ABCF->ab-angle a

Percentage Accurate: 18.8% → 57.2%
Time: 14.2s
Alternatives: 11
Speedup: 18.9×

Specification

?
\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
real(8) function code(a, b, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) + sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 11 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 18.8% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\ \frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0} \end{array} \end{array} \]
(FPCore (A B C F)
 :precision binary64
 (let* ((t_0 (- (pow B 2.0) (* (* 4.0 A) C))))
   (/
    (-
     (sqrt
      (*
       (* 2.0 (* t_0 F))
       (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
    t_0)))
double code(double A, double B, double C, double F) {
	double t_0 = pow(B, 2.0) - ((4.0 * A) * C);
	return -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / t_0;
}
real(8) function code(a, b, c, f)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8), intent (in) :: f
    real(8) :: t_0
    t_0 = (b ** 2.0d0) - ((4.0d0 * a) * c)
    code = -sqrt(((2.0d0 * (t_0 * f)) * ((a + c) + sqrt((((a - c) ** 2.0d0) + (b ** 2.0d0)))))) / t_0
end function
public static double code(double A, double B, double C, double F) {
	double t_0 = Math.pow(B, 2.0) - ((4.0 * A) * C);
	return -Math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / t_0;
}
def code(A, B, C, F):
	t_0 = math.pow(B, 2.0) - ((4.0 * A) * C)
	return -math.sqrt(((2.0 * (t_0 * F)) * ((A + C) + math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / t_0
function code(A, B, C, F)
	t_0 = Float64((B ^ 2.0) - Float64(Float64(4.0 * A) * C))
	return Float64(Float64(-sqrt(Float64(Float64(2.0 * Float64(t_0 * F)) * Float64(Float64(A + C) + sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0))))))) / t_0)
end
function tmp = code(A, B, C, F)
	t_0 = (B ^ 2.0) - ((4.0 * A) * C);
	tmp = -sqrt(((2.0 * (t_0 * F)) * ((A + C) + sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / t_0;
end
code[A_, B_, C_, F_] := Block[{t$95$0 = N[(N[Power[B, 2.0], $MachinePrecision] - N[(N[(4.0 * A), $MachinePrecision] * C), $MachinePrecision]), $MachinePrecision]}, N[((-N[Sqrt[N[(N[(2.0 * N[(t$95$0 * F), $MachinePrecision]), $MachinePrecision] * N[(N[(A + C), $MachinePrecision] + N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]) / t$95$0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {B}^{2} - \left(4 \cdot A\right) \cdot C\\
\frac{-\sqrt{\left(2 \cdot \left(t\_0 \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{t\_0}
\end{array}
\end{array}

Alternative 1: 57.2% accurate, 1.3× speedup?

\[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := C \cdot \left(A \cdot 4\right)\\ \mathbf{if}\;{B\_m}^{2} \leq 4 \cdot 10^{-18}:\\ \;\;\;\;\frac{\sqrt{\left(C \cdot 2\right) \cdot \left(\left(F \cdot \left({B\_m}^{2} - t\_0\right)\right) \cdot 2\right)}}{t\_0 - {B\_m}^{2}}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{F} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{-B\_m}\\ \end{array} \end{array} \]
B_m = (fabs.f64 B)
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
(FPCore (A B_m C F)
 :precision binary64
 (let* ((t_0 (* C (* A 4.0))))
   (if (<= (pow B_m 2.0) 4e-18)
     (/
      (sqrt (* (* C 2.0) (* (* F (- (pow B_m 2.0) t_0)) 2.0)))
      (- t_0 (pow B_m 2.0)))
     (* (sqrt F) (/ (sqrt (* (+ (hypot C B_m) C) 2.0)) (- B_m))))))
B_m = fabs(B);
assert(A < B_m && B_m < C && C < F);
double code(double A, double B_m, double C, double F) {
	double t_0 = C * (A * 4.0);
	double tmp;
	if (pow(B_m, 2.0) <= 4e-18) {
		tmp = sqrt(((C * 2.0) * ((F * (pow(B_m, 2.0) - t_0)) * 2.0))) / (t_0 - pow(B_m, 2.0));
	} else {
		tmp = sqrt(F) * (sqrt(((hypot(C, B_m) + C) * 2.0)) / -B_m);
	}
	return tmp;
}
B_m = Math.abs(B);
assert A < B_m && B_m < C && C < F;
public static double code(double A, double B_m, double C, double F) {
	double t_0 = C * (A * 4.0);
	double tmp;
	if (Math.pow(B_m, 2.0) <= 4e-18) {
		tmp = Math.sqrt(((C * 2.0) * ((F * (Math.pow(B_m, 2.0) - t_0)) * 2.0))) / (t_0 - Math.pow(B_m, 2.0));
	} else {
		tmp = Math.sqrt(F) * (Math.sqrt(((Math.hypot(C, B_m) + C) * 2.0)) / -B_m);
	}
	return tmp;
}
B_m = math.fabs(B)
[A, B_m, C, F] = sort([A, B_m, C, F])
def code(A, B_m, C, F):
	t_0 = C * (A * 4.0)
	tmp = 0
	if math.pow(B_m, 2.0) <= 4e-18:
		tmp = math.sqrt(((C * 2.0) * ((F * (math.pow(B_m, 2.0) - t_0)) * 2.0))) / (t_0 - math.pow(B_m, 2.0))
	else:
		tmp = math.sqrt(F) * (math.sqrt(((math.hypot(C, B_m) + C) * 2.0)) / -B_m)
	return tmp
B_m = abs(B)
A, B_m, C, F = sort([A, B_m, C, F])
function code(A, B_m, C, F)
	t_0 = Float64(C * Float64(A * 4.0))
	tmp = 0.0
	if ((B_m ^ 2.0) <= 4e-18)
		tmp = Float64(sqrt(Float64(Float64(C * 2.0) * Float64(Float64(F * Float64((B_m ^ 2.0) - t_0)) * 2.0))) / Float64(t_0 - (B_m ^ 2.0)));
	else
		tmp = Float64(sqrt(F) * Float64(sqrt(Float64(Float64(hypot(C, B_m) + C) * 2.0)) / Float64(-B_m)));
	end
	return tmp
end
B_m = abs(B);
A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
function tmp_2 = code(A, B_m, C, F)
	t_0 = C * (A * 4.0);
	tmp = 0.0;
	if ((B_m ^ 2.0) <= 4e-18)
		tmp = sqrt(((C * 2.0) * ((F * ((B_m ^ 2.0) - t_0)) * 2.0))) / (t_0 - (B_m ^ 2.0));
	else
		tmp = sqrt(F) * (sqrt(((hypot(C, B_m) + C) * 2.0)) / -B_m);
	end
	tmp_2 = tmp;
end
B_m = N[Abs[B], $MachinePrecision]
NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(C * N[(A * 4.0), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[Power[B$95$m, 2.0], $MachinePrecision], 4e-18], N[(N[Sqrt[N[(N[(C * 2.0), $MachinePrecision] * N[(N[(F * N[(N[Power[B$95$m, 2.0], $MachinePrecision] - t$95$0), $MachinePrecision]), $MachinePrecision] * 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[(t$95$0 - N[Power[B$95$m, 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[Sqrt[F], $MachinePrecision] * N[(N[Sqrt[N[(N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}
B_m = \left|B\right|
\\
[A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
\\
\begin{array}{l}
t_0 := C \cdot \left(A \cdot 4\right)\\
\mathbf{if}\;{B\_m}^{2} \leq 4 \cdot 10^{-18}:\\
\;\;\;\;\frac{\sqrt{\left(C \cdot 2\right) \cdot \left(\left(F \cdot \left({B\_m}^{2} - t\_0\right)\right) \cdot 2\right)}}{t\_0 - {B\_m}^{2}}\\

\mathbf{else}:\\
\;\;\;\;\sqrt{F} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{-B\_m}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (pow.f64 B #s(literal 2 binary64)) < 4.0000000000000003e-18

    1. Initial program 21.3%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in A around -inf

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    4. Step-by-step derivation
      1. lower-*.f6423.0

        \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    5. Applied rewrites23.0%

      \[\leadsto \frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \color{blue}{\left(2 \cdot C\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]

    if 4.0000000000000003e-18 < (pow.f64 B #s(literal 2 binary64))

    1. Initial program 14.7%

      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
    2. Add Preprocessing
    3. Taylor expanded in A around 0

      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
    4. Step-by-step derivation
      1. associate-*r*N/A

        \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
      2. lower-*.f64N/A

        \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
      3. mul-1-negN/A

        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
      4. lower-neg.f64N/A

        \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
      5. lower-/.f64N/A

        \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
      6. lower-sqrt.f64N/A

        \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
      7. lower-sqrt.f64N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
      8. *-commutativeN/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
      9. lower-*.f64N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
      10. +-commutativeN/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
      11. lower-+.f64N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
      12. +-commutativeN/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
      13. unpow2N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
      14. unpow2N/A

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
      15. lower-hypot.f6426.2

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
    5. Applied rewrites26.2%

      \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
    6. Step-by-step derivation
      1. Applied rewrites32.3%

        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
      2. Step-by-step derivation
        1. Applied rewrites32.3%

          \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
      3. Recombined 2 regimes into one program.
      4. Final simplification27.7%

        \[\leadsto \begin{array}{l} \mathbf{if}\;{B}^{2} \leq 4 \cdot 10^{-18}:\\ \;\;\;\;\frac{\sqrt{\left(C \cdot 2\right) \cdot \left(\left(F \cdot \left({B}^{2} - C \cdot \left(A \cdot 4\right)\right)\right) \cdot 2\right)}}{C \cdot \left(A \cdot 4\right) - {B}^{2}}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{F} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2}}{-B}\\ \end{array} \]
      5. Add Preprocessing

      Alternative 2: 56.7% accurate, 3.2× speedup?

