Data.Number.Erf:$cinvnormcdf from erf-2.0.0.0, A

Percentage Accurate: 99.5% → 99.5%
Time: 13.9s
Alternatives: 10
Speedup: 1.0×

Specification

?
\[\begin{array}{l} \\ \left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot e^{\frac{t \cdot t}{2}} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (* (* (- (* x 0.5) y) (sqrt (* z 2.0))) (exp (/ (* t t) 2.0))))
double code(double x, double y, double z, double t) {
	return (((x * 0.5) - y) * sqrt((z * 2.0))) * exp(((t * t) / 2.0));
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    code = (((x * 0.5d0) - y) * sqrt((z * 2.0d0))) * exp(((t * t) / 2.0d0))
end function
public static double code(double x, double y, double z, double t) {
	return (((x * 0.5) - y) * Math.sqrt((z * 2.0))) * Math.exp(((t * t) / 2.0));
}
def code(x, y, z, t):
	return (((x * 0.5) - y) * math.sqrt((z * 2.0))) * math.exp(((t * t) / 2.0))
function code(x, y, z, t)
	return Float64(Float64(Float64(Float64(x * 0.5) - y) * sqrt(Float64(z * 2.0))) * exp(Float64(Float64(t * t) / 2.0)))
end
function tmp = code(x, y, z, t)
	tmp = (((x * 0.5) - y) * sqrt((z * 2.0))) * exp(((t * t) / 2.0));
end
code[x_, y_, z_, t_] := N[(N[(N[(N[(x * 0.5), $MachinePrecision] - y), $MachinePrecision] * N[Sqrt[N[(z * 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Exp[N[(N[(t * t), $MachinePrecision] / 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot e^{\frac{t \cdot t}{2}}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 10 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 99.5% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot e^{\frac{t \cdot t}{2}} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (* (* (- (* x 0.5) y) (sqrt (* z 2.0))) (exp (/ (* t t) 2.0))))
double code(double x, double y, double z, double t) {
	return (((x * 0.5) - y) * sqrt((z * 2.0))) * exp(((t * t) / 2.0));
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    code = (((x * 0.5d0) - y) * sqrt((z * 2.0d0))) * exp(((t * t) / 2.0d0))
end function
public static double code(double x, double y, double z, double t) {
	return (((x * 0.5) - y) * Math.sqrt((z * 2.0))) * Math.exp(((t * t) / 2.0));
}
def code(x, y, z, t):
	return (((x * 0.5) - y) * math.sqrt((z * 2.0))) * math.exp(((t * t) / 2.0))
function code(x, y, z, t)
	return Float64(Float64(Float64(Float64(x * 0.5) - y) * sqrt(Float64(z * 2.0))) * exp(Float64(Float64(t * t) / 2.0)))
end
function tmp = code(x, y, z, t)
	tmp = (((x * 0.5) - y) * sqrt((z * 2.0))) * exp(((t * t) / 2.0));
end
code[x_, y_, z_, t_] := N[(N[(N[(N[(x * 0.5), $MachinePrecision] - y), $MachinePrecision] * N[Sqrt[N[(z * 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Exp[N[(N[(t * t), $MachinePrecision] / 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot e^{\frac{t \cdot t}{2}}
\end{array}

Alternative 1: 99.5% accurate, 1.0× speedup?

\[\begin{array}{l} \\ e^{\left(t \cdot t\right) \cdot 0.5} \cdot \left(\sqrt{2 \cdot z} \cdot \left(0.5 \cdot x - y\right)\right) \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (* (exp (* (* t t) 0.5)) (* (sqrt (* 2.0 z)) (- (* 0.5 x) y))))
double code(double x, double y, double z, double t) {
	return exp(((t * t) * 0.5)) * (sqrt((2.0 * z)) * ((0.5 * x) - y));
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    code = exp(((t * t) * 0.5d0)) * (sqrt((2.0d0 * z)) * ((0.5d0 * x) - y))
end function
public static double code(double x, double y, double z, double t) {
	return Math.exp(((t * t) * 0.5)) * (Math.sqrt((2.0 * z)) * ((0.5 * x) - y));
}
def code(x, y, z, t):
	return math.exp(((t * t) * 0.5)) * (math.sqrt((2.0 * z)) * ((0.5 * x) - y))
function code(x, y, z, t)
	return Float64(exp(Float64(Float64(t * t) * 0.5)) * Float64(sqrt(Float64(2.0 * z)) * Float64(Float64(0.5 * x) - y)))
end
function tmp = code(x, y, z, t)
	tmp = exp(((t * t) * 0.5)) * (sqrt((2.0 * z)) * ((0.5 * x) - y));
end
code[x_, y_, z_, t_] := N[(N[Exp[N[(N[(t * t), $MachinePrecision] * 0.5), $MachinePrecision]], $MachinePrecision] * N[(N[Sqrt[N[(2.0 * z), $MachinePrecision]], $MachinePrecision] * N[(N[(0.5 * x), $MachinePrecision] - y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
e^{\left(t \cdot t\right) \cdot 0.5} \cdot \left(\sqrt{2 \cdot z} \cdot \left(0.5 \cdot x - y\right)\right)
\end{array}
Derivation
  1. Initial program 99.8%

    \[\left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot e^{\frac{t \cdot t}{2}} \]
  2. Add Preprocessing
  3. Step-by-step derivation
    1. lift-/.f64N/A

      \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot e^{\color{blue}{\frac{t \cdot t}{2}}} \]
    2. div-invN/A

      \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot e^{\color{blue}{\left(t \cdot t\right) \cdot \frac{1}{2}}} \]
    3. metadata-evalN/A

      \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot e^{\left(t \cdot t\right) \cdot \color{blue}{\frac{1}{2}}} \]
    4. lower-*.f6499.8

      \[\leadsto \left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot e^{\color{blue}{\left(t \cdot t\right) \cdot 0.5}} \]
  4. Applied rewrites99.8%

    \[\leadsto \left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{e^{\left(t \cdot t\right) \cdot 0.5}} \]
  5. Final simplification99.8%

    \[\leadsto e^{\left(t \cdot t\right) \cdot 0.5} \cdot \left(\sqrt{2 \cdot z} \cdot \left(0.5 \cdot x - y\right)\right) \]
  6. Add Preprocessing

