2nthrt (problem 3.4.6)

Percentage Accurate: 53.7% → 91.9%
Time: 24.0s
Alternatives: 21
Speedup: 1.9×

Specification

?
\[\begin{array}{l} \\ {\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \end{array} \]
(FPCore (x n)
 :precision binary64
 (- (pow (+ x 1.0) (/ 1.0 n)) (pow x (/ 1.0 n))))
double code(double x, double n) {
	return pow((x + 1.0), (1.0 / n)) - pow(x, (1.0 / n));
}
real(8) function code(x, n)
    real(8), intent (in) :: x
    real(8), intent (in) :: n
    code = ((x + 1.0d0) ** (1.0d0 / n)) - (x ** (1.0d0 / n))
end function
public static double code(double x, double n) {
	return Math.pow((x + 1.0), (1.0 / n)) - Math.pow(x, (1.0 / n));
}
def code(x, n):
	return math.pow((x + 1.0), (1.0 / n)) - math.pow(x, (1.0 / n))
function code(x, n)
	return Float64((Float64(x + 1.0) ^ Float64(1.0 / n)) - (x ^ Float64(1.0 / n)))
end
function tmp = code(x, n)
	tmp = ((x + 1.0) ^ (1.0 / n)) - (x ^ (1.0 / n));
end
code[x_, n_] := N[(N[Power[N[(x + 1.0), $MachinePrecision], N[(1.0 / n), $MachinePrecision]], $MachinePrecision] - N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 21 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 53.7% accurate, 1.0× speedup?

\[\begin{array}{l} \\ {\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \end{array} \]
(FPCore (x n)
 :precision binary64
 (- (pow (+ x 1.0) (/ 1.0 n)) (pow x (/ 1.0 n))))
double code(double x, double n) {
	return pow((x + 1.0), (1.0 / n)) - pow(x, (1.0 / n));
}
real(8) function code(x, n)
    real(8), intent (in) :: x
    real(8), intent (in) :: n
    code = ((x + 1.0d0) ** (1.0d0 / n)) - (x ** (1.0d0 / n))
end function
public static double code(double x, double n) {
	return Math.pow((x + 1.0), (1.0 / n)) - Math.pow(x, (1.0 / n));
}
def code(x, n):
	return math.pow((x + 1.0), (1.0 / n)) - math.pow(x, (1.0 / n))
function code(x, n)
	return Float64((Float64(x + 1.0) ^ Float64(1.0 / n)) - (x ^ Float64(1.0 / n)))
end
function tmp = code(x, n)
	tmp = ((x + 1.0) ^ (1.0 / n)) - (x ^ (1.0 / n));
end
code[x_, n_] := N[(N[Power[N[(x + 1.0), $MachinePrecision], N[(1.0 / n), $MachinePrecision]], $MachinePrecision] - N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)}
\end{array}

Alternative 1: 91.9% accurate, 0.8× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)\\ \mathbf{if}\;x \leq 3 \cdot 10^{-153}:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;x \leq 0.2:\\ \;\;\;\;\mathsf{fma}\left(x \cdot x, \frac{0.5}{n \cdot n} - \frac{0.5}{n}, t\_0\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{1}{\frac{x}{{x}^{\left({n}^{-1}\right)}}}}{n}\\ \end{array} \end{array} \]
(FPCore (x n)
 :precision binary64
 (let* ((t_0 (- (/ x n) (expm1 (/ (log x) n)))))
   (if (<= x 3e-153)
     t_0
     (if (<= x 0.2)
       (fma (* x x) (- (/ 0.5 (* n n)) (/ 0.5 n)) t_0)
       (/ (/ 1.0 (/ x (pow x (pow n -1.0)))) n)))))
double code(double x, double n) {
	double t_0 = (x / n) - expm1((log(x) / n));
	double tmp;
	if (x <= 3e-153) {
		tmp = t_0;
	} else if (x <= 0.2) {
		tmp = fma((x * x), ((0.5 / (n * n)) - (0.5 / n)), t_0);
	} else {
		tmp = (1.0 / (x / pow(x, pow(n, -1.0)))) / n;
	}
	return tmp;
}
function code(x, n)
	t_0 = Float64(Float64(x / n) - expm1(Float64(log(x) / n)))
	tmp = 0.0
	if (x <= 3e-153)
		tmp = t_0;
	elseif (x <= 0.2)
		tmp = fma(Float64(x * x), Float64(Float64(0.5 / Float64(n * n)) - Float64(0.5 / n)), t_0);
	else
		tmp = Float64(Float64(1.0 / Float64(x / (x ^ (n ^ -1.0)))) / n);
	end
	return tmp
end
code[x_, n_] := Block[{t$95$0 = N[(N[(x / n), $MachinePrecision] - N[(Exp[N[(N[Log[x], $MachinePrecision] / n), $MachinePrecision]] - 1), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[x, 3e-153], t$95$0, If[LessEqual[x, 0.2], N[(N[(x * x), $MachinePrecision] * N[(N[(0.5 / N[(n * n), $MachinePrecision]), $MachinePrecision] - N[(0.5 / n), $MachinePrecision]), $MachinePrecision] + t$95$0), $MachinePrecision], N[(N[(1.0 / N[(x / N[Power[x, N[Power[n, -1.0], $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)\\
\mathbf{if}\;x \leq 3 \cdot 10^{-153}:\\
\;\;\;\;t\_0\\

\mathbf{elif}\;x \leq 0.2:\\
\;\;\;\;\mathsf{fma}\left(x \cdot x, \frac{0.5}{n \cdot n} - \frac{0.5}{n}, t\_0\right)\\

\mathbf{else}:\\
\;\;\;\;\frac{\frac{1}{\frac{x}{{x}^{\left({n}^{-1}\right)}}}}{n}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if x < 3e-153

    1. Initial program 42.5%

      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \color{blue}{\left(1 + \frac{x}{n}\right) - e^{\frac{\log x}{n}}} \]
    4. Step-by-step derivation
      1. associate--l+N/A

        \[\leadsto \color{blue}{1 + \left(\frac{x}{n} - e^{\frac{\log x}{n}}\right)} \]
      2. +-commutativeN/A

        \[\leadsto \color{blue}{\left(\frac{x}{n} - e^{\frac{\log x}{n}}\right) + 1} \]
      3. *-rgt-identityN/A

        \[\leadsto \left(\frac{\color{blue}{x \cdot 1}}{n} - e^{\frac{\log x}{n}}\right) + 1 \]
      4. associate-*r/N/A

        \[\leadsto \left(\color{blue}{x \cdot \frac{1}{n}} - e^{\frac{\log x}{n}}\right) + 1 \]
      5. remove-double-negN/A

        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\frac{\color{blue}{\mathsf{neg}\left(\left(\mathsf{neg}\left(\log x\right)\right)\right)}}{n}}\right) + 1 \]
      6. mul-1-negN/A

        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\frac{\mathsf{neg}\left(\color{blue}{-1 \cdot \log x}\right)}{n}}\right) + 1 \]
      7. distribute-neg-fracN/A

        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\color{blue}{\mathsf{neg}\left(\frac{-1 \cdot \log x}{n}\right)}}\right) + 1 \]
      8. mul-1-negN/A

        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\mathsf{neg}\left(\frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}\right)}\right) + 1 \]
      9. log-recN/A

        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\mathsf{neg}\left(\frac{\color{blue}{\log \left(\frac{1}{x}\right)}}{n}\right)}\right) + 1 \]
      10. mul-1-negN/A

        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\color{blue}{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}\right) + 1 \]
      11. associate-+l-N/A

        \[\leadsto \color{blue}{x \cdot \frac{1}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right)} \]
      12. lower--.f64N/A

        \[\leadsto \color{blue}{x \cdot \frac{1}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right)} \]
      13. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{x \cdot 1}{n}} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
      14. *-rgt-identityN/A

        \[\leadsto \frac{\color{blue}{x}}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
      15. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{x}{n}} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
      16. lower-expm1.f64N/A

        \[\leadsto \frac{x}{n} - \color{blue}{\mathsf{expm1}\left(-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}\right)} \]
      17. mul-1-negN/A

        \[\leadsto \frac{x}{n} - \mathsf{expm1}\left(\color{blue}{\mathsf{neg}\left(\frac{\log \left(\frac{1}{x}\right)}{n}\right)}\right) \]
    5. Applied rewrites96.7%

      \[\leadsto \color{blue}{\frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)} \]

    if 3e-153 < x < 0.20000000000000001

    1. Initial program 27.6%

      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right) - e^{\frac{\log x}{n}}} \]
    4. Applied rewrites90.0%

      \[\leadsto \color{blue}{\mathsf{fma}\left(x \cdot x, \frac{0.5}{n \cdot n} - \frac{0.5}{n}, \frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)\right)} \]

    if 0.20000000000000001 < x

    1. Initial program 67.6%

      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in x around inf

      \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
    4. Step-by-step derivation
      1. associate-/l/N/A

        \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
      2. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
      3. lower-/.f64N/A

        \[\leadsto \frac{\color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}}{n} \]
      4. log-recN/A

        \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{x}}{n} \]
      5. mul-1-negN/A

        \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{x}}{n} \]
      6. associate-*r/N/A

        \[\leadsto \frac{\frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{x}}{n} \]
      7. associate-*r*N/A

        \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{x}}{n} \]
      8. metadata-evalN/A

        \[\leadsto \frac{\frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{x}}{n} \]
      9. *-commutativeN/A

        \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{x}}{n} \]
      10. associate-/l*N/A

        \[\leadsto \frac{\frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{x}}{n} \]
      11. exp-to-powN/A

        \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
      12. lower-pow.f64N/A

        \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
      13. lower-/.f6499.2

        \[\leadsto \frac{\frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{x}}{n} \]
    5. Applied rewrites99.2%

      \[\leadsto \color{blue}{\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}} \]
    6. Step-by-step derivation
      1. Applied rewrites99.2%

        \[\leadsto \frac{\frac{1}{\frac{x}{{x}^{\left({n}^{-1}\right)}}}}{n} \]
    7. Recombined 3 regimes into one program.
    8. Add Preprocessing

    Alternative 2: 77.0% accurate, 0.4× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} t_0 := {x}^{\left(\frac{1}{n}\right)}\\ t_1 := {\left(1 + x\right)}^{\left(\frac{1}{n}\right)} - t\_0\\ \mathbf{if}\;t\_1 \leq -0.01:\\ \;\;\;\;1 - t\_0\\ \mathbf{elif}\;t\_1 \leq 10^{-11}:\\ \;\;\;\;\frac{\log \left(\frac{1 + x}{x}\right)}{n}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{\frac{0.3333333333333333 \cdot n - \left(n \cdot x\right) \cdot 0.5}{\left(n \cdot x\right) \cdot n}}{x} + \frac{1}{n}}{x}\\ \end{array} \end{array} \]
    (FPCore (x n)
     :precision binary64
     (let* ((t_0 (pow x (/ 1.0 n))) (t_1 (- (pow (+ 1.0 x) (/ 1.0 n)) t_0)))
       (if (<= t_1 -0.01)
         (- 1.0 t_0)
         (if (<= t_1 1e-11)
           (/ (log (/ (+ 1.0 x) x)) n)
           (/
            (+
             (/ (/ (- (* 0.3333333333333333 n) (* (* n x) 0.5)) (* (* n x) n)) x)
             (/ 1.0 n))
            x)))))
    double code(double x, double n) {
    	double t_0 = pow(x, (1.0 / n));
    	double t_1 = pow((1.0 + x), (1.0 / n)) - t_0;
    	double tmp;
    	if (t_1 <= -0.01) {
    		tmp = 1.0 - t_0;
    	} else if (t_1 <= 1e-11) {
    		tmp = log(((1.0 + x) / x)) / n;
    	} else {
    		tmp = (((((0.3333333333333333 * n) - ((n * x) * 0.5)) / ((n * x) * n)) / x) + (1.0 / n)) / x;
    	}
    	return tmp;
    }
    
    real(8) function code(x, n)
        real(8), intent (in) :: x
        real(8), intent (in) :: n
        real(8) :: t_0
        real(8) :: t_1
        real(8) :: tmp
        t_0 = x ** (1.0d0 / n)
        t_1 = ((1.0d0 + x) ** (1.0d0 / n)) - t_0
        if (t_1 <= (-0.01d0)) then
            tmp = 1.0d0 - t_0
        else if (t_1 <= 1d-11) then
            tmp = log(((1.0d0 + x) / x)) / n
        else
            tmp = (((((0.3333333333333333d0 * n) - ((n * x) * 0.5d0)) / ((n * x) * n)) / x) + (1.0d0 / n)) / x
        end if
        code = tmp
    end function
    
    public static double code(double x, double n) {
    	double t_0 = Math.pow(x, (1.0 / n));
    	double t_1 = Math.pow((1.0 + x), (1.0 / n)) - t_0;
    	double tmp;
    	if (t_1 <= -0.01) {
    		tmp = 1.0 - t_0;
    	} else if (t_1 <= 1e-11) {
    		tmp = Math.log(((1.0 + x) / x)) / n;
    	} else {
    		tmp = (((((0.3333333333333333 * n) - ((n * x) * 0.5)) / ((n * x) * n)) / x) + (1.0 / n)) / x;
    	}
    	return tmp;
    }
    
    def code(x, n):
    	t_0 = math.pow(x, (1.0 / n))
    	t_1 = math.pow((1.0 + x), (1.0 / n)) - t_0
    	tmp = 0
    	if t_1 <= -0.01:
    		tmp = 1.0 - t_0
    	elif t_1 <= 1e-11:
    		tmp = math.log(((1.0 + x) / x)) / n
    	else:
    		tmp = (((((0.3333333333333333 * n) - ((n * x) * 0.5)) / ((n * x) * n)) / x) + (1.0 / n)) / x
    	return tmp
    
    function code(x, n)
    	t_0 = x ^ Float64(1.0 / n)
    	t_1 = Float64((Float64(1.0 + x) ^ Float64(1.0 / n)) - t_0)
    	tmp = 0.0
    	if (t_1 <= -0.01)
    		tmp = Float64(1.0 - t_0);
    	elseif (t_1 <= 1e-11)
    		tmp = Float64(log(Float64(Float64(1.0 + x) / x)) / n);
    	else
    		tmp = Float64(Float64(Float64(Float64(Float64(Float64(0.3333333333333333 * n) - Float64(Float64(n * x) * 0.5)) / Float64(Float64(n * x) * n)) / x) + Float64(1.0 / n)) / x);
    	end
    	return tmp
    end
    
    function tmp_2 = code(x, n)
    	t_0 = x ^ (1.0 / n);
    	t_1 = ((1.0 + x) ^ (1.0 / n)) - t_0;
    	tmp = 0.0;
    	if (t_1 <= -0.01)
    		tmp = 1.0 - t_0;
    	elseif (t_1 <= 1e-11)
    		tmp = log(((1.0 + x) / x)) / n;
    	else
    		tmp = (((((0.3333333333333333 * n) - ((n * x) * 0.5)) / ((n * x) * n)) / x) + (1.0 / n)) / x;
    	end
    	tmp_2 = tmp;
    end
    
    code[x_, n_] := Block[{t$95$0 = N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]}, Block[{t$95$1 = N[(N[Power[N[(1.0 + x), $MachinePrecision], N[(1.0 / n), $MachinePrecision]], $MachinePrecision] - t$95$0), $MachinePrecision]}, If[LessEqual[t$95$1, -0.01], N[(1.0 - t$95$0), $MachinePrecision], If[LessEqual[t$95$1, 1e-11], N[(N[Log[N[(N[(1.0 + x), $MachinePrecision] / x), $MachinePrecision]], $MachinePrecision] / n), $MachinePrecision], N[(N[(N[(N[(N[(N[(0.3333333333333333 * n), $MachinePrecision] - N[(N[(n * x), $MachinePrecision] * 0.5), $MachinePrecision]), $MachinePrecision] / N[(N[(n * x), $MachinePrecision] * n), $MachinePrecision]), $MachinePrecision] / x), $MachinePrecision] + N[(1.0 / n), $MachinePrecision]), $MachinePrecision] / x), $MachinePrecision]]]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    t_0 := {x}^{\left(\frac{1}{n}\right)}\\
    t_1 := {\left(1 + x\right)}^{\left(\frac{1}{n}\right)} - t\_0\\
    \mathbf{if}\;t\_1 \leq -0.01:\\
    \;\;\;\;1 - t\_0\\
    
    \mathbf{elif}\;t\_1 \leq 10^{-11}:\\
    \;\;\;\;\frac{\log \left(\frac{1 + x}{x}\right)}{n}\\
    
    \mathbf{else}:\\
    \;\;\;\;\frac{\frac{\frac{0.3333333333333333 \cdot n - \left(n \cdot x\right) \cdot 0.5}{\left(n \cdot x\right) \cdot n}}{x} + \frac{1}{n}}{x}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 3 regimes
    2. if (-.f64 (pow.f64 (+.f64 x #s(literal 1 binary64)) (/.f64 #s(literal 1 binary64) n)) (pow.f64 x (/.f64 #s(literal 1 binary64) n))) < -0.0100000000000000002

      1. Initial program 99.8%

        \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
      2. Add Preprocessing
      3. Taylor expanded in x around 0

        \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
      4. Step-by-step derivation
        1. Applied rewrites99.0%

          \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]

        if -0.0100000000000000002 < (-.f64 (pow.f64 (+.f64 x #s(literal 1 binary64)) (/.f64 #s(literal 1 binary64) n)) (pow.f64 x (/.f64 #s(literal 1 binary64) n))) < 9.99999999999999939e-12

        1. Initial program 39.4%

          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
        2. Add Preprocessing
        3. Taylor expanded in n around inf

          \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
        4. Step-by-step derivation
          1. lower-/.f64N/A

            \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
          2. lower--.f64N/A

            \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
          3. lower-log1p.f64N/A

            \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
          4. lower-log.f6481.6

            \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
        5. Applied rewrites81.6%

          \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
        6. Step-by-step derivation
          1. Applied rewrites81.7%

            \[\leadsto \frac{\log \left(\frac{1 + x}{x}\right)}{n} \]

          if 9.99999999999999939e-12 < (-.f64 (pow.f64 (+.f64 x #s(literal 1 binary64)) (/.f64 #s(literal 1 binary64) n)) (pow.f64 x (/.f64 #s(literal 1 binary64) n)))

          1. Initial program 51.3%

            \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
          2. Add Preprocessing
          3. Taylor expanded in n around inf

            \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
          4. Step-by-step derivation
            1. lower-/.f64N/A

              \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
            2. lower--.f64N/A

              \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
            3. lower-log1p.f64N/A

              \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
            4. lower-log.f648.8

              \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
          5. Applied rewrites8.8%

            \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
          6. Taylor expanded in x around -inf

            \[\leadsto -1 \cdot \color{blue}{\frac{-1 \cdot \frac{\frac{1}{3} \cdot \frac{1}{n \cdot x} - \frac{1}{2} \cdot \frac{1}{n}}{x} - \frac{1}{n}}{x}} \]
          7. Step-by-step derivation
            1. Applied rewrites46.5%

              \[\leadsto \frac{\frac{\frac{\frac{0.3333333333333333}{n}}{x} - \frac{0.5}{n}}{x} + \frac{1}{n}}{\color{blue}{x}} \]
            2. Step-by-step derivation
              1. Applied rewrites51.6%

                \[\leadsto \frac{\frac{\frac{0.3333333333333333 \cdot n - \left(n \cdot x\right) \cdot 0.5}{\left(n \cdot x\right) \cdot n}}{x} + \frac{1}{n}}{x} \]
            3. Recombined 3 regimes into one program.
            4. Final simplification79.4%

              \[\leadsto \begin{array}{l} \mathbf{if}\;{\left(1 + x\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \leq -0.01:\\ \;\;\;\;1 - {x}^{\left(\frac{1}{n}\right)}\\ \mathbf{elif}\;{\left(1 + x\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \leq 10^{-11}:\\ \;\;\;\;\frac{\log \left(\frac{1 + x}{x}\right)}{n}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{\frac{0.3333333333333333 \cdot n - \left(n \cdot x\right) \cdot 0.5}{\left(n \cdot x\right) \cdot n}}{x} + \frac{1}{n}}{x}\\ \end{array} \]
            5. Add Preprocessing

            Alternative 3: 91.9% accurate, 1.0× speedup?

