ABCF->ab-angle a

Percentage Accurate: 19.7% → 63.9%
Time: 14.6s
Alternatives: 16
Speedup: 16.9×

Specification

?
\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
real(8) function code(a, b, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) + sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 16 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 19.7% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
real(8) function code(a, b, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) + sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Alternative 1: 63.9% accurate, 0.4× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\ t_1 := \frac{\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_0}\\ t_2 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;t\_1 \leq -5 \cdot 10^{-210}:\\ \;\;\;\;\left(\sqrt{F \cdot 2} \cdot \left(-\sqrt{\mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)}\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}}{t\_2}\\ \mathbf{elif}\;t\_1 \leq \infty:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot F\right) \cdot t\_2}}{-1} \cdot \frac{\sqrt{\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C\right) + C}}{t\_2}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{F} \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{-B\_m}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (let* ((t_0 (- (pow B_m 2.0) (* (* 4.0 A) C)))
        (t_1
         (/
          (sqrt
           (*
            (* 2.0 (* t_0 F))
            (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B_m 2.0))))))
          (- t_0)))
        (t_2 (fma -4.0 (* C A) (* B_m B_m))))
   (if (<= t_1 -5e-210)
     (*
      (* (sqrt (* F 2.0)) (- (sqrt (fma (* C A) -4.0 (* B_m B_m)))))
      (/ (sqrt (+ (+ (hypot (- A C) B_m) A) C)) t_2))
     (if (<= t_1 INFINITY)
       (*
        (/ (sqrt (* (* 2.0 F) t_2)) -1.0)
        (/ (sqrt (+ (fma -0.5 (/ (* B_m B_m) A) C) C)) t_2))
       (/ (* (sqrt F) (sqrt (* (+ (hypot C B_m) C) 2.0))) (- B_m))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double t_0 = pow(B_m, 2.0) - ((4.0 * A) * C);
	double t_1 = sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B_m, 2.0)))))) / -t_0;
	double t_2 = fma(-4.0, (C * A), (B_m * B_m));
	double tmp;
	if (t_1 <= -5e-210) {
		tmp = (sqrt((F * 2.0)) * -sqrt(fma((C * A), -4.0, (B_m * B_m)))) * (sqrt(((hypot((A - C), B_m) + A) + C)) / t_2);
	} else if (t_1 <= ((double) INFINITY)) {
		tmp = (sqrt(((2.0 * F) * t_2)) / -1.0) * (sqrt((fma(-0.5, ((B_m * B_m) / A), C) + C)) / t_2);
	} else {
		tmp = (sqrt(F) * sqrt(((hypot(C, B_m) + C) * 2.0))) / -B_m;
	}
	return tmp;
}
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	t_0 = Float64((B_m ^ 2.0) - Float64(Float64(4.0 * A) * C))
	t_1 = Float64(sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B_m ^ 2.0)))))) / Float64(-t_0))
	t_2 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
	tmp = 0.0
	if (t_1 <= -5e-210)
		tmp = Float64(Float64(sqrt(Float64(F * 2.0)) * Float64(-sqrt(fma(Float64(C * A), -4.0, Float64(B_m * B_m))))) * Float64(sqrt(Float64(Float64(hypot(Float64(A - C), B_m) + A) + C)) / t_2));
	elseif (t_1 <= Inf)
		tmp = Float64(Float64(sqrt(Float64(Float64(2.0 * F) * t_2)) / -1.0) * Float64(sqrt(Float64(fma(-0.5, Float64(Float64(B_m * B_m) / A), C) + C)) / t_2));
	else
		tmp = Float64(Float64(sqrt(F) * sqrt(Float64(Float64(hypot(C, B_m) + C) * 2.0))) / Float64(-B_m));
	end
	return tmp
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[Power[B$95$m, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision]}, Block[{t$95$2 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$1, -5e-210], N[(N[(N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision] * (-N[Sqrt[N[(N[(C * A), $MachinePrecision] * -4.0 + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision])), $MachinePrecision] * N[(N[Sqrt[N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] / t$95$2), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$1, Infinity], N[(N[(N[Sqrt[N[(N[(2.0 * F), $MachinePrecision] * t$95$2), $MachinePrecision]], $MachinePrecision] / -1.0), $MachinePrecision] * N[(N[Sqrt[N[(N[(-0.5 * N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] + C), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] / t$95$2), $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[F], $MachinePrecision] * N[Sqrt[N[(N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / (-B$95$m)), $MachinePrecision]]]]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
t_0 := {B\_m}^{2} - \left(4 \cdot A\right) \cdot C\\
t_1 := \frac{\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B\_m}^{2}}\right)}}{-t\_0}\\
t_2 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
\mathbf{if}\;t\_1 \leq -5 \cdot 10^{-210}:\\
\;\;\;\;\left(\sqrt{F \cdot 2} \cdot \left(-\sqrt{\mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)}\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}}{t\_2}\\

\mathbf{elif}\;t\_1 \leq \infty:\\
\;\;\;\;\frac{\sqrt{\left(2 \cdot F\right) \cdot t\_2}}{-1} \cdot \frac{\sqrt{\mathsf{fma}\left(-0.5, \frac{B\_m \cdot B\_m}{A}, C\right) + C}}{t\_2}\\

\mathbf{else}:\\
\;\;\;\;\frac{\sqrt{F} \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{-B\_m}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < -5.0000000000000002e-210

    1. Initial program 42.1%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Applied rewrites60.4%

      \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
    4. Step-by-step derivation
      1. lift-/.f64N/A

        \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1}} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      2. frac-2negN/A

        \[\leadsto \color{blue}{\frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\right)}{\mathsf{neg}\left(-1\right)}} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      3. metadata-evalN/A

        \[\leadsto \frac{\mathsf{neg}\left(\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\right)}{\color{blue}{1}} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      4. /-rgt-identityN/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\right)\right)} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      5. lift-sqrt.f64N/A

        \[\leadsto \left(\mathsf{neg}\left(\color{blue}{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      6. pow1/2N/A

        \[\leadsto \left(\mathsf{neg}\left(\color{blue}{{\left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}^{\frac{1}{2}}}\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      7. lift-*.f64N/A

        \[\leadsto \left(\mathsf{neg}\left({\color{blue}{\left(\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}}^{\frac{1}{2}}\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      8. unpow-prod-downN/A

        \[\leadsto \left(\mathsf{neg}\left(\color{blue}{{\left(2 \cdot F\right)}^{\frac{1}{2}} \cdot {\left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}^{\frac{1}{2}}}\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      9. distribute-rgt-neg-inN/A

        \[\leadsto \color{blue}{\left({\left(2 \cdot F\right)}^{\frac{1}{2}} \cdot \left(\mathsf{neg}\left({\left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)\right)\right)} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      10. lower-*.f64N/A

        \[\leadsto \color{blue}{\left({\left(2 \cdot F\right)}^{\frac{1}{2}} \cdot \left(\mathsf{neg}\left({\left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)\right)\right)} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      11. pow1/2N/A

        \[\leadsto \left(\color{blue}{\sqrt{2 \cdot F}} \cdot \left(\mathsf{neg}\left({\left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      12. lower-sqrt.f64N/A

        \[\leadsto \left(\color{blue}{\sqrt{2 \cdot F}} \cdot \left(\mathsf{neg}\left({\left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      13. lift-*.f64N/A

        \[\leadsto \left(\sqrt{\color{blue}{2 \cdot F}} \cdot \left(\mathsf{neg}\left({\left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      14. *-commutativeN/A

        \[\leadsto \left(\sqrt{\color{blue}{F \cdot 2}} \cdot \left(\mathsf{neg}\left({\left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      15. lower-*.f64N/A

        \[\leadsto \left(\sqrt{\color{blue}{F \cdot 2}} \cdot \left(\mathsf{neg}\left({\left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      16. lower-neg.f64N/A

        \[\leadsto \left(\sqrt{F \cdot 2} \cdot \color{blue}{\left(-{\left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)\right)}^{\frac{1}{2}}\right)}\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      17. pow1/2N/A

        \[\leadsto \left(\sqrt{F \cdot 2} \cdot \left(-\color{blue}{\sqrt{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      18. lift-fma.f64N/A

        \[\leadsto \left(\sqrt{F \cdot 2} \cdot \left(-\sqrt{\color{blue}{-4 \cdot \left(C \cdot A\right) + B \cdot B}}\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      19. +-commutativeN/A

        \[\leadsto \left(\sqrt{F \cdot 2} \cdot \left(-\sqrt{\color{blue}{B \cdot B + -4 \cdot \left(C \cdot A\right)}}\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      20. metadata-evalN/A

        \[\leadsto \left(\sqrt{F \cdot 2} \cdot \left(-\sqrt{B \cdot B + \color{blue}{\left(\mathsf{neg}\left(4\right)\right)} \cdot \left(C \cdot A\right)}\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      21. cancel-sign-sub-invN/A

        \[\leadsto \left(\sqrt{F \cdot 2} \cdot \left(-\sqrt{\color{blue}{B \cdot B - 4 \cdot \left(C \cdot A\right)}}\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
    5. Applied rewrites79.4%

      \[\leadsto \color{blue}{\left(\sqrt{F \cdot 2} \cdot \left(-\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}\right)\right)} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]

    if -5.0000000000000002e-210 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C))) < +inf.0

    1. Initial program 20.1%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Applied rewrites36.1%

      \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
    4. Taylor expanded in A around -inf

      \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
    5. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + C\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      2. lower-fma.f64N/A

        \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{\mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{A}, C\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      3. lower-/.f64N/A

        \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\mathsf{fma}\left(\frac{-1}{2}, \color{blue}{\frac{{B}^{2}}{A}}, C\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      4. unpow2N/A

        \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\mathsf{fma}\left(\frac{-1}{2}, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
      5. lower-*.f6430.8

        \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\mathsf{fma}\left(-0.5, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
    6. Applied rewrites30.8%

      \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]

    if +inf.0 < (/.f64 (neg.f64 (sqrt.f64 (*.f64 (*.f64 #s(literal 2 binary64) (*.f64 (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)) F)) (+.f64 (+.f64 A C) (sqrt.f64 (+.f64 (pow.f64 (-.f64 A C) #s(literal 2 binary64)) (pow.f64 B #s(literal 2 binary64)))))))) (-.f64 (pow.f64 B #s(literal 2 binary64)) (*.f64 (*.f64 #s(literal 4 binary64) A) C)))

    1. Initial program 0.0%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in A around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. associate-*r*N/A

        \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
      2. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
      3. mul-1-negN/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
      4. lower-neg.f64N/A

        \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
      5. lower-/.f64N/A

        \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
      6. lower-sqrt.f64N/A

        \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
      7. lower-sqrt.f64N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
      8. *-commutativeN/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
      9. lower-*.f64N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
      10. +-commutativeN/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
      11. lower-+.f64N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
      12. +-commutativeN/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
      13. unpow2N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
      14. unpow2N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
      15. lower-hypot.f6423.0

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
    5. Applied rewrites23.0%

      \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
    6. Step-by-step derivation
      1. Applied rewrites30.5%

        \[\leadsto \left(\frac{\sqrt{2}}{-B} \cdot \sqrt{\mathsf{hypot}\left(C, B\right) + C}\right) \cdot \color{blue}{\sqrt{F}} \]
      2. Step-by-step derivation
        1. Applied rewrites30.6%

          \[\leadsto \frac{\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2}}{-B} \cdot \color{blue}{\sqrt{F}} \]
        2. Step-by-step derivation
          1. Applied rewrites30.6%

            \[\leadsto \frac{\sqrt{F} \cdot \left(-\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2}\right)}{\color{blue}{B}} \]
        3. Recombined 3 regimes into one program.
        4. Final simplification47.8%

          \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq -5 \cdot 10^{-210}:\\ \;\;\;\;\left(\sqrt{F \cdot 2} \cdot \left(-\sqrt{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}\right)\right) \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{elif}\;\frac{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{-\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)} \leq \infty:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{F} \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2}}{-B}\\ \end{array} \]
        5. Add Preprocessing

        Alternative 2: 59.0% accurate, 1.2× speedup?

