Toniolo and Linder, Equation (3a)

Percentage Accurate: 98.4% → 100.0%
Time: 12.4s
Alternatives: 8
Speedup: 1.1×

Specification

?
\[\begin{array}{l} \\ \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \end{array} \]
(FPCore (l Om kx ky)
 :precision binary64
 (sqrt
  (*
   (/ 1.0 2.0)
   (+
    1.0
    (/
     1.0
     (sqrt
      (+
       1.0
       (*
        (pow (/ (* 2.0 l) Om) 2.0)
        (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0))))))))))
double code(double l, double Om, double kx, double ky) {
	return sqrt(((1.0 / 2.0) * (1.0 + (1.0 / sqrt((1.0 + (pow(((2.0 * l) / Om), 2.0) * (pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))))))));
}
real(8) function code(l, om, kx, ky)
    real(8), intent (in) :: l
    real(8), intent (in) :: om
    real(8), intent (in) :: kx
    real(8), intent (in) :: ky
    code = sqrt(((1.0d0 / 2.0d0) * (1.0d0 + (1.0d0 / sqrt((1.0d0 + ((((2.0d0 * l) / om) ** 2.0d0) * ((sin(kx) ** 2.0d0) + (sin(ky) ** 2.0d0)))))))))
end function
public static double code(double l, double Om, double kx, double ky) {
	return Math.sqrt(((1.0 / 2.0) * (1.0 + (1.0 / Math.sqrt((1.0 + (Math.pow(((2.0 * l) / Om), 2.0) * (Math.pow(Math.sin(kx), 2.0) + Math.pow(Math.sin(ky), 2.0)))))))));
}
def code(l, Om, kx, ky):
	return math.sqrt(((1.0 / 2.0) * (1.0 + (1.0 / math.sqrt((1.0 + (math.pow(((2.0 * l) / Om), 2.0) * (math.pow(math.sin(kx), 2.0) + math.pow(math.sin(ky), 2.0)))))))))
function code(l, Om, kx, ky)
	return sqrt(Float64(Float64(1.0 / 2.0) * Float64(1.0 + Float64(1.0 / sqrt(Float64(1.0 + Float64((Float64(Float64(2.0 * l) / Om) ^ 2.0) * Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))))))))
end
function tmp = code(l, Om, kx, ky)
	tmp = sqrt(((1.0 / 2.0) * (1.0 + (1.0 / sqrt((1.0 + ((((2.0 * l) / Om) ^ 2.0) * ((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))))))));
end
code[l_, Om_, kx_, ky_] := N[Sqrt[N[(N[(1.0 / 2.0), $MachinePrecision] * N[(1.0 + N[(1.0 / N[Sqrt[N[(1.0 + N[(N[Power[N[(N[(2.0 * l), $MachinePrecision] / Om), $MachinePrecision], 2.0], $MachinePrecision] * N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 8 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 98.4% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \end{array} \]
(FPCore (l Om kx ky)
 :precision binary64
 (sqrt
  (*
   (/ 1.0 2.0)
   (+
    1.0
    (/
     1.0
     (sqrt
      (+
       1.0
       (*
        (pow (/ (* 2.0 l) Om) 2.0)
        (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0))))))))))
double code(double l, double Om, double kx, double ky) {
	return sqrt(((1.0 / 2.0) * (1.0 + (1.0 / sqrt((1.0 + (pow(((2.0 * l) / Om), 2.0) * (pow(sin(kx), 2.0) + pow(sin(ky), 2.0)))))))));
}
real(8) function code(l, om, kx, ky)
    real(8), intent (in) :: l
    real(8), intent (in) :: om
    real(8), intent (in) :: kx
    real(8), intent (in) :: ky
    code = sqrt(((1.0d0 / 2.0d0) * (1.0d0 + (1.0d0 / sqrt((1.0d0 + ((((2.0d0 * l) / om) ** 2.0d0) * ((sin(kx) ** 2.0d0) + (sin(ky) ** 2.0d0)))))))))
end function
public static double code(double l, double Om, double kx, double ky) {
	return Math.sqrt(((1.0 / 2.0) * (1.0 + (1.0 / Math.sqrt((1.0 + (Math.pow(((2.0 * l) / Om), 2.0) * (Math.pow(Math.sin(kx), 2.0) + Math.pow(Math.sin(ky), 2.0)))))))));
}
def code(l, Om, kx, ky):
	return math.sqrt(((1.0 / 2.0) * (1.0 + (1.0 / math.sqrt((1.0 + (math.pow(((2.0 * l) / Om), 2.0) * (math.pow(math.sin(kx), 2.0) + math.pow(math.sin(ky), 2.0)))))))))
function code(l, Om, kx, ky)
	return sqrt(Float64(Float64(1.0 / 2.0) * Float64(1.0 + Float64(1.0 / sqrt(Float64(1.0 + Float64((Float64(Float64(2.0 * l) / Om) ^ 2.0) * Float64((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))))))))
end
function tmp = code(l, Om, kx, ky)
	tmp = sqrt(((1.0 / 2.0) * (1.0 + (1.0 / sqrt((1.0 + ((((2.0 * l) / Om) ^ 2.0) * ((sin(kx) ^ 2.0) + (sin(ky) ^ 2.0)))))))));
end
code[l_, Om_, kx_, ky_] := N[Sqrt[N[(N[(1.0 / 2.0), $MachinePrecision] * N[(1.0 + N[(1.0 / N[Sqrt[N[(1.0 + N[(N[Power[N[(N[(2.0 * l), $MachinePrecision] / Om), $MachinePrecision], 2.0], $MachinePrecision] * N[(N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)}
\end{array}

