expfmod (used to be hard to sample)

Percentage Accurate: 6.7% → 61.5%
Time: 10.6s
Alternatives: 6
Speedup: 3.9×

Specification

?
\[\begin{array}{l} \\ \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \end{array} \]
(FPCore (x) :precision binary64 (* (fmod (exp x) (sqrt (cos x))) (exp (- x))))
double code(double x) {
	return fmod(exp(x), sqrt(cos(x))) * exp(-x);
}
real(8) function code(x)
    real(8), intent (in) :: x
    code = mod(exp(x), sqrt(cos(x))) * exp(-x)
end function
def code(x):
	return math.fmod(math.exp(x), math.sqrt(math.cos(x))) * math.exp(-x)
function code(x)
	return Float64(rem(exp(x), sqrt(cos(x))) * exp(Float64(-x)))
end
code[x_] := N[(N[With[{TMP1 = N[Exp[x], $MachinePrecision], TMP2 = N[Sqrt[N[Cos[x], $MachinePrecision]], $MachinePrecision]}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision] * N[Exp[(-x)], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 6 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 6.7% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \end{array} \]
(FPCore (x) :precision binary64 (* (fmod (exp x) (sqrt (cos x))) (exp (- x))))
double code(double x) {
	return fmod(exp(x), sqrt(cos(x))) * exp(-x);
}
real(8) function code(x)
    real(8), intent (in) :: x
    code = mod(exp(x), sqrt(cos(x))) * exp(-x)
end function
def code(x):
	return math.fmod(math.exp(x), math.sqrt(math.cos(x))) * math.exp(-x)
function code(x)
	return Float64(rem(exp(x), sqrt(cos(x))) * exp(Float64(-x)))
end
code[x_] := N[(N[With[{TMP1 = N[Exp[x], $MachinePrecision], TMP2 = N[Sqrt[N[Cos[x], $MachinePrecision]], $MachinePrecision]}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision] * N[Exp[(-x)], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x}
\end{array}

Alternative 1: 61.5% accurate, 0.7× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := e^{-x}\\ \mathbf{if}\;t\_0 \cdot \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \leq 0.05:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(0.5, x, -1\right), x, 1\right) \cdot \left(\left(\mathsf{fma}\left(0.5, x, 1\right) \cdot x\right) \bmod 1\right)\\ \mathbf{else}:\\ \;\;\;\;\left(\left(1 + x\right) \bmod 1\right) \cdot t\_0\\ \end{array} \end{array} \]
(FPCore (x)
 :precision binary64
 (let* ((t_0 (exp (- x))))
   (if (<= (* t_0 (fmod (exp x) (sqrt (cos x)))) 0.05)
     (* (fma (fma 0.5 x -1.0) x 1.0) (fmod (* (fma 0.5 x 1.0) x) 1.0))
     (* (fmod (+ 1.0 x) 1.0) t_0))))
double code(double x) {
	double t_0 = exp(-x);
	double tmp;
	if ((t_0 * fmod(exp(x), sqrt(cos(x)))) <= 0.05) {
		tmp = fma(fma(0.5, x, -1.0), x, 1.0) * fmod((fma(0.5, x, 1.0) * x), 1.0);
	} else {
		tmp = fmod((1.0 + x), 1.0) * t_0;
	}
	return tmp;
}
function code(x)
	t_0 = exp(Float64(-x))
	tmp = 0.0
	if (Float64(t_0 * rem(exp(x), sqrt(cos(x)))) <= 0.05)
		tmp = Float64(fma(fma(0.5, x, -1.0), x, 1.0) * rem(Float64(fma(0.5, x, 1.0) * x), 1.0));
	else
		tmp = Float64(rem(Float64(1.0 + x), 1.0) * t_0);
	end
	return tmp
end
code[x_] := Block[{t$95$0 = N[Exp[(-x)], $MachinePrecision]}, If[LessEqual[N[(t$95$0 * N[With[{TMP1 = N[Exp[x], $MachinePrecision], TMP2 = N[Sqrt[N[Cos[x], $MachinePrecision]], $MachinePrecision]}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision]), $MachinePrecision], 0.05], N[(N[(N[(0.5 * x + -1.0), $MachinePrecision] * x + 1.0), $MachinePrecision] * N[With[{TMP1 = N[(N[(0.5 * x + 1.0), $MachinePrecision] * x), $MachinePrecision], TMP2 = 1.0}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision]), $MachinePrecision], N[(N[With[{TMP1 = N[(1.0 + x), $MachinePrecision], TMP2 = 1.0}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision] * t$95$0), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := e^{-x}\\
\mathbf{if}\;t\_0 \cdot \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \leq 0.05:\\
\;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(0.5, x, -1\right), x, 1\right) \cdot \left(\left(\mathsf{fma}\left(0.5, x, 1\right) \cdot x\right) \bmod 1\right)\\

\mathbf{else}:\\
\;\;\;\;\left(\left(1 + x\right) \bmod 1\right) \cdot t\_0\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (*.f64 (fmod.f64 (exp.f64 x) (sqrt.f64 (cos.f64 x))) (exp.f64 (neg.f64 x))) < 0.050000000000000003

    1. Initial program 6.2%

      \[\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{1}\right) \cdot e^{-x} \]
    4. Step-by-step derivation
      1. Applied rewrites5.8%