        \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\ t_1 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 10^{-195}:\\ \;\;\;\;\frac{\sqrt{t\_1 \cdot \left(F \cdot 2\right)}}{\frac{-t\_1}{\sqrt{C + C}}}\\ \mathbf{elif}\;{B\_m}^{2} \leq 4 \cdot 10^{+56}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot F\right) \cdot t\_0}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}}{t\_0}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{-B\_m} \cdot \sqrt{F}\\ \end{array} \end{array} \]
        B_m = (fabs.f64 B)
        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
        (FPCore (A B_m C F)
         :precision binary64
         (let* ((t_0 (fma -4.0 (* C A) (* B_m B_m)))
                (t_1 (fma (* -4.0 C) A (* B_m B_m))))
           (if (<= (pow B_m 2.0) 1e-195)
             (/ (sqrt (* t_1 (* F 2.0))) (/ (- t_1) (sqrt (+ C C))))
             (if (<= (pow B_m 2.0) 4e+56)
               (*
                (/ (sqrt (* (* 2.0 F) t_0)) -1.0)
                (/ (sqrt (+ (+ (hypot (- A C) B_m) A) C)) t_0))
               (* (/ (sqrt (* (+ (hypot C B_m) C) 2.0)) (- B_m)) (sqrt F))))))
        B_m = fabs(B);
        assert(A < B_m && B_m < C && C < F);
        double code(double A, double B_m, double C, double F) {
        	double t_0 = fma(-4.0, (C * A), (B_m * B_m));
        	double t_1 = fma((-4.0 * C), A, (B_m * B_m));
        	double tmp;
        	if (pow(B_m, 2.0) <= 1e-195) {
        		tmp = sqrt((t_1 * (F * 2.0))) / (-t_1 / sqrt((C + C)));
        	} else if (pow(B_m, 2.0) <= 4e+56) {
        		tmp = (sqrt(((2.0 * F) * t_0)) / -1.0) * (sqrt(((hypot((A - C), B_m) + A) + C)) / t_0);
        	} else {
        		tmp = (sqrt(((hypot(C, B_m) + C) * 2.0)) / -B_m) * sqrt(F);
        	}
        	return tmp;
        }
        
        B_m = abs(B)
        A, B_m, C, F = sort([A, B_m, C, F])
        function code(A, B_m, C, F)
        	t_0 = fma(-4.0, Float64(C * A), Float64(B_m * B_m))
        	t_1 = fma(Float64(-4.0 * C), A, Float64(B_m * B_m))
        	tmp = 0.0
        	if ((B_m ^ 2.0) <= 1e-195)
        		tmp = Float64(sqrt(Float64(t_1 * Float64(F * 2.0))) / Float64(Float64(-t_1) / sqrt(Float64(C + C))));
        	elseif ((B_m ^ 2.0) <= 4e+56)
        		tmp = Float64(Float64(sqrt(Float64(Float64(2.0 * F) * t_0)) / -1.0) * Float64(sqrt(Float64(Float64(hypot(Float64(A - C), B_m) + A) + C)) / t_0));
        	else
        		tmp = Float64(Float64(sqrt(Float64(Float64(hypot(C, B_m) + C) * 2.0)) / Float64(-B_m)) * sqrt(F));
        	end
        	return tmp
        end
        
        B_m = N[Abs[B], $MachinePrecision]
        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
        code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(-4.0 * N[(C * A), $MachinePrecision] + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(-4.0 * C), $MachinePrecision] * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e-195], N[(N[Sqrt[N[(t$95$1 * N[(F * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[((-t$95$1) / N[Sqrt[N[(C + C), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 4e+56], N[(N[(N[Sqrt[N[(N[(2.0 * F), $MachinePrecision] * t$95$0), $MachinePrecision]], $MachinePrecision] / -1.0), $MachinePrecision] * N[(N[Sqrt[N[(N[(N[Sqrt[N[(A - C), $MachinePrecision] ^ 2 + B$95$m ^ 2], $MachinePrecision] + A), $MachinePrecision] + C), $MachinePrecision]], $MachinePrecision] / t$95$0), $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision]]]]]
        
        \begin{array}{l}
        B_m = \left|B\right|
        \\
        [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
        \\
        \begin{array}{l}
        t_0 := \mathsf{fma}\left(-4, C \cdot A, B\_m \cdot B\_m\right)\\
        t_1 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\
        \mathbf{if}\;{B\_m}^{2} \leq 10^{-195}:\\
        \;\;\;\;\frac{\sqrt{t\_1 \cdot \left(F \cdot 2\right)}}{\frac{-t\_1}{\sqrt{C + C}}}\\
        
        \mathbf{elif}\;{B\_m}^{2} \leq 4 \cdot 10^{+56}:\\
        \;\;\;\;\frac{\sqrt{\left(2 \cdot F\right) \cdot t\_0}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\_m\right) + A\right) + C}}{t\_0}\\
        
        \mathbf{else}:\\
        \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{-B\_m} \cdot \sqrt{F}\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 3 regimes
        2. if (pow.f64 B #s(literal 2 binary64)) < 1.0000000000000001e-195

          1. Initial program 15.3%

            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. Add Preprocessing
          3. Applied rewrites30.0%

            \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
          4. Taylor expanded in C around inf

            \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \left(1 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
          5. Step-by-step derivation
            1. lower-*.f64N/A

              \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \left(1 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
            2. +-commutativeN/A

              \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \color{blue}{\left(\left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right) + 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
            3. distribute-lft1-inN/A

              \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \left(\color{blue}{\left(-1 + 1\right) \cdot \frac{A}{C}} + 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
            4. metadata-evalN/A

              \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \left(\color{blue}{0} \cdot \frac{A}{C} + 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
            5. lower-fma.f64N/A

              \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \color{blue}{\mathsf{fma}\left(0, \frac{A}{C}, 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
            6. lower-/.f6416.2

              \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \mathsf{fma}\left(0, \color{blue}{\frac{A}{C}}, 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
          6. Applied rewrites16.2%

            \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
          7. Step-by-step derivation
            1. lift-*.f64N/A

              \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
            2. lift-/.f64N/A

              \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \color{blue}{\frac{\sqrt{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
            3. clear-numN/A

              \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \color{blue}{\frac{1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right) + C}}}} \]
            4. un-div-invN/A

              \[\leadsto \color{blue}{\frac{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1}}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right) + C}}}} \]
            5. lower-/.f64N/A

              \[\leadsto \color{blue}{\frac{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1}}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right) + C}}}} \]
          8. Applied rewrites20.2%

            \[\leadsto \color{blue}{\frac{-\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)}}{\frac{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}{\sqrt{C + C}}}} \]

          if 1.0000000000000001e-195 < (pow.f64 B #s(literal 2 binary64)) < 4.00000000000000037e56

          1. Initial program 42.9%

            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. Add Preprocessing
          3. Applied rewrites53.9%

            \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]

          if 4.00000000000000037e56 < (pow.f64 B #s(literal 2 binary64))

          1. Initial program 11.0%

            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. Add Preprocessing
          3. Taylor expanded in A around 0

            \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
          4. Step-by-step derivation
            1. associate-*r*N/A

              \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
            2. lower-*.f64N/A

              \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
            3. mul-1-negN/A

              \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
            4. lower-neg.f64N/A

              \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
            5. lower-/.f64N/A

              \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
            6. lower-sqrt.f64N/A

              \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
            7. lower-sqrt.f64N/A

              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
            8. *-commutativeN/A

              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
            9. lower-*.f64N/A

              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
            10. +-commutativeN/A

              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
            11. lower-+.f64N/A

              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
            12. +-commutativeN/A

              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
            13. unpow2N/A

              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
            14. unpow2N/A

              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
            15. lower-hypot.f6429.1

              \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
          5. Applied rewrites29.1%

            \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
          6. Step-by-step derivation
            1. Applied rewrites37.5%

              \[\leadsto \left(\frac{\sqrt{2}}{-B} \cdot \sqrt{\mathsf{hypot}\left(C, B\right) + C}\right) \cdot \color{blue}{\sqrt{F}} \]
            2. Step-by-step derivation
              1. Applied rewrites37.6%

                \[\leadsto \frac{\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2}}{-B} \cdot \color{blue}{\sqrt{F}} \]
            3. Recombined 3 regimes into one program.
            4. Final simplification35.7%

              \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 10^{-195}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)}}{\frac{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}{\sqrt{C + C}}}\\ \mathbf{elif}\;{B}^{2} \leq 4 \cdot 10^{+56}:\\ \;\;\;\;\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2}}{-B} \cdot \sqrt{F}\\ \end{array} \]
            5. Add Preprocessing

            Alternative 3: 56.8% accurate, 1.9× speedup?

            \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 10^{+47}:\\ \;\;\;\;\frac{\sqrt{t\_0 \cdot \left(F \cdot 2\right)}}{\frac{-t\_0}{\sqrt{C + C}}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{-B\_m} \cdot \sqrt{F}\\ \end{array} \end{array} \]
            B_m = (fabs.f64 B)
            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
            (FPCore (A B_m C F)
             :precision binary64
             (let* ((t_0 (fma (* -4.0 C) A (* B_m B_m))))
               (if (<= (pow B_m 2.0) 1e+47)
                 (/ (sqrt (* t_0 (* F 2.0))) (/ (- t_0) (sqrt (+ C C))))
                 (* (/ (sqrt (* (+ (hypot C B_m) C) 2.0)) (- B_m)) (sqrt F)))))
            B_m = fabs(B);
            assert(A < B_m && B_m < C && C < F);
            double code(double A, double B_m, double C, double F) {
            	double t_0 = fma((-4.0 * C), A, (B_m * B_m));
            	double tmp;
            	if (pow(B_m, 2.0) <= 1e+47) {
            		tmp = sqrt((t_0 * (F * 2.0))) / (-t_0 / sqrt((C + C)));
            	} else {
            		tmp = (sqrt(((hypot(C, B_m) + C) * 2.0)) / -B_m) * sqrt(F);
            	}
            	return tmp;
            }
            
            B_m = abs(B)
            A, B_m, C, F = sort([A, B_m, C, F])
            function code(A, B_m, C, F)
            	t_0 = fma(Float64(-4.0 * C), A, Float64(B_m * B_m))
            	tmp = 0.0
            	if ((B_m ^ 2.0) <= 1e+47)
            		tmp = Float64(sqrt(Float64(t_0 * Float64(F * 2.0))) / Float64(Float64(-t_0) / sqrt(Float64(C + C))));
            	else
            		tmp = Float64(Float64(sqrt(Float64(Float64(hypot(C, B_m) + C) * 2.0)) / Float64(-B_m)) * sqrt(F));
            	end
            	return tmp
            end
            
            B_m = N[Abs[B], $MachinePrecision]
            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
            code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(-4.0 * C), $MachinePrecision] * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e+47], N[(N[Sqrt[N[(t$95$0 * N[(F * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[((-t$95$0) / N[Sqrt[N[(C + C), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision] * N[Sqrt[F], $MachinePrecision]), $MachinePrecision]]]
            
            \begin{array}{l}
            B_m = \left|B\right|
            \\
            [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
            \\
            \begin{array}{l}
            t_0 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\
            \mathbf{if}\;{B\_m}^{2} \leq 10^{+47}:\\
            \;\;\;\;\frac{\sqrt{t\_0 \cdot \left(F \cdot 2\right)}}{\frac{-t\_0}{\sqrt{C + C}}}\\
            
            \mathbf{else}:\\
            \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{-B\_m} \cdot \sqrt{F}\\
            
            
            \end{array}
            \end{array}
            
            Derivation
            1. Split input into 2 regimes
            2. if (pow.f64 B #s(literal 2 binary64)) < 1e47

              1. Initial program 25.9%

                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              2. Add Preprocessing
              3. Applied rewrites39.1%

                \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
              4. Taylor expanded in C around inf

                \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \left(1 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
              5. Step-by-step derivation
                1. lower-*.f64N/A

                  \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \left(1 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                2. +-commutativeN/A

                  \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \color{blue}{\left(\left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right) + 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                3. distribute-lft1-inN/A

                  \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \left(\color{blue}{\left(-1 + 1\right) \cdot \frac{A}{C}} + 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                4. metadata-evalN/A

                  \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \left(\color{blue}{0} \cdot \frac{A}{C} + 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                5. lower-fma.f64N/A

                  \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \color{blue}{\mathsf{fma}\left(0, \frac{A}{C}, 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                6. lower-/.f6420.6

                  \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \mathsf{fma}\left(0, \color{blue}{\frac{A}{C}}, 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
              6. Applied rewrites20.6%

                \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
              7. Step-by-step derivation
                1. lift-*.f64N/A

                  \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                2. lift-/.f64N/A

                  \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \color{blue}{\frac{\sqrt{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                3. clear-numN/A

                  \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \color{blue}{\frac{1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right) + C}}}} \]
                4. un-div-invN/A

                  \[\leadsto \color{blue}{\frac{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1}}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right) + C}}}} \]
                5. lower-/.f64N/A

                  \[\leadsto \color{blue}{\frac{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1}}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right) + C}}}} \]
              8. Applied rewrites24.8%

                \[\leadsto \color{blue}{\frac{-\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)}}{\frac{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}{\sqrt{C + C}}}} \]

              if 1e47 < (pow.f64 B #s(literal 2 binary64))

              1. Initial program 11.7%

                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              2. Add Preprocessing
              3. Taylor expanded in A around 0

                \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
              4. Step-by-step derivation
                1. associate-*r*N/A

                  \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                2. lower-*.f64N/A

                  \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                3. mul-1-negN/A

                  \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                4. lower-neg.f64N/A

                  \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                5. lower-/.f64N/A

                  \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                6. lower-sqrt.f64N/A

                  \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                7. lower-sqrt.f64N/A

                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                8. *-commutativeN/A

                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                9. lower-*.f64N/A

                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                10. +-commutativeN/A

                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                11. lower-+.f64N/A

                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                12. +-commutativeN/A

                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                13. unpow2N/A

                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                14. unpow2N/A

                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                15. lower-hypot.f6429.6

                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
              5. Applied rewrites29.6%

                \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
              6. Step-by-step derivation
                1. Applied rewrites38.0%

                  \[\leadsto \left(\frac{\sqrt{2}}{-B} \cdot \sqrt{\mathsf{hypot}\left(C, B\right) + C}\right) \cdot \color{blue}{\sqrt{F}} \]
                2. Step-by-step derivation
                  1. Applied rewrites38.1%

                    \[\leadsto \frac{\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                3. Recombined 2 regimes into one program.
                4. Final simplification31.4%

                  \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 10^{+47}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)}}{\frac{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}{\sqrt{C + C}}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2}}{-B} \cdot \sqrt{F}\\ \end{array} \]
                5. Add Preprocessing

                Alternative 4: 55.4% accurate, 2.4× speedup?

