                        \[\leadsto \begin{array}{l} \mathbf{if}\;{n}^{-1} \leq -5 \cdot 10^{-165}:\\ \;\;\;\;\frac{\frac{{x}^{\left({n}^{-1}\right)}}{x}}{n}\\ \mathbf{elif}\;{n}^{-1} \leq 2 \cdot 10^{-12}:\\ \;\;\;\;\frac{\mathsf{log1p}\left(x\right) - \log x}{n}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, x, {n}^{-1}\right), x, 1\right) - {x}^{\left({n}^{-1}\right)}\\ \end{array} \]
                      5. Add Preprocessing

                      Alternative 6: 53.3% accurate, 0.4× speedup?

                      \[\begin{array}{l} \\ \begin{array}{l} t_0 := {x}^{\left({n}^{-1}\right)}\\ \mathbf{if}\;{n}^{-1} \leq -0.2:\\ \;\;\;\;1 - t\_0\\ \mathbf{elif}\;{n}^{-1} \leq 5 \cdot 10^{-16}:\\ \;\;\;\;\frac{x - \log x}{n}\\ \mathbf{elif}\;{n}^{-1} \leq 4 \cdot 10^{+176}:\\ \;\;\;\;\left(\frac{x}{n} + 1\right) - t\_0\\ \mathbf{else}:\\ \;\;\;\;\left(\frac{x}{n \cdot n} \cdot 0.5\right) \cdot x\\ \end{array} \end{array} \]
                      (FPCore (x n)
                       :precision binary64
                       (let* ((t_0 (pow x (pow n -1.0))))
                         (if (<= (pow n -1.0) -0.2)
                           (- 1.0 t_0)
                           (if (<= (pow n -1.0) 5e-16)
                             (/ (- x (log x)) n)
                             (if (<= (pow n -1.0) 4e+176)
                               (- (+ (/ x n) 1.0) t_0)
                               (* (* (/ x (* n n)) 0.5) x))))))
                      double code(double x, double n) {
                      	double t_0 = pow(x, pow(n, -1.0));
                      	double tmp;
                      	if (pow(n, -1.0) <= -0.2) {
                      		tmp = 1.0 - t_0;
                      	} else if (pow(n, -1.0) <= 5e-16) {
                      		tmp = (x - log(x)) / n;
                      	} else if (pow(n, -1.0) <= 4e+176) {
                      		tmp = ((x / n) + 1.0) - t_0;
                      	} else {
                      		tmp = ((x / (n * n)) * 0.5) * x;
                      	}
                      	return tmp;
                      }
                      
                      real(8) function code(x, n)
                          real(8), intent (in) :: x
                          real(8), intent (in) :: n
                          real(8) :: t_0
                          real(8) :: tmp
                          t_0 = x ** (n ** (-1.0d0))
                          if ((n ** (-1.0d0)) <= (-0.2d0)) then
                              tmp = 1.0d0 - t_0
                          else if ((n ** (-1.0d0)) <= 5d-16) then
                              tmp = (x - log(x)) / n
                          else if ((n ** (-1.0d0)) <= 4d+176) then
                              tmp = ((x / n) + 1.0d0) - t_0
                          else
                              tmp = ((x / (n * n)) * 0.5d0) * x
                          end if
                          code = tmp
                      end function
                      
                      public static double code(double x, double n) {
                      	double t_0 = Math.pow(x, Math.pow(n, -1.0));
                      	double tmp;
                      	if (Math.pow(n, -1.0) <= -0.2) {
                      		tmp = 1.0 - t_0;
                      	} else if (Math.pow(n, -1.0) <= 5e-16) {
                      		tmp = (x - Math.log(x)) / n;
                      	} else if (Math.pow(n, -1.0) <= 4e+176) {
                      		tmp = ((x / n) + 1.0) - t_0;
                      	} else {
                      		tmp = ((x / (n * n)) * 0.5) * x;
                      	}
                      	return tmp;
                      }
                      
                      def code(x, n):
                      	t_0 = math.pow(x, math.pow(n, -1.0))
                      	tmp = 0
                      	if math.pow(n, -1.0) <= -0.2:
                      		tmp = 1.0 - t_0
                      	elif math.pow(n, -1.0) <= 5e-16:
                      		tmp = (x - math.log(x)) / n
                      	elif math.pow(n, -1.0) <= 4e+176:
                      		tmp = ((x / n) + 1.0) - t_0
                      	else:
                      		tmp = ((x / (n * n)) * 0.5) * x
                      	return tmp
                      
                      function code(x, n)
                      	t_0 = x ^ (n ^ -1.0)
                      	tmp = 0.0
                      	if ((n ^ -1.0) <= -0.2)
                      		tmp = Float64(1.0 - t_0);
                      	elseif ((n ^ -1.0) <= 5e-16)
                      		tmp = Float64(Float64(x - log(x)) / n);
                      	elseif ((n ^ -1.0) <= 4e+176)
                      		tmp = Float64(Float64(Float64(x / n) + 1.0) - t_0);
                      	else
                      		tmp = Float64(Float64(Float64(x / Float64(n * n)) * 0.5) * x);
                      	end
                      	return tmp
                      end
                      
                      function tmp_2 = code(x, n)
                      	t_0 = x ^ (n ^ -1.0);
                      	tmp = 0.0;
                      	if ((n ^ -1.0) <= -0.2)
                      		tmp = 1.0 - t_0;
                      	elseif ((n ^ -1.0) <= 5e-16)
                      		tmp = (x - log(x)) / n;
                      	elseif ((n ^ -1.0) <= 4e+176)
                      		tmp = ((x / n) + 1.0) - t_0;
                      	else
                      		tmp = ((x / (n * n)) * 0.5) * x;
                      	end
                      	tmp_2 = tmp;
                      end
                      
                      code[x_, n_] := Block[{t$95$0 = N[Power[x, N[Power[n, -1.0], $MachinePrecision]], $MachinePrecision]}, If[LessEqual[N[Power[n, -1.0], $MachinePrecision], -0.2], N[(1.0 - t$95$0), $MachinePrecision], If[LessEqual[N[Power[n, -1.0], $MachinePrecision], 5e-16], N[(N[(x - N[Log[x], $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision], If[LessEqual[N[Power[n, -1.0], $MachinePrecision], 4e+176], N[(N[(N[(x / n), $MachinePrecision] + 1.0), $MachinePrecision] - t$95$0), $MachinePrecision], N[(N[(N[(x / N[(n * n), $MachinePrecision]), $MachinePrecision] * 0.5), $MachinePrecision] * x), $MachinePrecision]]]]]
                      