        \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{1}\right) \cdot e^{-x} \]
      2. Taylor expanded in x around 0

        \[\leadsto \left(\color{blue}{\left(1 + x \cdot \left(1 + \frac{1}{2} \cdot x\right)\right)} \bmod 1\right) \cdot e^{-x} \]
      3. Step-by-step derivation
        1. +-commutativeN/A

          \[\leadsto \left(\color{blue}{\left(x \cdot \left(1 + \frac{1}{2} \cdot x\right) + 1\right)} \bmod 1\right) \cdot e^{-x} \]
        2. *-commutativeN/A

          \[\leadsto \left(\left(\color{blue}{\left(1 + \frac{1}{2} \cdot x\right) \cdot x} + 1\right) \bmod 1\right) \cdot e^{-x} \]
        3. lower-fma.f64N/A

          \[\leadsto \left(\color{blue}{\left(\mathsf{fma}\left(1 + \frac{1}{2} \cdot x, x, 1\right)\right)} \bmod 1\right) \cdot e^{-x} \]
        4. +-commutativeN/A

          \[\leadsto \left(\left(\mathsf{fma}\left(\color{blue}{\frac{1}{2} \cdot x + 1}, x, 1\right)\right) \bmod 1\right) \cdot e^{-x} \]
        5. lower-fma.f645.8

          \[\leadsto \left(\left(\mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(0.5, x, 1\right)}, x, 1\right)\right) \bmod 1\right) \cdot e^{-x} \]
      4. Applied rewrites5.8%

        \[\leadsto \left(\color{blue}{\left(\mathsf{fma}\left(\mathsf{fma}\left(0.5, x, 1\right), x, 1\right)\right)} \bmod 1\right) \cdot e^{-x} \]
      5. Taylor expanded in x around inf

        \[\leadsto \left(\left({x}^{2} \cdot \color{blue}{\left(\frac{1}{2} + \frac{1}{x}\right)}\right) \bmod 1\right) \cdot e^{-x} \]
      6. Step-by-step derivation
        1. Applied rewrites49.4%

          \[\leadsto \left(\left(\mathsf{fma}\left(0.5, x, 1\right) \cdot \color{blue}{x}\right) \bmod 1\right) \cdot e^{-x} \]
        2. Taylor expanded in x around 0

          \[\leadsto \left(\left(\mathsf{fma}\left(\frac{1}{2}, x, 1\right) \cdot x\right) \bmod 1\right) \cdot \color{blue}{\left(1 + x \cdot \left(\frac{1}{2} \cdot x - 1\right)\right)} \]
        3. Step-by-step derivation
          1. +-commutativeN/A

            \[\leadsto \left(\left(\mathsf{fma}\left(\frac{1}{2}, x, 1\right) \cdot x\right) \bmod 1\right) \cdot \color{blue}{\left(x \cdot \left(\frac{1}{2} \cdot x - 1\right) + 1\right)} \]
          2. *-commutativeN/A

            \[\leadsto \left(\left(\mathsf{fma}\left(\frac{1}{2}, x, 1\right) \cdot x\right) \bmod 1\right) \cdot \left(\color{blue}{\left(\frac{1}{2} \cdot x - 1\right) \cdot x} + 1\right) \]
          3. lower-fma.f64N/A

            \[\leadsto \left(\left(\mathsf{fma}\left(\frac{1}{2}, x, 1\right) \cdot x\right) \bmod 1\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{1}{2} \cdot x - 1, x, 1\right)} \]
          4. sub-negN/A

            \[\leadsto \left(\left(\mathsf{fma}\left(\frac{1}{2}, x, 1\right) \cdot x\right) \bmod 1\right) \cdot \mathsf{fma}\left(\color{blue}{\frac{1}{2} \cdot x + \left(\mathsf{neg}\left(1\right)\right)}, x, 1\right) \]
          5. metadata-evalN/A

            \[\leadsto \left(\left(\mathsf{fma}\left(\frac{1}{2}, x, 1\right) \cdot x\right) \bmod 1\right) \cdot \mathsf{fma}\left(\frac{1}{2} \cdot x + \color{blue}{-1}, x, 1\right) \]
          6. lower-fma.f6449.4

            \[\leadsto \left(\left(\mathsf{fma}\left(0.5, x, 1\right) \cdot x\right) \bmod 1\right) \cdot \mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(0.5, x, -1\right)}, x, 1\right) \]
        4. Applied rewrites49.4%

          \[\leadsto \left(\left(\mathsf{fma}\left(0.5, x, 1\right) \cdot x\right) \bmod 1\right) \cdot \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, x, -1\right), x, 1\right)} \]

        if 0.050000000000000003 < (*.f64 (fmod.f64 (exp.f64 x) (sqrt.f64 (cos.f64 x))) (exp.f64 (neg.f64 x)))

        1. Initial program 12.0%

          \[\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
        2. Add Preprocessing
        3. Taylor expanded in x around 0

          \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{1}\right) \cdot e^{-x} \]
        4. Step-by-step derivation
          1. Applied rewrites12.0%

            \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{1}\right) \cdot e^{-x} \]
          2. Taylor expanded in x around 0

            \[\leadsto \left(\color{blue}{\left(1 + x\right)} \bmod 1\right) \cdot e^{-x} \]
          3. Step-by-step derivation
            1. lower-+.f6497.2

              \[\leadsto \left(\color{blue}{\left(1 + x\right)} \bmod 1\right) \cdot e^{-x} \]
          4. Applied rewrites97.2%

            \[\leadsto \left(\color{blue}{\left(1 + x\right)} \bmod 1\right) \cdot e^{-x} \]
        5. Recombined 2 regimes into one program.
        6. Final simplification60.3%

          \[\leadsto \begin{array}{l} \mathbf{if}\;e^{-x} \cdot \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \leq 0.05:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(0.5, x, -1\right), x, 1\right) \cdot \left(\left(\mathsf{fma}\left(0.5, x, 1\right) \cdot x\right) \bmod 1\right)\\ \mathbf{else}:\\ \;\;\;\;\left(\left(1 + x\right) \bmod 1\right) \cdot e^{-x}\\ \end{array} \]
        7. Add Preprocessing

        Alternative 2: 60.3% accurate, 0.8× speedup?