                \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;B\_m \leq 6.2 \cdot 10^{+23}:\\ \;\;\;\;\frac{\sqrt{t\_0 \cdot \left(F \cdot 2\right)}}{\frac{-t\_0}{\sqrt{C + C}}}\\ \mathbf{elif}\;B\_m \leq 1.05 \cdot 10^{+189}:\\ \;\;\;\;\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2} \cdot \frac{\sqrt{F}}{-B\_m}\\ \mathbf{else}:\\ \;\;\;\;\frac{\mathsf{fma}\left(0.5, \sqrt{{B\_m}^{-1}} \cdot \left(C \cdot \sqrt{2}\right), \sqrt{B\_m} \cdot \sqrt{2}\right)}{B\_m} \cdot \left(-\sqrt{F}\right)\\ \end{array} \end{array} \]
                B_m = (fabs.f64 B)
                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                (FPCore (A B_m C F)
                 :precision binary64
                 (let* ((t_0 (fma (* -4.0 C) A (* B_m B_m))))
                   (if (<= B_m 6.2e+23)
                     (/ (sqrt (* t_0 (* F 2.0))) (/ (- t_0) (sqrt (+ C C))))
                     (if (<= B_m 1.05e+189)
                       (* (sqrt (* (+ (hypot C B_m) C) 2.0)) (/ (sqrt F) (- B_m)))
                       (*
                        (/
                         (fma
                          0.5
                          (* (sqrt (pow B_m -1.0)) (* C (sqrt 2.0)))
                          (* (sqrt B_m) (sqrt 2.0)))
                         B_m)
                        (- (sqrt F)))))))
                B_m = fabs(B);
                assert(A < B_m && B_m < C && C < F);
                double code(double A, double B_m, double C, double F) {
                	double t_0 = fma((-4.0 * C), A, (B_m * B_m));
                	double tmp;
                	if (B_m <= 6.2e+23) {
                		tmp = sqrt((t_0 * (F * 2.0))) / (-t_0 / sqrt((C + C)));
                	} else if (B_m <= 1.05e+189) {
                		tmp = sqrt(((hypot(C, B_m) + C) * 2.0)) * (sqrt(F) / -B_m);
                	} else {
                		tmp = (fma(0.5, (sqrt(pow(B_m, -1.0)) * (C * sqrt(2.0))), (sqrt(B_m) * sqrt(2.0))) / B_m) * -sqrt(F);
                	}
                	return tmp;
                }
                
                B_m = abs(B)
                A, B_m, C, F = sort([A, B_m, C, F])
                function code(A, B_m, C, F)
                	t_0 = fma(Float64(-4.0 * C), A, Float64(B_m * B_m))
                	tmp = 0.0
                	if (B_m <= 6.2e+23)
                		tmp = Float64(sqrt(Float64(t_0 * Float64(F * 2.0))) / Float64(Float64(-t_0) / sqrt(Float64(C + C))));
                	elseif (B_m <= 1.05e+189)
                		tmp = Float64(sqrt(Float64(Float64(hypot(C, B_m) + C) * 2.0)) * Float64(sqrt(F) / Float64(-B_m)));
                	else
                		tmp = Float64(Float64(fma(0.5, Float64(sqrt((B_m ^ -1.0)) * Float64(C * sqrt(2.0))), Float64(sqrt(B_m) * sqrt(2.0))) / B_m) * Float64(-sqrt(F)));
                	end
                	return tmp
                end
                
                B_m = N[Abs[B], $MachinePrecision]
                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(-4.0 * C), $MachinePrecision] * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[B$95$m, 6.2e+23], N[(N[Sqrt[N[(t$95$0 * N[(F * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[((-t$95$0) / N[Sqrt[N[(C + C), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[B$95$m, 1.05e+189], N[(N[Sqrt[N[(N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[F], $MachinePrecision] / (-B$95$m)), $MachinePrecision]), $MachinePrecision], N[(N[(N[(0.5 * N[(N[Sqrt[N[Power[B$95$m, -1.0], $MachinePrecision]], $MachinePrecision] * N[(C * N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(N[Sqrt[B$95$m], $MachinePrecision] * N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / B$95$m), $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]]]]
                
                \begin{array}{l}
                B_m = \left|B\right|
                \\
                [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                \\
                \begin{array}{l}
                t_0 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\
                \mathbf{if}\;B\_m \leq 6.2 \cdot 10^{+23}:\\
                \;\;\;\;\frac{\sqrt{t\_0 \cdot \left(F \cdot 2\right)}}{\frac{-t\_0}{\sqrt{C + C}}}\\
                
                \mathbf{elif}\;B\_m \leq 1.05 \cdot 10^{+189}:\\
                \;\;\;\;\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2} \cdot \frac{\sqrt{F}}{-B\_m}\\
                
                \mathbf{else}:\\
                \;\;\;\;\frac{\mathsf{fma}\left(0.5, \sqrt{{B\_m}^{-1}} \cdot \left(C \cdot \sqrt{2}\right), \sqrt{B\_m} \cdot \sqrt{2}\right)}{B\_m} \cdot \left(-\sqrt{F}\right)\\
                
                
                \end{array}
                \end{array}
                
                Derivation
                1. Split input into 3 regimes
                2. if B < 6.19999999999999941e23

                  1. Initial program 20.7%

                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  2. Add Preprocessing
                  3. Applied rewrites31.0%

                    \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                  4. Taylor expanded in C around inf

                    \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \left(1 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  5. Step-by-step derivation
                    1. lower-*.f64N/A

                      \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \left(1 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                    2. +-commutativeN/A

                      \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \color{blue}{\left(\left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right) + 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                    3. distribute-lft1-inN/A

                      \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \left(\color{blue}{\left(-1 + 1\right) \cdot \frac{A}{C}} + 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                    4. metadata-evalN/A

                      \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \left(\color{blue}{0} \cdot \frac{A}{C} + 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                    5. lower-fma.f64N/A

                      \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \color{blue}{\mathsf{fma}\left(0, \frac{A}{C}, 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                    6. lower-/.f6415.0

                      \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \mathsf{fma}\left(0, \color{blue}{\frac{A}{C}}, 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  6. Applied rewrites15.0%

                    \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                  7. Step-by-step derivation
                    1. lift-*.f64N/A

                      \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                    2. lift-/.f64N/A

                      \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \color{blue}{\frac{\sqrt{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                    3. clear-numN/A

                      \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \color{blue}{\frac{1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right) + C}}}} \]
                    4. un-div-invN/A

                      \[\leadsto \color{blue}{\frac{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1}}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right) + C}}}} \]
                    5. lower-/.f64N/A

                      \[\leadsto \color{blue}{\frac{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1}}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right) + C}}}} \]
                  8. Applied rewrites17.8%

                    \[\leadsto \color{blue}{\frac{-\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)}}{\frac{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}{\sqrt{C + C}}}} \]

                  if 6.19999999999999941e23 < B < 1.04999999999999996e189

                  1. Initial program 24.6%

                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                  2. Add Preprocessing
                  3. Taylor expanded in A around 0

                    \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                  4. Step-by-step derivation
                    1. associate-*r*N/A

                      \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                    2. lower-*.f64N/A

                      \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                    3. mul-1-negN/A

                      \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                    4. lower-neg.f64N/A

                      \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                    5. lower-/.f64N/A

                      \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                    6. lower-sqrt.f64N/A

                      \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                    7. lower-sqrt.f64N/A

                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                    8. *-commutativeN/A

                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                    9. lower-*.f64N/A

                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                    10. +-commutativeN/A

                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                    11. lower-+.f64N/A

                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                    12. +-commutativeN/A

                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                    13. unpow2N/A

                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                    14. unpow2N/A

                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                    15. lower-hypot.f6447.7

                      \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                  5. Applied rewrites47.7%

                    \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                  6. Step-by-step derivation
                    1. Applied rewrites56.3%

                      \[\leadsto \left(\frac{\sqrt{2}}{-B} \cdot \sqrt{\mathsf{hypot}\left(C, B\right) + C}\right) \cdot \color{blue}{\sqrt{F}} \]
                    2. Step-by-step derivation
                      1. Applied rewrites56.3%

                        \[\leadsto \frac{\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                      2. Step-by-step derivation
                        1. Applied rewrites56.4%

                          \[\leadsto \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2} \cdot \color{blue}{\frac{\sqrt{F}}{-B}} \]

                        if 1.04999999999999996e189 < B

                        1. Initial program 0.0%

                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                        2. Add Preprocessing
                        3. Taylor expanded in A around 0

                          \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                        4. Step-by-step derivation
                          1. associate-*r*N/A

                            \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                          2. lower-*.f64N/A

                            \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                          3. mul-1-negN/A

                            \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                          4. lower-neg.f64N/A

                            \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                          5. lower-/.f64N/A

                            \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                          6. lower-sqrt.f64N/A

                            \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                          7. lower-sqrt.f64N/A

                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                          8. *-commutativeN/A

                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                          9. lower-*.f64N/A

                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                          10. +-commutativeN/A

                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                          11. lower-+.f64N/A

                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                          12. +-commutativeN/A

                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                          13. unpow2N/A

                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                          14. unpow2N/A

                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                          15. lower-hypot.f6467.4

                            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                        5. Applied rewrites67.4%

                          \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                        6. Step-by-step derivation
                          1. Applied rewrites92.9%

                            \[\leadsto \left(\frac{\sqrt{2}}{-B} \cdot \sqrt{\mathsf{hypot}\left(C, B\right) + C}\right) \cdot \color{blue}{\sqrt{F}} \]
                          2. Step-by-step derivation
                            1. Applied rewrites93.2%

                              \[\leadsto \frac{\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                            2. Taylor expanded in C around 0

                              \[\leadsto \frac{\frac{1}{2} \cdot \left(\sqrt{\frac{1}{B}} \cdot \left(C \cdot \sqrt{2}\right)\right) + \sqrt{B} \cdot \sqrt{2}}{-B} \cdot \sqrt{F} \]
                            3. Step-by-step derivation
                              1. Applied rewrites87.1%

                                \[\leadsto \frac{\mathsf{fma}\left(0.5, \sqrt{\frac{1}{B}} \cdot \left(C \cdot \sqrt{2}\right), \sqrt{B} \cdot \sqrt{2}\right)}{-B} \cdot \sqrt{F} \]
                            4. Recombined 3 regimes into one program.
                            5. Final simplification31.1%

                              \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 6.2 \cdot 10^{+23}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)}}{\frac{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}{\sqrt{C + C}}}\\ \mathbf{elif}\;B \leq 1.05 \cdot 10^{+189}:\\ \;\;\;\;\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2} \cdot \frac{\sqrt{F}}{-B}\\ \mathbf{else}:\\ \;\;\;\;\frac{\mathsf{fma}\left(0.5, \sqrt{{B}^{-1}} \cdot \left(C \cdot \sqrt{2}\right), \sqrt{B} \cdot \sqrt{2}\right)}{B} \cdot \left(-\sqrt{F}\right)\\ \end{array} \]
                            6. Add Preprocessing

                            Alternative 5: 51.6% accurate, 2.5× speedup?

                            \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;B\_m \leq 7 \cdot 10^{+24}:\\ \;\;\;\;\frac{\sqrt{t\_0 \cdot \left(F \cdot 2\right)}}{\frac{-t\_0}{\sqrt{C + C}}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\mathsf{fma}\left(0.5, \sqrt{{B\_m}^{-1}} \cdot \left(C \cdot \sqrt{2}\right), \sqrt{B\_m} \cdot \sqrt{2}\right)}{B\_m} \cdot \left(-\sqrt{F}\right)\\ \end{array} \end{array} \]
                            B_m = (fabs.f64 B)
                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                            (FPCore (A B_m C F)
                             :precision binary64
                             (let* ((t_0 (fma (* -4.0 C) A (* B_m B_m))))
                               (if (<= B_m 7e+24)
                                 (/ (sqrt (* t_0 (* F 2.0))) (/ (- t_0) (sqrt (+ C C))))
                                 (*
                                  (/
                                   (fma
                                    0.5
                                    (* (sqrt (pow B_m -1.0)) (* C (sqrt 2.0)))
                                    (* (sqrt B_m) (sqrt 2.0)))
                                   B_m)
                                  (- (sqrt F))))))
                            B_m = fabs(B);
                            assert(A < B_m && B_m < C && C < F);
                            double code(double A, double B_m, double C, double F) {
                            	double t_0 = fma((-4.0 * C), A, (B_m * B_m));
                            	double tmp;
                            	if (B_m <= 7e+24) {
                            		tmp = sqrt((t_0 * (F * 2.0))) / (-t_0 / sqrt((C + C)));
                            	} else {
                            		tmp = (fma(0.5, (sqrt(pow(B_m, -1.0)) * (C * sqrt(2.0))), (sqrt(B_m) * sqrt(2.0))) / B_m) * -sqrt(F);
                            	}
                            	return tmp;
                            }
                            
                            B_m = abs(B)
                            A, B_m, C, F = sort([A, B_m, C, F])
                            function code(A, B_m, C, F)
                            	t_0 = fma(Float64(-4.0 * C), A, Float64(B_m * B_m))
                            	tmp = 0.0
                            	if (B_m <= 7e+24)
                            		tmp = Float64(sqrt(Float64(t_0 * Float64(F * 2.0))) / Float64(Float64(-t_0) / sqrt(Float64(C + C))));
                            	else
                            		tmp = Float64(Float64(fma(0.5, Float64(sqrt((B_m ^ -1.0)) * Float64(C * sqrt(2.0))), Float64(sqrt(B_m) * sqrt(2.0))) / B_m) * Float64(-sqrt(F)));
                            	end
                            	return tmp
                            end
                            
