Numeric.SpecFunctions:invIncompleteBetaWorker from math-functions-0.1.5.2, F

Percentage Accurate: 78.2% → 99.1%
Time: 8.7s
Alternatives: 10
Speedup: 9.6×

Specification

?
\[\begin{array}{l} \\ \frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \end{array} \]
(FPCore (x y) :precision binary64 (/ (exp (* x (log (/ x (+ x y))))) x))
double code(double x, double y) {
	return exp((x * log((x / (x + y))))) / x;
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = exp((x * log((x / (x + y))))) / x
end function
public static double code(double x, double y) {
	return Math.exp((x * Math.log((x / (x + y))))) / x;
}
def code(x, y):
	return math.exp((x * math.log((x / (x + y))))) / x
function code(x, y)
	return Float64(exp(Float64(x * log(Float64(x / Float64(x + y))))) / x)
end
function tmp = code(x, y)
	tmp = exp((x * log((x / (x + y))))) / x;
end
code[x_, y_] := N[(N[Exp[N[(x * N[Log[N[(x / N[(x + y), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / x), $MachinePrecision]
\begin{array}{l}

\\
\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 10 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 78.2% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \end{array} \]
(FPCore (x y) :precision binary64 (/ (exp (* x (log (/ x (+ x y))))) x))
double code(double x, double y) {
	return exp((x * log((x / (x + y))))) / x;
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = exp((x * log((x / (x + y))))) / x
end function
public static double code(double x, double y) {
	return Math.exp((x * Math.log((x / (x + y))))) / x;
}
def code(x, y):
	return math.exp((x * math.log((x / (x + y))))) / x
function code(x, y)
	return Float64(exp(Float64(x * log(Float64(x / Float64(x + y))))) / x)
end
function tmp = code(x, y)
	tmp = exp((x * log((x / (x + y))))) / x;
end
code[x_, y_] := N[(N[Exp[N[(x * N[Log[N[(x / N[(x + y), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / x), $MachinePrecision]
\begin{array}{l}

\\
\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x}
\end{array}

Alternative 1: 99.1% accurate, 1.8× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{e^{-y}}{x}\\ \mathbf{if}\;x \leq -480000000:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;x \leq 3 \cdot 10^{-5}:\\ \;\;\;\;\frac{1}{x}\\ \mathbf{else}:\\ \;\;\;\;t\_0\\ \end{array} \end{array} \]
(FPCore (x y)
 :precision binary64
 (let* ((t_0 (/ (exp (- y)) x)))
   (if (<= x -480000000.0) t_0 (if (<= x 3e-5) (/ 1.0 x) t_0))))
double code(double x, double y) {
	double t_0 = exp(-y) / x;
	double tmp;
	if (x <= -480000000.0) {
		tmp = t_0;
	} else if (x <= 3e-5) {
		tmp = 1.0 / x;
	} else {
		tmp = t_0;
	}
	return tmp;
}
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8) :: t_0
    real(8) :: tmp
    t_0 = exp(-y) / x
    if (x <= (-480000000.0d0)) then
        tmp = t_0
    else if (x <= 3d-5) then
        tmp = 1.0d0 / x
    else
        tmp = t_0
    end if
    code = tmp
end function
public static double code(double x, double y) {
	double t_0 = Math.exp(-y) / x;
	double tmp;
	if (x <= -480000000.0) {
		tmp = t_0;
	} else if (x <= 3e-5) {
		tmp = 1.0 / x;
	} else {
		tmp = t_0;
	}
	return tmp;
}
def code(x, y):
	t_0 = math.exp(-y) / x
	tmp = 0
	if x <= -480000000.0:
		tmp = t_0
	elif x <= 3e-5:
		tmp = 1.0 / x
	else:
		tmp = t_0
	return tmp
function code(x, y)
	t_0 = Float64(exp(Float64(-y)) / x)
	tmp = 0.0
	if (x <= -480000000.0)
		tmp = t_0;
	elseif (x <= 3e-5)
		tmp = Float64(1.0 / x);
	else
		tmp = t_0;
	end
	return tmp
end
function tmp_2 = code(x, y)
	t_0 = exp(-y) / x;
	tmp = 0.0;
	if (x <= -480000000.0)
		tmp = t_0;
	elseif (x <= 3e-5)
		tmp = 1.0 / x;
	else
		tmp = t_0;
	end
	tmp_2 = tmp;
end
code[x_, y_] := Block[{t$95$0 = N[(N[Exp[(-y)], $MachinePrecision] / x), $MachinePrecision]}, If[LessEqual[x, -480000000.0], t$95$0, If[LessEqual[x, 3e-5], N[(1.0 / x), $MachinePrecision], t$95$0]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{e^{-y}}{x}\\
\mathbf{if}\;x \leq -480000000:\\
\;\;\;\;t\_0\\

\mathbf{elif}\;x \leq 3 \cdot 10^{-5}:\\
\;\;\;\;\frac{1}{x}\\

\mathbf{else}:\\
\;\;\;\;t\_0\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if x < -4.8e8 or 3.00000000000000008e-5 < x

    1. Initial program 73.8%

      \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
    2. Add Preprocessing
    3. Taylor expanded in y around 0

      \[\leadsto \frac{e^{\color{blue}{-1 \cdot y}}}{x} \]
    4. Step-by-step derivation
      1. mul-1-negN/A

        \[\leadsto \frac{e^{\color{blue}{\mathsf{neg}\left(y\right)}}}{x} \]
      2. lower-neg.f64100.0

        \[\leadsto \frac{e^{\color{blue}{-y}}}{x} \]
    5. Applied rewrites100.0%

      \[\leadsto \frac{e^{\color{blue}{-y}}}{x} \]

    if -4.8e8 < x < 3.00000000000000008e-5

    1. Initial program 85.6%

      \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
    2. Add Preprocessing
    3. Taylor expanded in y around 0

      \[\leadsto \frac{\color{blue}{1}}{x} \]
    4. Step-by-step derivation
      1. Applied rewrites99.0%

        \[\leadsto \frac{\color{blue}{1}}{x} \]
    5. Recombined 2 regimes into one program.
    6. Add Preprocessing

    Alternative 2: 87.3% accurate, 2.7× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq -480000000:\\ \;\;\;\;\frac{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{0.3333333333333333}{x \cdot x} + \left(\frac{0.5}{x} + 0.16666666666666666\right), -y, \frac{0.5}{x} + 0.5\right), y, -1\right), y, 1\right)}{x}\\ \mathbf{elif}\;x \leq 3 \cdot 10^{-5}:\\ \;\;\;\;\frac{1}{x}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, y, 0.5\right), y, 1\right), y, 1\right) \cdot x}\\ \end{array} \end{array} \]
    (FPCore (x y)
     :precision binary64
     (if (<= x -480000000.0)
       (/
        (fma
         (fma
          (fma
           (+ (/ 0.3333333333333333 (* x x)) (+ (/ 0.5 x) 0.16666666666666666))
           (- y)
           (+ (/ 0.5 x) 0.5))
          y
          -1.0)
         y
         1.0)
        x)
       (if (<= x 3e-5)
         (/ 1.0 x)
         (/ 1.0 (* (fma (fma (fma 0.16666666666666666 y 0.5) y 1.0) y 1.0) x)))))
    double code(double x, double y) {
    	double tmp;
    	if (x <= -480000000.0) {
    		tmp = fma(fma(fma(((0.3333333333333333 / (x * x)) + ((0.5 / x) + 0.16666666666666666)), -y, ((0.5 / x) + 0.5)), y, -1.0), y, 1.0) / x;
    	} else if (x <= 3e-5) {
    		tmp = 1.0 / x;
    	} else {
    		tmp = 1.0 / (fma(fma(fma(0.16666666666666666, y, 0.5), y, 1.0), y, 1.0) * x);
    	}
    	return tmp;
    }
    
    function code(x, y)
    	tmp = 0.0
    	if (x <= -480000000.0)
    		tmp = Float64(fma(fma(fma(Float64(Float64(0.3333333333333333 / Float64(x * x)) + Float64(Float64(0.5 / x) + 0.16666666666666666)), Float64(-y), Float64(Float64(0.5 / x) + 0.5)), y, -1.0), y, 1.0) / x);
    	elseif (x <= 3e-5)
    		tmp = Float64(1.0 / x);
    	else
    		tmp = Float64(1.0 / Float64(fma(fma(fma(0.16666666666666666, y, 0.5), y, 1.0), y, 1.0) * x));
    	end
    	return tmp
    end
    
    code[x_, y_] := If[LessEqual[x, -480000000.0], N[(N[(N[(N[(N[(N[(0.3333333333333333 / N[(x * x), $MachinePrecision]), $MachinePrecision] + N[(N[(0.5 / x), $MachinePrecision] + 0.16666666666666666), $MachinePrecision]), $MachinePrecision] * (-y) + N[(N[(0.5 / x), $MachinePrecision] + 0.5), $MachinePrecision]), $MachinePrecision] * y + -1.0), $MachinePrecision] * y + 1.0), $MachinePrecision] / x), $MachinePrecision], If[LessEqual[x, 3e-5], N[(1.0 / x), $MachinePrecision], N[(1.0 / N[(N[(N[(N[(0.16666666666666666 * y + 0.5), $MachinePrecision] * y + 1.0), $MachinePrecision] * y + 1.0), $MachinePrecision] * x), $MachinePrecision]), $MachinePrecision]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;x \leq -480000000:\\
    \;\;\;\;\frac{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{0.3333333333333333}{x \cdot x} + \left(\frac{0.5}{x} + 0.16666666666666666\right), -y, \frac{0.5}{x} + 0.5\right), y, -1\right), y, 1\right)}{x}\\
    