Alternative 1: 100.0% accurate, 1.1× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \left(\ell \cdot \sin ky\right) \cdot \frac{2}{Om}\\ \sqrt{\left(\frac{1}{\sqrt{\mathsf{fma}\left(t\_0, t\_0, {\left(\left(\sin kx \cdot \ell\right) \cdot \frac{2}{Om}\right)}^{2} + 1\right)}} + 1\right) \cdot \frac{1}{2}} \end{array} \end{array} \]
(FPCore (l Om kx ky)
 :precision binary64
 (let* ((t_0 (* (* l (sin ky)) (/ 2.0 Om))))
   (sqrt
    (*
     (+
      (/
       1.0
       (sqrt (fma t_0 t_0 (+ (pow (* (* (sin kx) l) (/ 2.0 Om)) 2.0) 1.0))))
      1.0)
     (/ 1.0 2.0)))))
double code(double l, double Om, double kx, double ky) {
	double t_0 = (l * sin(ky)) * (2.0 / Om);
	return sqrt((((1.0 / sqrt(fma(t_0, t_0, (pow(((sin(kx) * l) * (2.0 / Om)), 2.0) + 1.0)))) + 1.0) * (1.0 / 2.0)));
}
function code(l, Om, kx, ky)
	t_0 = Float64(Float64(l * sin(ky)) * Float64(2.0 / Om))
	return sqrt(Float64(Float64(Float64(1.0 / sqrt(fma(t_0, t_0, Float64((Float64(Float64(sin(kx) * l) * Float64(2.0 / Om)) ^ 2.0) + 1.0)))) + 1.0) * Float64(1.0 / 2.0)))
end
code[l_, Om_, kx_, ky_] := Block[{t$95$0 = N[(N[(l * N[Sin[ky], $MachinePrecision]), $MachinePrecision] * N[(2.0 / Om), $MachinePrecision]), $MachinePrecision]}, N[Sqrt[N[(N[(N[(1.0 / N[Sqrt[N[(t$95$0 * t$95$0 + N[(N[Power[N[(N[(N[Sin[kx], $MachinePrecision] * l), $MachinePrecision] * N[(2.0 / Om), $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision] * N[(1.0 / 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \left(\ell \cdot \sin ky\right) \cdot \frac{2}{Om}\\
\sqrt{\left(\frac{1}{\sqrt{\mathsf{fma}\left(t\_0, t\_0, {\left(\left(\sin kx \cdot \ell\right) \cdot \frac{2}{Om}\right)}^{2} + 1\right)}} + 1\right) \cdot \frac{1}{2}}
\end{array}
\end{array}
Derivation
  1. Initial program 99.2%

    \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
  2. Add Preprocessing
  3. Step-by-step derivation
    1. lift-+.f64N/A

      \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\color{blue}{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}}\right)} \]
    2. +-commutativeN/A

      \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\color{blue}{{\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right) + 1}}}\right)} \]
    3. lift-*.f64N/A

      \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\color{blue}{{\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)} + 1}}\right)} \]
    4. lift-+.f64N/A

      \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{{\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \color{blue}{\left({\sin kx}^{2} + {\sin ky}^{2}\right)} + 1}}\right)} \]
    5. +-commutativeN/A

      \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{{\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \color{blue}{\left({\sin ky}^{2} + {\sin kx}^{2}\right)} + 1}}\right)} \]
    6. distribute-lft-inN/A

      \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\color{blue}{\left({\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot {\sin ky}^{2} + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot {\sin kx}^{2}\right)} + 1}}\right)} \]
    7. *-commutativeN/A

      \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\left(\color{blue}{{\sin ky}^{2} \cdot {\left(\frac{2 \cdot \ell}{Om}\right)}^{2}} + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot {\sin kx}^{2}\right) + 1}}\right)} \]
    8. associate-+l+N/A

      \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\color{blue}{{\sin ky}^{2} \cdot {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} + \left({\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot {\sin kx}^{2} + 1\right)}}}\right)} \]
    9. lift-pow.f64N/A

      \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\color{blue}{{\sin ky}^{2}} \cdot {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} + \left({\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot {\sin kx}^{2} + 1\right)}}\right)} \]
    10. lift-pow.f64N/A

      \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{{\sin ky}^{2} \cdot \color{blue}{{\left(\frac{2 \cdot \ell}{Om}\right)}^{2}} + \left({\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot {\sin kx}^{2} + 1\right)}}\right)} \]
    11. pow-prod-downN/A

      \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\color{blue}{{\left(\sin ky \cdot \frac{2 \cdot \ell}{Om}\right)}^{2}} + \left({\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot {\sin kx}^{2} + 1\right)}}\right)} \]
    12. pow2N/A

      \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\color{blue}{\left(\sin ky \cdot \frac{2 \cdot \ell}{Om}\right) \cdot \left(\sin ky \cdot \frac{2 \cdot \ell}{Om}\right)} + \left({\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot {\sin kx}^{2} + 1\right)}}\right)} \]
  4. Applied rewrites100.0%

    \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{\color{blue}{\mathsf{fma}\left(\left(\sin ky \cdot \ell\right) \cdot \frac{2}{Om}, \left(\sin ky \cdot \ell\right) \cdot \frac{2}{Om}, {\left(\left(\sin kx \cdot \ell\right) \cdot \frac{2}{Om}\right)}^{2} + 1\right)}}}\right)} \]
  5. Final simplification100.0%

    \[\leadsto \sqrt{\left(\frac{1}{\sqrt{\mathsf{fma}\left(\left(\ell \cdot \sin ky\right) \cdot \frac{2}{Om}, \left(\ell \cdot \sin ky\right) \cdot \frac{2}{Om}, {\left(\left(\sin kx \cdot \ell\right) \cdot \frac{2}{Om}\right)}^{2} + 1\right)}} + 1\right) \cdot \frac{1}{2}} \]
  6. Add Preprocessing