      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)\\ \mathbf{if}\;B\_m \leq 3 \cdot 10^{-20}:\\ \;\;\;\;\frac{\sqrt{\left(t\_0 \cdot \left(F \cdot 2\right)\right) \cdot \left(\mathsf{fma}\left(\frac{B\_m \cdot B\_m}{A}, -0.5, C\right) + C\right)}}{-t\_0}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{F} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{-B\_m}\\ \end{array} \end{array} \]
      B_m = (fabs.f64 B)
      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
      (FPCore (A B_m C F)
       :precision binary64
       (let* ((t_0 (fma (* C A) -4.0 (* B_m B_m))))
         (if (<= B_m 3e-20)
           (/
            (sqrt (* (* t_0 (* F 2.0)) (+ (fma (/ (* B_m B_m) A) -0.5 C) C)))
            (- t_0))
           (* (sqrt F) (/ (sqrt (* (+ (hypot C B_m) C) 2.0)) (- B_m))))))
      B_m = fabs(B);
      assert(A < B_m && B_m < C && C < F);
      double code(double A, double B_m, double C, double F) {
      	double t_0 = fma((C * A), -4.0, (B_m * B_m));
      	double tmp;
      	if (B_m <= 3e-20) {
      		tmp = sqrt(((t_0 * (F * 2.0)) * (fma(((B_m * B_m) / A), -0.5, C) + C))) / -t_0;
      	} else {
      		tmp = sqrt(F) * (sqrt(((hypot(C, B_m) + C) * 2.0)) / -B_m);
      	}
      	return tmp;
      }
      
      B_m = abs(B)
      A, B_m, C, F = sort([A, B_m, C, F])
      function code(A, B_m, C, F)
      	t_0 = fma(Float64(C * A), -4.0, Float64(B_m * B_m))
      	tmp = 0.0
      	if (B_m <= 3e-20)
      		tmp = Float64(sqrt(Float64(Float64(t_0 * Float64(F * 2.0)) * Float64(fma(Float64(Float64(B_m * B_m) / A), -0.5, C) + C))) / Float64(-t_0));
      	else
      		tmp = Float64(sqrt(F) * Float64(sqrt(Float64(Float64(hypot(C, B_m) + C) * 2.0)) / Float64(-B_m)));
      	end
      	return tmp
      end
      
      B_m = N[Abs[B], $MachinePrecision]
      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
      code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(C * A), $MachinePrecision] * -4.0 + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[B$95$m, 3e-20], N[(N[Sqrt[N[(N[(t$95$0 * N[(F * 2.0), $MachinePrecision]), $MachinePrecision] * N[(N[(N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] * -0.5 + C), $MachinePrecision] + C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], N[(N[Sqrt[F], $MachinePrecision] * N[(N[Sqrt[N[(N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision]), $MachinePrecision]]]
      
      \begin{array}{l}
      B_m = \left|B\right|
      \\
      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
      \\
      \begin{array}{l}
      t_0 := \mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)\\
      \mathbf{if}\;B\_m \leq 3 \cdot 10^{-20}:\\
      \;\;\;\;\frac{\sqrt{\left(t\_0 \cdot \left(F \cdot 2\right)\right) \cdot \left(\mathsf{fma}\left(\frac{B\_m \cdot B\_m}{A}, -0.5, C\right) + C\right)}}{-t\_0}\\
      
      \mathbf{else}:\\
      \;\;\;\;\sqrt{F} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot 2}}{-B\_m}\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if B < 3.00000000000000029e-20

        1. Initial program 16.7%

          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. Add Preprocessing
        3. Step-by-step derivation
          1. lift-sqrt.f64N/A

            \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. lift-*.f64N/A

            \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          3. *-commutativeN/A

            \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          4. lift-*.f64N/A

            \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          5. lift-*.f64N/A

            \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          6. associate-*r*N/A

            \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          7. associate-*r*N/A

            \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          8. sqrt-prodN/A

            \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          9. pow1/2N/A

            \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \color{blue}{{F}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        4. Applied rewrites17.4%

          \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        5. Taylor expanded in A around -inf

          \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        6. Step-by-step derivation
          1. +-commutativeN/A

            \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + C\right)} + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          2. lower-fma.f64N/A

            \[\leadsto \frac{-\sqrt{\left(\color{blue}{\mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{A}, C\right)} + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          3. lower-/.f64N/A

            \[\leadsto \frac{-\sqrt{\left(\mathsf{fma}\left(\frac{-1}{2}, \color{blue}{\frac{{B}^{2}}{A}}, C\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          4. unpow2N/A

            \[\leadsto \frac{-\sqrt{\left(\mathsf{fma}\left(\frac{-1}{2}, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
          5. lower-*.f6413.6

            \[\leadsto \frac{-\sqrt{\left(\mathsf{fma}\left(-0.5, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        7. Applied rewrites13.6%

          \[\leadsto \frac{-\sqrt{\left(\color{blue}{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right)} + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        8. Applied rewrites15.4%

          \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, C\right) + C\right) \cdot \left(\left(F \cdot 2\right) \cdot \mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)\right)}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \]

        if 3.00000000000000029e-20 < B

        1. Initial program 21.5%

          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
        2. Add Preprocessing
        3. Taylor expanded in A around 0

          \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
        4. Step-by-step derivation
          1. associate-*r*N/A

            \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
          2. lower-*.f64N/A

            \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
          3. mul-1-negN/A

            \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
          4. lower-neg.f64N/A

            \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
          5. lower-/.f64N/A

            \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
          6. lower-sqrt.f64N/A

            \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
          7. lower-sqrt.f64N/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
          8. *-commutativeN/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
          9. lower-*.f64N/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
          10. +-commutativeN/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
          11. lower-+.f64N/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
          12. +-commutativeN/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
          13. unpow2N/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
          14. unpow2N/A

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
          15. lower-hypot.f6450.6

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
        5. Applied rewrites50.6%

          \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
        6. Step-by-step derivation
          1. Applied rewrites62.1%

            \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
          2. Step-by-step derivation
            1. Applied rewrites62.3%

              \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
          3. Recombined 2 regimes into one program.
          4. Final simplification27.7%

            \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 3 \cdot 10^{-20}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot \left(F \cdot 2\right)\right) \cdot \left(\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, C\right) + C\right)}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{F} \cdot \frac{\sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot 2}}{-B}\\ \end{array} \]
          5. Add Preprocessing

          Alternative 3: 52.6% accurate, 3.3× speedup?

          \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)\\ \mathbf{if}\;B\_m \leq 3 \cdot 10^{-20}:\\ \;\;\;\;\frac{\sqrt{\left(t\_0 \cdot \left(F \cdot 2\right)\right) \cdot \left(\mathsf{fma}\left(\frac{B\_m \cdot B\_m}{A}, -0.5, C\right) + C\right)}}{-t\_0}\\ \mathbf{elif}\;B\_m \leq 2.5 \cdot 10^{+152}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot F\right) \cdot 2}}{-B\_m}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(C + B\_m\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\ \end{array} \end{array} \]
          B_m = (fabs.f64 B)
          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
          (FPCore (A B_m C F)
           :precision binary64
           (let* ((t_0 (fma (* C A) -4.0 (* B_m B_m))))
             (if (<= B_m 3e-20)
               (/
                (sqrt (* (* t_0 (* F 2.0)) (+ (fma (/ (* B_m B_m) A) -0.5 C) C)))
                (- t_0))
               (if (<= B_m 2.5e+152)
                 (/ (sqrt (* (* (+ (hypot C B_m) C) F) 2.0)) (- B_m))
                 (* (/ (sqrt (* (+ C B_m) 2.0)) B_m) (- (sqrt F)))))))
          B_m = fabs(B);
          assert(A < B_m && B_m < C && C < F);
          double code(double A, double B_m, double C, double F) {
          	double t_0 = fma((C * A), -4.0, (B_m * B_m));
          	double tmp;
          	if (B_m <= 3e-20) {
          		tmp = sqrt(((t_0 * (F * 2.0)) * (fma(((B_m * B_m) / A), -0.5, C) + C))) / -t_0;
          	} else if (B_m <= 2.5e+152) {
          		tmp = sqrt((((hypot(C, B_m) + C) * F) * 2.0)) / -B_m;
          	} else {
          		tmp = (sqrt(((C + B_m) * 2.0)) / B_m) * -sqrt(F);
          	}
          	return tmp;
          }
          
          B_m = abs(B)
          A, B_m, C, F = sort([A, B_m, C, F])
          function code(A, B_m, C, F)
          	t_0 = fma(Float64(C * A), -4.0, Float64(B_m * B_m))
          	tmp = 0.0
          	if (B_m <= 3e-20)
          		tmp = Float64(sqrt(Float64(Float64(t_0 * Float64(F * 2.0)) * Float64(fma(Float64(Float64(B_m * B_m) / A), -0.5, C) + C))) / Float64(-t_0));
          	elseif (B_m <= 2.5e+152)
          		tmp = Float64(sqrt(Float64(Float64(Float64(hypot(C, B_m) + C) * F) * 2.0)) / Float64(-B_m));
          	else
          		tmp = Float64(Float64(sqrt(Float64(Float64(C + B_m) * 2.0)) / B_m) * Float64(-sqrt(F)));
          	end
          	return tmp
          end
          
          B_m = N[Abs[B], $MachinePrecision]
          NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
          code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(C * A), $MachinePrecision] * -4.0 + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[B$95$m, 3e-20], N[(N[Sqrt[N[(N[(t$95$0 * N[(F * 2.0), $MachinePrecision]), $MachinePrecision] * N[(N[(N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] * -0.5 + C), $MachinePrecision] + C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], If[LessEqual[B$95$m, 2.5e+152], N[(N[Sqrt[N[(N[(N[(N[Sqrt[C ^ 2 + B$95$m ^ 2], $MachinePrecision] + C), $MachinePrecision] * F), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / (-B$95$m)), $MachinePrecision], N[(N[(N[Sqrt[N[(N[(C + B$95$m), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / B$95$m), $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]]]]
          
          \begin{array}{l}
          B_m = \left|B\right|
          \\
          [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
          \\
          \begin{array}{l}
          t_0 := \mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)\\
          \mathbf{if}\;B\_m \leq 3 \cdot 10^{-20}:\\
          \;\;\;\;\frac{\sqrt{\left(t\_0 \cdot \left(F \cdot 2\right)\right) \cdot \left(\mathsf{fma}\left(\frac{B\_m \cdot B\_m}{A}, -0.5, C\right) + C\right)}}{-t\_0}\\
          
          \mathbf{elif}\;B\_m \leq 2.5 \cdot 10^{+152}:\\
          \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\_m\right) + C\right) \cdot F\right) \cdot 2}}{-B\_m}\\
          
          \mathbf{else}:\\
          \;\;\;\;\frac{\sqrt{\left(C + B\_m\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 3 regimes
          2. if B < 3.00000000000000029e-20

            1. Initial program 16.7%

              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            2. Add Preprocessing
            3. Step-by-step derivation
              1. lift-sqrt.f64N/A

                \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              2. lift-*.f64N/A

                \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              3. *-commutativeN/A

                \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              4. lift-*.f64N/A

                \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              5. lift-*.f64N/A

                \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              6. associate-*r*N/A

                \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              7. associate-*r*N/A

                \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              8. sqrt-prodN/A

                \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              9. pow1/2N/A

                \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \color{blue}{{F}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            4. Applied rewrites17.4%

              \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            5. Taylor expanded in A around -inf

              \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            6. Step-by-step derivation
              1. +-commutativeN/A