                            B_m = N[Abs[B], $MachinePrecision]
                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                            code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(-4.0 * C), $MachinePrecision] * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[B$95$m, 7e+24], N[(N[Sqrt[N[(t$95$0 * N[(F * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[((-t$95$0) / N[Sqrt[N[(C + C), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(N[(0.5 * N[(N[Sqrt[N[Power[B$95$m, -1.0], $MachinePrecision]], $MachinePrecision] * N[(C * N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(N[Sqrt[B$95$m], $MachinePrecision] * N[Sqrt[2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / B$95$m), $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]]]
                            
                            \begin{array}{l}
                            B_m = \left|B\right|
                            \\
                            [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                            \\
                            \begin{array}{l}
                            t_0 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\
                            \mathbf{if}\;B\_m \leq 7 \cdot 10^{+24}:\\
                            \;\;\;\;\frac{\sqrt{t\_0 \cdot \left(F \cdot 2\right)}}{\frac{-t\_0}{\sqrt{C + C}}}\\
                            
                            \mathbf{else}:\\
                            \;\;\;\;\frac{\mathsf{fma}\left(0.5, \sqrt{{B\_m}^{-1}} \cdot \left(C \cdot \sqrt{2}\right), \sqrt{B\_m} \cdot \sqrt{2}\right)}{B\_m} \cdot \left(-\sqrt{F}\right)\\
                            
                            
                            \end{array}
                            \end{array}
                            
                            Derivation
                            1. Split input into 2 regimes
                            2. if B < 7.0000000000000004e24

                              1. Initial program 20.7%

                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              2. Add Preprocessing
                              3. Applied rewrites31.0%

                                \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                              4. Taylor expanded in C around inf

                                \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \left(1 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                              5. Step-by-step derivation
                                1. lower-*.f64N/A

                                  \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \left(1 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                2. +-commutativeN/A

                                  \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \color{blue}{\left(\left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right) + 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                3. distribute-lft1-inN/A

                                  \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \left(\color{blue}{\left(-1 + 1\right) \cdot \frac{A}{C}} + 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                4. metadata-evalN/A

                                  \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \left(\color{blue}{0} \cdot \frac{A}{C} + 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                5. lower-fma.f64N/A

                                  \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \color{blue}{\mathsf{fma}\left(0, \frac{A}{C}, 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                6. lower-/.f6415.0

                                  \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \mathsf{fma}\left(0, \color{blue}{\frac{A}{C}}, 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                              6. Applied rewrites15.0%

                                \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                              7. Step-by-step derivation
                                1. lift-*.f64N/A

                                  \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                                2. lift-/.f64N/A

                                  \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \color{blue}{\frac{\sqrt{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                                3. clear-numN/A

                                  \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \color{blue}{\frac{1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right) + C}}}} \]
                                4. un-div-invN/A

                                  \[\leadsto \color{blue}{\frac{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1}}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right) + C}}}} \]
                                5. lower-/.f64N/A

                                  \[\leadsto \color{blue}{\frac{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1}}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right) + C}}}} \]
                              8. Applied rewrites17.8%

                                \[\leadsto \color{blue}{\frac{-\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)}}{\frac{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}{\sqrt{C + C}}}} \]

                              if 7.0000000000000004e24 < B

                              1. Initial program 13.1%

                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                              2. Add Preprocessing
                              3. Taylor expanded in A around 0

                                \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                              4. Step-by-step derivation
                                1. associate-*r*N/A

                                  \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                2. lower-*.f64N/A

                                  \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                3. mul-1-negN/A

                                  \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                4. lower-neg.f64N/A

                                  \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                5. lower-/.f64N/A

                                  \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                6. lower-sqrt.f64N/A

                                  \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                7. lower-sqrt.f64N/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                8. *-commutativeN/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                9. lower-*.f64N/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                10. +-commutativeN/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                11. lower-+.f64N/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                12. +-commutativeN/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                                13. unpow2N/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                                14. unpow2N/A

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                                15. lower-hypot.f6457.0

                                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                              5. Applied rewrites57.0%

                                \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                              6. Step-by-step derivation
                                1. Applied rewrites73.4%

                                  \[\leadsto \left(\frac{\sqrt{2}}{-B} \cdot \sqrt{\mathsf{hypot}\left(C, B\right) + C}\right) \cdot \color{blue}{\sqrt{F}} \]
                                2. Step-by-step derivation
                                  1. Applied rewrites73.6%

                                    \[\leadsto \frac{\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                                  2. Taylor expanded in C around 0

                                    \[\leadsto \frac{\frac{1}{2} \cdot \left(\sqrt{\frac{1}{B}} \cdot \left(C \cdot \sqrt{2}\right)\right) + \sqrt{B} \cdot \sqrt{2}}{-B} \cdot \sqrt{F} \]
                                  3. Step-by-step derivation
                                    1. Applied rewrites69.4%

                                      \[\leadsto \frac{\mathsf{fma}\left(0.5, \sqrt{\frac{1}{B}} \cdot \left(C \cdot \sqrt{2}\right), \sqrt{B} \cdot \sqrt{2}\right)}{-B} \cdot \sqrt{F} \]
                                  4. Recombined 2 regimes into one program.
                                  5. Final simplification30.7%

                                    \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 7 \cdot 10^{+24}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)}}{\frac{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}{\sqrt{C + C}}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\mathsf{fma}\left(0.5, \sqrt{{B}^{-1}} \cdot \left(C \cdot \sqrt{2}\right), \sqrt{B} \cdot \sqrt{2}\right)}{B} \cdot \left(-\sqrt{F}\right)\\ \end{array} \]
                                  6. Add Preprocessing

                                  Alternative 6: 51.6% accurate, 2.5× speedup?

                                  \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 10^{+47}:\\ \;\;\;\;\frac{\sqrt{t\_0 \cdot \left(F \cdot 2\right)}}{\frac{-t\_0}{\sqrt{C + C}}}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
                                  B_m = (fabs.f64 B)
                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                  (FPCore (A B_m C F)
                                   :precision binary64
                                   (let* ((t_0 (fma (* -4.0 C) A (* B_m B_m))))
                                     (if (<= (pow B_m 2.0) 1e+47)
                                       (/ (sqrt (* t_0 (* F 2.0))) (/ (- t_0) (sqrt (+ C C))))
                                       (* (- (sqrt F)) (sqrt (/ 2.0 B_m))))))
                                  B_m = fabs(B);
                                  assert(A < B_m && B_m < C && C < F);
                                  double code(double A, double B_m, double C, double F) {
                                  	double t_0 = fma((-4.0 * C), A, (B_m * B_m));
                                  	double tmp;
                                  	if (pow(B_m, 2.0) <= 1e+47) {
                                  		tmp = sqrt((t_0 * (F * 2.0))) / (-t_0 / sqrt((C + C)));
                                  	} else {
                                  		tmp = -sqrt(F) * sqrt((2.0 / B_m));
                                  	}
                                  	return tmp;
                                  }
                                  
                                  B_m = abs(B)
                                  A, B_m, C, F = sort([A, B_m, C, F])
                                  function code(A, B_m, C, F)
                                  	t_0 = fma(Float64(-4.0 * C), A, Float64(B_m * B_m))
                                  	tmp = 0.0
                                  	if ((B_m ^ 2.0) <= 1e+47)
                                  		tmp = Float64(sqrt(Float64(t_0 * Float64(F * 2.0))) / Float64(Float64(-t_0) / sqrt(Float64(C + C))));
                                  	else
                                  		tmp = Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)));
                                  	end
                                  	return tmp
                                  end
                                  
                                  B_m = N[Abs[B], $MachinePrecision]
                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                  code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(-4.0 * C), $MachinePrecision] * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e+47], N[(N[Sqrt[N[(t$95$0 * N[(F * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[((-t$95$0) / N[Sqrt[N[(C + C), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]
                                  
                                  \begin{array}{l}
                                  B_m = \left|B\right|
                                  \\
                                  [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                  \\
                                  \begin{array}{l}
                                  t_0 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\
                                  \mathbf{if}\;{B\_m}^{2} \leq 10^{+47}:\\
                                  \;\;\;\;\frac{\sqrt{t\_0 \cdot \left(F \cdot 2\right)}}{\frac{-t\_0}{\sqrt{C + C}}}\\
                                  
                                  \mathbf{else}:\\
                                  \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\
                                  
                                  
                                  \end{array}
                                  \end{array}
                                  
                                  Derivation
                                  1. Split input into 2 regimes
                                  2. if (pow.f64 B #s(literal 2 binary64)) < 1e47

                                    1. Initial program 25.9%

                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    2. Add Preprocessing
                                    3. Applied rewrites39.1%

                                      \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                                    4. Taylor expanded in C around inf

                                      \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \left(1 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                    5. Step-by-step derivation
                                      1. lower-*.f64N/A

                                        \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \left(1 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                      2. +-commutativeN/A

                                        \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \color{blue}{\left(\left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right) + 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                      3. distribute-lft1-inN/A

                                        \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \left(\color{blue}{\left(-1 + 1\right) \cdot \frac{A}{C}} + 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                      4. metadata-evalN/A

                                        \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \left(\color{blue}{0} \cdot \frac{A}{C} + 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                      5. lower-fma.f64N/A

                                        \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \color{blue}{\mathsf{fma}\left(0, \frac{A}{C}, 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                      6. lower-/.f6420.6

                                        \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \mathsf{fma}\left(0, \color{blue}{\frac{A}{C}}, 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                    6. Applied rewrites20.6%

                                      \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                    7. Step-by-step derivation
                                      1. lift-*.f64N/A

                                        \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                                      2. lift-/.f64N/A

                                        \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \color{blue}{\frac{\sqrt{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                                      3. clear-numN/A

                                        \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \color{blue}{\frac{1}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right) + C}}}} \]
                                      4. un-div-invN/A

                                        \[\leadsto \color{blue}{\frac{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1}}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right) + C}}}} \]
                                      5. lower-/.f64N/A

                                        \[\leadsto \color{blue}{\frac{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1}}{\frac{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}{\sqrt{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right) + C}}}} \]
                                    8. Applied rewrites24.8%

                                      \[\leadsto \color{blue}{\frac{-\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)}}{\frac{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}{\sqrt{C + C}}}} \]

                                    if 1e47 < (pow.f64 B #s(literal 2 binary64))

                                    1. Initial program 11.7%

                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    2. Add Preprocessing
                                    3. Taylor expanded in B around inf

                                      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                    4. Step-by-step derivation
                                      1. mul-1-negN/A

                                        \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                      2. lower-neg.f64N/A

                                        \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                      3. lower-*.f64N/A

                                        \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                      4. lower-sqrt.f64N/A

                                        \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                      5. lower-/.f64N/A

                                        \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                      6. lower-sqrt.f6427.9

                                        \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                    5. Applied rewrites27.9%

                                      \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                    6. Step-by-step derivation
                                      1. Applied rewrites28.1%

                                        \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                      2. Step-by-step derivation
                                        1. Applied rewrites34.5%

                                          \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                      3. Recombined 2 regimes into one program.
                                      4. Final simplification29.7%

                                        \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 10^{+47}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)}}{\frac{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}{\sqrt{C + C}}}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
                                      5. Add Preprocessing

                                      Alternative 7: 51.5% accurate, 2.6× speedup?

                                      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 10^{+47}:\\ \;\;\;\;\frac{\sqrt{C + C}}{-t\_0} \cdot \sqrt{t\_0 \cdot \left(F \cdot 2\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
                                      B_m = (fabs.f64 B)
                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                      (FPCore (A B_m C F)
                                       :precision binary64
                                       (let* ((t_0 (fma (* -4.0 C) A (* B_m B_m))))
                                         (if (<= (pow B_m 2.0) 1e+47)
                                           (* (/ (sqrt (+ C C)) (- t_0)) (sqrt (* t_0 (* F 2.0))))
                                           (* (- (sqrt F)) (sqrt (/ 2.0 B_m))))))
                                      B_m = fabs(B);
                                      assert(A < B_m && B_m < C && C < F);
                                      double code(double A, double B_m, double C, double F) {
                                      	double t_0 = fma((-4.0 * C), A, (B_m * B_m));
                                      	double tmp;
                                      	if (pow(B_m, 2.0) <= 1e+47) {
                                      		tmp = (sqrt((C + C)) / -t_0) * sqrt((t_0 * (F * 2.0)));
                                      	} else {
                                      		tmp = -sqrt(F) * sqrt((2.0 / B_m));
                                      	}
                                      	return tmp;
                                      }
                                      
                                      B_m = abs(B)
                                      A, B_m, C, F = sort([A, B_m, C, F])
                                      function code(A, B_m, C, F)
                                      	t_0 = fma(Float64(-4.0 * C), A, Float64(B_m * B_m))
                                      	tmp = 0.0
                                      	if ((B_m ^ 2.0) <= 1e+47)
                                      		tmp = Float64(Float64(sqrt(Float64(C + C)) / Float64(-t_0)) * sqrt(Float64(t_0 * Float64(F * 2.0))));
                                      	else
                                      		tmp = Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)));
                                      	end
                                      	return tmp
                                      end
                                      
                                      B_m = N[Abs[B], $MachinePrecision]
                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                      code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(-4.0 * C), $MachinePrecision] * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e+47], N[(N[(N[Sqrt[N[(C + C), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision] * N[Sqrt[N[(t$95$0 * N[(F * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]
                                      
                                      \begin{array}{l}
                                      B_m = \left|B\right|
                                      \\
                                      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                      \\
                                      \begin{array}{l}
                                      t_0 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\
                                      \mathbf{if}\;{B\_m}^{2} \leq 10^{+47}:\\
                                      \;\;\;\;\frac{\sqrt{C + C}}{-t\_0} \cdot \sqrt{t\_0 \cdot \left(F \cdot 2\right)}\\
                                      
