Given's Rotation SVD example

Percentage Accurate: 79.1% → 99.8%
Time: 9.7s
Alternatives: 8
Speedup: 0.6×

Specification

?
\[10^{-150} < \left|x\right| \land \left|x\right| < 10^{+150}\]
\[\begin{array}{l} \\ \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \end{array} \]
(FPCore (p x)
 :precision binary64
 (sqrt (* 0.5 (+ 1.0 (/ x (sqrt (+ (* (* 4.0 p) p) (* x x))))))))
double code(double p, double x) {
	return sqrt((0.5 * (1.0 + (x / sqrt((((4.0 * p) * p) + (x * x)))))));
}
real(8) function code(p, x)
    real(8), intent (in) :: p
    real(8), intent (in) :: x
    code = sqrt((0.5d0 * (1.0d0 + (x / sqrt((((4.0d0 * p) * p) + (x * x)))))))
end function
public static double code(double p, double x) {
	return Math.sqrt((0.5 * (1.0 + (x / Math.sqrt((((4.0 * p) * p) + (x * x)))))));
}
def code(p, x):
	return math.sqrt((0.5 * (1.0 + (x / math.sqrt((((4.0 * p) * p) + (x * x)))))))
function code(p, x)
	return sqrt(Float64(0.5 * Float64(1.0 + Float64(x / sqrt(Float64(Float64(Float64(4.0 * p) * p) + Float64(x * x)))))))
end
function tmp = code(p, x)
	tmp = sqrt((0.5 * (1.0 + (x / sqrt((((4.0 * p) * p) + (x * x)))))));
end
code[p_, x_] := N[Sqrt[N[(0.5 * N[(1.0 + N[(x / N[Sqrt[N[(N[(N[(4.0 * p), $MachinePrecision] * p), $MachinePrecision] + N[(x * x), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 8 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 79.1% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \end{array} \]
(FPCore (p x)
 :precision binary64
 (sqrt (* 0.5 (+ 1.0 (/ x (sqrt (+ (* (* 4.0 p) p) (* x x))))))))
double code(double p, double x) {
	return sqrt((0.5 * (1.0 + (x / sqrt((((4.0 * p) * p) + (x * x)))))));
}
real(8) function code(p, x)
    real(8), intent (in) :: p
    real(8), intent (in) :: x
    code = sqrt((0.5d0 * (1.0d0 + (x / sqrt((((4.0d0 * p) * p) + (x * x)))))))
end function
public static double code(double p, double x) {
	return Math.sqrt((0.5 * (1.0 + (x / Math.sqrt((((4.0 * p) * p) + (x * x)))))));
}
def code(p, x):
	return math.sqrt((0.5 * (1.0 + (x / math.sqrt((((4.0 * p) * p) + (x * x)))))))
function code(p, x)
	return sqrt(Float64(0.5 * Float64(1.0 + Float64(x / sqrt(Float64(Float64(Float64(4.0 * p) * p) + Float64(x * x)))))))
end
function tmp = code(p, x)
	tmp = sqrt((0.5 * (1.0 + (x / sqrt((((4.0 * p) * p) + (x * x)))))));
end
code[p_, x_] := N[Sqrt[N[(0.5 * N[(1.0 + N[(x / N[Sqrt[N[(N[(N[(4.0 * p), $MachinePrecision] * p), $MachinePrecision] + N[(x * x), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}
\end{array}

Alternative 1: 99.8% accurate, 0.2× speedup?

\[\begin{array}{l} p_m = \left|p\right| \\ \begin{array}{l} t_0 := \mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p\_m \cdot 4, p\_m, x \cdot x\right)}}, 0.5, 0.5\right)\\ \mathbf{if}\;\frac{x}{\sqrt{x \cdot x + \left(p\_m \cdot 4\right) \cdot p\_m}} \leq -0.9:\\ \;\;\;\;\frac{-p\_m}{x}\\ \mathbf{else}:\\ \;\;\;\;{\left(t\_0 \cdot t\_0\right)}^{0.25}\\ \end{array} \end{array} \]
p_m = (fabs.f64 p)
(FPCore (p_m x)
 :precision binary64
 (let* ((t_0 (fma (/ x (sqrt (fma (* p_m 4.0) p_m (* x x)))) 0.5 0.5)))
   (if (<= (/ x (sqrt (+ (* x x) (* (* p_m 4.0) p_m)))) -0.9)
     (/ (- p_m) x)
     (pow (* t_0 t_0) 0.25))))
p_m = fabs(p);
double code(double p_m, double x) {
	double t_0 = fma((x / sqrt(fma((p_m * 4.0), p_m, (x * x)))), 0.5, 0.5);
	double tmp;
	if ((x / sqrt(((x * x) + ((p_m * 4.0) * p_m)))) <= -0.9) {
		tmp = -p_m / x;
	} else {
		tmp = pow((t_0 * t_0), 0.25);
	}
	return tmp;
}
p_m = abs(p)
function code(p_m, x)
	t_0 = fma(Float64(x / sqrt(fma(Float64(p_m * 4.0), p_m, Float64(x * x)))), 0.5, 0.5)
	tmp = 0.0
	if (Float64(x / sqrt(Float64(Float64(x * x) + Float64(Float64(p_m * 4.0) * p_m)))) <= -0.9)
		tmp = Float64(Float64(-p_m) / x);
	else
		tmp = Float64(t_0 * t_0) ^ 0.25;
	end
	return tmp
end
p_m = N[Abs[p], $MachinePrecision]
code[p$95$m_, x_] := Block[{t$95$0 = N[(N[(x / N[Sqrt[N[(N[(p$95$m * 4.0), $MachinePrecision] * p$95$m + N[(x * x), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * 0.5 + 0.5), $MachinePrecision]}, If[LessEqual[N[(x / N[Sqrt[N[(N[(x * x), $MachinePrecision] + N[(N[(p$95$m * 4.0), $MachinePrecision] * p$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], -0.9], N[((-p$95$m) / x), $MachinePrecision], N[Power[N[(t$95$0 * t$95$0), $MachinePrecision], 0.25], $MachinePrecision]]]
\begin{array}{l}
p_m = \left|p\right|

\\
\begin{array}{l}
t_0 := \mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p\_m \cdot 4, p\_m, x \cdot x\right)}}, 0.5, 0.5\right)\\
\mathbf{if}\;\frac{x}{\sqrt{x \cdot x + \left(p\_m \cdot 4\right) \cdot p\_m}} \leq -0.9:\\
\;\;\;\;\frac{-p\_m}{x}\\

\mathbf{else}:\\
\;\;\;\;{\left(t\_0 \cdot t\_0\right)}^{0.25}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x)))) < -0.900000000000000022

    1. Initial program 16.9%

      \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto \color{blue}{\sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}} \]
      2. pow1/2N/A

        \[\leadsto \color{blue}{{\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\frac{1}{2}}} \]
      3. metadata-evalN/A

        \[\leadsto {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\color{blue}{\left(2 \cdot \frac{1}{4}\right)}} \]
      4. metadata-evalN/A

        \[\leadsto {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(2 \cdot \color{blue}{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}\right)} \]
      5. pow-sqrN/A

        \[\leadsto \color{blue}{{\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)} \cdot {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
      6. pow-prod-downN/A

        \[\leadsto \color{blue}{{\left(\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right) \cdot \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
      7. lower-pow.f64N/A

        \[\leadsto \color{blue}{{\left(\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right) \cdot \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
    4. Applied rewrites16.9%

      \[\leadsto \color{blue}{{\left(\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p \cdot 4, p, x \cdot x\right)}}, 0.5, 0.5\right) \cdot \mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p \cdot 4, p, x \cdot x\right)}}, 0.5, 0.5\right)\right)}^{0.25}} \]
    5. Taylor expanded in x around -inf

      \[\leadsto \color{blue}{-1 \cdot \frac{p}{x}} \]
    6. Step-by-step derivation
      1. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{-1 \cdot p}{x}} \]
      2. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{-1 \cdot p}{x}} \]
      3. mul-1-negN/A

        \[\leadsto \frac{\color{blue}{\mathsf{neg}\left(p\right)}}{x} \]
      4. lower-neg.f6481.2

        \[\leadsto \frac{\color{blue}{-p}}{x} \]
    7. Applied rewrites81.2%

      \[\leadsto \color{blue}{\frac{-p}{x}} \]

    if -0.900000000000000022 < (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x))))