Alternative 2: 87.1% accurate, 2.1× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := \sqrt{2 \cdot z}\\ t_2 := \mathsf{fma}\left(t \cdot t, 0.5, 1\right) \cdot \left(t\_1 \cdot \left(0.5 \cdot x - y\right)\right)\\ \mathbf{if}\;t \cdot t \leq 5 \cdot 10^{+111}:\\ \;\;\;\;t\_2\\ \mathbf{elif}\;t \cdot t \leq 4 \cdot 10^{+281}:\\ \;\;\;\;\left(\left(-y\right) \cdot t\_1\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(0.125, t \cdot t, 0.5\right), t \cdot t, 1\right)\\ \mathbf{else}:\\ \;\;\;\;t\_2\\ \end{array} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (let* ((t_1 (sqrt (* 2.0 z)))
        (t_2 (* (fma (* t t) 0.5 1.0) (* t_1 (- (* 0.5 x) y)))))
   (if (<= (* t t) 5e+111)
     t_2
     (if (<= (* t t) 4e+281)
       (* (* (- y) t_1) (fma (fma 0.125 (* t t) 0.5) (* t t) 1.0))
       t_2))))
double code(double x, double y, double z, double t) {
	double t_1 = sqrt((2.0 * z));
	double t_2 = fma((t * t), 0.5, 1.0) * (t_1 * ((0.5 * x) - y));
	double tmp;
	if ((t * t) <= 5e+111) {
		tmp = t_2;
	} else if ((t * t) <= 4e+281) {
		tmp = (-y * t_1) * fma(fma(0.125, (t * t), 0.5), (t * t), 1.0);
	} else {
		tmp = t_2;
	}
	return tmp;
}
function code(x, y, z, t)
	t_1 = sqrt(Float64(2.0 * z))
	t_2 = Float64(fma(Float64(t * t), 0.5, 1.0) * Float64(t_1 * Float64(Float64(0.5 * x) - y)))
	tmp = 0.0
	if (Float64(t * t) <= 5e+111)
		tmp = t_2;
	elseif (Float64(t * t) <= 4e+281)
		tmp = Float64(Float64(Float64(-y) * t_1) * fma(fma(0.125, Float64(t * t), 0.5), Float64(t * t), 1.0));
	else
		tmp = t_2;
	end
	return tmp
end
code[x_, y_, z_, t_] := Block[{t$95$1 = N[Sqrt[N[(2.0 * z), $MachinePrecision]], $MachinePrecision]}, Block[{t$95$2 = N[(N[(N[(t * t), $MachinePrecision] * 0.5 + 1.0), $MachinePrecision] * N[(t$95$1 * N[(N[(0.5 * x), $MachinePrecision] - y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[(t * t), $MachinePrecision], 5e+111], t$95$2, If[LessEqual[N[(t * t), $MachinePrecision], 4e+281], N[(N[((-y) * t$95$1), $MachinePrecision] * N[(N[(0.125 * N[(t * t), $MachinePrecision] + 0.5), $MachinePrecision] * N[(t * t), $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision], t$95$2]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := \sqrt{2 \cdot z}\\
t_2 := \mathsf{fma}\left(t \cdot t, 0.5, 1\right) \cdot \left(t\_1 \cdot \left(0.5 \cdot x - y\right)\right)\\
\mathbf{if}\;t \cdot t \leq 5 \cdot 10^{+111}:\\
\;\;\;\;t\_2\\

\mathbf{elif}\;t \cdot t \leq 4 \cdot 10^{+281}:\\
\;\;\;\;\left(\left(-y\right) \cdot t\_1\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(0.125, t \cdot t, 0.5\right), t \cdot t, 1\right)\\

\mathbf{else}:\\
\;\;\;\;t\_2\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (*.f64 t t) < 4.9999999999999997e111 or 4.0000000000000001e281 < (*.f64 t t)

    1. Initial program 99.8%

      \[\left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot e^{\frac{t \cdot t}{2}} \]
    2. Add Preprocessing
    3. Taylor expanded in t around 0

      \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{\left(1 + \frac{1}{2} \cdot {t}^{2}\right)} \]
    4. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{\left(\frac{1}{2} \cdot {t}^{2} + 1\right)} \]
      2. *-commutativeN/A

        \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \left(\color{blue}{{t}^{2} \cdot \frac{1}{2}} + 1\right) \]
      3. lower-fma.f64N/A

        \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{\mathsf{fma}\left({t}^{2}, \frac{1}{2}, 1\right)} \]
      4. unpow2N/A

        \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \mathsf{fma}\left(\color{blue}{t \cdot t}, \frac{1}{2}, 1\right) \]
      5. lower-*.f6491.6

        \[\leadsto \left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \mathsf{fma}\left(\color{blue}{t \cdot t}, 0.5, 1\right) \]
    5. Applied rewrites91.6%

      \[\leadsto \left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{\mathsf{fma}\left(t \cdot t, 0.5, 1\right)} \]

    if 4.9999999999999997e111 < (*.f64 t t) < 4.0000000000000001e281

    1. Initial program 100.0%

      \[\left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot e^{\frac{t \cdot t}{2}} \]
    2. Add Preprocessing
    3. Taylor expanded in t around 0

      \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{1} \]
    4. Step-by-step derivation
      1. Applied rewrites17.0%

        \[\leadsto \left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{1} \]
      2. Taylor expanded in x around 0

        \[\leadsto \left(\color{blue}{\left(-1 \cdot y\right)} \cdot \sqrt{z \cdot 2}\right) \cdot 1 \]
      3. Step-by-step derivation
        1. mul-1-negN/A

          \[\leadsto \left(\color{blue}{\left(\mathsf{neg}\left(y\right)\right)} \cdot \sqrt{z \cdot 2}\right) \cdot 1 \]
        2. lower-neg.f6411.0

          \[\leadsto \left(\color{blue}{\left(-y\right)} \cdot \sqrt{z \cdot 2}\right) \cdot 1 \]
      4. Applied rewrites11.0%

        \[\leadsto \left(\color{blue}{\left(-y\right)} \cdot \sqrt{z \cdot 2}\right) \cdot 1 \]
      5. Taylor expanded in t around 0

        \[\leadsto \left(\left(-y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{\left(1 + {t}^{2} \cdot \left(\frac{1}{2} + \frac{1}{8} \cdot {t}^{2}\right)\right)} \]
      6. Step-by-step derivation
        1. +-commutativeN/A

          \[\leadsto \left(\left(-y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{\left({t}^{2} \cdot \left(\frac{1}{2} + \frac{1}{8} \cdot {t}^{2}\right) + 1\right)} \]
        2. *-commutativeN/A

          \[\leadsto \left(\left(-y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \left(\color{blue}{\left(\frac{1}{2} + \frac{1}{8} \cdot {t}^{2}\right) \cdot {t}^{2}} + 1\right) \]
        3. lower-fma.f64N/A

          \[\leadsto \left(\left(-y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{1}{2} + \frac{1}{8} \cdot {t}^{2}, {t}^{2}, 1\right)} \]
        4. +-commutativeN/A

          \[\leadsto \left(\left(-y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \mathsf{fma}\left(\color{blue}{\frac{1}{8} \cdot {t}^{2} + \frac{1}{2}}, {t}^{2}, 1\right) \]
        5. lower-fma.f64N/A

          \[\leadsto \left(\left(-y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(\frac{1}{8}, {t}^{2}, \frac{1}{2}\right)}, {t}^{2}, 1\right) \]
        6. unpow2N/A

          \[\leadsto \left(\left(-y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{8}, \color{blue}{t \cdot t}, \frac{1}{2}\right), {t}^{2}, 1\right) \]
        7. lower-*.f64N/A

          \[\leadsto \left(\left(-y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{8}, \color{blue}{t \cdot t}, \frac{1}{2}\right), {t}^{2}, 1\right) \]
        8. unpow2N/A