            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 1:\\ \;\;\;\;\frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{1}{\frac{x}{{x}^{\left({n}^{-1}\right)}}}}{n}\\ \end{array} \end{array} \]
            (FPCore (x n)
             :precision binary64
             (if (<= x 1.0)
               (- (/ x n) (expm1 (/ (log x) n)))
               (/ (/ 1.0 (/ x (pow x (pow n -1.0)))) n)))
            double code(double x, double n) {
            	double tmp;
            	if (x <= 1.0) {
            		tmp = (x / n) - expm1((log(x) / n));
            	} else {
            		tmp = (1.0 / (x / pow(x, pow(n, -1.0)))) / n;
            	}
            	return tmp;
            }
            
            public static double code(double x, double n) {
            	double tmp;
            	if (x <= 1.0) {
            		tmp = (x / n) - Math.expm1((Math.log(x) / n));
            	} else {
            		tmp = (1.0 / (x / Math.pow(x, Math.pow(n, -1.0)))) / n;
            	}
            	return tmp;
            }
            
            def code(x, n):
            	tmp = 0
            	if x <= 1.0:
            		tmp = (x / n) - math.expm1((math.log(x) / n))
            	else:
            		tmp = (1.0 / (x / math.pow(x, math.pow(n, -1.0)))) / n
            	return tmp
            
            function code(x, n)
            	tmp = 0.0
            	if (x <= 1.0)
            		tmp = Float64(Float64(x / n) - expm1(Float64(log(x) / n)));
            	else
            		tmp = Float64(Float64(1.0 / Float64(x / (x ^ (n ^ -1.0)))) / n);
            	end
            	return tmp
            end
            
            code[x_, n_] := If[LessEqual[x, 1.0], N[(N[(x / n), $MachinePrecision] - N[(Exp[N[(N[Log[x], $MachinePrecision] / n), $MachinePrecision]] - 1), $MachinePrecision]), $MachinePrecision], N[(N[(1.0 / N[(x / N[Power[x, N[Power[n, -1.0], $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision]]
            
            \begin{array}{l}
            
            \\
            \begin{array}{l}
            \mathbf{if}\;x \leq 1:\\
            \;\;\;\;\frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)\\
            
            \mathbf{else}:\\
            \;\;\;\;\frac{\frac{1}{\frac{x}{{x}^{\left({n}^{-1}\right)}}}}{n}\\
            
            
            \end{array}
            \end{array}
            
            Derivation
            1. Split input into 2 regimes
            2. if x < 1

              1. Initial program 34.6%

                \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
              2. Add Preprocessing
              3. Taylor expanded in x around 0

                \[\leadsto \color{blue}{\left(1 + \frac{x}{n}\right) - e^{\frac{\log x}{n}}} \]
              4. Step-by-step derivation
                1. associate--l+N/A

                  \[\leadsto \color{blue}{1 + \left(\frac{x}{n} - e^{\frac{\log x}{n}}\right)} \]
                2. +-commutativeN/A

                  \[\leadsto \color{blue}{\left(\frac{x}{n} - e^{\frac{\log x}{n}}\right) + 1} \]
                3. *-rgt-identityN/A

                  \[\leadsto \left(\frac{\color{blue}{x \cdot 1}}{n} - e^{\frac{\log x}{n}}\right) + 1 \]
                4. associate-*r/N/A

                  \[\leadsto \left(\color{blue}{x \cdot \frac{1}{n}} - e^{\frac{\log x}{n}}\right) + 1 \]
                5. remove-double-negN/A

                  \[\leadsto \left(x \cdot \frac{1}{n} - e^{\frac{\color{blue}{\mathsf{neg}\left(\left(\mathsf{neg}\left(\log x\right)\right)\right)}}{n}}\right) + 1 \]
                6. mul-1-negN/A

                  \[\leadsto \left(x \cdot \frac{1}{n} - e^{\frac{\mathsf{neg}\left(\color{blue}{-1 \cdot \log x}\right)}{n}}\right) + 1 \]
                7. distribute-neg-fracN/A

                  \[\leadsto \left(x \cdot \frac{1}{n} - e^{\color{blue}{\mathsf{neg}\left(\frac{-1 \cdot \log x}{n}\right)}}\right) + 1 \]
                8. mul-1-negN/A

                  \[\leadsto \left(x \cdot \frac{1}{n} - e^{\mathsf{neg}\left(\frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}\right)}\right) + 1 \]
                9. log-recN/A

                  \[\leadsto \left(x \cdot \frac{1}{n} - e^{\mathsf{neg}\left(\frac{\color{blue}{\log \left(\frac{1}{x}\right)}}{n}\right)}\right) + 1 \]
                10. mul-1-negN/A

                  \[\leadsto \left(x \cdot \frac{1}{n} - e^{\color{blue}{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}\right) + 1 \]
                11. associate-+l-N/A

                  \[\leadsto \color{blue}{x \cdot \frac{1}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right)} \]
                12. lower--.f64N/A

                  \[\leadsto \color{blue}{x \cdot \frac{1}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right)} \]
                13. associate-*r/N/A

                  \[\leadsto \color{blue}{\frac{x \cdot 1}{n}} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
                14. *-rgt-identityN/A

                  \[\leadsto \frac{\color{blue}{x}}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
                15. lower-/.f64N/A

                  \[\leadsto \color{blue}{\frac{x}{n}} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
                16. lower-expm1.f64N/A

                  \[\leadsto \frac{x}{n} - \color{blue}{\mathsf{expm1}\left(-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}\right)} \]
                17. mul-1-negN/A

                  \[\leadsto \frac{x}{n} - \mathsf{expm1}\left(\color{blue}{\mathsf{neg}\left(\frac{\log \left(\frac{1}{x}\right)}{n}\right)}\right) \]
              5. Applied rewrites87.6%

                \[\leadsto \color{blue}{\frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)} \]

              if 1 < x

              1. Initial program 67.6%

                \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
              2. Add Preprocessing
              3. Taylor expanded in x around inf

                \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
              4. Step-by-step derivation
                1. associate-/l/N/A

                  \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                2. lower-/.f64N/A

                  \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                3. lower-/.f64N/A

                  \[\leadsto \frac{\color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}}{n} \]
                4. log-recN/A

                  \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{x}}{n} \]
                5. mul-1-negN/A

                  \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{x}}{n} \]
                6. associate-*r/N/A

                  \[\leadsto \frac{\frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{x}}{n} \]
                7. associate-*r*N/A

                  \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{x}}{n} \]
                8. metadata-evalN/A

                  \[\leadsto \frac{\frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{x}}{n} \]
                9. *-commutativeN/A

                  \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{x}}{n} \]
                10. associate-/l*N/A

                  \[\leadsto \frac{\frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{x}}{n} \]
                11. exp-to-powN/A

                  \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                12. lower-pow.f64N/A

                  \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                13. lower-/.f6499.2

                  \[\leadsto \frac{\frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{x}}{n} \]
              5. Applied rewrites99.2%

                \[\leadsto \color{blue}{\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}} \]
              6. Step-by-step derivation
                1. Applied rewrites99.2%

                  \[\leadsto \frac{\frac{1}{\frac{x}{{x}^{\left({n}^{-1}\right)}}}}{n} \]
              7. Recombined 2 regimes into one program.
              8. Add Preprocessing

              Alternative 4: 82.5% accurate, 1.0× speedup?

              \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-22}:\\ \;\;\;\;\frac{{x}^{\left({n}^{-1}\right)}}{n \cdot x}\\ \mathbf{elif}\;\frac{1}{n} \leq 5 \cdot 10^{-11}:\\ \;\;\;\;\frac{\log \left(\frac{1 + x}{x}\right)}{n}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{0.5}{n} - 0.5}{n}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)}\\ \end{array} \end{array} \]
              (FPCore (x n)
               :precision binary64
               (if (<= (/ 1.0 n) -4e-22)
                 (/ (pow x (pow n -1.0)) (* n x))
                 (if (<= (/ 1.0 n) 5e-11)
                   (/ (log (/ (+ 1.0 x) x)) n)
                   (-
                    (fma (fma (/ (- (/ 0.5 n) 0.5) n) x (/ 1.0 n)) x 1.0)
                    (pow x (/ 1.0 n))))))
              double code(double x, double n) {
              	double tmp;
              	if ((1.0 / n) <= -4e-22) {
              		tmp = pow(x, pow(n, -1.0)) / (n * x);
              	} else if ((1.0 / n) <= 5e-11) {
              		tmp = log(((1.0 + x) / x)) / n;
              	} else {
              		tmp = fma(fma((((0.5 / n) - 0.5) / n), x, (1.0 / n)), x, 1.0) - pow(x, (1.0 / n));
              	}
              	return tmp;
              }
              
              function code(x, n)
              	tmp = 0.0
              	if (Float64(1.0 / n) <= -4e-22)
              		tmp = Float64((x ^ (n ^ -1.0)) / Float64(n * x));
              	elseif (Float64(1.0 / n) <= 5e-11)
              		tmp = Float64(log(Float64(Float64(1.0 + x) / x)) / n);
              	else
              		tmp = Float64(fma(fma(Float64(Float64(Float64(0.5 / n) - 0.5) / n), x, Float64(1.0 / n)), x, 1.0) - (x ^ Float64(1.0 / n)));
              	end
              	return tmp
              end
              
              code[x_, n_] := If[LessEqual[N[(1.0 / n), $MachinePrecision], -4e-22], N[(N[Power[x, N[Power[n, -1.0], $MachinePrecision]], $MachinePrecision] / N[(n * x), $MachinePrecision]), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 5e-11], N[(N[Log[N[(N[(1.0 + x), $MachinePrecision] / x), $MachinePrecision]], $MachinePrecision] / n), $MachinePrecision], N[(N[(N[(N[(N[(N[(0.5 / n), $MachinePrecision] - 0.5), $MachinePrecision] / n), $MachinePrecision] * x + N[(1.0 / n), $MachinePrecision]), $MachinePrecision] * x + 1.0), $MachinePrecision] - N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]]
              
              \begin{array}{l}
              
              \\
              \begin{array}{l}
              \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-22}:\\
              \;\;\;\;\frac{{x}^{\left({n}^{-1}\right)}}{n \cdot x}\\
              
              \mathbf{elif}\;\frac{1}{n} \leq 5 \cdot 10^{-11}:\\
              \;\;\;\;\frac{\log \left(\frac{1 + x}{x}\right)}{n}\\
              
              \mathbf{else}:\\
              \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{0.5}{n} - 0.5}{n}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)}\\
              
              
              \end{array}
              \end{array}
              
              Derivation
              1. Split input into 3 regimes
              2. if (/.f64 #s(literal 1 binary64) n) < -4.0000000000000002e-22

                1. Initial program 93.7%

                  \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                2. Add Preprocessing
                3. Taylor expanded in x around inf

                  \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                4. Step-by-step derivation
                  1. associate-/l/N/A

                    \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                  2. lower-/.f64N/A

                    \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                  3. lower-/.f64N/A

                    \[\leadsto \frac{\color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}}{n} \]
                  4. log-recN/A

                    \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{x}}{n} \]
                  5. mul-1-negN/A

                    \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{x}}{n} \]
                  6. associate-*r/N/A

                    \[\leadsto \frac{\frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{x}}{n} \]
                  7. associate-*r*N/A

                    \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{x}}{n} \]
                  8. metadata-evalN/A

                    \[\leadsto \frac{\frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{x}}{n} \]
                  9. *-commutativeN/A

                    \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{x}}{n} \]
                  10. associate-/l*N/A

                    \[\leadsto \frac{\frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{x}}{n} \]
                  11. exp-to-powN/A

                    \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                  12. lower-pow.f64N/A

                    \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                  13. lower-/.f6496.0

                    \[\leadsto \frac{\frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                5. Applied rewrites96.0%

                  \[\leadsto \color{blue}{\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}} \]
                6. Step-by-step derivation
                  1. Applied rewrites96.0%

                    \[\leadsto \frac{{x}^{\left({n}^{-1}\right)}}{\color{blue}{n \cdot x}} \]

                  if -4.0000000000000002e-22 < (/.f64 #s(literal 1 binary64) n) < 5.00000000000000018e-11

                  1. Initial program 25.7%

                    \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                  2. Add Preprocessing
                  3. Taylor expanded in n around inf

                    \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                  4. Step-by-step derivation
                    1. lower-/.f64N/A

                      \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                    2. lower--.f64N/A

                      \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                    3. lower-log1p.f64N/A

                      \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                    4. lower-log.f6479.9

                      \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                  5. Applied rewrites79.9%

                    \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                  6. Step-by-step derivation
                    1. Applied rewrites80.1%

                      \[\leadsto \frac{\log \left(\frac{1 + x}{x}\right)}{n} \]

                    if 5.00000000000000018e-11 < (/.f64 #s(literal 1 binary64) n)

                    1. Initial program 51.3%

                      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                    2. Add Preprocessing
                    3. Taylor expanded in x around 0

                      \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                    4. Step-by-step derivation
                      1. Applied rewrites46.0%

                        \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                      2. Taylor expanded in x around 0

                        \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                      3. Step-by-step derivation
                        1. +-commutativeN/A

                          \[\leadsto \color{blue}{\left(x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) + 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                        2. *-commutativeN/A

                          \[\leadsto \left(\color{blue}{\left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) \cdot x} + 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                        3. lower-fma.f64N/A

                          \[\leadsto \color{blue}{\mathsf{fma}\left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}, x, 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                      4. Applied rewrites81.4%

                        \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{0.5}{n} - 0.5}{n}, x, \frac{1}{n}\right), x, 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                    5. Recombined 3 regimes into one program.
                    6. Add Preprocessing

                    Alternative 5: 91.9% accurate, 1.0× speedup?

                    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 1:\\ \;\;\;\;\frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}\\ \end{array} \end{array} \]
                    (FPCore (x n)
                     :precision binary64
                     (if (<= x 1.0)
                       (- (/ x n) (expm1 (/ (log x) n)))
                       (/ (/ (pow x (/ 1.0 n)) x) n)))
                    double code(double x, double n) {
                    	double tmp;
                    	if (x <= 1.0) {
                    		tmp = (x / n) - expm1((log(x) / n));
                    	} else {
                    		tmp = (pow(x, (1.0 / n)) / x) / n;
                    	}
                    	return tmp;
                    }
                    
                    public static double code(double x, double n) {
                    	double tmp;
                    	if (x <= 1.0) {
                    		tmp = (x / n) - Math.expm1((Math.log(x) / n));
                    	} else {
                    		tmp = (Math.pow(x, (1.0 / n)) / x) / n;
                    	}
                    	return tmp;
                    }
                    
                    def code(x, n):
                    	tmp = 0
                    	if x <= 1.0:
                    		tmp = (x / n) - math.expm1((math.log(x) / n))
                    	else:
                    		tmp = (math.pow(x, (1.0 / n)) / x) / n
                    	return tmp
                    
                    function code(x, n)
                    	tmp = 0.0
                    	if (x <= 1.0)
                    		tmp = Float64(Float64(x / n) - expm1(Float64(log(x) / n)));
                    	else
                    		tmp = Float64(Float64((x ^ Float64(1.0 / n)) / x) / n);
                    	end
                    	return tmp
                    end
                    
                    code[x_, n_] := If[LessEqual[x, 1.0], N[(N[(x / n), $MachinePrecision] - N[(Exp[N[(N[Log[x], $MachinePrecision] / n), $MachinePrecision]] - 1), $MachinePrecision]), $MachinePrecision], N[(N[(N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision] / x), $MachinePrecision] / n), $MachinePrecision]]
                    
                    \begin{array}{l}
                    
                    \\
                    \begin{array}{l}
                    \mathbf{if}\;x \leq 1:\\
                    \;\;\;\;\frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)\\
                    
                    \mathbf{else}:\\
                    \;\;\;\;\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}\\
                    
                    
                    \end{array}
                    \end{array}
                    
                    Derivation
                    1. Split input into 2 regimes
                    2. if x < 1

                      1. Initial program 34.6%

                        \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                      2. Add Preprocessing
                      3. Taylor expanded in x around 0

                        \[\leadsto \color{blue}{\left(1 + \frac{x}{n}\right) - e^{\frac{\log x}{n}}} \]
                      4. Step-by-step derivation
                        1. associate--l+N/A

                          \[\leadsto \color{blue}{1 + \left(\frac{x}{n} - e^{\frac{\log x}{n}}\right)} \]
                        2. +-commutativeN/A

                          \[\leadsto \color{blue}{\left(\frac{x}{n} - e^{\frac{\log x}{n}}\right) + 1} \]
                        3. *-rgt-identityN/A

                          \[\leadsto \left(\frac{\color{blue}{x \cdot 1}}{n} - e^{\frac{\log x}{n}}\right) + 1 \]
                        4. associate-*r/N/A

                          \[\leadsto \left(\color{blue}{x \cdot \frac{1}{n}} - e^{\frac{\log x}{n}}\right) + 1 \]
                        5. remove-double-negN/A

                          \[\leadsto \left(x \cdot \frac{1}{n} - e^{\frac{\color{blue}{\mathsf{neg}\left(\left(\mathsf{neg}\left(\log x\right)\right)\right)}}{n}}\right) + 1 \]
                        6. mul-1-negN/A

                          \[\leadsto \left(x \cdot \frac{1}{n} - e^{\frac{\mathsf{neg}\left(\color{blue}{-1 \cdot \log x}\right)}{n}}\right) + 1 \]
                        7. distribute-neg-fracN/A

                          \[\leadsto \left(x \cdot \frac{1}{n} - e^{\color{blue}{\mathsf{neg}\left(\frac{-1 \cdot \log x}{n}\right)}}\right) + 1 \]
                        8. mul-1-negN/A

                          \[\leadsto \left(x \cdot \frac{1}{n} - e^{\mathsf{neg}\left(\frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}\right)}\right) + 1 \]
                        9. log-recN/A

                          \[\leadsto \left(x \cdot \frac{1}{n} - e^{\mathsf{neg}\left(\frac{\color{blue}{\log \left(\frac{1}{x}\right)}}{n}\right)}\right) + 1 \]
                        10. mul-1-negN/A

                          \[\leadsto \left(x \cdot \frac{1}{n} - e^{\color{blue}{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}\right) + 1 \]
                        11. associate-+l-N/A

                          \[\leadsto \color{blue}{x \cdot \frac{1}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right)} \]
                        12. lower--.f64N/A

                          \[\leadsto \color{blue}{x \cdot \frac{1}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right)} \]
                        13. associate-*r/N/A

                          \[\leadsto \color{blue}{\frac{x \cdot 1}{n}} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
                        14. *-rgt-identityN/A

                          \[\leadsto \frac{\color{blue}{x}}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
                        15. lower-/.f64N/A

                          \[\leadsto \color{blue}{\frac{x}{n}} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
                        16. lower-expm1.f64N/A

                          \[\leadsto \frac{x}{n} - \color{blue}{\mathsf{expm1}\left(-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}\right)} \]
                        17. mul-1-negN/A

                          \[\leadsto \frac{x}{n} - \mathsf{expm1}\left(\color{blue}{\mathsf{neg}\left(\frac{\log \left(\frac{1}{x}\right)}{n}\right)}\right) \]
                      5. Applied rewrites87.6%

                        \[\leadsto \color{blue}{\frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)} \]

                      if 1 < x

                      1. Initial program 67.6%

                        \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                      2. Add Preprocessing
                      3. Taylor expanded in x around inf

                        \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                      4. Step-by-step derivation
                        1. associate-/l/N/A

                          \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                        2. lower-/.f64N/A

                          \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                        3. lower-/.f64N/A

                          \[\leadsto \frac{\color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}}{n} \]
                        4. log-recN/A

                          \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{x}}{n} \]
                        5. mul-1-negN/A

                          \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{x}}{n} \]
                        6. associate-*r/N/A

                          \[\leadsto \frac{\frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{x}}{n} \]
                        7. associate-*r*N/A

                          \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{x}}{n} \]
                        8. metadata-evalN/A

                          \[\leadsto \frac{\frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{x}}{n} \]
                        9. *-commutativeN/A

                          \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{x}}{n} \]
                        10. associate-/l*N/A

                          \[\leadsto \frac{\frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{x}}{n} \]
                        11. exp-to-powN/A

                          \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                        12. lower-pow.f64N/A

                          \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                        13. lower-/.f6499.2

                          \[\leadsto \frac{\frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                      5. Applied rewrites99.2%

                        \[\leadsto \color{blue}{\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}} \]
                    3. Recombined 2 regimes into one program.
                    4. Add Preprocessing

                    Alternative 6: 82.6% accurate, 1.2× speedup?

                    \[\begin{array}{l} \\ \begin{array}{l} t_0 := {x}^{\left(\frac{1}{n}\right)}\\ \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-22}:\\ \;\;\;\;\frac{\frac{t\_0}{x}}{n}\\ \mathbf{elif}\;\frac{1}{n} \leq 5 \cdot 10^{-11}:\\ \;\;\;\;\frac{\log \left(\frac{1 + x}{x}\right)}{n}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{0.5}{n} - 0.5}{n}, x, \frac{1}{n}\right), x, 1\right) - t\_0\\ \end{array} \end{array} \]
                    (FPCore (x n)
                     :precision binary64
                     (let* ((t_0 (pow x (/ 1.0 n))))
                       (if (<= (/ 1.0 n) -4e-22)
                         (/ (/ t_0 x) n)
                         (if (<= (/ 1.0 n) 5e-11)
                           (/ (log (/ (+ 1.0 x) x)) n)
                           (- (fma (fma (/ (- (/ 0.5 n) 0.5) n) x (/ 1.0 n)) x 1.0) t_0)))))
                    double code(double x, double n) {
                    	double t_0 = pow(x, (1.0 / n));
                    	double tmp;
                    	if ((1.0 / n) <= -4e-22) {
                    		tmp = (t_0 / x) / n;
                    	} else if ((1.0 / n) <= 5e-11) {
                    		tmp = log(((1.0 + x) / x)) / n;
                    	} else {
                    		tmp = fma(fma((((0.5 / n) - 0.5) / n), x, (1.0 / n)), x, 1.0) - t_0;
                    	}
                    	return tmp;
                    }
                    
                    function code(x, n)
                    	t_0 = x ^ Float64(1.0 / n)
                    	tmp = 0.0
                    	if (Float64(1.0 / n) <= -4e-22)
                    		tmp = Float64(Float64(t_0 / x) / n);
                    	elseif (Float64(1.0 / n) <= 5e-11)
                    		tmp = Float64(log(Float64(Float64(1.0 + x) / x)) / n);
                    	else
                    		tmp = Float64(fma(fma(Float64(Float64(Float64(0.5 / n) - 0.5) / n), x, Float64(1.0 / n)), x, 1.0) - t_0);
                    	end
                    	return tmp
                    end
                    
                    code[x_, n_] := Block[{t$95$0 = N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[N[(1.0 / n), $MachinePrecision], -4e-22], N[(N[(t$95$0 / x), $MachinePrecision] / n), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 5e-11], N[(N[Log[N[(N[(1.0 + x), $MachinePrecision] / x), $MachinePrecision]], $MachinePrecision] / n), $MachinePrecision], N[(N[(N[(N[(N[(N[(0.5 / n), $MachinePrecision] - 0.5), $MachinePrecision] / n), $MachinePrecision] * x + N[(1.0 / n), $MachinePrecision]), $MachinePrecision] * x + 1.0), $MachinePrecision] - t$95$0), $MachinePrecision]]]]
                    