Alternative 2: 88.3% accurate, 0.9× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{1}{\sqrt{\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} + 1}} \leq 0.9998:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(\sqrt{\frac{1}{\mathsf{fma}\left(\left(\frac{\ell}{Om} \cdot \ell\right) \cdot \left(\frac{\mathsf{fma}\left(\mathsf{fma}\left(0.044444444444444446, ky \cdot ky, -0.3333333333333333\right), ky \cdot ky, 1\right)}{Om} \cdot \left(ky \cdot ky\right)\right), 4, 1\right)}}, 0.5, 0.5\right)}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{1}\\ \end{array} \end{array} \]
(FPCore (l Om kx ky)
 :precision binary64
 (if (<=
      (/
       1.0
       (sqrt
        (+
         (*
          (+ (pow (sin ky) 2.0) (pow (sin kx) 2.0))
          (pow (/ (* l 2.0) Om) 2.0))
         1.0)))
      0.9998)
   (sqrt
    (fma
     (sqrt
      (/
       1.0
       (fma
        (*
         (* (/ l Om) l)
         (*
          (/
           (fma
            (fma 0.044444444444444446 (* ky ky) -0.3333333333333333)
            (* ky ky)
            1.0)
           Om)
          (* ky ky)))
        4.0
        1.0)))
     0.5
     0.5))
   (sqrt 1.0)))
double code(double l, double Om, double kx, double ky) {
	double tmp;
	if ((1.0 / sqrt((((pow(sin(ky), 2.0) + pow(sin(kx), 2.0)) * pow(((l * 2.0) / Om), 2.0)) + 1.0))) <= 0.9998) {
		tmp = sqrt(fma(sqrt((1.0 / fma((((l / Om) * l) * ((fma(fma(0.044444444444444446, (ky * ky), -0.3333333333333333), (ky * ky), 1.0) / Om) * (ky * ky))), 4.0, 1.0))), 0.5, 0.5));
	} else {
		tmp = sqrt(1.0);
	}
	return tmp;
}
function code(l, Om, kx, ky)
	tmp = 0.0
	if (Float64(1.0 / sqrt(Float64(Float64(Float64((sin(ky) ^ 2.0) + (sin(kx) ^ 2.0)) * (Float64(Float64(l * 2.0) / Om) ^ 2.0)) + 1.0))) <= 0.9998)
		tmp = sqrt(fma(sqrt(Float64(1.0 / fma(Float64(Float64(Float64(l / Om) * l) * Float64(Float64(fma(fma(0.044444444444444446, Float64(ky * ky), -0.3333333333333333), Float64(ky * ky), 1.0) / Om) * Float64(ky * ky))), 4.0, 1.0))), 0.5, 0.5));
	else
		tmp = sqrt(1.0);
	end
	return tmp
end
code[l_, Om_, kx_, ky_] := If[LessEqual[N[(1.0 / N[Sqrt[N[(N[(N[(N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision] * N[Power[N[(N[(l * 2.0), $MachinePrecision] / Om), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 0.9998], N[Sqrt[N[(N[Sqrt[N[(1.0 / N[(N[(N[(N[(l / Om), $MachinePrecision] * l), $MachinePrecision] * N[(N[(N[(N[(0.044444444444444446 * N[(ky * ky), $MachinePrecision] + -0.3333333333333333), $MachinePrecision] * N[(ky * ky), $MachinePrecision] + 1.0), $MachinePrecision] / Om), $MachinePrecision] * N[(ky * ky), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * 4.0 + 1.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * 0.5 + 0.5), $MachinePrecision]], $MachinePrecision], N[Sqrt[1.0], $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;\frac{1}{\sqrt{\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} + 1}} \leq 0.9998:\\
\;\;\;\;\sqrt{\mathsf{fma}\left(\sqrt{\frac{1}{\mathsf{fma}\left(\left(\frac{\ell}{Om} \cdot \ell\right) \cdot \left(\frac{\mathsf{fma}\left(\mathsf{fma}\left(0.044444444444444446, ky \cdot ky, -0.3333333333333333\right), ky \cdot ky, 1\right)}{Om} \cdot \left(ky \cdot ky\right)\right), 4, 1\right)}}, 0.5, 0.5\right)}\\

\mathbf{else}:\\
\;\;\;\;\sqrt{1}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (/.f64 #s(literal 1 binary64) (sqrt.f64 (+.f64 #s(literal 1 binary64) (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))))) < 0.99980000000000002

    1. Initial program 100.0%

      \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in kx around 0

      \[\leadsto \sqrt{\color{blue}{\frac{1}{2} \cdot \left(1 + \sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}}\right)}} \]
    4. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto \sqrt{\frac{1}{2} \cdot \color{blue}{\left(\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} + 1\right)}} \]
      2. distribute-rgt-inN/A

        \[\leadsto \sqrt{\color{blue}{\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} \cdot \frac{1}{2} + 1 \cdot \frac{1}{2}}} \]
      3. metadata-evalN/A

        \[\leadsto \sqrt{\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} \cdot \frac{1}{2} + \color{blue}{\frac{1}{2}}} \]
      4. lower-fma.f64N/A

        \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}}, \frac{1}{2}, \frac{1}{2}\right)}} \]
    5. Applied rewrites70.8%

      \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\sqrt{\frac{1}{\mathsf{fma}\left(\frac{{\sin ky}^{2}}{Om} \cdot \frac{\ell \cdot \ell}{Om}, 4, 1\right)}}, 0.5, 0.5\right)}} \]
    6. Step-by-step derivation
      1. Applied rewrites74.4%

        \[\leadsto \sqrt{\mathsf{fma}\left(\sqrt{\frac{1}{\mathsf{fma}\left(\frac{{\sin ky}^{2}}{Om} \cdot \left(\frac{\ell}{Om} \cdot \ell\right), 4, 1\right)}}, 0.5, 0.5\right)} \]
      2. Taylor expanded in ky around 0

        \[\leadsto \sqrt{\mathsf{fma}\left(\sqrt{\frac{1}{\mathsf{fma}\left(\left({ky}^{2} \cdot \left({ky}^{2} \cdot \left(\frac{2}{45} \cdot \frac{{ky}^{2}}{Om} - \frac{1}{3} \cdot \frac{1}{Om}\right) + \frac{1}{Om}\right)\right) \cdot \left(\frac{\ell}{Om} \cdot \ell\right), 4, 1\right)}}, \frac{1}{2}, \frac{1}{2}\right)} \]
      3. Step-by-step derivation
        1. Applied rewrites73.8%

          \[\leadsto \sqrt{\mathsf{fma}\left(\sqrt{\frac{1}{\mathsf{fma}\left(\left(\mathsf{fma}\left(\mathsf{fma}\left(0.044444444444444446, \frac{ky \cdot ky}{Om}, \frac{-0.3333333333333333}{Om}\right), ky \cdot ky, \frac{1}{Om}\right) \cdot \left(ky \cdot ky\right)\right) \cdot \left(\frac{\ell}{Om} \cdot \ell\right), 4, 1\right)}}, 0.5, 0.5\right)} \]
        2. Taylor expanded in Om around 0