                                      \mathbf{else}:\\
                                      \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\
                                      
                                      
                                      \end{array}
                                      \end{array}
                                      
                                      Derivation
                                      1. Split input into 2 regimes
                                      2. if (pow.f64 B #s(literal 2 binary64)) < 1e47

                                        1. Initial program 25.9%

                                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                        2. Add Preprocessing
                                        3. Applied rewrites39.1%

                                          \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                                        4. Taylor expanded in C around inf

                                          \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \left(1 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                        5. Step-by-step derivation
                                          1. lower-*.f64N/A

                                            \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \left(1 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                          2. +-commutativeN/A

                                            \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \color{blue}{\left(\left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right) + 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                          3. distribute-lft1-inN/A

                                            \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \left(\color{blue}{\left(-1 + 1\right) \cdot \frac{A}{C}} + 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                          4. metadata-evalN/A

                                            \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \left(\color{blue}{0} \cdot \frac{A}{C} + 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                          5. lower-fma.f64N/A

                                            \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \color{blue}{\mathsf{fma}\left(0, \frac{A}{C}, 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                          6. lower-/.f6420.6

                                            \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \mathsf{fma}\left(0, \color{blue}{\frac{A}{C}}, 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                        6. Applied rewrites20.6%

                                          \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                        7. Step-by-step derivation
                                          1. lift-*.f64N/A

                                            \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                                          2. *-commutativeN/A

                                            \[\leadsto \color{blue}{\frac{\sqrt{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1}} \]
                                          3. lower-*.f6420.6

                                            \[\leadsto \color{blue}{\frac{\sqrt{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \cdot \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1}} \]
                                        8. Applied rewrites24.8%

                                          \[\leadsto \color{blue}{\frac{\sqrt{C + C}}{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \left(-\sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)}\right)} \]

                                        if 1e47 < (pow.f64 B #s(literal 2 binary64))

                                        1. Initial program 11.7%

                                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                        2. Add Preprocessing
                                        3. Taylor expanded in B around inf

                                          \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                        4. Step-by-step derivation
                                          1. mul-1-negN/A

                                            \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                          2. lower-neg.f64N/A

                                            \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                          3. lower-*.f64N/A

                                            \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                          4. lower-sqrt.f64N/A

                                            \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                          5. lower-/.f64N/A

                                            \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                          6. lower-sqrt.f6427.9

                                            \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                        5. Applied rewrites27.9%

                                          \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                        6. Step-by-step derivation
                                          1. Applied rewrites28.1%

                                            \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                          2. Step-by-step derivation
                                            1. Applied rewrites34.5%

                                              \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                          3. Recombined 2 regimes into one program.
                                          4. Final simplification29.6%

                                            \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 10^{+47}:\\ \;\;\;\;\frac{\sqrt{C + C}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \cdot \sqrt{\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
                                          5. Add Preprocessing

                                          Alternative 8: 52.5% accurate, 2.7× speedup?

                                          \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 10^{+47}:\\ \;\;\;\;\frac{\sqrt{\left(C + C\right) \cdot \left(t\_0 \cdot \left(F \cdot 2\right)\right)}}{-t\_0}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
                                          B_m = (fabs.f64 B)
                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                          (FPCore (A B_m C F)
                                           :precision binary64
                                           (let* ((t_0 (fma (* -4.0 C) A (* B_m B_m))))
                                             (if (<= (pow B_m 2.0) 1e+47)
                                               (/ (sqrt (* (+ C C) (* t_0 (* F 2.0)))) (- t_0))
                                               (* (- (sqrt F)) (sqrt (/ 2.0 B_m))))))
                                          B_m = fabs(B);
                                          assert(A < B_m && B_m < C && C < F);
                                          double code(double A, double B_m, double C, double F) {
                                          	double t_0 = fma((-4.0 * C), A, (B_m * B_m));
                                          	double tmp;
                                          	if (pow(B_m, 2.0) <= 1e+47) {
                                          		tmp = sqrt(((C + C) * (t_0 * (F * 2.0)))) / -t_0;
                                          	} else {
                                          		tmp = -sqrt(F) * sqrt((2.0 / B_m));
                                          	}
                                          	return tmp;
                                          }
                                          
                                          B_m = abs(B)
                                          A, B_m, C, F = sort([A, B_m, C, F])
                                          function code(A, B_m, C, F)
                                          	t_0 = fma(Float64(-4.0 * C), A, Float64(B_m * B_m))
                                          	tmp = 0.0
                                          	if ((B_m ^ 2.0) <= 1e+47)
                                          		tmp = Float64(sqrt(Float64(Float64(C + C) * Float64(t_0 * Float64(F * 2.0)))) / Float64(-t_0));
                                          	else
                                          		tmp = Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)));
                                          	end
                                          	return tmp
                                          end
                                          
                                          B_m = N[Abs[B], $MachinePrecision]
                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                          code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(-4.0 * C), $MachinePrecision] * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 1e+47], N[(N[Sqrt[N[(N[(C + C), $MachinePrecision] * N[(t$95$0 * N[(F * 2.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]
                                          
                                          \begin{array}{l}
                                          B_m = \left|B\right|
                                          \\
                                          [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                          \\
                                          \begin{array}{l}
                                          t_0 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\
                                          \mathbf{if}\;{B\_m}^{2} \leq 10^{+47}:\\
                                          \;\;\;\;\frac{\sqrt{\left(C + C\right) \cdot \left(t\_0 \cdot \left(F \cdot 2\right)\right)}}{-t\_0}\\
                                          
                                          \mathbf{else}:\\
                                          \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\
                                          
                                          
                                          \end{array}
                                          \end{array}
                                          
                                          Derivation
                                          1. Split input into 2 regimes
                                          2. if (pow.f64 B #s(literal 2 binary64)) < 1e47

                                            1. Initial program 25.9%

                                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            2. Add Preprocessing
                                            3. Applied rewrites39.1%

                                              \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                                            4. Taylor expanded in C around inf

                                              \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \left(1 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                            5. Step-by-step derivation
                                              1. lower-*.f64N/A

                                                \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \left(1 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                              2. +-commutativeN/A

                                                \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \color{blue}{\left(\left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right) + 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                              3. distribute-lft1-inN/A

                                                \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \left(\color{blue}{\left(-1 + 1\right) \cdot \frac{A}{C}} + 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                              4. metadata-evalN/A

                                                \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \left(\color{blue}{0} \cdot \frac{A}{C} + 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                              5. lower-fma.f64N/A

                                                \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \color{blue}{\mathsf{fma}\left(0, \frac{A}{C}, 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                              6. lower-/.f6420.6

                                                \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \mathsf{fma}\left(0, \color{blue}{\frac{A}{C}}, 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                            6. Applied rewrites20.6%

                                              \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                            7. Applied rewrites23.3%

                                              \[\leadsto \color{blue}{\frac{\sqrt{\left(C + C\right) \cdot \left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}} \]

                                            if 1e47 < (pow.f64 B #s(literal 2 binary64))

                                            1. Initial program 11.7%

                                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                            2. Add Preprocessing
                                            3. Taylor expanded in B around inf

                                              \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                            4. Step-by-step derivation
                                              1. mul-1-negN/A

                                                \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                              2. lower-neg.f64N/A

                                                \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                              3. lower-*.f64N/A

                                                \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                              4. lower-sqrt.f64N/A

                                                \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                              5. lower-/.f64N/A

                                                \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                              6. lower-sqrt.f6427.9

                                                \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                            5. Applied rewrites27.9%

                                              \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                            6. Step-by-step derivation
                                              1. Applied rewrites28.1%

                                                \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                              2. Step-by-step derivation
                                                1. Applied rewrites34.5%

                                                  \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                              3. Recombined 2 regimes into one program.
                                              4. Final simplification28.9%

                                                \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 10^{+47}:\\ \;\;\;\;\frac{\sqrt{\left(C + C\right) \cdot \left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
                                              5. Add Preprocessing

                                              Alternative 9: 44.4% accurate, 2.9× speedup?

                                              \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;{B\_m}^{2} \leq 5 \cdot 10^{-35}:\\ \;\;\;\;\frac{\sqrt{-16 \cdot \left(A \cdot \left(\left(C \cdot C\right) \cdot F\right)\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
                                              B_m = (fabs.f64 B)
                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                              (FPCore (A B_m C F)
                                               :precision binary64
                                               (if (<= (pow B_m 2.0) 5e-35)
                                                 (/ (sqrt (* -16.0 (* A (* (* C C) F)))) (- (fma (* -4.0 C) A (* B_m B_m))))
                                                 (* (- (sqrt F)) (sqrt (/ 2.0 B_m)))))
                                              B_m = fabs(B);
                                              assert(A < B_m && B_m < C && C < F);
                                              double code(double A, double B_m, double C, double F) {
                                              	double tmp;
                                              	if (pow(B_m, 2.0) <= 5e-35) {
                                              		tmp = sqrt((-16.0 * (A * ((C * C) * F)))) / -fma((-4.0 * C), A, (B_m * B_m));
                                              	} else {
                                              		tmp = -sqrt(F) * sqrt((2.0 / B_m));
                                              	}
                                              	return tmp;
                                              }
                                              
                                              B_m = abs(B)
                                              A, B_m, C, F = sort([A, B_m, C, F])
                                              function code(A, B_m, C, F)
                                              	tmp = 0.0
                                              	if ((B_m ^ 2.0) <= 5e-35)
                                              		tmp = Float64(sqrt(Float64(-16.0 * Float64(A * Float64(Float64(C * C) * F)))) / Float64(-fma(Float64(-4.0 * C), A, Float64(B_m * B_m))));
                                              	else
                                              		tmp = Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)));
                                              	end
                                              	return tmp
                                              end
                                              
                                              B_m = N[Abs[B], $MachinePrecision]
                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                              code[A_, B$95$m_, C_, F_] := If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 5e-35], N[(N[Sqrt[N[(-16.0 * N[(A * N[(N[(C * C), $MachinePrecision] * F), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-N[(N[(-4.0 * C), $MachinePrecision] * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision])), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]
                                              
                                              \begin{array}{l}
                                              B_m = \left|B\right|
                                              \\
                                              [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                              \\
                                              \begin{array}{l}
                                              \mathbf{if}\;{B\_m}^{2} \leq 5 \cdot 10^{-35}:\\
                                              \;\;\;\;\frac{\sqrt{-16 \cdot \left(A \cdot \left(\left(C \cdot C\right) \cdot F\right)\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)}\\
                                              
                                              \mathbf{else}:\\
                                              \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\
                                              
                                              
                                              \end{array}
                                              \end{array}
                                              
                                              Derivation
                                              1. Split input into 2 regimes
                                              2. if (pow.f64 B #s(literal 2 binary64)) < 4.99999999999999964e-35

                                                1. Initial program 23.7%

                                                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                2. Add Preprocessing
                                                3. Applied rewrites38.0%

                                                  \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                                                4. Taylor expanded in C around inf

                                                  \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \left(1 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                5. Step-by-step derivation
                                                  1. lower-*.f64N/A

                                                    \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \left(1 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                  2. +-commutativeN/A

                                                    \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \color{blue}{\left(\left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right) + 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                  3. distribute-lft1-inN/A

                                                    \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \left(\color{blue}{\left(-1 + 1\right) \cdot \frac{A}{C}} + 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                  4. metadata-evalN/A

                                                    \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \left(\color{blue}{0} \cdot \frac{A}{C} + 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                  5. lower-fma.f64N/A

                                                    \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \color{blue}{\mathsf{fma}\left(0, \frac{A}{C}, 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                  6. lower-/.f6419.4

                                                    \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \mathsf{fma}\left(0, \color{blue}{\frac{A}{C}}, 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                6. Applied rewrites19.4%

                                                  \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                7. Applied rewrites21.4%

                                                  \[\leadsto \color{blue}{\frac{\sqrt{\left(C + C\right) \cdot \left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}} \]
                                                8. Taylor expanded in A around -inf

                                                  \[\leadsto \frac{\sqrt{\color{blue}{-16 \cdot \left(A \cdot \left({C}^{2} \cdot F\right)\right)}}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                                9. Step-by-step derivation
                                                  1. lower-*.f64N/A

                                                    \[\leadsto \frac{\sqrt{\color{blue}{-16 \cdot \left(A \cdot \left({C}^{2} \cdot F\right)\right)}}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                                  2. lower-*.f64N/A

                                                    \[\leadsto \frac{\sqrt{-16 \cdot \color{blue}{\left(A \cdot \left({C}^{2} \cdot F\right)\right)}}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                                  3. lower-*.f64N/A

                                                    \[\leadsto \frac{\sqrt{-16 \cdot \left(A \cdot \color{blue}{\left({C}^{2} \cdot F\right)}\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                                  4. unpow2N/A

                                                    \[\leadsto \frac{\sqrt{-16 \cdot \left(A \cdot \left(\color{blue}{\left(C \cdot C\right)} \cdot F\right)\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                                  5. lower-*.f6413.5

                                                    \[\leadsto \frac{\sqrt{-16 \cdot \left(A \cdot \left(\color{blue}{\left(C \cdot C\right)} \cdot F\right)\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                                10. Applied rewrites13.5%

                                                  \[\leadsto \frac{\sqrt{\color{blue}{-16 \cdot \left(A \cdot \left(\left(C \cdot C\right) \cdot F\right)\right)}}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]

                                                if 4.99999999999999964e-35 < (pow.f64 B #s(literal 2 binary64))

                                                1. Initial program 15.1%

                                                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                2. Add Preprocessing
                                                3. Taylor expanded in B around inf

                                                  \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                4. Step-by-step derivation
                                                  1. mul-1-negN/A

                                                    \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                  2. lower-neg.f64N/A

                                                    \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                  3. lower-*.f64N/A

                                                    \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                  4. lower-sqrt.f64N/A

                                                    \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                  5. lower-/.f64N/A

                                                    \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                  6. lower-sqrt.f6425.1

                                                    \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                5. Applied rewrites25.1%

                                                  \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                6. Step-by-step derivation
                                                  1. Applied rewrites25.3%

                                                    \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                  2. Step-by-step derivation
                                                    1. Applied rewrites30.9%

                                                      \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                                  3. Recombined 2 regimes into one program.
                                                  4. Final simplification23.5%

                                                    \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 5 \cdot 10^{-35}:\\ \;\;\;\;\frac{\sqrt{-16 \cdot \left(A \cdot \left(\left(C \cdot C\right) \cdot F\right)\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
                                                  5. Add Preprocessing

                                                  Alternative 10: 51.5% accurate, 5.7× speedup?