                    \begin{array}{l}
                    
                    \\
                    \begin{array}{l}
                    t_0 := {x}^{\left(\frac{1}{n}\right)}\\
                    \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-22}:\\
                    \;\;\;\;\frac{\frac{t\_0}{x}}{n}\\
                    
                    \mathbf{elif}\;\frac{1}{n} \leq 5 \cdot 10^{-11}:\\
                    \;\;\;\;\frac{\log \left(\frac{1 + x}{x}\right)}{n}\\
                    
                    \mathbf{else}:\\
                    \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{0.5}{n} - 0.5}{n}, x, \frac{1}{n}\right), x, 1\right) - t\_0\\
                    
                    
                    \end{array}
                    \end{array}
                    
                    Derivation
                    1. Split input into 3 regimes
                    2. if (/.f64 #s(literal 1 binary64) n) < -4.0000000000000002e-22

                      1. Initial program 93.7%

                        \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                      2. Add Preprocessing
                      3. Taylor expanded in x around inf

                        \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                      4. Step-by-step derivation
                        1. associate-/l/N/A

                          \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                        2. lower-/.f64N/A

                          \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                        3. lower-/.f64N/A

                          \[\leadsto \frac{\color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}}{n} \]
                        4. log-recN/A

                          \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{x}}{n} \]
                        5. mul-1-negN/A

                          \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{x}}{n} \]
                        6. associate-*r/N/A

                          \[\leadsto \frac{\frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{x}}{n} \]
                        7. associate-*r*N/A

                          \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{x}}{n} \]
                        8. metadata-evalN/A

                          \[\leadsto \frac{\frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{x}}{n} \]
                        9. *-commutativeN/A

                          \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{x}}{n} \]
                        10. associate-/l*N/A

                          \[\leadsto \frac{\frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{x}}{n} \]
                        11. exp-to-powN/A

                          \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                        12. lower-pow.f64N/A

                          \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                        13. lower-/.f6496.0

                          \[\leadsto \frac{\frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                      5. Applied rewrites96.0%

                        \[\leadsto \color{blue}{\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}} \]

                      if -4.0000000000000002e-22 < (/.f64 #s(literal 1 binary64) n) < 5.00000000000000018e-11

                      1. Initial program 25.7%

                        \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                      2. Add Preprocessing
                      3. Taylor expanded in n around inf

                        \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                      4. Step-by-step derivation
                        1. lower-/.f64N/A

                          \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                        2. lower--.f64N/A

                          \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                        3. lower-log1p.f64N/A

                          \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                        4. lower-log.f6479.9

                          \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                      5. Applied rewrites79.9%

                        \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                      6. Step-by-step derivation
                        1. Applied rewrites80.1%

                          \[\leadsto \frac{\log \left(\frac{1 + x}{x}\right)}{n} \]

                        if 5.00000000000000018e-11 < (/.f64 #s(literal 1 binary64) n)

                        1. Initial program 51.3%

                          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                        2. Add Preprocessing
                        3. Taylor expanded in x around 0

                          \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                        4. Step-by-step derivation
                          1. Applied rewrites46.0%

                            \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                          2. Taylor expanded in x around 0

                            \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                          3. Step-by-step derivation
                            1. +-commutativeN/A

                              \[\leadsto \color{blue}{\left(x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) + 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                            2. *-commutativeN/A

                              \[\leadsto \left(\color{blue}{\left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) \cdot x} + 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                            3. lower-fma.f64N/A

                              \[\leadsto \color{blue}{\mathsf{fma}\left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}, x, 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                          4. Applied rewrites81.4%

                            \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{0.5}{n} - 0.5}{n}, x, \frac{1}{n}\right), x, 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                        5. Recombined 3 regimes into one program.
                        6. Add Preprocessing

                        Alternative 7: 82.9% accurate, 1.2× speedup?

                        \[\begin{array}{l} \\ \begin{array}{l} t_0 := {x}^{\left(\frac{1}{n}\right)}\\ \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-22}:\\ \;\;\;\;\frac{\frac{t\_0}{x}}{n}\\ \mathbf{elif}\;\frac{1}{n} \leq 5 \cdot 10^{-11}:\\ \;\;\;\;\frac{\log \left(\frac{1 + x}{x}\right)}{n}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\frac{\mathsf{fma}\left(\frac{0.5}{n} - 0.5, x, 1\right)}{n}, x, 1\right) - t\_0\\ \end{array} \end{array} \]
                        (FPCore (x n)
                         :precision binary64
                         (let* ((t_0 (pow x (/ 1.0 n))))
                           (if (<= (/ 1.0 n) -4e-22)
                             (/ (/ t_0 x) n)
                             (if (<= (/ 1.0 n) 5e-11)
                               (/ (log (/ (+ 1.0 x) x)) n)
                               (- (fma (/ (fma (- (/ 0.5 n) 0.5) x 1.0) n) x 1.0) t_0)))))
                        double code(double x, double n) {
                        	double t_0 = pow(x, (1.0 / n));
                        	double tmp;
                        	if ((1.0 / n) <= -4e-22) {
                        		tmp = (t_0 / x) / n;
                        	} else if ((1.0 / n) <= 5e-11) {
                        		tmp = log(((1.0 + x) / x)) / n;
                        	} else {
                        		tmp = fma((fma(((0.5 / n) - 0.5), x, 1.0) / n), x, 1.0) - t_0;
                        	}
                        	return tmp;
                        }
                        
                        function code(x, n)
                        	t_0 = x ^ Float64(1.0 / n)
                        	tmp = 0.0
                        	if (Float64(1.0 / n) <= -4e-22)
                        		tmp = Float64(Float64(t_0 / x) / n);
                        	elseif (Float64(1.0 / n) <= 5e-11)
                        		tmp = Float64(log(Float64(Float64(1.0 + x) / x)) / n);
                        	else
                        		tmp = Float64(fma(Float64(fma(Float64(Float64(0.5 / n) - 0.5), x, 1.0) / n), x, 1.0) - t_0);
                        	end
                        	return tmp
                        end
                        
                        code[x_, n_] := Block[{t$95$0 = N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[N[(1.0 / n), $MachinePrecision], -4e-22], N[(N[(t$95$0 / x), $MachinePrecision] / n), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 5e-11], N[(N[Log[N[(N[(1.0 + x), $MachinePrecision] / x), $MachinePrecision]], $MachinePrecision] / n), $MachinePrecision], N[(N[(N[(N[(N[(N[(0.5 / n), $MachinePrecision] - 0.5), $MachinePrecision] * x + 1.0), $MachinePrecision] / n), $MachinePrecision] * x + 1.0), $MachinePrecision] - t$95$0), $MachinePrecision]]]]
                        
                        \begin{array}{l}
                        
                        \\
                        \begin{array}{l}
                        t_0 := {x}^{\left(\frac{1}{n}\right)}\\
                        \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-22}:\\
                        \;\;\;\;\frac{\frac{t\_0}{x}}{n}\\
                        
                        \mathbf{elif}\;\frac{1}{n} \leq 5 \cdot 10^{-11}:\\
                        \;\;\;\;\frac{\log \left(\frac{1 + x}{x}\right)}{n}\\
                        
                        \mathbf{else}:\\
                        \;\;\;\;\mathsf{fma}\left(\frac{\mathsf{fma}\left(\frac{0.5}{n} - 0.5, x, 1\right)}{n}, x, 1\right) - t\_0\\
                        
                        
                        \end{array}
                        \end{array}
                        
                        Derivation
                        1. Split input into 3 regimes
                        2. if (/.f64 #s(literal 1 binary64) n) < -4.0000000000000002e-22

                          1. Initial program 93.7%

                            \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                          2. Add Preprocessing
                          3. Taylor expanded in x around inf

                            \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                          4. Step-by-step derivation
                            1. associate-/l/N/A

                              \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                            2. lower-/.f64N/A

                              \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                            3. lower-/.f64N/A

                              \[\leadsto \frac{\color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}}{n} \]
                            4. log-recN/A

                              \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{x}}{n} \]
                            5. mul-1-negN/A

                              \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{x}}{n} \]
                            6. associate-*r/N/A

                              \[\leadsto \frac{\frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{x}}{n} \]
                            7. associate-*r*N/A

                              \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{x}}{n} \]
                            8. metadata-evalN/A

                              \[\leadsto \frac{\frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{x}}{n} \]
                            9. *-commutativeN/A

                              \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{x}}{n} \]
                            10. associate-/l*N/A

                              \[\leadsto \frac{\frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{x}}{n} \]
                            11. exp-to-powN/A

                              \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                            12. lower-pow.f64N/A

                              \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                            13. lower-/.f6496.0

                              \[\leadsto \frac{\frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                          5. Applied rewrites96.0%

                            \[\leadsto \color{blue}{\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}} \]

                          if -4.0000000000000002e-22 < (/.f64 #s(literal 1 binary64) n) < 5.00000000000000018e-11

                          1. Initial program 25.7%

                            \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                          2. Add Preprocessing
                          3. Taylor expanded in n around inf

                            \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                          4. Step-by-step derivation
                            1. lower-/.f64N/A

                              \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                            2. lower--.f64N/A

                              \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                            3. lower-log1p.f64N/A

                              \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                            4. lower-log.f6479.9

                              \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                          5. Applied rewrites79.9%

                            \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                          6. Step-by-step derivation
                            1. Applied rewrites80.1%

                              \[\leadsto \frac{\log \left(\frac{1 + x}{x}\right)}{n} \]

                            if 5.00000000000000018e-11 < (/.f64 #s(literal 1 binary64) n)

                            1. Initial program 51.3%

                              \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                            2. Add Preprocessing
                            3. Taylor expanded in x around 0

                              \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                            4. Step-by-step derivation
                              1. Applied rewrites46.0%

                                \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                              2. Taylor expanded in x around 0

                                \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                              3. Step-by-step derivation
                                1. +-commutativeN/A

                                  \[\leadsto \color{blue}{\left(x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) + 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                2. *-commutativeN/A

                                  \[\leadsto \left(\color{blue}{\left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) \cdot x} + 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                3. lower-fma.f64N/A

                                  \[\leadsto \color{blue}{\mathsf{fma}\left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}, x, 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                              4. Applied rewrites81.4%

                                \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{0.5}{n} - 0.5}{n}, x, \frac{1}{n}\right), x, 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                              5. Taylor expanded in n around inf

                                \[\leadsto \mathsf{fma}\left(\frac{1 + \left(\frac{-1}{2} \cdot x + \frac{1}{2} \cdot \frac{x}{n}\right)}{n}, x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                              6. Step-by-step derivation
                                1. Applied rewrites81.3%

                                  \[\leadsto \mathsf{fma}\left(\frac{\mathsf{fma}\left(\frac{0.5}{n} - 0.5, x, 1\right)}{n}, x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                              7. Recombined 3 regimes into one program.
                              8. Add Preprocessing

                              Alternative 8: 82.6% accurate, 1.2× speedup?

                              \[\begin{array}{l} \\ \begin{array}{l} t_0 := {x}^{\left(\frac{1}{n}\right)}\\ \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-22}:\\ \;\;\;\;\frac{\frac{t\_0}{x}}{n}\\ \mathbf{elif}\;\frac{1}{n} \leq 5 \cdot 10^{-11}:\\ \;\;\;\;\frac{\log \left(\frac{1 + x}{x}\right)}{n}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\frac{\mathsf{fma}\left(-0.5, n, 0.5\right) \cdot x + n}{n \cdot n}, x, 1\right) - t\_0\\ \end{array} \end{array} \]
                              (FPCore (x n)
                               :precision binary64
                               (let* ((t_0 (pow x (/ 1.0 n))))
                                 (if (<= (/ 1.0 n) -4e-22)
                                   (/ (/ t_0 x) n)
                                   (if (<= (/ 1.0 n) 5e-11)
                                     (/ (log (/ (+ 1.0 x) x)) n)
                                     (- (fma (/ (+ (* (fma -0.5 n 0.5) x) n) (* n n)) x 1.0) t_0)))))
                              double code(double x, double n) {
                              	double t_0 = pow(x, (1.0 / n));
                              	double tmp;
                              	if ((1.0 / n) <= -4e-22) {
                              		tmp = (t_0 / x) / n;
                              	} else if ((1.0 / n) <= 5e-11) {
                              		tmp = log(((1.0 + x) / x)) / n;
                              	} else {
                              		tmp = fma((((fma(-0.5, n, 0.5) * x) + n) / (n * n)), x, 1.0) - t_0;
                              	}
                              	return tmp;
                              }
                              
                              function code(x, n)
                              	t_0 = x ^ Float64(1.0 / n)
                              	tmp = 0.0
                              	if (Float64(1.0 / n) <= -4e-22)
                              		tmp = Float64(Float64(t_0 / x) / n);
                              	elseif (Float64(1.0 / n) <= 5e-11)
                              		tmp = Float64(log(Float64(Float64(1.0 + x) / x)) / n);
                              	else
                              		tmp = Float64(fma(Float64(Float64(Float64(fma(-0.5, n, 0.5) * x) + n) / Float64(n * n)), x, 1.0) - t_0);
                              	end
                              	return tmp
                              end
                              
                              code[x_, n_] := Block[{t$95$0 = N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[N[(1.0 / n), $MachinePrecision], -4e-22], N[(N[(t$95$0 / x), $MachinePrecision] / n), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 5e-11], N[(N[Log[N[(N[(1.0 + x), $MachinePrecision] / x), $MachinePrecision]], $MachinePrecision] / n), $MachinePrecision], N[(N[(N[(N[(N[(N[(-0.5 * n + 0.5), $MachinePrecision] * x), $MachinePrecision] + n), $MachinePrecision] / N[(n * n), $MachinePrecision]), $MachinePrecision] * x + 1.0), $MachinePrecision] - t$95$0), $MachinePrecision]]]]
                              
                              \begin{array}{l}
                              
                              \\
                              \begin{array}{l}
                              t_0 := {x}^{\left(\frac{1}{n}\right)}\\
                              \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-22}:\\
                              \;\;\;\;\frac{\frac{t\_0}{x}}{n}\\
                              
                              \mathbf{elif}\;\frac{1}{n} \leq 5 \cdot 10^{-11}:\\
                              \;\;\;\;\frac{\log \left(\frac{1 + x}{x}\right)}{n}\\
                              
                              \mathbf{else}:\\
                              \;\;\;\;\mathsf{fma}\left(\frac{\mathsf{fma}\left(-0.5, n, 0.5\right) \cdot x + n}{n \cdot n}, x, 1\right) - t\_0\\
                              
                              
                              \end{array}
                              \end{array}
                              
                              Derivation
                              1. Split input into 3 regimes
                              2. if (/.f64 #s(literal 1 binary64) n) < -4.0000000000000002e-22

                                1. Initial program 93.7%

                                  \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                2. Add Preprocessing
                                3. Taylor expanded in x around inf

                                  \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                                4. Step-by-step derivation
                                  1. associate-/l/N/A

                                    \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                                  2. lower-/.f64N/A

                                    \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                                  3. lower-/.f64N/A

                                    \[\leadsto \frac{\color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}}{n} \]
                                  4. log-recN/A

                                    \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{x}}{n} \]
                                  5. mul-1-negN/A

                                    \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{x}}{n} \]
                                  6. associate-*r/N/A

                                    \[\leadsto \frac{\frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{x}}{n} \]
                                  7. associate-*r*N/A

                                    \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{x}}{n} \]
                                  8. metadata-evalN/A

                                    \[\leadsto \frac{\frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{x}}{n} \]
                                  9. *-commutativeN/A

                                    \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{x}}{n} \]
                                  10. associate-/l*N/A

                                    \[\leadsto \frac{\frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{x}}{n} \]
                                  11. exp-to-powN/A

                                    \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                                  12. lower-pow.f64N/A

                                    \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                                  13. lower-/.f6496.0

                                    \[\leadsto \frac{\frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                                5. Applied rewrites96.0%

                                  \[\leadsto \color{blue}{\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}} \]

                                if -4.0000000000000002e-22 < (/.f64 #s(literal 1 binary64) n) < 5.00000000000000018e-11

                                1. Initial program 25.7%

                                  \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                2. Add Preprocessing
                                3. Taylor expanded in n around inf

                                  \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                4. Step-by-step derivation
                                  1. lower-/.f64N/A

                                    \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                  2. lower--.f64N/A

                                    \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                                  3. lower-log1p.f64N/A

                                    \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                                  4. lower-log.f6479.9

                                    \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                                5. Applied rewrites79.9%

                                  \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                                6. Step-by-step derivation
                                  1. Applied rewrites80.1%

                                    \[\leadsto \frac{\log \left(\frac{1 + x}{x}\right)}{n} \]

                                  if 5.00000000000000018e-11 < (/.f64 #s(literal 1 binary64) n)

                                  1. Initial program 51.3%

                                    \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in x around 0

                                    \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                  4. Step-by-step derivation
                                    1. Applied rewrites46.0%

                                      \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                    2. Taylor expanded in x around 0

                                      \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                    3. Step-by-step derivation
                                      1. +-commutativeN/A

                                        \[\leadsto \color{blue}{\left(x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) + 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                      2. *-commutativeN/A

                                        \[\leadsto \left(\color{blue}{\left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) \cdot x} + 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                      3. lower-fma.f64N/A

                                        \[\leadsto \color{blue}{\mathsf{fma}\left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}, x, 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                    4. Applied rewrites81.4%

                                      \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{0.5}{n} - 0.5}{n}, x, \frac{1}{n}\right), x, 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                    5. Taylor expanded in n around 0

                                      \[\leadsto \mathsf{fma}\left(\frac{\frac{1}{2} \cdot x + n \cdot \left(1 + \frac{-1}{2} \cdot x\right)}{{n}^{2}}, x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                    6. Step-by-step derivation
                                      1. Applied rewrites78.7%

                                        \[\leadsto \mathsf{fma}\left(\frac{n + x \cdot \mathsf{fma}\left(-0.5, n, 0.5\right)}{n \cdot n}, x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
                                    7. Recombined 3 regimes into one program.
                                    8. Final simplification84.2%

                                      \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-22}:\\ \;\;\;\;\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}\\ \mathbf{elif}\;\frac{1}{n} \leq 5 \cdot 10^{-11}:\\ \;\;\;\;\frac{\log \left(\frac{1 + x}{x}\right)}{n}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\frac{\mathsf{fma}\left(-0.5, n, 0.5\right) \cdot x + n}{n \cdot n}, x, 1\right) - {x}^{\left(\frac{1}{n}\right)}\\ \end{array} \]
                                    9. Add Preprocessing

                                    Alternative 9: 82.6% accurate, 1.3× speedup?