    1. Initial program 100.0%

      \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto \color{blue}{\sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}} \]
      2. pow1/2N/A

        \[\leadsto \color{blue}{{\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\frac{1}{2}}} \]
      3. metadata-evalN/A

        \[\leadsto {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\color{blue}{\left(2 \cdot \frac{1}{4}\right)}} \]
      4. metadata-evalN/A

        \[\leadsto {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(2 \cdot \color{blue}{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}\right)} \]
      5. pow-sqrN/A

        \[\leadsto \color{blue}{{\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)} \cdot {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
      6. pow-prod-downN/A

        \[\leadsto \color{blue}{{\left(\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right) \cdot \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
      7. lower-pow.f64N/A

        \[\leadsto \color{blue}{{\left(\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right) \cdot \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
    4. Applied rewrites100.0%

      \[\leadsto \color{blue}{{\left(\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p \cdot 4, p, x \cdot x\right)}}, 0.5, 0.5\right) \cdot \mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p \cdot 4, p, x \cdot x\right)}}, 0.5, 0.5\right)\right)}^{0.25}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification96.4%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{x}{\sqrt{x \cdot x + \left(p \cdot 4\right) \cdot p}} \leq -0.9:\\ \;\;\;\;\frac{-p}{x}\\ \mathbf{else}:\\ \;\;\;\;{\left(\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p \cdot 4, p, x \cdot x\right)}}, 0.5, 0.5\right) \cdot \mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p \cdot 4, p, x \cdot x\right)}}, 0.5, 0.5\right)\right)}^{0.25}\\ \end{array} \]
  5. Add Preprocessing

Alternative 2: 99.2% accurate, 0.5× speedup?

\[\begin{array}{l} p_m = \left|p\right| \\ \begin{array}{l} t_0 := \frac{x}{\sqrt{x \cdot x + \left(p\_m \cdot 4\right) \cdot p\_m}}\\ \mathbf{if}\;t\_0 \leq -0.5:\\ \;\;\;\;\frac{-p\_m}{x}\\ \mathbf{elif}\;t\_0 \leq 0.02:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(\frac{x}{p\_m}, 0.25, 0.5\right)}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(0.5, \frac{\left(-p\_m\right) \cdot p\_m}{x \cdot x}, 1\right)\\ \end{array} \end{array} \]
p_m = (fabs.f64 p)
(FPCore (p_m x)
 :precision binary64
 (let* ((t_0 (/ x (sqrt (+ (* x x) (* (* p_m 4.0) p_m))))))
   (if (<= t_0 -0.5)
     (/ (- p_m) x)
     (if (<= t_0 0.02)
       (sqrt (fma (/ x p_m) 0.25 0.5))
       (fma 0.5 (/ (* (- p_m) p_m) (* x x)) 1.0)))))
p_m = fabs(p);
double code(double p_m, double x) {
	double t_0 = x / sqrt(((x * x) + ((p_m * 4.0) * p_m)));
	double tmp;
	if (t_0 <= -0.5) {
		tmp = -p_m / x;
	} else if (t_0 <= 0.02) {
		tmp = sqrt(fma((x / p_m), 0.25, 0.5));
	} else {
		tmp = fma(0.5, ((-p_m * p_m) / (x * x)), 1.0);
	}
	return tmp;
}
p_m = abs(p)
function code(p_m, x)
	t_0 = Float64(x / sqrt(Float64(Float64(x * x) + Float64(Float64(p_m * 4.0) * p_m))))
	tmp = 0.0
	if (t_0 <= -0.5)
		tmp = Float64(Float64(-p_m) / x);
	elseif (t_0 <= 0.02)
		tmp = sqrt(fma(Float64(x / p_m), 0.25, 0.5));
	else
		tmp = fma(0.5, Float64(Float64(Float64(-p_m) * p_m) / Float64(x * x)), 1.0);
	end
	return tmp
end
p_m = N[Abs[p], $MachinePrecision]
code[p$95$m_, x_] := Block[{t$95$0 = N[(x / N[Sqrt[N[(N[(x * x), $MachinePrecision] + N[(N[(p$95$m * 4.0), $MachinePrecision] * p$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, -0.5], N[((-p$95$m) / x), $MachinePrecision], If[LessEqual[t$95$0, 0.02], N[Sqrt[N[(N[(x / p$95$m), $MachinePrecision] * 0.25 + 0.5), $MachinePrecision]], $MachinePrecision], N[(0.5 * N[(N[((-p$95$m) * p$95$m), $MachinePrecision] / N[(x * x), $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision]]]]
\begin{array}{l}
p_m = \left|p\right|

\\
\begin{array}{l}
t_0 := \frac{x}{\sqrt{x \cdot x + \left(p\_m \cdot 4\right) \cdot p\_m}}\\
\mathbf{if}\;t\_0 \leq -0.5:\\
\;\;\;\;\frac{-p\_m}{x}\\

\mathbf{elif}\;t\_0 \leq 0.02:\\
\;\;\;\;\sqrt{\mathsf{fma}\left(\frac{x}{p\_m}, 0.25, 0.5\right)}\\

\mathbf{else}:\\
\;\;\;\;\mathsf{fma}\left(0.5, \frac{\left(-p\_m\right) \cdot p\_m}{x \cdot x}, 1\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x)))) < -0.5

    1. Initial program 18.5%

      \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto \color{blue}{\sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}} \]
      2. pow1/2N/A

        \[\leadsto \color{blue}{{\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\frac{1}{2}}} \]
      3. metadata-evalN/A

        \[\leadsto {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\color{blue}{\left(2 \cdot \frac{1}{4}\right)}} \]
      4. metadata-evalN/A

        \[\leadsto {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(2 \cdot \color{blue}{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}\right)} \]
      5. pow-sqrN/A

        \[\leadsto \color{blue}{{\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)} \cdot {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
      6. pow-prod-downN/A

        \[\leadsto \color{blue}{{\left(\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right) \cdot \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
      7. lower-pow.f64N/A

        \[\leadsto \color{blue}{{\left(\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right) \cdot \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
    4. Applied rewrites18.5%

      \[\leadsto \color{blue}{{\left(\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p \cdot 4, p, x \cdot x\right)}}, 0.5, 0.5\right) \cdot \mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p \cdot 4, p, x \cdot x\right)}}, 0.5, 0.5\right)\right)}^{0.25}} \]
    5. Taylor expanded in x around -inf

      \[\leadsto \color{blue}{-1 \cdot \frac{p}{x}} \]
    6. Step-by-step derivation
      1. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{-1 \cdot p}{x}} \]
      2. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{-1 \cdot p}{x}} \]
      3. mul-1-negN/A

        \[\leadsto \frac{\color{blue}{\mathsf{neg}\left(p\right)}}{x} \]
      4. lower-neg.f6480.1

        \[\leadsto \frac{\color{blue}{-p}}{x} \]
    7. Applied rewrites80.1%

      \[\leadsto \color{blue}{\frac{-p}{x}} \]

    if -0.5 < (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x)))) < 0.0200000000000000004

    1. Initial program 100.0%

      \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in p around inf

      \[\leadsto \sqrt{\color{blue}{\frac{1}{2} + \frac{1}{4} \cdot \frac{x}{p}}} \]
    4. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto \sqrt{\color{blue}{\frac{1}{4} \cdot \frac{x}{p} + \frac{1}{2}}} \]
      2. *-commutativeN/A

        \[\leadsto \sqrt{\color{blue}{\frac{x}{p} \cdot \frac{1}{4}} + \frac{1}{2}} \]
      3. lower-fma.f64N/A

        \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\frac{x}{p}, \frac{1}{4}, \frac{1}{2}\right)}} \]
      4. lower-/.f6499.1

        \[\leadsto \sqrt{\mathsf{fma}\left(\color{blue}{\frac{x}{p}}, 0.25, 0.5\right)} \]
    5. Applied rewrites99.1%