    \mathbf{elif}\;x \leq 3 \cdot 10^{-5}:\\
    \;\;\;\;\frac{1}{x}\\
    
    \mathbf{else}:\\
    \;\;\;\;\frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, y, 0.5\right), y, 1\right), y, 1\right) \cdot x}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 3 regimes
    2. if x < -4.8e8

      1. Initial program 66.4%

        \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
      2. Add Preprocessing
      3. Taylor expanded in y around 0

        \[\leadsto \frac{\color{blue}{1 + y \cdot \left(y \cdot \left(\frac{1}{2} + \left(-1 \cdot \left(y \cdot \left(\frac{1}{6} + \left(\frac{1}{3} \cdot \frac{1}{{x}^{2}} + \frac{1}{2} \cdot \frac{1}{x}\right)\right)\right) + \frac{1}{2} \cdot \frac{1}{x}\right)\right) - 1\right)}}{x} \]
      4. Step-by-step derivation
        1. +-commutativeN/A

          \[\leadsto \frac{\color{blue}{y \cdot \left(y \cdot \left(\frac{1}{2} + \left(-1 \cdot \left(y \cdot \left(\frac{1}{6} + \left(\frac{1}{3} \cdot \frac{1}{{x}^{2}} + \frac{1}{2} \cdot \frac{1}{x}\right)\right)\right) + \frac{1}{2} \cdot \frac{1}{x}\right)\right) - 1\right) + 1}}{x} \]
        2. *-commutativeN/A

          \[\leadsto \frac{\color{blue}{\left(y \cdot \left(\frac{1}{2} + \left(-1 \cdot \left(y \cdot \left(\frac{1}{6} + \left(\frac{1}{3} \cdot \frac{1}{{x}^{2}} + \frac{1}{2} \cdot \frac{1}{x}\right)\right)\right) + \frac{1}{2} \cdot \frac{1}{x}\right)\right) - 1\right) \cdot y} + 1}{x} \]
        3. lower-fma.f64N/A

          \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(y \cdot \left(\frac{1}{2} + \left(-1 \cdot \left(y \cdot \left(\frac{1}{6} + \left(\frac{1}{3} \cdot \frac{1}{{x}^{2}} + \frac{1}{2} \cdot \frac{1}{x}\right)\right)\right) + \frac{1}{2} \cdot \frac{1}{x}\right)\right) - 1, y, 1\right)}}{x} \]
      5. Applied rewrites72.5%

        \[\leadsto \frac{\color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\left(0.16666666666666666 + \frac{0.5}{x}\right) + \frac{0.3333333333333333}{x \cdot x}, -y, \frac{0.5}{x} + 0.5\right), y, -1\right), y, 1\right)}}{x} \]

      if -4.8e8 < x < 3.00000000000000008e-5

      1. Initial program 85.6%

        \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
      2. Add Preprocessing
      3. Taylor expanded in y around 0

        \[\leadsto \frac{\color{blue}{1}}{x} \]
      4. Step-by-step derivation
        1. Applied rewrites99.0%

          \[\leadsto \frac{\color{blue}{1}}{x} \]

        if 3.00000000000000008e-5 < x

        1. Initial program 80.5%

          \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
        2. Add Preprocessing
        3. Taylor expanded in y around 0

          \[\leadsto \frac{e^{\color{blue}{-1 \cdot y}}}{x} \]
        4. Step-by-step derivation
          1. mul-1-negN/A

            \[\leadsto \frac{e^{\color{blue}{\mathsf{neg}\left(y\right)}}}{x} \]
          2. lower-neg.f64100.0

            \[\leadsto \frac{e^{\color{blue}{-y}}}{x} \]
        5. Applied rewrites100.0%

          \[\leadsto \frac{e^{\color{blue}{-y}}}{x} \]
        6. Step-by-step derivation
          1. lift-/.f64N/A

            \[\leadsto \color{blue}{\frac{e^{-y}}{x}} \]
          2. clear-numN/A

            \[\leadsto \color{blue}{\frac{1}{\frac{x}{e^{-y}}}} \]
          3. lower-/.f64N/A

            \[\leadsto \color{blue}{\frac{1}{\frac{x}{e^{-y}}}} \]
          4. lower-/.f64100.0

            \[\leadsto \frac{1}{\color{blue}{\frac{x}{e^{-y}}}} \]
        7. Applied rewrites100.0%

          \[\leadsto \color{blue}{\frac{1}{\frac{x}{e^{-y}}}} \]
        8. Taylor expanded in x around inf

          \[\leadsto \frac{1}{\color{blue}{\frac{x}{e^{-1 \cdot y}}}} \]
        9. Step-by-step derivation
          1. *-lft-identityN/A

            \[\leadsto \frac{1}{\frac{\color{blue}{1 \cdot x}}{e^{-1 \cdot y}}} \]
          2. associate-*l/N/A

            \[\leadsto \frac{1}{\color{blue}{\frac{1}{e^{-1 \cdot y}} \cdot x}} \]
          3. lower-*.f64N/A

            \[\leadsto \frac{1}{\color{blue}{\frac{1}{e^{-1 \cdot y}} \cdot x}} \]
          4. rec-expN/A

            \[\leadsto \frac{1}{\color{blue}{e^{\mathsf{neg}\left(-1 \cdot y\right)}} \cdot x} \]
          5. mul-1-negN/A

            \[\leadsto \frac{1}{e^{\mathsf{neg}\left(\color{blue}{\left(\mathsf{neg}\left(y\right)\right)}\right)} \cdot x} \]
          6. remove-double-negN/A

            \[\leadsto \frac{1}{e^{\color{blue}{y}} \cdot x} \]
          7. lower-exp.f64100.0

            \[\leadsto \frac{1}{\color{blue}{e^{y}} \cdot x} \]
        10. Applied rewrites100.0%

          \[\leadsto \frac{1}{\color{blue}{e^{y} \cdot x}} \]
        11. Taylor expanded in y around 0

          \[\leadsto \frac{1}{\left(1 + y \cdot \left(1 + y \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot y\right)\right)\right) \cdot x} \]
        12. Step-by-step derivation
          1. Applied rewrites77.8%

            \[\leadsto \frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, y, 0.5\right), y, 1\right), y, 1\right) \cdot x} \]
        13. Recombined 3 regimes into one program.
        14. Final simplification85.9%

          \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -480000000:\\ \;\;\;\;\frac{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(\frac{0.3333333333333333}{x \cdot x} + \left(\frac{0.5}{x} + 0.16666666666666666\right), -y, \frac{0.5}{x} + 0.5\right), y, -1\right), y, 1\right)}{x}\\ \mathbf{elif}\;x \leq 3 \cdot 10^{-5}:\\ \;\;\;\;\frac{1}{x}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, y, 0.5\right), y, 1\right), y, 1\right) \cdot x}\\ \end{array} \]
        15. Add Preprocessing

        Alternative 3: 85.0% accurate, 4.7× speedup?

        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq -480000000:\\ \;\;\;\;\frac{\mathsf{fma}\left(\mathsf{fma}\left(0.5, y, -1\right), y, 1\right)}{x}\\ \mathbf{elif}\;x \leq 3 \cdot 10^{-5}:\\ \;\;\;\;\frac{1}{x}\\ \mathbf{elif}\;x \leq 7.5 \cdot 10^{+218}:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, y, 1\right), y, 1\right) \cdot x}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{x - y \cdot x}{x}}{x}\\ \end{array} \end{array} \]
        (FPCore (x y)
         :precision binary64
         (if (<= x -480000000.0)
           (/ (fma (fma 0.5 y -1.0) y 1.0) x)
           (if (<= x 3e-5)
             (/ 1.0 x)
             (if (<= x 7.5e+218)
               (/ 1.0 (* (fma (fma 0.5 y 1.0) y 1.0) x))
               (/ (/ (- x (* y x)) x) x)))))
        double code(double x, double y) {
        	double tmp;
        	if (x <= -480000000.0) {
        		tmp = fma(fma(0.5, y, -1.0), y, 1.0) / x;
        	} else if (x <= 3e-5) {
        		tmp = 1.0 / x;
        	} else if (x <= 7.5e+218) {
        		tmp = 1.0 / (fma(fma(0.5, y, 1.0), y, 1.0) * x);
        	} else {
        		tmp = ((x - (y * x)) / x) / x;
        	}
        	return tmp;
        }
        
        function code(x, y)
        	tmp = 0.0
        	if (x <= -480000000.0)
        		tmp = Float64(fma(fma(0.5, y, -1.0), y, 1.0) / x);
        	elseif (x <= 3e-5)
        		tmp = Float64(1.0 / x);
        	elseif (x <= 7.5e+218)
        		tmp = Float64(1.0 / Float64(fma(fma(0.5, y, 1.0), y, 1.0) * x));
        	else
        		tmp = Float64(Float64(Float64(x - Float64(y * x)) / x) / x);
        	end
        	return tmp
        end
        
        code[x_, y_] := If[LessEqual[x, -480000000.0], N[(N[(N[(0.5 * y + -1.0), $MachinePrecision] * y + 1.0), $MachinePrecision] / x), $MachinePrecision], If[LessEqual[x, 3e-5], N[(1.0 / x), $MachinePrecision], If[LessEqual[x, 7.5e+218], N[(1.0 / N[(N[(N[(0.5 * y + 1.0), $MachinePrecision] * y + 1.0), $MachinePrecision] * x), $MachinePrecision]), $MachinePrecision], N[(N[(N[(x - N[(y * x), $MachinePrecision]), $MachinePrecision] / x), $MachinePrecision] / x), $MachinePrecision]]]]
        
        \begin{array}{l}
        
        \\
        \begin{array}{l}
        \mathbf{if}\;x \leq -480000000:\\
        \;\;\;\;\frac{\mathsf{fma}\left(\mathsf{fma}\left(0.5, y, -1\right), y, 1\right)}{x}\\
        