                                    \[\begin{array}{l} \\ \begin{array}{l} t_0 := {x}^{\left(\frac{1}{n}\right)}\\ \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-22}:\\ \;\;\;\;\frac{\frac{t\_0}{x}}{n}\\ \mathbf{elif}\;\frac{1}{n} \leq 2 \cdot 10^{-14}:\\ \;\;\;\;\frac{\log \left(\frac{1 + x}{x}\right)}{n}\\ \mathbf{elif}\;\frac{1}{n} \leq 10^{+181}:\\ \;\;\;\;\frac{x}{n} - \left(t\_0 - 1\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{n}{x}}{n \cdot n}\\ \end{array} \end{array} \]
                                    (FPCore (x n)
                                     :precision binary64
                                     (let* ((t_0 (pow x (/ 1.0 n))))
                                       (if (<= (/ 1.0 n) -4e-22)
                                         (/ (/ t_0 x) n)
                                         (if (<= (/ 1.0 n) 2e-14)
                                           (/ (log (/ (+ 1.0 x) x)) n)
                                           (if (<= (/ 1.0 n) 1e+181)
                                             (- (/ x n) (- t_0 1.0))
                                             (/ (/ n x) (* n n)))))))
                                    double code(double x, double n) {
                                    	double t_0 = pow(x, (1.0 / n));
                                    	double tmp;
                                    	if ((1.0 / n) <= -4e-22) {
                                    		tmp = (t_0 / x) / n;
                                    	} else if ((1.0 / n) <= 2e-14) {
                                    		tmp = log(((1.0 + x) / x)) / n;
                                    	} else if ((1.0 / n) <= 1e+181) {
                                    		tmp = (x / n) - (t_0 - 1.0);
                                    	} else {
                                    		tmp = (n / x) / (n * n);
                                    	}
                                    	return tmp;
                                    }
                                    
                                    real(8) function code(x, n)
                                        real(8), intent (in) :: x
                                        real(8), intent (in) :: n
                                        real(8) :: t_0
                                        real(8) :: tmp
                                        t_0 = x ** (1.0d0 / n)
                                        if ((1.0d0 / n) <= (-4d-22)) then
                                            tmp = (t_0 / x) / n
                                        else if ((1.0d0 / n) <= 2d-14) then
                                            tmp = log(((1.0d0 + x) / x)) / n
                                        else if ((1.0d0 / n) <= 1d+181) then
                                            tmp = (x / n) - (t_0 - 1.0d0)
                                        else
                                            tmp = (n / x) / (n * n)
                                        end if
                                        code = tmp
                                    end function
                                    
                                    public static double code(double x, double n) {
                                    	double t_0 = Math.pow(x, (1.0 / n));
                                    	double tmp;
                                    	if ((1.0 / n) <= -4e-22) {
                                    		tmp = (t_0 / x) / n;
                                    	} else if ((1.0 / n) <= 2e-14) {
                                    		tmp = Math.log(((1.0 + x) / x)) / n;
                                    	} else if ((1.0 / n) <= 1e+181) {
                                    		tmp = (x / n) - (t_0 - 1.0);
                                    	} else {
                                    		tmp = (n / x) / (n * n);
                                    	}
                                    	return tmp;
                                    }
                                    
                                    def code(x, n):
                                    	t_0 = math.pow(x, (1.0 / n))
                                    	tmp = 0
                                    	if (1.0 / n) <= -4e-22:
                                    		tmp = (t_0 / x) / n
                                    	elif (1.0 / n) <= 2e-14:
                                    		tmp = math.log(((1.0 + x) / x)) / n
                                    	elif (1.0 / n) <= 1e+181:
                                    		tmp = (x / n) - (t_0 - 1.0)
                                    	else:
                                    		tmp = (n / x) / (n * n)
                                    	return tmp
                                    
                                    function code(x, n)
                                    	t_0 = x ^ Float64(1.0 / n)
                                    	tmp = 0.0
                                    	if (Float64(1.0 / n) <= -4e-22)
                                    		tmp = Float64(Float64(t_0 / x) / n);
                                    	elseif (Float64(1.0 / n) <= 2e-14)
                                    		tmp = Float64(log(Float64(Float64(1.0 + x) / x)) / n);
                                    	elseif (Float64(1.0 / n) <= 1e+181)
                                    		tmp = Float64(Float64(x / n) - Float64(t_0 - 1.0));
                                    	else
                                    		tmp = Float64(Float64(n / x) / Float64(n * n));
                                    	end
                                    	return tmp
                                    end
                                    
                                    function tmp_2 = code(x, n)
                                    	t_0 = x ^ (1.0 / n);
                                    	tmp = 0.0;
                                    	if ((1.0 / n) <= -4e-22)
                                    		tmp = (t_0 / x) / n;
                                    	elseif ((1.0 / n) <= 2e-14)
                                    		tmp = log(((1.0 + x) / x)) / n;
                                    	elseif ((1.0 / n) <= 1e+181)
                                    		tmp = (x / n) - (t_0 - 1.0);
                                    	else
                                    		tmp = (n / x) / (n * n);
                                    	end
                                    	tmp_2 = tmp;
                                    end
                                    
                                    code[x_, n_] := Block[{t$95$0 = N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[N[(1.0 / n), $MachinePrecision], -4e-22], N[(N[(t$95$0 / x), $MachinePrecision] / n), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 2e-14], N[(N[Log[N[(N[(1.0 + x), $MachinePrecision] / x), $MachinePrecision]], $MachinePrecision] / n), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 1e+181], N[(N[(x / n), $MachinePrecision] - N[(t$95$0 - 1.0), $MachinePrecision]), $MachinePrecision], N[(N[(n / x), $MachinePrecision] / N[(n * n), $MachinePrecision]), $MachinePrecision]]]]]
                                    
                                    \begin{array}{l}
                                    
                                    \\
                                    \begin{array}{l}
                                    t_0 := {x}^{\left(\frac{1}{n}\right)}\\
                                    \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-22}:\\
                                    \;\;\;\;\frac{\frac{t\_0}{x}}{n}\\
                                    
                                    \mathbf{elif}\;\frac{1}{n} \leq 2 \cdot 10^{-14}:\\
                                    \;\;\;\;\frac{\log \left(\frac{1 + x}{x}\right)}{n}\\
                                    
                                    \mathbf{elif}\;\frac{1}{n} \leq 10^{+181}:\\
                                    \;\;\;\;\frac{x}{n} - \left(t\_0 - 1\right)\\
                                    
                                    \mathbf{else}:\\
                                    \;\;\;\;\frac{\frac{n}{x}}{n \cdot n}\\
                                    
                                    
                                    \end{array}
                                    \end{array}
                                    
                                    Derivation
                                    1. Split input into 4 regimes
                                    2. if (/.f64 #s(literal 1 binary64) n) < -4.0000000000000002e-22

                                      1. Initial program 93.7%

                                        \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                      2. Add Preprocessing
                                      3. Taylor expanded in x around inf

                                        \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                                      4. Step-by-step derivation
                                        1. associate-/l/N/A

                                          \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                                        2. lower-/.f64N/A

                                          \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                                        3. lower-/.f64N/A

                                          \[\leadsto \frac{\color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}}{n} \]
                                        4. log-recN/A

                                          \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{x}}{n} \]
                                        5. mul-1-negN/A

                                          \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{x}}{n} \]
                                        6. associate-*r/N/A

                                          \[\leadsto \frac{\frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{x}}{n} \]
                                        7. associate-*r*N/A

                                          \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{x}}{n} \]
                                        8. metadata-evalN/A

                                          \[\leadsto \frac{\frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{x}}{n} \]
                                        9. *-commutativeN/A

                                          \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{x}}{n} \]
                                        10. associate-/l*N/A

                                          \[\leadsto \frac{\frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{x}}{n} \]
                                        11. exp-to-powN/A

                                          \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                                        12. lower-pow.f64N/A

                                          \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                                        13. lower-/.f6496.0

                                          \[\leadsto \frac{\frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                                      5. Applied rewrites96.0%

                                        \[\leadsto \color{blue}{\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}} \]

                                      if -4.0000000000000002e-22 < (/.f64 #s(literal 1 binary64) n) < 2e-14

                                      1. Initial program 25.8%

                                        \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                      2. Add Preprocessing
                                      3. Taylor expanded in n around inf

                                        \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                      4. Step-by-step derivation
                                        1. lower-/.f64N/A

                                          \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                        2. lower--.f64N/A

                                          \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                                        3. lower-log1p.f64N/A

                                          \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                                        4. lower-log.f6480.5

                                          \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                                      5. Applied rewrites80.5%

                                        \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                                      6. Step-by-step derivation
                                        1. Applied rewrites80.6%

                                          \[\leadsto \frac{\log \left(\frac{1 + x}{x}\right)}{n} \]

                                        if 2e-14 < (/.f64 #s(literal 1 binary64) n) < 9.9999999999999992e180

                                        1. Initial program 75.4%

                                          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                        2. Add Preprocessing
                                        3. Taylor expanded in x around 0

                                          \[\leadsto \color{blue}{\left(1 + \frac{x}{n}\right) - e^{\frac{\log x}{n}}} \]
                                        4. Step-by-step derivation
                                          1. associate--l+N/A

                                            \[\leadsto \color{blue}{1 + \left(\frac{x}{n} - e^{\frac{\log x}{n}}\right)} \]
                                          2. +-commutativeN/A

                                            \[\leadsto \color{blue}{\left(\frac{x}{n} - e^{\frac{\log x}{n}}\right) + 1} \]
                                          3. *-rgt-identityN/A

                                            \[\leadsto \left(\frac{\color{blue}{x \cdot 1}}{n} - e^{\frac{\log x}{n}}\right) + 1 \]
                                          4. associate-*r/N/A

                                            \[\leadsto \left(\color{blue}{x \cdot \frac{1}{n}} - e^{\frac{\log x}{n}}\right) + 1 \]
                                          5. remove-double-negN/A

                                            \[\leadsto \left(x \cdot \frac{1}{n} - e^{\frac{\color{blue}{\mathsf{neg}\left(\left(\mathsf{neg}\left(\log x\right)\right)\right)}}{n}}\right) + 1 \]
                                          6. mul-1-negN/A

                                            \[\leadsto \left(x \cdot \frac{1}{n} - e^{\frac{\mathsf{neg}\left(\color{blue}{-1 \cdot \log x}\right)}{n}}\right) + 1 \]
                                          7. distribute-neg-fracN/A

                                            \[\leadsto \left(x \cdot \frac{1}{n} - e^{\color{blue}{\mathsf{neg}\left(\frac{-1 \cdot \log x}{n}\right)}}\right) + 1 \]
                                          8. mul-1-negN/A

                                            \[\leadsto \left(x \cdot \frac{1}{n} - e^{\mathsf{neg}\left(\frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}\right)}\right) + 1 \]
                                          9. log-recN/A

                                            \[\leadsto \left(x \cdot \frac{1}{n} - e^{\mathsf{neg}\left(\frac{\color{blue}{\log \left(\frac{1}{x}\right)}}{n}\right)}\right) + 1 \]
                                          10. mul-1-negN/A

                                            \[\leadsto \left(x \cdot \frac{1}{n} - e^{\color{blue}{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}\right) + 1 \]
                                          11. associate-+l-N/A

                                            \[\leadsto \color{blue}{x \cdot \frac{1}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right)} \]
                                          12. lower--.f64N/A

                                            \[\leadsto \color{blue}{x \cdot \frac{1}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right)} \]
                                          13. associate-*r/N/A

                                            \[\leadsto \color{blue}{\frac{x \cdot 1}{n}} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
                                          14. *-rgt-identityN/A

                                            \[\leadsto \frac{\color{blue}{x}}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
                                          15. lower-/.f64N/A

                                            \[\leadsto \color{blue}{\frac{x}{n}} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
                                          16. lower-expm1.f64N/A

                                            \[\leadsto \frac{x}{n} - \color{blue}{\mathsf{expm1}\left(-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}\right)} \]
                                          17. mul-1-negN/A

                                            \[\leadsto \frac{x}{n} - \mathsf{expm1}\left(\color{blue}{\mathsf{neg}\left(\frac{\log \left(\frac{1}{x}\right)}{n}\right)}\right) \]
                                        5. Applied rewrites73.8%

                                          \[\leadsto \color{blue}{\frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)} \]
                                        6. Step-by-step derivation
                                          1. Applied rewrites73.8%

                                            \[\leadsto \frac{x}{n} - \left({x}^{\left({n}^{-1}\right)} - \color{blue}{1}\right) \]
                                          2. Step-by-step derivation
                                            1. Applied rewrites73.8%

                                              \[\leadsto \frac{x}{n} - \left({x}^{\left(\frac{1}{n}\right)} - 1\right) \]

                                            if 9.9999999999999992e180 < (/.f64 #s(literal 1 binary64) n)

                                            1. Initial program 20.2%

                                              \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                            2. Add Preprocessing
                                            3. Taylor expanded in n around inf

                                              \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                            4. Step-by-step derivation
                                              1. lower-/.f64N/A

                                                \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                              2. lower--.f64N/A

                                                \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                                              3. lower-log1p.f64N/A

                                                \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                                              4. lower-log.f6412.2

                                                \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                                            5. Applied rewrites12.2%

                                              \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                                            6. Step-by-step derivation
                                              1. Applied rewrites88.6%

                                                \[\leadsto \frac{\mathsf{log1p}\left(x\right) \cdot n - n \cdot \log x}{\color{blue}{n \cdot n}} \]
                                              2. Taylor expanded in x around inf

                                                \[\leadsto \frac{\frac{n}{x}}{\color{blue}{n} \cdot n} \]
                                              3. Step-by-step derivation
                                                1. Applied rewrites88.6%

                                                  \[\leadsto \frac{\frac{n}{x}}{\color{blue}{n} \cdot n} \]
                                              4. Recombined 4 regimes into one program.
                                              5. Add Preprocessing

                                              Alternative 10: 82.6% accurate, 1.3× speedup?

                                              \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-22}:\\ \;\;\;\;\frac{{x}^{\left(\frac{1}{n} - 1\right)}}{n}\\ \mathbf{elif}\;\frac{1}{n} \leq 2 \cdot 10^{-14}:\\ \;\;\;\;\frac{\log \left(\frac{1 + x}{x}\right)}{n}\\ \mathbf{elif}\;\frac{1}{n} \leq 10^{+181}:\\ \;\;\;\;\frac{x}{n} - \left({x}^{\left(\frac{1}{n}\right)} - 1\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{n}{x}}{n \cdot n}\\ \end{array} \end{array} \]
                                              (FPCore (x n)
                                               :precision binary64
                                               (if (<= (/ 1.0 n) -4e-22)
                                                 (/ (pow x (- (/ 1.0 n) 1.0)) n)
                                                 (if (<= (/ 1.0 n) 2e-14)
                                                   (/ (log (/ (+ 1.0 x) x)) n)
                                                   (if (<= (/ 1.0 n) 1e+181)
                                                     (- (/ x n) (- (pow x (/ 1.0 n)) 1.0))
                                                     (/ (/ n x) (* n n))))))
                                              double code(double x, double n) {
                                              	double tmp;
                                              	if ((1.0 / n) <= -4e-22) {
                                              		tmp = pow(x, ((1.0 / n) - 1.0)) / n;
                                              	} else if ((1.0 / n) <= 2e-14) {
                                              		tmp = log(((1.0 + x) / x)) / n;
                                              	} else if ((1.0 / n) <= 1e+181) {
                                              		tmp = (x / n) - (pow(x, (1.0 / n)) - 1.0);
                                              	} else {
                                              		tmp = (n / x) / (n * n);
                                              	}
                                              	return tmp;
                                              }
                                              
                                              real(8) function code(x, n)
                                                  real(8), intent (in) :: x
                                                  real(8), intent (in) :: n
                                                  real(8) :: tmp
                                                  if ((1.0d0 / n) <= (-4d-22)) then
                                                      tmp = (x ** ((1.0d0 / n) - 1.0d0)) / n
                                                  else if ((1.0d0 / n) <= 2d-14) then
                                                      tmp = log(((1.0d0 + x) / x)) / n
                                                  else if ((1.0d0 / n) <= 1d+181) then
                                                      tmp = (x / n) - ((x ** (1.0d0 / n)) - 1.0d0)
                                                  else
                                                      tmp = (n / x) / (n * n)
                                                  end if
                                                  code = tmp
                                              end function
                                              
                                              public static double code(double x, double n) {
                                              	double tmp;
                                              	if ((1.0 / n) <= -4e-22) {
                                              		tmp = Math.pow(x, ((1.0 / n) - 1.0)) / n;
                                              	} else if ((1.0 / n) <= 2e-14) {
                                              		tmp = Math.log(((1.0 + x) / x)) / n;
                                              	} else if ((1.0 / n) <= 1e+181) {
                                              		tmp = (x / n) - (Math.pow(x, (1.0 / n)) - 1.0);
                                              	} else {
                                              		tmp = (n / x) / (n * n);
                                              	}
                                              	return tmp;
                                              }
                                              
                                              def code(x, n):
                                              	tmp = 0
                                              	if (1.0 / n) <= -4e-22:
                                              		tmp = math.pow(x, ((1.0 / n) - 1.0)) / n
                                              	elif (1.0 / n) <= 2e-14:
                                              		tmp = math.log(((1.0 + x) / x)) / n
                                              	elif (1.0 / n) <= 1e+181:
                                              		tmp = (x / n) - (math.pow(x, (1.0 / n)) - 1.0)
                                              	else:
                                              		tmp = (n / x) / (n * n)
                                              	return tmp
                                              
                                              function code(x, n)
                                              	tmp = 0.0
                                              	if (Float64(1.0 / n) <= -4e-22)
                                              		tmp = Float64((x ^ Float64(Float64(1.0 / n) - 1.0)) / n);
                                              	elseif (Float64(1.0 / n) <= 2e-14)
                                              		tmp = Float64(log(Float64(Float64(1.0 + x) / x)) / n);
                                              	elseif (Float64(1.0 / n) <= 1e+181)
                                              		tmp = Float64(Float64(x / n) - Float64((x ^ Float64(1.0 / n)) - 1.0));
                                              	else
                                              		tmp = Float64(Float64(n / x) / Float64(n * n));
                                              	end
                                              	return tmp
                                              end
                                              
                                              function tmp_2 = code(x, n)
                                              	tmp = 0.0;
                                              	if ((1.0 / n) <= -4e-22)
                                              		tmp = (x ^ ((1.0 / n) - 1.0)) / n;
                                              	elseif ((1.0 / n) <= 2e-14)
                                              		tmp = log(((1.0 + x) / x)) / n;
                                              	elseif ((1.0 / n) <= 1e+181)
                                              		tmp = (x / n) - ((x ^ (1.0 / n)) - 1.0);
                                              	else
                                              		tmp = (n / x) / (n * n);
                                              	end
                                              	tmp_2 = tmp;
                                              end
                                              
                                              code[x_, n_] := If[LessEqual[N[(1.0 / n), $MachinePrecision], -4e-22], N[(N[Power[x, N[(N[(1.0 / n), $MachinePrecision] - 1.0), $MachinePrecision]], $MachinePrecision] / n), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 2e-14], N[(N[Log[N[(N[(1.0 + x), $MachinePrecision] / x), $MachinePrecision]], $MachinePrecision] / n), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 1e+181], N[(N[(x / n), $MachinePrecision] - N[(N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision] - 1.0), $MachinePrecision]), $MachinePrecision], N[(N[(n / x), $MachinePrecision] / N[(n * n), $MachinePrecision]), $MachinePrecision]]]]
                                              
                                              \begin{array}{l}
                                              
                                              \\
                                              \begin{array}{l}
                                              \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-22}:\\
                                              \;\;\;\;\frac{{x}^{\left(\frac{1}{n} - 1\right)}}{n}\\
                                              
                                              \mathbf{elif}\;\frac{1}{n} \leq 2 \cdot 10^{-14}:\\
                                              \;\;\;\;\frac{\log \left(\frac{1 + x}{x}\right)}{n}\\
                                              
                                              \mathbf{elif}\;\frac{1}{n} \leq 10^{+181}:\\
                                              \;\;\;\;\frac{x}{n} - \left({x}^{\left(\frac{1}{n}\right)} - 1\right)\\
                                              
                                              \mathbf{else}:\\
                                              \;\;\;\;\frac{\frac{n}{x}}{n \cdot n}\\
                                              
                                              
                                              \end{array}
                                              \end{array}
                                              
                                              Derivation
                                              1. Split input into 4 regimes
                                              2. if (/.f64 #s(literal 1 binary64) n) < -4.0000000000000002e-22

                                                1. Initial program 93.7%

                                                  \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                2. Add Preprocessing
                                                3. Taylor expanded in n around inf

                                                  \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                4. Step-by-step derivation
                                                  1. lower-/.f64N/A

                                                    \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                  2. lower--.f64N/A

                                                    \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                                                  3. lower-log1p.f64N/A

                                                    \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                                                  4. lower-log.f6453.8

                                                    \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                                                5. Applied rewrites53.8%

                                                  \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                                                6. Step-by-step derivation
                                                  1. Applied rewrites53.8%

                                                    \[\leadsto \frac{1}{\color{blue}{\frac{n}{\mathsf{log1p}\left(x\right) - \log x}}} \]
                                                  2. Taylor expanded in x around inf

                                                    \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                                                  3. Step-by-step derivation
                                                    1. *-commutativeN/A

                                                      \[\leadsto \frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{\color{blue}{x \cdot n}} \]
                                                    2. associate-/r*N/A

                                                      \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                                                    3. lower-/.f64N/A

                                                      \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                                                  4. Applied rewrites95.7%

                                                    \[\leadsto \color{blue}{\frac{{x}^{\left(\frac{1}{n} - 1\right)}}{n}} \]

                                                  if -4.0000000000000002e-22 < (/.f64 #s(literal 1 binary64) n) < 2e-14

                                                  1. Initial program 25.8%

                                                    \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                  2. Add Preprocessing
                                                  3. Taylor expanded in n around inf

                                                    \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                  4. Step-by-step derivation
                                                    1. lower-/.f64N/A

                                                      \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                    2. lower--.f64N/A

                                                      \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                                                    3. lower-log1p.f64N/A

                                                      \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                                                    4. lower-log.f6480.5

                                                      \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                                                  5. Applied rewrites80.5%

                                                    \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                                                  6. Step-by-step derivation
                                                    1. Applied rewrites80.6%

                                                      \[\leadsto \frac{\log \left(\frac{1 + x}{x}\right)}{n} \]

                                                    if 2e-14 < (/.f64 #s(literal 1 binary64) n) < 9.9999999999999992e180

                                                    1. Initial program 75.4%

                                                      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                    2. Add Preprocessing
                                                    3. Taylor expanded in x around 0

                                                      \[\leadsto \color{blue}{\left(1 + \frac{x}{n}\right) - e^{\frac{\log x}{n}}} \]
                                                    4. Step-by-step derivation
                                                      1. associate--l+N/A

                                                        \[\leadsto \color{blue}{1 + \left(\frac{x}{n} - e^{\frac{\log x}{n}}\right)} \]
                                                      2. +-commutativeN/A

                                                        \[\leadsto \color{blue}{\left(\frac{x}{n} - e^{\frac{\log x}{n}}\right) + 1} \]
                                                      3. *-rgt-identityN/A

                                                        \[\leadsto \left(\frac{\color{blue}{x \cdot 1}}{n} - e^{\frac{\log x}{n}}\right) + 1 \]
                                                      4. associate-*r/N/A

                                                        \[\leadsto \left(\color{blue}{x \cdot \frac{1}{n}} - e^{\frac{\log x}{n}}\right) + 1 \]
                                                      5. remove-double-negN/A

                                                        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\frac{\color{blue}{\mathsf{neg}\left(\left(\mathsf{neg}\left(\log x\right)\right)\right)}}{n}}\right) + 1 \]
                                                      6. mul-1-negN/A

                                                        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\frac{\mathsf{neg}\left(\color{blue}{-1 \cdot \log x}\right)}{n}}\right) + 1 \]
                                                      7. distribute-neg-fracN/A

                                                        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\color{blue}{\mathsf{neg}\left(\frac{-1 \cdot \log x}{n}\right)}}\right) + 1 \]
                                                      8. mul-1-negN/A

                                                        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\mathsf{neg}\left(\frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}\right)}\right) + 1 \]
                                                      9. log-recN/A

                                                        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\mathsf{neg}\left(\frac{\color{blue}{\log \left(\frac{1}{x}\right)}}{n}\right)}\right) + 1 \]
                                                      10. mul-1-negN/A

                                                        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\color{blue}{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}\right) + 1 \]
                                                      11. associate-+l-N/A

                                                        \[\leadsto \color{blue}{x \cdot \frac{1}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right)} \]
                                                      12. lower--.f64N/A

                                                        \[\leadsto \color{blue}{x \cdot \frac{1}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right)} \]
                                                      13. associate-*r/N/A

                                                        \[\leadsto \color{blue}{\frac{x \cdot 1}{n}} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
                                                      14. *-rgt-identityN/A

                                                        \[\leadsto \frac{\color{blue}{x}}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
                                                      15. lower-/.f64N/A

                                                        \[\leadsto \color{blue}{\frac{x}{n}} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
                                                      16. lower-expm1.f64N/A

                                                        \[\leadsto \frac{x}{n} - \color{blue}{\mathsf{expm1}\left(-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}\right)} \]
                                                      17. mul-1-negN/A

                                                        \[\leadsto \frac{x}{n} - \mathsf{expm1}\left(\color{blue}{\mathsf{neg}\left(\frac{\log \left(\frac{1}{x}\right)}{n}\right)}\right) \]
                                                    5. Applied rewrites73.8%

                                                      \[\leadsto \color{blue}{\frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)} \]
                                                    6. Step-by-step derivation
                                                      1. Applied rewrites73.8%

                                                        \[\leadsto \frac{x}{n} - \left({x}^{\left({n}^{-1}\right)} - \color{blue}{1}\right) \]
                                                      2. Step-by-step derivation
                                                        1. Applied rewrites73.8%

                                                          \[\leadsto \frac{x}{n} - \left({x}^{\left(\frac{1}{n}\right)} - 1\right) \]

                                                        if 9.9999999999999992e180 < (/.f64 #s(literal 1 binary64) n)

                                                        1. Initial program 20.2%

                                                          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                        2. Add Preprocessing
                                                        3. Taylor expanded in n around inf

                                                          \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                        4. Step-by-step derivation
                                                          1. lower-/.f64N/A

                                                            \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                          2. lower--.f64N/A

                                                            \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                                                          3. lower-log1p.f64N/A

                                                            \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                                                          4. lower-log.f6412.2

                                                            \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                                                        5. Applied rewrites12.2%

                                                          \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                                                        6. Step-by-step derivation
                                                          1. Applied rewrites88.6%

                                                            \[\leadsto \frac{\mathsf{log1p}\left(x\right) \cdot n - n \cdot \log x}{\color{blue}{n \cdot n}} \]
                                                          2. Taylor expanded in x around inf

                                                            \[\leadsto \frac{\frac{n}{x}}{\color{blue}{n} \cdot n} \]
                                                          3. Step-by-step derivation
                                                            1. Applied rewrites88.6%

                                                              \[\leadsto \frac{\frac{n}{x}}{\color{blue}{n} \cdot n} \]
                                                          4. Recombined 4 regimes into one program.
                                                          5. Add Preprocessing

                                                          Alternative 11: 82.4% accurate, 1.4× speedup?