                                                  \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\ \mathbf{if}\;B\_m \leq 2 \cdot 10^{-104}:\\ \;\;\;\;\frac{\sqrt{\left(C + C\right) \cdot \left(t\_0 \cdot \left(F \cdot 2\right)\right)}}{\left(4 \cdot A\right) \cdot C}\\ \mathbf{elif}\;B\_m \leq 7 \cdot 10^{+25}:\\ \;\;\;\;\frac{\sqrt{\left(t\_0 \cdot \left(C + C\right)\right) \cdot \left(F \cdot 2\right)}}{-t\_0}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
                                                  B_m = (fabs.f64 B)
                                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                  (FPCore (A B_m C F)
                                                   :precision binary64
                                                   (let* ((t_0 (fma (* -4.0 C) A (* B_m B_m))))
                                                     (if (<= B_m 2e-104)
                                                       (/ (sqrt (* (+ C C) (* t_0 (* F 2.0)))) (* (* 4.0 A) C))
                                                       (if (<= B_m 7e+25)
                                                         (/ (sqrt (* (* t_0 (+ C C)) (* F 2.0))) (- t_0))
                                                         (* (- (sqrt F)) (sqrt (/ 2.0 B_m)))))))
                                                  B_m = fabs(B);
                                                  assert(A < B_m && B_m < C && C < F);
                                                  double code(double A, double B_m, double C, double F) {
                                                  	double t_0 = fma((-4.0 * C), A, (B_m * B_m));
                                                  	double tmp;
                                                  	if (B_m <= 2e-104) {
                                                  		tmp = sqrt(((C + C) * (t_0 * (F * 2.0)))) / ((4.0 * A) * C);
                                                  	} else if (B_m <= 7e+25) {
                                                  		tmp = sqrt(((t_0 * (C + C)) * (F * 2.0))) / -t_0;
                                                  	} else {
                                                  		tmp = -sqrt(F) * sqrt((2.0 / B_m));
                                                  	}
                                                  	return tmp;
                                                  }
                                                  
                                                  B_m = abs(B)
                                                  A, B_m, C, F = sort([A, B_m, C, F])
                                                  function code(A, B_m, C, F)
                                                  	t_0 = fma(Float64(-4.0 * C), A, Float64(B_m * B_m))
                                                  	tmp = 0.0
                                                  	if (B_m <= 2e-104)
                                                  		tmp = Float64(sqrt(Float64(Float64(C + C) * Float64(t_0 * Float64(F * 2.0)))) / Float64(Float64(4.0 * A) * C));
                                                  	elseif (B_m <= 7e+25)
                                                  		tmp = Float64(sqrt(Float64(Float64(t_0 * Float64(C + C)) * Float64(F * 2.0))) / Float64(-t_0));
                                                  	else
                                                  		tmp = Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)));
                                                  	end
                                                  	return tmp
                                                  end
                                                  
                                                  B_m = N[Abs[B], $MachinePrecision]
                                                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                  code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(-4.0 * C), $MachinePrecision] * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[B$95$m, 2e-104], N[(N[Sqrt[N[(N[(C + C), $MachinePrecision] * N[(t$95$0 * N[(F * 2.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision], If[LessEqual[B$95$m, 7e+25], N[(N[Sqrt[N[(N[(t$95$0 * N[(C + C), $MachinePrecision]), $MachinePrecision] * N[(F * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]]
                                                  
                                                  \begin{array}{l}
                                                  B_m = \left|B\right|
                                                  \\
                                                  [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                  \\
                                                  \begin{array}{l}
                                                  t_0 := \mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right)\\
                                                  \mathbf{if}\;B\_m \leq 2 \cdot 10^{-104}:\\
                                                  \;\;\;\;\frac{\sqrt{\left(C + C\right) \cdot \left(t\_0 \cdot \left(F \cdot 2\right)\right)}}{\left(4 \cdot A\right) \cdot C}\\
                                                  
                                                  \mathbf{elif}\;B\_m \leq 7 \cdot 10^{+25}:\\
                                                  \;\;\;\;\frac{\sqrt{\left(t\_0 \cdot \left(C + C\right)\right) \cdot \left(F \cdot 2\right)}}{-t\_0}\\
                                                  
                                                  \mathbf{else}:\\
                                                  \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\
                                                  
                                                  
                                                  \end{array}
                                                  \end{array}
                                                  
                                                  Derivation
                                                  1. Split input into 3 regimes
                                                  2. if B < 1.99999999999999985e-104

                                                    1. Initial program 17.4%

                                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                    2. Add Preprocessing
                                                    3. Applied rewrites28.0%

                                                      \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                                                    4. Taylor expanded in C around inf

                                                      \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \left(1 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                    5. Step-by-step derivation
                                                      1. lower-*.f64N/A

                                                        \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \left(1 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                      2. +-commutativeN/A

                                                        \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \color{blue}{\left(\left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right) + 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                      3. distribute-lft1-inN/A

                                                        \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \left(\color{blue}{\left(-1 + 1\right) \cdot \frac{A}{C}} + 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                      4. metadata-evalN/A

                                                        \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \left(\color{blue}{0} \cdot \frac{A}{C} + 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                      5. lower-fma.f64N/A

                                                        \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \color{blue}{\mathsf{fma}\left(0, \frac{A}{C}, 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                      6. lower-/.f6414.1

                                                        \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \mathsf{fma}\left(0, \color{blue}{\frac{A}{C}}, 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                    6. Applied rewrites14.1%

                                                      \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                    7. Applied rewrites16.3%

                                                      \[\leadsto \color{blue}{\frac{\sqrt{\left(C + C\right) \cdot \left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}} \]
                                                    8. Taylor expanded in A around inf

                                                      \[\leadsto \frac{\sqrt{\left(C + C\right) \cdot \left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)\right)}}{\color{blue}{4 \cdot \left(A \cdot C\right)}} \]
                                                    9. Step-by-step derivation
                                                      1. associate-*r*N/A

                                                        \[\leadsto \frac{\sqrt{\left(C + C\right) \cdot \left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)\right)}}{\color{blue}{\left(4 \cdot A\right) \cdot C}} \]
                                                      2. lower-*.f64N/A

                                                        \[\leadsto \frac{\sqrt{\left(C + C\right) \cdot \left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)\right)}}{\color{blue}{\left(4 \cdot A\right) \cdot C}} \]
                                                      3. lower-*.f6411.6

                                                        \[\leadsto \frac{\sqrt{\left(C + C\right) \cdot \left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)\right)}}{\color{blue}{\left(4 \cdot A\right)} \cdot C} \]
                                                    10. Applied rewrites11.6%

                                                      \[\leadsto \frac{\sqrt{\left(C + C\right) \cdot \left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)\right)}}{\color{blue}{\left(4 \cdot A\right) \cdot C}} \]

                                                    if 1.99999999999999985e-104 < B < 6.99999999999999999e25

                                                    1. Initial program 40.2%

                                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                    2. Add Preprocessing
                                                    3. Applied rewrites48.7%

                                                      \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                                                    4. Taylor expanded in C around inf

                                                      \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \left(1 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                    5. Step-by-step derivation
                                                      1. lower-*.f64N/A

                                                        \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \left(1 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                      2. +-commutativeN/A

                                                        \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \color{blue}{\left(\left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right) + 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                      3. distribute-lft1-inN/A

                                                        \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \left(\color{blue}{\left(-1 + 1\right) \cdot \frac{A}{C}} + 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                      4. metadata-evalN/A

                                                        \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \left(\color{blue}{0} \cdot \frac{A}{C} + 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                      5. lower-fma.f64N/A

                                                        \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \color{blue}{\mathsf{fma}\left(0, \frac{A}{C}, 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                      6. lower-/.f6420.0

                                                        \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \mathsf{fma}\left(0, \color{blue}{\frac{A}{C}}, 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                    6. Applied rewrites20.0%

                                                      \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                    7. Applied rewrites20.4%

                                                      \[\leadsto \color{blue}{\frac{\sqrt{\left(C + C\right) \cdot \left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}} \]
                                                    8. Step-by-step derivation
                                                      1. lift-*.f64N/A

                                                        \[\leadsto \frac{\sqrt{\color{blue}{\left(C + C\right) \cdot \left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)\right)}}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                                      2. lift-*.f64N/A

                                                        \[\leadsto \frac{\sqrt{\left(C + C\right) \cdot \color{blue}{\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)\right)}}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                                      3. associate-*r*N/A

                                                        \[\leadsto \frac{\sqrt{\color{blue}{\left(\left(C + C\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)\right) \cdot \left(F \cdot 2\right)}}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                                      4. lower-*.f64N/A

                                                        \[\leadsto \frac{\sqrt{\color{blue}{\left(\left(C + C\right) \cdot \mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)\right) \cdot \left(F \cdot 2\right)}}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                                      5. *-commutativeN/A

                                                        \[\leadsto \frac{\sqrt{\color{blue}{\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(C + C\right)\right)} \cdot \left(F \cdot 2\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                                      6. lower-*.f6423.7

                                                        \[\leadsto \frac{\sqrt{\color{blue}{\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(C + C\right)\right)} \cdot \left(F \cdot 2\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]
                                                    9. Applied rewrites23.7%

                                                      \[\leadsto \frac{\sqrt{\color{blue}{\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(C + C\right)\right) \cdot \left(F \cdot 2\right)}}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)} \]

                                                    if 6.99999999999999999e25 < B

                                                    1. Initial program 13.1%

                                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                    2. Add Preprocessing
                                                    3. Taylor expanded in B around inf

                                                      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                    4. Step-by-step derivation
                                                      1. mul-1-negN/A

                                                        \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                      2. lower-neg.f64N/A

                                                        \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                      3. lower-*.f64N/A

                                                        \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                      4. lower-sqrt.f64N/A

                                                        \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                      5. lower-/.f64N/A

                                                        \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                      6. lower-sqrt.f6454.7

                                                        \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                    5. Applied rewrites54.7%

                                                      \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                    6. Step-by-step derivation
                                                      1. Applied rewrites55.0%

                                                        \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                      2. Step-by-step derivation
                                                        1. Applied rewrites69.1%

                                                          \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                                      3. Recombined 3 regimes into one program.
                                                      4. Final simplification27.3%

                                                        \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 2 \cdot 10^{-104}:\\ \;\;\;\;\frac{\sqrt{\left(C + C\right) \cdot \left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)\right)}}{\left(4 \cdot A\right) \cdot C}\\ \mathbf{elif}\;B \leq 7 \cdot 10^{+25}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(C + C\right)\right) \cdot \left(F \cdot 2\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
                                                      5. Add Preprocessing

                                                      Alternative 11: 50.6% accurate, 6.8× speedup?