        \mathbf{elif}\;x \leq 3 \cdot 10^{-5}:\\
        \;\;\;\;\frac{1}{x}\\
        
        \mathbf{elif}\;x \leq 7.5 \cdot 10^{+218}:\\
        \;\;\;\;\frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, y, 1\right), y, 1\right) \cdot x}\\
        
        \mathbf{else}:\\
        \;\;\;\;\frac{\frac{x - y \cdot x}{x}}{x}\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 4 regimes
        2. if x < -4.8e8

          1. Initial program 66.4%

            \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
          2. Add Preprocessing
          3. Taylor expanded in y around 0

            \[\leadsto \color{blue}{y \cdot \left(y \cdot \left(\frac{1}{2} \cdot \frac{1}{x} + \frac{1}{2} \cdot \frac{1}{{x}^{2}}\right) - \frac{1}{x}\right) + \frac{1}{x}} \]
          4. Step-by-step derivation
            1. *-commutativeN/A

              \[\leadsto \color{blue}{\left(y \cdot \left(\frac{1}{2} \cdot \frac{1}{x} + \frac{1}{2} \cdot \frac{1}{{x}^{2}}\right) - \frac{1}{x}\right) \cdot y} + \frac{1}{x} \]
            2. lower-fma.f64N/A

              \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot \left(\frac{1}{2} \cdot \frac{1}{x} + \frac{1}{2} \cdot \frac{1}{{x}^{2}}\right) - \frac{1}{x}, y, \frac{1}{x}\right)} \]
          5. Applied rewrites62.9%

            \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{0.5}{x}}{x} + \frac{0.5}{x}, y, \frac{-1}{x}\right), y, \frac{1}{x}\right)} \]
          6. Taylor expanded in x around inf

            \[\leadsto \frac{1 + y \cdot \left(\frac{1}{2} \cdot y - 1\right)}{\color{blue}{x}} \]
          7. Step-by-step derivation
            1. Applied rewrites69.7%

              \[\leadsto \frac{\mathsf{fma}\left(\mathsf{fma}\left(0.5, y, -1\right), y, 1\right)}{\color{blue}{x}} \]

            if -4.8e8 < x < 3.00000000000000008e-5

            1. Initial program 85.6%

              \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
            2. Add Preprocessing
            3. Taylor expanded in y around 0

              \[\leadsto \frac{\color{blue}{1}}{x} \]
            4. Step-by-step derivation
              1. Applied rewrites99.0%

                \[\leadsto \frac{\color{blue}{1}}{x} \]

              if 3.00000000000000008e-5 < x < 7.4999999999999993e218

              1. Initial program 88.8%

                \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
              2. Add Preprocessing
              3. Taylor expanded in y around 0

                \[\leadsto \frac{e^{\color{blue}{-1 \cdot y}}}{x} \]
              4. Step-by-step derivation
                1. mul-1-negN/A

                  \[\leadsto \frac{e^{\color{blue}{\mathsf{neg}\left(y\right)}}}{x} \]
                2. lower-neg.f64100.0

                  \[\leadsto \frac{e^{\color{blue}{-y}}}{x} \]
              5. Applied rewrites100.0%

                \[\leadsto \frac{e^{\color{blue}{-y}}}{x} \]
              6. Step-by-step derivation
                1. lift-/.f64N/A

                  \[\leadsto \color{blue}{\frac{e^{-y}}{x}} \]
                2. clear-numN/A

                  \[\leadsto \color{blue}{\frac{1}{\frac{x}{e^{-y}}}} \]
                3. lower-/.f64N/A

                  \[\leadsto \color{blue}{\frac{1}{\frac{x}{e^{-y}}}} \]
                4. lower-/.f64100.0

                  \[\leadsto \frac{1}{\color{blue}{\frac{x}{e^{-y}}}} \]
              7. Applied rewrites100.0%

                \[\leadsto \color{blue}{\frac{1}{\frac{x}{e^{-y}}}} \]
              8. Taylor expanded in x around inf

                \[\leadsto \frac{1}{\color{blue}{\frac{x}{e^{-1 \cdot y}}}} \]
              9. Step-by-step derivation
                1. *-lft-identityN/A

                  \[\leadsto \frac{1}{\frac{\color{blue}{1 \cdot x}}{e^{-1 \cdot y}}} \]
                2. associate-*l/N/A

                  \[\leadsto \frac{1}{\color{blue}{\frac{1}{e^{-1 \cdot y}} \cdot x}} \]
                3. lower-*.f64N/A

                  \[\leadsto \frac{1}{\color{blue}{\frac{1}{e^{-1 \cdot y}} \cdot x}} \]
                4. rec-expN/A

                  \[\leadsto \frac{1}{\color{blue}{e^{\mathsf{neg}\left(-1 \cdot y\right)}} \cdot x} \]
                5. mul-1-negN/A

                  \[\leadsto \frac{1}{e^{\mathsf{neg}\left(\color{blue}{\left(\mathsf{neg}\left(y\right)\right)}\right)} \cdot x} \]
                6. remove-double-negN/A

                  \[\leadsto \frac{1}{e^{\color{blue}{y}} \cdot x} \]
                7. lower-exp.f64100.0

                  \[\leadsto \frac{1}{\color{blue}{e^{y}} \cdot x} \]
              10. Applied rewrites100.0%

                \[\leadsto \frac{1}{\color{blue}{e^{y} \cdot x}} \]
              11. Taylor expanded in y around 0

                \[\leadsto \frac{1}{\left(1 + y \cdot \left(1 + \frac{1}{2} \cdot y\right)\right) \cdot x} \]
              12. Step-by-step derivation
                1. Applied rewrites81.2%

                  \[\leadsto \frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, y, 1\right), y, 1\right) \cdot x} \]

                if 7.4999999999999993e218 < x

                1. Initial program 56.1%

                  \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
                2. Add Preprocessing
                3. Taylor expanded in y around 0

                  \[\leadsto \color{blue}{-1 \cdot \frac{y}{x} + \frac{1}{x}} \]
                4. Step-by-step derivation
                  1. +-commutativeN/A

                    \[\leadsto \color{blue}{\frac{1}{x} + -1 \cdot \frac{y}{x}} \]
                  2. mul-1-negN/A

                    \[\leadsto \frac{1}{x} + \color{blue}{\left(\mathsf{neg}\left(\frac{y}{x}\right)\right)} \]
                  3. unsub-negN/A

                    \[\leadsto \color{blue}{\frac{1}{x} - \frac{y}{x}} \]
                  4. lower--.f64N/A

                    \[\leadsto \color{blue}{\frac{1}{x} - \frac{y}{x}} \]
                  5. lower-/.f64N/A

                    \[\leadsto \color{blue}{\frac{1}{x}} - \frac{y}{x} \]
                  6. lower-/.f6451.9

                    \[\leadsto \frac{1}{x} - \color{blue}{\frac{y}{x}} \]
                5. Applied rewrites51.9%

                  \[\leadsto \color{blue}{\frac{1}{x} - \frac{y}{x}} \]
                6. Step-by-step derivation
                  1. Applied rewrites82.3%

                    \[\leadsto \frac{\frac{x - y \cdot x}{x}}{\color{blue}{x}} \]
                7. Recombined 4 regimes into one program.
                8. Add Preprocessing

                Alternative 4: 86.1% accurate, 4.9× speedup?

                \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq -480000000:\\ \;\;\;\;\frac{\mathsf{fma}\left(\mathsf{fma}\left(0.5, y, -1\right), y, 1\right)}{x}\\ \mathbf{elif}\;x \leq 3 \cdot 10^{-5}:\\ \;\;\;\;\frac{1}{x}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, y, 0.5\right), y, 1\right), y, 1\right) \cdot x}\\ \end{array} \end{array} \]
                (FPCore (x y)
                 :precision binary64
                 (if (<= x -480000000.0)
                   (/ (fma (fma 0.5 y -1.0) y 1.0) x)
                   (if (<= x 3e-5)
                     (/ 1.0 x)
                     (/ 1.0 (* (fma (fma (fma 0.16666666666666666 y 0.5) y 1.0) y 1.0) x)))))
                double code(double x, double y) {
                	double tmp;
                	if (x <= -480000000.0) {
                		tmp = fma(fma(0.5, y, -1.0), y, 1.0) / x;
                	} else if (x <= 3e-5) {
                		tmp = 1.0 / x;
                	} else {
                		tmp = 1.0 / (fma(fma(fma(0.16666666666666666, y, 0.5), y, 1.0), y, 1.0) * x);
                	}
                	return tmp;
                }
                
                function code(x, y)
                	tmp = 0.0
                	if (x <= -480000000.0)
                		tmp = Float64(fma(fma(0.5, y, -1.0), y, 1.0) / x);
                	elseif (x <= 3e-5)
                		tmp = Float64(1.0 / x);
                	else
                		tmp = Float64(1.0 / Float64(fma(fma(fma(0.16666666666666666, y, 0.5), y, 1.0), y, 1.0) * x));
                	end
                	return tmp
                end
                
                code[x_, y_] := If[LessEqual[x, -480000000.0], N[(N[(N[(0.5 * y + -1.0), $MachinePrecision] * y + 1.0), $MachinePrecision] / x), $MachinePrecision], If[LessEqual[x, 3e-5], N[(1.0 / x), $MachinePrecision], N[(1.0 / N[(N[(N[(N[(0.16666666666666666 * y + 0.5), $MachinePrecision] * y + 1.0), $MachinePrecision] * y + 1.0), $MachinePrecision] * x), $MachinePrecision]), $MachinePrecision]]]
                
                \begin{array}{l}
                
                \\
                \begin{array}{l}
                \mathbf{if}\;x \leq -480000000:\\
                \;\;\;\;\frac{\mathsf{fma}\left(\mathsf{fma}\left(0.5, y, -1\right), y, 1\right)}{x}\\
                