        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{-x} \cdot \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \leq 0.05:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(0.5, x, -1\right), x, 1\right) \cdot \left(\left(\mathsf{fma}\left(0.5, x, 1\right) \cdot x\right) \bmod 1\right)\\ \mathbf{else}:\\ \;\;\;\;1 \cdot \left(\left(1 + x\right) \bmod 1\right)\\ \end{array} \end{array} \]
        (FPCore (x)
         :precision binary64
         (if (<= (* (exp (- x)) (fmod (exp x) (sqrt (cos x)))) 0.05)
           (* (fma (fma 0.5 x -1.0) x 1.0) (fmod (* (fma 0.5 x 1.0) x) 1.0))
           (* 1.0 (fmod (+ 1.0 x) 1.0))))
        double code(double x) {
        	double tmp;
        	if ((exp(-x) * fmod(exp(x), sqrt(cos(x)))) <= 0.05) {
        		tmp = fma(fma(0.5, x, -1.0), x, 1.0) * fmod((fma(0.5, x, 1.0) * x), 1.0);
        	} else {
        		tmp = 1.0 * fmod((1.0 + x), 1.0);
        	}
        	return tmp;
        }
        
        function code(x)
        	tmp = 0.0
        	if (Float64(exp(Float64(-x)) * rem(exp(x), sqrt(cos(x)))) <= 0.05)
        		tmp = Float64(fma(fma(0.5, x, -1.0), x, 1.0) * rem(Float64(fma(0.5, x, 1.0) * x), 1.0));
        	else
        		tmp = Float64(1.0 * rem(Float64(1.0 + x), 1.0));
        	end
        	return tmp
        end
        
        code[x_] := If[LessEqual[N[(N[Exp[(-x)], $MachinePrecision] * N[With[{TMP1 = N[Exp[x], $MachinePrecision], TMP2 = N[Sqrt[N[Cos[x], $MachinePrecision]], $MachinePrecision]}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision]), $MachinePrecision], 0.05], N[(N[(N[(0.5 * x + -1.0), $MachinePrecision] * x + 1.0), $MachinePrecision] * N[With[{TMP1 = N[(N[(0.5 * x + 1.0), $MachinePrecision] * x), $MachinePrecision], TMP2 = 1.0}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision]), $MachinePrecision], N[(1.0 * N[With[{TMP1 = N[(1.0 + x), $MachinePrecision], TMP2 = 1.0}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision]), $MachinePrecision]]
        
        \begin{array}{l}
        
        \\
        \begin{array}{l}
        \mathbf{if}\;e^{-x} \cdot \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \leq 0.05:\\
        \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(0.5, x, -1\right), x, 1\right) \cdot \left(\left(\mathsf{fma}\left(0.5, x, 1\right) \cdot x\right) \bmod 1\right)\\
        
        \mathbf{else}:\\
        \;\;\;\;1 \cdot \left(\left(1 + x\right) \bmod 1\right)\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 2 regimes
        2. if (*.f64 (fmod.f64 (exp.f64 x) (sqrt.f64 (cos.f64 x))) (exp.f64 (neg.f64 x))) < 0.050000000000000003

          1. Initial program 6.2%

            \[\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
          2. Add Preprocessing
          3. Taylor expanded in x around 0

            \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{1}\right) \cdot e^{-x} \]
          4. Step-by-step derivation
            1. Applied rewrites5.8%

              \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{1}\right) \cdot e^{-x} \]
            2. Taylor expanded in x around 0

              \[\leadsto \left(\color{blue}{\left(1 + x \cdot \left(1 + \frac{1}{2} \cdot x\right)\right)} \bmod 1\right) \cdot e^{-x} \]
            3. Step-by-step derivation
              1. +-commutativeN/A

                \[\leadsto \left(\color{blue}{\left(x \cdot \left(1 + \frac{1}{2} \cdot x\right) + 1\right)} \bmod 1\right) \cdot e^{-x} \]
              2. *-commutativeN/A

                \[\leadsto \left(\left(\color{blue}{\left(1 + \frac{1}{2} \cdot x\right) \cdot x} + 1\right) \bmod 1\right) \cdot e^{-x} \]
              3. lower-fma.f64N/A

                \[\leadsto \left(\color{blue}{\left(\mathsf{fma}\left(1 + \frac{1}{2} \cdot x, x, 1\right)\right)} \bmod 1\right) \cdot e^{-x} \]
              4. +-commutativeN/A

                \[\leadsto \left(\left(\mathsf{fma}\left(\color{blue}{\frac{1}{2} \cdot x + 1}, x, 1\right)\right) \bmod 1\right) \cdot e^{-x} \]
              5. lower-fma.f645.8

