2nthrt (problem 3.4.6)

Percentage Accurate: 53.8% → 92.3%
Time: 23.8s
Alternatives: 14
Speedup: 1.9×

Specification

?
\[\begin{array}{l} \\ {\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \end{array} \]
(FPCore (x n)
 :precision binary64
 (- (pow (+ x 1.0) (/ 1.0 n)) (pow x (/ 1.0 n))))
double code(double x, double n) {
	return pow((x + 1.0), (1.0 / n)) - pow(x, (1.0 / n));
}
real(8) function code(x, n)
    real(8), intent (in) :: x
    real(8), intent (in) :: n
    code = ((x + 1.0d0) ** (1.0d0 / n)) - (x ** (1.0d0 / n))
end function
public static double code(double x, double n) {
	return Math.pow((x + 1.0), (1.0 / n)) - Math.pow(x, (1.0 / n));
}
def code(x, n):
	return math.pow((x + 1.0), (1.0 / n)) - math.pow(x, (1.0 / n))
function code(x, n)
	return Float64((Float64(x + 1.0) ^ Float64(1.0 / n)) - (x ^ Float64(1.0 / n)))
end
function tmp = code(x, n)
	tmp = ((x + 1.0) ^ (1.0 / n)) - (x ^ (1.0 / n));
end
code[x_, n_] := N[(N[Power[N[(x + 1.0), $MachinePrecision], N[(1.0 / n), $MachinePrecision]], $MachinePrecision] - N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 14 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 53.8% accurate, 1.0× speedup?

\[\begin{array}{l} \\ {\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \end{array} \]
(FPCore (x n)
 :precision binary64
 (- (pow (+ x 1.0) (/ 1.0 n)) (pow x (/ 1.0 n))))
double code(double x, double n) {
	return pow((x + 1.0), (1.0 / n)) - pow(x, (1.0 / n));
}
real(8) function code(x, n)
    real(8), intent (in) :: x
    real(8), intent (in) :: n
    code = ((x + 1.0d0) ** (1.0d0 / n)) - (x ** (1.0d0 / n))
end function
public static double code(double x, double n) {
	return Math.pow((x + 1.0), (1.0 / n)) - Math.pow(x, (1.0 / n));
}
def code(x, n):
	return math.pow((x + 1.0), (1.0 / n)) - math.pow(x, (1.0 / n))
function code(x, n)
	return Float64((Float64(x + 1.0) ^ Float64(1.0 / n)) - (x ^ Float64(1.0 / n)))
end
function tmp = code(x, n)
	tmp = ((x + 1.0) ^ (1.0 / n)) - (x ^ (1.0 / n));
end
code[x_, n_] := N[(N[Power[N[(x + 1.0), $MachinePrecision], N[(1.0 / n), $MachinePrecision]], $MachinePrecision] - N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)}
\end{array}

Alternative 1: 92.3% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 1:\\ \;\;\;\;\frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}\\ \end{array} \end{array} \]
(FPCore (x n)
 :precision binary64
 (if (<= x 1.0)
   (- (/ x n) (expm1 (/ (log x) n)))
   (/ (/ (pow x (/ 1.0 n)) x) n)))
double code(double x, double n) {
	double tmp;
	if (x <= 1.0) {
		tmp = (x / n) - expm1((log(x) / n));
	} else {
		tmp = (pow(x, (1.0 / n)) / x) / n;
	}
	return tmp;
}
public static double code(double x, double n) {
	double tmp;
	if (x <= 1.0) {
		tmp = (x / n) - Math.expm1((Math.log(x) / n));
	} else {
		tmp = (Math.pow(x, (1.0 / n)) / x) / n;
	}
	return tmp;
}
def code(x, n):
	tmp = 0
	if x <= 1.0:
		tmp = (x / n) - math.expm1((math.log(x) / n))
	else:
		tmp = (math.pow(x, (1.0 / n)) / x) / n
	return tmp
function code(x, n)
	tmp = 0.0
	if (x <= 1.0)
		tmp = Float64(Float64(x / n) - expm1(Float64(log(x) / n)));
	else
		tmp = Float64(Float64((x ^ Float64(1.0 / n)) / x) / n);
	end
	return tmp
end
code[x_, n_] := If[LessEqual[x, 1.0], N[(N[(x / n), $MachinePrecision] - N[(Exp[N[(N[Log[x], $MachinePrecision] / n), $MachinePrecision]] - 1), $MachinePrecision]), $MachinePrecision], N[(N[(N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision] / x), $MachinePrecision] / n), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;x \leq 1:\\
\;\;\;\;\frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)\\

\mathbf{else}:\\
\;\;\;\;\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if x < 1

    1. Initial program 48.6%

      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in x around 0

      \[\leadsto \color{blue}{\left(1 + \frac{x}{n}\right) - e^{\frac{\log x}{n}}} \]
    4. Step-by-step derivation
      1. associate--l+N/A

        \[\leadsto \color{blue}{1 + \left(\frac{x}{n} - e^{\frac{\log x}{n}}\right)} \]
      2. +-commutativeN/A

        \[\leadsto \color{blue}{\left(\frac{x}{n} - e^{\frac{\log x}{n}}\right) + 1} \]
      3. *-rgt-identityN/A

        \[\leadsto \left(\frac{\color{blue}{x \cdot 1}}{n} - e^{\frac{\log x}{n}}\right) + 1 \]
      4. associate-*r/N/A

        \[\leadsto \left(\color{blue}{x \cdot \frac{1}{n}} - e^{\frac{\log x}{n}}\right) + 1 \]
      5. remove-double-negN/A

        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\frac{\color{blue}{\mathsf{neg}\left(\left(\mathsf{neg}\left(\log x\right)\right)\right)}}{n}}\right) + 1 \]
      6. mul-1-negN/A

        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\frac{\mathsf{neg}\left(\color{blue}{-1 \cdot \log x}\right)}{n}}\right) + 1 \]
      7. distribute-neg-fracN/A

        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\color{blue}{\mathsf{neg}\left(\frac{-1 \cdot \log x}{n}\right)}}\right) + 1 \]
      8. mul-1-negN/A

        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\mathsf{neg}\left(\frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}\right)}\right) + 1 \]
      9. log-recN/A

        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\mathsf{neg}\left(\frac{\color{blue}{\log \left(\frac{1}{x}\right)}}{n}\right)}\right) + 1 \]
      10. mul-1-negN/A

        \[\leadsto \left(x \cdot \frac{1}{n} - e^{\color{blue}{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}\right) + 1 \]
      11. associate-+l-N/A

        \[\leadsto \color{blue}{x \cdot \frac{1}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right)} \]
      12. lower--.f64N/A

        \[\leadsto \color{blue}{x \cdot \frac{1}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right)} \]
      13. associate-*r/N/A

        \[\leadsto \color{blue}{\frac{x \cdot 1}{n}} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
      14. *-rgt-identityN/A

        \[\leadsto \frac{\color{blue}{x}}{n} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
      15. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{x}{n}} - \left(e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}} - 1\right) \]
      16. lower-expm1.f64N/A

        \[\leadsto \frac{x}{n} - \color{blue}{\mathsf{expm1}\left(-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}\right)} \]
      17. mul-1-negN/A

        \[\leadsto \frac{x}{n} - \mathsf{expm1}\left(\color{blue}{\mathsf{neg}\left(\frac{\log \left(\frac{1}{x}\right)}{n}\right)}\right) \]
    5. Applied rewrites87.8%

      \[\leadsto \color{blue}{\frac{x}{n} - \mathsf{expm1}\left(\frac{\log x}{n}\right)} \]

    if 1 < x

    1. Initial program 73.1%

      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in x around inf

      \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
    4. Step-by-step derivation
      1. associate-/l/N/A

        \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
      2. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
      3. lower-/.f64N/A

        \[\leadsto \frac{\color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}}{n} \]
      4. log-recN/A

        \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{x}}{n} \]
      5. mul-1-negN/A

        \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{x}}{n} \]
      6. associate-*r/N/A

        \[\leadsto \frac{\frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{x}}{n} \]
      7. associate-*r*N/A

        \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{x}}{n} \]
      8. metadata-evalN/A

        \[\leadsto \frac{\frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{x}}{n} \]
      9. *-commutativeN/A

        \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{x}}{n} \]
      10. associate-/l*N/A

        \[\leadsto \frac{\frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{x}}{n} \]
      11. exp-to-powN/A

        \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
      12. lower-pow.f64N/A

        \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
      13. lower-/.f6499.6

        \[\leadsto \frac{\frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{x}}{n} \]
    5. Applied rewrites99.6%

      \[\leadsto \color{blue}{\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}} \]
  3. Recombined 2 regimes into one program.
  4. Add Preprocessing

Alternative 2: 81.1% accurate, 0.9× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := {x}^{\left(\frac{1}{n}\right)}\\ \mathbf{if}\;\frac{1}{n} \leq -5 \cdot 10^{-134}:\\ \;\;\;\;\frac{\frac{t\_0}{x}}{n}\\ \mathbf{elif}\;\frac{1}{n} \leq 4 \cdot 10^{-90}:\\ \;\;\;\;\frac{\mathsf{log1p}\left(x\right) - \log x}{n}\\ \mathbf{elif}\;\frac{1}{n} \leq 4 \cdot 10^{-13}:\\ \;\;\;\;\frac{\frac{1}{x} + \frac{\frac{\log x}{n}}{x}}{n}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, x, \frac{1}{n}\right), x, 1\right) - t\_0\\ \end{array} \end{array} \]
(FPCore (x n)
 :precision binary64
 (let* ((t_0 (pow x (/ 1.0 n))))
   (if (<= (/ 1.0 n) -5e-134)
     (/ (/ t_0 x) n)
     (if (<= (/ 1.0 n) 4e-90)
       (/ (- (log1p x) (log x)) n)
       (if (<= (/ 1.0 n) 4e-13)
         (/ (+ (/ 1.0 x) (/ (/ (log x) n) x)) n)
         (-
          (fma (fma (- (/ 0.5 (* n n)) (/ 0.5 n)) x (/ 1.0 n)) x 1.0)
          t_0))))))
double code(double x, double n) {
	double t_0 = pow(x, (1.0 / n));
	double tmp;
	if ((1.0 / n) <= -5e-134) {
		tmp = (t_0 / x) / n;
	} else if ((1.0 / n) <= 4e-90) {
		tmp = (log1p(x) - log(x)) / n;
	} else if ((1.0 / n) <= 4e-13) {
		tmp = ((1.0 / x) + ((log(x) / n) / x)) / n;
	} else {
		tmp = fma(fma(((0.5 / (n * n)) - (0.5 / n)), x, (1.0 / n)), x, 1.0) - t_0;
	}
	return tmp;
}
function code(x, n)
	t_0 = x ^ Float64(1.0 / n)
	tmp = 0.0
	if (Float64(1.0 / n) <= -5e-134)
		tmp = Float64(Float64(t_0 / x) / n);
	elseif (Float64(1.0 / n) <= 4e-90)
		tmp = Float64(Float64(log1p(x) - log(x)) / n);
	elseif (Float64(1.0 / n) <= 4e-13)
		tmp = Float64(Float64(Float64(1.0 / x) + Float64(Float64(log(x) / n) / x)) / n);
	else
		tmp = Float64(fma(fma(Float64(Float64(0.5 / Float64(n * n)) - Float64(0.5 / n)), x, Float64(1.0 / n)), x, 1.0) - t_0);
	end
	return tmp
end
code[x_, n_] := Block[{t$95$0 = N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[N[(1.0 / n), $MachinePrecision], -5e-134], N[(N[(t$95$0 / x), $MachinePrecision] / n), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 4e-90], N[(N[(N[Log[1 + x], $MachinePrecision] - N[Log[x], $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 4e-13], N[(N[(N[(1.0 / x), $MachinePrecision] + N[(N[(N[Log[x], $MachinePrecision] / n), $MachinePrecision] / x), $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision], N[(N[(N[(N[(N[(0.5 / N[(n * n), $MachinePrecision]), $MachinePrecision] - N[(0.5 / n), $MachinePrecision]), $MachinePrecision] * x + N[(1.0 / n), $MachinePrecision]), $MachinePrecision] * x + 1.0), $MachinePrecision] - t$95$0), $MachinePrecision]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {x}^{\left(\frac{1}{n}\right)}\\
\mathbf{if}\;\frac{1}{n} \leq -5 \cdot 10^{-134}:\\
\;\;\;\;\frac{\frac{t\_0}{x}}{n}\\

\mathbf{elif}\;\frac{1}{n} \leq 4 \cdot 10^{-90}:\\
\;\;\;\;\frac{\mathsf{log1p}\left(x\right) - \log x}{n}\\

\mathbf{elif}\;\frac{1}{n} \leq 4 \cdot 10^{-13}:\\
\;\;\;\;\frac{\frac{1}{x} + \frac{\frac{\log x}{n}}{x}}{n}\\