                \mathbf{elif}\;x \leq 3 \cdot 10^{-5}:\\
                \;\;\;\;\frac{1}{x}\\
                
                \mathbf{else}:\\
                \;\;\;\;\frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, y, 0.5\right), y, 1\right), y, 1\right) \cdot x}\\
                
                
                \end{array}
                \end{array}
                
                Derivation
                1. Split input into 3 regimes
                2. if x < -4.8e8

                  1. Initial program 66.4%

                    \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
                  2. Add Preprocessing
                  3. Taylor expanded in y around 0

                    \[\leadsto \color{blue}{y \cdot \left(y \cdot \left(\frac{1}{2} \cdot \frac{1}{x} + \frac{1}{2} \cdot \frac{1}{{x}^{2}}\right) - \frac{1}{x}\right) + \frac{1}{x}} \]
                  4. Step-by-step derivation
                    1. *-commutativeN/A

                      \[\leadsto \color{blue}{\left(y \cdot \left(\frac{1}{2} \cdot \frac{1}{x} + \frac{1}{2} \cdot \frac{1}{{x}^{2}}\right) - \frac{1}{x}\right) \cdot y} + \frac{1}{x} \]
                    2. lower-fma.f64N/A

                      \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot \left(\frac{1}{2} \cdot \frac{1}{x} + \frac{1}{2} \cdot \frac{1}{{x}^{2}}\right) - \frac{1}{x}, y, \frac{1}{x}\right)} \]
                  5. Applied rewrites62.9%

                    \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{0.5}{x}}{x} + \frac{0.5}{x}, y, \frac{-1}{x}\right), y, \frac{1}{x}\right)} \]
                  6. Taylor expanded in x around inf

                    \[\leadsto \frac{1 + y \cdot \left(\frac{1}{2} \cdot y - 1\right)}{\color{blue}{x}} \]
                  7. Step-by-step derivation
                    1. Applied rewrites69.7%

                      \[\leadsto \frac{\mathsf{fma}\left(\mathsf{fma}\left(0.5, y, -1\right), y, 1\right)}{\color{blue}{x}} \]

                    if -4.8e8 < x < 3.00000000000000008e-5

                    1. Initial program 85.6%

                      \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
                    2. Add Preprocessing
                    3. Taylor expanded in y around 0

                      \[\leadsto \frac{\color{blue}{1}}{x} \]
                    4. Step-by-step derivation
                      1. Applied rewrites99.0%

                        \[\leadsto \frac{\color{blue}{1}}{x} \]

                      if 3.00000000000000008e-5 < x

                      1. Initial program 80.5%

                        \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
                      2. Add Preprocessing
                      3. Taylor expanded in y around 0

                        \[\leadsto \frac{e^{\color{blue}{-1 \cdot y}}}{x} \]
                      4. Step-by-step derivation
                        1. mul-1-negN/A

                          \[\leadsto \frac{e^{\color{blue}{\mathsf{neg}\left(y\right)}}}{x} \]
                        2. lower-neg.f64100.0

                          \[\leadsto \frac{e^{\color{blue}{-y}}}{x} \]
                      5. Applied rewrites100.0%

                        \[\leadsto \frac{e^{\color{blue}{-y}}}{x} \]
                      6. Step-by-step derivation
                        1. lift-/.f64N/A

                          \[\leadsto \color{blue}{\frac{e^{-y}}{x}} \]
                        2. clear-numN/A

                          \[\leadsto \color{blue}{\frac{1}{\frac{x}{e^{-y}}}} \]
                        3. lower-/.f64N/A

                          \[\leadsto \color{blue}{\frac{1}{\frac{x}{e^{-y}}}} \]
                        4. lower-/.f64100.0

                          \[\leadsto \frac{1}{\color{blue}{\frac{x}{e^{-y}}}} \]
                      7. Applied rewrites100.0%

                        \[\leadsto \color{blue}{\frac{1}{\frac{x}{e^{-y}}}} \]
                      8. Taylor expanded in x around inf

                        \[\leadsto \frac{1}{\color{blue}{\frac{x}{e^{-1 \cdot y}}}} \]
                      9. Step-by-step derivation
                        1. *-lft-identityN/A

                          \[\leadsto \frac{1}{\frac{\color{blue}{1 \cdot x}}{e^{-1 \cdot y}}} \]
                        2. associate-*l/N/A

                          \[\leadsto \frac{1}{\color{blue}{\frac{1}{e^{-1 \cdot y}} \cdot x}} \]
                        3. lower-*.f64N/A

                          \[\leadsto \frac{1}{\color{blue}{\frac{1}{e^{-1 \cdot y}} \cdot x}} \]
                        4. rec-expN/A

                          \[\leadsto \frac{1}{\color{blue}{e^{\mathsf{neg}\left(-1 \cdot y\right)}} \cdot x} \]
                        5. mul-1-negN/A

                          \[\leadsto \frac{1}{e^{\mathsf{neg}\left(\color{blue}{\left(\mathsf{neg}\left(y\right)\right)}\right)} \cdot x} \]
                        6. remove-double-negN/A

                          \[\leadsto \frac{1}{e^{\color{blue}{y}} \cdot x} \]
                        7. lower-exp.f64100.0

                          \[\leadsto \frac{1}{\color{blue}{e^{y}} \cdot x} \]
                      10. Applied rewrites100.0%

                        \[\leadsto \frac{1}{\color{blue}{e^{y} \cdot x}} \]
                      11. Taylor expanded in y around 0

                        \[\leadsto \frac{1}{\left(1 + y \cdot \left(1 + y \cdot \left(\frac{1}{2} + \frac{1}{6} \cdot y\right)\right)\right) \cdot x} \]
                      12. Step-by-step derivation
                        1. Applied rewrites77.8%

                          \[\leadsto \frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(\mathsf{fma}\left(0.16666666666666666, y, 0.5\right), y, 1\right), y, 1\right) \cdot x} \]
                      13. Recombined 3 regimes into one program.
                      14. Add Preprocessing

                      Alternative 5: 85.6% accurate, 5.6× speedup?

                      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq -480000000:\\ \;\;\;\;\frac{\mathsf{fma}\left(\mathsf{fma}\left(0.5, y, -1\right), y, 1\right)}{x}\\ \mathbf{elif}\;x \leq 3 \cdot 10^{-5}:\\ \;\;\;\;\frac{1}{x}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, y, 1\right), y, 1\right) \cdot x}\\ \end{array} \end{array} \]
                      (FPCore (x y)
                       :precision binary64
                       (if (<= x -480000000.0)
                         (/ (fma (fma 0.5 y -1.0) y 1.0) x)
                         (if (<= x 3e-5) (/ 1.0 x) (/ 1.0 (* (fma (fma 0.5 y 1.0) y 1.0) x)))))
                      double code(double x, double y) {
                      	double tmp;
                      	if (x <= -480000000.0) {
                      		tmp = fma(fma(0.5, y, -1.0), y, 1.0) / x;
                      	} else if (x <= 3e-5) {
                      		tmp = 1.0 / x;
                      	} else {
                      		tmp = 1.0 / (fma(fma(0.5, y, 1.0), y, 1.0) * x);
                      	}
                      	return tmp;
                      }
                      
                      function code(x, y)
                      	tmp = 0.0
                      	if (x <= -480000000.0)
                      		tmp = Float64(fma(fma(0.5, y, -1.0), y, 1.0) / x);
                      	elseif (x <= 3e-5)
                      		tmp = Float64(1.0 / x);
                      	else
                      		tmp = Float64(1.0 / Float64(fma(fma(0.5, y, 1.0), y, 1.0) * x));
                      	end
                      	return tmp
                      end
                      
                      code[x_, y_] := If[LessEqual[x, -480000000.0], N[(N[(N[(0.5 * y + -1.0), $MachinePrecision] * y + 1.0), $MachinePrecision] / x), $MachinePrecision], If[LessEqual[x, 3e-5], N[(1.0 / x), $MachinePrecision], N[(1.0 / N[(N[(N[(0.5 * y + 1.0), $MachinePrecision] * y + 1.0), $MachinePrecision] * x), $MachinePrecision]), $MachinePrecision]]]
                      
                      \begin{array}{l}
                      
                      \\
                      \begin{array}{l}
                      \mathbf{if}\;x \leq -480000000:\\
                      \;\;\;\;\frac{\mathsf{fma}\left(\mathsf{fma}\left(0.5, y, -1\right), y, 1\right)}{x}\\
                      
                      \mathbf{elif}\;x \leq 3 \cdot 10^{-5}:\\
                      \;\;\;\;\frac{1}{x}\\
                      
                      \mathbf{else}:\\
                      \;\;\;\;\frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, y, 1\right), y, 1\right) \cdot x}\\
                      
                      
                      \end{array}
                      \end{array}
                      
                      Derivation
                      1. Split input into 3 regimes
                      2. if x < -4.8e8

                        1. Initial program 66.4%

                          \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
                        2. Add Preprocessing
                        3. Taylor expanded in y around 0

                          \[\leadsto \color{blue}{y \cdot \left(y \cdot \left(\frac{1}{2} \cdot \frac{1}{x} + \frac{1}{2} \cdot \frac{1}{{x}^{2}}\right) - \frac{1}{x}\right) + \frac{1}{x}} \]
                        4. Step-by-step derivation
                          1. *-commutativeN/A