                      \begin{array}{l}
                      
                      \\
                      \begin{array}{l}
                      t_0 := {x}^{\left({n}^{-1}\right)}\\
                      \mathbf{if}\;{n}^{-1} \leq -0.2:\\
                      \;\;\;\;1 - t\_0\\
                      
                      \mathbf{elif}\;{n}^{-1} \leq 5 \cdot 10^{-16}:\\
                      \;\;\;\;\frac{x - \log x}{n}\\
                      
                      \mathbf{elif}\;{n}^{-1} \leq 4 \cdot 10^{+176}:\\
                      \;\;\;\;\left(\frac{x}{n} + 1\right) - t\_0\\
                      
                      \mathbf{else}:\\
                      \;\;\;\;\left(\frac{x}{n \cdot n} \cdot 0.5\right) \cdot x\\
                      
                      
                      \end{array}
                      \end{array}
                      
                      Derivation
                      1. Split input into 4 regimes
                      2. if (/.f64 #s(literal 1 binary64) n) < -0.20000000000000001

                        1. Initial program 99.9%

                          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                        2. Add Preprocessing
                        3. Taylor expanded in x around 0

                          \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                        4. Step-by-step derivation
                          1. Applied rewrites63.6%

                            \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]

                          if -0.20000000000000001 < (/.f64 #s(literal 1 binary64) n) < 5.0000000000000004e-16

                          1. Initial program 26.5%

                            \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                          2. Add Preprocessing
                          3. Taylor expanded in x around 0

                            \[\leadsto \color{blue}{\left(1 + \frac{x}{n}\right) - e^{\frac{\log x}{n}}} \]
                          4. Step-by-step derivation
                            1. associate--l+N/A

                              \[\leadsto \color{blue}{1 + \left(\frac{x}{n} - e^{\frac{\log x}{n}}\right)} \]
                            2. +-commutativeN/A

                              \[\leadsto \color{blue}{\left(\frac{x}{n} - e^{\frac{\log x}{n}}\right) + 1} \]
                            3. *-rgt-identityN/A

                              \[\leadsto \left(\frac{\color{blue}{x \cdot 1}}{n} - e^{\frac{\log x}{n}}\right) + 1 \]
                            4. associate-*r/N/A

                              \[\leadsto \left(\color{blue}{x \cdot \frac{1}{n}} - e^{\frac{\log x}{n}}\right) + 1 \]
                            5. remove-double-negN/A

                              \[\leadsto \left(x \cdot \frac{1}{n} - e^{\frac{\color{blue}{\mathsf{neg}\left(\left(\mathsf{neg}\left(\log x\right)\right)\right)}}{n}}\right) + 1 \]
                            6. mul-1-negN/A

                              \[\leadsto \left(x \cdot \frac{1}{n} - e^{\frac{\mathsf{neg}\left(\color{blue}{-1 \cdot \log x}\right)}{n}}\right) + 1 \]
                            7. distribute-neg-fracN/A

                              \[\leadsto \left(x \cdot \frac{1}{n} - e^{\color{blue}{\mathsf{neg}\left(\frac{-1 \cdot \log x}{n}\right)}}\right) + 1 \]
                            8. mul-1-negN/A

                              \[\leadsto \left(x \cdot \frac{1}{n} - e^{\mathsf{neg}\left(\frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}\right)}\right) + 1 \]
                            9. log-recN/A

                              \[\leadsto \left(x \cdot \frac{1}{n} - e^{\mathsf{neg}\left(\frac{\color{blue}{\log \left(\frac{1}{x}\right)}}{n}\right)}\right) + 1 \]
                            10. mul-1-negN/A

                              \[\leadsto \left(x \cdot \frac{1}{n} - e^{\color{blue}{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}\right) + 1 \]
                            11. associate-+l-N/A

                              \[\leadsto \color{blue}{x \cdot \frac{1}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right)} \]
                            12. lower--.f64N/A

                              \[\leadsto \color{blue}{x \cdot \frac{1}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right)} \]
                            13. associate-*r/N/A

                              \[\leadsto \color{blue}{\frac{x \cdot 1}{n}} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
                            14. *-rgt-identityN/A

                              \[\leadsto \frac{\color{blue}{x}}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
                            15. lower-/.f64N/A

                              \[\leadsto \color{blue}{\frac{x}{n}} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
                          5. Applied rewrites53.7%

                            \[\leadsto \color{blue}{\frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)} \]
                          6. Taylor expanded in n around inf

                            \[\leadsto \frac{x - \log x}{\color{blue}{n}} \]
                          7. Step-by-step derivation
                            1. Applied rewrites53.3%

                              \[\leadsto \frac{x - \log x}{\color{blue}{n}} \]

                            if 5.0000000000000004e-16 < (/.f64 #s(literal 1 binary64) n) < 4e176

                            1. Initial program 69.7%

                              \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                            2. Add Preprocessing
                            3. Taylor expanded in x around 0

                              \[\leadsto \color{blue}{\left(1 + \frac{x}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                            4. Step-by-step derivation
                              1. +-commutativeN/A

                                \[\leadsto \color{blue}{\left(\frac{x}{n} + 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                              2. *-rgt-identityN/A

                                \[\leadsto \left(\frac{\color{blue}{x \cdot 1}}{n} + 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                              3. associate-*r/N/A

                                \[\leadsto \left(\color{blue}{x \cdot \frac{1}{n}} + 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                              4. lower-+.f64N/A

                                \[\leadsto \color{blue}{\left(x \cdot \frac{1}{n} + 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                              5. associate-*r/N/A

                                \[\leadsto \left(\color{blue}{\frac{x \cdot 1}{n}} + 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                              6. *-rgt-identityN/A

                                \[\leadsto \left(\frac{\color{blue}{x}}{n} + 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                              7. lower-/.f6462.7