      \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\frac{x}{p}, 0.25, 0.5\right)}} \]

    if 0.0200000000000000004 < (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x))))

    1. Initial program 100.0%

      \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. lift-sqrt.f64N/A

        \[\leadsto \color{blue}{\sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}} \]
      2. pow1/2N/A

        \[\leadsto \color{blue}{{\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\frac{1}{2}}} \]
      3. metadata-evalN/A

        \[\leadsto {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\color{blue}{\left(2 \cdot \frac{1}{4}\right)}} \]
      4. metadata-evalN/A

        \[\leadsto {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(2 \cdot \color{blue}{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}\right)} \]
      5. pow-sqrN/A

        \[\leadsto \color{blue}{{\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)} \cdot {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
      6. pow-prod-downN/A

        \[\leadsto \color{blue}{{\left(\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right) \cdot \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
      7. lower-pow.f64N/A

        \[\leadsto \color{blue}{{\left(\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right) \cdot \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
    4. Applied rewrites100.0%

      \[\leadsto \color{blue}{{\left(\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p \cdot 4, p, x \cdot x\right)}}, 0.5, 0.5\right) \cdot \mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p \cdot 4, p, x \cdot x\right)}}, 0.5, 0.5\right)\right)}^{0.25}} \]
    5. Taylor expanded in p around 0

      \[\leadsto \color{blue}{1 + \frac{-1}{2} \cdot \frac{{p}^{2}}{{x}^{2}}} \]
    6. Step-by-step derivation
      1. +-commutativeN/A

        \[\leadsto \color{blue}{\frac{-1}{2} \cdot \frac{{p}^{2}}{{x}^{2}} + 1} \]
      2. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{\frac{-1}{2} \cdot {p}^{2}}{{x}^{2}}} + 1 \]
      3. unpow2N/A

        \[\leadsto \frac{\frac{-1}{2} \cdot {p}^{2}}{\color{blue}{x \cdot x}} + 1 \]
      4. times-fracN/A

        \[\leadsto \color{blue}{\frac{\frac{-1}{2}}{x} \cdot \frac{{p}^{2}}{x}} + 1 \]
      5. lower-fma.f64N/A

        \[\leadsto \color{blue}{\mathsf{fma}\left(\frac{\frac{-1}{2}}{x}, \frac{{p}^{2}}{x}, 1\right)} \]
      6. lower-/.f64N/A

        \[\leadsto \mathsf{fma}\left(\color{blue}{\frac{\frac{-1}{2}}{x}}, \frac{{p}^{2}}{x}, 1\right) \]
      7. lower-/.f64N/A

        \[\leadsto \mathsf{fma}\left(\frac{\frac{-1}{2}}{x}, \color{blue}{\frac{{p}^{2}}{x}}, 1\right) \]
      8. unpow2N/A

        \[\leadsto \mathsf{fma}\left(\frac{\frac{-1}{2}}{x}, \frac{\color{blue}{p \cdot p}}{x}, 1\right) \]
      9. lower-*.f64100.0

        \[\leadsto \mathsf{fma}\left(\frac{-0.5}{x}, \frac{\color{blue}{p \cdot p}}{x}, 1\right) \]
    7. Applied rewrites100.0%

      \[\leadsto \color{blue}{\mathsf{fma}\left(\frac{-0.5}{x}, \frac{p \cdot p}{x}, 1\right)} \]
    8. Step-by-step derivation
      1. Applied rewrites100.0%

        \[\leadsto \mathsf{fma}\left(0.5, \color{blue}{\frac{\left(-p\right) \cdot p}{x \cdot x}}, 1\right) \]
    9. Recombined 3 regimes into one program.
    10. Final simplification95.6%

      \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{x}{\sqrt{x \cdot x + \left(p \cdot 4\right) \cdot p}} \leq -0.5:\\ \;\;\;\;\frac{-p}{x}\\ \mathbf{elif}\;\frac{x}{\sqrt{x \cdot x + \left(p \cdot 4\right) \cdot p}} \leq 0.02:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(\frac{x}{p}, 0.25, 0.5\right)}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(0.5, \frac{\left(-p\right) \cdot p}{x \cdot x}, 1\right)\\ \end{array} \]
    11. Add Preprocessing

    Alternative 3: 99.1% accurate, 0.5× speedup?

    \[\begin{array}{l} p_m = \left|p\right| \\ \begin{array}{l} t_0 := \frac{x}{\sqrt{x \cdot x + \left(p\_m \cdot 4\right) \cdot p\_m}}\\ \mathbf{if}\;t\_0 \leq -0.5:\\ \;\;\;\;\frac{-p\_m}{x}\\ \mathbf{elif}\;t\_0 \leq 0.02:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(\frac{x}{p\_m}, 0.25, 0.5\right)}\\ \mathbf{else}:\\ \;\;\;\;1\\ \end{array} \end{array} \]
    p_m = (fabs.f64 p)
    (FPCore (p_m x)
     :precision binary64
     (let* ((t_0 (/ x (sqrt (+ (* x x) (* (* p_m 4.0) p_m))))))
       (if (<= t_0 -0.5)
         (/ (- p_m) x)
         (if (<= t_0 0.02) (sqrt (fma (/ x p_m) 0.25 0.5)) 1.0))))
    p_m = fabs(p);
    double code(double p_m, double x) {
    	double t_0 = x / sqrt(((x * x) + ((p_m * 4.0) * p_m)));
    	double tmp;
    	if (t_0 <= -0.5) {
    		tmp = -p_m / x;
    	} else if (t_0 <= 0.02) {
    		tmp = sqrt(fma((x / p_m), 0.25, 0.5));
    	} else {
    		tmp = 1.0;
    	}
    	return tmp;
    }
    
    p_m = abs(p)
    function code(p_m, x)
    	t_0 = Float64(x / sqrt(Float64(Float64(x * x) + Float64(Float64(p_m * 4.0) * p_m))))
    	tmp = 0.0
    	if (t_0 <= -0.5)
    		tmp = Float64(Float64(-p_m) / x);
    	elseif (t_0 <= 0.02)
    		tmp = sqrt(fma(Float64(x / p_m), 0.25, 0.5));
    	else
    		tmp = 1.0;
    	end
    	return tmp
    end
    
    p_m = N[Abs[p], $MachinePrecision]
    code[p$95$m_, x_] := Block[{t$95$0 = N[(x / N[Sqrt[N[(N[(x * x), $MachinePrecision] + N[(N[(p$95$m * 4.0), $MachinePrecision] * p$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, -0.5], N[((-p$95$m) / x), $MachinePrecision], If[LessEqual[t$95$0, 0.02], N[Sqrt[N[(N[(x / p$95$m), $MachinePrecision] * 0.25 + 0.5), $MachinePrecision]], $MachinePrecision], 1.0]]]
    
    \begin{array}{l}
    p_m = \left|p\right|
    
    \\
    \begin{array}{l}
    t_0 := \frac{x}{\sqrt{x \cdot x + \left(p\_m \cdot 4\right) \cdot p\_m}}\\
    \mathbf{if}\;t\_0 \leq -0.5:\\
    \;\;\;\;\frac{-p\_m}{x}\\
    
    \mathbf{elif}\;t\_0 \leq 0.02:\\
    \;\;\;\;\sqrt{\mathsf{fma}\left(\frac{x}{p\_m}, 0.25, 0.5\right)}\\
    
    \mathbf{else}:\\
    \;\;\;\;1\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 3 regimes
    2. if (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x)))) < -0.5