          \[\leadsto \sqrt{\mathsf{fma}\left(\sqrt{\frac{1}{\mathsf{fma}\left(\left(\frac{1 + {ky}^{2} \cdot \left(\frac{2}{45} \cdot {ky}^{2} - \frac{1}{3}\right)}{Om} \cdot \left(ky \cdot ky\right)\right) \cdot \left(\frac{\ell}{Om} \cdot \ell\right), 4, 1\right)}}, \frac{1}{2}, \frac{1}{2}\right)} \]
        3. Step-by-step derivation
          1. Applied rewrites73.8%

            \[\leadsto \sqrt{\mathsf{fma}\left(\sqrt{\frac{1}{\mathsf{fma}\left(\left(\frac{\mathsf{fma}\left(\mathsf{fma}\left(0.044444444444444446, ky \cdot ky, -0.3333333333333333\right), ky \cdot ky, 1\right)}{Om} \cdot \left(ky \cdot ky\right)\right) \cdot \left(\frac{\ell}{Om} \cdot \ell\right), 4, 1\right)}}, 0.5, 0.5\right)} \]

          if 0.99980000000000002 < (/.f64 #s(literal 1 binary64) (sqrt.f64 (+.f64 #s(literal 1 binary64) (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))))

          1. Initial program 98.6%

            \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
          2. Add Preprocessing
          3. Taylor expanded in Om around inf

            \[\leadsto \sqrt{\color{blue}{1}} \]
          4. Step-by-step derivation
            1. Applied rewrites99.2%

              \[\leadsto \sqrt{\color{blue}{1}} \]
          5. Recombined 2 regimes into one program.
          6. Final simplification88.0%

            \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{1}{\sqrt{\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} + 1}} \leq 0.9998:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(\sqrt{\frac{1}{\mathsf{fma}\left(\left(\frac{\ell}{Om} \cdot \ell\right) \cdot \left(\frac{\mathsf{fma}\left(\mathsf{fma}\left(0.044444444444444446, ky \cdot ky, -0.3333333333333333\right), ky \cdot ky, 1\right)}{Om} \cdot \left(ky \cdot ky\right)\right), 4, 1\right)}}, 0.5, 0.5\right)}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{1}\\ \end{array} \]
          7. Add Preprocessing

          Alternative 3: 88.3% accurate, 0.9× speedup?

          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{1}{\sqrt{\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} + 1}} \leq 0.9998:\\ \;\;\;\;\sqrt{\frac{0.5}{\sqrt{\mathsf{fma}\left(\left(\frac{\ell}{Om} \cdot \ell\right) \cdot 4, \frac{ky \cdot ky}{Om}, 1\right)}} + 0.5}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{1}\\ \end{array} \end{array} \]
          (FPCore (l Om kx ky)
           :precision binary64
           (if (<=
                (/
                 1.0
                 (sqrt
                  (+
                   (*
                    (+ (pow (sin ky) 2.0) (pow (sin kx) 2.0))
                    (pow (/ (* l 2.0) Om) 2.0))
                   1.0)))
                0.9998)
             (sqrt
              (+ (/ 0.5 (sqrt (fma (* (* (/ l Om) l) 4.0) (/ (* ky ky) Om) 1.0))) 0.5))
             (sqrt 1.0)))
          double code(double l, double Om, double kx, double ky) {
          	double tmp;
          	if ((1.0 / sqrt((((pow(sin(ky), 2.0) + pow(sin(kx), 2.0)) * pow(((l * 2.0) / Om), 2.0)) + 1.0))) <= 0.9998) {
          		tmp = sqrt(((0.5 / sqrt(fma((((l / Om) * l) * 4.0), ((ky * ky) / Om), 1.0))) + 0.5));
          	} else {
          		tmp = sqrt(1.0);
          	}
          	return tmp;
          }
          
          function code(l, Om, kx, ky)
          	tmp = 0.0
          	if (Float64(1.0 / sqrt(Float64(Float64(Float64((sin(ky) ^ 2.0) + (sin(kx) ^ 2.0)) * (Float64(Float64(l * 2.0) / Om) ^ 2.0)) + 1.0))) <= 0.9998)
          		tmp = sqrt(Float64(Float64(0.5 / sqrt(fma(Float64(Float64(Float64(l / Om) * l) * 4.0), Float64(Float64(ky * ky) / Om), 1.0))) + 0.5));
          	else
          		tmp = sqrt(1.0);
          	end
          	return tmp
          end
          
          code[l_, Om_, kx_, ky_] := If[LessEqual[N[(1.0 / N[Sqrt[N[(N[(N[(N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision] * N[Power[N[(N[(l * 2.0), $MachinePrecision] / Om), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 0.9998], N[Sqrt[N[(N[(0.5 / N[Sqrt[N[(N[(N[(N[(l / Om), $MachinePrecision] * l), $MachinePrecision] * 4.0), $MachinePrecision] * N[(N[(ky * ky), $MachinePrecision] / Om), $MachinePrecision] + 1.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] + 0.5), $MachinePrecision]], $MachinePrecision], N[Sqrt[1.0], $MachinePrecision]]
          
          \begin{array}{l}
          
          \\
          \begin{array}{l}
          \mathbf{if}\;\frac{1}{\sqrt{\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} + 1}} \leq 0.9998:\\
          \;\;\;\;\sqrt{\frac{0.5}{\sqrt{\mathsf{fma}\left(\left(\frac{\ell}{Om} \cdot \ell\right) \cdot 4, \frac{ky \cdot ky}{Om}, 1\right)}} + 0.5}\\
          
          \mathbf{else}:\\
          \;\;\;\;\sqrt{1}\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if (/.f64 #s(literal 1 binary64) (sqrt.f64 (+.f64 #s(literal 1 binary64) (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))))) < 0.99980000000000002

            1. Initial program 100.0%

              \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
            2. Add Preprocessing
            3. Taylor expanded in kx around 0

              \[\leadsto \sqrt{\color{blue}{\frac{1}{2} \cdot \left(1 + \sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}}\right)}} \]
            4. Step-by-step derivation
              1. +-commutativeN/A

                \[\leadsto \sqrt{\frac{1}{2} \cdot \color{blue}{\left(\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} + 1\right)}} \]
              2. distribute-rgt-inN/A

                \[\leadsto \sqrt{\color{blue}{\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} \cdot \frac{1}{2} + 1 \cdot \frac{1}{2}}} \]
              3. metadata-evalN/A

                \[\leadsto \sqrt{\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} \cdot \frac{1}{2} + \color{blue}{\frac{1}{2}}} \]
              4. lower-fma.f64N/A