                \[\leadsto \left(\left(\mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(0.5, x, 1\right)}, x, 1\right)\right) \bmod 1\right) \cdot e^{-x} \]
            4. Applied rewrites5.8%

              \[\leadsto \left(\color{blue}{\left(\mathsf{fma}\left(\mathsf{fma}\left(0.5, x, 1\right), x, 1\right)\right)} \bmod 1\right) \cdot e^{-x} \]
            5. Taylor expanded in x around inf

              \[\leadsto \left(\left({x}^{2} \cdot \color{blue}{\left(\frac{1}{2} + \frac{1}{x}\right)}\right) \bmod 1\right) \cdot e^{-x} \]
            6. Step-by-step derivation
              1. Applied rewrites49.4%

                \[\leadsto \left(\left(\mathsf{fma}\left(0.5, x, 1\right) \cdot \color{blue}{x}\right) \bmod 1\right) \cdot e^{-x} \]
              2. Taylor expanded in x around 0

                \[\leadsto \left(\left(\mathsf{fma}\left(\frac{1}{2}, x, 1\right) \cdot x\right) \bmod 1\right) \cdot \color{blue}{\left(1 + x \cdot \left(\frac{1}{2} \cdot x - 1\right)\right)} \]
              3. Step-by-step derivation
                1. +-commutativeN/A

                  \[\leadsto \left(\left(\mathsf{fma}\left(\frac{1}{2}, x, 1\right) \cdot x\right) \bmod 1\right) \cdot \color{blue}{\left(x \cdot \left(\frac{1}{2} \cdot x - 1\right) + 1\right)} \]
                2. *-commutativeN/A

                  \[\leadsto \left(\left(\mathsf{fma}\left(\frac{1}{2}, x, 1\right) \cdot x\right) \bmod 1\right) \cdot \left(\color{blue}{\left(\frac{1}{2} \cdot x - 1\right) \cdot x} + 1\right) \]
                3. lower-fma.f64N/A

                  \[\leadsto \left(\left(\mathsf{fma}\left(\frac{1}{2}, x, 1\right) \cdot x\right) \bmod 1\right) \cdot \color{blue}{\mathsf{fma}\left(\frac{1}{2} \cdot x - 1, x, 1\right)} \]
                4. sub-negN/A

                  \[\leadsto \left(\left(\mathsf{fma}\left(\frac{1}{2}, x, 1\right) \cdot x\right) \bmod 1\right) \cdot \mathsf{fma}\left(\color{blue}{\frac{1}{2} \cdot x + \left(\mathsf{neg}\left(1\right)\right)}, x, 1\right) \]
                5. metadata-evalN/A

                  \[\leadsto \left(\left(\mathsf{fma}\left(\frac{1}{2}, x, 1\right) \cdot x\right) \bmod 1\right) \cdot \mathsf{fma}\left(\frac{1}{2} \cdot x + \color{blue}{-1}, x, 1\right) \]
                6. lower-fma.f6449.4

                  \[\leadsto \left(\left(\mathsf{fma}\left(0.5, x, 1\right) \cdot x\right) \bmod 1\right) \cdot \mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(0.5, x, -1\right)}, x, 1\right) \]
              4. Applied rewrites49.4%

                \[\leadsto \left(\left(\mathsf{fma}\left(0.5, x, 1\right) \cdot x\right) \bmod 1\right) \cdot \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, x, -1\right), x, 1\right)} \]

              if 0.050000000000000003 < (*.f64 (fmod.f64 (exp.f64 x) (sqrt.f64 (cos.f64 x))) (exp.f64 (neg.f64 x)))

              1. Initial program 12.0%

                \[\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
              2. Add Preprocessing
              3. Taylor expanded in x around 0

                \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{1}\right) \cdot e^{-x} \]
              4. Step-by-step derivation
                1. Applied rewrites12.0%

                  \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                2. Taylor expanded in x around 0

                  \[\leadsto \left(\left(e^{x}\right) \bmod 1\right) \cdot \color{blue}{1} \]
                3. Step-by-step derivation
                  1. Applied rewrites6.9%

                    \[\leadsto \left(\left(e^{x}\right) \bmod 1\right) \cdot \color{blue}{1} \]
                  2. Taylor expanded in x around 0

                    \[\leadsto \left(\color{blue}{\left(1 + x\right)} \bmod 1\right) \cdot 1 \]
                  3. Step-by-step derivation
                    1. lower-+.f6494.8

                      \[\leadsto \left(\color{blue}{\left(1 + x\right)} \bmod 1\right) \cdot 1 \]
                  4. Applied rewrites94.8%

                    \[\leadsto \left(\color{blue}{\left(1 + x\right)} \bmod 1\right) \cdot 1 \]
                4. Recombined 2 regimes into one program.
                5. Final simplification59.7%

                  \[\leadsto \begin{array}{l} \mathbf{if}\;e^{-x} \cdot \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \leq 0.05:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(0.5, x, -1\right), x, 1\right) \cdot \left(\left(\mathsf{fma}\left(0.5, x, 1\right) \cdot x\right) \bmod 1\right)\\ \mathbf{else}:\\ \;\;\;\;1 \cdot \left(\left(1 + x\right) \bmod 1\right)\\ \end{array} \]
                6. Add Preprocessing

                Alternative 3: 60.3% accurate, 0.8× speedup?