      1. Initial program 18.5%

        \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
      2. Add Preprocessing
      3. Step-by-step derivation
        1. lift-sqrt.f64N/A

          \[\leadsto \color{blue}{\sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}} \]
        2. pow1/2N/A

          \[\leadsto \color{blue}{{\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\frac{1}{2}}} \]
        3. metadata-evalN/A

          \[\leadsto {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\color{blue}{\left(2 \cdot \frac{1}{4}\right)}} \]
        4. metadata-evalN/A

          \[\leadsto {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(2 \cdot \color{blue}{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}\right)} \]
        5. pow-sqrN/A

          \[\leadsto \color{blue}{{\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)} \cdot {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
        6. pow-prod-downN/A

          \[\leadsto \color{blue}{{\left(\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right) \cdot \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
        7. lower-pow.f64N/A

          \[\leadsto \color{blue}{{\left(\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right) \cdot \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
      4. Applied rewrites18.5%

        \[\leadsto \color{blue}{{\left(\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p \cdot 4, p, x \cdot x\right)}}, 0.5, 0.5\right) \cdot \mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p \cdot 4, p, x \cdot x\right)}}, 0.5, 0.5\right)\right)}^{0.25}} \]
      5. Taylor expanded in x around -inf

        \[\leadsto \color{blue}{-1 \cdot \frac{p}{x}} \]
      6. Step-by-step derivation
        1. associate-*r/N/A

          \[\leadsto \color{blue}{\frac{-1 \cdot p}{x}} \]
        2. lower-/.f64N/A

          \[\leadsto \color{blue}{\frac{-1 \cdot p}{x}} \]
        3. mul-1-negN/A

          \[\leadsto \frac{\color{blue}{\mathsf{neg}\left(p\right)}}{x} \]
        4. lower-neg.f6480.1

          \[\leadsto \frac{\color{blue}{-p}}{x} \]
      7. Applied rewrites80.1%

        \[\leadsto \color{blue}{\frac{-p}{x}} \]

      if -0.5 < (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x)))) < 0.0200000000000000004

      1. Initial program 100.0%

        \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
      2. Add Preprocessing
      3. Taylor expanded in p around inf

        \[\leadsto \sqrt{\color{blue}{\frac{1}{2} + \frac{1}{4} \cdot \frac{x}{p}}} \]
      4. Step-by-step derivation
        1. +-commutativeN/A

          \[\leadsto \sqrt{\color{blue}{\frac{1}{4} \cdot \frac{x}{p} + \frac{1}{2}}} \]
        2. *-commutativeN/A

          \[\leadsto \sqrt{\color{blue}{\frac{x}{p} \cdot \frac{1}{4}} + \frac{1}{2}} \]
        3. lower-fma.f64N/A

          \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\frac{x}{p}, \frac{1}{4}, \frac{1}{2}\right)}} \]
        4. lower-/.f6499.1

          \[\leadsto \sqrt{\mathsf{fma}\left(\color{blue}{\frac{x}{p}}, 0.25, 0.5\right)} \]
      5. Applied rewrites99.1%

        \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\frac{x}{p}, 0.25, 0.5\right)}} \]

      if 0.0200000000000000004 < (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x))))

      1. Initial program 100.0%

        \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
      2. Add Preprocessing
      3. Step-by-step derivation
        1. lift-sqrt.f64N/A

          \[\leadsto \color{blue}{\sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}} \]
        2. pow1/2N/A

          \[\leadsto \color{blue}{{\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\frac{1}{2}}} \]
        3. metadata-evalN/A

          \[\leadsto {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\color{blue}{\left(2 \cdot \frac{1}{4}\right)}} \]
        4. metadata-evalN/A

          \[\leadsto {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(2 \cdot \color{blue}{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}\right)} \]
        5. pow-sqrN/A

          \[\leadsto \color{blue}{{\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)} \cdot {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
        6. pow-prod-downN/A

          \[\leadsto \color{blue}{{\left(\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right) \cdot \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
        7. lower-pow.f64N/A

          \[\leadsto \color{blue}{{\left(\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right) \cdot \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
      4. Applied rewrites100.0%

        \[\leadsto \color{blue}{{\left(\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p \cdot 4, p, x \cdot x\right)}}, 0.5, 0.5\right) \cdot \mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p \cdot 4, p, x \cdot x\right)}}, 0.5, 0.5\right)\right)}^{0.25}} \]
      5. Taylor expanded in p around 0

        \[\leadsto \color{blue}{1} \]
      6. Step-by-step derivation
        1. Applied rewrites98.6%

          \[\leadsto \color{blue}{1} \]
      7. Recombined 3 regimes into one program.
      8. Final simplification95.2%

        \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{x}{\sqrt{x \cdot x + \left(p \cdot 4\right) \cdot p}} \leq -0.5:\\ \;\;\;\;\frac{-p}{x}\\ \mathbf{elif}\;\frac{x}{\sqrt{x \cdot x + \left(p \cdot 4\right) \cdot p}} \leq 0.02:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(\frac{x}{p}, 0.25, 0.5\right)}\\ \mathbf{else}:\\ \;\;\;\;1\\ \end{array} \]
      9. Add Preprocessing

      Alternative 4: 98.4% accurate, 0.6× speedup?

      \[\begin{array}{l} p_m = \left|p\right| \\ \begin{array}{l} t_0 := \frac{x}{\sqrt{x \cdot x + \left(p\_m \cdot 4\right) \cdot p\_m}}\\ \mathbf{if}\;t\_0 \leq -0.5:\\ \;\;\;\;\frac{-p\_m}{x}\\ \mathbf{elif}\;t\_0 \leq 0.02:\\ \;\;\;\;\sqrt{0.5}\\ \mathbf{else}:\\ \;\;\;\;1\\ \end{array} \end{array} \]
      p_m = (fabs.f64 p)
      (FPCore (p_m x)
       :precision binary64
       (let* ((t_0 (/ x (sqrt (+ (* x x) (* (* p_m 4.0) p_m))))))
         (if (<= t_0 -0.5) (/ (- p_m) x) (if (<= t_0 0.02) (sqrt 0.5) 1.0))))
      p_m = fabs(p);
      double code(double p_m, double x) {
      	double t_0 = x / sqrt(((x * x) + ((p_m * 4.0) * p_m)));
      	double tmp;
      	if (t_0 <= -0.5) {
      		tmp = -p_m / x;
      	} else if (t_0 <= 0.02) {
      		tmp = sqrt(0.5);
      	} else {
      		tmp = 1.0;
      	}
      	return tmp;
      }
      
      p_m = abs(p)
      real(8) function code(p_m, x)
          real(8), intent (in) :: p_m
          real(8), intent (in) :: x
          real(8) :: t_0
          real(8) :: tmp
          t_0 = x / sqrt(((x * x) + ((p_m * 4.0d0) * p_m)))
          if (t_0 <= (-0.5d0)) then
              tmp = -p_m / x
          else if (t_0 <= 0.02d0) then
              tmp = sqrt(0.5d0)
          else
              tmp = 1.0d0
          end if
          code = tmp
      end function
      
      p_m = Math.abs(p);
      public static double code(double p_m, double x) {
      	double t_0 = x / Math.sqrt(((x * x) + ((p_m * 4.0) * p_m)));
      	double tmp;
      	if (t_0 <= -0.5) {
      		tmp = -p_m / x;
      	} else if (t_0 <= 0.02) {
      		tmp = Math.sqrt(0.5);
      	} else {
      		tmp = 1.0;
      	}
      	return tmp;
      }
      
      p_m = math.fabs(p)
      def code(p_m, x):
      	t_0 = x / math.sqrt(((x * x) + ((p_m * 4.0) * p_m)))
      	tmp = 0
      	if t_0 <= -0.5:
      		tmp = -p_m / x
      	elif t_0 <= 0.02:
      		tmp = math.sqrt(0.5)
      	else:
      		tmp = 1.0
      	return tmp
      
      p_m = abs(p)
      function code(p_m, x)
      	t_0 = Float64(x / sqrt(Float64(Float64(x * x) + Float64(Float64(p_m * 4.0) * p_m))))
      	tmp = 0.0
      	if (t_0 <= -0.5)
      		tmp = Float64(Float64(-p_m) / x);
      	elseif (t_0 <= 0.02)
      		tmp = sqrt(0.5);
      	else
      		tmp = 1.0;
      	end
      	return tmp
      end
      
      p_m = abs(p);
      function tmp_2 = code(p_m, x)
      	t_0 = x / sqrt(((x * x) + ((p_m * 4.0) * p_m)));
      	tmp = 0.0;
      	if (t_0 <= -0.5)
      		tmp = -p_m / x;
      	elseif (t_0 <= 0.02)
      		tmp = sqrt(0.5);
      	else
      		tmp = 1.0;
      	end
      	tmp_2 = tmp;
      end
      
      p_m = N[Abs[p], $MachinePrecision]
      code[p$95$m_, x_] := Block[{t$95$0 = N[(x / N[Sqrt[N[(N[(x * x), $MachinePrecision] + N[(N[(p$95$m * 4.0), $MachinePrecision] * p$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, -0.5], N[((-p$95$m) / x), $MachinePrecision], If[LessEqual[t$95$0, 0.02], N[Sqrt[0.5], $MachinePrecision], 1.0]]]
      
      \begin{array}{l}
      p_m = \left|p\right|
      
      \\
      \begin{array}{l}
      t_0 := \frac{x}{\sqrt{x \cdot x + \left(p\_m \cdot 4\right) \cdot p\_m}}\\
      \mathbf{if}\;t\_0 \leq -0.5:\\
      \;\;\;\;\frac{-p\_m}{x}\\
      