          \[\leadsto \left(\left(-y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{8}, t \cdot t, \frac{1}{2}\right), \color{blue}{t \cdot t}, 1\right) \]
        9. lower-*.f6478.6

          \[\leadsto \left(\left(-y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(0.125, t \cdot t, 0.5\right), \color{blue}{t \cdot t}, 1\right) \]
      7. Applied rewrites78.6%

        \[\leadsto \left(\left(-y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(0.125, t \cdot t, 0.5\right), t \cdot t, 1\right)} \]
    5. Recombined 2 regimes into one program.
    6. Final simplification89.7%

      \[\leadsto \begin{array}{l} \mathbf{if}\;t \cdot t \leq 5 \cdot 10^{+111}:\\ \;\;\;\;\mathsf{fma}\left(t \cdot t, 0.5, 1\right) \cdot \left(\sqrt{2 \cdot z} \cdot \left(0.5 \cdot x - y\right)\right)\\ \mathbf{elif}\;t \cdot t \leq 4 \cdot 10^{+281}:\\ \;\;\;\;\left(\left(-y\right) \cdot \sqrt{2 \cdot z}\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(0.125, t \cdot t, 0.5\right), t \cdot t, 1\right)\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(t \cdot t, 0.5, 1\right) \cdot \left(\sqrt{2 \cdot z} \cdot \left(0.5 \cdot x - y\right)\right)\\ \end{array} \]
    7. Add Preprocessing

    Alternative 3: 94.8% accurate, 2.2× speedup?

    \[\begin{array}{l} \\ \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.020833333333333332, t \cdot t, 0.125\right) \cdot t, t, 0.5\right), t \cdot t, 1\right) \cdot \left(\sqrt{2 \cdot z} \cdot \left(0.5 \cdot x - y\right)\right) \end{array} \]
    (FPCore (x y z t)
     :precision binary64
     (*
      (fma (fma (* (fma 0.020833333333333332 (* t t) 0.125) t) t 0.5) (* t t) 1.0)
      (* (sqrt (* 2.0 z)) (- (* 0.5 x) y))))
    double code(double x, double y, double z, double t) {
    	return fma(fma((fma(0.020833333333333332, (t * t), 0.125) * t), t, 0.5), (t * t), 1.0) * (sqrt((2.0 * z)) * ((0.5 * x) - y));
    }
    
    function code(x, y, z, t)
    	return Float64(fma(fma(Float64(fma(0.020833333333333332, Float64(t * t), 0.125) * t), t, 0.5), Float64(t * t), 1.0) * Float64(sqrt(Float64(2.0 * z)) * Float64(Float64(0.5 * x) - y)))
    end
    
    code[x_, y_, z_, t_] := N[(N[(N[(N[(N[(0.020833333333333332 * N[(t * t), $MachinePrecision] + 0.125), $MachinePrecision] * t), $MachinePrecision] * t + 0.5), $MachinePrecision] * N[(t * t), $MachinePrecision] + 1.0), $MachinePrecision] * N[(N[Sqrt[N[(2.0 * z), $MachinePrecision]], $MachinePrecision] * N[(N[(0.5 * x), $MachinePrecision] - y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
    
    \begin{array}{l}
    
    \\
    \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.020833333333333332, t \cdot t, 0.125\right) \cdot t, t, 0.5\right), t \cdot t, 1\right) \cdot \left(\sqrt{2 \cdot z} \cdot \left(0.5 \cdot x - y\right)\right)
    \end{array}
    
    Derivation
    1. Initial program 99.8%

      \[\left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot e^{\frac{t \cdot t}{2}} \]
    2. Add Preprocessing
    3. Taylor expanded in t around 0

      \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{\left(1 + {t}^{2} \cdot \left(\frac{1}{2} + {t}^{2} \cdot \left(\frac{1}{8} + \frac{1}{48} \cdot {t}^{2}\right)\right)\right)} \]
    4. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{\left({t}^{2} \cdot \left(\frac{1}{2} + {t}^{2} \cdot \left(\frac{1}{8} + \frac{1}{48} \cdot {t}^{2}\right)\right) + 1\right)} \]
      2. *-commutativeN/A

        \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \left(\color{blue}{\left(\frac{1}{2} + {t}^{2} \cdot \left(\frac{1}{8} + \frac{1}{48} \cdot {t}^{2}\right)\right) \cdot {t}^{2}} + 1\right) \]
      3. lower-fma.f64N/A

        \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{1}{2} + {t}^{2} \cdot \left(\frac{1}{8} + \frac{1}{48} \cdot {t}^{2}\right), {t}^{2}, 1\right)} \]
      4. +-commutativeN/A

        \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \mathsf{fma}\left(\color{blue}{{t}^{2} \cdot \left(\frac{1}{8} + \frac{1}{48} \cdot {t}^{2}\right) + \frac{1}{2}}, {t}^{2}, 1\right) \]
      5. *-commutativeN/A

        \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \mathsf{fma}\left(\color{blue}{\left(\frac{1}{8} + \frac{1}{48} \cdot {t}^{2}\right) \cdot {t}^{2}} + \frac{1}{2}, {t}^{2}, 1\right) \]
      6. lower-fma.f64N/A

        \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(\frac{1}{8} + \frac{1}{48} \cdot {t}^{2}, {t}^{2}, \frac{1}{2}\right)}, {t}^{2}, 1\right) \]
      7. +-commutativeN/A

        \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\frac{1}{48} \cdot {t}^{2} + \frac{1}{8}}, {t}^{2}, \frac{1}{2}\right), {t}^{2}, 1\right) \]
      8. lower-fma.f64N/A

        \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(\frac{1}{48}, {t}^{2}, \frac{1}{8}\right)}, {t}^{2}, \frac{1}{2}\right), {t}^{2}, 1\right) \]
      9. unpow2N/A

        \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{48}, \color{blue}{t \cdot t}, \frac{1}{8}\right), {t}^{2}, \frac{1}{2}\right), {t}^{2}, 1\right) \]
      10. lower-*.f64N/A

        \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{48}, \color{blue}{t \cdot t}, \frac{1}{8}\right), {t}^{2}, \frac{1}{2}\right), {t}^{2}, 1\right) \]
      11. unpow2N/A

        \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{48}, t \cdot t, \frac{1}{8}\right), \color{blue}{t \cdot t}, \frac{1}{2}\right), {t}^{2}, 1\right) \]
      12. lower-*.f64N/A

        \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{48}, t \cdot t, \frac{1}{8}\right), \color{blue}{t \cdot t}, \frac{1}{2}\right), {t}^{2}, 1\right) \]
      13. unpow2N/A

        \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{48}, t \cdot t, \frac{1}{8}\right), t \cdot t, \frac{1}{2}\right), \color{blue}{t \cdot t}, 1\right) \]
      14. lower-*.f6495.7

        \[\leadsto \left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.020833333333333332, t \cdot t, 0.125\right), t \cdot t, 0.5\right), \color{blue}{t \cdot t}, 1\right) \]
    5. Applied rewrites95.7%

      \[\leadsto \left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.020833333333333332, t \cdot t, 0.125\right), t \cdot t, 0.5\right), t \cdot t, 1\right)} \]
    6. Step-by-step derivation
      1. Applied rewrites95.7%

        \[\leadsto \left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.020833333333333332, t \cdot t, 0.125\right) \cdot t, t, 0.5\right), \color{blue}{t} \cdot t, 1\right) \]
      2. Final simplification95.7%