                \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + C\right)} + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              2. lower-fma.f64N/A

                \[\leadsto \frac{-\sqrt{\left(\color{blue}{\mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{A}, C\right)} + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              3. lower-/.f64N/A

                \[\leadsto \frac{-\sqrt{\left(\mathsf{fma}\left(\frac{-1}{2}, \color{blue}{\frac{{B}^{2}}{A}}, C\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              4. unpow2N/A

                \[\leadsto \frac{-\sqrt{\left(\mathsf{fma}\left(\frac{-1}{2}, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              5. lower-*.f6413.6

                \[\leadsto \frac{-\sqrt{\left(\mathsf{fma}\left(-0.5, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            7. Applied rewrites13.6%

              \[\leadsto \frac{-\sqrt{\left(\color{blue}{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right)} + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            8. Applied rewrites15.4%

              \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, C\right) + C\right) \cdot \left(\left(F \cdot 2\right) \cdot \mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)\right)}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \]

            if 3.00000000000000029e-20 < B < 2.5e152

            1. Initial program 45.0%

              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
            2. Add Preprocessing
            3. Taylor expanded in A around 0

              \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
            4. Step-by-step derivation
              1. associate-*r*N/A

                \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
              2. lower-*.f64N/A

                \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
              3. mul-1-negN/A

                \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
              4. lower-neg.f64N/A

                \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
              5. lower-/.f64N/A

                \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
              6. lower-sqrt.f64N/A

                \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
              7. lower-sqrt.f64N/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
              8. *-commutativeN/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
              9. lower-*.f64N/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
              10. +-commutativeN/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
              11. lower-+.f64N/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
              12. +-commutativeN/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
              13. unpow2N/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
              14. unpow2N/A

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
              15. lower-hypot.f6455.6

                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
            5. Applied rewrites55.6%

              \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
            6. Step-by-step derivation
              1. Applied rewrites55.8%

                \[\leadsto \frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{\color{blue}{-B}} \]

              if 2.5e152 < B

              1. Initial program 0.1%

                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
              2. Add Preprocessing
              3. Taylor expanded in A around 0

                \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
              4. Step-by-step derivation
                1. associate-*r*N/A

                  \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                2. lower-*.f64N/A

                  \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                3. mul-1-negN/A

                  \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                4. lower-neg.f64N/A

                  \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                5. lower-/.f64N/A

                  \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                6. lower-sqrt.f64N/A

                  \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                7. lower-sqrt.f64N/A

                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                8. *-commutativeN/A

                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                9. lower-*.f64N/A

                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                10. +-commutativeN/A

                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                11. lower-+.f64N/A

                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                12. +-commutativeN/A

                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                13. unpow2N/A

                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                14. unpow2N/A

                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                15. lower-hypot.f6446.0

                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
              5. Applied rewrites46.0%

                \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
              6. Step-by-step derivation
                1. Applied rewrites65.3%

                  \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                2. Step-by-step derivation
                  1. Applied rewrites65.4%

                    \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                  2. Taylor expanded in C around 0

                    \[\leadsto \frac{\sqrt{2 \cdot \left(B + C\right)}}{-B} \cdot \sqrt{F} \]
                  3. Step-by-step derivation
                    1. Applied rewrites62.8%

                      \[\leadsto \frac{\sqrt{2 \cdot \left(B + C\right)}}{-B} \cdot \sqrt{F} \]
                  4. Recombined 3 regimes into one program.
                  5. Final simplification26.9%

                    \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 3 \cdot 10^{-20}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot \left(F \cdot 2\right)\right) \cdot \left(\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, C\right) + C\right)}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}\\ \mathbf{elif}\;B \leq 2.5 \cdot 10^{+152}:\\ \;\;\;\;\frac{\sqrt{\left(\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F\right) \cdot 2}}{-B}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(C + B\right) \cdot 2}}{B} \cdot \left(-\sqrt{F}\right)\\ \end{array} \]
                  6. Add Preprocessing

                  Alternative 4: 51.7% accurate, 4.8× speedup?

                  \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} t_0 := \mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)\\ \mathbf{if}\;B\_m \leq 4.5 \cdot 10^{-20}:\\ \;\;\;\;\frac{\sqrt{\left(t\_0 \cdot \left(F \cdot 2\right)\right) \cdot \left(\mathsf{fma}\left(\frac{B\_m \cdot B\_m}{A}, -0.5, C\right) + C\right)}}{-t\_0}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(C + B\_m\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\ \end{array} \end{array} \]
                  B_m = (fabs.f64 B)
                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                  (FPCore (A B_m C F)
                   :precision binary64
                   (let* ((t_0 (fma (* C A) -4.0 (* B_m B_m))))
                     (if (<= B_m 4.5e-20)
                       (/
                        (sqrt (* (* t_0 (* F 2.0)) (+ (fma (/ (* B_m B_m) A) -0.5 C) C)))
                        (- t_0))
                       (* (/ (sqrt (* (+ C B_m) 2.0)) B_m) (- (sqrt F))))))
                  B_m = fabs(B);
                  assert(A < B_m && B_m < C && C < F);
                  double code(double A, double B_m, double C, double F) {
                  	double t_0 = fma((C * A), -4.0, (B_m * B_m));
                  	double tmp;
                  	if (B_m <= 4.5e-20) {
                  		tmp = sqrt(((t_0 * (F * 2.0)) * (fma(((B_m * B_m) / A), -0.5, C) + C))) / -t_0;
                  	} else {
                  		tmp = (sqrt(((C + B_m) * 2.0)) / B_m) * -sqrt(F);
                  	}
                  	return tmp;
                  }
                  
                  B_m = abs(B)
                  A, B_m, C, F = sort([A, B_m, C, F])
                  function code(A, B_m, C, F)
                  	t_0 = fma(Float64(C * A), -4.0, Float64(B_m * B_m))
                  	tmp = 0.0
                  	if (B_m <= 4.5e-20)
                  		tmp = Float64(sqrt(Float64(Float64(t_0 * Float64(F * 2.0)) * Float64(fma(Float64(Float64(B_m * B_m) / A), -0.5, C) + C))) / Float64(-t_0));
                  	else
                  		tmp = Float64(Float64(sqrt(Float64(Float64(C + B_m) * 2.0)) / B_m) * Float64(-sqrt(F)));
                  	end
                  	return tmp
                  end
                  
                  B_m = N[Abs[B], $MachinePrecision]
                  NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                  code[A_, B$95$m_, C_, F_] := Block[{t$95$0 = N[(N[(C * A), $MachinePrecision] * -4.0 + N[(B$95$m * B$95$m), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[B$95$m, 4.5e-20], N[(N[Sqrt[N[(N[(t$95$0 * N[(F * 2.0), $MachinePrecision]), $MachinePrecision] * N[(N[(N[(N[(B$95$m * B$95$m), $MachinePrecision] / A), $MachinePrecision] * -0.5 + C), $MachinePrecision] + C), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / (-t$95$0)), $MachinePrecision], N[(N[(N[Sqrt[N[(N[(C + B$95$m), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / B$95$m), $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]]]
                  
                  \begin{array}{l}
                  B_m = \left|B\right|
                  \\
                  [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                  \\
                  \begin{array}{l}
                  t_0 := \mathsf{fma}\left(C \cdot A, -4, B\_m \cdot B\_m\right)\\
                  \mathbf{if}\;B\_m \leq 4.5 \cdot 10^{-20}:\\
                  \;\;\;\;\frac{\sqrt{\left(t\_0 \cdot \left(F \cdot 2\right)\right) \cdot \left(\mathsf{fma}\left(\frac{B\_m \cdot B\_m}{A}, -0.5, C\right) + C\right)}}{-t\_0}\\
                  
                  \mathbf{else}:\\
                  \;\;\;\;\frac{\sqrt{\left(C + B\_m\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\
                  
                  
                  \end{array}
                  \end{array}
                  
                  Derivation
                  1. Split input into 2 regimes
                  2. if B < 4.5000000000000001e-20

                    1. Initial program 16.7%

                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    2. Add Preprocessing
                    3. Step-by-step derivation
                      1. lift-sqrt.f64N/A

                        \[\leadsto \frac{-\color{blue}{\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      2. lift-*.f64N/A

                        \[\leadsto \frac{-\sqrt{\color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      3. *-commutativeN/A

                        \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      4. lift-*.f64N/A

                        \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      5. lift-*.f64N/A

                        \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \color{blue}{\left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      6. associate-*r*N/A

                        \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \color{blue}{\left(\left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right) \cdot F\right)}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      7. associate-*r*N/A

                        \[\leadsto \frac{-\sqrt{\color{blue}{\left(\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)\right) \cdot F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      8. sqrt-prodN/A

                        \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      9. pow1/2N/A

                        \[\leadsto \frac{-\sqrt{\left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right) \cdot \left(2 \cdot \left({B}^{2} - \left(4 \cdot A\right) \cdot C\right)\right)} \cdot \color{blue}{{F}^{\frac{1}{2}}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    4. Applied rewrites17.4%

                      \[\leadsto \frac{-\color{blue}{\sqrt{\left(\left(\mathsf{hypot}\left(A - C, B\right) + A\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    5. Taylor expanded in A around -inf

                      \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(C + \frac{-1}{2} \cdot \frac{{B}^{2}}{A}\right)} + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    6. Step-by-step derivation
                      1. +-commutativeN/A

                        \[\leadsto \frac{-\sqrt{\left(\color{blue}{\left(\frac{-1}{2} \cdot \frac{{B}^{2}}{A} + C\right)} + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      2. lower-fma.f64N/A

                        \[\leadsto \frac{-\sqrt{\left(\color{blue}{\mathsf{fma}\left(\frac{-1}{2}, \frac{{B}^{2}}{A}, C\right)} + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      3. lower-/.f64N/A

                        \[\leadsto \frac{-\sqrt{\left(\mathsf{fma}\left(\frac{-1}{2}, \color{blue}{\frac{{B}^{2}}{A}}, C\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      4. unpow2N/A

                        \[\leadsto \frac{-\sqrt{\left(\mathsf{fma}\left(\frac{-1}{2}, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                      5. lower-*.f6413.6

                        \[\leadsto \frac{-\sqrt{\left(\mathsf{fma}\left(-0.5, \frac{\color{blue}{B \cdot B}}{A}, C\right) + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    7. Applied rewrites13.6%

                      \[\leadsto \frac{-\sqrt{\left(\color{blue}{\mathsf{fma}\left(-0.5, \frac{B \cdot B}{A}, C\right)} + C\right) \cdot \left(\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right) \cdot 2\right)} \cdot \sqrt{F}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    8. Applied rewrites15.4%

                      \[\leadsto \color{blue}{\frac{\sqrt{\left(\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, C\right) + C\right) \cdot \left(\left(F \cdot 2\right) \cdot \mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)\right)}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}} \]

                    if 4.5000000000000001e-20 < B

                    1. Initial program 21.5%

                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                    2. Add Preprocessing
                    3. Taylor expanded in A around 0