                                                      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;B\_m \leq 6.2 \cdot 10^{+23}:\\ \;\;\;\;\frac{\sqrt{\left(C + C\right) \cdot \left(\mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right) \cdot \left(F \cdot 2\right)\right)}}{\left(4 \cdot A\right) \cdot C}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
                                                      B_m = (fabs.f64 B)
                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                      (FPCore (A B_m C F)
                                                       :precision binary64
                                                       (if (<= B_m 6.2e+23)
                                                         (/
                                                          (sqrt (* (+ C C) (* (fma (* -4.0 C) A (* B_m B_m)) (* F 2.0))))
                                                          (* (* 4.0 A) C))
                                                         (* (- (sqrt F)) (sqrt (/ 2.0 B_m)))))
                                                      B_m = fabs(B);
                                                      assert(A < B_m && B_m < C && C < F);
                                                      double code(double A, double B_m, double C, double F) {
                                                      	double tmp;
                                                      	if (B_m <= 6.2e+23) {
                                                      		tmp = sqrt(((C + C) * (fma((-4.0 * C), A, (B_m * B_m)) * (F * 2.0)))) / ((4.0 * A) * C);
                                                      	} else {
                                                      		tmp = -sqrt(F) * sqrt((2.0 / B_m));
                                                      	}
                                                      	return tmp;
                                                      }
                                                      
                                                      B_m = abs(B)
                                                      A, B_m, C, F = sort([A, B_m, C, F])
                                                      function code(A, B_m, C, F)
                                                      	tmp = 0.0
                                                      	if (B_m <= 6.2e+23)
                                                      		tmp = Float64(sqrt(Float64(Float64(C + C) * Float64(fma(Float64(-4.0 * C), A, Float64(B_m * B_m)) * Float64(F * 2.0)))) / Float64(Float64(4.0 * A) * C));
                                                      	else
                                                      		tmp = Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)));
                                                      	end
                                                      	return tmp
                                                      end
                                                      
                                                      B_m = N[Abs[B], $MachinePrecision]
                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                      code[A_, B$95$m_, C_, F_] := If[LessEqual[B$95$m, 6.2e+23], N[(N[Sqrt[N[(N[(C + C), $MachinePrecision] * N[(N[(N[(-4.0 * C), $MachinePrecision] * A + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision] * N[(F * 2.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision], N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]
                                                      
                                                      \begin{array}{l}
                                                      B_m = \left|B\right|
                                                      \\
                                                      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                      \\
                                                      \begin{array}{l}
                                                      \mathbf{if}\;B\_m \leq 6.2 \cdot 10^{+23}:\\
                                                      \;\;\;\;\frac{\sqrt{\left(C + C\right) \cdot \left(\mathsf{fma}\left(-4 \cdot C, A, B\_m \cdot B\_m\right) \cdot \left(F \cdot 2\right)\right)}}{\left(4 \cdot A\right) \cdot C}\\
                                                      
                                                      \mathbf{else}:\\
                                                      \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\
                                                      
                                                      
                                                      \end{array}
                                                      \end{array}
                                                      
                                                      Derivation
                                                      1. Split input into 2 regimes
                                                      2. if B < 6.19999999999999941e23

                                                        1. Initial program 20.7%

                                                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                        2. Add Preprocessing
                                                        3. Applied rewrites31.0%

                                                          \[\leadsto \color{blue}{\frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}} \]
                                                        4. Taylor expanded in C around inf

                                                          \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \left(1 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                        5. Step-by-step derivation
                                                          1. lower-*.f64N/A

                                                            \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \left(1 + \left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right)\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                          2. +-commutativeN/A

                                                            \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \color{blue}{\left(\left(-1 \cdot \frac{A}{C} + \frac{A}{C}\right) + 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                          3. distribute-lft1-inN/A

                                                            \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \left(\color{blue}{\left(-1 + 1\right) \cdot \frac{A}{C}} + 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                          4. metadata-evalN/A

                                                            \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \left(\color{blue}{0} \cdot \frac{A}{C} + 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                          5. lower-fma.f64N/A

                                                            \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \color{blue}{\mathsf{fma}\left(0, \frac{A}{C}, 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                          6. lower-/.f6415.0

                                                            \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{C \cdot \mathsf{fma}\left(0, \color{blue}{\frac{A}{C}}, 1\right) + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                        6. Applied rewrites15.0%

                                                          \[\leadsto \frac{\sqrt{\left(2 \cdot F\right) \cdot \mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}{-1} \cdot \frac{\sqrt{\color{blue}{C \cdot \mathsf{fma}\left(0, \frac{A}{C}, 1\right)} + C}}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)} \]
                                                        7. Applied rewrites16.9%

                                                          \[\leadsto \color{blue}{\frac{\sqrt{\left(C + C\right) \cdot \left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)\right)}}{-\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right)}} \]
                                                        8. Taylor expanded in A around inf

                                                          \[\leadsto \frac{\sqrt{\left(C + C\right) \cdot \left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)\right)}}{\color{blue}{4 \cdot \left(A \cdot C\right)}} \]
                                                        9. Step-by-step derivation
                                                          1. associate-*r*N/A

                                                            \[\leadsto \frac{\sqrt{\left(C + C\right) \cdot \left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)\right)}}{\color{blue}{\left(4 \cdot A\right) \cdot C}} \]
                                                          2. lower-*.f64N/A

                                                            \[\leadsto \frac{\sqrt{\left(C + C\right) \cdot \left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)\right)}}{\color{blue}{\left(4 \cdot A\right) \cdot C}} \]
                                                          3. lower-*.f6412.7

                                                            \[\leadsto \frac{\sqrt{\left(C + C\right) \cdot \left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)\right)}}{\color{blue}{\left(4 \cdot A\right)} \cdot C} \]
                                                        10. Applied rewrites12.7%

                                                          \[\leadsto \frac{\sqrt{\left(C + C\right) \cdot \left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)\right)}}{\color{blue}{\left(4 \cdot A\right) \cdot C}} \]

                                                        if 6.19999999999999941e23 < B

                                                        1. Initial program 13.1%

                                                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                        2. Add Preprocessing
                                                        3. Taylor expanded in B around inf

                                                          \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                        4. Step-by-step derivation
                                                          1. mul-1-negN/A

                                                            \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                          2. lower-neg.f64N/A

                                                            \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                          3. lower-*.f64N/A

                                                            \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                          4. lower-sqrt.f64N/A

                                                            \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                          5. lower-/.f64N/A

                                                            \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                          6. lower-sqrt.f6454.7

                                                            \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                        5. Applied rewrites54.7%

                                                          \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                        6. Step-by-step derivation
                                                          1. Applied rewrites55.0%

                                                            \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                          2. Step-by-step derivation
                                                            1. Applied rewrites69.1%

                                                              \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                                          3. Recombined 2 regimes into one program.
                                                          4. Final simplification26.8%

                                                            \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 6.2 \cdot 10^{+23}:\\ \;\;\;\;\frac{\sqrt{\left(C + C\right) \cdot \left(\mathsf{fma}\left(-4 \cdot C, A, B \cdot B\right) \cdot \left(F \cdot 2\right)\right)}}{\left(4 \cdot A\right) \cdot C}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
                                                          5. Add Preprocessing

                                                          Alternative 12: 27.3% accurate, 12.3× speedup?

                                                          \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;F \leq 1.65 \cdot 10^{-254}:\\ \;\;\;\;\frac{2}{-B\_m} \cdot \sqrt{C \cdot F}\\ \mathbf{else}:\\ \;\;\;\;-\sqrt{\frac{F}{B\_m} \cdot 2}\\ \end{array} \end{array} \]
                                                          B_m = (fabs.f64 B)
                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                          (FPCore (A B_m C F)
                                                           :precision binary64
                                                           (if (<= F 1.65e-254)
                                                             (* (/ 2.0 (- B_m)) (sqrt (* C F)))
                                                             (- (sqrt (* (/ F B_m) 2.0)))))
                                                          B_m = fabs(B);
                                                          assert(A < B_m && B_m < C && C < F);
                                                          double code(double A, double B_m, double C, double F) {
                                                          	double tmp;
                                                          	if (F <= 1.65e-254) {
                                                          		tmp = (2.0 / -B_m) * sqrt((C * F));
                                                          	} else {
                                                          		tmp = -sqrt(((F / B_m) * 2.0));
                                                          	}
                                                          	return tmp;
                                                          }
                                                          
                                                          B_m = abs(b)
                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                          real(8) function code(a, b_m, c, f)
                                                              real(8), intent (in) :: a
                                                              real(8), intent (in) :: b_m
                                                              real(8), intent (in) :: c
                                                              real(8), intent (in) :: f
                                                              real(8) :: tmp
                                                              if (f <= 1.65d-254) then
                                                                  tmp = (2.0d0 / -b_m) * sqrt((c * f))
                                                              else
                                                                  tmp = -sqrt(((f / b_m) * 2.0d0))
                                                              end if
                                                              code = tmp
                                                          end function
                                                          
                                                          B_m = Math.abs(B);
                                                          assert A < B_m && B_m < C && C < F;
                                                          public static double code(double A, double B_m, double C, double F) {
                                                          	double tmp;
                                                          	if (F <= 1.65e-254) {
                                                          		tmp = (2.0 / -B_m) * Math.sqrt((C * F));
                                                          	} else {
                                                          		tmp = -Math.sqrt(((F / B_m) * 2.0));
                                                          	}
                                                          	return tmp;
                                                          }
                                                          
                                                          B_m = math.fabs(B)
                                                          [A, B_m, C, F] = sort([A, B_m, C, F])
                                                          def code(A, B_m, C, F):
                                                          	tmp = 0
                                                          	if F <= 1.65e-254:
                                                          		tmp = (2.0 / -B_m) * math.sqrt((C * F))
                                                          	else:
                                                          		tmp = -math.sqrt(((F / B_m) * 2.0))
                                                          	return tmp
                                                          
                                                          B_m = abs(B)
                                                          A, B_m, C, F = sort([A, B_m, C, F])
                                                          function code(A, B_m, C, F)
                                                          	tmp = 0.0
                                                          	if (F <= 1.65e-254)
                                                          		tmp = Float64(Float64(2.0 / Float64(-B_m)) * sqrt(Float64(C * F)));
                                                          	else
                                                          		tmp = Float64(-sqrt(Float64(Float64(F / B_m) * 2.0)));
                                                          	end
                                                          	return tmp
                                                          end
                                                          
                                                          B_m = abs(B);
                                                          A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                          function tmp_2 = code(A, B_m, C, F)
                                                          	tmp = 0.0;
                                                          	if (F <= 1.65e-254)
                                                          		tmp = (2.0 / -B_m) * sqrt((C * F));
                                                          	else
                                                          		tmp = -sqrt(((F / B_m) * 2.0));
                                                          	end
                                                          	tmp_2 = tmp;
                                                          end
                                                          
                                                          B_m = N[Abs[B], $MachinePrecision]
                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                          code[A_, B$95$m_, C_, F_] := If[LessEqual[F, 1.65e-254], N[(N[(2.0 / (-B$95$m)), $MachinePrecision] * N[Sqrt[N[(C * F), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], (-N[Sqrt[N[(N[(F / B$95$m), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision])]
                                                          
                                                          \begin{array}{l}
                                                          B_m = \left|B\right|
                                                          \\
                                                          [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                          \\
                                                          \begin{array}{l}
                                                          \mathbf{if}\;F \leq 1.65 \cdot 10^{-254}:\\
                                                          \;\;\;\;\frac{2}{-B\_m} \cdot \sqrt{C \cdot F}\\
                                                          
                                                          \mathbf{else}:\\
                                                          \;\;\;\;-\sqrt{\frac{F}{B\_m} \cdot 2}\\
                                                          
                                                          
                                                          \end{array}
                                                          \end{array}
                                                          
                                                          Derivation
                                                          1. Split input into 2 regimes
                                                          2. if F < 1.65000000000000008e-254

                                                            1. Initial program 31.2%

                                                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                            2. Add Preprocessing
                                                            3. Taylor expanded in A around 0

                                                              \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                                                            4. Step-by-step derivation
                                                              1. associate-*r*N/A

                                                                \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                              2. lower-*.f64N/A

                                                                \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                              3. mul-1-negN/A

                                                                \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                              4. lower-neg.f64N/A

                                                                \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                              5. lower-/.f64N/A

                                                                \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                              6. lower-sqrt.f64N/A

                                                                \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                                                              7. lower-sqrt.f64N/A

                                                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                                                              8. *-commutativeN/A

                                                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                              9. lower-*.f64N/A

                                                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                                                              10. +-commutativeN/A

                                                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                              11. lower-+.f64N/A

                                                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                                                              12. +-commutativeN/A

                                                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                                                              13. unpow2N/A

                                                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                                                              14. unpow2N/A

                                                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                                                              15. lower-hypot.f648.5

                                                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                                                            5. Applied rewrites8.5%

                                                              \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                                                            6. Step-by-step derivation
                                                              1. Applied rewrites8.2%

                                                                \[\leadsto \left(\frac{\sqrt{2}}{-B} \cdot \sqrt{\mathsf{hypot}\left(C, B\right) + C}\right) \cdot \color{blue}{\sqrt{F}} \]
                                                              2. Taylor expanded in B around 0

                                                                \[\leadsto -1 \cdot \color{blue}{\left(\frac{{\left(\sqrt{2}\right)}^{2}}{B} \cdot \sqrt{C \cdot F}\right)} \]
                                                              3. Step-by-step derivation
                                                                1. Applied rewrites3.6%

                                                                  \[\leadsto -\frac{2}{B} \cdot \sqrt{C \cdot F} \]

                                                                if 1.65000000000000008e-254 < F

                                                                1. Initial program 16.1%

                                                                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                2. Add Preprocessing
                                                                3. Taylor expanded in B around inf

                                                                  \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                4. Step-by-step derivation
                                                                  1. mul-1-negN/A

                                                                    \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                  2. lower-neg.f64N/A

                                                                    \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                  3. lower-*.f64N/A

                                                                    \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                  4. lower-sqrt.f64N/A

                                                                    \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                  5. lower-/.f64N/A

                                                                    \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                  6. lower-sqrt.f6419.9

                                                                    \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                                5. Applied rewrites19.9%

                                                                  \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                6. Step-by-step derivation
                                                                  1. Applied rewrites20.0%

                                                                    \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                7. Recombined 2 regimes into one program.
                                                                8. Final simplification17.1%

                                                                  \[\leadsto \begin{array}{l} \mathbf{if}\;F \leq 1.65 \cdot 10^{-254}:\\ \;\;\;\;\frac{2}{-B} \cdot \sqrt{C \cdot F}\\ \mathbf{else}:\\ \;\;\;\;-\sqrt{\frac{F}{B} \cdot 2}\\ \end{array} \]
                                                                9. Add Preprocessing

                                                                Alternative 13: 35.3% accurate, 12.6× speedup?