        \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.020833333333333332, t \cdot t, 0.125\right) \cdot t, t, 0.5\right), t \cdot t, 1\right) \cdot \left(\sqrt{2 \cdot z} \cdot \left(0.5 \cdot x - y\right)\right) \]
      3. Add Preprocessing

      Alternative 4: 92.3% accurate, 2.7× speedup?

      \[\begin{array}{l} \\ \mathsf{fma}\left(\mathsf{fma}\left(0.125, t \cdot t, 0.5\right), t \cdot t, 1\right) \cdot \left(\sqrt{2 \cdot z} \cdot \left(0.5 \cdot x - y\right)\right) \end{array} \]
      (FPCore (x y z t)
       :precision binary64
       (*
        (fma (fma 0.125 (* t t) 0.5) (* t t) 1.0)
        (* (sqrt (* 2.0 z)) (- (* 0.5 x) y))))
      double code(double x, double y, double z, double t) {
      	return fma(fma(0.125, (t * t), 0.5), (t * t), 1.0) * (sqrt((2.0 * z)) * ((0.5 * x) - y));
      }
      
      function code(x, y, z, t)
      	return Float64(fma(fma(0.125, Float64(t * t), 0.5), Float64(t * t), 1.0) * Float64(sqrt(Float64(2.0 * z)) * Float64(Float64(0.5 * x) - y)))
      end
      
      code[x_, y_, z_, t_] := N[(N[(N[(0.125 * N[(t * t), $MachinePrecision] + 0.5), $MachinePrecision] * N[(t * t), $MachinePrecision] + 1.0), $MachinePrecision] * N[(N[Sqrt[N[(2.0 * z), $MachinePrecision]], $MachinePrecision] * N[(N[(0.5 * x), $MachinePrecision] - y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
      
      \begin{array}{l}
      
      \\
      \mathsf{fma}\left(\mathsf{fma}\left(0.125, t \cdot t, 0.5\right), t \cdot t, 1\right) \cdot \left(\sqrt{2 \cdot z} \cdot \left(0.5 \cdot x - y\right)\right)
      \end{array}
      
      Derivation
      1. Initial program 99.8%

        \[\left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot e^{\frac{t \cdot t}{2}} \]
      2. Add Preprocessing
      3. Taylor expanded in t around 0

        \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{\left(1 + {t}^{2} \cdot \left(\frac{1}{2} + \frac{1}{8} \cdot {t}^{2}\right)\right)} \]
      4. Step-by-step derivation
        1. +-commutativeN/A

          \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{\left({t}^{2} \cdot \left(\frac{1}{2} + \frac{1}{8} \cdot {t}^{2}\right) + 1\right)} \]
        2. *-commutativeN/A

          \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \left(\color{blue}{\left(\frac{1}{2} + \frac{1}{8} \cdot {t}^{2}\right) \cdot {t}^{2}} + 1\right) \]
        3. lower-fma.f64N/A

          \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{1}{2} + \frac{1}{8} \cdot {t}^{2}, {t}^{2}, 1\right)} \]
        4. +-commutativeN/A

          \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \mathsf{fma}\left(\color{blue}{\frac{1}{8} \cdot {t}^{2} + \frac{1}{2}}, {t}^{2}, 1\right) \]
        5. lower-fma.f64N/A

          \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(\frac{1}{8}, {t}^{2}, \frac{1}{2}\right)}, {t}^{2}, 1\right) \]
        6. unpow2N/A

          \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{8}, \color{blue}{t \cdot t}, \frac{1}{2}\right), {t}^{2}, 1\right) \]
        7. lower-*.f64N/A

          \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{8}, \color{blue}{t \cdot t}, \frac{1}{2}\right), {t}^{2}, 1\right) \]
        8. unpow2N/A

          \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(\frac{1}{8}, t \cdot t, \frac{1}{2}\right), \color{blue}{t \cdot t}, 1\right) \]
        9. lower-*.f6492.7

          \[\leadsto \left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \mathsf{fma}\left(\mathsf{fma}\left(0.125, t \cdot t, 0.5\right), \color{blue}{t \cdot t}, 1\right) \]
      5. Applied rewrites92.7%

        \[\leadsto \left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(0.125, t \cdot t, 0.5\right), t \cdot t, 1\right)} \]
      6. Final simplification92.7%

        \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(0.125, t \cdot t, 0.5\right), t \cdot t, 1\right) \cdot \left(\sqrt{2 \cdot z} \cdot \left(0.5 \cdot x - y\right)\right) \]
      7. Add Preprocessing

      Alternative 5: 87.7% accurate, 2.7× speedup?

      \[\begin{array}{l} \\ \sqrt{z} \cdot \left(\left(\sqrt{2} \cdot \mathsf{fma}\left(0.5, x, -y\right)\right) \cdot \mathsf{fma}\left(t \cdot t, 0.5, 1\right)\right) \end{array} \]
      (FPCore (x y z t)
       :precision binary64
       (* (sqrt z) (* (* (sqrt 2.0) (fma 0.5 x (- y))) (fma (* t t) 0.5 1.0))))
      double code(double x, double y, double z, double t) {
      	return sqrt(z) * ((sqrt(2.0) * fma(0.5, x, -y)) * fma((t * t), 0.5, 1.0));
      }
      
      function code(x, y, z, t)
      	return Float64(sqrt(z) * Float64(Float64(sqrt(2.0) * fma(0.5, x, Float64(-y))) * fma(Float64(t * t), 0.5, 1.0)))
      end
      
      code[x_, y_, z_, t_] := N[(N[Sqrt[z], $MachinePrecision] * N[(N[(N[Sqrt[2.0], $MachinePrecision] * N[(0.5 * x + (-y)), $MachinePrecision]), $MachinePrecision] * N[(N[(t * t), $MachinePrecision] * 0.5 + 1.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
      
      \begin{array}{l}
      
      \\
      \sqrt{z} \cdot \left(\left(\sqrt{2} \cdot \mathsf{fma}\left(0.5, x, -y\right)\right) \cdot \mathsf{fma}\left(t \cdot t, 0.5, 1\right)\right)
      \end{array}
      