                \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{-x} \cdot \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \leq 10^{-8}:\\ \;\;\;\;\left(1 - x\right) \cdot \left(\left(\mathsf{fma}\left(0.5, x, 1\right) \cdot x\right) \bmod 1\right)\\ \mathbf{else}:\\ \;\;\;\;1 \cdot \left(\left(1 + x\right) \bmod 1\right)\\ \end{array} \end{array} \]
                (FPCore (x)
                 :precision binary64
                 (if (<= (* (exp (- x)) (fmod (exp x) (sqrt (cos x)))) 1e-8)
                   (* (- 1.0 x) (fmod (* (fma 0.5 x 1.0) x) 1.0))
                   (* 1.0 (fmod (+ 1.0 x) 1.0))))
                double code(double x) {
                	double tmp;
                	if ((exp(-x) * fmod(exp(x), sqrt(cos(x)))) <= 1e-8) {
                		tmp = (1.0 - x) * fmod((fma(0.5, x, 1.0) * x), 1.0);
                	} else {
                		tmp = 1.0 * fmod((1.0 + x), 1.0);
                	}
                	return tmp;
                }
                
                function code(x)
                	tmp = 0.0
                	if (Float64(exp(Float64(-x)) * rem(exp(x), sqrt(cos(x)))) <= 1e-8)
                		tmp = Float64(Float64(1.0 - x) * rem(Float64(fma(0.5, x, 1.0) * x), 1.0));
                	else
                		tmp = Float64(1.0 * rem(Float64(1.0 + x), 1.0));
                	end
                	return tmp
                end
                
                code[x_] := If[LessEqual[N[(N[Exp[(-x)], $MachinePrecision] * N[With[{TMP1 = N[Exp[x], $MachinePrecision], TMP2 = N[Sqrt[N[Cos[x], $MachinePrecision]], $MachinePrecision]}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision]), $MachinePrecision], 1e-8], N[(N[(1.0 - x), $MachinePrecision] * N[With[{TMP1 = N[(N[(0.5 * x + 1.0), $MachinePrecision] * x), $MachinePrecision], TMP2 = 1.0}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision]), $MachinePrecision], N[(1.0 * N[With[{TMP1 = N[(1.0 + x), $MachinePrecision], TMP2 = 1.0}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision]), $MachinePrecision]]
                
                \begin{array}{l}
                
                \\
                \begin{array}{l}
                \mathbf{if}\;e^{-x} \cdot \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \leq 10^{-8}:\\
                \;\;\;\;\left(1 - x\right) \cdot \left(\left(\mathsf{fma}\left(0.5, x, 1\right) \cdot x\right) \bmod 1\right)\\
                
                \mathbf{else}:\\
                \;\;\;\;1 \cdot \left(\left(1 + x\right) \bmod 1\right)\\
                
                
                \end{array}
                \end{array}
                
                Derivation
                1. Split input into 2 regimes
                2. if (*.f64 (fmod.f64 (exp.f64 x) (sqrt.f64 (cos.f64 x))) (exp.f64 (neg.f64 x))) < 1e-8

                  1. Initial program 5.5%

                    \[\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                  2. Add Preprocessing
                  3. Taylor expanded in x around 0

                    \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                  4. Step-by-step derivation
                    1. Applied rewrites5.5%

                      \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                    2. Taylor expanded in x around 0

                      \[\leadsto \left(\color{blue}{\left(1 + x \cdot \left(1 + \frac{1}{2} \cdot x\right)\right)} \bmod 1\right) \cdot e^{-x} \]
                    3. Step-by-step derivation
                      1. +-commutativeN/A

                        \[\leadsto \left(\color{blue}{\left(x \cdot \left(1 + \frac{1}{2} \cdot x\right) + 1\right)} \bmod 1\right) \cdot e^{-x} \]
                      2. *-commutativeN/A

                        \[\leadsto \left(\left(\color{blue}{\left(1 + \frac{1}{2} \cdot x\right) \cdot x} + 1\right) \bmod 1\right) \cdot e^{-x} \]
                      3. lower-fma.f64N/A

                        \[\leadsto \left(\color{blue}{\left(\mathsf{fma}\left(1 + \frac{1}{2} \cdot x, x, 1\right)\right)} \bmod 1\right) \cdot e^{-x} \]
                      4. +-commutativeN/A

                        \[\leadsto \left(\left(\mathsf{fma}\left(\color{blue}{\frac{1}{2} \cdot x + 1}, x, 1\right)\right) \bmod 1\right) \cdot e^{-x} \]
                      5. lower-fma.f645.5

                        \[\leadsto \left(\left(\mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(0.5, x, 1\right)}, x, 1\right)\right) \bmod 1\right) \cdot e^{-x} \]
                    4. Applied rewrites5.5%

                      \[\leadsto \left(\color{blue}{\left(\mathsf{fma}\left(\mathsf{fma}\left(0.5, x, 1\right), x, 1\right)\right)} \bmod 1\right) \cdot e^{-x} \]
                    5. Taylor expanded in x around inf

                      \[\leadsto \left(\left({x}^{2} \cdot \color{blue}{\left(\frac{1}{2} + \frac{1}{x}\right)}\right) \bmod 1\right) \cdot e^{-x} \]
                    6. Step-by-step derivation
                      1. Applied rewrites49.5%

                        \[\leadsto \left(\left(\mathsf{fma}\left(0.5, x, 1\right) \cdot \color{blue}{x}\right) \bmod 1\right) \cdot e^{-x} \]
                      2. Taylor expanded in x around 0