\mathbf{else}:\\
\;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, x, \frac{1}{n}\right), x, 1\right) - t\_0\\


\end{array}
\end{array}
Derivation
  1. Split input into 4 regimes
  2. if (/.f64 #s(literal 1 binary64) n) < -5.0000000000000003e-134

    1. Initial program 79.9%

      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in x around inf

      \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
    4. Step-by-step derivation
      1. associate-/l/N/A

        \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
      2. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
      3. lower-/.f64N/A

        \[\leadsto \frac{\color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}}{n} \]
      4. log-recN/A

        \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{x}}{n} \]
      5. mul-1-negN/A

        \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{x}}{n} \]
      6. associate-*r/N/A

        \[\leadsto \frac{\frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{x}}{n} \]
      7. associate-*r*N/A

        \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{x}}{n} \]
      8. metadata-evalN/A

        \[\leadsto \frac{\frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{x}}{n} \]
      9. *-commutativeN/A

        \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{x}}{n} \]
      10. associate-/l*N/A

        \[\leadsto \frac{\frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{x}}{n} \]
      11. exp-to-powN/A

        \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
      12. lower-pow.f64N/A

        \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
      13. lower-/.f6490.1

        \[\leadsto \frac{\frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{x}}{n} \]
    5. Applied rewrites90.1%

      \[\leadsto \color{blue}{\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}} \]

    if -5.0000000000000003e-134 < (/.f64 #s(literal 1 binary64) n) < 3.99999999999999998e-90

    1. Initial program 38.4%

      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in n around inf

      \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
    4. Step-by-step derivation
      1. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
      2. lower--.f64N/A

        \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
      3. lower-log1p.f64N/A

        \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
      4. lower-log.f6488.6

        \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
    5. Applied rewrites88.6%

      \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]

    if 3.99999999999999998e-90 < (/.f64 #s(literal 1 binary64) n) < 4.0000000000000001e-13

    1. Initial program 7.8%

      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
    2. Add Preprocessing
    3. Taylor expanded in x around inf

      \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
    4. Step-by-step derivation
      1. associate-/l/N/A

        \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
      2. lower-/.f64N/A

        \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
      3. lower-/.f64N/A

        \[\leadsto \frac{\color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}}{n} \]
      4. log-recN/A

        \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{x}}{n} \]
      5. mul-1-negN/A

        \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{x}}{n} \]
      6. associate-*r/N/A

        \[\leadsto \frac{\frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{x}}{n} \]
      7. associate-*r*N/A

        \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{x}}{n} \]
      8. metadata-evalN/A

        \[\leadsto \frac{\frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{x}}{n} \]
      9. *-commutativeN/A

        \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{x}}{n} \]
      10. associate-/l*N/A

        \[\leadsto \frac{\frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{x}}{n} \]
      11. exp-to-powN/A

        \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
      12. lower-pow.f64N/A

        \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
      13. lower-/.f6472.0

        \[\leadsto \frac{\frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{x}}{n} \]
    5. Applied rewrites72.0%

      \[\leadsto \color{blue}{\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}} \]
    6. Taylor expanded in n around inf

      \[\leadsto \frac{\frac{1}{x} + \frac{\log x}{n \cdot x}}{n} \]
    7. Step-by-step derivation
      1. Applied rewrites72.1%

        \[\leadsto \frac{\frac{\frac{\log x}{n}}{x} + \frac{1}{x}}{n} \]

      if 4.0000000000000001e-13 < (/.f64 #s(literal 1 binary64) n)

      1. Initial program 63.6%

        \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
      2. Add Preprocessing
      3. Taylor expanded in x around 0

        \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right)} - {x}^{\left(\frac{1}{n}\right)} \]
      4. Step-by-step derivation
        1. +-commutativeN/A

          \[\leadsto \color{blue}{\left(x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) + 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
        2. *-commutativeN/A

          \[\leadsto \left(\color{blue}{\left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) \cdot x} + 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
        3. lower-fma.f64N/A

          \[\leadsto \color{blue}{\mathsf{fma}\left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}, x, 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
        4. *-commutativeN/A

          \[\leadsto \mathsf{fma}\left(\color{blue}{\left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) \cdot x} + \frac{1}{n}, x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
        5. lower-fma.f64N/A

          \[\leadsto \mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right)}, x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
        6. lower--.f64N/A

          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
        7. associate-*r/N/A

          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\frac{\frac{1}{2} \cdot 1}{{n}^{2}}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
        8. metadata-evalN/A

          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\color{blue}{\frac{1}{2}}}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
        9. lower-/.f64N/A

          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\frac{\frac{1}{2}}{{n}^{2}}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
        10. unpow2N/A

          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{\color{blue}{n \cdot n}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
        11. lower-*.f64N/A

          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{\color{blue}{n \cdot n}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
        12. associate-*r/N/A

          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{n \cdot n} - \color{blue}{\frac{\frac{1}{2} \cdot 1}{n}}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
        13. metadata-evalN/A

          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{n \cdot n} - \frac{\color{blue}{\frac{1}{2}}}{n}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
        14. lower-/.f64N/A

          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{n \cdot n} - \color{blue}{\frac{\frac{1}{2}}{n}}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
        15. lower-/.f6469.5

          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, x, \color{blue}{\frac{1}{n}}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
      5. Applied rewrites69.5%

        \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, x, \frac{1}{n}\right), x, 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
    8. Recombined 4 regimes into one program.
    9. Final simplification85.3%

      \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{1}{n} \leq -5 \cdot 10^{-134}:\\ \;\;\;\;\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}\\ \mathbf{elif}\;\frac{1}{n} \leq 4 \cdot 10^{-90}:\\ \;\;\;\;\frac{\mathsf{log1p}\left(x\right) - \log x}{n}\\ \mathbf{elif}\;\frac{1}{n} \leq 4 \cdot 10^{-13}:\\ \;\;\;\;\frac{\frac{1}{x} + \frac{\frac{\log x}{n}}{x}}{n}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, x, \frac{1}{n}\right), x, 1\right) - {x}^{\left(\frac{1}{n}\right)}\\ \end{array} \]
    10. Add Preprocessing

    Alternative 3: 72.2% accurate, 1.6× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} t_0 := {x}^{\left(\frac{1}{n}\right)}\\ \mathbf{if}\;x \leq 5.8 \cdot 10^{-227}:\\ \;\;\;\;\left(\frac{x}{n} + 1\right) - t\_0\\ \mathbf{elif}\;x \leq 0.00012:\\ \;\;\;\;\frac{x - \log x}{n}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{t\_0}{x}}{n}\\ \end{array} \end{array} \]
    (FPCore (x n)
     :precision binary64
     (let* ((t_0 (pow x (/ 1.0 n))))
       (if (<= x 5.8e-227)
         (- (+ (/ x n) 1.0) t_0)
         (if (<= x 0.00012) (/ (- x (log x)) n) (/ (/ t_0 x) n)))))
    double code(double x, double n) {
    	double t_0 = pow(x, (1.0 / n));
    	double tmp;
    	if (x <= 5.8e-227) {
    		tmp = ((x / n) + 1.0) - t_0;
    	} else if (x <= 0.00012) {
    		tmp = (x - log(x)) / n;
    	} else {
    		tmp = (t_0 / x) / n;
    	}
    	return tmp;
    }
    
    real(8) function code(x, n)
        real(8), intent (in) :: x
        real(8), intent (in) :: n
        real(8) :: t_0
        real(8) :: tmp
        t_0 = x ** (1.0d0 / n)
        if (x <= 5.8d-227) then
            tmp = ((x / n) + 1.0d0) - t_0
        else if (x <= 0.00012d0) then
            tmp = (x - log(x)) / n
        else
            tmp = (t_0 / x) / n
        end if
        code = tmp
    end function
    
    public static double code(double x, double n) {
    	double t_0 = Math.pow(x, (1.0 / n));
    	double tmp;
    	if (x <= 5.8e-227) {
    		tmp = ((x / n) + 1.0) - t_0;
    	} else if (x <= 0.00012) {
    		tmp = (x - Math.log(x)) / n;
    	} else {
    		tmp = (t_0 / x) / n;
    	}
    	return tmp;
    }
    
    def code(x, n):
    	t_0 = math.pow(x, (1.0 / n))
    	tmp = 0
    	if x <= 5.8e-227:
    		tmp = ((x / n) + 1.0) - t_0
    	elif x <= 0.00012:
    		tmp = (x - math.log(x)) / n
    	else:
    		tmp = (t_0 / x) / n
    	return tmp
    
    function code(x, n)
    	t_0 = x ^ Float64(1.0 / n)
    	tmp = 0.0
    	if (x <= 5.8e-227)
    		tmp = Float64(Float64(Float64(x / n) + 1.0) - t_0);
    	elseif (x <= 0.00012)
    		tmp = Float64(Float64(x - log(x)) / n);
    	else
    		tmp = Float64(Float64(t_0 / x) / n);
    	end
    	return tmp
    end
    
    function tmp_2 = code(x, n)
    	t_0 = x ^ (1.0 / n);
    	tmp = 0.0;
    	if (x <= 5.8e-227)
    		tmp = ((x / n) + 1.0) - t_0;
    	elseif (x <= 0.00012)
    		tmp = (x - log(x)) / n;
    	else
    		tmp = (t_0 / x) / n;
    	end
    	tmp_2 = tmp;
    end
    
    code[x_, n_] := Block[{t$95$0 = N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[x, 5.8e-227], N[(N[(N[(x / n), $MachinePrecision] + 1.0), $MachinePrecision] - t$95$0), $MachinePrecision], If[LessEqual[x, 0.00012], N[(N[(x - N[Log[x], $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision], N[(N[(t$95$0 / x), $MachinePrecision] / n), $MachinePrecision]]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    t_0 := {x}^{\left(\frac{1}{n}\right)}\\
    \mathbf{if}\;x \leq 5.8 \cdot 10^{-227}:\\
    \;\;\;\;\left(\frac{x}{n} + 1\right) - t\_0\\
    
    \mathbf{elif}\;x \leq 0.00012:\\
    \;\;\;\;\frac{x - \log x}{n}\\
    
    \mathbf{else}:\\
    \;\;\;\;\frac{\frac{t\_0}{x}}{n}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 3 regimes
    2. if x < 5.80000000000000022e-227

      1. Initial program 63.4%

        \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
      2. Add Preprocessing
      3. Taylor expanded in x around 0

        \[\leadsto \color{blue}{\left(1 + \frac{x}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
      4. Step-by-step derivation
        1. +-commutativeN/A

          \[\leadsto \color{blue}{\left(\frac{x}{n} + 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
        2. *-rgt-identityN/A

          \[\leadsto \left(\frac{\color{blue}{x \cdot 1}}{n} + 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
        3. associate-*r/N/A

          \[\leadsto \left(\color{blue}{x \cdot \frac{1}{n}} + 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
        4. lower-+.f64N/A

          \[\leadsto \color{blue}{\left(x \cdot \frac{1}{n} + 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
        5. associate-*r/N/A

          \[\leadsto \left(\color{blue}{\frac{x \cdot 1}{n}} + 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
        6. *-rgt-identityN/A

          \[\leadsto \left(\frac{\color{blue}{x}}{n} + 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
        7. lower-/.f6463.4

          \[\leadsto \left(\color{blue}{\frac{x}{n}} + 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
      5. Applied rewrites63.4%

        \[\leadsto \color{blue}{\left(\frac{x}{n} + 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]

      if 5.80000000000000022e-227 < x < 1.20000000000000003e-4

      1. Initial program 43.2%

        \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
      2. Add Preprocessing
      3. Taylor expanded in n around inf

        \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
      4. Step-by-step derivation
        1. lower-/.f64N/A

          \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
        2. lower--.f64N/A

          \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
        3. lower-log1p.f64N/A

          \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
        4. lower-log.f6451.8

          \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
      5. Applied rewrites51.8%

        \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
      6. Taylor expanded in x around 0

        \[\leadsto \frac{x - \log x}{n} \]
      7. Step-by-step derivation
        1. Applied rewrites51.8%

          \[\leadsto \frac{x - \log x}{n} \]

        if 1.20000000000000003e-4 < x

        1. Initial program 73.1%

          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
        2. Add Preprocessing
        3. Taylor expanded in x around inf

          \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
        4. Step-by-step derivation
          1. associate-/l/N/A

            \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
          2. lower-/.f64N/A

            \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
          3. lower-/.f64N/A

            \[\leadsto \frac{\color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}}{n} \]
          4. log-recN/A

            \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{x}}{n} \]
          5. mul-1-negN/A

            \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{x}}{n} \]
          6. associate-*r/N/A

            \[\leadsto \frac{\frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{x}}{n} \]
          7. associate-*r*N/A

            \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{x}}{n} \]
          8. metadata-evalN/A

            \[\leadsto \frac{\frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{x}}{n} \]
          9. *-commutativeN/A