                            \[\leadsto \color{blue}{\left(y \cdot \left(\frac{1}{2} \cdot \frac{1}{x} + \frac{1}{2} \cdot \frac{1}{{x}^{2}}\right) - \frac{1}{x}\right) \cdot y} + \frac{1}{x} \]
                          2. lower-fma.f64N/A

                            \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot \left(\frac{1}{2} \cdot \frac{1}{x} + \frac{1}{2} \cdot \frac{1}{{x}^{2}}\right) - \frac{1}{x}, y, \frac{1}{x}\right)} \]
                        5. Applied rewrites62.9%

                          \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{0.5}{x}}{x} + \frac{0.5}{x}, y, \frac{-1}{x}\right), y, \frac{1}{x}\right)} \]
                        6. Taylor expanded in x around inf

                          \[\leadsto \frac{1 + y \cdot \left(\frac{1}{2} \cdot y - 1\right)}{\color{blue}{x}} \]
                        7. Step-by-step derivation
                          1. Applied rewrites69.7%

                            \[\leadsto \frac{\mathsf{fma}\left(\mathsf{fma}\left(0.5, y, -1\right), y, 1\right)}{\color{blue}{x}} \]

                          if -4.8e8 < x < 3.00000000000000008e-5

                          1. Initial program 85.6%

                            \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
                          2. Add Preprocessing
                          3. Taylor expanded in y around 0

                            \[\leadsto \frac{\color{blue}{1}}{x} \]
                          4. Step-by-step derivation
                            1. Applied rewrites99.0%

                              \[\leadsto \frac{\color{blue}{1}}{x} \]

                            if 3.00000000000000008e-5 < x

                            1. Initial program 80.5%

                              \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
                            2. Add Preprocessing
                            3. Taylor expanded in y around 0

                              \[\leadsto \frac{e^{\color{blue}{-1 \cdot y}}}{x} \]
                            4. Step-by-step derivation
                              1. mul-1-negN/A

                                \[\leadsto \frac{e^{\color{blue}{\mathsf{neg}\left(y\right)}}}{x} \]
                              2. lower-neg.f64100.0

                                \[\leadsto \frac{e^{\color{blue}{-y}}}{x} \]
                            5. Applied rewrites100.0%

                              \[\leadsto \frac{e^{\color{blue}{-y}}}{x} \]
                            6. Step-by-step derivation
                              1. lift-/.f64N/A

                                \[\leadsto \color{blue}{\frac{e^{-y}}{x}} \]
                              2. clear-numN/A

                                \[\leadsto \color{blue}{\frac{1}{\frac{x}{e^{-y}}}} \]
                              3. lower-/.f64N/A

                                \[\leadsto \color{blue}{\frac{1}{\frac{x}{e^{-y}}}} \]
                              4. lower-/.f64100.0

                                \[\leadsto \frac{1}{\color{blue}{\frac{x}{e^{-y}}}} \]
                            7. Applied rewrites100.0%

                              \[\leadsto \color{blue}{\frac{1}{\frac{x}{e^{-y}}}} \]
                            8. Taylor expanded in x around inf

                              \[\leadsto \frac{1}{\color{blue}{\frac{x}{e^{-1 \cdot y}}}} \]
                            9. Step-by-step derivation
                              1. *-lft-identityN/A

                                \[\leadsto \frac{1}{\frac{\color{blue}{1 \cdot x}}{e^{-1 \cdot y}}} \]
                              2. associate-*l/N/A

                                \[\leadsto \frac{1}{\color{blue}{\frac{1}{e^{-1 \cdot y}} \cdot x}} \]
                              3. lower-*.f64N/A

                                \[\leadsto \frac{1}{\color{blue}{\frac{1}{e^{-1 \cdot y}} \cdot x}} \]
                              4. rec-expN/A

                                \[\leadsto \frac{1}{\color{blue}{e^{\mathsf{neg}\left(-1 \cdot y\right)}} \cdot x} \]
                              5. mul-1-negN/A

                                \[\leadsto \frac{1}{e^{\mathsf{neg}\left(\color{blue}{\left(\mathsf{neg}\left(y\right)\right)}\right)} \cdot x} \]
                              6. remove-double-negN/A

                                \[\leadsto \frac{1}{e^{\color{blue}{y}} \cdot x} \]
                              7. lower-exp.f64100.0

                                \[\leadsto \frac{1}{\color{blue}{e^{y}} \cdot x} \]
                            10. Applied rewrites100.0%

                              \[\leadsto \frac{1}{\color{blue}{e^{y} \cdot x}} \]
                            11. Taylor expanded in y around 0

                              \[\leadsto \frac{1}{\left(1 + y \cdot \left(1 + \frac{1}{2} \cdot y\right)\right) \cdot x} \]
                            12. Step-by-step derivation
                              1. Applied rewrites75.2%

                                \[\leadsto \frac{1}{\mathsf{fma}\left(\mathsf{fma}\left(0.5, y, 1\right), y, 1\right) \cdot x} \]
                            13. Recombined 3 regimes into one program.
                            14. Add Preprocessing

                            Alternative 6: 83.5% accurate, 7.7× speedup?

                            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq -480000000:\\ \;\;\;\;\frac{\mathsf{fma}\left(\mathsf{fma}\left(0.5, y, -1\right), y, 1\right)}{x}\\ \mathbf{elif}\;x \leq 6.5 \cdot 10^{+25}:\\ \;\;\;\;\frac{1}{x}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(y, x, x\right)}\\ \end{array} \end{array} \]
                            (FPCore (x y)
                             :precision binary64
                             (if (<= x -480000000.0)
                               (/ (fma (fma 0.5 y -1.0) y 1.0) x)
                               (if (<= x 6.5e+25) (/ 1.0 x) (/ 1.0 (fma y x x)))))
                            double code(double x, double y) {
                            	double tmp;
                            	if (x <= -480000000.0) {
                            		tmp = fma(fma(0.5, y, -1.0), y, 1.0) / x;
                            	} else if (x <= 6.5e+25) {
                            		tmp = 1.0 / x;
                            	} else {
                            		tmp = 1.0 / fma(y, x, x);
                            	}
                            	return tmp;
                            }
                            
                            function code(x, y)
                            	tmp = 0.0
                            	if (x <= -480000000.0)
                            		tmp = Float64(fma(fma(0.5, y, -1.0), y, 1.0) / x);
                            	elseif (x <= 6.5e+25)
                            		tmp = Float64(1.0 / x);
                            	else
                            		tmp = Float64(1.0 / fma(y, x, x));
                            	end
                            	return tmp
                            end
                            
                            code[x_, y_] := If[LessEqual[x, -480000000.0], N[(N[(N[(0.5 * y + -1.0), $MachinePrecision] * y + 1.0), $MachinePrecision] / x), $MachinePrecision], If[LessEqual[x, 6.5e+25], N[(1.0 / x), $MachinePrecision], N[(1.0 / N[(y * x + x), $MachinePrecision]), $MachinePrecision]]]
                            
                            \begin{array}{l}
                            
                            \\
                            \begin{array}{l}
                            \mathbf{if}\;x \leq -480000000:\\
                            \;\;\;\;\frac{\mathsf{fma}\left(\mathsf{fma}\left(0.5, y, -1\right), y, 1\right)}{x}\\
                            
                            \mathbf{elif}\;x \leq 6.5 \cdot 10^{+25}:\\
                            \;\;\;\;\frac{1}{x}\\
                            
                            \mathbf{else}:\\
                            \;\;\;\;\frac{1}{\mathsf{fma}\left(y, x, x\right)}\\
                            
                            
                            \end{array}
                            \end{array}
                            
                            Derivation
                            1. Split input into 3 regimes
                            2. if x < -4.8e8

                              1. Initial program 66.4%

                                \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
                              2. Add Preprocessing
                              3. Taylor expanded in y around 0

                                \[\leadsto \color{blue}{y \cdot \left(y \cdot \left(\frac{1}{2} \cdot \frac{1}{x} + \frac{1}{2} \cdot \frac{1}{{x}^{2}}\right) - \frac{1}{x}\right) + \frac{1}{x}} \]
                              4. Step-by-step derivation
                                1. *-commutativeN/A

                                  \[\leadsto \color{blue}{\left(y \cdot \left(\frac{1}{2} \cdot \frac{1}{x} + \frac{1}{2} \cdot \frac{1}{{x}^{2}}\right) - \frac{1}{x}\right) \cdot y} + \frac{1}{x} \]
                                2. lower-fma.f64N/A

                                  \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot \left(\frac{1}{2} \cdot \frac{1}{x} + \frac{1}{2} \cdot \frac{1}{{x}^{2}}\right) - \frac{1}{x}, y, \frac{1}{x}\right)} \]
                              5. Applied rewrites62.9%

                                \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{0.5}{x}}{x} + \frac{0.5}{x}, y, \frac{-1}{x}\right), y, \frac{1}{x}\right)} \]
                              6. Taylor expanded in x around inf

                                \[\leadsto \frac{1 + y \cdot \left(\frac{1}{2} \cdot y - 1\right)}{\color{blue}{x}} \]
                              7. Step-by-step derivation
                                1. Applied rewrites69.7%

                                  \[\leadsto \frac{\mathsf{fma}\left(\mathsf{fma}\left(0.5, y, -1\right), y, 1\right)}{\color{blue}{x}} \]

                                if -4.8e8 < x < 6.50000000000000005e25

                                1. Initial program 85.8%

                                  \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
                                2. Add Preprocessing
                                3. Taylor expanded in y around 0