                      \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                    4. Step-by-step derivation
                      1. associate-*r*N/A

                        \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                      2. lower-*.f64N/A

                        \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                      3. mul-1-negN/A

                        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                      4. lower-neg.f64N/A

                        \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                      5. lower-/.f64N/A

                        \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                      6. lower-sqrt.f64N/A

                        \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                      7. lower-sqrt.f64N/A

                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                      8. *-commutativeN/A

                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                      9. lower-*.f64N/A

                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                      10. +-commutativeN/A

                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                      11. lower-+.f64N/A

                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                      12. +-commutativeN/A

                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                      13. unpow2N/A

                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                      14. unpow2N/A

                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                      15. lower-hypot.f6450.6

                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                    5. Applied rewrites50.6%

                      \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                    6. Step-by-step derivation
                      1. Applied rewrites62.1%

                        \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                      2. Step-by-step derivation
                        1. Applied rewrites62.3%

                          \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                        2. Taylor expanded in C around 0

                          \[\leadsto \frac{\sqrt{2 \cdot \left(B + C\right)}}{-B} \cdot \sqrt{F} \]
                        3. Step-by-step derivation
                          1. Applied rewrites55.8%

                            \[\leadsto \frac{\sqrt{2 \cdot \left(B + C\right)}}{-B} \cdot \sqrt{F} \]
                        4. Recombined 2 regimes into one program.
                        5. Final simplification26.0%

                          \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 4.5 \cdot 10^{-20}:\\ \;\;\;\;\frac{\sqrt{\left(\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right) \cdot \left(F \cdot 2\right)\right) \cdot \left(\mathsf{fma}\left(\frac{B \cdot B}{A}, -0.5, C\right) + C\right)}}{-\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(C + B\right) \cdot 2}}{B} \cdot \left(-\sqrt{F}\right)\\ \end{array} \]
                        6. Add Preprocessing

                        Alternative 5: 48.1% accurate, 9.3× speedup?

                        \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;B\_m \leq 1.65 \cdot 10^{-16}:\\ \;\;\;\;-\sqrt{\frac{-F}{A}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(C + B\_m\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\ \end{array} \end{array} \]
                        B_m = (fabs.f64 B)
                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                        (FPCore (A B_m C F)
                         :precision binary64
                         (if (<= B_m 1.65e-16)
                           (- (sqrt (/ (- F) A)))
                           (* (/ (sqrt (* (+ C B_m) 2.0)) B_m) (- (sqrt F)))))
                        B_m = fabs(B);
                        assert(A < B_m && B_m < C && C < F);
                        double code(double A, double B_m, double C, double F) {
                        	double tmp;
                        	if (B_m <= 1.65e-16) {
                        		tmp = -sqrt((-F / A));
                        	} else {
                        		tmp = (sqrt(((C + B_m) * 2.0)) / B_m) * -sqrt(F);
                        	}
                        	return tmp;
                        }
                        
                        B_m = abs(b)
                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                        real(8) function code(a, b_m, c, f)
                            real(8), intent (in) :: a
                            real(8), intent (in) :: b_m
                            real(8), intent (in) :: c
                            real(8), intent (in) :: f
                            real(8) :: tmp
                            if (b_m <= 1.65d-16) then
                                tmp = -sqrt((-f / a))
                            else
                                tmp = (sqrt(((c + b_m) * 2.0d0)) / b_m) * -sqrt(f)
                            end if
                            code = tmp
                        end function
                        
                        B_m = Math.abs(B);
                        assert A < B_m && B_m < C && C < F;
                        public static double code(double A, double B_m, double C, double F) {
                        	double tmp;
                        	if (B_m <= 1.65e-16) {
                        		tmp = -Math.sqrt((-F / A));
                        	} else {
                        		tmp = (Math.sqrt(((C + B_m) * 2.0)) / B_m) * -Math.sqrt(F);
                        	}
                        	return tmp;
                        }
                        
                        B_m = math.fabs(B)
                        [A, B_m, C, F] = sort([A, B_m, C, F])
                        def code(A, B_m, C, F):
                        	tmp = 0
                        	if B_m <= 1.65e-16:
                        		tmp = -math.sqrt((-F / A))
                        	else:
                        		tmp = (math.sqrt(((C + B_m) * 2.0)) / B_m) * -math.sqrt(F)
                        	return tmp
                        
                        B_m = abs(B)
                        A, B_m, C, F = sort([A, B_m, C, F])
                        function code(A, B_m, C, F)
                        	tmp = 0.0
                        	if (B_m <= 1.65e-16)
                        		tmp = Float64(-sqrt(Float64(Float64(-F) / A)));
                        	else
                        		tmp = Float64(Float64(sqrt(Float64(Float64(C + B_m) * 2.0)) / B_m) * Float64(-sqrt(F)));
                        	end
                        	return tmp
                        end
                        
                        B_m = abs(B);
                        A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                        function tmp_2 = code(A, B_m, C, F)
                        	tmp = 0.0;
                        	if (B_m <= 1.65e-16)
                        		tmp = -sqrt((-F / A));
                        	else
                        		tmp = (sqrt(((C + B_m) * 2.0)) / B_m) * -sqrt(F);
                        	end
                        	tmp_2 = tmp;
                        end
                        
                        B_m = N[Abs[B], $MachinePrecision]
                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                        code[A_, B$95$m_, C_, F_] := If[LessEqual[B$95$m, 1.65e-16], (-N[Sqrt[N[((-F) / A), $MachinePrecision]], $MachinePrecision]), N[(N[(N[Sqrt[N[(N[(C + B$95$m), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision] / B$95$m), $MachinePrecision] * (-N[Sqrt[F], $MachinePrecision])), $MachinePrecision]]
                        
                        \begin{array}{l}
                        B_m = \left|B\right|
                        \\
                        [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                        \\
                        \begin{array}{l}
                        \mathbf{if}\;B\_m \leq 1.65 \cdot 10^{-16}:\\
                        \;\;\;\;-\sqrt{\frac{-F}{A}}\\
                        
                        \mathbf{else}:\\
                        \;\;\;\;\frac{\sqrt{\left(C + B\_m\right) \cdot 2}}{B\_m} \cdot \left(-\sqrt{F}\right)\\
                        
                        
                        \end{array}
                        \end{array}
                        
                        Derivation
                        1. Split input into 2 regimes
                        2. if B < 1.64999999999999994e-16

                          1. Initial program 16.7%

                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                          2. Add Preprocessing
                          3. Taylor expanded in F around 0

                            \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                          4. Step-by-step derivation
                            1. mul-1-negN/A

                              \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                            2. *-commutativeN/A

                              \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}}\right) \]
                            3. distribute-lft-neg-inN/A

                              \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                            4. lower-*.f64N/A

                              \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                            5. lower-neg.f64N/A

                              \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \]
                            6. lower-sqrt.f64N/A

                              \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \]
                            7. lower-sqrt.f64N/A

                              \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                            8. lower-/.f64N/A

                              \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                          5. Applied rewrites21.6%

                            \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}} \]
                          6. Applied rewrites19.1%

                            \[\leadsto \color{blue}{-\sqrt{\left(\frac{F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \cdot \left(\mathsf{hypot}\left(A - C, B\right) + \left(C + A\right)\right)\right) \cdot 2}} \]
                          7. Taylor expanded in A around -inf

                            \[\leadsto -\sqrt{-1 \cdot \frac{F}{A}} \]
                          8. Step-by-step derivation
                            1. Applied rewrites20.4%

                              \[\leadsto -\sqrt{-\frac{F}{A}} \]

                            if 1.64999999999999994e-16 < B

                            1. Initial program 21.5%

                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                            2. Add Preprocessing
                            3. Taylor expanded in A around 0

                              \[\leadsto \color{blue}{-1 \cdot \left(\frac{\sqrt{2}}{B} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}\right)} \]
                            4. Step-by-step derivation
                              1. associate-*r*N/A

                                \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                              2. lower-*.f64N/A

                                \[\leadsto \color{blue}{\left(-1 \cdot \frac{\sqrt{2}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                              3. mul-1-negN/A

                                \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\frac{\sqrt{2}}{B}\right)\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                              4. lower-neg.f64N/A

                                \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right)} \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                              5. lower-/.f64N/A

                                \[\leadsto \left(-\color{blue}{\frac{\sqrt{2}}{B}}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                              6. lower-sqrt.f64N/A

                                \[\leadsto \left(-\frac{\color{blue}{\sqrt{2}}}{B}\right) \cdot \sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)} \]
                              7. lower-sqrt.f64N/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \color{blue}{\sqrt{F \cdot \left(C + \sqrt{{B}^{2} + {C}^{2}}\right)}} \]
                              8. *-commutativeN/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                              9. lower-*.f64N/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(C + \sqrt{{B}^{2} + {C}^{2}}\right) \cdot F}} \]
                              10. +-commutativeN/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                              11. lower-+.f64N/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\color{blue}{\left(\sqrt{{B}^{2} + {C}^{2}} + C\right)} \cdot F} \]
                              12. +-commutativeN/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{{C}^{2} + {B}^{2}}} + C\right) \cdot F} \]
                              13. unpow2N/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{\color{blue}{C \cdot C} + {B}^{2}} + C\right) \cdot F} \]
                              14. unpow2N/A

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\sqrt{C \cdot C + \color{blue}{B \cdot B}} + C\right) \cdot F} \]
                              15. lower-hypot.f6450.6

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\color{blue}{\mathsf{hypot}\left(C, B\right)} + C\right) \cdot F} \]
                            5. Applied rewrites50.6%

                              \[\leadsto \color{blue}{\left(-\frac{\sqrt{2}}{B}\right) \cdot \sqrt{\left(\mathsf{hypot}\left(C, B\right) + C\right) \cdot F}} \]
                            6. Step-by-step derivation
                              1. Applied rewrites62.1%

                                \[\leadsto \left(-\frac{\sqrt{2}}{B}\right) \cdot \left(\sqrt{\mathsf{hypot}\left(C, B\right) + C} \cdot \color{blue}{\sqrt{F}}\right) \]
                              2. Step-by-step derivation
                                1. Applied rewrites62.3%

                                  \[\leadsto \frac{\sqrt{2 \cdot \left(\mathsf{hypot}\left(C, B\right) + C\right)}}{-B} \cdot \color{blue}{\sqrt{F}} \]
                                2. Taylor expanded in C around 0

                                  \[\leadsto \frac{\sqrt{2 \cdot \left(B + C\right)}}{-B} \cdot \sqrt{F} \]
                                3. Step-by-step derivation
                                  1. Applied rewrites55.8%

                                    \[\leadsto \frac{\sqrt{2 \cdot \left(B + C\right)}}{-B} \cdot \sqrt{F} \]
                                4. Recombined 2 regimes into one program.
                                5. Final simplification29.6%

                                  \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 1.65 \cdot 10^{-16}:\\ \;\;\;\;-\sqrt{\frac{-F}{A}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\left(C + B\right) \cdot 2}}{B} \cdot \left(-\sqrt{F}\right)\\ \end{array} \]
                                6. Add Preprocessing

                                Alternative 6: 47.3% accurate, 10.9× speedup?