            \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{x}}{n} \]
          10. associate-/l*N/A

            \[\leadsto \frac{\frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{x}}{n} \]
          11. exp-to-powN/A

            \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
          12. lower-pow.f64N/A

            \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
          13. lower-/.f6499.6

            \[\leadsto \frac{\frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{x}}{n} \]
        5. Applied rewrites99.6%

          \[\leadsto \color{blue}{\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}} \]
      8. Recombined 3 regimes into one program.
      9. Add Preprocessing

      Alternative 4: 72.1% accurate, 1.6× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 5.8 \cdot 10^{-227}:\\ \;\;\;\;\left(\frac{x}{n} + 1\right) - {x}^{\left(\frac{1}{n}\right)}\\ \mathbf{elif}\;x \leq 0.00012:\\ \;\;\;\;\frac{x - \log x}{n}\\ \mathbf{else}:\\ \;\;\;\;\frac{{x}^{\left(\mathsf{fma}\left(2, \frac{0.5}{n}, -1\right)\right)}}{n}\\ \end{array} \end{array} \]
      (FPCore (x n)
       :precision binary64
       (if (<= x 5.8e-227)
         (- (+ (/ x n) 1.0) (pow x (/ 1.0 n)))
         (if (<= x 0.00012)
           (/ (- x (log x)) n)
           (/ (pow x (fma 2.0 (/ 0.5 n) -1.0)) n))))
      double code(double x, double n) {
      	double tmp;
      	if (x <= 5.8e-227) {
      		tmp = ((x / n) + 1.0) - pow(x, (1.0 / n));
      	} else if (x <= 0.00012) {
      		tmp = (x - log(x)) / n;
      	} else {
      		tmp = pow(x, fma(2.0, (0.5 / n), -1.0)) / n;
      	}
      	return tmp;
      }
      
      function code(x, n)
      	tmp = 0.0
      	if (x <= 5.8e-227)
      		tmp = Float64(Float64(Float64(x / n) + 1.0) - (x ^ Float64(1.0 / n)));
      	elseif (x <= 0.00012)
      		tmp = Float64(Float64(x - log(x)) / n);
      	else
      		tmp = Float64((x ^ fma(2.0, Float64(0.5 / n), -1.0)) / n);
      	end
      	return tmp
      end
      
      code[x_, n_] := If[LessEqual[x, 5.8e-227], N[(N[(N[(x / n), $MachinePrecision] + 1.0), $MachinePrecision] - N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], If[LessEqual[x, 0.00012], N[(N[(x - N[Log[x], $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision], N[(N[Power[x, N[(2.0 * N[(0.5 / n), $MachinePrecision] + -1.0), $MachinePrecision]], $MachinePrecision] / n), $MachinePrecision]]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      \mathbf{if}\;x \leq 5.8 \cdot 10^{-227}:\\
      \;\;\;\;\left(\frac{x}{n} + 1\right) - {x}^{\left(\frac{1}{n}\right)}\\
      
      \mathbf{elif}\;x \leq 0.00012:\\
      \;\;\;\;\frac{x - \log x}{n}\\
      
      \mathbf{else}:\\
      \;\;\;\;\frac{{x}^{\left(\mathsf{fma}\left(2, \frac{0.5}{n}, -1\right)\right)}}{n}\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 3 regimes
      2. if x < 5.80000000000000022e-227

        1. Initial program 63.4%

          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
        2. Add Preprocessing
        3. Taylor expanded in x around 0

          \[\leadsto \color{blue}{\left(1 + \frac{x}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
        4. Step-by-step derivation
          1. +-commutativeN/A

            \[\leadsto \color{blue}{\left(\frac{x}{n} + 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
          2. *-rgt-identityN/A

            \[\leadsto \left(\frac{\color{blue}{x \cdot 1}}{n} + 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
          3. associate-*r/N/A

            \[\leadsto \left(\color{blue}{x \cdot \frac{1}{n}} + 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
          4. lower-+.f64N/A

            \[\leadsto \color{blue}{\left(x \cdot \frac{1}{n} + 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]
          5. associate-*r/N/A

            \[\leadsto \left(\color{blue}{\frac{x \cdot 1}{n}} + 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
          6. *-rgt-identityN/A

            \[\leadsto \left(\frac{\color{blue}{x}}{n} + 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
          7. lower-/.f6463.4

            \[\leadsto \left(\color{blue}{\frac{x}{n}} + 1\right) - {x}^{\left(\frac{1}{n}\right)} \]
        5. Applied rewrites63.4%

          \[\leadsto \color{blue}{\left(\frac{x}{n} + 1\right)} - {x}^{\left(\frac{1}{n}\right)} \]

        if 5.80000000000000022e-227 < x < 1.20000000000000003e-4

        1. Initial program 43.2%

          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
        2. Add Preprocessing
        3. Taylor expanded in n around inf

          \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
        4. Step-by-step derivation
          1. lower-/.f64N/A

            \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
          2. lower--.f64N/A

            \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
          3. lower-log1p.f64N/A

            \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
          4. lower-log.f6451.8

            \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
        5. Applied rewrites51.8%

          \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
        6. Taylor expanded in x around 0

          \[\leadsto \frac{x - \log x}{n} \]
        7. Step-by-step derivation
          1. Applied rewrites51.8%

            \[\leadsto \frac{x - \log x}{n} \]

          if 1.20000000000000003e-4 < x

          1. Initial program 73.1%

            \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
          2. Add Preprocessing
          3. Taylor expanded in x around inf

            \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
          4. Step-by-step derivation
            1. associate-/l/N/A

              \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
            2. lower-/.f64N/A

              \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
            3. lower-/.f64N/A

              \[\leadsto \frac{\color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}}{n} \]
            4. log-recN/A

              \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{x}}{n} \]
            5. mul-1-negN/A

              \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{x}}{n} \]
            6. associate-*r/N/A

              \[\leadsto \frac{\frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{x}}{n} \]
            7. associate-*r*N/A

              \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{x}}{n} \]
            8. metadata-evalN/A

              \[\leadsto \frac{\frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{x}}{n} \]
            9. *-commutativeN/A

              \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{x}}{n} \]
            10. associate-/l*N/A

              \[\leadsto \frac{\frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{x}}{n} \]
            11. exp-to-powN/A

              \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
            12. lower-pow.f64N/A

              \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
            13. lower-/.f6499.6

              \[\leadsto \frac{\frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{x}}{n} \]
          5. Applied rewrites99.6%

            \[\leadsto \color{blue}{\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}} \]
          6. Step-by-step derivation
            1. Applied rewrites99.3%

              \[\leadsto \frac{{x}^{\left(\mathsf{fma}\left(2, \frac{0.5}{n}, -1\right)\right)}}{n} \]
          7. Recombined 3 regimes into one program.
          8. Add Preprocessing

          Alternative 5: 72.0% accurate, 1.6× speedup?

          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 5.8 \cdot 10^{-227}:\\ \;\;\;\;1 - {x}^{\left(\frac{1}{n}\right)}\\ \mathbf{elif}\;x \leq 0.00012:\\ \;\;\;\;\frac{x - \log x}{n}\\ \mathbf{else}:\\ \;\;\;\;\frac{{x}^{\left(\mathsf{fma}\left(2, \frac{0.5}{n}, -1\right)\right)}}{n}\\ \end{array} \end{array} \]
          (FPCore (x n)
           :precision binary64
           (if (<= x 5.8e-227)
             (- 1.0 (pow x (/ 1.0 n)))
             (if (<= x 0.00012)
               (/ (- x (log x)) n)
               (/ (pow x (fma 2.0 (/ 0.5 n) -1.0)) n))))
          double code(double x, double n) {
          	double tmp;
          	if (x <= 5.8e-227) {
          		tmp = 1.0 - pow(x, (1.0 / n));
          	} else if (x <= 0.00012) {
          		tmp = (x - log(x)) / n;
          	} else {
          		tmp = pow(x, fma(2.0, (0.5 / n), -1.0)) / n;
          	}
          	return tmp;
          }
          
          function code(x, n)
          	tmp = 0.0
          	if (x <= 5.8e-227)
          		tmp = Float64(1.0 - (x ^ Float64(1.0 / n)));
          	elseif (x <= 0.00012)
          		tmp = Float64(Float64(x - log(x)) / n);
          	else
          		tmp = Float64((x ^ fma(2.0, Float64(0.5 / n), -1.0)) / n);
          	end
          	return tmp
          end
          
          code[x_, n_] := If[LessEqual[x, 5.8e-227], N[(1.0 - N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], If[LessEqual[x, 0.00012], N[(N[(x - N[Log[x], $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision], N[(N[Power[x, N[(2.0 * N[(0.5 / n), $MachinePrecision] + -1.0), $MachinePrecision]], $MachinePrecision] / n), $MachinePrecision]]]
          
          \begin{array}{l}
          
          \\
          \begin{array}{l}
          \mathbf{if}\;x \leq 5.8 \cdot 10^{-227}:\\
          \;\;\;\;1 - {x}^{\left(\frac{1}{n}\right)}\\
          
          \mathbf{elif}\;x \leq 0.00012:\\
          \;\;\;\;\frac{x - \log x}{n}\\
          
          \mathbf{else}:\\
          \;\;\;\;\frac{{x}^{\left(\mathsf{fma}\left(2, \frac{0.5}{n}, -1\right)\right)}}{n}\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 3 regimes
          2. if x < 5.80000000000000022e-227

            1. Initial program 63.4%

              \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
            2. Add Preprocessing
            3. Taylor expanded in x around 0

              \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
            4. Step-by-step derivation
              1. Applied rewrites63.4%

                \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]

              if 5.80000000000000022e-227 < x < 1.20000000000000003e-4

              1. Initial program 43.2%

                \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
              2. Add Preprocessing
              3. Taylor expanded in n around inf

                \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
              4. Step-by-step derivation
                1. lower-/.f64N/A

                  \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                2. lower--.f64N/A

                  \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                3. lower-log1p.f64N/A

                  \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                4. lower-log.f6451.8

                  \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
              5. Applied rewrites51.8%

                \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
              6. Taylor expanded in x around 0

                \[\leadsto \frac{x - \log x}{n} \]
              7. Step-by-step derivation
                1. Applied rewrites51.8%

                  \[\leadsto \frac{x - \log x}{n} \]

                if 1.20000000000000003e-4 < x

                1. Initial program 73.1%

                  \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                2. Add Preprocessing
                3. Taylor expanded in x around inf

                  \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                4. Step-by-step derivation
                  1. associate-/l/N/A

                    \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                  2. lower-/.f64N/A

                    \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                  3. lower-/.f64N/A

                    \[\leadsto \frac{\color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}}{n} \]
                  4. log-recN/A

                    \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{x}}{n} \]
                  5. mul-1-negN/A

                    \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{x}}{n} \]
                  6. associate-*r/N/A

                    \[\leadsto \frac{\frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{x}}{n} \]
                  7. associate-*r*N/A

                    \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{x}}{n} \]
                  8. metadata-evalN/A

                    \[\leadsto \frac{\frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{x}}{n} \]
                  9. *-commutativeN/A

                    \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{x}}{n} \]
                  10. associate-/l*N/A

                    \[\leadsto \frac{\frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{x}}{n} \]
                  11. exp-to-powN/A

                    \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                  12. lower-pow.f64N/A

                    \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                  13. lower-/.f6499.6

                    \[\leadsto \frac{\frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                5. Applied rewrites99.6%

                  \[\leadsto \color{blue}{\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}} \]
                6. Step-by-step derivation
                  1. Applied rewrites99.3%

                    \[\leadsto \frac{{x}^{\left(\mathsf{fma}\left(2, \frac{0.5}{n}, -1\right)\right)}}{n} \]
                7. Recombined 3 regimes into one program.
                8. Add Preprocessing

                Alternative 6: 60.2% accurate, 1.8× speedup?