                                  \[\leadsto \frac{\color{blue}{1}}{x} \]
                                4. Step-by-step derivation
                                  1. Applied rewrites95.9%

                                    \[\leadsto \frac{\color{blue}{1}}{x} \]

                                  if 6.50000000000000005e25 < x

                                  1. Initial program 79.6%

                                    \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in y around 0

                                    \[\leadsto \frac{e^{\color{blue}{-1 \cdot y}}}{x} \]
                                  4. Step-by-step derivation
                                    1. mul-1-negN/A

                                      \[\leadsto \frac{e^{\color{blue}{\mathsf{neg}\left(y\right)}}}{x} \]
                                    2. lower-neg.f64100.0

                                      \[\leadsto \frac{e^{\color{blue}{-y}}}{x} \]
                                  5. Applied rewrites100.0%

                                    \[\leadsto \frac{e^{\color{blue}{-y}}}{x} \]
                                  6. Step-by-step derivation
                                    1. lift-/.f64N/A

                                      \[\leadsto \color{blue}{\frac{e^{-y}}{x}} \]
                                    2. clear-numN/A

                                      \[\leadsto \color{blue}{\frac{1}{\frac{x}{e^{-y}}}} \]
                                    3. lower-/.f64N/A

                                      \[\leadsto \color{blue}{\frac{1}{\frac{x}{e^{-y}}}} \]
                                    4. lower-/.f64100.0

                                      \[\leadsto \frac{1}{\color{blue}{\frac{x}{e^{-y}}}} \]
                                  7. Applied rewrites100.0%

                                    \[\leadsto \color{blue}{\frac{1}{\frac{x}{e^{-y}}}} \]
                                  8. Taylor expanded in y around 0

                                    \[\leadsto \frac{1}{\color{blue}{x + x \cdot y}} \]
                                  9. Step-by-step derivation
                                    1. +-commutativeN/A

                                      \[\leadsto \frac{1}{\color{blue}{x \cdot y + x}} \]
                                    2. *-commutativeN/A

                                      \[\leadsto \frac{1}{\color{blue}{y \cdot x} + x} \]
                                    3. lower-fma.f6470.3

                                      \[\leadsto \frac{1}{\color{blue}{\mathsf{fma}\left(y, x, x\right)}} \]
                                  10. Applied rewrites70.3%

                                    \[\leadsto \frac{1}{\color{blue}{\mathsf{fma}\left(y, x, x\right)}} \]
                                5. Recombined 3 regimes into one program.
                                6. Add Preprocessing

                                Alternative 7: 83.3% accurate, 7.7× speedup?

                                \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq -480000000:\\ \;\;\;\;\frac{\mathsf{fma}\left(0.5 \cdot y, y, 1\right)}{x}\\ \mathbf{elif}\;x \leq 6.5 \cdot 10^{+25}:\\ \;\;\;\;\frac{1}{x}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(y, x, x\right)}\\ \end{array} \end{array} \]
                                (FPCore (x y)
                                 :precision binary64
                                 (if (<= x -480000000.0)
                                   (/ (fma (* 0.5 y) y 1.0) x)
                                   (if (<= x 6.5e+25) (/ 1.0 x) (/ 1.0 (fma y x x)))))
                                double code(double x, double y) {
                                	double tmp;
                                	if (x <= -480000000.0) {
                                		tmp = fma((0.5 * y), y, 1.0) / x;
                                	} else if (x <= 6.5e+25) {
                                		tmp = 1.0 / x;
                                	} else {
                                		tmp = 1.0 / fma(y, x, x);
                                	}
                                	return tmp;
                                }
                                
                                function code(x, y)
                                	tmp = 0.0
                                	if (x <= -480000000.0)
                                		tmp = Float64(fma(Float64(0.5 * y), y, 1.0) / x);
                                	elseif (x <= 6.5e+25)
                                		tmp = Float64(1.0 / x);
                                	else
                                		tmp = Float64(1.0 / fma(y, x, x));
                                	end
                                	return tmp
                                end
                                
                                code[x_, y_] := If[LessEqual[x, -480000000.0], N[(N[(N[(0.5 * y), $MachinePrecision] * y + 1.0), $MachinePrecision] / x), $MachinePrecision], If[LessEqual[x, 6.5e+25], N[(1.0 / x), $MachinePrecision], N[(1.0 / N[(y * x + x), $MachinePrecision]), $MachinePrecision]]]
                                
                                \begin{array}{l}
                                
                                \\
                                \begin{array}{l}
                                \mathbf{if}\;x \leq -480000000:\\
                                \;\;\;\;\frac{\mathsf{fma}\left(0.5 \cdot y, y, 1\right)}{x}\\
                                
                                \mathbf{elif}\;x \leq 6.5 \cdot 10^{+25}:\\
                                \;\;\;\;\frac{1}{x}\\
                                
                                \mathbf{else}:\\
                                \;\;\;\;\frac{1}{\mathsf{fma}\left(y, x, x\right)}\\
                                
                                
                                \end{array}
                                \end{array}
                                
                                Derivation
                                1. Split input into 3 regimes
                                2. if x < -4.8e8

                                  1. Initial program 66.4%

                                    \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
                                  2. Add Preprocessing
                                  3. Taylor expanded in y around 0

                                    \[\leadsto \color{blue}{y \cdot \left(y \cdot \left(\frac{1}{2} \cdot \frac{1}{x} + \frac{1}{2} \cdot \frac{1}{{x}^{2}}\right) - \frac{1}{x}\right) + \frac{1}{x}} \]
                                  4. Step-by-step derivation
                                    1. *-commutativeN/A

                                      \[\leadsto \color{blue}{\left(y \cdot \left(\frac{1}{2} \cdot \frac{1}{x} + \frac{1}{2} \cdot \frac{1}{{x}^{2}}\right) - \frac{1}{x}\right) \cdot y} + \frac{1}{x} \]
                                    2. lower-fma.f64N/A

                                      \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot \left(\frac{1}{2} \cdot \frac{1}{x} + \frac{1}{2} \cdot \frac{1}{{x}^{2}}\right) - \frac{1}{x}, y, \frac{1}{x}\right)} \]
                                  5. Applied rewrites62.9%

                                    \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{0.5}{x}}{x} + \frac{0.5}{x}, y, \frac{-1}{x}\right), y, \frac{1}{x}\right)} \]
                                  6. Taylor expanded in x around inf

                                    \[\leadsto \frac{1 + y \cdot \left(\frac{1}{2} \cdot y - 1\right)}{\color{blue}{x}} \]
                                  7. Step-by-step derivation
                                    1. Applied rewrites69.7%

                                      \[\leadsto \frac{\mathsf{fma}\left(\mathsf{fma}\left(0.5, y, -1\right), y, 1\right)}{\color{blue}{x}} \]
                                    2. Taylor expanded in y around inf

                                      \[\leadsto \frac{\mathsf{fma}\left(\frac{1}{2} \cdot y, y, 1\right)}{x} \]
                                    3. Step-by-step derivation
                                      1. Applied rewrites69.0%

                                        \[\leadsto \frac{\mathsf{fma}\left(0.5 \cdot y, y, 1\right)}{x} \]

                                      if -4.8e8 < x < 6.50000000000000005e25

                                      1. Initial program 85.8%

                                        \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
                                      2. Add Preprocessing
                                      3. Taylor expanded in y around 0

                                        \[\leadsto \frac{\color{blue}{1}}{x} \]
                                      4. Step-by-step derivation
                                        1. Applied rewrites95.9%

                                          \[\leadsto \frac{\color{blue}{1}}{x} \]

                                        if 6.50000000000000005e25 < x

                                        1. Initial program 79.6%

                                          \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
                                        2. Add Preprocessing
                                        3. Taylor expanded in y around 0

                                          \[\leadsto \frac{e^{\color{blue}{-1 \cdot y}}}{x} \]
                                        4. Step-by-step derivation
                                          1. mul-1-negN/A

                                            \[\leadsto \frac{e^{\color{blue}{\mathsf{neg}\left(y\right)}}}{x} \]
                                          2. lower-neg.f64100.0

                                            \[\leadsto \frac{e^{\color{blue}{-y}}}{x} \]
                                        5. Applied rewrites100.0%

                                          \[\leadsto \frac{e^{\color{blue}{-y}}}{x} \]
                                        6. Step-by-step derivation
                                          1. lift-/.f64N/A

                                            \[\leadsto \color{blue}{\frac{e^{-y}}{x}} \]
                                          2. clear-numN/A

                                            \[\leadsto \color{blue}{\frac{1}{\frac{x}{e^{-y}}}} \]
                                          3. lower-/.f64N/A

                                            \[\leadsto \color{blue}{\frac{1}{\frac{x}{e^{-y}}}} \]
                                          4. lower-/.f64100.0

                                            \[\leadsto \frac{1}{\color{blue}{\frac{x}{e^{-y}}}} \]
                                        7. Applied rewrites100.0%

                                          \[\leadsto \color{blue}{\frac{1}{\frac{x}{e^{-y}}}} \]
                                        8. Taylor expanded in y around 0

                                          \[\leadsto \frac{1}{\color{blue}{x + x \cdot y}} \]
                                        9. Step-by-step derivation
                                          1. +-commutativeN/A

                                            \[\leadsto \frac{1}{\color{blue}{x \cdot y + x}} \]
                                          2. *-commutativeN/A

                                            \[\leadsto \frac{1}{\color{blue}{y \cdot x} + x} \]
                                          3. lower-fma.f6470.3

                                            \[\leadsto \frac{1}{\color{blue}{\mathsf{fma}\left(y, x, x\right)}} \]
                                        10. Applied rewrites70.3%

                                          \[\leadsto \frac{1}{\color{blue}{\mathsf{fma}\left(y, x, x\right)}} \]
                                      5. Recombined 3 regimes into one program.
                                      6. Add Preprocessing

                                      Alternative 8: 76.3% accurate, 8.2× speedup?