      Derivation
      1. Initial program 99.8%

        \[\left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot e^{\frac{t \cdot t}{2}} \]
      2. Add Preprocessing
      3. Taylor expanded in t around 0

        \[\leadsto \color{blue}{\frac{1}{2} \cdot \left(\left({t}^{2} \cdot \left(\sqrt{2} \cdot \left(\frac{1}{2} \cdot x - y\right)\right)\right) \cdot \sqrt{z}\right) + \sqrt{z} \cdot \left(\sqrt{2} \cdot \left(\frac{1}{2} \cdot x - y\right)\right)} \]
      4. Step-by-step derivation
        1. +-commutativeN/A

          \[\leadsto \color{blue}{\sqrt{z} \cdot \left(\sqrt{2} \cdot \left(\frac{1}{2} \cdot x - y\right)\right) + \frac{1}{2} \cdot \left(\left({t}^{2} \cdot \left(\sqrt{2} \cdot \left(\frac{1}{2} \cdot x - y\right)\right)\right) \cdot \sqrt{z}\right)} \]
        2. *-commutativeN/A

          \[\leadsto \color{blue}{\left(\sqrt{2} \cdot \left(\frac{1}{2} \cdot x - y\right)\right) \cdot \sqrt{z}} + \frac{1}{2} \cdot \left(\left({t}^{2} \cdot \left(\sqrt{2} \cdot \left(\frac{1}{2} \cdot x - y\right)\right)\right) \cdot \sqrt{z}\right) \]
        3. associate-*r*N/A

          \[\leadsto \left(\sqrt{2} \cdot \left(\frac{1}{2} \cdot x - y\right)\right) \cdot \sqrt{z} + \color{blue}{\left(\frac{1}{2} \cdot \left({t}^{2} \cdot \left(\sqrt{2} \cdot \left(\frac{1}{2} \cdot x - y\right)\right)\right)\right) \cdot \sqrt{z}} \]
        4. distribute-rgt-outN/A

          \[\leadsto \color{blue}{\sqrt{z} \cdot \left(\sqrt{2} \cdot \left(\frac{1}{2} \cdot x - y\right) + \frac{1}{2} \cdot \left({t}^{2} \cdot \left(\sqrt{2} \cdot \left(\frac{1}{2} \cdot x - y\right)\right)\right)\right)} \]
        5. *-commutativeN/A

          \[\leadsto \color{blue}{\left(\sqrt{2} \cdot \left(\frac{1}{2} \cdot x - y\right) + \frac{1}{2} \cdot \left({t}^{2} \cdot \left(\sqrt{2} \cdot \left(\frac{1}{2} \cdot x - y\right)\right)\right)\right) \cdot \sqrt{z}} \]
        6. lower-*.f64N/A

          \[\leadsto \color{blue}{\left(\sqrt{2} \cdot \left(\frac{1}{2} \cdot x - y\right) + \frac{1}{2} \cdot \left({t}^{2} \cdot \left(\sqrt{2} \cdot \left(\frac{1}{2} \cdot x - y\right)\right)\right)\right) \cdot \sqrt{z}} \]
      5. Applied rewrites87.2%

        \[\leadsto \color{blue}{\left(\mathsf{fma}\left(t \cdot t, 0.5, 1\right) \cdot \left(\mathsf{fma}\left(0.5, x, -y\right) \cdot \sqrt{2}\right)\right) \cdot \sqrt{z}} \]
      6. Final simplification87.2%

        \[\leadsto \sqrt{z} \cdot \left(\left(\sqrt{2} \cdot \mathsf{fma}\left(0.5, x, -y\right)\right) \cdot \mathsf{fma}\left(t \cdot t, 0.5, 1\right)\right) \]
      7. Add Preprocessing

      Alternative 6: 76.1% accurate, 3.1× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} t_1 := \sqrt{2 \cdot z}\\ \mathbf{if}\;t \cdot t \leq 5 \cdot 10^{+53}:\\ \;\;\;\;1 \cdot \left(t\_1 \cdot \left(0.5 \cdot x - y\right)\right)\\ \mathbf{else}:\\ \;\;\;\;\left(\mathsf{fma}\left(0.25, t \cdot t, 0.5\right) \cdot x\right) \cdot t\_1\\ \end{array} \end{array} \]
      (FPCore (x y z t)
       :precision binary64
       (let* ((t_1 (sqrt (* 2.0 z))))
         (if (<= (* t t) 5e+53)
           (* 1.0 (* t_1 (- (* 0.5 x) y)))
           (* (* (fma 0.25 (* t t) 0.5) x) t_1))))
      double code(double x, double y, double z, double t) {
      	double t_1 = sqrt((2.0 * z));
      	double tmp;
      	if ((t * t) <= 5e+53) {
      		tmp = 1.0 * (t_1 * ((0.5 * x) - y));
      	} else {
      		tmp = (fma(0.25, (t * t), 0.5) * x) * t_1;
      	}
      	return tmp;
      }
      
      function code(x, y, z, t)
      	t_1 = sqrt(Float64(2.0 * z))
      	tmp = 0.0
      	if (Float64(t * t) <= 5e+53)
      		tmp = Float64(1.0 * Float64(t_1 * Float64(Float64(0.5 * x) - y)));
      	else
      		tmp = Float64(Float64(fma(0.25, Float64(t * t), 0.5) * x) * t_1);
      	end
      	return tmp
      end
      
      code[x_, y_, z_, t_] := Block[{t$95$1 = N[Sqrt[N[(2.0 * z), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[N[(t * t), $MachinePrecision], 5e+53], N[(1.0 * N[(t$95$1 * N[(N[(0.5 * x), $MachinePrecision] - y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(N[(0.25 * N[(t * t), $MachinePrecision] + 0.5), $MachinePrecision] * x), $MachinePrecision] * t$95$1), $MachinePrecision]]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      t_1 := \sqrt{2 \cdot z}\\
      \mathbf{if}\;t \cdot t \leq 5 \cdot 10^{+53}:\\
      \;\;\;\;1 \cdot \left(t\_1 \cdot \left(0.5 \cdot x - y\right)\right)\\
      
      \mathbf{else}:\\
      \;\;\;\;\left(\mathsf{fma}\left(0.25, t \cdot t, 0.5\right) \cdot x\right) \cdot t\_1\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if (*.f64 t t) < 5.0000000000000004e53

        1. Initial program 99.7%

          \[\left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot e^{\frac{t \cdot t}{2}} \]
        2. Add Preprocessing
        3. Taylor expanded in t around 0

          \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{1} \]
        4. Step-by-step derivation
          1. Applied rewrites92.5%

            \[\leadsto \left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{1} \]

          if 5.0000000000000004e53 < (*.f64 t t)