                \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 5.8 \cdot 10^{-227}:\\ \;\;\;\;1 - {x}^{\left(\frac{1}{n}\right)}\\ \mathbf{elif}\;x \leq 5.5 \cdot 10^{-7}:\\ \;\;\;\;\frac{x - \log x}{n}\\ \mathbf{elif}\;x \leq 1.6 \cdot 10^{+59}:\\ \;\;\;\;\frac{\left(\frac{0.3333333333333333}{\left(x \cdot x\right) \cdot n} + \frac{1}{n}\right) - \frac{\frac{0.5}{n}}{x}}{x}\\ \mathbf{else}:\\ \;\;\;\;1 - 1\\ \end{array} \end{array} \]
                (FPCore (x n)
                 :precision binary64
                 (if (<= x 5.8e-227)
                   (- 1.0 (pow x (/ 1.0 n)))
                   (if (<= x 5.5e-7)
                     (/ (- x (log x)) n)
                     (if (<= x 1.6e+59)
                       (/
                        (- (+ (/ 0.3333333333333333 (* (* x x) n)) (/ 1.0 n)) (/ (/ 0.5 n) x))
                        x)
                       (- 1.0 1.0)))))
                double code(double x, double n) {
                	double tmp;
                	if (x <= 5.8e-227) {
                		tmp = 1.0 - pow(x, (1.0 / n));
                	} else if (x <= 5.5e-7) {
                		tmp = (x - log(x)) / n;
                	} else if (x <= 1.6e+59) {
                		tmp = (((0.3333333333333333 / ((x * x) * n)) + (1.0 / n)) - ((0.5 / n) / x)) / x;
                	} else {
                		tmp = 1.0 - 1.0;
                	}
                	return tmp;
                }
                
                real(8) function code(x, n)
                    real(8), intent (in) :: x
                    real(8), intent (in) :: n
                    real(8) :: tmp
                    if (x <= 5.8d-227) then
                        tmp = 1.0d0 - (x ** (1.0d0 / n))
                    else if (x <= 5.5d-7) then
                        tmp = (x - log(x)) / n
                    else if (x <= 1.6d+59) then
                        tmp = (((0.3333333333333333d0 / ((x * x) * n)) + (1.0d0 / n)) - ((0.5d0 / n) / x)) / x
                    else
                        tmp = 1.0d0 - 1.0d0
                    end if
                    code = tmp
                end function
                
                public static double code(double x, double n) {
                	double tmp;
                	if (x <= 5.8e-227) {
                		tmp = 1.0 - Math.pow(x, (1.0 / n));
                	} else if (x <= 5.5e-7) {
                		tmp = (x - Math.log(x)) / n;
                	} else if (x <= 1.6e+59) {
                		tmp = (((0.3333333333333333 / ((x * x) * n)) + (1.0 / n)) - ((0.5 / n) / x)) / x;
                	} else {
                		tmp = 1.0 - 1.0;
                	}
                	return tmp;
                }
                
                def code(x, n):
                	tmp = 0
                	if x <= 5.8e-227:
                		tmp = 1.0 - math.pow(x, (1.0 / n))
                	elif x <= 5.5e-7:
                		tmp = (x - math.log(x)) / n
                	elif x <= 1.6e+59:
                		tmp = (((0.3333333333333333 / ((x * x) * n)) + (1.0 / n)) - ((0.5 / n) / x)) / x
                	else:
                		tmp = 1.0 - 1.0
                	return tmp
                
                function code(x, n)
                	tmp = 0.0
                	if (x <= 5.8e-227)
                		tmp = Float64(1.0 - (x ^ Float64(1.0 / n)));
                	elseif (x <= 5.5e-7)
                		tmp = Float64(Float64(x - log(x)) / n);
                	elseif (x <= 1.6e+59)
                		tmp = Float64(Float64(Float64(Float64(0.3333333333333333 / Float64(Float64(x * x) * n)) + Float64(1.0 / n)) - Float64(Float64(0.5 / n) / x)) / x);
                	else
                		tmp = Float64(1.0 - 1.0);
                	end
                	return tmp
                end
                
                function tmp_2 = code(x, n)
                	tmp = 0.0;
                	if (x <= 5.8e-227)
                		tmp = 1.0 - (x ^ (1.0 / n));
                	elseif (x <= 5.5e-7)
                		tmp = (x - log(x)) / n;
                	elseif (x <= 1.6e+59)
                		tmp = (((0.3333333333333333 / ((x * x) * n)) + (1.0 / n)) - ((0.5 / n) / x)) / x;
                	else
                		tmp = 1.0 - 1.0;
                	end
                	tmp_2 = tmp;
                end
                
                code[x_, n_] := If[LessEqual[x, 5.8e-227], N[(1.0 - N[Power[x, N[(1.0 / n), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], If[LessEqual[x, 5.5e-7], N[(N[(x - N[Log[x], $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision], If[LessEqual[x, 1.6e+59], N[(N[(N[(N[(0.3333333333333333 / N[(N[(x * x), $MachinePrecision] * n), $MachinePrecision]), $MachinePrecision] + N[(1.0 / n), $MachinePrecision]), $MachinePrecision] - N[(N[(0.5 / n), $MachinePrecision] / x), $MachinePrecision]), $MachinePrecision] / x), $MachinePrecision], N[(1.0 - 1.0), $MachinePrecision]]]]
                
                \begin{array}{l}
                
                \\
                \begin{array}{l}
                \mathbf{if}\;x \leq 5.8 \cdot 10^{-227}:\\
                \;\;\;\;1 - {x}^{\left(\frac{1}{n}\right)}\\
                
                \mathbf{elif}\;x \leq 5.5 \cdot 10^{-7}:\\
                \;\;\;\;\frac{x - \log x}{n}\\
                
                \mathbf{elif}\;x \leq 1.6 \cdot 10^{+59}:\\
                \;\;\;\;\frac{\left(\frac{0.3333333333333333}{\left(x \cdot x\right) \cdot n} + \frac{1}{n}\right) - \frac{\frac{0.5}{n}}{x}}{x}\\
                
                \mathbf{else}:\\
                \;\;\;\;1 - 1\\
                
                
                \end{array}
                \end{array}
                
                Derivation
                1. Split input into 4 regimes
                2. if x < 5.80000000000000022e-227

                  1. Initial program 63.4%

                    \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                  2. Add Preprocessing
                  3. Taylor expanded in x around 0

                    \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                  4. Step-by-step derivation
                    1. Applied rewrites63.4%

                      \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]

                    if 5.80000000000000022e-227 < x < 5.5000000000000003e-7

                    1. Initial program 42.7%

                      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                    2. Add Preprocessing
                    3. Taylor expanded in n around inf

                      \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                    4. Step-by-step derivation
                      1. lower-/.f64N/A

                        \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                      2. lower--.f64N/A

                        \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                      3. lower-log1p.f64N/A

                        \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                      4. lower-log.f6452.3

                        \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                    5. Applied rewrites52.3%

                      \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                    6. Taylor expanded in x around 0

                      \[\leadsto \frac{x - \log x}{n} \]
                    7. Step-by-step derivation
                      1. Applied rewrites52.3%

                        \[\leadsto \frac{x - \log x}{n} \]

                      if 5.5000000000000003e-7 < x < 1.59999999999999991e59

                      1. Initial program 37.8%

                        \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                      2. Add Preprocessing
                      3. Taylor expanded in n around inf

                        \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                      4. Step-by-step derivation
                        1. lower-/.f64N/A

                          \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                        2. lower--.f64N/A

                          \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                        3. lower-log1p.f64N/A

                          \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                        4. lower-log.f6423.0

                          \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                      5. Applied rewrites23.0%

                        \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                      6. Taylor expanded in x around inf

                        \[\leadsto \frac{\left(\frac{\frac{1}{3}}{n \cdot {x}^{2}} + \frac{1}{n}\right) - \frac{\frac{1}{2}}{n \cdot x}}{\color{blue}{x}} \]
                      7. Step-by-step derivation
                        1. Applied rewrites65.1%

                          \[\leadsto \frac{\left(\frac{0.3333333333333333}{\left(x \cdot x\right) \cdot n} + \frac{1}{n}\right) - \frac{\frac{0.5}{n}}{x}}{\color{blue}{x}} \]

                        if 1.59999999999999991e59 < x

                        1. Initial program 81.6%

                          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                        2. Add Preprocessing
                        3. Taylor expanded in x around 0

                          \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                        4. Step-by-step derivation
                          1. Applied rewrites39.0%

                            \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                          2. Taylor expanded in n around inf

                            \[\leadsto 1 - \color{blue}{1} \]
                          3. Step-by-step derivation
                            1. Applied rewrites81.6%

                              \[\leadsto 1 - \color{blue}{1} \]
                          4. Recombined 4 regimes into one program.
                          5. Add Preprocessing

                          Alternative 7: 59.9% accurate, 1.9× speedup?

                          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 5.5 \cdot 10^{-7}:\\ \;\;\;\;\frac{x - \log x}{n}\\ \mathbf{elif}\;x \leq 1.6 \cdot 10^{+59}:\\ \;\;\;\;\frac{\left(\frac{0.3333333333333333}{\left(x \cdot x\right) \cdot n} + \frac{1}{n}\right) - \frac{\frac{0.5}{n}}{x}}{x}\\ \mathbf{else}:\\ \;\;\;\;1 - 1\\ \end{array} \end{array} \]
                          (FPCore (x n)
                           :precision binary64
                           (if (<= x 5.5e-7)
                             (/ (- x (log x)) n)
                             (if (<= x 1.6e+59)
                               (/
                                (- (+ (/ 0.3333333333333333 (* (* x x) n)) (/ 1.0 n)) (/ (/ 0.5 n) x))
                                x)
                               (- 1.0 1.0))))
                          double code(double x, double n) {
                          	double tmp;
                          	if (x <= 5.5e-7) {
                          		tmp = (x - log(x)) / n;
                          	} else if (x <= 1.6e+59) {
                          		tmp = (((0.3333333333333333 / ((x * x) * n)) + (1.0 / n)) - ((0.5 / n) / x)) / x;
                          	} else {
                          		tmp = 1.0 - 1.0;
                          	}
                          	return tmp;
                          }
                          
                          real(8) function code(x, n)
                              real(8), intent (in) :: x
                              real(8), intent (in) :: n
                              real(8) :: tmp
                              if (x <= 5.5d-7) then
                                  tmp = (x - log(x)) / n
                              else if (x <= 1.6d+59) then
                                  tmp = (((0.3333333333333333d0 / ((x * x) * n)) + (1.0d0 / n)) - ((0.5d0 / n) / x)) / x
                              else
                                  tmp = 1.0d0 - 1.0d0
                              end if
                              code = tmp
                          end function
                          
                          public static double code(double x, double n) {
                          	double tmp;
                          	if (x <= 5.5e-7) {
                          		tmp = (x - Math.log(x)) / n;
                          	} else if (x <= 1.6e+59) {
                          		tmp = (((0.3333333333333333 / ((x * x) * n)) + (1.0 / n)) - ((0.5 / n) / x)) / x;
                          	} else {
                          		tmp = 1.0 - 1.0;
                          	}
                          	return tmp;
                          }
                          
                          def code(x, n):
                          	tmp = 0
                          	if x <= 5.5e-7:
                          		tmp = (x - math.log(x)) / n
                          	elif x <= 1.6e+59:
                          		tmp = (((0.3333333333333333 / ((x * x) * n)) + (1.0 / n)) - ((0.5 / n) / x)) / x
                          	else:
                          		tmp = 1.0 - 1.0
                          	return tmp
                          
                          function code(x, n)
                          	tmp = 0.0
                          	if (x <= 5.5e-7)
                          		tmp = Float64(Float64(x - log(x)) / n);
                          	elseif (x <= 1.6e+59)
                          		tmp = Float64(Float64(Float64(Float64(0.3333333333333333 / Float64(Float64(x * x) * n)) + Float64(1.0 / n)) - Float64(Float64(0.5 / n) / x)) / x);
                          	else
                          		tmp = Float64(1.0 - 1.0);
                          	end
                          	return tmp
                          end
                          
                          function tmp_2 = code(x, n)
                          	tmp = 0.0;
                          	if (x <= 5.5e-7)
                          		tmp = (x - log(x)) / n;
                          	elseif (x <= 1.6e+59)
                          		tmp = (((0.3333333333333333 / ((x * x) * n)) + (1.0 / n)) - ((0.5 / n) / x)) / x;
                          	else
                          		tmp = 1.0 - 1.0;
                          	end
                          	tmp_2 = tmp;
                          end
                          
                          code[x_, n_] := If[LessEqual[x, 5.5e-7], N[(N[(x - N[Log[x], $MachinePrecision]), $MachinePrecision] / n), $MachinePrecision], If[LessEqual[x, 1.6e+59], N[(N[(N[(N[(0.3333333333333333 / N[(N[(x * x), $MachinePrecision] * n), $MachinePrecision]), $MachinePrecision] + N[(1.0 / n), $MachinePrecision]), $MachinePrecision] - N[(N[(0.5 / n), $MachinePrecision] / x), $MachinePrecision]), $MachinePrecision] / x), $MachinePrecision], N[(1.0 - 1.0), $MachinePrecision]]]
                          
                          \begin{array}{l}
                          
                          \\
                          \begin{array}{l}
                          \mathbf{if}\;x \leq 5.5 \cdot 10^{-7}:\\
                          \;\;\;\;\frac{x - \log x}{n}\\
                          
                          \mathbf{elif}\;x \leq 1.6 \cdot 10^{+59}:\\
                          \;\;\;\;\frac{\left(\frac{0.3333333333333333}{\left(x \cdot x\right) \cdot n} + \frac{1}{n}\right) - \frac{\frac{0.5}{n}}{x}}{x}\\
                          
                          \mathbf{else}:\\
                          \;\;\;\;1 - 1\\
                          
                          
                          \end{array}
                          \end{array}
                          
                          Derivation
                          1. Split input into 3 regimes
                          2. if x < 5.5000000000000003e-7