                        \[\leadsto \left(\left(\mathsf{fma}\left(\frac{1}{2}, x, 1\right) \cdot x\right) \bmod 1\right) \cdot \color{blue}{\left(1 + -1 \cdot x\right)} \]
                      3. Step-by-step derivation
                        1. neg-mul-1N/A

                          \[\leadsto \left(\left(\mathsf{fma}\left(\frac{1}{2}, x, 1\right) \cdot x\right) \bmod 1\right) \cdot \left(1 + \color{blue}{\left(\mathsf{neg}\left(x\right)\right)}\right) \]
                        2. unsub-negN/A

                          \[\leadsto \left(\left(\mathsf{fma}\left(\frac{1}{2}, x, 1\right) \cdot x\right) \bmod 1\right) \cdot \color{blue}{\left(1 - x\right)} \]
                        3. lower--.f6449.5

                          \[\leadsto \left(\left(\mathsf{fma}\left(0.5, x, 1\right) \cdot x\right) \bmod 1\right) \cdot \color{blue}{\left(1 - x\right)} \]
                      4. Applied rewrites49.5%

                        \[\leadsto \left(\left(\mathsf{fma}\left(0.5, x, 1\right) \cdot x\right) \bmod 1\right) \cdot \color{blue}{\left(1 - x\right)} \]

                      if 1e-8 < (*.f64 (fmod.f64 (exp.f64 x) (sqrt.f64 (cos.f64 x))) (exp.f64 (neg.f64 x)))

                      1. Initial program 14.3%

                        \[\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                      2. Add Preprocessing
                      3. Taylor expanded in x around 0

                        \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                      4. Step-by-step derivation
                        1. Applied rewrites13.0%

                          \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                        2. Taylor expanded in x around 0

                          \[\leadsto \left(\left(e^{x}\right) \bmod 1\right) \cdot \color{blue}{1} \]
                        3. Step-by-step derivation
                          1. Applied rewrites7.9%

                            \[\leadsto \left(\left(e^{x}\right) \bmod 1\right) \cdot \color{blue}{1} \]
                          2. Taylor expanded in x around 0

                            \[\leadsto \left(\color{blue}{\left(1 + x\right)} \bmod 1\right) \cdot 1 \]
                          3. Step-by-step derivation
                            1. lower-+.f6493.0

                              \[\leadsto \left(\color{blue}{\left(1 + x\right)} \bmod 1\right) \cdot 1 \]
                          4. Applied rewrites93.0%

                            \[\leadsto \left(\color{blue}{\left(1 + x\right)} \bmod 1\right) \cdot 1 \]
                        4. Recombined 2 regimes into one program.
                        5. Final simplification59.7%

                          \[\leadsto \begin{array}{l} \mathbf{if}\;e^{-x} \cdot \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \leq 10^{-8}:\\ \;\;\;\;\left(1 - x\right) \cdot \left(\left(\mathsf{fma}\left(0.5, x, 1\right) \cdot x\right) \bmod 1\right)\\ \mathbf{else}:\\ \;\;\;\;1 \cdot \left(\left(1 + x\right) \bmod 1\right)\\ \end{array} \]
                        6. Add Preprocessing

                        Alternative 4: 60.3% accurate, 0.8× speedup?

                        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{-x} \cdot \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \leq 10^{-8}:\\ \;\;\;\;1 \cdot \left(\left(\mathsf{fma}\left(0.5, x, 1\right) \cdot x\right) \bmod 1\right)\\ \mathbf{else}:\\ \;\;\;\;1 \cdot \left(\left(1 + x\right) \bmod 1\right)\\ \end{array} \end{array} \]
                        (FPCore (x)
                         :precision binary64
                         (if (<= (* (exp (- x)) (fmod (exp x) (sqrt (cos x)))) 1e-8)
                           (* 1.0 (fmod (* (fma 0.5 x 1.0) x) 1.0))
                           (* 1.0 (fmod (+ 1.0 x) 1.0))))
                        double code(double x) {
                        	double tmp;
                        	if ((exp(-x) * fmod(exp(x), sqrt(cos(x)))) <= 1e-8) {
                        		tmp = 1.0 * fmod((fma(0.5, x, 1.0) * x), 1.0);
                        	} else {
                        		tmp = 1.0 * fmod((1.0 + x), 1.0);
                        	}
                        	return tmp;
                        }
                        
                        function code(x)
                        	tmp = 0.0
                        	if (Float64(exp(Float64(-x)) * rem(exp(x), sqrt(cos(x)))) <= 1e-8)
                        		tmp = Float64(1.0 * rem(Float64(fma(0.5, x, 1.0) * x), 1.0));
                        	else
                        		tmp = Float64(1.0 * rem(Float64(1.0 + x), 1.0));
                        	end
                        	return tmp
                        end
                        
                        code[x_] := If[LessEqual[N[(N[Exp[(-x)], $MachinePrecision] * N[With[{TMP1 = N[Exp[x], $MachinePrecision], TMP2 = N[Sqrt[N[Cos[x], $MachinePrecision]], $MachinePrecision]}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision]), $MachinePrecision], 1e-8], N[(1.0 * N[With[{TMP1 = N[(N[(0.5 * x + 1.0), $MachinePrecision] * x), $MachinePrecision], TMP2 = 1.0}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision]), $MachinePrecision], N[(1.0 * N[With[{TMP1 = N[(1.0 + x), $MachinePrecision], TMP2 = 1.0}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision]), $MachinePrecision]]
                        