                                \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;B\_m \leq 1.65 \cdot 10^{-16}:\\ \;\;\;\;-\sqrt{\frac{-F}{A}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{F \cdot 2}}{-\sqrt{B\_m}}\\ \end{array} \end{array} \]
                                B_m = (fabs.f64 B)
                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                (FPCore (A B_m C F)
                                 :precision binary64
                                 (if (<= B_m 1.65e-16)
                                   (- (sqrt (/ (- F) A)))
                                   (/ (sqrt (* F 2.0)) (- (sqrt B_m)))))
                                B_m = fabs(B);
                                assert(A < B_m && B_m < C && C < F);
                                double code(double A, double B_m, double C, double F) {
                                	double tmp;
                                	if (B_m <= 1.65e-16) {
                                		tmp = -sqrt((-F / A));
                                	} else {
                                		tmp = sqrt((F * 2.0)) / -sqrt(B_m);
                                	}
                                	return tmp;
                                }
                                
                                B_m = abs(b)
                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                real(8) function code(a, b_m, c, f)
                                    real(8), intent (in) :: a
                                    real(8), intent (in) :: b_m
                                    real(8), intent (in) :: c
                                    real(8), intent (in) :: f
                                    real(8) :: tmp
                                    if (b_m <= 1.65d-16) then
                                        tmp = -sqrt((-f / a))
                                    else
                                        tmp = sqrt((f * 2.0d0)) / -sqrt(b_m)
                                    end if
                                    code = tmp
                                end function
                                
                                B_m = Math.abs(B);
                                assert A < B_m && B_m < C && C < F;
                                public static double code(double A, double B_m, double C, double F) {
                                	double tmp;
                                	if (B_m <= 1.65e-16) {
                                		tmp = -Math.sqrt((-F / A));
                                	} else {
                                		tmp = Math.sqrt((F * 2.0)) / -Math.sqrt(B_m);
                                	}
                                	return tmp;
                                }
                                
                                B_m = math.fabs(B)
                                [A, B_m, C, F] = sort([A, B_m, C, F])
                                def code(A, B_m, C, F):
                                	tmp = 0
                                	if B_m <= 1.65e-16:
                                		tmp = -math.sqrt((-F / A))
                                	else:
                                		tmp = math.sqrt((F * 2.0)) / -math.sqrt(B_m)
                                	return tmp
                                
                                B_m = abs(B)
                                A, B_m, C, F = sort([A, B_m, C, F])
                                function code(A, B_m, C, F)
                                	tmp = 0.0
                                	if (B_m <= 1.65e-16)
                                		tmp = Float64(-sqrt(Float64(Float64(-F) / A)));
                                	else
                                		tmp = Float64(sqrt(Float64(F * 2.0)) / Float64(-sqrt(B_m)));
                                	end
                                	return tmp
                                end
                                
                                B_m = abs(B);
                                A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                function tmp_2 = code(A, B_m, C, F)
                                	tmp = 0.0;
                                	if (B_m <= 1.65e-16)
                                		tmp = -sqrt((-F / A));
                                	else
                                		tmp = sqrt((F * 2.0)) / -sqrt(B_m);
                                	end
                                	tmp_2 = tmp;
                                end
                                
                                B_m = N[Abs[B], $MachinePrecision]
                                NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                code[A_, B$95$m_, C_, F_] := If[LessEqual[B$95$m, 1.65e-16], (-N[Sqrt[N[((-F) / A), $MachinePrecision]], $MachinePrecision]), N[(N[Sqrt[N[(F * 2.0), $MachinePrecision]], $MachinePrecision] / (-N[Sqrt[B$95$m], $MachinePrecision])), $MachinePrecision]]
                                
                                \begin{array}{l}
                                B_m = \left|B\right|
                                \\
                                [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                \\
                                \begin{array}{l}
                                \mathbf{if}\;B\_m \leq 1.65 \cdot 10^{-16}:\\
                                \;\;\;\;-\sqrt{\frac{-F}{A}}\\
                                
                                \mathbf{else}:\\
                                \;\;\;\;\frac{\sqrt{F \cdot 2}}{-\sqrt{B\_m}}\\
                                
                                
                                \end{array}
                                \end{array}
                                
                                Derivation
                                1. Split input into 2 regimes
                                2. if B < 1.64999999999999994e-16

                                  1. Initial program 16.7%

                                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in F around 0

                                    \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                  4. Step-by-step derivation
                                    1. mul-1-negN/A

                                      \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                    2. *-commutativeN/A

                                      \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}}\right) \]
                                    3. distribute-lft-neg-inN/A

                                      \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                                    4. lower-*.f64N/A

                                      \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                                    5. lower-neg.f64N/A

                                      \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \]
                                    6. lower-sqrt.f64N/A

                                      \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \]
                                    7. lower-sqrt.f64N/A

                                      \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                                    8. lower-/.f64N/A

                                      \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                                  5. Applied rewrites21.6%

                                    \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}} \]
                                  6. Applied rewrites19.1%

                                    \[\leadsto \color{blue}{-\sqrt{\left(\frac{F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \cdot \left(\mathsf{hypot}\left(A - C, B\right) + \left(C + A\right)\right)\right) \cdot 2}} \]
                                  7. Taylor expanded in A around -inf

                                    \[\leadsto -\sqrt{-1 \cdot \frac{F}{A}} \]
                                  8. Step-by-step derivation
                                    1. Applied rewrites20.4%

                                      \[\leadsto -\sqrt{-\frac{F}{A}} \]

                                    if 1.64999999999999994e-16 < B

                                    1. Initial program 21.5%

                                      \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                    2. Add Preprocessing
                                    3. Taylor expanded in B around inf

                                      \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                    4. Step-by-step derivation
                                      1. mul-1-negN/A

                                        \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                      2. *-commutativeN/A

                                        \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                      3. distribute-lft-neg-inN/A

                                        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                      4. lower-*.f64N/A

                                        \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                      5. lower-neg.f64N/A

                                        \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
                                      6. lower-sqrt.f64N/A

                                        \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
                                      7. lower-sqrt.f64N/A

                                        \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
                                      8. lower-/.f6441.7

                                        \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                    5. Applied rewrites41.7%

                                      \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
                                    6. Step-by-step derivation
                                      1. Applied rewrites41.9%

                                        \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                      2. Step-by-step derivation
                                        1. Applied rewrites56.1%

                                          \[\leadsto -\frac{\sqrt{F \cdot 2}}{\sqrt{B}} \]
                                      3. Recombined 2 regimes into one program.
                                      4. Final simplification29.7%

                                        \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 1.65 \cdot 10^{-16}:\\ \;\;\;\;-\sqrt{\frac{-F}{A}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{F \cdot 2}}{-\sqrt{B}}\\ \end{array} \]
                                      5. Add Preprocessing

                                      Alternative 7: 47.3% accurate, 10.9× speedup?

                                      \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;B\_m \leq 1.65 \cdot 10^{-16}:\\ \;\;\;\;-\sqrt{\frac{-F}{A}}\\ \mathbf{else}:\\ \;\;\;\;\frac{-\sqrt{F}}{\sqrt{0.5 \cdot B\_m}}\\ \end{array} \end{array} \]
                                      B_m = (fabs.f64 B)
                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                      (FPCore (A B_m C F)
                                       :precision binary64
                                       (if (<= B_m 1.65e-16)
                                         (- (sqrt (/ (- F) A)))
                                         (/ (- (sqrt F)) (sqrt (* 0.5 B_m)))))
                                      B_m = fabs(B);
                                      assert(A < B_m && B_m < C && C < F);
                                      double code(double A, double B_m, double C, double F) {
                                      	double tmp;
                                      	if (B_m <= 1.65e-16) {
                                      		tmp = -sqrt((-F / A));
                                      	} else {
                                      		tmp = -sqrt(F) / sqrt((0.5 * B_m));
                                      	}
                                      	return tmp;
                                      }
                                      
                                      B_m = abs(b)
                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                      real(8) function code(a, b_m, c, f)
                                          real(8), intent (in) :: a
                                          real(8), intent (in) :: b_m
                                          real(8), intent (in) :: c
                                          real(8), intent (in) :: f
                                          real(8) :: tmp
                                          if (b_m <= 1.65d-16) then
                                              tmp = -sqrt((-f / a))
                                          else
                                              tmp = -sqrt(f) / sqrt((0.5d0 * b_m))
                                          end if
                                          code = tmp
                                      end function
                                      
                                      B_m = Math.abs(B);
                                      assert A < B_m && B_m < C && C < F;
                                      public static double code(double A, double B_m, double C, double F) {
                                      	double tmp;
                                      	if (B_m <= 1.65e-16) {
                                      		tmp = -Math.sqrt((-F / A));
                                      	} else {
                                      		tmp = -Math.sqrt(F) / Math.sqrt((0.5 * B_m));
                                      	}
                                      	return tmp;
                                      }
                                      
                                      B_m = math.fabs(B)
                                      [A, B_m, C, F] = sort([A, B_m, C, F])
                                      def code(A, B_m, C, F):
                                      	tmp = 0
                                      	if B_m <= 1.65e-16:
                                      		tmp = -math.sqrt((-F / A))
                                      	else:
                                      		tmp = -math.sqrt(F) / math.sqrt((0.5 * B_m))
                                      	return tmp
                                      
                                      B_m = abs(B)
                                      A, B_m, C, F = sort([A, B_m, C, F])
                                      function code(A, B_m, C, F)
                                      	tmp = 0.0
                                      	if (B_m <= 1.65e-16)
                                      		tmp = Float64(-sqrt(Float64(Float64(-F) / A)));
                                      	else
                                      		tmp = Float64(Float64(-sqrt(F)) / sqrt(Float64(0.5 * B_m)));
                                      	end
                                      	return tmp
                                      end
                                      
                                      B_m = abs(B);
                                      A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                      function tmp_2 = code(A, B_m, C, F)
                                      	tmp = 0.0;
                                      	if (B_m <= 1.65e-16)
                                      		tmp = -sqrt((-F / A));
                                      	else
                                      		tmp = -sqrt(F) / sqrt((0.5 * B_m));
                                      	end
                                      	tmp_2 = tmp;
                                      end
                                      