          1. Initial program 100.0%

            \[\left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot e^{\frac{t \cdot t}{2}} \]
          2. Add Preprocessing
          3. Taylor expanded in t around 0

            \[\leadsto \color{blue}{\frac{1}{2} \cdot \left(\left({t}^{2} \cdot \left(\sqrt{2} \cdot \left(\frac{1}{2} \cdot x - y\right)\right)\right) \cdot \sqrt{z}\right) + \sqrt{z} \cdot \left(\sqrt{2} \cdot \left(\frac{1}{2} \cdot x - y\right)\right)} \]
          4. Step-by-step derivation
            1. +-commutativeN/A

              \[\leadsto \color{blue}{\sqrt{z} \cdot \left(\sqrt{2} \cdot \left(\frac{1}{2} \cdot x - y\right)\right) + \frac{1}{2} \cdot \left(\left({t}^{2} \cdot \left(\sqrt{2} \cdot \left(\frac{1}{2} \cdot x - y\right)\right)\right) \cdot \sqrt{z}\right)} \]
            2. *-commutativeN/A

              \[\leadsto \color{blue}{\left(\sqrt{2} \cdot \left(\frac{1}{2} \cdot x - y\right)\right) \cdot \sqrt{z}} + \frac{1}{2} \cdot \left(\left({t}^{2} \cdot \left(\sqrt{2} \cdot \left(\frac{1}{2} \cdot x - y\right)\right)\right) \cdot \sqrt{z}\right) \]
            3. associate-*r*N/A

              \[\leadsto \left(\sqrt{2} \cdot \left(\frac{1}{2} \cdot x - y\right)\right) \cdot \sqrt{z} + \color{blue}{\left(\frac{1}{2} \cdot \left({t}^{2} \cdot \left(\sqrt{2} \cdot \left(\frac{1}{2} \cdot x - y\right)\right)\right)\right) \cdot \sqrt{z}} \]
            4. distribute-rgt-outN/A

              \[\leadsto \color{blue}{\sqrt{z} \cdot \left(\sqrt{2} \cdot \left(\frac{1}{2} \cdot x - y\right) + \frac{1}{2} \cdot \left({t}^{2} \cdot \left(\sqrt{2} \cdot \left(\frac{1}{2} \cdot x - y\right)\right)\right)\right)} \]
            5. *-commutativeN/A

              \[\leadsto \color{blue}{\left(\sqrt{2} \cdot \left(\frac{1}{2} \cdot x - y\right) + \frac{1}{2} \cdot \left({t}^{2} \cdot \left(\sqrt{2} \cdot \left(\frac{1}{2} \cdot x - y\right)\right)\right)\right) \cdot \sqrt{z}} \]
            6. lower-*.f64N/A

              \[\leadsto \color{blue}{\left(\sqrt{2} \cdot \left(\frac{1}{2} \cdot x - y\right) + \frac{1}{2} \cdot \left({t}^{2} \cdot \left(\sqrt{2} \cdot \left(\frac{1}{2} \cdot x - y\right)\right)\right)\right) \cdot \sqrt{z}} \]
          5. Applied rewrites80.3%

            \[\leadsto \color{blue}{\left(\mathsf{fma}\left(t \cdot t, 0.5, 1\right) \cdot \left(\mathsf{fma}\left(0.5, x, -y\right) \cdot \sqrt{2}\right)\right) \cdot \sqrt{z}} \]
          6. Applied rewrites39.8%

            \[\leadsto \left(\mathsf{fma}\left(0.5, x, y\right) \cdot \mathsf{fma}\left(t \cdot t, 0.5, 1\right)\right) \cdot \color{blue}{\sqrt{2 \cdot z}} \]
          7. Taylor expanded in x around inf

            \[\leadsto \left(\frac{1}{2} \cdot \left(x \cdot \left(1 + \frac{1}{2} \cdot {t}^{2}\right)\right)\right) \cdot \sqrt{\color{blue}{2 \cdot z}} \]
          8. Step-by-step derivation
            1. Applied rewrites59.5%

              \[\leadsto \left(\mathsf{fma}\left(0.25, t \cdot t, 0.5\right) \cdot x\right) \cdot \sqrt{\color{blue}{2 \cdot z}} \]
          9. Recombined 2 regimes into one program.
          10. Final simplification77.7%

            \[\leadsto \begin{array}{l} \mathbf{if}\;t \cdot t \leq 5 \cdot 10^{+53}:\\ \;\;\;\;1 \cdot \left(\sqrt{2 \cdot z} \cdot \left(0.5 \cdot x - y\right)\right)\\ \mathbf{else}:\\ \;\;\;\;\left(\mathsf{fma}\left(0.25, t \cdot t, 0.5\right) \cdot x\right) \cdot \sqrt{2 \cdot z}\\ \end{array} \]
          11. Add Preprocessing

          Alternative 7: 85.6% accurate, 3.3× speedup?

          \[\begin{array}{l} \\ \mathsf{fma}\left(t \cdot t, 0.5, 1\right) \cdot \left(\sqrt{2 \cdot z} \cdot \left(0.5 \cdot x - y\right)\right) \end{array} \]
          (FPCore (x y z t)
           :precision binary64
           (* (fma (* t t) 0.5 1.0) (* (sqrt (* 2.0 z)) (- (* 0.5 x) y))))
          double code(double x, double y, double z, double t) {
          	return fma((t * t), 0.5, 1.0) * (sqrt((2.0 * z)) * ((0.5 * x) - y));
          }
          
          function code(x, y, z, t)
          	return Float64(fma(Float64(t * t), 0.5, 1.0) * Float64(sqrt(Float64(2.0 * z)) * Float64(Float64(0.5 * x) - y)))
          end
          
          code[x_, y_, z_, t_] := N[(N[(N[(t * t), $MachinePrecision] * 0.5 + 1.0), $MachinePrecision] * N[(N[Sqrt[N[(2.0 * z), $MachinePrecision]], $MachinePrecision] * N[(N[(0.5 * x), $MachinePrecision] - y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
          
          \begin{array}{l}
          
          \\
          \mathsf{fma}\left(t \cdot t, 0.5, 1\right) \cdot \left(\sqrt{2 \cdot z} \cdot \left(0.5 \cdot x - y\right)\right)
          \end{array}
          
          Derivation
          1. Initial program 99.8%

            \[\left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot e^{\frac{t \cdot t}{2}} \]
          2. Add Preprocessing
          3. Taylor expanded in t around 0

            \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{\left(1 + \frac{1}{2} \cdot {t}^{2}\right)} \]
          4. Step-by-step derivation
            1. +-commutativeN/A

              \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{\left(\frac{1}{2} \cdot {t}^{2} + 1\right)} \]
            2. *-commutativeN/A

              \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \left(\color{blue}{{t}^{2} \cdot \frac{1}{2}} + 1\right) \]
            3. lower-fma.f64N/A

              \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{\mathsf{fma}\left({t}^{2}, \frac{1}{2}, 1\right)} \]
            4. unpow2N/A

              \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \mathsf{fma}\left(\color{blue}{t \cdot t}, \frac{1}{2}, 1\right) \]
            5. lower-*.f6485.5

              \[\leadsto \left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \mathsf{fma}\left(\color{blue}{t \cdot t}, 0.5, 1\right) \]
          5. Applied rewrites85.5%

            \[\leadsto \left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{\mathsf{fma}\left(t \cdot t, 0.5, 1\right)} \]
          6. Final simplification85.5%

            \[\leadsto \mathsf{fma}\left(t \cdot t, 0.5, 1\right) \cdot \left(\sqrt{2 \cdot z} \cdot \left(0.5 \cdot x - y\right)\right) \]
          7. Add Preprocessing

          Alternative 8: 43.1% accurate, 3.4× speedup?