                                \[\leadsto \left(\color{blue}{\frac{x}{n}} + 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                            5. Applied rewrites62.7%

                              \[\leadsto \color{blue}{\left(\frac{x}{n} + 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]

                            if 4e176 < (/.f64 #s(literal 1 binary64) n)

                            1. Initial program 8.2%

                              \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                            2. Add Preprocessing
                            3. Taylor expanded in x around 0

                              \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right) - e^{\frac{\log x}{n}}} \]
                            4. Applied rewrites57.9%

                              \[\leadsto \color{blue}{\mathsf{fma}\left(x \cdot x, \frac{0.5}{n \cdot n} - \frac{0.5}{n}, \frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)\right)} \]
                            5. Taylor expanded in n around 0

                              \[\leadsto \frac{\frac{1}{2} \cdot {x}^{2} + n \cdot \left(x + \frac{-1}{2} \cdot {x}^{2}\right)}{\color{blue}{{n}^{2}}} \]
                            6. Step-by-step derivation
                              1. Applied rewrites34.2%

                                \[\leadsto \frac{\frac{\mathsf{fma}\left(\mathsf{fma}\left(-0.5, x, 1\right) \cdot n, x, \left(0.5 \cdot x\right) \cdot x\right)}{n}}{\color{blue}{n}} \]
                              2. Taylor expanded in x around 0

                                \[\leadsto x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \color{blue}{\frac{1}{n}}\right) \]
                              3. Step-by-step derivation
                                1. Applied rewrites94.9%

                                  \[\leadsto \mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, x, \frac{1}{n}\right) \cdot x \]
                                2. Taylor expanded in n around 0

                                  \[\leadsto \left(\frac{1}{2} \cdot \frac{x}{{n}^{2}}\right) \cdot x \]
                                3. Step-by-step derivation
                                  1. Applied rewrites94.9%

                                    \[\leadsto \left(\frac{x}{n \cdot n} \cdot 0.5\right) \cdot x \]
                                4. Recombined 4 regimes into one program.
                                5. Final simplification60.3%

                                  \[\leadsto \begin{array}{l} \mathbf{if}\;{n}^{-1} \leq -0.2:\\ \;\;\;\;1 - {x}^{\left({n}^{-1}\right)}\\ \mathbf{elif}\;{n}^{-1} \leq 5 \cdot 10^{-16}:\\ \;\;\;\;\frac{x - \log x}{n}\\ \mathbf{elif}\;{n}^{-1} \leq 4 \cdot 10^{+176}:\\ \;\;\;\;\left(\frac{x}{n} + 1\right) - {x}^{\left({n}^{-1}\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(\frac{x}{n \cdot n} \cdot 0.5\right) \cdot x\\ \end{array} \]
                                6. Add Preprocessing

                                Alternative 7: 53.3% accurate, 0.4× speedup?

                                \[\begin{array}{l} \\ \begin{array}{l} t_0 := 1 - {x}^{\left({n}^{-1}\right)}\\ \mathbf{if}\;{n}^{-1} \leq -0.2:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;{n}^{-1} \leq 2 \cdot 10^{-12}:\\ \;\;\;\;\frac{x - \log x}{n}\\ \mathbf{elif}\;{n}^{-1} \leq 2 \cdot 10^{+169}:\\ \;\;\;\;t\_0\\ \mathbf{else}:\\ \;\;\;\;\left(\frac{x}{n \cdot n} \cdot 0.5\right) \cdot x\\ \end{array} \end{array} \]
                                (FPCore (x n)
                                 :precision binary64
                                 (let* ((t_0 (- 1.0 (pow x (pow n -1.0)))))
                                   (if (<= (pow n -1.0) -0.2)
                                     t_0
                                     (if (<= (pow n -1.0) 2e-12)
                                       (/ (- x (log x)) n)
                                       (if (<= (pow n -1.0) 2e+169) t_0 (* (* (/ x (* n n)) 0.5) x))))))
                                double code(double x, double n) {
                                	double t_0 = 1.0 - pow(x, pow(n, -1.0));
                                	double tmp;
                                	if (pow(n, -1.0) <= -0.2) {
                                		tmp = t_0;
                                	} else if (pow(n, -1.0) <= 2e-12) {
                                		tmp = (x - log(x)) / n;
                                	} else if (pow(n, -1.0) <= 2e+169) {
                                		tmp = t_0;
                                	} else {
                                		tmp = ((x / (n * n)) * 0.5) * x;
                                	}
                                	return tmp;
                                }
                                
                                real(8) function code(x, n)
                                    real(8), intent (in) :: x
                                    real(8), intent (in) :: n
                                    real(8) :: t_0
                                    real(8) :: tmp
                                    t_0 = 1.0d0 - (x ** (n ** (-1.0d0)))
                                    if ((n ** (-1.0d0)) <= (-0.2d0)) then
                                        tmp = t_0
                                    else if ((n ** (-1.0d0)) <= 2d-12) then
                                        tmp = (x - log(x)) / n
                                    else if ((n ** (-1.0d0)) <= 2d+169) then
                                        tmp = t_0
                                    else
                                        tmp = ((x / (n * n)) * 0.5d0) * x
                                    end if
                                    code = tmp
                                end function
                                
                                public static double code(double x, double n) {
                                	double t_0 = 1.0 - Math.pow(x, Math.pow(n, -1.0));
                                	double tmp;
                                	if (Math.pow(n, -1.0) <= -0.2) {
                                		tmp = t_0;
                                	} else if (Math.pow(n, -1.0) <= 2e-12) {
                                		tmp = (x - Math.log(x)) / n;
                                	} else if (Math.pow(n, -1.0) <= 2e+169) {
                                		tmp = t_0;
                                	} else {
                                		tmp = ((x / (n * n)) * 0.5) * x;
                                	}
                                	return tmp;
                                }
                                
                                def code(x, n):
                                	t_0 = 1.0 - math.pow(x, math.pow(n, -1.0))
                                	tmp = 0
                                	if math.pow(n, -1.0) <= -0.2:
                                		tmp = t_0
                                	elif math.pow(n, -1.0) <= 2e-12:
                                		tmp = (x - math.log(x)) / n
                                	elif math.pow(n, -1.0) <= 2e+169:
                                		tmp = t_0
                                	else:
                                		tmp = ((x / (n * n)) * 0.5) * x
                                	return tmp
                                