                                      B_m = N[Abs[B], $MachinePrecision]
                                      NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                      code[A_, B$95$m_, C_, F_] := If[LessEqual[B$95$m, 1.65e-16], (-N[Sqrt[N[((-F) / A), $MachinePrecision]], $MachinePrecision]), N[((-N[Sqrt[F], $MachinePrecision]) / N[Sqrt[N[(0.5 * B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]
                                      
                                      \begin{array}{l}
                                      B_m = \left|B\right|
                                      \\
                                      [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                      \\
                                      \begin{array}{l}
                                      \mathbf{if}\;B\_m \leq 1.65 \cdot 10^{-16}:\\
                                      \;\;\;\;-\sqrt{\frac{-F}{A}}\\
                                      
                                      \mathbf{else}:\\
                                      \;\;\;\;\frac{-\sqrt{F}}{\sqrt{0.5 \cdot B\_m}}\\
                                      
                                      
                                      \end{array}
                                      \end{array}
                                      
                                      Derivation
                                      1. Split input into 2 regimes
                                      2. if B < 1.64999999999999994e-16

                                        1. Initial program 16.7%

                                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                        2. Add Preprocessing
                                        3. Taylor expanded in F around 0

                                          \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                        4. Step-by-step derivation
                                          1. mul-1-negN/A

                                            \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                          2. *-commutativeN/A

                                            \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}}\right) \]
                                          3. distribute-lft-neg-inN/A

                                            \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                                          4. lower-*.f64N/A

                                            \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                                          5. lower-neg.f64N/A

                                            \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \]
                                          6. lower-sqrt.f64N/A

                                            \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \]
                                          7. lower-sqrt.f64N/A

                                            \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                                          8. lower-/.f64N/A

                                            \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                                        5. Applied rewrites21.6%

                                          \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}} \]
                                        6. Applied rewrites19.1%

                                          \[\leadsto \color{blue}{-\sqrt{\left(\frac{F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \cdot \left(\mathsf{hypot}\left(A - C, B\right) + \left(C + A\right)\right)\right) \cdot 2}} \]
                                        7. Taylor expanded in A around -inf

                                          \[\leadsto -\sqrt{-1 \cdot \frac{F}{A}} \]
                                        8. Step-by-step derivation
                                          1. Applied rewrites20.4%

                                            \[\leadsto -\sqrt{-\frac{F}{A}} \]

                                          if 1.64999999999999994e-16 < B

                                          1. Initial program 21.5%

                                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                          2. Add Preprocessing
                                          3. Taylor expanded in B around inf

                                            \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                          4. Step-by-step derivation
                                            1. mul-1-negN/A

                                              \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                            2. *-commutativeN/A

                                              \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                            3. distribute-lft-neg-inN/A

                                              \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                            4. lower-*.f64N/A

                                              \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                            5. lower-neg.f64N/A

                                              \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
                                            6. lower-sqrt.f64N/A

                                              \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
                                            7. lower-sqrt.f64N/A

                                              \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
                                            8. lower-/.f6441.7

                                              \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                          5. Applied rewrites41.7%

                                            \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
                                          6. Step-by-step derivation
                                            1. Applied rewrites41.9%

                                              \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                            2. Step-by-step derivation
                                              1. Applied rewrites41.9%

                                                \[\leadsto -\sqrt{F \cdot \frac{2}{B}} \]
                                              2. Step-by-step derivation
                                                1. Applied rewrites56.1%

                                                  \[\leadsto -\frac{\sqrt{F}}{\sqrt{B \cdot 0.5}} \]
                                              3. Recombined 2 regimes into one program.
                                              4. Final simplification29.7%

                                                \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 1.65 \cdot 10^{-16}:\\ \;\;\;\;-\sqrt{\frac{-F}{A}}\\ \mathbf{else}:\\ \;\;\;\;\frac{-\sqrt{F}}{\sqrt{0.5 \cdot B}}\\ \end{array} \]
                                              5. Add Preprocessing

                                              Alternative 8: 47.3% accurate, 10.9× speedup?

                                              \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;B\_m \leq 1.65 \cdot 10^{-16}:\\ \;\;\;\;-\sqrt{\frac{-F}{A}}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\ \end{array} \end{array} \]
                                              B_m = (fabs.f64 B)
                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                              (FPCore (A B_m C F)
                                               :precision binary64
                                               (if (<= B_m 1.65e-16)
                                                 (- (sqrt (/ (- F) A)))
                                                 (* (- (sqrt F)) (sqrt (/ 2.0 B_m)))))
                                              B_m = fabs(B);
                                              assert(A < B_m && B_m < C && C < F);
                                              double code(double A, double B_m, double C, double F) {
                                              	double tmp;
                                              	if (B_m <= 1.65e-16) {
                                              		tmp = -sqrt((-F / A));
                                              	} else {
                                              		tmp = -sqrt(F) * sqrt((2.0 / B_m));
                                              	}
                                              	return tmp;
                                              }
                                              
                                              B_m = abs(b)
                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                              real(8) function code(a, b_m, c, f)
                                                  real(8), intent (in) :: a
                                                  real(8), intent (in) :: b_m
                                                  real(8), intent (in) :: c
                                                  real(8), intent (in) :: f
                                                  real(8) :: tmp
                                                  if (b_m <= 1.65d-16) then
                                                      tmp = -sqrt((-f / a))
                                                  else
                                                      tmp = -sqrt(f) * sqrt((2.0d0 / b_m))
                                                  end if
                                                  code = tmp
                                              end function
                                              
                                              B_m = Math.abs(B);
                                              assert A < B_m && B_m < C && C < F;
                                              public static double code(double A, double B_m, double C, double F) {
                                              	double tmp;
                                              	if (B_m <= 1.65e-16) {
                                              		tmp = -Math.sqrt((-F / A));
                                              	} else {
                                              		tmp = -Math.sqrt(F) * Math.sqrt((2.0 / B_m));
                                              	}
                                              	return tmp;
                                              }
                                              
                                              B_m = math.fabs(B)
                                              [A, B_m, C, F] = sort([A, B_m, C, F])
                                              def code(A, B_m, C, F):
                                              	tmp = 0
                                              	if B_m <= 1.65e-16:
                                              		tmp = -math.sqrt((-F / A))
                                              	else:
                                              		tmp = -math.sqrt(F) * math.sqrt((2.0 / B_m))
                                              	return tmp
                                              
                                              B_m = abs(B)
                                              A, B_m, C, F = sort([A, B_m, C, F])
                                              function code(A, B_m, C, F)
                                              	tmp = 0.0
                                              	if (B_m <= 1.65e-16)
                                              		tmp = Float64(-sqrt(Float64(Float64(-F) / A)));
                                              	else
                                              		tmp = Float64(Float64(-sqrt(F)) * sqrt(Float64(2.0 / B_m)));
                                              	end
                                              	return tmp
                                              end
                                              
                                              B_m = abs(B);
                                              A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                              function tmp_2 = code(A, B_m, C, F)
                                              	tmp = 0.0;
                                              	if (B_m <= 1.65e-16)
                                              		tmp = -sqrt((-F / A));
                                              	else
                                              		tmp = -sqrt(F) * sqrt((2.0 / B_m));
                                              	end
                                              	tmp_2 = tmp;
                                              end
                                              
                                              B_m = N[Abs[B], $MachinePrecision]
                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                              code[A_, B$95$m_, C_, F_] := If[LessEqual[B$95$m, 1.65e-16], (-N[Sqrt[N[((-F) / A), $MachinePrecision]], $MachinePrecision]), N[((-N[Sqrt[F], $MachinePrecision]) * N[Sqrt[N[(2.0 / B$95$m), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]
                                              
                                              \begin{array}{l}
                                              B_m = \left|B\right|
                                              \\
                                              [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                              \\
                                              \begin{array}{l}
                                              \mathbf{if}\;B\_m \leq 1.65 \cdot 10^{-16}:\\
                                              \;\;\;\;-\sqrt{\frac{-F}{A}}\\
                                              
                                              \mathbf{else}:\\
                                              \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B\_m}}\\
                                              
                                              
                                              \end{array}
                                              \end{array}
                                              
                                              Derivation
                                              1. Split input into 2 regimes
                                              2. if B < 1.64999999999999994e-16

                                                1. Initial program 16.7%

                                                  \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                2. Add Preprocessing
                                                3. Taylor expanded in F around 0

                                                  \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                                4. Step-by-step derivation
                                                  1. mul-1-negN/A

                                                    \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                                  2. *-commutativeN/A

                                                    \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}}\right) \]
                                                  3. distribute-lft-neg-inN/A

                                                    \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                                                  4. lower-*.f64N/A

                                                    \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                                                  5. lower-neg.f64N/A

                                                    \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \]
                                                  6. lower-sqrt.f64N/A

                                                    \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \]
                                                  7. lower-sqrt.f64N/A

                                                    \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                                                  8. lower-/.f64N/A

                                                    \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                                                5. Applied rewrites21.6%

                                                  \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}} \]
                                                6. Applied rewrites19.1%

                                                  \[\leadsto \color{blue}{-\sqrt{\left(\frac{F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \cdot \left(\mathsf{hypot}\left(A - C, B\right) + \left(C + A\right)\right)\right) \cdot 2}} \]
                                                7. Taylor expanded in A around -inf

                                                  \[\leadsto -\sqrt{-1 \cdot \frac{F}{A}} \]
                                                8. Step-by-step derivation
                                                  1. Applied rewrites20.4%

                                                    \[\leadsto -\sqrt{-\frac{F}{A}} \]

                                                  if 1.64999999999999994e-16 < B

                                                  1. Initial program 21.5%

                                                    \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                  2. Add Preprocessing
                                                  3. Taylor expanded in B around inf

                                                    \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                  4. Step-by-step derivation
                                                    1. mul-1-negN/A

                                                      \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                    2. *-commutativeN/A

                                                      \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                    3. distribute-lft-neg-inN/A

                                                      \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                    4. lower-*.f64N/A

                                                      \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                    5. lower-neg.f64N/A

                                                      \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
                                                    6. lower-sqrt.f64N/A

                                                      \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
                                                    7. lower-sqrt.f64N/A

                                                      \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
                                                    8. lower-/.f6441.7

                                                      \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                  5. Applied rewrites41.7%

                                                    \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                  6. Step-by-step derivation
                                                    1. Applied rewrites41.9%

                                                      \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                    2. Step-by-step derivation
                                                      1. Applied rewrites55.9%

                                                        \[\leadsto -\sqrt{F} \cdot \sqrt{\frac{2}{B}} \]
                                                    3. Recombined 2 regimes into one program.
                                                    4. Final simplification29.7%

                                                      \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 1.65 \cdot 10^{-16}:\\ \;\;\;\;-\sqrt{\frac{-F}{A}}\\ \mathbf{else}:\\ \;\;\;\;\left(-\sqrt{F}\right) \cdot \sqrt{\frac{2}{B}}\\ \end{array} \]
                                                    5. Add Preprocessing

                                                    Alternative 9: 39.6% accurate, 14.0× speedup?