                        \begin{array}{l}
                        
                        \\
                        \begin{array}{l}
                        \mathbf{if}\;e^{-x} \cdot \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \leq 10^{-8}:\\
                        \;\;\;\;1 \cdot \left(\left(\mathsf{fma}\left(0.5, x, 1\right) \cdot x\right) \bmod 1\right)\\
                        
                        \mathbf{else}:\\
                        \;\;\;\;1 \cdot \left(\left(1 + x\right) \bmod 1\right)\\
                        
                        
                        \end{array}
                        \end{array}
                        
                        Derivation
                        1. Split input into 2 regimes
                        2. if (*.f64 (fmod.f64 (exp.f64 x) (sqrt.f64 (cos.f64 x))) (exp.f64 (neg.f64 x))) < 1e-8

                          1. Initial program 5.5%

                            \[\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                          2. Add Preprocessing
                          3. Taylor expanded in x around 0

                            \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                          4. Step-by-step derivation
                            1. Applied rewrites5.5%

                              \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                            2. Taylor expanded in x around 0

                              \[\leadsto \left(\color{blue}{\left(1 + x \cdot \left(1 + \frac{1}{2} \cdot x\right)\right)} \bmod 1\right) \cdot e^{-x} \]
                            3. Step-by-step derivation
                              1. +-commutativeN/A

                                \[\leadsto \left(\color{blue}{\left(x \cdot \left(1 + \frac{1}{2} \cdot x\right) + 1\right)} \bmod 1\right) \cdot e^{-x} \]
                              2. *-commutativeN/A

                                \[\leadsto \left(\left(\color{blue}{\left(1 + \frac{1}{2} \cdot x\right) \cdot x} + 1\right) \bmod 1\right) \cdot e^{-x} \]
                              3. lower-fma.f64N/A

                                \[\leadsto \left(\color{blue}{\left(\mathsf{fma}\left(1 + \frac{1}{2} \cdot x, x, 1\right)\right)} \bmod 1\right) \cdot e^{-x} \]
                              4. +-commutativeN/A

                                \[\leadsto \left(\left(\mathsf{fma}\left(\color{blue}{\frac{1}{2} \cdot x + 1}, x, 1\right)\right) \bmod 1\right) \cdot e^{-x} \]
                              5. lower-fma.f645.5

                                \[\leadsto \left(\left(\mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(0.5, x, 1\right)}, x, 1\right)\right) \bmod 1\right) \cdot e^{-x} \]
                            4. Applied rewrites5.5%

                              \[\leadsto \left(\color{blue}{\left(\mathsf{fma}\left(\mathsf{fma}\left(0.5, x, 1\right), x, 1\right)\right)} \bmod 1\right) \cdot e^{-x} \]
                            5. Taylor expanded in x around inf

                              \[\leadsto \left(\left({x}^{2} \cdot \color{blue}{\left(\frac{1}{2} + \frac{1}{x}\right)}\right) \bmod 1\right) \cdot e^{-x} \]
                            6. Step-by-step derivation
                              1. Applied rewrites49.5%

                                \[\leadsto \left(\left(\mathsf{fma}\left(0.5, x, 1\right) \cdot \color{blue}{x}\right) \bmod 1\right) \cdot e^{-x} \]
                              2. Taylor expanded in x around 0

                                \[\leadsto \left(\left(\mathsf{fma}\left(\frac{1}{2}, x, 1\right) \cdot x\right) \bmod 1\right) \cdot \color{blue}{1} \]
                              3. Step-by-step derivation
                                1. Applied rewrites49.5%

                                  \[\leadsto \left(\left(\mathsf{fma}\left(0.5, x, 1\right) \cdot x\right) \bmod 1\right) \cdot \color{blue}{1} \]

                                if 1e-8 < (*.f64 (fmod.f64 (exp.f64 x) (sqrt.f64 (cos.f64 x))) (exp.f64 (neg.f64 x)))

                                1. Initial program 14.3%

                                  \[\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                                2. Add Preprocessing
                                3. Taylor expanded in x around 0

                                  \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                                4. Step-by-step derivation
                                  1. Applied rewrites13.0%

                                    \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                                  2. Taylor expanded in x around 0

                                    \[\leadsto \left(\left(e^{x}\right) \bmod 1\right) \cdot \color{blue}{1} \]
                                  3. Step-by-step derivation
                                    1. Applied rewrites7.9%

                                      \[\leadsto \left(\left(e^{x}\right) \bmod 1\right) \cdot \color{blue}{1} \]
                                    2. Taylor expanded in x around 0

                                      \[\leadsto \left(\color{blue}{\left(1 + x\right)} \bmod 1\right) \cdot 1 \]
                                    3. Step-by-step derivation
                                      1. lower-+.f6493.0

                                        \[\leadsto \left(\color{blue}{\left(1 + x\right)} \bmod 1\right) \cdot 1 \]
                                    4. Applied rewrites93.0%

                                      \[\leadsto \left(\color{blue}{\left(1 + x\right)} \bmod 1\right) \cdot 1 \]
                                  4. Recombined 2 regimes into one program.
                                  5. Final simplification59.7%

                                    \[\leadsto \begin{array}{l} \mathbf{if}\;e^{-x} \cdot \left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \leq 10^{-8}:\\ \;\;\;\;1 \cdot \left(\left(\mathsf{fma}\left(0.5, x, 1\right) \cdot x\right) \bmod 1\right)\\ \mathbf{else}:\\ \;\;\;\;1 \cdot \left(\left(1 + x\right) \bmod 1\right)\\ \end{array} \]
                                  6. Add Preprocessing

                                  Alternative 5: 24.4% accurate, 3.8× speedup?