                                function code(x, n)
                                	t_0 = Float64(1.0 - (x ^ (n ^ -1.0)))
                                	tmp = 0.0
                                	if ((n ^ -1.0) <= -0.2)
                                		tmp = t_0;
                                	elseif ((n ^ -1.0) <= 2e-12)
                                		tmp = Float64(Float64(x - log(x)) / n);
                                	elseif ((n ^ -1.0) <= 2e+169)
                                		tmp = t_0;
                                	else
                                		tmp = Float64(Float64(Float64(x / Float64(n * n)) * 0.5) * x);
                                	end
                                	return tmp
                                end
                                
                                function tmp_2 = code(x, n)
                                	t_0 = 1.0 - (x ^ (n ^ -1.0));
                                	tmp = 0.0;
                                	if ((n ^ -1.0) <= -0.2)
                                		tmp = t_0;
                                	elseif ((n ^ -1.0) <= 2e-12)
                                		tmp = (x - log(x)) / n;
                                	elseif ((n ^ -1.0) <= 2e+169)
                                		tmp = t_0;
                                	else
                                		tmp = ((x / (n * n)) * 0.5) * x;
                                	end
                                	tmp_2 = tmp;
                                end
                                
                                code[x_, n_] := Block[{t$95$0 = N[(1.0 - N[Power[x, N[Power[n, -1.0], $MachinePrecision]], $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[n, -1.0], $MachinePrecision], -0.2], t$95$0, If[LessEqual[N[Power[n, -1.0], $MachinePrecision], 2e-12], N[(N[(x - N[Log[x], $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision], If[LessEqual[N[Power[n, -1.0], $MachinePrecision], 2e+169], t$95$0, N[(N[(N[(x / N[(n * n), $MachinePrecision]), $MachinePrecision] * 0.5), $MachinePrecision] * x), $MachinePrecision]]]]]
                                
                                \begin{array}{l}
                                
                                \\
                                \begin{array}{l}
                                t_0 := 1 - {x}^{\left({n}^{-1}\right)}\\
                                \mathbf{if}\;{n}^{-1} \leq -0.2:\\
                                \;\;\;\;t\_0\\
                                
                                \mathbf{elif}\;{n}^{-1} \leq 2 \cdot 10^{-12}:\\
                                \;\;\;\;\frac{x - \log x}{n}\\
                                
                                \mathbf{elif}\;{n}^{-1} \leq 2 \cdot 10^{+169}:\\
                                \;\;\;\;t\_0\\
                                
                                \mathbf{else}:\\
                                \;\;\;\;\left(\frac{x}{n \cdot n} \cdot 0.5\right) \cdot x\\
                                
                                
                                \end{array}
                                \end{array}
                                
                                Derivation
                                1. Split input into 3 regimes
                                2. if (/.f64 #s(literal 1 binary64) n) < -0.20000000000000001 or 1.99999999999999996e-12 < (/.f64 #s(literal 1 binary64) n) < 1.99999999999999987e169

                                  1. Initial program 93.4%

                                    \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in x around 0

                                    \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                  4. Step-by-step derivation
                                    1. Applied rewrites64.2%

                                      \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]

                                    if -0.20000000000000001 < (/.f64 #s(literal 1 binary64) n) < 1.99999999999999996e-12

                                    1. Initial program 26.3%

                                      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                    2. Add Preprocessing
                                    3. Taylor expanded in x around 0

                                      \[\leadsto \color{blue}{\left(1 + \frac{x}{n}\right) - e^{\frac{\log x}{n}}} \]
                                    4. Step-by-step derivation
                                      1. associate--l+N/A

                                        \[\leadsto \color{blue}{1 + \left(\frac{x}{n} - e^{\frac{\log x}{n}}\right)} \]
                                      2. +-commutativeN/A

                                        \[\leadsto \color{blue}{\left(\frac{x}{n} - e^{\frac{\log x}{n}}\right) + 1} \]
                                      3. *-rgt-identityN/A

                                        \[\leadsto \left(\frac{\color{blue}{x \cdot 1}}{n} - e^{\frac{\log x}{n}}\right) + 1 \]
                                      4. associate-*r/N/A

                                        \[\leadsto \left(\color{blue}{x \cdot \frac{1}{n}} - e^{\frac{\log x}{n}}\right) + 1 \]
                                      5. remove-double-negN/A

                                        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\frac{\color{blue}{\mathsf{neg}\left(\left(\mathsf{neg}\left(\log x\right)\right)\right)}}{n}}\right) + 1 \]
                                      6. mul-1-negN/A

                                        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\frac{\mathsf{neg}\left(\color{blue}{-1 \cdot \log x}\right)}{n}}\right) + 1 \]
                                      7. distribute-neg-fracN/A

                                        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\color{blue}{\mathsf{neg}\left(\frac{-1 \cdot \log x}{n}\right)}}\right) + 1 \]
                                      8. mul-1-negN/A

                                        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\mathsf{neg}\left(\frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}\right)}\right) + 1 \]
                                      9. log-recN/A

                                        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\mathsf{neg}\left(\frac{\color{blue}{\log \left(\frac{1}{x}\right)}}{n}\right)}\right) + 1 \]
                                      10. mul-1-negN/A

                                        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\color{blue}{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}\right) + 1 \]
                                      11. associate-+l-N/A

                                        \[\leadsto \color{blue}{x \cdot \frac{1}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right)} \]
                                      12. lower--.f64N/A

                                        \[\leadsto \color{blue}{x \cdot \frac{1}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right)} \]
                                      13. associate-*r/N/A

                                        \[\leadsto \color{blue}{\frac{x \cdot 1}{n}} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
                                      14. *-rgt-identityN/A

                                        \[\leadsto \frac{\color{blue}{x}}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
                                      15. lower-/.f64N/A

                                        \[\leadsto \color{blue}{\frac{x}{n}} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
                                    5. Applied rewrites53.4%