                                                          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-22}:\\ \;\;\;\;\frac{{x}^{\left(\frac{1}{n} - 1\right)}}{n}\\ \mathbf{elif}\;\frac{1}{n} \leq 5 \cdot 10^{-11}:\\ \;\;\;\;\frac{\log \left(\frac{1 + x}{x}\right)}{n}\\ \mathbf{elif}\;\frac{1}{n} \leq 4 \cdot 10^{+169}:\\ \;\;\;\;1 - {x}^{\left(\frac{1}{n}\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{n}{x}}{n \cdot n}\\ \end{array} \end{array} \]
                                                          (FPCore (x n)
                                                           :precision binary64
                                                           (if (<= (/ 1.0 n) -4e-22)
                                                             (/ (pow x (- (/ 1.0 n) 1.0)) n)
                                                             (if (<= (/ 1.0 n) 5e-11)
                                                               (/ (log (/ (+ 1.0 x) x)) n)
                                                               (if (<= (/ 1.0 n) 4e+169)
                                                                 (- 1.0 (pow x (/ 1.0 n)))
                                                                 (/ (/ n x) (* n n))))))
                                                          double code(double x, double n) {
                                                          	double tmp;
                                                          	if ((1.0 / n) <= -4e-22) {
                                                          		tmp = pow(x, ((1.0 / n) - 1.0)) / n;
                                                          	} else if ((1.0 / n) <= 5e-11) {
                                                          		tmp = log(((1.0 + x) / x)) / n;
                                                          	} else if ((1.0 / n) <= 4e+169) {
                                                          		tmp = 1.0 - pow(x, (1.0 / n));
                                                          	} else {
                                                          		tmp = (n / x) / (n * n);
                                                          	}
                                                          	return tmp;
                                                          }
                                                          
                                                          real(8) function code(x, n)
                                                              real(8), intent (in) :: x
                                                              real(8), intent (in) :: n
                                                              real(8) :: tmp
                                                              if ((1.0d0 / n) <= (-4d-22)) then
                                                                  tmp = (x ** ((1.0d0 / n) - 1.0d0)) / n
                                                              else if ((1.0d0 / n) <= 5d-11) then
                                                                  tmp = log(((1.0d0 + x) / x)) / n
                                                              else if ((1.0d0 / n) <= 4d+169) then
                                                                  tmp = 1.0d0 - (x ** (1.0d0 / n))
                                                              else
                                                                  tmp = (n / x) / (n * n)
                                                              end if
                                                              code = tmp
                                                          end function
                                                          
                                                          public static double code(double x, double n) {
                                                          	double tmp;
                                                          	if ((1.0 / n) <= -4e-22) {
                                                          		tmp = Math.pow(x, ((1.0 / n) - 1.0)) / n;
                                                          	} else if ((1.0 / n) <= 5e-11) {
                                                          		tmp = Math.log(((1.0 + x) / x)) / n;
                                                          	} else if ((1.0 / n) <= 4e+169) {
                                                          		tmp = 1.0 - Math.pow(x, (1.0 / n));
                                                          	} else {
                                                          		tmp = (n / x) / (n * n);
                                                          	}
                                                          	return tmp;
                                                          }
                                                          
                                                          def code(x, n):
                                                          	tmp = 0
                                                          	if (1.0 / n) <= -4e-22:
                                                          		tmp = math.pow(x, ((1.0 / n) - 1.0)) / n
                                                          	elif (1.0 / n) <= 5e-11:
                                                          		tmp = math.log(((1.0 + x) / x)) / n
                                                          	elif (1.0 / n) <= 4e+169:
                                                          		tmp = 1.0 - math.pow(x, (1.0 / n))
                                                          	else:
                                                          		tmp = (n / x) / (n * n)
                                                          	return tmp
                                                          
                                                          function code(x, n)
                                                          	tmp = 0.0
                                                          	if (Float64(1.0 / n) <= -4e-22)
                                                          		tmp = Float64((x ^ Float64(Float64(1.0 / n) - 1.0)) / n);
                                                          	elseif (Float64(1.0 / n) <= 5e-11)
                                                          		tmp = Float64(log(Float64(Float64(1.0 + x) / x)) / n);
                                                          	elseif (Float64(1.0 / n) <= 4e+169)
                                                          		tmp = Float64(1.0 - (x ^ Float64(1.0 / n)));
                                                          	else
                                                          		tmp = Float64(Float64(n / x) / Float64(n * n));
                                                          	end
                                                          	return tmp
                                                          end
                                                          
                                                          function tmp_2 = code(x, n)
                                                          	tmp = 0.0;
                                                          	if ((1.0 / n) <= -4e-22)
                                                          		tmp = (x ^ ((1.0 / n) - 1.0)) / n;
                                                          	elseif ((1.0 / n) <= 5e-11)
                                                          		tmp = log(((1.0 + x) / x)) / n;
                                                          	elseif ((1.0 / n) <= 4e+169)
                                                          		tmp = 1.0 - (x ^ (1.0 / n));
                                                          	else
                                                          		tmp = (n / x) / (n * n);
                                                          	end
                                                          	tmp_2 = tmp;
                                                          end
                                                          
                                                          code[x_, n_] := If[LessEqual[N[(1.0 / n), $MachinePrecision], -4e-22], N[(N[Power[x, N[(N[(1.0 / n), $MachinePrecision] - 1.0), $MachinePrecision]], $MachinePrecision] / n), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 5e-11], N[(N[Log[N[(N[(1.0 + x), $MachinePrecision] / x), $MachinePrecision]], $MachinePrecision] / n), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 4e+169], N[(1.0 - N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], N[(N[(n / x), $MachinePrecision] / N[(n * n), $MachinePrecision]), $MachinePrecision]]]]
                                                          
                                                          \begin{array}{l}
                                                          
                                                          \\
                                                          \begin{array}{l}
                                                          \mathbf{if}\;\frac{1}{n} \leq -4 \cdot 10^{-22}:\\
                                                          \;\;\;\;\frac{{x}^{\left(\frac{1}{n} - 1\right)}}{n}\\
                                                          
                                                          \mathbf{elif}\;\frac{1}{n} \leq 5 \cdot 10^{-11}:\\
                                                          \;\;\;\;\frac{\log \left(\frac{1 + x}{x}\right)}{n}\\
                                                          
                                                          \mathbf{elif}\;\frac{1}{n} \leq 4 \cdot 10^{+169}:\\
                                                          \;\;\;\;1 - {x}^{\left(\frac{1}{n}\right)}\\
                                                          
                                                          \mathbf{else}:\\
                                                          \;\;\;\;\frac{\frac{n}{x}}{n \cdot n}\\
                                                          
                                                          
                                                          \end{array}
                                                          \end{array}
                                                          
                                                          Derivation
                                                          1. Split input into 4 regimes
                                                          2. if (/.f64 #s(literal 1 binary64) n) < -4.0000000000000002e-22

                                                            1. Initial program 93.7%

                                                              \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                            2. Add Preprocessing
                                                            3. Taylor expanded in n around inf

                                                              \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                            4. Step-by-step derivation
                                                              1. lower-/.f64N/A

                                                                \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                              2. lower--.f64N/A

                                                                \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                                                              3. lower-log1p.f64N/A

                                                                \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                                                              4. lower-log.f6453.8

                                                                \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                                                            5. Applied rewrites53.8%

                                                              \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                                                            6. Step-by-step derivation
                                                              1. Applied rewrites53.8%

                                                                \[\leadsto \frac{1}{\color{blue}{\frac{n}{\mathsf{log1p}\left(x\right) - \log x}}} \]
                                                              2. Taylor expanded in x around inf

                                                                \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                                                              3. Step-by-step derivation
                                                                1. *-commutativeN/A

                                                                  \[\leadsto \frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{\color{blue}{x \cdot n}} \]
                                                                2. associate-/r*N/A

                                                                  \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                                                                3. lower-/.f64N/A

                                                                  \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                                                              4. Applied rewrites95.7%

                                                                \[\leadsto \color{blue}{\frac{{x}^{\left(\frac{1}{n} - 1\right)}}{n}} \]

                                                              if -4.0000000000000002e-22 < (/.f64 #s(literal 1 binary64) n) < 5.00000000000000018e-11

                                                              1. Initial program 25.7%

                                                                \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                              2. Add Preprocessing
                                                              3. Taylor expanded in n around inf

                                                                \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                              4. Step-by-step derivation
                                                                1. lower-/.f64N/A

                                                                  \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                                2. lower--.f64N/A

                                                                  \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                                                                3. lower-log1p.f64N/A

                                                                  \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                                                                4. lower-log.f6479.9

                                                                  \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                                                              5. Applied rewrites79.9%

                                                                \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                                                              6. Step-by-step derivation
                                                                1. Applied rewrites80.1%

                                                                  \[\leadsto \frac{\log \left(\frac{1 + x}{x}\right)}{n} \]

                                                                if 5.00000000000000018e-11 < (/.f64 #s(literal 1 binary64) n) < 3.99999999999999974e169

                                                                1. Initial program 86.5%

                                                                  \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                2. Add Preprocessing
                                                                3. Taylor expanded in x around 0

                                                                  \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                4. Step-by-step derivation
                                                                  1. Applied rewrites80.1%

                                                                    \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]

                                                                  if 3.99999999999999974e169 < (/.f64 #s(literal 1 binary64) n)

                                                                  1. Initial program 26.2%

                                                                    \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                  2. Add Preprocessing
                                                                  3. Taylor expanded in n around inf

                                                                    \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                                  4. Step-by-step derivation
                                                                    1. lower-/.f64N/A

                                                                      \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                                    2. lower--.f64N/A

                                                                      \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                                                                    3. lower-log1p.f64N/A

                                                                      \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                                                                    4. lower-log.f6410.8

                                                                      \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                                                                  5. Applied rewrites10.8%

                                                                    \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                                                                  6. Step-by-step derivation
                                                                    1. Applied rewrites81.5%

                                                                      \[\leadsto \frac{\mathsf{log1p}\left(x\right) \cdot n - n \cdot \log x}{\color{blue}{n \cdot n}} \]
                                                                    2. Taylor expanded in x around inf

                                                                      \[\leadsto \frac{\frac{n}{x}}{\color{blue}{n} \cdot n} \]
                                                                    3. Step-by-step derivation
                                                                      1. Applied rewrites81.5%

                                                                        \[\leadsto \frac{\frac{n}{x}}{\color{blue}{n} \cdot n} \]
                                                                    4. Recombined 4 regimes into one program.
                                                                    5. Add Preprocessing

                                                                    Alternative 12: 60.8% accurate, 1.7× speedup?

                                                                    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 0.00047:\\ \;\;\;\;\frac{x}{n} - \frac{\log x}{n}\\ \mathbf{elif}\;x \leq 3.1 \cdot 10^{+135}:\\ \;\;\;\;\frac{\frac{\frac{\frac{0.3333333333333333}{x} - 0.5}{x} + 1}{x}}{n}\\ \mathbf{else}:\\ \;\;\;\;1 - 1\\ \end{array} \end{array} \]
                                                                    (FPCore (x n)
                                                                     :precision binary64
                                                                     (if (<= x 0.00047)
                                                                       (- (/ x n) (/ (log x) n))
                                                                       (if (<= x 3.1e+135)
                                                                         (/ (/ (+ (/ (- (/ 0.3333333333333333 x) 0.5) x) 1.0) x) n)
                                                                         (- 1.0 1.0))))
                                                                    double code(double x, double n) {
                                                                    	double tmp;
                                                                    	if (x <= 0.00047) {
                                                                    		tmp = (x / n) - (log(x) / n);
                                                                    	} else if (x <= 3.1e+135) {
                                                                    		tmp = (((((0.3333333333333333 / x) - 0.5) / x) + 1.0) / x) / n;
                                                                    	} else {
                                                                    		tmp = 1.0 - 1.0;
                                                                    	}
                                                                    	return tmp;
                                                                    }
                                                                    
                                                                    real(8) function code(x, n)
                                                                        real(8), intent (in) :: x
                                                                        real(8), intent (in) :: n
                                                                        real(8) :: tmp
                                                                        if (x <= 0.00047d0) then
                                                                            tmp = (x / n) - (log(x) / n)
                                                                        else if (x <= 3.1d+135) then
                                                                            tmp = (((((0.3333333333333333d0 / x) - 0.5d0) / x) + 1.0d0) / x) / n
                                                                        else
                                                                            tmp = 1.0d0 - 1.0d0
                                                                        end if
                                                                        code = tmp
                                                                    end function
                                                                    
                                                                    public static double code(double x, double n) {
                                                                    	double tmp;
                                                                    	if (x <= 0.00047) {
                                                                    		tmp = (x / n) - (Math.log(x) / n);
                                                                    	} else if (x <= 3.1e+135) {
                                                                    		tmp = (((((0.3333333333333333 / x) - 0.5) / x) + 1.0) / x) / n;
                                                                    	} else {
                                                                    		tmp = 1.0 - 1.0;
                                                                    	}
                                                                    	return tmp;
                                                                    }
                                                                    
                                                                    def code(x, n):
                                                                    	tmp = 0
                                                                    	if x <= 0.00047:
                                                                    		tmp = (x / n) - (math.log(x) / n)
                                                                    	elif x <= 3.1e+135:
                                                                    		tmp = (((((0.3333333333333333 / x) - 0.5) / x) + 1.0) / x) / n
                                                                    	else:
                                                                    		tmp = 1.0 - 1.0
                                                                    	return tmp
                                                                    
                                                                    function code(x, n)
                                                                    	tmp = 0.0
                                                                    	if (x <= 0.00047)
                                                                    		tmp = Float64(Float64(x / n) - Float64(log(x) / n));
                                                                    	elseif (x <= 3.1e+135)
                                                                    		tmp = Float64(Float64(Float64(Float64(Float64(Float64(0.3333333333333333 / x) - 0.5) / x) + 1.0) / x) / n);
                                                                    	else
                                                                    		tmp = Float64(1.0 - 1.0);
                                                                    	end
                                                                    	return tmp
                                                                    end
                                                                    
                                                                    function tmp_2 = code(x, n)
                                                                    	tmp = 0.0;
                                                                    	if (x <= 0.00047)
                                                                    		tmp = (x / n) - (log(x) / n);
                                                                    	elseif (x <= 3.1e+135)
                                                                    		tmp = (((((0.3333333333333333 / x) - 0.5) / x) + 1.0) / x) / n;
                                                                    	else
                                                                    		tmp = 1.0 - 1.0;
                                                                    	end
                                                                    	tmp_2 = tmp;
                                                                    end
                                                                    
                                                                    code[x_, n_] := If[LessEqual[x, 0.00047], N[(N[(x / n), $MachinePrecision] - N[(N[Log[x], $MachinePrecision] / n), $MachinePrecision]), $MachinePrecision], If[LessEqual[x, 3.1e+135], N[(N[(N[(N[(N[(N[(0.3333333333333333 / x), $MachinePrecision] - 0.5), $MachinePrecision] / x), $MachinePrecision] + 1.0), $MachinePrecision] / x), $MachinePrecision] / n), $MachinePrecision], N[(1.0 - 1.0), $MachinePrecision]]]
                                                                    
                                                                    \begin{array}{l}
                                                                    
                                                                    \\
                                                                    \begin{array}{l}
                                                                    \mathbf{if}\;x \leq 0.00047:\\
                                                                    \;\;\;\;\frac{x}{n} - \frac{\log x}{n}\\
                                                                    
                                                                    \mathbf{elif}\;x \leq 3.1 \cdot 10^{+135}:\\
                                                                    \;\;\;\;\frac{\frac{\frac{\frac{0.3333333333333333}{x} - 0.5}{x} + 1}{x}}{n}\\
                                                                    
                                                                    \mathbf{else}:\\
                                                                    \;\;\;\;1 - 1\\
                                                                    
                                                                    
                                                                    \end{array}
                                                                    \end{array}
                                                                    
                                                                    Derivation
                                                                    1. Split input into 3 regimes
                                                                    2. if x < 4.69999999999999986e-4

                                                                      1. Initial program 33.7%

                                                                        \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                      2. Add Preprocessing
                                                                      3. Taylor expanded in x around 0

                                                                        \[\leadsto \color{blue}{\left(1 + \frac{x}{n}\right) - e^{\frac{\log x}{n}}} \]
                                                                      4. Step-by-step derivation
                                                                        1. associate--l+N/A

                                                                          \[\leadsto \color{blue}{1 + \left(\frac{x}{n} - e^{\frac{\log x}{n}}\right)} \]
                                                                        2. +-commutativeN/A

                                                                          \[\leadsto \color{blue}{\left(\frac{x}{n} - e^{\frac{\log x}{n}}\right) + 1} \]
                                                                        3. *-rgt-identityN/A

                                                                          \[\leadsto \left(\frac{\color{blue}{x \cdot 1}}{n} - e^{\frac{\log x}{n}}\right) + 1 \]
                                                                        4. associate-*r/N/A

                                                                          \[\leadsto \left(\color{blue}{x \cdot \frac{1}{n}} - e^{\frac{\log x}{n}}\right) + 1 \]
                                                                        5. remove-double-negN/A

                                                                          \[\leadsto \left(x \cdot \frac{1}{n} - e^{\frac{\color{blue}{\mathsf{neg}\left(\left(\mathsf{neg}\left(\log x\right)\right)\right)}}{n}}\right) + 1 \]
                                                                        6. mul-1-negN/A

                                                                          \[\leadsto \left(x \cdot \frac{1}{n} - e^{\frac{\mathsf{neg}\left(\color{blue}{-1 \cdot \log x}\right)}{n}}\right) + 1 \]
                                                                        7. distribute-neg-fracN/A

                                                                          \[\leadsto \left(x \cdot \frac{1}{n} - e^{\color{blue}{\mathsf{neg}\left(\frac{-1 \cdot \log x}{n}\right)}}\right) + 1 \]
                                                                        8. mul-1-negN/A

                                                                          \[\leadsto \left(x \cdot \frac{1}{n} - e^{\mathsf{neg}\left(\frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}\right)}\right) + 1 \]
                                                                        9. log-recN/A

                                                                          \[\leadsto \left(x \cdot \frac{1}{n} - e^{\mathsf{neg}\left(\frac{\color{blue}{\log \left(\frac{1}{x}\right)}}{n}\right)}\right) + 1 \]
                                                                        10. mul-1-negN/A

                                                                          \[\leadsto \left(x \cdot \frac{1}{n} - e^{\color{blue}{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}\right) + 1 \]
                                                                        11. associate-+l-N/A

                                                                          \[\leadsto \color{blue}{x \cdot \frac{1}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right)} \]
                                                                        12. lower--.f64N/A

                                                                          \[\leadsto \color{blue}{x \cdot \frac{1}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right)} \]
                                                                        13. associate-*r/N/A

                                                                          \[\leadsto \color{blue}{\frac{x \cdot 1}{n}} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
                                                                        14. *-rgt-identityN/A

                                                                          \[\leadsto \frac{\color{blue}{x}}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
                                                                        15. lower-/.f64N/A

                                                                          \[\leadsto \color{blue}{\frac{x}{n}} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
                                                                        16. lower-expm1.f64N/A

                                                                          \[\leadsto \frac{x}{n} - \color{blue}{\mathsf{expm1}\left(-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}\right)} \]
                                                                        17. mul-1-negN/A

                                                                          \[\leadsto \frac{x}{n} - \mathsf{expm1}\left(\color{blue}{\mathsf{neg}\left(\frac{\log \left(\frac{1}{x}\right)}{n}\right)}\right) \]
                                                                      5. Applied rewrites88.6%

                                                                        \[\leadsto \color{blue}{\frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)} \]
                                                                      6. Taylor expanded in n around inf

                                                                        \[\leadsto \frac{x}{n} - \frac{\log x}{\color{blue}{n}} \]
                                                                      7. Step-by-step derivation
                                                                        1. Applied rewrites60.8%

                                                                          \[\leadsto \frac{x}{n} - \frac{\log x}{\color{blue}{n}} \]

                                                                        if 4.69999999999999986e-4 < x < 3.10000000000000022e135

                                                                        1. Initial program 47.9%

                                                                          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                        2. Add Preprocessing
                                                                        3. Taylor expanded in n around inf

                                                                          \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                                        4. Step-by-step derivation
                                                                          1. lower-/.f64N/A

                                                                            \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                                          2. lower--.f64N/A

                                                                            \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                                                                          3. lower-log1p.f64N/A

                                                                            \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                                                                          4. lower-log.f6441.9

                                                                            \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                                                                        5. Applied rewrites41.9%

                                                                          \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                                                                        6. Taylor expanded in x around inf

                                                                          \[\leadsto \frac{\frac{\left(1 + \frac{\frac{1}{3}}{{x}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{x}}{x}}{n} \]
                                                                        7. Step-by-step derivation
                                                                          1. Applied rewrites69.5%

                                                                            \[\leadsto \frac{\frac{\frac{\frac{0.3333333333333333}{x} - 0.5}{x} + 1}{x}}{n} \]

                                                                          if 3.10000000000000022e135 < x

                                                                          1. Initial program 84.7%

                                                                            \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                          2. Add Preprocessing
                                                                          3. Taylor expanded in x around 0

                                                                            \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                          4. Step-by-step derivation
                                                                            1. Applied rewrites44.6%

                                                                              \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                            2. Taylor expanded in n around inf

                                                                              \[\leadsto 1 - \color{blue}{1} \]
                                                                            3. Step-by-step derivation
                                                                              1. Applied rewrites84.7%

                                                                                \[\leadsto 1 - \color{blue}{1} \]
                                                                            4. Recombined 3 regimes into one program.
                                                                            5. Add Preprocessing

                                                                            Alternative 13: 60.8% accurate, 1.9× speedup?