                            1. Initial program 48.2%

                              \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                            2. Add Preprocessing
                            3. Taylor expanded in n around inf

                              \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                            4. Step-by-step derivation
                              1. lower-/.f64N/A

                                \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                              2. lower--.f64N/A

                                \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                              3. lower-log1p.f64N/A

                                \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                              4. lower-log.f6448.5

                                \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                            5. Applied rewrites48.5%

                              \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                            6. Taylor expanded in x around 0

                              \[\leadsto \frac{x - \log x}{n} \]
                            7. Step-by-step derivation
                              1. Applied rewrites48.5%

                                \[\leadsto \frac{x - \log x}{n} \]

                              if 5.5000000000000003e-7 < x < 1.59999999999999991e59

                              1. Initial program 37.8%

                                \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                              2. Add Preprocessing
                              3. Taylor expanded in n around inf

                                \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                              4. Step-by-step derivation
                                1. lower-/.f64N/A

                                  \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                2. lower--.f64N/A

                                  \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                                3. lower-log1p.f64N/A

                                  \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                                4. lower-log.f6423.0

                                  \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                              5. Applied rewrites23.0%

                                \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                              6. Taylor expanded in x around inf

                                \[\leadsto \frac{\left(\frac{\frac{1}{3}}{n \cdot {x}^{2}} + \frac{1}{n}\right) - \frac{\frac{1}{2}}{n \cdot x}}{\color{blue}{x}} \]
                              7. Step-by-step derivation
                                1. Applied rewrites65.1%

                                  \[\leadsto \frac{\left(\frac{0.3333333333333333}{\left(x \cdot x\right) \cdot n} + \frac{1}{n}\right) - \frac{\frac{0.5}{n}}{x}}{\color{blue}{x}} \]

                                if 1.59999999999999991e59 < x

                                1. Initial program 81.6%

                                  \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                2. Add Preprocessing
                                3. Taylor expanded in x around 0

                                  \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                4. Step-by-step derivation
                                  1. Applied rewrites39.0%

                                    \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                  2. Taylor expanded in n around inf

                                    \[\leadsto 1 - \color{blue}{1} \]
                                  3. Step-by-step derivation
                                    1. Applied rewrites81.6%

                                      \[\leadsto 1 - \color{blue}{1} \]
                                  4. Recombined 3 regimes into one program.
                                  5. Add Preprocessing

                                  Alternative 8: 59.8% accurate, 1.9× speedup?

                                  \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 5.5 \cdot 10^{-7}:\\ \;\;\;\;\frac{-\log x}{n}\\ \mathbf{elif}\;x \leq 1.6 \cdot 10^{+59}:\\ \;\;\;\;\frac{\left(\frac{0.3333333333333333}{\left(x \cdot x\right) \cdot n} + \frac{1}{n}\right) - \frac{\frac{0.5}{n}}{x}}{x}\\ \mathbf{else}:\\ \;\;\;\;1 - 1\\ \end{array} \end{array} \]
                                  (FPCore (x n)
                                   :precision binary64
                                   (if (<= x 5.5e-7)
                                     (/ (- (log x)) n)
                                     (if (<= x 1.6e+59)
                                       (/
                                        (- (+ (/ 0.3333333333333333 (* (* x x) n)) (/ 1.0 n)) (/ (/ 0.5 n) x))
                                        x)
                                       (- 1.0 1.0))))
                                  double code(double x, double n) {
                                  	double tmp;
                                  	if (x <= 5.5e-7) {
                                  		tmp = -log(x) / n;
                                  	} else if (x <= 1.6e+59) {
                                  		tmp = (((0.3333333333333333 / ((x * x) * n)) + (1.0 / n)) - ((0.5 / n) / x)) / x;
                                  	} else {
                                  		tmp = 1.0 - 1.0;
                                  	}
                                  	return tmp;
                                  }
                                  
                                  real(8) function code(x, n)
                                      real(8), intent (in) :: x
                                      real(8), intent (in) :: n
                                      real(8) :: tmp
                                      if (x <= 5.5d-7) then
                                          tmp = -log(x) / n
                                      else if (x <= 1.6d+59) then
                                          tmp = (((0.3333333333333333d0 / ((x * x) * n)) + (1.0d0 / n)) - ((0.5d0 / n) / x)) / x
                                      else
                                          tmp = 1.0d0 - 1.0d0
                                      end if
                                      code = tmp
                                  end function
                                  
                                  public static double code(double x, double n) {
                                  	double tmp;
                                  	if (x <= 5.5e-7) {
                                  		tmp = -Math.log(x) / n;
                                  	} else if (x <= 1.6e+59) {
                                  		tmp = (((0.3333333333333333 / ((x * x) * n)) + (1.0 / n)) - ((0.5 / n) / x)) / x;
                                  	} else {
                                  		tmp = 1.0 - 1.0;
                                  	}
                                  	return tmp;
                                  }
                                  
                                  def code(x, n):
                                  	tmp = 0
                                  	if x <= 5.5e-7:
                                  		tmp = -math.log(x) / n
                                  	elif x <= 1.6e+59:
                                  		tmp = (((0.3333333333333333 / ((x * x) * n)) + (1.0 / n)) - ((0.5 / n) / x)) / x
                                  	else:
                                  		tmp = 1.0 - 1.0
                                  	return tmp
                                  
                                  function code(x, n)
                                  	tmp = 0.0
                                  	if (x <= 5.5e-7)
                                  		tmp = Float64(Float64(-log(x)) / n);
                                  	elseif (x <= 1.6e+59)
                                  		tmp = Float64(Float64(Float64(Float64(0.3333333333333333 / Float64(Float64(x * x) * n)) + Float64(1.0 / n)) - Float64(Float64(0.5 / n) / x)) / x);
                                  	else
                                  		tmp = Float64(1.0 - 1.0);
                                  	end
                                  	return tmp
                                  end
                                  
                                  function tmp_2 = code(x, n)
                                  	tmp = 0.0;
                                  	if (x <= 5.5e-7)
                                  		tmp = -log(x) / n;
                                  	elseif (x <= 1.6e+59)
                                  		tmp = (((0.3333333333333333 / ((x * x) * n)) + (1.0 / n)) - ((0.5 / n) / x)) / x;
                                  	else
                                  		tmp = 1.0 - 1.0;
                                  	end
                                  	tmp_2 = tmp;
                                  end
                                  
                                  code[x_, n_] := If[LessEqual[x, 5.5e-7], N[((-N[Log[x], $MachinePrecision]) / n), $MachinePrecision], If[LessEqual[x, 1.6e+59], N[(N[(N[(N[(0.3333333333333333 / N[(N[(x * x), $MachinePrecision] * n), $MachinePrecision]), $MachinePrecision] + N[(1.0 / n), $MachinePrecision]), $MachinePrecision] - N[(N[(0.5 / n), $MachinePrecision] / x), $MachinePrecision]), $MachinePrecision] / x), $MachinePrecision], N[(1.0 - 1.0), $MachinePrecision]]]
                                  
                                  \begin{array}{l}
                                  
                                  \\
                                  \begin{array}{l}
                                  \mathbf{if}\;x \leq 5.5 \cdot 10^{-7}:\\
                                  \;\;\;\;\frac{-\log x}{n}\\
                                  
                                  \mathbf{elif}\;x \leq 1.6 \cdot 10^{+59}:\\
                                  \;\;\;\;\frac{\left(\frac{0.3333333333333333}{\left(x \cdot x\right) \cdot n} + \frac{1}{n}\right) - \frac{\frac{0.5}{n}}{x}}{x}\\
                                  
                                  \mathbf{else}:\\
                                  \;\;\;\;1 - 1\\
                                  
                                  
                                  \end{array}
                                  \end{array}
                                  
                                  Derivation
                                  1. Split input into 3 regimes
                                  2. if x < 5.5000000000000003e-7

                                    1. Initial program 48.2%

                                      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                    2. Add Preprocessing
                                    3. Taylor expanded in n around inf

                                      \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                    4. Step-by-step derivation
                                      1. lower-/.f64N/A

                                        \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                      2. lower--.f64N/A

                                        \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                                      3. lower-log1p.f64N/A

                                        \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                                      4. lower-log.f6448.5

                                        \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                                    5. Applied rewrites48.5%

                                      \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                                    6. Taylor expanded in x around 0

                                      \[\leadsto \frac{-1 \cdot \log x}{n} \]
                                    7. Step-by-step derivation
                                      1. Applied rewrites48.3%

                                        \[\leadsto \frac{-\log x}{n} \]

                                      if 5.5000000000000003e-7 < x < 1.59999999999999991e59

                                      1. Initial program 37.8%

                                        \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                      2. Add Preprocessing
                                      3. Taylor expanded in n around inf

                                        \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                      4. Step-by-step derivation
                                        1. lower-/.f64N/A

                                          \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                        2. lower--.f64N/A

                                          \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                                        3. lower-log1p.f64N/A

                                          \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                                        4. lower-log.f6423.0

                                          \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                                      5. Applied rewrites23.0%

                                        \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                                      6. Taylor expanded in x around inf

                                        \[\leadsto \frac{\left(\frac{\frac{1}{3}}{n \cdot {x}^{2}} + \frac{1}{n}\right) - \frac{\frac{1}{2}}{n \cdot x}}{\color{blue}{x}} \]
                                      7. Step-by-step derivation
                                        1. Applied rewrites65.1%

                                          \[\leadsto \frac{\left(\frac{0.3333333333333333}{\left(x \cdot x\right) \cdot n} + \frac{1}{n}\right) - \frac{\frac{0.5}{n}}{x}}{\color{blue}{x}} \]

                                        if 1.59999999999999991e59 < x

                                        1. Initial program 81.6%

                                          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                        2. Add Preprocessing
                                        3. Taylor expanded in x around 0

                                          \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                        4. Step-by-step derivation
                                          1. Applied rewrites39.0%

                                            \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                          2. Taylor expanded in n around inf

                                            \[\leadsto 1 - \color{blue}{1} \]
                                          3. Step-by-step derivation
                                            1. Applied rewrites81.6%

                                              \[\leadsto 1 - \color{blue}{1} \]
                                          4. Recombined 3 regimes into one program.
                                          5. Add Preprocessing

                                          Alternative 9: 48.9% accurate, 3.0× speedup?

                                          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{1}{n} \leq -2:\\ \;\;\;\;1 - 1\\ \mathbf{elif}\;\frac{1}{n} \leq 10^{+135}:\\ \;\;\;\;\frac{-1}{n} \cdot \frac{-1}{x}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\frac{0.5}{n \cdot n}, x, \frac{1}{n}\right), x, 1\right) - 1\\ \end{array} \end{array} \]
                                          (FPCore (x n)
                                           :precision binary64
                                           (if (<= (/ 1.0 n) -2.0)
                                             (- 1.0 1.0)
                                             (if (<= (/ 1.0 n) 1e+135)
                                               (* (/ -1.0 n) (/ -1.0 x))
                                               (- (fma (fma (/ 0.5 (* n n)) x (/ 1.0 n)) x 1.0) 1.0))))
                                          double code(double x, double n) {
                                          	double tmp;
                                          	if ((1.0 / n) <= -2.0) {
                                          		tmp = 1.0 - 1.0;
                                          	} else if ((1.0 / n) <= 1e+135) {
                                          		tmp = (-1.0 / n) * (-1.0 / x);
                                          	} else {
                                          		tmp = fma(fma((0.5 / (n * n)), x, (1.0 / n)), x, 1.0) - 1.0;
                                          	}
                                          	return tmp;
                                          }
                                          
                                          function code(x, n)
                                          	tmp = 0.0
                                          	if (Float64(1.0 / n) <= -2.0)
                                          		tmp = Float64(1.0 - 1.0);
                                          	elseif (Float64(1.0 / n) <= 1e+135)
                                          		tmp = Float64(Float64(-1.0 / n) * Float64(-1.0 / x));
                                          	else
                                          		tmp = Float64(fma(fma(Float64(0.5 / Float64(n * n)), x, Float64(1.0 / n)), x, 1.0) - 1.0);
                                          	end
                                          	return tmp
                                          end
                                          
                                          code[x_, n_] := If[LessEqual[N[(1.0 / n), $MachinePrecision], -2.0], N[(1.0 - 1.0), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 1e+135], N[(N[(-1.0 / n), $MachinePrecision] * N[(-1.0 / x), $MachinePrecision]), $MachinePrecision], N[(N[(N[(N[(0.5 / N[(n * n), $MachinePrecision]), $MachinePrecision] * x + N[(1.0 / n), $MachinePrecision]), $MachinePrecision] * x + 1.0), $MachinePrecision] - 1.0), $MachinePrecision]]]
                                          
                                          \begin{array}{l}
                                          
                                          \\
                                          \begin{array}{l}
                                          \mathbf{if}\;\frac{1}{n} \leq -2:\\
                                          \;\;\;\;1 - 1\\
                                          