                \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}}, \frac{1}{2}, \frac{1}{2}\right)}} \]
            5. Applied rewrites70.8%

              \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\sqrt{\frac{1}{\mathsf{fma}\left(\frac{{\sin ky}^{2}}{Om} \cdot \frac{\ell \cdot \ell}{Om}, 4, 1\right)}}, 0.5, 0.5\right)}} \]
            6. Taylor expanded in ky around 0

              \[\leadsto \sqrt{\mathsf{fma}\left(\sqrt{\frac{1}{\mathsf{fma}\left(\frac{{ky}^{2}}{Om} \cdot \frac{\ell \cdot \ell}{Om}, 4, 1\right)}}, \frac{1}{2}, \frac{1}{2}\right)} \]
            7. Step-by-step derivation
              1. Applied rewrites70.2%

                \[\leadsto \sqrt{\mathsf{fma}\left(\sqrt{\frac{1}{\mathsf{fma}\left(\frac{ky \cdot ky}{Om} \cdot \frac{\ell \cdot \ell}{Om}, 4, 1\right)}}, 0.5, 0.5\right)} \]
              2. Step-by-step derivation
                1. Applied rewrites73.4%

                  \[\leadsto \sqrt{\frac{0.5}{\sqrt{\mathsf{fma}\left(\left(\frac{\ell}{Om} \cdot \ell\right) \cdot 4, \frac{ky \cdot ky}{Om}, 1\right)}} + \color{blue}{0.5}} \]

                if 0.99980000000000002 < (/.f64 #s(literal 1 binary64) (sqrt.f64 (+.f64 #s(literal 1 binary64) (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))))

                1. Initial program 98.6%

                  \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
                2. Add Preprocessing
                3. Taylor expanded in Om around inf

                  \[\leadsto \sqrt{\color{blue}{1}} \]
                4. Step-by-step derivation
                  1. Applied rewrites99.2%

                    \[\leadsto \sqrt{\color{blue}{1}} \]
                5. Recombined 2 regimes into one program.
                6. Final simplification87.8%

                  \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{1}{\sqrt{\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} + 1}} \leq 0.9998:\\ \;\;\;\;\sqrt{\frac{0.5}{\sqrt{\mathsf{fma}\left(\left(\frac{\ell}{Om} \cdot \ell\right) \cdot 4, \frac{ky \cdot ky}{Om}, 1\right)}} + 0.5}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{1}\\ \end{array} \]
                7. Add Preprocessing

                Alternative 4: 91.4% accurate, 1.0× speedup?

                \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{1}{\sqrt{\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} + 1}} \leq 0.5:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(\frac{Om}{\ell \cdot ky}, 0.25, 0.5\right)}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{1}\\ \end{array} \end{array} \]
                (FPCore (l Om kx ky)
                 :precision binary64
                 (if (<=
                      (/
                       1.0
                       (sqrt
                        (+
                         (*
                          (+ (pow (sin ky) 2.0) (pow (sin kx) 2.0))
                          (pow (/ (* l 2.0) Om) 2.0))
                         1.0)))
                      0.5)
                   (sqrt (fma (/ Om (* l ky)) 0.25 0.5))
                   (sqrt 1.0)))
                double code(double l, double Om, double kx, double ky) {
                	double tmp;
                	if ((1.0 / sqrt((((pow(sin(ky), 2.0) + pow(sin(kx), 2.0)) * pow(((l * 2.0) / Om), 2.0)) + 1.0))) <= 0.5) {
                		tmp = sqrt(fma((Om / (l * ky)), 0.25, 0.5));
                	} else {
                		tmp = sqrt(1.0);
                	}
                	return tmp;
                }
                
                function code(l, Om, kx, ky)
                	tmp = 0.0
                	if (Float64(1.0 / sqrt(Float64(Float64(Float64((sin(ky) ^ 2.0) + (sin(kx) ^ 2.0)) * (Float64(Float64(l * 2.0) / Om) ^ 2.0)) + 1.0))) <= 0.5)
                		tmp = sqrt(fma(Float64(Om / Float64(l * ky)), 0.25, 0.5));
                	else
                		tmp = sqrt(1.0);
                	end
                	return tmp
                end
                
                code[l_, Om_, kx_, ky_] := If[LessEqual[N[(1.0 / N[Sqrt[N[(N[(N[(N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision] * N[Power[N[(N[(l * 2.0), $MachinePrecision] / Om), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 0.5], N[Sqrt[N[(N[(Om / N[(l * ky), $MachinePrecision]), $MachinePrecision] * 0.25 + 0.5), $MachinePrecision]], $MachinePrecision], N[Sqrt[1.0], $MachinePrecision]]
                
                \begin{array}{l}
                
                \\
                \begin{array}{l}
                \mathbf{if}\;\frac{1}{\sqrt{\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} + 1}} \leq 0.5:\\
                \;\;\;\;\sqrt{\mathsf{fma}\left(\frac{Om}{\ell \cdot ky}, 0.25, 0.5\right)}\\
                
                \mathbf{else}:\\
                \;\;\;\;\sqrt{1}\\
                
                
                \end{array}
                \end{array}
                
                Derivation
                1. Split input into 2 regimes
                2. if (/.f64 #s(literal 1 binary64) (sqrt.f64 (+.f64 #s(literal 1 binary64) (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))))) < 0.5

                  1. Initial program 100.0%

                    \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
                  2. Add Preprocessing
                  3. Taylor expanded in kx around 0

                    \[\leadsto \sqrt{\color{blue}{\frac{1}{2} \cdot \left(1 + \sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}}\right)}} \]
                  4. Step-by-step derivation
                    1. +-commutativeN/A

                      \[\leadsto \sqrt{\frac{1}{2} \cdot \color{blue}{\left(\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} + 1\right)}} \]
                    2. distribute-rgt-inN/A

                      \[\leadsto \sqrt{\color{blue}{\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} \cdot \frac{1}{2} + 1 \cdot \frac{1}{2}}} \]
                    3. metadata-evalN/A

                      \[\leadsto \sqrt{\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} \cdot \frac{1}{2} + \color{blue}{\frac{1}{2}}} \]
                    4. lower-fma.f64N/A