                                                                            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 0.00047:\\ \;\;\;\;\frac{x - \log x}{n}\\ \mathbf{elif}\;x \leq 3.1 \cdot 10^{+135}:\\ \;\;\;\;\frac{\frac{\frac{\frac{0.3333333333333333}{x} - 0.5}{x} + 1}{x}}{n}\\ \mathbf{else}:\\ \;\;\;\;1 - 1\\ \end{array} \end{array} \]
                                                                            (FPCore (x n)
                                                                             :precision binary64
                                                                             (if (<= x 0.00047)
                                                                               (/ (- x (log x)) n)
                                                                               (if (<= x 3.1e+135)
                                                                                 (/ (/ (+ (/ (- (/ 0.3333333333333333 x) 0.5) x) 1.0) x) n)
                                                                                 (- 1.0 1.0))))
                                                                            double code(double x, double n) {
                                                                            	double tmp;
                                                                            	if (x <= 0.00047) {
                                                                            		tmp = (x - log(x)) / n;
                                                                            	} else if (x <= 3.1e+135) {
                                                                            		tmp = (((((0.3333333333333333 / x) - 0.5) / x) + 1.0) / x) / n;
                                                                            	} else {
                                                                            		tmp = 1.0 - 1.0;
                                                                            	}
                                                                            	return tmp;
                                                                            }
                                                                            
                                                                            real(8) function code(x, n)
                                                                                real(8), intent (in) :: x
                                                                                real(8), intent (in) :: n
                                                                                real(8) :: tmp
                                                                                if (x <= 0.00047d0) then
                                                                                    tmp = (x - log(x)) / n
                                                                                else if (x <= 3.1d+135) then
                                                                                    tmp = (((((0.3333333333333333d0 / x) - 0.5d0) / x) + 1.0d0) / x) / n
                                                                                else
                                                                                    tmp = 1.0d0 - 1.0d0
                                                                                end if
                                                                                code = tmp
                                                                            end function
                                                                            
                                                                            public static double code(double x, double n) {
                                                                            	double tmp;
                                                                            	if (x <= 0.00047) {
                                                                            		tmp = (x - Math.log(x)) / n;
                                                                            	} else if (x <= 3.1e+135) {
                                                                            		tmp = (((((0.3333333333333333 / x) - 0.5) / x) + 1.0) / x) / n;
                                                                            	} else {
                                                                            		tmp = 1.0 - 1.0;
                                                                            	}
                                                                            	return tmp;
                                                                            }
                                                                            
                                                                            def code(x, n):
                                                                            	tmp = 0
                                                                            	if x <= 0.00047:
                                                                            		tmp = (x - math.log(x)) / n
                                                                            	elif x <= 3.1e+135:
                                                                            		tmp = (((((0.3333333333333333 / x) - 0.5) / x) + 1.0) / x) / n
                                                                            	else:
                                                                            		tmp = 1.0 - 1.0
                                                                            	return tmp
                                                                            
                                                                            function code(x, n)
                                                                            	tmp = 0.0
                                                                            	if (x <= 0.00047)
                                                                            		tmp = Float64(Float64(x - log(x)) / n);
                                                                            	elseif (x <= 3.1e+135)
                                                                            		tmp = Float64(Float64(Float64(Float64(Float64(Float64(0.3333333333333333 / x) - 0.5) / x) + 1.0) / x) / n);
                                                                            	else
                                                                            		tmp = Float64(1.0 - 1.0);
                                                                            	end
                                                                            	return tmp
                                                                            end
                                                                            
                                                                            function tmp_2 = code(x, n)
                                                                            	tmp = 0.0;
                                                                            	if (x <= 0.00047)
                                                                            		tmp = (x - log(x)) / n;
                                                                            	elseif (x <= 3.1e+135)
                                                                            		tmp = (((((0.3333333333333333 / x) - 0.5) / x) + 1.0) / x) / n;
                                                                            	else
                                                                            		tmp = 1.0 - 1.0;
                                                                            	end
                                                                            	tmp_2 = tmp;
                                                                            end
                                                                            
                                                                            code[x_, n_] := If[LessEqual[x, 0.00047], N[(N[(x - N[Log[x], $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision], If[LessEqual[x, 3.1e+135], N[(N[(N[(N[(N[(N[(0.3333333333333333 / x), $MachinePrecision] - 0.5), $MachinePrecision] / x), $MachinePrecision] + 1.0), $MachinePrecision] / x), $MachinePrecision] / n), $MachinePrecision], N[(1.0 - 1.0), $MachinePrecision]]]
                                                                            
                                                                            \begin{array}{l}
                                                                            
                                                                            \\
                                                                            \begin{array}{l}
                                                                            \mathbf{if}\;x \leq 0.00047:\\
                                                                            \;\;\;\;\frac{x - \log x}{n}\\
                                                                            
                                                                            \mathbf{elif}\;x \leq 3.1 \cdot 10^{+135}:\\
                                                                            \;\;\;\;\frac{\frac{\frac{\frac{0.3333333333333333}{x} - 0.5}{x} + 1}{x}}{n}\\
                                                                            
                                                                            \mathbf{else}:\\
                                                                            \;\;\;\;1 - 1\\
                                                                            
                                                                            
                                                                            \end{array}
                                                                            \end{array}
                                                                            
                                                                            Derivation
                                                                            1. Split input into 3 regimes
                                                                            2. if x < 4.69999999999999986e-4

                                                                              1. Initial program 33.7%

                                                                                \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                              2. Add Preprocessing
                                                                              3. Taylor expanded in n around inf

                                                                                \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                                              4. Step-by-step derivation
                                                                                1. lower-/.f64N/A

                                                                                  \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                                                2. lower--.f64N/A

                                                                                  \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                                                                                3. lower-log1p.f64N/A

                                                                                  \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                                                                                4. lower-log.f6460.9

                                                                                  \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                                                                              5. Applied rewrites60.9%

                                                                                \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                                                                              6. Taylor expanded in x around 0

                                                                                \[\leadsto \frac{x - \log x}{n} \]
                                                                              7. Step-by-step derivation
                                                                                1. Applied rewrites60.8%

                                                                                  \[\leadsto \frac{x - \log x}{n} \]

                                                                                if 4.69999999999999986e-4 < x < 3.10000000000000022e135

                                                                                1. Initial program 47.9%

                                                                                  \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                2. Add Preprocessing
                                                                                3. Taylor expanded in n around inf

                                                                                  \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                                                4. Step-by-step derivation
                                                                                  1. lower-/.f64N/A

                                                                                    \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                                                  2. lower--.f64N/A

                                                                                    \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                                                                                  3. lower-log1p.f64N/A

                                                                                    \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                                                                                  4. lower-log.f6441.9

                                                                                    \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                                                                                5. Applied rewrites41.9%

                                                                                  \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                                                                                6. Taylor expanded in x around inf

                                                                                  \[\leadsto \frac{\frac{\left(1 + \frac{\frac{1}{3}}{{x}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{x}}{x}}{n} \]
                                                                                7. Step-by-step derivation
                                                                                  1. Applied rewrites69.5%

                                                                                    \[\leadsto \frac{\frac{\frac{\frac{0.3333333333333333}{x} - 0.5}{x} + 1}{x}}{n} \]

                                                                                  if 3.10000000000000022e135 < x

                                                                                  1. Initial program 84.7%

                                                                                    \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                  2. Add Preprocessing
                                                                                  3. Taylor expanded in x around 0

                                                                                    \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                  4. Step-by-step derivation
                                                                                    1. Applied rewrites44.6%

                                                                                      \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                    2. Taylor expanded in n around inf

                                                                                      \[\leadsto 1 - \color{blue}{1} \]
                                                                                    3. Step-by-step derivation
                                                                                      1. Applied rewrites84.7%

                                                                                        \[\leadsto 1 - \color{blue}{1} \]
                                                                                    4. Recombined 3 regimes into one program.
                                                                                    5. Add Preprocessing

                                                                                    Alternative 14: 60.6% accurate, 1.9× speedup?

                                                                                    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 0.00047:\\ \;\;\;\;\frac{-\log x}{n}\\ \mathbf{elif}\;x \leq 3.1 \cdot 10^{+135}:\\ \;\;\;\;\frac{\frac{\frac{\frac{0.3333333333333333}{x} - 0.5}{x} + 1}{x}}{n}\\ \mathbf{else}:\\ \;\;\;\;1 - 1\\ \end{array} \end{array} \]
                                                                                    (FPCore (x n)
                                                                                     :precision binary64
                                                                                     (if (<= x 0.00047)
                                                                                       (/ (- (log x)) n)
                                                                                       (if (<= x 3.1e+135)
                                                                                         (/ (/ (+ (/ (- (/ 0.3333333333333333 x) 0.5) x) 1.0) x) n)
                                                                                         (- 1.0 1.0))))
                                                                                    double code(double x, double n) {
                                                                                    	double tmp;
                                                                                    	if (x <= 0.00047) {
                                                                                    		tmp = -log(x) / n;
                                                                                    	} else if (x <= 3.1e+135) {
                                                                                    		tmp = (((((0.3333333333333333 / x) - 0.5) / x) + 1.0) / x) / n;
                                                                                    	} else {
                                                                                    		tmp = 1.0 - 1.0;
                                                                                    	}
                                                                                    	return tmp;
                                                                                    }
                                                                                    
                                                                                    real(8) function code(x, n)
                                                                                        real(8), intent (in) :: x
                                                                                        real(8), intent (in) :: n
                                                                                        real(8) :: tmp
                                                                                        if (x <= 0.00047d0) then
                                                                                            tmp = -log(x) / n
                                                                                        else if (x <= 3.1d+135) then
                                                                                            tmp = (((((0.3333333333333333d0 / x) - 0.5d0) / x) + 1.0d0) / x) / n
                                                                                        else
                                                                                            tmp = 1.0d0 - 1.0d0
                                                                                        end if
                                                                                        code = tmp
                                                                                    end function
                                                                                    
                                                                                    public static double code(double x, double n) {
                                                                                    	double tmp;
                                                                                    	if (x <= 0.00047) {
                                                                                    		tmp = -Math.log(x) / n;
                                                                                    	} else if (x <= 3.1e+135) {
                                                                                    		tmp = (((((0.3333333333333333 / x) - 0.5) / x) + 1.0) / x) / n;
                                                                                    	} else {
                                                                                    		tmp = 1.0 - 1.0;
                                                                                    	}
                                                                                    	return tmp;
                                                                                    }
                                                                                    
                                                                                    def code(x, n):
                                                                                    	tmp = 0
                                                                                    	if x <= 0.00047:
                                                                                    		tmp = -math.log(x) / n
                                                                                    	elif x <= 3.1e+135:
                                                                                    		tmp = (((((0.3333333333333333 / x) - 0.5) / x) + 1.0) / x) / n
                                                                                    	else:
                                                                                    		tmp = 1.0 - 1.0
                                                                                    	return tmp
                                                                                    
                                                                                    function code(x, n)
                                                                                    	tmp = 0.0
                                                                                    	if (x <= 0.00047)
                                                                                    		tmp = Float64(Float64(-log(x)) / n);
                                                                                    	elseif (x <= 3.1e+135)
                                                                                    		tmp = Float64(Float64(Float64(Float64(Float64(Float64(0.3333333333333333 / x) - 0.5) / x) + 1.0) / x) / n);
                                                                                    	else
                                                                                    		tmp = Float64(1.0 - 1.0);
                                                                                    	end
                                                                                    	return tmp
                                                                                    end
                                                                                    
                                                                                    function tmp_2 = code(x, n)
                                                                                    	tmp = 0.0;
                                                                                    	if (x <= 0.00047)
                                                                                    		tmp = -log(x) / n;
                                                                                    	elseif (x <= 3.1e+135)
                                                                                    		tmp = (((((0.3333333333333333 / x) - 0.5) / x) + 1.0) / x) / n;
                                                                                    	else
                                                                                    		tmp = 1.0 - 1.0;
                                                                                    	end
                                                                                    	tmp_2 = tmp;
                                                                                    end
                                                                                    
                                                                                    code[x_, n_] := If[LessEqual[x, 0.00047], N[((-N[Log[x], $MachinePrecision]) / n), $MachinePrecision], If[LessEqual[x, 3.1e+135], N[(N[(N[(N[(N[(N[(0.3333333333333333 / x), $MachinePrecision] - 0.5), $MachinePrecision] / x), $MachinePrecision] + 1.0), $MachinePrecision] / x), $MachinePrecision] / n), $MachinePrecision], N[(1.0 - 1.0), $MachinePrecision]]]
                                                                                    
                                                                                    \begin{array}{l}
                                                                                    
                                                                                    \\
                                                                                    \begin{array}{l}
                                                                                    \mathbf{if}\;x \leq 0.00047:\\
                                                                                    \;\;\;\;\frac{-\log x}{n}\\
                                                                                    
                                                                                    \mathbf{elif}\;x \leq 3.1 \cdot 10^{+135}:\\
                                                                                    \;\;\;\;\frac{\frac{\frac{\frac{0.3333333333333333}{x} - 0.5}{x} + 1}{x}}{n}\\
                                                                                    
                                                                                    \mathbf{else}:\\
                                                                                    \;\;\;\;1 - 1\\
                                                                                    
                                                                                    
                                                                                    \end{array}
                                                                                    \end{array}
                                                                                    
                                                                                    Derivation
                                                                                    1. Split input into 3 regimes
                                                                                    2. if x < 4.69999999999999986e-4

                                                                                      1. Initial program 33.7%

                                                                                        \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                      2. Add Preprocessing
                                                                                      3. Taylor expanded in n around inf

                                                                                        \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                                                      4. Step-by-step derivation
                                                                                        1. lower-/.f64N/A

                                                                                          \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                                                        2. lower--.f64N/A

                                                                                          \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                                                                                        3. lower-log1p.f64N/A

                                                                                          \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                                                                                        4. lower-log.f6460.9

                                                                                          \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                                                                                      5. Applied rewrites60.9%

                                                                                        \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                                                                                      6. Taylor expanded in x around 0

                                                                                        \[\leadsto \frac{-1 \cdot \log x}{n} \]
                                                                                      7. Step-by-step derivation
                                                                                        1. Applied rewrites60.4%

                                                                                          \[\leadsto \frac{-\log x}{n} \]

                                                                                        if 4.69999999999999986e-4 < x < 3.10000000000000022e135

                                                                                        1. Initial program 47.9%

                                                                                          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                        2. Add Preprocessing
                                                                                        3. Taylor expanded in n around inf

                                                                                          \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                                                        4. Step-by-step derivation
                                                                                          1. lower-/.f64N/A

                                                                                            \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                                                          2. lower--.f64N/A

                                                                                            \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                                                                                          3. lower-log1p.f64N/A

                                                                                            \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                                                                                          4. lower-log.f6441.9

                                                                                            \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                                                                                        5. Applied rewrites41.9%

                                                                                          \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                                                                                        6. Taylor expanded in x around inf

                                                                                          \[\leadsto \frac{\frac{\left(1 + \frac{\frac{1}{3}}{{x}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{x}}{x}}{n} \]
                                                                                        7. Step-by-step derivation
                                                                                          1. Applied rewrites69.5%

                                                                                            \[\leadsto \frac{\frac{\frac{\frac{0.3333333333333333}{x} - 0.5}{x} + 1}{x}}{n} \]

                                                                                          if 3.10000000000000022e135 < x

                                                                                          1. Initial program 84.7%

                                                                                            \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                          2. Add Preprocessing
                                                                                          3. Taylor expanded in x around 0

                                                                                            \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                          4. Step-by-step derivation
                                                                                            1. Applied rewrites44.6%

                                                                                              \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                            2. Taylor expanded in n around inf

                                                                                              \[\leadsto 1 - \color{blue}{1} \]
                                                                                            3. Step-by-step derivation
                                                                                              1. Applied rewrites84.7%

                                                                                                \[\leadsto 1 - \color{blue}{1} \]
                                                                                            4. Recombined 3 regimes into one program.
                                                                                            5. Add Preprocessing

                                                                                            Alternative 15: 49.5% accurate, 3.4× speedup?

                                                                                            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{1}{n} \leq -40000000:\\ \;\;\;\;1 - 1\\ \mathbf{elif}\;\frac{1}{n} \leq 4 \cdot 10^{+169}:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(\frac{n}{x}, 0.5, n\right) \cdot x}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{n}{x}}{n \cdot n}\\ \end{array} \end{array} \]
                                                                                            (FPCore (x n)
                                                                                             :precision binary64
                                                                                             (if (<= (/ 1.0 n) -40000000.0)
                                                                                               (- 1.0 1.0)
                                                                                               (if (<= (/ 1.0 n) 4e+169)
                                                                                                 (/ 1.0 (* (fma (/ n x) 0.5 n) x))
                                                                                                 (/ (/ n x) (* n n)))))
                                                                                            double code(double x, double n) {
                                                                                            	double tmp;
                                                                                            	if ((1.0 / n) <= -40000000.0) {
                                                                                            		tmp = 1.0 - 1.0;
                                                                                            	} else if ((1.0 / n) <= 4e+169) {
                                                                                            		tmp = 1.0 / (fma((n / x), 0.5, n) * x);
                                                                                            	} else {
                                                                                            		tmp = (n / x) / (n * n);
                                                                                            	}
                                                                                            	return tmp;
                                                                                            }
                                                                                            
                                                                                            function code(x, n)
                                                                                            	tmp = 0.0
                                                                                            	if (Float64(1.0 / n) <= -40000000.0)
                                                                                            		tmp = Float64(1.0 - 1.0);
                                                                                            	elseif (Float64(1.0 / n) <= 4e+169)
                                                                                            		tmp = Float64(1.0 / Float64(fma(Float64(n / x), 0.5, n) * x));
                                                                                            	else
                                                                                            		tmp = Float64(Float64(n / x) / Float64(n * n));
                                                                                            	end
                                                                                            	return tmp
                                                                                            end
                                                                                            
                                                                                            code[x_, n_] := If[LessEqual[N[(1.0 / n), $MachinePrecision], -40000000.0], N[(1.0 - 1.0), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 4e+169], N[(1.0 / N[(N[(N[(n / x), $MachinePrecision] * 0.5 + n), $MachinePrecision] * x), $MachinePrecision]), $MachinePrecision], N[(N[(n / x), $MachinePrecision] / N[(n * n), $MachinePrecision]), $MachinePrecision]]]
                                                                                            
                                                                                            \begin{array}{l}
                                                                                            
                                                                                            \\
                                                                                            \begin{array}{l}
                                                                                            \mathbf{if}\;\frac{1}{n} \leq -40000000:\\
                                                                                            \;\;\;\;1 - 1\\
                                                                                            
                                                                                            \mathbf{elif}\;\frac{1}{n} \leq 4 \cdot 10^{+169}:\\
                                                                                            \;\;\;\;\frac{1}{\mathsf{fma}\left(\frac{n}{x}, 0.5, n\right) \cdot x}\\
                                                                                            
                                                                                            \mathbf{else}:\\
                                                                                            \;\;\;\;\frac{\frac{n}{x}}{n \cdot n}\\
                                                                                            
                                                                                            
                                                                                            \end{array}
                                                                                            \end{array}
                                                                                            
                                                                                            Derivation
                                                                                            1. Split input into 3 regimes
                                                                                            2. if (/.f64 #s(literal 1 binary64) n) < -4e7

                                                                                              1. Initial program 100.0%

                                                                                                \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                              2. Add Preprocessing
                                                                                              3. Taylor expanded in x around 0