                                  \[\begin{array}{l} \\ 1 \cdot \left(\left(1 + x\right) \bmod 1\right) \end{array} \]
                                  (FPCore (x) :precision binary64 (* 1.0 (fmod (+ 1.0 x) 1.0)))
                                  double code(double x) {
                                  	return 1.0 * fmod((1.0 + x), 1.0);
                                  }
                                  
                                  real(8) function code(x)
                                      real(8), intent (in) :: x
                                      code = 1.0d0 * mod((1.0d0 + x), 1.0d0)
                                  end function
                                  
                                  def code(x):
                                  	return 1.0 * math.fmod((1.0 + x), 1.0)
                                  
                                  function code(x)
                                  	return Float64(1.0 * rem(Float64(1.0 + x), 1.0))
                                  end
                                  
                                  code[x_] := N[(1.0 * N[With[{TMP1 = N[(1.0 + x), $MachinePrecision], TMP2 = 1.0}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision]), $MachinePrecision]
                                  
                                  \begin{array}{l}
                                  
                                  \\
                                  1 \cdot \left(\left(1 + x\right) \bmod 1\right)
                                  \end{array}
                                  
                                  Derivation
                                  1. Initial program 7.6%

                                    \[\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in x around 0

                                    \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                                  4. Step-by-step derivation
                                    1. Applied rewrites7.2%

                                      \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                                    2. Taylor expanded in x around 0

                                      \[\leadsto \left(\left(e^{x}\right) \bmod 1\right) \cdot \color{blue}{1} \]
                                    3. Step-by-step derivation
                                      1. Applied rewrites6.0%

                                        \[\leadsto \left(\left(e^{x}\right) \bmod 1\right) \cdot \color{blue}{1} \]
                                      2. Taylor expanded in x around 0

                                        \[\leadsto \left(\color{blue}{\left(1 + x\right)} \bmod 1\right) \cdot 1 \]
                                      3. Step-by-step derivation
                                        1. lower-+.f6426.0

                                          \[\leadsto \left(\color{blue}{\left(1 + x\right)} \bmod 1\right) \cdot 1 \]
                                      4. Applied rewrites26.0%

                                        \[\leadsto \left(\color{blue}{\left(1 + x\right)} \bmod 1\right) \cdot 1 \]
                                      5. Final simplification26.0%

                                        \[\leadsto 1 \cdot \left(\left(1 + x\right) \bmod 1\right) \]
                                      6. Add Preprocessing

                                      Alternative 6: 23.2% accurate, 3.9× speedup?

                                      \[\begin{array}{l} \\ \left(1 \bmod 1\right) \cdot 1 \end{array} \]
                                      (FPCore (x) :precision binary64 (* (fmod 1.0 1.0) 1.0))
                                      double code(double x) {
                                      	return fmod(1.0, 1.0) * 1.0;
                                      }
                                      
                                      real(8) function code(x)
                                          real(8), intent (in) :: x
                                          code = mod(1.0d0, 1.0d0) * 1.0d0
                                      end function
                                      
                                      def code(x):
                                      	return math.fmod(1.0, 1.0) * 1.0
                                      
                                      function code(x)
                                      	return Float64(rem(1.0, 1.0) * 1.0)
                                      end
                                      
                                      code[x_] := N[(N[With[{TMP1 = 1.0, TMP2 = 1.0}, Mod[Abs[TMP1], Abs[TMP2]] * Sign[TMP1]], $MachinePrecision] * 1.0), $MachinePrecision]
                                      
                                      \begin{array}{l}
                                      
                                      \\
                                      \left(1 \bmod 1\right) \cdot 1
                                      \end{array}
                                      
                                      Derivation
                                      1. Initial program 7.6%

                                        \[\left(\left(e^{x}\right) \bmod \left(\sqrt{\cos x}\right)\right) \cdot e^{-x} \]
                                      2. Add Preprocessing
                                      3. Taylor expanded in x around 0

                                        \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                                      4. Step-by-step derivation
                                        1. Applied rewrites7.2%

                                          \[\leadsto \left(\left(e^{x}\right) \bmod \color{blue}{1}\right) \cdot e^{-x} \]
                                        2. Taylor expanded in x around 0

                                          \[\leadsto \left(\left(e^{x}\right) \bmod 1\right) \cdot \color{blue}{1} \]
                                        3. Step-by-step derivation
                                          1. Applied rewrites6.0%

                                            \[\leadsto \left(\left(e^{x}\right) \bmod 1\right) \cdot \color{blue}{1} \]
                                          2. Taylor expanded in x around 0

                                            \[\leadsto \left(\color{blue}{1} \bmod 1\right) \cdot 1 \]
                                          3. Step-by-step derivation
                                            1. Applied rewrites23.3%

                                              \[\leadsto \left(\color{blue}{1} \bmod 1\right) \cdot 1 \]
                                            2. Add Preprocessing

                                            Reproduce

                                            ?
                                            herbie shell --seed 2024276 
                                            (FPCore (x)
                                              :name "expfmod (used to be hard to sample)"
                                              :precision binary64
                                              (* (fmod (exp x) (sqrt (cos x))) (exp (- x))))