                      \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}}, \frac{1}{2}, \frac{1}{2}\right)}} \]
                  5. Applied rewrites71.2%

                    \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\sqrt{\frac{1}{\mathsf{fma}\left(\frac{{\sin ky}^{2}}{Om} \cdot \frac{\ell \cdot \ell}{Om}, 4, 1\right)}}, 0.5, 0.5\right)}} \]
                  6. Taylor expanded in Om around 0

                    \[\leadsto \sqrt{\frac{1}{2} + \color{blue}{\frac{1}{4} \cdot \frac{Om}{\ell \cdot \sin ky}}} \]
                  7. Step-by-step derivation
                    1. Applied rewrites80.4%

                      \[\leadsto \sqrt{\mathsf{fma}\left(\frac{Om}{\sin ky \cdot \ell}, \color{blue}{0.25}, 0.5\right)} \]
                    2. Taylor expanded in ky around 0

                      \[\leadsto \sqrt{\mathsf{fma}\left(\frac{Om}{ky \cdot \ell}, \frac{1}{4}, \frac{1}{2}\right)} \]
                    3. Step-by-step derivation
                      1. Applied rewrites80.4%

                        \[\leadsto \sqrt{\mathsf{fma}\left(\frac{Om}{ky \cdot \ell}, 0.25, 0.5\right)} \]

                      if 0.5 < (/.f64 #s(literal 1 binary64) (sqrt.f64 (+.f64 #s(literal 1 binary64) (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))))

                      1. Initial program 98.6%

                        \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
                      2. Add Preprocessing
                      3. Taylor expanded in Om around inf

                        \[\leadsto \sqrt{\color{blue}{1}} \]
                      4. Step-by-step derivation
                        1. Applied rewrites98.8%

                          \[\leadsto \sqrt{\color{blue}{1}} \]
                      5. Recombined 2 regimes into one program.
                      6. Final simplification90.8%

                        \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{1}{\sqrt{\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} + 1}} \leq 0.5:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(\frac{Om}{\ell \cdot ky}, 0.25, 0.5\right)}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{1}\\ \end{array} \]
                      7. Add Preprocessing

                      Alternative 5: 97.5% accurate, 1.0× speedup?

                      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{1}{\sqrt{\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} + 1}} \leq 0.46:\\ \;\;\;\;\sqrt{0.5}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{1}\\ \end{array} \end{array} \]
                      (FPCore (l Om kx ky)
                       :precision binary64
                       (if (<=
                            (/
                             1.0
                             (sqrt
                              (+
                               (*
                                (+ (pow (sin ky) 2.0) (pow (sin kx) 2.0))
                                (pow (/ (* l 2.0) Om) 2.0))
                               1.0)))
                            0.46)
                         (sqrt 0.5)
                         (sqrt 1.0)))
                      double code(double l, double Om, double kx, double ky) {
                      	double tmp;
                      	if ((1.0 / sqrt((((pow(sin(ky), 2.0) + pow(sin(kx), 2.0)) * pow(((l * 2.0) / Om), 2.0)) + 1.0))) <= 0.46) {
                      		tmp = sqrt(0.5);
                      	} else {
                      		tmp = sqrt(1.0);
                      	}
                      	return tmp;
                      }
                      
                      real(8) function code(l, om, kx, ky)
                          real(8), intent (in) :: l
                          real(8), intent (in) :: om
                          real(8), intent (in) :: kx
                          real(8), intent (in) :: ky
                          real(8) :: tmp
                          if ((1.0d0 / sqrt(((((sin(ky) ** 2.0d0) + (sin(kx) ** 2.0d0)) * (((l * 2.0d0) / om) ** 2.0d0)) + 1.0d0))) <= 0.46d0) then
                              tmp = sqrt(0.5d0)
                          else
                              tmp = sqrt(1.0d0)
                          end if
                          code = tmp
                      end function
                      
                      public static double code(double l, double Om, double kx, double ky) {
                      	double tmp;
                      	if ((1.0 / Math.sqrt((((Math.pow(Math.sin(ky), 2.0) + Math.pow(Math.sin(kx), 2.0)) * Math.pow(((l * 2.0) / Om), 2.0)) + 1.0))) <= 0.46) {
                      		tmp = Math.sqrt(0.5);
                      	} else {
                      		tmp = Math.sqrt(1.0);
                      	}
                      	return tmp;
                      }
                      
                      def code(l, Om, kx, ky):
                      	tmp = 0
                      	if (1.0 / math.sqrt((((math.pow(math.sin(ky), 2.0) + math.pow(math.sin(kx), 2.0)) * math.pow(((l * 2.0) / Om), 2.0)) + 1.0))) <= 0.46:
                      		tmp = math.sqrt(0.5)
                      	else:
                      		tmp = math.sqrt(1.0)
                      	return tmp
                      
                      function code(l, Om, kx, ky)
                      	tmp = 0.0
                      	if (Float64(1.0 / sqrt(Float64(Float64(Float64((sin(ky) ^ 2.0) + (sin(kx) ^ 2.0)) * (Float64(Float64(l * 2.0) / Om) ^ 2.0)) + 1.0))) <= 0.46)
                      		tmp = sqrt(0.5);
                      	else
                      		tmp = sqrt(1.0);
                      	end
                      	return tmp
                      end
                      
                      function tmp_2 = code(l, Om, kx, ky)
                      	tmp = 0.0;
                      	if ((1.0 / sqrt(((((sin(ky) ^ 2.0) + (sin(kx) ^ 2.0)) * (((l * 2.0) / Om) ^ 2.0)) + 1.0))) <= 0.46)
                      		tmp = sqrt(0.5);
                      	else
                      		tmp = sqrt(1.0);
                      	end
                      	tmp_2 = tmp;
                      end
                      
                      code[l_, Om_, kx_, ky_] := If[LessEqual[N[(1.0 / N[Sqrt[N[(N[(N[(N[Power[N[Sin[ky], $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[Sin[kx], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision] * N[Power[N[(N[(l * 2.0), $MachinePrecision] / Om), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 0.46], N[Sqrt[0.5], $MachinePrecision], N[Sqrt[1.0], $MachinePrecision]]
                      