                                      \[\leadsto \color{blue}{\frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)} \]
                                    6. Taylor expanded in n around inf

                                      \[\leadsto \frac{x - \log x}{\color{blue}{n}} \]
                                    7. Step-by-step derivation
                                      1. Applied rewrites53.0%

                                        \[\leadsto \frac{x - \log x}{\color{blue}{n}} \]

                                      if 1.99999999999999987e169 < (/.f64 #s(literal 1 binary64) n)

                                      1. Initial program 12.4%

                                        \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                      2. Add Preprocessing
                                      3. Taylor expanded in x around 0

                                        \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right) - e^{\frac{\log x}{n}}} \]
                                      4. Applied rewrites57.1%

                                        \[\leadsto \color{blue}{\mathsf{fma}\left(x \cdot x, \frac{0.5}{n \cdot n} - \frac{0.5}{n}, \frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)\right)} \]
                                      5. Taylor expanded in n around 0

                                        \[\leadsto \frac{\frac{1}{2} \cdot {x}^{2} + n \cdot \left(x + \frac{-1}{2} \cdot {x}^{2}\right)}{\color{blue}{{n}^{2}}} \]
                                      6. Step-by-step derivation
                                        1. Applied rewrites31.3%

                                          \[\leadsto \frac{\frac{\mathsf{fma}\left(\mathsf{fma}\left(-0.5, x, 1\right) \cdot n, x, \left(0.5 \cdot x\right) \cdot x\right)}{n}}{\color{blue}{n}} \]
                                        2. Taylor expanded in x around 0

                                          \[\leadsto x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \color{blue}{\frac{1}{n}}\right) \]
                                        3. Step-by-step derivation
                                          1. Applied rewrites90.8%

                                            \[\leadsto \mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, x, \frac{1}{n}\right) \cdot x \]
                                          2. Taylor expanded in n around 0

                                            \[\leadsto \left(\frac{1}{2} \cdot \frac{x}{{n}^{2}}\right) \cdot x \]
                                          3. Step-by-step derivation
                                            1. Applied rewrites90.8%

                                              \[\leadsto \left(\frac{x}{n \cdot n} \cdot 0.5\right) \cdot x \]
                                          4. Recombined 3 regimes into one program.
                                          5. Final simplification60.3%

                                            \[\leadsto \begin{array}{l} \mathbf{if}\;{n}^{-1} \leq -0.2:\\ \;\;\;\;1 - {x}^{\left({n}^{-1}\right)}\\ \mathbf{elif}\;{n}^{-1} \leq 2 \cdot 10^{-12}:\\ \;\;\;\;\frac{x - \log x}{n}\\ \mathbf{elif}\;{n}^{-1} \leq 2 \cdot 10^{+169}:\\ \;\;\;\;1 - {x}^{\left({n}^{-1}\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(\frac{x}{n \cdot n} \cdot 0.5\right) \cdot x\\ \end{array} \]
                                          6. Add Preprocessing

                                          Alternative 8: 39.9% accurate, 1.9× speedup?

                                          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 3.1 \cdot 10^{+29}:\\ \;\;\;\;\frac{x - \log x}{n}\\ \mathbf{else}:\\ \;\;\;\;\left(\frac{x}{n \cdot n} \cdot 0.5\right) \cdot x\\ \end{array} \end{array} \]
                                          (FPCore (x n)
                                           :precision binary64
                                           (if (<= x 3.1e+29) (/ (- x (log x)) n) (* (* (/ x (* n n)) 0.5) x)))
                                          double code(double x, double n) {
                                          	double tmp;
                                          	if (x <= 3.1e+29) {
                                          		tmp = (x - log(x)) / n;
                                          	} else {
                                          		tmp = ((x / (n * n)) * 0.5) * x;
                                          	}
                                          	return tmp;
                                          }
                                          
                                          real(8) function code(x, n)
                                              real(8), intent (in) :: x
                                              real(8), intent (in) :: n
                                              real(8) :: tmp
                                              if (x <= 3.1d+29) then
                                                  tmp = (x - log(x)) / n
                                              else
                                                  tmp = ((x / (n * n)) * 0.5d0) * x
                                              end if
                                              code = tmp
                                          end function
                                          
                                          public static double code(double x, double n) {
                                          	double tmp;
                                          	if (x <= 3.1e+29) {
                                          		tmp = (x - Math.log(x)) / n;
                                          	} else {
                                          		tmp = ((x / (n * n)) * 0.5) * x;
                                          	}
                                          	return tmp;
                                          }
                                          
                                          def code(x, n):
                                          	tmp = 0
                                          	if x <= 3.1e+29:
                                          		tmp = (x - math.log(x)) / n
                                          	else:
                                          		tmp = ((x / (n * n)) * 0.5) * x
                                          	return tmp
                                          
                                          function code(x, n)
                                          	tmp = 0.0
                                          	if (x <= 3.1e+29)
                                          		tmp = Float64(Float64(x - log(x)) / n);
                                          	else
                                          		tmp = Float64(Float64(Float64(x / Float64(n * n)) * 0.5) * x);
                                          	end
                                          	return tmp
                                          end
                                          
                                          function tmp_2 = code(x, n)
                                          	tmp = 0.0;
                                          	if (x <= 3.1e+29)
                                          		tmp = (x - log(x)) / n;
                                          	else
                                          		tmp = ((x / (n * n)) * 0.5) * x;
                                          	end
                                          	tmp_2 = tmp;
                                          end
                                          
                                          code[x_, n_] := If[LessEqual[x, 3.1e+29], N[(N[(x - N[Log[x], $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision], N[(N[(N[(x / N[(n * n), $MachinePrecision]), $MachinePrecision] * 0.5), $MachinePrecision] * x), $MachinePrecision]]
                                          
                                          \begin{array}{l}
                                          
                                          \\
                                          \begin{array}{l}
                                          \mathbf{if}\;x \leq 3.1 \cdot 10^{+29}:\\
                                          \;\;\;\;\frac{x - \log x}{n}\\
                                          
                                          \mathbf{else}:\\
                                          \;\;\;\;\left(\frac{x}{n \cdot n} \cdot 0.5\right) \cdot x\\
                                          