                                                                \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \frac{-\sqrt{F}}{\sqrt{B\_m \cdot 0.5}} \end{array} \]
                                                                B_m = (fabs.f64 B)
                                                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                (FPCore (A B_m C F) :precision binary64 (/ (- (sqrt F)) (sqrt (* B_m 0.5))))
                                                                B_m = fabs(B);
                                                                assert(A < B_m && B_m < C && C < F);
                                                                double code(double A, double B_m, double C, double F) {
                                                                	return -sqrt(F) / sqrt((B_m * 0.5));
                                                                }
                                                                
                                                                B_m = abs(b)
                                                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                real(8) function code(a, b_m, c, f)
                                                                    real(8), intent (in) :: a
                                                                    real(8), intent (in) :: b_m
                                                                    real(8), intent (in) :: c
                                                                    real(8), intent (in) :: f
                                                                    code = -sqrt(f) / sqrt((b_m * 0.5d0))
                                                                end function
                                                                
                                                                B_m = Math.abs(B);
                                                                assert A < B_m && B_m < C && C < F;
                                                                public static double code(double A, double B_m, double C, double F) {
                                                                	return -Math.sqrt(F) / Math.sqrt((B_m * 0.5));
                                                                }
                                                                
                                                                B_m = math.fabs(B)
                                                                [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                def code(A, B_m, C, F):
                                                                	return -math.sqrt(F) / math.sqrt((B_m * 0.5))
                                                                
                                                                B_m = abs(B)
                                                                A, B_m, C, F = sort([A, B_m, C, F])
                                                                function code(A, B_m, C, F)
                                                                	return Float64(Float64(-sqrt(F)) / sqrt(Float64(B_m * 0.5)))
                                                                end
                                                                
                                                                B_m = abs(B);
                                                                A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                function tmp = code(A, B_m, C, F)
                                                                	tmp = -sqrt(F) / sqrt((B_m * 0.5));
                                                                end
                                                                
                                                                B_m = N[Abs[B], $MachinePrecision]
                                                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                code[A_, B$95$m_, C_, F_] := N[((-N[Sqrt[F], $MachinePrecision]) / N[Sqrt[N[(B$95$m * 0.5), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
                                                                
                                                                \begin{array}{l}
                                                                B_m = \left|B\right|
                                                                \\
                                                                [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                \\
                                                                \frac{-\sqrt{F}}{\sqrt{B\_m \cdot 0.5}}
                                                                \end{array}
                                                                
                                                                Derivation
                                                                1. Initial program 18.8%

                                                                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                2. Add Preprocessing
                                                                3. Taylor expanded in B around inf

                                                                  \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                4. Step-by-step derivation
                                                                  1. mul-1-negN/A

                                                                    \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                  2. lower-neg.f64N/A

                                                                    \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                  3. lower-*.f64N/A

                                                                    \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                  4. lower-sqrt.f64N/A

                                                                    \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                  5. lower-/.f64N/A

                                                                    \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                  6. lower-sqrt.f6416.6

                                                                    \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                                5. Applied rewrites16.6%

                                                                  \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                6. Step-by-step derivation
                                                                  1. Applied rewrites16.7%

                                                                    \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                  2. Step-by-step derivation
                                                                    1. Applied rewrites16.7%

                                                                      \[\leadsto -\sqrt{F \cdot \frac{2}{B}} \]
                                                                    2. Step-by-step derivation
                                                                      1. Applied rewrites20.7%

                                                                        \[\leadsto -\frac{\sqrt{F}}{\sqrt{B \cdot 0.5}} \]
                                                                      2. Final simplification20.7%

                                                                        \[\leadsto \frac{-\sqrt{F}}{\sqrt{B \cdot 0.5}} \]
                                                                      3. Add Preprocessing

                                                                      Alternative 14: 35.3% accurate, 12.6× speedup?

                                                                      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}} \end{array} \]
                                                                      B_m = (fabs.f64 B)
                                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                      (FPCore (A B_m C F) :precision binary64 (* (- (sqrt F)) (sqrt (/ 2.0 B_m))))
                                                                      B_m = fabs(B);
                                                                      assert(A < B_m && B_m < C && C < F);
                                                                      double code(double A, double B_m, double C, double F) {
                                                                      	return -sqrt(F) * sqrt((2.0 / B_m));
                                                                      }
                                                                      
                                                                      B_m = abs(b)
                                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                      real(8) function code(a, b_m, c, f)
                                                                          real(8), intent (in) :: a
                                                                          real(8), intent (in) :: b_m
                                                                          real(8), intent (in) :: c
                                                                          real(8), intent (in) :: f
                                                                          code = -sqrt(f) * sqrt((2.0d0 / b_m))
                                                                      end function
                                                                      
                                                                      B_m = Math.abs(B);
                                                                      assert A < B_m && B_m < C && C < F;
                                                                      public static double code(double A, double B_m, double C, double F) {
                                                                      	return -Math.sqrt(F) * Math.sqrt((2.0 / B_m));
                                                                      }
                                                                      
                                                                      B_m = math.fabs(B)
                                                                      [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                      def code(A, B_m, C, F):
                                                                      	return -math.sqrt(F) * math.sqrt((2.0 / B_m))
                                                                      
                                                                      B_m = abs(B)
                                                                      A, B_m, C, F = sort([A, B_m, C, F])
                                                                      function code(A, B_m, C, F)
                                                                      	return Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)))
                                                                      end
                                                                      
                                                                      B_m = abs(B);
                                                                      A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                      function tmp = code(A, B_m, C, F)
                                                                      	tmp = -sqrt(F) * sqrt((2.0 / B_m));
                                                                      end
                                                                      
                                                                      B_m = N[Abs[B], $MachinePrecision]
                                                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                      code[A_, B$95$m_, C_, F_] := N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
                                                                      
                                                                      \begin{array}{l}
                                                                      B_m = \left|B\right|
                                                                      \\
                                                                      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                      \\
                                                                      \left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}
                                                                      \end{array}
                                                                      
                                                                      Derivation
                                                                      1. Initial program 18.8%

                                                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                      2. Add Preprocessing
                                                                      3. Taylor expanded in B around inf

                                                                        \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                      4. Step-by-step derivation
                                                                        1. mul-1-negN/A

                                                                          \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                        2. lower-neg.f64N/A

                                                                          \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                        3. lower-*.f64N/A

                                                                          \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                        4. lower-sqrt.f64N/A

                                                                          \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                        5. lower-/.f64N/A

                                                                          \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                        6. lower-sqrt.f6416.6

                                                                          \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                                      5. Applied rewrites16.6%

                                                                        \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                      6. Step-by-step derivation
                                                                        1. Applied rewrites16.7%

                                                                          \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                        2. Step-by-step derivation
                                                                          1. Applied rewrites20.6%

                                                                            \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                                                          2. Final simplification20.6%

                                                                            \[\leadsto \left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}} \]
                                                                          3. Add Preprocessing

                                                                          Alternative 15: 27.1% accurate, 16.9× speedup?

                                                                          \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ -\sqrt{\frac{F}{B\_m} \cdot 2} \end{array} \]
                                                                          B_m = (fabs.f64 B)
                                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                          (FPCore (A B_m C F) :precision binary64 (- (sqrt (* (/ F B_m) 2.0))))
                                                                          B_m = fabs(B);
                                                                          assert(A < B_m && B_m < C && C < F);
                                                                          double code(double A, double B_m, double C, double F) {
                                                                          	return -sqrt(((F / B_m) * 2.0));
                                                                          }
                                                                          
                                                                          B_m = abs(b)
                                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                          real(8) function code(a, b_m, c, f)
                                                                              real(8), intent (in) :: a
                                                                              real(8), intent (in) :: b_m
                                                                              real(8), intent (in) :: c
                                                                              real(8), intent (in) :: f
                                                                              code = -sqrt(((f / b_m) * 2.0d0))
                                                                          end function
                                                                          
                                                                          B_m = Math.abs(B);
                                                                          assert A < B_m && B_m < C && C < F;
                                                                          public static double code(double A, double B_m, double C, double F) {
                                                                          	return -Math.sqrt(((F / B_m) * 2.0));
                                                                          }
                                                                          
                                                                          B_m = math.fabs(B)
                                                                          [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                          def code(A, B_m, C, F):
                                                                          	return -math.sqrt(((F / B_m) * 2.0))
                                                                          
                                                                          B_m = abs(B)
                                                                          A, B_m, C, F = sort([A, B_m, C, F])
                                                                          function code(A, B_m, C, F)
                                                                          	return Float64(-sqrt(Float64(Float64(F / B_m) * 2.0)))
                                                                          end
                                                                          
                                                                          B_m = abs(B);
                                                                          A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                          function tmp = code(A, B_m, C, F)
                                                                          	tmp = -sqrt(((F / B_m) * 2.0));
                                                                          end
                                                                          
                                                                          B_m = N[Abs[B], $MachinePrecision]
                                                                          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                          code[A_, B$95$m_, C_, F_] := (-N[Sqrt[N[(N[(F / B$95$m), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision])
                                                                          
                                                                          \begin{array}{l}
                                                                          B_m = \left|B\right|
                                                                          \\
                                                                          [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                          \\
                                                                          -\sqrt{\frac{F}{B\_m} \cdot 2}
                                                                          \end{array}
                                                                          
                                                                          Derivation
                                                                          1. Initial program 18.8%

                                                                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                          2. Add Preprocessing
                                                                          3. Taylor expanded in B around inf

                                                                            \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                          4. Step-by-step derivation
                                                                            1. mul-1-negN/A

                                                                              \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                            2. lower-neg.f64N/A

                                                                              \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                            3. lower-*.f64N/A

                                                                              \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                            4. lower-sqrt.f64N/A

                                                                              \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                            5. lower-/.f64N/A

                                                                              \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                            6. lower-sqrt.f6416.6

                                                                              \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                                          5. Applied rewrites16.6%

                                                                            \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                          6. Step-by-step derivation
                                                                            1. Applied rewrites16.7%

                                                                              \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                            2. Add Preprocessing

                                                                            Alternative 16: 27.1% accurate, 16.9× speedup?

                                                                            \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ -\sqrt{F \cdot \frac{2}{B\_m}} \end{array} \]
                                                                            B_m = (fabs.f64 B)
                                                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                            (FPCore (A B_m C F) :precision binary64 (- (sqrt (* F (/ 2.0 B_m)))))
                                                                            B_m = fabs(B);
                                                                            assert(A < B_m && B_m < C && C < F);
                                                                            double code(double A, double B_m, double C, double F) {
                                                                            	return -sqrt((F * (2.0 / B_m)));
                                                                            }
                                                                            
                                                                            B_m = abs(b)
                                                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                            real(8) function code(a, b_m, c, f)
                                                                                real(8), intent (in) :: a
                                                                                real(8), intent (in) :: b_m
                                                                                real(8), intent (in) :: c
                                                                                real(8), intent (in) :: f
                                                                                code = -sqrt((f * (2.0d0 / b_m)))
                                                                            end function
                                                                            
                                                                            B_m = Math.abs(B);
                                                                            assert A < B_m && B_m < C && C < F;
                                                                            public static double code(double A, double B_m, double C, double F) {
                                                                            	return -Math.sqrt((F * (2.0 / B_m)));
                                                                            }
                                                                            
                                                                            B_m = math.fabs(B)
                                                                            [A, B_m, C, F] = sort([A, B_m, C, F])
                                                                            def code(A, B_m, C, F):
                                                                            	return -math.sqrt((F * (2.0 / B_m)))
                                                                            
                                                                            B_m = abs(B)
                                                                            A, B_m, C, F = sort([A, B_m, C, F])
                                                                            function code(A, B_m, C, F)
                                                                            	return Float64(-sqrt(Float64(F * Float64(2.0 / B_m))))
                                                                            end
                                                                            
                                                                            B_m = abs(B);
                                                                            A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                                            function tmp = code(A, B_m, C, F)
                                                                            	tmp = -sqrt((F * (2.0 / B_m)));
                                                                            end
                                                                            
                                                                            B_m = N[Abs[B], $MachinePrecision]
                                                                            NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                                            code[A_, B$95$m_, C_, F_] := (-N[Sqrt[N[(F * N[(2.0 / B$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision])
                                                                            
                                                                            \begin{array}{l}
                                                                            B_m = \left|B\right|
                                                                            \\
                                                                            [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                                            \\
                                                                            -\sqrt{F \cdot \frac{2}{B\_m}}
                                                                            \end{array}
                                                                            
                                                                            Derivation
                                                                            1. Initial program 18.8%

                                                                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                                            2. Add Preprocessing
                                                                            3. Taylor expanded in B around inf

                                                                              \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                            4. Step-by-step derivation
                                                                              1. mul-1-negN/A

                                                                                \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                                              2. lower-neg.f64N/A

                                                                                \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                              3. lower-*.f64N/A

                                                                                \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                              4. lower-sqrt.f64N/A

                                                                                \[\leadsto -\color{blue}{\sqrt{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                              5. lower-/.f64N/A

                                                                                \[\leadsto -\sqrt{\color{blue}{\frac{F}{B}}} \cdot \sqrt{2} \]
                                                                              6. lower-sqrt.f6416.6

                                                                                \[\leadsto -\sqrt{\frac{F}{B}} \cdot \color{blue}{\sqrt{2}} \]
                                                                            5. Applied rewrites16.6%

                                                                              \[\leadsto \color{blue}{-\sqrt{\frac{F}{B}} \cdot \sqrt{2}} \]
                                                                            6. Step-by-step derivation
                                                                              1. Applied rewrites16.7%

                                                                                \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                                              2. Step-by-step derivation
                                                                                1. Applied rewrites16.7%

                                                                                  \[\leadsto -\sqrt{F \cdot \frac{2}{B}} \]
                                                                                2. Add Preprocessing

                                                                                Reproduce

                                                                                ?
                                                                                herbie shell --seed 2024298 
                                                                                (FPCore (A B C F)
                                                                                  :name "ABCF->ab-angle a"
                                                                                  :precision binary64
                                                                                  (/ (- (sqrt (* (* 2.0 (* (- (pow B 2.0) (* (* 4.0 A) C)) F)) (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))) (- (pow B 2.0) (* (* 4.0 A) C))))