                                                                                                \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                              4. Step-by-step derivation
                                                                                                1. Applied rewrites44.6%

                                                                                                  \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                2. Taylor expanded in n around inf

                                                                                                  \[\leadsto 1 - \color{blue}{1} \]
                                                                                                3. Step-by-step derivation
                                                                                                  1. Applied rewrites57.8%

                                                                                                    \[\leadsto 1 - \color{blue}{1} \]

                                                                                                  if -4e7 < (/.f64 #s(literal 1 binary64) n) < 3.99999999999999974e169

                                                                                                  1. Initial program 31.5%

                                                                                                    \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                  2. Add Preprocessing
                                                                                                  3. Taylor expanded in n around inf

                                                                                                    \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                                                                  4. Step-by-step derivation
                                                                                                    1. lower-/.f64N/A

                                                                                                      \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                                                                    2. lower--.f64N/A

                                                                                                      \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                                                                                                    3. lower-log1p.f64N/A

                                                                                                      \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                                                                                                    4. lower-log.f6471.5

                                                                                                      \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                                                                                                  5. Applied rewrites71.5%

                                                                                                    \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                                                                                                  6. Step-by-step derivation
                                                                                                    1. Applied rewrites71.5%

                                                                                                      \[\leadsto \frac{1}{\color{blue}{\frac{n}{\mathsf{log1p}\left(x\right) - \log x}}} \]
                                                                                                    2. Taylor expanded in x around inf

                                                                                                      \[\leadsto \frac{1}{x \cdot \color{blue}{\left(n + \frac{1}{2} \cdot \frac{n}{x}\right)}} \]
                                                                                                    3. Step-by-step derivation
                                                                                                      1. Applied rewrites43.3%

                                                                                                        \[\leadsto \frac{1}{\mathsf{fma}\left(\frac{n}{x}, 0.5, n\right) \cdot \color{blue}{x}} \]

                                                                                                      if 3.99999999999999974e169 < (/.f64 #s(literal 1 binary64) n)

                                                                                                      1. Initial program 26.2%

                                                                                                        \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                      2. Add Preprocessing
                                                                                                      3. Taylor expanded in n around inf

                                                                                                        \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                                                                      4. Step-by-step derivation
                                                                                                        1. lower-/.f64N/A

                                                                                                          \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                                                                        2. lower--.f64N/A

                                                                                                          \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                                                                                                        3. lower-log1p.f64N/A

                                                                                                          \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                                                                                                        4. lower-log.f6410.8

                                                                                                          \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                                                                                                      5. Applied rewrites10.8%

                                                                                                        \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                                                                                                      6. Step-by-step derivation
                                                                                                        1. Applied rewrites81.5%

                                                                                                          \[\leadsto \frac{\mathsf{log1p}\left(x\right) \cdot n - n \cdot \log x}{\color{blue}{n \cdot n}} \]
                                                                                                        2. Taylor expanded in x around inf

                                                                                                          \[\leadsto \frac{\frac{n}{x}}{\color{blue}{n} \cdot n} \]
                                                                                                        3. Step-by-step derivation
                                                                                                          1. Applied rewrites81.5%

                                                                                                            \[\leadsto \frac{\frac{n}{x}}{\color{blue}{n} \cdot n} \]
                                                                                                        4. Recombined 3 regimes into one program.
                                                                                                        5. Add Preprocessing

                                                                                                        Alternative 16: 48.3% accurate, 3.7× speedup?

                                                                                                        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{1}{n} \leq -40000000:\\ \;\;\;\;1 - 1\\ \mathbf{elif}\;\frac{1}{n} \leq 5 \cdot 10^{-40}:\\ \;\;\;\;\frac{\frac{1}{x}}{n}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{n}{x}}{n \cdot n}\\ \end{array} \end{array} \]
                                                                                                        (FPCore (x n)
                                                                                                         :precision binary64
                                                                                                         (if (<= (/ 1.0 n) -40000000.0)
                                                                                                           (- 1.0 1.0)
                                                                                                           (if (<= (/ 1.0 n) 5e-40) (/ (/ 1.0 x) n) (/ (/ n x) (* n n)))))
                                                                                                        double code(double x, double n) {
                                                                                                        	double tmp;
                                                                                                        	if ((1.0 / n) <= -40000000.0) {
                                                                                                        		tmp = 1.0 - 1.0;
                                                                                                        	} else if ((1.0 / n) <= 5e-40) {
                                                                                                        		tmp = (1.0 / x) / n;
                                                                                                        	} else {
                                                                                                        		tmp = (n / x) / (n * n);
                                                                                                        	}
                                                                                                        	return tmp;
                                                                                                        }
                                                                                                        
                                                                                                        real(8) function code(x, n)
                                                                                                            real(8), intent (in) :: x
                                                                                                            real(8), intent (in) :: n
                                                                                                            real(8) :: tmp
                                                                                                            if ((1.0d0 / n) <= (-40000000.0d0)) then
                                                                                                                tmp = 1.0d0 - 1.0d0
                                                                                                            else if ((1.0d0 / n) <= 5d-40) then
                                                                                                                tmp = (1.0d0 / x) / n
                                                                                                            else
                                                                                                                tmp = (n / x) / (n * n)
                                                                                                            end if
                                                                                                            code = tmp
                                                                                                        end function
                                                                                                        
                                                                                                        public static double code(double x, double n) {
                                                                                                        	double tmp;
                                                                                                        	if ((1.0 / n) <= -40000000.0) {
                                                                                                        		tmp = 1.0 - 1.0;
                                                                                                        	} else if ((1.0 / n) <= 5e-40) {
                                                                                                        		tmp = (1.0 / x) / n;
                                                                                                        	} else {
                                                                                                        		tmp = (n / x) / (n * n);
                                                                                                        	}
                                                                                                        	return tmp;
                                                                                                        }
                                                                                                        
                                                                                                        def code(x, n):
                                                                                                        	tmp = 0
                                                                                                        	if (1.0 / n) <= -40000000.0:
                                                                                                        		tmp = 1.0 - 1.0
                                                                                                        	elif (1.0 / n) <= 5e-40:
                                                                                                        		tmp = (1.0 / x) / n
                                                                                                        	else:
                                                                                                        		tmp = (n / x) / (n * n)
                                                                                                        	return tmp
                                                                                                        
                                                                                                        function code(x, n)
                                                                                                        	tmp = 0.0
                                                                                                        	if (Float64(1.0 / n) <= -40000000.0)
                                                                                                        		tmp = Float64(1.0 - 1.0);
                                                                                                        	elseif (Float64(1.0 / n) <= 5e-40)
                                                                                                        		tmp = Float64(Float64(1.0 / x) / n);
                                                                                                        	else
                                                                                                        		tmp = Float64(Float64(n / x) / Float64(n * n));
                                                                                                        	end
                                                                                                        	return tmp
                                                                                                        end
                                                                                                        
                                                                                                        function tmp_2 = code(x, n)
                                                                                                        	tmp = 0.0;
                                                                                                        	if ((1.0 / n) <= -40000000.0)
                                                                                                        		tmp = 1.0 - 1.0;
                                                                                                        	elseif ((1.0 / n) <= 5e-40)
                                                                                                        		tmp = (1.0 / x) / n;
                                                                                                        	else
                                                                                                        		tmp = (n / x) / (n * n);
                                                                                                        	end
                                                                                                        	tmp_2 = tmp;
                                                                                                        end
                                                                                                        
                                                                                                        code[x_, n_] := If[LessEqual[N[(1.0 / n), $MachinePrecision], -40000000.0], N[(1.0 - 1.0), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 5e-40], N[(N[(1.0 / x), $MachinePrecision] / n), $MachinePrecision], N[(N[(n / x), $MachinePrecision] / N[(n * n), $MachinePrecision]), $MachinePrecision]]]
                                                                                                        
                                                                                                        \begin{array}{l}
                                                                                                        
                                                                                                        \\
                                                                                                        \begin{array}{l}
                                                                                                        \mathbf{if}\;\frac{1}{n} \leq -40000000:\\
                                                                                                        \;\;\;\;1 - 1\\
                                                                                                        
                                                                                                        \mathbf{elif}\;\frac{1}{n} \leq 5 \cdot 10^{-40}:\\
                                                                                                        \;\;\;\;\frac{\frac{1}{x}}{n}\\
                                                                                                        
                                                                                                        \mathbf{else}:\\
                                                                                                        \;\;\;\;\frac{\frac{n}{x}}{n \cdot n}\\
                                                                                                        
                                                                                                        
                                                                                                        \end{array}
                                                                                                        \end{array}
                                                                                                        
                                                                                                        Derivation
                                                                                                        1. Split input into 3 regimes
                                                                                                        2. if (/.f64 #s(literal 1 binary64) n) < -4e7

                                                                                                          1. Initial program 100.0%

                                                                                                            \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                          2. Add Preprocessing
                                                                                                          3. Taylor expanded in x around 0

                                                                                                            \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                          4. Step-by-step derivation
                                                                                                            1. Applied rewrites44.6%

                                                                                                              \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                            2. Taylor expanded in n around inf

                                                                                                              \[\leadsto 1 - \color{blue}{1} \]
                                                                                                            3. Step-by-step derivation
                                                                                                              1. Applied rewrites57.8%

                                                                                                                \[\leadsto 1 - \color{blue}{1} \]

                                                                                                              if -4e7 < (/.f64 #s(literal 1 binary64) n) < 4.99999999999999965e-40

                                                                                                              1. Initial program 26.4%

                                                                                                                \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                              2. Add Preprocessing
                                                                                                              3. Taylor expanded in x around inf

                                                                                                                \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                                                                                                              4. Step-by-step derivation
                                                                                                                1. associate-/l/N/A

                                                                                                                  \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                                                                                                                2. lower-/.f64N/A

                                                                                                                  \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                                                                                                                3. lower-/.f64N/A

                                                                                                                  \[\leadsto \frac{\color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}}{n} \]
                                                                                                                4. log-recN/A

                                                                                                                  \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{x}}{n} \]
                                                                                                                5. mul-1-negN/A

                                                                                                                  \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{x}}{n} \]
                                                                                                                6. associate-*r/N/A

                                                                                                                  \[\leadsto \frac{\frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{x}}{n} \]
                                                                                                                7. associate-*r*N/A

                                                                                                                  \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{x}}{n} \]
                                                                                                                8. metadata-evalN/A

                                                                                                                  \[\leadsto \frac{\frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{x}}{n} \]
                                                                                                                9. *-commutativeN/A

                                                                                                                  \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{x}}{n} \]
                                                                                                                10. associate-/l*N/A

                                                                                                                  \[\leadsto \frac{\frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{x}}{n} \]
                                                                                                                11. exp-to-powN/A

                                                                                                                  \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                                                                                                                12. lower-pow.f64N/A

                                                                                                                  \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                                                                                                                13. lower-/.f6445.0

                                                                                                                  \[\leadsto \frac{\frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                                                                                                              5. Applied rewrites45.0%

                                                                                                                \[\leadsto \color{blue}{\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}} \]
                                                                                                              6. Taylor expanded in n around inf

                                                                                                                \[\leadsto \frac{\frac{1}{x}}{n} \]
                                                                                                              7. Step-by-step derivation
                                                                                                                1. Applied rewrites43.9%

                                                                                                                  \[\leadsto \frac{\frac{1}{x}}{n} \]

                                                                                                                if 4.99999999999999965e-40 < (/.f64 #s(literal 1 binary64) n)

                                                                                                                1. Initial program 47.9%

                                                                                                                  \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                                2. Add Preprocessing
                                                                                                                3. Taylor expanded in n around inf

                                                                                                                  \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                                                                                4. Step-by-step derivation
                                                                                                                  1. lower-/.f64N/A

                                                                                                                    \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                                                                                  2. lower--.f64N/A

                                                                                                                    \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                                                                                                                  3. lower-log1p.f64N/A

                                                                                                                    \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                                                                                                                  4. lower-log.f6410.2

                                                                                                                    \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                                                                                                                5. Applied rewrites10.2%

                                                                                                                  \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                                                                                                                6. Step-by-step derivation
                                                                                                                  1. Applied rewrites47.3%

                                                                                                                    \[\leadsto \frac{\mathsf{log1p}\left(x\right) \cdot n - n \cdot \log x}{\color{blue}{n \cdot n}} \]
                                                                                                                  2. Taylor expanded in x around inf

                                                                                                                    \[\leadsto \frac{\frac{n}{x}}{\color{blue}{n} \cdot n} \]
                                                                                                                  3. Step-by-step derivation
                                                                                                                    1. Applied rewrites50.9%

                                                                                                                      \[\leadsto \frac{\frac{n}{x}}{\color{blue}{n} \cdot n} \]
                                                                                                                  4. Recombined 3 regimes into one program.
                                                                                                                  5. Add Preprocessing

                                                                                                                  Alternative 17: 51.1% accurate, 4.1× speedup?

                                                                                                                  \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 3.1 \cdot 10^{+135}:\\ \;\;\;\;\frac{\frac{\frac{\frac{0.3333333333333333}{x} - 0.5}{x} + 1}{n}}{x}\\ \mathbf{else}:\\ \;\;\;\;1 - 1\\ \end{array} \end{array} \]
                                                                                                                  (FPCore (x n)
                                                                                                                   :precision binary64
                                                                                                                   (if (<= x 3.1e+135)
                                                                                                                     (/ (/ (+ (/ (- (/ 0.3333333333333333 x) 0.5) x) 1.0) n) x)
                                                                                                                     (- 1.0 1.0)))
                                                                                                                  double code(double x, double n) {
                                                                                                                  	double tmp;
                                                                                                                  	if (x <= 3.1e+135) {
                                                                                                                  		tmp = (((((0.3333333333333333 / x) - 0.5) / x) + 1.0) / n) / x;
                                                                                                                  	} else {
                                                                                                                  		tmp = 1.0 - 1.0;
                                                                                                                  	}
                                                                                                                  	return tmp;
                                                                                                                  }
                                                                                                                  
                                                                                                                  real(8) function code(x, n)
                                                                                                                      real(8), intent (in) :: x
                                                                                                                      real(8), intent (in) :: n
                                                                                                                      real(8) :: tmp
                                                                                                                      if (x <= 3.1d+135) then
                                                                                                                          tmp = (((((0.3333333333333333d0 / x) - 0.5d0) / x) + 1.0d0) / n) / x
                                                                                                                      else
                                                                                                                          tmp = 1.0d0 - 1.0d0
                                                                                                                      end if
                                                                                                                      code = tmp
                                                                                                                  end function
                                                                                                                  
                                                                                                                  public static double code(double x, double n) {
                                                                                                                  	double tmp;
                                                                                                                  	if (x <= 3.1e+135) {
                                                                                                                  		tmp = (((((0.3333333333333333 / x) - 0.5) / x) + 1.0) / n) / x;
                                                                                                                  	} else {
                                                                                                                  		tmp = 1.0 - 1.0;
                                                                                                                  	}
                                                                                                                  	return tmp;
                                                                                                                  }
                                                                                                                  
                                                                                                                  def code(x, n):
                                                                                                                  	tmp = 0
                                                                                                                  	if x <= 3.1e+135:
                                                                                                                  		tmp = (((((0.3333333333333333 / x) - 0.5) / x) + 1.0) / n) / x
                                                                                                                  	else:
                                                                                                                  		tmp = 1.0 - 1.0
                                                                                                                  	return tmp
                                                                                                                  
                                                                                                                  function code(x, n)
                                                                                                                  	tmp = 0.0
                                                                                                                  	if (x <= 3.1e+135)
                                                                                                                  		tmp = Float64(Float64(Float64(Float64(Float64(Float64(0.3333333333333333 / x) - 0.5) / x) + 1.0) / n) / x);
                                                                                                                  	else
                                                                                                                  		tmp = Float64(1.0 - 1.0);
                                                                                                                  	end
                                                                                                                  	return tmp
                                                                                                                  end
                                                                                                                  
                                                                                                                  function tmp_2 = code(x, n)
                                                                                                                  	tmp = 0.0;
                                                                                                                  	if (x <= 3.1e+135)
                                                                                                                  		tmp = (((((0.3333333333333333 / x) - 0.5) / x) + 1.0) / n) / x;
                                                                                                                  	else
                                                                                                                  		tmp = 1.0 - 1.0;
                                                                                                                  	end
                                                                                                                  	tmp_2 = tmp;
                                                                                                                  end
                                                                                                                  
                                                                                                                  code[x_, n_] := If[LessEqual[x, 3.1e+135], N[(N[(N[(N[(N[(N[(0.3333333333333333 / x), $MachinePrecision] - 0.5), $MachinePrecision] / x), $MachinePrecision] + 1.0), $MachinePrecision] / n), $MachinePrecision] / x), $MachinePrecision], N[(1.0 - 1.0), $MachinePrecision]]
                                                                                                                  
                                                                                                                  \begin{array}{l}
                                                                                                                  
                                                                                                                  \\
                                                                                                                  \begin{array}{l}
                                                                                                                  \mathbf{if}\;x \leq 3.1 \cdot 10^{+135}:\\
                                                                                                                  \;\;\;\;\frac{\frac{\frac{\frac{0.3333333333333333}{x} - 0.5}{x} + 1}{n}}{x}\\
                                                                                                                  
                                                                                                                  \mathbf{else}:\\
                                                                                                                  \;\;\;\;1 - 1\\
                                                                                                                  
                                                                                                                  
                                                                                                                  \end{array}
                                                                                                                  \end{array}
                                                                                                                  
                                                                                                                  Derivation
                                                                                                                  1. Split input into 2 regimes
                                                                                                                  2. if x < 3.10000000000000022e135

                                                                                                                    1. Initial program 37.1%

                                                                                                                      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                                    2. Add Preprocessing
                                                                                                                    3. Taylor expanded in n around inf

                                                                                                                      \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                                                                                    4. Step-by-step derivation
                                                                                                                      1. lower-/.f64N/A

                                                                                                                        \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                                                                                      2. lower--.f64N/A

                                                                                                                        \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                                                                                                                      3. lower-log1p.f64N/A

                                                                                                                        \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                                                                                                                      4. lower-log.f6456.4

                                                                                                                        \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                                                                                                                    5. Applied rewrites56.4%

                                                                                                                      \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                                                                                                                    6. Taylor expanded in x around -inf

                                                                                                                      \[\leadsto -1 \cdot \color{blue}{\frac{-1 \cdot \frac{\frac{1}{3} \cdot \frac{1}{n \cdot x} - \frac{1}{2} \cdot \frac{1}{n}}{x} - \frac{1}{n}}{x}} \]
                                                                                                                    7. Step-by-step derivation
                                                                                                                      1. Applied rewrites39.1%

                                                                                                                        \[\leadsto \frac{\frac{\frac{\frac{0.3333333333333333}{n}}{x} - \frac{0.5}{n}}{x} + \frac{1}{n}}{\color{blue}{x}} \]
                                                                                                                      2. Taylor expanded in n around 0

                                                                                                                        \[\leadsto \frac{\left(1 + \frac{1}{3} \cdot \frac{1}{{x}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{x}}{n \cdot \color{blue}{x}} \]
                                                                                                                      3. Step-by-step derivation
                                                                                                                        1. Applied rewrites39.1%

                                                                                                                          \[\leadsto \frac{\frac{\frac{\frac{0.3333333333333333}{x} - 0.5}{x} + 1}{n}}{x} \]

                                                                                                                        if 3.10000000000000022e135 < x

                                                                                                                        1. Initial program 84.7%

                                                                                                                          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                                        2. Add Preprocessing
                                                                                                                        3. Taylor expanded in x around 0

                                                                                                                          \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                                        4. Step-by-step derivation
                                                                                                                          1. Applied rewrites44.6%

                                                                                                                            \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                                          2. Taylor expanded in n around inf

                                                                                                                            \[\leadsto 1 - \color{blue}{1} \]
                                                                                                                          3. Step-by-step derivation
                                                                                                                            1. Applied rewrites84.7%

                                                                                                                              \[\leadsto 1 - \color{blue}{1} \]
                                                                                                                          4. Recombined 2 regimes into one program.
                                                                                                                          5. Add Preprocessing

                                                                                                                          Alternative 18: 46.9% accurate, 5.8× speedup?