                                          \mathbf{elif}\;\frac{1}{n} \leq 10^{+135}:\\
                                          \;\;\;\;\frac{-1}{n} \cdot \frac{-1}{x}\\
                                          
                                          \mathbf{else}:\\
                                          \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\frac{0.5}{n \cdot n}, x, \frac{1}{n}\right), x, 1\right) - 1\\
                                          
                                          
                                          \end{array}
                                          \end{array}
                                          
                                          Derivation
                                          1. Split input into 3 regimes
                                          2. if (/.f64 #s(literal 1 binary64) n) < -2

                                            1. Initial program 100.0%

                                              \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                            2. Add Preprocessing
                                            3. Taylor expanded in x around 0

                                              \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                            4. Step-by-step derivation
                                              1. Applied rewrites43.0%

                                                \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                              2. Taylor expanded in n around inf

                                                \[\leadsto 1 - \color{blue}{1} \]
                                              3. Step-by-step derivation
                                                1. Applied rewrites59.5%

                                                  \[\leadsto 1 - \color{blue}{1} \]

                                                if -2 < (/.f64 #s(literal 1 binary64) n) < 9.99999999999999962e134

                                                1. Initial program 38.6%

                                                  \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                2. Add Preprocessing
                                                3. Taylor expanded in n around inf

                                                  \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                4. Step-by-step derivation
                                                  1. lower-/.f64N/A

                                                    \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                  2. lower--.f64N/A

                                                    \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                                                  3. lower-log1p.f64N/A

                                                    \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                                                  4. lower-log.f6467.7

                                                    \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                                                5. Applied rewrites67.7%

                                                  \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                                                6. Step-by-step derivation
                                                  1. Applied rewrites67.7%

                                                    \[\leadsto \left(\log x - \mathsf{log1p}\left(x\right)\right) \cdot \color{blue}{\frac{-1}{n}} \]
                                                  2. Taylor expanded in x around inf

                                                    \[\leadsto \frac{-1}{x} \cdot \frac{\color{blue}{-1}}{n} \]
                                                  3. Step-by-step derivation
                                                    1. Applied rewrites49.5%

                                                      \[\leadsto \frac{-1}{x} \cdot \frac{\color{blue}{-1}}{n} \]

                                                    if 9.99999999999999962e134 < (/.f64 #s(literal 1 binary64) n)

                                                    1. Initial program 49.8%

                                                      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                    2. Add Preprocessing
                                                    3. Taylor expanded in x around 0

                                                      \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                    4. Step-by-step derivation
                                                      1. Applied rewrites41.7%

                                                        \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                      2. Taylor expanded in n around inf

                                                        \[\leadsto 1 - \color{blue}{1} \]
                                                      3. Step-by-step derivation
                                                        1. Applied rewrites2.2%

                                                          \[\leadsto 1 - \color{blue}{1} \]
                                                        2. Taylor expanded in x around 0

                                                          \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right)} - 1 \]
                                                        3. Step-by-step derivation
                                                          1. +-commutativeN/A

                                                            \[\leadsto \color{blue}{\left(x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) + 1\right)} - 1 \]
                                                          2. *-commutativeN/A

                                                            \[\leadsto \left(\color{blue}{\left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) \cdot x} + 1\right) - 1 \]
                                                          3. lower-fma.f64N/A

                                                            \[\leadsto \color{blue}{\mathsf{fma}\left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}, x, 1\right)} - 1 \]
                                                          4. *-commutativeN/A

                                                            \[\leadsto \mathsf{fma}\left(\color{blue}{\left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) \cdot x} + \frac{1}{n}, x, 1\right) - 1 \]
                                                          5. lower-fma.f64N/A

                                                            \[\leadsto \mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right)}, x, 1\right) - 1 \]
                                                          6. lower--.f64N/A

                                                            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}}, x, \frac{1}{n}\right), x, 1\right) - 1 \]
                                                          7. associate-*r/N/A

                                                            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\frac{\frac{1}{2} \cdot 1}{{n}^{2}}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - 1 \]
                                                          8. metadata-evalN/A

                                                            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\color{blue}{\frac{1}{2}}}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - 1 \]
                                                          9. lower-/.f64N/A

                                                            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\frac{\frac{1}{2}}{{n}^{2}}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - 1 \]
                                                          10. unpow2N/A

                                                            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{\color{blue}{n \cdot n}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - 1 \]
                                                          11. lower-*.f64N/A

                                                            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{\color{blue}{n \cdot n}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - 1 \]
                                                          12. associate-*r/N/A

                                                            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{n \cdot n} - \color{blue}{\frac{\frac{1}{2} \cdot 1}{n}}, x, \frac{1}{n}\right), x, 1\right) - 1 \]
                                                          13. metadata-evalN/A

                                                            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{n \cdot n} - \frac{\color{blue}{\frac{1}{2}}}{n}, x, \frac{1}{n}\right), x, 1\right) - 1 \]
                                                          14. lower-/.f64N/A

                                                            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{n \cdot n} - \color{blue}{\frac{\frac{1}{2}}{n}}, x, \frac{1}{n}\right), x, 1\right) - 1 \]
                                                          15. lower-/.f6455.7

                                                            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, x, \color{blue}{\frac{1}{n}}\right), x, 1\right) - 1 \]
                                                        4. Applied rewrites55.7%

                                                          \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, x, \frac{1}{n}\right), x, 1\right)} - 1 \]
                                                        5. Taylor expanded in n around 0

                                                          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{{n}^{2}}, x, \frac{1}{n}\right), x, 1\right) - 1 \]
                                                        6. Step-by-step derivation
                                                          1. Applied rewrites55.7%

                                                            \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{0.5}{n \cdot n}, x, \frac{1}{n}\right), x, 1\right) - 1 \]
                                                        7. Recombined 3 regimes into one program.
                                                        8. Final simplification53.4%

                                                          \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{1}{n} \leq -2:\\ \;\;\;\;1 - 1\\ \mathbf{elif}\;\frac{1}{n} \leq 10^{+135}:\\ \;\;\;\;\frac{-1}{n} \cdot \frac{-1}{x}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\mathsf{fma}\left(\frac{0.5}{n \cdot n}, x, \frac{1}{n}\right), x, 1\right) - 1\\ \end{array} \]
                                                        9. Add Preprocessing

                                                        Alternative 10: 48.7% accurate, 3.6× speedup?

                                                        \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{1}{n} \leq -2:\\ \;\;\;\;1 - 1\\ \mathbf{elif}\;\frac{1}{n} \leq 5 \cdot 10^{+161}:\\ \;\;\;\;\frac{-1}{n} \cdot \frac{-1}{x}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\frac{x}{n \cdot n} \cdot 0.5, x, 1\right) - 1\\ \end{array} \end{array} \]
                                                        (FPCore (x n)
                                                         :precision binary64
                                                         (if (<= (/ 1.0 n) -2.0)
                                                           (- 1.0 1.0)
                                                           (if (<= (/ 1.0 n) 5e+161)
                                                             (* (/ -1.0 n) (/ -1.0 x))
                                                             (- (fma (* (/ x (* n n)) 0.5) x 1.0) 1.0))))
                                                        double code(double x, double n) {
                                                        	double tmp;
                                                        	if ((1.0 / n) <= -2.0) {
                                                        		tmp = 1.0 - 1.0;
                                                        	} else if ((1.0 / n) <= 5e+161) {
                                                        		tmp = (-1.0 / n) * (-1.0 / x);
                                                        	} else {
                                                        		tmp = fma(((x / (n * n)) * 0.5), x, 1.0) - 1.0;
                                                        	}
                                                        	return tmp;
                                                        }
                                                        
                                                        function code(x, n)
                                                        	tmp = 0.0
                                                        	if (Float64(1.0 / n) <= -2.0)
                                                        		tmp = Float64(1.0 - 1.0);
                                                        	elseif (Float64(1.0 / n) <= 5e+161)
                                                        		tmp = Float64(Float64(-1.0 / n) * Float64(-1.0 / x));
                                                        	else
                                                        		tmp = Float64(fma(Float64(Float64(x / Float64(n * n)) * 0.5), x, 1.0) - 1.0);
                                                        	end
                                                        	return tmp
                                                        end
                                                        
                                                        code[x_, n_] := If[LessEqual[N[(1.0 / n), $MachinePrecision], -2.0], N[(1.0 - 1.0), $MachinePrecision], If[LessEqual[N[(1.0 / n), $MachinePrecision], 5e+161], N[(N[(-1.0 / n), $MachinePrecision] * N[(-1.0 / x), $MachinePrecision]), $MachinePrecision], N[(N[(N[(N[(x / N[(n * n), $MachinePrecision]), $MachinePrecision] * 0.5), $MachinePrecision] * x + 1.0), $MachinePrecision] - 1.0), $MachinePrecision]]]
                                                        
                                                        \begin{array}{l}
                                                        
                                                        \\
                                                        \begin{array}{l}
                                                        \mathbf{if}\;\frac{1}{n} \leq -2:\\
                                                        \;\;\;\;1 - 1\\
                                                        
                                                        \mathbf{elif}\;\frac{1}{n} \leq 5 \cdot 10^{+161}:\\
                                                        \;\;\;\;\frac{-1}{n} \cdot \frac{-1}{x}\\
                                                        
                                                        \mathbf{else}:\\
                                                        \;\;\;\;\mathsf{fma}\left(\frac{x}{n \cdot n} \cdot 0.5, x, 1\right) - 1\\
                                                        
                                                        
                                                        \end{array}
                                                        \end{array}
                                                        
                                                        Derivation
                                                        1. Split input into 3 regimes
                                                        2. if (/.f64 #s(literal 1 binary64) n) < -2

                                                          1. Initial program 100.0%

                                                            \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                          2. Add Preprocessing
                                                          3. Taylor expanded in x around 0

                                                            \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                          4. Step-by-step derivation
                                                            1. Applied rewrites43.0%

                                                              \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                            2. Taylor expanded in n around inf

                                                              \[\leadsto 1 - \color{blue}{1} \]
                                                            3. Step-by-step derivation
                                                              1. Applied rewrites59.5%

                                                                \[\leadsto 1 - \color{blue}{1} \]

                                                              if -2 < (/.f64 #s(literal 1 binary64) n) < 4.9999999999999997e161

                                                              1. Initial program 39.4%

                                                                \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                              2. Add Preprocessing
                                                              3. Taylor expanded in n around inf

                                                                \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                              4. Step-by-step derivation
                                                                1. lower-/.f64N/A

                                                                  \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                                2. lower--.f64N/A

                                                                  \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                                                                3. lower-log1p.f64N/A

                                                                  \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                                                                4. lower-log.f6465.7

                                                                  \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                                                              5. Applied rewrites65.7%

                                                                \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                                                              6. Step-by-step derivation
                                                                1. Applied rewrites65.7%

                                                                  \[\leadsto \left(\log x - \mathsf{log1p}\left(x\right)\right) \cdot \color{blue}{\frac{-1}{n}} \]
                                                                2. Taylor expanded in x around inf

                                                                  \[\leadsto \frac{-1}{x} \cdot \frac{\color{blue}{-1}}{n} \]
                                                                3. Step-by-step derivation
                                                                  1. Applied rewrites48.0%

                                                                    \[\leadsto \frac{-1}{x} \cdot \frac{\color{blue}{-1}}{n} \]

                                                                  if 4.9999999999999997e161 < (/.f64 #s(literal 1 binary64) n)

                                                                  1. Initial program 46.7%

                                                                    \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                  2. Add Preprocessing
                                                                  3. Taylor expanded in x around 0

                                                                    \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                  4. Step-by-step derivation
                                                                    1. Applied rewrites36.5%

                                                                      \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                    2. Taylor expanded in n around inf

                                                                      \[\leadsto 1 - \color{blue}{1} \]
                                                                    3. Step-by-step derivation
                                                                      1. Applied rewrites2.1%

                                                                        \[\leadsto 1 - \color{blue}{1} \]
                                                                      2. Taylor expanded in x around 0

                                                                        \[\leadsto \color{blue}{\left(1 + x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right)\right)} - 1 \]
                                                                      3. Step-by-step derivation
                                                                        1. +-commutativeN/A

                                                                          \[\leadsto \color{blue}{\left(x \cdot \left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) + 1\right)} - 1 \]
                                                                        2. *-commutativeN/A

                                                                          \[\leadsto \left(\color{blue}{\left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}\right) \cdot x} + 1\right) - 1 \]
                                                                        3. lower-fma.f64N/A

                                                                          \[\leadsto \color{blue}{\mathsf{fma}\left(x \cdot \left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) + \frac{1}{n}, x, 1\right)} - 1 \]
                                                                        4. *-commutativeN/A

                                                                          \[\leadsto \mathsf{fma}\left(\color{blue}{\left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}\right) \cdot x} + \frac{1}{n}, x, 1\right) - 1 \]
                                                                        5. lower-fma.f64N/A