                                                    \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;B\_m \leq 1.65 \cdot 10^{-16}:\\ \;\;\;\;-\sqrt{\frac{-F}{A}}\\ \mathbf{else}:\\ \;\;\;\;-\sqrt{\frac{F}{B\_m} \cdot 2}\\ \end{array} \end{array} \]
                                                    B_m = (fabs.f64 B)
                                                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                    (FPCore (A B_m C F)
                                                     :precision binary64
                                                     (if (<= B_m 1.65e-16) (- (sqrt (/ (- F) A))) (- (sqrt (* (/ F B_m) 2.0)))))
                                                    B_m = fabs(B);
                                                    assert(A < B_m && B_m < C && C < F);
                                                    double code(double A, double B_m, double C, double F) {
                                                    	double tmp;
                                                    	if (B_m <= 1.65e-16) {
                                                    		tmp = -sqrt((-F / A));
                                                    	} else {
                                                    		tmp = -sqrt(((F / B_m) * 2.0));
                                                    	}
                                                    	return tmp;
                                                    }
                                                    
                                                    B_m = abs(b)
                                                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                    real(8) function code(a, b_m, c, f)
                                                        real(8), intent (in) :: a
                                                        real(8), intent (in) :: b_m
                                                        real(8), intent (in) :: c
                                                        real(8), intent (in) :: f
                                                        real(8) :: tmp
                                                        if (b_m <= 1.65d-16) then
                                                            tmp = -sqrt((-f / a))
                                                        else
                                                            tmp = -sqrt(((f / b_m) * 2.0d0))
                                                        end if
                                                        code = tmp
                                                    end function
                                                    
                                                    B_m = Math.abs(B);
                                                    assert A < B_m && B_m < C && C < F;
                                                    public static double code(double A, double B_m, double C, double F) {
                                                    	double tmp;
                                                    	if (B_m <= 1.65e-16) {
                                                    		tmp = -Math.sqrt((-F / A));
                                                    	} else {
                                                    		tmp = -Math.sqrt(((F / B_m) * 2.0));
                                                    	}
                                                    	return tmp;
                                                    }
                                                    
                                                    B_m = math.fabs(B)
                                                    [A, B_m, C, F] = sort([A, B_m, C, F])
                                                    def code(A, B_m, C, F):
                                                    	tmp = 0
                                                    	if B_m <= 1.65e-16:
                                                    		tmp = -math.sqrt((-F / A))
                                                    	else:
                                                    		tmp = -math.sqrt(((F / B_m) * 2.0))
                                                    	return tmp
                                                    
                                                    B_m = abs(B)
                                                    A, B_m, C, F = sort([A, B_m, C, F])
                                                    function code(A, B_m, C, F)
                                                    	tmp = 0.0
                                                    	if (B_m <= 1.65e-16)
                                                    		tmp = Float64(-sqrt(Float64(Float64(-F) / A)));
                                                    	else
                                                    		tmp = Float64(-sqrt(Float64(Float64(F / B_m) * 2.0)));
                                                    	end
                                                    	return tmp
                                                    end
                                                    
                                                    B_m = abs(B);
                                                    A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                    function tmp_2 = code(A, B_m, C, F)
                                                    	tmp = 0.0;
                                                    	if (B_m <= 1.65e-16)
                                                    		tmp = -sqrt((-F / A));
                                                    	else
                                                    		tmp = -sqrt(((F / B_m) * 2.0));
                                                    	end
                                                    	tmp_2 = tmp;
                                                    end
                                                    
                                                    B_m = N[Abs[B], $MachinePrecision]
                                                    NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                    code[A_, B$95$m_, C_, F_] := If[LessEqual[B$95$m, 1.65e-16], (-N[Sqrt[N[((-F) / A), $MachinePrecision]], $MachinePrecision]), (-N[Sqrt[N[(N[(F / B$95$m), $MachinePrecision] * 2.0), $MachinePrecision]], $MachinePrecision])]
                                                    
                                                    \begin{array}{l}
                                                    B_m = \left|B\right|
                                                    \\
                                                    [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                    \\
                                                    \begin{array}{l}
                                                    \mathbf{if}\;B\_m \leq 1.65 \cdot 10^{-16}:\\
                                                    \;\;\;\;-\sqrt{\frac{-F}{A}}\\
                                                    
                                                    \mathbf{else}:\\
                                                    \;\;\;\;-\sqrt{\frac{F}{B\_m} \cdot 2}\\
                                                    
                                                    
                                                    \end{array}
                                                    \end{array}
                                                    
                                                    Derivation
                                                    1. Split input into 2 regimes
                                                    2. if B < 1.64999999999999994e-16

                                                      1. Initial program 16.7%

                                                        \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                      2. Add Preprocessing
                                                      3. Taylor expanded in F around 0

                                                        \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                                      4. Step-by-step derivation
                                                        1. mul-1-negN/A

                                                          \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                                        2. *-commutativeN/A

                                                          \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}}\right) \]
                                                        3. distribute-lft-neg-inN/A

                                                          \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                                                        4. lower-*.f64N/A

                                                          \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                                                        5. lower-neg.f64N/A

                                                          \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \]
                                                        6. lower-sqrt.f64N/A

                                                          \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \]
                                                        7. lower-sqrt.f64N/A

                                                          \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                                                        8. lower-/.f64N/A

                                                          \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                                                      5. Applied rewrites21.6%

                                                        \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}} \]
                                                      6. Applied rewrites19.1%

                                                        \[\leadsto \color{blue}{-\sqrt{\left(\frac{F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \cdot \left(\mathsf{hypot}\left(A - C, B\right) + \left(C + A\right)\right)\right) \cdot 2}} \]
                                                      7. Taylor expanded in A around -inf

                                                        \[\leadsto -\sqrt{-1 \cdot \frac{F}{A}} \]
                                                      8. Step-by-step derivation
                                                        1. Applied rewrites20.4%

                                                          \[\leadsto -\sqrt{-\frac{F}{A}} \]

                                                        if 1.64999999999999994e-16 < B

                                                        1. Initial program 21.5%

                                                          \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                        2. Add Preprocessing
                                                        3. Taylor expanded in B around inf

                                                          \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                        4. Step-by-step derivation
                                                          1. mul-1-negN/A

                                                            \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                          2. *-commutativeN/A

                                                            \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                          3. distribute-lft-neg-inN/A

                                                            \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                          4. lower-*.f64N/A

                                                            \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                          5. lower-neg.f64N/A

                                                            \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
                                                          6. lower-sqrt.f64N/A

                                                            \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
                                                          7. lower-sqrt.f64N/A

                                                            \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
                                                          8. lower-/.f6441.7

                                                            \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                        5. Applied rewrites41.7%

                                                          \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                        6. Step-by-step derivation
                                                          1. Applied rewrites41.9%

                                                            \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                        7. Recombined 2 regimes into one program.
                                                        8. Final simplification26.0%

                                                          \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 1.65 \cdot 10^{-16}:\\ \;\;\;\;-\sqrt{\frac{-F}{A}}\\ \mathbf{else}:\\ \;\;\;\;-\sqrt{\frac{F}{B} \cdot 2}\\ \end{array} \]
                                                        9. Add Preprocessing

                                                        Alternative 10: 39.6% accurate, 14.0× speedup?

                                                        \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ \begin{array}{l} \mathbf{if}\;B\_m \leq 1.65 \cdot 10^{-16}:\\ \;\;\;\;-\sqrt{\frac{-F}{A}}\\ \mathbf{else}:\\ \;\;\;\;-\sqrt{\frac{2}{B\_m} \cdot F}\\ \end{array} \end{array} \]
                                                        B_m = (fabs.f64 B)
                                                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                        (FPCore (A B_m C F)
                                                         :precision binary64
                                                         (if (<= B_m 1.65e-16) (- (sqrt (/ (- F) A))) (- (sqrt (* (/ 2.0 B_m) F)))))
                                                        B_m = fabs(B);
                                                        assert(A < B_m && B_m < C && C < F);
                                                        double code(double A, double B_m, double C, double F) {
                                                        	double tmp;
                                                        	if (B_m <= 1.65e-16) {
                                                        		tmp = -sqrt((-F / A));
                                                        	} else {
                                                        		tmp = -sqrt(((2.0 / B_m) * F));
                                                        	}
                                                        	return tmp;
                                                        }
                                                        
                                                        B_m = abs(b)
                                                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                        real(8) function code(a, b_m, c, f)
                                                            real(8), intent (in) :: a
                                                            real(8), intent (in) :: b_m
                                                            real(8), intent (in) :: c
                                                            real(8), intent (in) :: f
                                                            real(8) :: tmp
                                                            if (b_m <= 1.65d-16) then
                                                                tmp = -sqrt((-f / a))
                                                            else
                                                                tmp = -sqrt(((2.0d0 / b_m) * f))
                                                            end if
                                                            code = tmp
                                                        end function
                                                        
                                                        B_m = Math.abs(B);
                                                        assert A < B_m && B_m < C && C < F;
                                                        public static double code(double A, double B_m, double C, double F) {
                                                        	double tmp;
                                                        	if (B_m <= 1.65e-16) {
                                                        		tmp = -Math.sqrt((-F / A));
                                                        	} else {
                                                        		tmp = -Math.sqrt(((2.0 / B_m) * F));
                                                        	}
                                                        	return tmp;
                                                        }
                                                        
                                                        B_m = math.fabs(B)
                                                        [A, B_m, C, F] = sort([A, B_m, C, F])
                                                        def code(A, B_m, C, F):
                                                        	tmp = 0
                                                        	if B_m <= 1.65e-16:
                                                        		tmp = -math.sqrt((-F / A))
                                                        	else:
                                                        		tmp = -math.sqrt(((2.0 / B_m) * F))
                                                        	return tmp
                                                        
                                                        B_m = abs(B)
                                                        A, B_m, C, F = sort([A, B_m, C, F])
                                                        function code(A, B_m, C, F)
                                                        	tmp = 0.0
                                                        	if (B_m <= 1.65e-16)
                                                        		tmp = Float64(-sqrt(Float64(Float64(-F) / A)));
                                                        	else
                                                        		tmp = Float64(-sqrt(Float64(Float64(2.0 / B_m) * F)));
                                                        	end
                                                        	return tmp
                                                        end
                                                        