          \[\begin{array}{l} \\ \begin{array}{l} t_1 := \sqrt{2 \cdot z}\\ t_2 := 1 \cdot \left(\left(-y\right) \cdot t\_1\right)\\ \mathbf{if}\;y \leq -6.2 \cdot 10^{+37}:\\ \;\;\;\;t\_2\\ \mathbf{elif}\;y \leq 1.45 \cdot 10^{-42}:\\ \;\;\;\;\left(1 \cdot t\_1\right) \cdot \mathsf{fma}\left(0.5, x, y\right)\\ \mathbf{else}:\\ \;\;\;\;t\_2\\ \end{array} \end{array} \]
          (FPCore (x y z t)
           :precision binary64
           (let* ((t_1 (sqrt (* 2.0 z))) (t_2 (* 1.0 (* (- y) t_1))))
             (if (<= y -6.2e+37)
               t_2
               (if (<= y 1.45e-42) (* (* 1.0 t_1) (fma 0.5 x y)) t_2))))
          double code(double x, double y, double z, double t) {
          	double t_1 = sqrt((2.0 * z));
          	double t_2 = 1.0 * (-y * t_1);
          	double tmp;
          	if (y <= -6.2e+37) {
          		tmp = t_2;
          	} else if (y <= 1.45e-42) {
          		tmp = (1.0 * t_1) * fma(0.5, x, y);
          	} else {
          		tmp = t_2;
          	}
          	return tmp;
          }
          
          function code(x, y, z, t)
          	t_1 = sqrt(Float64(2.0 * z))
          	t_2 = Float64(1.0 * Float64(Float64(-y) * t_1))
          	tmp = 0.0
          	if (y <= -6.2e+37)
          		tmp = t_2;
          	elseif (y <= 1.45e-42)
          		tmp = Float64(Float64(1.0 * t_1) * fma(0.5, x, y));
          	else
          		tmp = t_2;
          	end
          	return tmp
          end
          
          code[x_, y_, z_, t_] := Block[{t$95$1 = N[Sqrt[N[(2.0 * z), $MachinePrecision]], $MachinePrecision]}, Block[{t$95$2 = N[(1.0 * N[((-y) * t$95$1), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[y, -6.2e+37], t$95$2, If[LessEqual[y, 1.45e-42], N[(N[(1.0 * t$95$1), $MachinePrecision] * N[(0.5 * x + y), $MachinePrecision]), $MachinePrecision], t$95$2]]]]
          
          \begin{array}{l}
          
          \\
          \begin{array}{l}
          t_1 := \sqrt{2 \cdot z}\\
          t_2 := 1 \cdot \left(\left(-y\right) \cdot t\_1\right)\\
          \mathbf{if}\;y \leq -6.2 \cdot 10^{+37}:\\
          \;\;\;\;t\_2\\
          
          \mathbf{elif}\;y \leq 1.45 \cdot 10^{-42}:\\
          \;\;\;\;\left(1 \cdot t\_1\right) \cdot \mathsf{fma}\left(0.5, x, y\right)\\
          
          \mathbf{else}:\\
          \;\;\;\;t\_2\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if y < -6.2000000000000004e37 or 1.4500000000000001e-42 < y

            1. Initial program 99.9%

              \[\left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot e^{\frac{t \cdot t}{2}} \]
            2. Add Preprocessing
            3. Taylor expanded in t around 0

              \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{1} \]
            4. Step-by-step derivation
              1. Applied rewrites63.6%

                \[\leadsto \left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{1} \]
              2. Taylor expanded in x around 0

                \[\leadsto \left(\color{blue}{\left(-1 \cdot y\right)} \cdot \sqrt{z \cdot 2}\right) \cdot 1 \]
              3. Step-by-step derivation
                1. mul-1-negN/A

                  \[\leadsto \left(\color{blue}{\left(\mathsf{neg}\left(y\right)\right)} \cdot \sqrt{z \cdot 2}\right) \cdot 1 \]
                2. lower-neg.f6448.8

                  \[\leadsto \left(\color{blue}{\left(-y\right)} \cdot \sqrt{z \cdot 2}\right) \cdot 1 \]
              4. Applied rewrites48.8%

                \[\leadsto \left(\color{blue}{\left(-y\right)} \cdot \sqrt{z \cdot 2}\right) \cdot 1 \]

              if -6.2000000000000004e37 < y < 1.4500000000000001e-42

              1. Initial program 99.8%

                \[\left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot e^{\frac{t \cdot t}{2}} \]
              2. Add Preprocessing
              3. Taylor expanded in t around 0

                \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{1} \]
              4. Step-by-step derivation
                1. Applied rewrites56.1%

                  \[\leadsto \left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{1} \]
                2. Step-by-step derivation
                  1. lift-*.f64N/A

                    \[\leadsto \color{blue}{\left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot 1} \]
                  2. lift-*.f64N/A

                    \[\leadsto \color{blue}{\left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right)} \cdot 1 \]
                  3. associate-*l*N/A

                    \[\leadsto \color{blue}{\left(x \cdot \frac{1}{2} - y\right) \cdot \left(\sqrt{z \cdot 2} \cdot 1\right)} \]
                3. Applied rewrites46.6%

                  \[\leadsto \color{blue}{\mathsf{fma}\left(0.5, x, y\right) \cdot \left(1 \cdot \sqrt{2 \cdot z}\right)} \]
              5. Recombined 2 regimes into one program.
              6. Final simplification47.6%

                \[\leadsto \begin{array}{l} \mathbf{if}\;y \leq -6.2 \cdot 10^{+37}:\\ \;\;\;\;1 \cdot \left(\left(-y\right) \cdot \sqrt{2 \cdot z}\right)\\ \mathbf{elif}\;y \leq 1.45 \cdot 10^{-42}:\\ \;\;\;\;\left(1 \cdot \sqrt{2 \cdot z}\right) \cdot \mathsf{fma}\left(0.5, x, y\right)\\ \mathbf{else}:\\ \;\;\;\;1 \cdot \left(\left(-y\right) \cdot \sqrt{2 \cdot z}\right)\\ \end{array} \]
              7. Add Preprocessing

              Alternative 9: 57.1% accurate, 4.4× speedup?

              \[\begin{array}{l} \\ 1 \cdot \left(\sqrt{2 \cdot z} \cdot \left(0.5 \cdot x - y\right)\right) \end{array} \]
              (FPCore (x y z t)
               :precision binary64
               (* 1.0 (* (sqrt (* 2.0 z)) (- (* 0.5 x) y))))
              double code(double x, double y, double z, double t) {
              	return 1.0 * (sqrt((2.0 * z)) * ((0.5 * x) - y));
              }
              
              real(8) function code(x, y, z, t)
                  real(8), intent (in) :: x
                  real(8), intent (in) :: y
                  real(8), intent (in) :: z
                  real(8), intent (in) :: t
                  code = 1.0d0 * (sqrt((2.0d0 * z)) * ((0.5d0 * x) - y))
              end function
              
              public static double code(double x, double y, double z, double t) {
              	return 1.0 * (Math.sqrt((2.0 * z)) * ((0.5 * x) - y));
              }
              
              def code(x, y, z, t):
              	return 1.0 * (math.sqrt((2.0 * z)) * ((0.5 * x) - y))
              
              function code(x, y, z, t)
              	return Float64(1.0 * Float64(sqrt(Float64(2.0 * z)) * Float64(Float64(0.5 * x) - y)))
              end
              
              function tmp = code(x, y, z, t)
              	tmp = 1.0 * (sqrt((2.0 * z)) * ((0.5 * x) - y));
              end
              
              code[x_, y_, z_, t_] := N[(1.0 * N[(N[Sqrt[N[(2.0 * z), $MachinePrecision]], $MachinePrecision] * N[(N[(0.5 * x), $MachinePrecision] - y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
              
              \begin{array}{l}
              
              \\
              1 \cdot \left(\sqrt{2 \cdot z} \cdot \left(0.5 \cdot x - y\right)\right)
              \end{array}
              