                                                                          \[\leadsto \mathsf{fma}\left(\color{blue}{\mathsf{fma}\left(\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right)}, x, 1\right) - 1 \]
                                                                        6. lower--.f64N/A

                                                                          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\frac{1}{2} \cdot \frac{1}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}}, x, \frac{1}{n}\right), x, 1\right) - 1 \]
                                                                        7. associate-*r/N/A

                                                                          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\frac{\frac{1}{2} \cdot 1}{{n}^{2}}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - 1 \]
                                                                        8. metadata-evalN/A

                                                                          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\color{blue}{\frac{1}{2}}}{{n}^{2}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - 1 \]
                                                                        9. lower-/.f64N/A

                                                                          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\color{blue}{\frac{\frac{1}{2}}{{n}^{2}}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - 1 \]
                                                                        10. unpow2N/A

                                                                          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{\color{blue}{n \cdot n}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - 1 \]
                                                                        11. lower-*.f64N/A

                                                                          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{\color{blue}{n \cdot n}} - \frac{1}{2} \cdot \frac{1}{n}, x, \frac{1}{n}\right), x, 1\right) - 1 \]
                                                                        12. associate-*r/N/A

                                                                          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{n \cdot n} - \color{blue}{\frac{\frac{1}{2} \cdot 1}{n}}, x, \frac{1}{n}\right), x, 1\right) - 1 \]
                                                                        13. metadata-evalN/A

                                                                          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{n \cdot n} - \frac{\color{blue}{\frac{1}{2}}}{n}, x, \frac{1}{n}\right), x, 1\right) - 1 \]
                                                                        14. lower-/.f64N/A

                                                                          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{\frac{1}{2}}{n \cdot n} - \color{blue}{\frac{\frac{1}{2}}{n}}, x, \frac{1}{n}\right), x, 1\right) - 1 \]
                                                                        15. lower-/.f6464.3

                                                                          \[\leadsto \mathsf{fma}\left(\mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, x, \color{blue}{\frac{1}{n}}\right), x, 1\right) - 1 \]
                                                                      4. Applied rewrites64.3%

                                                                        \[\leadsto \color{blue}{\mathsf{fma}\left(\mathsf{fma}\left(\frac{0.5}{n \cdot n} - \frac{0.5}{n}, x, \frac{1}{n}\right), x, 1\right)} - 1 \]
                                                                      5. Taylor expanded in n around 0

                                                                        \[\leadsto \mathsf{fma}\left(\frac{1}{2} \cdot \frac{x}{{n}^{2}}, x, 1\right) - 1 \]
                                                                      6. Step-by-step derivation
                                                                        1. Applied rewrites64.3%

                                                                          \[\leadsto \mathsf{fma}\left(\frac{x}{n \cdot n} \cdot 0.5, x, 1\right) - 1 \]
                                                                      7. Recombined 3 regimes into one program.
                                                                      8. Final simplification53.0%

                                                                        \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{1}{n} \leq -2:\\ \;\;\;\;1 - 1\\ \mathbf{elif}\;\frac{1}{n} \leq 5 \cdot 10^{+161}:\\ \;\;\;\;\frac{-1}{n} \cdot \frac{-1}{x}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(\frac{x}{n \cdot n} \cdot 0.5, x, 1\right) - 1\\ \end{array} \]
                                                                      9. Add Preprocessing

                                                                      Alternative 11: 49.5% accurate, 4.1× speedup?

                                                                      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 1.6 \cdot 10^{+59}:\\ \;\;\;\;\frac{\frac{\frac{\frac{0.3333333333333333}{x} - 0.5}{x} + 1}{x}}{n}\\ \mathbf{else}:\\ \;\;\;\;1 - 1\\ \end{array} \end{array} \]
                                                                      (FPCore (x n)
                                                                       :precision binary64
                                                                       (if (<= x 1.6e+59)
                                                                         (/ (/ (+ (/ (- (/ 0.3333333333333333 x) 0.5) x) 1.0) x) n)
                                                                         (- 1.0 1.0)))
                                                                      double code(double x, double n) {
                                                                      	double tmp;
                                                                      	if (x <= 1.6e+59) {
                                                                      		tmp = (((((0.3333333333333333 / x) - 0.5) / x) + 1.0) / x) / n;
                                                                      	} else {
                                                                      		tmp = 1.0 - 1.0;
                                                                      	}
                                                                      	return tmp;
                                                                      }
                                                                      
                                                                      real(8) function code(x, n)
                                                                          real(8), intent (in) :: x
                                                                          real(8), intent (in) :: n
                                                                          real(8) :: tmp
                                                                          if (x <= 1.6d+59) then
                                                                              tmp = (((((0.3333333333333333d0 / x) - 0.5d0) / x) + 1.0d0) / x) / n
                                                                          else
                                                                              tmp = 1.0d0 - 1.0d0
                                                                          end if
                                                                          code = tmp
                                                                      end function
                                                                      
                                                                      public static double code(double x, double n) {
                                                                      	double tmp;
                                                                      	if (x <= 1.6e+59) {
                                                                      		tmp = (((((0.3333333333333333 / x) - 0.5) / x) + 1.0) / x) / n;
                                                                      	} else {
                                                                      		tmp = 1.0 - 1.0;
                                                                      	}
                                                                      	return tmp;
                                                                      }
                                                                      
                                                                      def code(x, n):
                                                                      	tmp = 0
                                                                      	if x <= 1.6e+59:
                                                                      		tmp = (((((0.3333333333333333 / x) - 0.5) / x) + 1.0) / x) / n
                                                                      	else:
                                                                      		tmp = 1.0 - 1.0
                                                                      	return tmp
                                                                      
                                                                      function code(x, n)
                                                                      	tmp = 0.0
                                                                      	if (x <= 1.6e+59)
                                                                      		tmp = Float64(Float64(Float64(Float64(Float64(Float64(0.3333333333333333 / x) - 0.5) / x) + 1.0) / x) / n);
                                                                      	else
                                                                      		tmp = Float64(1.0 - 1.0);
                                                                      	end
                                                                      	return tmp
                                                                      end
                                                                      
                                                                      function tmp_2 = code(x, n)
                                                                      	tmp = 0.0;
                                                                      	if (x <= 1.6e+59)
                                                                      		tmp = (((((0.3333333333333333 / x) - 0.5) / x) + 1.0) / x) / n;
                                                                      	else
                                                                      		tmp = 1.0 - 1.0;
                                                                      	end
                                                                      	tmp_2 = tmp;
                                                                      end
                                                                      
                                                                      code[x_, n_] := If[LessEqual[x, 1.6e+59], N[(N[(N[(N[(N[(N[(0.3333333333333333 / x), $MachinePrecision] - 0.5), $MachinePrecision] / x), $MachinePrecision] + 1.0), $MachinePrecision] / x), $MachinePrecision] / n), $MachinePrecision], N[(1.0 - 1.0), $MachinePrecision]]
                                                                      
                                                                      \begin{array}{l}
                                                                      
                                                                      \\
                                                                      \begin{array}{l}
                                                                      \mathbf{if}\;x \leq 1.6 \cdot 10^{+59}:\\
                                                                      \;\;\;\;\frac{\frac{\frac{\frac{0.3333333333333333}{x} - 0.5}{x} + 1}{x}}{n}\\
                                                                      
                                                                      \mathbf{else}:\\
                                                                      \;\;\;\;1 - 1\\
                                                                      
                                                                      
                                                                      \end{array}
                                                                      \end{array}
                                                                      
                                                                      Derivation
                                                                      1. Split input into 2 regimes
                                                                      2. if x < 1.59999999999999991e59

                                                                        1. Initial program 46.7%

                                                                          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                        2. Add Preprocessing
                                                                        3. Taylor expanded in n around inf

                                                                          \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                                        4. Step-by-step derivation
                                                                          1. lower-/.f64N/A

                                                                            \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                                          2. lower--.f64N/A

                                                                            \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                                                                          3. lower-log1p.f64N/A

                                                                            \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                                                                          4. lower-log.f6444.8

                                                                            \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                                                                        5. Applied rewrites44.8%

                                                                          \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                                                                        6. Taylor expanded in x around 0

                                                                          \[\leadsto \frac{-1 \cdot \log x}{n} \]
                                                                        7. Step-by-step derivation
                                                                          1. Applied rewrites41.7%

                                                                            \[\leadsto \frac{-\log x}{n} \]
                                                                          2. Taylor expanded in x around inf

                                                                            \[\leadsto \frac{\frac{\left(1 + \frac{\frac{1}{3}}{{x}^{2}}\right) - \frac{1}{2} \cdot \frac{1}{x}}{x}}{n} \]
                                                                          3. Step-by-step derivation
                                                                            1. Applied rewrites36.5%

                                                                              \[\leadsto \frac{\frac{\frac{\frac{0.3333333333333333}{x} - 0.5}{x} + 1}{x}}{n} \]

                                                                            if 1.59999999999999991e59 < x

                                                                            1. Initial program 81.6%

                                                                              \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                            2. Add Preprocessing
                                                                            3. Taylor expanded in x around 0

                                                                              \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                            4. Step-by-step derivation
                                                                              1. Applied rewrites39.0%

                                                                                \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                              2. Taylor expanded in n around inf

                                                                                \[\leadsto 1 - \color{blue}{1} \]
                                                                              3. Step-by-step derivation
                                                                                1. Applied rewrites81.6%

                                                                                  \[\leadsto 1 - \color{blue}{1} \]
                                                                              4. Recombined 2 regimes into one program.
                                                                              5. Add Preprocessing

                                                                              Alternative 12: 47.4% accurate, 5.1× speedup?

                                                                              \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{1}{n} \leq -2:\\ \;\;\;\;1 - 1\\ \mathbf{else}:\\ \;\;\;\;\frac{-1}{n} \cdot \frac{-1}{x}\\ \end{array} \end{array} \]
                                                                              (FPCore (x n)
                                                                               :precision binary64
                                                                               (if (<= (/ 1.0 n) -2.0) (- 1.0 1.0) (* (/ -1.0 n) (/ -1.0 x))))
                                                                              double code(double x, double n) {
                                                                              	double tmp;
                                                                              	if ((1.0 / n) <= -2.0) {
                                                                              		tmp = 1.0 - 1.0;
                                                                              	} else {
                                                                              		tmp = (-1.0 / n) * (-1.0 / x);
                                                                              	}
                                                                              	return tmp;
                                                                              }
                                                                              
                                                                              real(8) function code(x, n)
                                                                                  real(8), intent (in) :: x
                                                                                  real(8), intent (in) :: n
                                                                                  real(8) :: tmp
                                                                                  if ((1.0d0 / n) <= (-2.0d0)) then
                                                                                      tmp = 1.0d0 - 1.0d0
                                                                                  else
                                                                                      tmp = ((-1.0d0) / n) * ((-1.0d0) / x)
                                                                                  end if
                                                                                  code = tmp
                                                                              end function
                                                                              
                                                                              public static double code(double x, double n) {
                                                                              	double tmp;
                                                                              	if ((1.0 / n) <= -2.0) {
                                                                              		tmp = 1.0 - 1.0;
                                                                              	} else {
                                                                              		tmp = (-1.0 / n) * (-1.0 / x);
                                                                              	}
                                                                              	return tmp;
                                                                              }
                                                                              
                                                                              def code(x, n):
                                                                              	tmp = 0
                                                                              	if (1.0 / n) <= -2.0:
                                                                              		tmp = 1.0 - 1.0
                                                                              	else:
                                                                              		tmp = (-1.0 / n) * (-1.0 / x)
                                                                              	return tmp
                                                                              
                                                                              function code(x, n)
                                                                              	tmp = 0.0
                                                                              	if (Float64(1.0 / n) <= -2.0)
                                                                              		tmp = Float64(1.0 - 1.0);
                                                                              	else
                                                                              		tmp = Float64(Float64(-1.0 / n) * Float64(-1.0 / x));
                                                                              	end
                                                                              	return tmp
                                                                              end
                                                                              
                                                                              function tmp_2 = code(x, n)
                                                                              	tmp = 0.0;
                                                                              	if ((1.0 / n) <= -2.0)
                                                                              		tmp = 1.0 - 1.0;
                                                                              	else
                                                                              		tmp = (-1.0 / n) * (-1.0 / x);
                                                                              	end
                                                                              	tmp_2 = tmp;
                                                                              end
                                                                              
                                                                              code[x_, n_] := If[LessEqual[N[(1.0 / n), $MachinePrecision], -2.0], N[(1.0 - 1.0), $MachinePrecision], N[(N[(-1.0 / n), $MachinePrecision] * N[(-1.0 / x), $MachinePrecision]), $MachinePrecision]]
                                                                              
                                                                              \begin{array}{l}
                                                                              
                                                                              \\
                                                                              \begin{array}{l}
                                                                              \mathbf{if}\;\frac{1}{n} \leq -2:\\
                                                                              \;\;\;\;1 - 1\\
                                                                              