      \mathbf{elif}\;t\_0 \leq 0.02:\\
      \;\;\;\;\sqrt{0.5}\\
      
      \mathbf{else}:\\
      \;\;\;\;1\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 3 regimes
      2. if (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x)))) < -0.5

        1. Initial program 18.5%

          \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
        2. Add Preprocessing
        3. Step-by-step derivation
          1. lift-sqrt.f64N/A

            \[\leadsto \color{blue}{\sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}} \]
          2. pow1/2N/A

            \[\leadsto \color{blue}{{\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\frac{1}{2}}} \]
          3. metadata-evalN/A

            \[\leadsto {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\color{blue}{\left(2 \cdot \frac{1}{4}\right)}} \]
          4. metadata-evalN/A

            \[\leadsto {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(2 \cdot \color{blue}{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}\right)} \]
          5. pow-sqrN/A

            \[\leadsto \color{blue}{{\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)} \cdot {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
          6. pow-prod-downN/A

            \[\leadsto \color{blue}{{\left(\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right) \cdot \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
          7. lower-pow.f64N/A

            \[\leadsto \color{blue}{{\left(\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right) \cdot \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
        4. Applied rewrites18.5%

          \[\leadsto \color{blue}{{\left(\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p \cdot 4, p, x \cdot x\right)}}, 0.5, 0.5\right) \cdot \mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p \cdot 4, p, x \cdot x\right)}}, 0.5, 0.5\right)\right)}^{0.25}} \]
        5. Taylor expanded in x around -inf

          \[\leadsto \color{blue}{-1 \cdot \frac{p}{x}} \]
        6. Step-by-step derivation
          1. associate-*r/N/A

            \[\leadsto \color{blue}{\frac{-1 \cdot p}{x}} \]
          2. lower-/.f64N/A

            \[\leadsto \color{blue}{\frac{-1 \cdot p}{x}} \]
          3. mul-1-negN/A

            \[\leadsto \frac{\color{blue}{\mathsf{neg}\left(p\right)}}{x} \]
          4. lower-neg.f6480.1

            \[\leadsto \frac{\color{blue}{-p}}{x} \]
        7. Applied rewrites80.1%

          \[\leadsto \color{blue}{\frac{-p}{x}} \]

        if -0.5 < (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x)))) < 0.0200000000000000004

        1. Initial program 100.0%

          \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
        2. Add Preprocessing
        3. Taylor expanded in p around inf

          \[\leadsto \sqrt{\color{blue}{\frac{1}{2}}} \]
        4. Step-by-step derivation
          1. Applied rewrites98.5%

            \[\leadsto \sqrt{\color{blue}{0.5}} \]

          if 0.0200000000000000004 < (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x))))

          1. Initial program 100.0%

            \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
          2. Add Preprocessing
          3. Step-by-step derivation
            1. lift-sqrt.f64N/A

              \[\leadsto \color{blue}{\sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}} \]
            2. pow1/2N/A

              \[\leadsto \color{blue}{{\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\frac{1}{2}}} \]
            3. metadata-evalN/A

              \[\leadsto {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\color{blue}{\left(2 \cdot \frac{1}{4}\right)}} \]
            4. metadata-evalN/A

              \[\leadsto {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(2 \cdot \color{blue}{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}\right)} \]
            5. pow-sqrN/A

              \[\leadsto \color{blue}{{\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)} \cdot {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
            6. pow-prod-downN/A

              \[\leadsto \color{blue}{{\left(\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right) \cdot \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
            7. lower-pow.f64N/A

              \[\leadsto \color{blue}{{\left(\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right) \cdot \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
          4. Applied rewrites100.0%

            \[\leadsto \color{blue}{{\left(\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p \cdot 4, p, x \cdot x\right)}}, 0.5, 0.5\right) \cdot \mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p \cdot 4, p, x \cdot x\right)}}, 0.5, 0.5\right)\right)}^{0.25}} \]
          5. Taylor expanded in p around 0

            \[\leadsto \color{blue}{1} \]
          6. Step-by-step derivation
            1. Applied rewrites98.6%

              \[\leadsto \color{blue}{1} \]
          7. Recombined 3 regimes into one program.
          8. Final simplification94.9%

            \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{x}{\sqrt{x \cdot x + \left(p \cdot 4\right) \cdot p}} \leq -0.5:\\ \;\;\;\;\frac{-p}{x}\\ \mathbf{elif}\;\frac{x}{\sqrt{x \cdot x + \left(p \cdot 4\right) \cdot p}} \leq 0.02:\\ \;\;\;\;\sqrt{0.5}\\ \mathbf{else}:\\ \;\;\;\;1\\ \end{array} \]
          9. Add Preprocessing

          Alternative 5: 99.8% accurate, 0.6× speedup?

          \[\begin{array}{l} p_m = \left|p\right| \\ \begin{array}{l} \mathbf{if}\;\frac{x}{\sqrt{x \cdot x + \left(p\_m \cdot 4\right) \cdot p\_m}} \leq -0.9:\\ \;\;\;\;\frac{-p\_m}{x}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p\_m \cdot 4, p\_m, x \cdot x\right)}}, 0.5, 0.5\right)}\\ \end{array} \end{array} \]
          p_m = (fabs.f64 p)
          (FPCore (p_m x)
           :precision binary64
           (if (<= (/ x (sqrt (+ (* x x) (* (* p_m 4.0) p_m)))) -0.9)
             (/ (- p_m) x)
             (sqrt (fma (/ x (sqrt (fma (* p_m 4.0) p_m (* x x)))) 0.5 0.5))))
          p_m = fabs(p);
          double code(double p_m, double x) {
          	double tmp;
          	if ((x / sqrt(((x * x) + ((p_m * 4.0) * p_m)))) <= -0.9) {
          		tmp = -p_m / x;
          	} else {
          		tmp = sqrt(fma((x / sqrt(fma((p_m * 4.0), p_m, (x * x)))), 0.5, 0.5));
          	}
          	return tmp;
          }
          
          p_m = abs(p)
          function code(p_m, x)
          	tmp = 0.0
          	if (Float64(x / sqrt(Float64(Float64(x * x) + Float64(Float64(p_m * 4.0) * p_m)))) <= -0.9)
          		tmp = Float64(Float64(-p_m) / x);
          	else
          		tmp = sqrt(fma(Float64(x / sqrt(fma(Float64(p_m * 4.0), p_m, Float64(x * x)))), 0.5, 0.5));
          	end
          	return tmp
          end
          
          p_m = N[Abs[p], $MachinePrecision]
          code[p$95$m_, x_] := If[LessEqual[N[(x / N[Sqrt[N[(N[(x * x), $MachinePrecision] + N[(N[(p$95$m * 4.0), $MachinePrecision] * p$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], -0.9], N[((-p$95$m) / x), $MachinePrecision], N[Sqrt[N[(N[(x / N[Sqrt[N[(N[(p$95$m * 4.0), $MachinePrecision] * p$95$m + N[(x * x), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * 0.5 + 0.5), $MachinePrecision]], $MachinePrecision]]
          
          \begin{array}{l}
          p_m = \left|p\right|
          
          \\
          \begin{array}{l}
          \mathbf{if}\;\frac{x}{\sqrt{x \cdot x + \left(p\_m \cdot 4\right) \cdot p\_m}} \leq -0.9:\\
          \;\;\;\;\frac{-p\_m}{x}\\
          