                      \begin{array}{l}
                      
                      \\
                      \begin{array}{l}
                      \mathbf{if}\;\frac{1}{\sqrt{\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} + 1}} \leq 0.46:\\
                      \;\;\;\;\sqrt{0.5}\\
                      
                      \mathbf{else}:\\
                      \;\;\;\;\sqrt{1}\\
                      
                      
                      \end{array}
                      \end{array}
                      
                      Derivation
                      1. Split input into 2 regimes
                      2. if (/.f64 #s(literal 1 binary64) (sqrt.f64 (+.f64 #s(literal 1 binary64) (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64))))))) < 0.46000000000000002

                        1. Initial program 100.0%

                          \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
                        2. Add Preprocessing
                        3. Taylor expanded in Om around 0

                          \[\leadsto \sqrt{\color{blue}{\frac{1}{2}}} \]
                        4. Step-by-step derivation
                          1. Applied rewrites97.7%

                            \[\leadsto \sqrt{\color{blue}{0.5}} \]

                          if 0.46000000000000002 < (/.f64 #s(literal 1 binary64) (sqrt.f64 (+.f64 #s(literal 1 binary64) (*.f64 (pow.f64 (/.f64 (*.f64 #s(literal 2 binary64) l) Om) #s(literal 2 binary64)) (+.f64 (pow.f64 (sin.f64 kx) #s(literal 2 binary64)) (pow.f64 (sin.f64 ky) #s(literal 2 binary64)))))))

                          1. Initial program 98.6%

                            \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
                          2. Add Preprocessing
                          3. Taylor expanded in Om around inf

                            \[\leadsto \sqrt{\color{blue}{1}} \]
                          4. Step-by-step derivation
                            1. Applied rewrites98.8%

                              \[\leadsto \sqrt{\color{blue}{1}} \]
                          5. Recombined 2 regimes into one program.
                          6. Final simplification98.3%

                            \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{1}{\sqrt{\left({\sin ky}^{2} + {\sin kx}^{2}\right) \cdot {\left(\frac{\ell \cdot 2}{Om}\right)}^{2} + 1}} \leq 0.46:\\ \;\;\;\;\sqrt{0.5}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{1}\\ \end{array} \]
                          7. Add Preprocessing

                          Alternative 6: 93.9% accurate, 1.3× speedup?

                          \[\begin{array}{l} \\ \sqrt{\mathsf{fma}\left(e^{-0.5 \cdot \mathsf{log1p}\left(\frac{4}{{\left(\frac{Om}{\ell \cdot \sin ky}\right)}^{2}}\right)}, 0.5, 0.5\right)} \end{array} \]
                          (FPCore (l Om kx ky)
                           :precision binary64
                           (sqrt
                            (fma
                             (exp (* -0.5 (log1p (/ 4.0 (pow (/ Om (* l (sin ky))) 2.0)))))
                             0.5
                             0.5)))
                          double code(double l, double Om, double kx, double ky) {
                          	return sqrt(fma(exp((-0.5 * log1p((4.0 / pow((Om / (l * sin(ky))), 2.0))))), 0.5, 0.5));
                          }
                          
                          function code(l, Om, kx, ky)
                          	return sqrt(fma(exp(Float64(-0.5 * log1p(Float64(4.0 / (Float64(Om / Float64(l * sin(ky))) ^ 2.0))))), 0.5, 0.5))
                          end
                          
                          code[l_, Om_, kx_, ky_] := N[Sqrt[N[(N[Exp[N[(-0.5 * N[Log[1 + N[(4.0 / N[Power[N[(Om / N[(l * N[Sin[ky], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * 0.5 + 0.5), $MachinePrecision]], $MachinePrecision]
                          
                          \begin{array}{l}
                          
                          \\
                          \sqrt{\mathsf{fma}\left(e^{-0.5 \cdot \mathsf{log1p}\left(\frac{4}{{\left(\frac{Om}{\ell \cdot \sin ky}\right)}^{2}}\right)}, 0.5, 0.5\right)}
                          \end{array}
                          
                          Derivation
                          1. Initial program 99.2%

                            \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
                          2. Add Preprocessing
                          3. Taylor expanded in kx around 0

                            \[\leadsto \sqrt{\color{blue}{\frac{1}{2} \cdot \left(1 + \sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}}\right)}} \]
                          4. Step-by-step derivation
                            1. +-commutativeN/A

                              \[\leadsto \sqrt{\frac{1}{2} \cdot \color{blue}{\left(\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} + 1\right)}} \]
                            2. distribute-rgt-inN/A

                              \[\leadsto \sqrt{\color{blue}{\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} \cdot \frac{1}{2} + 1 \cdot \frac{1}{2}}} \]
                            3. metadata-evalN/A

                              \[\leadsto \sqrt{\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} \cdot \frac{1}{2} + \color{blue}{\frac{1}{2}}} \]
                            4. lower-fma.f64N/A

                              \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}}, \frac{1}{2}, \frac{1}{2}\right)}} \]
                          5. Applied rewrites81.3%

                            \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\sqrt{\frac{1}{\mathsf{fma}\left(\frac{{\sin ky}^{2}}{Om} \cdot \frac{\ell \cdot \ell}{Om}, 4, 1\right)}}, 0.5, 0.5\right)}} \]
                          6. Step-by-step derivation
                            1. Applied rewrites80.2%

                              \[\leadsto \sqrt{\mathsf{fma}\left(\sqrt{\frac{1}{\mathsf{fma}\left(\frac{{\left(\ell \cdot \sin ky\right)}^{2}}{Om \cdot Om}, 4, 1\right)}}, 0.5, 0.5\right)} \]
                            2. Applied rewrites93.0%

                              \[\leadsto \sqrt{\mathsf{fma}\left(e^{\mathsf{log1p}\left(\frac{4}{{\left(\frac{Om}{\ell \cdot \sin ky}\right)}^{2}}\right) \cdot -0.5}, 0.5, 0.5\right)} \]
                            3. Final simplification93.0%

                              \[\leadsto \sqrt{\mathsf{fma}\left(e^{-0.5 \cdot \mathsf{log1p}\left(\frac{4}{{\left(\frac{Om}{\ell \cdot \sin ky}\right)}^{2}}\right)}, 0.5, 0.5\right)} \]
                            4. Add Preprocessing

                            Alternative 7: 93.9% accurate, 2.3× speedup?