                                          
                                          \end{array}
                                          \end{array}
                                          
                                          Derivation
                                          1. Split input into 2 regimes
                                          2. if x < 3.0999999999999999e29

                                            1. Initial program 43.0%

                                              \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                            2. Add Preprocessing
                                            3. Taylor expanded in x around 0

                                              \[\leadsto \color{blue}{\left(1 + \frac{x}{n}\right) - e^{\frac{\log x}{n}}} \]
                                            4. Step-by-step derivation
                                              1. associate--l+N/A

                                                \[\leadsto \color{blue}{1 + \left(\frac{x}{n} - e^{\frac{\log x}{n}}\right)} \]
                                              2. +-commutativeN/A

                                                \[\leadsto \color{blue}{\left(\frac{x}{n} - e^{\frac{\log x}{n}}\right) + 1} \]
                                              3. *-rgt-identityN/A

                                                \[\leadsto \left(\frac{\color{blue}{x \cdot 1}}{n} - e^{\frac{\log x}{n}}\right) + 1 \]
                                              4. associate-*r/N/A

                                                \[\leadsto \left(\color{blue}{x \cdot \frac{1}{n}} - e^{\frac{\log x}{n}}\right) + 1 \]
                                              5. remove-double-negN/A

                                                \[\leadsto \left(x \cdot \frac{1}{n} - e^{\frac{\color{blue}{\mathsf{neg}\left(\left(\mathsf{neg}\left(\log x\right)\right)\right)}}{n}}\right) + 1 \]
                                              6. mul-1-negN/A

                                                \[\leadsto \left(x \cdot \frac{1}{n} - e^{\frac{\mathsf{neg}\left(\color{blue}{-1 \cdot \log x}\right)}{n}}\right) + 1 \]
                                              7. distribute-neg-fracN/A

                                                \[\leadsto \left(x \cdot \frac{1}{n} - e^{\color{blue}{\mathsf{neg}\left(\frac{-1 \cdot \log x}{n}\right)}}\right) + 1 \]
                                              8. mul-1-negN/A

                                                \[\leadsto \left(x \cdot \frac{1}{n} - e^{\mathsf{neg}\left(\frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}\right)}\right) + 1 \]
                                              9. log-recN/A

                                                \[\leadsto \left(x \cdot \frac{1}{n} - e^{\mathsf{neg}\left(\frac{\color{blue}{\log \left(\frac{1}{x}\right)}}{n}\right)}\right) + 1 \]
                                              10. mul-1-negN/A

                                                \[\leadsto \left(x \cdot \frac{1}{n} - e^{\color{blue}{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}\right) + 1 \]
                                              11. associate-+l-N/A

                                                \[\leadsto \color{blue}{x \cdot \frac{1}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right)} \]
                                              12. lower--.f64N/A

                                                \[\leadsto \color{blue}{x \cdot \frac{1}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right)} \]
                                              13. associate-*r/N/A

                                                \[\leadsto \color{blue}{\frac{x \cdot 1}{n}} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
                                              14. *-rgt-identityN/A

                                                \[\leadsto \frac{\color{blue}{x}}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
                                              15. lower-/.f64N/A

                                                \[\leadsto \color{blue}{\frac{x}{n}} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
                                            5. Applied rewrites80.5%

                                              \[\leadsto \color{blue}{\frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)} \]
                                            6. Taylor expanded in n around inf

                                              \[\leadsto \frac{x - \log x}{\color{blue}{n}} \]
                                            7. Step-by-step derivation
                                              1. Applied rewrites46.6%

                                                \[\leadsto \frac{x - \log x}{\color{blue}{n}} \]

                                              if 3.0999999999999999e29 < x

                                              1. Initial program 64.6%

                                                \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                              2. Add Preprocessing
                                              3. Taylor expanded in x around 0

                                                \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right) - e^{\frac{\log x}{n}}} \]
                                              4. Applied rewrites1.7%

                                                \[\leadsto \color{blue}{\mathsf{fma}\left(x \cdot x, \frac{0.5}{n \cdot n} - \frac{0.5}{n}, \frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)\right)} \]
                                              5. Taylor expanded in n around 0

                                                \[\leadsto \frac{\frac{1}{2} \cdot {x}^{2} + n \cdot \left(x + \frac{-1}{2} \cdot {x}^{2}\right)}{\color{blue}{{n}^{2}}} \]
                                              6. Step-by-step derivation
                                                1. Applied rewrites1.5%

                                                  \[\leadsto \frac{\frac{\mathsf{fma}\left(\mathsf{fma}\left(-0.5, x, 1\right) \cdot n, x, \left(0.5 \cdot x\right) \cdot x\right)}{n}}{\color{blue}{n}} \]
                                                2. Taylor expanded in x around 0

                                                  \[\leadsto x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \color{blue}{\frac{1}{n}}\right) \]
                                                3. Step-by-step derivation
                                                  1. Applied rewrites2.1%

                                                    \[\leadsto \mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, x, \frac{1}{n}\right) \cdot x \]
                                                  2. Taylor expanded in n around 0

                                                    \[\leadsto \left(\frac{1}{2} \cdot \frac{x}{{n}^{2}}\right) \cdot x \]
                                                  3. Step-by-step derivation
                                                    1. Applied rewrites25.7%

                                                      \[\leadsto \left(\frac{x}{n \cdot n} \cdot 0.5\right) \cdot x \]
                                                  4. Recombined 2 regimes into one program.
                                                  5. Add Preprocessing

                                                  Alternative 9: 21.4% accurate, 3.3× speedup?