          \mathbf{else}:\\
          \;\;\;\;\sqrt{\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p\_m \cdot 4, p\_m, x \cdot x\right)}}, 0.5, 0.5\right)}\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x)))) < -0.900000000000000022

            1. Initial program 16.9%

              \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
            2. Add Preprocessing
            3. Step-by-step derivation
              1. lift-sqrt.f64N/A

                \[\leadsto \color{blue}{\sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}} \]
              2. pow1/2N/A

                \[\leadsto \color{blue}{{\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\frac{1}{2}}} \]
              3. metadata-evalN/A

                \[\leadsto {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\color{blue}{\left(2 \cdot \frac{1}{4}\right)}} \]
              4. metadata-evalN/A

                \[\leadsto {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(2 \cdot \color{blue}{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}\right)} \]
              5. pow-sqrN/A

                \[\leadsto \color{blue}{{\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)} \cdot {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
              6. pow-prod-downN/A

                \[\leadsto \color{blue}{{\left(\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right) \cdot \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
              7. lower-pow.f64N/A

                \[\leadsto \color{blue}{{\left(\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right) \cdot \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
            4. Applied rewrites16.9%

              \[\leadsto \color{blue}{{\left(\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p \cdot 4, p, x \cdot x\right)}}, 0.5, 0.5\right) \cdot \mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p \cdot 4, p, x \cdot x\right)}}, 0.5, 0.5\right)\right)}^{0.25}} \]
            5. Taylor expanded in x around -inf

              \[\leadsto \color{blue}{-1 \cdot \frac{p}{x}} \]
            6. Step-by-step derivation
              1. associate-*r/N/A

                \[\leadsto \color{blue}{\frac{-1 \cdot p}{x}} \]
              2. lower-/.f64N/A

                \[\leadsto \color{blue}{\frac{-1 \cdot p}{x}} \]
              3. mul-1-negN/A

                \[\leadsto \frac{\color{blue}{\mathsf{neg}\left(p\right)}}{x} \]
              4. lower-neg.f6481.2

                \[\leadsto \frac{\color{blue}{-p}}{x} \]
            7. Applied rewrites81.2%

              \[\leadsto \color{blue}{\frac{-p}{x}} \]

            if -0.900000000000000022 < (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x))))

            1. Initial program 100.0%

              \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
            2. Add Preprocessing
            3. Step-by-step derivation
              1. lift-*.f64N/A

                \[\leadsto \sqrt{\color{blue}{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}} \]
              2. lift-+.f64N/A

                \[\leadsto \sqrt{\frac{1}{2} \cdot \color{blue}{\left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}} \]
              3. +-commutativeN/A

                \[\leadsto \sqrt{\frac{1}{2} \cdot \color{blue}{\left(\frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}} + 1\right)}} \]
              4. distribute-rgt-inN/A

                \[\leadsto \sqrt{\color{blue}{\frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}} \cdot \frac{1}{2} + 1 \cdot \frac{1}{2}}} \]
              5. metadata-evalN/A

                \[\leadsto \sqrt{\frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}} \cdot \frac{1}{2} + \color{blue}{\frac{1}{2}}} \]
              6. lower-fma.f64100.0

                \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}, 0.5, 0.5\right)}} \]
              7. lift-+.f64N/A

                \[\leadsto \sqrt{\mathsf{fma}\left(\frac{x}{\sqrt{\color{blue}{\left(4 \cdot p\right) \cdot p + x \cdot x}}}, \frac{1}{2}, \frac{1}{2}\right)} \]
              8. lift-*.f64N/A

                \[\leadsto \sqrt{\mathsf{fma}\left(\frac{x}{\sqrt{\color{blue}{\left(4 \cdot p\right) \cdot p} + x \cdot x}}, \frac{1}{2}, \frac{1}{2}\right)} \]
              9. lower-fma.f64100.0

                \[\leadsto \sqrt{\mathsf{fma}\left(\frac{x}{\sqrt{\color{blue}{\mathsf{fma}\left(4 \cdot p, p, x \cdot x\right)}}}, 0.5, 0.5\right)} \]
              10. lift-*.f64N/A

                \[\leadsto \sqrt{\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(\color{blue}{4 \cdot p}, p, x \cdot x\right)}}, \frac{1}{2}, \frac{1}{2}\right)} \]
              11. *-commutativeN/A

                \[\leadsto \sqrt{\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(\color{blue}{p \cdot 4}, p, x \cdot x\right)}}, \frac{1}{2}, \frac{1}{2}\right)} \]
              12. lower-*.f64100.0

                \[\leadsto \sqrt{\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(\color{blue}{p \cdot 4}, p, x \cdot x\right)}}, 0.5, 0.5\right)} \]
            4. Applied rewrites100.0%

              \[\leadsto \sqrt{\color{blue}{\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p \cdot 4, p, x \cdot x\right)}}, 0.5, 0.5\right)}} \]
          3. Recombined 2 regimes into one program.
          4. Final simplification96.4%

            \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{x}{\sqrt{x \cdot x + \left(p \cdot 4\right) \cdot p}} \leq -0.9:\\ \;\;\;\;\frac{-p}{x}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p \cdot 4, p, x \cdot x\right)}}, 0.5, 0.5\right)}\\ \end{array} \]
          5. Add Preprocessing

          Alternative 6: 98.5% accurate, 0.6× speedup?

          \[\begin{array}{l} p_m = \left|p\right| \\ \begin{array}{l} \mathbf{if}\;\frac{x}{\sqrt{x \cdot x + \left(p\_m \cdot 4\right) \cdot p\_m}} \leq -0.5:\\ \;\;\;\;\frac{-p\_m}{x}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\left(\frac{x}{\mathsf{fma}\left(\frac{2}{x}, p\_m \cdot p\_m, x\right)} + 1\right) \cdot 0.5}\\ \end{array} \end{array} \]
          p_m = (fabs.f64 p)
          (FPCore (p_m x)
           :precision binary64
           (if (<= (/ x (sqrt (+ (* x x) (* (* p_m 4.0) p_m)))) -0.5)
             (/ (- p_m) x)
             (sqrt (* (+ (/ x (fma (/ 2.0 x) (* p_m p_m) x)) 1.0) 0.5))))
          p_m = fabs(p);
          double code(double p_m, double x) {
          	double tmp;
          	if ((x / sqrt(((x * x) + ((p_m * 4.0) * p_m)))) <= -0.5) {
          		tmp = -p_m / x;
          	} else {
          		tmp = sqrt((((x / fma((2.0 / x), (p_m * p_m), x)) + 1.0) * 0.5));
          	}
          	return tmp;
          }
          
          p_m = abs(p)
          function code(p_m, x)
          	tmp = 0.0
          	if (Float64(x / sqrt(Float64(Float64(x * x) + Float64(Float64(p_m * 4.0) * p_m)))) <= -0.5)
          		tmp = Float64(Float64(-p_m) / x);
          	else
          		tmp = sqrt(Float64(Float64(Float64(x / fma(Float64(2.0 / x), Float64(p_m * p_m), x)) + 1.0) * 0.5));
          	end
          	return tmp
          end
          
          p_m = N[Abs[p], $MachinePrecision]
          code[p$95$m_, x_] := If[LessEqual[N[(x / N[Sqrt[N[(N[(x * x), $MachinePrecision] + N[(N[(p$95$m * 4.0), $MachinePrecision] * p$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], -0.5], N[((-p$95$m) / x), $MachinePrecision], N[Sqrt[N[(N[(N[(x / N[(N[(2.0 / x), $MachinePrecision] * N[(p$95$m * p$95$m), $MachinePrecision] + x), $MachinePrecision]), $MachinePrecision] + 1.0), $MachinePrecision] * 0.5), $MachinePrecision]], $MachinePrecision]]
          
          \begin{array}{l}
          p_m = \left|p\right|
          
          \\
          \begin{array}{l}
          \mathbf{if}\;\frac{x}{\sqrt{x \cdot x + \left(p\_m \cdot 4\right) \cdot p\_m}} \leq -0.5:\\
          \;\;\;\;\frac{-p\_m}{x}\\
          