                            \[\begin{array}{l} \\ \sqrt{\frac{0.5}{\sqrt{\mathsf{fma}\left(4, {\left(\frac{\ell \cdot \sin ky}{Om}\right)}^{2}, 1\right)}} + 0.5} \end{array} \]
                            (FPCore (l Om kx ky)
                             :precision binary64
                             (sqrt (+ (/ 0.5 (sqrt (fma 4.0 (pow (/ (* l (sin ky)) Om) 2.0) 1.0))) 0.5)))
                            double code(double l, double Om, double kx, double ky) {
                            	return sqrt(((0.5 / sqrt(fma(4.0, pow(((l * sin(ky)) / Om), 2.0), 1.0))) + 0.5));
                            }
                            
                            function code(l, Om, kx, ky)
                            	return sqrt(Float64(Float64(0.5 / sqrt(fma(4.0, (Float64(Float64(l * sin(ky)) / Om) ^ 2.0), 1.0))) + 0.5))
                            end
                            
                            code[l_, Om_, kx_, ky_] := N[Sqrt[N[(N[(0.5 / N[Sqrt[N[(4.0 * N[Power[N[(N[(l * N[Sin[ky], $MachinePrecision]), $MachinePrecision] / Om), $MachinePrecision], 2.0], $MachinePrecision] + 1.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] + 0.5), $MachinePrecision]], $MachinePrecision]
                            
                            \begin{array}{l}
                            
                            \\
                            \sqrt{\frac{0.5}{\sqrt{\mathsf{fma}\left(4, {\left(\frac{\ell \cdot \sin ky}{Om}\right)}^{2}, 1\right)}} + 0.5}
                            \end{array}
                            
                            Derivation
                            1. Initial program 99.2%

                              \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
                            2. Add Preprocessing
                            3. Taylor expanded in kx around 0

                              \[\leadsto \sqrt{\color{blue}{\frac{1}{2} \cdot \left(1 + \sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}}\right)}} \]
                            4. Step-by-step derivation
                              1. +-commutativeN/A

                                \[\leadsto \sqrt{\frac{1}{2} \cdot \color{blue}{\left(\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} + 1\right)}} \]
                              2. distribute-rgt-inN/A

                                \[\leadsto \sqrt{\color{blue}{\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} \cdot \frac{1}{2} + 1 \cdot \frac{1}{2}}} \]
                              3. metadata-evalN/A

                                \[\leadsto \sqrt{\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}} \cdot \frac{1}{2} + \color{blue}{\frac{1}{2}}} \]
                              4. lower-fma.f64N/A

                                \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\sqrt{\frac{1}{1 + 4 \cdot \frac{{\ell}^{2} \cdot {\sin ky}^{2}}{{Om}^{2}}}}, \frac{1}{2}, \frac{1}{2}\right)}} \]
                            5. Applied rewrites81.3%

                              \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\sqrt{\frac{1}{\mathsf{fma}\left(\frac{{\sin ky}^{2}}{Om} \cdot \frac{\ell \cdot \ell}{Om}, 4, 1\right)}}, 0.5, 0.5\right)}} \]
                            6. Step-by-step derivation
                              1. Applied rewrites87.1%

                                \[\leadsto \sqrt{\mathsf{fma}\left(\sqrt{\frac{1}{\mathsf{fma}\left(\frac{{\sin ky}^{2}}{Om} \cdot \left(\frac{\ell}{Om} \cdot \ell\right), 4, 1\right)}}, 0.5, 0.5\right)} \]
                              2. Applied rewrites93.0%

                                \[\leadsto \sqrt{\frac{0.5}{\sqrt{\mathsf{fma}\left(4, {\left(\frac{\ell \cdot \sin ky}{Om}\right)}^{2}, 1\right)}} + \color{blue}{0.5}} \]
                              3. Add Preprocessing

                              Alternative 8: 55.8% accurate, 52.8× speedup?

                              \[\begin{array}{l} \\ \sqrt{0.5} \end{array} \]
                              (FPCore (l Om kx ky) :precision binary64 (sqrt 0.5))
                              double code(double l, double Om, double kx, double ky) {
                              	return sqrt(0.5);
                              }
                              
                              real(8) function code(l, om, kx, ky)
                                  real(8), intent (in) :: l
                                  real(8), intent (in) :: om
                                  real(8), intent (in) :: kx
                                  real(8), intent (in) :: ky
                                  code = sqrt(0.5d0)
                              end function
                              
                              public static double code(double l, double Om, double kx, double ky) {
                              	return Math.sqrt(0.5);
                              }
                              
                              def code(l, Om, kx, ky):
                              	return math.sqrt(0.5)
                              
                              function code(l, Om, kx, ky)
                              	return sqrt(0.5)
                              end
                              
                              function tmp = code(l, Om, kx, ky)
                              	tmp = sqrt(0.5);
                              end
                              
                              code[l_, Om_, kx_, ky_] := N[Sqrt[0.5], $MachinePrecision]
                              
                              \begin{array}{l}
                              
                              \\
                              \sqrt{0.5}
                              \end{array}
                              
                              Derivation
                              1. Initial program 99.2%

                                \[\sqrt{\frac{1}{2} \cdot \left(1 + \frac{1}{\sqrt{1 + {\left(\frac{2 \cdot \ell}{Om}\right)}^{2} \cdot \left({\sin kx}^{2} + {\sin ky}^{2}\right)}}\right)} \]
                              2. Add Preprocessing
                              3. Taylor expanded in Om around 0

                                \[\leadsto \sqrt{\color{blue}{\frac{1}{2}}} \]
                              4. Step-by-step derivation
                                1. Applied rewrites54.3%

                                  \[\leadsto \sqrt{\color{blue}{0.5}} \]
                                2. Add Preprocessing

                                Reproduce

                                ?
                                herbie shell --seed 2024270 
                                (FPCore (l Om kx ky)
                                  :name "Toniolo and Linder, Equation (3a)"
                                  :precision binary64
                                  (sqrt (* (/ 1.0 2.0) (+ 1.0 (/ 1.0 (sqrt (+ 1.0 (* (pow (/ (* 2.0 l) Om) 2.0) (+ (pow (sin kx) 2.0) (pow (sin ky) 2.0))))))))))