                                                                                                                          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{1}{n} \leq -40000000:\\ \;\;\;\;1 - 1\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{1}{x}}{n}\\ \end{array} \end{array} \]
                                                                                                                          (FPCore (x n)
                                                                                                                           :precision binary64
                                                                                                                           (if (<= (/ 1.0 n) -40000000.0) (- 1.0 1.0) (/ (/ 1.0 x) n)))
                                                                                                                          double code(double x, double n) {
                                                                                                                          	double tmp;
                                                                                                                          	if ((1.0 / n) <= -40000000.0) {
                                                                                                                          		tmp = 1.0 - 1.0;
                                                                                                                          	} else {
                                                                                                                          		tmp = (1.0 / x) / n;
                                                                                                                          	}
                                                                                                                          	return tmp;
                                                                                                                          }
                                                                                                                          
                                                                                                                          real(8) function code(x, n)
                                                                                                                              real(8), intent (in) :: x
                                                                                                                              real(8), intent (in) :: n
                                                                                                                              real(8) :: tmp
                                                                                                                              if ((1.0d0 / n) <= (-40000000.0d0)) then
                                                                                                                                  tmp = 1.0d0 - 1.0d0
                                                                                                                              else
                                                                                                                                  tmp = (1.0d0 / x) / n
                                                                                                                              end if
                                                                                                                              code = tmp
                                                                                                                          end function
                                                                                                                          
                                                                                                                          public static double code(double x, double n) {
                                                                                                                          	double tmp;
                                                                                                                          	if ((1.0 / n) <= -40000000.0) {
                                                                                                                          		tmp = 1.0 - 1.0;
                                                                                                                          	} else {
                                                                                                                          		tmp = (1.0 / x) / n;
                                                                                                                          	}
                                                                                                                          	return tmp;
                                                                                                                          }
                                                                                                                          
                                                                                                                          def code(x, n):
                                                                                                                          	tmp = 0
                                                                                                                          	if (1.0 / n) <= -40000000.0:
                                                                                                                          		tmp = 1.0 - 1.0
                                                                                                                          	else:
                                                                                                                          		tmp = (1.0 / x) / n
                                                                                                                          	return tmp
                                                                                                                          
                                                                                                                          function code(x, n)
                                                                                                                          	tmp = 0.0
                                                                                                                          	if (Float64(1.0 / n) <= -40000000.0)
                                                                                                                          		tmp = Float64(1.0 - 1.0);
                                                                                                                          	else
                                                                                                                          		tmp = Float64(Float64(1.0 / x) / n);
                                                                                                                          	end
                                                                                                                          	return tmp
                                                                                                                          end
                                                                                                                          
                                                                                                                          function tmp_2 = code(x, n)
                                                                                                                          	tmp = 0.0;
                                                                                                                          	if ((1.0 / n) <= -40000000.0)
                                                                                                                          		tmp = 1.0 - 1.0;
                                                                                                                          	else
                                                                                                                          		tmp = (1.0 / x) / n;
                                                                                                                          	end
                                                                                                                          	tmp_2 = tmp;
                                                                                                                          end
                                                                                                                          
                                                                                                                          code[x_, n_] := If[LessEqual[N[(1.0 / n), $MachinePrecision], -40000000.0], N[(1.0 - 1.0), $MachinePrecision], N[(N[(1.0 / x), $MachinePrecision] / n), $MachinePrecision]]
                                                                                                                          
                                                                                                                          \begin{array}{l}
                                                                                                                          
                                                                                                                          \\
                                                                                                                          \begin{array}{l}
                                                                                                                          \mathbf{if}\;\frac{1}{n} \leq -40000000:\\
                                                                                                                          \;\;\;\;1 - 1\\
                                                                                                                          
                                                                                                                          \mathbf{else}:\\
                                                                                                                          \;\;\;\;\frac{\frac{1}{x}}{n}\\
                                                                                                                          
                                                                                                                          
                                                                                                                          \end{array}
                                                                                                                          \end{array}
                                                                                                                          
                                                                                                                          Derivation
                                                                                                                          1. Split input into 2 regimes
                                                                                                                          2. if (/.f64 #s(literal 1 binary64) n) < -4e7

                                                                                                                            1. Initial program 100.0%

                                                                                                                              \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                                            2. Add Preprocessing
                                                                                                                            3. Taylor expanded in x around 0

                                                                                                                              \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                                            4. Step-by-step derivation
                                                                                                                              1. Applied rewrites44.6%

                                                                                                                                \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                                              2. Taylor expanded in n around inf

                                                                                                                                \[\leadsto 1 - \color{blue}{1} \]
                                                                                                                              3. Step-by-step derivation
                                                                                                                                1. Applied rewrites57.8%

                                                                                                                                  \[\leadsto 1 - \color{blue}{1} \]

                                                                                                                                if -4e7 < (/.f64 #s(literal 1 binary64) n)

                                                                                                                                1. Initial program 30.9%

                                                                                                                                  \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                                                2. Add Preprocessing
                                                                                                                                3. Taylor expanded in x around inf

                                                                                                                                  \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                                                                                                                                4. Step-by-step derivation
                                                                                                                                  1. associate-/l/N/A

                                                                                                                                    \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                                                                                                                                  2. lower-/.f64N/A

                                                                                                                                    \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                                                                                                                                  3. lower-/.f64N/A

                                                                                                                                    \[\leadsto \frac{\color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}}{n} \]
                                                                                                                                  4. log-recN/A

                                                                                                                                    \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{x}}{n} \]
                                                                                                                                  5. mul-1-negN/A

                                                                                                                                    \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{x}}{n} \]
                                                                                                                                  6. associate-*r/N/A

                                                                                                                                    \[\leadsto \frac{\frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{x}}{n} \]
                                                                                                                                  7. associate-*r*N/A

                                                                                                                                    \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{x}}{n} \]
                                                                                                                                  8. metadata-evalN/A

                                                                                                                                    \[\leadsto \frac{\frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{x}}{n} \]
                                                                                                                                  9. *-commutativeN/A

                                                                                                                                    \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{x}}{n} \]
                                                                                                                                  10. associate-/l*N/A

                                                                                                                                    \[\leadsto \frac{\frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{x}}{n} \]
                                                                                                                                  11. exp-to-powN/A

                                                                                                                                    \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                                                                                                                                  12. lower-pow.f64N/A

                                                                                                                                    \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                                                                                                                                  13. lower-/.f6437.7

                                                                                                                                    \[\leadsto \frac{\frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                                                                                                                                5. Applied rewrites37.7%

                                                                                                                                  \[\leadsto \color{blue}{\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}} \]
                                                                                                                                6. Taylor expanded in n around inf

                                                                                                                                  \[\leadsto \frac{\frac{1}{x}}{n} \]
                                                                                                                                7. Step-by-step derivation
                                                                                                                                  1. Applied rewrites42.0%

                                                                                                                                    \[\leadsto \frac{\frac{1}{x}}{n} \]
                                                                                                                                8. Recombined 2 regimes into one program.
                                                                                                                                9. Add Preprocessing

                                                                                                                                Alternative 19: 46.9% accurate, 5.8× speedup?

                                                                                                                                \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{1}{n} \leq -40000000:\\ \;\;\;\;1 - 1\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{1}{n}}{x}\\ \end{array} \end{array} \]
                                                                                                                                (FPCore (x n)
                                                                                                                                 :precision binary64
                                                                                                                                 (if (<= (/ 1.0 n) -40000000.0) (- 1.0 1.0) (/ (/ 1.0 n) x)))
                                                                                                                                double code(double x, double n) {
                                                                                                                                	double tmp;
                                                                                                                                	if ((1.0 / n) <= -40000000.0) {
                                                                                                                                		tmp = 1.0 - 1.0;
                                                                                                                                	} else {
                                                                                                                                		tmp = (1.0 / n) / x;
                                                                                                                                	}
                                                                                                                                	return tmp;
                                                                                                                                }
                                                                                                                                
                                                                                                                                real(8) function code(x, n)
                                                                                                                                    real(8), intent (in) :: x
                                                                                                                                    real(8), intent (in) :: n
                                                                                                                                    real(8) :: tmp
                                                                                                                                    if ((1.0d0 / n) <= (-40000000.0d0)) then
                                                                                                                                        tmp = 1.0d0 - 1.0d0
                                                                                                                                    else
                                                                                                                                        tmp = (1.0d0 / n) / x
                                                                                                                                    end if
                                                                                                                                    code = tmp
                                                                                                                                end function
                                                                                                                                
                                                                                                                                public static double code(double x, double n) {
                                                                                                                                	double tmp;
                                                                                                                                	if ((1.0 / n) <= -40000000.0) {
                                                                                                                                		tmp = 1.0 - 1.0;
                                                                                                                                	} else {
                                                                                                                                		tmp = (1.0 / n) / x;
                                                                                                                                	}
                                                                                                                                	return tmp;
                                                                                                                                }
                                                                                                                                
                                                                                                                                def code(x, n):
                                                                                                                                	tmp = 0
                                                                                                                                	if (1.0 / n) <= -40000000.0:
                                                                                                                                		tmp = 1.0 - 1.0
                                                                                                                                	else:
                                                                                                                                		tmp = (1.0 / n) / x
                                                                                                                                	return tmp
                                                                                                                                
                                                                                                                                function code(x, n)
                                                                                                                                	tmp = 0.0
                                                                                                                                	if (Float64(1.0 / n) <= -40000000.0)
                                                                                                                                		tmp = Float64(1.0 - 1.0);
                                                                                                                                	else
                                                                                                                                		tmp = Float64(Float64(1.0 / n) / x);
                                                                                                                                	end
                                                                                                                                	return tmp
                                                                                                                                end
                                                                                                                                
                                                                                                                                function tmp_2 = code(x, n)
                                                                                                                                	tmp = 0.0;
                                                                                                                                	if ((1.0 / n) <= -40000000.0)
                                                                                                                                		tmp = 1.0 - 1.0;
                                                                                                                                	else
                                                                                                                                		tmp = (1.0 / n) / x;
                                                                                                                                	end
                                                                                                                                	tmp_2 = tmp;
                                                                                                                                end
                                                                                                                                
                                                                                                                                code[x_, n_] := If[LessEqual[N[(1.0 / n), $MachinePrecision], -40000000.0], N[(1.0 - 1.0), $MachinePrecision], N[(N[(1.0 / n), $MachinePrecision] / x), $MachinePrecision]]
                                                                                                                                
                                                                                                                                \begin{array}{l}
                                                                                                                                
                                                                                                                                \\
                                                                                                                                \begin{array}{l}
                                                                                                                                \mathbf{if}\;\frac{1}{n} \leq -40000000:\\
                                                                                                                                \;\;\;\;1 - 1\\
                                                                                                                                
                                                                                                                                \mathbf{else}:\\
                                                                                                                                \;\;\;\;\frac{\frac{1}{n}}{x}\\
                                                                                                                                
                                                                                                                                
                                                                                                                                \end{array}
                                                                                                                                \end{array}
                                                                                                                                
                                                                                                                                Derivation
                                                                                                                                1. Split input into 2 regimes
                                                                                                                                2. if (/.f64 #s(literal 1 binary64) n) < -4e7

                                                                                                                                  1. Initial program 100.0%

                                                                                                                                    \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                                                  2. Add Preprocessing
                                                                                                                                  3. Taylor expanded in x around 0

                                                                                                                                    \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                                                  4. Step-by-step derivation
                                                                                                                                    1. Applied rewrites44.6%

                                                                                                                                      \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                                                    2. Taylor expanded in n around inf

                                                                                                                                      \[\leadsto 1 - \color{blue}{1} \]
                                                                                                                                    3. Step-by-step derivation
                                                                                                                                      1. Applied rewrites57.8%

                                                                                                                                        \[\leadsto 1 - \color{blue}{1} \]

                                                                                                                                      if -4e7 < (/.f64 #s(literal 1 binary64) n)

                                                                                                                                      1. Initial program 30.9%

                                                                                                                                        \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                                                      2. Add Preprocessing
                                                                                                                                      3. Taylor expanded in x around inf

                                                                                                                                        \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                                                                                                                                      4. Step-by-step derivation
                                                                                                                                        1. associate-/l/N/A

                                                                                                                                          \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                                                                                                                                        2. lower-/.f64N/A

                                                                                                                                          \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                                                                                                                                        3. lower-/.f64N/A

                                                                                                                                          \[\leadsto \frac{\color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}}{n} \]
                                                                                                                                        4. log-recN/A

                                                                                                                                          \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{x}}{n} \]
                                                                                                                                        5. mul-1-negN/A

                                                                                                                                          \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{x}}{n} \]
                                                                                                                                        6. associate-*r/N/A

                                                                                                                                          \[\leadsto \frac{\frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{x}}{n} \]
                                                                                                                                        7. associate-*r*N/A

                                                                                                                                          \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{x}}{n} \]
                                                                                                                                        8. metadata-evalN/A

                                                                                                                                          \[\leadsto \frac{\frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{x}}{n} \]
                                                                                                                                        9. *-commutativeN/A

                                                                                                                                          \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{x}}{n} \]
                                                                                                                                        10. associate-/l*N/A

                                                                                                                                          \[\leadsto \frac{\frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{x}}{n} \]
                                                                                                                                        11. exp-to-powN/A

                                                                                                                                          \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                                                                                                                                        12. lower-pow.f64N/A

                                                                                                                                          \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                                                                                                                                        13. lower-/.f6437.7

                                                                                                                                          \[\leadsto \frac{\frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                                                                                                                                      5. Applied rewrites37.7%

                                                                                                                                        \[\leadsto \color{blue}{\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}} \]
                                                                                                                                      6. Step-by-step derivation
                                                                                                                                        1. Applied rewrites37.6%

                                                                                                                                          \[\leadsto \frac{{x}^{\left(\mathsf{fma}\left(2, \frac{0.5}{n}, -1\right)\right)}}{n} \]
                                                                                                                                        2. Taylor expanded in n around inf

                                                                                                                                          \[\leadsto \frac{1}{\color{blue}{n \cdot x}} \]
                                                                                                                                        3. Step-by-step derivation
                                                                                                                                          1. Applied rewrites42.0%

                                                                                                                                            \[\leadsto \frac{\frac{1}{n}}{\color{blue}{x}} \]
                                                                                                                                        4. Recombined 2 regimes into one program.
                                                                                                                                        5. Add Preprocessing

                                                                                                                                        Alternative 20: 46.3% accurate, 6.8× speedup?

                                                                                                                                        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{1}{n} \leq -40000000:\\ \;\;\;\;1 - 1\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{n \cdot x}\\ \end{array} \end{array} \]
                                                                                                                                        (FPCore (x n)
                                                                                                                                         :precision binary64
                                                                                                                                         (if (<= (/ 1.0 n) -40000000.0) (- 1.0 1.0) (/ 1.0 (* n x))))
                                                                                                                                        double code(double x, double n) {
                                                                                                                                        	double tmp;
                                                                                                                                        	if ((1.0 / n) <= -40000000.0) {
                                                                                                                                        		tmp = 1.0 - 1.0;
                                                                                                                                        	} else {
                                                                                                                                        		tmp = 1.0 / (n * x);
                                                                                                                                        	}
                                                                                                                                        	return tmp;
                                                                                                                                        }
                                                                                                                                        
                                                                                                                                        real(8) function code(x, n)
                                                                                                                                            real(8), intent (in) :: x
                                                                                                                                            real(8), intent (in) :: n
                                                                                                                                            real(8) :: tmp
                                                                                                                                            if ((1.0d0 / n) <= (-40000000.0d0)) then
                                                                                                                                                tmp = 1.0d0 - 1.0d0
                                                                                                                                            else
                                                                                                                                                tmp = 1.0d0 / (n * x)
                                                                                                                                            end if
                                                                                                                                            code = tmp
                                                                                                                                        end function
                                                                                                                                        
                                                                                                                                        public static double code(double x, double n) {
                                                                                                                                        	double tmp;
                                                                                                                                        	if ((1.0 / n) <= -40000000.0) {
                                                                                                                                        		tmp = 1.0 - 1.0;
                                                                                                                                        	} else {
                                                                                                                                        		tmp = 1.0 / (n * x);
                                                                                                                                        	}
                                                                                                                                        	return tmp;
                                                                                                                                        }
                                                                                                                                        
                                                                                                                                        def code(x, n):
                                                                                                                                        	tmp = 0
                                                                                                                                        	if (1.0 / n) <= -40000000.0:
                                                                                                                                        		tmp = 1.0 - 1.0
                                                                                                                                        	else:
                                                                                                                                        		tmp = 1.0 / (n * x)
                                                                                                                                        	return tmp
                                                                                                                                        
                                                                                                                                        function code(x, n)
                                                                                                                                        	tmp = 0.0
                                                                                                                                        	if (Float64(1.0 / n) <= -40000000.0)
                                                                                                                                        		tmp = Float64(1.0 - 1.0);
                                                                                                                                        	else
                                                                                                                                        		tmp = Float64(1.0 / Float64(n * x));
                                                                                                                                        	end
                                                                                                                                        	return tmp
                                                                                                                                        end
                                                                                                                                        
                                                                                                                                        function tmp_2 = code(x, n)
                                                                                                                                        	tmp = 0.0;
                                                                                                                                        	if ((1.0 / n) <= -40000000.0)
                                                                                                                                        		tmp = 1.0 - 1.0;
                                                                                                                                        	else
                                                                                                                                        		tmp = 1.0 / (n * x);
                                                                                                                                        	end
                                                                                                                                        	tmp_2 = tmp;
                                                                                                                                        end
                                                                                                                                        
                                                                                                                                        code[x_, n_] := If[LessEqual[N[(1.0 / n), $MachinePrecision], -40000000.0], N[(1.0 - 1.0), $MachinePrecision], N[(1.0 / N[(n * x), $MachinePrecision]), $MachinePrecision]]
                                                                                                                                        
                                                                                                                                        \begin{array}{l}
                                                                                                                                        
                                                                                                                                        \\
                                                                                                                                        \begin{array}{l}
                                                                                                                                        \mathbf{if}\;\frac{1}{n} \leq -40000000:\\
                                                                                                                                        \;\;\;\;1 - 1\\
                                                                                                                                        
                                                                                                                                        \mathbf{else}:\\
                                                                                                                                        \;\;\;\;\frac{1}{n \cdot x}\\
                                                                                                                                        
                                                                                                                                        
                                                                                                                                        \end{array}
                                                                                                                                        \end{array}
                                                                                                                                        
                                                                                                                                        Derivation
                                                                                                                                        1. Split input into 2 regimes
                                                                                                                                        2. if (/.f64 #s(literal 1 binary64) n) < -4e7

                                                                                                                                          1. Initial program 100.0%

                                                                                                                                            \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                                                          2. Add Preprocessing
                                                                                                                                          3. Taylor expanded in x around 0

                                                                                                                                            \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                                                          4. Step-by-step derivation
                                                                                                                                            1. Applied rewrites44.6%

                                                                                                                                              \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                                                            2. Taylor expanded in n around inf

                                                                                                                                              \[\leadsto 1 - \color{blue}{1} \]
                                                                                                                                            3. Step-by-step derivation
                                                                                                                                              1. Applied rewrites57.8%

                                                                                                                                                \[\leadsto 1 - \color{blue}{1} \]

                                                                                                                                              if -4e7 < (/.f64 #s(literal 1 binary64) n)

                                                                                                                                              1. Initial program 30.9%

                                                                                                                                                \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                                                              2. Add Preprocessing
                                                                                                                                              3. Taylor expanded in n around inf

                                                                                                                                                \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                                                                                                              4. Step-by-step derivation
                                                                                                                                                1. lower-/.f64N/A

                                                                                                                                                  \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                                                                                                                2. lower--.f64N/A

                                                                                                                                                  \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                                                                                                                                                3. lower-log1p.f64N/A

                                                                                                                                                  \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                                                                                                                                                4. lower-log.f6464.9

                                                                                                                                                  \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                                                                                                                                              5. Applied rewrites64.9%

                                                                                                                                                \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                                                                                                                                              6. Step-by-step derivation
                                                                                                                                                1. Applied rewrites64.9%

                                                                                                                                                  \[\leadsto \frac{1}{\color{blue}{\frac{n}{\mathsf{log1p}\left(x\right) - \log x}}} \]
                                                                                                                                                2. Taylor expanded in x around inf

                                                                                                                                                  \[\leadsto \frac{1}{n \cdot \color{blue}{x}} \]
                                                                                                                                                3. Step-by-step derivation
                                                                                                                                                  1. Applied rewrites41.3%

                                                                                                                                                    \[\leadsto \frac{1}{n \cdot \color{blue}{x}} \]
                                                                                                                                                4. Recombined 2 regimes into one program.
                                                                                                                                                5. Add Preprocessing

                                                                                                                                                Alternative 21: 31.0% accurate, 57.8× speedup?

                                                                                                                                                \[\begin{array}{l} \\ 1 - 1 \end{array} \]
                                                                                                                                                (FPCore (x n) :precision binary64 (- 1.0 1.0))
                                                                                                                                                double code(double x, double n) {
                                                                                                                                                	return 1.0 - 1.0;
                                                                                                                                                }
                                                                                                                                                
                                                                                                                                                real(8) function code(x, n)
                                                                                                                                                    real(8), intent (in) :: x
                                                                                                                                                    real(8), intent (in) :: n
                                                                                                                                                    code = 1.0d0 - 1.0d0
                                                                                                                                                end function
                                                                                                                                                
                                                                                                                                                public static double code(double x, double n) {
                                                                                                                                                	return 1.0 - 1.0;
                                                                                                                                                }
                                                                                                                                                
                                                                                                                                                def code(x, n):
                                                                                                                                                	return 1.0 - 1.0
                                                                                                                                                
                                                                                                                                                function code(x, n)
                                                                                                                                                	return Float64(1.0 - 1.0)
                                                                                                                                                end
                                                                                                                                                
                                                                                                                                                function tmp = code(x, n)
                                                                                                                                                	tmp = 1.0 - 1.0;
                                                                                                                                                end
                                                                                                                                                
                                                                                                                                                code[x_, n_] := N[(1.0 - 1.0), $MachinePrecision]
                                                                                                                                                
                                                                                                                                                \begin{array}{l}
                                                                                                                                                
                                                                                                                                                \\
                                                                                                                                                1 - 1
                                                                                                                                                \end{array}
                                                                                                                                                
                                                                                                                                                Derivation
                                                                                                                                                1. Initial program 47.9%

                                                                                                                                                  \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                                                                2. Add Preprocessing
                                                                                                                                                3. Taylor expanded in x around 0

                                                                                                                                                  \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                                                                4. Step-by-step derivation
                                                                                                                                                  1. Applied rewrites33.4%

                                                                                                                                                    \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                                                                                  2. Taylor expanded in n around inf

                                                                                                                                                    \[\leadsto 1 - \color{blue}{1} \]
                                                                                                                                                  3. Step-by-step derivation
                                                                                                                                                    1. Applied rewrites29.5%

                                                                                                                                                      \[\leadsto 1 - \color{blue}{1} \]
                                                                                                                                                    2. Add Preprocessing

                                                                                                                                                    Reproduce

                                                                                                                                                    ?
                                                                                                                                                    herbie shell --seed 2024271 
                                                                                                                                                    (FPCore (x n)
                                                                                                                                                      :name "2nthrt (problem 3.4.6)"
                                                                                                                                                      :precision binary64
                                                                                                                                                      (- (pow (+ x 1.0) (/ 1.0 n)) (pow x (/ 1.0 n))))