          \mathbf{else}:\\
          \;\;\;\;\sqrt{\left(\frac{x}{\mathsf{fma}\left(\frac{2}{x}, p\_m \cdot p\_m, x\right)} + 1\right) \cdot 0.5}\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x)))) < -0.5

            1. Initial program 18.5%

              \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
            2. Add Preprocessing
            3. Step-by-step derivation
              1. lift-sqrt.f64N/A

                \[\leadsto \color{blue}{\sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}} \]
              2. pow1/2N/A

                \[\leadsto \color{blue}{{\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\frac{1}{2}}} \]
              3. metadata-evalN/A

                \[\leadsto {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\color{blue}{\left(2 \cdot \frac{1}{4}\right)}} \]
              4. metadata-evalN/A

                \[\leadsto {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(2 \cdot \color{blue}{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}\right)} \]
              5. pow-sqrN/A

                \[\leadsto \color{blue}{{\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)} \cdot {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
              6. pow-prod-downN/A

                \[\leadsto \color{blue}{{\left(\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right) \cdot \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
              7. lower-pow.f64N/A

                \[\leadsto \color{blue}{{\left(\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right) \cdot \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
            4. Applied rewrites18.5%

              \[\leadsto \color{blue}{{\left(\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p \cdot 4, p, x \cdot x\right)}}, 0.5, 0.5\right) \cdot \mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p \cdot 4, p, x \cdot x\right)}}, 0.5, 0.5\right)\right)}^{0.25}} \]
            5. Taylor expanded in x around -inf

              \[\leadsto \color{blue}{-1 \cdot \frac{p}{x}} \]
            6. Step-by-step derivation
              1. associate-*r/N/A

                \[\leadsto \color{blue}{\frac{-1 \cdot p}{x}} \]
              2. lower-/.f64N/A

                \[\leadsto \color{blue}{\frac{-1 \cdot p}{x}} \]
              3. mul-1-negN/A

                \[\leadsto \frac{\color{blue}{\mathsf{neg}\left(p\right)}}{x} \]
              4. lower-neg.f6480.1

                \[\leadsto \frac{\color{blue}{-p}}{x} \]
            7. Applied rewrites80.1%

              \[\leadsto \color{blue}{\frac{-p}{x}} \]

            if -0.5 < (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x))))

            1. Initial program 100.0%

              \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
            2. Add Preprocessing
            3. Taylor expanded in p around 0

              \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\color{blue}{x + 2 \cdot \frac{{p}^{2}}{x}}}\right)} \]
            4. Step-by-step derivation
              1. +-commutativeN/A

                \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\color{blue}{2 \cdot \frac{{p}^{2}}{x} + x}}\right)} \]
              2. associate-*r/N/A

                \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\color{blue}{\frac{2 \cdot {p}^{2}}{x}} + x}\right)} \]
              3. associate-*l/N/A

                \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\color{blue}{\frac{2}{x} \cdot {p}^{2}} + x}\right)} \]
              4. metadata-evalN/A

                \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\frac{\color{blue}{2 \cdot 1}}{x} \cdot {p}^{2} + x}\right)} \]
              5. associate-*r/N/A

                \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\color{blue}{\left(2 \cdot \frac{1}{x}\right)} \cdot {p}^{2} + x}\right)} \]
              6. lower-fma.f64N/A

                \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\color{blue}{\mathsf{fma}\left(2 \cdot \frac{1}{x}, {p}^{2}, x\right)}}\right)} \]
              7. associate-*r/N/A

                \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\mathsf{fma}\left(\color{blue}{\frac{2 \cdot 1}{x}}, {p}^{2}, x\right)}\right)} \]
              8. metadata-evalN/A

                \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\mathsf{fma}\left(\frac{\color{blue}{2}}{x}, {p}^{2}, x\right)}\right)} \]
              9. lower-/.f64N/A

                \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\mathsf{fma}\left(\color{blue}{\frac{2}{x}}, {p}^{2}, x\right)}\right)} \]
              10. unpow2N/A

                \[\leadsto \sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\mathsf{fma}\left(\frac{2}{x}, \color{blue}{p \cdot p}, x\right)}\right)} \]
              11. lower-*.f6499.0

                \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\mathsf{fma}\left(\frac{2}{x}, \color{blue}{p \cdot p}, x\right)}\right)} \]
            5. Applied rewrites99.0%

              \[\leadsto \sqrt{0.5 \cdot \left(1 + \frac{x}{\color{blue}{\mathsf{fma}\left(\frac{2}{x}, p \cdot p, x\right)}}\right)} \]
          3. Recombined 2 regimes into one program.
          4. Final simplification95.3%

            \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{x}{\sqrt{x \cdot x + \left(p \cdot 4\right) \cdot p}} \leq -0.5:\\ \;\;\;\;\frac{-p}{x}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\left(\frac{x}{\mathsf{fma}\left(\frac{2}{x}, p \cdot p, x\right)} + 1\right) \cdot 0.5}\\ \end{array} \]
          5. Add Preprocessing

          Alternative 7: 75.1% accurate, 1.0× speedup?

          \[\begin{array}{l} p_m = \left|p\right| \\ \begin{array}{l} \mathbf{if}\;\frac{x}{\sqrt{x \cdot x + \left(p\_m \cdot 4\right) \cdot p\_m}} \leq 0.46:\\ \;\;\;\;\sqrt{0.5}\\ \mathbf{else}:\\ \;\;\;\;1\\ \end{array} \end{array} \]
          p_m = (fabs.f64 p)
          (FPCore (p_m x)
           :precision binary64
           (if (<= (/ x (sqrt (+ (* x x) (* (* p_m 4.0) p_m)))) 0.46) (sqrt 0.5) 1.0))
          p_m = fabs(p);
          double code(double p_m, double x) {
          	double tmp;
          	if ((x / sqrt(((x * x) + ((p_m * 4.0) * p_m)))) <= 0.46) {
          		tmp = sqrt(0.5);
          	} else {
          		tmp = 1.0;
          	}
          	return tmp;
          }
          
          p_m = abs(p)
          real(8) function code(p_m, x)
              real(8), intent (in) :: p_m
              real(8), intent (in) :: x
              real(8) :: tmp
              if ((x / sqrt(((x * x) + ((p_m * 4.0d0) * p_m)))) <= 0.46d0) then
                  tmp = sqrt(0.5d0)
              else
                  tmp = 1.0d0
              end if
              code = tmp
          end function
          
          p_m = Math.abs(p);
          public static double code(double p_m, double x) {
          	double tmp;
          	if ((x / Math.sqrt(((x * x) + ((p_m * 4.0) * p_m)))) <= 0.46) {
          		tmp = Math.sqrt(0.5);
          	} else {
          		tmp = 1.0;
          	}
          	return tmp;
          }
          
          p_m = math.fabs(p)
          def code(p_m, x):
          	tmp = 0
          	if (x / math.sqrt(((x * x) + ((p_m * 4.0) * p_m)))) <= 0.46:
          		tmp = math.sqrt(0.5)
          	else:
          		tmp = 1.0
          	return tmp
          
          p_m = abs(p)
          function code(p_m, x)
          	tmp = 0.0
          	if (Float64(x / sqrt(Float64(Float64(x * x) + Float64(Float64(p_m * 4.0) * p_m)))) <= 0.46)
          		tmp = sqrt(0.5);
          	else
          		tmp = 1.0;
          	end
          	return tmp
          end
          
          p_m = abs(p);
          function tmp_2 = code(p_m, x)
          	tmp = 0.0;
          	if ((x / sqrt(((x * x) + ((p_m * 4.0) * p_m)))) <= 0.46)
          		tmp = sqrt(0.5);
          	else
          		tmp = 1.0;
          	end
          	tmp_2 = tmp;
          end
          
          p_m = N[Abs[p], $MachinePrecision]
          code[p$95$m_, x_] := If[LessEqual[N[(x / N[Sqrt[N[(N[(x * x), $MachinePrecision] + N[(N[(p$95$m * 4.0), $MachinePrecision] * p$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 0.46], N[Sqrt[0.5], $MachinePrecision], 1.0]
          
          \begin{array}{l}
          p_m = \left|p\right|
          
          \\
          \begin{array}{l}
          \mathbf{if}\;\frac{x}{\sqrt{x \cdot x + \left(p\_m \cdot 4\right) \cdot p\_m}} \leq 0.46:\\
          \;\;\;\;\sqrt{0.5}\\
          