                                      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \leq -1.4 \cdot 10^{+157}:\\ \;\;\;\;\frac{\left(y \cdot y\right) \cdot 0.5}{x}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{x}\\ \end{array} \end{array} \]
                                      (FPCore (x y)
                                       :precision binary64
                                       (if (<= y -1.4e+157) (/ (* (* y y) 0.5) x) (/ 1.0 x)))
                                      double code(double x, double y) {
                                      	double tmp;
                                      	if (y <= -1.4e+157) {
                                      		tmp = ((y * y) * 0.5) / x;
                                      	} else {
                                      		tmp = 1.0 / x;
                                      	}
                                      	return tmp;
                                      }
                                      
                                      real(8) function code(x, y)
                                          real(8), intent (in) :: x
                                          real(8), intent (in) :: y
                                          real(8) :: tmp
                                          if (y <= (-1.4d+157)) then
                                              tmp = ((y * y) * 0.5d0) / x
                                          else
                                              tmp = 1.0d0 / x
                                          end if
                                          code = tmp
                                      end function
                                      
                                      public static double code(double x, double y) {
                                      	double tmp;
                                      	if (y <= -1.4e+157) {
                                      		tmp = ((y * y) * 0.5) / x;
                                      	} else {
                                      		tmp = 1.0 / x;
                                      	}
                                      	return tmp;
                                      }
                                      
                                      def code(x, y):
                                      	tmp = 0
                                      	if y <= -1.4e+157:
                                      		tmp = ((y * y) * 0.5) / x
                                      	else:
                                      		tmp = 1.0 / x
                                      	return tmp
                                      
                                      function code(x, y)
                                      	tmp = 0.0
                                      	if (y <= -1.4e+157)
                                      		tmp = Float64(Float64(Float64(y * y) * 0.5) / x);
                                      	else
                                      		tmp = Float64(1.0 / x);
                                      	end
                                      	return tmp
                                      end
                                      
                                      function tmp_2 = code(x, y)
                                      	tmp = 0.0;
                                      	if (y <= -1.4e+157)
                                      		tmp = ((y * y) * 0.5) / x;
                                      	else
                                      		tmp = 1.0 / x;
                                      	end
                                      	tmp_2 = tmp;
                                      end
                                      
                                      code[x_, y_] := If[LessEqual[y, -1.4e+157], N[(N[(N[(y * y), $MachinePrecision] * 0.5), $MachinePrecision] / x), $MachinePrecision], N[(1.0 / x), $MachinePrecision]]
                                      
                                      \begin{array}{l}
                                      
                                      \\
                                      \begin{array}{l}
                                      \mathbf{if}\;y \leq -1.4 \cdot 10^{+157}:\\
                                      \;\;\;\;\frac{\left(y \cdot y\right) \cdot 0.5}{x}\\
                                      
                                      \mathbf{else}:\\
                                      \;\;\;\;\frac{1}{x}\\
                                      
                                      
                                      \end{array}
                                      \end{array}
                                      
                                      Derivation
                                      1. Split input into 2 regimes
                                      2. if y < -1.4000000000000001e157

                                        1. Initial program 70.4%

                                          \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
                                        2. Add Preprocessing
                                        3. Taylor expanded in y around 0

                                          \[\leadsto \color{blue}{y \cdot \left(y \cdot \left(\frac{1}{2} \cdot \frac{1}{x} + \frac{1}{2} \cdot \frac{1}{{x}^{2}}\right) - \frac{1}{x}\right) + \frac{1}{x}} \]
                                        4. Step-by-step derivation
                                          1. *-commutativeN/A

                                            \[\leadsto \color{blue}{\left(y \cdot \left(\frac{1}{2} \cdot \frac{1}{x} + \frac{1}{2} \cdot \frac{1}{{x}^{2}}\right) - \frac{1}{x}\right) \cdot y} + \frac{1}{x} \]
                                          2. lower-fma.f64N/A

                                            \[\leadsto \color{blue}{\mathsf{fma}\left(y \cdot \left(\frac{1}{2} \cdot \frac{1}{x} + \frac{1}{2} \cdot \frac{1}{{x}^{2}}\right) - \frac{1}{x}, y, \frac{1}{x}\right)} \]
                                        5. Applied rewrites37.1%

                                          \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{0.5}{x}}{x} + \frac{0.5}{x}, y, \frac{-1}{x}\right), y, \frac{1}{x}\right)} \]
                                        6. Taylor expanded in x around inf

                                          \[\leadsto \frac{1 + y \cdot \left(\frac{1}{2} \cdot y - 1\right)}{\color{blue}{x}} \]
                                        7. Step-by-step derivation
                                          1. Applied rewrites70.7%

                                            \[\leadsto \frac{\mathsf{fma}\left(\mathsf{fma}\left(0.5, y, -1\right), y, 1\right)}{\color{blue}{x}} \]
                                          2. Taylor expanded in y around inf

                                            \[\leadsto \frac{\frac{1}{2} \cdot {y}^{2}}{x} \]
                                          3. Step-by-step derivation
                                            1. Applied rewrites70.7%

                                              \[\leadsto \frac{\left(y \cdot y\right) \cdot 0.5}{x} \]

                                            if -1.4000000000000001e157 < y

                                            1. Initial program 80.1%

                                              \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
                                            2. Add Preprocessing
                                            3. Taylor expanded in y around 0

                                              \[\leadsto \frac{\color{blue}{1}}{x} \]
                                            4. Step-by-step derivation
                                              1. Applied rewrites78.6%

                                                \[\leadsto \frac{\color{blue}{1}}{x} \]
                                            5. Recombined 2 regimes into one program.
                                            6. Add Preprocessing

                                            Alternative 9: 79.2% accurate, 9.6× speedup?

                                            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 6.5 \cdot 10^{+25}:\\ \;\;\;\;\frac{1}{x}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{\mathsf{fma}\left(y, x, x\right)}\\ \end{array} \end{array} \]
                                            (FPCore (x y)
                                             :precision binary64
                                             (if (<= x 6.5e+25) (/ 1.0 x) (/ 1.0 (fma y x x))))
                                            double code(double x, double y) {
                                            	double tmp;
                                            	if (x <= 6.5e+25) {
                                            		tmp = 1.0 / x;
                                            	} else {
                                            		tmp = 1.0 / fma(y, x, x);
                                            	}
                                            	return tmp;
                                            }
                                            
                                            function code(x, y)
                                            	tmp = 0.0
                                            	if (x <= 6.5e+25)
                                            		tmp = Float64(1.0 / x);
                                            	else
                                            		tmp = Float64(1.0 / fma(y, x, x));
                                            	end
                                            	return tmp
                                            end
                                            
                                            code[x_, y_] := If[LessEqual[x, 6.5e+25], N[(1.0 / x), $MachinePrecision], N[(1.0 / N[(y * x + x), $MachinePrecision]), $MachinePrecision]]
                                            
                                            \begin{array}{l}
                                            
                                            \\
                                            \begin{array}{l}
                                            \mathbf{if}\;x \leq 6.5 \cdot 10^{+25}:\\
                                            \;\;\;\;\frac{1}{x}\\
                                            
                                            \mathbf{else}:\\
                                            \;\;\;\;\frac{1}{\mathsf{fma}\left(y, x, x\right)}\\
                                            
                                            
                                            \end{array}
                                            \end{array}
                                            
                                            Derivation
                                            1. Split input into 2 regimes
                                            2. if x < 6.50000000000000005e25

                                              1. Initial program 78.9%

                                                \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
                                              2. Add Preprocessing
                                              3. Taylor expanded in y around 0

                                                \[\leadsto \frac{\color{blue}{1}}{x} \]
                                              4. Step-by-step derivation
                                                1. Applied rewrites79.2%

                                                  \[\leadsto \frac{\color{blue}{1}}{x} \]

                                                if 6.50000000000000005e25 < x

                                                1. Initial program 79.6%

                                                  \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
                                                2. Add Preprocessing
                                                3. Taylor expanded in y around 0

                                                  \[\leadsto \frac{e^{\color{blue}{-1 \cdot y}}}{x} \]
                                                4. Step-by-step derivation
                                                  1. mul-1-negN/A

                                                    \[\leadsto \frac{e^{\color{blue}{\mathsf{neg}\left(y\right)}}}{x} \]
                                                  2. lower-neg.f64100.0

                                                    \[\leadsto \frac{e^{\color{blue}{-y}}}{x} \]
                                                5. Applied rewrites100.0%

                                                  \[\leadsto \frac{e^{\color{blue}{-y}}}{x} \]
                                                6. Step-by-step derivation
                                                  1. lift-/.f64N/A

                                                    \[\leadsto \color{blue}{\frac{e^{-y}}{x}} \]
                                                  2. clear-numN/A

                                                    \[\leadsto \color{blue}{\frac{1}{\frac{x}{e^{-y}}}} \]
                                                  3. lower-/.f64N/A

                                                    \[\leadsto \color{blue}{\frac{1}{\frac{x}{e^{-y}}}} \]
                                                  4. lower-/.f64100.0

                                                    \[\leadsto \frac{1}{\color{blue}{\frac{x}{e^{-y}}}} \]
                                                7. Applied rewrites100.0%

                                                  \[\leadsto \color{blue}{\frac{1}{\frac{x}{e^{-y}}}} \]
                                                8. Taylor expanded in y around 0

                                                  \[\leadsto \frac{1}{\color{blue}{x + x \cdot y}} \]
                                                9. Step-by-step derivation
                                                  1. +-commutativeN/A

                                                    \[\leadsto \frac{1}{\color{blue}{x \cdot y + x}} \]
                                                  2. *-commutativeN/A

                                                    \[\leadsto \frac{1}{\color{blue}{y \cdot x} + x} \]
                                                  3. lower-fma.f6470.3

                                                    \[\leadsto \frac{1}{\color{blue}{\mathsf{fma}\left(y, x, x\right)}} \]
                                                10. Applied rewrites70.3%

                                                  \[\leadsto \frac{1}{\color{blue}{\mathsf{fma}\left(y, x, x\right)}} \]
                                              5. Recombined 2 regimes into one program.
                                              6. Add Preprocessing

                                              Alternative 10: 74.7% accurate, 19.3× speedup?