                                                        B_m = abs(B);
                                                        A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                        function tmp_2 = code(A, B_m, C, F)
                                                        	tmp = 0.0;
                                                        	if (B_m <= 1.65e-16)
                                                        		tmp = -sqrt((-F / A));
                                                        	else
                                                        		tmp = -sqrt(((2.0 / B_m) * F));
                                                        	end
                                                        	tmp_2 = tmp;
                                                        end
                                                        
                                                        B_m = N[Abs[B], $MachinePrecision]
                                                        NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                        code[A_, B$95$m_, C_, F_] := If[LessEqual[B$95$m, 1.65e-16], (-N[Sqrt[N[((-F) / A), $MachinePrecision]], $MachinePrecision]), (-N[Sqrt[N[(N[(2.0 / B$95$m), $MachinePrecision] * F), $MachinePrecision]], $MachinePrecision])]
                                                        
                                                        \begin{array}{l}
                                                        B_m = \left|B\right|
                                                        \\
                                                        [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                        \\
                                                        \begin{array}{l}
                                                        \mathbf{if}\;B\_m \leq 1.65 \cdot 10^{-16}:\\
                                                        \;\;\;\;-\sqrt{\frac{-F}{A}}\\
                                                        
                                                        \mathbf{else}:\\
                                                        \;\;\;\;-\sqrt{\frac{2}{B\_m} \cdot F}\\
                                                        
                                                        
                                                        \end{array}
                                                        \end{array}
                                                        
                                                        Derivation
                                                        1. Split input into 2 regimes
                                                        2. if B < 1.64999999999999994e-16

                                                          1. Initial program 16.7%

                                                            \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                          2. Add Preprocessing
                                                          3. Taylor expanded in F around 0

                                                            \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                                          4. Step-by-step derivation
                                                            1. mul-1-negN/A

                                                              \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                                            2. *-commutativeN/A

                                                              \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}}\right) \]
                                                            3. distribute-lft-neg-inN/A

                                                              \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                                                            4. lower-*.f64N/A

                                                              \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                                                            5. lower-neg.f64N/A

                                                              \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \]
                                                            6. lower-sqrt.f64N/A

                                                              \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \]
                                                            7. lower-sqrt.f64N/A

                                                              \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                                                            8. lower-/.f64N/A

                                                              \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                                                          5. Applied rewrites21.6%

                                                            \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}} \]
                                                          6. Applied rewrites19.1%

                                                            \[\leadsto \color{blue}{-\sqrt{\left(\frac{F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \cdot \left(\mathsf{hypot}\left(A - C, B\right) + \left(C + A\right)\right)\right) \cdot 2}} \]
                                                          7. Taylor expanded in A around -inf

                                                            \[\leadsto -\sqrt{-1 \cdot \frac{F}{A}} \]
                                                          8. Step-by-step derivation
                                                            1. Applied rewrites20.4%

                                                              \[\leadsto -\sqrt{-\frac{F}{A}} \]

                                                            if 1.64999999999999994e-16 < B

                                                            1. Initial program 21.5%

                                                              \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                            2. Add Preprocessing
                                                            3. Taylor expanded in B around inf

                                                              \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                            4. Step-by-step derivation
                                                              1. mul-1-negN/A

                                                                \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F}{B}} \cdot \sqrt{2}\right)} \]
                                                              2. *-commutativeN/A

                                                                \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F}{B}}}\right) \]
                                                              3. distribute-lft-neg-inN/A

                                                                \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                              4. lower-*.f64N/A

                                                                \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                              5. lower-neg.f64N/A

                                                                \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F}{B}} \]
                                                              6. lower-sqrt.f64N/A

                                                                \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F}{B}} \]
                                                              7. lower-sqrt.f64N/A

                                                                \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F}{B}}} \]
                                                              8. lower-/.f6441.7

                                                                \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F}{B}}} \]
                                                            5. Applied rewrites41.7%

                                                              \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{F}{B}}} \]
                                                            6. Step-by-step derivation
                                                              1. Applied rewrites41.9%

                                                                \[\leadsto \color{blue}{-\sqrt{\frac{F}{B} \cdot 2}} \]
                                                              2. Step-by-step derivation
                                                                1. Applied rewrites41.9%

                                                                  \[\leadsto -\sqrt{F \cdot \frac{2}{B}} \]
                                                              3. Recombined 2 regimes into one program.
                                                              4. Final simplification26.0%

                                                                \[\leadsto \begin{array}{l} \mathbf{if}\;B \leq 1.65 \cdot 10^{-16}:\\ \;\;\;\;-\sqrt{\frac{-F}{A}}\\ \mathbf{else}:\\ \;\;\;\;-\sqrt{\frac{2}{B} \cdot F}\\ \end{array} \]
                                                              5. Add Preprocessing

                                                              Alternative 11: 26.8% accurate, 18.9× speedup?

                                                              \[\begin{array}{l} B_m = \left|B\right| \\ [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\ \\ -\sqrt{\frac{-F}{A}} \end{array} \]
                                                              B_m = (fabs.f64 B)
                                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                              (FPCore (A B_m C F) :precision binary64 (- (sqrt (/ (- F) A))))
                                                              B_m = fabs(B);
                                                              assert(A < B_m && B_m < C && C < F);
                                                              double code(double A, double B_m, double C, double F) {
                                                              	return -sqrt((-F / A));
                                                              }
                                                              
                                                              B_m = abs(b)
                                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                              real(8) function code(a, b_m, c, f)
                                                                  real(8), intent (in) :: a
                                                                  real(8), intent (in) :: b_m
                                                                  real(8), intent (in) :: c
                                                                  real(8), intent (in) :: f
                                                                  code = -sqrt((-f / a))
                                                              end function
                                                              
                                                              B_m = Math.abs(B);
                                                              assert A < B_m && B_m < C && C < F;
                                                              public static double code(double A, double B_m, double C, double F) {
                                                              	return -Math.sqrt((-F / A));
                                                              }
                                                              
                                                              B_m = math.fabs(B)
                                                              [A, B_m, C, F] = sort([A, B_m, C, F])
                                                              def code(A, B_m, C, F):
                                                              	return -math.sqrt((-F / A))
                                                              
                                                              B_m = abs(B)
                                                              A, B_m, C, F = sort([A, B_m, C, F])
                                                              function code(A, B_m, C, F)
                                                              	return Float64(-sqrt(Float64(Float64(-F) / A)))
                                                              end
                                                              
                                                              B_m = abs(B);
                                                              A, B_m, C, F = num2cell(sort([A, B_m, C, F])){:}
                                                              function tmp = code(A, B_m, C, F)
                                                              	tmp = -sqrt((-F / A));
                                                              end
                                                              
                                                              B_m = N[Abs[B], $MachinePrecision]
                                                              NOTE: A, B_m, C, and F should be sorted in increasing order before calling this function.
                                                              code[A_, B$95$m_, C_, F_] := (-N[Sqrt[N[((-F) / A), $MachinePrecision]], $MachinePrecision])
                                                              
                                                              \begin{array}{l}
                                                              B_m = \left|B\right|
                                                              \\
                                                              [A, B_m, C, F] = \mathsf{sort}([A, B_m, C, F])\\
                                                              \\
                                                              -\sqrt{\frac{-F}{A}}
                                                              \end{array}
                                                              
                                                              Derivation
                                                              1. Initial program 18.0%

                                                                \[\frac{-\sqrt{\left(2 \cdot \left(\left({B}^{2} - \left(4 \cdot A\right) \cdot C\right) \cdot F\right)\right) \cdot \left(\left(A + C\right) + \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{{B}^{2} - \left(4 \cdot A\right) \cdot C} \]
                                                              2. Add Preprocessing
                                                              3. Taylor expanded in F around 0

                                                                \[\leadsto \color{blue}{-1 \cdot \left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                                              4. Step-by-step derivation
                                                                1. mul-1-negN/A

                                                                  \[\leadsto \color{blue}{\mathsf{neg}\left(\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \cdot \sqrt{2}\right)} \]
                                                                2. *-commutativeN/A

                                                                  \[\leadsto \mathsf{neg}\left(\color{blue}{\sqrt{2} \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}}\right) \]
                                                                3. distribute-lft-neg-inN/A

                                                                  \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                                                                4. lower-*.f64N/A

                                                                  \[\leadsto \color{blue}{\left(\mathsf{neg}\left(\sqrt{2}\right)\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                                                                5. lower-neg.f64N/A

                                                                  \[\leadsto \color{blue}{\left(-\sqrt{2}\right)} \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \]
                                                                6. lower-sqrt.f64N/A

                                                                  \[\leadsto \left(-\color{blue}{\sqrt{2}}\right) \cdot \sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}} \]
                                                                7. lower-sqrt.f64N/A

                                                                  \[\leadsto \left(-\sqrt{2}\right) \cdot \color{blue}{\sqrt{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                                                                8. lower-/.f64N/A

                                                                  \[\leadsto \left(-\sqrt{2}\right) \cdot \sqrt{\color{blue}{\frac{F \cdot \left(A + \left(C + \sqrt{{B}^{2} + {\left(A - C\right)}^{2}}\right)\right)}{{B}^{2} - 4 \cdot \left(A \cdot C\right)}}} \]
                                                              5. Applied rewrites23.7%

                                                                \[\leadsto \color{blue}{\left(-\sqrt{2}\right) \cdot \sqrt{\frac{\left(\left(\mathsf{hypot}\left(A - C, B\right) + C\right) + A\right) \cdot F}{\mathsf{fma}\left(-4, C \cdot A, B \cdot B\right)}}} \]
                                                              6. Applied rewrites21.6%

                                                                \[\leadsto \color{blue}{-\sqrt{\left(\frac{F}{\mathsf{fma}\left(C \cdot A, -4, B \cdot B\right)} \cdot \left(\mathsf{hypot}\left(A - C, B\right) + \left(C + A\right)\right)\right) \cdot 2}} \]
                                                              7. Taylor expanded in A around -inf

                                                                \[\leadsto -\sqrt{-1 \cdot \frac{F}{A}} \]
                                                              8. Step-by-step derivation
                                                                1. Applied rewrites19.1%

                                                                  \[\leadsto -\sqrt{-\frac{F}{A}} \]
                                                                2. Final simplification19.1%

                                                                  \[\leadsto -\sqrt{\frac{-F}{A}} \]
                                                                3. Add Preprocessing

                                                                Reproduce

                                                                ?
                                                                herbie shell --seed 2024285 
                                                                (FPCore (A B C F)
                                                                  :name "ABCF->ab-angle a"
                                                                  :precision binary64
                                                                  (/ (- (sqrt (* (* 2.0 (* (- (pow B 2.0) (* (* 4.0 A) C)) F)) (+ (+ A C) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))) (- (pow B 2.0) (* (* 4.0 A) C))))