              Derivation
              1. Initial program 99.8%

                \[\left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot e^{\frac{t \cdot t}{2}} \]
              2. Add Preprocessing
              3. Taylor expanded in t around 0

                \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{1} \]
              4. Step-by-step derivation
                1. Applied rewrites59.5%

                  \[\leadsto \left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{1} \]
                2. Final simplification59.5%

                  \[\leadsto 1 \cdot \left(\sqrt{2 \cdot z} \cdot \left(0.5 \cdot x - y\right)\right) \]
                3. Add Preprocessing

                Alternative 10: 29.9% accurate, 5.4× speedup?

                \[\begin{array}{l} \\ 1 \cdot \left(\left(-y\right) \cdot \sqrt{2 \cdot z}\right) \end{array} \]
                (FPCore (x y z t) :precision binary64 (* 1.0 (* (- y) (sqrt (* 2.0 z)))))
                double code(double x, double y, double z, double t) {
                	return 1.0 * (-y * sqrt((2.0 * z)));
                }
                
                real(8) function code(x, y, z, t)
                    real(8), intent (in) :: x
                    real(8), intent (in) :: y
                    real(8), intent (in) :: z
                    real(8), intent (in) :: t
                    code = 1.0d0 * (-y * sqrt((2.0d0 * z)))
                end function
                
                public static double code(double x, double y, double z, double t) {
                	return 1.0 * (-y * Math.sqrt((2.0 * z)));
                }
                
                def code(x, y, z, t):
                	return 1.0 * (-y * math.sqrt((2.0 * z)))
                
                function code(x, y, z, t)
                	return Float64(1.0 * Float64(Float64(-y) * sqrt(Float64(2.0 * z))))
                end
                
                function tmp = code(x, y, z, t)
                	tmp = 1.0 * (-y * sqrt((2.0 * z)));
                end
                
                code[x_, y_, z_, t_] := N[(1.0 * N[((-y) * N[Sqrt[N[(2.0 * z), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
                
                \begin{array}{l}
                
                \\
                1 \cdot \left(\left(-y\right) \cdot \sqrt{2 \cdot z}\right)
                \end{array}
                
                Derivation
                1. Initial program 99.8%

                  \[\left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot e^{\frac{t \cdot t}{2}} \]
                2. Add Preprocessing
                3. Taylor expanded in t around 0

                  \[\leadsto \left(\left(x \cdot \frac{1}{2} - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{1} \]
                4. Step-by-step derivation
                  1. Applied rewrites59.5%

                    \[\leadsto \left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot \color{blue}{1} \]
                  2. Taylor expanded in x around 0

                    \[\leadsto \left(\color{blue}{\left(-1 \cdot y\right)} \cdot \sqrt{z \cdot 2}\right) \cdot 1 \]
                  3. Step-by-step derivation
                    1. mul-1-negN/A

                      \[\leadsto \left(\color{blue}{\left(\mathsf{neg}\left(y\right)\right)} \cdot \sqrt{z \cdot 2}\right) \cdot 1 \]
                    2. lower-neg.f6428.8

                      \[\leadsto \left(\color{blue}{\left(-y\right)} \cdot \sqrt{z \cdot 2}\right) \cdot 1 \]
                  4. Applied rewrites28.8%

                    \[\leadsto \left(\color{blue}{\left(-y\right)} \cdot \sqrt{z \cdot 2}\right) \cdot 1 \]
                  5. Final simplification28.8%

                    \[\leadsto 1 \cdot \left(\left(-y\right) \cdot \sqrt{2 \cdot z}\right) \]
                  6. Add Preprocessing

                  Developer Target 1: 99.5% accurate, 0.6× speedup?

                  \[\begin{array}{l} \\ \left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot {\left(e^{1}\right)}^{\left(\frac{t \cdot t}{2}\right)} \end{array} \]
                  (FPCore (x y z t)
                   :precision binary64
                   (* (* (- (* x 0.5) y) (sqrt (* z 2.0))) (pow (exp 1.0) (/ (* t t) 2.0))))
                  double code(double x, double y, double z, double t) {
                  	return (((x * 0.5) - y) * sqrt((z * 2.0))) * pow(exp(1.0), ((t * t) / 2.0));
                  }
                  
                  real(8) function code(x, y, z, t)
                      real(8), intent (in) :: x
                      real(8), intent (in) :: y
                      real(8), intent (in) :: z
                      real(8), intent (in) :: t
                      code = (((x * 0.5d0) - y) * sqrt((z * 2.0d0))) * (exp(1.0d0) ** ((t * t) / 2.0d0))
                  end function
                  
                  public static double code(double x, double y, double z, double t) {
                  	return (((x * 0.5) - y) * Math.sqrt((z * 2.0))) * Math.pow(Math.exp(1.0), ((t * t) / 2.0));
                  }
                  
                  def code(x, y, z, t):
                  	return (((x * 0.5) - y) * math.sqrt((z * 2.0))) * math.pow(math.exp(1.0), ((t * t) / 2.0))
                  
                  function code(x, y, z, t)
                  	return Float64(Float64(Float64(Float64(x * 0.5) - y) * sqrt(Float64(z * 2.0))) * (exp(1.0) ^ Float64(Float64(t * t) / 2.0)))
                  end
                  
                  function tmp = code(x, y, z, t)
                  	tmp = (((x * 0.5) - y) * sqrt((z * 2.0))) * (exp(1.0) ^ ((t * t) / 2.0));
                  end
                  
                  code[x_, y_, z_, t_] := N[(N[(N[(N[(x * 0.5), $MachinePrecision] - y), $MachinePrecision] * N[Sqrt[N[(z * 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[Power[N[Exp[1.0], $MachinePrecision], N[(N[(t * t), $MachinePrecision] / 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
                  
                  \begin{array}{l}
                  
                  \\
                  \left(\left(x \cdot 0.5 - y\right) \cdot \sqrt{z \cdot 2}\right) \cdot {\left(e^{1}\right)}^{\left(\frac{t \cdot t}{2}\right)}
                  \end{array}
                  

                  Reproduce

                  ?
                  herbie shell --seed 2024296 
                  (FPCore (x y z t)
                    :name "Data.Number.Erf:$cinvnormcdf from erf-2.0.0.0, A"
                    :precision binary64
                  
                    :alt
                    (! :herbie-platform default (* (* (- (* x 1/2) y) (sqrt (* z 2))) (pow (exp 1) (/ (* t t) 2))))
                  
                    (* (* (- (* x 0.5) y) (sqrt (* z 2.0))) (exp (/ (* t t) 2.0))))