                                              \[\begin{array}{l} \\ \frac{1}{x} \end{array} \]
                                              (FPCore (x y) :precision binary64 (/ 1.0 x))
                                              double code(double x, double y) {
                                              	return 1.0 / x;
                                              }
                                              
                                              real(8) function code(x, y)
                                                  real(8), intent (in) :: x
                                                  real(8), intent (in) :: y
                                                  code = 1.0d0 / x
                                              end function
                                              
                                              public static double code(double x, double y) {
                                              	return 1.0 / x;
                                              }
                                              
                                              def code(x, y):
                                              	return 1.0 / x
                                              
                                              function code(x, y)
                                              	return Float64(1.0 / x)
                                              end
                                              
                                              function tmp = code(x, y)
                                              	tmp = 1.0 / x;
                                              end
                                              
                                              code[x_, y_] := N[(1.0 / x), $MachinePrecision]
                                              
                                              \begin{array}{l}
                                              
                                              \\
                                              \frac{1}{x}
                                              \end{array}
                                              
                                              Derivation
                                              1. Initial program 79.1%

                                                \[\frac{e^{x \cdot \log \left(\frac{x}{x + y}\right)}}{x} \]
                                              2. Add Preprocessing
                                              3. Taylor expanded in y around 0

                                                \[\leadsto \frac{\color{blue}{1}}{x} \]
                                              4. Step-by-step derivation
                                                1. Applied rewrites73.7%

                                                  \[\leadsto \frac{\color{blue}{1}}{x} \]
                                                2. Add Preprocessing

                                                Developer Target 1: 77.5% accurate, 0.7× speedup?

                                                \[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{e^{\frac{-1}{y}}}{x}\\ t_1 := \frac{{\left(\frac{x}{y + x}\right)}^{x}}{x}\\ \mathbf{if}\;y < -3.7311844206647956 \cdot 10^{+94}:\\ \;\;\;\;t\_0\\ \mathbf{elif}\;y < 2.817959242728288 \cdot 10^{+37}:\\ \;\;\;\;t\_1\\ \mathbf{elif}\;y < 2.347387415166998 \cdot 10^{+178}:\\ \;\;\;\;\log \left(e^{t\_1}\right)\\ \mathbf{else}:\\ \;\;\;\;t\_0\\ \end{array} \end{array} \]
                                                (FPCore (x y)
                                                 :precision binary64
                                                 (let* ((t_0 (/ (exp (/ -1.0 y)) x)) (t_1 (/ (pow (/ x (+ y x)) x) x)))
                                                   (if (< y -3.7311844206647956e+94)
                                                     t_0
                                                     (if (< y 2.817959242728288e+37)
                                                       t_1
                                                       (if (< y 2.347387415166998e+178) (log (exp t_1)) t_0)))))
                                                double code(double x, double y) {
                                                	double t_0 = exp((-1.0 / y)) / x;
                                                	double t_1 = pow((x / (y + x)), x) / x;
                                                	double tmp;
                                                	if (y < -3.7311844206647956e+94) {
                                                		tmp = t_0;
                                                	} else if (y < 2.817959242728288e+37) {
                                                		tmp = t_1;
                                                	} else if (y < 2.347387415166998e+178) {
                                                		tmp = log(exp(t_1));
                                                	} else {
                                                		tmp = t_0;
                                                	}
                                                	return tmp;
                                                }
                                                
                                                real(8) function code(x, y)
                                                    real(8), intent (in) :: x
                                                    real(8), intent (in) :: y
                                                    real(8) :: t_0
                                                    real(8) :: t_1
                                                    real(8) :: tmp
                                                    t_0 = exp(((-1.0d0) / y)) / x
                                                    t_1 = ((x / (y + x)) ** x) / x
                                                    if (y < (-3.7311844206647956d+94)) then
                                                        tmp = t_0
                                                    else if (y < 2.817959242728288d+37) then
                                                        tmp = t_1
                                                    else if (y < 2.347387415166998d+178) then
                                                        tmp = log(exp(t_1))
                                                    else
                                                        tmp = t_0
                                                    end if
                                                    code = tmp
                                                end function
                                                
                                                public static double code(double x, double y) {
                                                	double t_0 = Math.exp((-1.0 / y)) / x;
                                                	double t_1 = Math.pow((x / (y + x)), x) / x;
                                                	double tmp;
                                                	if (y < -3.7311844206647956e+94) {
                                                		tmp = t_0;
                                                	} else if (y < 2.817959242728288e+37) {
                                                		tmp = t_1;
                                                	} else if (y < 2.347387415166998e+178) {
                                                		tmp = Math.log(Math.exp(t_1));
                                                	} else {
                                                		tmp = t_0;
                                                	}
                                                	return tmp;
                                                }
                                                
                                                def code(x, y):
                                                	t_0 = math.exp((-1.0 / y)) / x
                                                	t_1 = math.pow((x / (y + x)), x) / x
                                                	tmp = 0
                                                	if y < -3.7311844206647956e+94:
                                                		tmp = t_0
                                                	elif y < 2.817959242728288e+37:
                                                		tmp = t_1
                                                	elif y < 2.347387415166998e+178:
                                                		tmp = math.log(math.exp(t_1))
                                                	else:
                                                		tmp = t_0
                                                	return tmp
                                                
                                                function code(x, y)
                                                	t_0 = Float64(exp(Float64(-1.0 / y)) / x)
                                                	t_1 = Float64((Float64(x / Float64(y + x)) ^ x) / x)
                                                	tmp = 0.0
                                                	if (y < -3.7311844206647956e+94)
                                                		tmp = t_0;
                                                	elseif (y < 2.817959242728288e+37)
                                                		tmp = t_1;
                                                	elseif (y < 2.347387415166998e+178)
                                                		tmp = log(exp(t_1));
                                                	else
                                                		tmp = t_0;
                                                	end
                                                	return tmp
                                                end
                                                
                                                function tmp_2 = code(x, y)
                                                	t_0 = exp((-1.0 / y)) / x;
                                                	t_1 = ((x / (y + x)) ^ x) / x;
                                                	tmp = 0.0;
                                                	if (y < -3.7311844206647956e+94)
                                                		tmp = t_0;
                                                	elseif (y < 2.817959242728288e+37)
                                                		tmp = t_1;
                                                	elseif (y < 2.347387415166998e+178)
                                                		tmp = log(exp(t_1));
                                                	else
                                                		tmp = t_0;
                                                	end
                                                	tmp_2 = tmp;
                                                end
                                                
                                                code[x_, y_] := Block[{t$95$0 = N[(N[Exp[N[(-1.0 / y), $MachinePrecision]], $MachinePrecision] / x), $MachinePrecision]}, Block[{t$95$1 = N[(N[Power[N[(x / N[(y + x), $MachinePrecision]), $MachinePrecision], x], $MachinePrecision] / x), $MachinePrecision]}, If[Less[y, -3.7311844206647956e+94], t$95$0, If[Less[y, 2.817959242728288e+37], t$95$1, If[Less[y, 2.347387415166998e+178], N[Log[N[Exp[t$95$1], $MachinePrecision]], $MachinePrecision], t$95$0]]]]]
                                                
                                                \begin{array}{l}
                                                
                                                \\
                                                \begin{array}{l}
                                                t_0 := \frac{e^{\frac{-1}{y}}}{x}\\
                                                t_1 := \frac{{\left(\frac{x}{y + x}\right)}^{x}}{x}\\
                                                \mathbf{if}\;y < -3.7311844206647956 \cdot 10^{+94}:\\
                                                \;\;\;\;t\_0\\
                                                
                                                \mathbf{elif}\;y < 2.817959242728288 \cdot 10^{+37}:\\
                                                \;\;\;\;t\_1\\
                                                
                                                \mathbf{elif}\;y < 2.347387415166998 \cdot 10^{+178}:\\
                                                \;\;\;\;\log \left(e^{t\_1}\right)\\
                                                
                                                \mathbf{else}:\\
                                                \;\;\;\;t\_0\\
                                                
                                                
                                                \end{array}
                                                \end{array}
                                                

                                                Reproduce

                                                ?
                                                herbie shell --seed 2024256 
                                                (FPCore (x y)
                                                  :name "Numeric.SpecFunctions:invIncompleteBetaWorker from math-functions-0.1.5.2, F"
                                                  :precision binary64
                                                
                                                  :alt
                                                  (! :herbie-platform default (if (< y -37311844206647956000000000000000000000000000000000000000000000000000000000000000000000000000000) (/ (exp (/ -1 y)) x) (if (< y 28179592427282880000000000000000000000) (/ (pow (/ x (+ y x)) x) x) (if (< y 23473874151669980000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000) (log (exp (/ (pow (/ x (+ y x)) x) x))) (/ (exp (/ -1 y)) x)))))
                                                
                                                  (/ (exp (* x (log (/ x (+ x y))))) x))