                                                                              \mathbf{else}:\\
                                                                              \;\;\;\;\frac{-1}{n} \cdot \frac{-1}{x}\\
                                                                              
                                                                              
                                                                              \end{array}
                                                                              \end{array}
                                                                              
                                                                              Derivation
                                                                              1. Split input into 2 regimes
                                                                              2. if (/.f64 #s(literal 1 binary64) n) < -2

                                                                                1. Initial program 100.0%

                                                                                  \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                2. Add Preprocessing
                                                                                3. Taylor expanded in x around 0

                                                                                  \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                4. Step-by-step derivation
                                                                                  1. Applied rewrites43.0%

                                                                                    \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                  2. Taylor expanded in n around inf

                                                                                    \[\leadsto 1 - \color{blue}{1} \]
                                                                                  3. Step-by-step derivation
                                                                                    1. Applied rewrites59.5%

                                                                                      \[\leadsto 1 - \color{blue}{1} \]

                                                                                    if -2 < (/.f64 #s(literal 1 binary64) n)

                                                                                    1. Initial program 40.2%

                                                                                      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                    2. Add Preprocessing
                                                                                    3. Taylor expanded in n around inf

                                                                                      \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                                                    4. Step-by-step derivation
                                                                                      1. lower-/.f64N/A

                                                                                        \[\leadsto \color{blue}{\frac{\log \left(1 + x\right) - \log x}{n}} \]
                                                                                      2. lower--.f64N/A

                                                                                        \[\leadsto \frac{\color{blue}{\log \left(1 + x\right) - \log x}}{n} \]
                                                                                      3. lower-log1p.f64N/A

                                                                                        \[\leadsto \frac{\color{blue}{\mathsf{log1p}\left(x\right)} - \log x}{n} \]
                                                                                      4. lower-log.f6459.1

                                                                                        \[\leadsto \frac{\mathsf{log1p}\left(x\right) - \color{blue}{\log x}}{n} \]
                                                                                    5. Applied rewrites59.1%

                                                                                      \[\leadsto \color{blue}{\frac{\mathsf{log1p}\left(x\right) - \log x}{n}} \]
                                                                                    6. Step-by-step derivation
                                                                                      1. Applied rewrites59.1%

                                                                                        \[\leadsto \left(\log x - \mathsf{log1p}\left(x\right)\right) \cdot \color{blue}{\frac{-1}{n}} \]
                                                                                      2. Taylor expanded in x around inf

                                                                                        \[\leadsto \frac{-1}{x} \cdot \frac{\color{blue}{-1}}{n} \]
                                                                                      3. Step-by-step derivation
                                                                                        1. Applied rewrites47.1%

                                                                                          \[\leadsto \frac{-1}{x} \cdot \frac{\color{blue}{-1}}{n} \]
                                                                                      4. Recombined 2 regimes into one program.
                                                                                      5. Final simplification51.2%

                                                                                        \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{1}{n} \leq -2:\\ \;\;\;\;1 - 1\\ \mathbf{else}:\\ \;\;\;\;\frac{-1}{n} \cdot \frac{-1}{x}\\ \end{array} \]
                                                                                      6. Add Preprocessing

                                                                                      Alternative 13: 47.4% accurate, 5.8× speedup?

                                                                                      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{1}{n} \leq -2:\\ \;\;\;\;1 - 1\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{1}{n}}{x}\\ \end{array} \end{array} \]
                                                                                      (FPCore (x n)
                                                                                       :precision binary64
                                                                                       (if (<= (/ 1.0 n) -2.0) (- 1.0 1.0) (/ (/ 1.0 n) x)))
                                                                                      double code(double x, double n) {
                                                                                      	double tmp;
                                                                                      	if ((1.0 / n) <= -2.0) {
                                                                                      		tmp = 1.0 - 1.0;
                                                                                      	} else {
                                                                                      		tmp = (1.0 / n) / x;
                                                                                      	}
                                                                                      	return tmp;
                                                                                      }
                                                                                      
                                                                                      real(8) function code(x, n)
                                                                                          real(8), intent (in) :: x
                                                                                          real(8), intent (in) :: n
                                                                                          real(8) :: tmp
                                                                                          if ((1.0d0 / n) <= (-2.0d0)) then
                                                                                              tmp = 1.0d0 - 1.0d0
                                                                                          else
                                                                                              tmp = (1.0d0 / n) / x
                                                                                          end if
                                                                                          code = tmp
                                                                                      end function
                                                                                      
                                                                                      public static double code(double x, double n) {
                                                                                      	double tmp;
                                                                                      	if ((1.0 / n) <= -2.0) {
                                                                                      		tmp = 1.0 - 1.0;
                                                                                      	} else {
                                                                                      		tmp = (1.0 / n) / x;
                                                                                      	}
                                                                                      	return tmp;
                                                                                      }
                                                                                      
                                                                                      def code(x, n):
                                                                                      	tmp = 0
                                                                                      	if (1.0 / n) <= -2.0:
                                                                                      		tmp = 1.0 - 1.0
                                                                                      	else:
                                                                                      		tmp = (1.0 / n) / x
                                                                                      	return tmp
                                                                                      
                                                                                      function code(x, n)
                                                                                      	tmp = 0.0
                                                                                      	if (Float64(1.0 / n) <= -2.0)
                                                                                      		tmp = Float64(1.0 - 1.0);
                                                                                      	else
                                                                                      		tmp = Float64(Float64(1.0 / n) / x);
                                                                                      	end
                                                                                      	return tmp
                                                                                      end
                                                                                      
                                                                                      function tmp_2 = code(x, n)
                                                                                      	tmp = 0.0;
                                                                                      	if ((1.0 / n) <= -2.0)
                                                                                      		tmp = 1.0 - 1.0;
                                                                                      	else
                                                                                      		tmp = (1.0 / n) / x;
                                                                                      	end
                                                                                      	tmp_2 = tmp;
                                                                                      end
                                                                                      
                                                                                      code[x_, n_] := If[LessEqual[N[(1.0 / n), $MachinePrecision], -2.0], N[(1.0 - 1.0), $MachinePrecision], N[(N[(1.0 / n), $MachinePrecision] / x), $MachinePrecision]]
                                                                                      
                                                                                      \begin{array}{l}
                                                                                      
                                                                                      \\
                                                                                      \begin{array}{l}
                                                                                      \mathbf{if}\;\frac{1}{n} \leq -2:\\
                                                                                      \;\;\;\;1 - 1\\
                                                                                      
                                                                                      \mathbf{else}:\\
                                                                                      \;\;\;\;\frac{\frac{1}{n}}{x}\\
                                                                                      
                                                                                      
                                                                                      \end{array}
                                                                                      \end{array}
                                                                                      
                                                                                      Derivation
                                                                                      1. Split input into 2 regimes
                                                                                      2. if (/.f64 #s(literal 1 binary64) n) < -2

                                                                                        1. Initial program 100.0%

                                                                                          \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                        2. Add Preprocessing
                                                                                        3. Taylor expanded in x around 0

                                                                                          \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                        4. Step-by-step derivation
                                                                                          1. Applied rewrites43.0%

                                                                                            \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                          2. Taylor expanded in n around inf

                                                                                            \[\leadsto 1 - \color{blue}{1} \]
                                                                                          3. Step-by-step derivation
                                                                                            1. Applied rewrites59.5%

                                                                                              \[\leadsto 1 - \color{blue}{1} \]

                                                                                            if -2 < (/.f64 #s(literal 1 binary64) n)

                                                                                            1. Initial program 40.2%

                                                                                              \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                            2. Add Preprocessing
                                                                                            3. Taylor expanded in x around inf

                                                                                              \[\leadsto \color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{n \cdot x}} \]
                                                                                            4. Step-by-step derivation
                                                                                              1. associate-/l/N/A

                                                                                                \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                                                                                              2. lower-/.f64N/A

                                                                                                \[\leadsto \color{blue}{\frac{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}{n}} \]
                                                                                              3. lower-/.f64N/A

                                                                                                \[\leadsto \frac{\color{blue}{\frac{e^{-1 \cdot \frac{\log \left(\frac{1}{x}\right)}{n}}}{x}}}{n} \]
                                                                                              4. log-recN/A

                                                                                                \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{\mathsf{neg}\left(\log x\right)}}{n}}}{x}}{n} \]
                                                                                              5. mul-1-negN/A

                                                                                                \[\leadsto \frac{\frac{e^{-1 \cdot \frac{\color{blue}{-1 \cdot \log x}}{n}}}{x}}{n} \]
                                                                                              6. associate-*r/N/A

                                                                                                \[\leadsto \frac{\frac{e^{\color{blue}{\frac{-1 \cdot \left(-1 \cdot \log x\right)}{n}}}}{x}}{n} \]
                                                                                              7. associate-*r*N/A

                                                                                                \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\left(-1 \cdot -1\right) \cdot \log x}}{n}}}{x}}{n} \]
                                                                                              8. metadata-evalN/A

                                                                                                \[\leadsto \frac{\frac{e^{\frac{\color{blue}{1} \cdot \log x}{n}}}{x}}{n} \]
                                                                                              9. *-commutativeN/A

                                                                                                \[\leadsto \frac{\frac{e^{\frac{\color{blue}{\log x \cdot 1}}{n}}}{x}}{n} \]
                                                                                              10. associate-/l*N/A

                                                                                                \[\leadsto \frac{\frac{e^{\color{blue}{\log x \cdot \frac{1}{n}}}}{x}}{n} \]
                                                                                              11. exp-to-powN/A

                                                                                                \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                                                                                              12. lower-pow.f64N/A

                                                                                                \[\leadsto \frac{\frac{\color{blue}{{x}^{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                                                                                              13. lower-/.f6443.3

                                                                                                \[\leadsto \frac{\frac{{x}^{\color{blue}{\left(\frac{1}{n}\right)}}}{x}}{n} \]
                                                                                            5. Applied rewrites43.3%

                                                                                              \[\leadsto \color{blue}{\frac{\frac{{x}^{\left(\frac{1}{n}\right)}}{x}}{n}} \]
                                                                                            6. Taylor expanded in n around inf

                                                                                              \[\leadsto \frac{1}{\color{blue}{n \cdot x}} \]
                                                                                            7. Step-by-step derivation
                                                                                              1. Applied rewrites47.1%

                                                                                                \[\leadsto \frac{\frac{1}{n}}{\color{blue}{x}} \]
                                                                                            8. Recombined 2 regimes into one program.
                                                                                            9. Add Preprocessing

                                                                                            Alternative 14: 31.0% accurate, 57.8× speedup?

                                                                                            \[\begin{array}{l} \\ 1 - 1 \end{array} \]
                                                                                            (FPCore (x n) :precision binary64 (- 1.0 1.0))
                                                                                            double code(double x, double n) {
                                                                                            	return 1.0 - 1.0;
                                                                                            }
                                                                                            
                                                                                            real(8) function code(x, n)
                                                                                                real(8), intent (in) :: x
                                                                                                real(8), intent (in) :: n
                                                                                                code = 1.0d0 - 1.0d0
                                                                                            end function
                                                                                            
                                                                                            public static double code(double x, double n) {
                                                                                            	return 1.0 - 1.0;
                                                                                            }
                                                                                            
                                                                                            def code(x, n):
                                                                                            	return 1.0 - 1.0
                                                                                            
                                                                                            function code(x, n)
                                                                                            	return Float64(1.0 - 1.0)
                                                                                            end
                                                                                            
                                                                                            function tmp = code(x, n)
                                                                                            	tmp = 1.0 - 1.0;
                                                                                            end
                                                                                            
                                                                                            code[x_, n_] := N[(1.0 - 1.0), $MachinePrecision]
                                                                                            
                                                                                            \begin{array}{l}
                                                                                            
                                                                                            \\
                                                                                            1 - 1
                                                                                            \end{array}
                                                                                            
                                                                                            Derivation
                                                                                            1. Initial program 60.1%

                                                                                              \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                            2. Add Preprocessing
                                                                                            3. Taylor expanded in x around 0

                                                                                              \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                            4. Step-by-step derivation
                                                                                              1. Applied rewrites40.0%

                                                                                                \[\leadsto \color{blue}{1} - {x}^{\left(\frac{1}{n}\right)} \]
                                                                                              2. Taylor expanded in n around inf

                                                                                                \[\leadsto 1 - \color{blue}{1} \]
                                                                                              3. Step-by-step derivation
                                                                                                1. Applied rewrites36.1%

                                                                                                  \[\leadsto 1 - \color{blue}{1} \]
                                                                                                2. Add Preprocessing

                                                                                                Reproduce

                                                                                                ?
                                                                                                herbie shell --seed 2024242 
                                                                                                (FPCore (x n)
                                                                                                  :name "2nthrt (problem 3.4.6)"
                                                                                                  :precision binary64
                                                                                                  (- (pow (+ x 1.0) (/ 1.0 n)) (pow x (/ 1.0 n))))