          \mathbf{else}:\\
          \;\;\;\;1\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x)))) < 0.46000000000000002

            1. Initial program 77.9%

              \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
            2. Add Preprocessing
            3. Taylor expanded in p around inf

              \[\leadsto \sqrt{\color{blue}{\frac{1}{2}}} \]
            4. Step-by-step derivation
              1. Applied rewrites73.3%

                \[\leadsto \sqrt{\color{blue}{0.5}} \]

              if 0.46000000000000002 < (/.f64 x (sqrt.f64 (+.f64 (*.f64 (*.f64 #s(literal 4 binary64) p) p) (*.f64 x x))))

              1. Initial program 100.0%

                \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
              2. Add Preprocessing
              3. Step-by-step derivation
                1. lift-sqrt.f64N/A

                  \[\leadsto \color{blue}{\sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}} \]
                2. pow1/2N/A

                  \[\leadsto \color{blue}{{\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\frac{1}{2}}} \]
                3. metadata-evalN/A

                  \[\leadsto {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\color{blue}{\left(2 \cdot \frac{1}{4}\right)}} \]
                4. metadata-evalN/A

                  \[\leadsto {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(2 \cdot \color{blue}{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}\right)} \]
                5. pow-sqrN/A

                  \[\leadsto \color{blue}{{\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)} \cdot {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
                6. pow-prod-downN/A

                  \[\leadsto \color{blue}{{\left(\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right) \cdot \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
                7. lower-pow.f64N/A

                  \[\leadsto \color{blue}{{\left(\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right) \cdot \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
              4. Applied rewrites100.0%

                \[\leadsto \color{blue}{{\left(\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p \cdot 4, p, x \cdot x\right)}}, 0.5, 0.5\right) \cdot \mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p \cdot 4, p, x \cdot x\right)}}, 0.5, 0.5\right)\right)}^{0.25}} \]
              5. Taylor expanded in p around 0

                \[\leadsto \color{blue}{1} \]
              6. Step-by-step derivation
                1. Applied rewrites98.6%

                  \[\leadsto \color{blue}{1} \]
              7. Recombined 2 regimes into one program.
              8. Final simplification80.4%

                \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{x}{\sqrt{x \cdot x + \left(p \cdot 4\right) \cdot p}} \leq 0.46:\\ \;\;\;\;\sqrt{0.5}\\ \mathbf{else}:\\ \;\;\;\;1\\ \end{array} \]
              9. Add Preprocessing

              Alternative 8: 35.9% accurate, 58.0× speedup?

              \[\begin{array}{l} p_m = \left|p\right| \\ 1 \end{array} \]
              p_m = (fabs.f64 p)
              (FPCore (p_m x) :precision binary64 1.0)
              p_m = fabs(p);
              double code(double p_m, double x) {
              	return 1.0;
              }
              
              p_m = abs(p)
              real(8) function code(p_m, x)
                  real(8), intent (in) :: p_m
                  real(8), intent (in) :: x
                  code = 1.0d0
              end function
              
              p_m = Math.abs(p);
              public static double code(double p_m, double x) {
              	return 1.0;
              }
              
              p_m = math.fabs(p)
              def code(p_m, x):
              	return 1.0
              
              p_m = abs(p)
              function code(p_m, x)
              	return 1.0
              end
              
              p_m = abs(p);
              function tmp = code(p_m, x)
              	tmp = 1.0;
              end
              
              p_m = N[Abs[p], $MachinePrecision]
              code[p$95$m_, x_] := 1.0
              
              \begin{array}{l}
              p_m = \left|p\right|
              
              \\
              1
              \end{array}
              
              Derivation
              1. Initial program 84.1%

                \[\sqrt{0.5 \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)} \]
              2. Add Preprocessing
              3. Step-by-step derivation
                1. lift-sqrt.f64N/A

                  \[\leadsto \color{blue}{\sqrt{\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)}} \]
                2. pow1/2N/A

                  \[\leadsto \color{blue}{{\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\frac{1}{2}}} \]
                3. metadata-evalN/A

                  \[\leadsto {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\color{blue}{\left(2 \cdot \frac{1}{4}\right)}} \]
                4. metadata-evalN/A

                  \[\leadsto {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(2 \cdot \color{blue}{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}\right)} \]
                5. pow-sqrN/A

                  \[\leadsto \color{blue}{{\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)} \cdot {\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
                6. pow-prod-downN/A

                  \[\leadsto \color{blue}{{\left(\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right) \cdot \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
                7. lower-pow.f64N/A

                  \[\leadsto \color{blue}{{\left(\left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right) \cdot \left(\frac{1}{2} \cdot \left(1 + \frac{x}{\sqrt{\left(4 \cdot p\right) \cdot p + x \cdot x}}\right)\right)\right)}^{\left(\frac{1}{2} \cdot \frac{1}{2}\right)}} \]
              4. Applied rewrites84.1%

                \[\leadsto \color{blue}{{\left(\mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p \cdot 4, p, x \cdot x\right)}}, 0.5, 0.5\right) \cdot \mathsf{fma}\left(\frac{x}{\sqrt{\mathsf{fma}\left(p \cdot 4, p, x \cdot x\right)}}, 0.5, 0.5\right)\right)}^{0.25}} \]
              5. Taylor expanded in p around 0

                \[\leadsto \color{blue}{1} \]
              6. Step-by-step derivation
                1. Applied rewrites39.3%

                  \[\leadsto \color{blue}{1} \]
                2. Add Preprocessing

                Developer Target 1: 79.1% accurate, 0.2× speedup?

                \[\begin{array}{l} \\ \sqrt{0.5 + \frac{\mathsf{copysign}\left(0.5, x\right)}{\mathsf{hypot}\left(1, \frac{2 \cdot p}{x}\right)}} \end{array} \]
                (FPCore (p x)
                 :precision binary64
                 (sqrt (+ 0.5 (/ (copysign 0.5 x) (hypot 1.0 (/ (* 2.0 p) x))))))
                double code(double p, double x) {
                	return sqrt((0.5 + (copysign(0.5, x) / hypot(1.0, ((2.0 * p) / x)))));
                }
                
                public static double code(double p, double x) {
                	return Math.sqrt((0.5 + (Math.copySign(0.5, x) / Math.hypot(1.0, ((2.0 * p) / x)))));
                }
                
                def code(p, x):
                	return math.sqrt((0.5 + (math.copysign(0.5, x) / math.hypot(1.0, ((2.0 * p) / x)))))
                
                function code(p, x)
                	return sqrt(Float64(0.5 + Float64(copysign(0.5, x) / hypot(1.0, Float64(Float64(2.0 * p) / x)))))
                end
                
                function tmp = code(p, x)
                	tmp = sqrt((0.5 + ((sign(x) * abs(0.5)) / hypot(1.0, ((2.0 * p) / x)))));
                end
                
                code[p_, x_] := N[Sqrt[N[(0.5 + N[(N[With[{TMP1 = Abs[0.5], TMP2 = Sign[x]}, TMP1 * If[TMP2 == 0, 1, TMP2]], $MachinePrecision] / N[Sqrt[1.0 ^ 2 + N[(N[(2.0 * p), $MachinePrecision] / x), $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
                
                \begin{array}{l}
                
                \\
                \sqrt{0.5 + \frac{\mathsf{copysign}\left(0.5, x\right)}{\mathsf{hypot}\left(1, \frac{2 \cdot p}{x}\right)}}
                \end{array}
                

                Reproduce

                ?
                herbie shell --seed 2024242 
                (FPCore (p x)
                  :name "Given's Rotation SVD example"
                  :precision binary64
                  :pre (and (< 1e-150 (fabs x)) (< (fabs x) 1e+150))
                
                  :alt
                  (! :herbie-platform default (sqrt (+ 1/2 (/ (copysign 1/2 x) (hypot 1 (/ (* 2 p) x))))))
                
                  (sqrt (* 0.5 (+ 1.0 (/ x (sqrt (+ (* (* 4.0 p) p) (* x x))))))))