                                                  \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 0.82:\\ \;\;\;\;\left(\mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, -1, \frac{-1}{n \cdot x}\right) \cdot \left(-x\right)\right) \cdot x\\ \mathbf{else}:\\ \;\;\;\;\left(\frac{x}{n \cdot n} \cdot 0.5\right) \cdot x\\ \end{array} \end{array} \]
                                                  (FPCore (x n)
                                                   :precision binary64
                                                   (if (<= x 0.82)
                                                     (* (* (fma (- (/ 0.5 (* n n)) (/ 0.5 n)) -1.0 (/ -1.0 (* n x))) (- x)) x)
                                                     (* (* (/ x (* n n)) 0.5) x)))
                                                  double code(double x, double n) {
                                                  	double tmp;
                                                  	if (x <= 0.82) {
                                                  		tmp = (fma(((0.5 / (n * n)) - (0.5 / n)), -1.0, (-1.0 / (n * x))) * -x) * x;
                                                  	} else {
                                                  		tmp = ((x / (n * n)) * 0.5) * x;
                                                  	}
                                                  	return tmp;
                                                  }
                                                  
                                                  function code(x, n)
                                                  	tmp = 0.0
                                                  	if (x <= 0.82)
                                                  		tmp = Float64(Float64(fma(Float64(Float64(0.5 / Float64(n * n)) - Float64(0.5 / n)), -1.0, Float64(-1.0 / Float64(n * x))) * Float64(-x)) * x);
                                                  	else
                                                  		tmp = Float64(Float64(Float64(x / Float64(n * n)) * 0.5) * x);
                                                  	end
                                                  	return tmp
                                                  end
                                                  
                                                  code[x_, n_] := If[LessEqual[x, 0.82], N[(N[(N[(N[(N[(0.5 / N[(n * n), $MachinePrecision]), $MachinePrecision] - N[(0.5 / n), $MachinePrecision]), $MachinePrecision] * -1.0 + N[(-1.0 / N[(n * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * (-x)), $MachinePrecision] * x), $MachinePrecision], N[(N[(N[(x / N[(n * n), $MachinePrecision]), $MachinePrecision] * 0.5), $MachinePrecision] * x), $MachinePrecision]]
                                                  
                                                  \begin{array}{l}
                                                  
                                                  \\
                                                  \begin{array}{l}
                                                  \mathbf{if}\;x \leq 0.82:\\
                                                  \;\;\;\;\left(\mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, -1, \frac{-1}{n \cdot x}\right) \cdot \left(-x\right)\right) \cdot x\\
                                                  
                                                  \mathbf{else}:\\
                                                  \;\;\;\;\left(\frac{x}{n \cdot n} \cdot 0.5\right) \cdot x\\
                                                  
                                                  
                                                  \end{array}
                                                  \end{array}
                                                  
                                                  Derivation
                                                  1. Split input into 2 regimes
                                                  2. if x < 0.819999999999999951

                                                    1. Initial program 43.1%

                                                      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                    2. Add Preprocessing
                                                    3. Taylor expanded in x around 0

                                                      \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right) - e^{\frac{\log x}{n}}} \]
                                                    4. Applied rewrites73.9%

                                                      \[\leadsto \color{blue}{\mathsf{fma}\left(x \cdot x, \frac{0.5}{n \cdot n} - \frac{0.5}{n}, \frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)\right)} \]
                                                    5. Taylor expanded in n around 0

                                                      \[\leadsto \frac{\frac{1}{2} \cdot {x}^{2} + n \cdot \left(x + \frac{-1}{2} \cdot {x}^{2}\right)}{\color{blue}{{n}^{2}}} \]
                                                    6. Step-by-step derivation
                                                      1. Applied rewrites7.9%

                                                        \[\leadsto \frac{\frac{\mathsf{fma}\left(\mathsf{fma}\left(-0.5, x, 1\right) \cdot n, x, \left(0.5 \cdot x\right) \cdot x\right)}{n}}{\color{blue}{n}} \]
                                                      2. Taylor expanded in x around 0

                                                        \[\leadsto x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \color{blue}{\frac{1}{n}}\right) \]
                                                      3. Step-by-step derivation
                                                        1. Applied rewrites15.7%

                                                          \[\leadsto \mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, x, \frac{1}{n}\right) \cdot x \]
                                                        2. Taylor expanded in x around -inf

                                                          \[\leadsto \left(-1 \cdot \left(x \cdot \left(-1 \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) - \frac{1}{n \cdot x}\right)\right)\right) \cdot x \]
                                                        3. Step-by-step derivation
                                                          1. Applied rewrites20.4%

                                                            \[\leadsto \left(\mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, -1, \frac{-1}{n \cdot x}\right) \cdot \left(-x\right)\right) \cdot x \]

                                                          if 0.819999999999999951 < x

                                                          1. Initial program 62.5%

                                                            \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                          2. Add Preprocessing
                                                          3. Taylor expanded in x around 0

                                                            \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right) - e^{\frac{\log x}{n}}} \]
                                                          4. Applied rewrites1.8%

                                                            \[\leadsto \color{blue}{\mathsf{fma}\left(x \cdot x, \frac{0.5}{n \cdot n} - \frac{0.5}{n}, \frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)\right)} \]
                                                          5. Taylor expanded in n around 0

                                                            \[\leadsto \frac{\frac{1}{2} \cdot {x}^{2} + n \cdot \left(x + \frac{-1}{2} \cdot {x}^{2}\right)}{\color{blue}{{n}^{2}}} \]
                                                          6. Step-by-step derivation
                                                            1. Applied rewrites1.5%

                                                              \[\leadsto \frac{\frac{\mathsf{fma}\left(\mathsf{fma}\left(-0.5, x, 1\right) \cdot n, x, \left(0.5 \cdot x\right) \cdot x\right)}{n}}{\color{blue}{n}} \]
                                                            2. Taylor expanded in x around 0

                                                              \[\leadsto x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \color{blue}{\frac{1}{n}}\right) \]
                                                            3. Step-by-step derivation
                                                              1. Applied rewrites2.1%

                                                                \[\leadsto \mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, x, \frac{1}{n}\right) \cdot x \]
                                                              2. Taylor expanded in n around 0

                                                                \[\leadsto \left(\frac{1}{2} \cdot \frac{x}{{n}^{2}}\right) \cdot x \]
                                                              3. Step-by-step derivation
                                                                1. Applied rewrites23.8%

                                                                  \[\leadsto \left(\frac{x}{n \cdot n} \cdot 0.5\right) \cdot x \]
                                                              4. Recombined 2 regimes into one program.
                                                              5. Add Preprocessing

                                                              Alternative 10: 19.1% accurate, 8.6× speedup?

                                                              \[\begin{array}{l} \\ \left(\frac{x}{n \cdot n} \cdot 0.5\right) \cdot x \end{array} \]
                                                              (FPCore (x n) :precision binary64 (* (* (/ x (* n n)) 0.5) x))
                                                              double code(double x, double n) {
                                                              	return ((x / (n * n)) * 0.5) * x;
                                                              }
                                                              
                                                              real(8) function code(x, n)
                                                                  real(8), intent (in) :: x
                                                                  real(8), intent (in) :: n
                                                                  code = ((x / (n * n)) * 0.5d0) * x
                                                              end function
                                                              
                                                              public static double code(double x, double n) {
                                                              	return ((x / (n * n)) * 0.5) * x;
                                                              }
                                                              
                                                              def code(x, n):
                                                              	return ((x / (n * n)) * 0.5) * x
                                                              
                                                              function code(x, n)
                                                              	return Float64(Float64(Float64(x / Float64(n * n)) * 0.5) * x)
                                                              end
                                                              
                                                              function tmp = code(x, n)
                                                              	tmp = ((x / (n * n)) * 0.5) * x;
                                                              end
                                                              
                                                              code[x_, n_] := N[(N[(N[(x / N[(n * n), $MachinePrecision]), $MachinePrecision] * 0.5), $MachinePrecision] * x), $MachinePrecision]
                                                              
                                                              \begin{array}{l}
                                                              
                                                              \\
                                                              \left(\frac{x}{n \cdot n} \cdot 0.5\right) \cdot x
                                                              \end{array}
                                                              
                                                              Derivation
                                                              1. Initial program 50.3%

                                                                \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                              2. Add Preprocessing
                                                              3. Taylor expanded in x around 0

                                                                \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right) - e^{\frac{\log x}{n}}} \]
                                                              4. Applied rewrites47.1%

                                                                \[\leadsto \color{blue}{\mathsf{fma}\left(x \cdot x, \frac{0.5}{n \cdot n} - \frac{0.5}{n}, \frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)\right)} \]
                                                              5. Taylor expanded in n around 0

                                                                \[\leadsto \frac{\frac{1}{2} \cdot {x}^{2} + n \cdot \left(x + \frac{-1}{2} \cdot {x}^{2}\right)}{\color{blue}{{n}^{2}}} \]
                                                              6. Step-by-step derivation
                                                                1. Applied rewrites5.5%

                                                                  \[\leadsto \frac{\frac{\mathsf{fma}\left(\mathsf{fma}\left(-0.5, x, 1\right) \cdot n, x, \left(0.5 \cdot x\right) \cdot x\right)}{n}}{\color{blue}{n}} \]
                                                                2. Taylor expanded in x around 0

                                                                  \[\leadsto x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \color{blue}{\frac{1}{n}}\right) \]
                                                                3. Step-by-step derivation
                                                                  1. Applied rewrites10.6%

                                                                    \[\leadsto \mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, x, \frac{1}{n}\right) \cdot x \]
                                                                  2. Taylor expanded in n around 0

                                                                    \[\leadsto \left(\frac{1}{2} \cdot \frac{x}{{n}^{2}}\right) \cdot x \]
                                                                  3. Step-by-step derivation
                                                                    1. Applied rewrites18.3%

                                                                      \[\leadsto \left(\frac{x}{n \cdot n} \cdot 0.5\right) \cdot x \]
                                                                    2. Add Preprocessing

                                                                    Alternative 11: 4.5% accurate, 19.3× speedup?

                                                                    \[\begin{array}{l} \\ \frac{x}{n} \end{array} \]
                                                                    (FPCore (x n) :precision binary64 (/ x n))
                                                                    double code(double x, double n) {
                                                                    	return x / n;
                                                                    }
                                                                    
                                                                    real(8) function code(x, n)
                                                                        real(8), intent (in) :: x
                                                                        real(8), intent (in) :: n
                                                                        code = x / n
                                                                    end function
                                                                    
                                                                    public static double code(double x, double n) {
                                                                    	return x / n;
                                                                    }
                                                                    
                                                                    def code(x, n):
                                                                    	return x / n
                                                                    
                                                                    function code(x, n)
                                                                    	return Float64(x / n)
                                                                    end
                                                                    
                                                                    function tmp = code(x, n)
                                                                    	tmp = x / n;
                                                                    end
                                                                    
                                                                    code[x_, n_] := N[(x / n), $MachinePrecision]
                                                                    
                                                                    \begin{array}{l}
                                                                    
                                                                    \\
                                                                    \frac{x}{n}
                                                                    \end{array}
                                                                    
                                                                    Derivation
                                                                    1. Initial program 50.3%

                                                                      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                    2. Add Preprocessing
                                                                    3. Taylor expanded in x around 0

                                                                      \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right) - e^{\frac{\log x}{n}}} \]
                                                                    4. Applied rewrites47.1%

                                                                      \[\leadsto \color{blue}{\mathsf{fma}\left(x \cdot x, \frac{0.5}{n \cdot n} - \frac{0.5}{n}, \frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)\right)} \]
                                                                    5. Taylor expanded in n around 0

                                                                      \[\leadsto \frac{\frac{1}{2} \cdot {x}^{2} + n \cdot \left(x + \frac{-1}{2} \cdot {x}^{2}\right)}{\color{blue}{{n}^{2}}} \]
                                                                    6. Step-by-step derivation
                                                                      1. Applied rewrites5.5%

                                                                        \[\leadsto \frac{\frac{\mathsf{fma}\left(\mathsf{fma}\left(-0.5, x, 1\right) \cdot n, x, \left(0.5 \cdot x\right) \cdot x\right)}{n}}{\color{blue}{n}} \]
                                                                      2. Taylor expanded in x around 0

                                                                        \[\leadsto \frac{x}{n} \]
                                                                      3. Step-by-step derivation
                                                                        1. Applied rewrites4.6%

                                                                          \[\leadsto \frac{x}{n} \]
                                                                        2. Add Preprocessing

                                                                        Reproduce

                                                                        ?
                                                                        herbie shell --seed 2024299 
                                                                        (FPCore (x n)
                                                                          :name "2nthrt (problem 3.4.6)"
                                                                          :precision binary64
                                                                          (- (pow (+ x 1.0) (/ 1.0 n)) (pow x (/ 1.0 n))))